diff --git a/.gitignore b/.gitignore
new file mode 100644
index 0000000000000000000000000000000000000000..ba0430d26c996e7f078385407f959c96c271087c
--- /dev/null
+++ b/.gitignore
@@ -0,0 +1 @@
+__pycache__/
\ No newline at end of file
diff --git a/README.md b/README.md
new file mode 100644
index 0000000000000000000000000000000000000000..8c6ace3d8e49b9e546a7f655d7de7d853ee81372
--- /dev/null
+++ b/README.md
@@ -0,0 +1,13 @@
+---
+configs:
+- config_name: final_dataset
+  data_files: "data/final_dataset.csv"
+- config_name: evaluation_dataset
+  data_files: "data/evaluation_dataset.csv"
+- config_name: testset
+  data_files: "data/testset.csv"
+- config_name: train
+  data_files: "data/train.csv"
+---
+
+# Socratic benchmark
diff --git a/data/evaluation_dataset.csv b/data/evaluation_dataset.csv
new file mode 100644
index 0000000000000000000000000000000000000000..2355ebf7f54d08e3f05a7abd5e881dc1fda9ceb7
--- /dev/null
+++ b/data/evaluation_dataset.csv
@@ -0,0 +1,8445 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
+","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n <= 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+    a = 0
+   b = 1
+   for i in range(0, n):
+     temp = b
+     b = a + b
+     a = temp
+   return b","On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.","Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.","assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_0_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(0, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.\n</bug_desc>\n<bug_fixes>\nReplace `range(0, n)` with `range(1, n)` on line 11.\nReplace `range(0, n)` with `range(0, n - 1)` on line 11.\nReplace `range(0, n)` with `range(2, n + 1)` on line 11.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\nThe student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey, I really need help. This function is not returning the correct number.'}, {'role': 'assistant', 'content': ""I'll be happy to help you. What happens when you call `fibonacci(5)`?"", 'alt': ['Happy to help. Can you give me an example of your function returning an incorrect number?', 'Sure. Can you list the first 5 numbers in the Fibonacci sequence?', 'Can you describe what your code does line by line?']}, {'role': 'user', 'content': 'When I run the function with `n` as 5 the output is 8 instead of 5.'}, {'role': 'assistant', 'content': 'I see. What do you think might be the cause of this?', 'alt': ['Can you describe your for loop on line 11?', 'Can you walk me through the steps your function takes to generate the Fibonacci sequence?', 'Can you identify any issues with the loop that generates the Fibonacci sequence?', 'Which part of your code do you suspect of causing this issue?']}, {'role': 'user', 'content': ""I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return."", 'alt': ['I am not sure. Can you help?', 'I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.']}, {'role': 'assistant', 'content': 'Good. Can you explain your for loop on line 11?', 'alt': ['What specifically about your for loop on line 11 might be causing the issue?', 'Good. Can you describe how many times the for loop iterates on line 11?', 'Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?', 'Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?', 'Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?']}, {'role': 'user', 'content': 'The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.', 'alt': ['It loops `n` times', 'Not really sure how to describe it.']}, {'role': 'assistant', 'content': ""Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?"", 'alt': ['What are the values of `a` and `b` in each iteration?', 'What variables used in the for loop on line 11 should we pay attention to identify the issue?', ""Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?"", ""Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?""]}, {'role': 'user', 'content': ""I'm not really sure can you suggest a way?"", 'alt': ['I can use the debugger!', 'I can add print statements.']}, {'role': 'assistant', 'content': 'Have you considered inserting a print statement after line 12 to output the 3 variables?', 'alt': ['Have you considered using the debugger?']}, {'role': 'user', 'content': 'Aha! Good idea! Perfect let me do that.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.   b = 1\n11.   for i in range(0, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Let's look at the outputs what do you observe?""}, {'role': 'user', 'content': 'I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.', 'alt': ['It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.', ""Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.""]}, {'role': 'assistant', 'content': 'What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?', 'alt': ['Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?']}, {'role': 'user', 'content': 'We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.'}, {'role': 'assistant', 'content': 'Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?', 'alt': ['Good. What should you do now to return the correct Fibonacci number?']}, {'role': 'user', 'content': 'I think I should edit the range of the loop to iterate one less time. Let me edit my code.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Good work. Don't forget to remove the print statement!""}, {'role': 'user', 'content': 'Ah yes! Thank you so much for your help!\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'You are welcome. Let me know if you have any further questions.'}, {'role': 'user', 'content': 'Thanks again! Goodbye!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 or n == 2:
+       return 1
+   else:
+       return fibonacci(n) + fibonacci(n-1)",`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.,Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_5_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n) + fibonacci(n-1)\n</bug_code>\n<bug_desc>\n`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.\n</bug_desc>\n<bug_fixes>\nReplace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?'}, {'role': 'assistant', 'content': 'I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?', 'alt': ['According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?', 'According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?', 'Can you explain what infinite recursion means?', 'Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?', ""Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?"", 'Can you explain what a recursive function is? When do we call a function recursive?', 'According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?']}, {'role': 'user', 'content': 'I believe it is line 7, because that is the line that is executed when `n` is larger than 2.'}, {'role': 'assistant', 'content': 'That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?', 'alt': ['Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?', 'Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?']}, {'role': 'user', 'content': 'Well, the function is called recursively to compute `fibonacci(3)`.\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 1) + fibonacci(n - 2)\n```', 'alt': ['Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.', 'Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...', 'The call `fibonacci(n)`.']}, {'role': 'assistant', 'content': 'So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?', 'alt': ['Do you see now why infinite recursion happens?', 'So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?']}, {'role': 'user', 'content': 'Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 2) + fibonacci(n - 1)\n```'}, {'role': 'assistant', 'content': 'Great, your program now works as expected!'}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 and n == 2:
+       return 1
+   elif n > 2:
+       a = 1
+       b = 1
+       for i in range(3, n+1):
+           c = a + b
+           a = b
+           b = c
+       return b","On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.",Replace `and` with `or` on line 4.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_6_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 and n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n</bug_code>\n<bug_desc>\nOn line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.\n</bug_desc>\n<bug_fixes>\nReplace `and` with `or` on line 4.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, my program passes all test cases except the second and third. Can you help?'}, {'role': 'assistant', 'content': 'Hi! Sure, what does the problem description say about these two cases?', 'alt': ['Hi! Sure, what is the value of `n` in these two cases?', 'Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?', 'Hi! Sure, what is the output supposed to be for each of these cases?']}, {'role': 'user', 'content': 'I am not sure, how can I find that?', 'alt': ['It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`']}, {'role': 'assistant', 'content': 'What are the values of `n` for these two cases?', 'alt': ['There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?']}, {'role': 'user', 'content': 'In the second test case, the value of `n` is `1` and in the third case `n` is `2`.'}, {'role': 'assistant', 'content': 'Correct, what are we supposed to return for these values of `n`?'}, {'role': 'user', 'content': 'We are supposed to return `1`, and I handled these cases on lines 4 and 5.'}, {'role': 'assistant', 'content': 'Ok, when does line 4 evaluate to true?', 'alt': ['Ok, for what value of `n` will line 5 be executed?']}, {'role': 'user', 'content': 'It evaluates to true if `n` is `1` and if it is `2`'}, {'role': 'assistant', 'content': 'Will the value of `n` ever be `1` and `2` at the same time?'}, {'role': 'user', 'content': 'No, it can be either `1` or `2`, but never both at the same time.', 'alt': ['No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?']}, {'role': 'assistant', 'content': 'Correct! It is either `1` OR `2`, does your if statement check for that?'}, {'role': 'user', 'content': 'Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n```'}, {'role': 'assistant', 'content': 'That looks great! It now returns `1` when `n` is either `1` or `2`.'}, {'role': 'user', 'content': 'Thank you for explaining the difference between `or` and `and`!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n < 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+   a = 0
+   b = 1
+   for i in range(1, n):
+     temp = b 
+     b = a + b 
+     a = temp
+   return b","On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`.",Replace `if n < 0` with `if n <= 0` on line 2.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_2_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n < 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `\'OOPS\'` when `n` is equal to `0`. \n</bug_desc>\n<bug_fixes>\nReplace `if n < 0` with `if n <= 0` on line 2.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I need help on this my code is failing the first test case.', 'alt': ['Hello. I need help with my code.']}, {'role': 'assistant', 'content': 'Can you walk me through your code step by step given that `n` is 0?', 'alt': [""Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?"", 'Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?']}, {'role': 'user', 'content': '`n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'Good. Did you try it for all the unit tests?'}, {'role': 'user', 'content': 'Yes I have. Thank you so much for your help!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   hw = hw * 0.2
+   exams = exams * 0.4
+   projects = projects * 0.30
+   att = att * 0.10
+
+   finalScore = hw + exams + projects + att
+   roundedScore = round(finalScore)
+
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.","Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_10_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if finalScore >= 90:\n11.        letterGrade = ""A""\n12.    elif finalScore >= 80:\n13.        letterGrade = ""B""\n14.    elif finalScore >= 70:\n15.        letterGrade = ""C""\n16.    elif finalScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nOn lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.\n</bug_desc>\n<bug_fixes>\nReplace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?'}, {'role': 'assistant', 'content': 'I would love to! What kind of problems are you having?', 'alt': ['Can you describe what your code fails to do?', 'Can you explain your code to me line by line?']}, {'role': 'user', 'content': ""I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).""}, {'role': 'assistant', 'content': ""Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?"", 'alt': ['Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?', 'Let’s trace back what your function did. Where did `D` in your returned tuple come from?', 'Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?']}, {'role': 'user', 'content': 'The value assigned to `finalScore` is 69.6.', 'alt': ['The value would be 70, right?']}, {'role': 'assistant', 'content': 'Correct. Which block of the if-elif-else statement is executed?', 'alt': ['What does the boolean expression on line 14 evaluate to?', 'Can you explain the differences between `finalScore` and `roundedScore`?', 'What is the truth value of the boolean expression on line 14?']}, {'role': 'user', 'content': 'Oh! The boolean on line 16 becomes true, assigning `letterGrade` to \'D\'! But I\'m not sure how to fix that.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```', 'alt': ['Oh, I put `finalScore` instead of `roundedScore`!']}, {'role': 'assistant', 'content': 'How would you ensure that the grade would be treated as its nearest integer for the comparison?', 'alt': ['How does your code return a grade of 70, yet compares with 69.6?']}, {'role': 'user', 'content': 'Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good. Happy to help. Let me know if you have any further questions!'}, {'role': 'user', 'content': 'Thank you so much for your help again!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.   elif roundedScore >= 60:
+11.       letterGrade = ""D""
+12.   else:
+13.       letterGrade = ""F""
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore >= 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+  elif roundedScore >= 60:
+      letterGrade = ""D""
+  else:
+      letterGrade = ""F""
+  return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue","The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.","Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_11_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\ncalculateGrade(100, 89, 85, 90) => ('A', 90)\ncalculateGrade(72, 96, 74, 98) => ('B', 85)\ncalculateGrade(100, 82, 68, 94) => ('B', 83)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(12, 14, 23, 10) => ('F', 16)\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\n```\n</problem>\n<bug_desc>\nThe return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.\n</bug_desc>\n<bug_fixes>\nRemove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(72, 96, 74, 98) == ('B', 85)\nassert calculateGrade(100, 82, 68, 94) == ('B', 83)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(12, 14, 23, 10) == ('F', 16)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hi, please help I'm not sure what's going wrong""}, {'role': 'assistant', 'content': ""Hello. Let's take a look at your code together. What problem are you facing?"", 'alt': ['Hi. Are you encountering an error?', 'Hello. Can you describe your code line by line?', ""Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?""]}, {'role': 'user', 'content': 'The function only seems to return the `letterGrade` but otherwise it runs alright.', 'alt': ['It does not throw an error, but it does not show everything I want it to either.', 'No errors but it is not working as expected.']}, {'role': 'assistant', 'content': ""Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?""}, {'role': 'user', 'content': 'Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?', 'alt': ['It seems like the last line never executes.']}, {'role': 'assistant', 'content': 'Good! Given this observation, when does your function terminate?', 'alt': ['Good! Can you describe what are you trying to do on line 15?', 'What makes you think line 15 is not being executed?', 'Can you describe what are you trying to do on lines 14 and 15?']}, {'role': 'user', 'content': 'It seems like once the return statement has executed, the function does not go further.'}, {'role': 'assistant', 'content': 'Is it possible for a function to have two consecutive return statements?', 'alt': [""Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?"", 'How about we look up this behavior in the documentation to get more clarity?']}, {'role': 'user', 'content': 'It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?', 'alt': ['But then how do I make sure to return both the `letterGrade` and `roundedScore`?', 'Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!']}, {'role': 'assistant', 'content': ""Good question! Let's turn to the documentation - how can we return multiple variables?"", 'alt': [""Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?"", ""Let's look at the examples in the instructions. What do you notice is being returned?""]}, {'role': 'user', 'content': 'Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.   elif roundedScore >= 60:\n11.       letterGrade = ""D""\n12.   else:\n13.       letterGrade = ""F""\n14.   return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Great job! Is your code working now?', 'alt': ['Did that fix your problem?']}, {'role': 'user', 'content': 'Yes it did, thanks!', 'alt': [""I'm all done!""]}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   weights = [0.1, 0.3, 0.4, 0.2]
+   grades = [hw, exams, projects, att]
+   final_grade = 0
+   for i in range(len(weights)):
+       final_grade += weights[i] * grades[i]
+   final_grade = round(final_grade)
+   
+   if final_grade >= 90:
+       return ('A', final_grade)
+   elif final_grade >= 80:
+       return ('B', final_grade)
+   elif final_grade >= 70:
+       return ('C', final_grade)
+   elif final_grade >= 60:
+       return ('D', final_grade)
+   else:
+       return ('F', final_grade)","On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.","On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_13_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(100, 89, 85, 90) == ('A', 90)\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.1, 0.3, 0.4, 0.2]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.\n</bug_desc>\n<bug_fixes>\nOn line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.\nOn line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck""}, {'role': 'assistant', 'content': 'Okay, what do you think the problem is?', 'alt': ['Can you tell me what test cases are failing?', 'Have you thought about the problem?']}, {'role': 'user', 'content': ""It isn't calculating correctly."", 'alt': [""It's failing the second test case.""]}, {'role': 'assistant', 'content': 'How is the calculation made in the function?', 'alt': ['Can you tell me what test cases are failing?', 'Where do you think the problem is?', 'Start with line 1, do you see any problems with the method header?', 'Look at the second test case, how is it different from the first test case?']}, {'role': 'user', 'content': 'The scores are multiplied with the weights and summed up.', 'alt': ['Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.']}, {'role': 'assistant', 'content': 'So, is it working for the first test case?', 'alt': ['Do you see any problems adding the scores on the assignments to the grades array?', 'Do you see any problems with the loop?', 'Do you see any problems with the weights?', ""Check the instructions, do you see anything you aren't doing?"", 'Why is it working on the first test case and not the second?', 'Check the loop, are all the values being considered?']}, {'role': 'user', 'content': 'Yes, the first test case is correct, but the second one is wrong.'}, {'role': 'assistant', 'content': 'How are the two test cases different?', 'alt': ['Do you see any problems with the weights?', 'Do you see any problems with passing in the grades?', ""Check the instructions, do you see anything you aren't doing?"", 'Do you see any differences in the numbers between the two test cases?']}, {'role': 'user', 'content': 'The first test case has all the values the same, and the second test case has different values.', 'alt': ['The first test case has all 100s, but different numbers for the second case.', ""I'm not sure.""]}, {'role': 'assistant', 'content': 'Does the order of the input parameters matter?', 'alt': ['Why does the order matter?', 'Are any specific lines of code impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Which parameter represents homework?']}, {'role': 'user', 'content': 'Yes, the order of inputs does matter.'}, {'role': 'assistant', 'content': 'Why?', 'alt': ['Which lines are impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Look back at the instructions, what should the weight be for the first value?']}, {'role': 'user', 'content': 'Because that determines which value is associated with the different grade categories.'}, {'role': 'assistant', 'content': 'Why does that change the calculation?', 'alt': ['What is the correct weight for the homework?', 'On what line of code are those values assigned?', 'Are those values passed into the array in the proper order?']}, {'role': 'user', 'content': 'The type of grade changes the weight for the calculation.'}, {'role': 'assistant', 'content': 'What is the correct weight for homework?', 'alt': ['Look at the grades array, does it match the order the parameters are passed in?', 'Look at the weights array, does that match the order for the categories?', 'What do you think is causing the problem here?']}, {'role': 'user', 'content': 'Homework should have a weight of 20%.'}, {'role': 'assistant', 'content': 'How is that set in the code?', 'alt': ['What weight should exams have?', 'Look at the weights array, does that match the order for the categories?']}, {'role': 'user', 'content': ""It's set in the weights array."", 'alt': ['I see, the weights array is wrong!']}, {'role': 'assistant', 'content': 'Check the weights array, does the first item match the correct weight for homework?', 'alt': ['How does the weights array interact with the grades array?', 'Which item in the weights array should correspond with homework?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""No, the first item is 0.1, that's the weight for attendance."", 'alt': [""It's in the wrong order.""]}, {'role': 'assistant', 'content': 'What should you change the weights array to?', 'alt': ['Should the first item in the weights array go with the first item in the grades array?', 'Should the arrays be parallel?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""I'll switch the attendance and homework weights on line 2.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.3, 0.4, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Did that fix it?', 'alt': ['Is that everything?', 'Did you check the other weights?']}, {'role': 'user', 'content': ""No, it still doesn't work.""}, {'role': 'assistant', 'content': 'Keep looking, do you see any other problems with the weights array?', 'alt': ['Did which test cases pass change?', 'Does the first test case still pass?', 'What about the second item in the grades array, does it match with the second item in the weights array?', 'What is the correct weight for exams?']}, {'role': 'user', 'content': ""Yes, exams and projects are flipped too!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.4, 0.3, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Does it pass now?'}, {'role': 'user', 'content': 'Yes, all the test cases pass. Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = ""A""
+7.    elif roundedScore >= 80:
+8.        letterGrade = ""B""
+9.    elif roundedScore >= 70:
+10.        letterGrade = ""C""
+11.    elif roundedScore >= 60:
+12.        letterGrade = ""D""
+13.    else:
+14.        letterGrade = ""F""
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore > 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+   elif roundedScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.",Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.,"assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_8_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore > 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nWhen `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `roundedScore > 90` with `roundedScore >= 90` on line 4.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['What test cases are passing?', 'What test cases are failing?', 'Have you reread the prompt?', 'Have you checked the calculation for the grade?', 'Have you checked the if-statement?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's go through your function line by line, how can you check the calculation on line 2?"", 'alt': [""Let's start by looking at the test cases, what is the first one to fail?"", ""Let's start by looking at the test cases, does the first one pass?""]}, {'role': 'user', 'content': 'I can add a print statement to check the number.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    if roundedScore > 90:\n6.        letterGrade = ""A""\n7.    elif roundedScore >= 80:\n8.        letterGrade = ""B""\n9.    elif roundedScore >= 70:\n10.        letterGrade = ""C""\n11.    elif roundedScore >= 60:\n12.        letterGrade = ""D""\n13.    else:\n14.        letterGrade = ""F""\n15.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good, what is the first test case to fail?', 'alt': ['Good, does the first test case succeed?', 'Good, is the first `finalScore` correct?', 'Good, what is the first incorrect `finalScore`?']}, {'role': 'user', 'content': 'The second test case fails.'}, {'role': 'assistant', 'content': 'Is the `finalScore` correct for that test case?', 'alt': ['Do you think it is a rounding error?', 'What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?', 'How can you check if it is a rounding error?']}, {'role': 'user', 'content': 'Yes, the final score is correct for that test case.'}, {'role': 'assistant', 'content': 'How can you check if it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?']}, {'role': 'user', 'content': 'I can add another print statement after line 4 and check the rounding.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore > 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good. Do you think it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': ""No, I don't think so.""}, {'role': 'assistant', 'content': ""Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?"", 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': 'It checks if the rounded score is greater than 90.', 'alt': ['I see, it should be greater than or equal to!']}, {'role': 'assistant', 'content': 'Think about that carefully, would it return true or false if the grade was exactly 90?'}, {'role': 'user', 'content': 'No, it wouldn\'t! That\'s wrong, it should be greater than or equal to!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore >= 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Try running it again, does it work now?'}, {'role': 'user', 'content': 'Yes! It does. I\'ll remove the extra print statements.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good.'}, {'role': 'user', 'content': 'Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = ""A""
+6.    elif finalScore >= 80:
+7.        letterGrade = ""B""
+8.    elif finalScore >= 70:
+9.        letterGrade = ""C""
+10.    elif finalScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, finalScore","The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.","After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_9_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(100, 89, 85, 90) == (\'A\', 90)\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    if finalScore >= 90:\n4.        letterGrade = ""A""\n5.    elif finalScore >= 80:\n6.        letterGrade = ""B""\n7.    elif finalScore >= 70:\n8.        letterGrade = ""C""\n9.    elif finalScore >= 60:\n10.        letterGrade = ""D""\n11.    else:\n12.        letterGrade = ""F""\n13.    return letterGrade, finalScore\n</bug_code>\n<bug_desc>\nThe function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.\n</bug_desc>\n<bug_fixes>\nAfter line 2, add a new line with the following snippet `finalScore = round(finalScore)`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.""}, {'role': 'assistant', 'content': 'Where, in your code, do you think this problem is happening?', 'alt': ['Why do you expect the output of 69.6 to return D?', 'What do you think we can do to figure out where our problem is?']}, {'role': 'user', 'content': ""I think it's happening in the if-statements."", 'alt': [""I don't know where."", ""It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70."", ""I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.""]}, {'role': 'assistant', 'content': 'Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?', 'alt': ['Which condition in the if-statements is causing your problem?']}, {'role': 'user', 'content': ""Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way."", 'alt': ['I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.', 'I have no idea.', ""I don't really understand how if-statements work.""]}, {'role': 'assistant', 'content': ""That's a good point! What do you think you should do next?"", 'alt': ['Good observation! How would you round `finalScore`?']}, {'role': 'user', 'content': ""I need to round `finalScore`, but I don't know how to do that."", 'alt': ['I can use the `round()` method on the `finalScore`.', 'I can do`finalScore = round(finalScore)`', 'I can do `finalScore = finalScore.round()`']}, {'role': 'assistant', 'content': 'You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?', 'alt': [""If you don't know how to round a variable, do you have any idea where you could look to figure it out?""]}, {'role': 'user', 'content': 'Oh, wait. I found a round() function. If I don\'t specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    finalScore = round(finalScore)\n4.    if finalScore >= 90:\n5.        letterGrade = ""A""\n6.    elif finalScore >= 80:\n7.        letterGrade = ""B""\n8.    elif finalScore >= 70:\n9.        letterGrade = ""C""\n10.    elif finalScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, finalScore\n```', 'alt': ['I have no idea what method can help me.', ""I don't understand what a method is."", 'I could use `finalScore = round(finalScore, 2)`']}, {'role': 'assistant', 'content': 'Good work! You did it.'}]}"
+"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input ""English""?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, ""x"")
+      else:
+           sen = sen.replace(i, ""X"")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>","Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```","def toxNGLXSH(sen):
+ vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+ for i in vowels:
+     if i.islower():
+          sen.replace(i, ""x"")
+     else:
+          sen.replace(i, ""X"")
+ sen.swapcase()
+ return sen","On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.",Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.,"assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'",10_39_xnglxsh,"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+","{'system': '<problem>\nCreate a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with \'X\', each uppercase vowel is replaced with \'x\', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.\n\n## Example Cases:\n```\ntoxNGLXSH(\'English\') => \'xNGLXSH\'\ntoxNGLXSH(\'hello there!\') => \'HXLLX THXRX!\'\ntoxNGLXSH(""My name is John!"") => \'mY NXMX XS jXHN!\'\ntoxNGLXSH(\'To be or not to be!\') => \'tX BX XR NXT TX BX!\'\ntoxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') => \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n```\n</problem>\n<bug_code>\n1. def toxNGLXSH(sen):\n2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n3.  for i in vowels:\n4.      if i.islower():\n5.           sen.replace(i, ""x"")\n6.      else:\n7.           sen.replace(i, ""X"")\n8.  sen.swapcase()\n9.  return sen\n</bug_code>\n<bug_desc>\nOn lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.\n</bug_desc>\n<bug_fixes>\nReplace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.\n</bug_fixes>\n<unit_tests>\nassert toxNGLXSH(\'English\') == \'xNGLXSH\'\nassert toxNGLXSH(\'hello there!\') == \'HXLLX THXRX!\'\nassert toxNGLXSH(""My name is John!"") == \'mY NXMX XS jXHN!\'\nassert toxNGLXSH(\'To be or not to be!\') == \'tX BX XR NXT TX BX!\'\nassert toxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') == \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Help! I wrote a lot of code and nothing is working.'}, {'role': 'assistant', 'content': ""I'm here to help. Can you describe the problem you are having?"", 'alt': ['Can you walk me through your code line by line?', 'Let\'s start with a simple example. What is the output of your code when you run it with the input ""English""?', 'What does the `.replace()` method do?', 'What does the `.swapcase()` method do?']}, {'role': 'user', 'content': ""I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?""}, {'role': 'assistant', 'content': 'What are some reasons it could be staying the same?', 'alt': ['What does the `.replace()` method do and does it modify the original string?', 'What does the `.swapcase()` method do and does it modify the original string?']}, {'role': 'user', 'content': 'If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.', 'alt': [""I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.""]}, {'role': 'assistant', 'content': 'Let\'s open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?', 'alt': ['Let\'s open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?']}, {'role': 'user', 'content': 'Ok, I tried that, and it looks like it returns the modified string I expect `TX`.', 'alt': ['Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.']}, {'role': 'assistant', 'content': 'Good. Now let\'s try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?', 'alt': [""Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?""]}, {'role': 'user', 'content': 'Ah. It looks like the string methods don\'t modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.\n```python\ndef toxNGLXSH(sen):\n  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n  for i in vowels:\n      if i.islower():\n           sen = sen.replace(i, ""x"")\n      else:\n           sen = sen.replace(i, ""X"")\n  sen = sen.swapcase()\n  return sen\n```'}, {'role': 'assistant', 'content': 'That looks good! Why do you think it worked?'}, {'role': 'user', 'content': ""It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.""}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>","Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```","def is_palindrome(string):
+ rev_string = ''
+ for i in string:
+   rev_string = i + rev_string
+ if rev_string = string:
+   return True
+ else:
+   return False","On line 5, the function throws a syntax error.",Replace `=` with `==` on line 5.,"assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True",11_40_palindrome,"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.\n## Example Cases:\n```\nis_palindrome(""racecar"") => True\nis_palindrome(""hello"") => False\nis_palindrome(""hannah"") => True\nis_palindrome(""firetruck"") => False\nis_palindrome(""nice"") => False\nis_palindrome("""") => True\n```\n</problem>\n<bug_code>\n1. def is_palindrome(string):\n2.  rev_string = \'\'\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string = string:\n6.    return True\n7.  else:\n8.    return False\n</bug_code>\n<bug_desc>\nOn line 5, the function throws a syntax error.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on line 5.\n</bug_fixes>\n<unit_tests>\nassert is_palindrome(""racecar"") == True\nassert is_palindrome(""hello"") == False\nassert is_palindrome(""hannah"") == True\nassert is_palindrome(""firetruck"") == False\nassert is_palindrome(""nice"") == False\nassert is_palindrome("""") == True\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey! I have a compiler error here.'}, {'role': 'assistant', 'content': 'Ok, what error do you see?', 'alt': [""Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?"", 'What line is the compiler error pointing towards?']}, {'role': 'user', 'content': ""It's giving me an error on my equality operator use.""}, {'role': 'assistant', 'content': 'I see. How do you assign a value of 1 to a variable `x`?', 'alt': ['How do you assign an empty string to the variable `rev_string`?', 'How would you check if two  variables `x` and `y` are equivalent?', 'Can you recall what the assignment operator is?']}, {'role': 'user', 'content': 'I use the `=` operator.'}, {'role': 'assistant', 'content': 'What are you trying to do in line 5?', 'alt': ['How would you check if  two variables `x` and `y` are equivalent?']}, {'role': 'user', 'content': 'I am trying to check if `rev_string` is equal to `string`', 'alt': ['Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.']}, {'role': 'assistant', 'content': ""You used `=` for variable assignment. Shouldn't there be a different operator for equality?"", 'alt': [""Let's check the documentation. What is the operator for equality?"", 'Are you sure that `=` checks for equality? How can we verify that?', 'If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?']}, {'role': 'user', 'content': ""I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.\n```python\n1. def is_palindrome(string):\n2.  rev_string = ''\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string == string:\n6.    return True\n7.  else:\n8.    return False\n```""}, {'role': 'assistant', 'content': 'Looks good!'}, {'role': 'user', 'content': 'Thank you so much!'}]}"
+"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>","Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```","def reverse_list(lst):
+   return lst[-1:]","On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.",Replace `return lst[-1:]` with `return lst[::-1]` on line 2.,"assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]",12_41_reversing_a_list,"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.\n## Example Cases:\n```\nreverse_list([1, 2, 3]) => [3, 2, 1]\nreverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]\nreverse_list([]) => []\nreverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]\n```\n</problem>\n<bug_code>\n1. def reverse_list(lst):\n2.    return lst[-1:]\n</bug_code>\n<bug_desc>\nOn line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.\n</bug_desc>\n<bug_fixes>\nReplace `return lst[-1:]` with `return lst[::-1]` on line 2.\n</bug_fixes>\n<unit_tests>\nassert reverse_list([1, 2, 3]) == [3, 2, 1]\nassert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]\nassert reverse_list([]) == []\nassert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to reverse the elements of a list but it's not working.""}, {'role': 'assistant', 'content': ""Can you describe how you're trying to reverse the list?"", 'alt': [""Can you describe the problem you're having in more detail?"", ""Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?"", ""Let's start with a warm-up question. What does the slicing operator `[-1:]` do?"", 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?', 'Where can you learn more about how to reverse a list?']}, {'role': 'user', 'content': 'Sure, I used the `[-1:]` slicing operator.'}, {'role': 'assistant', 'content': 'Can you describe what the `[-1:]` slicing operator does?', 'alt': ['How do you think this reverses the list?', ""Do you notice a pattern in your function's outputs?"", 'How does slicing work in Python?', 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?']}, {'role': 'user', 'content': ""I think it should return a list in reverse order but it's returning the last element of the list instead."", 'alt': ['The `[-1:]` slicing operator should return a list in reverse order.']}, {'role': 'assistant', 'content': ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'alt': [""Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?"", 'Good. So where can you learn more about how to reverse a list?', ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?']}, {'role': 'user', 'content': ""I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.\n```python\n def reverse_list(lst):\n    return lst[::-1]\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you run into any other problems!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```","def limitFinder(lst, limit):
+ lst2 = []
+ for i in lst2:
+   if i < limit:
+     lst2.append(i)
+ return lst2","On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.",Replace `lst2` with `lst` on line 3.,"assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []",13_42_limit,"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+","{'system': '<problem>\nWrite a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.\n## Example Cases:\n```\nlimitFinder([1, 2, 3, 4, 5], 3) => [1, 2]\nlimitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]\nlimitFinder([100, 2, 145, 3,8], 0) => []\nlimitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]\nlimitFinder([], 0) => []\n```\n</problem>\n<bug_code>\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst2:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n</bug_code>\n<bug_desc>\nOn line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.\n</bug_desc>\n<bug_fixes>\nReplace `lst2` with `lst` on line 3.\n</bug_fixes>\n<unit_tests>\nassert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]\nassert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]\nassert limitFinder([100, 2, 145, 3,8], 0) == []\nassert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]\nassert limitFinder([], 0) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My program seems to always return an empty list instead of a list of numbers, can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you walk me through what each line does?', 'alt': ['Sure. Can you tell me which list are you supposed to find the numbers from?', 'Sure, can you explain what line 3 does?', 'Sure. It looks like your for-loop is never executed. Do you know why?']}, {'role': 'user', 'content': 'Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.'}, {'role': 'assistant', 'content': 'Ok, what about the next line?'}, {'role': 'user', 'content': 'Line 3 - loops through all the numbers in `lst2`', 'alt': ['It looks like line 3 loops through the wrong list! Is that the issue here?']}, {'role': 'assistant', 'content': 'How many numbers are in `lst2`?', 'alt': ['Will the for loop ever be executed?', 'Is `lst2` empty?', 'How many times will the for loop execute?', 'Is that the list that you want to loop through?']}, {'role': 'user', 'content': '`Oh I see, `lst2` is empty, so the for loop is never executed.'}, {'role': 'assistant', 'content': 'Correct, how would you fix your for loop now?'}, {'role': 'user', 'content': 'Should I be looping over `lst` instead?'}, {'role': 'assistant', 'content': 'Yes, what does the new code look like?'}, {'role': 'user', 'content': 'This code works, thank you!\n```python\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = ""True""
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>","Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```","def isTwice(str, chr):
+ count = 0
+ for i in str:
+   if i == chr:
+     count+=1
+
+ if count >= 2:
+   return true
+ else:
+   return false","On line 8, the function throws a NameError since `true` is not a boolean value.",Replace `true` with `True` and `false` with `False` on lines 8 and 10.,"assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False",14_43_used_twice,"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+","{'system': '<problem>\nWrite a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.\n## Example Cases:\n```\nisTwice(""hello"", ""l"") => True\nisTwice(""hello"", ""o"") => False\nisTwice(""hello"", ""h"") => False\nisTwice("""", ""e"") => False\nisTwice(""I\'m a string!"", "" "") => True\nisTwice(""Hey, I\'m a string!"", "" "") => False\n```\n</problem>\n<bug_code>\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return true\n9.  else:\n10.    return false\n</bug_code>\n<bug_desc>\nOn line 8, the function throws a NameError since `true` is not a boolean value.\n</bug_desc>\n<bug_fixes>\nReplace `true` with `True` and `false` with `False` on lines 8 and 10.\n</bug_fixes>\n<unit_tests>\nassert isTwice(""hello"", ""l"") == True\nassert isTwice(""hello"", ""o"") == False\nassert isTwice(""hello"", ""h"") == False\nassert isTwice("""", ""e"") == False\nassert isTwice(""I\'m a string!"", "" "") == True\nassert isTwice(""Hey, I\'m a string!"", "" "") == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I wrote this code and it isn't working. can you help me?""}, {'role': 'assistant', 'content': ""First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?"", 'alt': ['It seems that you have a `NameError` error in your code. Are you able to find where this error is?', 'Let\'s talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?', ""Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?""]}, {'role': 'user', 'content': ""I have a syntax error. My code won't even compile."", 'alt': [""I think it's a runtime error because it just stopped running."", ""Can you tell me what the different types of errors are? I don't remember."", ""It's a logic error, I think. That's the one that is the result of a grammatical error, right?""]}, {'role': 'assistant', 'content': ""I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?"", 'alt': [""Can you write a code snippet of assigning `False` to a boolean variable called 'var'?"", 'Where is the syntax error located in your code? You look for the line number.', 'How do you know that it is a syntax error? What are the different types of errors?']}, {'role': 'user', 'content': '`var = True`', 'alt': ['`var = true`', 'var = 1', 'var = ""True""']}, {'role': 'assistant', 'content': ""That's right. Is this what you wrote in your code on line 8?"", 'alt': [""That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?"", 'Can you point out in your code where you use boolean variables?']}, {'role': 'user', 'content': ""No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead."", 'alt': [""The code would get a syntax error and it wouldn't run."", ""I'm not sure what you are asking.""]}, {'role': 'assistant', 'content': ""That's right! How can you modify your `isTwice` function now to fix this error?""}, {'role': 'user', 'content': 'Oh! I found it! I was returning all lowercase True and False values! I will fix it.\n```python\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return True\n9.  else:\n10.    return False\n```'}, {'role': 'assistant', 'content': 'Looks like it works now. Good job!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x <= seq[i]:
+     return i",The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.,"Insert a line following line 4, with one indentation containing `return len(seq)`","assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_45_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n</bug_code>\n<bug_desc>\nThe function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.\n</bug_desc>\n<bug_fixes>\nInsert a line following line 4, with one indentation containing `return len(seq)` \n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output.'}, {'role': 'assistant', 'content': 'What inputs have you tried? When do you get `None`?', 'alt': ['Do you notice a pattern with the cases that produce `None`?', 'When do you notice `None` as the output?', 'What inputs have you tried? When do you get `None`?', 'It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?']}, {'role': 'user', 'content': 'I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.', 'alt': ['I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list', 'It seems like I get the wrong answer when `x` is bigger than all the existing list elements']}, {'role': 'assistant', 'content': 'Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?', 'alt': ['Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?', 'What do you expect your code to return when `x` is bigger than the `seq` elements?']}, {'role': 'user', 'content': 'Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.'}, {'role': 'assistant', 'content': 'What happens if `x` is not less than or equal to any element?', 'alt': ['What does your code do if `x` is greater than all of the elements in `seq`?']}, {'role': 'user', 'content': ""I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!\n```python\n def search(x, seq):    \n  for i in range(len(seq)):\n    if x <= seq[i]:\n      return i\n  return len(seq)\n```""}, {'role': 'assistant', 'content': 'Good work. Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x < seq[i]:
+     return i
+ return len(seq)","On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.",Replace `<` with `<=` on line 3,"assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_44_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x < seq[i]:\n4.      return i\n5.  return len(seq)\n</bug_code>\n<bug_desc>\nOn line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.\n</bug_desc>\n<bug_fixes>\nReplace `<` with `<=` on line 3\n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?""}, {'role': 'assistant', 'content': 'Sure. In the first test case, can you explain why the correct returned value should be 1?', 'alt': ['Sure. Can you tell me if you notice any difference between the first test case and the other test cases?', 'Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?', ""Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?""]}, {'role': 'user', 'content': 'The correct answer is 1 because 5 is found at position 1 in the input list.'}, {'role': 'assistant', 'content': 'Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?', 'alt': ['Good. What does your code do when position `i = 1`?']}, {'role': 'user', 'content': 'Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!\n```python\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n5.  return len(seq)\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could help.""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       max_len = max(len(crt_str), max_len)        
+
+       pos = s.find(t, start)
+   
+   last_str = s[start:]
+   max_len = max(len(last_str), max_len)
+
+   return max_len","The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.",On line 8 insert the code `start = pos + len(t)`.,"assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_56_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n</bug_code>\n<bug_desc>\nThe value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.\n</bug_desc>\n<bug_fixes>\nOn line 8 insert the code `start = pos + len(t)`.\n</bug_fixes>\nOn line 11 insert a new line with `ind += len(t)`.\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code does not stop and I do not understand why, can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?"", 'alt': ['Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.', 'Sure. Can you tell me the role of the variable `start`?']}, {'role': 'user', 'content': 'In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.        start = pos + len(t)\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       crt_len = len(crt_str)
+       if crt_len > max_len:
+           max_len = crt_len
+       start = pos + len(t)
+       pos = s.find(t, start)
+   return max_len","The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.","After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```","assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_46_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    return max_len\n</bug_code>\n<bug_desc>\nThe code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.\n</bug_desc>\n<bug_fixes>\nAfter line 11, insert the following outside the while loop scope:\n```py\nlast_str = s[start:]\nlast_len = len(last_str)\nif last_len > max_len:\n       max_len = last_len\n```\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?'}, {'role': 'assistant', 'content': 'I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?', 'alt': ['Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?', 'Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?', 'Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?', ""Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?"", 'Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?', 'Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?']}, {'role': 'user', 'content': '`max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.'}, {'role': 'assistant', 'content': ""Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?"", 'alt': ['Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?', 'Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?', 'Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?']}, {'role': 'user', 'content': 'Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    \n13.    last_str = s[start:]\n14.    last_len = len(last_str)\n15.    if last_len > max_len:\n16.       max_len = last_len\n17.    \n18.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>","Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```","def top_k(lst, k):
+   result = []
+   for i in range(k):
+       result.append(max(lst))
+       lst.pop(max(lst))
+   return result","The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.","On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`","assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]",17_47_topk,"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.\n## Example Cases:\n```\ntop_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]\ntop_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]\ntop_k([], 0) => []\ntop_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]\ntop_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]\n```\n</problem>\n<bug_code>\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.pop(max(lst))\n6.    return result\n</bug_code>\n<bug_desc>\nThe function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.\n</bug_desc>\n<bug_fixes>\nOn line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`\n</bug_fixes>\n<unit_tests>\nassert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]\nassert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]\nassert top_k([], 0) == []\nassert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]\nassert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi. I am confused. My code doesn’t seem to work. Can you help?'}, {'role': 'assistant', 'content': ""Hello. Sure, let's see. Do you know what might be the issue?""}, {'role': 'user', 'content': 'I think the problem is with the `.pop()` method. It seems to have issues with indexing.', 'alt': ['When I use the `.pop()` method, I get an IndexError on some inputs.', ""For some inputs, I get an error and other inputs don't produce the right answer.""]}, {'role': 'assistant', 'content': ""Ok, no worries. Let's review your code line by line. Could you please explain it to me?"", 'alt': [""Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?"", ""Let's start with a warm-up question. What does the `.pop()` method do?"", ""Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?"", 'Could you please explain what line 5 in your code does?', 'Let’s look into the Python documentation. Can you describe what the `.pop()` method does?']}, {'role': 'user', 'content': 'Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.'}, {'role': 'assistant', 'content': 'Good. What can you do right now to debug your code and diagnose what might be causing the problem?'}, {'role': 'user', 'content': 'Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(max(lst))\n6.        lst.pop(max(lst))\n7.        print(lst)\n8.    return result\n```', 'alt': ['I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.']}, {'role': 'assistant', 'content': 'Are there other ways of debugging the `.pop()` method?', 'alt': ['What happens if you use a different input value for the `top_k()` function?', 'Have you considered using the debugger?', 'What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?']}, {'role': 'user', 'content': 'Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(lst)\n6.        lst.pop(1)\n7.        print(lst)\n8.    return result \n```'}, {'role': 'assistant', 'content': 'Perhaps there are other solutions you can use aside from `.pop()`?', 'alt': ['Where can we learn more about other list methods that can help us remove elements from an array?', 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?']}, {'role': 'user', 'content': ""I think but I can't remember them...""}, {'role': 'assistant', 'content': 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?'}, {'role': 'user', 'content': 'Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.remove(max(lst))\n6.    return result\n```'}, {'role': 'assistant', 'content': 'Great! Please let me know if you need help with anything else.'}]}"
+"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `""a""`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don't think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return ""Password added!""
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>","Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```","def validate_or_add_password(menu_choice, password, passwords_dict):
+   if menu_choice == ""v"":
+       if password in passwords_dict.values():
+           return ""Welcome!""
+       else:
+           return ""I don't know you.""
+   elif menu_choice == ""a"":
+       if password in passwords_dict.values():
+           return ""Password already exists!""
+       else:
+           return ""Password added!""",The function does not add `password` to `passwords_dict` as specified in the instructions.,After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`,"passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""",18_48_password_validator,"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+","{'system': '<problem>\nCreate a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:\n* `menu_choice (str)`: either \'v\' for validate or \'a\' for add password\n* `password (str)`: the password to be validated or added\n* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords\n\nThe function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is \'v\'. If the password is not found in the dictionary, the function returns ""I don\'t know you."". If menu_choice is \'a\', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".\n## Example Cases:\n```\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nvalidate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""\nvalidate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don\'t know you.""\nvalidate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""\npasswords_dict[4] => ""newpass""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""\n```\n</problem>\n<bug_code>\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            return ""Password added!""\n</bug_code>\n<bug_desc>\nThe function does not add `password` to `passwords_dict` as specified in the instructions.\n</bug_desc>\n<bug_fixes>\nAfter line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`\n</bug_fixes>\n<unit_tests>\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nassert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""\nassert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don\'t know you.""\nassert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""\nassert passwords_dict[4] == ""newpass""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello. I need help with my code.', 'alt': [""I need help with this code. It's throwing a `KeyError`. I'm not sure why.""]}, {'role': 'assistant', 'content': 'Can you describe the issue you are experiencing?', 'alt': ['Can you walk me through what your code does line by line when `menu_choice` is `""a""`?', 'Let\'s go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?']}, {'role': 'user', 'content': 'I am getting a `KeyError: 4`. Not really sure why.', 'alt': [""My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.""]}, {'role': 'assistant', 'content': ""Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?"", 'alt': ['What does `KeyError` typically mean and why does it occur?', ""Let's look at the example cases, where do you see `4` being used as a key?"", ""Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?"", ""Let's look at your error again. What line is throwing the `KeyError`?"", 'Which parameter in the `validate_or_add_password` function is a data structure that uses keys?']}, {'role': 'user', 'content': 'After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.'}, {'role': 'assistant', 'content': ""Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?"", 'alt': ['Good. Which test case do you think is causing the `KeyError`?', ""Let's look at your error again. What line is throwing the `KeyError`?""]}, {'role': 'user', 'content': 'Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.', 'alt': ['Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.']}, {'role': 'assistant', 'content': 'Good. What is the statement right before line 18 attempting to do?'}, {'role': 'user', 'content': 'Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don\'t think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.\n```python\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            passwords_dict[len(passwords_dict) + 1] = password\n12.            return ""Password added!""\n```'}, {'role': 'assistant', 'content': 'Good. Does your code pass all the example cases?'}, {'role': 'user', 'content': 'Yes it does thank you for your help. I learned more about `KeyError`s today.'}, {'role': 'assistant', 'content': ""You're welcome to let me know if I can be of any further assistance.""}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for i in range(1, len(sentence)):
+       if sentence[i] == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   if not space_mode:
+       words +=1
+   return words","On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.","On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_49_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for i in range(1, len(sentence)):\n5.        if sentence[i] == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    if not space_mode:\n12.        words +=1\n13.    return words\n</bug_code>\n<bug_desc>\nOn line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `(1, len(sentence))` with `(len(sentence)):`\nOn line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am having a problem with this programming problem. My count seems off.'}, {'role': 'assistant', 'content': 'Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?', 'alt': ['Are there specific inputs that give you the wrong answer or is it always wrong?', 'Off in what way?']}, {'role': 'user', 'content': 'Yes! My output seems to be 1 less than it should be.', 'alt': ['My output is sometimes correct and sometimes lower than it should be']}, {'role': 'assistant', 'content': 'Does this happen with all inputs or just some inputs?'}, {'role': 'user', 'content': 'I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.']}, {'role': 'assistant', 'content': 'Can you check how your function handles the beginning of the input? It seems like the issue might be there.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'Where do you count your first word?']}, {'role': 'user', 'content': ""Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for i in range(len(sentence)):\n        if sentence[i] == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great!'}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for c in sentence:
+       if c == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   return words",There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.,"Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_50_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for c in sentence:\n5.        if c == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    return words\n</bug_code>\n<bug_desc>\nThere is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.\n</bug_desc>\n<bug_fixes>\nInsert the following after line 10 outside the scope of the for loop:\n```py\nif not space_mode:\n     words +=1\n```\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm writing some code to count words and it doesn't seem to be working""}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': [""Let's walk through your code line by line. Can you explain what your code does?"", 'When you run your code, what do you observe?']}, {'role': 'user', 'content': 'My output counts are off by one.'}, {'role': 'assistant', 'content': 'Hm, ok. Can you walk me through your code?', 'alt': ['Does this happen with all inputs?', 'Can you give me an example input where this happens? Include what you expect and what you get.']}, {'role': 'user', 'content': 'Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.'}, {'role': 'assistant', 'content': 'Ok. What happens when you reach the end of the sentence?', 'alt': ['Does your loop count the last word in the sentence?']}, {'role': 'user', 'content': ""Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for c in sentence:\n        if c == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thank you so much for your help!'}]}"
+"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>","Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```","def split (cookies, people):
+ if cookies % people == 0:
+   return (cookies // people, 0, ""Cookies can be split evenly!"")
+ else:
+   newCookies = cookies - (cookies % people)
+   return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")","On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.","Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.","assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")",2_18_splitting_cookies,"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.\n\n## Example Cases:\n```\nsplit(10, 2) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nsplit(20, 4) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 5) => (2, 0, ""Cookies can be split evenly!"")\nsplit(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n```\n</problem>\n<bug_code>\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    newCookies = cookies - (cookies % people)\n6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n</bug_code>\n<bug_desc>\nOn line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.\n</bug_desc>\n<bug_fixes>\nReplace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.\nReplace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.\nRemove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.\n</bug_fixes>\n<unit_tests>\nassert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nassert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")\nassert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello I need help with my code, it is not giving me the output I expect.'}, {'role': 'assistant', 'content': ""Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?"", 'alt': [""Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?"", 'Sure, have you tried the test cases as inputs? What have you observed about the output?', ""Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?"", ""Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?"", ""Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?""]}, {'role': 'user', 'content': 'For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, \'Cookies cannot be split evenly. Bought more cookies.\')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.', 'alt': ['My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.', 'I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.', 'I need `cookies` to be a multiple of the `people` to get the right answer.']}, {'role': 'assistant', 'content': ""Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?"", 'alt': ['Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?', 'How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?']}, {'role': 'user', 'content': 'So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well\n```python\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    leftOverCookies = cookies % people\n6.    newCookies = people - leftOverCookies + cookies\n7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n```', 'alt': ['Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now']}, {'role': 'assistant', 'content': 'Sounds good! Let me know if you need any more help.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>","Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```","def spellchecker(words, words_to_check):
+   result = []
+   for word in words_to_check:
+       if word in words:
+           result.append(word + "" is spelled properly!"")
+       else:
+           result.append(word + "" is misspelled!"")",The function returns `None` instead of an iterable of strings.,"After line 7, insert `return result` with one indentation level.","assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']",20_51_spell_checker,"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+","{'system': '<problem>\nWrite a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.\n## Example Cases:\n```\nlist(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nlist(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nlist(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) => [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nlist(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) => [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n```\n</problem>\n<bug_code>\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n</bug_code>\n<bug_desc>\nThe function returns `None` instead of an iterable of strings.\n</bug_desc>\n<bug_fixes>\nAfter line 7, insert `return result` with one indentation level.\n</bug_fixes>\n<unit_tests>\nassert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nassert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nassert list(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) == [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nassert list(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) == [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of the test cases passing?', 'Have you completed all the steps in the instructions?', ""Let's look at your function, can you explain what it is supposed to do?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Can you explain what your function is supposed to do?', 'alt': ['Do any of the test cases pass?', 'Have you skipped any steps in the instructions?']}, {'role': 'user', 'content': 'My function takes in one list of words and compares it to another list.', 'alt': ['My function compares two lists of words and then returns information about them.', 'I followed the prompt.']}, {'role': 'assistant', 'content': 'Okay, on what line of code does it take in those lists of words?', 'alt': ['Does it do anything else?', 'Is that everything it is supposed to do according to the prompt?', ""Let's look at the first line of the function on line 1, does it take in two lists of words?""]}, {'role': 'user', 'content': 'On line 1.'}, {'role': 'assistant', 'content': 'Does that line take in those lists?', 'alt': ['Do you see any problems on that line?', 'What should your function do after taking in those lines?']}, {'role': 'user', 'content': 'Yes, it does.'}, {'role': 'assistant', 'content': 'Okay, so what is the next thing your function is supposed to do?', 'alt': [""Let's check the loops where we compare the lists, what line do those start on?"", 'How does your function compare the lists?']}, {'role': 'user', 'content': ""It's supposed to compare the two lists and say if the word is spelled wrong.""}, {'role': 'assistant', 'content': 'Where is it supposed to put the information about the spelling?', 'alt': ['How does it determine if the word is spelled wrong?', ""Let's examine the loop, what line does it start on?""]}, {'role': 'user', 'content': 'In a list called result.'}, {'role': 'assistant', 'content': ""Let's examine that list, where is it created?"", 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?""]}, {'role': 'user', 'content': 'On line 2.'}, {'role': 'assistant', 'content': 'What happens to that list next?', 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?"", 'Do we do anything with that list after we finish adding to it?']}, {'role': 'user', 'content': 'We add strings to it for if the word is spelled right.'}, {'role': 'assistant', 'content': ""Do we do anything else to it after we've finished with the loop?"", 'alt': ['How would that information be sent out of the function?', 'What information is supposed to be returned from the function?']}, {'role': 'user', 'content': ""No, we don't."", 'alt': ['I forgot to return result!']}, {'role': 'assistant', 'content': 'How can that information be used outside of this function?', 'alt': ['What information is supposed to be returned from the function?']}, {'role': 'user', 'content': 'I need to return result.\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.        return result\n```'}, {'role': 'assistant', 'content': 'Does it work now?'}, {'role': 'user', 'content': ""No, it doesn't.""}, {'role': 'assistant', 'content': 'Is it passing any of the test cases?', 'alt': ['Look at what you added, why did you put it there?', 'Look at what you added, when should this happen?']}, {'role': 'user', 'content': 'No, but the message changed to Assertion error.'}, {'role': 'assistant', 'content': ""Okay, let's look back at what you added. When should that code run?"", 'alt': [""Let's look at what you added. Should it be inside or outside the for-loop?""]}, {'role': 'user', 'content': 'Oh! I put it inside the loop!\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.    return result\n```'}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It's not freezing!"" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the ""<"" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the ""less than"" operator. It compares `c` to 0.
+	<alt>That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the ""<="" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns ""It's not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".
+	<alt>Oh... I see the problem now. I don't want to return ""It's not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".
+Assistant: Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the ""<="" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</code>
+Assistant: Good work!
+</dialogue>","Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```","def fToC(temp):
+ c = (temp - 32) * (5/9)
+ if c < 0:
+   return ""Freezing!""
+ else:
+   return ""It's not freezing!""","If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""","On line 3, change `<` to `<=`.","assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""",21_52_fahrenheit_to_celsius_converter,"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It\'s not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \\frac{5}{9}$. Note that the function should return a string, not a float.\n## Example Cases:\n```\nfToC(32.0) => ""Freezing!""\nfToC(0.5) => ""Freezing!""\nfToC(45.0) => ""It\'s not freezing!""\nfToC(-5.4) == ""Freezing!""\n```\n</problem>\n<bug_code>\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c < 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n</bug_code>\n<bug_desc>\nIf `temp` is equal to 32, the function returns ""It\'s not freezing!"" rather than ""Freezing!""\n</bug_desc>\n<bug_fixes>\nOn line 3, change `<` to `<=`.\n</bug_fixes>\n<unit_tests>\nassert fToC(32.0) == ""Freezing!""\nassert fToC(0.5) == ""Freezing!""\nassert fToC(45.0) == ""It\'s not freezing!""\nassert fToC(-5.4) == ""Freezing!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'There is an issue with my code.'}, {'role': 'assistant', 'content': 'Can you describe the issue to me?', 'alt': [""Let's assume that `temp` is 32. Can you explain your code to me line by line?""]}, {'role': 'user', 'content': 'My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It\'s not freezing!"" Why is that happening?'}, {'role': 'assistant', 'content': 'Let\'s take a look at the if-statement block. Do you remember what the ""<"" operator does?', 'alt': [""Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?""]}, {'role': 'user', 'content': 'That is the ""less than"" operator. It compares `c` to 0.', 'alt': ['That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.']}, {'role': 'assistant', 'content': 'Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?', 'alt': ['Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?', 'Can you explain what the ""<="" operator does?']}, {'role': 'user', 'content': 'When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.'}, {'role': 'assistant', 'content': 'Good. Could you explain what happens when `c` is equal to 0 on line 3?', 'alt': ['Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'Good. Now on line 3, what should your function return if `c` is equal to 0?']}, {'role': 'user', 'content': 'The function returns ""It\'s not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".', 'alt': ['Oh... I see the problem now. I don\'t want to return ""It\'s not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".']}, {'role': 'assistant', 'content': 'Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'alt': [""Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.""]}, {'role': 'user', 'content': 'I should use the ""<="" operator! Let me try that.\n```python\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c <= 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n```'}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {""discount"": discount, ""price"": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>","Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```","def cookiePurchase(cookies):
+   price = cookies * 1.75
+   discount = 0
+   if cookies > 10 and cookies / 10 == 0:
+       discount = price * 0.1
+       price = price - discount
+   return {""discount"": discount, ""price"": price}","On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.","On line 4, replace `/` with `%` and on line 4.","assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}",22_53_cookie_purchase,"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+","{'system': '<problem>\nWrite a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.\n## Example Cases:\n```\ncookiePurchase(2) => {\'discount\': 0.0, \'price\': 3.5}\ncookiePurchase(70) => {\'discount\': 12.25, \'price\': 110.25}\ncookiePurchase(22) => {\'discount\': 0.0, \'price\': 38.5}\ncookiePurchase(10) => {\'discount\': 0.0, \'price\': 17.5}\ncookiePurchase(20) => {\'discount\': 3.5, \'price\': 31.5}\n```\n</problem>\n<bug_code>\n1. def cookiePurchase(cookies):\n2.    price = cookies * 1.75\n3.    discount = 0\n4.    if cookies > 10 and cookies / 10 == 0:\n5.        discount = price * 0.1\n6.        price = price - discount\n7.    return {""discount"": discount, ""price"": price}\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `/` with `%` and on line 4.\n</bug_fixes>\n<unit_tests>\nassert cookiePurchase(2) == {\'discount\': 0, \'price\': 3.5}\nassert cookiePurchase(70) == {\'discount\': 12.25, \'price\': 110.25}\nassert cookiePurchase(22) == {\'discount\': 0, \'price\': 38.5}\nassert cookiePurchase(10) == {\'discount\': 0, \'price\': 17.5}\nassert cookiePurchase(20) == {\'discount\': 3.5, \'price\': 31.5}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm having a problem with my code"", 'alt': ['Hi! My code seems to sometimes give answers that are very off.']}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': ['Can you walk me through your function line by line?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you check if a number is divisible by 10?""]}, {'role': 'user', 'content': ""My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.""}, {'role': 'assistant', 'content': ""Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?"", 'alt': [""Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?"", ""Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?"", ""Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?""]}, {'role': 'user', 'content': ""First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.""}, {'role': 'assistant', 'content': 'Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?', 'alt': ['What operator should you use to check whether a number is a multiple of 10?', 'Where can you learn more about Python operators?\t']}, {'role': 'user', 'content': 'Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...'}, {'role': 'assistant', 'content': ""Let's take a look at the Python documentation to see if there is a different operator that does what you want."", 'alt': ['Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Oh, interesting. The modulus operator seems to fit. I\'ll modify my code and see if it works. It looks like it does!\n```python\n def cookiePurchase(cookies):\n    price = cookies * 1.75\n    discount = 0\n    if cookies > 10 and cookies % 10 == 0:\n        discount = price * 0.1\n        price = price - discount\n    return {""discount"": discount, ""price"": price}\n```'}, {'role': 'assistant', 'content': 'Great! Glad to help.'}, {'role': 'user', 'content': 'Thank you very much!'}]}"
+"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```","def factorial(n):
+       if n < 0:
+               return 0
+       fact = 1
+       for i in range(n):
+               fact = fact * i
+       return fact","On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n","Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.","assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120",24_29_factorial,"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+","{'system': '<problem>\nWrite a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:\n\n$0! = 1$\n$n! = n \\times (n - 1)!$\n\nAdditionally, if the input integer n is negative the function should return 0.\n\n## Example Cases:\n```\nfactorial(-1) => 0\nfactorial(0) => 1\nfactorial(1) => 1\nfactorial(2) => 2\nfactorial(3) => 6\nfactorial(4) => 24\nfactorial(5) => 120\n```\n</problem>\n<bug_code>\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * i\n7.        return fact\n</bug_code>\n<bug_desc>\nOn line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n\n\n</bug_desc>\n<bug_fixes>\nReplace `i` with `(i + 1)` in line 6.\nReplace `range(n)` with `range(1, n + 1)` in line 5.\n</bug_fixes>\n<unit_tests>\nassert factorial(-1) == 0\nassert factorial(0) == 1\nassert factorial(1) == 1\nassert factorial(2) == 2\nassert factorial(3) == 6\nassert factorial(4) == 24\nassert factorial(5) == 120\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?'}, {'role': 'user', 'content': 'For `n = 1` or larger it returns the same value, 0.'}, {'role': 'assistant', 'content': 'Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?', 'alt': ['Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?', 'Can you tell me what `range(n)` does?']}, {'role': 'user', 'content': 'The first value assigned to `i` will be 1.', 'alt': ['Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.']}, {'role': 'assistant', 'content': 'Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?', 'alt': ['Can you explain why `i` will be equal to 1 during the first iteration of the for loop?', 'Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?']}, {'role': 'user', 'content': 'I don’t know, how can I verify that?', 'alt': ['OK, let me print its value at each iteration.', 'OK, let me check in the Python documentation what range does.']}, {'role': 'assistant', 'content': 'Can you edit the code to print the value of `i` at each iteration of the for loop?', 'alt': ['Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?', 'Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?', 'Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?', 'Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?']}, {'role': 'user', 'content': 'Sure … Aaah, I see, the first value is 0, not 1!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i\n8.        return fact\n```', 'alt': ['How do I do that?']}, {'role': 'assistant', 'content': 'How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?', 'alt': ['Why do you think the first value is 0?', 'Good! Can you explain how that makes the function return 0 for n = 1 or larger?', 'Good! What can you do now to fix the issue?']}, {'role': 'user', 'content': 'I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i + 1\n8.        return fact\n```', 'alt': ['I can change it to `range(1, n + 1)` so that it starts iterating at 1.', 'I can change it to `range(1, n)` so that it starts iterating at 1.', 'I can change it to `range(n) + 1`, so that the first value is 0 + 1.', 'I don’t know, can you help?']}, {'role': 'assistant', 'content': 'Can you also try it with `n = 2` and `n = 3`?', 'alt': ['Do you think your code will work for all values of `n`, for example `n = 3`?']}, {'role': 'user', 'content': 'Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.'}, {'role': 'assistant', 'content': 'The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?', 'alt': ['Why is the code giving an incorrect answer for n = 3?', 'What should the output of factorial(3) be?']}, {'role': 'user', 'content': 'Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * (i + 1)\n8.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.'}, {'role': 'user', 'content': 'Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * (i + 1)\n7.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return ""Previous node is not in linked list""
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>","Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```","class Node:
+   def __init__(self, data=None, next=None):
+       self.data = data
+       self.next = next
+
+def insert_after(head, prev_data, new_data):
+   curr_head = head
+   while curr_head is not None:
+       if curr_head.data == prev_data:
+           new_node = Node(data=new_data)
+           curr_head.next = new_node
+           return
+       else:
+           curr_head = curr_head.next
+   
+   return ""Previous node is not in linked list""","The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.","After line 10, insert a line `new_node.next = curr_head.next`","head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""",25_55_insert_to_linked_list,"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.\nYou are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.\nclass Node:\n    def __init__(self, data=None, next=None):\n        self.data = data\n        self.next = next\n```\n## Example Cases:\n```py\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\ninsert_after(head, 2, 5) => None\nhead.data == 1\nhead.next.data == 2\nhead.next.next.data == 5\nhead.next.next.next.data == 3\nhead.next.next.next.next.data == 4\ninsert_after(head, 8, 6) => ""Previous node is not in linked list""\n```\n</problem>\n<bug_code>\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6. def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            curr_head.next = new_node\n12.            return\n13.        else:\n14.            curr_head = curr_head.next\n15.    \n16.    return ""Previous node is not in linked list""\n</bug_code>\n<bug_desc>\nThe function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.\n</bug_desc>\n<bug_fixes>\nAfter line 10, insert a line `new_node.next = curr_head.next`\n</bug_fixes>\n<unit_tests>\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\nassert insert_after(head, 2, 5) == None\nassert head.data == 1\nassert head.next.data == 2\nassert head.next.next.data == 5\nassert head.next.next.next.data == 3\nassert head.next.next.next.next.data == 4\nassert insert_after(head, 8, 6) == ""Previous node is not in linked list""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?', 'alt': ['Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?']}, {'role': 'assistant', 'content': 'Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.'}, {'role': 'user', 'content': 'The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).'}, {'role': 'assistant', 'content': ""Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?"", 'alt': [""Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?"", 'Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?', ""Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?""]}, {'role': 'user', 'content': 'If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.'}, {'role': 'assistant', 'content': ""That's right! Could you now tell me what happens when we complete the test case checks?"", 'alt': [""That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?""]}, {'role': 'user', 'content': 'Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.\n```python\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6.def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            new_node.next = curr_head.next\n12.            curr_head.next = new_node\n13.            return\n14.       else:\n15.           curr_head = curr_head.next\n16.    \n17.   return ""Previous node is not in linked list""\n```', 'alt': [""Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order."", 'It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.']}, {'role': 'assistant', 'content': 'Great! Let me know if you need more help.'}]}"
+"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>","Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```","def sequenceBetween(start, end):
+   l = []
+   if(start >= end):
+       i = start 
+       while i > end:
+           l.append(i)
+           i -= 1
+   else:
+       i = start
+       while i < end:
+           l.append(i)
+           i += 1
+   
+   return l","On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.",Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.,"assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]",3_20_counting_down,"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.\n\n## Example Cases:\n```\nsequenceBetween(0, 3) => [0, 1, 2, 3]\nsequenceBetween(1, 1) => [1]\nsequenceBetween(7, 5) => [7, 6, 5]\nsequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]\nsequenceBetween(12, 10) => [12, 11, 10]\nsequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]\n```\n</problem>\n<bug_code>\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i < end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n</bug_code>\n<bug_desc>\nOn lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.\n</bug_desc>\n<bug_fixes>\nReplace `>` with `>=` on line 5 and `<` with `<=` on line 10.\n</bug_fixes>\n<unit_tests>\nassert sequenceBetween(0, 3) == [0, 1, 2, 3]\nassert sequenceBetween(1, 1) == [1]\nassert sequenceBetween(7, 5) == [7, 6, 5]\nassert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]\nassert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi I need to fix my code, I am not getting the expected output.'}, {'role': 'assistant', 'content': ""Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?"", 'alt': [""Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?"", ""Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?"", ""Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?"", 'Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?']}, {'role': 'user', 'content': 'When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```', 'alt': ['I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.']}, {'role': 'assistant', 'content': ""For completeness, let's test another test case. What happens when you run `(1, 1)` as input?"", 'alt': [""Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?"", 'Could you also try the next test case, `(1, 1)`, and observe the output?']}, {'role': 'user', 'content': ""I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i >= end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```"", 'alt': ['It looks like I also need to fix the `if` portion of the code which has a similar issue as before.']}, {'role': 'assistant', 'content': ""Sounds good, let's check all the test cases and check how it goes!""}, {'role': 'user', 'content': 'Everything is running as expected now, thanks!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i % 2 =! 0:
+     newNums.append(i)
+ return newNums","There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.",Replace `=!` with `!=` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_22_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 =! 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `=!` with `!=` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I keep getting an error with my code,  but I'm not sure how to fix it""}, {'role': 'assistant', 'content': 'Where is the syntax error happening and what is it?', 'alt': ['Do you see any red squiggly lines in your code? If so, what is it highlighting?', 'Do you see a line number next to the error? If so, what is it?']}, {'role': 'user', 'content': 'Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""'}, {'role': 'assistant', 'content': 'Do you see a squiggly line in your code? If so, what is it highlighting?', 'alt': ['It might be an issue with your operator. Could you list all the comparison operators you know?', 'How do you check if two numbers are unequal?', 'Is the error message highlighting a specific portion of the line like an operator or a parenthesis?']}, {'role': 'user', 'content': 'Yes, it is highlighting the =! operator.'}, {'role': 'assistant', 'content': 'Then, what do you think the problem is?', 'alt': [""Are you sure that's the correct operator to check whether two numbers are unequal?""]}, {'role': 'user', 'content': ""I'm not sure. I am trying to check if `i` is not divisible by 2.""}, {'role': 'assistant', 'content': 'Are you sure that `=!` is the correct operator to check if two numbers are not equal?', 'alt': ['Is there a difference between `=!` and `!=`?']}, {'role': 'user', 'content': 'Ah! I see. I should be using `!=` instead of `=!`.\n```python\n def returnOdd(nums):\n  newNums = []\n  for i in nums:\n    if i % 2 != 0:\n      newNums.append(i)\n  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Now try running your code again.'}, {'role': 'user', 'content': 'It works! Thanks for your help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums
+   if i % 2 != 0:
+     newNums.append(i)
+ return newNums",There is a syntax error on line 3. The for loop syntax is incorrect.,Add `:` after `nums` on line 3.,"assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []",4_28_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]\nreturnOdd([2,4,6,8,10]) => []\nreturnOdd([1,3,5,7,9]) => [1,3,5,7,9]\nreturnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 3. The for loop syntax is incorrect.\n</bug_desc>\n<bug_fixes>\nAdd `:` after `nums` on line 3.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]\nassert returnOdd([2,4,6,8,10]) == []\nassert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]\nassert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, I am not sure why my program for removing even numbers is not running. Can you please help?', 'alt': ['Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?']}, {'role': 'assistant', 'content': 'Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?', 'alt': ['Hi, Sure! Do you know why it is throwing a syntax error on line 3?']}, {'role': 'user', 'content': 'I am not sure what that error means', 'alt': ['Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?']}, {'role': 'assistant', 'content': 'It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?'}, {'role': 'user', 'content': 'Yes, it looks like the caret is pointing towards the end of line 3.'}, {'role': 'assistant', 'content': 'Correct, what do you think is wrong with the end of the line 3?', 'alt': ['Correct, what do you think is missing towards the end of line 3?']}, {'role': 'user', 'content': 'I am not sure, is it a punctuation mark?', 'alt': ['Is it missing a colon?']}, {'role': 'assistant', 'content': 'Yes, can you find the correct syntax using the documentation?', 'alt': ['Yes, where can you find the correct syntax of a for loop?']}, {'role': 'user', 'content': 'What is the documentation?', 'alt': ['Yes, is it supposed to have a colon at the end?']}, {'role': 'assistant', 'content': 'Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org'}, {'role': 'user', 'content': 'After going through the python documentation, I think this is what my code is supposed to look like this.\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Correct, you can always come back to the documentation if you ever run into a syntax error.'}, {'role': 'user', 'content': 'My program works now, thank you for helping me resolve that error!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error ""SyntaxError: 'return' outside function"" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+return newNums",There is a syntax error on line 6. The return statement is not within a function scope.,Insert a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_25_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6. return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 6. The return statement is not within a function scope.\n</bug_desc>\n<bug_fixes>\nInsert a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?', 'alt': ['Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?']}, {'role': 'assistant', 'content': 'Sure, let\'s look at the error together. Do you know what the error ""SyntaxError: \'return\' outside function"" means?', 'alt': [""I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?"", 'Let\'s warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?']}, {'role': 'user', 'content': 'Does it mean that my return statement is not currently a part of my function?', 'alt': ['The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.']}, {'role': 'assistant', 'content': ""That's right, taking a look at your code, do you think your return statement is a part of your function?"", 'alt': ['Could you tell me what we might need to do to make sure that the function returns the value we need it to?', 'What might you need to do to make sure the return statement is in the scope of your function?']}, {'role': 'user', 'content': 'I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```', 'alt': ['I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.']}, {'role': 'assistant', 'content': 'Looks good! Let me know if you need more help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+       return newNums","On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.",Remove a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_26_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.        return newNums\n</bug_code>\n<bug_desc>\nOn line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.\n</bug_desc>\n<bug_fixes>\nRemove a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck.""}, {'role': 'assistant', 'content': 'What should your code be doing?', 'alt': ['Which test cases (if any) are failing?', 'What are you stuck on?', 'Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?']}, {'role': 'user', 'content': ""Right now, it's only returning the first number in the list, not all of them."", 'alt': [""It's only passing the second test case.""]}, {'role': 'assistant', 'content': ""Okay, let's look at your loop. Do you see anything that could be causing it to end early?"", 'alt': ['Have you checked the loop and how many times it iterates?', ""Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?"", 'What do you think might cause your function to return a list with one element instead of multiple elements?', ""Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?"", 'What do you think is causing the lists not to include all the numbers?', 'Look at line 3, is it iterating through the whole list?']}, {'role': 'user', 'content': ""No I do not. I'm iterating through the whole list of numbers."", 'alt': [""I don't know, how could I find out?"", 'Oh, I see, the return statement is in the wrong place.']}, {'role': 'assistant', 'content': ""Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?"", 'alt': ['What can cause a function to end early?', 'What forces a loop to end?']}, {'role': 'user', 'content': 'Line 3 starts the loop, and it iterates through everything in `nums`.'}, {'role': 'assistant', 'content': 'Good, then what happens?', 'alt': ['Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?', 'Think back to what you know about functions. What makes them end early?', 'Think back to what you know about loops, what can make them stop?']}, {'role': 'user', 'content': 'The if statement starts on line 4, it checks if the number is even.'}, {'role': 'assistant', 'content': 'Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?', 'alt': ['Do you notice anything on line 4 that causes the function to end early?', 'Do you notice anything on line 4 that causes the for loop to end?']}, {'role': 'user', 'content': ""I don't see anything that can cause that problem."", 'alt': ['I see! The return statement after the if-statement is indented too much!']}, {'role': 'assistant', 'content': 'Okay, so what happens next on line 6?'}, {'role': 'user', 'content': 'It returns the list.', 'alt': [""I get it! It's returning after every iteration!"", ""It's returning too soon.""]}, {'role': 'assistant', 'content': 'When should it return the list?', 'alt': ['Would a return statement end a loop?', 'Would a return statement cause the function to terminate early?', 'Is there anything on this line that would cause the loop or the function to end early?', 'When does your return statement execute?']}, {'role': 'user', 'content': 'It should return the list when it finishes all the numbers.'}, {'role': 'assistant', 'content': 'Look at line 6, what level of indentation is the list on?', 'alt': ['Think back to what you have learned about indentation, how does that control the order of actions in a loop?', 'Can the return statement end the loop early?']}, {'role': 'user', 'content': ""I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```""}, {'role': 'assistant', 'content': 'What does it return now, after you changed the indentation of the return statement?'}, {'role': 'user', 'content': 'It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.'}, {'role': 'assistant', 'content': ""You're welcome. Let me know if I can be of any further assistance.""}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i / 2 != 0:
+     newNums.append(i)
+ return newNums","On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.",Replace `/` with `%` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_23_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i / 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.\n</bug_desc>\n<bug_fixes>\nReplace `/` with `%` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I have a problem with my code. It's just not working, and I just don't know why.""}, {'role': 'assistant', 'content': 'Can you explain what the issue appears to be?', 'alt': ['Can you walk me through your function line by line?', 'Does your code throw an error or do you just get the wrong answer?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you know if a number is even or odd?""]}, {'role': 'user', 'content': ""The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed."", 'alt': [""It doesn't seem like my function modifies anything on most input lists."", ""I can't figure out why my function doesn't remove most of the even numbers in the lists I input.""]}, {'role': 'assistant', 'content': 'Can you explain your function to me line by line?', 'alt': ['Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?""]}, {'role': 'user', 'content': 'OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.'}, {'role': 'assistant', 'content': ""Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?"", 'alt': ['Can you explain what line 4 of your code does?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?"", 'When does dividing by 2 give you 0?', 'How do you check if a number is even in your code?']}, {'role': 'user', 'content': ""Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?""}, {'role': 'assistant', 'content': ""Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?"", 'alt': [""Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?"", 'Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Hm ok, let me try modulus. It works!\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Happy to help!'}, {'role': 'user', 'content': 'Thank you so much for your help! I learned more about how to check for divisibility in Python.'}]}"
+"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>","Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```","def get_words(s):
+   words = [word.lower() for word in s.split("" "")]
+   return sorted(words)","The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.","Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.","assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']",5_30_sorted_words,"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+","{'system': '<problem>\nWrite a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `[\'hello\', \'world\']`.\n\n## Example Cases:\n```\nget_words(""Hello World"") => [\'hello\', \'world\']\nget_words(""Hello World hello"") => [\'hello\', \'world\']\nget_words(""Hello World hello world"") => [\'hello\', \'world\']\nget_words(""Hello World H e l l o W o r l d"") => [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nget_words(""Hello World el WORld"") => [\'el\', \'hello\', \'world\']\nget_words(""A C B c b a"") => [\'a\', \'b\', \'c\']\n```\n</problem>\n<bug_code>\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(words)\n</bug_code>\n<bug_desc>\nThe function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.\n</bug_desc>\n<bug_fixes>\nReplace `sorted(words)` with `sorted(set(words))` on line 3.\nInsert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.\n</bug_fixes>\n<unit_tests>\nassert get_words(""Hello World"") == [""hello"", ""world""]\nassert get_words(""Hello World hello"") == [""hello"", ""world""]\nassert get_words(""Hello World hello world"") == [""hello"", ""world""]\nassert get_words(""Hello World H e l l o W o r l d"") == [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nassert get_words(""Hello World el WORld"") == [\'el\', \'hello\', \'world\']\nassert get_words(\'A C B c b a\') == [\'a\', \'b\', \'c\']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on this function and it doesn't seem to be correct."", 'alt': ['I\'m trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.']}, {'role': 'assistant', 'content': 'Does your code work for all the examples in the problem description or does it fail on some of them?', 'alt': ['Hello! Can you explain to me what the code on line 2 does?', ""Let's review the problem description together. What are the requirements for the returned list?"", 'Can you walk me through your `get_words` function?', 'Let\'s run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?', ""Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?""]}, {'role': 'user', 'content': 'If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?'}, {'role': 'assistant', 'content': ""Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?"", 'alt': ['I see. How can you remove duplicates from a list?', ""Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?"", 'I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?', 'Where can you learn about deduplicating a list in Python?', 'Have you considered simply looping through the list and removing duplicates?']}, {'role': 'user', 'content': 'Maybe a set would be better than a list for this then. I\'ve modified my code. The output for that sentence now is: [\'hello\', \'world\'], so it looks like it works!\n```python\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(set(words))\n```'}, {'role': 'assistant', 'content': 'Perfect!'}]}"
+"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>","Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```","def calculate_average(x, y):
+   return x + y / 2","On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.",Replace `x + y` with `(x + y)` on line 2.,"assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0",56_15_compute_average,"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.\n\n## Example Cases:\n```\ncalculate_average(0, 0) => 0.0\ncalculate_average(1, 3) => 2.0\ncalculate_average(-1, 1) => 0.0\ncalculate_average(-5, -2) => -3.5\ncalculate_average(5.5, 7.5) => 6.5\ncalculate_average(405, 135) => 270.0\n```\n</problem>\n<bug_code>\n1. def calculate_average(x, y):\n2.    return x + y / 2\n</bug_code>\n<bug_desc>\nOn line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.\n</bug_desc>\n<bug_fixes>\nReplace `x + y` with `(x + y)` on line 2.\n</bug_fixes>\n<unit_tests>\nassert calculate_average(0, 0) == 0.0\nassert calculate_average(1, 3) == 2.0\nassert calculate_average(-1, 1) == 0.0\nassert calculate_average(-5, -2) == -3.5\nassert calculate_average(5.5, 7.5) == 6.5\nassert calculate_average(405, 135) == 270.0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?""}, {'role': 'assistant', 'content': ""Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?"", 'alt': ['Can you describe what happens when you run your code using one of the example cases?', 'Given `x = 2` and `y = 4`, can you explain how line 2 works?']}, {'role': 'user', 'content': 'I should get a 3, but I am getting a 4.'}, {'role': 'assistant', 'content': 'Why do you think it returns 4 instead of 3?', 'alt': ['Can you describe what line 2 is doing when `x` is 2 and `y` is 4?']}, {'role': 'user', 'content': 'I am not sure why it is returning 4.'}, {'role': 'assistant', 'content': 'Can you describe what line 2 is doing when `x` is 2 and `y` is 4?', 'alt': ['Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'Do you recall what the order of operations is when evaluating a mathematical expression?']}, {'role': 'user', 'content': 'The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.'}, {'role': 'assistant', 'content': 'Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'alt': ['Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?']}, {'role': 'user', 'content': 'Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.\n```python\n1. def calculate_average(x, y):\n2.    return (x + y) / 2\n```', 'alt': ['Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. ', 'I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. ']}, {'role': 'assistant', 'content': 'Very good! Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes it does! Thank you so much for your help!'}, {'role': 'assistant', 'content': 'You’re welcome please let me know if you have any questions.'}, {'role': 'user', 'content': 'Thank you will do!'}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   i = 0
+   while apples > 0 and apples > children:
+       apples = apples - children
+       i += 1
+   return i","The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.",Replace `apples > children` with `apples >= children` on line 3.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_59_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples > children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n</bug_code>\n<bug_desc>\nThe while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.\n</bug_desc>\n<bug_fixes>\nReplace `apples > children` with `apples >= children` on line 3.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My function fails two test cases and I do not understand why, can you help?'}, {'role': 'assistant', 'content': 'Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?', 'alt': [""Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?"", ""Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?"", 'Sure. Can you explain to me what you are trying to do with the while loop?', 'Sure. Can you tell me what the loop condition `apples > children` is there for?', 'Sure. Can you explain your code to me, what is supposed to do, line by line?']}, {'role': 'user', 'content': 'It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.', 'alt': [""It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.""]}, {'role': 'assistant', 'content': 'Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?', 'alt': ['Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.', ""Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?""]}, {'role': 'user', 'content': 'It is 1 less than the correct number.'}, {'role': 'assistant', 'content': 'Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?', 'alt': ['Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?']}, {'role': 'user', 'content': 'Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!\n```python\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples >= children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   return apples / children",The function returns a float instead of the largest possible integer after distributing the apples evenly.,Replace `/` with `//` on line 2.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_58_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    return apples / children\n</bug_code>\n<bug_desc>\nThe function returns a float instead of the largest possible integer after distributing the apples evenly. \n</bug_desc>\n<bug_fixes>\nReplace `/` with `//` on line 2.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck!""}, {'role': 'assistant', 'content': 'Where do you think the problem is?', 'alt': ['Have you read your code carefully?', 'Which test cases are passing?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': ""I don't know."", 'alt': ['I think the math is wrong.']}, {'role': 'assistant', 'content': 'Look at the test cases, does the first test case pass?', 'alt': ['Look at the test cases, what is the first test case to fail?', 'Have you read your code carefully?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': 'What is the correct answer for case 2?', 'alt': ['What is the correct answer for case 1?', 'Does case 1 require rounding?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'It should output 3.'}, {'role': 'assistant', 'content': 'Would there be a remainder?', 'alt': ['What is the correct answer for case 1?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'Yes, there would be a remainder of 1.', 'alt': ['Oh! I see, the problem is the remainder!']}, {'role': 'assistant', 'content': 'Is there a way you can see what the result is?', 'alt': ['Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'Trace the code, what would the output of line 2 be with 7 and 2?', 'How can you test the output of line 2?']}, {'role': 'user', 'content': 'I can add a print statement before the return.\n```python\n1. def split_apples(apples, children):\n2.    print(apples / children)\n3.    return apples / children\n```'}, {'role': 'assistant', 'content': 'Try running the code, what is the result of dividing 7 by 2?', 'alt': ['Try running the code, what is the result of dividing 10 by 2?', 'Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?']}, {'role': 'user', 'content': ""It's returning 3.5 for 7 divided by 2.""}, {'role': 'assistant', 'content': 'What should the output be?', 'alt': ['Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?', 'Look at the prompt, is there anything special about the format of the numbers?', 'Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'What do you need to change to make the output a whole number?']}, {'role': 'user', 'content': 'It should be 3.'}, {'role': 'assistant', 'content': 'Look at the Python documentation on operators, are you using the correct one to round down?', 'alt': ['Are you using the correct operator?', 'Is there a specific operator you should use when dividing whole numbers?', 'Is there a specific operator you should use when you need to round down?', 'Think about division in Python, what does `/` indicate?', 'How can you make it round down?']}, {'role': 'user', 'content': 'No! I need to use // instead.\n```python\n1. def split_apples(apples, children):\n2.    print(apples // children)\n3.    return apples // children\n```'}, {'role': 'assistant', 'content': 'Run it again, does it output correctly?', 'alt': ['Run it now, do all the test cases pass?']}, {'role': 'user', 'content': ""Yes, it works! I'll remove the extra print statement. \n```python\n1. def split_apples(apples, children):\n2.    return apples // children\n```""}, {'role': 'assistant', 'content': 'Run it one more time, do all the test cases pass?', 'alt': ['Run it again, does it output correctly?']}, {'role': 'user', 'content': 'Yes! It works, thank you!'}]}"
+"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>","Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```","def Product(a, b):
+a * b","The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.",Add `return` before `a * b`.,"assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25",59_60_product,"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).\n\n## Example Cases: \n```\nProduct(1,2) => 2\nProduct(2,4) => 8\nProduct(4,4) => 16\nProduct(5,5) => 25\n```\n</problem>\n<bug_code>\n1. def Product(a, b):\n2.\ta * b\n</bug_code>\n<bug_desc>\nThe function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.\n</bug_desc>\n<bug_fixes>\nAdd `return` before `a * b`.\n</bug_fixes>\n<unit_tests>\nassert Product(1,2) == 2\nassert Product(2,4) == 8\nassert Product(4,4) == 16\nassert Product(5,5) == 25\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.""}, {'role': 'assistant', 'content': 'Okay, can you explain your `Product()` function in detail?', 'alt': ['How familiar are you with functions in Python?']}, {'role': 'user', 'content': 'I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.'}, {'role': 'assistant', 'content': 'Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?', 'alt': ['Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?']}, {'role': 'user', 'content': 'Okay, I\'ve made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn\'t it be printing out a number?\n```python\n1. def Product(a, b):\n2.\ta * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?'}, {'role': 'user', 'content': 'Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?\n```python\n1. def Product(a, b):\n2.\treturn a * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'Yes. What is the purpose of line 3? Do you still need it?'}, {'role': 'user', 'content': ""It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!\n```python\n1. def Product(a, b):\n2.\treturn a * b\n```""}, {'role': 'assistant', 'content': ""You're welcome. Is there anything else that I can help you with today?""}, {'role': 'user', 'content': ""No, that's all. Thank you!""}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `""E""` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+12. store = turn_clockwise(""N"")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == ""N"":
+        return ""E""
+    elif compass_point == ""E"":
+        return ""S""
+    elif compass_point == ""S"":
+        return ""W""
+    elif compass_point == ""W"":
+        return ""N""
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point == ""N"":
+       print (""E"")
+   elif compass_point == ""E"":
+       print (""S"")
+   elif compass_point == ""S"":
+       print (""W"")
+   elif compass_point == ""W"":
+       print (""N"")
+   else:
+       print (""None"")","The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.","Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_33_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '\ufeff<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value `None`.\n\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n</bug_code>\n<bug_desc>\nThe function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.\n</bug_desc>\n<bug_fixes>\nReplace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I have a problem. My code does not generate the right result and I cannot figure that out.'}, {'role': 'assistant', 'content': ""Hi! Let's take a look at your code. Could you explain how your code works?"", 'alt': ['Hi! What makes you think that your program is not working properly?', 'Can you give me an example where your code does not return the correct result?', 'I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?']}, {'role': 'user', 'content': 'Ok. My code gets the current `compass_point` and prints the next one.'}, {'role': 'assistant', 'content': 'What do you see as your output in the terminal and what are you passing as `compass_point`?', 'alt': ['What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?']}, {'role': 'user', 'content': 'When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That\'s strange since my output is printed correctly, but my program does not pass any of the tests.'}, {'role': 'assistant', 'content': 'What does a unit test need from a function to ensure that the function works properly?', 'alt': ['Ah. How did you determine whether your function is correct?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?', 'Say you want to store the output of your function into a variable, what would you need to do?', 'What do you think a function needs to pass along its output to say get stored in a variable?']}, {'role': 'user', 'content': 'It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.', 'alt': [""I don't understand the question. Can you tell me more about unit tests?""]}, {'role': 'assistant', 'content': 'Correct. So would you be able to store the value outputted by the function into say a variable?', 'alt': ['Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?']}, {'role': 'user', 'content': 'Hypothetically yes. I should be able to store it in a variable. I have not tried though.'}, {'role': 'assistant', 'content': 'Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'alt': ['Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?']}, {'role': 'user', 'content': 'Ah I think, it would be `""E""` in `store`.'}, {'role': 'assistant', 'content': 'Let’s try it and then print `store`. What do you observe in your terminal?'}, {'role': 'user', 'content': 'Hmm... I see `None`. That’s really strange.\n\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n12. store = turn_clockwise(""N"")\n13. print(store)\n```'}, {'role': 'assistant', 'content': 'What do you think the function needs to have in order to give its output to the variable?', 'alt': ['Do you recall, which reserved word in Python is used to return the output for a function back to a variable?']}, {'role': 'user', 'content': 'Ah! I think it might be `return`. Let me try that.\n```python\ndef turn_clockwise(compass_point):\n    if compass_point == ""N"":\n        return ""E""\n    elif compass_point == ""E"":\n        return ""S""\n    elif compass_point == ""S"":\n        return ""W""\n    elif compass_point == ""W"":\n        return ""N""\n    else:\n        return None\n\t\t\n```', 'alt': ['I’m not really sure.']}, {'role': 'assistant', 'content': 'Very good.', 'alt': ['Very good. Is there a way for you to simplify your code?']}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You’re welcome! Let me know if I can be of any further help.'}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says ""SyntaxError: invalid syntax""
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to ""N""
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = ""N""`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        return ""E""
+4.    elif compass_point == ""E"":
+5.        return ""S""
+6.    elif compass_point == ""S"":
+7.        return ""W""
+8.    elif compass_point == ""W"":
+9.        return ""N""
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point = ""N"":
+       return ""E""
+   elif compass_point = ""E"":
+       return ""S""
+   elif compass_point = ""S"":
+       return ""W""
+   elif compass_point = ""W"":
+       return ""N""
+   else:
+       return None","There are syntax errors on lines 2, 4, 6, and 8.","Replace `=` with `==` on lines 2, 4, 6, and 8.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_34_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value None.\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point = ""N"":\n3.        return ""E""\n4.    elif compass_point = ""E"":\n5.        return ""S""\n6.    elif compass_point = ""S"":\n7.        return ""W""\n8.    elif compass_point = ""W"":\n9.        return ""N""\n10.    else:\n11.        return None\n</bug_code>\n<bug_desc>\nThere are syntax errors on lines 2, 4, 6, and 8.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on lines 2, 4, 6, and 8.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with the code can you help me? It's throwing an error.""}, {'role': 'assistant', 'content': 'What is the error that you observe?', 'alt': ['Let\'s start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?', 'Can you describe what your code is trying to do?']}, {'role': 'user', 'content': ""I have a syntax error on line 2. I'm not sure why."", 'alt': ['The terminal says ""SyntaxError: invalid syntax""']}, {'role': 'assistant', 'content': 'Can you describe what you are trying to do on line 2?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?', 'What operator do you use to check for equality?', 'Can you show me how you would assign the value 1 to a variable `x`?']}, {'role': 'user', 'content': 'I am trying to check if `compass_point` is equal to ""N""'}, {'role': 'assistant', 'content': 'What operator do you use to check for equality?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I use the `=` operator to check for equality.', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'alt': ['Can you show me how you would assign the value 1 to a variable `x`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I would use `compass_point = ""N""`', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Are you sure that you can use the same operator `=` for assignment and to check for equality?'}, {'role': 'user', 'content': 'Oh! Probably not. What operator should I use?', 'alt': ['Oh! I checked the documentation. I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Can you look in the Python documentation to see what operator is used to check for equality?'}, {'role': 'user', 'content': 'Oh I found it! I should use `==` instead of `=`. Let me edit my code!\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        return ""E""\n4.    elif compass_point == ""E"":\n5.        return ""S""\n6.    elif compass_point == ""S"":\n7.        return ""W""\n8.    elif compass_point == ""W"":\n9.        return ""N""\n10.   else:\n11.        return None\n```'}, {'role': 'assistant', 'content': 'Good job. Look good. Let me know if you have any more questions.'}, {'role': 'user', 'content': 'Thank you! Goodbye!'}]}"
+"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```","def Largest(a, b, c):
+if(a > b and a > c):
+	return a
+elif(b > a and b > c):
+	return b
+else:
+	return c","When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.",Change the > to >= in all the conditions.,"assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1",60_61_largest_number,"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.\n\n## Example Cases:\n```\nLargest(1,2,3) => 3\nLargest(3,2,1) => 3\nLargest(2,2,1) => 2\nLargest(1,1,1) => 1\n```\n</problem>\n<bug_code>\n1. def Largest(a, b, c):\n2.\tif(a > b and a > c):\n3.\t\treturn a\n4.\telif(b > a and b > c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n</bug_code>\n<bug_desc>\nWhen `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.\n</bug_desc>\n<bug_fixes>\nChange the > to >= in all the conditions.\n</bug_fixes>\n<unit_tests>\nassert Largest(1,2,3) == 3\nassert Largest(3,2,1) == 3\nassert Largest(2,2,1) == 2\nassert Largest(1,1,1) == 1\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.""}, {'role': 'assistant', 'content': 'Hello! Can you explain how your function works step by step?'}, {'role': 'user', 'content': 'Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.'}, {'role': 'assistant', 'content': 'Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?'}, {'role': 'user', 'content': 'Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?'}, {'role': 'assistant', 'content': 'Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?', 'alt': ['What about when `Largest(2,2,1)` is ran? What will be returned?']}, {'role': 'user', 'content': ""I'm not sure, how could you pick between them?""}, {'role': 'assistant', 'content': 'While it is required to pick one or the other, what difference would picking the first over the second make in the output?'}, {'role': 'user', 'content': ""Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!\n```python\n1. def Largest(a, b, c):\n2.\tif(a >= b and a >= c):\n3.\t\treturn a\n4.\telif(b >= a and b >= c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n```""}, {'role': 'assistant', 'content': ""I'm happy that I could help! Is there anything else that I could help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```","def SumIsEven(a, b):
+return (a+b) % 2 == 1
+",The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.,Replace `1` with `0` to ensure that the sum is even.,"assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False",61_62_is_even,"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.\n\n## Example Cases: \n```\nSumIsEven(1,1) => True\nSumIsEven(1,2) => False\nSumIsEven(2,2) => True\nSumIsEven(2,3) => False\n```\n</problem>\n<bug_code>\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 1\n3.\n</bug_code>\n<bug_desc>\nThe function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` to ensure that the sum is even.\n</bug_fixes>\n<unit_tests>\nassert SumIsEven(1,1) == True\nassert SumIsEven(1,2) == False\nassert SumIsEven(2,2) == True\nassert SumIsEven(2,3) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.""}, {'role': 'assistant', 'content': ""Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?""}, {'role': 'user', 'content': 'From what I understand, it tells you if a number is divisible by another number, right?'}, {'role': 'assistant', 'content': 'The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?', 'alt': ['The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?']}, {'role': 'user', 'content': ""Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!\n```python\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 0\n```""}, {'role': 'assistant', 'content': ""I'm happy to help! Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```","def SumBetween(low, high):
+num = 0
+for i in range(low, high):
+	num += i
+return num","The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range.",Replace `high` with `high + 1`.,"assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12",62_63_summing_between_integers,"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.\n\n## Example Cases:\n```\nSumBetween(0,1) => 1\nSumBetween(0,2) => 3\nSumBetween(1,2) => 3\nSumBetween(3,5) => 12\n```\n</problem>\n<bug_code>\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high):\n4.\t\tnum += i\n5.\treturn num\n</bug_code>\n<bug_desc>\nThe function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. \n</bug_desc>\n<bug_fixes>\nReplace `high` with `high + 1`.\n</bug_fixes>\n<unit_tests>\nassert SumBetween(0,1) == 1\nassert SumBetween(0,2) == 3\nassert SumBetween(1,2) == 3\nassert SumBetween(3,5) == 12\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.""}, {'role': 'assistant', 'content': 'Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?'}, {'role': 'user', 'content': ""I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.""}, {'role': 'assistant', 'content': '`range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?'}, {'role': 'user', 'content': 'That would just be 0, right?'}, {'role': 'assistant', 'content': 'Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?'}, {'role': 'user', 'content': ""Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?""}, {'role': 'assistant', 'content': ""Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?"", 'alt': [""Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?""]}, {'role': 'user', 'content': 'I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?'}, {'role': 'assistant', 'content': 'Can you explain why you think that is the correct answer?'}, {'role': 'user', 'content': 'Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.'}, {'role': 'assistant', 'content': 'That is entirely correct. Now how would you change your code to express this?'}, {'role': 'user', 'content': 'Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!\n```python\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high+1):\n4.\t\tnum += i\n5.\treturn num\n```'}, {'role': 'assistant', 'content': 'I am glad I could be of assistance. Is there anything else you wanted to ask?'}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```","def GoodDinner(pizzas, weekend):
+       if(pizzas >= 10 and weekend):
+               return True
+       elif(pizzas <= 20 and not(weekend)):
+               return True
+       return False",The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10.,Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.,"assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False",63_64_good_dinner,"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+","{'system': ""<problem>\nYou like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.\n\n## Example Cases:\n```\nGoodDinner(10, False) => True\nGoodDinner(20, False) => True\nGoodDinner(5, False) => False\nGoodDinner(21, False) => False\nGoodDinner(10, True) => True\nGoodDinner(21, True) => True\nGoodDinner(5, True) => False\n```\n</problem>\n<bug_code>\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n</bug_code>\n<bug_desc>\nThe function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. \n</bug_desc>\n<bug_fixes>\nInsert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.\n</bug_fixes>\n<unit_tests>\nassert GoodDinner(10, False) == True\nassert GoodDinner(20, False) == True\nassert GoodDinner(5, False) == False\nassert GoodDinner(21, False) == False\nassert GoodDinner(10, True) == True\nassert GoodDinner(21, True) == True\nassert GoodDinner(5, True) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.""}, {'role': 'assistant', 'content': ""Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?"", 'alt': ['When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?']}, {'role': 'user', 'content': 'It would be 10 or more pizzas.'}, {'role': 'assistant', 'content': 'And how would you produce a boolean that is `True` when the `pizzas` fits that condition?'}, {'role': 'user', 'content': 'It would be `pizzas >= 10`.'}, {'role': 'assistant', 'content': ""Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?""}, {'role': 'user', 'content': ""That's where I'm confused. It's between 10 and 20, inclusively, right?""}, {'role': 'assistant', 'content': 'That is correct, what about that condition is confusing you?'}, {'role': 'user', 'content': ""I'm not sure how to convert a number between two other numbers into Python.""}, {'role': 'assistant', 'content': ""Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?""}, {'role': 'user', 'content': 'That would be `pizzas >= 10` and `pizzas <= 20`.'}, {'role': 'assistant', 'content': 'And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?', 'alt': ['And would you use `and`, `or`, or `xor` to produce your desired outcome?']}, {'role': 'user', 'content': 'That would be `and` right?'}, {'role': 'assistant', 'content': 'Correct. Do you see now how you would implement a condition for when `weekend` is `False`?'}, {'role': 'user', 'content': 'Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!\n```python\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n```'}, {'role': 'assistant', 'content': ""I'm glad to be of assistance. Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```","def CountOnes(integers):
+count = 0
+for i in range(1, len(integers)):
+	if(integers[i] == 1):
+		count++
+return count","On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.",Replace `1` with `0` in the `range` call on line 3.,"assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0",64_65_count_ones,"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.\n\n## Example Cases:\n```\nCountOnes([1,1,1,0,0]) => 3\nCountOnes([1,0,0]) => 1\nCountOnes([]) => 0\nCountOnes([3]) => 0\n```\n</problem>\n<bug_code>\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(1, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount++\n6.\treturn count\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert CountOnes([1,1,1,0,0]) == 3\nassert CountOnes([1,0,0]) == 1\nassert CountOnes([]) == 0\nassert CountOnes([3]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.""}, {'role': 'assistant', 'content': 'Hello! Can you explain what your `for` loop does?'}, {'role': 'user', 'content': 'It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.'}, {'role': 'assistant', 'content': 'Can you tell me how many elements are in `range(1, len(integers))`?'}, {'role': 'user', 'content': 'Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?'}, {'role': 'assistant', 'content': 'That\'s not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".', 'alt': ['At what index do Python lists begin?', 'Can you tell me how many elements are in `range(1, len(integers))`?']}, {'role': 'user', 'content': 'Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!\n```python\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(0, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount += 1\n6.\treturn count\n```'}, {'role': 'assistant', 'content': ""I'm glad I could be of assistance. Is there anything else you wanted to discuss today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>","Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```","def Range(array):
+       smallest = 0
+       largest = 0
+       for element in array:
+               if(element > largest):
+                       largest = element
+               if(element < smallest):
+                       smallest = element
+       return largest - smallest","On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.",Initialize `smallest` and `largest` to the first element of array `array[0]`.,"assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13",65_66_list_range,"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.\n\n## Example Cases:\n```\nRange([1,2]) => 1\nRange([1,1,1,1,1,1,5])  => 4\nRange([2,2,1,3])  => 2\nRange([-10,-3,-1])  => 9\nRange([-10,3,1])  => 13\n```\n</problem>\n<bug_code>\n1. def Range(array):\n2.        smallest = 0\n3.        largest = 0\n4.        for element in array:\n5.                if(element > largest):\n6.                        largest = element\n7.                if(element < smallest):\n8.                        smallest = element\n9.        return largest - smallest\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.\n</bug_desc>\n<bug_fixes>\nInitialize `smallest` and `largest` to the first element of array `array[0]`.\n</bug_fixes>\n<unit_tests>\nassert Range([1,2]) == 1\nassert Range([1,1,1,1,1,1,5]) == 4\nassert Range([2,2,1,3]) == 2\nassert Range([-10,-3,-1]) == 9\nassert Range([-10,3,1]) == 13\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am working on the `Range()` function and I am getting unexpected results.'}, {'role': 'assistant', 'content': ""Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?""}, {'role': 'user', 'content': 'The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.'}, {'role': 'assistant', 'content': 'This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?'}, {'role': 'user', 'content': 'Oh. So I should choose a really big number for smallest and a really small number for largest?'}, {'role': 'assistant', 'content': 'Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.', 'alt': [""Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?""]}, {'role': 'user', 'content': 'Would it work to just set them to start as an element of the array?'}, {'role': 'assistant', 'content': 'And which element of the array would you set it to?', 'alt': ['That is correct. Why would that be the case?']}, {'role': 'user', 'content': 'I set it to the first element of the array and it works now! Thank you!\n```python\n1. def Range(array):\n2.\tsmallest = array[0]\n3.\tlargest = array[0]\n4.\tfor element in array:\n5.\t\tif(element > largest):\n6.\t\t\tlargest = element\n7.\t\tif(element < smallest):\n8.\t\t\tsmallest = element\n9.\treturn largest - smallest\n```'}, {'role': 'assistant', 'content': ""I'm glad I could help you! Is there anything else I can help you with today?""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does ""range"" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does ""range"" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = -1
+for i in range(1, len(array)):
+	if(value == array[i]):
+		index = i
+return index","On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.",Replace `1` with `0` in the `range` call on line 3.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_68_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(1, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Does the first test case pass?', 'Which line has the first failing test case?', 'Have you read the instructions carefully to check if your code does everything it needs to?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Which line has the first failing test case?', 'alt': ['Does the first test case pass?', 'Which line has the first part of your function on it?', 'What is your function supposed to do?']}, {'role': 'user', 'content': ""It's failing test 4, on line 11""}, {'role': 'assistant', 'content': 'Why is that one failing?', 'alt': ['Is the value in the array?', 'Which line has the first part of your function in it?', 'How is that one different from the first test case on line 8?']}, {'role': 'user', 'content': ""I don't know, it can't find the four.""}, {'role': 'assistant', 'content': ""Since it can't find the four, can it find other values?"", 'alt': ['Is there a four in the array?', 'Is that different from test case 1?', 'Which line has the first part of your function in it?']}, {'role': 'user', 'content': 'It found the one in the first test case.'}, {'role': 'assistant', 'content': ""Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?"", 'alt': ['What makes test case 1 and test case 4 different?', 'Which line has the first part of your function in it?', 'What part of the code checks each element in the array?']}, {'role': 'user', 'content': 'Maybe the problem is in the loop part where I check the values.'}, {'role': 'assistant', 'content': 'What line is that on?'}, {'role': 'user', 'content': ""It's on line 3.""}, {'role': 'assistant', 'content': 'Very good, so where should it start looking and stop looking?', 'alt': ['What exactly does this line do?', 'What does ""range"" mean in Python?']}, {'role': 'user', 'content': 'It should start at the first element and stop at the end of the array.'}, {'role': 'assistant', 'content': 'Which part of that line indicates that?', 'alt': ['What does ""range"" mean in Python?', 'What is the numeric value of the first index in an array in Python?']}, {'role': 'user', 'content': 'The part inside the range.', 'alt': [""Oh! I'm starting at 1 instead of 0""]}, {'role': 'assistant', 'content': 'Which index does it start at?', 'alt': ['What is the numeric value of the first index in an array in Python?', 'How do you find the first index of an array in Python?']}, {'role': 'user', 'content': 'It starts at 1.', 'alt': [""I'm starting in the wrong place!""]}, {'role': 'assistant', 'content': 'What number marks the first index of an array in Python?', 'alt': ['Could it be skipping anything?']}, {'role': 'user', 'content': ""Arrays in Python start at 0, I'm skipping the first index!""}, {'role': 'assistant', 'content': 'How would you fix it?\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```', 'alt': ['What number should be there?']}, {'role': 'user', 'content': 'I switched it to a zero and it works! Thanks!'}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = 0
+for i in range(0, len(array)):
+	if(value == array[i]):
+		index = i
+return index",The function returns 0 when `value` is not in `array` instead of returning -1.,Initialize `index` to -1 on line 2.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_67_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = 0\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nThe function returns 0 when `value` is not in `array` instead of returning -1.\n</bug_desc>\n<bug_fixes>\nInitialize `index` to -1 on line 2.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.'}, {'role': 'assistant', 'content': 'Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?'}, {'role': 'user', 'content': '`index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.'}, {'role': 'assistant', 'content': 'And what would distinguish that action from the function finding a match at index 0?', 'alt': ['Can you explain the difference between that and if the first element is the last index of the value?']}, {'role': 'user', 'content': ""I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.""}, {'role': 'assistant', 'content': 'The intended return value is -1, as given in the problem.', 'alt': ['This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.']}, {'role': 'user', 'content': ""Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```""}, {'role': 'assistant', 'content': ""I'm glad to be of assistance, is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+   index = -1
+   for i in range(len(array)-1, -1):
+       if(array[i] == value):
+           index = i
+           break
+   return index","On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.","Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.","assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_69_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n</bug_code>\n<bug_desc>\nOn line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.\n</bug_desc>\n<bug_fixes>\nChange the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': ""Okay, let's go over the code. Does the first test case pass?"", 'alt': ['Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': ""No, it doesn't pass.""}, {'role': 'assistant', 'content': ""Let's start by going over the first line of your function, what does line 1 do?"", 'alt': [""Let's start with your function. What do you think is the most complicated part?"", 'Can you describe what your function does?']}, {'role': 'user', 'content': 'It takes in the array and the value we are looking for.'}, {'role': 'assistant', 'content': 'Very good, does line 1 take in both of those things?', 'alt': [""Very good, let's move on to the next area, what does line 2 do?"", 'Very good, what can you explain what else your function is supposed to do?', 'What do you think is the most complicated part of your function?']}, {'role': 'user', 'content': 'Yes, line 1 does.'}, {'role': 'assistant', 'content': ""Okay, let's move on to the next area, what does line 2 do?"", 'alt': ['What is the next thing your function needs to do?', ""Let's check the most complex part of the function for problems next, where would you say that is?"", ""Let's make sure your function ends correctly, what value is it returning?""]}, {'role': 'user', 'content': 'It makes the index variable that keeps track of where the value is.'}, {'role': 'assistant', 'content': 'What should your function do next?', 'alt': [""Let's make sure your function ends correctly, what value is it returning?"", 'Why do we start index at -1?']}, {'role': 'user', 'content': 'It needs to loop through the list.'}, {'role': 'assistant', 'content': ""Let's examine that loop carefully. What variable controls the loop?"", 'alt': [""Let's examine that loop carefully,  what determines how many times the loop will run?"", ""Let's check that loop carefully, how should we move through the list?"", 'Is there anything special about how we are moving through the list?']}, {'role': 'user', 'content': 'The variable i controls the loop.'}, {'role': 'assistant', 'content': 'What value should i have on the first iteration of the loop?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", ""Let's examine that loop carefully,  what determines how many times the loop will run?""]}, {'role': 'user', 'content': 'The loop is supposed to start at the highest value in the array minus 1.'}, {'role': 'assistant', 'content': 'Is there anything special about how we are moving through the list?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", 'What value should i have at the end of the loop?']}, {'role': 'user', 'content': 'We are moving through the list backward.'}, {'role': 'assistant', 'content': 'Check the Python documentation, how do we iterate in a loop by default?', 'alt': ['Check the Python documentation, what is the default step?', 'Check the Python documentation, how would we move through a list not incrementing by one each time?', 'Have you ever moved through a list in reverse with range?']}, {'role': 'user', 'content': 'Oh! In Python it increases by one by default! We are going the wrong way.'}, {'role': 'assistant', 'content': 'What would you need do in the code to fix that?\n```python\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n```'}, {'role': 'user', 'content': 'I need to add a -1 step!'}, {'role': 'assistant', 'content': 'Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>","Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```","import math
+def area_circle(radius):
+   if radius < 0:
+       return 0
+   return math.pi * radius ** radius","On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.","Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`","import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)",67_70_area_circle,"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+","{'system': '<problem>\nWrite a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.\n\n## Example Cases:\n```\narea_circle(1.0) => 3.141\narea_circle(2.5) => 19.634\narea_circle(3.6) => 40.715\narea_circle(4.1) => 52.810\narea_circle(7.0) => 153.938\narea_circle(-2.0) => 0\n```\n</problem>\n<bug_code>\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** radius\n</bug_code>\n<bug_desc>\nOn line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.\n</bug_desc>\n<bug_fixes>\nChange the return statement on line 4 to `math.pi * radius * radius`\nChange the return statement on line 4 to `math.pi * radius **2`\n</bug_fixes>\n<unit_tests>\nimport math\nassert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)\nassert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)\nassert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)\nassert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)\nassert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)\nassert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, do you have any ideas what the problem is?', 'alt': ['Are any of the test cases passing?', 'Recheck the instructions, do you think anything is missing?']}, {'role': 'user', 'content': ""No, I don't know what's wrong."", 'alt': ['The first test case is passing, but the second one is failing.']}, {'role': 'assistant', 'content': ""Okay, let's start by looking at the test cases, does the one on line 8 pass?"", 'alt': ['Check the instructions, did you skip any steps?', 'What exactly is this function designed to do?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': ""Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?"", 'alt': [""That's interesting, why do you think the first test case is passing?"", 'What is the radius of the circle in the first test case that is passing?', 'What is the radius of the circle in the first test case that is failing?', 'Look at the if-statement on line 3, do you see any problems with it?']}, {'role': 'user', 'content': 'I calculate the area on line 5.'}, {'role': 'assistant', 'content': 'Look carefully at that line, can you tell me exactly what the code there does?', 'alt': [""First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?"", 'What is the formula for calculating the area of a circle?', 'What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Look carefully at that line, can you tell me exactly what the code there is supposed to do?']}, {'role': 'user', 'content': ""That's where the area of the circle is calculated.""}, {'role': 'assistant', 'content': ""What's the formula for calculating that?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': 'Pi times the radius of the circle squared.', 'alt': [""Oh! I'm not squaring the radius, I'm multiplying it times itself!""]}, {'role': 'assistant', 'content': ""Very good, so let's check that part, do you have Pi in the line?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': ""Yes, that's the math.pi part.""}, {'role': 'assistant', 'content': 'Very good, and do you have the radius in there?', 'alt': ['What do you multiply pi by?', 'Are you multiplying pi by the correct value?']}, {'role': 'user', 'content': ""Yes, that's the radius variable."", 'alt': [""I'm not squaring it!""]}, {'role': 'assistant', 'content': 'What are you supposed to do with the radius?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?', 'How do you square a variable?']}, {'role': 'user', 'content': ""I'm supposed to square it.""}, {'role': 'assistant', 'content': 'How do you square a number in Python?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?']}, {'role': 'user', 'content': ""It's ** with a 2."", 'alt': [""I'm raising it to itself, not squaring it!""]}, {'role': 'assistant', 'content': 'Look at that line again, are you squaring the value?'}, {'role': 'user', 'content': ""No! I'm raising it to itself. I'll fix it.\n```python\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** 2\n```""}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': ""Yes! It's passing all the test cases! Thanks!""}]}"
+"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>","Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```","def get_combinations(list_c):
+   ans=[]
+   for i in range(0,len(list_c)):
+       for j in range(i,len(list_c)):
+           ans.append(list_c[j]+list_c[i])
+   return ans","On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it.","On line 4, change the for loop to `for j in range(len(list_c))`.","assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']",69_81_get_combinations,"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+","{'system': ""<problem>\nWrite a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.\n\n## Example Cases:\n```\nget_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']\nget_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nget_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n```\n</problem>\n<bug_code>\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(i,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n</bug_code>\n<bug_desc>\nOn line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. \n</bug_desc>\n<bug_fixes>\nOn line 4, change the for loop to `for j in range(len(list_c))`.\n\n</bug_fixes>\n<unit_tests>\nassert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']\nassert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nassert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': ""Okay, let's look at the code. Tell me about what happens on line 2?"", 'alt': [""Okay, let's go over the code. Does the first test case pass?"", 'Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': 'Line 2 makes an empty list that we are going to fill later.'}, {'role': 'assistant', 'content': ""Yes, now let's move on to the first part of the loop. What happens on line 3?"", 'alt': ['Where do you think the problem is?', 'Do you see any problems with line 2?']}, {'role': 'user', 'content': 'Line 3 makes a for loop.'}, {'role': 'assistant', 'content': 'What is the variable name for the iterator made on line 3?', 'alt': ['What controls the loop?', 'How many times does the loop iterate?', 'What is the role of range on line 3?']}, {'role': 'user', 'content': 'The iterator is named i.'}, {'role': 'assistant', 'content': 'What value does i start on, and what value does it stop on?', 'alt': ['What determines when that loop ends?', 'How many times does it iterate?', 'What is range for?']}, {'role': 'user', 'content': 'i is supposed to start at 0 and end at the length of the list.'}, {'role': 'assistant', 'content': 'Look at range, does i start and stop where it should?', 'alt': ['How many times does it iterate?', 'What determines that the loop runs the right number of times?']}, {'role': 'user', 'content': 'Yes, that part looks right.'}, {'role': 'assistant', 'content': ""Let's check the second loop next. Where does it start?""}, {'role': 'user', 'content': 'The loop starts on line 4.'}, {'role': 'assistant', 'content': 'What iterator is made on that line?', 'alt': ['How many times should that loop iterate?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'We make j on that line.'}, {'role': 'assistant', 'content': 'How many times should that loop iterate?', 'alt': ['Where in the array list should we start for the second term?', 'Should we go through the whole array list for the second term in the combination?', 'What part of the code on that line controls the iteration of the loop?']}, {'role': 'user', 'content': 'It should iterate once for every item in `list_c`.', 'alt': [""Oh! It's starting at i not at 0!""]}, {'role': 'assistant', 'content': 'What value should it start at to iterate once for every item in list_c?', 'alt': ['What part of the code on that line controls the iteration of the loop?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'It should start at the beginning of the list, at 0.'}, {'role': 'assistant', 'content': 'What piece of the code would control that?'}, {'role': 'user', 'content': 'The values inside of range. Oh! I need to make it start at 0 not at i!\n```python\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(0,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n```'}, {'role': 'assistant', 'content': ""Great! Now let's run the code and see if it works.""}, {'role': 'user', 'content': 'It works! Thank you!'}]}"
+"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>","Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```","def my_func(valList):
+   result = {}
+   for key, value in valList:
+        result[key] = [value]
+   return result","The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.","Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`","assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}",7_35_integer_grouping,"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+","{'system': '<problem>\nImplement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where\n`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.\nReturn a dictionary where the:\n* key: first elements of `valList`\n* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.\n\n```py\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\n```\nIn the example above:\n\n* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`\n* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`\n* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`\n\n## Example Cases:\n```\nmy_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nmy_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n```\n</problem>\n<bug_code>\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.    return result\n</bug_code>\n<bug_desc>\nThe function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  \n</bug_desc>\n<bug_fixes>\nReplace line 4 with the following lines:\n```py\nif key in result.keys():\n      result[key].append(value)\nelse:\n      result[key] = [value]\n```\nReplace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`\n</bug_fixes>\n<unit_tests>\nassert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}\nassert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nassert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice."", 'alt': ['Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.', 'Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?', ""Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?"", 'Sure. Can you go through your code line by line and explain to me what each line is supposed to do?', 'Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?', 'Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?']}, {'role': 'user', 'content': ""I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?', 'alt': ['That is correct. Do you know how to append a new element to a list?']}, {'role': 'user', 'content': ""I did that, but when I run my code I get a `KeyError` message in line 4.\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] += [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict', 'alt': ['Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?', 'Do you know what happens when you try to get a value using a key that does not exist in the dictionary?']}, {'role': 'user', 'content': ""It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.        print('key = ', key, ' value = ', result[key])\n9.    return result\n10.\n11.my_func([(1, 2), (1, 3)])\n```"", 'alt': ['It is raised when `key` is not in the map.']}, {'role': 'assistant', 'content': 'Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?'}, {'role': 'user', 'content': 'I did that and it works on all test cases. Thank you!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.    return result\n```'}, {'role': 'assistant', 'content': ""You're welcome, I am glad I could be of help.""}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of ""years"" in line 8?
+	<alt>Where does ""current_fee"" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+
+   current_fee = 623.00
+   years = 0
+   total_fee = current_fee
+
+   while total_fee < target_amount:
+       total_fee = current_fee*(1.015**years)
+       years += 1
+
+   return years","On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.",Move line 9 to be above line 8 and within the while loop.,"assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_78_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        total_fee = current_fee*(1.015**years)\n9.        years += 1\n10.\n11.    return years\n</bug_code>\n<bug_desc>\nOn line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.\n</bug_desc>\n<bug_fixes>\nMove line 9 to be above line 8 and within the while loop.\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm really stuck!""}, {'role': 'assistant', 'content': ""Let me help, do you have any idea what's wrong?"", 'alt': ['What test cases are passing?', 'Have you read the instructions and made sure you are doing everything?', 'Where do you think the problem is?']}, {'role': 'user', 'content': ""I don't know. None of the test cases are passing.""}, {'role': 'assistant', 'content': ""Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?"", 'alt': [""Let's start by checking the math, what numbers do we start with?"", 'How should the calculation work?', 'Could we add some print statements to check the math?']}, {'role': 'user', 'content': ""That's where I set up the variables.""}, {'role': 'assistant', 'content': ""Okay, let's check the loop now, what is it for?""}, {'role': 'user', 'content': ""That's where we calculate the change over all the years.""}, {'role': 'assistant', 'content': 'So what happens on line 7?', 'alt': ['How do we decide when we want to stop looping?', 'Can you explain the calculation on line 8?', 'What is the purpose of line 9?']}, {'role': 'user', 'content': 'Line 7 starts the loop, and sets it to run until the fee goes over the target.'}, {'role': 'assistant', 'content': ""Okay, so now let's check on line 8, what does that line do?"", 'alt': ['What is the purpose of line 9?', 'Does anything look incorrect with line 7?']}, {'role': 'user', 'content': ""That's where we do the calculation.""}, {'role': 'assistant', 'content': 'What is the purpose of line 9?', 'alt': ['What is the role of ""years"" in line 8?', 'Where does ""current_fee"" come from in line 8?', 'Could we add a print statement here to check the figures?']}, {'role': 'user', 'content': 'It increments the number of years.'}, {'role': 'assistant', 'content': 'So what value would years have the first time the loop iterates?', 'alt': ['What is the value of years in the calculation on line 8 the first time the loop is run?', 'Should we be incrementing years after we do the calculation?']}, {'role': 'user', 'content': 'Years would start at 0.', 'alt': ['I need to change that, we would calculate at the end of year 1, not year 0!']}, {'role': 'assistant', 'content': 'When would we calculate interest?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': 'At the end of a year.'}, {'role': 'assistant', 'content': 'When would we want to calculate the number of years?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': ""It's off by 1, I should be incrementing first!""}, {'role': 'assistant', 'content': 'Make that change and try running it. What happens?\n```python\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        years += 1\n9.        total_fee = current_fee*(1.015**years)\n10.\n11.    return years\n```'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+   i=623
+   years=0
+   while i < target_amount:
+       years= years+1
+       i= 0.015*i
+   return years","On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.","On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`","assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_77_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= 0.015*i\n7.    return years\n</bug_code>\n<bug_desc>\nOn line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.\n</bug_desc>\n<bug_fixes>\nOn line 6, replace `i= 0.015*i` with `i= i + 0.015*i`\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', ""Let's start with the first part of your function, what happens on lines 2 and 3?"", ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's start with your function. What happens on lines 2 and 3?"", 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', 'Have you read the prompt carefully?', ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': 'I declare some variables for the starting amount and the years.'}, {'role': 'assistant', 'content': ""Very good, so let's look at the loop part now. What happens on line 4?"", 'alt': ['What should happen next?', 'Does your function return the correct variable?']}, {'role': 'user', 'content': ""It checks if i is less than the target amount and keeps looping if that's true.""}, {'role': 'assistant', 'content': ""That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?"", 'alt': ['Is that what it is supposed to do?', 'What do we do on line 5?']}, {'role': 'user', 'content': ""It's the current amount plus the interest rate times the current amount."", 'alt': [""I don't know.""]}, {'role': 'assistant', 'content': 'What line in your code would have that calculation?', 'alt': ['Does that calculation match the one in your code?']}, {'role': 'user', 'content': 'Line 6'}, {'role': 'assistant', 'content': 'Look carefully at that line, does it match the equation you just told me about?', 'alt': ['Is there anything wrong with that line?', 'What would 623 times 0.015 be?']}, {'role': 'user', 'content': ""No! It doesn't match, I forgot to add back the initial amount!\n```python\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= i+0.015*i\n7.    return years\n```""}, {'role': 'assistant', 'content': 'Try running the code here, what happens?'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>","Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```","import random as rand
+rand.seed(42)
+
+def my_func(len):
+   y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+   return y",The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.,"Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.","assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]",8_36_plot_function,"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+","{'system': ""<problem>\nWrite a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.\n\n## Example Cases:\n```\nmy_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nmy_func(7) => [4, 7, 13, 19, 26, 32, 41]\nmy_func(5) => [5, 7, 17, 20, 29]\nmy_func(3) => [2, 7, 14]\nmy_func(1) => [1]\n```\n</problem>\n<bug_code>\n1. import random as rand\n2. rand.seed(42)\n3.\n4. def my_func(len):\n5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))\n6.    return y\n</bug_code>\n<bug_desc>\nThe function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.\n</bug_desc>\n<bug_fixes>\nReplace `def yOf(x):` with `lambda x:` on line 4.\nAfter line 2 insert the following:\n```py\ndef yOf(x, len):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.\nAfter line 4 insert the following:\n```py\ndef yOf(x):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.\n</bug_fixes>\n<unit_tests>\nassert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nassert my_func(7) == [4, 7, 13, 19, 26, 32, 41]\nassert my_func(5) == [5, 7, 17, 20, 29]\nassert my_func(3) == [2, 7, 14]\nassert my_func(1) == [1]\n</unit_tests>\n<stu_desc>\nThe student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?""}, {'role': 'assistant', 'content': 'Certainly. Can you describe what you know about the `map` function so far with an example if possible?', 'alt': ['Certainly. Can you describe what your code does on line 5?', 'Certainly. Do you know what the `map` function takes in as parameters?']}, {'role': 'user', 'content': 'So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.'}, {'role': 'assistant', 'content': 'Ah good explanation. When you try to run your code what do you observe in the terminal?', 'alt': ['Good explanation. So what is the specific issue that you have?', 'Good explanation. Where can you learn more about the `map` function and its use?']}, {'role': 'user', 'content': 'So when I try to run my code, it throws a syntax error on line 5.'}, {'role': 'assistant', 'content': 'Can you explain to me what the `def` reserved word in Python does?', 'alt': ['Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?', ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""]}, {'role': 'user', 'content': '`def` stands for define and it creates a function in Python to be used later on in the code.'}, {'role': 'assistant', 'content': ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""}, {'role': 'user', 'content': 'I guess not from the looks of it. Maybe I should define my function outside of the `map` call?', 'alt': ['It seems to be the case. Not really sure though what to do though.']}, {'role': 'assistant', 'content': ""Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?""}, {'role': 'user', 'content': 'Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.', 'alt': ['Maybe after line 4? Inside of `my_func` so that it is within scope?', 'Not really sure.']}, {'role': 'assistant', 'content': ""Sounds good. Let's try it. What do you pass into `map` now?""}, {'role': 'user', 'content': ""Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf,  range(len)))\n7.    return y\n```""}, {'role': 'assistant', 'content': 'What does `len` refer to on line 4?'}, {'role': 'user', 'content': 'Hmm. It refers to my variable `len` does it not?', 'alt': ['Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.']}, {'role': 'assistant', 'content': 'Where do you declare `len` in your code?'}, {'role': 'user', 'content': 'I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.'}, {'role': 'assistant', 'content': 'According to the problem specification, what is the upper-bound of the randomly generated integers?', 'alt': ['Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?']}, {'role': 'user', 'content': 'Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.', 'alt': ['Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.']}, {'role': 'assistant', 'content': 'Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?', 'alt': ['Good. Where in your code would you need to pass `len` to `yOf`?']}, {'role': 'user', 'content': ""I actually don't know how to do that."", 'alt': [""I don't know how to do that. But I guess it would be inside the `map` function."", 'I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.']}, {'role': 'assistant', 'content': 'Can you point me to a line where you think you might want to pass a new parameter to `yOf`?', 'alt': ['Do you know how many parameters `map` takes in?', 'Where can you learn more about how to pass multiple parameters to a function called in `map`?']}, {'role': 'user', 'content': 'I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.'}, {'role': 'assistant', 'content': 'Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?'}, {'role': 'user', 'content': 'Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return  x * 6 + rand.randint(1, len)  \n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'Good. What do you observe after running this?', 'alt': ['How many parameters does the function `yOf` take on now?', 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'What do you notice in your terminal now when you run this?', 'alt': ['How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'I notice that it runs without any issues but it fails all the test cases. Hmm..'}, {'role': 'assistant', 'content': 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?', 'alt': [""That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?""]}, {'role': 'user', 'content': 'Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.', 'alt': ['Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.']}, {'role': 'assistant', 'content': 'Good. How many iterable elements are in your second iterables parameter to the `map` function?'}, {'role': 'user', 'content': ""Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len] * len))\n7.    return y \n```""}, {'role': 'assistant', 'content': 'Good work. Does your code pass all the tests?'}, {'role': 'user', 'content': 'Yes now it does! Thank you so much for all your help! I learned a lot today!'}]}"
+"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says ""'int' object is not subscriptable"" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `""'int' object is not subscriptable""` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>","Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```","def det2d(matrix):
+   return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+
+def determinant(matrix):
+
+   subm1 = [val[1:3] for val in matrix[1:3]]
+   subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+   subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+
+   return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)","On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.","Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.","assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329",9_38_calculating_determinant,"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+","{'system': '<problem>\nWrite a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.\n## Example Cases:\n```\ndeterminant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0\ndeterminant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315\ndeterminant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156\ndeterminant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329\n```\n</problem>\n<bug_code>\n1. def det2d(matrix):\n2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\n3.\n4. def determinant(matrix):\n5.\n6.    subm1 = [val[1:3] for val in matrix[1:3]]\n7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]\n8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]\n9.\n10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n</bug_code>\n<bug_desc>\nOn line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.\n</bug_desc>\n<bug_fixes>\nChange line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.\n</bug_fixes>\n<unit_tests>\nassert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0\nassert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315\nassert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156\nassert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices."", 'alt': [""I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.""]}, {'role': 'assistant', 'content': ""I know we can fix this together. What are the issues you're having?"", 'alt': ['Can you describe your code of the method `determinant` line by line to me?', ""Can you explain how you're creating the 2x2 submatrices?""]}, {'role': 'user', 'content': 'Well, at first I was getting the wrong answer and now I\'m getting TypeErrors. It says ""\'int\' object is not subscriptable"" when I\'m calling the `det2d` function.'}, {'role': 'assistant', 'content': 'What are the intended inputs and outputs of the `det2d` function?', 'alt': ['What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.', 'Can you describe the `det2d` function to me?', 'What does the error message `""\'int\' object is not subscriptable""` mean?', 'How do you know that the error is coming from the `det2d` function?', 'Which variables are getting subscripted and how do you know what the data type of those variables are?', ""Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?""]}, {'role': 'user', 'content': ""I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.""}, {'role': 'assistant', 'content': 'Great! Did you make the same mistake anywhere else?', 'alt': ['Great! Does that also apply for `subm3` or is that calculated correctly?', 'What about the other two submatrices?']}, {'role': 'user', 'content': ""I think I made a similar mistake with `subm3`. I'll change both. It works!\n```python\n def det2d(matrix):\n    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\ndef determinant(matrix):\n    subm1 = [val[1:3] for val in matrix[1:3]]\n    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]\n    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]\n    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n```""}]}"
diff --git a/data/final_dataset.csv b/data/final_dataset.csv
new file mode 100644
index 0000000000000000000000000000000000000000..2355ebf7f54d08e3f05a7abd5e881dc1fda9ceb7
--- /dev/null
+++ b/data/final_dataset.csv
@@ -0,0 +1,8445 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
+","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n <= 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+    a = 0
+   b = 1
+   for i in range(0, n):
+     temp = b
+     b = a + b
+     a = temp
+   return b","On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.","Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.","assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_0_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(0, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.\n</bug_desc>\n<bug_fixes>\nReplace `range(0, n)` with `range(1, n)` on line 11.\nReplace `range(0, n)` with `range(0, n - 1)` on line 11.\nReplace `range(0, n)` with `range(2, n + 1)` on line 11.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\nThe student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey, I really need help. This function is not returning the correct number.'}, {'role': 'assistant', 'content': ""I'll be happy to help you. What happens when you call `fibonacci(5)`?"", 'alt': ['Happy to help. Can you give me an example of your function returning an incorrect number?', 'Sure. Can you list the first 5 numbers in the Fibonacci sequence?', 'Can you describe what your code does line by line?']}, {'role': 'user', 'content': 'When I run the function with `n` as 5 the output is 8 instead of 5.'}, {'role': 'assistant', 'content': 'I see. What do you think might be the cause of this?', 'alt': ['Can you describe your for loop on line 11?', 'Can you walk me through the steps your function takes to generate the Fibonacci sequence?', 'Can you identify any issues with the loop that generates the Fibonacci sequence?', 'Which part of your code do you suspect of causing this issue?']}, {'role': 'user', 'content': ""I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return."", 'alt': ['I am not sure. Can you help?', 'I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.']}, {'role': 'assistant', 'content': 'Good. Can you explain your for loop on line 11?', 'alt': ['What specifically about your for loop on line 11 might be causing the issue?', 'Good. Can you describe how many times the for loop iterates on line 11?', 'Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?', 'Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?', 'Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?']}, {'role': 'user', 'content': 'The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.', 'alt': ['It loops `n` times', 'Not really sure how to describe it.']}, {'role': 'assistant', 'content': ""Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?"", 'alt': ['What are the values of `a` and `b` in each iteration?', 'What variables used in the for loop on line 11 should we pay attention to identify the issue?', ""Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?"", ""Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?""]}, {'role': 'user', 'content': ""I'm not really sure can you suggest a way?"", 'alt': ['I can use the debugger!', 'I can add print statements.']}, {'role': 'assistant', 'content': 'Have you considered inserting a print statement after line 12 to output the 3 variables?', 'alt': ['Have you considered using the debugger?']}, {'role': 'user', 'content': 'Aha! Good idea! Perfect let me do that.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.   b = 1\n11.   for i in range(0, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Let's look at the outputs what do you observe?""}, {'role': 'user', 'content': 'I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.', 'alt': ['It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.', ""Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.""]}, {'role': 'assistant', 'content': 'What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?', 'alt': ['Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?']}, {'role': 'user', 'content': 'We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.'}, {'role': 'assistant', 'content': 'Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?', 'alt': ['Good. What should you do now to return the correct Fibonacci number?']}, {'role': 'user', 'content': 'I think I should edit the range of the loop to iterate one less time. Let me edit my code.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Good work. Don't forget to remove the print statement!""}, {'role': 'user', 'content': 'Ah yes! Thank you so much for your help!\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'You are welcome. Let me know if you have any further questions.'}, {'role': 'user', 'content': 'Thanks again! Goodbye!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 or n == 2:
+       return 1
+   else:
+       return fibonacci(n) + fibonacci(n-1)",`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.,Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_5_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n) + fibonacci(n-1)\n</bug_code>\n<bug_desc>\n`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.\n</bug_desc>\n<bug_fixes>\nReplace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?'}, {'role': 'assistant', 'content': 'I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?', 'alt': ['According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?', 'According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?', 'Can you explain what infinite recursion means?', 'Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?', ""Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?"", 'Can you explain what a recursive function is? When do we call a function recursive?', 'According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?']}, {'role': 'user', 'content': 'I believe it is line 7, because that is the line that is executed when `n` is larger than 2.'}, {'role': 'assistant', 'content': 'That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?', 'alt': ['Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?', 'Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?']}, {'role': 'user', 'content': 'Well, the function is called recursively to compute `fibonacci(3)`.\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 1) + fibonacci(n - 2)\n```', 'alt': ['Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.', 'Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...', 'The call `fibonacci(n)`.']}, {'role': 'assistant', 'content': 'So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?', 'alt': ['Do you see now why infinite recursion happens?', 'So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?']}, {'role': 'user', 'content': 'Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 2) + fibonacci(n - 1)\n```'}, {'role': 'assistant', 'content': 'Great, your program now works as expected!'}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 and n == 2:
+       return 1
+   elif n > 2:
+       a = 1
+       b = 1
+       for i in range(3, n+1):
+           c = a + b
+           a = b
+           b = c
+       return b","On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.",Replace `and` with `or` on line 4.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_6_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 and n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n</bug_code>\n<bug_desc>\nOn line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.\n</bug_desc>\n<bug_fixes>\nReplace `and` with `or` on line 4.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, my program passes all test cases except the second and third. Can you help?'}, {'role': 'assistant', 'content': 'Hi! Sure, what does the problem description say about these two cases?', 'alt': ['Hi! Sure, what is the value of `n` in these two cases?', 'Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?', 'Hi! Sure, what is the output supposed to be for each of these cases?']}, {'role': 'user', 'content': 'I am not sure, how can I find that?', 'alt': ['It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`']}, {'role': 'assistant', 'content': 'What are the values of `n` for these two cases?', 'alt': ['There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?']}, {'role': 'user', 'content': 'In the second test case, the value of `n` is `1` and in the third case `n` is `2`.'}, {'role': 'assistant', 'content': 'Correct, what are we supposed to return for these values of `n`?'}, {'role': 'user', 'content': 'We are supposed to return `1`, and I handled these cases on lines 4 and 5.'}, {'role': 'assistant', 'content': 'Ok, when does line 4 evaluate to true?', 'alt': ['Ok, for what value of `n` will line 5 be executed?']}, {'role': 'user', 'content': 'It evaluates to true if `n` is `1` and if it is `2`'}, {'role': 'assistant', 'content': 'Will the value of `n` ever be `1` and `2` at the same time?'}, {'role': 'user', 'content': 'No, it can be either `1` or `2`, but never both at the same time.', 'alt': ['No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?']}, {'role': 'assistant', 'content': 'Correct! It is either `1` OR `2`, does your if statement check for that?'}, {'role': 'user', 'content': 'Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n```'}, {'role': 'assistant', 'content': 'That looks great! It now returns `1` when `n` is either `1` or `2`.'}, {'role': 'user', 'content': 'Thank you for explaining the difference between `or` and `and`!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n < 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+   a = 0
+   b = 1
+   for i in range(1, n):
+     temp = b 
+     b = a + b 
+     a = temp
+   return b","On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`.",Replace `if n < 0` with `if n <= 0` on line 2.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_2_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n < 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `\'OOPS\'` when `n` is equal to `0`. \n</bug_desc>\n<bug_fixes>\nReplace `if n < 0` with `if n <= 0` on line 2.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I need help on this my code is failing the first test case.', 'alt': ['Hello. I need help with my code.']}, {'role': 'assistant', 'content': 'Can you walk me through your code step by step given that `n` is 0?', 'alt': [""Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?"", 'Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?']}, {'role': 'user', 'content': '`n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'Good. Did you try it for all the unit tests?'}, {'role': 'user', 'content': 'Yes I have. Thank you so much for your help!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   hw = hw * 0.2
+   exams = exams * 0.4
+   projects = projects * 0.30
+   att = att * 0.10
+
+   finalScore = hw + exams + projects + att
+   roundedScore = round(finalScore)
+
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.","Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_10_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if finalScore >= 90:\n11.        letterGrade = ""A""\n12.    elif finalScore >= 80:\n13.        letterGrade = ""B""\n14.    elif finalScore >= 70:\n15.        letterGrade = ""C""\n16.    elif finalScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nOn lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.\n</bug_desc>\n<bug_fixes>\nReplace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?'}, {'role': 'assistant', 'content': 'I would love to! What kind of problems are you having?', 'alt': ['Can you describe what your code fails to do?', 'Can you explain your code to me line by line?']}, {'role': 'user', 'content': ""I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).""}, {'role': 'assistant', 'content': ""Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?"", 'alt': ['Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?', 'Let’s trace back what your function did. Where did `D` in your returned tuple come from?', 'Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?']}, {'role': 'user', 'content': 'The value assigned to `finalScore` is 69.6.', 'alt': ['The value would be 70, right?']}, {'role': 'assistant', 'content': 'Correct. Which block of the if-elif-else statement is executed?', 'alt': ['What does the boolean expression on line 14 evaluate to?', 'Can you explain the differences between `finalScore` and `roundedScore`?', 'What is the truth value of the boolean expression on line 14?']}, {'role': 'user', 'content': 'Oh! The boolean on line 16 becomes true, assigning `letterGrade` to \'D\'! But I\'m not sure how to fix that.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```', 'alt': ['Oh, I put `finalScore` instead of `roundedScore`!']}, {'role': 'assistant', 'content': 'How would you ensure that the grade would be treated as its nearest integer for the comparison?', 'alt': ['How does your code return a grade of 70, yet compares with 69.6?']}, {'role': 'user', 'content': 'Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good. Happy to help. Let me know if you have any further questions!'}, {'role': 'user', 'content': 'Thank you so much for your help again!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.   elif roundedScore >= 60:
+11.       letterGrade = ""D""
+12.   else:
+13.       letterGrade = ""F""
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore >= 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+  elif roundedScore >= 60:
+      letterGrade = ""D""
+  else:
+      letterGrade = ""F""
+  return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue","The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.","Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_11_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\ncalculateGrade(100, 89, 85, 90) => ('A', 90)\ncalculateGrade(72, 96, 74, 98) => ('B', 85)\ncalculateGrade(100, 82, 68, 94) => ('B', 83)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(12, 14, 23, 10) => ('F', 16)\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\n```\n</problem>\n<bug_desc>\nThe return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.\n</bug_desc>\n<bug_fixes>\nRemove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(72, 96, 74, 98) == ('B', 85)\nassert calculateGrade(100, 82, 68, 94) == ('B', 83)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(12, 14, 23, 10) == ('F', 16)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hi, please help I'm not sure what's going wrong""}, {'role': 'assistant', 'content': ""Hello. Let's take a look at your code together. What problem are you facing?"", 'alt': ['Hi. Are you encountering an error?', 'Hello. Can you describe your code line by line?', ""Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?""]}, {'role': 'user', 'content': 'The function only seems to return the `letterGrade` but otherwise it runs alright.', 'alt': ['It does not throw an error, but it does not show everything I want it to either.', 'No errors but it is not working as expected.']}, {'role': 'assistant', 'content': ""Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?""}, {'role': 'user', 'content': 'Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?', 'alt': ['It seems like the last line never executes.']}, {'role': 'assistant', 'content': 'Good! Given this observation, when does your function terminate?', 'alt': ['Good! Can you describe what are you trying to do on line 15?', 'What makes you think line 15 is not being executed?', 'Can you describe what are you trying to do on lines 14 and 15?']}, {'role': 'user', 'content': 'It seems like once the return statement has executed, the function does not go further.'}, {'role': 'assistant', 'content': 'Is it possible for a function to have two consecutive return statements?', 'alt': [""Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?"", 'How about we look up this behavior in the documentation to get more clarity?']}, {'role': 'user', 'content': 'It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?', 'alt': ['But then how do I make sure to return both the `letterGrade` and `roundedScore`?', 'Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!']}, {'role': 'assistant', 'content': ""Good question! Let's turn to the documentation - how can we return multiple variables?"", 'alt': [""Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?"", ""Let's look at the examples in the instructions. What do you notice is being returned?""]}, {'role': 'user', 'content': 'Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.   elif roundedScore >= 60:\n11.       letterGrade = ""D""\n12.   else:\n13.       letterGrade = ""F""\n14.   return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Great job! Is your code working now?', 'alt': ['Did that fix your problem?']}, {'role': 'user', 'content': 'Yes it did, thanks!', 'alt': [""I'm all done!""]}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   weights = [0.1, 0.3, 0.4, 0.2]
+   grades = [hw, exams, projects, att]
+   final_grade = 0
+   for i in range(len(weights)):
+       final_grade += weights[i] * grades[i]
+   final_grade = round(final_grade)
+   
+   if final_grade >= 90:
+       return ('A', final_grade)
+   elif final_grade >= 80:
+       return ('B', final_grade)
+   elif final_grade >= 70:
+       return ('C', final_grade)
+   elif final_grade >= 60:
+       return ('D', final_grade)
+   else:
+       return ('F', final_grade)","On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.","On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_13_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(100, 89, 85, 90) == ('A', 90)\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.1, 0.3, 0.4, 0.2]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.\n</bug_desc>\n<bug_fixes>\nOn line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.\nOn line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck""}, {'role': 'assistant', 'content': 'Okay, what do you think the problem is?', 'alt': ['Can you tell me what test cases are failing?', 'Have you thought about the problem?']}, {'role': 'user', 'content': ""It isn't calculating correctly."", 'alt': [""It's failing the second test case.""]}, {'role': 'assistant', 'content': 'How is the calculation made in the function?', 'alt': ['Can you tell me what test cases are failing?', 'Where do you think the problem is?', 'Start with line 1, do you see any problems with the method header?', 'Look at the second test case, how is it different from the first test case?']}, {'role': 'user', 'content': 'The scores are multiplied with the weights and summed up.', 'alt': ['Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.']}, {'role': 'assistant', 'content': 'So, is it working for the first test case?', 'alt': ['Do you see any problems adding the scores on the assignments to the grades array?', 'Do you see any problems with the loop?', 'Do you see any problems with the weights?', ""Check the instructions, do you see anything you aren't doing?"", 'Why is it working on the first test case and not the second?', 'Check the loop, are all the values being considered?']}, {'role': 'user', 'content': 'Yes, the first test case is correct, but the second one is wrong.'}, {'role': 'assistant', 'content': 'How are the two test cases different?', 'alt': ['Do you see any problems with the weights?', 'Do you see any problems with passing in the grades?', ""Check the instructions, do you see anything you aren't doing?"", 'Do you see any differences in the numbers between the two test cases?']}, {'role': 'user', 'content': 'The first test case has all the values the same, and the second test case has different values.', 'alt': ['The first test case has all 100s, but different numbers for the second case.', ""I'm not sure.""]}, {'role': 'assistant', 'content': 'Does the order of the input parameters matter?', 'alt': ['Why does the order matter?', 'Are any specific lines of code impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Which parameter represents homework?']}, {'role': 'user', 'content': 'Yes, the order of inputs does matter.'}, {'role': 'assistant', 'content': 'Why?', 'alt': ['Which lines are impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Look back at the instructions, what should the weight be for the first value?']}, {'role': 'user', 'content': 'Because that determines which value is associated with the different grade categories.'}, {'role': 'assistant', 'content': 'Why does that change the calculation?', 'alt': ['What is the correct weight for the homework?', 'On what line of code are those values assigned?', 'Are those values passed into the array in the proper order?']}, {'role': 'user', 'content': 'The type of grade changes the weight for the calculation.'}, {'role': 'assistant', 'content': 'What is the correct weight for homework?', 'alt': ['Look at the grades array, does it match the order the parameters are passed in?', 'Look at the weights array, does that match the order for the categories?', 'What do you think is causing the problem here?']}, {'role': 'user', 'content': 'Homework should have a weight of 20%.'}, {'role': 'assistant', 'content': 'How is that set in the code?', 'alt': ['What weight should exams have?', 'Look at the weights array, does that match the order for the categories?']}, {'role': 'user', 'content': ""It's set in the weights array."", 'alt': ['I see, the weights array is wrong!']}, {'role': 'assistant', 'content': 'Check the weights array, does the first item match the correct weight for homework?', 'alt': ['How does the weights array interact with the grades array?', 'Which item in the weights array should correspond with homework?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""No, the first item is 0.1, that's the weight for attendance."", 'alt': [""It's in the wrong order.""]}, {'role': 'assistant', 'content': 'What should you change the weights array to?', 'alt': ['Should the first item in the weights array go with the first item in the grades array?', 'Should the arrays be parallel?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""I'll switch the attendance and homework weights on line 2.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.3, 0.4, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Did that fix it?', 'alt': ['Is that everything?', 'Did you check the other weights?']}, {'role': 'user', 'content': ""No, it still doesn't work.""}, {'role': 'assistant', 'content': 'Keep looking, do you see any other problems with the weights array?', 'alt': ['Did which test cases pass change?', 'Does the first test case still pass?', 'What about the second item in the grades array, does it match with the second item in the weights array?', 'What is the correct weight for exams?']}, {'role': 'user', 'content': ""Yes, exams and projects are flipped too!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.4, 0.3, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Does it pass now?'}, {'role': 'user', 'content': 'Yes, all the test cases pass. Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = ""A""
+7.    elif roundedScore >= 80:
+8.        letterGrade = ""B""
+9.    elif roundedScore >= 70:
+10.        letterGrade = ""C""
+11.    elif roundedScore >= 60:
+12.        letterGrade = ""D""
+13.    else:
+14.        letterGrade = ""F""
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore > 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+   elif roundedScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.",Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.,"assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_8_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore > 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nWhen `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `roundedScore > 90` with `roundedScore >= 90` on line 4.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['What test cases are passing?', 'What test cases are failing?', 'Have you reread the prompt?', 'Have you checked the calculation for the grade?', 'Have you checked the if-statement?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's go through your function line by line, how can you check the calculation on line 2?"", 'alt': [""Let's start by looking at the test cases, what is the first one to fail?"", ""Let's start by looking at the test cases, does the first one pass?""]}, {'role': 'user', 'content': 'I can add a print statement to check the number.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    if roundedScore > 90:\n6.        letterGrade = ""A""\n7.    elif roundedScore >= 80:\n8.        letterGrade = ""B""\n9.    elif roundedScore >= 70:\n10.        letterGrade = ""C""\n11.    elif roundedScore >= 60:\n12.        letterGrade = ""D""\n13.    else:\n14.        letterGrade = ""F""\n15.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good, what is the first test case to fail?', 'alt': ['Good, does the first test case succeed?', 'Good, is the first `finalScore` correct?', 'Good, what is the first incorrect `finalScore`?']}, {'role': 'user', 'content': 'The second test case fails.'}, {'role': 'assistant', 'content': 'Is the `finalScore` correct for that test case?', 'alt': ['Do you think it is a rounding error?', 'What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?', 'How can you check if it is a rounding error?']}, {'role': 'user', 'content': 'Yes, the final score is correct for that test case.'}, {'role': 'assistant', 'content': 'How can you check if it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?']}, {'role': 'user', 'content': 'I can add another print statement after line 4 and check the rounding.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore > 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good. Do you think it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': ""No, I don't think so.""}, {'role': 'assistant', 'content': ""Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?"", 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': 'It checks if the rounded score is greater than 90.', 'alt': ['I see, it should be greater than or equal to!']}, {'role': 'assistant', 'content': 'Think about that carefully, would it return true or false if the grade was exactly 90?'}, {'role': 'user', 'content': 'No, it wouldn\'t! That\'s wrong, it should be greater than or equal to!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore >= 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Try running it again, does it work now?'}, {'role': 'user', 'content': 'Yes! It does. I\'ll remove the extra print statements.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good.'}, {'role': 'user', 'content': 'Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = ""A""
+6.    elif finalScore >= 80:
+7.        letterGrade = ""B""
+8.    elif finalScore >= 70:
+9.        letterGrade = ""C""
+10.    elif finalScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, finalScore","The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.","After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_9_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(100, 89, 85, 90) == (\'A\', 90)\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    if finalScore >= 90:\n4.        letterGrade = ""A""\n5.    elif finalScore >= 80:\n6.        letterGrade = ""B""\n7.    elif finalScore >= 70:\n8.        letterGrade = ""C""\n9.    elif finalScore >= 60:\n10.        letterGrade = ""D""\n11.    else:\n12.        letterGrade = ""F""\n13.    return letterGrade, finalScore\n</bug_code>\n<bug_desc>\nThe function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.\n</bug_desc>\n<bug_fixes>\nAfter line 2, add a new line with the following snippet `finalScore = round(finalScore)`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.""}, {'role': 'assistant', 'content': 'Where, in your code, do you think this problem is happening?', 'alt': ['Why do you expect the output of 69.6 to return D?', 'What do you think we can do to figure out where our problem is?']}, {'role': 'user', 'content': ""I think it's happening in the if-statements."", 'alt': [""I don't know where."", ""It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70."", ""I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.""]}, {'role': 'assistant', 'content': 'Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?', 'alt': ['Which condition in the if-statements is causing your problem?']}, {'role': 'user', 'content': ""Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way."", 'alt': ['I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.', 'I have no idea.', ""I don't really understand how if-statements work.""]}, {'role': 'assistant', 'content': ""That's a good point! What do you think you should do next?"", 'alt': ['Good observation! How would you round `finalScore`?']}, {'role': 'user', 'content': ""I need to round `finalScore`, but I don't know how to do that."", 'alt': ['I can use the `round()` method on the `finalScore`.', 'I can do`finalScore = round(finalScore)`', 'I can do `finalScore = finalScore.round()`']}, {'role': 'assistant', 'content': 'You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?', 'alt': [""If you don't know how to round a variable, do you have any idea where you could look to figure it out?""]}, {'role': 'user', 'content': 'Oh, wait. I found a round() function. If I don\'t specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    finalScore = round(finalScore)\n4.    if finalScore >= 90:\n5.        letterGrade = ""A""\n6.    elif finalScore >= 80:\n7.        letterGrade = ""B""\n8.    elif finalScore >= 70:\n9.        letterGrade = ""C""\n10.    elif finalScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, finalScore\n```', 'alt': ['I have no idea what method can help me.', ""I don't understand what a method is."", 'I could use `finalScore = round(finalScore, 2)`']}, {'role': 'assistant', 'content': 'Good work! You did it.'}]}"
+"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input ""English""?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, ""x"")
+      else:
+           sen = sen.replace(i, ""X"")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>","Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```","def toxNGLXSH(sen):
+ vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+ for i in vowels:
+     if i.islower():
+          sen.replace(i, ""x"")
+     else:
+          sen.replace(i, ""X"")
+ sen.swapcase()
+ return sen","On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.",Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.,"assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'",10_39_xnglxsh,"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+","{'system': '<problem>\nCreate a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with \'X\', each uppercase vowel is replaced with \'x\', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.\n\n## Example Cases:\n```\ntoxNGLXSH(\'English\') => \'xNGLXSH\'\ntoxNGLXSH(\'hello there!\') => \'HXLLX THXRX!\'\ntoxNGLXSH(""My name is John!"") => \'mY NXMX XS jXHN!\'\ntoxNGLXSH(\'To be or not to be!\') => \'tX BX XR NXT TX BX!\'\ntoxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') => \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n```\n</problem>\n<bug_code>\n1. def toxNGLXSH(sen):\n2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n3.  for i in vowels:\n4.      if i.islower():\n5.           sen.replace(i, ""x"")\n6.      else:\n7.           sen.replace(i, ""X"")\n8.  sen.swapcase()\n9.  return sen\n</bug_code>\n<bug_desc>\nOn lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.\n</bug_desc>\n<bug_fixes>\nReplace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.\n</bug_fixes>\n<unit_tests>\nassert toxNGLXSH(\'English\') == \'xNGLXSH\'\nassert toxNGLXSH(\'hello there!\') == \'HXLLX THXRX!\'\nassert toxNGLXSH(""My name is John!"") == \'mY NXMX XS jXHN!\'\nassert toxNGLXSH(\'To be or not to be!\') == \'tX BX XR NXT TX BX!\'\nassert toxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') == \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Help! I wrote a lot of code and nothing is working.'}, {'role': 'assistant', 'content': ""I'm here to help. Can you describe the problem you are having?"", 'alt': ['Can you walk me through your code line by line?', 'Let\'s start with a simple example. What is the output of your code when you run it with the input ""English""?', 'What does the `.replace()` method do?', 'What does the `.swapcase()` method do?']}, {'role': 'user', 'content': ""I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?""}, {'role': 'assistant', 'content': 'What are some reasons it could be staying the same?', 'alt': ['What does the `.replace()` method do and does it modify the original string?', 'What does the `.swapcase()` method do and does it modify the original string?']}, {'role': 'user', 'content': 'If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.', 'alt': [""I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.""]}, {'role': 'assistant', 'content': 'Let\'s open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?', 'alt': ['Let\'s open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?']}, {'role': 'user', 'content': 'Ok, I tried that, and it looks like it returns the modified string I expect `TX`.', 'alt': ['Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.']}, {'role': 'assistant', 'content': 'Good. Now let\'s try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?', 'alt': [""Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?""]}, {'role': 'user', 'content': 'Ah. It looks like the string methods don\'t modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.\n```python\ndef toxNGLXSH(sen):\n  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n  for i in vowels:\n      if i.islower():\n           sen = sen.replace(i, ""x"")\n      else:\n           sen = sen.replace(i, ""X"")\n  sen = sen.swapcase()\n  return sen\n```'}, {'role': 'assistant', 'content': 'That looks good! Why do you think it worked?'}, {'role': 'user', 'content': ""It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.""}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>","Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```","def is_palindrome(string):
+ rev_string = ''
+ for i in string:
+   rev_string = i + rev_string
+ if rev_string = string:
+   return True
+ else:
+   return False","On line 5, the function throws a syntax error.",Replace `=` with `==` on line 5.,"assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True",11_40_palindrome,"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.\n## Example Cases:\n```\nis_palindrome(""racecar"") => True\nis_palindrome(""hello"") => False\nis_palindrome(""hannah"") => True\nis_palindrome(""firetruck"") => False\nis_palindrome(""nice"") => False\nis_palindrome("""") => True\n```\n</problem>\n<bug_code>\n1. def is_palindrome(string):\n2.  rev_string = \'\'\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string = string:\n6.    return True\n7.  else:\n8.    return False\n</bug_code>\n<bug_desc>\nOn line 5, the function throws a syntax error.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on line 5.\n</bug_fixes>\n<unit_tests>\nassert is_palindrome(""racecar"") == True\nassert is_palindrome(""hello"") == False\nassert is_palindrome(""hannah"") == True\nassert is_palindrome(""firetruck"") == False\nassert is_palindrome(""nice"") == False\nassert is_palindrome("""") == True\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey! I have a compiler error here.'}, {'role': 'assistant', 'content': 'Ok, what error do you see?', 'alt': [""Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?"", 'What line is the compiler error pointing towards?']}, {'role': 'user', 'content': ""It's giving me an error on my equality operator use.""}, {'role': 'assistant', 'content': 'I see. How do you assign a value of 1 to a variable `x`?', 'alt': ['How do you assign an empty string to the variable `rev_string`?', 'How would you check if two  variables `x` and `y` are equivalent?', 'Can you recall what the assignment operator is?']}, {'role': 'user', 'content': 'I use the `=` operator.'}, {'role': 'assistant', 'content': 'What are you trying to do in line 5?', 'alt': ['How would you check if  two variables `x` and `y` are equivalent?']}, {'role': 'user', 'content': 'I am trying to check if `rev_string` is equal to `string`', 'alt': ['Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.']}, {'role': 'assistant', 'content': ""You used `=` for variable assignment. Shouldn't there be a different operator for equality?"", 'alt': [""Let's check the documentation. What is the operator for equality?"", 'Are you sure that `=` checks for equality? How can we verify that?', 'If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?']}, {'role': 'user', 'content': ""I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.\n```python\n1. def is_palindrome(string):\n2.  rev_string = ''\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string == string:\n6.    return True\n7.  else:\n8.    return False\n```""}, {'role': 'assistant', 'content': 'Looks good!'}, {'role': 'user', 'content': 'Thank you so much!'}]}"
+"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>","Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```","def reverse_list(lst):
+   return lst[-1:]","On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.",Replace `return lst[-1:]` with `return lst[::-1]` on line 2.,"assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]",12_41_reversing_a_list,"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.\n## Example Cases:\n```\nreverse_list([1, 2, 3]) => [3, 2, 1]\nreverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]\nreverse_list([]) => []\nreverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]\n```\n</problem>\n<bug_code>\n1. def reverse_list(lst):\n2.    return lst[-1:]\n</bug_code>\n<bug_desc>\nOn line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.\n</bug_desc>\n<bug_fixes>\nReplace `return lst[-1:]` with `return lst[::-1]` on line 2.\n</bug_fixes>\n<unit_tests>\nassert reverse_list([1, 2, 3]) == [3, 2, 1]\nassert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]\nassert reverse_list([]) == []\nassert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to reverse the elements of a list but it's not working.""}, {'role': 'assistant', 'content': ""Can you describe how you're trying to reverse the list?"", 'alt': [""Can you describe the problem you're having in more detail?"", ""Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?"", ""Let's start with a warm-up question. What does the slicing operator `[-1:]` do?"", 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?', 'Where can you learn more about how to reverse a list?']}, {'role': 'user', 'content': 'Sure, I used the `[-1:]` slicing operator.'}, {'role': 'assistant', 'content': 'Can you describe what the `[-1:]` slicing operator does?', 'alt': ['How do you think this reverses the list?', ""Do you notice a pattern in your function's outputs?"", 'How does slicing work in Python?', 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?']}, {'role': 'user', 'content': ""I think it should return a list in reverse order but it's returning the last element of the list instead."", 'alt': ['The `[-1:]` slicing operator should return a list in reverse order.']}, {'role': 'assistant', 'content': ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'alt': [""Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?"", 'Good. So where can you learn more about how to reverse a list?', ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?']}, {'role': 'user', 'content': ""I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.\n```python\n def reverse_list(lst):\n    return lst[::-1]\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you run into any other problems!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```","def limitFinder(lst, limit):
+ lst2 = []
+ for i in lst2:
+   if i < limit:
+     lst2.append(i)
+ return lst2","On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.",Replace `lst2` with `lst` on line 3.,"assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []",13_42_limit,"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+","{'system': '<problem>\nWrite a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.\n## Example Cases:\n```\nlimitFinder([1, 2, 3, 4, 5], 3) => [1, 2]\nlimitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]\nlimitFinder([100, 2, 145, 3,8], 0) => []\nlimitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]\nlimitFinder([], 0) => []\n```\n</problem>\n<bug_code>\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst2:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n</bug_code>\n<bug_desc>\nOn line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.\n</bug_desc>\n<bug_fixes>\nReplace `lst2` with `lst` on line 3.\n</bug_fixes>\n<unit_tests>\nassert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]\nassert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]\nassert limitFinder([100, 2, 145, 3,8], 0) == []\nassert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]\nassert limitFinder([], 0) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My program seems to always return an empty list instead of a list of numbers, can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you walk me through what each line does?', 'alt': ['Sure. Can you tell me which list are you supposed to find the numbers from?', 'Sure, can you explain what line 3 does?', 'Sure. It looks like your for-loop is never executed. Do you know why?']}, {'role': 'user', 'content': 'Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.'}, {'role': 'assistant', 'content': 'Ok, what about the next line?'}, {'role': 'user', 'content': 'Line 3 - loops through all the numbers in `lst2`', 'alt': ['It looks like line 3 loops through the wrong list! Is that the issue here?']}, {'role': 'assistant', 'content': 'How many numbers are in `lst2`?', 'alt': ['Will the for loop ever be executed?', 'Is `lst2` empty?', 'How many times will the for loop execute?', 'Is that the list that you want to loop through?']}, {'role': 'user', 'content': '`Oh I see, `lst2` is empty, so the for loop is never executed.'}, {'role': 'assistant', 'content': 'Correct, how would you fix your for loop now?'}, {'role': 'user', 'content': 'Should I be looping over `lst` instead?'}, {'role': 'assistant', 'content': 'Yes, what does the new code look like?'}, {'role': 'user', 'content': 'This code works, thank you!\n```python\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = ""True""
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>","Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```","def isTwice(str, chr):
+ count = 0
+ for i in str:
+   if i == chr:
+     count+=1
+
+ if count >= 2:
+   return true
+ else:
+   return false","On line 8, the function throws a NameError since `true` is not a boolean value.",Replace `true` with `True` and `false` with `False` on lines 8 and 10.,"assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False",14_43_used_twice,"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+","{'system': '<problem>\nWrite a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.\n## Example Cases:\n```\nisTwice(""hello"", ""l"") => True\nisTwice(""hello"", ""o"") => False\nisTwice(""hello"", ""h"") => False\nisTwice("""", ""e"") => False\nisTwice(""I\'m a string!"", "" "") => True\nisTwice(""Hey, I\'m a string!"", "" "") => False\n```\n</problem>\n<bug_code>\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return true\n9.  else:\n10.    return false\n</bug_code>\n<bug_desc>\nOn line 8, the function throws a NameError since `true` is not a boolean value.\n</bug_desc>\n<bug_fixes>\nReplace `true` with `True` and `false` with `False` on lines 8 and 10.\n</bug_fixes>\n<unit_tests>\nassert isTwice(""hello"", ""l"") == True\nassert isTwice(""hello"", ""o"") == False\nassert isTwice(""hello"", ""h"") == False\nassert isTwice("""", ""e"") == False\nassert isTwice(""I\'m a string!"", "" "") == True\nassert isTwice(""Hey, I\'m a string!"", "" "") == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I wrote this code and it isn't working. can you help me?""}, {'role': 'assistant', 'content': ""First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?"", 'alt': ['It seems that you have a `NameError` error in your code. Are you able to find where this error is?', 'Let\'s talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?', ""Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?""]}, {'role': 'user', 'content': ""I have a syntax error. My code won't even compile."", 'alt': [""I think it's a runtime error because it just stopped running."", ""Can you tell me what the different types of errors are? I don't remember."", ""It's a logic error, I think. That's the one that is the result of a grammatical error, right?""]}, {'role': 'assistant', 'content': ""I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?"", 'alt': [""Can you write a code snippet of assigning `False` to a boolean variable called 'var'?"", 'Where is the syntax error located in your code? You look for the line number.', 'How do you know that it is a syntax error? What are the different types of errors?']}, {'role': 'user', 'content': '`var = True`', 'alt': ['`var = true`', 'var = 1', 'var = ""True""']}, {'role': 'assistant', 'content': ""That's right. Is this what you wrote in your code on line 8?"", 'alt': [""That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?"", 'Can you point out in your code where you use boolean variables?']}, {'role': 'user', 'content': ""No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead."", 'alt': [""The code would get a syntax error and it wouldn't run."", ""I'm not sure what you are asking.""]}, {'role': 'assistant', 'content': ""That's right! How can you modify your `isTwice` function now to fix this error?""}, {'role': 'user', 'content': 'Oh! I found it! I was returning all lowercase True and False values! I will fix it.\n```python\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return True\n9.  else:\n10.    return False\n```'}, {'role': 'assistant', 'content': 'Looks like it works now. Good job!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x <= seq[i]:
+     return i",The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.,"Insert a line following line 4, with one indentation containing `return len(seq)`","assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_45_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n</bug_code>\n<bug_desc>\nThe function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.\n</bug_desc>\n<bug_fixes>\nInsert a line following line 4, with one indentation containing `return len(seq)` \n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output.'}, {'role': 'assistant', 'content': 'What inputs have you tried? When do you get `None`?', 'alt': ['Do you notice a pattern with the cases that produce `None`?', 'When do you notice `None` as the output?', 'What inputs have you tried? When do you get `None`?', 'It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?']}, {'role': 'user', 'content': 'I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.', 'alt': ['I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list', 'It seems like I get the wrong answer when `x` is bigger than all the existing list elements']}, {'role': 'assistant', 'content': 'Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?', 'alt': ['Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?', 'What do you expect your code to return when `x` is bigger than the `seq` elements?']}, {'role': 'user', 'content': 'Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.'}, {'role': 'assistant', 'content': 'What happens if `x` is not less than or equal to any element?', 'alt': ['What does your code do if `x` is greater than all of the elements in `seq`?']}, {'role': 'user', 'content': ""I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!\n```python\n def search(x, seq):    \n  for i in range(len(seq)):\n    if x <= seq[i]:\n      return i\n  return len(seq)\n```""}, {'role': 'assistant', 'content': 'Good work. Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x < seq[i]:
+     return i
+ return len(seq)","On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.",Replace `<` with `<=` on line 3,"assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_44_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x < seq[i]:\n4.      return i\n5.  return len(seq)\n</bug_code>\n<bug_desc>\nOn line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.\n</bug_desc>\n<bug_fixes>\nReplace `<` with `<=` on line 3\n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?""}, {'role': 'assistant', 'content': 'Sure. In the first test case, can you explain why the correct returned value should be 1?', 'alt': ['Sure. Can you tell me if you notice any difference between the first test case and the other test cases?', 'Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?', ""Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?""]}, {'role': 'user', 'content': 'The correct answer is 1 because 5 is found at position 1 in the input list.'}, {'role': 'assistant', 'content': 'Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?', 'alt': ['Good. What does your code do when position `i = 1`?']}, {'role': 'user', 'content': 'Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!\n```python\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n5.  return len(seq)\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could help.""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       max_len = max(len(crt_str), max_len)        
+
+       pos = s.find(t, start)
+   
+   last_str = s[start:]
+   max_len = max(len(last_str), max_len)
+
+   return max_len","The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.",On line 8 insert the code `start = pos + len(t)`.,"assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_56_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n</bug_code>\n<bug_desc>\nThe value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.\n</bug_desc>\n<bug_fixes>\nOn line 8 insert the code `start = pos + len(t)`.\n</bug_fixes>\nOn line 11 insert a new line with `ind += len(t)`.\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code does not stop and I do not understand why, can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?"", 'alt': ['Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.', 'Sure. Can you tell me the role of the variable `start`?']}, {'role': 'user', 'content': 'In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.        start = pos + len(t)\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       crt_len = len(crt_str)
+       if crt_len > max_len:
+           max_len = crt_len
+       start = pos + len(t)
+       pos = s.find(t, start)
+   return max_len","The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.","After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```","assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_46_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    return max_len\n</bug_code>\n<bug_desc>\nThe code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.\n</bug_desc>\n<bug_fixes>\nAfter line 11, insert the following outside the while loop scope:\n```py\nlast_str = s[start:]\nlast_len = len(last_str)\nif last_len > max_len:\n       max_len = last_len\n```\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?'}, {'role': 'assistant', 'content': 'I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?', 'alt': ['Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?', 'Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?', 'Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?', ""Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?"", 'Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?', 'Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?']}, {'role': 'user', 'content': '`max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.'}, {'role': 'assistant', 'content': ""Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?"", 'alt': ['Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?', 'Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?', 'Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?']}, {'role': 'user', 'content': 'Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    \n13.    last_str = s[start:]\n14.    last_len = len(last_str)\n15.    if last_len > max_len:\n16.       max_len = last_len\n17.    \n18.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>","Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```","def top_k(lst, k):
+   result = []
+   for i in range(k):
+       result.append(max(lst))
+       lst.pop(max(lst))
+   return result","The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.","On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`","assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]",17_47_topk,"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.\n## Example Cases:\n```\ntop_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]\ntop_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]\ntop_k([], 0) => []\ntop_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]\ntop_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]\n```\n</problem>\n<bug_code>\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.pop(max(lst))\n6.    return result\n</bug_code>\n<bug_desc>\nThe function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.\n</bug_desc>\n<bug_fixes>\nOn line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`\n</bug_fixes>\n<unit_tests>\nassert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]\nassert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]\nassert top_k([], 0) == []\nassert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]\nassert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi. I am confused. My code doesn’t seem to work. Can you help?'}, {'role': 'assistant', 'content': ""Hello. Sure, let's see. Do you know what might be the issue?""}, {'role': 'user', 'content': 'I think the problem is with the `.pop()` method. It seems to have issues with indexing.', 'alt': ['When I use the `.pop()` method, I get an IndexError on some inputs.', ""For some inputs, I get an error and other inputs don't produce the right answer.""]}, {'role': 'assistant', 'content': ""Ok, no worries. Let's review your code line by line. Could you please explain it to me?"", 'alt': [""Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?"", ""Let's start with a warm-up question. What does the `.pop()` method do?"", ""Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?"", 'Could you please explain what line 5 in your code does?', 'Let’s look into the Python documentation. Can you describe what the `.pop()` method does?']}, {'role': 'user', 'content': 'Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.'}, {'role': 'assistant', 'content': 'Good. What can you do right now to debug your code and diagnose what might be causing the problem?'}, {'role': 'user', 'content': 'Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(max(lst))\n6.        lst.pop(max(lst))\n7.        print(lst)\n8.    return result\n```', 'alt': ['I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.']}, {'role': 'assistant', 'content': 'Are there other ways of debugging the `.pop()` method?', 'alt': ['What happens if you use a different input value for the `top_k()` function?', 'Have you considered using the debugger?', 'What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?']}, {'role': 'user', 'content': 'Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(lst)\n6.        lst.pop(1)\n7.        print(lst)\n8.    return result \n```'}, {'role': 'assistant', 'content': 'Perhaps there are other solutions you can use aside from `.pop()`?', 'alt': ['Where can we learn more about other list methods that can help us remove elements from an array?', 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?']}, {'role': 'user', 'content': ""I think but I can't remember them...""}, {'role': 'assistant', 'content': 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?'}, {'role': 'user', 'content': 'Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.remove(max(lst))\n6.    return result\n```'}, {'role': 'assistant', 'content': 'Great! Please let me know if you need help with anything else.'}]}"
+"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `""a""`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don't think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return ""Password added!""
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>","Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```","def validate_or_add_password(menu_choice, password, passwords_dict):
+   if menu_choice == ""v"":
+       if password in passwords_dict.values():
+           return ""Welcome!""
+       else:
+           return ""I don't know you.""
+   elif menu_choice == ""a"":
+       if password in passwords_dict.values():
+           return ""Password already exists!""
+       else:
+           return ""Password added!""",The function does not add `password` to `passwords_dict` as specified in the instructions.,After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`,"passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""",18_48_password_validator,"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+","{'system': '<problem>\nCreate a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:\n* `menu_choice (str)`: either \'v\' for validate or \'a\' for add password\n* `password (str)`: the password to be validated or added\n* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords\n\nThe function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is \'v\'. If the password is not found in the dictionary, the function returns ""I don\'t know you."". If menu_choice is \'a\', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".\n## Example Cases:\n```\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nvalidate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""\nvalidate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don\'t know you.""\nvalidate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""\npasswords_dict[4] => ""newpass""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""\n```\n</problem>\n<bug_code>\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            return ""Password added!""\n</bug_code>\n<bug_desc>\nThe function does not add `password` to `passwords_dict` as specified in the instructions.\n</bug_desc>\n<bug_fixes>\nAfter line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`\n</bug_fixes>\n<unit_tests>\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nassert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""\nassert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don\'t know you.""\nassert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""\nassert passwords_dict[4] == ""newpass""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello. I need help with my code.', 'alt': [""I need help with this code. It's throwing a `KeyError`. I'm not sure why.""]}, {'role': 'assistant', 'content': 'Can you describe the issue you are experiencing?', 'alt': ['Can you walk me through what your code does line by line when `menu_choice` is `""a""`?', 'Let\'s go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?']}, {'role': 'user', 'content': 'I am getting a `KeyError: 4`. Not really sure why.', 'alt': [""My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.""]}, {'role': 'assistant', 'content': ""Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?"", 'alt': ['What does `KeyError` typically mean and why does it occur?', ""Let's look at the example cases, where do you see `4` being used as a key?"", ""Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?"", ""Let's look at your error again. What line is throwing the `KeyError`?"", 'Which parameter in the `validate_or_add_password` function is a data structure that uses keys?']}, {'role': 'user', 'content': 'After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.'}, {'role': 'assistant', 'content': ""Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?"", 'alt': ['Good. Which test case do you think is causing the `KeyError`?', ""Let's look at your error again. What line is throwing the `KeyError`?""]}, {'role': 'user', 'content': 'Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.', 'alt': ['Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.']}, {'role': 'assistant', 'content': 'Good. What is the statement right before line 18 attempting to do?'}, {'role': 'user', 'content': 'Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don\'t think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.\n```python\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            passwords_dict[len(passwords_dict) + 1] = password\n12.            return ""Password added!""\n```'}, {'role': 'assistant', 'content': 'Good. Does your code pass all the example cases?'}, {'role': 'user', 'content': 'Yes it does thank you for your help. I learned more about `KeyError`s today.'}, {'role': 'assistant', 'content': ""You're welcome to let me know if I can be of any further assistance.""}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for i in range(1, len(sentence)):
+       if sentence[i] == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   if not space_mode:
+       words +=1
+   return words","On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.","On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_49_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for i in range(1, len(sentence)):\n5.        if sentence[i] == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    if not space_mode:\n12.        words +=1\n13.    return words\n</bug_code>\n<bug_desc>\nOn line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `(1, len(sentence))` with `(len(sentence)):`\nOn line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am having a problem with this programming problem. My count seems off.'}, {'role': 'assistant', 'content': 'Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?', 'alt': ['Are there specific inputs that give you the wrong answer or is it always wrong?', 'Off in what way?']}, {'role': 'user', 'content': 'Yes! My output seems to be 1 less than it should be.', 'alt': ['My output is sometimes correct and sometimes lower than it should be']}, {'role': 'assistant', 'content': 'Does this happen with all inputs or just some inputs?'}, {'role': 'user', 'content': 'I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.']}, {'role': 'assistant', 'content': 'Can you check how your function handles the beginning of the input? It seems like the issue might be there.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'Where do you count your first word?']}, {'role': 'user', 'content': ""Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for i in range(len(sentence)):\n        if sentence[i] == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great!'}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for c in sentence:
+       if c == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   return words",There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.,"Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_50_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for c in sentence:\n5.        if c == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    return words\n</bug_code>\n<bug_desc>\nThere is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.\n</bug_desc>\n<bug_fixes>\nInsert the following after line 10 outside the scope of the for loop:\n```py\nif not space_mode:\n     words +=1\n```\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm writing some code to count words and it doesn't seem to be working""}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': [""Let's walk through your code line by line. Can you explain what your code does?"", 'When you run your code, what do you observe?']}, {'role': 'user', 'content': 'My output counts are off by one.'}, {'role': 'assistant', 'content': 'Hm, ok. Can you walk me through your code?', 'alt': ['Does this happen with all inputs?', 'Can you give me an example input where this happens? Include what you expect and what you get.']}, {'role': 'user', 'content': 'Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.'}, {'role': 'assistant', 'content': 'Ok. What happens when you reach the end of the sentence?', 'alt': ['Does your loop count the last word in the sentence?']}, {'role': 'user', 'content': ""Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for c in sentence:\n        if c == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thank you so much for your help!'}]}"
+"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>","Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```","def split (cookies, people):
+ if cookies % people == 0:
+   return (cookies // people, 0, ""Cookies can be split evenly!"")
+ else:
+   newCookies = cookies - (cookies % people)
+   return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")","On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.","Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.","assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")",2_18_splitting_cookies,"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.\n\n## Example Cases:\n```\nsplit(10, 2) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nsplit(20, 4) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 5) => (2, 0, ""Cookies can be split evenly!"")\nsplit(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n```\n</problem>\n<bug_code>\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    newCookies = cookies - (cookies % people)\n6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n</bug_code>\n<bug_desc>\nOn line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.\n</bug_desc>\n<bug_fixes>\nReplace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.\nReplace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.\nRemove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.\n</bug_fixes>\n<unit_tests>\nassert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nassert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")\nassert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello I need help with my code, it is not giving me the output I expect.'}, {'role': 'assistant', 'content': ""Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?"", 'alt': [""Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?"", 'Sure, have you tried the test cases as inputs? What have you observed about the output?', ""Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?"", ""Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?"", ""Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?""]}, {'role': 'user', 'content': 'For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, \'Cookies cannot be split evenly. Bought more cookies.\')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.', 'alt': ['My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.', 'I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.', 'I need `cookies` to be a multiple of the `people` to get the right answer.']}, {'role': 'assistant', 'content': ""Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?"", 'alt': ['Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?', 'How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?']}, {'role': 'user', 'content': 'So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well\n```python\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    leftOverCookies = cookies % people\n6.    newCookies = people - leftOverCookies + cookies\n7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n```', 'alt': ['Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now']}, {'role': 'assistant', 'content': 'Sounds good! Let me know if you need any more help.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>","Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```","def spellchecker(words, words_to_check):
+   result = []
+   for word in words_to_check:
+       if word in words:
+           result.append(word + "" is spelled properly!"")
+       else:
+           result.append(word + "" is misspelled!"")",The function returns `None` instead of an iterable of strings.,"After line 7, insert `return result` with one indentation level.","assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']",20_51_spell_checker,"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+","{'system': '<problem>\nWrite a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.\n## Example Cases:\n```\nlist(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nlist(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nlist(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) => [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nlist(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) => [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n```\n</problem>\n<bug_code>\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n</bug_code>\n<bug_desc>\nThe function returns `None` instead of an iterable of strings.\n</bug_desc>\n<bug_fixes>\nAfter line 7, insert `return result` with one indentation level.\n</bug_fixes>\n<unit_tests>\nassert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nassert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nassert list(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) == [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nassert list(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) == [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of the test cases passing?', 'Have you completed all the steps in the instructions?', ""Let's look at your function, can you explain what it is supposed to do?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Can you explain what your function is supposed to do?', 'alt': ['Do any of the test cases pass?', 'Have you skipped any steps in the instructions?']}, {'role': 'user', 'content': 'My function takes in one list of words and compares it to another list.', 'alt': ['My function compares two lists of words and then returns information about them.', 'I followed the prompt.']}, {'role': 'assistant', 'content': 'Okay, on what line of code does it take in those lists of words?', 'alt': ['Does it do anything else?', 'Is that everything it is supposed to do according to the prompt?', ""Let's look at the first line of the function on line 1, does it take in two lists of words?""]}, {'role': 'user', 'content': 'On line 1.'}, {'role': 'assistant', 'content': 'Does that line take in those lists?', 'alt': ['Do you see any problems on that line?', 'What should your function do after taking in those lines?']}, {'role': 'user', 'content': 'Yes, it does.'}, {'role': 'assistant', 'content': 'Okay, so what is the next thing your function is supposed to do?', 'alt': [""Let's check the loops where we compare the lists, what line do those start on?"", 'How does your function compare the lists?']}, {'role': 'user', 'content': ""It's supposed to compare the two lists and say if the word is spelled wrong.""}, {'role': 'assistant', 'content': 'Where is it supposed to put the information about the spelling?', 'alt': ['How does it determine if the word is spelled wrong?', ""Let's examine the loop, what line does it start on?""]}, {'role': 'user', 'content': 'In a list called result.'}, {'role': 'assistant', 'content': ""Let's examine that list, where is it created?"", 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?""]}, {'role': 'user', 'content': 'On line 2.'}, {'role': 'assistant', 'content': 'What happens to that list next?', 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?"", 'Do we do anything with that list after we finish adding to it?']}, {'role': 'user', 'content': 'We add strings to it for if the word is spelled right.'}, {'role': 'assistant', 'content': ""Do we do anything else to it after we've finished with the loop?"", 'alt': ['How would that information be sent out of the function?', 'What information is supposed to be returned from the function?']}, {'role': 'user', 'content': ""No, we don't."", 'alt': ['I forgot to return result!']}, {'role': 'assistant', 'content': 'How can that information be used outside of this function?', 'alt': ['What information is supposed to be returned from the function?']}, {'role': 'user', 'content': 'I need to return result.\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.        return result\n```'}, {'role': 'assistant', 'content': 'Does it work now?'}, {'role': 'user', 'content': ""No, it doesn't.""}, {'role': 'assistant', 'content': 'Is it passing any of the test cases?', 'alt': ['Look at what you added, why did you put it there?', 'Look at what you added, when should this happen?']}, {'role': 'user', 'content': 'No, but the message changed to Assertion error.'}, {'role': 'assistant', 'content': ""Okay, let's look back at what you added. When should that code run?"", 'alt': [""Let's look at what you added. Should it be inside or outside the for-loop?""]}, {'role': 'user', 'content': 'Oh! I put it inside the loop!\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.    return result\n```'}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It's not freezing!"" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the ""<"" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the ""less than"" operator. It compares `c` to 0.
+	<alt>That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the ""<="" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns ""It's not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".
+	<alt>Oh... I see the problem now. I don't want to return ""It's not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".
+Assistant: Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the ""<="" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</code>
+Assistant: Good work!
+</dialogue>","Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```","def fToC(temp):
+ c = (temp - 32) * (5/9)
+ if c < 0:
+   return ""Freezing!""
+ else:
+   return ""It's not freezing!""","If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""","On line 3, change `<` to `<=`.","assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""",21_52_fahrenheit_to_celsius_converter,"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It\'s not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \\frac{5}{9}$. Note that the function should return a string, not a float.\n## Example Cases:\n```\nfToC(32.0) => ""Freezing!""\nfToC(0.5) => ""Freezing!""\nfToC(45.0) => ""It\'s not freezing!""\nfToC(-5.4) == ""Freezing!""\n```\n</problem>\n<bug_code>\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c < 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n</bug_code>\n<bug_desc>\nIf `temp` is equal to 32, the function returns ""It\'s not freezing!"" rather than ""Freezing!""\n</bug_desc>\n<bug_fixes>\nOn line 3, change `<` to `<=`.\n</bug_fixes>\n<unit_tests>\nassert fToC(32.0) == ""Freezing!""\nassert fToC(0.5) == ""Freezing!""\nassert fToC(45.0) == ""It\'s not freezing!""\nassert fToC(-5.4) == ""Freezing!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'There is an issue with my code.'}, {'role': 'assistant', 'content': 'Can you describe the issue to me?', 'alt': [""Let's assume that `temp` is 32. Can you explain your code to me line by line?""]}, {'role': 'user', 'content': 'My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It\'s not freezing!"" Why is that happening?'}, {'role': 'assistant', 'content': 'Let\'s take a look at the if-statement block. Do you remember what the ""<"" operator does?', 'alt': [""Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?""]}, {'role': 'user', 'content': 'That is the ""less than"" operator. It compares `c` to 0.', 'alt': ['That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.']}, {'role': 'assistant', 'content': 'Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?', 'alt': ['Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?', 'Can you explain what the ""<="" operator does?']}, {'role': 'user', 'content': 'When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.'}, {'role': 'assistant', 'content': 'Good. Could you explain what happens when `c` is equal to 0 on line 3?', 'alt': ['Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'Good. Now on line 3, what should your function return if `c` is equal to 0?']}, {'role': 'user', 'content': 'The function returns ""It\'s not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".', 'alt': ['Oh... I see the problem now. I don\'t want to return ""It\'s not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".']}, {'role': 'assistant', 'content': 'Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'alt': [""Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.""]}, {'role': 'user', 'content': 'I should use the ""<="" operator! Let me try that.\n```python\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c <= 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n```'}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {""discount"": discount, ""price"": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>","Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```","def cookiePurchase(cookies):
+   price = cookies * 1.75
+   discount = 0
+   if cookies > 10 and cookies / 10 == 0:
+       discount = price * 0.1
+       price = price - discount
+   return {""discount"": discount, ""price"": price}","On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.","On line 4, replace `/` with `%` and on line 4.","assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}",22_53_cookie_purchase,"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+","{'system': '<problem>\nWrite a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.\n## Example Cases:\n```\ncookiePurchase(2) => {\'discount\': 0.0, \'price\': 3.5}\ncookiePurchase(70) => {\'discount\': 12.25, \'price\': 110.25}\ncookiePurchase(22) => {\'discount\': 0.0, \'price\': 38.5}\ncookiePurchase(10) => {\'discount\': 0.0, \'price\': 17.5}\ncookiePurchase(20) => {\'discount\': 3.5, \'price\': 31.5}\n```\n</problem>\n<bug_code>\n1. def cookiePurchase(cookies):\n2.    price = cookies * 1.75\n3.    discount = 0\n4.    if cookies > 10 and cookies / 10 == 0:\n5.        discount = price * 0.1\n6.        price = price - discount\n7.    return {""discount"": discount, ""price"": price}\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `/` with `%` and on line 4.\n</bug_fixes>\n<unit_tests>\nassert cookiePurchase(2) == {\'discount\': 0, \'price\': 3.5}\nassert cookiePurchase(70) == {\'discount\': 12.25, \'price\': 110.25}\nassert cookiePurchase(22) == {\'discount\': 0, \'price\': 38.5}\nassert cookiePurchase(10) == {\'discount\': 0, \'price\': 17.5}\nassert cookiePurchase(20) == {\'discount\': 3.5, \'price\': 31.5}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm having a problem with my code"", 'alt': ['Hi! My code seems to sometimes give answers that are very off.']}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': ['Can you walk me through your function line by line?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you check if a number is divisible by 10?""]}, {'role': 'user', 'content': ""My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.""}, {'role': 'assistant', 'content': ""Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?"", 'alt': [""Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?"", ""Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?"", ""Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?""]}, {'role': 'user', 'content': ""First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.""}, {'role': 'assistant', 'content': 'Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?', 'alt': ['What operator should you use to check whether a number is a multiple of 10?', 'Where can you learn more about Python operators?\t']}, {'role': 'user', 'content': 'Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...'}, {'role': 'assistant', 'content': ""Let's take a look at the Python documentation to see if there is a different operator that does what you want."", 'alt': ['Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Oh, interesting. The modulus operator seems to fit. I\'ll modify my code and see if it works. It looks like it does!\n```python\n def cookiePurchase(cookies):\n    price = cookies * 1.75\n    discount = 0\n    if cookies > 10 and cookies % 10 == 0:\n        discount = price * 0.1\n        price = price - discount\n    return {""discount"": discount, ""price"": price}\n```'}, {'role': 'assistant', 'content': 'Great! Glad to help.'}, {'role': 'user', 'content': 'Thank you very much!'}]}"
+"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```","def factorial(n):
+       if n < 0:
+               return 0
+       fact = 1
+       for i in range(n):
+               fact = fact * i
+       return fact","On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n","Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.","assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120",24_29_factorial,"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+","{'system': '<problem>\nWrite a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:\n\n$0! = 1$\n$n! = n \\times (n - 1)!$\n\nAdditionally, if the input integer n is negative the function should return 0.\n\n## Example Cases:\n```\nfactorial(-1) => 0\nfactorial(0) => 1\nfactorial(1) => 1\nfactorial(2) => 2\nfactorial(3) => 6\nfactorial(4) => 24\nfactorial(5) => 120\n```\n</problem>\n<bug_code>\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * i\n7.        return fact\n</bug_code>\n<bug_desc>\nOn line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n\n\n</bug_desc>\n<bug_fixes>\nReplace `i` with `(i + 1)` in line 6.\nReplace `range(n)` with `range(1, n + 1)` in line 5.\n</bug_fixes>\n<unit_tests>\nassert factorial(-1) == 0\nassert factorial(0) == 1\nassert factorial(1) == 1\nassert factorial(2) == 2\nassert factorial(3) == 6\nassert factorial(4) == 24\nassert factorial(5) == 120\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?'}, {'role': 'user', 'content': 'For `n = 1` or larger it returns the same value, 0.'}, {'role': 'assistant', 'content': 'Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?', 'alt': ['Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?', 'Can you tell me what `range(n)` does?']}, {'role': 'user', 'content': 'The first value assigned to `i` will be 1.', 'alt': ['Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.']}, {'role': 'assistant', 'content': 'Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?', 'alt': ['Can you explain why `i` will be equal to 1 during the first iteration of the for loop?', 'Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?']}, {'role': 'user', 'content': 'I don’t know, how can I verify that?', 'alt': ['OK, let me print its value at each iteration.', 'OK, let me check in the Python documentation what range does.']}, {'role': 'assistant', 'content': 'Can you edit the code to print the value of `i` at each iteration of the for loop?', 'alt': ['Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?', 'Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?', 'Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?', 'Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?']}, {'role': 'user', 'content': 'Sure … Aaah, I see, the first value is 0, not 1!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i\n8.        return fact\n```', 'alt': ['How do I do that?']}, {'role': 'assistant', 'content': 'How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?', 'alt': ['Why do you think the first value is 0?', 'Good! Can you explain how that makes the function return 0 for n = 1 or larger?', 'Good! What can you do now to fix the issue?']}, {'role': 'user', 'content': 'I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i + 1\n8.        return fact\n```', 'alt': ['I can change it to `range(1, n + 1)` so that it starts iterating at 1.', 'I can change it to `range(1, n)` so that it starts iterating at 1.', 'I can change it to `range(n) + 1`, so that the first value is 0 + 1.', 'I don’t know, can you help?']}, {'role': 'assistant', 'content': 'Can you also try it with `n = 2` and `n = 3`?', 'alt': ['Do you think your code will work for all values of `n`, for example `n = 3`?']}, {'role': 'user', 'content': 'Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.'}, {'role': 'assistant', 'content': 'The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?', 'alt': ['Why is the code giving an incorrect answer for n = 3?', 'What should the output of factorial(3) be?']}, {'role': 'user', 'content': 'Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * (i + 1)\n8.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.'}, {'role': 'user', 'content': 'Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * (i + 1)\n7.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return ""Previous node is not in linked list""
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>","Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```","class Node:
+   def __init__(self, data=None, next=None):
+       self.data = data
+       self.next = next
+
+def insert_after(head, prev_data, new_data):
+   curr_head = head
+   while curr_head is not None:
+       if curr_head.data == prev_data:
+           new_node = Node(data=new_data)
+           curr_head.next = new_node
+           return
+       else:
+           curr_head = curr_head.next
+   
+   return ""Previous node is not in linked list""","The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.","After line 10, insert a line `new_node.next = curr_head.next`","head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""",25_55_insert_to_linked_list,"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.\nYou are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.\nclass Node:\n    def __init__(self, data=None, next=None):\n        self.data = data\n        self.next = next\n```\n## Example Cases:\n```py\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\ninsert_after(head, 2, 5) => None\nhead.data == 1\nhead.next.data == 2\nhead.next.next.data == 5\nhead.next.next.next.data == 3\nhead.next.next.next.next.data == 4\ninsert_after(head, 8, 6) => ""Previous node is not in linked list""\n```\n</problem>\n<bug_code>\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6. def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            curr_head.next = new_node\n12.            return\n13.        else:\n14.            curr_head = curr_head.next\n15.    \n16.    return ""Previous node is not in linked list""\n</bug_code>\n<bug_desc>\nThe function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.\n</bug_desc>\n<bug_fixes>\nAfter line 10, insert a line `new_node.next = curr_head.next`\n</bug_fixes>\n<unit_tests>\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\nassert insert_after(head, 2, 5) == None\nassert head.data == 1\nassert head.next.data == 2\nassert head.next.next.data == 5\nassert head.next.next.next.data == 3\nassert head.next.next.next.next.data == 4\nassert insert_after(head, 8, 6) == ""Previous node is not in linked list""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?', 'alt': ['Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?']}, {'role': 'assistant', 'content': 'Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.'}, {'role': 'user', 'content': 'The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).'}, {'role': 'assistant', 'content': ""Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?"", 'alt': [""Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?"", 'Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?', ""Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?""]}, {'role': 'user', 'content': 'If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.'}, {'role': 'assistant', 'content': ""That's right! Could you now tell me what happens when we complete the test case checks?"", 'alt': [""That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?""]}, {'role': 'user', 'content': 'Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.\n```python\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6.def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            new_node.next = curr_head.next\n12.            curr_head.next = new_node\n13.            return\n14.       else:\n15.           curr_head = curr_head.next\n16.    \n17.   return ""Previous node is not in linked list""\n```', 'alt': [""Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order."", 'It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.']}, {'role': 'assistant', 'content': 'Great! Let me know if you need more help.'}]}"
+"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>","Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```","def sequenceBetween(start, end):
+   l = []
+   if(start >= end):
+       i = start 
+       while i > end:
+           l.append(i)
+           i -= 1
+   else:
+       i = start
+       while i < end:
+           l.append(i)
+           i += 1
+   
+   return l","On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.",Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.,"assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]",3_20_counting_down,"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.\n\n## Example Cases:\n```\nsequenceBetween(0, 3) => [0, 1, 2, 3]\nsequenceBetween(1, 1) => [1]\nsequenceBetween(7, 5) => [7, 6, 5]\nsequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]\nsequenceBetween(12, 10) => [12, 11, 10]\nsequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]\n```\n</problem>\n<bug_code>\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i < end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n</bug_code>\n<bug_desc>\nOn lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.\n</bug_desc>\n<bug_fixes>\nReplace `>` with `>=` on line 5 and `<` with `<=` on line 10.\n</bug_fixes>\n<unit_tests>\nassert sequenceBetween(0, 3) == [0, 1, 2, 3]\nassert sequenceBetween(1, 1) == [1]\nassert sequenceBetween(7, 5) == [7, 6, 5]\nassert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]\nassert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi I need to fix my code, I am not getting the expected output.'}, {'role': 'assistant', 'content': ""Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?"", 'alt': [""Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?"", ""Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?"", ""Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?"", 'Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?']}, {'role': 'user', 'content': 'When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```', 'alt': ['I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.']}, {'role': 'assistant', 'content': ""For completeness, let's test another test case. What happens when you run `(1, 1)` as input?"", 'alt': [""Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?"", 'Could you also try the next test case, `(1, 1)`, and observe the output?']}, {'role': 'user', 'content': ""I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i >= end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```"", 'alt': ['It looks like I also need to fix the `if` portion of the code which has a similar issue as before.']}, {'role': 'assistant', 'content': ""Sounds good, let's check all the test cases and check how it goes!""}, {'role': 'user', 'content': 'Everything is running as expected now, thanks!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i % 2 =! 0:
+     newNums.append(i)
+ return newNums","There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.",Replace `=!` with `!=` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_22_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 =! 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `=!` with `!=` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I keep getting an error with my code,  but I'm not sure how to fix it""}, {'role': 'assistant', 'content': 'Where is the syntax error happening and what is it?', 'alt': ['Do you see any red squiggly lines in your code? If so, what is it highlighting?', 'Do you see a line number next to the error? If so, what is it?']}, {'role': 'user', 'content': 'Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""'}, {'role': 'assistant', 'content': 'Do you see a squiggly line in your code? If so, what is it highlighting?', 'alt': ['It might be an issue with your operator. Could you list all the comparison operators you know?', 'How do you check if two numbers are unequal?', 'Is the error message highlighting a specific portion of the line like an operator or a parenthesis?']}, {'role': 'user', 'content': 'Yes, it is highlighting the =! operator.'}, {'role': 'assistant', 'content': 'Then, what do you think the problem is?', 'alt': [""Are you sure that's the correct operator to check whether two numbers are unequal?""]}, {'role': 'user', 'content': ""I'm not sure. I am trying to check if `i` is not divisible by 2.""}, {'role': 'assistant', 'content': 'Are you sure that `=!` is the correct operator to check if two numbers are not equal?', 'alt': ['Is there a difference between `=!` and `!=`?']}, {'role': 'user', 'content': 'Ah! I see. I should be using `!=` instead of `=!`.\n```python\n def returnOdd(nums):\n  newNums = []\n  for i in nums:\n    if i % 2 != 0:\n      newNums.append(i)\n  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Now try running your code again.'}, {'role': 'user', 'content': 'It works! Thanks for your help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums
+   if i % 2 != 0:
+     newNums.append(i)
+ return newNums",There is a syntax error on line 3. The for loop syntax is incorrect.,Add `:` after `nums` on line 3.,"assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []",4_28_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]\nreturnOdd([2,4,6,8,10]) => []\nreturnOdd([1,3,5,7,9]) => [1,3,5,7,9]\nreturnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 3. The for loop syntax is incorrect.\n</bug_desc>\n<bug_fixes>\nAdd `:` after `nums` on line 3.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]\nassert returnOdd([2,4,6,8,10]) == []\nassert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]\nassert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, I am not sure why my program for removing even numbers is not running. Can you please help?', 'alt': ['Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?']}, {'role': 'assistant', 'content': 'Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?', 'alt': ['Hi, Sure! Do you know why it is throwing a syntax error on line 3?']}, {'role': 'user', 'content': 'I am not sure what that error means', 'alt': ['Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?']}, {'role': 'assistant', 'content': 'It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?'}, {'role': 'user', 'content': 'Yes, it looks like the caret is pointing towards the end of line 3.'}, {'role': 'assistant', 'content': 'Correct, what do you think is wrong with the end of the line 3?', 'alt': ['Correct, what do you think is missing towards the end of line 3?']}, {'role': 'user', 'content': 'I am not sure, is it a punctuation mark?', 'alt': ['Is it missing a colon?']}, {'role': 'assistant', 'content': 'Yes, can you find the correct syntax using the documentation?', 'alt': ['Yes, where can you find the correct syntax of a for loop?']}, {'role': 'user', 'content': 'What is the documentation?', 'alt': ['Yes, is it supposed to have a colon at the end?']}, {'role': 'assistant', 'content': 'Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org'}, {'role': 'user', 'content': 'After going through the python documentation, I think this is what my code is supposed to look like this.\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Correct, you can always come back to the documentation if you ever run into a syntax error.'}, {'role': 'user', 'content': 'My program works now, thank you for helping me resolve that error!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error ""SyntaxError: 'return' outside function"" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+return newNums",There is a syntax error on line 6. The return statement is not within a function scope.,Insert a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_25_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6. return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 6. The return statement is not within a function scope.\n</bug_desc>\n<bug_fixes>\nInsert a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?', 'alt': ['Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?']}, {'role': 'assistant', 'content': 'Sure, let\'s look at the error together. Do you know what the error ""SyntaxError: \'return\' outside function"" means?', 'alt': [""I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?"", 'Let\'s warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?']}, {'role': 'user', 'content': 'Does it mean that my return statement is not currently a part of my function?', 'alt': ['The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.']}, {'role': 'assistant', 'content': ""That's right, taking a look at your code, do you think your return statement is a part of your function?"", 'alt': ['Could you tell me what we might need to do to make sure that the function returns the value we need it to?', 'What might you need to do to make sure the return statement is in the scope of your function?']}, {'role': 'user', 'content': 'I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```', 'alt': ['I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.']}, {'role': 'assistant', 'content': 'Looks good! Let me know if you need more help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+       return newNums","On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.",Remove a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_26_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.        return newNums\n</bug_code>\n<bug_desc>\nOn line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.\n</bug_desc>\n<bug_fixes>\nRemove a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck.""}, {'role': 'assistant', 'content': 'What should your code be doing?', 'alt': ['Which test cases (if any) are failing?', 'What are you stuck on?', 'Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?']}, {'role': 'user', 'content': ""Right now, it's only returning the first number in the list, not all of them."", 'alt': [""It's only passing the second test case.""]}, {'role': 'assistant', 'content': ""Okay, let's look at your loop. Do you see anything that could be causing it to end early?"", 'alt': ['Have you checked the loop and how many times it iterates?', ""Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?"", 'What do you think might cause your function to return a list with one element instead of multiple elements?', ""Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?"", 'What do you think is causing the lists not to include all the numbers?', 'Look at line 3, is it iterating through the whole list?']}, {'role': 'user', 'content': ""No I do not. I'm iterating through the whole list of numbers."", 'alt': [""I don't know, how could I find out?"", 'Oh, I see, the return statement is in the wrong place.']}, {'role': 'assistant', 'content': ""Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?"", 'alt': ['What can cause a function to end early?', 'What forces a loop to end?']}, {'role': 'user', 'content': 'Line 3 starts the loop, and it iterates through everything in `nums`.'}, {'role': 'assistant', 'content': 'Good, then what happens?', 'alt': ['Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?', 'Think back to what you know about functions. What makes them end early?', 'Think back to what you know about loops, what can make them stop?']}, {'role': 'user', 'content': 'The if statement starts on line 4, it checks if the number is even.'}, {'role': 'assistant', 'content': 'Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?', 'alt': ['Do you notice anything on line 4 that causes the function to end early?', 'Do you notice anything on line 4 that causes the for loop to end?']}, {'role': 'user', 'content': ""I don't see anything that can cause that problem."", 'alt': ['I see! The return statement after the if-statement is indented too much!']}, {'role': 'assistant', 'content': 'Okay, so what happens next on line 6?'}, {'role': 'user', 'content': 'It returns the list.', 'alt': [""I get it! It's returning after every iteration!"", ""It's returning too soon.""]}, {'role': 'assistant', 'content': 'When should it return the list?', 'alt': ['Would a return statement end a loop?', 'Would a return statement cause the function to terminate early?', 'Is there anything on this line that would cause the loop or the function to end early?', 'When does your return statement execute?']}, {'role': 'user', 'content': 'It should return the list when it finishes all the numbers.'}, {'role': 'assistant', 'content': 'Look at line 6, what level of indentation is the list on?', 'alt': ['Think back to what you have learned about indentation, how does that control the order of actions in a loop?', 'Can the return statement end the loop early?']}, {'role': 'user', 'content': ""I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```""}, {'role': 'assistant', 'content': 'What does it return now, after you changed the indentation of the return statement?'}, {'role': 'user', 'content': 'It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.'}, {'role': 'assistant', 'content': ""You're welcome. Let me know if I can be of any further assistance.""}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i / 2 != 0:
+     newNums.append(i)
+ return newNums","On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.",Replace `/` with `%` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_23_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i / 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.\n</bug_desc>\n<bug_fixes>\nReplace `/` with `%` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I have a problem with my code. It's just not working, and I just don't know why.""}, {'role': 'assistant', 'content': 'Can you explain what the issue appears to be?', 'alt': ['Can you walk me through your function line by line?', 'Does your code throw an error or do you just get the wrong answer?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you know if a number is even or odd?""]}, {'role': 'user', 'content': ""The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed."", 'alt': [""It doesn't seem like my function modifies anything on most input lists."", ""I can't figure out why my function doesn't remove most of the even numbers in the lists I input.""]}, {'role': 'assistant', 'content': 'Can you explain your function to me line by line?', 'alt': ['Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?""]}, {'role': 'user', 'content': 'OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.'}, {'role': 'assistant', 'content': ""Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?"", 'alt': ['Can you explain what line 4 of your code does?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?"", 'When does dividing by 2 give you 0?', 'How do you check if a number is even in your code?']}, {'role': 'user', 'content': ""Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?""}, {'role': 'assistant', 'content': ""Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?"", 'alt': [""Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?"", 'Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Hm ok, let me try modulus. It works!\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Happy to help!'}, {'role': 'user', 'content': 'Thank you so much for your help! I learned more about how to check for divisibility in Python.'}]}"
+"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>","Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```","def get_words(s):
+   words = [word.lower() for word in s.split("" "")]
+   return sorted(words)","The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.","Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.","assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']",5_30_sorted_words,"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+","{'system': '<problem>\nWrite a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `[\'hello\', \'world\']`.\n\n## Example Cases:\n```\nget_words(""Hello World"") => [\'hello\', \'world\']\nget_words(""Hello World hello"") => [\'hello\', \'world\']\nget_words(""Hello World hello world"") => [\'hello\', \'world\']\nget_words(""Hello World H e l l o W o r l d"") => [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nget_words(""Hello World el WORld"") => [\'el\', \'hello\', \'world\']\nget_words(""A C B c b a"") => [\'a\', \'b\', \'c\']\n```\n</problem>\n<bug_code>\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(words)\n</bug_code>\n<bug_desc>\nThe function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.\n</bug_desc>\n<bug_fixes>\nReplace `sorted(words)` with `sorted(set(words))` on line 3.\nInsert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.\n</bug_fixes>\n<unit_tests>\nassert get_words(""Hello World"") == [""hello"", ""world""]\nassert get_words(""Hello World hello"") == [""hello"", ""world""]\nassert get_words(""Hello World hello world"") == [""hello"", ""world""]\nassert get_words(""Hello World H e l l o W o r l d"") == [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nassert get_words(""Hello World el WORld"") == [\'el\', \'hello\', \'world\']\nassert get_words(\'A C B c b a\') == [\'a\', \'b\', \'c\']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on this function and it doesn't seem to be correct."", 'alt': ['I\'m trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.']}, {'role': 'assistant', 'content': 'Does your code work for all the examples in the problem description or does it fail on some of them?', 'alt': ['Hello! Can you explain to me what the code on line 2 does?', ""Let's review the problem description together. What are the requirements for the returned list?"", 'Can you walk me through your `get_words` function?', 'Let\'s run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?', ""Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?""]}, {'role': 'user', 'content': 'If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?'}, {'role': 'assistant', 'content': ""Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?"", 'alt': ['I see. How can you remove duplicates from a list?', ""Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?"", 'I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?', 'Where can you learn about deduplicating a list in Python?', 'Have you considered simply looping through the list and removing duplicates?']}, {'role': 'user', 'content': 'Maybe a set would be better than a list for this then. I\'ve modified my code. The output for that sentence now is: [\'hello\', \'world\'], so it looks like it works!\n```python\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(set(words))\n```'}, {'role': 'assistant', 'content': 'Perfect!'}]}"
+"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>","Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```","def calculate_average(x, y):
+   return x + y / 2","On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.",Replace `x + y` with `(x + y)` on line 2.,"assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0",56_15_compute_average,"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.\n\n## Example Cases:\n```\ncalculate_average(0, 0) => 0.0\ncalculate_average(1, 3) => 2.0\ncalculate_average(-1, 1) => 0.0\ncalculate_average(-5, -2) => -3.5\ncalculate_average(5.5, 7.5) => 6.5\ncalculate_average(405, 135) => 270.0\n```\n</problem>\n<bug_code>\n1. def calculate_average(x, y):\n2.    return x + y / 2\n</bug_code>\n<bug_desc>\nOn line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.\n</bug_desc>\n<bug_fixes>\nReplace `x + y` with `(x + y)` on line 2.\n</bug_fixes>\n<unit_tests>\nassert calculate_average(0, 0) == 0.0\nassert calculate_average(1, 3) == 2.0\nassert calculate_average(-1, 1) == 0.0\nassert calculate_average(-5, -2) == -3.5\nassert calculate_average(5.5, 7.5) == 6.5\nassert calculate_average(405, 135) == 270.0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?""}, {'role': 'assistant', 'content': ""Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?"", 'alt': ['Can you describe what happens when you run your code using one of the example cases?', 'Given `x = 2` and `y = 4`, can you explain how line 2 works?']}, {'role': 'user', 'content': 'I should get a 3, but I am getting a 4.'}, {'role': 'assistant', 'content': 'Why do you think it returns 4 instead of 3?', 'alt': ['Can you describe what line 2 is doing when `x` is 2 and `y` is 4?']}, {'role': 'user', 'content': 'I am not sure why it is returning 4.'}, {'role': 'assistant', 'content': 'Can you describe what line 2 is doing when `x` is 2 and `y` is 4?', 'alt': ['Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'Do you recall what the order of operations is when evaluating a mathematical expression?']}, {'role': 'user', 'content': 'The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.'}, {'role': 'assistant', 'content': 'Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'alt': ['Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?']}, {'role': 'user', 'content': 'Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.\n```python\n1. def calculate_average(x, y):\n2.    return (x + y) / 2\n```', 'alt': ['Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. ', 'I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. ']}, {'role': 'assistant', 'content': 'Very good! Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes it does! Thank you so much for your help!'}, {'role': 'assistant', 'content': 'You’re welcome please let me know if you have any questions.'}, {'role': 'user', 'content': 'Thank you will do!'}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   i = 0
+   while apples > 0 and apples > children:
+       apples = apples - children
+       i += 1
+   return i","The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.",Replace `apples > children` with `apples >= children` on line 3.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_59_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples > children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n</bug_code>\n<bug_desc>\nThe while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.\n</bug_desc>\n<bug_fixes>\nReplace `apples > children` with `apples >= children` on line 3.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My function fails two test cases and I do not understand why, can you help?'}, {'role': 'assistant', 'content': 'Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?', 'alt': [""Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?"", ""Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?"", 'Sure. Can you explain to me what you are trying to do with the while loop?', 'Sure. Can you tell me what the loop condition `apples > children` is there for?', 'Sure. Can you explain your code to me, what is supposed to do, line by line?']}, {'role': 'user', 'content': 'It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.', 'alt': [""It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.""]}, {'role': 'assistant', 'content': 'Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?', 'alt': ['Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.', ""Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?""]}, {'role': 'user', 'content': 'It is 1 less than the correct number.'}, {'role': 'assistant', 'content': 'Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?', 'alt': ['Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?']}, {'role': 'user', 'content': 'Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!\n```python\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples >= children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   return apples / children",The function returns a float instead of the largest possible integer after distributing the apples evenly.,Replace `/` with `//` on line 2.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_58_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    return apples / children\n</bug_code>\n<bug_desc>\nThe function returns a float instead of the largest possible integer after distributing the apples evenly. \n</bug_desc>\n<bug_fixes>\nReplace `/` with `//` on line 2.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck!""}, {'role': 'assistant', 'content': 'Where do you think the problem is?', 'alt': ['Have you read your code carefully?', 'Which test cases are passing?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': ""I don't know."", 'alt': ['I think the math is wrong.']}, {'role': 'assistant', 'content': 'Look at the test cases, does the first test case pass?', 'alt': ['Look at the test cases, what is the first test case to fail?', 'Have you read your code carefully?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': 'What is the correct answer for case 2?', 'alt': ['What is the correct answer for case 1?', 'Does case 1 require rounding?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'It should output 3.'}, {'role': 'assistant', 'content': 'Would there be a remainder?', 'alt': ['What is the correct answer for case 1?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'Yes, there would be a remainder of 1.', 'alt': ['Oh! I see, the problem is the remainder!']}, {'role': 'assistant', 'content': 'Is there a way you can see what the result is?', 'alt': ['Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'Trace the code, what would the output of line 2 be with 7 and 2?', 'How can you test the output of line 2?']}, {'role': 'user', 'content': 'I can add a print statement before the return.\n```python\n1. def split_apples(apples, children):\n2.    print(apples / children)\n3.    return apples / children\n```'}, {'role': 'assistant', 'content': 'Try running the code, what is the result of dividing 7 by 2?', 'alt': ['Try running the code, what is the result of dividing 10 by 2?', 'Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?']}, {'role': 'user', 'content': ""It's returning 3.5 for 7 divided by 2.""}, {'role': 'assistant', 'content': 'What should the output be?', 'alt': ['Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?', 'Look at the prompt, is there anything special about the format of the numbers?', 'Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'What do you need to change to make the output a whole number?']}, {'role': 'user', 'content': 'It should be 3.'}, {'role': 'assistant', 'content': 'Look at the Python documentation on operators, are you using the correct one to round down?', 'alt': ['Are you using the correct operator?', 'Is there a specific operator you should use when dividing whole numbers?', 'Is there a specific operator you should use when you need to round down?', 'Think about division in Python, what does `/` indicate?', 'How can you make it round down?']}, {'role': 'user', 'content': 'No! I need to use // instead.\n```python\n1. def split_apples(apples, children):\n2.    print(apples // children)\n3.    return apples // children\n```'}, {'role': 'assistant', 'content': 'Run it again, does it output correctly?', 'alt': ['Run it now, do all the test cases pass?']}, {'role': 'user', 'content': ""Yes, it works! I'll remove the extra print statement. \n```python\n1. def split_apples(apples, children):\n2.    return apples // children\n```""}, {'role': 'assistant', 'content': 'Run it one more time, do all the test cases pass?', 'alt': ['Run it again, does it output correctly?']}, {'role': 'user', 'content': 'Yes! It works, thank you!'}]}"
+"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>","Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```","def Product(a, b):
+a * b","The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.",Add `return` before `a * b`.,"assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25",59_60_product,"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).\n\n## Example Cases: \n```\nProduct(1,2) => 2\nProduct(2,4) => 8\nProduct(4,4) => 16\nProduct(5,5) => 25\n```\n</problem>\n<bug_code>\n1. def Product(a, b):\n2.\ta * b\n</bug_code>\n<bug_desc>\nThe function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.\n</bug_desc>\n<bug_fixes>\nAdd `return` before `a * b`.\n</bug_fixes>\n<unit_tests>\nassert Product(1,2) == 2\nassert Product(2,4) == 8\nassert Product(4,4) == 16\nassert Product(5,5) == 25\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.""}, {'role': 'assistant', 'content': 'Okay, can you explain your `Product()` function in detail?', 'alt': ['How familiar are you with functions in Python?']}, {'role': 'user', 'content': 'I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.'}, {'role': 'assistant', 'content': 'Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?', 'alt': ['Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?']}, {'role': 'user', 'content': 'Okay, I\'ve made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn\'t it be printing out a number?\n```python\n1. def Product(a, b):\n2.\ta * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?'}, {'role': 'user', 'content': 'Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?\n```python\n1. def Product(a, b):\n2.\treturn a * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'Yes. What is the purpose of line 3? Do you still need it?'}, {'role': 'user', 'content': ""It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!\n```python\n1. def Product(a, b):\n2.\treturn a * b\n```""}, {'role': 'assistant', 'content': ""You're welcome. Is there anything else that I can help you with today?""}, {'role': 'user', 'content': ""No, that's all. Thank you!""}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `""E""` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+12. store = turn_clockwise(""N"")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == ""N"":
+        return ""E""
+    elif compass_point == ""E"":
+        return ""S""
+    elif compass_point == ""S"":
+        return ""W""
+    elif compass_point == ""W"":
+        return ""N""
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point == ""N"":
+       print (""E"")
+   elif compass_point == ""E"":
+       print (""S"")
+   elif compass_point == ""S"":
+       print (""W"")
+   elif compass_point == ""W"":
+       print (""N"")
+   else:
+       print (""None"")","The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.","Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_33_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '\ufeff<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value `None`.\n\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n</bug_code>\n<bug_desc>\nThe function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.\n</bug_desc>\n<bug_fixes>\nReplace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I have a problem. My code does not generate the right result and I cannot figure that out.'}, {'role': 'assistant', 'content': ""Hi! Let's take a look at your code. Could you explain how your code works?"", 'alt': ['Hi! What makes you think that your program is not working properly?', 'Can you give me an example where your code does not return the correct result?', 'I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?']}, {'role': 'user', 'content': 'Ok. My code gets the current `compass_point` and prints the next one.'}, {'role': 'assistant', 'content': 'What do you see as your output in the terminal and what are you passing as `compass_point`?', 'alt': ['What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?']}, {'role': 'user', 'content': 'When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That\'s strange since my output is printed correctly, but my program does not pass any of the tests.'}, {'role': 'assistant', 'content': 'What does a unit test need from a function to ensure that the function works properly?', 'alt': ['Ah. How did you determine whether your function is correct?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?', 'Say you want to store the output of your function into a variable, what would you need to do?', 'What do you think a function needs to pass along its output to say get stored in a variable?']}, {'role': 'user', 'content': 'It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.', 'alt': [""I don't understand the question. Can you tell me more about unit tests?""]}, {'role': 'assistant', 'content': 'Correct. So would you be able to store the value outputted by the function into say a variable?', 'alt': ['Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?']}, {'role': 'user', 'content': 'Hypothetically yes. I should be able to store it in a variable. I have not tried though.'}, {'role': 'assistant', 'content': 'Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'alt': ['Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?']}, {'role': 'user', 'content': 'Ah I think, it would be `""E""` in `store`.'}, {'role': 'assistant', 'content': 'Let’s try it and then print `store`. What do you observe in your terminal?'}, {'role': 'user', 'content': 'Hmm... I see `None`. That’s really strange.\n\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n12. store = turn_clockwise(""N"")\n13. print(store)\n```'}, {'role': 'assistant', 'content': 'What do you think the function needs to have in order to give its output to the variable?', 'alt': ['Do you recall, which reserved word in Python is used to return the output for a function back to a variable?']}, {'role': 'user', 'content': 'Ah! I think it might be `return`. Let me try that.\n```python\ndef turn_clockwise(compass_point):\n    if compass_point == ""N"":\n        return ""E""\n    elif compass_point == ""E"":\n        return ""S""\n    elif compass_point == ""S"":\n        return ""W""\n    elif compass_point == ""W"":\n        return ""N""\n    else:\n        return None\n\t\t\n```', 'alt': ['I’m not really sure.']}, {'role': 'assistant', 'content': 'Very good.', 'alt': ['Very good. Is there a way for you to simplify your code?']}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You’re welcome! Let me know if I can be of any further help.'}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says ""SyntaxError: invalid syntax""
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to ""N""
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = ""N""`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        return ""E""
+4.    elif compass_point == ""E"":
+5.        return ""S""
+6.    elif compass_point == ""S"":
+7.        return ""W""
+8.    elif compass_point == ""W"":
+9.        return ""N""
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point = ""N"":
+       return ""E""
+   elif compass_point = ""E"":
+       return ""S""
+   elif compass_point = ""S"":
+       return ""W""
+   elif compass_point = ""W"":
+       return ""N""
+   else:
+       return None","There are syntax errors on lines 2, 4, 6, and 8.","Replace `=` with `==` on lines 2, 4, 6, and 8.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_34_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value None.\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point = ""N"":\n3.        return ""E""\n4.    elif compass_point = ""E"":\n5.        return ""S""\n6.    elif compass_point = ""S"":\n7.        return ""W""\n8.    elif compass_point = ""W"":\n9.        return ""N""\n10.    else:\n11.        return None\n</bug_code>\n<bug_desc>\nThere are syntax errors on lines 2, 4, 6, and 8.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on lines 2, 4, 6, and 8.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with the code can you help me? It's throwing an error.""}, {'role': 'assistant', 'content': 'What is the error that you observe?', 'alt': ['Let\'s start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?', 'Can you describe what your code is trying to do?']}, {'role': 'user', 'content': ""I have a syntax error on line 2. I'm not sure why."", 'alt': ['The terminal says ""SyntaxError: invalid syntax""']}, {'role': 'assistant', 'content': 'Can you describe what you are trying to do on line 2?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?', 'What operator do you use to check for equality?', 'Can you show me how you would assign the value 1 to a variable `x`?']}, {'role': 'user', 'content': 'I am trying to check if `compass_point` is equal to ""N""'}, {'role': 'assistant', 'content': 'What operator do you use to check for equality?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I use the `=` operator to check for equality.', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'alt': ['Can you show me how you would assign the value 1 to a variable `x`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I would use `compass_point = ""N""`', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Are you sure that you can use the same operator `=` for assignment and to check for equality?'}, {'role': 'user', 'content': 'Oh! Probably not. What operator should I use?', 'alt': ['Oh! I checked the documentation. I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Can you look in the Python documentation to see what operator is used to check for equality?'}, {'role': 'user', 'content': 'Oh I found it! I should use `==` instead of `=`. Let me edit my code!\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        return ""E""\n4.    elif compass_point == ""E"":\n5.        return ""S""\n6.    elif compass_point == ""S"":\n7.        return ""W""\n8.    elif compass_point == ""W"":\n9.        return ""N""\n10.   else:\n11.        return None\n```'}, {'role': 'assistant', 'content': 'Good job. Look good. Let me know if you have any more questions.'}, {'role': 'user', 'content': 'Thank you! Goodbye!'}]}"
+"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```","def Largest(a, b, c):
+if(a > b and a > c):
+	return a
+elif(b > a and b > c):
+	return b
+else:
+	return c","When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.",Change the > to >= in all the conditions.,"assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1",60_61_largest_number,"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.\n\n## Example Cases:\n```\nLargest(1,2,3) => 3\nLargest(3,2,1) => 3\nLargest(2,2,1) => 2\nLargest(1,1,1) => 1\n```\n</problem>\n<bug_code>\n1. def Largest(a, b, c):\n2.\tif(a > b and a > c):\n3.\t\treturn a\n4.\telif(b > a and b > c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n</bug_code>\n<bug_desc>\nWhen `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.\n</bug_desc>\n<bug_fixes>\nChange the > to >= in all the conditions.\n</bug_fixes>\n<unit_tests>\nassert Largest(1,2,3) == 3\nassert Largest(3,2,1) == 3\nassert Largest(2,2,1) == 2\nassert Largest(1,1,1) == 1\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.""}, {'role': 'assistant', 'content': 'Hello! Can you explain how your function works step by step?'}, {'role': 'user', 'content': 'Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.'}, {'role': 'assistant', 'content': 'Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?'}, {'role': 'user', 'content': 'Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?'}, {'role': 'assistant', 'content': 'Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?', 'alt': ['What about when `Largest(2,2,1)` is ran? What will be returned?']}, {'role': 'user', 'content': ""I'm not sure, how could you pick between them?""}, {'role': 'assistant', 'content': 'While it is required to pick one or the other, what difference would picking the first over the second make in the output?'}, {'role': 'user', 'content': ""Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!\n```python\n1. def Largest(a, b, c):\n2.\tif(a >= b and a >= c):\n3.\t\treturn a\n4.\telif(b >= a and b >= c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n```""}, {'role': 'assistant', 'content': ""I'm happy that I could help! Is there anything else that I could help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```","def SumIsEven(a, b):
+return (a+b) % 2 == 1
+",The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.,Replace `1` with `0` to ensure that the sum is even.,"assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False",61_62_is_even,"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.\n\n## Example Cases: \n```\nSumIsEven(1,1) => True\nSumIsEven(1,2) => False\nSumIsEven(2,2) => True\nSumIsEven(2,3) => False\n```\n</problem>\n<bug_code>\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 1\n3.\n</bug_code>\n<bug_desc>\nThe function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` to ensure that the sum is even.\n</bug_fixes>\n<unit_tests>\nassert SumIsEven(1,1) == True\nassert SumIsEven(1,2) == False\nassert SumIsEven(2,2) == True\nassert SumIsEven(2,3) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.""}, {'role': 'assistant', 'content': ""Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?""}, {'role': 'user', 'content': 'From what I understand, it tells you if a number is divisible by another number, right?'}, {'role': 'assistant', 'content': 'The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?', 'alt': ['The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?']}, {'role': 'user', 'content': ""Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!\n```python\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 0\n```""}, {'role': 'assistant', 'content': ""I'm happy to help! Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```","def SumBetween(low, high):
+num = 0
+for i in range(low, high):
+	num += i
+return num","The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range.",Replace `high` with `high + 1`.,"assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12",62_63_summing_between_integers,"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.\n\n## Example Cases:\n```\nSumBetween(0,1) => 1\nSumBetween(0,2) => 3\nSumBetween(1,2) => 3\nSumBetween(3,5) => 12\n```\n</problem>\n<bug_code>\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high):\n4.\t\tnum += i\n5.\treturn num\n</bug_code>\n<bug_desc>\nThe function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. \n</bug_desc>\n<bug_fixes>\nReplace `high` with `high + 1`.\n</bug_fixes>\n<unit_tests>\nassert SumBetween(0,1) == 1\nassert SumBetween(0,2) == 3\nassert SumBetween(1,2) == 3\nassert SumBetween(3,5) == 12\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.""}, {'role': 'assistant', 'content': 'Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?'}, {'role': 'user', 'content': ""I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.""}, {'role': 'assistant', 'content': '`range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?'}, {'role': 'user', 'content': 'That would just be 0, right?'}, {'role': 'assistant', 'content': 'Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?'}, {'role': 'user', 'content': ""Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?""}, {'role': 'assistant', 'content': ""Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?"", 'alt': [""Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?""]}, {'role': 'user', 'content': 'I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?'}, {'role': 'assistant', 'content': 'Can you explain why you think that is the correct answer?'}, {'role': 'user', 'content': 'Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.'}, {'role': 'assistant', 'content': 'That is entirely correct. Now how would you change your code to express this?'}, {'role': 'user', 'content': 'Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!\n```python\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high+1):\n4.\t\tnum += i\n5.\treturn num\n```'}, {'role': 'assistant', 'content': 'I am glad I could be of assistance. Is there anything else you wanted to ask?'}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```","def GoodDinner(pizzas, weekend):
+       if(pizzas >= 10 and weekend):
+               return True
+       elif(pizzas <= 20 and not(weekend)):
+               return True
+       return False",The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10.,Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.,"assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False",63_64_good_dinner,"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+","{'system': ""<problem>\nYou like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.\n\n## Example Cases:\n```\nGoodDinner(10, False) => True\nGoodDinner(20, False) => True\nGoodDinner(5, False) => False\nGoodDinner(21, False) => False\nGoodDinner(10, True) => True\nGoodDinner(21, True) => True\nGoodDinner(5, True) => False\n```\n</problem>\n<bug_code>\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n</bug_code>\n<bug_desc>\nThe function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. \n</bug_desc>\n<bug_fixes>\nInsert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.\n</bug_fixes>\n<unit_tests>\nassert GoodDinner(10, False) == True\nassert GoodDinner(20, False) == True\nassert GoodDinner(5, False) == False\nassert GoodDinner(21, False) == False\nassert GoodDinner(10, True) == True\nassert GoodDinner(21, True) == True\nassert GoodDinner(5, True) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.""}, {'role': 'assistant', 'content': ""Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?"", 'alt': ['When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?']}, {'role': 'user', 'content': 'It would be 10 or more pizzas.'}, {'role': 'assistant', 'content': 'And how would you produce a boolean that is `True` when the `pizzas` fits that condition?'}, {'role': 'user', 'content': 'It would be `pizzas >= 10`.'}, {'role': 'assistant', 'content': ""Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?""}, {'role': 'user', 'content': ""That's where I'm confused. It's between 10 and 20, inclusively, right?""}, {'role': 'assistant', 'content': 'That is correct, what about that condition is confusing you?'}, {'role': 'user', 'content': ""I'm not sure how to convert a number between two other numbers into Python.""}, {'role': 'assistant', 'content': ""Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?""}, {'role': 'user', 'content': 'That would be `pizzas >= 10` and `pizzas <= 20`.'}, {'role': 'assistant', 'content': 'And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?', 'alt': ['And would you use `and`, `or`, or `xor` to produce your desired outcome?']}, {'role': 'user', 'content': 'That would be `and` right?'}, {'role': 'assistant', 'content': 'Correct. Do you see now how you would implement a condition for when `weekend` is `False`?'}, {'role': 'user', 'content': 'Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!\n```python\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n```'}, {'role': 'assistant', 'content': ""I'm glad to be of assistance. Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```","def CountOnes(integers):
+count = 0
+for i in range(1, len(integers)):
+	if(integers[i] == 1):
+		count++
+return count","On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.",Replace `1` with `0` in the `range` call on line 3.,"assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0",64_65_count_ones,"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.\n\n## Example Cases:\n```\nCountOnes([1,1,1,0,0]) => 3\nCountOnes([1,0,0]) => 1\nCountOnes([]) => 0\nCountOnes([3]) => 0\n```\n</problem>\n<bug_code>\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(1, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount++\n6.\treturn count\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert CountOnes([1,1,1,0,0]) == 3\nassert CountOnes([1,0,0]) == 1\nassert CountOnes([]) == 0\nassert CountOnes([3]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.""}, {'role': 'assistant', 'content': 'Hello! Can you explain what your `for` loop does?'}, {'role': 'user', 'content': 'It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.'}, {'role': 'assistant', 'content': 'Can you tell me how many elements are in `range(1, len(integers))`?'}, {'role': 'user', 'content': 'Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?'}, {'role': 'assistant', 'content': 'That\'s not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".', 'alt': ['At what index do Python lists begin?', 'Can you tell me how many elements are in `range(1, len(integers))`?']}, {'role': 'user', 'content': 'Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!\n```python\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(0, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount += 1\n6.\treturn count\n```'}, {'role': 'assistant', 'content': ""I'm glad I could be of assistance. Is there anything else you wanted to discuss today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>","Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```","def Range(array):
+       smallest = 0
+       largest = 0
+       for element in array:
+               if(element > largest):
+                       largest = element
+               if(element < smallest):
+                       smallest = element
+       return largest - smallest","On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.",Initialize `smallest` and `largest` to the first element of array `array[0]`.,"assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13",65_66_list_range,"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.\n\n## Example Cases:\n```\nRange([1,2]) => 1\nRange([1,1,1,1,1,1,5])  => 4\nRange([2,2,1,3])  => 2\nRange([-10,-3,-1])  => 9\nRange([-10,3,1])  => 13\n```\n</problem>\n<bug_code>\n1. def Range(array):\n2.        smallest = 0\n3.        largest = 0\n4.        for element in array:\n5.                if(element > largest):\n6.                        largest = element\n7.                if(element < smallest):\n8.                        smallest = element\n9.        return largest - smallest\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.\n</bug_desc>\n<bug_fixes>\nInitialize `smallest` and `largest` to the first element of array `array[0]`.\n</bug_fixes>\n<unit_tests>\nassert Range([1,2]) == 1\nassert Range([1,1,1,1,1,1,5]) == 4\nassert Range([2,2,1,3]) == 2\nassert Range([-10,-3,-1]) == 9\nassert Range([-10,3,1]) == 13\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am working on the `Range()` function and I am getting unexpected results.'}, {'role': 'assistant', 'content': ""Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?""}, {'role': 'user', 'content': 'The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.'}, {'role': 'assistant', 'content': 'This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?'}, {'role': 'user', 'content': 'Oh. So I should choose a really big number for smallest and a really small number for largest?'}, {'role': 'assistant', 'content': 'Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.', 'alt': [""Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?""]}, {'role': 'user', 'content': 'Would it work to just set them to start as an element of the array?'}, {'role': 'assistant', 'content': 'And which element of the array would you set it to?', 'alt': ['That is correct. Why would that be the case?']}, {'role': 'user', 'content': 'I set it to the first element of the array and it works now! Thank you!\n```python\n1. def Range(array):\n2.\tsmallest = array[0]\n3.\tlargest = array[0]\n4.\tfor element in array:\n5.\t\tif(element > largest):\n6.\t\t\tlargest = element\n7.\t\tif(element < smallest):\n8.\t\t\tsmallest = element\n9.\treturn largest - smallest\n```'}, {'role': 'assistant', 'content': ""I'm glad I could help you! Is there anything else I can help you with today?""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does ""range"" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does ""range"" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = -1
+for i in range(1, len(array)):
+	if(value == array[i]):
+		index = i
+return index","On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.",Replace `1` with `0` in the `range` call on line 3.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_68_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(1, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Does the first test case pass?', 'Which line has the first failing test case?', 'Have you read the instructions carefully to check if your code does everything it needs to?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Which line has the first failing test case?', 'alt': ['Does the first test case pass?', 'Which line has the first part of your function on it?', 'What is your function supposed to do?']}, {'role': 'user', 'content': ""It's failing test 4, on line 11""}, {'role': 'assistant', 'content': 'Why is that one failing?', 'alt': ['Is the value in the array?', 'Which line has the first part of your function in it?', 'How is that one different from the first test case on line 8?']}, {'role': 'user', 'content': ""I don't know, it can't find the four.""}, {'role': 'assistant', 'content': ""Since it can't find the four, can it find other values?"", 'alt': ['Is there a four in the array?', 'Is that different from test case 1?', 'Which line has the first part of your function in it?']}, {'role': 'user', 'content': 'It found the one in the first test case.'}, {'role': 'assistant', 'content': ""Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?"", 'alt': ['What makes test case 1 and test case 4 different?', 'Which line has the first part of your function in it?', 'What part of the code checks each element in the array?']}, {'role': 'user', 'content': 'Maybe the problem is in the loop part where I check the values.'}, {'role': 'assistant', 'content': 'What line is that on?'}, {'role': 'user', 'content': ""It's on line 3.""}, {'role': 'assistant', 'content': 'Very good, so where should it start looking and stop looking?', 'alt': ['What exactly does this line do?', 'What does ""range"" mean in Python?']}, {'role': 'user', 'content': 'It should start at the first element and stop at the end of the array.'}, {'role': 'assistant', 'content': 'Which part of that line indicates that?', 'alt': ['What does ""range"" mean in Python?', 'What is the numeric value of the first index in an array in Python?']}, {'role': 'user', 'content': 'The part inside the range.', 'alt': [""Oh! I'm starting at 1 instead of 0""]}, {'role': 'assistant', 'content': 'Which index does it start at?', 'alt': ['What is the numeric value of the first index in an array in Python?', 'How do you find the first index of an array in Python?']}, {'role': 'user', 'content': 'It starts at 1.', 'alt': [""I'm starting in the wrong place!""]}, {'role': 'assistant', 'content': 'What number marks the first index of an array in Python?', 'alt': ['Could it be skipping anything?']}, {'role': 'user', 'content': ""Arrays in Python start at 0, I'm skipping the first index!""}, {'role': 'assistant', 'content': 'How would you fix it?\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```', 'alt': ['What number should be there?']}, {'role': 'user', 'content': 'I switched it to a zero and it works! Thanks!'}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = 0
+for i in range(0, len(array)):
+	if(value == array[i]):
+		index = i
+return index",The function returns 0 when `value` is not in `array` instead of returning -1.,Initialize `index` to -1 on line 2.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_67_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = 0\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nThe function returns 0 when `value` is not in `array` instead of returning -1.\n</bug_desc>\n<bug_fixes>\nInitialize `index` to -1 on line 2.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.'}, {'role': 'assistant', 'content': 'Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?'}, {'role': 'user', 'content': '`index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.'}, {'role': 'assistant', 'content': 'And what would distinguish that action from the function finding a match at index 0?', 'alt': ['Can you explain the difference between that and if the first element is the last index of the value?']}, {'role': 'user', 'content': ""I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.""}, {'role': 'assistant', 'content': 'The intended return value is -1, as given in the problem.', 'alt': ['This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.']}, {'role': 'user', 'content': ""Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```""}, {'role': 'assistant', 'content': ""I'm glad to be of assistance, is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+   index = -1
+   for i in range(len(array)-1, -1):
+       if(array[i] == value):
+           index = i
+           break
+   return index","On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.","Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.","assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_69_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n</bug_code>\n<bug_desc>\nOn line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.\n</bug_desc>\n<bug_fixes>\nChange the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': ""Okay, let's go over the code. Does the first test case pass?"", 'alt': ['Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': ""No, it doesn't pass.""}, {'role': 'assistant', 'content': ""Let's start by going over the first line of your function, what does line 1 do?"", 'alt': [""Let's start with your function. What do you think is the most complicated part?"", 'Can you describe what your function does?']}, {'role': 'user', 'content': 'It takes in the array and the value we are looking for.'}, {'role': 'assistant', 'content': 'Very good, does line 1 take in both of those things?', 'alt': [""Very good, let's move on to the next area, what does line 2 do?"", 'Very good, what can you explain what else your function is supposed to do?', 'What do you think is the most complicated part of your function?']}, {'role': 'user', 'content': 'Yes, line 1 does.'}, {'role': 'assistant', 'content': ""Okay, let's move on to the next area, what does line 2 do?"", 'alt': ['What is the next thing your function needs to do?', ""Let's check the most complex part of the function for problems next, where would you say that is?"", ""Let's make sure your function ends correctly, what value is it returning?""]}, {'role': 'user', 'content': 'It makes the index variable that keeps track of where the value is.'}, {'role': 'assistant', 'content': 'What should your function do next?', 'alt': [""Let's make sure your function ends correctly, what value is it returning?"", 'Why do we start index at -1?']}, {'role': 'user', 'content': 'It needs to loop through the list.'}, {'role': 'assistant', 'content': ""Let's examine that loop carefully. What variable controls the loop?"", 'alt': [""Let's examine that loop carefully,  what determines how many times the loop will run?"", ""Let's check that loop carefully, how should we move through the list?"", 'Is there anything special about how we are moving through the list?']}, {'role': 'user', 'content': 'The variable i controls the loop.'}, {'role': 'assistant', 'content': 'What value should i have on the first iteration of the loop?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", ""Let's examine that loop carefully,  what determines how many times the loop will run?""]}, {'role': 'user', 'content': 'The loop is supposed to start at the highest value in the array minus 1.'}, {'role': 'assistant', 'content': 'Is there anything special about how we are moving through the list?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", 'What value should i have at the end of the loop?']}, {'role': 'user', 'content': 'We are moving through the list backward.'}, {'role': 'assistant', 'content': 'Check the Python documentation, how do we iterate in a loop by default?', 'alt': ['Check the Python documentation, what is the default step?', 'Check the Python documentation, how would we move through a list not incrementing by one each time?', 'Have you ever moved through a list in reverse with range?']}, {'role': 'user', 'content': 'Oh! In Python it increases by one by default! We are going the wrong way.'}, {'role': 'assistant', 'content': 'What would you need do in the code to fix that?\n```python\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n```'}, {'role': 'user', 'content': 'I need to add a -1 step!'}, {'role': 'assistant', 'content': 'Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>","Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```","import math
+def area_circle(radius):
+   if radius < 0:
+       return 0
+   return math.pi * radius ** radius","On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.","Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`","import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)",67_70_area_circle,"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+","{'system': '<problem>\nWrite a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.\n\n## Example Cases:\n```\narea_circle(1.0) => 3.141\narea_circle(2.5) => 19.634\narea_circle(3.6) => 40.715\narea_circle(4.1) => 52.810\narea_circle(7.0) => 153.938\narea_circle(-2.0) => 0\n```\n</problem>\n<bug_code>\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** radius\n</bug_code>\n<bug_desc>\nOn line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.\n</bug_desc>\n<bug_fixes>\nChange the return statement on line 4 to `math.pi * radius * radius`\nChange the return statement on line 4 to `math.pi * radius **2`\n</bug_fixes>\n<unit_tests>\nimport math\nassert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)\nassert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)\nassert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)\nassert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)\nassert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)\nassert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, do you have any ideas what the problem is?', 'alt': ['Are any of the test cases passing?', 'Recheck the instructions, do you think anything is missing?']}, {'role': 'user', 'content': ""No, I don't know what's wrong."", 'alt': ['The first test case is passing, but the second one is failing.']}, {'role': 'assistant', 'content': ""Okay, let's start by looking at the test cases, does the one on line 8 pass?"", 'alt': ['Check the instructions, did you skip any steps?', 'What exactly is this function designed to do?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': ""Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?"", 'alt': [""That's interesting, why do you think the first test case is passing?"", 'What is the radius of the circle in the first test case that is passing?', 'What is the radius of the circle in the first test case that is failing?', 'Look at the if-statement on line 3, do you see any problems with it?']}, {'role': 'user', 'content': 'I calculate the area on line 5.'}, {'role': 'assistant', 'content': 'Look carefully at that line, can you tell me exactly what the code there does?', 'alt': [""First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?"", 'What is the formula for calculating the area of a circle?', 'What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Look carefully at that line, can you tell me exactly what the code there is supposed to do?']}, {'role': 'user', 'content': ""That's where the area of the circle is calculated.""}, {'role': 'assistant', 'content': ""What's the formula for calculating that?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': 'Pi times the radius of the circle squared.', 'alt': [""Oh! I'm not squaring the radius, I'm multiplying it times itself!""]}, {'role': 'assistant', 'content': ""Very good, so let's check that part, do you have Pi in the line?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': ""Yes, that's the math.pi part.""}, {'role': 'assistant', 'content': 'Very good, and do you have the radius in there?', 'alt': ['What do you multiply pi by?', 'Are you multiplying pi by the correct value?']}, {'role': 'user', 'content': ""Yes, that's the radius variable."", 'alt': [""I'm not squaring it!""]}, {'role': 'assistant', 'content': 'What are you supposed to do with the radius?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?', 'How do you square a variable?']}, {'role': 'user', 'content': ""I'm supposed to square it.""}, {'role': 'assistant', 'content': 'How do you square a number in Python?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?']}, {'role': 'user', 'content': ""It's ** with a 2."", 'alt': [""I'm raising it to itself, not squaring it!""]}, {'role': 'assistant', 'content': 'Look at that line again, are you squaring the value?'}, {'role': 'user', 'content': ""No! I'm raising it to itself. I'll fix it.\n```python\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** 2\n```""}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': ""Yes! It's passing all the test cases! Thanks!""}]}"
+"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>","Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```","def get_combinations(list_c):
+   ans=[]
+   for i in range(0,len(list_c)):
+       for j in range(i,len(list_c)):
+           ans.append(list_c[j]+list_c[i])
+   return ans","On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it.","On line 4, change the for loop to `for j in range(len(list_c))`.","assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']",69_81_get_combinations,"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+","{'system': ""<problem>\nWrite a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.\n\n## Example Cases:\n```\nget_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']\nget_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nget_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n```\n</problem>\n<bug_code>\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(i,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n</bug_code>\n<bug_desc>\nOn line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. \n</bug_desc>\n<bug_fixes>\nOn line 4, change the for loop to `for j in range(len(list_c))`.\n\n</bug_fixes>\n<unit_tests>\nassert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']\nassert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nassert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': ""Okay, let's look at the code. Tell me about what happens on line 2?"", 'alt': [""Okay, let's go over the code. Does the first test case pass?"", 'Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': 'Line 2 makes an empty list that we are going to fill later.'}, {'role': 'assistant', 'content': ""Yes, now let's move on to the first part of the loop. What happens on line 3?"", 'alt': ['Where do you think the problem is?', 'Do you see any problems with line 2?']}, {'role': 'user', 'content': 'Line 3 makes a for loop.'}, {'role': 'assistant', 'content': 'What is the variable name for the iterator made on line 3?', 'alt': ['What controls the loop?', 'How many times does the loop iterate?', 'What is the role of range on line 3?']}, {'role': 'user', 'content': 'The iterator is named i.'}, {'role': 'assistant', 'content': 'What value does i start on, and what value does it stop on?', 'alt': ['What determines when that loop ends?', 'How many times does it iterate?', 'What is range for?']}, {'role': 'user', 'content': 'i is supposed to start at 0 and end at the length of the list.'}, {'role': 'assistant', 'content': 'Look at range, does i start and stop where it should?', 'alt': ['How many times does it iterate?', 'What determines that the loop runs the right number of times?']}, {'role': 'user', 'content': 'Yes, that part looks right.'}, {'role': 'assistant', 'content': ""Let's check the second loop next. Where does it start?""}, {'role': 'user', 'content': 'The loop starts on line 4.'}, {'role': 'assistant', 'content': 'What iterator is made on that line?', 'alt': ['How many times should that loop iterate?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'We make j on that line.'}, {'role': 'assistant', 'content': 'How many times should that loop iterate?', 'alt': ['Where in the array list should we start for the second term?', 'Should we go through the whole array list for the second term in the combination?', 'What part of the code on that line controls the iteration of the loop?']}, {'role': 'user', 'content': 'It should iterate once for every item in `list_c`.', 'alt': [""Oh! It's starting at i not at 0!""]}, {'role': 'assistant', 'content': 'What value should it start at to iterate once for every item in list_c?', 'alt': ['What part of the code on that line controls the iteration of the loop?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'It should start at the beginning of the list, at 0.'}, {'role': 'assistant', 'content': 'What piece of the code would control that?'}, {'role': 'user', 'content': 'The values inside of range. Oh! I need to make it start at 0 not at i!\n```python\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(0,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n```'}, {'role': 'assistant', 'content': ""Great! Now let's run the code and see if it works.""}, {'role': 'user', 'content': 'It works! Thank you!'}]}"
+"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>","Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```","def my_func(valList):
+   result = {}
+   for key, value in valList:
+        result[key] = [value]
+   return result","The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.","Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`","assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}",7_35_integer_grouping,"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+","{'system': '<problem>\nImplement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where\n`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.\nReturn a dictionary where the:\n* key: first elements of `valList`\n* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.\n\n```py\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\n```\nIn the example above:\n\n* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`\n* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`\n* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`\n\n## Example Cases:\n```\nmy_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nmy_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n```\n</problem>\n<bug_code>\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.    return result\n</bug_code>\n<bug_desc>\nThe function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  \n</bug_desc>\n<bug_fixes>\nReplace line 4 with the following lines:\n```py\nif key in result.keys():\n      result[key].append(value)\nelse:\n      result[key] = [value]\n```\nReplace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`\n</bug_fixes>\n<unit_tests>\nassert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}\nassert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nassert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice."", 'alt': ['Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.', 'Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?', ""Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?"", 'Sure. Can you go through your code line by line and explain to me what each line is supposed to do?', 'Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?', 'Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?']}, {'role': 'user', 'content': ""I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?', 'alt': ['That is correct. Do you know how to append a new element to a list?']}, {'role': 'user', 'content': ""I did that, but when I run my code I get a `KeyError` message in line 4.\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] += [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict', 'alt': ['Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?', 'Do you know what happens when you try to get a value using a key that does not exist in the dictionary?']}, {'role': 'user', 'content': ""It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.        print('key = ', key, ' value = ', result[key])\n9.    return result\n10.\n11.my_func([(1, 2), (1, 3)])\n```"", 'alt': ['It is raised when `key` is not in the map.']}, {'role': 'assistant', 'content': 'Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?'}, {'role': 'user', 'content': 'I did that and it works on all test cases. Thank you!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.    return result\n```'}, {'role': 'assistant', 'content': ""You're welcome, I am glad I could be of help.""}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of ""years"" in line 8?
+	<alt>Where does ""current_fee"" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+
+   current_fee = 623.00
+   years = 0
+   total_fee = current_fee
+
+   while total_fee < target_amount:
+       total_fee = current_fee*(1.015**years)
+       years += 1
+
+   return years","On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.",Move line 9 to be above line 8 and within the while loop.,"assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_78_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        total_fee = current_fee*(1.015**years)\n9.        years += 1\n10.\n11.    return years\n</bug_code>\n<bug_desc>\nOn line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.\n</bug_desc>\n<bug_fixes>\nMove line 9 to be above line 8 and within the while loop.\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm really stuck!""}, {'role': 'assistant', 'content': ""Let me help, do you have any idea what's wrong?"", 'alt': ['What test cases are passing?', 'Have you read the instructions and made sure you are doing everything?', 'Where do you think the problem is?']}, {'role': 'user', 'content': ""I don't know. None of the test cases are passing.""}, {'role': 'assistant', 'content': ""Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?"", 'alt': [""Let's start by checking the math, what numbers do we start with?"", 'How should the calculation work?', 'Could we add some print statements to check the math?']}, {'role': 'user', 'content': ""That's where I set up the variables.""}, {'role': 'assistant', 'content': ""Okay, let's check the loop now, what is it for?""}, {'role': 'user', 'content': ""That's where we calculate the change over all the years.""}, {'role': 'assistant', 'content': 'So what happens on line 7?', 'alt': ['How do we decide when we want to stop looping?', 'Can you explain the calculation on line 8?', 'What is the purpose of line 9?']}, {'role': 'user', 'content': 'Line 7 starts the loop, and sets it to run until the fee goes over the target.'}, {'role': 'assistant', 'content': ""Okay, so now let's check on line 8, what does that line do?"", 'alt': ['What is the purpose of line 9?', 'Does anything look incorrect with line 7?']}, {'role': 'user', 'content': ""That's where we do the calculation.""}, {'role': 'assistant', 'content': 'What is the purpose of line 9?', 'alt': ['What is the role of ""years"" in line 8?', 'Where does ""current_fee"" come from in line 8?', 'Could we add a print statement here to check the figures?']}, {'role': 'user', 'content': 'It increments the number of years.'}, {'role': 'assistant', 'content': 'So what value would years have the first time the loop iterates?', 'alt': ['What is the value of years in the calculation on line 8 the first time the loop is run?', 'Should we be incrementing years after we do the calculation?']}, {'role': 'user', 'content': 'Years would start at 0.', 'alt': ['I need to change that, we would calculate at the end of year 1, not year 0!']}, {'role': 'assistant', 'content': 'When would we calculate interest?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': 'At the end of a year.'}, {'role': 'assistant', 'content': 'When would we want to calculate the number of years?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': ""It's off by 1, I should be incrementing first!""}, {'role': 'assistant', 'content': 'Make that change and try running it. What happens?\n```python\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        years += 1\n9.        total_fee = current_fee*(1.015**years)\n10.\n11.    return years\n```'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+   i=623
+   years=0
+   while i < target_amount:
+       years= years+1
+       i= 0.015*i
+   return years","On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.","On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`","assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_77_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= 0.015*i\n7.    return years\n</bug_code>\n<bug_desc>\nOn line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.\n</bug_desc>\n<bug_fixes>\nOn line 6, replace `i= 0.015*i` with `i= i + 0.015*i`\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', ""Let's start with the first part of your function, what happens on lines 2 and 3?"", ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's start with your function. What happens on lines 2 and 3?"", 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', 'Have you read the prompt carefully?', ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': 'I declare some variables for the starting amount and the years.'}, {'role': 'assistant', 'content': ""Very good, so let's look at the loop part now. What happens on line 4?"", 'alt': ['What should happen next?', 'Does your function return the correct variable?']}, {'role': 'user', 'content': ""It checks if i is less than the target amount and keeps looping if that's true.""}, {'role': 'assistant', 'content': ""That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?"", 'alt': ['Is that what it is supposed to do?', 'What do we do on line 5?']}, {'role': 'user', 'content': ""It's the current amount plus the interest rate times the current amount."", 'alt': [""I don't know.""]}, {'role': 'assistant', 'content': 'What line in your code would have that calculation?', 'alt': ['Does that calculation match the one in your code?']}, {'role': 'user', 'content': 'Line 6'}, {'role': 'assistant', 'content': 'Look carefully at that line, does it match the equation you just told me about?', 'alt': ['Is there anything wrong with that line?', 'What would 623 times 0.015 be?']}, {'role': 'user', 'content': ""No! It doesn't match, I forgot to add back the initial amount!\n```python\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= i+0.015*i\n7.    return years\n```""}, {'role': 'assistant', 'content': 'Try running the code here, what happens?'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>","Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```","import random as rand
+rand.seed(42)
+
+def my_func(len):
+   y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+   return y",The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.,"Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.","assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]",8_36_plot_function,"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+","{'system': ""<problem>\nWrite a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.\n\n## Example Cases:\n```\nmy_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nmy_func(7) => [4, 7, 13, 19, 26, 32, 41]\nmy_func(5) => [5, 7, 17, 20, 29]\nmy_func(3) => [2, 7, 14]\nmy_func(1) => [1]\n```\n</problem>\n<bug_code>\n1. import random as rand\n2. rand.seed(42)\n3.\n4. def my_func(len):\n5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))\n6.    return y\n</bug_code>\n<bug_desc>\nThe function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.\n</bug_desc>\n<bug_fixes>\nReplace `def yOf(x):` with `lambda x:` on line 4.\nAfter line 2 insert the following:\n```py\ndef yOf(x, len):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.\nAfter line 4 insert the following:\n```py\ndef yOf(x):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.\n</bug_fixes>\n<unit_tests>\nassert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nassert my_func(7) == [4, 7, 13, 19, 26, 32, 41]\nassert my_func(5) == [5, 7, 17, 20, 29]\nassert my_func(3) == [2, 7, 14]\nassert my_func(1) == [1]\n</unit_tests>\n<stu_desc>\nThe student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?""}, {'role': 'assistant', 'content': 'Certainly. Can you describe what you know about the `map` function so far with an example if possible?', 'alt': ['Certainly. Can you describe what your code does on line 5?', 'Certainly. Do you know what the `map` function takes in as parameters?']}, {'role': 'user', 'content': 'So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.'}, {'role': 'assistant', 'content': 'Ah good explanation. When you try to run your code what do you observe in the terminal?', 'alt': ['Good explanation. So what is the specific issue that you have?', 'Good explanation. Where can you learn more about the `map` function and its use?']}, {'role': 'user', 'content': 'So when I try to run my code, it throws a syntax error on line 5.'}, {'role': 'assistant', 'content': 'Can you explain to me what the `def` reserved word in Python does?', 'alt': ['Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?', ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""]}, {'role': 'user', 'content': '`def` stands for define and it creates a function in Python to be used later on in the code.'}, {'role': 'assistant', 'content': ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""}, {'role': 'user', 'content': 'I guess not from the looks of it. Maybe I should define my function outside of the `map` call?', 'alt': ['It seems to be the case. Not really sure though what to do though.']}, {'role': 'assistant', 'content': ""Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?""}, {'role': 'user', 'content': 'Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.', 'alt': ['Maybe after line 4? Inside of `my_func` so that it is within scope?', 'Not really sure.']}, {'role': 'assistant', 'content': ""Sounds good. Let's try it. What do you pass into `map` now?""}, {'role': 'user', 'content': ""Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf,  range(len)))\n7.    return y\n```""}, {'role': 'assistant', 'content': 'What does `len` refer to on line 4?'}, {'role': 'user', 'content': 'Hmm. It refers to my variable `len` does it not?', 'alt': ['Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.']}, {'role': 'assistant', 'content': 'Where do you declare `len` in your code?'}, {'role': 'user', 'content': 'I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.'}, {'role': 'assistant', 'content': 'According to the problem specification, what is the upper-bound of the randomly generated integers?', 'alt': ['Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?']}, {'role': 'user', 'content': 'Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.', 'alt': ['Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.']}, {'role': 'assistant', 'content': 'Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?', 'alt': ['Good. Where in your code would you need to pass `len` to `yOf`?']}, {'role': 'user', 'content': ""I actually don't know how to do that."", 'alt': [""I don't know how to do that. But I guess it would be inside the `map` function."", 'I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.']}, {'role': 'assistant', 'content': 'Can you point me to a line where you think you might want to pass a new parameter to `yOf`?', 'alt': ['Do you know how many parameters `map` takes in?', 'Where can you learn more about how to pass multiple parameters to a function called in `map`?']}, {'role': 'user', 'content': 'I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.'}, {'role': 'assistant', 'content': 'Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?'}, {'role': 'user', 'content': 'Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return  x * 6 + rand.randint(1, len)  \n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'Good. What do you observe after running this?', 'alt': ['How many parameters does the function `yOf` take on now?', 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'What do you notice in your terminal now when you run this?', 'alt': ['How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'I notice that it runs without any issues but it fails all the test cases. Hmm..'}, {'role': 'assistant', 'content': 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?', 'alt': [""That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?""]}, {'role': 'user', 'content': 'Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.', 'alt': ['Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.']}, {'role': 'assistant', 'content': 'Good. How many iterable elements are in your second iterables parameter to the `map` function?'}, {'role': 'user', 'content': ""Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len] * len))\n7.    return y \n```""}, {'role': 'assistant', 'content': 'Good work. Does your code pass all the tests?'}, {'role': 'user', 'content': 'Yes now it does! Thank you so much for all your help! I learned a lot today!'}]}"
+"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says ""'int' object is not subscriptable"" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `""'int' object is not subscriptable""` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>","Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```","def det2d(matrix):
+   return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+
+def determinant(matrix):
+
+   subm1 = [val[1:3] for val in matrix[1:3]]
+   subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+   subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+
+   return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)","On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.","Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.","assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329",9_38_calculating_determinant,"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+","{'system': '<problem>\nWrite a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.\n## Example Cases:\n```\ndeterminant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0\ndeterminant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315\ndeterminant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156\ndeterminant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329\n```\n</problem>\n<bug_code>\n1. def det2d(matrix):\n2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\n3.\n4. def determinant(matrix):\n5.\n6.    subm1 = [val[1:3] for val in matrix[1:3]]\n7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]\n8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]\n9.\n10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n</bug_code>\n<bug_desc>\nOn line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.\n</bug_desc>\n<bug_fixes>\nChange line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.\n</bug_fixes>\n<unit_tests>\nassert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0\nassert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315\nassert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156\nassert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices."", 'alt': [""I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.""]}, {'role': 'assistant', 'content': ""I know we can fix this together. What are the issues you're having?"", 'alt': ['Can you describe your code of the method `determinant` line by line to me?', ""Can you explain how you're creating the 2x2 submatrices?""]}, {'role': 'user', 'content': 'Well, at first I was getting the wrong answer and now I\'m getting TypeErrors. It says ""\'int\' object is not subscriptable"" when I\'m calling the `det2d` function.'}, {'role': 'assistant', 'content': 'What are the intended inputs and outputs of the `det2d` function?', 'alt': ['What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.', 'Can you describe the `det2d` function to me?', 'What does the error message `""\'int\' object is not subscriptable""` mean?', 'How do you know that the error is coming from the `det2d` function?', 'Which variables are getting subscripted and how do you know what the data type of those variables are?', ""Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?""]}, {'role': 'user', 'content': ""I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.""}, {'role': 'assistant', 'content': 'Great! Did you make the same mistake anywhere else?', 'alt': ['Great! Does that also apply for `subm3` or is that calculated correctly?', 'What about the other two submatrices?']}, {'role': 'user', 'content': ""I think I made a similar mistake with `subm3`. I'll change both. It works!\n```python\n def det2d(matrix):\n    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\ndef determinant(matrix):\n    subm1 = [val[1:3] for val in matrix[1:3]]\n    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]\n    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]\n    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n```""}]}"
diff --git a/data/manual_evaluation_dialogues.csv b/data/manual_evaluation_dialogues.csv
new file mode 100644
index 0000000000000000000000000000000000000000..772696acab1deaede092f6b5f56f04feb4773dca
--- /dev/null
+++ b/data/manual_evaluation_dialogues.csv
@@ -0,0 +1,994 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 or n == 2:
+       return 1
+   else:
+       return fibonacci(n) + fibonacci(n-1)",`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.,Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_5_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n) + fibonacci(n-1)\n</bug_code>\n<bug_desc>\n`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.\n</bug_desc>\n<bug_fixes>\nReplace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?'}, {'role': 'assistant', 'content': 'I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?', 'alt': ['According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?', 'According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?', 'Can you explain what infinite recursion means?', 'Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?', ""Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?"", 'Can you explain what a recursive function is? When do we call a function recursive?', 'According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?']}, {'role': 'user', 'content': 'I believe it is line 7, because that is the line that is executed when `n` is larger than 2.'}, {'role': 'assistant', 'content': 'That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?', 'alt': ['Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?', 'Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?']}, {'role': 'user', 'content': 'Well, the function is called recursively to compute `fibonacci(3)`.\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 1) + fibonacci(n - 2)\n```', 'alt': ['Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.', 'Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...', 'The call `fibonacci(n)`.']}, {'role': 'assistant', 'content': 'So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?', 'alt': ['Do you see now why infinite recursion happens?', 'So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?']}, {'role': 'user', 'content': 'Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 2) + fibonacci(n - 1)\n```'}, {'role': 'assistant', 'content': 'Great, your program now works as expected!'}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x <= seq[i]:
+     return i",The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.,"Insert a line following line 4, with one indentation containing `return len(seq)`","assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_45_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n</bug_code>\n<bug_desc>\nThe function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.\n</bug_desc>\n<bug_fixes>\nInsert a line following line 4, with one indentation containing `return len(seq)` \n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output.'}, {'role': 'assistant', 'content': 'What inputs have you tried? When do you get `None`?', 'alt': ['Do you notice a pattern with the cases that produce `None`?', 'When do you notice `None` as the output?', 'What inputs have you tried? When do you get `None`?', 'It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?']}, {'role': 'user', 'content': 'I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.', 'alt': ['I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list', 'It seems like I get the wrong answer when `x` is bigger than all the existing list elements']}, {'role': 'assistant', 'content': 'Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?', 'alt': ['Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?', 'What do you expect your code to return when `x` is bigger than the `seq` elements?']}, {'role': 'user', 'content': 'Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.'}, {'role': 'assistant', 'content': 'What happens if `x` is not less than or equal to any element?', 'alt': ['What does your code do if `x` is greater than all of the elements in `seq`?']}, {'role': 'user', 'content': ""I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!\n```python\n def search(x, seq):    \n  for i in range(len(seq)):\n    if x <= seq[i]:\n      return i\n  return len(seq)\n```""}, {'role': 'assistant', 'content': 'Good work. Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       max_len = max(len(crt_str), max_len)        
+
+       pos = s.find(t, start)
+   
+   last_str = s[start:]
+   max_len = max(len(last_str), max_len)
+
+   return max_len","The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.",On line 8 insert the code `start = pos + len(t)`.,"assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_56_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n</bug_code>\n<bug_desc>\nThe value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.\n</bug_desc>\n<bug_fixes>\nOn line 8 insert the code `start = pos + len(t)`.\n</bug_fixes>\nOn line 11 insert a new line with `ind += len(t)`.\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code does not stop and I do not understand why, can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?"", 'alt': ['Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.', 'Sure. Can you tell me the role of the variable `start`?']}, {'role': 'user', 'content': 'In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.        start = pos + len(t)\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       crt_len = len(crt_str)
+       if crt_len > max_len:
+           max_len = crt_len
+       start = pos + len(t)
+       pos = s.find(t, start)
+   return max_len","The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.","After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```","assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_46_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    return max_len\n</bug_code>\n<bug_desc>\nThe code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.\n</bug_desc>\n<bug_fixes>\nAfter line 11, insert the following outside the while loop scope:\n```py\nlast_str = s[start:]\nlast_len = len(last_str)\nif last_len > max_len:\n       max_len = last_len\n```\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?'}, {'role': 'assistant', 'content': 'I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?', 'alt': ['Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?', 'Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?', 'Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?', ""Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?"", 'Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?', 'Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?']}, {'role': 'user', 'content': '`max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.'}, {'role': 'assistant', 'content': ""Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?"", 'alt': ['Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?', 'Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?', 'Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?']}, {'role': 'user', 'content': 'Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    \n13.    last_str = s[start:]\n14.    last_len = len(last_str)\n15.    if last_len > max_len:\n16.       max_len = last_len\n17.    \n18.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+       return newNums","On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.",Remove a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_26_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.        return newNums\n</bug_code>\n<bug_desc>\nOn line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.\n</bug_desc>\n<bug_fixes>\nRemove a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck.""}, {'role': 'assistant', 'content': 'What should your code be doing?', 'alt': ['Which test cases (if any) are failing?', 'What are you stuck on?', 'Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?']}, {'role': 'user', 'content': ""Right now, it's only returning the first number in the list, not all of them."", 'alt': [""It's only passing the second test case.""]}, {'role': 'assistant', 'content': ""Okay, let's look at your loop. Do you see anything that could be causing it to end early?"", 'alt': ['Have you checked the loop and how many times it iterates?', ""Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?"", 'What do you think might cause your function to return a list with one element instead of multiple elements?', ""Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?"", 'What do you think is causing the lists not to include all the numbers?', 'Look at line 3, is it iterating through the whole list?']}, {'role': 'user', 'content': ""No I do not. I'm iterating through the whole list of numbers."", 'alt': [""I don't know, how could I find out?"", 'Oh, I see, the return statement is in the wrong place.']}, {'role': 'assistant', 'content': ""Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?"", 'alt': ['What can cause a function to end early?', 'What forces a loop to end?']}, {'role': 'user', 'content': 'Line 3 starts the loop, and it iterates through everything in `nums`.'}, {'role': 'assistant', 'content': 'Good, then what happens?', 'alt': ['Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?', 'Think back to what you know about functions. What makes them end early?', 'Think back to what you know about loops, what can make them stop?']}, {'role': 'user', 'content': 'The if statement starts on line 4, it checks if the number is even.'}, {'role': 'assistant', 'content': 'Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?', 'alt': ['Do you notice anything on line 4 that causes the function to end early?', 'Do you notice anything on line 4 that causes the for loop to end?']}, {'role': 'user', 'content': ""I don't see anything that can cause that problem."", 'alt': ['I see! The return statement after the if-statement is indented too much!']}, {'role': 'assistant', 'content': 'Okay, so what happens next on line 6?'}, {'role': 'user', 'content': 'It returns the list.', 'alt': [""I get it! It's returning after every iteration!"", ""It's returning too soon.""]}, {'role': 'assistant', 'content': 'When should it return the list?', 'alt': ['Would a return statement end a loop?', 'Would a return statement cause the function to terminate early?', 'Is there anything on this line that would cause the loop or the function to end early?', 'When does your return statement execute?']}, {'role': 'user', 'content': 'It should return the list when it finishes all the numbers.'}, {'role': 'assistant', 'content': 'Look at line 6, what level of indentation is the list on?', 'alt': ['Think back to what you have learned about indentation, how does that control the order of actions in a loop?', 'Can the return statement end the loop early?']}, {'role': 'user', 'content': ""I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```""}, {'role': 'assistant', 'content': 'What does it return now, after you changed the indentation of the return statement?'}, {'role': 'user', 'content': 'It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.'}, {'role': 'assistant', 'content': ""You're welcome. Let me know if I can be of any further assistance.""}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   i = 0
+   while apples > 0 and apples > children:
+       apples = apples - children
+       i += 1
+   return i","The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.",Replace `apples > children` with `apples >= children` on line 3.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_59_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples > children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n</bug_code>\n<bug_desc>\nThe while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.\n</bug_desc>\n<bug_fixes>\nReplace `apples > children` with `apples >= children` on line 3.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My function fails two test cases and I do not understand why, can you help?'}, {'role': 'assistant', 'content': 'Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?', 'alt': [""Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?"", ""Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?"", 'Sure. Can you explain to me what you are trying to do with the while loop?', 'Sure. Can you tell me what the loop condition `apples > children` is there for?', 'Sure. Can you explain your code to me, what is supposed to do, line by line?']}, {'role': 'user', 'content': 'It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.', 'alt': [""It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.""]}, {'role': 'assistant', 'content': 'Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?', 'alt': ['Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.', ""Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?""]}, {'role': 'user', 'content': 'It is 1 less than the correct number.'}, {'role': 'assistant', 'content': 'Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?', 'alt': ['Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?']}, {'role': 'user', 'content': 'Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!\n```python\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples >= children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `""E""` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+12. store = turn_clockwise(""N"")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == ""N"":
+        return ""E""
+    elif compass_point == ""E"":
+        return ""S""
+    elif compass_point == ""S"":
+        return ""W""
+    elif compass_point == ""W"":
+        return ""N""
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point == ""N"":
+       print (""E"")
+   elif compass_point == ""E"":
+       print (""S"")
+   elif compass_point == ""S"":
+       print (""W"")
+   elif compass_point == ""W"":
+       print (""N"")
+   else:
+       print (""None"")","The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.","Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_33_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '\ufeff<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value `None`.\n\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n</bug_code>\n<bug_desc>\nThe function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.\n</bug_desc>\n<bug_fixes>\nReplace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I have a problem. My code does not generate the right result and I cannot figure that out.'}, {'role': 'assistant', 'content': ""Hi! Let's take a look at your code. Could you explain how your code works?"", 'alt': ['Hi! What makes you think that your program is not working properly?', 'Can you give me an example where your code does not return the correct result?', 'I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?']}, {'role': 'user', 'content': 'Ok. My code gets the current `compass_point` and prints the next one.'}, {'role': 'assistant', 'content': 'What do you see as your output in the terminal and what are you passing as `compass_point`?', 'alt': ['What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?']}, {'role': 'user', 'content': 'When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That\'s strange since my output is printed correctly, but my program does not pass any of the tests.'}, {'role': 'assistant', 'content': 'What does a unit test need from a function to ensure that the function works properly?', 'alt': ['Ah. How did you determine whether your function is correct?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?', 'Say you want to store the output of your function into a variable, what would you need to do?', 'What do you think a function needs to pass along its output to say get stored in a variable?']}, {'role': 'user', 'content': 'It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.', 'alt': [""I don't understand the question. Can you tell me more about unit tests?""]}, {'role': 'assistant', 'content': 'Correct. So would you be able to store the value outputted by the function into say a variable?', 'alt': ['Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?']}, {'role': 'user', 'content': 'Hypothetically yes. I should be able to store it in a variable. I have not tried though.'}, {'role': 'assistant', 'content': 'Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'alt': ['Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?']}, {'role': 'user', 'content': 'Ah I think, it would be `""E""` in `store`.'}, {'role': 'assistant', 'content': 'Let’s try it and then print `store`. What do you observe in your terminal?'}, {'role': 'user', 'content': 'Hmm... I see `None`. That’s really strange.\n\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n12. store = turn_clockwise(""N"")\n13. print(store)\n```'}, {'role': 'assistant', 'content': 'What do you think the function needs to have in order to give its output to the variable?', 'alt': ['Do you recall, which reserved word in Python is used to return the output for a function back to a variable?']}, {'role': 'user', 'content': 'Ah! I think it might be `return`. Let me try that.\n```python\ndef turn_clockwise(compass_point):\n    if compass_point == ""N"":\n        return ""E""\n    elif compass_point == ""E"":\n        return ""S""\n    elif compass_point == ""S"":\n        return ""W""\n    elif compass_point == ""W"":\n        return ""N""\n    else:\n        return None\n\t\t\n```', 'alt': ['I’m not really sure.']}, {'role': 'assistant', 'content': 'Very good.', 'alt': ['Very good. Is there a way for you to simplify your code?']}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You’re welcome! Let me know if I can be of any further help.'}]}"
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..69cd2f3befba3bf4fbf9ec6883999b4b44ae4da2
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,119 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student has a misconception about for loop ranges. The student also struggles to explain their code. The student knows how to use the debugger.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I can use the debugger perhaps.
+	<alt>I can add print statements.
+	<alt>I'm not really sure can you suggest a way?
+Assistant: Let's first examine the values of `i`. How many times in total does the for loop iterate?
+User: Using the debugger I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks good! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..065bb32ed9acd4e0e41fe8295da0602690554d9a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,141 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to `0` not `1`? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time and remove the print statement. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks correct! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3e0a27c8151d319d456c91146ba16ef7f1425e5e
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,199 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0, not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that. 
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(n)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that `i` is always 5 when `n` is 5. That doesn't make sense.
+Assistant: Are you sure that you are looking at the values of `i`? Examine line 12.
+	<alt>What variable are you printing on line 12?
+User: Oh whoops! Let me fix that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the terminal output. How many times does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5, and the values of `n` range from 0 to 4 or `n - 1`.
+Assistant: Good. Can you identify other variables that might be important for us to track to identify the issue?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>What would happen to the returned Fibonacci term if the for loop iterates 6 times?
+User: I think it would be good to track the variables `a` and `b` since I return `b` in the end and `a` is used to compute `b`.
+Assistant: Good. What do you think would be a good way for us to track the values of `a` and `b`?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: I think I can add a print statement for these variables inside the for loop!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(f"a: {a}\tb: {b}\t i: {i}")
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good. What do you observe about the values of `b` as the loop iterates?
+User: Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the last value of `b`?
+User: Oh! It's 8 which is what I am returning instead of 5! But why is that?
+Assistant: How was `b` computed in the final iteration of the for loop?
+User: I think `b` was 5 and `a` was 3 so  `b = 3 + 5` which is 8. Not sure how to get it to return 5 though.
+Assistant: What would happen to the returned Fibonacci sequence if the for loop iterates 6 times?
+	<alt>Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: Hm. I think it would `b = 5 + 8` which is 13 the next number in the Fibonacci sequence.
+Assistant: Do you notice a relationship between the number of for loop iterations and the Fibonacci term returned?
+User: Yes! I do think that the more the loop iterates the larger the Fibonacci term is returned. Maybe my for loop is iterating more than it should.
+Assistant: Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code and remove my print statement.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all is correct thank you so much!
+Assistant: You are welcome. Let me know if I can help with anything else!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a9b5b0ef4344a852e7725224c599a5f6b336ecd
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,158 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6b2b5d9ebca861c02068de0a199821dfb9f52a44
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,91 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>Hello! I need help on this my code is failing the first test case.
+Assistant: Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Can you walk me through your code step by step given that `n` is 0?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+	<alt>Can you describe the issue you are facing? Is your code failing any test cases?
+	<alt>Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: Hm... I've never seen assignment being done like this before. I presume it would be a compiler error?
+	<alt>I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Let's verify that. Can you open a Python terminal and type in `x = 0` then on a new line `y = 1 if x < 0 else 0`. What do you observe?
+User: Ah. It works! I learned something new today.
+Assistant: What do you think the value of `y` is?
+User: I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Good. Let's look at your `fibonacci` function. Given that `n` is 0. Can you walk me through your code step by step?
+	<alt>Let's verify that. Can you print `y`? What do you observe?
+	<alt>Good. Let's look at your `fibonacci` function. Given that `n` is 0. What does the if statement on line 2 evaluate to?
+	<alt>Good. Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: On line 2 `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good. Did you try running your code through all the test cases?
+User: Yes. Thank you very much for your help!
+Assistant: You're welcome.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..692135c1808168d758578b95b634ed96cd7e3ff3
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..75350a91e85f7f7fef581e7c82b70b7b582ad5d2
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,79 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: The previous two positions.
+	<alt>The numbers at positions n - 1 and n - 2.
+	<alt>The numbers at positions n - 1 and n - 2. Ah, now I see, I made a mistake on line 7, I used the wrong positions there. Let me fix it... It works now, thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n-1) + fibonacci(n-2)
+
+</code>
+Assistant: Correct. Since the current position is `n`, what are the previous two positions?
+	<alt>That is correct. Looking at your code, does it really add the Fibonacci numbers at the previous two positions?
+User: Ah, now I see what the problem is. The code on line 7 adds the number at the current position, instead of positions `n - 1` and `n - 2`. Let me fix that... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome, happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76f4d0a06fb8486c07330eb167c986744f0e45a4
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,84 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: Can you explain what infinite recursion means?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: Infinite recursion means that the function calls itself without ever stopping.
+	<alt>I am not sure, can you explain infinite recursion to me?
+Assistant: Correct. Where in the code does the function call itself?
+	<alt>Good. Given that the problem is caused by the function calling itself forever, where in the code do you think the problem is?
+User: It is on line 7.
+Assistant: Correct. There are two recursive calls there, can you figure out which of them leads to infinite recursion?
+	<alt>Correct. So, when the function is called as `fibonacci(n)`, if it gets to line 7 it calls `fibonacci(n)` again, and if that is completed it then calls `fibonacci(n - 1)`. Do you see why this leads to infinite recursion?
+User: Ah, I see. It is the call to `fibonacci(n)`, because `fibonacci(n)`calls `fibonacci(n)`which will again call `fibonacci(n)`, forever.
+	<alt>Ah, I see, it is the call to `fibonacci(n)`. I made a mistake, I should have called fibonacci for `n - 1` and `n - 2`. Let me do that ... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+Assistant: Good! That means the code on line 7 is not correct. Can you look at the problem description to see how the Fibonacci number at position `n` needs to be computed and fix your code?
+	<alt>Good! Can you fix the code in line 7 so that it implements what is in the problem description?
+User: Ah, I see now, the previous two numbers are at positions `n - 1` and `n - 2`. Let me fix that... it works now! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..465f2800ce958f878af1ebf2a69e8821aae7a0ea
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>Can you explain what infinite recursion means?
+User: We get the Fibonacci number for `n + 1`. Ah, I see what the problem is, I used the wrong inputs in the recursive calls. Let me fix that... it works, it passes all the tests now. Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+	<alt>We get the Fibonacci number for `n + 1`.
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..051ac2ae597cb75601ac0694350209c2e2f5a0d6
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..bc33e1d17632dbf5f59182fb9124d55463546161
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,82 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: It says to return 1 when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: So will it return `1` when `n` is only equal to `1`?
+	<alt>Will `n` ever be `1` and `2` at the same time?
+User: No, it looks like it will return `1` only when `n` is `1` and `2`.
+Assistant: Will that ever happen?
+	<alt>Is that what you are supposed to do according to the instructions?
+User: No, `n` can be either `1` or `2`, but never both `1` and `2`.
+Assistant: Correct! How do you check if `n` is `1` or `2` instead of both `1` and `2`?
+User: Will it look like this?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: Correct, do you now see the difference between `or` and `and`?
+User: I see it now, `and` evaluates to true only when both cases are correct. But `or` evaluates to true if either of the cases are correct. Thank you for your help!
+Assistant: That is right, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d2154b30aa8f17ece8888c2a5dbedc8c29175f0
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c244e010918d5f3c22614c505ad804ef4eb67c6a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_conversational_thread_1.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+	<alt>If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+Assistant: Let's test each of these separately. How can you check whether the methods are being called?
+User: One way I could check this is by adding `print` statements right before the methods to make sure I'm reaching those parts of the code. It looks like I'm reaching each part, but the sentence isn't changing. I think I'm not using these methods properly.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           print("here1", sen)
+           sen.replace(i, "x")
+      else:
+           print("here2", sen)
+           sen.replace(i, "X")
+  print("here3", sen)
+  sen.swapcase()
+  return sen
+
+</code>
+Assistant: Is there an easy way to modify your code to verify whether your code is modifying the original string?
+     <alt>What makes you think that you are using the methods incorrectly?
+     <alt>Have you considered printing the output of the method calls to see if they are changing the string, for example, `print(sen.replace(i, "x"))`?
+     <alt>Have you considered assigning the output of the method calls to a variable?
+     <alt>Where can you learn more about how `.replace()` and `.swapcase()` work and how they are used?
+User: Hm, I guess I can just assign `sen` the output of the method calls, in case they don't do in-place changes. That works!
+     <alt>I could also just print the output of the method calls to see if they are changing the string.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: Great! let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9160d401c193a67ea8b57aa8e809699d0854c3d7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_socratic_dialogue.txt
@@ -0,0 +1,75 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = "To"` and then `sen.replace("o", "X")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = "English"` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace("o", "X")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67d4e9361aaa605be0735a6ed1c76f8dae5d0cb6
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: Ah I see the problem now. I should use `==` instead of equals to check for equality. Let me edit my code.
+	<alt>I am trying to check if `rev_string` is equal to `string`.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good! Does it pass all the test cases now?
+User: Yes it does! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ccb927b1d35b709abe5b5b8d8ba6901a41f79114
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_2.txt
@@ -0,0 +1,94 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't added yet?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..05f680bfee5168ebe0d451dbcd61e748705c8fe5
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_3.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't completed yet?
+	<alt>I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..608c84efc580ebe5d8951024b6e71480399a0b03
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_socratic_dialogue.txt
@@ -0,0 +1,73 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9e45c7683bf8e36d8dacc6f4354183ee3d9908e6
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: The `[-1:]` slicing operator should return a list in reverse order.
+	<alt>I think it should return a list in reverse order but it's returning the last element of the list instead.
+Assistant: What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Let's run your code through all the test cases. Do you notice a pattern in your function's outputs?
+	<alt>Let's open the terminal and run `[1, 2, 3][-1:]`. What do you observe?
+	<alt>Let's start with a simpler problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+User: It returns `[3]` instead of `[3, 2, 1]`. Hm... it seems to be returning the last element of the list instead of the whole list in reverse order.
+Assistant: Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+User: For an input list `a`, we can get every other element by using `a[::2]`. So `a[::2]` should return `[1, 3]`.
+Assistant: Good. Given that `[-1:]` returns the last element in the list, how do we combine using `::` with `[-1:]` to get every element in reverse order?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Good. `::2` gives us every other element and `[-1:]` gives us the last element. How can we get every element in reverse order?
+User: Oh, I see. We can just get every element of the list in increments of -1. So `a[::-1]`. I'll update my code. It looks like it's working now
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..071edd0259455dc702e145d33c8c244d2bd6d83d
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..111e617adc183b4a313c4a6e21420cebbf15236a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many times will the for loop execute?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>Is that the list that you want to loop through?
+User: It will be executed the length of the `lst2` times.
+	<alt>It will execute 0 times because `lst2` is empty.
+	<alt>How do I find that out?
+Assistant: What is the length of `lst2`?
+	<alt>Is `lst2` the list that you want to loop over?
+User: It is 0, so does that mean the for loop is never executed?
+	<alt>It is 0, should I loop over `lst` instead?
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+	<alt>Yes.
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fb83ca8d767fb22839d3d9cb4f928dc75874b376
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/13_42_limit_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cbbcd5dfa285b7355d54c0d8e3eae61cde9c4fd1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_conversational_thread_1.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! This code isn't working. Can you help?
+Assistant: Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: Well, boolean and Strings are different data types. Booleans have a true or false value, and Strings are just written words.
+	<alt>a boolean true is written like `bool = True`, whereas a String variable is written as str = "True."
+	<alt>I don't think there is a difference. I think both boolean "true" and String "true" looks the same when you write the code. For example, str = true and bool = true.
+Assistant: Let's try an example. How would you declare a string variable "str" and initialize it to the value "true?"
+	<alt>What are the two possible values of a boolean variable in Python?
+User: String str = "true";
+	<alt>Wouldn't you want to use a boolean variable for that instead?
+	<alt>String str = true;
+	<alt>str = true
+	<alt>String str = True;
+Assistant: That's right! Now, how would you declare a boolean variable `bool` and initialize it to false?
+User: boolean bool = false;
+	<alt>boolean bool = False;
+	<alt>boolean bool = "False";
+	<alt>I don't see that we are using boolean variables in the code.
+Assistant: Programming languages are very sensitive to syntax. For example, String variables require the use of quotations around their input. Can you think of any similar constraints to boolean inputs?
+	<alt>Try looking at the Python documentation. Can you find the section where they describe the use of Boolean variables? How does it compare to what you wrote here?
+	<alt>Let's try that in the Python terminal. What happens when you type `bool = false`?
+User: Oh, I see. I was writing `bool = true` when I should have been writing `bool = True`. I am missing a capitalization.
+	<alt>I should be using 0 and 1 instead of false and true.
+	<alt>I can't think of any constraints.
+Assistant: Good! Can you find where you made this mistake in your code?
+	<alt>How can you edit your code to fix this error?
+User: Yes, I found it. I'm going to show you the changed code now.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Good work! Looks like you did it.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fed235c9f380c3072884cf6a17a1c2bd4164c248
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_socratic_dialogue.txt
@@ -0,0 +1,83 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = "True"
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a2444fd8fc1fc32d185025275eff35f4a441991b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ca3e5b177344b28bdac27a25a96d6bb2148a6737
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: Oh, it always returns a position where `seq[i] > x`. I think I need to also test for equality, let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c01957c386144f83d5e40c90e7adc81514e78a49
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: Because the element at position 1 is equal to 5, and according to the problem description whenever the number is present in the input list we should return its position.
+Assistant: Good. Now, can you tell me what happens in your code for test example 1 when `i` takes the value 1? Start with line 3.
+	<alt>Good. Does your code ever test if the number `x` is present in the list?
+	<alt>Good. How can you determine, using code in Python, if a number `x` is present in a list `seq`?
+User: When `i` is 1, `seq[1]` is equal to 5. On line 3, since 5 is not less than 5, this means that line 4 is not executed, so we go back to line `2` where `i` is assigned the next value of 2. Ah, now I understand where the problem is,  I should have tested for equality too, let me do that ... It works now! Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..971311e0e39aa34053be4ca60d7da34fecf47353
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_conversational_thead_1.txt b/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_conversational_thead_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a70d26285fac100164974287447f4465eba01da
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_conversational_thead_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: Can you walk me through how your function handles some simple examples? For example, `search(5, [-1, 5, 8, 10, 12])`.
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: For that example, I get an output of 1. I first iterate through the elements in the list and check when the 5 is less than or equal to the current element, which happens at index 1. 
+	<alt>This just gives an output of 1
+Assistant: I see. What happens when you have a larger `x` value? Try `search(20, [-1, 5, 8, 10, 12])`.
+	<alt>I see. What about when your `x` is not less than or equal to any elements?
+	<alt>That seems right. How do you deal with negative numbers and numbers greater than all the list elements?
+	<alt>Good. Is there a case where your function might not return anything?
+User: For that, my code seems to return `None`. I use the same procedure and iterate through the list element. Oh, I see. Since 20 is greater than all the current list elements, I never get to the `return`
+Assistant: It looks like you just need to handle that other case then. What's a good answer to return when `x` is greater than all the existing elements?
+	<alt>Where would you want to insert an element that is larger than all the current ones?
+	<alt>What's a good place to insert 20 in the example I gave you?
+User: I think I should put it at the end of the list. I'll update the code and see if it works.
+<code>
+ def search(x, seq):
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Looks like it works! Let me know if you need more help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e99e9d5280aee8185297b28e38a4c7cd8e99e12
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d78c074069ad55788fb28f108ae631fa1663e622
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_1.txt
@@ -0,0 +1,108 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+	<alt>That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+User: OK. I think I need to look at the substring that starts at the last value of `start` and ends at the end of the string. Let me do that... It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+	<alt>Not sure how to do that, can you help?
+Assistant: That's great! Glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7b4e3cbce5f3bf61db44e521928097c52f7c4e67
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_2.txt
@@ -0,0 +1,110 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+	<alt>I don't know, how can I find that?
+Assistant: Great. Now that you know where it starts and where it ends, can you add code that extracts this substring and looks at its length too?
+User: I did that, and it works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f4b15267cf56ade259b3d6b9093f52cf9c9cd408
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_3.txt
@@ -0,0 +1,117 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I don't know, how can I find that?
+	<alt>I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+Assistant: If you look at the test example, 'dabra' appears right after the last occurrence of `ca`. Which variable in your code computes that position?
+	<alt>Can you tell me what the variable `start` is supposed to do and how it is computed?
+	<alt>Which variable in your code computes the index right after the last occurrence of the string `t`?
+User: So it must be the sum between where `ca` starts, which is in `pos` and the length of `ca`, that is what `start` does.
+Assistant: Correct. Now, where does 'dabra' end?
+	<alt>Correct. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: It ends at the end of the input string `s`.
+Assistant: Correct. So it starts at the last value of `start` and ends at `len(s)`. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: Ok, I did that and it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: Great, glad that I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9596004c0330f7a64b8df111fd59d911a85f629a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b4d1dfe8e505d610d732f5f7749b018450ac978
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: Ah, I see the problem, I forgot to change `start` inside the while loop. Let me do that ... it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: Great, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e826944d56d97aabaa32ccf77a174b32cd58c356
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_2.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: First, `start` is initialized with 0. Then `pos` becomes 4, then ... ah, I forgot to update `start` inside the loop. Let me try to fix that ... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c5955c5511673f2c69c5e249c9a5c5f8d3f3d8c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_3.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Does `start` ever change inside the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+User: Ah, it doesn't! It stays equal to 0, which means that `pos` does not change either. Let me fix that... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76250045f41995ac9a4765999215119b64828ec3
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_socratic_dialogue.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..374ed2d7231845cd77b9b540ce4c48d6a31ba5e9
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3bd99c0f8e2ed5f3d3602d10ef28c5b04aafc241
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_thread_1.txt
@@ -0,0 +1,76 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0,1]`, It seems to work, but `[1]`, it throws an error. 
+	<alt>Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: What does that tell you about the `.pop()` method?
+	<alt>What conclusion can you draw from examining the output of the `.pop()` method?
+User: I think it is removing by index and not value, maybe I should use a different deletion method. I'll try `.remove()`. It works!
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Glad to help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5798a2092a147a9cc0146ccecbe51b60f43a879b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_conversational_thread_1.txt
@@ -0,0 +1,89 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+	<alt>Hello. I need help with my code.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist. I wonder if this relates to adding a new password.
+Assistant: Good hypothesis. Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Certainly. So when `menu_choice` is `"a"` we go to line 8, we check if  `password` is already stored in `passwords_dict`. If so, the function returns "Password already exists!" otherwise it returns "Password added!".
+Assistant: Good. Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>According to the problem description, what do you need to do with `password` if `menu_choice` is `"a"`?
+User: Oh. It is supposed to add `password` to `passwords_dict` and then return "Password added!". Let me edit my code.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Have you tried your code on all the example cases?
+User: Yes. It works correctly! Thank you for helping me today!
+Assistant: You're welcome. Let me know if I can be of any further assistance in the future.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0dbda996e22db730584f590a074dd393d85e15db
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_socratic_dialogue.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == "newpass"`. However, `passwords_dict` is initialized to `passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == "newpass"` after calling `validate_or_add_password("a", "newpass", passwords_dict)` in an attempt to add "newpass" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `"newpass"` to `passwords_dict`. I don't think I do that. I thought I just need to print "Password added!". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7ec3a3bd78ab55dabef8e2ad4415656e48b194a5
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?.
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c58814d64883b072a0e12ad53944879fa7c7017
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4b030dfeb7859cf8370115d5263b42543f7724e8
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_conversational_thread_1.txt
@@ -0,0 +1,84 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one
+Assistant: Does this happen with all inputs?
+	<alt>Hm, ok. Can you walk me through your code?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: It's happened with all the inputs so far, but I'm not sure if it would happen with all of them
+Assistant: Can you try perturbing the inputs? Maybe add characters before or after.
+    <alt>What happens when you run `count_words("hello world ")`?
+    <alt>How does your function handle trailing whitespace?
+    <alt>Can you describe to me how you are counting words?
+    <alt>Does your loop count the last word in the sentence?
+User: It's still the same if I had numbers or non-letter characters after and before
+Assistant: Have you tried adding whitespace?
+    <alt>What happens when you run `count_words("hello world ")`?
+User: Huh, weird. When I pass the input "hello world ", the answer is correct, but it is wrong without the whitespace at the end.
+Assistant: How does your function handle trailing whitespace?
+User: I see now, I'm not counting the last word unless a space follows it. I'll amend my code to handle this. It looks like it works!
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf9ecb249246e778624f474dc19d6695f60ecad4
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d93f911372ea6e09d6fafa18fd04ceacd7001033
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,132 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Can you explain the differences between `finalScore` and `roundedScore`?
+User: `finalScore` is the unrounded grade and `roundedScore` is the rounded version.
+	<alt>Oh! I see now, I put the wrong score into the comparisons. It works now, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And which of those values are you returning with the letter grade?
+User: Oh! I'm returning a letter calculated from `finalScore` and the grade from `roundedScore`. I fixed the issue, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..873a50745b3a367f894358f9638a38df5a95d9d4
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_2.txt
@@ -0,0 +1,111 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to finalScore is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: It would be false, it wouldn't produce the right `letterGrade`.
+	<alt>It would be true, 70=70.
+Assistant: Correct. But you said you were still returning 70, why do you think that is?
+User: Oh! I'm returning `roundedScore`! If I compare by that too, then I get consistent results. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7c9c01f900c49f29fa12f4755be3b3ded3005653
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_conversational_thread_3.txt
@@ -0,0 +1,162 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+User: I am returning ('D', 70) for test 4 and I don't know why.
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+User:  It would be true, 70=70.
+Assistant: Is that true? Can you verify that?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>Is that true? Can you print the value of `finalScore >= 70`?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+User: Yes, I'll use a print statement to do that.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.    
+10.    print(finalScore >= 70)
+11.
+12.    if finalScore >= 90:
+13.        letterGrade = "A"
+14.    elif finalScore >= 80:
+15.        letterGrade = "B"
+16.    elif finalScore >= 70:
+17.        letterGrade = "C"
+18.    elif finalScore >= 60:
+19.        letterGrade = "D"
+20.    else:
+21.        letterGrade = "F"
+22.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what does it print for test 4?
+User: It prints `False` but I don't know why.
+	<alt>Oh, it prints `False` because it's 69.6, not 70. I need to use `roundedScore` instead. That makes it work, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what is the value of `finalScore` when you use it on line 10?
+	<alt>How does the value of `finalScore` affect the truth value of the boolean expression on line 10?
+User: Oh! I was using the wrong variable. After switching `finalScore` to `roundedScore` in the comparisons it worked. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aa261fea9a34e4a4be8f0c10fabbb4ba40042ec5
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_10_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,138 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fa366d6e26d8844a51959421ae1aaf1a01c12cb1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+    <alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Let's look at the instructions. Is there any information that is missing or not being displayed in your output?
+	<alt>What seems to be missing from your output if you run your code and compare it with the expected output?
+User: I want to return two variables `letterGrade` and `roundedScore` but my function only returns `letterGrade`.
+	<alt>I want to return two variables, but my code only returns one even though I am trying to return both.
+	<alt>I am attempting to return two variables in my code, but only one is being returned despite my efforts to return both.
+Assistant: At which line are you attempting to return two variables?
+User: Although I am returning `letterGrade` on line 14 and `roundedScore` on line 15, it seems like line 15 never runs.
+	<alt>I am returning the variables on lines 14 and 15, but it seems like the code stops after line 14.
+Assistant: Based on the observed behavior, do you believe a function can contain two back-to-back return statements?
+	<alt>After looking at the comparison with the instructions, do you think this might be the correct way to return multiple variables?
+User: No, I think I can only use one return statement. But how do I return multiple variables?
+	<alt>How do I return multiple variables with only one return statement?
+Assistant: Let's refer back to the instructions, and this time we will pay attention to the data type of the expected output. What do you observe?
+User: The expected output consists of a tuple. I suppose I can return the variables together as a tuple with one return statement. I'll try that now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return (letterGrade, roundedScore)
+
+</code>
+Assistant: Does your output match the expected output now?
+User: It displays the expected output.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..569ccc4f9dd5118de9013cc70cb1230b76f7f671
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_11_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_13_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/1_13_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c48ee80ac5aa5926ddbe62ac5a63450e56b67615
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_13_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,183 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_8_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/1_8_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e738b89b749edcaa48a75e228c2740479b244c6d
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_8_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,179 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = "A"
+7.    elif roundedScore >= 80:
+8.        letterGrade = "B"
+9.    elif roundedScore >= 70:
+10.        letterGrade = "C"
+11.    elif roundedScore >= 60:
+12.        letterGrade = "D"
+13.    else:
+14.        letterGrade = "F"
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..78f874f9904471f3ce4a0d1fbbc8e946d96aa081
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,112 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+	<alt>I think that the test cases may be glitched.
+	<alt>Maybe I misunderstood the instructions.
+Assistant: What do you think could be missing in your calculation?
+	<alt>Did you expect to get a rounded number from your equation here?
+	<alt>Do you know any method that can give you a rounded number?
+	<alt>Python has a lot of documentation that can help you solve specific problems. Do you think it would help to look for your solution there?
+User: I see that I don't actually have any rounding mechanism. I could use the round() method.
+	<alt>I don't have any rounding mechanism, but I don't know how to round.
+	<alt>I don't think anything is missing. I get 69.6. But I just need to get rid of the .6 somehow.
+	<alt>Maybe I'm writing my calculations wrong, though I don't know where.
+Assistant: That's a good point! We can use methods in Python to help us solve problems. How could you apply the round() method to your code?
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore.round()
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+User: I am getting an error...What's going on?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: If you are getting a new error, do you think that means the way you applied the round() method could be causing you problems? Are you sure that you applied it correctly?
+	<alt>If you received a new error from your addition, what do you think that means?
+	<alt>When you look in the Python documentation for this method, do you see any difference between your application and their application?
+	<alt>Which part of your code do you think is causing the error?
+	<alt>Try using a debugger to step through your code to find where your problem is.
+User: OK, I guess I didn't apply it correctly. I just looked it up and it says I need to put the variable inside the parenthesis. So, I changed it to this, but I don't think it's working still. It's giving me the original error.
+	<alt>Yeah, I'm sure I applied it correctly. That's how you call methods, isn't it?
+	<alt>I'm assuming I didn't do it correctly. Can you show me how to call this method?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: To help us understand what's going on, let's take a look at how you calculated `finalScore`. You created a mathematical equation and you stored it into the variable `finalScore`. Why did you store it into a variable?
+	<alt>Try to compare what you wrote to a practical application in the Python documentation. Do you notice anything different between your answer and theirs?
+	<alt>We need to find out what part of your code has the problem. What can you do to figure out whether your rounding method is giving you the rounded answer or not?
+User: I stored it in a variable because you can't use that answer otherwise. If you just did the calculation, you wouldn't be able to check it in the if-statements.
+	<alt>I stored it in a variable because that's how the syntax of the language works. You can't just write calculations right in the IDE.
+Assistant: That makes sense. You need to store the answer somewhere. Notice how you wrote the round() method. Based on our discussion, do you think something is missing?
+User: Oh! I see. I am not storing the result of the rounding calculation anywhere. I need to save it back to the original variable.
+	<alt>I'm not sure I understand how the problems are related.
+	<alt>Am I not storing the rounded number anywhere? I thought that using the Python method would be enough.
+	<alt>Instead of using the `finalScore` variable, I should just put the equation directly into the round() method.
+User: It works now! Thanks for the help.
+Assistant: Great! Let me know if you have any other questions.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..658a9d80a86f26feb27a32c9203579ba1b1420d7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/1_9_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1923efad8daf0f895478a02edf114ea43a62e9dd
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Is that everything it is supposed to do according to the prompt?
+	<alt>Does it do anything else?
+	<alt>Okay, on what line of code does it take in those lists of words?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: I think so.
+Assistant: Let's take a more detailed look at the output. What does that part say?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: It says there is a TypeError and that NoneType objects aren't iterable.
+Assistant: Okay, so let's break that down. Let's focus on the NoneType part, what is a NoneType?
+	<alt>Okay, so let's break that down. What does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: A that's an object that doesn't have a value.
+	<alt>I'm not sure.
+Assistant: So why would there be an object that doesn't have a value there?
+	<alt>Let's look at the second part, what does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: I don't know.
+	<alt>My function doesn't return anything!
+Assistant: Where could a NoneType be coming from?
+	<alt>Why could your function be returning a NoneType object?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: My function.
+Assistant: Why could it be returning something with no value?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: I forgot the return statement!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9c527fa1fca8cbe668dab52c626ee3b42557cecb
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/20_51_spell_checker_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a94dc6f8d67e4f4de528d1519ee714155568bfc9
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Can you explain what the "<=" operator does?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+User: That is the "less than or equal to" operator. It returns true if `c` is less than or equal to 0 and false otherwise.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+	<alt>The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..35b266e30f10e8da14bba1b085d89c33763c4293
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the "<=" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+	<alt>Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+Assistant: Which operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the "<=" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf64c30ebf7ca0cd68adbbd8be2e764757281ad1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_conversational_thread_1.txt
@@ -0,0 +1,75 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code
+Assistant: Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: I think there should be a discount of 10% but when I run `cookiePurchase(70)`, I get a discount of 0. I'm so lost.
+Assistant: Let's review the problem description again. What are the conditions for a discount and where in your code do you check for these conditions?
+	<alt>From the task description, you need to check whether the number of cookies is divisible by 10, and it looks like you fail on an input that is divisible by 10. Can you explain how you're checking whether 70 is divisible by 10?
+User: The task description tells me to check whether the number of `cookies` is greater than 10 and whether `cookies` is a multiple of 10, and I fail on 70 cookies, so maybe I'm not checking this properly.
+Assistant: Let's walk through your if statement on line 4 then. 70 > 10 is True, but what is the value of `cookies / 10` when `cookies` is 70?
+User: So, for 70, I first check if it is greater than 10, which it is, and then I check whether it is a multiple of 10. I do this by dividing by 10 and seeing if the output is 0. Wait, that's not right. 70 / 10 is 7, not 0.
+	<alt>So, for 70, I first check that it is greater than 10, and then I divide by 10 to check divisibility
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Where can you learn more about arithmetic operators in Python?
+	<alt>Let's take a look at the Python documentation to see if there is a different operator that does what you want.	
+User: Ah! The Python documentation would be good to look at right now. Looking at the documentation, I think I should be using the modulus operator. I'll try that.
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Looks like it works!
+User: Yes it does for all the test cases! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0456f3ba3d42d12e763e91f4f271458123228ab0
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/22_53_cookie_purchase_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f80d7e1c34a0763ae5139738f00046c6a73882c1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_1.txt
@@ -0,0 +1,78 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+	<alt>The first value assigned to `i` will be 1.
+	<alt>Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: That’s right. So, what happens when `i` is 0?
+	<alt>Correct. Given that `i` is 0, what happens when line 6 is evaluated?
+User: We go into the for loop and compute `fact`.
+	<alt>The value of `fact` will be 0 because `i` is 0. I think I got it `fact` will always be because of this. I need to change the `range` call to start at 1 instead of 0 and end at `n+1` instead of `n`.
+Assistant: That's right. Given that `i` is 0, what will the value of `fact` be after line 6 is executed?
+User: Aha! I see what is happening. `fact` is always 0 because `i` is 0 in the first iteration of the for loop. I need to change the range to start at 1 instead of 0 and end at `n+1` instead of `n`.  Thanks! I think I got it now.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: I am glad I could help. If you have any other questions, please let me know.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1bd1ec69c73a91735f9a53d6e5cf316447e291fe
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_2.txt
@@ -0,0 +1,82 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: Let's examine what happens in this case. Open the Python shell and type `[i for i in range(1)]`. What do you see?
+	<alt>Let's investigate this further. Open the Python shell and type `for i in range(1): print(i)`. Press `Enter` twice to execute. What do you see?
+User: I see that `i` is not declared before the for loop is created. Yet the list comprehension `[i for i in range(1)]` returns `[0]`. So the issue is not with initializing `i` before the for loop.
+	<alt>I see a `[0]` in the list comprehension `[i for i in range(1)]`. So the issue is not with initializing `i` before the for loop but rather with the first value of `i` in the for loop. It is not 1 but 0 so `fact` will always be 0.
+Assistant: Good. Let's take a closer look. What is the first value of `i` in the for loop?
+	<alt>Correct. What do you notice about the first value of `i` in the for loop?
+	<alt>Notice that the value of `i` in the first iteration of the for loop is 0. How do you think this affects the value of `fact`?
+User: I see. The value of `i` in the first iteration of the for loop is 0. So `fact` will always be 0 because the first value of `fact = 1 * 0` is 0. Then, `fact` will be `0 * 1` in the second iteration of the for loop, and so on.
+Assistant: Good! How can we fix this issue?
+	<alt>Good. Now, what does a correct factorial sequence look like for `n=4`?
+User: I think we can fix this by changing the range of `i` to `range(1, n + 1)`.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: Good! Let's test it. What is the factorial of 5?
+User: The factorial of 5 is 120. It works!
+Assistant: I am glad I could help. If you have any other questions, feel free to ask me.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..586ad2f28814182968cc2c41d80e0399031ed181
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_conversational_thread_3.txt
@@ -0,0 +1,166 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of n it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because `range` by default starts at 0.
+	<alt>Oh! `i` is not declared before the for loop is created maybe that causes this issue.
+Assistant: Are you sure about that? Can you verify that the first value assigned to `i` is 1?
+User: OK, let me print its value at each iteration. I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>OK, let me check in the Python documentation what range does. I see, the first value is 0, not 1!
+Assistant: How can you fix the code so that in the first iteration fact is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+User: I don’t know, can you help?
+	<alt>I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+	<alt>I can change to `range(1,  n + 1)` so that it starts iterating at 1.
+	<alt>I can change to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change to `range(n) + 1`, so that the first value is 0 + 1.
+Assistant: How can you ensure that in the first iteration `fact` is multiplied with 1?
+User: I can add a line that sets `i` to 1 before the for loop.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+User: Hm... It still returns 0.
+	<alt>It still returns 0. I think I need to change the for loop.
+Assistant: Do you know why it still returns 0?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>Let’s look at the terminal output. What value is `i` on line 7 when being printed?
+User: I think the problem is that `i` is still 0 in the first iteration of the for loop. It still prints 0. I think I can add an `if` statement to the for loop that checks if `i` is 0 and if so, sets it to 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                if i == 0:
+8.                    i = 1
+9.                  print(i)
+10.                fact = fact * i
+11.        return fact
+
+</code>
+	<alt>It still prints 0. I think I need to make a change in the for loop.
+	<alt>I don't know. Can you help?
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Good. Can you try it for `n = 2` and `n = 3`?
+	<alt>Ok! Let's run the code for `n = 3` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: Hm... it's incorrect for both `n = 2` and `n = 3`. I think I need to multiply `fact` starting from 1, then 2, then 3 instead of what I'm doing now 1, then 1, then 2.
+Assistant: Good. How can you change the for loop so that the iterator variable `i` is not equal to 0 in the first iteration of the for loop?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>How can you edit the code so that `fact` is multiplied with 1, then 2, then 3?
+	<alt>What do you think you can do to make sure that `fact` is multiplied with 1, then 2, then 3?
+	<alt>How can you change the for loop so that the iterator variable `i` iterates starting from 1?
+User: I think I am going to change `range` to `range(1, n + 1)` so that it starts iterating at 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+	<alt>I think I am going to change `range` to `range(1, n)` so that it starts iterating at 1.
+	<alt>I think I am going to change `range` to `range(n) + 1` so that the first value is 0 + 1.
+Assistant: Sounds good, let's try it for `n = 2` and `n = 3` again.
+	<alt>Did you try it again for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Awesome. Don't forget to remove the print statement before you submit your code.
+	<alt>Good! I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you! I will do that.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                fact = fact * i
+8.        return fact
+</code>
+Assistant: I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7df61e9d91ff71c70cffa036b44cee77c5e49f14
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/24_29_factorial_socratic_dialogue.txt
@@ -0,0 +1,135 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3923bde64ffe0970724120b16b7b24e77f734792
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2  , Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as 1-> 2-> 3 -> 4.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind? 
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Now checking assertions, what happens when we run the checks?
+	<alt>Looking at our test case, can you trace what happens as your code runs?
+User: Lines 24, 25, 26 run successfully, which means that the data attribute of the head node of the linked list is equal to 1, the next node holds data 2, and the node after that holds data 5. However, we run into an error at line 27.
+	<alt>It looks like I run into an error at line 27, so it seems that the node after Node5 is unavailable.
+	<alt>It looks like Node3 is no longer in the linked list.
+	<alt>Somehow it looks like the linked list is broken, and checking for a node with data 3 throws an AttributeError.
+Assistant: That's right. Can you tell me what your linked list is currently looking like (after running `insert_after(head, 2, 5)`)?
+	<alt>Let's take a look at the current linked list we have. What might be missing from this list?
+User: It seems that `head.next.next.next` is None. It means that the new linked list is actually `1 -> 2 -> 5`, after executing `assert_after(head, 2, 5)`.
+	<alt>It looks like I have a broken linked list. The current list stops at `node` with data 5.
+Assistant: Yes. You are right. These nodes after node 2 in the original linked list (`1 ->2 -> 3 -> 4`) are gone, after executing your function, `assert_after(head, 2, 5)`. Namely, we are supposed to get a new linked list, 1->2->5->3->4, but your function implementation gives a list of 1->2->5. Which link is missing in the execution of your function?
+	<alt>That's right, we need to account for making sure that the current connections keep working when we add a new element somewhere before the end. Can you tell what needs to be updated in the code to make sure we update all existing links?
+User: I see. The link from node5 to node3 is missing. The next attribute of node5 should refers to node3.
+	<alt>That makes sense, I think I need to make sure that when I place a new node into the list, I assign the node link to the previous node's next link, so I can maintain the connections.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.           new_node = Node(data=new_data)
+11.           new_node.next = curr_head.next
+12.           curr_head.next = new_node
+13.           return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c2f04014f2be36ec150b6d47a51b004d5034d36a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5816fc7a4f695df04168eac18525185aa67a600d
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_conversational_thread_1.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` an then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: That's right. According to the problem statement, we can buy more cookies, but not reduce the cookies we have. In which line of your code might this requirement be violated?
+	<alt>Let's also keep in mind that we can buy more cookies, but not waste any that we already have in the process of ensuring everyone gets the same amount, as mentioned in the problem statement. Where can we account for this in your code?
+User: That makes sense. I think I need to modify line 5, and account for the requirement that I can buy more cookies but not vice versa. I will update line 5.
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    purchasedCookies = people - cookies % people
+6.    newCookies = cookies + purchasedCookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</code>
+Assistant: Sounds good, see you later!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85a0354c3b499bffc872b15a12f25deea1ff3fd8
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/2_18_splitting_cookies_socratic_dialogue.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9f03ecc9e575e5f0cf636ebbf18ecc558645fe1a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+	<alt>When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3.
+Assistant: That's right. In your `else` condition, we run into this error. Let's also review your `if` condition. Do you observe any similar issues?
+	<alt>Let's also try other test cases. Based on the observed outputs, do you think there is another similar issue in your code? If yes, which lines are affected?
+	<alt>Let's complete our analysis of the issues by checking what happens if we run the other test cases as well. Do you observe any issues?
+User: Yes, the while loop in the `if` condition also has a similar issue. I will fix this issue for both the if and else conditions.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.   return l
+</code>
+Assistant: Do all the test cases work correctly now?
+User: Yes they do, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3cf29f118180022365583ed08c26ea38933e89f7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/3_20_counting_down_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1428e2d960a33311a690e94fa5d1de1f13145762
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Ok, they are >=, <=, >, <, =!, and ==.
+Assistant: Ok, what does =! do?
+  <alt>How do you check if two numbers are unequal?
+User: It checks if two numbers are not equal.
+Assistant: Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I think I used the wrong operator. I should have used != instead of =!.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..354c5133f17c48e48c66cbae273a9d4639b5b641
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_22_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,62 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9bd416f7fa51284317fcae08059df9cdf4acc118
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>Can you explain your function to me line by line?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: For example, the input list `[0,2,3]` will return `[2,3]`, but many other inputs result in unchanged outputs.
+	<alt>I seem to only remove 0s from my lists
+	<alt>Running `returnOdd([2, 4, 6, 8, 10])` gives the same list back, for example
+Assistant: Can you explain what your if-statement on line 4 is doing? Let's assume `i` is 4.
+	<alt>How do you check if a number is even in your code?
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+User: In the case before, we can look at 0 first. `0 / 2` is 0, so we get False on line 4 and do not append. For `4 / 2` is equal to `2`, it looks like I'm not getting what I want. Line 4 gives True, so we still append. That's not what I want though.
+Assistant: It looks like just dividing isn't doing what you want. Is there another operator that can test whether a number is divisible by another? Feel free to reference the documentation.
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Looking at the documentation, it seems like I can use a `%` to test whether the number is even. I'll try that.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Looks like it works!
+User: Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0939ecc606a1fd49f467cd1588ac4f0b6f4af25f
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_23_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..30070b15a2e20b9e636a2e6d76fcfd5e69ccd69a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,55 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+User: The scope refers to the visibility of a certain variable depending on where it has been used. For example, a variable defined inside a function is only visible to the function, and cannot be used outside the function.
+	<alt>The scope means certain variables can only be used within the visibility of the code block they are a part of.
+Assistant: That's right. Let's look back at your code now. Is the return statement in the correct scope?
+	<alt>Right, so how would you indent line 6 so that it is part of the method?
+User: I would need to indent it so that it is inside the function. I will make changes now.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Sounds great! Happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..463a697ddd004f912dd87d61d0edc2dba5c1b598
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_25_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..187bd3ed7c77b8654f0efff763d9765e59e4ac74
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases if any are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: I don't know, how could I find out?
+	<alt>No, I'm iterating through the whole list of numbers.
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+User: When running the function with `nums` as `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]` only `1` is printed. I think this means the for loop is iterating only once and therefore returning `[1]`.
+Assistant: Do you notice anything in your function that might cause the for loop or the function to end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know. What do you think can make a loop end early?
+User: I don't see any break statements. Perhaps it might be the return statement on line 6.
+Assistant: Good. When is that return statement getting executed? Is it before or after the for loop completes iterating?
+User: I get it! It's returning after one iteration! Let me unindent the return statement so that it returns after the for loop is completed.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..573522c58359c29be4591852b5a1633261555e7d
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_26_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,93 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d274557923f75bb99fedfee06d53bf7bbe6eadd3
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: Yes, can you use the caret in your output to figure out what is wrong with your syntax?
+User: It looks like there is something wrong towards the end of line 3, but I am not sure what that is.
+Assistant: Can use the documentation to figure out the syntax of a for loop?
+	<alt>It looks like you are missing a punctuation mark, do you know what that is?
+User: Am I missing a colon at the end?
+Assistant: Yes, you need to include that colon at the end of line 3.
+User: This code now works, thank you for your help!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: That looks great, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c605112e950fb1b7d189aca6b9600a28a219d49
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/4_28_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..19b112a9b28e9331603d712ec7d390177eee2329
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide 6 by 2.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type in `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ac351106c4d0060c6182dd4b7fe0b879868900d5
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_conversational_thread_2.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant:   Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8999a05df5cfc4c5811ce2dcdb8588748e1c7f21
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/56_15_compute_average_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/58_58_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/58_58_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92804610fa5671a78bcf745e893efbb9ba218875
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/58_58_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,107 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4539114e548434b02d3f85b83d374c5806368b8b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_1.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is  ... false. Ah, I see where the problem is, the loop stops too early, it should iterate also when `apples` is equal to `children`. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..204476a2e5c01e00d40070025d85a5a7e7215267
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_2.txt
@@ -0,0 +1,57 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is true. Then on line 4, `apples` is assigned the value 100 - 100 = 0 and on line 5 `i` is incremented to 1. Then the while condition `apples > 0` is not true anymore, so the loop ends and the value 1 of `i` should be returned from line 6.
+Assistant: You said that, when we run the code on the third test case, `apples > children` is true. Are you sure about that?
+	<alt>Well, your explanation must contain a mistake, because your function returns 0, not 1 as you said. This means that `i` is never incremented. Can you see where the problem is?
+User: Ah, `apples` is actually equal to, not strictly greater than, `children`. I see now what the problem is.  Let me fix that ... it works now! Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d0d29f8fac42541225d87d5e8c5ee6d3b5df09a6
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_conversational_thread_3.txt
@@ -0,0 +1,56 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It ensures that there are still enough apples so that we can give each child ` more apples.
+Assistant: OK, but is it necessary for `apples` to be strictly greater than `children`? What if they were equal, would it still be sufficient to give 1 apple to each child?
+	<alt>Sure, but is that condition really necessary? Think of the third test case, where `apples` is `100` and `children` is `100`, would these numbers satisfy that condition?
+User: Ah, I understand now, they can also be equal. Let me try to fix that ... it works now. Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You are welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..93e8936d3618ce036b5ef9428f5357693c2c75ca
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/58_59_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d08b8a7d1f982ac1c75d3ebd3c67bdb1c7162c0c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_1.txt
@@ -0,0 +1,52 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still fails the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to as `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..678c3ea9748d45f4d25e48f24552644b255147b7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: Correct! When you run the code now, you should see that there are no longer any assertion errors.
+User: Yes, that is the case. Thank you for your help!
+Assistant: You're welcome, thank you for asking questions to further your understanding. It is important to understand the fundamentals when you are first learning. Is there anything else that I can help you with today?
+User: No, that is all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8061e160bfbc8b7b6788c4e3f5be29b2bd8416ae
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_conversational_thread_3.txt
@@ -0,0 +1,54 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Oh! I made the change and now it prints out `None`.  I realized I just forgot to put a `return` statement and I've now fixed it. Thanks for the help!
+<code>
+1. def Product(a, b):
+2.	a * b
+3. print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3. print(Product(1,2))
+</code>
+Assistant: You're welcome! Any other ways I can help you today?
+	<alt>It is likely a good decision to remove the `print` statement on line 3 before using this, as it would lead to confusion with a user running this program without knowing your reasoning behind it being there.
+User: That makes sense. Thanks for the help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/59_60_product_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3447706bd18f9798905a6143c6bb087c22ab02ee
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/59_60_product_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5a913de0a055bae71188b38bf8bbb590018e1605
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+	<alt>Hi! I've been working on this function and it doesn't seem to be correct.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: It works for all the example cases except for `get_words("Hello World")`.
+Assistant: Let's look at the example cases closely. What is so special about `get_words("Hello World")` compared to the other examples?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+User: For that sentence, there are no repeated words.
+Assistant: Good. How does your code behave when there are repeated words in the input string `s` and how is it different from the expected behavior?
+	<alt>What would your code need to do to ensure that when there are duplicate words in the input string, the function returns a list of unique words?
+User: It seems like I am not deduplicating. How would I go about doing that?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: I could try using a set instead since that makes sure elements are unique. I'll change my code
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: It looks like it works!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d645aaecd6b075ea42d6716e59a313703e2b698b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_2.txt
@@ -0,0 +1,66 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: Can you insert a print statement to print the value of `words` before line 3?
+	<alt>And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+User: Yes, for the input `"Hello World hello"` it returns `["hello", "world", "hello" ]`. Is that not correct?
+	<alt>Oh, the problem wants me to return unique values only. I've fixed it, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Let's look at the examples in the problem description. What happens when you run `get_words("Hello World hello")`? What should the output be?
+User: Oh! I've fixed my code, I missed that in the problem. Thank you for the clarification!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Any time! If you have any more questions, feel free to ask.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1f9289d5140eae02bebf35a3a70a18962d913b07
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_conversational_thread_3.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+	<alt>Can you print the value of words before line 3?
+User: It sorts the values in `words` alphabetically.
+Assistant: Can you explain what the problem wants you to return?
+	<alt>Where do you remove duplicate values from words?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+User: Oh! The problem wants me to return a sorted list without duplicates. Is there a given function to do that?
+	<alt>Oh! The problem wants me to return a list with no duplicates! I've fixed it now, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>Is there a data structure in Python that stores unique elements only?
+	<alt>Where can you learn about deduplicating a list in Python?
+User: Oh, a set! I figured it out, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: No problem! If you have any more issues, please feel free to talk about them now or later.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4a84f7ffbafbac182376e7e75ffb262bd1abd1b8
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/5_30_sorted_words_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like "hello world hello world", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..41c5b9add9306768bd4e16e8f46db1bb3efc476a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_1.txt
@@ -0,0 +1,56 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: Oh! I would have to pick from one of the two, but it doesn't matter which since I'm returning the value, which input is the highest. That makes a lot more sense, I've made some alterations to my code and it works now. Thank you!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b9944434a0fb6adc229a5be99ec52fc4af89519
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: Oh, I have to do greater than or equal to rather than just greater than. Thank you for the advice!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..48027de0229ad33d8984d9bf7f4bbe64fb4a7b72
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_conversational_thread_3.txt
@@ -0,0 +1,67 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: That would return `None`, right? What should I do in this case, none of my conditions can catch that, do I need to add another case?
+Assistant: I don't think that is necessary, I think there is a way to modify your existing cases to make this work. How would you check if a number is either larger or the same as another number?
+User: Oh! I could use the `>=` operator. That makes it work as expected now, thank you so much!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c64d548f36fd47251621714106ff3e6d954858f1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/60_61_largest_number_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e575f4d448c7bfd170e481ef1b8ca5a68dace75
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_1.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: I'm sorry I think too much is going on in that question and I'm confused. Can you simplify it?
+Assistant: Let's break the problem down. Can you create a temporary variable to store `a+b`?
+	<alt>Gladly. First, let's change your code into an `if`/`else` condition. When `(a+b)%2==1`, what do you output?
+User: Okay, I've changed my code.
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 1
+</code>
+Assistant: Okay, now when you do modulo 2 of `inputSum`, what number would be outputted if `inputSum` is even?
+	<alt>Given the revised definition of the modulo operation, can you explain what is outputted from an even sum mod 2?
+User: Since even numbers are divisible by 2, the remainder would be 0, right?
+Assistant: That is correct! And what is the output of `0 == 1`?
+User: Oh, that would be False! I needed to change the 1 into a 0 and now it works as expected. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 0
+</code>
+Assistant: I'm glad to be of assistance! Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..95e016f9a9cfea3e5c68a8e928a73eb548210b41
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_2.txt
@@ -0,0 +1,61 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	  return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: That means that `inputSum` is divisible by 2, right?
+Assistant: That is incorrect. Modulo returns the value of the remainder when the first operand is divided by the second. Given this, when `inputSum % 2 == 1`, is `inputSum` even or odd?
+User: Oh! That means the number is odd, right?
+Assistant: Correct! Since the number is odd, what would the expected response from the `SumIsEven()` function be?
+User: Oh, the expected output would be `False`, I had my booleans backward. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return False
+5.    else:
+6.	  return True
+</code>
+Assistant: I'm happy to help. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2070ad10ef09c7a08a0b02820fd1e24ff19b9bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_conversational_thread_3.txt
@@ -0,0 +1,57 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: Oh, I have my conditions backward! That means that the number is odd, not even. I changed the 1 to a 0 and it works now. Thank you so much for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 0):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: I'm glad to be of assistance. Did you want to ask any other questions today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c1f95a3c598d2b8906b6d9b8079176069006045f
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/61_62_is_even_socratic_dialogue.txt
@@ -0,0 +1,45 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e32377a10c32c78892cff131fb25f6cdf9a73505
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_1.txt
@@ -0,0 +1,62 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Could I use a temporary variable to do that?
+Assistant: Yes, a temporary variable is entirely fine. Where would you include it?
+	<alt>Why do you feel a temporary variable is necessary?
+User: I created a variable `newHigh` and set it equal to `high+1` and then put that into `range()`'s second input and that fixed it. Thank you!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	newHigh = high+1
+4.	for i in range(low, newHigh):
+5.		num += i
+6.	return num
+</code>
+Assistant: I'm happy that I was of assistance. Is there anything else you wanted to ask about?
+User: No, that was all. Thank you again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f08e6af0a40ef6e93a994f9a05bdb2ea9d6656d2
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would turn it into `range(0,2)`, but is that always the case? Why would it always be adding 1?
+Assistant: Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: Oh, yeah, since it is every integer between the two inputs, not including the second input, `y` would be in `range(x,y+1)` but not `range(x,y)`.
+Assistant: That is correct. Given that, how would you change your code?
+User: I added one to `high` and it fixed everything. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of service to you. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..580b549b1bf9579667dbe080da60bd88961a083c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_conversational_thread_3.txt
@@ -0,0 +1,49 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: It would be a list containing 0 and 1, right?
+Assistant: That is not correct. `range()` is not inclusive of its second argument, meaning that `range(0,1)` is actually a list containing only one element, 0.
+User: Oh, I added 1 to `high` in my `range()` function and it works now, I didn't know that it wasn't inclusive of the second argument. Thank you for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8309521875cf1009334bcdc57c55eca5361154af
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/62_63_summing_between_integers_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f9ccdb9cb52ad6bc8cc840b20c1c3eb12aef34aa
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_1.txt
@@ -0,0 +1,73 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: That's two conditions though, how would I be able to put three booleans into a single if statement?
+Assistant: I see where the confusion is coming from now. Boolean operands can be put into sequence, the same as mathematical operations.
+User: Oh, so it would be syntactically correct to put `pizzas >= 10 and pizzas <= 20 and not(weekend)`?
+Assistant: That is correct.
+User: Oh, that makes the problem a lot easier then! Thank you for clarifying that! My program is working correctly now.
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44e5512491b5a802751848f4c7a8e2e50ab7d9c0
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_2.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if `pizzas` is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, I was just missing a condition on my `elif` statement. I've fixed the issue now, thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d1f82e12e4fd9c26bfbaf7ebe8e1ed05d53200e
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would make turn a dinner into a good dinner?
+	<alt>What would happen when `pizzas` is between 0 and 9, but `weekend` is `False`?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: It would be between 10 and 20 pizzas, inclusively.
+Assistant: Correct, and how would you express that in Python?
+User: Would it be `10 <= pizzas <= 20`?
+Assistant: That notation does not work in Python, you can instead split it up into two statements using an `and` operation. How would you put your previous statement into two statements?
+	<alt>That notation is not correct Python syntax. How would you simplify this problem? It may help to physically speak what the mathematical symbols mean.
+User: Oh, I put it as `10 <=pizzas and pizzas <= 20` and that fixed my code. Thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(10 <= pizzas and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to hear that I was able to help. Is there anything else I could help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e45d2c2adf260dd57c3c6ca15e0fa2a61e06050c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/63_64_good_dinner_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f6fbac0c54c97a10de1a04c598441c02d9bd30ac
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+	<alt>At what index do Python lists begin?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(0, len(integers))`, right?
+Assistant: That is correct, Python lists index from 0, not 1.
+User: That makes sense! The code is working as intended now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that helped you understand. How else can I help you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..51829e6e1ed9187fcee90dd8d33826a769d4c1df
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct!
+	<alt>That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Ah, that is a lot easier to use! My code is working now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..50688dcfaaae29e8966a1e8ba41a94bab964e15c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Oh, I think my previous loop only iterated `len(integers)-1` times, while this loop iterates `len(integers)` times. Was I supposed to use `range(0, len(integers))` in the initial solution?
+Assistant: That is entirely correct. Python lists start their indices at 0, not 1.
+User: Thank you for your help! I plugged the new solution into my code and it works now.
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that I could clear up the concepts for you. Is there anything else you would want to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b2acfe19bbad8312880bb0ebe0a33d311d7c3f60
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/64_65_count_ones_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as "distance from the first element" rather than "element number".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..daef07ba3ef314a6d9d4bf62f0bf727664394bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of `smallest` and `largest` throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest` or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for `smallest` and a really small number for `largest`?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: That is correct. Why would that be the case?
+User: If the variables start as members of the array, and are only compared to other members of the array, then they would both always be both members of the array and, by the conditions of the `for` loop, the correct members of the array.
+Assistant: That is correct!
+User: I made the change and the code works now, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..665d9214a4b4d2af11b377247eb7e2210f33c732
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of `array`?
+Assistant: That is correct. Why would that be the case?
+User: That's where I am confused, why does starting as an element of `array` change anything about the solution?
+Assistant: If you pick an element of the list, you can be certain that you never have the same issue as when you just picked 0. As there either exists an element in `array` that is larger or smaller than your initial value, or your initial value is the largest or smallest element itself.
+User: Oh, that makes a lot more sense now! Thank you for the help, my code is working now!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm happy to help. How else can I help you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..196c4e4bd219d77334db421c0f05c2c244bb52fd
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5]) => 4
+Range([2,2,1,3]) =>2
+Range([-10,-3,-1]) => -9
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.	smallest = 0
+3.	largest = 0
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = array[i]
+7.		if(element < smallest):
+8.			smallest = array[i]
+9.	return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == -9
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Oh, [-1001, -1010] would work for that. I see the point now, if I set `largest` and `smallest` to `array[0]` initially, they would always be a member of the array, which ensures the comparisons will always be between elements within the array rather than arbitrary values. Now my code is working, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could clear that concept up for you. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6863cc01239d47043165ecf302209054e1b619ce
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/65_66_list_range_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..27c6a4ad428c38f6e247ddec3fe1080dffd7e3c8
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant:  This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, it says -1 in the problem. Thank you for pointing it out!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5cf132b9132d3f054d0ec5c0310690394c737488
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. How would someone differentiate between those scenarios?
+Assistant: There is a standard response of -1 for this kind of function, but it is further defined in the problem given.
+User: Oh, I suppose I misread that part of the problem. I made the change and it works correctly now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad I could help, is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f46343b0931227f5535a67e1708ab113596b4cd0
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. I just reread the problem information and noticed it is supposed to return -1, but I'm unsure how to make sure that is the case. How can you ensure that -1 is what returns?
+Assistant: I believe you know the answer to this question based on how you described the activation of your function. Think about from initialization to `return`, what changes the value of `index`?
+	<alt>If the `if` condition in your `for` loop is never `True`, what would the value of `index` be?
+User: After initialization, it changes only when the value of the element at index `i` of the list `array` is equal to `value`.
+Assistant: And what does that tell you about the case where no element of `array` is equal versus when there is an equal element?
+User: That it will stay at the initialized value until an element of `array` is equal to `value`?
+Assistant: Correct. So how would you return -1 only when no element of `array` is equal to `value`?
+User: Oh! I would just use the initialization value, initializing `index` to -1, which would then return! I made the change, and it works as intended now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I am glad that I could help you. Is there anything else I could do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ced4c7015ed0c3bf6f6219811002ea26cf8334cb
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_67_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..55fbf2d97c46bef7552dd03f956458187da50ba2
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first part of the body of your function on it?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>What is your function supposed to do?
+User: Line 2.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: Line 2 sets the a variable called index to -1.
+Assistant: Let's look at the loop next, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: The loop starts on line 3.
+Assistant: Is there somewhere we could add a print statement to help us figure out what is going on?
+	<alt>Does everything look correct in the values for the loop?
+	<alt>What is the index of the first place in the array that we should check?
+User: We could add a print statement in the loop to check the values.
+Assistant: Where should we put it?
+	<alt>What should we print?
+User: We should add it after line 3.
+Assistant: What should we print?
+	<alt>What are the important values at that spot to help us understand what's wrong?
+	<alt>How would we print the index at that spot?
+	<alt>How would we print the value in the array at that index?
+User: We should print what's in the array at the current index.
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		print(array[i])
+5.		if(value == array[i]):
+6.			index = i
+7.	return index
+</code>
+Assistant: Compare what prints to the test cases, what do you notice?
+	<alt>Is it skipping any values?
+	<alt>What does this tell you about your loop?
+User: It's skipping the first value in all the arrays.
+Assistant: What does that tell you about your loop?
+	<alt>Can you use that to help you find the problem?
+	<alt>Do you have any new ideas about why the test cases are failing?
+User: My loop is wrong, it's not starting at the beginning.
+	<alt>I don't know.
+	<alt>I see! I need to start my loop at zero!
+Assistant: What value in your loop do you need to change to have your loop start in the right place?
+	<alt>What controls where a loop starts?
+	<alt>What are you setting i to?
+User: I need to change the first value in range. It's 1, and it should be 0!
+Assistant: Very good, try that. Does it work now?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: Yes! I removed the print statement and it works now! Thanks.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..708e87160928dd63de6194ffffad8683053baa07
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_68_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,92 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does "range" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does "range" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ad0546d69f04b8089be8b6e7319357406bb5440b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>What is the next thing your function needs to do?
+	<alt> Okay, let's move on to the next area, what does line 2 do?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: That's probably the loop.
+Assistant: Let's explore the loop a bit. Can you add some print statements to see what's happening?
+	<alt>What variable controls the loop?
+	<alt>What determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: I don't know, where would I put them?
+Assistant: What's a piece of information that would be useful to check what the loop is doing?
+	<alt>What are some important variables in the loop?
+	<alt>How could you check if the loop was starting at all?
+User: I need to know about i and index.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        print(i)
+5.        print(index)
+6.        if(array[i] == value):
+7.            index = i
+8.            break
+9.    return index
+</code>
+Assistant: What happens when you run it?
+User: Nothing prints.
+Assistant: What does that tell you about the loop?
+	<alt>What does that mean about the loop conditions?
+	<alt>Why would a statement not print?
+	<alt>Why would a loop not run?
+User: It means we don't start looping.
+Assistant: Why would a loop not run?
+	<alt>What does that mean about the loop conditions?
+User: There is something wrong with the loop conditions.
+Assistant: Let's check the loop conditions, what controls if the loop loops?
+	<alt>What number is the loop supposed to start on?
+	<alt>What number is the loop supposed to stop on?
+	<alt>What variable are we monitoring?
+	<alt>What are the parameters for range?
+User: It runs if i is between the last index minus 1 of the array and -1.
+Assistant: What is the default step for loops in Python?
+	<alt>What sets i?
+	<alt>Check the Python documentation, what direction do loops move through in Python?
+	<alt>What is the default increment for a range in Python?
+User: Oh! The default step is 1, and I want my number to decrease! It should be -1!
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1,-1,-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: Try it now, does it work?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92ba7af635e8a659031c04f4670efda2f404ded1
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, I suppose it would be simpler to just count upwards rather than downwards. I made that change and my code is working as expected now.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(0, len(array)-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c39a21aa8745f0b9d2b0e3f945325666f2ee6c05
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, but why would it work differently than a forward counting loop?
+Assistant: That is due to the function you are using for your `for` loop. You are using `range(start, end)` which only counts up by 1. Can you give me the form of `range(start, end, step)` you should be using?
+	<alt>Can you notice something awry with your use of the `range()` function as compared to how you've used it in previous assignments?
+User: So that is the difference! It would become `range(len(array)-1, -1, -1)`.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: That is entirely correct.
+	<alt>That is entirely correct! Can you explain why your version would be more efficient than a version that counts upwards, in some scenarios?
+User: Thank you for your help!
+Assistant: I'm glad that I could be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4efe32adfce0765c4fa1ca09a818307bf2af0d30
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/66_69_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,91 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1ee1401cc1a99f412d9dd47826680545134fd346
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_conversational_thread_1.txt
@@ -0,0 +1,104 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the radius of the circle in the first test case that is passing?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: The radius of the first test case that is passing is one.
+Assistant: What is the radius of the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+User: It's 2.5.
+Assistant: What is the formula for calculating the area of a circle?
+	<alt>That's interesting, do you think there is anything significant about those numbers?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+User: It's Pi times the radius squared.
+Assistant: Let's think about those two different values for the radius. Do they act differently when they are squared?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+	<alt>What happens when you square 1?
+	<alt>What is the Python operator for squaring a number?
+User: Yes, 1 squared doesn't change it's still 1, and 2.5 squared is 6.25.
+	<alt>I think made a mistake on the squaring part.
+Assistant: Okay, since it works for 1 but not for 2.5, let's look at the code that does the squaring. Where is that code?
+	<alt>Does 1 have any special properties when you multiply it that might make it act differently?
+	<alt>What is the Python operator for squaring a number?
+User: That's on line 5.
+Assistant: What is the expression that is doing the squaring?
+	<alt>What operator does the squaring?
+User: It is the radius ** radius part.
+Assistant: What does it mean to square a number?
+	<alt>How do you raise a variable to a power?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>What does ** mean?
+User: It means you multiply it times itself.
+Assistant: Okay, so what does ** mean?
+	<alt>What does * mean?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: It means to raise to a power.
+	<alt>Oh! I'm raising the radius to itself instead of squaring it!
+Assistant: What should you be doing to the radius?
+	<alt>What does * mean?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: I'm supposed to multiply it by itself, not raise it to itself!
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius * radius
+</code>
+Assistant: Does it pass the test cases now?
+User: Yes! It passes, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..34f3649e3a644d508017d090c53ee81b915387bc
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/67_70_area_circle_socratic_dialogue.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..df5545a0a6f74caa3dad6309a70036bf3bfb7816
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What controls the loop?
+	<alt>What is the variable name for the iterator made on line 3?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: Range determines the number of times the loop runs.
+Assistant: Now let's look at line 4, how many times will that loop run?
+	<alt>What iterator is made on line 4?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: It will start at i and run until the end of the list.
+	<alt>I'm supposed to start at 0 not i!
+Assistant: Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: We should start at the beginning.
+Assistant: Is it always at the beginning of the list?
+	<alt>Should we start at 0?
+	<alt>Are there any combinations we are trying to skip?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+User: I see! I should have it start at 0, not i!
+Assistant: Does it run correctly now?
+User: Yes, it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b3ad9e28b9515a3dadc9f794e4da6fab5b07af13
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/69_81_get_combinations_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/6_33_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/6_33_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67401016d82b3953ff4378f067fe4e7dd281dc3d
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/6_33_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+</bug_code>
+<bug_desc>
+The function prints the strings "N", "E", "S", "W", and "None". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print ("E")`, `print ("S")`, `print ("W")`, `print ("N")`, `print("None")` with the return statements `return "E"`, `return "S"`, `return "W"`, `return "N"`, `return "None"` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `"N"` as `compass_point`. I see `"E"` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `"E"` in the terminal when I pass in `"N"` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `"E"` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+12. store = turn_clockwise("N")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return "E"
+    elif compass_point == "E":
+        return "S"
+    elif compass_point == "S":
+        return "W"
+    elif compass_point == "W":
+        return "N"
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..840288393e10f16e10f620ac51f6ec088497ff9a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_conversational_thread_1.txt
@@ -0,0 +1,86 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! I checked the documentation. I should be using `==` instead of `=` to check equality. Let me edit my code.
+	<alt>What operator should I use?
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good. Let me know if you have any other questions!
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..febe2da36bf25c4a8e945ea8caa8e83b73c7fd0a
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/6_34_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/74_77_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/74_77_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85bc61a327c01e6e185b9b9f5ef9845c41c43abb
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/74_77_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44f2431c86f5be0e8e24678162fcd131ce15a1d4
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Could we add some print statements to check the math?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+User: Yes, we could add some to see what's happening, but I don't know where to put them.
+	<alt>I could add one in the loop to see what's happening with the fee.
+Assistant: Okay, look at the code, what are some important variables in your calculations?
+	<alt>How would you print the number of years to see how far off the answer is from the test case?
+User: Well, years is important, and so is total fee and current fee.
+Assistant: Let's print those, where should we put the print statements?
+User: We could put them after line 7 in the loop.
+	<alt>I don't know.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        print(years)
+9.        print(total_fee)
+10.        print(current_fee)
+11.        total_fee = current_fee*(1.015**years)
+12.        years += 1
+13.
+14.    return years
+</code>
+Assistant: Look at the printed output, do you see anything odd?
+	<alt>Look at the printed output, what is the value for years?
+	<alt>Look at the printed output, why do you think it is repeating?
+User: It's doing zero years first. That isn't right, it's supposed to start at 1.
+Assistant: What line determines that?
+	<alt>Where is years incremented?
+User: Line 12.
+Assistant: What should you do with line 12?
+	<alt>Is that line where it should be?
+User: I see! I'll move it up above the calculation.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+Assistant: Try it now. Does it pass the test cases?
+User: Yes! It works, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8fea1e119b4c9f9003729bd7fc729f6a990d8527
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/74_78_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of "years" in line 8?
+	<alt>Where does "current_fee" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..43f4011cb3b5a7b2aaa2bcd163a50c9579514512
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_1.txt
@@ -0,0 +1,95 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: In line 2, `result` is initialized as an empty dictionary. Then for every (key, value) pair in the input list, line 4 adds the value to the list stored for that key in the dictionary. Finally, line 5 returns the result.
+Assistant: Are you sure that line 4 adds the `value` to the list for that key? Can you try running `d = {1: [7]}` then `d[1] = [5]` in the interpreter and observing what happens?
+	<alt>What exactly in line 4 makes you think that `[value]` is appended to `results[key]`?
+	<alt>Are you sure the value is added to the list? Line 4 shows an assignment statement. According to the Python documentation: https://docs.python.org/3/library/stdtypes.html#dict, if `d` is a dictionary, then the assignment `d[k] = v` only sets `d[k] to have the value `v`.			
+User: Ah, now I see. The old value `[7]` stored in the dictionary is overwritten by the new value `[5]`. Let me fix that so that it is appended to the current value... I did that, but now I get a `KeyError` message on line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        result[key] += [value]
+5.    return result
+
+</code>
+Assistant: I will give you a hint. Can you try running `d = {}` then `d[2] += [7]` in your interpreter window and tell me what happens?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+	<alt>Can you run your code on the input list `[(1, 1)]` and see what happens, then change your current code and in line 2 initialize `result = {1: 0}`, run it on the same list and see if you notice anything different?
+User: Ah, I see now. It raises a `KeyError` in the beginning when the dictionary does not have the key yet. I need to check first if `key` is in the dictionary. How do I do that?
+Assistant: Can you look at the documentation using: https://docs.python.org/3/library/stdtypes.html#dict. It also shows some nice examples. Let me know if you cannot find it.
+	<alt>Sure, to determine if a key `k` is in a dictionary `d`, you use the in operator as in `k in d`, which returns True if the key `k` is in the dictionary, False otherwise.
+User: I found it. Let me change my code to do that... It works now, thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You are welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8e7472f519273dfc7555ccccd4a5bbff3b1b2f12
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_conversational_thread_2.txt
@@ -0,0 +1,105 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+User: It will have value 2.
+Assistant: So the value 1 that was in `a` is lost and overwritten with the new value '2'. Now, looking at the second test example, let's consider what happens in line 4 when the `(key, value)` tuple has value `(2, 7)`. What will be stored in `result[2]` after executing line 4?
+User: `result[2]` will be equal to `[7]`.
+Assistant: Good. Now, at the next iteration, the tuple `(key, value)` will contain `(2, 5)`. What will `result[2]` become after executing the assignment in line 4?
+User: Oh, now I see. The previous value will be overwritten and `result[2]` is assigned `[5]`. This explains why for every repeating key, only the last value that appears with it is stored in the dictionary. This means that instead of assignment I need to do something else to append. Let me see... Well, I edited the code to append the value, but now I get a `KeyError` message.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+
+</code>
+Assistant: Can you change your current code and in line 2 initialize `result = {1: [0], 2: [0], 3: [0]}`, then run it on the first example and see if it works this time? If yes, what do you think is the problem?
+	<alt>Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: Now it works, it is able to append the values to what it already has for each key. I believe this means it does not work when the key is not in the dictionary.
+<code>
+1. def my_func(valList):
+2.    result = {1: [0], 2: [0], 3: [0]}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+6.
+7.print(my_func([(1, 1),(2, 2),(3, 3)]))
+
+</code>
+Assistant: That is correct. Can you change the code now so that whenever you append a value, the key is in the dictionary?
+	<alt>That is correct. Can you change the code so that it checks to see if the key is in the dictionary first and proceed correspondingly?
+User: I made it work! I added another loop where I initialize the dictionary with empty lists for each key that appears in the input list. It passed all tests. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for (key, _) in valList:
+4.        if not key in result:
+5.            result[key] = []
+6.    for key, value in valList:
+7.         result[key] += [value]
+8.    return result
+
+</code>
+Assistant: Great! You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..104ebb5cef5e5f4e088744d10a028ac8cb6c3199
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/7_35_integer_grouping_socratic_dialogue.txt
@@ -0,0 +1,122 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c7103d150a8fae622f5cff05c825a71aa2b3d3b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_1.txt
@@ -0,0 +1,98 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Probably before `my_func` so on line 3 I can insert my function definition for `yOf(x)`.
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. Are you planning to declare a function inside of another function?
+User: Yes. It's called a nested function! Let me edit my code. Ah I see that `x` is not defined, but I do define it on line 5.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: What is the scope of the parameters declared for the function `yOf`?
+	<alt>Where can `x` be used?
+User: Oh the scope is only line 6. I see it. I don't need `x` on line 6 since I am the `map` function takes care of passing each element in `range(len)` to `yOf` as the parameter `x`. Let me edit my code.
+<code>
+1. import random as rand
+2.rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: Good. Have you tried your code for all examples?
+User: Yes it does! Thank you for your help today!
+Assistant: You're welcome! Let me know if you have any other questions!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_2.txt b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0541576191cb148319873bc12fe44df30da7034b
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_conversational_thread_2.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: It seems to be the case. Not really sure though what to do though.
+Assistant: You wanted to learn more about the `map` function and how to use it in this problem. What is a good resource for you to find examples where the `map` function is being used?
+	<alt>Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Ah. Let me look at the Python documentation for the `map` function. After looking through some examples -- I see `lambda` being used with `map` quite often for example you can declare a list `numbers = [1, 2, 3, 4]` and then use the map function with `lambda` like this `result = map(lambda x: x + x, numbers)`.
+Assistant: Good find. Let's try it in the terminal and printing `result` as a list. What do you observe is being stored in `result`?
+User: I observe `[2, 4, 6, 8]` as the output.
+Assistant: Given that, what do you think the `lambda` did in the snippet here?
+	<alt>Can you describe what `lambda` does?
+User: It seemed to have summed up each element in `numbers` with itself so `[1 +  1,  2 + 2, 3 + 3, 4 + 4]` so I guess `x` in `lambda` represent each element in `numbers`.
+Assistant: Good. So looking at our programming exercises. Do you see a use for `lambda` in your code?
+	<alt>Good. Now, where can you use `lambda` in your programming exercise?
+	<alt>Good. Do you see a use of `lambda` in your `map` function call on line 5?
+User: Ah yes! I'll replace my messy function declaration with `lambda`. I think it works!
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    y = list(map(lambda x:  x * 6 + rand.randint(1, len),  range(len)))
+5.    return y
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes it does! Thank you! I learned more about `map` and `lambda` today!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..870ad5e7b0b17adc1ce3dc2b559e19dbd05b7b75
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/8_36_plot_function_socratic_dialogue.txt
@@ -0,0 +1,147 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_conversational_thread_1.txt b/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aedba6fbbb1b6c8a599e81442bb390529b5d6c8c
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange `TypeError` in my helper function
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices
+Assistant: Ok, let's start with your helper function `det2d` then. What are you trying to do there?
+	<alt>Can you describe the inputs and outputs of your helper function?
+	<alt>How does your `det2d` function work with the `determinant` function? How do they interact with each other?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices that you're passing to the helper function `det2d`?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+User: I am using this function to calculate the determinant of a 2x2 submatrix. Then, I'll compute the determinant of the 3x3 matrix using those submatrix determinants.
+Assistant: Good. How can you verify that you are computing the determinant of a 2x2 matrix correctly?
+	<alt>What happens if you pass an array with the incorrect dimensions to this function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I looked through an online resource. My code matches the formula, and I tested it with some simple matrices. I use a 2x2 matrix represented as an array of arrays. The first index represents the row and the second index represents the column number. To access a specific value, I select a row array and then get the value from that array.
+Assistant: Ok. How can you verify that `matrix` is a 2x2 matrix?
+	<alt>What happens if you pass an array with the incorrect dimensions to the `det2d` function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I think that's the issue. It looks like I accidentally passed in my values as a 1D array. I'll add a set of brackets. It looks like `subm2` and `subm3` both have this issue
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+Assistant: It looks like your code works now!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_socratic_dialogue.txt b/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..58c862ac4e04af16882183dffb51173e9b65f10f
--- /dev/null
+++ b/data/raw/v2_sigcse/evaluation_dataset/9_38_calculating_determinant_socratic_dialogue.txt
@@ -0,0 +1,67 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says "'int' object is not subscriptable" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..69cd2f3befba3bf4fbf9ec6883999b4b44ae4da2
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,119 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student has a misconception about for loop ranges. The student also struggles to explain their code. The student knows how to use the debugger.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I can use the debugger perhaps.
+	<alt>I can add print statements.
+	<alt>I'm not really sure can you suggest a way?
+Assistant: Let's first examine the values of `i`. How many times in total does the for loop iterate?
+User: Using the debugger I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks good! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..065bb32ed9acd4e0e41fe8295da0602690554d9a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,141 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to `0` not `1`? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time and remove the print statement. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks correct! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3e0a27c8151d319d456c91146ba16ef7f1425e5e
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,199 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0, not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that. 
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(n)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that `i` is always 5 when `n` is 5. That doesn't make sense.
+Assistant: Are you sure that you are looking at the values of `i`? Examine line 12.
+	<alt>What variable are you printing on line 12?
+User: Oh whoops! Let me fix that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the terminal output. How many times does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5, and the values of `n` range from 0 to 4 or `n - 1`.
+Assistant: Good. Can you identify other variables that might be important for us to track to identify the issue?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>What would happen to the returned Fibonacci term if the for loop iterates 6 times?
+User: I think it would be good to track the variables `a` and `b` since I return `b` in the end and `a` is used to compute `b`.
+Assistant: Good. What do you think would be a good way for us to track the values of `a` and `b`?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: I think I can add a print statement for these variables inside the for loop!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(f"a: {a}\tb: {b}\t i: {i}")
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good. What do you observe about the values of `b` as the loop iterates?
+User: Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the last value of `b`?
+User: Oh! It's 8 which is what I am returning instead of 5! But why is that?
+Assistant: How was `b` computed in the final iteration of the for loop?
+User: I think `b` was 5 and `a` was 3 so  `b = 3 + 5` which is 8. Not sure how to get it to return 5 though.
+Assistant: What would happen to the returned Fibonacci sequence if the for loop iterates 6 times?
+	<alt>Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: Hm. I think it would `b = 5 + 8` which is 13 the next number in the Fibonacci sequence.
+Assistant: Do you notice a relationship between the number of for loop iterations and the Fibonacci term returned?
+User: Yes! I do think that the more the loop iterates the larger the Fibonacci term is returned. Maybe my for loop is iterating more than it should.
+Assistant: Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code and remove my print statement.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all is correct thank you so much!
+Assistant: You are welcome. Let me know if I can help with anything else!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a9b5b0ef4344a852e7725224c599a5f6b336ecd
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_0_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,158 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
diff --git a/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6b2b5d9ebca861c02068de0a199821dfb9f52a44
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,91 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>Hello! I need help on this my code is failing the first test case.
+Assistant: Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Can you walk me through your code step by step given that `n` is 0?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+	<alt>Can you describe the issue you are facing? Is your code failing any test cases?
+	<alt>Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: Hm... I've never seen assignment being done like this before. I presume it would be a compiler error?
+	<alt>I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Let's verify that. Can you open a Python terminal and type in `x = 0` then on a new line `y = 1 if x < 0 else 0`. What do you observe?
+User: Ah. It works! I learned something new today.
+Assistant: What do you think the value of `y` is?
+User: I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Good. Let's look at your `fibonacci` function. Given that `n` is 0. Can you walk me through your code step by step?
+	<alt>Let's verify that. Can you print `y`? What do you observe?
+	<alt>Good. Let's look at your `fibonacci` function. Given that `n` is 0. What does the if statement on line 2 evaluate to?
+	<alt>Good. Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: On line 2 `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good. Did you try running your code through all the test cases?
+User: Yes. Thank you very much for your help!
+Assistant: You're welcome.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..692135c1808168d758578b95b634ed96cd7e3ff3
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_2_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..75350a91e85f7f7fef581e7c82b70b7b582ad5d2
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,79 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: The previous two positions.
+	<alt>The numbers at positions n - 1 and n - 2.
+	<alt>The numbers at positions n - 1 and n - 2. Ah, now I see, I made a mistake on line 7, I used the wrong positions there. Let me fix it... It works now, thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n-1) + fibonacci(n-2)
+
+</code>
+Assistant: Correct. Since the current position is `n`, what are the previous two positions?
+	<alt>That is correct. Looking at your code, does it really add the Fibonacci numbers at the previous two positions?
+User: Ah, now I see what the problem is. The code on line 7 adds the number at the current position, instead of positions `n - 1` and `n - 2`. Let me fix that... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome, happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76f4d0a06fb8486c07330eb167c986744f0e45a4
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,84 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: Can you explain what infinite recursion means?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: Infinite recursion means that the function calls itself without ever stopping.
+	<alt>I am not sure, can you explain infinite recursion to me?
+Assistant: Correct. Where in the code does the function call itself?
+	<alt>Good. Given that the problem is caused by the function calling itself forever, where in the code do you think the problem is?
+User: It is on line 7.
+Assistant: Correct. There are two recursive calls there, can you figure out which of them leads to infinite recursion?
+	<alt>Correct. So, when the function is called as `fibonacci(n)`, if it gets to line 7 it calls `fibonacci(n)` again, and if that is completed it then calls `fibonacci(n - 1)`. Do you see why this leads to infinite recursion?
+User: Ah, I see. It is the call to `fibonacci(n)`, because `fibonacci(n)`calls `fibonacci(n)`which will again call `fibonacci(n)`, forever.
+	<alt>Ah, I see, it is the call to `fibonacci(n)`. I made a mistake, I should have called fibonacci for `n - 1` and `n - 2`. Let me do that ... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+Assistant: Good! That means the code on line 7 is not correct. Can you look at the problem description to see how the Fibonacci number at position `n` needs to be computed and fix your code?
+	<alt>Good! Can you fix the code in line 7 so that it implements what is in the problem description?
+User: Ah, I see now, the previous two numbers are at positions `n - 1` and `n - 2`. Let me fix that... it works now! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..465f2800ce958f878af1ebf2a69e8821aae7a0ea
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>Can you explain what infinite recursion means?
+User: We get the Fibonacci number for `n + 1`. Ah, I see what the problem is, I used the wrong inputs in the recursive calls. Let me fix that... it works, it passes all the tests now. Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+	<alt>We get the Fibonacci number for `n + 1`.
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..051ac2ae597cb75601ac0694350209c2e2f5a0d6
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_5_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..bc33e1d17632dbf5f59182fb9124d55463546161
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,82 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: It says to return 1 when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: So will it return `1` when `n` is only equal to `1`?
+	<alt>Will `n` ever be `1` and `2` at the same time?
+User: No, it looks like it will return `1` only when `n` is `1` and `2`.
+Assistant: Will that ever happen?
+	<alt>Is that what you are supposed to do according to the instructions?
+User: No, `n` can be either `1` or `2`, but never both `1` and `2`.
+Assistant: Correct! How do you check if `n` is `1` or `2` instead of both `1` and `2`?
+User: Will it look like this?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: Correct, do you now see the difference between `or` and `and`?
+User: I see it now, `and` evaluates to true only when both cases are correct. But `or` evaluates to true if either of the cases are correct. Thank you for your help!
+Assistant: That is right, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d2154b30aa8f17ece8888c2a5dbedc8c29175f0
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/0_6_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c244e010918d5f3c22614c505ad804ef4eb67c6a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_conversational_thread_1.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+	<alt>If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+Assistant: Let's test each of these separately. How can you check whether the methods are being called?
+User: One way I could check this is by adding `print` statements right before the methods to make sure I'm reaching those parts of the code. It looks like I'm reaching each part, but the sentence isn't changing. I think I'm not using these methods properly.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           print("here1", sen)
+           sen.replace(i, "x")
+      else:
+           print("here2", sen)
+           sen.replace(i, "X")
+  print("here3", sen)
+  sen.swapcase()
+  return sen
+
+</code>
+Assistant: Is there an easy way to modify your code to verify whether your code is modifying the original string?
+     <alt>What makes you think that you are using the methods incorrectly?
+     <alt>Have you considered printing the output of the method calls to see if they are changing the string, for example, `print(sen.replace(i, "x"))`?
+     <alt>Have you considered assigning the output of the method calls to a variable?
+     <alt>Where can you learn more about how `.replace()` and `.swapcase()` work and how they are used?
+User: Hm, I guess I can just assign `sen` the output of the method calls, in case they don't do in-place changes. That works!
+     <alt>I could also just print the output of the method calls to see if they are changing the string.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: Great! let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9160d401c193a67ea8b57aa8e809699d0854c3d7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/10_39_xnglxsh_socratic_dialogue.txt
@@ -0,0 +1,75 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = "To"` and then `sen.replace("o", "X")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = "English"` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace("o", "X")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67d4e9361aaa605be0735a6ed1c76f8dae5d0cb6
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: Ah I see the problem now. I should use `==` instead of equals to check for equality. Let me edit my code.
+	<alt>I am trying to check if `rev_string` is equal to `string`.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good! Does it pass all the test cases now?
+User: Yes it does! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ccb927b1d35b709abe5b5b8d8ba6901a41f79114
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_2.txt
@@ -0,0 +1,94 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't added yet?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..05f680bfee5168ebe0d451dbcd61e748705c8fe5
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_conversational_thread_3.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't completed yet?
+	<alt>I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/11_40_palindrome_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..608c84efc580ebe5d8951024b6e71480399a0b03
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/11_40_palindrome_socratic_dialogue.txt
@@ -0,0 +1,73 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9e45c7683bf8e36d8dacc6f4354183ee3d9908e6
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: The `[-1:]` slicing operator should return a list in reverse order.
+	<alt>I think it should return a list in reverse order but it's returning the last element of the list instead.
+Assistant: What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Let's run your code through all the test cases. Do you notice a pattern in your function's outputs?
+	<alt>Let's open the terminal and run `[1, 2, 3][-1:]`. What do you observe?
+	<alt>Let's start with a simpler problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+User: It returns `[3]` instead of `[3, 2, 1]`. Hm... it seems to be returning the last element of the list instead of the whole list in reverse order.
+Assistant: Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+User: For an input list `a`, we can get every other element by using `a[::2]`. So `a[::2]` should return `[1, 3]`.
+Assistant: Good. Given that `[-1:]` returns the last element in the list, how do we combine using `::` with `[-1:]` to get every element in reverse order?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Good. `::2` gives us every other element and `[-1:]` gives us the last element. How can we get every element in reverse order?
+User: Oh, I see. We can just get every element of the list in increments of -1. So `a[::-1]`. I'll update my code. It looks like it's working now
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..071edd0259455dc702e145d33c8c244d2bd6d83d
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/12_41_reversing_a_list_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/13_42_limit_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/13_42_limit_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..111e617adc183b4a313c4a6e21420cebbf15236a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/13_42_limit_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many times will the for loop execute?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>Is that the list that you want to loop through?
+User: It will be executed the length of the `lst2` times.
+	<alt>It will execute 0 times because `lst2` is empty.
+	<alt>How do I find that out?
+Assistant: What is the length of `lst2`?
+	<alt>Is `lst2` the list that you want to loop over?
+User: It is 0, so does that mean the for loop is never executed?
+	<alt>It is 0, should I loop over `lst` instead?
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+	<alt>Yes.
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/13_42_limit_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/13_42_limit_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fb83ca8d767fb22839d3d9cb4f928dc75874b376
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/13_42_limit_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/14_43_used_twice_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/14_43_used_twice_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cbbcd5dfa285b7355d54c0d8e3eae61cde9c4fd1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/14_43_used_twice_conversational_thread_1.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! This code isn't working. Can you help?
+Assistant: Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: Well, boolean and Strings are different data types. Booleans have a true or false value, and Strings are just written words.
+	<alt>a boolean true is written like `bool = True`, whereas a String variable is written as str = "True."
+	<alt>I don't think there is a difference. I think both boolean "true" and String "true" looks the same when you write the code. For example, str = true and bool = true.
+Assistant: Let's try an example. How would you declare a string variable "str" and initialize it to the value "true?"
+	<alt>What are the two possible values of a boolean variable in Python?
+User: String str = "true";
+	<alt>Wouldn't you want to use a boolean variable for that instead?
+	<alt>String str = true;
+	<alt>str = true
+	<alt>String str = True;
+Assistant: That's right! Now, how would you declare a boolean variable `bool` and initialize it to false?
+User: boolean bool = false;
+	<alt>boolean bool = False;
+	<alt>boolean bool = "False";
+	<alt>I don't see that we are using boolean variables in the code.
+Assistant: Programming languages are very sensitive to syntax. For example, String variables require the use of quotations around their input. Can you think of any similar constraints to boolean inputs?
+	<alt>Try looking at the Python documentation. Can you find the section where they describe the use of Boolean variables? How does it compare to what you wrote here?
+	<alt>Let's try that in the Python terminal. What happens when you type `bool = false`?
+User: Oh, I see. I was writing `bool = true` when I should have been writing `bool = True`. I am missing a capitalization.
+	<alt>I should be using 0 and 1 instead of false and true.
+	<alt>I can't think of any constraints.
+Assistant: Good! Can you find where you made this mistake in your code?
+	<alt>How can you edit your code to fix this error?
+User: Yes, I found it. I'm going to show you the changed code now.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Good work! Looks like you did it.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/14_43_used_twice_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/14_43_used_twice_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fed235c9f380c3072884cf6a17a1c2bd4164c248
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/14_43_used_twice_socratic_dialogue.txt
@@ -0,0 +1,83 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = "True"
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a2444fd8fc1fc32d185025275eff35f4a441991b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ca3e5b177344b28bdac27a25a96d6bb2148a6737
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: Oh, it always returns a position where `seq[i] > x`. I think I need to also test for equality, let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c01957c386144f83d5e40c90e7adc81514e78a49
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: Because the element at position 1 is equal to 5, and according to the problem description whenever the number is present in the input list we should return its position.
+Assistant: Good. Now, can you tell me what happens in your code for test example 1 when `i` takes the value 1? Start with line 3.
+	<alt>Good. Does your code ever test if the number `x` is present in the list?
+	<alt>Good. How can you determine, using code in Python, if a number `x` is present in a list `seq`?
+User: When `i` is 1, `seq[1]` is equal to 5. On line 3, since 5 is not less than 5, this means that line 4 is not executed, so we go back to line `2` where `i` is assigned the next value of 2. Ah, now I understand where the problem is,  I should have tested for equality too, let me do that ... It works now! Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..971311e0e39aa34053be4ca60d7da34fecf47353
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_44_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_conversational_thead_1.txt b/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_conversational_thead_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a70d26285fac100164974287447f4465eba01da
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_conversational_thead_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: Can you walk me through how your function handles some simple examples? For example, `search(5, [-1, 5, 8, 10, 12])`.
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: For that example, I get an output of 1. I first iterate through the elements in the list and check when the 5 is less than or equal to the current element, which happens at index 1. 
+	<alt>This just gives an output of 1
+Assistant: I see. What happens when you have a larger `x` value? Try `search(20, [-1, 5, 8, 10, 12])`.
+	<alt>I see. What about when your `x` is not less than or equal to any elements?
+	<alt>That seems right. How do you deal with negative numbers and numbers greater than all the list elements?
+	<alt>Good. Is there a case where your function might not return anything?
+User: For that, my code seems to return `None`. I use the same procedure and iterate through the list element. Oh, I see. Since 20 is greater than all the current list elements, I never get to the `return`
+Assistant: It looks like you just need to handle that other case then. What's a good answer to return when `x` is greater than all the existing elements?
+	<alt>Where would you want to insert an element that is larger than all the current ones?
+	<alt>What's a good place to insert 20 in the example I gave you?
+User: I think I should put it at the end of the list. I'll update the code and see if it works.
+<code>
+ def search(x, seq):
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Looks like it works! Let me know if you need more help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e99e9d5280aee8185297b28e38a4c7cd8e99e12
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/15_45_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d78c074069ad55788fb28f108ae631fa1663e622
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_1.txt
@@ -0,0 +1,108 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+	<alt>That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+User: OK. I think I need to look at the substring that starts at the last value of `start` and ends at the end of the string. Let me do that... It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+	<alt>Not sure how to do that, can you help?
+Assistant: That's great! Glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7b4e3cbce5f3bf61db44e521928097c52f7c4e67
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_2.txt
@@ -0,0 +1,110 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+	<alt>I don't know, how can I find that?
+Assistant: Great. Now that you know where it starts and where it ends, can you add code that extracts this substring and looks at its length too?
+User: I did that, and it works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f4b15267cf56ade259b3d6b9093f52cf9c9cd408
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_conversational_thread_3.txt
@@ -0,0 +1,117 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I don't know, how can I find that?
+	<alt>I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+Assistant: If you look at the test example, 'dabra' appears right after the last occurrence of `ca`. Which variable in your code computes that position?
+	<alt>Can you tell me what the variable `start` is supposed to do and how it is computed?
+	<alt>Which variable in your code computes the index right after the last occurrence of the string `t`?
+User: So it must be the sum between where `ca` starts, which is in `pos` and the length of `ca`, that is what `start` does.
+Assistant: Correct. Now, where does 'dabra' end?
+	<alt>Correct. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: It ends at the end of the input string `s`.
+Assistant: Correct. So it starts at the last value of `start` and ends at `len(s)`. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: Ok, I did that and it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: Great, glad that I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_46_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9596004c0330f7a64b8df111fd59d911a85f629a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_46_substring_length_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b4d1dfe8e505d610d732f5f7749b018450ac978
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: Ah, I see the problem, I forgot to change `start` inside the while loop. Let me do that ... it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: Great, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e826944d56d97aabaa32ccf77a174b32cd58c356
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_2.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: First, `start` is initialized with 0. Then `pos` becomes 4, then ... ah, I forgot to update `start` inside the loop. Let me try to fix that ... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c5955c5511673f2c69c5e249c9a5c5f8d3f3d8c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_conversational_thread_3.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Does `start` ever change inside the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+User: Ah, it doesn't! It stays equal to 0, which means that `pos` does not change either. Let me fix that... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/16_56_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76250045f41995ac9a4765999215119b64828ec3
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/16_56_substring_length_socratic_dialogue.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..374ed2d7231845cd77b9b540ce4c48d6a31ba5e9
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_thread_1.txt b/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3bd99c0f8e2ed5f3d3602d10ef28c5b04aafc241
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/17_47_topk_socratic_thread_1.txt
@@ -0,0 +1,76 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0,1]`, It seems to work, but `[1]`, it throws an error. 
+	<alt>Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: What does that tell you about the `.pop()` method?
+	<alt>What conclusion can you draw from examining the output of the `.pop()` method?
+User: I think it is removing by index and not value, maybe I should use a different deletion method. I'll try `.remove()`. It works!
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Glad to help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/18_48_password_validator_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/18_48_password_validator_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5798a2092a147a9cc0146ccecbe51b60f43a879b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/18_48_password_validator_conversational_thread_1.txt
@@ -0,0 +1,89 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+	<alt>Hello. I need help with my code.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist. I wonder if this relates to adding a new password.
+Assistant: Good hypothesis. Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Certainly. So when `menu_choice` is `"a"` we go to line 8, we check if  `password` is already stored in `passwords_dict`. If so, the function returns "Password already exists!" otherwise it returns "Password added!".
+Assistant: Good. Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>According to the problem description, what do you need to do with `password` if `menu_choice` is `"a"`?
+User: Oh. It is supposed to add `password` to `passwords_dict` and then return "Password added!". Let me edit my code.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Have you tried your code on all the example cases?
+User: Yes. It works correctly! Thank you for helping me today!
+Assistant: You're welcome. Let me know if I can be of any further assistance in the future.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/18_48_password_validator_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/18_48_password_validator_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0dbda996e22db730584f590a074dd393d85e15db
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/18_48_password_validator_socratic_dialogue.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == "newpass"`. However, `passwords_dict` is initialized to `passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == "newpass"` after calling `validate_or_add_password("a", "newpass", passwords_dict)` in an attempt to add "newpass" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `"newpass"` to `passwords_dict`. I don't think I do that. I thought I just need to print "Password added!". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/19_49_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/19_49_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7ec3a3bd78ab55dabef8e2ad4415656e48b194a5
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/19_49_word_counter_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?.
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/19_49_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/19_49_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c58814d64883b072a0e12ad53944879fa7c7017
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/19_49_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/19_50_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/19_50_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4b030dfeb7859cf8370115d5263b42543f7724e8
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/19_50_word_counter_conversational_thread_1.txt
@@ -0,0 +1,84 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one
+Assistant: Does this happen with all inputs?
+	<alt>Hm, ok. Can you walk me through your code?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: It's happened with all the inputs so far, but I'm not sure if it would happen with all of them
+Assistant: Can you try perturbing the inputs? Maybe add characters before or after.
+    <alt>What happens when you run `count_words("hello world ")`?
+    <alt>How does your function handle trailing whitespace?
+    <alt>Can you describe to me how you are counting words?
+    <alt>Does your loop count the last word in the sentence?
+User: It's still the same if I had numbers or non-letter characters after and before
+Assistant: Have you tried adding whitespace?
+    <alt>What happens when you run `count_words("hello world ")`?
+User: Huh, weird. When I pass the input "hello world ", the answer is correct, but it is wrong without the whitespace at the end.
+Assistant: How does your function handle trailing whitespace?
+User: I see now, I'm not counting the last word unless a space follows it. I'll amend my code to handle this. It looks like it works!
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/19_50_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/19_50_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf9ecb249246e778624f474dc19d6695f60ecad4
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/19_50_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d93f911372ea6e09d6fafa18fd04ceacd7001033
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,132 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Can you explain the differences between `finalScore` and `roundedScore`?
+User: `finalScore` is the unrounded grade and `roundedScore` is the rounded version.
+	<alt>Oh! I see now, I put the wrong score into the comparisons. It works now, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And which of those values are you returning with the letter grade?
+User: Oh! I'm returning a letter calculated from `finalScore` and the grade from `roundedScore`. I fixed the issue, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..873a50745b3a367f894358f9638a38df5a95d9d4
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_2.txt
@@ -0,0 +1,111 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to finalScore is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: It would be false, it wouldn't produce the right `letterGrade`.
+	<alt>It would be true, 70=70.
+Assistant: Correct. But you said you were still returning 70, why do you think that is?
+User: Oh! I'm returning `roundedScore`! If I compare by that too, then I get consistent results. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7c9c01f900c49f29fa12f4755be3b3ded3005653
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_conversational_thread_3.txt
@@ -0,0 +1,162 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+User: I am returning ('D', 70) for test 4 and I don't know why.
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+User:  It would be true, 70=70.
+Assistant: Is that true? Can you verify that?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>Is that true? Can you print the value of `finalScore >= 70`?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+User: Yes, I'll use a print statement to do that.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.    
+10.    print(finalScore >= 70)
+11.
+12.    if finalScore >= 90:
+13.        letterGrade = "A"
+14.    elif finalScore >= 80:
+15.        letterGrade = "B"
+16.    elif finalScore >= 70:
+17.        letterGrade = "C"
+18.    elif finalScore >= 60:
+19.        letterGrade = "D"
+20.    else:
+21.        letterGrade = "F"
+22.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what does it print for test 4?
+User: It prints `False` but I don't know why.
+	<alt>Oh, it prints `False` because it's 69.6, not 70. I need to use `roundedScore` instead. That makes it work, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what is the value of `finalScore` when you use it on line 10?
+	<alt>How does the value of `finalScore` affect the truth value of the boolean expression on line 10?
+User: Oh! I was using the wrong variable. After switching `finalScore` to `roundedScore` in the comparisons it worked. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aa261fea9a34e4a4be8f0c10fabbb4ba40042ec5
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_10_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,138 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fa366d6e26d8844a51959421ae1aaf1a01c12cb1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+    <alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Let's look at the instructions. Is there any information that is missing or not being displayed in your output?
+	<alt>What seems to be missing from your output if you run your code and compare it with the expected output?
+User: I want to return two variables `letterGrade` and `roundedScore` but my function only returns `letterGrade`.
+	<alt>I want to return two variables, but my code only returns one even though I am trying to return both.
+	<alt>I am attempting to return two variables in my code, but only one is being returned despite my efforts to return both.
+Assistant: At which line are you attempting to return two variables?
+User: Although I am returning `letterGrade` on line 14 and `roundedScore` on line 15, it seems like line 15 never runs.
+	<alt>I am returning the variables on lines 14 and 15, but it seems like the code stops after line 14.
+Assistant: Based on the observed behavior, do you believe a function can contain two back-to-back return statements?
+	<alt>After looking at the comparison with the instructions, do you think this might be the correct way to return multiple variables?
+User: No, I think I can only use one return statement. But how do I return multiple variables?
+	<alt>How do I return multiple variables with only one return statement?
+Assistant: Let's refer back to the instructions, and this time we will pay attention to the data type of the expected output. What do you observe?
+User: The expected output consists of a tuple. I suppose I can return the variables together as a tuple with one return statement. I'll try that now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return (letterGrade, roundedScore)
+
+</code>
+Assistant: Does your output match the expected output now?
+User: It displays the expected output.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..569ccc4f9dd5118de9013cc70cb1230b76f7f671
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_11_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_13_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/1_13_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c48ee80ac5aa5926ddbe62ac5a63450e56b67615
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_13_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,183 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_8_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/1_8_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e738b89b749edcaa48a75e228c2740479b244c6d
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_8_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,179 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = "A"
+7.    elif roundedScore >= 80:
+8.        letterGrade = "B"
+9.    elif roundedScore >= 70:
+10.        letterGrade = "C"
+11.    elif roundedScore >= 60:
+12.        letterGrade = "D"
+13.    else:
+14.        letterGrade = "F"
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..78f874f9904471f3ce4a0d1fbbc8e946d96aa081
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,112 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+	<alt>I think that the test cases may be glitched.
+	<alt>Maybe I misunderstood the instructions.
+Assistant: What do you think could be missing in your calculation?
+	<alt>Did you expect to get a rounded number from your equation here?
+	<alt>Do you know any method that can give you a rounded number?
+	<alt>Python has a lot of documentation that can help you solve specific problems. Do you think it would help to look for your solution there?
+User: I see that I don't actually have any rounding mechanism. I could use the round() method.
+	<alt>I don't have any rounding mechanism, but I don't know how to round.
+	<alt>I don't think anything is missing. I get 69.6. But I just need to get rid of the .6 somehow.
+	<alt>Maybe I'm writing my calculations wrong, though I don't know where.
+Assistant: That's a good point! We can use methods in Python to help us solve problems. How could you apply the round() method to your code?
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore.round()
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+User: I am getting an error...What's going on?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: If you are getting a new error, do you think that means the way you applied the round() method could be causing you problems? Are you sure that you applied it correctly?
+	<alt>If you received a new error from your addition, what do you think that means?
+	<alt>When you look in the Python documentation for this method, do you see any difference between your application and their application?
+	<alt>Which part of your code do you think is causing the error?
+	<alt>Try using a debugger to step through your code to find where your problem is.
+User: OK, I guess I didn't apply it correctly. I just looked it up and it says I need to put the variable inside the parenthesis. So, I changed it to this, but I don't think it's working still. It's giving me the original error.
+	<alt>Yeah, I'm sure I applied it correctly. That's how you call methods, isn't it?
+	<alt>I'm assuming I didn't do it correctly. Can you show me how to call this method?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: To help us understand what's going on, let's take a look at how you calculated `finalScore`. You created a mathematical equation and you stored it into the variable `finalScore`. Why did you store it into a variable?
+	<alt>Try to compare what you wrote to a practical application in the Python documentation. Do you notice anything different between your answer and theirs?
+	<alt>We need to find out what part of your code has the problem. What can you do to figure out whether your rounding method is giving you the rounded answer or not?
+User: I stored it in a variable because you can't use that answer otherwise. If you just did the calculation, you wouldn't be able to check it in the if-statements.
+	<alt>I stored it in a variable because that's how the syntax of the language works. You can't just write calculations right in the IDE.
+Assistant: That makes sense. You need to store the answer somewhere. Notice how you wrote the round() method. Based on our discussion, do you think something is missing?
+User: Oh! I see. I am not storing the result of the rounding calculation anywhere. I need to save it back to the original variable.
+	<alt>I'm not sure I understand how the problems are related.
+	<alt>Am I not storing the rounded number anywhere? I thought that using the Python method would be enough.
+	<alt>Instead of using the `finalScore` variable, I should just put the equation directly into the round() method.
+User: It works now! Thanks for the help.
+Assistant: Great! Let me know if you have any other questions.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..658a9d80a86f26feb27a32c9203579ba1b1420d7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/1_9_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1923efad8daf0f895478a02edf114ea43a62e9dd
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Is that everything it is supposed to do according to the prompt?
+	<alt>Does it do anything else?
+	<alt>Okay, on what line of code does it take in those lists of words?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: I think so.
+Assistant: Let's take a more detailed look at the output. What does that part say?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: It says there is a TypeError and that NoneType objects aren't iterable.
+Assistant: Okay, so let's break that down. Let's focus on the NoneType part, what is a NoneType?
+	<alt>Okay, so let's break that down. What does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: A that's an object that doesn't have a value.
+	<alt>I'm not sure.
+Assistant: So why would there be an object that doesn't have a value there?
+	<alt>Let's look at the second part, what does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: I don't know.
+	<alt>My function doesn't return anything!
+Assistant: Where could a NoneType be coming from?
+	<alt>Why could your function be returning a NoneType object?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: My function.
+Assistant: Why could it be returning something with no value?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: I forgot the return statement!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9c527fa1fca8cbe668dab52c626ee3b42557cecb
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/20_51_spell_checker_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a94dc6f8d67e4f4de528d1519ee714155568bfc9
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Can you explain what the "<=" operator does?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+User: That is the "less than or equal to" operator. It returns true if `c` is less than or equal to 0 and false otherwise.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+	<alt>The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..35b266e30f10e8da14bba1b085d89c33763c4293
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the "<=" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+	<alt>Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+Assistant: Which operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the "<=" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf64c30ebf7ca0cd68adbbd8be2e764757281ad1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_conversational_thread_1.txt
@@ -0,0 +1,75 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code
+Assistant: Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: I think there should be a discount of 10% but when I run `cookiePurchase(70)`, I get a discount of 0. I'm so lost.
+Assistant: Let's review the problem description again. What are the conditions for a discount and where in your code do you check for these conditions?
+	<alt>From the task description, you need to check whether the number of cookies is divisible by 10, and it looks like you fail on an input that is divisible by 10. Can you explain how you're checking whether 70 is divisible by 10?
+User: The task description tells me to check whether the number of `cookies` is greater than 10 and whether `cookies` is a multiple of 10, and I fail on 70 cookies, so maybe I'm not checking this properly.
+Assistant: Let's walk through your if statement on line 4 then. 70 > 10 is True, but what is the value of `cookies / 10` when `cookies` is 70?
+User: So, for 70, I first check if it is greater than 10, which it is, and then I check whether it is a multiple of 10. I do this by dividing by 10 and seeing if the output is 0. Wait, that's not right. 70 / 10 is 7, not 0.
+	<alt>So, for 70, I first check that it is greater than 10, and then I divide by 10 to check divisibility
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Where can you learn more about arithmetic operators in Python?
+	<alt>Let's take a look at the Python documentation to see if there is a different operator that does what you want.	
+User: Ah! The Python documentation would be good to look at right now. Looking at the documentation, I think I should be using the modulus operator. I'll try that.
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Looks like it works!
+User: Yes it does for all the test cases! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0456f3ba3d42d12e763e91f4f271458123228ab0
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/22_53_cookie_purchase_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f80d7e1c34a0763ae5139738f00046c6a73882c1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_1.txt
@@ -0,0 +1,78 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+	<alt>The first value assigned to `i` will be 1.
+	<alt>Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: That’s right. So, what happens when `i` is 0?
+	<alt>Correct. Given that `i` is 0, what happens when line 6 is evaluated?
+User: We go into the for loop and compute `fact`.
+	<alt>The value of `fact` will be 0 because `i` is 0. I think I got it `fact` will always be because of this. I need to change the `range` call to start at 1 instead of 0 and end at `n+1` instead of `n`.
+Assistant: That's right. Given that `i` is 0, what will the value of `fact` be after line 6 is executed?
+User: Aha! I see what is happening. `fact` is always 0 because `i` is 0 in the first iteration of the for loop. I need to change the range to start at 1 instead of 0 and end at `n+1` instead of `n`.  Thanks! I think I got it now.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: I am glad I could help. If you have any other questions, please let me know.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1bd1ec69c73a91735f9a53d6e5cf316447e291fe
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_2.txt
@@ -0,0 +1,82 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: Let's examine what happens in this case. Open the Python shell and type `[i for i in range(1)]`. What do you see?
+	<alt>Let's investigate this further. Open the Python shell and type `for i in range(1): print(i)`. Press `Enter` twice to execute. What do you see?
+User: I see that `i` is not declared before the for loop is created. Yet the list comprehension `[i for i in range(1)]` returns `[0]`. So the issue is not with initializing `i` before the for loop.
+	<alt>I see a `[0]` in the list comprehension `[i for i in range(1)]`. So the issue is not with initializing `i` before the for loop but rather with the first value of `i` in the for loop. It is not 1 but 0 so `fact` will always be 0.
+Assistant: Good. Let's take a closer look. What is the first value of `i` in the for loop?
+	<alt>Correct. What do you notice about the first value of `i` in the for loop?
+	<alt>Notice that the value of `i` in the first iteration of the for loop is 0. How do you think this affects the value of `fact`?
+User: I see. The value of `i` in the first iteration of the for loop is 0. So `fact` will always be 0 because the first value of `fact = 1 * 0` is 0. Then, `fact` will be `0 * 1` in the second iteration of the for loop, and so on.
+Assistant: Good! How can we fix this issue?
+	<alt>Good. Now, what does a correct factorial sequence look like for `n=4`?
+User: I think we can fix this by changing the range of `i` to `range(1, n + 1)`.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: Good! Let's test it. What is the factorial of 5?
+User: The factorial of 5 is 120. It works!
+Assistant: I am glad I could help. If you have any other questions, feel free to ask me.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..586ad2f28814182968cc2c41d80e0399031ed181
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/24_29_factorial_conversational_thread_3.txt
@@ -0,0 +1,166 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of n it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because `range` by default starts at 0.
+	<alt>Oh! `i` is not declared before the for loop is created maybe that causes this issue.
+Assistant: Are you sure about that? Can you verify that the first value assigned to `i` is 1?
+User: OK, let me print its value at each iteration. I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>OK, let me check in the Python documentation what range does. I see, the first value is 0, not 1!
+Assistant: How can you fix the code so that in the first iteration fact is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+User: I don’t know, can you help?
+	<alt>I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+	<alt>I can change to `range(1,  n + 1)` so that it starts iterating at 1.
+	<alt>I can change to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change to `range(n) + 1`, so that the first value is 0 + 1.
+Assistant: How can you ensure that in the first iteration `fact` is multiplied with 1?
+User: I can add a line that sets `i` to 1 before the for loop.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+User: Hm... It still returns 0.
+	<alt>It still returns 0. I think I need to change the for loop.
+Assistant: Do you know why it still returns 0?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>Let’s look at the terminal output. What value is `i` on line 7 when being printed?
+User: I think the problem is that `i` is still 0 in the first iteration of the for loop. It still prints 0. I think I can add an `if` statement to the for loop that checks if `i` is 0 and if so, sets it to 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                if i == 0:
+8.                    i = 1
+9.                  print(i)
+10.                fact = fact * i
+11.        return fact
+
+</code>
+	<alt>It still prints 0. I think I need to make a change in the for loop.
+	<alt>I don't know. Can you help?
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Good. Can you try it for `n = 2` and `n = 3`?
+	<alt>Ok! Let's run the code for `n = 3` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: Hm... it's incorrect for both `n = 2` and `n = 3`. I think I need to multiply `fact` starting from 1, then 2, then 3 instead of what I'm doing now 1, then 1, then 2.
+Assistant: Good. How can you change the for loop so that the iterator variable `i` is not equal to 0 in the first iteration of the for loop?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>How can you edit the code so that `fact` is multiplied with 1, then 2, then 3?
+	<alt>What do you think you can do to make sure that `fact` is multiplied with 1, then 2, then 3?
+	<alt>How can you change the for loop so that the iterator variable `i` iterates starting from 1?
+User: I think I am going to change `range` to `range(1, n + 1)` so that it starts iterating at 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+	<alt>I think I am going to change `range` to `range(1, n)` so that it starts iterating at 1.
+	<alt>I think I am going to change `range` to `range(n) + 1` so that the first value is 0 + 1.
+Assistant: Sounds good, let's try it for `n = 2` and `n = 3` again.
+	<alt>Did you try it again for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Awesome. Don't forget to remove the print statement before you submit your code.
+	<alt>Good! I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you! I will do that.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                fact = fact * i
+8.        return fact
+</code>
+Assistant: I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/24_29_factorial_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/24_29_factorial_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7df61e9d91ff71c70cffa036b44cee77c5e49f14
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/24_29_factorial_socratic_dialogue.txt
@@ -0,0 +1,135 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3923bde64ffe0970724120b16b7b24e77f734792
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2  , Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as 1-> 2-> 3 -> 4.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind? 
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Now checking assertions, what happens when we run the checks?
+	<alt>Looking at our test case, can you trace what happens as your code runs?
+User: Lines 24, 25, 26 run successfully, which means that the data attribute of the head node of the linked list is equal to 1, the next node holds data 2, and the node after that holds data 5. However, we run into an error at line 27.
+	<alt>It looks like I run into an error at line 27, so it seems that the node after Node5 is unavailable.
+	<alt>It looks like Node3 is no longer in the linked list.
+	<alt>Somehow it looks like the linked list is broken, and checking for a node with data 3 throws an AttributeError.
+Assistant: That's right. Can you tell me what your linked list is currently looking like (after running `insert_after(head, 2, 5)`)?
+	<alt>Let's take a look at the current linked list we have. What might be missing from this list?
+User: It seems that `head.next.next.next` is None. It means that the new linked list is actually `1 -> 2 -> 5`, after executing `assert_after(head, 2, 5)`.
+	<alt>It looks like I have a broken linked list. The current list stops at `node` with data 5.
+Assistant: Yes. You are right. These nodes after node 2 in the original linked list (`1 ->2 -> 3 -> 4`) are gone, after executing your function, `assert_after(head, 2, 5)`. Namely, we are supposed to get a new linked list, 1->2->5->3->4, but your function implementation gives a list of 1->2->5. Which link is missing in the execution of your function?
+	<alt>That's right, we need to account for making sure that the current connections keep working when we add a new element somewhere before the end. Can you tell what needs to be updated in the code to make sure we update all existing links?
+User: I see. The link from node5 to node3 is missing. The next attribute of node5 should refers to node3.
+	<alt>That makes sense, I think I need to make sure that when I place a new node into the list, I assign the node link to the previous node's next link, so I can maintain the connections.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.           new_node = Node(data=new_data)
+11.           new_node.next = curr_head.next
+12.           curr_head.next = new_node
+13.           return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c2f04014f2be36ec150b6d47a51b004d5034d36a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/25_55_insert_to_linked_list_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5816fc7a4f695df04168eac18525185aa67a600d
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_conversational_thread_1.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` an then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: That's right. According to the problem statement, we can buy more cookies, but not reduce the cookies we have. In which line of your code might this requirement be violated?
+	<alt>Let's also keep in mind that we can buy more cookies, but not waste any that we already have in the process of ensuring everyone gets the same amount, as mentioned in the problem statement. Where can we account for this in your code?
+User: That makes sense. I think I need to modify line 5, and account for the requirement that I can buy more cookies but not vice versa. I will update line 5.
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    purchasedCookies = people - cookies % people
+6.    newCookies = cookies + purchasedCookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</code>
+Assistant: Sounds good, see you later!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85a0354c3b499bffc872b15a12f25deea1ff3fd8
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/2_18_splitting_cookies_socratic_dialogue.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/3_20_counting_down_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/3_20_counting_down_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9f03ecc9e575e5f0cf636ebbf18ecc558645fe1a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/3_20_counting_down_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+	<alt>When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3.
+Assistant: That's right. In your `else` condition, we run into this error. Let's also review your `if` condition. Do you observe any similar issues?
+	<alt>Let's also try other test cases. Based on the observed outputs, do you think there is another similar issue in your code? If yes, which lines are affected?
+	<alt>Let's complete our analysis of the issues by checking what happens if we run the other test cases as well. Do you observe any issues?
+User: Yes, the while loop in the `if` condition also has a similar issue. I will fix this issue for both the if and else conditions.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.   return l
+</code>
+Assistant: Do all the test cases work correctly now?
+User: Yes they do, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/3_20_counting_down_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/3_20_counting_down_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3cf29f118180022365583ed08c26ea38933e89f7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/3_20_counting_down_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1428e2d960a33311a690e94fa5d1de1f13145762
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Ok, they are >=, <=, >, <, =!, and ==.
+Assistant: Ok, what does =! do?
+  <alt>How do you check if two numbers are unequal?
+User: It checks if two numbers are not equal.
+Assistant: Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I think I used the wrong operator. I should have used != instead of =!.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..354c5133f17c48e48c66cbae273a9d4639b5b641
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_22_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,62 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9bd416f7fa51284317fcae08059df9cdf4acc118
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>Can you explain your function to me line by line?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: For example, the input list `[0,2,3]` will return `[2,3]`, but many other inputs result in unchanged outputs.
+	<alt>I seem to only remove 0s from my lists
+	<alt>Running `returnOdd([2, 4, 6, 8, 10])` gives the same list back, for example
+Assistant: Can you explain what your if-statement on line 4 is doing? Let's assume `i` is 4.
+	<alt>How do you check if a number is even in your code?
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+User: In the case before, we can look at 0 first. `0 / 2` is 0, so we get False on line 4 and do not append. For `4 / 2` is equal to `2`, it looks like I'm not getting what I want. Line 4 gives True, so we still append. That's not what I want though.
+Assistant: It looks like just dividing isn't doing what you want. Is there another operator that can test whether a number is divisible by another? Feel free to reference the documentation.
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Looking at the documentation, it seems like I can use a `%` to test whether the number is even. I'll try that.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Looks like it works!
+User: Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0939ecc606a1fd49f467cd1588ac4f0b6f4af25f
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_23_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..30070b15a2e20b9e636a2e6d76fcfd5e69ccd69a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,55 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+User: The scope refers to the visibility of a certain variable depending on where it has been used. For example, a variable defined inside a function is only visible to the function, and cannot be used outside the function.
+	<alt>The scope means certain variables can only be used within the visibility of the code block they are a part of.
+Assistant: That's right. Let's look back at your code now. Is the return statement in the correct scope?
+	<alt>Right, so how would you indent line 6 so that it is part of the method?
+User: I would need to indent it so that it is inside the function. I will make changes now.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Sounds great! Happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..463a697ddd004f912dd87d61d0edc2dba5c1b598
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_25_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..187bd3ed7c77b8654f0efff763d9765e59e4ac74
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases if any are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: I don't know, how could I find out?
+	<alt>No, I'm iterating through the whole list of numbers.
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+User: When running the function with `nums` as `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]` only `1` is printed. I think this means the for loop is iterating only once and therefore returning `[1]`.
+Assistant: Do you notice anything in your function that might cause the for loop or the function to end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know. What do you think can make a loop end early?
+User: I don't see any break statements. Perhaps it might be the return statement on line 6.
+Assistant: Good. When is that return statement getting executed? Is it before or after the for loop completes iterating?
+User: I get it! It's returning after one iteration! Let me unindent the return statement so that it returns after the for loop is completed.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..573522c58359c29be4591852b5a1633261555e7d
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_26_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,93 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d274557923f75bb99fedfee06d53bf7bbe6eadd3
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: Yes, can you use the caret in your output to figure out what is wrong with your syntax?
+User: It looks like there is something wrong towards the end of line 3, but I am not sure what that is.
+Assistant: Can use the documentation to figure out the syntax of a for loop?
+	<alt>It looks like you are missing a punctuation mark, do you know what that is?
+User: Am I missing a colon at the end?
+Assistant: Yes, you need to include that colon at the end of line 3.
+User: This code now works, thank you for your help!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: That looks great, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c605112e950fb1b7d189aca6b9600a28a219d49
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/4_28_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..19b112a9b28e9331603d712ec7d390177eee2329
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide 6 by 2.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type in `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ac351106c4d0060c6182dd4b7fe0b879868900d5
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_conversational_thread_2.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant:   Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/56_15_compute_average_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8999a05df5cfc4c5811ce2dcdb8588748e1c7f21
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/56_15_compute_average_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/58_58_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/58_58_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92804610fa5671a78bcf745e893efbb9ba218875
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/58_58_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,107 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4539114e548434b02d3f85b83d374c5806368b8b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_1.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is  ... false. Ah, I see where the problem is, the loop stops too early, it should iterate also when `apples` is equal to `children`. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..204476a2e5c01e00d40070025d85a5a7e7215267
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_2.txt
@@ -0,0 +1,57 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is true. Then on line 4, `apples` is assigned the value 100 - 100 = 0 and on line 5 `i` is incremented to 1. Then the while condition `apples > 0` is not true anymore, so the loop ends and the value 1 of `i` should be returned from line 6.
+Assistant: You said that, when we run the code on the third test case, `apples > children` is true. Are you sure about that?
+	<alt>Well, your explanation must contain a mistake, because your function returns 0, not 1 as you said. This means that `i` is never incremented. Can you see where the problem is?
+User: Ah, `apples` is actually equal to, not strictly greater than, `children`. I see now what the problem is.  Let me fix that ... it works now! Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d0d29f8fac42541225d87d5e8c5ee6d3b5df09a6
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_conversational_thread_3.txt
@@ -0,0 +1,56 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It ensures that there are still enough apples so that we can give each child ` more apples.
+Assistant: OK, but is it necessary for `apples` to be strictly greater than `children`? What if they were equal, would it still be sufficient to give 1 apple to each child?
+	<alt>Sure, but is that condition really necessary? Think of the third test case, where `apples` is `100` and `children` is `100`, would these numbers satisfy that condition?
+User: Ah, I understand now, they can also be equal. Let me try to fix that ... it works now. Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You are welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..93e8936d3618ce036b5ef9428f5357693c2c75ca
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/58_59_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d08b8a7d1f982ac1c75d3ebd3c67bdb1c7162c0c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_1.txt
@@ -0,0 +1,52 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still fails the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to as `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..678c3ea9748d45f4d25e48f24552644b255147b7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: Correct! When you run the code now, you should see that there are no longer any assertion errors.
+User: Yes, that is the case. Thank you for your help!
+Assistant: You're welcome, thank you for asking questions to further your understanding. It is important to understand the fundamentals when you are first learning. Is there anything else that I can help you with today?
+User: No, that is all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8061e160bfbc8b7b6788c4e3f5be29b2bd8416ae
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/59_60_product_conversational_thread_3.txt
@@ -0,0 +1,54 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Oh! I made the change and now it prints out `None`.  I realized I just forgot to put a `return` statement and I've now fixed it. Thanks for the help!
+<code>
+1. def Product(a, b):
+2.	a * b
+3. print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3. print(Product(1,2))
+</code>
+Assistant: You're welcome! Any other ways I can help you today?
+	<alt>It is likely a good decision to remove the `print` statement on line 3 before using this, as it would lead to confusion with a user running this program without knowing your reasoning behind it being there.
+User: That makes sense. Thanks for the help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/59_60_product_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/59_60_product_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3447706bd18f9798905a6143c6bb087c22ab02ee
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/59_60_product_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5a913de0a055bae71188b38bf8bbb590018e1605
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+	<alt>Hi! I've been working on this function and it doesn't seem to be correct.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: It works for all the example cases except for `get_words("Hello World")`.
+Assistant: Let's look at the example cases closely. What is so special about `get_words("Hello World")` compared to the other examples?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+User: For that sentence, there are no repeated words.
+Assistant: Good. How does your code behave when there are repeated words in the input string `s` and how is it different from the expected behavior?
+	<alt>What would your code need to do to ensure that when there are duplicate words in the input string, the function returns a list of unique words?
+User: It seems like I am not deduplicating. How would I go about doing that?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: I could try using a set instead since that makes sure elements are unique. I'll change my code
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: It looks like it works!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d645aaecd6b075ea42d6716e59a313703e2b698b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_2.txt
@@ -0,0 +1,66 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: Can you insert a print statement to print the value of `words` before line 3?
+	<alt>And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+User: Yes, for the input `"Hello World hello"` it returns `["hello", "world", "hello" ]`. Is that not correct?
+	<alt>Oh, the problem wants me to return unique values only. I've fixed it, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Let's look at the examples in the problem description. What happens when you run `get_words("Hello World hello")`? What should the output be?
+User: Oh! I've fixed my code, I missed that in the problem. Thank you for the clarification!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Any time! If you have any more questions, feel free to ask.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1f9289d5140eae02bebf35a3a70a18962d913b07
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_conversational_thread_3.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+	<alt>Can you print the value of words before line 3?
+User: It sorts the values in `words` alphabetically.
+Assistant: Can you explain what the problem wants you to return?
+	<alt>Where do you remove duplicate values from words?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+User: Oh! The problem wants me to return a sorted list without duplicates. Is there a given function to do that?
+	<alt>Oh! The problem wants me to return a list with no duplicates! I've fixed it now, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>Is there a data structure in Python that stores unique elements only?
+	<alt>Where can you learn about deduplicating a list in Python?
+User: Oh, a set! I figured it out, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: No problem! If you have any more issues, please feel free to talk about them now or later.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4a84f7ffbafbac182376e7e75ffb262bd1abd1b8
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/5_30_sorted_words_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like "hello world hello world", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..41c5b9add9306768bd4e16e8f46db1bb3efc476a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_1.txt
@@ -0,0 +1,56 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: Oh! I would have to pick from one of the two, but it doesn't matter which since I'm returning the value, which input is the highest. That makes a lot more sense, I've made some alterations to my code and it works now. Thank you!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b9944434a0fb6adc229a5be99ec52fc4af89519
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: Oh, I have to do greater than or equal to rather than just greater than. Thank you for the advice!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..48027de0229ad33d8984d9bf7f4bbe64fb4a7b72
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_conversational_thread_3.txt
@@ -0,0 +1,67 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: That would return `None`, right? What should I do in this case, none of my conditions can catch that, do I need to add another case?
+Assistant: I don't think that is necessary, I think there is a way to modify your existing cases to make this work. How would you check if a number is either larger or the same as another number?
+User: Oh! I could use the `>=` operator. That makes it work as expected now, thank you so much!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/60_61_largest_number_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c64d548f36fd47251621714106ff3e6d954858f1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/60_61_largest_number_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e575f4d448c7bfd170e481ef1b8ca5a68dace75
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_1.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: I'm sorry I think too much is going on in that question and I'm confused. Can you simplify it?
+Assistant: Let's break the problem down. Can you create a temporary variable to store `a+b`?
+	<alt>Gladly. First, let's change your code into an `if`/`else` condition. When `(a+b)%2==1`, what do you output?
+User: Okay, I've changed my code.
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 1
+</code>
+Assistant: Okay, now when you do modulo 2 of `inputSum`, what number would be outputted if `inputSum` is even?
+	<alt>Given the revised definition of the modulo operation, can you explain what is outputted from an even sum mod 2?
+User: Since even numbers are divisible by 2, the remainder would be 0, right?
+Assistant: That is correct! And what is the output of `0 == 1`?
+User: Oh, that would be False! I needed to change the 1 into a 0 and now it works as expected. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 0
+</code>
+Assistant: I'm glad to be of assistance! Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..95e016f9a9cfea3e5c68a8e928a73eb548210b41
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_2.txt
@@ -0,0 +1,61 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	  return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: That means that `inputSum` is divisible by 2, right?
+Assistant: That is incorrect. Modulo returns the value of the remainder when the first operand is divided by the second. Given this, when `inputSum % 2 == 1`, is `inputSum` even or odd?
+User: Oh! That means the number is odd, right?
+Assistant: Correct! Since the number is odd, what would the expected response from the `SumIsEven()` function be?
+User: Oh, the expected output would be `False`, I had my booleans backward. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return False
+5.    else:
+6.	  return True
+</code>
+Assistant: I'm happy to help. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2070ad10ef09c7a08a0b02820fd1e24ff19b9bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/61_62_is_even_conversational_thread_3.txt
@@ -0,0 +1,57 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: Oh, I have my conditions backward! That means that the number is odd, not even. I changed the 1 to a 0 and it works now. Thank you so much for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 0):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: I'm glad to be of assistance. Did you want to ask any other questions today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/61_62_is_even_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/61_62_is_even_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c1f95a3c598d2b8906b6d9b8079176069006045f
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/61_62_is_even_socratic_dialogue.txt
@@ -0,0 +1,45 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e32377a10c32c78892cff131fb25f6cdf9a73505
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_1.txt
@@ -0,0 +1,62 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Could I use a temporary variable to do that?
+Assistant: Yes, a temporary variable is entirely fine. Where would you include it?
+	<alt>Why do you feel a temporary variable is necessary?
+User: I created a variable `newHigh` and set it equal to `high+1` and then put that into `range()`'s second input and that fixed it. Thank you!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	newHigh = high+1
+4.	for i in range(low, newHigh):
+5.		num += i
+6.	return num
+</code>
+Assistant: I'm happy that I was of assistance. Is there anything else you wanted to ask about?
+User: No, that was all. Thank you again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f08e6af0a40ef6e93a994f9a05bdb2ea9d6656d2
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would turn it into `range(0,2)`, but is that always the case? Why would it always be adding 1?
+Assistant: Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: Oh, yeah, since it is every integer between the two inputs, not including the second input, `y` would be in `range(x,y+1)` but not `range(x,y)`.
+Assistant: That is correct. Given that, how would you change your code?
+User: I added one to `high` and it fixed everything. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of service to you. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..580b549b1bf9579667dbe080da60bd88961a083c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_conversational_thread_3.txt
@@ -0,0 +1,49 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: It would be a list containing 0 and 1, right?
+Assistant: That is not correct. `range()` is not inclusive of its second argument, meaning that `range(0,1)` is actually a list containing only one element, 0.
+User: Oh, I added 1 to `high` in my `range()` function and it works now, I didn't know that it wasn't inclusive of the second argument. Thank you for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8309521875cf1009334bcdc57c55eca5361154af
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/62_63_summing_between_integers_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f9ccdb9cb52ad6bc8cc840b20c1c3eb12aef34aa
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_1.txt
@@ -0,0 +1,73 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: That's two conditions though, how would I be able to put three booleans into a single if statement?
+Assistant: I see where the confusion is coming from now. Boolean operands can be put into sequence, the same as mathematical operations.
+User: Oh, so it would be syntactically correct to put `pizzas >= 10 and pizzas <= 20 and not(weekend)`?
+Assistant: That is correct.
+User: Oh, that makes the problem a lot easier then! Thank you for clarifying that! My program is working correctly now.
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44e5512491b5a802751848f4c7a8e2e50ab7d9c0
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_2.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if `pizzas` is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, I was just missing a condition on my `elif` statement. I've fixed the issue now, thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d1f82e12e4fd9c26bfbaf7ebe8e1ed05d53200e
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would make turn a dinner into a good dinner?
+	<alt>What would happen when `pizzas` is between 0 and 9, but `weekend` is `False`?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: It would be between 10 and 20 pizzas, inclusively.
+Assistant: Correct, and how would you express that in Python?
+User: Would it be `10 <= pizzas <= 20`?
+Assistant: That notation does not work in Python, you can instead split it up into two statements using an `and` operation. How would you put your previous statement into two statements?
+	<alt>That notation is not correct Python syntax. How would you simplify this problem? It may help to physically speak what the mathematical symbols mean.
+User: Oh, I put it as `10 <=pizzas and pizzas <= 20` and that fixed my code. Thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(10 <= pizzas and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to hear that I was able to help. Is there anything else I could help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e45d2c2adf260dd57c3c6ca15e0fa2a61e06050c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/63_64_good_dinner_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f6fbac0c54c97a10de1a04c598441c02d9bd30ac
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+	<alt>At what index do Python lists begin?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(0, len(integers))`, right?
+Assistant: That is correct, Python lists index from 0, not 1.
+User: That makes sense! The code is working as intended now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that helped you understand. How else can I help you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..51829e6e1ed9187fcee90dd8d33826a769d4c1df
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct!
+	<alt>That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Ah, that is a lot easier to use! My code is working now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..50688dcfaaae29e8966a1e8ba41a94bab964e15c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Oh, I think my previous loop only iterated `len(integers)-1` times, while this loop iterates `len(integers)` times. Was I supposed to use `range(0, len(integers))` in the initial solution?
+Assistant: That is entirely correct. Python lists start their indices at 0, not 1.
+User: Thank you for your help! I plugged the new solution into my code and it works now.
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that I could clear up the concepts for you. Is there anything else you would want to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/64_65_count_ones_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b2acfe19bbad8312880bb0ebe0a33d311d7c3f60
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/64_65_count_ones_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as "distance from the first element" rather than "element number".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..daef07ba3ef314a6d9d4bf62f0bf727664394bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of `smallest` and `largest` throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest` or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for `smallest` and a really small number for `largest`?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: That is correct. Why would that be the case?
+User: If the variables start as members of the array, and are only compared to other members of the array, then they would both always be both members of the array and, by the conditions of the `for` loop, the correct members of the array.
+Assistant: That is correct!
+User: I made the change and the code works now, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..665d9214a4b4d2af11b377247eb7e2210f33c732
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of `array`?
+Assistant: That is correct. Why would that be the case?
+User: That's where I am confused, why does starting as an element of `array` change anything about the solution?
+Assistant: If you pick an element of the list, you can be certain that you never have the same issue as when you just picked 0. As there either exists an element in `array` that is larger or smaller than your initial value, or your initial value is the largest or smallest element itself.
+User: Oh, that makes a lot more sense now! Thank you for the help, my code is working now!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm happy to help. How else can I help you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..196c4e4bd219d77334db421c0f05c2c244bb52fd
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/65_66_list_range_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5]) => 4
+Range([2,2,1,3]) =>2
+Range([-10,-3,-1]) => -9
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.	smallest = 0
+3.	largest = 0
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = array[i]
+7.		if(element < smallest):
+8.			smallest = array[i]
+9.	return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == -9
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Oh, [-1001, -1010] would work for that. I see the point now, if I set `largest` and `smallest` to `array[0]` initially, they would always be a member of the array, which ensures the comparisons will always be between elements within the array rather than arbitrary values. Now my code is working, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could clear that concept up for you. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/65_66_list_range_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/65_66_list_range_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6863cc01239d47043165ecf302209054e1b619ce
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/65_66_list_range_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..27c6a4ad428c38f6e247ddec3fe1080dffd7e3c8
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant:  This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, it says -1 in the problem. Thank you for pointing it out!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5cf132b9132d3f054d0ec5c0310690394c737488
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. How would someone differentiate between those scenarios?
+Assistant: There is a standard response of -1 for this kind of function, but it is further defined in the problem given.
+User: Oh, I suppose I misread that part of the problem. I made the change and it works correctly now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad I could help, is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f46343b0931227f5535a67e1708ab113596b4cd0
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. I just reread the problem information and noticed it is supposed to return -1, but I'm unsure how to make sure that is the case. How can you ensure that -1 is what returns?
+Assistant: I believe you know the answer to this question based on how you described the activation of your function. Think about from initialization to `return`, what changes the value of `index`?
+	<alt>If the `if` condition in your `for` loop is never `True`, what would the value of `index` be?
+User: After initialization, it changes only when the value of the element at index `i` of the list `array` is equal to `value`.
+Assistant: And what does that tell you about the case where no element of `array` is equal versus when there is an equal element?
+User: That it will stay at the initialized value until an element of `array` is equal to `value`?
+Assistant: Correct. So how would you return -1 only when no element of `array` is equal to `value`?
+User: Oh! I would just use the initialization value, initializing `index` to -1, which would then return! I made the change, and it works as intended now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I am glad that I could help you. Is there anything else I could do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ced4c7015ed0c3bf6f6219811002ea26cf8334cb
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_67_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..55fbf2d97c46bef7552dd03f956458187da50ba2
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first part of the body of your function on it?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>What is your function supposed to do?
+User: Line 2.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: Line 2 sets the a variable called index to -1.
+Assistant: Let's look at the loop next, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: The loop starts on line 3.
+Assistant: Is there somewhere we could add a print statement to help us figure out what is going on?
+	<alt>Does everything look correct in the values for the loop?
+	<alt>What is the index of the first place in the array that we should check?
+User: We could add a print statement in the loop to check the values.
+Assistant: Where should we put it?
+	<alt>What should we print?
+User: We should add it after line 3.
+Assistant: What should we print?
+	<alt>What are the important values at that spot to help us understand what's wrong?
+	<alt>How would we print the index at that spot?
+	<alt>How would we print the value in the array at that index?
+User: We should print what's in the array at the current index.
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		print(array[i])
+5.		if(value == array[i]):
+6.			index = i
+7.	return index
+</code>
+Assistant: Compare what prints to the test cases, what do you notice?
+	<alt>Is it skipping any values?
+	<alt>What does this tell you about your loop?
+User: It's skipping the first value in all the arrays.
+Assistant: What does that tell you about your loop?
+	<alt>Can you use that to help you find the problem?
+	<alt>Do you have any new ideas about why the test cases are failing?
+User: My loop is wrong, it's not starting at the beginning.
+	<alt>I don't know.
+	<alt>I see! I need to start my loop at zero!
+Assistant: What value in your loop do you need to change to have your loop start in the right place?
+	<alt>What controls where a loop starts?
+	<alt>What are you setting i to?
+User: I need to change the first value in range. It's 1, and it should be 0!
+Assistant: Very good, try that. Does it work now?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: Yes! I removed the print statement and it works now! Thanks.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..708e87160928dd63de6194ffffad8683053baa07
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_68_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,92 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does "range" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does "range" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ad0546d69f04b8089be8b6e7319357406bb5440b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>What is the next thing your function needs to do?
+	<alt> Okay, let's move on to the next area, what does line 2 do?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: That's probably the loop.
+Assistant: Let's explore the loop a bit. Can you add some print statements to see what's happening?
+	<alt>What variable controls the loop?
+	<alt>What determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: I don't know, where would I put them?
+Assistant: What's a piece of information that would be useful to check what the loop is doing?
+	<alt>What are some important variables in the loop?
+	<alt>How could you check if the loop was starting at all?
+User: I need to know about i and index.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        print(i)
+5.        print(index)
+6.        if(array[i] == value):
+7.            index = i
+8.            break
+9.    return index
+</code>
+Assistant: What happens when you run it?
+User: Nothing prints.
+Assistant: What does that tell you about the loop?
+	<alt>What does that mean about the loop conditions?
+	<alt>Why would a statement not print?
+	<alt>Why would a loop not run?
+User: It means we don't start looping.
+Assistant: Why would a loop not run?
+	<alt>What does that mean about the loop conditions?
+User: There is something wrong with the loop conditions.
+Assistant: Let's check the loop conditions, what controls if the loop loops?
+	<alt>What number is the loop supposed to start on?
+	<alt>What number is the loop supposed to stop on?
+	<alt>What variable are we monitoring?
+	<alt>What are the parameters for range?
+User: It runs if i is between the last index minus 1 of the array and -1.
+Assistant: What is the default step for loops in Python?
+	<alt>What sets i?
+	<alt>Check the Python documentation, what direction do loops move through in Python?
+	<alt>What is the default increment for a range in Python?
+User: Oh! The default step is 1, and I want my number to decrease! It should be -1!
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1,-1,-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: Try it now, does it work?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92ba7af635e8a659031c04f4670efda2f404ded1
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, I suppose it would be simpler to just count upwards rather than downwards. I made that change and my code is working as expected now.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(0, len(array)-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c39a21aa8745f0b9d2b0e3f945325666f2ee6c05
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, but why would it work differently than a forward counting loop?
+Assistant: That is due to the function you are using for your `for` loop. You are using `range(start, end)` which only counts up by 1. Can you give me the form of `range(start, end, step)` you should be using?
+	<alt>Can you notice something awry with your use of the `range()` function as compared to how you've used it in previous assignments?
+User: So that is the difference! It would become `range(len(array)-1, -1, -1)`.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: That is entirely correct.
+	<alt>That is entirely correct! Can you explain why your version would be more efficient than a version that counts upwards, in some scenarios?
+User: Thank you for your help!
+Assistant: I'm glad that I could be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4efe32adfce0765c4fa1ca09a818307bf2af0d30
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/66_69_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,91 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/67_70_area_circle_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/67_70_area_circle_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1ee1401cc1a99f412d9dd47826680545134fd346
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/67_70_area_circle_conversational_thread_1.txt
@@ -0,0 +1,104 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the radius of the circle in the first test case that is passing?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: The radius of the first test case that is passing is one.
+Assistant: What is the radius of the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+User: It's 2.5.
+Assistant: What is the formula for calculating the area of a circle?
+	<alt>That's interesting, do you think there is anything significant about those numbers?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+User: It's Pi times the radius squared.
+Assistant: Let's think about those two different values for the radius. Do they act differently when they are squared?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+	<alt>What happens when you square 1?
+	<alt>What is the Python operator for squaring a number?
+User: Yes, 1 squared doesn't change it's still 1, and 2.5 squared is 6.25.
+	<alt>I think made a mistake on the squaring part.
+Assistant: Okay, since it works for 1 but not for 2.5, let's look at the code that does the squaring. Where is that code?
+	<alt>Does 1 have any special properties when you multiply it that might make it act differently?
+	<alt>What is the Python operator for squaring a number?
+User: That's on line 5.
+Assistant: What is the expression that is doing the squaring?
+	<alt>What operator does the squaring?
+User: It is the radius ** radius part.
+Assistant: What does it mean to square a number?
+	<alt>How do you raise a variable to a power?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>What does ** mean?
+User: It means you multiply it times itself.
+Assistant: Okay, so what does ** mean?
+	<alt>What does * mean?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: It means to raise to a power.
+	<alt>Oh! I'm raising the radius to itself instead of squaring it!
+Assistant: What should you be doing to the radius?
+	<alt>What does * mean?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: I'm supposed to multiply it by itself, not raise it to itself!
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius * radius
+</code>
+Assistant: Does it pass the test cases now?
+User: Yes! It passes, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/67_70_area_circle_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/67_70_area_circle_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..34f3649e3a644d508017d090c53ee81b915387bc
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/67_70_area_circle_socratic_dialogue.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..df5545a0a6f74caa3dad6309a70036bf3bfb7816
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What controls the loop?
+	<alt>What is the variable name for the iterator made on line 3?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: Range determines the number of times the loop runs.
+Assistant: Now let's look at line 4, how many times will that loop run?
+	<alt>What iterator is made on line 4?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: It will start at i and run until the end of the list.
+	<alt>I'm supposed to start at 0 not i!
+Assistant: Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: We should start at the beginning.
+Assistant: Is it always at the beginning of the list?
+	<alt>Should we start at 0?
+	<alt>Are there any combinations we are trying to skip?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+User: I see! I should have it start at 0, not i!
+Assistant: Does it run correctly now?
+User: Yes, it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b3ad9e28b9515a3dadc9f794e4da6fab5b07af13
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/69_81_get_combinations_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..767285588f80950b4f4809b7dae2c58bf5cd8dfe
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_conversational_thread_1.txt
@@ -0,0 +1,113 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+</bug_code>
+<bug_desc>
+The function prints the strings "N", "E", "S", "W", and "None". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print ("E")`, `print ("S")`, `print ("W")`, `print ("N")`, `print("None")` with the return statements `return "E"`, `return "S"`, `return "W"`, `return "N"`, `return "None"` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant:  I see. Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see? 
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+User: When I pass in `"N"` as `compass_point`. I see `"E"` printed in the terminal. But the value of 'store' is shown as `"None"`. I am confused as my code and `if` statement seem to be correct. 
+Assistant: Let's think about it differently. Suppose that you are using a vending machine and you already have inserted the money and selected the item you want. What will happen next?
+User: I should receive the item I want since the machine will vend it.
+Assistant: What is the equivalent of the machine vending into the dispenser in your code?
+User: I think the `print` statement is doing the job, isn't it?
+Assistant: Let's assume that the `print` statement is doing the job. How do you explain your program failing all the tests?
+	<alt>Let’s run your code again with the function call `store = print(turn_clockwise("N"))` then print `store` and observe the output in the terminal. What do you see?
+User: I think you might be right. The `print` is printing the correct values, but something is missing here.
+Assistant: So, does the `print` statement in Python return any values?
+    <alt>Let’s run your code again with the function call `store = print(turn_clockwise("N"))` then print `store` and observe the output in the terminal. What do you see?
+User: When I `google` it, it says "It doesn't return any value; returns None ."
+Assistant: Ok. So, what statement needs to be used to actually "return" the value you want from your function?
+	<alt>Let me think. Isn't it the `return` statement?
+Assistant: Do you know how to try it?
+User: I will just replace all `print` statements to `return`. Let me make the changes and try it.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return ("E")
+    elif compass_point == "E":
+        return ("S")
+    elif compass_point == "S":
+        return ("W")
+    elif compass_point == "W":
+        return ("N")
+    else:
+        return "None"
+
+</code>
+Assistant: Very good. Did you try your code again for all test cases?
+	<alt>Very good. Could you further simplify your code and follow best practices?
+User: It's working very well. Thank you so much!
+Assistant: Let's try it for the test case `turn_clockwise("rubbish")`. What do you observe?
+User: Ah. It's failing. Why is that?
+Assistant: Let's refer to the problem description. What value should be returned for the case `turn_clockwise("rubbish")`?
+    <alt>Let's open the Python terminal and try `turn_clockwise("rubbish") == "None"`. What do you observe?
+User: It should return `None`.
+    <alt>It should return `"None"`.
+Assistant: What value is being returned by your code?
+User: It's returning `"None"`.
+Assistant: Are `"None"` and `None` the same?
+    <alt>Let's open the Python terminal and try `None == "None"`. What do you observe?
+User: Ah! No. They are not the same. I think I need to change the return statement to `return None`.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return ("E")
+    elif compass_point == "E":
+        return ("S")
+    elif compass_point == "S":
+        return ("W")
+    elif compass_point == "W":
+        return ("N")
+    else:
+        return None
+
+</code>
+Assistant: Very good. Did you try your code again for all test cases?
+    <alt>Very good. Could you further simplify your code and follow best practices?
+User: It's working well now! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67401016d82b3953ff4378f067fe4e7dd281dc3d
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/6_33_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+</bug_code>
+<bug_desc>
+The function prints the strings "N", "E", "S", "W", and "None". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print ("E")`, `print ("S")`, `print ("W")`, `print ("N")`, `print("None")` with the return statements `return "E"`, `return "S"`, `return "W"`, `return "N"`, `return "None"` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `"N"` as `compass_point`. I see `"E"` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `"E"` in the terminal when I pass in `"N"` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `"E"` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+12. store = turn_clockwise("N")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return "E"
+    elif compass_point == "E":
+        return "S"
+    elif compass_point == "S":
+        return "W"
+    elif compass_point == "W":
+        return "N"
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..840288393e10f16e10f620ac51f6ec088497ff9a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_conversational_thread_1.txt
@@ -0,0 +1,86 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! I checked the documentation. I should be using `==` instead of `=` to check equality. Let me edit my code.
+	<alt>What operator should I use?
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good. Let me know if you have any other questions!
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..febe2da36bf25c4a8e945ea8caa8e83b73c7fd0a
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/6_34_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/74_77_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/74_77_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85bc61a327c01e6e185b9b9f5ef9845c41c43abb
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/74_77_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44f2431c86f5be0e8e24678162fcd131ce15a1d4
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Could we add some print statements to check the math?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+User: Yes, we could add some to see what's happening, but I don't know where to put them.
+	<alt>I could add one in the loop to see what's happening with the fee.
+Assistant: Okay, look at the code, what are some important variables in your calculations?
+	<alt>How would you print the number of years to see how far off the answer is from the test case?
+User: Well, years is important, and so is total fee and current fee.
+Assistant: Let's print those, where should we put the print statements?
+User: We could put them after line 7 in the loop.
+	<alt>I don't know.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        print(years)
+9.        print(total_fee)
+10.        print(current_fee)
+11.        total_fee = current_fee*(1.015**years)
+12.        years += 1
+13.
+14.    return years
+</code>
+Assistant: Look at the printed output, do you see anything odd?
+	<alt>Look at the printed output, what is the value for years?
+	<alt>Look at the printed output, why do you think it is repeating?
+User: It's doing zero years first. That isn't right, it's supposed to start at 1.
+Assistant: What line determines that?
+	<alt>Where is years incremented?
+User: Line 12.
+Assistant: What should you do with line 12?
+	<alt>Is that line where it should be?
+User: I see! I'll move it up above the calculation.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+Assistant: Try it now. Does it pass the test cases?
+User: Yes! It works, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8fea1e119b4c9f9003729bd7fc729f6a990d8527
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/74_78_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of "years" in line 8?
+	<alt>Where does "current_fee" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..43f4011cb3b5a7b2aaa2bcd163a50c9579514512
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_1.txt
@@ -0,0 +1,95 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: In line 2, `result` is initialized as an empty dictionary. Then for every (key, value) pair in the input list, line 4 adds the value to the list stored for that key in the dictionary. Finally, line 5 returns the result.
+Assistant: Are you sure that line 4 adds the `value` to the list for that key? Can you try running `d = {1: [7]}` then `d[1] = [5]` in the interpreter and observing what happens?
+	<alt>What exactly in line 4 makes you think that `[value]` is appended to `results[key]`?
+	<alt>Are you sure the value is added to the list? Line 4 shows an assignment statement. According to the Python documentation: https://docs.python.org/3/library/stdtypes.html#dict, if `d` is a dictionary, then the assignment `d[k] = v` only sets `d[k] to have the value `v`.			
+User: Ah, now I see. The old value `[7]` stored in the dictionary is overwritten by the new value `[5]`. Let me fix that so that it is appended to the current value... I did that, but now I get a `KeyError` message on line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        result[key] += [value]
+5.    return result
+
+</code>
+Assistant: I will give you a hint. Can you try running `d = {}` then `d[2] += [7]` in your interpreter window and tell me what happens?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+	<alt>Can you run your code on the input list `[(1, 1)]` and see what happens, then change your current code and in line 2 initialize `result = {1: 0}`, run it on the same list and see if you notice anything different?
+User: Ah, I see now. It raises a `KeyError` in the beginning when the dictionary does not have the key yet. I need to check first if `key` is in the dictionary. How do I do that?
+Assistant: Can you look at the documentation using: https://docs.python.org/3/library/stdtypes.html#dict. It also shows some nice examples. Let me know if you cannot find it.
+	<alt>Sure, to determine if a key `k` is in a dictionary `d`, you use the in operator as in `k in d`, which returns True if the key `k` is in the dictionary, False otherwise.
+User: I found it. Let me change my code to do that... It works now, thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You are welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8e7472f519273dfc7555ccccd4a5bbff3b1b2f12
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_conversational_thread_2.txt
@@ -0,0 +1,105 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+User: It will have value 2.
+Assistant: So the value 1 that was in `a` is lost and overwritten with the new value '2'. Now, looking at the second test example, let's consider what happens in line 4 when the `(key, value)` tuple has value `(2, 7)`. What will be stored in `result[2]` after executing line 4?
+User: `result[2]` will be equal to `[7]`.
+Assistant: Good. Now, at the next iteration, the tuple `(key, value)` will contain `(2, 5)`. What will `result[2]` become after executing the assignment in line 4?
+User: Oh, now I see. The previous value will be overwritten and `result[2]` is assigned `[5]`. This explains why for every repeating key, only the last value that appears with it is stored in the dictionary. This means that instead of assignment I need to do something else to append. Let me see... Well, I edited the code to append the value, but now I get a `KeyError` message.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+
+</code>
+Assistant: Can you change your current code and in line 2 initialize `result = {1: [0], 2: [0], 3: [0]}`, then run it on the first example and see if it works this time? If yes, what do you think is the problem?
+	<alt>Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: Now it works, it is able to append the values to what it already has for each key. I believe this means it does not work when the key is not in the dictionary.
+<code>
+1. def my_func(valList):
+2.    result = {1: [0], 2: [0], 3: [0]}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+6.
+7.print(my_func([(1, 1),(2, 2),(3, 3)]))
+
+</code>
+Assistant: That is correct. Can you change the code now so that whenever you append a value, the key is in the dictionary?
+	<alt>That is correct. Can you change the code so that it checks to see if the key is in the dictionary first and proceed correspondingly?
+User: I made it work! I added another loop where I initialize the dictionary with empty lists for each key that appears in the input list. It passed all tests. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for (key, _) in valList:
+4.        if not key in result:
+5.            result[key] = []
+6.    for key, value in valList:
+7.         result[key] += [value]
+8.    return result
+
+</code>
+Assistant: Great! You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..104ebb5cef5e5f4e088744d10a028ac8cb6c3199
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/7_35_integer_grouping_socratic_dialogue.txt
@@ -0,0 +1,122 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c7103d150a8fae622f5cff05c825a71aa2b3d3b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_1.txt
@@ -0,0 +1,98 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Probably before `my_func` so on line 3 I can insert my function definition for `yOf(x)`.
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. Are you planning to declare a function inside of another function?
+User: Yes. It's called a nested function! Let me edit my code. Ah I see that `x` is not defined, but I do define it on line 5.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: What is the scope of the parameters declared for the function `yOf`?
+	<alt>Where can `x` be used?
+User: Oh the scope is only line 6. I see it. I don't need `x` on line 6 since I am the `map` function takes care of passing each element in `range(len)` to `yOf` as the parameter `x`. Let me edit my code.
+<code>
+1. import random as rand
+2.rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: Good. Have you tried your code for all examples?
+User: Yes it does! Thank you for your help today!
+Assistant: You're welcome! Let me know if you have any other questions!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_2.txt b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0541576191cb148319873bc12fe44df30da7034b
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_conversational_thread_2.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: It seems to be the case. Not really sure though what to do though.
+Assistant: You wanted to learn more about the `map` function and how to use it in this problem. What is a good resource for you to find examples where the `map` function is being used?
+	<alt>Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Ah. Let me look at the Python documentation for the `map` function. After looking through some examples -- I see `lambda` being used with `map` quite often for example you can declare a list `numbers = [1, 2, 3, 4]` and then use the map function with `lambda` like this `result = map(lambda x: x + x, numbers)`.
+Assistant: Good find. Let's try it in the terminal and printing `result` as a list. What do you observe is being stored in `result`?
+User: I observe `[2, 4, 6, 8]` as the output.
+Assistant: Given that, what do you think the `lambda` did in the snippet here?
+	<alt>Can you describe what `lambda` does?
+User: It seemed to have summed up each element in `numbers` with itself so `[1 +  1,  2 + 2, 3 + 3, 4 + 4]` so I guess `x` in `lambda` represent each element in `numbers`.
+Assistant: Good. So looking at our programming exercises. Do you see a use for `lambda` in your code?
+	<alt>Good. Now, where can you use `lambda` in your programming exercise?
+	<alt>Good. Do you see a use of `lambda` in your `map` function call on line 5?
+User: Ah yes! I'll replace my messy function declaration with `lambda`. I think it works!
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    y = list(map(lambda x:  x * 6 + rand.randint(1, len),  range(len)))
+5.    return y
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes it does! Thank you! I learned more about `map` and `lambda` today!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/8_36_plot_function_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..870ad5e7b0b17adc1ce3dc2b559e19dbd05b7b75
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/8_36_plot_function_socratic_dialogue.txt
@@ -0,0 +1,147 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_conversational_thread_1.txt b/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aedba6fbbb1b6c8a599e81442bb390529b5d6c8c
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange `TypeError` in my helper function
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices
+Assistant: Ok, let's start with your helper function `det2d` then. What are you trying to do there?
+	<alt>Can you describe the inputs and outputs of your helper function?
+	<alt>How does your `det2d` function work with the `determinant` function? How do they interact with each other?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices that you're passing to the helper function `det2d`?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+User: I am using this function to calculate the determinant of a 2x2 submatrix. Then, I'll compute the determinant of the 3x3 matrix using those submatrix determinants.
+Assistant: Good. How can you verify that you are computing the determinant of a 2x2 matrix correctly?
+	<alt>What happens if you pass an array with the incorrect dimensions to this function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I looked through an online resource. My code matches the formula, and I tested it with some simple matrices. I use a 2x2 matrix represented as an array of arrays. The first index represents the row and the second index represents the column number. To access a specific value, I select a row array and then get the value from that array.
+Assistant: Ok. How can you verify that `matrix` is a 2x2 matrix?
+	<alt>What happens if you pass an array with the incorrect dimensions to the `det2d` function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I think that's the issue. It looks like I accidentally passed in my values as a 1D array. I'll add a set of brackets. It looks like `subm2` and `subm3` both have this issue
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+Assistant: It looks like your code works now!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_socratic_dialogue.txt b/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..58c862ac4e04af16882183dffb51173e9b65f10f
--- /dev/null
+++ b/data/raw/v2_sigcse/final_dataset/9_38_calculating_determinant_socratic_dialogue.txt
@@ -0,0 +1,67 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says "'int' object is not subscriptable" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/0_5_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/0_5_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..051ac2ae597cb75601ac0694350209c2e2f5a0d6
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/0_5_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/15_44_sequential_search_conversational_thread_1.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/15_44_sequential_search_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a2444fd8fc1fc32d185025275eff35f4a441991b
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/15_44_sequential_search_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/15_45_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/15_45_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e99e9d5280aee8185297b28e38a4c7cd8e99e12
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/15_45_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/16_46_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/16_46_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9596004c0330f7a64b8df111fd59d911a85f629a
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/16_46_substring_length_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/16_56_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/16_56_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76250045f41995ac9a4765999215119b64828ec3
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/16_56_substring_length_socratic_dialogue.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/24_29_factorial_conversational_thread_1.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/24_29_factorial_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f80d7e1c34a0763ae5139738f00046c6a73882c1
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/24_29_factorial_conversational_thread_1.txt
@@ -0,0 +1,78 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+	<alt>The first value assigned to `i` will be 1.
+	<alt>Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: That’s right. So, what happens when `i` is 0?
+	<alt>Correct. Given that `i` is 0, what happens when line 6 is evaluated?
+User: We go into the for loop and compute `fact`.
+	<alt>The value of `fact` will be 0 because `i` is 0. I think I got it `fact` will always be because of this. I need to change the `range` call to start at 1 instead of 0 and end at `n+1` instead of `n`.
+Assistant: That's right. Given that `i` is 0, what will the value of `fact` be after line 6 is executed?
+User: Aha! I see what is happening. `fact` is always 0 because `i` is 0 in the first iteration of the for loop. I need to change the range to start at 1 instead of 0 and end at `n+1` instead of `n`.  Thanks! I think I got it now.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: I am glad I could help. If you have any other questions, please let me know.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/4_26_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/4_26_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..573522c58359c29be4591852b5a1633261555e7d
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/4_26_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,93 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/58_59_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/58_59_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..93e8936d3618ce036b5ef9428f5357693c2c75ca
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/58_59_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/6_33_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/6_33_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67401016d82b3953ff4378f067fe4e7dd281dc3d
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/6_33_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+</bug_code>
+<bug_desc>
+The function prints the strings "N", "E", "S", "W", and "None". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print ("E")`, `print ("S")`, `print ("W")`, `print ("N")`, `print("None")` with the return statements `return "E"`, `return "S"`, `return "W"`, `return "N"`, `return "None"` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `"N"` as `compass_point`. I see `"E"` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `"E"` in the terminal when I pass in `"N"` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `"E"` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+12. store = turn_clockwise("N")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return "E"
+    elif compass_point == "E":
+        return "S"
+    elif compass_point == "S":
+        return "W"
+    elif compass_point == "W":
+        return "N"
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/6_34_turning_clockwise_conversational_thread_1.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/6_34_turning_clockwise_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..840288393e10f16e10f620ac51f6ec088497ff9a
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/6_34_turning_clockwise_conversational_thread_1.txt
@@ -0,0 +1,86 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! I checked the documentation. I should be using `==` instead of `=` to check equality. Let me edit my code.
+	<alt>What operator should I use?
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good. Let me know if you have any other questions!
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/manual_evaluation_dialogues/7_35_integer_grouping_conversational_thread_1.txt b/data/raw/v2_sigcse/manual_evaluation_dialogues/7_35_integer_grouping_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..43f4011cb3b5a7b2aaa2bcd163a50c9579514512
--- /dev/null
+++ b/data/raw/v2_sigcse/manual_evaluation_dialogues/7_35_integer_grouping_conversational_thread_1.txt
@@ -0,0 +1,95 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: In line 2, `result` is initialized as an empty dictionary. Then for every (key, value) pair in the input list, line 4 adds the value to the list stored for that key in the dictionary. Finally, line 5 returns the result.
+Assistant: Are you sure that line 4 adds the `value` to the list for that key? Can you try running `d = {1: [7]}` then `d[1] = [5]` in the interpreter and observing what happens?
+	<alt>What exactly in line 4 makes you think that `[value]` is appended to `results[key]`?
+	<alt>Are you sure the value is added to the list? Line 4 shows an assignment statement. According to the Python documentation: https://docs.python.org/3/library/stdtypes.html#dict, if `d` is a dictionary, then the assignment `d[k] = v` only sets `d[k] to have the value `v`.			
+User: Ah, now I see. The old value `[7]` stored in the dictionary is overwritten by the new value `[5]`. Let me fix that so that it is appended to the current value... I did that, but now I get a `KeyError` message on line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        result[key] += [value]
+5.    return result
+
+</code>
+Assistant: I will give you a hint. Can you try running `d = {}` then `d[2] += [7]` in your interpreter window and tell me what happens?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+	<alt>Can you run your code on the input list `[(1, 1)]` and see what happens, then change your current code and in line 2 initialize `result = {1: 0}`, run it on the same list and see if you notice anything different?
+User: Ah, I see now. It raises a `KeyError` in the beginning when the dictionary does not have the key yet. I need to check first if `key` is in the dictionary. How do I do that?
+Assistant: Can you look at the documentation using: https://docs.python.org/3/library/stdtypes.html#dict. It also shows some nice examples. Let me know if you cannot find it.
+	<alt>Sure, to determine if a key `k` is in a dictionary `d`, you use the in operator as in `k in d`, which returns True if the key `k` is in the dictionary, False otherwise.
+User: I found it. Let me change my code to do that... It works now, thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You are welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_1.txt b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a2444fd8fc1fc32d185025275eff35f4a441991b
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_2.txt b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ca3e5b177344b28bdac27a25a96d6bb2148a6737
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: Oh, it always returns a position where `seq[i] > x`. I think I need to also test for equality, let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_3.txt b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c01957c386144f83d5e40c90e7adc81514e78a49
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_44_sequential_search_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: Because the element at position 1 is equal to 5, and according to the problem description whenever the number is present in the input list we should return its position.
+Assistant: Good. Now, can you tell me what happens in your code for test example 1 when `i` takes the value 1? Start with line 3.
+	<alt>Good. Does your code ever test if the number `x` is present in the list?
+	<alt>Good. How can you determine, using code in Python, if a number `x` is present in a list `seq`?
+User: When `i` is 1, `seq[1]` is equal to 5. On line 3, since 5 is not less than 5, this means that line 4 is not executed, so we go back to line `2` where `i` is assigned the next value of 2. Ah, now I understand where the problem is,  I should have tested for equality too, let me do that ... It works now! Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_44_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/15_44_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..971311e0e39aa34053be4ca60d7da34fecf47353
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_44_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_45_sequential_search_conversational_thead_1.txt b/data/raw/v2_sigcse/testset/15_45_sequential_search_conversational_thead_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a70d26285fac100164974287447f4465eba01da
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_45_sequential_search_conversational_thead_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: Can you walk me through how your function handles some simple examples? For example, `search(5, [-1, 5, 8, 10, 12])`.
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: For that example, I get an output of 1. I first iterate through the elements in the list and check when the 5 is less than or equal to the current element, which happens at index 1. 
+	<alt>This just gives an output of 1
+Assistant: I see. What happens when you have a larger `x` value? Try `search(20, [-1, 5, 8, 10, 12])`.
+	<alt>I see. What about when your `x` is not less than or equal to any elements?
+	<alt>That seems right. How do you deal with negative numbers and numbers greater than all the list elements?
+	<alt>Good. Is there a case where your function might not return anything?
+User: For that, my code seems to return `None`. I use the same procedure and iterate through the list element. Oh, I see. Since 20 is greater than all the current list elements, I never get to the `return`
+Assistant: It looks like you just need to handle that other case then. What's a good answer to return when `x` is greater than all the existing elements?
+	<alt>Where would you want to insert an element that is larger than all the current ones?
+	<alt>What's a good place to insert 20 in the example I gave you?
+User: I think I should put it at the end of the list. I'll update the code and see if it works.
+<code>
+ def search(x, seq):
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Looks like it works! Let me know if you need more help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/15_45_sequential_search_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/15_45_sequential_search_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e99e9d5280aee8185297b28e38a4c7cd8e99e12
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/15_45_sequential_search_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_1.txt b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f80d7e1c34a0763ae5139738f00046c6a73882c1
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_1.txt
@@ -0,0 +1,78 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+	<alt>The first value assigned to `i` will be 1.
+	<alt>Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: That’s right. So, what happens when `i` is 0?
+	<alt>Correct. Given that `i` is 0, what happens when line 6 is evaluated?
+User: We go into the for loop and compute `fact`.
+	<alt>The value of `fact` will be 0 because `i` is 0. I think I got it `fact` will always be because of this. I need to change the `range` call to start at 1 instead of 0 and end at `n+1` instead of `n`.
+Assistant: That's right. Given that `i` is 0, what will the value of `fact` be after line 6 is executed?
+User: Aha! I see what is happening. `fact` is always 0 because `i` is 0 in the first iteration of the for loop. I need to change the range to start at 1 instead of 0 and end at `n+1` instead of `n`.  Thanks! I think I got it now.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: I am glad I could help. If you have any other questions, please let me know.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_2.txt b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1bd1ec69c73a91735f9a53d6e5cf316447e291fe
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_2.txt
@@ -0,0 +1,82 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: Oh! `i` is not declared before the for loop is created, maybe that causes this issue.
+Assistant: Let's examine what happens in this case. Open the Python shell and type `[i for i in range(1)]`. What do you see?
+	<alt>Let's investigate this further. Open the Python shell and type `for i in range(1): print(i)`. Press `Enter` twice to execute. What do you see?
+User: I see that `i` is not declared before the for loop is created. Yet the list comprehension `[i for i in range(1)]` returns `[0]`. So the issue is not with initializing `i` before the for loop.
+	<alt>I see a `[0]` in the list comprehension `[i for i in range(1)]`. So the issue is not with initializing `i` before the for loop but rather with the first value of `i` in the for loop. It is not 1 but 0 so `fact` will always be 0.
+Assistant: Good. Let's take a closer look. What is the first value of `i` in the for loop?
+	<alt>Correct. What do you notice about the first value of `i` in the for loop?
+	<alt>Notice that the value of `i` in the first iteration of the for loop is 0. How do you think this affects the value of `fact`?
+User: I see. The value of `i` in the first iteration of the for loop is 0. So `fact` will always be 0 because the first value of `fact = 1 * 0` is 0. Then, `fact` will be `0 * 1` in the second iteration of the for loop, and so on.
+Assistant: Good! How can we fix this issue?
+	<alt>Good. Now, what does a correct factorial sequence look like for `n=4`?
+User: I think we can fix this by changing the range of `i` to `range(1, n + 1)`.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(1, n + 1):
+6.                fact = fact * i
+7.        return fact
+</code>
+Assistant: Good! Let's test it. What is the factorial of 5?
+User: The factorial of 5 is 120. It works!
+Assistant: I am glad I could help. If you have any other questions, feel free to ask me.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_3.txt b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..586ad2f28814182968cc2c41d80e0399031ed181
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/24_29_factorial_conversational_thread_3.txt
@@ -0,0 +1,166 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of n it fails and what values it returns in those cases?
+User: For n = 1 or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because `range` by default starts at 0.
+	<alt>Oh! `i` is not declared before the for loop is created maybe that causes this issue.
+Assistant: Are you sure about that? Can you verify that the first value assigned to `i` is 1?
+User: OK, let me print its value at each iteration. I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>OK, let me check in the Python documentation what range does. I see, the first value is 0, not 1!
+Assistant: How can you fix the code so that in the first iteration fact is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+User: I don’t know, can you help?
+	<alt>I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+	<alt>I can change to `range(1,  n + 1)` so that it starts iterating at 1.
+	<alt>I can change to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change to `range(n) + 1`, so that the first value is 0 + 1.
+Assistant: How can you ensure that in the first iteration `fact` is multiplied with 1?
+User: I can add a line that sets `i` to 1 before the for loop.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+User: Hm... It still returns 0.
+	<alt>It still returns 0. I think I need to change the for loop.
+Assistant: Do you know why it still returns 0?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>Let’s look at the terminal output. What value is `i` on line 7 when being printed?
+User: I think the problem is that `i` is still 0 in the first iteration of the for loop. It still prints 0. I think I can add an `if` statement to the for loop that checks if `i` is 0 and if so, sets it to 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(n):
+7.                if i == 0:
+8.                    i = 1
+9.                  print(i)
+10.                fact = fact * i
+11.        return fact
+
+</code>
+	<alt>It still prints 0. I think I need to make a change in the for loop.
+	<alt>I don't know. Can you help?
+Assistant: Let’s see if that works. Can you try it for `n = 1`?
+	<alt>Ok! Let's run the code for `n = 2` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Good. Can you try it for `n = 2` and `n = 3`?
+	<alt>Ok! Let's run the code for `n = 3` and see what happens.
+	<alt>Did you try it for `n >=2`?
+User: Hm... it's incorrect for both `n = 2` and `n = 3`. I think I need to multiply `fact` starting from 1, then 2, then 3 instead of what I'm doing now 1, then 1, then 2.
+Assistant: Good. How can you change the for loop so that the iterator variable `i` is not equal to 0 in the first iteration of the for loop?
+	<alt>What do you think `range(n)` is doing to `i`?
+	<alt>How can you edit the code so that `fact` is multiplied with 1, then 2, then 3?
+	<alt>What do you think you can do to make sure that `fact` is multiplied with 1, then 2, then 3?
+	<alt>How can you change the for loop so that the iterator variable `i` iterates starting from 1?
+User: I think I am going to change `range` to `range(1, n + 1)` so that it starts iterating at 1.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                print(i)
+8.                fact = fact * i
+9.        return fact
+
+</code>
+	<alt>I think I am going to change `range` to `range(1, n)` so that it starts iterating at 1.
+	<alt>I think I am going to change `range` to `range(n) + 1` so that the first value is 0 + 1.
+Assistant: Sounds good, let's try it for `n = 2` and `n = 3` again.
+	<alt>Did you try it again for `n >=2`?
+User: It works! Thank you for your help!
+Assistant: Awesome. Don't forget to remove the print statement before you submit your code.
+	<alt>Good! I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you! I will do that.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        i = 1
+6.        for i in range(1, n + 1):
+7.                fact = fact * i
+8.        return fact
+</code>
+Assistant: I’m glad I could help. If you have any other questions, feel free to ask me again.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/24_29_factorial_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/24_29_factorial_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7df61e9d91ff71c70cffa036b44cee77c5e49f14
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/24_29_factorial_socratic_dialogue.txt
@@ -0,0 +1,135 @@
+<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/6_33_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/6_33_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67401016d82b3953ff4378f067fe4e7dd281dc3d
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/6_33_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+</bug_code>
+<bug_desc>
+The function prints the strings "N", "E", "S", "W", and "None". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print ("E")`, `print ("S")`, `print ("W")`, `print ("N")`, `print("None")` with the return statements `return "E"`, `return "S"`, `return "W"`, `return "N"`, `return "None"` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `"N"` as `compass_point`. I see `"E"` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `"E"` in the terminal when I pass in `"N"` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise("N")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise("N")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `"E"` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        print ("E")
+4.    elif compass_point == "E":
+5.        print ("S")
+6.    elif compass_point == "S":
+7.        print ("W")
+8.    elif compass_point == "W":
+9.        print ("N")
+10.    else:
+11.        print ("None")
+12. store = turn_clockwise("N")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == "N":
+        return "E"
+    elif compass_point == "E":
+        return "S"
+    elif compass_point == "S":
+        return "W"
+    elif compass_point == "W":
+        return "N"
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/6_34_turning_clockwise_conversational_thread_1.txt b/data/raw/v2_sigcse/testset/6_34_turning_clockwise_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..840288393e10f16e10f620ac51f6ec088497ff9a
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/6_34_turning_clockwise_conversational_thread_1.txt
@@ -0,0 +1,86 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! I checked the documentation. I should be using `==` instead of `=` to check equality. Let me edit my code.
+	<alt>What operator should I use?
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good. Let me know if you have any other questions!
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/6_34_turning_clockwise_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/6_34_turning_clockwise_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..febe2da36bf25c4a8e945ea8caa8e83b73c7fd0a
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/6_34_turning_clockwise_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise("N") => "E"
+turn_clockwise("W") => "N"
+turn_clockwise("S") => "W"
+turn_clockwise("E") => "S"
+turn_clockwise(42) => None
+turn_clockwise("rubbish") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = "N":
+3.        return "E"
+4.    elif compass_point = "E":
+5.        return "S"
+6.    elif compass_point = "S":
+7.        return "W"
+8.    elif compass_point = "W":
+9.        return "N"
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise("N") == "E"
+assert turn_clockwise("W") == "N" 
+assert turn_clockwise("S") == "W"
+assert turn_clockwise("E") == "S"
+assert turn_clockwise(42) == None
+assert turn_clockwise("rubbish") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value "N" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says "SyntaxError: invalid syntax"
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to "N"
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value "N" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = "N"`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == "N":
+3.        return "E"
+4.    elif compass_point == "E":
+5.        return "S"
+6.    elif compass_point == "S":
+7.        return "W"
+8.    elif compass_point == "W":
+9.        return "N"
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_1.txt b/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..43f4011cb3b5a7b2aaa2bcd163a50c9579514512
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_1.txt
@@ -0,0 +1,95 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: In line 2, `result` is initialized as an empty dictionary. Then for every (key, value) pair in the input list, line 4 adds the value to the list stored for that key in the dictionary. Finally, line 5 returns the result.
+Assistant: Are you sure that line 4 adds the `value` to the list for that key? Can you try running `d = {1: [7]}` then `d[1] = [5]` in the interpreter and observing what happens?
+	<alt>What exactly in line 4 makes you think that `[value]` is appended to `results[key]`?
+	<alt>Are you sure the value is added to the list? Line 4 shows an assignment statement. According to the Python documentation: https://docs.python.org/3/library/stdtypes.html#dict, if `d` is a dictionary, then the assignment `d[k] = v` only sets `d[k] to have the value `v`.			
+User: Ah, now I see. The old value `[7]` stored in the dictionary is overwritten by the new value `[5]`. Let me fix that so that it is appended to the current value... I did that, but now I get a `KeyError` message on line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        result[key] += [value]
+5.    return result
+
+</code>
+Assistant: I will give you a hint. Can you try running `d = {}` then `d[2] += [7]` in your interpreter window and tell me what happens?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+	<alt>Can you run your code on the input list `[(1, 1)]` and see what happens, then change your current code and in line 2 initialize `result = {1: 0}`, run it on the same list and see if you notice anything different?
+User: Ah, I see now. It raises a `KeyError` in the beginning when the dictionary does not have the key yet. I need to check first if `key` is in the dictionary. How do I do that?
+Assistant: Can you look at the documentation using: https://docs.python.org/3/library/stdtypes.html#dict. It also shows some nice examples. Let me know if you cannot find it.
+	<alt>Sure, to determine if a key `k` is in a dictionary `d`, you use the in operator as in `k in d`, which returns True if the key `k` is in the dictionary, False otherwise.
+User: I found it. Let me change my code to do that... It works now, thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You are welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_2.txt b/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8e7472f519273dfc7555ccccd4a5bbff3b1b2f12
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/7_35_integer_grouping_conversational_thread_2.txt
@@ -0,0 +1,105 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+User: It will have value 2.
+Assistant: So the value 1 that was in `a` is lost and overwritten with the new value '2'. Now, looking at the second test example, let's consider what happens in line 4 when the `(key, value)` tuple has value `(2, 7)`. What will be stored in `result[2]` after executing line 4?
+User: `result[2]` will be equal to `[7]`.
+Assistant: Good. Now, at the next iteration, the tuple `(key, value)` will contain `(2, 5)`. What will `result[2]` become after executing the assignment in line 4?
+User: Oh, now I see. The previous value will be overwritten and `result[2]` is assigned `[5]`. This explains why for every repeating key, only the last value that appears with it is stored in the dictionary. This means that instead of assignment I need to do something else to append. Let me see... Well, I edited the code to append the value, but now I get a `KeyError` message.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+
+</code>
+Assistant: Can you change your current code and in line 2 initialize `result = {1: [0], 2: [0], 3: [0]}`, then run it on the first example and see if it works this time? If yes, what do you think is the problem?
+	<alt>Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: Now it works, it is able to append the values to what it already has for each key. I believe this means it does not work when the key is not in the dictionary.
+<code>
+1. def my_func(valList):
+2.    result = {1: [0], 2: [0], 3: [0]}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.    return result
+6.
+7.print(my_func([(1, 1),(2, 2),(3, 3)]))
+
+</code>
+Assistant: That is correct. Can you change the code now so that whenever you append a value, the key is in the dictionary?
+	<alt>That is correct. Can you change the code so that it checks to see if the key is in the dictionary first and proceed correspondingly?
+User: I made it work! I added another loop where I initialize the dictionary with empty lists for each key that appears in the input list. It passed all tests. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for (key, _) in valList:
+4.        if not key in result:
+5.            result[key] = []
+6.    for key, value in valList:
+7.         result[key] += [value]
+8.    return result
+
+</code>
+Assistant: Great! You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/testset/7_35_integer_grouping_socratic_dialogue.txt b/data/raw/v2_sigcse/testset/7_35_integer_grouping_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..104ebb5cef5e5f4e088744d10a028ac8cb6c3199
--- /dev/null
+++ b/data/raw/v2_sigcse/testset/7_35_integer_grouping_socratic_dialogue.txt
@@ -0,0 +1,122 @@
+<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..69cd2f3befba3bf4fbf9ec6883999b4b44ae4da2
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,119 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student has a misconception about for loop ranges. The student also struggles to explain their code. The student knows how to use the debugger.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I can use the debugger perhaps.
+	<alt>I can add print statements.
+	<alt>I'm not really sure can you suggest a way?
+Assistant: Let's first examine the values of `i`. How many times in total does the for loop iterate?
+User: Using the debugger I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks good! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..065bb32ed9acd4e0e41fe8295da0602690554d9a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,141 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to `0` not `1`? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time and remove the print statement. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks correct! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3e0a27c8151d319d456c91146ba16ef7f1425e5e
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_0_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,199 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0, not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that. 
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(n)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that `i` is always 5 when `n` is 5. That doesn't make sense.
+Assistant: Are you sure that you are looking at the values of `i`? Examine line 12.
+	<alt>What variable are you printing on line 12?
+User: Oh whoops! Let me fix that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the terminal output. How many times does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5, and the values of `n` range from 0 to 4 or `n - 1`.
+Assistant: Good. Can you identify other variables that might be important for us to track to identify the issue?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>What would happen to the returned Fibonacci term if the for loop iterates 6 times?
+User: I think it would be good to track the variables `a` and `b` since I return `b` in the end and `a` is used to compute `b`.
+Assistant: Good. What do you think would be a good way for us to track the values of `a` and `b`?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: I think I can add a print statement for these variables inside the for loop!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(f"a: {a}\tb: {b}\t i: {i}")
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good. What do you observe about the values of `b` as the loop iterates?
+User: Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the last value of `b`?
+User: Oh! It's 8 which is what I am returning instead of 5! But why is that?
+Assistant: How was `b` computed in the final iteration of the for loop?
+User: I think `b` was 5 and `a` was 3 so  `b = 3 + 5` which is 8. Not sure how to get it to return 5 though.
+Assistant: What would happen to the returned Fibonacci sequence if the for loop iterates 6 times?
+	<alt>Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: Hm. I think it would `b = 5 + 8` which is 13 the next number in the Fibonacci sequence.
+Assistant: Do you notice a relationship between the number of for loop iterations and the Fibonacci term returned?
+User: Yes! I do think that the more the loop iterates the larger the Fibonacci term is returned. Maybe my for loop is iterating more than it should.
+Assistant: Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code and remove my print statement.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all is correct thank you so much!
+Assistant: You are welcome. Let me know if I can help with anything else!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_0_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/train/0_0_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1a9b5b0ef4344a852e7725224c599a5f6b336ecd
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_0_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,158 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
diff --git a/data/raw/v2_sigcse/train/0_2_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/train/0_2_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6b2b5d9ebca861c02068de0a199821dfb9f52a44
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_2_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,91 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>Hello! I need help on this my code is failing the first test case.
+Assistant: Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Can you walk me through your code step by step given that `n` is 0?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+	<alt>Can you describe the issue you are facing? Is your code failing any test cases?
+	<alt>Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: Hm... I've never seen assignment being done like this before. I presume it would be a compiler error?
+	<alt>I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Let's verify that. Can you open a Python terminal and type in `x = 0` then on a new line `y = 1 if x < 0 else 0`. What do you observe?
+User: Ah. It works! I learned something new today.
+Assistant: What do you think the value of `y` is?
+User: I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Good. Let's look at your `fibonacci` function. Given that `n` is 0. Can you walk me through your code step by step?
+	<alt>Let's verify that. Can you print `y`? What do you observe?
+	<alt>Good. Let's look at your `fibonacci` function. Given that `n` is 0. What does the if statement on line 2 evaluate to?
+	<alt>Good. Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: On line 2 `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good. Did you try running your code through all the test cases?
+User: Yes. Thank you very much for your help!
+Assistant: You're welcome.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_2_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/train/0_2_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..692135c1808168d758578b95b634ed96cd7e3ff3
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_2_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..75350a91e85f7f7fef581e7c82b70b7b582ad5d2
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,79 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: The previous two positions.
+	<alt>The numbers at positions n - 1 and n - 2.
+	<alt>The numbers at positions n - 1 and n - 2. Ah, now I see, I made a mistake on line 7, I used the wrong positions there. Let me fix it... It works now, thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n-1) + fibonacci(n-2)
+
+</code>
+Assistant: Correct. Since the current position is `n`, what are the previous two positions?
+	<alt>That is correct. Looking at your code, does it really add the Fibonacci numbers at the previous two positions?
+User: Ah, now I see what the problem is. The code on line 7 adds the number at the current position, instead of positions `n - 1` and `n - 2`. Let me fix that... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome, happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_2.txt b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76f4d0a06fb8486c07330eb167c986744f0e45a4
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_2.txt
@@ -0,0 +1,84 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: Can you explain what infinite recursion means?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: Infinite recursion means that the function calls itself without ever stopping.
+	<alt>I am not sure, can you explain infinite recursion to me?
+Assistant: Correct. Where in the code does the function call itself?
+	<alt>Good. Given that the problem is caused by the function calling itself forever, where in the code do you think the problem is?
+User: It is on line 7.
+Assistant: Correct. There are two recursive calls there, can you figure out which of them leads to infinite recursion?
+	<alt>Correct. So, when the function is called as `fibonacci(n)`, if it gets to line 7 it calls `fibonacci(n)` again, and if that is completed it then calls `fibonacci(n - 1)`. Do you see why this leads to infinite recursion?
+User: Ah, I see. It is the call to `fibonacci(n)`, because `fibonacci(n)`calls `fibonacci(n)`which will again call `fibonacci(n)`, forever.
+	<alt>Ah, I see, it is the call to `fibonacci(n)`. I made a mistake, I should have called fibonacci for `n - 1` and `n - 2`. Let me do that ... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+Assistant: Good! That means the code on line 7 is not correct. Can you look at the problem description to see how the Fibonacci number at position `n` needs to be computed and fix your code?
+	<alt>Good! Can you fix the code in line 7 so that it implements what is in the problem description?
+User: Ah, I see now, the previous two numbers are at positions `n - 1` and `n - 2`. Let me fix that... it works now! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_3.txt b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..465f2800ce958f878af1ebf2a69e8821aae7a0ea
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_5_fibonacci_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>Can you explain what infinite recursion means?
+User: We get the Fibonacci number for `n + 1`. Ah, I see what the problem is, I used the wrong inputs in the recursive calls. Let me fix that... it works, it passes all the tests now. Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+	<alt>We get the Fibonacci number for `n + 1`.
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_5_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/train/0_5_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..051ac2ae597cb75601ac0694350209c2e2f5a0d6
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_5_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_6_fibonacci_conversational_thread_1.txt b/data/raw/v2_sigcse/train/0_6_fibonacci_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..bc33e1d17632dbf5f59182fb9124d55463546161
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_6_fibonacci_conversational_thread_1.txt
@@ -0,0 +1,82 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: It says to return 1 when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: So will it return `1` when `n` is only equal to `1`?
+	<alt>Will `n` ever be `1` and `2` at the same time?
+User: No, it looks like it will return `1` only when `n` is `1` and `2`.
+Assistant: Will that ever happen?
+	<alt>Is that what you are supposed to do according to the instructions?
+User: No, `n` can be either `1` or `2`, but never both `1` and `2`.
+Assistant: Correct! How do you check if `n` is `1` or `2` instead of both `1` and `2`?
+User: Will it look like this?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: Correct, do you now see the difference between `or` and `and`?
+User: I see it now, `and` evaluates to true only when both cases are correct. But `or` evaluates to true if either of the cases are correct. Thank you for your help!
+Assistant: That is right, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/0_6_fibonacci_socratic_dialogue.txt b/data/raw/v2_sigcse/train/0_6_fibonacci_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d2154b30aa8f17ece8888c2a5dbedc8c29175f0
--- /dev/null
+++ b/data/raw/v2_sigcse/train/0_6_fibonacci_socratic_dialogue.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/10_39_xnglxsh_conversational_thread_1.txt b/data/raw/v2_sigcse/train/10_39_xnglxsh_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c244e010918d5f3c22614c505ad804ef4eb67c6a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/10_39_xnglxsh_conversational_thread_1.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+	<alt>If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+Assistant: Let's test each of these separately. How can you check whether the methods are being called?
+User: One way I could check this is by adding `print` statements right before the methods to make sure I'm reaching those parts of the code. It looks like I'm reaching each part, but the sentence isn't changing. I think I'm not using these methods properly.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           print("here1", sen)
+           sen.replace(i, "x")
+      else:
+           print("here2", sen)
+           sen.replace(i, "X")
+  print("here3", sen)
+  sen.swapcase()
+  return sen
+
+</code>
+Assistant: Is there an easy way to modify your code to verify whether your code is modifying the original string?
+     <alt>What makes you think that you are using the methods incorrectly?
+     <alt>Have you considered printing the output of the method calls to see if they are changing the string, for example, `print(sen.replace(i, "x"))`?
+     <alt>Have you considered assigning the output of the method calls to a variable?
+     <alt>Where can you learn more about how `.replace()` and `.swapcase()` work and how they are used?
+User: Hm, I guess I can just assign `sen` the output of the method calls, in case they don't do in-place changes. That works!
+     <alt>I could also just print the output of the method calls to see if they are changing the string.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: Great! let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/10_39_xnglxsh_socratic_dialogue.txt b/data/raw/v2_sigcse/train/10_39_xnglxsh_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9160d401c193a67ea8b57aa8e809699d0854c3d7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/10_39_xnglxsh_socratic_dialogue.txt
@@ -0,0 +1,75 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = "To"` and then `sen.replace("o", "X")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = "English"` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace("o", "X")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_1.txt b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..67d4e9361aaa605be0735a6ed1c76f8dae5d0cb6
--- /dev/null
+++ b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: Ah I see the problem now. I should use `==` instead of equals to check for equality. Let me edit my code.
+	<alt>I am trying to check if `rev_string` is equal to `string`.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good! Does it pass all the test cases now?
+User: Yes it does! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_2.txt b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ccb927b1d35b709abe5b5b8d8ba6901a41f79114
--- /dev/null
+++ b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_2.txt
@@ -0,0 +1,94 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't added yet?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_3.txt b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..05f680bfee5168ebe0d451dbcd61e748705c8fe5
--- /dev/null
+++ b/data/raw/v2_sigcse/train/11_40_palindrome_conversational_thread_3.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't completed yet?
+	<alt>I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/11_40_palindrome_socratic_dialogue.txt b/data/raw/v2_sigcse/train/11_40_palindrome_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..608c84efc580ebe5d8951024b6e71480399a0b03
--- /dev/null
+++ b/data/raw/v2_sigcse/train/11_40_palindrome_socratic_dialogue.txt
@@ -0,0 +1,73 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/12_41_reversing_a_list_conversational_thread_1.txt b/data/raw/v2_sigcse/train/12_41_reversing_a_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9e45c7683bf8e36d8dacc6f4354183ee3d9908e6
--- /dev/null
+++ b/data/raw/v2_sigcse/train/12_41_reversing_a_list_conversational_thread_1.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: The `[-1:]` slicing operator should return a list in reverse order.
+	<alt>I think it should return a list in reverse order but it's returning the last element of the list instead.
+Assistant: What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Let's run your code through all the test cases. Do you notice a pattern in your function's outputs?
+	<alt>Let's open the terminal and run `[1, 2, 3][-1:]`. What do you observe?
+	<alt>Let's start with a simpler problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+User: It returns `[3]` instead of `[3, 2, 1]`. Hm... it seems to be returning the last element of the list instead of the whole list in reverse order.
+Assistant: Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+User: For an input list `a`, we can get every other element by using `a[::2]`. So `a[::2]` should return `[1, 3]`.
+Assistant: Good. Given that `[-1:]` returns the last element in the list, how do we combine using `::` with `[-1:]` to get every element in reverse order?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Good. `::2` gives us every other element and `[-1:]` gives us the last element. How can we get every element in reverse order?
+User: Oh, I see. We can just get every element of the list in increments of -1. So `a[::-1]`. I'll update my code. It looks like it's working now
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/12_41_reversing_a_list_socratic_dialogue.txt b/data/raw/v2_sigcse/train/12_41_reversing_a_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..071edd0259455dc702e145d33c8c244d2bd6d83d
--- /dev/null
+++ b/data/raw/v2_sigcse/train/12_41_reversing_a_list_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/13_42_limit_conversational_thread_1.txt b/data/raw/v2_sigcse/train/13_42_limit_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..111e617adc183b4a313c4a6e21420cebbf15236a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/13_42_limit_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many times will the for loop execute?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>Is that the list that you want to loop through?
+User: It will be executed the length of the `lst2` times.
+	<alt>It will execute 0 times because `lst2` is empty.
+	<alt>How do I find that out?
+Assistant: What is the length of `lst2`?
+	<alt>Is `lst2` the list that you want to loop over?
+User: It is 0, so does that mean the for loop is never executed?
+	<alt>It is 0, should I loop over `lst` instead?
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+	<alt>Yes.
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/13_42_limit_socratic_dialogue.txt b/data/raw/v2_sigcse/train/13_42_limit_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fb83ca8d767fb22839d3d9cb4f928dc75874b376
--- /dev/null
+++ b/data/raw/v2_sigcse/train/13_42_limit_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/14_43_used_twice_conversational_thread_1.txt b/data/raw/v2_sigcse/train/14_43_used_twice_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cbbcd5dfa285b7355d54c0d8e3eae61cde9c4fd1
--- /dev/null
+++ b/data/raw/v2_sigcse/train/14_43_used_twice_conversational_thread_1.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! This code isn't working. Can you help?
+Assistant: Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: Well, boolean and Strings are different data types. Booleans have a true or false value, and Strings are just written words.
+	<alt>a boolean true is written like `bool = True`, whereas a String variable is written as str = "True."
+	<alt>I don't think there is a difference. I think both boolean "true" and String "true" looks the same when you write the code. For example, str = true and bool = true.
+Assistant: Let's try an example. How would you declare a string variable "str" and initialize it to the value "true?"
+	<alt>What are the two possible values of a boolean variable in Python?
+User: String str = "true";
+	<alt>Wouldn't you want to use a boolean variable for that instead?
+	<alt>String str = true;
+	<alt>str = true
+	<alt>String str = True;
+Assistant: That's right! Now, how would you declare a boolean variable `bool` and initialize it to false?
+User: boolean bool = false;
+	<alt>boolean bool = False;
+	<alt>boolean bool = "False";
+	<alt>I don't see that we are using boolean variables in the code.
+Assistant: Programming languages are very sensitive to syntax. For example, String variables require the use of quotations around their input. Can you think of any similar constraints to boolean inputs?
+	<alt>Try looking at the Python documentation. Can you find the section where they describe the use of Boolean variables? How does it compare to what you wrote here?
+	<alt>Let's try that in the Python terminal. What happens when you type `bool = false`?
+User: Oh, I see. I was writing `bool = true` when I should have been writing `bool = True`. I am missing a capitalization.
+	<alt>I should be using 0 and 1 instead of false and true.
+	<alt>I can't think of any constraints.
+Assistant: Good! Can you find where you made this mistake in your code?
+	<alt>How can you edit your code to fix this error?
+User: Yes, I found it. I'm going to show you the changed code now.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Good work! Looks like you did it.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/14_43_used_twice_socratic_dialogue.txt b/data/raw/v2_sigcse/train/14_43_used_twice_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fed235c9f380c3072884cf6a17a1c2bd4164c248
--- /dev/null
+++ b/data/raw/v2_sigcse/train/14_43_used_twice_socratic_dialogue.txt
@@ -0,0 +1,83 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = "True"
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d78c074069ad55788fb28f108ae631fa1663e622
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_1.txt
@@ -0,0 +1,108 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+	<alt>That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+User: OK. I think I need to look at the substring that starts at the last value of `start` and ends at the end of the string. Let me do that... It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+	<alt>Not sure how to do that, can you help?
+Assistant: That's great! Glad I could help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7b4e3cbce5f3bf61db44e521928097c52f7c4e67
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_2.txt
@@ -0,0 +1,110 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+	<alt>I don't know, how can I find that?
+Assistant: Great. Now that you know where it starts and where it ends, can you add code that extracts this substring and looks at its length too?
+User: I did that, and it works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f4b15267cf56ade259b3d6b9093f52cf9c9cd408
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_46_substring_length_conversational_thread_3.txt
@@ -0,0 +1,117 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I don't know, how can I find that?
+	<alt>I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+Assistant: If you look at the test example, 'dabra' appears right after the last occurrence of `ca`. Which variable in your code computes that position?
+	<alt>Can you tell me what the variable `start` is supposed to do and how it is computed?
+	<alt>Which variable in your code computes the index right after the last occurrence of the string `t`?
+User: So it must be the sum between where `ca` starts, which is in `pos` and the length of `ca`, that is what `start` does.
+Assistant: Correct. Now, where does 'dabra' end?
+	<alt>Correct. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: It ends at the end of the input string `s`.
+Assistant: Correct. So it starts at the last value of `start` and ends at `len(s)`. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: Ok, I did that and it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: Great, glad that I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_46_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/train/16_46_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9596004c0330f7a64b8df111fd59d911a85f629a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_46_substring_length_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_1.txt b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b4d1dfe8e505d610d732f5f7749b018450ac978
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: Ah, I see the problem, I forgot to change `start` inside the while loop. Let me do that ... it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: Great, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_2.txt b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e826944d56d97aabaa32ccf77a174b32cd58c356
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_2.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: First, `start` is initialized with 0. Then `pos` becomes 4, then ... ah, I forgot to update `start` inside the loop. Let me try to fix that ... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_3.txt b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c5955c5511673f2c69c5e249c9a5c5f8d3f3d8c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_56_substring_length_conversational_thread_3.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Does `start` ever change inside the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+User: Ah, it doesn't! It stays equal to 0, which means that `pos` does not change either. Let me fix that... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/16_56_substring_length_socratic_dialogue.txt b/data/raw/v2_sigcse/train/16_56_substring_length_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..76250045f41995ac9a4765999215119b64828ec3
--- /dev/null
+++ b/data/raw/v2_sigcse/train/16_56_substring_length_socratic_dialogue.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/17_47_topk_socratic_dialogue.txt b/data/raw/v2_sigcse/train/17_47_topk_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..374ed2d7231845cd77b9b540ce4c48d6a31ba5e9
--- /dev/null
+++ b/data/raw/v2_sigcse/train/17_47_topk_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/17_47_topk_socratic_thread_1.txt b/data/raw/v2_sigcse/train/17_47_topk_socratic_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3bd99c0f8e2ed5f3d3602d10ef28c5b04aafc241
--- /dev/null
+++ b/data/raw/v2_sigcse/train/17_47_topk_socratic_thread_1.txt
@@ -0,0 +1,76 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0,1]`, It seems to work, but `[1]`, it throws an error. 
+	<alt>Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: What does that tell you about the `.pop()` method?
+	<alt>What conclusion can you draw from examining the output of the `.pop()` method?
+User: I think it is removing by index and not value, maybe I should use a different deletion method. I'll try `.remove()`. It works!
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Glad to help
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/18_48_password_validator_conversational_thread_1.txt b/data/raw/v2_sigcse/train/18_48_password_validator_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5798a2092a147a9cc0146ccecbe51b60f43a879b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/18_48_password_validator_conversational_thread_1.txt
@@ -0,0 +1,89 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+	<alt>Hello. I need help with my code.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist. I wonder if this relates to adding a new password.
+Assistant: Good hypothesis. Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Certainly. So when `menu_choice` is `"a"` we go to line 8, we check if  `password` is already stored in `passwords_dict`. If so, the function returns "Password already exists!" otherwise it returns "Password added!".
+Assistant: Good. Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>According to the problem description, what do you need to do with `password` if `menu_choice` is `"a"`?
+User: Oh. It is supposed to add `password` to `passwords_dict` and then return "Password added!". Let me edit my code.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Have you tried your code on all the example cases?
+User: Yes. It works correctly! Thank you for helping me today!
+Assistant: You're welcome. Let me know if I can be of any further assistance in the future.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/18_48_password_validator_socratic_dialogue.txt b/data/raw/v2_sigcse/train/18_48_password_validator_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0dbda996e22db730584f590a074dd393d85e15db
--- /dev/null
+++ b/data/raw/v2_sigcse/train/18_48_password_validator_socratic_dialogue.txt
@@ -0,0 +1,90 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == "newpass"`. However, `passwords_dict` is initialized to `passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == "newpass"` after calling `validate_or_add_password("a", "newpass", passwords_dict)` in an attempt to add "newpass" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `"newpass"` to `passwords_dict`. I don't think I do that. I thought I just need to print "Password added!". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/19_49_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/train/19_49_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7ec3a3bd78ab55dabef8e2ad4415656e48b194a5
--- /dev/null
+++ b/data/raw/v2_sigcse/train/19_49_word_counter_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?.
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/19_49_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/train/19_49_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c58814d64883b072a0e12ad53944879fa7c7017
--- /dev/null
+++ b/data/raw/v2_sigcse/train/19_49_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/19_50_word_counter_conversational_thread_1.txt b/data/raw/v2_sigcse/train/19_50_word_counter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4b030dfeb7859cf8370115d5263b42543f7724e8
--- /dev/null
+++ b/data/raw/v2_sigcse/train/19_50_word_counter_conversational_thread_1.txt
@@ -0,0 +1,84 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one
+Assistant: Does this happen with all inputs?
+	<alt>Hm, ok. Can you walk me through your code?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: It's happened with all the inputs so far, but I'm not sure if it would happen with all of them
+Assistant: Can you try perturbing the inputs? Maybe add characters before or after.
+    <alt>What happens when you run `count_words("hello world ")`?
+    <alt>How does your function handle trailing whitespace?
+    <alt>Can you describe to me how you are counting words?
+    <alt>Does your loop count the last word in the sentence?
+User: It's still the same if I had numbers or non-letter characters after and before
+Assistant: Have you tried adding whitespace?
+    <alt>What happens when you run `count_words("hello world ")`?
+User: Huh, weird. When I pass the input "hello world ", the answer is correct, but it is wrong without the whitespace at the end.
+Assistant: How does your function handle trailing whitespace?
+User: I see now, I'm not counting the last word unless a space follows it. I'll amend my code to handle this. It looks like it works!
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/19_50_word_counter_socratic_dialogue.txt b/data/raw/v2_sigcse/train/19_50_word_counter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf9ecb249246e778624f474dc19d6695f60ecad4
--- /dev/null
+++ b/data/raw/v2_sigcse/train/19_50_word_counter_socratic_dialogue.txt
@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d93f911372ea6e09d6fafa18fd04ceacd7001033
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,132 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Can you explain the differences between `finalScore` and `roundedScore`?
+User: `finalScore` is the unrounded grade and `roundedScore` is the rounded version.
+	<alt>Oh! I see now, I put the wrong score into the comparisons. It works now, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And which of those values are you returning with the letter grade?
+User: Oh! I'm returning a letter calculated from `finalScore` and the grade from `roundedScore`. I fixed the issue, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_2.txt b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..873a50745b3a367f894358f9638a38df5a95d9d4
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_2.txt
@@ -0,0 +1,111 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to finalScore is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: It would be false, it wouldn't produce the right `letterGrade`.
+	<alt>It would be true, 70=70.
+Assistant: Correct. But you said you were still returning 70, why do you think that is?
+User: Oh! I'm returning `roundedScore`! If I compare by that too, then I get consistent results. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_3.txt b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7c9c01f900c49f29fa12f4755be3b3ded3005653
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_conversational_thread_3.txt
@@ -0,0 +1,162 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+User: I am returning ('D', 70) for test 4 and I don't know why.
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: What is the truth value of the boolean expression on line 14?
+User:  It would be true, 70=70.
+Assistant: Is that true? Can you verify that?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>Is that true? Can you print the value of `finalScore >= 70`?
+	<alt>Correct. Which block of the if-elif-else statement is executed?
+User: Yes, I'll use a print statement to do that.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.    
+10.    print(finalScore >= 70)
+11.
+12.    if finalScore >= 90:
+13.        letterGrade = "A"
+14.    elif finalScore >= 80:
+15.        letterGrade = "B"
+16.    elif finalScore >= 70:
+17.        letterGrade = "C"
+18.    elif finalScore >= 60:
+19.        letterGrade = "D"
+20.    else:
+21.        letterGrade = "F"
+22.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what does it print for test 4?
+User: It prints `False` but I don't know why.
+	<alt>Oh, it prints `False` because it's 69.6, not 70. I need to use `roundedScore` instead. That makes it work, thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: And what is the value of `finalScore` when you use it on line 10?
+	<alt>How does the value of `finalScore` affect the truth value of the boolean expression on line 10?
+User: Oh! I was using the wrong variable. After switching `finalScore` to `roundedScore` in the comparisons it worked. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_10_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aa261fea9a34e4a4be8f0c10fabbb4ba40042ec5
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_10_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,138 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = "A"
+12.    elif finalScore >= 80:
+13.        letterGrade = "B"
+14.    elif finalScore >= 70:
+15.        letterGrade = "C"
+16.    elif finalScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = "A"
+12.    elif roundedScore >= 80:
+13.        letterGrade = "B"
+14.    elif roundedScore >= 70:
+15.        letterGrade = "C"
+16.    elif roundedScore >= 60:
+17.        letterGrade = "D"
+18.    else:
+19.        letterGrade = "F"
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_11_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/train/1_11_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..fa366d6e26d8844a51959421ae1aaf1a01c12cb1
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_11_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+    <alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Let's look at the instructions. Is there any information that is missing or not being displayed in your output?
+	<alt>What seems to be missing from your output if you run your code and compare it with the expected output?
+User: I want to return two variables `letterGrade` and `roundedScore` but my function only returns `letterGrade`.
+	<alt>I want to return two variables, but my code only returns one even though I am trying to return both.
+	<alt>I am attempting to return two variables in my code, but only one is being returned despite my efforts to return both.
+Assistant: At which line are you attempting to return two variables?
+User: Although I am returning `letterGrade` on line 14 and `roundedScore` on line 15, it seems like line 15 never runs.
+	<alt>I am returning the variables on lines 14 and 15, but it seems like the code stops after line 14.
+Assistant: Based on the observed behavior, do you believe a function can contain two back-to-back return statements?
+	<alt>After looking at the comparison with the instructions, do you think this might be the correct way to return multiple variables?
+User: No, I think I can only use one return statement. But how do I return multiple variables?
+	<alt>How do I return multiple variables with only one return statement?
+Assistant: Let's refer back to the instructions, and this time we will pay attention to the data type of the expected output. What do you observe?
+User: The expected output consists of a tuple. I suppose I can return the variables together as a tuple with one return statement. I'll try that now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return (letterGrade, roundedScore)
+
+</code>
+Assistant: Does your output match the expected output now?
+User: It displays the expected output.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_11_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/train/1_11_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..569ccc4f9dd5118de9013cc70cb1230b76f7f671
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_11_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.   elif roundedScore >= 60:
+11.       letterGrade = "D"
+12.   else:
+13.       letterGrade = "F"
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_13_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/train/1_13_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c48ee80ac5aa5926ddbe62ac5a63450e56b67615
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_13_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,183 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_8_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/train/1_8_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e738b89b749edcaa48a75e228c2740479b244c6d
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_8_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,179 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = "A"
+7.    elif roundedScore >= 80:
+8.        letterGrade = "B"
+9.    elif roundedScore >= 70:
+10.        letterGrade = "C"
+11.    elif roundedScore >= 60:
+12.        letterGrade = "D"
+13.    else:
+14.        letterGrade = "F"
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = "A"
+8.    elif roundedScore >= 80:
+9.        letterGrade = "B"
+10.    elif roundedScore >= 70:
+11.        letterGrade = "C"
+12.    elif roundedScore >= 60:
+13.        letterGrade = "D"
+14.    else:
+15.        letterGrade = "F"
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = "A"
+6.    elif roundedScore >= 80:
+7.        letterGrade = "B"
+8.    elif roundedScore >= 70:
+9.        letterGrade = "C"
+10.    elif roundedScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_9_calculating_a_grade_conversational_thread_1.txt b/data/raw/v2_sigcse/train/1_9_calculating_a_grade_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..78f874f9904471f3ce4a0d1fbbc8e946d96aa081
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_9_calculating_a_grade_conversational_thread_1.txt
@@ -0,0 +1,112 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+	<alt>I think that the test cases may be glitched.
+	<alt>Maybe I misunderstood the instructions.
+Assistant: What do you think could be missing in your calculation?
+	<alt>Did you expect to get a rounded number from your equation here?
+	<alt>Do you know any method that can give you a rounded number?
+	<alt>Python has a lot of documentation that can help you solve specific problems. Do you think it would help to look for your solution there?
+User: I see that I don't actually have any rounding mechanism. I could use the round() method.
+	<alt>I don't have any rounding mechanism, but I don't know how to round.
+	<alt>I don't think anything is missing. I get 69.6. But I just need to get rid of the .6 somehow.
+	<alt>Maybe I'm writing my calculations wrong, though I don't know where.
+Assistant: That's a good point! We can use methods in Python to help us solve problems. How could you apply the round() method to your code?
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore.round()
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+User: I am getting an error...What's going on?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: If you are getting a new error, do you think that means the way you applied the round() method could be causing you problems? Are you sure that you applied it correctly?
+	<alt>If you received a new error from your addition, what do you think that means?
+	<alt>When you look in the Python documentation for this method, do you see any difference between your application and their application?
+	<alt>Which part of your code do you think is causing the error?
+	<alt>Try using a debugger to step through your code to find where your problem is.
+User: OK, I guess I didn't apply it correctly. I just looked it up and it says I need to put the variable inside the parenthesis. So, I changed it to this, but I don't think it's working still. It's giving me the original error.
+	<alt>Yeah, I'm sure I applied it correctly. That's how you call methods, isn't it?
+	<alt>I'm assuming I didn't do it correctly. Can you show me how to call this method?
+	<alt>Oh, I didn't apply that correctly. I need to do `round(finalScore)`.
+Assistant: To help us understand what's going on, let's take a look at how you calculated `finalScore`. You created a mathematical equation and you stored it into the variable `finalScore`. Why did you store it into a variable?
+	<alt>Try to compare what you wrote to a practical application in the Python documentation. Do you notice anything different between your answer and theirs?
+	<alt>We need to find out what part of your code has the problem. What can you do to figure out whether your rounding method is giving you the rounded answer or not?
+User: I stored it in a variable because you can't use that answer otherwise. If you just did the calculation, you wouldn't be able to check it in the if-statements.
+	<alt>I stored it in a variable because that's how the syntax of the language works. You can't just write calculations right in the IDE.
+Assistant: That makes sense. You need to store the answer somewhere. Notice how you wrote the round() method. Based on our discussion, do you think something is missing?
+User: Oh! I see. I am not storing the result of the rounding calculation anywhere. I need to save it back to the original variable.
+	<alt>I'm not sure I understand how the problems are related.
+	<alt>Am I not storing the rounded number anywhere? I thought that using the Python method would be enough.
+	<alt>Instead of using the `finalScore` variable, I should just put the equation directly into the round() method.
+User: It works now! Thanks for the help.
+Assistant: Great! Let me know if you have any other questions.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/1_9_calculating_a_grade_socratic_dialogue.txt b/data/raw/v2_sigcse/train/1_9_calculating_a_grade_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..658a9d80a86f26feb27a32c9203579ba1b1420d7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/1_9_calculating_a_grade_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = "A"
+5.    elif finalScore >= 80:
+6.        letterGrade = "B"
+7.    elif finalScore >= 70:
+8.        letterGrade = "C"
+9.    elif finalScore >= 60:
+10.        letterGrade = "D"
+11.    else:
+12.        letterGrade = "F"
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = "A"
+6.    elif finalScore >= 80:
+7.        letterGrade = "B"
+8.    elif finalScore >= 70:
+9.        letterGrade = "C"
+10.    elif finalScore >= 60:
+11.        letterGrade = "D"
+12.    else:
+13.        letterGrade = "F"
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/20_51_spell_checker_conversational_thread_1.txt b/data/raw/v2_sigcse/train/20_51_spell_checker_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1923efad8daf0f895478a02edf114ea43a62e9dd
--- /dev/null
+++ b/data/raw/v2_sigcse/train/20_51_spell_checker_conversational_thread_1.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Is that everything it is supposed to do according to the prompt?
+	<alt>Does it do anything else?
+	<alt>Okay, on what line of code does it take in those lists of words?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: I think so.
+Assistant: Let's take a more detailed look at the output. What does that part say?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: It says there is a TypeError and that NoneType objects aren't iterable.
+Assistant: Okay, so let's break that down. Let's focus on the NoneType part, what is a NoneType?
+	<alt>Okay, so let's break that down. What does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: A that's an object that doesn't have a value.
+	<alt>I'm not sure.
+Assistant: So why would there be an object that doesn't have a value there?
+	<alt>Let's look at the second part, what does it mean when something is iterable?
+	<alt>Why could your function be returning a NoneType object?
+User: I don't know.
+	<alt>My function doesn't return anything!
+Assistant: Where could a NoneType be coming from?
+	<alt>Why could your function be returning a NoneType object?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: My function.
+Assistant: Why could it be returning something with no value?
+	<alt>Check the python documentation, why do functions return NoneType objects?
+User: I forgot the return statement!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/20_51_spell_checker_socratic_dialogue.txt b/data/raw/v2_sigcse/train/20_51_spell_checker_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9c527fa1fca8cbe668dab52c626ee3b42557cecb
--- /dev/null
+++ b/data/raw/v2_sigcse/train/20_51_spell_checker_socratic_dialogue.txt
@@ -0,0 +1,114 @@
+<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say "[word] is spelled properly!". If a word is misspelled, the string should say "[word] is misspelled!". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) => ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) => ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker(["dog", "cat", "giraffe", "horse", "dragon"], ["dogz", "cet", "giraffe", "horsee", "dragon"])) == ["dogz is misspelled!", "cet is misspelled!", "giraffe is spelled properly!", "horsee is misspelled!", "dragon is spelled properly!"]
+assert list(spellchecker(["apple", "banana", "orange", "pear", "grape"], ["apple", "baana", "orange", "pier", "grayp"])) == ["apple is spelled properly!", "baana is misspelled!", "orange is spelled properly!", "pier is misspelled!", "grayp is misspelled!"]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + " is spelled properly!")
+6.        else:
+7.            result.append(word + " is misspelled!")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt b/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..a94dc6f8d67e4f4de528d1519ee714155568bfc9
--- /dev/null
+++ b/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_conversational_thread_1.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Can you explain what the "<=" operator does?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+User: That is the "less than or equal to" operator. It returns true if `c` is less than or equal to 0 and false otherwise.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+	<alt>The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt b/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..35b266e30f10e8da14bba1b085d89c33763c4293
--- /dev/null
+++ b/data/raw/v2_sigcse/train/21_52_fahrenheit_to_celsius_converter_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say "Freezing!". If the temperature in Celsius is above 0, the string should say "It's not freezing!". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => "Freezing!"
+fToC(0.5) => "Freezing!"
+fToC(45.0) => "It's not freezing!"
+fToC(-5.4) == "Freezing!"
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns "It's not freezing!" rather than "Freezing!"
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == "Freezing!"
+assert fToC(0.5) == "Freezing!"
+assert fToC(45.0) == "It's not freezing!"
+assert fToC(-5.4) == "Freezing!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me "Freezing!", it gives me "It's not freezing!" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the "<" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the "less than" operator. It compares `c` to 0.
+	<alt>That is the "less than" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the "<=" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns "It's not freezing!" when `c` is equal to 0, but I want it to return "Freezing!".
+	<alt>Oh... I see the problem now. I don't want to return "It's not freezing!" when `c` is equal to 0, I want to return "Freezing!". I should change the "<" to "<=".
+Assistant: Which operator should you use on line 3 if you want to return "Freezing!" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the "<=" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return "Freezing!"
+5.  else:
+6.    return "It's not freezing!"
+</code>
+Assistant: Good work!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/22_53_cookie_purchase_conversational_thread_1.txt b/data/raw/v2_sigcse/train/22_53_cookie_purchase_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..cf64c30ebf7ca0cd68adbbd8be2e764757281ad1
--- /dev/null
+++ b/data/raw/v2_sigcse/train/22_53_cookie_purchase_conversational_thread_1.txt
@@ -0,0 +1,75 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code
+Assistant: Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: I think there should be a discount of 10% but when I run `cookiePurchase(70)`, I get a discount of 0. I'm so lost.
+Assistant: Let's review the problem description again. What are the conditions for a discount and where in your code do you check for these conditions?
+	<alt>From the task description, you need to check whether the number of cookies is divisible by 10, and it looks like you fail on an input that is divisible by 10. Can you explain how you're checking whether 70 is divisible by 10?
+User: The task description tells me to check whether the number of `cookies` is greater than 10 and whether `cookies` is a multiple of 10, and I fail on 70 cookies, so maybe I'm not checking this properly.
+Assistant: Let's walk through your if statement on line 4 then. 70 > 10 is True, but what is the value of `cookies / 10` when `cookies` is 70?
+User: So, for 70, I first check if it is greater than 10, which it is, and then I check whether it is a multiple of 10. I do this by dividing by 10 and seeing if the output is 0. Wait, that's not right. 70 / 10 is 7, not 0.
+	<alt>So, for 70, I first check that it is greater than 10, and then I divide by 10 to check divisibility
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Where can you learn more about arithmetic operators in Python?
+	<alt>Let's take a look at the Python documentation to see if there is a different operator that does what you want.	
+User: Ah! The Python documentation would be good to look at right now. Looking at the documentation, I think I should be using the modulus operator. I'll try that.
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Looks like it works!
+User: Yes it does for all the test cases! Thank you so much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/22_53_cookie_purchase_socratic_dialogue.txt b/data/raw/v2_sigcse/train/22_53_cookie_purchase_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0456f3ba3d42d12e763e91f4f271458123228ab0
--- /dev/null
+++ b/data/raw/v2_sigcse/train/22_53_cookie_purchase_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {"discount": discount, "price": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {"discount": discount, "price": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_conversational_thread_1.txt b/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3923bde64ffe0970724120b16b7b24e77f734792
--- /dev/null
+++ b/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2  , Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as 1-> 2-> 3 -> 4.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind? 
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Now checking assertions, what happens when we run the checks?
+	<alt>Looking at our test case, can you trace what happens as your code runs?
+User: Lines 24, 25, 26 run successfully, which means that the data attribute of the head node of the linked list is equal to 1, the next node holds data 2, and the node after that holds data 5. However, we run into an error at line 27.
+	<alt>It looks like I run into an error at line 27, so it seems that the node after Node5 is unavailable.
+	<alt>It looks like Node3 is no longer in the linked list.
+	<alt>Somehow it looks like the linked list is broken, and checking for a node with data 3 throws an AttributeError.
+Assistant: That's right. Can you tell me what your linked list is currently looking like (after running `insert_after(head, 2, 5)`)?
+	<alt>Let's take a look at the current linked list we have. What might be missing from this list?
+User: It seems that `head.next.next.next` is None. It means that the new linked list is actually `1 -> 2 -> 5`, after executing `assert_after(head, 2, 5)`.
+	<alt>It looks like I have a broken linked list. The current list stops at `node` with data 5.
+Assistant: Yes. You are right. These nodes after node 2 in the original linked list (`1 ->2 -> 3 -> 4`) are gone, after executing your function, `assert_after(head, 2, 5)`. Namely, we are supposed to get a new linked list, 1->2->5->3->4, but your function implementation gives a list of 1->2->5. Which link is missing in the execution of your function?
+	<alt>That's right, we need to account for making sure that the current connections keep working when we add a new element somewhere before the end. Can you tell what needs to be updated in the code to make sure we update all existing links?
+User: I see. The link from node5 to node3 is missing. The next attribute of node5 should refers to node3.
+	<alt>That makes sense, I think I need to make sure that when I place a new node into the list, I assign the node link to the previous node's next link, so I can maintain the connections.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.           new_node = Node(data=new_data)
+11.           new_node.next = curr_head.next
+12.           curr_head.next = new_node
+13.           return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_socratic_dialogue.txt b/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c2f04014f2be36ec150b6d47a51b004d5034d36a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/25_55_insert_to_linked_list_socratic_dialogue.txt
@@ -0,0 +1,100 @@
+<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => "Previous node is not in linked list"
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return "Previous node is not in linked list"
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == "Previous node is not in linked list"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return "Previous node is not in linked list"
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/2_18_splitting_cookies_conversational_thread_1.txt b/data/raw/v2_sigcse/train/2_18_splitting_cookies_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5816fc7a4f695df04168eac18525185aa67a600d
--- /dev/null
+++ b/data/raw/v2_sigcse/train/2_18_splitting_cookies_conversational_thread_1.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` an then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: That's right. According to the problem statement, we can buy more cookies, but not reduce the cookies we have. In which line of your code might this requirement be violated?
+	<alt>Let's also keep in mind that we can buy more cookies, but not waste any that we already have in the process of ensuring everyone gets the same amount, as mentioned in the problem statement. Where can we account for this in your code?
+User: That makes sense. I think I need to modify line 5, and account for the requirement that I can buy more cookies but not vice versa. I will update line 5.
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    purchasedCookies = people - cookies % people
+6.    newCookies = cookies + purchasedCookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</code>
+Assistant: Sounds good, see you later!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/2_18_splitting_cookies_socratic_dialogue.txt b/data/raw/v2_sigcse/train/2_18_splitting_cookies_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85a0354c3b499bffc872b15a12f25deea1ff3fd8
--- /dev/null
+++ b/data/raw/v2_sigcse/train/2_18_splitting_cookies_socratic_dialogue.txt
@@ -0,0 +1,68 @@
+<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying "Cookies can be split evenly!". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying "Cookies cannot be split evenly. Bought more cookies." Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, "Cookies can be split evenly!")
+split(10, 3) => (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+split(20, 4) => (5, 0, "Cookies can be split evenly!")
+split(10, 5) => (2, 0, "Cookies can be split evenly!")
+split(25, 10) => (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 3) == (12, 4, "Cookies cannot be split evenly. Bought more cookies.")
+assert split(20, 4) == (5, 0, "Cookies can be split evenly!")
+assert split(10, 5) == (2, 0, "Cookies can be split evenly!")
+assert split(25, 10) == (30, 3, "Cookies cannot be split evenly. Bought more cookies.")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, "Cookies can be split evenly!")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, "Cookies can be split evenly!")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, "Cookies cannot be split evenly. Bought more cookies.")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/3_20_counting_down_conversational_thread_1.txt b/data/raw/v2_sigcse/train/3_20_counting_down_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9f03ecc9e575e5f0cf636ebbf18ecc558645fe1a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/3_20_counting_down_conversational_thread_1.txt
@@ -0,0 +1,77 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+	<alt>When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3.
+Assistant: That's right. In your `else` condition, we run into this error. Let's also review your `if` condition. Do you observe any similar issues?
+	<alt>Let's also try other test cases. Based on the observed outputs, do you think there is another similar issue in your code? If yes, which lines are affected?
+	<alt>Let's complete our analysis of the issues by checking what happens if we run the other test cases as well. Do you observe any issues?
+User: Yes, the while loop in the `if` condition also has a similar issue. I will fix this issue for both the if and else conditions.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.   return l
+</code>
+Assistant: Do all the test cases work correctly now?
+User: Yes they do, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/3_20_counting_down_socratic_dialogue.txt b/data/raw/v2_sigcse/train/3_20_counting_down_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3cf29f118180022365583ed08c26ea38933e89f7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/3_20_counting_down_socratic_dialogue.txt
@@ -0,0 +1,96 @@
+<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a "countup" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a "countdown" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_22_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/4_22_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1428e2d960a33311a690e94fa5d1de1f13145762
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_22_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Ok, they are >=, <=, >, <, =!, and ==.
+Assistant: Ok, what does =! do?
+  <alt>How do you check if two numbers are unequal?
+User: It checks if two numbers are not equal.
+Assistant: Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+  <alt>Do you see a squiggly line in your code? If so, what is it highlighting?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I think I used the wrong operator. I should have used != instead of =!.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_22_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/4_22_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..354c5133f17c48e48c66cbae273a9d4639b5b641
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_22_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,62 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for "not equal to" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says "SyntaxError: invalid syntax"
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_23_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/4_23_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..9bd416f7fa51284317fcae08059df9cdf4acc118
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_23_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>Can you explain your function to me line by line?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: For example, the input list `[0,2,3]` will return `[2,3]`, but many other inputs result in unchanged outputs.
+	<alt>I seem to only remove 0s from my lists
+	<alt>Running `returnOdd([2, 4, 6, 8, 10])` gives the same list back, for example
+Assistant: Can you explain what your if-statement on line 4 is doing? Let's assume `i` is 4.
+	<alt>How do you check if a number is even in your code?
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+User: In the case before, we can look at 0 first. `0 / 2` is 0, so we get False on line 4 and do not append. For `4 / 2` is equal to `2`, it looks like I'm not getting what I want. Line 4 gives True, so we still append. That's not what I want though.
+Assistant: It looks like just dividing isn't doing what you want. Is there another operator that can test whether a number is divisible by another? Feel free to reference the documentation.
+	<alt>Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Looking at the documentation, it seems like I can use a `%` to test whether the number is even. I'll try that.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Looks like it works!
+User: Thanks for your help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_23_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/4_23_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0939ecc606a1fd49f467cd1588ac4f0b6f4af25f
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_23_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,70 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_25_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/4_25_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..30070b15a2e20b9e636a2e6d76fcfd5e69ccd69a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_25_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,55 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+User: The scope refers to the visibility of a certain variable depending on where it has been used. For example, a variable defined inside a function is only visible to the function, and cannot be used outside the function.
+	<alt>The scope means certain variables can only be used within the visibility of the code block they are a part of.
+Assistant: That's right. Let's look back at your code now. Is the return statement in the correct scope?
+	<alt>Right, so how would you indent line 6 so that it is part of the method?
+User: I would need to indent it so that it is inside the function. I will make changes now.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Sounds great! Happy to help.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_25_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/4_25_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..463a697ddd004f912dd87d61d0edc2dba5c1b598
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_25_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error "SyntaxError: 'return' outside function" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the "scope" of a code block means. Do you know what that is and how that might affect a "return" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_26_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/4_26_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..187bd3ed7c77b8654f0efff763d9765e59e4ac74
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_26_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases if any are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: I don't know, how could I find out?
+	<alt>No, I'm iterating through the whole list of numbers.
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+User: When running the function with `nums` as `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]` only `1` is printed. I think this means the for loop is iterating only once and therefore returning `[1]`.
+Assistant: Do you notice anything in your function that might cause the for loop or the function to end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know. What do you think can make a loop end early?
+User: I don't see any break statements. Perhaps it might be the return statement on line 6.
+Assistant: Good. When is that return statement getting executed? Is it before or after the for loop completes iterating?
+User: I get it! It's returning after one iteration! Let me unindent the return statement so that it returns after the for loop is completed.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_26_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/4_26_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..573522c58359c29be4591852b5a1633261555e7d
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_26_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,93 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_28_removing_even_numbers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/4_28_removing_even_numbers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d274557923f75bb99fedfee06d53bf7bbe6eadd3
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_28_removing_even_numbers_conversational_thread_1.txt
@@ -0,0 +1,57 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: Yes, can you use the caret in your output to figure out what is wrong with your syntax?
+User: It looks like there is something wrong towards the end of line 3, but I am not sure what that is.
+Assistant: Can use the documentation to figure out the syntax of a for loop?
+	<alt>It looks like you are missing a punctuation mark, do you know what that is?
+User: Am I missing a colon at the end?
+Assistant: Yes, you need to include that colon at the end of line 3.
+User: This code now works, thank you for your help!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: That looks great, you are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/4_28_removing_even_numbers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/4_28_removing_even_numbers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1c605112e950fb1b7d189aca6b9600a28a219d49
--- /dev/null
+++ b/data/raw/v2_sigcse/train/4_28_removing_even_numbers_socratic_dialogue.txt
@@ -0,0 +1,65 @@
+<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_1.txt b/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..19b112a9b28e9331603d712ec7d390177eee2329
--- /dev/null
+++ b/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide 6 by 2.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type in `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_2.txt b/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ac351106c4d0060c6182dd4b7fe0b879868900d5
--- /dev/null
+++ b/data/raw/v2_sigcse/train/56_15_compute_average_conversational_thread_2.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant:   Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall the order of operations when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first.
+	<alt>Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+Instructor: Good. How can you modify the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Good. Why do you think it is evaluating `4 / 2` first?
+	<alt>Good. What do you think might be missing from the expression so that it evaluates `2 + 4` before `4 / 2`?
+	<alt>Let's recall the order of operations. Can you list which operations take precedence over division and multiplication?
+User: I think I need to add parentheses around `(2 + 4)` to enforce addition to be done first.
+Assistant: Good. Let’s try it in the Python terminal. Type `(2 + 4) / 2` and press enter. What does it return?
+	<alt>Now, what changes would you need to make to your code on line 2?
+	<alt>Now, what changes would you need to make to your code to fix the bug?
+User: I typed `(2 + 4) / 2` evaluates to 3. Let me try it in my code.
+	<alt>I typed `(2 + 4) / 2` evaluates to 3.
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/56_15_compute_average_socratic_dialogue.txt b/data/raw/v2_sigcse/train/56_15_compute_average_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8999a05df5cfc4c5811ce2dcdb8588748e1c7f21
--- /dev/null
+++ b/data/raw/v2_sigcse/train/56_15_compute_average_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/58_58_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/train/58_58_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92804610fa5671a78bcf745e893efbb9ba218875
--- /dev/null
+++ b/data/raw/v2_sigcse/train/58_58_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,107 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_1.txt b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4539114e548434b02d3f85b83d374c5806368b8b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_1.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is  ... false. Ah, I see where the problem is, the loop stops too early, it should iterate also when `apples` is equal to `children`. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_2.txt b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..204476a2e5c01e00d40070025d85a5a7e7215267
--- /dev/null
+++ b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_2.txt
@@ -0,0 +1,57 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: On line 2, the variable `i`, which holds the number of apples we give each child so far, is initialized with 0. On line 3, we check to see first if `apples > 0`, which is true, and if `apples > children`, which is true. Then on line 4, `apples` is assigned the value 100 - 100 = 0 and on line 5 `i` is incremented to 1. Then the while condition `apples > 0` is not true anymore, so the loop ends and the value 1 of `i` should be returned from line 6.
+Assistant: You said that, when we run the code on the third test case, `apples > children` is true. Are you sure about that?
+	<alt>Well, your explanation must contain a mistake, because your function returns 0, not 1 as you said. This means that `i` is never incremented. Can you see where the problem is?
+User: Ah, `apples` is actually equal to, not strictly greater than, `children`. I see now what the problem is.  Let me fix that ... it works now! Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+
+</code>
+Assistant: You are welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_3.txt b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d0d29f8fac42541225d87d5e8c5ee6d3b5df09a6
--- /dev/null
+++ b/data/raw/v2_sigcse/train/58_59_splitting_apples_conversational_thread_3.txt
@@ -0,0 +1,56 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It ensures that there are still enough apples so that we can give each child ` more apples.
+Assistant: OK, but is it necessary for `apples` to be strictly greater than `children`? What if they were equal, would it still be sufficient to give 1 apple to each child?
+	<alt>Sure, but is that condition really necessary? Think of the third test case, where `apples` is `100` and `children` is `100`, would these numbers satisfy that condition?
+User: Ah, I understand now, they can also be equal. Let me try to fix that ... it works now. Thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You are welcome, happy to help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/58_59_splitting_apples_socratic_dialogue.txt b/data/raw/v2_sigcse/train/58_59_splitting_apples_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..93e8936d3618ce036b5ef9428f5357693c2c75ca
--- /dev/null
+++ b/data/raw/v2_sigcse/train/58_59_splitting_apples_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/59_60_product_conversational_thread_1.txt b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d08b8a7d1f982ac1c75d3ebd3c67bdb1c7162c0c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_1.txt
@@ -0,0 +1,52 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still fails the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to as `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/59_60_product_conversational_thread_2.txt b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..678c3ea9748d45f4d25e48f24552644b255147b7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: Correct! When you run the code now, you should see that there are no longer any assertion errors.
+User: Yes, that is the case. Thank you for your help!
+Assistant: You're welcome, thank you for asking questions to further your understanding. It is important to understand the fundamentals when you are first learning. Is there anything else that I can help you with today?
+User: No, that is all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/59_60_product_conversational_thread_3.txt b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8061e160bfbc8b7b6788c4e3f5be29b2bd8416ae
--- /dev/null
+++ b/data/raw/v2_sigcse/train/59_60_product_conversational_thread_3.txt
@@ -0,0 +1,54 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Oh! I made the change and now it prints out `None`.  I realized I just forgot to put a `return` statement and I've now fixed it. Thanks for the help!
+<code>
+1. def Product(a, b):
+2.	a * b
+3. print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh! That makes a lot more sense. So I would place the `return` statement on line 2 like this?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3. print(Product(1,2))
+</code>
+Assistant: You're welcome! Any other ways I can help you today?
+	<alt>It is likely a good decision to remove the `print` statement on line 3 before using this, as it would lead to confusion with a user running this program without knowing your reasoning behind it being there.
+User: That makes sense. Thanks for the help!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/59_60_product_socratic_dialogue.txt b/data/raw/v2_sigcse/train/59_60_product_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3447706bd18f9798905a6143c6bb087c22ab02ee
--- /dev/null
+++ b/data/raw/v2_sigcse/train/59_60_product_socratic_dialogue.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out "None" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_1.txt b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5a913de0a055bae71188b38bf8bbb590018e1605
--- /dev/null
+++ b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+	<alt>Hi! I've been working on this function and it doesn't seem to be correct.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: It works for all the example cases except for `get_words("Hello World")`.
+Assistant: Let's look at the example cases closely. What is so special about `get_words("Hello World")` compared to the other examples?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+User: For that sentence, there are no repeated words.
+Assistant: Good. How does your code behave when there are repeated words in the input string `s` and how is it different from the expected behavior?
+	<alt>What would your code need to do to ensure that when there are duplicate words in the input string, the function returns a list of unique words?
+User: It seems like I am not deduplicating. How would I go about doing that?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: I could try using a set instead since that makes sure elements are unique. I'll change my code
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: It looks like it works!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_2.txt b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..d645aaecd6b075ea42d6716e59a313703e2b698b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_2.txt
@@ -0,0 +1,66 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: Can you insert a print statement to print the value of `words` before line 3?
+	<alt>And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+User: Yes, for the input `"Hello World hello"` it returns `["hello", "world", "hello" ]`. Is that not correct?
+	<alt>Oh, the problem wants me to return unique values only. I've fixed it, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Let's look at the examples in the problem description. What happens when you run `get_words("Hello World hello")`? What should the output be?
+User: Oh! I've fixed my code, I missed that in the problem. Thank you for the clarification!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Any time! If you have any more questions, feel free to ask.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_3.txt b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1f9289d5140eae02bebf35a3a70a18962d913b07
--- /dev/null
+++ b/data/raw/v2_sigcse/train/5_30_sorted_words_conversational_thread_3.txt
@@ -0,0 +1,72 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I made my `get_words(s)` function, but it's not working correctly. What should I do?
+Assistant: Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: The code on line two is a single-line loop that will return the value of every word in lowercase.
+	<alt>It returns a list of words.
+Assistant: And what does line 3 accomplish?
+	<alt>Where do you alphabetically sort the list provided?
+	<alt>Can you print the value of words before line 3?
+User: It sorts the values in `words` alphabetically.
+Assistant: Can you explain what the problem wants you to return?
+	<alt>Where do you remove duplicate values from words?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+User: Oh! The problem wants me to return a sorted list without duplicates. Is there a given function to do that?
+	<alt>Oh! The problem wants me to return a list with no duplicates! I've fixed it now, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>Is there a data structure in Python that stores unique elements only?
+	<alt>Where can you learn about deduplicating a list in Python?
+User: Oh, a set! I figured it out, thank you!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: No problem! If you have any more issues, please feel free to talk about them now or later.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/5_30_sorted_words_socratic_dialogue.txt b/data/raw/v2_sigcse/train/5_30_sorted_words_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4a84f7ffbafbac182376e7e75ffb262bd1abd1b8
--- /dev/null
+++ b/data/raw/v2_sigcse/train/5_30_sorted_words_socratic_dialogue.txt
@@ -0,0 +1,61 @@
+<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words("Hello World hello")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words("Hello World") => ['hello', 'world']
+get_words("Hello World hello") => ['hello', 'world']
+get_words("Hello World hello world") => ['hello', 'world']
+get_words("Hello World H e l l o W o r l d") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words("Hello World el WORld") => ['el', 'hello', 'world']
+get_words("A C B c b a") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words("Hello World") == ["hello", "world"]
+assert get_words("Hello World hello") == ["hello", "world"]
+assert get_words("Hello World hello world") == ["hello", "world"]
+assert get_words("Hello World H e l l o W o r l d") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words("Hello World el WORld") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words("Hello World hello")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words("Hello World")` and `get_words("Hello World hello")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like "hello world hello world", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split(" ")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_1.txt b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..41c5b9add9306768bd4e16e8f46db1bb3efc476a
--- /dev/null
+++ b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_1.txt
@@ -0,0 +1,56 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: Oh! I would have to pick from one of the two, but it doesn't matter which since I'm returning the value, which input is the highest. That makes a lot more sense, I've made some alterations to my code and it works now. Thank you!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_2.txt b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2b9944434a0fb6adc229a5be99ec52fc4af89519
--- /dev/null
+++ b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: Oh, I have to do greater than or equal to rather than just greater than. Thank you for the advice!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_3.txt b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..48027de0229ad33d8984d9bf7f4bbe64fb4a7b72
--- /dev/null
+++ b/data/raw/v2_sigcse/train/60_61_largest_number_conversational_thread_3.txt
@@ -0,0 +1,67 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Oh, I get that now. So if I made this change it would be correct, since I cannot make the assumption?
+<code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	elif(c > a and c > b):
+7.		return c
+</code>
+Assistant: This is still incorrect, but it has fixed one of the issues. What would happen if all of the inputs are equal? What would the function return?
+	<alt>Can you tell me about a situation where this function would now return `None`?
+User: That would return `None`, right? What should I do in this case, none of my conditions can catch that, do I need to add another case?
+Assistant: I don't think that is necessary, I think there is a way to modify your existing cases to make this work. How would you check if a number is either larger or the same as another number?
+User: Oh! I could use the `>=` operator. That makes it work as expected now, thank you so much!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	elif(c >= a and c >= b):
+7.		return c
+</code>
+Assistant: That is entirely correct! I'm glad I could be of assistance. Can I help you with anything else today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/60_61_largest_number_socratic_dialogue.txt b/data/raw/v2_sigcse/train/60_61_largest_number_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c64d548f36fd47251621714106ff3e6d954858f1
--- /dev/null
+++ b/data/raw/v2_sigcse/train/60_61_largest_number_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_1.txt b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6e575f4d448c7bfd170e481ef1b8ca5a68dace75
--- /dev/null
+++ b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_1.txt
@@ -0,0 +1,59 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: I'm sorry I think too much is going on in that question and I'm confused. Can you simplify it?
+Assistant: Let's break the problem down. Can you create a temporary variable to store `a+b`?
+	<alt>Gladly. First, let's change your code into an `if`/`else` condition. When `(a+b)%2==1`, what do you output?
+User: Okay, I've changed my code.
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 1
+</code>
+Assistant: Okay, now when you do modulo 2 of `inputSum`, what number would be outputted if `inputSum` is even?
+	<alt>Given the revised definition of the modulo operation, can you explain what is outputted from an even sum mod 2?
+User: Since even numbers are divisible by 2, the remainder would be 0, right?
+Assistant: That is correct! And what is the output of `0 == 1`?
+User: Oh, that would be False! I needed to change the 1 into a 0 and now it works as expected. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a + b
+3.	return inputSum % 2 == 0
+</code>
+Assistant: I'm glad to be of assistance! Is there anything else I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_2.txt b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..95e016f9a9cfea3e5c68a8e928a73eb548210b41
--- /dev/null
+++ b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_2.txt
@@ -0,0 +1,61 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	  return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: That means that `inputSum` is divisible by 2, right?
+Assistant: That is incorrect. Modulo returns the value of the remainder when the first operand is divided by the second. Given this, when `inputSum % 2 == 1`, is `inputSum` even or odd?
+User: Oh! That means the number is odd, right?
+Assistant: Correct! Since the number is odd, what would the expected response from the `SumIsEven()` function be?
+User: Oh, the expected output would be `False`, I had my booleans backward. Thank you for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return False
+5.    else:
+6.	  return True
+</code>
+Assistant: I'm happy to help. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_3.txt b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..2070ad10ef09c7a08a0b02820fd1e24ff19b9bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/61_62_is_even_conversational_thread_3.txt
@@ -0,0 +1,57 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble making `SumIsEven()` work, and I think I have just managed to make it too complicated to easily debug. Can you help me convert it into an if/else control flow?
+Assistant: Hello! I would be more than glad to help you with that. I notice your first line is already returning a boolean value, what if we use that as a condition for our `if` statement? First, let's simplify the problem so it's easier to look at. Can you store `a+b` in a temporary variable?
+User: Okay! I've put the sum of a and b into the temporary variable `inputSum` and gone ahead and converted the return into an if/else but it's still not working as intended. Can you give me more guidance?
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 1):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: Okay, when `inputSum % 2` is equal to 1, what does that mean about the value of `inputSum`?
+	<alt>If `inputSum` is even, what is the output of `inputSum % 2`?
+User: Oh, I have my conditions backward! That means that the number is odd, not even. I changed the 1 to a 0 and it works now. Thank you so much for your help!
+<code>
+1. def SumIsEven(a, b):
+2.    inputSum = a+b
+3.    if(inputSum % 2 == 0):
+4.        return True
+5.    else:
+6.	    return False
+</code>
+Assistant: I'm glad to be of assistance. Did you want to ask any other questions today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/61_62_is_even_socratic_dialogue.txt b/data/raw/v2_sigcse/train/61_62_is_even_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c1f95a3c598d2b8906b6d9b8079176069006045f
--- /dev/null
+++ b/data/raw/v2_sigcse/train/61_62_is_even_socratic_dialogue.txt
@@ -0,0 +1,45 @@
+<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_1.txt b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e32377a10c32c78892cff131fb25f6cdf9a73505
--- /dev/null
+++ b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_1.txt
@@ -0,0 +1,62 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Could I use a temporary variable to do that?
+Assistant: Yes, a temporary variable is entirely fine. Where would you include it?
+	<alt>Why do you feel a temporary variable is necessary?
+User: I created a variable `newHigh` and set it equal to `high+1` and then put that into `range()`'s second input and that fixed it. Thank you!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	newHigh = high+1
+4.	for i in range(low, newHigh):
+5.		num += i
+6.	return num
+</code>
+Assistant: I'm happy that I was of assistance. Is there anything else you wanted to ask about?
+User: No, that was all. Thank you again!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_2.txt b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f08e6af0a40ef6e93a994f9a05bdb2ea9d6656d2
--- /dev/null
+++ b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would turn it into `range(0,2)`, but is that always the case? Why would it always be adding 1?
+Assistant: Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: Oh, yeah, since it is every integer between the two inputs, not including the second input, `y` would be in `range(x,y+1)` but not `range(x,y)`.
+Assistant: That is correct. Given that, how would you change your code?
+User: I added one to `high` and it fixed everything. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of service to you. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_3.txt b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..580b549b1bf9579667dbe080da60bd88961a083c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/62_63_summing_between_integers_conversational_thread_3.txt
@@ -0,0 +1,49 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: It would be a list containing 0 and 1, right?
+Assistant: That is not correct. `range()` is not inclusive of its second argument, meaning that `range(0,1)` is actually a list containing only one element, 0.
+User: Oh, I added 1 to `high` in my `range()` function and it works now, I didn't know that it wasn't inclusive of the second argument. Thank you for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/62_63_summing_between_integers_socratic_dialogue.txt b/data/raw/v2_sigcse/train/62_63_summing_between_integers_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8309521875cf1009334bcdc57c55eca5361154af
--- /dev/null
+++ b/data/raw/v2_sigcse/train/62_63_summing_between_integers_socratic_dialogue.txt
@@ -0,0 +1,58 @@
+<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_1.txt b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f9ccdb9cb52ad6bc8cc840b20c1c3eb12aef34aa
--- /dev/null
+++ b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_1.txt
@@ -0,0 +1,73 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: That's two conditions though, how would I be able to put three booleans into a single if statement?
+Assistant: I see where the confusion is coming from now. Boolean operands can be put into sequence, the same as mathematical operations.
+User: Oh, so it would be syntactically correct to put `pizzas >= 10 and pizzas <= 20 and not(weekend)`?
+Assistant: That is correct.
+User: Oh, that makes the problem a lot easier then! Thank you for clarifying that! My program is working correctly now.
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_2.txt b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44e5512491b5a802751848f4c7a8e2e50ab7d9c0
--- /dev/null
+++ b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_2.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if `pizzas` is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, I was just missing a condition on my `elif` statement. I've fixed the issue now, thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_3.txt b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..7d1f82e12e4fd9c26bfbaf7ebe8e1ed05d53200e
--- /dev/null
+++ b/data/raw/v2_sigcse/train/63_64_good_dinner_conversational_thread_3.txt
@@ -0,0 +1,65 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would make turn a dinner into a good dinner?
+	<alt>What would happen when `pizzas` is between 0 and 9, but `weekend` is `False`?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: It would be between 10 and 20 pizzas, inclusively.
+Assistant: Correct, and how would you express that in Python?
+User: Would it be `10 <= pizzas <= 20`?
+Assistant: That notation does not work in Python, you can instead split it up into two statements using an `and` operation. How would you put your previous statement into two statements?
+	<alt>That notation is not correct Python syntax. How would you simplify this problem? It may help to physically speak what the mathematical symbols mean.
+User: Oh, I put it as `10 <=pizzas and pizzas <= 20` and that fixed my code. Thank you!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(10 <= pizzas and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to hear that I was able to help. Is there anything else I could help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/63_64_good_dinner_socratic_dialogue.txt b/data/raw/v2_sigcse/train/63_64_good_dinner_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..e45d2c2adf260dd57c3c6ca15e0fa2a61e06050c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/63_64_good_dinner_socratic_dialogue.txt
@@ -0,0 +1,69 @@
+<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_1.txt b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f6fbac0c54c97a10de1a04c598441c02d9bd30ac
--- /dev/null
+++ b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+	<alt>At what index do Python lists begin?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(0, len(integers))`, right?
+Assistant: That is correct, Python lists index from 0, not 1.
+User: That makes sense! The code is working as intended now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that helped you understand. How else can I help you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_2.txt b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..51829e6e1ed9187fcee90dd8d33826a769d4c1df
--- /dev/null
+++ b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_2.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct!
+	<alt>That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Ah, that is a lot easier to use! My code is working now, thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_3.txt b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..50688dcfaaae29e8966a1e8ba41a94bab964e15c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/64_65_count_ones_conversational_thread_3.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: When you loop with `i in range(1, len(integers))` you put into `i` every value in the list `range(1, len(integers))`. Do you think there is a better way to loop over a list using this paradigm?
+User: Oh, is it possible to do `for integer in integers:`?
+Assistant: That is entirely correct! Can you explain the functional difference between your previous solution and this one?
+User: Oh, I think my previous loop only iterated `len(integers)-1` times, while this loop iterates `len(integers)` times. Was I supposed to use `range(0, len(integers))` in the initial solution?
+Assistant: That is entirely correct. Python lists start their indices at 0, not 1.
+User: Thank you for your help! I plugged the new solution into my code and it works now.
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for integer in integers:
+4.		if(integer == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad that I could clear up the concepts for you. Is there anything else you would want to ask?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/64_65_count_ones_socratic_dialogue.txt b/data/raw/v2_sigcse/train/64_65_count_ones_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b2acfe19bbad8312880bb0ebe0a33d311d7c3f60
--- /dev/null
+++ b/data/raw/v2_sigcse/train/64_65_count_ones_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as "distance from the first element" rather than "element number".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_1.txt b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..daef07ba3ef314a6d9d4bf62f0bf727664394bf7
--- /dev/null
+++ b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_1.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of `smallest` and `largest` throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest` or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for `smallest` and a really small number for `largest`?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: That is correct. Why would that be the case?
+User: If the variables start as members of the array, and are only compared to other members of the array, then they would both always be both members of the array and, by the conditions of the `for` loop, the correct members of the array.
+Assistant: That is correct!
+User: I made the change and the code works now, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_2.txt b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..665d9214a4b4d2af11b377247eb7e2210f33c732
--- /dev/null
+++ b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_2.txt
@@ -0,0 +1,65 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of `array`?
+Assistant: That is correct. Why would that be the case?
+User: That's where I am confused, why does starting as an element of `array` change anything about the solution?
+Assistant: If you pick an element of the list, you can be certain that you never have the same issue as when you just picked 0. As there either exists an element in `array` that is larger or smaller than your initial value, or your initial value is the largest or smallest element itself.
+User: Oh, that makes a lot more sense now! Thank you for the help, my code is working now!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm happy to help. How else can I help you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_3.txt b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..196c4e4bd219d77334db421c0f05c2c244bb52fd
--- /dev/null
+++ b/data/raw/v2_sigcse/train/65_66_list_range_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5]) => 4
+Range([2,2,1,3]) =>2
+Range([-10,-3,-1]) => -9
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.	smallest = 0
+3.	largest = 0
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = array[i]
+7.		if(element < smallest):
+8.			smallest = array[i]
+9.	return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == -9
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Oh, [-1001, -1010] would work for that. I see the point now, if I set `largest` and `smallest` to `array[0]` initially, they would always be a member of the array, which ensures the comparisons will always be between elements within the array rather than arbitrary values. Now my code is working, thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could clear that concept up for you. Is there anything else I can do for you today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/65_66_list_range_socratic_dialogue.txt b/data/raw/v2_sigcse/train/65_66_list_range_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..6863cc01239d47043165ecf302209054e1b619ce
--- /dev/null
+++ b/data/raw/v2_sigcse/train/65_66_list_range_socratic_dialogue.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..27c6a4ad428c38f6e247ddec3fe1080dffd7e3c8
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,54 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant:  This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, it says -1 in the problem. Thank you for pointing it out!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..5cf132b9132d3f054d0ec5c0310690394c737488
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,53 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. How would someone differentiate between those scenarios?
+Assistant: There is a standard response of -1 for this kind of function, but it is further defined in the problem given.
+User: Oh, I suppose I misread that part of the problem. I made the change and it works correctly now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad I could help, is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..f46343b0931227f5535a67e1708ab113596b4cd0
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_67_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant:  Can you explain the difference between that and if the first element is the last index of the value?
+User: Oh, that is true that there wouldn't be a difference between those two scenarios. I just reread the problem information and noticed it is supposed to return -1, but I'm unsure how to make sure that is the case. How can you ensure that -1 is what returns?
+Assistant: I believe you know the answer to this question based on how you described the activation of your function. Think about from initialization to `return`, what changes the value of `index`?
+	<alt>If the `if` condition in your `for` loop is never `True`, what would the value of `index` be?
+User: After initialization, it changes only when the value of the element at index `i` of the list `array` is equal to `value`.
+Assistant: And what does that tell you about the case where no element of `array` is equal versus when there is an equal element?
+User: That it will stay at the initialized value until an element of `array` is equal to `value`?
+Assistant: Correct. So how would you return -1 only when no element of `array` is equal to `value`?
+User: Oh! I would just use the initialization value, initializing `index` to -1, which would then return! I made the change, and it works as intended now, thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I am glad that I could help you. Is there anything else I could do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_67_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/train/66_67_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ced4c7015ed0c3bf6f6219811002ea26cf8334cb
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_67_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,55 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_68_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/train/66_68_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..55fbf2d97c46bef7552dd03f956458187da50ba2
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_68_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first part of the body of your function on it?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>What is your function supposed to do?
+User: Line 2.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: Line 2 sets the a variable called index to -1.
+Assistant: Let's look at the loop next, what line does it start on?
+	<alt>Can we add some print statements to figure out what is going on?
+	<alt>Where in the function do you think the problem is?
+User: The loop starts on line 3.
+Assistant: Is there somewhere we could add a print statement to help us figure out what is going on?
+	<alt>Does everything look correct in the values for the loop?
+	<alt>What is the index of the first place in the array that we should check?
+User: We could add a print statement in the loop to check the values.
+Assistant: Where should we put it?
+	<alt>What should we print?
+User: We should add it after line 3.
+Assistant: What should we print?
+	<alt>What are the important values at that spot to help us understand what's wrong?
+	<alt>How would we print the index at that spot?
+	<alt>How would we print the value in the array at that index?
+User: We should print what's in the array at the current index.
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		print(array[i])
+5.		if(value == array[i]):
+6.			index = i
+7.	return index
+</code>
+Assistant: Compare what prints to the test cases, what do you notice?
+	<alt>Is it skipping any values?
+	<alt>What does this tell you about your loop?
+User: It's skipping the first value in all the arrays.
+Assistant: What does that tell you about your loop?
+	<alt>Can you use that to help you find the problem?
+	<alt>Do you have any new ideas about why the test cases are failing?
+User: My loop is wrong, it's not starting at the beginning.
+	<alt>I don't know.
+	<alt>I see! I need to start my loop at zero!
+Assistant: What value in your loop do you need to change to have your loop start in the right place?
+	<alt>What controls where a loop starts?
+	<alt>What are you setting i to?
+User: I need to change the first value in range. It's 1, and it should be 0!
+Assistant: Very good, try that. Does it work now?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: Yes! I removed the print statement and it works now! Thanks.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_68_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/train/66_68_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..708e87160928dd63de6194ffffad8683053baa07
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_68_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,92 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does "range" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does "range" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_1.txt b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..ad0546d69f04b8089be8b6e7319357406bb5440b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_1.txt
@@ -0,0 +1,109 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>What is the next thing your function needs to do?
+	<alt> Okay, let's move on to the next area, what does line 2 do?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: That's probably the loop.
+Assistant: Let's explore the loop a bit. Can you add some print statements to see what's happening?
+	<alt>What variable controls the loop?
+	<alt>What determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: I don't know, where would I put them?
+Assistant: What's a piece of information that would be useful to check what the loop is doing?
+	<alt>What are some important variables in the loop?
+	<alt>How could you check if the loop was starting at all?
+User: I need to know about i and index.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        print(i)
+5.        print(index)
+6.        if(array[i] == value):
+7.            index = i
+8.            break
+9.    return index
+</code>
+Assistant: What happens when you run it?
+User: Nothing prints.
+Assistant: What does that tell you about the loop?
+	<alt>What does that mean about the loop conditions?
+	<alt>Why would a statement not print?
+	<alt>Why would a loop not run?
+User: It means we don't start looping.
+Assistant: Why would a loop not run?
+	<alt>What does that mean about the loop conditions?
+User: There is something wrong with the loop conditions.
+Assistant: Let's check the loop conditions, what controls if the loop loops?
+	<alt>What number is the loop supposed to start on?
+	<alt>What number is the loop supposed to stop on?
+	<alt>What variable are we monitoring?
+	<alt>What are the parameters for range?
+User: It runs if i is between the last index minus 1 of the array and -1.
+Assistant: What is the default step for loops in Python?
+	<alt>What sets i?
+	<alt>Check the Python documentation, what direction do loops move through in Python?
+	<alt>What is the default increment for a range in Python?
+User: Oh! The default step is 1, and I want my number to decrease! It should be -1!
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1,-1,-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: Try it now, does it work?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_2.txt b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..92ba7af635e8a659031c04f4670efda2f404ded1
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_2.txt
@@ -0,0 +1,58 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, I suppose it would be simpler to just count upwards rather than downwards. I made that change and my code is working as expected now.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(0, len(array)-1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_3.txt b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_3.txt
new file mode 100644
index 0000000000000000000000000000000000000000..c39a21aa8745f0b9d2b0e3f945325666f2ee6c05
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_69_last_index_of_conversational_thread_3.txt
@@ -0,0 +1,64 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was working on the `LastIndexOf()` function and it only responds with -1 each time and I cannot understand why.
+Assistant: Can you explain what your function does step by step?
+User: `index` is initialized to -1, then the entire list is iterated in reverse, checking if each element of `array` at index `i` is equivalent to `value`, and if it is setting index equal to that value.
+Assistant: What is important about counting backwards?
+User: We are looking for the greatest index of `value`, searching in reverse would make that faster.
+Assistant: How would you defend against changing the value of `index` when you have already found the last index of `value` in the list?
+User: Oh, I can put in `array[i] == value and i > index`, right?
+Assistant: But if speed was the goal of counting backwards, would you still not process every element of the list?
+	<alt>This would be correct, except there is one issue remaining with how you're using `range()`. Can you see a problem with the numbers you're using as input?
+User: Oh, that is true, but why would it work differently than a forward counting loop?
+Assistant: That is due to the function you are using for your `for` loop. You are using `range(start, end)` which only counts up by 1. Can you give me the form of `range(start, end, step)` you should be using?
+	<alt>Can you notice something awry with your use of the `range()` function as compared to how you've used it in previous assignments?
+User: So that is the difference! It would become `range(len(array)-1, -1, -1)`.
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+Assistant: That is entirely correct.
+	<alt>That is entirely correct! Can you explain why your version would be more efficient than a version that counts upwards, in some scenarios?
+User: Thank you for your help!
+Assistant: I'm glad that I could be of assistance. Is there anything else I can do for you today?
+User: No, that's all for now. Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/66_69_last_index_of_socratic_dialogue.txt b/data/raw/v2_sigcse/train/66_69_last_index_of_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..4efe32adfce0765c4fa1ca09a818307bf2af0d30
--- /dev/null
+++ b/data/raw/v2_sigcse/train/66_69_last_index_of_socratic_dialogue.txt
@@ -0,0 +1,91 @@
+<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/67_70_area_circle_conversational_thread_1.txt b/data/raw/v2_sigcse/train/67_70_area_circle_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..1ee1401cc1a99f412d9dd47826680545134fd346
--- /dev/null
+++ b/data/raw/v2_sigcse/train/67_70_area_circle_conversational_thread_1.txt
@@ -0,0 +1,104 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the radius of the circle in the first test case that is passing?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: The radius of the first test case that is passing is one.
+Assistant: What is the radius of the first test case that is failing?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+User: It's 2.5.
+Assistant: What is the formula for calculating the area of a circle?
+	<alt>That's interesting, do you think there is anything significant about those numbers?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+User: It's Pi times the radius squared.
+Assistant: Let's think about those two different values for the radius. Do they act differently when they are squared?
+	<alt>Okay, let's look at your function now, what line do you do your calculation of area on?
+	<alt>What happens when you square 1?
+	<alt>What is the Python operator for squaring a number?
+User: Yes, 1 squared doesn't change it's still 1, and 2.5 squared is 6.25.
+	<alt>I think made a mistake on the squaring part.
+Assistant: Okay, since it works for 1 but not for 2.5, let's look at the code that does the squaring. Where is that code?
+	<alt>Does 1 have any special properties when you multiply it that might make it act differently?
+	<alt>What is the Python operator for squaring a number?
+User: That's on line 5.
+Assistant: What is the expression that is doing the squaring?
+	<alt>What operator does the squaring?
+User: It is the radius ** radius part.
+Assistant: What does it mean to square a number?
+	<alt>How do you raise a variable to a power?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>What does ** mean?
+User: It means you multiply it times itself.
+Assistant: Okay, so what does ** mean?
+	<alt>What does * mean?
+	<alt>Look back at the Python documentation, how do you raise a variable to a specific value?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: It means to raise to a power.
+	<alt>Oh! I'm raising the radius to itself instead of squaring it!
+Assistant: What should you be doing to the radius?
+	<alt>What does * mean?
+	<alt>Is there a difference between the operators for multiplying and raising to a power?
+User: I'm supposed to multiply it by itself, not raise it to itself!
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius * radius
+</code>
+Assistant: Does it pass the test cases now?
+User: Yes! It passes, thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/67_70_area_circle_socratic_dialogue.txt b/data/raw/v2_sigcse/train/67_70_area_circle_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..34f3649e3a644d508017d090c53ee81b915387bc
--- /dev/null
+++ b/data/raw/v2_sigcse/train/67_70_area_circle_socratic_dialogue.txt
@@ -0,0 +1,101 @@
+<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/69_81_get_combinations_conversational_thread_1.txt b/data/raw/v2_sigcse/train/69_81_get_combinations_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..df5545a0a6f74caa3dad6309a70036bf3bfb7816
--- /dev/null
+++ b/data/raw/v2_sigcse/train/69_81_get_combinations_conversational_thread_1.txt
@@ -0,0 +1,74 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What controls the loop?
+	<alt>What is the variable name for the iterator made on line 3?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: Range determines the number of times the loop runs.
+Assistant: Now let's look at line 4, how many times will that loop run?
+	<alt>What iterator is made on line 4?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: It will start at i and run until the end of the list.
+	<alt>I'm supposed to start at 0 not i!
+Assistant: Where in the array list should we start for the second term?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+User: We should start at the beginning.
+Assistant: Is it always at the beginning of the list?
+	<alt>Should we start at 0?
+	<alt>Are there any combinations we are trying to skip?
+	<alt>Where could we add some print statements to better understand what is happening in those loops?
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+User: I see! I should have it start at 0, not i!
+Assistant: Does it run correctly now?
+User: Yes, it does! Thank you.
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/69_81_get_combinations_socratic_dialogue.txt b/data/raw/v2_sigcse/train/69_81_get_combinations_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..b3ad9e28b9515a3dadc9f794e4da6fab5b07af13
--- /dev/null
+++ b/data/raw/v2_sigcse/train/69_81_get_combinations_socratic_dialogue.txt
@@ -0,0 +1,87 @@
+<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/74_77_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/train/74_77_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..85bc61a327c01e6e185b9b9f5ef9845c41c43abb
--- /dev/null
+++ b/data/raw/v2_sigcse/train/74_77_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,78 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/74_78_disney_vacation_club_conversational_thread_1.txt b/data/raw/v2_sigcse/train/74_78_disney_vacation_club_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..44f2431c86f5be0e8e24678162fcd131ce15a1d4
--- /dev/null
+++ b/data/raw/v2_sigcse/train/74_78_disney_vacation_club_conversational_thread_1.txt
@@ -0,0 +1,101 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Could we add some print statements to check the math?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+User: Yes, we could add some to see what's happening, but I don't know where to put them.
+	<alt>I could add one in the loop to see what's happening with the fee.
+Assistant: Okay, look at the code, what are some important variables in your calculations?
+	<alt>How would you print the number of years to see how far off the answer is from the test case?
+User: Well, years is important, and so is total fee and current fee.
+Assistant: Let's print those, where should we put the print statements?
+User: We could put them after line 7 in the loop.
+	<alt>I don't know.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        print(years)
+9.        print(total_fee)
+10.        print(current_fee)
+11.        total_fee = current_fee*(1.015**years)
+12.        years += 1
+13.
+14.    return years
+</code>
+Assistant: Look at the printed output, do you see anything odd?
+	<alt>Look at the printed output, what is the value for years?
+	<alt>Look at the printed output, why do you think it is repeating?
+User: It's doing zero years first. That isn't right, it's supposed to start at 1.
+Assistant: What line determines that?
+	<alt>Where is years incremented?
+User: Line 12.
+Assistant: What should you do with line 12?
+	<alt>Is that line where it should be?
+User: I see! I'll move it up above the calculation.
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+Assistant: Try it now. Does it pass the test cases?
+User: Yes! It works, thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/74_78_disney_vacation_club_socratic_dialogue.txt b/data/raw/v2_sigcse/train/74_78_disney_vacation_club_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..8fea1e119b4c9f9003729bd7fc729f6a990d8527
--- /dev/null
+++ b/data/raw/v2_sigcse/train/74_78_disney_vacation_club_socratic_dialogue.txt
@@ -0,0 +1,95 @@
+<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual "maintenance fee" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of "years" in line 8?
+	<alt>Where does "current_fee" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_1.txt b/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..3c7103d150a8fae622f5cff05c825a71aa2b3d3b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_1.txt
@@ -0,0 +1,98 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Probably before `my_func` so on line 3 I can insert my function definition for `yOf(x)`.
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. Are you planning to declare a function inside of another function?
+User: Yes. It's called a nested function! Let me edit my code. Ah I see that `x` is not defined, but I do define it on line 5.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: What is the scope of the parameters declared for the function `yOf`?
+	<alt>Where can `x` be used?
+User: Oh the scope is only line 6. I see it. I don't need `x` on line 6 since I am the `map` function takes care of passing each element in `range(len)` to `yOf` as the parameter `x`. Let me edit my code.
+<code>
+1. import random as rand
+2.rand.seed(42)
+3. def my_func(len):
+4.    def yOf(x):
+5.        return  x * 6 + rand.randint(1, len)
+6.    y = list(map(yOf, range(len)))
+7.    return y 
+
+</code>
+Assistant: Good. Have you tried your code for all examples?
+User: Yes it does! Thank you for your help today!
+Assistant: You're welcome! Let me know if you have any other questions!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_2.txt b/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_2.txt
new file mode 100644
index 0000000000000000000000000000000000000000..0541576191cb148319873bc12fe44df30da7034b
--- /dev/null
+++ b/data/raw/v2_sigcse/train/8_36_plot_function_conversational_thread_2.txt
@@ -0,0 +1,88 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: It seems to be the case. Not really sure though what to do though.
+Assistant: You wanted to learn more about the `map` function and how to use it in this problem. What is a good resource for you to find examples where the `map` function is being used?
+	<alt>Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Ah. Let me look at the Python documentation for the `map` function. After looking through some examples -- I see `lambda` being used with `map` quite often for example you can declare a list `numbers = [1, 2, 3, 4]` and then use the map function with `lambda` like this `result = map(lambda x: x + x, numbers)`.
+Assistant: Good find. Let's try it in the terminal and printing `result` as a list. What do you observe is being stored in `result`?
+User: I observe `[2, 4, 6, 8]` as the output.
+Assistant: Given that, what do you think the `lambda` did in the snippet here?
+	<alt>Can you describe what `lambda` does?
+User: It seemed to have summed up each element in `numbers` with itself so `[1 +  1,  2 + 2, 3 + 3, 4 + 4]` so I guess `x` in `lambda` represent each element in `numbers`.
+Assistant: Good. So looking at our programming exercises. Do you see a use for `lambda` in your code?
+	<alt>Good. Now, where can you use `lambda` in your programming exercise?
+	<alt>Good. Do you see a use of `lambda` in your `map` function call on line 5?
+User: Ah yes! I'll replace my messy function declaration with `lambda`. I think it works!
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def my_func(len):
+4.    y = list(map(lambda x:  x * 6 + rand.randint(1, len),  range(len)))
+5.    return y
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes it does! Thank you! I learned more about `map` and `lambda` today!
+Assistant: You're welcome!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/8_36_plot_function_socratic_dialogue.txt b/data/raw/v2_sigcse/train/8_36_plot_function_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..870ad5e7b0b17adc1ce3dc2b559e19dbd05b7b75
--- /dev/null
+++ b/data/raw/v2_sigcse/train/8_36_plot_function_socratic_dialogue.txt
@@ -0,0 +1,147 @@
+<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/9_38_calculating_determinant_conversational_thread_1.txt b/data/raw/v2_sigcse/train/9_38_calculating_determinant_conversational_thread_1.txt
new file mode 100644
index 0000000000000000000000000000000000000000..aedba6fbbb1b6c8a599e81442bb390529b5d6c8c
--- /dev/null
+++ b/data/raw/v2_sigcse/train/9_38_calculating_determinant_conversational_thread_1.txt
@@ -0,0 +1,71 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange `TypeError` in my helper function
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices
+Assistant: Ok, let's start with your helper function `det2d` then. What are you trying to do there?
+	<alt>Can you describe the inputs and outputs of your helper function?
+	<alt>How does your `det2d` function work with the `determinant` function? How do they interact with each other?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices that you're passing to the helper function `det2d`?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+User: I am using this function to calculate the determinant of a 2x2 submatrix. Then, I'll compute the determinant of the 3x3 matrix using those submatrix determinants.
+Assistant: Good. How can you verify that you are computing the determinant of a 2x2 matrix correctly?
+	<alt>What happens if you pass an array with the incorrect dimensions to this function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I looked through an online resource. My code matches the formula, and I tested it with some simple matrices. I use a 2x2 matrix represented as an array of arrays. The first index represents the row and the second index represents the column number. To access a specific value, I select a row array and then get the value from that array.
+Assistant: Ok. How can you verify that `matrix` is a 2x2 matrix?
+	<alt>What happens if you pass an array with the incorrect dimensions to the `det2d` function?
+	<alt>What would happen if you passed in a 1x1 matrix as `matrix`?
+	<alt>How can you verify that `matrix` is a 2x2 matrix?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I think that's the issue. It looks like I accidentally passed in my values as a 1D array. I'll add a set of brackets. It looks like `subm2` and `subm3` both have this issue
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+Assistant: It looks like your code works now!
+</dialogue>
\ No newline at end of file
diff --git a/data/raw/v2_sigcse/train/9_38_calculating_determinant_socratic_dialogue.txt b/data/raw/v2_sigcse/train/9_38_calculating_determinant_socratic_dialogue.txt
new file mode 100644
index 0000000000000000000000000000000000000000..58c862ac4e04af16882183dffb51173e9b65f10f
--- /dev/null
+++ b/data/raw/v2_sigcse/train/9_38_calculating_determinant_socratic_dialogue.txt
@@ -0,0 +1,67 @@
+<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says "'int' object is not subscriptable" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `"'int' object is not subscriptable"` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>
\ No newline at end of file
diff --git a/data/testset.csv b/data/testset.csv
new file mode 100644
index 0000000000000000000000000000000000000000..5094781be98362bd47d84a960391a47233fa0ef4
--- /dev/null
+++ b/data/testset.csv
@@ -0,0 +1,954 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x <= seq[i]:
+     return i",The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.,"Insert a line following line 4, with one indentation containing `return len(seq)`","assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_45_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n</bug_code>\n<bug_desc>\nThe function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.\n</bug_desc>\n<bug_fixes>\nInsert a line following line 4, with one indentation containing `return len(seq)` \n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output.'}, {'role': 'assistant', 'content': 'What inputs have you tried? When do you get `None`?', 'alt': ['Do you notice a pattern with the cases that produce `None`?', 'When do you notice `None` as the output?', 'What inputs have you tried? When do you get `None`?', 'It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?']}, {'role': 'user', 'content': 'I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.', 'alt': ['I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list', 'It seems like I get the wrong answer when `x` is bigger than all the existing list elements']}, {'role': 'assistant', 'content': 'Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?', 'alt': ['Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?', 'What do you expect your code to return when `x` is bigger than the `seq` elements?']}, {'role': 'user', 'content': 'Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.'}, {'role': 'assistant', 'content': 'What happens if `x` is not less than or equal to any element?', 'alt': ['What does your code do if `x` is greater than all of the elements in `seq`?']}, {'role': 'user', 'content': ""I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!\n```python\n def search(x, seq):    \n  for i in range(len(seq)):\n    if x <= seq[i]:\n      return i\n  return len(seq)\n```""}, {'role': 'assistant', 'content': 'Good work. Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x < seq[i]:
+     return i
+ return len(seq)","On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.",Replace `<` with `<=` on line 3,"assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_44_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x < seq[i]:\n4.      return i\n5.  return len(seq)\n</bug_code>\n<bug_desc>\nOn line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.\n</bug_desc>\n<bug_fixes>\nReplace `<` with `<=` on line 3\n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?""}, {'role': 'assistant', 'content': 'Sure. In the first test case, can you explain why the correct returned value should be 1?', 'alt': ['Sure. Can you tell me if you notice any difference between the first test case and the other test cases?', 'Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?', ""Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?""]}, {'role': 'user', 'content': 'The correct answer is 1 because 5 is found at position 1 in the input list.'}, {'role': 'assistant', 'content': 'Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?', 'alt': ['Good. What does your code do when position `i = 1`?']}, {'role': 'user', 'content': 'Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!\n```python\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n5.  return len(seq)\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could help.""}]}"
+"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?
+Assistant: Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?
+User: For `n = 1` or larger it returns the same value, 0.
+Assistant: Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?
+	<alt>Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?
+	<alt>Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?
+	<alt>Can you tell me what `range(n)` does?
+User: The first value assigned to `i` will be 1.
+	<alt>Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.
+Assistant: Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?
+	<alt>Can you explain why `i` will be equal to 1 during the first iteration of the for loop?
+	<alt>Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?
+User: I don’t know, how can I verify that?
+	<alt>OK, let me print its value at each iteration.
+	<alt>OK, let me check in the Python documentation what range does.
+Assistant: Can you edit the code to print the value of `i` at each iteration of the for loop?
+	<alt>Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?
+	<alt>Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?
+	<alt>Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?
+	<alt>Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?
+User: Sure … Aaah, I see, the first value is 0, not 1!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i
+8.        return fact
+
+</code>
+	<alt>How do I do that?
+Assistant: How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?
+	<alt>Why do you think the first value is 0?
+	<alt>Good! Can you explain how that makes the function return 0 for n = 1 or larger?
+	<alt>Good! What can you do now to fix the issue?
+User: I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * i + 1
+8.        return fact
+
+</code>
+	<alt>I can change it to `range(1, n + 1)` so that it starts iterating at 1.
+	<alt>I can change it to `range(1, n)` so that it starts iterating at 1.
+	<alt>I can change it to `range(n) + 1`, so that the first value is 0 + 1.
+	<alt>I don’t know, can you help?
+Assistant: Can you also try it with `n = 2` and `n = 3`?
+	<alt>Do you think your code will work for all values of `n`, for example `n = 3`?
+User: Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.
+Assistant: The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?
+	<alt>Why is the code giving an incorrect answer for n = 3?
+	<alt>What should the output of factorial(3) be?
+User: Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                print(i)
+7.                fact = fact * (i + 1)
+8.        return fact
+
+</code>
+Assistant: You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.
+User: Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.
+<code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * (i + 1)
+7.        return fact
+
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```","def factorial(n):
+       if n < 0:
+               return 0
+       fact = 1
+       for i in range(n):
+               fact = fact * i
+       return fact","On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n","Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.","assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120",24_29_factorial,"<problem>
+Write a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:
+
+$0! = 1$
+$n! = n \times (n - 1)!$
+
+Additionally, if the input integer n is negative the function should return 0.
+
+## Example Cases:
+```
+factorial(-1) => 0
+factorial(0) => 1
+factorial(1) => 1
+factorial(2) => 2
+factorial(3) => 6
+factorial(4) => 24
+factorial(5) => 120
+```
+</problem>
+<bug_code>
+1. def factorial(n):
+2.        if n < 0:
+3.                return 0
+4.        fact = 1
+5.        for i in range(n):
+6.                fact = fact * i
+7.        return fact
+</bug_code>
+<bug_desc>
+On line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n
+
+</bug_desc>
+<bug_fixes>
+Replace `i` with `(i + 1)` in line 6.
+Replace `range(n)` with `range(1, n + 1)` in line 5.
+</bug_fixes>
+<unit_tests>
+assert factorial(-1) == 0
+assert factorial(0) == 1
+assert factorial(1) == 1
+assert factorial(2) == 2
+assert factorial(3) == 6
+assert factorial(4) == 24
+assert factorial(5) == 120
+</unit_tests>
+","{'system': '<problem>\nWrite a function `factorial(n:int) -> int` that computes the factorial n! of a natural number n, which is defined mathematically as:\n\n$0! = 1$\n$n! = n \\times (n - 1)!$\n\nAdditionally, if the input integer n is negative the function should return 0.\n\n## Example Cases:\n```\nfactorial(-1) => 0\nfactorial(0) => 1\nfactorial(1) => 1\nfactorial(2) => 2\nfactorial(3) => 6\nfactorial(4) => 24\nfactorial(5) => 120\n```\n</problem>\n<bug_code>\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * i\n7.        return fact\n</bug_code>\n<bug_desc>\nOn line 6, `fact` is multiplied with 0 in the first iteration of the for loop. Consequently, at every iteration fact stays equal with 0 instead of being updated to be equal with factorial of `(i + 1)`. Therefore, the function will return 0, irrespective of n\n\n</bug_desc>\n<bug_fixes>\nReplace `i` with `(i + 1)` in line 6.\nReplace `range(n)` with `range(1, n + 1)` in line 5.\n</bug_fixes>\n<unit_tests>\nassert factorial(-1) == 0\nassert factorial(0) == 1\nassert factorial(1) == 1\nassert factorial(2) == 2\nassert factorial(3) == 6\nassert factorial(4) == 24\nassert factorial(5) == 120\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the factorial function but it doesn’t work and I do not know why. Can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you tell me for what values of `n` it fails and what values it returns in those cases?'}, {'role': 'user', 'content': 'For `n = 1` or larger it returns the same value, 0.'}, {'role': 'assistant', 'content': 'Let’s see what happens when `n` is 1. What is the first value that is assigned to variable `i` in line 5?', 'alt': ['Let’s see what happens when `n` is 1. Before line 6 is evaluated in the first iteration of the for loop, what are the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. Can you insert a new line between lines 5 and 6 that prints the values of the variables `fact` and `i`?', 'Let’s see what happens when `n` is 1. What does `range(n)` do when `n` is 1?', 'Can you tell me what `range(n)` does?']}, {'role': 'user', 'content': 'The first value assigned to `i` will be 1.', 'alt': ['Aaah, I understand! The first value assigned to `i` will be 0, because range by default starts at 0.']}, {'role': 'assistant', 'content': 'Are you sure about that? Can you verify that indeed the first value assigned to `i` is 1?', 'alt': ['Can you explain why `i` will be equal to 1 during the first iteration of the for loop?', 'Let’s assume that `i` is equal to 1 during the first iteration of the for loop. Given that `fact` is assigned the value 1 on line 4, how do you explain the function returning 0 when `n` is 1?']}, {'role': 'user', 'content': 'I don’t know, how can I verify that?', 'alt': ['OK, let me print its value at each iteration.', 'OK, let me check in the Python documentation what range does.']}, {'role': 'assistant', 'content': 'Can you edit the code to print the value of `i` at each iteration of the for loop?', 'alt': ['Can you look in the Python documentation to see what is the first value computed by range, when used with only one argument?', 'Let’s consider this mathematically, `fact` is assigned the value of 1 on line 4. `fact` is multiplied by all values of `i` in a range. What value would `i` need to be for `fact` to be equal to 0 after the for loop?', 'Let’s try it out on the terminal. Open the Python terminal using the `python` command. Then, type in a for loop similar to yours with `n` being 2. Then, in your for loop body, add in a print statement that prints `i`. What do you observe?', 'Let’s open the debugger. Step through your code until you reach line 6 for the first time. What do you notice about the value of `i`?']}, {'role': 'user', 'content': 'Sure … Aaah, I see, the first value is 0, not 1!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i\n8.        return fact\n```', 'alt': ['How do I do that?']}, {'role': 'assistant', 'content': 'How can you fix the code so that in the first iteration `fact` is multiplied with 1, not with 0?', 'alt': ['Why do you think the first value is 0?', 'Good! Can you explain how that makes the function return 0 for n = 1 or larger?', 'Good! What can you do now to fix the issue?']}, {'role': 'user', 'content': 'I will multiply fact with `i + 1`. Let me do that … It works! Thank you for your help!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * i + 1\n8.        return fact\n```', 'alt': ['I can change it to `range(1, n + 1)` so that it starts iterating at 1.', 'I can change it to `range(1, n)` so that it starts iterating at 1.', 'I can change it to `range(n) + 1`, so that the first value is 0 + 1.', 'I don’t know, can you help?']}, {'role': 'assistant', 'content': 'Can you also try it with `n = 2` and `n = 3`?', 'alt': ['Do you think your code will work for all values of `n`, for example `n = 3`?']}, {'role': 'user', 'content': 'Hmm … it returns the correct value for `n = 2`, but for `n = 3` it returns 3, which is wrong.'}, {'role': 'assistant', 'content': 'The code you edited in line 7 was supposed to multiply `fact` with `i + 1`. Does that code really multiply `fact` with `i + 1`?', 'alt': ['Why is the code giving an incorrect answer for n = 3?', 'What should the output of factorial(3) be?']}, {'role': 'user', 'content': 'Aaaah, I see now, I should have used parentheses around `i + 1`. Let me do that … It works now! Thank you so much!\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                print(i)\n7.                fact = fact * (i + 1)\n8.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome! Do not forget to remove the `print` statement and try it for other values of n as well.'}, {'role': 'user', 'content': 'Yes, I forgot about that. Here it is … It works for all test cases! Thanks again.\n```python\n1. def factorial(n):\n2.        if n < 0:\n3.                return 0\n4.        fact = 1\n5.        for i in range(n):\n6.                fact = fact * (i + 1)\n7.        return fact\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `""E""` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+12. store = turn_clockwise(""N"")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == ""N"":
+        return ""E""
+    elif compass_point == ""E"":
+        return ""S""
+    elif compass_point == ""S"":
+        return ""W""
+    elif compass_point == ""W"":
+        return ""N""
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point == ""N"":
+       print (""E"")
+   elif compass_point == ""E"":
+       print (""S"")
+   elif compass_point == ""S"":
+       print (""W"")
+   elif compass_point == ""W"":
+       print (""N"")
+   else:
+       print (""None"")","The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.","Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_33_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '\ufeff<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value `None`.\n\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n</bug_code>\n<bug_desc>\nThe function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.\n</bug_desc>\n<bug_fixes>\nReplace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I have a problem. My code does not generate the right result and I cannot figure that out.'}, {'role': 'assistant', 'content': ""Hi! Let's take a look at your code. Could you explain how your code works?"", 'alt': ['Hi! What makes you think that your program is not working properly?', 'Can you give me an example where your code does not return the correct result?', 'I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?']}, {'role': 'user', 'content': 'Ok. My code gets the current `compass_point` and prints the next one.'}, {'role': 'assistant', 'content': 'What do you see as your output in the terminal and what are you passing as `compass_point`?', 'alt': ['What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?']}, {'role': 'user', 'content': 'When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That\'s strange since my output is printed correctly, but my program does not pass any of the tests.'}, {'role': 'assistant', 'content': 'What does a unit test need from a function to ensure that the function works properly?', 'alt': ['Ah. How did you determine whether your function is correct?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?', 'Say you want to store the output of your function into a variable, what would you need to do?', 'What do you think a function needs to pass along its output to say get stored in a variable?']}, {'role': 'user', 'content': 'It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.', 'alt': [""I don't understand the question. Can you tell me more about unit tests?""]}, {'role': 'assistant', 'content': 'Correct. So would you be able to store the value outputted by the function into say a variable?', 'alt': ['Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?']}, {'role': 'user', 'content': 'Hypothetically yes. I should be able to store it in a variable. I have not tried though.'}, {'role': 'assistant', 'content': 'Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'alt': ['Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?']}, {'role': 'user', 'content': 'Ah I think, it would be `""E""` in `store`.'}, {'role': 'assistant', 'content': 'Let’s try it and then print `store`. What do you observe in your terminal?'}, {'role': 'user', 'content': 'Hmm... I see `None`. That’s really strange.\n\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n12. store = turn_clockwise(""N"")\n13. print(store)\n```'}, {'role': 'assistant', 'content': 'What do you think the function needs to have in order to give its output to the variable?', 'alt': ['Do you recall, which reserved word in Python is used to return the output for a function back to a variable?']}, {'role': 'user', 'content': 'Ah! I think it might be `return`. Let me try that.\n```python\ndef turn_clockwise(compass_point):\n    if compass_point == ""N"":\n        return ""E""\n    elif compass_point == ""E"":\n        return ""S""\n    elif compass_point == ""S"":\n        return ""W""\n    elif compass_point == ""W"":\n        return ""N""\n    else:\n        return None\n\t\t\n```', 'alt': ['I’m not really sure.']}, {'role': 'assistant', 'content': 'Very good.', 'alt': ['Very good. Is there a way for you to simplify your code?']}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You’re welcome! Let me know if I can be of any further help.'}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with the code can you help me? It's throwing an error.
+Assistant: What is the error that you observe?
+	<alt>Let's start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you describe what your code is trying to do?
+User: I have a syntax error on line 2. I'm not sure why.
+	<alt>The terminal says ""SyntaxError: invalid syntax""
+Assistant: Can you describe what you are trying to do on line 2?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+	<alt>What operator do you use to check for equality?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+User: I am trying to check if `compass_point` is equal to ""N""
+Assistant: What operator do you use to check for equality?
+	<alt>Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>What operator do you use to assign a value?
+User: I use the `=` operator to check for equality.
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?
+	<alt>Can you show me how you would assign the value 1 to a variable `x`?
+	<alt>What operator do you use to assign a value?
+User: I would use `compass_point = ""N""`
+	<alt>Oh! I should be using `==` instead of `=` to check equality
+Assistant: Are you sure that you can use the same operator `=` for assignment and to check for equality?
+User: Oh! Probably not. What operator should I use?
+	<alt>Oh! I checked the documentation. I should be using `==` instead of `=` to check equality
+Assistant: Can you look in the Python documentation to see what operator is used to check for equality?
+User: Oh I found it! I should use `==` instead of `=`. Let me edit my code!
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        return ""E""
+4.    elif compass_point == ""E"":
+5.        return ""S""
+6.    elif compass_point == ""S"":
+7.        return ""W""
+8.    elif compass_point == ""W"":
+9.        return ""N""
+10.   else:
+11.        return None
+
+</code>
+Assistant: Good job. Look good. Let me know if you have any more questions.
+User: Thank you! Goodbye!
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point = ""N"":
+       return ""E""
+   elif compass_point = ""E"":
+       return ""S""
+   elif compass_point = ""S"":
+       return ""W""
+   elif compass_point = ""W"":
+       return ""N""
+   else:
+       return None","There are syntax errors on lines 2, 4, 6, and 8.","Replace `=` with `==` on lines 2, 4, 6, and 8.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_34_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value None.
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point = ""N"":
+3.        return ""E""
+4.    elif compass_point = ""E"":
+5.        return ""S""
+6.    elif compass_point = ""S"":
+7.        return ""W""
+8.    elif compass_point = ""W"":
+9.        return ""N""
+10.    else:
+11.        return None
+</bug_code>
+<bug_desc>
+There are syntax errors on lines 2, 4, 6, and 8.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on lines 2, 4, 6, and 8.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value None.\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point = ""N"":\n3.        return ""E""\n4.    elif compass_point = ""E"":\n5.        return ""S""\n6.    elif compass_point = ""S"":\n7.        return ""W""\n8.    elif compass_point = ""W"":\n9.        return ""N""\n10.    else:\n11.        return None\n</bug_code>\n<bug_desc>\nThere are syntax errors on lines 2, 4, 6, and 8.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on lines 2, 4, 6, and 8.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with the code can you help me? It's throwing an error.""}, {'role': 'assistant', 'content': 'What is the error that you observe?', 'alt': ['Let\'s start with a warm-up exercise. How do you assign the value ""N"" to a variable `compass_point`?', 'Can you describe what your code is trying to do?']}, {'role': 'user', 'content': ""I have a syntax error on line 2. I'm not sure why."", 'alt': ['The terminal says ""SyntaxError: invalid syntax""']}, {'role': 'assistant', 'content': 'Can you describe what you are trying to do on line 2?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?', 'What operator do you use to check for equality?', 'Can you show me how you would assign the value 1 to a variable `x`?']}, {'role': 'user', 'content': 'I am trying to check if `compass_point` is equal to ""N""'}, {'role': 'assistant', 'content': 'What operator do you use to check for equality?', 'alt': ['Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I use the `=` operator to check for equality.', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Ah. Can you show me how you would assign the value ""N"" to a variable `compass_point`?', 'alt': ['Can you show me how you would assign the value 1 to a variable `x`?', 'What operator do you use to assign a value?']}, {'role': 'user', 'content': 'I would use `compass_point = ""N""`', 'alt': ['Oh! I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Are you sure that you can use the same operator `=` for assignment and to check for equality?'}, {'role': 'user', 'content': 'Oh! Probably not. What operator should I use?', 'alt': ['Oh! I checked the documentation. I should be using `==` instead of `=` to check equality']}, {'role': 'assistant', 'content': 'Can you look in the Python documentation to see what operator is used to check for equality?'}, {'role': 'user', 'content': 'Oh I found it! I should use `==` instead of `=`. Let me edit my code!\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        return ""E""\n4.    elif compass_point == ""E"":\n5.        return ""S""\n6.    elif compass_point == ""S"":\n7.        return ""W""\n8.    elif compass_point == ""W"":\n9.        return ""N""\n10.   else:\n11.        return None\n```'}, {'role': 'assistant', 'content': 'Good job. Look good. Let me know if you have any more questions.'}, {'role': 'user', 'content': 'Thank you! Goodbye!'}]}"
+"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?
+Assistant: Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice.
+	<alt>Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.
+	<alt>Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?
+	<alt>Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?
+	<alt>Sure. Can you go through your code line by line and explain to me what each line is supposed to do?
+	<alt>Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?
+	<alt>Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?
+	<alt>Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?
+User: I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?
+	<alt>That is correct. Do you know how to append a new element to a list?
+User: I did that, but when I run my code I get a `KeyError` message in line 4.
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] += [value]
+5.         print('key = ', key, ' value = ', result[key])
+6.    return result
+7.
+8.my_func([(1, 2), (1, 3)])
+
+</code>
+Assistant: Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict
+	<alt>Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?
+	<alt>Do you know what happens when you try to get a value using a key that does not exist in the dictionary?
+User: It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.        print('key = ', key, ' value = ', result[key])
+9.    return result
+10.
+11.my_func([(1, 2), (1, 3)])
+
+</code>
+	<alt>It is raised when `key` is not in the map.
+Assistant: Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?
+User: I did that and it works on all test cases. Thank you!
+<code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.        if key in result:
+5.            result[key] += [value]
+6.        else:
+7.            result[key] = [value]
+8.    return result
+
+</code>
+Assistant: You're welcome, I am glad I could be of help.
+</dialogue>","Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```","def my_func(valList):
+   result = {}
+   for key, value in valList:
+        result[key] = [value]
+   return result","The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.","Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`","assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}",7_35_integer_grouping,"<problem>
+Implement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where
+`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.
+Return a dictionary where the:
+* key: first elements of `valList`
+* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.
+
+```py
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+```
+In the example above:
+
+* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`
+* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`
+* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`
+
+## Example Cases:
+```
+my_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}
+my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+my_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+```
+</problem>
+<bug_code>
+1. def my_func(valList):
+2.    result = {}
+3.    for key, value in valList:
+4.         result[key] = [value]
+5.    return result
+</bug_code>
+<bug_desc>
+The function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  
+</bug_desc>
+<bug_fixes>
+Replace line 4 with the following lines:
+```py
+if key in result.keys():
+      result[key].append(value)
+else:
+      result[key] = [value]
+```
+Replace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`
+</bug_fixes>
+<unit_tests>
+assert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}
+assert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}
+assert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}
+</unit_tests>
+","{'system': '<problem>\nImplement a function `my_func(valList:List[Tuple[int,int]])->Dict[int,List[int]]` where\n`valList` is a list of `n` tuples where each tuple contains two integers `a,b` `(1<=a,b)`.\nReturn a dictionary where the:\n* key: first elements of `valList`\n* value: list containing all the second elements of the tuples in `valList` that have the same first element as the key.\n\n```py\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\n```\nIn the example above:\n\n* Tuples with 6 as the first element are `(6, 5)` so the value for key 6 is `[5]`\n* Tuples with 2 as the first element are `(2, 7)`, `(2, 5)`, and `(2, 7)` so the value for key 2 is `[7, 5, 7]`\n* Tuples with 8 as the first element are `(8, 7)` and `(8, 9)` so the value for key 8 is `[7, 9]`\n\n## Example Cases:\n```\nmy_func([(1, 1),(2, 2),(3, 3)]) => {1: [1], 2: [2], 3: [3]}\nmy_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) => {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nmy_func([(-78, 13),(-9, 2),(10, 2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) => {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n```\n</problem>\n<bug_code>\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.    return result\n</bug_code>\n<bug_desc>\nThe function assigns a list of one element to each key in the dictionary `result` on line 4. Consequently, each list in the dictionary contains exactly one element instead of all the second elements of the tuples in `valList` that have the same first element as the key.  \n</bug_desc>\n<bug_fixes>\nReplace line 4 with the following lines:\n```py\nif key in result.keys():\n      result[key].append(value)\nelse:\n      result[key] = [value]\n```\nReplace line 4 with: `result[key] = [value] if key not in result else result[key] + [value]`\n</bug_fixes>\n<unit_tests>\nassert my_func([(1, 1),(2, 2),(3, 3)]) == {1: [1], 2: [2], 3: [3]}\nassert my_func([(6, 5),(2, 7),(2, 5),(8, 7),(8, 9),(2, 7)]) == {6: [5], 2: [7, 5, 7], 8: [7, 9]}\nassert my_func([(-78, 13),(-9, 2),(10,2), (-78, 45), (-9, 2), (10, -78), (-9, 22)]) == {-78: [13, 45], -9: [2, 2, 22], 10: [2, -78]}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help, my code seems to always create dictionary values that contain only one element, which works for the first test case, but not for the rest. Can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's try to see what happens with your dictionary values during the execution of the program. Inside the for loop, after line 4, can you add code that prints the key and the value stored in `results[key]`? Then evaluate the function on the list `[(1, 2), (1, 3)]` and tell me what you notice."", 'alt': ['Sure. Can you evaluate the function twice, once on the list `[(1, 2), (1, 3)]`, and once on `[(1, 3), (1, 2)]`? Then see if you notice anything interesting.', 'Sure. Looking at the second test case, your code does not work well for keys that appear multiple times as the first elements in the input tuples. Can you say what happens on line 4 in your code the second time it sees 6 as a key? What is already stored in `result[key]` before line 4 is executed, and what will be stored in `result[key]` after line 4 is executed?', ""Sure. Looking at the second test case, let's say that the variable `results` already maps the key 2 to value `[7]`. What happens in line 4 when the variable `key` is 2 and the variable `value` is 5? To what value will the `result` map the key 2 after executing line 4?"", 'Sure. Can you go through your code line by line and explain to me what each line is supposed to do?', 'Sure. Do you notice anything different about the second and third test cases that makes your code output the wrong result, when compared with the first test case?', 'Sure. Looking at the second test case and your code output for it, what is the value that it includes for key 2 in the result and what are the values that it ignores for the same key?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `[1]`, e.g., `a = [1]`, what value will it have after you evaluate the new assignment statement `a = [2]`?', 'Sure. Let me ask you a warm-up question first. If you have a variable `a` that is initially assigned the value `1`, e.g., `a = 1`, what value will it have after you evaluate the new assignment statement `a = 2`?']}, {'role': 'user', 'content': ""I did that and I think I see what the problem is. When the code encountered the value 3, instead of appending it to the list of previous values, it created a new list...\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] = [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Good observation. Can you now edit your code so that, if the key is already in the dictionary, it appends the new value for that key?', 'alt': ['That is correct. Do you know how to append a new element to a list?']}, {'role': 'user', 'content': ""I did that, but when I run my code I get a `KeyError` message in line 4.\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.         result[key] += [value]\n5.         print('key = ', key, ' value = ', result[key])\n6.    return result\n7.\n8.my_func([(1, 2), (1, 3)])\n```""}, {'role': 'assistant', 'content': 'Can you read in the Python documentation the section on the `dict` built-in type and see when `KeyError` is raised? Here is the link: https://docs.python.org/3/library/stdtypes.html#dict', 'alt': ['Can you change your current code and in line 2 initialize `result = {1: 0}`, then run it on the same example and see if you notice anything different?', 'Do you know what happens when you try to get a value using a key that does not exist in the dictionary?']}, {'role': 'user', 'content': ""It is raised when `key` is not in the map. Oh, I see, I need an if to check if `key` is in the map. Let me try it... It works now!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.        print('key = ', key, ' value = ', result[key])\n9.    return result\n10.\n11.my_func([(1, 2), (1, 3)])\n```"", 'alt': ['It is raised when `key` is not in the map.']}, {'role': 'assistant', 'content': 'Very good! Can you now remove the print statement and restore the test cases, so that you can verify your code passes all of them?'}, {'role': 'user', 'content': 'I did that and it works on all test cases. Thank you!\n```python\n1. def my_func(valList):\n2.    result = {}\n3.    for key, value in valList:\n4.        if key in result:\n5.            result[key] += [value]\n6.        else:\n7.            result[key] = [value]\n8.    return result\n```'}, {'role': 'assistant', 'content': ""You're welcome, I am glad I could be of help.""}]}"
diff --git a/data/train.csv b/data/train.csv
new file mode 100644
index 0000000000000000000000000000000000000000..12c5e02ad440d7ec1a318bef7c5138e29c7c36da
--- /dev/null
+++ b/data/train.csv
@@ -0,0 +1,7492 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f""a: {a}\tb: {b}\t i: {i}"")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>
+","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n <= 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+    a = 0
+   b = 1
+   for i in range(0, n):
+     temp = b
+     b = a + b
+     a = temp
+   return b","On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.","Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.","assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_0_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(0, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.\n</bug_desc>\n<bug_fixes>\nReplace `range(0, n)` with `range(1, n)` on line 11.\nReplace `range(0, n)` with `range(0, n - 1)` on line 11.\nReplace `range(0, n)` with `range(2, n + 1)` on line 11.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\nThe student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey, I really need help. This function is not returning the correct number.'}, {'role': 'assistant', 'content': ""I'll be happy to help you. What happens when you call `fibonacci(5)`?"", 'alt': ['Happy to help. Can you give me an example of your function returning an incorrect number?', 'Sure. Can you list the first 5 numbers in the Fibonacci sequence?', 'Can you describe what your code does line by line?']}, {'role': 'user', 'content': 'When I run the function with `n` as 5 the output is 8 instead of 5.'}, {'role': 'assistant', 'content': 'I see. What do you think might be the cause of this?', 'alt': ['Can you describe your for loop on line 11?', 'Can you walk me through the steps your function takes to generate the Fibonacci sequence?', 'Can you identify any issues with the loop that generates the Fibonacci sequence?', 'Which part of your code do you suspect of causing this issue?']}, {'role': 'user', 'content': ""I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return."", 'alt': ['I am not sure. Can you help?', 'I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.']}, {'role': 'assistant', 'content': 'Good. Can you explain your for loop on line 11?', 'alt': ['What specifically about your for loop on line 11 might be causing the issue?', 'Good. Can you describe how many times the for loop iterates on line 11?', 'Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?', 'Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?', 'Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?']}, {'role': 'user', 'content': 'The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.', 'alt': ['It loops `n` times', 'Not really sure how to describe it.']}, {'role': 'assistant', 'content': ""Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?"", 'alt': ['What are the values of `a` and `b` in each iteration?', 'What variables used in the for loop on line 11 should we pay attention to identify the issue?', ""Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?"", ""Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?""]}, {'role': 'user', 'content': ""I'm not really sure can you suggest a way?"", 'alt': ['I can use the debugger!', 'I can add print statements.']}, {'role': 'assistant', 'content': 'Have you considered inserting a print statement after line 12 to output the 3 variables?', 'alt': ['Have you considered using the debugger?']}, {'role': 'user', 'content': 'Aha! Good idea! Perfect let me do that.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.   b = 1\n11.   for i in range(0, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Let's look at the outputs what do you observe?""}, {'role': 'user', 'content': 'I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.', 'alt': ['It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.', ""Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.""]}, {'role': 'assistant', 'content': 'What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?', 'alt': ['Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?']}, {'role': 'user', 'content': 'We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.'}, {'role': 'assistant', 'content': 'Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?', 'alt': ['Good. What should you do now to return the correct Fibonacci number?']}, {'role': 'user', 'content': 'I think I should edit the range of the loop to iterate one less time. Let me edit my code.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      print(f""a: {a}\\tb: {b}\\t i: {i}"")\n14.      b = a + b\n15.      a = temp\n16.    return b\n```'}, {'role': 'assistant', 'content': ""Good work. Don't forget to remove the print statement!""}, {'role': 'user', 'content': 'Ah yes! Thank you so much for your help!\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.     a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b\n13.      b = a + b\n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'You are welcome. Let me know if you have any further questions.'}, {'role': 'user', 'content': 'Thanks again! Goodbye!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 or n == 2:
+       return 1
+   else:
+       return fibonacci(n) + fibonacci(n-1)",`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.,Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_5_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n) + fibonacci(n-1)\n</bug_code>\n<bug_desc>\n`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.\n</bug_desc>\n<bug_fixes>\nReplace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?'}, {'role': 'assistant', 'content': 'I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?', 'alt': ['According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?', 'According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?', 'Can you explain what infinite recursion means?', 'Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?', ""Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?"", 'Can you explain what a recursive function is? When do we call a function recursive?', 'According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?']}, {'role': 'user', 'content': 'I believe it is line 7, because that is the line that is executed when `n` is larger than 2.'}, {'role': 'assistant', 'content': 'That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?', 'alt': ['Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?', 'Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?']}, {'role': 'user', 'content': 'Well, the function is called recursively to compute `fibonacci(3)`.\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 1) + fibonacci(n - 2)\n```', 'alt': ['Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.', 'Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...', 'The call `fibonacci(n)`.']}, {'role': 'assistant', 'content': 'So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?', 'alt': ['Do you see now why infinite recursion happens?', 'So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?']}, {'role': 'user', 'content': 'Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 2) + fibonacci(n - 1)\n```'}, {'role': 'assistant', 'content': 'Great, your program now works as expected!'}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 and n == 2:
+       return 1
+   elif n > 2:
+       a = 1
+       b = 1
+       for i in range(3, n+1):
+           c = a + b
+           a = b
+           b = c
+       return b","On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.",Replace `and` with `or` on line 4.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_6_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 and n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n</bug_code>\n<bug_desc>\nOn line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.\n</bug_desc>\n<bug_fixes>\nReplace `and` with `or` on line 4.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, my program passes all test cases except the second and third. Can you help?'}, {'role': 'assistant', 'content': 'Hi! Sure, what does the problem description say about these two cases?', 'alt': ['Hi! Sure, what is the value of `n` in these two cases?', 'Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?', 'Hi! Sure, what is the output supposed to be for each of these cases?']}, {'role': 'user', 'content': 'I am not sure, how can I find that?', 'alt': ['It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`']}, {'role': 'assistant', 'content': 'What are the values of `n` for these two cases?', 'alt': ['There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?']}, {'role': 'user', 'content': 'In the second test case, the value of `n` is `1` and in the third case `n` is `2`.'}, {'role': 'assistant', 'content': 'Correct, what are we supposed to return for these values of `n`?'}, {'role': 'user', 'content': 'We are supposed to return `1`, and I handled these cases on lines 4 and 5.'}, {'role': 'assistant', 'content': 'Ok, when does line 4 evaluate to true?', 'alt': ['Ok, for what value of `n` will line 5 be executed?']}, {'role': 'user', 'content': 'It evaluates to true if `n` is `1` and if it is `2`'}, {'role': 'assistant', 'content': 'Will the value of `n` ever be `1` and `2` at the same time?'}, {'role': 'user', 'content': 'No, it can be either `1` or `2`, but never both at the same time.', 'alt': ['No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?']}, {'role': 'assistant', 'content': 'Correct! It is either `1` OR `2`, does your if statement check for that?'}, {'role': 'user', 'content': 'Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    elif n > 2:\n7.        a = 1\n8.        b = 1\n9.        for i in range(3, n+1):\n10.            c = a + b\n11.            a = b\n12.            b = c\n13.        return b\n```'}, {'role': 'assistant', 'content': 'That looks great! It now returns `1` when `n` is either `1` or `2`.'}, {'role': 'user', 'content': 'Thank you for explaining the difference between `or` and `and`!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+ if n < 0:
+   return ""OOPS""
+ elif n == 1:
+   return 1
+ elif n == 2:
+   return 1
+ else:
+   a = 0
+   b = 1
+   for i in range(1, n):
+     temp = b 
+     b = a + b 
+     a = temp
+   return b","On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`.",Replace `if n < 0` with `if n <= 0` on line 2.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_2_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return ""OOPS""
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.  if n < 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n</bug_code>\n<bug_desc>\nOn line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `\'OOPS\'` when `n` is equal to `0`. \n</bug_desc>\n<bug_fixes>\nReplace `if n < 0` with `if n <= 0` on line 2.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I need help on this my code is failing the first test case.', 'alt': ['Hello. I need help with my code.']}, {'role': 'assistant', 'content': 'Can you walk me through your code step by step given that `n` is 0?', 'alt': [""Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?"", 'Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?']}, {'role': 'user', 'content': '`n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of ""OOPS"". I see the issue is the condition on line 2. Let me fix it.\n```python\n1. def fibonacci(n):\n2.  if n <= 0:\n3.    return ""OOPS""\n4.  elif n == 1:\n5.    return 1\n6.  elif n == 2:\n7.    return 1\n8.  else:\n9.    a = 0\n10.    b = 1\n11.    for i in range(1, n):\n12.      temp = b \n13.      b = a + b \n14.      a = temp\n15.    return b\n```'}, {'role': 'assistant', 'content': 'Good. Did you try it for all the unit tests?'}, {'role': 'user', 'content': 'Yes I have. Thank you so much for your help!'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?
+Assistant: I would love to! What kind of problems are you having?
+	<alt>Can you describe what your code fails to do?
+	<alt>Can you explain your code to me line by line?
+User: I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).
+Assistant: Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?
+	<alt>Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?
+	<alt>Let’s trace back what your function did. Where did `D` in your returned tuple come from?
+	<alt>Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?
+User: The value assigned to `finalScore` is 69.6.
+	<alt>The value would be 70, right?
+Assistant: Correct. Which block of the if-elif-else statement is executed?
+	<alt>What does the boolean expression on line 14 evaluate to?
+	<alt>Can you explain the differences between `finalScore` and `roundedScore`?
+	<alt>What is the truth value of the boolean expression on line 14?
+User: Oh! The boolean on line 16 becomes true, assigning `letterGrade` to 'D'! But I'm not sure how to fix that.
+	<alt>Oh, I put `finalScore` instead of `roundedScore`!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: How would you ensure that the grade would be treated as its nearest integer for the comparison?
+	<alt>How does your code return a grade of 70, yet compares with 69.6?
+User: Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if roundedScore >= 90:
+11.        letterGrade = ""A""
+12.    elif roundedScore >= 80:
+13.        letterGrade = ""B""
+14.    elif roundedScore >= 70:
+15.        letterGrade = ""C""
+16.    elif roundedScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good. Happy to help. Let me know if you have any further questions!
+User: Thank you so much for your help again!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   hw = hw * 0.2
+   exams = exams * 0.4
+   projects = projects * 0.30
+   att = att * 0.10
+
+   finalScore = hw + exams + projects + att
+   roundedScore = round(finalScore)
+
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.","Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_10_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    hw = hw * 0.2
+3.    exams = exams * 0.4
+4.    projects = projects * 0.30
+5.    att = att * 0.10
+6.
+7.    finalScore = hw + exams + projects + att
+8.    roundedScore = round(finalScore)
+9.
+10.    if finalScore >= 90:
+11.        letterGrade = ""A""
+12.    elif finalScore >= 80:
+13.        letterGrade = ""B""
+14.    elif finalScore >= 70:
+15.        letterGrade = ""C""
+16.    elif finalScore >= 60:
+17.        letterGrade = ""D""
+18.    else:
+19.        letterGrade = ""F""
+20.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+On lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.
+</bug_desc>
+<bug_fixes>
+Replace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if finalScore >= 90:\n11.        letterGrade = ""A""\n12.    elif finalScore >= 80:\n13.        letterGrade = ""B""\n14.    elif finalScore >= 70:\n15.        letterGrade = ""C""\n16.    elif finalScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nOn lines 10, 12, 14, and 16 the function uses `finalScore`, which is not rounded to the nearest integer, to determine the `letterGrade`.  Consequently, the function returns the incorrect `letterGrade` on edge cases where the closest integer is in a new category.\n</bug_desc>\n<bug_fixes>\nReplace `finalScore` with `roundedScore` on lines 10, 12, 14, and 16.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `calculateGrade` function, but I am having some problems. Can you help me?'}, {'role': 'assistant', 'content': 'I would love to! What kind of problems are you having?', 'alt': ['Can you describe what your code fails to do?', 'Can you explain your code to me line by line?']}, {'role': 'user', 'content': ""I am returning ('D', 70) for the fourth example case `calculateGrade(75, 60, 73, 87)` and I don't know why. It is supposed to be (`C`, 70).""}, {'role': 'assistant', 'content': ""Let's walk through that test input then. Can you tell me what is the value assigned to `finalScore` on line 7 for the inputs provided?"", 'alt': ['Can you explain the difference between `finalScore` and `roundedScore` on lines 7 and 8 respectively?', 'Let’s trace back what your function did. Where did `D` in your returned tuple come from?', 'Let’s add a print statement for `finalScore`, `roundedScore`, and `letterGrade` after line 19. What do you observe about those values?']}, {'role': 'user', 'content': 'The value assigned to `finalScore` is 69.6.', 'alt': ['The value would be 70, right?']}, {'role': 'assistant', 'content': 'Correct. Which block of the if-elif-else statement is executed?', 'alt': ['What does the boolean expression on line 14 evaluate to?', 'Can you explain the differences between `finalScore` and `roundedScore`?', 'What is the truth value of the boolean expression on line 14?']}, {'role': 'user', 'content': 'Oh! The boolean on line 16 becomes true, assigning `letterGrade` to \'D\'! But I\'m not sure how to fix that.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```', 'alt': ['Oh, I put `finalScore` instead of `roundedScore`!']}, {'role': 'assistant', 'content': 'How would you ensure that the grade would be treated as its nearest integer for the comparison?', 'alt': ['How does your code return a grade of 70, yet compares with 69.6?']}, {'role': 'user', 'content': 'Oh! I used the wrong variable. After using `roundedScore` that fixed it. Thank you!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    hw = hw * 0.2\n3.    exams = exams * 0.4\n4.    projects = projects * 0.30\n5.    att = att * 0.10\n6.\n7.    finalScore = hw + exams + projects + att\n8.    roundedScore = round(finalScore)\n9.\n10.    if roundedScore >= 90:\n11.        letterGrade = ""A""\n12.    elif roundedScore >= 80:\n13.        letterGrade = ""B""\n14.    elif roundedScore >= 70:\n15.        letterGrade = ""C""\n16.    elif roundedScore >= 60:\n17.        letterGrade = ""D""\n18.    else:\n19.        letterGrade = ""F""\n20.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good. Happy to help. Let me know if you have any further questions!'}, {'role': 'user', 'content': 'Thank you so much for your help again!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.   elif roundedScore >= 60:
+11.       letterGrade = ""D""
+12.   else:
+13.       letterGrade = ""F""
+14.   return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, please help I'm not sure what's going wrong
+Assistant: Hello. Let's take a look at your code together. What problem are you facing?
+	<alt>Hi. Are you encountering an error?
+	<alt>Hello. Can you describe your code line by line?
+	<alt>Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+User: The function only seems to return the `letterGrade` but otherwise it runs alright.
+	<alt>It does not throw an error, but it does not show everything I want it to either.
+	<alt>No errors but it is not working as expected.
+Assistant: Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?
+User: Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?
+	<alt>It seems like the last line never executes.
+Assistant: Good! Given this observation, when does your function terminate?
+	<alt>Good! Can you describe what are you trying to do on line 15?
+	<alt>What makes you think line 15 is not being executed?
+	<alt>Can you describe what are you trying to do on lines 14 and 15?
+User: It seems like once the return statement has executed, the function does not go further.
+Assistant: Is it possible for a function to have two consecutive return statements? 
+	<alt>Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?
+	<alt>How about we look up this behavior in the documentation to get more clarity?
+User: It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?
+	<alt>But then how do I make sure to return both the `letterGrade` and `roundedScore`?
+	<alt>Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!
+Assistant: Good question! Let's turn to the documentation - how can we return multiple variables?
+	<alt>Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?
+	<alt>Let's look at the examples in the instructions. What do you notice is being returned?
+User: Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.
+<code>
+def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore >= 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+  elif roundedScore >= 60:
+      letterGrade = ""D""
+  else:
+      letterGrade = ""F""
+  return letterGrade, roundedScore
+
+
+</code>
+Assistant: Great job! Is your code working now?
+	<alt>Did that fix your problem?
+User: Yes it did, thanks!
+	<alt>I'm all done!
+</dialogue","The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.","Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_11_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_desc>
+The return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.
+</bug_desc>
+<bug_fixes>
+Remove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\ncalculateGrade(100, 89, 85, 90) => ('A', 90)\ncalculateGrade(72, 96, 74, 98) => ('B', 85)\ncalculateGrade(100, 82, 68, 94) => ('B', 83)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(12, 14, 23, 10) => ('F', 16)\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\n```\n</problem>\n<bug_desc>\nThe return statement on line 15 is never executed. Consequently, the function only returns a string `letterGrade` instead of returning a tuple with a string and an integer containing the letter grade and the rounded final score respectively.\n</bug_desc>\n<bug_fixes>\nRemove line 15 and replace `letterGrade` with `(letterGrade, roundedScore)` on line 15.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(72, 96, 74, 98) == ('B', 85)\nassert calculateGrade(100, 82, 68, 94) == ('B', 83)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(12, 14, 23, 10) == ('F', 16)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hi, please help I'm not sure what's going wrong""}, {'role': 'assistant', 'content': ""Hello. Let's take a look at your code together. What problem are you facing?"", 'alt': ['Hi. Are you encountering an error?', 'Hello. Can you describe your code line by line?', ""Hi. Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?""]}, {'role': 'user', 'content': 'The function only seems to return the `letterGrade` but otherwise it runs alright.', 'alt': ['It does not throw an error, but it does not show everything I want it to either.', 'No errors but it is not working as expected.']}, {'role': 'assistant', 'content': ""Python code runs line-by-line. Let's look at yours again - can you pinpoint where the problem might be?""}, {'role': 'user', 'content': 'Yes, it seems like line 15 never runs. Does that mean my function stops at line 14?', 'alt': ['It seems like the last line never executes.']}, {'role': 'assistant', 'content': 'Good! Given this observation, when does your function terminate?', 'alt': ['Good! Can you describe what are you trying to do on line 15?', 'What makes you think line 15 is not being executed?', 'Can you describe what are you trying to do on lines 14 and 15?']}, {'role': 'user', 'content': 'It seems like once the return statement has executed, the function does not go further.'}, {'role': 'assistant', 'content': 'Is it possible for a function to have two consecutive return statements?', 'alt': [""Let's recall what you know about return statements in Python. What happens when a compiler encounters a return statement?"", 'How about we look up this behavior in the documentation to get more clarity?']}, {'role': 'user', 'content': 'It seems like I can only use one return statement here. What should I do to return both `letterGrade` and `roundedScore`?', 'alt': ['But then how do I make sure to return both the `letterGrade` and `roundedScore`?', 'Looking at the documentation, it seems I can only use one return statement per function. However, I would still have a problem with returning both the `letterGrade` and `roundedScore`!']}, {'role': 'assistant', 'content': ""Good question! Let's turn to the documentation - how can we return multiple variables?"", 'alt': [""Let's look at the instructions. When looking at the function signature, can you determine the data type that is specified as the return value?"", ""Let's look at the examples in the instructions. What do you notice is being returned?""]}, {'role': 'user', 'content': 'Ah I see. Looks like I need only one statement, but I can include more variables in the same statement. Updating my code now.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.   elif roundedScore >= 60:\n11.       letterGrade = ""D""\n12.   else:\n13.       letterGrade = ""F""\n14.   return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Great job! Is your code working now?', 'alt': ['Did that fix your problem?']}, {'role': 'user', 'content': 'Yes it did, thanks!', 'alt': [""I'm all done!""]}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck
+Assistant: Okay, what do you think the problem is?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Have you thought about the problem?
+User: It isn't calculating correctly.
+	<alt>It's failing the second test case.
+Assistant: How is the calculation made in the function?
+	<alt>Can you tell me what test cases are failing?
+	<alt>Where do you think the problem is?
+	<alt>Start with line 1, do you see any problems with the method header?
+	<alt>Look at the second test case, how is it different from the first test case?
+User: The scores are multiplied with the weights and summed up.
+	<alt>Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.
+Assistant: So, is it working for the first test case?
+	<alt>Do you see any problems adding the scores on the assignments to the grades array?
+	<alt>Do you see any problems with the loop?
+	<alt>Do you see any problems with the weights?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt> Why is it working on the first test case and not the second?
+	<alt> Check the loop, are all the values being considered?
+User: Yes, the first test case is correct, but the second one is wrong.
+Assistant: How are the two test cases different?
+	<alt>Do you see any problems with the weights?
+	<alt>Do you see any problems with passing in the grades?
+	<alt>Check the instructions, do you see anything you aren't doing?
+	<alt>Do you see any differences in the numbers between the two test cases?
+User: The first test case has all the values the same, and the second test case has different values.
+	<alt>The first test case has all 100s, but different numbers for the second case.
+	<alt>I'm not sure.
+Assistant: Does the order of the input parameters matter?
+	<alt>Why does the order matter?
+	<alt>Are any specific lines of code impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Which parameter represents homework?
+User: Yes, the order of inputs does matter.
+Assistant: Why?
+	<alt>Which lines are impacted by the order of the values?
+	<alt>What type of grade does the first value being passed in represent?
+	<alt>Look back at the instructions, what should the weight be for the first value?
+User: Because that determines which value is associated with the different grade categories.
+Assistant: Why does that change the calculation?
+	<alt>What is the correct weight for the homework?
+	<alt>On what line of code are those values assigned?
+	<alt>Are those values passed into the array in the proper order?
+User: The type of grade changes the weight for the calculation.
+Assistant: What is the correct weight for homework?
+	<alt>Look at the grades array, does it match the order the parameters are passed in?
+	<alt>Look at the weights array, does that match the order for the categories?
+	<alt>What do you think is causing the problem here?
+User: Homework should have a weight of 20%.
+Assistant: How is that set in the code?
+	<alt>What weight should exams have?
+	<alt>Look at the weights array, does that match the order for the categories?
+User: It's set in the weights array.
+	<alt>I see, the weights array is wrong!
+Assistant: Check the weights array, does the first item match the correct weight for homework?
+	<alt>How does the weights array interact with the grades array?
+	<alt>Which item in the weights array should correspond with homework?
+	<alt>Are the arrays parallel?
+User: No, the first item is 0.1, that's the weight for attendance.
+	<alt>It's in the wrong order.
+Assistant: What should you change the weights array to?
+	<alt>Should the first item in the weights array go with the first item in the grades array?
+	<alt>Should the arrays be parallel?
+	<alt>Are the arrays parallel?
+User: I'll switch the attendance and homework weights on line 2.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.3, 0.4, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Did that fix it?
+	<alt>Is that everything?
+	<alt>Did you check the other weights?
+User: No, it still doesn't work.
+Assistant: Keep looking, do you see any other problems with the weights array?
+	<alt>Did which test cases pass change?
+	<alt>Does the first test case still pass?
+	<alt>What about the second item in the grades array, does it match with the second item in the weights array?
+	<alt>What is the correct weight for exams?
+User: Yes, exams and projects are flipped too!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.2, 0.4, 0.3, 0.1]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+
+</code>
+Assistant: Does it pass now?
+User: Yes, all the test cases pass. Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   weights = [0.1, 0.3, 0.4, 0.2]
+   grades = [hw, exams, projects, att]
+   final_grade = 0
+   for i in range(len(weights)):
+       final_grade += weights[i] * grades[i]
+   final_grade = round(final_grade)
+   
+   if final_grade >= 90:
+       return ('A', final_grade)
+   elif final_grade >= 80:
+       return ('B', final_grade)
+   elif final_grade >= 70:
+       return ('C', final_grade)
+   elif final_grade >= 60:
+       return ('D', final_grade)
+   else:
+       return ('F', final_grade)","On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.","On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_13_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    weights = [0.1, 0.3, 0.4, 0.2]
+3.    grades = [hw, exams, projects, att]
+4.    final_grade = 0
+5.    for i in range(len(weights)):
+6.        final_grade += weights[i] * grades[i]
+7.    final_grade = round(final_grade)
+8.    
+9.    if final_grade >= 90:
+10.        return ('A', final_grade)
+11.    elif final_grade >= 80:
+12.        return ('B', final_grade)
+13.    elif final_grade >= 70:
+14.        return ('C', final_grade)
+15.    elif final_grade >= 60:
+16.        return ('D', final_grade)
+17.    else:
+18.        return ('F', final_grade)
+</bug_code>
+<bug_desc>
+On lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.
+</bug_desc>
+<bug_fixes>
+On line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.
+On line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': ""<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => ('F', 0)\ncalculateGrade(70, 60, 65, 70) => ('D', 64)\ncalculateGrade(75, 60, 73, 100) => ('C', 71)\ncalculateGrade(75, 60, 73, 87) => ('C', 70)\ncalculateGrade(100, 89, 85, 90) == ('A', 90)\ncalculateGrade(100, 100, 100, 100) => ('A', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.1, 0.3, 0.4, 0.2]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, the `weights` and `grades` are not parallel arrays. Consequently, the function will return an incorrect weighted sum of the final grade.\n</bug_desc>\n<bug_fixes>\nOn line 2 replace `[0.1, 0.3, 0.4, 0.2]` with `[0.2, 0.4, 0.3, 0.1]`.\nOn line 3 replace `[hw, exams, projects, att]` with  ` [att, projects, exams, hw]`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == ('A', 100)\nassert calculateGrade(100, 89, 85, 90) == ('A', 90)\nassert calculateGrade(75, 60, 73, 100) == ('C', 71)\nassert calculateGrade(75, 60, 73, 87) == ('C', 70)\nassert calculateGrade(70, 60, 65, 70) == ('D', 64)\nassert calculateGrade(0, 0, 0, 0) == ('F', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck""}, {'role': 'assistant', 'content': 'Okay, what do you think the problem is?', 'alt': ['Can you tell me what test cases are failing?', 'Have you thought about the problem?']}, {'role': 'user', 'content': ""It isn't calculating correctly."", 'alt': [""It's failing the second test case.""]}, {'role': 'assistant', 'content': 'How is the calculation made in the function?', 'alt': ['Can you tell me what test cases are failing?', 'Where do you think the problem is?', 'Start with line 1, do you see any problems with the method header?', 'Look at the second test case, how is it different from the first test case?']}, {'role': 'user', 'content': 'The scores are multiplied with the weights and summed up.', 'alt': ['Pass in the scores, put them in an array, multiply those values with the weights, and add them with a for-loop.']}, {'role': 'assistant', 'content': 'So, is it working for the first test case?', 'alt': ['Do you see any problems adding the scores on the assignments to the grades array?', 'Do you see any problems with the loop?', 'Do you see any problems with the weights?', ""Check the instructions, do you see anything you aren't doing?"", 'Why is it working on the first test case and not the second?', 'Check the loop, are all the values being considered?']}, {'role': 'user', 'content': 'Yes, the first test case is correct, but the second one is wrong.'}, {'role': 'assistant', 'content': 'How are the two test cases different?', 'alt': ['Do you see any problems with the weights?', 'Do you see any problems with passing in the grades?', ""Check the instructions, do you see anything you aren't doing?"", 'Do you see any differences in the numbers between the two test cases?']}, {'role': 'user', 'content': 'The first test case has all the values the same, and the second test case has different values.', 'alt': ['The first test case has all 100s, but different numbers for the second case.', ""I'm not sure.""]}, {'role': 'assistant', 'content': 'Does the order of the input parameters matter?', 'alt': ['Why does the order matter?', 'Are any specific lines of code impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Which parameter represents homework?']}, {'role': 'user', 'content': 'Yes, the order of inputs does matter.'}, {'role': 'assistant', 'content': 'Why?', 'alt': ['Which lines are impacted by the order of the values?', 'What type of grade does the first value being passed in represent?', 'Look back at the instructions, what should the weight be for the first value?']}, {'role': 'user', 'content': 'Because that determines which value is associated with the different grade categories.'}, {'role': 'assistant', 'content': 'Why does that change the calculation?', 'alt': ['What is the correct weight for the homework?', 'On what line of code are those values assigned?', 'Are those values passed into the array in the proper order?']}, {'role': 'user', 'content': 'The type of grade changes the weight for the calculation.'}, {'role': 'assistant', 'content': 'What is the correct weight for homework?', 'alt': ['Look at the grades array, does it match the order the parameters are passed in?', 'Look at the weights array, does that match the order for the categories?', 'What do you think is causing the problem here?']}, {'role': 'user', 'content': 'Homework should have a weight of 20%.'}, {'role': 'assistant', 'content': 'How is that set in the code?', 'alt': ['What weight should exams have?', 'Look at the weights array, does that match the order for the categories?']}, {'role': 'user', 'content': ""It's set in the weights array."", 'alt': ['I see, the weights array is wrong!']}, {'role': 'assistant', 'content': 'Check the weights array, does the first item match the correct weight for homework?', 'alt': ['How does the weights array interact with the grades array?', 'Which item in the weights array should correspond with homework?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""No, the first item is 0.1, that's the weight for attendance."", 'alt': [""It's in the wrong order.""]}, {'role': 'assistant', 'content': 'What should you change the weights array to?', 'alt': ['Should the first item in the weights array go with the first item in the grades array?', 'Should the arrays be parallel?', 'Are the arrays parallel?']}, {'role': 'user', 'content': ""I'll switch the attendance and homework weights on line 2.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.3, 0.4, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Did that fix it?', 'alt': ['Is that everything?', 'Did you check the other weights?']}, {'role': 'user', 'content': ""No, it still doesn't work.""}, {'role': 'assistant', 'content': 'Keep looking, do you see any other problems with the weights array?', 'alt': ['Did which test cases pass change?', 'Does the first test case still pass?', 'What about the second item in the grades array, does it match with the second item in the weights array?', 'What is the correct weight for exams?']}, {'role': 'user', 'content': ""Yes, exams and projects are flipped too!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    weights = [0.2, 0.4, 0.3, 0.1]\n3.    grades = [hw, exams, projects, att]\n4.    final_grade = 0\n5.    for i in range(len(weights)):\n6.        final_grade += weights[i] * grades[i]\n7.    final_grade = round(final_grade)\n8.    \n9.    if final_grade >= 90:\n10.        return ('A', final_grade)\n11.    elif final_grade >= 80:\n12.        return ('B', final_grade)\n13.    elif final_grade >= 70:\n14.        return ('C', final_grade)\n15.    elif final_grade >= 60:\n16.        return ('D', final_grade)\n17.    else:\n18.        return ('F', final_grade)\n```""}, {'role': 'assistant', 'content': 'Does it pass now?'}, {'role': 'user', 'content': 'Yes, all the test cases pass. Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>What test cases are passing?
+	<alt>What test cases are failing?
+	<alt>Have you reread the prompt?
+	<alt>Have you checked the calculation for the grade?
+	<alt>Have you checked the if-statement?
+User: I don't know.
+Assistant: Let's go through your function line by line, how can you check the calculation on line 2?
+	<alt>Let's start by looking at the test cases, what is the first one to fail?
+	<alt>Let's start by looking at the test cases, does the first one pass?
+User: I can add a print statement to check the number.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    if roundedScore > 90:
+6.        letterGrade = ""A""
+7.    elif roundedScore >= 80:
+8.        letterGrade = ""B""
+9.    elif roundedScore >= 70:
+10.        letterGrade = ""C""
+11.    elif roundedScore >= 60:
+12.        letterGrade = ""D""
+13.    else:
+14.        letterGrade = ""F""
+15.    return letterGrade, roundedScore
+
+</code>
+Assistant: Good, what is the first test case to fail?
+	<alt>Good, does the first test case succeed?
+	<alt>Good, is the first `finalScore` correct?
+	<alt>Good, what is the first incorrect `finalScore`?
+User: The second test case fails.
+Assistant: Is the `finalScore` correct for that test case?
+	<alt>Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+	<alt>How can you check if it is a rounding error?
+User: Yes, the final score is correct for that test case.
+Assistant: How can you check if it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem with matching the grade to the letter?
+User: I can add another print statement after line 4 and check the rounding.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore > 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good. Do you think it is a rounding error?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: No, I don't think so.
+Assistant: Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?
+	<alt>What do you think the error is?
+	<alt>Do you think it is a problem matching the grade to the letter?
+User: It checks if the rounded score is greater than 90.
+	<alt>I see, it should be greater than or equal to!
+Assistant: Think about that carefully, would it return true or false if the grade was exactly 90?
+User: No, it wouldn't! That's wrong, it should be greater than or equal to!
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    print(finalScore)
+4.    roundedScore = round(finalScore)
+5.    print(roundedScore)
+6.    if roundedScore >= 90:
+7.        letterGrade = ""A""
+8.    elif roundedScore >= 80:
+9.        letterGrade = ""B""
+10.    elif roundedScore >= 70:
+11.        letterGrade = ""C""
+12.    elif roundedScore >= 60:
+13.        letterGrade = ""D""
+14.    else:
+15.        letterGrade = ""F""
+16.    return letterGrade, roundedScore
+
+</code>
+Assistant: Try running it again, does it work now?
+User: Yes! It does. I'll remove the extra print statements.
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore >= 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+
+</code>
+Assistant: Very good.
+User: Thank you!
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   roundedScore = round(finalScore)
+   if roundedScore > 90:
+       letterGrade = ""A""
+   elif roundedScore >= 80:
+       letterGrade = ""B""
+   elif roundedScore >= 70:
+       letterGrade = ""C""
+   elif roundedScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, roundedScore","When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.",Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.,"assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_8_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+calculateGrade(100, 89, 85, 90) => ('A', 90)
+calculateGrade(72, 96, 74, 98) => ('B', 85)
+calculateGrade(100, 82, 68, 94) => ('B', 83)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(12, 14, 23, 10) => ('F', 16)
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    roundedScore = round(finalScore)
+4.    if roundedScore > 90:
+5.        letterGrade = ""A""
+6.    elif roundedScore >= 80:
+7.        letterGrade = ""B""
+8.    elif roundedScore >= 70:
+9.        letterGrade = ""C""
+10.    elif roundedScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, roundedScore
+</bug_code>
+<bug_desc>
+When `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `roundedScore > 90` with `roundedScore >= 90` on line 4.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(72, 96, 74, 98) == ('B', 85)
+assert calculateGrade(100, 82, 68, 94) == ('B', 83)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(12, 14, 23, 10) == ('F', 16)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\ncalculateGrade(100, 89, 85, 90) => (\'A\', 90)\ncalculateGrade(72, 96, 74, 98) => (\'B\', 85)\ncalculateGrade(100, 82, 68, 94) => (\'B\', 83)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(12, 14, 23, 10) => (\'F\', 16)\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore > 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n</bug_code>\n<bug_desc>\nWhen `roundedScore` is `90` the if statement on line 4 evaluates to False, since `90` is not strictly greater than `90`.  Consequently, the function assigns `B` to `letterGrade` which is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `roundedScore > 90` with `roundedScore >= 90` on line 4.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(72, 96, 74, 98) == (\'B\', 85)\nassert calculateGrade(100, 82, 68, 94) == (\'B\', 83)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(12, 14, 23, 10) == (\'F\', 16)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['What test cases are passing?', 'What test cases are failing?', 'Have you reread the prompt?', 'Have you checked the calculation for the grade?', 'Have you checked the if-statement?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's go through your function line by line, how can you check the calculation on line 2?"", 'alt': [""Let's start by looking at the test cases, what is the first one to fail?"", ""Let's start by looking at the test cases, does the first one pass?""]}, {'role': 'user', 'content': 'I can add a print statement to check the number.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    if roundedScore > 90:\n6.        letterGrade = ""A""\n7.    elif roundedScore >= 80:\n8.        letterGrade = ""B""\n9.    elif roundedScore >= 70:\n10.        letterGrade = ""C""\n11.    elif roundedScore >= 60:\n12.        letterGrade = ""D""\n13.    else:\n14.        letterGrade = ""F""\n15.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Good, what is the first test case to fail?', 'alt': ['Good, does the first test case succeed?', 'Good, is the first `finalScore` correct?', 'Good, what is the first incorrect `finalScore`?']}, {'role': 'user', 'content': 'The second test case fails.'}, {'role': 'assistant', 'content': 'Is the `finalScore` correct for that test case?', 'alt': ['Do you think it is a rounding error?', 'What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?', 'How can you check if it is a rounding error?']}, {'role': 'user', 'content': 'Yes, the final score is correct for that test case.'}, {'role': 'assistant', 'content': 'How can you check if it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem with matching the grade to the letter?']}, {'role': 'user', 'content': 'I can add another print statement after line 4 and check the rounding.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore > 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good. Do you think it is a rounding error?', 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': ""No, I don't think so.""}, {'role': 'assistant', 'content': ""Now, let's look at the if-statement that matches letters to the grades. Can you tell me what the first statement checks?"", 'alt': ['What do you think the error is?', 'Do you think it is a problem matching the grade to the letter?']}, {'role': 'user', 'content': 'It checks if the rounded score is greater than 90.', 'alt': ['I see, it should be greater than or equal to!']}, {'role': 'assistant', 'content': 'Think about that carefully, would it return true or false if the grade was exactly 90?'}, {'role': 'user', 'content': 'No, it wouldn\'t! That\'s wrong, it should be greater than or equal to!\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    print(finalScore)\n4.    roundedScore = round(finalScore)\n5.    print(roundedScore)\n6.    if roundedScore >= 90:\n7.        letterGrade = ""A""\n8.    elif roundedScore >= 80:\n9.        letterGrade = ""B""\n10.    elif roundedScore >= 70:\n11.        letterGrade = ""C""\n12.    elif roundedScore >= 60:\n13.        letterGrade = ""D""\n14.    else:\n15.        letterGrade = ""F""\n16.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Try running it again, does it work now?'}, {'role': 'user', 'content': 'Yes! It does. I\'ll remove the extra print statements.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    roundedScore = round(finalScore)\n4.    if roundedScore >= 90:\n5.        letterGrade = ""A""\n6.    elif roundedScore >= 80:\n7.        letterGrade = ""B""\n8.    elif roundedScore >= 70:\n9.        letterGrade = ""C""\n10.    elif roundedScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, roundedScore\n```'}, {'role': 'assistant', 'content': 'Very good.'}, {'role': 'user', 'content': 'Thank you!'}]}"
+"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.
+Assistant: Where, in your code, do you think this problem is happening?
+	<alt>Why do you expect the output of 69.6 to return D?
+	<alt>What do you think we can do to figure out where our problem is?
+User: I think it's happening in the if-statements.
+	<alt>I don't know where.
+	<alt>It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70.
+	<alt>I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.
+Assistant: Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?
+	<alt>Which condition in the if-statements is causing your problem?
+User: Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way.
+	<alt>I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.
+	<alt>I have no idea.
+	<alt>I don't really understand how if-statements work.
+Assistant: That's a good point! What do you think you should do next?
+	<alt>Good observation! How would you round `finalScore`?
+User: I need to round `finalScore`, but I don't know how to do that.
+	<alt>I can use the `round()` method on the `finalScore`.
+	<alt>I can do`finalScore = round(finalScore)`
+	<alt>I can do `finalScore = finalScore.round()`
+Assistant: You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?
+	<alt>If you don't know how to round a variable, do you have any idea where you could look to figure it out?
+User: Oh, wait. I found a round() function. If I don't specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.
+	<alt>I have no idea what method can help me.
+	<alt>I don't understand what a method is.
+	<alt>I could use `finalScore = round(finalScore, 2)`
+<code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    finalScore = round(finalScore)
+4.    if finalScore >= 90:
+5.        letterGrade = ""A""
+6.    elif finalScore >= 80:
+7.        letterGrade = ""B""
+8.    elif finalScore >= 70:
+9.        letterGrade = ""C""
+10.    elif finalScore >= 60:
+11.        letterGrade = ""D""
+12.    else:
+13.        letterGrade = ""F""
+14.    return letterGrade, finalScore
+</code>
+Assistant: Good work! You did it.
+</dialogue>","Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```","def calculateGrade(hw, exams, projects, att):
+   finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+   if finalScore >= 90:
+       letterGrade = ""A""
+   elif finalScore >= 80:
+       letterGrade = ""B""
+   elif finalScore >= 70:
+       letterGrade = ""C""
+   elif finalScore >= 60:
+       letterGrade = ""D""
+   else:
+       letterGrade = ""F""
+   return letterGrade, finalScore","The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.","After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.","assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)",1_9_calculating_a_grade,"<problem>
+Create a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student's grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.
+
+The letter grade should be determined based on the following scale:
+
+* A for a final rounded grade between 90 and 100 (inclusive)
+* B for a final rounded grade between 80 and 89 (inclusive)
+* C for a final rounded grade between 70 and 79 (inclusive)
+* D for a final rounded  grade between 60 and 69 (inclusive)
+* F for a final rounded grade below 60.
+
+For example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `('C', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.
+
+## Example Cases:
+```
+calculateGrade(0, 0, 0, 0) => ('F', 0)
+calculateGrade(70, 60, 65, 70) => ('D', 64)
+calculateGrade(75, 60, 73, 100) => ('C', 71)
+calculateGrade(75, 60, 73, 87) => ('C', 70)
+calculateGrade(100, 89, 85, 90) == ('A', 90)
+calculateGrade(100, 100, 100, 100) => ('A', 100)
+```
+</problem>
+<bug_code>
+1. def calculateGrade(hw, exams, projects, att):
+2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1
+3.    if finalScore >= 90:
+4.        letterGrade = ""A""
+5.    elif finalScore >= 80:
+6.        letterGrade = ""B""
+7.    elif finalScore >= 70:
+8.        letterGrade = ""C""
+9.    elif finalScore >= 60:
+10.        letterGrade = ""D""
+11.    else:
+12.        letterGrade = ""F""
+13.    return letterGrade, finalScore
+</bug_code>
+<bug_desc>
+The function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.
+</bug_desc>
+<bug_fixes>
+After line 2, add a new line with the following snippet `finalScore = round(finalScore)`.
+</bug_fixes>
+<unit_tests>
+assert calculateGrade(100, 100, 100, 100) == ('A', 100)
+assert calculateGrade(100, 89, 85, 90) == ('A', 90)
+assert calculateGrade(75, 60, 73, 100) == ('C', 71)
+assert calculateGrade(75, 60, 73, 87) == ('C', 70)
+assert calculateGrade(70, 60, 65, 70) == ('D', 64)
+assert calculateGrade(0, 0, 0, 0) == ('F', 0)
+</unit_tests>
+","{'system': '<problem>\nCreate a method `calculateGrade(hw:float, exams: float, projects: float, att:float) -> Tuple[str, int]` that takes in four float parameters between 0 and 100 representing a student\'s grades in four different categories: Homework (`hw`) which is worth 20% of the final grade, Exams (`exams`) worth 40% of the final grade, Projects (`projects`) worth 30%, and Attendance (`att`), worth 10%. The function should calculate the final grade a student is getting and return a tuple containing the final letter grade and the final numeric grade rounded up to the nearest whole number.\n\nThe letter grade should be determined based on the following scale:\n\n* A for a final rounded grade between 90 and 100 (inclusive)\n* B for a final rounded grade between 80 and 89 (inclusive)\n* C for a final rounded grade between 70 and 79 (inclusive)\n* D for a final rounded  grade between 60 and 69 (inclusive)\n* F for a final rounded grade below 60.\n\nFor example, if you enter `calculateGrade(75, 60, 73, 87)`, the function should return `(\'C\', 70)` because the final raw score is `69.6` which rounds up to `70` and corresponds to a letter grade of `C`.\n\n## Example Cases:\n```\ncalculateGrade(0, 0, 0, 0) => (\'F\', 0)\ncalculateGrade(70, 60, 65, 70) => (\'D\', 64)\ncalculateGrade(75, 60, 73, 100) => (\'C\', 71)\ncalculateGrade(75, 60, 73, 87) => (\'C\', 70)\ncalculateGrade(100, 89, 85, 90) == (\'A\', 90)\ncalculateGrade(100, 100, 100, 100) => (\'A\', 100)\n```\n</problem>\n<bug_code>\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    if finalScore >= 90:\n4.        letterGrade = ""A""\n5.    elif finalScore >= 80:\n6.        letterGrade = ""B""\n7.    elif finalScore >= 70:\n8.        letterGrade = ""C""\n9.    elif finalScore >= 60:\n10.        letterGrade = ""D""\n11.    else:\n12.        letterGrade = ""F""\n13.    return letterGrade, finalScore\n</bug_code>\n<bug_desc>\nThe function does not round `finalScore` to the nearest whole number. Consequently, when `finalScore` is `69.6` the function will return `D` instead of `C` as `letterGrade`. The function also returns a float `finalScore` instead of an integer.\n</bug_desc>\n<bug_fixes>\nAfter line 2, add a new line with the following snippet `finalScore = round(finalScore)`.\n</bug_fixes>\n<unit_tests>\nassert calculateGrade(100, 100, 100, 100) == (\'A\', 100)\nassert calculateGrade(100, 89, 85, 90) == (\'A\', 90)\nassert calculateGrade(75, 60, 73, 100) == (\'C\', 71)\nassert calculateGrade(75, 60, 73, 87) == (\'C\', 70)\nassert calculateGrade(70, 60, 65, 70) == (\'D\', 64)\nassert calculateGrade(0, 0, 0, 0) == (\'F\', 0)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""My code doesn't work. When the `finalScore` is 69.6, the function returns D instead of C.""}, {'role': 'assistant', 'content': 'Where, in your code, do you think this problem is happening?', 'alt': ['Why do you expect the output of 69.6 to return D?', 'What do you think we can do to figure out where our problem is?']}, {'role': 'user', 'content': ""I think it's happening in the if-statements."", 'alt': [""I don't know where."", ""It's happening in the if-statement `finalScore >= 70` and `finalScore >= 60` It isn't reaching the `finalScore` of 70."", ""I think it's happening in the calculation of the `finalScore`. I'm not getting a rounded number.""]}, {'role': 'assistant', 'content': 'Try manually going through the if-statements yourself. If `finalScore` is 69.6, what output do you get? Which condition does it fulfill?', 'alt': ['Which condition in the if-statements is causing your problem?']}, {'role': 'user', 'content': ""Oh. I see. I need 69.6 to be rounded to 70, which would give me C, but it isn't being rounded. Obviously, it won't work this way."", 'alt': ['I am getting that 69.6 should be caught in the `elif finalScore >= 60`. 69.6 is greater than or equal to 60.', 'I have no idea.', ""I don't really understand how if-statements work.""]}, {'role': 'assistant', 'content': ""That's a good point! What do you think you should do next?"", 'alt': ['Good observation! How would you round `finalScore`?']}, {'role': 'user', 'content': ""I need to round `finalScore`, but I don't know how to do that."", 'alt': ['I can use the `round()` method on the `finalScore`.', 'I can do`finalScore = round(finalScore)`', 'I can do `finalScore = finalScore.round()`']}, {'role': 'assistant', 'content': 'You may need to look at the Python documentation to find the method you are looking for. Can you find a method that can help us?', 'alt': [""If you don't know how to round a variable, do you have any idea where you could look to figure it out?""]}, {'role': 'user', 'content': 'Oh, wait. I found a round() function. If I don\'t specify the number of decimals, it rounds to the next integer. I could put a line of code that says `finalScore = round(finalScore)`.\n```python\n1. def calculateGrade(hw, exams, projects, att):\n2.    finalScore = hw * 0.2 + exams * 0.4 + projects * 0.3 + att * 0.1\n3.    finalScore = round(finalScore)\n4.    if finalScore >= 90:\n5.        letterGrade = ""A""\n6.    elif finalScore >= 80:\n7.        letterGrade = ""B""\n8.    elif finalScore >= 70:\n9.        letterGrade = ""C""\n10.    elif finalScore >= 60:\n11.        letterGrade = ""D""\n12.    else:\n13.        letterGrade = ""F""\n14.    return letterGrade, finalScore\n```', 'alt': ['I have no idea what method can help me.', ""I don't understand what a method is."", 'I could use `finalScore = round(finalScore, 2)`']}, {'role': 'assistant', 'content': 'Good work! You did it.'}]}"
+"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input ""English""?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, ""x"")
+      else:
+           sen = sen.replace(i, ""X"")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>","Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```","def toxNGLXSH(sen):
+ vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+ for i in vowels:
+     if i.islower():
+          sen.replace(i, ""x"")
+     else:
+          sen.replace(i, ""X"")
+ sen.swapcase()
+ return sen","On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.",Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.,"assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'",10_39_xnglxsh,"<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH(""My name is John!"") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, ""x"")
+6.      else:
+7.           sen.replace(i, ""X"")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH(""My name is John!"") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+","{'system': '<problem>\nCreate a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with \'X\', each uppercase vowel is replaced with \'x\', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.\n\n## Example Cases:\n```\ntoxNGLXSH(\'English\') => \'xNGLXSH\'\ntoxNGLXSH(\'hello there!\') => \'HXLLX THXRX!\'\ntoxNGLXSH(""My name is John!"") => \'mY NXMX XS jXHN!\'\ntoxNGLXSH(\'To be or not to be!\') => \'tX BX XR NXT TX BX!\'\ntoxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') => \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n```\n</problem>\n<bug_code>\n1. def toxNGLXSH(sen):\n2.  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n3.  for i in vowels:\n4.      if i.islower():\n5.           sen.replace(i, ""x"")\n6.      else:\n7.           sen.replace(i, ""X"")\n8.  sen.swapcase()\n9.  return sen\n</bug_code>\n<bug_desc>\nOn lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.\n</bug_desc>\n<bug_fixes>\nReplace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.\n</bug_fixes>\n<unit_tests>\nassert toxNGLXSH(\'English\') == \'xNGLXSH\'\nassert toxNGLXSH(\'hello there!\') == \'HXLLX THXRX!\'\nassert toxNGLXSH(""My name is John!"") == \'mY NXMX XS jXHN!\'\nassert toxNGLXSH(\'To be or not to be!\') == \'tX BX XR NXT TX BX!\'\nassert toxNGLXSH(\'The quick brown fox jumped over the lazy rabbit.\') == \'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.\'\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Help! I wrote a lot of code and nothing is working.'}, {'role': 'assistant', 'content': ""I'm here to help. Can you describe the problem you are having?"", 'alt': ['Can you walk me through your code line by line?', 'Let\'s start with a simple example. What is the output of your code when you run it with the input ""English""?', 'What does the `.replace()` method do?', 'What does the `.swapcase()` method do?']}, {'role': 'user', 'content': ""I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?""}, {'role': 'assistant', 'content': 'What are some reasons it could be staying the same?', 'alt': ['What does the `.replace()` method do and does it modify the original string?', 'What does the `.swapcase()` method do and does it modify the original string?']}, {'role': 'user', 'content': 'If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.', 'alt': [""I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.""]}, {'role': 'assistant', 'content': 'Let\'s open up the Python terminal and try running `sen = ""To""` and then `sen.replace(""o"", ""X"")`. What do you observe?', 'alt': ['Let\'s open up the Python terminal and try running `sen = ""English""` and then `sen.swapcase()`. What do you observe?']}, {'role': 'user', 'content': 'Ok, I tried that, and it looks like it returns the modified string I expect `TX`.', 'alt': ['Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.']}, {'role': 'assistant', 'content': 'Good. Now let\'s try running `sen = sen.replace(""o"", ""X"")` and then `print(sen)`. What do you observe?', 'alt': [""Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?""]}, {'role': 'user', 'content': 'Ah. It looks like the string methods don\'t modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.\n```python\ndef toxNGLXSH(sen):\n  vowels = [""a"", ""e"", ""i"", ""o"", ""u"", ""A"", ""E"", ""I"", ""O"", ""U""]\n  for i in vowels:\n      if i.islower():\n           sen = sen.replace(i, ""x"")\n      else:\n           sen = sen.replace(i, ""X"")\n  sen = sen.swapcase()\n  return sen\n```'}, {'role': 'assistant', 'content': 'That looks good! Why do you think it worked?'}, {'role': 'user', 'content': ""It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.""}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>","Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```","def is_palindrome(string):
+ rev_string = ''
+ for i in string:
+   rev_string = i + rev_string
+ if rev_string = string:
+   return True
+ else:
+   return False","On line 5, the function throws a syntax error.",Replace `=` with `==` on line 5.,"assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True",11_40_palindrome,"<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome(""racecar"") => True
+is_palindrome(""hello"") => False
+is_palindrome(""hannah"") => True
+is_palindrome(""firetruck"") => False
+is_palindrome(""nice"") => False
+is_palindrome("""") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome(""racecar"") == True
+assert is_palindrome(""hello"") == False
+assert is_palindrome(""hannah"") == True
+assert is_palindrome(""firetruck"") == False
+assert is_palindrome(""nice"") == False
+assert is_palindrome("""") == True
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.\n## Example Cases:\n```\nis_palindrome(""racecar"") => True\nis_palindrome(""hello"") => False\nis_palindrome(""hannah"") => True\nis_palindrome(""firetruck"") => False\nis_palindrome(""nice"") => False\nis_palindrome("""") => True\n```\n</problem>\n<bug_code>\n1. def is_palindrome(string):\n2.  rev_string = \'\'\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string = string:\n6.    return True\n7.  else:\n8.    return False\n</bug_code>\n<bug_desc>\nOn line 5, the function throws a syntax error.\n</bug_desc>\n<bug_fixes>\nReplace `=` with `==` on line 5.\n</bug_fixes>\n<unit_tests>\nassert is_palindrome(""racecar"") == True\nassert is_palindrome(""hello"") == False\nassert is_palindrome(""hannah"") == True\nassert is_palindrome(""firetruck"") == False\nassert is_palindrome(""nice"") == False\nassert is_palindrome("""") == True\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hey! I have a compiler error here.'}, {'role': 'assistant', 'content': 'Ok, what error do you see?', 'alt': [""Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?"", 'What line is the compiler error pointing towards?']}, {'role': 'user', 'content': ""It's giving me an error on my equality operator use.""}, {'role': 'assistant', 'content': 'I see. How do you assign a value of 1 to a variable `x`?', 'alt': ['How do you assign an empty string to the variable `rev_string`?', 'How would you check if two  variables `x` and `y` are equivalent?', 'Can you recall what the assignment operator is?']}, {'role': 'user', 'content': 'I use the `=` operator.'}, {'role': 'assistant', 'content': 'What are you trying to do in line 5?', 'alt': ['How would you check if  two variables `x` and `y` are equivalent?']}, {'role': 'user', 'content': 'I am trying to check if `rev_string` is equal to `string`', 'alt': ['Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.']}, {'role': 'assistant', 'content': ""You used `=` for variable assignment. Shouldn't there be a different operator for equality?"", 'alt': [""Let's check the documentation. What is the operator for equality?"", 'Are you sure that `=` checks for equality? How can we verify that?', 'If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?']}, {'role': 'user', 'content': ""I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.\n```python\n1. def is_palindrome(string):\n2.  rev_string = ''\n3.  for i in string:\n4.    rev_string = i + rev_string\n5.  if rev_string == string:\n6.    return True\n7.  else:\n8.    return False\n```""}, {'role': 'assistant', 'content': 'Looks good!'}, {'role': 'user', 'content': 'Thank you so much!'}]}"
+"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>","Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```","def reverse_list(lst):
+   return lst[-1:]","On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.",Replace `return lst[-1:]` with `return lst[::-1]` on line 2.,"assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]",12_41_reversing_a_list,"<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.\n## Example Cases:\n```\nreverse_list([1, 2, 3]) => [3, 2, 1]\nreverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]\nreverse_list([]) => []\nreverse_list([""Hi"", ""Hello"", ""Goodbye""]) => [""Goodbye"", ""Hello"", ""Hi""]\n```\n</problem>\n<bug_code>\n1. def reverse_list(lst):\n2.    return lst[-1:]\n</bug_code>\n<bug_desc>\nOn line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.\n</bug_desc>\n<bug_fixes>\nReplace `return lst[-1:]` with `return lst[::-1]` on line 2.\n</bug_fixes>\n<unit_tests>\nassert reverse_list([1, 2, 3]) == [3, 2, 1]\nassert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]\nassert reverse_list([]) == []\nassert reverse_list([""Hi"", ""Hello"", ""Goodbye""]) == [""Goodbye"", ""Hello"", ""Hi""]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to reverse the elements of a list but it's not working.""}, {'role': 'assistant', 'content': ""Can you describe how you're trying to reverse the list?"", 'alt': [""Can you describe the problem you're having in more detail?"", ""Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?"", ""Let's start with a warm-up question. What does the slicing operator `[-1:]` do?"", 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?', 'Where can you learn more about how to reverse a list?']}, {'role': 'user', 'content': 'Sure, I used the `[-1:]` slicing operator.'}, {'role': 'assistant', 'content': 'Can you describe what the `[-1:]` slicing operator does?', 'alt': ['How do you think this reverses the list?', ""Do you notice a pattern in your function's outputs?"", 'How does slicing work in Python?', 'What happens when you run `reverse_list([1, 2, 3])`? What do you observe?']}, {'role': 'user', 'content': ""I think it should return a list in reverse order but it's returning the last element of the list instead."", 'alt': ['The `[-1:]` slicing operator should return a list in reverse order.']}, {'role': 'assistant', 'content': ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'alt': [""Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?"", 'Good. So where can you learn more about how to reverse a list?', ""Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?"", 'Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?']}, {'role': 'user', 'content': ""I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.\n```python\n def reverse_list(lst):\n    return lst[::-1]\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you run into any other problems!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>","Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```","def limitFinder(lst, limit):
+ lst2 = []
+ for i in lst2:
+   if i < limit:
+     lst2.append(i)
+ return lst2","On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.",Replace `lst2` with `lst` on line 3.,"assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []",13_42_limit,"<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+","{'system': '<problem>\nWrite a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.\n## Example Cases:\n```\nlimitFinder([1, 2, 3, 4, 5], 3) => [1, 2]\nlimitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]\nlimitFinder([100, 2, 145, 3,8], 0) => []\nlimitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]\nlimitFinder([], 0) => []\n```\n</problem>\n<bug_code>\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst2:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n</bug_code>\n<bug_desc>\nOn line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.\n</bug_desc>\n<bug_fixes>\nReplace `lst2` with `lst` on line 3.\n</bug_fixes>\n<unit_tests>\nassert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]\nassert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]\nassert limitFinder([100, 2, 145, 3,8], 0) == []\nassert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]\nassert limitFinder([], 0) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My program seems to always return an empty list instead of a list of numbers, can you help?'}, {'role': 'assistant', 'content': 'Sure. Can you walk me through what each line does?', 'alt': ['Sure. Can you tell me which list are you supposed to find the numbers from?', 'Sure, can you explain what line 3 does?', 'Sure. It looks like your for-loop is never executed. Do you know why?']}, {'role': 'user', 'content': 'Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.'}, {'role': 'assistant', 'content': 'Ok, what about the next line?'}, {'role': 'user', 'content': 'Line 3 - loops through all the numbers in `lst2`', 'alt': ['It looks like line 3 loops through the wrong list! Is that the issue here?']}, {'role': 'assistant', 'content': 'How many numbers are in `lst2`?', 'alt': ['Will the for loop ever be executed?', 'Is `lst2` empty?', 'How many times will the for loop execute?', 'Is that the list that you want to loop through?']}, {'role': 'user', 'content': '`Oh I see, `lst2` is empty, so the for loop is never executed.'}, {'role': 'assistant', 'content': 'Correct, how would you fix your for loop now?'}, {'role': 'user', 'content': 'Should I be looping over `lst` instead?'}, {'role': 'assistant', 'content': 'Yes, what does the new code look like?'}, {'role': 'user', 'content': 'This code works, thank you!\n```python\n1. def limitFinder(lst, limit):\n2.  lst2 = []\n3.  for i in lst:\n4.    if i < limit:\n5.      lst2.append(i)\n6.  return lst2\n```'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = ""True""
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>","Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```","def isTwice(str, chr):
+ count = 0
+ for i in str:
+   if i == chr:
+     count+=1
+
+ if count >= 2:
+   return true
+ else:
+   return false","On line 8, the function throws a NameError since `true` is not a boolean value.",Replace `true` with `True` and `false` with `False` on lines 8 and 10.,"assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False",14_43_used_twice,"<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice(""hello"", ""l"") => True
+isTwice(""hello"", ""o"") => False
+isTwice(""hello"", ""h"") => False
+isTwice("""", ""e"") => False
+isTwice(""I'm a string!"", "" "") => True
+isTwice(""Hey, I'm a string!"", "" "") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice(""hello"", ""l"") == True
+assert isTwice(""hello"", ""o"") == False
+assert isTwice(""hello"", ""h"") == False
+assert isTwice("""", ""e"") == False
+assert isTwice(""I'm a string!"", "" "") == True
+assert isTwice(""Hey, I'm a string!"", "" "") == False
+</unit_tests>
+","{'system': '<problem>\nWrite a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.\n## Example Cases:\n```\nisTwice(""hello"", ""l"") => True\nisTwice(""hello"", ""o"") => False\nisTwice(""hello"", ""h"") => False\nisTwice("""", ""e"") => False\nisTwice(""I\'m a string!"", "" "") => True\nisTwice(""Hey, I\'m a string!"", "" "") => False\n```\n</problem>\n<bug_code>\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return true\n9.  else:\n10.    return false\n</bug_code>\n<bug_desc>\nOn line 8, the function throws a NameError since `true` is not a boolean value.\n</bug_desc>\n<bug_fixes>\nReplace `true` with `True` and `false` with `False` on lines 8 and 10.\n</bug_fixes>\n<unit_tests>\nassert isTwice(""hello"", ""l"") == True\nassert isTwice(""hello"", ""o"") == False\nassert isTwice(""hello"", ""h"") == False\nassert isTwice("""", ""e"") == False\nassert isTwice(""I\'m a string!"", "" "") == True\nassert isTwice(""Hey, I\'m a string!"", "" "") == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I wrote this code and it isn't working. can you help me?""}, {'role': 'assistant', 'content': ""First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?"", 'alt': ['It seems that you have a `NameError` error in your code. Are you able to find where this error is?', 'Let\'s talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `""False""` is?', ""Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?""]}, {'role': 'user', 'content': ""I have a syntax error. My code won't even compile."", 'alt': [""I think it's a runtime error because it just stopped running."", ""Can you tell me what the different types of errors are? I don't remember."", ""It's a logic error, I think. That's the one that is the result of a grammatical error, right?""]}, {'role': 'assistant', 'content': ""I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?"", 'alt': [""Can you write a code snippet of assigning `False` to a boolean variable called 'var'?"", 'Where is the syntax error located in your code? You look for the line number.', 'How do you know that it is a syntax error? What are the different types of errors?']}, {'role': 'user', 'content': '`var = True`', 'alt': ['`var = true`', 'var = 1', 'var = ""True""']}, {'role': 'assistant', 'content': ""That's right. Is this what you wrote in your code on line 8?"", 'alt': [""That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?"", 'Can you point out in your code where you use boolean variables?']}, {'role': 'user', 'content': ""No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead."", 'alt': [""The code would get a syntax error and it wouldn't run."", ""I'm not sure what you are asking.""]}, {'role': 'assistant', 'content': ""That's right! How can you modify your `isTwice` function now to fix this error?""}, {'role': 'user', 'content': 'Oh! I found it! I was returning all lowercase True and False values! I will fix it.\n```python\n1. def isTwice(str, chr):\n2.  count = 0\n3.  for i in str:\n4.    if i == chr:\n5.      count+=1\n6.\n7.  if count >= 2:\n8.    return True\n9.  else:\n10.    return False\n```'}, {'role': 'assistant', 'content': 'Looks like it works now. Good job!'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       max_len = max(len(crt_str), max_len)        
+
+       pos = s.find(t, start)
+   
+   last_str = s[start:]
+   max_len = max(len(last_str), max_len)
+
+   return max_len","The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.",On line 8 insert the code `start = pos + len(t)`.,"assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_56_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n</bug_code>\n<bug_desc>\nThe value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.\n</bug_desc>\n<bug_fixes>\nOn line 8 insert the code `start = pos + len(t)`.\n</bug_fixes>\nOn line 11 insert a new line with `ind += len(t)`.\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code does not stop and I do not understand why, can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?"", 'alt': ['Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.', 'Sure. Can you tell me the role of the variable `start`?']}, {'role': 'user', 'content': 'In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.        start = pos + len(t)\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       crt_len = len(crt_str)
+       if crt_len > max_len:
+           max_len = crt_len
+       start = pos + len(t)
+       pos = s.find(t, start)
+   return max_len","The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.","After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```","assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_46_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    return max_len\n</bug_code>\n<bug_desc>\nThe code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.\n</bug_desc>\n<bug_fixes>\nAfter line 11, insert the following outside the while loop scope:\n```py\nlast_str = s[start:]\nlast_len = len(last_str)\nif last_len > max_len:\n       max_len = last_len\n```\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?'}, {'role': 'assistant', 'content': 'I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?', 'alt': ['Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?', 'Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?', 'Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?', ""Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?"", 'Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?', 'Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?']}, {'role': 'user', 'content': '`max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.'}, {'role': 'assistant', 'content': ""Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?"", 'alt': ['Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?', 'Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?', 'Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?']}, {'role': 'user', 'content': 'Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    \n13.    last_str = s[start:]\n14.    last_len = len(last_str)\n15.    if last_len > max_len:\n16.       max_len = last_len\n17.    \n18.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>","Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```","def top_k(lst, k):
+   result = []
+   for i in range(k):
+       result.append(max(lst))
+       lst.pop(max(lst))
+   return result","The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.","On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`","assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]",17_47_topk,"<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+","{'system': '<problem>\nWrite a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.\n## Example Cases:\n```\ntop_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]\ntop_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]\ntop_k([], 0) => []\ntop_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]\ntop_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]\n```\n</problem>\n<bug_code>\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.pop(max(lst))\n6.    return result\n</bug_code>\n<bug_desc>\nThe function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.\n</bug_desc>\n<bug_fixes>\nOn line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`\n</bug_fixes>\n<unit_tests>\nassert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]\nassert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]\nassert top_k([], 0) == []\nassert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]\nassert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi. I am confused. My code doesn’t seem to work. Can you help?'}, {'role': 'assistant', 'content': ""Hello. Sure, let's see. Do you know what might be the issue?""}, {'role': 'user', 'content': 'I think the problem is with the `.pop()` method. It seems to have issues with indexing.', 'alt': ['When I use the `.pop()` method, I get an IndexError on some inputs.', ""For some inputs, I get an error and other inputs don't produce the right answer.""]}, {'role': 'assistant', 'content': ""Ok, no worries. Let's review your code line by line. Could you please explain it to me?"", 'alt': [""Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?"", ""Let's start with a warm-up question. What does the `.pop()` method do?"", ""Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?"", 'Could you please explain what line 5 in your code does?', 'Let’s look into the Python documentation. Can you describe what the `.pop()` method does?']}, {'role': 'user', 'content': 'Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.'}, {'role': 'assistant', 'content': 'Good. What can you do right now to debug your code and diagnose what might be causing the problem?'}, {'role': 'user', 'content': 'Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(max(lst))\n6.        lst.pop(max(lst))\n7.        print(lst)\n8.    return result\n```', 'alt': ['I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.']}, {'role': 'assistant', 'content': 'Are there other ways of debugging the `.pop()` method?', 'alt': ['What happens if you use a different input value for the `top_k()` function?', 'Have you considered using the debugger?', 'What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?']}, {'role': 'user', 'content': 'Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        print(lst)\n6.        lst.pop(1)\n7.        print(lst)\n8.    return result \n```'}, {'role': 'assistant', 'content': 'Perhaps there are other solutions you can use aside from `.pop()`?', 'alt': ['Where can we learn more about other list methods that can help us remove elements from an array?', 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?']}, {'role': 'user', 'content': ""I think but I can't remember them...""}, {'role': 'assistant', 'content': 'I would suggest checking Python documentation. Perhaps you will be able to find useful information there?'}, {'role': 'user', 'content': 'Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.\n```python\n1. def top_k(lst, k):\n2.    result = []\n3.    for i in range(k):\n4.        result.append(max(lst))\n5.        lst.remove(max(lst))\n6.    return result\n```'}, {'role': 'assistant', 'content': 'Great! Please let me know if you need help with anything else.'}]}"
+"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `""a""`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don't think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return ""Password added!""
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>","Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```","def validate_or_add_password(menu_choice, password, passwords_dict):
+   if menu_choice == ""v"":
+       if password in passwords_dict.values():
+           return ""Welcome!""
+       else:
+           return ""I don't know you.""
+   elif menu_choice == ""a"":
+       if password in passwords_dict.values():
+           return ""Password already exists!""
+       else:
+           return ""Password added!""",The function does not add `password` to `passwords_dict` as specified in the instructions.,After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`,"passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""",18_48_password_validator,"<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns ""I don't know you."". If menu_choice is 'a', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".
+## Example Cases:
+```
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+validate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""
+validate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don't know you.""
+validate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""
+passwords_dict[4] => ""newpass""
+validate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == ""v"":
+3.        if password in passwords_dict.values():
+4.            return ""Welcome!""
+5.        else:
+6.            return ""I don't know you.""
+7.    elif menu_choice == ""a"":
+8.        if password in passwords_dict.values():
+9.            return ""Password already exists!""
+10.        else:
+11.            return ""Password added!""
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}
+assert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""
+assert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don't know you.""
+assert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""
+assert passwords_dict[4] == ""newpass""
+assert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""
+</unit_tests>
+","{'system': '<problem>\nCreate a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:\n* `menu_choice (str)`: either \'v\' for validate or \'a\' for add password\n* `password (str)`: the password to be validated or added\n* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords\n\nThe function returns a string ""Welcome!"" if the password is found in the dictionary and menu_choice is \'v\'. If the password is not found in the dictionary, the function returns ""I don\'t know you."". If menu_choice is \'a\', the function adds the password to the dictionary and returns ""Password added!"". If the password is already in the dictionary, the function returns ""Password already exists!"".\n## Example Cases:\n```\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nvalidate_or_add_password(""v"", ""abc123"", passwords_dict) => ""Welcome!""\nvalidate_or_add_password(""v"", ""xyz789"", passwords_dict) => ""I don\'t know you.""\nvalidate_or_add_password(""a"", ""abc123"", passwords_dict) => ""Password already exists!""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password added!""\npasswords_dict[4] => ""newpass""\nvalidate_or_add_password(""a"", ""newpass"", passwords_dict) => ""Password already exists!""\n```\n</problem>\n<bug_code>\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            return ""Password added!""\n</bug_code>\n<bug_desc>\nThe function does not add `password` to `passwords_dict` as specified in the instructions.\n</bug_desc>\n<bug_fixes>\nAfter line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`\n</bug_fixes>\n<unit_tests>\npasswords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}\nassert validate_or_add_password(""v"", ""abc123"", passwords_dict) == ""Welcome!""\nassert validate_or_add_password(""v"", ""xyz789"", passwords_dict) == ""I don\'t know you.""\nassert validate_or_add_password(""a"", ""abc123"", passwords_dict) == ""Password already exists!""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password added!""\nassert passwords_dict[4] == ""newpass""\nassert validate_or_add_password(""a"", ""newpass"", passwords_dict) == ""Password already exists!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello. I need help with my code.', 'alt': [""I need help with this code. It's throwing a `KeyError`. I'm not sure why.""]}, {'role': 'assistant', 'content': 'Can you describe the issue you are experiencing?', 'alt': ['Can you walk me through what your code does line by line when `menu_choice` is `""a""`?', 'Let\'s go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `""a""`?']}, {'role': 'user', 'content': 'I am getting a `KeyError: 4`. Not really sure why.', 'alt': [""My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.""]}, {'role': 'assistant', 'content': ""Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?"", 'alt': ['What does `KeyError` typically mean and why does it occur?', ""Let's look at the example cases, where do you see `4` being used as a key?"", ""Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?"", ""Let's look at your error again. What line is throwing the `KeyError`?"", 'Which parameter in the `validate_or_add_password` function is a data structure that uses keys?']}, {'role': 'user', 'content': 'After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.'}, {'role': 'assistant', 'content': ""Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?"", 'alt': ['Good. Which test case do you think is causing the `KeyError`?', ""Let's look at your error again. What line is throwing the `KeyError`?""]}, {'role': 'user', 'content': 'Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""`. However, `passwords_dict` is initialized to `passwords_dict = {1: ""abc123"", 2: ""qwerty"", 3: ""password""}` and does not have 4 as a key.', 'alt': ['Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == ""newpass""` after calling `validate_or_add_password(""a"", ""newpass"", passwords_dict)` in an attempt to add ""newpass"" as a password.']}, {'role': 'assistant', 'content': 'Good. What is the statement right before line 18 attempting to do?'}, {'role': 'user', 'content': 'Oh! I get it now! This example case is testing whether my function adds `""newpass""` to `passwords_dict`. I don\'t think I do that. I thought I just need to print ""Password added!"". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.\n```python\n1. def validate_or_add_password(menu_choice, password, passwords_dict):\n2.    if menu_choice == ""v"":\n3.        if password in passwords_dict.values():\n4.            return ""Welcome!""\n5.        else:\n6.            return ""I don\'t know you.""\n7.    elif menu_choice == ""a"":\n8.        if password in passwords_dict.values():\n9.            return ""Password already exists!""\n10.        else:\n11.            passwords_dict[len(passwords_dict) + 1] = password\n12.            return ""Password added!""\n```'}, {'role': 'assistant', 'content': 'Good. Does your code pass all the example cases?'}, {'role': 'user', 'content': 'Yes it does thank you for your help. I learned more about `KeyError`s today.'}, {'role': 'assistant', 'content': ""You're welcome to let me know if I can be of any further assistance.""}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for i in range(1, len(sentence)):
+       if sentence[i] == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   if not space_mode:
+       words +=1
+   return words","On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.","On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_49_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for i in range(1, len(sentence)):\n5.        if sentence[i] == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    if not space_mode:\n12.        words +=1\n13.    return words\n</bug_code>\n<bug_desc>\nOn line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `(1, len(sentence))` with `(len(sentence)):`\nOn line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am having a problem with this programming problem. My count seems off.'}, {'role': 'assistant', 'content': 'Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?', 'alt': ['Are there specific inputs that give you the wrong answer or is it always wrong?', 'Off in what way?']}, {'role': 'user', 'content': 'Yes! My output seems to be 1 less than it should be.', 'alt': ['My output is sometimes correct and sometimes lower than it should be']}, {'role': 'assistant', 'content': 'Does this happen with all inputs or just some inputs?'}, {'role': 'user', 'content': 'I only seem to notice it on sentences that begin with ""I"" or ""A"", so I guess one-letter words.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'I thought it was working properly, but I just checked the sentence ""I walked the dog"" and the output was wrong.']}, {'role': 'assistant', 'content': 'Can you check how your function handles the beginning of the input? It seems like the issue might be there.', 'alt': ['It only happens with sentences that start with short words, it seems.', 'Where do you count your first word?']}, {'role': 'user', 'content': ""Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for i in range(len(sentence)):\n        if sentence[i] == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great!'}]}"
+"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one.
+Assistant: Hm, ok. Can you walk me through your code? 
+	<alt>Does this happen with all inputs?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.
+Assistant: Ok. What happens when you reach the end of the sentence?
+    <alt>Does your loop count the last word in the sentence?
+User: Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great! Let me know if you have any other questions.
+User: Thank you so much for your help!
+</dialogue>","Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```","def count_words(sentence):
+   words = 0
+   space_mode = True
+   for c in sentence:
+       if c == ' ':
+           if not space_mode:
+               words += 1
+           space_mode = True
+       else:
+           space_mode = False
+   return words",There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.,"Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```","assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0",19_50_word_counter,"<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. 
+## Example Cases:
+```
+count_words(""hello world"") => 2
+count_words(""hello    world"") => 2
+count_words(""This is a sentence"") => 4
+count_words(""I love Python"") => 3
+count_words("""") => 0
+count_words("" "") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words(""hello world"") == 2
+assert count_words(""hello    world"") == 2
+assert count_words(""This is a sentence"") == 4
+assert count_words(""I love Python"") == 3
+assert count_words("""") == 0
+assert count_words("" "") == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words("" This is a sentence "")` returns 4. \n## Example Cases:\n```\ncount_words(""hello world"") => 2\ncount_words(""hello    world"") => 2\ncount_words(""This is a sentence"") => 4\ncount_words(""I love Python"") => 3\ncount_words("""") => 0\ncount_words("" "") => 0\n```\n</problem>\n<bug_code>\n1. def count_words(sentence):\n2.    words = 0\n3.    space_mode = True\n4.    for c in sentence:\n5.        if c == \' \':\n6.            if not space_mode:\n7.                words += 1\n8.            space_mode = True\n9.        else:\n10.            space_mode = False\n11.    return words\n</bug_code>\n<bug_desc>\nThere is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.\n</bug_desc>\n<bug_fixes>\nInsert the following after line 10 outside the scope of the for loop:\n```py\nif not space_mode:\n     words +=1\n```\n</bug_fixes>\n<unit_tests>\nassert count_words(""hello world"") == 2\nassert count_words(""hello    world"") == 2\nassert count_words(""This is a sentence"") == 4\nassert count_words(""I love Python"") == 3\nassert count_words("""") == 0\nassert count_words("" "") == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm writing some code to count words and it doesn't seem to be working""}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': [""Let's walk through your code line by line. Can you explain what your code does?"", 'When you run your code, what do you observe?']}, {'role': 'user', 'content': 'My output counts are off by one.'}, {'role': 'assistant', 'content': 'Hm, ok. Can you walk me through your code?', 'alt': ['Does this happen with all inputs?', 'Can you give me an example input where this happens? Include what you expect and what you get.']}, {'role': 'user', 'content': 'Sure! Essentially, I walk through each character in the sentence. I only want to count a word when the characters change from spaces to letters, so I keep a `space_mode` boolean to keep track of when we are in between words.'}, {'role': 'assistant', 'content': 'Ok. What happens when you reach the end of the sentence?', 'alt': ['Does your loop count the last word in the sentence?']}, {'role': 'user', 'content': ""Oh. I think I see the issue. I'm not counting the last word in the sentence. The for loop always ends on the last letter in the sentence which typically is not a space, so I never count the last word. `space_mode` is typically false at the end of the sentence, so I never increment `words`. I'll update my code to account for this.\n```python\n def count_words(sentence):\n    words = 0\n    space_mode = True\n    for c in sentence:\n        if c == ' ':\n            if not space_mode:\n                words += 1\n            space_mode = True\n        else:\n            space_mode = False\n    if not space_mode:\n        words +=1\n    return words\n```""}, {'role': 'assistant', 'content': 'Great! Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thank you so much for your help!'}]}"
+"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello I need help with my code, it is not giving me the output I expect.
+Assistant: Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?
+	<alt>Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?
+	<alt>Sure, have you tried the test cases as inputs? What have you observed about the output?
+	<alt>Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?
+	<alt>Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?
+	<alt>Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?
+User: For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, 'Cookies cannot be split evenly. Bought more cookies.')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.
+	<alt>My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.
+	<alt>I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.
+	<alt>I need `cookies` to be a multiple of the `people` to get the right answer.
+Assistant: Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?
+	<alt>Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?
+	<alt>How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?
+User: So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well
+	<alt>Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now
+<code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    leftOverCookies = cookies % people
+6.    newCookies = people - leftOverCookies + cookies
+7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+
+</code>
+Assistant: Sounds good! Let me know if you need any more help.
+User: Thanks!
+</dialogue>","Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```","def split (cookies, people):
+ if cookies % people == 0:
+   return (cookies // people, 0, ""Cookies can be split evenly!"")
+ else:
+   newCookies = cookies - (cookies % people)
+   return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")","On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.","Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.","assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")",2_18_splitting_cookies,"<problem>
+Write a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.
+
+## Example Cases:
+```
+split(10, 2) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+split(20, 4) => (5, 0, ""Cookies can be split evenly!"")
+split(10, 5) => (2, 0, ""Cookies can be split evenly!"")
+split(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+```
+</problem>
+<bug_code>
+1. def split (cookies, people):
+2.  if cookies % people == 0:
+3.    return (cookies // people, 0, ""Cookies can be split evenly!"")
+4.  else:
+5.    newCookies = cookies - (cookies % people)
+6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")
+</bug_code>
+<bug_desc>
+On line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.
+</bug_desc>
+<bug_fixes>
+Replace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.
+Replace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.
+Remove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.
+</bug_fixes>
+<unit_tests>
+assert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")
+assert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")
+assert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")
+assert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split(cookies:int, people:int) -> Tuple[int,int, str]` that takes in a number of cookies and a number of people. The function should find if the cookies can be split evenly amongst all people. If so, return a `Tuple` containing how many cookies each person will get and the number of leftover cookies, which is `0` and a string saying ""Cookies can be split evenly!"". If the cookies cannot be split evenly, then calculate the minimum number of cookies that need to be purchased to split the cookies evenly. The function should return the total number of cookies after the purchase, how many cookies each person will get then, and a string saying ""Cookies cannot be split evenly. Bought more cookies."" Assume that `people` and `cookies` are positive integers.\n\n## Example Cases:\n```\nsplit(10, 2) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 3) => (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nsplit(20, 4) => (5, 0, ""Cookies can be split evenly!"")\nsplit(10, 5) => (2, 0, ""Cookies can be split evenly!"")\nsplit(25, 10) => (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n```\n</problem>\n<bug_code>\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    newCookies = cookies - (cookies % people)\n6.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n</bug_code>\n<bug_desc>\nOn line 5, `newCookies` computes the maximum subset of cookies that can be split evenly among the people, which are less than the given number of cookies. However, the problem description asks for more cookies to be purchased, so the total number of cookies that is returned should be larger than the given number of cookies.\n</bug_desc>\n<bug_fixes>\nReplace line 5 with `purchasedCookies = people - cookies % people` and then insert a line after that containing `newCookies = cookies + purchasedCookies`.\nReplace `cookies - (cookies % people)` with `people - cookies % people + cookies` on line 5.\nRemove line 5. Add then insert the following lines in its place`leftOverCookies = cookies % people` and  `newCookies = people - leftOverCookies + cookies`.\n</bug_fixes>\n<unit_tests>\nassert split(10, 2) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 3) == (12, 4, ""Cookies cannot be split evenly. Bought more cookies."")\nassert split(20, 4) == (5, 0, ""Cookies can be split evenly!"")\nassert split(10, 5) == (2, 0, ""Cookies can be split evenly!"")\nassert split(25, 10) == (30, 3, ""Cookies cannot be split evenly. Bought more cookies."")\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello I need help with my code, it is not giving me the output I expect.'}, {'role': 'assistant', 'content': ""Let's look into what's going on. What happens when you try to run the sample test cases `split(10, 2)` and `split(10, 3)`?"", 'alt': [""Let's walk through your code. What is the output if your input is `(10, 2)` and `(10,3)`?"", 'Sure, have you tried the test cases as inputs? What have you observed about the output?', ""Here to help! Let's track the values of the variables in your code as we step through it. How do they change when the input is `(10, 2)` vs when the input is `(10, 3)`?"", ""Let's look at what happens when we go line by line. Can you tell me the values of `newCookies` for the different test inputs?"", ""Let's look at one of the test examples. If we can only assign whole cookies to each person, then in which case would we need to buy more cookies?""]}, {'role': 'user', 'content': 'For `split(10, 2)`, I get the correct answer which is `(5, 0, ""Cookies can be split evenly!"")`. But with `split(10, 3)`, I get `(9, 3, \'Cookies cannot be split evenly. Bought more cookies.\')` which is not the correct answer. It seems like the answer is only correct when the number of `cookies` is divisible by the number of `people`.', 'alt': ['My code gives the wrong output for inputs where the `cookies` are not divisible by the `people`.', 'I get the wrong answer for any case where the `cookies` are more or less than multiples of the `people`.', 'I need `cookies` to be a multiple of the `people` to get the right answer.']}, {'role': 'assistant', 'content': ""Let's look at the problem statement once again. When we do not have enough cookies for everyone, what should our code do?"", 'alt': ['Looks like we also need to make sure the `cookies` are sufficient for everyone. How could we do that?', 'How can we ensure that we give everyone the same amount of `cookies` when we can purchase more cookies?']}, {'role': 'user', 'content': 'So we need to ensure that everyone gets the same amount of cookies, and if there are any leftovers, we instead buy more cookies so everyone has the same amount. Let me update my code to reflect this as well\n```python\n1. def split (cookies, people):\n2.  if cookies % people == 0:\n3.    return (cookies // people, 0, ""Cookies can be split evenly!"")\n4.  else:\n5.    leftOverCookies = cookies % people\n6.    newCookies = people - leftOverCookies + cookies\n7.    return (newCookies, newCookies // people, ""Cookies cannot be split evenly. Bought more cookies."")\n```', 'alt': ['Ah I need to also ensure that everyone gets the same amount with buying more cookies if needed! Making this change now']}, {'role': 'assistant', 'content': 'Sounds good! Let me know if you need any more help.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Have you completed all the steps in the instructions?
+	<alt>Let's look at your function, can you explain what it is supposed to do?
+User: I don't know.
+Assistant: Can you explain what your function is supposed to do?
+	<alt>Do any of the test cases pass?
+	<alt>Have you skipped any steps in the instructions?
+User: My function takes in one list of words and compares it to another list.
+	<alt>My function compares two lists of words and then returns information about them.
+	<alt>I followed the prompt.
+Assistant: Okay, on what line of code does it take in those lists of words?
+	<alt>Does it do anything else?
+	<alt>Is that everything it is supposed to do according to the prompt?
+	<alt>Let's look at the first line of the function on line 1, does it take in two lists of words?
+User: On line 1.
+Assistant: Does that line take in those lists?
+	<alt>Do you see any problems on that line?
+	<alt>What should your function do after taking in those lines?
+User: Yes, it does.
+Assistant: Okay, so what is the next thing your function is supposed to do?
+	<alt>Let's check the loops where we compare the lists, what line do those start on?
+	<alt>How does your function compare the lists?
+User: It's supposed to compare the two lists and say if the word is spelled wrong.
+Assistant: Where is it supposed to put the information about the spelling?
+	<alt>How does it determine if the word is spelled wrong?
+	<alt>Let's examine the loop, what line does it start on?
+User: In a list called result.
+Assistant: Let's examine that list, where is it created?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+User: On line 2.
+Assistant: What happens to that list next?
+	<alt>Let's examine that list, what happens to it after it is made?
+	<alt>Let's examine that list, what lines is it modified on?
+	<alt>Do we do anything with that list after we finish adding to it?
+User: We add strings to it for if the word is spelled right.
+Assistant: Do we do anything else to it after we've finished with the loop?
+	<alt>How would that information be sent out of the function?
+	<alt>What information is supposed to be returned from the function?
+User: No, we don't.
+	<alt>I forgot to return result!
+Assistant: How can that information be used outside of this function?
+	<alt>What information is supposed to be returned from the function?
+User: I need to return result.
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.        return result
+</code>
+Assistant: Does it work now?
+User: No, it doesn't. 
+Assistant: Is it passing any of the test cases?
+	<alt>Look at what you added, why did you put it there?
+	<alt>Look at what you added, when should this happen?
+User: No, but the message changed to Assertion error.
+Assistant: Okay, let's look back at what you added. When should that code run?
+	<alt>Let's look at what you added. Should it be inside or outside the for-loop?
+User: Oh! I put it inside the loop!
+<code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+8.    return result
+</code>
+Assistant: Does it run correctly now?
+User: Yes! Thank you!
+</dialogue>","Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```","def spellchecker(words, words_to_check):
+   result = []
+   for word in words_to_check:
+       if word in words:
+           result.append(word + "" is spelled properly!"")
+       else:
+           result.append(word + "" is misspelled!"")",The function returns `None` instead of an iterable of strings.,"After line 7, insert `return result` with one indentation level.","assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']",20_51_spell_checker,"<problem>
+Write a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.
+## Example Cases:
+```
+list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) => ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+list(spellchecker([], ['bubbles', 'cup', 'food'])) => ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+```
+</problem>
+<bug_code>
+1. def spellchecker(words, words_to_check):
+2.    result = []
+3.    for word in words_to_check:
+4.        if word in words:
+5.            result.append(word + "" is spelled properly!"")
+6.        else:
+7.            result.append(word + "" is misspelled!"")
+</bug_code>
+<bug_desc>
+The function returns `None` instead of an iterable of strings.
+</bug_desc>
+<bug_fixes>
+After line 7, insert `return result` with one indentation level.
+</bug_fixes>
+<unit_tests>
+assert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]
+assert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]
+assert list(spellchecker(['bubbles', 'cup', 'food'], ['bubbles', 'cup', 'food', 'bubbles', 'cup', 'food'])) == ['bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!', 'bubbles is spelled properly!', 'cup is spelled properly!', 'food is spelled properly!']
+assert list(spellchecker([], ['bubbles', 'cup', 'food'])) == ['bubbles is misspelled!', 'cup is misspelled!', 'food is misspelled!']
+
+</unit_tests>
+","{'system': '<problem>\nWrite a function `spellchecker(words: List[str], words_to_check: List[str]) -> Iterable[str]` that takes in a list of words and a list of words to check. The function should return an iterable of strings that indicate whether or not each word in `words_to_check` are spelled properly. A word is spelled properly if it is in the `words` list. If a word is spelled properly, the string should say ""[word] is spelled properly!"". If a word is misspelled, the string should say ""[word] is misspelled!"". The order of the strings in the returned list should be the same as the order of the words in `words_to_check`.\n## Example Cases:\n```\nlist(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) => [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nlist(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) => [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nlist(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) => [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nlist(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) => [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n```\n</problem>\n<bug_code>\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n</bug_code>\n<bug_desc>\nThe function returns `None` instead of an iterable of strings.\n</bug_desc>\n<bug_fixes>\nAfter line 7, insert `return result` with one indentation level.\n</bug_fixes>\n<unit_tests>\nassert list(spellchecker([""dog"", ""cat"", ""giraffe"", ""horse"", ""dragon""], [""dogz"", ""cet"", ""giraffe"", ""horsee"", ""dragon""])) == [""dogz is misspelled!"", ""cet is misspelled!"", ""giraffe is spelled properly!"", ""horsee is misspelled!"", ""dragon is spelled properly!""]\nassert list(spellchecker([""apple"", ""banana"", ""orange"", ""pear"", ""grape""], [""apple"", ""baana"", ""orange"", ""pier"", ""grayp""])) == [""apple is spelled properly!"", ""baana is misspelled!"", ""orange is spelled properly!"", ""pier is misspelled!"", ""grayp is misspelled!""]\nassert list(spellchecker([\'bubbles\', \'cup\', \'food\'], [\'bubbles\', \'cup\', \'food\', \'bubbles\', \'cup\', \'food\'])) == [\'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\', \'bubbles is spelled properly!\', \'cup is spelled properly!\', \'food is spelled properly!\']\nassert list(spellchecker([], [\'bubbles\', \'cup\', \'food\'])) == [\'bubbles is misspelled!\', \'cup is misspelled!\', \'food is misspelled!\']\n\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of the test cases passing?', 'Have you completed all the steps in the instructions?', ""Let's look at your function, can you explain what it is supposed to do?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Can you explain what your function is supposed to do?', 'alt': ['Do any of the test cases pass?', 'Have you skipped any steps in the instructions?']}, {'role': 'user', 'content': 'My function takes in one list of words and compares it to another list.', 'alt': ['My function compares two lists of words and then returns information about them.', 'I followed the prompt.']}, {'role': 'assistant', 'content': 'Okay, on what line of code does it take in those lists of words?', 'alt': ['Does it do anything else?', 'Is that everything it is supposed to do according to the prompt?', ""Let's look at the first line of the function on line 1, does it take in two lists of words?""]}, {'role': 'user', 'content': 'On line 1.'}, {'role': 'assistant', 'content': 'Does that line take in those lists?', 'alt': ['Do you see any problems on that line?', 'What should your function do after taking in those lines?']}, {'role': 'user', 'content': 'Yes, it does.'}, {'role': 'assistant', 'content': 'Okay, so what is the next thing your function is supposed to do?', 'alt': [""Let's check the loops where we compare the lists, what line do those start on?"", 'How does your function compare the lists?']}, {'role': 'user', 'content': ""It's supposed to compare the two lists and say if the word is spelled wrong.""}, {'role': 'assistant', 'content': 'Where is it supposed to put the information about the spelling?', 'alt': ['How does it determine if the word is spelled wrong?', ""Let's examine the loop, what line does it start on?""]}, {'role': 'user', 'content': 'In a list called result.'}, {'role': 'assistant', 'content': ""Let's examine that list, where is it created?"", 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?""]}, {'role': 'user', 'content': 'On line 2.'}, {'role': 'assistant', 'content': 'What happens to that list next?', 'alt': [""Let's examine that list, what happens to it after it is made?"", ""Let's examine that list, what lines is it modified on?"", 'Do we do anything with that list after we finish adding to it?']}, {'role': 'user', 'content': 'We add strings to it for if the word is spelled right.'}, {'role': 'assistant', 'content': ""Do we do anything else to it after we've finished with the loop?"", 'alt': ['How would that information be sent out of the function?', 'What information is supposed to be returned from the function?']}, {'role': 'user', 'content': ""No, we don't."", 'alt': ['I forgot to return result!']}, {'role': 'assistant', 'content': 'How can that information be used outside of this function?', 'alt': ['What information is supposed to be returned from the function?']}, {'role': 'user', 'content': 'I need to return result.\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.        return result\n```'}, {'role': 'assistant', 'content': 'Does it work now?'}, {'role': 'user', 'content': ""No, it doesn't.""}, {'role': 'assistant', 'content': 'Is it passing any of the test cases?', 'alt': ['Look at what you added, why did you put it there?', 'Look at what you added, when should this happen?']}, {'role': 'user', 'content': 'No, but the message changed to Assertion error.'}, {'role': 'assistant', 'content': ""Okay, let's look back at what you added. When should that code run?"", 'alt': [""Let's look at what you added. Should it be inside or outside the for-loop?""]}, {'role': 'user', 'content': 'Oh! I put it inside the loop!\n```python\n1. def spellchecker(words, words_to_check):\n2.    result = []\n3.    for word in words_to_check:\n4.        if word in words:\n5.            result.append(word + "" is spelled properly!"")\n6.        else:\n7.            result.append(word + "" is misspelled!"")\n8.    return result\n```'}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: There is an issue with my code.
+Assistant: Can you describe the issue to me?
+	<alt>Let's assume that `temp` is 32. Can you explain your code to me line by line?
+User: My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It's not freezing!"" Why is that happening?
+Assistant: Let's take a look at the if-statement block. Do you remember what the ""<"" operator does?
+	<alt>Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?
+User: That is the ""less than"" operator. It compares `c` to 0.
+	<alt>That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.
+Assistant: Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?
+	<alt>Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?
+	<alt>Can you explain what the ""<="" operator does?
+User: When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.
+Assistant: Good. Could you explain what happens when `c` is equal to 0 on line 3?
+	<alt>Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Good. Now on line 3, what should your function return if `c` is equal to 0?
+User: The function returns ""It's not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".
+	<alt>Oh... I see the problem now. I don't want to return ""It's not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".
+Assistant: Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?
+	<alt>Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.
+User: I should use the ""<="" operator! Let me try that.
+<code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c <= 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</code>
+Assistant: Good work!
+</dialogue>","Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```","def fToC(temp):
+ c = (temp - 32) * (5/9)
+ if c < 0:
+   return ""Freezing!""
+ else:
+   return ""It's not freezing!""","If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""","On line 3, change `<` to `<=`.","assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""",21_52_fahrenheit_to_celsius_converter,"<problem>
+Write a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It's not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \frac{5}{9}$. Note that the function should return a string, not a float.
+## Example Cases:
+```
+fToC(32.0) => ""Freezing!""
+fToC(0.5) => ""Freezing!""
+fToC(45.0) => ""It's not freezing!""
+fToC(-5.4) == ""Freezing!""
+```
+</problem>
+<bug_code>
+1. def fToC(temp):
+2.  c = (temp - 32) * (5/9)
+3.  if c < 0:
+4.    return ""Freezing!""
+5.  else:
+6.    return ""It's not freezing!""
+</bug_code>
+<bug_desc>
+If `temp` is equal to 32, the function returns ""It's not freezing!"" rather than ""Freezing!""
+</bug_desc>
+<bug_fixes>
+On line 3, change `<` to `<=`.
+</bug_fixes>
+<unit_tests>
+assert fToC(32.0) == ""Freezing!""
+assert fToC(0.5) == ""Freezing!""
+assert fToC(45.0) == ""It's not freezing!""
+assert fToC(-5.4) == ""Freezing!""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `fToC(temp: float) -> str` that takes in a temperature in Fahrenheit and returns a string that indicates whether or not the temperature is below freezing. If the temperature in Celcius is less than or equal to 0, the string should say ""Freezing!"". If the temperature in Celsius is above 0, the string should say ""It\'s not freezing!"". The formula for converting Fahrenheit to Celsius is $C = (F - 32) * \\frac{5}{9}$. Note that the function should return a string, not a float.\n## Example Cases:\n```\nfToC(32.0) => ""Freezing!""\nfToC(0.5) => ""Freezing!""\nfToC(45.0) => ""It\'s not freezing!""\nfToC(-5.4) == ""Freezing!""\n```\n</problem>\n<bug_code>\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c < 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n</bug_code>\n<bug_desc>\nIf `temp` is equal to 32, the function returns ""It\'s not freezing!"" rather than ""Freezing!""\n</bug_desc>\n<bug_fixes>\nOn line 3, change `<` to `<=`.\n</bug_fixes>\n<unit_tests>\nassert fToC(32.0) == ""Freezing!""\nassert fToC(0.5) == ""Freezing!""\nassert fToC(45.0) == ""It\'s not freezing!""\nassert fToC(-5.4) == ""Freezing!""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'There is an issue with my code.'}, {'role': 'assistant', 'content': 'Can you describe the issue to me?', 'alt': [""Let's assume that `temp` is 32. Can you explain your code to me line by line?""]}, {'role': 'user', 'content': 'My code works for most cases, but when I write 32, which should give me ""Freezing!"", it gives me ""It\'s not freezing!"" Why is that happening?'}, {'role': 'assistant', 'content': 'Let\'s take a look at the if-statement block. Do you remember what the ""<"" operator does?', 'alt': [""Let's take a look at the if-statement block in line 3. What happens if `c` is equal to 0?""]}, {'role': 'user', 'content': 'That is the ""less than"" operator. It compares `c` to 0.', 'alt': ['That is the ""less than"" operator. It returns true if `c` is less than 0 and false otherwise.']}, {'role': 'assistant', 'content': 'Could you explain that more clearly? What is returned by `c < 0` when `c` is 1 and what is returned when `c` is -1?', 'alt': ['Can you explain that a bit more, what is returned by `c < 0` when `c` is equal to 0?', 'Can you explain what the ""<="" operator does?']}, {'role': 'user', 'content': 'When `c` is 1, `c < 0` returns False. When `c` is -1, `c < 0` returns True.'}, {'role': 'assistant', 'content': 'Good. Could you explain what happens when `c` is equal to 0 on line 3?', 'alt': ['Good. Now, what operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'Good. Now on line 3, what should your function return if `c` is equal to 0?']}, {'role': 'user', 'content': 'The function returns ""It\'s not freezing!"" when `c` is equal to 0, but I want it to return ""Freezing!"".', 'alt': ['Oh... I see the problem now. I don\'t want to return ""It\'s not freezing!"" when `c` is equal to 0, I want to return ""Freezing!"". I should change the ""<"" to ""<="".']}, {'role': 'assistant', 'content': 'Which operator should you use on line 3 if you want to return ""Freezing!"" when `c` is equal to 0?', 'alt': [""Let's check the Python documentation for an operator that checks if two numbers are less than or equal to each other.""]}, {'role': 'user', 'content': 'I should use the ""<="" operator! Let me try that.\n```python\n1. def fToC(temp):\n2.  c = (temp - 32) * (5/9)\n3.  if c <= 0:\n4.    return ""Freezing!""\n5.  else:\n6.    return ""It\'s not freezing!""\n```'}, {'role': 'assistant', 'content': 'Good work!'}]}"
+"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm having a problem with my code
+	<alt>Hi! My code seems to sometimes give answers that are very off.
+Assistant: What seems to be the issue?
+	<alt>Can you walk me through your function line by line?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is divisible by 10?
+User: My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.
+Assistant: Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?
+	<alt>Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?
+	<alt>Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?
+	<alt>Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?
+User: First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.
+Assistant: Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?
+	<alt>What operator should you use to check whether a number is a multiple of 10?
+	<alt>Where can you learn more about Python operators?	
+User: Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...
+Assistant: Let's take a look at the Python documentation to see if there is a different operator that does what you want.
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Oh, interesting. The modulus operator seems to fit. I'll modify my code and see if it works. It looks like it does!
+<code>
+ def cookiePurchase(cookies):
+    price = cookies * 1.75
+    discount = 0
+    if cookies > 10 and cookies % 10 == 0:
+        discount = price * 0.1
+        price = price - discount
+    return {""discount"": discount, ""price"": price}
+
+</code>
+Assistant: Great! Glad to help.
+User: Thank you very much!
+</dialogue>","Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```","def cookiePurchase(cookies):
+   price = cookies * 1.75
+   discount = 0
+   if cookies > 10 and cookies / 10 == 0:
+       discount = price * 0.1
+       price = price - discount
+   return {""discount"": discount, ""price"": price}","On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.","On line 4, replace `/` with `%` and on line 4.","assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}",22_53_cookie_purchase,"<problem>
+Write a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.
+## Example Cases:
+```
+cookiePurchase(2) => {'discount': 0.0, 'price': 3.5}
+cookiePurchase(70) => {'discount': 12.25, 'price': 110.25}
+cookiePurchase(22) => {'discount': 0.0, 'price': 38.5}
+cookiePurchase(10) => {'discount': 0.0, 'price': 17.5}
+cookiePurchase(20) => {'discount': 3.5, 'price': 31.5}
+```
+</problem>
+<bug_code>
+1. def cookiePurchase(cookies):
+2.    price = cookies * 1.75
+3.    discount = 0
+4.    if cookies > 10 and cookies / 10 == 0:
+5.        discount = price * 0.1
+6.        price = price - discount
+7.    return {""discount"": discount, ""price"": price}
+</bug_code>
+<bug_desc>
+On line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `/` with `%` and on line 4.
+</bug_fixes>
+<unit_tests>
+assert cookiePurchase(2) == {'discount': 0, 'price': 3.5}
+assert cookiePurchase(70) == {'discount': 12.25, 'price': 110.25}
+assert cookiePurchase(22) == {'discount': 0, 'price': 38.5}
+assert cookiePurchase(10) == {'discount': 0, 'price': 17.5}
+assert cookiePurchase(20) == {'discount': 3.5, 'price': 31.5}
+</unit_tests>
+","{'system': '<problem>\nWrite a function `cookiePurchase(cookies: float) -> dict` that takes in the number of cookies a customer wants to purchase and returns a dictionary with the total price of the cookies and the discount that the customer will receive. The price of a cookie is $1.75. If the customer purchases more than 10 cookies and the number of cookies is a multiple of 10, then the customer will receive a 10% discount. The function should return a dictionary with the keys `price` and `discount`. The `discount` key should map to the amount of the discount and the `price` key should map to the total price of the cookies after the discount is applied. Assume that the customer will always purchase a positive number of cookies.\n## Example Cases:\n```\ncookiePurchase(2) => {\'discount\': 0.0, \'price\': 3.5}\ncookiePurchase(70) => {\'discount\': 12.25, \'price\': 110.25}\ncookiePurchase(22) => {\'discount\': 0.0, \'price\': 38.5}\ncookiePurchase(10) => {\'discount\': 0.0, \'price\': 17.5}\ncookiePurchase(20) => {\'discount\': 3.5, \'price\': 31.5}\n```\n</problem>\n<bug_code>\n1. def cookiePurchase(cookies):\n2.    price = cookies * 1.75\n3.    discount = 0\n4.    if cookies > 10 and cookies / 10 == 0:\n5.        discount = price * 0.1\n6.        price = price - discount\n7.    return {""discount"": discount, ""price"": price}\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if the quotient `cookies` and 10 is 0 instead of checking whether `cookies` is a multiple of 10.\n</bug_desc>\n<bug_fixes>\nOn line 4, replace `/` with `%` and on line 4.\n</bug_fixes>\n<unit_tests>\nassert cookiePurchase(2) == {\'discount\': 0, \'price\': 3.5}\nassert cookiePurchase(70) == {\'discount\': 12.25, \'price\': 110.25}\nassert cookiePurchase(22) == {\'discount\': 0, \'price\': 38.5}\nassert cookiePurchase(10) == {\'discount\': 0, \'price\': 17.5}\nassert cookiePurchase(20) == {\'discount\': 3.5, \'price\': 31.5}\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I'm having a problem with my code"", 'alt': ['Hi! My code seems to sometimes give answers that are very off.']}, {'role': 'assistant', 'content': 'What seems to be the issue?', 'alt': ['Can you walk me through your function line by line?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you check if a number is divisible by 10?""]}, {'role': 'user', 'content': ""My outputs seem to be wrong sometimes, but I don't notice anything wrong with my code.""}, {'role': 'assistant', 'content': ""Ok, let's assume that `cookies` is 70. Can you walk me through what your code does line by line?"", 'alt': [""Let's use a debugger to step through your code. Let's run `cookiePurchase(70)` and see what happens. Is `70` divisible by 10? and what is the value of `discount` after line 4?"", ""Okay. Let's try 70 for `cookies`. 70 is greater than 10 and divisible by 10, so what should the value of `discount` be after line 4?"", ""Okay. Let's add a print statement to track the truth value of the condition on line 4. What is the value of `cookies / 10` when `cookies` is 70?""]}, {'role': 'user', 'content': ""First, I calculate the price based on the number of cookies. Then, I check whether I should apply a discount by checking the number of cookies and dividing by 10 to determine whether that number is a multiple of 10. Then I apply the discount if it is relevant. So for 70 cookies, I would calculate the price to be 70 * 1.75 = 122.5. Then I would check whether 70 > 10 which is True but 70 / 10 == 0, is false, so I would not apply a discount and would return the full price of 122.5. That's incorrect.""}, {'role': 'assistant', 'content': 'Hm... Are you sure that dividing by 10 is the right way to check whether a number is a multiple of 10?', 'alt': ['What operator should you use to check whether a number is a multiple of 10?', 'Where can you learn more about Python operators?\t']}, {'role': 'user', 'content': 'Hm... I think `/` regular division does not check whether a number is a multiple of 10. I am not sure what operator I should use to check whether a number is a multiple of 10...'}, {'role': 'assistant', 'content': ""Let's take a look at the Python documentation to see if there is a different operator that does what you want."", 'alt': ['Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Oh, interesting. The modulus operator seems to fit. I\'ll modify my code and see if it works. It looks like it does!\n```python\n def cookiePurchase(cookies):\n    price = cookies * 1.75\n    discount = 0\n    if cookies > 10 and cookies % 10 == 0:\n        discount = price * 0.1\n        price = price - discount\n    return {""discount"": discount, ""price"": price}\n```'}, {'role': 'assistant', 'content': 'Great! Glad to help.'}, {'role': 'user', 'content': 'Thank you very much!'}]}"
+"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?
+	<alt>Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?
+Assistant: Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.
+User: The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).
+Assistant: Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?
+	<alt>Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?
+	<alt>Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?
+	<alt>Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?
+User: If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.
+Assistant: That's right! Could you now tell me what happens when we complete the test case checks?
+	<alt>That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?
+User: Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.
+	<alt>Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order.
+	<alt>It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.
+<code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6.def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            new_node.next = curr_head.next
+12.            curr_head.next = new_node
+13.            return
+14.       else:
+15.           curr_head = curr_head.next
+16.    
+17.   return ""Previous node is not in linked list""
+
+</code>
+Assistant: Great! Let me know if you need more help.
+</dialogue>","Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```","class Node:
+   def __init__(self, data=None, next=None):
+       self.data = data
+       self.next = next
+
+def insert_after(head, prev_data, new_data):
+   curr_head = head
+   while curr_head is not None:
+       if curr_head.data == prev_data:
+           new_node = Node(data=new_data)
+           curr_head.next = new_node
+           return
+       else:
+           curr_head = curr_head.next
+   
+   return ""Previous node is not in linked list""","The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.","After line 10, insert a line `new_node.next = curr_head.next`","head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""",25_55_insert_to_linked_list,"<problem>
+Write a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.
+You are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.
+class Node:
+    def __init__(self, data=None, next=None):
+        self.data = data
+        self.next = next
+```
+## Example Cases:
+```py
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+insert_after(head, 2, 5) => None
+head.data == 1
+head.next.data == 2
+head.next.next.data == 5
+head.next.next.next.data == 3
+head.next.next.next.next.data == 4
+insert_after(head, 8, 6) => ""Previous node is not in linked list""
+```
+</problem>
+<bug_code>
+1. class Node:
+2.    def __init__(self, data=None, next=None):
+3.        self.data = data
+4.        self.next = next
+5.
+6. def insert_after(head, prev_data, new_data):
+7.    curr_head = head
+8.    while curr_head is not None:
+9.        if curr_head.data == prev_data:
+10.            new_node = Node(data=new_data)
+11.            curr_head.next = new_node
+12.            return
+13.        else:
+14.            curr_head = curr_head.next
+15.    
+16.    return ""Previous node is not in linked list""
+</bug_code>
+<bug_desc>
+The function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.
+</bug_desc>
+<bug_fixes>
+After line 10, insert a line `new_node.next = curr_head.next`
+</bug_fixes>
+<unit_tests>
+head = Node(data=1)
+head.next = Node(data=2)
+head.next.next = Node(data=3)
+head.next.next.next = Node(data=4)
+assert insert_after(head, 2, 5) == None
+assert head.data == 1
+assert head.next.data == 2
+assert head.next.next.data == 5
+assert head.next.next.next.data == 3
+assert head.next.next.next.next.data == 4
+assert insert_after(head, 8, 6) == ""Previous node is not in linked list""
+</unit_tests>
+","{'system': '<problem>\nWrite a function `insert_after(head: Node, prev_data: int, new_data: int) -> None` that takes in the head of a linked list, the data of a node in the linked list, and some new data. The function should insert a new node with the new data after the node with the `prev_data`. If the `prev_data` is not in the linked list, the function should do nothing. The function should return None. Note that the function should modify the linked list in place.\nYou are provided with a `Node` class that has a `data` attribute and a `next` attribute. The `next` attribute points to the next node in the linked list. The `head` of the linked list is the first node in the linked list.\nclass Node:\n    def __init__(self, data=None, next=None):\n        self.data = data\n        self.next = next\n```\n## Example Cases:\n```py\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\ninsert_after(head, 2, 5) => None\nhead.data == 1\nhead.next.data == 2\nhead.next.next.data == 5\nhead.next.next.next.data == 3\nhead.next.next.next.next.data == 4\ninsert_after(head, 8, 6) => ""Previous node is not in linked list""\n```\n</problem>\n<bug_code>\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6. def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            curr_head.next = new_node\n12.            return\n13.        else:\n14.            curr_head = curr_head.next\n15.    \n16.    return ""Previous node is not in linked list""\n</bug_code>\n<bug_desc>\nThe function returns an incomplete linked list when inserting an element in a linked list. For example, upon inserting `5`, after `2` in the list: 1->2->3->4 , the returned list is 1->2->5 instead of 1->2->5->3->4.\n</bug_desc>\n<bug_fixes>\nAfter line 10, insert a line `new_node.next = curr_head.next`\n</bug_fixes>\n<unit_tests>\nhead = Node(data=1)\nhead.next = Node(data=2)\nhead.next.next = Node(data=3)\nhead.next.next.next = Node(data=4)\nassert insert_after(head, 2, 5) == None\nassert head.data == 1\nassert head.next.data == 2\nassert head.next.next.data == 5\nassert head.next.next.next.data == 3\nassert head.next.next.next.next.data == 4\nassert insert_after(head, 8, 6) == ""Previous node is not in linked list""\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented the `insert_after()` function, but it doesn’t work. Can you help?', 'alt': ['Hi! I implemented the `insert_after()` function, but its execution stops at line 26 with an error. Can you help?']}, {'role': 'assistant', 'content': 'Sure. Let us first check your understanding of this problem itself. Assume that we have a linked list with four nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to Node3, Node3 contains the data value 3 and the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list). What should be the result after executing the `insert_after(Node1, 2, 5)` function? Please be advised that if the data value in a node uniquely represents this node, the linked list can be simply represented as `1 -> 2 -> 3 -> 4`.'}, {'role': 'user', 'content': 'The results would be a linked list with five nodes: Node1 contains the data value 1 and the next attribute that refers to Node2, Node2 contains the data value 2 and the next attribute that refers to a new node, called Node5, Node5 contains the data value 5 and the next attribute that refers to Node3, Node3 contains the data value 3 and points the next attribute that refers to Node4, Node4 contains the data value 4 and the next attribute that refers to None (the end of the list).'}, {'role': 'assistant', 'content': ""Great job! Let's now look at what happens in `insert_after` in your code. Can you track execution line-by-line?"", 'alt': [""Let's now walk through the first test case. Can you tell what happens when we run lines 18 to 22?"", 'Could you explain what is happening in the while loop of your ‘insert_after()’ function implementation keeping this in mind?', ""Let's look at what happens if we run `insert_after(Node1, 2, 5)` from your code - can you tell me what the value of each variable will be?""]}, {'role': 'user', 'content': 'If the `head` refers to Node1, `prev_data` is 2, and `new_data` is 5, the loop will run since `curr_head` will refer to Node1. Then since the `curr_head.data` is not 2, we will go to `curr_head` as Node2. Then the value will match, so we make a new Node5 with data 5 and update the `curr_head.next` to be Node5.'}, {'role': 'assistant', 'content': ""That's right! Could you now tell me what happens when we complete the test case checks?"", 'alt': [""That's right! Keep going forward with our check - do you think we will run into an error with any of the assertions?""]}, {'role': 'user', 'content': 'Yes, I think we run into an error when we reach check for the node with value 3 (Node3). It looks like we do not have that in the linked list anymore - I see that this is because the link from its previous node is broken. I think I need to make sure to update that link.\n```python\n1. class Node:\n2.    def __init__(self, data=None, next=None):\n3.        self.data = data\n4.        self.next = next\n5.\n6.def insert_after(head, prev_data, new_data):\n7.    curr_head = head\n8.    while curr_head is not None:\n9.        if curr_head.data == prev_data:\n10.            new_node = Node(data=new_data)\n11.            new_node.next = curr_head.next\n12.            curr_head.next = new_node\n13.            return\n14.       else:\n15.           curr_head = curr_head.next\n16.    \n17.   return ""Previous node is not in linked list""\n```', 'alt': [""Yes, there's an error when we check Node3 which should come after Node5. I will assign the next node for Node5 (the new node) as Node3 to maintain the next order."", 'It seems that the new linked list is actually 1->2->5, after executing the function, `assert_after(head, 2, 5)`. The next attribute of Node5 should refers to Node3.']}, {'role': 'assistant', 'content': 'Great! Let me know if you need more help.'}]}"
+"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi I need to fix my code, I am not getting the expected output.
+Assistant: Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?
+	<alt>Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?
+	<alt>Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?
+	<alt>Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?
+	<alt>Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?
+User: When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.
+	<alt>I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: For completeness, let's test another test case. What happens when you run `(1, 1)` as input?
+	<alt>Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?
+	<alt>Could you also try the next test case, `(1, 1)`, and observe the output?
+User: I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.
+	<alt>It looks like I also need to fix the `if` portion of the code which has a similar issue as before.
+<code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i >= end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i <= end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+
+</code>
+Assistant: Sounds good, let's check all the test cases and check how it goes!
+User: Everything is running as expected now, thanks!
+</dialogue>","Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```","def sequenceBetween(start, end):
+   l = []
+   if(start >= end):
+       i = start 
+       while i > end:
+           l.append(i)
+           i -= 1
+   else:
+       i = start
+       while i < end:
+           l.append(i)
+           i += 1
+   
+   return l","On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.",Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.,"assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]",3_20_counting_down,"<problem>
+Create a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.
+
+## Example Cases:
+```
+sequenceBetween(0, 3) => [0, 1, 2, 3]
+sequenceBetween(1, 1) => [1]
+sequenceBetween(7, 5) => [7, 6, 5]
+sequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]
+sequenceBetween(12, 10) => [12, 11, 10]
+sequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]
+```
+</problem>
+<bug_code>
+1. def sequenceBetween(start, end):
+2.    l = []
+3.    if(start >= end):
+4.        i = start 
+5.        while i > end:
+6.            l.append(i)
+7.            i -= 1
+8.    else:
+9.        i = start
+10.        while i < end:
+11.            l.append(i)
+12.            i += 1
+13.    
+14.    return l
+</bug_code>
+<bug_desc>
+On lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.
+</bug_desc>
+<bug_fixes>
+Replace `>` with `>=` on line 5 and `<` with `<=` on line 10.
+</bug_fixes>
+<unit_tests>
+assert sequenceBetween(0, 3) == [0, 1, 2, 3]
+assert sequenceBetween(1, 1) == [1]
+assert sequenceBetween(7, 5) == [7, 6, 5]
+assert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]
+assert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `sequenceBetween(start: int, end: int) -> List[int]` that takes two positive integers and returns a list of all the numbers between the integers, including the start and end values. You begin counting from `start`, and end counting on `end`. If `start` is smaller than `end`, then you perform a ""countup"" operation where you return a list of the numbers from the smaller number to the bigger number. If the user enters a bigger number as `start` you perform a ""countdown"" operation where you return a list of all the numbers from the bigger number to the smaller number.\n\n## Example Cases:\n```\nsequenceBetween(0, 3) => [0, 1, 2, 3]\nsequenceBetween(1, 1) => [1]\nsequenceBetween(7, 5) => [7, 6, 5]\nsequenceBetween(100, 95) => [100, 99, 98, 97, 96, 95]\nsequenceBetween(12, 10) => [12, 11, 10]\nsequenceBetween(14, 20) => [14, 15, 16, 17, 18, 19, 20]\n```\n</problem>\n<bug_code>\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i < end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n</bug_code>\n<bug_desc>\nOn lines 5 and 10, there is an off by one error. The while loop ranges are inclusive of `start` but exclusive of `end`. Consequently, the function returns a list that includes all the numbers from `start` to `end - 1` instead of `end`.\n</bug_desc>\n<bug_fixes>\nReplace `>` with `>=` on line 5 and `<` with `<=` on line 10.\n</bug_fixes>\n<unit_tests>\nassert sequenceBetween(0, 3) == [0, 1, 2, 3]\nassert sequenceBetween(1, 1) == [1]\nassert sequenceBetween(7, 5) == [7, 6, 5]\nassert sequenceBetween(100, 95) == [100, 99, 98, 97, 96, 95]\nassert sequenceBetween(14, 20) == [14, 15, 16, 17, 18, 19, 20]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi I need to fix my code, I am not getting the expected output.'}, {'role': 'assistant', 'content': ""Sure, let's walk through your code. When you provide the first test input `sequenceBetween(0, 3)` what are the values in your output list `l`?"", 'alt': [""Here to help! Let's go through your code, and the expected output together. Can you track each variable when you try `sequenceBetween(0, 3)`?"", ""Let's take a look at your code, can you test what happens when you run `sequenceBetween(0, 3)`? What do you notice?"", ""Let's go through code, and focus on what happens when you try the first test case - `sequenceBetween(0, 3)`. Which lines reflect the code that runs in this case?"", 'Can you tell me what happens when you enter `(0, 3)`as the input? Which lines execute and what is stored in the variables?']}, {'role': 'user', 'content': 'When the `start` is 0, and `end` is 3, the else condition on lines 9 to 12 executes. This means that the while loop executes when `i` is 0, 1, 2. Ah I see that when `i` is 3, the while loop does not execute and that means `l` does not contain 3. I will update this.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i > end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```', 'alt': ['I think that in lines 9 to 12, the while condition completes execution before it reaches the end value.']}, {'role': 'assistant', 'content': ""For completeness, let's test another test case. What happens when you run `(1, 1)` as input?"", 'alt': [""Let's consider another case. If we try `sequenceBetween(1, 1)` which lines execute in your code?"", 'Could you also try the next test case, `(1, 1)`, and observe the output?']}, {'role': 'user', 'content': ""I don't get the correct output for the next test case `(1, 1)`. I think this is because of the same issue as before, but in the if portion since `start` = `end`. I also need to update line 5.\n```python\n1. def sequenceBetween(start, end):\n2.    l = []\n3.    if(start >= end):\n4.        i = start \n5.        while i >= end:\n6.            l.append(i)\n7.            i -= 1\n8.    else:\n9.        i = start\n10.        while i <= end:\n11.            l.append(i)\n12.            i += 1\n13.    \n14.    return l\n```"", 'alt': ['It looks like I also need to fix the `if` portion of the code which has a similar issue as before.']}, {'role': 'assistant', 'content': ""Sounds good, let's check all the test cases and check how it goes!""}, {'role': 'user', 'content': 'Everything is running as expected now, thanks!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I keep getting an error with my code,  but I'm not sure how to fix it
+Assistant: Where is the syntax error happening and what is it?
+  <alt>Do you see any red squiggly lines in your code? If so, what is it highlighting?
+  <alt>Do you see a line number next to the error? If so, what is it?
+User: Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""
+Assistant: Do you see a squiggly line in your code? If so, what is it highlighting?
+  <alt> It might be an issue with your operator. Could you list all the comparison operators you know?
+  <alt>How do you check if two numbers are unequal?
+  <alt>Is the error message highlighting a specific portion of the line like an operator or a parenthesis?
+User: Yes, it is highlighting the =! operator.
+Assistant: Then, what do you think the problem is?
+  <alt>Are you sure that's the correct operator to check whether two numbers are unequal?
+User: I'm not sure. I am trying to check if `i` is not divisible by 2.
+Assistant: Are you sure that `=!` is the correct operator to check if two numbers are not equal?
+  <alt>Is there a difference between `=!` and `!=`?
+User: Ah! I see. I should be using `!=` instead of `=!`.
+<code>
+ def returnOdd(nums):
+  newNums = []
+  for i in nums:
+    if i % 2 != 0:
+      newNums.append(i)
+  return newNums
+</code>
+Assistant: Great! Now try running your code again.
+User: It works! Thanks for your help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i % 2 =! 0:
+     newNums.append(i)
+ return newNums","There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.",Replace `=!` with `!=` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_22_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 =! 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.
+</bug_desc>
+<bug_fixes>
+Replace `=!` with `!=` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 =! 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 4. The operator used for ""not equal to"" is incorrect.\n</bug_desc>\n<bug_fixes>\nReplace `=!` with `!=` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I keep getting an error with my code,  but I'm not sure how to fix it""}, {'role': 'assistant', 'content': 'Where is the syntax error happening and what is it?', 'alt': ['Do you see any red squiggly lines in your code? If so, what is it highlighting?', 'Do you see a line number next to the error? If so, what is it?']}, {'role': 'user', 'content': 'Around if-statement, line my code throws an error. It says ""SyntaxError: invalid syntax""'}, {'role': 'assistant', 'content': 'Do you see a squiggly line in your code? If so, what is it highlighting?', 'alt': ['It might be an issue with your operator. Could you list all the comparison operators you know?', 'How do you check if two numbers are unequal?', 'Is the error message highlighting a specific portion of the line like an operator or a parenthesis?']}, {'role': 'user', 'content': 'Yes, it is highlighting the =! operator.'}, {'role': 'assistant', 'content': 'Then, what do you think the problem is?', 'alt': [""Are you sure that's the correct operator to check whether two numbers are unequal?""]}, {'role': 'user', 'content': ""I'm not sure. I am trying to check if `i` is not divisible by 2.""}, {'role': 'assistant', 'content': 'Are you sure that `=!` is the correct operator to check if two numbers are not equal?', 'alt': ['Is there a difference between `=!` and `!=`?']}, {'role': 'user', 'content': 'Ah! I see. I should be using `!=` instead of `=!`.\n```python\n def returnOdd(nums):\n  newNums = []\n  for i in nums:\n    if i % 2 != 0:\n      newNums.append(i)\n  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Now try running your code again.'}, {'role': 'user', 'content': 'It works! Thanks for your help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, I am not sure why my program for removing even numbers is not running. Can you please help?
+	<alt>Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?
+Assistant: Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?
+	<alt>Hi, Sure! Do you know why it is throwing a syntax error on line 3?
+User: I am not sure what that error means
+	<alt>Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?
+Assistant: It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?
+User: Yes, it looks like the caret is pointing towards the end of line 3.
+Assistant: Correct, what do you think is wrong with the end of the line 3?
+	<alt>Correct, what do you think is missing towards the end of line 3?
+User: I am not sure, is it a punctuation mark?
+	<alt>Is it missing a colon?
+Assistant: Yes, can you find the correct syntax using the documentation?
+	<alt>Yes, where can you find the correct syntax of a for loop?
+User: What is the documentation?
+	<alt>Yes, is it supposed to have a colon at the end?
+Assistant: Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org
+User: After going through the python documentation, I think this is what my code is supposed to look like this.
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</code>
+Assistant: Correct, you can always come back to the documentation if you ever run into a syntax error.
+User: My program works now, thank you for helping me resolve that error!
+Assistant: You are welcome!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums
+   if i % 2 != 0:
+     newNums.append(i)
+ return newNums",There is a syntax error on line 3. The for loop syntax is incorrect.,Add `:` after `nums` on line 3.,"assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []",4_28_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]
+returnOdd([2,4,6,8,10]) => []
+returnOdd([1,3,5,7,9]) => [1,3,5,7,9]
+returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 3. The for loop syntax is incorrect.
+</bug_desc>
+<bug_fixes>
+Add `:` after `nums` on line 3.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]
+assert returnOdd([2,4,6,8,10]) == []
+assert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]
+assert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1,2,3,4,5,6,7,8,9]) => [1,3,5,7,9]\nreturnOdd([2,4,6,8,10]) => []\nreturnOdd([1,3,5,7,9]) => [1,3,5,7,9]\nreturnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) => []\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 3. The for loop syntax is incorrect.\n</bug_desc>\n<bug_fixes>\nAdd `:` after `nums` on line 3.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1,2,3,4,5,6,7,8,9]) == [1,3,5,7,9]\nassert returnOdd([2,4,6,8,10]) == []\nassert returnOdd([1,3,5,7,9]) == [1,3,5,7,9]\nassert returnOdd([-10,-8,-6,-4,-2,0,2,4,6,8,10]) == []\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi, I am not sure why my program for removing even numbers is not running. Can you please help?', 'alt': ['Hi, my program for removing even numbers is throwing an error. Can you help me understand the error?']}, {'role': 'assistant', 'content': 'Hi, Sure! It looks like your program has a syntax error on line 3, do you know what that means?', 'alt': ['Hi, Sure! Do you know why it is throwing a syntax error on line 3?']}, {'role': 'user', 'content': 'I am not sure what that error means', 'alt': ['Does it mean that my expression on line 3 is not following the rules on how the for loop should be written?']}, {'role': 'assistant', 'content': 'It means there is a mistake in your code, with the spelling or punctuation or usage of wrong names, etc. The caret in the output shows where this mistake might be. Do you see what the caret is pointing at?'}, {'role': 'user', 'content': 'Yes, it looks like the caret is pointing towards the end of line 3.'}, {'role': 'assistant', 'content': 'Correct, what do you think is wrong with the end of the line 3?', 'alt': ['Correct, what do you think is missing towards the end of line 3?']}, {'role': 'user', 'content': 'I am not sure, is it a punctuation mark?', 'alt': ['Is it missing a colon?']}, {'role': 'assistant', 'content': 'Yes, can you find the correct syntax using the documentation?', 'alt': ['Yes, where can you find the correct syntax of a for loop?']}, {'role': 'user', 'content': 'What is the documentation?', 'alt': ['Yes, is it supposed to have a colon at the end?']}, {'role': 'assistant', 'content': 'Documentation of a language, like python tells you what the code does and how to use it. You can find it at docs.python.org'}, {'role': 'user', 'content': 'After going through the python documentation, I think this is what my code is supposed to look like this.\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Correct, you can always come back to the documentation if you ever run into a syntax error.'}, {'role': 'user', 'content': 'My program works now, thank you for helping me resolve that error!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?
+	<alt>Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?
+Assistant: Sure, let's look at the error together. Do you know what the error ""SyntaxError: 'return' outside function"" means?
+	<alt>I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?
+	<alt>Let's warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?
+User: Does it mean that my return statement is not currently a part of my function?
+	<alt>The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.
+Assistant: That's right, taking a look at your code, do you think your return statement is a part of your function?
+	<alt>Could you tell me what we might need to do to make sure that the function returns the value we need it to?
+	<alt>What might you need to do to make sure the return statement is in the scope of your function?
+User: I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.
+	<alt>I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+</code>
+Assistant: Looks good! Let me know if you need more help!
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+return newNums",There is a syntax error on line 6. The return statement is not within a function scope.,Insert a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_25_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6. return newNums
+</bug_code>
+<bug_desc>
+There is a syntax error on line 6. The return statement is not within a function scope.
+</bug_desc>
+<bug_fixes>
+Insert a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6. return newNums\n</bug_code>\n<bug_desc>\nThere is a syntax error on line 6. The return statement is not within a function scope.\n</bug_desc>\n<bug_fixes>\nInsert a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I implemented my method but it throws a syntax error that says my return statement is outside the function. Can you help me resolve this?', 'alt': ['Hi! I am working on the method to remove even numbers, but it is not running because of line 6. Can you help me find out what is wrong here?']}, {'role': 'assistant', 'content': 'Sure, let\'s look at the error together. Do you know what the error ""SyntaxError: \'return\' outside function"" means?', 'alt': [""I'm here to help! Let's think about what this error might mean. Do you know what might be causing it?"", 'Let\'s warm up by thinking about what the ""scope"" of a code block means. Do you know what that is and how that might affect a ""return"" statement?']}, {'role': 'user', 'content': 'Does it mean that my return statement is not currently a part of my function?', 'alt': ['The scope of the function means that the statements should be at the indentation level of the function, so all those statements are a part of the function.']}, {'role': 'assistant', 'content': ""That's right, taking a look at your code, do you think your return statement is a part of your function?"", 'alt': ['Could you tell me what we might need to do to make sure that the function returns the value we need it to?', 'What might you need to do to make sure the return statement is in the scope of your function?']}, {'role': 'user', 'content': 'I see, so to make the return statement a part of the function correctly, I need to indent it to make sure it lies in the right scope.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```', 'alt': ['I think the indentation for the return statement to be inside the function it needs to be indented, to the level of line 2 not line 1.']}, {'role': 'assistant', 'content': 'Looks good! Let me know if you need more help!'}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+       return newNums","On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.",Remove a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_26_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.        return newNums\n</bug_code>\n<bug_desc>\nOn line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.\n</bug_desc>\n<bug_fixes>\nRemove a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck.""}, {'role': 'assistant', 'content': 'What should your code be doing?', 'alt': ['Which test cases (if any) are failing?', 'What are you stuck on?', 'Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?']}, {'role': 'user', 'content': ""Right now, it's only returning the first number in the list, not all of them."", 'alt': [""It's only passing the second test case.""]}, {'role': 'assistant', 'content': ""Okay, let's look at your loop. Do you see anything that could be causing it to end early?"", 'alt': ['Have you checked the loop and how many times it iterates?', ""Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?"", 'What do you think might cause your function to return a list with one element instead of multiple elements?', ""Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?"", 'What do you think is causing the lists not to include all the numbers?', 'Look at line 3, is it iterating through the whole list?']}, {'role': 'user', 'content': ""No I do not. I'm iterating through the whole list of numbers."", 'alt': [""I don't know, how could I find out?"", 'Oh, I see, the return statement is in the wrong place.']}, {'role': 'assistant', 'content': ""Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?"", 'alt': ['What can cause a function to end early?', 'What forces a loop to end?']}, {'role': 'user', 'content': 'Line 3 starts the loop, and it iterates through everything in `nums`.'}, {'role': 'assistant', 'content': 'Good, then what happens?', 'alt': ['Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?', 'Think back to what you know about functions. What makes them end early?', 'Think back to what you know about loops, what can make them stop?']}, {'role': 'user', 'content': 'The if statement starts on line 4, it checks if the number is even.'}, {'role': 'assistant', 'content': 'Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?', 'alt': ['Do you notice anything on line 4 that causes the function to end early?', 'Do you notice anything on line 4 that causes the for loop to end?']}, {'role': 'user', 'content': ""I don't see anything that can cause that problem."", 'alt': ['I see! The return statement after the if-statement is indented too much!']}, {'role': 'assistant', 'content': 'Okay, so what happens next on line 6?'}, {'role': 'user', 'content': 'It returns the list.', 'alt': [""I get it! It's returning after every iteration!"", ""It's returning too soon.""]}, {'role': 'assistant', 'content': 'When should it return the list?', 'alt': ['Would a return statement end a loop?', 'Would a return statement cause the function to terminate early?', 'Is there anything on this line that would cause the loop or the function to end early?', 'When does your return statement execute?']}, {'role': 'user', 'content': 'It should return the list when it finishes all the numbers.'}, {'role': 'assistant', 'content': 'Look at line 6, what level of indentation is the list on?', 'alt': ['Think back to what you have learned about indentation, how does that control the order of actions in a loop?', 'Can the return statement end the loop early?']}, {'role': 'user', 'content': ""I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```""}, {'role': 'assistant', 'content': 'What does it return now, after you changed the indentation of the return statement?'}, {'role': 'user', 'content': 'It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.'}, {'role': 'assistant', 'content': ""You're welcome. Let me know if I can be of any further assistance.""}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I have a problem with my code. It's just not working, and I just don't know why.
+Assistant: Can you explain what the issue appears to be?
+	<alt>Can you walk me through your function line by line?
+	<alt>Does your code throw an error or do you just get the wrong answer?
+	<alt>Let's start with a simple warm-up question. How do you check if a number is even?
+	<alt>Let's start with a simple warm-up question. How do you know if a number is even or odd?
+User: The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed.
+	<alt>It doesn't seem like my function modifies anything on most input lists.
+	<alt>I can't figure out why my function doesn't remove most of the even numbers in the lists I input.
+Assistant: Can you explain your function to me line by line?
+	<alt>Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+User: OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.
+Assistant: Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?
+	<alt>Can you explain what line 4 of your code does?
+	<alt>It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?
+	<alt>When does dividing by 2 give you 0?
+	<alt>How do you check if a number is even in your code?
+User: Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?
+Assistant: Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?
+	<alt>Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?
+	<alt>Where can you learn more about arithmetic operators in Python?
+User: Hm ok, let me try modulus. It works!
+<code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i % 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+
+</code>
+Assistant: Great! Happy to help!
+User: Thank you so much for your help! I learned more about how to check for divisibility in Python.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+ newNums = []
+ for i in nums:
+   if i / 2 != 0:
+     newNums.append(i)
+ return newNums","On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.",Replace `/` with `%` on line 4.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_23_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.  newNums = []
+3.  for i in nums:
+4.    if i / 2 != 0:
+5.      newNums.append(i)
+6.  return newNums
+</bug_code>
+<bug_desc>
+On line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.
+</bug_desc>
+<bug_fixes>
+Replace `/` with `%` on line 4.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i / 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n</bug_code>\n<bug_desc>\nOn line 4, the function checks if `i` divided by `2` is not equal to `0` which is true for `i > 0 and i < 0`. Consequently, the function removes all elements equal to `0` in `nums` instead of removing all elements that are divisible by `2`.\n</bug_desc>\n<bug_fixes>\nReplace `/` with `%` on line 4.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I have a problem with my code. It's just not working, and I just don't know why.""}, {'role': 'assistant', 'content': 'Can you explain what the issue appears to be?', 'alt': ['Can you walk me through your function line by line?', 'Does your code throw an error or do you just get the wrong answer?', ""Let's start with a simple warm-up question. How do you check if a number is even?"", ""Let's start with a simple warm-up question. How do you know if a number is even or odd?""]}, {'role': 'user', 'content': ""The code does not throw an error, but it doesn't give the right answers. Most lists I input stay the same. Even numbers are not removed."", 'alt': [""It doesn't seem like my function modifies anything on most input lists."", ""I can't figure out why my function doesn't remove most of the even numbers in the lists I input.""]}, {'role': 'assistant', 'content': 'Can you explain your function to me line by line?', 'alt': ['Do you observe any patterns in the outputs of your function or is it always returning a list identical to the input?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?""]}, {'role': 'user', 'content': 'OK. My method takes a list of numbers. Then, I create a new list of numbers called `newNums` to store the new numbers. Then, I create a for loop that goes through every element in the list. For every element, I divide it by 2 to see if the result will be 0. If it is, then I would add it to the list. Finally, I output the new array.'}, {'role': 'assistant', 'content': ""Let's manually run through your if statement with the number 8 as `i`. Would your code append 8 to `newNums`?"", 'alt': ['Can you explain what line 4 of your code does?', ""It seems that you're instantiating a new list `newNums`, appending elements to it, and then returning it. What would cause `newNums` to be identical to `nums`?"", 'When does dividing by 2 give you 0?', 'How do you check if a number is even in your code?']}, {'role': 'user', 'content': ""Walking through the code, I would get 4, so it wouldn't select 8 even though it should. I just want to test divisibility. Maybe I should chain it with another operator?""}, {'role': 'assistant', 'content': ""Let's review the Python documentation for arithmetic operations. Are you using the right operator to check if a number is even?"", 'alt': [""Hm, it seems like the current method won't work for divisibility. Where can you look for more information about divisibility testing in Python?"", 'Where can you learn more about arithmetic operators in Python?']}, {'role': 'user', 'content': 'Hm ok, let me try modulus. It works!\n```python\n1. def returnOdd(nums):\n2.  newNums = []\n3.  for i in nums:\n4.    if i % 2 != 0:\n5.      newNums.append(i)\n6.  return newNums\n```'}, {'role': 'assistant', 'content': 'Great! Happy to help!'}, {'role': 'user', 'content': 'Thank you so much for your help! I learned more about how to check for divisibility in Python.'}]}"
+"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on this function and it doesn't seem to be correct.
+	<alt>I'm trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.
+Assistant: Does your code work for all the examples in the problem description or does it fail on some of them?
+	<alt>Hello! Can you explain to me what the code on line 2 does?
+	<alt>Let's review the problem description together. What are the requirements for the returned list?
+	<alt>Can you walk me through your `get_words` function?
+	<alt>Let's run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?
+	<alt>Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+User: If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?
+Assistant: Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?
+	<alt>I see. How can you remove duplicates from a list?
+	<alt>Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?
+	<alt>I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?
+	<alt>Where can you learn about deduplicating a list in Python?
+	<alt>Have you considered simply looping through the list and removing duplicates?
+User: Maybe a set would be better than a list for this then. I've modified my code. The output for that sentence now is: ['hello', 'world'], so it looks like it works!
+<code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(set(words))
+
+</code>
+Assistant: Perfect!
+</dialogue>","Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```","def get_words(s):
+   words = [word.lower() for word in s.split("" "")]
+   return sorted(words)","The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.","Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.","assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']",5_30_sorted_words,"<problem>
+Write a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `['hello', 'world']`.
+
+## Example Cases:
+```
+get_words(""Hello World"") => ['hello', 'world']
+get_words(""Hello World hello"") => ['hello', 'world']
+get_words(""Hello World hello world"") => ['hello', 'world']
+get_words(""Hello World H e l l o W o r l d"") => ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+get_words(""Hello World el WORld"") => ['el', 'hello', 'world']
+get_words(""A C B c b a"") => ['a', 'b', 'c']
+```
+</problem>
+<bug_code>
+1. def get_words(s):
+2.    words = [word.lower() for word in s.split("" "")]
+3.    return sorted(words)
+</bug_code>
+<bug_desc>
+The function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.
+</bug_desc>
+<bug_fixes>
+Replace `sorted(words)` with `sorted(set(words))` on line 3.
+Insert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.
+</bug_fixes>
+<unit_tests>
+assert get_words(""Hello World"") == [""hello"", ""world""]
+assert get_words(""Hello World hello"") == [""hello"", ""world""]
+assert get_words(""Hello World hello world"") == [""hello"", ""world""]
+assert get_words(""Hello World H e l l o W o r l d"") == ['d', 'e', 'h', 'hello', 'l', 'o', 'r', 'w', 'world']
+assert get_words(""Hello World el WORld"") == ['el', 'hello', 'world']
+assert get_words('A C B c b a') == ['a', 'b', 'c']
+</unit_tests>
+","{'system': '<problem>\nWrite a function `get_words (s:str) -> List[str]` that extracts all the words from the input string `s`, changes them all to be lower case, and returns a list containing all unique words (no duplicates) in alphabetical order. Assume that a word is a maximal sequence of characters that does not contain any space. For example, `get_words(""Hello World hello"")` should return `[\'hello\', \'world\']`.\n\n## Example Cases:\n```\nget_words(""Hello World"") => [\'hello\', \'world\']\nget_words(""Hello World hello"") => [\'hello\', \'world\']\nget_words(""Hello World hello world"") => [\'hello\', \'world\']\nget_words(""Hello World H e l l o W o r l d"") => [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nget_words(""Hello World el WORld"") => [\'el\', \'hello\', \'world\']\nget_words(""A C B c b a"") => [\'a\', \'b\', \'c\']\n```\n</problem>\n<bug_code>\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(words)\n</bug_code>\n<bug_desc>\nThe function returns a list of sorted words in alphabetical order, however, if `s` contains repeated words, the function returns all the words instead of removing the duplicated words in `s`.\n</bug_desc>\n<bug_fixes>\nReplace `sorted(words)` with `sorted(set(words))` on line 3.\nInsert a line with `words = set(words)`  after that insert another line with `words = list(set(words))` after line 2.\n</bug_fixes>\n<unit_tests>\nassert get_words(""Hello World"") == [""hello"", ""world""]\nassert get_words(""Hello World hello"") == [""hello"", ""world""]\nassert get_words(""Hello World hello world"") == [""hello"", ""world""]\nassert get_words(""Hello World H e l l o W o r l d"") == [\'d\', \'e\', \'h\', \'hello\', \'l\', \'o\', \'r\', \'w\', \'world\']\nassert get_words(""Hello World el WORld"") == [\'el\', \'hello\', \'world\']\nassert get_words(\'A C B c b a\') == [\'a\', \'b\', \'c\']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on this function and it doesn't seem to be correct."", 'alt': ['I\'m trying to implement this function, but my code is failing on certain examples like `get_words(""Hello World hello"")`.']}, {'role': 'assistant', 'content': 'Does your code work for all the examples in the problem description or does it fail on some of them?', 'alt': ['Hello! Can you explain to me what the code on line 2 does?', ""Let's review the problem description together. What are the requirements for the returned list?"", 'Can you walk me through your `get_words` function?', 'Let\'s run through the examples in the problem description. What happens when you run `get_words(""Hello World"")` and `get_words(""Hello World hello"")`? What do you observe?', ""Let's start with a simple example. Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?""]}, {'role': 'user', 'content': 'If I put in a sentence like ""hello world hello world"", all the duplicate words still appear in the final output. How do I go about removing the duplicates?'}, {'role': 'assistant', 'content': ""Let's recollect what we know about data structures. Which data structure in Python would store unique elements only?"", 'alt': ['I see. How can you remove duplicates from a list?', ""Say you have a list of letters `['A', 'A', 'B']`. How would you remove the duplicate letters from the list and return a list of unique letters?"", 'I feel like the best way to describe this would be to enforce a math concept. What do you call a mathematical collection without duplicates?', 'Where can you learn about deduplicating a list in Python?', 'Have you considered simply looping through the list and removing duplicates?']}, {'role': 'user', 'content': 'Maybe a set would be better than a list for this then. I\'ve modified my code. The output for that sentence now is: [\'hello\', \'world\'], so it looks like it works!\n```python\n1. def get_words(s):\n2.    words = [word.lower() for word in s.split("" "")]\n3.    return sorted(set(words))\n```'}, {'role': 'assistant', 'content': 'Perfect!'}]}"
+"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?
+Assistant: Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?
+	<alt>Can you describe what happens when you run your code using one of the example cases?
+	<alt>Given `x = 2` and `y = 4`, can you explain how line 2 works?
+User: I should get a 3, but I am getting a 4.
+Assistant: Why do you think it returns 4 instead of 3?
+	<alt>Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+User: I am not sure why it is returning 4.
+Assistant: Can you describe what line 2 is doing when `x` is 2 and `y` is 4?
+	<alt>Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression?
+User: The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.
+Assistant: Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?
+	<alt>Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?
+User: Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.
+	<alt>Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. 
+	<alt>I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. 
+<code>
+1. def calculate_average(x, y):
+2.    return (x + y) / 2
+</code>
+Assistant: Very good! Does it pass all the test cases?
+User: Yes it does! Thank you so much for your help!
+Assistant: You’re welcome please let me know if you have any questions.
+User: Thank you will do!
+</dialogue>","Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```","def calculate_average(x, y):
+   return x + y / 2","On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.",Replace `x + y` with `(x + y)` on line 2.,"assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0",56_15_compute_average,"<problem>
+Write a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.
+
+## Example Cases:
+```
+calculate_average(0, 0) => 0.0
+calculate_average(1, 3) => 2.0
+calculate_average(-1, 1) => 0.0
+calculate_average(-5, -2) => -3.5
+calculate_average(5.5, 7.5) => 6.5
+calculate_average(405, 135) => 270.0
+```
+</problem>
+<bug_code>
+1. def calculate_average(x, y):
+2.    return x + y / 2
+</bug_code>
+<bug_desc>
+On line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.
+</bug_desc>
+<bug_fixes>
+Replace `x + y` with `(x + y)` on line 2.
+</bug_fixes>
+<unit_tests>
+assert calculate_average(0, 0) == 0.0
+assert calculate_average(1, 3) == 2.0
+assert calculate_average(-1, 1) == 0.0
+assert calculate_average(-5, -2) == -3.5
+assert calculate_average(5.5, 7.5) == 6.5
+assert calculate_average(405, 135) == 270.0
+</unit_tests>
+","{'system': '<problem>\nWrite a function `calculate_average(x: float, y: float) -> float` that takes in two integers `x` and `y` and returns their average as a float.\n\n## Example Cases:\n```\ncalculate_average(0, 0) => 0.0\ncalculate_average(1, 3) => 2.0\ncalculate_average(-1, 1) => 0.0\ncalculate_average(-5, -2) => -3.5\ncalculate_average(5.5, 7.5) => 6.5\ncalculate_average(405, 135) => 270.0\n```\n</problem>\n<bug_code>\n1. def calculate_average(x, y):\n2.    return x + y / 2\n</bug_code>\n<bug_desc>\nOn line 2, using operator precedence rules the function first computes the quotient of `y/2` and then the sum of `x` and `y/2`. Consequently, the function does not return the average of x and y which is `x + y` that is then divided by 2.\n</bug_desc>\n<bug_fixes>\nReplace `x + y` with `(x + y)` on line 2.\n</bug_fixes>\n<unit_tests>\nassert calculate_average(0, 0) == 0.0\nassert calculate_average(1, 3) == 2.0\nassert calculate_average(-1, 1) == 0.0\nassert calculate_average(-5, -2) == -3.5\nassert calculate_average(5.5, 7.5) == 6.5\nassert calculate_average(405, 135) == 270.0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I am calculating the average of two numbers and it is not working. I don't know why. Could you take a look and guide me, please?""}, {'role': 'assistant', 'content': ""Sure. Let's take a look. Try running `calculate_average (2, 4)`. What does the function return?"", 'alt': ['Can you describe what happens when you run your code using one of the example cases?', 'Given `x = 2` and `y = 4`, can you explain how line 2 works?']}, {'role': 'user', 'content': 'I should get a 3, but I am getting a 4.'}, {'role': 'assistant', 'content': 'Why do you think it returns 4 instead of 3?', 'alt': ['Can you describe what line 2 is doing when `x` is 2 and `y` is 4?']}, {'role': 'user', 'content': 'I am not sure why it is returning 4.'}, {'role': 'assistant', 'content': 'Can you describe what line 2 is doing when `x` is 2 and `y` is 4?', 'alt': ['Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'Do you recall what the order of operations is when evaluating a mathematical expression?']}, {'role': 'user', 'content': 'The code should sum up `2 + 4` which evaluates to `6` and then it should divide `6 by `2`.'}, {'role': 'assistant', 'content': 'Let’s suppose that’s true, the function should return `3` in that case but it returns `4`. Let’s solve this step by step `2 + 4 / 2`. Which operation do we evaluate first `2 + 4` or `4 / 2`?', 'alt': ['Do you recall what the order of operations is when evaluating a mathematical expression? Do we evaluate `+` or `/` first?']}, {'role': 'user', 'content': 'Ohhh. We evaluate `4 / 2` first. I see. It is the order of precedence. I need to add parentheses around `(x + y)` to enforce addition to be completed first.\n```python\n1. def calculate_average(x, y):\n2.    return (x + y) / 2\n```', 'alt': ['Hm… I thought we would evaluate `2 + 4` first but that is inconsistent with the output we observe. So it must be `4 / 2` first. ', 'I think we would evaluate `2 + 4` first since the order of operations is from left to right all the time. ']}, {'role': 'assistant', 'content': 'Very good! Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes it does! Thank you so much for your help!'}, {'role': 'assistant', 'content': 'You’re welcome please let me know if you have any questions.'}, {'role': 'user', 'content': 'Thank you will do!'}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   i = 0
+   while apples > 0 and apples > children:
+       apples = apples - children
+       i += 1
+   return i","The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.",Replace `apples > children` with `apples >= children` on line 3.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_59_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples > children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n</bug_code>\n<bug_desc>\nThe while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.\n</bug_desc>\n<bug_fixes>\nReplace `apples > children` with `apples >= children` on line 3.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My function fails two test cases and I do not understand why, can you help?'}, {'role': 'assistant', 'content': 'Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?', 'alt': [""Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?"", ""Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?"", 'Sure. Can you explain to me what you are trying to do with the while loop?', 'Sure. Can you tell me what the loop condition `apples > children` is there for?', 'Sure. Can you explain your code to me, what is supposed to do, line by line?']}, {'role': 'user', 'content': 'It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.', 'alt': [""It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.""]}, {'role': 'assistant', 'content': 'Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?', 'alt': ['Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.', ""Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?""]}, {'role': 'user', 'content': 'It is 1 less than the correct number.'}, {'role': 'assistant', 'content': 'Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?', 'alt': ['Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?']}, {'role': 'user', 'content': 'Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!\n```python\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples >= children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck!
+Assistant: Where do you think the problem is?
+	<alt>Have you read your code carefully?
+	<alt>Which test cases are passing?
+	<alt>Have you read the prompt carefully?
+User: I don't know.
+	<alt>I think the math is wrong.
+Assistant: Look at the test cases, does the first test case pass?
+	<alt>Look at the test cases, what is the first test case to fail?
+	<alt>Have you read your code carefully?
+	<alt>Have you read the prompt carefully?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: What is the correct answer for case 2?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 1 require rounding?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: It should output 3.
+Assistant: Would there be a remainder?
+	<alt>What is the correct answer for case 1?
+	<alt>Does case 2 require rounding?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Think about division in Python, how does it handle remainders?
+User: Yes, there would be a remainder of 1.
+	<alt>Oh! I see, the problem is the remainder!
+Assistant: Is there a way you can see what the result is?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>Trace the code, what would the output of line 2 be with 7 and 2?
+	<alt>How can you test the output of line 2?
+User: I can add a print statement before the return.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples / children)
+3.    return apples / children
+
+</code>
+Assistant: Try running the code, what is the result of dividing 7 by 2?
+	<alt>Try running the code, what is the result of dividing 10 by 2?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+User: It's returning 3.5 for 7 divided by 2.
+Assistant: What should the output be?
+	<alt>Look at the prompt, what are you dividing?
+	<alt>Look at the prompt, do you see anything you have forgotten?
+	<alt>Look at the prompt, is there anything special about the format of the numbers?
+	<alt>Think about division in Python, how does it handle remainders?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>What do you need to change to make the output a whole number?
+User: It should be 3.
+Assistant: Look at the Python documentation on operators, are you using the correct one to round down?
+	<alt>Are you using the correct operator?
+	<alt>Is there a specific operator you should use when dividing whole numbers?
+	<alt>Is there a specific operator you should use when you need to round down?
+	<alt>Think about division in Python, what does `/` indicate?
+	<alt>How can you make it round down?
+User: No! I need to use // instead.
+<code>
+1. def split_apples(apples, children):
+2.    print(apples // children)
+3.    return apples // children
+
+</code>
+Assistant: Run it again, does it output correctly?
+	<alt>Run it now, do all the test cases pass?
+User: Yes, it works! I'll remove the extra print statement. 
+<code>
+1. def split_apples(apples, children):
+2.    return apples // children
+
+</code>
+Assistant: Run it one more time, do all the test cases pass?
+	<alt>Run it again, does it output correctly?
+User: Yes! It works, thank you!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   return apples / children",The function returns a float instead of the largest possible integer after distributing the apples evenly.,Replace `/` with `//` on line 2.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_58_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    return apples / children
+</bug_code>
+<bug_desc>
+The function returns a float instead of the largest possible integer after distributing the apples evenly. 
+</bug_desc>
+<bug_fixes>
+Replace `/` with `//` on line 2.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    return apples / children\n</bug_code>\n<bug_desc>\nThe function returns a float instead of the largest possible integer after distributing the apples evenly. \n</bug_desc>\n<bug_fixes>\nReplace `/` with `//` on line 2.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck!""}, {'role': 'assistant', 'content': 'Where do you think the problem is?', 'alt': ['Have you read your code carefully?', 'Which test cases are passing?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': ""I don't know."", 'alt': ['I think the math is wrong.']}, {'role': 'assistant', 'content': 'Look at the test cases, does the first test case pass?', 'alt': ['Look at the test cases, what is the first test case to fail?', 'Have you read your code carefully?', 'Have you read the prompt carefully?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': 'What is the correct answer for case 2?', 'alt': ['What is the correct answer for case 1?', 'Does case 1 require rounding?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'It should output 3.'}, {'role': 'assistant', 'content': 'Would there be a remainder?', 'alt': ['What is the correct answer for case 1?', 'Does case 2 require rounding?', 'Think about division in Python, what does `/` indicate?', 'Think about division in Python, how does it handle remainders?']}, {'role': 'user', 'content': 'Yes, there would be a remainder of 1.', 'alt': ['Oh! I see, the problem is the remainder!']}, {'role': 'assistant', 'content': 'Is there a way you can see what the result is?', 'alt': ['Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'Trace the code, what would the output of line 2 be with 7 and 2?', 'How can you test the output of line 2?']}, {'role': 'user', 'content': 'I can add a print statement before the return.\n```python\n1. def split_apples(apples, children):\n2.    print(apples / children)\n3.    return apples / children\n```'}, {'role': 'assistant', 'content': 'Try running the code, what is the result of dividing 7 by 2?', 'alt': ['Try running the code, what is the result of dividing 10 by 2?', 'Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?']}, {'role': 'user', 'content': ""It's returning 3.5 for 7 divided by 2.""}, {'role': 'assistant', 'content': 'What should the output be?', 'alt': ['Look at the prompt, what are you dividing?', 'Look at the prompt, do you see anything you have forgotten?', 'Look at the prompt, is there anything special about the format of the numbers?', 'Think about division in Python, how does it handle remainders?', 'Think about division in Python, what does `/` indicate?', 'What do you need to change to make the output a whole number?']}, {'role': 'user', 'content': 'It should be 3.'}, {'role': 'assistant', 'content': 'Look at the Python documentation on operators, are you using the correct one to round down?', 'alt': ['Are you using the correct operator?', 'Is there a specific operator you should use when dividing whole numbers?', 'Is there a specific operator you should use when you need to round down?', 'Think about division in Python, what does `/` indicate?', 'How can you make it round down?']}, {'role': 'user', 'content': 'No! I need to use // instead.\n```python\n1. def split_apples(apples, children):\n2.    print(apples // children)\n3.    return apples // children\n```'}, {'role': 'assistant', 'content': 'Run it again, does it output correctly?', 'alt': ['Run it now, do all the test cases pass?']}, {'role': 'user', 'content': ""Yes, it works! I'll remove the extra print statement. \n```python\n1. def split_apples(apples, children):\n2.    return apples // children\n```""}, {'role': 'assistant', 'content': 'Run it one more time, do all the test cases pass?', 'alt': ['Run it again, does it output correctly?']}, {'role': 'user', 'content': 'Yes! It works, thank you!'}]}"
+"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.
+Assistant: Okay, can you explain your `Product()` function in detail?
+	<alt>How familiar are you with functions in Python?
+User: I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.
+Assistant: Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?
+	<alt>Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?
+User: Okay, I've made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn't it be printing out a number?
+<code>
+1. def Product(a, b):
+2.	a * b
+3.print(Product(1,2))
+</code>
+Assistant: A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?
+User: Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?
+<code>
+1. def Product(a, b):
+2.	return a * b
+3.print(Product(1,2))
+</code>
+Assistant: Yes. What is the purpose of line 3? Do you still need it?
+User: It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!
+<code>
+1. def Product(a, b):
+2.	return a * b
+</code>
+Assistant: You're welcome. Is there anything else that I can help you with today?
+User: No, that's all. Thank you!
+</dialogue>","Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```","def Product(a, b):
+a * b","The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.",Add `return` before `a * b`.,"assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25",59_60_product,"<problem>
+Define a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).
+
+## Example Cases: 
+```
+Product(1,2) => 2
+Product(2,4) => 8
+Product(4,4) => 16
+Product(5,5) => 25
+```
+</problem>
+<bug_code>
+1. def Product(a, b):
+2.	a * b
+</bug_code>
+<bug_desc>
+The function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.
+</bug_desc>
+<bug_fixes>
+Add `return` before `a * b`.
+</bug_fixes>
+<unit_tests>
+assert Product(1,2) == 2
+assert Product(2,4) == 8
+assert Product(4,4) == 16
+assert Product(5,5) == 25
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Product(a:int, b:int) -> int` which takes two integer inputs: a and b. The function should return the product of these two values (i.e. a * b).\n\n## Example Cases: \n```\nProduct(1,2) => 2\nProduct(2,4) => 8\nProduct(4,4) => 16\nProduct(5,5) => 25\n```\n</problem>\n<bug_code>\n1. def Product(a, b):\n2.\ta * b\n</bug_code>\n<bug_desc>\nThe function does not return anything, thus when evaluated it computes the value `None` instead of returning the product.\n</bug_desc>\n<bug_fixes>\nAdd `return` before `a * b`.\n</bug_fixes>\n<unit_tests>\nassert Product(1,2) == 2\nassert Product(2,4) == 8\nassert Product(4,4) == 16\nassert Product(5,5) == 25\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello, I'm having trouble with `Product()` function. I swear that I have done it correctly, but I'm failing even the first assertion and I can't figure out why.""}, {'role': 'assistant', 'content': 'Okay, can you explain your `Product()` function in detail?', 'alt': ['How familiar are you with functions in Python?']}, {'role': 'user', 'content': 'I take in two inputs, which I have named `a` and `b`, and then I multiply the two numbers together.'}, {'role': 'assistant', 'content': 'Okay, can you modify your code such that on line 3, you execute the line `print(Product(1,2))`?', 'alt': ['Are you familiar with a way to output the value of `Product(1,2)` to the user through the console?']}, {'role': 'user', 'content': 'Okay, I\'ve made that change, but when I run it, it just prints out ""None"" and still failing the assertion. Shouldn\'t it be printing out a number?\n```python\n1. def Product(a, b):\n2.\ta * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'A function will only take on a value when the keyword `return` is used followed by a value. Otherwise, it will return a special value referred to by `None`, stating that the function did not return any value. Do you know where to put `return` in your code?'}, {'role': 'user', 'content': 'Oh, I put `return` on line 2 and it has started printing out a number, and the assertion statements are no longer providing an error. Should I remove the code on line 3?\n```python\n1. def Product(a, b):\n2.\treturn a * b\n3.print(Product(1,2))\n```'}, {'role': 'assistant', 'content': 'Yes. What is the purpose of line 3? Do you still need it?'}, {'role': 'user', 'content': ""It was to help us figure out what was wrong. I don't need it anymore. Thank you for your help!\n```python\n1. def Product(a, b):\n2.\treturn a * b\n```""}, {'role': 'assistant', 'content': ""You're welcome. Is there anything else that I can help you with today?""}, {'role': 'user', 'content': ""No, that's all. Thank you!""}]}"
+"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.
+Assistant: Hello! Can you explain how your function works step by step?
+User: Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.
+Assistant: Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?
+User: Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?
+Assistant: Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?
+	<alt>What about when `Largest(2,2,1)` is ran? What will be returned?
+User: I'm not sure, how could you pick between them?
+Assistant: While it is required to pick one or the other, what difference would picking the first over the second make in the output?
+User: Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!
+<code>
+1. def Largest(a, b, c):
+2.	if(a >= b and a >= c):
+3.		return a
+4.	elif(b >= a and b >= c):
+5.		return b
+6.	else:
+7.		return c
+</code>
+Assistant: I'm happy that I could help! Is there anything else that I could help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```","def Largest(a, b, c):
+if(a > b and a > c):
+	return a
+elif(b > a and b > c):
+	return b
+else:
+	return c","When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.",Change the > to >= in all the conditions.,"assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1",60_61_largest_number,"<problem>
+Define a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.
+
+## Example Cases:
+```
+Largest(1,2,3) => 3
+Largest(3,2,1) => 3
+Largest(2,2,1) => 2
+Largest(1,1,1) => 1
+```
+</problem>
+<bug_code>
+1. def Largest(a, b, c):
+2.	if(a > b and a > c):
+3.		return a
+4.	elif(b > a and b > c):
+5.		return b
+6.	else:
+7.		return c
+</bug_code>
+<bug_desc>
+When `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.
+</bug_desc>
+<bug_fixes>
+Change the > to >= in all the conditions.
+</bug_fixes>
+<unit_tests>
+assert Largest(1,2,3) == 3
+assert Largest(3,2,1) == 3
+assert Largest(2,2,1) == 2
+assert Largest(1,1,1) == 1
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `Largest(a:int, b:int, c:int) -> int` which takes three integer inputs: a, b and c. The function should return the largest of these three values.\n\n## Example Cases:\n```\nLargest(1,2,3) => 3\nLargest(3,2,1) => 3\nLargest(2,2,1) => 2\nLargest(1,1,1) => 1\n```\n</problem>\n<bug_code>\n1. def Largest(a, b, c):\n2.\tif(a > b and a > c):\n3.\t\treturn a\n4.\telif(b > a and b > c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n</bug_code>\n<bug_desc>\nWhen `a` and `b` are equal, `c` is returned regardless of its comparison to `a` or `b`. For example: `Largest(2,2,1)` returns 1.\n</bug_desc>\n<bug_fixes>\nChange the > to >= in all the conditions.\n</bug_fixes>\n<unit_tests>\nassert Largest(1,2,3) == 3\nassert Largest(3,2,1) == 3\nassert Largest(2,2,1) == 2\nassert Largest(1,1,1) == 1\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hi! I've been working on the `Largest()` function for a while and I can't tell why it's not working. From what I understand it is working, but then it isn't passing the `assert` statements.""}, {'role': 'assistant', 'content': 'Hello! Can you explain how your function works step by step?'}, {'role': 'user', 'content': 'Yes, I can. My `Largest()` function first checks if the first input is the largest, then if the second input is the largest, and if neither of those is the largest, then the function assumes the last input is the largest since neither the first nor the second is the largest.'}, {'role': 'assistant', 'content': 'Okay, you definitely have an understanding of the control flow of this program. However, why would you be able to assume that the final input is the largest if the first is not the greatest and the second is not the greatest?'}, {'role': 'user', 'content': 'Because one of the values has to be the greatest, so if it is neither of the first two, then it would have to be the last value, right?'}, {'role': 'assistant', 'content': 'Think about a case where the first and second inputs are greater than the final input but equal to each other. Which input is the greatest input?', 'alt': ['What about when `Largest(2,2,1)` is ran? What will be returned?']}, {'role': 'user', 'content': ""I'm not sure, how could you pick between them?""}, {'role': 'assistant', 'content': 'While it is required to pick one or the other, what difference would picking the first over the second make in the output?'}, {'role': 'user', 'content': ""Oh, it wouldn't make a difference in the returning value. I changed my operations to allow for equal values and it's now working as expected. Thank you for your help!\n```python\n1. def Largest(a, b, c):\n2.\tif(a >= b and a >= c):\n3.\t\treturn a\n4.\telif(b >= a and b >= c):\n5.\t\treturn b\n6.\telse:\n7.\t\treturn c\n```""}, {'role': 'assistant', 'content': ""I'm happy that I could help! Is there anything else that I could help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.
+Assistant: Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?
+User: From what I understand, it tells you if a number is divisible by another number, right?
+Assistant: The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?
+	<alt>The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?
+User: Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!
+<code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 0
+</code>
+Assistant: I'm happy to help! Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```","def SumIsEven(a, b):
+return (a+b) % 2 == 1
+",The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.,Replace `1` with `0` to ensure that the sum is even.,"assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False",61_62_is_even,"<problem>
+Define a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.
+
+## Example Cases: 
+```
+SumIsEven(1,1) => True
+SumIsEven(1,2) => False
+SumIsEven(2,2) => True
+SumIsEven(2,3) => False
+```
+</problem>
+<bug_code>
+1. def SumIsEven(a, b):
+2.	return (a+b) % 2 == 1
+3.
+</bug_code>
+<bug_desc>
+The function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` to ensure that the sum is even.
+</bug_fixes>
+<unit_tests>
+assert SumIsEven(1,1) == True
+assert SumIsEven(1,2) == False
+assert SumIsEven(2,2) == True
+assert SumIsEven(2,3) == False
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumIsEven(a:int, b:int) -> bool` which takes two integer inputs and returns true if and only if the sum of the two values is an even number. If the sum of the input values is an odd number, then the function must return false.\n\n## Example Cases: \n```\nSumIsEven(1,1) => True\nSumIsEven(1,2) => False\nSumIsEven(2,2) => True\nSumIsEven(2,3) => False\n```\n</problem>\n<bug_code>\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 1\n3.\n</bug_code>\n<bug_desc>\nThe function returns True when `a + b` is not divisible by 2 instead of returning True when `a + b` is divisible by 2.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` to ensure that the sum is even.\n</bug_fixes>\n<unit_tests>\nassert SumIsEven(1,1) == True\nassert SumIsEven(1,2) == False\nassert SumIsEven(2,2) == True\nassert SumIsEven(2,3) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I'm working with the `SumIsEven()` function and it is giving me the opposite answer than I am expecting and I'm not sure why that is the case.""}, {'role': 'assistant', 'content': ""Hello! I see you're using a modulo operation in your code, can you explain how that operation works in simple terms?""}, {'role': 'user', 'content': 'From what I understand, it tells you if a number is divisible by another number, right?'}, {'role': 'assistant', 'content': 'The modulo operation is capable of doing this, but it actually does more than that. The modulo operation will return the remainder of the division of the two operands. If this is the case, what will be the value of `(a+b) % 2` when `a+b` is even?', 'alt': ['The modulo operation is more than a divisibility operand. It returns a remainder. Can you explain the significance of that?']}, {'role': 'user', 'content': ""Oh, it would return 0! That's why my program is responding with the opposite answer. That makes a lot more sense now, thank you!\n```python\n1. def SumIsEven(a, b):\n2.\treturn (a+b) % 2 == 0\n```""}, {'role': 'assistant', 'content': ""I'm happy to help! Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.
+Assistant: Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?
+User: I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.
+Assistant: `range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?
+User: That would just be 0, right?
+Assistant: Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?
+User: Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?
+Assistant: Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?
+	<alt>Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?
+User: I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?
+Assistant: Can you explain why you think that is the correct answer?
+User: Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.
+Assistant: That is entirely correct. Now how would you change your code to express this?
+User: Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!
+<code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high+1):
+4.		num += i
+5.	return num
+</code>
+Assistant: I am glad I could be of assistance. Is there anything else you wanted to ask?
+User: No, that's all for now. Thank you!
+</dialogue>","Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```","def SumBetween(low, high):
+num = 0
+for i in range(low, high):
+	num += i
+return num","The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range.",Replace `high` with `high + 1`.,"assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12",62_63_summing_between_integers,"<problem>
+Define a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.
+
+## Example Cases:
+```
+SumBetween(0,1) => 1
+SumBetween(0,2) => 3
+SumBetween(1,2) => 3
+SumBetween(3,5) => 12
+```
+</problem>
+<bug_code>
+1. def SumBetween(low, high):
+2.	num = 0
+3.	for i in range(low, high):
+4.		num += i
+5.	return num
+</bug_code>
+<bug_desc>
+The function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. 
+</bug_desc>
+<bug_fixes>
+Replace `high` with `high + 1`.
+</bug_fixes>
+<unit_tests>
+assert SumBetween(0,1) == 1
+assert SumBetween(0,2) == 3
+assert SumBetween(1,2) == 3
+assert SumBetween(3,5) == 12
+</unit_tests>
+","{'system': '<problem>\nDefine a function called `SumBetween(low:int, high:int) -> int` which takes two integer inputs, low and high. This function should calculate the sum of all integers between low and high inclusive.\n\n## Example Cases:\n```\nSumBetween(0,1) => 1\nSumBetween(0,2) => 3\nSumBetween(1,2) => 3\nSumBetween(3,5) => 12\n```\n</problem>\n<bug_code>\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high):\n4.\t\tnum += i\n5.\treturn num\n</bug_code>\n<bug_desc>\nThe function returns the sum of numbers between `low` and `high`, but excludes the upper bound `high` instead of including both ends of the range. \n</bug_desc>\n<bug_fixes>\nReplace `high` with `high + 1`.\n</bug_fixes>\n<unit_tests>\nassert SumBetween(0,1) == 1\nassert SumBetween(0,2) == 3\nassert SumBetween(1,2) == 3\nassert SumBetween(3,5) == 12\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I am having trouble with my `SumBetween()` function. It keeps producing values that are only a little bit wrong compared to the expected values, and I don't know why.""}, {'role': 'assistant', 'content': 'Hello! I think that your issue may be in your understanding of `range()`. What do you believe is returned from `range(0,1)`, for example?'}, {'role': 'user', 'content': ""I'm not sure, I know that this is how we typically construct a `for` loop but I don't know what `range()` is returning for it to work.""}, {'role': 'assistant', 'content': '`range(0,1)` is returning a value referred to as a list, specifically a list of integers from 0, inclusively, to 1, exclusively. Can you tell me what the elements of that list would be?'}, {'role': 'user', 'content': 'That would just be 0, right?'}, {'role': 'assistant', 'content': 'Correct! The line `for i in range(0,1)` means it will, for every value in the list `range(0,1)`, set `i` equal to that value and then run an iteration of the loop. Can you see where your code would make a mistake when taking the sum between 0 and 1?'}, {'role': 'user', 'content': ""Oh, 0 is an element of the list, but 1 isn't! How would I extend the range though, if I am only given `low` and `high`?""}, {'role': 'assistant', 'content': ""Let's approach that question from a different direction. If you wanted to include 1 as an element in the list, how would you change `range(0,1)`?"", 'alt': [""Let's abstract this a bit then. Let's say we have variables `x` and `y`, which are integers. What number is in `range(x,y+1)` that is not in `range(x,y)`?""]}, {'role': 'user', 'content': 'I would change `range(0,1)` to `range(0,2)` so that it would include 1. So I just need to add 1 every time to `high`?'}, {'role': 'assistant', 'content': 'Can you explain why you think that is the correct answer?'}, {'role': 'user', 'content': 'Because since `range()` will return every integer in the range, not including the highest value, if we increase the highest value by 1, we would add the previous highest value as an element in the returned list.'}, {'role': 'assistant', 'content': 'That is entirely correct. Now how would you change your code to express this?'}, {'role': 'user', 'content': 'Oh, when I change `high` to `high + 1` it works as expected. Thank you so much for your help!\n```python\n1. def SumBetween(low, high):\n2.\tnum = 0\n3.\tfor i in range(low, high+1):\n4.\t\tnum += i\n5.\treturn num\n```'}, {'role': 'assistant', 'content': 'I am glad I could be of assistance. Is there anything else you wanted to ask?'}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.
+Assistant: Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?
+	<alt>When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?
+User: It would be 10 or more pizzas.
+Assistant: And how would you produce a boolean that is `True` when the `pizzas` fits that condition?
+User: It would be `pizzas >= 10`.
+Assistant: Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?
+User: That's where I'm confused. It's between 10 and 20, inclusively, right?
+Assistant: That is correct, what about that condition is confusing you?
+User: I'm not sure how to convert a number between two other numbers into Python.
+Assistant: Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?
+User: That would be `pizzas >= 10` and `pizzas <= 20`.
+Assistant: And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?
+	<alt>And would you use `and`, `or`, or `xor` to produce your desired outcome?
+User: That would be `and` right?
+Assistant: Correct. Do you see now how you would implement a condition for when `weekend` is `False`?
+User: Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!
+<code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</code>
+Assistant: I'm glad to be of assistance. Is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```","def GoodDinner(pizzas, weekend):
+       if(pizzas >= 10 and weekend):
+               return True
+       elif(pizzas <= 20 and not(weekend)):
+               return True
+       return False",The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10.,Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.,"assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False",63_64_good_dinner,"<problem>
+You like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.
+
+## Example Cases:
+```
+GoodDinner(10, False) => True
+GoodDinner(20, False) => True
+GoodDinner(5, False) => False
+GoodDinner(21, False) => False
+GoodDinner(10, True) => True
+GoodDinner(21, True) => True
+GoodDinner(5, True) => False
+```
+</problem>
+<bug_code>
+1. def GoodDinner(pizzas, weekend):
+2.        if(pizzas >= 10 and weekend):
+3.                return True
+4.        elif(pizzas <= 20 and not(weekend)):
+5.                return True
+6.        return False
+</bug_code>
+<bug_desc>
+The function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. 
+</bug_desc>
+<bug_fixes>
+Insert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.
+</bug_fixes>
+<unit_tests>
+assert GoodDinner(10, False) == True
+assert GoodDinner(20, False) == True
+assert GoodDinner(5, False) == False
+assert GoodDinner(21, False) == False
+assert GoodDinner(10, True) == True
+assert GoodDinner(21, True) == True
+assert GoodDinner(5, True) == False
+</unit_tests>
+","{'system': ""<problem>\nYou like to eat pizzas for dinner. A good dinner is a dinner where you eat between 10 and 20 pizzas (inclusive). Unless it is a weekend, in which case there is no upper bound on the number of pizzas. Write a function called `GoodDinner(pizzas_int, weekend:bool) -> bool` which takes two inputs: the number of pizzas you eat, and a boolean which is true if it is the weekend and false otherwise. Your function should return true if you had a good dinner, and false if you didn't.\n\n## Example Cases:\n```\nGoodDinner(10, False) => True\nGoodDinner(20, False) => True\nGoodDinner(5, False) => False\nGoodDinner(21, False) => False\nGoodDinner(10, True) => True\nGoodDinner(21, True) => True\nGoodDinner(5, True) => False\n```\n</problem>\n<bug_code>\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n</bug_code>\n<bug_desc>\nThe function incorrectly returns True instead of False when it is a weekday and `pizzas` is less than 10. \n</bug_desc>\n<bug_fixes>\nInsert `pizzas >= 10 and` before `pizzas <= 20 and not(weekend)` in the elif condition on line 4.\n</bug_fixes>\n<unit_tests>\nassert GoodDinner(10, False) == True\nassert GoodDinner(20, False) == True\nassert GoodDinner(5, False) == False\nassert GoodDinner(21, False) == False\nassert GoodDinner(10, True) == True\nassert GoodDinner(21, True) == True\nassert GoodDinner(5, True) == False\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `GoodDinner()` function and I'm running into a roadblock. I just can't see where the issue in my code is.""}, {'role': 'assistant', 'content': ""Okay let's start with the simpler case. When `weekend` is `True`, how many pizzas would turn a dinner into a good dinner?"", 'alt': ['When `weekend` is `False` and `pizzas` is between 0 and 10, what is the expected behavior?']}, {'role': 'user', 'content': 'It would be 10 or more pizzas.'}, {'role': 'assistant', 'content': 'And how would you produce a boolean that is `True` when the `pizzas` fits that condition?'}, {'role': 'user', 'content': 'It would be `pizzas >= 10`.'}, {'role': 'assistant', 'content': ""Okay, and making an `and` between these two makes your first condition. Now let's move to the more complex condition. When `weekend` is `False`, how many pizzas would make a dinner into a good dinner?""}, {'role': 'user', 'content': ""That's where I'm confused. It's between 10 and 20, inclusively, right?""}, {'role': 'assistant', 'content': 'That is correct, what about that condition is confusing you?'}, {'role': 'user', 'content': ""I'm not sure how to convert a number between two other numbers into Python.""}, {'role': 'assistant', 'content': ""Let's break it into two parts. How would you check if `pizzas` is 10 or over and how would you check if `pizzas` is 20 or under?""}, {'role': 'user', 'content': 'That would be `pizzas >= 10` and `pizzas <= 20`.'}, {'role': 'assistant', 'content': 'And what logical operator would we use to connect those operations to create a boolean that is only `True` if pizzas is between 10 and 20, inclusively?', 'alt': ['And would you use `and`, `or`, or `xor` to produce your desired outcome?']}, {'role': 'user', 'content': 'That would be `and` right?'}, {'role': 'assistant', 'content': 'Correct. Do you see now how you would implement a condition for when `weekend` is `False`?'}, {'role': 'user', 'content': 'Oh, now I see where I went wrong. I added another `and` statement and it works now. Thank you for your help!\n```python\n1. def GoodDinner(pizzas, weekend):\n2.        if(pizzas >= 10 and weekend):\n3.                return True\n4.        elif(pizzas >= 10 and pizzas <= 20 and not(weekend)):\n5.                return True\n6.        return False\n```'}, {'role': 'assistant', 'content': ""I'm glad to be of assistance. Is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.
+Assistant: Hello! Can you explain what your `for` loop does?
+User: It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.
+Assistant: Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?
+Assistant: That's not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".
+	<alt>At what index do Python lists begin?
+	<alt>Can you tell me how many elements are in `range(1, len(integers))`?
+User: Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!
+<code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(0, len(integers)):
+4.		if(integers[i] == 1):
+5.			count += 1
+6.	return count
+</code>
+Assistant: I'm glad I could be of assistance. Is there anything else you wanted to discuss today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```","def CountOnes(integers):
+count = 0
+for i in range(1, len(integers)):
+	if(integers[i] == 1):
+		count++
+return count","On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.",Replace `1` with `0` in the `range` call on line 3.,"assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0",64_65_count_ones,"<problem>
+Write a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.
+
+## Example Cases:
+```
+CountOnes([1,1,1,0,0]) => 3
+CountOnes([1,0,0]) => 1
+CountOnes([]) => 0
+CountOnes([3]) => 0
+```
+</problem>
+<bug_code>
+1. def CountOnes(integers):
+2.	count = 0
+3.	for i in range(1, len(integers)):
+4.		if(integers[i] == 1):
+5.			count++
+6.	return count
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert CountOnes([1,1,1,0,0]) == 3
+assert CountOnes([1,0,0]) == 1
+assert CountOnes([]) == 0
+assert CountOnes([3]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `CountOnes(integers:list) -> int` which is passed one input a list of integers. This function should count how many elements in the array are equal to 1, and it should return this number.\n\n## Example Cases:\n```\nCountOnes([1,1,1,0,0]) => 3\nCountOnes([1,0,0]) => 1\nCountOnes([]) => 0\nCountOnes([3]) => 0\n```\n</problem>\n<bug_code>\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(1, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount++\n6.\treturn count\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `integers - 1` times instead of `integers` times. Consequently, the function does not access all elements in the `integers` list and always skips the first element in `integers`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert CountOnes([1,1,1,0,0]) == 3\nassert CountOnes([1,0,0]) == 1\nassert CountOnes([]) == 0\nassert CountOnes([3]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Hello! I was working on my `CountOnes()` function and I keep getting the wrong count but I don't know what I'm doing wrong.""}, {'role': 'assistant', 'content': 'Hello! Can you explain what your `for` loop does?'}, {'role': 'user', 'content': 'It is a loop over `range(1, len(integers))` and then checks if the element of `integers` at index `i` is 1, and if it is, increments the count.'}, {'role': 'assistant', 'content': 'Can you tell me how many elements are in `range(1, len(integers))`?'}, {'role': 'user', 'content': 'Oh, it only has `len(integers)-1` elements. So I would have to use `range(1, len(integers)+1)`, right?'}, {'role': 'assistant', 'content': 'That\'s not quite right. Lists in Python begin at index 0, not index 1. Try to think about indices as ""distance from the first element"" rather than ""element number"".', 'alt': ['At what index do Python lists begin?', 'Can you tell me how many elements are in `range(1, len(integers))`?']}, {'role': 'user', 'content': 'Oh, that makes a lot more sense. I made the change and my code is working as intended now. Thank you!\n```python\n1. def CountOnes(integers):\n2.\tcount = 0\n3.\tfor i in range(0, len(integers)):\n4.\t\tif(integers[i] == 1):\n5.\t\t\tcount += 1\n6.\treturn count\n```'}, {'role': 'assistant', 'content': ""I'm glad I could be of assistance. Is there anything else you wanted to discuss today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am working on the `Range()` function and I am getting unexpected results.
+Assistant: Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?
+User: The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.
+Assistant: This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?
+User: Oh. So I should choose a really big number for smallest and a really small number for largest?
+Assistant: Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.
+	<alt>Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?
+User: Would it work to just set them to start as an element of the array?
+Assistant: And which element of the array would you set it to?
+	<alt>That is correct. Why would that be the case?
+User: I set it to the first element of the array and it works now! Thank you!
+<code>
+1. def Range(array):
+2.	smallest = array[0]
+3.	largest = array[0]
+4.	for element in array:
+5.		if(element > largest):
+6.			largest = element
+7.		if(element < smallest):
+8.			smallest = element
+9.	return largest - smallest
+</code>
+Assistant: I'm glad I could help you! Is there anything else I can help you with today?
+</dialogue>","Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```","def Range(array):
+       smallest = 0
+       largest = 0
+       for element in array:
+               if(element > largest):
+                       largest = element
+               if(element < smallest):
+                       smallest = element
+       return largest - smallest","On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.",Initialize `smallest` and `largest` to the first element of array `array[0]`.,"assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13",65_66_list_range,"<problem>
+Write a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.
+
+## Example Cases:
+```
+Range([1,2]) => 1
+Range([1,1,1,1,1,1,5])  => 4
+Range([2,2,1,3])  => 2
+Range([-10,-3,-1])  => 9
+Range([-10,3,1])  => 13
+```
+</problem>
+<bug_code>
+1. def Range(array):
+2.        smallest = 0
+3.        largest = 0
+4.        for element in array:
+5.                if(element > largest):
+6.                        largest = element
+7.                if(element < smallest):
+8.                        smallest = element
+9.        return largest - smallest
+</bug_code>
+<bug_desc>
+On lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.
+</bug_desc>
+<bug_fixes>
+Initialize `smallest` and `largest` to the first element of array `array[0]`.
+</bug_fixes>
+<unit_tests>
+assert Range([1,2]) == 1
+assert Range([1,1,1,1,1,1,5]) == 4
+assert Range([2,2,1,3]) == 2
+assert Range([-10,-3,-1]) == 9
+assert Range([-10,3,1]) == 13
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `Range(array:list) -> int` which is passed one input, a list of integers. This function should return the difference between the largest value in the array and the smallest value in the array.\n\n## Example Cases:\n```\nRange([1,2]) => 1\nRange([1,1,1,1,1,1,5])  => 4\nRange([2,2,1,3])  => 2\nRange([-10,-3,-1])  => 9\nRange([-10,3,1])  => 13\n```\n</problem>\n<bug_code>\n1. def Range(array):\n2.        smallest = 0\n3.        largest = 0\n4.        for element in array:\n5.                if(element > largest):\n6.                        largest = element\n7.                if(element < smallest):\n8.                        smallest = element\n9.        return largest - smallest\n</bug_code>\n<bug_desc>\nOn lines 2 and 3, `smallest` and `largest` are initialized to 0 if the largest element in the array is a negative number `largest` will remain 0 and consequently the range will be computed incorrectly.\n</bug_desc>\n<bug_fixes>\nInitialize `smallest` and `largest` to the first element of array `array[0]`.\n</bug_fixes>\n<unit_tests>\nassert Range([1,2]) == 1\nassert Range([1,1,1,1,1,1,5]) == 4\nassert Range([2,2,1,3]) == 2\nassert Range([-10,-3,-1]) == 9\nassert Range([-10,3,1]) == 13\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello! I am working on the `Range()` function and I am getting unexpected results.'}, {'role': 'assistant', 'content': ""Hello! Of course, I can be of assistance.  With the return value of your program, let's look at the values of smallest and largest throughout your program. Can you walk through how you expect your code to operate?""}, {'role': 'user', 'content': 'The values of `largest` and `smallest` start out at 0, and the `for` loop iterates over every element in the array, and if an element larger than the current value of `largest`or smaller than the current value of `smallest`, the respective variable is set equal to that value. After every element is checked,  it returns the difference between `largest` and `smallest`, which is the range of the list.'}, {'role': 'assistant', 'content': 'This is how the program is intended to run, however, what if there is not a value smaller than 0 or larger than 0 in the list?'}, {'role': 'user', 'content': 'Oh. So I should choose a really big number for smallest and a really small number for largest?'}, {'role': 'assistant', 'content': 'Would you be able to guarantee that the list you are given is only of values that are within the arbitrary constraints you set? There is a better way to ensure that the values of `largest` and `smallest` are always within the list.', 'alt': [""Let's say you picked -1000 for your initial value of `largest`, can you think of a list where your initial value is larger than every element of the list?""]}, {'role': 'user', 'content': 'Would it work to just set them to start as an element of the array?'}, {'role': 'assistant', 'content': 'And which element of the array would you set it to?', 'alt': ['That is correct. Why would that be the case?']}, {'role': 'user', 'content': 'I set it to the first element of the array and it works now! Thank you!\n```python\n1. def Range(array):\n2.\tsmallest = array[0]\n3.\tlargest = array[0]\n4.\tfor element in array:\n5.\t\tif(element > largest):\n6.\t\t\tlargest = element\n7.\t\tif(element < smallest):\n8.\t\t\tsmallest = element\n9.\treturn largest - smallest\n```'}, {'role': 'assistant', 'content': ""I'm glad I could help you! Is there anything else I can help you with today?""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, where do you think the problem is?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first failing test case?
+	<alt>Have you read the instructions carefully to check if your code does everything it needs to?
+User: I don't know.
+Assistant: Which line has the first failing test case?
+	<alt>Does the first test case pass?
+	<alt>Which line has the first part of your function on it?
+	<alt>What is your function supposed to do?
+User: It's failing test 4, on line 11
+Assistant: Why is that one failing?
+	<alt>Is the value in the array?
+	<alt>Which line has the first part of your function in it?
+	<alt>How is that one different from the first test case on line 8?
+User: I don't know, it can't find the four.
+Assistant: Since it can't find the four, can it find other values?
+	<alt>Is there a four in the array?
+	<alt>Is that different from test case 1?
+	<alt>Which line has the first part of your function in it?
+User: It found the one in the first test case.
+Assistant: Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?
+	<alt>What makes test case 1 and test case 4 different?
+	<alt>Which line has the first part of your function in it?
+	<alt>What part of the code checks each element in the array?
+User: Maybe the problem is in the loop part where I check the values.
+Assistant: What line is that on?
+User: It's on line 3.
+Assistant: Very good, so where should it start looking and stop looking?
+	<alt>What exactly does this line do?
+	<alt>What does ""range"" mean in Python?
+User: It should start at the first element and stop at the end of the array.
+Assistant: Which part of that line indicates that?
+	<alt>What does ""range"" mean in Python?
+	<alt>What is the numeric value of the first index in an array in Python?
+User: The part inside the range.
+	<alt>Oh! I'm starting at 1 instead of 0
+Assistant: Which index does it start at?
+	<alt>What is the numeric value of the first index in an array in Python?
+	<alt>How do you find the first index of an array in Python?
+User: It starts at 1.
+	<alt>I'm starting in the wrong place!
+Assistant: What number marks the first index of an array in Python?
+	<alt>Could it be skipping anything?
+User: Arrays in Python start at 0, I'm skipping the first index!
+Assistant: How would you fix it?
+	<alt>What number should be there?
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+User: I switched it to a zero and it works! Thanks!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = -1
+for i in range(1, len(array)):
+	if(value == array[i]):
+		index = i
+return index","On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.",Replace `1` with `0` in the `range` call on line 3.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_68_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(1, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+On line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.
+</bug_desc>
+<bug_fixes>
+Replace `1` with `0` in the `range` call on line 3.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(1, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nOn line 3, the loop iterates `array - 1` times instead of `array` times. Consequently, the function does not access all elements in the `array` list and always skips the first element in the `array`.\n</bug_desc>\n<bug_fixes>\nReplace `1` with `0` in the `range` call on line 3.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Does the first test case pass?', 'Which line has the first failing test case?', 'Have you read the instructions carefully to check if your code does everything it needs to?']}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': 'Which line has the first failing test case?', 'alt': ['Does the first test case pass?', 'Which line has the first part of your function on it?', 'What is your function supposed to do?']}, {'role': 'user', 'content': ""It's failing test 4, on line 11""}, {'role': 'assistant', 'content': 'Why is that one failing?', 'alt': ['Is the value in the array?', 'Which line has the first part of your function in it?', 'How is that one different from the first test case on line 8?']}, {'role': 'user', 'content': ""I don't know, it can't find the four.""}, {'role': 'assistant', 'content': ""Since it can't find the four, can it find other values?"", 'alt': ['Is there a four in the array?', 'Is that different from test case 1?', 'Which line has the first part of your function in it?']}, {'role': 'user', 'content': 'It found the one in the first test case.'}, {'role': 'assistant', 'content': ""Okay, so it didn't find the four, but it can find other values. Does that give you any ideas about where the problem might be?"", 'alt': ['What makes test case 1 and test case 4 different?', 'Which line has the first part of your function in it?', 'What part of the code checks each element in the array?']}, {'role': 'user', 'content': 'Maybe the problem is in the loop part where I check the values.'}, {'role': 'assistant', 'content': 'What line is that on?'}, {'role': 'user', 'content': ""It's on line 3.""}, {'role': 'assistant', 'content': 'Very good, so where should it start looking and stop looking?', 'alt': ['What exactly does this line do?', 'What does ""range"" mean in Python?']}, {'role': 'user', 'content': 'It should start at the first element and stop at the end of the array.'}, {'role': 'assistant', 'content': 'Which part of that line indicates that?', 'alt': ['What does ""range"" mean in Python?', 'What is the numeric value of the first index in an array in Python?']}, {'role': 'user', 'content': 'The part inside the range.', 'alt': [""Oh! I'm starting at 1 instead of 0""]}, {'role': 'assistant', 'content': 'Which index does it start at?', 'alt': ['What is the numeric value of the first index in an array in Python?', 'How do you find the first index of an array in Python?']}, {'role': 'user', 'content': 'It starts at 1.', 'alt': [""I'm starting in the wrong place!""]}, {'role': 'assistant', 'content': 'What number marks the first index of an array in Python?', 'alt': ['Could it be skipping anything?']}, {'role': 'user', 'content': ""Arrays in Python start at 0, I'm skipping the first index!""}, {'role': 'assistant', 'content': 'How would you fix it?\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```', 'alt': ['What number should be there?']}, {'role': 'user', 'content': 'I switched it to a zero and it works! Thanks!'}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.
+Assistant: Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?
+User: `index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.
+Assistant: And what would distinguish that action from the function finding a match at index 0?
+	<alt>Can you explain the difference between that and if the first element is the last index of the value?
+User: I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.
+Assistant: The intended return value is -1, as given in the problem.
+	<alt>This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.
+User: Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!
+<code>
+1. def LastIndexOf(value, array):
+2.	index = -1
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</code>
+Assistant: I'm glad to be of assistance, is there anything else I can help you with today?
+User: No, that's all for now. Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+index = 0
+for i in range(0, len(array)):
+	if(value == array[i]):
+		index = i
+return index",The function returns 0 when `value` is not in `array` instead of returning -1.,Initialize `index` to -1 on line 2.,"assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_67_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.	index = 0
+3.	for i in range(0, len(array)):
+4.		if(value == array[i]):
+5.			index = i
+6.	return index
+</bug_code>
+<bug_desc>
+The function returns 0 when `value` is not in `array` instead of returning -1.
+</bug_desc>
+<bug_fixes>
+Initialize `index` to -1 on line 2.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.\tindex = 0\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n</bug_code>\n<bug_desc>\nThe function returns 0 when `value` is not in `array` instead of returning -1.\n</bug_desc>\n<bug_fixes>\nInitialize `index` to -1 on line 2.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hello, I was having an issue with my `LastIndexOf()` function and I was wondering if I could get some guidance as to where I am going wrong.'}, {'role': 'assistant', 'content': 'Hello! I am happy to help you. Can you explain what would happen in the case that the integer you are searching for is not in the list?'}, {'role': 'user', 'content': '`index` would start at 0, then since the `if` condition is never met, it will stay as 0 and then `index` will return.'}, {'role': 'assistant', 'content': 'And what would distinguish that action from the function finding a match at index 0?', 'alt': ['Can you explain the difference between that and if the first element is the last index of the value?']}, {'role': 'user', 'content': ""I suppose that is an important distinction to make. What number would be appropriate to return then? I'm not sure what number would not be misconstrued.""}, {'role': 'assistant', 'content': 'The intended return value is -1, as given in the problem.', 'alt': ['This is a good question, the answer is that value is arbitrary, and would be given. In this case, it is given in the problem.']}, {'role': 'user', 'content': ""Oh, I missed that when reading the problem description. I've changed it and now my code is working as expected now. Thank you!\n```python\n1. def LastIndexOf(value, array):\n2.\tindex = -1\n3.\tfor i in range(0, len(array)):\n4.\t\tif(value == array[i]):\n5.\t\t\tindex = i\n6.\treturn index\n```""}, {'role': 'assistant', 'content': ""I'm glad to be of assistance, is there anything else I can help you with today?""}, {'role': 'user', 'content': ""No, that's all for now. Thank you!""}]}"
+"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: No, it doesn't pass.
+Assistant: Let's start by going over the first line of your function, what does line 1 do?
+	<alt>Let's start with your function. What do you think is the most complicated part?
+	<alt>Can you describe what your function does?
+User: It takes in the array and the value we are looking for.
+Assistant: Very good, does line 1 take in both of those things?
+	<alt>Very good, let's move on to the next area, what does line 2 do?
+	<alt>Very good, what can you explain what else your function is supposed to do?
+	<alt>What do you think is the most complicated part of your function?
+User: Yes, line 1 does.
+Assistant: Okay, let's move on to the next area, what does line 2 do?
+	<alt>What is the next thing your function needs to do?
+	<alt>Let's check the most complex part of the function for problems next, where would you say that is?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+User: It makes the index variable that keeps track of where the value is.
+Assistant: What should your function do next?
+	<alt>Let's make sure your function ends correctly, what value is it returning?
+	<alt>Why do we start index at -1?
+User: It needs to loop through the list.
+Assistant: Let's examine that loop carefully. What variable controls the loop?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Is there anything special about how we are moving through the list?
+User: The variable i controls the loop.
+Assistant: What value should i have on the first iteration of the loop?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>Let's examine that loop carefully,  what determines how many times the loop will run?
+User: The loop is supposed to start at the highest value in the array minus 1.
+Assistant: Is there anything special about how we are moving through the list?
+	<alt>Let's check that loop carefully, how should we move through the list?
+	<alt>What value should i have at the end of the loop?
+User: We are moving through the list backward.
+Assistant: Check the Python documentation, how do we iterate in a loop by default?
+	<alt>Check the Python documentation, what is the default step?
+	<alt>Check the Python documentation, how would we move through a list not incrementing by one each time?
+	<alt>Have you ever moved through a list in reverse with range?
+User: Oh! In Python it increases by one by default! We are going the wrong way.
+Assistant: What would you need do in the code to fix that?
+<code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</code>
+User: I need to add a -1 step!
+Assistant: Does it pass all the test cases?
+User: Yes! Thank you!
+</dialogue>","Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```","def LastIndexOf(value, array):
+   index = -1
+   for i in range(len(array)-1, -1):
+       if(array[i] == value):
+           index = i
+           break
+   return index","On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.","Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.","assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0",66_69_last_index_of,"<problem>
+Write a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.
+
+## Example Cases:
+```
+LastIndexOf(1, [1,1,1,1]) => 3
+LastIndexOf(2, [2,0,1,2])  => 3
+LastIndexOf(3, [1,1,1,1]) => -1
+LastIndexOf(4, [4,1,1,1]) => 0
+```
+</problem>
+<bug_code>
+1. def LastIndexOf(value, array):
+2.    index = -1
+3.    for i in range(len(array)-1, -1):
+4.        if(array[i] == value):
+5.            index = i
+6.            break
+7.    return index
+</bug_code>
+<bug_desc>
+On line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.
+</bug_desc>
+<bug_fixes>
+Change the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.
+</bug_fixes>
+<unit_tests>
+assert LastIndexOf(1, [1,1,1,1]) == 3
+assert LastIndexOf(2, [2,0,1,2]) == 3
+assert LastIndexOf(3, [1,1,1,1]) == -1
+assert LastIndexOf(4, [4,1,1,1]) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a function called `LastIndexOf(value:int, array:list) -> int` which is passed two inputs: a value to search for, and a list of integers in which to search. This function should return the index position of the last occurrence (i.e. the rightmost occurrence) of the value being searched for. If the value being searched for does not exist in the array, then the function should return -1.\n\n## Example Cases:\n```\nLastIndexOf(1, [1,1,1,1]) => 3\nLastIndexOf(2, [2,0,1,2])  => 3\nLastIndexOf(3, [1,1,1,1]) => -1\nLastIndexOf(4, [4,1,1,1]) => 0\n```\n</problem>\n<bug_code>\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n</bug_code>\n<bug_desc>\nOn line 3, the range is from `len(array)-1` to `-1`. The `range` function does not iterate when the start is greater than the stop. Consequently, the for loop is not executed and the function always returns -1.\n</bug_desc>\n<bug_fixes>\nChange the `range` function on line 3 to `range(len(array)-1, -1, -1)` to iterate backwards from `len(array)-1 to -1`.\n</bug_fixes>\n<unit_tests>\nassert LastIndexOf(1, [1,1,1,1]) == 3\nassert LastIndexOf(2, [2,0,1,2]) == 3\nassert LastIndexOf(3, [1,1,1,1]) == -1\nassert LastIndexOf(4, [4,1,1,1]) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': ""Okay, let's go over the code. Does the first test case pass?"", 'alt': ['Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': ""No, it doesn't pass.""}, {'role': 'assistant', 'content': ""Let's start by going over the first line of your function, what does line 1 do?"", 'alt': [""Let's start with your function. What do you think is the most complicated part?"", 'Can you describe what your function does?']}, {'role': 'user', 'content': 'It takes in the array and the value we are looking for.'}, {'role': 'assistant', 'content': 'Very good, does line 1 take in both of those things?', 'alt': [""Very good, let's move on to the next area, what does line 2 do?"", 'Very good, what can you explain what else your function is supposed to do?', 'What do you think is the most complicated part of your function?']}, {'role': 'user', 'content': 'Yes, line 1 does.'}, {'role': 'assistant', 'content': ""Okay, let's move on to the next area, what does line 2 do?"", 'alt': ['What is the next thing your function needs to do?', ""Let's check the most complex part of the function for problems next, where would you say that is?"", ""Let's make sure your function ends correctly, what value is it returning?""]}, {'role': 'user', 'content': 'It makes the index variable that keeps track of where the value is.'}, {'role': 'assistant', 'content': 'What should your function do next?', 'alt': [""Let's make sure your function ends correctly, what value is it returning?"", 'Why do we start index at -1?']}, {'role': 'user', 'content': 'It needs to loop through the list.'}, {'role': 'assistant', 'content': ""Let's examine that loop carefully. What variable controls the loop?"", 'alt': [""Let's examine that loop carefully,  what determines how many times the loop will run?"", ""Let's check that loop carefully, how should we move through the list?"", 'Is there anything special about how we are moving through the list?']}, {'role': 'user', 'content': 'The variable i controls the loop.'}, {'role': 'assistant', 'content': 'What value should i have on the first iteration of the loop?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", ""Let's examine that loop carefully,  what determines how many times the loop will run?""]}, {'role': 'user', 'content': 'The loop is supposed to start at the highest value in the array minus 1.'}, {'role': 'assistant', 'content': 'Is there anything special about how we are moving through the list?', 'alt': [""Let's check that loop carefully, how should we move through the list?"", 'What value should i have at the end of the loop?']}, {'role': 'user', 'content': 'We are moving through the list backward.'}, {'role': 'assistant', 'content': 'Check the Python documentation, how do we iterate in a loop by default?', 'alt': ['Check the Python documentation, what is the default step?', 'Check the Python documentation, how would we move through a list not incrementing by one each time?', 'Have you ever moved through a list in reverse with range?']}, {'role': 'user', 'content': 'Oh! In Python it increases by one by default! We are going the wrong way.'}, {'role': 'assistant', 'content': 'What would you need do in the code to fix that?\n```python\n1. def LastIndexOf(value, array):\n2.    index = -1\n3.    for i in range(len(array)-1, -1, -1):\n4.        if(array[i] == value):\n5.            index = i\n6.            break\n7.    return index\n```'}, {'role': 'user', 'content': 'I need to add a -1 step!'}, {'role': 'assistant', 'content': 'Does it pass all the test cases?'}, {'role': 'user', 'content': 'Yes! Thank you!'}]}"
+"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck!
+Assistant: Okay, do you have any ideas what the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Recheck the instructions, do you think anything is missing?
+User: No, I don't know what's wrong.
+	<alt>The first test case is passing, but the second one is failing.
+Assistant: Okay, let's start by looking at the test cases, does the one on line 8 pass?
+	<alt>Check the instructions, did you skip any steps?
+	<alt>What exactly is this function designed to do?
+User: Yes, the first test case passes, but the second one fails.
+Assistant: Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?
+	<alt>That's interesting, why do you think the first test case is passing?
+	<alt>What is the radius of the circle in the first test case that is passing?
+	<alt>What is the radius of the circle in the first test case that is failing?
+	<alt>Look at the if-statement on line 3, do you see any problems with it?
+User: I calculate the area on line 5.
+Assistant: Look carefully at that line, can you tell me exactly what the code there does?
+	<alt>First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?
+	<alt>What is the formula for calculating the area of a circle?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Look carefully at that line, can you tell me exactly what the code there is supposed to do?
+User: That's where the area of the circle is calculated.
+Assistant: What's the formula for calculating that?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Pi times the radius of the circle squared.
+	<alt>Oh! I'm not squaring the radius, I'm multiplying it times itself!
+Assistant: Very good, so let's check that part, do you have Pi in the line?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>What is the python operator for multiplying two numbers?
+	<alt>Walk me through that line, what does the first variable represent?
+User: Yes, that's the math.pi part.
+Assistant: Very good, and do you have the radius in there?
+	<alt>What do you multiply pi by?
+	<alt>Are you multiplying pi by the correct value?
+User: Yes, that's the radius variable.
+	<alt>I'm not squaring it!
+Assistant: What are you supposed to do with the radius?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+	<alt>How do you square a variable?
+User: I'm supposed to square it.
+Assistant: How do you square a number in Python?
+	<alt>What is the python operator for raising one value to the power of another?
+	<alt>Did you square the radius?
+User: It's ** with a 2.
+	<alt>I'm raising it to itself, not squaring it!
+Assistant: Look at that line again, are you squaring the value?
+User: No! I'm raising it to itself. I'll fix it.
+<code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** 2
+</code>
+Assistant: Does it run correctly now?
+User: Yes! It's passing all the test cases! Thanks!
+</dialogue>","Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```","import math
+def area_circle(radius):
+   if radius < 0:
+       return 0
+   return math.pi * radius ** radius","On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.","Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`","import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)",67_70_area_circle,"<problem>
+Write a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.
+
+## Example Cases:
+```
+area_circle(1.0) => 3.141
+area_circle(2.5) => 19.634
+area_circle(3.6) => 40.715
+area_circle(4.1) => 52.810
+area_circle(7.0) => 153.938
+area_circle(-2.0) => 0
+```
+</problem>
+<bug_code>
+1. import math
+2.def area_circle(radius):
+3.    if radius < 0:
+4.        return 0
+5.    return math.pi * radius ** radius
+</bug_code>
+<bug_desc>
+On line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.
+</bug_desc>
+<bug_fixes>
+Change the return statement on line 4 to `math.pi * radius * radius`
+Change the return statement on line 4 to `math.pi * radius **2`
+</bug_fixes>
+<unit_tests>
+import math
+assert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)
+assert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)
+assert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)
+assert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)
+assert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)
+assert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)
+</unit_tests>
+","{'system': '<problem>\nWrite a function that computes the area of a circle. You will name your function `area_circle(radius: float) -> float`. It has one parameter, the radius of the circle, radius. `The area_circle` function will return the area of the circle.\n\n## Example Cases:\n```\narea_circle(1.0) => 3.141\narea_circle(2.5) => 19.634\narea_circle(3.6) => 40.715\narea_circle(4.1) => 52.810\narea_circle(7.0) => 153.938\narea_circle(-2.0) => 0\n```\n</problem>\n<bug_code>\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** radius\n</bug_code>\n<bug_desc>\nOn line 3, the function raises the radius to the power of the radius instead of squaring it. As a result, the function does not compute the circle area correctly.\n</bug_desc>\n<bug_fixes>\nChange the return statement on line 4 to `math.pi * radius * radius`\nChange the return statement on line 4 to `math.pi * radius **2`\n</bug_fixes>\n<unit_tests>\nimport math\nassert math.isclose(area_circle(1.0), 3.141, abs_tol=0.001)\nassert math.isclose(area_circle(2.5), 19.634, abs_tol=0.001)\nassert math.isclose(area_circle(3.6), 40.715, abs_tol=0.001)\nassert math.isclose(area_circle(4.1), 52.810, abs_tol=0.001)\nassert math.isclose(area_circle(7.0), 153.938, abs_tol=0.001)\nassert math.isclose(area_circle(-2.0), 0, abs_tol=0.001)\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm stuck!""}, {'role': 'assistant', 'content': 'Okay, do you have any ideas what the problem is?', 'alt': ['Are any of the test cases passing?', 'Recheck the instructions, do you think anything is missing?']}, {'role': 'user', 'content': ""No, I don't know what's wrong."", 'alt': ['The first test case is passing, but the second one is failing.']}, {'role': 'assistant', 'content': ""Okay, let's start by looking at the test cases, does the one on line 8 pass?"", 'alt': ['Check the instructions, did you skip any steps?', 'What exactly is this function designed to do?']}, {'role': 'user', 'content': 'Yes, the first test case passes, but the second one fails.'}, {'role': 'assistant', 'content': ""Okay, the code is running, so let's start by looking at your function. Which line do you do your calculations on?"", 'alt': [""That's interesting, why do you think the first test case is passing?"", 'What is the radius of the circle in the first test case that is passing?', 'What is the radius of the circle in the first test case that is failing?', 'Look at the if-statement on line 3, do you see any problems with it?']}, {'role': 'user', 'content': 'I calculate the area on line 5.'}, {'role': 'assistant', 'content': 'Look carefully at that line, can you tell me exactly what the code there does?', 'alt': [""First, let's make sure that the radius we are inputting is okay, do you see any problems on line 3 with the if-statement?"", 'What is the formula for calculating the area of a circle?', 'What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Look carefully at that line, can you tell me exactly what the code there is supposed to do?']}, {'role': 'user', 'content': ""That's where the area of the circle is calculated.""}, {'role': 'assistant', 'content': ""What's the formula for calculating that?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': 'Pi times the radius of the circle squared.', 'alt': [""Oh! I'm not squaring the radius, I'm multiplying it times itself!""]}, {'role': 'assistant', 'content': ""Very good, so let's check that part, do you have Pi in the line?"", 'alt': ['What is the python operator for raising one value to the power of another?', 'What is the python operator for multiplying two numbers?', 'Walk me through that line, what does the first variable represent?']}, {'role': 'user', 'content': ""Yes, that's the math.pi part.""}, {'role': 'assistant', 'content': 'Very good, and do you have the radius in there?', 'alt': ['What do you multiply pi by?', 'Are you multiplying pi by the correct value?']}, {'role': 'user', 'content': ""Yes, that's the radius variable."", 'alt': [""I'm not squaring it!""]}, {'role': 'assistant', 'content': 'What are you supposed to do with the radius?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?', 'How do you square a variable?']}, {'role': 'user', 'content': ""I'm supposed to square it.""}, {'role': 'assistant', 'content': 'How do you square a number in Python?', 'alt': ['What is the python operator for raising one value to the power of another?', 'Did you square the radius?']}, {'role': 'user', 'content': ""It's ** with a 2."", 'alt': [""I'm raising it to itself, not squaring it!""]}, {'role': 'assistant', 'content': 'Look at that line again, are you squaring the value?'}, {'role': 'user', 'content': ""No! I'm raising it to itself. I'll fix it.\n```python\n1. import math\n2.def area_circle(radius):\n3.    if radius < 0:\n4.        return 0\n5.    return math.pi * radius ** 2\n```""}, {'role': 'assistant', 'content': 'Does it run correctly now?'}, {'role': 'user', 'content': ""Yes! It's passing all the test cases! Thanks!""}]}"
+"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm stuck.
+Assistant: Okay, let's look at the code. Tell me about what happens on line 2?
+	<alt>Okay, let's go over the code. Does the first test case pass?
+	<alt>Where do you think the problem is?
+	<alt>Have you completed all parts of the instructions?
+User: Line 2 makes an empty list that we are going to fill later.
+Assistant: Yes, now let's move on to the first part of the loop. What happens on line 3?
+	<alt>Where do you think the problem is?
+	<alt>Do you see any problems with line 2?
+User: Line 3 makes a for loop.
+Assistant: What is the variable name for the iterator made on line 3?
+	<alt>What controls the loop?
+	<alt>How many times does the loop iterate?
+	<alt>What is the role of range on line 3?
+User: The iterator is named i.
+Assistant: What value does i start on, and what value does it stop on?
+	<alt>What determines when that loop ends?
+	<alt>How many times does it iterate?
+	<alt>What is range for?
+User: i is supposed to start at 0 and end at the length of the list.
+Assistant: Look at range, does i start and stop where it should?
+	<alt>How many times does it iterate?
+	<alt>What determines that the loop runs the right number of times?
+User: Yes, that part looks right.
+Assistant: Let's check the second loop next. Where does it start?
+User: The loop starts on line 4.
+Assistant: What iterator is made on that line?
+	<alt>How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+User: We make j on that line.
+Assistant: How many times should that loop iterate?
+	<alt>Where in the array list should we start for the second term?
+	<alt>Should we go through the whole array list for the second term in the combination?
+	<alt>What part of the code on that line controls the iteration of the loop?
+User: It should iterate once for every item in `list_c`.
+	<alt>Oh! It's starting at i not at 0!
+Assistant: What value should it start at to iterate once for every item in list_c?
+	<alt>What part of the code on that line controls the iteration of the loop?
+	<alt>Where in the array list should we start for the second term?
+User: It should start at the beginning of the list, at 0.
+Assistant: What piece of the code would control that?
+User: The values inside of range. Oh! I need to make it start at 0 not at i!
+<code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(0,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</code>
+Assistant: Great! Now let's run the code and see if it works.
+User: It works! Thank you!
+</dialogue>","Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```","def get_combinations(list_c):
+   ans=[]
+   for i in range(0,len(list_c)):
+       for j in range(i,len(list_c)):
+           ans.append(list_c[j]+list_c[i])
+   return ans","On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it.","On line 4, change the for loop to `for j in range(len(list_c))`.","assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']",69_81_get_combinations,"<problem>
+Write a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.
+
+## Example Cases:
+```
+get_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']
+get_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+get_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+```
+</problem>
+<bug_code>
+1. def get_combinations(list_c):
+2.    ans=[]
+3.    for i in range(0,len(list_c)):
+4.        for j in range(i,len(list_c)):
+5.            ans.append(list_c[j]+list_c[i])
+6.    return ans
+</bug_code>
+<bug_desc>
+On line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. 
+</bug_desc>
+<bug_fixes>
+On line 4, change the for loop to `for j in range(len(list_c))`.
+
+</bug_fixes>
+<unit_tests>
+assert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']
+assert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']
+assert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']
+</unit_tests>
+","{'system': ""<problem>\nWrite a Python function called `get_combinations(my_list: list(str)) -> list(str)` that takes a list of distinct characters as a parameter, and returns a list containing all of the 2-letter combinations of said characters. The ordering of the elements in the list does not matter, so long as all of the 2-letter combinations are contained within the list.\n\n## Example Cases:\n```\nget_combinations(['a', 'b']) => ['aa', 'ba', 'ab', 'bb']\nget_combinations(['a', 'b', 'c']) => ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nget_combinations(['ta', 'er', 'c']) => ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n```\n</problem>\n<bug_code>\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(i,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n</bug_code>\n<bug_desc>\nOn line 4, the second for loop starts at `i` rather than at `0`, so it is missing combinations of the i-th character with characters that precede it. \n</bug_desc>\n<bug_fixes>\nOn line 4, change the for loop to `for j in range(len(list_c))`.\n\n</bug_fixes>\n<unit_tests>\nassert get_combinations(['a', 'b']) == ['aa', 'ba', 'ab', 'bb']\nassert get_combinations(['a', 'b', 'c']) == ['aa', 'ba', 'ca', 'ab', 'bb', 'cb', 'ac', 'bc', 'cc']\nassert get_combinations(['ta', 'er', 'c']) == ['tata', 'erta', 'cta', 'taer', 'erer', 'cer', 'tac', 'erc', 'cc']\n</unit_tests>\n<stu_desc>\n\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Help! I'm stuck.""}, {'role': 'assistant', 'content': ""Okay, let's look at the code. Tell me about what happens on line 2?"", 'alt': [""Okay, let's go over the code. Does the first test case pass?"", 'Where do you think the problem is?', 'Have you completed all parts of the instructions?']}, {'role': 'user', 'content': 'Line 2 makes an empty list that we are going to fill later.'}, {'role': 'assistant', 'content': ""Yes, now let's move on to the first part of the loop. What happens on line 3?"", 'alt': ['Where do you think the problem is?', 'Do you see any problems with line 2?']}, {'role': 'user', 'content': 'Line 3 makes a for loop.'}, {'role': 'assistant', 'content': 'What is the variable name for the iterator made on line 3?', 'alt': ['What controls the loop?', 'How many times does the loop iterate?', 'What is the role of range on line 3?']}, {'role': 'user', 'content': 'The iterator is named i.'}, {'role': 'assistant', 'content': 'What value does i start on, and what value does it stop on?', 'alt': ['What determines when that loop ends?', 'How many times does it iterate?', 'What is range for?']}, {'role': 'user', 'content': 'i is supposed to start at 0 and end at the length of the list.'}, {'role': 'assistant', 'content': 'Look at range, does i start and stop where it should?', 'alt': ['How many times does it iterate?', 'What determines that the loop runs the right number of times?']}, {'role': 'user', 'content': 'Yes, that part looks right.'}, {'role': 'assistant', 'content': ""Let's check the second loop next. Where does it start?""}, {'role': 'user', 'content': 'The loop starts on line 4.'}, {'role': 'assistant', 'content': 'What iterator is made on that line?', 'alt': ['How many times should that loop iterate?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'We make j on that line.'}, {'role': 'assistant', 'content': 'How many times should that loop iterate?', 'alt': ['Where in the array list should we start for the second term?', 'Should we go through the whole array list for the second term in the combination?', 'What part of the code on that line controls the iteration of the loop?']}, {'role': 'user', 'content': 'It should iterate once for every item in `list_c`.', 'alt': [""Oh! It's starting at i not at 0!""]}, {'role': 'assistant', 'content': 'What value should it start at to iterate once for every item in list_c?', 'alt': ['What part of the code on that line controls the iteration of the loop?', 'Where in the array list should we start for the second term?']}, {'role': 'user', 'content': 'It should start at the beginning of the list, at 0.'}, {'role': 'assistant', 'content': 'What piece of the code would control that?'}, {'role': 'user', 'content': 'The values inside of range. Oh! I need to make it start at 0 not at i!\n```python\n1. def get_combinations(list_c):\n2.    ans=[]\n3.    for i in range(0,len(list_c)):\n4.        for j in range(0,len(list_c)):\n5.            ans.append(list_c[j]+list_c[i])\n6.    return ans\n```'}, {'role': 'assistant', 'content': ""Great! Now let's run the code and see if it works.""}, {'role': 'user', 'content': 'It works! Thank you!'}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm really stuck!
+Assistant: Let me help, do you have any idea what's wrong?
+	<alt>What test cases are passing?
+	<alt>Have you read the instructions and made sure you are doing everything?
+	<alt>Where do you think the problem is?
+User: I don't know. None of the test cases are passing.
+Assistant: Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?
+	<alt>Let's start by checking the math, what numbers do we start with?
+	<alt>How should the calculation work?
+	<alt>Could we add some print statements to check the math?
+User: That's where I set up the variables.
+Assistant: Okay, let's check the loop now, what is it for?
+User: That's where we calculate the change over all the years.
+Assistant: So what happens on line 7?
+	<alt>How do we decide when we want to stop looping?
+	<alt>Can you explain the calculation on line 8?
+	<alt>What is the purpose of line 9?
+User: Line 7 starts the loop, and sets it to run until the fee goes over the target.
+Assistant: Okay, so now let's check on line 8, what does that line do?
+	<alt>What is the purpose of line 9?
+	<alt>Does anything look incorrect with line 7?
+User: That's where we do the calculation.
+Assistant: What is the purpose of line 9?
+	<alt>What is the role of ""years"" in line 8?
+	<alt>Where does ""current_fee"" come from in line 8?
+	<alt>Could we add a print statement here to check the figures?
+User: It increments the number of years.
+Assistant: So what value would years have the first time the loop iterates?
+	<alt>What is the value of years in the calculation on line 8 the first time the loop is run?
+	<alt>Should we be incrementing years after we do the calculation?
+User: Years would start at 0.
+	<alt>I need to change that, we would calculate at the end of year 1, not year 0!
+Assistant: When would we calculate interest?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: At the end of a year.
+Assistant: When would we want to calculate the number of years?
+	<alt>Should we be incrementing years before or after we do our calculation?
+User: It's off by 1, I should be incrementing first!
+Assistant: Make that change and try running it. What happens?
+<code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        years += 1
+9.        total_fee = current_fee*(1.015**years)
+10.
+11.    return years
+</code>
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+
+   current_fee = 623.00
+   years = 0
+   total_fee = current_fee
+
+   while total_fee < target_amount:
+       total_fee = current_fee*(1.015**years)
+       years += 1
+
+   return years","On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.",Move line 9 to be above line 8 and within the while loop.,"assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_78_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.
+3.    current_fee = 623.00
+4.    years = 0
+5.    total_fee = current_fee
+6.
+7.    while total_fee < target_amount:
+8.        total_fee = current_fee*(1.015**years)
+9.        years += 1
+10.
+11.    return years
+</bug_code>
+<bug_desc>
+On line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.
+</bug_desc>
+<bug_fixes>
+Move line 9 to be above line 8 and within the while loop.
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        total_fee = current_fee*(1.015**years)\n9.        years += 1\n10.\n11.    return years\n</bug_code>\n<bug_desc>\nOn line 8, the new total fee is calculated before the number of years is incremented, so the final result will be 1 greater than the correct answer.\n</bug_desc>\n<bug_fixes>\nMove line 9 to be above line 8 and within the while loop.\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm really stuck!""}, {'role': 'assistant', 'content': ""Let me help, do you have any idea what's wrong?"", 'alt': ['What test cases are passing?', 'Have you read the instructions and made sure you are doing everything?', 'Where do you think the problem is?']}, {'role': 'user', 'content': ""I don't know. None of the test cases are passing.""}, {'role': 'assistant', 'content': ""Okay, let's start with the first part of your function. What happens on lines 3, 4, and 5?"", 'alt': [""Let's start by checking the math, what numbers do we start with?"", 'How should the calculation work?', 'Could we add some print statements to check the math?']}, {'role': 'user', 'content': ""That's where I set up the variables.""}, {'role': 'assistant', 'content': ""Okay, let's check the loop now, what is it for?""}, {'role': 'user', 'content': ""That's where we calculate the change over all the years.""}, {'role': 'assistant', 'content': 'So what happens on line 7?', 'alt': ['How do we decide when we want to stop looping?', 'Can you explain the calculation on line 8?', 'What is the purpose of line 9?']}, {'role': 'user', 'content': 'Line 7 starts the loop, and sets it to run until the fee goes over the target.'}, {'role': 'assistant', 'content': ""Okay, so now let's check on line 8, what does that line do?"", 'alt': ['What is the purpose of line 9?', 'Does anything look incorrect with line 7?']}, {'role': 'user', 'content': ""That's where we do the calculation.""}, {'role': 'assistant', 'content': 'What is the purpose of line 9?', 'alt': ['What is the role of ""years"" in line 8?', 'Where does ""current_fee"" come from in line 8?', 'Could we add a print statement here to check the figures?']}, {'role': 'user', 'content': 'It increments the number of years.'}, {'role': 'assistant', 'content': 'So what value would years have the first time the loop iterates?', 'alt': ['What is the value of years in the calculation on line 8 the first time the loop is run?', 'Should we be incrementing years after we do the calculation?']}, {'role': 'user', 'content': 'Years would start at 0.', 'alt': ['I need to change that, we would calculate at the end of year 1, not year 0!']}, {'role': 'assistant', 'content': 'When would we calculate interest?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': 'At the end of a year.'}, {'role': 'assistant', 'content': 'When would we want to calculate the number of years?', 'alt': ['Should we be incrementing years before or after we do our calculation?']}, {'role': 'user', 'content': ""It's off by 1, I should be incrementing first!""}, {'role': 'assistant', 'content': 'Make that change and try running it. What happens?\n```python\n1. def get_years_until(target_amount):\n2.\n3.    current_fee = 623.00\n4.    years = 0\n5.    total_fee = current_fee\n6.\n7.    while total_fee < target_amount:\n8.        years += 1\n9.        total_fee = current_fee*(1.015**years)\n10.\n11.    return years\n```'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, where do you think the problem is?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Let's start with the first part of your function, what happens on lines 2 and 3?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I don't know.
+Assistant: Let's start with your function. What happens on lines 2 and 3?
+	<alt>Are any of test cases passing?
+	<alt>What is your function supposed to do?
+	<alt>Have you read the prompt carefully?
+	<alt>Let's start by examining your loop, what happens on line 4?
+User: I declare some variables for the starting amount and the years.
+Assistant: Very good, so let's look at the loop part now. What happens on line 4?
+	<alt>What should happen next?
+	<alt>Does your function return the correct variable?
+User: It checks if i is less than the target amount and keeps looping if that's true.
+Assistant: That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?
+	<alt>Is that what it is supposed to do?
+	<alt>What do we do on line 5?
+User: It's the current amount plus the interest rate times the current amount.
+	<alt>I don't know.
+Assistant: What line in your code would have that calculation?
+	<alt>Does that calculation match the one in your code?
+User: Line 6
+Assistant: Look carefully at that line, does it match the equation you just told me about?
+	<alt>Is there anything wrong with that line?
+	<alt>What would 623 times 0.015 be?
+User: No! It doesn't match, I forgot to add back the initial amount!
+<code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= i+0.015*i
+7.    return years
+</code>
+Assistant: Try running the code here, what happens?
+User: It works! Thanks!
+</dialogue>","The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```","def get_years_until(target_amount):
+   i=623
+   years=0
+   while i < target_amount:
+       years= years+1
+       i= 0.015*i
+   return years","On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.","On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`","assert get_years_until(624) == 1
+assert get_years_until(1000) == 32",74_77_disney_vacation_club,"<problem>
+The CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).
+
+This year, the maintenance was $623.00. If that isn't bad enough, your course director discovered that maintenance fees aren't fixed! On the contrary, it accues each year at a rate of approximately 1.5%.
+
+Write a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.
+
+## Example Cases:
+```
+get_years_until(624) => 1
+get_years_until(1000) => 32
+```
+
+</problem>
+<bug_code>
+1. def get_years_until(target_amount):
+2.    i=623
+3.    years=0
+4.    while i < target_amount:
+5.        years= years+1
+6.        i= 0.015*i
+7.    return years
+</bug_code>
+<bug_desc>
+On line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.
+</bug_desc>
+<bug_fixes>
+On line 6, replace `i= 0.015*i` with `i= i + 0.015*i`
+</bug_fixes>
+<unit_tests>
+assert get_years_until(624) == 1
+assert get_years_until(1000) == 32
+</unit_tests>
+","{'system': '<problem>\nThe CS110Z course director, unfortunately, was tricked into purchasing a Disney Vacation Club timeshare. The good news about DVC is that it lets you reserve a room at any Disney Resort for one week! The downside, however, is that members have to pay an annual ""maintenance fee"" so that the mouse can keep the property looking good (EVEN when Disney World was closed due to COVID-19 . . . yay).\n\nThis year, the maintenance was $623.00. If that isn\'t bad enough, your course director discovered that maintenance fees aren\'t fixed! On the contrary, it accues each year at a rate of approximately 1.5%.\n\nWrite a Python function called `get_years_until(target_value: float) -> int` that takes a target value as a parameter, and returns the number of years (assuming a fixed interest rate) before the maintenance fee exceeds this value.\n\n## Example Cases:\n```\nget_years_until(624) => 1\nget_years_until(1000) => 32\n```\n\n</problem>\n<bug_code>\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= 0.015*i\n7.    return years\n</bug_code>\n<bug_desc>\nOn line 6, the new fee is calculated as 1.5% of the old fee, rather than increasing by 1.5%. As a result, the loop will not terminate.\n</bug_desc>\n<bug_fixes>\nOn line 6, replace `i= 0.015*i` with `i= i + 0.015*i`\n</bug_fixes>\n<unit_tests>\nassert get_years_until(624) == 1\nassert get_years_until(1000) == 32\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help! I'm really stuck.""}, {'role': 'assistant', 'content': 'Okay, where do you think the problem is?', 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', ""Let's start with the first part of your function, what happens on lines 2 and 3?"", ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': ""I don't know.""}, {'role': 'assistant', 'content': ""Let's start with your function. What happens on lines 2 and 3?"", 'alt': ['Are any of test cases passing?', 'What is your function supposed to do?', 'Have you read the prompt carefully?', ""Let's start by examining your loop, what happens on line 4?""]}, {'role': 'user', 'content': 'I declare some variables for the starting amount and the years.'}, {'role': 'assistant', 'content': ""Very good, so let's look at the loop part now. What happens on line 4?"", 'alt': ['What should happen next?', 'Does your function return the correct variable?']}, {'role': 'user', 'content': ""It checks if i is less than the target amount and keeps looping if that's true.""}, {'role': 'assistant', 'content': ""That makes sense, let's look at the calculation part inside the loop. How do we calculate the interest amount?"", 'alt': ['Is that what it is supposed to do?', 'What do we do on line 5?']}, {'role': 'user', 'content': ""It's the current amount plus the interest rate times the current amount."", 'alt': [""I don't know.""]}, {'role': 'assistant', 'content': 'What line in your code would have that calculation?', 'alt': ['Does that calculation match the one in your code?']}, {'role': 'user', 'content': 'Line 6'}, {'role': 'assistant', 'content': 'Look carefully at that line, does it match the equation you just told me about?', 'alt': ['Is there anything wrong with that line?', 'What would 623 times 0.015 be?']}, {'role': 'user', 'content': ""No! It doesn't match, I forgot to add back the initial amount!\n```python\n1. def get_years_until(target_amount):\n2.    i=623\n3.    years=0\n4.    while i < target_amount:\n5.        years= years+1\n6.        i= i+0.015*i\n7.    return years\n```""}, {'role': 'assistant', 'content': 'Try running the code here, what happens?'}, {'role': 'user', 'content': 'It works! Thanks!'}]}"
+"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+<stu_desc>
+The student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.
+</stu_desc>
+<dialogue>
+User: Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?
+Assistant: Certainly. Can you describe what you know about the `map` function so far with an example if possible?
+	<alt>Certainly. Can you describe what your code does on line 5?
+	<alt>Certainly. Do you know what the `map` function takes in as parameters?
+User: So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.
+Assistant: Ah good explanation. When you try to run your code what do you observe in the terminal?
+	<alt>Good explanation. So what is the specific issue that you have?
+	<alt>Good explanation. Where can you learn more about the `map` function and its use?
+User: So when I try to run my code, it throws a syntax error on line 5.
+Assistant: Can you explain to me what the `def` reserved word in Python does?
+	<alt>Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?
+	<alt>It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: `def` stands for define and it creates a function in Python to be used later on in the code.
+Assistant: It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?
+User: I guess not from the looks of it. Maybe I should define my function outside of the `map` call?
+	<alt>It seems to be the case. Not really sure though what to do though.
+Assistant: Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?
+User: Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.
+	<alt>Maybe after line 4? Inside of `my_func` so that it is within scope?
+	<alt>Not really sure.
+Assistant: Sounds good. Let's try it. What do you pass into `map` now?
+User: Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf,  range(len)))
+7.    return y
+
+</code>
+Assistant: What does `len` refer to on line 4?
+User: Hmm. It refers to my variable `len` does it not?
+	<alt>Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: Where do you declare `len` in your code?
+User: I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.
+Assistant: According to the problem specification, what is the upper-bound of the randomly generated integers?
+	<alt>Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?
+User: Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.
+	<alt>Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.
+Assistant: Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?
+	<alt>Good. Where in your code would you need to pass `len` to `yOf`?
+User: I actually don't know how to do that.
+	<alt>I don't know how to do that. But I guess it would be inside the `map` function.
+	<alt>I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.
+Assistant: Can you point me to a line where you think you might want to pass a new parameter to `yOf`?
+	<alt>Do you know how many parameters `map` takes in?
+	<alt>Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.
+Assistant: Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?
+User: Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x):
+4.    return  x * 6 + rand.randint(1, len)  
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: Good. What do you observe after running this?
+	<alt>How many parameters does the function `yOf` take on now?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len]))
+7.    return y 
+
+</code>
+Assistant: What do you notice in your terminal now when you run this?
+	<alt>How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+User: I notice that it runs without any issues but it fails all the test cases. Hmm..
+Assistant: How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?
+	<alt>That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?
+User: Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.
+	<alt>Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.
+Assistant: Good. How many iterable elements are in your second iterables parameter to the `map` function?
+User: Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.
+<code>
+1. import random as rand
+2. rand.seed(42)
+3. def yOf(x, len):
+4.    return  x * 6 + rand.randint(1, len)
+5. def my_func(len):
+6.    y = list(map(yOf, range(len), [len] * len))
+7.    return y 
+
+</code>
+Assistant: Good work. Does your code pass all the tests?
+User: Yes now it does! Thank you so much for all your help! I learned a lot today!
+</dialogue>","Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```","import random as rand
+rand.seed(42)
+
+def my_func(len):
+   y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+   return y",The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.,"Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.","assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]",8_36_plot_function,"<problem>
+Write a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.
+
+## Example Cases:
+```
+my_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+my_func(7) => [4, 7, 13, 19, 26, 32, 41]
+my_func(5) => [5, 7, 17, 20, 29]
+my_func(3) => [2, 7, 14]
+my_func(1) => [1]
+```
+</problem>
+<bug_code>
+1. import random as rand
+2. rand.seed(42)
+3.
+4. def my_func(len):
+5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))
+6.    return y
+</bug_code>
+<bug_desc>
+The function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.
+</bug_desc>
+<bug_fixes>
+Replace `def yOf(x):` with `lambda x:` on line 4.
+After line 2 insert the following:
+```py
+def yOf(x, len):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.
+After line 4 insert the following:
+```py
+def yOf(x):
+    return  x * 6 + rand.randint(1, len)
+```
+Replace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.
+</bug_fixes>
+<unit_tests>
+assert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]
+assert my_func(7) == [4, 7, 13, 19, 26, 32, 41]
+assert my_func(5) == [5, 7, 17, 20, 29]
+assert my_func(3) == [2, 7, 14]
+assert my_func(1) == [1]
+</unit_tests>
+","{'system': ""<problem>\nWrite a function `my_func(len: int) -> List[int]` that generates a list of `len` integers. The element at each position 'i' in the list should be computed as `i * 6 + rand.randint(1, len)`. Before calling the function, use 42 as the seed for the random number generator by calling `rand.seed(42)`. Assume that `len` is a non-negative integer.\n\n## Example Cases:\n```\nmy_func(10) => [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nmy_func(7) => [4, 7, 13, 19, 26, 32, 41]\nmy_func(5) => [5, 7, 17, 20, 29]\nmy_func(3) => [2, 7, 14]\nmy_func(1) => [1]\n```\n</problem>\n<bug_code>\n1. import random as rand\n2. rand.seed(42)\n3.\n4. def my_func(len):\n5.    y = list(map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len)))\n6.    return y\n</bug_code>\n<bug_desc>\nThe function has a syntax error on line 4. Defining a function inside of the built-in function `map` using `def` is invalid.\n</bug_desc>\n<bug_fixes>\nReplace `def yOf(x):` with `lambda x:` on line 4.\nAfter line 2 insert the following:\n```py\ndef yOf(x, len):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len), [len] * len)` on line 4.\nAfter line 4 insert the following:\n```py\ndef yOf(x):\n    return  x * 6 + rand.randint(1, len)\n```\nReplace `map(def yOf(x):  x * 6 + rand.randint(1, len),  range(len))` with `map(yOf, range(len))`.\n</bug_fixes>\n<unit_tests>\nassert my_func(10) == [2, 7, 17, 22, 28, 33, 38, 51, 50, 64]\nassert my_func(7) == [4, 7, 13, 19, 26, 32, 41]\nassert my_func(5) == [5, 7, 17, 20, 29]\nassert my_func(3) == [2, 7, 14]\nassert my_func(1) == [1]\n</unit_tests>\n<stu_desc>\nThe student is very familiar with basic programming concepts and wants to go above and beyond by solving a problem using the `map` function which the student is still learning how to use.\n</stu_desc>"", 'messages': [{'role': 'user', 'content': ""Hey, I learned recently about the use of `map` in Python and I'm trying to use it to solve this problem. I am stuck though. Can you help me out?""}, {'role': 'assistant', 'content': 'Certainly. Can you describe what you know about the `map` function so far with an example if possible?', 'alt': ['Certainly. Can you describe what your code does on line 5?', 'Certainly. Do you know what the `map` function takes in as parameters?']}, {'role': 'user', 'content': 'So I learned that the `map` function takes in a function and an iterable. The `map` function applies the function to each element in the iterable provided and returns an iterable. In this case, I am passing `def yOf(x):  x * 6 + rand.randint(1, len)` as the function and `range(len)` as the iterable. I really think I can solve this problem with `map`.'}, {'role': 'assistant', 'content': 'Ah good explanation. When you try to run your code what do you observe in the terminal?', 'alt': ['Good explanation. So what is the specific issue that you have?', 'Good explanation. Where can you learn more about the `map` function and its use?']}, {'role': 'user', 'content': 'So when I try to run my code, it throws a syntax error on line 5.'}, {'role': 'assistant', 'content': 'Can you explain to me what the `def` reserved word in Python does?', 'alt': ['Can you describe what `def yOf(x):   x * 6  + rand.randint(1, len)` does?', ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""]}, {'role': 'user', 'content': '`def` stands for define and it creates a function in Python to be used later on in the code.'}, {'role': 'assistant', 'content': ""It looks like you are trying to define the function `yOf(x)` inside of the `map` function call. Do you think that's supported by Python syntax?""}, {'role': 'user', 'content': 'I guess not from the looks of it. Maybe I should define my function outside of the `map` call?', 'alt': ['It seems to be the case. Not really sure though what to do though.']}, {'role': 'assistant', 'content': ""Let's try defining the function `yOf(x)` before using it in `map`. Where do you think it is best to define your function?""}, {'role': 'user', 'content': 'Probably before `my_func` so on line 3. I can insert my function definition for `yOf(x)`.', 'alt': ['Maybe after line 4? Inside of `my_func` so that it is within scope?', 'Not really sure.']}, {'role': 'assistant', 'content': ""Sounds good. Let's try it. What do you pass into `map` now?""}, {'role': 'user', 'content': ""Hmm I edited my code to create my function `yOf(x)` on line 3. I think I'll pass in `yOf` to `map` since that is the function name. It seems like I get another error here saying `unsupported operand types` between an integer and a built-in function.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf,  range(len)))\n7.    return y\n```""}, {'role': 'assistant', 'content': 'What does `len` refer to on line 4?'}, {'role': 'user', 'content': 'Hmm. It refers to my variable `len` does it not?', 'alt': ['Ah. I declare `len` on line 5. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.']}, {'role': 'assistant', 'content': 'Where do you declare `len` in your code?'}, {'role': 'user', 'content': 'I declare `len` on line 5. I see it now. Since `len` on line 4 is out of scope it probably thinks that it is the Python built it function `len` that measures the length of an iterable.'}, {'role': 'assistant', 'content': 'According to the problem specification, what is the upper-bound of the randomly generated integers?', 'alt': ['Given the function call `my_func(5)`. What would you need to pass into `rand.randint` as the upper-bound on line 4?']}, {'role': 'user', 'content': 'Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`.', 'alt': ['Hm. I think it would be the value on `len` from `my_func`. Given the function call `my_func(5)` it would be `rand.randint(1, 5)`. Not really sure how I would pass `len` to the function `yOf` though.']}, {'role': 'assistant', 'content': 'Good. So now how would you pass `len` as another parameter to your function `yOf` on line 6?', 'alt': ['Good. Where in your code would you need to pass `len` to `yOf`?']}, {'role': 'user', 'content': ""I actually don't know how to do that."", 'alt': [""I don't know how to do that. But I guess it would be inside the `map` function."", 'I would probably pass it as another parameter of the `map` function and update `yOf` to take two parameters.']}, {'role': 'assistant', 'content': 'Can you point me to a line where you think you might want to pass a new parameter to `yOf`?', 'alt': ['Do you know how many parameters `map` takes in?', 'Where can you learn more about how to pass multiple parameters to a function called in `map`?']}, {'role': 'user', 'content': 'I think perhaps on line 6 where I try to apply `yOf` to all numbers from 0 to `len` using the `map` function. I would want to pass an element from `range` and `len` to each `yOf` function call.'}, {'role': 'assistant', 'content': 'Good. Where can you learn more about how to pass multiple parameters to a function called in `map`?'}, {'role': 'user', 'content': 'Ah good point. Let me check the Python documentation now. I see so I can pass multiple parameters to `map` the first is the function I want to apply, and then I can pass as many iterables as I need as parameters. Let me edit my code and try it out.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x):\n4.    return  x * 6 + rand.randint(1, len)  \n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'Good. What do you observe after running this?', 'alt': ['How many parameters does the function `yOf` take on now?', 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'Ah. I get a runtime error. `yOf` expects two parameters. Let me fix that. I need to pass in `len` also as a parameter to it.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len]))\n7.    return y \n```'}, {'role': 'assistant', 'content': 'What do you notice in your terminal now when you run this?', 'alt': ['How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?']}, {'role': 'user', 'content': 'I notice that it runs without any issues but it fails all the test cases. Hmm..'}, {'role': 'assistant', 'content': 'How many times are you calling `yOf` on line 7? How does that relate to the length of the iterables passed as parameters?', 'alt': [""That's progress. Let's add a print statement to look at what `my_func (10)` is returning. What do you observe?""]}, {'role': 'user', 'content': 'Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function.', 'alt': ['Hm. I think `yOf` is called as many times as there are iterables passed as parameters to the `map` function. Oh I see. I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.']}, {'role': 'assistant', 'content': 'Good. How many iterable elements are in your second iterables parameter to the `map` function?'}, {'role': 'user', 'content': ""Oh I get what's happening now!  I am passing in only one `len` as my second parameter so maybe `yOf` is only called once because of that.  I need to pass in an array of `len` values. That array needs to be as long as `range(len)`. I'm not entirely sure how to instantiate an array with a variable number of elements. Let me look into the Python documentation and fix that.\n```python\n1. import random as rand\n2. rand.seed(42)\n3. def yOf(x, len):\n4.    return  x * 6 + rand.randint(1, len)\n5. def my_func(len):\n6.    y = list(map(yOf, range(len), [len] * len))\n7.    return y \n```""}, {'role': 'assistant', 'content': 'Good work. Does your code pass all the tests?'}, {'role': 'user', 'content': 'Yes now it does! Thank you so much for all your help! I learned a lot today!'}]}"
+"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices.
+	<alt>I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.
+Assistant: I know we can fix this together. What are the issues you're having?
+	<alt>Can you describe your code of the method `determinant` line by line to me?
+	<alt>Can you explain how you're creating the 2x2 submatrices?
+User: Well, at first I was getting the wrong answer and now I'm getting TypeErrors. It says ""'int' object is not subscriptable"" when I'm calling the `det2d` function.
+Assistant: What are the intended inputs and outputs of the `det2d` function?
+	<alt>What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.
+	<alt>Can you describe the `det2d` function to me?
+	<alt>What does the error message `""'int' object is not subscriptable""` mean?
+	<alt>How do you know that the error is coming from the `det2d` function?
+	<alt>Which variables are getting subscripted and how do you know what the data type of those variables are?
+	<alt>Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?
+User: I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.
+Assistant: Great! Did you make the same mistake anywhere else?
+	<alt>Great! Does that also apply for `subm3` or is that calculated correctly?
+	<alt>What about the other two submatrices?
+User: I think I made a similar mistake with `subm3`. I'll change both. It works!
+<code>
+ def det2d(matrix):
+    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+def determinant(matrix):
+    subm1 = [val[1:3] for val in matrix[1:3]]
+    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]
+    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]
+    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+
+</code>
+</dialogue>","Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```","def det2d(matrix):
+   return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+
+def determinant(matrix):
+
+   subm1 = [val[1:3] for val in matrix[1:3]]
+   subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+   subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+
+   return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)","On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.","Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.","assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329",9_38_calculating_determinant,"<problem>
+Write a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.
+## Example Cases:
+```
+determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0
+determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315
+determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156
+determinant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329
+```
+</problem>
+<bug_code>
+1. def det2d(matrix):
+2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]
+3.
+4. def determinant(matrix):
+5.
+6.    subm1 = [val[1:3] for val in matrix[1:3]]
+7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]
+8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]
+9.
+10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)
+</bug_code>
+<bug_desc>
+On line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.
+</bug_desc>
+<bug_fixes>
+Change line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.
+</bug_fixes>
+<unit_tests>
+assert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0
+assert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315
+assert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156
+assert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329
+</unit_tests>
+","{'system': '<problem>\nWrite a function `determinant(matrix:List[List [int]]) -> List[List[int]]` that calculates the determinant of a 3x3 matrix.\n## Example Cases:\n```\ndeterminant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) => 0\ndeterminant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) => 315\ndeterminant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) => -156\ndeterminant([[2, -1, -8], [5,-1,-3], [-1,-9, 6]]) => 329\n```\n</problem>\n<bug_code>\n1. def det2d(matrix):\n2.    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\n3.\n4. def determinant(matrix):\n5.\n6.    subm1 = [val[1:3] for val in matrix[1:3]]\n7.    subm2 = [matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]\n8.    subm3 = [matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]\n9.\n10.    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n</bug_code>\n<bug_desc>\nOn line 7, `subm2` is created as a one dimensional array. However, when line 10 evaluates `det2d(subm2)`, it assumes that it is a two dimensional array, which raises a TypeError exception.\n</bug_desc>\n<bug_fixes>\nChange line 7 to `subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]` and change line 8 with `subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]`.\n</bug_fixes>\n<unit_tests>\nassert determinant([[1, 2, 3], [4, 5, 6], [7, 8, 9]]) == 0\nassert determinant([[4, -7, 9], [6, 0, 3], [-1, 7, 0]]) == 315\nassert determinant([[-6, 0, 5], [-8, -8, -5], [-10, 2, 8]]) == -156\nassert determinant([[2, -1, -8], [5, -1, -3], [-1, -9, 6]]) == 329\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""I'm trying to write a function to calculate the determinant of a 3x3 matrix, and it's not going well. I want to calculate the determinant using the three 2x2 submatrices."", 'alt': [""I'm trying to write a function to calculate the determinant of a 3x3 matrix using submatrices, but I'm getting a strange TypeError in my helper function.""]}, {'role': 'assistant', 'content': ""I know we can fix this together. What are the issues you're having?"", 'alt': ['Can you describe your code of the method `determinant` line by line to me?', ""Can you explain how you're creating the 2x2 submatrices?""]}, {'role': 'user', 'content': 'Well, at first I was getting the wrong answer and now I\'m getting TypeErrors. It says ""\'int\' object is not subscriptable"" when I\'m calling the `det2d` function.'}, {'role': 'assistant', 'content': 'What are the intended inputs and outputs of the `det2d` function?', 'alt': ['What are the intended inputs and outputs of the `det2d` function? You may be passing in an `int` when you intend to pass a `list`.', 'Can you describe the `det2d` function to me?', 'What does the error message `""\'int\' object is not subscriptable""` mean?', 'How do you know that the error is coming from the `det2d` function?', 'Which variables are getting subscripted and how do you know what the data type of those variables are?', ""Let's open the Python interpreter and try running `[1, 2, 3][0][0]`. What happens?""]}, {'role': 'user', 'content': ""I'm trying to pass in the submatrix, so an array of arrays. Right now I'm passing in `[matrix[1][0], matrix[1][2], matrix[2][0], matrix[2][2]]`. Oh, I see, I'm missing a set of brackets! This is just a 1D array right now.""}, {'role': 'assistant', 'content': 'Great! Did you make the same mistake anywhere else?', 'alt': ['Great! Does that also apply for `subm3` or is that calculated correctly?', 'What about the other two submatrices?']}, {'role': 'user', 'content': ""I think I made a similar mistake with `subm3`. I'll change both. It works!\n```python\n def det2d(matrix):\n    return matrix[0][0] * matrix[1][1] - matrix[0][1] * matrix[1][0]\ndef determinant(matrix):\n    subm1 = [val[1:3] for val in matrix[1:3]]\n    subm2 = [[matrix[1][0], matrix[1][2]], [matrix[2][0], matrix[2][2]]]\n    subm3 = [[matrix[1][0], matrix[1][1]], [matrix[2][0], matrix[2][1]]]\n    return matrix[0][0] * det2d(subm1) - matrix[0][1] * det2d(subm2) + matrix[0][2] * det2d(subm3)\n```""}]}"
diff --git a/src/conversation.py b/src/conversation.py
new file mode 100644
index 0000000000000000000000000000000000000000..9027756824bcd66714b96971770eef27bee40c1a
--- /dev/null
+++ b/src/conversation.py
@@ -0,0 +1,138 @@
+import re
+from typing import Dict, List, Any, Optional
+
+def parse_conversation(raw: str) -> Dict[str, Any]:
+    """
+    Parse a single conversation payload.
+    
+    - Everything before the `<dialogue>` tag becomes the system prompt.
+    - Inside <dialogue>…</dialogue>, lines starting with `User:` or `Assistant:` open a new turn.
+    - Lines starting with `<alt>` are stored as alternatives on the *current* turn, under key "alt".
+    - <code>…</code> blocks are embedded into the current turn as a fenced code block (```).
+
+    Returns:
+        {
+          "system": str,
+          "messages": [
+            {"role": "user"|"assistant", "content": str, "alt": [str, ...]?},
+            ...
+          ]
+        }
+    """
+    # 1) Split system vs dialogue
+    start = raw.find("<dialogue>")
+    if start == -1:
+        raise ValueError("No <dialogue> tag found.")
+    end = raw.find("</dialogue>", start)
+    if end == -1:
+        # If no closing tag, assume dialogue runs to the end
+        end = len(raw)
+
+    system_prompt = raw[:start].strip()
+    dialogue = raw[start + len("<dialogue>"):end].strip("\n")
+
+    # 2) Helpers for building messages
+    messages: List[Dict[str, Any]] = []
+    current_role: Optional[str] = None
+    current_lines: List[str] = []
+    current_alts: List[str] = []
+
+    def flush():
+        nonlocal current_role, current_lines, current_alts
+        if current_role is not None:
+            msg: Dict[str, Any] = {
+                "role": current_role,
+                "content": "\n".join(current_lines).strip()
+            }
+            if current_alts:
+                msg["alt"] = current_alts[:]
+            messages.append(msg)
+        current_role = None
+        current_lines = []
+        current_alts = []
+
+    # 3) Line-by-line parse of dialogue
+    i = 0
+    lines = dialogue.splitlines()
+    while i < len(lines):
+        line = lines[i]
+
+        # New speaker?
+        m_user = re.match(r'^\s*User:\s*(.*)$', line)
+        m_assistant = re.match(r'^\s*Assistant:\s*(.*)$', line)
+
+        if m_user or m_assistant:
+            # close previous turn
+            flush()
+            current_role = "user" if m_user else "assistant"
+            first_text = (m_user or m_assistant).group(1)
+            current_lines.append(first_text)
+            i += 1
+            continue
+
+        # Alternative for current turn?
+        m_alt = re.match(r'^\s*<alt>\s*(.*)$', line)
+        if m_alt:
+            # If there's no current role yet, ignore dangling <alt>
+            if current_role is not None:
+                current_alts.append(m_alt.group(1))
+            i += 1
+            continue
+
+        # Code block?
+        if "<code>" in line:
+            # Collect until </code>
+            code_content_lines: List[str] = []
+            # If there is inline content after <code>, capture only what's after the tag
+            after_open = line.split("<code>", 1)[1]
+            # If the close is on the same line
+            if "</code>" in after_open:
+                inside, after = after_open.split("</code>", 1)
+                code_content_lines.append(inside)
+                code_text = "\n".join(code_content_lines).strip("\n")
+                current_lines.append("```python\n" + code_text + "\n```")
+                # If trailing text after </code> on same line, keep it
+                if after.strip():
+                    current_lines.append(after.strip())
+                i += 1
+                continue
+            else:
+                # Multi-line code
+                code_content_lines.append(after_open)
+                i += 1
+                found_close = False
+                while i < len(lines):
+                    if "</code>" in lines[i]:
+                        before_close, after = lines[i].split("</code>", 1)
+                        code_content_lines.append(before_close)
+                        code_text = "\n".join(code_content_lines).strip("\n")
+                        current_lines.append("```python\n" + code_text + "\n```")
+                        if after.strip():
+                            current_lines.append(after.strip())
+                        found_close = True
+                        i += 1
+                        break
+                    else:
+                        code_content_lines.append(lines[i])
+                        i += 1
+                if not found_close:
+                    # No closing tag found; still append what we have as code
+                    code_text = "\n".join(code_content_lines).strip("\n")
+                    current_lines.append("```python\n" + code_text + "\n```")
+                continue
+
+        # Regular content line: attach to current turn if any
+        if current_role is not None:
+            current_lines.append(line)
+        # else ignore blank/dangling lines
+
+        i += 1
+
+    # flush last
+    flush()
+
+    return {
+        "system": system_prompt,
+        "messages": messages
+    }
+
diff --git a/src/process.py b/src/process.py
new file mode 100644
index 0000000000000000000000000000000000000000..bfb6a5a2fd7fdf8b10f68a6a444de831eff537c1
--- /dev/null
+++ b/src/process.py
@@ -0,0 +1,73 @@
+import os 
+import re
+import pandas as pd
+from argparse import ArgumentParser
+from src.conversation import parse_conversation
+
+def parse_args():
+    parser = ArgumentParser(description="Process the Socratic data.")
+    parser.add_argument("--input", type=str, 
+                        help="Input directory containing raw data.",
+                        default="data/raw/v2_sigcse")
+    return parser.parse_args()
+
+def process(data_folder):
+
+    files = os.listdir(data_folder)
+    files = sorted([f for f in files if f.endswith("socratic_dialogue.txt")], key= lambda t: t[: t.find("_")])
+    files = [os.path.join(data_folder, f) for f in files]
+    
+    dataframe = []
+    for path in files:
+        with open(path, "r") as fp:
+            info = extract_information(fp.read())
+            info["id"] = path.split("/")[-1].replace("_socratic_dialogue.txt", "")
+            dataframe.append(info)
+
+    dataframe = pd.DataFrame(dataframe)
+    # since given to the student straight away, we can ignore it
+    dataframe.bug_code = dataframe.bug_code.apply(remove_line_numbers)
+    dataframe["original_text_for_feedback"] = dataframe["original_text"].apply(lambda t: t[:t.find("<stu_desc>")])
+    dataframe["conversation"] = dataframe.original_text.apply(parse_conversation)
+
+    return dataframe
+
+def extract_information(data):
+    beacons = ["problem", "bug_code", "bug_desc", "bug_fixes", "unit_tests"]
+    information = {"original_text": data}
+    for beacon in beacons:
+        start = data.find(f"<{beacon}>") + len(f"<{beacon}>")
+        end = data.find(f"</{beacon}>")
+        information[beacon] = data[start: end].strip()
+
+    return information
+
+def remove_line_numbers(code_str: str) -> str:
+    """
+    Removes leading line numbers (e.g., '1. ', '10. ', etc.) from a string of Python code,
+    preserving indentation so the output remains executable.
+
+    Args:
+        code_str (str): Multiline string containing Python code with line numbers.
+
+    Returns:
+        str: Code with line numbers removed.
+    """
+    cleaned_lines = []
+    for line in code_str.splitlines():
+        # Match a line number at the start: digits, a dot, optional space(s)
+        cleaned_line = re.sub(r'^\d+\.\s?', '', line)
+        cleaned_lines.append(cleaned_line)
+    return "\n".join(cleaned_lines)
+
+def main():
+    args = parse_args()
+    folders = os.listdir(args.input)
+    for folder in folders:
+        data_folder_path = os.path.join(args.input, folder)
+        dataframe = process(data_folder_path)
+        dataframe.to_csv(os.path.join("./data", folder + '.csv'), index=False)
+        print(f"Processed {folder} with {len(dataframe)} entries.")
+
+if __name__ == "__main__":
+    main()
\ No newline at end of file