Datasets:
Tasks:
Text Generation
Modalities:
Text
Sub-tasks:
language-modeling
Languages:
English
Size:
100K - 1M
License:
(* | |
File: Interval.thy | |
Author: Bohua Zhan | |
*) | |
section \<open>Intervals\<close> | |
theory Interval | |
imports "Auto2_HOL.Auto2_Main" | |
begin | |
text \<open>Basic definition of intervals.\<close> | |
subsection \<open>Definition of interval\<close> | |
datatype 'a interval = Interval (low: 'a) (high: 'a) | |
setup \<open>add_simple_datatype "interval"\<close> | |
instantiation interval :: (linorder) linorder begin | |
definition int_less: "(a < b) = (low a < low b | (low a = low b \<and> high a < high b))" | |
definition int_less_eq: "(a \<le> b) = (low a < low b | (low a = low b \<and> high a \<le> high b))" | |
instance proof | |
fix x y z :: "'a interval" | |
show a: "(x < y) = (x \<le> y \<and> \<not> y \<le> x)" | |
using int_less int_less_eq by force | |
show b: "x \<le> x" | |
by (simp add: int_less_eq) | |
show c: "x \<le> y \<Longrightarrow> y \<le> z \<Longrightarrow> x \<le> z" | |
by (smt int_less_eq dual_order.trans less_trans) | |
show d: "x \<le> y \<Longrightarrow> y \<le> x \<Longrightarrow> x = y" | |
using int_less_eq a interval.expand int_less by fastforce | |
show e: "x \<le> y \<or> y \<le> x" | |
by (meson int_less_eq leI not_less_iff_gr_or_eq) | |
qed end | |
definition is_interval :: "('a::linorder) interval \<Rightarrow> bool" where [rewrite]: | |
"is_interval it \<longleftrightarrow> (low it \<le> high it)" | |
subsection \<open>Definition of interval with an index\<close> | |
datatype 'a idx_interval = IdxInterval (int: "'a interval") (idx: nat) | |
setup \<open>add_simple_datatype "idx_interval"\<close> | |
instantiation idx_interval :: (linorder) linorder begin | |
definition iint_less: "(a < b) = (int a < int b | (int a = int b \<and> idx a < idx b))" | |
definition iint_less_eq: "(a \<le> b) = (int a < int b | (int a = int b \<and> idx a \<le> idx b))" | |
instance proof | |
fix x y z :: "'a idx_interval" | |
show a: "(x < y) = (x \<le> y \<and> \<not> y \<le> x)" | |
using iint_less iint_less_eq by force | |
show b: "x \<le> x" | |
by (simp add: iint_less_eq) | |
show c: "x \<le> y \<Longrightarrow> y \<le> z \<Longrightarrow> x \<le> z" | |
by (smt iint_less_eq dual_order.trans less_trans) | |
show d: "x \<le> y \<Longrightarrow> y \<le> x \<Longrightarrow> x = y" | |
using a idx_interval.expand iint_less iint_less_eq by auto | |
show e: "x \<le> y \<or> y \<le> x" | |
by (meson iint_less_eq leI not_less_iff_gr_or_eq) | |
qed end | |
lemma interval_less_to_le_low [forward]: | |
"(a::('a::linorder idx_interval)) < b \<Longrightarrow> low (int a) \<le> low (int b)" | |
by (metis eq_iff iint_less int_less less_imp_le) | |
subsection \<open>Overlapping intervals\<close> | |
definition is_overlap :: "('a::linorder) interval \<Rightarrow> 'a interval \<Rightarrow> bool" where [rewrite]: | |
"is_overlap x y \<longleftrightarrow> (high x \<ge> low y \<and> high y \<ge> low x)" | |
definition has_overlap :: "('a::linorder) idx_interval set \<Rightarrow> 'a interval \<Rightarrow> bool" where [rewrite]: | |
"has_overlap xs y \<longleftrightarrow> (\<exists>x\<in>xs. is_overlap (int x) y)" | |
end | |