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hackercup / 2019 /round2 /grading.cpp
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2019 Problems
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// Grading
// Solution by Jacob Plachta
#define DEBUG 0
#include <algorithm>
#include <functional>
#include <numeric>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <complex>
#include <cstdlib>
#include <ctime>
#include <cstring>
#include <cassert>
#include <string>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <sstream>
using namespace std;
#define LL long long
#define LD long double
#define PR pair<int,int>
#define Fox(i,n) for (i=0; i<n; i++)
#define Fox1(i,n) for (i=1; i<=n; i++)
#define FoxI(i,a,b) for (i=a; i<=b; i++)
#define FoxR(i,n) for (i=(n)-1; i>=0; i--)
#define FoxR1(i,n) for (i=n; i>0; i--)
#define FoxRI(i,a,b) for (i=b; i>=a; i--)
#define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++)
#define Min(a,b) a=min(a,b)
#define Max(a,b) a=max(a,b)
#define Sz(s) int((s).size())
#define All(s) (s).begin(),(s).end()
#define Fill(s,v) memset(s,v,sizeof(s))
#define pb push_back
#define mp make_pair
#define x first
#define y second
template<typename T> T Abs(T x) { return(x<0 ? -x : x); }
template<typename T> T Sqr(T x) { return(x*x); }
string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); }
const int INF = (int)1e9;
const LD EPS = 1e-12;
const LD PI = acos(-1.0);
#if DEBUG
#define GETCHAR getchar
#else
#define GETCHAR getchar_unlocked
#endif
bool Read(int &x)
{
char c,r=0,n=0;
x=0;
for(;;)
{
c=GETCHAR();
if ((c<0) && (!r))
return(0);
if ((c=='-') && (!r))
n=1;
else
if ((c>='0') && (c<='9'))
x=x*10+c-'0',r=1;
else
if (r)
break;
}
if (n)
x=-x;
return(1);
}
#define LIM 302
#define LIM2 90001
int H,S,K;
char P[LIM][LIM];
// dyn[i][s][p] = min discards for at most s context switches in the first i papers in stack,
// with current paper type being p
int dyn[LIM][LIM][2];
// minD[f][s] = min total discards for at most s context switches assuming first paper type is f
int minD[2][LIM];
// ans[d] = min total context switches for at most d discards
int ans[LIM2];
int main()
{
if (DEBUG)
freopen("in.txt","r",stdin);
// vars
int T,t;
int i,j,f,s,p,d;
// testcase loop
Read(T);
Fox1(t,T)
{
// input
Read(H),Read(S),Read(K);
Fox(i,H)
scanf("%s",&P[i]);
// DP on each stack
Fill(minD,0);
Fox(f,2)
Fox(j,S)
{
Fill(dyn,60);
Fox(s,H+1)
dyn[0][s][f]=0;
Fox(i,H)
Fox(s,H+1)
Fox(p,2)
{
d=dyn[i][s][p];
int p2=P[i][j]-'A';
Min(dyn[i+1][s+(p2==p ? 0 : 1)][p2],d); // grade
Min(dyn[i+1][s][p],d+1); // discard
}
Fox(s,H+1)
minD[f][s]+=min(dyn[H][s][0],dyn[H][s][1]);
}
// compute answers
Fill(ans,60);
Fox(f,2)
Fox(s,H+1)
Min(ans[minD[f][s]],s);
Fox(d,H*S)
Min(ans[d+1],ans[d]);
// process queries
printf("Case #%d:",t);
while (K--)
{
Read(d);
printf(" %d",ans[d]+1);
}
printf("\n");
}
return(0);
}