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hackercup / 2017 /round1 /manicmoving.cpp
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2017 Problems
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// Hacker Cup 2017
// Round 1
// Manic Moving
// Jacob Plachta
#include <algorithm>
#include <functional>
#include <numeric>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <complex>
#include <cstdlib>
#include <ctime>
#include <cstring>
#include <cassert>
#include <string>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <sstream>
using namespace std;
#define LL long long
#define LD long double
#define PR pair<int,int>
#define Fox(i,n) for (i=0; i<n; i++)
#define Fox1(i,n) for (i=1; i<=n; i++)
#define FoxI(i,a,b) for (i=a; i<=b; i++)
#define FoxR(i,n) for (i=(n)-1; i>=0; i--)
#define FoxR1(i,n) for (i=n; i>0; i--)
#define FoxRI(i,a,b) for (i=b; i>=a; i--)
#define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++)
#define Min(a,b) a=min(a,b)
#define Max(a,b) a=max(a,b)
#define Sz(s) int((s).size())
#define All(s) (s).begin(),(s).end()
#define Fill(s,v) memset(s,v,sizeof(s))
#define pb push_back
#define mp make_pair
#define x first
#define y second
template<typename T> T Abs(T x) { return(x<0 ? -x : x); }
template<typename T> T Sqr(T x) { return(x*x); }
const int INF = (int)1e9;
const LD EPS = 1e-12;
const LD PI = acos(-1.0);
bool Read(int &x)
{
char c,r=0,n=0;
x=0;
for(;;)
{
c=getchar();
if ((c<0) && (!r))
return(0);
if ((c=='-') && (!r))
n=1;
else
if ((c>='0') && (c<='9'))
x=x*10+c-'0',r=1;
else
if (r)
break;
}
if (n)
x=-x;
return(1);
}
int main()
{
int T,t;
int N,M,K;
int i,j,k,d,ans;
int A[5000],B[5000];
static int dist[100][100],dyn[5001][101][2];
Read(T);
Fox1(t,T)
{
Read(N),Read(M),Read(K);
Fill(dist,60);
Fox(i,N)
dist[i][i]=0;
while (M--)
{
Read(i),Read(j),Read(k),i--,j--;
Min(dist[i][j],k);
Min(dist[j][i],k);
}
Fox(i,N)
Fox(j,N)
Fox(k,N)
Min(dist[j][k],dist[j][i]+dist[i][k]);
Fox(i,K)
Read(A[i]),Read(B[i]),A[i]--,B[i]--;
Fox(i,K)
if (max(dist[0][A[i]],dist[0][B[i]])>INF)
{
ans=-1;
goto Done;
}
Fill(dyn,60);
dyn[0][0][0]=0;
Fox(i,K)
Fox(k,2)
Fox(j,N)
if ((d=dyn[i][j][k])<INF)
if (!k) // must pick up i next
Min(dyn[i][A[i]][1],d+dist[j][A[i]]);
else // i already picked up
{
// deliver i immediately
Min(dyn[i+1][B[i]][0],d+dist[j][B[i]]);
// pick up i+1 and then deliver i
if (i<K-1)
Min(dyn[i+1][B[i]][1],d+dist[j][A[i+1]]+dist[A[i+1]][B[i]]);
}
ans=dyn[K][B[K-1]][0];
Done:;
printf("Case #%d: %d\n",t,ans);
}
return(0);
}