reverting to working version

wordle_functions.py

@@ -7,20 +7,18 @@ import pandas as pd
 
 english_alphabet = "abcdefghijklmnopqrstuvwxyz"
 
-def get_letter_counts(word_list: list, letters: str = english_alphabet, sort: str = "descending", unique: bool = False):
+def get_letter_counts(letters: str, word_list: list, sort: str = "descending"):
     """
     Given a passed str of letters and a list of words, produces a frequency distribution of all letters
 
     Parameters:
     ------
-    `word_list`: list
-        list of words (str) from which word frequencies will be counted
     `letters`: str
         a string of letters to be counted. String must only be desired letters, with no spaces. Default is local variable containing all letters of the English alphabet
+    `word_list`: list
+        list of words (str) from which word frequencies will be counted
     `sort`: str
-        if either "descending" or "ascending" are passed, returned list of tuples will be sorted accordingly, else returned dictionary will be unsorted
-    `unique`: bool
-        if True, only unique letters in a word are counted. That means that words with more unique letters are rated more highly than any words with duplicate letters
+        if either "descending" or "ascending" are passed, returned list of tuples will be sorted accoringly, else returned dictionary will be unsorted
 
     Returns:
     ------