Create app.py

app.py

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+import gradio as gr
+
+gr.Markdown("""
+The range of a projectile is the horizontal distance it travels during its motion. The horizontal displacement of a projectile at any time can be calculated using the following kinematic equation:
+
+$$x = x_0 + v_0 \cos \theta \cdot t$$
+
+where $x$ is the horizontal displacement, $x_0$ is the initial horizontal position, $v_0$ is the initial velocity, $\theta$ is the angle at which the projectile is launched, and $t$ is the time.
+
+To find the range of the projectile, we need to find the time at which it hits the ground (i.e., when its vertical displacement becomes zero). The vertical displacement of a projectile at any time can be calculated using the following kinematic equation:
+
+$$y = y_0 + v_0 \sin \theta \cdot t - \frac{1}{2}gt^2$$
+
+where $y$ is the vertical displacement, $y_0$ is the initial vertical position, $v_0$ is the initial velocity, $\theta$ is the angle at which the projectile is launched, $t$ is the time, $g$ is the acceleration due to gravity, and $t$ is the time.
+
+To find the time at which the projectile hits the ground, we can set the vertical displacement to zero and solve for $t$. This gives us the following equation:
+
+$$0 = y_0 + v_0 \sin \theta \cdot t - \frac{1}{2}gt^2$$
+
+Solving for $t$, we get:
+
+$$t = \frac{v_0 \sin \theta \pm \sqrt{v_0^2 \sin^2 \theta + 2gy_0}}{g}$$
+
+Since the projectile will hit the ground at a later time, we need to take the positive value of $t$. Substituting this value into the equation for horizontal displacement, we get the following equation for the range of the projectile:
+
+""").launch()