Question: how many atoms are there in a molecule of ca3(po4)2?
Answer: For Ca3(PO4)2 there are a total of 13 atoms in the compound. To find the number of atoms in one mole of Ca3(PO4)2 we multiply the number of each atom (for example there are two P atoms) by Avogadro's number, 6.02 x 10^23.