Question: if the empirical formula of the unknown was c3h2cl what is the molecular formula?
Answer: From empirical formula; Carbon chlorine Hydrogen 49.0% 48.2% 2.75% Divide by their molar masses, 4.08 1.35 2.75 Divide by the smallest number 3.00 1 2.03 Empirical formula is C3H2Cl Thus molecular formula is (C3H2Cl)n = 147g 73.5n = 147 n = 2 : molecular formula of unknown compound = C6H4Cl2…..