Question: how many grams of aluminum are required to produce 8.70 moles of aluminum chloride?
Answer: 1 Expert Answer Assuming the Cl2 is in excess, this means that 8.70 moles of Al are required to make 8.70 moles Al Cl3 . However, from the periodic table, it is found that one mole of Al is 26.98 g of Al. So the required mass of Al is 8.70 x 26.98 = 234.7 g.