Question: how many moles of water are produced in 2c8h18(g)+25o2(g)→16co2(g)+18h2o(g)?
Answer: Here is the balanced equation: 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) number of moles of C8H18 reacted = 6.16×10−2 mol H2O produced = 0.554 mol oxygen is the limiting reactant.