Question: how many atoms of carbon are present in 18g of glucose c6h12o6?
Answer: Molar Mass of glucose (C6H12O6)=180 grams, 1 mol glucose =180 grams glucose,from the formula we can see that 1 mol glucose contains 6 mols of carbon atom. now,18 grams of glucose will contain =(180/18) mols of glucose=0.1 mol glucose=(6*0.1 )mol carbon=0.6 mol carbon.