Question: how to find height of ball thrown up?
Answer: The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s. d = 20 m/s • 4.08 s = 81.6 m. Q: What is the maximum height reached by a ball when it is thrown upwards with a velocity of 40 meters/second?