Question: what is 5 n hcl?
Answer: N2 = Normality of dilute acid to be prepared = 5 N. V2 = Volume of dilute acid to be prepared = 250 ml. 12 x V1 = 5 x 250. Therefore 104.2 ml of concentrated acid should be taken and diluted with water to make the volume 250 ml. The resulting solution will be 5N HCl.