Question: what is the change in enthalpy when 180g of water?
Answer: A Chemistry tutor answered It will be: ? moles H2O = 180g H2O *(1mole H2O/18.01528 g) = 9.99moles H2O. Hence, the enthalpy of condensation for 180 g of water is = -40.657 kJ/9.99moles H2O = -4.069 kJ/mole.