Question: in the adjoining figure ad is a median of /aabc and the ba .show that be is also a median of /aabc?
Answer: Answer Expert Verified Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem, it bisects the third side which in this case is AC at E. Therefore, E is the mid point of AC. Hence, BE is the median of ΔABC.