Question: how much energy is required to neutralize 1500 cm cube of 0.1 normal hcl?
Answer: Gram equivalent = w/E = N×V. Here w is weight of compound(NaOH), E is equivalent weight of compound(NaOH), N is normality of solution and V is volume of solution in litres. So, 0.15 = w/40 (equivalent weight of NaOH is 40). So 60 gram of NaOH is required to neutralize 1500 cm^3 of 0.1N HCl.