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/*
最長公共子序列
時間複雜度: O(N^2)
*/
#include <algorithm>
#include <iostream>
#include <vector>
using namespace std;
int main() {
cin.tie(0);
ios_base::sync_with_stdio(0);
int n, m, case_n = 1;
while (cin >> n >> m && (n || m)) {
++m;
++n;
vector<int> tower_1(n, 0), tower_2(m, 0);
vector<vector<int>> dp(n, vector<int>(m, 0));
for (int i = 1; i < n; i++)
cin >> tower_1[i];
for (int i = 1; i < m; i++)
cin >> tower_2[i];
for (int i = 1; i < n; i++) {
for (int j = 1; j < m; j++) {
if (tower_1[i] == tower_2[j])
dp[i][j] = dp[i - 1][j - 1] + 1;
else
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
}
}
cout << "Twin Towers #" << case_n++ << "\nNumber of Tiles : " << dp.back().back() << "\n\n";
}
}