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#include<vector> |
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#include<stack> |
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#include<set> |
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#include<map> |
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#include<queue> |
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#include<deque> |
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#include<string> |
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#include<list> |
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#include<iostream> |
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#include<algorithm> |
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#include<cstring> |
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#include<cassert> |
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#include<cstdlib> |
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#include<cstdio> |
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#include<cmath> |
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#include<sstream> |
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#define maX(a,b) ( (a) > (b) ? (a) : (b)) |
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#define miN(a,b) ( (a) < (b) ? (a) : (b)) |
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#define FOR(i,a,b) for(int i=a;i<b;i++) |
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#define FORs(i,a,b) for(int i=a;i>=b;i--) |
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#define fill(a,v) memset(a,v,sizeof a) |
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#define abS(x) ((x)<0?-(x):(x)) |
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#define mP make_pair |
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#define pB push_back |
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#define error(x) cout << #x << " : " << (x) << endl |
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#define ITER(i,a) for( typeof(a.begin()) i=a.begin();i!=a.end();i++) |
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#define mod 1000000007 |
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#define MAXN 1000010 |
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#define MP make_pair |
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#define INF mod |
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#define s(n) scanf("%d",&n) |
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#define sc(n) scanf("%c",&n) |
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#define sl(n) scanf("%lld",&n) |
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#define sf(n) scanf("%lf",&n) |
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#define ss(n) scanf("%s",n) |
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#define p(n) printf("%d",n) |
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#define pc(n) printf("%c",n) |
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#define pl(n) printf("%lld",n) |
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#define pf(n) printf("%lf",n) |
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#define ps(n) printf("%s",n) |
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using namespace std; |
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typedef long long LL; |
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typedef pair<int,int> PII; |
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typedef pair<LL,LL> PLL; |
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typedef pair<int,PII> TRI; |
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typedef vector<int> VI; |
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typedef vector<LL> VL; |
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typedef vector<PII> VII; |
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typedef vector<PLL> VLL; |
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typedef vector<TRI> VT; |
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typedef vector<VI> VVI; |
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typedef vector<VL> VVL; |
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typedef vector<VII> VVII; |
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typedef vector<VLL> VVLL; |
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typedef vector<VT> VVT; |
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void chekarre(int * arr,int n) |
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{ |
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cout<<"["; |
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for(int i=0;i<n;i++) |
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cout<<arr[i]<<" "; |
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cout<<"]"<<endl; |
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} |
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inline int haint() |
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{ |
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int h; |
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register char c=0; |
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while (c<33) c=getchar(); |
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h=0; |
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while (c>33) |
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{ |
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h=h*10+c-'0'; |
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c=getchar(); |
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} |
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return h; |
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} |
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int n, m ; |
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char s1[6200], s2[6200]; |
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int dp[2][6200]; |
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int main() |
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{ |
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int T; |
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s(T); |
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while(T--) |
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{ |
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ss(s1); |
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n=strlen(s1); |
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memset(dp,0,sizeof(dp)); |
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FOR(i,0,n) |
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s2[i]=s1[n-i-1]; |
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if(s1[0]==s2[0]) |
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dp[0][0]=1; |
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FOR(i,1,n) |
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{ |
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if(s1[0]==s2[i]) |
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dp[0][i]=1; |
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else |
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dp[0][i]=dp[0][i-1]; |
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} |
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FOR(i,1,n) |
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{ |
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if(s1[i]==s2[0]) |
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dp[i%2][0]=1; |
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FOR(j,1,n) |
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{ |
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if(s1[i]==s2[j]) |
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{ |
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dp[i%2][j]=1+dp[(i-1)%2][(j-1)]; |
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} |
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else |
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{ |
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dp[i%2][j]=maX(dp[(i-1)%2][j], maX(dp[i%2][(j-1)], dp[(i-1)%2][(j-1)])); |
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} |
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} |
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} |
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p(n-maX(dp[0][n-1], dp[1][n-1]));printf("\n"); |
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} |
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return 0; |
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} |
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