Talk:Busemann biplane

message: "successfully tested for ammunition" 
wtf does this mean--Dj245 (talk) 17:14, 14 December 2007 (UTC)
replies: text: An educated guess--a significant source of sound for some firearms is actually the sonic boom created by the bullet. If you made a bullet that could maintain a Busemann Biplane form in flight, however, there would be no telltale crack.  Coupled with a good suppressor, I can definitely see how the military would be interested in this sort of thing. --Lode Runner (talk) 09:30, 15 December 2007 (UTC)
replies: text: There is a paper kicking around on the net somewhere somebody tested biplane based ammunition and tried to persuade the military to buy it. It had maybe 20% extra range or something because it wasn't wasting energy on the shock; but range isn't as useful as you would expect, since it's even harder to aim when you're going further and stuff like that. I'm not aware, and can't recall any mention of it being extra quiet, but it would be expected to be I suppose.- (User) WolfKeeper (Talk) 10:11, 15 December 2007 (UTC)
replies: text: Of course, the lack of a sonic boom would be good for range too.  I forgot.  Given the push towards unmanned and computer-assisted attack vehicles (I have it on good authority that in the latest attack helicopter systems, it's pretty much "point 'n' click" and the computer does the shooting for you), I bet that 20% will come in handy some day. Also, in addition to added range, the bullets should be going faster when they hit their target (at *any* range), thus resulting in more penetration. Faster bullets should mean a flatter trajectory, too, which should make aiming easier at medium ranges. --22:29, 15 December 2007 (UTC)
thread_title: tested for ammunition

message: About the diagram. The waves emanating from the wedge peak and its reflection at the symmetry plane, they are expansion waves, not shock waves. Butakun 12:00, 31 December 2006 (UTC)
replies: text: No, expansion fans are not discontinuities (though often depicted as a fan of discrete lines) and isentropic, unlike shock waves. Across shock waves, static pressure rises and total pressure decreases (thus increase in entropy), whereas across expansion waves, static pressure decreases and total pressure remains constant.--Butakun 00:52, 1 January 2007 (UTC)

text: 1) The first part I agree with. What I was referring to was not the leading edge shocks. However, as for the second part, I do not agree completely. If the throat area is sufficient enough to swallow the mass flow, the oblique L.E. shocks will be weak shocks, meaning that the shock angle will decrease as Mach number increases. 3) I agree also, but I used the word "shock" simply to mean compression discontinuity, but yes, Mach wave is an infinitesimally weak shock of which Prandtl-Meyer fan is made.--Butakun 11:37, 30 January 2007 (UTC)
replies: text:  I agree, I meant to say slow for as Mach number decreases, the shock will become more normal to the flow. I have made the appropriate corrections. Thank you. Myth  (Talk) 12:05, 30 January 2007 (UTC)
thread_title:  About the diagram 

message: http://web.mit.edu/press/2012/biplane-to-break-the-sound-barrier.html -- watch to see if the article needs to be updated soon. :-) --SarekOfVulcan (talk) 19:37, 19 March 2012 (UTC)
thread_title:  MIT figured it out? 

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thread_title:  External links modified