Talk:Center of percussion

message: I think 'centre of percussion' should redirect here but I do not know how to do it 130.88.168.247 (talk) 18:00, 14 January 2008 (UTC)
thread_title:  Redirect 

message: The derivation presented here and in reference 1 differ in their use of the moment of inertia. In this article, I is about the CoG, while in the reference I is about the pivot. Both derivations are correct as long as they are not mixed together. Turidoth (talk) 00:08, 4 August 2008 (UTC)
thread_title:  Warning 

message: IMHO I think that the formula should have been soved for A, not for b as b is already given as the point of impact of F. Huibc
--84.197.88.254 (talk) 14:42, 30 January 2009 (UTC)
thread_title:  A or b ? 

message: So would I be right in thinking that, if a racket (say) which is positioned vertically in outer space and under zero gravity were hit normally at the Center of Percussion, the resulting motion of the racket would be purely rotational (ie no translational motion) and the racket would rotate around an axis at the handle of the racket only?
Thanks  —Preceding unsigned comment added by 91.111.20.10 (talk) 13:27, 18 April 2009 (UTC)
replies: text: Only partly right.  It is not possible to produce purely rotational continuous motion by a single impact on a free object (regardless of whether it is in outer space or under gravity), but the racket would rotate about an axis through the handle initially, causing the centre of mass to start moving in the direction of the impact as the racket continued to rotate with constant angular speed.  It is usual to regard this motion as linear motion of the centre of mass plus rotation about the centre of mass, but it amounts to the same thing.To produce pure rotation, you would have to confine the racket with an axis through the handle.  Initially, at the instant of the blow, there would be no force at all at the axis, but a force would appear as the racket rotated, preventing linear motion of the handle and constraining the motion to pure rotation.  The same applies to a racket suspended by its handle under gravity.  If it is hit at its centre of percussion, there is no horizontal force at the axis initially, but one gradually builds up to keep the racket moving in a vertical circle.  Dbfirs 09:53, 19 April 2009 (UTC)

text: Thank you - most helpful.  —Preceding unsigned comment added by 91.111.20.10 (talk) 21:20, 19 April 2009 (UTC)
thread_title:  impact under zero gravity 

message: If pivot point seat at COG of rigid object, can we still find a center of percussion on it.
:No, if the pivot is at the centre of gravity, then any impact will cause a reactive force at the pivot.  Dbfirs 12:26, 13 October 2014 (UTC)
thread_title:  Pivot point at COG 

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thread_title:  External links modified