lflage/wiki-talks huggingface dataset:
Talk:Peter Dolving

message: I'm aware of Dolving's online activities, but to state that he has "incited the wrath" of metal fans through his frequent "ranting" and "soul-searching" sounds very POV to me. Arkyopterix 21:08, 16 March 2007 (UTC)
thread_title: Non POV

message: Ok to say "Dolving then re-joined his former Swedish heavy metal band The Haunted, supporting himself by drawing fetish art and working as a carpenter." without there actually being a previous mention of The Haunted is... stupid. The article needs to actually go in to some back history of The Haunted and mention why Dolving left The Haunted in the first place. The article is just missing too much information.  —Preceding unsigned comment added by 12.156.166.47 (talk) 20:49, 13 August 2008 (UTC)
thread_title:  Very Barebones
Talk:Federal government

message: Immaterial quasi-vandalism removed from talk page. Famspear 16:09, 22 March 2007 (UTC)
thread_title: 2007 to early 2009 Talk page itmes

message: I have removed three individual vandalism edits to this talk page that were made since February of this year. N2e (talk) 14:08, 1 November 2009 (UTC)
thread_title: Vandalism cleanup

message: I note that several of the existing wikilinks point to the "Politics of ..." articles for various countries rather than the "Government of ..." or the "Federal government of ..."  While this may be necessary in some cases (where no better article exists), it is not in all cases.  For example, Government of Russia exists so it would appear to be a better link than the current Politics of Russia.  What do others think?  Cheers, N2e (talk) 14:12, 1 November 2009 (UTC)
replies: text: That would definitely be the right course for clicks to take. I altered the links, as I don't see anybody disputing that. Malaysia, Mexico and Germany still don't appear to have separate articles for their respective federal governments, and "Government of ..." redirects to "Politics of..." in each case. But the Swiss Council and the Russian Government articles are adequate. Night w (talk) 03:45, 2 November 2009 (UTC)
thread_title:  Wikilink cleanup
Talk:Red Hills (Kansas)

message: Am I reading this right that this would be the region in which you find Wichita? ----Steve 20:38, 2 March 2007 (UTC)
replies: text: Wichita is on the Arkansas River, in the Great Bend Prairie, a lowland per the map on the article. These hills are southwest of Wichita. – wbm1058 (talk) 01:28, 4 April 2023 (UTC)
thread_title: Untitled
Talk:Palindromic polynomial

message: I've beefed up the examples and re-arranged slightly. I'd like to see two things added:
* Factorisation techniques.
* Examples of transformation into reciprocal equations e.g. 4x^2 + 4x + 1 transformed to y^2 + 2y + 1 by writing y = 2x.  — Preceding unsigned comment added by MartinPackerIBM (talk • contribs) 07:40, 14 September 2012 (UTC)

message: While I commend the attempt to expand this article and appreciate the effort taken to do so, I am a little concerned about WP:NOR given some of the above comments. This concern is easily dismissed by providing some reliable references (and there are none at the moment). Wikipedia is not the place to publish original work, no matter how simple or easy it is. There is a little more wiggle room in mathematics articles than in WP as a whole, we allow simple examples and basic calculations that are aids to the reader in understanding concepts, but that is about it. Everything else must be referenced and that includes the list of properties here (with or without proofs). Unreferenced material can be removed by any editor with or without notice or explanation, and there are certainly editors that will do that. Bill Cherowitzo  (talk) 17:07, 15 September 2012 (UTC)
thread_title:  Be careful about OR violation
Talk:Primitive permutation group

message: The article defines a group to be primitive if it preserves no nontrivial partitions. In the last paragraph of the opening section, it is claimed that primitive permutation groups are transitive. A two element set has only trivial partitions. Therefore the action of the trivial group preserves no nontrivial partitions. However, this action is intransitive. So I think to get at common usage, transitivity needs to be built into the definition of primitivity. I'll try to reword the definition accordingly. Michael Kinyon (talk) 21:08, 7 December 2010 (UTC)

message: Insipid numbers on OEIS https://oeis.org/A102842  — Preceding unsigned comment added by 83.29.28.131 (talk) 11:52, 2 October 2021 (UTC)
thread_title:  Would some kind soul add a section about insipid numbers?
Talk:Prüfer group

message: The article gives this definition : "the Prüfer p-group or the p-quasicyclic group or p∞-group, Z(p∞), for a prime number p is the unique torsion group in which every element has p pth roots." I think this definition is wrong. The multiplicative group of all complex roots of unity is a torsion group in which every element has exactly p pth roots, but this group is not isomorphic to the Prüfer p-group. Marvoir (talk) 08:46, 1 December 2010 (UTC)
replies: text: Yes, you're right. I changed "torsion group" to "p-group".82.35.82.162 (talk) 01:52, 23 January 2011 (UTC)
replies: text: Yes, you have to eliminate the possibility of elements whose order is not a power of p. Good catch. -Krasnoludek (talk) 14:49, 11 February 2011 (UTC)
thread_title:  Wrong definition ? 

message: The article reports "As both the integers \mathbb{Z} and the p-adic rationals \mathbb{Z}[1/p] are rings in addition to groups, the quotient ring \mathbb{Z}(p^\infty) = \mathbb{Z}[1/p]/\mathbb{Z} is the Prüfer p-group with a ring structure, or the Prüfer p-ring. "
First things first, no reference is given and cannot be found (there is a notion of Prüfer ring/domain, but that's a different thing). About the quote:
1) The quotient \mathbb{Z}(p^\infty) = \mathbb{Z}[1/p]/\mathbb{Z} is not a quotient ring because \mathbb{Z} is not an ideal. However, it makes sense as a quotient of additive groups (and it is the Prüfer p-group, indeed).
2) The Prüfer p-group does not admit a ring structure in either cases in which the group multiplication plays the rôle of ring addition (it cannot be of finite characteristic since every element has arbitrarily large additive order, but every element is of finite additive order, hence none can be the ring unit) or multiplication (see https://math.stackexchange.com/a/93411). 06:37, 21 April 2020‎ 188.152.82.187
:The stack exchange post just says that this cannot be a ring with identity. It can still be a ring, and \mathbb{Z}[1/p]/\mathbb{Z} with its usual multiplication seems to satisfy the ring axioms.  — Preceding unsigned comment added by 24.250.184.73 (talk) 18:28, 21 October 2020 (UTC)
thread_title:  The Prüfer p-group cannot be a ring
Talk:State Library of Kansas

message: Prior content in this  duplicated one or more previously published sources. The material was copied from: http://kslib.info/239/History and other pages of that website. Copied or closely paraphrased material has been rewritten or removed and must not be restored, unless it is duly released under a compatible license. (For more information, please see "using copyrighted works from others" if you are not the copyright holder of this material, or "donating copyrighted materials" if you are.)
For legal reasons, we cannot accept copyrighted text or images borrowed from other web sites or published material; such additions will be deleted. Contributors may use copyrighted publications as a source of information, and, if allowed under fair use, may copy sentences and phrases, provided they are included in quotation marks and referenced properly. The material may also be rewritten, providing it does not infringe on the copyright of the original or plagiarize from that source. Therefore, such paraphrased portions must provide their source. Please see our guideline on non-free text for how to properly implement limited quotations of copyrighted text. Wikipedia takes copyright violations very seriously, and persistent violators will be blocked from editing. While we appreciate contributions, we must require all contributors to understand and comply with these policies. Thank you.  Justlettersandnumbers (talk) 22:52, 9 November 2015 (UTC)
thread_title:  Copyright problem removed 

message: permissions pending Bbqsauceasaurus (talk) 14:05, 20 January 2023 (UTC)
thread_title:  Copyright permissions
Talk:Pseudo algebraically closed field

message: I'm afraid the new lead does not make sense. The Nullstellensatz does not hold for any non-algebraically closed field. In fact, already the weak Nullstellensatz for univariate polynomials implies that the field is algebraically closed: if f is a non-constant polynomial, then I = f K[x] is a proper ideal in K[x], hence V(I) is nonempty, i.e., f has a root. — Emil J. 13:35, 26 November 2009 (UTC)

message: The comment (consequence of Riemann Hypothesis for function fields) (twice) seems to be nonsense.  I have removed it.  Lichfielder (talk) 08:49, 20 September 2012 (UTC)
replies: text: It appears to be correct, at least as far as the ultraproduct example is concerned.  See Fried & Jarden (2004) p.217.  Deltahedron (talk) 18:32, 21 September 2012 (UTC)
thread_title:  Examples 

message: I don't quite follow the statement If R is a finitely generated integral domain over K with quotient field which is regular over K, then there exist a homomorphism h:R\to K such that h(a)=a for each a\in K.  The field K = C is algebraically closed and so PAC.  The field C(X) is a regular extension of C (any extension of an AC field is regular), and hence R = C(X) is a finitely generated integral domain with itself as field of fractions.  But there is no C-homomorphism of C(X) to C.  Is there a reference for this claim?  Deltahedron (talk) 07:30, 13 November 2012 (UTC)
replies: text: While I know nothing about the claim or any references, C(X) is not finitely generated over C as a ring. C[X] is, but then there are plenty of evaluation homomorphisms.—Emil J. 11:39, 13 November 2012 (UTC)
replies: text: Yes, my mistake — finitely generated as a field but not as a ring.  But a reference would still be good.  Deltahedron (talk) 18:14, 13 November 2012 (UTC)
thread_title:  Formulation
Talk:Heap (mathematics)

message: Groud is also an african artist see Gilbert G. Groud so "Groud" not point directly to the mathematical heap but to a page who differs the two. How do i do this?
Ourima 10:16, 17 March 2007 (UTC)
thread_title:  Groud is not only a heap 

message: Suggestion: for the group operation: add x^-1 := [e,x,e]
- Alexey (dobriak@yahoo.com)  —Preceding unsigned comment added by 129.34.20.23 (talk) 19:06, 5 October 2007 (UTC)
thread_title:  Suggestion: for the group operation: add "x^-1 := [e,x,e]" 

message: Suggestion #2: add a link to the article "http://en.wikipedia.org/wiki/Principal_homogeneous_space"
(it gives a definition of G-torsor). 
- Alexey (dobriak@yahoo.com)  —Preceding unsigned comment added by 129.34.20.23 (talk) 21:36, 5 October 2007 (UTC)
thread_title:  Suggestion #2: add a link to the article "http://en.wikipedia.org/wiki/Principal_homogeneous_space" 

message: The para-associative law is quoted as
::\forall \ a,b,c,d,e \in H \ \ \ \ [[a,b,c],d,e] = [a,[d,c,b],e] = [a,b,[c,d,e]]
Then later we have 
* A pseudoheap or pseudogroud satisfies the partial para-associative condition
::[[a,b,c],d,e] = [a,b,[c,d,e]]
Am I missing something, or is every "pseudoheap" in fact a heap? That is, doesn't the identity law and partial para-associative condition imply the full para-associative law? Or does anyone care to give an example of a pseudoheap that isn't a heap? --99.238.163.176 (talk) 00:25, 14 April 2019 (UTC)
replies: text: See Boris Stein's review  for clarification. — Rgdboer (talk) 22:41, 24 June 2019 (UTC)
thread_title:  para-associative law / pseudoheap 

message: A section "Intuitive understanding" states the following:
:Heaps can be understood as groups with the identity element forgotten. The heap operation [a,b,c] finds the "transformation" that takes b to c, and applies it to a.
An argument or reference is necessary to support this statement. In fact, deeper in the article "Heterogeneous relations" states that a heap is more than a tweak of a group. — Rgdboer (talk) 04:56, 2 August 2020 (UTC)
replies: text: you could have raised questions first *without* deleting the section. i don't think your quote contradicts the deleted text. even so, it has no relevance for an intuitive understanding, as most math-savvy people will be familiar with groups, thus it is a good stepping stone. if you desire more precision, extend or clarify. Krisztián Pintér (talk) 17:20, 7 August 2020 (UTC)
thread_title:  Group without identity 

message: Груда means something inherently unorderly, like a pile or bunch of something. It got same root as rarely used transitive perfect verb "сгрудить" - to pile , to drop something in unorderly way, and it's intransitive form - "сгрудиться" (about a group of people) to crowd, to fill certain space. Stack supposes a somewhat orderly pile, which would be стопка.  — Preceding unsigned comment added by 83.237.190.95 (talk) 09:02, 18 March 2021 (UTC)
thread_title:  Груда doesn't mean stack
Talk:Slender group

message: The Examples section requires a lot more explanation. Specifically, there's no indication of what Q is supposed to mean.
166.137.101.169 (talk) 23:07, 25 June 2014 (UTC)
replies: text: It is the additive group of rational numbers: added now.  Deltahedron (talk) 18:35, 26 June 2014 (UTC)
thread_title:  What is Q?
Talk:Socle (mathematics)

message: A discussion of socle series/socle layers would probably be desirable at some point. --172.188.53.88 15:24, 9 August 2007 (UTC)

message: The definition of 'socle' depends on the phrase 'minimal non-trivial normal subgroups', which is not defined. The Abelian example given is some help, but does not explain enough. What is the minimal non-trivial normal subgroup of A4? Maproom (talk) 11:33, 5 March 2012 (UTC)
replies: text: The most reasonable interpretation of "minimal non-trivial normal subgroup of a group G" is a minimal element of the poset of normal subgroups, excluding 0 and G. A4 has exactly three normal subgroups, two of them being trivial. I'll see if I can make an adjustment to the text to address your comments above. Rschwieb (talk) 13:47, 5 March 2012 (UTC)
thread_title:  "minimal non-trivial normal subgroups"
Talk:Hilbert's nineteenth problem

message: what about Nash and De Giorgi work??--achab (talk) 09:09, 5 January 2008 (UTC)

message: Does anyone check these articles? "Informally, and perhaps less directly, since Hilbert's concept of a "regular variational problem" identifies precisely a variational problem whose Euler–Lagrange equation is an elliptic partial differential equation with analytic coefficients" is not an English sentence.  — Preceding unsigned comment added by 82.70.251.158 (talk) 09:54, 7 March 2019 (UTC)
thread_title:  Poor English 

message: I've seen some sources mention that Olga Aleksandrovna Ladyzhenskaya was involved in solving Hilbert's nineteenth problem, but I don't know the details. For example: "Developing ideas of De Giorgi and Nash, Ladyzhenskaya and her coauthors gave the complete answer to Hilbert’s 19th problem." – Notices of the AMS. Does anyone know more information on what her contribution was specifically? Kaldari (talk) 05:30, 26 March 2012 (UTC)
thread_title:  Olga Aleksandrovna Ladyzhenskaya 

message: In his page, Vladimir Gilelevich Maz'ya is quoted to have founded a counterexample (I assume the author meant the first one), but this information is not mentioned here, is it true? --Agi 90 (talk) 21:47, 2 October 2012 (UTC)
thread_title:  Maz'ya Counterexample 
Talk:Term algebra

message: I can't tell the difference between a term algebra, and a Herbrand universe. Can someone clarify? linas (talk) 15:51, 9 April 2008 (UTC)
replies: text: Err, maybe I've got it .. a Herbrand universe cannot contain any free variables, by definition. A term algebra does not even raise the issue of free variables, and so one can define a term algebra to consist of a set of constants, variables, and other terms.  linas (talk) 15:57, 9 April 2008 (UTC)
replies: text:  I don't think they are the same, Herbrand Universe is defined for first order languages, so it's just an example (or special case) or term algebra, not the general definition, assuming Mathworld is correct. Tijfo098 (talk) 05:06, 18 April 2011 (UTC)

text:  Unfortunately "Herbrand Universe" is used almost exclusively in comp sci texts, which are seldom the epitome of mathematical clarity. I can't find a clear definition for it. Tijfo098 (talk) 07:16, 18 April 2011 (UTC)
replies: text:  Herbrand structures and term algebras are topics from very different fields (Logik, Algebra). IMO, mixing them in one article can only go wrong and it already is. -- Cobalt pen (talk) 07:18, 9 December 2015 (UTC)
thread_title:  [[Herbrand Universe]] 

message: I am confused. A term algebra is a "freely generated algebraic structure", and there is an algebraic structure that respects an axiom. Axioms are not mentioned in the article. The question is, may a term algebra be generated from an algebraic theory and respect its axioms? If "yes", we should include some example like a free monoid. If "no", we should replace "freely generated algebraic structure" with "freely generated universal algebra". --Beroal (talk) 09:36, 7 December 2010 (UTC)
replies: text: You're right, a term algebra does not include any axioms or it would not be "absolutely free". Tijfo098 (talk) 07:19, 18 April 2011 (UTC)
thread_title:  Axioms
Talk:Hilbert's twelfth problem

message: … in English reads:
It is about my favourite childhood dream, namely to prove that the Abel’s equations with square roots of rational numbers are just as exhausted by the transformation equations of elliptical functions with singular modules, as the integer Abel’s equations are by the circle division equations.
Is this worth sharing in the article?  --yoyo (talk) 02:06, 30 May 2021 (UTC)
thread_title:  The  quote from Kronecker's letter to Dedekind …
Talk:Trans Island Air 2000

message: The operational fleet at the time of the accident was (3) DHC-6-300 Twin Otters (8P-MLK, BGC, and ERK) and (1) Rockwell AC500B Aero Commander(8P-BJK). The accident occured on 30 June, 2004. The remaining aircraft were transferred to a sister company on the closure of the company on 24 September, 2004.
There was another Twin Otter (8P-JME) that was routinely leased from an Arizona-based company for the high-demand seasonal charters from December to April.  — Preceding unsigned comment added by 65.48.212.215 (talk) 21:15, 5 September 2011 (UTC)
thread_title:  Fleet and Closure History
Talk:Lists of Polish films

message: List of films made in Poland in the Interwar Period Xx236 10:59, 25 September 2007 (UTC)
replies: text: Agreed, this list should be integrated into other lists. However, I'd suggest separating 1920s.
In 1940s there should be also a division between Polish movies:
*completed/released in occupied Poland
*made in the West (UK/USA)
*made after the war in Poland
because Polish film industry didn't exist during the German occupation.
RolaPL (talk) 01:32, 23 February 2013 (UTC)
thread_title:  Integration or separation needed 

message: Does it have a reason, why some titles are spelled with diacritics and some without? 85.178.170.107 17:10, 31 October 2007 (UTC)
thread_title:  Diacritics 
Talk:Spadikam

message: This film created box office waves.Mohanlal with a RayBan glass turned out to be a Trendsetter.Mohanlal became the first actor in malayalam to win a filmfare award for best actor for portraying a Rowdi character with mass appeal.
Along with Mammootty's 'THE KING',it became the biggest hit of that year.  —Preceding unsigned comment added by 59.88.66.108 (talk) 19:06, 6 February 2010 (UTC)
thread_title:  BOX OFFICE 

message: Spadikam is the top grosser of the year Mejomon (talk) 04:25, 23 February 2018 (UTC)
replies: text: Not done: as you have not requested a specific change in the form "Please replace XXX with YYY" or "Please add ZZZ between PPP and QQQ".More importantly, you have not cited reliable sources to back up your request, without which no information should be added to, or changed in, any article. - Arjayay (talk) 12:11, 23 February 2018 (UTC)
thread_title:  Semi-protected edit request on 23 February 2018 
Talk:TUI fly Belgium

message: All this mention of the 767's and it is not included in the fleet box?  — Preceding unsigned comment added by 108.81.226.148 (talk) 16:06, 11 August 2015 (UTC)
replies: text: They have one "OO-JNL" leased from ILFC, I have added it to the table, thanks. MilborneOne (talk) 18:39, 11 August 2015 (UTC)
thread_title:  767?
Talk:Los Chichos

message: shouldn't the spanish language page just be translated into english? this pages looks quite a bit different from the spanish one. Minnaert 21:47, 16 March 2007 (UTC)
replies: text: They have not sold 20 million records in Spain, is impossible--85.152.176.146 (talk) 22:22, 1 January 2008 (UTC)
replies: text: In Spain alone does not generally have sold 20 million records, Also, ask for help, to do a better translation than the current one, thanks Doblebrap  —Preceding undated comment added 19:12, 2 August 2012 (UTC)
replies: text: Hello, I'm new translated in English, if someone is kind enough to give me a hand with rule be grateful. a greeting. VictorAlvarez89 (talk) 23:34, 15 December 2012 (UTC)
thread_title: Talk discussion
Talk:Macromedia Central

message: I did exactly as the instructions told and the easter egg didn't work. 67.188.172.165 21:48, 16 March 2007 (UTC)
thread_title: Homestar Runner

message: Install Now brings up a dialog that will always say "Connection Error" or something, thus Macromedia Central is no longer available to install. --70.226.174.151 (talk) 15:02, 24 February 2008 (UTC)
thread_title:  Install Now... 
Talk:Fox Creek, Alberta

message: -The recent vanity vandalism left a notables section in the article with no notables in it, I'm considering revising.Razamatraz 21:58, 16 March 2007 (UTC)
replies: text: Please be my guest.  Just make sure the people listed are notable enough to have their own Wikipedia article.  It's not strictly required but it's a good idea.  --Yamla 22:19, 16 March 2007 (UTC)
replies: text: It appears we were on at the same time.  I actually intended to remove the heading entirely and place the data in more appropriate sections...as you can see now :) Razamatraz 22:22, 16 March 2007 (UTC)
thread_title:  Vandalism and Reversions 

message: Although poorly written, I believe the anonymous user who keeps changing the pewter penguin to sporty the fox is in fact correct.  Fox Creek has never had a pewter penguin as a mascot AFAIK.  I will attempt to verify this with current residents.  The school mascot is definitely Sporty the Fox.  Razamatraz (talk) 18:36, 5 November 2009 (UTC)
replies: text: Perhaps try validating the mascot's name with the school's librarian. Hwy43 (talk) 23:26, 6 November 2009 (UTC)
replies: text: I have found verification of a mascot named "Sporty the Fox". It appears Sporty is the Town of Fox Creek's mascot, not Fox Creek School's mascot. I will update the article accordingly.It may still be that the school has its own different mascot. Until such time as this is verfiable though, I am removing the current content about it being a penguin since it cannot be verified (even by the school's website). Hwy43 (talk) 22:42, 25 June 2011 (UTC)
thread_title:  Mascot