Talk:Inductrack

message: I would remove this section. It's almost certainly someone's "wishful thinking" fantasy rather than anything the researchers announced. "No moving parts friction"? Doesn't that section start out by saying it would use a moving track? There's no benefit to keeping it levitated and there's even a major disadvantage to getting rid of the wheels. The wheels are part of the fail-safe design of Inductrack. Sometime, somewhere, if it were to be built, there would be some kind of system failure and probably not at this fantastical "moving track" area, at which point it would need the wheels to settle down on. If there were no wheels, it would grind to a stop on the track like an airliner without landing gear. 24.58.246.19 08:09, 30 December 2006 (UTC)
thread_title: Stationary cars

message: How much of the kinetic energy in my train is converted to heat by the electric resistance of the loops? How fast does it slow down ? And what kind of perpetuum mobile do i get when i use superconducting loops? ;-) --Maxus96 (talk) 21:33, 16 March 2010 (UTC)
thread_title:  energy consumption 

message: OK, so permanent magnets induce a current that levitates a train in a superconducting coil. But won't they lose some of their magnetism in the process? Otherwise it seems like so many perpetual motion machines that turn magnetic field into a boundless source of motion.
24.184.234.24 (talk) 21:41, 2 October 2010 (UTC)
replies: text: No, not at all, the maglev takes significant power, which is taken from the forward motion of the train. The generated currents create resistive losses in the coils, and an inevitable effect of the resistance creates a slight phase shift on the magnetic field that puts the magnetic field slightly ahead of the train, and this forces the train backwards (although mostly upwards). So it costs energy to give the levitation effect; if there was no resistance in the coils (they were superconducting) then the magnetic field would be (in principle) right under the train and the lift would cost nothing. The magnets themselves are neodymium magnets and are magnetically very robust and wouldn't degauss in normal use. If you were using ferrites though, all bets would be off.Rememberway (talk) 19:38, 30 November 2010 (UTC)
thread_title:  How long will the induction persist? 

message: I believe the primary inventor, Richard Post, has died.
Here is a preliminary answer to Citation Needed:
v*x = w*t
B.x=B.0*sin(w*t)     B.y=B.0*cos(w*t)
L=0.0001 henry      C=1 farad
R.L = 1 ohm          R.C = 100 ohm
V.L=L*(dB/dt)
sqrt(1/LC) = 10 Hz
NeFeB 1 in cubes    lamba = 4 in
v = 40 in/sec         ~B = B.0 * 10 Hz
V = data collected  I = induced current
Questions:
What is the induced current I?
What is the induced average lift?
What is the induced average drag?
Answers:
RL track:
"The Inductrack Approach..."
RLC track:
"Spring 2013" (working title)
NVCC-Annadale SPS Team 4
Doug Goncz (talk) 12:47, 3 November 2012 (UTC)
thread_title:  Description 

message: I've added the Inductrack III, but I've munged the patent link. It doesn't generate the right query to retrieve the patent application on espacenet so I've commented it out. This is a direct link to the patent, 2010064929 A1. If anyone can see what I've stuffed up, feel free to fix and uncomment. Thanks -- PaulxSA (talk) 23:49, 21 May 2013 (UTC)
thread_title:  Patent - Inductrack III 

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thread_title:  External links modified 

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thread_title:  External links modified (January 2018)