Talk:Ram pressure

message: Not a Physics student here. Just to add this: if any body can pressure any fluid, then the concept of ram pressure is strongly connected to the one of buoyancy, isn't it right? This should be mentioned and further explained in the main article, if my observation is correct. And, if it isn't, maybe it should be made clear as well.
:No, this is not strongly related to buoyancy, because ram pressure does not require gravitational forces, while ram pressure requires only relative motion. -- David W. Hogg 16:37, 3 January 2007 (UTC)
thread_title:  ram pressure and buoyancy 

message: This article should mention and distinguish ram pressure from viscous drag.  The example at the end with the hand in the fluid may be dominated by viscous drag, not ram pressure. -- David W. Hogg 16:37, 3 January 2007 (UTC)
replies: text: Just replaced that example with a more correct example (wind on body). -- David W. Hogg 16:45, 3 January 2007 (UTC)
thread_title:  ram pressure vs viscous drag 

message: Naive readers might find a brief explanation of the term's origin to be helpful. (I.e. "pressure" is clear, but "ram" needs to be clarified.)
--  Gary Marcus, 16:48,  3 January 2007 (UTC)
:..I suppose this is related to the "ramming air" meaning (??) 37.176.248.236 (talk) 12:10, 10 July 2016 (UTC)
thread_title:  etymology 

message: Should this not be a redirect to dynamic pressure?  If not, what's the distinction? --Reuben 20:46, 25 July 2007 (UTC)
replies: text: Note that e.g. Ram-air intake links to Ram pressure as opposed to dynamic pressure. Maybe we should add disambiguation-style cross-links between the two concepts? If I find a reasonable template for this I will do so. 85.195.223.119 (talk) 19:12, 9 August 2022 (UTC)
thread_title:  redirect? 

message: Per https://ned.ipac.caltech.edu/level5/Sept08/Schindler/Schindler2.html, I believe the formula is incorrect, namely the constant term should be 1 not 1/2. Dcunning11235 (talk) 00:23, 18 January 2017 (UTC)
replies: text: This may be due to the source (Gunn & Gott 1972) using an "approximately equals" to 1, while the (Bernoulli?) pressure is derived with the "1/2" term.  I may make sense to change this to "approximately equals", then, depending on the context, which here seems to mostly astrophysical. Dcunning11235 (talk) 00:45, 18 January 2017 (UTC)
thread_title:  Ram pressure formula incorrect? 

message: In addition to the Grebel, Gallagher, Harbeck source, should include a reference (and a sentence or two) pointing to (Gunn & Gott 1972) as early (or original?) proposers of ram pressure stripping gas from galaxies in clusters. Dcunning11235 (talk) 01:18, 18 January 2017 (UTC)
thread_title:  Original proposal re: galactic stripping 

message: did I overlook it or is the name "ram" not explained? is it an acronym or does it stem from the verb to ram (compare ram-jet)? - ah, I see that somebody above asked the same question under the title "etymology"; so it stays relevant. HilmarHansWerner (talk) 06:26, 23 November 2020 (UTC)
thread_title:  name? ram? 

message: the difference of ram pressure to dynamic pressure needs to be explained (see disc. above), best first just verbally. HilmarHansWerner (talk) 06:33, 23 November 2020 (UTC)
thread_title:  difference to dynamic pressure? 

message: I'd suggest that the astrophysics meaning of the term is so loosely related to traditional continuum fluid  dynamics that it really should be broken out into a separate article. I actually think that's what this article is trying to be as every reference is astrophysics based.  
Gjxj (talk) 20:40, 30 November 2020 (UTC)
thread_title:  astrophysics 

message: I'm not a physicist but I love reading on space and related topics, I'd like to ask, could someone write an explanation of this mechanic? The lead paragraph assumes you understand the terms that are used to explain it in the first place
83.25.197.148 (talk) 14:27, 28 February 2024 (UTC)
thread_title:  Explanation 

message: The lead states that the ram pressure is P_\text{ram} = \rho u^2 yet in the two sea level examples it is calculated as P = 0.5 × ρ × v2, with a factor 0.5 as found in the expression for the drag pressure/force. Which is correct?
130.246.57.110 (talk) 09:34, 14 May 2024 (UTC)
replies: text: It used to say half rho vee squared but it was changed about 6 years ago. See the diff. I hope someone more conversant with the subject can clarify. Dolphin (t) 13:02, 14 May 2024 (UTC)
replies: text: https://royalsocietypublishing.org/doi/full/10.1098/rspa.2022.0504 2600:1700:77B6:28BF:9CC:99D9:D813:7AE9 (talk) 01:58, 24 May 2024 (UTC)
thread_title:  Inconsistency