Talk:Newton-metre

message: While the article is correct (as far as I know, anyway), I feel the "joule" paragraph is confusing and makes it almost seem as if there is some relationship between a newton metre and a joule, other than the dimension. Specifically, the sentence about the "normal" vs. "colinear" arm sounds like maybe a newton metre is a joule except measured in a different direction.
 
It seems to me that the article should just state something like "although a joule can also be (or maybe "is often"?) expressed in units of newton metres, it is an unrelated unit of measure". 
Kwh033 04:12, 11 November 2006 (UTC)
thread_title:  newton metre vs. joule 

message: obviously newtons are weight (well force but in this context weight) and kilograms are mass. These only apply at nominal standard for gravity at the earth's surface-- hence essentially G (9.801...) in the equations. Should this somehow be added (without being too wordy)? I would suggest somehow without precocity referring to G (9.80665...) and then using it in the equations. This is only a mean value for G (but usually good enough). SimonTrew (talk) 00:35, 23 March 2009 (UTC)
thread_title:  Conversion to kilos 

message: Lets say I want to tighten a bolt with 20N. That is roughly the same as applying a force of 20N and the end of my wrench, which is one meter long. Let's say now, that my wrench is only 0.5 meters long. How much pressure should then be applied at the end of it. 40N? 80.162.194.33 (talk) 21:14, 2 August 2011 (UTC)
replies: text: Pressure would depend on the area of the spanner's handle which you're pushing (and actually vary over different parts of the handle. As for force, you're right: 20 N × 1 m = 20 N·m = 40 N × 0.5 m. JIMp talk·cont 00:27, 15 March 2012 (UTC)
thread_title:  Newton half-meters? 

message: The various items in the conversion table were inconsistent with each other, expressed to different numbers of decimal places, and not consistently linked. I cleaned up the table by ensuring the proper use of "≈" as opposed to "=", calcing all factors to 8 digits, using the same syntax for and equivalents for the english units, adding the definitions of a couple of constants to help show how the conversion factors were derived, and added more links to the appropriate wiki articles. Compare version 2015-09-27T19:54:16‎ with previous to see changes. Gcronau (talk) 16:39, 27 September 2015 (UTC)
thread_title:  Conversion Table 

message: As above. 210.162.143.223 (talk) 06:23, 26 June 2023 (UTC)
replies: text: Like for all units expressed with a multiplication, the  is generally preferred to , if easily available. However, the middle dot is part of the basic Latin-1 character set, so it may be more convenient to type, and will probably look the same in most contexts. Hqb (talk) 07:06, 26 June 2023 (UTC)
thread_title:  Does unit use Unicode middle dot (·) or dot operator (⋅)? 

message: In the context of circles, angles and rotation, units of length are either tangential or\rm radial. Let there be two new units that replace good old  \rm m  (meters):  \rm m_{tan}  (tangential meters) and  \rm m_{rad}  (radial meters). The unit of a  \rm rad  is the conversion or ratio between these two units.
\rm rad = \frac{\rm m_{tan}}{\rm m_{rad}} = \frac{\rm m}{\rm m_{rad}} 
Angular frequency in this context should be \rm rad/s , not  1/ \rm s . Formulation of the relationship of  L  and  \tau  is a little more clear if you add  \Delta s or  d s like this:  \tau \cdot dt = dL . Doesn't really matter for this question use  s  instead of  ds  or  \Delta s .
So the units are  [\tau] = \rm N\cdot m_{rad} = \frac{\rm N\cdot m}{\rm rad} = \frac{\rm J}{\rm rad} . Notice the use of radial meters.
Additional related information is . Voproshatel (talk) 08:37, 2 July 2023 (UTC)
thread_title:  Unit of torque is Joule/rad