Talk:Del

message: Is "del" really the most common name of the operator?  I have heard the names "nabla", "grad" and "gradient" before, but never "del".  Maybe the page should be renamed to "Nabla" and just mention
"del" as an alternative name for the operator?  -- Jochen
:The formal operator was certainly called "del" in all of my mathematics and physics courses, which also mentioned the (infrequently used) name "nabla operator".  The operations it is typically used to construct are called "div", "grad" and "curl".  "Del" is one syllable, "nabla" two, so when you have to speak a lot of equations, it's more natural to use "del". It's also easier to say "del squared" than "laplacian of". -- Karada 11:17, 7 Nov 2004 (UTC)
replies: text: Asking Google for "del operator" gives 1620 hits, asking for "nabla operator" gives 2380.  This would indicate that "nabla" is more common. -- J.Voss 13:50, 7 Nov 2004 (UTC)
replies: text: But, then, most people say "del", not "the del operator," so it's not clear that this is meant. As below, the google fight for "del+math" vs. "nabla+math" shows del+math on top. So I'm not willing to say either is definitive proof. 24.59.199.228 09:40, 23 November 2006 (UTC)

text: Just to add to this, the del symbol itself isn't the same as the "grad" operation; you only get the grad operation by "multiplying" a scalar field by del. -- Karada 11:21, 7 Nov 2004 (UTC)

text: But compare http://www.googlefight.com/index.php?lang=en_GB&word1=%22nabla+operator%22&word2=%22del+operator%22 --Jochen 10:09, 29 September 2005 (UTC)
replies: text: I am also in favour of a move of del to nabla. I think "del" is a manifestation of loss of culture (so we should fight against this). There is no sense imho of calling this "del". The symbol is a reversed delta, OK, but then call it "led" or "atled". (Besides the fact that many other things would deserve the WP "Del" page much more than this one...) — MFH:Talk 15:13, 16 March 2006 (UTC)
replies: text:  This article is about the operator, not the symbol. 130.64.137.188 (talk) 17:24, 3 December 2008 (UTC)

text:  Wikipedia isn't a forum for the preservation of culture. Nabla is the symbol, del is the operator, that makes sense, and the rest is nothing to fret over. 24.59.199.228 09:40, 23 November 2006 (UTC)

text: PS: if you add Ostrogradsky, it's 27 against 4 - as I said, a problem of culture... (I better don't mention the result for Ostrogradski... ;-) — MFH:Talk 15:44, 16 March 2006 (UTC)

text: Same here. It's called Nabla operator almost everywhere on this planet. Moving the topic to this title would also solve the various primary topic and disambiguation issues with the Del name. --Matthiaspaul (talk) 22:03, 31 July 2017 (UTC)
thread_title: page title

message: Is it best to expand on how to convert del to different coordinate systems here or in the other coordinate systems?  This is done very poorly at them moment, from new unit vectors (and relationship to i,j,k), why you get (1/r).(d/d theta) e.t.c. --rex_the_first 18:30, 05 Nov 2005 (GMT)
: Yeah, sorry about that; I know it's not incredibly obvious. Sadly, there are easy ways to do it (h-factors), but they look way too handwavy for wikipedia, and there are rigorous ways to do it (actual coordinate substitution), but they look way too imposing and deep for Wikipedia. Unless people have proofs that I haven't seen, I don't think anything like that is coming to wikipedia. 24.59.199.228 09:40, 23 November 2006 (UTC)
thread_title:  Coordinates 

message: The page defines ∇ beautifully, without actually saying what it is/does. In other words, unless you're a mathematician, the page is meaningless.
There must be a real life example that will clarify what ∇ does. I believe it could be applied to the surface of an irregular hill, in which case, what do ∇, d/dx, etc, represent? Do the d/dx, etc represent the slopes in three different coordinates, in which case ∇ is what? The direction in which a ball will roll? Something else? --Iantresman 13:28, 13 June 2006 (UTC)
replies: text: Del is an operator. It does different things depending on what you ask it to do. Gradients of potential energy fields are forces. The divergence of the electric field is related to the charge density at a point. Et cetera.
In the final paragraph of the section on Gradient, we are suddenly confronted with an example of vector fields(?) being directly multiplied with the \nabla operator (rather than multiplying with the results of \nabla). This could be done more gently, at least by explaining what the \vec u represents, references to dot and cross products over vector fields, and the definition/representation of \nabla as a vector field in itself. --Pgagge 12:57, 10 June 2007 (UTC)

text: Part of the problem is that notations such as "∇ x" for curl are used before they are introduced symbolically.  They are introduced verbally at the top of the article, but the verbiage is not tied to the symbols.  However, placing them at the top of the article is probably too soon.  I'd put them as appositives or in a second sentence after the single sentence that introduces the "Notational Uses" section -- i.e. "These expressions are notated as .... respectively." (140.232.0.70 (talk) 14:47, 3 August 2011 (UTC)
thread_title:  So what is ∇?  

message: The article says:
::Since del does not really have a direction, this is hardly expectable
How does del 'not really have a direction'? It's a product of basis vectors, right, so isn't it just another vector? -- Ornette 10:39, 22 June 2006 (UTC)
replies: text:  Thanks, I cut out that part. Oleg Alexandrov (talk) 23:30, 22 June 2006 (UTC)
replies: text:  I added what I believe this was talking about to the end of the article. Del *doesn't* have a direction -- not in the same way that k does. kx has the same direction as ky, but ∇x and ∇y are orthogonal. Real directions don't act that way under scalar multiplication. 24.59.199.228 09:40, 23 November 2006 (UTC)
thread_title:  Confusing?  

message: I think it would be nice to know where the name "del" came from.  (My guess is likely because it looks like a delta upside-down...perhaps?)
:In my opinion this is related to the first contradiction del vs nabla. I haven't heard of del until I came to wikipedia, since I have been always taught that this is nabla, because the guy that introduced this notation (sorry, not good at remembering names) named it after a guitar-like musical instrument called nabla. The naming comes from the fact that the instrument had a triangular shape.  —Preceding unsigned comment added by 134.147.107.43 (talk) 15:10, 1 June 2010 (UTC)
thread_title:  Etymology 

message: I guess there is, as I write this, since I don't see an equality sign in 4.  Correction please?  Thanks
:Identities (3) and (4) did not actually make any formal sense and were eliminated in my most recent edit. 24.59.199.228 09:26, 23 November 2006 (UTC)
thread_title:  error in identity 4. ? 

message: In analogy to the one shown in the gradient section, I added some product rules in that same and other sections. Do you think it breaks the flow too much? Perhaps it would be better to move the examples to a separate section on product rules. −Woodstone 16:20, 3 April 2007 (UTC)
thread_title:  Product rules with del 

message: Commenting on the last part of this article:
"Central to these distinctions is the fact that del is not a vector — it is a vector operator. Whereas a vector is an object with both a precise numerical magnitude and direction, del doesn't have a precise value for either until it is allowed to operate on something."
Is this true considering that differential operations are by definition linear.  Central to this question is whether or not we can create a vector space of differential operators.  Based on the stringent requirements that define a vector space, we can indeed come up with a set of differential operators that define a vector space.  Note that magnitude and multiplicative commutation are not requirements.  If this is the case, then we can create a linear combination of differential operators that span a basis and can therefore create any arbitrary differential vector operator that can be classified as a vector.  Then the next question is, can we have vector in euclidean space with differential elements and still classify it as a vector?  It would seem that even in this case, the elements in the gradient operator can still define a vector space (maybe a subspace in euclidean space) which then suggests that the gradient operator is indeed a vector.
Anyone with a strong mathematics background who can comment on this?  —Preceding unsigned comment added by 128.193.140.64 (talk) 21:54, 17 October 2007 (UTC)
thread_title:  Gradient operator not a vector? 

message: Is the \partial operator (as in \frac{\partial f(x,y,z)}{\partial x}) also called "del," or is that not technically correct? Thanks. -Grick(talk to me!) 15:38, 23 March 2009 (UTC)
replies: text: I can, however, tell you, that the Dolbeault operator \bar\partial is sometimes called "del-bar operator", and I am not the only one: Del Bar Operator at Mathworld. This makes it plausible that some people call \partial "del". --Momotaro (talk) 16:10, 14 December 2010 (UTC)
thread_title:  \partial also called "del"? 

message: 'The del symbol can be interpreted as a vector of partial derivative operators, and its three possible meanings—gradient, divergence, and curl—can be formally viewed as the scalar product, dot product, and cross product, respectively, of the del "operator" with the field.'
This is not correct.  The scalar product is exactly the same as the dot product, and the gradient operator does not produce a scalar; it produces a vector.  See the below paragraph, taken from the wikipedia article for dot product:
'In mathematics, the dot product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number obtained by multiplying corresponding entries and adding up those products. The name is derived from the dot that is often used to designate this operation; the alternative name scalar product emphasizes the scalar (rather than vector) nature of the result.'
In terms of general vector products, the analogy of gradient is just simply a scalar multiplied by a vector to yield a vector. 219.89.230.151 (talk) 12:18, 18 June 2010 (UTC)
replies: text: I'll agree, the introduction is wrong and it is contradicting the definition. In the definition del is defined as a vector of derivation operators: \nabla = \left( {\partial \over \partial x}, {\partial \over \partial y}, {\partial \over \partial z} \right) = \mathbf{\hat{x}} {\partial \over \partial x} + \mathbf{\hat{y}} {\partial \over \partial y} + \mathbf{\hat{z}} {\partial \over \partial z}. In the introduction it its said to be also divergence and curl. Let F be scalar field, then \nabla F is the gradient of F, \nabla\cdot F is divergence of F and \nabla\times F is the curl of F. Also, gradient is a vector field and all vector fields are gradients of some scalar field (if there are no singularities). I would change the end of first paragraph to: "Del produces the gradient (the steepest slope) when applied to a scalar field. The dot product of del with a scalar field is called divergence (sink or source). Similarly, the cross product of del is called the curl (rotation)." Later in the text it may be added that  "Del operator can operate to a vector producing a tensor (curvature matrix). The dot and cross product of del with a vector are vector and tensor respectively." The suggested replacement may require some grammar tweaks, but the idea is there. In the current form the article is not internally consistent. Dv3 (talk) 21:48, 11 December 2014 (UTC)

text: Moreover, referring to "del symbol" is confusing.  The \nabla operator is called Del here, but the symbol itself is known as 'nabla'.  By contrast the del symbol is unambiguously \partial with its own page here ∂. Chumpih (talk) 10:03, 25 May 2020 (UTC)
thread_title: Error in Introductory Paragraph

message: I found the notation used in several places very confusing:  Del as I understand it is taken to operate on the variable to the right of the nabla symbol.  What then does it mean to write e.g.  
:  (\vec u \cdot \nabla) \vec v ?
It isn't clear what del is operating on here.  If this is standard mathematical usage, then perhaps a brief explanation early in the article, or a pointer to another article where that usage is explained would be helpful.  If not, is there a more explicit way to write these formulas?  
While we may drop writing out dependencies in everyday usage to save the effort of writing them over and over, an introductory article is arguably the place to be as explicit as we reasonably can be.
Ma-Ma-Max Headroom (talk) 18:17, 26 March 2011 (UTC)
replies: text: It's named and defined at Del#Directional derivative. It can be thought of as calculating the rate of change in a particular direction. It's like ∇2 in that it takes scalars to scalars rather than to vectors, so it can also take vectors to vectors. It has it's own page at directional derivative for any reader interested in more detail.--JohnBlackburnewordsdeeds 19:02, 26 March 2011 (UTC)
thread_title:  Confusing notation 

message: Hello,
Does anyone else find this chart :File:DCG chart.svg really confusing? It looks like the author has tried to embed the equations for repeated application of various operators into some kind of state diagram, but the states are not states at all; rather it appears that the edges are equation sides (both LHS and RHS), and that the vertices are the particular operators themselves. There appears to be an implicit field that it is operating upon that is not shown.
Unless I am mistaken, this chart is simply a mnemonic, not actually any kind of fundamental insight into the relations between these operators. I find it really confusing and unhelpful -- is anyone else having this problem, or is it just me? 129.67.86.189 (talk) 13:33, 27 April 2011 (UTC)
thread_title:  Chart is confusing 

message: Why does this, and related articles, have no mention of the history.  
Who developed the concept originally?  Who devised the notation? 
—DIV (137.111.13.4 (talk) 23:45, 1 April 2014 (UTC)
replies: text: See A History of Vector Analysis and links there.Rgdboer (talk) 02:52, 2 April 2014 (UTC)

text: See nabla symbol for more information, and some light for discussion below. — Rgdboer (talk) 03:09, 11 February 2017 (UTC)
thread_title:  History 

message: The current article says:
:In particular, this notation is powerful because the gradient product rule looks very similar to the 1d-derivative case:
:: \nabla(f g) = f \nabla g + g \nabla f
:However, the rules for dot products do not turn out to be simple, as illustrated by:
:: \nabla (\vec u \cdot \vec v) = (\vec u \cdot \nabla) \vec v + (\vec v \cdot \nabla) \vec u + \vec u \times (\nabla \times \vec v) + \vec v \times (\nabla \times \vec u)
Both of those equations are correct.  But I think this is correct, too:
: \nabla(\vec u \cdot \vec v) = \vec u \cdot \nabla \vec v + \vec v \cdot \nabla \vec u
If that's true, then isn't the text incorrect when it claims that the dot products are less simple?  — Preceding unsigned comment added by 2600:1700:2F00:B2E0:987A:C7B6:32BD:26D0 (talk) 18:23, 5 May 2018 (UTC)
replies: text: At the very least you would have to explain that applying grad to a vector makes a matrix, and how to premultiply that by a vector: not really simple (I did not try to verify it). −Woodstone (talk) 07:25, 6 May 2018 (UTC)
thread_title:  Not Simple? 

message: It appears as though the second image, in the Second Derivatives sub section, may have a defect.
https://wikimedia.org/api/rest_v1/media/math/render/svg/963282bdeed9310ab31e000e3231a3d723cfda23
The second line in the image, starting 'div(curl' , does not have the round brackets it should on the right hand side of the first equals sign.
currently reads div(curl v) = ∇ ⋅ ∇ × v = 0
should read     div(curl v) = ∇⋅(∇ × v) = 0
Where v should be vector notation, that is v with and over arrow, non-bold italic serif accented by a right arrow.
York Earwaker (talk) 13:47, 16 September 2021 (UTC)
replies: text: It's not ambiguous because ∇⋅∇ is a scalar, which cannot be part of a cross product. Nevertheless, brackets make it clearer. They have been added. −Woodstone (talk) 15:45, 16 September 2021 (UTC)
thread_title:  Second derivatives - image defect 

message: where is del from pbs kids? waste of time :( this del≠the del i want  — Preceding unsigned comment added by 172.101.214.126 (talk) 02:57, 6 November 2021 (UTC)
thread_title:  pbs kids 

message: This Wikipedia page introduced me to the term `curl` as a synonym for `rot` for the first time. I would not know, how common place either of the terms is, but this article should at least mention, that curl is also commonly known as rotation (rot).  — Preceding unsigned comment added by 2003:E5:272A:9679:71A9:B073:735E:50FE (talk) 15:44, 2 January 2022 (UTC)
thread_title:  curl is better known as rot (rotation) in many books and circles.