Talk:Quadrature of the Parabola

message: In 1906 Heiberg suggested that Archimedes' proof was written as
4A/3 = A + A/4 + A/12
:Archimedes' proof was also written as
:1, 5/8, 14/27, 30/64, ....., Pn/n3, ..... tends at number 1/3, as n tends to infinity 
:where the numerator of the sequence terms is the nth square pyramidal number Pn.
:see "Quadrature of the parabola with the square pyramidal number" in this talk page.--Ancora Luciano (talk) 18:50, 14 May 2013 (UTC)
thread_title:  Moved from the end of the intro 

message: As Archimedes gave two proofs, can we have a section for the other one too, the proof by abstract mechanics? I'd do it, but don't really have the skills for a mathematical article.--Annielogue (talk) 15:31, 24 November 2012 (UTC)
thread_title:  Proof by abstract mechanics 

message: This proof (possibly unpublished) of the Archimedes' theorem: "Quadrature of the parabolic segment" is obtained numerically, without 
the aid of Mathematical Analysis.
Below we show a summary of the proof. The entire article is at the following web address:
::https://sites.google.com/site/leggendoarchimede
Proposition: The area of ​​ parabolic segment is a third of the triangle ABC.
Divide AB and BC into 6 equal parts and use the green triangle as measurement unit of the areas.
 
The triangle ABC contains:
:(1+3+5+7+9+11).6 = 62.6 = 63 green triangles.   
The parabola circumscribed figure (in red) contains: 
:A(cir.) = 6.1 + 5.3 + 4.5 + 3.7 + 2.9 + 1.11 = 91 green triangles.     (3)
The sum (3) can be written:
:A(cir.) = 6 + 11 + 15 + 18 + 20 + 21 ,  that is: 
:6+ 
:6+5+ 
:6+5+4+ 
:6+5+4+3+ 
:6+5+4+3+2 
:6+5+4+3+2+1
or rather: 
:A(cir.) = sum of the squares of first 6 natural numbers ! 
Generally, for any number n of divisions of AB and BC, it is:
#   The triangle ABC contains n3 green triangles 
#   An(cir.) = sum of the squares of first n natural numbers 
So, the saw-tooth figure that circumscribes the parabolic segment can be expressed with the "square pyramidal number" of number theory!
For the principle of mathematical induction, this circumstance (which was well hidden in (3)) we can reduce the proof to the simple check of the following statement:
: the sequence of the areas ratio: 1, 5/8, 14/27, 30/64, ....., Pn/n3, ..... tends at number 1/3, as n tends to infinity     (4a)
where the numerator of the sequence terms is the nth square pyramidal number Pn.
But (4a) state that: the area (measured in green triangles) of the circumscribed figure is one-third the area of ​​the triangle ABC, at the limit of n = infinity. End of proof
This proof is very beautiful! Notice its three essential steps:
# Choice of equivalent triangles for measuring areas.
# With this choice, the area of ​​triangle ABC measure n3 triangles.
# Counting the number of triangles in the saw-tooth figure that encloses the parabolic segment and discovery that, for each number n of divisions, this number is the square pyramidal number !
  
The rest came by itself.--Ancora Luciano (talk) 18:49, 14 May 2013 (UTC)
thread_title:  Quadrature of the parabola with the "square pyramidal number" (new proof) 

message: In this section, there are some diagrams, and this statement:
"Archimedes proves that the area of each green triangle is one eighth of the area of the blue triangle. From a modern point of view, this is because the green triangle has half the width and a fourth of the height:[1]"
It is untrue that the green triangle has a fourth of the height of the blue triangle. The "height" being referred to in Archimedes proof is the height from the vertex to the midpoint of each green triangle base. It is most definitely not the height of the green triangle by any stretch. It shouldn't be called "height" but rather vertical distance from apex to base. 2603:7080:AFF0:60:289F:139F:D4E7:51A4 (talk) 16:40, 6 August 2022 (UTC)
thread_title:  Areas of the Triangles 

message: Substituted at 02:38, 5 May 2016 (UTC)
thread_title: Assessment comment

message: Hello fellow Wikipedians,
I have just modified one external link on The Quadrature of the Parabola. Please take a moment to review my edit. If you have any questions, or need the bot to ignore the links, or the page altogether, please visit this simple FaQ for additional information. I made the following changes:
*Added archive https://web.archive.org/web/20110805040431/http://planetmath.org/encyclopedia/ArchimedesCalculus.html to http://planetmath.org/encyclopedia/ArchimedesCalculus.html
When you have finished reviewing my changes, you may follow the instructions on the template below to fix any issues with the URLs.
Cheers.—InternetArchiveBot (Report bug) 06:09, 12 January 2017 (UTC)
thread_title:  External links modified