Talk:Isotopes of beryllium

message: decay width = 5.57 (25) eV per http://www-nds.iaea.org/relnsd/NdsEnsdf/showensdfdata.jsp?NucNo=8&NucID=BE
Using standard decay width to time conversion ħ/Γ = half-life in s and applying error range to the same 
1.18 (5) x 10-16s
So I would say that both values are incorrect as listed currently on the Table for this isotope.
24.8.144.79 (talk) 07:05, 28 April 2013 (UTC)
thread_title:  <sup>8</sup>Be half life measure 

message: Given that an alpha particle happens to be a helium-4 nucleus in the first place, why is alpha decay ***to*** helium-4 not noted as fission if the daughter nuclei are identical? It would make more sense to note it that way in my opinion (and to that of the average reader) to denote it as such. Thank you. 2602:306:BCA6:AC60:28F0:1D2E:C6A4:796D (talk) 07:23, 24 June 2013 (UTC)
thread_title:  <sup>8</sup>Be: Shouldn't alpha decay to helium-4 (read: two helium-4 nuclei) be considered fission? 

message: Given that the isotope EO4Be9 is the isotope that supplies the positrons for the Fermi positron acceleration experiments, why isn't there a description of how this is accomplished? Is that due to the decay of a proton or a neutron? And how can a point source contain a +1 electrostatic charge?WFPM (talk) 21:30, 13 November 2013 (UTC)
replies: text: I have no idea what you're talking about and can see no way that Be-9, our normal Be isotope, could supply positrons. Do you have a link? As for how a point source can be charged it's no harder for a positron than an electron. Ultimately it's still a mystery although QED helps explain what happens to space at such high field strengths very near the point charge. Ultimately the vacuum breaks down into virtual particles that prevent infinite field strengths. SBHarris 08:55, 14 November 2013 (UTC)

text: At Fermilab now they use a target of Inconel, an iron/nickel/chromium superalloy steel that can withstand sudden thermal shock stresses from proton beam heating.  Antiprotons are then focused with a lithium lens, basically a cylinder of lithium with a current running down it. Lithium because it is the least dense electric current conductor, thus minimizing scattering and annihiliation loss as the antiprotons travel through it. It's a fascinating problem in engineering physics, as is anything to do with accelerators. But I see no role for beryllium except its usual one to keep other metals from oxidizing while itself serving as a low density window for various radiations. SBHarris 02:46, 16 November 2013 (UTC)

text: Okay but that's what the article said. And I'm studying "The hunting of the Quark" By Michael Riordan, which details the history of SLAC and trying to understand how both point particles and quark containing composite particles can wind up with a net unit electric charge. Since it would have to be for different reasons, it sounds like quite a coincidence.WFPM (talk) 00:07, 17 November 2013 (UTC)
thread_title: Positron emission

message: Could you tell us where you found that there is a possible 17Be? There is no site where it is mentionned.  — Preceding unsigned comment added by 92.92.224.178 (talk) 20:04, 2 February 2015 (UTC)
thread_title: Beryllium-17?

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thread_title:  External links modified 

message: Beryllium-6 is an intermediate in the proton proton chain. 2 He-3 > Be-6 > He-4 + 2 H-1 . 2603:6000:8740:54B1:C941:7ADA:D88:9366 (talk) 17:17, 6 May 2023 (UTC)
thread_title:  Beryllium-6 

message: Shouldn't Beryllium-8 be listed as extinct, rather than synthetic? It's in helium fusing stars. 174.103.211.189 (talk) 17:56, 21 November 2023 (UTC)
replies: text: It's somewhat tricky to define. I don't believe 8Be can be considered extinct because it is constantly being created and destroyed in stellar cores (existing in secular equilibrium), yet due to its extremely short half-life, it does not exist on Earth outside of laboratories and has never been primordial (as is the case with extinct nuclides) anywhere. The infobox in beryllium-8 just states "0 natural abundance" with a footnote; for , it might be best to leave it as "synthetic" but with a similar footnote. Complex/Rational 19:13, 21 November 2023 (UTC)
replies: text: You could argue that beryllium-8 is the most important isotope of beryllium (along with beryllium-6 in the proton-proton chain). Who changed it from "extinct " to "synthetic " ? Besides, doesn't it occur naturally in the sun (stars above around 0.5 solar masses fuse helium) ? 174.103.211.189 (talk) 02:49, 27 November 2023 (UTC)
replies: text: Shouldn't there be "intermediate " for nuclei like this. 174.103.211.189 (talk) 03:49, 27 November 2023 (UTC)
replies: text: Another classification could potentially be beneficial, but "natural abundance" generally refers to abundance on Earth, now. Otherwise, we'd have to consistently list every nuclide found in stars or the interstellar medium that doesn't occur on Earth (e.g., 17F in the CNO II cycle; 52Fe in the alpha ladder; various isotopes potentially observed in Przybylski's Star), for which inclusion criteria are not quite as clear. Complex/Rational 23:25, 27 November 2023 (UTC)

text: By that logic, wouldn't we have to call many more nuclides extinct, considering the r-process path? Double sharp (talk) 05:20, 3 December 2023 (UTC)
replies: text: Yes, but beryllium-8 is an intermediate in a major chain (triple alpha) in the Sun's lifetime. Sure, secular equilibrium is far beyond current technology (anyone who achieves this would be a surefire Nobel Prize winner) but it is in secular equilibrium as part of the triple alpha process. Was it created in the Big Bang or no? 174.103.211.175 (talk) 16:29, 10 May 2024 (UTC)
replies: text: Almost certainly yes during the odd triple-alpha event, but the abundance of the CNO produced would be too low to detect (and it would also be swamped by stellar CNO). Last I remembered, it was something like one 12C atom produced for every 1014 atoms of 1H. Double sharp (talk) 14:17, 22 May 2024 (UTC)
thread_title:  Beryllium-8 natural occurrence  

message: The decay 6Be → 2He + 4He is energetially possible. 5He, 5Li, 6Be and 8Be are the only light nuclides that undergo alpha decay. 129.104.241.214 (talk) 02:44, 3 March 2024 (UTC)
replies: text: "5He, 5Li, 6Be" someone else is thinking outside the box! 24.115.255.37 (talk) 23:11, 20 April 2024 (UTC)

text: Yeah, it's probably better to consider 8Be as being like these light nuclides than like the more normal heavy alpha emitters, because in these cases the alpha itself is no longer small compared to the nucleus. Double sharp (talk) 14:21, 22 May 2024 (UTC)
thread_title:  Is the 2p decay of <sup>6</sup>Be a <sup>2</sup>He-emission? 

message: there are 6 isomers shown in the table but the first sentence says there are 3 isomers can someone fix 24.115.255.37 (talk) 23:10, 20 April 2024 (UTC)
thread_title:  what