Question: How often do respondents encounter knowledge silos as producitivity friction in percentage terms?
SQL:
SELECT KnowledgeSilosFreq, COUNT(KnowledgeSilosFreq) * 100.0 / (SELECT COUNT(KnowledgeSilosFreq) FROM Responses) AS percentage FROM Responses WHERE NOT KnowledgeSilosFreq IS NULL GROUP BY KnowledgeSilosFreq
SELECT KnowledgeSilosFreq, COUNT(*) * 100.0 / (SELECT COUNT(*) FROM Responses) AS Percentage FROM Responses WHERE NOT KnowledgeSilosFreq IS NULL GROUP BY KnowledgeSilosFreq