Question: What is the percentage distribution of respondents in terms of agreement with them being able to quickly find answers with existing tools and resources?
SQL:
SELECT QuicklyFindAnswers, COUNT(QuicklyFindAnswers) * 100.0 / (SELECT COUNT(QuicklyFindAnswers) FROM Responses) AS percentage FROM Responses WHERE NOT QuicklyFindAnswers IS NULL GROUP BY QuicklyFindAnswers
SELECT QuicklyFindAnswers, COUNT(*) * 100.0 / (SELECT COUNT(*) FROM Responses) AS Percentage FROM Responses WHERE NOT QuicklyFindAnswers IS NULL GROUP BY QuicklyFindAnswers