TnT/Multi_CodeNet4Repair huggingface dataset:
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
def main():
	n = int(input())
	r = [0]*5
	r[0] = int(input())
	r[1] = int(input())
	r[2] = int(input())
	r[3] = int(input())
	r[4] = int(input())
	total = 4
	min_r = min(r)
	print(min_r)
	div = n // min_r
	mod = n % min_r
	total += div
	if mod != 0:
		total += 1

	print(total)

if __name__ == '__main__':
    main()

def main():
	n = int(input())
	r = [0]*5
	r[0] = int(input())
	r[1] = int(input())
	r[2] = int(input())
	r[3] = int(input())
	r[4] = int(input())
	total = 4
	min_r = min(r)
	div = n // min_r
	mod = n % min_r
	total += div
	if mod != 0:
		total += 1

	print(total)

if __name__ == '__main__':
    main()

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math
n=int(input())
x=[]
for i in range(5):
  x.append(int(input()))
if n==min(x):
  print(5)
else:
  print(5+math.ceil(n/min(x)))

import math
n=int(input())
x=[]
for i in range(5):
  x.append(int(input()))
if n==min(x):
  print(5)
else:
  print(4+math.ceil(n/min(x)))

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n=int(input())
for i in range(5):
  x.append(int(input()))
a=max(x)
print(n//a+5)


n=int(lnput())
for i in range(5):
  x.append(int(input()))
a=max(x)
print(n//a+5)

import math
n=int(input())
x=[]
for i in range(5):
  x.append(int(input()))
a=min(x)
print(math.ceil(n/a)+4)


Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
a,*b=eval('int(input()),'*6);print(4+a//min(b))

a,*b=eval('int(input()),'*6);print(4--a//min(b))

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
ABC = [N,0,0,0,0]
time = 0
flag = 0
i = 0
while ABC[4] > 0 or flag == 0:
    print(ABC)
    if i >= 4:
        if ABC[4] >= E:
            ABC[4]-=E
        else:
            ABC[4]=0
    if i >= 3:
        if ABC[3] >= D:
            ABC[3]-=D
            ABC[4]+=D
            flag = 1
        else:
            ABC[4]+=ABC[3]
            flag = 1
            ABC[3]=0
    if i >= 2:
        if ABC[2] >= C:
            ABC[2]-=C
            ABC[3]+=C
        else:
            ABC[3]+=ABC[2]
            ABC[2]=0
    if i >= 1:
        if ABC[1] >= B:
            ABC[1]-=B
            ABC[2]+=B
        else:
            ABC[2]+=ABC[1]
            ABC[1]=0
    if ABC[0] >= A:
        ABC[0]-=A
        ABC[1]+=A
    else:
        ABC[1]+=ABC[0]
        ABC[0]=0
        
        
    time += 1
    i += 1
print('end',ABC)
print(time)

N = int(input())
A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())
ABC = [N,0,0,0,0]
time = 0
flag = 0
i = 0
while ABC[4] > 0 or flag == 0:
    print(ABC)
    if i >= 4:
        if ABC[4] >= E:
            ABC[4]-=E
        else:
            ABC[4]=0
    if i >= 3:
        if ABC[3] >= D:
            ABC[3]-=D
            ABC[4]+=D
            flag = 1
        else:
            ABC[4]+=ABC[3]
            flag = 1
            ABC[3]=0
    if i >= 2:
        if ABC[2] >= C:
            ABC[2]-=C
            ABC[3]+=C
        else:
            ABC[3]+=ABC[2]
            ABC[2]=0
    if i >= 1:
        if ABC[1] >= B:
            ABC[1]-=B
            ABC[2]+=B
        else:
            ABC[2]+=ABC[1]
            ABC[1]=0
    if ABC[0] >= A:
        ABC[0]-=A
        ABC[1]+=A
    else:
        ABC[1]+=ABC[0]
        ABC[0]=0
        
        
    time += 1
    i += 1
print('end',ABC)
print(time)

N = int(input())
abc = [int(input()) for _ in range(5)]
ans = 4+N//min(abc) if N%min(abc) == 0 else 4+N//min(abc)+1
print(ans)

Verdicts: Runtime Error

Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import sys
import math

input = sys.stdin.readline

n = int(input())

lis = [int(input()) for _ in range(5)]

lis.sort()

p = lis[0]

if (n > p):
    print(5 + int(n / p) + math.ceil(n / p)-1)
else:
    print(5)


import sys
import math

input = sys.stdin.readline

n = int(input())

lis = [int(input()) for _ in range(5)]


print(math.ceil(n/min(lis))+4)


Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import sys

stdin = sys.stdin

ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip()  # ignore trailing spaces


li = []
n = int(input())
for i in range(5):
    li.append(int(input()))
if n >= min(li):
    print(5)
else:
    print(5 + n // min(li))

import sys

stdin = sys.stdin

ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip()  # ignore trailing spaces


li = []
n = int(input())
for i in range(5):
    li.append(int(input()))
if n == min(i):
    print(5)
else:
    print(5 + n // min(li))

import sys

stdin = sys.stdin

ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
ns = lambda: stdin.readline().rstrip()  # ignore trailing spaces


li = []
n = int(input())
for i in range(5):
    li.append(int(input()))
if n <= min(li):
    print(5)
else:
    if n % min(li) == 0:
        print(5 + n // min(li) -1)
    else:
        print(5 + n // min(li))

Verdicts: Wrong Answer

Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math
n = int(input())
l = [input() for _ in range(5)]
print(math.ceil(n/min(l)+4))

import math
n = int(input())
l = [int(input()) for _ in range(5)]
print(math.ceil(n/min(l))+4)

Verdicts: Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math
n = int(input())

l = [int(input()) for _ in range(5)]

print(math.ceil(n//min(l)) + 4)

import math
n = int(input())

l = [int(input()) for _ in range(5)]

print(math.ceil(n/min(l)) + 4)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n=int(input())
a=int(input())
b=int(input())
c=int(input())
d=int(input())
e=int(input())
route=[a,b,c,d,e]
min_route=a
for i in route:
    if i < min_route:
        min_route=i
if n%min_route != 0:
    time=n//min_route+4
else:
    time=n//min_route+5
print(time)

n=int(input())
a=int(input())
b=int(input())
c=int(input())
d=int(input())
e=int(input())
route=[a,b,c,d,e]
min_route=a
for i in route:
    if i < min_route:
        min_route=i
if n%min_route == 0:
    time=n//min_route+4
else:
    time=n//min_route+5
print(time)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
a = input()
s = input()
d = input()
f = input()
g = input()
h = input()
j = min(int(s), int(d), int(f), int(g), int(h))

if int(a)%j = 0:
    k = int(a)//j + 4
else:
    k = int(a)//j + 5
print(i)



a = input()
s = input()
d = input()
f = input()
g = input()
h = input()
j = min(int(s), int(d), int(f), int(g), int(h))

if int(a)%j == 0:
    k = int(a)//j + 4
else:
    k = int(a)//j + 5
print(i)



a = input()
s = input()
d = input()
f = input()
g = input()
h = input()
j = min(int(s), int(d), int(f), int(g), int(h))

k = int(a)//j + 5

for i in str(k):
    print(i, end ='')



a = input()
s = input()
d = input()
f = input()
g = input()
h = input()
j = min(int(s), int(d), int(f), int(g), int(h))

if int(a)%j == 0:
    k = int(a)//j + 4
else:
    k = int(a)//j + 5
print(k)



Verdicts: Runtime Error

Runtime Error

Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n = int(input())
mov = []
for i in range(5):
    mov.append(int(input()))
mov.reverse()

status = [0 for i in range(6)]
status[0] = n
status.reverse()

print(mov)
print(status)

count = 0
while True:
    count += 1
    for i in range(1,len(status)):
        status[i-1] += min(status[i],mov[i-1])
        status[i] -= min(status[i],mov[i-1])
    if status[0]==n:
        print(count)
        exit()
    elif status[-1]==0:
        status.pop(-1)
        mov.pop(-1)


import math

n = int(input())
mov = []
for i in range(5):
    mov.append(int(input()))

print(math.ceil(n/min(mov))+4)


Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
from sys import exit
from math import ceil
# A,B,C = [int(n) for n in input().split()]
N = int(input())
ABCDE = [int(input()) for _ in range(5)]
mostn = min(ABCDE)
ans = 0
print(mostn + 4)


from sys import exit
from math import ceil
# A,B,C = [int(n) for n in input().split()]
N = int(input())
ABCDE = [int(input()) for _ in range(5)]
mostn = min(ABCDE)
print(ceil(N/mostn) + 4)


Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
info=[]
for _ in range(6):
  info.append(int(input()))
ans=4+info[0]//min(info[1:])
print(ans)

info=[]
for _ in range(6):
  info.append(int(input()))
from math import ceil
ans=4+ceil(info[0]/min(info[1:]))
print(ans)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n = int(input())
cap_list = [int(input()) fot i in range(5)]
min_cap = min(cap_list)
c = (n + min_cap - 1) // min_cap
print(c + 4)


n = int(input())
cap_list = [int(input()) for i in range(5)]
min_cap = min(cap_list)
c = (n + min_cap - 1) // min_cap
print(c + 4)


Verdicts: Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math
import sys

N=int(input())
a=[int(input()) for i in range(5)]

m=min(a)

tmp=-1
for i in range(5):
    if a[i]==m: p=i

print(i)

print(math.ceil(N/m)+4)

import math
import sys

N=int(input())
a=[int(input()) for i in range(5)]

m=min(a)

tmp=-1
for i in range(5):
    if a[i]==m: p=i


print(math.ceil(N/m)+4)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
population = int(input())
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())

vehicle = [a2b,b2c,c2d,d2e,e2f]

print(int(population/vehicle_min) + 5)

population = int(input())
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())
vehicle_min = min(vehicle)
vehicle = [a2b,b2c,c2d,d2e,e2f]

print(int(population/vehicle_min) + 5)

population = int(input())
print(population)
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())
city = [population,0,0,0,0,0]
vehicle = [a2b,b2c,c2d,d2e,e2f]
time = 0
while(city[5]!=population):
    for i in range(5):
        if city[4-i] >= vehicle[4-i]:
            city[5-i] += vehicle[4-i]
            city[4-i] -= vehicle[4-i]
        else:
            city[5-i] += city[4-i]
            city[4-i] = 0
    print(city)
    time += 1

print(time)
        

population = int(input())
print(population)
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())
city = [population,0,0,0,0,0]
vehicle = [a2b,b2c,c2d,d2e,e2f]
time = 0
while(city[5]!=population):
    for i in range(5):
        if city[4-i] >= vehicle[4-i]:
            city[5-i] += vehicle[4-i]
            city[4-i] -= vehicle[4-i]
        else:
            city[5-i] += city[4-i]
            city[4-i] = 0
    time += 1

print(time)

population = int(input())
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())
city = [population,0,0,0,0,0]
vehicle = [a2b,b2c,c2d,d2e,e2f]
print(round(population/min(vehicle)) + 4)

import math
population = int(input())
a2b = int(input())
b2c = int(input())
c2d = int(input())
d2e = int(input())
e2f = int(input())
city = [population,0,0,0,0,0]
vehicle = [a2b,b2c,c2d,d2e,e2f]
print(math.ceil(population/min(vehicle)) + 4)

Verdicts: Runtime Error

Runtime Error

Wrong Answer

Wrong Answer

Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
a, b, c, d, e,f= [int(input()) for i in range(6)]
A = [b,c,d,e,f]
pos = 0;
min = 99999999999
for i in range(5):
  if(A[i] < min):
    min=A[i]
    pos = 5-i
res = int(a/min) + pos 
print(res)

import math
 
a = [int(input()) for i in range(6)]
b = min([a[n] for n in range(1,6)])
print(math.ceil(a[0]/b)+4)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
N, a,b,c,d,e = [int(input()) for _ in range(6)]
m = min([a,b,c,d,e])
 
print((N//m)+4)

N, a,b,c,d,e = [int(input()) for _ in range(6)]
m = min([a,b,c,d,e])
 
print((N//m + bool(N%m))+4)  

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
N = int(input())
cyapa = []
for i in range (1,6):
    cyapa.append(int(input()))
city1 = N
city2 = 0
city3 = 0
city4 = 0
city5 = 0
city6 = 0
mi = 0
while city6 < N:
    city6 = city6 + min(city5,cyapa[6])
    city5 = city5 + min(city4,cyapa[5]) - min(city5,cyapa[6])
    city4 = city4 + min(city3,cyapa[4]) - min(city4,cyapa[5])
    city3 = city3 + min(city2,cyapa[3]) - min(city3,cyapa[4])
    city2 = city2 + min(city1,cyapa[2]) - min(city2,cyapa[3])
    city1 = city1 - min(city1,cyapa[2])
    mi = mi + 1

N = int(input())
cyapa = []
for i in range (1,6):
    cyapa.append(int(input()))
kasu = min(cyapa)
if kasu >= N:
    ans = 5
else:
    ans = 5 + (N-1)//kasu
print(ans)

Verdicts: Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
N = int(input())
A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())

class Transporter():
    def __init__(self, cap_out, temp=0):
        self.temp_num = temp
        self.cap_out = cap_out

    def transport(self):
        if self.temp_num < self.cap_out:
            num = self.temp_num
            self.temp_num = 0
            return num
        else:
            self.temp_num -= self.cap_out
            return self.cap_out

A_ = Transporter(A, temp=N)
B_ = Transporter(B)
C_ = Transporter(C)
D_ = Transporter(D)
E_ = Transporter(E)

time = 0
while (A_.temp_num!=0):
    time += 1
    a=A_.transport()
    b=B_.transport()
    c=C_.transport()
    d=D_.transport()
    e=E_.transport()
    B_.temp_num+=a
    C_.temp_num+=b
    D_.temp_num+=c
    E_.temp_num+=d

while (B_.temp_num!=0):
    time += 1
    b=B_.transport()
    c=C_.transport()
    d=D_.transport()
    e=E_.transport()
    C_.temp_num+=b
    D_.temp_num+=c
    E_.temp_num+=d

while (C_.temp_num!=0):
    time += 1
    c=C_.transport()
    d=D_.transport()
    e=E_.transport()
    D_.temp_num+=c
    E_.temp_num+=d

while (D_.temp_num!=0):
    time += 1
    d=D_.transport()
    e=E_.transport()
    E_.temp_num+=d

whileD(E_.temp_num!=0):
    time += 1
    E_.transport()
print(time)


N = int(input())
A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())

min_city = min([A, B, C, D, E])

print(4+(N+min_city-1)//min_city)


Verdicts: Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
N, A, B, C, D, E = int(input()), int(input()), int(input()), int(input()), int(
    input()), int(input())
ABC = [A, B, C, D, E]
ans = 0
push = N
for i in range(5):
    if push <= ABC[i]:
        ans += 1
    else:
        ans += N // ABC[i] + 1
        push = ABC[i]

print(ans)


N, A, B, C, D, E = int(input()), int(input()), int(input()), int(input()), int(
    input()), int(input())
Min = min([A, B, C, D, E])
print(N // Min + 1 + 4 if N // Min != N / Min else N // Min + 4)


Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n=int(input())
a=[0]*5
for i in range(5):
    a[i]=int(input())
print(5+(n+min(a)-1)//min(a))

n=int(input())
a=[0]*5
for i in range(5):
    a[i]=int(input())
b=5+n//min(a)
if n%min(a)==0:
    b-=1
print(b)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
X,Y,Z,K = map(int, input().split())
a_list = [int(i) for i in input().split()]
b_list = [int(i) for i in input().split()]
c_list = [int(i) for i in input().split()]
a_b_total = [0 for _ in range(X*Y)]
for i in range(X):
    for j in range(Y):
        a_b_total[i*Y+j] = a_list[i] + b_list[j]
a_b_total.sort(reverse = True)
a_b_c_total = [0 for _ in range(min(K,X*Y)*Z)]
for i in range(min(K,X*Y)):
    for j in range(Z):
        a_b_c_total[i*Z+j] = a_b_total[i] + c_list[j]
a_b_c_total.sort(reverse = True)
for i in range(K):
    print(a_b_c_total[i])

X,Y,Z,K = map(int, input().split())
a_list = [int(i) for i in input().split()]
b_list = [int(i) for i in input().split()]
c_list = [int(i) for i in input().split()]
a_list.sort(reverse = True)
b_list.sort(reverse = True)
c_list.sort(reverse = True)
total_list = [0 for _ in range(min(106307,X*Y*Z))]
for i in range(X):
    for j in range(Y):
        for k in range(Z):
            if (i+1)*(j+1)*(k+1) <= K:
                total_list[i*(Z*Y)+j*Z+k] = (a_list[i] + b_list[j] + c_list[k])
            else:
                break
total_list =  sorted(total_list, reverse = True)
for i in range(K):
    print(total_list[i])

N,A,B,C,D,E = [int(input()) for _ in range(6)]
times = [A,B,C,D,E]
for i in range(4):
    if times[i] < times[i+1]:
        times[i+1] = times[i]
A,B,C,D,E = times
l = -(-N//A)
m = -(-(N - (l-1)*B)//B)
n = -(-(N - (l+m-2)*C)//C)
p = -(-(N - (l+m+n-3)*D)//D)
q = -(-(N - (l+m+n+p-4)*E)//E)
print(l+m+n+p+q)

Verdicts: Runtime Error

Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n = int(input())
trans = [int(input()) for _ in range(5)]
x = min(trans)
t = n-1 // x
t += 4
print(t)

n = int(input())
trans = [int(input()) for _ in range(5)]
x = min(trans)
t = (n-1) // x
t += 4
print(t)

n = int(input())
trans = [int(input()) for _ in range(5)]
x = min(trans)
t = n // x if n % x == 0 else n // x + 1
t += 4
print(t)

Verdicts: Wrong Answer

Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n = int(input())
city = [int(input()) for _ in range(5)]
if n <= min(city):
    print(5)
    exit()
print(round(n/min(city))+4)

n = int(input())
a = list(int(input()) for _ in range(5))
Min = min(a)

if n <= Min:
    print(5)
    exit()

x = n//Min
if n%Min != 0: x += 1
print(4-a.index(Min)+x+a.index(Min))

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
#!venv/bin/python
 
import math
import numpy as np
import random
import copy
import statistics 
import bisect
import heapq
from collections import defaultdict 
 
N, *num = [int(input()) for i in range(6)]
min = sorted(num)[0]

print(N//min + 4)

#!venv/bin/python
 
import math
import numpy as np
import random
import copy
import statistics 
import bisect
import heapq
from collections import defaultdict 
 
N, *num = [int(input()) for i in range(6)]
min = sorted(num)[0]

if N % min == 0:
    print(N//min + 4)
else:
    print(N//min + 5)



Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n=int(input())
x = [int(input()) for _ in range(5)]
p = min(x)
q = n//p
print(q+4)


n=int(input())
x = [int(input()) for _ in range(5)]
p = min(x)
q = n//p
if n % p == 0:
        print(q+4)
else:
        print(q+5)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math
n = int(input())
l=[int(input) for i in range(5)]
print(math.ceil(n/min(l))+4)

import math
n=int(input())
l=[int(input()) for i in range(5)]
print(math.ceil(n/min(l))+4)

Verdicts: Runtime Error

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
#2019/10/04
N, A, B, C, D, E = list(map(int, open(0).read().split()))
# print(N)
print(-~(N//min(A,B,C,D,E)) + 5)

#2019/10/04
N, A, B, C, D, E = list(map(int, open(0).read().split()))
# print(N)
print(-(-N//min(A,B,C,D,E)) + 4)

Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
n = int(input())
ls = [int(input()) for _ in range(5)]
print(ls)
k = n/min(ls)
if k % 1 != 0:
    k = int(k) + 1
else:
    k = int(k)
print(k+4)


n = int(input())
ls = [int(input()) for _ in range(5)]
k = n//min(ls)
if (n/min(ls)) % 1 != 0:
    k += 1
print(k+4)


Verdicts: Wrong Answer

Accepted
Problem: In 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!  There are five means of transport in this empire:    * Train: travels from City 1 to 2 in one minute. A train can occupy at most A people.   * Bus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.   * Taxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.   * Airplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.   * Ship: travels from City 5 to 6 in one minute. A ship can occupy at most E people.  For each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).  There is a group of N people at City 1, and they all want to go to City 6.   At least how long does it take for all of them to reach there? You can ignore the time needed to transfer.

Submission attempts (in order):
import math

n = int(input())
l = [int(input()) for _ in range(5)]
ans = 0

tmp = n

necks = []
for i in range(5):
    neck = math.ceil(tmp/l[i])
    necks.append(neck)
    print(neck)
    tmp = l[i]

before = 0
f = True
for neck in necks:
    if neck < before:
        f = False

    if f:
        if neck >= before:
            ans += neck
            before = neck
        else:
            ans += 1
    else:
        ans += 1

print(ans)


import math

n = int(input())
l = [int(input()) for _ in range(5)]
print(math.ceil(n / min(l)) + 4)


Verdicts: Wrong Answer

Accepted