TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke has N dogs and M monkeys. He wants them to line up in a row.  As a Japanese saying goes, these dogs and monkeys are on bad terms. _("ken'en no naka", literally "the relationship of dogs and monkeys", means a relationship of mutual hatred.)_ Snuke is trying to reconsile them, by arranging the animals so that there are neither two adjacent dogs nor two adjacent monkeys.  How many such arrangements there are? Find the count modulo 10^9+7 (since animals cannot understand numbers larger than that). Here, dogs and monkeys are both distinguishable. Also, two arrangements that result from reversing each other are distinguished.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
ans=1
if abs(a-b)>1:
  print(0)
elif abs(a-b)==1:
  ans=2
while a>1:
  ans*=a
  a-=1
while b>1:
  ans*=b
  b-=1
print(ans)

Fixed, accepted submission:
a,b=map(int,input().split())
mod=1000000007
ans=1
if abs(a-b)>1:
  print(0)
else:
  if abs(a-b)==0:
    ans=2
  while a>1:
    ans*=a
    ans%=mod
    a-=1
  while b>1:
    ans*=b
    ans%=mod
    b-=1
  print(ans)
Problem:
We have a sequence of length N, a = (a_1, a_2, ..., a_N). Each a_i is a positive integer.  Snuke's objective is to permute the element in a so that the following condition is satisfied:    * For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.  Determine whether Snuke can achieve his objective.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))

k0 = 0
k2 = 0
k4 = 0

for a in A:
  if a%4==0:
    k4 += 1
  elif a%2==0:
    k2 += 1
  else:
    k0 += 1
print(k4,k2,k0)

if k2 > 0:
  k0 += 1

if k0 > k4+1:
  print("No")
else:
  print("Yes")


Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))

k0 = 0
k2 = 0
k4 = 0

for a in A:
  if a%4==0:
    k4 += 1
  elif a%2==0:
    k2 += 1
  else:
    k0 += 1


if k2 > 0:
  k0 += 1

if k0 <= k4+1:
  print("Yes")  
else:
  print("No")
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if b+b-1 >= a:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a,b = map(int,input().split())
if b+b-1 <= a:
  print("YES")
else:
  print("NO")
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
import math
k=int(input())
def primes(n):
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

pl=primes(k)
ans=[]
print(pl)
m=math.factorial(k)
for i in range(len(pl)):
    tmp=0
    while m%pl[i]==0:
        m=m//pl[i]
        tmp+=1
    ans.append(tmp)
a=1
for i in range(len(ans)):
    a=a*(ans[i]+1)%(10**9+7)
print(a)


Fixed, accepted submission:
import math
k=int(input())
def primes(n):
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

pl=primes(k)
ans=[]
m=math.factorial(k)
for i in range(len(pl)):
    tmp=0
    while m%pl[i]==0:
        m=m//pl[i]
        tmp+=1
    ans.append(tmp)
a=1
for i in range(len(ans)):
    a=a*(ans[i]+1)%(10**9+7)
print(a)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):

a, b, c = map(int, input().strip().split())
a_temp = a

flg = False

for i in range(b):
    if (a_temp - c) % b == 0:
        print('Yes')
        exit()
    a_temp += a
else:
    print('No')


Fixed, accepted submission:

a, b, c = map(int, input().strip().split())
a_temp = a

for i in range(b):
    if a_temp % b == c:
        print('YES')
        break
    a_temp += a
else:
    print('NO')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

n = N -1000
while n >= 1000:
    n -= 1000
print(n)

Fixed, accepted submission:
N = int(input())

n = N
while n > 0:
    n -= 1000
    
print(abs(n))
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int,input().split())

if a <= x <= a+b:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
a,b,x = map(int,input().split())

if a <= x <= a+b:
    print('YES')
else:
    print('NO')
Problem:
Takahashi, who works at DISCO, is standing before an iron bar. The bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.  Takahashi wanted to choose a notch and cut the bar at that point into two parts with the same length. However, this may not be possible as is, so he will do the following operations some number of times **before** he does the cut:    * Choose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).   * Choose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.  Find the minimum amount of money needed before cutting the bar into two parts with the same length.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))

left = 0
right = 0
center = 0
sum_a = sum(a)
flg = False
for i in range(n):
    if left + a[i] > sum_a/2 and flg is False:
        flg = True
        center = a[i]
        right -= a[i]
    elif left + a[i] == sum_a // 2:
        print(0)
        exit()
    if flg is False:
        left += a[i]
    else:
        right += a[i]
print(left, center, right)

print(min(left+center-right, right+center-left))


Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))

left = a[0]
right = a[-1]
center = 0
sum_a = sum(a)
flg = False
for i in range(1, n-1):
    if left + a[i] > sum_a/2 and flg is False:
        flg = True
        center = a[i]
        right -= a[i]
    elif left + a[i] == sum_a / 2:
        print(0)
        exit()
    if flg is False:
        left += a[i]
    else:
        right += a[i]

print(abs(min(left+center-right, right+center-left)))
Problem:
An expression is given in a line. Two consequtive symbols (operand or operator) are separated by a space character.  You can assume that +, - and * are given as the operator and an operand is a positive integer less than 106

Incorrect submission (verdict: Wrong Answer):
import sys
a = list(input().split())
stack = []
for i in range(len(a)):
    n = len(stack)
    if a[i] == '+':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp = int(stack.pop(n-1)) + int(stack.pop(n-2))
        stack.append(tmp)
        
    elif a[i] == '-':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp_1 = int(stack.pop(n-1))
        tmp_2 = int(stack.pop(n-2))
        tmp = tmp_2 - tmp_1
        stack.append(tmp)
        
    elif a[i] == '*':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp = int(stack.pop(n-1)) * int(stack.pop(n-2))
        stack.append(tmp)
        
    elif a[i] == '/':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp_1 = int(stack.pop(n-1))
        tmp_2 = int(stack.pop(n-2))
        tmp = tmp_2 / tmp_1
        stack.append(tmp)
    else:
        stack.append(int(a[i]))


Fixed, accepted submission:
import sys
a = list(input().split())
stack = []
for i in range(len(a)):
    n = len(stack)
    if a[i] == '+':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp = int(stack.pop(n-1)) + int(stack.pop(n-2))
        stack.append(tmp)
        
    elif a[i] == '-':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp_1 = int(stack.pop(n-1))
        tmp_2 = int(stack.pop(n-2))
        tmp = tmp_2 - tmp_1
        stack.append(tmp)
        
    elif a[i] == '*':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp = int(stack.pop(n-1)) * int(stack.pop(n-2))
        stack.append(tmp)
        
    elif a[i] == '/':
        if (n-2) <0:
            sys.exit("スタックアンダーフロー")
        tmp_1 = int(stack.pop(n-1))
        tmp_2 = int(stack.pop(n-2))
        tmp = tmp_2 / tmp_1
        stack.append(tmp)
    else:
        stack.append(int(a[i]))
print(stack[0])
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
def evencheck(a, b):
    p = a * b
    s = ''
    if p % 2 == 0:
        s = 'Even'
    else:
        s = 'Odd'
    return s

a, b = map(int, input().split())
result = evencheck(a, b)

Fixed, accepted submission:
def evencheck(a, b):
    p = a * b
    s = ''
    if p % 2 == 0:
        s = 'Even'
    else:
        s = 'Odd'
    return s
  
a, b = map(int, input().split())
result = evencheck(a, b)
print(result)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int, input().split())      

c = a*b

if c%2 == 1:
    print("Even")
else:
    print("Odd")

Fixed, accepted submission:
a,b = map(int, input().split())      

c = a*b

if c%2 == 1:
    print("Odd")
else:
    print("Even")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
result_list = ['AC', 'WA', 'TLE', 'RE']
count_list = [0, 0, 0, 0]
for i in range(N):
  S = input()
  count_list[result_list.index(S)] = count_list[result_list.index(S)] + 1

for i in range(4):
  print(result_list[i]+' × '+str(count_list[i]))

Fixed, accepted submission:
N=int(input())
result_list = ['AC', 'WA', 'TLE', 'RE']
count_list = [0, 0, 0, 0]
for i in range(N):
  S = input()
  count_list[result_list.index(S)] = count_list[result_list.index(S)] + 1

for i in range(4):
  print(result_list[i]+' x '+str(count_list[i]))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

X=int(input())

money = 100
ans = 0

while money <= X:
    money += math.floor(money * 0.01)
    ans += 1

print(ans)

Fixed, accepted submission:
import math

X=int(input())

money = 100
ans = 0

while money < X:
    money += math.floor(money * 0.01)
    ans += 1

print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a*b%2 :
    print('odd')
else:
    print('even')

Fixed, accepted submission:
a,b=map(int,input().split())
if a*b%2 :
    print('Odd')
else:
    print('Even')
Problem:
Your friend who lives in undisclosed country is involved in debt. He is borrowing 100,000-yen from a loan shark. The loan shark adds 5% interest of the debt and rounds it to the nearest 1,000 above week by week.  Write a program which computes the amount of the debt in n weeks.

Incorrect submission (verdict: Wrong Answer):
import math
d=100
for _ in[0]*int(input()):
 d=math.ceil(d*1.05)
print(d*1e3)


Fixed, accepted submission:
a=100
for _ in[0]*int(input()):a=int(a*1.05)+(a%20>0)
print(a*1000)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
a=list(map(int, input().split()))
ans = 0
for i in range(N):
  d = 0
  while (a[i] %2 == 0):
    d += 1
    a[i] //= 2
  ans = min(d,ans)
print(ans)
  

Fixed, accepted submission:
N=int(input())
a=list(map(int, input().split()))
ans = 100000000
for i in range(N):
  d = 0
  while (a[i] %2 == 0):
    d += 1
    a[i] //= 2
  ans = min(d,ans)
print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = []
for n in range(N):
    S.append(input())

print('AC ×',S.count('AC'))
print('WA ×',S.count('WA'))
print('TLE ×',S.count('TLE'))
print('RE ×',S.count('RE'))

Fixed, accepted submission:
N = int(input())
S = []
for n in range(N):
    S.append(input())

print('AC x',S.count('AC'))
print('WA x',S.count('WA'))
print('TLE x',S.count('TLE'))
print('RE x',S.count('RE'))
Problem:
For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Incorrect submission (verdict: Wrong Answer):
try:
    (m,n)  =  map(int,input().split())
except:
    exit

print(m,n)
r = pow(m,n) %  1000000007
print (r)


Fixed, accepted submission:
(m,n)  =  map(int,input().split())

bi = str(format(n,"b"))
bi = bi[::-1]

c = 1
d = 1000000007

for i in bi:
    if ( i == "1"):
        c = ( c * m ) % d
    m = (m * m) %d
print (c)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
# ABC086 C Traveling

n = int(input())
t, x, y = 0, 0, 0
flag = True

for i in range(n):
    _t,_x,_y = map(int, input().split())
    _d = abs(x - _x) + abs(y - _y)
    _dt = abs(t - _t)
    if _d > _dt or ((_d - _dt)%2) == 1:
        flag = False
    t,x,y = _t,_x,_y

if flag:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
# ABC086 C Traveling

n = int(input())
t, x, y = 0, 0, 0
flag = True

for i in range(n):
    _t,_x,_y = map(int, input().split())
    _d = abs(x - _x) + abs(y - _y)
    _dt = abs(t - _t)
    if _d > _dt or ((_d - _dt)%2) == 1:
        flag = False
    t,x,y = _t,_x,_y

if flag:
    print("Yes")
else:
    print("No")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

print(n % 1000)

Fixed, accepted submission:
from math import ceil

n=int(input())
print(ceil(n/1000)*1000-n)
Problem:
You start with the number 0 and you want to reach the number N.  You can change the number, paying a certain amount of coins, with the following operations:    * Multiply the number by 2, paying A coins.   * Multiply the number by 3, paying B coins.   * Multiply the number by 5, paying C coins.   * Increase or decrease the number by 1, paying D coins.  You can perform these operations in arbitrary order and an arbitrary number of times.  What is the minimum number of coins you need to reach N?  **You have to solve T testcases.**

Incorrect submission (verdict: Wrong Answer):
import sys
from functools import lru_cache
sys.setrecursionlimit(10**7)
@lru_cache(maxsize=None)
def dfs(x):
    if x == 0:
        return 0
    if x == 1:
        return d
    l2 = x//2
    r2 = (x+1)//2
    l3 = x//3
    r3 = (x+2)//3
    l5 = x//5
    r5 = (x+4)//5
    count = x*d
    count = min(count,abs(l2*2-x)*d+a+dfs(l2))
    count = min(count,abs(r2*2-x)*d+a+dfs(r2))
    count = min(count,abs(l3*3-x)*d+b+dfs(l3))
    count = min(count,abs(r3*3-x)*d+b+dfs(r3))
    count = min(count,abs(l5*5-x)*d+c+dfs(l5))
    count = min(count,abs(r5*5-x)*d+c+dfs(r5))
    return count

t = int(input())
for _ in range(t):
    n,a,b,c,d = map(int,input().split())
    print(dfs(n))

Fixed, accepted submission:
import sys
from functools import lru_cache
sys.setrecursionlimit(10**7)

def solve(x,a,b,c,d):
    @lru_cache(None)
    def dfs(x):
        if x == 0:
            return 0
        if x == 1:
            return d
        l2 = x//2
        r2 = (x+1)//2
        l3 = x//3
        r3 = (x+2)//3
        l5 = x//5
        r5 = (x+4)//5
        count = x*d
        count = min(count,abs(l2*2-x)*d+a+dfs(l2))
        count = min(count,abs(r2*2-x)*d+a+dfs(r2))
        count = min(count,abs(l3*3-x)*d+b+dfs(l3))
        count = min(count,abs(r3*3-x)*d+b+dfs(r3))
        count = min(count,abs(l5*5-x)*d+c+dfs(l5))
        count = min(count,abs(r5*5-x)*d+c+dfs(r5))
        return count
    return dfs(x)
t = int(input())
for _ in range(t):
    n,a,b,c,d = map(int,input().split())
    print(solve(n,a,b,c,d))
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):

R,G,B,n = map(int,input().split())
cnt = 0
for i in range(n//R):
    for j in range(n//G):
        for k in range(n//B):
            if i*R + j*G + k*B == n:
                cnt += 1
                
print(cnt)


Fixed, accepted submission:

R,G,B,n = map(int,input().split())
cnt = 0
for i in range(n//R + 1):
    for j in range(n - i*R + 1):
        c = n - (i*R + j*G)
        if c >= 0 and c%B == 0:
            cnt += 1
        else:
            pass
                
print(cnt)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

x = int(input())
orig = 100
counter = 0

while orig <= x:
    orig = math.floor(orig * 1.01)
    counter += 1

print(counter)


Fixed, accepted submission:
import math

x = int(input())
orig = 100
counter = 0

while orig < x:
    orig = math.floor(orig * 1.01)
    counter += 1

print(counter)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
A, B = map(int, input().split())
if A % 3 == 0 or B % 3 == 0 or (A+B) % 3 == 0:
  print('Yes')
else:
  print('No')


Fixed, accepted submission:
A, B = map(int, input().split())
if A % 3 == 0 or B % 3 == 0 or (A+B) % 3 == 0:
  print('Possible')
else:
  print('Impossible')
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
X = int(input())

ans = 0
money = 100
while money <= X:
    ans += 1
    money *= 1.01
    money = int(money)
print(ans)


Fixed, accepted submission:
X = int(input())

ans = 0
money = 100
while money < X:
    ans += 1
    money *= 1.01
    money = int(money)
print(ans)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

print(n % 1000)


Fixed, accepted submission:
n = int(input())

print( (1000 - n % 1000) % 1000)
Problem:
We have a 3×3 square grid, where each square contains a lowercase English letters. The letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.  Print the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.

Incorrect submission (verdict: Wrong Answer):
x1 = input()
x2 = input()
x3 = input()

print(x1[0], x2[1], x3[2])

Fixed, accepted submission:
s1 = input()
s2 = input()
s3 = input()

print('{}{}{}'.format(s1[0], s2[1], s3[2]))
Problem:
AtCoDeer the deer recently bought three paint cans. The color of the one he bought two days ago is a, the color of the one he bought yesterday is b, and the color of the one he bought today is c. Here, the color of each paint can is represented by an integer between 1 and 100, inclusive.  Since he is forgetful, he might have bought more than one paint can in the same color. Count the number of different kinds of colors of these paint cans and tell him.

Incorrect submission (verdict: Wrong Answer):
a,b,c = input().split()

score = 1
if a != b:
	score = score + 1
elif a !=c:
	score = score + 1
else:
	score = score
print(score)

Fixed, accepted submission:
a,b,c = input().split()

if a == b and a == c:
	print(1)
elif a ==b and a != c:
	print(2)
elif b == c and b != a:
	print(2)
elif c ==a and c != b:
	print(2)
elif a != b and b != c and c != a:
	print(3)
Problem:
There are N stones arranged in a row. Every stone is painted white or black. A string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is `.`, and the stone is black if the character is `#`.  Takahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone. Find the minimum number of stones that needs to be recolored.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = input()

best = n
curr = 0
nblack = 0

for ch in s:
  if ch == '.':
    curr = min(nblack, 1 + curr)
  else:
    nblack += 1
  best = min(best, curr)

print(best)


Fixed, accepted submission:
n = int(input())
s = input()

curr = 0
nblack = 0

for ch in s:
  if ch == '.':
    curr = min(nblack, 1 + curr)
  else:
    nblack += 1

print(curr)