TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = list(input())
ans = 0
for i in range(1,n-1):
    sa = set(s[:i])
    sb = set(s[i+1:])
    ans = max(ans,len(sa&sb))

print(ans)
    


Fixed, accepted submission:
n = int(input())
s = list(input())
ans = 0
for i in range(1,n-1):
    sa = set(s[:i])
    sb = set(s[i:])
    ans = max(ans,len(sa&sb))

print(ans)
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a, b, h = map(int, [input() for _ in range(3)])
print(round((a + b) * h))

Fixed, accepted submission:
a, b, h = map(int, [input() for _ in range(3)])
print(round(((a + b) * h) / 2))
Problem:
Takahashi is a user of a site that hosts programming contests.   When a user competes in a contest, the _rating_ of the user (not necessarily an integer) changes according to the _performance_ of the user, as follows:    * Let the current rating of the user be a.   * Suppose that the performance of the user in the contest is b.   * Then, the new rating of the user will be the avarage of a and b.  For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.  Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.   Find the performance required to achieve it.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
print(b-2*a)

Fixed, accepted submission:
r=int(input())
g=int(input())
print(2*g-r)
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
a=input()
if a=="abc" and a=="acb" and a=="bac" and a=="bca" and a=="cab" and a=="cba":
  print="Yes"
else:
  print="No"
  

Fixed, accepted submission:
a=input()
if a=="abc" or a=="acb" or a=="bac" or a=="bca" or a=="cab" or a=="cba":
  print("Yes")
else:
  print("No")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n = int(input())

total = 0

for i in range(n):
    total = total + i*i

print(total)

Fixed, accepted submission:
n = int(input())

total = 0

for i in range(n+1):
    total = total + i

print(total)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())
print(min(abs(x - a), abs(x - b)))

Fixed, accepted submission:
x, a, b = map(int, input().split())
print('AB'[abs(x - a) > abs(x - b)::2])
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
table = input().split()
A,B,C = int(table[0]),int(table[1]),int(table[2])
if A <= C and C<= B:
    print('yes')
else:
    print('no')

Fixed, accepted submission:
table = input().split()
A,B,C = int(table[0]),int(table[1]),int(table[2])
if A <= C and C<= B:
    print('Yes')
else:
    print('No')
Problem:
You are given an integer N. Build an undirected graph with N vertices with indices 1 to N that satisfies the following two conditions:    * The graph is simple and connected.   * There exists an integer S such that, for every vertex, the sum of the indices of the vertices adjacent to that vertex is S.  It can be proved that at least one such graph exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
if(N%2 == 0):
    for i in range(1,N):
        for j in range(i+1,N+1):
            if(i+j != N+1):
                print(*[i,j])
else:
    for i in range(1,N):
        for j in range(i+1,N+1):
            if(i+j != N):
                print(*[i,j])

Fixed, accepted submission:
N = int(input())
print(N*(N-1)//2 - N//2)
if(N%2 == 0):
    for i in range(1,N):
        for j in range(i+1,N+1):
            if(i+j != N+1):
                print(*[i,j])
else:
    for i in range(1,N):
        for j in range(i+1,N+1):
            if(i+j != N):
                print(*[i,j])
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):
a = list(input())
br = []
for ar in a:
    br.append(a.count(ar))
x = 0
for b in br:
    if b % 2 == 1:
        x += 1
if x == 0:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
a = list(input())
br = []
for ar in a:
    br.append(a.count(ar))
x = 0
for b in br:
    if b % 2 == 1:
        x += 1
if x == 0:
    print("Yes")
else:
    print("No")
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=list(map(int,input().split()))[::-1]
flag=1
count=0
while flag:
    flag=0
    for i in range(N-1):
        if A[i]<A[i+1]:
            A[i],A[i+1]=A[i+1],A[i]
            flag=1
            count+=1

print(A[::-1],count,sep='\n')


Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))[::-1]
flag=1
count=0
while flag:
    flag=0
    for i in range(N-1):
        if A[i]<A[i+1]:
            A[i],A[i+1]=A[i+1],A[i]
            flag=1
            count+=1

print(*A[::-1])
print(count)
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Wrong Answer):
numbers = {str(i) for i in range(10)}
N, K = map(int, input().split())
*D, = map(str, input().split())
D = set(D)
available = numbers - D
ans = 0
for i in range(N, 100000):
    nums = set(str(i))
    if nums < available:
        print(i)
        break

Fixed, accepted submission:
numbers = {str(i) for i in range(10)}
N, K = map(int, input().split())
*D, = map(str, input().split())
D = set(D)
available = numbers - D
ans = 0
for i in range(N, 100000):
    nums = set(str(i))
    if nums <= available:
        print(i)
        break
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math
x = int(input())
d = 100
a = 0
while x >= d:
    d += math.floor(d*0.01)
    a += 1
print(a)

Fixed, accepted submission:
import math

x = int(input())
d = 100
a = 0
while x > d:
    d += math.floor(d*0.01)
    a += 1
print(a)
Problem:
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).  The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Incorrect submission (verdict: Wrong Answer):
Suit = ["S","H","C","D"]
deck = []


for i in range(4):
    for n in range(1,14):
        tmp = (Suit[i]+" "+str(n))
        deck.append(tmp)

u = int(input())

for _ in range(u):
    s = str(input())
    if s in deck:
        deck.remove(s)

for y in range(len(deck)):
    print('{} {}'.format(deck[y][0],deck[y][2]))




Fixed, accepted submission:
Suit = ["S","H","C","D"]
deck = []


for i in range(4):
    for n in range(1,14):
        tmp = (Suit[i]+" "+str(n))
        deck.append(tmp)

#print (deck)

u = int(input())

for _ in range(u):
    s = str(input())
    if s in deck:
        deck.remove(s)

for y in range(len(deck)):
    print('{}'.format(deck[y]))
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
N, H = map(int, input().split())
A = []
B = []
for _ in range(N):
    a, b = map(int, input().split())
    A.append(a)
    B.append(b)

a = max(A)
B.sort(reverse=True)

ans = 0
for b in B:
    if b < a:
        break
    H -= b
    ans += 1
    if H <= 0:
        print(ans)
        exit()

import math
ans += math.floor(H / a)

print(int(ans))


Fixed, accepted submission:
N, H = map(int, input().split())
A = []
B = []
for _ in range(N):
    a, b = map(int, input().split())
    A.append(a)
    B.append(b)

a = max(A)
B.sort(reverse=True)

ans = 0
for b in B:
    if b < a:
        break
    H -= b
    ans += 1
    if H <= 0:
        print(ans)
        exit()

import math
ans += math.ceil(H / a)

print(int(ans))
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
import string
al = string.ascii_lowercase

S = input()
ans = "Yes"
for a in al:
  if S.count(a) > 1:
    ans = "No"
print(ans)


Fixed, accepted submission:
import string
al = string.ascii_lowercase

S = input()
ans = "yes"
for a in al:
  if S.count(a) > 1:
    ans = "no"
print(ans)
Problem:
There is an integer sequence A of length N whose values are unknown.  Given is an integer sequence B of length N-1 which is known to satisfy the following:  B_i \geq \max(A_i, A_{i+1})  Find the maximum possible sum of the elements of A.

Incorrect submission (verdict: Wrong Answer):
while True:
    try:
        num = int(input())
        lst = list(map(int, input().split()))
        point = lst[-1]
        ans = 0
        for n in lst[-1::-1]:
            point = min(point, n)
            ans += point
        ans += point
        print(ans)
    except:
        break

Fixed, accepted submission:
while True:
    try:
        num = int(input())
        lst = list(map(int, input().split()))
        ans = 0
        ans += lst[-1] + lst[0]
        if num == 2:
            print(ans)
            continue
        for i in range(1, num-1):
            ans += min(lst[i], lst[i-1])
        print(ans)
    except:
        break
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):

a, b, x = map(int, input().split())

count = 0
for i in range(a,b):
    if(i % x):
        count += 1

print(count)


Fixed, accepted submission:

a, b, x = map(int, input().split())

all_count = 0
dev = 0
if b > 0:
    all_count = b // x

if a > 0:
    dev = (a-1) // x
else:
    dev = -1
print(all_count - dev)
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
A, B = map(float, input().split())
F = A * B
print(round(F))

Fixed, accepted submission:
A, B = input().split()
A = int(A)
B = float(B)
X = A * round(100*B)
print(X//100)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):

N=int(input())

print(N%1000)


Fixed, accepted submission:
N=int(input())

if N%1000==0:
    print(0)
else:
    print(1000-N%1000)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print (n % 1000)


Fixed, accepted submission:
n = int(input())
m = n % 1000
if m == 0:
    print(0)
else:
    print(1000 - m)
Problem:
Given is a rooted tree with N vertices numbered 1 to N. The root is Vertex 1, and the i-th edge (1 \leq i \leq N - 1) connects Vertex a_i and b_i.  Each of the vertices has a counter installed. Initially, the counters on all the vertices have the value 0.  Now, the following Q operations will be performed:    * Operation j (1 \leq j \leq Q): Increment by x_j the counter on every vertex contained in the subtree rooted at Vertex p_j.  Find the value of the counter on each vertex after all operations.

Incorrect submission (verdict: Wrong Answer):
m=lambda:map(int,input().split())
n,q=m()
edges=[set()for _ in range(n)]
for i in range(n-1):
    a,b=m()
    a-=1;b-=1
    edges[a].add(b);edges[b].add(a)
rank={}
R=[0]
par={}
r=0;rep=[];pre=[0]
cnt=n-1
ok=[0]*n
ok[0]=1
while cnt!=0:
    ret=0;r+=1
    for i in pre:
        for j in edges[i]:
            if ok[j]:continue
            ok[j]=1
            rank[j]=r
            ret+=1
            par[j]=i
            rep.append(j)
    cnt-=ret
    pre=rep;rep=[]
    R+=pre
cou=[0]*n
for _ in range(q):
    root,v=m()
    root-=1
    cou[root]+=v
rcou=[0]*n;rcou[0]=cou[0]
print(cou[0])
for i in R[1:]:
    p=cou[i]+rcou[par[i]]
    print(p)
    rcou[i]=p

Fixed, accepted submission:
import sys
input=sys.stdin.buffer.readline
inputs=sys.stdin.buffer.readlines
sys.setrecursionlimit(10**9)
n, q = map(int, input().split())
edges=[[] for i in range(1+n)]
for i in range(n-1):
    
    _,__=map(int,input().split())
    edges[_].append(__)
    edges[__].append(_)
    """
"""
cnt=[0]*(1+n)
for i in range(q):
    x,p=map(int,input().split())
    cnt[x]+=p
def f(now,pars_value,par):
    cnt[now]+=pars_value
    a=cnt[now]
    for i in edges[now]:
        if i!=par:f(i,a,now)
f(1,0,-1)
print(*cnt[1:])
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
k=int(input())
c=0
while a>=b:
	b*=2
	c+=1
while b>=c:
	c*=2
	c+=1
if c<=k:
	print('Yes')
else:print('No')

Fixed, accepted submission:
a,b,c=map(int,input().split())
k=int(input())
ans=0
while a>=b:
	b*=2
	ans+=1
while b>=c:
	c*=2
	ans+=1
if ans<=k:
	print('Yes')
else:print('No')
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3



Fixed, accepted submission:
N, L = [int(i) for i in input().split()]
S = sorted([input() for _ in range(N)])

print(*S, sep="")
Problem:
To become a millionaire, M-kun has decided to make money by trading in the next N days. Currently, he has 1000 yen and no stocks - only one kind of stock is issued in the country where he lives.  He is famous across the country for his ability to foresee the future. He already knows that the price of one stock in the next N days will be as follows:    * A_1 yen on the 1-st day, A_2 yen on the 2-nd day, ..., A_N yen on the N-th day.  In the i-th day, M-kun can make the following trade **any number of times** (possibly zero), **within the amount of money and stocks that he has at the time**.    * Buy stock: Pay A_i yen and receive one stock.   * Sell stock: Sell one stock for A_i yen.  What is the maximum possible amount of money that M-kun can have in the end by trading optimally?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))

prev = a[0]
mon = 1000
stc = 0

for i in range(1, n):
    print(prev)
    if prev < a[i]:
        stc = mon // prev
        mon = mon - stc * prev
        print("stc = {} mon = {}" .format(stc, mon))
    elif prev > a [i]:
        mon = mon + stc * prev
        stc = 0
        print("stc = {} mon = {}" .format(stc, mon))
    prev = a[i]

if stc != 0:
    mon = mon + stc * a[n - 1]

print(mon)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))

prev = a[0]
mon = 1000
stc = 0

for i in range(1, n):
    #print(prev)
    if prev < a[i]:
        stc = mon // prev
        mon = mon - stc * prev
        mon = stc * a[i] + mon
        #print("stc = {} mon = {}" .format(stc, mon))
    elif prev >= a [i]:
        pass
        #print("stc = {} mon = {}" .format(stc, mon))
    prev = a[i]

#mon = mon + stc * a[n - 1]

print(mon)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
n0 = int(n/1.08)

while int(n0 * 1.08) < n:
    n0 += 1

if int(n0 * 1.08) == n:
    print(int(n0 * 1.08))
else:
    print(':(')

Fixed, accepted submission:
n = int(input())
n0 = int(n/1.08)

while int(n0 * 1.08) < n:
    n0 += 1

if int(n0 * 1.08) == n:
    print(n0)
else:
    print(':(')
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a, b, c = input().split()
if a[-1]==b[0] and b[-1]==c[0]:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a, b, c = input().split()
if a[-1]==b[0] and b[-1]==c[0]:
  print("YES")
else:
  print("NO")
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
(w, h, n) = map(int, input().split())

minx = 0
maxx = w
miny = 0
maxy = h

for i in range(n):
	x, y, a = map(int, input().split())

	if a == 1:
		maxx = min(maxx, x)
	elif a == 2:
		minx = max(minx, x)
	elif a == 3:
		maxy = min(maxy, y)
	else:
		miny = max(miny, y)

ans = (maxx - minx) * (maxy - miny)

if minx < maxx and miny < maxy:
	print(ans)
else:
	print(0)

Fixed, accepted submission:

(w, h, n) = map(int, input().split())

minx = 0
maxx = w
miny = 0
maxy = h

for i in range(n):
	x, y, a = map(int, input().split())

	if a == 2:
		maxx = min(maxx, x)
	elif a == 1:
		minx = max(minx, x)
	elif a == 4:
		maxy = min(maxy, y)
	else:
		miny = max(miny, y)

ans = (maxx - minx) * (maxy - miny)

if minx < maxx and miny < maxy:
	print(ans)
else:
	print(0)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
import math

is_no = 0
num1, num2 = map(int, input().split())
str1 = input()
table = list(str1)
print(table)
for i in range(num1):
    if table[i].isdigit():
        continue
    else:
        is_no = 1
if table[num1] != '-':
    is_no = 1
for j in range(num2, num1+num2+1):
    if table[j].isdigit():
        continue
    else:
        is_no = 1
if is_no == 0:
    print('Yes')
elif is_no == 1:
    print('No')


Fixed, accepted submission:
import math

is_no = 0
num1, num2 = map(int, input().split())
str1 = input()
table = list(str1)
count = 0
for i in range(len(str1)):
    if table[i] == '-':
        count += 1
    else:
        continue
if count == 1 and table[num1] =='-':
    print('Yes')
else:
    print('No')
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())
print(N*2-A)


Fixed, accepted submission:
N = int(input())
A = int(input())
print(N**2-A)