TnT/CodeNet4Repair huggingface dataset:
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin

n, a, b = [int(x) for x in stdin.readline().strip().split()]
s = stdin.readline()

a = a + b
all_num = 0
oversea_num = 0

for t in s:
  if t == 'a':
    if all_num < a:
      print('Yes')
      all_num += 1
    else:
      print('No')
  elif t == 'b':
    if oversea_num < b and all_num < a:
      print('Yes')
      all_num += 1
      oversea_num += 1
    else:
      print('No')
  else:
    print('No')

Fixed, accepted submission:
N, A, B = map(int, input().split())
S = input()

clears = 0
clears_foreigner = 0

for s in S:
    if s == "a" and clears < A + B:
        print("Yes")
        clears += 1
    elif s == "b" and clears < A + B and clears_foreigner < B:
        print("Yes")
        clears += 1
        clears_foreigner += 1
    else:
        print("No")
Problem:
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.  He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.  To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.  How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = [int(x) for x in input().split()]
B = [int(x) for x in input().split()]
C = [int(x) for x in input().split()]

ans = 0
for a in A:
    B_a = [b > a for b in B]
    for b in B_a:
        C_b = [c > b for c in C]
        ans += len(C_b)
print(ans)

Fixed, accepted submission:
import bisect as bs

def main():
    with open(0) as f:
        N = int(f.readline())
        A = sorted(list(map(int, f.readline().split())))
        B = list(map(int, f.readline().split()))
        C = sorted(list(map(int, f.readline().split())))

    ans = 0
    for b in B:
        ans += bs.bisect_left(A, b) * (N-bs.bisect_right(C, b))
    print(ans)

main()
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int, input().split())
k=int(input())

d=k
for i in range(k):
  if b < a:
    b = b*2
  if b > a:
    d=d-k
    break;

for i in range(d):
  if c < b:
    c = c*2
  if c > b:
    break;
  
if a < b and b < c:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
a,b,c = map(int, input().split())
k=int(input())
 
count=0
while a >= b:
  b *= 2
  count+=1
 
while b >= c:
  c *=2
  count+=1
 
if count <= k:
  print('Yes')
else:
  print('No')
Problem:
You are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N). Your objective is to remove some of the elements in a so that a will be a **good sequence**.  Here, an sequence b is a **good sequence** when the following condition holds true:    * For each element x in b, the value x occurs exactly x times in b.  For example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.  Find the minimum number of elements that needs to be removed so that a will be a good sequence.

Incorrect submission (verdict: Wrong Answer):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

n = int(readline())
a = list(map(int, read().split()))

dic = {}
ans = 0

for i in range(n):
  ans += 1
  try:
    dic[a[i]] += 1
    if dic[a[i]] == a[i]:
      ans -= a[i]
  except KeyError:
    dic[a[i]] = 1
    if dic[a[i]] == a[i]:
      ans -= a[i]

print(dic)
print(ans)


Fixed, accepted submission:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

n = int(readline())
a = list(map(int, read().split()))

dic = {}
ans = 0

for i in range(n):
  ans += 1
  try:
    dic[a[i]] += 1
    if dic[a[i]] == a[i]:
      ans -= a[i]
  except KeyError:
    dic[a[i]] = 1
    if dic[a[i]] == a[i]:
      ans -= a[i]

print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if a <= c and b >= c:
    print("YES")
else:
    print("NO")


Fixed, accepted submission:
a, b, c = map(int, input().split())
if a <= c and b >= c:
    print("Yes")
else:
    print("No")
Problem:
Binary trees are defined recursively. A binary tree _T_ is a structure defined on a finite set of nodes that either    * contains no nodes, or   * is composed of three disjoint sets of nodes:   \- a root node.   \- a binary tree called its left subtree.   \- a binary tree called its right subtree.    Your task is to write a program which perform tree walks (systematically traverse all nodes in a tree) based on the following algorithms:    1. Print the root, the left subtree and right subtree (preorder).   2. Print the left subtree, the root and right subtree (inorder).   3. Print the left subtree, right subtree and the root (postorder).  Here, the given binary tree consists of _n_ nodes and evey node has a unique ID from 0 to _n_ -1.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
tree = [[] for i in range(n)]
for i in range(n):
    id, left, right = map(int, input().split())
    tree[id] = [left, right]

def preoder(id):
    if id == -1:
        return
    print(' ' + str(id), end='')
    preoder(tree[id][0])
    preoder(tree[id][1])

def inorder(id):
    if id == -1:
        return
    inorder(tree[id][0])
    print(' ' + str(id), end='')
    inorder(tree[id][1])

def postorder(id):
    if id == -1:
        return
    postorder(tree[id][0])
    postorder(tree[id][1])
    print(' ' + str(id), end='')

print('Preoder')
preoder(0)
print('')
print('Inorder')
inorder(0)
print('')
print('Postorder')
postorder(0)



Fixed, accepted submission:
n = int(input())
tree = [[-1, -1, True] for i in range(n)]
for i in range(n):
    id, left, right = map(int, input().split())
    if left != -1:
        tree[id][0] = left
        tree[left][2] = False
    if right != -1:
        tree[id][1] = right
        tree[right][2] = False

def preoder(id):
    if id == -1:
        return
    print(' ' + str(id), end='')
    preoder(tree[id][0])
    preoder(tree[id][1])

def inorder(id):
    if id == -1:
        return
    inorder(tree[id][0])
    print(' ' + str(id), end='')
    inorder(tree[id][1])

def postorder(id):
    if id == -1:
        return
    postorder(tree[id][0])
    postorder(tree[id][1])
    print(' ' + str(id), end='')

root = 0
for i, node in enumerate(tree):
    if node[2] == True:
        root = i

print('Preorder')
preoder(root)
print('')
print('Inorder')
inorder(root)
print('')
print('Postorder')
postorder(root)
print('')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
word_list = ['AC','WA','TLE','RE']
A = 0
W = 0
T = 0
R = 0

for i in range(n):
    s = input()
    if s == 'AC':
        A = A + 1
    elif s == 'WA':
        W = W + 1
    elif s == 'TLE':
        T = T + 1
    else:
        R = R + 1
Ans_list = [A,W,T,R]
for i in range(4):
    print(str(word_list[i])+ ' × '+ str(Ans_list[i]))

Fixed, accepted submission:
n=int(input())
word_list = ['AC','WA','TLE','RE']
A = 0
W = 0
T = 0
R = 0

for i in range(n):
    s = input()
    if s == 'AC':
        A = A + 1
    elif s == 'WA':
        W = W + 1
    elif s == 'TLE':
        T = T + 1
    else:
        R = R + 1
Ans_list = [A,W,T,R]
for i in range(4):
    print(str(word_list[i])+ ' x '+ str(Ans_list[i]))
Problem:
Your task is to perform a simple table calculation.  Write a program which reads the number of rows r, columns c and a table of r × c elements, and prints a new table, which includes the total sum for each row and column.

Incorrect submission (verdict: Wrong Answer):
r, c = map(int,input().split())
for i in range(r):
        a=list(map(int,input().split()))
        a_str=map(str,a)
        print(" ".join(a_str)+" "+str(sum(a)))

Fixed, accepted submission:
r, c = map(int,input().split())
b=[]
for i in range(r):    
        a=list(map(int,input().split()))
        a.append(sum(a))
        b.append(a)
        a=map(str,a)
        print(" ".join(a))
d=[]
for i in range(c+1):
    cs=[]
    for j in range(r):
        cs.append(b[j][i])
    d.append(sum(cs))
d=map(str,d)
print(" ".join(d))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math
X=float(input())
i=0
y= 100

while X >= y:
	i=i+1
	y=y*1.01
	y=math.floor(y)

print(i)



Fixed, accepted submission:
import math
import sys

X=int(input())
i=0
y= 100

if X==y:
	print(i)
	sys.exit()

while X > y:
	i=i+1
	y=y*1.01
	y=math.floor(y)
	if X==y:
		print(i)
		sys.exit()

print(i)
Problem:
Snuke has N integers: 1,2,\ldots,N. He will choose K of them and give those to Takahashi.  How many ways are there to choose K consecutive integers?

Incorrect submission (verdict: Wrong Answer):
N,K = map(int,input().split())
ans = K-N+1
print(ans)

Fixed, accepted submission:
N,K = map(int,input().split())
ans = N-K+1
print(ans)
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
N=input()
print(N[3:])

Fixed, accepted submission:
print('ABC'+input())
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int, input().split())

if a > x:
  print('No')
elif a+b < x:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
a,b,x = map(int, input().split())

if a > x:
  print('NO')
elif a+b < x:
  print('NO')
else:
  print('YES')
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())
s = input()

x = A + B
cnt = 1
rank = 1
for i in range(N):
    y = s[i : i+1]
    if cnt <= x:
        if y == "a":
            print("yes")
            cnt += 1
        elif y == "b" and rank <= B:
            print("yes")
            cnt += 1
            rank += 1
        else:
            print("No")
    else:
        print("No")

Fixed, accepted submission:
N, A, B = map(int, input().split())
s = input()

x = A + B
cnt = 1
rank = 1
for i in range(N):
    y = s[i : i+1]
    if cnt <= x:
        if y == "a":
            print("Yes")
            cnt += 1
        elif y == "b" and rank <= B:
            print("Yes")
            cnt += 1
            rank += 1
        else:
            print("No")
    else:
        print("No")
Problem:
To become a millionaire, M-kun has decided to make money by trading in the next N days. Currently, he has 1000 yen and no stocks - only one kind of stock is issued in the country where he lives.  He is famous across the country for his ability to foresee the future. He already knows that the price of one stock in the next N days will be as follows:    * A_1 yen on the 1-st day, A_2 yen on the 2-nd day, ..., A_N yen on the N-th day.  In the i-th day, M-kun can make the following trade **any number of times** (possibly zero), **within the amount of money and stocks that he has at the time**.    * Buy stock: Pay A_i yen and receive one stock.   * Sell stock: Sell one stock for A_i yen.  What is the maximum possible amount of money that M-kun can have in the end by trading optimally?

Incorrect submission (verdict: Wrong Answer):
import sys
input=sys.stdin.readline
n=int(input())
arr=list(map(int,input().split()))
have=0
ans=0
rate=0
for i in range(n-1):
    #print(have)
    if(have!=0):
        if(arr[i+1]<arr[i]):
            ans+=have*(arr[i]-rate)
            have=0
    else:
        if(arr[i+1]>arr[i]):
            have=1000//arr[i]
            rate=arr[i]
#print(have)
if(have!=0):
    ans+=have*(arr[-1]-rate)
    have=0
print(ans+1000)            
    
           
        

    

Fixed, accepted submission:
import sys
input=sys.stdin.readline
n=int(input())
arr=list(map(int,input().split()))
have=0
ans=1000
rate=0
for i in range(n-1):
    
    if(have!=0):
        if(arr[i+1]<arr[i]):
            ans+=have*(arr[i]-rate)
            have=0
    else:
        if(arr[i+1]>arr[i]):
            have=ans//arr[i]
            rate=arr[i]
    #print(have,ans,rate)
#print(have)
if(have!=0):
    ans+=have*(arr[-1]-rate)
    have=0
print(ans)
Problem:
You are given a string S of length N consisting of `(` and `)`. Your task is to insert some number of `(` and `)` into S to obtain a _correct bracket sequence_.   Here, a correct bracket sequence is defined as follows:    * `()` is a correct bracket sequence.   * If X is a correct bracket sequence, the concatenation of `(`, X and `)` in this order is also a correct bracket sequence.   * If X and Y are correct bracket sequences, the concatenation of X and Y in this order is also a correct bracket sequence.   * Every correct bracket sequence can be derived from the rules above.  Find the shortest correct bracket sequence that can be obtained. If there is more than one such sequence, find the lexicographically smallest one.

Incorrect submission (verdict: Wrong Answer):
N, S = open(0)

cnt = left = 0
for s in S:
    if s == "(":
        cnt += 1
    else:
        cnt -= 1

    if cnt < 0:
        left = max(left, -cnt)

S = "(" * left + S

right = 0
for s in S:
    if s == "(":
        right += 1
    else:
        right -= 1

S = S + ")" * right

print(S)

Fixed, accepted submission:
N, S = open(0)
S = S.strip()

cnt = left = 0
for s in S:
    if s == "(":
        cnt += 1
    else:
        cnt -= 1

        if cnt < 0:
            left = max(left, -cnt)

S = "(" * left + S

right = 0
for s in S:
    if s == "(":
        right += 1
    else:
        right -= 1

S = S + ")" * right

print(S)
Problem:
There are N dishes of cuisine placed in front of Takahashi and Aoki. For convenience, we call these dishes Dish 1, Dish 2, ..., Dish N.  When Takahashi eats Dish i, he earns A_i points of _happiness_ ; when Aoki eats Dish i, she earns B_i points of happiness.  Starting from Takahashi, they alternately choose one dish and eat it, until there is no more dish to eat. Here, both of them choose dishes so that the following value is maximized: "the sum of the happiness he/she will earn in the end" minus "the sum of the happiness the other person will earn in the end".  Find the value: "the sum of the happiness Takahashi earns in the end" minus "the sum of the happiness Aoki earns in the end".

Incorrect submission (verdict: Wrong Answer):
from operator import itemgetter
N = int(input())
dish = [[0 for _ in range(3)] for _ in range(N)]
Takahashi = []
Aoki = []
for i in range(N):
    dish[i][0],dish[i][1] = [int(x) for x in input().split()]
    dish[i][2] = dish[i][0]+dish[i][1]
dish.sort(key=itemgetter(2),reverse=True)
for i in range(int(N/2)):
    Takahashi.append(dish[2*i][0])
    if(2*i<=N-2):
        Aoki.append(dish[2*i+1][1])
print(sum(Takahashi)-sum(Aoki))

Fixed, accepted submission:
N = int(input())
dish = [[0 for _ in range(3)] for _ in range(N)]
Takahashi = []
Aoki = []
for i in range(N):
    dish[i][0],dish[i][1] = [int(x) for x in input().split()]
    dish[i][2] = dish[i][0]+dish[i][1]
dish.sort(key=lambda x:(x[2],x[0],x[1]),reverse=True)
for i in range(N):
    if(i%2==0):
        Takahashi.append(dish[i][0])
    else:
        Aoki.append(dish[i][1])

print(sum(Takahashi)-sum(Aoki))
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
if(N%2==0):
  print(N/2-1)
else:
  print(N//2)

Fixed, accepted submission:
N = int(input())
if(N%2==0):
  print(N//2-1)
else:
  print(N//2)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A, B, X = map(int,input().split())

if A > X or A + B < X:
    print('No')
else:
    print('Yes')

Fixed, accepted submission:
A, B, X = map(int,input().split())

if A > X or A + B < X:
    print('NO')
else:
    print('YES')
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
import re




s = input().replace('?', '.')
t = input()
print("s,t:", s, t)

for i in range(len(s) - len(t), -1, -1):
    
    if re.match(s[i:i + len(t)], t):
        #print(s[i:i + len(t)], t)
        s = s.replace('.', 'a')
        print(s[:i] + t + s[i + len(t):])
        exit()

print('UNRESTORABLE')


Fixed, accepted submission:
import re




s = input().replace('?', '.')
t = input()
#print("s,t:", s, t)

for i in range(len(s) - len(t), -1, -1):
    
    if re.match(s[i:i + len(t)], t):
        #print(s[i:i + len(t)], t)
        s = s.replace('.', 'a')
        print(s[:i] + t + s[i + len(t):])
        exit()

print('UNRESTORABLE')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

wa = 0
ac = 0
tle = 0
re = 0

for i in range(n):
  x = input()
  if x == "RE": re+=1
  if x == "TLE": tle+=1
  if x == "AC": ac+=1
  if x == "WA": wa+=1

print("AC × "+str(ac))
print("WA × "+str(wa))
print("TLE × "+str(tle))
print("RE × "+str(re))

Fixed, accepted submission:
n = int(input())

wa = 0
ac = 0
tle = 0
re = 0

for i in range(n):
  x = input()
  if x == "RE": re+=1
  if x == "TLE": tle+=1
  if x == "AC": ac+=1
  if x == "WA": wa+=1

print("AC x "+str(ac))
print("WA x "+str(wa))
print("TLE x "+str(tle))
print("RE x "+str(re))