TnT/CodeNet4Repair huggingface dataset:
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
num = int(input())
a = [int(e) for e in input().split()]
cnt = 0   
while 1:
  cnt = 0
  for i in range(num):
    if a[i]%2 != 0:
      cnt += 1
  if cnt != 0:
    break
  for i in range(num):
    a[i] = int(a[i]/2)
  
print(a)

Fixed, accepted submission:
num = int(input())
a = [int(e) for e in input().split()]
cnt = 0   
cnt2 = 0
while 1:
  cnt = 0
  for i in range(num):
    if a[i]%2 != 0:
      cnt += 1
  if cnt != 0:
    break
  for i in range(num):
    a[i] = int(a[i]/2)
  cnt2 += 1
  
print(cnt2)
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int, input().split())
if c>=(a+b):
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b,c=map(int, input().split())
if c<=(a+b):
    print("Yes")
else:
    print("No")
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
N=int(input())

Z=[0]*10005
for i in range(1,102):
    for j in range(1,102):
        for k in range(1,102):
            n=i**2+j**2+k**2+i*j+j*k+k*i
            if n<=N:
                Z[n]+=1
for i in range(N+1):
    print(Z[i])

Fixed, accepted submission:
N=int(input())

Z=[0]*10005
for i in range(1,102):
    for j in range(1,102):
        for k in range(1,102):
            n=i**2+j**2+k**2+i*j+j*k+k*i
            if n<=N:
                Z[n-1]+=1
for i in range(N):
    print(Z[i])
Problem:
Snuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.  Snuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:    * Operation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.  For example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure. If the die is rotated toward the right as shown in the figure, the side showing 3 will face upward. Besides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.    Find the minimum number of operation Snuke needs to perform in order to score at least x points in total.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
ans = 2 * x // 11

m = x % 11
if m >= 7:
    ans += 2
elif m >= 1:
    ans += 1
print(ans)

Fixed, accepted submission:
x = int(input())
ans = x // 11
ans *= 2

m = x % 11
if m >= 7:
    ans += 2
elif m >= 1:
    ans += 1
print(ans)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
X = int(input())

base = 100
rate = 1.01
year = 1

while True:
    base = base * rate // 1
    if base > X:
        print(year)
        break
    year += 1

Fixed, accepted submission:
import math

X = int(input())

base = 100
rate = 1.01
year = 1

while True:
    base = math.floor(base) * rate
    if base > X:
        print(year)
        break
    year += 1
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):

a = input()

b = input()

h = input()


print((int(a) + int(b)) * int(h) / 2)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())
print((a+b)*h//2)
Problem:
Write a program which reads an directed graph $G = (V, E)$, and finds the shortest distance from vertex $1$ to each vertex (the number of edges in the shortest path). Vertices are identified by IDs $1, 2, ... n$.

Incorrect submission (verdict: Wrong Answer):
#coding:utf-8
n = int(input())
Q = [1]
M = [[False for i in range(n)] for j in range(n)]
dataList = []
for i in range(n):
    data = list(map(int,input().split()))
    dataList.append(data)
    for j in range(data[1]):
        v = data[j+2] - 1
        M[i][v] = True
color = ["white" for i in range(n)]
d = [0 for i in range(n)]

while Q != []:
    u = Q.pop() - 1
    color[u] = "gray"
    data = dataList[u]
    for i in range(data[1]):
        v = data[i+2] - 1
        if M[u][v] == True and color[v] == "white":
            d[v] = d[u] + 1
            Q.append(v+1)
    color[u] = "black"

print(" ".join([str(num) for num in d]))
    



Fixed, accepted submission:
#coding: utf-8
inf = 100000000
n = int(input())

List = [0] + [list(map(int,input().split())) for i in range(n)]
d = [inf for i in range(n+1)]
color = ["white" for i in range(n+1)]

s = 1
Q = [s]
d[s] = 0
color[s] = "gray"

while Q != []:
    q = Q.pop(0)
    k = List[q][1]
    for i in List[q][2:2+k]:
        if color[i] == "white":
            Q.append(i)
        d[i] = min(d[q] + 1, d[i])
    color[q] = "gray"


for i, dis in enumerate(d[1:], 1):
    if dis == inf:
        dis = -1
    print(i, dis)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = list(map(int, input().split()))

x = max(b)
y = min(c)

p = max(a[2],x)
q = min(a[3],y)

if q-p > 0:
    print("No war")
else:
    print("War")

Fixed, accepted submission:
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = list(map(int, input().split()))

x = max(b)
y = min(c)

p = max(a[2],x)
q = min(a[3],y)

if q-p > 0:
    print("No War")
else:
    print("War")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if n % 1000 == 0:
    print(0)
else:
    s = n // 1000
    print(s + 1)

Fixed, accepted submission:
n = int(input())
if n % 1000 == 0:
    print(0)
else:
    s = n // 1000 + 1
    print(1000*s - n)
Problem:
There is an empty array. The following N operations will be performed to insert integers into the array. In the i-th operation (1≤i≤N), b_i copies of an integer a_i are inserted into the array. Find the K-th smallest integer in the array after the N operations. For example, the 4-th smallest integer in the array \\{1,2,2,3,3,3\\} is 3.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
d = [[0] * 2 for i in range(n)]
for i in range(n):
    d[i][0], d[i][1] = map(int, input().split())

d = sorted(d)
s = 0
ans = 0
for a, b in d:
    s += b
    if (s > k):
        break
    ans = a

print(ans)


Fixed, accepted submission:
n, k = map(int, input().split())
d = [[0] * 2 for i in range(n)]
for i in range(n):
    d[i][0], d[i][1] = map(int, input().split())

d = sorted(d)
s = 0
ans = 0
for a, b in d:
    s += b
    ans = a
    if (s >= k):
        break


print(ans)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
s = input()
tc = [ chr(i)*2 for i in range(ord('a'), ord('z')+1) ]  + [ chr(i)+chr(j)+chr(i) for i in range(ord('a'), ord('z')+1) for j in range(ord('a'), ord('z')+1)]
if len(s) == 2:
  if s[0] == s[1]:
    print(1, 2)
  else:
    print(-1, -1)
else:
  for i in tc:
    if i in s:
      t = i
      break
    else:
      t = 0
  if t == 0:
    print(-1, -1)
  else:
    for i in range(len(s)-len(t)+1):
      if s[i:i+len(t)] == t:
        if len(t) == 2:
          if i+len(t)+1 > len(s):
            print(i, i+len(t))
          
          else:
            print(i+1, i+len(t)+1)
        elif len(t) == 3:
          print(i+1, i+len(t))

Fixed, accepted submission:
N = int(input())
print((N+1)*N//2)
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):
n,k=map(lambda x: int(x), input().split())
a=list(map(lambda x: int(x), input().split()))
dic={}
for i in range(n):
    dic[a[i]]=dic.get(a[i],0)+1
count=list(dic.values())
count.sort(reverse=True)
print(count)
if len(count) <= k:
    print(0)
else:
    print(sum(count[k:]))

Fixed, accepted submission:
n,k=map(lambda x: int(x), input().split())
a=list(map(lambda x: int(x), input().split()))
dic={}
for i in range(n):
    dic[a[i]]=dic.get(a[i],0)+1
count=list(dic.values())
count.sort(reverse=True)
if len(count) <= k:
    print(0)
else:
    print(sum(count[k:]))
Problem:
Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int, input().split()))
cnt = 0
for i in range(a[0], a[1] + 1, 1):
    if a[2] % i == 0:
        cnt += 1

Fixed, accepted submission:
z = input()
a = list(map(int, z.split()))
cnt = 0
for i in range(a[0], a[1] + 1, 1):
    if a[2] % i == 0:
        cnt += 1
print(cnt)
Problem:
We have a grid with N rows and M columns of squares. Initially, all the squares are white.  There is a button attached to each row and each column. When a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa. When a button attached to a column is pressed, the colors of all the squares in that column are inverted.  Takahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.

Incorrect submission (verdict: Wrong Answer):
print('Later')

Fixed, accepted submission:
n, m, k = map(int, input().split())
ans = 'No'
for i in range(n+1):
    for j in range(m+1):
        if i*(m-j)+j*(n-i)==k:
            ans = 'Yes'
            break
print(ans)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
# -*- coding: utf-8 -*-

n = int(input())
a = list(map(int,input().split()))

def check(ar):
    b = True
    for i in range(len(ar)):
        if ar[i] % 2 != 0:
            b = False
            break
    return b

answer = 0

for i in range(1000000000):
    if check(a) == True:
        for j in range(len(a)):
            a[j] = int(a[j]/2)
        answer += 1

print(answer)


Fixed, accepted submission:
# -*- coding: utf-8 -*-

n = int(input())
a = list(map(int,input().split()))

flag = False
cnt = 0

for i in range(10000000000):
    for j in range(n):
        if a[j] % 2 == 0:
            a[j] = int(a[j] / 2)
        else:
            flag = True
            break
    if flag == True:
        break
    else:
        cnt += 1

print(cnt)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Time Limit Exceeded):
n = 10**4
k = [0]*10**4
for x in range(1,10):
    for y in range(1,10):
        for z in range(1,10):
            for i in range(n+1):
                if x**2 + y** 2 + z**2 + x*y + y*z + z*x == i:
                    k[i-1] += 1
for i in range(int(input())):
    print(k[i])

Fixed, accepted submission:
n = 10**4
ans = [0]*10**4
for x in range(1,100):
    for y in range(1,100):
        for z in range(1,100):
            a = (x+y+z)**2 -(x*y+y*z+z*x)
            if a <= n:
                ans[a-1] += 1
for i in range(int(input())):
    print(ans[i])
Problem:
縦 8、横 8 のマスからなる図 1 のような平面があります。   □| □| □| □| □| □| □| □   ---|---|---|---|---|---|---|---   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □      図１   ---       この平面上に、以下の A から G の図形のどれかが一つだけ置かれています。  | A   ---   ■| ■| |   ---|---|---|---   ■| ■| |   | | |   | | |   | B   ---   | ■| |   ---|---|---|---   | ■| |   | ■| |   | ■| |   | C   ---   ■| ■| ■| ■   ---|---|---|---   | | |   | | |   | | |      | D   ---   | ■| |   ---|---|---|---   ■| ■| |   ■| | |   | | |   | E   ---   ■| ■| |   ---|---|---|---   | ■| ■|   | | |   | | |   | F   ---   ■| | |   ---|---|---|---   ■| ■| |   | ■| |   | | |   | G   ---   | ■| ■|   ---|---|---|---   ■| ■| |   | | |   | | |       たとえば、次の図 2 の例では E の図形が置かれています。   | □| □| □| □| □| □| □| □   ---|---|---|---|---|---|---|---   □| □| □| □| □| □| □| □   □| ■| ■| □| □| □| □| □   □| □| ■| ■| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □   □| □| □| □| □| □| □| □      図２   ---       平面の中で図形が占めているマスを 1、占めていないマスを 0 で表現した数字の列を読み込んで、置かれている図形の種類（A〜G）を出力するプログラムを作成してください。  ただし、ひとつの平面に置かれている図形は必ず１つで、複数の図形が置かれていることはありません。また、A〜G で表される図形以外のものが置かれていることはありません。

Incorrect submission (verdict: Wrong Answer):
maxl = 8

offsetV = ('A', 'B', 'C', 'D', 'E', 'F', 'G')
offset = (((0, 1), (1, 0), (1, 1)),
          ((0, 1), (0, 2), (0, 3)),
          ((1, 0), (2, 0), (3, 0)),
          ((0, 1), (-1, 1), (-1, 2)),
          ((1, 0), (1, 1), (2, 1)),
          ((0, 1), (1, 1), (1, 2)),
          ((1, 0), (-1, 1), (0, 1)),
          )


def match(l, x, y, oi):
    for offX, offY in [a for a in offset[oi]]:
        if 0 <= x + offX  <= maxl and 0 <= y + offY < maxl:
            pass
        else:
            return False

        if l[y + offY][x + offX] == '0':
            return False
    return True


def solve():
    l = [input() for i in range(9)]
    for y in range(7):
        for x in range(7):
            if l[y][x] == '1':
                for o in range(7):
                    if match(l, x, y, o):
                        return offsetV[o]



try:
    while 1:
        print(solve())
except:
    pass

Fixed, accepted submission:
maxl = 8

offsetV = ('A', 'B', 'C', 'D', 'E', 'F', 'G')
offset = (((0, 1), (1, 0), (1, 1)),
          ((0, 1), (0, 2), (0, 3)),
          ((1, 0), (2, 0), (3, 0)),
          ((0, 1), (-1, 1), (-1, 2)),
          ((1, 0), (1, 1), (2, 1)),
          ((0, 1), (1, 1), (1, 2)),
          ((1, 0), (-1, 1), (0, 1)),
          )


def match(l, x, y, oi):
    for offX, offY in [a for a in offset[oi]]:
        if 0 <= x + offX < maxl and 0 <= y + offY < maxl:
            pass
        else:
            return False

        if l[y + offY][x + offX] == '0':
            return False
    return True


def solve():
    l = [input() for i in range(8)]
    for y in range(8):
        for x in range(8):
            if l[y][x] == '1':
                for o in range(7):
                    if match(l, x, y, o):
                        return offsetV[o]



try:
    while 1:
        print(solve())
        l = input()
except:
    pass
Problem:
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.  Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.  Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)  At most how much can he earn on balance?  Note that the same string may be written on multiple cards.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
from collections import defaultdict
s = defaultdict(int)
for i in range(n):
    si = input()
    s[si] += 1

m = int(input())
for i in range(m):
    ti = input()
    s[ti] -= 1

print(max(s[max(s)], 0))

Fixed, accepted submission:
n = int(input())
from collections import defaultdict
s = defaultdict(int)
for i in range(n):
    si = input()
    s[si] += 1

m = int(input())
for i in range(m):
    ti = input()
    s[ti] -= 1

print(max(0,max(s.values())))
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ns = list(map(int, input().split()))
print(n)

print(min(ns), max(ns), sum(ns))


Fixed, accepted submission:
n = int(input())
ns = list(map(int, input().split()))


print(min(ns), max(ns), sum(ns))
Problem:
You are given three integers, A, B and C.   Among them, two are the same, but the remaining one is different from the rest.   For example, when A=5,B=7,C=5, A and C are the same, but B is different.   Find the one that is different from the rest among the given three integers.

Incorrect submission (verdict: Wrong Answer):
arr = list(map(int,input().split()))
if arr[0]==arr[1]:
  print(arr[0])
else:
  print(arr[2])

Fixed, accepted submission:
a = list(map(int,input().split()))
a.sort()
print(a[0]*a[2]//a[1])
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
w,h,n=map(int,input().split())
w_d=0
h_d=0
for i in range(n):
  x,y,a=map(int,input().split())
  if a==0:
    w_d=max(w_d,x)
  if a==1:
    w=min(w,x)
  if a==2:
    h_d=max(h_d,y)
  if a==3:
    h=min(h,y)
if w<=w_d or h<=h_d:
  print(0)
else:
  print((w-w_d)*(h-h_d))

Fixed, accepted submission:
w,h,n=map(int,input().split())
w_d=0
h_d=0
for i in range(n):
  x,y,a=map(int,input().split())
  if a==1:
    w_d=max(w_d,x)
  if a==2:
    w=min(w,x)
  if a==3:
    h_d=max(h_d,y)
  if a==4:
    h=min(h,y)
if w<=w_d or h<=h_d:
  print(0)
else:
  print((w-w_d)*(h-h_d))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
x=int(input())
print((1000-x//1000)%1000)

Fixed, accepted submission:
x=int(input())
print((1000-x%1000)%1000)
Problem:
We have a grid with N rows and M columns of squares. Initially, all the squares are white.  There is a button attached to each row and each column. When a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa. When a button attached to a column is pressed, the colors of all the squares in that column are inverted.  Takahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.

Incorrect submission (verdict: Wrong Answer):
import itertools
N, M, K = [int(_) for _ in input().split()]
for i, j in itertools.product(range(N), range(M)):
    if (N-i)*j+i*(M-j) == K:
        print('YES')
        exit()
print('NO')


Fixed, accepted submission:
import itertools
N, M, K = [int(_) for _ in input().split()]
for i, j in itertools.product(range(N+1), range(M+1)):
    if (N-i)*j+i*(M-j) == K:
        print('Yes')
        exit()
print('No')
Problem:
Snuke has N strings. The i-th string is s_i.  Let us concatenate these strings into one string after arranging them in some order. Find the maximum possible number of occurrences of `AB` in the resulting string.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans = 0
b_x = 0
b_a = 0
x_a = 0
y = 0
for _ in range(N):
  s = input()
  ans += s.find('AB')
  if s[0] == 'B' and s[-1] == 'A':
    b_a += 1
  elif s[0] == 'B':
    b_x += 1
  elif s[-1] == 'A':
    x_a += 1
  else:
    y += 1
if x_a >= 1 and b_x >= 1:
  ans += b_a
elif x_a >= 1 or b_x >= 1:
  ans += b_a - 1
else:
  ans += b_a - 2
if x_a - 1 <= 0 or b_x -1 <= 0:
  ans += 0
else:
  ans += min(x_a - 1, b_x - 1)
print(ans)  

Fixed, accepted submission:
N = int(input())
ans = 0
b_x = 0
b_a = 0
x_a = 0
y = 0
for _ in range(N):
  s = input()
  ans += s.count('AB')
  if s[0] == 'B' and s[-1] == 'A':
    b_a += 1
  elif s[0] == 'B':
    b_x += 1
  elif s[-1] == 'A':
    x_a += 1
  else:
    y += 1
if x_a >= 1 and b_x >= 1:
  ans += b_a + 1	
elif x_a >= 1 or b_x >= 1:
  ans += b_a
else:
  if b_a > 0:
    ans += b_a - 1
if x_a - 1 <= 0 or b_x -1 <= 0:
  ans += 0
else:
  ans += min(x_a - 1, b_x - 1)
print(ans)
Problem:
You are given an integer sequence of length n, a_1, ..., a_n. Let us consider performing the following n operations on an empty sequence b.  The i-th operation is as follows:    1. Append a_i to the end of b.   2. Reverse the order of the elements in b.  Find the sequence b obtained after these n operations.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

A=list(map(int,input().split()))

B=[]
for i in range(1,n+1):
    C=[]
    B.append(A[i-1])
    for i in B[::-1]:
        C.append(i)
    B=C
    
print(B)

Fixed, accepted submission:
from collections import deque

n=int(input())

A=list(map(int,input().split()))

B=deque([])
if n%2==0:
    for i in range(n):
        if i%2==0:
            B.append(A[i])
        else:
            B.appendleft(A[i])
else:
    for i in range(n):
        if i%2==0:
            B.appendleft(A[i])
        else:
            B.append(A[i])
        

print(*B)