TnT/CodeNet4Repair huggingface dataset:
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
_=input();print("".join(sorted(list(input().split()))))

Fixed, accepted submission:
print("".join(sorted(open(0).read().split()[2:])))
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a = [1,3,5,7,8,10,12]
b = [4,6,9,11]

x,y = map(int,(input().split()))
cou1 = 0
cou2 = 0

for i in a:
    if i==x or i==y:
        cou1 += 1
for i in b:
    if i==x or i==y:
        cou2 += 1

if cou1>1 or cou2>1:
    print("YES")
else:
    print("NO")


Fixed, accepted submission:
a = [1,3,5,7,8,10,12]
b = [4,6,9,11]

x,y = map(int,(input().split()))
cou1 = 0
cou2 = 0

for i in a:
    if i==x or i==y:
        cou1 += 1
for i in b:
    if i==x or i==y:
        cou2 += 1

if cou1>1 or cou2>1:
    print("Yes")
else:
    print("No")
Problem:
Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Incorrect submission (verdict: Wrong Answer):
S = int(input())
h = (S / 3600)
m = int((S % 3600) % 60)
s = (S % 60)

print("{}:{}:{}".format(h,m,s))

Fixed, accepted submission:
S = int(input())
h = (S // 3600)
m = ((S % 3600) // 60)
s = (S % 60)
 
print("{}:{}:{}".format(h,m,s))
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
l = list(map(int,input().split()))
l_r = sorted(l,reverse=True)
Alice = l_r[::2]
Bob = l_r[1::2]

m =0
n = 0
for i in Alice:
    m += i
for j in Bob:
    n += j
print({m-n})


Fixed, accepted submission:
# a = int(input())
# b,c = map(int, input().split())

# print('{} {}'.format(a+b+c,s))
#
# a,b = map(int, input().split())
# if a*b%2 == 0:
#     print("Even")
# else :
#     print("Odd")
# l = list(input())
# l_new = [int(n) for n in l]
# count = 0


#         count += 1
# print(count)

# ans = 10 **9
# N = int(input())
# A = list(map(int,input().split()))

#     p = 0
#     while i % 2 ==0:

#         p += 1
#     if p < ans:
#         ans = p

# print(ans)




# a = int(input())
# b = int(input())
# c = int(input())
# X = int(input())
# count = 0

#     x = 500 * i
#     for j in range(b+1):

#         for k in range(c+1):



N = int(input())
l = list(map(int,input().split()))
l_r = sorted(l,reverse=True)
Alice = l_r[::2]
Bob = l_r[1::2]

m =0
n = 0
for i in Alice:
    m += i
for j in Bob:
    n += j
print(m-n)
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
if n >= 2*k-1:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
n, k = map(int, input().split())
if n >= 2*k-1:
    print('YES')
else:
    print('NO')
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
L = [0] * b
for i in range(1, b):
    s = (a * i) % b
    if L[s] == 1:
        print('No')
        break
    elif s == c:
        print('Yes')
        break
    else:
        L[s] = 1
else:
    print('No')


Fixed, accepted submission:
a, b, c = map(int, input().split())
L = [0] * b
for i in range(1, b):
    s = (a * i) % b
    if L[s] == 1:
        print('NO')
        break
    elif s == c:
        print('YES')
        break
    else:
        L[s] = 1
else:
    print('NO')
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
print('NO' if int(input().replace(' ',''))%4 else 'Yes')

Fixed, accepted submission:
print('NO' if int(input().replace(' ',''))%4 else 'YES')
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    N, M, X, Y = list(map(int, input().split()))
    x = list(map(int, input().split()))
    y = list(map(int, input().split()))

    mx = max(x)
    my = min(y)

    if mx >= my:
        print("War")
    else:
        m_list = [i for i in range(mx+1, my+1)]
        cap = [i for i in range(X+1, Y+1)]
        if len(set(m_list) & set(cap)) >= 1:
            print("No war")
        else:
            print("War")

Fixed, accepted submission:
if __name__ == '__main__':
    N, M, X, Y = list(map(int, input().split()))
    x = list(map(int, input().split()))
    y = list(map(int, input().split()))

    mx = max(x)
    my = min(y)

    lx = max(mx, X)
    ly = min(my, Y)
    if lx < ly:
        print("No War")
    else:
        print("War")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

print((a + b) * h / 2)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())

print(int((a + b) * h / 2))
Problem:
You are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N. Determine if we can repeat the following operation zero or more times so that the sequences a and b become equal.  Operation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions **simultaneously** :    * Add 2 to a_i.   * Add 1 to b_j.

Incorrect submission (verdict: Wrong Answer):
import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, tan, asin, acos, atan, radians, degrees, log2
from itertools import accumulate, permutations, combinations, combinations_with_replacement, product, groupby
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left, insort, insort_left
from fractions import gcd
from heapq import heappush, heappop
from functools import reduce
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def ZIP(n): return zip(*(MAP() for _ in range(n)))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10**9 + 7
from decimal import *

N = INT()
a = LIST()
b = LIST()

A = 0
B = 0

for i in range(N):
	if a[i] > b[i]:
		B += a[i]-b[i]
	elif a[i] < b[i]:
		A += b[i]-a[i]

if 2*B <= A:
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, tan, asin, acos, atan, radians, degrees, log2, gcd
from itertools import accumulate, permutations, combinations, combinations_with_replacement, product, groupby
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
from bisect import bisect, bisect_left, insort, insort_left
from heapq import heappush, heappop
from functools import reduce
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
def ZIP(n): return zip(*(MAP() for _ in range(n)))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7 
#mod = 998244353
from decimal import *
#import numpy as np
#decimal.getcontext().prec = 10

N = INT()
a = LIST()
b = LIST()

a_cnt = 0
b_cnt = 0

for i in range(N):
	if a[i] < b[i]:
		a_cnt += -(a[i]-b[i])//2
	elif a[i] > b[i]:
		b_cnt += a[i]-b[i]


if b_cnt <= a_cnt:
	print("Yes")
else:
	print("No")
Problem:
Joisino the magical girl has decided to turn every single digit that exists on this world into 1.  Rewriting a digit i with j (0≤i,j≤9) costs c_{i,j} MP (Magic Points).  She is now standing before a wall. The wall is divided into HW squares in H rows and W columns, and at least one square contains a digit between 0 and 9 (inclusive).  You are given A_{i,j} that describes the square at the i-th row from the top and j-th column from the left, as follows:    * If A_{i,j}≠-1, the square contains a digit A_{i,j}.   * If A_{i,j}=-1, the square does not contain a digit.  Find the minimum total amount of MP required to turn every digit on this wall into 1 in the end.

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())
C = [list(map(int, input().split())) for _ in range(10)]
A = [list(map(int, input().split())) for _ in range(H)]

for k in range(10):
    for i in range(10):
        for j in range(10):
            C[i][j] = min(C[i][j], C[i][k] + C[k][j])

answer = 0
for i in range(H):
    for j in range(W):
        if A[i][j] == -1:
            continue
        answer += C[A[i][j]][1]
        print(A[i][j])

print(answer)

Fixed, accepted submission:
H, W = map(int, input().split())
C = [list(map(int, input().split())) for _ in range(10)]
A = [list(map(int, input().split())) for _ in range(H)]

for k in range(10):
    for i in range(10):
        for j in range(10):
            C[i][j] = min(C[i][j], C[i][k] + C[k][j])

answer = 0
for i in range(H):
    for j in range(W):
        if A[i][j] == -1:
            continue
        answer += C[A[i][j]][1]

print(answer)
Problem:
We have a grid with H rows and W columns, where all the squares are initially white.  You will perform some number of painting operations on the grid. In one operation, you can do one of the following two actions:    * Choose one row, then paint all the squares in that row black.   * Choose one column, then paint all the squares in that column black.  At least how many operations do you need in order to have N or more black squares in the grid? It is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.

Incorrect submission (verdict: Wrong Answer):
h = int(input())
w = int(input())
n = int(input())

if h >= w:
    cnt = int(n // h)
    if not isinstance(n // h, int):
        cnt += 1
else:
    cnt = int(n // w)
    if not isinstance(n // w, int):
        cnt += 1
print(cnt)

Fixed, accepted submission:
h = int(input())
w = int(input())
n = int(input())

if h >= w:
    cnt = int(n // h)
    if n % h != 0 :
        cnt += 1
else:
    cnt = int(n // w)
    if n % w != 0:
        cnt += 1
print(cnt)
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
if n/10%111==0 or n%1000%111==0:
 print("Yes")
else:
 print("No")

Fixed, accepted submission:
n=int(input())
if n//10%111==0 or n%1000%111==0:
  print("Yes")
else:
  print("No")
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
def solve():
    N, M = map(int, input().split())
    if N*M % 2 == 0:
        return N*M/2
    else:
        return (N*M//2)+1
print(solve())

Fixed, accepted submission:
def solve():
    N, M = map(int, input().split())
    if N == 1:
        return 1
    if M == 1:
        return 1
    
    if N % 2 == 0:
        return M * N // 2
    else:
        a = N // 2 * M
        if M % 2 == 0:
            return a + M//2
        else:
            return a + (M//2 + 1)

print(solve())
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input()
q = [0]
flag = False
while len(s) > 0:
    if s[0:5] in ['dream','erase'] and flag == False:
        q.append(s[0:5])
        s = s[5:]
        flag = False
    elif s[0:6] == 'eraser':
        q.append(s[0:6])
        s = s[6:]
        flag = False
    elif s[0:7] == 'dreamer':
        q.append(s[0:7])
        s = s[7:]
        flag = False
    elif q[-1] in ['dream','erase']:
        s = q[-1] + s
        q.pop()
        flag = True
    else:
        print('NO')
        exit()

print('Yes')


Fixed, accepted submission:
s = input()
q = [0]
flag = False
while len(s) > 0:
    if s[0:5] in ['dream','erase'] and flag == False:
        q.append(s[0:5])
        s = s[5:]
        flag = False
    elif s[0:6] == 'eraser':
        q.append(s[0:6])
        s = s[6:]
        flag = False
    elif s[0:7] == 'dreamer':
        q.append(s[0:7])
        s = s[7:]
        flag = False
    elif q[-1] in ['dream','erase']:
        s = q[-1] + s
        q.pop()
        flag = True
    else:
        print('NO')
        exit()

print('YES')
Problem:
Given is an integer sequence of length N+1: A_0, A_1, A_2, \ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

a_li = list(map(int, input().split()))

ans = 0
li = [0]*(n+1)

for i,a in enumerate(a_li):
  ans += (i+1)*a

for i,a in enumerate(a_li[::-1]):
  if i >= 1:
    li[i] = li[i-1]+a
  else:
    li[i] = a

li = li[::-1]

flag = True
ne = 0.5
for i in range(n+1):
  if li[i]  > 2*ne:
    ans -= li[i] -2*ne

  ne = 2*ne - a_li[i]
  if ne <= 0:
    flag = False
if flag:
  print(int(ans))
else:
  print(-1)

Fixed, accepted submission:
n = int(input())

a_li = list(map(int, input().split()))

ans = 0
li = [0]*(n+1)

for i,a in enumerate(a_li):
  ans += (i+1)*a

for i,a in enumerate(a_li[::-1]):
  if i >= 1:
    li[i] = li[i-1]+a
  else:
    li[i] = a

li = li[::-1]

flag = True
ne = 0.5
for i in range(n+1):
  if li[i]  > 2*ne:
    ans -= li[i] -int(2*ne)

  
  ne = min(li[i] - a_li[i],int(2*ne)-a_li[i])

  if (i == n and ne != 0) or (i != n and ne <= 0):
    flag = False

  
if flag:
  print(ans)
else:
  print(-1)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
c = int(input())
x = int(input())

counter = 0

for i in range(a):
    for j in range(b):
        for k in range(c):
            total = 500 * i + 100 * j + 50 * k
            if total == x:
                counter += 1

print(counter)


Fixed, accepted submission:
a = int(input())
b = int(input())
c = int(input())
x = int(input())

counter = 0

for i in range(0, a+1):
    for j in range(0, b+1):
        for k in range(0, c+1):
            total = (500 * i) + (100 * j) + (50 * k)
            if total == x:
                counter += 1

print(counter)
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r, g, b = map(int, input().split())
if ((10 * g + b) % 4):
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
r, g, b = map(int, input().split())
if ((10 * g + b) % 4 == 0):
    print("YES")
else:
    print("NO")
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
S = input()
keybord = [s for s in S]
editor = ''
for i in range(len(S)):
    if keybord[i] == '0':
        editor += '0'
    elif keybord[i] == '1':
        editor += '1'
    else:
        if editor == '':
            continue
        else:
            editor = editor[:-1]


Fixed, accepted submission:
S = input()
keybord = [s for s in S]
editor = ''
for i in range(len(S)):
    if keybord[i] == '0':
        editor += '0'
    elif keybord[i] == '1':
        editor += '1'
    else:
        if editor == '':
            continue
        else:
            editor = editor[:-1]

print(editor)
Problem:
There are N cities and M roads. The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally. There may be more than one road that connects the same pair of two cities. For each city, how many roads are connected to the city?

Incorrect submission (verdict: Wrong Answer):
# Counting Roads

n,m =  list(map(int, input().split()))
a = []
for i in range(m):
    a.append( list(map(int, input().split())) ) 

b = []
for s in a:
    b.extend(s)
print(b)

for i in range (n):
    print(b.count(i+1))

Fixed, accepted submission:
# Counting Roads

n,m =  list(map(int, input().split()))
a = []
for i in range(m):
    a.append( list(map(int, input().split())) ) 

b = []
for s in a:
    b.extend(s)
for i in range (n):
    print(b.count(i+1))
Problem:
We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.  We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.  At most how many people can sit on the seat?

Incorrect submission (verdict: Wrong Answer):
X, Y, Z = map(int, input().split())

result = X // (Y + Z) - 1
while X < result * Y + (result + 1) * Z:
    result += 1
print(result)

Fixed, accepted submission:
X, Y, Z = map(int, input().split())

print((X - Z) // (Y + Z))
Problem:
You are given three words s_1, s_2 and s_3, each composed of lowercase English letters, with spaces in between. Print the acronym formed from the uppercased initial letters of the words.

Incorrect submission (verdict: Wrong Answer):


s1,s2,s3=input().split(" ")

print(s1[0].upper()+s1[0].upper()+s1[0].upper())

Fixed, accepted submission:


s1,s2,s3=input().split(" ")

print(s1[0].upper()+s2[0].upper()+s3[0].upper())
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def insertionSort(A, N):
  for i in range(1, N):
    v = A[i]
    j = i - 1
    while j >= 0 and A[j] > v:
      A[j + 1] = A[j]
      j -= 1
    A[j + 1] = v
    print(' '.join(map(str, A)))

N = int(input())
A = list(map(int, input().split()))
insertionSort(A,N)


Fixed, accepted submission:
def insertionSort(A, N):
  print(' '.join(map(str, A)))
  for i in range(1, N):
    v = A[i]
    j = i - 1
    while j >= 0 and A[j] > v:
      A[j + 1] = A[j]
      j -= 1
    A[j + 1] = v
    print(' '.join(map(str, A)))

N = int(input())
A = list(map(int, input().split()))
insertionSort(A,N)