TnT/CodeNet4Repair huggingface dataset:
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from collections import defaultdict
import queue
d = defaultdict(list)
n,m = [int(i) for i in input().split()]
q=  queue.Queue()
for i in range(m):
    a,b =[int(i) for i in input().split()]
    d[a].append(b)
    d[b].append(a)
l = n-1
arr = [0]*(n+2)
#print(d)
for i in d[1]:
    if arr[i]==0:
        q.put(i)
        arr[i]=1
        l-=1
    
while(not(q.empty())):
    k = q.get()
    for i in d[k]:
        if arr[i]==0 and i!=1:
            arr[i]=k
            q.put(i)
            l-=1
    if l==0:
        break
if l==0:
    print('YES')
    for i in range(2,n+1):
        print(arr[i])
else:
    print('NO')

Fixed, accepted submission:
from collections import defaultdict
import queue
d = defaultdict(list)
n,m = [int(i) for i in input().split()]
q=  queue.Queue()
for i in range(m):
    a,b =[int(i) for i in input().split()]
    d[a].append(b)
    d[b].append(a)
l = n-1
arr = [0]*(n+2)
#print(d)
for i in d[1]:
    if arr[i]==0:
        q.put(i)
        arr[i]=1
        l-=1
    
while(not(q.empty())):
    k = q.get()
    for i in d[k]:
        if arr[i]==0 and i!=1:
            arr[i]=k
            q.put(i)
            l-=1
    if l==0:
        break
if l==0:
    print('Yes')
    for i in range(2,n+1):
        print(arr[i])
else:
    print('No')
Problem:
You are given an integer sequence of length n, a_1, ..., a_n. Let us consider performing the following n operations on an empty sequence b.  The i-th operation is as follows:    1. Append a_i to the end of b.   2. Reverse the order of the elements in b.  Find the sequence b obtained after these n operations.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
even = 0
if n % 2 == 0:
    even = 1

el = []
ol = []

s = list(map(int,(input().split())))
for i in range(n):
    if i%2 ==0:
        el.append(s[i])
    else:
        ol.append(s[i])
if even == 1:
    ol.reverse()
    ans = ol.extend(el)
    print(ol)
else:
    el.reverse()
    ans = el.extend(ol)
    print(el)


Fixed, accepted submission:
from collections import deque
n = int(input())
even = n%2
ans = deque()
s = list(map(int,(input().split())))
for i in range(n):
    if i%2 != even:
        ans.appendleft(s[i])
    else:
        ans.append(s[i])
print(" ".join(map(str,ans)))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter
import sys

sys.setrecursionlimit(10 ** 6)

mod = 1000000007
inf = int(1e18)

dx = [0, 1, 0, -1]
dy = [1, 0, -1, 0]


def inverse(a):
    return pow(a, mod - 2, mod)


def usearch(x, a):
    lft = 0
    rgt = len(a) + 1
    while rgt - lft > 1:
        mid = (rgt + lft) // 2
        if a[mid] <= x:
            lft = mid
        else:
            rgt = mid
    return lft



def main():
    n = int(input())
    s = [input() for i in range(n)]
    r = {}
    for x in s:
        r[x] = r.get(x, 0) + 1

    for i in ['AC', 'WA', "TLE", "E"]:
        print("{} x {}".format(i, r.get(i, 0)))

main()


Fixed, accepted submission:
from collections import Counter
import sys

sys.setrecursionlimit(10 ** 6)

mod = 1000000007
inf = int(1e18)

dx = [0, 1, 0, -1]
dy = [1, 0, -1, 0]


def inverse(a):
    return pow(a, mod - 2, mod)


def usearch(x, a):
    lft = 0
    rgt = len(a) + 1
    while rgt - lft > 1:
        mid = (rgt + lft) // 2
        if a[mid] <= x:
            lft = mid
        else:
            rgt = mid
    return lft



def main():
    n = int(input())
    s = [input() for i in range(n)]
    r = {}
    for x in s:
        r[x] = r.get(x, 0) + 1

    for i in ['AC', 'WA', "TLE", "RE"]:
        print("{} x {}".format(i, r.get(i, 0)))

main()
Problem:
AtCoder Mart sells 1000000 of each of the six items below:    * Riceballs, priced at 100 yen (the currency of Japan) each   * Sandwiches, priced at 101 yen each   * Cookies, priced at 102 yen each   * Cakes, priced at 103 yen each   * Candies, priced at 104 yen each   * Computers, priced at 105 yen each  Takahashi wants to buy some of them that cost exactly X yen in total. Determine whether this is possible.   (Ignore consumption tax.)

Incorrect submission (verdict: Wrong Answer):
p = int(input())
n = p%100
m = p//100
flag = 0
while n!=0:
  if n>=5:
    n-=5
    flag+=1
  elif n>=4:
    n-=4
    flag+=1
  elif n>=3:
    n-=3
    flag+=1
  elif n>=2:
    n-=2
    flag+=1
  elif n>=1:
    n-=1
    flag+=1
if flag>=m:
  print(1)
else:
  print(0)

  

Fixed, accepted submission:
p = int(input())
n = p%100
m = p//100
flag = 0
while n!=0:
  if n>=5:
    n-=5
    flag+=1
  elif n>=4:
    n-=4
    flag+=1
  elif n>=3:
    n-=3
    flag+=1
  elif n>=2:
    n-=2
    flag+=1
  elif n>=1:
    n-=1
    flag+=1
if flag<=m:
  print(1)
else:
  print(0)
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
n=input()

print("ABC"+"n")

Fixed, accepted submission:
n=input()

print("ABC"+n)
Problem:
You are given a sequence of _n_ integers S and a sequence of different _q_ integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Incorrect submission (verdict: Time Limit Exceeded):
# encoding: utf-8


class Solution:
    @staticmethod
    def binary_search():
        array_length_1 = int(input())
        array_1 = [int(x) for x in input().split()]
        array_length_2 = int(input())
        array_2 = [int(x) for x in input().split()]

        # print(len(set(array_1).intersection(set(array_2))))
        left, right, count = 0, array_length_1, 0
        for each in array_2:
            while left < right:
                mid = (left + right) // 2
                if array_1[mid] == each:
                    count += 1
                elif each < array_1[mid]:
                    right = mid
                else:
                    left = mid + 1

        print(count)


if __name__ == '__main__':
    solution = Solution()
    solution.binary_search()

Fixed, accepted submission:
# encoding: utf-8


import sys


class Solution:
    def __init__(self):
        """
        init input array
        """
        self.__input = sys.stdin.readlines()

    @property
    def solution(self):
        length_1 = int(self.__input[0])
        array_1 = list(map(int, self.__input[1].split()))
        length_2 = int(self.__input[2])
        array_2 = list(map(int, self.__input[3].split()))

        assert length_1 == len(array_1) and length_2 == len(array_2)

        count = 0

        for each in array_2:
            if self.binary_search(key=each, array=array_1, array_length=length_1):
                count += 1

        return str(count)

    @staticmethod
    def binary_search(key, array, array_length):
        # print(len(set(array_1).intersection(set(array_2))))
        left, right = 0, array_length
        while left < right:
            mid = (left + right) // 2
            if key == array[mid]:
                return True
            elif key < array[mid]:
                right = mid
            else:
                left = mid + 1
        return False


if __name__ == '__main__':
    case = Solution()
    print(case.solution)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
a = input()
b = input()
if a==reversed(b):
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
a = input()
b = input()
if a==b[::-1]:
    print('YES')
else:
    print('NO')
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
range_N = range(1,N+1) # 1<=M<=100
target = 1
for i in range_N:
  if 2 ** 1 <= N :
    target = 2 ** i
print(target)

Fixed, accepted submission:
N = int(input())
range_N = range(1,N+1) # 1<=M<=100
target = 1
for i in range_N:
  if 2 ** i <= N :
    target = 2 ** i
print(target)
Problem:
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.  Snuke can perform the following operation any number of times:    * Choose a box containing at least one candy, and eat one of the candies in the chosen box.  His objective is as follows:    * Any two neighboring boxes contain at most x candies in total.  Find the minimum number of operations required to achieve the objective.

Incorrect submission (verdict: Wrong Answer):
n,x=map(int,input().split())
a=list(map(int,input().split()))
b=[]
for i in range(1,n):
  b.append(max(0,a[i]+a[i-1]-x))
print(sum(b))
  

Fixed, accepted submission:
n,x=map(int,input().split())
a=list(map(int,input().split()))
ans=0
for i in range(1,n):
  k=max(0,a[i]+a[i-1]-x)
  ans+=k
  a[i]=max(0,a[i]-k)
print(ans)
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
print('A'+str(input())[9]+'C')

Fixed, accepted submission:
print('A'+str(input())[8]+'C')
Problem:
There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Incorrect submission (verdict: Wrong Answer):
import collections
n=int(input())

A=list(map(int,input().split()))

X=collections.Counter(A)


if n%2==0:
    flag=True
    for k,v in X.items():
        if v!=2:
            flag=False
            break
        if k not in [int(i) for i in range(1,n+1,2)]:
            flag=False
            break
    if flag:
        print((2**(n//2))%(10**9+7))
    else:
        print(0)
else:
    flag=True
    if X['0']!=1:
        flag=False
    for k,v in X.items():
        if v!=2:
            flag=False
            break
        if k not in [int(i) for i in range(0,n+1,2)]:
            flag=False
            break
    if flag:
        print((2**(n//2))%(10**9+7))
    else:
        print(0)

Fixed, accepted submission:
n=int(input())

A=list(map(int,input().split()))
A.sort()

if n%2==0:
    X=[int(i) for i in range(1,n+1,2)]*2
elif n%2==1 and n>2:
    X=[int(i) for i in range(2,n+1,2)]*2+[0]
else:
    X=[0]    

X.sort()
ans=(2**(n//2))%(10**9+7)

for a,x in zip(A,X):
    if a!=x:
        ans=0
print(ans)
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
a, v = list(map(int,input().strip().split()))
b, w = list(map(int,input().strip().split()))
t = int(input())

if w - v >= 0:
  print("NO")
else:
  time = abs(a-b)/(v-w)
  if t <= time:
    print("YES")
  else:
    print("NO")

Fixed, accepted submission:
a, v = list(map(int,input().strip().split()))
b, w = list(map(int,input().strip().split()))
t = int(input())

if w - v >= 0:
  print("NO")
else:
  time = abs(a-b)/(v-w)
  if time <= t:
    print("YES")
  else:
    print("NO")
Problem:
タナカ氏が HW アールの果樹園を残して亡くなりました。果樹園は東西南北方向に H × W の区画に分けられ、区画ごとにリンゴ、カキ、ミカンが植えられています。タナカ氏はこんな遺言を残していました。  果樹園は区画単位でできるだけ多くの血縁者に分けること。ただし、ある区画の東西南北どれかの方向にとなりあう区画に同じ種類の果物が植えられていた場合は、区画の境界が分からないのでそれらは 1 つの大きな区画として扱うこと。  例えば次のような 3 × 10 の区画であれば ('リ'はリンゴ、'カ'はカキ、'ミ'はミカンを表す)      同じ樹がある区画の間の境界を消すと次のようになり、      結局 10 個の区画、つまり 10 人で分けられることになります。  雪が降って区画の境界が見えなくなる前に分配を終えなくてはなりません。あなたの仕事は果樹園の地図をもとに分配する区画の数を決めることです。  果樹園の地図を読み込み、分配を受けられる血縁者の人数を出力するプログラムを作成してください。

Incorrect submission (verdict: Wrong Answer):
h = 0
w = 0
list1 = []

def dfs(x, y, f):
    list1[y] = list1[y][:x] + '1' + list1[y][x+1:]

    if y + 1 < h:
        if list1[y + 1][x] == f:
            dfs(x, y + 1, f)
    if x - 1 >= 0:
        if list1[y][x - 1] == f:
            dfs(x - 1, y, f)
    if x + 1 < w:
        if list1[y][x + 1] == f:
            dfs(x + 1, y, f)
    return 1

h, w = list(map(lambda x: int(x),input().split(" ")))
n = 0

for i in range(0, h):
    list1.append(input())
for i in range(0, h):
    for j in range(0, w):
        if list1[i][j] != '1':
           n += dfs(j, i, list1[i][j])


#print(list1)
print(n)

Fixed, accepted submission:
h = w = 0
slist =[]
list1=[]
def dfs(f):
    while True:
        if len(slist) == 0:
            return 1
        coordinate= slist.pop()
        #print(coordinate)
        x = coordinate[0]
        y = coordinate[1]

        list1[y] = list1[y][:x] + '1' + list1[y][x + 1:]
        if x + 1 < w:
            if list1[y][x + 1] == f:
                slist.append([x + 1,y])
        if x - 1 >= 0:
            if list1[y][x-1] == f:
                slist.append([x - 1, y])
        if y + 1 < h:
            if list1[y + 1][x] == f:
                slist.append([x, y + 1])
        if y -1 >= 0:
            if list1[y -1][x] == f:
                slist.append([x, y - 1])

while True:
    h, w = list(map(lambda x: int(x),input().split(" ")))
    if 0 in (h, w):
        break
    n = 0
    for i in range(0, h):
        list1.append(input())
    for i in range(0, h):
        for j in range(0, w):
            if list1[i][j] != '1':
                slist.append([j,i])
                n += dfs(list1[i][j])
            #print(list1)
    print(n)
    list1=[]
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
d=a//b
r=a%b
f=a/b
print(str(d)+' '+str(r)+' '+str(float(f)))

Fixed, accepted submission:
a,b=map(int,input().split())
print(str(a//b)+' '+str(a%b)+' '+str("{:.5f}".format(a/b)))
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
c=int(input())
x=int(input())
y=0
d=0
s=0
t=0
u=0
for i in range(a+1):
    t=0
    u=0
    if s==0: 
        y=500*i
        if x < y:
            s =1
        else:
            for j in range(b+1):
                u=0
                if t==0:
                    y=500*i+100*j
                    if x < y:
                        t=1
                    else:
                        for k in range(c+1):
                            if u==0:
                                y=500*i+100*j+50*k
                                if x==y:
                                    d=d+1
                                    u=1
                                    print(i,j,k)
print(str(d))
                
            


Fixed, accepted submission:
a=int(input())
b=int(input())
c=int(input())
x=int(input())
y=0
d=0
s=0
t=0
u=0
for i in range(a+1):
    t=0
    u=0
    if s==0: 
        y=500*i
        if x < y:
            s =1
        else:
            for j in range(b+1):
                u=0
                if t==0:
                    y=500*i+100*j
                    if x < y:
                        t=1
                    else:
                        for k in range(c+1):
                            if u==0:
                                y=500*i+100*j+50*k
                                if x==y:
                                    d=d+1
                                    u=1
print(str(d))
Problem:
Snuke has one biscuit and zero Japanese yen (the currency) in his pocket. He will perform the following operations exactly K times in total, in the order he likes:    * Hit his pocket, which magically increases the number of biscuits by one.   * Exchange A biscuits to 1 yen.   * Exchange 1 yen to B biscuits.  Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Incorrect submission (verdict: Wrong Answer):
from math import ceil
K, A, B = map(int, input().split())
b = 1

if B - A > 2:
    b += min(A - 1, K)
    K -= min(A - 1, K)
    if K == 0:
        print(b)
        exit()
    n = K // 2
    b += n * (B - A)
    n += K
    print(b)
else:
    b += K
    print(b)


Fixed, accepted submission:
k, a, b = map(int, input().split())
bis = 1
if b - a < 3 or k < a + 1:
    print (k+1)
else:
    k -= (a-1)
    bis += (a-1)
    n = k // 2
    bis += (b-a) * n
    bis += k % 2
    print (bis)
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

d = a // b
r = a % b
f = a / b

print("{} {} {}".format(d, r, f))

Fixed, accepted submission:
a, b = map(int, input().split())

d = a // b
r = a % b
f = a / b

print("{} {} {:.5f}".format(d, r, f))
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

if a < b:
    print(f"{a} {b}")
else:
    print(f"{b} {a}")



Fixed, accepted submission:
while True:
    a, b = map(int, input().split())

    if (a == 0 and b == 0):
        break
    if a < b:
        print(f"{a} {b}")
    else:
        print(f"{b} {a}")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N  = int(input())

print(N*(N+1)/2)

Fixed, accepted submission:
n = int(input())
ans = 0
for i in range(n+1):
  ans += i
print(ans)
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
import math
H,W=[7,3]
print(math.ceil(H*W/2))


Fixed, accepted submission:
H,W=map(int, input().split())
if H==1 or W==1:
  print(1)
else:
  print((H*W+1)//2)
Problem:
Find places where a string P is found within a text T. Print all indices of T where P found. The indices of T start with 0.

Incorrect submission (verdict: Wrong Answer):
T = input()
P = input()
idx = 0
while (1):
    ans = T.find(P, idx)
    if (ans != -1):
        print(ans)
        T=T.replace(T[ans],"?",1)
        print(T)
        idx += len(P)
    else:
        break

Fixed, accepted submission:
T = input()
P = input()
idx = 0
while (1):
    ans = T.find(P, idx)
    if (ans == -1):
        break
    else:
        print(ans)
        if (ans==0):
            idx+=1
        else:
            idx=ans+1
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
x=800*n
y=n//15
print(x-y)

Fixed, accepted submission:
n=int(input())
x=800*n
y=n//15 * 200
print(x-y)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n, m, x, y = map(int, input().split())
xl = list(map(int, input().split()))
yl = list(map(int, input().split()))
mx = max(xl) + 1
my = min(yl)
for i in range(x + 1, y + 1):
    if mx <= i <= my:
        print(mx, my, i, x, y)
        print("No War")
        exit()
print("War")


Fixed, accepted submission:
n, m, x, y = map(int, input().split())
xl = list(map(int, input().split()))
yl = list(map(int, input().split()))
mx = max(xl) + 1
my = min(yl)
for i in range(x + 1, y + 1):
    if mx <= i <= my:
        print("No War")
        exit()
print("War")