TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.  Snuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:    * Operation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.  For example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure. If the die is rotated toward the right as shown in the figure, the side showing 3 will face upward. Besides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.    Find the minimum number of operation Snuke needs to perform in order to score at least x points in total.

Incorrect submission (verdict: Wrong Answer):
x = int(input())

if x % 11 == 0:
    ans = (x // 11)*2
else:
    ans = (x // 11)*2 + 1

print(ans)

Fixed, accepted submission:
x = int(input())
X = x % 11
N = x // 11

ans = 0
if 1 <= X <= 6:
    ans = N*2 + 1
elif 7 <= X <= 10:
    ans = N*2 + 2
else:
    ans = N*2

print(ans)
Problem:
The problem set at _CODE FESTIVAL 20XX Finals_ consists of N problems.  The score allocated to the i-th (1≦i≦N) problem is i points.  Takahashi, a contestant, is trying to score exactly N points. For that, he is deciding which problems to solve.  As problems with higher scores are harder, he wants to minimize the highest score of a problem among the ones solved by him.  Determine the set of problems that should be solved.

Incorrect submission (verdict: Wrong Answer):
def solve(n):
    score = 0
    res = []
    for p in range(1, n+1):
        res.append(p)
        score += p
        if score >= n:
            break
    return "\n".join(map(str, res))

n = int(input())
print(solve(n))

Fixed, accepted submission:
def solve(n):
    score = 0
    for p in range(1, n+1):
        score += p
        if score >= n:
            break
    x = score - n
    res = list(range(1,x)) + list(range(x+1,p+1))
    return "\n".join(map(str, res))

n = int(input())
print(solve(n))
Problem:
N persons are standing in a row. The height of the i-th person from the front is A_i.  We want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:  Condition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.  Find the minimum total height of the stools needed to meet this goal.

Incorrect submission (verdict: Wrong Answer):
N = int(input(''))
A = input('')
A_N = A.split()
num = 0 
for i in range(1,N):
    if int(A_N[i]) >= int(A_N[i-1]):
        num += 0
    elif (A_N[i]) < (A_N[i-1]):
        num += int(A_N[i-1]) - int(A_N[i])
print(num)

Fixed, accepted submission:
N = int(input(''))
A = input('')
a_n = A.split()
A_N = list(map(int, a_n))
num = 0 
for i in range(1,N):
    if A_N[i] >= A_N[i-1]:
        num += 0
    elif A_N[i] < A_N[i-1]:
        num += A_N[i-1] - A_N[i]
        A_N[i] = A_N[i-1]
print(num)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    n = int(input())
    k = [int(i) for i in input().split()]
    a = 0
    b = 0
    k.sort(reverse=True)
    print(k)
    flag = True
    for i in k:
        if flag == True:
            a+=i
            flag=False
        else:
            b+=i
            flag=True
    print(a-b)


Fixed, accepted submission:
if __name__ == '__main__':
    n = int(input())
    k = [int(i) for i in input().split()]
    a = 0
    b = 0
    k.sort(reverse=True)
    flag = True
    for i in k:
        if flag == True:
            a+=i
            flag=False
        else:
            b+=i
            flag=True
    print(a-b)
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
lst = [i**2 for i in range(1,32)]+[8,27,125,216,343,512,1000]+[32,243]+[128]+[1001]
lst.sort()
print(lst)
for i in range(len(lst)):
    if lst[i]<=x<lst[i+1]:
        print(lst[i])

Fixed, accepted submission:
x = int(input())
lst = [i**2 for i in range(1,32)]+[8,27,125,216,343,512,1000]+[32,243]+[128]+[1001]
lst.sort()
for i in range(len(lst)):
    if lst[i]<=x<lst[i+1]:
        print(lst[i])
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):

li=list(map(int,input().split()))	
min=li[0]//li[2]
max=li[1]//li[2]
count=max-min
if li[0]==0:
  count+=1
print(count)

Fixed, accepted submission:

li=list(map(int,input().split()))	
min=li[0]//li[2]
max=li[1]//li[2]
count=max-min
if li[0]%li[2]==0:
  count+=1
print(count)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
def main():
  a = int(input())
  if a%2==0:
    print((a+1)*a/2)
  else:
    print((a+1)*a/2+(a+1)/2)

if __name__=='__main__':main()

Fixed, accepted submission:
#!/usr/bin/env python3
def main():
  a = int(input())
  print(int(((a+1)*a)/2))

if __name__=='__main__':main()
Problem:
An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.  Given an integer N, determine whether it is a Harshad number.

Incorrect submission (verdict: Wrong Answer):
N=input()
t=sum(map(int, list(N)))
print("Yes" if int(N)==t else "No")

Fixed, accepted submission:
X = input()

fx = 0
for x in X:
    fx += int(x)

if int(X) % fx == 0:
    print("Yes")
else:
    print("No")
Problem:
We have N points in a two-dimensional plane.   The coordinates of the i-th point (1 \leq i \leq N) are (x_i,y_i).   Let us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.   Here, points on the sides of the rectangle are considered to be in the interior.   Find the minimum possible area of such a rectangle.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int,input().split())
xs = []
ys = []
points = []
for _ in range(n):
    x, y = map(int, input().split())
    xs.append(x)
    ys.append(y)
    points.append((x, y))

for leftx in xs:
    for rightx in xs:
        if leftx >= rightx:
            continue
        for downy in ys:
            for upy in ys:
                if downy >= upy:
                    continue
                
                min_ = float('inf')
                for tx, ty in points:
                    if (leftx <= tx <= rightx) and (downy <= ty <= upy):
                        yoko = rightx - leftx
                        tate = upy - downy
                        men = yoko*tate
                        if men < min_:
                            min_ = men

print(min_)

Fixed, accepted submission:
n, k = map(int,input().split())
ps = [tuple(map(int,input().split())) for i in range(n)]

sx = sorted(ps,key = lambda x: x[0]) 
nx = list(enumerate(sx)) 
ans = 5e18

for f, (x1,y1) in nx[:n-k+1]: 
    for e, (x2,y2) in nx[f+k-1:]: 
        dx = x2 - x1 
        sy = sorted(y for x,y in sx[f:e+1]) 
        for y3,y4 in zip(sy,sy[k-1:]): 
            if y3 <= y1 and y4 >= y2: 
                ans = min(ans, dx * (y4 - y3))

print(ans)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))
B = []
for a in A:
  i = 0
  while True:
    if a % 2 ** i == 0:
      i += 1
    else:
      B.append(i)
      break
B.sort()
print(B[0])

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))
B = []
for a in A:
  i = 0
  while a % 2 ** i == 0:
    i += 1
  B.append(i - 1)
B.sort()
print(B[0])
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
n = list(input())
for i in range(8):
    ans = n[0]
    ans += '+-'[i%2] + n[1]
    ans += '+-'[i//4] + n[2]
    ans += '+-'[(i%4)//2] + n[3]
    if eval(ans) == 7:
        print(ans)
        break

Fixed, accepted submission:
n = list(input())
for i in range(8):
    ans = n[0]
    ans += '+-'[i%2] + n[1]
    ans += '+-'[i//4] + n[2]
    ans += '+-'[(i%4)//2] + n[3]
    if eval(ans) == 7:
        print(ans+"=7")
        break
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())
print(min(A, B), max(0, N - (A + B)))

Fixed, accepted submission:
N, A, B = map(int, input().split())
print(min(A, B), max(0, (A + B) - N))
Problem:
Snuke has N strings. The i-th string is s_i.  Let us concatenate these strings into one string after arranging them in some order. Find the maximum possible number of occurrences of `AB` in the resulting string.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
res = 0
both = 0
head = 0
last = 0
for i in range(N):
  inp = input()
  if 'AB' in inp:
    res += 1
  if 'B'==inp[0] and 'A'==inp[-1]:
    both+=1
  elif 'B'==inp[0]:
    head+=1
  elif 'A'==inp[-1]:
    last += 1

res += max(0,both -1)
if head > 0 and last >0:
  res += 2 + min(head-1,last-1)
elif head>0:
  res += 1 + min(head-1,last)
elif last>0:
  res += 1 + min(head,last-1)
print(res)

Fixed, accepted submission:
n=int(input())
s=[0]*n
ct=0
a=0
b=0
c=0
for i in range(n):
    s[i]=input()
for i in range(n):
    for j in range(len(s[i])):
        t=s[i]
        ts=list(t)
        ts.append(0)
        if ts[j]=='A' and ts[j+1]=='B':
            ct+=1
    if ts[0]=='B' and ts[len(s[i])-1]!='A':
        a+=1
    if ts[len(s[i])-1]=='A' and ts[0]!='B':
        b+=1
    if ts[0]=='B' and ts[len(s[i])-1]=='A':
        c+=1
ct += max(0,c -1)
if c !=0:
  if a > 0 and b >0:
    ct += 2 + min(a-1,b-1)
  elif a>0:
    ct += 1 + min(a-1,b)
  elif b>0:
    ct += 1 + min(a,b-1)
else:
  ct += min(a,b)
print(ct)
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Time Limit Exceeded):
o = list(input())
e = list(input())
c = ""
for i in range(len(o)):
    c += o[i]
    while e:
        c += e[i]

print(c)

Fixed, accepted submission:
o = list(input())
e = list(input())
c = ""
for i in range(len(o)):
    c += o[i]
    if i < len(e):
        c += e[i]

print(c)
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3

def main():
    a, b, c = map(int, input().split())
    print("YES" if b - a == c - a else "NO")


if __name__ == "__main__":
    main()


Fixed, accepted submission:
#!/usr/bin/env python3

def main():
    a, b, c = map(int, input().split())
    print("YES" if b - a == c - b else "NO")


if __name__ == "__main__":
    main()
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
N,A,B = map(int,input().split())
S =input()

for i in range(N):
  if S[i]=='a' and i < A+B:
    print('Yes')
  elif S[i]=='b' and i < B:
    print('Yes')
  else:
    print('No')

Fixed, accepted submission:
N,A,B = map(int,input().split())
S = input()

passed = 0 
fo = 1 
for i in range(N):
  if(S[i] == 'a'):
    if(passed < A+B):
      print('Yes')
      passed += 1
    else:
      print('No')
  elif(S[i] == 'b'):
    if((passed < A+B)and(fo <= B)):
      print('Yes')
      fo += 1
      passed += 1
    else:
      print('No')
  elif(S[i] == 'c'):
     print('No')
Problem:
_n_ _q_   _name 1 time1_   _name 2 time2_   ...   _name n timen_    In the first line the number of processes _n_ and the quantum _q_ are given separated by a single space.  In the following _n_ lines, names and times for the _n_ processes are given. _name i_ and _time i_ are separated by a single space.

Incorrect submission (verdict: Wrong Answer):
N, Q = map(int, input().strip().split())

A = []
D = {}
for l in range(N):
    n, t = input().strip().split()
    D[n] = int(t)
    A.append(n)

print(A)
T = 0
d = 0
while True:
    n = A.pop(0)
    if D[n] > Q:
        D[n] -= Q
        T += Q
        A.append(n)
    else:
        T += D[n]
        print('{0} {1}'.format(n, T))
        d += 1
        if d == N:
            break

Fixed, accepted submission:
N, qms = map(int, input().split())

raw_proc = [input() for i in range(N)]
queue = [{} for i in range(N+1)]
limit = N+1
for i in range(N):
    name, time = raw_proc[i].split()
    time = int(time)
    queue[i] = {"name": name, "time": time}

def enque(tail, p):
    queue[tail] = p
    tail = (tail+1) % limit
    return tail

def deque(head):
    proc = queue[head]
    head = (head+1) % limit
    return proc, head


if __name__ == '__main__':
    head = 0
    tail = N
    total_time = 0
    while head != tail:
        p, head = deque(head)
        t = min(qms, p["time"])
        p["time"] = p["time"] - t
        total_time += t
        if p["time"] > 0:
            tail = enque(tail, p)
        else:
            print("{} {}".format(p["name"], total_time))
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
n=int(input())
a=list(map(int,input().split()))
ans=0
while all(j%2==0 for j in a):
    for k in range(len(a)):
        a[k]==a[k]//2
    ans+=1
print(ans)

Fixed, accepted submission:
n=int(input())
A=list(map(int,input().split()))
ans=0
while all(a%2==0 for a in A):
    A=[a/2 for a in A]
    ans+=1
print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int, input().split())
print(a)
print(b)

if a*b/2 == 1:
    print("Odd")
else:
    print("Even")

Fixed, accepted submission:
a,b = map(int, input().split())

if a*b%2 == 1:
    print("Odd")
else:
	print("Even")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

if a%2 == 0 and b%2 == 0:
  print('Even')
else:
  print('Odd')

Fixed, accepted submission:
a, b = map(int, input().split())
if a*b%2 == 0:
  print('Even')
else:
  print('Odd')
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
print('Yes' if 'abc' in input() else 'No')

Fixed, accepted submission:
string = input()
if string[0] != string[1] and string[1] != string[2] and string[2] != string[0]:
    print("Yes")
else:
    print("No")
Problem:
AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.  The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.  How many different PIN codes can he set this way?  Both the lucky number and the PIN code may begin with a 0.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline
import numpy as np

from math import factorial
import itertools

def permutations_count(n, r):
    
    return factorial(n) // factorial(n - r)

def combinations_count(n, r):
    
    return factorial(n) // (factorial(n - r) * factorial(r))

n = int(input())
*s, = map(int, list(input().split()[0]))

ans = 0
for i in range(1000):
    num_str = str(i)
    if i < 100:
        num_str = '0'+num_str
    if i<10:
        num_str = '0'+num_str
    idx = 0
    for j in s:
        # print(j, idx)
        if j == int(s[idx]):
            idx += 1
            if idx==3:
                break
    if idx == 3:
        ans += 1
print(ans)

Fixed, accepted submission:
import sys
input = sys.stdin.readline

n = int(input())
s = input().split()[0]

ans = 0
for i in range(1000):
    num_str = str(i).zfill(3)
    a = s.find(num_str[0])
    if a==-1:
        continue
    b = s[a+1:].find(num_str[1])
    if b==-1:
        continue
    b += a+1
    c = s[b+1:].find(num_str[2])
    if c!=-1:
        ans += 1
print(ans)
Problem:
There are N + 1 squares arranged in a row, numbered 0, 1, ..., N from left to right.  Initially, you are in Square X. You can freely travel between adjacent squares. Your goal is to reach Square 0 or Square N. However, for each i = 1, 2, ..., M, there is a toll gate in Square A_i, and traveling to Square A_i incurs a cost of 1. It is guaranteed that there is no toll gate in Square 0, Square X and Square N.  Find the minimum cost incurred before reaching the goal.

Incorrect submission (verdict: Wrong Answer):
N, M, X = map(int,input().split())
A = list(map(int,input().split()))
ans = []
z = 0
y = 0
for i in range(X + 1, N + 1):
    if  i in A:
        z += 1
    print(z)
ans.append(z)
for i in range(1,X):
    if  i in A:
        y += 1
    print(y)
ans.append(y)
ans = sorted(ans)
print(ans)
print(ans[0])

Fixed, accepted submission:
N, M, X = map(int,input().split())
A = list(map(int,input().split()))
ans = []
z = 0
y = 0
for i in range(X + 1, N + 1):
    if  i in A:
        z += 1
ans.append(z)
for i in range(1,X):
    if  i in A:
        y += 1
ans.append(y)
ans = sorted(ans)
print(ans[0])
Problem:
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.  At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:    * Choose a (connected) rope with a total length of at least L, then untie one of its knots.  Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.

Incorrect submission (verdict: Wrong Answer):
N, L = map(int, input().split())
A = [int(a) for a in input().split()]

CanRemain = []
for i in range(N-1):
    if A[i] + A[i+1] >= L: CanRemain.append(i+1)

if not CanRemain: print("impossible")
else:
    print("possible")
    for i in range(1, CanRemain[-1]): 
        if i not in CanRemain: print(i)
    for i in reversed(range(CanRemain[-1]+1, N)): print(i)
    for num in CanRemain: print(num)

Fixed, accepted submission:
import sys

def solve():
    input = sys.stdin.readline
    N, L = map(int, input().split())
    A = [int(a) for a in input().split()]
    for i in range(N - 1):
        if A[i] + A[i+1] >= L:
            print("Possible")
            for k in range(i): print(k + 1)
            for k in reversed(range(i + 1, N - 1)): print(k + 1)
            print(i + 1)
            break
    else: print("Impossible")

    return 0

if __name__ == "__main__":
    solve()
Problem:
You went shopping to buy cakes and donuts with X yen (the currency of Japan).  First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.  How much do you have left after shopping?

Incorrect submission (verdict: Wrong Answer):
X,A,B=[int(input()) for i in range(3)]
s=X-(((X-A)//B)*B+A)
s

Fixed, accepted submission:
X,A,B=[int(input()) for i in range(3)]
s=X-(((X-A)//B)*B+A)
print(s)