TnT/CodeNet4Repair huggingface dataset:
Problem:
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.  Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Incorrect submission (verdict: Wrong Answer):
s=input()
k='keyence'
if k in s:
    exit(print('YES'))

for i in range(len(k)):
    print(s[:i], s[len(k)-i:])
    if s[:i]+s[len(s)-len(k)+i:] == k:
        exit(print('YES'))
print('NO')


Fixed, accepted submission:
s=input()
k='keyence'
if k in s:
    exit(print('YES'))

for i in range(len(k)):
    #print(s[:i], s[len(k)-i:])
    if s[:i]+s[len(s)-len(k)+i:] == k:
        exit(print('YES'))
print('NO')
Problem:
On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis. Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i. Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.  For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.  That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
import sys

input = sys.stdin.readline


def read_values():
    return map(int, input().split())


def read_list():
    return list(read_values())


def func(N, mod):
    F = [1]
    for i in range(1, N + 1):
        F.append(F[-1] * i % mod)
    return F


INV = {}


def inv(a, mod):
    if a in INV:
        return INV[a]
    r = pow(a, mod - 2, mod)
    INV[a] = r
    return r


def C(F, a, b, mod):
    return F[a] * inv(F[b], mod) * inv(F[a - b], mod) % mod


def main():
    mod = 10 ** 9 + 7
    N, M = read_values()
    X = read_list()
    Y = read_list()

    res_x = 0
    for i in range(N - 1):
        res_x += (i + 1) * (N - i - 1) * (X[i + 1] - X[i]) % mod
        res_x %= mod

    res_y = 0
    for i in range(M - 1):
        res_y += (i + 1) * (M - i - 1) * (Y[i + 1] - Y[i]) % mod
        res_y %= mod
    print(res_x, res_y)

    print(res_x * res_y % mod)


if __name__ == "__main__":
    main()



Fixed, accepted submission:
import sys

input = sys.stdin.readline


def read_values():
    return map(int, input().split())


def read_list():
    return list(read_values())


def func(N, mod):
    F = [1]
    for i in range(1, N + 1):
        F.append(F[-1] * i % mod)
    return F


INV = {}


def inv(a, mod):
    if a in INV:
        return INV[a]
    r = pow(a, mod - 2, mod)
    INV[a] = r
    return r


def C(F, a, b, mod):
    return F[a] * inv(F[b], mod) * inv(F[a - b], mod) % mod


def main():
    mod = 10 ** 9 + 7
    N, M = read_values()
    X = read_list()
    Y = read_list()

    res_x = 0
    for i in range(N - 1):
        res_x += (i + 1) * (N - i - 1) * (X[i + 1] - X[i]) % mod
        res_x %= mod

    res_y = 0
    for i in range(M - 1):
        res_y += (i + 1) * (M - i - 1) * (Y[i + 1] - Y[i]) % mod
        res_y %= mod
    print(res_x * res_y % mod)


if __name__ == "__main__":
    main()
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
import math
x = int(input())
seen = [0] * 1001
ans = 1
for i in range(x):
    if(seen[i]): pass
    cur = i
    if(i > 1):
        while (cur <= x):
            cur *= i
            if(cur <= x): ans = max(ans, cur)
print(ans)


Fixed, accepted submission:
n = int(input())
s = input()
ans = 0
for i in range(n):
    x, y = s[:i], s[i:]
    cnt = 0
    for j in range(26):
        if x.count(chr(ord('a') + j)) and y.count(chr(ord('a') + j)):
            cnt += 1
    ans = max(ans, cnt)
print(ans)
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
N = int(input("何食食べた？："))
x = N * 800
y = (N // 15) * 200

A = x - y
print(A)

Fixed, accepted submission:

N = int(input())


x = 800 * N
y = N // 15 * 200

answer = x - y
print(answer)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int,input().split())
print('YES' if a<=c<=b else 'NO')

Fixed, accepted submission:
a,b,c = map(int,input().split())
print('Yes' if a<=c<=b else 'No')
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
s=list(input().split())

a=int(s[0])
b=int(s[1])
c=a*b%2
if c==0:
        d='Even'
else:
        d='Odd' 
print(c)

Fixed, accepted submission:
s=list(input().split())

a=int(s[0])
b=int(s[1])
c=a*b%2
if c==0:
        d='Even'
else:
        d='Odd' 
print(d)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n % 1000)

Fixed, accepted submission:
n = int(input())
tmp = 1000 - n % 1000
print(tmp) if tmp != 1000 else print(0)
Problem:
We have a sequence of N integers A~=~A_0,~A_1,~...,~A_{N - 1}.  Let B be a sequence of K \times N integers obtained by concatenating K copies of A. For example, if A~=~1,~3,~2 and K~=~2, B~=~1,~3,~2,~1,~3,~2.  Find the inversion number of B, modulo 10^9 + 7.  Here the inversion number of B is defined as the number of ordered pairs of integers (i,~j)~(0 \leq i < j \leq K \times N - 1) such that B_i > B_j.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

n, k = map(int, input().split())
a = np.array(list(map(int, input().split())))


coef = 0
for i in range(n):
    coef += np.where(a < a[i])[0].shape[0]

 - 調整数
diff = 0
for i in range(1, n):
    diff += np.where(a[:i - 1] < a[i])[0].shape[0]

mod = 10**9 + 7

ans = (coef * (1 + k) * k // 2 - diff) % mod

print(ans)

Fixed, accepted submission:
import numpy as np

n, k = map(int, input().split())
arr = np.array(list(map(int, input().split())))


a = 0
for i in range(n - 1):
    a += np.where(arr[i + 1:] < arr[i])[0].shape[0]


d = 0
for i in range(n):
    d += np.where(arr < arr[i])[0].shape[0]

mod = 10**9 + 7

ans = (a + a + d * (k - 1)) * k // 2 % mod

print(ans)
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
print('Yes' if len(input().split())==3 else 'No')

Fixed, accepted submission:
print('Yes' if len(set(input()))==3 else 'No')
Problem:
Write a program which reads a sequence and prints it in the reverse order.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
y = [int(i) for i in input().split()]
for i in range(x,0,-1):
    print('{0} '.format(i),end='')

Fixed, accepted submission:
input()
a = input().split()
a.reverse()
print(" ".join(a))
Problem:
Write a program which reads a list of student test scores and evaluates the performance for each student.  The test scores for a student include scores of the midterm examination m (out of 50), the final examination f (out of 50) and the makeup examination r (out of 100). If the student does not take the examination, the score is indicated by -1.  The final performance of a student is evaluated by the following procedure:    * If the student does not take the midterm or final examination, the student's grade shall be F.   * If the total score of the midterm and final examination is greater than or equal to 80, the student's grade shall be A.   * If the total score of the midterm and final examination is greater than or equal to 65 and less than 80, the student's grade shall be B.   * If the total score of the midterm and final examination is greater than or equal to 50 and less than 65, the student's grade shall be C.   * If the total score of the midterm and final examination is greater than or equal to 30 and less than 50, the student's grade shall be D. However, if the score of the makeup examination is greater than or equal to 50, the grade shall be C.   * If the total score of the midterm and final examination is less than 30, the student's grade shall be F.

Incorrect submission (verdict: Wrong Answer):
while True:
    m, f, r = [int(i) for i in input().split()]

    if m == f == r == -1:
        break

    if m + f <= 80:
        print('A')
    if 65<= m + f <80:
        print('B')
    if 50 <= m+f < 65:
        print('C')
    if 30<= m+f < 50:
        print('D')
    if m+r <= 30:
        print('F')
    if 50 <= r:
        print('C')
    else:
        m+f+r-1

Fixed, accepted submission:
while True:
    m, f, r = [int(i) for i in input().split()]
 
    if m == f == r == -1:
        break
 
    total = m + f
    if m == -1 or f == -1 or total < 30:
        print('F')
 
    elif total < 50 and r < 50:
        print('D')
 
    elif total < 65:
        print('C')
 
    elif total < 80:
        print('B')
         
    else:
        print('A')
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
from collections import defaultdict
n = int(input())

res = defaultdict(int)
for i in range(1, 105):
    for j in range(1, 105):
        for k in range(1, 105):
            v = i*i + j*j + k*k + i*j + j*k + k*i
            res[v] += 1

for i in range(n):
    print(res.get(i, 0))


Fixed, accepted submission:
from collections import defaultdict
n = int(input())

res = defaultdict(int)
for i in range(1, 105):
    for j in range(1, 105):
        for k in range(1, 105):
            v = i*i + j*j + k*k + i*j + j*k + k*i
            res[v] += 1

for i in range(1, n + 1):
    print(res.get(i, 0))
Problem:
When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.  You are given N numbers X_1, X_2, ..., X_N, where N is an even number. For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.  Find B_i for each i = 1, 2, ..., N.

Incorrect submission (verdict: Wrong Answer):
n= int(input())
m = int(n//2)
data = [int(i) for i in input().split()]

data.sort()

for i in range(m):
    print(data[m])
for i in range(m):
    print(data[m-1])

Fixed, accepted submission:
n= int(input())
m = int(n//2)
data = [int(i) for i in input().split()]

sdata = sorted(data)


for i in range(n):
    if data[i] < sdata[m]:
        print(sdata[m])
    else:
        print(sdata[m-1])
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n, a, b = map(int, input().split())
ans = 0
for i in range(n+1):
    if a <= sum(list(map(int,list(str(i))))) <=b:
        ans += 1
print(ans)

Fixed, accepted submission:
n, a, b = map(int, input().split())
ans = 0
for i in range(n+1):
    if a <= sum(list(map(int,list(str(i))))) <= b:
        ans += i
print(ans)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=int(input())
if(N%500==0 or N%500-A<=0):
    print('yes')
else:
    print('no')


Fixed, accepted submission:
N=int(input())
A=int(input())
if(N%500==0 or N%500-A<=0):
    print('Yes')
else:
    print('No')
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
s = str(input())
count = 0
if s[0] == "1":
    count += 1
elif s[1] == "1":
    count += 1
elif s[2] == "1":
    count += 1

print(count)


Fixed, accepted submission:
s = str(input())
count = 0
if s[0] == "1":
    count += 1
if s[1] == "1":
    count += 1
if s[2] == "1":
    count += 1

print(count)
Problem:
Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order. From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized. If there are multiple pairs that maximize the value, any of them is accepted.

Incorrect submission (verdict: Wrong Answer):
def main():
    n = int(input())
    A = list(map(int, input().split()))

    A = sorted(A)
    x = A[-1]
    del A[-1]
    b = x // 2

    m = 10**9
    y = A[0]
    for a in A:
        mm = abs(a - b)
        if mm < m:
            m = mm
            y = a

    print(x, y)


main()


Fixed, accepted submission:
def main():
    n = int(input())
    A = list(map(int, input().split()))

    A = sorted(A)
    x = A[-1]
    del A[-1]
    b = x / 2

    m = 10**9
    y = A[0]
    for a in A:
        mm = abs(a - b)
        if mm < m:
            m = mm
            y = a

    print(x, y)


main()
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a=[1,3,5,7,8,10,12]
b=[4,6,9,11]

n,m=map(int,input().split())

if n in a == m in a:
  print("Yes")
elif n in b == m in b:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a=[1,3,5,7,8,10,12]
b=[4,6,9,11]

n,m=map(int,input().split())

if n in a and m in a:
  print("Yes")
elif n in b and m in b:
  print("Yes")
else:
  print("No")
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
def main():

    n = int(input())
    numbers = list(map(int, input().split()))
    ans1 = max(numbers)
    ans2 = min(numbers)
    ans3 = sum(numbers)
    print(ans1, ans2, ans3)






if __name__=="__main__":
    main()

Fixed, accepted submission:
def main():

    n = int(input())
    numbers = list(map(int, input().split()))
    ans1 = min(numbers)
    ans2 = max(numbers)
    ans3 = sum(numbers)
    print(ans1, ans2, ans3)






if __name__=="__main__":
    main()
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter

S = input()
C = Counter(S)
ans = "YES"
for c in C.values():
	if c % 2 == 1:
		ans = 'NO'
		break
print(ans)

Fixed, accepted submission:
from collections import Counter

S = input()
C = Counter(S)
ans = "Yes"
for c in C.values():
	if c % 2 == 1:
		ans = 'No'
		break
print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
import sys
from collections import Counter
input()
ct=Counter(sys.stdin)
for k,v in ct.items():
    print(k.strip(),'x',v)


Fixed, accepted submission:
import sys
input()
d={k:0 for k in 'AC WA TLE RE'.split()}
for ln in sys.stdin:
    d[ln.strip()]+=1
for k,v in d.items():
    print(k,'x',v)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())



F=0
kekka=0
i=0
l=[]

while F==0:
    A=(a*i)%b
    if A==c:
        kekka="OK"
        F=1
    else:
        if l.count(A)==0:
            l.append(A)
            i+=1
        else:
            kekka="NG"
            F=1
            
print(kekka)





Fixed, accepted submission:
a,b,c=map(int,input().split())



F=0
kekka=0
i=0
l=[]

while F==0:
    A=(a*i)%b
    if A==c:
        kekka="YES"
        F=1
    else:
        if l.count(A)==0:
            l.append(A)
            i+=1
        else:
            kekka="NO"
            F=1
            
print(kekka)
Problem:
N persons are standing in a row. The height of the i-th person from the front is A_i.  We want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:  Condition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.  Find the minimum total height of the stools needed to meet this goal.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int,input().split()))

keep = 0
cnt =0
cnt2=0


for a in A:
    if keep > a:
        cnt += keep -a
        cnt2=0
        cnt2 += keep -a
    keep = a + cnt2
    
print(cnt)

Fixed, accepted submission:
N = int(input())
A = list(map(int,input().split()))

keep = 0
cnt =0
x=0


for a in A:
    if keep > a:
        cnt += keep -a
        x = keep -a
        keep = a + x
    else:
      keep = a
    
    
print(cnt)
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

import numpy as np

H, W, K = map(int, input().split())

c = np.zeros((H, W))
result = 0
for i in range(H):
    word = input()
    for j in range(W):
        if word[j] == '.':
            c[i][j] = 0
        elif word[j] == '#':
            c[i][j] = 1

for mask_h in range(2**H):
    bin_mask_h = format(mask_h,  '0' + str(H) + 'b')
    for mask_w in range(2**W):
        bin_mask_w = format(mask_w, '0' + str(W) + 'b')
        black_num = 0
        for i in range(H):
            if bin_mask_h[i] == '0':
                continue
            for j in range(W):
                if bin_mask_w[j] == '0':
                    continue
                if c[i][j] == 1:
                    black_num += 1
        print(str(bin_mask_h) + ' ' + str(bin_mask_w) + ' ' + str(black_num))
        if black_num == K:
            result += 1

print(result)


Fixed, accepted submission:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

import numpy as np

H, W, K = map(int, input().split())

c = np.zeros((H, W))
result = 0
for i in range(H):
    word = input()
    for j in range(W):
        if word[j] == '.':
            c[i][j] = 0
        elif word[j] == '#':
            c[i][j] = 1

for mask_h in range(2**H):
    bin_mask_h = format(mask_h,  '0' + str(H) + 'b')
    for mask_w in range(2**W):
        bin_mask_w = format(mask_w, '0' + str(W) + 'b')
        black_num = 0
        for i in range(H):
            if bin_mask_h[i] == '0':
                continue
            for j in range(W):
                if bin_mask_w[j] == '0':
                    continue
                if c[i][j] == 1:
                    black_num += 1
        # print(str(bin_mask_h) + ' ' + str(bin_mask_w) + ' ' + str(black_num))
        if black_num == K:
            result += 1

print(result)
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
s = input()
print(s)
n: int = 0
odds = []


for i in s:
    if n % 2 == 0:
        odd = s[n]
        odds += odd
    elif n == 0:
        odd = s[n]
        odds += odd
    else:
        pass
    n += 1
    
print(odds)

Fixed, accepted submission:
s = input()
# print(s)
n: int = 0
odds = ""


for i in s:
    if n % 2 == 0:
        odd = s[n]
        odds += odd
    elif n == 0:
        odd = s[n]
        odds += odd
    else:
        pass
    n += 1
    
print(odds)
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

s = input()
print(s)
for i in range(len(s)):
    if s[i] == 'A':
        s = s[i:]
        break

s = s[::-1]
print(s)

for i in range(len(s)):
    if s[i] == 'Z':
        s = s[i:]
        print(len(s))
        break


Fixed, accepted submission:
# -*- coding: utf-8 -*-

s = input()
for i in range(len(s)):
    if s[i] == 'A':
        s = s[i:]
        break

s = s[::-1]

for i in range(len(s)):
    if s[i] == 'Z':
        s = s[i:]
        print(len(s))
        break
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
def goatsSnuke():
    a = int(input('Quantos biscoitos tem na lata A? '))
    b = int(input('Quantos biscoitos tem na lata B? '))
    soma = a + b
    if a % 3 == 0:
        return 'Possible'
    elif b % 3 == 0:
        return 'Possible'
    elif soma % 3 == 0:
        return 'Possible'
    else:
        return 'Impossible'

Fixed, accepted submission:
a,b =(input().split())
a = int(a)
b = int(b)
soma = a + b
if a % 3 == 0:
    print ('Possible')
elif b % 3 == 0:
    print ('Possible')
elif soma % 3 == 0:
    print ('Possible')
else:
    print ('Impossible')