TnT/CodeNet4Repair huggingface dataset:
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

s = []
for i in range(n):
    s.append(input())

out = {"AC":0,"WA":0,"TLE":0,"RE":0}

for i in range(n):
    out[s[i]] += 1
for i in ["AC","WA","TLE","RE"]:
    print(f"{i} × {out[i]}") 


Fixed, accepted submission:
n = int(input())

s = []
for i in range(n):
    s.append(input())

out = {"AC":0,"WA":0,"TLE":0,"RE":0}

for i in range(n):
    out[s[i]] += 1
for i in ["AC","WA","TLE","RE"]:
    print(f"{i} x {out[i]}")
Problem:
You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Incorrect submission (verdict: Wrong Answer):
A = [int(_) for _ in input().split()]

ttt = all((x == 1or x == 9 or x== 7 or x == 4  for x in A))
print(ttt)

Fixed, accepted submission:
A = [int(_) for _ in input().split()]

res = sorted(set(A), key=A.index)
ttt = all((x == 1or x == 9 or x== 7 or x == 4  for x in A))

if ttt and len(res)==4:
    print("YES")
else:
    print("NO")
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int,input().split())
k = int(input())
count = -1

if a > b:
    for i in range(k):
        b = 2*b
        if a < b:
            count = i
            break
if b > c:
    for j in range(count+1, k):
        c = 2*c
        if b < c:
            break
if a < b and b < c:
        print("Yes")
else:
    print("No")
print(a, b, c)

Fixed, accepted submission:
a, b, c = map(int,input().split())
k = int(input())
count = -1

if a >= b:
    for i in range(k):
        b = 2*b
        if a < b:
            count = i
            break
if b >= c:
    for j in range(count+1, k):
        c = 2*c
        if b < c:
            break
if a < b and b < c:
        print("Yes")
else:
    print("No")
Problem:
We have an H \times W grid whose squares are painted black or white. The square at the i-th row from the top and the j-th column from the left is denoted as (i, j).   Snuke would like to play the following game on this grid. At the beginning of the game, there is a character called Kenus at square (1, 1). The player repeatedly moves Kenus up, down, left or right by one square. The game is completed when Kenus reaches square (H, W) passing only white squares.   Before Snuke starts the game, he can change the color of some of the white squares to black. However, he cannot change the color of square (1, 1) and (H, W). Also, changes of color must all be carried out before the beginning of the game.   When the game is completed, Snuke's score will be the number of times he changed the color of a square before the beginning of the game. Find the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed, that is, Kenus can never reach square (H, W) regardless of how Snuke changes the color of the squares.  The color of the squares are given to you as characters s_{i, j}. If square (i, j) is initially painted by white, s_{i, j} is `.`; if square (i, j) is initially painted by black, s_{i, j} is `#`.

Incorrect submission (verdict: Wrong Answer):
H,W=map(int, input().split())
S = tuple(input().rstrip() for _ in range(H))
a=0
d=[(1,0),(-1,0),(0,1),(0,-1)]
lity=[[0 for i in range(W)] for j in range(H)]
lity[0][0]=1
def roop()->None:
  p=[(0,0)]
  while p:
    x,y=p.pop(0)
    for dx,dy in d:
      if 0<=x+dx<H and 0<=y+dy<W and S[x+dx][y+dy]=='.' and lity[x+dx][y+dy]==0:
        p.append((x+dx,y+dy))
        lity[x+dx][y+dy]=lity[x][y]+1
roop()
white=sum(t.count(".") for t in S)
x=lity[-1][-1]
print(lity)
print(x)
ans = white - x
if 0<x:
  print(ans)
else:
  print(-1)

Fixed, accepted submission:
from collections import deque
H,W=map(int,input().split())
s=[['#']*(W+2)for _ in range(H+2)]
count=0
for i in range(1,H+1):
  S=list(input())
  s[i]=['#']+S+['#']
  count+=S.count('.')
move=[(1,0),(-1,0),(0,1),(0,-1)]
que=deque([(1,1)])
s[1][1]=1
while que:
  a,b=que.popleft()
  if (a,b)==(H,W):
    break
  for my,mx in move:
    ny=my+a
    nx=mx+b
    if s[ny][nx]=='#':
      continue
    elif s[ny][nx]=='.':
      que.append((ny,nx))
      s[ny][nx]=s[a][b]+1
ans=-1
if s[H][W]!='.':
  ans=count-s[H][W]
print(ans)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())

print(max(abs(x-a), abs(x-b)))

Fixed, accepted submission:
x, a, b = map(int, input().split())
print("A") if abs(x-a)<abs(x-b) else print("B")
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A, B, X = list(map(int, input().split()))

if 0<=X-A and X-A<=B:
    print('Yes')
else:
    print('No')


Fixed, accepted submission:
A, B, X = list(map(int, input().split()))

if 0<=X-A and X-A<=B:
    print('YES')
else:
    print('NO')
Problem:
You are given a sequence of _n_ integers S and a sequence of different _q_ integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = set(input().split())
q = int(input())
t = set(input().split())

print(len(s) - len(s & t))

Fixed, accepted submission:
n = int(input())
s = set(input().split())
q = int(input())
t = set(input().split())

print(len(s & t))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
def resolve():
    N = int(input())
    ans = [0,0,0,0]
    for i in range(N):
        S = input()
        if S == 'AC':
            ans[0] += 1
        if S == 'WA':
            ans[1] += 1
        if S == 'TLE':
            ans[2] += 1
        if S == 'RE':
            ans[3] += 1
    print( 'AC × ' + str(ans[0]) )
    print( 'WA × ' + str(ans[1]) )
    print( 'TLE × ' + str(ans[2]) )
    print( 'RE × ' + str(ans[3]) )
resolve()

Fixed, accepted submission:
def resolve():
    N = int(input())
    ans = [0,0,0,0]
    for i in range(N):
        S = input()
        if S == 'AC':
            ans[0] += 1
        if S == 'WA':
            ans[1] += 1
        if S == 'TLE':
            ans[2] += 1
        if S == 'RE':
            ans[3] += 1
    print( 'AC x ' + str(ans[0]) )
    print( 'WA x ' + str(ans[1]) )
    print( 'TLE x ' + str(ans[2]) )
    print( 'RE x ' + str(ans[3]) )
resolve()
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x=int(input())
n=100
cnt=0
while n<=x:
  n=int(n*1.01)
  cnt+=1
print(cnt)

Fixed, accepted submission:
x=int(input())
n=100
cnt=0
while n<x:
  n=int(n*1.01)
  cnt+=1
print(cnt)
Problem:
We will call a string that can be obtained by concatenating two equal strings an _even_ string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.  You are given an even string S consisting of lowercase English letters. Find the length of the longest even string that can be obtained by deleting one or more characters from the end of S. It is guaranteed that such a non-empty string exists for a given input.

Incorrect submission (verdict: Wrong Answer):
S = input()
ans = 0
for i in range(1, len(S)):
  s = S[: -2*i]
  l = (len(S) - 2*i) // 2
  if s[:l] == s[l:]:
    ans = 2*i
    break
print(ans)

Fixed, accepted submission:
S = input()
ans = 0
for i in range(1, len(S)):
  s = S[: -2*i]
  l = (len(S) - 2*i) // 2
  if s[:l] == s[l:]:
    ans = len(S) - 2*i
    break
print(ans)
Problem:
We have a 3×3 square grid, where each square contains a lowercase English letters. The letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.  Print the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.

Incorrect submission (verdict: Wrong Answer):
s1=input()
s2=input()
s3=input()

print(s1[0],s2[1],s3[2])

Fixed, accepted submission:
s1=input()
s2=input()
s3=input()

print(s1[0]+s2[1]+s3[2])
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

def check(t, x, y):
    for i in range(t + 1):
        for j in range(t + 1 - i):
            for k in range(t + 1 - i - j):
                if (i - j == x) and (k - (t - i - j - k)) == y:
                    return True
    return False

if all(check(l[0], l[1], l[2]) for l in [list(map(int, input().split())) for i in range(n)]):
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
n = int(input())

def check(t, x, y):
    return (t - (abs(x) + abs(y))) >= 0 and (t - (abs(x) + abs(y))) % 2 == 0
t0, x0, y0 = 0, 0, 0
for l in [list(map(int, input().split())) for i in range(n)]:
    if not check(l[0] - t0, l[1] - x0, l[2] - y0):
        print('No')
        exit()
    t0, x0, y0 = l[0], l[1], l[2]
print('Yes')
Problem:
Two foxes Jiro and Saburo are playing a game called _1D Reversi_. This game is played on a board, using black and white stones. On the board, stones are placed in a row, and each player places a new stone to either end of the row. Similarly to the original game of Reversi, when a white stone is placed, all black stones between the new white stone and another white stone, turn into white stones, and vice versa.  In the middle of a game, something came up and Saburo has to leave the game. The state of the board at this point is described by a string S. There are |S| (the length of S) stones on the board, and each character in S represents the color of the i-th (1 ≦ i ≦ |S|) stone from the left. If the i-th character in S is `B`, it means that the color of the corresponding stone on the board is black. Similarly, if the i-th character in S is `W`, it means that the color of the corresponding stone is white.  Jiro wants all stones on the board to be of the same color. For this purpose, he will place new stones on the board according to the rules. Find the minimum number of new stones that he needs to place.

Incorrect submission (verdict: Wrong Answer):
ret=0
s=input()
for i in range(len(s)-1):
  if s[i]==s[i+1]:
    ret+=1
print(ret)

Fixed, accepted submission:
ret=0
s=input()
for i in range(len(s)-1):
  if s[i]!=s[i+1]:
    ret+=1
print(ret)
Problem:
Rng is going to a festival.  The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.  Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.

Incorrect submission (verdict: Wrong Answer):
s=input()
for x in range(len(s)-8):print(s[x])

Fixed, accepted submission:
s = input()
print(s[:-8])
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n, a, b = list(map(int, input().split()))
res = 0
for i in range(1, n+1):
  sum = int(i/10000) + int(i%10000/1000) + int(i%1000/100) + int(i%100/10) + int(i%10)
  print(i, sum)
  if a <= sum and sum <= b:
    res += i

print(res)

Fixed, accepted submission:
def findSumOfDigits(n):
  sum = 0
  while n > 0:
    sum += n % 10
    n = int(n/10)
  return sum

N, A, B = list(map(int, input().split()))
total = 0
for i in range(1, N+1):
  if A <= findSumOfDigits(i) <= B:
    total += i

print(total)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):

a,b=map(int,input().split())
if(a%3==0 or b%3==0 or (a+b)%3==0):
    print("possible")

else:
    print("Impossible")
    






        
        


Fixed, accepted submission:

a,b=map(int,input().split())
if(a%3==0 or b%3==0 or (a+b)%3==0):
    print("Possible")

else:
    print("Impossible")
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
print(x*3)



Fixed, accepted submission:
print(int(input())**3)
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
*a,= [int(input()) for _ in range(n)]
len(set(a))

Fixed, accepted submission:
n = int(input())
*a,= [int(input()) for _ in range(n)]
print(len(set(a)))
Problem:
There are N cities and M roads. The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally. There may be more than one road that connects the same pair of two cities. For each city, how many roads are connected to the city?

Incorrect submission (verdict: Wrong Answer):
n, m = map(int, input().split())
load = []
load.extend(map(int, input().split()))

for i in range(n):
    print(load.count(i+1))

Fixed, accepted submission:
n, m = map(int, input().split())
load = []
for _ in range(m):
	load.extend(map(int, input().split()))

for i in range(n):
    print(load.count(i+1))
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
N = list(map(int,input().split()))

if N[2] >= N[0] and N[2] <= N[1]:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
N = list(map(int,input().split()))

if N[2] >= N[0] and N[2] <= N[1]:
    print("Yes")
else:
    print("No")
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r, g, b = map(int, input().split())
print("Yes" if (10 * g + b) % 4 == 0 else "No")



Fixed, accepted submission:
r, g, b = map(int, input().split())
print("YES" if (10 * g + b) % 4 == 0 else "NO")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

answer = (a + b) * h /2

print(answer)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())

answer = (a + b) * h /2

print(int(answer))
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
s=input()
x=int(s)**3


print('s=',s,'x=',x)



Fixed, accepted submission:


x=input()
n=int(x)**3
print(n)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
abc = list(map(int,input().split()))
ans = "No"
if 5 in abc:
  abc.remove(5)
  if 5 in abc and 7 in abc:
    ans = "Yes"

print(ans)

Fixed, accepted submission:
abc = list(map(int,input().split()))
ans = "NO"
if 5 in abc:
  abc.remove(5)
  if 5 in abc and 7 in abc:
    ans = "YES"

print(ans)
Problem:
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.  He wrote an integer X on the blackboard, then performed the following operation N times:    * Choose one element from S and remove it.   * Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.  There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
import bisect
import os
from collections import Counter, deque
from fractions import gcd
from functools import lru_cache
from functools import reduce
import functools
import heapq
import itertools
import math
import numpy as np
import re
import sys

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(2147483647)
INF = float("inf")

N, X = list(map(int, sys.stdin.readline().split()))
S = list(map(int, sys.stdin.readline().split()))
MOD = 10 ** 9 + 7

S.sort()


def test(x, i):
    
    if i == 0:
        ret = [0.0] * max(X, *S)
        ret[x % S[i]] = 1.0
        return np.array(ret)
    
    ret = test(x % S[i], i=0)
    for j in range(1, i):
        ret += test(x % S[i], i=j)
    return ret / i


ans = 0
for i in range(N):
    ans += test(X, i) / N
print(np.dot(ans, range(len(ans))) * math.factorial(N) % MOD)


Fixed, accepted submission:
import math
import os
import sys

import numpy as np

if os.getenv("LOCAL"):
    sys.stdin = open("_in.txt", "r")

sys.setrecursionlimit(2147483647)
INF = float("inf")

N, X = list(map(int, sys.stdin.readline().split()))
S = list(map(int, sys.stdin.readline().split()))
MOD = 10 ** 9 + 7


def mod_invs(max, mod):
    
    invs = [1] * (max + 1)
    for x in range(2, max + 1):
        invs[x] = (-(mod // x) * invs[mod % x]) % mod
    return invs


S.sort()

invs = mod_invs(N, MOD)
dp = np.arange(X + 1) % S[0]
for i in range(1, N):
    dp += dp[np.arange(X + 1) % S[i]] * invs[i]
    dp %= MOD
print(int(dp[X] * math.factorial(N) % MOD * invs[N] % MOD))
Problem:
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.  Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-

h,w=map(int,input().split())
ans=h*w
if h*w%3==0:
    print(0)
else:
    for x,y in ((h,w),(w,h)):
        x1=x//3
        x2=(x+2)//3
        y1=y//2
        y2=(y+1)//2
        ans=min(ans,abs(y*x2-y*x1))
        ans=min(ans,abs(y*x2-(x-x2)*(y-y2)))
        ans=min(ans,abs(y*x1-(x-x1)*(y-y2)))
print(ans)

Fixed, accepted submission:
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-

h,w=map(int,input().split())
for i in range(h+2):
    if i==0 or i==h+1:
        print("#"*w+"##")
    else:
        a=input()
        print("#"+a+"#")
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
import math
a, b = map(int, input().split())
print((a+b)/2)
print(math.ceil((a+b)/2))

Fixed, accepted submission:
import math
a, b = map(int, input().split())
print(math.ceil((a+b)/2))
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def insertionSort(A, N):
    for i in range(N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j + 1] = A[j]
            j -= 1
        A[j + 1] = v
        print(A)

n = int(input())
a = [int(i) for i in input().split()]

insertionSort(a,n)

Fixed, accepted submission:
def insertionSort(A, N):
    for i in range(N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j + 1] = A[j]
            j -= 1
        A[j + 1] = v
        t = str(A[0])
        for i in range(1,N):
            t = t + " " + str(A[i])
        print(t)


             
n = int(input())
a = [int(i) for i in input().split()]

insertionSort(a,n)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
x = input();
a = '7 7'in x

if a == True :print("NO")
else : print("Yes")

Fixed, accepted submission:
x = input()
a = x.count("5")
b = x.count("7")
if a == 2 and b == 1 :print("YES")
else : print("NO")