TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
#49c
S = str(input()) 




i = len(S) - 5
if i < 0:
    print("NO")
else:
    while i >= 0:
        end_5_char = S[i:i+5]

        print(i,end_5_char)

        if end_5_char == "eamer":
            print(i,S[i-2:i])
            if i < 2 or S[i-2:i] != "dr":
                print("NO")
                break
            else:
                i -= 2
        elif end_5_char == "raser":
            print(i,S[i-1:i])
            if i < 1 or S[i-1:i] != "e":
                print("NO")
                break
            else:
                i -= 1
        elif end_5_char != "dream" and end_5_char != "erase":
            print("NO")
            break

        i -= 5
    else:
        print("OK")

Fixed, accepted submission:
#49c
S = str(input()) 




i = len(S) - 5
if i < 0:
    print("NO")
else:
    while i >= 0:
        end_5_char = S[i:i+5]

        #print(i,end_5_char)

        if end_5_char == "eamer":
            #print(i,S[i-2:i])
            if i < 2 or S[i-2:i] != "dr":
                print("NO")
                break
            else:
                i -= 2
        elif end_5_char == "raser":
            #print(i,S[i-1:i])
            if i < 1 or S[i-1:i] != "e":
                print("NO")
                break
            else:
                i -= 1
        elif end_5_char != "dream" and end_5_char != "erase":
            print("NO")
            break

        i -= 5
    else:
        print("YES")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
import math 
a,b=input().split()
c = a + b 
n_c = int(c)

if math.sqrt(n_c).is_integer == True :
    print("Yes")
    
else:
    print("No")


Fixed, accepted submission:
import math 
a,b=input().split()
c = a + b 
n_c = int(c)
if((n_c ** 0.5).is_integer()==True):
        print("Yes")
else:
    print('No')
Problem:
There are N people standing in a row from west to east. Each person is facing east or west. The directions of the people is given as a string S of length N. The i-th person from the west is facing east if S_i = `E`, and west if S_i = `W`.  You will appoint one of the N people as the leader, then command the rest of them to face in the direction of the leader. Here, we do not care which direction the leader is facing.  The people in the row hate to change their directions, so you would like to select the leader so that the number of people who have to change their directions is minimized. Find the minimum number of people who have to change their directions.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = input()

ans = n

for i in range(0, n):
  kaeru = sum(s[j] == 'W' for j in range(i)) + sum(s[j] == 'E' for j in range(i+1,n))
  
  print(kaeru)
  ans = min(kaeru, ans)
print(ans)

Fixed, accepted submission:
n = int(input())
s = input()

w = [0] * n
for i in range(n-1):
  w[i+1] = w[i] + int(s[i] == 'W')
    
    
e = [0] * n
for i in reversed(range(1, n)):
  e[i-1] = e[i] + int(s[i] == 'E')
    
print(min(ww+ee for ww, ee in zip(w, e)))
Problem:
For a given weighted graph $G = (V, E)$, find the minimum spanning tree (MST) of $G$ and print total weight of edges belong to the MST.

Incorrect submission (verdict: Wrong Answer):
INF = 9999


def prim(G):
    n = len(G)
    color = ['White' for _ in range(n)]
    d = [INF for _ in range(n)]
    p = [-1 for _ in range(n)]
    d[0] = 0

    while True:
        mincost = INF
        u = -1
        for i in range(n):
            if color[i] != 'Black' and d[i] < mincost:
                mincost = d[i]
                u = i

        if u == -1:
            break

        color[u] = 'Black'

        for v in range(n):
            if color[v] != 'Black' and G[u][v] != INF:
                if G[u][v] < d[v]:
                    d[v] = G[u][v]
                    p[v] = u
                    color[u] = 'Gray'

        sum = 0
        for i in range(n):
            if p[i] != -1:
               sum += G[i][p[i]]
        return sum


if __name__ == '__main__':
    n = int(input())
    GL = [list(map(int, input().split())) for _ in range(n)]
    for i in range(n):
        for j in range(n):
            if GL[i][j] == -1:
                GL[i][j] = INF
    print(prim(GL))

Fixed, accepted submission:
INF = 9999


def prim(M):
    n = len(M)
    color = [0] * n
    d = [INF] * n
    d[0] = 0

    while True:
        minv = INF
        u = -1
        for i in range(n):
            # Black:2
            if minv > d[i] and color[i] != 2:
                u = i
                minv = d[i]
        if u == -1: break
        color[u] = 2

        for v in range(n):
            if color[v] != 2 and M[u][v] != INF:
                if d[v] > M[u][v]:
                    d[v] = M[u][v]
    return sum(d)


if __name__ == '__main__':
    n = int(input())
    A = []
    for i in range(n):
        src = input()
        dst = src.replace('-1', str(INF))
        ai = list(map(int, dst.split()))
        A.append(ai)
    print(prim(A))
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
n,y = list(map(int,input().split()))
if y/10000 > n:
    print('-1 -1 -1')
else:
    b = False
    YY =[]
    Y10=1+int(y/10000)
    Y5 =1+int((y%10000)/5000)
    Y1 =1+int((y%5000)/1000)
    for i in range(Y10):
        if b== True:
            break
        if i <= n:
            YY.append(i)
        for j in range(Y5+2*i):
            if b == True:
                break
            if i+j <= n:
                YY.append(j)
            for k in range(Y1 +5*j):
                if i+j+k <= n and i*10000+j*5000+k*1000 ==y:
                    YY = [i,j,k]
                    print('%d %d %d' % (YY[0], YY[1], YY[2]))
                    b = True
                    break
                else:
                    YY=[]

Fixed, accepted submission:
n,y = list(map(int,input().split()))
if y/10000 > n:
    print('-1 -1 -1')
if y/10000 ==n:
    print('%d %d %d' % (y/10000, 0, 0))
else:
    b = False
    YY =[]
    Y10=int(y/10000)
    Y5 =int(y/5000)
    Y1 =int(y/1000)
    for i in range(Y10,-1,-1):
        if b== True or i > n:
            break
        for j in range(Y5+1-2*i):
            if b == True or i+j > n:
                break
            k = n - i - j
            if i*10000+j*5000+k*1000 ==y:
                YY = [i,j,k]
                print('%d %d %d' % (YY[0], YY[1], YY[2]))
                b = True
                break
            else:
                YY=[]
        if i == 0 and b == False:
            print('-1 -1 -1')
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
s = input()
s = s.replace("hi", "")
if s:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
s = input()
s = s.replace("hi", "")
if s == "":
  print("Yes")
else:
  print("No")
Problem:
You are given two positive integers A and B. Compare the magnitudes of these numbers.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
if a>b:
  print("GRATER")
elif a<b:
  print("LESS")
else:
  print("EQUAL")

Fixed, accepted submission:

A = int(input())
B = int(input())

if (A > B):
    print("GREATER")
elif (A < B):
    print("LESS")
elif (A == B):
    print("EQUAL")
Problem:
M-kun is a competitor in AtCoder, whose highest rating is X.   In this site, a competitor is given a _kyu_ (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:    * From 400 through 599: 8-kyu   * From 600 through 799: 7-kyu   * From 800 through 999: 6-kyu   * From 1000 through 1199: 5-kyu   * From 1200 through 1399: 4-kyu   * From 1400 through 1599: 3-kyu   * From 1600 through 1799: 2-kyu   * From 1800 through 1999: 1-kyu  What kyu does M-kun have?

Incorrect submission (verdict: Wrong Answer):
X = int(input())

lst = [ [400, 599, 8], [600, 799, 7], [800, 999, 6], [1000, 1199, 5], [1200, 1399, 4], [1400, 1599, 3], [1600, 1799, 2], [1800, 1999, 1] ]

def Kyu(X):
   
   for i in lst:
      if i[0] <= X <= i[1]:
         result = i[2]
         break
   
   print(result)

Fixed, accepted submission:
X = int(input())

lst = [ [400, 599, 8], [600, 799, 7], [800, 999, 6], [1000, 1199, 5], [1200, 1399, 4], [1400, 1599, 3], [1600, 1799, 2], [1800, 1999, 1] ]

def Kyu(X):
   
   for i in lst:
      if i[0] <= X <= i[1]:
         result = i[2]
         break
   print(result)

Kyu(X)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = n % 1000
print(ans)

Fixed, accepted submission:
n = int(input())
ans = n % 1000
if ans != 0:
    ans = 1000-ans
print(ans)
Problem:
For a dynamic array $A = \\{a_0, a_1, ...\\}$ of integers, perform a sequence of the following operations:    * push($d$, $x$): Add element $x$ at the begining of $A$, if $d = 0$. Add element $x$ at the end of $A$, if $d = 1$.   * randomAccess($p$): Print element $a_p$.   * pop($d$): Delete the first element of $A$, if $d = 0$. Delete the last element of $A$, if $d = 1$.  $A$ is a 0-origin array and it is empty in the initial state.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

from collections import deque

n = int(input())
word = deque()

for i in range(n):
    command = list(map(int, input().split()))
    if command[0] == 0:
        if command[1] == 0:
            word.insert(0, command[1])
        else:
            word.append(command[1])
    elif command[0] == 1:
        print('{0}'.format(word[command[1]]))
    elif command[0] == 2:
        if command[1] == 0:
            word.pop()
        else:
            word.popleft()



Fixed, accepted submission:
# -*- coding: utf-8 -*-

from collections import deque

n = int(input())
word = deque()

for i in range(n):
    command = list(map(int, input().split()))
    if command[0] == 0:
        if command[1] == 0:
            word.insert(0, command[2])
        else:
            word.append(command[2])
    elif command[0] == 1:
        print('{0}'.format(word[command[1]]))
    elif command[0] == 2:
        if command[1] == 1:
            word.pop()
        else:
            word.popleft()
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python
size = int(input())
line = list(map(int, input().split()))

def insertionSort(A, N):
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v


def main():
    insertionSort(line, size)
    ans = " ".join(map(str, line))
    print(ans)

if __name__ == '__main__':
    main()

Fixed, accepted submission:
#!/usr/bin/env python
size = int(input())
line = list(map(int, input().split()))

def insertionSort(A, N):
    ans = " ".join(map(str, line))
    print(ans)
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v
        ans = " ".join(map(str, line))
        print(ans)

def main():
    insertionSort(line, size)

if __name__ == '__main__':
    main()
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
p=list(map(int,input().split()))
p_=[]
b=True
c=0
while b:
  p_=list(map(lambda in_:type(in_)=="int",p))
  b = "False" in p_
  p_=list(map(lambda in_:in_/2,p))
  c+=1
print(c)

Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split()))
ans=0
flg=0
while flg==0:
    for i in a:
        if i%2 != 0:
            flg=1
    a=list(map(lambda x: x/2,a))
    ans+=1
print(ans-1)
Problem:
Let's arrange a deck of cards. There are totally 36 cards of 4 suits(S, H, C, D) and 9 values (1, 2, ... 9). For example, 'eight of heart' is represented by H8 and 'one of diamonds' is represented by D1.  Your task is to write a program which sorts a given set of cards in ascending order by their values using the Bubble Sort algorithms and the Selection Sort algorithm respectively. These algorithms should be based on the following pseudocode:                 BubbleSort(C) 1 for i = 0 to C.length-1 2     for j = C.length-1 downto i+1 3         if C[j].value < C[j-1].value 4             swap C[j] and C[j-1]                 SelectionSort(C) 1 for i = 0 to C.length-1 2     mini = i 3     for j = i to C.length-1 4         if C[j].value < C[mini].value 5             mini = j 6     swap C[i] and C[mini]   Note that, indices for array elements are based on 0-origin.  For each algorithm, report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).

Incorrect submission (verdict: Wrong Answer):
import copy
n=int(input())
num=input().split()
numa=copy.copy(num)
numb=copy.copy(num)

#buble
for i in range(0,n):
	a=0
	for j in range(n-1,i,-1):
		if numa[j]<numa[j-1]:
			a=numa[j]
			numa[j]=numa[j-1]
			numa[j-1]=a
print(' '.join(list(map(str,numa))))
print('Stable')

#select
for i in range(0,n):
	minj=i
	b=0
	for j in range(i,n):
		if numb[j]<numb[minj]:
			minj=j
	b=numb[minj]
	numb[minj]=numb[i]
	numb[i]=b
print(' '.join(list(map(str,numb))))
if numb==numa:
	print('Stable')
else:
	print('Not stable')
		



Fixed, accepted submission:
import copy
n=int(input())
num=input().split()
numa=copy.copy(num)
numb=copy.copy(num)

#buble
for i in range(0,n):
	a=0
	for j in range(n-1,i,-1):
		if numa[j][1:]<numa[j-1][1:]:
			a=numa[j]
			numa[j]=numa[j-1]
			numa[j-1]=a
print(' '.join(list(map(str,numa))))
print('Stable')

#select
for i in range(0,n):
	minj=i
	b=0
	for j in range(i,n):
		if numb[j][1:]<numb[minj][1:]:
			minj=j
	b=numb[minj]
	numb[minj]=numb[i]
	numb[i]=b
print(' '.join(list(map(str,numb))))
if numb==numa:
	print('Stable')
else:
	print('Not stable')
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
alpha=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

s=input()
s_list=sorted(set(s))
print(s_list)
for x, y in zip(s_list, alpha):
    if x!=y:
        print(y)
        exit()
print("None")

Fixed, accepted submission:
#alpha=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
alpha= list("abcdefghijklmnopqrstuvwxyz")

s=input()
for x in alpha:
    if x not in s:
        print(x)
        exit()
    
print("None")
Problem:
Write a program which reads an integer n and identifies the number of combinations of a, b, c and d (0 ≤ a, b, c, d ≤ 9) which meet the following equality:      a + b + c + d = n      For example, for n = 35, we have 4 different combinations of (a, b, c, d): (8, 9, 9, 9), (9, 8, 9, 9), (9, 9, 8, 9), and (9, 9, 9, 8).

Incorrect submission (verdict: Wrong Answer):
num=int(input())
sum=0
Range=10
for a in range(Range):
    for b in range(Range):
        for c in range(Range):
            for d in range(Range):
                if num==a+b+c+d:
                    sum+=1
print(sum)

Fixed, accepted submission:
while True:
    try:
        num=int(input())
    except:
        break
    sum=0
    Range=10
    for a in range(Range):
        for b in range(Range):
            for c in range(Range):
                for d in range(Range):
                    if num==a+b+c+d:
                        sum+=1
    print(sum)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
import sys
n=int(next(sys.stdin))
print(n%1000)


Fixed, accepted submission:
import sys
n=int(next(sys.stdin))
print((n+999)//1000*1000-n)
Problem:
There are N integers, A_1, A_2, ..., A_N, written on a blackboard.  We will repeat the following operation N-1 times so that we have only one integer on the blackboard.    * Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.  Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=[]
r=0
for i in input().split():
  a.append(int(i))
a.sort()
for i in range(n):
  if i<=n//2:
    r=r+a[-1-i]
  else:
    r=r-a[-1-i]
print(r)
while len(a)>1:
  b=a.pop(-1)
  c=a.pop(0)
  print(b,c)
  a.insert(0,c-b)

Fixed, accepted submission:
n=int(input())
a=[]
r=[]
for i in input().split():
  a.append(int(i))
a.sort()
t=a.pop(-1)
b=a.pop(0)
for i in a:
  if i>=0:
    r.append([b,i])
    b=b-i
  else:
    r.append([t,i])
    t=t-i
print(t-b)
r.append([t,b])
for i in r:
  print(i[0],i[1])
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r,g,b = [int(x) for x in input().split()]

if (r*100+g*10+b) % 4 == 0:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
r,g,b = [int(x) for x in input().split()]

if (r*100+g*10+b) % 4 == 0:
    print("YES")
else:
    print("NO")
Problem:
Takahashi, who works at DISCO, is standing before an iron bar. The bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.  Takahashi wanted to choose a notch and cut the bar at that point into two parts with the same length. However, this may not be possible as is, so he will do the following operations some number of times **before** he does the cut:    * Choose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).   * Choose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.  Find the minimum amount of money needed before cutting the bar into two parts with the same length.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int,input().split()))
l = 0
r = 0
ans = 0
for i in a:
  l += i
  r = sum(a)-l
  if l==r:
    break;
  elif l>r:
    ans = l-r
print(ans)

Fixed, accepted submission:
n = int(input())
a = list(map(int,input().split()))
b = sum(a)
l = 0
r = 0
x = 0
ans = 0
for i in a:
  l += i
  r = b - l
  if l==r:
    break;
  elif l>r:
    ans = min(l-r,y-x)
    break;
  x = l
  y = r
print(ans)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n,m,x,y = map(int, input().split())
x_list = list(map(int, input().split()))
y_list = list(map(int, input().split()))
x_list.sort()
y_list.sort()
if x_list[-1]+1 < y_list[0]:
  print("No War")
else:
  print("War")

Fixed, accepted submission:
n,m,x,y = map(int, input().split())
x_list = list(map(int, input().split()))
y_list = list(map(int, input().split()))
x_list.sort()
y_list.sort()
if x_list[-1] < y_list[0]:
  if (y_list[0] > x) and (x_list[-1] < y):
    print("No War")
  else:
    print("War")
else:
  print("War")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
a = int(input())

print(a%1000)

Fixed, accepted submission:
a = int(input())

b = a%1000
if(b > 0):
    print(1000-b)
else:
    print(b)