TnT/CodeNet4Repair huggingface dataset:
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if b<=a:
  print(a+1)
else:
  print(a)

Fixed, accepted submission:
a,b = map(int,input().split())
c = a - 1
if b<a :
  print(c)
else:
  print(a)
Problem:
Takahashi wants to gain muscle, and decides to work out at AtCoder Gym.  The exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up. These buttons are numbered 1 through N. When Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i. When Button i is not lighten up, nothing will happen by pressing it.  Initially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.  Determine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
button = list()
for i in range(N):
    button.append(int(input()))

pre  = 1
print(button)
i = 0
c = 1
rireki = [0]*N
while all: 
    if(button[i]==2):
        print(c)
        break
    rireki[i] +=1
    if(rireki[i]==2):
        print(-1)
        break
    i = button[i]-1
    c+=1

Fixed, accepted submission:
N = int(input())
button = list()
for i in range(N):
    button.append(int(input()))

pre  = 1
# print(button)
i = 0
c = 1
rireki = [0]*N
while all: 
    if(button[i]==2):
        print(c)
        break
    rireki[i] +=1
    if(rireki[i]==2):
        print(-1)
        break
    i = button[i]-1
    c+=1
Problem:
Summer vacation ended at last and the second semester has begun. You, a Kyoto University student, came to university and heard a rumor that somebody will barricade the entrance of your classroom. The barricade will be built just before the start of the A-th class and removed by Kyoto University students just before the start of the B-th class. All the classes conducted when the barricade is blocking the entrance will be cancelled and you will not be able to attend them. Today you take N classes and class i is conducted in the t_i- th period. You take at most one class in each period. Find the number of classes you can attend.

Incorrect submission (verdict: Wrong Answer):
import itertools

def getTi():
    return int(input())

N,A,B = map(int, input().split())
t = [getTi() for i in range(N)]
t.sort()
td = list(itertools.dropwhile(lambda x:A<=x and x<B, t))

print(len(td))

Fixed, accepted submission:
N,A,B = map(int, input().split())
t = [(A <= int(input()) < B) for i in range(N)]
print(t.count(False))
Problem:
You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Incorrect submission (verdict: Wrong Answer):
n = list(map(int, input().split()))
n.sort()
print('Yes') if n==[1, 4, 7, 9] else print('No')

Fixed, accepted submission:
n = list(map(int, input().split()))
n.sort()
print('YES') if n==[1, 4, 7, 9] else print('NO')
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
c = input()

str1 = "dream"
str2 = "dreamer"
str3 = "erase"
str4 = "eraser"

tmpstr = ""

endflag = False

while(True):
  tmpstr = c
  c.replace(c, str1)
  c.replace(c, str2)
  c.replace(c, str3)
  c.replace(c, str4)
  if (c == tmpstr):
    endflag = True
    break

if (endflag):
  print("NO")
else:
  print("YES")

Fixed, accepted submission:
c = input().rstrip('\n')

str1 = "eraser"
str2 = "erase"
str3 = "dreamer"
str4 = "dream"



c = c.replace(str1, "")
c = c.replace(str2, "")
c = c.replace(str3, "")
c = c.replace(str4, "")

if (c == ""):
  print("YES")
else:
  print("NO")
Problem:
太郎君はよくJOI雑貨店で買い物をする． JOI雑貨店には硬貨は500円，100円，50円，10円，5円，1円が十分な数だけあり，いつも最も枚数が少なくなるようなおつりの支払い方をする．太郎君がJOI雑貨店で買い物をしてレジで1000円札を1枚出した時，もらうおつりに含まれる硬貨の枚数を求めるプログラムを作成せよ．  例えば入力例1の場合は下の図に示すように，4を出力しなければならない．  

Incorrect submission (verdict: Wrong Answer):
COINS = [500, 100, 50, 10, 5, 1]

change = 1000 - int(input())
total = 0
for coin in COINS:
    total += change // coin
    change %= coin

print(total)

Fixed, accepted submission:
COINS = [500, 100, 50, 10, 5, 1]

change = 1000 - int(input())
while change != 1000:
    total = 0
    for coin in COINS:
        total += change // coin
        change %= coin

    print(total)

    change = 1000 - int(input())
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

x = int(input())

money = 100
i = 0
while True:
  money = math.floor(money*1.01)
  i += 1

  if money > x:
    break

print(i)

Fixed, accepted submission:
import math

X = int(input())

P = 100
step = 0

while P < X:
  P += math.floor(P / 100)
  step += 1

print(step)
Problem:
AtCoDeer the deer is seeing a quick report of election results on TV. Two candidates are standing for the election: Takahashi and Aoki. The report shows the ratio of the current numbers of votes the two candidates have obtained, but not the actual numbers of votes. AtCoDeer has checked the report N times, and when he checked it for the i-th (1≦i≦N) time, the ratio was T_i:A_i. It is known that each candidate had at least one vote when he checked the report for the first time.  Find the minimum possible total number of votes obtained by the two candidates when he checked the report for the N-th time. It can be assumed that the number of votes obtained by each candidate never decreases.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
t0, a0 = 1, 1
for _ in range(N):
    t, a = map(int, input().split())
    n = max((t0- 1)/ t+ 1, (a0-1)//a+1)
    t0, a0 = n*t, n*a

print(t0 + a0)

Fixed, accepted submission:
N = int(input())
t0, a0 = 1, 1
for _ in range(N):
    t, a = map(int, input().split())
    n = max((t0- 1)// t+ 1, (a0-1)//a+1)
    t0, a0 = n*t, n*a

print(t0 + a0)
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
words = ['dream', 'dreamer' ,'erase' ,'eraser']
t = ''
s = input()

s = s[::-1]
words = [word[::-1] for word in words]

start=0
for i in range(1, len(s)+1):
  if s[start:i] in words:
    t+=s[start:i]
    start=i
    
if s==t:
  print('True')
else:
  print('False')

Fixed, accepted submission:
words = ['dream', 'dreamer' ,'erase' ,'eraser']
t = ''
s = input()

s = s[::-1]
words = [word[::-1] for word in words]

start=0
for i in range(1, len(s)+1):
  if s[start:i] in words:
    t+=s[start:i]
    start=i
    
if s==t:
  print('YES')
else:
  print('NO')
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
s=str(input())
s1=s.count('R')
s2=s.count('B')
if(s1>s2):
    print('yes')
else:
    print('no')
    

Fixed, accepted submission:
n=int(input())
s=str(input())
s1=s.count('R')
s2=s.count('B')
if(s1>s2):
    print('Yes')
else:
    print('No')
Problem:
You are given an undirected connected graph with N vertices and M edges that does not contain self-loops and double edges.   The i-th edge (1 \leq i \leq M) connects Vertex a_i and Vertex b_i.  An edge whose removal disconnects the graph is called a _bridge_.   Find the number of the edges that are bridges among the M edges.

Incorrect submission (verdict: Wrong Answer):
import sys
import itertools

N, M = [int(i) for i in sys.stdin.readline().split()]
edges = [[] for _ in range(N)]
for l in sys.stdin.readlines():
  a, b = [int(i)-1 for i in l.strip().split()]
  edges[a].append(b)
  edges[b].append(a)

def flatten(l):
  return list(itertools.chain.from_iterable(l))

def is_spanning_tree(edges):
  new_edges = [[] for _ in range(N)]
  for a, b in edges:
    return 1
    new_edges[a].append(b)
    new_edges[b].append(a)
  edges = new_edges
  nodes = set([0])
  next_node_candidates = set(flatten([edges[n] for n in nodes]))
  while next_node_candidates:
    nodes.add(list(next_node_candidates)[0])
    next_node_candidates = set(flatten([edges[n] for n in nodes]))
    next_node_candidates = nodes ^ next_node_candidates 
  return True if len(nodes) == N else False

cnt = 0
edges = flatten([[(i, j) for j in edges[i] if i>=j] for i in range(N)])
incomplete_graphs = [[edges[j] for j in range(len(edges)) if i != j] for i in range(len(edges))]
spanning_trees = [1 if not is_spanning_tree(graph) else 0 for graph in incomplete_graphs]
print(len(spanning_trees))

Fixed, accepted submission:
import sys
import itertools

N, M = [int(i) for i in sys.stdin.readline().split()]
edges = [[] for _ in range(N)]
for l in sys.stdin.readlines():
  a, b = [int(i)-1 for i in l.strip().split()]
  edges[a].append(b)
  edges[b].append(a)

def flatten(l):
  return list(itertools.chain.from_iterable(l))

def is_spanning_tree(edges):
  # list of tuple to 2d-list
  new_edges = [[] for _ in range(N)]
  for a, b in edges:
    new_edges[a].append(b)
    new_edges[b].append(a)
  edges = new_edges
  nodes = set([0])
  next_node_candidates = set(flatten([edges[n] for n in nodes]))
  while next_node_candidates:
    nodes.add(list(next_node_candidates)[0])
    next_node_candidates = set(flatten([edges[n] for n in nodes]))
    next_node_candidates = [x for x in next_node_candidates if x not in nodes] 
  return True if len(nodes) == N else False

cnt = 0
edges = flatten([[(i, j) for j in edges[i] if i>=j] for i in range(N)])
incomplete_graphs = [[edges[j] for j in range(len(edges)) if i != j] for i in range(len(edges))]
spanning_trees = [1 if not is_spanning_tree(graph) else 0 for graph in incomplete_graphs]
print(sum(spanning_trees))
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a, b, x=map(int,input().split())
if a <= x <= a+b:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a, b, x=map(int,input().split())
if a <= x <= a+b:
  print("YES")
else:
  print("NO")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
a = N%1000
print(a%1000)

Fixed, accepted submission:
N=int(input())
a = N%1000
print((1000-a)%1000)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

x = int(input())
n = 100
i = 0
while n <= x:
    n += n * 0.01
    n = math.floor(n)
    i += 1
print(i)

Fixed, accepted submission:
import math

x = int(input())
n = 100
i = 0
while n < x:
    
    n = n * 101 // 100
    i += 1
print(i)
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = [int(i) for i in input().split()]
a.sort(reverse=True)
ans = a[0]
idx = 1
flag = False
for i in range(n-1):
    ans += a[idx]
    if flag:
        idx += 1
        flag = False
    else:
        flag = True
print(ans)

Fixed, accepted submission:
n = int(input())
a = [int(i) for i in input().split()]
a.sort(reverse=True)
ans = a[0]
idx = 1
flag = False
for i in range(n-2):
    ans += a[idx]
    if flag:
        idx += 1
        flag = False
    else:
        flag = True
print(ans)
Problem:
We say that a odd number N is _similar to 2017_ when both N and (N+1)/2 are prime.  You are given Q queries.  In the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.

Incorrect submission (verdict: Wrong Answer):
def main():
    numbers = [0] * (10 ** 5 + 1)
    prime = [0] * (10 ** 5 + 1)
    numbers[1] = 1
    prime[1] = 1
    for i in range(2, 10 ** 5 + 1):
        if i % 2:
            is_prime = True
            j = 1
            while j * j <= i and is_prime:
                if (not i % j) and j > 1:
                    is_prime = False
                j += 1
            if is_prime:
                prime[i] = 1
            if is_prime and prime[(i + 1) // 2]:
                numbers[i] = numbers[i - 1] + 1
            else:
                numbers[i] = numbers[i - 1]
        else:
            numbers[i] = numbers[i - 1]
    query = int(input())
    for _ in range(query):
        left, right = map(int, input().split())
        print(numbers[right] - numbers[left - 1])


if __name__ == '__main__':
    main()

Fixed, accepted submission:
def is_prime(n):
    result = True
    i = 2
    while i * i <= n:
        if n % i == 0:
            result = False
            break
        i += 1
    if n == 1:
        result = False
    return result


def main():
    q = int(input())
    max_num = 10 ** 5
    count_num = [0 for _ in range(max_num + 1)]
    is_prime_num = [False for _ in range(max_num + 1)]
    count_num[3] = 1
    is_prime_num[3] = True
    for i in range(4, max_num + 1):
        count_num[i] = count_num[i - 1]
        if i % 2:
            if is_prime(i):
                is_prime_num[i] = True
                count_num[i] = count_num[i - 1]
                if is_prime_num[(i + 1) // 2]:
                    count_num[i] += 1
    for _ in range(q):
        l, r = map(int, input().split())
        print(count_num[r] - count_num[l - 1])


if __name__ == '__main__':
    main()
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
a = input()
if a[0] == a[1] == a[2] == 1:
  print(3)
elif a[0] == a[1] == a[2] == 0:
  print(0)
elif a[0] == a[1] == 1 or a[1] == a[2] == 1:
  print(2)
elif a[0] == a[1] == 1 or a[1] == a[2] == 0:
  print(1)

Fixed, accepted submission:
a = input()
print(a.count('1'))
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n, m, x, y = map(int, input().split())
xs = list(map(int, input().split()))
ys = list(map(int, input().split()))
xs.append(x)
ys.append(y)
if max(xs) < min(ys):
    print("N0 War")
else:
    print("War")


Fixed, accepted submission:
n, m, x, y = map(int, input().split())
xs = list(map(int, input().split()))
ys = list(map(int, input().split()))
xs.append(x)
ys.append(y)
if max(xs) < min(ys):
    print("No War")
else:
    print("War")
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):
s=input()
a=len(s)
b=len(set(s))
if int(a/2)==b:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
s=input()
li=[i for i in s]
p="abcdefghijklmnopqrstuvwxyz"
for i in p:
    if li.count(i)%2==1:
        print("No")
        exit()
else:
    print("Yes")
Problem:
Given an integer N not less than 3, find the sum of the interior angles of a regular polygon with N sides.  Print the answer in degrees, but do not print units.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
print(n*(180-360/n)//1)

Fixed, accepted submission:
n=int(input())
print(n*180-360)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a%3==0 or b%3==0 or (a+b)%3==0:
    print("POSSIBLE")
else:
    print("IMPOSSIBLE")


Fixed, accepted submission:
a,b=map(int,input().split())
if a%3==0 or b%3==0 or (a+b)%3==0:
    print("Possible")
else:
    print("Impossible")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
n = int(input().replace(' ',''))
print('Yes' if (n*(1/2))**2 == n else 'No')

Fixed, accepted submission:
n = int(input().replace(' ',''))
print('Yes' if (int(n**(1/2)))**2 == n else 'No')
Problem:
In this problem, we only consider strings consisting of lowercase English letters.  Strings s and t are said to be **isomorphic** when the following conditions are satisfied:    * |s| = |t| holds.   * For every pair i, j, one of the following holds:     * s_i = s_j and t_i = t_j.     * s_i \neq s_j and t_i \neq t_j.  For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.  A string s is said to be in **normal form** when the following condition is satisfied:    * For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.  For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.  You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = [[] for i in range(n+1)]
s[1].append('a')
ans_s = []
for num in range(1,n):
    for st in s[num]:
        for add in range(97, max(map(ord,st))+2):
            s[num+1].append(st + chr(add))
print(s[n])

Fixed, accepted submission:
n = int(input())
s = [[] for i in range(n+1)]
s[1].append('a')
ans_s = []
for num in range(1,n):
    for st in s[num]:
        for add in range(97, max(map(ord,st))+2):
            s[num+1].append(st + chr(add))
for sw in s[n]:
    print(sw)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int, input().split())
l = list()
for i in range(x):
    if a <= a+i <= b:
        l.append(a+i)
    if a <= b+i <= b:
        l.append(b-i)
l = set(sorted(l))
for i in l:
    print(i)

Fixed, accepted submission:
a,b,x = map(int, input().split())
l = list()
for i in range(x):
    if a <= a+i <= b:
        l.append(a+i)
    if a <= b-i <= b:
        l.append(b-i)
l = sorted(set(l))
for i in l:
    print(i)
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
s = str(input())

if s[0] != s[1]: 
    if s[0] != s[2]:
        if s[1] != s[2]:
            print("yes")
        else:
            print("no")
    else:
        print("no")
else:
    print("no")

Fixed, accepted submission:
s = input()

if s[0] != s[1]: 
    if s[0] != s[2]:
        if s[1] != s[2]:
            print("Yes")
        else:
            print("No")
    else:
        print("No")
else:
    print("No")
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
A, B, C = map(int, input().split())
K = int(input())
m = max(A,B,C)
print(A+B+C-m+m**K)

Fixed, accepted submission:
A, B, C = map(int, input().split())
K = int(input())
m = max(A,B,C)
print(A+B+C-m+m*(2**K))