TnT/CodeNet4Repair huggingface dataset:
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
import itertools
import copy

h,w,k = map(int,input().split())
c = [list(input()) for i in range(h)]
ans = 0
hh = []
for i in range(h+1):
    hh.append(list(itertools.combinations(range(h+1), i)))
ww = []
for i in range(w+1):
    ww.append(list(itertools.combinations(range(w+1), i)))
# print(hh)
# print(hh[0])

for _ in range(h+1):
    for hs in hh[_]:
        #init
        temp = copy.deepcopy(c)
        # print(c)

        for i in hs:
            
            if i == 0:
                continue
            temp[i-1] = list('r' * w)

        for _ in range(w+1):
            for ws in ww[_]:
                #init
                temp2 = copy.deepcopy(temp)

                for j in ws:
                    
                    if j == 0:
                        continue
                    for ii in range(h):
                        # print(temp[ii][j-1])
                        temp2[ii][j-1] = 'r'
                print(temp2)
                
                cnttemp = 0
                for iii in range(h):
                    cnttemp+= temp2[iii].count('#')
                if cnttemp == k:
                    ans += 1

print(ans//4)


Fixed, accepted submission:
import itertools
import copy

h,w,k = map(int,input().split())
c = [list(input()) for i in range(h)]
ans = 0
hh = []
for i in range(h+1):
    hh.append(list(itertools.combinations(range(h+1), i)))
ww = []
for i in range(w+1):
    ww.append(list(itertools.combinations(range(w+1), i)))
# print(hh)
# print(hh[0])

for _ in range(h+1):
    for hs in hh[_]:
        #init
        temp = copy.deepcopy(c)
        # print(c)

        for i in hs:
            
            if i == 0:
                continue
            temp[i-1] = list('r' * w)

        for _ in range(w+1):
            for ws in ww[_]:
                #init
                temp2 = copy.deepcopy(temp)

                for j in ws:
                    
                    if j == 0:
                        continue
                    for ii in range(h):
                        # print(temp[ii][j-1])
                        temp2[ii][j-1] = 'r'
                # print(temp2)
                
                cnttemp = 0
                for iii in range(h):
                    cnttemp+= temp2[iii].count('#')
                if cnttemp == k:
                    ans += 1

print(ans//4)
Problem:
Ringo is giving a present to Snuke.  Ringo has found out that Snuke loves _yakiniku_ (a Japanese term meaning grilled meat. _yaki_ : grilled, _niku_ : meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.  You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.

Incorrect submission (verdict: Wrong Answer):
s=input()
if len(s)>=4:
    if s[0:3]=="YAKI":
        print("Yes")
    else:
        print("No")
else:
    print("No")

Fixed, accepted submission:
s=input()
if len(s)>=4:
    if s[0:4]=="YAKI":
        print("Yes")
    else:
        print("No")
else:
    print("No")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
print('A'+input()[0]+'C')

Fixed, accepted submission:
print('A'+input().split()[1][0]+'C')
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
A = list(map(int, input().split()))

flag = True
cnt = 0
while(flag):
    for i in range(len(A)):
        A[i] = A[i] / 2
        if A[i] % 2 != 0:
            flag = False
            break
    cnt = cnt + 1
print(cnt)

Fixed, accepted submission:
n = int(input())
A = list(map(int, input().split()))

flag = True
for i in range(n):
    if A[i] % 2 != 0:
        flag = False

cnt = 0
while(flag):
    for i in range(n):
        A[i] = A[i] / 2
        if A[i] % 2 != 0:
            flag = False
            break
    cnt = cnt + 1
print(cnt)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
A = list(map(int,input().split()))

if A.count(5) == 2 and A.count(7) == 1:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
A = list(input())

if A.count('5') == 2 and A.count('7') == 1:
    print('YES')
else:
    print('NO')
Problem:
We have a large square grid with H rows and W columns. Iroha is now standing in the top-left cell. She will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.  However, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.  Find the number of ways she can travel to the bottom-right cell.  Since this number can be extremely large, print the number modulo 10^9+7.

Incorrect submission (verdict: Time Limit Exceeded):
h, w, a, b = map(int, input().split(' '))

MOD = 10**9 + 7
MAX = 10**6 + 5


def mod(a, b):
    r = 1
    while b:
        if b & 1:
            r = (r * a) % MOD
        a = (a * a) % MOD
        b >>= 1
    return r


f = [0]*MAX
invf = [0]*MAX


def ncr(n, r):
    if r == 0 or r == n:
        return 1
    return (((f[n] * invf[n-r]) % MOD) * invf[r]) % MOD


f[0] = 1
for i in range(1, MAX):
    f[i] = (f[i-1] * i) % MOD
    invf[i] = mod(f[i], MOD-2)
r = 0
for i in range(b, w):
    y1 = h - a - 1
    x1 = i
    y2 = a - 1
    x2 = w - i - 1
    p = (ncr(x1 + y1, x1) * ncr(x2 + y2, x2)) % MOD
    r = (r + p) % MOD

print(r)


Fixed, accepted submission:
from array import *
import time
h, w, a, b = map(int, input().split(' '))
MOD = 10**9 + 7
MAX = max(h+w-a-1, a+w)


def modpow(a, b):
    res = 1
    while b:
        if (b & 1):
            res = (res * a) % MOD
        a = (a * a) % MOD
        b >>= 1
    return res


def nCr(n, r):
    if r == 0 or n == r:
        return 1
    return (((f[n] * ivf[n-r]) % MOD) * ivf[r]) % MOD


f = [1] * MAX
f = array('q', f)
ivf = [0] * MAX
ivf = array('q', ivf)
for i in range(1, MAX):
    f[i] = (f[i-1] * i) % MOD
    ivf[i] = modpow(f[i], MOD-2)
r = 0
for i in range(b, w):
    y1 = h - a - 1
    x1 = i
    y2 = a - 1
    x2 = w - i - 1
    p = (nCr(x1 + y1, x1) * nCr(x2 + y2, x2)) % MOD
    r = (r + p) % MOD
print(int(r))
Problem:
Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

able = 0
if c - a - b <= 0:
  able = 0
else:
  if (c - a - b) ** 2 > 2 * a * b:
  	able = 1
if able:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a, b, c = map(int, input().split())
 
able = 0
if c - a - b <= 0:
  able = 0
else:
  if (c - a - b) ** 2 > 4 * a * b:
  	able = 1
  else:
    able = 0
    
if able:
  print("Yes")
else:
  print("No")
Problem:
Snuke built an online judge to hold a programming contest.  When a program is submitted to the judge, the judge returns a verdict, which is a two-character string that appears in the string S as a contiguous substring. (The judge can return any two-character substring of S.)  Determine whether the judge can return the string `AC` as the verdict to a program.

Incorrect submission (verdict: Wrong Answer):
s=input()
ans='No'
for i in range(len(s)-1):
  if s[i]+s[i+1]=='AC':
    ans=='Yes'
print(ans)

Fixed, accepted submission:
s=input()
ans='No'
if s.count('AC')!=0:
  ans='Yes'
print(ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
a = input().split()
print(a.count('1'))

Fixed, accepted submission:
a = input()
print(a.count('1'))
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
print("A{}C".format(input()[0]))

Fixed, accepted submission:
list = [word for word in input().split()]

print("A{}C".format(list[1][0]))
Problem:
We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.  We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.  At most how many people can sit on the seat?

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
print(a-1//(b+c))

Fixed, accepted submission:
a,b,c=map(int,input().split())
print((a-c)//(b+c))
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
s = input()
print('yes' if list(s) == set(s) else 'no')

Fixed, accepted submission:
s = input()
print('yes' if len(list(s)) == len(set(s)) else 'no')
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if b >= c:
  print(c, b + c - a)
else:
  print(b, b + c - a)

Fixed, accepted submission:
n, a, b = map(int, input().split())
print(min(a, b), max(0, (a + b) - n))
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Time Limit Exceeded):
R, G, B, N = map(int, input().split())

ans = 0
for r in range(3001):
    for g in range(3001):
        tmp = N - r * R - g * G
        if tmp % B == 0 and tmp // B >= 0:
            ans += 1

print(ans)


Fixed, accepted submission:
R, G, B, N = map(int, input().split())

ans = 0
for r in range(N // R + 1):
    for g in range((N - R * r) // G + 1):
        tmp = N - r * R - g * G
        if tmp % B == 0:
            ans += 1

print(ans)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A,B,X = map(int,input().split())
if A > X:
    print("No")
elif X-A <= B:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
A,B,X = map(int,input().split())
if A > X:
    print("NO")
elif X-A <= B:
    print("YES")
else:
    print("NO")
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
def calc(x, y, z):
    return (x + y + z) ** 2 - x * y - y * z - z * x

def comb(x):
    fact = 1
    while x > 1:
        fact *= x
        x -= 1
    return fact

N = int(input())
res = [0] * (N + 1)
for i in range(1, 100):
    for j in range(i, 100):
        for k in range(j, 100):
            tmp = calc(i, j, k)
            if tmp > N:
                continue
            cnt = len(set([i, j, k]))
            res[tmp] += 6 // comb(4 - cnt)
print(*res, sep='\n')

Fixed, accepted submission:
def calc(x, y, z):
    return (x + y + z) ** 2 - x * y - y * z - z * x

def comb(x):
    fact = 1
    while x > 1:
        fact *= x
        x -= 1
    return fact

N = int(input())
res = [0] * (N + 1)
for i in range(1, 100):
    for j in range(i, 100):
        for k in range(j, 100):
            tmp = calc(i, j, k)
            if tmp > N:
                continue
            cnt = len(set([i, j, k]))
            res[tmp] += 6 // comb(4 - cnt)
print(*res[1:], sep='\n')
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Time Limit Exceeded):
n=int(input())
i=1
while(True):
  if (i+1)**2<=n:
    i+=1
print(i**2)

Fixed, accepted submission:
n=int(input())
i=1
while(True):
  if (i+1)**2<=n:
    i+=1
  else:
    break
print(i**2)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
#9
a,b,c = map(int,input().split())
ans = "No"

for i in range(1,b+1):
    if a*i%b == c:
        ans = "Yes"
        break
        
print(ans)

Fixed, accepted submission:
#9
a,b,c = map(int,input().split())
ans = "NO"

for i in range(1,b+1):
    if a*i%b == c:
        ans = "YES"
        break
        
print(ans)
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a, b, x = map(int, input().split())
count = b//x - a//x
if a == 0:
    print(count+1)
else:
    print(count)

Fixed, accepted submission:
a, b, x = map(int, input().split())
count = b//x - a//x
if a % x == 0:
    print(count+1)
else:
    print(count)
Problem:
We say that a odd number N is _similar to 2017_ when both N and (N+1)/2 are prime.  You are given Q queries.  In the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.

Incorrect submission (verdict: Time Limit Exceeded):
import math
def primes(n):
    a = list(range(2, n+1))
    primes = [2]
    for i in a:
        flag = True
        m = math.sqrt(i)
        for j in primes:
            if j > m:
                break
            else:
                if i % j == 0:
                    flag = False
                    break
        if flag:
            primes.append(i)
    return primes
primes = primes(10**5)
anss = []
for p in primes:
    if (p+1)//2 in primes:
        anss.append(p)
dp = [0]*(10**5+1)
cnt = 0
for i in range(1, 10**5+1, 2):
    if i in anss:
        cnt += 1
    dp[i] = cnt

    
Q = int(input())
for _ in range(Q):
    l, r = map(int, input().split())
    print(dp[r]-dp[l-2])

Fixed, accepted submission:
M = 10**5+1
p = [1]*M
p[0] = p[1] = 0
for i in range(2, 10**3):
    if p[i]:
        for j in range(i*i, M, i):
            p[j] = 0
C = [0]*M
for i in range(2, M):
    if p[i] and p[(i+1)//2]:
        C[i] = C[i-1] + 1
    else:
        C[i] = C[i-1]
q = int(input())
for i in range(q):
    l, r = map(int, input().split())
    print(C[r] - C[l-1])
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
W,H,N = (int(i) for i in input().split())

area = H*W

for i in range(N):
    x,y,a = (int(i) for i in input().split())
    if a == 1:
        area = area - H*x
    elif a == 2:
        area = area - H*(W-x)
    elif a == 3:
        area = area - W*y
    else:
        area = area - W*(H-y)

print(area)

Fixed, accepted submission:
W,H,N = (int(i) for i in input().split())

upright = [W,H]
downleft = [0,0]

for i in range(N):
    x,y,a = (int(k) for k in input().split())
    if a == 1:
        if x >= downleft[0]:
            downleft[0] = x
    elif a == 2:
        if x <= upright[0]:
            upright[0] = x
    elif a == 3:
        if y >= downleft[1]:
            downleft[1] = y
    else:
        if y <= upright[1]:
            upright[1] = y

height = upright[1]-downleft[1]
width = upright[0]-downleft[0]

if height >= 0 and width >= 0:
    area = height*width
else:
    area = 0

print(area)
Problem:
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
for a in range(-500, 500):
    for b in range(-500, 500):
        if a**5 - b**5 == x:
            print(a, b)

Fixed, accepted submission:
memorization_dict = dict()
max_number = 10 ** 13
i = 0
power_value = 0
while power_value <= max_number:
    power_value = i ** 5
    memorization_dict[power_value] = i
    i += 1

X = int(input())

solution_1 = 0
solution_2 = 0

for B in memorization_dict.keys():
    A = X + B
    if A in memorization_dict.keys():
        solution_1 = memorization_dict[A]
        solution_2 = memorization_dict[B]
        break
    A = X - B
    if A in memorization_dict.keys():
        solution_1 = memorization_dict[A]
        solution_2 = memorization_dict[B] * (-1)
        break

print(solution_1, solution_2)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
A=input()
B=A.split(" ")
a=int(B[0])
b=int(B[1])
c=a+b
import math
avg=math.floor(c/2)+1
print(avg)

Fixed, accepted submission:
A=input()
B=A.split(" ")
a=int(B[0])
b=int(B[1])
c=a+b
avg=c/2
iavg=int(c/2)
if avg==iavg:
 print(iavg)
else:
 import math
 print(math.floor(avg)+1)
Problem:
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.  Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.  Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.

Incorrect submission (verdict: Wrong Answer):
A, B, C, D = map(str, input().split())
L=A+B
R=C+D
print("left" if R < L else "right" if R > L else "Balanced")

Fixed, accepted submission:
A, B, C, D = map(int, input().split())
print(["Balanced","Left","Right"][A+B>C+D or -(A+B<C+D)])
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
count = 0

for i in range(n):
  if (i + 1) % 2 == 0:
    if a[i] % 2 == 0: 
      count += 1
      
print(count)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
count = 0
 
for i in range(n):
  if (i + 1) % 2 != 0:
    if a[i] % 2 != 0: 
      count += 1
      
print(count)
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(int(n//2))

Fixed, accepted submission:
n = int(input())
if n % 2 == 0:
  print(int(n/2 - 1))
else:
  print(int((n-1)/2))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

count = n // 1000
total = n - count * 1000
print(total)

Fixed, accepted submission:
n = int(input())
if n % 1000 != 0:
  count = n // 1000
  total = (count+1) * 1000 - n
  print(total)
elif n % 1000 == 0:
  print(0)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
A, B = map(int,input().split())
S = list(input())
ans = True
if len(S) != (A+B+1):
    ans = False
elif S.count("-") != 1:
    ans = False
elif S.index("-") != A:
    ans = False
elif S != [i for i in S if i.isdecimal() or i == "-"]:
    ans = False
print(ans)


Fixed, accepted submission:
A, B = map(int,input().split())
S = list(input())
ans = True
if len(S) != (A+B+1):
    ans = False
elif S.count("-") != 1:
    ans = False
elif S.index("-") != A:
    ans = False
elif S != [i for i in S if i.isdecimal() or i == "-"]:
    ans = False
if ans:
    print("Yes")
else:
    print("No")