TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a, b, x = list(map(int, input().split()))
if a % x == 0:
    m = a // x
else:
    m = a // x

if b % x == 0:
    M = b // x
else:
    M = b // x

print((M-m)/x)


Fixed, accepted submission:
a, b, x = list(map(int, input().split()))
M = b // x

if a % x == 0:
    m = a // x - 1
else:
    m = a//x

print(M-m)
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
print("A"+input()[0]+"C")

Fixed, accepted submission:
print("".join(s[0] for s in input().split()))
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
D,X = map(int, input().split())
for i in range(N):
  X += -(-D//int(input()))
  print(X)
print(X)

Fixed, accepted submission:
N = int(input())
D,X = map(int, input().split())
for i in range(N):
  X += -(-D//int(input()))
print(X)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
print("Yes" if a<=c>=b else "No")

Fixed, accepted submission:
a,b,c=map(int,input().split())
print("Yes" if a<=c<=b else "No")
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
D,X = map(int,input().split())

count = 0
A = [int(input()) for i in range(N)]
j = 0
for i in range(N):
    while j * A[i] + 1 <= D:
        j += 1
        count += 1
    print(count + X)

Fixed, accepted submission:
N = int(input())
D,X = map(int,input().split())

count = 0
A = [int(input()) for i in range(N)]

for i in range(N):
    j = 0
    while j * A[i] + 1 <= D:
        j += 1
        count += 1
print(count + X)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
total_sum, cats, animal = map(int,input().split())
if total_sum < cats:
  print("NO")
elif total_sum - cats - animal < 0:
  print("NO")
else:
  print("YES")

Fixed, accepted submission:
cats, animal, num = map(int,input().split())
if num > cats + animal:
  print("NO")
elif cats > num:
  print("NO")
else:
  print("YES")
Problem:
How many multiples of d are there among the integers between L and R (inclusive)?

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

print(b//c + a //c)

Fixed, accepted submission:
a, b, c = map(int, input().split())

d = 0

for i in range(a, b+1):
    if i % c == 0:
        d += 1

print(d)
Problem:
You are given a string S.  Takahashi can insert the character `A` at any position in this string any number of times.  Can he change S into `AKIHABARA`?

Incorrect submission (verdict: Wrong Answer):
S=list(str(input()))
for i in range(9):
    S.append('')
c=0
if S[0]!='A':
    c+=1
if S[1-c]!='K':
    c+=1
if S[2-c]!='I':
    c+=1
if S[3-c]!='H':
    c+=1
if S[4-c]!='A':
    c+=1
if S[5-c]!='B':
    c+=1
if S[6-c]!='A':
    c+=1
if S[7-c]!='R':
    c+=1
if S[8-c]!='A':
    c+=1
#print(c)
if len(S)+c-9==9:
    print('Yes')
else:
    print('No')


Fixed, accepted submission:
S=list(str(input()))
for i in range(9):
    S.append('')
t=''
for i in range(9):
    if i==0 or i==4 or i==6 or i==8:
        if S[0]=='A':
            t+=S.pop(0)
        else:
            t+='A'
    elif i==1:
        if S[0]=='K':
            t+=S.pop(0)
    elif i==2:
        if S[0]=='I':
            t+=S.pop(0)
    elif i==3:
        if S[0]=='H':
            t+=S.pop(0)
    elif i==5:
        if S[0]=='B':
            t+=S.pop(0)
    elif i==7:
        if S[0]=='R':
            t+=S.pop(0)
if t=='AKIHABARA' and len(S)==9:
    print('YES')
else:
    print('NO')
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)
    return divisors
  
def solve():
  n = int(input())
  a = list(int(i) for i in input().split())
  ans = [0]*n
  for i in range(n-1,-1,-1):
    if a[i] == 0:
      continue
    else:
      tmp = i+1
      div = make_divisors(tmp)
      for j in div:
        ans[j-1] = 1^ans[j-1]
  print(sum(ans))
  for i in range(sum(ans)):
    print(1, end=" ")
solve()

Fixed, accepted submission:

import sys
input = sys.stdin.readline
def main():
    n = int(input())
    A = [0] + list(int(i) for i in input().split())
    for i in range(n//2,0,-1):
        A[i] = sum(A[i::i]) % 2
    ans = [i for i, j in enumerate(A) if j]
    print(len(ans))
    print(*ans)
 
 
if __name__ == "__main__":
    main()
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
c=-1
d=-1
e=-1
x=b//10000
for i in range(1,x+1,1):
  y=(b-10000*i)//5000
  for j in range(1,y+1,1):
    k=(b-10000*i-5000*j)//1000
    if i+j+k==a:
      c=i
      d=y
      e=k
print(c,d,e)

Fixed, accepted submission:
a,b=map(int,input().split())
c=-1
d=-1
e=-1
x=b//10000
for i in range(0,x+1,1):
  y=(b-10000*i)//5000
  for j in range(0,y+1,1):
    k=(b-10000*i-5000*j)//1000
    if i+j+k==a:
      c=i
      d=j
      e=k
print(c,d,e)
Problem:
An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.  Given an integer N, determine whether it is a Harshad number.

Incorrect submission (verdict: Wrong Answer):
n = input()
fx = 0
for s in n:
    fx += int(s)
print('Yes' if int(n) % fx else 'No')


Fixed, accepted submission:
n = input()
fx = 0
for s in n:
    fx += int(s)
print('Yes' if int(n) % fx==0 else 'No')
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b=map(int,input().split())
print(max(abs(x-a),abs(x-b)))

Fixed, accepted submission:
x,a,b=map(int,input().split())
print("AB"[abs(x-a)>abs(x-b)])
Problem:
Find the number of _palindromic numbers_ among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Incorrect submission (verdict: Wrong Answer):
A, B = [int(ab) for ab in input().split()]
ans = 0
for AB in range(A, B+1):
  AB = str(AB)
  for i in range(len(AB)//2):
    if AB[i] != AB[-i]:
      break
  else:
    ans += 1
print(ans)

Fixed, accepted submission:
A, B = [int(ab) for ab in input().split()]
ans = 0
for AB in range(A, B+1):
  AB_str = str(AB)
  for i in range(len(AB_str)//2):
    if AB_str[i] != AB_str[-i-1]:
      break
  else:
    ans += 1
print(ans)
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
S = input()
results = True
while results:
    for key_word in ["erase", "eraser", "dream", "dreamer"]:
        if S.endswith(key_word):
            S = S.rstrip(key_word)
            continue
    if S == '':
        print("YES")
        results = False
        break
    else:
        print("NO")
        results = False
        break

Fixed, accepted submission:
s = input()
s = s.replace('eraser', '')
s = s.replace('erase', '')
s = s.replace('dreamer', '')
s = s.replace('dream', '')
if s:
  print('NO')
else:
  print('YES')
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x = int(input())
r = 100
age = 0
while(r <= x):
    age += 1
    r += r//100
print(age)

Fixed, accepted submission:
import sys
x = int(input())
a = 100
age = 0
while (1):
    if x <= a:
        print(age)
        sys.exit()
    else:
        age += 1
        a += a//100
Problem:
Joisino the magical girl has decided to turn every single digit that exists on this world into 1.  Rewriting a digit i with j (0≤i,j≤9) costs c_{i,j} MP (Magic Points).  She is now standing before a wall. The wall is divided into HW squares in H rows and W columns, and at least one square contains a digit between 0 and 9 (inclusive).  You are given A_{i,j} that describes the square at the i-th row from the top and j-th column from the left, as follows:    * If A_{i,j}≠-1, the square contains a digit A_{i,j}.   * If A_{i,j}=-1, the square does not contain a digit.  Find the minimum total amount of MP required to turn every digit on this wall into 1 in the end.

Incorrect submission (verdict: Wrong Answer):
# 078-D
def IL(): return list(map(int,input().split()))
def SL(): return input().split()
def I(): return int(input())
def S(): return list(input())
h,w=IL()
c=[IL() for i in range(10)]
a=[IL() for i in range(h)]

for k in range(10):
    for i in range(10):
        for j in range(10):
            c[i][j]=min(c[i][j],c[i][k]+c[k][j])
    
ans=0
for i in range(h):
    for j in range(w):
        if a[i][j]==-1:
            continue
        ans+=c[a[i][j]][1]

Fixed, accepted submission:
# 078-D
def IL(): return list(map(int,input().split()))
def SL(): return input().split()
def I(): return int(input())
def S(): return list(input())
h,w=IL()
c=[IL() for i in range(10)]
a=[IL() for i in range(h)]

for k in range(10):
    for i in range(10):
        for j in range(10):
            c[i][j]=min(c[i][j],c[i][k]+c[k][j])
    
ans=0
for i in range(h):
    for j in range(w):
        if a[i][j]==-1:
            continue
        ans+=c[a[i][j]][1]
print(ans)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8

N = int(input())

ANS = [0] * (N+1)

for i in range(1,101):
    for j in range(1,101):
        for k in range(1,101):
            a = i**2 + j**2 + k**2 + i*j + j*k + k*i
            if a <= N:
                ANS[a] += 1

for a in ANS:
    print(a)

Fixed, accepted submission:
# coding: utf-8

N = int(input())

ANS = [0] * (N+1)

for i in range(1,101):
    for j in range(1,101):
        for k in range(1,101):
            a = i**2 + j**2 + k**2 + i*j + j*k + k*i
            if a <= N:
                ANS[a] += 1

for i in range(1,N+1):
    print(ANS[i])
Problem:
We have a large square grid with H rows and W columns. Iroha is now standing in the top-left cell. She will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.  However, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.  Find the number of ways she can travel to the bottom-right cell.  Since this number can be extremely large, print the number modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
H, W, A, B = map(int, input().split())

import math

def f(n):
  a1 = math.factorial(B + n + H - A - 1) % (10**9 + 7)
  a2 = math.factorial(W - B - 1 - n + A - 1) % (10**9 + 7)
  b1 = math.factorial(B + n) % (10**9 + 7)
  b2 = math.factorial(H - A - 1) % (10**9 + 7)
  b3 = math.factorial(W - B - 1 - n) % (10**9 + 7)
  b4 = math.factorial(A - 1) % (10**9 + 7)
  return a1 * a2 / b1 / b2 / b3 / b4

def sigma(func, frm, to):
  result = 0
  for i in range(frm, to+1):
    result += func(i)
  return result

print(sigma(f, 0, W-B-1))

Fixed, accepted submission:
H, W, A, B = map(int, input().split())

MOD = 1000000007

fac = [1, 1]
inverse = [0, 1]
ifac = [1, 1]
  
for i in range(2, H+W):
  fac.append((fac[-1] * i) % MOD)
  inverse.append((-inverse[MOD % i] * (MOD // i))  % MOD)
  ifac.append((ifac[-1] * inverse[i]) % MOD)

def f(n):
  return fac[B+n+H-A-1] * fac[W-B-1-n+A-1] * ifac[B+n] * ifac[H-A-1] * ifac[W-B-1-n] * ifac[A-1]

def sigma(func, frm, to):
  result = 0
  for i in range(frm, to+1):
    result += func(i)
  return result
 
print(sigma(f, 0, W-B-1)%MOD)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
#import re
import sys
input = sys.stdin.readline
#import heapq

from collections import deque
#import math

def main():
    n, m = map(int, input().split())
    AL = [[] for i in range(n+1)]
    check = [0 for i in range(n+1)]
    for i in range(m):
        s, e = map(int, input().split())
        AL[s].append(e)
        AL[e].append(s)
    que = deque()
    pb = 1, 1
    que.append(pb)
    ANS = [0 for i in range(n+1)]
    while(que):
        pb = que.popleft()
        p = pb[0]
        b = pb[1]
        if check[p] == 1:
            continue
        elif check[p] == 0:
            ANS[p] = b
            check[p] = 1
            for num in AL[p]:
                que.append((num, p))
    print("yes")
    for i in range(n+1):
        if i in [0, 1]:
            continue
        else:
            print(ANS[i])

    
if __name__ == '__main__':
    main()


Fixed, accepted submission:
#import re
import sys
input = sys.stdin.readline
#import heapq

from collections import deque
#import math

def main():
    n, m = map(int, input().split())
    AL = [[] for i in range(n+1)]
    check = [0 for i in range(n+1)]
    for i in range(m):
        s, e = map(int, input().split())
        AL[s].append(e)
        AL[e].append(s)
    que = deque()
    pb = 1, 1
    que.append(pb)
    ANS = [0 for i in range(n+1)]
    while(que):
        pb = que.popleft()
        p = pb[0]
        b = pb[1]
        if check[p] == 1:
            continue
        elif check[p] == 0:
            ANS[p] = b
            check[p] = 1
            for num in AL[p]:
                que.append((num, p))
    print("Yes")
    for i in range(n+1):
        if i in [0, 1]:
            continue
        else:
            print(ANS[i])

    
if __name__ == '__main__':
    main()
Problem:
Takahashi is a user of a site that hosts programming contests.   When a user competes in a contest, the _rating_ of the user (not necessarily an integer) changes according to the _performance_ of the user, as follows:    * Let the current rating of the user be a.   * Suppose that the performance of the user in the contest is b.   * Then, the new rating of the user will be the avarage of a and b.  For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.  Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.   Find the performance required to achieve it.

Incorrect submission (verdict: Wrong Answer):
def rating_goal(R: float, G: float)->float:
    return 2*G - R


if __name__ == "__main__":
    R = float(input())
    G = float(input())
    ans = rating_goal(R, G)
    print(ans)


Fixed, accepted submission:
def rating_goal(R: float, G: float)->float:
    return 2*G - R


if __name__ == "__main__":
    R = int(input())
    G = int(input())
    ans = rating_goal(R, G)
    print(ans)
Problem:
Joisino is working as a receptionist at a theater.  The theater has 100000 seats, numbered from 1 to 100000.  According to her memo, N groups of audiences have come so far, and the i-th group occupies the consecutive seats from Seat l_i to Seat r_i (inclusive).  How many people are sitting at the theater now?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = 0

for i in range(N):
  l,r = list(map(int,input().split()))
  a+=r-l

print(a)

Fixed, accepted submission:
a = 0

for n in range(int(input())):
  l,r = map(int,input().split())
  a+=r-l+1

print(a)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
a = [64, 32, 16, 8, 4, 2, 1]
N = int(input())

for i in a:
  if i < N:
    print(i)



Fixed, accepted submission:
a = [64, 32, 16, 8, 4, 2, 1]
N = int(input())
 
for i in a:
  if i <= N:
    print(i)
    break
Problem:
Write a program which reads a list of student test scores and evaluates the performance for each student.  The test scores for a student include scores of the midterm examination m (out of 50), the final examination f (out of 50) and the makeup examination r (out of 100). If the student does not take the examination, the score is indicated by -1.  The final performance of a student is evaluated by the following procedure:    * If the student does not take the midterm or final examination, the student's grade shall be F.   * If the total score of the midterm and final examination is greater than or equal to 80, the student's grade shall be A.   * If the total score of the midterm and final examination is greater than or equal to 65 and less than 80, the student's grade shall be B.   * If the total score of the midterm and final examination is greater than or equal to 50 and less than 65, the student's grade shall be C.   * If the total score of the midterm and final examination is greater than or equal to 30 and less than 50, the student's grade shall be D. However, if the score of the makeup examination is greater than or equal to 50, the grade shall be C.   * If the total score of the midterm and final examination is less than 30, the student's grade shall be F.

Incorrect submission (verdict: Wrong Answer):
m,f,r=map(int,input().split())

if m or f==-1:
    print("F")

elif m+f>=80:
    print("A")

elif 65<=m+f<80:
    print("B")

elif 50<=m+f<65:
    pritn("C")

elif 30<=m+f<50:
    print("D")

elif 30<m+f<50 and r>50:
    print("C")

elif m+f<30:
    print("F")

Fixed, accepted submission:
while True:
    m,f,r=map(int,input().split())
    if m==f==r==-1:
        break

    elif m==-1 or f==-1:
        print("F")

    elif m+f>=80:
        print("A")

    elif 65<=m+f<80:
        print("B")

    elif 50<=m+f<65:
        print("C")

    elif r>=50:
        print("C")

    elif 30<=m+f<50:
        print("D")

    else:
        print("F")