TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input()
while True:
	S = s
	if len(S) < 5:
		print('No')
		break
	if S == 'dream' or S == 'erase':
		print('Yes')
		break
	else:
		if S[0] == 'd':
			if S[7] == 'a':
				T ='dream'
				if S[:5] == T:
					S = S[5:]
					T = ""
					if S == "":
						print('Yes')
						break
					s = S
				else:
					print('No')
					break
			else:
				T = 'dreamer'
				if S[:7] == T:
					S = S[7:]
					T = ""
					if S == "":
						print('Yes')
						break
					s = S
				else:
					print('No')
					break
		if S[0] == 'e':
			if len(S) >= 6 and S[5] == 'r':
				T = 'eraser'
				if S[:6] == T:
					S = S[6:]
					T = ""
					if S == "":
						print('Yes')
						break
					s = S
				else:
					print('No')
					break
			else:
				T = 'erase'
				if S[:5] == T:
					S = S[5:]
					T = ""
					if S == "":
						print('Yes')
						break
					s = S
				else:
					print('No')
					break
		else:
			print('No')

Fixed, accepted submission:
S=input()
 
S=S.replace('eraser','')
S=S.replace('erase','')
S=S.replace('dreamer','')
S=S.replace('dream','')
 
if S=='':
    print('YES')
else:
    print('NO')
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
alice=0
bob=0
for i in range(N):
  if i % 2==1:
    alice+=a[i]
  else:
    bob+=a[i]
print(alice-bob)

Fixed, accepted submission:
N=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
alice=0
bob=0
for i in range(N):
  if i % 2==0:
    alice+=a[i]
  else:
    bob+=a[i]
print(alice-bob)
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

N, K = map(np.int, input().split())
alist = np.array(list(map(np.int, input().split())))
keys = np.sort(np.array(list(set(alist))))
values = np.zeros(len(keys))
for i in range(len(keys)):
    values[i] = np.sum(alist == keys[i])
balls = dict(zip(keys, values))
balls=dict(sorted(balls.items(), key=lambda x: x[1]))
number = len(list(balls.keys())) - K
if number <= 0:
    print(0)
else:
    print(np.int(np.sum(list(balls.values())[:number]))) 


Fixed, accepted submission:
import collections

N, K = map(int, input().split())
alist = collections.Counter(map(int, input().split()))
number = max(0,len(alist) - K )
answer = 0
if number == 0:
    print(0)
else:
    for a in alist.most_common()[-number:]:
        answer += a[1]
    print(answer)
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Wrong Answer):
def dfs(A: list):
    if len(A) > nn:
        return
    if len(A) and (x := int("".join(A))) >= n and ans[0] > x:
        ans[0] = x
        return

    for v in d:
        if v == "0" and len(A) == 0:
            next
        A.append(v)
        dfs(A)
        A.pop()


n, k = map(int, input().split())
d = sorted(list(set([str(i) for i in range(10)]) - set(input().split())))
nn = len(str(n))+1
ans = [10**7]
dfs([])
print(ans)


Fixed, accepted submission:
def dfs(A: list):
    if len(A) > nn:
        return
    if len(A) and (x := int("".join(A))) >= n and ans[0] > x:
        ans[0] = x
        return

    for v in d:
        if v == "0" and len(A) == 0:
            next
        A.append(v)
        dfs(A)
        A.pop()


n, k = map(int, input().split())
d = sorted(list(set([str(i) for i in range(10)]) - set(input().split())))
nn = len(str(n))+1
ans = [10**7]
dfs([])
print(ans[0])
Problem:
Takahashi is a user of a site that hosts programming contests.   When a user competes in a contest, the _rating_ of the user (not necessarily an integer) changes according to the _performance_ of the user, as follows:    * Let the current rating of the user be a.   * Suppose that the performance of the user in the contest is b.   * Then, the new rating of the user will be the avarage of a and b.  For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.  Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.   Find the performance required to achieve it.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
K = int(input())

x = 1

for i in range(N):
	if x < K:
		x *= 2
	else:
		x += K

print(x)

Fixed, accepted submission:
R = int(input())
G = int(input())
print(2*G-R)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())
c_list = []
for i in range(H):
    c = input().split()
    c_list.append(c)
    c_list.append(c)

for c in c_list:
    print(c)

Fixed, accepted submission:
H, W = map(int, input().split())
c_list = []
for i in range(H):
    c = input().split()
    c_list.append(c)
    c_list.append(c)

for c in c_list:
    print(c[0])
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
S0=input()
S1=list(S0)
T=list(input())
T1=['0']*len(T)
is_break=0
for i in range(1 << len(T)):
    if is_break:
        break
    for j in range(len(T)):
        T1[j]='?' if i&(1<<j) else T[j]
    T2=''.join(T1)
    if S0.find(T2)+1:
        print(S0, T2)
        j=0
        for i in range(S0.find(T2),S0.find(T2)+len(T)):
            S1[i]=T[j]
            j+=1
        is_break=1
        break
if is_break==0:
    print("UNRESTORABLE")
    exit(0)
print(S1)
for i in range(len(S1)):
    if S1[i]=='?':
        S1[i]='a'
S2=''.join(S1)
print(S2)


Fixed, accepted submission:
S=list(input())
T=list(input())
A=[]
for i in range(len(S)-len(T)+1):
    is_ok=1
    for j in range(i, i+len(T)):
        if S[j]!=T[j-i] and S[j]!='?':
            is_ok=0
    if is_ok:
        tmp=S[:]
        is_con=1
        for j in range(i, i+len(T)):
            tmp[j]=T[j-i]
        A.append(tmp)
if len(A)==0:
    print("UNRESTORABLE")
    exit(0)
B=[]
for a in A:
    for i in range(len(a)):
        if a[i]=='?':
            a[i]='a'
    B.append(''.join(a))
B.sort()
print(B[0])
Problem:
Write a program which judges wheather given length of three side form a right triangle. Print "YES" if the given sides (integers) form a right triangle, "NO" if not so.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
for i in range(n):
    a,b,c=map(int, input().split())
    if a > b+c and b > c+a and c > b+a:
        print('YES')
    else:
        print('NO')

Fixed, accepted submission:
n=int(input())
for i in range(n):
    a=list(map(int, input().split()))
    a.sort()
    if a[2]**2 == a[1]**2+a[0]**2:
        print('YES')
    else:
        print('NO')
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
l = input().split()
if l[0] <= l[2] and l[2] <= (l[0] + l[1]):
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
l = input().split()
if int(l[0]) <= int(l[2])  <= (int(l[0]) + int(l[1])):
    print("YES")
else:
    print("NO")
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())
print('Yes' if n % 500 >= a else 'No')

Fixed, accepted submission:
n = int(input())
a = int(input())
print('Yes' if n % 500 <= a else 'No')
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
print('a+b'if a+b<10 else 'error')

Fixed, accepted submission:
a,b=map(int,input().split())
print(a+b if a+b<10 else 'error')
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split())
count=0

div=a//x
md=a % x

mn=a+(x-md)

count=(b-mn+1)//x
amari=(b-mn+1) % x

if amari==0 :
  print(count)
else :
  print(count+1)


Fixed, accepted submission:
a,b,x=map(int,input().split())

def fn(n,x) :
  if n<0 :
    return 0
  else :
    return n//x +1
print(fn(b,x)-fn(a-1,x))
Problem:
AtCoDeer the deer and his friend TopCoDeer is playing a game. The game consists of N turns. In each turn, each player plays one of the two _gestures_ , _Rock_ and _Paper_ , as in Rock-paper-scissors, under the following condition:  (※) After each turn, (the number of times the player has played Paper)≦(the number of times the player has played Rock).  Each player's score is calculated by (the number of turns where the player wins) - (the number of turns where the player loses), where the outcome of each turn is determined by the rules of Rock-paper-scissors.  _(For those who are not familiar with Rock-paper-scissors: If one player plays Rock and the other plays Paper, the latter player will win and the former player will lose. If both players play the same gesture, the round is a tie and neither player will win nor lose.)_  With his supernatural power, AtCoDeer was able to foresee the gesture that TopCoDeer will play in each of the N turns, before the game starts. Plan AtCoDeer's gesture in each turn to maximize AtCoDeer's score.  The gesture that TopCoDeer will play in each turn is given by a string s. If the i-th (1≦i≦N) character in s is `g`, TopCoDeer will play Rock in the i-th turn. Similarly, if the i-th (1≦i≦N) character of s in `p`, TopCoDeer will play Paper in the i-th turn.

Incorrect submission (verdict: Wrong Answer):
hands = input()
ans = 0
for i, h in enumerate(hands):
  if i % 2 == 1:
    if h == "p":
      ans -= 1
  else:
    if h == "g":
      ans += 1
      
print(ans)
   

Fixed, accepted submission:
hands = input()
ans = 0
for i, h in enumerate(hands):
  if i % 2 == 0:
    if h == "p":
      ans -= 1
  else:
    if h == "g":
      ans += 1
      
print(ans)
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
D, X = map(int, input().split())
As = [int(input()) for _ in range(N)]

c = X
for A in As:
  c += (D-1) // A
  
print(c)

Fixed, accepted submission:
N = int(input())
D, X = map(int, input().split())
As = [int(input()) for _ in range(N)]
 
c = X
for A in As:
  c += ((D-1) // A) + 1
  
print(c)
Problem:
Snuke has N integers: 1,2,\ldots,N. He will choose K of them and give those to Takahashi.  How many ways are there to choose K consecutive integers?

Incorrect submission (verdict: Wrong Answer):
N,K=map(int,input().split())

print(K-N+1)

Fixed, accepted submission:
N,K=map(int,input().split())
cnt=0

for i in range(1,N+1):
  if i+K-1<=N:
    cnt+=1

print(cnt)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
list = list(map(int,input().split()))

x=list[0]
a=list[1]
b=list[2]

if a>x:
    s=a-x
else:
    s=x-a

if b>x:
    t=b-x
else:
    t=x-b
    
if s<t:
    print('B')
else:
    print('A')

Fixed, accepted submission:
list = list(map(int,input().split()))

x=list[0]
a=list[1]
b=list[2]

if a>x:
    s=a-x
else:
    s=x-a

if b>x:
    t=b-x
else:
    t=x-b
    
if s<t:
    print('A')
else:
    print('B')
Problem:
Joisino the magical girl has decided to turn every single digit that exists on this world into 1.  Rewriting a digit i with j (0≤i,j≤9) costs c_{i,j} MP (Magic Points).  She is now standing before a wall. The wall is divided into HW squares in H rows and W columns, and at least one square contains a digit between 0 and 9 (inclusive).  You are given A_{i,j} that describes the square at the i-th row from the top and j-th column from the left, as follows:    * If A_{i,j}≠-1, the square contains a digit A_{i,j}.   * If A_{i,j}=-1, the square does not contain a digit.  Find the minimum total amount of MP required to turn every digit on this wall into 1 in the end.

Incorrect submission (verdict: Wrong Answer):
h,w=map(int,input().split())
grid = []
for i in range(10):
    array = list(map(int, input().strip().split(' ')))
    grid.append(array)
wall = []
for i in range(h):
    array = list(map(int, input().strip().split(' ')))
    wall.append(array)
def warshall_floyd(n):
    for k in range(n):
        for i in range(n):
            for j in range(n):
                grid[i][j] = min(grid[i][j], grid[i][k] + grid[k][j])
warshall_floyd(10)
cost=[]
for arrays in grid:
  cost.append(arrays[1])
ans = 0
for arrays in wall:
  for nums in arrays:
    ans += cost[nums]
print(ans)

Fixed, accepted submission:
h,w=map(int,input().split())
grid = []
for i in range(10):
    array = list(map(int, input().strip().split(' ')))
    grid.append(array)
wall = []
for i in range(h):
    array = list(map(int, input().strip().split(' ')))
    wall.append(array)
def warshall_floyd(n):
    for k in range(n):
        for i in range(n):
            for j in range(n):
                grid[i][j] = min(grid[i][j], grid[i][k] + grid[k][j])
warshall_floyd(10)
cost=[]
for arrays in grid:
  cost.append(arrays[1])
ans = 0
for arrays in wall:
  for nums in arrays:
    if nums == -1:
      pass
    else:
      ans += cost[nums]
print(ans)
Problem:
It is September 9 in Japan now.  You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Incorrect submission (verdict: Wrong Answer):
x=int(input())

if x==9 or x//10==9:
    print("Yes")
else:
    print("No")  

Fixed, accepted submission:
x=int(input())

if x==9 or x//10==9 or x%10==9:
    print("Yes")
else:
    print("No")
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
S = list(input())
s = set(S)
S = list(s)
S.sort()
if len(S) == 26:
    print (None)
else:
    tmp = 0
    for i in 'abcdefghijklmnopqrstuvwxyz':
        if tmp >= len(S):
            print (i)
            break
        if i == S[tmp]:
            tmp += 1
        else:
            print (i)
            break
    


Fixed, accepted submission:
X, A, B = map(int, input().split())

if abs(X - A) < abs(X - B):
    print ('A')
else:
    print ('B')
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
s = input()
print(s[1::2])

Fixed, accepted submission:
s = input()
print(s[::2])
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int, input().split()))
print("Yes" if a[0]== a[2] == 5 and a[1] == 7 else "No")

Fixed, accepted submission:
a = list(map(int, input().split()))
print("YES" if a.count(5) == 2 and a.count(7) == 1 else "NO")
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
n = int(input())
for i in range(3, n+1, 3):
    print(' '+str(i), end='')



Fixed, accepted submission:
n = int(input())
for i in range(1, n+1):
    if i%3 == 0:print(' '+str(i), end='')
    else:
        if '3' in str(i):print(' '+str(i), end='')
print()
Problem:
There are N sightseeing spots on the x-axis, numbered 1, 2, ..., N. Spot i is at the point with coordinate A_i. It costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.  You planned a trip along the axis. In this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.  However, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i. You will visit the remaining spots as planned in the order they are numbered. You will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.  For each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
if n==3:
  exit()
al=list(map(int,input().split()))
l1=[]
l2=[]
bl=[0]+al+[0]
for i in range(len(bl)-1):
  l1.append(abs(bl[i]-bl[i+1]))
  if i!=len(bl)-2:
    l2.append(abs(bl[i]-bl[i+2]))
for i in range(len(l2)):
  print(l2[i]+sum(l1[:i])+sum(l1[i+2:]))

Fixed, accepted submission:
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7

def LI(): return list(map(int,input().split()))
def I(): return int(input())
def LS(): return input().split()
def S(): return input()

def main():
  n=I()
  l=LI()

  l=[0]+l+[0]

  sm=sum([abs(l[i+1]-l[i]) for i in range(len(l)-1)])

  for i in range(1,len(l)-1):
    a=abs(l[i]-l[i-1])
    b=abs(l[i+1]-l[i])
    c=abs(l[i+1]-l[i-1])
    print(sm-(a+b-c))

main()
Problem:
Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.  They will share these cards. First, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards. Here, both Snuke and Raccoon have to take at least one card.  Let the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively. They would like to minimize |x-y|. Find the minimum possible value of |x-y|.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a_arr = list(map(int, input().split()))

def main(arr):
    sum_sunuke = 0
    sum_arai      = sum(arr)
    min_val = 2*(10**5)
    for i in range(1,N):
        sum_sunuke += arr[i]
        sum_arai      -= arr[i]
        val = abs(sum_sunuke - sum_arai)
        print(sum_sunuke)
        if min_val > val:
            min_val = val
    return min_val

print(main(a_arr))

Fixed, accepted submission:
N = int(input())
a_arr = list(map(int, input().split()))

def main(arr):
    sum_sunuke = 0
    sum_arai      = sum(arr)
    min_val = 10**10
    
#     if N == 2:
#         return abs(arr[0]- arr[1])
    
    for i in range(N-1):
        sum_sunuke += arr[i]
        sum_arai      -= arr[i]
        val = abs(sum_sunuke - sum_arai)

#         print("arai: {}".format(sum_arai))
        if min_val > val:
            min_val = val
#             print("min val: {}".format(min_val))
#         print("*************")
    return min_val

print(main(a_arr))
Problem:
It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.  The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.  How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
H=int(input())
W=int(input())
print((N-H)*(N-W))

Fixed, accepted submission:
N=int(input())
H=int(input())
W=int(input())
print((N-H+1)*(N-W+1))