TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N). Your objective is to remove some of the elements in a so that a will be a **good sequence**.  Here, an sequence b is a **good sequence** when the following condition holds true:    * For each element x in b, the value x occurs exactly x times in b.  For example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.  Find the minimum number of elements that needs to be removed so that a will be a good sequence.

Incorrect submission (verdict: Wrong Answer):
s = "".join(sorted(input()))
t = "".join(sorted(input(), reverse=True))

if s < t: print("Yes")
else: print("No")

Fixed, accepted submission:
from collections import Counter
n = int(input())
a = list(map(int, input().split()))

count = Counter(a)
ans = 0
for k,v in count.items():
  if k < v: ans += v-k
  elif v < k: ans += v
print(ans)
Problem:
You are given three words s_1, s_2 and s_3, each composed of lowercase English letters, with spaces in between. Print the acronym formed from the uppercased initial letters of the words.

Incorrect submission (verdict: Wrong Answer):
s = input().split()
ans = ""
for i in range(3):
  ans += s[i][0]
ans.upper()
print(ans)

Fixed, accepted submission:
s = input().split()
ans = ""
for i in range(3):
  ans += s[i][0]
print(ans.upper())
Problem:
This contest is `CODEFESTIVAL`, which can be shortened to the string `CF` by deleting some characters.  Mr. Takahashi, full of curiosity, wondered if he could obtain `CF` from other strings in the same way.  You are given a string s consisting of uppercase English letters. Determine whether the string `CF` can be obtained from the string s by deleting some characters.

Incorrect submission (verdict: Wrong Answer):
import re
S1 = input()
p = r'C*F'
result = re.match(p, S1)
if result:
    print('yes')
else:
    print('No')


Fixed, accepted submission:
import re
S1 = input()
p = r'C.+F|CF'
result = re.search(p, S1)
if result:
    print('Yes')
else:
    print('No')
Problem:
Write a program which computes the digit number of sum of two integers a and b.

Incorrect submission (verdict: Wrong Answer):
def main():
    while True:
        try:
            a, b = (int(x) for x in input().split())
            print(len(str(a+b)))
        except EOFError:
            break


Fixed, accepted submission:
def main():
    while True:
        try:
            a, b = (int(x) for x in input().split())
            print(len(str(a+b)))
        except EOFError:
            break
main()
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
import math
num = int(input().replace(" ", ""))
squreRoot = math.sqrt(num)
print('Yes' if squreRoot == int(squreRoot) else 'No')

Fixed, accepted submission:
a, b = map(int, input().split())
print('Odd' if (a * b) % 2 == 1 else 'Even')
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int, input().split())
K = int(input())

d = 0
for i in range(K):
    for j in range(K - i):
        for k in range(K - i - j+1):
            a = A*2**i
            b = B*2**j
            c = C*2**k
            print("a:",a, ",b:",b, ",c:",c)
            if a<b and b<c:
                d = 1
                break
if d ==0:
    print("No")

Fixed, accepted submission:
A,B,C = map(int, input().split())
K = int(input())

def F(d):
    for i in range(K):
        for j in range(K - i):
            for k in range(K - i - j+1):
                a = A*2**i
                b = B*2**j
                c = C*2**k
                #print("a:",a, ",b:",b, ",c:",c)
                if a<b and b<c:
                    d = 1
                    return "Yes"
    if d ==0:
        return "No"

print(F(0))
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
import sys

args = sys.argv

count_5 = 0
count_7 = 0

for i in args:
    print(i)
    if i == '5':
        count_5+=1
    if i == '7':
        count_7+=1

if count_5 == 2 and count_7 == 1:
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
A, B, C = map(int, input().split())

l = [5, 5, 7]

def main(A=A, B=B, C=C):
    if A in l:
        l.remove(A)
        if B in l:
            l.remove(B)
            if C in l:
                return 'YES'
    return 'NO'

if __name__ == '__main__':
    result = main()
    print(result)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
x = int(n / 1.08)
n2 = x * 1.08
if x == n2:
    print(x)
else:
    print(":(")

Fixed, accepted submission:
n = int(input())
x1 = int(n / 1.08)
x2 = int(n / 1.08) + 1
n1 = int(x1 * 1.08)
n2 = int(x2 * 1.08)
if n == n1:
    print(x1)
elif n == n2:
    print(x2)
else:
    print(":(")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

ans = a * b
if ans % 2 == 0:
    print("Odd")
else:
    print("Even")

Fixed, accepted submission:
a, b = map(int, input().split())

ans = a * b
if ans % 2 == 0:
    print("Even")
else:
    print("Odd")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
a, s, c=input().split()
s.lower()
s[0].upper()
print("{} {} {}".format(a, s, c))


Fixed, accepted submission:
a, s, c=input().split()
print(a[0]+s[0].upper()+c[0])
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
ans = 0
for i in range(0,n,2):
  if a[i] % 2 == 0:
    ans += 1
print(ans)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
ans = 0
for i in range(0,n,2):
  if a[i] % 2 == 1:
    ans += 1
print(ans)
Problem:
10^{10^{10}} participants, including Takahashi, competed in two programming contests. In each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.  The _score_ of a participant is the product of his/her ranks in the two contests.  Process the following Q queries:    * In the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.

Incorrect submission (verdict: Wrong Answer):
def upper_square(A: int, B: int) -> int:
    
    l, r = min(A, B), max(A, B)
    while r - l > 1:
        m = (l + r) // 2
        if m * m < A * B:
            l = m
        else:
            r = m
    return l


def query(A: int, B: int) -> int:
    A, B = min(A, B), max(A, B)
    if A == B:
        # (1, 2A-1), ..., (A-1, A+1), (A+1, A-1), ..., (2A-1, 1)
        
        return 2 * A - 2
    if B == A + 1:
        # (1, 2A), ..., (A-1, A+2), (A+2, A-1), ..., (2A, 1)
        
        return 2 * A - 2

    # C = A
    # while (C + 1) ** 2 < A * B:
    #     C += 1
    C = upper_square(A, B)

    if A * B <= C * (C + 1):
        
        
        return 2 * C - 2

    
    
    return 2*C - 1


def worst_case(Q: int, queries: list) -> list:
    return [query(A, B) for A, B in queries]


if __name__ == "__main__":
    Q = int(input())
    queries = [tuple(map(int, input().split())) for _ in range(Q)]
    ans = worst_case(Q, queries)
    print(ans)


Fixed, accepted submission:
def upper_square(A: int, B: int) -> int:
    
    l, r = min(A, B), max(A, B)
    while r - l > 1:
        m = (l + r) // 2
        if m * m < A * B:
            l = m
        else:
            r = m
    return l


def query(A: int, B: int) -> int:
    A, B = min(A, B), max(A, B)
    if A == B:
        # (1, 2A-1), ..., (A-1, A+1), (A+1, A-1), ..., (2A-1, 1)
        
        return 2 * A - 2
    if B == A + 1:
        # (1, 2A), ..., (A-1, A+2), (A+2, A-1), ..., (2A, 1)
        
        return 2 * A - 2

    # C = A
    # while (C + 1) ** 2 < A * B:
    #     C += 1
    C = upper_square(A, B)

    if A * B <= C * (C + 1):
        
        
        return 2 * C - 2

    
    
    return 2*C - 1


def worst_case(Q: int, queries: list) -> list:
    return [query(A, B) for A, B in queries]


if __name__ == "__main__":
    Q = int(input())
    queries = [tuple(map(int, input().split())) for _ in range(Q)]
    ans = worst_case(Q, queries)
    for a in ans:
        print(a)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
power = [2,4,8,16,32,64]
print(max([i if i <= N else N for i in power]))

Fixed, accepted submission:
N = int(input())
power = [2,4,8,16,32,64]
if N < 2: print(N)
else: print(max([i for i in power if i <= N]))
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N*800-15//N*400)

Fixed, accepted submission:
N = int(input())
print(N*800-N//15*200)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b=map(int,input().split())
ans=0
for i in range(n):
    tmp=sum([int(j) for j in list(str(i+1))])
    if a<=tmp<=b:
        ans+=1
print(ans)


Fixed, accepted submission:
n,a,b=map(int,input().split())
ans=0
for i in range(n):
    tmp=sum([int(j) for j in list(str(i+1))])
    if a<=tmp<=b:
        ans+=i+1
print(ans)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())

if (N%500) <= A:
    print ("YES")
else:
    print ("NO")

Fixed, accepted submission:
N = int(input())
A = int(input())

if (N%500) <= A:
    print ("Yes")
else:
    print ("No")
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
print(a // b, a % b, "{:.5}".format(a / b))


Fixed, accepted submission:
a, b = map(int, input().split())
print(a // b, a % b, "{0:.5f}".format(a / b))
Problem:
Given an integer N not less than 3, find the sum of the interior angles of a regular polygon with N sides.  Print the answer in degrees, but do not print units.

Incorrect submission (verdict: Wrong Answer):
s = input()

win = 0
for i in s:
        if i == 'o':
                win += 1

if (15 - len(s)) + win >= 8:
        print('YES')
else:
        print('NO')

Fixed, accepted submission:
n = int(input())

print(180*(n-2))
Problem:
We have a grid with H rows and W columns, where all the squares are initially white.  You will perform some number of painting operations on the grid. In one operation, you can do one of the following two actions:    * Choose one row, then paint all the squares in that row black.   * Choose one column, then paint all the squares in that column black.  At least how many operations do you need in order to have N or more black squares in the grid? It is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split()))

t=sum(a)
m=10**9
flag=0
for i in range(len(a)-1):
    t-=2*a[i]
    if t<=0 :
        if i==0:
            print(abs(t))
            flag = 1
            break
        else:
            print(min(abs(t+2*a[i]),abs(t)))
            flag=1
            break
if flag==0:
    print(t)

Fixed, accepted submission:
import math

h=int(input())
w=int(input())
n=int(input())
print(math.ceil(n/max(h,w)))
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
import sys
while True:
    x = sys.stdin.readline().strip()
    if "?" in x:
        break
    else:
        a = list(x.split())
        if a[1] == "+":
            print(a[0] + a[2])
        elif a[1] == "-":
            print(a[0] - a[2])
        elif a[1] == "*":
            print(a[0] * a[2])
        elif a[1] == "/":
            print(a[0] / a[2])

Fixed, accepted submission:
import sys
import math
while True:
    x = sys.stdin.readline().strip()
    a = list(x.split())
    if a[1] == "?":
        break
    else:
        x = int(a[0])
        y = int(a[2])
        if a[1] == "+":
            print(x + y)
        elif a[1] == "-":
            print(x - y)
        elif a[1] == "*":
            print(x * y)
        elif a[1] == "/":
            print(math.floor(x / y))
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
S = str(input())
T = str(input())
sl = [c for c in S]
tl = [c for c in T]
sl.sort()
tl.sort()
print("YES" if sl[0] < [c for c in reversed(tl)][0] else "NO")

Fixed, accepted submission:
S = sorted(input())
N = sorted(input())
N.reverse()
print("Yes" if S < N  else "No")
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
cnt = 0
n = int(input())
lst = list(map(int, input().split()))
for i in range(n):
    for j in range(n-1,i,-1):
        if lst[j] < lst[j-1]:
            lst[j-1:j+1] = lst[j], lst[j-1]
            cnt += 1
print(lst)
print(cnt)

Fixed, accepted submission:
cnt = 0
n = int(input())
lst = list(map(int, input().split()))
for i in range(n):
    for j in range(n-1,i,-1):
        if lst[j] < lst[j-1]:
            lst[j-1:j+1] = lst[j], lst[j-1]
            cnt += 1
print(*lst)
print(cnt)
Problem:
In a public bath, there is a shower which emits water for T seconds when the switch is pushed.  If the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds. Note that it does not mean that the shower emits water for T additional seconds.  N people will push the switch while passing by the shower. The i-th person will push the switch t_i seconds after the first person pushes it.  How long will the shower emit water in total?

Incorrect submission (verdict: Wrong Answer):
n, T = [int(i) for i in input().split()]
t = [int(i) for i in input().split()]

print(n, T, t)

sum = 0

for i in range(1,n):
    interval = t[i] - t[i-1]
    if interval < T:
        sum += interval
    else:
        sum += T

sum += T

print(sum)


Fixed, accepted submission:
n, T = [int(i) for i in input().split()]
t = [int(i) for i in input().split()]

# print(n, T, t)

sum = 0

for i in range(1,n):
    interval = t[i] - t[i-1]
    if interval < T:
        sum += interval
    else:
        sum += T

sum += T

print(sum)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
ans = []
for i, x in enumerate(open(0).readlines()):
    ans.append("Case %d: %s" % (i, x))
open(1,'w').writelines(ans[:-1])



Fixed, accepted submission:
ans = []
for i, x in enumerate(open(0).readlines()):
    ans.append("Case %d: %s" % (i+1, x))
open(1,'w').writelines(ans[:-1])
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
sum(range(int(input())+1))

Fixed, accepted submission:
print(sum(range(int(input())+1)))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

result=[0,0,0,0]

for i in range(N):
  S=input()
  if S == "AC":
    result[0] += 1
  elif S == "WA":
    result[1] += 1
  elif S == "TLE":
    result[2] += 1
  else:
    result[3] += 1

print("AC × " + str(result[0]))
print("WA × " + str(result[1]))
print("TLE × " + str(result[2]))
print("RE × " + str(result[3]))

Fixed, accepted submission:
N = int(input())

result=[0,0,0,0]

for i in range(N):
  S=input()
  if S == "AC":
    result[0] += 1
  elif S == "WA":
    result[1] += 1
  elif S == "TLE":
    result[2] += 1
  else:
    result[3] += 1

print("AC x " + str(result[0]))
print("WA x " + str(result[1]))
print("TLE x " + str(result[2]))
print("RE x " + str(result[3]))
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
a,v=map(int,input().split())
b,w=map(int,input().split())
s=int(input())
if(((b*w)-(a*v))>(a*v)):
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a,v=map(int,input().split())
b,w=map(int,input().split())
s=int(input())
if(abs(a-b)>(v-w)*s):
  print("NO")
else:
  print("YES")
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int,input().split()))

b = [0 for i in range(N//2)]+a[N//2:]

for i in range(N//2-1,-1,-1):
    if sum(b[i::i+1])%2 == 0:
        b[i] = a[i]
    else:
        b[i] = 1-a[i]

for i in range(N):
    if b[i] == 1:
        print(i+1,end=' ')


Fixed, accepted submission:
N = int(input())
a = list(map(int,input().split()))

b = [0 for i in range(N//2)]+a[N//2:]

for i in range(N//2-1,-1,-1):
    if sum(b[i::i+1])%2 == 0:
        b[i] = a[i]
    else:
        b[i] = 1-a[i]

ans = []
for i in range(N):
    if b[i] == 1:
        ans.append(i+1)

print(len(ans))
print(' '.join(map(str,ans)))
Problem:
Two students of AtCoder Kindergarten are fighting over candy packs.  There are three candy packs, each of which contains a, b, and c candies, respectively.  Teacher Evi is trying to distribute the packs between the two students so that each student gets the same number of candies. Determine whether it is possible.  Note that Evi cannot take candies out of the packs, and the whole contents of each pack must be given to one of the students.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if a + b == c or a == c + b or b == a + c:
    print("YES")
else:
    print("NO")


Fixed, accepted submission:
a, b, c = map(int, input().split())
if a + b == c or a == c + b or b == a + c:
    print("Yes")
else:
    print("No")