TnT/CodeNet4Repair huggingface dataset:
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
a=[]
i=0
while 1:
    n=int(input())
    if n==0:
        break
    else:
        a.append(n)
        i=i+1
l=0
while l<i:
    print("case "+str(l+1)+": "+str(a[l]))
    l=l+1


Fixed, accepted submission:
a=[]
i=0
while 1:
    n=int(input())
    if n==0:
        break
    else:
        a.append(n)
        i=i+1
l=0
while l<i:
    print("Case "+str(l+1)+": "+str(a[l]))
    l=l+1
Problem:
AtCoder Mart sells 1000000 of each of the six items below:    * Riceballs, priced at 100 yen (the currency of Japan) each   * Sandwiches, priced at 101 yen each   * Cookies, priced at 102 yen each   * Cakes, priced at 103 yen each   * Candies, priced at 104 yen each   * Computers, priced at 105 yen each  Takahashi wants to buy some of them that cost exactly X yen in total. Determine whether this is possible.   (Ignore consumption tax.)

Incorrect submission (verdict: Wrong Answer):
x=int(input())
a=int(x/100)
r=x-a*100
print(a,r)
if r/5<=a:
    print(1)
else:
    print(0)


Fixed, accepted submission:
x=int(input())
a=int(x/100)
r=x-a*100
if r/5<=a:
    print(1)
else:
    print(0)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = sorted(map(int, input().split()))
a = 0
b = 0
for i in range(n):
  if i % 2 == 0:
  	a += l.pop()
  else:
    b += l.pop()
print(a)

Fixed, accepted submission:
n = int(input())
l = sorted(map(int, input().split()))
a = 0
b = 0
for i in range(n):
  if i % 2 == 0:
  	a += l.pop()
  else:
    b += l.pop()
print(a - b)
Problem:
We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:    * For any two vertices painted in the same color, the distance between them is an even number.  Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
import queue

N = int(input())

adj = dict([(i+1, []) for i in range(N)])
color = [-1 for i in range(N)]

for i in range(N-1):
    u, v, w = map(int, input().split())
    adj[u].append((v, w))
    adj[v].append((u, w))

q = queue.Queue()
q.put((1, 0))
while(not q.empty()):
    v, w = q.get()
    color[v-1] = (color[v-1]+w)%2
    for nv, nw in adj[v]:
        if(color[nv-1]!=-1):
            continue
        q.put((nv, nw))

for c in color:
    print(c)

Fixed, accepted submission:
import queue

N = int(input())

adj = dict([(i+1, []) for i in range(N)])
dist = [-1 for i in range(N)]
dist[0] = 0
for i in range(N-1):
    u, v, w = map(int, input().split())
    adj[u].append((v, w))
    adj[v].append((u, w))

q = queue.Queue()
q.put((1, 0))
while(not q.empty()):
    v, w = q.get()
    dist[v-1] = w
    for nv, nw in adj[v]:
        if(dist[nv-1]!=-1):
            continue
        q.put((nv, dist[v-1]+nw))

for c in dist:
    print(c%2)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
def Main(N):
    return N % 1000

print(Main(N))


Fixed, accepted submission:
N = int(input())
def Main(N):
    d, m  = divmod(N, 1000)
    if m == 0:
        return 0
    else:
        return (d+1)*1000 - N

print(Main(N))
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
o=list(input())
e=list(input())+[""]
result = [x+y for x,y in zip(o,e)]
print(result)

Fixed, accepted submission:
o=list(input())
e=list(input())+[""]
result="".join([x+y for x,y in zip(o,e)])
print(result)
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
a = input()
c="" 
b = 0
for i in a:
  if c == i:
    b +=1
  c = i
if b >=3:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
n=input()
 
if n[0]==n[1]==n[2] or n[1]==n[2]==n[3]:
  print("Yes")
else:
  print("No")
Problem:
Takahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.  More specifically, in one move, he can go from coordinate x to x + D or x - D.  He wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.  Find the minimum possible absolute value of the coordinate of the destination.

Incorrect submission (verdict: Wrong Answer):
import math
while True:
    try:
        x, k, d = map(int, input().split());
        if x == 0:
            k %= 2;
            if k:
                print(abs(x - d));
            else :
                print(0);
        elif abs(x) - k * d > 0:
            print(abs(x) - k * d);
        elif x > 0:
            k -= x // d;
            k %= 2;
            x -= x // d * d;
            if k:
                print(abs(x - d));
            else:
                print(x);
        else:
            num = x // d + 1;
            x += num * d;
            k -= num;
            if k:
                print(abs(x - d));
            else:
                print(x);
    except EOFError:
        break;


Fixed, accepted submission:
import math
while True:
    try:
        x, k, d = map(int, input().split());
        if x == 0:
            k %= 2;
            if k:
                print(abs(x - d));
            else :
                print(0);
        elif abs(x) - k * d > 0:
            print(abs(x) - k * d);
        elif x > 0:
            k -= x // d;
            k %= 2;
            x -= x // d * d;
            if k:
                print(abs(x - d));
            else:
                print(x);
        else:
            num = abs(x) // d + 1;
            x += num * d;
            k -= num;
            k %= 2;
            if k:
                print(abs(x - d));
            else:
                print(x);
    except EOFError:
        break;
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
A = int(input())

result = A%1000
print(result)

Fixed, accepted submission:
A = int(input())

result = A%1000

if result != 0:
    result = 1000 - result

print(result)
Problem:
You are going to hold a competition of one-to-one game called AtCoder Janken. _(Janken is the Japanese name for Rock-paper-scissors.)_ N players will participate in this competition, and they are given distinct integers from 1 through N. The arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive). You cannot assign the same integer to multiple playing fields. The competition consists of N rounds, each of which proceeds as follows:    * For each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.   * Then, each player adds 1 to its integer. If it becomes N+1, change it to 1.  You want to ensure that no player fights the same opponent more than once during the N rounds. Print an assignment of integers to the playing fields satisfying this condition. It can be proved that such an assignment always exists under the constraints given.

Incorrect submission (verdict: Wrong Answer):
n, m = map(int, input().split())

if n % 2 == 1:
    for i in range(m):
        print(1+i, n-1-i)
else:
    for i in range(m):
        print(1+i, n-i)


Fixed, accepted submission:
n, m = map(int, input().split())

if n % 2 == 1:
    for i in range(m):
        print(1+i, n-1-i)
else:
    for i in range(m):
        if i % 2 == 0:
            print(n//2-i//2, n//2+1+i//2)
        else:
            print(1+i//2, n-1-i//2)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = list(map(int,input().split()))
if abs(a - x) > abs(b - x):
  print("A")
else:
  print("B")

Fixed, accepted submission:
x, a, b = list(map(int,input().split()))
if abs(a - x) > abs(b - x):
  print("B")
else:
  print("A")
Problem:
We have a sandglass that runs for X seconds. The sand drops from the upper bulb at a rate of 1 gram per second. That is, the upper bulb initially contains X grams of sand.  How many grams of sand will the upper bulb contains after t seconds?

Incorrect submission (verdict: Wrong Answer):
x,t = map(int, input().split())
print(min(0, x-t))

Fixed, accepted submission:
x, t = map(int, input().split())
print(max(0, x-t))
Problem:
In AtCoder, a person who has participated in a contest receives a _color_ , which corresponds to the person's rating as follows:    * Rating 1-399 : gray   * Rating 400-799 : brown   * Rating 800-1199 : green   * Rating 1200-1599 : cyan   * Rating 1600-1999 : blue   * Rating 2000-2399 : yellow   * Rating 2400-2799 : orange   * Rating 2800-3199 : red  Other than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.   Currently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.   Find the minimum and maximum possible numbers of different colors of the users.

Incorrect submission (verdict: Wrong Answer):
input();A=map(int,input().split());C=[0]*99;D=0
for a in A:a//=400;D+=a>7;C[a]+=a<8
E=sum(C);print(max(E,1),E+D)


Fixed, accepted submission:
input();A=map(int,input().split());C=[0]*99;D=0
for a in A:a//=400;D+=a>7;C[a]=a<8
E=sum(C);print(max(E,1),E+D)
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
i=1
while i**2<n:
  i+=1
print(i**2)

Fixed, accepted submission:
n=int(input())
i=1
while i**2<=n:
  i+=1
print((i-1)**2)
Problem:
We have a permutation of the integers from 1 through N, p_1, p_2, .., p_N. We also have M pairs of two integers between 1 and N (inclusive), represented as (x_1,y_1), (x_2,y_2), .., (x_M,y_M). AtCoDeer the deer is going to perform the following operation on p as many times as desired so that the number of i (1 ≤ i ≤ N) such that p_i = i is maximized:    * Choose j such that 1 ≤ j ≤ M, and swap p_{x_j} and p_{y_j}.  Find the maximum possible number of i such that p_i = i after operations.

Incorrect submission (verdict: Wrong Answer):
n,m = map(int,input().split())
p = list(map(lambda x:int(x)-1,input().split()))
par = [i for i in range(n)]
rank = [0]*n

def find(x):
    if par[x] == x:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def unite(x, y):
    x = find(x)
    y = find(y)
    if rank[x] < rank[y]:
        par[x] = y
    else:
        par[y] = x
    if rank[x] == rank[y]:
        rank[x] += 1

def same(x, y):
    return find(x) == find(y)

for i in range(m):
    x,y = map(int,input().split())
    unite(x-1,y-1)

ans = 0
for i in range(n):
    if same(i,p[i]-1):
        ans += 1
print(ans)

Fixed, accepted submission:
n,m = map(int,input().split())
p = list(map(lambda x:int(x)-1,input().split()))
par = [i for i in range(n)]
rank = [0]*n

def find(x):
    if par[x] == x:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def unite(x, y):
    x = find(x)
    y = find(y)
    if rank[x] < rank[y]:
        par[x] = y
    else:
        par[y] = x
    if rank[x] == rank[y]:
        rank[x] += 1

def same(x, y):
    return find(x) == find(y)

for i in range(m):
    x,y = map(int,input().split())
    unite(x-1,y-1)

ans = 0
for i in range(n):
    if same(i,p[i]):
        ans += 1
print(ans)
Problem:
Today is August 24, one of the five Product Days in a year.  A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):    * d_1 \geq 2   * d_{10} \geq 2   * d_1 \times d_{10} = m  Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.  In Takahashi Calendar, how many Product Days does a year have?

Incorrect submission (verdict: Wrong Answer):
m,d=map(int,input().split())
x=0
if m>=4 and d>=22:
  o=int(str(d)[1])
  t=int(str(d)[0])
  for i in range(2,t):
    if m%i==0 and m/i<10:
      x+=1
  if m%t==0 and m/t<=o:
    x+=1
print(x)

Fixed, accepted submission:
m,d=map(int,input().split())
x=0
if m>=4 and d>=22:
  for i in range(4,m+1):
    for j in range(22,d+1):
      if j%10>1 and int(str(j)[1])*int(str(j)[0])==i:
        x+=1
print(x)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int, input().split())

c = a+b

d = round(c)

print(d)

Fixed, accepted submission:
a,b=[int(i) for i in input().split()]
round=lambda x:(x*2+1)//2
print(int(round(float((a+b)/2))))
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
a = str(input())
count = 0
for i in a:
  if a == 0:
    count += 1
print(count)

Fixed, accepted submission:
a = str(input())
count = 0
for i in a:
  if i == "1":
    count += 1
print(count)
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s=input()
N=len(s)-2
print(s[0], N, s[-1:])

Fixed, accepted submission:
s=input()
N=len(s)-2
print(s[0]+str(N)+s[-1:])
Problem:
AtCoDeer the deer recently bought three paint cans. The color of the one he bought two days ago is a, the color of the one he bought yesterday is b, and the color of the one he bought today is c. Here, the color of each paint can is represented by an integer between 1 and 100, inclusive.  Since he is forgetful, he might have bought more than one paint can in the same color. Count the number of different kinds of colors of these paint cans and tell him.

Incorrect submission (verdict: Wrong Answer):
lst = input().split()
print(set(lst))

Fixed, accepted submission:
lst = input().split()
print(len(list(set(lst))))
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
n,k=map(int,input().split())
if n>=k*2+1:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
n,k=map(int,input().split())
if n>=k*2-1:
  print("YES")
else:
  print("NO")
Problem:
You are given an undirected connected graph with N vertices and M edges that does not contain self-loops and double edges.   The i-th edge (1 \leq i \leq M) connects Vertex a_i and Vertex b_i.  An edge whose removal disconnects the graph is called a _bridge_.   Find the number of the edges that are bridges among the M edges.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-


import sys
read = sys.stdin.readline

n, m = map(int, input().split())    # single line use regular input() is faster

l = [list(tuple(map(int, read().split()))) for i in range(m)]   

def root(x): #recursively find root for a node
    if parent[x] < 0: # if at root, return self
        return x
    else:
        parent[x] = root(parent[x])  # while searching rejoint queried node to a common parent for hierarchical tree
        return parent[x]
    
def merge(a, b):
    a = root(a)
    b = root(b)
    if rank[a] < rank[b]: # joint lower rank node to a higher rank one
        parent[a] = b
    else:
        parent[b] = a
        if rank[a] == rank[b]: # rank only change if two same rank node joined
            rank[a] +=1    
    return

score = 0

for i in range(m):
    parent = [-1]*(n+1)
    rank = [0]*(n+1)
    for j, (a, b) in enumerate(l[i:]): #iteraete from different starting point - test different "last bridge"
        a = root(a)
        b = root(b)
        if a != b:
            merge(a, b)
        else:
            if j == (len(l)-1):# if the last bridge is redundant, +1
                score += 1 

print(m-score)

Fixed, accepted submission:
# -*- coding: utf-8 -*-


import sys
read = sys.stdin.readline

n, m = map(int, input().split())    # single line use regular input() is faster

l = [list(tuple(map(int, read().split()))) for i in range(m)]   

def root(x): #recursively find root for a node
    if parent[x] < 0: # if at root, return self
        return x
    else:
        parent[x] = root(parent[x])  # while searching rejoint queried node to a common parent for hierarchical tree
        return parent[x]
    
def merge(a, b):
    a = root(a)
    b = root(b)
    if rank[a] < rank[b]: # joint lower rank node to a higher rank one
        parent[a] = b
    else:
        parent[b] = a
        if rank[a] == rank[b]: # rank only change if two same rank node joined
            rank[a] +=1    
    return

score = 0

for i in range(m):
    parent = [-1]*(n+1)
    rank = [0]*(n+1)
    for j, (a, b) in enumerate(l[i:]+l[:i]): #iteraete from different starting point - test different last bridge
        a = root(a)
        b = root(b)
        if a != b:
            merge(a, b)
        else:
            if j == (len(l)-1):
                score += 1 # if the last bridge is redundant, +1

print(m-score)
Problem:
There are N towns in the State of Atcoder, connected by M bidirectional roads.  The i-th road connects Town A_i and B_i and has a length of C_i.  Joisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).  She will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.  If she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?

Incorrect submission (verdict: Wrong Answer):
n,m,R = map(int,input().split())
r = list(map(int,input().split()))
from itertools import permutations
import numpy as np
cost = np.ones((n,n))*float('inf')
for i in range(m):
    a,b,c = map(int,input().split())
    cost[a-1][b-1]=cost[b-1][a-1]=c

def main():

    def dijkstra(g,n,s):
        d = [float('inf')]*n
        U = [i for i in range(n)]
        d[s] = 0
        while len(U)>0:
            w = U[0]
            for u in U:
                if d[u]<d[w]:
                    w = u
            U.pop(U.index(w))
            for v in U:
                d[v] = min(d[v],d[w]+g[w][v])
        return d

    dis_dict = {}
    m = float('inf')
    for i in range(n):
        dis_dict[i] = dijkstra(cost,n,i)
    for j in permutations(r):
        l = 0
        for i in range(len(j)-1):
            s,t = j[i],j[i+1]
            l += dis_dict[s-1][t-1]
        if l<m:
            m = l
    print(m)


if __name__ == "__main__":
    main()

Fixed, accepted submission:
n,m,R = map(int,input().split())
r = list(map(int,input().split()))

from itertools import permutations
import numpy as np
from scipy.sparse.csgraph import floyd_warshall
cost = np.ones((n,n))*float('inf')
for i in range(m):
    a,b,c = map(int,input().split())
    cost[a-1][b-1]=cost[b-1][a-1]=c
d = floyd_warshall(cost)
def main():
    m = float('inf')

    for j in permutations(r):
        l = 0
        for i in range(len(j)-1):
            s,t = j[i],j[i+1]
            l += d[s-1][t-1]
        if l<m:
            m = l
    print(int(m))


if __name__ == "__main__":
    main()
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
S = str(input())

if S[0] != S[1] and S[0] != S[2] and S[1] != S[2]:
    result = "Yse"
else:
    result = "No"

print(result)



Fixed, accepted submission:
S = str(input())

if S[0] != S[1] and S[0] != S[2] and S[1] != S[2]:
    result = 'Yes'
else:
    result = 'No'

print(result)
Problem:
We have a string s consisting of lowercase English letters. Snuke can perform the following operation repeatedly:    * Insert a letter `x` to any position in s of his choice, including the beginning and end of s.  Snuke's objective is to turn s into a palindrome. Determine whether the objective is achievable. If it is achievable, find the minimum number of operations required.

Incorrect submission (verdict: Wrong Answer):
s = input()
i = 0
j = len(s)-1
ist = 0

while i < j:
    if s[i] == s[j]:
        i += 1
        j -= 1
        print("i="+str(i))
        print("j="+str(j))
    elif s[i] == 'x':
        ist += 1
        i += 1
        print("i="+str(i))
        print("j="+str(j))
    elif s[j] == 'x':
        ist += 1
        j -= 1
        print("i="+str(i))
        print("j="+str(j))
    else:
        print(-1)
        exit()

print(ist)



Fixed, accepted submission:
s = input()
i = 0
j = len(s)-1
ist = 0

while i < j:
    if s[i] == s[j]:
        i += 1
        j -= 1
    elif s[i] == 'x':
        ist += 1
        i += 1
    elif s[j] == 'x':
        ist += 1
        j -= 1
    else:
        print(-1)
        exit()

print(ist)