TnT/CodeNet4Repair huggingface dataset:
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())

print((H / 2)*(W / 2))

Fixed, accepted submission:
H,W = map(int, input().split())

if H > W:
    H,W = W,H

if H == 1:
    print(1)
else:
    N = H * W
    print((N+1)//2)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

N = int(input())

S = []
for i in range(N):
    S.append(input())

count_map = {"AC": 0, "WA": 0, "TLE": 0, "RE": 0}

for s in S:
    count_map[s] += 1
    print(count_map)

for count_key, count in count_map.items():
    print(count_key + " x " + str(count))


Fixed, accepted submission:
# -*- coding: utf-8 -*-

N = int(input())

S = []
for i in range(N):
    S.append(input())

count_map = {"AC": 0, "WA": 0, "TLE": 0, "RE": 0}

for s in S:
    count_map[s] += 1

for count_key, count in count_map.items():
    print(count_key + " x " + str(count))
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
print(a+(a<=b))

Fixed, accepted submission:
a,b=map(int,input().split())
print(a+(a<=b)-1)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
t = list(input())

s.sort()


t.sort(reverse=True)


s = ''.join(s)
t = ''.join(t)

print(s)
print(t)

if s < t :
	print('Yes')
else:
	print('No')


Fixed, accepted submission:
s = list(input())
t = list(input())

s.sort()


t.sort(reverse=True)


s = ''.join(s)
t = ''.join(t)

#print(s)
#print(t)

if s < t :
	print('Yes')
else:
	print('No')
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
import re

def main():
    s = list(input())
    sr = ''.join(list(reversed(s)))
    print(sr)
    t = ['dream', 'dreamer', 'erase', 'eraser']
    tr = list()
    for i in t:
        tr.append(''.join(list(reversed(i))))
    while True:
        for i in tr:
            sr_split = re.split('^' + i, sr ,1)
            print(sr_split)
            if len(sr_split) == 2:
                sr = sr_split[1]
                print(sr)
        if sr_split == 1 or not sr_split == '':
            print('No')
            break
        if sr == '':
            print('Yes')
            break
if __name__ == '__main__':
    main()

Fixed, accepted submission:
import re

def main():
    s = list(input())
    sr = ''.join(list(reversed(s)))
    t = ['dream', 'dreamer', 'erase', 'eraser']
    tr = list()
    for i in t:
        tr.append(''.join(list(reversed(i))))
    while sr:
        flag = False
        for i in tr:
            if sr.startswith(i):
                sr = sr.replace(i ,'', 1)
                flag = True
        if not flag:
            print('NO')
            break
        if sr == '':
            print('YES')
            break
if __name__ == '__main__':
    main()
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
loop_count = int(input())

ac_count = 0
wa_count = 0
tle_count = 0
re_count = 0

for i in range(loop_count):
    result = input()
    if result == 'AC':
        ac_count += 1
    elif result == 'WA':
        wa_count += 1
    elif result == 'TLE':
        tle_count += 1
    else:
        re_count += 1

print("AC ×　{0}".format(str(ac_count)))
print("WA ×　{0}".format(str(wa_count)))
print("TLE ×　{0}".format(str(tle_count)))
print("RE ×　{0}".format(str(re_count)))



Fixed, accepted submission:
loop_count = int(input())

ac_count = 0
wa_count = 0
tle_count = 0
re_count = 0

for i in range(loop_count):
    result = input()
    if result == 'AC':
        ac_count += 1
    elif result == 'WA':
        wa_count += 1
    elif result == 'TLE':
        tle_count += 1
    else:
        re_count += 1

print("AC x {0}".format(str(ac_count)))
print("WA x {0}".format(str(wa_count)))
print("TLE x {0}".format(str(tle_count)))
print("RE x {0}".format(str(re_count)))
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
#n = int(input())
#n,k = map(int,input().split())
#x = list(map(int,input().split()))


s = list(map(int,list(input())))
li = [1,-1]

for i in range(1<<3):
    ans = s[0]
    for j in range(1,4):
        if i>>(j-1)&1:
            ans += s[j]
        else:
            ans -= s[j]
    print(bin(i),ans)
    if ans == 7:
        print(s[0],end="")
        for j in range(1,4):
            if i>>(j-1)&1:
                print("+",end="")
                print(s[j],end="")
            else:
                print("-",end="")
                print(s[j],end="")
        print("=7")
        break







Fixed, accepted submission:
#n = int(input())
#n,k = map(int,input().split())
#x = list(map(int,input().split()))


s = list(map(int,list(input())))
li = [1,-1]

for i in range(1<<3):
    ans = s[0]
    for j in range(1,4):
        if i>>(j-1)&1:
            ans += s[j]
        else:
            ans -= s[j]
    #print(bin(i),ans)
    if ans == 7:
        print(s[0],end="")
        for j in range(1,4):
            if i>>(j-1)&1:
                print("+",end="")
                print(s[j],end="")
            else:
                print("-",end="")
                print(s[j],end="")
        print("=7")
        break
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a, b, k = map(int, input().split())
ans = []
k = min(k, b - a)

for i in range(k):
    ans.append(a + i)
    
for i in range(k-1, -1, -1):
    ans.append(b - i)
    
for i in set(ans):
    print(i)

Fixed, accepted submission:
a, b, k = map(int, input().split())
X = range(a, b + 1)
for i in sorted(set(X[: k]) | set(X[- k :])):
    print(i)
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
s = input()

left, right = s.find('A'), s.rfind('B')
print(right-left+1)


Fixed, accepted submission:
s = input()

left, right = s.find('A'), s.rfind('Z')
print(right-left+1)
Problem:
You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.  For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.  Assume that initially no person lives in the building.

Incorrect submission (verdict: Wrong Answer):
buils = [
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]]

n = int(input())

for i in range(n):
    BFRV = input().split()
    b = int(BFRV[0])
    f = int(BFRV[1])
    r = int(BFRV[2])
    v = int(BFRV[3])
    
    buils[b-1][f-1][r-1] = buils[b-1][f-1][r-1] + v

for b in range(4):
    for f in range(3):
        for r in range(10):
            print(" ",end="" )
            print(buils[b][f][r], end="")
        print("")
    print("####################")

Fixed, accepted submission:
buils = [
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],
    [
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
        [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]]

n = int(input())

for i in range(n):
    BFRV = input().split()
    b = int(BFRV[0])
    f = int(BFRV[1])
    r = int(BFRV[2])
    v = int(BFRV[3])
    
    buils[b-1][f-1][r-1] = buils[b-1][f-1][r-1] + v

for b in range(4):
    for f in range(3):
        for r in range(10):
            print(" ", end="")
            print(buils[b][f][r], end="")
        print("")
    if b != 3:
        print("####################")
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
w,h,n = map(int, input().split())
s = [[1 for i in range(w)] for j in range(h)]
b = [[1,2,3,4,5],[6,7,8,9,10]]
print(b[1][0])
print(b)
alist = []
print(s)
for i in range(n):
    x,y,a = map(int, input().split())
    alist.append(a)
    if a == 1:
        for j in range(h):
            for k in range(0,x):
                s[j][k] = 0
    if a == 2:
        for j in range(h):
            for k in range(x,w):
                s[j][k] = 0
    if a == 3:
        for k in range(w):
            for j in range(0,y):
                s[j][k] = 0
    if a == 4:
        for k in range(w):
            for j in range(y,h):
                s[j][k] = 0
ans = 0
for i in range(h):
    ans = ans + s[i].count(1)
print(ans)

Fixed, accepted submission:
w,h,n = map(int, input().split())
s = [[1 for i in range(w)] for j in range(h)]
b = [[1,2,3,4,5],[6,7,8,9,10]]
alist = []
for i in range(n):
    x,y,a = map(int, input().split())
    alist.append(a)
    if a == 1:
        for j in range(h):
            for k in range(0,x):
                s[j][k] = 0
    if a == 2:
        for j in range(h):
            for k in range(x,w):
                s[j][k] = 0
    if a == 3:
        for k in range(w):
            for j in range(0,y):
                s[j][k] = 0
    if a == 4:
        for k in range(w):
            for j in range(y,h):
                s[j][k] = 0
ans = 0
for i in range(h):
    ans = ans + s[i].count(1)
print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

c0 = 0
c1 = 0
c2 = 0
c3 = 0

for i in range(n):
    a = input()
    if(a == 'AC'):
        c0 += 1
    elif(a == 'WA'):
        c1 += 1
    elif(a == 'TLE'):
        c2 += 1
    elif(a == 'RE'):
        c3 += 1

print('AC × ' + str(c0))
print('WA × ' + str(c1))
print('TLE × ' + str(c2))
print('RE × ' + str(c3))



Fixed, accepted submission:
n = int(input())

c0 = 0
c1 = 0
c2 = 0
c3 = 0

for i in range(n):
    a = input()
    if(a == 'AC'):
        c0 += 1
    elif(a == 'WA'):
        c1 += 1
    elif(a == 'TLE'):
        c2 += 1
    elif(a == 'RE'):
        c3 += 1

print('AC x ' + str(c0))
print('WA x ' + str(c1))
print('TLE x ' + str(c2))
print('RE x ' + str(c3))
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())

sum = 0

for n in range(1, N+1):
    nsum = 0
    while n != 0:
        nsum += n % 10
        n = n//10
    if nsum >= A and nsum <= B:
        sum += 1
print(sum)


Fixed, accepted submission:
N, A, B = map(int, input().split())

sum = 0

for n in range(1, N+1):
    nsum = 0
    m = n
    while m != 0:
        nsum += m % 10
        m = m//10
    if nsum >= A and nsum <= B:
        sum += n
print(sum)
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = input()
B = input()
C = input()

ans = 0
for i in range(N):
      if A[i] != B[i] != C[i]:
        ans += 2

      elif A[i] != B[i]:
        ans += 1

      elif A[i] != C[i]:
        ans += 1

      elif B[i] != C[i]:
        ans += 1

print(ans)

Fixed, accepted submission:
N = int(input())
A = input()
B = input()
C = input()

ans = 0
for i in range(N):
  if A[i] == B[i] == C[i]:
    ans += 0

  elif A[i] == B[i]:
    ans += 1

  elif A[i] == C[i]:
    ans += 1

  elif B[i] == C[i]:
    ans += 1

  elif A[i] != B[i] and B[i] != C[i]:
    ans += 2

print(ans)
Problem:
In _K-city_ , there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?

Incorrect submission (verdict: Wrong Answer):

s = input()

number = len(s) - 2

print(s[0] + str(number) + s[-1])


Fixed, accepted submission:
n,m = map(int,input().split())
print((n-1)*(m-1))
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int,input().split())

if (b-a) == (c-a):
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
a,b,c = map(int,input().split())

if (b-a) == (c-b):
    print('YES')
else:
    print('NO')
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
power = 1
for i in range(n):
  power *= i + 1
  power //= 1000000007
print(power)

Fixed, accepted submission:
n = int(input())
power = 1
for i in range(n):
  power *= i + 1
  power %= 1000000007
print(power)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
c=[[i for i in input()] for j in range(2)]
if c[0][0]==c[1][2] and c[0][1]==c[1][1] and c[0][2]==c[1][0]:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
c=[[i for i in input()] for j in range(2)]
if c[0][0]==c[1][2] and c[0][1]==c[1][1] and c[0][2]==c[1][0]:
  print("YES")
else:
  print("NO")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):


N = int(input()) 

candy = N * (N + 1) / 2

print(candy)


Fixed, accepted submission:


N = int(input()) 

candy = int(N * (N + 1) / 2)

print(candy)
Problem:
There are two standard ways to represent a graph $G = (V, E)$, where $V$ is a set of vertices and $E$ is a set of edges; Adjacency list representation and Adjacency matrix representation.  An adjacency-list representation consists of an array $Adj[|V|]$ of $|V|$ lists, one for each vertex in $V$. For each $u \in V$, the adjacency list $Adj[u]$ contains all vertices $v$ such that there is an edge $(u, v) \in E$. That is, $Adj[u]$ consists of all vertices adjacent to $u$ in $G$.  An adjacency-matrix representation consists of $|V| \times |V|$ matrix $A = a_{ij}$ such that $a_{ij} = 1$ if $(i, j) \in E$, $a_{ij} = 0$ otherwise.  Write a program which reads a directed graph $G$ represented by the adjacency list, and prints its adjacency-matrix representation. $G$ consists of $n\; (=|V|)$ vertices identified by their IDs $1, 2,.., n$ respectively.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    N = int(input())
    matrix = [[0] * N for _ in range(N)]
    for i in matrix:
        node_info = [int(i) for i in input().split()]
        node_i = node_info[0] - 1
        if not node_info[1] == 0:
            for i in node_info[2:]:
                matrix[node_i][i-1] = 1
    [print(line) for line in matrix]

Fixed, accepted submission:
if __name__ == '__main__':
    N = int(input())
    matrix = [['0'] * N for _ in range(N)]
    for i in matrix:
        node_info = [int(i) for i in input().split()]
        node_i = node_info[0] - 1
        if not node_info[1] == 0:
            for i in node_info[2:]:
                matrix[node_i][i - 1] = '1'
    [print(' '.join(line)) for line in matrix]
Problem:
Takahashi and Aoki are training for long-distance races in an infinitely long straight course running from west to east.  They start simultaneously at the same point and moves as follows **towards the east** :    * Takahashi runs A_1 meters per minute for the first T_1 minutes, then runs at A_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.   * Aoki runs B_1 meters per minute for the first T_1 minutes, then runs at B_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.  How many times will Takahashi and Aoki meet each other, that is, come to the same point? We do not count the start of the run. If they meet infinitely many times, report that fact.

Incorrect submission (verdict: Time Limit Exceeded):
T1, T2 = map(int, input().split())
A1, A2 = map(int, input().split())
B1, B2 = map(int, input().split())

D1 = T1 * (A1 - B1)
D2 = T2 * (A2 - B2)
li = [D1, D2]
li.sort()

pos = 0
cnt = 0
for _ in range(10000000):
  pos += li[0]
  pos1 = pos
  pos += li[1]
  pos2 = pos
  if pos1 < 0 and pos2 >= 0:
    cnt += 2
if cnt >= 1000000:
  print("infinity")
else:
  print(cnt-1)

Fixed, accepted submission:
t1, t2 = map(int, input().split())
a1, a2 = map(int, input().split())
b1, b2 = map(int, input().split())

if ((a1 - b1) * (a2 - b2) > 0) or (abs(a1 - b1) * t1 > abs(a2 - b2) * t2):
  print(0)
elif abs(a1 - b1) * t1 == abs(a2 - b2) * t2:
  print("infinity")
else:
  d, m = divmod(abs(a1 - b1) * t1, abs(a2 - b2) * t2 - abs(a1 - b1) * t1)
  ans = d * 2
  if m > 0:
    ans += 1
  print(ans)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
s = input()

if a+b+1 == len(s):
  ok = True
else:
  ok = False
  
for i in range(len(s)):
  if i == a:
    if s[i] != "-":
      ok = False
  if type(s[i]) != int:
    ok = False

if ok:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a, b = map(int, input().split())
s = input()

ok = False
if s.count("-") == 1:
  ind = s.index("-")
  if len(s[:ind]) == a and len(s[ind+1:]) == b:
    ok = True

if ok:
  print("Yes")
else:
  print("No")