TnT/CodeNet4Repair huggingface dataset:
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
def main():
    sx, sy, tx, ty = map(int, input().split())
    result = "U" * (ty - sy)
    result += "R" * (tx - sx)
    result += "D" * (ty - sy)
    result += "L" * (tx - sx)

    result += "L"
    result += "U" * (ty - sy + 1)
    result += "R" * (tx - sx + 1)
    result += "D"
    result += "U"
    result += "D" * (ty - sy + 1)
    result += "L" * (tx - sx + 1)
    result += "R"

if __name__ == "__main__":
    main()


Fixed, accepted submission:
def main():
    sx, sy, tx, ty = map(int, input().split())
    result = "U" * (ty - sy)
    result += "R" * (tx - sx)
    result += "D" * (ty - sy)
    result += "L" * (tx - sx)

    result += "L"
    result += "U" * (ty - sy + 1)
    result += "R" * (tx - sx + 1)
    result += "D"
    result += "R"
    result += "D" * (ty - sy + 1)
    result += "L" * (tx - sx + 1)
    result += "U"
    print(result)

if __name__ == "__main__":
    main()
Problem:
When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.  You are given N numbers X_1, X_2, ..., X_N, where N is an even number. For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.  Find B_i for each i = 1, 2, ..., N.

Incorrect submission (verdict: Wrong Answer):
import bisect
n=int(input())
l=list(map(int,input().split()))
l.sort()
if n==2:
    print(l[1],l[0])
    exit()
m=max(l)
k=m//2
if m%2==1:
    k+=1
i=bisect.bisect_left(l,k)
if abs(l[i]-k)<=abs(l[i+1]-k):
    print(m,l[i])
else:
    print(m,l[i+1])


Fixed, accepted submission:
n=int(input())
li = list(map(int,input().split()))
s=sorted(li)
a=s[round(n/2)-1]
b=s[round(n/2)]
for i in range(n):
    if li[i]<a+1:
        print(b)
    else:
        print(a)
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
s,y=(input() for i in range(2))
ans="{"*len(s);pa=ans
for i in range(len(s)-len(y)):
  for j in range(len(y)):
    if s[i+j]!='?' and s[i+j]!=y[j]:break
  else:ans=min(ans,s[:i].replace("?","a")+y+s[i+len(y):].replace("?","a"))
if pa==ans:print("UNRESTORABLE")
  
else:print(ans)

Fixed, accepted submission:
s,t=input(),input()
ans='z'*len(s)
for i in range(len(s)-len(t)+1):
    pre=s[:i].replace("?",'a')
    
    for x,y in zip(list(s[i:]),list(t)):
        if x!="?"and x!=y:break
        pre+=y
    else:
        pre+=s[i+len(t):].replace("?",'a')
        ans=min(ans,pre)
print(ans if ans!='z'*len(s) else 'UNRESTORABLE')
Problem:
Snuke has one biscuit and zero Japanese yen (the currency) in his pocket. He will perform the following operations exactly K times in total, in the order he likes:    * Hit his pocket, which magically increases the number of biscuits by one.   * Exchange A biscuits to 1 yen.   * Exchange 1 yen to B biscuits.  Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Incorrect submission (verdict: Wrong Answer):
K,A,B = map(int,input().split())
ans = K + 1

t = ((K+1) // (A+1)) * B
t += (K+1) % (A+1)
ans = max(ans,t)
print(ans)


Fixed, accepted submission:
K,A,B = map(int,input().split())

if K < A+1 or B <= A+2:
  print(K+1)
  exit(0)
  
K -= A - 1
ans = A
p,q = divmod(K,2)
ans += (B-A) * p + q
print(ans)
Problem:
Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: `a`, `e`, `i`, `o` and `u`.

Incorrect submission (verdict: Wrong Answer):
S = input()
sc = ["eraser", "erase", "dreamer", "dream"]
for i in sc:
    S = S.replace(i, "")
if S:
    print("NO")
else:
    print("YES")

Fixed, accepted submission:
c = input()
p = "aeiou"
if c in p:
    print("vowel")
else:
    print("consonant")
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while 1:
    s=input()
    if '?' in s:break
    print(eval(s))

Fixed, accepted submission:
while 1:
    s=input()
    if '?' in s:break
    print(int(eval(s)))
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin
# import itertools as itr





A = str(input())
B = str(input())

A = list(A)
B = list(B)


AL = len(A)
BL = len(B)

print(AL)

b = []
for i in range(BL):
  b.append(A[i] + B[i])
  if AL -BL == 1:
    b.append(A[-1])

print(",".join(b).replace(",", ""))





# print(C)



Fixed, accepted submission:
A = str(input())
B = str(input())

A = list(A)
B = list(B)

AL = len(A)
BL = len(B)

b = []
for i in range(BL):
  b.append(A[i] + B[i])
if AL -BL == 1:
    # b.append(A[-1])
  b.append(A[-1])
print(",".join(b).replace(",", ""))
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
s = input()
A = s.find('a')
Z = s.rfind('z')
print(Z-A+1)


Fixed, accepted submission:
s = input()
A = s.find('A')
Z = s.rfind('Z')
print(Z-A+1)
Problem:
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.  Given an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print `Yes`; if it cannot, print `No`.

Incorrect submission (verdict: Wrong Answer):
import sys

for line in sys.stdin:
    N = int(line)
    found=False
    for i in range(1, 10, 1): 
        if N % i == 0:
            found = True
            break
    if found:
        print('Yes')
    else:
        print('No')

Fixed, accepted submission:
import sys
import math

l = []
for i in range(1, 10, 1):
    for j in range(1,10,1):
        l.append(i*j)


for line in sys.stdin:
    N = int(line)

    if N in l:
        print('Yes')
    else:
        print('No')
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split(" "))
print(a)
print(b)
c=a+b
d=c%2
e=c//2
if d==1:
  	e=e+1
print(e)

Fixed, accepted submission:

# Python 3rd Try
from math import ceil


def ceil2number(a, b):
    result = 0
    c = (a + b) / 2
    result = ceil(c)
    return result


if __name__ == "__main__":
    answer = 0
    a, b = map(int, input().split(' '))
    answer = ceil2number(a, b)
    print(answer)
Problem:
You are given an integer sequence of length N, a_1,a_2,...,a_N.  For each 1≤i≤N, you have three choices: add 1 to a_i, subtract 1 from a_i or do nothing.  After these operations, you select an integer X and count the number of i such that a_i=X.  Maximize this count by making optimal choices.

Incorrect submission (verdict: Wrong Answer):
import sys
import itertools
import numpy as np

read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

N, *a = map(int, read().split())
A = np.array(a)

counter = np.bincount(A)
print(type(counter))
B = counter.copy()
B[1:] += counter[:-1]
B[:-1] += counter[1:]

print(B.max())


Fixed, accepted submission:
import sys
import itertools
import numpy as np

read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

N, *a = map(int, read().split())
A = np.array(a)

counter = np.bincount(A)
B = counter.copy()
B[1:] += counter[:-1]
B[:-1] += counter[1:]

print(B.max())
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
from collections import  Counter
s = sorted(str(input()))
l = list(Counter(s))
print(l)
a = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
for i in range(0,len(l)):
        if l[i]!=a[i]:
            print(a[i])
            break

Fixed, accepted submission:
import string
x = input()
def func(x):
    diff = set(string.ascii_lowercase)- set(x)
  
    if diff:
        print(sorted(diff)[0])
    else:
        print('None')
        
func(x)
Problem:
We held two competitions: Coding Contest and Robot Maneuver.  In each competition, the contestants taking the 3-rd, 2-nd, and 1-st places receive 100000, 200000, and 300000 yen (the currency of Japan), respectively. Furthermore, a contestant taking the first place in both competitions receives an additional 400000 yen.  DISCO-Kun took the X-th place in Coding Contest and the Y-th place in Robot Maneuver. Find the total amount of money he earned.

Incorrect submission (verdict: Wrong Answer):
X, Y = map(int, input().split())

prices = {1: 3e5, 2: 2e5, 3: 1e5}

ans = 0
if X < 4:
    ans += prices[X]

if Y < 4:
    ans += prices[Y]

if Y == 1 and X == 1:
    ans += 4e5

print(ans)
    


Fixed, accepted submission:
X, Y = map(int, input().split())
 
prices = {1: 300000, 2: 200000, 3: 100000}
 
ans = 0
if X < 4:
    ans += prices[X]
 
if Y < 4:
    ans += prices[Y]
 
if Y == 1 and X == 1:
    ans += 400000
 
print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

x = a * b

if x // 2 == 0:
    print('Even')
else:
    print('Odd')


Fixed, accepted submission:
a, b = map(int, input().split())

x = a * b

if x % 2 == 0:
    print('Even')
else:
    print('Odd')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = [input() for i in range(n)]
ac = 0
wa = 0
tle = 0
re = 0
for s in a:
  if a=='AC':
    ac+=1
  if a=='WA':
    wa+=1
  if a=='TLE':
    tle+=1
  if a=='RE':
    re+=1
print(f'AC × {ac}')
print(f'WA × {wa}')
print(f'TLE × {tle}')
print(f'RE × {re}')
    


Fixed, accepted submission:
from collections import Counter

n = int(input())
s = [input() for _ in range(n)]
counter = Counter(s)
output = ['AC', 'WA', 'TLE', 'RE']

for key in output:
    print(f'{key} x {counter[key]}')
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
a=input()
n=input().split()
s=n.sort()
print(s)


Fixed, accepted submission:
def show (nums):
    for i in range(len(nums)):
        if i!=len(nums)-1:
            print(nums[i],end=' ')
        else :
            print(nums[i])
 
n=int(input())
nums=list(map(int,input().split()))
show(nums)
for i in range(1,n):
    v=nums[i]
    j=i-1
    while (j>=0 and nums[j]>v):
        nums[j+1]=nums[j]
        j-=1
    nums[j+1]=v
    show(nums)
Problem:
There are N towns located in a line, conveniently numbered 1 through N. Takahashi the merchant is going on a travel from town 1 to town N, buying and selling apples.  Takahashi will begin the travel at town 1, with no apple in his possession. The actions that can be performed during the travel are as follows:    * _Move_ : When at town i (i < N), move to town i + 1.   * _Merchandise_ : Buy or sell an arbitrary number of apples at the current town. Here, it is assumed that one apple can always be bought and sold for A_i yen (the currency of Japan) at town i (1 ≦ i ≦ N), where A_i are distinct integers. Also, you can assume that he has an infinite supply of money.  For some reason, there is a constraint on merchandising apple during the travel: the sum of the number of apples bought and the number of apples sold during the whole travel, must be at most T. (Note that a single apple can be counted in both.)  During the travel, Takahashi will perform actions so that the _profit_ of the travel is maximized. Here, the profit of the travel is the amount of money that is gained by selling apples, minus the amount of money that is spent on buying apples. Note that we are not interested in apples in his possession at the end of the travel.  Aoki, a business rival of Takahashi, wants to trouble Takahashi by manipulating the market price of apples. Prior to the beginning of Takahashi's travel, Aoki can change A_i into another arbitrary non-negative integer A_i' for any town i, any number of times. The cost of performing this operation is |A_i - A_i'|. After performing this operation, different towns may have equal values of A_i.  Aoki's objective is to decrease Takahashi's expected profit by at least 1 yen. Find the minimum total cost to achieve it. You may assume that Takahashi's expected profit is initially at least 1 yen.

Incorrect submission (verdict: Wrong Answer):
n,t= map(int,input().split())
a= list(map(int,input().split()))
mp,mprof = 999999999,0
bid = []
bsus = []
sid = []
nc=0
for i in range(n):
    cp = a[i]-mp
    if cp<0:
        nc += min(len(bid),len(sid))
        mp = a[i]
        sid=[]
        bid=[]
        bsus=[i]
    elif cp>0:
        if mprof <= cp:
            bid += bsus
            bsus = []
            if mprof < cp:
                mprof,sid,nc = cp,[i],0
            else:sid.append(i)
    else:bsus.append(i)
    print(a[i],nc,mprof,bid,sid,bsus)
else:
    if len(bid)!=0 and len(sid)!=0:
        nc += min(len(bid),len(sid))
print(nc)

Fixed, accepted submission:
n,t= map(int,input().split())
a= list(map(int,input().split()))
mp,mprof = 999999999,0
bid = []
bsus = []
sid = []
nc=0
for i in range(n):
    cp = a[i]-mp
    if cp<0:
        nc += min(len(bid),len(sid))
        mp = a[i]
        sid=[]
        bid=[]
        bsus=[i]
    elif cp>0:
        if mprof <= cp:
            bid += bsus
            bsus = []
            if mprof < cp:
                mprof,sid,nc = cp,[i],0
            else:sid.append(i)
    else:bsus.append(i)
else:
    if len(bid)!=0 and len(sid)!=0:
        nc += min(len(bid),len(sid))
print(nc)
Problem:
AtCoDeer the deer is seeing a quick report of election results on TV. Two candidates are standing for the election: Takahashi and Aoki. The report shows the ratio of the current numbers of votes the two candidates have obtained, but not the actual numbers of votes. AtCoDeer has checked the report N times, and when he checked it for the i-th (1≦i≦N) time, the ratio was T_i:A_i. It is known that each candidate had at least one vote when he checked the report for the first time.  Find the minimum possible total number of votes obtained by the two candidates when he checked the report for the N-th time. It can be assumed that the number of votes obtained by each candidate never decreases.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
t=a=1
for i in range(N):
    T,A=map(int,input().split())
    num=max(-(-t//T),-(-a//A))
    t,a=num*T,num*A
    print(t, a)

print(t + a)


Fixed, accepted submission:
N=int(input())
t=a=1
for i in range(N):
    T,A=map(int,input().split())
    num=max(-(-t//T),-(-a//A))
    t,a=num*T,num*A

print(t + a)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
# 043A





n =int(input())


ansewr = (n + 1) * n / 2

print(ansewr)


Fixed, accepted submission:
# 043A




n = int(input())


answer = (n + 1) * n // 2

print(answer)
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(str, input().split())
if a[-1]==b[0] and b[-1]==c[0]:
 print ('Yes')
else:
 print('No')

Fixed, accepted submission:
a,b,c=map(str, input().split())
if a[-1]==b[0] and b[-1]==c[0]:
 print ('YES')
else:
 print('NO')
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):
A,B,C,N=map(int, input().split())
count=0
for x in range(A+1):
    for y in range(B+1):
        for z in range(C+1):
            if N==x+y+z:
                count+=1
                print(x,y,z)
print(count)

Fixed, accepted submission:
A,B,C,N=map(int, input().split())
count=0
for x in range(N+1):
  for y in range(N-x*A+1):
    b=(N-x*A-y*B)
    if b>=0 and b%C==0:
      count+=1
                
print(count)
Problem:
Taro and Jiro will play the following game against each other.  Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:    * Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.  Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.  Assuming that the two players play optimally, find the resulting value of X - Y.

Incorrect submission (verdict: Wrong Answer):
import sys
sys.setrecursionlimit(10 ** 6)


def main():
    N = int(input())
    A = list(map(int, input().split()))
    print(A)
    c = [[None] * (N + 1) for _ in range(N + 1)]
    def dp(r, l, A, c):
        if r == l:
            return A[r]
        if c[r][l] != None:
            return c[r][l]
        print(r, l)
        t = max(-dp(r + 1, l, A, c) + A[r],
                -dp(r, l - 1, A, c) + A[l])
        c[r][l] = t
        return t
    
    print(dp(0, N - 1, A, c))


main()


Fixed, accepted submission:
def main():
    N = int(input())
    A = list(map(int, input().split()))
    c = [0] * N
    for r in reversed(range(N)):
        ar = A[r]
        c[r] = t = ar
        for l in range(r + 1, N):
            c[l] = t = max(ar - c[l], A[l] - t)
    
    print(c[-1])


main()
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
import random
s_given = list(input())
t_given = list(input())

s_len = len(s_given)
t_len = len(t_given)
s_random = random.sample(s_given, s_len)
t_random = random.sample(t_given, t_len)


print(s_random, t_random)

for i in range(t_len):
    if s_random[i] < t_random[i]:
        print('Yes')
        break
    elif s_random[i] > t_random[i]:
        print('No')
        break
    if i == t_len - 1:
        print('No')
        break
    elif i == s_len - 1 :
        print('Yes')
        break

        

Fixed, accepted submission:
s_given = list(input())
t_given = list(input())

s_len = len(s_given)
t_len = len(t_given)
s_sorted = sorted(s_given)
t_sorted = sorted(t_given, reverse=True)

for i in range(t_len):
    if s_sorted[i] < t_sorted[i]:
        print('Yes')
        break
    elif s_sorted[i] > t_sorted[i]:
        print('No')
        break

    
    if i == t_len - 1:
        print('No')
        break
    elif i == s_len - 1 :
        print('Yes')
        break