TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
if a + b % 3 == 0 or a % 3 == 0 or b % 3 == 0:
    print('Possible')
else:
    print('Impossible')   

Fixed, accepted submission:
a, b = map(int, input().split())
if (a + b) % 3 == 0 or a % 3 == 0 or b % 3 == 0:
    print('Possible')
else:
    print('Impossible')
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = [int(i) for i in input().split()]
print (a,b)

if (a*b)%2 == 0 :
    print ("Even")
else:
    print ("Odd")


Fixed, accepted submission:
InA = list(map(int, input().split(" ")))

ans = InA[0] * InA[1]

if ans % 2 == 1 :
    print ("Odd")
else:
    print ("Even")
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
count=0
a=int(N/2)
if(N%2==0):
  count +=1
  while(a%2!=1):
   count +=1
   a=int(a/2)
else:
 count =0
print(count)


Fixed, accepted submission:
N = int(input())
i = 0

while(1):
  if(pow(2,i)<= N <pow(2,i+1)):
    print(pow(2,i))
    break
  i += 1
Problem:
AtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W. If we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of   AtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle. Find the minimum distance it needs to be moved.

Incorrect submission (verdict: Wrong Answer):
w,a,b=map(int,input().split())
print(min(0,abs(b-a-w),abs(a-b-w)))

Fixed, accepted submission:
w,a,b=map(int,input().split())
if a<b:
    if a+w>b:
        print(0)
    else:
        print(b-a-w)
else:
    if a<b+w:
        print(0)
    else:
        print(a-b-w)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a,b=int(n/1.08),int((n+1)/1.08)
if b-a==1:
  print(b)
else:
  print(":(")

Fixed, accepted submission:
def main():
    import math

    n = int(input())
    x, y = n / 1.08, (n + 1) / 1.08
    a, b = math.floor(x), math.ceil(y)

    for i in range(a, b):
        if math.floor(1.08 * i) == n:
            print(i)
            break
    else:
        print(':(')


if __name__ == '__main__':
    main()
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
print(sorted(map(int,"2 1 4 3".split())))

Fixed, accepted submission:
s=input()
answer=s[0]+str(len(s)-2)+s[-1]
print(answer)
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
a, b = map(float, input().split())
ans = a * b
print(ans // 1)


Fixed, accepted submission:
from fractions import Fraction
a, b = input().split()
a = int(a)
b = Fraction(b) * 100
ans = (a * b) // 100
print(ans)
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
x = input()
y = int(x)^3


Fixed, accepted submission:
x = int(input())
print(x*x*x)
Problem:
You are going to hold a competition of one-to-one game called AtCoder Janken. _(Janken is the Japanese name for Rock-paper-scissors.)_ N players will participate in this competition, and they are given distinct integers from 1 through N. The arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive). You cannot assign the same integer to multiple playing fields. The competition consists of N rounds, each of which proceeds as follows:    * For each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.   * Then, each player adds 1 to its integer. If it becomes N+1, change it to 1.  You want to ensure that no player fights the same opponent more than once during the N rounds. Print an assignment of integers to the playing fields satisfying this condition. It can be proved that such an assignment always exists under the constraints given.

Incorrect submission (verdict: Wrong Answer):
import math
N,M = map(int,input().split())
answer=[]
a,b,c,d=1,math.ceil(N/2),math.ceil(N/2)+1,N
for i in range(M):
  if i%2 == 0:
    answer.append([a+i/2,b-i/2])
  else:
    answer.append([c+(i-1)/2,d-(i-1)/2])
print('\n'.join([str(int(v[0]))+' '+str(int(v[1])) for v in answer]))

Fixed, accepted submission:
n,m=map(int,input().split())

if n%2 == 1:
  for i in range(1,m+1):
    a,b=i,n-i
    print(a,b)
else:
  for i in range(1,m+1):
    a,b = i,n-i
    if b-a <= n//2:
      a+=1
    print(a,b)
Problem:
You are given an integer N.  Find a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.  If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Time Limit Exceeded):
N = int(input())
w = 0
h = 0
n = 0
for i in range(1,3501):
    for j in range(i,3501):
        if 4*i*j-N*i-N*j <= 0:
            continue
        if (N*i*j)%(4*i*j-N*i-N*j) == 0:
            w = N*i*j//(4*i*j-N*i-N*j)
            h = i
            n = j
            break
print(h,n,w)


Fixed, accepted submission:
import sys
N = int(input())
for i in range(1,3501):
    for j in range(i,3501):

        if 4*i*j-N*i-N*j > 0:
            if (N*i*j)%(4*i*j-N*i-N*j) == 0:
                w = int((N*i*j)/(4*i*j-N*i-N*j))
                print(i,j,w)
                sys.exit()
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
#!usr/bin/env python3

import sys
import operator


def string_to_list_spliter():
    lst = [int(i) if isinstance(i, int) == True else i for i in sys.stdin.readline().split()]
    return lst


def main():
    ops = {'+': operator.add, '-': operator.sub, '*': operator.mul, '/': operator.truediv}

    while True:
        lst = string_to_list_spliter()
        if lst[1] == '?':
            break
        elif lst[1] == '+':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '-':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '*':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '/':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))


if __name__ == '__main__':
    main()

Fixed, accepted submission:
#!usr/bin/env python3

import sys
import operator
from math import floor


def string_to_list_spliter():
    lst = [i for i in sys.stdin.readline().split()]
    return lst


def main():
    ops = {'+': operator.add, '-': operator.sub, '*': operator.mul, '/': operator.truediv}

    # TODO Refactor: include the ugly code below into the function above.
    while True:
        lst = string_to_list_spliter()
        if lst[1] == '?':
            break
        elif lst[1] == '+':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '-':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '*':
            print(ops[lst[1]](int(lst[0]), int(lst[2])))
        elif lst[1] == '/':
            print(floor(ops[lst[1]](int(lst[0]), int(lst[2]))))


if __name__ == '__main__':
    main()
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int,input().split())
k = int(input())

print(2**k*max(a,b,c))

Fixed, accepted submission:
a,b,c = map(int,input().split())
k = int(input())

print((2**k-1)*max(a,b,c)+a+b+c)
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
s=sorted(set(list(input())))[0]
alpha=list("bcdefghijklmnopqrstuvwxyz")
if s == "a":
    print("None")
for i in range(len(alpha)):
    if alpha[i] == s:
        print(alpha[i-1])
        break

Fixed, accepted submission:
s=set(list(input()))
alpha=list("abcdefghijklmnopqrstuvwxyz")
for i in reversed(range(len(alpha))):
    if alpha[i] in s:
        alpha.pop(i)
if alpha == []:
    print("None")
else:
    print(alpha[0])
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
c1=list(map(int,input().split()))
c2=list(map(int,input().split()))
c3=list(map(int,input().split()))

a=[0]*3
b=[0]*3

a[0]=min(c1[0],c1[1],c1[2])
a[1]=min(c2[0],c2[1],c2[2])
a[2]=min(c3[0],c3[1],c3[2])

b[0]=min(c1[0],c2[0],c3[0])
b[1]=min(c1[1],c2[1],c3[1])
b[2]=min(c1[2],c2[2],c3[2])


d1=[0]*3
d2=[0]*3
d3=[0]*3

for i in range(3):
    d1[i]=a[0]+b[i]
    d2[i]=a[1]+b[i]
    d3[i]=a[2]+b[i]

A=[0]*3
B=[0]*3
A[0]=min(c1[0]-d1[0],c1[1]-d1[1],c1[2]-d1[2])
A[1]=min(c2[0]-d2[0],c2[1]-d2[1],c2[2]-d2[2])
A[2]=min(c3[0]-d3[0],c3[1]-d3[1],c3[2]-d3[2])

B[0]=min(c1[0]-d1[0],c2[0]-d2[0],c3[0]-d3[0])
B[1]=min(c1[1]-d1[1],c2[1]-d2[1],c3[1]-d3[1])
B[2]=min(c1[2]-d1[2],c2[2]-d2[2],c3[2]-d3[2])


##print(c1,c2,c3)
if((min(A)==0)&(min(B)==0)):
    print("YES")
else:
    ("No")



Fixed, accepted submission:
C = []
for i in range(3):
    C.append([int(c) for c in input().split()])

ans = "Yes"
tmp=C[0][0]

A=[0]*3
B=[0]*3
for i in range(3):
    B[i]=C[0][i]
for i in range(3):
    A[i]=C[i][0]-B[0]

for i in range(3):
    for j in range(3):
        if(C[i][j]!=A[i]+B[j]):
            ans = "No"
            
print(ans)
Problem:
You went shopping to buy cakes and donuts with X yen (the currency of Japan).  First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.  How much do you have left after shopping?

Incorrect submission (verdict: Wrong Answer):
x=int(input())
y=int(input())
z=int(input())
print((x-y)//z)

Fixed, accepted submission:
x=int(input())
y=int(input())
z=int(input())
print((x-y)%z)
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = int(input())
for i in range(10):
  n = min(2*n,n+k)
print(n)

Fixed, accepted submission:

n = int(input())
k = int(input())
t = 1
for i in range(n):
	t = min(2*t,t+k)
print(t)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n*(n+1)/2)

Fixed, accepted submission:
n = int(input())
a = n * (n+1) / 2
print(int(a))
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
(n, k) = map(int, input().split())

a1 = k // 10000
k %= 10000
a2 = k // 5000
k %= 5000
a3 = k // 1000

if n >= a1 + a2 + a3:
    print(str(a1) + ' ' + str(a2) + ' ' + str(a3))
else:
    print('-1 -1 -1')

Fixed, accepted submission:
import sys
(n, k) = map(int, input().split())

a1 = k // 10000
k %= 10000
a2 = k // 5000
k %= 5000
a3 = k // 1000
for i in range(a1 + 1):
    for j in range(a2 + i * 2 + 1):
        if (a1 - i) +(a2 + i * 2 - j) + (a3 + j * 5) == n:
            print(str(a1 - i) + ' ' + str(a2 + i * 2 - j) + ' ' + str(a3 + j * 5))
            sys.exit(0)
print('-1 -1 -1')
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())
x = N%500
if x <= A:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
N = int(input())
A = int(input())
if N%500 <= A:
    print("Yes")
else:
    print("No")
Problem:
Snuke stands on a number line. He has L ears, and he will walk along the line continuously under the following conditions:    * He never visits a point with coordinate less than 0, or a point with coordinate greater than L.   * He starts walking at a point with integer coordinate, and also finishes walking at a point with integer coordinate.   * He only changes direction at a point with integer coordinate.  Each time when Snuke passes a point with coordinate i-0.5, where i is an integer, he put a stone in his i-th ear.  After Snuke finishes walking, Ringo will repeat the following operations in some order so that, for each i, Snuke's i-th ear contains A_i stones:    * Put a stone in one of Snuke's ears.   * Remove a stone from one of Snuke's ears.  Find the minimum number of operations required when Ringo can freely decide how Snuke walks.

Incorrect submission (verdict: Wrong Answer):
L = int(input())

inf = float('inf')
dp = [[inf] * (L+1) for _ in range(5)]
dp[0][0] = 0
for i in range(1, L+1):
    a = int(input())
    if a == 0:
        dp[0][i] = dp[0][i-1] + a
        dp[1][i] = min(dp[0][i-1], dp[1][i-1] + 2)
        dp[2][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1]) + 1
        dp[3][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1], dp[3][i-1]) + 2
        dp[4][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1], dp[3][i-1], dp[4][i-1])
    else:
        b = a & 1
        c = not b
        dp[0][i] = dp[0][i-1] + a
        dp[1][i] = min(dp[0][i-1], dp[1][i-1]) + b
        dp[2][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1]) + c
        dp[3][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1], dp[3][i-1]) + b
        dp[4][i] = min(dp[0][i-1], dp[1][i-1], dp[2][i-1], dp[3][i-1]) + a

print(min(dp[3][L], dp[4][L]))

Fixed, accepted submission:
L = int(input())

inf = float('inf')
dp = [[inf] * 5 for _ in range(L+1)]
dp[0][0] = 0
for i in range(1, L+1):
    a = int(input())

    b = a & 1
    c = b ^ 1
    p, n = dp[i-1], dp[i]
    n[0] = p[0] + a
    n[1] = min(p[:2]) + b
    n[2] = min(p[:3]) + c
    n[3] = min(p[:4]) + b
    n[4] = min(p[:5]) + a

    if a == 0:
        n[1] += 2
        n[3] += 2

print(min(dp[L]))
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split(" "))

for i in range(1, b+1):
    if (a*i)%b == c:
        print("Yes")
        exit()
print("No")

Fixed, accepted submission:
a, b, c = map(int, input().split(" "))

for i in range(1, b+1):
    if (a*i)%b == c:
        print("YES")
        exit()
print("NO")
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
n,k,x,y=[int(input()) for _ in range(4)]
print(x*k+x*max(0,n-k))

Fixed, accepted submission:
n, k, x, y = [int(input()) for _ in range(4)]
print((x * min(n, k)) + (y * max(0, n - k)))
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
S_list = list(map(int,input().split()))

A, B = S_list[0], S_list[1]
if (A * B * (A + B)) % 3 == 0 :
    result = "Possilbe"
else:
    result = "Impossilbe"
print(result)


Fixed, accepted submission:
S_list = list(map(int,input().split()))

A, B = S_list[0], S_list[1]
if (A * B * (A + B)) % 3 == 0 :
    result = "Possible"
else:
    result = "Impossible"
print(result)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
print(sum(list(map(int, input().split()))))

Fixed, accepted submission:
num_str = input()

print(sum([1 for a in num_str if a == '1']))
Problem:
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.  At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:    * Choose a (connected) rope with a total length of at least L, then untie one of its knots.  Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline
inf = float("inf")

n,L = map(int,input().split())
a = tuple(map(int,input().split()))

for i in range(1,n):
    if a[i]+a[i-1]>=L:
        print('Possible')
        for j in range(i):
            print(j)
        for j in range(i+1,n):
            print(j)
        print(i)
        exit()

print('Impossible')

Fixed, accepted submission:
import sys
input = sys.stdin.readline
inf = float("inf")

n,L = map(int,input().split())
a = tuple(map(int,input().split()))

for i in range(1,n):
    if a[i]+a[i-1]>=L:
        print('Possible')
        for j in range(1,i):
            print(j)
        for j in range(n-1,i,-1):
            print(j)
        print(i)
        exit()

print('Impossible')
Problem:
AtCoDeer the deer recently bought three paint cans. The color of the one he bought two days ago is a, the color of the one he bought yesterday is b, and the color of the one he bought today is c. Here, the color of each paint can is represented by an integer between 1 and 100, inclusive.  Since he is forgetful, he might have bought more than one paint can in the same color. Count the number of different kinds of colors of these paint cans and tell him.

Incorrect submission (verdict: Wrong Answer):
a, b, c = list(map(int, input().split()))
A = [a, b, c]
A.sort()
if A[0] == A[2]:
	print(3)
elif A[0] == A[1] or A[1] == A[2]:
	print(2)
else:
	print(1)

Fixed, accepted submission:
a, b, c = list(map(int, input().split()))
A = [a, b, c]
A.sort()
if A[0] == A[2]:
	print(1)
elif A[0] == A[1] or A[1] == A[2]:
	print(2)
else:
	print(3)
Problem:
You are playing the following game with Joisino.    * Initially, you have a blank sheet of paper.   * Joisino announces a number. If that number is written on the sheet, erase the number from the sheet; if not, write the number on the sheet. This process is repeated N times.   * Then, you are asked a question: How many numbers are written on the sheet now?  The numbers announced by Joisino are given as A_1, ... ,A_N in the order she announces them. How many numbers will be written on the sheet at the end of the game?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans = []
for i in range(N):
    num = input()
    check = ans.count(num)
    if check == 0:
        ans.append(num)
    else:
        ans.remove(num)
print(ans)

Fixed, accepted submission:
N = int(input())
ans = set()
for i in range(N):
    num = int(input())
    if num in ans:
        ans.remove(num)
    else:
        ans.add(num)
print(len(ans))
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
S=input()
s=len(S)
ans=S.count("o")
print(ans)
if ans+(15-s)>=8:
    print("Yes")
if ans+(15-s)<8:
    print("No")

Fixed, accepted submission:
S=input()
s=len(S)
ans=S.count("o")
if ans+(15-s)>=8:
    print("YES")
if ans+(15-s)<8:
    print("NO")