TnT/CodeNet4Repair huggingface dataset:
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
sd=input()
t=input()
lsd=len(sd)
lt=len(t)
ans='UNRESTRABLE'
for i in range(lsd-lt):
    for j in range(lt):
        if sd[i+j]!='?' and sd[i+j]!=t[j]:
            break
        else:
            ans=(sd[:i]+t+sd[i+lt:]).replace('?','a')
        break
print(ans)

Fixed, accepted submission:
sd=input()
t=input()
lsd=len(sd)
lt=len(t)
for i in range(lsd-lt,-1,-1):
    for j in range(lt):
        if sd[i+j]!='?' and sd[i+j]!=t[j]:
            break
    else:
            print((sd[:i]+t+sd[i+lt:]).replace('?','a'))
            break
else:
    print('UNRESTORABLE')
Problem:
Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.                 Merge(A, left, mid, right)   n1 = mid - left;   n2 = right - mid;   create array L[0...n1], R[0...n2]   for i = 0 to n1-1     do L[i] = A[left + i]   for i = 0 to n2-1     do R[i] = A[mid + i]   L[n1] = SENTINEL   R[n2] = SENTINEL   i = 0;   j = 0;   for k = left to right-1     if L[i] <= R[j]       then A[k] = L[i]            i = i + 1       else A[k] = R[j]            j = j + 1  Merge-Sort(A, left, right){   if left+1 < right     then mid = (left + right)/2;          call Merge-Sort(A, left, mid)          call Merge-Sort(A, mid, right)          call Merge(A, left, mid, right)

Incorrect submission (verdict: Wrong Answer):
import math

class MergeSort:
    def merge(self, a, n, left, mid, right): 
        n1 = mid - left
        n2 = right - mid
        l = a[left:(left+n1)]
        r = a[mid:(mid+n2)]
        l.append(2000000000)
        r.append(2000000000)
        i = 0
        j = 0
        for k in range(left, right):
            if l[i] <= r[j]:
                a[k] = l[i]
                i += 1
            else:
                a[k] = r[j]
                j += 1
        return a
        
    def mergeSort(self, a, n, left, right):
        if left + 1 < right:
            mid = (left + right) // 2
            self.mergeSort(a, n, left, mid)
            self.mergeSort(a, n, mid, right)
            self.merge(a, n, left, mid, right)
        return a

if __name__ == '__main__':
    n = int(input().rstrip())
    s = [int(i) for i in input().rstrip().split(" ")]
    x = MergeSort()
    print(x.mergeSort(s, n, 0, n))

Fixed, accepted submission:
import math

class MergeSort:
    cnt = 0
    def merge(self, a, n, left, mid, right): 
        n1 = mid - left
        n2 = right - mid
        l = a[left:(left+n1)]
        r = a[mid:(mid+n2)]
        l.append(2000000000)
        r.append(2000000000)
        i = 0
        j = 0
        for k in range(left, right):
            self.cnt += 1
            if l[i] <= r[j]:
                a[k] = l[i]
                i += 1
            else:
                a[k] = r[j]
                j += 1
        return a
        
    def mergeSort(self, a, n, left, right):
        if left + 1 < right:
            mid = (left + right) // 2
            self.mergeSort(a, n, left, mid)
            self.mergeSort(a, n, mid, right)
            self.merge(a, n, left, mid, right)
        return a

if __name__ == '__main__':
    n = int(input().rstrip())
    s = [int(i) for i in input().rstrip().split(" ")]
    x = MergeSort()
    print(" ".join(map(str, x.mergeSort(s, n, 0, n))))
    print(x.cnt)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
def main():
    A, B = map(int, input().split())
    S = input()
    digit = [str(a) for a in range(10)]
    collect = True
    for i in range(len(S)):
        if i == A:
            if S[i] != "-":
                collect = False
                break
        else:
            if i not in digit:
                collect = False
                break
    if collect == True:
        print("Yes")
    else:
        print("No")
main()

Fixed, accepted submission:
def main():
    A, B = map(int, input().split())
    S = input()
    digit = [str(a) for a in range(10)]
    collect = True
    for i in range(len(S)):
        if i == A:
            if S[i] != "-":
                collect = False
                break
        else:
            if S[i] not in digit:
                collect = False
                break
    if collect == True:
        print("Yes")
    else:
        print("No")
main()
Problem:
Write a program which reads three integers, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
a, b, c = [int(i) for i in input().split()]
print(min)

Fixed, accepted submission:
data = [int(i) for i in input().split()]

data.sort()
print("{0} {1} {2}".format(data[0],data[1],data[2]))
Problem:
You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.  For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.  Assume that initially no person lives in the building.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
start=[[[0 for i in range(10)] for j in range(3)] for k in range(4)]
for i in range(n):
    b,f,r,v=[int(i) for i in input().split()]
    start[b-1][f-1][r-1]+=v
for i in range(4):
    for j in range(3):
        for k in range(10):
            print(" ",end="")
            print(start[i][j][k],end="")
        print()
    for m in range(20):
        print("#",end="")
    print() 


Fixed, accepted submission:
n=int(input())
start=[[[0 for i in range(10)] for j in range(3)] for k in range(4)]
for i in range(n):
    b,f,r,v=[int(i) for i in input().split()]
    start[b-1][f-1][r-1]+=v
for i in range(4):
    for j in range(3):
        for k in range(10):
            print(" ",end="")
            print(start[i][j][k],end="")
        print()
    if i<=2:
        for m in range(20):
            print("#",end="")
        print()
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if(n % 1000):
  print(0)
else:
  print(1000 - n % 1000)

Fixed, accepted submission:
n = int(input())
if(n % 1000 == 0):
  print(0)
else:
  print(1000 - n % 1000)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
S1 = list(input())
S2 = list(input())

flag = 0
for i in range(3):
  if S1[i] != S2[2-i]:
    flag = 1

if flag:
  print('No')
else:
  print('Yes')

Fixed, accepted submission:
S1 = list(input())
S2 = list(input())

flag = 0
for i in range(3):
  if S1[i] != S2[2-i]:
    flag = 1

if flag:
  print('NO')
else:
  print('YES')
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
N = int(input())
num = [0]*N
for i in range(1,10**2):
    for j in range(1,10**2):
        for k in range(1,10**2):
            ans = i**2 + j**2 + k**2 + i*j + j*k + k*i
            if ans < N:
                num[ans] += 1
for i in range(N):
    print(num[i])


Fixed, accepted submission:
N = int(input())
num = [0]*N
for i in range(1,10**2 + 1):
    for j in range(1,10**2 + 1):
        for k in range(1,10**2 + 1):
            ans = i**2 + j**2 + k**2 + i*j + j*k + k*i
            if ans <= N:
                num[ans - 1] += 1
for i in range(N):
    print(num[i])
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
N, H = map(int, input().split(' '))
katana = [map(int, input().split(' ')) for _ in range(N)]
dmg_wield, dmg_throw = zip(*katana)

dmg_wield_max = max(dmg_wield)
dmg_throw = [d for d in sorted(dmg_throw, reverse=True) if d >= dmg_wield_max]

n = len(dmg_throw)
H -= sum(dmg_throw)
n += int(H // dmg_wield_max)

if H - dmg_wield_max * n > 0:
    n += 1

print(n)

Fixed, accepted submission:
N, H = map(int, input().split(' '))
katana = [map(int, input().split(' ')) for _ in range(N)]
dmg_wield, dmg_throw = zip(*katana)

dmg_wield_max = max(dmg_wield)
dmg_throw = sorted([d for d in dmg_throw if d > dmg_wield_max])

n = 0
while H > 0 and dmg_throw:
    H -= dmg_throw.pop()
    n += 1

print(n + max(H-1, -1) // dmg_wield_max + 1)
Problem:
You are given an integer K. Print the string obtained by repeating the string `ACL` K times and concatenating them.  For example, if K = 3, print `ACLACLACL`.

Incorrect submission (verdict: Wrong Answer):
#a
k=int(input())
ans=[]
for i in range(k):
    ans.append('acl')
a=''.join(ans)
print(a)

Fixed, accepted submission:
#a
k=int(input())
ans=[]
for i in range(k):
    ans.append('ACL')
a=''.join(ans)
print(a)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
c=int(input())
d=int(input())
count=0
for i in range(a+1):
    for j in range(b+1):
        for z in range(c+1):
            if a*500+b*100+c*50 == d:
                count+=1
print(count)


Fixed, accepted submission:
a=int(input())
b=int(input())
c=int(input())
d=int(input())
count=0
for i in range(a+1):
    for j in range(b+1):
        for z in range(c+1):
            if i*500+j*100+z*50 == d:
                count+=1
print(count)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b=map(int,input().split());print("AB"[abs(x-a)<abs(x-b)])

Fixed, accepted submission:
x,a,b=map(int,input().split());print("AB"[abs(x-a)>abs(x-b)])
Problem:
You are given two integers a and b. Determine if a+b=15 or a\times b=15 or neither holds.  Note that a+b=15 and a\times b=15 do not hold at the same time.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a*b==15 and a+b==15:
  print("*")
else:
  print("x")

Fixed, accepted submission:
a,b=map(int,input().split())
if a*b==15:
  print("*")
elif a+b==15:
  print("+")
else:
  print("x")
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int,input().split()))

c = 0
a.sort(reverse=True)
for i in range(N):
  if i//2 == 0:
    c += a[i]
  else:
    c -= a[i]
print(a[i])

Fixed, accepted submission:
N = int(input())
a = list(map(int,input().split()))

c = 0
a.sort(reverse=True)
for i in range(N):
  if i%2 == 0:
    c += a[i]
  else:
    c -= a[i]
print(c)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a, b, c, x = map(int, [input() for i in range(4)])
count = 0
for i in range(a+1):
    for j in range(b+1):
        for k in range(c+1):
            total = 500 * a + 100 * b + 50 * c
            if total == x:
                count = count + 1
print(count)



Fixed, accepted submission:
a, b, c, x = map(int, [input() for i in range(4)])
count = 0
for i in range(a+1):
    for j in range(b+1):
        for k in range(c+1):
            total = 500 * i + 100 * j + 50 * k
            if total == x:
                count = count + 1
print(count)
Problem:
N persons are standing in a row. The height of the i-th person from the front is A_i.  We want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:  Condition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.  Find the minimum total height of the stools needed to meet this goal.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
total = 0
for i in range(1, n):
  if a[i-1] > a[i]:
    total += a[i-1] - a[i]
    a[i] = a[i-1]

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
total = 0
for i in range(1, n):
  if a[i-1] > a[i]:
    total += a[i-1] - a[i]
    a[i] = a[i-1]
print(total)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b=map(int,input().rstrip().split(' '))

def count(n):
  x = str(n)
  sum=0
  for s in x:
    sum+=int(s)
  return sum
    
ans=0
for i in range(1,n+1):
  if(a <= count(i) and count(i) <=b):ans+=1

print(ans)

Fixed, accepted submission:
n,a,b=map(int,input().rstrip().split(' '))

def count(n):
  x = str(n)
  sum=0
  for s in x:
    sum+=int(s)
  return sum
    
ans=0
for i in range(1,n+1):
  if(a <= count(i) and count(i) <=b):ans+=i

print(ans)
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
print(input()[1::2])


Fixed, accepted submission:
print(input()[::2])
Problem:
We have a board with a 2 \times N grid. Snuke covered the board with N dominoes without overlaps. Here, a domino can cover a 1 \times 2 or 2 \times 1 square.  Then, Snuke decided to paint these dominoes using three colors: red, cyan and green. Two dominoes that are adjacent by side should be painted by different colors. Here, it is not always necessary to use all three colors.  Find the number of such ways to paint the dominoes, modulo 1000000007.  The arrangement of the dominoes is given to you as two strings S_1 and S_2 in the following manner:    * Each domino is represented by a different English letter (lowercase or uppercase).   * The j-th character in S_i represents the domino that occupies the square at the i-th row from the top and j-th column from the left.

Incorrect submission (verdict: Wrong Answer):
P=10**9+7
N=int(input())
S1=input()
S2=input()
L=[1]
k=0
P=10**9+7
for i in range(1,N):
    if S1[i]!=S1[i-1]:
        L.append(0)
        k+=1
    L[k]+=1
M=len(L)
S=1
if L[k]==1:
    S=3
else:
    S=6
for i in range(1,M):
    if L[i-1]==1:
        S=(S*2)%P
    else:
        if L[i]==2:
            S=(S*3)%P
print(S)


Fixed, accepted submission:
P=10**9+7
N=int(input())
S1=input()
S2=input()
L=[1]
k=0
P=10**9+7
for i in range(1,N):
    if S1[i]!=S1[i-1]:
        L.append(0)
        k+=1
    L[k]+=1
M=len(L)
S=1
if L[0]==1:
    S=3
else:
    S=6
for i in range(1,M):
    if L[i-1]==1:
        S=(S*2)%P
    else:
        if L[i]==2:
            S=(S*3)%P
print(S)
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
a=set(input())
if len(a)<2:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
a=input()
b=set(a[:-1]);c=set(a[1:])

if len(b)==1 or len(c)==1:
  print('Yes')
else:
  print('No')
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
def main():
    N = input_ints()

    a = input_int_list_in_line()

    print(len([True for i in range(N) if i % 2 == 0 and a[i] % 2 == 0]))




def input_ints():
    line_list = input().split()

    if len(line_list) == 1:
        return int(line_list[0])
    else:
        return map(int, line_list)


def input_int_list_in_line():
    return list(map(int, input().split()))


def input_int_tuple_list(n: int):
    return [tuple(map(int, input().split())) for _ in range(n)]


main()


Fixed, accepted submission:
def main():
    N = input_ints()

    a = input_int_list_in_line()

    print(len([True for i in range(N) if i % 2 == 0 and a[i] % 2 == 1]))




def input_ints():
    line_list = input().split()

    if len(line_list) == 1:
        return int(line_list[0])
    else:
        return map(int, line_list)


def input_int_list_in_line():
    return list(map(int, input().split()))


def input_int_tuple_list(n: int):
    return [tuple(map(int, input().split())) for _ in range(n)]


main()
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
#from collections import deque
n,m=map(int,input().split())
root=[[] for _ in range(n)]
for i in range(m):
	a,b=map(int,input().split())
	root[a-1].append(b-1)
	root[b-1].append(a-1)
times=[0]*n
sign=[-1]*n
sign[0]=0
#q=deque(root[0])
flag=0
a=root[0]
b=[]
f=False
while True:
	for i in a:
		if sign[i]==-1:
			sign[i]=flag
			b.extend(root[i])
			f=True
	flag=i
	a=b
	b=[]
	if f==False:
		break
	f=False
for i in range(n-1):
	print(sign[i+1]+1)


Fixed, accepted submission:
from collections import deque
n,m=map(int,input().split())
root=[[] for _ in range(n)]
for i in range(m):
	a,b=map(int,input().split())
	root[a-1].append(b-1)
	root[b-1].append(a-1)
times=[0]*n
sign=[-1]*n
sign[0]=0
color=[False]*n
que=deque([0])
while que: 
	i=que.popleft()
	if color[i]==False:
		for edge in root[i]:
			if color[edge]==False and sign[edge]==-1: 
				sign[edge]=i
				que.append(edge)
		color[i]=True
print('Yes')
for i in range(n-1):
	print(sign[i+1]+1)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s=input()
t=input()
s_l,t_l=[],[]
for i in s:
	s_l.append(i)
for i in t:
	t_l.append(i)
s_l.sort(reverse=True)
t_l.sort()
s="".join(s_l)
t="".join(t_l)
if s<t:
	print("Yes")
else:
	print("No")


Fixed, accepted submission:
s=input()
t=input()
s_l,t_l=[],[]
for i in s:
	s_l.append(i)
for i in t:
	t_l.append(i)
s_l.sort()
t_l.sort(reverse=True)
s="".join(s_l)
t="".join(t_l)
if s<t:
	print("Yes")
else:
	print("No")