TnT/CodeNet4Repair huggingface dataset:
Problem:
We have a canvas divided into a grid with H rows and W columns. The square at the i-th row from the top and the j-th column from the left is represented as (i, j).   Initially, all the squares are white. square1001 wants to draw a picture with black paint. His specific objective is to make Square (i, j) black when s_{i, j}= `#`, and to make Square (i, j) white when s_{i, j}= `.`.   However, since he is not a good painter, he can only choose two squares that are horizontally or vertically adjacent and paint those squares black, for some number of times (possibly zero). He may choose squares that are already painted black, in which case the color of those squares remain black.   Determine if square1001 can achieve his objective.

Incorrect submission (verdict: Wrong Answer):
import sys
H, W = map(int, input().split())
s = [input() for _ in range(H)]
print(s)
dx = [1, 0, -1, 0]
dy = [0, 1, 0, -1]
for i in range(H):
    for j in range(W):
        if s[i][j] == '#':
            for k in range(4):
                try:
                    if s[i + dy[k]][j + dx[k]] == '#':
                        flag = False
                        break
                    else:
                        flag = True
                except IndexError:
                    pass
            if flag:
                print('No')
                sys.exit()
print('Yes')


Fixed, accepted submission:
import sys
H, W = map(int, input().split())
s = [input() for _ in range(H)]
dx = [1, 0, -1, 0]
dy = [0, 1, 0, -1]
for i in range(H):
    for j in range(W):
        if s[i][j] == '#':
            for k in range(4):
                try:
                    if s[i + dy[k]][j + dx[k]] == '#':
                        flag = False
                        break
                    else:
                        flag = True
                except IndexError:
                    pass
            if flag:
                print('No')
                sys.exit()
print('Yes')
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s.find("1") != -1:
    print("NO")
elif s.find("2") != -1:
    print("NO")
else:
    a = s.replace("dream", "11111").replace("erase", "22222").replace("11111er", "1111111").replace("22222r", "111111")
    print(a)
    if a.count("1") == len(a):
        print("YES")
    else:
        print("NO")


Fixed, accepted submission:
s = input()
if s.find("1") != -1:
    print("NO")
elif s.find("2") != -1:
    print("NO")
else:
    a = s.replace("dream", "11111").replace("erase", "22222").replace("11111er", "1111111").replace("22222r", "111111").replace("22222", "11111")
    if a.count("1") == len(a):
        print("YES")
    else:
        print("NO")
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
inData = int(input())

seqData = list(range(1,inData+1,1))
outData = [0] * inData
for thisData in seqData:
    if thisData == inData:
        print(thisData)
    else:
        if thisData%3 == 0:
            print(thisData, end = "")
        else:
            pass
    
    


Fixed, accepted submission:
inData = int(input())

seqData = list(range(1,inData+1,1))
outData = [0] * inData
for thisData in seqData:
    if thisData == inData:
        if thisData%3 == 0 or thisData%10==3:
            print(" "+str(thisData))
        else:
            for i in range(5):
                i=i+1
                over =  10 ** i
                tmp = thisData/over
                if int(tmp % 10) == 3:
                    print(" "+str(thisData))
                    break
                else:
                    pass
            print("")
    else:
        if thisData%3 == 0 or thisData%10==3:
            print(" "+str(thisData), end = "")
        else:
            for i in range(5):
                i=i+1
                over =  10 ** i
                tmp = thisData/over
                if int(tmp % 10) == 3:
                    print(" "+str(thisData), end = "")
                    break
                else:
                    pass
Problem:
Write a program to simulate rolling a dice, which can be constructed by the following net.                  As shown in the figures, each face is identified by a different label from 1 to 6.  Write a program which reads integers assigned to each face identified by the label and a sequence of commands to roll the dice, and prints the integer on the top face. At the initial state, the dice is located as shown in the above figures.

Incorrect submission (verdict: Wrong Answer):
d = [_ for _ in input().split()]                 
                                                 
commands = input()                               
                                                 
for c in commands:                               
  if c == 'E':                                   
    d[0], d[1], d[3], d[5] = d[1], d[5], d[0], d[
3]                                               
  elif c == 'W':                                 
    d[0], d[1], d[3], d[5] = d[3], d[0], d[5], d[
1]                                               
  elif c == 'N':                                 
    d[0], d[2], d[4], d[5] = d[2], d[5], d[0], d[
4]                                               
  elif c == 'S':                                 
    d[0], d[2], d[4], d[5] = d[4], d[0], d[5], d[
2]                                               
                                                 
print(d[0])                                      

Fixed, accepted submission:
class dice:
  def __init__(self, dice):
    self.d = dice

  def roll(self, c):
    d = self.d
    if c == 'E':
      d[0], d[2], d[3], d[5] = d[3], d[0], d[5], d[2]
    elif c == 'W':
      d[0], d[2], d[3], d[5] = d[2], d[5], d[0], d[3]
    elif c == 'N':
      d[0], d[1], d[4], d[5] = d[1], d[5], d[0], d[4]
    elif c == 'S':
      d[0], d[1], d[4], d[5] = d[4], d[0], d[5], d[1]
    self.d = d
  def print(self):
    print(self.d[0])

d = dice([_ for _ in input().split()])

commands = input()
for c in commands:
  d.roll(c)
d.print()
Problem:
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Incorrect submission (verdict: Wrong Answer):
text = input()

count={}

for i in range(97,97+26):
    count[chr(i)] = 0

for letter in text:
    if letter in count:
        count[letter] += 1

for x,y in sorted(count.items()):
    print("{0} : {1}".format(x,y))

Fixed, accepted submission:
count={}
for i in range(97,97+26):
    count[chr(i)] = 0

text=[]
while True:
    try:
        text.append(input())
    except EOFError:
        break

text_out="".join(text)
text_lower=text_out.lower()

for letter in text_lower:
    if letter in count:
        count[letter] += 1

for x,y in sorted(count.items()):
    print("{0} : {1}".format(x,y))
Problem:
We have an H \times W grid whose squares are painted black or white. The square at the i-th row from the top and the j-th column from the left is denoted as (i, j).   Snuke would like to play the following game on this grid. At the beginning of the game, there is a character called Kenus at square (1, 1). The player repeatedly moves Kenus up, down, left or right by one square. The game is completed when Kenus reaches square (H, W) passing only white squares.   Before Snuke starts the game, he can change the color of some of the white squares to black. However, he cannot change the color of square (1, 1) and (H, W). Also, changes of color must all be carried out before the beginning of the game.   When the game is completed, Snuke's score will be the number of times he changed the color of a square before the beginning of the game. Find the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed, that is, Kenus can never reach square (H, W) regardless of how Snuke changes the color of the squares.  The color of the squares are given to you as characters s_{i, j}. If square (i, j) is initially painted by white, s_{i, j} is `.`; if square (i, j) is initially painted by black, s_{i, j} is `#`.

Incorrect submission (verdict: Wrong Answer):
from collections import deque

H, W = map(int, input().split())
S = [input() for _ in range(H)]

s = 0
for c in S:
    s += c.count('.')

que = deque()
dist = [[-1 for j in range(W)] for i in range(H)]
dist[0][0] = 0
st = (0, 0)
que.append(st)
dydx = [(1, 0), (0, 1), (-1, 0), (0, -1)]

while que:
    p, q = que.popleft()

    for dy, dx in dydx:
        print(dy, dx)
        if 0 <= p+dy and p+dy < H and 0 <= q+dx and q+dx < W:
            if dist[p+dy][q+dx] != -1 or S[p+dy][q+dx] != '.':
                continue

            dist[p+dy][q+dx] = dist[p][q] + 1
            que.append((p+dy, q+dx))

if dist[H-1][W-1] == -1:
    print(-1)
else:
    print(s-dist[H-1][W-1]-1)

Fixed, accepted submission:
from collections import deque

H, W = map(int, input().split())
S = [input() for _ in range(H)]

s = 0
for c in S:
    s += c.count('.')

que = deque()
dist = [[-1 for j in range(W)] for i in range(H)]
dist[0][0] = 0
st = (0, 0)
que.append(st)
dydx = [(1, 0), (0, 1), (-1, 0), (0, -1)]

while que:
    p, q = que.popleft()

    for dy, dx in dydx:
        if 0 <= p+dy and p+dy < H and 0 <= q+dx and q+dx < W:
            if dist[p+dy][q+dx] != -1 or S[p+dy][q+dx] != '.':
                continue

            dist[p+dy][q+dx] = dist[p][q] + 1
            que.append((p+dy, q+dx))

if dist[H-1][W-1] == -1:
    print(-1)
else:
    print(s-dist[H-1][W-1]-1)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Time Limit Exceeded):
x = int(input())
n, y = 100, 0
while n < x:
    n = n % 1.01
    y = y + 1
print(n)
print(y)

Fixed, accepted submission:
import math
x = int(input())
n, y = 100, 0
while n < x:
    n = math.floor(n * 1.01)
    y = y + 1
print(y)
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
H, W, K=map(int,input().split())
F = [input() for _ in range(H)]
print(F)
ans = 0 
for i in range(2**H):
  for j in range(2**W):
    cnt = 0
    for ii in range(H):
      for jj in range(W):
        if (i>>ii)%2==0 or (j>>jj)%2==0 or F[ii][jj]==".":
          continue
        cnt+=1
    if cnt==K:
      ans+=1
print(ans)

Fixed, accepted submission:
H, W, K=map(int,input().split())
F = [input() for _ in range(H)]
ans = 0 
for i in range(2**H):
  for j in range(2**W):
    cnt = 0
    for ii in range(H):
      for jj in range(W):
        if (i>>ii)%2==0 or (j>>jj)%2==0 or F[ii][jj]==".":
          continue
        cnt+=1
    if cnt==K:
      ans+=1
print(ans)
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s = input()
n = len(s)
print(s[0]+str(n)+s[-1])

Fixed, accepted submission:
s = input()
n = len(s)
print(s[0]+str(n-2)+s[-1])
Problem:
We have a grid with H rows and W columns. At first, all cells were painted white.  Snuke painted N of these cells. The i-th ( 1 \leq i \leq N ) cell he painted is the cell at the a_i-th row and b_i-th column.  Compute the following:    * For each integer j ( 0 \leq j \leq 9 ), how many subrectangles of size 3×3 of the grid contains exactly j black cells, after Snuke painted N cells?

Incorrect submission (verdict: Wrong Answer):
H, W, N = [int(v) for v in input().split()]
points = (map(int, input().split()) for _ in range(N))
memory = {}

for ai, bi in points:
    for i in range(max(2, ai - 1), min(H - 1, ai + 1) + 1):
        for j in range(max(2, bi - 1), min(W - 1, bi + 1) + 1):
            key = (i, j)
            if not key in memory:
                memory[key] = 0
            memory[key] += 1

counter = {i: 0 for i in range(1, 9 + 1)}
for v in memory.values():
    counter[v] += 1

for i in range(1, 9 + 1):
    print(counter[i])

Fixed, accepted submission:
H, W, N = [int(v) for v in input().split()]
points = (map(int, input().split()) for _ in range(N))
memory = {}
for ai, bi in points:
    for i in range(max(2, ai - 1), min(H - 1, ai + 1) + 1):
        for j in range(max(2, bi - 1), min(W - 1, bi + 1) + 1):
            key = (i, j)
            if not key in memory:
                memory[key] = 0
            memory[key] += 1

counter = {i: 0 for i in range(1, 10)}
for v in memory.values():
    counter[v] += 1

print((H - 2) * (W - 2) - sum(counter.values()))
for i in range(1, 10):
    print(counter[i])
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
x, y, z = [i for i in input().split()]
if x[-1] != y[0]:
     print('no')
elif y[-1] != z[0]:
    print('no')
else: 
    print ('yes')

Fixed, accepted submission:
x, y, z = [i for i in input().split()]
if x[-1] != y[0]:
     print('NO')
elif y[-1] != z[0]:
    print('NO')
else: 
    print ('YES')
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
import sys


def main():
    x = int(sys.stdin.readline())
    print(x**2)
    return


if __name__ == '__main__':
    main()



Fixed, accepted submission:
import sys


def main():
    x = int(sys.stdin.readline())
    print(x**3)
    return


if __name__ == '__main__':
    main()
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,k = map(int,input().split())
lst = []
for i in range(a,a+k):
    if a<=i<=b:
        lst.append(i)
for i in range(b-k+1,b+1):
    if a<=i<=b:
        lst.append(i)    
ans = list(set(lst))
for i in range(len(ans)):
    print(ans[i])

Fixed, accepted submission:
a,b,k = map(int,input().split())
lst = []
for i in range(a,a+k):
    if a<=i<=b:
        lst.append(i)
for i in range(b-k+1,b+1):
    if a<=i<=b:
        lst.append(i)    
ans = list(set(lst))
ans.sort()
for i in range(len(ans)):
    print(ans[i])
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
xy_data=[]
while True:
    xy=list(map(int,input().split()))
    xy.sort()
    print(xy)
    if xy[0]==xy[1]==0:
        break
    else:
        xy_data.append(xy)
for xy in xy_data:
    print(*xy)

Fixed, accepted submission:
xy_data=[]
while True:
    xy=list(map(int,input().split()))
    xy.sort()
    if xy[0]==xy[1]==0:
        break
    else:
        xy_data.append(xy)
for xy in xy_data:
    print(*xy)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
def main():
    N = int(input())
    A = list(map(int, input().split()))[::-1]
    B = list(range(1, N + 1))[::-1]
    C = []

    for a, b in zip(A, B):
        n = 1
        cnt = 0
        while b * n <= N:
            cnt += A[N - b * n]
            n += 1

        C.append(cnt % 2)

    print(*C[::-1])


main()


Fixed, accepted submission:
import sys

import numpy as np

readline = sys.stdin.buffer.readline


def main():
    N = int(readline())
    A = [0] + list(map(int, readline().split()))
    A = np.array(A)
    C = np.zeros(N + 1, dtype=np.int32)

    if A[-1] == 1:
        C[-1] == 1

    for j in range(N, 0, -1):
        cnt = np.count_nonzero(C[j::j])
        C[j] = (cnt % 2) ^ A[j]

    ans = np.sum(C)
    print(ans)
    if ans != 0:
        B = np.arange(N + 1)
        li = B[C == 1]
        print(*li, sep='\n')


main()
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
nums = [int(e) for e in input().split()]

if nums.count(5) == 2 and nums.count(7) == 1:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
nums = [int(e) for e in input().split()]

if nums.count(5) == 2 and nums.count(7) == 1:
  print('YES')
else:
  print('NO')
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = (int(i) for i in input().split())

if a <= c and b >= c:
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
a, b, c = (int(i) for i in input().split())

if a <= c and b >= c:
    print('Yes')
else:
    print('No')
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
n = input()
print(n[0:3:2])

Fixed, accepted submission:
n = input()
print(n[::2])
Problem:
JOI大学のM教授はプログラミングの授業を担当している．クラスには30人の受講生がいて各受講生には1番から30番までの出席番号がふられている．この授業の課題を28人の学生が提出した．提出した28人の出席番号から提出していない2人の出席番号を求めるプログラムを作成せよ．

Incorrect submission (verdict: Wrong Answer):
print(*sorted(set(range(1, 31)) ^ set(int(input()) for _ in range(28))))

Fixed, accepted submission:
for i in sorted(set(range(1, 31)) ^ set(int(input()) for _ in range(28))):
    print(i)
Problem:
You are given an integer sequence of length n, a_1, ..., a_n. Let us consider performing the following n operations on an empty sequence b.  The i-th operation is as follows:    1. Append a_i to the end of b.   2. Reverse the order of the elements in b.  Find the sequence b obtained after these n operations.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = list(map(int, input().split()))
ogya = list()

for i in range (0, n):
	if i%2==0:
		ogya.append(l[i])
	else:
		ogya.insert(0, l[i])

if n%2==0:
	print(ogya, sep=" ")
else:
	ogya.reverse()
	print(ogya, sep=" ")

Fixed, accepted submission:
n = int(input())
L = list(map(int, input().split()))

l = []

if n == 1:
	print(*L)
	exit()

if n%2 == 0:
	for i in range (0,n//2):
		l.append(L[n-1-2*i])
	for i in range (0,n//2):
		l.append(L[2*i])
else:
	for i in range (0,n//2+1):
		l.append(L[n-1-2*i])
	for i in range (0,n//2):
		l.append(L[2*i+1])

print(*l)
Problem:
In this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.  Integers M_1, D_1, M_2, and D_2 will be given as input.   It is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.   Determine whether the date 2019-M_1-D_1 is the last day of a month.

Incorrect submission (verdict: Wrong Answer):
x=input().split()
print(x)

Fixed, accepted submission:
x=input().split()
y=input().split()
if(x[0]!=y[0]):
    print("1")
else:
    print("0")
Problem:
Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.  You are given Smeke's current rating, x. Print `ABC` if Smeke will participate in ABC, and print `ARC` otherwise.

Incorrect submission (verdict: Wrong Answer):
x=int(input())

a=x%11
b=x//11
if 0<a<6:
    ans=2*b+1
elif a==0:
    ans=2*b
elif 5<a<11:
    ans=2*(b+1)
print(ans)

Fixed, accepted submission:
N=int(input())
if N<1200:
  print("ABC")
else:
  print("ARC")
Problem:
We have a string s consisting of lowercase English letters. Snuke can perform the following operation repeatedly:    * Insert a letter `x` to any position in s of his choice, including the beginning and end of s.  Snuke's objective is to turn s into a palindrome. Determine whether the objective is achievable. If it is achievable, find the minimum number of operations required.

Incorrect submission (verdict: Wrong Answer):
s = input()
n = len(s)

sr = s.replace("x", "")

if sr != "".join(reversed(sr)):
    print(-1)
else:
    ans = 0
    l = 0
    r = -1
    while l < n and -r <= n:
        if s[l] == s[r]:
            l += 1
            r -= 1
            continue
        elif s[l] == "x" and s[r] != "x":
            ans += 1
            l += 1
        elif s[l] != "x" and s[r] == "x":
            ans += 1
            r -= 1
    print(ans)


Fixed, accepted submission:
s = input()
n = len(s)

sr = s.replace("x", "")

if sr != "".join(reversed(sr)):
    print(-1)
else:
    ans = 0
    l = 0
    r = -1
    while l - r < n:
        if s[l] == s[r]:
            l += 1
            r -= 1
            continue
        elif s[l] == "x" and s[r] != "x":
            ans += 1
            l += 1
        elif s[l] != "x" and s[r] == "x":
            ans += 1
            r -= 1
        
    print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if a<=b and b<=c:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
a, b, c = map(int, input().split())
if a<=c and c<=b:
  print('Yes')
else:
  print('No')