TnT/CodeNet4Repair huggingface dataset:
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
n,a,b=map(int, input().split())
print(min(a,b),a+b-n)

Fixed, accepted submission:
n,a,b=map(int, input().split())
print(min(a,b),max(0,a+b-n))
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
x,y=map(int,input().split())
a=[4,6,9,11]
if x==2 or y==2:
	ans='No'
elif x in a==y in a:
     ans='Yes'
else:ans='No'
print(ans)
     

Fixed, accepted submission:
x,y=map(int,input().split())
a=[4,6,9,11]
if ((x in a)==(y in a)) and x!=2 and y!=2:
    ans='Yes'
else:ans='No'
print(ans)
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a = [1,3,5,7,8,10,12]
b = [4,6,9,11]
x, y = map(int,input().split())
for i in a:
  if x == i:
    x = "a"
  if y == i:
    y == "a"
for i in b:
  if x == i:
    x = "b"
  if y == i:
    y == "b"
if x == y:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a = [1,3,5,7,8,10,12]
b = [4,6,9,11]
x, y = map(int,input().split())
for i in a:
  if x == i:
    x = "a"
  if y == i:
    y = "a"
for i in b:
  if x == i:
    x = "b"
  if y == i:
    y = "b"
if x == y:
  print("Yes")
else:
  print("No")
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
import math
n = int(input())
print(math.factorial(n) / (pow(10, 9) + 7))


Fixed, accepted submission:
n = int(input())
print(800 *n - ( 200 * int(n / 15)))
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int,input().split()))
ans = 10**10
for i in range(-100,101):
    t = 0
    for j in a:
        t += (j-i)**2
        if t < ans:
            ans =t
print(ans)

Fixed, accepted submission:
n = int(input())
a = list(map(int,input().split()))
ans = 10**10
for i in range(-100,101):
    t = 0
    for j in a:
        t += (j-i)**2
    if t < ans:
        ans =t
print(ans)
Problem:
There are two rectangles. The lengths of the vertical sides of the first rectangle are A, and the lengths of the horizontal sides of the first rectangle are B. The lengths of the vertical sides of the second rectangle are C, and the lengths of the horizontal sides of the second rectangle are D.  Print the area of the rectangle with the larger area. If the two rectangles have equal areas, print that area.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d = map(int,input().split())
print(a*b,c*d)

Fixed, accepted submission:
a,b,c,d = map(int,input().split())
print(max(a*b,c*d))
Problem:
In this problem, we only consider strings consisting of lowercase English letters.  Strings s and t are said to be **isomorphic** when the following conditions are satisfied:    * |s| = |t| holds.   * For every pair i, j, one of the following holds:     * s_i = s_j and t_i = t_j.     * s_i \neq s_j and t_i \neq t_j.  For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.  A string s is said to be in **normal form** when the following condition is satisfied:    * For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.  For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.  You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
pw = ['a', 'b', 'c']
ans = ['' for _ in range(n)]
# print(ord('b'))
def dfs(i):
    if i == n:
        print(''.join(ans))
        return
    for j in range(97, 100):
        # print(j)
        ans[i] = chr(j)
        dfs(i+1)

dfs(0)

Fixed, accepted submission:
n = int(input())
ans = ['' for _ in range(n)]

def dfs(i, mx):
    if i == n:
        print(''.join(ans))
        return
    for j in range(mx+1):
        ans[i] = chr(ord('a') + j)
        dfs(i+1, max(j+1, mx))

dfs(0, 0)
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = 0
for i in range(n+1):
  ans *= i
print(ans % (10 **9 + 7))

Fixed, accepted submission:
n = int(input())
ans = 1
for i in range(1,n+1):
  ans *= i
  ans %= (10**9 + 7)
print(ans)
Problem:
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.  At least how many operations are necessary to satisfy the following conditions?    * For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.   * For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=list(map(int,input().split()))
cur=A[0]
ans=0
isplus=True
ind=1
if cur<0:
  isplus=False
if cur==0:
  
  allzero=True
  firstNotZero=0
  firstNotZeroInd=0
  for i in range(N):
    if A[i]!=0:
      firstNotZero=A[i]
      firstNotZeroInd=i
      allzero=False
      break
  if allzero:
    print(N)
    exit(0)
  
  if firstNotZero>0:
    cur=-1
    ind=firstNotZeroInd
    isplus=False
    print("ind",ind,"isplus",isplus)
  else:
    cur=1
    ind=firstNotZeroInd
    isplus=True
    print("ind",ind,"isplus",isplus)

for i in range(ind,N):
  print("i",i,"cur",cur,"A[i]",A[i])
  if isplus:
    if cur+A[i]>=0:
      diff=abs((cur+A[i])-(-1))
      print("cur",cur,"cur+A[i]",cur+A[i]," -> -1 diff",diff)
      ans+=diff
      print("ans",ans)
      cur=-1
    else:
      print("no problem")
      cur+=A[i]
    isplus=False
  else:
    if cur+A[i]<=0:
      diff=abs((cur+A[i])-1)
      print("cur",cur,"cur+A[i]",cur+A[i]," -> 1 diff",diff)
      ans+=diff
      print("ans",ans)
      cur=1
    else:
      print("no problem")
      cur+=A[i]
    isplus=True
  
print(ans)

Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))
ans=[0]*2
for pat in range(2):
  cur=0
  isplus=pat
  for i in range(N):
    cur+=A[i]
    if isplus:
      if cur<=0:
        ans[pat]+=abs(cur-1)
        cur=1
    else:
      if cur>=0:
        ans[pat]+=abs(cur-(-1))
        cur=-1
    isplus^=1

print(min(ans))
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
A,B,K = map(int, input().split())

if (B-A)>2*K:
    for i in range(A,A+K,1):
        print(i)
    for j in range(B-K,B,1):
        print(j)

else:
    for k in range(A,B+1,1):
        print(k)



Fixed, accepted submission:
A,B,K = map(int, input().split())

if (B-A)>=2*K:
    for i in range(A,A+K,1):
        print(i)
    for j in range(B-K+1,B+1,1):
        print(j)

else:
    for k in range(A,B+1,1):
        print(k)
Problem:
Snuke is making sugar water in a beaker. Initially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.    * Operation 1: Pour 100A grams of water into the beaker.   * Operation 2: Pour 100B grams of water into the beaker.   * Operation 3: Put C grams of sugar into the beaker.   * Operation 4: Put D grams of sugar into the beaker.  In our experimental environment, E grams of sugar can dissolve into 100 grams of water.  Snuke will make sugar water with the highest possible density.  The beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker. Find the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it. If there is more than one candidate, any of them will be accepted.  We remind you that the sugar water that contains a grams of water and b grams of sugar is \frac{100b}{a + b} percent. Also, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d,e,f=map(int,input().split())

def calc(w,s):
    sugar=0
#    while sugar/(w+sugar)<=e/(100+e) and w+sugar<=f:
    while sugar/w <= e/100 and w+sugar<=f:
        sugar+=s
    return w,sugar-s

w1,s1=calc(100*a,c)
w2,s2=calc(100*a,d)
w3,s3=calc(100*b,c)
w4,s4=calc(100*b,d)

print(w1,s1,w2,s2,w3,s3,w4,s4)

ansx=0
ansy=0
mol=0
for i in range(30):
    for j in range(30):
        for k in range(30):
            for l in range(30):
                sugar=s1*i+s2*j+s3*k+s4*l
                solvent=sugar+w1*i+w2*j+w3*k+w4*l
#                print(sugar,solvent)
                if solvent!=0 and sugar/solvent<=e/(100+e) and solvent<=f:
                    if mol < (100*sugar)/solvent:
                        ansx=solvent
                        ansy=sugar
                        mol=(100*sugar)/solvent
print(ansx,ansy)

Fixed, accepted submission:
a,b,c,d,e,f=map(int,input().split())

water_g=[]
for i in range(f//100+1):
  for j in range(f//100+1):
#    print(i,j)
    w=100*a*i + 100*b*j
    if w<=f:
      water_g.append(w)
    else:
      break
water_g=sorted(list(set(water_g)),reverse=True)

sugar_g=[]
for i in range(f*e//100):
  for j in range(f*e//100):
    s=c*i + d*j
    if s<=f:
      sugar_g.append(s)
    else:
      break
sugar_g=sorted(list(set(sugar_g)),reverse=True)

#print(water_g, sugar_g)

ans_water=100*a
ans_sugar=0
for water in water_g:
  if water==0:
    break
  for sugar in sugar_g:
    if water+sugar<=f and sugar/water<=e/100:
      if sugar/(sugar+water)>ans_sugar/(ans_sugar+ans_water):
        ans_water=water
        ans_sugar=sugar
print(ans_water+ans_sugar,ans_sugar)
Problem:
There are N people, conveniently numbered 1 through N. They were standing in a row yesterday, but now they are unsure of the order in which they were standing. However, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person. According to their reports, the difference above for person i is A_i.  Based on these reports, find the number of the possible orders in which they were standing. Since it can be extremely large, print the answer modulo 10^9+7. Note that the reports may be incorrect and thus there may be no consistent order. In such a case, print 0.

Incorrect submission (verdict: Wrong Answer):
import sys
import itertools
# import numpy as np
import time
import math
import heapq
from collections import defaultdict
sys.setrecursionlimit(10 ** 7)
 
INF = 10 ** 18
MOD = 10 ** 9 + 7
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

# map(int, input().split())

N = int(input())
A = list(map(int, input().split()))

X = [0] * N
for i, a in enumerate(A):
    j = (N - 1 - a) // 2
    X[j] += 1

for i, x in enumerate(X):
    if x == 1 and not (i == (N + 1) // 2):
        print(0)
        exit()
    if x > 2:
        print(0)
        exit()

ans = 1
for x in X:
    if x == 0:
        break
    ans *= x
    ans %= MOD
print(ans)



Fixed, accepted submission:
import sys
import itertools
# import numpy as np
import time
import math
import heapq
from collections import defaultdict
sys.setrecursionlimit(10 ** 7)
 
INF = 10 ** 18
MOD = 10 ** 9 + 7
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

# map(int, input().split())

N = int(input())
A = list(map(int, input().split()))

X = [0] * N
for i, a in enumerate(A):
    j = (N - 1 - a) // 2
    X[j] += 1

for i, x in enumerate(X):
    if x == 1 and not (i == (N + 1) // 2 - 1):
        print(0)
        exit()
    if x > 2:
        print(0)
        exit()

ans = 1
for x in X:
    if x == 0:
        break
    ans *= x
    ans %= MOD
print(ans)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
import sys

N = int(input())
t = [0 for i in range(N)]
x = [0 for i in range(N)]
y = [0 for i in range(N)]

for i in range(N):
    t[i], x[i], y[i] = map(int, input().split())

for i in range(N-1):
    time = t[i+1] - t[i]
    dist = abs(x[i+1] - x[i]) + abs(y[i+1] - y[i])
    if (time - dist) >= 0 and (time - dist) % 2 == 0:
        pass
    else:
        print("No")
        sys.exit()


Fixed, accepted submission:
import sys

N = int(input())
t = [0 for i in range(N+1)]
x = [0 for i in range(N+1)]
y = [0 for i in range(N+1)]

for i in range(1, N+1):
    t[i], x[i], y[i] = map(int, input().split())

for i in range(N):
    time = t[i+1] - t[i]
    dist = abs(x[i+1] - x[i]) + abs(y[i+1] - y[i])
    if (time - dist) >= 0 and (time - dist) % 2 == 0:
        pass
    else:
        print("No")
        sys.exit()
print("Yes")
Problem:
There are N rabbits, numbered 1 through N.  The i-th (1≤i≤N) rabbit likes rabbit a_i. Note that no rabbit can like itself, that is, a_i≠i.  For a pair of rabbits i and j (i＜j), we call the pair (i，j) a _friendly pair_ if the following condition is met.    * Rabbit i likes rabbit j and rabbit j likes rabbit i.  Calculate the number of the friendly pairs.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(lambda x:int(x)-1,input().split()))
ans = 0
for i in range(N):
    if a[i] == i:
        ans += 1
print(ans//2)

Fixed, accepted submission:
N = int(input())
a = list(map(lambda x:int(x)-1,input().split()))
ans = 0
for i in range(N):
    if a[a[i]] == i:
        ans += 1
print(ans//2)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
x=N//1.08
if int(x*1.08) == N:
  print(x)
elif int((x+1)*1.08) == N:
  print(x+1)
else:
  print(':(')

Fixed, accepted submission:
#N,a,b = map(int,input().split())
N = int(input())

X=int(N/1.08)
if int(X*1.08) == N:
    print(X)

elif int((X+1)*1.08) == N:
    print(X+1)

else:
    print(':(')
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):

s=input().replace("eraser", "").replace("erase","").replace("dreamer","").replace("dream","")
if s:
    print("NO")
else:
    print("Yes")


Fixed, accepted submission:
s=input().replace("eraser","").replace("erase","").replace("dreamer","").replace("dream","")
if s:
    print("NO")
else:
    print("YES")
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
import sys
n = int(input())
sys.stdout.write(" ")
answer = []
for i in range(n + 1):
    if i%3 == 0:
        answer.append(i)
    elif '3' in str(i):
        answer.append(i)
print(*answer)

Fixed, accepted submission:
import sys
n = int(input())
sys.stdout.write(" ")
answer = []
for i in range(3, n + 1):
    if i%3 == 0:
        answer.append(i)
    elif '3' in str(i):
        answer.append(i)
print(*answer)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x = int(input())
n = 100
c = 0
while n -100< x:
    n = int(n *1.01)
    c += 1
print(c)

Fixed, accepted submission:
x = int(input())
n = 100
c = 0
while n  < x:
    n += int(n / 100)
    c += 1
    #print(n,c)
print(c)
Problem:
"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.  Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Incorrect submission (verdict: Wrong Answer):
A, B, C, X, Y = map(int, input().split())
ans = 0

if A + B <= C:
    ans = A*X + B*Y
else:
    ans = 2*C*max(X, Y)

print (ans) 


Fixed, accepted submission:
A, B, C, X, Y = map(int, input().split())
ans = 0

if A + B <= 2*C:
    ans = A*X + B*Y
else:
    ans += 2*C*min(X, Y)

    if X >= Y:
        ans += min(A, 2*C) * (X-Y)
    else:
        ans += min(B, 2*C) * (Y-X)

print (ans)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
x=int(input())
val = x//1.08
if val*1.08 == x:
  print(val)
else:
  print(":(")

Fixed, accepted submission:
from math import floor
n = int(input())
val = round(n/1.08)
if floor(val*1.08) == n:
  print(val)
elif floor((val+1)*1.08) ==n:
  print(val+1)
else:
  print(":(")
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
SX,SY,TX,TY=map(int,input().split())
vx=TX-SX
vy=TY-SY
print('U'*vy+'R'*vx+'L'*vx+'D'*vy+'L'+'U'*(vy+1)+'R'*(vx+1)+'D'+ 'R'+'D'*(vy+1)+'L'*(vx+1)+'U')

Fixed, accepted submission:
p,q,x,y=map(int,input().split())
x-=p
y-=q
u='U'*y+'R'*x
d='D'*y+'L'*x+'LU'
print(u+d+u+'RDRD'+d)