TnT/CodeNet4Repair huggingface dataset:
Problem:
There are N balls in a two-dimensional plane. The i-th ball is at coordinates (x_i, y_i).  We will collect all of these balls, by choosing two integers p and q such that p \neq 0 or q \neq 0 and then repeating the following operation:    * Choose a ball remaining in the plane and collect it. Let (a, b) be the coordinates of this ball. If we collected a ball at coordinates (a - p, b - q) in the previous operation, the cost of this operation is 0. Otherwise, including when this is the first time to do this operation, the cost of this operation is 1.  Find the minimum total cost required to collect all the balls when we optimally choose p and q.

Incorrect submission (verdict: Wrong Answer):
import itertools
from collections import Counter


def main():
    N = int(input())
    data = []
    for _ in range(N):
        data.append( list(map(int, input().split())) )

    if N <= 2:
        return 1
    else:
        key_num = ( N*(N - 3) ) // 2 + N
        common_data = []
        max_common_num = 0

        for obj in itertools.combinations(data, 2):
            # print(obj)
            common_data.append( str(obj[0][0] - obj[1][0]) + "_" + str(obj[0][1] - obj[1][1]) )

        
        counter = Counter(common_data)
        for word, cnt in counter.most_common():
            max_common_num = cnt
            break

    print(N - max_common_num)
    # print(common_data)

if __name__ == '__main__':
    main()


Fixed, accepted submission:
import itertools
from collections import Counter

def main():
    N = int(input())
    data = []
    common_data = []
    max_common_num = 0
    for _ in range(N):
        data.append( list(map(int, input().split())) )

    data.sort()

    if N == 1:
        return 1
    else:
        for obj in itertools.combinations(data, 2):
            # print(obj)
            common_data.append( str(obj[0][0] - obj[1][0]) + "_" + str(obj[0][1] - obj[1][1]) )

        
        counter = Counter(common_data)
        for word, cnt in counter.most_common():
            if cnt >= max_common_num:
                max_common_num = cnt

    # print(common_data)
    return N - max_common_num

if __name__ == '__main__':
    print( main() )
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
def SieveOfEratosthenes(n):
    prime = [True for i in range(n + 1)]
    p = 2
    while (p * p <= n):

        if (prime[p] == True):

            for i in range(p * 2, n + 1, p):
                prime[i] = False
        p += 1
    lis = []
    for i in range(2,n):
        if prime[i]:
            lis.append(i)
    return lis

n = int(input())

lis1 = []

l = SieveOfEratosthenes(n)

for i in l:
    m = n
    z = i
    exp = 0
    while(m>=z):
        exp += m//z
        z*=i
    lis1.append(exp)

mul = 1
for i in lis1:
    mul *= (i+1)


print(mul)



Fixed, accepted submission:
def SieveOfEratosthenes(n):
    prime = [True for i in range(n + 1)]
    p = 2
    while (p * p <= n):

        if (prime[p] == True):

            for i in range(p * 2, n + 1, p):
                prime[i] = False
        p += 1
    lis = []
    for i in range(2,n+1):
        if prime[i]:
            lis.append(i)
    return lis

n = int(input())

lis1 = []

l = SieveOfEratosthenes(n)

for i in l:
    m = n
    z = i
    exp = 0
    while(m>=z):
        exp += m//z
        z*=i
    lis1.append(exp)

mul = 1
for i in lis1:
    mul *= (i+1)

print(mul%(10**9+7))
Problem:
Write a program which reads a list of student test scores and evaluates the performance for each student.  The test scores for a student include scores of the midterm examination m (out of 50), the final examination f (out of 50) and the makeup examination r (out of 100). If the student does not take the examination, the score is indicated by -1.  The final performance of a student is evaluated by the following procedure:    * If the student does not take the midterm or final examination, the student's grade shall be F.   * If the total score of the midterm and final examination is greater than or equal to 80, the student's grade shall be A.   * If the total score of the midterm and final examination is greater than or equal to 65 and less than 80, the student's grade shall be B.   * If the total score of the midterm and final examination is greater than or equal to 50 and less than 65, the student's grade shall be C.   * If the total score of the midterm and final examination is greater than or equal to 30 and less than 50, the student's grade shall be D. However, if the score of the makeup examination is greater than or equal to 50, the grade shall be C.   * If the total score of the midterm and final examination is less than 30, the student's grade shall be F.

Incorrect submission (verdict: Wrong Answer):
while():
    m,f,r = list(map(int, input().split()))
    
    if (m==-1 & f == -1 & r==-1):
        break
        
    
    if (m == -1 | f == -1):
        print ("F")
    
    elif (m + f >= 80):
        print ("A")
    
    elif (m+f >= 65):    
        print ("B")
    
    elif (m+f >= 65):
        print ("C")
    
    elif (m+f >= 30):
        if (r >= 50):
            print ("C")
        else:
            print ("D")
    
    elif (m+f<30):
        print ("F")

Fixed, accepted submission:
while True:
    m,f,r = list(map(int, input().split()))
    
    if (m == -1) and (f == -1) and (r == -1):
        break
    elif (m == -1 or f == -1):
        print("F")
    elif (m+f >= 80):
        print("A")
    elif (m+f >= 65) and (m+f < 80):
        print("B")
    elif (m+f >= 50) and (m+f < 65):
        print("C")
    elif (m+f >= 30) and (m+f < 50):
        if (r >= 50):
            print("C")
        else:
            print("D")
    elif (m+f < 30):
            print("F")
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
def sort_two_numbers(a, b): 
    """ 
    a: int
    b: int
    returns a sorted list

    >>> sort_two_numbers(1, 3)
    [1, 3]
    >>> sort_two_numbers(3, 1)
    [1, 3]
    """
    result = []
    
    if a < b:
        result.append(a)
        result.append(b)
    else:
        result.append(b)
        result.append(a)

    return result

if __name__ == '__main__':

#    doctest.testmod()

    while True:
        try:
            (a, b) = input().split(' ')
            print('{0[0]} {0[1]}'.format(sort_two_numbers(int(a), int(b))))
        except EOFError:
            break

Fixed, accepted submission:
def sort_two_numbers(a, b):
    """
    a: int
    b: int
    returns a sorted list

    >>> sort_two_numbers(1, 3)
    [1, 3]
    >>> sort_two_numbers(3, 1)
    [1, 3]
    """
    result = []
    
    if a < b:
        result.append(a)
        result.append(b)
    else:
        result.append(b)
        result.append(a)

    return result

if __name__ == '__main__':

#    doctest.testmod()

    while True:
        try:
            (a, b) = [int(i) for i in input().split(' ')]
            if a == 0 and b == 0:
                break
            print('{0[0]} {0[1]}'.format(sort_two_numbers(int(a), int(b))))
        except EOFError:
            break
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
a = int(input())-1
b = str(input())
c = b[a]
print(c)

Fixed, accepted submission:
a = int(input())
b = str(input())
c = []
for i in b:
    c += i
if c.count('R') > c.count('B'):
    print("Yes")
else:
    print("No")
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
import math
math.ceil((a+b)/2)

Fixed, accepted submission:
a,b=map(int,input().split())
import math
print(math.ceil((a+b)/2))
Problem:
Write a program which reads a sequence _A_ of _n_ elements and an integer _M_ , and outputs "yes" if you can make _M_ by adding elements in _A_ , otherwise "no". You can use an element only once.  You are given the sequence _A_ and _q_ questions where each question contains _M i_.

Incorrect submission (verdict: Wrong Answer):
import itertools
given_n = int(input())
given_A = list(map(int,input().split()))
given_q = int(input())
given_m = list(map(int,input().split()))

for mi in given_m:
    partial_A = list(filter(lambda ai:ai<mi,given_A))
    check = False
    for num in range(1,len(partial_A)+1):
        combinationPartialA = list(itertools.combinations(partial_A,num))
        for tmp_cpa in combinationPartialA:
            if sum(tmp_cpa) == mi:
                check = True
    if check:
        print("yes")
    else:
        print("no")

Fixed, accepted submission:
from functools import lru_cache

@lru_cache(maxsize = None)
def canProd(i,m):
     
    if m == 0:
        return True
    if i >= n:
        return False
 
    res = canProd(i+1,m) or canProd(i+1,m-a[i])
    return res
 
 
n = int(input())
a = [int(x) for x in input().split()]
q = int(input())
m = [int(x) for x in input().split()]

rs = [None]*2001

maxm = max(m)
minm = min(m)

for i in range(minm,maxm+1):
    if canProd(0,i):
        rs[i] = "yes"
    else:
        rs[i] = "no"

for i in m:
    print(rs[i])
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
i = input()
data = i.split(" ")
if (int(data[0])*int(data[1]))%2 == 0:
    print(int(data[0])*int(data[1])/2)
else:
    print(int(data[0])*int(data[1])//2+1)

Fixed, accepted submission:
i = input()
data = i.split(" ")
if int(data[0])*int(data[1]) == int(data[0]) or int(data[0])*int(data[1]) == int(data[1]):
    print(1)
elif (int(data[0])*int(data[1]))%2 == 0:
    print(int(data[0])*int(data[1])//2)
else:
    print(int(data[0])*int(data[1])//2+1)
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
nums = map(int, input().split())
print(len(set(nums)))


Fixed, accepted submission:
nums = [int(input()) for _ in range(int(input()))]
print(len(set(nums)))
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
A, B, C = [int(i) for i in input().split()]

if A + B >= C:
	print("yes")
else:
	print("No")

Fixed, accepted submission:
A, B, C = [int(i) for i in input().split()]

if A + B >= C:
	print("Yes")
else:
	print("No")
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a ,b  = map(int, input().split())
g2 =  [4,6,9,11]
g1 =[1,3,5,7,8,10,12]
if a in g2 and b in g2:
    print("Yes")
elif a == 2 and b ==2:
    print("Yes")
elif a in g1 and b in g2:
    print("Yes")
else:print("No")

Fixed, accepted submission:
a ,b  = map(int, input().split())
g2 =  [4,6,9,11]
g1 =[1,3,5,7,8,10,12]
if a in g2 and b in g2:
    print("Yes")
elif a == 2 and b ==2:
    print("Yes")
elif a in g1 and b in g1:
    print("Yes")
else:print("No")
Problem:
Let's first write a program to calculate the score from a pair of input and output. You can know the total score by submitting your solution, or an official program to calculate a score is often provided for local evaluation as in this contest. Nevertheless, writing a score calculator by yourself is still useful to check your understanding of the problem specification. Moreover, the source code of the score calculator can often be reused for solving the problem or debugging your solution. So it is worthwhile to write a score calculator unless it is very complicated.

Incorrect submission (verdict: Wrong Answer):
import copy
D = int(input())
c = list(map(int, input().split()))
s = []
for _ in range(D):
  s.append(list(map(int, input().split())))
t = []
for _ in range(D):
  t.append(int(input()))
u = [] 
x = [0] * 26
u.append(x)
for i in range(D):
  v = copy.deepcopy(u)
  y = v[-1]
  y[t[i]-1] = i+1
  u.append(y)
del u[0]
print(D)
print(c)
print(s)
print(t)
print(u)
ans = 0
for i in range(D):
  ans += s[i][t[i]-1]
  for j in range(26):
    ans -= c[j] * ((i+1) - u[i][j]) 
  print(ans)

Fixed, accepted submission:
import copy
D = int(input())
c = list(map(int, input().split()))
s = []
for _ in range(D):
  s.append(list(map(int, input().split())))
t = []
for _ in range(D):
  t.append(int(input()))
u = [] 
x = [0] * 26
u.append(x)
for i in range(D):
  v = copy.deepcopy(u)
  y = v[-1]
  y[t[i]-1] = i+1
  u.append(y)
del u[0]

ans = 0
for i in range(D):
  ans += s[i][t[i]-1]
  for j in range(26):
    ans -= c[j] * ((i+1) - u[i][j]) 
  print(ans)
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
import math


def isPrime(num):
    
    if num < 2: return False
    
    elif num == 2: return True
    
    elif num % 2 == 0: return False

    
    
    for i in range(3, math.floor(math.sqrt(num))+1, 2):
        if num % i == 0:
            return False

    
    return True

判定
def callIsPrime(input_num):
    numbers = []
    
    for i in range(1, input_num):
        if isPrime(i):
            numbers.append(i)
    return numbers
   

def myAnswer(X:int) -> int:
   prime = callIsPrime(X)
   ans = 1
   for p in prime:
      i = 2
      while True:
         if(p**i <= X):
            ans = max(p**i,ans)
            i += 1
         else:
            break
   return ans


def modelAnswer():
   tmp=1
def main():
   X = int(input())
   print(myAnswer(X))
if __name__ == '__main__':
   main()

Fixed, accepted submission:

def myAnswer(X:int) -> int:
   numbers = [i for i in range(2,X+1)]
   ans = 1
   for p in numbers:
      i = 2
      while True:
         if(p**i <= X):
            ans = max(p**i,ans)
            i += 1
         else:
            break
   return ans


def modelAnswer():
   tmp=1
def main():
   X = int(input())
   print(myAnswer(X))
if __name__ == '__main__':
   main()
Problem:
How many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?

Incorrect submission (verdict: Wrong Answer):
m = int(input())

print(24-m)

Fixed, accepted submission:
print(48 - int(input()))
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
def main(N,xs):
    # type: (int, List[int]) -> None
    xs.sort(reverse=True)
    alice = sum(xs[0::2])
    bob = sum(xs[0:1:2])
    print(alice-bob)
    return

if __name__ == '__main__':
    N = int(input())
    xs = list(map(int,input().split()))
    main(N,xs)


Fixed, accepted submission:
def main(N,xs):
    # type: (int, List[int]) -> None
    xs.sort(reverse=True)
    alice = xs[0::2]
    bob = xs[1::2]
    print(sum(alice)-sum(bob))
    return

if __name__ == '__main__':
    N = int(input())
    xs = list(map(int,input().split()))
    main(N,xs)
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a,b,c = [int(i) for i in input().split()]

if (b-a) == (c-b):
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b,c = [int(i) for i in input().split()]

if (b-a) == (c-b):
    print("YES")
else:
    print("NO")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

countA = 0
countW = 0
countT = 0
countR = 0
for i in range(n):
  a = input()
  if a == "AC":
    countA += 1
  elif a == "WA":
    countW += 1
  elif a == "TLE":
    countT += 1
  elif a == "RE":
    countR += 1

print("AC × " + str(countA))
print("WA × " + str(countW))
print("TLE × " + str(countT))
print("RE × " + str(countR))
    

Fixed, accepted submission:
n = int(input())

countA = 0
countW = 0
countT = 0
countR = 0
for i in range(n):
  a = input()
  if a == "AC":
    countA += 1
  elif a == "WA":
    countW += 1
  elif a == "TLE":
    countT += 1
  elif a == "RE":
    countR += 1

print("AC x " + str(countA))
print("WA x " + str(countW))
print("TLE x " + str(countT))
print("RE x " + str(countR))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
if n%1000==0 :
  print("0")
else : 
  print(n-n%1000)

Fixed, accepted submission:
n=int(input())
print((1000-n%1000)%1000)
Problem:
Snuke has N strings. The i-th string is s_i.  Let us concatenate these strings into one string after arranging them in some order. Find the maximum possible number of occurrences of `AB` in the resulting string.

Incorrect submission (verdict: Wrong Answer):

# coding: utf-8

# In[7]:

import sys
input = sys.stdin.readline
N = int(input())
S = [input() for i in range(N)]


# In[9]:

b_cnt = 0
a_cnt = 0
for i in range(N):
    if S[i][0]=='B':
        b_cnt += 1
    if S[i][-1]=='A':
        a_cnt += 1
#print(b_cnt, a_cnt)
print('/'.join(S).count('AB') + min(a_cnt, b_cnt))


# In[ ]:





Fixed, accepted submission:

# coding: utf-8

# In[17]:

import sys
#input = sys.stdin.readline
N = int(input())
S = [input() for i in range(N)]


# In[18]:

b_cnt = 0
a_cnt = 0
ab_cnt = 0
for i in range(N):
    if S[i][0]=='B'and S[i][-1]=='A':
        ab_cnt += 1
    elif S[i][0]=='B':
        b_cnt += 1
    elif S[i][-1]=='A':
        a_cnt += 1
#print(b_cnt, a_cnt)
#print(ab_cnt, a_cnt, b_cnt, '/'.join(S).count('AB') )

#if abs(a_cnt-b_cnt) >= 1 and ab_cnt > 0:
ans = 0
if ab_cnt > 0:
    ans += ab_cnt - 1
    if b_cnt > 0:
        b_cnt -= 1
        ans += 1
    if a_cnt > 0:
        a_cnt -= 1
        ans += 1
ans += min(a_cnt, b_cnt)

"""
if max(a_cnt, b_cnt) == 0 and ab_cnt > 0:
    ab_cnt -= 1
elif min(a_cnt, b_cnt) > 0 and ab_cnt > 0:
    ab_cnt += 1
elif abs(a_cnt-b_cnt) == 0 and ab_cnt > 0:
    ab_cnt += 1
elif abs(a_cnt-b_cnt) > 0 and ab_cnt > 0:
    ab_cnt += 0
"""
    
#if ab_cnt < 0:
#    ab_cnt = 0
#ab_cnt = ab_cnt-1 if ab_cnt!=0 else ab_cnt
print('/'.join(S).count('AB') + ans)


# In[ ]:
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
x, y = map(int, input().split())
 
cnt = 0
for i in range(1, 13):
    if i > x:
        break
    for j in range(1, 13):
        if i == x and j == y:
            break
        if i == j:
            cnt += 1
print(cnt)

Fixed, accepted submission:
x, y = map(int, input().split())
 
cnt = 0
for i in range(1, 13):
    if i > x:
        break
    for j in range(1, 13):
        if i == j:
            cnt += 1
        if i == x and j == y:
            break
print(cnt)