TnT/CodeNet4Repair huggingface dataset:
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
### coding: UTF-8

#import math
#import random as rd
#import numpy as np

#n,a,b=map(int,input().split( ))

n=100
a=4
b=16

s=0


for i in range(n):
    line=list(map(int,str(i+1)))
    if sum(line)>=a and sum(line)<=b:
        s+=i+1


Fixed, accepted submission:
### coding: UTF-8

#import math
#import random as rd
#import numpy as np

n,a,b=map(int,input().split( ))

s=0


for i in range(n):
    line=list(map(int,str(i+1)))
    if sum(line)>=a and sum(line)<=b:
        s+=i+1

print(s)
Problem:
You are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W). Determine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:    * The matrix has H rows and W columns.   * Each element of the matrix is an integer between -10^9 and 10^9 (inclusive).   * The sum of all the elements of the matrix is positive.   * The sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.

Incorrect submission (verdict: Wrong Answer):
H, W, h, w = map(int, input().split())

if H % h == 0 or W % w == 0:
    print("No")
    exit(0)

blocks = (H//h) * (W//w)
left = H * W - blocks * h * w
offset = blocks // left + 1
v = [offset, -offset * h * w - 1]

print("Yes")
for i in range(H):
    a = []
    for j in range(W):
        a.append(v[1 if i % h == h-1 and j % w == w-1 else 0])
    print(" ".join(list(map(str, a))))


Fixed, accepted submission:
H, W, h, w = map(int, input().split())

if H % h == 0 and W % w == 0:
    print("No")
    exit(0)

blocks = (H//h) * (W//w)
left = H * W - blocks * h * w
offset = blocks // left + 1
v = [offset, -offset * (h * w - 1) - 1]

print("Yes")
for i in range(H):
    a = []
    for j in range(W):
        a.append(v[1 if i % h == h-1 and j % w == w-1 else 0])
    print(" ".join(list(map(str, a))))
Problem:
On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in `yyyy/mm/dd` format. For example, January 23, 2018 should be written as `2018/01/23`.  After finishing the document, she noticed that she had mistakenly wrote `2017` at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to `2018` and prints it.

Incorrect submission (verdict: Wrong Answer):
S = input()
S[3]=="8"
print(S)

Fixed, accepted submission:
s = input()
print('2018'+s[4:])
Problem:
Find the smallest possible sum of the digits in the decimal notation of a positive multiple of K.

Incorrect submission (verdict: Time Limit Exceeded):
n = input()


def get_sum(n):
    s = str(n)
    arr = list(map(int, list(s)))
    return sum(arr)

ans = get_sum(n)
i = 1
for i in range(1, 10000):
    m = get_sum(n * i)
    if ans > m:
        ans = m

print(ans)


Fixed, accepted submission:
import collections


def ans(n):
    dist = [10 ** 5] * n
    dist[1] = 1
    d = collections.deque()
    d.append(1)
    while not d.count == 0:
        u = d.popleft()
        if u == 0:
            return dist[u]
        if dist[u] < dist[(u * 10) % n]:
            dist[(u * 10) % n] = dist[u]
            d.appendleft((u * 10) % n)
        if dist[u] < dist[(u + 1) % n]:
            dist[(u + 1) % n] = dist[u] + 1
            d.append((u + 1) % n)

n = int(input())
print(ans(n))
Problem:
"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.  Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    A, B, C, X, Y = list(map(int, input().split()))
    if A + B < 2 * C:
        print(1)
        print(A * X + B * Y)
    else:
        if X == Y:
            print(2)
            print(C * 2 * X)
        elif X < Y:
            print(3)
            print(X * C * 2 + B * (Y - X))
        else:
            print(4)
            print(Y * C * 2 + A * (X - Y))


Fixed, accepted submission:
if __name__ == '__main__':
    A, B, C, X, Y = list(map(int, input().split()))
    if A + B <= 2 * C:
        # print(1)
        print(A * X + B * Y)
    else:
        if X == Y:
            # print(2)
            print(C * 2 * X)
        elif X < Y:
            # print(3)
            print(min(X * C * 2 + B * (Y - X), C * 2 * Y))
        else:
            # print(4)
            print(min(Y * C * 2 + A * (X - Y), C * 2 * X))
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
s=int(input().replace(" ",""))
print("YES" if s//4==0 else "NO")

Fixed, accepted submission:
s=int(input()[::2])
print("NO" if s%4 else "YES")
Problem:
平成31年4月30日をもって現行の元号である平成が終了し，その翌日より新しい元号が始まることになった．平成最後の日の翌日は新元号元年5月1日になる．  ACM-ICPC OB/OGの会 (Japanese Alumni Group; JAG) が開発するシステムでは，日付が和暦（元号とそれに続く年数によって年を表現する日本の暦）を用いて "平成 _y_ 年 _m_ 月 _d_ 日" という形式でデータベースに保存されている．この保存形式は変更することができないため，JAGは元号が変更されないと仮定して和暦で表した日付をデータベースに保存し，出力の際に日付を正しい元号を用いた形式に変換することにした．  あなたの仕事はJAGのデータベースに保存されている日付を，平成または新元号を用いた日付に変換するプログラムを書くことである．新元号はまだ発表されていないため，"?" を用いて表すことにする．

Incorrect submission (verdict: Wrong Answer):
while True:
    line = input()
    if line == '#':
        exit()

    g = line.split()[0]
    y, m, d = map(int, line.split()[1:])
    if y > 31:
        g = '?'
    elif m > 4:
        g = '?'
    print(g, y, m, d)



Fixed, accepted submission:
while True:
    line = input()
    if line == '#':
        exit()

    g = line.split()[0]
    y, m, d = map(int, line.split()[1:])
    if y > 31 or y >= 31 and m >= 5:
        g = '?'
        y -= 30
    print(g, y, m, d)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

N = int(input())


ans = N % 1000


print(ans)


Fixed, accepted submission:
# -*- coding: utf-8 -*-

def get_input() -> int:
    
    N = int(input())

    return N


def main(N: int) -> None:
    
    
    ans = (1000 - (N % 1000)) % 1000

    
    print(ans)


if __name__ == "__main__":
    
    N = get_input()

    
    main(N)
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
def bubbleSort(A, N):
    swap_count = 0
    flag = True
    while flag:
        flag = False
        for j in range(N-1, 0, -1):
            if A[j] < A[j-1]:
                A[j], A[j-1] = A[j-1], A[j]
                flag = True
                swap_count += 1
                print(A)
    return swap_count

n = int(input())
A = list(map(int, input().split()))
count = bubbleSort(A,n)
print(*A)
print(count)

Fixed, accepted submission:
def bubbleSort(A, N):
    swap_count = 0
    flag = True
    while flag:
        flag = False
        for j in range(N-1, 0, -1):
            if A[j] < A[j-1]:
                A[j], A[j-1] = A[j-1], A[j]
                flag = True
                swap_count += 1
    return swap_count

n = int(input())
A = list(map(int, input().split()))
count = bubbleSort(A,n)
print(*A)
print(count)
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
input()
a=list(map(int,input().split()))
a.sort(reverse=True)
sum(a[:-1])

Fixed, accepted submission:
input()
a=list(map(int,input().split()))
a.sort(reverse=True)

import collections
count=len(a)
ans=0
c = collections.Counter(a)
for i in c.keys():
    tmp = c[i]*2
    if count<=tmp:
        ans+=i*count
        break
    else:
        ans+=i*tmp
        count-=tmp
print(ans-max(a))
Problem:
Snuke is making sugar water in a beaker. Initially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.    * Operation 1: Pour 100A grams of water into the beaker.   * Operation 2: Pour 100B grams of water into the beaker.   * Operation 3: Put C grams of sugar into the beaker.   * Operation 4: Put D grams of sugar into the beaker.  In our experimental environment, E grams of sugar can dissolve into 100 grams of water.  Snuke will make sugar water with the highest possible density.  The beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker. Find the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it. If there is more than one candidate, any of them will be accepted.  We remind you that the sugar water that contains a grams of water and b grams of sugar is \frac{100b}{a + b} percent. Also, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d,e,f = map(int, input().split())
s_max = f*e//(e+100)
w_max = f//(e+100)

s=[]
w=[]

max = 0
ans = []
for i in range(s_max//c+1):
    for j in range(s_max//d+1):
        if c*i + d*j <= s_max:
            s.append(c*i + d*j)

for i in range(w_max//a+1):
    for j in range(w_max//b+1):
        if 0<a*i + b*j <= w_max:
            w.append(a*i + b*j)

for i in range(len(s)):
    for j in range(len(w)):
        if s[i]/(w[j]*100+s[i])<=e/(e+100) and s[i]/(w[j]*100+s[i])>max:
            max = s[i]/(w[j]*100+s[i])
            ans = [w[j]*100+s[i],s[i]]

print(ans)


Fixed, accepted submission:
a,b,c,d,e,f = map(int, input().split())
s_max = f*e//(e+100)
w_max = f//100

s=[]
w=[]

max = 0
ans = [100*a,0]
for i in range(s_max//c+1):
    for j in range(s_max//d+1):
        if c*i + d*j <= s_max:
            s.append(c*i + d*j)

for i in range(w_max//a+1):
    for j in range(w_max//b+1):
        if 0<a*i + b*j <= w_max:
            w.append(a*i + b*j)

for i in range(len(s)):
    for j in range(len(w)):
        if s[i]/(w[j]*100+s[i])<=e/(e+100) and s[i]/(w[j]*100+s[i])>=max and w[j]*100+s[i]<=f:
            max = s[i]/(w[j]*100+s[i])
            ans = [w[j]*100+s[i],s[i]]

print(ans[0],ans[1])
Problem:
There are four towns, numbered 1,2,3 and 4. Also, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally. No two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.  Determine if we can visit all the towns by traversing each of the roads exactly once.

Incorrect submission (verdict: Wrong Answer):
list1 =[]
total =0
for i in range(3):
  MM = input().split()
  a = int(MM[0])
  b = int(MM[1])
  list1.append(a)
  list1.append(b)
for i in range(5):
  x = list1.count(i)
  if x >2:
    total +=1
if total == 0:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
list1 =[]
total =0
for i in range(3):
  MM = input().split()
  a = int(MM[0])
  b = int(MM[1])
  list1.append(a)
  list1.append(b)
for i in range(5):
  x = list1.count(i)
  if x >2:
    total +=1
if total == 0:
  print('YES')
else:
  print('NO')
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
if s == list(set(s)):
  print("yes")
else:
  print("no")

Fixed, accepted submission:
s = list(input())
if len(s) == len(list(set(s))):
  print("yes")
else:
  print("no")
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))
A.sort(reverse=True)
print(A)
ans = 0
for i in range(N - 1):
    ans += A[i]
print(ans)

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))
A.sort(reverse=True)
# print(A)
ans = A[0]
if N >= 3:
    a = (N - 2) // 2
    b = (N - 2)  % 2
# print(a)
# print(b)
    if b == 0:
        for i in range(a):
            ans += (A[i+1] * 2)
    else:
        for i in range(a):
            ans += (A[i+1] * 2)
        ans += A[a+1]
print(ans)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
a = input()
b = input()

if a[0] == b[2] and a[1] == b[1] and b[0] == a[2]:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a = input()
b = input()

if a[0] == b[2] and a[1] == b[1] and b[0] == a[2]:
    print("YES")
else:
    print("NO")
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
hoge = int(input())
l = [int(i) for i in input().split()]

mx = max(l)
mn = min(l)
sm = sum(l)

print(mx,mn,sm)

Fixed, accepted submission:
hoge = int(input())
l = [int(i) for i in input().split()]

mn = min(l)
mx = max(l)
sm = sum(l)

print(mn,mx,sm)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map( int, input().split())

for i in range(1,101):
    if((a * i) % b == c):
        print('YES')
        exit()

    else:
        print('NO')
        exit()

Fixed, accepted submission:
a, b, c = map( int, input().split())

for i in range(1,101):
    if((a * i) % b == c):
        print('YES')
        exit()

else:
    print('NO')
    exit()
Problem:
Let's arrange a deck of cards. There are totally 36 cards of 4 suits(S, H, C, D) and 9 values (1, 2, ... 9). For example, 'eight of heart' is represented by H8 and 'one of diamonds' is represented by D1.  Your task is to write a program which sorts a given set of cards in ascending order by their values using the Bubble Sort algorithms and the Selection Sort algorithm respectively. These algorithms should be based on the following pseudocode:                 BubbleSort(C) 1 for i = 0 to C.length-1 2     for j = C.length-1 downto i+1 3         if C[j].value < C[j-1].value 4             swap C[j] and C[j-1]                 SelectionSort(C) 1 for i = 0 to C.length-1 2     mini = i 3     for j = i to C.length-1 4         if C[j].value < C[mini].value 5             mini = j 6     swap C[i] and C[mini]   Note that, indices for array elements are based on 0-origin.  For each algorithm, report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).

Incorrect submission (verdict: Wrong Answer):
def bubble_sort(A):
    for i in range(len(A)):
        for j in range(len(A) - 1, i, -1):
            if int(A[j][1]) < int(A[j - 1][1]):
                A[j], A[j - 1] = A[j - 1], A[j]
    return A


def selection_sort(A):
    n = len(A)
    for i in range(n):
        mini = i
        for j in range(i, n):
            if int(A[j][1]) < int(A[mini][1]):
                mini = j
        if mini != i:
            A[i], A[mini] = A[mini], A[i]
    return A

n = int(input())
A = input().split()
B = bubble_sort(A)
C = selection_sort(A)
print(B)
print('Stable')
print(C)
if B == C:
    print('Stable')
else:
    print('Not stable')



Fixed, accepted submission:
from copy import copy


def bubble_sort(org_A):
    A = copy(org_A)
    for i in range(len(A)):
        for j in range(len(A) - 1, i, -1):
            if int(A[j][1]) < int(A[j - 1][1]):
                A[j], A[j - 1] = A[j - 1], A[j]
    return A


def selection_sort(org_A):
    A = copy(org_A)
    n = len(A)
    for i in range(n):
        mini = i
        for j in range(i, n):
            if int(A[j][1]) < int(A[mini][1]):
                mini = j
        if mini != i:
            A[i], A[mini] = A[mini], A[i]
    return A

n = int(input())
A = input().split()
B = bubble_sort(A)
C = selection_sort(A)
print(' '.join(B))
print('Stable')
print(' '.join(C))
if B == C:
    print('Stable')
else:
    print('Not stable')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
import sys
import numpy as np
import math  
from collections import deque
from collections import defaultdict
from copy import deepcopy
from itertools import accumulate 
def input(): return sys.stdin.readline().rstrip()
from functools import lru_cache 

def main():
    n = int(input())
    print(n%1000)
    return 0

if __name__ == "__main__":
    main()

Fixed, accepted submission:
import sys
import numpy as np
import math  
from collections import deque
from collections import defaultdict
from copy import deepcopy
from itertools import accumulate 
def input(): return sys.stdin.readline().rstrip()
from functools import lru_cache 

def main():
    n = int(input())
    if n % 1000 == 0:
        print('0')
    else:
        print((n // 1000 + 1) * 1000 - n)
    return 0

if __name__ == "__main__":
    main()
Problem:
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).  The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Incorrect submission (verdict: Wrong Answer):
count = int(input())
cards = []
for i in range(count):
    cards.append(input())
capitals = "SHCD"
for j in capitals:
    for k in range(1,14):
        if (j + " " + str(k)) in cards == False:
            print(j + " " + str(k))


Fixed, accepted submission:
count = int(input())
cards = []
for i in range(count):
    cards.append(input())
capitals = "SHCD"
for j in capitals:
    for k in range(1,14):
        if ((j + " " + str(k)) in cards) == False:
            print(j + " " + str(k))
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
def BubbleSort(A,n):
    for i in range(n):
        for j in range(n-1,i,-1):
            if A[j] < A[j-1]:
                A[j], A[j-1] = A[j-1], A[j]
    return A

n = int(input())
A = [int(input()) for i in range(n)]

print (BubbleSort(A,n))

Fixed, accepted submission:
n = int(input())
 
numbers = list(map(int, input().split(" ")))
 
cnt = 0
 
for i in range(n):
    for j in range(n - 1, i, -1):
        if numbers[j] < numbers[j - 1]:
            numbers[j],numbers[j - 1] = numbers[j - 1], numbers[j]
            cnt += 1
 
numbers = map(str, numbers)
print(" ".join(numbers))
 
print(cnt)
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):

r, g, b = map(int, input().split())

answer = r * 100 + g * 10 + b

if answer % 4 == 0:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:

r, g, b = map(int, input().split())

answer = r * 100 + g * 10 + b

if answer % 4 == 0:
    print('YES')
else:
    print('NO')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
print(int(input())%1000)

Fixed, accepted submission:
N=int(input())%1000
print(0 if not(N) else 1000-N)
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
S = input()

import collections

c = collections.Counter(list(S))

ans = "yes"
for i in c.values():
    print(i)
    if i == 1:
        pass
    else:
        ans = "no"
        break

print(ans)

Fixed, accepted submission:
S = input()

import collections

c = collections.Counter(list(S))

ans = "yes"
for i in c.values():
    if i == 1:
        pass
    else:
        ans = "no"
        break

print(ans)