TnT/CodeNet4Repair huggingface dataset:
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
c=int(input())
x=int(input())
x_dash=x//50
cnt=0
for i in range(1,a+1):
  for j in range(1,b+1):
    k=x_dash-10*i-2*j
    if 0<=k<=c:
      cnt+=1
print(cnt)

Fixed, accepted submission:
a=int(input())
b=int(input())
c=int(input())
x=int(input())
x_dash=x//50
cnt=0
for i in range(0,a+1):
  for j in range(0,b+1):
    k=x_dash-10*i-2*j
    if 0<=k<=c:
      cnt+=1
print(cnt)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
A,B,K = map(int,input().split())
S = [i for i in range(A,B+1)]
S = S[:K]+S[len(S)-K:]
S = set(S)
for s in S: print(s)

Fixed, accepted submission:
A,B,K = map(int,input().split())
if 2*K<B-A+1:
    S = [i for i in range(A,A+K)]+[i for i in range(B-K+1,B+1)]
else:
    S = [i for i in range(A,B+1)]
for s in S:
    print(s)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s=list(str(input()))
t=list(str(input()))
alphabet=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
for i in range (len(s)):
    for j in range (len(alphabet)):
        if s[i]==alphabet[j]:
            s[i]=j
for i in range (len(t)):
    for j in range (len(alphabet)):
        if t[i]==alphabet[j]:
            t[i]=j
if len(s)>len(t):
    lst=[-1]*(len(s)-len(t))
    t=t+lst

if len(t)>len(s):
    lst=[-1]*(len(t)-len(s))
    s=s+lst
import sys
for i in range (len(s)):
    if min(s)<max(t):
        print ('Yes')
        print(s)
        print(t)
        sys.exit()
    elif min(s)>max(t):
        print ('No')
        print(s)
        print(t)
        sys.exit()
    else:
        if min(s)==max(t):
            s.remove(min(s))
            t.remove(max(t))
print ('No')

Fixed, accepted submission:
s=list(input())
t=list(input())
s.sort()
t.sort(reverse=True)
if s<t:
    print('Yes')
else:
    print('No')
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
import itertools
num = str(input())

olist = [int(i+1) for i in range(len(num)-1)]
comblist = []
for i, _ in enumerate(olist, 1):     
    for j in itertools.combinations(olist, r=i):
        comblist.append(j)

L = []
for i in range(len(comblist)):
  t = num
  for j in range(len(comblist[i])):
    t = t[0:comblist[i][j]+j] + "," + t[comblist[i][j]+j:]
  L.append(t)

out = 0
for i in range(len(L)):
  t = L[i].split(",")
  for j in range(len(t)):
    out += int(t[j])
print(out+int(num))

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())

print((a+b)*h//2)
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
W,H,N=map(int,input().split())
A=np.zeros((W,H))
B=[list(map(int,input().split())) for _ in range(N)]
print(B)
for b in B:
    if b[2]==1:
        A[:b[0],:]=1
    elif b[2]==2:
        A[b[0]:,:]=1
    elif b[2]==3:
        A[:,:b[1]]=1
    elif b[2]==4:
        A[:,b[1]:]=1
    print(A)
print(np.count_nonzero(A==0))

Fixed, accepted submission:
import numpy as np
W,H,N=map(int,input().split())
A=np.zeros((W,H))
B=[list(map(int,input().split())) for _ in range(N)]
for b in B:
    if b[2]==1:
        A[:b[0],:]=1
    elif b[2]==2:
        A[b[0]:,:]=1
    elif b[2]==3:
        A[:,:b[1]]=1
    elif b[2]==4:
        A[:,b[1]:]=1
print(np.count_nonzero(A==0))
Problem:
恒星歴 2005.11.5。あなたは宇宙船 UAZ アドバンス号の艦長として敵の宇宙船と交戦しようとしています。 幸い敵の宇宙船はまだこちらに気付かずに静止しています。また、すでに敵の宇宙座標は判明しており強力な直線のビームを放つ「フェザー砲」は発射準備を完了しています。あとは、発射命令を出すばかりです。  ところが、宇宙空間には、敵の設置したエネルギーバリアが存在しています。バリアは三角形をしており「フェザー砲」のビームをはね返してしまいます。また、ビームがバリアに当たれば敵に気付かれて逃げられてしまいます。事前に命中すると判定できなければ、発射命令は出せません。  そこで、UAZ アドバンス号、敵、バリアの位置の宇宙座標(3次元座標 x, y, z) を入力して、ビームがバリアをさけて敵に命中する場合は "HIT"、バリアに当たってしまう場合"MISS"と出力するプログラムを作成してください。  ただし、バリアはアドバンス号から 3 角形に見えるものだけが対象であり、線分につぶれて見えるものはないものとします。また、バリアは 3 角形の頂点を含む境界でも有効であり、ビームをはね返すものとします。また、敵がバリア内にいる場合は"MISS"と出力して下さい。

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/python
from fractions import Fraction
import sys
if sys.version_info[0]>=3: raw_input=input

def gauss(a):
	if not a or len(a)==0: return None
	n=len(a)
	for i in range(n):
		if a[i][i]==0:
			for j in range(i+1,n):
				if a[j][i]!=0:
					for k in range(i,n+1): a[i][k]+=a[j][k]
					break
			else:
				return None
		for j in range(n):
			if i!=j:
				r = Fraction(a[j][i],a[i][i])
				for k in range(i,n+1): a[j][k] = a[j][k] - a[i][k]*r
	for i in range(n):
		x=Fraction(a[i][i],1)
		for j in range(len(a[i])):
			a[i][j] /= x
	return a

uaz=map(int,raw_input().split())
enemy=[0]+[-x+y for x,y in zip(map(int,raw_input().split()),uaz)]
b0=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
b1=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
b2=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
sol=gauss(list(map(list,zip(b0,b1,b2,enemy,[1,0,0,0]))))
print('MISS' if sol and all(0<=e[-1]<=1 for e in sol) else 'HIT')

Fixed, accepted submission:
#!/usr/bin/python
from fractions import Fraction
import sys
if sys.version_info[0]>=3: raw_input=input

def gauss(a):
	if not a or len(a)==0: return None
	n=len(a)
	for i in range(n):
		if a[i][i]==0:
			for j in range(i+1,n):
				if a[j][i]!=0:
					for k in range(i,n+1): a[i][k]+=a[j][k]
					break
			else:
				return None
		for j in range(n):
			if i!=j:
				r = Fraction(a[j][i],a[i][i])
				for k in range(i,n+1): a[j][k] = a[j][k] - a[i][k]*r
	for i in range(n):
		x=Fraction(a[i][i],1)
		for j in range(len(a[i])):
			a[i][j] /= x
	return a

uaz=list(map(int,raw_input().split()))
enemy=[0]+[-x+y for x,y in zip(map(int,raw_input().split()),uaz)]
b0=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
b1=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
b2=[1]+[x-y for x,y in zip(map(int,raw_input().split()),uaz)]
sol=gauss(list(map(list,zip(b0,b1,b2,enemy,[1,0,0,0]))))
print('MISS' if sol and all(0<=e[-1]<=1 for e in sol) else 'HIT')
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
input_list = list(input().split())
bill_num = int(input_list[0])
total_price = int(input_list[1])

yen_10000 = 10000
yen_5000 = 5000
yen_1000 = 1000
bill_num_list = []

for i in range(bill_num):
    for j in range(bill_num):
        for k in range(bill_num):
            if total_price == (i+1) * yen_10000 + (j+1) * yen_5000 + (k+1) * yen_1000:
                bill_num_list = [i+1, j+1, k+1]
                bill_num_list_str = list(map(str, bill_num_list))
                break

if bill_num_list == []:
    print('-1 -1 -1')
else:
    print(' '.join(bill_num_list_str))


Fixed, accepted submission:
input_list = list(input().split())
bill_num = int(input_list[0])
total_price = int(input_list[1])

yen_10000 = 10000
yen_5000 = 5000
yen_1000 = 1000
bill_num_list = []

for i in range(bill_num + 1):
    for j in range(bill_num - i + 1):
        k = 0
        k = bill_num - i - j
        total = i * yen_10000 + j * yen_5000 + k * yen_1000
        if  (i + j + k == bill_num) and (k >= 0) and (total == total_price):
            bill_num_list = [i, j, k]
            bill_num_list_str = list(map(str, bill_num_list))
            break

if bill_num_list == []:
    print('-1 -1 -1')
else:
    print(' '.join(bill_num_list_str))
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
import sys

if sys.platform =='ios':
    sys.stdin=open('input_file.txt')


S=input()

if sorted(S)=="abc":
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
import sys

if sys.platform =='ios':
    sys.stdin=open('input_file.txt')


S=input()

if sorted(S)==["a","b","c"]:
	print("Yes")
else:
	print("No")
Problem:
We will call a string that can be obtained by concatenating two equal strings an _even_ string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.  You are given an even string S consisting of lowercase English letters. Find the length of the longest even string that can be obtained by deleting one or more characters from the end of S. It is guaranteed that such a non-empty string exists for a given input.

Incorrect submission (verdict: Wrong Answer):
A= [i for i in input()]
while True:
    A.pop()
    A.pop()
    B=len(A)//2
    if A[:B]==A[B+1:]:
        print(len(A))
        break

Fixed, accepted submission:
A= list(input())
while True:
    A.pop()
    A.pop()
    B=len(A)//2
    if A[:B]==A[B:]:
        print(len(A))
        break
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
k=int(input())
ans=1
j=0
while ans<k or j<n:
  ans*=2
  j+=1
if j<n:
  print(ans+k*(n-j))
else:
  print(ans)

Fixed, accepted submission:
n=int(input())
k=int(input())
ans=1
j=0
while ans<k and j<n:
  ans*=2
  j+=1
if j<n:
  print(ans+k*(n-j))
else:
  print(ans)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=a
while b==0:
  a+=a-1
  b-=1
  


Fixed, accepted submission:
a=int(input())
c=0
while a>=0:
  c+=a
  a=a-1
print(int(c))
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
ar = input().split(" ")
f = 0
s = 0
for a in ar:
  if a == "5":
    f += 1
  elif a == "7":
    s += 1
if f == 5 and s == 1:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
ar = input().split(" ")
f = 0
s = 0
for a in ar:
  if a == "5":
    f += 1
  elif a == "7":
    s += 1
if f == 2 and s == 1:
  print("YES")
else:
  print("NO")
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=list(map(int,input().split()))
ans=0
for i in range(N):
  if i%2==0 and A[i]%2==0:
    ans+=1
print(ans)

Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))
ans=0
for i in range(N):
  if i%2==0 and A[i]%2==1:
    ans+=1
print(ans)
Problem:
It is September 9 in Japan now.  You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Incorrect submission (verdict: Wrong Answer):
N = input()
# print(N.find("9"))
if N.find("9") != -1:
    print("Yse")
else:
    print("No")

Fixed, accepted submission:
N = input()
if N.find("9") != -1:
    print("Yes")
else:
    print("No")
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s.count("R") > s.count("B"):
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
n = int(input())
s = input()
if s.count("R") > s.count("B"):
  print("Yes")
else:
  print("No")
Problem:
You are given a string S consisting of lowercase English letters. We will write down this string, starting a new line after every w letters. Print the string obtained by concatenating the letters at the beginnings of these lines from top to bottom.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
w = int(input())
index = 0
l = []
while index <= len(s) - 1:
  print(index)
  l.append(s[index])
  index += w
print(*l, sep="")

Fixed, accepted submission:
s = list(input())
w = int(input())
index = 0
l = []
while index <= len(s) - 1:
  l.append(s[index])
  index += w
print(*l, sep="")
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
S = input()
T = input()
lenS = len(S)
lenT = len(T)

for i in range(lenS - lenT, -1, -1):
    flag = True
    for ii in range(lenT):
        if S[i+ii] == '?' or S[i+ii] == T[ii]:
            continue
        else:
            flag = False
            break
    if flag == True:
        print((S[:ii] + T + S[ii + lenT:]).replace('?', 'a'))
        exit()
print('UNRESTORABLE')


Fixed, accepted submission:
def is_possible(start_i):
    for i in range(lenT):
        if S[start_i + i] != '?' and S[start_i + i] != T[i]:
            return False
    return True


if __name__ == '__main__':
    S = input()
    T = input()
    lenS = len(S)
    lenT = len(T)
    tmp_i = None
    for i in range(lenS):
        if i + lenT > lenS:
            break
        else:
            if is_possible(i):
                tmp_i = i

    if tmp_i is None:
        print('UNRESTORABLE')
    else:
        print(S[:tmp_i].replace('?', 'a') + T + S[tmp_i + lenT:].replace('?', 'a'))
Problem:
Print the K-th element of the following sequence of length 32:                1, 1, 1, 2, 1, 2, 1, 5, 2, 2, 1, 5, 1, 2, 1, 14, 1, 5, 1, 5, 2, 2, 1, 15, 2, 2, 5, 4, 1, 4, 1, 51

Incorrect submission (verdict: Wrong Answer):
a = int(input())
if a%2==0 and (a!=25 or a!=27):
    print(1)
elif a==32:
    print(51)
elif a==24:
    print(15)
elif a==16:
    print(14)
elif a==28 or a==30:
    print(4)
elif (a!=4 and a%4==0) or a==18 or a==27:
    print(5)
else:
    print(2)

Fixed, accepted submission:
a = int(input())
if (a%2==1 and (a!=25 and a!=27 and a!=9 and a!=21)) or a==2:
    print(1)
elif a==32:
    print(51)
elif a==24:
    print(15)
elif a==16:
    print(14)
elif a==28 or a==30:
    print(4)
elif (a!=4 and a%4==0) or a==18 or a==27:
    print(5)
else:
    print(2)
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
K = int(input())
ans = 1
for i in range(N):
    ans = min(ans+K,2*ans)
print(min)

Fixed, accepted submission:
N = int(input())
K = int(input())
ans = 1
for i in range(N):
    ans = min(ans+K,2*ans)
print(ans)
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
X = int(input())
ans = 0
if X == 1:
	ans = 1
else:
  for b in range(1, 32):
    for p in range(2, 11):
      ans = max(ans, pow(b, p))
print(ans)

Fixed, accepted submission:
X = int(input())
ans = 1
if X > 1:
  for b in range(1, 32):
    for p in range(2, 11):
      if ans <= X and pow(b, p) <= X:
      	ans = max(ans, pow(b, p))
print(ans)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
dataset = input().split("\n")
c = 1
for i in dataset :
    print("Case " + str(c) + ":" + " " + str(i))
    c = c + 1

Fixed, accepted submission:
import sys
c = 1
for i in sys.stdin.readlines() :
    if i.strip() == "0" :
        break
    else :
        print("Case " + str(c) + ":" + " " + str(i.strip()))
        c = c + 1
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = input()
r = [None] * (n + 1)
for i in range(n, 0, -1):
    r[i] = (ord(a[2 * i - 2]) + sum(r[i * 2::i])) % 2
ans = []
for i, x in enumerate(r):
    if x:
        ans.append(i)
print(r.count(1))
print(ans)

Fixed, accepted submission:
n = int(input())
a = input()
r = [None] * (n + 1)
for i in range(n, 0, -1):
    r[i] = (ord(a[2 * i - 2]) + sum(r[i * 2::i])) % 2
print(r.count(1))
print(*(i for i, x in enumerate(r) if x))
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))

mn = 10**9
for i in range(N):
  cost = 0
  for j in range(N):
    cost += (A[i]-A[j])**2
  mn = min(cost, mn)
print(mn)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))

ans = float('INF')
for i in range(min(a), max(a)+1):
    cost = 0
    for aa in a:
        cost += (i - aa)**2
    if cost < ans :
        ans = cost
print(ans)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
A, B = tuple(int(num) for num in input().split())
S = input()

s_list = list(S)
  

for i, s in enumerate(s_list):
  if s_list[A] != '-':
    print('No')
    break
  if isinstance(s, int):
    continue
  else:
    print('No')
    break
else:
  print('Yes')

Fixed, accepted submission:
A, B = tuple(int(num) for num in input().split())
S = input()

s_list = list(S)
  
for i, s in enumerate(s_list):
  if i == A:
    if s_list[A] != '-':
      print('No')
      break
  else:
    try:
      s = int(s)
    except:
      print('No')
      break
else:
  print('Yes')
Problem:
Write a program to simulate rolling a dice, which can be constructed by the following net.                  As shown in the figures, each face is identified by a different label from 1 to 6.  Write a program which reads integers assigned to each face identified by the label and a sequence of commands to roll the dice, and prints the integer on the top face. At the initial state, the dice is located as shown in the above figures.

Incorrect submission (verdict: Wrong Answer):
class Dice:
  def __init__(self):
    self.top = 1
    self.front = 2
    self.left = 3

  @property
  def bottom(self):
    return 7 - self.top

  @property
  def back(self):
    return 7 - self.front

  @property
  def right(self):
    return 7 - self.left

  def move(self, direction):
    if direction == 'N':
      bottom = self.bottom
      self.top = self.front
      self.front = bottom
    elif direction == 'W':
      right = self.right
      self.left = self.top
      self.top = right
    elif direction == 'E':
      bottom = self.bottom
      self.top = self.left
      self.left = bottom
    elif direction == 'S':
      back = self.back
      self.front = self.top
      self.top = back


dice = Dice()
numbers = input().split()
for cmd in input():
  dice.move(cmd)
print(numbers[dice.top - 1])

Fixed, accepted submission:
class Dice:
  def __init__(self):
    self.top = 1
    self.front = 2
    self.left = 4

  @property
  def bottom(self):
    return 7 - self.top

  @property
  def back(self):
    return 7 - self.front

  @property
  def right(self):
    return 7 - self.left

  def move(self, direction):
    if direction == 'N':
      bottom = self.bottom
      self.top = self.front
      self.front = bottom
    elif direction == 'W':
      right = self.right
      self.left = self.top
      self.top = right
    elif direction == 'E':
      bottom = self.bottom
      self.top = self.left
      self.left = bottom
    elif direction == 'S':
      back = self.back
      self.front = self.top
      self.top = back

  def __repr__(self):
    print(self.__dict__)

dice = Dice()
numbers = input().split()
for cmd in input():
  dice.move(cmd)
print(numbers[dice.top - 1])