TnT/CodeNet4Repair huggingface dataset:
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
n,m=list(map(int,input().split()))
road_input=[]
for i in range(m):
    road_input.append(list(map(int,input().split())))


road=[[] for i in range(n+1)]
for i in range(m):
    road[road_input[i][0]].append(road_input[i][1])
    road[road_input[i][1]].append(road_input[i][0])

from collections import deque
q=deque([1])
ans=[-1 for i in range(n)]
print(ans)
while len(q)>0:
  p=q.popleft()
  for i in road[p]:
    if ans[i-1]== -1:
      ans[i-1]=p
      q.append(i)

print("Yes")
for j in range(1,n):
    print(ans[j])


Fixed, accepted submission:
n,m=list(map(int,input().split()))
road=[[] for i in range(n)]

for i in range(m):
  a,b=list(map(int,input().split()))
  road[a-1].append(b)
  road[b-1].append(a)
from collections import deque
q=deque([1])
check=[0 for i in range(n)]
check[0]=1
ans=[0 for i in range(n)]
while len(q)>0:
  p=q.popleft()
  for i in range(len(road[p-1])):
    if check[road[p-1][i]-1]==0:
      q.append(road[p-1][i])
      check[road[p-1][i]-1]=1
      ans[road[p-1][i]-1]=p
      
      
print("Yes")
for i in range(1,n):
  print(ans[i])
Problem:
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.

Incorrect submission (verdict: Wrong Answer):
x=int(input())
for i in range(-100,100):
  for j in range(-100,100):
    if x==(i**5-j**5):
      print(i,j)
      break

Fixed, accepted submission:
x=int(input())
for i in range(-200,200):
  for j in range(-200,200):
    if x==(i**5-j**5):
      a=i
      b=j
      break
print(a,b)
Problem:
You are given an integer sequence of length N, a_1,a_2,...,a_N.  For each 1≤i≤N, you have three choices: add 1 to a_i, subtract 1 from a_i or do nothing.  After these operations, you select an integer X and count the number of i such that a_i=X.  Maximize this count by making optimal choices.

Incorrect submission (verdict: Wrong Answer):
import collections
N = int(input())
L = list(map(int,input().split()))
C = collections.Counter(L)
print(C)

Fixed, accepted submission:


N = int(input())
A = list(map(int,input().split()))
cnt = [0]*(10**5+2)
for i in A:
    cnt[i]+=1
    cnt[i+1]+=1
    cnt[i+2]+=1
    
print(max(cnt))
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
s = input()
a = s.find('A')
b = s.rfind('B')
print(b-a+1)

Fixed, accepted submission:
s = input()
a = s.find('A')
b = s.rfind('Z')
print(b-a+1)
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
A, B = input().split()
A = float(A)
B = float(B)
ans = int(A * B)
print(A * B)

Fixed, accepted submission:
from decimal import Decimal

A, B = input().split()
ans = int(Decimal(A) * Decimal(B))

print(ans)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split( ))
if x-a>=b:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
a,b,x=map(int,input().split( ))
if x-a>=0 and x-a<=b:
    print('YES')
else:
    print('NO')
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,n=list(map(int,input().split()))
print(b/n-~-a/n)

Fixed, accepted submission:
a,b,n=map(int,input().split())
print(b//n-~-a//n)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())

print(0.5*N*(N+1))

Fixed, accepted submission:
N=int(input())

print(int(0.5*N*(N+1)))
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
n = int(input())
l=list(map(int ,input().split()))
cnt=0
while True:
    for i in range(n):
        if l[i]%2==0:
            l[i]==l[i]//2
        else:
            print(cnt)
            exit()     
    cnt+=1

Fixed, accepted submission:
n = int(input())
l=list(map(int ,input().split()))
count=0
while True:
    for i in range(n):
        if l[i]%2==0:
            l[i]=l[i]//2
        else:
            print(count)
            exit()
    count+=1
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
print("A{}C".format(input().split()[1]))

Fixed, accepted submission:
print("A%cC"%input().split()[1][0])
Problem:
In this problem, we use the 24-hour clock.  Takahashi gets up exactly at the time H_1 : M_1 and goes to bed exactly at the time H_2 : M_2. (See Sample Inputs below for clarity.) He has decided to study for K consecutive minutes while he is up. What is the length of the period in which he can start studying?

Incorrect submission (verdict: Wrong Answer):
h1, m1, h2, m2, k = map(int, input().split())

time = (h1 * 60 + m1) - (h2 * 60 + m2)

print(time - k)

Fixed, accepted submission:
h1, m1, h2, m2, k = map(int, input().split())

time = (h2 * 60 + m2) - (h1 * 60 + m1)

print(time - k)
Problem:
Write a program which calculates the area and perimeter of a given rectangle.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
print(a,b)
c=int(a)*int(b)
d=2*(a+b)
print(c,d)


Fixed, accepted submission:
a,b=map(int,input().split())
print(a*b,2*(a+b))
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n * (n + 1) / 2)

Fixed, accepted submission:
n = int(input())

ans = 0
for i in range(1, n + 1):
    ans += i

print(ans)
Problem:
On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).  A red point and a blue point can form a _friendly pair_ when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.  At most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

reds = []
for i in range(N):
    a, b = map(int, input().split())
    reds.append([a,b])
reds.sort(key=lambda x: x[1], reverse=True)

blues = []
for i in range(N):
    c, d = map(int, input().split())
    blues.append([c,d])
blues.sort()

flag = [False for i in range(N)]
ans = 0
for i in range(N):
    c, d = blues[i][0], blues[i][1]
    for j in range(N):
        if flag[j] == True:
            continue
        a, b = reds[i][0], reds[i][1]
        if c>a and d>b:
            flag[j] = True
            ans += 1
print(ans)


Fixed, accepted submission:
N = int(input())

reds = []
for i in range(N):
    a, b = map(int, input().split())
    reds.append([a,b])
reds.sort(key=lambda x: x[1], reverse=True)

blues = []
for i in range(N):
    c, d = map(int, input().split())
    blues.append([c,d])
blues.sort()

flag = [False for i in range(N)]
ans = 0
for i in range(N):
    c, d = blues[i][0], blues[i][1]
    for j in range(N):
        if flag[j] == True:
            continue
        a, b = reds[j][0], reds[j][1]
        if c>a and d>b:
            flag[j] = True
            ans += 1
            break
print(ans)
Problem:
Snuke has an empty sequence a.  He will perform N operations on this sequence.  In the i-th operation, he chooses an integer j satisfying 1 \leq j \leq i, and insert j at position j in a (the beginning is position 1).  You are given a sequence b of length N. Determine if it is possible that a is equal to b after N operations. If it is, show one possible sequence of operations that achieves it.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
b = list(map(int, input().split()))
ans = []
queue = []

if 1 not in b:
    print(-1)
else:
    start = N
    for i in range(N-1, -1, -1):
        if b[i] == 1:
            queue.append(b[i:start])
            start = i

    for a in queue:
        flag = True
        for i in range(len(a)):
            if a[i] <= i+1:
                pass
            else:
                flag = False
                ans = [-1]
                break
        if not flag:
            break

        ans.append(1)
        next_pass = False
        for i in range(len(a)-1, 0, -1):
            if not next_pass:
                if a[i-1] <= a[i]:
                    ans.extend([a[i-1], a[i]])
                    next_pass = True
                else:
                    ans.append(a[i])
            else:
                next_pass = False

    for a in ans:
        print(a)

Fixed, accepted submission:
N = int(input())
b = list(map(int, input().split()))

ans = [None] * N

for i in range(N):
    for j in range(len(b), -1, -1):
        if b[j-1] == j:
            ans[i] = b.pop(j-1)
            break
    else: break

if not b: 
    for a in ans[::-1]: print(a)
else: print(-1)
Problem:
Two students of AtCoder Kindergarten are fighting over candy packs.  There are three candy packs, each of which contains a, b, and c candies, respectively.  Teacher Evi is trying to distribute the packs between the two students so that each student gets the same number of candies. Determine whether it is possible.  Note that Evi cannot take candies out of the packs, and the whole contents of each pack must be given to one of the students.

Incorrect submission (verdict: Wrong Answer):
print("Yes" if (lambda x: x[0] == sum(x[1:]) or sum(x[0:2]) == x[2])([int(i) for i in input().split()]) else "No")

Fixed, accepted submission:
print("Yes" if (lambda x: x[0] == sum(x[1:]) or sum(x[0:2]) == x[2])(sorted([int(i) for i in input().split()])) else "No")
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
x = [i for i in input().rsplit('\n')]
money = []
unit = []
for i in x[1:]:
    m, u = i.split()
    money.append(float(m))
    unit.append(u)

total = 0
for m, u in zip(money, unit):
    if u == 'JPY':
        total += m
    else:
        total += 380000*m

print(total)

Fixed, accepted submission:
n = int(input())
money = []
unit = []
for i in range(n):
    m, u = input().split()
    money.append(float(m))
    unit.append(u)

total = 0.0
for m, u in zip(money, unit):
    if u == 'JPY':
        total += m
    else:
        total += 380000.0*m
print(total)
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
n=int(input())

d=[]
print('n=',n)
for i in range(n):
    d.append(int(input()))

k=0


for i in range(n-1):
    print('i =',i)
    for j in range(i+1,n):
        if d[i]==d[j]:
            j -= 1
            break
    print('j =',j)
    if j == n-1:
        k += 1
k += 1

print('k =',k)

Fixed, accepted submission:
n=int(input())

d=[]

for i in range(n):
    d.append(int(input()))

k=0


for i in range(n-1):

    for j in range(i+1,n):
        if d[i]==d[j]:
            j -= 1
            break

    if j == n-1:
        k += 1
k += 1

print(k)
Problem:
For an integer n not less than 0, let us define f(n) as follows:    * f(n) = 1 (if n < 2)   * f(n) = n f(n-2) (if n \geq 2)  Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if n%2 != 0:
    print(0)
else:
    c = 0
    k = 1
    while n >= 2:
        if n%10 == 0:
            c += int(str(n)[0])
            if n % 5 == 0:
                c += 1
        n //= 10
    print(c)


Fixed, accepted submission:
 

def findTrailingZeros(n): 
      
    # Initialize result 
    count = 0
  
    # Keep dividing n by 
    # powers of 5 and 
    # update Count 
    i=10
    while (n/i>0): 
        count += n//i 
        i *= 5
  
    return int(count) 

n = int(input())
if n%2 != 0:
    print(0)
else:
    print(findTrailingZeros(n))
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
_, k, *x = map(int, open(0).read().split())
print(sum(min(i, k-i) for i in x)*2)

Fixed, accepted submission:
print(int(input())**2-int(input()))
Problem:
You have an integer variable x. Initially, x=0.  Some person gave you a string S of length N, and using the string you performed the following operation N times. In the i-th operation, you incremented the value of x by 1 if S_i=`I`, and decremented the value of x by 1 if S_i=`D`.  Find the maximum value taken by x during the operations (including before the first operation, and after the last operation).

Incorrect submission (verdict: Wrong Answer):
N=int(input())
S=input()
ans = 0
for c in S:
    if c == "I":
        ans += 1
    else:
        ans -= 1
print(ans)

Fixed, accepted submission:
input()
m=0
x=0
for c in input():
    if c == "I":
        x += 1
    else:
        x -= 1
    m = max(x,m)
print(m)
Problem:
Snuke has N sticks. The length of the i-th stick is l_i.  Snuke is making a snake toy by joining K of the sticks together.  The length of the toy is represented by the sum of the individual sticks that compose it. Find the maximum possible length of the toy.

Incorrect submission (verdict: Wrong Answer):
a,b=list(map(int,input().split()))
c=list(int(i) for i in input().split())  
c.sort(reverse=True)
print(c)
count=0
for i in range(b):
    count+=c[i]
print(count)

Fixed, accepted submission:
a,b=list(map(int,input().split()))
c=list(int(i) for i in input().split())  
c.sort(reverse=True)
count=0
for i in range(b):
    count+=c[i]
print(count)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
h,w = map(int, input().split())
l=[]
for i in range(h):
    l.append(list(input().split()))
for i in range(h):
    print(l[i])
    print(l[i])

Fixed, accepted submission:
h,w = map(int, input().split())
l=[]
for i in range(h):
    l.append(list(input().split())*2)

for i in range(h):
    for j in range(2):
        print(l[i][j])
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def Insertion_Sort(A, N):
    A = list(map(int, A.split()))
    for i in range(1,N):
        v = A[i]  
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v
        print(" ".join(map(str,A)))

N = int(input())
A = input()
Insertion_Sort(A, N)


Fixed, accepted submission:
def Insertion_Sort(A, N):
    print(A)
    A = list(map(int, A.split()))
    for i in range(1,N):
        v = A[i]  
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v
        print(" ".join(map(str,A)))

N = int(input())
A = input()
Insertion_Sort(A, N)
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
S = input()
win_no = 0
for match in S:
    if match == "o":
        win_no += 1
    
if win_no + 15 - len(S)>= 8:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
S = input()
win_no = 0
for match in S:
    if match == "o":
        win_no += 1
    
if win_no + 15 - len(S)>= 8:
    print("YES")
else:
    print("NO")
Problem:
Your task is to perform a simple table calculation.  Write a program which reads the number of rows r, columns c and a table of r × c elements, and prints a new table, which includes the total sum for each row and column.

Incorrect submission (verdict: Wrong Answer):
r, c = map(int, input().split())
matrix = []
for i in range(r):
    l = list(map(int, input().split()))
    l.append(sum(l))
    matrix.append(l)
print(list(zip(*matrix)))
matrix.append([sum(i) for i in zip(*matrix)])
print(matrix)

Fixed, accepted submission:
r, c = map(int, input().split())
matrix = []
for i in range(r):
    l = list(map(int, input().split()))
    l.append(sum(l))
    matrix.append(l)
matrix.append([sum(i) for i in zip(*matrix)])
for l in matrix:
    print(" ".join(str(n) for n in l))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
x=int(input())
if(x&1000==0):
  print(0)
else:
  print(x%1000)

Fixed, accepted submission:
x=int(input())
if(x%1000==0):
    print(0)
else:
    print(1000-x%1000)
Problem:
Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier. He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.  Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.  Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.  Write a program that outputs `delicious` if he found it delicious, `safe` if he did not found it delicious but did not get a stomachache either, and `dangerous` if he got a stomachache.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())

if b - a <= x:
  print('delicious')
else:
  print('dangerous')

Fixed, accepted submission:
x, a, b = map(int, input().split())

if b - a > x:
  print('dangerous')
elif b - a > 0:
  print('safe')
else:
  print('delicious')
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
n = input()
num = list(map(int,input().split()))
print(num)
# mul = int(input().split())
cnt = 0
for i in range(len(num)):
    if(i % 2 != 0 and num[i] %2 != 0):
        cnt += 1
print(cnt)

Fixed, accepted submission:
if __name__ == "__main__":
    n = int(input())
    num = list(map(int,input().split()))
    # print(type(num[0]))
    cnt = 0
    for i in range(1,n+1):
        # print(i,num[i-1])
        if(num[i-1] % 2 != 0 and i % 2 != 0):
            cnt += 1
    print(cnt)