TnT/CodeNet4Repair huggingface dataset:
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
print("YES" if input().count("x") >= 8 else "NO")

Fixed, accepted submission:
print("YES" if input().count("x") < 8 else "NO")
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a, b = map(int,input().split())
if a >= b:
    print(a-1)
else:
    print(a)


Fixed, accepted submission:
a, b = map(int,input().split())
if a > b:
    print(a-1)
else:
    print(a)
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
k=int(input())
a=int(input())
b=int(input())
print(min(n-k,k)*a+max(0,n-k)*b)

Fixed, accepted submission:
n=int(input())
k=int(input())
a=int(input())
b=int(input())
print(min(n,k)*a+max(0,n-k)*b)
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
# your code goes here
x,y,z = map(int,input().split())

if x + y <= z:
	print('Yes')
else:
	print('No')

Fixed, accepted submission:
# your code goes here
x,y,z = map(int,input().split())

if x + y >= z:
	print('Yes')
else:
	print('No')
Problem:
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.  Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.  Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.

Incorrect submission (verdict: Wrong Answer):
a, b, c, d = map(int, input().split())
left = a + b
right = c + d
if left < right:
    print('Left')
elif left > right:
    print('Right')
else:
    print('Balanced')


Fixed, accepted submission:
a, b, c, d = map(int, input().split())
left = a + b
right = c + d
if left > right:
    print('Left')
elif left < right:
    print('Right')
else:
    print('Balanced')
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
sorted(a, reverse=True)
alice = 0
bob = 0
flag_alice = True
for num in a:
    print(num)
    if flag_alice:
        alice += num
        flag_alice = False
    else:
        bob += num
        flag_alice = True
print(alice - bob)


Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
a.sort(reverse=True)
alice = 0
bob = 0
flag_alice = True
for num in a:
    if flag_alice:
        alice += num
        flag_alice = False
    else:
        bob += num
        flag_alice = True
print(alice - bob)
Problem:
We have a sequence of N integers A~=~A_0,~A_1,~...,~A_{N - 1}.  Let B be a sequence of K \times N integers obtained by concatenating K copies of A. For example, if A~=~1,~3,~2 and K~=~2, B~=~1,~3,~2,~1,~3,~2.  Find the inversion number of B, modulo 10^9 + 7.  Here the inversion number of B is defined as the number of ordered pairs of integers (i,~j)~(0 \leq i < j \leq K \times N - 1) such that B_i > B_j.

Incorrect submission (verdict: Wrong Answer):
import sys

if sys.platform =='ios':
    sys.stdin=open('input_file.txt')
    
N,K=map(int,input().split())
l=list(map(int,input().split()))

cnt=0
cntt=0
p=10**9+7
for i in range(N):
	for j in range(N):
		if l[i]>l[j] and j>i:
			cnt+=1
for k in range(N):
	for m in range(N):
		if l[k]>l[m] and k>m:
			cntt+=1
Cn=cntt*int((K-1)*K/2)%p+int(K*(K+1)/2)*cnt%p
print(cnt,cntt)
print(Cn%p)

Fixed, accepted submission:
import sys

if sys.platform =='ios':
    sys.stdin=open('input_file.txt')
    
N,K=map(int,input().split())
l=list(map(int,input().split()))

cnt=0
cnt2=0
p=10**9+7
for i in range(N):
	for j in range(N):
		if l[i]>l[j] and j>i:
			cnt+=1
for k in range(N):
	for m in range(N):
		if l[k]>l[m] and k>m:
			cnt2+=1
Cn=K*(K+1)//2*cnt+(K-1)*K//2*cnt2
print(Cn%p)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

a = int(input())
b = a % 1000

print(b)

Fixed, accepted submission:
# -*- coding: utf-8 -*-

a = int(input())
b = a // 1000

if a % 1000 == 0:
    print(0)
else:
    print(1000*(b+1) - a)
Problem:
There are N stones arranged in a row. Every stone is painted white or black. A string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is `.`, and the stone is black if the character is `#`.  Takahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone. Find the minimum number of stones that needs to be recolored.

Incorrect submission (verdict: Wrong Answer):
import sys
sys.setrecursionlimit(20000000)
input = sys.stdin.readline
mod = 10**9 + 7
n = int(input())
s = input().rsplit()[0]
print(s)
kuro = 0
siro = 0
ans = 0
syo = 0
while syo < n and s[syo] == ".":
    syo += 1
for i in range(syo,n):
    if s[i] == "#":
        if siro:
            ans += min(siro,kuro)
            siro = 0
            kuro = 1
        else:
            kuro += 1
    else:
        siro += 1
ans += min(siro,kuro)
print(ans)

Fixed, accepted submission:
import sys
sys.setrecursionlimit(20000000)
input = sys.stdin.readline
mod = 10**9 + 7
n = int(input())
s = input().rsplit()[0]
kuro = [0]*n
siro = [0]*n
for i in range(n):
    if s[i] == "#":
        siro[i]+=1
    if s[-i-1] == ".":
        kuro[-i-1] += 1
    siro[i] += siro[i-1]
    kuro[-i-1] += kuro[-i]
ans = min(kuro[0],siro[-1])
for i in range(1,n):
    ans = min(ans,siro[i-1]+kuro[i])
print(ans)
Problem:
Fennec and Snuke are playing a board game.  On the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.  Initially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored. Fennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell. More specifically, each player performs the following action in her/his turn:    * Fennec: selects an uncolored cell that is adjacent to a **black** cell, and paints it **black**.   * Snuke: selects an uncolored cell that is adjacent to a **white** cell, and paints it **white**.  A player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.

Incorrect submission (verdict: Wrong Answer):
from collections import deque
from copy import deepcopy
N = int( input())
Path = [ [] for _ in range(N)]
for _ in range(N-1):
    a, b = map( int, input().split())
    a, b = a-1, b-1
    Path[a].append(b)
    Path[b].append(a)
Mass = [-1 for _ in range(N)]
F = deque([0])
S = deque([N-1])
while len(F) != 0 or len(S) != 0:
    KF = deque([])
    while len(F) != 0:
        f = F.pop()
        for x in Path[f]:
            if Mass[x] == -1:
                Mass[x] = 1
                KF.append(x)
    F = deepcopy(KF)
    KS = deque([])
    while len(S) != 0:
        s = S.pop()
        for y in Path[s]:
            if Mass[y] == -1:
                Mass[y] = 0
                KS.append(y)
    KF = deepcopy(KS)
print(Mass)
if sum(Mass) >= N//2+1:
    print('Fennec')
else:
    print('Snuke')

Fixed, accepted submission:
from collections import deque
from copy import deepcopy
N = int( input())
Path = [ [] for _ in range(N)]
for _ in range(N-1):
    a, b = map( int, input().split())
    a, b = a-1, b-1
    Path[a].append(b)
    Path[b].append(a)
Mass = [-1 for _ in range(N)]
F = deque([0])
S = deque([N-1])
while len(F) != 0 or len(S) != 0:
    KF = deque([])
    while len(F) != 0:
        f = F.pop()
        for x in Path[f]:
            if Mass[x] == -1:
                Mass[x] = 1
                KF.append(x)
    F = deepcopy(KF)
    KS = deque([])
    while len(S) != 0:
        s = S.pop()
        for y in Path[s]:
            if Mass[y] == -1:
                Mass[y] = 0
                KS.append(y)
    S = deepcopy(KS)
if sum(Mass) >= N//2+1:
    print('Fennec')
else:
    print('Snuke')
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
sum = 0
min = a[0]
max = a[0]
for i in range(1, n):
  if a[i] < min:
    min = a[i]
  elif a[i] > max:
    max = a[i]
  sum += a[i]
print(min, max, sum)
  

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
sum = a[0]
min = a[0]
max = a[0]
for i in range(1, n):
  if a[i] < min:
    min = a[i]
  if a[i] > max:
    max = a[i]
  sum += a[i]
print(min, max, sum)
Problem:
Niwango-kun is an employee of Dwango Co., Ltd.   One day, he is asked to generate a thumbnail from a video a user submitted.   To generate a thumbnail, he needs to select a frame of the video according to the following procedure:    * Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.   * Select t-th frame whose representation a_t is nearest to the average of all frame representations.   * If there are multiple such frames, select the frame with the smallest index.  Find the index t of the frame he should select to generate a thumbnail.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int,input().split()))
avg = sum(a)/n
mi = sum(a)
ans = 0
for i in range(n):
  if mi > abs(avg-a[i]):
    mi = abs(avg-a[i])
    ans = i+1
print(ans)

Fixed, accepted submission:
n = int(input())
a = list(map(int,input().split()))
avg = sum(a)/n
mi = sum(a)
ans = 0
for i in range(n):
  if mi > abs(avg-a[i]):
    mi = abs(avg-a[i])
    ans = i
print(ans)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int,input().split())
if (c-a) > b:
    print("No")
else:
    print("Yes")


Fixed, accepted submission:
A,B,X = map(int,input().split())
if A > X:
  print("NO")

elif B >= X - A:
  print("YES")
else:
  print("NO")
Problem:
You are given two positive integers A and B. Compare the magnitudes of these numbers.

Incorrect submission (verdict: Wrong Answer):
a = input()
b = input()
if len(a)-1<len(b):
	print("LESS")
elif len(a)-1>len(b):
	print("GREATER")
else:
	x = 0
	for i in range(len(b)):
		if int(a[i])<int(b[i]):
			print("LESS")
			x = 1
			break
		elif int(a[i])>int(b[i]):
			print("GREATER")
			x = 1
			break
	if x == 0: print("EQUAL")

Fixed, accepted submission:
a = int(input())
b = int(input())
if a>b: print("GREATER")
elif a<b: print("LESS")
else: print("EQUAL")
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
card = list(map(int, input().split()))

alice = []
bob = []
for i in range(1, n):
    val = max(card)
    del card[card.index(val)]
    if i % 2 == 1:
        alice.append(val)
    else:
        bob.append(val)

diff = sum(alice) - sum(bob)
print(diff)



Fixed, accepted submission:
n = int(input())
card = list(map(int, input().split()))

alice = []
bob = []
for i in range(1, n+1):
    val = max(card)
    del card[card.index(val)]
    if i % 2 == 1:
        alice.append(val)
    else:
        bob.append(val)

diff = sum(alice) - sum(bob)
print(diff)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):

import sys
import math
from functools import reduce
from bisect import bisect_left

def readString():
    return sys.stdin.readline()

def readInteger():
    return int(readString())

def readStringSet(n):
    return sys.stdin.readline().split(" ")[:n]

def readIntegerSet(n):
    return list(map(int, readStringSet(n)))

def readIntegerMatrix(n, m):
    return reduce(lambda acc, _: acc + [readIntegerSet(m)], range(0, n), [])

def main(N):
    for n in range(1, N+1):
        count = 0
        maxi = int(math.sqrt(N))
        x = 1
        for x in range(1, maxi):
            for y in range(1, maxi):
                
                
                a = n - pow(x, 2) - pow(y, 2) - x * y
                z = 0
                for z in range(1, maxi):
                    if pow(z, 2) + (x+y)*z == a:
                        count += 1
                    z += 1
                y += 1
            x += 1
        print(n, count)

if __name__ == "__main__":
    _N = readInteger()

    main(_N)

Fixed, accepted submission:

import sys
import math
from functools import reduce
from bisect import bisect_left

def readString():
    return sys.stdin.readline()

def readInteger():
    return int(readString())

def readStringSet(n):
    return sys.stdin.readline().split(" ")[:n]

def readIntegerSet(n):
    return list(map(int, readStringSet(n)))

def readIntegerMatrix(n, m):
    return reduce(lambda acc, _: acc + [readIntegerSet(m)], range(0, n), [])

def main(N):
    maxi = int(math.sqrt(N))
    result = dict()
    for x in range(1, maxi+1):
        for y in range(1, maxi+1):
            for z in range(1, maxi+1):
                n = pow(x, 2) + pow(y, 2) + pow(z, 2) + x*y + y*z + z*x
                if n not in result.keys():
                    result[n] = 1
                else:
                    result[n] += 1

    for n in range(1, N+1):
        if n in result.keys():
            print(result[n])
        else:
            print(0)

if __name__ == "__main__":
    _N = readInteger()

    main(_N)
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
import math


x = input().split()
n1 = float((x[0]))
n2 = float(x[2])
op = str(x[1])

try:
    result = eval("{} {} {}".format(n1, op, n2))
    print(math.floor(result))
except:
    pass


Fixed, accepted submission:
while True:
    x = input()
    if "?" in x: break
    result = eval(x)
    print(int(result))
Problem:
Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:  \\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]  where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Incorrect submission (verdict: Wrong Answer):
n, m, l = map(int, input().split())
mat_a = []
mat_b = []

for i in range(n):
    mat_a.append(list(map(int, input().split())))
    
for j in range(m):
    mat_b.append(list(map(int, input().split())))
    
for p in range(n):
    sum = 0
    mat_c = []
    for q in range(l):
        for r in range(m):
            sum += mat_a[p][r] * mat_b[r][q]
        mat_c.append(sum)
    print(' '.join(map(str, mat_c)))





Fixed, accepted submission:
n, m, l = map(int, input().split())
mat_a = []
mat_b = []

for i in range(n):
    mat_a.append(list(map(int, input().split())))
    
for j in range(m):
    mat_b.append(list(map(int, input().split())))
    
for p in range(n):
    mat_c = []
    for q in range(l):
        sum = 0
        for r in range(m):
            sum += mat_a[p][r] * mat_b[r][q]
        mat_c.append(sum)
    print(' '.join(map(str, mat_c)))
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
count=0
max=0
max_number=1

if N==1:
  print(1)

for i in range(1,N+1):
  while i>=1:
    if i%2==0:
      i=i//2
      count+=1
    else:
      break
  if count>=max:
    max=count
    max_number=1
print(max_number)

Fixed, accepted submission:
import math
n=int(input())

print(2**math.floor(math.log2(n)))
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):

# C - Factors of Factorial

N = int(input())

n = 1
for i in range(2, N + 1):
    n = n * i


def get_prime_factor(n):
    from collections import defaultdict
    res = defaultdict(int)
    for i in range(2, n + 1):
        if i * i > n:
            break
        while n % i == 0:
            res[i] = res[i] + 1
            n = n // i
    if n != 1:
        res[n] = 1
    return res

prime_factor = get_prime_factor(n)

# WIP



Fixed, accepted submission:

# C - Factors of Factorial

N = int(input())

n = 1
for i in range(2, N + 1):
    n = n * i

def get_prime_factor(n):
    from collections import defaultdict
    res = defaultdict(int)
    for i in range(2, n + 1):
        if i * i > n:
            break
        while n % i == 0:
            res[i] = res[i] + 1
            n = n // i
    if n != 1:
        res[n] = 1
    return res

prime_factor = get_prime_factor(n)

factors_count = 1
for count in prime_factor.values():
    factors_count = factors_count * (count + 1)

res = factors_count % (10 ** 9 + 7)
print(res)
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
h1=input()
print(h1)

Fixed, accepted submission:
x = int(input())
print(x*x*x)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Time Limit Exceeded):
N = int(input())
while True:
  for i in range(1,7):
    b = 2^(7-i)
    c = N%b
    if c ==0:
      break
    else:
      continue
    break
print(b)

Fixed, accepted submission:
N = int(input())
while True:
    for i in range(7):
        b = 2**(6-i)
        if b <= N:
            break
    break
print(b)
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
input = input()
input = input[8:]
input = input[:-7]

print(input)

Fixed, accepted submission:
input = input()
input = input[8:]
input = input[:-7]

print('A' + input[0] + 'C')
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
result = [1]
for i in range(2,1001):
  for j in range(1,11):
    if pow(i,j) <= 1000 and pow(i,j) not in result:
      result.append(pow(i,j))
print(max(result))

Fixed, accepted submission:
N=int(input())
result = [1]
for i in range(2,1001):
  for j in range(2,11):
    if pow(i,j) <= N and pow(i,j) not in result:
      result.append(pow(i,j))
print(max(result))
Problem:
Two students of AtCoder Kindergarten are fighting over candy packs.  There are three candy packs, each of which contains a, b, and c candies, respectively.  Teacher Evi is trying to distribute the packs between the two students so that each student gets the same number of candies. Determine whether it is possible.  Note that Evi cannot take candies out of the packs, and the whole contents of each pack must be given to one of the students.

Incorrect submission (verdict: Wrong Answer):
import itertools

a = list(map(int,(input().split(' '))))
c = list(itertools.combinations(a, 2))
#b = int(input())
#h = int(input())
#print(c)
a.sort()
if a[0]+a[1] == a[2]:
  print('YES')
else :
  print('NO')
  

Fixed, accepted submission:
import itertools

a = list(map(int,(input().split(' '))))
c = list(itertools.combinations(a, 2))
#b = int(input())
#h = int(input())
#print(c)
a.sort()

if a[0]+a[1] == a[2]:
  print('Yes')
else :
  print('No')