TnT/CodeNet4Repair huggingface dataset:
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
d = list(map(int, input().split()))

ds = set(d)
print(len(ds))

Fixed, accepted submission:
N = int(input())
d = []
for ni in range(N):
    d.append(int(input()))

ds = set(d)
print(len(ds))
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int, input().split())
c = 0
for i in range(1,n+1):
  n4 = n//10**4
  n3 = n//10**3 - n4*10
  n2 = n//10**2 - n4*100 - n3*10
  n1 = n//10**1 - n4*1000 - n3*100 -n2*10
  n0 = n - n4*10000 -n3*1000-n2*100-n1*10
  sum = n4+n3+n2+n1+n0
  if sum>=a and sum<=b:
    c+=sum


Fixed, accepted submission:
n,a,b = map(int, input().split())
c = 0
for i in range(1,n+1):
  n4 = i//10**4
  n3 = i//10**3 - n4*10
  n2 = i//10**2 - n4*100 - n3*10
  n1 = i//10**1 - n4*1000 - n3*100 -n2*10
  n0 = i - n4*10000 -n3*1000-n2*100-n1*10
  total = n4+n3+n2+n1+n0
  if total>=a and total<=b:
    c+= i
print(c)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int, input().split())

flag = False

print(C)

for i in range(B):
    
    t = i*A%B
    
    if t == C: 
        flag = True
        

if flag == True:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
A,B,C = map(int, input().split())

flag = False

for i in range(B):
    
    t = i*A%B
    
    if t == C: 
        flag = True
        

if flag == True:
    print("YES")
else:
    print("NO")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
print((n+1)*n/2)

Fixed, accepted submission:
n=int(input())
print(int((n+1)*n/2))
Problem:
Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order. From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized. If there are multiple pairs that maximize the value, any of them is accepted.

Incorrect submission (verdict: Wrong Answer):
from scipy.misc import comb
n=int(input())
A=list(map(int,input().split()))

A.sort()
max_,num=0,0
for a in A:
  if max_<comb(A[-1],a):
    max_=comb(A[-1],a)
    num=a
  else:
    break
print(A[-1],num)

Fixed, accepted submission:
n=int(input())
A=list(map(int,input().split()))

A.sort()
num=float('inf')
for i in range(n-1):
  if abs(num-A[-1]/2)>abs(A[i]-A[-1]/2):
    num=A[i]
print(A[-1],num)
Problem:
Write a program which computes the digit number of sum of two integers a and b.

Incorrect submission (verdict: Wrong Answer):
import sys, math

def run():
    N = []
    for n in sys.stdin:
        a,b = map(int, n.split())
        N.append((a,b))

    for a,b in N:
        print(math.ceil(math.log10(a+b)))

if __name__ == '__main__':
    run()




Fixed, accepted submission:
import sys, math

def run():
    N = []
    for n in sys.stdin:
        a,b = map(int, n.split())
        N.append((a,b))

    for a,b in N:
        print(math.floor(math.log10(a+b)) + 1)

if __name__ == '__main__':
    run()
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a=int(input());b=int(input());h=int(input())
S=h*(a+b)/2

print(S)

Fixed, accepted submission:
a=int(input());b=int(input());h=int(input())
S=h*(a+b)/2
s=int(S)
print(s)
Problem:
Snuke has N dogs and M monkeys. He wants them to line up in a row.  As a Japanese saying goes, these dogs and monkeys are on bad terms. _("ken'en no naka", literally "the relationship of dogs and monkeys", means a relationship of mutual hatred.)_ Snuke is trying to reconsile them, by arranging the animals so that there are neither two adjacent dogs nor two adjacent monkeys.  How many such arrangements there are? Find the count modulo 10^9+7 (since animals cannot understand numbers larger than that). Here, dogs and monkeys are both distinguishable. Also, two arrangements that result from reversing each other are distinguished.

Incorrect submission (verdict: Wrong Answer):
a=list(map(int,input().split()))
ans=0
i=0
if max(a)-min(a)>=2:
    pass
else:
    ans=1
    i=max(a)
    if a[0]==a[1]:
        while i!=0:
            ans=ans*i
            i=i-1
        ans=ans*ans
    else:
        while i!=0:
            ans=ans*i
            i=i-1
        ans=ans*ans/max(a)
        #print(ans)

print(int(ans%1000000007 ))

Fixed, accepted submission:
import math
a=list(map(int,input().split()))
ans=0
if max(a)-min(a)>=2:
    print(0)
else:
    if a[0]==a[1]:
        ans=math.factorial(max(a))
        ans=(ans%1000000007)*(ans%1000000007)*2
    else:
        ans=math.factorial(max(a))
        ans1 = math.factorial(min(a))
        ans=(ans%1000000007)*((ans1)%1000000007)
    print(int(ans%1000000007 ))
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
print(int(input())  % 1000000007)

Fixed, accepted submission:
N = int(input())
p = 1
for i in range(1,N+1):
    p *= i
    p %= 1000000007
print(p)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

h, w = map(int, readline().split())
for i in range(h):
    c = read().rstrip().decode()
    print(c + '\n' + c)


Fixed, accepted submission:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

h, w = map(int, readline().split())
for i in range(h):
    c = readline().rstrip().decode()
    print(c + '\n' + c)
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s = str(input())

print(s[0] + str(len(s[1:-2])) + s[-1])

Fixed, accepted submission:
s = str(input())

print(s[0] + str(len(s[1:-1])) + s[-1])
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):

from collections import Counter

w = input()
c = Counter(w)
for k, v in c.items():
    if v % 2 != 0:
        print("NO")
        exit()
        
print("YES")


Fixed, accepted submission:

from collections import Counter

w = input()
c = Counter(w)
for k, v in c.items():
    if v % 2 != 0:
        print("No")
        exit()

print("Yes")
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
s = input()
t = input()
ans = "UNRESTORABLE"

for i in range(len(s)-len(t)+1):
    for j in range(len(t)):
        if s[i+j] != t[j] and s[i+j] != "?":
            break
        if j == len(t) - 1:
            mazai = (s[:i] + t + s[i+len(t):]).replace("?","a")
            if mazai < "UNRESTORABLE":
                ans = mazai
print(ans)

Fixed, accepted submission:
s = input()
t = input()
ans = "UNRESTORABLE"

for i in range(len(s)-len(t)+1):
    for j in range(len(t)):
        if s[i+j] != t[j] and s[i+j] != "?":
            break
        if j == len(t) - 1:
            mazai = (s[:i] + t + s[i+len(t):]).replace("?","a")
            if True or mazai < "UNRESTORABLE":
                ans = mazai
print(ans)
Problem:
Ringo is giving a present to Snuke.  Ringo has found out that Snuke loves _yakiniku_ (a Japanese term meaning grilled meat. _yaki_ : grilled, _niku_ : meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.  You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s[0:3] == 'YAKI':
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
s = input()
if s[0:4] == 'YAKI':
    print('Yes')
else:
    print('No')
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
def main():
    s = sorted(input())
    t = sorted(input())

    S = ','.join(s)
    T = ','.join(t)

    if S < T:
        print('Yes')
    else:
        print('No')

if __name__ == '__main__':
    main()

Fixed, accepted submission:
def main():
    s = sorted(input())
    t = sorted(input())[::-1]

    S = ','.join(s)
    T = ','.join(t)

    if S < T:
        print('Yes')
    else:
        print('No')

if __name__ == '__main__':
    main()
Problem:
A string is called a KEYENCE string when it can be changed to `keyence` by removing its contiguous substring (possibly empty) only once.  Given a string S consisting of lowercase English letters, determine if S is a KEYENCE string.

Incorrect submission (verdict: Wrong Answer):
#15 B - KEYENCE String
S = list(input())

result = 'NO'

for i in range(len(S)):
    Scpy = S.copy()
    for j in range(i,len(S)):
        Scond = Scpy[:i]+Scpy[j:]
        print(Scond)
        if (''.join(Scond)) == ('keyence'):
            result = 'YES'
            break
    else:
        continue
    break
print(result)

Fixed, accepted submission:
#15 B - KEYENCE String
S = list(input())

result = 'NO'
for i in range(len(S)):
    Scpy = S.copy()
    for j in range(i,len(S)):
        Scond = Scpy[:i]+Scpy[j:]
        if (''.join(Scond)) == ('keyence'):
            result = 'YES'
            break
    else:
        continue
    break
print(result)
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
from itertools import product
li = list(map(int, input()))

for ops in product('+-', repeat=3):
    tmp = li[0]
    for o, n in zip(ops, li[1:]):
        if o == '+':
            tmp += n
        else:
            tmp -= n
    if tmp == 7:
        ans = str(li[0])
        for o, n in zip(ops, li[1:]):
            ans += o + str(n)

print(ans)


Fixed, accepted submission:
from itertools import product
li = list(map(int, input()))

for ops in product('+-', repeat=3):
    tmp = li[0]
    for o, n in zip(ops, li[1:]):
        if o == '+':
            tmp += n
        else:
            tmp -= n
    if tmp == 7:
        ans = str(li[0])
        for o, n in zip(ops, li[1:]):
            ans += o + str(n)
        ans += '=7'
        break

print(ans)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from collections import deque

n, m = map(int, input().split())

graph = [[] for _ in range(n + 1)]

for i in range(m):
    a, b = map(int, input().split())
    graph[a].append(b)
    graph[b].append(a)

#  print(graph)

mark = [-1]*(n+1)
mark[0] = 0
mark[1] = 0

d = deque()
d.append(1)

while d:
    v = d.popleft()
    for i in graph[v]:
        if mark[i] != -1:
            continue
        mark[i] = v
        d.append(i)
if mark.count(-1) > 0:
    print("No")
else:
    print("Yes")
    ans = mark[1:]
    print(*ans, sep="\n")

Fixed, accepted submission:
from collections import deque

n, m = map(int, input().split())

graph = [[] for _ in range(n + 1)]

for i in range(m):
    a, b = map(int, input().split())
    graph[a].append(b)
    graph[b].append(a)

#  print(graph)

mark = [-1]*(n+1)
mark[0] = 0
mark[1] = 0

d = deque()
d.append(1)

while d:
    v = d.popleft()
    for i in graph[v]:
        if mark[i] != -1:
            continue
        mark[i] = v
        d.append(i)
if mark.count(-1) > 0:
    print("No")
else:
    print("Yes")
    ans = mark[2:]
    print(*ans, sep="\n")
Problem:
You have an integer variable x. Initially, x=0.  Some person gave you a string S of length N, and using the string you performed the following operation N times. In the i-th operation, you incremented the value of x by 1 if S_i=`I`, and decremented the value of x by 1 if S_i=`D`.  Find the maximum value taken by x during the operations (including before the first operation, and after the last operation).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = input()
cnt = 0
n = 0
for i in range(n):
  if s[i] == "I":
    n += 1
  elif s[i] =="D":
    n -= 1
  cnt = max(cnt,n)
print(cnt)
            

Fixed, accepted submission:
n = int(input())
s = input()
max1 = -100
n = 0
for i in range(len(s)):
    if s[i] == "I":
        n += 1
    elif s[i] =="D":
        n -= 1
    max1 = max(max1,n)
print(max(max1,0))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x=int(input())
m=100
cnt=0
while x>=m:
    cnt+=1
    m=(m*1.01)//1
print(str(cnt))



Fixed, accepted submission:
x=int(input())
m=100
cnt=0
while x>m:
    cnt+=1
    m=(m*1.01)//1
print(str(cnt))
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
ans=0
while 2**ans <n:
  ans+=1
print(2**ans)

Fixed, accepted submission:
n=int(input())
ans=0
while 2**ans <=n:
  ans+=1
print(2**(ans-1))
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r, g, b = map(int, input().split())
if int(r + g + b) % 4 == 0:
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
r, g, b = input().split()
if int(r + g + b) % 4 == 0:
    print('YES')
else:
    print('NO')
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a, b, x = (map(int, input().split()))
k = a+b>=x and a<=x
print('Yes' if k else 'No')


Fixed, accepted submission:
a, b, x = (map(int, input().split()))
k = (a+b>=x) and (a<=x)
print('YES' if k else 'NO')
Problem:
The problem set at _CODE FESTIVAL 20XX Finals_ consists of N problems.  The score allocated to the i-th (1≦i≦N) problem is i points.  Takahashi, a contestant, is trying to score exactly N points. For that, he is deciding which problems to solve.  As problems with higher scores are harder, he wants to minimize the highest score of a problem among the ones solved by him.  Determine the set of problems that should be solved.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

for k in range(N):
    if(N >= 2 * k + 1):
        N -= k
    else:
        break

print(N)

Fixed, accepted submission:
N = int(input())
vec = []

k = 0
sum = 0
while(k**2 + k < 2*N):
  k += 1
  sum += k
  vec.append(k)
if(sum - N):
  vec.remove(sum - N)


for i in range(len(vec)):
  print(vec[i])
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
import math

if __name__ == "__main__":
	print("--2つの整数を入力する--")
	a, b = map(int, input().split())
	
	print( math.ceil( (a + b ) / 2) )

Fixed, accepted submission:
import math

if __name__ == "__main__":
	a, b = map(int, input().split())
	print( math.ceil( (a + b ) / 2) )
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
def main():
    a, b = input().split()
    a = int(a)
    b = float(b)
    
    print(a*b)



main()


Fixed, accepted submission:
from decimal import Decimal

def main():
    a, b = input().split()
    a = Decimal(a)
    b = Decimal(b)
    res = int(a*b)
    print(res)



main()
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
import sys
n = int(input())
a = [2**i for i in range(0,7)]

for i in range(len(a)):
    if n <= a[i]:
        print(a[i])
        sys.exit()

print(64)

Fixed, accepted submission:
import sys
n = int(input())
a = [2**i for i in range(0,7)]
for i in range(len(a)):
    if n == a[i]:
        print(a[i])
        sys.exit()
    elif n < a[i]:
        print(a[i-1])
        sys.exit()

print(64)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a, b, x = map(int, input().split())
if x-a > 0 and a+b >= x:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
a, b, x = map(int, input().split())
if x-a >= 0 and a+b >= x:
    print('YES')
else:
    print('NO')
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
n = a + b
if n >= 10:
    print('error')
else:
    print('n')

Fixed, accepted submission:
a,b = map(int,input().split())
n = a + b
if n >= 10:
    print('error')
else:
    print(n)