TnT/CodeNet4Repair huggingface dataset:
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
import math
N,H = map(int,input().split())

aList = []
bList = []
for count in range(0,N):
    a,b = map(int, input().split())
    aList.append(a)
    bList.append(b)

bList.sort()
bList.reverse()

count = 0
damage = 0
for b in bList:
    damage+=b
    count+=1
    if damage > H:
        break

if damage < H:
    remainingHP = H - sum(bList)
    maxA = max(aList)
    count = count + math.floor(remainingHP / maxA)

print(count)

Fixed, accepted submission:
import math
N,H = map(int,input().split())

aList = []
bList = []
for count in range(0,N):
    a,b = map(int, input().split())
    aList.append(a)
    bList.append(b)

bList.sort()
bList.reverse()

maxA = max(aList)

count = 0
damage = 0
for b in bList:
    if maxA < b:
        damage+=b
        count+=1
    if damage >= H:
        break

if damage < H:
    remainingHP = H - damage
    count = count + math.ceil(remainingHP / maxA)

print(count)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

if a <= c and c <= b:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
a, b, c = map(int, input().split())

if a <= c and c <= b:
    print("Yes")
else:
    print("No")
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
if list(map(int,input().split())).sort()==[5,5,7]:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
if sorted(list(map(int,input().split())))==[5,5,7]:
  print("YES")
else:
  print("NO")
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
m,d = map(int,input().split())
print(m if d>m else m-1)

Fixed, accepted submission:
m,d = map(int,input().split())
print(m if d>=m else m-1)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

cards = map(int, input().split())

sorted_cards = sorted(cards)

Alice = sum(sorted_cards[0::2])
Bob = sum(sorted_cards[1::2])

print(Alice-Bob)

Fixed, accepted submission:
def solve():
    N = int(input())

    cards = map(int, input().split())

    sorted_cards = sorted(cards, reverse=True)

    Alice = sum(sorted_cards[0::2])
    Bob = sum(sorted_cards[1::2])

    print(Alice-Bob)


solve()
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=0
d=0
e=0
f=0
g=0
while b<a:
    c=input()
    if c=='AC':
        d=d+1
    if c=='WA':
        e=e+1
    if c=='TLE':
        f=f+1
    if c=='RE':
        g=g+1
    b=b+1
print('AC','x',d)
print('WA','x',e)
print('TLE','x',f)
print('RE','x',f)



Fixed, accepted submission:
a=int(input())
b=0
d=0
e=0
f=0
g=0
while b<a:
    c=input()
    if c=='AC':
        d=d+1
    if c=='WA':
        e=e+1
    if c=='TLE':
        f=f+1
    if c=='RE':
        g=g+1
    b=b+1
print('AC','x',d)
print('WA','x',e)
print('TLE','x',f)
print('RE','x',g)
Problem:
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.  Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.  Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.

Incorrect submission (verdict: Wrong Answer):
A,B,C,D=map(int,input().split())
if(A+B<C+D):
    print("Left")
if(A+B>C+D):
    print("Right")
if(A+B==C+D):
    print("Balanced")

Fixed, accepted submission:
A,B,C,D=map(int,input().split())
if(A+B>C+D):
    print("Left")
if(A+B<C+D):
    print("Right")
if(A+B==C+D):
    print("Balanced")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
m = n // 1000
print(n - m * 1000)

Fixed, accepted submission:
n = int(input())
if n <= 1000:
    print(1000 - n)
else:
    if n % 1000 == 0:
        print(0)
    else:
        m = n // 1000 + 1
        print(m * 1000 - n)
Problem:
Snuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.  Snuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:    * Operation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.  For example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure. If the die is rotated toward the right as shown in the figure, the side showing 3 will face upward. Besides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.    Find the minimum number of operation Snuke needs to perform in order to score at least x points in total.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
print(x % 11)
if x % 11 == 0:
    print(x // 11 * 2)
elif x % 11 <= 6:
    print(x // 11 * 2 + 1)
else:
    print(x // 11 * 2 + 2)

Fixed, accepted submission:
x = int(input())
if x % 11 == 0:
    print(x // 11 * 2)
elif x % 11 <= 6:
    print(x // 11 * 2 + 1)
else:
    print(x // 11 * 2 + 2)
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = input()
b = input()
c = input()
ans = 0
for i in range(n):
  if (a[i] == b[i]) & (b[i] == c[i]):
    continue
  if (a[i] == b[i]) | (b[i] == c[i]):
    ans += 1
    continue
  ans += 2
print(ans)

Fixed, accepted submission:
n = int(input())
a = input()
b = input()
c = input()
ans = 0
for i in range(n):
  if (a[i] == b[i]) & (b[i] == c[i]):
    continue
  if (a[i] == b[i]) | (b[i] == c[i]) | (c[i] == a[i]):
    ans += 1
    continue
  ans += 2
print(ans)
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
alp = "a b c d e f g h i j k l m n o p q r s t u v w x y z"
alp = list(map(str, alp.split()))
s = input()
for i in range(len(s)):
    for j in range(26):
        if(s[i] == alp[j]):
            alp[j] = "?"
while("?" in alp):
    alp.remove("?")
if(len(alp) == 0):
    print("None")
else:
    print(alp)


Fixed, accepted submission:
alp = "a b c d e f g h i j k l m n o p q r s t u v w x y z"
alp = list(map(str, alp.split()))
s = input()
for i in range(len(s)):
    for j in range(26):
        if(s[i] == alp[j]):
            alp[j] = "?"
while("?" in alp):
    alp.remove("?")
if(len(alp) == 0):
    print("None")
else:
    print(alp[0])
Problem:
Given an integer N not less than 3, find the sum of the interior angles of a regular polygon with N sides.  Print the answer in degrees, but do not print units.

Incorrect submission (verdict: Wrong Answer):
print(180*int(input())-2)

Fixed, accepted submission:
print(180*(int(input())-2))
Problem:
In AtCoder, a person who has participated in a contest receives a _color_ , which corresponds to the person's rating as follows:    * Rating 1-399 : gray   * Rating 400-799 : brown   * Rating 800-1199 : green   * Rating 1200-1599 : cyan   * Rating 1600-1999 : blue   * Rating 2000-2399 : yellow   * Rating 2400-2799 : orange   * Rating 2800-3199 : red  Other than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.   Currently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.   Find the minimum and maximum possible numbers of different colors of the users.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
N = int(input())
a_list = list(map(int, input().split()))
class_list = []
free_list = []
for a in a_list:  
  if a < 3200:
    amod = a // 400
    class_list.append(amod)
  
  else:
    free_list.append(a)

print(class_list)
print(free_list)

set_list = list(set(class_list))

print(len(set_list), len(set_list) + len(free_list))

    

  



Fixed, accepted submission:
import numpy as np
N = int(input())
a_list = list(map(int, input().split()))
class_list = []
free_list = []
for a in a_list:  
  if a < 3200:
    amod = a // 400
    class_list.append(amod)
  
  else:
    free_list.append(a)

set_list = list(set(class_list))
min_list = len(set_list)
max_list = len(set_list) + len(free_list)

if min_list == 0:
  min_list = 1
print(min_list, max_list)
Problem:
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.  Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.  Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d=map(int,input().split())
if (a+b)>(c+d):
  print("Right")
elif a+b==c+d:
  print("Balanced")
else:
  print("Left")

Fixed, accepted submission:
a,b,c,d=map(int,input().split())
if (a+b)<(c+d):
  print("Right")
elif a+b==c+d:
  print("Balanced")
else:
  print("Left")
Problem:
You are given an integer N. Determine if there exists a tuple of subsets of \\{1,2,...N\\}, (S_1,S_2,...,S_k), that satisfies the following conditions:    * Each of the integers 1,2,...,N is contained in exactly two of the sets S_1,S_2,...,S_k.   * Any two of the sets S_1,S_2,...,S_k have exactly one element in common.  If such a tuple exists, construct one such tuple.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
OK = []
i = 2
while True:
    OK.append(i*(i+1)//2)
    if OK[-1] > 10**5:
        break
    i += 1
N = int(input())

if N in OK:
    print("Yes")
    W = OK.index(N) + 2
    S = [[] for _ in range(W+1)]
    j = 0
    L = list(range(1, N+1))
    l = 1
    for i, w in enumerate(range(W, 0, -1)):
        for s in range(l, l+w):
            S[i].append(s)
        l = l+w
    l = 1
    for i, w in enumerate(range(W, 0, -1)):
        for j, s in enumerate(range(l, l+w)):
            S[i+1+j].append(s)
        l = l+w
    
    for s in S:
        print(len(s), *s)
else:
    print("No")


Fixed, accepted submission:
# -*- coding: utf-8 -*-
OK = []
i = 1
while True:
    OK.append(i*(i+1)//2)
    if OK[-1] > 10**5:
        break
    i += 1
N = int(input())

if N in OK:
    print("Yes")
    W = OK.index(N) + 1
    S = [[] for _ in range(W+1)]
    j = 0
    L = list(range(1, N+1))
    l = 1
    for i, w in enumerate(range(W, 0, -1)):
        for s in range(l, l+w):
            S[i].append(s)
        l = l+w
    l = 1
    for i, w in enumerate(range(W, 0, -1)):
        for j, s in enumerate(range(l, l+w)):
            S[i+1+j].append(s)
        l = l+w
    print(len(S))
    for s in S:
        print(len(s), *s)
else:
    print("No")
Problem:
There are N slimes standing on a number line. The i-th slime from the left is at position x_i.  It is guaruanteed that 1 \leq x_1 < x_2 < \ldots < x_N \leq 10^{9}.  Niwango will perform N-1 operations. The i-th operation consists of the following procedures:    * Choose an integer k between 1 and N-i (inclusive) with equal probability.   * Move the k-th slime from the left, to the position of the neighboring slime to the right.   * Fuse the two slimes at the same position into one slime.  Find the total distance traveled by the slimes multiplied by (N-1)! (we can show that this value is an integer), modulo (10^{9}+7). If a slime is born by a fuse and that slime moves, we count it as just one slime.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))
mod = 1e+9 + 7
p = mod - 2
S = []
while p != 0:
  S = [p%2] + S[:]
  p //= 2
frac = 1
for i in range(N - 1):
  frac *= i+1
  frac %= mod
T = 0
for i in range(N - 1):
  k = 1
  for j in range(len(S)):
    if S[j] == 1:
      k *= i+1
      k %= mod
    if j != len(S) - 1:
      k *= k
      k %= mod
  T += (frac * k * (A[N - 1] - A[i])) % mod
  T %= mod
print(T%mod)

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))
mod = int(1e+9 + 7)
def inved(a):
  x, y, u, v, k, l = 1, 0, 0, 1, a, mod
  while l != 0:
    x, y, u, v = u, v, x - u * (k // l), y - v * (k // l)
    k, l = l, k % l
  return x

frac = 1
for i in range(N - 1):
  frac *= i+1
  frac %= mod
T = 0
for i in range(N - 1):
  k = inved(i+1)
  T += (k * (A[N - 1] - A[i])) % mod
  T %= mod
print((T*frac)%mod)
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
odd=input()
even=input()
passwd=''

for i in range(len(odd)):
  passwd+=odd[i]
  if len(even)-2 >= i:
    passwd+=even[i]

Fixed, accepted submission:
o=input()
e=input()
s=''
for i in range(len(e)):
  s+=o[i]+e[i]
print(s if len(o)==len(e) else s+o[-1])
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())
if A + (V*T) >= B + (W*T):
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())

if V<=W:
    print("NO")
    import sys
    sys.exit()

# import math
if abs(B-A)/(V-W) <= T:
    print("YES")
else:
    print("NO")
Problem:
Takahashi, who works at DISCO, is standing before an iron bar. The bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.  Takahashi wanted to choose a notch and cut the bar at that point into two parts with the same length. However, this may not be possible as is, so he will do the following operations some number of times **before** he does the cut:    * Choose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).   * Choose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.  Find the minimum amount of money needed before cutting the bar into two parts with the same length.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int,input().split()))

def func(A):
    A_inf = 0
    A_sup = 0
    L = sum(A)

    for a in A:
        if A_inf + a <= L/2:
            A_inf += a
            A_sup += a

        if A_sup <= L/2 and A_sup + a > L/2:
            A_sup += a

    if A_inf == A_sup:
        return 0
    x = sum(A) - 2*A_sup
    y = 2*A_sup - sum(A)
    result = min(x,y)
    return result

print(func(A))

Fixed, accepted submission:
N = int(input())
A = list(map(int,input().split()))

def func(A):
    A_inf = 0
    A_sup = 0
    N_inf = 0
    N_sup = 0
    L = sum(A)

    for a in A:
        if A_inf <= L/2 - a:
            A_inf += a
            A_sup += a
            N_inf += 1
            N_sup += 1
            continue
        else:
            if A_sup <= L/2 and A_sup + a > L/2:
                A_sup += a
                N_sup += 1
            break

    if A_inf == A_sup:
        return 0

    A_mid = A_sup - A_inf
    A_left = L/2 - A_inf
    A_right = A_sup - L/2
    A_lrmin = min(A_left, A_right)
    if A_mid-1 >= 2*A_lrmin:
        return int(2*A_lrmin)
    else:
        return int(A_mid)

print(func(A))
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
a,v=map(int,input().split())
b,w=map(int,input().split())
t=int(input())
ans="No"
if v<=w:
    ans="No"
else:
    for i in range(1,t+1):
        if a<b:
            a=a+v
            b=b+w
            if a==b:
                ans="Yes"
        else:
            a=a-v
            b=b-v
            if a==b:
                ans="Yes"
print(ans)

Fixed, accepted submission:
a,v=map(int,input().split())
b,w=map(int,input().split())
t=int(input())
ans="NO"
if v<=w:
    ans="NO"
else:
    if a>b:
        if (a-b)%(v-w)==0:
            if (a-b)//(v-w)<=t:
                ans="YES"
        else:
            if (a-b)//(v-w)+1<=t:
                ans="YES"
    elif a<b:
        if (a-b)%(v-w)==0:
            if (b-a)//(v-w)<=t:
                ans="YES"
        else:
            if (b-a)//(v-w)+1<=t:
                ans="YES"
print(ans)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())
b = 0
while True:
    if (500*b + a) > n:
        print("NO")
        break

    if (500*b + a) - n == 0:
        print("YES")
        break

    b+=1


Fixed, accepted submission:
import sys
n = int(input())
a = int(input())
b = 0
while True:
    c = 0
    if (500*b + c) > n:
        print("No")
        break
    for i in range(a+1):
        if (500*b + c) == n:
            print("Yes")
            sys.exit(0)
        c+=1
    b+=1
Problem:
On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in `yyyy/mm/dd` format. For example, January 23, 2018 should be written as `2018/01/23`.  After finishing the document, she noticed that she had mistakenly wrote `2017` at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to `2018` and prints it.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
s[3] = "8"
print(s)

Fixed, accepted submission:
s = input()
print("2018" + s[4:])
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
S = input()

dp = [False] * (len(S) + 1)
dp[0] = True
T = ['dream', 'dreamer', 'erase', 'eraser']
for i in range(1, len(S) + 1):
    tmp = []
    for t in T:
        if i < len(t):
            continue
        tmp.append(dp[i-len(t)] and t == S[i-len(t): i])
    if any(tmp):
        dp[i] = True
print('Yes' if dp[len(S)] else 'No')

Fixed, accepted submission:
S = input()

dp = [False] * (len(S) + 1)
dp[0] = True
T = ['dream', 'dreamer', 'erase', 'eraser']
for i in range(1, len(S) + 1):
    tmp = []
    for t in T:
        if i < len(t):
            continue
        tmp.append(dp[i-len(t)] and t == S[i-len(t): i])
    if any(tmp):
        dp[i] = True
print('YES' if dp[len(S)] else 'NO')
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
from itertools import*
A,B,C,D=input()
for i,j,k in product(["+","-"],repeat=3):
 s=A+i+B+j+C+k+D
 if eval(s)==7:print(s+"=7");break

Fixed, accepted submission:
s = str(input())
li = list(map(int, s))
if (li[0]==li[1]&li[1]==li[2])or(li[1] == li[2]&li[2]==li[3]):
    print("Yes")
else:
    print("No")