TnT/CodeNet4Repair huggingface dataset:
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
def main():
  element_num = int(input())
  elements = [int(s) for s in input().split()]
  swap_count = 0

  for i in range(1, element_num):
    for j in reversed(range(i, element_num)):
      if elements[j-1] > elements[j]:
        elements[j-1], elements[j] = elements[j], elements[j-1]
        swap_count += 1

  print(elements)
  print(swap_count)
  return 0

Fixed, accepted submission:
def main():
  element_num = int(input())
  elements = [int(s) for s in input().split()]
  swap_count = 0

  for i in range(1, element_num):
    for j in reversed(range(i, element_num)):
      if elements[j-1] > elements[j]:
        elements[j-1], elements[j] = elements[j], elements[j-1]
        swap_count += 1

  print(' '.join(list(map(str, elements))))
  print(swap_count)
  return 0

if __name__ == '__main__':
  main()
Problem:
There are N rabbits, numbered 1 through N.  The i-th (1≤i≤N) rabbit likes rabbit a_i. Note that no rabbit can like itself, that is, a_i≠i.  For a pair of rabbits i and j (i＜j), we call the pair (i，j) a _friendly pair_ if the following condition is met.    * Rabbit i likes rabbit j and rabbit j likes rabbit i.  Calculate the number of the friendly pairs.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
jk =0
le = list(map(int,input().split()))

le = [0] + le
for i in range(N):
    print(le[le[i]])
    if le[le[i]] == i:
        jk += 1

print(le[le[i]])


Fixed, accepted submission:
N = int(input())
jk =0
le = list(map(int,input().split()))

le = [0] + le
for i in range(N):
    if le[le[i]] == i:
        jk += 1

print(jk // 2)
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
# -*- coding-UTF-8 -*-
A, B, K = map(int, input().split())

i = 0
while True:
    i += 1
    if A%2:
         A -= 1
    A /= 2
    B += A
    if i == K:
        break
    i += 1
    if B%2:
        B -= 1
    B /= 2
    A += B
    if i == K:
        break
print(A,B)

Fixed, accepted submission:
# -*- coding-UTF-8 -*-
A, B, K = map(int, input().split())

i = 0
while True:
    i += 1
    if A%2:
         A -= 1
    A /= 2
    B += A
    if i == K:
        break
    i += 1
    if B%2:
        B -= 1
    B /= 2
    A += B
    if i == K:
        break
print(int(A),int(B))
Problem:
Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers.  She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of **distinct** positive integers is called **special** if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is **not** 1.  Nagase wants to find a **special** set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a **special** set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000.

Incorrect submission (verdict: Wrong Answer):
import sys
stdin = sys.stdin
sys.setrecursionlimit(10**6)
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
nn = lambda: list(stdin.readline().split())
ns = lambda: stdin.readline().rstrip()

n = ni()
import math

a = [2,3]
now = 30000

for i in range(n-2):
    if i == n-3:
        total = sum(a)
        while True:
            if (total+now)%6 == 0 and math.gcd(total,now) > 1:
                a.append(now)
                break
            now-=1
    else:
        while True:
            if now%2 == 0 or now%3 == 0:
                a.append(now)
                break
            now-=1

print(*a)

Fixed, accepted submission:
import sys
stdin = sys.stdin
sys.setrecursionlimit(10**6)
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
nn = lambda: list(stdin.readline().split())
ns = lambda: stdin.readline().rstrip()

n = ni()
import math

if n==3:
    print(2,5,63)
    exit()

a = [2,3,5]
now = 30000

for i in range(n-3):
    if i == n-4:
        total = sum(a)
        m = now
        while True:
            if (total+now)%30 == 0 and math.gcd(total,now) > 1:
                a.append(now)
                break
            if now < 6:
                if a[-1]%2==0:
                    a[-1]-=2
                elif a[-1]%3==0:
                    a[-1]-=3
                elif a[-1]%5==0:
                    a[-1]-=5
                total = sum(a)
                now = m+1
            now-=1
    else:
        while True:
            if now%2 == 0 or now%3 == 0 or now%5 == 0:
                a.append(now)
                now-=1
                break
            now-=1

print(*a)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
info = [list(map(int, input().split())) for i in range(n)]

info.insert(0, [0, 0, 0])
x_diff, y_diff = 0, 0

for i in range(n):
    dt = info[i+1][0] - info[i][0]
    x_diff = abs(info[i+1][1] - info[i][1])
    y_diff = abs(info[i+1][2] - info[i][2])
    if dt < x_diff + y_diff:
        print('NO')
        exit()
    if dt%2 != (x_diff + y_diff)%2:
        print('NO')
        exit()

print('YES')

Fixed, accepted submission:
n = int(input())
for i in range(n):
    t, x, y = map(int, input().split())
    if (x + y) > t or (x + y + t) % 2:
        print('No')
        exit()
print('Yes')
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N, A = int(input()), int(input())
print(N, A)

while N >= 500:
    N = N - 500

if A >= N:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
N, A = int(input()), int(input())

while N >= 500:
    N = N - 500

if A >= N:
    print("Yes")
else:
    print("No")
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int,input().split())
A_ = A
counter = 0
while True:
    if A_%B == C:
        print("Yes")
        break
    A_ += A
    counter += 1
    if counter > B:
        print("No")
        break

#go


Fixed, accepted submission:
A,B,C = map(int,input().split())
A_ = A
counter = 0
while True:
    if A_%B == C:
        print("YES")
        break
    A_ += A
    counter += 1
    if counter > B:
        print("NO")
        break

#go
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
S = []
a = 0
t = 0
w = 0
r = 0
for _ in range(n):
    S.append(input())
for i in range(n):
  if S[i]=="AC":
    a += 1
  elif S[i]=="TLE":
    t += 1
  elif S[i]=="WA":
    w += 1
  else:
    r += 1
a = str(a)
w = str(w)
t = str(t)
r = str(r)
print("ACx"+a)
print("WAx"+w)
print("TLE"+t)
print("REx"+r)
    
    

Fixed, accepted submission:
n = int(input())
S = []
a = 0
t = 0
w = 0
r = 0
for _ in range(n):
    S.append(input())
for i in range(n):
  if S[i]=="AC":
    a += 1
  elif S[i]=="TLE":
    t += 1
  elif S[i]=="WA":
    w += 1
  else:
    r += 1
a = str(a)
w = str(w)
t = str(t)
r = str(r)
print("AC x "+a)
print("WA x "+w)
print("TLE x "+t)
print("RE x "+r)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
for _ in range(n) :
    l = list(input())
print('AC x ' + str(l.count('AC')))
print('WA x ' + str(l.count('WA')))
print('TLE x ' + str(l.count('TLE')))
print('RE x ' + str(l.count('RE')))

Fixed, accepted submission:
n = int(input())
l = []
for i in range(n) :
    l.append(input())
print('AC x ' + str(l.count('AC')))
print('WA x ' + str(l.count('WA')))
print('TLE x ' + str(l.count('TLE')))
print('RE x ' + str(l.count('RE')))
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
import bisect
import sys

n,h = map(int,input().split())
ab = [list(map(int,input().split())) for i in range(n)]

b = [ab[i][1] for i in range(n)]

if n == 1:
    if h <= ab[0][1]:
        print(1)
        sys.exit()
    
    else:
        print(1+(h-ab[0][1])//ab[0][0])
        sys.exit()
    

max_a = 0

for i in range(n):
    max_a = max(max_a, ab[i][0])

b.sort()
idx = bisect.bisect_right(b,max_a)

ans = 0

for i in b[idx:][::-1]:
    h -= i
    ans += 1
    
    if h <= 0:
        break
    
if h <= 0:
    print(ans)

else:
    print(ans + h//max_a)
    

Fixed, accepted submission:
import bisect
import sys
import math

n,h = map(int,input().split())
ab = [list(map(int,input().split())) for i in range(n)]

b = [ab[i][1] for i in range(n)]

if n == 1:
    if h <= ab[0][1]:
        print(1)
        sys.exit()
    
    
    else:
        if ab[0][1] >= ab[0][0]:
            print(1+(math.ceil((h-ab[0][1])/ab[0][0])))
            sys.exit()
        
        else:
            print(math.ceil(h/ab[0][1]))
            sys.exit()

max_a = 0

for i in range(n):
    max_a = max(max_a, ab[i][0])

b.sort()
idx = bisect.bisect_right(b,max_a)

ans = 0

for i in b[idx:][::-1]:
    h -= i
    ans += 1
    
    if h <= 0:
        break
    
if h <= 0:
    print(ans)

else:
    print(ans + math.ceil(h/max_a))
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n, m, x, y = map(int, input().split())
xx = tuple(map(int, input().split()))
yy = tuple(map(int, input().split()))

if x > y:
    print('War')
    exit(0)

if min(yy) - max(xx) > 1:
    print("No War")
else:
    print("War")

Fixed, accepted submission:
n, m, x, y = map(int, input().split())
xx = tuple(map(int, input().split())) + (x,)
yy = tuple(map(int, input().split())) + (y,)

maxx = max(xx)
miny = min(yy)

if maxx >= miny:
    print('War')
else:
    print('No War')
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

def main():
    X = input()
    X = int(X)
    output = 100
    year = 0
    while output <= X:
        output = int(output * 1.01)
        math.floor(output)
        year += 1

    print(year)

if __name__ == "__main__":
    main()

Fixed, accepted submission:
import math

def main():
    X = input()
    X = int(X)
    output = 100
    year = 0
    while output < X:
        output = int(output * 1.01)
        math.floor(output)
        year += 1

    print(year)

if __name__ == "__main__":
    main()
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = input()
al = list(map(int, a.split()))
ans = [al.index(i)+1 for i in al if i == 1]


if set(al) == 0:
    print(0)
else:
    if sum(al)%2 != al[0]:
        print(-1)
    else:
        for i in range(2,n):
            if sum(al[i::i])%2 != al[i]:
                print(-1)
                break
        else:
            print(sum(al))
            print(ans)


Fixed, accepted submission:
N = int(input())
a = list(map(int, input().split()))
b = [0 for i in range(N)]

def check(i):

    n = i
    cnt = 0
    
    while n <= N:
        cnt += b[n-1]
        n += i
        
    return cnt

for i in range(N-1, -1, -1):
    if (a[i]+check(i+1))%2 == 1:
        b[i] = 1
    
ans = sum(b)
ll = []
for i in range(N):
    if b[i] == 1:
        ll.append(i+1)

lll = [str(i) for i in ll]
if ans == 0:
    print(ans)
else:
    print(ans)
    print(" ".join(lll))
Problem:
We have a sequence of length N, a = (a_1, a_2, ..., a_N). Each a_i is a positive integer.  Snuke's objective is to permute the element in a so that the following condition is satisfied:    * For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.  Determine whether Snuke can achieve his objective.

Incorrect submission (verdict: Wrong Answer):
a_list = list(map(int,input().split()))
cntn = 0
cnt2 = 0
cnt4 = 0
for i in a_list:
    if i%4 == 0:
        cnt4 += 1
    elif i%2 == 0:
        cnt2 += 1
    else:
        cntn += 1
        
cnt4seat = cnt4*2
flag = True
cnt4seat -= cntn
if cnt2 == 1:
    cnt4seat -= 1
    
if cnt4seat >= 0:
    print('Yes')
    
else:
    print('No')

Fixed, accepted submission:
n = int(input())
a_list = list(map(int,input().split()))
cntn = 0
cnt2 = 0
cnt4 = 0
for i in a_list:
    if i%4 == 0:
        cnt4 += 1
    elif i%2 == 0:
        cnt2 += 1
    else:
        cntn += 1
        
flag = True

if cnt4+ 1 >= cntn :
    flag = True

else:
    flag = False

if cnt2 >= 1:
    if cnt4 >= cntn :
        flag = True
    else:
        flag = False

if flag:
    print('Yes')

else:
    print('No')
Problem:
We have a grid with (2^N - 1) rows and (2^M-1) columns. You are asked to write 0 or 1 in each of these squares. Let a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.  For a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\leq i_1 \leq i_2\leq 2^N-1, 1\leq j_1 \leq j_2\leq 2^M-1, let S(i_1, i_2, j_1, j_2) = \displaystyle \sum_{r=i_1}^{i_2}\sum_{c=j_1}^{j_2}a_{r,c}. Then, let the _oddness_ of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.  Find a way to fill in the grid that maximizes its oddness.

Incorrect submission (verdict: Wrong Answer):
n, m = map(int, input().split())
ans = []
ans.append('0' + '1' * (2 ** m - 2))
ans.extend(['1' + '0' * (2 ** m - 2)] * (2 ** n - 2))
print('\n'.join(ans))


Fixed, accepted submission:
n, m = map(int, input().split())
ans = [0, 1]
for i in range(1, min(n, m)):
    k = 1 << i
    x = (1 << k) - 1
    slide = [a << k for a in ans]
    new_ans = [s | a for s, a in zip(slide, ans)]
    new_ans.extend(s | (a ^ x) for s, a in zip(slide, ans))
    ans = new_ans
if n > m:
    ans *= 1 << (n - m)
elif n < m:
    for i in range(n, m):
        k = 1 << i
        ans = [(a << k) | a for a in ans]

ans = [a0 ^ a1 for a0, a1 in zip(ans, ans[1:])]
ans = [a ^ (a >> 1) for a in ans]

print('\n'.join(map(('{:0' + str(2 ** m - 1) + 'b}').format, ans)))
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
x =int(input())
print(x^3)


Fixed, accepted submission:
x = int(input())
print(x**3)
Problem:
We have a grid with H rows and W columns, where all the squares are initially white.  You will perform some number of painting operations on the grid. In one operation, you can do one of the following two actions:    * Choose one row, then paint all the squares in that row black.   * Choose one column, then paint all the squares in that column black.  At least how many operations do you need in order to have N or more black squares in the grid? It is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.

Incorrect submission (verdict: Wrong Answer):
h = int(input())
w = int(input())
n = int(input())
print(min(n//h,n//w))

Fixed, accepted submission:
h = int(input())
w = int(input())
n = int(input())
print(min(-(-n//h),-(-n//w)))
Problem:
Snuke is making sugar water in a beaker. Initially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.    * Operation 1: Pour 100A grams of water into the beaker.   * Operation 2: Pour 100B grams of water into the beaker.   * Operation 3: Put C grams of sugar into the beaker.   * Operation 4: Put D grams of sugar into the beaker.  In our experimental environment, E grams of sugar can dissolve into 100 grams of water.  Snuke will make sugar water with the highest possible density.  The beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker. Find the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it. If there is more than one candidate, any of them will be accepted.  We remind you that the sugar water that contains a grams of water and b grams of sugar is \frac{100b}{a + b} percent. Also, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d,e,f=map(int,input().split())

ans_wat = 0
ans_sug = 0
ans_rate = 0

maxrate = 100 * e / (e + 100)

for i in range(31):
    for j in range(31):
        water = (i * a + j * b) * 100
        if (water <= f and water):
            nsug = min(f - water, water)
            for k in range(nsug):
                l = (nsug - k*c)
                suger = k * c + l * d
                rate = 100 * suger / (suger + water)
                if(ans_rate <= rate) and (rate <= maxrate):
                    ans_rate = rate
                    ans_sug = suger
                    ans_wat = water

print(ans_wat+ans_sug,ans_sug)

Fixed, accepted submission:
a,b,c,d,e,f=map(int,input().split())

ans_wat = 0
ans_sug = 0
ans_rate = 0

for i in range(31):
    for j in range(31):
        water = (i * a + j * b) * 100
        if (water <= f and water):
            nsug = min(water * e // 100, f - water)
            for k in range(nsug//c+1):
                l = (nsug - k*c)//d
                suger = k * c + l * d
                rate = 100 * suger / (suger + water)
                if(ans_rate <= rate):
                    ans_rate = rate
                    ans_sug = suger
                    ans_wat = water

print(ans_wat+ans_sug,ans_sug)
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
k = int(input())
m = max(max(a, b), c)
sum_ = a + b + c
res = sum_ - m + m*(2**k)

Fixed, accepted submission:
a, b, c = map(int, input().split())
k = int(input())
m = max(max(a, b), c)
sum_ = a + b + c
res = sum_ - m + m*(2**k)
print(res)
Problem:
An integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.  Given an integer N, determine whether it is a Harshad number.

Incorrect submission (verdict: Wrong Answer):
N = input()
f = lambda X:sum(int(x) for x in X)
print('Yes' if f(N)%int(N) == 0 else 'No')
    

Fixed, accepted submission:

def harshad(n):
    if n % sum(map(int, list(str(n)))) == 0:
        return True
    else:
        return False

N = int(input())
print('Yes' if harshad(N) else 'No')