TnT/CodeNet4Repair huggingface dataset:
Problem:
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.  Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.  Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)  At most how much can he earn on balance?  Note that the same string may be written on multiple cards.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter
import numpy as np

a = int(input())
a_list = []
b_list = []

for i in range(a):
  a_list.append(input())
a_list.append('null')

b = int(input())

for i in range(b):
  b_list.append(input())
a_count = Counter(a_list)
b_count = Counter(b_list)
a_list_no_overlap = set(a_list)
print(a_count)

point = []
for i in a_list_no_overlap:
    point.append(a_count[i]-b_count[i])

point_max = np.argmax(point)
print(point_max)


Fixed, accepted submission:
from collections import Counter
import numpy as np

a = int(input())
a_list = []
b_list = []

for i in range(a):
  a_list.append(input())

b = int(input())

for i in range(b):
  b_list.append(input())
a_count = Counter(a_list)
b_count = Counter(b_list)
a_list_no_overlap = set(a_list)

point = []
for i in a_list_no_overlap:
    point.append(a_count[i]-b_count[i])

point_max = max(point)
if point_max<0:
  print(0)
else:
  print(point_max)
Problem:
You are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N). Your objective is to remove some of the elements in a so that a will be a **good sequence**.  Here, an sequence b is a **good sequence** when the following condition holds true:    * For each element x in b, the value x occurs exactly x times in b.  For example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.  Find the minimum number of elements that needs to be removed so that a will be a good sequence.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter as ct

n=int(input())
lists=list(map(int,input().split()))
wanted=dict(ct(lists))
print(wanted)
if n>=2:
    numbers=0
    for i in wanted.keys():
        a=i-wanted[i]
        if a<0:
            numbers+=abs(a)
        elif a==0:
            numbers+=0
        if a>0:
            numbers+=wanted[i]
    print(numbers)
elif n==1:
    if lists==[1]:
        print(0)
    else:
        print(1)
    

Fixed, accepted submission:
from collections import Counter as ct

n=int(input())
lists=list(map(int,input().split()))
wanted=dict(ct(lists))
if n>=2:
    numbers=0
    for i in wanted.keys():
        a=i-wanted[i]
        if a<0:
            numbers+=abs(a)
        elif a==0:
            numbers+=0
        if a>0:
            numbers+=wanted[i]
    print(numbers)
elif n==1:
    if lists==[1]:
        print(0)
    else:
        print(1)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=1
for i in range(a+1):
  b = b+i
print(b)


Fixed, accepted submission:
a=int(input())
b=0
for i in range(a+1):
    b=b+i
print(b)
Problem:
Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: `a`, `e`, `i`, `o` and `u`.

Incorrect submission (verdict: Wrong Answer):
a="abcde"
c = input()
print("Yes" if c in a else "No")

Fixed, accepted submission:
a="aeiou"
c = input()
print("vowel" if c in a else "consonant")
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
if a==c or b==c or a+b==c:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b,c=map(int,input().split())
if a+b>=c:
    print("Yes")
else:
    print("No")
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r,g,b=map(int,input().split())
if (r*100+g*10+b) % 4 == 0:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
if (int(input().replace(" ",""))) % 4 == 0:
    print("YES")
else:
    print("NO")
Problem:
There are N cities and M roads. The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally. There may be more than one road that connects the same pair of two cities. For each city, how many roads are connected to the city?

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
road_list=[]
for _ in range(b):
  road_list+=list(input())
for i in range(a+1):
  print(road_list.count(i))

Fixed, accepted submission:
n,m = map(int,input().split())
road_list=[0 for _ in range(n)]

for _ in range(m):
  a,b = map(int,input().split())
  road_list[a-1]+=1
  road_list[b-1]+=1
for i in range(n):
  print(road_list[i])
Problem:
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one- dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.  You are now at town 1, and you want to visit all the other towns. You have two ways to travel:    * Walk on the line. Your _fatigue level_ increases by A each time you travel a distance of 1, regardless of direction.    * Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.  Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.

Incorrect submission (verdict: Wrong Answer):
n,a,b=map(int,input().split())
x=list(map(int,input().split()))
ans = 0
maxwalk = b//a
for i in range(n-1):
  if x[i+1]-x[i]>=maxwalk:
    ans+=b
  else:
    ans+=(x[i+1]-x[i])*a
print(ans)

Fixed, accepted submission:
n,a,b=map(int,input().split())
x=list(map(int,input().split()))
ans = 0
maxwalk = b//a
for i in range(n-1):
  if x[i+1]-x[i]>maxwalk:
    ans+=b
  else:
    ans+=(x[i+1]-x[i])*a
print(ans)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
import math

def main():
	N = int(input())
	A = [int(a) for a in input().split(" ")]
	B = [0] * N
	for i in range(1, N):
		for j in range(math.ceil(N / (i + 1)), math.floor(N / i) + 1):
			ball = 0
			for k in range(2 * j, N, j):
				if B[k - 1] == 1:
					ball += 1
			B[j - 1] = (ball % 2 + A[j - 1]) % 2
	ans = [str(x) for x, v in enumerate(B) if v == 1]
	print(" ".join(ans))

main()


Fixed, accepted submission:
import math

def main():
	N = int(input())
	A = [int(a) for a in input().split(" ")]
	B = [0] * N
	if N == 1:
		if A[0] == 1:
			print(1)
			print(1)
		else:
			print(0)
		return 0
	for i in range(1, N):
		for j in range(math.ceil(N / (i + 1)), math.floor(N / i) + 1):
			ball = 0
			for k in range(2 * j, N + 1, j):
				ball += B[k - 1]
			B[j - 1] = (ball % 2 + A[j - 1]) % 2
	ans = [str(x + 1) for x, v in enumerate(B) if v == 1]
	print(len(ans))
	if len(ans) > 0:
		print(" ".join(ans))

main()
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
""" AtCoder """

x, y = map(int, input().split())

a = [1, 3, 5, 7, 8, 10, 12]
b = [4, 6, 9, 11]
c = [2]

if (x in a and y in b) or (x in b and y in b) or (x in c and y in c):
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
""" AtCoder """

x, y = map(int, input().split())

a = [1, 3, 5, 7, 8, 10, 12]
b = [4, 6, 9, 11]
c = [2]

if (x in a and y in a) or (x in b and y in b) or (x in c and y in c):
    print("Yes")
else:
    print("No")
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3


Fixed, accepted submission:
s = input()
print(s[0]+str(len(s)-2)+s[-1])
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
M = 10**9+7
sum = 1
for i in range(1,n):
  sum *= i%M
print(sum%M)

Fixed, accepted submission:
n = int(input())
d = 1
for i in range(1,n+1):
  d = (d*i)%(10**9+7)
print(d)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

if a <= c and c <= b:
  ans = 'YES'
else:
  ans = 'NO'

print(ans)

Fixed, accepted submission:
a, b, c = map(int, input().split())

if a <= c and c <= b:
  ans = 'Yes'
else:
  ans = 'No'

print(ans)
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
print((int(input())+int(input()))//2*int(input()))

Fixed, accepted submission:
a = int(input())
b = int(input())
c = int(input())

print((a+b)*c//2)
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while True:
  a, op, b = map(str, input().split())
  a = int(a)
  b = int(b)
  if op == '?':
    break
  if op == '+':
    print(a+b)
  if op == '-':
    print(a*b)
  if op == '*':
    print(a//b)


Fixed, accepted submission:
while True:
  a, op, b = map(str, input().split())
  a = int(a)
  b = int(b)
  if op == '?':
    break
  if op == '+':
    print(a+b)
  if op == '-':
    print(a-b)
  if op == '*':
    print(a*b)
  if op == '/':
    print(a//b)
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
N,L=map(int,input().split())
s=[]

for i in range(N):
  s.append(input())

s.sort()
print(s)

result=""
for i in range(N):
	result+=s[i]
print(result)

Fixed, accepted submission:
N,L=map(int,input().split())
s=[]

for i in range(N):
  s.append(input())

s.sort()

result=""
for i in range(N):
	result+=s[i]
print(result)
Problem:
A country has a budget of more than 81 trillion yen. We want to process such data, but conventional integer type which uses signed 32 bit can represent up to 2,147,483,647.  Your task is to write a program which reads two integers (more than or equal to zero), and prints a sum of these integers.  If given integers or the sum have more than 80 digits, print "overflow".

Incorrect submission (verdict: Wrong Answer):

import sys

def main():
    n = int(sys.stdin.readline().strip())

    for _ in range(n):
        x = int(sys.stdin.readline().strip())
        y = int(sys.stdin.readline().strip())
        print(x + y)

if __name__ == '__main__':
    main()

Fixed, accepted submission:

import sys

def main():
    n = int(sys.stdin.readline().strip())

    for _ in range(n):
        x = sys.stdin.readline().strip()
        y = sys.stdin.readline().strip()

        if len(x) > 80 or len(y) > 80:
            print('overflow')
        else:
            ans = int(x) + int(y)
            if len(str(ans)) > 80:
                print('overflow')
            else:
                print(ans)

if __name__ == '__main__':
    main()
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = input().strip()
b = input().strip()
c = input().strip()
ans = 0
for _a, _b, _c in zip(a, b, c):
  if _a != _b and _b != _c:
    ans += 2
  elif _a == _b and _b == _c:
    continue
  else:
    ans += 1
print(ans)

Fixed, accepted submission:
n = int(input())
a = input().strip()
b = input().strip()
c = input().strip()
ans = 0
for _a, _b, _c in zip(a, b, c):
  if _a != _b and _b != _c and _a != _c:
    ans += 2
  elif _a == _b and _b == _c:
    continue
  else:
    ans += 1
print(ans)
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin
s = (stdin.readline().rstrip())
A = 10**9
Z = -10**9
for ind,i in enumerate(s):
    if i == "A" and ind < A:
        A = ind
    if i == "Z" and ind > Z:
        A = ind
print(Z-A+1)

Fixed, accepted submission:
from sys import stdin
s = (stdin.readline().rstrip())
A = 10**9
Z = -10**9
for ind,i in enumerate(s):
    if i == "A" and ind < A:
        A = ind
    if i == "Z" and ind > Z:
        Z = ind
print(Z-A+1)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin
import sys
import math

# A, B, C = [int(x) for x in stdin.readline().rstrip().split()]
# A = list(map(int, input().split()))
s = int(input())
print(s-(s//1000)*1000)


Fixed, accepted submission:
from sys import stdin
import sys
import math

# A, B, C = [int(x) for x in stdin.readline().rstrip().split()]
# A = list(map(int, input().split()))
s = int(input())
if s % 1000 == 0:
    print('0')
    sys.exit()
print(((s//1000)+1)*1000-s)
Problem:
There are three houses on a number line: House 1, 2 and 3, with coordinates A, B and C, respectively. Print `Yes` if we pass the coordinate of House 3 on the straight way from House 1 to House 2 without making a detour, and print `No` otherwise.

Incorrect submission (verdict: Wrong Answer):
*s, t = map(int, input().split())
s.sort()
for i in range(s[0],s[1]):
  if i == t:
    print("Yes")
print("No")

Fixed, accepted submission:
*s, t = map(int, input().split())
s.sort()
f = False
for i in range(s[0],s[1]+1):
  if i == t:
    f = True
print("Yes") if f else print("No")
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
n = (N**0.5) //1
print(n**2)

Fixed, accepted submission:
N = int(input())
n = int(N**0.5) 
print(n**2)
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
S = input()

S = sorted(S)

S_dict = {}
cnt = 0
for s in S:
  if s not in S_dict:
    S_dict[s] = 1

print(S_dict)

ALL = 'abcdefghijklmnopqrstuvwxyz'

answer= None
for c in ALL:
  if c not in S_dict:
    answer = c
    break

print(answer)


  

Fixed, accepted submission:
S = input()

S = sorted(S)

S_dict = {}
cnt = 0
#ord : return number of character based on character
#chr : return character based on number of character
for i in range(ord("a"), ord("z") +1):
  S_dict[i] = S.count(chr(i))

#print(S_dict)

ans =None
for i in range(ord("a"), ord("z") +1):
  if S_dict[i] == 0:
    ans = chr(i)
    break
    
print(ans)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
import sys
A, B, K = map(int, input().split())

if B-A+1 <= K:
  for i in range(A, B+1):
    print(i)
  sys.exit()
  
ans = set()

for i in range(A, A+K):
  ans.add(i)

for i in range(B, B-K, -1):
  ans.add(i)

for x in ans:
  print(x)

Fixed, accepted submission:
import sys
A, B, K = map(int, input().split())

if B-A+1 <= K:
  for i in range(A, B+1):
    print(i)
  sys.exit()
  
ans = set()

for i in range(A, A+K):
  ans.add(i)

for i in range(B, B-K, -1):
  ans.add(i)

for x in sorted(ans):
  print(x)
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())

if (V-W)<=0:
    print ("NO")
    exit(0)
if A > B:
    if (A-B) // (V-W) <= T:
        print("YES")
    else:
        print("NO")
else: 
    if (B-A) // (V-W) <= T:
        print("YEs")
    else:
        print("NO")

Fixed, accepted submission:
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())

if (V-W)<=0:
    print ("NO")
    exit(0)
if A > B:
    if (A-B) / (V-W) <= T:
        print("YES")
    else:
        print("NO")
else: 
    if (B-A) / (V-W) <= T:
        print("YES")
    else:
        print("NO")
Problem:
AtCoDeer the deer is seeing a quick report of election results on TV. Two candidates are standing for the election: Takahashi and Aoki. The report shows the ratio of the current numbers of votes the two candidates have obtained, but not the actual numbers of votes. AtCoDeer has checked the report N times, and when he checked it for the i-th (1≦i≦N) time, the ratio was T_i:A_i. It is known that each candidate had at least one vote when he checked the report for the first time.  Find the minimum possible total number of votes obtained by the two candidates when he checked the report for the N-th time. It can be assumed that the number of votes obtained by each candidate never decreases.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
ans=1
def retsmlst(s,n):
  tmp=s
  while s+tmp<n:
    tmp+=s
  return tmp
  
  
for _ in range(N):
  a,b=map(int,input().split())
  s=a+b
  ans=retsmlst(s,ans)
print(ans)


Fixed, accepted submission:









N = int(input())
ans = 1


def ret_nm(t, a, n, m):
    times_t = (n - 1) // t + 1
    times_a = (m - 1) // a + 1
    times = max(times_t, times_a)
    return times * t, times * a


n = m = 1
for _ in range(N):
    t, a = map(int, input().split())
    n, m = ret_nm(t, a, n, m)


print(n + m)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
print(int(input())%1000)

Fixed, accepted submission:
n=int(input())
print(-(-n//1000)*1000-n)
Problem:
Today is August 24, one of the five Product Days in a year.  A date m-d (m is the month, d is the date) is called a Product Day when d is a two-digit number, and all of the following conditions are satisfied (here d_{10} is the tens digit of the day and d_1 is the ones digit of the day):    * d_1 \geq 2   * d_{10} \geq 2   * d_1 \times d_{10} = m  Takahashi wants more Product Days, and he made a new calendar called Takahashi Calendar where a year consists of M month from Month 1 to Month M, and each month consists of D days from Day 1 to Day D.  In Takahashi Calendar, how many Product Days does a year have?

Incorrect submission (verdict: Wrong Answer):
m,d=map(int,input().split())
cnt=0
for j in range(1,m+1):
  for i in range(1,d+1):
    a=i//10
    b=i%10
    if a*b==j:
      cnt+=1
print(cnt)
    
  


Fixed, accepted submission:
m,d=map(int,input().split())
cnt=0
for j in range(1,m+1):
  for i in range(1,d+1):
    a=i//10
    b=i%10
    if a>1 and b>1:
      if a*b==j:
        cnt+=1
print(cnt)