TnT/CodeNet4Repair huggingface dataset:
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = list(map(int, input().split(' ')))

l.sort()
l.reverse()

result = 0

for e in enumerate(l):
    result += e[1] if e[0] % 2 else -e[1]

print(result)

Fixed, accepted submission:
n = int(input())
l = list(map(int, input().split(' ')))

l.sort()
l.reverse()

result = 0

for e in enumerate(l):
    result += e[1] if e[0] % 2 == 0 else -e[1]

print(result)
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N*800-(N/15)*200)

Fixed, accepted submission:
N = int(input())
print(N*800-(N//15)*200)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
Ss = [input() for _ in range(N)]

import collections

c = collections.Counter(Ss)
print(c)
print("AC x " + str(c["AC"]))
print("WA x " + str(c["WA"]))
print("TLE x " + str(c["TLE"]))
print("RE x " + str(c["RE"]))

Fixed, accepted submission:
N = int(input())
Ss = [input() for _ in range(N)]

import collections

c = collections.Counter(Ss)

print("AC x " + str(c["AC"]))
print("WA x " + str(c["WA"]))
print("TLE x " + str(c["TLE"]))
print("RE x " + str(c["RE"]))
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
s = input()
end = []
for i in s:
    if (end.count(i)==0):
        end.append(i)
    else:
        print("no")
        exit()
print("Yes")

Fixed, accepted submission:
s = input()
end = []
for i in s:
    if (end.count(i)==0):
        end.append(i)
    else:
        print("no")
        exit()
print("yes")
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a=input()
a=[int(x) for x in a.split()]
b=a[0]+a[1]
c=a[2]
print("Yes" if a[0]<=c and c<=b else "No")

Fixed, accepted submission:
a, b, x = [int(i) for i in input().split()]
print("YES" if a <= x <= a + b else "NO")
Problem:
Write a program which reads an integer _n_ and draws a Koch curve based on recursive calles of depth _n_.  The Koch curve is well known as a kind of   You should start (0, 0), (100, 0) as the first segment.

Incorrect submission (verdict: Wrong Answer):
def koch_curve(n, x1, y1, x2, y2):
    if n == 0:
        return [(x1, y1), (x2, y2)]
    s_x = (2 * x1 + x2) / 3
    s_y = (2 * y1 + y2) / 3
    t_x = (x1 + 2 * x2) / 3
    t_y = (y1 + 2 * y2) / 3
    
    u_x = (t_x - s_x) * .5 - (t_y - s_y) * (3 ** .5 / 2) + s_x
    u_y = (t_x - s_x) * (3 ** .5 / 2) + (t_y - s_y) * .5  + s_y
    ret = koch_curve(n - 1, x1, y1, s_x, s_y) + \
        koch_curve(n - 1, s_x, s_y, u_x, u_y) + \
        koch_curve(n - 1, u_x, u_y, t_x, t_y) + \
        koch_curve(n - 1, t_x, t_y, x2, y2)
    return ret
for x, y in koch_curve(int(input()), 0, 0, 100, 0):
    print('{:.4f} {:.4f}'.format(x, y))


Fixed, accepted submission:
def koch_curve(n, x1, y1, x2, y2):
    if n == 0:
        return [(x1, y1)]
    s_x = (2 * x1 + x2) / 3
    s_y = (2 * y1 + y2) / 3
    t_x = (x1 + 2 * x2) / 3
    t_y = (y1 + 2 * y2) / 3
    
    u_x = (t_x - s_x) * .5 - (t_y - s_y) * (3 ** .5 / 2) + s_x
    u_y = (t_x - s_x) * (3 ** .5 / 2) + (t_y - s_y) * .5  + s_y
    ret = koch_curve(n - 1, x1, y1, s_x, s_y) + \
        koch_curve(n - 1, s_x, s_y, u_x, u_y) + \
        koch_curve(n - 1, u_x, u_y, t_x, t_y) + \
        koch_curve(n - 1, t_x, t_y, x2, y2)
    return ret
for x, y in koch_curve(int(input()), 0, 0, 100, 0):
    print('{:.8f} {:.8f}'.format(x, y))
print('{:.8f} {:.8f}'.format(100, 0))
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
s = input()
listA = ["a","b","c","d","e","f","g","h","i","j","k",
         "l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
for i in range(27):
  if s.count("listA[i]")==0:
    print(listA[i])
    break

Fixed, accepted submission:
s = input()
x=0
listA = ["a","b","c","d","e","f","g","h","i","j","k",
         "l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
for i in range(26):
  if s.count(listA[i])==0:
    print(listA[i])
    x=1
    break
if x==0:
  print("None")
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
lis = input().split()

if int(lis[0]) > int(lis[2]):
    print("No")

else:
    print("Yes") if int(lis[0]) + int(lis[1]) >= int(lis[2]) else print("No")
    

Fixed, accepted submission:
lis = input().split()

if int(lis[0]) > int(lis[2]):
    print("NO")

else:
    print("YES") if int(lis[0]) + int(lis[1]) >= int(lis[2]) else print("NO")
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
x=2;
y=x*x*x
y

Fixed, accepted submission:
x=int(input())
print(x**3)
Problem:
You are going to hold a competition of one-to-one game called AtCoder Janken. _(Janken is the Japanese name for Rock-paper-scissors.)_ N players will participate in this competition, and they are given distinct integers from 1 through N. The arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive). You cannot assign the same integer to multiple playing fields. The competition consists of N rounds, each of which proceeds as follows:    * For each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.   * Then, each player adds 1 to its integer. If it becomes N+1, change it to 1.  You want to ensure that no player fights the same opponent more than once during the N rounds. Print an assignment of integers to the playing fields satisfying this condition. It can be proved that such an assignment always exists under the constraints given.

Incorrect submission (verdict: Wrong Answer):
# E - Rotation Matching

N, M = map(int, input().split())

if N%2==0:
    for i in range(M):
        print(i+1, N-(i))
else:
    for i in range(M):
        print(i+1, N-(i+1))

Fixed, accepted submission:
# E - Rotation Matching

N, M = map(int, input().split())

if N%2:
    for i in range(M):
        print(i+1, N-(i))
else:
    for i in range(M):
        if (i+1)+(N-(N-(i+1))) < N-(i+1)-(i+1):
            print(i+1, N-(i+1))
        else:
            print(i+2, N-(i+1))
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
n = list(map(int,input().split()))
k = int(input())
n.sort(reverse=True)
print(n[0]**k+n[1]+n[2])

Fixed, accepted submission:
li = list(map(int,input().split()))
k=int(input())
li.sort(reverse=True)
for i in range(k):
  li[0] = li[0]*2
print(li[0]+li[1]+li[2])
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
input()
a = list(map(int,input().split()))
a.reverse()
str = ""
for d in a:
    str += "%d "%(d)
print(str[:-1])

Fixed, accepted submission:
input()
a = list(map(int,input().split()))
sum = 0
for x in a:
    sum+=x
print(min(a),max(a),sum)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):

# Python 2nd Try


def solver(givenNumber):
    answer = 0
    for j in range(0, givenNumber):
        counter = 0
        baseNumber = j + 1
        while True:
            if baseNumber % 2 == 0:
                counter = counter + 1
                baseNumber = baseNumber / 2
            else:
                break
        if answer <= counter:
            counter = answer
    return answer


if __name__ == "__main__":
    N = int(input())
    print(solver(N))


Fixed, accepted submission:

# python 3rd Try


import sys


def twoDividedCounter(N):
    answer = 0
    copyNumber = N
    while True:
        if copyNumber % 2 == 0:
            answer = answer + 1
            copyNumber = copyNumber / 2
        else:
            break
    return answer


def solver(N):
    answer = 1
    counter = 0
    for j in range(1, N+1):
        jcount = twoDividedCounter(j)
        if counter < jcount:
            answer = j
            counter = jcount

    return answer


if __name__ == "__main__":
    N = sys.stdin.readline().rsplit()
    print(solver(int(N[0])))
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while 1:
    t = input()
    if t == '0 ? 0':
        break
    print(eval(t))

Fixed, accepted submission:
while 1:
    t = input()
    if '?' in t:
        break
    print(int(eval(t)))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x = int(input())
a = 100
ans = 0
while a <= x:
    a += a*0.01
    a = int(a)
    ans += 1
print(ans)

Fixed, accepted submission:
x = int(input())
a = 100
ans = 0
while a < x:
    a += a*0.01
    a = int(a)
    ans += 1
print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
print("Yes" if c<=a<=b else 'No')

Fixed, accepted submission:
a,b,c=map(int,input().split())
print("Yes" if a<=c<=b else 'No')
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
def decsum(i):
  ans = 0
  while(i==0):
    ans+=i%10
    i//=10
  return ans

n,a,b = tuple(map(int,input().split()))

ans = 0
for i in range(1,n+1):
  t = decsum(i)
  if a<=t<=b:
    ans+=1
print(ans)

Fixed, accepted submission:
def decsum(i):
  ans = 0
  while(i>0):
    ans+=i%10
    i//=10
  return ans

n,a,b = tuple(map(int,input().split()))

ans = 0
for i in range(1,n+1):
  t = decsum(i)
  if a<=t and t<=b:
    ans+=i
print(ans)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8
import time
import re
import math
import fractions

def main():
    N,A,B=map(int,input().split())
    count=0
    for a in range(1,N+1):
        s=str(a)
        total=0
        for b in s:
            total+=int(b)
        if A<=total and total<=B:
            count+=1
    print(count)
start=time.time()
main()

#"YNeos"[True::2]
#A=list(map(int,input().split()))
#A,B,C=map(int,input().split())
#n=int(input())




Fixed, accepted submission:
# coding: utf-8
import time
import re
import math
import fractions

def main():
    N,A,B=map(int,input().split())
    count=0
    for a in range(1,N+1):
        s=str(a)
        total=0
        for b in s:
            total+=int(b)
        if A<=total and total<=B:
            count+=a
    print(count)
start=time.time()
main()

#"YNeos"[True::2]
#A=list(map(int,input().split()))
#A,B,C=map(int,input().split())
#n=int(input())
Problem:
In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands. For convenience, we will call them Island 1, Island 2, ..., Island N.  There are M kinds of regular boat services between these islands. Each service connects two islands. The i-th service connects Island a_i and Island b_i.  Cat Snuke is on Island 1 now, and wants to go to Island N. However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.  Help him.

Incorrect submission (verdict: Wrong Answer):
n,m = map(int,input().split())
lis1 = []
lis2 = []
ans = "IMPOSSIBLE"
for i in range(m):
    a,b = map(int,input().split())
    if a == 1:
        lis1.append(b)
    else:
        lis2.append((a,b))
lis2 = set(lis2)        
for j in lis1:
    if (j,n) in lis2:
        ans = "POSSIBLE"
    else:
        pass
print(lis1,lis2)
print(ans)

Fixed, accepted submission:
n,m = map(int,input().split())
lis1 = []
lis2 = []
ans = "IMPOSSIBLE"
for i in range(m):
    a,b = map(int,input().split())
    if a == 1:
        lis1.append(b)
    else:
        lis2.append((a,b))
lis2 = set(lis2)        
for j in lis1:
    if (j,n) in lis2:
        ans = "POSSIBLE"
    else:
        pass

print(ans)
Problem:
Write a program which judges wheather given length of three side form a right triangle. Print "YES" if the given sides (integers) form a right triangle, "NO" if not so.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
for i in range(n):
    a = list(map(int, input().split()))
    m = max(a)
    b = sum([i**2 for i in a if i != m])
    if (m**2 == b):
        print("Yes")
    else:
        print("No")

Fixed, accepted submission:
n = int(input())
for i in range(n):
    a = list(map(int, input().split()))
    m = max(a)
    b = sum([i**2 for i in a if i != m])
    if (m**2 == b):
        print("YES")
    else:
        print("NO")
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
nums = list(map(int, input()))

ans_map = {}
for i in range(3):
    if i == 0:
        ans_map['-'] = nums[0] - nums[1]
        ans_map['+'] = nums[0] + nums[2]
        continue

    for operators in dict.fromkeys(ans_map):
        tmp_val = ans_map[operators]
        if i == 2:
            if tmp_val + nums[i + 1] == 7:
                print('{}{}{}{}{}{}{}'.format(
                    nums[0],
                    operators[0],
                    nums[1],
                    operators[1],
                    nums[2],
                    '+',
                    nums[3]
                ))
                break

            if tmp_val - nums[i + 1] == 7:
                print('{}{}{}{}{}{}{}'.format(
                    nums[0],
                    operators[0],
                    nums[1],
                    operators[1],
                    nums[2],
                    '-',
                    nums[3]
                ))
                break

        ans_map[operators + '-'] = tmp_val - nums[i + 1]
        ans_map[operators + '+'] = tmp_val + nums[i + 1]
        del ans_map[operators]

Fixed, accepted submission:
nums = list(map(int, input()))

ans_map = {}
for i in range(3):
    if i == 0:
        ans_map['+'] = nums[0] + nums[1]
        ans_map['-'] = nums[0] - nums[1]
        continue

    for operators in dict.fromkeys(ans_map):
        tmp_val = ans_map[operators]
        if i == 2:
            if tmp_val + nums[i + 1] == 7:
                print('{}{}{}{}{}{}{}=7'.format(
                    nums[0],
                    operators[0],
                    nums[1],
                    operators[1],
                    nums[2],
                    '+',
                    nums[3]
                ))
                break

            if tmp_val - nums[i + 1] == 7:
                print('{}{}{}{}{}{}{}=7'.format(
                    nums[0],
                    operators[0],
                    nums[1],
                    operators[1],
                    nums[2],
                    '-',
                    nums[3]
                ))
                break
            continue

        ans_map[operators + '+'] = tmp_val + nums[i + 1]
        ans_map[operators + '-'] = tmp_val - nums[i + 1]
        del ans_map[operators]
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
n = str(input(()))

if n[0] == n[1] == n[2] or n[1] == n[2] == n[3]:
    print("Yes")
else:
    print("No") 

Fixed, accepted submission:
n = str(input())

if n[0] == n[1] == n[2] or n[1] == n[2] == n[3]:
    print("Yes")
else:
    print("No")
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Time Limit Exceeded):
N = int(input())
x = 0
a = []
for i in range(N):
    while i % 2 == 0:
        i //= 2
        x += 1
    a.append(x)
    x = 0
a = sorted(a)
a = a[::-1]
print(a[0])


Fixed, accepted submission:
N = int(input())
x = 1

while x <= N:
    x *= 2
    
 
print(x // 2)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
c = 0

while True:
  x = int(input())
  if(x == 0):
   break;
  print('Case {0}: {1}'.format(c,x))
  c += 1

Fixed, accepted submission:
c = 1

while True:
  x = int(input())
  if(x == 0):
   break;
  print('Case {0}: {1}'.format(c,x))
  c += 1
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
num = int(input())
print(num)

if num == 1:
    print(1)
elif num == 2 | 3:
    print(2)
elif 4 <= num <= 7:
    print(4)
elif 8 <= num <= 15:
    print(8)
elif 16 <= num <= 31:
    print(16)
elif 32 <= num <= 63:
    print(32)
else:
    print(64)



Fixed, accepted submission:
num = int(input())


if num == 1:
    print(1)
elif num == 2 | 3:
    print(2)
elif 4 <= num <= 7:
    print(4)
elif 8 <= num <= 15:
    print(8)
elif 16 <= num <= 31:
    print(16)
elif 32 <= num <= 63:
    print(32)
else:
    print(64)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
coin500 = int(input())
coin100 = int(input())
coin050 = int(input())
target = int(input())
x = 0

for a in range(coin500):
  for b in range(coin100):
    for c in range (coin050):
     if target == a * 500 + b * 100 + c * 50:x += 1
print(x)

Fixed, accepted submission:
coin500 = int(input())
coin100 = int(input())
coin050 = int(input())
target = int(input())
x = 0
 
for a in range(coin500+1):
  for b in range(coin100+1):
    for c in range (coin050+1):
     if target == a * 500 + b * 100 + c * 50:x += 1
print(x)
Problem:
For an integer n not less than 0, let us define f(n) as follows:    * f(n) = 1 (if n < 2)   * f(n) = n f(n-2) (if n \geq 2)  Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

n = int(input())

if n % 2 == 1:
    print(0)
else:
    c = 0
    s = 0
    while 5**c < n:
        s += n // 5**c
        c += 1
    print(s)

Fixed, accepted submission:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

n = int(input())

if n % 2 == 1:
    print(0)
else:
    c = 1
    s = 0
    while 2 * 5**c <= n:
        s += n // (2 * 5**c)
        c += 1
    print(s)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())

if a <= c and c <=b:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
a,b,c = map(int, input().split())

if a <= c and c <=b:
    print("Yes")
else:
    print("No")