TnT/CodeNet4Repair huggingface dataset:
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
flag="No"
for i in range(1,100):
  if a*i%b==c:
    flag="Yes"
    break
print(flag)

Fixed, accepted submission:
a,b,c=map(int,input().split())
flag="NO"
for i in range(1,100):
  if a*i%b==c:
    flag="YES"
    break
print(flag)
Problem:
We have a deck consisting of N cards. Each card has an integer written on it. The integer on the i-th card from the top is a_i.  Two people X and Y will play a game using this deck. Initially, X has a card with Z written on it in his hand, and Y has a card with W written on it in his hand. Then, starting from X, they will alternately perform the following action:    * Draw some number of cards from the top of the deck. Then, discard the card in his hand and keep the last drawn card instead. Here, at least one card must be drawn.  The game ends when there is no more card in the deck. The score of the game is the absolute difference of the integers written on the cards in the two players' hand.  X will play the game so that the score will be maximized, and Y will play the game so that the score will be minimized. What will be the score of the game?

Incorrect submission (verdict: Wrong Answer):
n,z,w = [int(i) for i in input().split()]
a = list(int(i) for i in input().split())
print(a)
abs1 = abs(a[n-1] - w)
abs2 = abs(a[n-2]-a[n-1])
print(max(abs1,abs2))


Fixed, accepted submission:
n,z,w = [int(i) for i in input().split()]
a = list(int(i) for i in input().split())
#print(a)
abs1 = abs(a[n-1] - w)
abs2 = abs(a[n-2]-a[n-1])
print(max(abs1,abs2))
Problem:
Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.  You are given Smeke's current rating, x. Print `ABC` if Smeke will participate in ABC, and print `ARC` otherwise.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

x = int(input())




quot, rem = divmod(x, 11)
quot *= 2


if rem>6:
    quot += 2
elif rem>0:
    quot += 1

print(quot)

Fixed, accepted submission:
x = int(input())
if x<1200:
    print("ABC")
else:
    print("ARC")
Problem:
There are N dishes of cuisine placed in front of Takahashi and Aoki. For convenience, we call these dishes Dish 1, Dish 2, ..., Dish N.  When Takahashi eats Dish i, he earns A_i points of _happiness_ ; when Aoki eats Dish i, she earns B_i points of happiness.  Starting from Takahashi, they alternately choose one dish and eat it, until there is no more dish to eat. Here, both of them choose dishes so that the following value is maximized: "the sum of the happiness he/she will earn in the end" minus "the sum of the happiness the other person will earn in the end".  Find the value: "the sum of the happiness Takahashi earns in the end" minus "the sum of the happiness Aoki earns in the end".

Incorrect submission (verdict: Wrong Answer):
# input
n = int(input())
ab = sorted([list(map(int, input().split())) for _ in range(n)])

res = 0
for i in range(n):
    if i % 2 == 0:
        abi = ab.pop(len(ab)-1)
        res += abi[0]
    else:
        abi = ab.pop(len(ab)-1)
        res -= abi[1]
    print(abi)

print(res)

Fixed, accepted submission:
n = int(input())
dd = []
sb = 0
for _ in range(n):
    a, b = map(int, input().split())
    dd.append(a+b)
    sb -= b

abd = sorted(dd, reverse=True)

res = 0
for i in range(n):
    d = abd.pop(0)
    if i % 2 == 0:
        res += d

print(res+sb)
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
D, X = map(int, input().split())
A = [int(input()) for i in range(N)]

choco = 0

for i in A:
    for j in range(1,D+1,i):
        print(j)
        choco += 1
print(choco + X)

Fixed, accepted submission:
N = int(input())
D, X = map(int, input().split())
A = [int(input()) for i in range(N)]

choco = 0

for i in A:
    for j in range(1,D+1,i):
        choco += 1
print(choco + X)
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
N = int(input())

A = []
a, *an = map(int, input().split())
A.append(a)
A += an
A.sort()

Node = []
score = 0
Node.append(A.pop())

print(A)

for n in range(N - 1):
    score += Node.pop(0)
    num = A.pop()
    Node.append(num)
    Node.append(num)

#print(Node)
print(score)

Fixed, accepted submission:
N = int(input())

A = []
a, *an = map(int, input().split())
A.append(a)
A += an
A.sort()

Node = []
score = 0
Node.append(A.pop())

#print(A)
start = 0

for n in range(N - 1):
    score += Node[start]
    num = A.pop()
    start += 1
    #Node = Node[1:]
    Node.append(num)
    Node.append(num)

#print(Node)
print(score)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
#93b
a,b,k=map(int,input().split())

for i in range(k):
    print(a+i)
for i in range(k):
    print(b-k+i)
    
    
          

Fixed, accepted submission:
#93b
a,b,k=map(int,input().split())
c=min(a+k,b)
for i in range(a,c):print(i)
for i in range(max(c,b-k+1),b+1):print(i)
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(str,input().split())
print("Yes" if a[-1] == b[0] and b[-1] == c[0] else "No")

Fixed, accepted submission:
a,b,c = map(str,input().split())
print("YES" if (a[-1] == b[0] and b[-1] == c[0]) else "NO")
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
hat = input()
num = 0
for i in hat:
  if i == "R":
    num += 1
if num > (len(hat)/2):
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
input()
hat = input()
num = 0
for i in hat:
  if i == "R":
    num += 1
if num > (len(hat)/2):
  print("Yes")
else:
  print("No")
Problem:
We held two competitions: Coding Contest and Robot Maneuver.  In each competition, the contestants taking the 3-rd, 2-nd, and 1-st places receive 100000, 200000, and 300000 yen (the currency of Japan), respectively. Furthermore, a contestant taking the first place in both competitions receives an additional 400000 yen.  DISCO-Kun took the X-th place in Coding Contest and the Y-th place in Robot Maneuver. Find the total amount of money he earned.

Incorrect submission (verdict: Wrong Answer):
X,Y = map(int,input().split())
if X*Y == 1:
    print(10^6)
else:
  print(10^5*(max(0,4-X)+max(0,4-X)))


Fixed, accepted submission:
X,Y = map(int,input().split())
if X*Y == 1:
    print(10**6)
else:
  print(10**5*(max(0,4-X)+max(0,4-Y)))
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int,input().split())
if A <= C and C <= B:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
a,b,c = map(int, input().split())
if a <= c <= b:
  print("Yes")
else:
  print("No")
Problem:
You are parking at a parking lot. You can choose from the following two fee plans:    * Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.   * Plan 2: The fee will be B yen, regardless of the duration.  Find the minimum fee when you park for N hours.

Incorrect submission (verdict: Wrong Answer):
n, a, b = map(int, input().split())

if n*a > b:
  print(n*a)
else:
  print(b)

Fixed, accepted submission:
n, a, b = map(int, input().split())
 
if n*a >= b:
  print(b)
else:
  print(n*a)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a_ls = list(map(int,input().split(" ")))
a_ls_rev = a_ls[::-1]
N_rev = [0]*N
l = len(a_ls)
for i,a in enumerate(a_ls_rev):
    s_2 = sum(N_rev[::(i+1)])%2
    if s_2 != a:
        N_rev[i]+=1
s = ""
for i,n in enumerate(N_rev[::-1]):
    if n == 1:
        s += "{} ".format(i+1)
if len(s) == 0:
    print(0)
else:
    print(s[:-1])








Fixed, accepted submission:
N = int(input())
a_ls = list(map(int,input().split(" ")))
N = [0]*N
l = len(a_ls)


for i in range(l):
    a = a_ls[-(i+1)]
    s = sum(N[(l-i)-1::(l-i)])%2
    # print(s)
    # print(a)
    if a != s:
        N[-(i+1)]=1
        
sen = ""
for i,n in enumerate(N):
    if n == 1:
        sen += "{} ".format(i+1)

if len(sen) == 0:
    print(0)
else:
    print(sum(N))
    print(sen[:-1])
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
A = list(map(int,input().split()))
a=A[0]
b=A[1]
x=A[2]
s = 0
n = 0
s=(b-a)//x
print(s)

Fixed, accepted submission:
A = list(map(int,input().split()))
a=A[0]
b=A[1]
x=A[2]
a = (a-1) // x
b = b // x
s = b-a
print(s)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
def func(x,y,z):
    return x**2+y**2+z**2+x*y+y*z+z*x

n = int(input())

ans = 0
arr = []
for x in range(1,100):
    for y in range(1,100):
        for z in range(1,100):
            arr.append(func(x,y,z))
for i in range(n):
    print(arr.count(i))

Fixed, accepted submission:
import itertools
import math
import collections

def func(x,y,z):
    return x**2+y**2+z**2+x*y+y*z+z*x
 
n = int(input())
 
ans = 0
arr = []
for x in range(1,100):
    for y in range(1,100):
        for z in range(1,100):
            ans = func(x,y,z)
            arr.append(ans)
            if ans > n:
                break
 

c = collections.Counter(arr)
for i in range(n):
    print(c[i+1])
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
a, b, k = map(int, input().split())
for i in range(k):
    if i % 2 == 0:
        if a % 2 == 1:
            a -= 1
        b += a / 2
        a /= 2
        
    else:
        if b % 2 == 1:
            b -= 1
        a += b / 2
        b /= 2
print(a, b)

Fixed, accepted submission:
a, b, k = map(int, input().split())
for i in range(k):
    if i % 2 == 0:
        if a % 2 == 1:
            a -= 1
        b += a // 2
        a //= 2
        
    else:
        if b % 2 == 1:
            b -= 1
        a += b // 2
        b //= 2
print(a, b)
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
list = []
for i in range(N):
    a, b = input().split()
    list.append(float(a) if b == "JPY" else float(a) * 380000)
print(list)
print(sum(list))


Fixed, accepted submission:
N = int(input())
list = []
for i in range(N):
    a, b = input().split()
    list.append(float(a) if b == "JPY" else float(a) * 380000)
print(sum(list))
Problem:
Write a program which reads an integer n and identifies the number of combinations of a, b, c and d (0 ≤ a, b, c, d ≤ 9) which meet the following equality:      a + b + c + d = n      For example, for n = 35, we have 4 different combinations of (a, b, c, d): (8, 9, 9, 9), (9, 8, 9, 9), (9, 9, 8, 9), and (9, 9, 9, 8).

Incorrect submission (verdict: Wrong Answer):
s = int(input())
results=set()
for a in range(10):
    for b in range(10):
        for c in range(10):
            d = s-a-b-c
            if d<0:break
            if d<=9: results.add((a,b,c,d))
print(len(results))

Fixed, accepted submission:
import sys
#from me.io import dup_file_stdin


def solve():
    for s in map(int,sys.stdin):
        results=set()
        for a in range(10):
            for b in range(10):
                for c in range(10):
                    d = s-a-b-c
                    if d<0:break
                    if d<=9: results.add((a,b,c,d))
        print(len(results))
solve()
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
NKXY = [int(input()) for i in range(4)]
total=0
for i in range(NKXY[0]):
  if i<=NKXY[1]:
    total += NKXY[2]
  else:
    total += NKXY[3]
print(total)

Fixed, accepted submission:
NKXY = [int(input()) for i in range(4)]
total=0
for i in range(NKXY[0]):
  if i<NKXY[1]:
    total += NKXY[2]
  else:
    total += NKXY[3]
print(total)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
lis = [input() for _ in range(n)]
dic = {"AC":0, "WA":0, "TLE":0, "RE":0}

for x in lis:
  dic[x] += 1

for y in dic.keys():
  print(y, "×", dic[y])

Fixed, accepted submission:
n = int(input())
lis = [input() for _ in range(n)]
dic = {"AC":0, "WA":0, "TLE":0, "RE":0}

for x in lis:
  dic[x] += 1

for y in dic.keys():
  print(y, "x", dic[y])
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n%1000)

Fixed, accepted submission:
n = int(input())
ans = 1000 - n%1000
if ans ==1000:
	ans -=1000
print(ans)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
print(round(a+b)/2)

Fixed, accepted submission:
import math
a,b = map(int,input().split())
print(math.ceil((a+b)/2))
Problem:
To become a millionaire, M-kun has decided to make money by trading in the next N days. Currently, he has 1000 yen and no stocks - only one kind of stock is issued in the country where he lives.  He is famous across the country for his ability to foresee the future. He already knows that the price of one stock in the next N days will be as follows:    * A_1 yen on the 1-st day, A_2 yen on the 2-nd day, ..., A_N yen on the N-th day.  In the i-th day, M-kun can make the following trade **any number of times** (possibly zero), **within the amount of money and stocks that he has at the time**.    * Buy stock: Pay A_i yen and receive one stock.   * Sell stock: Sell one stock for A_i yen.  What is the maximum possible amount of money that M-kun can have in the end by trading optimally?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))


# dp[i]: 



dp = [0] * N

dp[0] = 1000 
for i in range(1, N):
  
  for j in range(0, i):
    
    v = int(dp[j] / A[j])
    
    
    
    
    
    w = dp[j] - v*A[j] + v*A[i]
    
    print(v, w)
    
    dp[i] = max(dp[i-1], w)
    
print(dp)   
    
 

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))


# dp[i]: 



dp = [0] * N

dp[0] = 1000 
for i in range(1, N):
  
  for j in range(0, i):
    
    v = int(dp[j] / A[j])
    
    
    
    
    
    w = dp[j] - v*A[j] + v*A[i]
    
    dp[i] = max(dp[i-1], w)
    
print(max(dp))
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
t=[[0,0,0]]
for i in range(N):
    A=list(map(int, input().strip().split()))
    t.append(A)

flag3=0
for i in range(N):
    flag=0
    flag2=0
    time=t[i+1][0]-t[i][0]
    x=t[i+1][1]-t[i][1]
    y=t[i+1][2]-t[i][2]
    time=abs(time)
    x=abs(x)
    y=abs(y)
    if time==(x+y):
        flag=1
    elif (time-(x+y))%2==0 and time>x+y:
        flag=1
    if flag!=1:
        flag3=1
if flag3==1:
    print("No")
else:
    print("Yes")

print(t)

Fixed, accepted submission:
N = int(input())
t=[[0,0,0]]
for i in range(N):
    A=list(map(int, input().strip().split()))
    t.append(A)

flag=0
flag2=0
for i in range(N):
    flag=0
    time=t[i+1][0]-t[i][0]
    x=t[i+1][1]-t[i][1]
    y=t[i+1][2]-t[i][2]
    time=abs(time)
    x=abs(x)
    y=abs(y)
    
    if (time-(x+y))%2==0 and time>=(x+y):
        flag=1
    if flag!=1:
        flag2=1    

if flag2==1:
    print("No")
else:
    print("Yes")
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
C1 = list(input())
C2 = list(input())

if (C1[0]==C2[2])&(C1[1]==C2[1])&(C1[2]==C2[0]):
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
C1 = list(input())
C2 = list(input())

if (C1[0]==C2[2])&(C1[1]==C2[1])&(C1[2]==C2[0]):
    print("YES")
else:
    print("NO")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if (a*b)% 2 == 0:
    print('Odd')
else:
    print('Even')


Fixed, accepted submission:
a,b = map(int,input().split())
if (a*b)% 2 == 1:
    print('Odd')
else:
    print('Even')
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
sx, sy, tx, ty = map(int,input().split())

print("U"*(ty-sy) + "R"*(tx-sx) + "U" + "L"*(tx-sx+1) + "D"*(ty-sy+1) + "R"*(tx-sx)+ "U"*(ty-sy) + "R" + "D"*(ty-sy+1) + "L"*(tx-sx+1))

Fixed, accepted submission:
sx, sy, tx, ty = map(int,input().split())

print("U"*(ty-sy) + "R"*(tx-sx) + "D"*(ty-sy) + "L"*(tx-sx) + "L" + "U"*(ty-sy+1) + "R"*(tx-sx+1) + "D" + "R" + "D"*(ty-sy+1) + "L"*(tx-sx+1) + "U")