TnT/CodeNet4Repair huggingface dataset:
Problem:
AtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W. If we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of   AtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle. Find the minimum distance it needs to be moved.

Incorrect submission (verdict: Wrong Answer):
w, a, b = [int(x) for x in input().split()]


if abs(a - b) > w:
    ans = abs(a - b) + w
else:
    ans = 0

print(ans)

Fixed, accepted submission:
import sys

w, a, b = map(int, sys.stdin.readline().split())

def main():
    if a + w < b:
        return b - (a + w)
    elif b + w < a:
        return a - (b + w)
    else:
        return 0

if __name__ == '__main__':
    ans = main()
    print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a ,b, c=map(int,input().split())
if c >= a and c <= b:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
a ,b, c=map(int,input().split())
if c >= a and c <= b:
    print('Yes')
else:
    print('No')
Problem:
We will call a string that can be obtained by concatenating two equal strings an _even_ string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.  You are given an even string S consisting of lowercase English letters. Find the length of the longest even string that can be obtained by deleting one or more characters from the end of S. It is guaranteed that such a non-empty string exists for a given input.

Incorrect submission (verdict: Wrong Answer):
s = input().strip()
ls = len(s)
for i in range(ls//2-1, 0, -1):
    if s[:i] == s[i:2*1]:
        print(2*i)
        break

Fixed, accepted submission:
S = input()

for i in range(1, len(S)):
    if len(S[:-i]) % 2 == 1:
        continue
    if S[:int(len(S[:-i])/2)] == S[int(len(S[:-i])/2):-i]:
        ans = len(S[:int(len(S[:-i]))])
        break
print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
print('Yes'if[i for i in input().split() if int(i)%2]else'No')

Fixed, accepted submission:
print('Even'if[i for i in input().split() if int(i)%2==0]else'Odd')
Problem:
There is a grid with H horizontal rows and W vertical columns. Let (i, j) denote the square at the i-th row from the top and the j-th column from the left.  For each i and j (1 \leq i \leq H, 1 \leq j \leq W), Square (i, j) is described by a character a_{i, j}. If a_{i, j} is `.`, Square (i, j) is an empty square; if a_{i, j} is `#`, Square (i, j) is a wall square. It is guaranteed that Squares (1, 1) and (H, W) are empty squares.  Taro will start from Square (1, 1) and reach (H, W) by repeatedly moving right or down to an adjacent empty square.  Find the number of Taro's paths from Square (1, 1) to (H, W). As the answer can be extremely large, find the count modulo 10^9 + 7.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

MOD = 10 ** 9 + 7

H, W = map(int, input().split())
count = np.ones((H, W), dtype=np.int)

row = input()
for w in range(1, W):
  if row[w] == '#':
    count[w:] = 0
    break

flag = True
for h in range(1, H):
  row = input()
  if flag and row[0] == '#':
    count[h:, 0] = 0
    flag = False
  count[h, 1:] = count[h-1, 1:]
  for w in range(1, W):
    period = 0
    if row[w] == '#':
      count[h, period : w] = count[h, period : w].cumsum() % MOD
      count[h, w] = 0
      period = w + 1
  count[h, period:] = count[h, period:].cumsum() % MOD
print(count[-1, -1])

Fixed, accepted submission:
MOD = 10 ** 9 + 7

H, W = map(int, input().split())
count = [0] * W

row = input()
for w in range(W):
  if row[w] == '#':
    break
  else:
    count[w] = 1

for h in range(1, H):
  row = input()
  if row[0] == '#':
    count[0] = 0
  for w in range(1, W):
    if row[w] == '#':
      count[w] = 0
    else:
      count[w] = (count[w-1] + count[w]) % MOD
print(count[-1])
Problem:
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Incorrect submission (verdict: Wrong Answer):
import string
x=input()
allcase=string.ascii_lowercase
for letter in allcase:
    print(letter + " : " + repr(x.count(letter)))

Fixed, accepted submission:
import string
x = ''
allcase = string.ascii_lowercase
while True:
    try: x+=input().lower()
    except:break
for letter in allcase:
    print(letter + " : " + repr(x.count(letter)))
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

ans = [a // b, a % b, a / b]
print(" ".join(map(str, ans)))



Fixed, accepted submission:
a, b = map(int, input().split())

d = a // b
r = a % b
f = a / b

print(d, r, '{:.5f}'.format(f))
Problem:
明日から、待ちに待った夏休みが始まります。なのでわたしは、友だちを誘って、海に遊びに行くこ とに決めました。  けれども、わたしの友だちには、恥ずかしがりやさんが多いです。その人たちは、あまり多くの人が いっしょに来ると知ったら、きっと嫌がるでしょう。  ほかにも、わたしの友だちには、目立ちたがりやさんも多いです。その人たちは、いっしょに来る人 があまり多くないと知れば、きっと嫌がるでしょう。  それと、わたしの友だちには、いつもは目立ちたがりやなのに実は恥ずかしがりやさんな人もいま す。その人たちは、いっしょに来る人が多すぎても少なすぎても、きっと嫌がるでしょう。  こういうのは、大勢で行った方が楽しいはずです。だからわたしは、できるだけたくさんの友だちを 誘いたいと思っています。けれども、嫌がる友だちを無理やり連れていくのはよくありません。  いったい、わたしは最大で何人の友だちを誘うことができるのでしょうか。  わたしは、こういう頭を使いそうな問題が大の苦手です。なので、あなたにお願いがあります。もし よろしければ、わたしの代わりにこの問題を解いていただけないでしょうか。いえ、決して無理にと は言いません。けれど、もし解いていただるのでしたら、わたしはとても嬉しいです。

Incorrect submission (verdict: Wrong Answer):
import heapq
n=int(input())
abs=sorted([list(map(int,input().split())) for _ in range(n)])
s=0
best=0
heap=[]
for k in range(1,n+1):
    while(s < n and abs[s][0] <= k+1):
        heapq.heappush(heap, -abs[s][1])
        s+=1
    while(len(heap) > 0 and -heap[0] <= k):
        heapq.heappop(heap)
    if(len(heap) >= k):
        best = k
print(best)

Fixed, accepted submission:
import heapq
n=int(input())
abs=sorted([list(map(int,input().split())) for _ in range(n)])
s=0
best=0
heap=[]
for k in range(1,n+1):
    while(s < n and abs[s][0] <= k+1):
        heapq.heappush(heap, abs[s][1])
        s+=1
    while(len(heap) > 0 and heap[0] <= k):
        heapq.heappop(heap)
    if(len(heap) >= k):
        best = k
print(best)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
print("No")

Fixed, accepted submission:
from collections import deque
N,M=map(int,input().split())
haba=[[] for i in range(N+1)]
for i in range(M):
    A,B=map(int,input().split())
    haba[A].append(B)
    haba[B].append(A)
kyori=[-1]*(N+1)
kyori[0]=0
kyori[1]=0

que=deque()
que.append(1)

while que:
    kari=que.popleft()
    for i in haba[kari]:
        if kyori[i]!=-1:
            continue
        kyori[i]=kari
        que.append(i)

ans=kyori[2:]
print("Yes")
for i in range(len(ans)):
    print(ans[i])
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b=map(int,input().split())
print(min(abs(x-a),abs(x-b)))

Fixed, accepted submission:
x,a,b=map(int,input().split())
if abs(x-a)>abs(x-b):
  print("B")
else:
  print("A")
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())
res = 0
for num in range(N):
  tmp = 0
  while num > 0:
    tmp += num % 10
    num //= 10
  if A <= tmp and tmp <= B:
    res += 1
print(res)

Fixed, accepted submission:
N, A, B = map(int, input().split())
res = 0
for i in range(1, N + 1):
  tmp = 0
  num = i
  while num > 0:
    tmp += num % 10
    num //= 10
  if A <= tmp and tmp <= B:
    res += i
print(res)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
def hiku():
	lst=input()
	lst = lst.split()
	lst.sort()
	print(lst)
	if lst[0]=='5' and lst[1]=='5' and lst[2]=='7':
		print("YES")
	else:
		print('NO')
hiku()

Fixed, accepted submission:
def test():
  x = input()
  x = x.split()
  if x == ['5', '5', '7']:
    print("YES")
  elif x == ['5', '7', '5']:
    print("YES")
  elif x == ['7', '5', '5']:
    print("YES")
  else:
    print("NO")
    
test()
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

X=int(input())
M=100
count=0
while M <= X:
    M=math.floor(M*1.01)
    count+=1
print(count)

Fixed, accepted submission:
import math

X=int(input())
M=100
count=0
while M < X:
    M=math.floor(M*1.01)
    count+=1
print(count)
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
a,b = input().split()
C = a + b
number_list =list(range(1,101))
squared_list =[]
for i in number_list:
        D = i * i
        squared_list.append(D)
if C in squared_list:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b = input().split()
C = a + b
number_list =list(range(1,1000))
squared_list =[]
for i in number_list:
        D = i * i
        D2 = str(D)
        squared_list.append(D2)
if C in squared_list:
    print("Yes")
else:
    print("No")
Problem:
Given is a tree G with N vertices. The vertices are numbered 1 through N, and the i-th edge connects Vertex a_i and Vertex b_i.  Consider painting the edges in G with some number of colors. We want to paint them so that, for each vertex, the colors of the edges incident to that vertex are all different.  Among the colorings satisfying the condition above, construct one that uses the minimum number of colors.

Incorrect submission (verdict: Wrong Answer):
def main():
    n = int(input())
    G = [[0] * (n-1) for i in range(2)]
    cnt = [0] * n
    for i in range(n-1):
        a,b = map(int, input().split())
        G[0][i] = a-1
        G[1][i] = b-1
        cnt[a-1] += 1
        cnt[b-1] += 1
    num = 0
    print(G)
    print(max(cnt))

    tmp_clr = [0] * (n-1)

    for i in range(n-1):
        clr = 1
        for j in range(i):
            if G[0][j] == G[0][i] or G[1][j] == G[0][i] or G[0][j] == G[1][i] or G[1][j] == G[1][i]:
                if tmp_clr[j] == clr:
                    clr += 1
        tmp_clr[i] = clr
    print('\n'.join(map(str, tmp_clr)))

if __name__=='__main__':
    main()


Fixed, accepted submission:
def main():
    n = int(input())
    
    cnt = [0] * n
    G = [[] for i in range(n)]
    for i in range(n-1):
        a, b = map(int, input().split())
        G[a-1].append((b-1, i))
        cnt[a-1] += 1
        cnt[b-1] += 1


    
    #     a,b = map(int, input().split())
    #     G[0][i] = a-1
    #     G[1][i] = b-1
    #     cnt[a-1] += 1
    #     cnt[b-1] += 1
    num = 0
    # print(G)
    print(max(cnt))

    tmp_clr = [0] * (n-1)
    tmp_edge = [0] * n

    # print(G)
    for frm, child in enumerate(G):
        clr = 1
        for j, to  in enumerate(child):

            if tmp_edge[frm] == clr :
                clr += 1
            tmp_clr[to[1]] = clr
            # tmp_edge[frm] = clr
            tmp_edge[to[0]] = clr
            clr+=1
    # print(tmp_edge)
    # print(tmp_clr)
    print('\n'.join(map(str, tmp_clr)))

if __name__=='__main__':
    main()
Problem:
On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis. Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i. Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.  For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.  That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
n,m = map(int,input().split())
X = list(map(int,input().split()))
Y = list(map(int,input().split()))
area=0
mod=10**9+7

x=0

for i in range(n):
  x += -(n-i-1)*X[i]+i*X[i]
  print("x",x)

y = 0

for i in range(m):
  y += -(m-i-1)*Y[i]+i*Y[i]

print(x*y%mod)

Fixed, accepted submission:
n,m = map(int,input().split())
X = list(map(int,input().split()))
Y = list(map(int,input().split()))
area=0
mod=10**9+7

x=0

for i in range(n):
  x += -(n-i-1)*X[i]+i*X[i]

y = 0

for i in range(m):
  y += -(m-i-1)*Y[i]+i*Y[i]

print(x*y%mod)
Problem:
Let's arrange a deck of cards. There are totally 36 cards of 4 suits(S, H, C, D) and 9 values (1, 2, ... 9). For example, 'eight of heart' is represented by H8 and 'one of diamonds' is represented by D1.  Your task is to write a program which sorts a given set of cards in ascending order by their values using the Bubble Sort algorithms and the Selection Sort algorithm respectively. These algorithms should be based on the following pseudocode:                 BubbleSort(C) 1 for i = 0 to C.length-1 2     for j = C.length-1 downto i+1 3         if C[j].value < C[j-1].value 4             swap C[j] and C[j-1]                 SelectionSort(C) 1 for i = 0 to C.length-1 2     mini = i 3     for j = i to C.length-1 4         if C[j].value < C[mini].value 5             mini = j 6     swap C[i] and C[mini]   Note that, indices for array elements are based on 0-origin.  For each algorithm, report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).

Incorrect submission (verdict: Wrong Answer):
import copy

def bubble_sort(a):
    ba = copy.copy(a)
    flag = True
    for i in range(0, n):
        if not flag:
            break
        flag = False
        for j in range(n-1, 0, -1):
            if int(ba[j][1]) < int(ba[j-1][1]):
                ba[j], ba[j-1] = ba[j-1], ba[j]
                flag = True

    return ba

def selection_sort(a):
    sa = copy.copy(a)
    for i in range(n):
        flag = False
        minj = i
        for j in range(i, n):
            if int(sa[j][1]) < int(sa[minj][1]):
                minj = j
                flag = True
        if flag:
            sa[i], sa[minj] = sa[minj], sa[i]

    return sa

def is_stable(ba, sa):
    for b, s in zip(ba, sa):
        if b != s:
            return 'Not Stable'
    return 'Stable'


n = int(input())
a = list(map(str, input().split()))

ba = bubble_sort(a)
print(' '.join(map(str, ba)))
print('Stable')

sa = selection_sort(a)
print(' '.join(map(str, sa)))
print(is_stable(ba, sa))



Fixed, accepted submission:
import copy

def bubble_sort(a):
    ba = copy.copy(a)
    flag = True
    for i in range(0, n):
        if not flag:
            break
        flag = False
        for j in range(n-1, 0, -1):
            if int(ba[j][1]) < int(ba[j-1][1]):
                ba[j], ba[j-1] = ba[j-1], ba[j]
                flag = True

    return ba

def selection_sort(a):
    sa = copy.copy(a)
    for i in range(n):
        flag = False
        minj = i
        for j in range(i, n):
            if int(sa[j][1]) < int(sa[minj][1]):
                minj = j
                flag = True
        if flag:
            sa[i], sa[minj] = sa[minj], sa[i]

    return sa

def is_stable(ba, sa):
    for b, s in zip(ba, sa):
        if b != s:
            return 'Not stable'
    return 'Stable'


n = int(input())
a = list(map(str, input().split()))

ba = bubble_sort(a)
print(' '.join(map(str, ba)))
print('Stable')

sa = selection_sort(a)
print(' '.join(map(str, sa)))
print(is_stable(ba, sa))
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
grid = list()
for i in range(3):
    grid.append([int(k) for k in input().split(" ")])


def check_vert():
    for i in range(2):
        diffs = [grid[k][i] - grid[k][i+1]for k in range(3)]
        print(diffs)
        if not len(set(diffs)) == 1:
            return False
    else:
        return True


def check_hor():
    for i in range(2):
        diffs = [grid[i][k] - grid[i+1][k] for k in range(3)]
        print(diffs)
        if not len(set(diffs)) == 1:
            return False
    else:
        return True


if check_hor() and check_vert():
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
grid = list()
for i in range(3):
    grid.append([int(k) for k in input().split(" ")])


def check_vert():
    for i in range(2):
        diffs = [grid[k][i] - grid[k][i+1]for k in range(3)]
        if not len(set(diffs)) == 1:
            return False
    else:
        return True


def check_hor():
    for i in range(2):
        diffs = [grid[i][k] - grid[i+1][k] for k in range(3)]
        if not len(set(diffs)) == 1:
            return False
    else:
        return True


if check_hor() and check_vert():
    print("Yes")
else:
    print("No")
Problem:
The problem set at _CODE FESTIVAL 20XX Finals_ consists of N problems.  The score allocated to the i-th (1≦i≦N) problem is i points.  Takahashi, a contestant, is trying to score exactly N points. For that, he is deciding which problems to solve.  As problems with higher scores are harder, he wants to minimize the highest score of a problem among the ones solved by him.  Determine the set of problems that should be solved.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = 1
while True:
  if k*(k+1)//2 >= n:
    ans = k
    break
  k += 1
print(ans)

Fixed, accepted submission:
n = int(input())
k = 1
while True:
  if k*(k+1)//2 >= n:
    ans = k
    break
  k += 1
if n == ans*(ans+1)//2:
  i = 1
  while i <= ans:
    print(i)
    i += 1
else:
  i = 1
  l = []
  cnt = 1
  while i < ans:
    if cnt <= (ans-1)*(ans+2)//2 - n:
      print(i)
      cnt += 1
    else:
      print(i+1)
    i += 1
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
listA=[list(input().split()) for _ in range(N)]
print(listA)

ans=0
for i in range(N):
    ans+=float(listA[i][0])*(1,380000)[listA[i][1]=='BTC']
print(ans)

Fixed, accepted submission:
N=int(input())
listA=[list(input().split()) for _ in range(N)]

ans=0
for i in range(N):
    ans+=float(listA[i][0])*(1,380000)[listA[i][1]=='BTC']
print(ans)
Problem:
Ringo is giving a present to Snuke.  Ringo has found out that Snuke loves _yakiniku_ (a Japanese term meaning grilled meat. _yaki_ : grilled, _niku_ : meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.  You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s[0:4] == 'YAKI':
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
s = input()
if s[0:4] == 'YAKI':
    print('Yes')
else:
    print('No')