TnT/CodeNet4Repair huggingface dataset:
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
b=int(input())
c=int(input())
x=int(input())

ans=0
for i in range(0,a):
    for j in range(0,b):
        for k in range(0,c):
            if 500*i+100*j+50*k==x:
                ans+=1
                
                print(ans)

Fixed, accepted submission:
a=int(input())
b=int(input())
c=int(input())
x=int(input())

ans=0
for i in range(a+1):
    for j in range(b+1):
        for k in range(c+1):
            if 500*i+100*j+50*k==x:
                ans+=1
print(ans)
Problem:
Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: `a`, `e`, `i`, `o` and `u`.

Incorrect submission (verdict: Wrong Answer):
S = input()
S = S[::-1]

T = ['dream'[::-1],'dreamer'[::-1],'erase'[::-1],'eraser'[::-1]]
size = 0


while size < len(S):
	if S[size:size+5] == T[0] or S[size:size+5] == T[2]:
		size += 5
	elif S[size:size+6] == T[3]:
		size += 6
	elif S[size:size+7] == T[1]:
		size += 7
	else :
		print('No')
		exit()
print('Yes')

Fixed, accepted submission:
c = input()

if c in 'aiueo':
	print('vowel')
else:
	print('consonant')
Problem:
Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:  \\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]  where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Incorrect submission (verdict: Wrong Answer):
#Input
n,m,l = map(int,input().split())
A = [list(map(int,input().split())) for i in range(n)]
B = [list(map(int,input().split())) for i in range(m)]

c = [list(sum([A[i][k] * B[k][j] for k in range(m)]) for j in range(l)) for i in range(n)]

#Output
for i in c:
    print(*c)

Fixed, accepted submission:
#Input
n,m,l = map(int,input().split())
A = [list(map(int,input().split())) for i in range(n)]
B = [list(map(int,input().split())) for i in range(m)]

c = [list(sum([A[i][k] * B[k][j] for k in range(m)]) for j in range(l)) for i in range(n)]

#Output
for i in c:
    print(*i)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
import sys

a = map(int, sys.stdin.readline().split())

seven = 0
five = 0

for i in a:
    if i == seven:
        seven += 1
    else:
        five += 1

if seven == 1 and five == 2:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
import sys

a = map(int, sys.stdin.readline().split())

seven = 0
five = 0

for i in a:
    if i == 7:
        seven += 1
    else:
        five += 1

if seven == 1 and five == 2:
    print("YES")
else:
    print("NO")
Problem:
There is an apple tree that bears apples of N colors. The N colors of these apples are numbered 1 to N, and there are a_i apples of Color i.  You and Lunlun the dachshund alternately perform the following operation (starting from you):    * Choose one or more apples from the tree and eat them. Here, the apples chosen at the same time must all have different colors.  The one who eats the last apple from the tree will be declared winner. If both you and Lunlun play optimally, which will win?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
cnt=float('inf')
for i in range(n):
    a=int(input())
    cnt=min(cnt,a)

tm=n^cnt
if tm%2==0:
    print("first")
else:
    print("second")

Fixed, accepted submission:
n=int(input())
a=[int(input()) for i in range(n)]

print( "second" if all(a[i]%2==0 for i in range(n)) else "first" )
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
S = input()
lll = "abcdefghijklmnopqrstuvwxyz"
for i in range(26):
    if lll[i] in S:
        print(lll[i])
        exit()
    else:
        pass
    
print("None")
    

Fixed, accepted submission:
S = input()
lll = "abcdefghijklmnopqrstuvwxyz"
for i in range(26):
    if lll[i] in S:
        pass
    else:
        print(lll[i])
        exit()
    
print("None")
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = input()
B = input()
C = input()
target_list = []
for a, b, c in zip(A, B, C):
    if a==b and b==c:
        target_list.append(3)
    elif a==b or a==c:
        target_list.append(2)
    else:
        target_list.append(1)
print(N*3 - sum(target_list))

Fixed, accepted submission:
N = int(input())
A = input()
B = input()
C = input()
target_list = []
for a, b, c in zip(A, B, C):
    if a==b and b==c and c==a:
        target_list.append(3)
    elif a==b or b==c or c==a: 
        target_list.append(2)
    else:
        target_list.append(1)
print(N*3 - sum(target_list))
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r,g,b=map(int,input().split())
if(r+g+b)%4 == 0:
  print('YES')
else:
  print('NO')

Fixed, accepted submission:
g=int(input().replace(' ', ''))
if g%4 == 0:
  print('YES')
else :
  print('NO')
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
def how_many_times_divisible(n):
    ans = 0
    while  n % 2 == 0:
        n = n / 2
        ans += 1
    return ans

n = input()
a = list(map(int,input().split()))

a_divided = list(map(how_many_times_divisible,a))

ans = max(a_divided)

print(ans)


Fixed, accepted submission:
def how_many_times_divisible(n):
    ans = 0
    while  n % 2 == 0:
        n = n / 2
        ans += 1
    return ans

n = input()
a = list(map(int,input().split()))

a_divided = list(map(how_many_times_divisible,a))

ans = min(a_divided)

print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N=int(input())

ac=0
wa=0
tle=0
re=0

S=[input() for i in range(N)]
for s in S:
    if s =='AC':
        ac=ac+1
    elif s == 'WA':
        wa = wa + 1
    elif s == 'TLE':
        tle = tle + 1
    else:
        re = re + 1

print("AC ×",ac)
print("WA ×",wa)
print("TLE ×",tle)
print("RE ×",re)

Fixed, accepted submission:
N=int(input())
ac=0
wa=0
tle=0
re=0

S=[input() for i in range(N)]
for s in S:
    if s =='AC':
        ac=ac+1
    elif s == 'WA':
        wa = wa + 1
    elif s == 'TLE':
        tle = tle + 1
    else:
        re = re + 1

print("AC x",ac)
print("WA x",wa)
print("TLE x",tle)
print("RE x",re)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = int(input())
C = int(input())
X = int(input())

counts = 0

for a in range(A+1):
    for b in range(B+1):
        for c in range(C+1):
            if (A*500 + B*100 + C*50)==X:
                counts += 1
                
print(counts)

Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())

counts = 0

for a in range(A+1):
    for b in range(B+1):
        for c in range(C+1):
            if (a*500 + b*100 + c*50)==X:
                counts += 1
                
print(counts)
Problem:
You are given three integers, A, B and C.   Among them, two are the same, but the remaining one is different from the rest.   For example, when A=5,B=7,C=5, A and C are the same, but B is different.   Find the one that is different from the rest among the given three integers.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
print("c" if a==b else "b" if a==c else "a")

Fixed, accepted submission:
a,b,c=map(int,input().split())
print(c if a==b else b if a==c else a)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
X = int(input())
money = 100
count = 0
while money <= X:
    money = int(money*1.01) 
    count +=1
print(count)

Fixed, accepted submission:
X = int(input())
money = 100
count = 0
while money < X:
    money = int(money*1.01) 
    count +=1
print(count)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
def main():

    N = int(input())
    a = {i: inp for i, inp in enumerate(map(int, input().split()), 1)}
        
    M = 0
    b = {i : 0 for i in range(1, N+1)}

    for i in range(N, 0, -1):
        sum_multiple = 0
        cursor = 2
        while i * cursor <= N:
            sum_multiple += a[i * cursor]
            cursor += 1

        if a[i] == 1:
            if sum_multiple % 2:
                b[i] = 0
            else:
                b[i] = 1
                M += 1
        else:
            if sum_multiple % 2:
                b[i] = 1
                M += 1
            else:
                b[i] = 0

    b = [str(value) for value in b.values()]
    b = ' '.join(b)

    print(M)
    print(b)

if __name__=="__main__":
    main()

Fixed, accepted submission:
def main():

    N = int(input())
    a = {i: inp for i, inp in enumerate(map(int, input().split()), 1)}
        
    b = {i : 0 for i in range(1, N+1)}
    ret = []

    for i in range(N, 0, -1):
        sum_multiple = 0
        cursor = 2
        while i * cursor <= N:
            sum_multiple += b[i * cursor]
            cursor += 1

        if a[i] == 1:
            if sum_multiple % 2 == 0:
                b[i] = 1
                ret.append(i)
        else:
            if sum_multiple % 2:
                b[i] = 1
                ret.append(i)

    M = len(ret)
    print(M)
    if M:
        ret = ' '.join([str(i) for i in ret])
        print(ret)

if __name__=="__main__":
    main()
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Time Limit Exceeded):
N = int(input())
s = input()
i = 1
li = []
charas = 'abcdefghijklmnopqrstuvwxyz'
while i < N:
  m = 0
  s1 = s[0:i]
  s2 = s[i:]
  for chara in charas:
    if chara in s1 and chara in s2:
      m += 1
  li.append(m)
print(max(li))

Fixed, accepted submission:
N = int(input())
s = input()
i = 1
li = []
charas = 'abcdefghijklmnopqrstuvwxyz'
while i < N:
  m = 0
  s1 = s[0:i]
  s2 = s[i:]
  for chara in charas:
    if chara in s1 and chara in s2:
      m += 1
  li.append(m)
  i += 1
print(max(li))
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
num = list(map(int,input().split()))
k = int(input())
num.sort()
print(sum(num[:2])+num[-1]**k)

Fixed, accepted submission:
num = list(map(int,input().split()))
k = int(input())
num.sort()
print(sum(num[:2])+num[-1] * 2**k)
Problem:
In a factory, there are N robots placed on a number line. Robot i is placed at coordinate X_i and can extend its arms of length L_i in both directions, positive and negative.  We want to remove zero or more robots so that the movable ranges of arms of no two remaining robots intersect. Here, for each i (1 \leq i \leq N), the movable range of arms of Robot i is the part of the number line between the coordinates X_i - L_i and X_i + L_i, excluding the endpoints.  Find the maximum number of robots that we can keep.

Incorrect submission (verdict: Wrong Answer):
import sys
input=sys.stdin.buffer.readline

L=[]
for _ in range(int(input())):
  x,l=map(int,input().split())
  L.append((x-l,x+l))

L.sort(key=lambda x:x[1])
ans=0
cur=-1
for a,b in L:
  if a>=cur:
    cur=b
    ans+=1
print(ans)

Fixed, accepted submission:
import sys
input=sys.stdin.buffer.readline

L=[]
for _ in range(int(input())):
  x,l=map(int,input().split())
  L.append((x-l,x+l))

L.sort(key=lambda x:x[1])
ans=0
cur=-11111111111111111
for a,b in L:
  if a>=cur:
    cur=b
    ans+=1
print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
if a<=c<=b:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
a,b,c=map(int,input().split())
if a<=c<=b:
    print("Yes")
else:
    print("No")
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A, B, X = map( int, input().split())

D = A + B

if( D <= X):
  print('Yes')
  
if( X <= D):
  print('No')

Fixed, accepted submission:
A, B, X = map( int, input().split())

D = A + B

if( X <= D):
  if( A <= X):
    print('YES')
  
  else:
    print('NO')
    
else:
  print('NO')
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = []

for i in range(n):
  getn = int(input())
  a.append(getn)
  
b = set(a)

print(len(a)-len(b)+1)

Fixed, accepted submission:
n = int(input())
a = []

for i in range(n):
  getn = int(input())
  a.append(getn)
  
b = set(a)

print(len(b))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = input()
n = int(n)
ac = 0
wa = 0
tle = 0
re = 0
for i in range(n):
    wk = input()
    if wk == "AC":
        ac +=1
    elif wk == "WA":
        wa += 1
    elif wk == "TLE":
        tle += 1
    else :
        re += 1
print("AC × {0}".format(ac))
print("WA × {0}".format(wa))
print("TLE × {0}".format(tle))
print("RE × {0}".format(re))


Fixed, accepted submission:
n = input()
n = int(n)
ac = 0
wa = 0
tle = 0
re = 0
for i in range(n):
    wk = input()
    if wk == "AC":
        ac +=1
    elif wk == "WA":
        wa += 1
    elif wk == "TLE":
        tle += 1
    else :
        re += 1
print("AC x {0}".format(ac))
print("WA x {0}".format(wa))
print("TLE x {0}".format(tle))
print("RE x {0}".format(re))
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
N, L=map(int, input().split())
lst = []
ans = str()
for i in range(N):
    lst.append(input())
lst.sort

for i in range(len(lst)):
    ans += lst[i]
    
print(ans)

Fixed, accepted submission:
N, L=map(int, input().split())
lst = []
ans = ""
for i in range(N):
    lst.append(input())
lst.sort()

for i in range(len(lst)):
    ans += lst[i]
    
print(ans)
Problem:
Rng is preparing a problem set for a qualification round of CODEFESTIVAL.  He has N candidates of problems. The difficulty of the i-th candidate is D_i.  There must be M problems in the problem set, and the difficulty of the i-th problem must be T_i. Here, one candidate of a problem cannot be used as multiple problems.  Determine whether Rng can complete the problem set without creating new candidates of problems.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python
# coding: utf-8

# In[7]:


N = int(input())
D = list(map(int, input().split()))
M = int(input())
T = list(map(int, input().split()))


# In[8]:


for i,t in enumerate(T):
    if t in D:
        D.pop(D.index(t))
    else:
        print("No")
        break
else:
    print("Yes")


# In[ ]:






Fixed, accepted submission:
#!/usr/bin/env python
# coding: utf-8

# In[9]:


import collections


# In[32]:


N = int(input())
D = list(map(int, input().split()))
M = int(input())
T = list(map(int, input().split()))


# In[34]:


t_count = collections.Counter(T)
d_count = collections.Counter(D)

for key,c in t_count.items():
    if key in d_count.keys():
        if d_count[key] < c:
            print("NO")
            break
    else:
        print("NO")
        break
else:
    print("YES")


# In[ ]:
Problem:
You are going to hold a competition of one-to-one game called AtCoder Janken. _(Janken is the Japanese name for Rock-paper-scissors.)_ N players will participate in this competition, and they are given distinct integers from 1 through N. The arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive). You cannot assign the same integer to multiple playing fields. The competition consists of N rounds, each of which proceeds as follows:    * For each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.   * Then, each player adds 1 to its integer. If it becomes N+1, change it to 1.  You want to ensure that no player fights the same opponent more than once during the N rounds. Print an assignment of integers to the playing fields satisfying this condition. It can be proved that such an assignment always exists under the constraints given.

Incorrect submission (verdict: Wrong Answer):
N,M = map(int, input().split())

for i in range(M):
    a=i+1
    b=2*M-i
    print(a,b)

Fixed, accepted submission:
N,M = map(int, input().split())

M1 = M//2
M2 = M-M1

for i in range(M1):
    a=i+1
    b=2*M1+1-i
    print(a,b)
for i in range(M2):
    a=i+1
    b=2*M2-i
    print(2*M1+1 + a,2*M1+1 + b)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a%3==0 or b%3==0 or a+b%3==0:
  print("Possible")
else:
  print("Impossible")

Fixed, accepted submission:
a,b=map(int,input().split())
if a%3==0 or b%3==0 or (a+b)%3==0:
  print("Possible")
else:
  print("Impossible")