TnT/CodeNet4Repair huggingface dataset:
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
# Swapping Two Numbers

zeroCount = 0
while zeroCount == 0:
    numbers = [int(i) for i in input().rstrip().split()]
    # print(numbers)
    if numbers[0] == 0 and numbers[1] == 0:
        zeroCount += 1
    else:
        swap = sorted(numbers)
        # print(swap)
        output = [str(number) for number in swap]
        print(output)



Fixed, accepted submission:
# Swapping Two Numbers

zeroCount = 0
while zeroCount == 0:
    numbers = [int(i) for i in input().rstrip().split()]
    # print(numbers)
    if numbers[0] == 0 and numbers[1] == 0:
        zeroCount += 1
    else:
        swap = sorted(numbers)
        # print(swap)
        a = [str(n) for n in swap]
        print(" ".join(a))
Problem:
There is a grid with H horizontal rows and W vertical columns. Let (i, j) denote the square at the i-th row from the top and the j-th column from the left.  For each i and j (1 \leq i \leq H, 1 \leq j \leq W), Square (i, j) is described by a character a_{i, j}. If a_{i, j} is `.`, Square (i, j) is an empty square; if a_{i, j} is `#`, Square (i, j) is a wall square. It is guaranteed that Squares (1, 1) and (H, W) are empty squares.  Taro will start from Square (1, 1) and reach (H, W) by repeatedly moving right or down to an adjacent empty square.  Find the number of Taro's paths from Square (1, 1) to (H, W). As the answer can be extremely large, find the count modulo 10^9 + 7.

Incorrect submission (verdict: Wrong Answer):
n , m = map(int , input().split())
dp = [[1 for j in range(m + 1)] for i in range(n + 1)]
for i in range(n + 1):
    dp.append([])
    for j in range(m + 1):
        dp[i].append(0)
arr = []
for i in range(n):
    arr.append(input())
dp[1][1] = 1
for i in range(1,n + 1):
    for j in range(1,m + 1):
        if arr[i - 1][j - 1] == '#' or (i == 1 and j == 1):
            continue
        dp[i][j] = dp[i - 1][j] + dp[i][j - 1]
print(dp[n][m] % 1000000007)


Fixed, accepted submission:
n , m = map(int , input().split())
dp = []
for i in range(n + 1):
    dp.append([])
    for j in range(m + 1):
        dp[i].append(0)
arr = []
for i in range(n):
    arr.append(input())
dp[1][1] = 1
for i in range(1,n + 1):
    for j in range(1,m + 1):
        if arr[i - 1][j - 1] == '#' or (i == 1 and j == 1):
            continue
        dp[i][j] = dp[i - 1][j] + dp[i][j - 1]
print(dp[n][m] % 1000000007)
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a,b,c=(int(x) for x in input().split())
k=int(input())
flag=True
for i in range(k+1):
    if a<2**(k-i)*b and 2**(k-i)*b<2**i*c:
        print("Yes",i)
        exit()
        flag=False
        break
if flag:
    print("No")

Fixed, accepted submission:
a,b,c=(int(x) for x in input().split())
k=int(input())
flag=True
for i in range(k+1):
    if a<2**(k-i)*b and 2**(k-i)*b<2**i*c:
        print("Yes")
        exit()
        flag=False
        break
if flag:
    print("No")
Problem:
A country has a budget of more than 81 trillion yen. We want to process such data, but conventional integer type which uses signed 32 bit can represent up to 2,147,483,647.  Your task is to write a program which reads two integers (more than or equal to zero), and prints a sum of these integers.  If given integers or the sum have more than 80 digits, print "overflow".

Incorrect submission (verdict: Wrong Answer):
from collections import deque




def align_digit(a, b):
    la, lb = len(a), len(b)
    if la < lb:
        a = a.zfill(lb)
    elif lb < la:
        b = b.zfill(la)
    return a, b


def split_to_ints(s, n=10):
    length = len(s)
    return reversed([int(s[i:i + n]) for i in range(0, length, n)])


def add(a, b, n=10):
    a, b = align_digit(a, b)
    ints_a = split_to_ints(a, n)
    ints_b = split_to_ints(b, n)
    carry = 0
    result = deque()

    zipped = list(zip(ints_a, ints_b))
    for i, (int_a, int_b) in enumerate(zipped):
        s = int_a + int_b + carry
        carry = int(s / (10 ** n))
        if i != len(zipped) - 1:
            result.append(str(s % (10 ** (n - 1))).zfill(n))
        else:
            result.append(str(s))
        i += 1
    return str(int(''.join(result)))


if __name__ == '__main__':
    n_input = int(input())
    for i in range(n_input):
        a, b = input(), input()
        #print(a + b)
        print(add(a, b))


Fixed, accepted submission:
# 12,432 -> 012,432
def align_digits(a, b):
    la, lb = len(a), len(b)
    if la < lb:
        a = a.zfill(lb)
    elif lb < la:
        b = b.zfill(la)
    return a, b


def add(a, b):
    a, b = align_digits(a, b)
    zipped = list(zip(a[::-1], b[::-1]))
    carry = 0
    result = []
    for i, z in enumerate(zipped):
        a, b = z
        s = int(a) + int(b) + carry
        carry = int(s / 10)
        if i == len(zipped) - 1:
            result.append(str(s))
        else:
            result.append(str(s % 10))
    ans = ''.join(result[::-1])
    if len(ans) > 80:
        return 'overflow'
    return ans


if __name__ == '__main__':
    n_input = int(input())
    inputs = []
    for i in range(n_input):
        inputs.append((input(), input()))
    for a, b in inputs:
        print(add(a, b))
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
import numpy

Fixed, accepted submission:
import numpy as np
n = input()
l = np.array(list(map(int,input().split())))
counter = 0
while True:
    if not (l%2==0).all():
        break
    l = l/2
    counter+=1
print(counter)
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while True:
    Input = input().split()
    a = int(Input[0])
    op = Input[1]
    b = int(Input[2])
    if a >= 0 and b >= 0 and a <= 20000 and b <= 20000:
        if op == "+":
            print(a + b)
        elif op == "-":
            print(a - b)
        elif op == "*":
            print(a * b)
        elif op == "/":
            if b != 0:
                print(a / b)
        elif op == "?":
            break

Fixed, accepted submission:
while True:
    Input = input().split()
    a = int(Input[0])
    op = Input[1]
    b = int(Input[2])
    if a >= 0 and b >= 0 and a <= 20000 and b <= 20000:
        if op == "+":
            print(a + b)
        elif op == "-":
            print(a - b)
        elif op == "*":
            print(a * b)
        elif op == "/":
            if b != 0:
                print(int(a / b))
        elif op == "?":
            break
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
data = []
for i in range(N):
    data.append(list(map(int, input().split())))

t, x, y = 0, 0, 0
for i in range(N):
    deltaT = data[i][0] - t
    absX = abs(data[i][1] - x)
    absY = abs(data[i][2] - y)
    prob = deltaT - absX - absY
    if not prob >= 0 and prob % 2 == 0:
        print("NO")
        quit()
print("YES")


Fixed, accepted submission:
N = int(input())
data = []
for i in range(N):
    data.append(list(map(int, input().split())))
if N == 1:
    prob = data[0][0] - data[0][1] - data[0][2]
    if prob < 0 or prob % 2 != 0:
        print("No")
    else:
        print("Yes")
    quit()
for i in range(N-1):
    t = data[i][0]
    x = data[i][1]
    y = data[i][2]
    deltaT = data[i+1][0] - t
    absX = abs(data[i+1][1] - x)
    absY = abs(data[i+1][2] - y)
    prob = deltaT - absX - absY
    if prob < 0 or prob % 2 != 0:
        print("No")
        quit()
print("Yes")
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
s = list(str(input()))
s.sort()
a = [chr(ord('a') + i) for i in range(26)]
b = {}
for i in a:
    b[i] = 0
for i in s:
    b[i] += 1

alf = ''
for i in a:
    if b[i] == 0:
        print(i)
        alf = i
        break
if alf:
    print(i)
else:
    print('None')


Fixed, accepted submission:
s = list(str(input()))
s.sort()
a = [chr(ord('a') + i) for i in range(26)]
b = {}
for i in a:
    b[i] = 0
for i in s:
    b[i] += 1

alf = ''
for i in a:
    if b[i] == 0:
        alf = i
        break
if alf:
    print(i)
else:
    print('None')
Problem:
Joisino wants to evaluate the formula "A op B". Here, A and B are integers, and the binary operator op is either `+` or `-`. Your task is to evaluate the formula instead of her.

Incorrect submission (verdict: Wrong Answer):
import sys
from io import StringIO
import unittest


def resolve():
    input_string = list(input())
    num1 = int(input_string[0])
    num2 = int(input_string[4])
    operater = input_string[2]
    
    result = 0
    if operater == "+":
        result = num1 + num2
    elif operater == "-":
        result = num1 - num2
    
    print(result)


class TestClass(unittest.TestCase):
    def assertIO(self, input, output):
        stdout, stdin = sys.stdout, sys.stdin
        sys.stdout, sys.stdin = StringIO(), StringIO(input)
        resolve()
        sys.stdout.seek(0)
        out = sys.stdout.read()[:-1]
        sys.stdout, sys.stdin = stdout, stdin
        self.assertEqual(out, output)
    def test_入力例_1(self):
        input = """1 + 2"""
        output = """3"""
        self.assertIO(input, output)
    def test_入力例_2(self):
        input = """5 - 7"""
        output = """-2"""
        self.assertIO(input, output)

if __name__ == "__main__":
    unittest.main()

Fixed, accepted submission:
input_string = input().split()
num1 = int(input_string[0])
num2 = int(input_string[2])
operater = input_string[1]

result = 0
if operater == "+":
    result = num1 + num2
elif operater == "-":
    result = num1 - num2

print(result)
Problem:
On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).  A red point and a blue point can form a _friendly pair_ when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.  At most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = [0 for i in range(N)]
b = [0 for i in range(N)]
c = [0 for i in range(N)]
d = [0 for i in range(N)]
for i in range(N):
    a[i],b[i] = map(int,input().split())
for i in range(N):
    c[i],d[i] = map(int,input().split())
cnt = 0
fin = []
for i in range(N):
    f = 0
    s1 = 100000000000
    s2 = 100000000000
    tmp1 = 100000000000
    tmp2 = 100000000000
    for j in range(N):            
        tmp1 = a[i] - c[j]
        tmp2 = b[i] - d[j]
        if tmp1 < 0 and tmp2 < 0:
            s1 = abs(tmp1) + abs(tmp2)
            #print(i,j)
            if s1 < s2 :
                ti = i
                tj = j
                s2 = s1
                f = 1
    if f == 1 and not (j in fin) :
        fin.append(tj)
        cnt += 1
        print(ti,tj)
print(cnt)

Fixed, accepted submission:
N = int(input())
r = [list(map(int,input().split())) for _ in range(N)]
b = [list(map(int,input().split())) for _ in range(N)]
r.sort(key = lambda x:x[1],reverse = True)
b.sort(key = lambda x:x[0])
cnt = 0
fin = []
for i in range(N):
    for j in range(N):
        if b[i][0] > r[j][0] and b[i][1] > r[j][1]:
            if not(j in fin):
                cnt += 1
                fin.append(j)
                break
print(cnt)
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
import itertools

h, w, k = list(map(int, input().split()))
def convert(char):
  if char == '.':
    return 0
  else:
    return 1

def add_elements(c, row, column):
  s = 0
  for i in range(h):
    for j in range(w):
      if (i not in row) and (j not in column):
        s += c[i,j]
  return s

c = np.empty((h, w))

ans = 0

for i in range(h):
  line = list(map(convert, list(input())))
  c[i,:] = np.array(line)

for i in range(h+1):
  for j in range(w+1):
    rows = list(itertools.combinations(range(h),i))
    columns = list(itertools.combinations(range(h),j))
    for row in rows:
      for column in columns:
        s = add_elements(c, row, column)
        if s == k:
          ans += 1

print(ans)



Fixed, accepted submission:
import numpy as np
import itertools

h, w, k = list(map(int, input().split()))
def convert(char):
  if char == '.':
    return 0
  else:
    return 1

def add_elements(c, row, column):
  s = 0
  for i in range(h):
    for j in range(w):
      if (i not in row) and (j not in column):
        s += c[i,j]
  return s

c = np.empty((h, w))

ans = 0

for i in range(h):
  line = list(map(convert, list(input())))
  c[i,:] = np.array(line)

for i in range(h+1):
  for j in range(w+1):
    rows = list(itertools.combinations(range(h),i))
    columns = list(itertools.combinations(range(w),j))
    for row in rows:
      for column in columns:
        s = add_elements(c, row, column)
        if s == k:
          ans += 1

print(ans)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline
from collections import deque
N, M = map(int, input().split())
C = [list(map(int, input().split())) for i in range(M)]

def bfs(room, now):
    # print(room, now)
    plan = deque([])
    # for r in room:
    #     plan.append(r)
    plan.append(room)
    # print(plan)
    visited[1][0] = True
    while plan:
        nextque = plan.popleft()
        # print(nextque)
        for i in PATH[now]:
            if visited[i][0] == True:
                # print('true')
                continue
            else:
                # for r in PATH[next]:
                #     plan.append(r)
                plan.append(PATH[i])
                # print(plan)
                visited[i][0] = True
                visited[i][1] = now
        now = i

if __name__ == '__main__':
    PATH = [[] for i in range(N+1)]
    
    for i in range(M):
        PATH[C[i][0]].append(C[i][1])
        PATH[C[i][1]].append(C[i][0])
    # print(PATH)
    visited = [[False,0] for i in range(N+1)]
    bfs(PATH[1], 1)
    # print(visited)
    for i in range(2,N+1):
        print(visited[i][1])


Fixed, accepted submission:
import sys
input = sys.stdin.readline
from collections import deque
N, M = map(int, input().split())
C = [list(map(int, input().split())) for i in range(M)]

def bfs(now):
    plan = deque([])
    plan.append(now)
    visited[now][0] = True
    while plan:
        now = plan.popleft()
        for i in PATH[now]:
            if visited[i][0] == True:
                continue
            else:
                plan.append(i)
                visited[i][0] = True
                visited[i][1] = now

if __name__ == '__main__':
    PATH = [deque([]) for i in range(N+1)]
    
    for i in range(M):
        PATH[C[i][0]].append(C[i][1])
        PATH[C[i][1]].append(C[i][0])
    visited = [[False,0] for i in range(N+1)]
    bfs(1)
    print("Yes")
    for i in range(2,N+1):
        print(visited[i][1])
Problem:
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.  Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.  Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)  At most how much can he earn on balance?  Note that the same string may be written on multiple cards.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter
n=int(input())
S=[input() for i in range(n)]
S=dict(Counter(S).most_common())
m=int(input())
T=[input() for i in range(m)]
T=dict(Counter(T).most_common())

for i in S:
  for k in T:
    if i==k:
      S[i] -= T[i]

if S[max(S)]< 0:
  print(0)
else:
  print(S[max(S)])


Fixed, accepted submission:
from collections import Counter
n=int(input())
S=[input() for i in range(n)]
S=dict(Counter(S).most_common())
m=int(input())
T=[input() for i in range(m)]
T=dict(Counter(T).most_common())

for i in S:
  for k in T:
    if i==k:
      S[i] -= T[k]

S=sorted(S.items(),key=lambda x:x[1],reverse=True)

if S[0][1] < 0:
  print(0)
else:
  print(S[0][1])
Problem:
You are given three integers A, B and C.  Determine if there exists an equilateral triangle whose sides have lengths A, B and C.

Incorrect submission (verdict: Wrong Answer):
_input = list(map(int, input().split(" ")))
_input.sort()

_A = _input[0] * _input[0]
_B = _input[1] * _input[1]
_C = _input[2] * _input[2]

if _A + _B == _C:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
_input = input().split(" ")
_A = int(_input[0])
_B = int(_input[1])
_C = int(_input[2])

if _A == _B and _A == _C:
  print("Yes")
else:
  print("No")
Problem:
Write a program which reads three integers a, b and c, and prints "Yes" if a < b < c, otherwise "No".

Incorrect submission (verdict: Wrong Answer):
# 04-Branch_on_Condition-Range.py

# ??????


# Input

# Output
# Yes?????????No????????????????????????????????????

# Sample Input 1
# 1 3 8
# Sample Output 1
# Yes
# Sample Input 2
# 3 8 1
# Sample Output 2
# No

print("a,b,c?????\??????")
a,b,c=map(int,input().split())
print("a=%d, b=%d, c=%d."%(a,b,c))

if a<b and b<c:
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
# 04-Branch_on_Condition-Range.py

# ??????


# Input

# Output
# Yes?????????No????????????????????????????????????

# Sample Input 1
# 1 3 8
# Sample Output 1
# Yes
# Sample Input 2
# 3 8 1
# Sample Output 2
# No

# print("a,b,c?????\??????")
a,b,c=map(int,input().split())
# print("a=%d, b=%d, c=%d."%(a,b,c))

if a<b and b<c:
	print("Yes")
else:
	print("No")
Problem:
It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.   There are N houses along _TopCoDeer street_. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.   Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Incorrect submission (verdict: Wrong Answer):
import sys
import itertools
sys.setrecursionlimit(1000000000)
from heapq import heapify,heappop,heappush,heappushpop
import math
import collections
MOD = 10**9 + 7

n = int(input())
a = list(map(int,input().split()))
ans = 0
for i in a:
    cost = 0
    for j in a:
        d = abs(i-j)
        cost += d
    ans = max(ans,cost)
print(ans)

Fixed, accepted submission:
import sys
import itertools
sys.setrecursionlimit(1000000000)
from heapq import heapify,heappop,heappush,heappushpop
import math
import collections
MOD = 10**9 + 7

n = int(input())
a = sorted(list(map(int,input().split())))
print(a[-1]-a[0])
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split())
t=x-a
if t<=b:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a,b,x=map(int,input().split())
if a<=x<=a+b:
  print("YES")
else:
  print("NO")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
div, mod = divmod(int(input()), 1000)
print(mod)

Fixed, accepted submission:
div,mod = divmod(int(input()), 1000)
print((1000 - mod) % 1000)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math
x = int(input())
a = 100
i = 0
while a < x:
  i = i + 1
  a = math.floor(a * 1.01)
print(i, a)

Fixed, accepted submission:
import math
x = int(input())
a = 100
i = 0
while a < x:
  i = i + 1
  a = math.floor(a * 1.01)
print(i)
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int, input().split())
print("YES" if A+B >C else "NO")

Fixed, accepted submission:
A, B, C = map(int, input().split())
print("Yes" if A + B >= C else "No")