TnT/CodeNet4Repair huggingface dataset:
Problem:
It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.  You are given an integer N. Find the N-th Lucas number.  Here, the i-th Lucas number L_i is defined as follows:    * L_0=2   * L_1=1   * L_i=L_{i-1}+L_{i-2} (i≥2)

Incorrect submission (verdict: Wrong Answer):
# -*- cooding utf-8 -*-
n=int(input())
l=[2,1]

for i in range(2,n-1):
    l.append(l[i-2]+l[i-1])

print(l[-1])


Fixed, accepted submission:
n=int(input())
L=[2,1]


for i in range(2,n+1):
    x=L[-1]+L[-2]
    L.append(x)

print(L[-1])
Problem:
You start with the number 0 and you want to reach the number N.  You can change the number, paying a certain amount of coins, with the following operations:    * Multiply the number by 2, paying A coins.   * Multiply the number by 3, paying B coins.   * Multiply the number by 5, paying C coins.   * Increase or decrease the number by 1, paying D coins.  You can perform these operations in arbitrary order and an arbitrary number of times.  What is the minimum number of coins you need to reach N?  **You have to solve T testcases.**

Incorrect submission (verdict: Time Limit Exceeded):
import heapq



def pay(N,A,B,C,D):
  q = []
  heapq.heapify(q)
  num = {}
  num[0] = 0
  num[-1] = -1
  heapq.heappush(q,( 0, 0 ))
  while q:
    c, n = heapq.heappop(q)
#    print(n,c)
    if n == N:
      break
    if num.setdefault(n*2,N*D+1) > c+A:
      heapq.heappush(q,( c+A, n*2 ))
      num[n*2] = c+A
    if num.setdefault(n*3,N*D+1) > c+B:
      heapq.heappush(q,( c+B, n*3 ))
      num[n*3] = c+B
    if num.setdefault(n*5,N*D+1) > c+C:
      heapq.heappush(q,( c+C, n*5 ))
      num[n*5] = c+C
    if num.setdefault(n+1,N*D+1) > c+D:
      heapq.heappush(q,( c+D, n+1 ))
      num[n+1] = c+D
    if num.setdefault(n-1,N*D+1) > c+D:
      heapq.heappush(q,( c+D, n-1 ))
      num[n-1] = c+D
  #
  print(num.setdefault(N,-1))
#

T = int(input())
for i in range(T):
  N,A,B,C,D = map(int, input().split())
  pay(N,A,B,C,D)


Fixed, accepted submission:
import heapq

def pay2win():
  num = set()
  q = []
  heapq.heapify(q)
  heapq.heappush(q,( 0, N ))
  cost = N*D
  while q:
    c0, n0 = heapq.heappop(q)
    if n0 in num:
      continue
    num.add(n0)
    if n0 == 0:
      break
    if c0 >= cost:
      break
    cost = min(cost,c0+n0*D)
    #
    n2, m = divmod(n0, 2)
    if m == 0:
      heapq.heappush(q,( c0+A, n2 ))
    else:
      heapq.heappush(q,( c0+D+A, n2 ))
      heapq.heappush(q,( c0+D+A, n2+1 ))
    #
    n3, m = divmod(n0, 3)
    if m == 0:
      heapq.heappush(q,( c0+B, n3 ))
    elif m == 1:
      heapq.heappush(q,( c0+D+B, n3 ))
    else:
      heapq.heappush(q,( c0+D+B, n3+1 ))
    #
    n5, m = divmod(n0, 5)
    if m == 0:
      heapq.heappush(q,( c0+C, n5 ))
    elif m <= 2:
      heapq.heappush(q,( c0+D*m+C, n5 ))
    else:
      heapq.heappush(q,( c0+D*(5-m)+C, n5+1 ))
    #
  print(cost)
#

T = int(input())
for i in range(T):
  N,A,B,C,D = map(int, input().split())
  pay2win()
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from collections import deque

n,m = map(int,input().split())
graph = [[] for i in range(n)]
mark = [0]*n

for i in range(m):
    a, b = map(int,input().split())
    a -=1; b -=1
    graph[a].append(b)
    graph[b].append(a)

d = deque([0])
visited = [False]*n
visited[0] = True

while d:
    v = d.popleft()
    for i in graph[v]:
        if visited[i]:continue
        visited[i] = True
        mark[i] = v
        d.append(i)



print('Yes')

for i in mark:
    print(i+1)

Fixed, accepted submission:
from collections import deque

n,m = map(int,input().split())
graph = [[] for i in range(n)]
mark = [0]*n

for i in range(m):
    a, b = map(int,input().split())
    a -=1; b -=1
    graph[a].append(b)
    graph[b].append(a)

d = deque([0])
visited = [False]*n
visited[0] = True

while d:
    v = d.popleft()
    for i in graph[v]:
        if visited[i]:continue
        visited[i] = True
        mark[i] = v
        d.append(i)



print('Yes')

for i in mark[1:]:
    print(i+1)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
n=0
for i in range(b):
    if a*(i+1)%b==c:
        print("Yes")
        break
    n+=1
if n==b:
    print("No")

Fixed, accepted submission:
a,b,c=map(int,input().split())
n=0
for i in range(b):
    if a*(i+1)%b==c:
        print("YES")
        break
    n+=1
if n==b:
    print("NO")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
print(N%1000)

Fixed, accepted submission:
N=int(input())
print((1000-N%1000)%1000)
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
A = input()
count = 0
p = len(A)
min_=200000
max_=0
for i in range(p):
  if (A[i] == 'A'):
    min_ = min(i,min_)
    print(min_)
  if (A[i] == 'Z'):
    max_ = max(i,max_)
    print(max_)
print(max_-min_+1)

Fixed, accepted submission:
A = input()
count = 0
p = len(A)
min_=200000
max_=0
for i in range(p):
  if (A[i] == 'A'):
    min_ = min(i,min_)
  if (A[i] == 'Z'):
    max_ = max(i,max_)
print(max_-min_+1)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline

A,B,K = list(map(int,input().split()))
num_lis = []
for i in range(A,A+K):
    if i <= B:
        num_lis.append(i)
    else:
        break
    
for i in range(B,B-K,-1):
    if i>= A:
        num_lis.append(i)
    else:
        break
b = sorted(list(set(num_lis)))
print(b)


Fixed, accepted submission:
import sys
input = sys.stdin.readline

A,B,K = list(map(int,input().split()))
num_lis = []
for i in range(A,A+K):
    if i <= B:
        num_lis.append(i)
    else:
        break
    
for i in range(B,B-K,-1):
    if i>= A:
        num_lis.append(i)
    else:
        break
b = sorted(list(set(num_lis)))

for i in range(len(b)):
    print(b[i])
Problem:
Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.  You are given Smeke's current rating, x. Print `ABC` if Smeke will participate in ABC, and print `ARC` otherwise.

Incorrect submission (verdict: Wrong Answer):
import itertools
s = list(input())
s1 = list(itertools.dropwhile(lambda x: x != 'A',s))
s2 = list(itertools.dropwhile(lambda x: x != 'Z',s1[::-1]))
print(len(s2))

Fixed, accepted submission:
x = int(input())
ans = "ABC" if x < 1200 else "ARC"
print(ans)
Problem:
Two foxes Jiro and Saburo are playing a game called _1D Reversi_. This game is played on a board, using black and white stones. On the board, stones are placed in a row, and each player places a new stone to either end of the row. Similarly to the original game of Reversi, when a white stone is placed, all black stones between the new white stone and another white stone, turn into white stones, and vice versa.  In the middle of a game, something came up and Saburo has to leave the game. The state of the board at this point is described by a string S. There are |S| (the length of S) stones on the board, and each character in S represents the color of the i-th (1 ≦ i ≦ |S|) stone from the left. If the i-th character in S is `B`, it means that the color of the corresponding stone on the board is black. Similarly, if the i-th character in S is `W`, it means that the color of the corresponding stone is white.  Jiro wants all stones on the board to be of the same color. For this purpose, he will place new stones on the board according to the rules. Find the minimum number of new stones that he needs to place.

Incorrect submission (verdict: Wrong Answer):
#n = int(input())
#n,k = map(int,input().split())
#x = list(map(int,input().split()))


s = list(input())

cnt = 0

for i in range(len(s)):
    if s[i-1] != s[i]:
        cnt += 1

print(cnt)



Fixed, accepted submission:
#n = int(input())
#n,k = map(int,input().split())
#x = list(map(int,input().split()))


s = list(input())

cnt = 0

for i in range(1,len(s)):
    if s[i-1] != s[i]:
        cnt += 1

print(cnt)
Problem:
_n_ _q_   _name 1 time1_   _name 2 time2_   ...   _name n timen_    In the first line the number of processes _n_ and the quantum _q_ are given separated by a single space.  In the following _n_ lines, names and times for the _n_ processes are given. _name i_ and _time i_ are separated by a single space.

Incorrect submission (verdict: Wrong Answer):


class MyQueue:
    def __init__(self):
        self.queue = [] # list
        self.top = 0
    
    def isEmpty(self):
        if self.top==0:
            return True
        return False
    
    def isFull(self):
        pass

    def enqueue(self, x):
        self.queue.append(x)
        self.top += 1
    
    def dequeue(self):
        if self.top>0:
            self.top -= 1
            return self.queue.pop()
        else:
            print("there aren't enough values in Queue")

def main():
    n, q = map(int, input().split())
    A = [
        list(map(lambda x: int(x) if x.isdigit() else x, input().split()))
        for i in range(n)
    ]
    A = [{'name': name, 'time': time} for name, time in A]
    queue = MyQueue()
    for a in A:
        queue.enqueue(a)
    elapsed = 0
    while not queue.isEmpty():
        elapsed += q
        job = queue.dequeue()
        job['time'] = job['time'] - q
        if job['time']>0:
            queue.enqueue(job)
        else:
            print(job['name']+ ' ' + str(elapsed))

main()


Fixed, accepted submission:


class MyQueue:
    def __init__(self):
        self.queue = [] # list
        self.top = 0
    
    def isEmpty(self):
        if self.top==0:
            return True
        return False
    
    def isFull(self):
        pass

    def enqueue(self, x):
        self.queue.append(x)
        self.top += 1
    
    def dequeue(self):
        if self.top>0:
            self.top -= 1            
            return self.queue.pop(0)
        else:
            print("there aren't enough values in Queue")

def main():
    n, q = map(int, input().split())
    A = [
        list(map(lambda x: int(x) if x.isdigit() else x, input().split()))
        for i in range(n)
    ]
    A = [{'name': name, 'time': time} for name, time in A]
    queue = MyQueue()
    for a in A:
        queue.enqueue(a)
    elapsed = 0
    while not queue.isEmpty():        
        job = queue.dequeue()        
        if job['time']>q:
            elapsed += q
            job['time'] = job['time'] - q
            queue.enqueue(job)
        else:
            elapsed += job['time']
            print(job['name']+ ' ' + str(elapsed))

main()
Problem:
There is a data which provides heights (in meter) of mountains. The data is only for ten mountains.  Write a program which prints heights of the top three mountains in descending order.

Incorrect submission (verdict: Wrong Answer):
ans=[]
for i in range (0,10):
    ans.append(input())
ans.sort(reverse=True)
for i in range (0,3):
    print(ans[i])

Fixed, accepted submission:
ans=[]
for i in range (0,10):
    ans.append(int(input()))
ans.sort(reverse=True)
for i in range (0,3):
    print(ans[i])
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
NL = [ x for x in map(int,input().split()) ]
cha = []
i = 0
while i < NL[0]:
  cha.append(input())
  i += 1
print(sorted(cha))

Fixed, accepted submission:
NL = [ x for x in map(int,input().split()) ]
cha = []
i = 0
while i < NL[0]:
  cha.append(input())
  i += 1
print(''.join(sorted(cha)))
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
lis = list(map(int,input().split()))

cnt=0
n=0
for i in lis:
    if (i)%2 != 0 and n%2 != 0:
        cnt += 1
    n += 1
    print(n)
print(cnt)

Fixed, accepted submission:
n = int(input())
lis = list(map(int,input().split()))

cnt=0
n=1
for i in lis:
    if i%2 != 0 and n%2 != 0:
        cnt += 1
    n += 1
print(cnt)
Problem:
We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:    * For any two vertices painted in the same color, the distance between them is an even number.  Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
links=[set() for _ in [0]*N]
print(links)
for i in range(1,N):
  u,v,w=map(int,input().split())
  u-=1
  v-=1
  links[u].add((v,w))
  links[v].add((u,w))
ans=[-1]*N
q=[(0,0,-1)]
while q:
  v,d,p=q.pop()
  if d%2==0:
    ans[v]=0
  else:
    ans[v]=1
  for u,w in links[v]:
    if u==p:
      continue
    q.append((u,w+d,v))
print('\n'.join(map(str,ans)))

Fixed, accepted submission:
N=int(input())
links=[set() for _ in [0]*N]
for i in range(1,N):
  u,v,w=map(int,input().split())
  u-=1
  v-=1
  links[u].add((v,w))
  links[v].add((u,w))
ans=[-1]*N
q=[(0,0,-1)]
while q:
  v,d,p=q.pop()
  if d%2==0:
    ans[v]=0
  else:
    ans[v]=1
  for u,w in links[v]:
    if u==p:
      continue
    q.append((u,w+d,v))
print('\n'.join(map(str,ans)))
Problem:
How many multiples of d are there among the integers between L and R (inclusive)?

Incorrect submission (verdict: Wrong Answer):
L,S,R = map(int,input().split())
for i in range(L,S+1):
  if (i%R == 0):
    print(i)

Fixed, accepted submission:
L,S,R = map(int,input().split())
a = 0
for i in range(L,S+1):
  if (i%R == 0):
    a = a + 1
print(a)
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
x=int(input())
y=int(input())
x*x-y

Fixed, accepted submission:
x=int(input())
y=int(input())
print(x**2-y)
Problem:
In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands. For convenience, we will call them Island 1, Island 2, ..., Island N.  There are M kinds of regular boat services between these islands. Each service connects two islands. The i-th service connects Island a_i and Island b_i.  Cat Snuke is on Island 1 now, and wants to go to Island N. However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.  Help him.

Incorrect submission (verdict: Wrong Answer):
n,m=map(int,input().split())
s=[]
k=[]
for i in range(m):
    a,b=map(int,input().split())
    if a==1:
        s.append(b)
    if b==n:
        k.append(1)
s_i=set(s)
k_i=set(k)
for _ in s_i:
    if _ in k_i:
        print("POSSIBLE")
        break
else:
    print("IMPOSSIBLE")
    

Fixed, accepted submission:
n,m=map(int,input().split())
t=[tuple(map(int,input().split()))for i in range(m)]
ans=[]
ans_2=[]
for i in range(m):
    if t[i][0]==1:
        ans.append(t[i][1])
    if t[i][1]==n:
        ans_2.append(t[i][0])
a=set(ans)
b=set(ans_2)
if a&b:
    print("POSSIBLE")
else:
    print("IMPOSSIBLE")
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
a=int(input())
if a % 2 == 0:
    print(a / 2-1)
else:
    print((a-1)/2) 


Fixed, accepted submission:
a=int(input())
if a % 2 == 0:
    print(str(int(a / 2-1)))
else:
    print(str(int((a-1)/2)))
Problem:
There is an apple tree that bears apples of N colors. The N colors of these apples are numbered 1 to N, and there are a_i apples of Color i.  You and Lunlun the dachshund alternately perform the following operation (starting from you):    * Choose one or more apples from the tree and eat them. Here, the apples chosen at the same time must all have different colors.  The one who eats the last apple from the tree will be declared winner. If both you and Lunlun play optimally, which will win?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = [int(input()) for i in range(n)]
for i in a:
    if i%2==1:
        print('frist')
        exit()
print('second')

Fixed, accepted submission:
n = int(input())
a = [int(input()) for i in range(n)]
for i in a:
    if i%2==1:
        print('first')
        exit()
print('second')
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int,input().split())
ans = 0
for i in range(n):
  ione = i%10
  iten = i//10
  if a<=(ione+iten)<=b:
    ans += i
  
print(ans)

Fixed, accepted submission:
N, A, B = map(int, input().split())
ans = 0
for i in range(1, N+1):
  if A <= sum(map(int, list(str(i)))) <= B:
    ans += i
 
print(ans)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
a.sort()

alice = sum(a[0:n:2])
bob = sum(a[1:n:2])

print(alice - bob)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
a.sort(reverse = True)

alice = sum(a[0:n:2])
bob = sum(a[1:n:2])

print(alice - bob)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Time Limit Exceeded):
n, a, b = map(int, input().split())
ans = 0

for i in range(1,n+1):
    mod = 0
    while n != 0:
        mod = mod + (i % 10)
        i = i // 10
    if mod >= a and mod <= b:
        ans += mod

print(ans)


Fixed, accepted submission:
n, a, b = map(int, input().split())
ans = 0

for i in range(1,n+1):
    mod = 0
    div = i
    while div > 0:
        mod += (div % 10)
        div //= 10
    if mod >= a and mod <= b:
        ans += i

print(ans)
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
s = list(input())
str = ""

for i in range(len(s)):
  if s[i] == 'B':
    str = str[0:-2]
  else:
    str += s[i]

print(str)


Fixed, accepted submission:
s = list(input())
str = ""

for i in range(len(s)):
  if s[i] == 'B':
    str = str[0:-1]
  else:
    str += s[i]

print(str)
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
sum = 0
for i in range(n):
        a = input().split()
        if a[1] == 'BTC':
                sum += float(a[0])*380000
        else:
                sum += float(a[0])
        print(sum)

Fixed, accepted submission:
n = int(input())
sum = 0
for i in range(n):
        a = input().split()
        if a[1] == 'BTC':
                sum += float(a[0])*380000
        else:
                sum += float(a[0])
print(sum)
Problem:
You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Incorrect submission (verdict: Wrong Answer):
N = list(map(int, input().split()))

print('Yes' if 1 in N and 4 in N and 7 in N and 9 in N else 'No')


Fixed, accepted submission:
N = list(map(int, input().split()))

print('YES' if 1 in N and 4 in N and 7 in N and 9 in N else 'NO')