Problem:
There are N sightseeing spots on the x-axis, numbered 1, 2, ..., N. Spot i is at the point with coordinate A_i. It costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.  You planned a trip along the axis. In this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.  However, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i. You will visit the remaining spots as planned in the order they are numbered. You will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.  For each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.

Incorrect submission (verdict: Wrong Answer):
#!usr/bin/env python3
from collections import defaultdict
from heapq import heappush, heappop
import sys
import math
import bisect
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return list(sys.stdin.readline())
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
mod = 1000000007

#A
"""
a = IR(2)
b = IR(2)
print(min(a)+min(b))
"""

#B
"""
n = I()
d, x = LI()
a = IR(n)
ans = x
for i in a:
    k = 0
    while k * i + 1 <= d:
        ans += 1
        k += 1
print(ans)
"""

#C
n = I()
a = LI()
a.insert(0, 0)
a.append(0)
ans = 0
for i in range(1, n + 2):
    ans += abs(a[i] - a[i - 1])
print(ans)
for k in range(1, n + 1):
    if a[k - 1] < a[k]:
        if a[k] > a[k + 1]:
            print(ans - 2 * min(abs(a[k] - a[k - 1]), abs(a[k] - a[k + 1])))
        else:
            print(ans)
    if a[k - 1] > a[k]:
        if a[k] < a[k + 1]:
            print(ans - 2 * min(abs(a[k] - a[k - 1]), abs(a[k] - a[k + 1])))
        else:
            print(ans)

Fixed, accepted submission:
#!usr/bin/env python3
from collections import defaultdict
from heapq import heappush, heappop
import sys
import math
import bisect
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return list(sys.stdin.readline())
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
mod = 1000000007

#A
"""
a = IR(2)
b = IR(2)
print(min(a)+min(b))
"""

#B
"""
n = I()
d, x = LI()
a = IR(n)
ans = x
for i in a:
    k = 0
    while k * i + 1 <= d:
        ans += 1
        k += 1
print(ans)
"""

#C
n = I()
a = LI()
a.insert(0, 0)
a.append(0)
ans = 0
for i in range(1, n + 2):
    ans += abs(a[i] - a[i - 1])
#print(ans)
for k in range(1, n + 1):
    if a[k - 1] < a[k]:
        if a[k] > a[k + 1]:
            print(ans - 2 * min(abs(a[k] - a[k - 1]), abs(a[k] - a[k + 1])))
        else:
            print(ans)
    if a[k - 1] > a[k]:
        if a[k] < a[k + 1]:
            print(ans - 2 * min(abs(a[k] - a[k - 1]), abs(a[k] - a[k + 1])))
        else:
            print(ans)
    if a[k - 1] == a[k]:
        print(ans)