TnT/CodeNet4Repair huggingface dataset:
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
def addition_and_multiplication(N: int, K: int)->int:
    min_d = float('inf')
    for i in range(1 << N):
        d = 1
        
        
        for _ in range(N):
            if i & 1:
                d = d * 2
            else:
                d = d + K
        min_d = min(d, min_d)
    return min_d


if __name__ == "__main__":
    N = int(input())
    K = int(input())
    ans = addition_and_multiplication(N, K)
    print(ans)


Fixed, accepted submission:
def addition_and_multiplication(N: int, K: int)->int:
    min_d = float('inf')
    for i in range(1 << N):
        d = 1
        
        
        for _ in range(N):
            if i & 1:
                d = d * 2
            else:
                d = d + K
            i >>= 1
        min_d = min(d, min_d)
    return min_d


if __name__ == "__main__":
    N = int(input())
    K = int(input())
    ans = addition_and_multiplication(N, K)
    print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin


n, *s = (x.rstrip() for x in stdin.readlines())

ac = s.count('AC')
wa = s.count('WA')
tle = s.count('TLE')
re = s.count('RE')

print(f'AC × {ac}')
print(f'WA × {wa}')
print(f'TLE × {tle}')
print(f'RE × {re}')


Fixed, accepted submission:
from sys import stdin


n, *s = (x.rstrip() for x in stdin.readlines())

ac = s.count('AC')
wa = s.count('WA')
tle = s.count('TLE')
re = s.count('RE')

print(f'AC x {ac}')
print(f'WA x {wa}')
print(f'TLE x {tle}')
print(f'RE x {re}')
Problem:
When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.  You are given N numbers X_1, X_2, ..., X_N, where N is an even number. For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.  Find B_i for each i = 1, 2, ..., N.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
an = list(map(int, input().split()))
an.sort()
a, b = an[n//2-1:n//2+1]
if a == b:
  for _ in range(n):
    print(n)
else:
  for ai in an:
    if ai <= a:
      print(b)
    else:
      print(a)


Fixed, accepted submission:
n = int(input())
xn = list(map(int, input().split()))
xsort = sorted(xn)
a, b = xsort[n//2-1:n//2+1]
if a == b:
  for _ in range(n):
    print(a)
else:
  for x in xn:
    if x <= a:
      print(b)
    else:
      print(a)
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
if len(set(list(input().strip())))==26:
    print("yes")
else:
    print("no")

Fixed, accepted submission:
S = input().strip()
n = len(S)
if len(set(list(S)))==n:
    print("yes")
else:
    print("no")
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
s=input()
s.replace('hi', '')
if s == '':
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
s=input()
x=len(s) // 2
a=x*'hi'
if a == s:
  print('Yes')
else:
  print('No')
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
x = list(map(int, input().split()))
num = x[0] + x[1] + x[2]
if int(num) % 4 == 0:
    print('YES')
else:
    print('No')

Fixed, accepted submission:
x = input().split()
num = x[0] + x[1] + x[2]
if int(num) % 4 == 0:
    print('YES')
else:
    print('NO')
Problem:
There are N integers a_1, a_2, ..., a_N not less than 1. The values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \times a_2 \times ... \times a_N = P.  Find the maximum possible greatest common divisor of a_1, a_2, ..., a_N.

Incorrect submission (verdict: Wrong Answer):
n,p= map(int,input().split())
if n==1:
    print(p)
else :print(1)
 

Fixed, accepted submission:
n,p= map(int,input().split())
for i in range(round(p**(1/n)),0,-1):
    if p%(i**n)==0:
        print(i)
        exit()
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())

if abs(x - a) > abs(x - b):
  print("A")
else:
  print("B")

Fixed, accepted submission:
x, a, b = map(int, input().split())

if abs(x - a) > abs(x - b):
  print("B")
else:
  print("A")
Problem:
You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.  For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.  Assume that initially no person lives in the building.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
room=[[[ 0 for i in range(10)] for j in range(3)] for k in range(4)]
for i in range(n) :
    b,f,r,v=map(int,input().split())
    room[b-1][f-1][r-1]+=v
for i in range(4) :
    for j in range(3) :
        for k in range(10) :
            print(" {}".format(room[i][j][k]),end="")
        print("")
    if i!=3 :
        for l in range(20) :
            print("#",end="")


Fixed, accepted submission:
room=[ [ [ 0 for k in range(10) ] for j in range(3) ] for i in range(4)]
n=int(input())
for i in range(n) :
    b,f,r,v=map(int,input().split())
    room[b-1][f-1][r-1]+=v
for i in range(4) :
    for j in range(3) :
        for k in range(10) :
            print(" {}".format(room[i][j][k]),end="")
        print("")
    if i!=3 :
        for l in range(20) :
            print("#",end="")
        print("")
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
A,B,K = map(int,input().split())
ans = []

if(K <= A-B+1):
 for i in range(A,A+K):
   ans.append(i)
 for j in range(B-K+1,B+1):
   ans.append(j)
 ans = set(ans)
 ans = list(ans)
 ans.sort()
 for i in range(len(ans)):
   print(ans[i])
  
else:
  for i in range(A,B+1):
    print(i)

Fixed, accepted submission:
A,B,K = map(int,input().split())
ans = []

for i in range(A,A+K):
  if(A<= i<= B):
   ans.append(i)
for j in range(B-K+1,B+1):
  if(A<= j<= B):
   ans .append(j)
  
ans = set(ans)
ans = list(ans)
ans.sort()
for i in range(len(ans)):
   print(ans[i])
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))
s = 0
m = 100000000
for j in range(-100,101):
  for i in range(N):
    s += (A[i]-j)**2
  m = min(m, s)
print(m)

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))
s = 0
m = 100000000
for j in range(-100,101):
  for i in range(N):
    s += (A[i]-j)**2
  m = min(m, s)
  s = 0
print(m)
Problem:
We have N bulbs arranged on a number line, numbered 1 to N from left to right. Bulb i is at coordinate i.  Each bulb has a non-negative integer parameter called intensity. When there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5. Initially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:    * For each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.  Find the intensity of each bulb after the K operations.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

N,K = map(int, input().split())
A =list(map(int, input().split()))

ans = np.array(A, np.int8)
for i in range(K):
  k = np.array([0]*N, np.int8)
  for n in range(N):
    
    k[max(0, n - ans[n]):min(N, n + ans[n])+1] += 1
  ans = k
  
for i in  ans:
  print(min(i, N))

Fixed, accepted submission:
import numpy as np
from numba import njit

N,K = map(int, input().split())
A = np.array(list(map(int, input().split())))

@njit
def main(N, K, A):
  for _ in range(min(K, 42)):
    A_ = np.zeros_like(A)
    for n in range(N):
      A_[max(0, n - A[n])] += 1
      if n + A[n] + 1  < N:
        A_[n + A[n] + 1] -= 1
    A = A_.cumsum()
        
  return A

print(*main(N, K, A))
Problem:
福島県は果物の産地としても有名で、その中でも特に桃とりんごは全国でも指折りの生産量を誇っています。ところで、ある販売用の英文パンフレットの印刷原稿を作ったところ、手違いでりんごに関する記述と桃に関する記述を逆に書いてしまいました。  あなたは、apple と peach を修正する仕事を任されましたが、なにぶん面倒です。１行の英文を入力して、そのなかの apple という文字列を全て peach に、peach という文字列を全てapple に交換した英文を出力するプログラムを作成してください。

Incorrect submission (verdict: Wrong Answer):
w=str(input())
print(len(w))
for i in range(len(w)):
    if i>len(w):break
    if w[i]=="a" and w[i+1]=="p" and w[i+2]=="p" and w[i+3]=="l" and w[i+4]=="e":
        w=w[:i]+"peach"+w[i+5:]
        continue
    if w[i]=="p" and w[i+1]=="e" and w[i+2]=="a" and w[i+3]=="c" and w[i+4]=="h":
        w=w[:i]+"apple"+w[i+5:]
print(w)


Fixed, accepted submission:
w=str(input())
for i in range(len(w)):
    if i>len(w):break
    if w[i]=="a" and w[i+1]=="p" and w[i+2]=="p" and w[i+3]=="l" and w[i+4]=="e":
        w=w[:i]+"peach"+w[i+5:]
        continue
    if w[i]=="p" and w[i+1]=="e" and w[i+2]=="a" and w[i+3]=="c" and w[i+4]=="h":
        w=w[:i]+"apple"+w[i+5:]
print(w)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a, b = map(float, input().split())
print(round((a+b)/2, 0))

Fixed, accepted submission:
import math
a, b = map(float, input().split())
print(int(math.ceil((a+b)/2)))
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
s = set(s)
s = sorted(s)
m = 'abcdefghijklmnopqrstuvwxyz'

for i in range(len(m)):
    if s[i] != m[i]:
        print(m[i])
        exit(0)

    if i + 1 != len(m) and i + 1 == len(s):
        print(m[i + 1])
        exit(0)

print('None')

Fixed, accepted submission:
x,a,b = map(int,input().split())

if abs(x - a) > abs(x - b):
    print('B')
else:
    print('A')
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
S = input()
Mozi = ["dreamer","eraser","dream","erase"]

for i in Mozi:
    T = S.replace(i,"X")
    S = T
if S not in "X":
    print("No")
else:
    print("Yes")

Fixed, accepted submission:
S = input()
Mozi = ["resare","esare","remaerd","maerd"]

S = S[::-1]
for i in Mozi:
    S = S.replace(i,"")
if not S:
    print("YES")
else:
    print("NO")
Problem:
Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.  They will share these cards. First, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards. Here, both Snuke and Raccoon have to take at least one card.  Let the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively. They would like to minimize |x-y|. Find the minimum possible value of |x-y|.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline

N = int(input())
nums = list(map(int, input().split()))

s = sum(nums)
x = 0
y = 0
for i in range(N):
    a = nums[i]
    if x + a <= s//2:
        x += a
    else:
        y = x + a
        break
    print(x)
if x == 0:
    x = nums[0]
if y == s:
    y = 0

print(min(s-2*x, 2*y-2))

Fixed, accepted submission:
import sys
input = sys.stdin.readline

n = int(input())
A = list(map(int, input().split()))
x = 0
s = sum(A)
ab = -1
for i in range(n-1):
    a = A[i]
    x += a
    if ab == -1:
        ab = abs(s - 2*x)
    else:
        ab = min(ab, abs(s - 2*x))
print(ab)
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
# sys.stdin.readline()
import sys
input = sys.stdin.readline

s = input()
if 15-len(s)+s.count('o') >= 8:
    ans = 'YES'
else:
    ans = 'NO'
print(ans)

Fixed, accepted submission:
s = input()
if 15-len(s)+s.count('o') >= 8:
    ans = 'YES'
else:
    ans = 'NO'
print(ans)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
N, M, X, Y = [int(i) for i in input().split()]
x_ls = [int(i) for i in input().split()]
y_ls = [int(i) for i in input().split()]
max_x = max(x_ls)
min_y = min(y_ls)
flg = 0
for z in range(int(X + 0.00001), int(Y)):
    if max_x < z <= min_y:
        flg = 1
if flg > 0:
    print("War")
else:
    print("No War")

Fixed, accepted submission:
import math
N, M, X, Y = [int(i) for i in input().split()]
x_ls = [int(i) for i in input().split()]
y_ls = [int(i) for i in input().split()]
max_x = max(x_ls)
min_y = min(y_ls)
flg = 0
for z in range(int(math.ceil(X + 0.00001)), int(Y)):
    if max_x < z <= min_y:
        flg = 1
if flg > 0:
    print("No War")
else:
    print("War")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
s = input()
print("A"+s+"C")

Fixed, accepted submission:
st = input()
print("A"+st[8]+"C")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
a,b,c=input().split()
print("a"+b[0]+"c")

Fixed, accepted submission:
a,b,c=input().split()
print(a[0]+b[0]+c[0])
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
S = input().split(" ")
print([i[0] for i in S])

Fixed, accepted submission:
S = input().split(" ")
print("".join([i[0] for i in S]))
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
N = int(input())

ans = [0]*(N+1)

for i in range(1, int(N**0.5)+1):
    for j in range(1, 101 - i):
       for k in range(1, 101 - i - j):
            f = i*i + j*j + k*k +i*j + j*k + k*i
            if f <= N:
                ans[f] += 1
print(*ans, sep='\n')


Fixed, accepted submission:
N = int(input())

ans = [0]*(N+1)

for i in range(1, int(N**0.5)+1):
    for j in range(1, int(N**0.5)+2):
       for k in range(1, int(N**0.5)+2):
            f = i*i + j*j + k*k +i*j + j*k + k*i
            if f <= N:
                ans[f] += 1
print(*ans[1:], sep='\n')
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
t, x, y = [], [], []

for i in range(N) :
    _t, _x, _y = map(int, input().split())
    t.append(_t)
    x.append(_x)
    y.append(_y)

cur_x, cur_y = 0, 0
cur_t = 0
flg_impossible = "YES"

for i in range(N) :
    dloc = (x[i] - cur_x) + (y[i] - cur_y)
    dt = t[i] - cur_t
    
    if ((dloc % 2 == 0 and dt % 2 == 0) or (dloc % 2 != 0 and dt % 2 != 0)) and dloc <= dt :
        cur_x, cur_y, cur_t = x[i], y[i], t[i]
    else :
        flg_impossible = "NO"
        
print(flg_impossible)

Fixed, accepted submission:
N = int(input())
t, x, y = [], [], []

for i in range(N) :
    _t, _x, _y = map(int, input().split())
    t.append(_t)
    x.append(_x)
    y.append(_y)
    

cur_x = 0
cur_y = 0
cur_time = 0 
flg_possible = True

for i in range(N) :
    min_dist = abs(x[i] - cur_x) + abs(y[i] - cur_y)

    if min_dist > t[i] or not((t[i] - cur_time) % 2 == min_dist % 2):
        print("No")
        flg_possible = False
        break
    else :
        cur_x, cur_y, cur_time = x[i], y[i], t[i]
        
if flg_possible == True :
    print("Yes")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
for i in range(100):
    if int(a+b) == i**2:
        print('Yes')
        exit()

print('No')

Fixed, accepted submission:
a,b = map(str,input().split())
for i in range(1,100100):
    if int(a+b) == i**2:
        print('Yes')
        exit()

print('No')
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
a = [input() for i in range(2)]

N = int(a[0])
data = a[1].split(' ')

data = [int(i) for i in data]

result = []
for i in range(N):
    for j in range(N):
        if i <= j:
            continue
        result.append(data[i] ^ data[j])
        
sorted_data = data.sort()
sorted_result = result.sort()

if sorted_data == sorted_result:
    print('Yes')
    
print('No')

        
        
    

Fixed, accepted submission:
a = [input() for i in range(2)]
 
N = int(a[0])
data = a[1].split(' ')
 
data = [int(i) for i in data]
 
result = []
a = 0
for i in range(N):
    a = a ^ data[i]
    
if a == 0:
    print('Yes')
    exit()
    
print('No')
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
D, X = map(int, input().split())
a_list = list(map(int, [input() for i in range(N)]))
counter = 0
for a in a_list:
  counter += 1
  base = 1
  for i in range(1, D):
    base = (i * a + 1)
    print(base)
    if base <= D:
      counter += 1
    else: 
      break
counter += X
print(counter)

Fixed, accepted submission:
N = int(input())
D, X = map(int, input().split())
a_list = list(map(int, [input() for i in range(N)]))
counter = 0
for a in a_list:
  counter += 1
  base = 1
  for i in range(1, D):
    base = (i * a + 1)
    if base <= D:
      counter += 1
    else: 
      break
counter += X
print(counter)