TnT/CodeNet4Repair huggingface dataset:
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
s=input()
temp = ""
for c in s:
  if c == '1' or c == '0':
    temp += c
  else:
    temp = temp[0:len(temp)]
print(temp)

Fixed, accepted submission:
s=input()

answer=""

for c in s:
  if c != "B":
    answer += c
  elif answer != "":
    answer = answer[:-1]
  else:
    continue
print(answer)
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
vowelslist=["a","e","i","o","u"]
print(input() in vowelslist)

Fixed, accepted submission:
a,b,c=input().split()
print(a[0]+b[0]+c[0])
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
N=list(input())
l=len(N)-1
for n in range(2**l):
    lis=list(format(n,'b'))
    list(map(int,lis))
    nagasa=len(lis)
    if nagasa<l:
        for _ in range(l-nagasa):
            lis.insert(0,0)
    S=int(N[0])
    ans=[]
    for ll in range(l):
        if lis[ll]=='1':
            S=S+int(N[ll+1])
            ans.append('+')
        else:
            S=int(N[ll])-int(N[ll+1])
            ans.append('-')
    if S==7:
        kotae=[N[0]]
        for x in range(l):
            kotae.append(ans[x])
            kotae.append(N[x+1])
        last=''.join(kotae)
        print(last)
        break


Fixed, accepted submission:
N=list(input())
l=len(N)-1
for n in range(2**l):
    lis=list(format(n,'b'))
    list(map(int,lis))
    nagasa=len(lis)
    if nagasa<l:
        for _ in range(l-nagasa):
            lis.insert(0,0)
    S=int(N[0])
    ans=[]
    for ll in range(l):
        if lis[ll]=='1':
            S=S+int(N[ll+1])
            ans.append('+')
        else:
            S=S-int(N[ll+1])
            ans.append('-')
    if S==7:
        kotae=[N[0]]
        for x in range(l):
            kotae.append(ans[x])
            kotae.append(N[x+1])
        kotae.append('=7')
        last=''.join(kotae)
        print(last)
        break
Problem:
Takahashi is a user of a site that hosts programming contests.   When a user competes in a contest, the _rating_ of the user (not necessarily an integer) changes according to the _performance_ of the user, as follows:    * Let the current rating of the user be a.   * Suppose that the performance of the user in the contest is b.   * Then, the new rating of the user will be the avarage of a and b.  For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.  Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.   Find the performance required to achieve it.

Incorrect submission (verdict: Wrong Answer):
R = int(input())
G = int(input())
print(G + (G-R)/2)

Fixed, accepted submission:
R = int(input())
G = int(input())
print(G + G - R)
Problem:
We have a 3×3 square grid, where each square contains a lowercase English letters. The letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.  Print the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.

Incorrect submission (verdict: Wrong Answer):
l=input()
l1=input()
l2=input()
a=l[0],l1[1],l2[2]
print(*a)

Fixed, accepted submission:
l=input()[0]
l+=input()[1]
l+=input()[2]
print(l)
Problem:
AtCoder Mart sells 1000000 of each of the six items below:    * Riceballs, priced at 100 yen (the currency of Japan) each   * Sandwiches, priced at 101 yen each   * Cookies, priced at 102 yen each   * Cakes, priced at 103 yen each   * Candies, priced at 104 yen each   * Computers, priced at 105 yen each  Takahashi wants to buy some of them that cost exactly X yen in total. Determine whether this is possible.   (Ignore consumption tax.)

Incorrect submission (verdict: Wrong Answer):
x = int(input())
if 100 <= x//100 <= 105: print(1)
else: print(0)

Fixed, accepted submission:
x = int(input())
cnt = x//100

if 100*cnt <= x <= 105*cnt:
    print(1)
else:
    print(0)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n, a, b = map(int, input().split())
ans = 0
for i in range(1, n+1):
  if a <= sum(map(int, list(str(i)))) <= b:
    ans += 1
print(ans)

Fixed, accepted submission:
n, a, b = map(int, input().split())
ans = 0
for i in range(1, n+1):
  if a <= sum(map(int, list(str(i)))) <= b:
    ans += i
print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
print(1)

Fixed, accepted submission:
ab = input().split()
a,b = int(ab[0]),int(ab[1])
if a*b % 2 ==1:
  print("Odd")
else:
  print("Even")
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n,m,X,Y = list(map(int,input().split()))
x = list(map(int,input().split()))
y = list(map(int,input().split()))

if (X < Y) and max(x) <min(y) and max(x) <= X and min(y) >= Y:
    print("No War")
else:
    print("War")

Fixed, accepted submission:
n,m,X,Y = list(map(int,input().split()))
x = list(map(int,input().split()))
y = list(map(int,input().split()))

Z = min(min(y),Y)
if (X < Z) and max(x) < Z :
    print("No War")
else:
    print("War")
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
answer=0
if n % 2 == 0:
    answer=n/2-1
else:
    answer=(n-1)/2
print(answer)

Fixed, accepted submission:
n = int(input())
answer=0
if n % 2 == 0:
    answer=n/2-1
else:
    answer=(n-1)/2
print(int(answer))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
AC = 0
WA = 0
TLE = 0
RE = 0
for i in range(N):
  deta = input()
  if deta == 'AC':
    AC += 1
  elif deta == 'WA':
    WA += 1
  elif deta == 'WA':
    TLE += 1
  else :
    RE += 1
print('AC x {}'.format(AC))   
print('WA x {}'.format(WA))  
print('TLE x {}'.format(TLE))  
print('RE x {}'.format(RE))  

Fixed, accepted submission:
N = int(input())
AC = 0
WA = 0
TLE = 0
RE = 0
for i in range(N):
  deta = input()
  if deta == 'AC':
    AC += 1
  elif deta == 'WA':
    WA += 1
  elif deta == 'TLE':
    TLE += 1
  else :
    RE += 1
print('AC x {}'.format(AC))   
print('WA x {}'.format(WA))  
print('TLE x {}'.format(TLE))  
print('RE x {}'.format(RE))
Problem:
Let's first write a program to calculate the score from a pair of input and output. You can know the total score by submitting your solution, or an official program to calculate a score is often provided for local evaluation as in this contest. Nevertheless, writing a score calculator by yourself is still useful to check your understanding of the problem specification. Moreover, the source code of the score calculator can often be reused for solving the problem or debugging your solution. So it is worthwhile to write a score calculator unless it is very complicated.

Incorrect submission (verdict: Wrong Answer):
D = int(input())
c = list(map(int,input().split()))
s = [ [0 for j in range(26)] for i in range(D)]
for i in range(D):
    tmp = list(map(int,input().split()))
    for j in range(26):
        s[i][j] = tmp[j]
t = []
for i in range(D):
    t.append(int(input()))


v = [0] * D
last = [ [0 for j in range(26)] for i in range(D)]
sum = 0
for i in range(D):
    sum += s[i][t[i]-1]
    last[i][t[i]-1] = i+1
    for j in range(26):
        sum -= c[j] * ( (i+1) - last[i][j] )
    v[i] = sum

for i in range(D):
    print(v[i])

Fixed, accepted submission:
D = int(input())
c = list(map(int,input().split()))
s = [ [0 for j in range(26)] for i in range(D)]
for i in range(D):
    tmp = list(map(int,input().split()))
    for j in range(26):
        s[i][j] = tmp[j]
t = []
for i in range(D):
    t.append(int(input()))


v = [0] * D
last = [0] * 26
sat = 0
for d in range(D):
    j = t[d] - 1
    sat += s[d][j]
    last[j] = d+1
    for j in range(26):
        sat -= c[j] * ( d + 1 - last[j] )
    v[d] = sat

for i in range(D):
    print(v[i])
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
X, A, B = map(int, input().split())
print(["No", "Yes"][(A*10+B)%4==0])

Fixed, accepted submission:
X, A, B = map(int, input().split())
print(["NO", "YES"][(A*10+B)%4==0])
Problem:
You are given three words s_1, s_2 and s_3, each composed of lowercase English letters, with spaces in between. Print the acronym formed from the uppercased initial letters of the words.

Incorrect submission (verdict: Wrong Answer):
s1,s2,s3 = input().split()
print((s1+s2+s3).upper())

Fixed, accepted submission:
s1,s2,s3 = input().split()
print((s1[0]+s2[0]+s3[0]).upper())
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
def BlCannotGo(dt, dx, dy): 
    if (dt % 2) != ((dx + dy) % 2) or (dx + dy) > dt:
        return True
    else:
        return False

if __name__ == '__main__':
    n = int(input())
    l = list(list(map(int, input().split())) for _ in range(n))

    dt = l[0][0]
    dx = l[0][1]
    dy = l[0][2]
    if BlCannotGo(dt, dx, dy):
        print('NO')    
        exit()
        
    for i in range(1,n):
        dt = l[i][0] -  l[i-1][0] 
        dx = l[i][1] -  l[i-1][1]
        dy = l[i][2] -  l[i-1][2]
        if BlCannotGo(dt, dx, dy):
            print('NO')    
            exit()

    print('YES')

Fixed, accepted submission:
def main():
    import sys
    input = sys.stdin.readline

    N = int(input())

    pt, px, py = 0, 0, 0
    for _ in range(N):
        t, x, y = map(int, input().split())
        dt = t - pt
        dx = abs(x - px)
        dy = abs(y - py)
        dl = dx + dy

        if dt < dl or dl % 2 != dt % 2:
            print('No')
            return

        pt, px, py = t, x, y

    print('Yes')


if __name__ == '__main__':
    main()
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b=map(int,input().split());print(['a','b'][abs(x-a)>abs(x-b)])

Fixed, accepted submission:
x,a,b=map(int,input().split());print('AB'[abs(x-a)-abs(x-b)>=0])
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s = input()

print(s[0] + str(len(s[-2])) + s[-1])

Fixed, accepted submission:
s = input()
print(s[0] + str(len(s)-2) + s[-1])
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
satu = n//1000
print(n-1000*satu)

Fixed, accepted submission:
n = int(input())
satu = n//1000
if  n % 1000 == 0:
  print(0)
  quit()
ans = 1000*(satu+1)-n
print(ans)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a//2==1 and b//2==1:
  print('odd')
else:
  print('even')

Fixed, accepted submission:
a,b=map(int,input().split())
if a%2==0 or b%2==0:
  print('Even')
else:
  print('Odd')
Problem:
You went shopping to buy cakes and donuts with X yen (the currency of Japan).  First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.  How much do you have left after shopping?

Incorrect submission (verdict: Wrong Answer):
s = int(input())
s -= int(input())
b = int(input())
while s <= 0:
  s -= b
print(s+b)

Fixed, accepted submission:
s = int(input())
s -= int(input())
b = int(input())
while s >= 0:
  s -= b
print(s+b)
Problem:
Given a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: `a`, `e`, `i`, `o` and `u`.

Incorrect submission (verdict: Wrong Answer):
#ABC49-C
S=input()
divide=["dream","dreamer","erase","eraser"]
for i in range(4): 
    divide[i]=divide[i][::-1]
len_s=len(S)
S=S[::-1]

check=0
i=0
a=[]
while check==0:
    if i==len_s: 
        a.append(1)
        break
    if len_s-i <5: 
        check=1
        a.append(2)
        break
    if S[i:i+5] == divide[0]:
        i=i+5
        a.append(3)
        continue
    if S[i:i+5] == divide[2]:
        i=i+5
        a.append(4)
        continue
    if len_s-i <7: 
        check=1
        a.append(5)
        break
    if S[i:i+7] == divide[1]:
        i=i+7
        a.append(6)
        continue
    if S[i:i+7] == divide[3]:
        i=i+7
        a.append(7)
        continue


if check==0:
    print("YES")
else:
    print("NO")
#print(a)

Fixed, accepted submission:
k=["a","e","i","o","u"]
c=input()
if any(c==k[i] for i in range(5)):
    print("vowel")
else:
    print("consonant")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
import math
a,b = input().split()

num = int(a + b)
print(num)
if math.sqrt(num) % 1 == 0:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
import math
a,b = input().split()

num = int(a + b)
if math.sqrt(num) % 1 == 0:
    print("Yes")
else:
    print("No")
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
line = input()
a = 20000000
z = 0
for i in range(len(line)):
  if line[i] == 'A':
    min(a,i)
  elif line[i] == 'Z':
    max(z,i)
print(z-a+1)

Fixed, accepted submission:
line = input()
a = 20000000
z = 0
for i in range(len(line)):
  if line[i] == 'A':
    a = min(a,i)
  elif line[i] == 'Z':
    z = max(z,i)
print(z-a+1)
Problem:
An expression is given in a line. Two consequtive symbols (operand or operator) are separated by a space character.  You can assume that +, - and * are given as the operator and an operand is a positive integer less than 106

Incorrect submission (verdict: Wrong Answer):
data = list(map(str,input().split()))
stack = []
for i in data:
    if(i == "+" or i == "-" or i == "*" or i == "/"):
        stack.append(i)
    else:
        stack.append(int(i))
op1 = 0
op2 = 0
n = len(stack)
while(len(stack) != 1):
    i = stack.pop()
    if(i == "+"):
        stack.append(op1+op2)
        op1,op2 = op1+op2,0
    elif(i == "-"):
        stack.append(op1-op2)
        op1,op2 = op1-op2,0
    elif(i == "*"):
        stack.append(op1*op2)
        op1,op2 = op1*op2,0
    elif(i == "/"):
        stack.append(op1/op2)
        op1,op2 = op1/op2,0
    else:
        if(op2 == 0):
            op2 = i
        else:
            op1 = i
        
print(stack.pop())


Fixed, accepted submission:
data = list(map(str,input().split()))
stack = []
op1 = 0
op2 = 0
k = 0
for i in data:
# print(i,type(i))
  if(i == "+" or i == "-" or i == "*" or i == "/"):
    op1 = stack.pop()
    op2 = stack.pop()
    if(i == "+"): stack.append(op2+op1)
    elif(i == "-"): stack.append(op2-op1)
    elif(i == "*"): stack.append(op2*op1)
    elif(i == "/"): stack.append(int(op2/op1))
  else:
    stack.append(int(i))


print(stack.pop())
Problem:
You are given a sequence of _n_ integers S and a sequence of different _q_ integers T. Write a program which outputs C, the number of integers in T which are also in the set S.

Incorrect submission (verdict: Wrong Answer):
input()
n1 = set(input().split())
input()
n2 = set(input().split())

print(len(n1-n2))


Fixed, accepted submission:
input()
n1 = set(input().split())
input()
n2 = set(input().split())

print(len(n1&n2))
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n, a, b = map(int, input().split())

cnt = 0
for num in range(1, n + 1):
    s = str(num)
    sm = 0
    for let in s:
        sm += int(let)
    if a <= sm <= b:
        cnt += 1

print(cnt)


Fixed, accepted submission:
n, a, b = map(int, input().split())

ans = 0
for num in range(1, n + 1):
    s = str(num)
    sm = 0
    for let in s:
        sm += int(let)
    if a <= sm <= b:
        ans += num

print(ans)
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
import sys

s_d = input()
t = input()

s = ''
for i in range(len(s_d)):
    find_num = t.find(s_d[i])
    if not find_num == -1:
        if len(s_d[:i]) >= len(t[:find_num]) or len(s_d[i:]) >= len(t[find_num:]):
            s_d = s_d[:i-find_num] + t + s_d[i+len(t)-1:]
            break
    elif i == len(s_d)-1:
        print('UNRESTORABLE');
        sys.exit()
        
for i in range(len(s_d)):
    if s_d[i] == '?':
        s = s + 'a'
    else:
        s = s + s_d[i]
          

print(s)

Fixed, accepted submission:
s = input()
t = input()

def check(s, t):
    for i in range(len(s)):
        for j in range(min(len(t), len(s[i:]))):
            if s[i:][j] != '?' and s[i:][j] != t[j]:
                break
            if j == len(t)-1:
                return True, i
    return False, 0


s = s[::-1]
t = t[::-1]
c, i = check(s, t)
ans = ''
if c:
    ans = s[:i] + t + s[(i+len(t)):]
    ans = ans.replace('?', 'a')
    print(ans[::-1])
else:
    print('UNRESTORABLE')
Problem:
You are given a string S of length 2 or 3 consisting of lowercase English letters. If the length of the string is 2, print it as is; if the length is 3, print the string after reversing it.

Incorrect submission (verdict: Wrong Answer):
print(input()[::-1].upper())

Fixed, accepted submission:
S = input()
if len(S) == 2:
  print(S)
else:
  print(S[::-1])
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
A,B,C,D = map(int,list(input()))

dic = { 1:"+" , -1:"-"}

import itertools
for AB,BC,CD in itertools.product([1,-1],repeat=3):
    tmp = A + B*AB + C*BC + D*CD

    if tmp ==7:
        ans = str(A)+dic[AB]+str(B)+dic[BC]+str(C)+dic[CD]+str(D)
        print(ans)
        exit()

Fixed, accepted submission:
A,B,C,D = map(int,list(input()))

dic = { 1:"+" , -1:"-"}

import itertools
for AB,BC,CD in itertools.product([1,-1],repeat=3):
    tmp = A + B*AB + C*BC + D*CD

    if tmp ==7:
        ans = str(A)+dic[AB]+str(B)+dic[BC]+str(C)+dic[CD]+str(D)+"=7"
        print(ans)
        exit()