TnT/CodeNet4Repair huggingface dataset:
Problem:
We have an H-by-W matrix. Let a_{ij} be the element at the i-th row from the top and j-th column from the left. In this matrix, each a_{ij} is a lowercase English letter.  Snuke is creating another H-by-W matrix, A', by freely rearranging the elements in A. Here, he wants to satisfy the following condition:    * Every row and column in A' can be read as a palindrome.  Determine whether he can create a matrix satisfying the condition.

Incorrect submission (verdict: Wrong Answer):
h,w=map(int,input().split())
ans=[['']*w for _ in range(h)]
print(ans)
char={}
for _ in range(h):
  s=input()
  for c in s:
    if c not in char:
      char[c]=1
    else:
      char[c]+=1
print(char)
ch=h//2
cw=w//2
fh=False
fw=False
if h%2==1:
  ch+=1
  fh=True
if w%2==1:
  cw+=1
  fw=True
for i in range(ch):
  for j in range(cw):
    if (i==ch-1 and fh==True) and (j==cw-1 and fw==True):
      for c in char.keys():
        if char[c]%2==1:
          ans[i][j]=c
          char[c]-=1
          if char[c]==0:
            del char[c]
          break
    elif i==ch-1 and fh==True:
      for c in char.keys():
        if char[c]%4==2:
          ans[i][j]=c
          ans[i][w-j-1]=c
          char[c]-=2
          if char[c]==0:
            del char[c]
          break
      else:
        for c in char.keys():
          if char[c]>=2:
            ans[i][j]=c
            ans[i][w-j-1]=c
            char[c]-=2
            if char[c]==0:
              del char[c]
            break
    elif j==cw-1 and fw==True:
      for c in char.keys():
        if char[c]%4==2:
          ans[i][j]=c
          ans[h-i-1][j]=c
          char[c]-=2
          if char[c]==0:
            del char[c]
          break
      else:
        for c in char.keys():
          if char[c]>=2:
            ans[i][j]=c
            ans[h-i-1][j]=c
            char[c]-=2
            if char[c]==0:
              del char[c]
            break
    else:
      for c in char.keys():
        if char[c]>=4:
          ans[i][j]=c
          ans[i][w-j-1]=c
          ans[h-i-1][j]=c
          ans[h-i-1][w-j-1]=c
          char[c]-=4
          if char[c]==0:
            del char[c]
          break
fy=True
for i in range(ch):
  for j in range(cw):
    if ans[i][j]=='':
      fy=False
if fy==True:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
h,w=map(int,input().split())
char={}
for _ in range(h):
  s=input()
  for c in s:
    if c not in char:
      char[c]=1
    else:
      char[c]+=1
cnt4=(h//2)*(w//2)
cnt2=0
cnt1=0
if h%2==1 and w%2==1:
  cnt1=1
  cnt2=h//2+w//2
elif h%2==1:
  cnt2=w//2
elif w%2==1:
  cnt2=h//2
flag=True
for _ in range(cnt4):
  for c in char.keys():
    if char[c]>=4:
      char[c]-=4
      if char[c]==0:
        del char[c]
      break
  else:
    flag=False
for _ in range(cnt2):
  for c in char.keys():
    if char[c]>=2:
      char[c]-=2
      if char[c]==0:
        del char[c]
      break
  else:
    flag=False
for _ in range(cnt1):
  for c in char.keys():
    if char[c]>=1:
      char[c]-=1
      if char[c]==0:
        del char[c]
      break
  else:
    flag=False
if flag==True:
  print('Yes')
else:
  print('No')
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b  = map(int, input().split())
if a*b % 2 == 0:
    print("even")
else:
    print("odd")

Fixed, accepted submission:
a,b  = map(int, input().split())
if a*b % 2 == 0:
    print("Even")
else:
    print("Odd")
Problem:
Mountaineers Mr. Takahashi and Mr. Aoki recently trekked across a certain famous mountain range. The mountain range consists of N mountains, extending from west to east in a straight line as Mt. 1, Mt. 2, ..., Mt. N. Mr. Takahashi traversed the range from the west and Mr. Aoki from the east.  The height of Mt. i is h_i, but they have forgotten the value of each h_i. Instead, for each i (1 ≤ i ≤ N), they recorded the maximum height of the mountains climbed up to the time they reached the peak of Mt. i (including Mt. i). Mr. Takahashi's record is T_i and Mr. Aoki's record is A_i.  We know that the height of each mountain h_i is a positive integer. Compute the number of the possible sequences of the mountains' heights, modulo 10^9 + 7.  Note that the records may be incorrect and thus there may be no possible sequence of the mountains' heights. In such a case, output 0.

Incorrect submission (verdict: Wrong Answer):
mod = 1000000007
n= int(input())
t= list(map(int,input().split()))
a= list(map(int,input().split()))
tb = [-1]*n
pre=-1
for i in range(n):
    if i==0:tb[i]=1
    else:
        if pre!=t[i]:tb[i]=1
    pre=t[i]
ab = [-1]*n
post=-1
for i in range(n-1,-1,-1):
    if i==n-1:post=a[i]
    else:
        if post!=a[i]:
            ab[i]=1
    post=a[i]
er = False
b=1
for i in range(n):
    if tb[i]==1 or ab[i]==1:
        if tb[i]==1 and ab[i]==1:
            if t[i]==a[i]:pass
            else:
                er=True
                break
        else:pass
    else:
        m = min(a[i],t[i])
        b = ((b% mod) * (m % mod)) % mod
if er:print(0)
else:print(b)

Fixed, accepted submission:
mod = 1000000007
n= int(input())
t= list(map(int,input().split()))
a= list(map(int,input().split()))
tb = [-1]*n
pre=-1
for i in range(n):
    if i==0:tb[i]=1
    else:
        if pre!=t[i]:tb[i]=1
    pre=t[i]
ab = [-1]*n
post=-1
for i in range(n-1,-1,-1):
    if i==n-1:ab[i]=1
    else:
        if post!=a[i]:ab[i]=1
    post=a[i]
er = False
if a[0]!=t[-1]:er=True
else:
    b=1
    for i in range(n):
        if tb[i]==1 or ab[i]==1:
            if tb[i]==1 and ab[i]==1:
                if t[i]==a[i]:pass
                else:
                    er=True
                    break
            else:
                if tb[i]==1:
                    if a[i]<t[i]:
                        er=True
                        break
                elif ab[i]==1:
                    if a[i]>t[i]:
                        er = True
                        break
        else:
            m = min(a[i],t[i])
            b = ((b% mod) * (m % mod)) % mod
if er:print(0)
else:print(b)
Problem:
AtCoDeer the deer recently bought three paint cans. The color of the one he bought two days ago is a, the color of the one he bought yesterday is b, and the color of the one he bought today is c. Here, the color of each paint can is represented by an integer between 1 and 100, inclusive.  Since he is forgetful, he might have bought more than one paint can in the same color. Count the number of different kinds of colors of these paint cans and tell him.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
if a==b or b==c or c==a:
    if a==b==c:
        print(1)
    else:
        print(2)
else:
    print(2)

Fixed, accepted submission:
a,b,c=map(int,input().split())
if a==b or b==c or c==a:
    if a==b==c:
        print(1)
    else:
        print(2)
else:
    print(3)
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int,input().split())
print(str(min(A, B)) + " " + str(abs(N - (2 * N - A - B))))


Fixed, accepted submission:
N, A, B = map(int,input().split())
if A + B <= N :
    print(str(min(A, B)) + " 0")
else :
    print(str(min(A, B)) + " " + str(abs(N - (2 * N - A - B))))
Problem:
There is a data which provides heights (in meter) of mountains. The data is only for ten mountains.  Write a program which prints heights of the top three mountains in descending order.

Incorrect submission (verdict: Wrong Answer):
s=[int(input(x)) for x in range(10)]
print(sorted(s)[-1])
print(sorted(s)[-2])
print(sorted(s)[-3])

Fixed, accepted submission:
s=[int(input()) for x in range(10)]
print(sorted(s)[-1])
print(sorted(s)[-2])
print(sorted(s)[-3])
Problem:
    図のように二股に分かれている容器があります。1 から 10 までの番号が付けられた10 個の玉を容器の開口部 A から落とし、左の筒 B か右の筒 C に玉を入れます。板 D は支点 E を中心に左右に回転できるので、板 D を動かすことで筒 B と筒 C のどちらに入れるか決めることができます。  開口部 A から落とす玉の並びを与えます。それらを順番に筒 B 又は筒 Cに入れていきます。このとき、筒 B と筒 C のおのおのが両方とも番号の小さい玉の上に大きい玉を並べられる場合は YES、並べられない場合は NO と出力するプログラムを作成してください。ただし、容器の中で玉の順序を入れ替えることはできないものとします。また、続けて同じ筒に入れることができるものとし、筒 B, C ともに 10 個の玉がすべて入るだけの余裕があるものとします。

Incorrect submission (verdict: Wrong Answer):
def dfs(i, b, c):
    if i == 10:
        b_sort = sorted(b)
        c_sort = sorted(c)
        return (b == b_sort and c == c_sort)

    if dfs(i + 1, b + [balls[i - 1]], c):
        return True

    if dfs(i + 1, b, c + [balls[i - 1]]):
        return True

    return False


if __name__ == '__main__':
    N = int(input())
    for i in range(N):
        balls = list(map(int, input().split()))
        if dfs(1, [0], [0]):
            print("Yes")
        else:
            print("No")

Fixed, accepted submission:
def dfs(i, b, c):
    if i == 11:
        return (b == sorted(b) and c == sorted(c))

    if dfs(i + 1, b + [balls[i - 1]], c):
        return True

    if dfs(i + 1, b, c + [balls[i - 1]]):
        return True

    return False


if __name__ == '__main__':
    N = int(input())
    for i in range(N):
        balls = list(map(int, input().split()))
        if dfs(1, [], []):
            print("YES")
        else:
            print("NO")
Problem:
Some number of chocolate pieces were prepared for a training camp. The camp had N participants and lasted for D days. The i-th participant (1 \leq i \leq N) ate one chocolate piece on each of the following days in the camp: the 1-st day, the (A_i + 1)-th day, the (2A_i + 1)-th day, and so on. As a result, there were X chocolate pieces remaining at the end of the camp. During the camp, nobody except the participants ate chocolate pieces.  Find the number of chocolate pieces prepared at the beginning of the camp.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
d,x = map(int, input().split())
a = []
for _ in range(n):
    a.append(int(input()))

res = 0
for e in a:
    i = 0
    while e*i+1 <= d:
        print(e*i+1)
        res += 1
        i += 1

print(res+x)

Fixed, accepted submission:
n = int(input())
d,x = map(int, input().split())
a = []
for _ in range(n):
    a.append(int(input()))

res = 0
for e in a:
    i = 0
    while e*i+1 <= d:
        res += 1
        i += 1

print(res+x)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
N, M = map(int, input().split())
E = [[] for _ in range(N)]
for _ in range(M):
  A, B = map(int, input().split())
  E[A-1] += [B-1]
  E[B-1] += [A-1]

ans = [-1]*N
T = [0]
while len(T)>0:
  P = T
  T = []
  for x in P:
    for e in E[x]:
      if ans[e]==-1:
        T += [e]
        ans[e] = x
for a in ans[1:]:
  print(a+1)


Fixed, accepted submission:
N, M = map(int, input().split())
E = [[] for _ in range(N)]
for _ in range(M):
  A, B = map(int, input().split())
  E[A-1] += [B-1]
  E[B-1] += [A-1]

ans = [-1]*N
T = [0]
while len(T)>0:
  P = T
  T = []
  for x in P:
    for e in E[x]:
      if ans[e]==-1:
        T += [e]
        ans[e] = x

print("Yes")
for a in ans[1:]:
  print(a+1)
Problem:
Write a program which reads $n$ dices constructed in the same way as [Dice I](description.jsp?id=ITP1_11_A), and determines whether they are all different. For the determination, use the same way as [Dice III](description.jsp?id=ITP1_11_C).

Incorrect submission (verdict: Wrong Answer):
p = [(-1, 2, 4, 1, 3, -1), (3, -1, 0, 5, -1, 2), (1, 5, -1, -1, 0, 4),
(4, 0, -1, -1, 5, 1), (2, -1, 5, 0, -1, 3), (-1, 3, 1, 4, 2, -1)]

def is_equal(d, a):
  ts = [i for i, x in enumerate(d) if x == a[0]]
  fs = [i for i, x in enumerate(d) if x == a[1]]
  b = 0
  for t in ts:
    for f in fs:
      if t == f: continue
      r = p[t][f]
      if r == -1: continue
      l = [d[t], d[f], d[r], d[5-r], d[5-f], d[5-t]]
      if a == l: b += 1; break
  return 1 if b > 0 else 0

l = []
b = 0
for _ in range(int(input())):
  l += [input().split()]
print(l)
for i in range(0, len(l)):
  for j in range(i+1, len(l)):
    print(i, j)
    b = is_equal(l[i], l[j])
    if b > 0: break
print("No") if b > 0 else print("Yes")


Fixed, accepted submission:
p = [(-1, 2, 4, 1, 3, -1), (3, -1, 0, 5, -1, 2), (1, 5, -1, -1, 0, 4),
(4, 0, -1, -1, 5, 1), (2, -1, 5, 0, -1, 3), (-1, 3, 1, 4, 2, -1)]

def is_equal(d, a):
  ts = [i for i, x in enumerate(d) if x == a[0]]
  fs = [i for i, x in enumerate(d) if x == a[1]]
  b = 0
  for t in ts:
    for f in fs:
      if t == f: continue
      r = p[t][f]
      if r == -1: continue
      l = [d[t], d[f], d[r], d[5-r], d[5-f], d[5-t]]
      if a == l: b += 1; break
  return 1 if b > 0 else 0

l = []
b = 0
for _ in range(int(input())):
  l += [input().split()]
for i in range(0, len(l)):
  for j in range(i+1, len(l)):
    b += is_equal(l[i], l[j])
    if b > 0: break
print("No") if b > 0 else print("Yes")
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

s_list = list(input())
t_list = list(input())


s_list.sort()

t_list.sort(reverse=True)


if "".join(s_list) < "".join(t_list):
    print("yes")
else:
    print("No")

Fixed, accepted submission:
# -*- coding: utf-8 -*-

s_list = list(input())
t_list = list(input())


s_list.sort()

t_list.sort(reverse=True)


if "".join(s_list) < "".join(t_list):
    print("Yes")
else:
    print("No")
Problem:
_n_ _q_   _name 1 time1_   _name 2 time2_   ...   _name n timen_    In the first line the number of processes _n_ and the quantum _q_ are given separated by a single space.  In the following _n_ lines, names and times for the _n_ processes are given. _name i_ and _time i_ are separated by a single space.

Incorrect submission (verdict: Time Limit Exceeded):
n,q = map(int,input().split())
A = [list(map(str,input().split())) for i in range(n)]
time = 0
flag = 1
while flag == 1:
    if int(A[0][1]) <= q: 
        time += int(A[0][1])
        print(A[0][1],time)
        del A[0]
    else: 
        time += q
        A.append(A[0])
        del A[0]
    if len(A) == 0:
        flag = 0


Fixed, accepted submission:
n,q = map(int,input().split())
A = [list(map(str,input().split())) for i in range(n)]
time = 0
flag = 1
while len(A) > 0:
    if int(A[0][1]) <= q: 
        time += int(A[0][1])
        print(A[0][0],time)
        del A[0]
    else: 
        time += q
        A[0][1] = str(int(A[0][1])-q)
        A.append(A[0])
        del A[0]
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a, b, k = map(int, input().split())
s = []

for i in range(k):
  s.append(a+k)
  s.append(b-k)
  
s.sort()
t = set(s)

for u in t:
  print(u)

Fixed, accepted submission:
a, b, k = map(int, input().split())

ak = [i for i in range(a, min(b + 1, a + k))]
bk = [i for i in range(max(a, b - k + 1), b + 1)]

abk = list(set(ak) | set(bk))
abk.sort()

for i in abk:
    print(i)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):

a = int(input())

while a >= 1000:
    a = a - 1000

print(a)

Fixed, accepted submission:

a = int(input())
b = 0
while b < a:
    b = b + 1000

print(abs(a-b))
Problem:
There are N stones arranged in a row. Every stone is painted white or black. A string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is `.`, and the stone is black if the character is `#`.  Takahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone. Find the minimum number of stones that needs to be recolored.

Incorrect submission (verdict: Wrong Answer):
from functools import reduce
input()
src = input()
costs = [reduce(lambda x,y: x+(1 if y=="
costs.append(reduce(lambda x,y: x+(1 if y=="#" else 0), src, 0))
print(costs)
print(min(costs))

Fixed, accepted submission:
from functools import reduce
l = int(input())
src = list(map(lambda x: 1 if x=="." else 0, input()))
lb = 0
rw = sum(src)
a = rw
for i in range(l):
  if src[i]==0:
    lb+=1
  else:
    rw-=1
  a = min(a, lb + rw)
  if a==0:
    break
print(a)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

i = 1
while i < N:
  i = i*2

if i < N:
  print(i)
else:
  print(i / 2)

Fixed, accepted submission:
import math

N = int(input())

i = 1
while i < N:
  i = i*2

if i <= N:
  print(i)
else:
  print(math.floor(i/2))
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
print(a)
print(b)
print(a+b)
sum = a + b
if (sum % 2 == 0 ):
	print('Even')
else:
	print('Odd')

Fixed, accepted submission:
a, b = map(int, input().split())

if ((a*b) % 2 == 0 ):
	print('Even')
else:
	print('Odd')
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if (a+b)%2==0:
  print(a+b)
else:
  print(a+b+1)

Fixed, accepted submission:
a,b = map(int,input().split())
print(int((a+b+1)/2))
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
x = 800 * N
y = 200 * (N/15)
print(x-y)


Fixed, accepted submission:
N = int(input())
x = 800 * N
y = 200 * int(N/15)
print(x-y)
Problem:
Given is an integer sequence of length N+1: A_0, A_1, A_2, \ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.

Incorrect submission (verdict: Wrong Answer):
print(-1)

Fixed, accepted submission:
n,*a=map(int,open(0).read().split())
tot=sum(a)
v=[1]
for q in a:
  tot-=q
  vt=min(2*(v[-1]-q),tot)
  if vt<0:print(-1);exit()
  v.append(vt)
print(sum(v))
Problem:
N people are standing in a queue, numbered 1, 2, 3, ..., N from front to back. Each person wears a hat, which is red, blue, or green.  The person numbered i says:    * "In front of me, exactly A_i people are wearing hats with the same color as mine."  Assuming that all these statements are correct, find the number of possible combinations of colors of the N people's hats.  Since the count can be enormous, compute it modulo 1000000007.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline

n = int(input())
a = list(map(int, input().split()))
rbg = [0, 0, 0]
ans = 1
mod = 10 ** 9 + 7

for A in a:
    ans *= rbg.count(A)
    ans %= mod
    if A is not rbg:
        ans = 0
        break
    rbg[rbg.index(A)] += 1

print(ans)


Fixed, accepted submission:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

n, *a = map(int, read().split())
ans = 1
mod = 10 ** 9 + 7
memo = [0, 0, 0]
for check in a:
    if check in memo:
        ans *= memo.count(check)
        ans %= mod
        memo[memo.index(check)] += 1
    else:
        print(0)
        exit()
print(ans)