TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
A, B, C=input().split(" ")
print("Yes" if ((A[-1]==B[0])and(B[-1]==C[0])) else "No")

Fixed, accepted submission:
A, B, C=input().split(" ")
print("YES" if ((A[-1]==B[0])and(B[-1]==C[0])) else "NO")
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n=input()
n=int(n)

x1=n/1.08
x2=n//1.08
# print(x1,x2)
if x1==x2:
	print(x1)
else:
	print(':(')

Fixed, accepted submission:
n=input()
n=int(n)
import math
x1=n/1.08

a=math.floor(math.floor(x1)*1.08)
b=math.floor(math.ceil(x1)*1.08)
if n==a:
	print(math.floor(x1))
elif n==b:
	print(math.ceil(x1))
else:
	print(':(')
Problem:
A大学ではIDの入力ミスが多発していた。   そこで、A大学は入力ミス防止のため新しいIDを発行することにした。   新しいIDには入力ミス防止のためにIDが正しいかどうかチェックする方法がある。       ・全ての桁の数字の総和を求める。   ・ただし、右端の桁を１番目として、偶数番目の桁の数字を２倍にする。   ・２倍することによって数字が１０以上になった時、１の位の数字と１０の位の数字を加算した数字をその桁の数字とする。   ・総和が１０で割り切れれば正しいID、そうでなければ間違いとする。       例として、53579というIDをチェックする。   全ての桁の数字の総和を求めるので、   5 + 3 + 5 + 7 + 9    ただし、偶数番目の桁の数字を２倍にするので、   5 + _6_ \+ 5 + _14_ \+ 9    ２倍することによって数字が１０以上になった時、１の位の数字と１０の位の数字を加算した数字をその桁の数字とするので、   5 + 6 + 5 + _(1 + 4)_ \+ 9    以上より、総和は30となる。30は10で割り切れるので、53579は正しいIDである。    B君はA大学の大学生であり、新しいIDを発行してもらったが、IDの一部の桁を忘れてしまった。   しかし、忘れてしまった部分にどんな数字が入るか、いくつか候補を絞ることに成功した。   あなたの仕事は、B君のIDの正しい組み合わせが何通りあるかを求めることである。

Incorrect submission (verdict: Wrong Answer):
import itertools

n = int(input())
id = input()[::-1]
count = 0
a = []
odd, even = 0 , 0
tmp = 0
for i in range(1,n+1):
    if id[i-1] == "*":
        if i % 2:
            odd += 1
        else:
            even += 1
        continue
    if i % 2:
        x = int(id[i-1])
        if x >= 5:
            tmp += (int(id[i-1]) * 2 - 9)
            continue
        tmp += (int(id[i-1]) * 2 - 9)
    tmp += (int(id[i-1]))
m = int(input())

data = list(map(int, input().split()))

def sum2(ls):
    ans = 0
    for k in ls:
        if k >= 5:
            ans += (k * 2 - 9)
        else:
            ans += (k * 2)
    return ans

odd_list = list(map(lambda x: (sum(x) % 10),list(itertools.product(data, repeat=odd))))
even_list = list(map(lambda x: ((sum2(x)) % 10),list(itertools.product(data, repeat=even))))
odd_mod = [odd_list.count(i) for i in range(10)]
even_mod = [even_list.count(i) for i in range(10)]
for i in range(10):
    for j in range(10):
        if ((i + j + tmp) % 10) == 0:
            count += odd_mod[i] * even_mod[j]

print(count)



Fixed, accepted submission:
import itertools

n = int(input())
id = input()[::-1]
count = 0
a = []
odd, even = 0 , 0
tmp = 0
for i in range(1,n+1):
    if id[i-1] == "*":
        if i % 2:
            odd += 1
        else:
            even += 1
    elif i % 2 == 0:
        x = int(id[i-1])
        if x >= 5:
            tmp += (x * 2 - 9)
        else:
            tmp += (x * 2)
    else:
        tmp += (int(id[i-1]))
m = int(input())

data = list(map(int, input().split()))

def sum2(ls):
    ans = 0
    for k in ls:
        if k >= 5:
            ans += (k * 2 - 9)
        else:
            ans += (k * 2)
    return ans

odd_list = list(map(lambda x: (sum(x) % 10),list(itertools.product(data, repeat=odd))))
even_list = list(map(lambda x: ((sum2(x)) % 10),list(itertools.product(data, repeat=even))))
odd_mod = [odd_list.count(i) for i in range(10)]
even_mod = [even_list.count(i) for i in range(10)]
for i in range(10):
    for j in range(10):
        if ((i + j + tmp) % 10) == 0:
            count += odd_mod[i] * even_mod[j]

print(count)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = int(input())
C = int(input())
X = int(input())
count = 0
for a in range(A):
    for b in range(B):
        for c in range(C):
            s = a * 500 + b * 100 + c * 50
            if s == X:
                count += 1

print(count)

Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())
count = 0
for a in range(A+1):
    for b in range(B+1):
        for c in range(C+1):
            s = a * 500 + b * 100 + c * 50
            # print(a, b, c, s)
            if s == X:
                count += 1

print(count)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
import sys
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(rs())
def rs_(): return [_ for _ in rs().split()]
def ri_(): return [int(_) for _ in rs().split()]

N = ri()
print(N % 1000)

Fixed, accepted submission:
import sys
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(rs())
def rs_(): return [_ for _ in rs().split()]
def ri_(): return [int(_) for _ in rs().split()]

N = ri()
print(1000 - N % 1000 if N % 1000 > 0 else 0)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

N = int(input())

a_inputs = input().split()

a = np.zeros(N)
for i in range(N):
  a[i] = int(a_inputs[i])
  
a = np.sort(a)[::-1]

alice = a[0::2].sum()
bob   = a[1::2].sum()

print(alice - bob)

Fixed, accepted submission:
import numpy as np

N = int(input())

a_inputs = input().split()

a = np.zeros(N)
for i in range(N):
  a[i] = int(a_inputs[i])
  
a = np.sort(a)[::-1]

alice = a[0::2].sum()
bob   = a[1::2].sum()

print(int(alice - bob))
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())

S = N * N

ANS = N - S
ANS = abs(ANS)

print (ANS)

Fixed, accepted submission:
N = int(input())
A = int(input())
    
S = N * N
    
ANS = A - S
ANS = abs(ANS)
    
print (ANS)
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int,input().split())
print("Yes" if b-a == c-b else "No")

Fixed, accepted submission:
a, b, c = map(int,input().split())
print("YES" if b-a == c-b else "NO")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
child = int(input())
sum = 0
for i in range(child):
  sum += i
print(sum)

Fixed, accepted submission:
child = int(input())
sum = 0
for i in range(child+1):
  sum += i
print(sum)
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=input()
b=input()
c=input()
ans=0
for j in range(n):
    d=a[j]
    e=b[j]
    f=c[j]
    if d==e and d!=f:
      ans+=1
    elif d==f and d!=e:
      ans+=1
    elif e==f and e!=d:
      ans+=1
    elif d!=e and e!=f and f!=d:
      ans+=2

Fixed, accepted submission:
n=int(input())
a=input()
b=input()
c=input()
ans=0
for j in range(n):
    d=a[j]
    e=b[j]
    f=c[j]
    if d==e and d!=f:
      ans+=1
    elif d==f and d!=e:
      ans+=1
    elif e==f and e!=d:
      ans+=1
    elif d!=e and e!=f and f!=d:
      ans+=2
    
print(ans)
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
c = 0
for i in range(N):
 a = list(input().split())
 if a[1] == 'BTC':
  c += float(a[0])*38000
 else:
  c += float(a[0])
print(c)

Fixed, accepted submission:
N = int(input())
c = 0
for i in range(N):
 a = list(input().split())
 if a[1] == 'BTC':
  c += float(a[0])*380000.0
 else:
  c += float(a[0])
print(c)
Problem:
You are parking at a parking lot. You can choose from the following two fee plans:    * Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.   * Plan 2: The fee will be B yen, regardless of the duration.  Find the minimum fee when you park for N hours.

Incorrect submission (verdict: Wrong Answer):
N,A,B=map(int,input().split())
print("B" if N+A>B else "N+A" )

Fixed, accepted submission:
N,A,B=map(int,input().split())
print(B if N*A>B else N*A )
Problem:
Joisino the magical girl has decided to turn every single digit that exists on this world into 1.  Rewriting a digit i with j (0≤i,j≤9) costs c_{i,j} MP (Magic Points).  She is now standing before a wall. The wall is divided into HW squares in H rows and W columns, and at least one square contains a digit between 0 and 9 (inclusive).  You are given A_{i,j} that describes the square at the i-th row from the top and j-th column from the left, as follows:    * If A_{i,j}≠-1, the square contains a digit A_{i,j}.   * If A_{i,j}=-1, the square does not contain a digit.  Find the minimum total amount of MP required to turn every digit on this wall into 1 in the end.

Incorrect submission (verdict: Wrong Answer):
H,W=map(int,input().split())
C=[]
A=[]
from queue import Queue
def djcstra(frm,to,D):
    dist=D[frm]
    Q=sorted(range(len(D)) , key=lambda x:-dist[x])
    Q.pop(-1)
    while len(Q):
        u=Q.pop(-1)
        if u==to:break
        for i,d in enumerate(D[u]):
            if dist[i] >dist[u]+d:
                dist[i]=dist[u]+d
        Q=sorted(sorted(Q , key=lambda x:-dist[x]))
    return dist[to]
for i in range(10):
    C.append(list(map(int,input().split())))
for i in range(H):
    A.append(list(map(int,input().split())))
cst=[float('inf')]*10
for i in range(10):
    cst[i]=djcstra(i,1,C)
sum(sum(cst[i] for i in AA if i >= 0) for AA in A)

Fixed, accepted submission:
H,W=map(int,input().split())
C=[]
A=[]
for i in range(10):
    C.append(list(map(int,input().split())))
for i in range(H):
    A.append(list(map(int,input().split())))
# WF
for i in range(10):
    for j in range(10):
        for k in range(10):
            C[j][k]=min(C[j][k], C[j][i]+C[i][k])
print(sum(sum(C[i][1] for i in AA if i >= 0) for AA in A))
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
def types(st1, st2):
    ret = 0
    for i in range(26):
        j = chr(i + 97)
        if j in st1 and j in st2:
            ret += 1
    return ret

n = int(input())
s = input()

ans = 0
for i in range(n-1):
    ans = max(ans, types(s[:i], s[i+1:]))
print(ans)


Fixed, accepted submission:
def types(st1, st2):
    ret = 0
    for i in range(26):
        j = chr(i + 97)
        if j in st1 and j in st2:
            ret += 1
    return ret

n = int(input())
s = input()

ans = 0
for i in range(n-1):
    ans = max(ans, types(s[:i], s[i:]))
print(ans)
Problem:
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.  Snuke can perform the following operation any number of times:    * Choose a box containing at least one candy, and eat one of the candies in the chosen box.  His objective is as follows:    * Any two neighboring boxes contain at most x candies in total.  Find the minimum number of operations required to achieve the objective.

Incorrect submission (verdict: Wrong Answer):
def m():
    n, x = map(int, input().split())
    a = list(map(int, input().split()))
    ans = 0
    for i in range(1, n-1, 2):
        if a[i+1] > a[i-1]:
            if a[i+1] + a[i] < x:
                continue
            ans += (a[i+1] + a[i]) -x
        else:
            if a[i-1] + a[i] < x:
                continue
            ans += (a[i-1] + a[i]) -x
    if a[-1] + a[-2] < x:
        return ans
    ans += (a[-1] + a[-2]) -x
    return ans


print(m())

Fixed, accepted submission:
def m():
    n, x = map(int, input().split())
    a = list(map(int, input().split()))
    b = a.copy()
    ans = 0
    for i in range(n):
        if b[i] > x:
            b[i] = x

    for j in range(1, n):
        if b[j-1] + b[j] > x:
            b[j] -= (b[j-1] + b[j]) - x
        else:
            pass
    for k in range(n):
        ans += a[k] - b[k]
    return ans

print(m())
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
for i in range(10000):
    n = int(input())
    if n:
        print(f'Case {i}: {n}')


Fixed, accepted submission:
for i in range(1,10001):
    n = int(input())
    if n:
        print(f'Case {i}: {n}')
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
n=input()
cnt=0
for i in range(1,len(n)):
    if n[i]==n[i-1]:
        cnt+=1

if cnt >=3:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
n=input()

if (n[0]==n[1] and n[1]==n[2]) or (n[1]==n[2] and n[2]==n[3]):
    print("Yes")
else:
    print("No")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter
n = int(input())
a = [input() for i in range(n)]
b = Counter(a)
b.setdefault("AC", 0)
b.setdefault("WA", 0)
b.setdefault("TLE", 0)
b.setdefault("RE", 0)
for i in b.keys():
    print(i + " x " + str(b[i]))

Fixed, accepted submission:
from collections import Counter
n = int(input())
a = [input() for i in range(n)]
b = Counter(a)
b.setdefault("AC", 0)
b.setdefault("WA", 0)
b.setdefault("TLE", 0)
b.setdefault("RE", 0)
print("AC" + " x " + str(b["AC"]))
print("WA" + " x " + str(b["WA"]))
print("TLE" + " x " + str(b["TLE"]))
print("RE" + " x " + str(b["RE"]))
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a, b, x = (i for i in input().split())
if x <= b:
  print('Yes')
else:
  print('No')
  

Fixed, accepted submission:
a, b, x = (int(i) for i in input().split())
if x >= a and x-a <= b:
  print('YES')
else:
  print('NO')
Problem:
In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands. For convenience, we will call them Island 1, Island 2, ..., Island N.  There are M kinds of regular boat services between these islands. Each service connects two islands. The i-th service connects Island a_i and Island b_i.  Cat Snuke is on Island 1 now, and wants to go to Island N. However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.  Help him.

Incorrect submission (verdict: Wrong Answer):
# ABC068 C - Cat Snuke and a Voyage
ni = lambda: int(input())
nm = lambda: map(int, input().split())
nl = lambda: list(map(int, input().split()))

n,m = nm()
G = [[] for _ in range(n)]

for i in range(m):
    a,b = map(int,input().split())
    G[a-1].append(b-1)
    G[b-1].append(a-1)

# print(G)

for g in G:
    island_1toi = False
    island_iton = False
    for gg in g:
        if gg == 1:
            island_1toi = True
        if gg == n-1:
            island_iton = True

        if island_1toi == True and island_iton == True:
            print('POSSIBLE')
            exit()

print('IMPOSSIBLE')

Fixed, accepted submission:
n,m=map(int,input().split())
G=[[] for i in range(n)]
for i in range(m):
    a,b=map(int,input().split())
    a-=1
    b-=1
    G[a].append(b)
    G[b].append(a)

for g in G:
    island_1=False
    island_n=False
    for gg in g:
        if gg==0:
            island_1=True
        if gg==n-1:
            island_n=True
    if island_1==True and island_n==True: 
        print('POSSIBLE')
        exit()
print('IMPOSSIBLE')
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
i=list(map(int,input().split(" ")))
print("{0} {1} {2}".format(i[0]//i[1],i[0]%i[1],i[0]/i[1]))

Fixed, accepted submission:
i=list(map(int,input().split(" ")))
print("{0} {1} {2:0.5f}".format(i[0]//i[1],i[0]%i[1],float(i[0])/float(i[1])))
Problem:
We have a grid with N rows and M columns of squares. Initially, all the squares are white.  There is a button attached to each row and each column. When a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa. When a button attached to a column is pressed, the colors of all the squares in that column are inverted.  Takahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.

Incorrect submission (verdict: Wrong Answer):
import sys
import socket

hostname = socket.gethostname()

if hostname == 'F451C':
    sys.stdin = open('b1.in')


def read_int_list():
    return list(map(int, input().split()))


def read_str_list():
    return input().split()


def read_int():
    return int(input())


def read_str():
    return input()


def main():
    n, m, k = read_int_list()

    if n <= m:
        for i in range(n + 1):
            if k == (n * n - i * n) + (i * (m - n)):
                print('Yes')

    if n > m:
        for i in range(m + 1):
            if k == (m * m - i * m) + (i * (n - m)):
                print('Yes')

    else:
        print('No')


main()


Fixed, accepted submission:
import sys
import socket

hostname = socket.gethostname()

if hostname == 'F451C':
    sys.stdin = open('b1.in')


def read_int_list():
    return list(map(int, input().split()))


def read_str_list():
    return input().split()


def read_int():
    return int(input())


def read_str():
    return input()


def main():
    n, m, k = read_int_list()

    for i in range(m + 1):
        for j in range(n + 1):
            if k == (m - i) * j + (n - j) * i:
                print('Yes')
                return

    print('No')


main()
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
a = list(sorted(list(map(int,input().split()))))
print(a[-1] + a[-2])

Fixed, accepted submission:
a = list(sorted(list(map(int,input().split()))))
print(a[0] + a[-2])
Problem:
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.  He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.  To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.  How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
AS = list(map(int,input().split()))
AS.sort()
BS = list(map(int,input().split()))
BS.sort()
CS = list(map(int,input().split()))
CS.sort()
import bisect
AB  = [0 for _ in range(n)]
BC  = [0 for _ in range(n)]
a = 0
for b in range(n):
  AB[b] = bisect.bisect_left(AS,BS[b])
  
for b in range(n):
  BC[b] = n-bisect.bisect_left(CS,BS[b])

ans = 0
for i in range(n):
  ans += AB[b] * BC[b]
print(ans)
    



Fixed, accepted submission:
n = int(input())
AS = list(map(int,input().split()))
AS.sort()
BS = list(map(int,input().split()))
CS = list(map(int,input().split()))
CS.sort()
import bisect
  
ans = 0
for b in range(n):
  ans += bisect.bisect_left(AS,BS[b])*(n-bisect.bisect_right(CS,BS[b]))

print(ans)