TnT/CodeNet4Repair huggingface dataset:
Problem:
Write a program which reads the two dices constructed in the same way as [Dice I](description.jsp?id=ITP1_11_A), and determines whether these two dices are identical. You can roll a dice in the same way as [Dice I](description.jsp?id=ITP1_11_A), and if all integers observed from the six directions are the same as that of another dice, these dices can be considered as identical.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
# coding: utf-8
import random


class Dice() :

    mask = {'N':(1,5,2,3,0,4), 'E':(3,1,0,5,4,2),
            'W':(2,1,5,0,4,3), 'S':(4,0,2,3,5,1)}
    way = ("N","E","W","S")

    def __init__(self, data):
        self.label = data

    def move(self, data):
        self.label = [self.label[idx] for idx in self.mask[data]]

    def get_up(self):
        return self.label[0]

    def compare(self, dice2):
        ok = False
        for i in range(1000):
            check = True
            for i2 in range(6):
                if self.label[i2] == dice2.label[i2] :
                    continue
                else:
                    check = False
                    break

            if check :
                ok = True
                break
            else:
                self.move(self.way[random.randint(0,3)])
        return ok

dice1 = Dice(input().split())
dice2 = Dice(input().split())

if dice1.compare(dice2) :
    print ("OK")
else:
    print ("NG")


Fixed, accepted submission:
#!/usr/bin/env python3
# coding: utf-8
import random


class Dice() :

    mask = {'N':(1,5,2,3,0,4), 'E':(3,1,0,5,4,2),
            'W':(2,1,5,0,4,3), 'S':(4,0,2,3,5,1),'CW':(0,2,4,1,3,5)}

    way = ("N","E","W","S","CW","Nop")

    def __init__(self, data):
        self.label = data

    def move(self, data):
        if data == "Nop":
            return
        self.label = [self.label[idx] for idx in self.mask[data]]

    def get_up(self):
        return self.label[0]

    def compare_6sq(self, dice2):
        check = True
        for i in range(6):
            if self.label[i] == dice2.label[i] :
                continue
            else:
                check = False
                break

        return check
    
    def compare_4rot(self, dice2):
        ok = False
        for i in range(4):
            self.move("CW")
            if self.compare_6sq(dice2) :
                ok =True
                break
        return ok
    
    def compare(self,dice2):
        ok = False
        orderway =("Nop","E","N","E","N","E")

        for s in orderway:
            self.move(s)
            if self.compare_4rot(dice2):
                ok = True
                break
        
        return ok





dice1 = Dice(input().split())
dice2 = Dice(input().split())

if dice1.compare(dice2) :
    print ("Yes")
else:
    print ("No")
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
A, B, C = map(int, input().split())

print("YES") if(C>=A and C<=B) else print("NO")

Fixed, accepted submission:
A, B, C = map(int, input().split())

print("Yes") if(C>=A and C<=B) else print("No")
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
_input = [i for i in open(0).read().split('\n') if i]
n = int(_input[0])
a = [int(i) for i in _input[1].split()]

import functools
if functools.reduce(lambda a, b: a^b, a) == 0:
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
_input = [i for i in open(0).read().split('\n') if i]
n = int(_input[0])
a = [int(i) for i in _input[1].split()]

import functools
if functools.reduce(lambda a, b: a^b, a) == 0:
    print('Yes')
else:
    print('No')
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
s = input()
ans = ''
for i in range(len(s)):
  if s[i] == '0':
    ans += '0'
  elif s[i] == '1':
    ans += '1'
  else:
    ans = ans[:len(ans)-2]
print(ans)

Fixed, accepted submission:
s = input()
ans = ''
for i in range(len(s)):
  if s[i] == '0':
    ans += '0'
  elif s[i] == '1':
    ans += '1'
  else:
    ans = ans[:len(ans)-1]
print(ans)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())


for i in range(1,100000):
    if a+(a*i)%b==c:
        print("YES")
        break
else:
    print("NO")

Fixed, accepted submission:
a,b,c=map(int,input().split())


for i in range(1,100000):
    if (a+(a*i))%b==c:
        print("YES")
        break
else:
    print("NO")
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
import sys
count = 0
for i in sys.stdin.readlines():
    count +=1
    if i == 0:
         break
    else:
        print("Case "+str(count)+" "+i)

Fixed, accepted submission:
count = 0
while True:
    count += 1
    a = int(input())
    if a == 0:
        break
    print("Case "+str(count)+": "+str(a))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import numpy as np
import math
X=int(input())
tmp=100

#x=((math.log(X)/math.log(1.01)))//1+1
for i in range(5000):
  tmp=int(tmp*1.01)
  if(tmp>X):
    print(i+1)
    break

Fixed, accepted submission:
import numpy as np
import math
X=int(input())
tmp=100

#x=((math.log(X)/math.log(1.01)))//1+1
for i in range(6000):
  tmp=int(tmp*1.01)
  if(tmp>=X):
    print(i+1)
    break
Problem:
It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.  You are given an integer N. Find the N-th Lucas number.  Here, the i-th Lucas number L_i is defined as follows:    * L_0=2   * L_1=1   * L_i=L_{i-1}+L_{i-2} (i≥2)

Incorrect submission (verdict: Wrong Answer):
luca=[0]*87
luca[0]=2
luca[1]=1
for i in range(3,87):
  luca[i]=luca[i-1]+luca[i-2]
n=int(input())
print(luca[n])

Fixed, accepted submission:
luca=[0]*87
luca[0]=2
luca[1]=1
for i in range(2,87):
  luca[i]=luca[i-1]+luca[i-2]
n=int(input())
print(luca[n])
Problem:
Snuke has N sticks. The length of the i-th stick is l_i.  Snuke is making a snake toy by joining K of the sticks together.  The length of the toy is represented by the sum of the individual sticks that compose it. Find the maximum possible length of the toy.

Incorrect submission (verdict: Wrong Answer):
N,K = map(int, input().split())
ans = 0
l = [int(i) for i in input().split()]
l = sorted(l)
for i in range(K-1):
    ans += l[i]
print(ans)

Fixed, accepted submission:
N,K = map(int, input().split())
ans = 0
l = [int(i) for i in input().split()]
l = sorted(l, reverse=True)
for i in range(K):
    ans += l[i]
print(ans)
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
alist = list(map(int, input().split()))

ans = alist[0]
for a in alist:
    ans ^= a
if ans == 0:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
N = int(input())
alist = list(map(int, input().split()))

ans = alist[0] ^ alist[1]
for a in alist[2:]:
    ans ^= a
if ans == 0:
    print("Yes")
else:
    print("No")
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
x, y = map(int, input().split())
if x == 2 or y == 2:
    print('No')
elif x == 4 or x == 6 or x == 9 or x == 11:
    if y == 4 or y == 6 or y == 9 or y == 11:
        print('Yes')
    else:
        print('No')

Fixed, accepted submission:
x, y = map(int, input().split())
if x == 2 or y == 2:
    print('No')
elif x == 4 or x == 6 or x == 9 or x == 11:
    if y == 4 or y == 6 or y == 9 or y == 11:
        print('Yes')
    else:
        print('No')
elif x == 1 or x == 3 or x == 5 or x == 7 or x == 8 or x == 10 or x == 12:
    if x == 1 or x == 3 or x == 5 or x == 7 or x == 8 or x == 10 or x == 12:
        print('Yes')
    else:
        print('No')
Problem:
Find the number of _palindromic numbers_ among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Incorrect submission (verdict: Wrong Answer):
A, B = map(int, input().split())

print ((B-A)//100)

Fixed, accepted submission:
A, B = map(int, input().split())

count = 0
for i in range(A, B+1):
    if i//10000 == i%10 and (i//1000)%10 == (i%100)//10:
        count += 1 

print (count)
Problem:
How many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?

Incorrect submission (verdict: Wrong Answer):
M = int(input())
print(24 + (M-24))


Fixed, accepted submission:
M = int(input())
print(24 + (24-M))
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
print(sum([int(x) for x in input().split()]))

Fixed, accepted submission:
print(sum([x for x in range(1,int(input())+1)]))
Problem:
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.  Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.

Incorrect submission (verdict: Wrong Answer):
h,w=map(int,input().split())
a=[input() for i in range(h)]
print((w+1)*"#")
for i in range(h):
    print("#",a[i],"#",sep="")
print((w+1)*"#")

Fixed, accepted submission:
h,w=map(int,input().split())
a=[input() for i in range(h)]
print((w+2)*"#")
for i in range(h):
    print("#",a[i],"#",sep="")
print((w+2)*"#")
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
k=1
for i in range(1,7):
  k*= i
  if k > N:
    break
print(k)

Fixed, accepted submission:
N=int(input())
for i in range(6,-1,-1):
  k = 2**i
  if N >= k:
    print(k)
    exit()
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
n = input()
ct = 0
for i in range(len(n)):
  if i == "1":
    ct += 1
    
print(ct)

Fixed, accepted submission:
n = input()
ct = 0
for i in range(3):
  if n[i] == "1":
    ct += 1
    
print(ct)
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s=str(input())
s=s[::-1]
print(s)
stack=""
for i in s:
  stack=i+stack
  if stack=="dream"or stack=="dreamer"or stack=="erase"or stack=="eraser":
    stack=""
  elif len(stack)>7:
    print("NO")
    exit()
print("YES")

Fixed, accepted submission:
s=str(input())
s=s[::-1]
stack=""
for i in s:
  stack=i+stack
  if stack=="dream"or stack=="dreamer"or stack=="erase"or stack=="eraser":
    stack=""
  elif len(stack)>7:
    print("NO")
    exit()
print("YES")
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int,input().split())

a += (a - a%x)
b -= b%x

ans = b//x - a//x + 1
print(ans)


Fixed, accepted submission:
a,b,x = map(int,input().split())

a += (x - a%x) if a%x else 0
b -= b%x

ans = b//x - a//x + 1
print(ans)
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split())
print((b-a+1)//x) if a%x == 0 else print((b-a+1)//x-1)

Fixed, accepted submission:
a,b,x=map(int,input().split())
print((b//x)-((a-1)//x))
Problem:
Joisino the magical girl has decided to turn every single digit that exists on this world into 1.  Rewriting a digit i with j (0≤i,j≤9) costs c_{i,j} MP (Magic Points).  She is now standing before a wall. The wall is divided into HW squares in H rows and W columns, and at least one square contains a digit between 0 and 9 (inclusive).  You are given A_{i,j} that describes the square at the i-th row from the top and j-th column from the left, as follows:    * If A_{i,j}≠-1, the square contains a digit A_{i,j}.   * If A_{i,j}=-1, the square does not contain a digit.  Find the minimum total amount of MP required to turn every digit on this wall into 1 in the end.

Incorrect submission (verdict: Wrong Answer):
h,w=map(int,input().split())
field=[[int(i) for i in input().split()] for i in range(10)]
wall=[[int(i) for i in input().split()] for i in range(h)]

def warshall_floyd(d,n):
    
    for k in range(n):
        for i in range(n):
            for j in range(n):
                d[i][j] = min(d[i][j],d[i][k] + d[k][j])
    return d
    
ans=0
for i in wall:
    for j in i:
        if j!=-1 and j!=1:
            ans+=field[j][1]
print(ans)

Fixed, accepted submission:
h,w=map(int,input().split())
field=[[int(i) for i in input().split()] for i in range(10)]
wall=[[int(i) for i in input().split()] for i in range(h)]


def warshall_floyd(d,n):
    
    for k in range(n):
        for i in range(n):
            for j in range(n):
                d[i][j] = min(d[i][j],d[i][k] + d[k][j])
    return d
    
d=warshall_floyd(field,10)

ans=0
for i in wall:
    for j in i:
        if j!=-1 and j!=1:
            ans+=d[j][1]
print(ans)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N%1000)

Fixed, accepted submission:
N = int(input())
if N % 1000 == 0:
    print(0)
else:
    print(1000-N%1000)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b=map(int,input().split())
ans = 0
l = range(1, n+1)

def digitSum(n):
    
    s = str(n)
    
    array = list(map(int, s))
    
    return sum(array)


# => 6

# => 27

for i in l:
    if digitSum(i) >= a and digitSum(i) <= b:
        ans += digitSum(i)
print(ans)
    


Fixed, accepted submission:
n, a, b = map(int, input().split())
ans = 0
for i in range(1, n+1):
    if a <= sum([int(c) for c in str(i)]) <= b:
        ans += i
print(ans)
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
[W, H, N] = list(map(int, input().split()))
[x, y, a] = [ [], [], [] ]
for _ in range(N):
  input_line = list(map(int, input().split()))
  x.append(input_line[0])
  y.append(input_line[1])
  a.append(input_line[2])
area = []
for i in range(W+1):
  area.append([])
  for j in range(H+1):
    area[i].append("")
    
for i in range(N):
  if a[i] == 1:
    for X in range(x[i]):
      for Y in range(H+1):
        area[X][Y] = "f"
  if a[i] == 2:
    for X in range(x[i], W+1):
      for Y in range(H+1):
        area[X][Y] = "f"
  if a[i] == 3:
    for X in range(W+1):
      for Y in range(y[i]):
        area[X][Y] = "f"
  if a[i] == 4:
    for X in range(W+1):
      for Y in range(y[i], H+1):
        area[X][Y] = "f"
        
count = 0
for i in range(W+1):
  for j in range(H+1):
    if area[i][j] == "":
      count += 1
      
print(count)

Fixed, accepted submission:
[W, H, N] = list(map(int, input().split()))
[x, y, a] = [ [], [], [] ]
for _ in range(N):
  input_line = list(map(int, input().split()))
  x.append(input_line[0])
  y.append(input_line[1])
  a.append(input_line[2])
area = []
for i in range(W):
  area.append([])
  for j in range(H):
    area[i].append("")
    
for i in range(N):
  if a[i] == 1:
    for X in range(x[i]):
      for Y in range(H):
        area[X][Y] = "f"
  if a[i] == 2:
    for X in range(x[i], W):
      for Y in range(H):
        area[X][Y] = "f"
  if a[i] == 3:
    for X in range(W):
      for Y in range(y[i]):
        area[X][Y] = "f"
  if a[i] == 4:
    for X in range(W):
      for Y in range(y[i], H):
        area[X][Y] = "f"
        
count = 0
for i in range(W):
  for j in range(H):
    if area[i][j] == "":
      count += 1
      
print(count)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b =map(int, input().split())

if a*b%2==1:
    print("odd")
else:
    print("even")

Fixed, accepted submission:
a, b =map(int, input().split())

if a*b%2==1:
    print("Odd")
else:
    print("Even")
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
import math
n=int(input());print(2**(math.log(n,2)//1))

Fixed, accepted submission:
n=int(input())
print(1<<(n.bit_length()-1))