TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke has decided to play a game using cards. He has a deck consisting of N cards. On the i-th card from the top, an integer A_i is written.  He will perform the operation described below zero or more times, so that the values written on the remaining cards will be pairwise distinct. Find the maximum possible number of remaining cards. Here, N is odd, which guarantees that at least one card can be kept.  Operation: Take out three arbitrary cards from the deck. Among those three cards, eat two: one with the largest value, and another with the smallest value. Then, return the remaining one card to the deck.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
lst = list(map(int, input().split()))

print (len(set(lst)))

Fixed, accepted submission:
N = int(input())
lst = list(map(int, input().split()))

s = len(set(lst))
print ((s - 1)//2 * 2 + 1)
Problem:
You are given three integers A, B and C.  Determine if there exists an equilateral triangle whose sides have lengths A, B and C.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if a == b and a == c:
  print('Yes')
print('No')

Fixed, accepted submission:
a, b, c = map(int, input().split())
if a == b and a == c:
  print('Yes')
else:
  print('No')
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
lst = list(map(int, input().split()))
sum = lst[0] + lst[1]
if sum%2 == 0:
    x = int(sum/2)
else:
    x = int(sum + 1)
  

Fixed, accepted submission:
a, b = map(int, input().split())
print(int((a+b+1)/2))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
print(N%1000)

Fixed, accepted submission:
N=int(input())
Na=N%1000
if Na==0:
  print(Na)
else:
  print(1000-Na)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
i = 0
while True:
    x = int(input()); i += 1
    if x == 0:
        break
    print("case {}: {}".format(i, x))


Fixed, accepted submission:
i = 0
while True:
    x = int(input()); i += 1
    if x == 0:
        break
    print("Case {}: {}".format(i, x))
Problem:
It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.  The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.  How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
print((n-int(input()))*(n-int(input())))

Fixed, accepted submission:
n=int(input())
print((n-int(input())+1)*(n-int(input())+1))
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while True:
  x=input()
  if '?' in x:
    break
    print(int(eval(x)))

Fixed, accepted submission:
while True:
    a,b,c = input().split()
 
    if b == "?":
        break
    elif b == "+":
        s = int(a)+int(c)
    elif b == "-":
        s = int(a)-int(c)
         
    elif b == "*":
        s = int(a)*int(c)
         
    else :
        s = int(a)/int(c)
    print(int(s))
Problem:
You are given an integer N. Build an undirected graph with N vertices with indices 1 to N that satisfies the following two conditions:    * The graph is simple and connected.   * There exists an integer S such that, for every vertex, the sum of the indices of the vertices adjacent to that vertex is S.  It can be proved that at least one such graph exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
print(n-1)
for i in range(n-1):
    print(n-1,i+1,sep=" ")

Fixed, accepted submission:
n=int(input())
if n%2:
    print(2*(n//2)**2)
    for i in range(1,n+1):
        for j in range(i+1,n+1):
            if i+j==n:continue
            print(i,j,sep=" ")
else:
    s=n//2
    print(2*(s-1)*s)
    for i in range(1,n+1):
        for j in range(i+1,n+1):
            if i+j==n+1 :continue
            print(i,j,sep=" ")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
import math

a, b = input().split()
n = int(a+b)
if math.sqrt(n)%1 == 0:
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
a, b = map(int, input().split())

if (a%2 == 0 or b%2 == 0):
    print("Even")
else:
    print("Odd")
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):

n = input()
a = int(n[0])

for i in range(8):
    x = "{0:03b}".format(i)
    s = a
    ss = "{0}".format(a)
    for j in range(3):
        if x[j] == '0':
            s -= int(n[j+1])
            ss += "-{0}".format(int(n[j+1]))
        else:
            s += int(n[j+1])
            ss += "+{0}".format(int(n[j+1]))
    if s == 7:
        break
print(ss)

Fixed, accepted submission:
n = input()
a = int(n[0])

for i in range(8):
    x = "{0:03b}".format(i)
    s = a
    ss = "{0}".format(a)
    for j in range(3):
        if x[j] == '0':
            s -= int(n[j+1])
            ss += "-{0}".format(int(n[j+1]))
        else:
            s += int(n[j+1])
            ss += "+{0}".format(int(n[j+1]))
    if s == 7:
        break
print(ss+"=7")
Problem:
Given is a tree G with N vertices. The vertices are numbered 1 through N, and the i-th edge connects Vertex a_i and Vertex b_i.  Consider painting the edges in G with some number of colors. We want to paint them so that, for each vertex, the colors of the edges incident to that vertex are all different.  Among the colorings satisfying the condition above, construct one that uses the minimum number of colors.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

import sys
sys.setrecursionlimit(10 ** 7)

graph = [[] for _ in range(n)]
for i in range(n - 1):
    a, b = map(int, input().split())
    graph[a - 1].append((b - 1, i))
    graph[b - 1].append((a - 1, i))
print(graph)

max_color=0
for graph_i in graph:
    max_color=max(max_color, len(graph_i))
# print(max_color)

colors=[-1]*(n-1)

def dfs(v, color, pre):
    if color!=1:
        nc=0
    else:
        nc=1
    for e in graph[v]:
        # print(e,nc)
        if e[0]==pre:
            continue
        colors[e[1]]=nc
        dfs(e[0],nc,v)
        nc+=1
        if nc==color:
            nc+=1

dfs(0,-1,-1)

for c in colors:
    print(c+1)


Fixed, accepted submission:
n=int(input())

import sys
sys.setrecursionlimit(10 ** 7)

graph = [[] for _ in range(n)]
for i in range(n - 1):
    a, b = map(int, input().split())
    graph[a - 1].append((b - 1, i))
    graph[b - 1].append((a - 1, i))
# print(graph)

max_color=0
for graph_i in graph:
    max_color=max(max_color, len(graph_i))
print(max_color)

colors=[-1]*(n-1)

def dfs(v, color, pre):
    if color!=0:
        nc=0
    else:
        nc=1
    for e in graph[v]:
        # print(e,nc)
        if e[0]==pre:
            continue
        colors[e[1]]=nc
        dfs(e[0],nc,v)
        nc+=1
        if nc==color:
            nc+=1

dfs(0,-1,-1)

for c in colors:
    print(c+1)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A, B, X = map(int, input().split())
print("YES" if X <= A+B <= X else "NO")

Fixed, accepted submission:
A, B, X = map(int, input().split())
if 0 <= X-A <= B:
    print("YES")
else:
    print("NO")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
a,b,s=input().split()
print(list(a)[0]+b+list(s)[0])

Fixed, accepted submission:
n,*s,=zip(*input().split());print("".join(n))
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
A = A ** 0.5
int(A)
A = A*A
print(A)

Fixed, accepted submission:
print(int(int(input())** 0.5)**2)
Problem:
Find the edit distance between given two words s1 and s2.  The disntace is the minimum number of single-character edits required to change one word into the other. The edits including the following operations:    * **insertion** : Insert a character at a particular position.   * **deletion** : Delete a character at a particular position.    * **substitution** : Change the character at a particular position to a different character

Incorrect submission (verdict: Wrong Answer):

import sys
def search(a,b):
    na=len(a)
    nb=len(b)
    array = [[0]*(nb+1) for _ in range(na+1)]
    for i in range(na):
        array[i][0]=i
    for j in range(nb):
        array[0][j]=j
    for i,x in enumerate(a,1):
        prerow=array[i-1]
        row=array[i]
    for j,y in enumerate(b,1):
            if x == y:
                row[j]=prerow[j-1]
            elif prerow[j] > row[j-1]:
                row[j] = row[j-1]+1
            else:
                row[j] = prerow[j]+1
    return array[-1][-1]

a=input()
b=input()
print(search(a,b))


Fixed, accepted submission:

def search(a,b):
    na=len(a)
    nb=len(b)
    array = [[0]*(nb+1) for _ in range(na+1)]
    for i in range(na+1):
        array[i][0]=i
    for j in range(nb+1):
        array[0][j]=j
    for i,x in enumerate(a,1):
        prerow=array[i-1]
        row=array[i]
        for j,y in enumerate(b,1):
            if x == y:
                row[j]=prerow[j-1]
            else:
                row[j]=min(prerow[j], prerow[j-1], row[j-1])+1
    return array[-1][-1]
a=input()
b=input()
print(search(a,b))
Problem:
Your task is to perform a simple table calculation.  Write a program which reads the number of rows r, columns c and a table of r × c elements, and prints a new table, which includes the total sum for each row and column.

Incorrect submission (verdict: Wrong Answer):
r,c = map(int,input().split())
data = [[0] * (c+1) for i in range(r)]
for row in range(r):
    data[row] = [int(i) for i in input().split()]

for row in range(r):
    for column in range(c+1):
        if column == (c):
            print(sum(data[row]))
        else: 
            print("%d " %data[row][column],end = "")


Fixed, accepted submission:
r,c = map(int,input().split())
data = [[0] * (c+1) for i in range(r)]
for row in range(r):
    data[row] = [int(i) for i in input().split()]
    data[row].append(sum(data[row]))
for row in range(r):
    for column in range(c+1):
        if column == (c):
            print(data[row][column])
        else: 
            print("%d " %data[row][column],end = "")


data_t = []
sumColumn = []
sumSumRow = 0
for column in range(c):
    dataRow = []
    for rowVector in data:
        dataRow.append(rowVector[column])
    data_t.append(dataRow) 

for column in data_t:
    sumColumn.append(sum(column))
for index in range(c):
    print("%d " %sumColumn[index],end = "")
for row in range(r):
    sumSumRow = sumSumRow + sum(data[row][:-1])
print("%d" % sumSumRow)
Problem:
Snuke has an empty sequence a.  He will perform N operations on this sequence.  In the i-th operation, he chooses an integer j satisfying 1 \leq j \leq i, and insert j at position j in a (the beginning is position 1).  You are given a sequence b of length N. Determine if it is possible that a is equal to b after N operations. If it is, show one possible sequence of operations that achieves it.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
list_b = list(map(int, input().split()))
aaa = []
ans = []
for i in range(N):
  if i == 0:
    aaa.append(1)
    ans.append(1)
  elif i == 1:
    s = []
    f = []
    for h in range(i+1):
      a = aaa.copy()
      b = ans.copy()
      a.insert(h, h+1)
      b.append(h+1)
      s.append(a)
      f.append(b)
    aaa = s
    ans = f
  else:
    j = []
    f = []
    for d in range(len(aaa)):
      s = []
      t = []
      for k in range(i+1):
        a = aaa[d].copy()
        b = ans[d].copy()
        a.insert(k, k+1)
        b.append(k+1)
        s.append(a)
        t.append(b)
      j = s
      f = t
    aaa = j
    ans = f

if list_b in aaa:
  index = aaa.index(list_b)
  anser = ans[index]
  for i in range(N):
    print(anser[i])
else:
  print('-1')

Fixed, accepted submission:
N = int(input())
list_b = list(map(int, input().split()))
ans = [0 for i in range(N)]

finish = False

for i in range(N-1, -1, -1):
  mx = -1
  for k in range(i+1):
    if list_b[k] == k+1:
      mx = max(mx, k+1)
  if mx == -1:
    finish = True
    break
  else:
    ans[i] = mx
    for j in range(mx-1, i):
      list_b[j] = list_b[j+1]
    
if not finish:
    for i in range(N):
        print(ans[i])
else:
    print(-1)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = input().split()

ab = a + b
ans = 'No'
for i in range(1,100):
  sq = i**2
  if int(ab) == sq:
    ans = 'Yes'
    break

print(ans)

Fixed, accepted submission:
a,b = map(int, input().split())

if a*b %2 == 0:
  print('Even')
else:
  print('Odd')
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
sx, sy, tx, ty = map(int, input().split())
y = ty - sy
x = tx - sx
print(len("U"*y+"R"*x+"D"*y+"L"*x+"L"+"U"*(y+1) +
          "R"*(x+1)+"D"+"R"+"D"*(y+1)+"L"*(x+1)+"U"))

Fixed, accepted submission:
sx, sy, tx, ty = map(int, input().split())
y = ty - sy
x = tx - sx
print("U"*y+"R"*x+"D"*y+"L"*x+"L"+"U"*(y+1) +
      "R"*(x+1)+"D"+"R"+"D"*(y+1)+"L"*(x+1)+"U")
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
A, B = map(int, input().split())

print(A+B if A+B >= 10 else 'error')

Fixed, accepted submission:
A, B = map(int, input().split())

print(A+B if A+B < 10 else 'error')
Problem:
Write a program which judges wheather given length of three side form a right triangle. Print "YES" if the given sides (integers) form a right triangle, "NO" if not so.

Incorrect submission (verdict: Wrong Answer):
#-*-coding:utf-8-*-

def get_input():
    for i in range(int(input())):
        yield "".join(input())
    print()
  
if __name__ == "__main__":
    array = list(get_input())
    for i in range(len(array)):        
        a,b,c = array[i].split()
        if int(a)^2 + int(b)^2 == int(c)^2:
            print("YES")
        elif int(c)^2 + int(a)^2 == int(b)^2:
            print("YES")
        elif int(b)^2 + int(c)^2 == int(a)^2:
            print("YES")
        else:
            print("NO")     

Fixed, accepted submission:
#-*-coding:utf-8-*-

def get_input():
    for i in range(int(input())):
        yield "".join(input())

if __name__ == "__main__":
    array = list(get_input())
    
    for i in range(len(array)):        
        a,b,c = array[i].split()
        if int(a)**2 + int(b)**2 == int(c)**2:
            print(u"YES")
        elif int(c)**2 + int(a)**2 == int(b)**2:
            print(u"YES")
        elif int(b)**2 + int(c)**2 == int(a)**2:
            print(u"YES")
        else:
            print(u"NO")
Problem:
Give a pair of integers (A, B) such that A^5-B^5 = X. It is guaranteed that there exists such a pair for the given integer X.

Incorrect submission (verdict: Wrong Answer):
def main():
    X = int(input())  

    for B in range(0, 1000):
        for A in range(B, 1000):
            if A**5 - B**5 == X:
                print(A, B, sep=" ")
                return
            if A**5 + B**5 == X:
                print(A, B, sep=" ")
                return

if __name__ == '__main__':
    main()



Fixed, accepted submission:
def main():
    X = int(input())  

    for B in range(0, 1000):
        for A in range(B, 1000):
            if A**5 - B**5 == X:
                print(A, B, sep=" ")
                return
            if A**5 + B**5 == X:
                print(A, -B, sep=" ")
                return

if __name__ == '__main__':
    main()
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
A,B,C=map(int,input().split())

for i in range(1,B+1):
  if (i*A)%B==C:
    print("Yes")
    break
else:
  print("No")

Fixed, accepted submission:
A,B,C=map(int,input().split())

for i in range(1,B+1):
  if (i*A)%B==C:
    print("YES")
    break
else:
  print("NO")
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=int(input())
n-=(n%500)
if (n<a) :
    print("yes")
else :
    print("no")

Fixed, accepted submission:
n=int(input())
a=int(input())
n=(n%500)
if (n<=a) :
    print("Yes")
else :
    print("No")
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())

if a%3 == 0 or b%3 == 0 or (a+b)%3 == 0:
  print("possible")
else:
  print("impossible")

Fixed, accepted submission:
a,b = map(int,input().split())

if a%3 == 0 or b%3 == 0 or (a+b)%3 == 0:
  print("Possible")
else:
  print("Impossible")
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
import sys
stdin = sys.stdin
mod = 10**9 + 7

ns = lambda: stdin.readline().rstrip()
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))
sa = lambda h: [list(map(int, stdin.readline().split())) for i in range(h)]

n = ni()
ans = "YES"
tpre, xpre, ypre = 0, 0, 0
for _ in range(n):
    t, x, y = na()
    move = abs(x - xpre) + abs(y - ypre) 
    time = (t - tpre)
    if move <= time and move % 2 == time % 2:
        continue
    else:
        ans = "No"

    tpre, xpre, ypre = t, x, y
print(ans)

Fixed, accepted submission:
import sys
stdin = sys.stdin
from itertools import accumulate, groupby
mod = 10**9 + 7

def ns(): return stdin.readline().rstrip()
def ni(): return int(ns())
def na(): return list(map(int, stdin.readline().split()))

n = ni()
tp, xp, yp = 0, 0, 0
for _ in range(n):
    t, x, y = na()
    ta, l = t-tp, abs(x - xp) + abs(y - yp)
    if ta >= l and ta % 2 ==l % 2:
        continue
    else:
        print("No")
        quit()
print("Yes")
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
S = str(input())

flag = False
if len(S) % 2 == 1:
    flag = False
else:
    for count in range(int(len(S)/2)):
        if S[count] != "h" and S[count + 1] != "i":
            flag = False
            break
        else:
            flag = True

if flag == True:
    print("Yes")
else:
    print("No")

     

Fixed, accepted submission:
S = str(input())

flag = False
if len(S) % 2 == 1:
    flag = False
else:
    for count in range(int(len(S)/2)):
        if S[count*2] != "h" or S[count*2 + 1] != "i":
            flag = False
            break
        else:
            flag = True

if flag == True:
    print("Yes")
else:
    print("No")
Problem:
Snuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.  Snuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:    * Operation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.  For example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure. If the die is rotated toward the right as shown in the figure, the side showing 3 will face upward. Besides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.    Find the minimum number of operation Snuke needs to perform in order to score at least x points in total.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
if n%11>6:
  print(n//11*2+1)
else:
  print(n//11*2)

Fixed, accepted submission:
n=int(input())
if n%11>6:
  print(n//11*2+2)
elif n%11>0:
  print(n//11*2+1)
else:
  print(n//11*2)