TnT/CodeNet4Repair huggingface dataset:
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
s = str(input())
t = str(input())
ns = len(s)
nt = len(t)
start = -1
for j in range(ns):
    if t[0] == s[j] or s[j] == '?':
        i = 0
        j_temp = j
        is_ok = True
        while i < nt:
            i += 1
            j_temp += 1
            if j_temp >= ns:
                is_ok = False
                break
            if s[j_temp] == '?' or s[j_temp] == t[i]:
                if i == nt - 1:
                    break
                continue
            if s[j_temp] != t[i]:
                is_ok = False
                break
        if is_ok:
            start = j
ans = ""
if start == -1:
    print("UNRESTORABLE")
    exit()
for i in range(ns):
    if start <= i < start + nt:
        ans += t[i - start]
    elif s[i] == "?":
        ans += "a"
    else:
        ans += s[i]
print(start)
print(ans)

Fixed, accepted submission:
s = str(input())
t = str(input())
ns = len(s)
nt = len(t)
start = -1
for j in range(ns):
    if t[0] == s[j] or s[j] == '?':
        j_temp = j
        i_temp = 0
        is_ok = True
        while i_temp < nt - 1:
            i_temp += 1
            j_temp += 1
            if j_temp >= ns:
                is_ok = False
                break
            if s[j_temp] == '?' or s[j_temp] == t[i_temp]:
                if i_temp == nt - 1:
                    break
                continue
            if s[j_temp] != t[i_temp]:
                is_ok = False
                break
        if is_ok:
            start = max(j, start)
ans = ""
if start == -1:
    print("UNRESTORABLE")
    exit()
for i in range(ns):
    if start <= i < start + nt:
        ans += t[i - start]
    elif s[i] == "?":
        ans += "a"
    else:
        ans += s[i]
print(ans)
Problem:
Write a program which counts and reports the number of each alphabetical letter. Ignore the case of characters.

Incorrect submission (verdict: Wrong Answer):
z = input()
a = []
b = 0
for i in z:
    if i.isupper():
        a += i.upper()
    a += i
print(a)
al = [chr(i) for i in range(97, 97 + 26)]
for i in al:
    b = str(a.count(i))
    print('{} : {}'.format(i,b))

Fixed, accepted submission:
z=''
while True:
    try:
        z += input()
    except EOFError:
        break
a = []
b = 0
for i in z:
    if i.isupper():
        a += i.lower()
    a += i
al = [chr(i) for i in range(97, 97 + 26)]
for i in al:
    b = str(a.count(i))
    print('{} : {}'.format(i,b))
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
x1,y1,x2,y2 = map(int ,input().split())
x = x2 - x1
y = y2 - y1
ans = ''
a = 'U'
b = 'D'
c = 'R'
d = 'L'


for _ in range(y):
    ans += a
for _ in range(x):
    ans += c
for _ in range(y):
    ans += b
for _ in range(x) :
    ans += d
ans += d
for _ in range(y + 1):
    ans += a
for _ in range(x +1):
    ans += c
ans += b
ans += c
for _ in range(y + 1):
    ans += b
for _ in range(x + 1):
    ans += d
print(ans)

Fixed, accepted submission:
x1,y1,x2,y2 = map(int ,input().split())
x = x2 - x1
y = y2 - y1
ans = ''
a = 'U'
b = 'D'
c = 'R'
d = 'L'


for _ in range(y):
    ans += a
for _ in range(x):
    ans += c
for _ in range(y):
    ans += b
for _ in range(x) :
    ans += d
ans += d
for _ in range(y + 1):
    ans += a
for _ in range(x +1):
    ans += c
ans += b
ans += c
for _ in range(y + 1):
    ans += b
for _ in range(x + 1):
    ans += d
ans += a
print(ans)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int,input().split())
def ketawa(i):
  ret = 0
  while(i):
    ret += i % 10
    i //= 10
  return ret

ret = 0
for i in range(1,n+1):
  if a <= ketawa(i) <= b: ret += 1
print(ret)

Fixed, accepted submission:
n,a,b = map(int,input().split())
def ketawa(i):
  ret = 0
  while(i):
    ret += i % 10
    i //= 10
  return ret

ret = 0
for i in range(1,n+1):
  if a <= ketawa(i) <= b: ret += i
print(ret)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
print("YES" if int(input())%500<int(input()) else "NO")

Fixed, accepted submission:
print("Yes" if int(input())%500<=int(input()) else "No")
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
import sys
a,b,c,d=input()
op=["-","+"]

for i in op:
  for j in op:
    for k in op:
      o=a+i+b+j+c+k+d
      ans=eval(o)
      if ans==7:
        print(o+"+=7")
        sys.exit()

Fixed, accepted submission:
import sys
a,b,c,d=input()
op=["-","+"]

for i in op:
  for j in op:
    for k in op:
      o=a+i+b+j+c+k+d
      ans=eval(o)
      if ans==7:
        print(o+"=7")
        sys.exit()
Problem:
To become a millionaire, M-kun has decided to make money by trading in the next N days. Currently, he has 1000 yen and no stocks - only one kind of stock is issued in the country where he lives.  He is famous across the country for his ability to foresee the future. He already knows that the price of one stock in the next N days will be as follows:    * A_1 yen on the 1-st day, A_2 yen on the 2-nd day, ..., A_N yen on the N-th day.  In the i-th day, M-kun can make the following trade **any number of times** (possibly zero), **within the amount of money and stocks that he has at the time**.    * Buy stock: Pay A_i yen and receive one stock.   * Sell stock: Sell one stock for A_i yen.  What is the maximum possible amount of money that M-kun can have in the end by trading optimally?

Incorrect submission (verdict: Wrong Answer):
K = int(input())
A = list(map(int, input().split()))

sum = 1000
kabu = 0

for k in range(K):
    if k+1 ==K:
        sum +=kabu*A[K-1]
        break
    if A[k]<A[k+1] and A[k]<=sum:
        S = int(sum/A[k])
        sum = sum-A[k]*S
        kabu +=S
    elif A[k]>A[k+1] and kabu != 0:
        sum = sum + kabu * A[k]
        kabu = 0
    print(sum)
    

print(sum)

Fixed, accepted submission:
K = int(input())
A = list(map(int, input().split()))

sum = 1000
kabu = 0

for k in range(K):
    if k+1 ==K:
        sum +=kabu*A[K-1]
        break
    if A[k]<A[k+1] and A[k]<=sum:
        S = int(sum/A[k])
        sum = sum-A[k]*S
        kabu +=S
    elif A[k]>A[k+1] and kabu != 0:
        sum = sum + kabu * A[k]
        kabu = 0
    

print(sum)
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
str_list = ['abc','acb','bac','bca','cab','cba']
ans = 'No'
for l in str_list:
  if s == l:
    ans = 'Yes'
    break
print(ans)

Fixed, accepted submission:
s = input()
if 'a' in s and 'b' in s and 'c' in s:
  print('Yes')
else:
  print('No')
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
ans = 1
tmp = 0
for i in range(2, x):
  tmp = i
  while tmp*i <= x:
    ans+=1
    tmp*=i
print(ans)
  

Fixed, accepted submission:
x = int(input())
ans = 1
for i in range(2, 1000):
  tmp = 2
  while i**tmp <= x:
    ans=max(ans, i**tmp)
    tmp+=1
    
print(ans)
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
s=input()
s=list(s)
l=[]
ls=len(s)
for i in range (ls):
    if s[i]=='1':
        l.append(1)
    elif s[i]=='0':
        l.append(0)
    else:
        if len(l)==0:
            l=l
        else:
            l.pop()
print(l)

Fixed, accepted submission:
s=input()
s=list(s)
l=[]
ls=len(s)
for i in range (ls):
    if s[i]=='1':
        l.append(1)
    elif s[i]=='0':
        l.append(0)
    else:
        if len(l)==0:
            l=l
        else:
            l.pop()
ans=""
for i in range(len(l)):
    ans=ans+str(l[i])
print(ans)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))

def devide(array, count):
	print(array);
	dividable = True
	for i in array:
		if ((i % 2) != 0):
			dividable = False
	if (dividable):
		print('a')
		for index, value in enumerate(array):
			array[index] = value / 2
		count += 1
		return devide(array, count)
	else:
		print('b')
		print(array)
		print(count)
		return array, count

devided, count = devide(A, 0)
print(count)

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))

def devide(array, count):
	dividable = True
	for i in array:
		if ((i % 2) != 0):
			dividable = False
	if (dividable):
		for index, value in enumerate(array):
			array[index] = value / 2
		count += 1
		return devide(array, count)
	else:
		return array, count

devided, count = devide(A, 0)
print(count)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
l = list(map(int, input().split()))
a = l[0]
b = l[1]
c = l[2]

ss = []
ll = []
def checkK(x,y,z):
    if y - x + 1 <= z:
        counter = int(x)
        while counter != y:
            ss.append(counter)
            counter = counter + 1
        for i in range(len(ss)):
            print(ss[i])
    else:
        for i in range(c):
            ll.append(a+i)
        for i in range(c):
            ll.append(b-c+i)
        for i in range(len(ll)):
            print(ll[i])
        
checkK(a,b,c)



Fixed, accepted submission:
l = list(map(int, input().split()))
a = l[0]
b = l[1]
c = l[2]

ss = []
mm = []
ll = []
def checkK(x,y,z):
    if y - x + 1 <= z *2:
        counter = int(x)
        while counter != y+1:
            ss.append(counter)
            counter = counter + 1
        for i in range(len(ss)):
            print(ss[i])
    
        
    else:
        for i in range(c):
            ll.append(a+i)
        for i in range(c):
            ll.append(b-c+i+1)
        for i in range(len(ll)):
            print(ll[i])
        
checkK(a,b,c)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split())
if a<=x and x<=a+b:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b,x=map(int,input().split())
if a<=x and x<=a+b:
    print("YES")
else:
    print("NO")
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
S = input()

t = S.count("x")
if t <= 7:
    print("Yes")
else:
    print("No")
    


Fixed, accepted submission:
S = input()

t = S.count("x")

if t <= 7:
    print("YES")
else:
    print("NO")
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s=input()
print(s[0]+'len(s)'+s[-1])

Fixed, accepted submission:
s=input()
a=len(s)-2
print(s[0]+str(a)+s[-1])
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = input()
a = [int(i) for i in input().split()]
a = sorted(a)
alice = 0
bob = 0
for i in reversed(range(len(a))):
    if i % 2 == 0:
        alice += a[i]
    else:
        bob += a[i]
print(alice-bob)

Fixed, accepted submission:
n = input()
a = [int(i) for i in input().split()]
a = sorted(a)
alice = 0
bob = 0
for i in range(len(a)):
    if i % 2 == 0:
        alice += a[-i-1]
    else:
        bob += a[-i- 1]
print(alice-bob)
Problem:
How many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?

Incorrect submission (verdict: Wrong Answer):
print(24+int(input())%24)

Fixed, accepted submission:
print(48-int(input())%24)
Problem:
Write a program which identifies the number of combinations of three integers which satisfy the following conditions:    * You should select three distinct integers from 1 to n.   * A total sum of the three integers is x.  For example, there are two combinations for n = 5 and x = 9.    * 1 + 3 + 5 = 9   * 2 + 3 + 4 = 9

Incorrect submission (verdict: Wrong Answer):
import math
while True:
    n,x = map(int,input().split())
    if n == x == 0:
        break

    c = 0
    for i in range(math.ceil(x/3), x-3):
        for j in range(math.ceil(i/2), i):
            k = i - j
            if x == i + j + k:
                #print(x, i, j, k)
                c += 1
    print(c)


Fixed, accepted submission:
while True:
    n,x = map(int,input().split())
    if n == x == 0:
        break

    n = n + 1
    c = 0
    for i in range(1,n):
        for j in range(i+1,n):
            for k in range(j+1,n):
                if x == i + j + k:
                    c += 1
    print(c)
Problem:
We have a string s consisting of lowercase English letters. Snuke can perform the following operation repeatedly:    * Insert a letter `x` to any position in s of his choice, including the beginning and end of s.  Snuke's objective is to turn s into a palindrome. Determine whether the objective is achievable. If it is achievable, find the minimum number of operations required.

Incorrect submission (verdict: Wrong Answer):
s = input()
ans = 0
while s:
  if s[0] == s[-1]:
    s = s[1:-2]
  else:
    if s[0] == "x":
      ans += 1
      s = s[1:]
    elif s[-1] == "x":
      ans += 1
      s = s[:-1]
    else:
      print(-1)
      exit()
print(ans)

Fixed, accepted submission:
s = input()
ans = 0
while s:
  if s[0] == s[-1]:
    s = s[1:-1]
  else:
    if s[0] == "x":
      ans += 1
      s = s[1:]
    elif s[-1] == "x":
      ans += 1
      s = s[:-1]
    else:
      print(-1)
      exit()
print(ans)
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
if(a in [4, 6, 9, 11]):
	print("YES" if b in [4, 6, 9, 11] else "NO")
elif(a in [1, 3, 5, 7, 8, 10, 12]):
	print("YES" if b in [1, 3, 5, 7, 8, 10, 12] else "NO")
else:
	print("NO")

Fixed, accepted submission:
a, b = map(int, input().split())
if(a in [4, 6, 9, 11]):
	print("Yes" if (b in [4, 6, 9, 11]) else "No")
elif(a in [1, 3, 5, 7, 8, 10, 12]):
	print("Yes" if (b in [1, 3, 5, 7, 8, 10, 12]) else "No")
else:
	print("No")
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
a=input()
LIs=list(a)
count=0
for i in range(len(LIs)):
       for g in range (len(LIs)):
              if LIs[i]==LIs[g]:
                  count+=1
if count==0:
     print("yes")
else:
     print("no")

Fixed, accepted submission:
a,b=map(int,input().split())
if a+b>=10:
     print("error")
else:
     print(a+b)
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
def solve(N, A, B):
  maxNum = max(A, B)
  minNum = max(0, N - (A + B))
  print(maxNum, minNum)

N, A, B = map(int, input().split())
solve(N, A, B)

Fixed, accepted submission:
def solve(N, A, B):
  maxNum = min(A, B)
  minNum = max(0, (A + B) - N)
  print(maxNum, minNum)

N, A, B = map(int, input().split())
solve(N, A, B)
Problem:
We have a grid with H rows and W columns, where all the squares are initially white.  You will perform some number of painting operations on the grid. In one operation, you can do one of the following two actions:    * Choose one row, then paint all the squares in that row black.   * Choose one column, then paint all the squares in that column black.  At least how many operations do you need in order to have N or more black squares in the grid? It is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.

Incorrect submission (verdict: Wrong Answer):
import sys
H = int(input())
W = int(input())
N = int(input())
X = max(H, W)
Y = min(H, W)
count = 0
total = 0
for i in range(Y):
    total += X
    count += 1
    if count >= N:
        print(count)
        sys.exit()
for i in range(X):
    total += Y
    count += 1
    if count >= N:
        print(count)
        break


Fixed, accepted submission:
import sys
H = int(input())
W = int(input())
N = int(input())
X = max(H, W)
Y = min(H, W)
count = 0
total = 0
for _ in range(Y):
    total += X
    count += 1
    if total >= N:
        print(count)
        sys.exit()
for _ in range(X):
    total += Y
    count += 1
    if ctotal >= N:
        print(count)
        break
Problem:
n! = n × (n − 1) × (n − 2) × ...  × 3 × 2 × 1      を n の階乗といいます。例えば、12 の階乗は      12! = 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 479001600      となり、末尾に 0 が 2 つ連続して並んでいます。  整数 n を入力して、n! の末尾に連続して並んでいる 0 の数を出力するプログラムを作成してください。ただし、n は 20000 以下の正の整数とします。

Incorrect submission (verdict: Wrong Answer):
while 1:
    try:
        zero=0
        number=1
        n=int(input())
        for i in range(1,n+1):
            number*=i
            while len(str(number))>7:number=int(str(number)[1:])
            while number%10==0:
                zero+=1
                number=int(number/10)
        print(zero)
    except:break


Fixed, accepted submission:
while 1:
    zero=0
    number=1
    n=int(input())
    if n==0:break
    for i in range(1,n+1):
        number*=i
        while len(str(number))>7:number=int(str(number)[1:])
        while number%10==0:
            zero+=1
            number=int(number/10)
    print(zero)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
num = list(map(int,input().split()))

for i,s in enumerate(num,1):
        print("Case {0}: {1}".format(i,s))

Fixed, accepted submission:
count = 0
while(True):
        num = int(input())
        if num == 0:
                break
        count += 1
        print("Case {0}: {1}".format(count,num))
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
n = input().split()
x = int("".join(n))
print("Yes") if x%x**0.5 == x**0.5 else print("No")

Fixed, accepted submission:
n = input().split()
x = int("".join(n))**0.5
print("Yes") if x.is_integer() else print("No")