TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python

def main():
    matrix = []
    for _ in range(2):
        matrix.append(list(input()))

    if matrix[0][0] == matrix[1][2] \
        and matrix[0][1] == matrix[1][1] \
        and matrix[0][2] == matrix[1][0]:
        print("Yes")
    else:
        print("No")

if __name__ == '__main__':
    main()

Fixed, accepted submission:

def main():
    matrix = []
    for _ in range(2):
        matrix.append(list(input()))

    if matrix[0][0] == matrix[1][2] \
        and matrix[0][1] == matrix[1][1] \
        and matrix[0][2] == matrix[1][0]:
        print("YES")
    else:
        print("NO")

if __name__ == '__main__':
    main()
Problem:
There are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i). Thus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.  In order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B. Then, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i). Thus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.  When activated, each type of robot will operate as follows.    * When a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.    * When a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.  Snuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.

Incorrect submission (verdict: Wrong Answer):
N,K,*x =map(int,open(0).read().split())
print(sum([min(i,K-i) for i in x]))


Fixed, accepted submission:
N,K,*x =map(int,open(0).read().split())
print(sum(2*[min(i,K-i) for i in x]))
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
import math
a=input().split()
d=int(a[0]+a[1])
x=int(math.sqrt(d))
x=x*x
print("YES" if x==d else "No")

Fixed, accepted submission:
import math
a=input().split()
d=int(a[0]+a[1])
x=int(math.sqrt(d))
x=x*x
print("Yes" if x==d else "No")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())
print((a+b)*h/2)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())
ans = (a+b)*h/2
print(int(ans))
Problem:
For an integer n not less than 0, let us define f(n) as follows:    * f(n) = 1 (if n < 2)   * f(n) = n f(n-2) (if n \geq 2)  Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Incorrect submission (verdict: Time Limit Exceeded):
N = int(input())

ans = 0
i = 0
while True:
    x = (2 * 5 * (5 ** i))
    if x <= N:
        ans += N // x
        i += 1

print(ans)

Fixed, accepted submission:
N = int(input())

ans = 0
if N % 2 == 0:
    i = 0
    while True:
        x = (2 * 5 * (5 ** i))
        if x > N:
            break
        ans += N // x
        i += 1

print(ans)
Problem:
Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order. From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized. If there are multiple pairs that maximize the value, any of them is accepted.

Incorrect submission (verdict: Wrong Answer):
import bisect

N = int(input())
A = sorted(list(map(int,input().split())))

if N == 2:
    print(A[-1],A[0])
    exit()

r_val = A[-1]//2
r_ind = bisect.bisect_left(A,r_val,0,N-1)
# if abs(A[-1]/2 - float(A[r_ind])) < abs(A[-1]/2 - float(A[min(r_ind+1,N-2)])):
#     r_ind = r_ind + 1

#print(A[r_ind])
ans = [A[-1],A[r_ind]]


# print(A)
# for i,n in enumerate(A[:-1]):
#     print(i,n,n//2)

#     r_val = n // 2


#     if abs(n/2 - A[r_ind]) > abs(n/2 - A[r_ind+1]):
#         r_ind = r_ind + 1
#     print(r_val,'r_ind = ',r_ind,A[r_ind])

#     r = A[r_ind]
#     print(n,r,comb(n,r))
#     if max_comb < comb(n,r):
#         ans = [n,r]
print(ans)


Fixed, accepted submission:
N = int(input())
A = sorted(list(map(int,input().split())))

n = A[-1]
A = A[:-1]

r_val = n//2
diff_min = float(n)

for a in A:
    diff = abs(n/2 - float(a))
    if diff_min > diff:
        diff_min = diff
        r = a

print(n,r)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int,input().split())
count = 0

for i in range(1, n + 1):
    tmp = i
    x = 0
    for j in range(5)[::-1]:
        x += tmp // (10**j)
        tmp = tmp - (tmp // (10**j))*(10**j)
        
    if a <= x <= b:
        count +=1
        
print(count)

Fixed, accepted submission:
n,a,b = map(int,input().split())
sum = 0

for i in range(1, n + 1):
    tmp = i
    x = 0
    for j in range(5)[::-1]:
        x += tmp // (10**j)
        tmp = tmp - (tmp // (10**j))*(10**j)
        
    if a <= x <= b:
        sum += i
        
print(sum)
Problem:
We have a grid with H rows and W columns, where all the squares are initially white.  You will perform some number of painting operations on the grid. In one operation, you can do one of the following two actions:    * Choose one row, then paint all the squares in that row black.   * Choose one column, then paint all the squares in that column black.  At least how many operations do you need in order to have N or more black squares in the grid? It is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.

Incorrect submission (verdict: Wrong Answer):
H,W,N = [int(input()) for i in range(3)]

print(min(N//H,N//W))


Fixed, accepted submission:
import math


H,W,N = [int(input()) for i in range(3)]
 
print(min(math.ceil(N/H),math.ceil(N/W)))
Problem:
Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers.  She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of **distinct** positive integers is called **special** if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is **not** 1.  Nagase wants to find a **special** set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a **special** set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000.

Incorrect submission (verdict: Wrong Answer):
import math
k = int(input())
if k == 3:
    print("3 6 9")
elif k == 4:
    print("3 9 2 4")
elif k == 6:
    print("3 9 2 4 8 10")
elif k <= 15002:
    prints = set([3, 9]) 
    k -= 2
    for i in range(int(math.ceil(k / 3))):
        prints.add(i*6+2)
        prints.add(i*6+4)
        prints.add(i*6+6)
    if 3 - k % 3 == 1:
        prints.remove(6)
    if 3 - k % 3 == 2:
        prints.remove(6)
        prints.remove(12)
    print(" ".join([str(item) for item in prints]))
else:
    prints = set() 
    for i in range(5000):
        prints.add(i*6+2)
        prints.add(i*6+4)
        prints.add(i*6+6)
    k -= 15000
    for i in range(int(math.ceil(k / 2))):
        prints.add(i*12+3)
        prints.add(i*12+9)
    if 3 - k % 3 == 1:
        prints.remove(6)
    print(" ".join([str(item) for item in prints]))

Fixed, accepted submission:
import math
k = int(input())
if k == 3:
    print("2 5 63")
elif k == 4:
    print("3 9 2 4")
elif k == 6:
    print("3 9 2 4 8 10")
elif k <= 15002:
    prints = set([3, 9]) 
    k -= 2
    for i in range(int(math.ceil(k / 3))):
        prints.add(i*6+2)
        prints.add(i*6+4)
        prints.add(i*6+6)
    if 3 - k % 3 == 1:
        prints.remove(6)
    if 3 - k % 3 == 2:
        prints.remove(6)
        prints.remove(12)
    print(" ".join([str(item) for item in prints]))
else:
    prints = set() 
    for i in range(5000):
        prints.add(i*6+2)
        prints.add(i*6+4)
        prints.add(i*6+6)
    k -= 15000
    for i in range(int(math.ceil(k / 2))):
        prints.add(i*12+3)
        prints.add(i*12+9)
    if 2 - k % 2 == 1:
        prints.remove(6)
    print(" ".join([str(item) for item in prints]))
Problem:
There are four towns, numbered 1,2,3 and 4. Also, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally. No two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.  Determine if we can visit all the towns by traversing each of the roads exactly once.

Incorrect submission (verdict: Wrong Answer):
a1, b1 = map(int, input().split())
a2, b2 = map(int, input().split())
a3, b3 = map(int, input().split())

l = [a1, a2, a3, b1, b2, b3]

res = [sum([1 for _ in l if _ == __]) for __ in [1,2,3,4]]

if 3 in res:
    print("No")
else:
    print("Yes")

Fixed, accepted submission:
a1, b1 = map(int, input().split())
a2, b2 = map(int, input().split())
a3, b3 = map(int, input().split())

l = [a1, a2, a3, b1, b2, b3]

res = [sum([1 for _ in l if _ == __]) for __ in [1,2,3,4]]

if 3 in res:
    print("NO")
else:
    print("YES")
Problem:
You are given an integer sequence of length N, a_1,a_2,...,a_N.  For each 1≤i≤N, you have three choices: add 1 to a_i, subtract 1 from a_i or do nothing.  After these operations, you select an integer X and count the number of i such that a_i=X.  Maximize this count by making optimal choices.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
p = list(map(int, input().split()))
i=0
ans =0

while i<n:
    if p[i]==i+1:
        ans += 1
        i+=1
    if not (i==n-2 and p[i+1]==i+2):
        i += 1
print(ans)

Fixed, accepted submission:
from collections import Counter
n = int(input())
a = list(map(int, input().split()))
c = []
for i in a:
    c.append(i)
    c.append(i-1)
    c.append(i+1)
c = Counter(c)

print(max(c.values()))
Problem:
We have N ID cards, and there are M gates.  We can pass the i-th gate if we have one of the following ID cards: the L_i- th, (L_i+1)-th, ..., and R_i-th ID cards.  How many of the ID cards allow us to pass all the gates alone?

Incorrect submission (verdict: Wrong Answer):
while True:
    try:
        N, M = map(int, input().split())
        gate = [list(map(int, input().split())) for i in range(M)]
        
        L, R = 0, 10**5+5
        for l, r in gate:
            L = max(L, l)
            R = min(R, r)
            
        print(R-L+1)
    except:
        break

Fixed, accepted submission:
while True:
    try:
        N, M = map(int, input().split())
        
        dp = [0]*(10**5+5)
        for i in range(M):
            L, R = map(int, input().split())
            dp[L-1] += 1
            dp[R] -= 1
        
        cnt = 0
        ans = 0
        for i in range(N):
            cnt += dp[i]
            if cnt == M:
                ans += 1
            
        print(ans)
    except:
        break
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input()
while len(s)>0:
    if s[-5:]=='erase' or s[-5:]=='dream':
        s=s[:-5]
    elif s[-6:]=='eraser':
        s=s[:-6]
    elif s[-7:]=='dreamer':
        s=s[:-7]
    else:
        print('No')
        exit(0)
print('Yes')


Fixed, accepted submission:
s = input()
while len(s)>0:
    if s[-5:]=='erase' or s[-5:]=='dream':
        s=s[:-5]
    elif s[-6:]=='eraser':
        s=s[:-6]
    elif s[-7:]=='dreamer':
        s=s[:-7]
    else:
        print('NO')
        exit(0)
print('YES')
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
S = list(input())[:-1]
T = list(input())[:-1]

ans_list=[]
for i in range(len(S)-len(T)+1):
    S_temp=S.copy()
    serch_S=S_temp[i:i+len(T)]
#     print(serch_S)
    count=0
    for t in range(len(T)):
        if serch_S[t] in [T[t],'?']:
#             print(serch_S[t])
            count+=1
        else:
            break
        
        if count==len(T):
            S_temp[i:i+len(T)]=T

            for s in range(len(S_temp)):
                if S_temp[s]=='?':
                    S_temp[s]='a'
                    
            S_temp_str=''
            for s_t in S_temp:
                S_temp_str+=s_t

            ans_list.append(S_temp_str)

if len(ans_list)>0:
    
    ans_list.sort()
    ans=ans_list[0]
else:
    ans='UNRESTORABLE'
    
print(ans)

Fixed, accepted submission:
S = list(input())
T = list(input())

ans_list=[]
for i in range(len(S)-len(T)+1):
    S_temp=S.copy()
    serch_S=S_temp[i:i+len(T)]
    count=0
    for t in range(len(T)):
        if serch_S[t] in [T[t],'?']:
            count+=1
        else:
            break
        
        if count==len(T):
            S_temp[i:i+len(T)]=T

            for s in range(len(S_temp)):
                if S_temp[s]=='?':
                    S_temp[s]='a'
                    
            S_temp_str=''
            for s_t in S_temp:
                S_temp_str+=s_t

            ans_list.append(S_temp_str)

if len(ans_list)>0:
    
    ans_list.sort()
    ans=ans_list[0]
else:
    ans='UNRESTORABLE'
    
print(ans)
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
X = int(input())
print(int(X**0.5-1)**2)

Fixed, accepted submission:
X = int(input())

lst = []
for i in range(1,101):
    for j in range(2,11):
        if i**j > 1000:
            break
        else:
            lst.append(i**j)

for k in range(X):
    if X - k in lst:
        print(X-k)
        break
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a = input()

if a.count('5') == 2:
    if a.count('7') == 1:
        print('yes')
    else:
        print('no')
else:
    print('no')

Fixed, accepted submission:
a = input().split()

if a.count('5') == 2:
    if a.count('7') == 1:
        print('YES')
    else:
        print('NO')
else:
    print('NO')
Problem:
AtCoder currently hosts three types of contests: ABC, ARC, and AGC. As the number of users has grown, in order to meet the needs of more users, AtCoder has decided to increase the number of contests to 26 types, from AAC to AZC. For convenience, we number these 26 types as type 1 through type 26. AtCoder wants to schedule contests for D days so that user satisfaction is as high as possible. For every day, AtCoder will hold exactly one contest, and each contest will end on that day. The satisfaction is calculated as follows.    * The satisfaction at the beginning of day 1 is 0. Satisfaction can be negative.   * Holding contests increases satisfaction. The amount of increase will vary depending on a variety of factors. Specifically, we know in advance that holding a contest of type i on day d will increase the satisfaction by s_{d,i}.   * If a particular type of contest is not held for a while, the satisfaction decreases. Each contest type i has an integer c_i, and at the end of each day d=1,2,...,D, the satisfaction decreases as follows. Let \mathrm{last}(d,i) be the last day before day d (including d) on which a contest of type i was held. If contests of type i have never been held yet, we define \mathrm{last}(d,i)=0. At the end of day d, the satisfaction decreases by \sum _{i=1}^{26}c_i \times (d-\mathrm{last}(d,i)).  Please schedule contests on behalf of AtCoder. If the satisfaction at the end of day D is S, you will get a score of \max(10^6 + S, 0). There are 50 test cases, and the score of a submission is the total scores for each test case. You can make submissions multiple times, and the highest score among your submissions will be your score.

Incorrect submission (verdict: Wrong Answer):
import sys
import numpy as np
from operator import mul
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

d = int(readline())
c = list(map(int, readline().split()))
s = []
for _ in range(d):
    add = list(map(int, readline().split()))
    s.append(add)

#t = [0] * d
day = 0
satisfy = 0
sumC = sum(c)
count = np.zeros(26)

for i in range(d):
    #t = int(readline()) - 1
    tarLis = s[day]
    tar = max(tarLis)
    t = tarLis.index(tar)
    up = s[day][t]
    count += 1
    count[t] = 0
    sub = map(mul, count, c)
    satisfy += (up - sum(sub))

    # satisfy
    print(int(satisfy))
    day += 1


Fixed, accepted submission:
import sys
import numpy as np
from operator import mul
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines

d = int(readline())
c = list(map(int, readline().split()))
s = []
for _ in range(d):
    add = list(map(int, readline().split()))
    s.append(add)

#t = [0] * d
day = 0
satisfy = 0
sumC = sum(c)
count = np.zeros(26)

for i in range(d):
    #t = int(readline()) - 1
    tarLis = s[day]
    tar = max(tarLis)
    t = tarLis.index(tar) + 1
    print(t)
    day += 1
    '''
    up = s[day][t]
    count += 1
    count[t] = 0
    sub = map(mul, count, c)
    satisfy += (up - sum(sub))

    # satisfy
    print(satisfy)
    '''
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
for i in range(3000):
    k=input().split()
    a=int(k[0])
    b=int(k[0])
    if a==0 and b==0:
        break
    else:
        if a<b:
            print(str(a)+" "+str(b))
        else:
            print(str(b)+" "+str(a))


Fixed, accepted submission:
for i in range(3000):
    k=input().split()
    a=int(k[0])
    b=int(k[1])
    if a==0 and b==0:
        break
    else:
        if a<b:
            print(str(a)+" "+str(b))
        else:
            print(str(b)+" "+str(a))
Problem:
We have a string s consisting of lowercase English letters. Snuke can perform the following operation repeatedly:    * Insert a letter `x` to any position in s of his choice, including the beginning and end of s.  Snuke's objective is to turn s into a palindrome. Determine whether the objective is achievable. If it is achievable, find the minimum number of operations required.

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8
# Here your code !
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Mon Oct  9 22:12:40 2017

@author: kitagenbakurou
"""
import numpy as np
import copy

def insert(pos, s, x):
  return x.join([s[:pos], s[pos:] ])

s = input()
N = len(s)

i = 0
cnt = 0
flag = True
while i < N - i - 1 : 
    if s[i] != s[N - i - 1] : 
        if s[i] == "x" : 
            cnt += 1
            s = insert(N - i  , s , "x")
            i = -1
        elif s[N - i - 1] == "x" : 
            cnt += 1
            s = insert(i , s , "x")
            i = -1
        else : 
            flag = False
            break
    N = len(s)
    i += 1

print(s)
if flag : 
    print(cnt)
else : 
    print(-1)

Fixed, accepted submission:
# coding: utf-8
# Here your code !
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Mon Oct  9 22:12:40 2017

@author: kitagenbakurou
"""
import numpy as np
import copy

def insert(pos, s, x):
  return x.join([s[:pos], s[pos:] ])

s = input()
N = len(s)

i = 0
j = N - 1
cnt = 0
flag = True
while i < j : 
    if s[i] != s[j] : 
        if s[i] == "x" : 
            cnt += 1
            
            i += 1
            j += 0
        elif s[j] == "x" : 
            cnt += 1
            
            i +=0
            j -= 1
        else : 
            flag = False
            break
    else : 
        i += 1
        j -= 1

if flag : 
    print(cnt)
else : 
    print(-1)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
As = [int(c) for c in input().split()]
counter = 0
w = 0


while w == 0:
    for i in range(N):
        if As[i] % 2 != 0:
            w = 1
        As[i] = int(As[i] / 2)
    counter += 1

print(counter)

Fixed, accepted submission:
N = int(input())
As = [int(c) for c in input().split()]
counter = 0


while True:
    for i in range(N):
        if As[i] % 2 != 0:
            break
        As[i] = int(As[i] / 2)
    else:
        counter += 1
        continue
    break

print(counter)
Problem:
On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).  A red point and a blue point can form a _friendly pair_ when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.  At most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=[]
b=[]
for i in range(n):
    a.append(list(map(int,input().split())))
for i in range(n):
    b.append(list(map(int,input().split())))
an=sorted(a,reverse=True)
bn=sorted(b,reverse=True)
print(an,bn)
count=0
for i in range(len(bn)):
    for j in range(len(an)):
#        print(an[j],bn[i])
        if bn[i][0]>an[j][0] and bn[i][1]>an[j][1]:
            count+=1
            an.pop(j)
            break

print(count)

Fixed, accepted submission:
n=int(input())
a=[]
b=[]
for i in range(n):
    a.append(list(map(int,input().split())))
for i in range(n):
    b.append(list(map(int,input().split())))
an=sorted(a, key=lambda x:-x[1])
bn=sorted(b)#, key=lambda x:(x[0],x[1]))
count=0
for i in range(len(bn)):
    for j in range(len(an)):
#        print(an[j],bn[i])
        if bn[i][0]>an[j][0] and bn[i][1]>an[j][1]:
            count+=1
            an.pop(j)
            break
 
print(count)