TnT/CodeNet4Repair huggingface dataset:
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
print("odd") if a*b%2 == 1 else print("even")

Fixed, accepted submission:
a, b = map(int, input().split())
print("Odd") if (a * b) % 2 == 1 else print("Even")
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
n,k,x,y=(int(input()) for i in [0]*4)
print(n*x-(x-y)*max(k-n,0))

Fixed, accepted submission:
n,k,x,y=(int(input()) for i in [0]*4)
print(n*x-(x-y)*max(n-k,0))
Problem:
There are N people standing in a row from west to east. Each person is facing east or west. The directions of the people is given as a string S of length N. The i-th person from the west is facing east if S_i = `E`, and west if S_i = `W`.  You will appoint one of the N people as the leader, then command the rest of them to face in the direction of the leader. Here, we do not care which direction the leader is facing.  The people in the row hate to change their directions, so you would like to select the leader so that the number of people who have to change their directions is minimized. Find the minimum number of people who have to change their directions.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = input()

cost = S.count('E')

ans = N
for c in S:
    if c == 'E':
        cost -= 1
    else:
        if ans > cost:
            ans = cost
        cost += 1
else:
    if ans > cost:
        ans = cost
print(cost)

Fixed, accepted submission:
N = int(input())
S = input()

cost = S.count('E')

ans = N
for c in S:
    if c == 'E':
        cost -= 1
    else:
        if ans > cost:
            ans = cost
        cost += 1
else:
    if ans > cost:
        ans = cost
print(ans)
Problem:
Snuke has N integers: 1,2,\ldots,N. He will choose K of them and give those to Takahashi.  How many ways are there to choose K consecutive integers?

Incorrect submission (verdict: Wrong Answer):
#input
N, K = input().split()

#output
print(int(N) + int(K) - 1)


Fixed, accepted submission:
n, k =input().split()
print(int(n) - int(k) + 1)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
def main():
  N = int(input())
  sum = 0
  for i in range(1,N+1):
    sum = sum + i
  return sum
  
main()

Fixed, accepted submission:
def main():
  N = int(input())
  sum = 0
  for i in range(1,N+1):
    sum = sum + i
  print(sum)

main()
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
s=input().replace("abc","").replace("acb","").replace("bac","").replace("bca","").replace("cab","").replace("cba","")
if s:
    print("NO")
else:
    print("YES")

Fixed, accepted submission:
S = input()

S1='abc'
S2='acb'
S3='bac'
S4='bca'
S5='cab'
S6='cba'
if S==S1:
    print ('Yes')
elif S==S2:
    print ('Yes')
elif S==S3:
    print ('Yes')
elif S==S4:
    print ('Yes')
elif S==S5:
    print ('Yes')
elif S==S6:
    print ('Yes')
else:
    print ('No')
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

if a + b <= c:
    print("Yes")
else :
    print("No")

Fixed, accepted submission:
a, b, c = map(int, input().split())

if a + b >= c:
    print("Yes")
else :
    print("No")
Problem:
In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands. For convenience, we will call them Island 1, Island 2, ..., Island N.  There are M kinds of regular boat services between these islands. Each service connects two islands. The i-th service connects Island a_i and Island b_i.  Cat Snuke is on Island 1 now, and wants to go to Island N. However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.  Help him.

Incorrect submission (verdict: Wrong Answer):
N,M=map(int,input().split())
s=[]
for j in range(M):
    x=list(input().split())
    if str(N) in x and "1" in x:
        print("POSSIBLE")
        exit()
    if str(N) in x:
        s+=x
    if "1" in x:
        if x[0] in s or x[1] in s:
            print("POSSIBLE")
            exit()
print("IMPOSSIBLE")            

Fixed, accepted submission:
N,M=map(int,input().split())
s=[]
for j in range(M):
    x=list(map(int,input().split()))
    if N in x and 1 in x:
        print("POSSIBLE")
        exit()
    if N in x:
        x.remove(N)
        s+=x
    if 1 in x:
        x.remove(1)
        s+=x
if len(list(set(s)))!=len(s):
    print("POSSIBLE")
    exit()
print("IMPOSSIBLE")
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
s1 = input().split()
print(s1.count("1"))

Fixed, accepted submission:
s=input()
print(s.count("1"))
Problem:
Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

yakusuu = []

for i in range(a, b+1):

    if (c % a == 0) and (c % b == 0):
 
        yakusuu.append(i)

print(yakusuu)


Fixed, accepted submission:
a, b, c = map(int, input().split())

yakusuu = []

for i in range(a, b+1):

    if (c % i == 0):
 
        yakusuu.append(i)

print(len(yakusuu))
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans = 0
for i in range(N):
    x,u = map(str,input().split())
    if(u == "JPY"):
        ans += int(x)
    else:
        x = x.replace(".","")
        ans += (int(x) * 380000 // 10**8)
print(str(ans))

Fixed, accepted submission:
N = int(input())
ans = 0
for i in range(N):
    x,u = map(str,input().split())
    if(u == "JPY"):
        ans += int(x)
    else:
        x = x.replace(".","")
        ans += (int(x) * 380000 / 10**8)
print(str(ans))
Problem:
You are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N). Your objective is to remove some of the elements in a so that a will be a **good sequence**.  Here, an sequence b is a **good sequence** when the following condition holds true:    * For each element x in b, the value x occurs exactly x times in b.  For example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.  Find the minimum number of elements that needs to be removed so that a will be a good sequence.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
an = list(map(int,input().split()))

anset = list(set(an))

counter = 0

for i in range(len(anset)):
    while an.count(anset[i]) > anset[i]:
        couonter = counter + 1
        an.remove(anset[i])
    while 0 < an.count(anset[i]) < anset[i]:
        counter = counter + 1
        an.remove(anset[i])
        
print(counter)

Fixed, accepted submission:
n = int(input())
an = list(map(int,input().split()))

anset = list(set(an))

andict = {}

for i in range(len(an)):
    if an[i] in andict:
        andict[an[i]] = andict[an[i]] + 1
    else:
        andict.update({an[i]:1})

counter = 0

for i ,j in andict.items():
    if i == j :
        None
    elif i > j:
        counter = counter + j
    elif i < j:
        counter = counter + j - i
    
        
print(counter)
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
import numpy

A, B = input().split()
A = int(A)
B = float(B)
print(numpy.int(numpy.floor(A * B)))

Fixed, accepted submission:
import numpy
A, B = input().split()
A = int(A)
B = int(numpy.round(float(B) * 100))
print(A * B // 100)
Problem:
Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 SelectionSort(A) 1 for i = 0 to A.length-1 2     mini = i 3     for j = i to A.length-1 4         if A[j] < A[mini] 5             mini = j 6     swap A[i] and A[mini]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

N = int(input())
A = list(map(int, input().split()))


count = 0
for i in range(N):
    minj = i
    for j in range(i, N):
        if A[j] < A[minj]:
            minj = j
    A[i], A[minj] = A[minj], A[i]
    count += 1

for i in range(N):
    if i == N - 1:
        print("{0}".format(A[i]))
    else:
        print("{0} ".format(A[i]), end="")

print(count)


Fixed, accepted submission:
# -*- coding: utf-8 -*-

N = int(input())
A = list(map(int, input().split()))


count = 0
flag = 0
for i in range(N):

    if N == 1:
        break

    minj = i
    for j in range(i, N):
        if A[j] < A[minj]:
            minj = j
            flag = 1

    if flag == 1:
        A[i], A[minj] = A[minj], A[i]
        count += 1

    flag = 0


for i in range(N):
    if i == N - 1:
        print("{0}".format(A[i]))
    else:
        print("{0} ".format(A[i]), end="")

print(count)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def insertionsSort(A):
    N = len(A)
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j + 1] = A[j]
            j -= 1
        A[j + 1] = v
        print(*A)

N = int(input())
A = list(map(int, input().split()))
insertionsSort(A)

Fixed, accepted submission:
def insertionsSort(A):
    print(*A)
    N = len(A)
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >= 0 and A[j] > v:
            A[j + 1] = A[j]
            j -= 1
        A[j + 1] = v
        print(*A)

N = int(input())
A = list(map(int, input().split()))
insertionsSort(A)
Problem:
There are N cities and M roads. The i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally. There may be more than one road that connects the same pair of two cities. For each city, how many roads are connected to the city?

Incorrect submission (verdict: Wrong Answer):
N, M = list(map(int, input().split()))
array= [0] * (N+1)

for  i in range(1, M+1):
    a, b = list(map(int, input().split()))
    array[a] = array[a] +1
    array[b] = array[b] +1

for j in range(1, N):
    print(array[j])


Fixed, accepted submission:
N, M = list(map(int, input().split()))
array= [0] * (N+1)

for  i in range(1, M+1):
    a, b = list(map(int, input().split()))
    array[a] = array[a] +1
    array[b] = array[b] +1

for j in range(0, N):
    print(array[j+1])
Problem:
Taro's summer vacation starts tomorrow, and he has decided to make plans for it now.  The vacation consists of N days. For each i (1 \leq i \leq N), Taro will choose one of the following activities and do it on the i-th day:    * A: Swim in the sea. Gain a_i points of happiness.   * B: Catch bugs in the mountains. Gain b_i points of happiness.   * C: Do homework at home. Gain c_i points of happiness.  As Taro gets bored easily, he cannot do the same activities for two or more consecutive days.  Find the maximum possible total points of happiness that Taro gains.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = []; B = []; C = []
for i in range(N):
    a, b, c = map(int, input().split())
    A.append(a); B.append(b); C.append(c)

dp = [[0,0,0]]*(N+1)
for i in range(N):
    dp[i+1][0] = max(dp[i+1][0], dp[i][1], dp[i][2]) + A[i]
    dp[i+1][1] = max(dp[i+1][1], dp[i][2], dp[i][0]) + B[i]
    dp[i+1][2] = max(dp[i+1][2], dp[i][0], dp[i][1]) + C[i]


print(max(dp[N]))


Fixed, accepted submission:
N = int(input())
table = []
for i in range(N):
    a, b, c = map(int, input().split())
    table.append((a,b,c))

dpA = [0]*(N+1)
dpB = [0]*(N+1)
dpC = [0]*(N+1)

for i in range(N):
    a, b, c = table[i]
    dpA[i+1] = max(dpB[i], dpC[i]) + a
    dpB[i+1] = max(dpC[i], dpA[i]) + b
    dpC[i+1] = max(dpA[i], dpB[i]) + c

print(max(dpA[N], dpB[N], dpC[N]))
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a, b = [int(i) for i in input().split()]

d = int(a / b)
r = a % b
f = float(a / b)

print(d, r, f)

Fixed, accepted submission:
a, b = [float(i) for i in input().split()]

d = int(a / b)
r = int(a % b)
f = float(a) / float(b)

print('%s %s %.5f' %(d, r, f))
Problem:
You are given two positive integers A and B. Compare the magnitudes of these numbers.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-


a = int(input())
b = int(input())

def comp(a, b):
    if a < b:
        print("LESS")
    if a < b:
        print("GREATER")
    else:
        print("EQUAL")

Fixed, accepted submission:
# -*- coding: utf-8 -*-


a = int(input())
b = int(input())

def comp(a, b):
    if a < b:
        print("LESS")
    elif a > b:
        print("GREATER")
    else:
        print("EQUAL")
        
comp(a, b)
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
def main():
    a,b = list(map(int,input().split()))
    print(solve(a,b))
def solve(a,b):
    m = (a-1) * 12
    n =  b if b < 12 else 12

if __name__ == '__main__':
    main()


Fixed, accepted submission:
def main():
    a,b = list(map(int,input().split()))
    print(solve(a,b))
def solve(a,b):
    m = a-1
    n = 1 if a <= b else 0
    return m + n

if __name__ == '__main__':
    main()
Problem:
Given is a rooted tree with N vertices numbered 1 to N. The root is Vertex 1, and the i-th edge (1 \leq i \leq N - 1) connects Vertex a_i and b_i.  Each of the vertices has a counter installed. Initially, the counters on all the vertices have the value 0.  Now, the following Q operations will be performed:    * Operation j (1 \leq j \leq Q): Increment by x_j the counter on every vertex contained in the subtree rooted at Vertex p_j.  Find the value of the counter on each vertex after all operations.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter,defaultdict
import sys,heapq,bisect,math,itertools,string,queue
mod = 10**9+7
def inp(): return int(sys.stdin.readline())
def inpl(): return list(map(int, sys.stdin.readline().split()))
def inpl_str(): return list(sys.stdin.readline().split())
def conb(n,r): return math.factorial(n) // (math.factorial(n - r) * math.factorial(r))


n,q = inpl()
ki = [[] for i in range(n)]
ans = [0] * n
for i in range(n-1):
    a,b = inpl()
    ki[a-1].append(b)
for i in range(q):
    p,x = inpl()
    ans[p-1] += x

st = [1]
while st:
    tmp = st.pop()
    for j in ki[tmp-1]:
        ans[j-1] += ans[tmp-1]
    st += ki[tmp-1]
print(ans)



Fixed, accepted submission:
from collections import Counter,defaultdict,deque
from heapq import heappop,heappush,heapify
import sys,bisect,math,itertools,pprint,fractions
sys.setrecursionlimit(10**8)
mod = 10**9+7
mod2 = 998244353
INF = float('inf')
def inp(): return int(sys.stdin.readline())
def inpl(): return list(map(int, sys.stdin.readline().split()))
def inpln(n): return list(int(sys.stdin.readline()) for i in range(n))

n,q = inpl()
g = [[]for i in range(n)]
c = [0 for i in range(n)]
seen = [False] * n
for i in range(n-1):
    a,b = inpl()
    g[a-1].append(b-1)
    g[b-1].append(a-1)
for i in range(q):
    a,b = inpl()
    c[a-1] += b
def dfs(node):
    for v in g[node]:
        if seen[v]:
            continue
        c[v] += c[node]
        seen[v] = True
        dfs(v) 
seen[0] = True
dfs(0)
print(*c)
Problem:
Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 SelectionSort(A) 1 for i = 0 to A.length-1 2     mini = i 3     for j = i to A.length-1 4         if A[j] < A[mini] 5             mini = j 6     swap A[i] and A[mini]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Incorrect submission (verdict: Wrong Answer):
def selectsort(A):
	t=0
	for i in range(0,len(A)):
		mini=i
		for j in range(i, len(A)):
			if A[j]<A[mini]:
				mini=j
		if i!=mini:
			temp=A[i]
			A[i]=A[mini]
			A[mini]=temp
			t+=1
	return t		

input=input()
A=[int(s) for s in input.split(' ')]
t=selectsort(A)
print (A,t)

Fixed, accepted submission:
def selectsort(A):
	t=0
	for i in range(0,len(A)):
		mini=i
		for j in range(i, len(A)):
			if A[j]<A[mini]:
				mini=j
		if i!=mini:
			temp=A[i]
			A[i]=A[mini]
			A[mini]=temp
			t+=1
	return t		

input()
input=input()
A=[int(s) for s in input.split(' ')]
t=selectsort(A)
print (' '.join(map(str,A)))
print(t)
Problem:
You are given a string S of length N consisting of lowercase English letters, and an integer K. Print the string obtained by replacing every character in S that differs from the K-th character of S, with `*`.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = str(input())
K = int(input())

t = S[K - 1]

print(t)

ans = ''
for i in S:
    if i == t:
        ans += i
    else:
        ans += '*'

print(ans)

Fixed, accepted submission:
N = int(input())
S = str(input())
K = int(input())

t = S[K - 1]

ans = ''
for i in S:
    if i == t:
        ans += i
    else:
        ans += '*'

print(ans)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
def main():
    a, b, c = map(int, input().split())
    list = []
    list.append(a)
    list.append(b)
    list.append(c)

    if list.count(5) == 2 and list.count(7) == 1 :
        print("Yes")
    else :
        print("No")

if __name__ == '__main__':
    main()


Fixed, accepted submission:
def main():
    a, b, c = map(int, input().split())
    list = []
    list.append(a)
    list.append(b)
    list.append(c)

    if list.count(5) == 2 and list.count(7) == 1 :
        print("YES")
    else :
        print("NO")

if __name__ == '__main__':
    main()
Problem:
Write a program of a Merge Sort algorithm implemented by the following pseudocode. You should also report the number of comparisons in the Merge function.                 Merge(A, left, mid, right)   n1 = mid - left;   n2 = right - mid;   create array L[0...n1], R[0...n2]   for i = 0 to n1-1     do L[i] = A[left + i]   for i = 0 to n2-1     do R[i] = A[mid + i]   L[n1] = SENTINEL   R[n2] = SENTINEL   i = 0;   j = 0;   for k = left to right-1     if L[i] <= R[j]       then A[k] = L[i]            i = i + 1       else A[k] = R[j]            j = j + 1  Merge-Sort(A, left, right){   if left+1 < right     then mid = (left + right)/2;          call Merge-Sort(A, left, mid)          call Merge-Sort(A, mid, right)          call Merge(A, left, mid, right)

Incorrect submission (verdict: Wrong Answer):
def merge(A, left, mid, right):
    L = A[left:mid] + [int(1e9)]
    R = A[mid:right] + [int(1e9)]
    i,j = 0,0
    for k in range(left, right):
        if L[i] <= R[j]:
            A[k] = L[i]
            i += 1
        else:
            A[k] = R[j]
            j += 1
    global count
    count += (right - left)

def merge_sort(A, left, right):
    if left+1 < right:
        mid = (left + right) // 2
        merge_sort(A, left, mid)
        merge_sort(A, mid, right)
        merge(A, left, mid, right)


if __name__=='__main__':
    A = list(map(int, input().strip().split()))
    count = 0
    merge_sort(A, 0, len(A))
    print(" ".join(map(str, A)))
    print(count)

Fixed, accepted submission:
def merge(A, left, mid, right):
    L = A[left:mid] + [int(1e9)]
    R = A[mid:right] + [int(1e9)]
    i,j = 0,0
    for k in range(left, right):
        if L[i] <= R[j]:
            A[k] = L[i]
            i += 1
        else:
            A[k] = R[j]
            j += 1
    global count
    count += (right - left)

def merge_sort(A, left, right):
    if left+1 < right:
        mid = (left + right) // 2
        merge_sort(A, left, mid)
        merge_sort(A, mid, right)
        merge(A, left, mid, right)


if __name__=='__main__':
    n = int(input())
    A = list(map(int, input().strip().split()))
    count = 0
    merge_sort(A, 0, n)
    print(" ".join(map(str, A)))
    print(count)
Problem:
Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())
l = 4 * a * b
r = (c * c - a * a - b * b) * (c * c - a * a - b * b)

if l < r:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a,b,c = map(int, input().split())
l = 4 * a * b
r = (c - a - b) * (c - a - b)

if c - a - b <= 0:
    print("No")
elif c < a or c < b:
    print("No")
elif l < r:
    print("Yes")
else:
    print("No")