TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:    * Choose two among A, B and C, then increase both by 1.   * Choose one among A, B and C, then increase it by 2.  It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Incorrect submission (verdict: Wrong Answer):
L = [int(i) for i in input().split()]
count = 0
L.sort()
while L[2]-L[0] >= 2:
    L[0] += 2
    count += 1
while L[2]-L[1] >= 2:
    L[1] += 2
    count += 1
L.sort()
print(L)
if L[0] != L[1]:
    count += 2
else:
    if L[0] != L[2]:
        count += 1

print(count)


Fixed, accepted submission:
L = [int(i) for i in input().split()]
count = 0
L.sort()
while L[2]-L[0] >= 2:
    L[0] += 2
    count += 1
while L[2]-L[1] >= 2:
    L[1] += 2
    count += 1
L.sort()
if L[0] != L[1]:
    count += 2
else:
    if L[0] != L[2]:
        count += 1

print(count)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b = map(int,input().split())
answer = 0
if abs(x-a) >= abs(x-b):
  answer = "a"
else:
  answer = "b"
print(answer.upper())

Fixed, accepted submission:
x,a,b = map(int,input().split())

print("B" if abs(x-a)>abs(x-b) else "A")
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
a = [4,6,9,	11]
x,y = list(map(int, input().split()))
if x ==2 or y ==2:
  print("No")
elif x in a and y in a:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a = [4,6,9,	11]
b = [1,3,5,7,8,10,12]
x,y = list(map(int, input().split()))
if x ==2 or y ==2:
  print("No")
elif x in a and y in a:
  print("Yes")
elif x in b and y in b:
  print("Yes")
else:
  print("No")
Problem:
You are given an integer sequence of length n, a_1, ..., a_n. Let us consider performing the following n operations on an empty sequence b.  The i-th operation is as follows:    1. Append a_i to the end of b.   2. Reverse the order of the elements in b.  Find the sequence b obtained after these n operations.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline
from collections import deque

n = int(input())
q = deque(list(input().split()))
s = ""
for i in range(n):
  s += q.popleft()
  s[::-1]
  
print(" ".join(s))  


Fixed, accepted submission:
from collections import deque
N = int(input())
S = input().split()
B = deque()

for i in range(N):
  if i%2==0:
    B.append(S[i])
  else:
    B.appendleft(S[i])

if N%2 == 1:
  B.reverse()
print(*B)
Problem:
Niwango-kun is an employee of Dwango Co., Ltd.   One day, he is asked to generate a thumbnail from a video a user submitted.   To generate a thumbnail, he needs to select a frame of the video according to the following procedure:    * Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.   * Select t-th frame whose representation a_t is nearest to the average of all frame representations.   * If there are multiple such frames, select the frame with the smallest index.  Find the index t of the frame he should select to generate a thumbnail.

Incorrect submission (verdict: Wrong Answer):
n=int(input());a=list(map(int,input().split()));ave=sum(a)//n;minn=0
for i in range(1,n):
  if abs(a[minn]-ave)>abs(a[i]-ave):minn=i
print(i)

Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split()))
ave=sum(a)/n
m=10**10
ans=0
for i in a:
  if m>abs(ave-i):
    m=abs(ave-i)
    ans=i
print(a.index(ans))
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
# coding : utf-8

import numpy as np

A = input().split()
A = [int(i) for i in A]

if(A[0] < A[2] and A[0]+A[1] > A[2]):
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
# coding : utf-8

import numpy as np

A = [int(i) for i in input().split()]

if A[0] <= A[2] and A[0] + A[1] >= A[2]:
	print("YES")
else:
	print("NO")
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
a = []
b = []
a = str(input())
b = str(input())
if a[0] == b[2] and a[1] == b[1] and a[2] == b[0]:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
a = []
b = []
a = str(input())
b = str(input())
if a[0] == b[2] and a[1] == b[1] and a[2] == b[0]:
    print("YES")
else:
    print("NO")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

TestCase = int(input())

str_list = []
str_list = [input() for _ in range(TestCase)]


print("{} {}".format("AC ×",str_list.count('AC')))
print("{} {}".format("WA ×",str_list.count('WA')))
print("{} {}".format("TLE ×",str_list.count('TLE')))
print("{} {}".format("RE ×",str_list.count('RE')))

Fixed, accepted submission:
a = int(input())
str_list = []
str_list = [input() for _ in range(a)]
print("AC x",str_list.count("AC"))
print("WA x",str_list.count("WA"))
print("TLE x",str_list.count("TLE"))
print("RE x",str_list.count("RE"))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
i = 0
o = 0
p = 0
s = 0
l = 0
while i < a :
    b = input()
    if b == "AC" :
        o = o + 1
    if b == "WA" :
        p = p + 1
    if b == "TLE" :
        s = s + 1
    if b == "RE" :
        l = l + 1
    i = i + 1
print("AC" , "*" , o)
print("WA" , "*" , p)
print("TLE" , "*" , s)
print("RE" , "*" , l)

Fixed, accepted submission:
a = int(input())
i = 0
o = 0
p = 0
s = 0
l = 0
while i < a :
    b = input()
    if b == "AC" :
        o = o + 1
    if b == "WA" :
        p = p + 1
    if b == "TLE" :
        s = s + 1
    if b == "RE" :
        l = l + 1
    i = i + 1
print("AC" , "x" , o)
print("WA" , "x" , p)
print("TLE" , "x" , s)
print("RE" , "x" , l)
Problem:
Consider the following arithmetic progression with n terms:    * x, x + d, x + 2d, \ldots, x + (n-1)d  What is the product of all terms in this sequence? Compute the answer modulo 1\ 000\ 003.  You are given Q queries of this form. In the i-th query, compute the answer in case x = x_i, d = d_i, n = n_i.

Incorrect submission (verdict: Wrong Answer):
class FactMod:

    def __init__(self, n, mod):
        self.mod = mod
        self.f = [1] * (n + 1)
        for i in range(1, n + 1):
            self.f[i] = self.f[i - 1] * i % mod

        self.inv = [pow(self.f[-1], mod - 2, mod)]
        for i in reversed(range(1, n + 1)):
            self.inv.append(self.inv[-1] * i % mod)
        self.inv.reverse()

    def fact(self, n):
        """
        :return: n!
        """
        return self.f[n]

    def comb(self, n, r):
        """
        :return: nCr
        """
        return self.f[n] * self.inv[n - r] * self.inv[r] % self.mod


Fixed, accepted submission:
class FactMod:

    def __init__(self, n, mod):
        self.mod = mod
        self.f = [1] * (n + 1)
        for i in range(1, n + 1):
            self.f[i] = self.f[i - 1] * i % mod

        self.inv = [pow(self.f[-1], mod - 2, mod)]
        for i in reversed(range(1, n + 1)):
            self.inv.append(self.inv[-1] * i % mod)
        self.inv.reverse()

    def fact(self, n):
        """
        :return: n!
        """
        return self.f[n]


Q = int(input())
items = []
for i in range(Q):
    items.append(tuple(map(int, input().split())))

mod = 10 ** 6 + 3
fact_mod = FactMod(mod - 1, mod)

for x, d, n in items:
    if d == 0:
        print(pow(x, n, mod))
    elif x == 0:
        print(0)
    else:
        
        invd = pow(d, mod - 2, mod)

        
        xd = x * invd % mod

        
        if n - 1 + xd >= mod:
            print(0)
            continue
        
        dn = pow(d, n, mod)
        print(fact_mod.fact(xd + n - 1) * fact_mod.inv[xd - 1] % mod * dn % mod)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a, b, k = map(int,input().split())
for i in range(1, min(a + k + 1, b + 1)):
  print(i)
for i in range(max(b - k, a + k + 1, b + 1)):
  print(i)
  

Fixed, accepted submission:
a, b, k = map(int,input().split())
for i in range(a, min(a + k, b + 1)):
  print(i)
for i in range(max(b - k + 1, a + k), b + 1):
  print(i)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int,input().split(" ")))
b = [5,7,5]

if b == a.sort():
 print("YES")
else:
 print("NO")

Fixed, accepted submission:
a = list(map(int,input().split(" ")))
b = [5,5,7]
a.sort()
if b == a:
 print("YES")
else:
 print("NO")
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Wrong Answer):
N_str, K=input().split()
N_digit=list(map(int,list(N_str)))
D=sorted(list(map(int,input().split())))
l_digit=[n>D[-1] for n in N_digit]

if any(l_digit):
  N_n=l_digit.index(True)
  if not any([n<D[-1] for n in N_digit[0:N_n]]):
    out=[str(D[0]) for i in range(len(N_digit)+1)]
  else:
    out=[str(D[[n<=D[j] for j in range(int(K))].index(True)]) for n in N_digit[0:N_n]] + [str(D[0]) for n in N_digit[N_n:]]
    for k in range(N_n-1,-1,-1):
      if N_digit[k]<D[-1]:
        out[k]=str(D[[N_digit[k]<D[j] for j in range(int(K))].index(True)])
        break
    
else:
  out=[str(D[[n<=D[j] for j in range(int(K))].index(True)]) for n in N_digit]

print(int("".join(out)))



Fixed, accepted submission:
N_str, K=input().split()
K=10-int(K)
N_digit=list(map(int,list(N_str)))
D=sorted(list(map(int,input().split())))
D=[d for d in range(10) if d not in D]

l_digit=[n>D[-1] for n in N_digit]

if any(l_digit):
  N_n=l_digit.index(True)
  if not any([n is not D[-1] for n in N_digit[0:N_n]]):
    out=list(str(D[1] if D[0]==0 else D[0]))
    out+=[str(D[0]) for i in range(len(N_digit))]
  else:
    flag=False
    out=[]
    for i in range(N_n):
      if not flag:
      	for j in range(K):
          if D[j]>=N_digit[i]:
            out.append(str(D[j]))
            if D[j]!=N_digit[i]:
              flag=True
              break
      else:
        out.append(str(D[0]))
    for i in range(N_n,len(N_digit)):
      out.append(str(D[0]))
else:
  out=[]
  flag=False
  for n in N_digit:
    if not flag:
      for j in range(K):
        if D[j]>=n:
          out.append(str(D[j]))
          if D[j]>n:
            flag=True
          break
    else:
      out.append(str(D[0]))
      
print(int("".join(out)))
Problem:
太陽が現れることを「日の出」、隠れることを「日の入り」と呼びますが、その厳密な時刻は太陽が地平線に対してどのような位置にある時でしょうか。  下の図のように、太陽を円、地平線を直線で表すことにします。このとき、太陽の「日の出」「日の入り」の時刻は、太陽を表す円の上端が地平線を表す直線と一致する瞬間とされています。日の出の時刻を過ぎ、円の上端が直線より上にある時間帯が昼間、円が直線の下へ完全に隠れている時間帯が夜間となります。      ある時刻の地平線から太陽の中心までの高さと、太陽の半径を入力とし、その時刻が「昼間」か、「日の出または日の入り」か、「夜間」かを出力するプログラムを作成せよ。

Incorrect submission (verdict: Wrong Answer):
h, r = map(int, input().split())
if h + r < 0:print(-1)
else:print(0 if h == r else 1)


Fixed, accepted submission:
h, r = map(int, input().split())
if h + r < 0:print(-1)
else:print(0 if h + r == 0 else 1)
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
from statistics import median
N = int(input())
a = [int(ai) for ai in input().split()]
med = median(set(a))
ret = sum([(ai - med)**2 for ai in a])
print(ret)

Fixed, accepted submission:
import numpy as np
import math
N = input()
a = np.array([int(ai) for ai in input().split()])
m = np.mean(a)
a1 = (a - math.floor(m))**2
a2 = (a - math.ceil(m))**2
print(min(sum(a1), sum(a2)))
Problem:
On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis. Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i. Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.  For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.  That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
o = input()
e = input()
for i in range(min(len(o),len(e))):
    print('%s%s' % (o[i],e[i]), end='')
if len(o)>len(e): print(o[-1])

Fixed, accepted submission:
n, m = map(int, input().split())
x_list = tuple(map(int, input().split()))
y_list = tuple(map(int, input().split()))
mod = 10 ** 9 + 7
x_sum = 0
for i in range(1, n + 1):
    x_sum += ((i - 1) * x_list[i - 1] - (n - i) * x_list[i - 1]) % mod
y_sum = 0
for i in range(1, m + 1):
    y_sum += ((i - 1) * y_list[i - 1] - (m - i) * y_list[i - 1]) % mod
print(x_sum * y_sum % mod )
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
numbers = list(map(int, input().split()))

for i in range(1, n):
    key = numbers[i]
    j = i - 1
    while 0 <= j and key < numbers[j]:
        numbers[j+1] = numbers[j]
        j -= 1
    numbers[j+1] = key
    print(' '.join(str(x) for x in numbers))

Fixed, accepted submission:
n = int(input())
numbers = list(map(int, input().split()))

print(' '.join(str(x) for x in numbers))
for i in range(1, n):
    key = numbers[i]
    j = i - 1
    while 0 <= j and key < numbers[j]:
        numbers[j+1] = numbers[j]
        j -= 1
    numbers[j+1] = key
    print(' '.join(str(x) for x in numbers))
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())

if ((a+b)%2 == 1):
    print((a+b+1)/2)
else:
  print((a+b)/2)

Fixed, accepted submission:
a, b = map(int, input().split())

if ((a+b)%2 == 1):
    print(int((a+b+1)/2))
else:
    print(int((a+b)/2))
Problem:
Write a program which calculates the area and perimeter of a given rectangle.

Incorrect submission (verdict: Wrong Answer):
s = input()
input_str = s.split(" ")
x = int(input_str[0])
y = int(input_str[1])

print(x * y)

print(2 * (x + y))

Fixed, accepted submission:
s = input()
input_str = s.split(" ")
x = int(input_str[0])
y = int(input_str[1])

print("{0} {1}".format(x * y, 2 * (x + y)))
Problem:
Two students of AtCoder Kindergarten are fighting over candy packs.  There are three candy packs, each of which contains a, b, and c candies, respectively.  Teacher Evi is trying to distribute the packs between the two students so that each student gets the same number of candies. Determine whether it is possible.  Note that Evi cannot take candies out of the packs, and the whole contents of each pack must be given to one of the students.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(lambda x: int(x), input().split())
lis = [a, b, c]
lis.sort()

if a + b == c:
  print('Yes')
else:
  print('No')


Fixed, accepted submission:
a, b, c = map(lambda x: int(x), input().split())
lis = [a, b, c]
lis.sort()

if lis[0] + lis[1] == lis[2]:
  print('Yes')
else:
  print('No')
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
# -*- coding:utf-8 -*-

n = int(input())
t, x, y = [0], [0], [0]
for i in range(n):
  t_i, x_i, y_i = map(int, input().strip().split())
  t.append(t_i)
  x.append(x_i)
  y.append(y_i)
  
can = "YES"
for i in range(n):
  dt = t[i+1] - t[i]
  dist = abs(x[i+1] - x[i]) + abs(y[i+1] - y[i])
  can = "NO" if dt < dist else "YES"
  can = "NO" if dist % 2 != dt % 2 else "YES"
print(can)

Fixed, accepted submission:
# -*- coding:utf-8 -*-

n = int(input())
t, x, y = [0], [0], [0]
for i in range(n):
  t_i, x_i, y_i = map(int, input().strip().split())
  t.append(t_i)
  x.append(x_i)
  y.append(y_i)

  
can = "Yes"
for i in range(n):
  dt = t[i+1] - t[i]
  dist = abs(x[i+1] - x[i]) + abs(y[i+1] - y[i])
  if (dt < dist):
    can = "No"
  if(dist % 2 != dt % 2):
    can = "No"
print(can)
Problem:
You have an integer variable x. Initially, x=0.  Some person gave you a string S of length N, and using the string you performed the following operation N times. In the i-th operation, you incremented the value of x by 1 if S_i=`I`, and decremented the value of x by 1 if S_i=`D`.  Find the maximum value taken by x during the operations (including before the first operation, and after the last operation).

Incorrect submission (verdict: Wrong Answer):
n=int(input())
s=input()
d=[0]*n
for i in range(1,n):
    if s[i]=="I":
        d[i]=d[i-1]+1
    else:
        d[i]=d[i-1]-1
print(max(d))

Fixed, accepted submission:
n=int(input())
s=input()
d=[0]*(n+1)
for i in range(n):
    if s[i]=="I":
        d[i]=d[i-1]+1
    else:
        d[i]=d[i-1]-1
print(max(d))
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
s=input()
s.replace("hi", "")
if s=="":
	print("Yes")
else:
	print("No")

Fixed, accepted submission:
s=input()
for i in range(6):
	if s=="hi" *i:
		print("Yes")
		exit()
print("No")
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
from fractions import Fraction

def is_integer(fraction):
    return fraction.numerator % fraction.denominator == 0

def main(*args, **kwargs):
    """Write Codes for contest here."""
    grid = []
    for i in range(3):
        grid.append(list(map(int, input().split())))

    for b_sum in range(1, 301):
        a1 = Fraction(Fraction(sum(grid[0]), b_sum), 3)
        a2 = Fraction(Fraction(sum(grid[1]), b_sum), 3)
        a3 = Fraction(Fraction(sum(grid[2]), b_sum), 3)
        if is_integer(a1) and is_integer(a2) and is_integer(a3) and 0 <= a1 <= 100 and 0 <= a2 <= 100 and 0 <= a3 <= 100:
            print('Yes')

    print('No')
main()

Fixed, accepted submission:
def main(*args, **kwargs):
    """Write Codes for contest here."""
    grid = []
    for i in range(3):
        grid.append(list(map(int, input().split())))

    #for b_sum in range(1, 301):
    #    a1 = Fraction(Fraction(sum(grid[0]), b_sum), 3)
    #    a2 = Fraction(Fraction(sum(grid[1]), b_sum), 3)
    #    a3 = Fraction(Fraction(sum(grid[2]), b_sum), 3)
    #    if is_integer(a1) and is_integer(a2) and is_integer(a3) and 0 <= a1 <= 100 and 0 <= a2 <= 100 and 0 <= a3 <= 100:
    #        print('Yes')

    for a1 in range(0, 101):
        b1_1 = grid[0][0] - a1
        b2_1 = grid[0][1] - a1
        b3_1 = grid[0][2] - a1
        for a2 in range(0, 101):
            b1_2 = grid[1][0] - a2
            b2_2 = grid[1][1] - a2
            b3_2 = grid[1][2] - a2
            for a3 in range(0, 101):
                b1_3 = grid[2][0] - a3
                b2_3 = grid[2][1] - a3
                b3_3 = grid[2][2] - a3

                # Check the condition
                if b1_1 == b1_2 == b1_3 and b2_1 == b2_2 == b2_3 and b3_1 == b3_2 == b3_3:
                    print('Yes')
                    return
    print('No')
    return
main()
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = 0

for i in range(N):
    if i % 2== 0:
        a = i
        
print(a)
        

Fixed, accepted submission:
N = int(input())
a = 0

if N == 1:
    print(1)
elif N <4:
    print(2)
elif N<8:
    print(4)
elif N<16:
    print(8)
elif N<32:
    print(16)
elif N<64:
    print(32)
elif N<=100:
    print(64)