TnT/CodeNet4Repair huggingface dataset:
Problem:
A binary heap which satisfies max-heap property is called max-heap. In a max- heap, for every node $i$ other than the root, $A    Write a program which reads an array and constructs a max-heap from the array based on the following pseudo code.  $maxHeapify(A, i)$ move the value of $A[i]$ down to leaves to make a sub-tree of node $i$ a max-heap. Here, $H$ is the size of the heap.                 1  maxHeapify(A, i) 2      l = left(i) 3      r = right(i) 4      // select the node which has the maximum value 5      if l ≤ H and A[l] > A[i] 6          largest = l 7      else  8          largest = i 9      if r ≤ H and A[r] > A[largest] 10         largest = r 11 12     if largest ≠ i　// value of children is larger than that of i 13         swap A[i] and A[largest] 14         maxHeapify(A, largest) // call recursively   The following procedure buildMaxHeap(A) makes $A$ a max-heap by performing maxHeapify in a bottom-up manner.                 1 buildMaxHeap(A) 2    for i = H/2 downto 1 3        maxHeapify(A, i)

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))


def maxheapify(a, i):
    l = i*2 + 1
    r = i*2 + 2

    if l <= n and a[l] > a[i]:
        largest = l
    else:
        largest = i
    if r <= n and a[r] > a[largest]:
        largest = r

    if largest != i:
        memo = a[i]
        a[i] = a[largest]
        a[largest] = memo
        maxheapify(a, largest)

h = (n - 1) // 2
for i in reversed(range(h)):
    maxheapify(a, i)


Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))

def maxheapify(a, i):
    l = i*2 + 1
    r = i*2 + 2

    if r < n:
        if a[l] > a[i]:
            largest = l
        else:
            largest = i
        if a[r] > a[largest]:
            largest = r

        if largest != i:
            memo = a[i]
            a[i] = a[largest]
            a[largest] = memo
            maxheapify(a, largest)

    elif l < n:
        if a[l] > a[i]:
            largest = l
        else:
            largest = i
        if largest != i:
            memo = a[i]
            a[i] = a[largest]
            a[largest] = memo
            maxheapify(a, largest)

for i in reversed(range(n)):
    maxheapify(a, i)

print("", *a)
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
s = input()
print("".join([str(s[2*i+1]) for i in range(len(s)//2)]))

Fixed, accepted submission:
s = input()
ans = ""
for i in range(len(s)):
  if i%2 == 0:
    ans = ans + s[i]
print(ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
data = [x for x in input().rstrip()]
print(data.count(1))

Fixed, accepted submission:
data = [x for x in input().rstrip()]
print(data.count("1"))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
otsuri = N % 1000
print(otsuri)

Fixed, accepted submission:
N = int(input())
a = N // 1000
b = N % 1000

if b ==0:
    print(0)
else:
    if N<=1000:
        print(1000-b)
    else:
        print(1000*(a+1)-N)
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans=0
if N%2==0:
    ans=N/2
else:
    ans=int(N/2)
print(ans)

Fixed, accepted submission:
N = int(input())
ans=0
if N%2==0:
    ans=N/2-1
elif N!=1:
    ans=N/2
print(int(ans))
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
# -*- codinf: utf-8 -*-





numList = [int(num) for num in input().split()]


productNumList = numList[0] * numList[1]


if ((productNumList % 2) == 0 ):
    print("even")
else:
    print("odd")


Fixed, accepted submission:
#2019/10/10
a, b = map(int, open(0).read().split())
print("Odd" if (a*b)%2!=0 else "Even")
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))

for i in range(1, N):
    
    v = A[i]
    
    j = i - 1
    
    
    
    while j >= 0 and A[j] > v:
        A[j + 1] = A[j]
        j -= 1
    A[j + 1] = v
    print(' '.join(map(str, A)))

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))

for i in range(N):
    
    v = A[i]
    
    j = i - 1
    
    
    
    while j >= 0 and A[j] > v:
        A[j + 1] = A[j]
        j -= 1
    A[j + 1] = v
    print(' '.join(map(str, A)))
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
import collections

a,b,k=map(int,input().split())
l1=list(range(a,a+k))
l1=[str(i) for i in l1]
l2=list(range(b-k+1,b+1))
l2=[str(i) for i in l2]
ans=l1+l2
ans=collections.Counter(ans)
ans=sorted(ans)
print(" ".join(ans))



Fixed, accepted submission:
a,b,k=map(int,input().split())
ans=[]
for i in range(k):
  if a+i<=b:
    ans.append(a+i)
  if b-i>=a:
    ans.append(b-i)
ans=sorted(set(ans))
print(*ans, sep='\n')
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
def main():
    n = int(input())

    for i in range(n+1):
        if i % 3 == 0 or i % 3 == 10:
            print(i,end=" ")

if __name__ == "__main__":
    main()

Fixed, accepted submission:
def call(a):
    if a % 3 == 0:
        return True

    while a != 0:
        if a % 10 == 3:
            return True

        a //= 10

    return False

def main():
    n = int(input())

    for i in range(1, n + 1):
        if call(i):
            print(" {0}".format(i), end="")

    print("")

if __name__ == "__main__":
    main()
Problem:
You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Incorrect submission (verdict: Wrong Answer):
s = 'keyence'
S = input()
ans = 'NO'

for i in range(len(S)):
    if S[i] == 'k':
        for l in range(1, len(s)):
            if S[i+l] != s[l]:
                break
        for n in range(len(S)-l):

            if S[i:l] + S[l+n:l+n+7-3] == s:
                ans = 'YES'
                break
    if ans == 'YES':
        break
print(ans)


Fixed, accepted submission:
N = input()

if '1' in N and '9' in N and '7' in N and '4' in N:
    print('YES')
else:
    print('NO')
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
N = int(input())
from collections import defaultdict
ans = defaultdict(int)
for a in range(101):
  for b in range(101):
    for c in range(101):
      ans[a**2 + b**2 + c**2 + a*b + a*c + b*c] += 1
for n in range(1,N+1):
  print(ans[n])

Fixed, accepted submission:
N = int(input())
from collections import defaultdict
ans = defaultdict(int)
for a in range(1,101):
  for b in range(1,101):
    for c in range(1,101):
      ans[a**2 + b**2 + c**2 + a*b + a*c + b*c] += 1
for n in range(1,N+1):
  print(ans[n])
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
ab = input().split()
a = int(ab[0])
b = int(ab[1])

if (a+b)%2 == 0:
    print((a+b)/2)
else:
    print((a+b)//2 + 1)

Fixed, accepted submission:
ab = input().split()
a, b = int(ab[0]), int(ab[1])
if (a+b)%2 == 0:
    print((a+b)//2)
else:
    print((a+b)//2 + 1)
Problem:
On a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis. Among the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i. Similarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.  For every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.  That is, for every quadruple (i,j,k,l) satisfying 1\leq i < j\leq n and 1\leq k < l\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
m,n=map(int,input().split())
X=list(map(int,input().split()))
Y=list(map(int,input().split()))
mod=10**9+7

if m>2 and n>2:
    X2=[(X[1]-X[0])%mod,(X[-2]-X[1])%mod,(X[-1]-X[-2])%mod]
    Y2=[(Y[1]-Y[0])%mod,(Y[-2]-Y[1])%mod,(Y[-1]-Y[-2])%mod]
    ans=0
    a,b1,b2,c=m*n,(2*m-2)*n,(2*n-2)*m,(2*m-2)*(2*n-2)
    ans+=(X2[0]*Y2[0] + X2[2]*Y2[0] + X2[0]*Y2[2] + X2[2]*Y2[2])*a%mod
    ans+=(X2[1]*Y2[0]+X2[1]*Y2[2])*b1%mod
    ans+=(X2[0]*Y2[1]+X2[2]*Y2[1])*b2%mod
    ans+=X2[1]*Y2[1]*c%mod
    print(ans%mod)
else:
    print(mod)

Fixed, accepted submission:
n,m=map(int,input().split())
X=list(map(int,input().split()))
Y=list(map(int,input().split()))
mod=10**9+7

ans1=0
for k in range(1,n+1):
    ans1+=(2*k-1-n)*X[k-1]
    ans1%=mod
ans2=0
for k in range(1,m+1):
    ans2+=(2*k-1-m)*Y[k-1]
    ans2%=mod
print(ans1*ans2%mod)
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
nums = list(map(int, input().split()))

unq = list(set(nums))


if len(unq) > 3:
  print("No")

if len(unq) == 3:
    
    a,b,c = unq
    if a ^ b ^ c != 0:
      if nums.count(a) == nums.count(b) == nums.count(c):
        print("Yes")
      else:
        print("No")
    else:
      print("No")

if len(unq) == 2:
    a,b = sorted(unq)
    if a == 0:
      if nums.count(a) * 2 == nums.count(b):
        print("Yes")
      else:
        print("No")
    else:
      print("No")

if len(unq) == 1:
    a = unq[0]
    if a != 0:
      print("No")
    else:
      print("Yes")

Fixed, accepted submission:
n = int(input())
nums = list(map(int, input().split()))

unq = list(set(nums))


if len(unq) > 3:
  print("No")

if len(unq) == 3:
    
    a,b,c = unq
    if a ^ b ^ c == 0:
      if nums.count(a) == nums.count(b) == nums.count(c):
        print("Yes")
      else:
        print("No")
    else:
      print("No")

if len(unq) == 2:
    a,b = sorted(unq)
    if a == 0:
      if nums.count(a) * 2 == nums.count(b):
        print("Yes")
      else:
        print("No")
    else:
      print("No")

if len(unq) == 1:
    a = unq[0]
    if a != 0:
      print("No")
    else:
      print("Yes")
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split()))
n=0
if all(aa%2==0 for aa in a):
  n+=1
print(n)

Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split()))
ans=0
while all(aa%2==0 for aa in a):
  ans+=1
  a=[aa//2 for aa in a]
print(ans)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
print('YNEOS'[eval(input().replace(*' *'))!=245::2])

Fixed, accepted submission:
print('YNEOS'[eval(input().replace(*' *'))!=175::2])
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
print(input())

Fixed, accepted submission:
x = int(input())
print(x*x*x)
Problem:
In this problem, we only consider strings consisting of lowercase English letters.  Strings s and t are said to be **isomorphic** when the following conditions are satisfied:    * |s| = |t| holds.   * For every pair i, j, one of the following holds:     * s_i = s_j and t_i = t_j.     * s_i \neq s_j and t_i \neq t_j.  For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.  A string s is said to be in **normal form** when the following condition is satisfied:    * For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.  For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.  You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python
# coding: utf-8

def ri():
    return int(input())

def rl():
    return list(input().split())

def rli():
    return list(map(int, input().split()))

words = set()
alp = list("abcdefghij")
def dfs(n, s):
    if len(s) == n:
        return
    for i in range(0, len(s)):
        for c in alp:
            if ord(c)>ord(s[i])+1:
                break
            ns = s[:i+1]+c+s[i+1:]
            if ns in words:
                continue
            words.add(ns)
            dfs(n, ns)

def main():
    n = ri()
    dfs(n, 'a')
    for w in sorted(words):
        if len(w) == n:
            print(w)



if __name__ == '__main__':
    main()


Fixed, accepted submission:
#!/usr/bin/env python
# coding: utf-8

def ri():
    return int(input())

def rl():
    return list(input().split())

def rli():
    return list(map(int, input().split()))

words = set()
alp = list("abcdefghij")
def dfs(n, s):
    if len(s) == n:
        return
    for i in range(0, len(s)):
        for c in alp:
            if ord(c)>ord(s[i])+1:
                break
            ns = s[:i+1]+c+s[i+1:]
            if ns in words:
                continue
            words.add(ns)
            dfs(n, ns)

def main():
    n = ri()
    if n == 1:
        print("a")
        return
    dfs(n, 'a')
    for w in sorted(words):
        if len(w) == n:
            print(w)



if __name__ == '__main__':
    main()
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
s = input()
x = s[0]
ans = 'A'+x+'C'
print(ans)

Fixed, accepted submission:
s = input()
x = s[8]
ans = 'A'+x+'C'
print(ans)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())

temp = n%500
if temp<=a:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
n = int(input())
a = int(input())

temp = n%500
if temp<=a:
  print("Yes")
else:
  print("No")
Problem:
There is an empty array. The following N operations will be performed to insert integers into the array. In the i-th operation (1≤i≤N), b_i copies of an integer a_i are inserted into the array. Find the K-th smallest integer in the array after the N operations. For example, the 4-th smallest integer in the array \\{1,2,2,3,3,3\\} is 3.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
l = [tuple(map(int, input().split())) for i in range(n)]
l.sort()
l.append((0, k))
d = [l[0][1]]
for i in range(1,n+1):
    d.append(d[i-1] + l[i][1])
t = 0
while d[t] <= k:
    t += 1
print(l[t-1][0])

Fixed, accepted submission:
n, k = map(int, input().split())
l = [tuple(map(int, input().split())) for i in range(n)]
l.sort()
l.append((0, k))
d = [l[0][1]]
for i in range(1,n+1):
    d.append(d[i-1] + l[i][1])
t = 0
while d[t] < k:
    t += 1
print(l[t][0])
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
if (a,b,c).count("5")==2 and (a,b,c).count("7")==1:
    print('YES')
else:
    print('NO')


Fixed, accepted submission:
a,b,c=map(int,input().split())
if (a,b,c).count(5)==2 and (a,b,c).count(7)==1:
    print('YES')
else:
    print('NO')
Problem:
Takahashi received _otoshidama_ (New Year's money gifts) from N of his relatives.  You are given N values x_1, x_2, ..., x_N and N strings u_1, u_2, ..., u_N as input. Each string u_i is either `JPY` or `BTC`, and x_i and u_i represent the content of the otoshidama from the i-th relative.  For example, if x_1 = `10000` and u_1 = `JPY`, the otoshidama from the first relative is 10000 Japanese yen; if x_2 = `0.10000000` and u_2 = `BTC`, the otoshidama from the second relative is 0.1 bitcoins.  If we convert the bitcoins into yen at the rate of 380000.0 JPY per 1.0 BTC, how much are the gifts worth in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
X = [input().split() for _ in range(N)]

Y = 0
for i in X:
    print(i[1])
    if i[1] == 'JPY':
        Y += int(i[0])
    elif i[1] == 'BTC':
        Y += (380000.0 * float(i[0]))

print(Y)

Fixed, accepted submission:
N = int(input())
X = [input().split() for _ in range(N)]

Y = 0
for i in X:
    if i[1] == 'JPY':
        Y += int(i[0])
    elif i[1] == 'BTC':
        Y += (380000.0 * float(i[0]))

print(Y)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
untax_N = round(N/1.08)

if round(untax_N*1.08) != N:
  print(":(")
else:
  pass

Fixed, accepted submission:
N = int(input())
count = 0

for i in range(N+1):
  if N <= int(i*1.08) < N+1:
    print(i)
    count += 1
    break

if count == 0:
    print(":(")
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split()))
a.sort()
print((sum(a[::2])-(sum(a[1::2]))))

Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
print((sum(a[::2])-(sum(a[1::2]))))
Problem:
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.  Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.  Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.

Incorrect submission (verdict: Wrong Answer):
a,b,c,d=map(int,input().split())
x=a+b
y=c+d
if x>y:
  print("Left")
if x>y:
  print("Right")
if x==y:
  print("Balanced")
  

Fixed, accepted submission:
a,b,c,d=map(int,input().split())
x=a+b
y=c+d
if x>y:
  print("Left")
if x<y:
  print("Right")
if x==y:
  print("Balanced")