TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
def solve():
    while 1:
        try:
            s = list(input())
            s.reverse()
            s = "".join(s)
            if len(s) < 5:
                raise EndLoop

            l = 0
            r = 5
            while r <= len(s):
                if s[l:r] == "maerd" or s[l:r] == "esare":
                    l += 5
                    r += 5
                elif s[l:r] == "remae" or s[l:r] == "resar":
                    l += 7
                    r += 7
                else:
                    raise EndLoop

            print(l, r)
            print(len(s))
            print("YES")
            break
        except:
            print("NO")
            break


solve()

Fixed, accepted submission:
def solve():
    while 1:
        try:
            s = list(input())
            s.reverse()
            s = "".join(s)
            if len(s) < 5:
                raise EndLoop

            l = 0
            r = 5
            while r <= len(s):
                if s[l:r] == "maerd" or s[l:r] == "esare":
                    l += 5
                    r += 5
                elif s[l:r] == "remae":
                    if s[l:r + 2] == "remaerd":
                        l += 7
                        r += 7
                    else:
                        raise EndLoop
                elif s[l:r] == "resar":
                    if s[l:r + 1] == "resare":
                        l += 6
                        r += 6
                    else:
                        raise EndLoop
                else:
                    raise EndLoop

            print("YES")
            break
        except:
            print("NO")
            break


solve()
Problem:
There are a number of ways to shuffle a deck of cards. Hanafuda shuffling for Japanese card game 'Hanafuda' is one such example. The following is how to perform Hanafuda shuffling.  There is a deck of _n_ cards. Starting from the _p_ -th card from the top of the deck, _c_ cards are pulled out and put on the top of the deck, as shown in Figure 1. This operation, called a cutting operation, is repeated.  Write a program that simulates Hanafuda shuffling and answers which card will be finally placed on the top of the deck.     ---   Figure 1: Cutting operation

Incorrect submission (verdict: Wrong Answer):
while True:
    n, r = list(map(lambda x: int(x), input().split(" ")))
    if n == 0 and r == 0:
        break
    cards = [i for i in range(1,n+1)]
    cards = cards[::-1]

    for i in range(r):
        print(cards)
        p, c = list(map(lambda x: int(x), input().split(" ")))
        p -= 1
        cards = cards[p:p+c] + cards[0:p] + cards[p+c:]
    
    print(cards[0])


Fixed, accepted submission:
while True:
    n, r = list(map(lambda x: int(x), input().split(" ")))
    if n == 0 and r == 0:
        break
    cards = [i for i in range(1,n+1)]
    cards = cards[::-1]

    for i in range(r):
        p, c = list(map(lambda x: int(x), input().split(" ")))
        p -= 1
        cards = cards[p:p+c] + cards[0:p] + cards[p+c:]
    
    print(cards[0])
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
import math
a,b=input().split()
n=int(a+b)
"Yes" if math.sqrt(n)%1==0 else "No"


Fixed, accepted submission:
import math
a,b=input().split()
n=int(a+b)
print("Yes" if math.sqrt(n).is_integer() else "No")
Problem:
You are given a string S consisting of lowercase English letters. We will write down this string, starting a new line after every w letters. Print the string obtained by concatenating the letters at the beginnings of these lines from top to bottom.

Incorrect submission (verdict: Wrong Answer):
S = input()
w = int(input())

L = (len(S) // w)

moji = str()

for i in range(L):
    moji = moji + S[(i + 1)* w - 2]

print(moji) 

Fixed, accepted submission:
S = str(input())
w = int(input())

if len(S) % w == 0:
    L = len(S) // w
else:
    L = len(S) // w + 1

moji = str()

for i in range(L):
    moji = moji + S[i* w]

print(moji)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
t = []
x = []
y = []
ans = "Yes"
tmpx = 0
tmpy = 0
for i in range(n):
    v1,v2,v3 = map(int,input().split())
    t.append(v1)
    x.append(v2)
    y.append(v3)
for i in range(n):
    if abs(tmpx-x[i]) + abs(tmpy-y[i]) <= t[i]:
        tmpx = x[i]
        tmpy = y[i]
        continue
    else:
        flg = "No"
        break

Fixed, accepted submission:
n = int(input())
t = []
x = []
y = []
ans = "Yes"
tmpx = 0
tmpy = 0
tmpt = 0
for i in range(n):
    v1,v2,v3 = map(int,input().split())
    t.append(v1)
    x.append(v2)
    y.append(v3)
for i in range(n):
    if abs(tmpx-x[i]) + abs(tmpy-y[i]) <= t[i] - tmpt and (abs(tmpx-x[i]) + abs(tmpy-y[i])) % 2 == (t[i] - tmpt) % 2:
        tmpx = x[i]
        tmpy = y[i]
        tmpt = t[i]
        continue
    else:
        ans = "No"
        break
print(ans)
Problem:
AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.  The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.  How many different PIN codes can he set this way?  Both the lucky number and the PIN code may begin with a 0.

Incorrect submission (verdict: Wrong Answer):

import sys
import math
from functools import reduce

def readString():
    return sys.stdin.readline()

def readInteger():
    return int(readString())

def main(N, S):
    """ main
    """
    count = 0
    skip1 = []
    skip2 = []
    skip3 = []

    for i in range(0, N):
        if S[i] in skip1:
            continue
        skip1.append(S[i])
        for j in range(i+1, N):
            if S[j] in skip2:
                continue
            skip2.append(S[j])
            for k in range(j+1, N):
                if S[k] in skip3:
                    continue
                skip3.append(S[k])
                print(S[i]+S[j]+S[k])
                count += 1
            skip3 = []
        skip2 = []

    return count

if __name__ == "__main__":
    _N = readInteger()
    _S = readString()

    print(main(_N, _S))

Fixed, accepted submission:

import sys
import math
from functools import reduce

def readString():
    return sys.stdin.readline()

def readInteger():
    return int(readString())

def main(N, S):
    """ main
    """
    count = 0
    skip1 = []
    skip2 = []
    skip3 = []

    for i in range(0, N):
        if S[i] in skip1:
            continue
        skip1.append(S[i])
        for j in range(i+1, N):
            if S[j] in skip2:
                continue
            skip2.append(S[j])
            for k in range(j+1, N):
                if S[k] in skip3:
                    continue
                skip3.append(S[k])
                count += 1
            skip3 = []
        skip2 = []

    return count

if __name__ == "__main__":
    _N = readInteger()
    _S = readString()

    print(main(_N, _S))
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
tmp = input()

a = int(tmp.split(" ")[0])
b = int(tmp.split(" ")[1])

x = a * b

if x % 2 == 0:
  print('Odd')
else:
  print('Even')

Fixed, accepted submission:
tmp = input()

a = int(tmp.split(" ")[0])
b = int(tmp.split(" ")[1])

x = a * b

if x % 2 == 0:
  print('Even')
else:
  print('Odd')
Problem:
You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:    * Choose two among A, B and C, then increase both by 1.   * Choose one among A, B and C, then increase it by 2.  It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Incorrect submission (verdict: Wrong Answer):
# input
X = list(map(int, input().split()))

X.sort()

if (2 * X[2] - X[1] - X[0]) % 2 == 0:
    ans = (2 * X[2] - X[1] - X[0]) / 2
else:
    ans = (2 * X[2] - X[1] - X[0] + 1) / 2

print(ans)

Fixed, accepted submission:
# input
X = list(map(int, input().split()))

X.sort()

if (X[1] - X[0]) % 2 == 0:
    ans = X[2] - X[1] + (X[1] - X[0]) // 2 
else:
    ans = X[2] - X[1] + 1 + (X[1] - X[0] + 1) //2

print(ans)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
def resolve():
    n, m = map(int, input().split())
    ab = [list(map(int, input().split()))for i in range(m)]
    ans = [0] * n
    edge = [[]for _ in range(n)]
    for a, b in ab:
        edge[a - 1].append(b - 1)
        edge[b - 1].append(a - 1)
    visited = {0}
    stack = [0]
    for i in stack:
        for j in edge[i]:
            if j in visited:
                continue
            stack.append(j)
            visited.add(j)
            ans[j] = i + 1
    print("Yes")
    print('\n'.join(map(str, ans[1:])))

Fixed, accepted submission:
def resolve():
    n, m = map(int, input().split())
    ab = [list(map(int, input().split()))for i in range(m)]
    ans = [0] * n
    edge = [[]for _ in range(n)]
    for a, b in ab:
        edge[a - 1].append(b - 1)
        edge[b - 1].append(a - 1)
    visited = {0}
    stack = [0]
    for i in stack:
        for j in edge[i]:
            if j in visited:
                continue
            stack.append(j)
            visited.add(j)
            ans[j] = i + 1
    print("Yes")
    print('\n'.join(map(str, ans[1:])))


resolve()
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
a = input()
b = input()
if a == b[--1]:
  print('YES')
else:
  print('NO')

Fixed, accepted submission:
a = input()
b = input()
if a == b[::-1]:
  print('YES')
else:
  print('NO')
Problem:
Let {\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order. From n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\rm comb}(a_i,a_j) is maximized. If there are multiple pairs that maximize the value, any of them is accepted.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int,input().split()))
m = 0
st_n = a[0]
st_r = a[1]
for n in range(N-1):
    for r in range(n+1,N):
        if a[r] != 0:
            if m < a[n]*(a[n]-1)//a[r]:
                st_n = a[n]
                st_r = a[r]
                m = a[n]*(a[n]-1)//a[r]
a.reverse()
for n in range(N-1):
    for r in range(n+1,N):
        if a[r] != 0:
            if m < a[n]*(a[n]-1)//a[r]:
                st_n = a[n]
                st_r = a[r]
                m = a[n]*(a[n]-1)//a[r]

print(st_n,st_r)

Fixed, accepted submission:
N = int(input())
a = list(map(int,input().split()))
a.sort(reverse=True)
st_n = a[0]
st_r = a[1]
m = st_r*(st_n-st_r)
for r in range(2,N):
    cn = a[r]*(st_n-a[r])
    if m < cn:
        st_r = a[r]
        m = cn
print(st_n,st_r)
Problem:
Takahashi is a user of a site that hosts programming contests.   When a user competes in a contest, the _rating_ of the user (not necessarily an integer) changes according to the _performance_ of the user, as follows:    * Let the current rating of the user be a.   * Suppose that the performance of the user in the contest is b.   * Then, the new rating of the user will be the avarage of a and b.  For example, if a user with rating 1 competes in a contest and gives performance 1000, his/her new rating will be 500.5, the average of 1 and 1000.  Takahashi's current rating is R, and he wants his rating to be exactly G after the next contest.   Find the performance required to achieve it.

Incorrect submission (verdict: Wrong Answer):
R=input()
G=input()
print(2*G+R)

Fixed, accepted submission:
R=int(input())
G=int(input())
print(2*G-R)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python
# -*- coding: utf-8 -*-


def iSort(A,N):
    """ ?????\????????? """
#    print(" ".join(map(str,A)))
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >=0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v
        print(" ".join(map(str,A)))

# ?????????
num = int(input().strip())
arr = list(map(int,input().strip().split()))
iSort(arr,num)

Fixed, accepted submission:
#!/usr/bin/env python
# -*- coding: utf-8 -*-


def iSort(A,N):
    """ ?????\????????? """
    print(" ".join(map(str,A)))
    for i in range(1, N):
        v = A[i]
        j = i - 1
        while j >=0 and A[j] > v:
            A[j+1] = A[j]
            j -= 1
        A[j+1] = v
        print(" ".join(map(str,A)))

# ?????????
num = int(input().strip())
arr = list(map(int,input().strip().split()))
iSort(arr,num)
Problem:
Given is a rooted tree with N vertices numbered 1 to N. The root is Vertex 1, and the i-th edge (1 \leq i \leq N - 1) connects Vertex a_i and b_i.  Each of the vertices has a counter installed. Initially, the counters on all the vertices have the value 0.  Now, the following Q operations will be performed:    * Operation j (1 \leq j \leq Q): Increment by x_j the counter on every vertex contained in the subtree rooted at Vertex p_j.  Find the value of the counter on each vertex after all operations.

Incorrect submission (verdict: Wrong Answer):
N,Q=map(int,input().split())
side=[[0 for i in range(2)]for j in range(N-1)]
yobun=[[0 for i in range(2)]for j in range(Q)]

l=[0]*N


for i in range(N-1):
    side[i][0],side[i][1]=map(int,input().split())
    
for i in range(Q):
    yobun[i][0],yobun[i][1]=map(int,input().split())


def kyusyu(p,x):
    l[p-1]+=x
    for i in range(N-1):
        if p==side[i][0]:
            kyusyu(side[i][1],x)
            
for i in range(Q):
    kyusyu(yobun[i][0],yobun[i][1])
    
    
print(l)
    






Fixed, accepted submission:
# coding: utf-8 
# Your code here!
import sys
input=sys.stdin.readline
sys.setrecursionlimit(100000000)

N,Q=map(int,input().split()) 

l=[[i] for i in range(N)] 

#print(l) 
def dfs(num,point,visited): 
    visited[num]=1 
    point+=plus[num] 
    
    ans[num]=point 
    while l[num][-1]!=num: 
        temp=l[num].pop(-1) 
        if visited[temp]==0: 
            dfs(temp,point,visited) 
            
    return 0 

for _ in range(N-1): 
    a,b=map(int,input().split()) 
    l[a-1].append(b-1) 
    l[b-1].append(a-1) 
    
ans=[0]*N 
plus=[0]*N 

for _ in range(Q): 
    p,x=map(int,input().split()) 
    plus[p-1]+=x 

dfs(0,0,[0]*N) 

print(*ans)
Problem:
    This figure shows railway tracks for reshuffling cars. The rail tracks end in the bottom and the top-left rail track is used for the entrace and the top- right rail track is used for the exit. Ten cars, which have numbers from 1 to 10 respectively, use the rail tracks.  We can simulate the movement (comings and goings) of the cars as follow:    * An entry of a car is represented by its number.   * An exit of a car is represented by 0  For example, a sequence                 1 6 0 8 10   demonstrates that car 1 and car 6 enter to the rail tracks in this order, car 6 exits from the rail tracks, and then car 8 and car 10 enter.  Write a program which simulates comings and goings of the cars which are represented by the sequence of car numbers. The program should read the sequence of car numbers and 0, and print numbers of cars which exit from the rail tracks in order. At the first, there are no cars on the rail tracks. You can assume that 0 will not be given when there is no car on the rail tracks.

Incorrect submission (verdict: Wrong Answer):
a=[]
while 1:
 try:n=int(input());a.append(e)if e else print(a.pop())
 except:break


Fixed, accepted submission:
import sys
a=[]
for e in map(int,sys.stdin):a.append(e)if e else print(a.pop())
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
N = input()

if N[1] == N[2]:
  print('YES')
else:
  print('NO')

Fixed, accepted submission:
N = input()

nums = ["000", "111", "222", "333", "444", "555", "666", "777", "888", "999"]

if N[:3] in nums or N[1:] in nums:
  print('Yes')

else:
  print('No')
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
rows = []
for _ in range(3):
  rows.append(list(map(int, input().split())))
for i in range(3):
  for j in range(3):
    rows[i][j] -= rows[i][0]
ok = True
for j in range(3):
  for i in range(3):
    if rows[i][j] != rows[0][j]:
      ok = False
if ok: print("Yes")
else: print("No")

Fixed, accepted submission:
rows = []
for _ in range(3):
  rows.append(list(map(int, input().split())))
for i in range(3):
  for j in range(2, -1, -1):
    rows[i][j] -= rows[i][0]
ok = True
for j in range(3):
  for i in range(3):
    if rows[i][j] != rows[0][j]:
      ok = False
if ok: print("Yes")
else: print("No")
Problem:
We have N sticks with negligible thickness. The length of the i-th stick is A_i.  Snuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides. Find the maximum possible area of the rectangle.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int,input().split()))
from collections import Counter
c = Counter(a)
#print(c.most_common())
if c.most_common()[0][1] >= 4:
    print((c.most_common()[1][1])**2)
elif c.most_common()[0][1] == 1:
    print(0)
elif c.most_common()[1][1] >= 2:
    print(c.most_common()[0][1]*c.most_common()[1][1])
else:print(0)

Fixed, accepted submission:
N = int(input())
A = list(map(int,input().split()))
A.sort(reverse=True)
#print(A)
cnt = 0
prev = 0
candidates = []
for i in A:
    if i == prev:
        cnt += 1
        prev = i
    elif i != prev:
        prev = i
        cnt = 0
    if cnt >= 3:
        print(i**2)
        exit()
    if cnt == 1:
        candidates.append(i)
    if len(candidates) == 2:
        print(candidates[0]*candidates[1])
        exit()

print(0)
Problem:
You are given a string S consisting of lowercase English letters. Find the lexicographically (alphabetically) smallest lowercase English letter that does not occur in S. If every lowercase English letter occurs in S, print `None` instead.

Incorrect submission (verdict: Wrong Answer):
sList = sorted(list(set(list(input()))))
chI = ord('a')
for i in sList:
  if chI == ord(i):
    chI += 1
  else:
    print(chI)
    exit(0)

print("None")


Fixed, accepted submission:
sList = sorted(list(set(list(input()))))
chI = ord('a')
for i in sList:
  if chI == ord(i):
    chI += 1
  else:
    print(chr(chI))
    exit(0)
if len(sList) != 26:
  print(chr(chI))
else:
  print("None")
Problem:
There is a kangaroo at coordinate 0 on an infinite number line that runs from left to right, at time 0. During the period between time i-1 and time i, the kangaroo can either stay at his position, or perform a jump of length exactly i to the left or to the right. That is, if his coordinate at time i-1 is x, he can be at coordinate x-i, x or x+i at time i. The kangaroo's nest is at coordinate X, and he wants to travel to coordinate X as fast as possible. Find the earliest possible time to reach coordinate X.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if n == 1:
    print(1)
elif n == 2:
    print(2)
else:
    for i in range(n):
        if n <= i // 2 * (i + 1):
            break

    print(i)


Fixed, accepted submission:
n = int(input())
ans = 0
for i in range(1, n + 1):
    if n <= i * (i + 1) // 2:
        ans = i
        break
print(ans)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
def gcd(a, b):
  if b == 0:
    return a
  else:
    return gcd(b, a%b)

A, B, C = map(int, input().split())

print(["YES","NO"][gcd(A,B)<=C])

Fixed, accepted submission:
def gcd(a, b):
  if b == 0:
    return a
  else:
    return gcd(b, a%b)

A, B, C = map(int, input().split())

print(["NO","YES"][B>C and C%gcd(A,B)==0])