TnT/CodeNet4Repair huggingface dataset:
Problem:
Write a program which reads a sequence _A_ of _n_ elements and an integer _M_ , and outputs "yes" if you can make _M_ by adding elements in _A_ , otherwise "no". You can use an element only once.  You are given the sequence _A_ and _q_ questions where each question contains _M i_.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf_8 -*-

from itertools import repeat

def rec(s, i, total, m):
    if total == m:
        return 1

    if len(s) - 1 == i or total > m:
        return 0

    return rec(s, i + 1, total, m) + rec(s, i + 1, total + s[i], m)

if __name__ == "__main__":
    n = int(input())
    a = [int (x) for x in input().split()]
    q = int(input())
    m = [int (x) for x in input().split()]
    for i in m:
        print("yes") if rec(a, 0, 0, i) > 0 else print("no")

Fixed, accepted submission:
# -*- coding: utf_8 -*-

from itertools import repeat
from itertools import combinations

def rec(s, i, total, m):
    if total == m:
        return 1

    if len(s) == i or total > m:
        return 0

    return rec(s, i + 1, total, m) + rec(s, i + 1, total + s[i], m)


def makeCache(s):
    cache = {}
    for i in range(len(s)):
        comb = list(combinations(s, i))
        for c in comb:
            cache[sum(c)] = 1

    return cache

def loop(s, m):
    for i in range(len(s)):
        comb = list(combinations(s, i))
        for c in comb:
            if sum(c) == m:
                return 1

    return 0

if __name__ == "__main__":
    n = int(input())
    a = [int (x) for x in input().split()]
    q = int(input())
    m = [int (x) for x in input().split()]
    s = makeCache(a)
    for i in m:
        #print("yes") if rec(a, 0, 0, i) > 0 else print("no")
        #print("yes") if loop(a, i) > 0 else print("no")
        print("yes") if i in s else print("no")
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
import itertools

def solve(S):
    bit_list = list(itertools.product([0, 1], repeat=3))
    
    for pattern in bit_list:
        count = int(S[0])
        ans = S[0]
        for i in range(3):
            if pattern[i] == 0:
                count += int(S[i+1])
                ans += "+" + S[i+1]
            else:
                count -= int(S[i+1])
                ans += "-" + S[i+1]
        
        if count == 7:
            print(ans)
            break
    

if __name__ == '__main__':
    S = input()
    solve(S)

Fixed, accepted submission:
import itertools

def solve(S):
    bit_list = list(itertools.product([0, 1], repeat=3))
    
    for pattern in bit_list:
        count = int(S[0])
        ans = S[0]
        for i in range(3):
            if pattern[i] == 0:
                count += int(S[i+1])
                ans += "+" + S[i+1]
            else:
                count -= int(S[i+1])
                ans += "-" + S[i+1]
        
        if count == 7:
            print(ans + "=7")
            break
    

if __name__ == '__main__':
    S = input()
    solve(S)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
A,B,X=map(int,input().split())
if B>=X-A and A<X:
  print("Yes")
else:
  print("No")


Fixed, accepted submission:
A,B,X=map(int,input().split())
if B>=X-A and A<=X:
  print("YES")
else:
  print("NO")
Problem:
You went shopping to buy cakes and donuts with X yen (the currency of Japan).  First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.  How much do you have left after shopping?

Incorrect submission (verdict: Wrong Answer):
x = int(input())
a = int(input())
b = int(input())
print(x-a-b)

Fixed, accepted submission:
x = int(input())
a = int(input())
b = int(input())
print((x-a)%b)
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
X, Y, N = map(int, input().split())
lst = [[0 for i in range(X)] for j in range(Y)]

for i in (range(N)):
    x, y, a = map(int, input().split())
    if a == 1:
        for j in range(Y):
            for k in range(x):
                lst[j][k] = 1
    elif a == 2:
        for j in range(Y):
            for k in range(X-1, x-1, -1):
                lst[j][k] = 1
    elif a == 3:
        for j in range(y):
            for k in range(X):
                lst[j][k] = 1
    elif a == 4:
        for j in range(Y-1, y-1, -1):
            for k in range(X):
                lst[j][k] = 1
for i in lst:
    print(i)

count = 0
for i in lst:
    count += i.count(0)
print(count)



Fixed, accepted submission:
X, Y, N = map(int, input().split())
lst = [[0 for i in range(X)] for j in range(Y)]

for i in (range(N)):
    x, y, a = map(int, input().split())
    if a == 1:
        for j in range(Y):
            for k in range(x):
                lst[j][k] = 1
    elif a == 2:
        for j in range(Y):
            for k in range(X-1, x-1, -1):
                lst[j][k] = 1
    elif a == 3:
        for j in range(y):
            for k in range(X):
                lst[j][k] = 1
    elif a == 4:
        for j in range(Y-1, y-1, -1):
            for k in range(X):
                lst[j][k] = 1

count = 0
for i in lst:
    count += i.count(0)
print(count)
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/python3
# ABC058_B


test = True

def restore():
    
    O = input()  
    E = input()  
    password = ''  
    len_O = len(O)
    if test:
        print(len_O)

    for i in range(len_O):
        password += O[i]
        try:
            password += E[i]
        except IndexError:
            pass

    return password


def main():
    
    print(restore())


if __name__ == '__main__':
    main()


Fixed, accepted submission:
#!/usr/bin/python3
# ABC058_B


test = False

def restore():
    
    O = input()  
    E = input()  
    password = ''  
    len_O = len(O)
    if test:
        print(len_O)

    for i in range(len_O):
        password += O[i]
        try:
            password += E[i]
        except IndexError:
            pass

    return password


def main():
    
    print(restore())


if __name__ == '__main__':
    main()
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
N=int(input())
A=list(map(int,input().split()))
cnt=0
while True:
    if [a%2 for a in A]==[0]*N:
        A=[a//2 for a in A]
        cnt+=1
print(cnt)

       
       

Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))
cnt=0
while True:
    if [a%2 for a in A]==[0]*N:
        A=[a//2 for a in A]
        cnt+=1
    else:break
print(cnt)
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
n,k=map(int,input().split())
print('NO' if n<2*k else 'YES')

Fixed, accepted submission:
n,k=map(int,input().split())
print('NO' if n<2*k-1 else 'YES')
Problem:
There are N towns on a line running east-west. The towns are numbered 1 through N, in order from west to east. Each point on the line has a one- dimensional coordinate, and a point that is farther east has a greater coordinate value. The coordinate of town i is X_i.  You are now at town 1, and you want to visit all the other towns. You have two ways to travel:    * Walk on the line. Your _fatigue level_ increases by A each time you travel a distance of 1, regardless of direction.    * Teleport to any location of your choice. Your fatigue level increases by B, regardless of the distance covered.  Find the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.

Incorrect submission (verdict: Wrong Answer):
N,A,B=(int(i) for i in input().split())
X=list(map(int,input().split()))
count=0

for i in range(N-1):
    M=X[i+1]-X[i]
    if M>=B:
        count+=M
    else:
        count+=B
print(count)

Fixed, accepted submission:
N,A,B=(int(i) for i in input().split())
X=list(map(int,input().split()))
count=0

for i in range(N-1):
    M=(X[i+1]-X[i])*A
    if M<=B:
        count=count+M
    else:
        count=count+B
print(count)
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())
print('A' if abs(x-a)>abs(x-b) else 'B')

Fixed, accepted submission:
x, a, b = map(int, input().split())
print('A' if abs(x-a)<abs(x-b) else 'B')
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x,a,b=map(int,input().split())
c=abs(x-a)
d=abs(x-b)
if c > d:
  print(d)
else:
  print(c)

Fixed, accepted submission:
x,a,b=map(int,input().split())
c=abs(x-a)
d=abs(x-b)
if c > d:
  print("B")
else:
  print("A")
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
if (n - 1) // k >= 2:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
n, k = map(int, input().split())
if (n + 1) // k >= 2:
  print("YES")
else:
  print("NO")
Problem:
There is a grid with H rows and W columns.  The square at the i-th row and j-th column contains a string S_{i,j} of length 5.  The rows are labeled with the numbers from 1 through H, and the columns are labeled with the uppercase English letters from `A` through the W-th letter of the alphabet.    Exactly one of the squares in the grid contains the string `snuke`. Find this square and report its location.  For example, the square at the 6-th row and 8-th column should be reported as `H6`.

Incorrect submission (verdict: Wrong Answer):
import sys
import math
import itertools
import collections
import heapq
import re
import numpy as np
from functools import reduce

rr = lambda: sys.stdin.readline().rstrip()
rs = lambda: sys.stdin.readline().split()
ri = lambda: int(sys.stdin.readline())
rm = lambda: map(int, sys.stdin.readline().split())
rf = lambda: map(float, sys.stdin.readline().split())
rl = lambda: list(map(int, sys.stdin.readline().split()))
inf = float('inf')
mod = 10**9 + 7

h,w = rm()
for i in range(h):
    a = list(rs())
    for idx, j in enumerate(a):
        if j == 'snuke':
            print(f'{chr(65+i)}{idx+1}')
            exit()














Fixed, accepted submission:
import sys
import math
import itertools
import collections
import heapq
import re
import numpy as np
from functools import reduce

rr = lambda: sys.stdin.readline().rstrip()
rs = lambda: sys.stdin.readline().split()
ri = lambda: int(sys.stdin.readline())
rm = lambda: map(int, sys.stdin.readline().split())
rf = lambda: map(float, sys.stdin.readline().split())
rl = lambda: list(map(int, sys.stdin.readline().split()))
inf = float('inf')
mod = 10**9 + 7

h,w = rm()
for i in range(h):
    a = list(rs())
    for idx, j in enumerate(a):
        if j == 'snuke':
            print(f'{chr(65+idx)}{i+1}')
            exit()
Problem:
There are N integers, A_1, A_2, ..., A_N, written on a blackboard.  We will repeat the following operation N-1 times so that we have only one integer on the blackboard.    * Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.  Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
*A, = map(int, input().split())
A.sort()
r = 1
a, b = A[0], A[1]
t = []

while 1:
    x, y = (a, b) if a<b else (b, a)
    t.append((x, y))
    
    r += 1
    if not r<N:
        break
    a, b = x-y, A[r]

a, b = t[-1]
t[-1] = (b, a)
print(len(t))
for i in t:
    print(*i)

Fixed, accepted submission:
from bisect import bisect_left

N = int(input())
*A, = map(int, input().split())
A.sort()

if A[0]<=0 and A[-1]<=0:
    ans = sum(map(abs, A[:-1]))+A[-1]
    A.reverse()

    r = 1
    a, b = A[0], A[1]
    t = []
    
    while 1:
        x, y = (a, b) if a>b else (b, a)
        t.append((x, y))
        r += 1
        if not r<N:
            break
        a, b = x-y, A[r]

elif A[0]>=0 and A[-1]>=0:
    ans = sum(A[1:])-A[0]

    r = 1
    a, b = A[0], A[1]
    t = []
    
    while 1:
        x, y = (a, b) if a<b else (b, a)
        t.append((x, y))
        
        r += 1
        if not r<N:
            break
        a, b = x-y, A[r]
    a, b = t[-1]
    t[-1] = (b, a)


else:
    ans = sum(map(abs, A))
    p = bisect_left(A, 0)
    t = []
    s = []

    a = A[p-1]
    for i in range(p, N-1):
        b = A[i]
        t.append((a, b))
        a = a - b
        
    c = A[N-1]
    for i in ([a]+A[:p-1]):
        t.append((c, i))
        c = c-i

print(ans)
for i in t:
    print(*i)
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
C=[list(map(int,input().split())) for i in range(3)]
print(C)
print(C[1][0])
if C[0][1]-C[0][0]==C[1][1]-C[1][0] and C[1][1]-C[1][0]==C[2][1]-C[2][0]:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
C=[list(map(int,input().split())) for i in range(3)]
for n in range(0,2):
  x=C[0][2]-C[0][n]
  y=C[1][2]-C[1][n]
  z=C[2][2]-C[2][n]
  if x!=y or y!=z :
    print('No')
    exit()
else:
  print('Yes')
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())

k = int(input())

m = 0
n = 1

while a > b:
    m = m + 1
    b = b * 2
    if a < b:
        break

while b > c:
    n = n + 1
    c = c * 2
    if b < c:
        break



if m + n <= k:
    print('Yes')

elif m + n > k:
    print('No')


Fixed, accepted submission:
a, b, c = map(int, input().split())

k = int(input())

times = 0

while a >= b:
    b *= 2
    times += 1

while b >= c:
    c *= 2
    times += 1

if times <= k:
    print('Yes')

else:
    print('No')
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
A = [list(map(int,input().split())) for _ in range(3)]

ok = True
for i in range(3):
  if A[i][1] - A[i][0] == A[i][2] - A[i][1]:
    continue
  else:
    ok = False
    break

for i in range(3):
  if A[1][i] - A[0][i] == A[2][i] - A[1][i]:
    continue
  else:
    ok = False
    break
    
if not ok:
  print('No')
else:
  print('Yes')
  

  





Fixed, accepted submission:
A = [list(map(int,input().split())) for _ in range(3)]

R1 = [A[i][1] - A[i][0] for i in range(3)]
R2 = [A[i][2] - A[i][1] for i in range(3)]
C1 = [A[1][i] - A[0][i] for i in range(3)]
C2 = [A[2][i] - A[1][i] for i in range(3)]

ok = True
for x in [R1,R2,C1,C2]:
  if len(set(x)) != 1:
    ok = False
    break
    
if not ok:
  print('No')
else:
  print('Yes')
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())
ans = "No"
if A < B:
  x = A + V * T
  y = B + W * T
  if x >= y:
    ans = "Yes"
else:
  x = A - V * T
  y = B - W * T
  if x <= y:
    ans = "Yes"
print(ans)

Fixed, accepted submission:
A, V = map(int, input().split())
B, W = map(int, input().split())
T = int(input())
ans = "NO"
if A < B:
  x = A + V * T
  y = B + W * T
  if x >= y:
    ans = "YES"
else:
  x = A - V * T
  y = B - W * T
  if x <= y:
    ans = "YES"
print(ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

s = input()
a = [int(c) for c in s]

count = 0
#
for i in range(1, 3):
  if a[i] == 1:
  	count = count + 1
    
print(count)      

Fixed, accepted submission:
s = input()
print(s.count('1'))
Problem:
Write a program which calculates the area and circumference of a circle for given radius r.

Incorrect submission (verdict: Wrong Answer):
r = float(input())

x = 3.141592653589
print("{0:.5f} {1:.5f}".format((r*2*x),(r**2*x)))


Fixed, accepted submission:
r = float(input())
n = 3.141592653589
print("{:.6f} {:.6f}".format(r**2*n,r*2*n))
Problem:
Snuke has N integers: 1,2,\ldots,N. He will choose K of them and give those to Takahashi.  How many ways are there to choose K consecutive integers?

Incorrect submission (verdict: Wrong Answer):
import sys
import math
import bisect

def main():
    n, k = map(int, input().split())
    A = [0] * (k + 1)
    A[0] = 1
    for _ in range(n):
        for i in range(k, -1, -1):
            if i - 1 >= 0:
                A[i] += A[i-1]
    #print('n: %d, k: %d, A: %s' % (n, k, str(A)))
    print(A[k])
    
if __name__ == "__main__":
    main()


Fixed, accepted submission:
import sys
import math
import bisect

def main():
    n, k = map(int, input().split())
    print(n - k + 1)
    
if __name__ == "__main__":
    main()
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
import sys
numbers = []
max = 0
for line in sys.stdin:
	numbers.append(int(line))

for i in range(0, len(numbers)):
	for j in range(i,len(numbers)):
		if numbers[j] - numbers[i] > max :
			max = numbers[j] - numbers[i]
print(max)


Fixed, accepted submission:
import sys
input_number = int(input())
if __name__ == '__main__':
    print(str(input_number ** 3))
Problem:
You are given two integers A and B. Find the largest value among A+B, A-B and A \times B.

Incorrect submission (verdict: Wrong Answer):
a, b=map(int, input().split())
print(a+b, a-b, a*b)

Fixed, accepted submission:
a, b=map(int, input().split())
print(max(a+b, a-b, a*b))
Problem:
Write a program which reads a word W and a text T, and prints the number of word W which appears in text T  T consists of string Ti separated by space characters and newlines. Count the number of Ti which equals to W. The word and text are case insensitive.

Incorrect submission (verdict: Wrong Answer):
y = input().lower()
cnt = 0
s=""
while True:
    x = input().lower()
    if x == "end_of_text":
        break
    s += x
    for i in x:
        if i == y:
            cnt += 1
print(cnt)

Fixed, accepted submission:
W = input()
num = 0
while True:
    line = input()
    if line == 'END_OF_TEXT':
        break
    for word in line.split():
        if word.lower() == W.lower():
            num += 1
print(num)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())

if (N-A)%500==0:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
N = int(input())
A = int(input())

if N%500<=A:
  print('Yes')
else:
  print('No')
Problem:
Write a program which performs a sequence of commands to a given string $str$. The command is one of:    * print a b: print from the a-th character to the b-th character of $str$   * reverse a b: reverse from the a-th character to the b-th character of $str$   * replace a b p: replace from the a-th character to the b-th character of $str$ with p  Note that the indices of $str$ start with 0.

Incorrect submission (verdict: Wrong Answer):
s=list(input())
n=int(input())
for i in range(n):
	l=input().split()
	if l[0]=="replace":
		a=int(l[1])
		b=int(l[2])
		s[a:b+1]=list(l[3])
	elif l[0]=="reverse":
		a=int(l[1])
		b=int(l[2])
		s[a:b+1]=s[a:b+1:-1]
	else:
		a=int(l[1])
		b=int(l[2])
		print("".join(s[a:b+1]))

Fixed, accepted submission:
s=list(input())
n=int(input())
for i in range(n):
	l=input().split()
	if l[0]=="replace":
		a=int(l[1])
		b=int(l[2])
		s[a:b+1]=list(l[3])
	elif l[0]=="reverse":
		a=int(l[1])
		b=int(l[2])
		c=s[a:b+1][::-1]
		s[a:b+1]=c
	else:
		a=int(l[1])
		b=int(l[2])
		print("".join(s[a:b+1]))