TnT/CodeNet4Repair huggingface dataset:
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
def main():
    N = int(input())
    judges = [input() for _ in range(N)]
    print(judges)
    
    res_dic = {"AC": 0, "WA": 0, "TLE": 0, "RE": 0}
    for judge in judges:
        if judge in res_dic:
            res_dic[judge] += 1
        else:
            res_dic[judge] = 0
            
    for k, v in res_dic.items():
        print("{} x {}".format(k, v))

if __name__ == '__main__':
    main()
    

Fixed, accepted submission:
def main():
    N = int(input())
    judges = [input() for _ in range(N)]
    
    res_dic = {"AC": 0, "WA": 0, "TLE": 0, "RE": 0}
    for judge in judges:
        if judge in res_dic:
            res_dic[judge] += 1
        else:
            res_dic[judge] = 0
            
    for k, v in res_dic.items():
        print("{} x {}".format(k, v))

if __name__ == '__main__':
    main()
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
print(input().count('a'))

Fixed, accepted submission:
print(input().count('1'))
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())
for _ in range(H-1):
    s = input()
    print(s)
    print(s)

Fixed, accepted submission:
H, W = map(int, input().split())
array = []
for _ in range(H):
    s = input()
    array.append(s)
for i in range(H):
    print(array[i])
    print(array[i])
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())
ResMax = max(A, B)
ResMin = max(0, A+B-N)
print(ResMax, ResMin)

Fixed, accepted submission:
N, A, B = map(int, input().split())
ResMax = min(A, B)
ResMin = max(0, A+B-N)
print(ResMax, ResMin)
Problem:
You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`.

Incorrect submission (verdict: Wrong Answer):
s = input()
set1 = set(s)

print(set1)

if set1 == {'c', 'b', 'a'}:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
s = input()
set1 = set(s)

if set1 == {'c', 'b', 'a'}:
    print("Yes")
else:
    print("No")
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
import sys
n = int(input())
a = list(map(int, input().split()))
i = 0
while(True):
  for x in a:
    if x%2!=0:
      print(i)
      sys.exit()
    else:
      x = x//2
  i += 1


Fixed, accepted submission:
import sys
def main():
    n = int(input())
    a = list(map(int, input().split()))
    i = 0
    while(True):
        for x in a:
            if x%2!=0:
                print(i)
                sys.exit()

        a = [x//2 for x in a]
        i += 1

if __name__=="__main__":
    main()
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
print(str(input())[1::2])

Fixed, accepted submission:
print(str(input())[::2])
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
import itertools
A=input()
for i in list(itertools.product(range(2),repeat=3)):
  c=''
  c+=A[0]
  bns=int(A[0])
  for j in range(3):
    if i[j]==0:
      bns+=int(A[j+1])
      c+='+'+A[j+1]
    else:
      bns-=int(A[j+1])
      c+='-'+A[j+1]
  if bns==7:
    print(c)
    exit()

Fixed, accepted submission:
import itertools
A=input()
for i in list(itertools.product(range(2),repeat=3)):
  c=''
  c+=A[0]
  bns=int(A[0])
  for j in range(3):
    if i[j]==0:
      bns+=int(A[j+1])
      c+='+'+A[j+1]
    else:
      bns-=int(A[j+1])
      c+='-'+A[j+1]
  if bns==7:
    print(c+'=7')
    exit()
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
k = int(input())

ans = 0
sub = a + b + c
ans = max(a * (2 * k) + sub, b * (2 * k) + sub, c * (2 * k) + sub)
print(ans)

Fixed, accepted submission:
a, b, c = map(int, input().split())
k = int(input())

print(a + b + c + max(a, b, c) * (2 ** k - 1))
Problem:
You are given three strings A, B and C. Check whether they form a _word chain_.  More formally, determine whether both of the following are true:    * The last character in A and the initial character in B are the same.   * The last character in B and the initial character in C are the same.  If both are true, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
nums = input().split()
if nums[0][-1] == nums[1][0] and nums[1][-1] == nums[2][0]:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
nums = input().split()
if nums[0][-1] == nums[1][0] and nums[1][-1] == nums[2][0]:
    print('YES')
else:
    print('NO')
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ANS = 0
for i in range(1,n+1):
  check = i
  ans = 0
  while check % 2 == 0:
    check = check // 2
    ans += 1
  if ANS < ans:
    ANS = ans
print(ANS)

Fixed, accepted submission:
n = int(input())
ANS = 1
keep = 0
for i in range(1,n+1):
  check = i
  ans = 0
  while check % 2 == 0:
    check = check // 2
    ans += 1
  if keep < ans:
    keep = ans
    ANS = i
print(ANS)
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
a=1
mod=1e9+7
for i in range(1,N+1):
  a*=i
  a%=mod
print(a)

Fixed, accepted submission:
N=int(input().rstrip())
a=1
mod=1e9+7
for i in range(1,N+1):
  a*=i
  a%=mod
print(int(a))
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a, b = map( int, input().split())

count = 0

for i in range(1, a + 1):
  if( i < b):
    count += 1
    
  else:
    continue
    
print(count)

Fixed, accepted submission:
a, b = map( int, input().split())

if( b < a):
  count = a - 1
    
else:
  count = a
    
print(count)
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
sx, sy, tx, ty = map(int, input().split())
distance_x, distance_y = tx-sx, ty-sy
x_now, y_now = sx, sy

#path1
for i in range(distance_y):
    print("U",end="")
for i in range(distance_x):
    print("R",end="")

#path2
for i in range(distance_y):
    print("D",end="")
for i in range(distance_x):
    print("L",end="")

#path3
print("L",end="")
for i in range(distance_y+1):
    print("U",end="")
for i in range(distance_x+1):
    print("R",end="")
print("D",end="")

#path4
print("R",end="")
for i in range(distance_y+1):
    print("D",end="")
for i in range(distance_x):
    print("L",end="")
print("U")


Fixed, accepted submission:
sx, sy, tx, ty = map(int, input().split())
distance_x, distance_y = tx-sx, ty-sy
x_now, y_now = sx, sy
up, down, right, left = 'U', 'D', 'R', 'L'

#path1
print(up*distance_y+""+right*distance_x,end="")
#path2
print(down*distance_y+""+left*distance_x,end="")
#path3
print("L"+""+up*(distance_y+1)+""+right*(distance_x+1)+""+"D",end="")
#path4
print("R"+""+down*(distance_y+1)+""+left*(distance_x+1)+""+"U")
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
from functools import reduce
n = int(input())
l = list(map(int, input().split()))
if n%3:
  if max(l) == 0:
    print("YES")
  else:
    print("NO")
else:
  if reduce((lambda x, y:x ^ y), l) == 0:
    print("YES")
  else:
    print("NO")

Fixed, accepted submission:
from functools import reduce as f;input();print("YNeos"[f(lambda x,y:x^y,map(int,input().split()))>0::2])
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
print((a+b)//2+1)

Fixed, accepted submission:
a,b=map(int,input().split())
if (a+b) % 2==1:
  print((a+b+1)//2)
else:
  print((a+b)//2)
Problem:
We will call a string that can be obtained by concatenating two equal strings an _even_ string. For example, `xyzxyz` and `aaaaaa` are even, while `ababab` and `xyzxy` are not.  You are given an even string S consisting of lowercase English letters. Find the length of the longest even string that can be obtained by deleting one or more characters from the end of S. It is guaranteed that such a non-empty string exists for a given input.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-


def main():
    """Function."""
    s = str(input())

    max_len = 0
    for i in range((len(s)-1)//2):
        if s[:i+1] * 2 == s[:(i+1)*2]:
            print(s[:i+1])
            max_len = (i + 1) * 2

    print(max_len)


if __name__ == "__main__":
    main()


Fixed, accepted submission:
# -*- coding: utf-8 -*-


def main():
    """Function."""
    s = str(input())

    max_len = 0
    for i in range((len(s)-1)//2):
        if s[:i+1] * 2 == s[:(i+1)*2]:
            max_len = (i + 1) * 2

    print(max_len)


if __name__ == "__main__":
    main()
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
S = list(input())
flug = True
for i in range(0,len(S),2):
    if i+1 < len(S):
        st = S[i] + S[i + 1]

        if st != "hi":
            flug = False
    else:
        flug = False

if flug == True:
    print("YES")
else:
    print("NO")

Fixed, accepted submission:
S = list(input())
flug = True
for i in range(0,len(S),2):
    if i+1 < len(S):
        st = S[i] + S[i + 1]

        if st != "hi":
            flug = False
    else:
        flug = False

if flug == True:
    print("Yes")
else:
    print("No")
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s = input()
aida = str(len(s))
print(s[0] + aida + s[-1])

Fixed, accepted submission:
s = input()
aida = str(len(s)-2)
print(s[0] + aida + s[-1])
Problem:
There are N integers, A_1, A_2, ..., A_N, written on a blackboard.  We will repeat the following operation N-1 times so that we have only one integer on the blackboard.    * Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.  Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

nums = list(map(int, input().split() ))

nums.sort()

print(nums)
if nums[0] >= 0:
	
	print(sum(list(map(abs, nums))) - 2 * nums[0])

	hikareru = nums[0]
	for idx in range(2,n):
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]

	print("{} {}".format(nums[1], hikareru) )

elif nums[-1] <= 0:
	
	print(sum(list(map(abs, nums))) - 2 * (-1)*nums[-1] )

	hikareru = nums[-1]
	for idx in range(n-1):
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]

else:
	print(sum(list(map(abs, nums))) )

	hikareru = nums[0]
	idx = n-2
	while True:
		if nums[idx] < 0:
			break
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]
		idx -= 1

	hiku = hikareru
	print("{} {}".format(nums[n-1], hiku) )
	hikareru = nums[n-1] -  hiku

	idx = 1
	while True:
		if nums[idx] >= 0:
			break
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]
		idx += 1


Fixed, accepted submission:
n = int(input())
nums = list(map(int, input().split() ))
nums.sort()

if nums[0] >= 0:
	
	print(sum(list(map(abs, nums))) - 2 * nums[0])

	hikareru = nums[0]
	for idx in range(2,n):
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]

	print("{} {}".format(nums[1], hikareru) )

elif nums[-1] <= 0:
	
	print(sum(list(map(abs, nums))) - 2 * (-1)*nums[-1] )

	hikareru = nums[-1]
	for idx in range(n-1):
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]

else:
	print(sum(list(map(abs, nums))) )

	hikareru = nums[0]
	idx = n-2
	while True:
		if nums[idx] < 0:
			break
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]
		idx -= 1

	hiku = hikareru
	print("{} {}".format(nums[n-1], hiku) )
	hikareru = nums[n-1] -  hiku

	idx = 1
	while True:
		if nums[idx] >= 0:
			break
		print("{} {}".format(hikareru, nums[idx]) )
		hikareru -= nums[idx]
		idx += 1
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
import sys
#DEBUG = True
DEBUG = False
if DEBUG:
    f=open("202007_1st/A_input.txt")
else:
    f=sys.stdin
N=int(f.readline())
print(N%1000)
f.close()

Fixed, accepted submission:
import sys
#DEBUG = True
DEBUG = False
if DEBUG:
    f=open("202007_1st/A_input.txt")
else:
    f=sys.stdin
N=int(f.readline().strip())
R=N%1000
if R==0:
    print(R)
else:
    print(1000-(N%1000))
f.close()
Problem:
There is a data which provides heights (in meter) of mountains. The data is only for ten mountains.  Write a program which prints heights of the top three mountains in descending order.

Incorrect submission (verdict: Wrong Answer):
mountains = []

for i in range(10):
    m = int(input())
    mountains.append(m)

mountains.sort()

for i in range(3):
    print(mountains[i])


Fixed, accepted submission:
mountains = []

for i in range(10):
    m = int(input())
    mountains.append(m)

mountains.sort(reverse=True)

for i in range(3):
    print(mountains[i])
Problem:
There is a kangaroo at coordinate 0 on an infinite number line that runs from left to right, at time 0. During the period between time i-1 and time i, the kangaroo can either stay at his position, or perform a jump of length exactly i to the left or to the right. That is, if his coordinate at time i-1 is x, he can be at coordinate x-i, x or x+i at time i. The kangaroo's nest is at coordinate X, and he wants to travel to coordinate X as fast as possible. Find the earliest possible time to reach coordinate X.

Incorrect submission (verdict: Wrong Answer):
x = int(input())

cnt = 0
i = 1

while cnt >= x:
    cnt += i
    i += 1

print(i-1)


Fixed, accepted submission:
x = int(input())

cnt = 0
i = 1

while cnt < x:
    cnt += i
    i += 1

print(i-1)
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
r,g,b=map(int,input().split())

n=r*100000000+r*10000000+r*1000000+g*100000+g*10000+g*1000+b*100+b*10+b

print("Yes" if n%4==0 else "No")

Fixed, accepted submission:
r,g,b=map(int,input().split())

n=r*100+g*10+b

print("YES" if n%4==0 else "NO")
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

for i in range(50000):
 if int(i*1.08)== n:
  print(i)
  break
 else:
  print(':(')
  break

Fixed, accepted submission:
n=int(input())

for i in range(50000):
 if int(i*1.08)== n:
  print(i)
  exit()
  
print(':(')
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
h, w = map(int, input().split())
c = [input() for i in range(h)]

for i in c*2:
    print(i)

Fixed, accepted submission:
h, w = map(int, input().split())

for i in range(h):
    c = input()
    print(c + "\n" + c)
Problem:
In programming, hexadecimal notation is often used.  In hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters `A`, `B`, `C`, `D`, `E` and `F` are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.  In this problem, you are given two letters X and Y. Each X and Y is `A`, `B`, `C`, `D`, `E` or `F`.  When X and Y are seen as hexadecimal numbers, which is larger?

Incorrect submission (verdict: Wrong Answer):
x,y=input().split()
print('>' if x < y else '=')


Fixed, accepted submission:
x,y=input().split()
if x < y:
  print('<')
elif x > y:
  print('>')
else:
  print('=')
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
N = input()

print('ABC',N)

Fixed, accepted submission:
N = input()

print("ABC"+N)