TnT/CodeNet4Repair huggingface dataset:
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
T = []
Z = []
time = []
T.append([0,0,0])
for i in range(N):
    t = list(map(int, input().split()))
    T.append(t)
goal = True

for l in range(len(T)-1):
    Z.append(abs(T[l+1][1]-T[l][1]) + abs(T[l+1][2]-T[l][2]))
    time.append(T[l+1][0] - T[l][0])

for j in range(len(T)-1):
    if Z[j] > time[j] or Z[j]%2 != time[j]%2:
        goal = False
        break

if goal == False:
    print('NO')
else:
    print('YES')

 

Fixed, accepted submission:
_,*l=map(int,open(0).read().split());print("YNeos"[any((t+x+y)%2+(t<x+y)for t,x,y in zip(*[iter(l)]*3))::2])
Problem:
Takahashi has come to a party as a special guest. There are N ordinary guests at the party. The i-th ordinary guest has a _power_ of A_i.  Takahashi has decided to perform M _handshakes_ to increase the _happiness_ of the party (let the current happiness be 0). A handshake will be performed as follows:    * Takahashi chooses one (ordinary) guest x for his left hand and another guest y for his right hand (x and y can be the same).   * Then, he shakes the left hand of Guest x and the right hand of Guest y simultaneously to increase the happiness by A_x+A_y.  However, Takahashi should not perform the same handshake more than once. Formally, the following condition must hold:    * Assume that, in the k-th handshake, Takahashi shakes the left hand of Guest x_k and the right hand of Guest y_k. Then, there is no pair p, q (1 \leq p < q \leq M) such that (x_p,y_p)=(x_q,y_q).  What is the maximum possible happiness after M handshakes?

Incorrect submission (verdict: Wrong Answer):
def ints():
  return [int(x) for x in input().split()]
def ii():
  return int(input())

N, M = ints()
A = ints()
A.sort()

def combinations(x):
  s = 0
  i = 0
  j = N-1
  while j>=0:
    while i<N and A[i]+A[j]<x:
      i += 1
    s += N-i

    j -= 1
    
  return s

def koufukudo(x):
  s = 0
  si = 0
  j = 0
  i = N-1
  while j<N:
    while i>=0 and A[i]+A[j]>=x:
      si += A[i]
      i -= 1
    s += si + A[j]*(N-1-i)

    j += 1
    
  return s


def bsearch(lower, upper):
  l = lower
  u = upper
  m = (l+u)//2
  c = combinations(m)
  if c<M:
    return bsearch(l, m)
  else:
    if l==m:
      return (l, c-M)
    return bsearch(m, u)

x, dm = bsearch(0, A[-1]*2+1)
print(x)
print(koufukudo(x)-dm*x)


Fixed, accepted submission:
def ints():
  return [int(x) for x in input().split()]
def ii():
  return int(input())

N, M = ints()
A = ints()
A.sort()
A.reverse()

def combinations_and_kofukudo(x):
  c = 0
  k = 0
  si = 0
  i = 0
  for j in reversed(range(N)):
    while i<N and A[i]+A[j]>=x:
      si += A[i]
      i += 1
    c += i
    k += si + A[j]*i
    
  return (c, k)

def bsearch(l, u):
  m = (l+u)//2
  c, k = combinations_and_kofukudo(m)
  if c<M:
    return bsearch(l, m)
  else:
    if l==m:
      print(k-(c-M)*l)
      exit()
    return bsearch(m, u)

bsearch(0, A[0]*2+1)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
sum=0
for i in range(N):
  sum+=i+1

Fixed, accepted submission:
N=int(input())
sum=0
for i in range(N):
  sum+=i+1
print(sum)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
from itertools import count

A, B, C = map(int, input().split())
reminders = []

for n in count(start=A // C):
    r = (n * A - C) % B
    if r == 0:
        print("Yes")
        break
    else:
        if r not in reminders:
            reminders.append(r)
        else:
            print("No")
            break


Fixed, accepted submission:
from itertools import count

A, B, C = map(int, input().split())
reminders = []

for n in count(start=A // C):
    r = (n * A - C) % B
    if r == 0:
        print("YES")
        break
    else:
        if r not in reminders:
            reminders.append(r)
        else:
            print("NO")
            break
Problem:
There are three houses on a number line: House 1, 2 and 3, with coordinates A, B and C, respectively. Print `Yes` if we pass the coordinate of House 3 on the straight way from House 1 to House 2 without making a detour, and print `No` otherwise.

Incorrect submission (verdict: Wrong Answer):
A,B,C = map(int,input().split())
if A < B < C:
  print("YES")
else:
  print("No")

Fixed, accepted submission:
A,B,C = map(int,input().split())
if A < C < B or B < C < A:
  print("Yes")
else:
  print("No")
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())

print(n * 2 - a)

Fixed, accepted submission:
n = int(input())
a = int(input())

print(n ** 2 - a)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
print(N*(N+1)/2)

Fixed, accepted submission:
N=int(input())
print(N*(N+1)//2)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a,b= map(int,input().split())
if a%3==0 or b%3==0 or (a*b)%3==0:
  result='Possible'
else:
  result='Impossible'
  
print(result)

Fixed, accepted submission:
a,b= map(int,input().split())
if a%3==0 or b%3==0 or (a+b)%3==0:
  result='Possible'
else:
  result='Impossible'
  
print(result)
Problem:
There is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region. The front and back sides of these cards can be distinguished, and initially every card faces up.  We will perform the following operation once for each square contains a card:    * For each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.  It can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed. Find the number of cards that face down after all the operations.

Incorrect submission (verdict: Wrong Answer):
N,M=map(int,input().split())
print(max(M-2,1)*max(N-2,1))

Fixed, accepted submission:
N,M=map(int,input().split())
print(abs((M-2)*(N-2)))
Problem:
You are parking at a parking lot. You can choose from the following two fee plans:    * Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.   * Plan 2: The fee will be B yen, regardless of the duration.  Find the minimum fee when you park for N hours.

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int,input().split())

if n * a >= b:
    print(n * a)
else:
    print(b)

Fixed, accepted submission:
n,a,b = map(int,input().split())

if n * a <= b:
    print(n * a)
else:
    print(b)
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
A,B,C = list(map(int,input().split()))
if 10*B + C % 4 == 0:
  print("YES")
else:
  print("NO")



Fixed, accepted submission:
A,B,C = list(map(int,input().split()))
if (10*B + C) % 4 == 0:
  print("YES")
else:
  print("NO")
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8
import math
n = int(input())
t = 0
x = 0
y = 0
for i in range(n):
    ti, xi, yi = list(map(int, input().split()))
    if xi - x + yi - y > ti - t:
        print("NO")
        exit()
    elif (xi - x + yi - y - (ti - t)) % 2 != 0:
        print("NO")
        exit()
print("YES")

Fixed, accepted submission:
# coding: utf-8
import math
n = int(input())
t = 0
x = 0
y = 0
# txy = []

#     ti, xi, yi = list(map(int, input().split()))
#     txy.append((ti, xi, yi))
for i in range(n):
    ti, xi, yi = map(int, input().split())
    if abs(xi - x) + abs(yi - y) > abs(ti - t):
        print("No")
        exit()
    elif (abs(xi - x) + abs(yi - y) - abs(ti - t)) % 2 != 0:
        print("No")
        exit()
    else:
        t = ti
        x = xi
        y = yi
print("Yes")
Problem:
On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in `yyyy/mm/dd` format. For example, January 23, 2018 should be written as `2018/01/23`.  After finishing the document, she noticed that she had mistakenly wrote `2017` at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to `2018` and prints it.

Incorrect submission (verdict: Wrong Answer):
S = input()

print('2017' + S[4:])

Fixed, accepted submission:
S = input()

print('2018' + S[4:])
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
listn = list(range(1,n+1))

def n2(n):
    counter = 0
    while n % 2 == 0:
        n = n / 2
        counter += 1
    return counter

lists_n2 = list(map(n2, listn))
print(max(lists_n2))

Fixed, accepted submission:
n = int(input())

def n2(n):
    counter = 0
    while n % 2 == 0:
        n = n / 2
        counter += 1
    return counter

max_resistor = 0
max_n2 = 0
for i in range(1,n+1):
    i_n2 = n2(i)
    if max_n2 <= i_n2:
        max_n2 = i_n2
        max_resistor = i
    
print(max_resistor)
Problem:
Rng is going to a festival.  The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.  Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.

Incorrect submission (verdict: Wrong Answer):
s = input()
print(s[:-9])


Fixed, accepted submission:
s = input()
print(s[:-8])
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
s = [input() for i in range(N)]

res = {
    'AC' : 0,
    'TLE' : 0,
    'WA' : 0,
    'RE' : 0
}

for k in s:
    print(res[k])
    res[k] = res[k] + 1

for k, v in res.items():
    print(k + ' x ' + str(v))

Fixed, accepted submission:
N = int(input())
s = [input() for i in range(N)]

res = {
    'AC' : 0,
    'WA' : 0,
    'TLE' : 0,
    'RE' : 0
}

for k in s:
    res[k] = res[k] + 1

for k, v in res.items():
    print(k + ' x ' + str(v))
Problem:
Your task is to implement a double linked list.  Write a program which performs the following operations:    * insert x: insert an element with key x into the front of the list.   * delete x: delete the first element which has the key of x from the list. If there is not such element, you need not do anything.   * deleteFirst: delete the first element from the list.    * deleteLast: delete the last element from the list.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
commands=[input().split() for i in range(n)]
print(commands)
    
List=[]
def command(list_command):
    if 'insert' in list_command:
        List.insert(0,list_command[1])
    elif 'delete' in list_command:
        try:
            t=List.index(list_command[1])
            del List[t]
        except:
            pass
    elif 'deleteFirst' in list_command:
        del List[0]
    elif 'deleteLast' in list_command:
        del List[-1]

    return True
    
for i in commands:
    command(i)
print(*List)

Fixed, accepted submission:
from collections import deque
n=int(input())
commands=[input().split() for i in range(n)]
    
List=deque()
for list_command in commands:
    if 'insert' in list_command:
        List.appendleft(list_command[1])
    elif 'delete' in list_command:
        try:
            List.remove(list_command[1])
        except:
            pass
    elif 'deleteFirst' in list_command:
        List.popleft()
    elif 'deleteLast' in list_command:
        List.pop()
  
print(*List)
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
#Beginner 047 B
W, H, N = map(int, input().split())

s = [input() for i in range(N)]
S = []
for i in range(N):
    S.append(list(map(int, s[i].split())))

lst = [[1 for i in range(W)] for j in range(H)]
print(lst)

for i in range(N):
    if S[i][2] == 1:
        for j in range(0,S[i][0]):
            for k in range(H):
                lst[k][j] = 0
    if S[i][2] == 2:
        for j in range(S[i][0],W):
            for k in range(H):
                lst[k][j] = 0
    if S[i][2] == 3:
        for j in range(0,S[i][1]):
            for k in range(W):
                lst[j][k] = 0
    if S[i][2] == 4:
        for j in range(S[i][1],H):
            for k in range(W):
                lst[j][k] = 0

print(sum(lst,[]).count(1))


Fixed, accepted submission:
#Beginner 047 B
W, H, N = map(int, input().split())

s = [input() for i in range(N)]
S = []
for i in range(N):
    S.append(list(map(int, s[i].split())))

lst = [[1 for i in range(W)] for j in range(H)]

for i in range(N):
    if S[i][2] == 1:
        for j in range(0,S[i][0]):
            for k in range(H):
                lst[k][j] = 0
    if S[i][2] == 2:
        for j in range(S[i][0],W):
            for k in range(H):
                lst[k][j] = 0
    if S[i][2] == 3:
        for j in range(0,S[i][1]):
            for k in range(W):
                lst[j][k] = 0
    if S[i][2] == 4:
        for j in range(S[i][1],H):
            for k in range(W):
                lst[j][k] = 0

print(sum(lst,[]).count(1))
Problem:
For an integer n not less than 0, let us define f(n) as follows:    * f(n) = 1 (if n < 2)   * f(n) = n f(n-2) (if n \geq 2)  Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Incorrect submission (verdict: Wrong Answer):
n = int(input())

if n % 2 == 0:
    n5 = 1
    y = 10

    while n % y == 0:
        n5 += 1
        y = 2*(5**n5)

    n5 -= 1
    c = [n//(2*(5**i)) for i in range(1, n5+1)]

    cnt = 0
    for i in range(n5):
        if i != n5-1:
            c[i] -= c[i+1]

        cnt += c[i]*(i+1)

    print(cnt)
else:
    print(0)

Fixed, accepted submission:
n = int(input())

if n % 2 == 0:
    n5 = 1
    y = 10
    c = []

    while y <= n:
        c.append(n//y)
        if len(c) > 1:
            c[-2] -= c[-1]
        y *= 5

    cnt = 0
    for i in range(len(c)):
        cnt += c[i]*(i+1)

    print(cnt)
else:
    print(0)
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
def getStrangeString(s):
    res = ""
    for i in range(len(s)):
        if i%2 != 0:
            res += s[i]
print(getStrangeString(input()))

Fixed, accepted submission:
def getStrangeString(s):
    res = ""
    for i in range(len(s)):
        if i%2 == 0:
            res += s[i]
    return res
print(getStrangeString(input()))
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
x = input("input x: ")
x = int(x)
x = pow(x,3)
print(x)

Fixed, accepted submission:
x=int(input())
print(x**3)
Problem:
You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.  For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.  Assume that initially no person lives in the building.

Incorrect submission (verdict: Wrong Answer):
house = [[[0 for i in range(10)] for i in range(3)] for i in range(4)]

n = int(input())
input_4 = list(map(int,input().split()))

for i in range(n):
    house[input_4[0]-1][input_4[1]-1][input_4[2]-1] = input_4[3]
for i in range(4):
    for j in range(3):
        print('',''.join(map(str,house[i][j])))
    print('#'*20)

Fixed, accepted submission:
house = [[[0 for i in range(10)] for i in range(3)] for i in range(4)]
n = int(input())
for i in range(n):
    input_4 = list(map(int,input().split()))
    house[input_4[0]-1][input_4[1]-1][input_4[2]-1] += input_4[3]
for i in range(4):
    for j in range(3):
        print('',' '.join(map(str,house[i][j])))
    if i != 3:
        print('#'*20)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
i = 0
ans=0
for i in range(N+1):
    ans += i

ans

Fixed, accepted submission:
N = int(input())
i = 0
ans=0
for i in range(N+1):
    ans += i

print(ans)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
N,M,X,Y = map(int, input().split(" "))
xList = input().split(" ")
yList = input().split(" ")

for i in range(len(xList)):
  xList[i] = int(xList[i])
for j in range(len(yList)):
  yList[j] = int(yList[j])

xList.sort()
yList.sort()

if yList[0] - 1 >= xList[len(xList) - 1]:
  index = yList[0] - 1
  while index > xList[len(xList) - 1]:
    if X < index and index <= Y:
      print("No War")
      break
    else:
      index -= 1
    
  print("War")
else:
  print("War")

Fixed, accepted submission:
N,M,X,Y = map(int, input().split(" "))
xList = input().split(" ")
yList = input().split(" ")

for i in range(len(xList)):
  xList[i] = int(xList[i])
for j in range(len(yList)):
  yList[j] = int(yList[j])

xList.sort()
yList.sort()

if yList[0] > xList[len(xList) - 1] and yList[0] > X and Y > xList[len(xList) - 1]:
  print("No War")
else:
  print("War")
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int, input().split()))
b=[]
for i in reversed(range(n)):
    count=0
    for j in range(1,n+1):
        if j%(i+1)==0:
            count+=a[j-1]
    if count%2==1:       
        b.append(1)
        
for _ in range(len(b)):
  print("1")

Fixed, accepted submission:
n=int(input())
a=list(map(int, input().split()))
b=[0]*n
for i in range(n,0,-1):
    count=0
    for j in range(i,n+1,i):
        count+=b[j-1]
    if (count%2)!=a[i-1]:      
        b[i-1]=1
c=[i+1 for i in range(n) if b[i]==1]
if len(c)==0:
    print("0")
else:
    print(len(c))
    print(*c)