TnT/CodeNet4Repair huggingface dataset:
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int, input().split())


q=min(a, b)
w=a+b-n

print(q,w)


Fixed, accepted submission:
n,a,b = map(int, input().split())


q=min(a, b)
w=max(0,a+b-n)

print(q,w)
Problem:
Write a program which performs a sequence of commands to a given string $str$. The command is one of:    * print a b: print from the a-th character to the b-th character of $str$   * reverse a b: reverse from the a-th character to the b-th character of $str$   * replace a b p: replace from the a-th character to the b-th character of $str$ with p  Note that the indices of $str$ start with 0.

Incorrect submission (verdict: Wrong Answer):
def main():
    class MyClass:
        def __init__(self):
            self.strings = ""

        def rpl(self, int1, int2, str1):
            self.strings = self.strings.replace(self.strings[int1:int2+1], str1)
            print(self.strings)

        def rvr(self, int1, int2):
            if int1 >= 1:
                revstr = self.strings[int2:int1-1:-1]
            else:
                revstr = self.strings[int2::-1]
            self.strings = self.strings[:int1] + revstr + self.strings[int2+1:]
            print(self.strings)

        def pri(self, int1, int2):
            print(self.strings[int1:int2+1])

    cls = MyClass()
    cls.strings = input()
    n = int(input())
    for _ in range(n):
        li = input().split()
        if li[0] == "replace":
            cls.rpl(int(li[1]), int(li[2]), li[3])
        elif li[0] == "reverse":
            cls.rvr(int(li[1]), int(li[2]))
        elif li[0] == "print":
            cls.pri(int(li[1]), int(li[2]))


if __name__ == "__main__":
    main()

Fixed, accepted submission:
def main():
    class MyClass:
        def __init__(self):
            self.strings = ""

        def rpl(self, int1, int2, str1):
            self.strings = self.strings[:int1] + str1 + self.strings[int2+1:]

        def rvr(self, int1, int2):
            if int1 >= 1:
                revstr = self.strings[int2:int1-1:-1]
            else:
                revstr = self.strings[int2::-1]
            self.strings = self.strings[:int1] + revstr + self.strings[int2+1:]

        def pri(self, int1, int2):
            print(self.strings[int1:int2+1])

    cls = MyClass()
    cls.strings = input()
    n = int(input())
    for _ in range(n):
        li = input().split()
        if li[0] == "replace":
            cls.rpl(int(li[1]), int(li[2]), li[3])
        elif li[0] == "reverse":
            cls.rvr(int(li[1]), int(li[2]))
        elif li[0] == "print":
            cls.pri(int(li[1]), int(li[2]))


if __name__ == "__main__":
    main()
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
while True:
    s = input()
    a, op, b = s.split()
    if op == '?': break
    print(eval(s))

Fixed, accepted submission:
while True:
    s = input()
    a, op, b = s.split()
    if op == '?': break
    print(int(eval(s)))
Problem:
It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.  The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.  How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print((n - int(input())) * (n - int(input())))

Fixed, accepted submission:
n = int(input())
print((n - int(input()) + 1) * (n - int(input()) + 1))
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
list_1=list(input())
list_2=list(input())
print(list_1[0],list_2[2])
if(list_1[0]==list_2[2] and list_1[1]==list_2[1] and list_1[2]==list_2[0]):
  print('YES')
else:print('NO')

Fixed, accepted submission:
print(["NO","YES"][input()==input()[::-1]])
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
import sys


def main(lines):
    print(len(set(lines[1:-1])))


if __name__ == '__main__':
    lines = []
    for l in sys.stdin:
        lines.append(l.rstrip('\r\n'))
    main(lines)


Fixed, accepted submission:
import sys


def main(lines):
    print(len(set(lines[1:])))


if __name__ == '__main__':
    lines = []
    for l in sys.stdin:
        lines.append(l.rstrip('\r\n'))
    main(lines)
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
info = input().split()
lst = []
for i in range(int(info[0])):
  lst.append(str(input()))
lst = sorted(lst)
print(lst)

Fixed, accepted submission:
info = input().split()
lst = []
for i in range(int(info[0])):
  lst.append(str(input()))
lst = "".join(sorted(lst))
print((lst))
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = input()
B = input()
C = input()
X = input()

ans = 0
for a in A:
    for b in B:
        for c in C:
            total = (500 * a) + (100 * b) + (50 * c)
            if total == X:
                ans += 1
print(ans)

Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())

ans = 0
for a in range(A+1):
    for b in range(B+1):
        for c in range(C+1):
            total = (500 * a) + (100 * b) + (50 * c)
            if total == X:
                ans += 1
print(ans)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
dp = [0 for i in range(n+1)]
maxn = 101
for x in range(1,maxn):
    for y in range(1,maxn):
        for z in range(1,maxn):
            p = (x+y+z)**2
            p-=(x*y + y*z + z*x)
            if p<=n:
                dp[p]+=1
for i in dp:
    print(i)

Fixed, accepted submission:
n = int(input())
dp = [0 for i in range(n+1)]
maxn = n**0.5
maxn = int(maxn)+1
for x in range(1,maxn):
    for y in range(1,maxn):
        for z in range(1,maxn):
            p = x*x + y*y + z*z + x*y + y*z +z*x
            if p<=n:
                dp[p]+=1
for i in dp[1::]:
    print(i)
Problem:
We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.  We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.  At most how many people can sit on the seat?

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
max = int((a + c) / (b + 2*c))
print(max)
    

    


Fixed, accepted submission:
import sys
import math
 

a, b, c = map(int, input().split())

if a < (b + 2*c):
    print("a >= b + 2*cとなるようにしてください")
    sys.exit()
elif a == (b + 2*c):
    print("1")
else:
    max = math.floor((a - c) / (b + c))
    print(max)
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
print(n*800-(n%15)*200)

Fixed, accepted submission:
n=int(input())
print(n*800-(int(n/15))*200)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
a = [0] + a
 
c = [0] * (n+1)
 
for i in range(n, 0, -1):
    c[i] = a[i]
    tmp = i * 2
    while tmp <= n:
        c[i] -= c[tmp]
        tmp += i
    c[i] = c[i] % 2
    
for i in range(1, n+1):
    if c[i] == 1:
        print(i)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
a = [0] + a
 
c = [0] * (n+1)
 
for i in range(n, 0, -1):
    c[i] = a[i]
    tmp = i * 2
    while tmp <= n:
        c[i] -= c[tmp]
        tmp += i
    c[i] = c[i] % 2
    
print(sum(c))
for i in range(1, n+1):
    if c[i] == 1:
        print(i)
Problem:
Your friend who lives in undisclosed country is involved in debt. He is borrowing 100,000-yen from a loan shark. The loan shark adds 5% interest of the debt and rounds it to the nearest 1,000 above week by week.  Write a program which computes the amount of the debt in n weeks.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
for i in range(5):
	a*=1.05
	if a%1000==0:
		pass
	else:
		a=(a+1000)-a%1000
print(int(a))

Fixed, accepted submission:
a=100000
j=int(input())
for i in range(j):
	a*=1.05
	if a%1000==0:
		pass
	else:
		a=(a+1000)-a%1000
print(int(a))
Problem:
You are visiting a large electronics store to buy a refrigerator and a microwave.  The store sells A kinds of refrigerators and B kinds of microwaves. The i-th refrigerator ( 1 \le i \le A ) is sold at a_i yen (the currency of Japan), and the j-th microwave ( 1 \le j \le B ) is sold at b_j yen.  You have M discount tickets. With the i-th ticket ( 1 \le i \le M ), you can get a discount of c_i yen from the total price when buying the x_i-th refrigerator and the y_i-th microwave together. Only one ticket can be used at a time.  You are planning to buy one refrigerator and one microwave. Find the minimum amount of money required.

Incorrect submission (verdict: Wrong Answer):
na,nb,M=map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
C = [[0 for i in range(3)] for j in range(M)]
#C = [[0]*3]*M
s=min(A)+min(B)
t=0

#print(A)


for i in range(M):
	C[i][0],C[i][1],C[i][2] = map(int, input().split())

#print(C)

for j in range(M):
	print(j)
	t=A[C[j][0]-1]+B[C[j][1]-1]-C[j][2]
	if t<s:
		s=t

print(s)

Fixed, accepted submission:
na,nb,M=map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
C = [[0 for i in range(3)] for j in range(M)]
#C = [[0]*3]*M
s=min(A)+min(B)
t=0

#print(A)


for i in range(M):
	C[i][0],C[i][1],C[i][2] = map(int, input().split())

#print(C)

for j in range(M):
	#print(j)
	t=A[C[j][0]-1]+B[C[j][1]-1]-C[j][2]
	if t<s:
		s=t

print(s)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
def main():
    n = int(input())
    print(n % 1000)

if __name__ == '__main__':
    main()

Fixed, accepted submission:
def main():
    n = int(input())
    n = n % 1000
    if n == 0:
        print(0)
    else:
        print(1000 - n)



if __name__ == '__main__':
    main()
Problem:
You are given a string s. Among the **different** substrings of s, print the K-th lexicographically smallest one.  A substring of s is a string obtained by taking out a non-empty contiguous part in s. For example, if s = `ababc`, `a`, `bab` and `ababc` are substrings of s, while `ac`, `z` and an empty string are not. Also, we say that substrings are different when they are different as strings.  Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Incorrect submission (verdict: Wrong Answer):
#encoding utf-8

import copy
import numpy as np
import random


s = list(str(input()))
k = int(input())

substrings = []
for length in range(1,len(s)+1):
    for i in range(len(s)-length+1):
        word = "".join(s[i:i+length])
        print(word)

        if word in substrings:
            pass
        else:
            substrings.append(str(word))

substrings.sort()
# print(substrings)
print(substrings[k-1])

Fixed, accepted submission:
#encoding utf-8

import copy
import numpy as np
import random


s = list(str(input()))
k = int(input())

substrings = []
for length in range(1,len(s)+1):
    if length > 5:
        break
    for i in range(len(s)-length+1):
        word = "".join(s[i:i+length])
        # print(word)
        if word in substrings:
            pass
        else:
            substrings.append(str(word))

substrings.sort()
# print(substrings)
print(substrings[k-1])
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
x = str(input())
l = [x[0], x[1], x[2], x[3]]
m = [int(s) for s in l]
N = 2 ** 3
for i in range(N):
  n = [m[0], 0, 0, 0]
  o = [] 
  for j in range(3):
    if (i >> j) & 1:
      n[-j-1] = -m[-j-1]
      o.append('-')
    else:
      n[-j-1] = m[-j-1]
      o.append('+')
  if sum(n) == 7:
    print(str(m[0]) + o[0] + str(m[1]) + o[1] + str(m[2]) + o[2] + str(m[3]))
    exit()

Fixed, accepted submission:
x = str(input())
l = [x[0], x[1], x[2], x[3]]
m = [int(s) for s in l]
N = 2 ** 3
for i in range(N):
  n = [m[0], 0, 0, 0]
  o = [] 
  for j in range(3):
    if (i >> j) & 1:
      n[-j-1] = -m[-j-1]
      o.append('-')
    else:
      n[-j-1] = m[-j-1]
      o.append('+')
  if sum(n) == 7:
    print(str(m[0]) + o[2] + str(m[1]) + o[1] + str(m[2]) + o[0] + str(m[3]) + '=7')
    exit()
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
hitachi = list(input())

if len(hitachi) % 2 == 1:
    print("NO")

else:
    H = True
    for i in range(len(hitachi)):
        if i % 2 == 0:
            if hitachi[i] != "h":
                H = False
        else:
            if hitachi[i] != "i":
                H = False

    if H == True:
        print("YES")
    else:
        print("NO")

Fixed, accepted submission:
hitachi = list(input())

if len(hitachi) % 2 == 1:
    print("No")

else:
    H = True
    for i in range(len(hitachi)):
        if i % 2 == 0:
            if hitachi[i] != "h":
                H = False
        else:
            if hitachi[i] != "i":
                H = False

    if H == True:
        print("Yes")
    else:
        print("No")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
s = input()
print('s[0]' + 's[8]' + 's[10]')

Fixed, accepted submission:
s = input()
print('A' + s[8] + 'C')
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

#a = int(input())


lists=list(map(int,input().split()))

#s = input()

#print("{} {}".format(a+b+c, s))


if lists[0]<=lists[2] and lists[1]>=lists[2]:
        print("YES")
else:
    print("NO")


Fixed, accepted submission:
# -*- coding: utf-8 -*-

#a = int(input())


lists=list(map(int,input().split()))

#s = input()

#print("{} {}".format(a+b+c, s))


if lists[0]<=lists[2] and lists[1]>=lists[2]:
        print("Yes")
else:
    print("No")
Problem:
Write a program of the Selection Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 SelectionSort(A) 1 for i = 0 to A.length-1 2     mini = i 3     for j = i to A.length-1 4         if A[j] < A[mini] 5             mini = j 6     swap A[i] and A[mini]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 6 of the pseudocode in the case where i ≠ mini.

Incorrect submission (verdict: Wrong Answer):
def selectionSort(A,N):
    count = 0
    for i in range(N):
        minj = i
        for j in range(i,N):
            if A[j] < A[minj]:
                minj = j
        A[i],A[minj] = A[minj],A[i]
        count += 1
    return (count)

if __name__ == '__main__':
    n = int(input())
    data = [int(i) for i in range(n)]
    result = selectionSort(data,n)
    print(" ".join(map(str,data)))
    print(result)

Fixed, accepted submission:
def selection_Sort(A,N):
    count = 0
    for i in range(N):
        minj = i
        for j in range(i,N):
            if A[j] < A[minj]:
                minj = j
        if i != minj:
            A[i],A[minj] = A[minj],A[i]
            count += 1
    return (count)

if __name__ == '__main__':
    n = int(input())
    data = [int(i) for i in input().split()]
    result = selection_Sort(data,n)
    print(" ".join(map(str,data)))
    print(result)
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
def main():
    h, w = list(map(int, input().split()))
    if (h==1 or w==1):
        print(1)
    elif (h%2==0 or w%2==0):
        print((h*w)/2)
    else:
        print((h*w)//2+1)

if __name__ == '__main__':
    main()


Fixed, accepted submission:
def main():
    h, w = list(map(int, input().split()))
    if (h==1 or w==1):
        print(1)
    elif (h%2==0 or w%2==0):
        print(int((h*w)/2))
    else:
        print(int((h*w)//2+1))

if __name__ == '__main__':
    main()
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a , b , c = map(int,input().split())
if b - a == c - b:
  print("Yes")
else: 
  print("No")

Fixed, accepted submission:
a , b , c = map(int,input().split())
if b - a == c - b:
  print("YES")
else: 
  print("NO")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b=map(int, input().split())
c=a*b
# print(c)
d=c%2
if d==0:
    print("EVEN")
else:
    print("ODD")

Fixed, accepted submission:
a, b=map(int, input().split())
c=a*b
# print(c)
d=c%2
if d==0:
    print("Even")
else:
    print("Odd")
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
x = 1
for i in range(N):
  x = x*i
  if x >= 10**9+7:
    x = x-10**9-7
print(x%(10**+7))

Fixed, accepted submission:
N = int(input())
x = 1
for i in range(1,N+1):
  x = x*i
  x = x%(10**9+7)
print(x%(10**9+7))
#457992974
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
#58a
a,b,c = map(int,input().split())
print('Yes' if b-a==c-b else 'No')

Fixed, accepted submission:
#58a
a,b,c = map(int,input().split())
print('YES' if b-a==c-b else 'NO')
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
c = int(input())
print((a+b)*c/2)

Fixed, accepted submission:
a = int(input())
b = int(input())
c = int(input())
ans = int((a+b)*c/2)
print(ans)