TnT/CodeNet4Repair huggingface dataset:
Problem:
In cryptography, Caesar cipher is one of the simplest and most widely known encryption method. Caesar cipher is a type of substitution cipher in which each letter in the text is replaced by a letter some fixed number of positions down the alphabet. For example, with a shift of 1, 'a' would be replaced by 'b', 'b' would become 'c', 'y' would become 'z', 'z' would become 'a', and so on. In that case, a text:                 this is a pen   is would become:                 uijt jt b qfo   Write a program which reads a text encrypted by Caesar Chipher and prints the corresponding decoded text. The number of shift is secret and it depends on datasets, but you can assume that the decoded text includes any of the following words: "the", "this", or "that".

Incorrect submission (verdict: Wrong Answer):
import fileinput
import string

alphabetArray = list(string.ascii_lowercase)


for data in fileinput.input():
    for n in range(-25, 26):
        replacedStr = data
        for i in range(0, 26):
            if n > 0:
                replacedStr = replacedStr.replace(alphabetArray[i], alphabetArray[(i + n) % 26])
            else:
                replacedStr = replacedStr.replace(alphabetArray[i], alphabetArray[i + n])
        if "this" in replacedStr or "the" in replacedStr or "that" in replacedStr:
            print(replacedStr)
            break

Fixed, accepted submission:
import fileinput
import string

alphabetArray = list(string.ascii_lowercase)

for data in fileinput.input():
    for n in range(-26, 27):
        replacedStrAry = list(data.replace('\n', '').replace('\r', ''))
        for index in range(0, len(replacedStrAry)):
            if not replacedStrAry[index] in alphabetArray:
                continue
            if n >= 0:
                replacedStrAry[index] = alphabetArray[(alphabetArray.index(replacedStrAry[index]) + n) % 26]
            else:
                replacedStrAry[index] = replacedStrAry[index] = alphabetArray[alphabetArray.index(replacedStrAry[index]) + n]
        replacedStr = "".join(replacedStrAry)
        replacedStrSplitedBySpace = replacedStr.split(' ')
        if "the" in replacedStrSplitedBySpace or "this" in replacedStrSplitedBySpace or "that" in replacedStrSplitedBySpace:
            print(replacedStr)
            break
Problem:
Niwango-kun is an employee of Dwango Co., Ltd.   One day, he is asked to generate a thumbnail from a video a user submitted.   To generate a thumbnail, he needs to select a frame of the video according to the following procedure:    * Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.   * Select t-th frame whose representation a_t is nearest to the average of all frame representations.   * If there are multiple such frames, select the frame with the smallest index.  Find the index t of the frame he should select to generate a thumbnail.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
data = list(map(int, input().split()))
ave = sum(data) / len(data)
thumbnail_num = 1000
for i in range(len(data)):
  if abs(data[i] - ave) < thumbnail_num:
    thumbnail_num = i

print(thumbnail_num)


Fixed, accepted submission:
N = int(input())
data = list(map(int, input().split()))
ave = sum(data) / len(data)
ans = 0
for i in range(len(data)):
  if abs(data[i] - ave) < abs(data[ans] - ave):
    ans = i

print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
list1=[]
for i in range(N):
  a = input()
  list1.append(a)  
  
a = list1.count('AC')
b = list1.count('WA')
c = list1.count('TLE')
d = list1.count('RE')
list2 = [a,b,c,d]
print('AC x'+str(a))
print('WA x'+str(b))
print('TLE x'+str(c))
print('RE x'+str(d))

Fixed, accepted submission:
A = int(input())
list1 = []
for i in range(A):
  a = input()
  list1.append(a)
b =list1.count('AC')
c =list1.count('TLE')
d =list1.count('RE')
e =list1.count('WA')
print('AC x '+ str(b))
print('WA x '+ str(e))
print('TLE x '+str(c))
print('RE x '+str(d))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
price = int(input())
bochi = price % 1000

print(bochi)

Fixed, accepted submission:
price = int(input())
sen = 1000
senCnt = int(price / 1000)
num = 0

if price % sen != 0:
    senCnt = senCnt + 1
    sen = sen * senCnt
    num = sen - price
    
print(num)
Problem:
Let N be a positive odd number.  There are N coins, numbered 1, 2, \ldots, N. For each i (1 \leq i \leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.  Taro has tossed all the N coins. Find the probability of having more heads than tails.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
N = int(input())
p = np.array([0.0] + list(map(float, input().split())))


dp = np.zeros((N + 1, N + 1), np.float32)
dp[0, 0] = 1
dp[:, 0] = np.cumprod(1 - p).T

for i in range(1, N + 1):
    dp[i][1:] = dp[i - 1][:-1] * p[i] + dp[i - 1][1:] * (1 - p[i])

print(dp[-1][N // 2 + 1:].sum())

Fixed, accepted submission:
import numpy as np
N = int(input())
p = np.array([0.0] + list(map(float, input().split())))


dp = np.zeros((N + 1, N + 1), np.float64)
dp[0, 0] = 1
dp[:, 0] = np.cumprod(1 - p).T

for i in range(1, N + 1):
    dp[i][1:] = dp[i - 1][:-1] * p[i] + dp[i - 1][1:] * (1 - p[i])

print(dp[-1][(N + 1) // 2:].sum())
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
n,m=map(int,input().split())
ab=[list(map(int,input().split())) for i in range(m)]
l=[[]]*n
for a,b in ab:
  l[a-1].append(b)
  l[b-1].append(a)
ans=[[0]]*(n)
for j in range(n):
  for lll in l[j]:
    ans[lll-1]=j+1
for t in range(1,n):
  print(ans)

Fixed, accepted submission:
n,m=map(int,input().split())
l=[[] for _ in range(n)]
for i in range(m):
  a,b=map(int,input().split())
  l[a-1].append(b-1)
  l[b-1].append(a-1)
queue=[0]
visit=[0]*n
visit[0]=1
ans=[0]*n

while len(queue)>0: 
  now=queue.pop(0)
  for p in l[now]:
    if visit[p]==0:
      visit[p]+=1
      queue.append(p)
      ans[p]=now+1
k=ans[1:]
if not all(kk!=0 for kk in k):
  print('No')
  exit()
print('Yes')
for kk in k:
  print(kk)
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
s=list(input())

num=0
for i in range(n):
    x=set(s[:n])
    y=set(s[n:])
    if len(x&y)>num:
        num=len(x&y)

print(num)




Fixed, accepted submission:
n=int(input())
s=list(input())

num=0
for i in range(n):
    x=set(s[:i])
    y=set(s[i:])
    if len(x&y)>num:
        num=len(x&y)

print(num)
Problem:
Mountaineers Mr. Takahashi and Mr. Aoki recently trekked across a certain famous mountain range. The mountain range consists of N mountains, extending from west to east in a straight line as Mt. 1, Mt. 2, ..., Mt. N. Mr. Takahashi traversed the range from the west and Mr. Aoki from the east.  The height of Mt. i is h_i, but they have forgotten the value of each h_i. Instead, for each i (1 ≤ i ≤ N), they recorded the maximum height of the mountains climbed up to the time they reached the peak of Mt. i (including Mt. i). Mr. Takahashi's record is T_i and Mr. Aoki's record is A_i.  We know that the height of each mountain h_i is a positive integer. Compute the number of the possible sequences of the mountains' heights, modulo 10^9 + 7.  Note that the records may be incorrect and thus there may be no possible sequence of the mountains' heights. In such a case, output 0.

Incorrect submission (verdict: Wrong Answer):
from itertools import groupby
print(sum(1 for _ in groupby(input())) - 1)


Fixed, accepted submission:
N = int(input())
T = list(map(int, input().split()))
A = list(map(int, input().split()))
R = []
M = 1000000007


def main():
    global R
    global A
    p = -1
    for t in T:
        if t > p: # new
            R.append(t)
            p = t
        else:
            R.append(-t)

    
    R = list(reversed(R))
    A = list(reversed(A))

    p = -1
    for i, t in enumerate(A):
        r = R[i]
        if r < 0:
            max_h = -r
            if t > p: # new
                p = t
                if t <= max_h:
                    R[i] = t
                else:
                    return 0
            else:
                R[i] = -min(max_h, t)
        else:
            if t > p: # new
                p = t
                if t != r:
                    return 0
            else:
                if r > t:
                    return 0

    answer = 1
    for r in R:
        if r > 0:
            answer *= 1
        else:
            max_h = -r
            answer *= max_h
            answer %= M
    return answer
print(main())
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = int(input())
x = int(input())
y = int(input())

if n <= k:
    print(n*x)
else:
    print(n*x + (k-n)*y)

Fixed, accepted submission:
n = int(input())
k = int(input())
x = int(input())
y = int(input())

if n <= k:
    print(n*x)
else:
    print(k*x + (n-k)*y)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
k=n%1000
print(k)

Fixed, accepted submission:
from math import *
n=int(input())
k=n/1000
p=ceil(k)*1000
print(p-n)
Problem:
You manage 4 buildings, each of which has 3 floors, each of which consists of 10 rooms. Write a program which reads a sequence of tenant/leaver notices, and reports the number of tenants for each room.  For each notice, you are given four integers b, f, r and v which represent that v persons entered to room r of fth floor at building b. If v is negative, it means that −v persons left.  Assume that initially no person lives in the building.

Incorrect submission (verdict: Wrong Answer):
A = []
for _ in range(4):
        floor = []
        for _ in range(3):
                room = []
                for _ in range(10):
                        room.append(0)
                floor.append(room)
        A.append(floor)

n = int(input())

for _ in range(n):
        b, f, r, v = map(int, input().split())
        A[b-1][f-1][r-1] += v

for b in A:
        for f in b:
                f = list(map(str, f))
                print(' '.join(f))
        print('#'*20)



Fixed, accepted submission:
A = []
for _ in range(12):
	A.append([0]*10)

n = int(input())
for _ in range(n):
	b, f, r, v = map(int, input().split())
	A[3*b-(3-f)-1][r-1] += v

for i in range(12):        
	print(' ', end='')
	print(' '.join(map(str, A[i])))
	if i in [2, 5, 8]:
		print('#'*20)
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
A,B = map(int,input().split())
S = list(input())
c = 0

if len(S) != A+B+1:
    print("No")
else:
    for i in range(A):
        if S[i] == "-":
            print("No")
            break
        else:
            c += 1
if c == 1 :
    if S[A+1] != "-":
        print("No")
        c += 1
    else:
        for j in range(A+1,A+B+2):
            if S[j] == "-":
                print("No")
                c += 1
                break

if c == 1:
    print("Yes")


Fixed, accepted submission:
A,B = map(int,input().split())
S = list(input())
c = 0

if len(S) != A+B+1:
    print("No")
else:
    for i in range(A):
        if S[i] == "-":
            print("No")
            break
        else:
            c += 1

if c == A:
    if S[A] != "-":
        print("No")
        c += 1
    else:
        for j in range(A+1,A+B+1):
            if S[j] == "-":
                print("No")
                c += 1
                break

if c == A:
    print("Yes")
Problem:
Write a program which judges wheather given length of three side form a right triangle. Print "YES" if the given sides (integers) form a right triangle, "NO" if not so.

Incorrect submission (verdict: Wrong Answer):
import sys
input()
for line in sys.stdin:
    a, b, c = map(int, line.split())
    d = (a + b + c) / 2
    if(a > d or b > d or c > d):
        print("NO")
    else:
        print("YES")

Fixed, accepted submission:
N = int(input())
for i in range(N):
    a, b, c = map(int, input().split())
    if(a > c):
        a, c = c, a
    if(b > c):
        b, c = c, b
    if(c**2 == a**2 + b**2):
        print("YES")
    else:
        print("NO")
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):
import collections


def calc(A, K):
    dist = {}
    tmp = collections.Counter(A)
    type_ = len(tmp)

    if type_ <= K:
        return 0

    for a, count in tmp.items():
        if count not in dist.keys():
            dist[count] = [a]
        else:
            dist[count].append(a)

    rewrite = 0
    print(dist)
    for i, c in enumerate(sorted(dist.keys()), 1):
        for _ in dist[c]:
            rewrite += c
            if i == type_ - K:
                return rewrite


def main():
    N, K = map(int, input().split())
    A = list(map(int, input().split()))
    ans = calc(A, K)
    print(ans)


if __name__ == "__main__":
    main()

Fixed, accepted submission:
N, K = map(int, input().split())
cnt = [0 for _ in range(N)]

for i in map(int, input().split()):
    cnt[i-1] += 1

ans = 0
for i in sorted(cnt)[:N - K]:
    ans += i

print(ans)
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
A,B, C= list(map(int,input().split()))
K = int(input())

for i in range((K)):
    if(B>C):
        C=C*2
        print(A,B,C)
    elif(A>B):
        B=B*2
        print(A,B,C)
    
if (C>B >A):
     print('Yes')
else:
     print('No')

Fixed, accepted submission:
A,B, C= list(map(int,input().split()))
K = int(input())

for i in range((K)):
    if(A>=B):
        B=B*2
    elif(B>=C):
        C=C*2
    else:
        break
        
    
if (C>B >A):
     print('Yes')
else:
     print('No')
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
a,b,k=map(int,input().split())

for i in range(k):
    a-=a%2
    b-=b%2
    tmp=a//2
    a=b//2
    b=tmp
print(a,b)

Fixed, accepted submission:
a,b,k=map(int,input().split())

for i in range(k):
    if i%2==0:
        a-=a%2
        b+=a//2
        a=a//2
    else:
        b-=b%2
        a+=b//2
        b=b//2
print(a,b)
Problem:
10^{10^{10}} participants, including Takahashi, competed in two programming contests. In each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.  The _score_ of a participant is the product of his/her ranks in the two contests.  Process the following Q queries:    * In the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.

Incorrect submission (verdict: Wrong Answer):
from math import sqrt

q = int(input())
query = [tuple(map(int, input().split())) for _ in range(q)]


def sqrtfloor(x):
    s = int(sqrt(x))
    if s ** 2 == x:
        s -= 1
    return s


def solve(a, b):
    a, b = min(a, b), max(a, b)
    if a == b or a + 1 == b:
        return 2 * a - 1
    else:
        s = sqrtfloor(a * b)
        if s * (s + 1) < a * b:
            return 2 * s - 1
        else:
            return 2 * s - 2


for a, b in query:
    print(solve(a, b))


Fixed, accepted submission:
from math import sqrt

q = int(input())
query = [tuple(map(int, input().split())) for _ in range(q)]


def sqrtfloor(x):
    s = int(sqrt(x))
    if s ** 2 == x:
        s -= 1
    return s


def solve(a, b):
    a, b = min(a, b), max(a, b)
    if a == b or a + 1 == b:
        return 2 * a - 2
    else:
        s = sqrtfloor(a * b)
        if s * (s + 1) < a * b:
            return 2 * s - 1
        else:
            return 2 * s - 2


for a, b in query:
    print(solve(a, b))
Problem:
Write a program which judges wheather given length of three side form a right triangle. Print "YES" if the given sides (integers) form a right triangle, "NO" if not so.

Incorrect submission (verdict: Wrong Answer):
def judge(lists):
    lists.sort()
    if lists[0] ** 2 + lists[1] ** 2 - lists[2] ** 2:
        return False
    else:
        return True


def run():
    N = int(input())
    for _ in range(N):
        if judge([int(x) for x in input().split()]):
            print("Yes")
        else:
            print("NO")

if __name__ == '__main__':
    run()


Fixed, accepted submission:
def judge(lists):
    lists.sort()
    if lists[0] ** 2 + lists[1] ** 2 - lists[2] ** 2:
        return False
    else:
        return True


def run():
    N = int(input())
    for _ in range(N):
        if judge([int(x) for x in input().split()]):
            print("YES")
        else:
            print("NO")

if __name__ == '__main__':
    run()
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
def main():
    n = int(input())
    for i in range(3, n + 1, 3):
        print("", i, end="")
    print("")

if __name__ == "__main__":
    main()

Fixed, accepted submission:
def main():
    """
    n=30
     3 6 9 12 13 15 18 21 23 24 27 30
    """
    n = int(input())
    for i in range(1, n + 1):
        x = i
        if x % 3 == 0:
            print("", i, end="")
            continue

        while x > 0:
            if x % 10 == 3:
                print("", i, end="")
                break

            x //= 10

    print("")

if __name__ == "__main__":
    main()
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
s = input()
print(s)

Fixed, accepted submission:
a,b = map(int,input().split())
if a*b%2 == 0:
  print("Even")
else:
  print("Odd")
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
x=int(input())
num=100
cnt=0
while num < x:
    num*=1.01
    num=int(num)
    print(num)
    cnt+=1
print(cnt)

Fixed, accepted submission:
x=int(input())
num=100
cnt=0
while num < x:
    num*=1.01
    num=int(num)
    cnt+=1
print(cnt)
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
import math
h, w = map(int, input().split())
ans = math.ceil(h*w)
print(ans)

Fixed, accepted submission:
import math
h, w = map(int, input().split())
if h == 1 or w == 1:
    ans = 1
else:
    ans = math.ceil(h*w/2)
print(ans)