TnT/CodeNet4Repair huggingface dataset:
Problem:
We have N sticks with negligible thickness. The length of the i-th stick is A_i.  Snuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides. Find the maximum possible area of the rectangle.

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8
N=int(input())
A=list(map(int,input().split()))
A.sort(reverse=True)
cnt=1
ans=[]
for i in range(N-1):
    #print(cnt,ans)
    if A[i]==A[i+1]:
        cnt+=1
    elif cnt>=2:
        ans.append(A[i-1])
        cnt=1
        if len(ans)==2:
            break
#print(A)
if len(ans)<=1:
    print(0)
else:
    print(ans[0]*ans[1])

Fixed, accepted submission:
# coding: utf-8
N=int(input())
A=list(map(int,input().split()))
A.sort(reverse=True)
ans=[]
l=0
while l<N-1:
    #print(cnt,ans)
    if A[l]==A[l+1]:
        ans.append(A[l])
        if len(ans)==2:
            break
        else:
            l+=2
    else:
        l+=1
#print(A)
if len(ans)<=1:
    print(0)
else:
    print(ans[0]*ans[1])
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
N,A,B=map(int,input().split())
ans=0
for x in range(1,N+1):
  temp=0
  for y in str(x):
    temp+=int(y)
    if temp>=A and temp<=B:
      ans+=temp
print(ans)

Fixed, accepted submission:
N,A,B=map(int,input().split())
ans=0
for x in range(1,N+1):
  temp=0
  for y in str(x):
    temp+=int(y)
  else:
    if temp>=A and temp<=B:
      ans+=x
print(ans)
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())
print(a + b + c + max(a, b, c) * (2 ^ (int(input())-1)))

Fixed, accepted submission:
a,b,c = map(int, input().split())
print(a + b + c + max(a, b, c) * (2 ** int(input()) - 1))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N%1000)

Fixed, accepted submission:
def solve():
    N = int(input())
    print((1000-N%1000)%1000)

if __name__ == "__main__":
    solve()
Problem:
You are given a string S of length N consisting of `(` and `)`. Your task is to insert some number of `(` and `)` into S to obtain a _correct bracket sequence_.   Here, a correct bracket sequence is defined as follows:    * `()` is a correct bracket sequence.   * If X is a correct bracket sequence, the concatenation of `(`, X and `)` in this order is also a correct bracket sequence.   * If X and Y are correct bracket sequences, the concatenation of X and Y in this order is also a correct bracket sequence.   * Every correct bracket sequence can be derived from the rules above.  Find the shortest correct bracket sequence that can be obtained. If there is more than one such sequence, find the lexicographically smallest one.

Incorrect submission (verdict: Wrong Answer):
import sys

stdin = sys.stdin

ns = lambda: stdin.readline()
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))

N = ni()
S = ns()

X = [0]*(len(S)-1)
for i in range(len(S)-1):
    if(S[i] == '('):
        X[i] = 1
    else:
        X[i] = -1

x = 0
d = [0]*(len(S))

for i in range(1, len(S)):
    d[i] = sum(X[0:i])

print ('('*-min(d)+S+')'*(d[len(S)-1]-min(d)))

Fixed, accepted submission:
import sys

stdin = sys.stdin

ns = lambda: stdin.readline()
ni = lambda: int(ns())
na = lambda: list(map(int, stdin.readline().split()))

N = ni()
S = ns().strip()

d = 0
mind = 0

for i in range(len(S)):
    if(S[i] == '('):
        d += 1
    else:
        d -= 1
    mind = min(mind,d)
print ('('*(-mind) + S + ')'*(d-mind))
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
def loop(n,y):
	for s1 in range(n+1):
		for s2 in range(n+1):
			if y== s1*10000+s2*5000+(n-s1-s2)*1000:
				return s1,s2,n-s1-s2
	else:
		return -1,-1,-1

def main():
	n,y = map(int,input().split())
	s1,s2,s3 = loop(n,y)
	print("{} {} {}".format(s1,s2,s3))

if __name__ == '__main__':
	main()

Fixed, accepted submission:
def solve(n, y):
	tmp1000 = n * 1000
	if tmp1000 > y:		
		return -1, -1, -1
	diff = y - tmp1000		
	
	for y in range(diff // 4000 + 1):
		tmp5000 = y * 4000
		if (diff - tmp5000) % 9000 == 0:	
			x = (diff - tmp5000) // 9000
			if x + y <= n:			
				return x, y, n - x - y
	return -1, -1, -1
    
print(*solve(*map(int, input().split())))
Problem:
AtCoDeer the deer recently bought three paint cans. The color of the one he bought two days ago is a, the color of the one he bought yesterday is b, and the color of the one he bought today is c. Here, the color of each paint can is represented by an integer between 1 and 100, inclusive.  Since he is forgetful, he might have bought more than one paint can in the same color. Count the number of different kinds of colors of these paint cans and tell him.

Incorrect submission (verdict: Wrong Answer):
c = [map(int,input().split())]
print(len(set(c)))

Fixed, accepted submission:
c = list(map(int,input().split()))
print(len(set(c)))
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b = list(map(float,input().split()))

if float(a+b/2) == int(a+b/2):
  print(int(a+b/2))
else:
  print(int(a+b/2)+1)

Fixed, accepted submission:
a,b = list(map(float,input().split()))

if float((a+b)/2) == int((a+b)/2):
  print(int((a+b)/2))
else:
  print(int((a+b)/2)+1)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
i = int(input())

print(i % 1000)

Fixed, accepted submission:
i = int(input())

if i % 1000 == 0:
    print(0)
else:
    div = i / 1000
    print((int(div)+1) * 1000 - i)
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input()
s = s[::-1]
l = ['erase','eraser','dream','dreamer']
lst = []
for i in range(4):
    w = l[i]
    w = w[::-1]
    lst.append(w)

for word in lst:
    s = s.replace(word,'')
if len(s) == 0:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
s = input()[::-1]
lst = [l[::-1] for l in ['dream', 'dreamer', 'erase', 'eraser']]
while len(s):
    flg = False
    if s[:5] == lst[0]:
        s = s[5:]
        flg = True
    elif s[:7] == lst[1]:
        s = s[7:]
        flg = True
    elif s[:5] == lst[2]:
        s = s[5:]
        flg = True
    elif s[:6] == lst[3]:
        s = s[6:]
        flg = True
    if flg is False:
        break
print('YES' if len(s)==0 else 'NO')
Problem:
Write a program which reads three integers, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
x=input().split( )
x.sort()
print(x)

Fixed, accepted submission:
x=input().split( )
x.sort()
print(x[0] + " " + x[1] + " " + x[2])
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
h, w, k = map(int, input().split())
c = []
for _ in range(h):
    c.append(list(input()))
def calc_black_cnt(maskR, maskC):
    cnt = 0
    for i in range(h):
        for j in range(w):
            if maskR>>i & 1 == 0 and maskC>>j & 1 == 0 and c[i][j] == '#':
                cnt += 1
    return cnt
ans = 0
for maskR in range(1<<h):
    for maskC in range(1<<w):
         if calc_black_cnt(maskR, maskC) == k:
                ans += 1
ans

Fixed, accepted submission:
h, w, k = map(int, input().split())
c = []
for _ in range(h):
    c.append(list(input()))
def calc_black_cnt(maskR, maskC):
    cnt = 0
    for i in range(h):
        for j in range(w):
            if maskR>>i & 1 == 0 and maskC>>j & 1 == 0 and c[i][j] == '#':
                cnt += 1
    return cnt
ans = 0
for maskR in range(1<<h):
    for maskC in range(1<<w):
         if calc_black_cnt(maskR, maskC) == k:
                ans += 1
print(ans)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a,b,c=input().split()
ls=[a,b,c]
ls.sort
if ls[0]==ls[1]==5 and ls[2]==7:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
a,b,c=input().split()
ls=[a,b,c]
ls.sort()
if ls[0]==ls[1]=="5" and ls[2]=="7":
  print("YES")
else:
  print("NO")
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = int(input())
C = int(input())
X = int(input())
X_div = X%50
count = 0
for i in range(A):
    for j in range(B):
        for k in range(C):
            if(10*i + 5*j + k == X_div):
                count += 1
print(count)


Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())
X_div = int(X/50)
count = 0
for i in range(1+A):
    for j in range(1+B):
        for k in range(1+C):
            if(10*i + 2*j + k == X_div):
                count += 1
print(count)
Problem:
Alice and Brown are brothers in a family and each receives pocket money in celebration of the coming year. They are very close and share the total amount of the money fifty-fifty. The pocket money each receives is a multiple of 1,000 yen.  Write a program to calculate each one’s share given the amount of money Alice and Brown received.

Incorrect submission (verdict: Wrong Answer):
# coding=utf-8

a, b = map(int, input().split())
print((a+b)/2)



Fixed, accepted submission:
# coding=utf-8

a, b = map(int, input().split())
print((a+b)//2)
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
A,B,C = [int(i) for i in input().split()]
if (A+B <= C) :
	print("Yes")
else :
	print("No")

Fixed, accepted submission:
A,B,C = [int(i) for i in input().split()]
if (A+B >= C) :
	print("Yes")
else :
	print("No")
Problem:
Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier. He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.  Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.  Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.  Write a program that outputs `delicious` if he found it delicious, `safe` if he did not found it delicious but did not get a stomachache either, and `dangerous` if he got a stomachache.

Incorrect submission (verdict: Wrong Answer):
X,A,B = map(int,input().split())

if X >= (A+B):
    print("delicious")
elif  X <= ((A+B)) <= (X+1):
    print("safe")
elif  X+1 < (A+B):
    print("dangerous")


Fixed, accepted submission:
X, A, B = map(int, input().split())
if A - B >= 0:
    print('delicious')
elif B - A <= X:
    print('safe')
else:
    print('dangerous')
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a=int(input());b=int(input());h=int(input())
print((a+b)*h/2)

Fixed, accepted submission:
a=int(input());b=int(input());h=int(input())
print((a+b)*h//2)
Problem:
There are 2N squares arranged from left to right. You are given a string of length 2N representing the color of each of the squares.  The color of the i-th square from the left is black if the i-th character of S is `B`, and white if that character is `W`.  You will perform the following operation exactly N times: choose two distinct squares, then invert the colors of these squares and the squares between them. Here, to invert the color of a square is to make it white if it is black, and vice versa.  Throughout this process, you cannot choose the same square twice or more. That is, each square has to be chosen exactly once.  Find the number of ways to make all the squares white at the end of the process, modulo 10^9+7.  Two ways to make the squares white are considered different if and only if there exists i (1 \leq i \leq N) such that the pair of the squares chosen in the i-th operation is different.

Incorrect submission (verdict: Wrong Answer):
import sys
n = int(input())
s = input()
if s[0] == "W":
  print(0)
  sys.exit()
MOD = 10**9+7
ans = 1
cnt = 1
for i in range(n):
  if s[i+1] != s[i]:
    cnt += 1
  else:
    ans *= cnt
    ans %= MOD
    cnt -= 1
if cnt != 0:
  print(0)
else:
  print(ans)

Fixed, accepted submission:
import sys
n = int(input())
s = input()
if s[0] == "W":
  print(0)
  sys.exit()
MOD = 10**9+7
ans = 1
cnt = 1
right = 1
for i in range(2*n-1):
  if s[i+1] == s[i]:
    right ^= 1
  if right:
    cnt += 1
  else:
    ans *= cnt
    ans %= MOD
    cnt -= 1
if cnt != 0:
  print(0)
else:
  for i in range(1, n+1):
    ans *= i
    ans %= MOD
  print(ans)
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())

A = [a,b,c]
A.sort()
if A[2] - A[1] == A[1] - A[0]:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
a,b,c = map(int, input().split())

A = [a,b,c]
A.sort()
if A[2] - A[1] == A[1] - A[0]:
  print("YES")
else:
  print("NO")
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
a,b,c=input().split()
print(a+b[0].upper()+c)

Fixed, accepted submission:
a,b,c=input().split()
print("A"+b[0]+"C")
Problem:
Write a program which computes the digit number of sum of two integers a and b.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int, input().split())
sum = a + b
digits = 1
while(sum//10 != 0):
    digits += 1
    sum //= 10
print(str(digits))



Fixed, accepted submission:

A = []
B = []
s = True
while(s):
    try:
        a,b = map(int, input().split())
    except:
        break
    A.append(a)
    B.append(b)

for i in range(len(A)):
    sum = A[i] + B[i]
    digits = 1
    while(sum//10 != 0):
        digits += 1
        sum //= 10
    print(str(digits))
Problem:
There is a directed graph G with N vertices and M edges. The vertices are numbered 1, 2, \ldots, N, and for each i (1 \leq i \leq M), the i-th directed edge goes from Vertex x_i to y_i. G **does not contain directed cycles**.  Find the length of the longest directed path in G. Here, the length of a directed path is the number of edges in it.

Incorrect submission (verdict: Wrong Answer):
from heapq import heappush, heappop
import collections
import math
import heapq
from collections import defaultdict
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)
MOD = 10 ** 9 + 7
inf = float("inf")


def main():
    n, m = map(int, input().split())
    e = [[]for i in range(n)]
    for i in range(m):
        a, b = map(int, input().split())
        a -= 1
        b -= 1
        e[a].append(b)

    dp = [-1 for i in range(n)]
    def f(i):
        if dp[i] != -1:
            return dp[i]
        ret = 0
        for v in e[i]:
            ret = max(ret, f(v) + 1)
        dp[i] = ret
        return dp[i]

    ans = 0
    for i in range(n):
        ans = max(f(i), ans)
    print(ans, dp)


if __name__ == '__main__':
    main()


Fixed, accepted submission:
from heapq import heappush, heappop
import collections
import math
import heapq
from collections import defaultdict
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)
MOD = 10 ** 9 + 7
inf = float("inf")


def main():
    n, m = map(int, input().split())
    e = [[]for i in range(n)]
    for i in range(m):
        a, b = map(int, input().split())
        a -= 1
        b -= 1
        e[a].append(b)

    dp = [-1 for i in range(n)]
    def f(i):
        if dp[i] != -1:
            return dp[i]
        ret = 0
        for v in e[i]:
            ret = max(ret, f(v) + 1)
        dp[i] = ret
        return dp[i]

    ans = 0
    for i in range(n):
        ans = max(f(i), ans)
    print(ans)


if __name__ == '__main__':
    main()
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = int(input())
C = int(input())
X = int(input())

count = 0
for a in range(A + 1):
  for b in range(B + 1):
    for c in range(C + 1):
      if 500 * a + 100 * b + 50 * c == X:
        count += 0


print(count)

Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())

count = 0
for a in range(A + 1):
  for b in range(B + 1):
    for c in range(C + 1):
      if 500 * a + 100 * b + 50 * c == X:
        count += 1


print(count)
Problem:
M-kun is a competitor in AtCoder, whose highest rating is X.   In this site, a competitor is given a _kyu_ (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:    * From 400 through 599: 8-kyu   * From 600 through 799: 7-kyu   * From 800 through 999: 6-kyu   * From 1000 through 1199: 5-kyu   * From 1200 through 1399: 4-kyu   * From 1400 through 1599: 3-kyu   * From 1600 through 1799: 2-kyu   * From 1800 through 1999: 1-kyu  What kyu does M-kun have?

Incorrect submission (verdict: Wrong Answer):
x = int(input())
print(f"{10 - x // 200}-kyu")


Fixed, accepted submission:
x = int(input())
print(f"{10 - x // 200}")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

print((a+b)*h/2)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())

print((a+b)*h//2)
Problem:
Write a program which reads three integers, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
I = input().split()
for i in[0, 1, 2]:
    I[i] = int(I[i])
for i in[0, 1, 2]:
    j = i + 1
    while j <= 2:
        if I[i] > I[j]:
            w = I[i]
            I[i] = I[j]
            I[j] = w
        j += 1
print(I)

Fixed, accepted submission:
I = input().split()
for i in[0, 1, 2]:
    I[i] = int(I[i])
for i in[0, 1, 2]:
    j = i + 1
    while j <= 2:
        if I[i] > I[j]:
            w = I[i]
            I[i] = I[j]
            I[j] = w
        j += 1
print(str(I[0]) + ' ' + str(I[1]) + ' ' + str(I[2]))
Problem:
There is an apple tree that bears apples of N colors. The N colors of these apples are numbered 1 to N, and there are a_i apples of Color i.  You and Lunlun the dachshund alternately perform the following operation (starting from you):    * Choose one or more apples from the tree and eat them. Here, the apples chosen at the same time must all have different colors.  The one who eats the last apple from the tree will be declared winner. If both you and Lunlun play optimally, which will win?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
l = [int(input()) for _ in range(N)]
print("Second" if (N-2)%2 else "First")

Fixed, accepted submission:
N = int(input())
l = [int(input()) for _ in range(N)]
print("second" if all(map(lambda x:x%2==0, l)) else "first")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
a=int(input())
print(a%1000)

Fixed, accepted submission:
N = int(input())
tmp = N % 1000
if tmp :
    print(1000 - tmp)
else :
    print(0)
Problem:
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.  At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:    * Choose a (connected) rope with a total length of at least L, then untie one of its knots.  Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.

Incorrect submission (verdict: Wrong Answer):
n,l=map(int,input().split())
A=[int(i) for i in input().split()]

wa=[A[i]+A[i+1] for i in range(n-1)]
lim=max(wa)

if l<lim:
    print("Possible")
else:
    print("Impossible")

Fixed, accepted submission:
n,l=map(int,input().split())
A=[int(i) for i in input().split()]

wa=[A[i]+A[i+1] for i in range(n-1)]
lim=max(wa)
knot=wa.index(lim)

go=False
if l<=lim:
    print("Possible")
    go=True
else:
    print("Impossible")
    
if go:
    for i in range(knot):
        print(i+1)
    for i in range(n-knot-2):
        print(n-i-1)
    print(knot+1)