TnT/CodeNet4Repair huggingface dataset:
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
n,m,X,Y=map(int,input().split())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
z=[]
for i in range(X+1,Y+1):
  z.append(i)
if max(x)>=min(y):
  print("War")
else:
  for i in range(max(x)+1,min(y)+1):
    if i in z:
      print("No war")
      break
    else:
      if i==min(y) and i not in z:
        print("War")

Fixed, accepted submission:
n,m,X,Y=map(int,input().split())
x_List=list(map(int,input().split()))
y_List=list(map(int,input().split()))
x_List.append(X)
y_List.append(Y)
ans=''
if max(x_List)<min(y_List):
  ans='No War'
else:
  ans='War'
print(ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
sl = [int(x) for x in input().split()]
n=0
for s in sl:
  if s==1:
    n+=1

print(n)


Fixed, accepted submission:
sl = [int(x) for x in input()]
n=0
for s in sl:
  if s==1:
    n+=1

print(n)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):

n=int(input())
print(1000-n//1000)

Fixed, accepted submission:
n=int(input())
if n%1000!=0:
    print(1000-n%1000)
else:
    print(0)
Problem:
There are K pieces of cakes. Mr. Takahashi would like to eat one cake per day, taking K days to eat them all.  There are T types of cake, and the number of the cakes of type i (1 ≤ i ≤ T) is a_i.  Eating the same type of cake two days in a row would be no fun, so Mr. Takahashi would like to decide the order for eating cakes that minimizes the number of days on which he has to eat the same type of cake as the day before.  Compute the minimum number of days on which the same type of cake as the previous day will be eaten.

Incorrect submission (verdict: Wrong Answer):
K, T = map(int, input().split())
a = list(map(int, input().split()))
print(max(a)-(sum(a)-max(a))-1, 0)

Fixed, accepted submission:
K, T = map(int, input().split())
a = list(map(int, input().split()))
print(max(max(a)-(sum(a)-max(a))-1, 0))
Problem:
Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Incorrect submission (verdict: Wrong Answer):
from math import sqrt
a,b,c=list(map(int,input().split()))
d=2*sqrt(a*b)
if c-a-b-d>0:
    print("Yes")
else:
    print("NO")

Fixed, accepted submission:
a,b,c=list(map(int,input().split()))
d=(c-a-b)**2
if 4*a*b<d and c-a-b>0:
    print("Yes")
else:
    print("No")
Problem:
Snuke has N integers: 1,2,\ldots,N. He will choose K of them and give those to Takahashi.  How many ways are there to choose K consecutive integers?

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
print(n + k -1)

Fixed, accepted submission:
n, k = map(int, input().split())
print(n - k + 1)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
_ = input()
l = list(map(int,input().split()))
mn = 99999
for i in l:
  count = 0
  if i %2 ==0:
    count +=1
    i /= 2
  else:
    continue
  if mn > count:
    count = mn
print(count)

Fixed, accepted submission:
n = int(input())

AS = list(map(int,input().split()))
count = 0

while True:
  for i in range(n):
    a = AS[i]
    if a %2:
      break
    AS[i] = int(a/2)
  else:
    count += 1
    continue
  break
print(count)
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Time Limit Exceeded):
def prm(a):
  if a==1:
    return False
  for i in range(2,int(a**0.5+1)):
    if a%i==0:
      return False
  else:
    return True
x=int(input())
d=[1]*(x+1)
for i in range(1,x+1):
  if prm(i):
    d[i]+=1
  else:
    while not prm(i):
      for j in range(2,i):
        if i%j==0:
          d[j]+=1
          i=i//j
          break
ans=0
for i in range(x+1):
  ans = ans * d[i] % (10**9+7)
print(ans)

Fixed, accepted submission:
def prm(a):
  if a==1 or a == 4:
    return False
  for i in range(2,int(a**0.5+1)):
    if a%i==0:
      return False
  else:
    return True
x=int(input())
d=[1]*(x+1)
for i in range(1,x+1):
  if prm(i):
    d[i]+=1
  else:
    while not prm(i) and i != 1:
      for j in range(2,i):
        if i%j==0:
          d[j]+=1
          i=i//j
          break
    if i!= 1:
      d[i]+=1
ans=1

for i in range(x+1):
  ans = ans * d[i] % (10**9+7)
print(ans)
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,x=map(int,input().split())
print(b//x-a//x)

Fixed, accepted submission:
a,b,x=map(int,input().split())
print(b//x-(a-1)//x if a else b//x+1)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a=list(map(int,input().split()))
if a[0]*a[1]*a[2] ==5*7*5:
    print("yes")
else : 
    print("no")

Fixed, accepted submission:
a=list(map(int,input().split()))
if a[0]*a[1]*a[2] ==5*7*5:
    print("YES")
else : 
    print("NO")
Problem:
We have a tree with N vertices numbered 1 to N. The i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i. Your objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:    * For any two vertices painted in the same color, the distance between them is an even number.  Find a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
def solve():
	n,*l=map(int,open(0).read().split())
	con=[[] for _ in range(n)]
	dist=[None]*n
	dist[0]=0
	for a,b,c in zip(*[iter(l)]*3):
		con[a-1].append((b-1,c%2))
		con[b-1].append((a-1,c%2))
 
	stk=[0]
	while stk:
		cur=stk.pop()
		for nxt,d in con[cur]:
			if dist[nxt]==None:
				stk.append(nxt)
				dist[nxt]=(dist[cur]+d)%2

	print(*dist,sep="\n")

Fixed, accepted submission:
def solve():
	from collections import deque
	n,*l=map(int,open(0).read().split())
	con=[[] for _ in range(n)]
	dist=[-1]*n
	dist[0]=0
	for a,b,c in zip(*[iter(l)]*3):
		con[a-1].append((b-1,c%2))
		con[b-1].append((a-1,c%2))
 
	stk=deque([0])
	while stk:
		cur=stk.pop()
		for nxt,d in con[cur]:
			if dist[nxt]<0:
				stk.append(nxt)
				dist[nxt]=(dist[cur]+d)%2

	print(*dist,sep="\n")

if __name__=="__main__":
	solve()
Problem:
Find the number of _palindromic numbers_ among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Incorrect submission (verdict: Wrong Answer):
def main():
    A, B = input().split()
    print(int(B[:3]) - int(A[:3]))


main()


Fixed, accepted submission:
def main():
    A, B = map(int, input().split())
    c = 0
    for i in range(A, B + 1):
        if str(i)[:2] == str(i)[4] + str(i)[3]:
            c += 1
    print(c)


main()
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
data=[]
for i in range(4):
  data.append(int(input()))

if data[0]>=data[1]:
  a=data[2]*data[0]
  b=data[3]*(data[0]-data[1])
  print(a+b)
else:
  print(data[2]*data[0])

Fixed, accepted submission:
data=[]
for i in range(4):
  data.append(int(input()))

if data[0]>=data[1]:
  a=data[2]*data[1]
  b=data[3]*(data[0]-data[1])
  print(a+b)
else:
  print(data[2]*data[0])
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
s = input()
R = 0
B = 0
for i in s:
    if i == 'R':
        R += 1
    if i == 'B':
        B += 1
if R > B:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
N = int(input())
s = input()
R = 0
B = 0
for i in s:
    if i == 'R':
        R += 1
    if i == 'B':
        B += 1
if R > B:
    print('Yes')
else:
    print('No')
Problem:
Snuke has N sticks. The length of the i-th stick is l_i.  Snuke is making a snake toy by joining K of the sticks together.  The length of the toy is represented by the sum of the individual sticks that compose it. Find the maximum possible length of the toy.

Incorrect submission (verdict: Wrong Answer):
N, K = [int(i) for i in input().split()]

l = [int(j) for j in input().split()]

l = sorted(l)

ans = 0
for k in range(-1, -K-1 -1):
    ans += l[k]

print(ans)


Fixed, accepted submission:
N, K = [int(i) for i in input().split()]

l = [int(j) for j in input().split()]

l = sorted(l)

ans = 0
for k in range(N-K, N, 1):
    ans += l[k]

print(ans)
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
answer = 0
for x in range(1, 100000):
  if x ** 2 <= N:
    answer = x
  else:
    break
print(answer)
    

Fixed, accepted submission:
N = int(input())
answer = 0
for x in range(1, 100000):
  if x ** 2 <= N:
    answer = x ** 2
  else:
    break
print(answer)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
Data = []
for _ in range(N):
    Data.append(list(map(int,input().split())))

ctime = 0
cx = 0
cy = 0
ans = True

for i in range(N):
    nt,nx,ny = Data[i]
    dist = abs(nx-cx)+abs(ny-cy)
    dtime  = nt-ctime 

    print(dist,dtime)

    if dist > dtime or (dtime-dist) % 2 == 1:
        ans = False
        break

    ctime = nt
    cx = nx
    cy = ny

if ans :
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
N = int(input())
Data = []
for _ in range(N):
    Data.append(list(map(int,input().split())))

ctime = 0
cx = 0
cy = 0
ans = True

for i in range(N):
    nt,nx,ny = Data[i]
    dist = abs(nx-cx)+abs(ny-cy)
    dtime  = nt-ctime 

    if dist > dtime or (dtime-dist) % 2 == 1:
        ans = False
        break

    ctime = nt
    cx = nx
    cy = ny

if ans :
    print('Yes')
else:
    print('No')
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split());print('AB'[abs(a-b)>abs(b-c)])

Fixed, accepted submission:
x,a,b=map(int,input().split());print('AB'[abs(x-a)>abs(x-b)])
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
A = int(input())

if A >= 3000:
    print(1)
else:
    a = [100,101,102,103,104,105]
    N = A//100
    dp = np.array([np.array([0 for i in range(A+1)]) for j in range(N+1)])
    dp[0][0] = 1

    for i in range(N):
        for j in np.where(dp[i] == 1)[0]:
        #for j in range(A+1):
           
            dp[i+1][j+100:j+106] = 1
    print(dp[N][A])

Fixed, accepted submission:
import math
n = int(input())

a = n // 1.08

for i in range(3):
    b = math.floor(a*1.08)
    if b == n:
        ans = round(a)
    else:
        a += 1
        ans = ":("
print(ans)
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
N= [int(input()) for n in range(4)]
print(N[0]*N[2]+(N[0]-N[1])*N[3])

Fixed, accepted submission:
N= [int(input()) for n in range(4)]
if N[0] < N[1]:
    print(N[0]*N[2])
else:
    print(N[1]*N[2]+(N[0]-N[1])*N[3])
Problem:
You have written N problems to hold programming contests. The i-th problem will have a score of P_i points if used in a contest.  With these problems, you would like to hold as many contests as possible under the following condition:    * A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.  The same problem should not be used in multiple contests. At most how many contests can be held?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a,b = map(int,input().split())
p = map(int,input().split())

print(p)

list1 = []
list2 = []
list3 = []

for i in p:
    if i<=a:
        list1.append(i)
    elif i<=b:
        list2.append(i)
    else:
        list3.append(i)


if len(list1)>=len(list2):
    if len(list2)>=len(list3):
        print(len(list3))
    else:
        print(len(list2))
else:
    if len(list1)>=len(list3):
        print(len(list3))
    else:
        print(len(list1))

Fixed, accepted submission:
n=int(input())
a,b = map(int,input().split())
p = map(int,input().split())



list1 = []
list2 = []
list3 = []

for i in p:
    if i<=a:
        list1.append(i)
    elif i<=b:
        list2.append(i)
    else:
        list3.append(i)


if len(list1)>=len(list2):
    if len(list2)>=len(list3):
        print(len(list3))
    else:
        print(len(list2))
else:
    if len(list1)>=len(list3):
        print(len(list3))
    else:
        print(len(list1))
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from collections import deque

[N, M] = [ int(x) for x in input().split() ]

G = dict()
for i in range(1,N+1):
    G[i] = set()

for i in range(M):
    [A,B] = [ int(x) for x in input().split() ]
    G[A].add(B)
    G[B].add(A)

ans = [0]*(N+1)

Q = deque([1])
visited = set()
while Q:
    room = Q.popleft()
    
    if room not in visited:
        visited.add(room)
        
        for r in G[room]:
            if r not in visited:
                ans[r] = room
                Q.append(r)
ans[1] = 'Yes'
for i in range(1, N+1):
    print(ans[i])

Fixed, accepted submission:
from collections import deque

[N, M] = [ int(x) for x in input().split() ]

G = dict()
for i in range(1,N+1):
    G[i] = set()

for i in range(M):
    [A,B] = [ int(x) for x in input().split() ]
    G[A].add(B)
    G[B].add(A)

ans = dict()

Q = deque([1])
visited = set()
while Q:
    room = Q.popleft()
    
    if room not in visited:
        visited.add(room)
        
        for r in G[room]:
            if r not in ans:
                ans[r] = room
            Q.append(r)
for i in range(2, N+1):
    if i not in ans:
        print('No')
        exit()

ans[1] = 'Yes'
for i in range(1, N+1):
    print(ans[i])
Problem:
Write a program which calculates the area and perimeter of a given rectangle.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
print(a*b)



Fixed, accepted submission:
a,b = map(int,input().split())
print(a*b,2*(a+b))
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
import math

N = int(input())

NN = math.floor(N / 1.08)

NNN = math.floor(NN*1.08)

print(NN, NNN)

if N == NNN:
    print(NN)
else:
    print(':(')

Fixed, accepted submission:
import math

N = int(input())

NN = math.floor(N / 1.08)

NNN = math.floor(NN*1.08)

if N == NNN:
    print(NN)
else:
    if math.floor((NN+1)*1.08) == N:
        print(NN+1)
    else:
        print(':(')
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from collections import defaultdict
from collections import deque
n , m = map(int , input().split())
g = defaultdict(list)
for i in range(m):
	u , v = map(int , input().split())
	g[u].append(v)
	g[v].append(u)
print(g)
ans = [0]*(n+1)
visited = [False]*(n+1)

q = deque()
q.append(1)
depth = 1
while q:
	node = q.popleft()
	visited[node] = True
	for ele in g[node]:
		if not visited[ele]:
			if ans[ele] == 0: ans[ele] = depth
			q.append(ele)
	depth+=1
#print(ans)
a = []
for i in range(2,n+1):
	f = 1
	for node in g[i]:
		print(i,node,ans[i],ans[node])
		if ans[node] == ans[i] - 1:
			a.append(node)
			f = 0
			break
	if f: print("NO"); exit()

print("YES")
for i in a:
	print(i)

#print(ans)
			


Fixed, accepted submission:
from collections import defaultdict
from collections import deque
n , m = map(int , input().split())
g = defaultdict(list)
for i in range(m):
	u , v = map(int , input().split())
	g[u].append(v)
	g[v].append(u)
#print(g)
visited = [False]*(n+1)
a = [10**10]*(n+1)
q = deque()
q.append(1)
while q:
	node = q.popleft()
	visited[node] = True
	for ele in g[node]:
		if not visited[ele]:
			if a[ele] != 10**10: 
				continue
			a[ele] = node
			q.append(ele)
#print(ans)
#print(a)
print("Yes")
for i in a[2:]:
	print(i)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
x = (a + b) / 2

if (a + b) % 2 == 0:
  print(x)
else:
  print(x + 1)

Fixed, accepted submission:
a, b = map(int, input().split())
x = (a + b) / 2

if (a + b) % 2 == 0:
  print(int(x))
else:
  print(int(x + 1))
Problem:
In _K-city_ , there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?

Incorrect submission (verdict: Wrong Answer):
chr = input()
chr_list = list(chr)
length = len(chr_list)

a, z =  chr_list[0], chr_list[length - 1]

print(a, length - 2, z, sep = '')

Fixed, accepted submission:
n, m = input().split()
n = int(n)
m = int(m)
print((n-1)*(m-1))