Problem:
There is a string s of length 3 or greater. No two neighboring characters in s are equal.  Takahashi and Aoki will play a game against each other. The two players alternately performs the following operation, Takahashi going first:    * Remove one of the characters in s, excluding both ends. However, a character cannot be removed if removal of the character would result in two neighboring equal characters in s.  The player who becomes unable to perform the operation, loses the game. Determine which player will win when the two play optimally.

Incorrect submission (verdict: Wrong Answer):

# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
from pprint import pprint
from collections import Counter, defaultdict, deque
import queue
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
from operator import add, mul, sub

sys.setrecursionlimit(10000)


def read_int():
    return int(input())


def read_int_n():
    return list(map(int, input().split()))


def read_float():
    return float(input())


def read_float_n():
    return list(map(float, input().split()))


def read_str():
    return input().strip()


def read_str_n():
    return list(map(str, input().split()))


def error_print(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.time()
        ret = f(*args, **kwargs)
        e = time.time()

        error_print(e - s, 'sec')
        return ret

    return wrap


def Prim(g):
    V = list(g.keys())
    for v in g.values():
        V.extend(list(v.keys()))
    V = list(set(V))

    used = set([])
    q = []
    heapq.heappush(q, (0, V[0]))

    ret = 0
    while q:
        c, v = heapq.heappop(q)

        if v in used:
            continue
        used.add(v)
        ret += c
        for u in g[v]:
            heapq.heappush(q, (g[v][u], u))
    return ret


@mt
def slv(S):
    even = len(S) % 2 == 0
    hte = S[0] == S[1]

    if even != hte:
        return 'Second'
    return 'First'


def main():
    S = read_str()

    print(slv(S))


if __name__ == '__main__':
    main()


Fixed, accepted submission:

# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
from pprint import pprint
from collections import Counter, defaultdict, deque
import queue
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
from operator import add, mul, sub

sys.setrecursionlimit(10000)


def read_int():
    return int(input())


def read_int_n():
    return list(map(int, input().split()))


def read_float():
    return float(input())


def read_float_n():
    return list(map(float, input().split()))


def read_str():
    return input().strip()


def read_str_n():
    return list(map(str, input().split()))


def error_print(*args):
    print(*args, file=sys.stderr)


def mt(f):
    import time

    def wrap(*args, **kwargs):
        s = time.time()
        ret = f(*args, **kwargs)
        e = time.time()

        error_print(e - s, 'sec')
        return ret

    return wrap


def Prim(g):
    V = list(g.keys())
    for v in g.values():
        V.extend(list(v.keys()))
    V = list(set(V))

    used = set([])
    q = []
    heapq.heappush(q, (0, V[0]))

    ret = 0
    while q:
        c, v = heapq.heappop(q)

        if v in used:
            continue
        used.add(v)
        ret += c
        for u in g[v]:
            heapq.heappush(q, (g[v][u], u))
    return ret


@mt
def slv(S):
    even = len(S) % 2 == 0
    hte = S[0] == S[-1]
    if even != hte:
        return 'Second'
    return 'First'


def main():
    S = read_str()

    print(slv(S))


if __name__ == '__main__':
    main()