TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):
n = [int(i) for i in input().split() ]


rgb =  n[0:3]
rgb.sort(reverse=True)
#rgb = list(filter(lambda x:x >= n[3],rgb))

rm = int(n[3]/rgb[0] ) + 1
c = 0
for i in range(rm):
    print(i)
    if i * rgb[0] == n[3]:
            c += 1
            break
        
    for j in range(int((n[3] - i * rgb[0])/rgb[1]) + 1):
        

        if (n[3] - i * rgb[0] - j * rgb[1]) % rgb[2] == 0:
            c += 1

print (c)
    

Fixed, accepted submission:
n = [int(i) for i in input().split() ]


rgb =  n[0:3]
rgb.sort(reverse=True)
#rgb = list(filter(lambda x:x >= n[3],rgb))

rm = int(n[3]/rgb[0] ) + 1
c = 0
for i in range(rm):
    if i * rgb[0] == n[3]:
            c += 1
            break
        
    for j in range(int((n[3] - i * rgb[0])/rgb[1]) + 1):
        

        if (n[3] - i * rgb[0] - j * rgb[1]) % rgb[2] == 0:
            c += 1

print (c)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
input()
A=list(map(int,input().split()))
ans=0
while all(a%2==0 for a in A):
  ans+=1
print(ans)

Fixed, accepted submission:
input()
A=list(map(int,input().split()))
ans=0
while all(a%2==0 for a in A):
  A=[a/2 for a in A]
  ans+=1
print(ans)
Problem:
_n_ _q_   _name 1 time1_   _name 2 time2_   ...   _name n timen_    In the first line the number of processes _n_ and the quantum _q_ are given separated by a single space.  In the following _n_ lines, names and times for the _n_ processes are given. _name i_ and _time i_ are separated by a single space.

Incorrect submission (verdict: Wrong Answer):
s=0
A=input().split()
n=(int)(A[0])
t=(int)(A[1])
x=[0 for i in range(2*n)]
for i in range(n):
    B=input().split()
    k=2*i
    x[k]=(B[0])
    x[k+1]=(int)(B[1])
while len(x)>0:
    s=x[1]-t
    if s>0: 
        sum=t
        x.append(x[0])
        x.append(s)
        del x[0]
        del x[0]
    if s<=0:
        sum+=x[1]
        print( x[0],":",sum)
        del x[0]
        del x[0]



Fixed, accepted submission:
sum=0
s=0
A=input().split()
n=(int)(A[0])
t=(int)(A[1])
x=[0 for i in range(2*n)]
for i in range(n):
    B=input().split()
    k=2*i
    x[k]=(B[0])
    x[k+1]=(int)(B[1])
while len(x)>0:
    s=x[1]-t
    if s>0: 
        sum+=t
        x.append(x[0])
        x.append(s)
        del x[0]
        del x[0]
    if s<=0:
        sum+=x[1]
        print( x[0],sum)
        del x[0]
        del x[0]
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
N,K = [int(_) for _ in input().split()]
if N/2 >= K:
    print("YES")
else:
    print("NO")


Fixed, accepted submission:
N,K = [int(_) for _ in input().split()]
if N >= K*2 - 1:
    print("YES")
else:
    print("NO")
Problem:
Write a program which calculates the area and perimeter of a given rectangle.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
print(int(a) * int(b))

Fixed, accepted submission:
a,b = map(int,input().split())
c = a + b
print(int(a) * int(b),c * 2)
Problem:
How many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?

Incorrect submission (verdict: Wrong Answer):
i = int(input())
print(i+24)

Fixed, accepted submission:
i = int(input())
print((24-i)+24)
Problem:
Joisino is planning to open a shop in a shopping street.  Each of the five weekdays is divided into two periods, the morning and the evening. For each of those ten periods, a shop must be either open during the whole period, or closed during the whole period. Naturally, a shop must be open during at least one of those periods.  There are already N stores in the street, numbered 1 through N.  You are given information of the business hours of those shops, F_{i,j,k}. If F_{i,j,k}=1, Shop i is open during Period k on Day j (this notation is explained below); if F_{i,j,k}=0, Shop i is closed during that period. Here, the days of the week are denoted as follows. Monday: Day 1, Tuesday: Day 2, Wednesday: Day 3, Thursday: Day 4, Friday: Day 5. Also, the morning is denoted as Period 1, and the afternoon is denoted as Period 2.  Let c_i be the number of periods during which both Shop i and Joisino's shop are open. Then, the profit of Joisino's shop will be P_{1,c_1}+P_{2,c_2}+...+P_{N,c_N}.  Find the maximum possible profit of Joisino's shop when she decides whether her shop is open during each period, making sure that it is open during at least one period.

Incorrect submission (verdict: Wrong Answer):
from itertools import product

n = int(input())
F = [list(map(int,input().split())) for i in range(n)]
P = [list(map(int,input().split())) for i in range(n)]

ans = []
for p in product([0,1],repeat = 10):
	if sum(p) == 0:
		continue
	res = 0
	for i in range(n):
		cnt = 0
		for j in range(10):
			if p[j] == 1:
				cnt += F[i][j]
				res += P[i][cnt]
	ans.append(res)
print(max(ans))

Fixed, accepted submission:
from itertools import product

n = int(input())
F = [list(map(int,input().split())) for i in range(n)]
P = [list(map(int,input().split())) for i in range(n)]

ans = []
for p in product([0,1],repeat = 10):
	if sum(p) == 0:
		continue
	res = 0
	for i in range(n):
		cnt = 0
		for j in range(10):
			if p[j]:
				cnt += F[i][j]
		res += P[i][cnt]
	ans.append(res)
print(max(ans))
Problem:
How many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python
# -*- coding utf-8 -*-
x = int(input())
print("{}".format(x + 24))

Fixed, accepted submission:
# -*- coding: utf-8 -*-
M = int(input())
print(48-M)
Problem:
You went shopping to buy cakes and donuts with X yen (the currency of Japan).  First, you bought one cake for A yen at a cake shop. Then, you bought as many donuts as possible for B yen each, at a donut shop.  How much do you have left after shopping?

Incorrect submission (verdict: Wrong Answer):
print(int(input())-int(input())-int(input()))

Fixed, accepted submission:
x = int(input())
a = int(input())
b = int(input())
x -= a
print(x % b)
Problem:
宝物がたくさん収蔵されている博物館に、泥棒が大きな風呂敷を一つだけ持って忍び込みました。盗み出したいものはたくさんありますが、風呂敷が耐えられる重さが限られており、これを超えると風呂敷が破れてしまいます。そこで泥棒は、用意した風呂敷を破らず且つ最も価値が高くなるようなお宝の組み合わせを考えなくてはなりません。  風呂敷が耐えられる重さ W、および博物館にある個々のお宝の価値と重さを読み込んで、重さの総和が W を超えない範囲で価値の総和が最大になるときの、お宝の価値総和と重さの総和を出力するプログラムを作成してください。ただし、価値の総和が最大になる組み合わせが複数あるときは、重さの総和が小さいものを出力することとします。

Incorrect submission (verdict: Wrong Answer):
from sys import stdin

case = 0
while(True):
    case += 1
    W = int(stdin.readline())
    if not W: break
    print("Case %d"%case)
    N = int(stdin.readline())
    v = [0] * N
    w = [0] * N
    dp = [[0]*(W + 1) for _ in range(N + 1)]

    for k in range(N):
        v[k], w[k] = map(int, stdin.readline().split(","))
    for i in range(N-1,-1,-1):
        for j in range(W+1):
            if j < w[i]:
                dp[i][j] = dp[i + 1][j]
            else:
                dp[i][j] = max(dp[i + 1][j], dp[i + 1][j - w[i]] + v[i])
    print(dp[0][W])
    for i in range(W+1):
        if dp[0][i] == dp[0][W]: print(i); break




Fixed, accepted submission:
from sys import stdin

case = 0
while(True):
    case += 1
    W = int(stdin.readline())
    if not W: break
    print("Case %d:"%case)
    N = int(stdin.readline())
    v = [0] * N
    w = [0] * N
    dp = [[0]*(W + 1) for _ in range(N + 1)]

    for k in range(N):
        v[k], w[k] = map(int, stdin.readline().split(","))
    for i in range(N-1,-1,-1):
        for j in range(W+1):
            if j < w[i]:
                dp[i][j] = dp[i + 1][j]
            else:
                dp[i][j] = max(dp[i + 1][j], dp[i + 1][j - w[i]] + v[i])
    print(dp[0][W])
    for i in range(W+1):
        if dp[0][i] == dp[0][W]: print(i); break
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
A,B,C = list(input().split())

count = 0
if A == "7":
    count += 1
if B == "7":
    count += 1
if C == "7":
    count += 1

if count == 1:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
A = list(map(int, input().split()))

if A.count(7) == 1 and A.count(5) == 2:
    print("YES")
else:
    print("NO")
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
x, a, b = map(int, input().split())

if abs(x - a) > abs(x - b):
    print("A")
else:
    print("B")


Fixed, accepted submission:
x, a, b = map(int, input().split())

if abs(x - a) < abs(x - b):
    print("A")
else:
    print("B")
Problem:
AtCoder Mart sells 1000000 of each of the six items below:    * Riceballs, priced at 100 yen (the currency of Japan) each   * Sandwiches, priced at 101 yen each   * Cookies, priced at 102 yen each   * Cakes, priced at 103 yen each   * Candies, priced at 104 yen each   * Computers, priced at 105 yen each  Takahashi wants to buy some of them that cost exactly X yen in total. Determine whether this is possible.   (Ignore consumption tax.)

Incorrect submission (verdict: Wrong Answer):
ni = lambda: int(input())
nm = lambda: map(int, input().split())
nl = lambda: list(map(int, input().split()))
from math import ceil

x=ni()
p=x%100
if ceil(p/5) <= x//100:
  print('Yes')
else:
  print('No')


Fixed, accepted submission:
ni = lambda: int(input())
nm = lambda: map(int, input().split())
nl = lambda: list(map(int, input().split()))
from math import ceil

x=ni()
p=x%100
if ceil(p/5) <= x//100:
  print(1)
else:
  print(0)
Problem:
ある学級の生徒の出席番号と ABO 血液型を保存したデータを読み込んで、おのおのの血液型の人数を出力するプログラムを作成してください。なお、ABO 血液型には、A 型、B 型、AB 型、O 型の４種類の血液型があります。

Incorrect submission (verdict: Wrong Answer):
a={'A':0,'B':0,'O':0,'AB':0}
while 1:
    try:
        _,b=input().split(",")
        a[b]+=1
    except:
        for i in a:print(a[i])
        break

Fixed, accepted submission:
a={'A':0,'B':0,'O':0,'AB':0}
while 1:
    try:
        _,b=input().split(",")
        a[b]+=1
    except:
        for i in ['A','B','AB','O']:print(a[i])
        break
Problem:
In Takahashi Kingdom, there is an archipelago of N islands, called Takahashi Islands. For convenience, we will call them Island 1, Island 2, ..., Island N.  There are M kinds of regular boat services between these islands. Each service connects two islands. The i-th service connects Island a_i and Island b_i.  Cat Snuke is on Island 1 now, and wants to go to Island N. However, it turned out that there is no boat service from Island 1 to Island N, so he wants to know whether it is possible to go to Island N by using two boat services.  Help him.

Incorrect submission (verdict: Wrong Answer):
N,M = map(int,input().split())
li = []
numb = []
ans = ''
for i in range(M):
  li.append(tuple(map(int,input().split())))
  if li[i][0] == 1:
    numb.append(i)
for i in range(M):
  if li[i][0] in numb and li[i][1] == N:
    ans = 'POSSIBLE'
    break
if ans == '':
  print('IMPOSSIBLE')
else:
  print(ans)
    

Fixed, accepted submission:
N,M = map(int,input().split())
li = []
numb = []
for i in range(M):
    a,b = map(int,input().split())
    if a == 1:
        li.append(b)
    elif b == N:
        numb.append(a)
ans = set(li) & set(numb)
if len(ans) >= 1:
    print('POSSIBLE')
else:
    print('IMPOSSIBLE')
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n*800 - n*200//15)

Fixed, accepted submission:
n = int(input())
print(n*800 - (n//15)*200)
Problem:
You are given an integer K. Print the string obtained by repeating the string `ACL` K times and concatenating them.  For example, if K = 3, print `ACLACLACL`.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

def solve():
   return 'ALC'*int(input())

if __name__ == '__main__':
    print(solve())



Fixed, accepted submission:
# -*- coding: utf-8 -*-

def solve():
   return 'ACL'*int(input())

if __name__ == '__main__':
    print(solve())
Problem:
There are four towns, numbered 1,2,3 and 4. Also, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally. No two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.  Determine if we can visit all the towns by traversing each of the roads exactly once.

Incorrect submission (verdict: Wrong Answer):
a1,b1=map(int,input().split())
a2,b2=map(int,input().split())
a3,b3=map(int,input().split())
l=[]
l.append(a1)
l.append(b1)
l.append(a2)
l.append(b2)
l.append(a3)
l.append(b3)
print(l)
if l.count(1)==1 and l.count(4)==1 and l.count(2)==2 and l.count(3)==2:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
li=[0]*4
for i in range(3):
    a,b=map(int,input().split())
    li[a-1]+=1
    li[b-1]+=1
    
if li.count(1)==2 and li.count(2)==2:
    print('YES')
else:
    print('NO')
Problem:
It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.  The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.  How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Incorrect submission (verdict: Wrong Answer):
3
2
3


Fixed, accepted submission:
import sys
import math
import fractions
import bisect
import queue
import heapq
from collections import deque
sys.setrecursionlimit(4100000)

MOD = int(1e9+7)
PI = 3.14159265358979323846264338327950288
INF = 1e18



N = int(input())
H = int(input())
W = int(input())

print((N-H+1)*(N-W+1))
Problem:
AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.  The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.  How many different PIN codes can he set this way?  Both the lucky number and the PIN code may begin with a 0.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = input()
ans = 0
for a in range(10):
  for b in range(10):
    for c in range(10):
      for i in range(n-2):
        if s[i] == str(a):
          for j in range(i+1, n-1):
            if s[j] == str(b):
              for k in range(j+1, n):
                if s[k] == str(c):
                  ans += 1
print(ans)

Fixed, accepted submission:
n = int(input())
s = input()

before = [[-1] * 10]

for i in range(n):
  c = s[i]
  num = int(c)
  hoge = before[-1][::]
  hoge[num] = i
  before.append(hoge)

ans = 0
for i in range(10):
  now = before[-1][i]
  if now == -1:
    continue
  for j in range(10):
    now2 = before[now][j]
    if now2 == -1:
      continue
    for k in range(10):
      now3 = before[now2][k]
      if now3 == -1:
        continue
      ans += 1
print(ans)
Problem:
There are N items, numbered 1, 2, \ldots, N. For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.  Taro has decided to choose some of the N items and carry them home in a knapsack. The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.  Find the maximum possible sum of the values of items that Taro takes home.

Incorrect submission (verdict: Wrong Answer):
import numpy as np

N, W = map(int, input().split())
dp = np.zeros(W+1)
for i in range(N):
    w, v = map(int, input().split())
    dp[w:] = np.maximum(dp[w:], dp[:-w] + v)
    print(dp)

print(int(dp.max()))


Fixed, accepted submission:
import numpy as np

N, W = map(int, input().split())
dp = np.zeros(W+1)
for i in range(N):
    w, v = map(int, input().split())
    dp[w:] = np.maximum(dp[w:], dp[:-w] + v)

print(int(dp.max()))
Problem:
Given is an integer sequence of length N+1: A_0, A_1, A_2, \ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.

Incorrect submission (verdict: Wrong Answer):
import math

N = int(input())
leaf = list(map(int,input().split()))

end_flag = False
count = sum(leaf)
ans = 0
node = 1

for i in range(N+1):
    if end_flag:
        break
    ans += node
    count -= leaf[i]
    node = min(count, (node-leaf[i])*2)

    if node < 0:
        end_flag = True

if end_flag:
    print('-1')
else:
    print(1+sum(leaf)-leaf[N]+N*2)

Fixed, accepted submission:
import math

N = int(input())
leaf = list(map(int,input().split()))

end_flag = False
count = sum(leaf)
ans = 0
node = 1

for i in range(N+1):
    if end_flag:
        break
    ans += node
    count -= leaf[i]
    node = min(count, (node-leaf[i])*2)

    if node < 0:
        end_flag = True

if end_flag:
    print('-1')
else:
    print(ans)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
m=int(input())
print(m%1000)


Fixed, accepted submission:
m=int(input())
print((1000-m%1000)%1000)
Problem:
Write a program which reads a sequence of $n$ integers $a_i (i = 1, 2, ... n)$, and prints the minimum value, maximum value and sum of the sequence.

Incorrect submission (verdict: Wrong Answer):
def bubble_sort(l):
    N = len(l)
    isChange = True
    while isChange:
        isChange = False
        for i in range(N-1):
            if(l[i] > l[i+1]):
                l[i], l[i+1] = l[i+1], l[i]
                isChange = True
    return l

N = int(input())
l = input().split()
L = bubble_sort(l)
sum = 0
for k in L:
    n = int(k)
    sum += n

print("{} {} {}".format(L[0], L[-1], sum))

Fixed, accepted submission:
N = input()
l = map(int, input().split())
l = list(l)
print("{} {} {}".format(min(l), max(l), sum(l)))
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-


a = int(input())
b = int(input())
h = int(input())

print( ((a+b)*h)/2)

Fixed, accepted submission:
# -*- coding: utf-8 -*-


a = int(input())
b = int(input())
h = int(input())

print( int(((a+b)*h)/2) )
Problem:
You are given a string s. Among the **different** substrings of s, print the K-th lexicographically smallest one.  A substring of s is a string obtained by taking out a non-empty contiguous part in s. For example, if s = `ababc`, `a`, `bab` and `ababc` are substrings of s, while `ac`, `z` and an empty string are not. Also, we say that substrings are different when they are different as strings.  Let X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \neq y_{j}.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
k = int(input())
t = sorted(s)
u = []
v = []
for i in range(min(len(s), 5)):
    u.append(t[i])
for i in range(len(s)):
    if s[i] in u:
        if not [s[i]] in v:
            v.append([s[i]])
        l = [s[i]]
        for j in range(1, 5):
            if i + j == len(s):
                break
            l = l + [s[i + j]]
            if not l in v:
                v.append(l)
for i in range(len(v)):
    v[i] = "".join(v[i])
v.sort()
print(v[k - 1])
print(v)

Fixed, accepted submission:
s = list(input())
k = int(input())
t = sorted(s)
u = []
v = []
for i in range(min(len(s), 5)):
    u.append(t[i])
for i in range(len(s)):
    if s[i] in u:
        if not [s[i]] in v:
            v.append([s[i]])
        l = [s[i]]
        for j in range(1, 5):
            if i + j == len(s):
                break
            l = l + [s[i + j]]
            if not l in v:
                v.append(l)
for i in range(len(v)):
    v[i] = "".join(v[i])
v.sort()
print(v[k - 1])
Problem:
Snuke has N strings. The i-th string is s_i.  Let us concatenate these strings into one string after arranging them in some order. Find the maximum possible number of occurrences of `AB` in the resulting string.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
c = 0
xa = 0
bx = 0
ba = 0
for _ in range(n):
  si = str(input())
  l = len(si)
  s1 = si[0]
  s2 = si[-1]
  if s1=="B":
    if s2=="A":
      ba += 1
    else:
      bx += 1
  elif s2 == "A":
    xa += 1
  for i in range(l-1):
    if si[i]=="A" and si[i+1]=="B":
      c += 1
print(c,ba,bx,xa)
if ba == 0:
  print(c+min(bx,xa))
  exit()
if bx == 0:
  if  xa == 0:
    print(ba-1+c)
    exit()
  else:
    print(ba+c)
    exit()
if xa == 0:
  print(ba+c)
  exit()
print(min(bx,xa)+ba+c)

Fixed, accepted submission:
n = int(input())
c = 0
xa = 0
bx = 0
ba = 0
for _ in range(n):
  si = str(input())
  l = len(si)
  s1 = si[0]
  s2 = si[-1]
  if s1=="B":
    if s2=="A":
      ba += 1
    else:
      bx += 1
  elif s2 == "A":
    xa += 1
  for i in range(l-1):
    if si[i]=="A" and si[i+1]=="B":
      c += 1
if ba == 0:
  print(c+min(bx,xa))
  exit()
if bx == 0:
  if  xa == 0:
    print(ba-1+c)
    exit()
  else:
    print(ba+c)
    exit()
if xa == 0:
  print(ba+c)
  exit()
print(min(bx,xa)+ba+c)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s = input()
t = input()

s = sorted(s)
t = sorted(t)[::-1]

if s < t:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
s = input()
t = input()

s = sorted(s)
t = sorted(t)[::-1]

if s < t:
    print('Yes')
else:
    print('No')
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
# coding: utf-8

N_yen = int(input())
A_1mai = int(input())

answer = 'YES' if N_yen % 500 <= A_1mai else 'NO'
print(answer)


Fixed, accepted submission:
# coding: utf-8

N_yen = int(input())
A_1mai = int(input())

answer = 'Yes' if N_yen % 500 <= A_1mai else 'No'
print(answer)
Problem:
You are given four digits N_1, N_2, N_3 and N_4. Determine if these can be arranged into the sequence of digits "1974".

Incorrect submission (verdict: Wrong Answer):
n = set(map(int,input().split()))
print('YNeos'[n!={1,9,7,4}::2])

Fixed, accepted submission:
n = set(map(int,input().split()))
print('YNEOS'[n!={1,9,7,4}::2])