TnT/CodeNet4Repair huggingface dataset:
Problem:
We have a sandglass that runs for X seconds. The sand drops from the upper bulb at a rate of 1 gram per second. That is, the upper bulb initially contains X grams of sand.  How many grams of sand will the upper bulb contains after t seconds?

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
print(max(0, b - a))

Fixed, accepted submission:
a, b = map(int, input().split())
print(max(0, a - b))
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int,input().split())
print(["No","Yes"][x-a<b])

Fixed, accepted submission:
a,b,x = map(int,input().split())
print(["NO","YES"][a+b>=x>=a])
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
H, W, K = map(int, input().split())
S = []
for _ in range(H):
    S.append(input())
    


A = [[], [], [], [], [], []]
for i in range(H):
  A[i].append(','.join(map(lambda x: '"{}"'.format(x), S[0])))


print(A)

Fixed, accepted submission:
h, w, k = map(int, input().split())
c = []
for _ in range(h):
  c.append(list(input()))


all = 0
for i in c:
  all += i.count("#")

ans = 0
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
for hh in range(2 ** h):
  for ww in range(2 ** w):
    
    cnt = 0
    
    for i in range(h):
      for j in range(w):
        
        if (hh >> i) & 1 == 0 and (ww >> j) & 1 == 0:
          if c[i][j] == "#":
            cnt += 1
    if cnt == k:
      ans += 1
print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

s_list = {"AC": 0, "TLE": 0, "WA": 0, "RE": 0}

# a, t, w, r = 0, 0, 0, 0

for i in range(N):
  s = input()
  if s == "AC":
    s_list["AC"] += 1
  elif s == "TLE":
    s_list["TLE"] += 1
  elif s == "WA":
    s_list["WA"] += 1
  else:
    s_list["RE"] += 1
    

print("AC × {}\nTLE × {}\nWA × {}\nRE × {}".format(s_list["AC"], s_list["TLE"], s_list["WA"], s_list["RE"]))

Fixed, accepted submission:
N = int(input())

s_list = {"AC": 0, "TLE": 0, "WA": 0, "RE": 0}

# a, t, w, r = 0, 0, 0, 0

for i in range(N):
  s = input()
  if s == "AC":
    s_list["AC"] += 1
  elif s == "TLE":
    s_list["TLE"] += 1
  elif s == "WA":
    s_list["WA"] += 1
  else:
    s_list["RE"] += 1
    

print("AC x {}\nWA x {}\nTLE x {}\nRE x {}".format(s_list["AC"], s_list["WA"], s_list["TLE"], s_list["RE"]))
Problem:
N programmers are going to participate in the preliminary stage of DDCC 20XX. Due to the size of the venue, however, at most 9 contestants can participate in the finals.  The preliminary stage consists of several rounds, which will take place as follows:    * All the N contestants will participate in the first round.   * When X contestants participate in some round, the number of contestants advancing to the next round will be decided as follows:     * The organizer will choose two consecutive digits in the decimal notation of X, and replace them with the sum of these digits. The number resulted will be the number of contestants advancing to the next round.   For example, when X = 2378, the number of contestants advancing to the next round will be 578 (if 2 and 3 are chosen), 2108 (if 3 and 7 are chosen), or 2315 (if 7 and 8 are chosen).   When X = 100, the number of contestants advancing to the next round will be 10, no matter which two digits are chosen.    * The preliminary stage ends when 9 or fewer contestants remain.  Ringo, the chief organizer, wants to hold as many rounds as possible. Find the maximum possible number of rounds in the preliminary stage.  Since the number of contestants, N, can be enormous, it is given to you as two integer sequences d_1, \ldots, d_M and c_1, \ldots, c_M, which means the following: the decimal notation of N consists of c_1 + c_2 + \ldots + c_M digits, whose first c_1 digits are all d_1, the following c_2 digits are all d_2, \ldots, and the last c_M digits are all d_M.

Incorrect submission (verdict: Wrong Answer):
import sys
sys.stdin.readline

def main():
    m = int(input())
    a = [list(map(int, input().split())) for _ in range(m)]
    wa = 0
    length = 0
    for i,j in a:
        wa += i*j
        length += j
    print(wa,length)
    print(length-1+(wa-1)//9)
    
    
if __name__=="__main__":
    main()


Fixed, accepted submission:
import sys
sys.stdin.readline

def main():
    m = int(input())
    a = [list(map(int, input().split())) for _ in range(m)]
    wa = 0
    length = 0
    for i,j in a:
        wa += i*j
        length += j
    #print(wa,length)
    print(length-1+(wa-1)//9)
    
    
if __name__=="__main__":
    main()
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s.count('5') == 2 and s.count('1') == 1:
  print('YES')
else:
  print('NO')

Fixed, accepted submission:
s = input()
if s.count('5') == 2 and s.count('7') == 1:
  print('YES')
else:
  print('NO')
Problem:
Joisino is planning to record N TV programs with recorders.  The TV can receive C channels numbered 1 through C.  The i-th program that she wants to record will be broadcast from time s_i to time t_i (including time s_i but not t_i) on Channel c_i.  Here, there will never be more than one program that are broadcast on the same channel at the same time.  When the recorder is recording a channel from time S to time T (including time S but not T), it cannot record other channels from time S-0.5 to time T (including time S-0.5 but not T).  Find the minimum number of recorders required to record the channels so that all the N programs are completely recorded.

Incorrect submission (verdict: Wrong Answer):
n, c = map(int, input().split())
record = [[0]*(10**5+2) for _ in range(c+1)]
stc = [list(map(int, input().split())) for _ in range(n)]

for s, t, c in stc:
    record[c][s] += 1
    record[c][t] -= 1

for r in record:
    for i in range(10**5+1):
        r[i+1] += r[i]

ans = 0
for i in range(10**5):
    y = 0
    for r in record:
        y += r[i]
    ans = max(ans, y)
print(ans)

Fixed, accepted submission:
n, c = map(int, input().split())
stc = [list(map(int, input().split())) for _ in range(n)]
T = 10**5+1
record = [[0]*(T+3) for _ in range(c+1)]
channel = [[] for _ in range(c+1)]
stc.sort()

for s, t, c in stc:
    if not channel[c]:
        channel[c].append([s - 1, t])
        continue
    if channel[c][-1][1] == s:
        channel[c][-1][1] = t
    else:
        channel[c].append([s-1, t])

for i, v in enumerate(channel):
    for s, t in v:
        record[i][s] += 1
        record[i][t] -= 1

for i in record:
    for j in range(T+2):
        i[j+1] += i[j]

ans = 0
for i in range(T+2):
    y = 0
    for r in record:
        y += r[i]
    ans = max(ans, y)
print(ans)
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int,input().split()))

min = min(a)
max = max(a)
dis = 0
temp = 0

for i in range(n):
    dis += (a[i]-min)**2
print(dis)

for i in range(min+1,max+1):
    for j in range(n):
        print(i,j)
        temp += (a[j]-i)**2
        print("AAAAA")
        print(temp)
        print("AAAAA")

        if dis >= temp:
            dis = temp
        print("#####")
        print(dis)
    temp = 0

print(dis)


Fixed, accepted submission:

N = int(input())
A = list(map(int, input().split()))
 
ans = 10**9

for i in range(min(A), max(A)+1):
  cost = 0
  for a in A:
    cost += (a - i) ** 2
  ans = min(cost, ans)
 
print(ans)
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
s = input()
s_list = []

for i in s:
    s_list.append(i)
del s_list[-1]

while True:
    s_half = int(len(s_list)/2)
    s1 = s_list[:s_half]
    s2 = s_list[s_half:]
    if s1 == s2:
        print(s_half*2)
        break
    else:
        del s_list[-1]


Fixed, accepted submission:
a = list(map(int,input().split()))
a.sort()
print(a[0] + a[1])
Problem:
You are given two positive integers A and B. Compare the magnitudes of these numbers.

Incorrect submission (verdict: Wrong Answer):
A=int(input())
B=int(input())
print('GRATER' if A>B else 'LESS' if A<B else 'EQUAL')
 

Fixed, accepted submission:
A=int(input())
B=int(input())
print('GREATER' if A>B else 'LESS' if A<B else 'EQUAL')
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s = input()
t = input()

boolist = []
dict_s = sorted({i for i in s})[::-1]
dict_t = sorted({i for i in t})[::-1]

count = [len(dict_s), len(dict_t)][len(dict_s) > len(dict_t)]-1

if len(dict_s) == len(dict_t):
    print(["No", "Yes"][len(s) < len(t)])
else:
    for i in range(count):
        if dict_s[i] < dict_t[i]:
            boolist.append(True)
    print(["No", "Yes"][True in boolist])

Fixed, accepted submission:
s = "".join(sorted(input()))
t = "".join(sorted(input()))[::-1]
print(["No", "Yes"][s<t])
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
s=input()
for i in range(len(s)):
    x=-1
    for j in range(len(s)):
        if s[i]==s[j]:
            x+=1
    if x!=0:
        print("no")
        exit()
print("yes")


Fixed, accepted submission:
a,b=(int(x) for x in input().split())
if a+b>=10:
    print("error")
else:
    print(a+b)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
sum=a+b+c
g=[5,7]
if a and b and c in g:
    if sum==17:
        print("Yes")
    else:
        print("No")
else:
    print("No")

Fixed, accepted submission:
a,b,c=map(int,input().split())
sum=a+b+c
g=[5,7]
if a and b and c in g:
    if sum==17:
        print("YES")
    else:
        print("NO")
else:
    print("NO")
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
N, L = map(int, input().split())
s_list = []
for i in range(int(N)):
    s_list.append((input()))

s_list = sorted(s_list)

answer = ','.join(s_list)
print(answer)

Fixed, accepted submission:
N, L = map(int, input().split())
s_list = []
for i in range(int(N)):
    s_list.append((input()))

s_list = sorted(s_list)

answer = ''.join(s_list)
print(answer)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
S=[input() for i in range(N)]

print("AC x "+str(S.count("AC")))
print("WA x "+str(S.count("WA")))
print("TEL x "+str(S.count("TEL")))
print("RE x "+str(S.count("RE")))

Fixed, accepted submission:
N=int(input())
S=[input() for i in range(N)]

print("AC x "+str(S.count("AC")))
print("WA x "+str(S.count("WA")))
print("TLE x "+str(S.count("TLE")))
print("RE x "+str(S.count("RE")))
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
list_an = input().split()
list_an_int = [int(s) for s in list_an]

list_an_int.sort()
list_an_int.reverse()

print(list_an_int)
Alice_counter = 0
Bob_counter = 0

counter = 0
for i in range(N):
    if counter % 2 == 0:
        Alice_counter += list_an_int[i]
    else:
        Bob_counter += list_an_int[i]
    counter += 1
print(Alice_counter - Bob_counter)


Fixed, accepted submission:
N = int(input())
list_an = input().split()
list_an_int = [int(s) for s in list_an]

list_an_int.sort()
list_an_int.reverse()

Alice_counter = 0
Bob_counter = 0

counter = 0
for i in range(N):
    if counter % 2 == 0:
        Alice_counter += list_an_int[i]
    else:
        Bob_counter += list_an_int[i]
    counter += 1
print(Alice_counter - Bob_counter)
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
s = str(input())

win = 0
for i in s:
    if(i == "o"):
        win += 1
        
win += 15- len(s)

if(win >= 8):
    print("Yes")
else:
    print('No')

Fixed, accepted submission:
s = str(input())

win = 0
for i in s:
    if(i == "o"):
        win += 1
        
win += 15- len(s)

if(win >= 8):
    print("YES")
else:
    print('NO')
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n*(n-1)/2)

Fixed, accepted submission:
n = int(input())
print(n*(n+1)//2)
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = str(input())

M = 0
for n in range(1,N) :
    set1 = set([])
    set2 = set([])
    I = set([])
    for c in (S[:n]) :
        set1.add(c)
    for d in (S[n+1:]) :
        set2.add(d)
    I = set1 & set2
    if(len(I)>M) :
        M = len(I)
print(M)

Fixed, accepted submission:
N = int(input())
S = str(input())

M = 0
for n in range(1,N) :
    set1 = set([])
    set2 = set([])
    I = set([])
    for c in (S[:n]) :
        set1.add(c)
    for d in (S[n:]) :
        set2.add(d)
    I = set1 & set2
    if(len(I)>M) :
        M = len(I)
print(M)
Problem:
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.  All strings that can be obtained in this way can be evaluated as formulas.  Evaluate all possible formulas, and print the sum of the results.

Incorrect submission (verdict: Wrong Answer):
S = str(input())
l = list(map(str,(map(bin,range(2**(len(S)-1))))))
print(l)

ans = 0
for i in range(len(l)):
    ev = l[i][2:].zfill(len(S)-1)
    res = 0
    num_str = S[0]
    for j in range(1,len(S)):
        if(ev[j-1] == '0'):
            num_str = num_str + S[j]
        else:
            res += int(num_str)
            num_str = S[j]
    res += int(num_str)
    ans += res

print(ans)

Fixed, accepted submission:
S = str(input())
l = list(map(str,(map(bin,range(2**(len(S)-1))))))

ans = 0
for i in range(len(l)):
    ev = l[i][2:].zfill(len(S)-1)
    res = 0
    num_str = S[0]
    for j in range(1,len(S)):
        if(ev[j-1] == '0'):
            num_str = num_str + S[j]
        else:
            res += int(num_str)
            num_str = S[j]
    res += int(num_str)
    ans += res

print(ans)
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print((N**0.5//1)**2)

Fixed, accepted submission:
N = int(input())
print(int((N**0.5//1)**2))
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s=input()
s=s.replace("eraser","")
s=s.replace("erase","")
s=s.replace("dreamer","")
s=s.replace("dream","")
if len(s)==0:
    print("NO")
else:
    print("YES")

Fixed, accepted submission:
a=["eraser","erase","dreamer","dream"]
s=input()
 
for i in range(4):
    s=s.replace(a[i],"")
if s=="":
    print("YES")
else:
    print("NO")
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
s = (input())
sa = s.find("a")
sz = int(s.rfind("z"))
print(sz-sa+1)


Fixed, accepted submission:
s = (input())
sa = s.find("A")
sz = int(s.rfind("Z"))
print(sz-sa+1)
Problem:
ある過疎地域での話である． この地域ではカントリーロードと呼ばれるまっすぐな道に沿って， 家がまばらに建っている． 今までこの地域には電気が通っていなかったのだが， 今回政府からいくつかの発電機が与えられることになった． 発電機は好きなところに設置できるが， 家に電気が供給されるにはどれかの発電機に電線を介してつながっていなければならず， 電線には長さに比例するコストが発生する． 地域で唯一の技術系公務員であるあなたの仕事は， すべての家に電気が供給されるという条件の下で， できるだけ電線の長さの総計が短くなるような発電機 および電線の配置を求めることである． なお，発電機の容量は十分に大きいので， いくらでも多くの家に電気を供給することができるものとする．  サンプル入力の1番目のデータセットを図2に示す． この問題に対する最適な配置を与えるには， 図のように x = 20 と x = 80 の位置に発電機を配置し， それぞれ図中のグレーで示した位置に電線を引けばよい．     ---   図2: 発電機と電線の配置の例（入力例の最初のデータセット）．

Incorrect submission (verdict: Wrong Answer):

Fixed, accepted submission:
def cuntry(N,K,X):
    if N <= K:
        return 0
    XX=[]
    for a in range(1,N):
        XX.append(X[a]-X[a-1])
    XX.sort(reverse=True)
    del XX[0:K-1]
    return sum(XX)
n= int(input())  
for j in range(n):
    N, K = map(int,input().strip().split())
    X = list(map(int,input().strip().split()))
    if N==0:
        break;
    print(cuntry(N,K,X))
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
S = input()

f = 0
while(1):
    print(S)
    if len(S) <= 4:
        break
    if S[:5] == "dream":
        if len(S) == 5:
            f = 1
            break
        elif len(S) == 6:
            break
        if S[:7] == "dreamer":
            if len(S) == 7:
                f = 1
                break
            if S[7] != "a":
                S = S[7:]
                continue
            else:
                S = S[5:]
        else:
            S = S[5:]
    elif S[:5] == "erase":
        if len(S) == 5:
            f = 1
            break
        if S[:6] == "eraser":
            if len(S) == 6:
                f = 1
                break
            if S[6] != "a":
                S = S[7:]
                continue
            else:
                S = S[:5]
        else:
            S = S[5:]
    else:
        break

if f == 0:
    print("NO")
else:
    print("YES")


Fixed, accepted submission:
S = input()

f = 0
while(1):
    #print(S)
    if len(S) <= 4:
        break
    if S[:5] == "dream":
        if len(S) == 5:
            f = 1
            break
        elif len(S) == 6:
            break
        if S[:7] == "dreamer":
            if len(S) == 7:
                f = 1
                break
            if S[7] != "a":
                S = S[7:]
                continue
            else:
                S = S[5:]
        else:
            S = S[5:]
    elif S[:5] == "erase":
        if len(S) == 5:
            f = 1
            break
        if S[:6] == "eraser":
            if len(S) == 6:
                f = 1
                break
            if S[6] != "a":
                S = S[6:]
                continue
            else:
                S = S[:5]
        else:
            S = S[5:]
    else:
        break

if f == 0:
    print("NO")
else:
    print("YES")