TnT/CodeNet4Repair huggingface dataset:
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):

def invr():
    return(map(int, input().split()))


h, w = invr()

c = (int((h+1)/2)*w)
print(c)
if h % 2 != 0:
    c = c - (w-1)/2
print(int(c))


Fixed, accepted submission:

def invr():
    return(map(int, input().split()))


h, w = invr()

c = (int((h+1)/2)*w)
if h % 2 != 0:
    c = c - (w-1)/2
if h == 1 or w == 1:
    c = 1
print(int(c))
Problem:
There is an empty array. The following N operations will be performed to insert integers into the array. In the i-th operation (1≤i≤N), b_i copies of an integer a_i are inserted into the array. Find the K-th smallest integer in the array after the N operations. For example, the 4-th smallest integer in the array \\{1,2,2,3,3,3\\} is 3.

Incorrect submission (verdict: Wrong Answer):
n,k = map(int,input().split())
t = [[0,0] for i in range(n)]
for i in range(n):
    a,b = map(int,input().split())
kk = 0
t = sorted(t, key=lambda t:t[0])

for i in range(n):
    kk += t[i][1]
    if kk >= k:
        print(t[i][1])
        break

Fixed, accepted submission:
n,m = map(int,input().split())
lis = [list(map(int,input().split())) for i in range(n)]
cou = 0
lis.sort()
for i in range(n):
  cou += lis[i][1]
  if cou >= m:
    print(lis[i][0])
    exit()
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
l = (list)(map(int,input().split()))

l = sorted(l)
ans = 'NO'
if l[0]=='5' and l[1]=='5' and l[2]=='7':
  ans = 'YES'
print(ans)

Fixed, accepted submission:
l = (list)(map(int, input().split()))
l = sorted(l)

ans = 'NO'
if l[0] == 5 and l[1] == 5 and l[2] == 7:
    ans = 'YES'
print(ans)
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
n, a, b = [int(i) for i in input().split()]
border = a + b
foreign_pass = 0
passed = 0
s = input()
for x in s:
    if passed >= border:
        print('No')
        continue
    if x == 'a':
        print('Yes')
        passed += 1
    elif x == 'b' and foreign_pass < b:
        print('Yes')
        foreign_pass += 1
    else:
        print('No')

Fixed, accepted submission:
n, a, b = [int(i) for i in input().split()]
border = a + b
foreign_pass = 0
passed = 0
s = input()
for x in s:
    if passed >= border:
        print('No')
        continue
    if x == 'a':
        print('Yes')
        passed += 1
    elif x == 'b' and foreign_pass < b:
        print('Yes')
        passed += 1
        foreign_pass += 1
    else:
        print('No')
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = list(map(int, input().split()))
l.sort(reverse=True)
Alice = 0
for i in range(0, n, 2):
    print(i)
    Alice += l[i]
Bob = sum(l) - Alice
print(abs(Bob - Alice))


Fixed, accepted submission:
n = int(input())
l = list(map(int, input().split()))
l.sort(reverse=True)
Alice = 0
for i in range(0, n, 2):
    Alice += l[i]
Bob = sum(l) - Alice
print(abs(Bob - Alice))
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
s = list(input())
ans = []
for i in range(len(s)):
    if i%2==0:
        ans.append(s[i])
print(ans)

Fixed, accepted submission:
s = list(input())
ans = []
for i in range(len(s)):
    if i%2==0:
        ans.append(s[i])
print(''.join(ans))
Problem:
We have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \leq i \leq H, 1 \leq j \leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is `.`, and black if c_{i,j} is `#`.  Consider doing the following operation:    * Choose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.  You are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.

Incorrect submission (verdict: Wrong Answer):
h,w,k=map(int,input().split())
c=list()
for i in range(h):
  d=list(input())
  c.append(d)


num_h = 2**(h+1)
num_w = 2**(w+1)
result = 0
for i in range(num_h):
  for j in range(num_w):
    tmp = 0
    for row in range(h):
      for col in range(w):
        if (j >> row) & 1 == 0:
          if (i >> col) & 1 == 0:
            if c[row][col] == '#':
              tmp += 1
    if tmp == k:
      result += 1
print(result/4)

Fixed, accepted submission:
h,w,k=map(int,input().split())
c=list()
for i in range(h):
  d=list(input())
  c.append(d)


num_h = 2**h-1
num_w = 2**w-1
result = 0
for i in range(num_h):
  for j in range(num_w):
    tmp = 0
    for row in range(h):
      for col in range(w):
        if (i >> row) & 1 == 1:
          continue
        if (j >> col) & 1 == 1:
          continue
        if c[row][col] == '#':
          tmp += 1
    if tmp == k:
      result += 1

print(int(result))
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8

s = input()
s = s[-1]
t = ['maerd', 'remaerd', 'esare', 'resare']
flag = True
while s:
    for n in range(len(t)):
        if s[0:len(t[n])] == t[n]:
            s.lstrip(t[n])
            flag = True
        else:
            flag = False
    if not flag:
        break
if flag:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
# -*- coding: utf-8

s = input()
t = ["eraser", "erase", "dreamer", "dream"]
for n in range(4):
    s = s.replace(t[n], "")
if not s:
    print('YES')
else:
    print('NO')
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
d = [int(input()) for j in range(N)]

# d = [3,15,15]

d.sort(reverse=True)

current_mochi = 0
next_mochi = 0
counter = 0

for i,num in enumerate(d):
    next_mochi = num
    if i == 0:
        counter+=1
        current_mochi = num
    elif i + 1 == len(d):
        break
    elif current_mochi > next_mochi:
        counter+=1
        current_mochi = num

print(counter)

Fixed, accepted submission:
N = int(input())
d = [int(input()) for j in range(N)]

# d = [1,2]

d.sort(reverse=True)

current_mochi = 0
next_mochi = 0
counter = 0

for i,num in enumerate(d):
    next_mochi = num
    if i == 0:
        counter+=1
        current_mochi = num
    elif i + 1 == len(d):
        if current_mochi > next_mochi:
            counter+=1
            break
        else:
            break
    elif current_mochi > next_mochi:
        counter+=1
        current_mochi = num

print(counter)
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
S = input()
M = len(S)
N = set(S)
O = list(N)
P = len(O)
if M == P:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
S = input()
M = len(S)
N = set(S)
O = list(N)
P = len(O)
if M == P:
  print('yes')
else:
  print('no')
Problem:
Snuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.  They will share these cards. First, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards. Here, both Snuke and Raccoon have to take at least one card.  Let the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively. They would like to minimize |x-y|. Find the minimum possible value of |x-y|.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int, input().split()))

total = sum(a)
half = total / 2.0

base = 0
diff = half
for i in range(len(a)):
    base += a[i]
    diff_n = abs(base - half)
    if diff_n > diff:
        print(abs(sum(a[:i]) * 2 - total))
        break


Fixed, accepted submission:
N = int(input())
a = list(map(int, input().split()))

total = sum(a)

acc_sum = [0] * N
base = 0
for i in range(N):
    base += a[i]
    acc_sum[i] = base

diff = [abs(acc * 2 - total) for acc in acc_sum]
print(min(diff[:-1]))
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):
a,b,c,n=map(int,input().split())
q=0
for i in range(n//a+1):
  for j in range((n-a*i)//b+1):
    if(n-i*a+j*b)%c==0:q+=1
print(q)

Fixed, accepted submission:
a,b,c,n=map(int,input().split())
q=0
for i in range(n//a+1):
  for j in range((n-a*i)//b+1):
    t=n-i*a-j*b
    if t%c==0:
      q+=1
print(q)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
h,w=map(int,input().split())
x=[input() for _ in range(h)]
for i in x:
    print(i)
for i in x:
    print(i)

Fixed, accepted submission:
h,w=map(int,input().split())
x=[input() for _ in range(h)]
for i in x:
    print(i)
    print(i)
Problem:
Mammy decided to give Taro his first shopping experience. Mammy tells him to choose any two items he wants from those listed in the shopping catalogue, but Taro cannot decide which two, as all the items look attractive. Thus he plans to buy the pair of two items with the highest price sum, not exceeding the amount Mammy allows. As getting two of the same item is boring, he wants two different items.  You are asked to help Taro select the two items. The price list for all of the items is given. Among pairs of two items in the list, find the pair with the highest price sum not exceeding the allowed amount, and report the sum. Taro is buying two items, not one, nor three, nor more. Note that, two or more items in the list may be priced equally.

Incorrect submission (verdict: Wrong Answer):
import sys
while(True):
    items=[]
    max=0
    n, m = map(int, input().split())
    if (n == 0 & m == 0):exit()
    items = list(map(int, input().split()))
    for i in range(n):
        for j in range(n):
            sum = items[i] + items[j]
            if (i != j and sum < m and sum > max):
                max = sum
    if (max == 0):
        print("NONE")
    else:
        print(max)



Fixed, accepted submission:
import sys
while(True):
    items=[]
    max=0
    n, m = map(int, input().split())
    if (n == 0 & m == 0):exit()
    items = list(map(int, input().split()))
    for i in range(n):
        for j in range(n):
            sum = items[i] + items[j]
            if (i != j and sum <= m and sum > max):
                max = sum
    if (max == 0):
        print("NONE")
    else:
        print(max)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
A = list(map(int, input().split()))
A.sort()

print("Yes" if A == [5,5,7] else "No")

Fixed, accepted submission:
A = list(map(int, input().split()))
A.sort()

print("YES" if A == [5,5,7] else "NO")
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
A = list(map(int, input().split()))
A.sort()
if A[0] == 5 and A[1] == 5 and A[2] ==7:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
A = list(map(int, input().split()))
A.sort()
if A[0] == 5 and A[1] == 5 and A[2] ==7:
  print('YES')
else:
  print('NO')
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
print(math.ceil(eval(input().replace(" ", "+")) / 2) for math in [__import__("math")])


Fixed, accepted submission:
[print(math.ceil(eval(input().replace(" ", "+")) / 2)) for math in [__import__("math")]]
Problem:
We have N sticks with negligible thickness. The length of the i-th stick is A_i.  Snuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides. Find the maximum possible area of the rectangle.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = [int(a) for a in input().split(" ")]

A.sort(reverse=True)
l1 = 0
c1 = 0
l2 = 0
c2 = 0

L1 = 0
L2 = 0

for i in range(len(A)):
  print(" ".join([str(s) for s in [i, l1, c1, l2, c2, L1, L2]]))
  if L1 and L2:
    break
  elif L1:
    if l2 == A[i]:
      c2 += 1
    elif l2 != A[i]:
      l2 = A[i]
      c2 = 1
    if c2 == 2:
      L2 = l2
  else:
    if l1 == A[i]:
      c1 += 1
    elif l1 != A[i]:
      l1 = A[i]
      c1 = 1
    if c1 == 2:
      L1 = l1

print(L1 * L2)

Fixed, accepted submission:
N = int(input())
A = [int(a) for a in input().split(" ")]

A.sort(reverse=True)
l1 = 0
c1 = 0
l2 = 0
c2 = 0

L1 = 0
L2 = 0

for i in range(len(A)):
  if L1 and L2:
    break
  elif L1:
    if l2 == A[i]:
      c2 += 1
    elif l2 != A[i]:
      l2 = A[i]
      c2 = 1
    if c2 == 2:
      L2 = l2
  else:
    if l1 == A[i]:
      c1 += 1
    elif l1 != A[i]:
      l1 = A[i]
      c1 = 1
    if c1 == 2:
      L1 = l1

print(L1 * L2)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
#Cats and Dogs


A, B, X = map(int, input().split())


if ((X-A) <= B) and (A <= X):
	print("Yes")
else:
	print("No")


Fixed, accepted submission:
#Cats and Dogs


A, B, X = map(int, input().split())


if ((X-A) <= B) and (A <= X):
	print("YES")
else:
	print("NO")
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
n = input()

count = 0
if(n[0]=='1'):
  count+=1
elif(n[1]=='1'):
  count+=1
elif(n[2]=='1'):
  count+=1

print(count)

Fixed, accepted submission:
n = input()
 
count = 0
if(n[0]=='1'):
  count+=1
if(n[1]=='1'):
  count+=1
if(n[2]=='1'):
  count+=1
 
print(count)
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
A = list(input().split())
a = int(''.join(A))
if a%4==0:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
A = list(input().split())
a = int(''.join(A))
if a%4==0:
    print("YES")
else:
    print("NO")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
n=int(input());print(n*-~n/2)

Fixed, accepted submission:
n=int(input());print(n*-~n//2)
Problem:
0 から 9 の数字から異なる n 個の数を取り出して合計が s となる組み合わせの数を出力するプログラムを作成してください。n 個の数はおのおの 0 から 9 までとし、１つの組み合わせに同じ数字は使えません。たとえば、n が 3 で s が 6 のとき、3 個の数字の合計が 6 になる組み合わせは、      1 + 2 + 3 = 6   0 + 1 + 5 = 6   0 + 2 + 4 = 6      の 3 通りとなります。

Incorrect submission (verdict: Wrong Answer):
while 1:
 n,x=map(int,input().split())
 if n+x==0:break
 print(sum([max(0,(x-a-1)//2-max(a,x-a-1-n))for a in range(1,x//3)]))


Fixed, accepted submission:
import itertools
for e in iter(input,'0 0'):
 n,s=map(int,e.split())
 print(sum(s==sum(p)for p in itertools.combinations(range(10),n)))
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
n=input()
if n[0]==n[1] and n[1]==n[2]:
  print("Yes")
if n[1]==n[2] and n[3]==n[2]:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
n=input()
if n[0]==n[1]==n[2]:
  print("Yes")
elif n[1]==n[2]==n[3]:
  print("Yes")
else:
  print("No")
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter
n,k=map(int,input().split())
a=Counter(input().split())
ans=0
keys,counts=zip(*a.most_common())
for num,(key,count) in enumerate(zip(keys,counts)):
    if int(num)>k:ans+=count
print(ans)

Fixed, accepted submission:
from collections import Counter
n,k=map(int,input().split())
a=Counter(input().split())
print(sum(sorted(a.values(),reverse=True)[k:]))
Problem:
Snuke is making sugar water in a beaker. Initially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.    * Operation 1: Pour 100A grams of water into the beaker.   * Operation 2: Pour 100B grams of water into the beaker.   * Operation 3: Put C grams of sugar into the beaker.   * Operation 4: Put D grams of sugar into the beaker.  In our experimental environment, E grams of sugar can dissolve into 100 grams of water.  Snuke will make sugar water with the highest possible density.  The beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker. Find the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it. If there is more than one candidate, any of them will be accepted.  We remind you that the sugar water that contains a grams of water and b grams of sugar is \frac{100b}{a + b} percent. Also, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.

Incorrect submission (verdict: Wrong Answer):
a, b, c, d, e, f = map(int, input().split())

result = [0, 0]
noude = 0
for i in range(31):
    for j in range(31):
        for k in range(101):
            for l in range(101):
                water = a * 100 * i + b * 100 * j
                sugar = c * k + d * l
                if water == 0 or water + sugar > f:
                    break
                if (water / 100) * e >= sugar and noude < (100 * sugar) / (water + sugar):
                    noude = (100 * sugar) / (water + sugar)
                    result = [water + sugar, sugar]

print(result)


Fixed, accepted submission:
a, b, c, d, e, f = map(int, input().split())

result = [0, 0]
noude = 0
for i in range(31):
    for j in range(31):
        for k in range(101):
            for l in range(101):
                water = a * 100 * i + b * 100 * j
                sugar = c * k + d * l
                if water == 0 or water + sugar > f:
                    break
                if (water / 100) * e >= sugar and noude < (100 * sugar) / (water + sugar):
                    noude = (100 * sugar) / (water + sugar)
                    result = [water + sugar, sugar]

if result[1] == 0:
    print(a * 100, 0)
else:
    print(result[0], result[1])