TnT/CodeNet4Repair huggingface dataset:
Problem:
Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers.  She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of **distinct** positive integers is called **special** if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is **not** 1.  Nagase wants to find a **special** set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a **special** set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000.

Incorrect submission (verdict: Wrong Answer):
import fractions

def verify(seq):
    sm = sum(seq)
    print(all([fractions.gcd(2, sm-2) != 1 for s in seq]))

n = int(input())
cnt = 0
ans = []
for i in range(2, 30001):
    if cnt == n - 1:
        break
    if i % 2 == 0 or i % 3 == 0:
        ans.append(i)
        cnt += 1

sm = sum(ans)
for j in range(i, 30001):
    if ((sm + j) % (2*3)) == 0:
        if j % 2 == 0 or j % 3 == 0:
            ans.append(j)
            break
print(' '.join(map(str, ans)))


Fixed, accepted submission:
n = int(input())
cnt = 0
ans = []
if n == 3:
    print('2 5 63')
else:
    for i in range(2, 30001):
        if cnt == n - 2:
            break
        if i % 2 == 0 or i % 3 == 0 or i % 5 == 0:
            ans.append(i)
            cnt += 1

    sm = sum(ans)
    for j in range(i+1, 30001):
        for k in range(j+1, 30001):
            if (sm + j + k) % (2*3*5) == 0 and\
               (j % 2 == 0 or j % 3 == 0 or j % 5 == 0) and\
               (k % 2 == 0 or k % 3 == 0 or k % 5 == 0):
                ans.append(j)
                ans.append(k)
                break
        else:
            continue
        break
    print(' '.join(map(str, ans)))
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
n,a,b = tuple(map(int,input().split()))
s = list(input())

count = 0
foreign = 0
for s_i in s:
  if s_i=='a':
    if count<=a+b:
      count+=1
      print("Yes")
  elif s_i=='b':
    if count<=a+b and foreign <= b:
      count+=1
      foreign+=1
      print("Yes")
  else:
    print("No")

Fixed, accepted submission:
n,a,b = tuple(map(int,input().split()))

s = list(input())
rank = 0
brank = 0
for s_i in s:
  if s_i=='a':
    if rank==a+b:
      print("No")
      continue
    rank+=1
    print("Yes")
  elif s_i=='b':
    if rank==a+b:
      print("No")
      continue
    if brank==b:
      print("No")
      continue
    rank+=1
    brank+=1
    print("Yes")
  else:
    print("No")
Problem:
Given is a rooted tree with N vertices numbered 1 to N. The root is Vertex 1, and the i-th edge (1 \leq i \leq N - 1) connects Vertex a_i and b_i.  Each of the vertices has a counter installed. Initially, the counters on all the vertices have the value 0.  Now, the following Q operations will be performed:    * Operation j (1 \leq j \leq Q): Increment by x_j the counter on every vertex contained in the subtree rooted at Vertex p_j.  Find the value of the counter on each vertex after all operations.

Incorrect submission (verdict: Wrong Answer):
n,q = map(int,input().split())
bond = []
for i in range(n-1):
    a,b = map(int,input().split())
    a -= 1
    b -= 1
    if a > b:
        tmp = a
        a = b
        b = tmp
    bond.append((a,b))
bond.sort()
qry = []
for i in range(q):
    p,x = map(int,input().split())
    p -= 1
    qry.append((p,x))
parent = [[] for i in range(n)]
for i, ab in enumerate(bond):
    a,b = ab
    parent[a].append(b)

ans = [0] * n
for i, qx in enumerate(qry):
    q,x = qx
    ans[q] += x
a = ''
for i, son in enumerate(parent):
    a += str(ans[i]) + ' '
    for j, s in enumerate(son):
        ans[s] += ans[i]
print(a)


Fixed, accepted submission:
from collections import deque

n,q = map(int,input().split())
edge = [[] for i in range(n)]
for i in range(n-1):
    a,b = map(int,input().split())
    a -= 1
    b -= 1
    edge[a].append(b)
    edge[b].append(a)

ans = [0] * n
for i in range(q):
    p,x = map(int,input().split())
    p -= 1
    ans[p] += x


isVisited = [False] * n
dq = deque([0])
isVisited[0] = True
while len(dq) > 0:
    parent = dq.popleft()
    for j, son in enumerate(edge[parent]):
        if isVisited[son]:
            continue
        ans[son] += ans[parent]
        isVisited[son] = True
        dq.append(son)

print(' '.join(map(str, ans)))
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
N, K = map(int, input().split())
if (N + K - 1) // 2 >= K:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
N, K = map(int, input().split())
if (N + 1) // 2 >= K:
    print("YES")
else:
    print("NO")
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
import sys
input = sys.stdin.readline

n = int(input())
a = (input().split())
b = 1

while True:
    for i in range(n-1):

        if int(a[i]) % 2 == 1:
            break

        a[i] = int(a[i]) / 2
        b +=1


print(b)


Fixed, accepted submission:
import sys
input = sys.stdin.readline

n = int(input())
a = list(map(int,input().split()))
b = 0
c = 2
f = 0


while True:
    for i in a:
        if i % c > 0:
            f = f +1
            break
    if f == 1:
        break

    b = b + 1
    c = c * 2



print(b)
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Wrong Answer):

N,K = list(map(int, input().split()))
D = list(map(int, input().split()))

availbale_numbers = [0,1,2,3,4,5,6,7,8,9]

for i in D:
    availbale_numbers.remove(i)

print(availbale_numbers)
flg = False
for item1 in availbale_numbers:
    for item2 in availbale_numbers:
        for item3 in availbale_numbers:
            for item4 in availbale_numbers:
                if(N <= int(('').join([str(item1),str(item2),str(item3),str(item4)]))):
                    print(('').join([str(item1),str(item2),str(item3),str(item4)]))
                    exit()

Nmin = min(availbale_numbers)
print(f'{Nmin}{Nmin}{Nmin}{Nmin}{Nmin}')

Fixed, accepted submission:

N,K = list(map(int, input().split()))
D = list(map(int, input().split()))

availbale_numbers = [0,1,2,3,4,5,6,7,8,9]

for i in D:
    availbale_numbers.remove(i)

for i in range(N,99999):
    if(set(str(i)) <= set([str(a) for a in availbale_numbers])):
        print(i)
        break
Problem:
Mr. Takahashi has a string s consisting of lowercase English letters. He repeats the following operation on s exactly K times.    * Choose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of `z` is `a`.  For example, if you perform an operation for the second letter on `aaz`, `aaz` becomes `abz`. If you then perform an operation for the third letter on `abz`, `abz` becomes `aba`.  Mr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s. Find the such string.

Incorrect submission (verdict: Wrong Answer):

str = input()
K = int(input())
tempK = K
result = ""
for i in range(len(str)):
	changeNum = 122-ord(str[i])+1
	if (changeNum <= tempK):
		result += "a"
		tempK -= changeNum
	else:
		result += str[i]
print(result)
if (tempK != 0):
	result = result[:-1] + chr(ord(str[-1]) + tempK)
print(result)


Fixed, accepted submission:

str = input()
K = int(input())
tempK = K
result = ""
for i in range(len(str)-1):
	changeNum = 122-ord(str[i])+1
	if (changeNum <= tempK and str[i] != "a"):
		result += "a"
		tempK -= changeNum
	else:
		result += str[i]
tempK %= 26
if (tempK > 0):
	changeNum = ord(str[-1]) + tempK
	if (changeNum > 122):
		changeNum = changeNum -122 + 97 -1
	else:
		changeNum = changeNum
	result += chr(changeNum)
else:
	result += str[-1]
print(result)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().strip().split())
if all([s % 3 == 0 for s in [a, b, a + b]]):
    print('Possible')
else:
    print('Impossible')


Fixed, accepted submission:
a, b = map(int, input().strip().split())
if any([s % 3 == 0 for s in [a, b, a + b]]):
    print('Possible')
else:
    print('Impossible')
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a,b=(int(x) for x in input().split())

if a*b%2 == 0:
    print("even")
else:
    print("odd")
    


Fixed, accepted submission:
a,b=(int(x) for x in input().split())

if a*b%2 == 0:
    print("Even")
else:
    print("Odd")
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
import math
a, b = map(int, input().split())
print(math.ceil(a+b))

Fixed, accepted submission:
import math
a, b = map(int, input().split())
print(math.ceil((a + b) / 2))
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())

cnt = 0
if a <= b :
	while(cnt <= a):
  		print(cnt+1)
  		cnt = cnt+1
        
else :
	while(cnt < a):
  		print(cnt+1)
  		cnt = cnt+1

Fixed, accepted submission:
a,b = map(int,input().split())

if a <= b :
	print(a)
    
else :
	print(a-1)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int, input().split()))
b = sorted(a)[:: -1]
print(sum(b[:: 2]) - sum(b[1:: 2]))

Fixed, accepted submission:
N, A = eval("int(input())," * 2)
if N % 500 <= A:
	print("Yes")
else:
	print("No")
Problem:
Snuke has one biscuit and zero Japanese yen (the currency) in his pocket. He will perform the following operations exactly K times in total, in the order he likes:    * Hit his pocket, which magically increases the number of biscuits by one.   * Exchange A biscuits to 1 yen.   * Exchange 1 yen to B biscuits.  Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Incorrect submission (verdict: Wrong Answer):
k,a,b=map(int,input().split())
n=1
if b-a<=2:
    print(k+1)

else:
    if n < a:
        n = a
        k = k-a
    m = k // 2
    print(n,m,b-a)
    n += (b-a)*m
    if k % 2 ==1:
        n+=1
    print(n)


Fixed, accepted submission:
k,a,b=map(int,input().split())
n=1
if b-a<=2:
    n += k
    print(n)

elif k<a-1:
    n += k
    print(n)

else: #b-a>2 k-(a-1)>=0
    
    n = a
    k -= a-1  #>0
    m = k // 2
    n += (b-a)*m
    if k - 2*m ==1:
        n+=1
    print(n)
Problem:
You are given a string S.  Takahashi can insert the character `A` at any position in this string any number of times.  Can he change S into `AKIHABARA`?

Incorrect submission (verdict: Wrong Answer):
import re
akb_re = re.compile(r'A?KIHA?BA?RA?$')

s = input()
mo = akb_re.match(s)
if mo == None:
  print('No')
else:
  print('Yes')


Fixed, accepted submission:
import re
akb_re = re.compile(r'A?KIHA?BA?RA?$')

s = input()
mo = akb_re.match(s)
if mo == None:
  print('NO')
else:
  print('YES')
Problem:
There are N dishes of cuisine placed in front of Takahashi and Aoki. For convenience, we call these dishes Dish 1, Dish 2, ..., Dish N.  When Takahashi eats Dish i, he earns A_i points of _happiness_ ; when Aoki eats Dish i, she earns B_i points of happiness.  Starting from Takahashi, they alternately choose one dish and eat it, until there is no more dish to eat. Here, both of them choose dishes so that the following value is maximized: "the sum of the happiness he/she will earn in the end" minus "the sum of the happiness the other person will earn in the end".  Find the value: "the sum of the happiness Takahashi earns in the end" minus "the sum of the happiness Aoki earns in the end".

Incorrect submission (verdict: Wrong Answer):
N = int(input())
l = []
for i in range(N):
    l.append(list(map(int, input().split())))
    l[i] += [i]
lA = sorted(l, key=lambda x: (x[0], -x[1]))
lB = sorted(l, key=lambda x: (-x[1]))
A = B = 0
while lA or lB:
    #A
    if i % 2 == 0:
        tmp = lA.pop(0)
        A += tmp[0]
        lB.remove(tmp)
    #B
    else:
        tmp = lB.pop(0)
        B += tmp[1]
        lA.remove(tmp)
    i += 1
print(A-B)

Fixed, accepted submission:
N = int(input())
l = []
sumB = 0
for i in range(N):
    a, b = map(int, input().split())
    l.append(a + b)
    sumB += b
l.sort(reverse=True)
A = 0
for i in range(0, N, 2):
        A += l[i]
print(A - sumB)
Problem:
Write a program which reads an integer _n_ and draws a Koch curve based on recursive calles of depth _n_.  The Koch curve is well known as a kind of   You should start (0, 0), (100, 0) as the first segment.

Incorrect submission (verdict: Wrong Answer):
from math import sin, cos, pi
def koch(px, py, qx, qy, n):
    if n == 0:
        return True
    sx = (2 * px + qx) / 3
    sy = (2 * py + qy) / 3
    tx = (px + 2 * qx) / 3
    ty = (py + 2 * qy) / 3
    ux = sx + (tx - sx) * cos(pi / 3) - (ty - sy) * sin(pi / 3)
    uy = sy + (tx - sx) * sin(pi / 3) - (ty - sy) * cos(pi / 3)
    koch(px, py, sx, sy, n - 1)
    print("{:.8f} {:.8f}".format(sx, sy))
    koch(sx, sy, ux, uy, n - 1)
    print("{:.8f} {:.8f}".format(ux, uy))
    koch(ux, uy, tx, ty, n - 1)
    print("{:.8f} {:.8f}".format(tx, ty))
    koch(tx, ty, qx, qy, n - 1)
print("{:.8f} {:.8f}".format(0, 0))
koch(0, 0, 100, 0, 2)
print("{:.8f} {:.8f}".format(100, 0))

Fixed, accepted submission:
from math import sin, cos, pi
def koch(px, py, qx, qy, n):
    if n == 0:
        return True
    sx = (2 * px + qx) / 3
    sy = (2 * py + qy) / 3
    tx = (px + 2 * qx) / 3
    ty = (py + 2 * qy) / 3
    ux = sx + (tx - sx) * cos(pi / 3) - (ty - sy) * sin(pi / 3)
    uy = sy + (tx - sx) * sin(pi / 3) + (ty - sy) * cos(pi / 3)
    koch(px, py, sx, sy, n - 1)
    print("{:.8f} {:.8f}".format(sx, sy))
    koch(sx, sy, ux, uy, n - 1)
    print("{:.8f} {:.8f}".format(ux, uy))
    koch(ux, uy, tx, ty, n - 1)
    print("{:.8f} {:.8f}".format(tx, ty))
    koch(tx, ty, qx, qy, n - 1)
n = int(input())
print("{:.8f} {:.8f}".format(0, 0))
koch(0, 0, 100, 0, n)
print("{:.8f} {:.8f}".format(100, 0))
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
L = list(map(int, input().split()))
L.sort()
if L[0] == 5 and L[1]==5 and L[2]==7:
    print("Yes");
else:
    print("No");

Fixed, accepted submission:
L = list(map(int, input().split()))
L.sort()
if L[0] == 5 and L[1]==5 and L[2]==7:
    print("YES");
else:
    print("NO");
Problem:
Taro is going to play a card game. However, now he has only n cards, even though there should be 52 cards (he has no Jokers).  The 52 cards include 13 ranks of each of the four suits: spade, heart, club and diamond.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
cards = []
for i in range(N):
    line = input().split()
    a = line[0]
    num = int(line[1])
    cards.append((a, num))
tarinai_list = []
for a in ['S', 'H', 'C', 'D']:
    for num in range(1, 14):
        for card in cards:
            if a == card[0] and num == card[1]:
                break
        tarinai_list.append((a, num))
for l in tarinai_list:
    print(' '.join(map(str, l)))


Fixed, accepted submission:
suits = ['S', 'H', 'C', 'D']
table = [[False] * 14 for i in range(4)]

N = int(input())
for _i in range(N):
    mark, num = input().split()
    num = int(num)

    if mark == 'S':
        table[0][num] = True
    if mark == 'H':
        table[1][num] = True
    if mark == 'C':
        table[2][num] = True
    if mark == 'D':
        table[3][num] = True

for i in range(4):
    for j in range(1, 14):
        if not table[i][j]:
            print(f'{suits[i]} {j}')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = 0
b = 0
c = 0
d = 0
for i in range(n):
    s = str(input())
    if s == 'AC' :
        a += 1
    elif s == 'WA':
        b += 1
    elif s == 'TLE':
        c += 1
    else:
        d += 1
print('AC × {}'.format(a))
print('WA × {}'.format(b))
print('TLE × {}'.format(c))
print('RE × {}'.format(d))

Fixed, accepted submission:
n = int(input())
a = 0
b = 0
c = 0
d = 0
for i in range(n):
    s = str(input())
    if s == 'AC' :
        a += 1
    elif s == 'WA':
        b += 1
    elif s == 'TLE':
        c += 1
    else:
        d += 1
print('AC x {}'.format(a))
print('WA x {}'.format(b))
print('TLE x {}'.format(c))
print('RE x {}'.format(d))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
def input_int():
    return map(int, input().split())

def one_int():
    return int(input())

def one_str():
    return input()

def many_int():
    return list(map(int, input().split()))

a=one_int()

print(a%1000)

Fixed, accepted submission:
def input_int():
    return map(int, input().split())

def one_int():
    return int(input())

def one_str():
    return input()

def many_int():
    return list(map(int, input().split()))

a=one_int()

if a%1000>0:
    print(1000-a%1000)
else:
    print(0)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
if a+b+c==17:
  if a==7 or b==7 or c==7:
    print("YES")
print("NO")

Fixed, accepted submission:
a,b,c=map(int,input().split())
 
if a+b+c==17:
  if a==5 and b==5:
    print("YES")
  elif a==5 and c==5:
    print("YES")  
  elif b==5 and c==5:
    print("YES") 
  else:
  	print("NO")
else:
	print("NO")
Problem:
Niwango-kun is an employee of Dwango Co., Ltd.   One day, he is asked to generate a thumbnail from a video a user submitted.   To generate a thumbnail, he needs to select a frame of the video according to the following procedure:    * Get an integer N and N integers a_0, a_1, ..., a_{N-1} as inputs. N denotes the number of the frames of the video, and each a_i denotes the representation of the i-th frame of the video.   * Select t-th frame whose representation a_t is nearest to the average of all frame representations.   * If there are multiple such frames, select the frame with the smallest index.  Find the index t of the frame he should select to generate a thumbnail.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int,input().split()))

sum = 0

for i in a:
  sum += i
  
avg = sum/N
result = 0
tmp = 0

for i in range(len(a)):
  ans = avg - a[i]
  ans = ans if ans < 0 else ans * -1
  if i == 0:
    result = i
    tmp = ans
  elif tmp > ans:
    result = i

print(result)

Fixed, accepted submission:
N = int(input())
a = list(map(int,input().split()))

sum = sum(a)
avg = sum/N

result = 0
tmp = 0

for i in range(len(a)):
  ans = avg - a[i]
  ans = ans if ans > 0 else ans * -1
  if i == 0:
    result = i
    tmp = ans
  elif tmp > ans:
    result = i
    tmp = ans

print(result)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,k = map(int,input().split())
A=[]
for i in range(a,min(a+k+1,b+1)):
    A.append(i)
for j in range(b,max(b-k,a),-1):
    A.append(j)
A.sort(reverse=False)
B=list(set(A))
for p in range(len(B)):
    print(B[p])

Fixed, accepted submission:
a,b,k = map(int,input().split())
A=[]
B=[]
for i in range(a,min(a+k,b+1)):
    A.append(i)
for j in range(b,max(b-k,a-1),-1):
    A.append(j)
B=list(set(A))
B.sort(reverse=False)
for p in range(len(B)):
    print(B[p])
Problem:
You are given an integer sequence of length n, a_1, ..., a_n. Let us consider performing the following n operations on an empty sequence b.  The i-th operation is as follows:    1. Append a_i to the end of b.   2. Reverse the order of the elements in b.  Find the sequence b obtained after these n operations.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = list(map(int,input().split()))
ans = []
for i in l:
  ans.append(i)
  ans = ans[::-1]
print(ans)

Fixed, accepted submission:
n = int(input())
l = list(map(int,input().split()))
if n % 2 == 0:
    ans = [l[i] for i in range(n-1,-1,-2)] + [l[i] for i in range(0,n-1,2)]
    print(*ans)
else:
    ans = [l[i] for i in range(n-1,-1,-2)] + [l[i] for i in range(1,n-1,2)]
    print(*ans)