TnT/CodeNet4Repair huggingface dataset:
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a, b = (int(i) for i in input().split()) 
if(a > b):
  print(a-1)
elif(a < b):
  print(a)

Fixed, accepted submission:
a, b = (int(i) for i in input().split()) 
if(a > b):
  print(a-1)
elif(a <= b):
  print(a)
Problem:
You are given two positive integers A and B. Compare the magnitudes of these numbers.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

A = int(input())
B = int(input())

if A > B:
    print('GRATER')
elif B > A:
    print('LESS')
else:
    print('EQUAL')


Fixed, accepted submission:
# -*- coding: utf-8 -*-

A = int(input())
B = int(input())

if A > B:
    print('GREATER')
elif B > A:
    print('LESS')
else:
    print('EQUAL')
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
n=input()
op_cnt=len(n)-1
for i in range(2**op_cnt):
    s=n[0]
    for j in range(op_cnt):
        if ((i<<j)&1):
            s+="+"
        else:
            s+="-"
        s+=n[j+1]
    if eval(s)==7:
        print(s+"=7")
        exit()


Fixed, accepted submission:
n=input()
op_cnt=len(n)-1
for i in range(2**op_cnt):
    s=n[0]
    for j in range(op_cnt):
        if ((i>>j)&1):
            s+="+"
        else:
            s+="-"
        s+=n[j+1]
    if eval(s)==7:
        print(s+"=7")
        exit()
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
b1= float(input())
b2 = float(100)
for i in range (1,100000000):
    b2 =int( b2 * 1.01)
    if b2 <= b1 :
       continue
    else : break
print(i)


Fixed, accepted submission:
b1= float(input())
b2 = float(100)
for i in range (1,10**18):
    b2 =int( b2 * 1.01)
    if b2 < b1 :
       continue
    else : break
print(i)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = input()
li = list(map(int,input().split()))
x = 0

print(N)
print(li)

while all(a%2 == 0 for a in li):
    li = [a/2 for a in li]
    x += 1
print(x)


Fixed, accepted submission:
N = input()
li = list(map(int,input().split()))
x = 0
while all(a%2 == 0 for a in li):
    li = [a/2 for a in li]
    x += 1
print(x)
Problem:
There are three houses on a number line: House 1, 2 and 3, with coordinates A, B and C, respectively. Print `Yes` if we pass the coordinate of House 3 on the straight way from House 1 to House 2 without making a detour, and print `No` otherwise.

Incorrect submission (verdict: Wrong Answer):
def main():
    A,B,C = [int(x) for x in input().split()]
    if A < C < B:
        print('yes')
    elif B < C < A:
        print('yes')
    else:
        print('no')

if __name__ == "__main__":
    main()
    

Fixed, accepted submission:
def main():
    A,B,C = [int(x) for x in input().split()]
    if A < C < B:
        print('Yes')
    elif B < C < A:
        print('Yes')
    else:
        print('No')

if __name__ == "__main__":
    main()
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())

Answer = (N*(N+1)/2)

print(Answer)

Fixed, accepted submission:
N = int(input())

Answer = N * (N + 1) // 2
print(Answer)
Problem:
We held two competitions: Coding Contest and Robot Maneuver.  In each competition, the contestants taking the 3-rd, 2-nd, and 1-st places receive 100000, 200000, and 300000 yen (the currency of Japan), respectively. Furthermore, a contestant taking the first place in both competitions receives an additional 400000 yen.  DISCO-Kun took the X-th place in Coding Contest and the Y-th place in Robot Maneuver. Find the total amount of money he earned.

Incorrect submission (verdict: Wrong Answer):
X, Y = map(int,input().split())

ans = max(X-4,0)* 100000 + max(Y-4,0)* 100000
if X == Y == 1:
  ans += 400000
print(ans)

Fixed, accepted submission:

X, Y = map(int,input().split())

ans = max(4-X,0)* 100000 + max(4-Y,0)* 100000
if (X == Y) *  (Y== 1):
  ans += 400000
print(ans)
Problem:
How many multiples of d are there among the integers between L and R (inclusive)?

Incorrect submission (verdict: Wrong Answer):
l,r,d=map(int, input().split()) #a1 a2 a3

ans=0
s=d
while s<=r:
  ans+=1
  s+=d
print(ans)

Fixed, accepted submission:
l,r,d=map(int, input().split()) #a1 a2 a3

ans=0
for i in range(l,r+1):
  if i%d==0:
    ans+=1
print(ans)
Problem:
We have a sequence of length N, a = (a_1, a_2, ..., a_N). Each a_i is a positive integer.  Snuke's objective is to permute the element in a so that the following condition is satisfied:    * For each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.  Determine whether Snuke can achieve his objective.

Incorrect submission (verdict: Wrong Answer):
import sys, os, math, bisect, itertools, collections, heapq, queue
# from scipy.sparse.csgraph import csgraph_from_dense, floyd_warshall
from decimal import Decimal
from collections import defaultdict, deque

sys.setrecursionlimit(10000000)

ii = lambda: int(sys.stdin.buffer.readline().rstrip())
il = lambda: list(map(int, sys.stdin.buffer.readline().split()))
fl = lambda: list(map(float, sys.stdin.buffer.readline().split()))
iln = lambda n: [int(sys.stdin.buffer.readline().rstrip()) for _ in range(n)]

iss = lambda: sys.stdin.buffer.readline().decode().rstrip()
sl = lambda: list(map(str, sys.stdin.buffer.readline().decode().split()))
isn = lambda n: [sys.stdin.buffer.readline().decode().rstrip() for _ in range(n)]

lcm = lambda x, y: (x * y) // math.gcd(x, y)

MOD = 10 ** 9 + 7
MAX = float('inf')


def main():
    if os.getenv("LOCAL"):
        sys.stdin = open("input.txt", "r")

    N = ii()
    A = il()

    cnt = 0
    for a in A:
        if a % 4 == 0:
            cnt += 1
        elif a % 2 == 0:
            cnt += .5
    print('YES' if N // 2 <= int(cnt) else 'NO')


if __name__ == '__main__':
    main()


Fixed, accepted submission:
import sys, os, math, bisect, itertools, collections, heapq, queue
# from scipy.sparse.csgraph import csgraph_from_dense, floyd_warshall
from decimal import Decimal
from collections import defaultdict, deque

sys.setrecursionlimit(10000000)

ii = lambda: int(sys.stdin.buffer.readline().rstrip())
il = lambda: list(map(int, sys.stdin.buffer.readline().split()))
fl = lambda: list(map(float, sys.stdin.buffer.readline().split()))
iln = lambda n: [int(sys.stdin.buffer.readline().rstrip()) for _ in range(n)]

iss = lambda: sys.stdin.buffer.readline().decode().rstrip()
sl = lambda: list(map(str, sys.stdin.buffer.readline().decode().split()))
isn = lambda n: [sys.stdin.buffer.readline().decode().rstrip() for _ in range(n)]

lcm = lambda x, y: (x * y) // math.gcd(x, y)

MOD = 10 ** 9 + 7
MAX = float('inf')


def main():
    if os.getenv("LOCAL"):
        sys.stdin = open("input.txt", "r")

    N = ii()
    A = il()

    cnt = 0
    for a in A:
        if a % 4 == 0:
            cnt += 1
        elif a % 2 == 0:
            cnt += .5
    print('Yes' if N // 2 <= int(cnt) else 'No')


if __name__ == '__main__':
    main()
Problem:
Takahashi is organizing a party.  At the party, each guest will receive one or more snack pieces.  Takahashi predicts that the number of guests at this party will be A or B.  Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.  We assume that a piece cannot be divided and distributed to multiple guests.

Incorrect submission (verdict: Wrong Answer):
def gcd(a, b):
  if a == 0: return b
  if b == 0: return a
  if a == b: return a
  if a > b: return gcd(b, a%b)
  return gcd(a, b%a)
def lcm(a, b):
  if a == b == 0:
  	return abs(a*b)/gcd(a, b)
  return 0
a, b = map(int, input().split())
print(lcm(a, b))

Fixed, accepted submission:
def gcd(a, b):
    if a == 0: return b
    if b == 0: return a
    if a == b: return a
    if a > b: return gcd(b, a%b)
    return gcd(a, b%a)
def lcm(a, b):
    if a == b == 0:
        return 0
    return abs(a*b)/gcd(a, b)
a, b = map(int, input().split())
print(int(lcm(a, b)))
Problem:
Mountaineers Mr. Takahashi and Mr. Aoki recently trekked across a certain famous mountain range. The mountain range consists of N mountains, extending from west to east in a straight line as Mt. 1, Mt. 2, ..., Mt. N. Mr. Takahashi traversed the range from the west and Mr. Aoki from the east.  The height of Mt. i is h_i, but they have forgotten the value of each h_i. Instead, for each i (1 ≤ i ≤ N), they recorded the maximum height of the mountains climbed up to the time they reached the peak of Mt. i (including Mt. i). Mr. Takahashi's record is T_i and Mr. Aoki's record is A_i.  We know that the height of each mountain h_i is a positive integer. Compute the number of the possible sequences of the mountains' heights, modulo 10^9 + 7.  Note that the records may be incorrect and thus there may be no possible sequence of the mountains' heights. In such a case, output 0.

Incorrect submission (verdict: Wrong Answer):
import sys
n = int(input())
t = list(map(int, input().split(' ')))
a = list(map(int, input().split(' ')))
a.append(a[-1])
for i in range(1, n):
    print(t[i], a[i])
    if t[i] > t[i-1]:
        if t[i] <= a[i]:
            a[i] = 1
            continue
        else:
            print(0)
            sys.exit()
    elif a[i] > a[i+1]:
        if t[i] >= a[i]:
            a[i] = 1
            continue
        else:
            print(0)
            sys.exit()

result = []
for i in range(n):
    result.append(min(t[i], a[i]))
counter = 1
for i in range(1, n-1):
    counter *= result[i]
print(counter%(10**9+7))

Fixed, accepted submission:
n = int(input())
t = list(map(int, input().split(' ')))
a = list(map(int, input().split(' ')))
result = 1
for i in range(n):
    h_max, h_min = min(t[i], a[i])+1, 1
    if i != 0:
        if t[i-1] < t[i]:
            h_min = t[i]
    else:
        h_min = t[0]

    if i != n-1:
        if a[i] > a[i+1]:
            h_min = max(a[i], h_min)
    else:
        h_min = max(a[i], h_min)
    result = result * max(h_max - h_min, 0) % (10**9+7)
print(result)
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())
print((a+b)*h/2)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())

print(int((a+b)*h/2))
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
i = 1
while True:
    x = int(input())
    if x:
        print('Case {:d}: {:d}'.format(i, x))
    else:
        break

Fixed, accepted submission:
x = input()
i = 1
while x != '0':
    print('Case {0}: {1}'.format(i, x))
    x = input()
    i += 1
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
print('NYoe s'[sorted(input())<list(input())::2])

Fixed, accepted submission:
s=lambda:sorted(input());print('NYoe s'[s()<s()[::-1]::2])
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
a,b,c=[int(1) for i in input().split()]
list=[a,b,c]
list.sort()
print(list[0]+list[1])

Fixed, accepted submission:
a,b,c=[int(i) for i in input().split()]
list=[a,b,c]
list.sort()
print(list[0]+list[1])
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = n % 1000
print(ans)


Fixed, accepted submission:
n = int(input())
ans = 1000 - n % 1000
ans %= 1000
print(ans)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
x = int(input())
ans = 0
while x%2==0:
  x /=2
  ans += 1
print(ans)

Fixed, accepted submission:
x = int(input())


if x >= 64:
    print(64)
elif x >= 32:
    print(32)
elif x >= 16:
    print(16)
elif x >= 8:
    print(8)
elif x >= 4:
    print(4)
elif x >= 2:
    print(2)
else:
    print(1)
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
from scipy.sparse import csr_matrix
from scipy.sparse.csgraph import shortest_path

def get_path(start, goal, pred):
    return get_path_row(start, goal, pred[start])

def get_path_row(start, goal, pred_row):
    path = []
    i = goal
    while i != start and i >= 0:
        path.append(i)
        i = pred_row[i]
    if i < 0:
        return []
    path.append(i)
    return path[::-1]

n, m = map(int, input().split())
data = []
row = []
col = []
for _ in range(m):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    data.append(1)
    row.append(a)
    col.append(b)
    data.append(1)
    row.append(b)
    col.append(a)
graph = csr_matrix((data, (row, col)), shape=(n, n))
_, p = shortest_path(graph, return_predecessors=True, directed=False, unweighted=True, indices=0)
for item in p[1:]:
    if(item < 0):
        print("No")
        exit()
for item in p[1:]:
    print(item + 1)


Fixed, accepted submission:
from heapq import heappush, heappop

n, m = map(int, input().split())
edges = [[] for _ in range(n)]
for _ in range(m):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    edges[a].append((1, b))
    edges[b].append((1, a))

INF = 10 ** 9
dist = [INF] * n
prev = [-1] * n
def dijkstra(s):
    q = [(0, s)]
    dist[s] = 0
    while q:
        v = heappop(q)[1]
        for cost, to in edges[v]:
            if dist[v] + cost < dist[to]:
                dist[to] = dist[v] + cost
                prev[to] = v
                heappush(q, (dist[to], to))

dijkstra(0)
print("Yes")
for i in range(1, n):
    print(prev[i] + 1)
Problem:
An _X -layered kagami mochi_ (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.  Lunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
an = []
cnt = 0

for i in range(n):
  an.append(int(input()))
  
sorted_an = sorted(an, reverse=True)

for i in range(len(sorted_an)-1):
  if i == 0:
    cnt += 1
  else:
    if sorted_an[i] > sorted_an[i+1]:
      cnt += 1

print(cnt)

Fixed, accepted submission:
n = int(input())
an = []
cnt = 1

for i in range(n):
  an.append(int(input()))
  
sorted_an = sorted(an, reverse=True)

for i in range(len(sorted_an)-1):
  if sorted_an[i] > sorted_an[i+1]:
    cnt += 1

print(cnt)
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())

a_b = a+b
a_c = a+c
b_c = b+c

print(max(a_b,a_c,b_c))


Fixed, accepted submission:
a,b,c = map(int, input().split())

a_b = a+b
a_c = a+c
b_c = b+c

print(min(a_b,a_c,b_c))
Problem:
Write a program which reads two integers a and b, and calculates the following values:    * a ÷ b: d (in integer)   * remainder of a ÷ b: r (in integer)   * a ÷ b: f (in real number)

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
d = a // b
r = a % b
f = float(a / b)
print("{} {} {}".format(d,r,f))

Fixed, accepted submission:
a,b = map(int,input().split())
d = a // b
r = a % b
f = a / b
print("{} {} {:.5f}".format(d,r,f))
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
s = str(input())

n = len(s) - 1

for i in range(1 << n):
    f = ""
    f += s[0]

    for j in range(n):

        if 1 & (i >> j):

            f += "+"
            f += s[j + 1]
        else :

            f += "-"
            f += s[j + 1]

    print(eval(f))


Fixed, accepted submission:
s = str(input())

n = len(s) - 1

for i in range(1 << n):
    f = ""
    f += s[0]

    for j in range(n):

        if 1 & (i >> j):

            f += "+"
            f += s[j + 1]
        else :

            f += "-"
            f += s[j + 1]

    if eval(f) == 7:
        print(f + "=7")
        break
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
X = int(input())



syozikin = 100
ans = 0

while syozikin <= X:
    syozikin = syozikin*1.01
    syozikin =syozikin  // 1
    ans = ans + 1
print(ans)



Fixed, accepted submission:
X = int(input())



syozikin = 100
ans = 0

while syozikin < X:
    syozikin = syozikin*1.01
    syozikin =syozikin  // 1
    ans = ans + 1
print(ans)
Problem:
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.  Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())
a = [str(input()) for i in range(H)]
sharp = str("#"*(W+2))

Lists = []
Lists.append([sharp])
for i in range(H):
    Lists.append(["#" + a[0] +"#"])

Lists.append([sharp])

for List in Lists:
    print(*List)


Fixed, accepted submission:
H, W = map(int, input().split())
a = [str(input()) for i in range(H)]
sharp = str("#"*(W+2))

Lists = []
Lists.append([sharp])
for i in range(H):
    Lists.append(["#" + a[i] +"#"])

Lists.append([sharp])

for List in Lists:
    print(*List)
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

N, K = map(int, input().split())
A = list(map(int, input().split()))

A.sort()
num = len(list(set(A)))
c = [0] * A[-1]
for a in A:
    c[a - 1] += 1
c.sort()
ans = 0
if num > K:
    for i in range(num - K):
        ans += c[i]

print(ans)


Fixed, accepted submission:
# -*- coding: utf-8 -*-

N, K = map(int, input().split())
A = list(map(int, input().split()))

A.sort()
num = len(list(set(A)))
c = [0] * A[-1]
for a in A:
    c[a - 1] += 1
c.sort()
ans = 0
if num > K:
    i = 0
    diff = 0
    while diff != num - K:
        if c[i] != 0:
            ans += c[i]
            i += 1
            diff += 1
        else:
            i += 1

print(ans)