TnT/CodeNet4Repair huggingface dataset:
Problem:
Taro's summer vacation starts tomorrow, and he has decided to make plans for it now.  The vacation consists of N days. For each i (1 \leq i \leq N), Taro will choose one of the following activities and do it on the i-th day:    * A: Swim in the sea. Gain a_i points of happiness.   * B: Catch bugs in the mountains. Gain b_i points of happiness.   * C: Do homework at home. Gain c_i points of happiness.  As Taro gets bored easily, he cannot do the same activities for two or more consecutive days.  Find the maximum possible total points of happiness that Taro gains.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
l=[list(map(int,input().split())) for i in range(n)]
dp=[[0,0,0] for _ in range(n)]
dp[0]=l[0]
for i in  range(1,n):
    dp[i][0]=l[i][0]+max(dp[i-1][1],dp[i-1][2])
    dp[i][1]=l[i][1]+max(dp[i-1][0],dp[i-1][2])
    dp[i][2]=l[i][2]+max(dp[i-1][0],dp[i-1][1])
    print(dp)
print(max(dp[-1]))

Fixed, accepted submission:
n=int(input())
l=[list(map(int,input().split())) for i in range(n)]
dp=[[0,0,0] for _ in range(n)]
dp[0]=l[0]
for i in  range(1,n):
    dp[i][0]=l[i][0]+max(dp[i-1][1],dp[i-1][2])
    dp[i][1]=l[i][1]+max(dp[i-1][0],dp[i-1][2])
    dp[i][2]=l[i][2]+max(dp[i-1][0],dp[i-1][1])

print(max(dp[-1]))
Problem:
Takahashi is organizing a party.  At the party, each guest will receive one or more snack pieces.  Takahashi predicts that the number of guests at this party will be A or B.  Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.  We assume that a piece cannot be divided and distributed to multiple guests.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split()) 

count = 1
an = []
bn = []
eee = min(a,b)

for ii in range(1, eee+2):
    bbb = b * ii
    bn.append(bbb)

while True:
    aaa = a * count
    print(aaa)
    if aaa in bn:
        print(aaa)
        break
    count += 1

Fixed, accepted submission:
a, b = map(int, input().split()) 
count = 1
 
while True:
    aaa = a * count
    if aaa % b == 0:
        print(aaa)
        break

    count += 1
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
N = int(input())

ret = [0 for i in range(N)]
for x in range(1,100):
    for y in range(1,100):
        for z in range(1,100):
            a = x**2 + y**2 + z**2 + x*y + y*z + z*x
            if a < N:
                ret[a] += 1

for i in ret:
    print(i)


Fixed, accepted submission:
N = int(input())
#N = 20

ret = [0 for i in range(N)]
for x in range(1,100):
    for y in range(1,100):
        for z in range(1,100):
            a = x**2 + y**2 + z**2 + x*y + y*z + z*x
            if a <= N:
                ret[a-1] += 1

for i in ret:
    print(i)
Problem:
When a boy was cleaning up after his grand father passing, he found an old paper:         In addition, other side of the paper says that "go ahead a number of steps equivalent to the first integer, and turn clockwise by degrees equivalent to the second integer".  His grand mother says that Sanbonmatsu was standing at the center of town. However, now buildings are crammed side by side and people can not walk along exactly what the paper says in. Your task is to write a program which hunts for the treature on the paper.  For simplicity, 1 step is equivalent to 1 meter. Input consists of several pairs of two integers d (the first integer) and t (the second integer) separated by a comma. Input ends with "0, 0". Your program should print the coordinate (x, y) of the end point. There is the treature where x meters to the east and y meters to the north from the center of town.  You can assume that d ≤ 100 and -180 ≤ t ≤ 180\.

Incorrect submission (verdict: Wrong Answer):
import cmath,math,sys
z=0;p=90
for e in sys.stdin:
 r,d=map(int,e.split(','))
 z+=cmath.rect(r,math.radians(p))
 p-=d
print(int(z.real),int(z.imag))


Fixed, accepted submission:
import cmath,math,sys
z=0;p=90
for e in sys.stdin:
 r,d=map(int,e.split(','))
 z+=cmath.rect(r,math.radians(p))
 p-=d
print(int(z.real),'\n',int(z.imag),sep='')
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    N = int(input())
    A = list(map(int, input().split(' ')))
    print(N,A)
    count = 0
    while True:
        A_b = [x%2 == 0 for x in A]
        if not False in A_b:
            A = list(map(lambda x: x//2, A))
            count += 1
        else:
            print(count)
            break
    

Fixed, accepted submission:
if __name__ == '__main__':
    N = int(input())
    A = list(map(int, input().split(' ')))
    count = 0
    while True:
        A_b = [x%2 == 0 for x in A]
        if not False in A_b:
            A = list(map(lambda x: x//2, A))
            count += 1
        else:
            print(count)
            break
Problem:
There are N balls placed in a row. AtCoDeer the deer is painting each of these in one of the K colors of his paint cans. For aesthetic reasons, any two adjacent balls must be painted in different colors.  Find the number of the possible ways to paint the balls.

Incorrect submission (verdict: Wrong Answer):
N,K=map(int,input().split())
print(K*((K-1)**N-1))

Fixed, accepted submission:
N,K=map(int,input().split())
print(K*((K-1)**(N-1)))
Problem:
On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in `yyyy/mm/dd` format. For example, January 23, 2018 should be written as `2018/01/23`.  After finishing the document, she noticed that she had mistakenly wrote `2017` at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to `2018` and prints it.

Incorrect submission (verdict: Wrong Answer):
s = str(input())
strlist = list(s)
strlist[3] = '8'
s = str(strlist)
print(s)

Fixed, accepted submission:
s = str(input())
strlist = list(s)
strlist[3] = '8'
s = ''.join(strlist)
print(s)
Problem:
AtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.  The company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.  How many different PIN codes can he set this way?  Both the lucky number and the PIN code may begin with a 0.

Incorrect submission (verdict: Wrong Answer):
from itertools import groupby


N = int(input())
S = input()
S = ''.join([x[0] for x in groupby(S)])

ans = 0
for i in range(0, 1000):
    num = str(i).zfill(3)
    flag = True
    _idx = 0
    for s in num:
        idx = S[_idx:].find(s)
        if idx == -1:
            flag = False
            break
        else:
            _idx += idx + 1
    if flag:
        ans += 1
print(ans)


Fixed, accepted submission:
N = int(input())
S = input()

ans = 0
for i in range(0, 1000):
    num = str(i).zfill(3)
    flag = True
    _idx = 0
    for s in num:
        idx = S[_idx:].find(s)
        if idx == -1:
            flag = False
            break
        else:
            _idx += idx + 1
    if flag:
        ans += 1
print(ans)
Problem:
We have N cards. A number a_i is written on the i-th card.   Alice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.   The game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.

Incorrect submission (verdict: Wrong Answer):
n = input()
a = list(map(int, input().split()))
a.sort(reverse=True)

alice = 0
bob = 0

for i in range(len(a)):
    if (i // 2) == 0:
        alice += a[i]
    else:
        bob += a[i]

print(alice - bob)

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
a.sort(reverse=True)

alice = 0
bob = 0

for i in range(n):
    if (i % 2) == 0:
        alice += a[i]
    else:
        bob += a[i]


print(alice - bob)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
num = int(input())
a = list(map(int, input().split()))

count = 0
for i in a:
  c = 0
  while i != 0 and i % 2 == 0:
    i /= 2
    c += 1
  if c >= count:
    count = c
print(count)

Fixed, accepted submission:
num = int(input())
a = list(map(int, input().split()))

carray = []
for i in a:
  c = 0
  while i != 0 and i % 2 == 0:
    i /= 2
    c += 1
  carray.append(c)
print(min(carray))
Problem:
You are going to hold a competition of one-to-one game called AtCoder Janken. _(Janken is the Japanese name for Rock-paper-scissors.)_ N players will participate in this competition, and they are given distinct integers from 1 through N. The arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive). You cannot assign the same integer to multiple playing fields. The competition consists of N rounds, each of which proceeds as follows:    * For each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.   * Then, each player adds 1 to its integer. If it becomes N+1, change it to 1.  You want to ensure that no player fights the same opponent more than once during the N rounds. Print an assignment of integers to the playing fields satisfying this condition. It can be proved that such an assignment always exists under the constraints given.

Incorrect submission (verdict: Wrong Answer):
import sys
def main():
    N,M=tuple(map(int,sys.stdin.readline().split()))
    for i in range(M):
        print(str(i+1)+' '+str(N-2+1+1-i))
if __name__=='__main__':main()

Fixed, accepted submission:
import sys
def main():
    N,M=tuple(map(int,sys.stdin.readline().split()))
    if M%2==1:
        m1,m2=M//2,M//2+1
        for i in range(m1):
            l,r=i+1,M-i
            print(str(l)+' '+str(r))
        for i in range(m2):
            l,r=M+1+i,2*M+1-i
            print(str(l)+' '+str(r))
    else:
        m=M//2
        for i in range(m):
            l,r=i+1,M+1-i
            print(str(l)+' '+str(r))
        for i in range(m):
            l,r=M+2+i,2*M+1-i
            print(str(l)+' '+str(r))
if __name__=='__main__':main()
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
N, A, B = map(int, input().split())
arr = [i for i in range(1, N)]
k = 0
for j in arr:
  if j / 10 + j % 10 >= A and j / 10 + j % 10 <= B:
    k += j
    
print (k)

Fixed, accepted submission:
N, A, B = map(int, input().split())

ans = 0

for x in range(1, N + 1):
    SUM = 0
    num = x
    while x > 0:
        SUM += (x % 10)
        x //= 10
    if A <= SUM <= B:
        ans += num
        
print(ans)
Problem:
Alice and Brown loves games. Today, they will play the following game.  In this game, there are two piles initially consisting of X and Y stones, respectively. Alice and Bob alternately perform the following operation, starting from Alice:    * Take 2i stones from one of the piles. Then, throw away i of them, and put the remaining i in the other pile. Here, the integer i (1≤i) can be freely chosen as long as there is a sufficient number of stones in the pile.  The player who becomes unable to perform the operation, loses the game.  Given X and Y, determine the winner of the game, assuming that both players play optimally.

Incorrect submission (verdict: Wrong Answer):
x,y = map(int,input().split())
if abs(x-y) <= 1:
  print("Alice")
else:
  print("Brown")

Fixed, accepted submission:
x,y = map(int,input().split())
if abs(x-y) <= 1:
  print("Brown")
else:
  print("Alice")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())

x=int(str(a)+str(b))

for i in range(1,101):
    if i*i==x:
        print('Yes')
    else:
        print('No')

Fixed, accepted submission:
a,b=map(int,input().split())

x=int(str(a)+str(b))
ans='No'
for i in range(1,400):
    if i*i==x:
        ans='Yes'
print(ans)
Problem:
You have drawn a chart of a perfect binary tree, like one shown in Figure G.1. The figure shows a finite tree, but, if needed, you can add more nodes beneath the leaves, making the tree arbitrarily deeper.     Figure G.1. A Perfect Binary Tree Chart       Tree nodes are associated with their depths, defined recursively. The root has the depth of zero, and the child nodes of a node of depth d have their depths $d + 1$.  You also have a pile of a certain number of medals, each engraved with some number. You want to know whether the medals can be placed on the tree chart satisfying the following conditions.    * A medal engraved with $d$ should be on a node of depth $d$.   * One tree node can accommodate at most one medal.   * The path to the root from a node with a medal should not pass through another node with a medal.  You have to place medals satisfying the above conditions, one by one, starting from the top of the pile down to its bottom. If there exists no placement of a medal satisfying the conditions, you have to throw it away and simply proceed to the next medal.  You may have choices to place medals on different nodes. You want to find the best placement. When there are two or more placements satisfying the rule, one that places a medal upper in the pile is better. For example, when there are two placements of four medal, one that places only the top and the 2nd medal, and the other that places the top, the 3rd, and the 4th medal, the former is better.  In Sample Input 1, you have a pile of six medals engraved with 2, 3, 1, 1, 4, and 2 again respectively, from top to bottom.    * The first medal engraved with 2 can be placed, as shown in Figure G.2 (A).   * Then the second medal engraved with 3 may be placed , as shown in Figure G.2 (B).   * The third medal engraved with 1 cannot be placed if the second medal were placed as stated above, because both of the two nodes of depth 1 are along the path to the root from nodes already with a medal. Replacing the second medal satisfying the placement conditions, however, enables a placement shown in Figure G.2 (C).   * The fourth medal, again engraved with 1, cannot be placed with any replacements of the three medals already placed satisfying the conditions. This medal is thus thrown away.   * The fifth medal engraved with 4 can be placed as shown in of Figure G.2 (D).    * The last medal engraved with 2 cannot be placed on any of the nodes with whatever replacements.     Figure G.2. Medal Placements

Incorrect submission (verdict: Wrong Answer):
c=p=0;b=[0]*1000000
for _ in range(int(input())):
    x=int(input())
    if (c==x and p!=x) or b[0]==1 or c>x:print('NO');continue
    print('YES')
    if x>=1000000:continue
    p+=1;b[x]+=1
    while b[x]>1:p-=1;b[x]-=2;b[x-1]+=1;x-=1
    while b[c+1]==1 and c<999999:c+=1

Fixed, accepted submission:
c=p=0;b=[0]*1000000
for _ in range(int(input())):
    x=int(input())
    if (c==x and p!=x) or b[0]==1 or c>x:print('No');continue
    print('Yes')
    if x>=1000000:continue
    p+=1;b[x]+=1
    while b[x]>1:p-=1;b[x]-=2;b[x-1]+=1;x-=1
    while b[c+1]==1 and c<999999:c+=1
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
word = list(input())

rep_word = []
num_abb = len(word) - 2

rep_word.append(word[0])
rep_word.append(str(num_abb))
rep_word.append(word[-1])

print(''.join(word))

Fixed, accepted submission:
word = list(input())

rep_word = []
num_abb = len(word) - 2

rep_word.append(word[0])
rep_word.append(str(num_abb))
rep_word.append(word[-1])

print(''.join(rep_word))
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ac = 0
wa = 0
tle = 0
re = 0
for i in range(N):
  S = input()
  if S == 'AC':
    ac += 1
  elif S == 'WA':
    wa += 1
  elif S == 'TLE':
    tle += 1
  elif S == 'RE':
    re += 1
print('AC * {}'.format(ac))
print('WA * {}'.format(wa))
print('TLE * {}'.format(tle))
print('RE * {}'.format(re))

Fixed, accepted submission:
N = int(input())
ac = 0
wa = 0
tle = 0
re = 0
for i in range(N):
  S = input()
  if S == 'AC':
    ac += 1
  elif S == 'WA':
    wa += 1
  elif S == 'TLE':
    tle += 1
  elif S == 'RE':
    re += 1
print('AC x {}'.format(ac))
print('WA x {}'.format(wa))
print('TLE x {}'.format(tle))
print('RE x {}'.format(re))
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):

s = input()
a = int(s.count('o'))
print(int(700+a*100))

Fixed, accepted submission:

number = list(map(int,input()))
a = 0
for i in number:
    if i == 1:
        a = a+1
print(a)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
queue=list(map(int,input().split()))
queue.sort()
if queue[0]==5 and queue[1]==5 and queue[2]==7:
  print("Yes")
else:
  print("No")
    

Fixed, accepted submission:
queue=list(map(int,input().split()))
queue.sort()
if queue[0]==5 and queue[1]==5 and queue[2]==7:
  print("YES")
else:
  print("NO")
Problem:
Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Incorrect submission (verdict: Wrong Answer):
a = int(input())

h = a % (60 * 60)
m = (a % 60 * 60) % 60
s = a % 60

print(h, m, s, sep = ":")

Fixed, accepted submission:
s = int(input())

h = int(s / (60 * 60))
m = int((s % (60 * 60)) / 60)
s = int(s % 60)

print(h, m, s, sep = ":")
Problem:
Find the largest square number not exceeding N. Here, a _square number_ is an integer that can be represented as the square of an integer.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = 0

while True:
	if ans * ans >= n:
		break
	ans += 1
	
print(ans)
	

Fixed, accepted submission:
n = int(input())
ans = 0

while True:
	if ans * ans > n:
		break
	ans += 1
	
print((ans-1)*(ans-1))
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):

A,B,C=map(int,input().split())


def gcd(GCD1,GCD2):
    x = min(GCD1,GCD2)
    y = max(GCD1,GCD2)
    if y%x == 0:
        return x
    else:
        return gcd(x,y%x)
    
d=gcd(A,B)
if gcd(d,C) == 1:
    print("No")
else:
    print("Yes")

Fixed, accepted submission:
#B
A,B,C = map(int,input().split())

a = 0
flag = 0
for i in range(B+1):
    a+=A
    if a%B == C:
        flag = 1
        break
        
if flag == 0:
    print("NO")
else:
    print("YES")
Problem:
You are given a string S of length N consisting of `(` and `)`. Your task is to insert some number of `(` and `)` into S to obtain a _correct bracket sequence_.   Here, a correct bracket sequence is defined as follows:    * `()` is a correct bracket sequence.   * If X is a correct bracket sequence, the concatenation of `(`, X and `)` in this order is also a correct bracket sequence.   * If X and Y are correct bracket sequences, the concatenation of X and Y in this order is also a correct bracket sequence.   * Every correct bracket sequence can be derived from the rules above.  Find the shortest correct bracket sequence that can be obtained. If there is more than one such sequence, find the lexicographically smallest one.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = input()

ans = []
st = 0
for c in S:
    if c == '(':
        st += 1
        ans.append('(')
    else:
        if st > 0:
            st -= 1
        else:
            ans.insert(0, '(')
        ans.append(')')
    print(*ans, sep='')

ans.extend(')' * st)

print(*ans, sep='')


Fixed, accepted submission:
N = int(input())
S = input()
 
ans = []
st = 0
for c in S:
    if c == '(':
        st += 1
        ans.append('(')
    else:
        if st > 0:
            st -= 1
        else:
            ans.insert(0, '(')
        ans.append(')')
 
ans.extend(')' * st)
 
print(*ans, sep='')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N % 1000)

Fixed, accepted submission:
N = int(input())
if N % 1000 == 0:
  print(0)
else:
  print(1000 - N % 1000)
Problem:
We have N sticks with negligible thickness. The length of the i-th stick is A_i.  Snuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides. Find the maximum possible area of the rectangle.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter

n = int(input())
a = list(map(int,input().split()))

ac = Counter(a)

cur_a = 0
cur_c = 0
res = 0
for a,c in ac.items():
	if c < 2:
		break
	if cur_c == c:
		res = max(res,cur_a*a)
		cur_a = max(cur_a,a)
	else:
		cur_a = a
		cur_c = c

print(res)


Fixed, accepted submission:
from collections import Counter

n = int(input())
a = list(map(int,input().split()))

ac = Counter(a)

cur_a = 0
res = 0
# print(ac)
for a,c in ac.items():
	# print(a,c)
	if c < 2:
		continue
	else:
		res = max(res,cur_a*a)
		cur_a = max(cur_a,a)
		if c >= 4:
			res = max(res,a*a)
	# print(cur_a,res)
print(res)