TnT/CodeNet4Repair huggingface dataset:
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
# encoding:utf-8
import copy
import random
import bisect 
import fractions 
import math
import sys

mod = 10**9+7
sys.setrecursionlimit(mod) 

sx,sy,gx,gy = map(int,input().split())

ans = []
# go
way1 = ["U"] * (gy-sy) + ["R"] * (gx-sx)
#return
way2 = ["D"] * (gx-sx) + ["L"] * (gy-sy)

way3 = ["L"] + ["U"] * (gy-sy+1) + ["R"] * (gx-sx+1) + ["D"]
way4 = ["R"] + ["D"] * (gx-sx+1) + ["L"] * (gy-sy+1) + ["U"]
ans += way1 + way2 + way3 + way4

print("".join(ans))


Fixed, accepted submission:
# encoding:utf-8
import copy
import random
import bisect 
import fractions 
import math
import sys

mod = 10**9+7
sys.setrecursionlimit(mod) 

sx,sy,gx,gy = map(int,input().split())

ans = []
# go
way1 = ["U"] * (gy-sy) + ["R"] * (gx-sx)
#return
way2 = ["D"] * (gy-sy) + ["L"] * (gx-sx)

way3 = ["L"] + ["U"] * (gy-sy+1) + ["R"] * (gx-sx+1) + ["D"]
way4 = ["R"] + ["D"] * (gy-sy+1) + ["L"] * (gx-sx+1) + ["U"]
ans += way1 + way2 + way3 + way4

print("".join(ans))
# print(len(ans))
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
s = float(input())
print(s**3)


Fixed, accepted submission:
s = int(input())
print(s**3)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
nums = []
nums = input().split()

def insertationSort(A,N):
    for i in range(1,N):
        v = A[i]
        j = i - 1
        while j>=0 and A[j]>v:
            A[j+1] = A[j]
            j = j - 1
        A[j+1] = v
        print(' '.join(A))

insertationSort(nums,n)


Fixed, accepted submission:
n = int(input())
nums = []
nums = input().split()
intNums = list(map(int,nums))

def insertationSort(nums,intNums):
    print(' '.join(nums))
    for i in range(1,len(nums)):
        v = intNums[i]
        j = i - 1
        while j>=0 and intNums[j]>v:
            intNums[j+1] = intNums[j]
            j = j - 1
        intNums[j+1] = v
        nums = list(map(str,intNums))
        print(' '.join(nums))

insertationSort(nums,intNums)
Problem:
For an integer n not less than 0, let us define f(n) as follows:    * f(n) = 1 (if n < 2)   * f(n) = n f(n-2) (if n \geq 2)  Given is an integer N. Find the number of trailing zeros in the decimal notation of f(N).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if n % 2 == 1:
    print(0)
    exit()
ans = 0
for i in range(1,50):
    ans += (n // (5 ** i))
print(ans)

Fixed, accepted submission:
n = int(input())
if n % 2 == 1:
    print(0)
    exit()
n = n//2
ans = 0
for i in range(1,50):
    ans += (n // (5 ** i))
print(ans)
Problem:
Write a program which identifies the number of combinations of three integers which satisfy the following conditions:    * You should select three distinct integers from 1 to n.   * A total sum of the three integers is x.  For example, there are two combinations for n = 5 and x = 9.    * 1 + 3 + 5 = 9   * 2 + 3 + 4 = 9

Incorrect submission (verdict: Wrong Answer):
while True:
    n,x=map(int,input().split())
    if n==0 and x==0:
        break
    sum=0
    for i in range(x//3,n+1):
        if (x-i)%2==0:
            
            sum+=((x-i)/2)-1
        else:
            
            sum+=(x-i-1)/2
    print(sum)

Fixed, accepted submission:
while True:
    n,x=map(int,input().split())
    if n==0 and x==0:
        break
    sum=0
    for i in range(x//3+1,n+1):
        for j in range((x-i)//2+1,i):
            if 0<x-i-j<j :   
                sum+=1
    print(int(sum))
Problem:
You are playing the following game with Joisino.    * Initially, you have a blank sheet of paper.   * Joisino announces a number. If that number is written on the sheet, erase the number from the sheet; if not, write the number on the sheet. This process is repeated N times.   * Then, you are asked a question: How many numbers are written on the sheet now?  The numbers announced by Joisino are given as A_1, ... ,A_N in the order she announces them. How many numbers will be written on the sheet at the end of the game?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = set()

for i in range(N):
  ai = int(input())
  a.add(ai)
print(len(list(a)))

Fixed, accepted submission:
n = int(input())
d = {}

for i in range(n):
    a = input()
    if a not in d:
        d[a] = 1
    else:
        d[a] = d[a] + 1

ans = 0
for val in d.values():
    if val % 2 == 1:
        ans += 1
    else:
        continue
print(ans)
Problem:
Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Incorrect submission (verdict: Wrong Answer):
S =int(input())
h = S // 3600
m = S % 3600 // 60
s = S // 60
print(h,m,s, sep=':')

Fixed, accepted submission:
S = int(input())
h = S // 3600
m = S % 3600 // 60
s = S % 60
print(h, m, s, sep=':')
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
#072_b
s = input()
a = []
if s.islower() and 1 <= len(s) and len(s) <= 10 ** 5:
    b=""
    for n in range(len(s)):
        if n % 2 != 0:
            a.append(s[n])
    for m in range(len(a)):
        b=b+a[m]
    print(b)


Fixed, accepted submission:
#072_b
s = input()
a = []
if s.islower() and 1 <= len(s) and len(s) <= 10 ** 5:
    b=""
    for n in range(len(s)):
        if n % 2 == 0:
            a.append(s[n])
    for m in range(len(a)):
        b=b+a[m]
    print(b)
Problem:
Let's arrange a deck of cards. There are totally 36 cards of 4 suits(S, H, C, D) and 9 values (1, 2, ... 9). For example, 'eight of heart' is represented by H8 and 'one of diamonds' is represented by D1.  Your task is to write a program which sorts a given set of cards in ascending order by their values using the Bubble Sort algorithms and the Selection Sort algorithm respectively. These algorithms should be based on the following pseudocode:                 BubbleSort(C) 1 for i = 0 to C.length-1 2     for j = C.length-1 downto i+1 3         if C[j].value < C[j-1].value 4             swap C[j] and C[j-1]                 SelectionSort(C) 1 for i = 0 to C.length-1 2     mini = i 3     for j = i to C.length-1 4         if C[j].value < C[mini].value 5             mini = j 6     swap C[i] and C[mini]   Note that, indices for array elements are based on 0-origin.  For each algorithm, report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(str,input().split()))

data1 = a[:]
data2 = a[:]

def bubble_sort(data):
	for i in range(len(data)):
		for j in range(len(data)-1,i,-1):
			if(data[j][1] < data[j-1][1]):
				data[j],data[j-1] = data[j-1],data[j]

	return(data)

def selection_sort(data):
	for i in range(len(data)):
		minj = i
		for j in range(i,len(data)):
			if(data[j][1] < data[minj][1]):
				minj = j

		data[i],data[minj] = data[minj],data[i]

	return(data)
data1 = bubble_sort(data1)
data2 = selection_sort(data2)
print(*data1)
print("Stable")
print(*data2)
print("Stable" if data1 == data2 else "NotStable")



Fixed, accepted submission:
n = int(input())
a = list(map(str,input().split()))

data1 = a[:]
data2 = a[:]

def bubble_sort(data):
	for i in range(len(data)):
		for j in range(len(data)-1,i,-1):
			if(data[j][1] < data[j-1][1]):
				data[j],data[j-1] = data[j-1],data[j]

	return(data)

def selection_sort(data):
	for i in range(len(data)):
		minj = i
		for j in range(i,len(data)):
			if(data[j][1] < data[minj][1]):
				minj = j

		data[i],data[minj] = data[minj],data[i]

	return(data)
data1 = bubble_sort(data1)
data2 = selection_sort(data2)
print(*data1)
print("Stable")
print(*data2)
print("Stable" if data1 == data2 else "Not stable")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

print(1/2 * (a + b) * h)

Fixed, accepted submission:
a = int(input())
b = int(input())
h = int(input())
print((a+b)*h//2)
Problem:
There is a kangaroo at coordinate 0 on an infinite number line that runs from left to right, at time 0. During the period between time i-1 and time i, the kangaroo can either stay at his position, or perform a jump of length exactly i to the left or to the right. That is, if his coordinate at time i-1 is x, he can be at coordinate x-i, x or x+i at time i. The kangaroo's nest is at coordinate X, and he wants to travel to coordinate X as fast as possible. Find the earliest possible time to reach coordinate X.

Incorrect submission (verdict: Wrong Answer):
X = int(input())

i = 1
x = X
while(True):
    if x == i:
        print(i)
        break
    elif x >= (i * 2 + 1):
        x = x - i
        i += 1
    elif x < i:
        break
    else:
        i += 1
    print(i, x)


Fixed, accepted submission:
X = int(input())

i = 1
x = 1
while(x <= X):
  x += i
  i += 1
  
print(i - 1)
Problem:
You are given a string S of length N consisting of lowercase English letters, and an integer K. Print the string obtained by replacing every character in S that differs from the K-th character of S, with `*`.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = input()
C = int(input())
mark = B[C-1]
for i in range(A):
  if B[i] != mark:
    B = B.replace(B[i], '*', 1)
    print(1)

print(B)


Fixed, accepted submission:
A = int(input())
B = input()
C = int(input())
mark = B[C-1]
for i in range(A):
  if B[i] != mark:
    B = B.replace(B[i], '*', 1)
    
 
print(B)
Problem:
Two children are playing tag on a number line. (In the game of tag, the child called "it" tries to catch the other child.) The child who is "it" is now at coordinate A, and he can travel the distance of V per second. The other child is now at coordinate B, and she can travel the distance of W per second.  He can catch her when his coordinate is the same as hers. Determine whether he can catch her within T seconds (including exactly T seconds later). We assume that both children move optimally.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python


def run(a, v, b, w, t):
    if a == b:
        return 'Yes'
    elif b < a:
        if a - (v * t) <= b - (w * t):
            return 'Yes'
        else:
            return 'No'
    else:
        if b + (w * t) <= a + (v * t):
            return 'Yes'
        else:
            return 'No'


def main():
    A, V = list(map(int, input().split()))
    B, W = list(map(int, input().split()))
    T = int(input())

    print(run(A, V, B, W, T))


if __name__ == '__main__':
    main()


Fixed, accepted submission:
#!/usr/bin/env python



def run(a, vt, b, wt):
    if a < b:
        if b + wt <= a + vt:
            return 'YES'
        else:
            return 'NO'
    else:
        if a - vt <= b - wt:
            return 'YES'
        else:
            return 'NO'


def main():
    A, V = list(map(int, input().split()))
    B, W = list(map(int, input().split()))
    T = int(input())

    print(run(A, V*T, B, W*T))


if __name__ == '__main__':
    main()
Problem:
Snuke received a positive integer N from Takahashi. A positive integer m is called a _favorite number_ when the following condition is satisfied:    * The quotient and remainder of N divided by m are equal, that is, \lfloor \frac{N}{m} \rfloor = N \bmod m holds.  Find all favorite numbers and print the sum of those.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

div=[]
for i in range(1,int((n**0.5)//1)+1):
    if(n%i==0):
        div.append(i)
        div.append(n//i)
div=sorted(list(set(div)))

ans=[0]

#i//m + i%m
#m*x + x = i
#x = i/(m+1)


for divi in div:
    m=divi-1
    if(n//divi < m):
        ans.append(m)
print(ans)
print(sum(ans))


Fixed, accepted submission:
n=int(input())

div=[]
for i in range(1,int((n**0.5)//1)+1):
    if(n%i==0):
        div.append(i)
        div.append(n//i)
div=sorted(list(set(div)))

ans=[0]

#i//m + i%m
#m*x + x = i
#x = i/(m+1)


for divi in div:
    m=divi-1
    if(n//divi < m):
        ans.append(m)
print(sum(ans))
Problem:
It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.  You are given an integer N. Find the N-th Lucas number.  Here, the i-th Lucas number L_i is defined as follows:    * L_0=2   * L_1=1   * L_i=L_{i-1}+L_{i-2} (i≥2)

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = [2,1]

if n == 1:
  print(2)
  exit()

for _ in range(n-2):
  ans.append(ans[-1]+ans[-2])
  
print(ans[-1])

Fixed, accepted submission:
n = int(input())
ans = [2,1]

if n == 1:
  print(1)
  exit()


for _ in range(n-1):
  ans.append(ans[-1]+ans[-2])
  
print(ans[-1])
Problem:
AtCoDeer has three cards, one red, one green and one blue.   An integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.   We will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.   Is this integer a multiple of 4?

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int, input().split())  
d = int(a+b+c) % 4
if d != 0:
    print('NO')
else:
    print('YES')

Fixed, accepted submission:
a,b,c=map(int, input().split())  
d = int(str(a)+str(b)+str(c)) % 4
if d != 0:
    print('NO')
else:
    print('YES')
Problem:
There are N rabbits, numbered 1 through N.  The i-th (1≤i≤N) rabbit likes rabbit a_i. Note that no rabbit can like itself, that is, a_i≠i.  For a pair of rabbits i and j (i＜j), we call the pair (i，j) a _friendly pair_ if the following condition is met.    * Rabbit i likes rabbit j and rabbit j likes rabbit i.  Calculate the number of the friendly pairs.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
# !/usr/bin/env python
# vim: set fileencoding=utf-8 :

"""
#
# Author:   Noname
# URL:      https://github.com/pettan0818
# License:  MIT License
# Created:  2016-09-28
#

# Usage
#
"""
import sys

def input_single_line():
    
    return input()

def input_two_line():
    """Receive Two Lined Inputs.
    Like this.

    N
    1 2 3 4 5
    """
    sys.stdin.readline()
    target = sys.stdin.readline()
    target = target.rstrip("\n")
    target = target.split(" ")

    return target


def search_lovers(target_list: list) -> None:
    """Search Simple."""
    lovers = []
    for i in target_list:
        if target_list[i-1] == i-1:
            lovers.append(i-1)

    print(len(lovers))


if __name__ == "__main__":
    import doctest
    doctest.testmod()

    target = input_two_line()



Fixed, accepted submission:
# -*- coding: utf-8 -*-
# !/usr/bin/env python
# vim: set fileencoding=utf-8 :

"""
#
# Author:   Noname
# URL:      https://github.com/pettan0818
# License:  MIT License
# Created:  2016-09-28
#

# Usage
#
"""
import sys

def input_single_line():
    
    return input()

def input_two_line():
    """Receive Two Lined Inputs.
    Like this.

    N
    1 2 3 4 5
    """
    sys.stdin.readline()
    target = sys.stdin.readline()
    target = target.rstrip("\n")
    target = target.split(" ")

    return target


def search_lovers(target_list: list) -> None:
    """Search Simple.
    >>> target_list = [2, 3, 1]
    >>> search_lovers(target_list)
    0
    >>> target_list = [2, 1, 4, 3]
    >>> search_lovers(target_list)
    2
    >>> target_list = [5, 5, 5, 5, 1]
    >>> search_lovers(target_list)
    1
    """
    target_list = [int(i) - 1 for i in target_list]
    lovers = []
    ans = 0
    for i, n in enumerate(target_list):
        if target_list[n] == i:
            ans = ans + 1

    print(int(ans/2))


if __name__ == "__main__":
    import doctest
    doctest.testmod()

    target = input_two_line()

    search_lovers(target)
Problem:
There are N rabbits, numbered 1 through N.  The i-th (1≤i≤N) rabbit likes rabbit a_i. Note that no rabbit can like itself, that is, a_i≠i.  For a pair of rabbits i and j (i＜j), we call the pair (i，j) a _friendly pair_ if the following condition is met.    * Rabbit i likes rabbit j and rabbit j likes rabbit i.  Calculate the number of the friendly pairs.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = list(map(int, input().split()))
a = [i - 1 for i in a]

count = 0
for i in range(N):
    print(a[i])
    if i == a[a[i]]:
        count += 1
print(count // 2)


Fixed, accepted submission:
N = int(input())
a = list(map(int, input().split()))
a = [i - 1 for i in a]

count = 0
for i in range(N):
    if i == a[a[i]]:
        count += 1
print(count // 2)
Problem:
Snuke is giving cookies to his three goats.  He has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).  Your task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if a%3==0:
    print("Possible")
elif b%3==0:
    print("Possible")
elif a+b%3==0:
    print("Possible")
else:
    print("Impossible")

Fixed, accepted submission:
a,b = map(int,input().split())
if a%3==0:
    print("Possible")
elif b%3==0:
    print("Possible")
elif (a+b)%3==0:
    print("Possible")
else:
    print("Impossible")
Problem:
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.  Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.  Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)  At most how much can he earn on balance?  Note that the same string may be written on multiple cards.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
s=[input() for i in range(N)]
M=int(input())
l=[input() for i in range(M)]
list_str=list(dict.fromkeys(s+l))
s_l=[]
for i in range(len(list_str)):
  s_l.append(s.count(list_str[i])-l.count(list_str[i]))
print(all([i < 0 for i in s_l]))
if(all([i < 0 for i in s_l])):
  t='a'
  while(t==any(s_l)):
    t+='a'
  print(t)
else:print(max(s_l))

Fixed, accepted submission:
N=int(input())
s=[input() for i in range(N)]
M=int(input())
l=[input() for i in range(M)]
list_str=list(dict.fromkeys(s+l))
s_l=[]
for i in range(len(list_str)):
  s_l.append(s.count(list_str[i])-l.count(list_str[i]))

if(all([i < 0 for i in s_l])):
  print(0)
else:print(max(s_l))
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Wrong Answer):
n,k,*a=open(0).read().split()
while set(a)&{n}:n=str(int(n)+1)
print(n)

Fixed, accepted submission:
n,a=open(0)
n=int(n.split()[0])
while set(a)&set(str(n)):n+=1
print(n)
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
a,b=input().split()
c=(int(a+b))
for i in range(350):
  if c==i*i:
    print("Yes")
  else:
    print("No")


Fixed, accepted submission:
from math import sqrt
a,b=input().split()
c=sqrt(int(a+b))
if c==int(c):
  print("Yes")
else:
  print("No")
Problem:
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.  Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.  Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)  At most how much can he earn on balance?  Note that the same string may be written on multiple cards.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
d = {}
for _ in range(n):
  s = input()
  if s not in d:
    d[s] = 0
  d[s] += 1
m  =int(input())
for _ in range(m):
  s = input()
  if s not in d:
    d[s] = 0
  d[s] -= 1
  
ans = 0
for key in d:
  ans += max(d[key], 0)
print(ans)

Fixed, accepted submission:
n = int(input())
d = {}
for _ in range(n):
  s = input()
  if s not in d:
    d[s] = 0
  d[s] += 1
m  =int(input())
for _ in range(m):
  s = input()
  if s not in d:
    d[s] = 0
  d[s] -= 1
  
ans = 0
for key in d:
  ans = max(d[key], ans)
print(ans)