TnT/CodeNet4Repair huggingface dataset:
Problem:
In a factory, there are N robots placed on a number line. Robot i is placed at coordinate X_i and can extend its arms of length L_i in both directions, positive and negative.  We want to remove zero or more robots so that the movable ranges of arms of no two remaining robots intersect. Here, for each i (1 \leq i \leq N), the movable range of arms of Robot i is the part of the number line between the coordinates X_i - L_i and X_i + L_i, excluding the endpoints.  Find the maximum number of robots that we can keep.

Incorrect submission (verdict: Wrong Answer):
def main():
    n=int(input())
    xs=[0]*n
    ls=[0]*n
    ranges=[0]*n
    for i in range(n):
        xs[i],ls[i]=map(int,input().split())
        ranges[i]=[xs[i]-ls[i],xs[i]+ls[i]]
    ranges.sort(key=lambda x:x[1])
    count=0
    point=-10000
    for irange in ranges:
        if irange[0]>=point:
            count+=1
        point=irange[1]
    print(count)
if __name__ == "__main__":
    main()


Fixed, accepted submission:
def main():
    n=int(input())
    xs=[0]*n
    ls=[0]*n
    ranges=[0]*n
    for i in range(n):
        xs[i],ls[i]=map(int,input().split())
        ranges[i]=[xs[i]-ls[i],xs[i]+ls[i]]
    ranges.sort(key=lambda x:x[1])
    count=0
    point=-1000000000000
    for irange in ranges:
        if irange[0]>=point:
            count+=1
            point=irange[1]
    print(count)
if __name__ == "__main__":
    main()
Problem:
You are parking at a parking lot. You can choose from the following two fee plans:    * Plan 1: The fee will be A×T yen (the currency of Japan) when you park for T hours.   * Plan 2: The fee will be B yen, regardless of the duration.  Find the minimum fee when you park for N hours.

Incorrect submission (verdict: Wrong Answer):
n,a,b = map(int,input().split())

print(max(a*n,b))

Fixed, accepted submission:
n,a,b = map(int,input().split())

print(min(a*n,b))
Problem:
When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.  You are given N numbers X_1, X_2, ..., X_N, where N is an even number. For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.  Find B_i for each i = 1, 2, ..., N.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
X = list(map(int, input().split()))

sorted_X = sorted(X)

left_med = sorted_X[N//2 -1]
X_left = sorted_X[0 : N//2]
right_mid = sorted_X[N//2]
X_right = sorted_X[N//2 : N]

for i in range(N):
    if X[i] in X_left:
        print(left_med)
    else:
        print(right_mid)

Fixed, accepted submission:
N = int(input())
X = list(map(int, input().split()))

sorted_X = sorted(X)

left_med = sorted_X[N//2 -1]
right_mid = sorted_X[N//2]

for i in range(N):
    if X[i] <= left_med:
        print(right_mid)
    else:
        print(left_med)
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(int(N*800- (N//15)))

Fixed, accepted submission:
N = int(input())
print(int(N*800- (N//15)*200))
Problem:
"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.  Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Incorrect submission (verdict: Wrong Answer):
A,B,C,X,Y=map(int,input().split())
if A+B<2*C:
  ans=A*X+B*Y
else:
  if X<=Y:
    ans=C*2*X
    if 2*C<=B:
      ans+=2*C*(Y-X)
    else:
      ans+=B*(Y-X)
  else:
    ans=C*2*Y
    if Y<=X:
      ans+=2*C*(X-Y)
    else:
      ans+=B*(Y-X)
print(ans)

Fixed, accepted submission:
A,B,C,X,Y=map(int,input().split())
if A+B<2*C:
  ans=A*X+B*Y
else:
  if X<=Y:
    ans=C*2*X
    if 2*C<=B:
      ans+=2*C*(Y-X)
    else:
      ans+=B*(Y-X)
  else:
    ans=C*2*Y
    if 2*C<=A:
      ans+=2*C*(X-Y)
    else:
      ans+=A*(X-Y)
print(ans)
Problem:
時は2020 年。パソコン甲子園 2020 の予選結果を保存したデータがあります。このデータには、各チームに振られる整理番号と正解数が保存されています。ここでは、正解数で順位を決定するものとし、正解数の多いほうから順に 1 位、2 位 ... と順位をつけていくこととします。  予選結果のデータと整理番号をキーボードから入力して、その番号のチームの順位を出力するプログラムを作成してください。

Incorrect submission (verdict: Wrong Answer):
team_score=[]
while True:

	x,y=map(int,input().split(','))
	if x==y==0:
		break
	team_score.append((x,y))

team_score.sort(key=lambda x:x[1],reverse=True)
for i,j in team_score:
	print(i) 

Fixed, accepted submission:
def Inquiry(team):
	ranking=1
	score=team_score[0][1]
	for i in team_score:
		if score>i[1]:
			ranking+=1
			score=i[1]
		if i[0]==team:
			return ranking

team_score=[]
while True:

	x,y=map(int,input().split(','))
	if x==y==0:
		break
	team_score.append((x,y))

#print(team_score)
team_score.sort(key=lambda x:x[1],reverse=True)
#print(team_score)

while True:
	try:
		team=int(input())
		print(Inquiry(team))
	
	except EOFError:
		break
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
otsuri = n % 1000
print(otsuri)

Fixed, accepted submission:
n = int(input())

if n >= 1000:
  siharai = n % 1000
  if siharai == 0:
    print(0)
  else:
    otsuri = 1000 - siharai
    print(otsuri)
  
else:
  otsuri = 1000 - n
  print(otsuri)
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
k=int(input())
x=int(input())
y=int(input())
if n<=k:
  print(n*x)
else:
  print(n*k+(n-k)*y)

Fixed, accepted submission:
n=int(input())
k=int(input())
x=int(input())
y=int(input())
if n<=k:
  print(n*x)
else:
  print(x*k+(n-k)*y)
Problem:
Snuke, who loves animals, built a zoo.  There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.  There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.  Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.  More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.  Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
s = list(input())
check_SW = True
X = ["S"]

for i in range(1,N):
    if check_SW:
        if s[i-1] == "o":
            X.append("S")
            check_SW = True
        else:
            X.append("W")
            check_SW = False
    else:
        if s[i-1] =="×":
            X.append("S")
            check_SW = False
        else:
            X.append("W")
            check_SW = True

print(X)

Fixed, accepted submission:
N = int(input())
S = input().replace('o', '0').replace('x', '1')
S = list(map(int, S))

for pattern in [[0, 0], [0, 1], [1, 0], [1, 1]]:
    for s in S[1:]:
        if pattern[-2] ^ pattern[-1] ^ s == 0:
            pattern.append(0)
        else:
            pattern.append(1)

    pattern = pattern[:-1]
    for i, s in enumerate(S):
        if pattern[i - 1] ^ pattern[(i + 1) % N] ^ s != pattern[i]:
            break
    else:
        pattern = ''.join(map(str, pattern)).replace('0', 'S').replace('1', 'W')
        print(*pattern, sep='')
        break
else:
    print(-1)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
print(N % 1000)

Fixed, accepted submission:
N = int(input())
mod1 = N % 1000

if mod1 != 0 :
    print(1000-mod1)
else:
    print(0)
Problem:
ガイウス・ユリウス・カエサル（Gaius Julius Caesar)，英語読みでジュリアス・シーザー（Julius Caesar）は，古代ローマの軍人であり政治家である．カエサルは，秘密の手紙を書くときに， 'A' を 'D' に， 'B' を 'E' に， 'C' を 'F' に，というように3つずらして表記したという記録が残っている．  大文字のアルファベット26文字だけからなる文字列を，カエサルがしたように3文字ずつずらす変換を施し得られた文字列がある．このような文字列を元の文字列に戻すプログラムを作成せよ．  各文字の変換前と変換後の対応は次のようになる．  変換前 | A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z   ---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---   変換後 | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z | A | B | C      例えば，この方法で文字列 JOI を変換すると MRL が得られ，この方法で変換された文字列 FURDWLD の元の文字列は CROATIA である．

Incorrect submission (verdict: Wrong Answer):
x = input()

str_list = list(x)

for a in str_list:
    if ord(a) + 3  > 90:
        print(chr(ord(a) - 24) ,end = "")
    else:
        print(chr(ord(a) + 3) ,end = "")
print()


Fixed, accepted submission:
x = input()

str_list = list(x)
dict_ = {
    "D":"A",
"E":"B",
"F":"C",
"G":"D",
"H":"E",
"I":"F",
"J":"G",
"K":"H",
"L":"I",
"M":"J",
"N":"K",
"O":"L",
"P":"M",
"Q":"N",
"R":"O",
"S":"P",
"T":"Q",
"U":"R",
"V":"S",
"W":"T",
"X":"U",
"Y":"V",
"Z":"W",
"A":"X",
"B":"Y",
"C":"Z"
    }

for a in str_list:
    print(dict_.get(a) , end = "")
print()
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a, b, x = map(int, input().split())

if a == b:
  if a % x == 0:
    print(1)
  else:
    print(0)
else:
  print((b-a)//x)

Fixed, accepted submission:
a, b, x = map(int, input().split())

def f(n):
  if n == -1:
    return 0
  else:
    return (n//x+1)

print(f(b)-(f(a-1)))
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = sorted(list(map(int,input().split())), reverse = True)
print(sum(a[::2])-sum(a[1::2]))

Fixed, accepted submission:
n = int(input())
a = int(input())
if n%500 <= a:
    print('Yes')
else:
    print('No')
Problem:
Three poles stand evenly spaced along a line. Their heights are a, b and c meters, from left to right. We will call the arrangement of the poles _beautiful_ if the tops of the poles lie on the same line, that is, b-a = c-b.  Determine whether the arrangement of the poles is beautiful.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if a == b == c:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
a, b, c = map(int, input().split())
if b - a == c - b:
    print('YES')
else:
    print('NO')
Problem:
We have a grid with N rows and M columns of squares. Initially, all the squares are white.  There is a button attached to each row and each column. When a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa. When a button attached to a column is pressed, the colors of all the squares in that column are inverted.  Takahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.

Incorrect submission (verdict: Wrong Answer):
n,m,k = map(int, input().split())
def check():
    globals()
    for i in range(n+1):
        for j in range(m+1):
            if j*(n-i)+i*(m-j)==k:
                return True
    return False
if check():
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
n,m,k = map(int, input().split())
def check():
    globals()
    for i in range(n+1):
        for j in range(m+1):
            if j*(n-i)+i*(m-j)==k:
                return True
    return False
if check():
    print('Yes')
else:
    print('No')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N=int(input())

print(N%1000)

Fixed, accepted submission:
N=int(input())

if N%1000==0:
    print(0)

else:
    print(1000-N%1000)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
if __name__ == '__main__':
    N = int(input())
    res = []
    for _ in range(N):
        res.append(str(input()))
    print('AC x {}'.format(res.count('AC')))
    print('WA x {}'.format('WA'))
    print('TLE x {}'.format('TLE'))
    print('RE x {}'.format('RE'))

Fixed, accepted submission:
if __name__ == '__main__':
    N = int(input())
    res = []
    for _ in range(N):
        res.append(str(input()))
    print('AC x {}'.format(res.count('AC')))
    print('WA x {}'.format(res.count('WA')))
    print('TLE x {}'.format(res.count('TLE')))
    print('RE x {}'.format(res.count('RE')))
Problem:
Snuke loves working out. He is now exercising N times.  Before he starts exercising, his _power_ is 1. After he exercises for the i-th time, his power gets multiplied by i.  Find Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.

Incorrect submission (verdict: Wrong Answer):
inN = int(input())

D=1000000000 + 7
p=0
for i in range(inN):
  p*=i
  if (D < p): p=p%D

print(str(p))

Fixed, accepted submission:
inN = int(input())
 
D=1000000000+7
p=1
for i in range(inN):
  p*=(i+1)
  if (D < p): p=p%D
 
print(str(p))
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans = N * (N + 1) / 2
print(ans)

Fixed, accepted submission:
N = int(input())
ans = int(N * (N + 1) / 2)
print(ans)
Problem:
Find the sum of the integers between 1 and N (inclusive), whose sum of digits written in base 10 is between A and B (inclusive).

Incorrect submission (verdict: Wrong Answer):
n, a, b = list(map(int, input().split()))
total = 0

for i in range(n):
  if a <= sum(list(map(int, str(i)))) <= b:
    total += i
    
print(total)

Fixed, accepted submission:
n, a, b = list(map(int, input().split()))
total = 0

for i in range(1, n+1):
  if a <= sum(list(map(int, str(i)))) <= b:
    total += i
    
print(total)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
px = list(map(int, input().split()))
pxs = [x for x in input()]
for i in pxs:
  print(i)
  print(i)


Fixed, accepted submission:
H, W = map(int, input().split())
C = [input() for i in range(H)]
for px in C:
    print(px)
    print(px)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
a=[]
n=int(input())
a=input().strip().split(' ')
print(a)
for i in range(1,n):
	v=a[i]
	j=i-1
	while j>=0 and a[j]>v:
		a[j+1]=a[j]
		j=j-1
	a[j+1]=v
	print(a)


Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split()))

for i in range(n):
	v=a[i]
	j=i-1
	while j>=0 and a[j]>v:
		a[j+1]=a[j]
		j=j-1
	a[j+1]=v
	print(' '.join(map(str,a)))
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
inp = input().split()
r = int(inp[0] + inp[1])

if r >= 10:
    print("error")
else:
    print(r)

Fixed, accepted submission:
inp = input().split()
r = int(inp[0]) + int(inp[1])
if r >= 10:
    print("error")
else:
    print(r)
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
c = []
c.append(list(map(int, input().split())))
c.append(list(map(int, input().split())))
c.append(list(map(int, input().split())))

c0 = c[0][0] + c[0][1] + c[0][2]
c1 = c[1][0] + c[1][1] + c[1][2]
c2 = c[2][0] + c[2][1] + c[2][2]

# a0 + b0 = c00
# a0 + b1 = c01
# a0 + b2 = c02
# 3*a2 + b0 + b1 + b2 = c20 + c21 + c22
# 3*a2 - 3*a0 = c20 + c21 + c22 - (c00 + c01 + c02)
print(str(c))
for a0 in range(101):
    b0 = c[0][0] - a0
    b1 = c[0][1] - a0
    b2 = c[0][2] - a0
    for a1 in range(101):
        a2 = (c2 - c0 + 3 * a0) / 3
        if (
            c[1][0] - a1 == b0
            and c[1][1] - a1 == b1
            and c[1][2] - a1 == b2
            and c[2][0] - a2 == b0
            and c[2][1] - a2 == b1
            and c[2][2] - a2 == b2
        ):
            print("Yes")
            exit(0)
print("No")


Fixed, accepted submission:
c = []
c.append(list(map(int, input().split())))
c.append(list(map(int, input().split())))
c.append(list(map(int, input().split())))

c0 = c[0][0] + c[0][1] + c[0][2]
c1 = c[1][0] + c[1][1] + c[1][2]
c2 = c[2][0] + c[2][1] + c[2][2]

# a0 + b0 = c00
# a0 + b1 = c01
# a0 + b2 = c02
# 3*a2 + b0 + b1 + b2 = c20 + c21 + c22
# 3*a2 - 3*a0 = c20 + c21 + c22 - (c00 + c01 + c02)
for a0 in range(101):
    b0 = c[0][0] - a0
    b1 = c[0][1] - a0
    b2 = c[0][2] - a0
    for a1 in range(101):
        a2 = (c2 - c0 + 3 * a0) / 3
        if (
            c[1][0] - a1 == b0
            and c[1][1] - a1 == b1
            and c[1][2] - a1 == b2
            and c[2][0] - a2 == b0
            and c[2][1] - a2 == b1
            and c[2][2] - a2 == b2
        ):
            print("Yes")
            exit(0)
print("No")
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a, b, h = (int(input()) for _ in range(3))
print((a+b)*h/2)

Fixed, accepted submission:
a, b, h = (int(input()) for _ in range(3))
print(int((a+b)*h/2))
Problem:
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.  He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.  To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.  How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))


a=sorted(a)
b=sorted(b)
c=sorted(c)


def lower_bound(arr,x):
    l=0
    r=len(arr)-1
    while l<=r:
        mid=(l+r)//2
        if x==arr[mid]:
            return mid+1
        elif x<arr[mid]:
            r=mid-1
        else:
            l=mid+1
        #print(mid,r,l)
    return r+1


def upper_bound(arr,x):
    l=0
    r=len(arr)-1
    while l<=r:
        mid=(l+r)//2
        if x==arr[mid]:
            return mid-1
        elif x<arr[mid]:
            r=mid-1
        else:
            l=mid+1
        #print(mid,r,l)
    return r


count=0
for i in range(n):
    a_count=upper_bound(a,b[i])+1
    c_count=lower_bound(c,b[i])+1
    count+=a_count*(len(c)-c_count+1)
    print(upper_bound(a,b[i]),lower_bound(c,b[i]))
    print(a_count,len(c),c_count,len(c)-c_count+1)
    print(count)

print(count)


Fixed, accepted submission:

import bisect

#################
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))


a=sorted(a)
b=sorted(b)
c=sorted(c)

count=0

for i in range(n):
    a_count = bisect.bisect_left(a, b[i])
    c_count = bisect.bisect_right(c, b[i])
    count+=a_count*(len(c)-c_count)

print(count)