TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a sequence of positive integers of length N, a = (a_1, a_2, ..., a_N). Your objective is to remove some of the elements in a so that a will be a **good sequence**.  Here, an sequence b is a **good sequence** when the following condition holds true:    * For each element x in b, the value x occurs exactly x times in b.  For example, (3, 3, 3), (4, 2, 4, 1, 4, 2, 4) and () (an empty sequence) are good sequences, while (3, 3, 3, 3) and (2, 4, 1, 4, 2) are not.  Find the minimum number of elements that needs to be removed so that a will be a good sequence.

Incorrect submission (verdict: Wrong Answer):
import sys
import collections
input=sys.stdin.readline

n=int(input())
l=list(map(int,input().split()))
li=collections.Counter(l)
print(li)
a=0
for k,v in li.items():
    if k>v:
        a+=v
    else:
        a+=v-k
print(a)

Fixed, accepted submission:
import sys
import collections
input=sys.stdin.readline

n=int(input())
l=list(map(int,input().split()))
s=collections.Counter(l)
#print(s)
a=0
for k,v in s.items():
    if k>v:
        a+=v
    else:
        a+=v-k
print(a)
Problem:
Takahashi is competing in a sumo tournament. The tournament lasts for 15 days, during which he performs in one match per day. If he wins 8 or more matches, he can also participate in the next tournament.  The matches for the first k days have finished. You are given the results of Takahashi's matches as a string S consisting of `o` and `x`. If the i-th character in S is `o`, it means that Takahashi won the match on the i-th day; if that character is `x`, it means that Takahashi lost the match on the i-th day.  Print `YES` if there is a possibility that Takahashi can participate in the next tournament, and print `NO` if there is no such possibility.

Incorrect submission (verdict: Wrong Answer):
S = input()

sum_maru = sum([1 for c in S if c == 'x'])
if sum_maru >= 8:
    print("No")
else:
    print("Yes")

Fixed, accepted submission:
S = input()

sum_maru = sum([1 for c in S if c == 'x'])
if sum_maru >= 8:
    print("NO")
else:
    print("YES")
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3

# Generated by 1.1.6 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the default template now. You can remove this line by using your custom template)
def main():
    N, l = map(int,input().split())
    s = []

    for i in range(N):
        s.append(input())

    s_sorted = sorted(s)
    answer = ""

    for i in range(N):
        answer += s[i]

    print(answer)

if __name__ == '__main__':
    main()

Fixed, accepted submission:
#!/usr/bin/env python3

# Generated by 1.1.6 https://github.com/kyuridenamida/atcoder-tools  (tips: You use the default template now. You can remove this line by using your custom template)
def main():
    N, l = map(int,input().split())
    s_sorted = sorted([input() for i in range(N)])
    print("".join(s_sorted))

if __name__ == '__main__':
    main()
Problem:
You are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.

Incorrect submission (verdict: Wrong Answer):
s = input()
flag = 1
for i in range(len(s)-1) :
    for j in range(i+1,len(s)) :
        if s[i] == s[j] :
            flag = 0

if flag == 1 :
    print("Yes")
else :
    print("No")            


Fixed, accepted submission:
s = input()
flag = 1
for i in range(len(s)-1) :
    for j in range(i+1,len(s)) :
        if s[i] == s[j] :
            flag = 0

if flag == 1 :
    print("yes")
else :
    print("no")
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

from scipy.sparse import csr_matrix
from scipy.sparse.csgraph import dijkstra

n, m = map(int, readline().split())
graph = [[0] * n for _ in range(n)]
ab = [list(map(int, readline().split())) for _ in range(m)]
for a, b in ab:
    graph[a - 1][b - 1] = 1
    graph[b - 1][a - 1] = 1
_, ans = dijkstra(csr_matrix(graph), return_predecessors=True)
if any(int(v) == -9999 for v in ans[0][1:]):
    print('NO')
else:
    print('YES')
    print('\n'.join(map(str, ans[0][1:] + 1)))


Fixed, accepted submission:
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)


def bfs(s):
    from collections import deque
    check = [0] * (n + 1)
    check[s] = 1
    q = deque([s])
    while q:
        now = q.popleft()
        for next in graph[now]:
            if check[next] == 0:
                check[next] = str(now)
                q.append(next)
    return check


n, m = map(int, readline().split())
graph = [[] for _ in range(n + 1)]
for i in range(m):
    a, b = map(int, readline().split())
    graph[a].append(b)
    graph[b].append(a)
print('Yes')
print('\n'.join(bfs(1)[2:]))
Problem:
Write a program of the Bubble Sort algorithm which sorts a sequence _A_ in ascending order. The algorithm should be based on the following pseudocode:                 BubbleSort(A) 1 for i = 0 to A.length-1 2     for j = A.length-1 downto i+1 3         if A[j] < A[j-1] 4             swap A[j] and A[j-1]   Note that, indices for array elements are based on 0-origin.  Your program should also print the number of swap operations defined in line 4 of the pseudocode.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: UTF-8 -*-



N = int(input()) 
A = list(map(int,input().split())) 

#print('input')
#print(N)
#print(A)

flag = 1
i = 0
cnt = 0


while flag:
    flag = 0
    for j in reversed(range(i+1,N)):
        if A[j] < A[j-1]:
            tmp = A[j-1]
            A[j-1] = A[j]
            A[j] = tmp
            flag = 1
            cnt += 1
    i += 1

#print('output')
print(A)
print(cnt)



Fixed, accepted submission:
# -*- coding: UTF-8 -*-



N = int(input()) 
A = list(map(int,input().split())) 

#print('input')
#print(N)
#print(A)

flag = 1
i = 0
cnt = 0


while flag:
    flag = 0
    for j in reversed(range(i+1,N)):
        if A[j] < A[j-1]:
            tmp = A[j-1]
            A[j-1] = A[j]
            A[j] = tmp
            flag = 1
            cnt += 1
    i += 1

#print('output')
#print(A)
print(' '.join(map(str,A)))
print(cnt)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
i=1
while i<=N:
  i=i*2
print(i)

Fixed, accepted submission:
N=int(input())
i=1
while i<=int(N/2):
  i=i*2
print(i)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
#42a
l = sorted(input().split())
print(l)
print('YES' if l==['5','5','7'] else 'NO')


Fixed, accepted submission:
#42a
l = sorted(input().split())
print('YES' if l==['5','5','7'] else 'NO')
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
def resolve():
    w, h, n = map(int, input().split())
    min_x, min_y = 0, 0
    max_x, max_y = w, h
    for _ in range(n):
        x, y, a = map(int, input().split())
        if a == 1:
            min_x = min(min_x, x)
        elif a == 2:
            max_x = max(max_x, x)
        elif a == 3:
            min_y = min(min_y, y)
        elif a == 4:
            max_y = max(max_y, y)
    if min_x >= max_x or min_y >= max_y:
        print(0)
    else:
        print((max_x - min_x) * (max_y - min_y))


if __name__ == "__main__":
    resolve()


Fixed, accepted submission:
def resolve():
    w, h, n = map(int, input().split())
    min_x, min_y = 0, 0
    max_x, max_y = w, h
    for _ in range(n):
        x, y, a = map(int, input().split())
        if a == 1:
            min_x = max(min_x, x)
        elif a == 2:
            max_x = min(max_x, x)
        elif a == 3:
            min_y = max(min_y, y)
        elif a == 4:
            max_y = min(max_y, y)
    if min_x >= max_x or min_y >= max_y:
        print(0)
    else:
        print((max_x - min_x) * (max_y - min_y))


if __name__ == "__main__":
    resolve()
Problem:
Alice さんは Miku さんに携帯電話でメールを送ろうとしている。  携帯電話には入力に使えるボタンは数字のボタンしかない。 そこで、文字の入力をするために数字ボタンを何度か押して文字の入力を行う。携帯電話の数字ボタンには、次の文字が割り当てられており、ボタン 0 は確定ボタンが割り当てられている。この携帯電話では 1 文字の入力が終わったら必ず確定ボタンを押すことになっている。    * 1: . , ! ? (スペース)    * 2: a b c    * 3: d e f    * 4: g h i    * 5: j k l    * 6: m n o    * 7: p q r s    * 8: t u v    * 9: w x y z    * 0: 確定ボタン   例えば、ボタン 2、ボタン 2、ボタン 0 と押すと、文字が 'a' → 'b' と変化し、ここで確定ボタンが押されるので、文字 b が出力される。 同じ数字を続けて入力すると変化する文字はループする。すなわち、ボタン 2 を 5 回押して、次にボタン 0 を押すと、文字が 'a' → 'b' → 'c' → 'a' → 'b' と変化し、ここで確定ボタンを押されるから 'b' が出力される。  何もボタンが押されていないときに確定ボタンを押すことはできるが、その場合には何も文字は出力されない。  あなたの仕事は、Alice さんが押したボタンの列から、Alice さんが作ったメッセージを再現することである。

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/python3

def atoi(c):
    return ord(c) - ord('0')

table = [(), #dummy
        ('.',',','!','?'),\
        ('a','b','c'),
        ('d','e','f'),
        ('g','h','i'),
        ('j','k','l'),
        ('m','n','o'),
        ('p','q','r','s'),
        ('t','u','v'),
        ('w','x','y','z')]

n = int(input())
for i in range(n):
    digits = list(input())
    s = ""
    c = ''
    m = 0
    for d in digits:
        if d == '0':
            s += c
            c = ''
            m = 0
        else:
            c = table[atoi(d)][m]
            m = (m + 1) % len(table[atoi(d)])
    print(s)

Fixed, accepted submission:
#!/usr/bin/python3

def atoi(c):
    return ord(c) - ord('0')

table = [(), #dummy
        ('.',',','!','?',' '),\
        ('a','b','c'),
        ('d','e','f'),
        ('g','h','i'),
        ('j','k','l'),
        ('m','n','o'),
        ('p','q','r','s'),
        ('t','u','v'),
        ('w','x','y','z')]

n = int(input())
for i in range(n):
    digits = list(input())
    s = ""
    c = ''
    m = 0
    for d in digits:
        if d == '0':
            s += c
            c = ''
            m = 0
        else:
            c = table[atoi(d)][m]
            m = (m + 1) % len(table[atoi(d)])
    print(s)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
s=input()
c=1
for i in range(0,3):
  if s[i]==1:
    c+=1
    
print(c)

Fixed, accepted submission:
s=input()
c=0
for i in range(0,3):
  if s[i]=="1":
    c+=1
    
print(c)
Problem:
_ButCoder Inc._ runs a programming competition site called _ButCoder_. In this site, a user is given an integer value called rating that represents his/her skill, which changes each time he/she participates in a contest. The initial value of a new user's rating is 0, and a user whose rating reaches K or higher is called _Kaiden_ ("total transmission"). Note that a user's rating may become negative.  Hikuhashi is a new user in ButCoder. It is estimated that, his rating increases by A in each of his odd-numbered contests (first, third, fifth, ...), and decreases by B in each of his even-numbered contests (second, fourth, sixth, ...).  According to this estimate, after how many contests will he become Kaiden for the first time, or will he never become Kaiden?

Incorrect submission (verdict: Wrong Answer):
import math

g,a,b=map(int,input().split())
if g<=a:
  print(1)
else:
  if a<=b:
    print(-1)
  else:
    print(2*math.ceil((g-a)//(a-b))+1)

Fixed, accepted submission:
g,a,b=map(int,input().split())
if g<=a:
  print(1)
else:
  if a<=b:
    print(-1)
  else:
    if (g-a)%(a-b)==0:
      print(2*((g-a)//(a-b))+1)
    else:
      print(2*((g-a)//(a-b)+1)+1)
Problem:
We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.  We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.  At most how many people can sit on the seat?

Incorrect submission (verdict: Wrong Answer):
x,y,z=map(int,input().split())
total=x-z
one_pair=y+z
k=0
while True:
    k+=1
    if total<=one_pair*k:
        break
print(k-1)

Fixed, accepted submission:
x,y,z=map(int,input().split())
total=x-z
one_pair=y+z
k=1
while one_pair*k<total:
    k+=1
if one_pair*k%total==0:
    print(k)
else:
    print(k-1)
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
import math
n = input()
numbers = list(map(int, input().split()))
print(numbers)

s = sum(numbers)
t = math.floor(s/2)

r = 0
for num in numbers:
  r += abs((num - t) * 2)
  
print(r)


Fixed, accepted submission:
# -*- coding: utf-8 -*-
import math
n = input()
numbers = list(map(int, input().split()))

unique_numbers = list(set(numbers))
if len(unique_numbers) == 1:
  print(0)
  exit(0)

min_num = min(numbers)
max_num = max(numbers)

results = []
for i in range(min_num, max_num):
  r = 0
  for num in numbers:
    r += abs((num - i) ** 2)
  results.append(r)

min_r = min(results)
print(min_r)
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=int(input())
print(N**-A)

Fixed, accepted submission:
N=int(input())
A=int(input())
B=N**2-A
print(B)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):


N = int(input())
A = [int(N) for N in input().split()]

for i in range(1, N-1):
    v = A[i]
    j = i - 1
    while(j >=0 and A[j] > v):
        A[j+1] = A[j]
        j -= 1
    A[j+1] = v

Fixed, accepted submission:

N = int(input())
A = [int(a) for a in input().split()]

print((" ").join((str(a) for a in A)))
for i in range(1, N):
    v = A[i]
    j = i - 1
    while(j >=0 and A[j] > v):
        A[j+1] = A[j]
        j -= 1
    A[j+1] = v
    print((" ").join((str(a) for a in A)))
Problem:
Write a program which reads three integers, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
nums = input().split()
a = int( nums[0])
b = int( nums[1])
c = int( nums[2])

if a > b:
    tmp = a
    a = b
    b = tmp
if b > c:
    tmp = b
    b = c
    c = tmp

print( a, b, c)

Fixed, accepted submission:
nums = input().split()
a = int( nums[0])
b = int( nums[1])
c = int( nums[2])

if a > b:
    tmp = a
    a = b
    b = tmp
if b > c:
    tmp = b
    b = c
    c = tmp
if a > b:
    tmp = a
    a = b
    b = tmp

print( a, b, c)
Problem:
Taro's summer vacation starts tomorrow, and he has decided to make plans for it now.  The vacation consists of N days. For each i (1 \leq i \leq N), Taro will choose one of the following activities and do it on the i-th day:    * A: Swim in the sea. Gain a_i points of happiness.   * B: Catch bugs in the mountains. Gain b_i points of happiness.   * C: Do homework at home. Gain c_i points of happiness.  As Taro gets bored easily, he cannot do the same activities for two or more consecutive days.  Find the maximum possible total points of happiness that Taro gains.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

ab = []
for _ in range(n):
    a, b, c = (int(x) for x in input().split())
    ab.append([a, b, c])

dp = [0]*n
memo = -1
memos = -1

for i in range(n):
    for j in range(3):
        if i == 0:
            dp[i] = max(ab[0])
            memos = j
        elif memo != j and dp[i] < dp[i-1]+ab[i][j]:
            dp[i] = dp[i-1]+ab[i][j]
            memos = j
    memo = memos
print(dp)

Fixed, accepted submission:
n=int(input())

ab = []
for _ in range(n):
    a, b, c = (int(x) for x in input().split())
    ab.append([a, b, c])

dp = [[0 for i in range(3)] for j in range(n+1)]

for i in range(n):
    for j in range(3):
        for k in range(3):
            if j != k:
                dp[i+1][k] = max([dp[i+1][k], dp[i][j]+ab[i][k]])

print(max(dp[n]))
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())

print('YES' if a+b >= c else 'NO')

Fixed, accepted submission:
a,b,c = map(int, input().split())

print('Yes' if a+b >= c else 'No')
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
X = []
temp = []

for i in range(N):
    X.append([int(i) for i in input().split()])

for i in X:
    if temp == []:
        if i[0] % 2 == 0 and (i[1] + i[2]) % 2 == 1:
            print("No")
            break
        elif i[0] % 2 == 1 and (i[1] + i[2]) % 2 == 0:
            print("No")
            break
        else:
            if i[1] + i[2] < i[0]:
                print("Yes")
                break
            else:
                print("No")
                break
    else:
        if (i[0]-temp[0]) % 2 == 0 and (abs(i[1]-temp[1])+abs(i[2]-temp[2])) % 2 == 1:
            print("No")
            break
        elif (i[0]-temp[0]) % 2 == 1 and (abs(i[1]-temp[1])+abs(i[2]-temp[2])) % 2 == 0:
            print("No")
            break
        else:
            if abs(i[1]-temp[1])+abs(i[2]-temp[2]) < i[0]-temp[0]:
                print("Yes")
                break
            else:
                print("No")
                break
    temp = i

Fixed, accepted submission:
N = int(input())
X = []
flag = True
dt=0
dx=0
dy=0

for i in range(N):
    X.append([int(i) for i in input().split()])

for i in X:
     dt = abs(i[0] - dt)
     dx = abs(i[1] - dx)
     dy = abs(i[2] - dy)
     if dx + dy > dt:
         flag = False
     elif (dt - dx - dy) % 2 == 1:
         flag = False

if flag == False:
    print("No")
else:
    print("Yes")
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
N=int(input())

if N%2==1:
    print(N//2)

else:
    print(N/2-1)


Fixed, accepted submission:
N=int(input())

if N%2==1:
    print(int(N//2))

else:
    print(int(N/2-1))
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
a = [int(item) for item in input().split()]
seki = a[0] * a[1]
if seki % 2 == 0:
    print('Even')
else:
    print('Odd')

Fixed, accepted submission:
a = int(input().replace(' ', ''))

count = 1
while count < a:
    if a == count * count:
        print('Yes')
        exit()
    count += 1
print('No')
Problem:
There are K pieces of cakes. Mr. Takahashi would like to eat one cake per day, taking K days to eat them all.  There are T types of cake, and the number of the cakes of type i (1 ≤ i ≤ T) is a_i.  Eating the same type of cake two days in a row would be no fun, so Mr. Takahashi would like to decide the order for eating cakes that minimizes the number of days on which he has to eat the same type of cake as the day before.  Compute the minimum number of days on which the same type of cake as the previous day will be eaten.

Incorrect submission (verdict: Wrong Answer):
K,T=map(int,input().split())
a=list(map(int,input().split()))
print(max(a)-(K-max(a))-1,0)

Fixed, accepted submission:
K,T=map(int,input().split())
a=list(map(int,input().split()))
print(max(max(a)-(K-max(a))-1,0))