TnT/CodeNet4Repair huggingface dataset:
Problem:
There is a cave.  The cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.  It is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.  Since it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.    * If you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.  Determine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.

Incorrect submission (verdict: Wrong Answer):
n,m=map(int,input().split())
d={}
for i in range(m):
	x,y=map(int,input().split())
	if x in d:
		d[x].append(y)
	else:
		d[x]=[y]
	if y in d:
		d[y].append(x)
	else:
		d[y]=[x]

parent=[0]*(n+1)
bfs=[1]
visited=set([1])
while len(bfs)!=0:
	x=bfs.pop(0)
	visited.add(x)
	for i in d[x]:
		if i not in visited:
			bfs.append(i)
			parent[i]=x
			visited.add(i)


if len(visited)==n:
	print('YES')
	for i in range(2,n+1):
		print(parent[i])
else:
	print('NO')




Fixed, accepted submission:
n,m=map(int,input().split())
d={}
for i in range(m):
	x,y=map(int,input().split())
	if x in d:
		d[x].append(y)
	else:
		d[x]=[y]
	if y in d:
		d[y].append(x)
	else:
		d[y]=[x]

parent=[0]*(n+1)
bfs=[1]
visited=set([1])
while len(bfs)!=0:
	x=bfs.pop(0)
	visited.add(x)
	for i in d[x]:
		if i not in visited:
			bfs.append(i)
			parent[i]=x
			visited.add(i)


if len(visited)==n:
	print('Yes')
	for i in range(2,n+1):
		print(parent[i])
else:
	print('No')
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
O = list(input())
E = list(input())

ans = []

for i in range(len(E)):
    ans.append(O[i])
    ans.append(E[i])

if len(O) > len(E):
    ans.append(O[-1])
print(ans)

Fixed, accepted submission:
O = list(input())
E = list(input())

ans = []

for i in range(len(E)):
    ans.append(O[i])
    ans.append(E[i])

if len(O) > len(E):
    ans.append(O[-1])
print(''.join(ans))
Problem:
Write a program which calculates the cube of a given integer x.

Incorrect submission (verdict: Wrong Answer):
2**3

Fixed, accepted submission:
num = input()
num = int(num)
print(num**3)
Problem:
あなたはある機械の製造工場で品質管理の責任者をしている． この機械には， 部品として電源とモーターとケーブルが必要である． 製造工場には電源が a 個， モーターが b 個， ケーブルが c 個あり， それぞれ 1 から a まで， a+1 から a+b まで， a+b+1 から a+b+c までの番号が付いている． 困ったことに， 部品の中に故障しているものがあるかもしれない． 工場ではどの部品が故障していてどの部品が正常であるかを知りたい．  そこで， 工場では次の方法で部品を検査した． 電源とモーターとケーブルを１つずつ持ってきてつなぎ， 動作させてみる． このとき， ３つの部品がすべて正常であるときは正しく動作して「合格」とわかる． ３つの中に故障している部品が１つでも入っているときは正しく動作しないので「不合格」とわかる． （工場で作っている機械はとても精密なので， 故障した部品がまざっているのに偶然正しく動作してしまうなどということは起きないのだ．）  あなたには検査結果のリストが渡される． 検査結果のリストの各行には， 検査に使った電源とモーターとケーブルの番号と， 検査が合格だったか不合格だったかが書かれている．  検査結果のリストが与えられたとき， すべての部品を， 検査結果から確実に故障しているとわかる部品と， 確実に正常とわかる部品と， 検査結果からは故障しているとも正常であるとも決まらない部品に分類するプログラムを作成せよ．

Incorrect submission (verdict: Wrong Answer):
for e in iter(input,'0 0 0'):
 d=[2]*-~sum(map(int,e.split()))
 f=[]
 for _ in[0]*int(input()):
  s,t,u,v=map(int,input().split())
  if v:d[s]=d[t]=d[u]=1
  else:f+=[(s,t,u)]
 for s,t,u in f:
  if d[t]*d[u]<2:d[s]=0
  if d[u]*d[s]<2:d[t]=0
  if d[s]*d[t]<2:d[u]=0
 for x in d[1:]:print(x)


Fixed, accepted submission:
for e in iter(input,'0 0 0'):
 d=[2]*-~sum(map(int,e.split()))
 f=[]
 for _ in[0]*int(input()):
  s,t,u,v=map(int,input().split())
  if v:d[s]=d[t]=d[u]=1
  else:f+=[(s,t,u)]
 for s,t,u in f:
  if d[t]*d[u]==1:d[s]=0
  if d[u]*d[s]==1:d[t]=0
  if d[s]*d[t]==1:d[u]=0
 for x in d[1:]:print(x)
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
N = input()

print("ABC" + "N")

Fixed, accepted submission:
N = input()

print("ABC" + N)
Problem:
We have a 3×3 square grid, where each square contains a lowercase English letters. The letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.  Print the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.

Incorrect submission (verdict: Wrong Answer):
A = list(input())
B = list(input())
C = list(input())

print(A[0],B[1],C[2])

Fixed, accepted submission:
A = list(input())
B = list(input())
C = list(input())

print(A[0]+B[1]+C[2])
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
A, B, C = [int(x) for x in input().split()]

if A == 5 and B == 7 and C == 5:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
ABC = [int(x) for x in input().split()]
S = sorted(ABC)

if S[0] == 5 and  S[1] == 5 and  S[2] == 7:
    print('YES')
else:
    print('NO')
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a = input()
a = [int(i)for i in a.split(" ")]
print((a[0] == 5 or a[0] == 7) and (a[1] == 5 or a[1] == 7) and (sum(a) == 17))

Fixed, accepted submission:
a = input()
a = [int(i)for i in a.split(" ")]
print("YES" if (a[0] == 5 or a[0] == 7) and (a[1] == 5 or a[1] == 7) and (sum(a) == 17) else "NO")
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
""" AtCoder """

A, B, C = map(int, input().split())

if C >= A and C >= B:
    print("Yes")
else:
    print("No")


Fixed, accepted submission:
""" AtCoder """

A, B, C = map(int, input().split())

if C >= A and C <= B:
    print("Yes")
else:
    print("No")
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter

w=input()

d=Counter(w)

ans="Yes"

for i in d.values():
  if i%2==0:
    ans="No"
    break

print(ans)

Fixed, accepted submission:
from collections import Counter

w=input()

d=Counter(w)

ans="Yes"

for i in d.values():
  if i%2!=0:
    ans="No"
    break

print(ans)
Problem:
N persons are standing in a row. The height of the i-th person from the front is A_i.  We want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:  Condition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.  Find the minimum total height of the stools needed to meet this goal.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=list(map(int,input().split()))
c=1000000000
for i in range(len(A)):
  base=A[i]
  cc=0
  p=8
  for t in range(0, i):
    if base<A[t]:
      p=6
      break
  if p==6:
    continue
  for t in range(i, len(A)):
    if base>A[t]:
      cc+=base-A[t]
  if c > cc:
    c = cc
print(c)

Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))
base = A[0]
c = 0
for i in range(len(A)):
  if A[i] < base:
    c += base-A[i]
  elif A[i] > base:
    base = A[i]
print(c)
Problem:
Snuke has an empty sequence a.  He will perform N operations on this sequence.  In the i-th operation, he chooses an integer j satisfying 1 \leq j \leq i, and insert j at position j in a (the beginning is position 1).  You are given a sequence b of length N. Determine if it is possible that a is equal to b after N operations. If it is, show one possible sequence of operations that achieves it.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
prob = list(map(int, input().split()))
ans = []
for i in reversed(range(N)):
  boo = False
  for j in reversed(range(i + 1)):
    if prob[j] == j + 1:
      boo = True
      ans.append(j + 1)
      del prob[j]
      break
  if not boo:
    break
if len(ans) == N:
  for x in ans:
    print(x)
else:
  print(-1)

Fixed, accepted submission:
N = int(input())
prob = list(map(int, input().split()))
ans = []
for i in reversed(range(N)):
  boo = False
  for j in reversed(range(i + 1)):
    if prob[j] == j + 1:
      boo = True
      ans.append(j + 1)
      del prob[j]
      break
  if not boo:
    break
if len(ans) == N:
  for x in reversed(ans):
    print(x)
else:
  print(-1)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
A,B,K=map(int,input().split())
K=min(K,B-A)
ans=set()
for i in range(K+1):
    ans.add(A+i)
    ans.add(B-i)
ans=list(ans)
ans=sorted(ans)
for i in ans:
    print(i)

Fixed, accepted submission:
A,B,K=map(int,input().split())
if B==A:
    print(A)
    exit()
K=min(K,B-A)
ans=set()
for i in range(K):
    ans.add(A+i)
    ans.add(B-i)
ans=list(ans)
ans=sorted(ans)
for i in ans:
    print(i)
Problem:
You have an integer variable x. Initially, x=0.  Some person gave you a string S of length N, and using the string you performed the following operation N times. In the i-th operation, you incremented the value of x by 1 if S_i=`I`, and decremented the value of x by 1 if S_i=`D`.  Find the maximum value taken by x during the operations (including before the first operation, and after the last operation).

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = input()
x = 0
max_x = 0
for i in range(N):
    if S[i] == "I":
        x += 1
    else:
        x -= 1
    max_x - max(max_x, x)
print(max_x)


Fixed, accepted submission:
N = int(input())
S = input()
x = 0
max_x = 0
for i in range(N):
    if S[i] == "I":
        x += 1
    else:
        x -= 1
    max_x = max(max_x, x)
print(max_x)
Problem:
We held two competitions: Coding Contest and Robot Maneuver.  In each competition, the contestants taking the 3-rd, 2-nd, and 1-st places receive 100000, 200000, and 300000 yen (the currency of Japan), respectively. Furthermore, a contestant taking the first place in both competitions receives an additional 400000 yen.  DISCO-Kun took the X-th place in Coding Contest and the Y-th place in Robot Maneuver. Find the total amount of money he earned.

Incorrect submission (verdict: Wrong Answer):
X,Y = map(int,input().split())
if X < 4:
  X = X*10000
else:
  None
if Y < 4:
  Y = Y*10000
else:
  None
print(X+Y)

Fixed, accepted submission:
X,Y = map(int,input().split())
if X < 4:
  X = (4-X)*100000
else:
  X = 0
if Y < 4:
  Y = (4-Y)*100000
else:
  Y = 0
if X == 300000 and Y == 300000:
  print(X+Y+400000)
else:
  print(X+Y)
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
c = int(input())
total = int(input())
pattern_num = 0
for i in range(0, a):
    for j in range(0, b):
        for k in range(0, c):
            if i*500+j*100+k*50 == total:
                pattern_num += 1
print (pattern_num)


Fixed, accepted submission:
a = int(input()) + 1
b = int(input()) + 1
c = int(input()) + 1
total = int(input())
pattern_num = 0
for i in range(0, a):
    for j in range(0, b):
        for k in range(0, c):
            if i*500+j*100+k*50 == total:
                pattern_num += 1
print (pattern_num)
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Wrong Answer):
i = 0
while 1:
	i += 1
	test = input()
	if test == "0":
		break
	print("case " + str(i) + ":" + test)

Fixed, accepted submission:
i = 0
while 1:
	i += 1
	test = input()
	if test == "0":
		break
	print("Case " + str(i) + ": " + test)
Problem:
We have N squares assigned the numbers 1,2,3,\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.  How many squares i satisfy both of the following conditions?    * The assigned number, i, is odd.   * The written integer is odd.

Incorrect submission (verdict: Wrong Answer):
'''
5
1 3 4 5 7
'''
lens = int(input())
vals = [int(x) for x in input().split()]
odds = 0
for i in range(lens):
  if i % 2 == 0 and vals[i] % 2 == 0:
    odds += 1
print(odds)    

Fixed, accepted submission:
'''
5
1 3 4 5 7
'''
lens = int(input())
vals = [0] + [int(x) for x in input().split()]
odds = 0
for i in range(1, lens + 1):
    if i % 2 == 1 and vals[i] % 2 == 1:
        odds += 1
print(odds)
Problem:
複線（上りと下りが別の線路になっていてどこででもすれ違える）の鉄道路線があります。この路線には終端駅を含めて11 の駅があり、それぞれの駅と駅の間は図で示す区間番号で呼ばれています。      この路線の両方の終端駅から列車が同時に出発して、途中で停まらずに走ります。各区間の長さと2 本の列車の速度を読み込んで、それぞれの場合について列車がすれ違う区間の番号を出力するプログラムを作成してください。ただし、ちょうど駅のところですれ違う場合は、両側の区間番号のうち小さいほうの数字を出力します。また、列車の長さ、駅の長さは無視できるものとします。

Incorrect submission (verdict: Wrong Answer):
while True:
    try:
        A = list(map(int,input().split(',')))
    except EOFError:
        break
    V1 = A [-2]
    V2 = A [-1]
    del A [-1]
    del A [-1]

    for i in range(len(A)):
        A [i] *= V1 + V2

    point = sum(A) // (V1 + V2) * V1
    print(point)
    for i in range(len(A)):
        if sum(A [0:i + 1]) >= point:
            print(i + 1)
            break

Fixed, accepted submission:
while True:
    try:
        A = list(map(int,input().split(',')))
    except EOFError:
        break
    V1 = A [-2]
    V2 = A [-1]
    del A [-1]
    del A [-1]

    for i in range(len(A)):
        A [i] *= V1 + V2

    point = sum(A) // (V1 + V2) * V1
    for i in range(len(A)):
        if sum(A [0:i + 1]) >= point:
            print(i + 1)
            break
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int, input().split()))
m = 0
while 0 in [a % 2 for a in A]:
    A = [a / 2 for a in A]
    m += 1
print(m)
    

Fixed, accepted submission:
N = int(input())
A = list(map(int, input().split()))
m = 0
while 1 not in [a % 2 for a in A]:
    A = [int(a / 2) for a in A]
    m += 1
print(m)
Problem:
Snuke signed up for a new website which holds programming competitions. He worried that he might forget his password, and he took notes of it. Since directly recording his password would cause him trouble if stolen, he took two notes: one contains the characters at the odd-numbered positions, and the other contains the characters at the even-numbered positions.  You are given two strings O and E. O contains the characters at the odd- numbered positions retaining their relative order, and E contains the characters at the even-numbered positions retaining their relative order. Restore the original password.

Incorrect submission (verdict: Wrong Answer):
O = input()
E = input()
ans = ''
if O>E:
    ans += O[0]
    O = O[1:]
    for o, e in zip(O,E):
        ans += (e + o)
else:
    for o, e in zip(O, E):
        ans += (o + e)
print(ans)


Fixed, accepted submission:
O = input()
E = input()
ans = ''
if len(O) > len(E):
    ans += O[0]
    O = O[1:]
    for o, e in zip(O, E):
        ans += (e + o)
else:
    for o, e in zip(O, E):
        ans += (o + e)
print(ans)
Problem:
Snuke loves puzzles.  Today, he is working on a puzzle using `S`\- and `c`-shaped pieces. In this puzzle, you can combine two `c`-shaped pieces into one `S`-shaped piece, as shown in the figure below:    Snuke decided to create as many `Scc` groups as possible by putting together one `S`-shaped piece and two `c`-shaped pieces.  Find the maximum number of `Scc` groups that can be created when Snuke has N `S`-shaped pieces and M `c`-shaped pieces.

Incorrect submission (verdict: Wrong Answer):
N, M = list(map(int, input().split(" ")))

if 2*N >= M:
    print(N)
else:
    
    while(2*N < M-4):
        N += 1
        M -= 2

    print(N)

Fixed, accepted submission:
N, M = list(map(int, input().split(" ")))

if M < 2:
    print(0)
elif N >= M // 2:
    print(M // 2)
else:
    ans = N
    M -= 2*N
    ans += M // 4
    print(ans)
Problem:
Write a program which calculates the area and perimeter of a given rectangle.

Incorrect submission (verdict: Wrong Answer):





# Input

# Output


# Sample Input
# 3 5
# Sample Output
# 15 16


a,b=map(int,input().split())
# print("a=%d, b=%d."%(a,b))
# a=3
# b=5
print("??¢??????%f ."%(a*b));
print("??¨????????????%f ."%(2*a+2*b));

Fixed, accepted submission:





# Input

# Output


# Sample Input
# 3 5
# Sample Output
# 15 16


a,b=map(int,input().split())
# print("a=%d, b=%d."%(a,b))



print("{0} {1}".format(a*b, 2*a+2*b));
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
sx, sy, tx, ty = map(int, input().split())
ax, ay = tx - sx, ty - sy
print(('R'*ax+'U'*ay)+('D'*ay+'L'*ax)+('D'+'R'*(ax+1)+'U'*(ay+1)+'L')+('U'+'L'*(ax+1)+'D'*(ay+1)+'R'))

Fixed, accepted submission:
U,D,R,L='UDRL';x,y,a,b=map(int,input().split());x,y=a-x,b-y;a,b=x+1,y+1;print(U*y+R*x+D*y+L*a+U*b+R*a+D+R+D*b+L*a+U)
Problem:
Determine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.

Incorrect submission (verdict: Wrong Answer):
n, k = map(int, input().split())
if 2 * k - 1 < n : print("Yes")
else : print("No")

Fixed, accepted submission:
n, k = map(int, input().split())
if 2 * k - 1 <= n : print("YES")
else : print("NO")
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
a,b = map(str,input().split())
import math
print(math.sqrt(int(a)+int(b)))

Fixed, accepted submission:
import numpy as np
a,b = map(str,input().split())
ans = "No"
N =np.sqrt(int(a+b))
if int(N) == N:
    ans ="Yes"
print(ans)
Problem:
You are given an integer N that has exactly four digits in base ten. How many times does `2` occur in the base-ten representation of N?

Incorrect submission (verdict: Wrong Answer):
print(4-input().count('2'))

Fixed, accepted submission:
print(input().count('2'))
Problem:
For a given weighted graph $G = (V, E)$, find the shortest path from a source to each vertex. For each vertex $u$, print the total weight of edges on the shortest path from vertex $0$ to $u$.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
M=[[-1]*n for _ in[0]*n]
for _ in[0]*n:
 e=list(map(int,input().split()))
 for i in range(e[1]):k=2*-~i;M[e[0]][e[k]]=e[k+1]
d=[0]+[1e6]*~-n
c=[1]*n
while 1:
 m,u=1e6,-1
 for i in range(n):
  if m>d[i]and c[i]:m,u=d[i],i
 if u<0:break
 c[u]=0
 for v in range(n):
  if c[v]and 1+M[u][v]and d[v]>d[u]+M[u][v]:
   d[v]=d[u]+M[u][v]
for i in range(i):print(i,d[i])


Fixed, accepted submission:
n=int(input())
M=[[-1]*n for _ in[0]*n]
for _ in[0]*n:
 e=list(map(int,input().split()))
 for i in range(e[1]):k=2*-~i;M[e[0]][e[k]]=e[k+1]
d=[0]+[1e6]*n
c=[1]*n
while 1:
 m,u=1e6,-1
 for i in range(n):
  if m>d[i]and c[i]:m,u=d[i],i
 if u<0:break
 c[u]=0
 for v in range(n):
  if c[v]and 1+M[u][v]and d[v]>d[u]+M[u][v]:
   d[v]=d[u]+M[u][v]
for i in range(n):print(i,d[i])
Problem:
Snuke has N hats. The i-th hat has an integer a_i written on it.  There are N camels standing in a circle. Snuke will put one of his hats on each of these camels.  If there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print `Yes`; otherwise, print `No`.    * The bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.  What is XOR? The bitwise XOR x_1 \oplus x_2 \oplus \ldots \oplus x_n of n non- negative integers x_1, x_2, \ldots, x_n is defined as follows: - When x_1 \oplus x_2 \oplus \ldots \oplus x_n is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if the number of integers among x_1, x_2, \ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even. For example, 3 \oplus 5 = 6.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = list(map(int, input().split()))
s = 1
for i in a:
    s ^= 1
if s == 1:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
n = int(input())
a = list(map(int, input().split()))
s = 1
for i in a:
    s ^= i
if s == 1:
    print('Yes')
else:
    print('No')
Problem:
There are N people numbered 1 to N. Each person wears a red hat or a blue hat.  You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.  Determine if there are more people wearing a red hat than people wearing a blue hat.

Incorrect submission (verdict: Wrong Answer):
s = input()
if s.count("R")>s.count("B"):
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
N=input()
s = input()
if s.count("R")>s.count("B"):
  print("Yes")
else:
  print("No")