TnT/CodeNet4Repair huggingface dataset:
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
def read_plus_1():
    return(int(input())+1)


a = read_plus_1()
b = read_plus_1()
c = read_plus_1()
x = int(input())

count = 0
for i in range(0, a):
    if i * 500 > x:
        continue
    for j in range(0, b):
        if i * 500 + j * 100 > x:
            continue
        for k in range(0, c):
            print(i * 500 + j * 100 + k * 50)
            if i * 500 + j * 100 + k * 50 == x:
                count += 1
                break
print(count)


Fixed, accepted submission:
def read_plus_1():
    return(int(input())+1)


a = read_plus_1()
b = read_plus_1()
c = read_plus_1()
x = int(input())

count = 0
for i in range(0, a):
    if i * 500 > x:
        continue
    for j in range(0, b):
        if i * 500 + j * 100 > x:
            continue
        for k in range(0, c):
            if i * 500 + j * 100 + k * 50 == x:
                count += 1
                break
print(count)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):

#
a,b = map(int,input().split())
if ((a+b)% 2) == 0:
    print("Even")
else:
    print("Odd")

Fixed, accepted submission:

#
a,b = map(int,input().split())
if ((a*b)% 2) == 0:
    print("Even")
else:
    print("Odd")
Problem:
You are given two integers a and b. Determine if a+b=15 or a\times b=15 or neither holds.  Note that a+b=15 and a\times b=15 do not hold at the same time.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
if a+b==15 or a*b==15:
    if a*b==15:
        print("+")
    else:
        print("*")
else:
    print("x")

Fixed, accepted submission:
a,b = map(int,input().split())
if a+b==15 or a*b==15:
    if a*b==15:
        print("*")
    else:
        print("+")
else:
    print("x")
Problem:
We have a board with H horizontal rows and W vertical columns of squares. There is a bishop at the top-left square on this board. How many squares can this bishop reach by zero or more movements?  Here the bishop can only move diagonally. More formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:    * r_1 + c_1 = r_2 + c_2   * r_1 - c_1 = r_2 - c_2  For example, in the following figure, the bishop can move to any of the red squares in one move:  

Incorrect submission (verdict: Wrong Answer):
h,w = map(int,input().split())
if h %2 == 0:
    print(h*w /2)
else:
    tmp = (h+1)/2
    tmp1 = (h-1)/2
    if w %2 == 0:
        print((tmp+tmp1)*w/2)
    else:
        print(int((tmp+tmp1)*(w-1)/2 + tmp))

Fixed, accepted submission:
h,w = map(int,input().split())
if w == 1:
    print(int(1))
elif h == 1:
    print(int(1))
else:
    if h %2 == 0:
        print(int(h*w /2))
    else:
        tmp = (h+1)/2
        tmp1 = (h-1)/2
        if w %2 == 0:
            print(int(h*w/2))
        else:
            print(int(h*(w-1)/2 +tmp))
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):

def main():
    s = list(input())
    tmp = ''
    n_tmp=""
    max_s = len(s)
    cnt = 0
    flag = True
    while cnt < max_s:

        for i in range(cnt,cnt+5):
            tmp += s[i]
        if cnt +10 > max_s:
            for i in s[cnt+5:]:
                tmp += i
            if tmp == "dreamer" or tmp == "eraser":
                break
            else:
                flag = False
                break
        else:
            for j in range(cnt+5,cnt+10):
                n_tmp += s[j]
        if (tmp == "dream" or tmp == "erase") and (n_tmp == "dream" or n_tmp =="erase"):
            tmp = ""
            n_tmp = ""
            cnt += 5
        elif tmp == "dream" and (n_tmp=="erdre" or n_tmp == "erera"):
            tmp=""
            n_tmp=""
            cnt += 7
        elif tmp =="erase" and (n_tmp == "erdre" or n_tmp == "erera"):
            tmp=""
            n_tmp=""
            cnt += 6
        if len(s) - cnt <= 7:
            tmp = ""
            for i in s[cnt:]:
                tmp += i
            if tmp == "dream" or tmp == "dreamer" or tmp == "erase" or tmp == "eraser":
                break
            else:
                flag = False
                break
        flag = False
        break

    if flag:
        print('Yes')
    else:
        print('No')
if __name__ == '__main__':
    main()

Fixed, accepted submission:
import re
def main():
    s = input()
    pattern = "^(dream|dreamer|erase|eraser)+$"
    if re.match(pattern,s):
        print('YES')
    else:
        print('NO')

if __name__ == '__main__':
    main()
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a, b, x = map(int,input().split())
print((b-a)//x)

Fixed, accepted submission:
a, b, x = map(int,input().split())
print(b//x-(a-1)//x)
Problem:
Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:  \\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]  where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Incorrect submission (verdict: Wrong Answer):
n, m, l = map(int, input().split())
A = [list(map(int, input().split())) for i in range(n)]
B = [list(map(int, input().split())) for i in range(m)]
Sum = []
key = 0
for i in range(n):
    Sum_s = []
    for j in range(l):
        key = 0
        for k in range(m):
            key += A[i][k] * B[k][j]
        Sum_s.append(key)
    Sum.append(Sum_s)
print(Sum)
for i in range(n):
    for j in range(l - 1):
        print(Sum[i][j], end = ' ')
    print(Sum[i][l - 1])



Fixed, accepted submission:
n, m, l = map(int, input().split())
A = [list(map(int, input().split())) for i in range(n)]
B = [list(map(int, input().split())) for i in range(m)]
Sum = []
key = 0
for i in range(n):
    Sum_s = []
    for j in range(l):
        key = 0
        for k in range(m):
            key += A[i][k] * B[k][j]
        Sum_s.append(key)
    Sum.append(Sum_s)
for i in range(n):
    for j in range(l - 1):
        print(Sum[i][j], end = ' ')
    print(Sum[i][l - 1])
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int,input().split())
k = int(input())

m = a
count = 0
if b>m:
    m=b
    count=1
if c>m:
    m=c
    count=2

if count==0:
    print(a**k+b+c)
if count==1:
    print(a+b**k+c)
if count==2:
    print(a+b+c**k)


Fixed, accepted submission:
a,b,c = map(int,input().split())
k = int(input())

m = a
count = 0
if b>m:
    m=b
    count=1
if c>m:
    m=c
    count=2

if count==0:
    print(a*2**k+b+c)
if count==1:
    print(a+b*2**k+c)
if count==2:
    print(a+b+c*2**k)
Problem:
You are given three strings A, B and C. Each of these is a string of length N consisting of lowercase English letters.  Our objective is to make all these three strings equal. For that, you can repeatedly perform the following operation:    * Operation: Choose one of the strings A, B and C, and specify an integer i between 1 and N (inclusive). Change the i-th character from the beginning of the chosen string to some other lowercase English letter.  What is the minimum number of operations required to achieve the objective?

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = (input())
c = (input())
d = (input())
count = 0
for i in range(a):
    if b[i] == c[i] == d[i]:
        count += 0
    elif b[i] == c[i] or b[i] == d[i] == c[i] == d[i]:
        count += 1
    else:
        count += 2
print(count)


Fixed, accepted submission:
a = int(input())
b = (input())
c = (input())
d = (input())
count = 0
for i in range(a):
    if b[i] == c[i] == d[i]:
        count += 0
    elif b[i] == c[i] or b[i] == d[i]  or  c[i] == d[i]:
        count += 1
    else:
        count += 2
print(count)
Problem:
AtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W. If we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of   AtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle. Find the minimum distance it needs to be moved.

Incorrect submission (verdict: Wrong Answer):
w,a,b = map(int, input().split())
if a==b:
  print(0)
elif min(a,b)+w >= max(a,b):
  print(0)
elif min(a,b)+w < max(a,b):
  print(max(a,b)-min(a,b)+w)


Fixed, accepted submission:
w,a,b = map(int, input().split())
if a==b:
  print(0)
elif min(a,b)+w >= max(a,b):
  print(0)
elif min(a,b)+w < max(a,b):
  print(max(a,b)-min(a,b)-w)
Problem:
In a public bath, there is a shower which emits water for T seconds when the switch is pushed.  If the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds. Note that it does not mean that the shower emits water for T additional seconds.  N people will push the switch while passing by the shower. The i-th person will push the switch t_i seconds after the first person pushes it.  How long will the shower emit water in total?

Incorrect submission (verdict: Wrong Answer):
n,t=map(int,input().split())

Fixed, accepted submission:
n,T=map(int,input().split())
t=list(map(int,input().split()))
ts=[]
tf=[]
ts.append(t[0])
tb=t[0]
for i in t:
  if(i>tb+T):
    tf.append(tb+T)
    ts.append(i)
  tb=i
tf.append(t[-1]+T)
time=0
#print(ts)
#print(tf)
for i in range(len(ts)):
  time+=tf[i]-ts[i]
print(time)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
def iroha():
    A, B, C = map(int, input().split())
    S = A + B + C
    if S == 17:
        print("YES")
    else:
        print("NO")


Fixed, accepted submission:
def iroha():
    A, B, C = map(int, input().split())
    S = A + B + C
    if S == 17:
        print("YES")
    else:
        print("NO")


if __name__ == "__main__":
    iroha()
Problem:
You are given a string S of length N consisting of lowercase English letters, and an integer K. Print the string obtained by replacing every character in S that differs from the K-th character of S, with `*`.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
s=input()
k=int(input())
d=s[k-1]
for a in s:
  if a!=d:
    a='*'
print(s)

Fixed, accepted submission:
n=int(input())
s=input()
k=int(input())
d=s[k-1]
s_list=list(s)
for a in range(n):
  if s[a] != d:
    s_list[a]="*"
s2="".join(s_list)
print(s2)
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int, input().split())

if a+b<x:
  print('No')
else:
  print('Yes')

Fixed, accepted submission:
a,b,x = map(int,input().split())
if a > x or a + b < x:
  print("NO")
else:
  print("YES")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
list1 = []
dict1 = {}
for x in range(a):
    b = input()
    list1.append(b)

for x in list1:
    if x not in dict1:
        dict1[x] = 1
    else:
        dict1[x] += 1

for x in dict1:
    print(f'{x} x {dict1[x]}')

Fixed, accepted submission:
a = int(input())
list1 = []
dict1 = {'AC': 0, 'WA': 0, 'TLE': 0, 'RE': 0,}
for x in range(a):
    b = input()
    list1.append(b)

for x in list1:
    dict1[x] += 1

for x in dict1:
    print(f'{x} x {dict1[x]}')
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):

n,m,x,y = map(int,input().split())
x = list(map(int,input().split()))
y = list(map(int,input().split()))

x.sort()
y.sort()

#print(x)
#print(y)

distance = y[0] - x[-1]

if distance > 1:
    print("No War")
else:
    print("War")


Fixed, accepted submission:

n,m,x,y = map(int,input().split())
X = list(map(int,input().split()))
Y = list(map(int,input().split()))
X.append(x)
Y.append(y)
X.sort()
Y.sort()

for i in range(-100,100):
    if X[-1] < i <= Y[0]:
        print("No War")
        exit()

print("War")
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
c = a * b
if c % 2 == 0:
  print("Odd")
elif c % 2 == 1:
  print("Even")

Fixed, accepted submission:
a, b = map(int, input().split())
c = a * b
if c % 2 == 0:
  print("Even")
else:
  print("Odd")
Problem:
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.  All strings that can be obtained in this way can be evaluated as formulas.  Evaluate all possible formulas, and print the sum of the results.

Incorrect submission (verdict: Wrong Answer):
import sys
import itertools

s = sys.stdin.readline().rstrip()
n = len(s)


ans = 0
for i in range(n):
    combs = list(map(list, itertools.combinations(range(1, n), i)))
    res2 = 0
    for c in combs:
        c.insert(0, 0); c.append(n)
        print(c)
        res1 = 0
        for j in range(1, i+2):
            res1 += int(s[c[j-1]:c[j]])
            print(int(s[c[j-1]:c[j]]))
        res2 += res1
    ans += res2

print(ans)

Fixed, accepted submission:
import sys

s = sys.stdin.readline().rstrip()
n = len(s)

def c(n):
    return pow(2, max(0, n - 1))
  
def main():
    res = 0
    for l in range(n):
        for r in range(l, n):
            res += int(s[l:r+1]) * c(l) * c(n - 1 - r)
    print(res)

if __name__ ==  '__main__':
    main()
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,k=map(int,input().split())
for i in range(a,a+k+1):
  print(i)
for i in range(b-k+1,b+1):
  print(i)

Fixed, accepted submission:
a,b,k=map(int,input().split())
l=[]
for i in range(a,min(b+1,a+k)):
  l.append(i)
for i in range(max(a,b-k+1),b+1):
  l.append(i)
for x in  sorted(set(l)):
  print(x)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
a = list(input())
b = list(input())
if a[0] == a[2] and b[0] == b[2]:
    print('YES')
else:
    print('NO')

Fixed, accepted submission:
a = list(input())
b = list(input())
if a[0] == b[2] and b[0] == a[2] and a[1]==b[1]:
    print('YES')
else:
    print('NO')
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math
x=int(input())
n=0
start=100
while True:
    n+=1
    start+=start/100
    start=math.floor(start)
    if start>=x:
        print(start)
        print(n)
        break

Fixed, accepted submission:
import math
x=int(input())
n=0
start=100
while True:
    n+=1
    start+=start/100
    start=math.floor(start)
    if start>=x:
        print(n)
        break
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
def main():
    N = int(input())
    A = list(map(int, input().split()))
    c = 0
    while True:
        for i in range(N):
            if A[i] % 2 == 1:
                return c
            else:
                A[i] = A[i] // 2
        c += 1

main()

Fixed, accepted submission:
def main():
    N = int(input())
    A = list(map(int, input().split()))
    c = 0
    while True:
        for i in range(N):
            if A[i] % 2 == 1:
                print(c)
                return
            else:
                A[i] = A[i] // 2
        c += 1

main()
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
input()
A = list(map(int, input().split()))

A.sort()
minval = A[0]
count = 0

while minval % 2 == 0:
  minval /= 2
  count += 1
  
print(count)

Fixed, accepted submission:
input()
A = list(map(int, input().split()))

count = 0
while all(a % 2 == 0 for a in A):
  A = [a / 2 for a in A]
  count += 1
  
print(count)
Problem:
Sitting in a station waiting room, Joisino is gazing at her train ticket.  The ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).  In the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with `+` or `-` so that the formula holds.  The given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.

Incorrect submission (verdict: Wrong Answer):
from itertools import product
S = input()

for string in product(["+","-"],repeat = 3):
    string = list(string)
    string.append("")
    sum_ = [a + b for a,b in zip(S,string)]
    if eval("".join(sum_)) == 7:
        print("".join(sum_),"=7")
        break

Fixed, accepted submission:
from itertools import product
S = input()

for string in product(["+","-"],repeat = 3):
    string = list(string)
    string.append("")
    sum_ = [a + b for a,b in zip(S,string)]
    if eval("".join(sum_)) == 7:
        print("".join(sum_)+"=7")
        break
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
abc = list(map(int, input().split()))
abc.sort()
print(abc[-1]+abc[-2])

Fixed, accepted submission:
abc = list(map(int, input().split()))
abc.sort()
print(abc[0]+abc[1])
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
numbers=sorted(list(map(int,input().split())))
if numbers == [5,7,7]:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
numbers=sorted(list(map(int,input().split())))
if numbers == [5,5,7]:
  print("YES")
else:
  print("NO")
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = list(input() for _ in range(n))
print("AC × " + str(s.count("AC")))
print("WA × " + str(s.count("WA")))
print("TLE × " + str(s.count("TLE")))
print("RE × " + str(s.count("RE")))

Fixed, accepted submission:
n = int(input())
s = list(input() for _ in range(n))
print("AC x " + str(s.count("AC")))
print("WA x " + str(s.count("WA")))
print("TLE x " + str(s.count("TLE")))
print("RE x " + str(s.count("RE")))
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math as M
a = int(input())
print(M.ceil(M.log(a / 100,  1.1)))


Fixed, accepted submission:
import math as M
a = int(input())
n = 0

while a > 100 :
    a = M.ceil(a / 1.01)
    n += 1
print(n)
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
sentence = input()
new_sent = sentence.split(" ")
acro = ""
for i in range(len(new_sent)):
  acro += new_sent[i]
print(acro)

Fixed, accepted submission:
sentence = input()
new_sent = sentence.split(" ")
acro = ""
for i in new_sent:
  acro += i[0]
print(acro)