TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
a,b,x = map(int,input().split())
ans = 0
for i in range(a,b):
    if i % x ==0:
        ans += 1
print(ans)

Fixed, accepted submission:
a,b,x = map(int,input().split())
print((b//x)-((a-1)//x))
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
if __name__ == "__main__":
    a = int(input())
    b = int(input())
    h = int(input())
    print((a+b)*h/2)

Fixed, accepted submission:
if __name__ == "__main__":
    a = int(input())
    b = int(input())
    h = int(input())
    print(int((a+b)*h/2))
Problem:
Write a program which converts uppercase/lowercase letters to lowercase/uppercase for a given string.

Incorrect submission (verdict: Wrong Answer):
s=input()
for c in s:
  if 'A' <= c and c <= 'Z':
    print(c.lower(), end='')
  elif 'a' <= c and c <= 'z':
    print(c.upper(), end='')
  else:
    pass


Fixed, accepted submission:
s=input()
for c in s:
  if 'A' <= c and c <= 'Z':
    print(c.lower(), end='')
  elif 'a' <= c and c <= 'z':
    print(c.upper(), end='')
  else:
    print(c,end='')
print()
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())
a = N % 500
if a == 0:
    print("yes")
else:
    if a <= A:
        print("yes")
    else:
        print("no")


Fixed, accepted submission:
N = int(input())
A = int(input())
a = N % 500
if a == 0:
    print("Yes")
else:
    if a <= A:
        print("Yes")
    else:
        print("No")
Problem:
You are given an undirected connected graph with N vertices and M edges that does not contain self-loops and double edges.   The i-th edge (1 \leq i \leq M) connects Vertex a_i and Vertex b_i.  An edge whose removal disconnects the graph is called a _bridge_.   Find the number of the edges that are bridges among the M edges.

Incorrect submission (verdict: Wrong Answer):
from collections import deque
N, M = map(int, input().split())

ab = [list(map(int, input().split())) for _ in range(M)]
c = 0
print(ab)
for i in range(M):
    G = [[] for _ in range(N)]
    for j in range(M):
        if i == j:
            continue
        a, b = ab[j][0], ab[j][1]
        G[a - 1].append(b - 1)
        G[b - 1].append(a - 1)
    Q = deque()
    Q.append(0)
    d = [0] * N
    d[0] = 1
    while Q:
        q = Q.popleft()
        for g in G[q]:
            if d[g] == 0:
                d[g] = 1
                Q.append(g)
    if 0 in d:
        c += 1

print(c)


Fixed, accepted submission:
from collections import deque
N, M = map(int, input().split())

ab = [list(map(int, input().split())) for _ in range(M)]
c = 0
for i in range(M):
    G = [[] for _ in range(N)]
    for j in range(M):
        if i == j:
            continue
        a, b = ab[j][0], ab[j][1]
        G[a - 1].append(b - 1)
        G[b - 1].append(a - 1)
    Q = deque()
    Q.append(0)
    d = [0] * N
    d[0] = 1
    while Q:
        q = Q.popleft()
        for g in G[q]:
            if d[g] == 0:
                d[g] = 1
                Q.append(g)
    if 0 in d:
        c += 1

print(c)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin
def stdinput():
    return stdin.readline().strip()

def main():
    n = int(stdinput())
    a = list(map(int, stdinput().split()))

    for i in range(1, n):
        v = a[i]
        j = i - 1
        while j >= 0 and a[j] > v:
            a[j+1] = a[j]
            j -= 1
        a[j + 1] = v
        print(' '.join(map(str, a)))

if __name__ == '__main__':
    main()


Fixed, accepted submission:
from sys import stdin
def stdinput():
    return stdin.readline().strip()

def main():
    n = int(stdinput())
    a = list(map(int, stdinput().split()))

    for i in range(0, n):
        v = a[i]
        j = i - 1
        while j >= 0 and a[j] > v:
            a[j+1] = a[j]
            j -= 1
        a[j + 1] = v
        print(' '.join(map(str, a)))

if __name__ == '__main__':
    main()
Problem:
On some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in `yyyy/mm/dd` format. For example, January 23, 2018 should be written as `2018/01/23`.  After finishing the document, she noticed that she had mistakenly wrote `2017` at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to `2018` and prints it.

Incorrect submission (verdict: Wrong Answer):
s=input()
s="2018"+s[:4]

Fixed, accepted submission:
s=input()
s="2018"+s[4:]
print(s)
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
for i in range(3000):
  x,y=map(int,input().split())
  if x == 0 and y == 0:
   break
  print('{0} {1}'.format(x,y))

Fixed, accepted submission:
for i in range(3000):
  x,y=map(int,input().split())
  if x == 0 and y == 0:
    break
  print('{0} {1}'.format(min(x,y),max(x,y)))
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Time Limit Exceeded):
n=int(input())
ans=1
while(ans<=n):
    ans*2
print(ans//2)

Fixed, accepted submission:
n=int(input())
ans=1
while ans<=n:
    ans*=2
print(ans//2)
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
import math
N=int(input())
L=int(math.log(N,2))
print(2**L)

Fixed, accepted submission:
print('ABC'+input())
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
import sys

sys.setrecursionlimit(10 ** 6)
input = sys.stdin.readline
int1 = lambda x: int(x) - 1

def main():
    n=int(input())
    a=int(input())
    if a<=n%500:
        print("Yes")
    else:
        print("No")

main()

Fixed, accepted submission:
import sys

sys.setrecursionlimit(10 ** 6)
input = sys.stdin.readline
int1 = lambda x: int(x) - 1

def main():
    n=int(input())
    a=int(input())
    if a>=n%500:
        print("Yes")
    else:
        print("No")

main()
Problem:
There are K pieces of cakes. Mr. Takahashi would like to eat one cake per day, taking K days to eat them all.  There are T types of cake, and the number of the cakes of type i (1 ≤ i ≤ T) is a_i.  Eating the same type of cake two days in a row would be no fun, so Mr. Takahashi would like to decide the order for eating cakes that minimizes the number of days on which he has to eat the same type of cake as the day before.  Compute the minimum number of days on which the same type of cake as the previous day will be eaten.

Incorrect submission (verdict: Wrong Answer):
k,t =map(int,input().split())
a = list(map(int,input().split()))
a.append(0)
a.sort()
t = a[-1]
s = sum(a[:-1])
if t == 1:
    print(t-1)
else:
    print(t-s)

Fixed, accepted submission:
k,f =map(int,input().split())
a = list(map(int,input().split()))
a.append(0)
a.sort()
t = a[-1]
s = sum(a[:-1])
if 1 == f:
    print(t-1)
elif t<=s:
    print(0)
else:
    print(t-s-1)
Problem:
There are N integers, A_1, A_2, ..., A_N, written on a blackboard.  We will repeat the following operation N-1 times so that we have only one integer on the blackboard.    * Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.  Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = list(map(int,input().split()))

A = sorted(A)

for i in range(N-1):
    print(A[0],A[-1])
    diff = A[0]-A[-1]
    A = A[1:len(A)-1]
    A.insert(0,diff)

Fixed, accepted submission:
N = int(input())
A = list(map(int,input().split()))

A = sorted(A)
plus = []
minus = []

for i in range(N):
    if i == 0:
        minus.append(A[i])
    elif i == N-1:
        plus.append(A[i])
    else:
        if A[i] > 0:
            plus.append(A[i])
        else:
            minus.append(A[i])

print(sum(plus)-sum(minus))
tmp = minus[0]
for i in range(len(plus)-1):
    print(tmp,plus[i])
    tmp -= plus[i]

minus[0] = tmp
tmp2 = plus[-1]
for i in range(len(minus)):
    print(tmp2,minus[i])
    tmp2 -= minus[i]
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
div = ['maerd', 'remaerd', 'esare', 'resare']
s = input()
rs = ''.join(list(reversed(s)))

can1 = True
cnt = 0
for i in range(len(s)):
    if cnt != 0:
        cnt -= 1
        continue
    print(i)
    can2 = False 
    for d in range(len(div)):
        if (rs.find(div[d])) == i:
            can2 = True
            cnt = len(div[d]) -1
    if can2 == False:
        can1 = False

if can1:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
import re
print("YES" if re.match("^(dream|dreamer|erase|eraser)+$",input()) else "NO")
Problem:
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.  She will concatenate all of the strings in some order, to produce a long string.  Among all strings that she can produce in this way, find the lexicographically smallest one.  Here, a string s=s_1s_2s_3...s_n is _lexicographically smaller_ than another string t=t_1t_2t_3...t_m if and only if one of the following holds:    * There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.   * s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.

Incorrect submission (verdict: Wrong Answer):
A = list(map(str, input().split()))
A.sort()

res = ''
for a in A:
    res += a

print(res)


Fixed, accepted submission:
N, L = list(map(int, input().split()))

input_str_list = []
for input_str_index in range(N):
    input_str_list.append(input())

input_str_list.sort()

print(''.join(input_str_list))
Problem:
Snuke has a favorite restaurant.  The price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.  So far, Snuke has ordered N meals at the restaurant. Let the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen. Find x-y.

Incorrect submission (verdict: Wrong Answer):
e = int(input())
print(int(e/15))
print(e*800 - (int(e/15)*200))

Fixed, accepted submission:
e = int(input())
print(e*800 - (int(e/15)*200))
Problem:
You are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:    * Choose two among A, B and C, then increase both by 1.   * Choose one among A, B and C, then increase it by 2.  It can be proved that we can always make A, B and C all equal by repeatedly performing these operations.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())


M = max(a, max(b, c))

if (a+b+c)%2 == 1:
    X = M
else:
    X = M + 1


print((3*X - (a+b+c)) / 2)

Fixed, accepted submission:
a, b, c = map(int, input().split())


X = 0

M = max(a, max(b, c))
if (3*M)%2 == (a+b+c)%2:
    X = M
else:
    X = M + 1

print(int((3*X - (a+b+c)) / 2))
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
print(n % 1000)

Fixed, accepted submission:
n = int(input())
oturi = n % 1000
if (oturi == 0):
	print(0)
else:
	print(1000 - oturi)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

n = int(input())

result = n % 1000

print(result)


Fixed, accepted submission:

n = int(input())
print((1000 - (n % 1000)) % 1000)
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):

for i in range(1000):
    
    a, b, c = input().split()
    
    if b == '?': break
    
    a = int(a)
    c = int(c)
    
    print(a, b, c)







Fixed, accepted submission:

for i in range(1000):
    
    a, b, c = input().split()
    
    if b == '?': break
    
    a = int(a)
    c = int(c)
    
    if b == '+': print(a + c)
    if b == '-': print(a - c)
    if b == '*': print(a * c)
    if b == '/': print(a // c)
Problem:
You are given a image with a height of H pixels and a width of W pixels. Each pixel is represented by a lowercase English letter. The pixel at the i-th row from the top and j-th column from the left is a_{ij}.  Put a box around this image and output the result. The box should consist of `#` and have a thickness of 1.

Incorrect submission (verdict: Wrong Answer):
H,W = map(int,input().split())
print("#"*W)
for i in range(H-2):
  print("#" + input() + "#")
print("#"*W)

Fixed, accepted submission:
H,W = map(int,input().split())
print("#"*(W+2))
for i in range(H):
  print("#" + input() + "#")
print("#"*(W+2))
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
K = int(input())

A = 1 + ( N * K )
print(A)

Fixed, accepted submission:
N = int(input())
K = int(input())
number = 1

for i in range(N):
    if number * 2 < number + K:
        number = number * 2
    else:
        number = number + K

print(number)
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())
B=N*N-A*A
print(B)

Fixed, accepted submission:
N = int(input())
A = int(input())
B=N*N-A
print(B)
Problem:
There is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.  Snuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).  Then, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:    * If a_i = 1, he painted the region satisfying x < x_i within the rectangle.   * If a_i = 2, he painted the region satisfying x > x_i within the rectangle.   * If a_i = 3, he painted the region satisfying y < y_i within the rectangle.   * If a_i = 4, he painted the region satisfying y > y_i within the rectangle.  Find the area of the white region within the rectangle after he finished painting.

Incorrect submission (verdict: Wrong Answer):
W,H,N=map(int, input().split())
b=0
c=W
d=0
e=H
for i in range(N):
 x,y,a=map(int, input().split())
 if a==1:
  b==max(b,x)
 elif a==2:
  c==min(c,x)
 elif a==3:
  d==max(d,y)
 else:
  e==min(e,y)
print(max(0,(c-b))*max(0,(e-d)))


Fixed, accepted submission:
W,H,N=map(int, input().split())
w=0
h=0
for i in range(N):
 x,y,a=map(int, input().split())
 if a==1:
  w=max(w,x)
 elif a==2:
  W=min(W,x)
 elif a==3:
  h=max(h,y)
 else:
  H=min(H,y)
print(max(0,(W-w))*max(0,(H-h)))
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
print((int(input())+int(input()))+int(input())//2)


Fixed, accepted submission:
print((int(input())+int(input()))*int(input())//2)
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):
R,G,B,N = map(int, input().split())
c = 0
for i in range(int(N/R)):
    for j in range(int((N-R*i)/G)):
        for k in range(int((N-R*i-G*j)/B)):
            if N-R*i-G*j-B*k-int(N-R*i-G*j-B*k) == 0:
                c += 1
print(c)

Fixed, accepted submission:
R,G,B,N = map(int, input().split())
c = 0
for i in range(0,int(N/R)+1):
    for j in range(0,int((N-R*i)/G)+1):
        if (N-R*i-G*j)%B == 0:
            c += 1
print(c)
Problem:
AtCoDeer the deer has N cards with positive integers written on them. The number on the i-th card (1≤i≤N) is a_i. Because he loves big numbers, he calls a subset of the cards _good_ when the sum of the numbers written on the cards in the subset, is K or greater.  Then, for each card i, he judges whether it is _unnecessary_ or not, as follows:    * If, for any good subset of the cards containing card i, the set that can be obtained by eliminating card i from the subset is also good, card i is unnecessary.   * Otherwise, card i is NOT unnecessary.  Find the number of the unnecessary cards. Here, he judges each card independently, and he does not throw away cards that turn out to be unnecessary.

Incorrect submission (verdict: Time Limit Exceeded):
import sys

N, K = map(int, input().split())
a = list(map(int, input().split()))

def isNecessary(now) :
    psum = 0
    for i in range(N) :
        if i == now :
            continue
        psum += a[i]
        if psum >= K :
            return False
    else :
        return True

S = sum(a)
ans = 0
a = sorted(a, reverse=True)
l, r = 0, N-1
now = N//2
while True :
    if isNecessary(now) :
        r = now
    else :
        l = now
    now = (l+r)//2
    if r == l :
        if N==1 and a[0]<K :
            print(1)
        else :
            print(r)

Fixed, accepted submission:
N, K = map(int, input().split())
a = list(map(int, input().split()))

a = sorted(a)
ans = N
psum = 0
for i in range(N-1, -1, -1) :
    if psum+a[i] < K :
        psum += a[i]
    else :
        ans = min(ans, i)

print(ans)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A = int(input())

if N % 500 == A:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
N = int(input())
A = int(input())
 
if N % 500 <= A:
    print('Yes')
else:
    print('No')
Problem:
Your task is to simulate a flood damage.  For a given cross-section diagram, reports areas of flooded sections.         Assume that rain is falling endlessly in the region and the water overflowing from the region is falling in the sea at the both sides. For example, for the above cross-section diagram, the rain will create floods which have areas of 4, 2, 1, 19 and 9 respectively.

Incorrect submission (verdict: Wrong Answer):

lines = input()
stack_1 = []

area = 0
for i, line in enumerate(lines):
    if line == '\\':
        stack_1.append(i)
    elif line == '_':
        pass
    elif line == '/':
        if not stack_1 == []:
            this_area = i - stack_1.pop()
            area += this_area
    else:
        raise ValueError('Unexpected line: {i}, {line}')
print(area)



Fixed, accepted submission:
lines = input()
stack_1 = []
stack_2 = []

area = 0
for i, line in enumerate(lines):
    if line == '\\':
        stack_1.append(i)
    elif line == '_':
        pass
    elif line == '/':
        if stack_1 == []:
            continue
        last_index = stack_1.pop()
        this_area = i - last_index
        area += this_area

        if stack_2 == []:
            stack_2.append((last_index, this_area))
            continue

        block_area = this_area
        while True:
            if stack_2 == []:
                break
            stack_2_index, stack_2_area = stack_2.pop()
            if stack_2_index < last_index:
                stack_2.append((stack_2_index, stack_2_area))
                break
            else:
                block_area += stack_2_area
        stack_2.append((last_index, block_area))

print(area)
kazu = len(stack_2)
kaku_menseki = [stack_2[i][1] for i in range(len(stack_2))]
kaku_menseki_out = ' '.join(map(str, kaku_menseki))
if kazu > 0:
    print(f'{kazu} {kaku_menseki_out}')
else:
    print(f'{kazu}')
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
S = input()
ans = ""
for i in S:
  if i == "B":
    S = S[:-1]
  else:
    ans += i
print(ans)

Fixed, accepted submission:
S = input()
ans = ""
for i in S:
  if i == "B":
    ans = ans[:-1]
  else:
    ans += i
print(ans)