TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

def area():
    return (a+b)*h/2

print(area())

Fixed, accepted submission:
list = []

for i in range(3):
    list.append(int(input()))

area = (list[0]+list[1])*list[2]/2


print(int(area))
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
import math
if math.floor(N*(100/108))+1<float((N+1)*(100/108)):
    print(math.floor(math.floor(N*(100/108))+1))
else:
  print(':(')

Fixed, accepted submission:
import math
N=int(input())
c=math.ceil(N*100/108)
f=((N+1)*100/108)
if c<f:
    print(c)
else:
    print(":(")
Problem:
We have a canvas divided into a grid with H rows and W columns. The square at the i-th row from the top and the j-th column from the left is represented as (i, j).   Initially, all the squares are white. square1001 wants to draw a picture with black paint. His specific objective is to make Square (i, j) black when s_{i, j}= `#`, and to make Square (i, j) white when s_{i, j}= `.`.   However, since he is not a good painter, he can only choose two squares that are horizontally or vertically adjacent and paint those squares black, for some number of times (possibly zero). He may choose squares that are already painted black, in which case the color of those squares remain black.   Determine if square1001 can achieve his objective.

Incorrect submission (verdict: Wrong Answer):
h, w = map(int, input().split())
S = []
flag = True
for i in range(h):
    r = list(input())
    S.append(r)
for i in range(0,h-1):
    for j in range(0,w-1):
        if S[i][j]=='#' and S[i-1][j]=='.' and S[i][j-1]=='.' and S[i+1][j]=='.' and S[i][j+1]=='.':
            flag = False
print(flag)

Fixed, accepted submission:
h, w = map(int, input().split())
S = []
flag = True
for i in range(h):
    r = list(input())
    S.append(r)
for i in range(0,h-1):
    for j in range(0,w-1):
        if S[i][j]=='#' and S[i-1][j]=='.' and S[i][j-1]=='.' and S[i+1][j]=='.' and S[i][j+1]=='.':
            flag = False
if flag:
    print('Yes')
else:
    print('No')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

ac = 0
wa = 0
tle = 0
re = 0

for i in range(n):
    s = input()
    if s == "AC":
        ac += 1
    elif s == "WA":
        wa += 1
    elif s == "TLE":
        tle += 1
    else:
        re += 1
print("AC ×" + str(ac))
print("WA ×" + str(wa))
print("TLE ×" + str(tle))
print("RE ×" + str(re))


Fixed, accepted submission:
n = int(input())

ac = 0
wa = 0
tle = 0
re = 0

for i in range(n):
    s = input()
    if s == "AC":
        ac += 1
    elif s == "WA":
        wa += 1
    elif s == "TLE":
        tle += 1
    else:
        re += 1
print("AC x " + str(ac))
print("WA x " + str(wa))
print("TLE x " + str(tle))
print("RE x " + str(re))
Problem:
A group of people played a game. All players had distinct scores, which are positive integers.  Takahashi knows N facts on the players' scores. The i-th fact is as follows: the A_i-th highest score among the players is B_i.  Find the maximum possible number of players in the game.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ab = sorted([list(map(int, input().split())) for _ in range(n)])
ans = 0

ans += ab[n-1][0]
if ab[0][0] != 1:
    ans += ab[0][0] - 1
if ab[n-1][1] > 0:
    ans += ab[n-1][1]

print(ans)

Fixed, accepted submission:
n = int(input())
ab = sorted([list(map(int, input().split())) for _ in range(n)])
print(ab[-1][0] + ab[-1][1])
Problem:
Let w be a string consisting of lowercase letters. We will call w _beautiful_ if the following condition is satisfied:    * Each lowercase letter of the English alphabet occurs even number of times in w.  You are given the string w. Determine if w is beautiful.

Incorrect submission (verdict: Wrong Answer):
def main():
    w = input()

    for o in range(ord('a'), ord('z')+1):
        c = chr(o)
        if w.count(c) % 2 == 1:
            print("NO")
            return

    print("YES")


if __name__ == '__main__':
    main()


Fixed, accepted submission:
def main():
    w = input()

    for o in range(ord('a'), ord('z')+1):
        c = chr(o)
        if w.count(c) % 2 == 1:
            print("No")
            return

    print("Yes")


if __name__ == '__main__':
    main()
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
n = list(map(int,input().split()))
s = 1
for i in range(3):
    s *=10
    if n[1]<s:
        N = n[0]*s+n[1]
        for i in range(100):
            if N==i*i:
                print('Yes')
                exit()
    break
print('No')

Fixed, accepted submission:
a,b = input().split()
x = int(a+b)

if x == int(x**0.5)**2:
    print('Yes')
else:
    print('No')
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
x=n//1000

m=n-(1000*x)
print(m)
  

Fixed, accepted submission:
n=int(input())
x=n//1000

m=n-(1000*x)

if m==0:
  print(0)
else:
	y=1000-m
	print(y)
Problem:
The programming contest named _Concours de Programmation Comtemporaine Interuniversitaire_ (CPCI) has a judging system similar to that of ICPC; contestants have to submit correct outputs for two different inputs to be accepted as a correct solution. Each of the submissions should include the program that generated the output. A pair of submissions is judged to be a correct solution when, in addition to the correctness of the outputs, they include an identical program.  Many contestants, however, do not stop including a different version of their programs in their second submissions, after modifying a single string literal in their programs representing the input file name, attempting to process different input. The organizers of CPCI are exploring the possibility of showing a special error message for such _close_ submissions, indicating contestants what's wrong with such submissions. Your task is to detect such close submissions.

Incorrect submission (verdict: Wrong Answer):
while 1:
    s1 = input().split('"')
    l1 = len(s1)
    if s1[0] == ".": break
    s2 = input().split('"')
    l2 = len(s2)
    if l1 != l2:
        print("DIFFERENT")
        break
    i = 0
    j = 0
    k = 0
    flag_1 = 0
    flag_2 = 0
    cnt = 0
    x1 = []
    x2 = []
    while 1:
        if i > l1-2:
            if cnt == 1:
                print("CLOSE")
                break
            else:
                print("IDENTICAL")
                break
        if s1[i] != s2[i]:
            print("DIFFERENT")
            break
        if s1[i+1] != s2[i+1]:
            if cnt == 1:
                print("DIFFERENT")
                break
            else: cnt = 1
        i += 2



Fixed, accepted submission:
while 1:
    s1 = input().split('"')
    l1 = len(s1)
    if s1[0] == ".": break
    s2 = input().split('"')
    l2 = len(s2)
    if l1 != l2:
        print("DIFFERENT")
        continue
    i = 0
    cnt = 0
    while 1:
        if s1[i] != s2[i]:
            print("DIFFERENT")
            break
        if i > l1-2:
            if cnt == 1:
                print("CLOSE")
                break
            else:
                print("IDENTICAL")
                break
        if s1[i+1] != s2[i+1]:
            if cnt == 1:
                print("DIFFERENT")
                break
            else: cnt = 1
        i += 2
Problem:
You are given two integers A and B as the input. Output the value of A + B.  However, if A + B is 10 or greater, output `error` instead.

Incorrect submission (verdict: Wrong Answer):
def main():
    s = input().strip()
    if len(s) == len(set(s)):
        print("yes")
    else:
        print("no")

if __name__ == '__main__':
    main()


Fixed, accepted submission:
def main():
    a, b = list(map(int, input().split()))
    answer = a + b
    if answer >= 10:
        print("error")
    else:
        print(answer)


if __name__ == '__main__':
    main()
Problem:
Write a program which reads a $n \times m$ matrix $A$ and a $m \times l$ matrix $B$, and prints their product, a $n \times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:  \\[ c_{ij} = \sum_{k=1}^m a_{ik}b_{kj} \\]  where $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.

Incorrect submission (verdict: Wrong Answer):
n, m, l = [int(i) for i in input().split()]

A = []
B = []
C = []
D = []


for ni in range(n):
    A.append([int(i) for i in input().split()])

for mi in range(m):
    B.append([int(i) for i in input().split()])

print(A)
print(B)

for j in range(n):
    for h in range(l):
        for f in range(m):
            C.append((A[j][f])*(B[f][h]))

for a in range(0,len(C),m):
    D.append(C[a]+C[a+m-1])

for b in range(0,len(D)):
    if (b+1) % n == 0:
        print(D[b],end=' \n')
    else:
        print(D[b], end=' ')

Fixed, accepted submission:
n, m, l = [int(i) for i in input().split()]

A = []
B = []
C = []
for ni in range(n):
    A.append([int(i) for i in input().split()])

for mi in range(m):
    B.append([int(i) for i in input().split()])

for i in range(n):
    C.append([])
    for j in range(l):
        C[i].append(0)
        for k in range(m):
            C[i][j] += A[i][k] * B[k][j]

for ni in range(n):
    print(" ".join([str(s) for s in C[ni]]))
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
A, B, K = map(int, input().split())

for k in range(K):

    if A % 2 != 0:
        
        A -= 1

    B += A/2
    A -= A/2

    if B % 2!= 0:

        B -= 1

    A += B/2
    B -= B/2

print(round(A), round(B))

Fixed, accepted submission:
A, B, K = map(int, input().split())

k = 0
while True:

    if A % 2 != 0:
            
        A -= 1

    

    B += round(A/2)
    A -= round(A/2)

    
    k += 1
    if k == K:
        break

    if B % 2 != 0:
        
        B -= 1

    

    A += round(B/2)
    B -= round(B/2)

    
    k += 1
    if k == K:
        break

print(A, B)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def insertionSort(length, array):
    for i in range(1, length):
        v = array[i]
        j = i - 1
        while j >= 0 and array[j] > v:
            array[j+1] = array[j]
            j -= 1
        array[j+1] = v
        print(' '.join(map(str, array)))

length = int(input())
num_array = [int(x) for x in input().split()]
insertionSort(length, num_array)



Fixed, accepted submission:
def insertionSort(a):
    n = len(a)
    print(*a)
    for i in range(1, n):
        v = a[i]
        j = i-1
        while j >= 0 and a[j] > v:
            a[j+1] = a[j]
            j += -1
        a[j+1] = v
        print(*a)


n = int(input())
a = [int(x) for x in input().split()]

insertionSort(a)
Problem:
There are four towns, numbered 1,2,3 and 4. Also, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally. No two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.  Determine if we can visit all the towns by traversing each of the roads exactly once.

Incorrect submission (verdict: Wrong Answer):
d=[0,0,0,0]
for i in range(3):
    a,b=map(int,input().split())
    d[a-1]+=1
    d[b-1]+=1

if d[0] <= 2 and d[1] <= 2 and d[2] <= 2 and d[3] <= 2:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
d=[0,0,0,0]
for i in range(3):
    a,b=map(int,input().split())
    d[a-1]+=1
    d[b-1]+=1

if d[0] <= 2 and d[1] <= 2 and d[2] <= 2 and d[3] <= 2:
    print("YES")
else:
    print("NO")
Problem:
Takahashi, who works at DISCO, is standing before an iron bar. The bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.  Takahashi wanted to choose a notch and cut the bar at that point into two parts with the same length. However, this may not be possible as is, so he will do the following operations some number of times **before** he does the cut:    * Choose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).   * Choose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.  Find the minimum amount of money needed before cutting the bar into two parts with the same length.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
A=list(map(int,input().split()))
s=ans=sum(A)
k=0
for i in range(N-1):
    k+=A[i]
    ans=min(ans,abs(s-2*k))
    print(k,ans)
print(ans)

Fixed, accepted submission:
N=int(input())
A=list(map(int,input().split()))
s=ans=sum(A)
k=0
for i in range(N-1):
    k+=A[i]
    ans=min(ans,abs(s-2*k))
print(ans)
Problem:
Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier. He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.  Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.  Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.  Write a program that outputs `delicious` if he found it delicious, `safe` if he did not found it delicious but did not get a stomachache either, and `dangerous` if he got a stomachache.

Incorrect submission (verdict: Wrong Answer):
import sys
x,a,b = map(int,input().split())

if b <= a:
  print("delicious")
elif a + x <= b:
  print("safe")
else:
  print("dangerous")

Fixed, accepted submission:
import sys
x,a,b = map(int,input().split())

if b <= a:
  print("delicious")
elif a + x >= b:
  print("safe")
else:
  print("dangerous")
Problem:
The word `internationalization` is sometimes abbreviated to `i18n`. This comes from the fact that there are 18 letters between the first `i` and the last `n`.  You are given a string s of length at least 3 consisting of lowercase English letters. Abbreviate s in the same way.

Incorrect submission (verdict: Wrong Answer):
s=input();n=len(s);print(s[0]+str(n)+s[-1])

Fixed, accepted submission:
s=input();n=len(s)-2;print(s[0]+str(n)+s[-1])
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
a = []
for c in input():
    if c in '01':
        a.append(c)
    else:
        a = a[:-1]
print(a)


Fixed, accepted submission:
a = []
for c in input():
    if c in '01':
        a.append(c)
    else:
        a = a[:-1]
print("".join(a))
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,k=map(int,input().split())
if (b-a)>2*k:
  ans=[i for i in range(a,a+k+1)]+[i for i in range(b-k,b+1)]
else:
  ans=[i for i in range(a,b+1)]
for i in ans:
  print(i)

Fixed, accepted submission:
a,b,k=map(int,input().split())
if b-a+1>2*k:
  ans=sorted(list(set([i for i in range(a,a+k)]+[i for i in range(b-k+1,b+1)])))
else:
  ans=[i for i in range(a,b+1)]
for i in ans:
  print(i)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
s = a+b
if s%2!=0:
    print(int(s/2)+1)
else:
    print(s/2)

Fixed, accepted submission:
a, b = map(int, input().split())
s = a+b
if s%2!=0:
    print(int(s/2)+1)
else:
    print(int(s/2))
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
from sys import stdin


def main() -> None:
    a = next_int()
    b = next_int()

    ab = int(str(a) + str(b))
    sqrt = int(ab ** 0.5)

    print("YES" if sqrt ** 2 == ab else "No")


def next_int() -> int:
    return int(next_str())


def next_str() -> str:
    result = ""
    while True:
        tmp = stdin.read(1)
        if tmp.strip() != "":
            result += tmp
        elif tmp != '\r':
            break
    return result


if __name__ == '__main__':
    main()

Fixed, accepted submission:
from sys import stdin


def main() -> None:
    a = next_int()
    b = next_int()

    ab = int(str(a) + str(b))
    sqrt = int(ab ** 0.5)

    print(["No", "Yes"][int(sqrt ** 2 == ab)])


def next_int() -> int:
    return int(next_str())


def next_str() -> str:
    result = ""
    while True:
        tmp = stdin.read(1)
        if tmp.strip() != "":
            result += tmp
        elif tmp != '\r':
            break
    return result


if __name__ == '__main__':
    main()
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
A, B, C = map(int, input().split())
q = int(input())

k = 0

for i in range(q+1):
    for j in range(0, q-i+1):
        print(i, j)
        B_ = B * (2 ** i)
        C_ = C * (2 ** j)
        if A < B_ and B_ < C_ and A < C_:
            k = 1
if k != 0:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
A, B, C = map(int, input().split())
q = int(input())

k = 0

for i in range(q+1):
    for j in range(0, q-i+1):
        B_ = B * (2 ** i)
        C_ = C * (2 ** j)
        if A < B_ and B_ < C_ and A < C_:
            k = 1
if k != 0:
    print('Yes')
else:
    print('No')
Problem:
You are given a string S of length N consisting of `(` and `)`. Your task is to insert some number of `(` and `)` into S to obtain a _correct bracket sequence_.   Here, a correct bracket sequence is defined as follows:    * `()` is a correct bracket sequence.   * If X is a correct bracket sequence, the concatenation of `(`, X and `)` in this order is also a correct bracket sequence.   * If X and Y are correct bracket sequences, the concatenation of X and Y in this order is also a correct bracket sequence.   * Every correct bracket sequence can be derived from the rules above.  Find the shortest correct bracket sequence that can be obtained. If there is more than one such sequence, find the lexicographically smallest one.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
lis = []
li = []
cou = 0
s = str(input())
for i in range(n):
    if s[i] == "(":
        cou += 1
        lis.append(s[i])
    else:
        cou -= 1
        while cou < 0:
            lis.append("(")
            cou += 1
        lis.append(s[i])
while cou > 0:
    lis.append(")")
    cou -= 1
print("".join(lis))

Fixed, accepted submission:
n = int(input())
s = input()
cnt = [0, 0]
add = [0, 0]
ans = ''
for i in range(n):
    if s[i] == ')':
        cnt[0] += 1
        if cnt[0] > cnt[1]:
            add[1] += 1
            cnt[1] += 1
    else:
        cnt[1] += 1

print('(' * add[1] + s + ')'*(cnt[1] -cnt[0]))
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
S = input()
s = S.replace("eraser","").replace("erase","").replace("dreamer","").replace("dream","")
if s == "":
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
S = input()
s = S.replace("eraser", "").replace("erase", "").replace("dreamer", "").replace("dream", "")
if s == "":
  print("YES")
else:
  print("NO")