Problem:
We have a rectangular grid of squares with H horizontal rows and W vertical columns. Let (i,j) denote the square at the i-th row from the top and the j-th column from the left. On this grid, there is a piece, which is initially placed at square (s_r,s_c).  Takahashi and Aoki will play a game, where each player has a string of length N. Takahashi's string is S, and Aoki's string is T. S and T both consist of four kinds of letters: `L`, `R`, `U` and `D`.  The game consists of N steps. The i-th step proceeds as follows:    * First, Takahashi performs a move. He either moves the piece in the direction of S_i, or does not move the piece.   * Second, Aoki performs a move. He either moves the piece in the direction of T_i, or does not move the piece.  Here, to move the piece in the direction of `L`, `R`, `U` and `D`, is to move the piece from square (r,c) to square (r,c-1), (r,c+1), (r-1,c) and (r+1,c), respectively. If the destination square does not exist, the piece is removed from the grid, and the game ends, even if less than N steps are done.  Takahashi wants to remove the piece from the grid in one of the N steps. Aoki, on the other hand, wants to finish the N steps with the piece remaining on the grid. Determine if the piece will remain on the grid at the end of the game when both players play optimally.

Incorrect submission (verdict: Wrong Answer):

import numpy as np
from functools import *

import sys

sys.setrecursionlimit(100000)
input = sys.stdin.readline


def acinput():
    return list(map(int, input().split(" ")))


def factorial(n):
    fact = 1
    for integer in range(1, n + 1):
        fact *= integer
    return fact


def serch(x, count):
    #print("top", x, count)

    for d in directions:
        nx = d+x
        # print(nx)
        if np.all(0 <= nx) and np.all(nx < (H, W)):
            if field[nx[0]][nx[1]] == "E":
                count += 1
                field[nx[0]][nx[1]] = "V"
                count = serch(nx, count)
                continue
            if field[nx[0]][nx[1]] == "#":
                field[nx[0]][nx[1]] = "V"
                count = serch(nx, count)

    return count


H, W, N = acinput()

initp= np.array(acinput())

S = list(input())[:-1]
T = list(input())[:-1]
#S = list(input().split(""))
#T = list(input().split(""))


def position_relative(direction,flg,seq1,seq2):
    cs = 0
    N=len(seq1)
    for i in range(len(seq1)):
        s1=seq1[i]
        s2=seq2[i]
        if s1==direction:
            cs += flg
            
        if cs<0 or cs>N:
            return False
        if s2!=direction:
            cs-=flg
        
        if cs < 0 or cs > N:
            return False
            
    return cs




sr=position_relative("R",initp[0],S,T)
sl = position_relative("L",initp[1],S,T)

su = position_relative("U",-1,S, T)
sd = position_relative("D",1, S, T)

#print(sr,sl,su,sd)

if sr or sl or su or sd:
    print("Yes")
else:
    print("No")



Fixed, accepted submission:

import numpy as np
from functools import *

import sys

sys.setrecursionlimit(100000)
input = sys.stdin.readline


def acinput():
    return list(map(int, input().split(" ")))


def factorial(n):
    fact = 1
    for integer in range(1, n + 1):
        fact *= integer
    return fact


H, W, NN = acinput()

initp = np.array(acinput())

S = list(input())[:-1]
T = list(input())[:-1]
#S = list(input().split(""))
#T = list(input().split(""))


def position_relative(direction, direction_op, cs, flg, seq1, seq2, N):
    global H, W
    # N=len(seq1)
    for i in range(len(seq1)):
        s1 = seq1[i]
        s2 = seq2[i]

        #print(cs,flg)
        if s1 == direction:
            cs += flg

        if flg > 0:
            if cs > N:
                return False

        else:
            if cs <= 0:
                return False
            # elif cs>N:
            #    cs=N
        #print(cs)
        if s2 == direction_op:
            #print("op",N)
            cs -= flg
    
    
        if cs > N:
           cs = N
        
        if cs <= 0:
            cs = 1

    return cs


sr = position_relative("R", "L", initp[1], 1, S, T, W)
sl = position_relative("L", "R", initp[1], -1, S, T, W)
su = position_relative("U", "D", initp[0], -1, S, T, H)
sd = position_relative("D", "U", initp[0], 1, S, T, H)



# su=0
# if sr or sl or su or sd:
if sr*sl*su*sd == 0:
    print("NO")
else:
    print("YES")