TnT/CodeNet4Repair huggingface dataset:
Problem:
Snuke has come to a store that sells boxes containing balls. The store sells the following three kinds of boxes:    * Red boxes, each containing R red balls   * Green boxes, each containing G green balls   * Blue boxes, each containing B blue balls  Snuke wants to get a total of exactly N balls by buying r red boxes, g green boxes and b blue boxes. How many triples of non-negative integers (r,g,b) achieve this?

Incorrect submission (verdict: Wrong Answer):
R, G, B, N = map(int, input().split())

count = 0
for r in range(N):
    for g in range(N):
        b = (N - R*r - G*g) / B
        if b >= 0 and b.is_integer():
            count += 1
print(count, R, G, B, N)

Fixed, accepted submission:
R, G, B, N = map(int, input().split())

box = sorted([R,G,B],reverse=True)

count = 0
for x in range(0,N+1,box[0]):
    for y in range(0,N+1 - x ,box[1]):
        z = (N - x - y) / box[2]
        if z >= 0 and z.is_integer():
            count += 1
print(count)
Problem:
We conducted a survey on newspaper subscriptions. More specifically, we asked each of the N respondents the following two questions:    * Question 1: Are you subscribing to Newspaper X?   * Question 2: Are you subscribing to Newspaper Y?  As the result, A respondents answered "yes" to Question 1, and B respondents answered "yes" to Question 2.  What are the maximum possible number and the minimum possible number of respondents subscribing to both newspapers X and Y?  Write a program to answer this question.

Incorrect submission (verdict: Wrong Answer):
n, a, b = list(map(int, input().split()))
print(min(a, b), a + b - n)


Fixed, accepted submission:
n, a, b = list(map(int, input().split()))
print(min(a, b), max(0, a + b - n))
Problem:
We have an N \times N square grid.  We will paint each square in the grid either black or white.  If we paint exactly A squares white, how many squares will be painted black?

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())

print(n-a)

Fixed, accepted submission:
n = int(input())
a = int(input())
 
print(n*n-a)
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
import math
a, b = input().split()
c = int(a+b)
d = math.sqrt(c)
if d * d == c :
	print("Yes")
else :
	print("No")

Fixed, accepted submission:
# -*- coding: utf-8 -*-
a, b = map(int, input().split())
if a*b % 2 == 0 :
        print("Even")
else :
        print("Odd")
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
H, W = map(int, input().split())
matrix = []
for i in range(H):
    matrix.append(list(map(str, input().split())))
for j in range(H):
    ans = ','.join(matrix[i])
    print(ans)
    print(ans)

Fixed, accepted submission:
H, W = map(int, input().split())
matrix = []
for i in range(H):
    matrix.append(list(map(str, input().split())))
for j in range(H):
    ans = ','.join(matrix[j])
    print(ans)
    print(ans)
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

sosu = []

primes = list(range(n+1))
primes[1] = 0
for i in range(2,int(n**.5)+1):
    if primes[i]!=0:
        for j in range(i*2,n+1,i):
            primes[j] = 0
primes = [prime for prime in primes if prime!=0]

power = []
for prime in primes:
    p = prime
    tmp = 0
    while p<=n:
        tmp += n // p
        p *= prime
    power.append(tmp)
print(power)

res = 1
mod = 10**9+7
for i in power:
    res *= i + 1
    res %= mod

print(res)


Fixed, accepted submission:
n = int(input())

sosu = []

primes = list(range(n+1))
primes[1] = 0
for i in range(2,int(n**.5)+1):
    if primes[i]!=0:
        for j in range(i*2,n+1,i):
            primes[j] = 0
primes = [prime for prime in primes if prime!=0]

power = []
for prime in primes:
    p = prime
    tmp = 0
    while p<=n:
        tmp += n // p
        p *= prime
    power.append(tmp)
#print(power)

res = 1
mod = 10**9+7
for i in power:
    res *= i + 1
    res %= mod

print(res)
Problem:
It is September 9 in Japan now.  You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Incorrect submission (verdict: Wrong Answer):
a=input()
if a[0]==9 or a[1]==9:
    print('Yes')
else:
    print('No')

Fixed, accepted submission:
s=input()
print('Yes' if s[0]=='9' or s[1]=='9' else 'No')
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
a = [int(x) for x in input().split()]
b = 0
while len(list(filter(lambda i : i % 2 != 0, list(a)))) == 0 :
    a = list(map(lambda x: x/2, a))
    b += 1
b

Fixed, accepted submission:
N = int(input())
a = [int(x) for x in input().split()]
b = 0
while len(list(filter(lambda i : i % 2 != 0, list(a)))) == 0 :
    a = list(map(lambda x: x/2, a))
    b += 1
print(b)
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
f = int(n/1.08)
if (f+1)*1.08 != n:
  print(':(')
else:
  print(f)

Fixed, accepted submission:
n = int(input())
f = int(n/1.08)
if int(f*1.08) != n and int((f+1)*1.08) != n:
  print(':(')
elif int(f*1.08) == n:
  print(f)
else:
  print(f+1)
Problem:
Based on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below. Given two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.  

Incorrect submission (verdict: Wrong Answer):
x,y = map(int,input().split())
li = [[1, 3, 5, 7, 8, 10, 12], [4, 6, 9, 11], [2]]
for i, l in enumerate(li):
    if x in l and y in l:
        print("YES")
        break
    if i == len(li) - 1:
        print("No")


Fixed, accepted submission:
x,y = map(int,input().split())
li = [[1, 3, 5, 7, 8, 10, 12], [4, 6, 9, 11], [2]]
for i, l in enumerate(li):
    if x in l and y in l:
        print("Yes")
        break
    if i == len(li) - 1:
        print("No")
Problem:
In the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.  Write a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.

Incorrect submission (verdict: Time Limit Exceeded):
x=int(input())
i=1
while not x==0:
    print(f"Case {i}: {x}")
    i=i+1


Fixed, accepted submission:
i = 0
while True:
    x = int(input()); i += 1
    if x == 0: break
    print("Case {}: {}".format(i, x))
Problem:
Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters.  Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s.  Given the name of the contest, print the abbreviation of the name.

Incorrect submission (verdict: Wrong Answer):
a,b,c=input().split()
print('A'+b.upper()+'C')

Fixed, accepted submission:
a,b,c=input().split()
print('A'+b[0].upper()+'C')
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int, input().split()))
def calc(a):
    return a /2
count = 0
for i in range(0, 99999999):
    if sum(a) % 2 == 0:
        count += 1
        a = list(map(calc,a))
    else:
        break
print(count)

Fixed, accepted submission:
n = input()
a = list(map(int, input().split()))

import numpy as np
a = np.array(a)
count = 0
while (True):
    exist_odd = False
    for i in a:
        if i % 2 != 0:
            exist_odd = True
    if exist_odd:
        break
    
    a = a / 2
    count += 1
print(count)
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
x = (a+b)/2
print(int((x+9)//10))

Fixed, accepted submission:
a, b = map(int, input().split())
print((a + b + 1) // 2)
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a = int(input())
b = int(input())
h = int(input())

print((a + b) * h / 2)


Fixed, accepted submission:
a, b, h = [int(input()) for i in range(3)]

print(int((a + b) * h / 2))
Problem:
You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings.  Here, a subsequence of a string is a concatenation of **one or more** characters from the string without changing the order.

Incorrect submission (verdict: Wrong Answer):
from itertools import groupby as gb
n,s=open(0)
n=int(n)
s=sorted(s)
ans=1
mod=10**9+7
for i,x in gb(s):
  ans=ans*(len(list(x))+1)%mod
print(ans-1)

Fixed, accepted submission:
from itertools import groupby as gb
n,s=open(0)
n=int(n)
s=sorted(s[:-1])

ans=1
mod=10**9+7
for i,x in gb(s):
  ans=ans*(len(list(x))+1)%mod
print(ans-1)
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = 0
for i in range(1, 33):
    if n == i*i:
        print(i*i)
        break
    elif n < i*i:
        print((i-1)*(i-1))
        break


Fixed, accepted submission:
N = int(input())
S = input()
ans = 0
for i in range(N - 1):
    ans = max(ans, len(set(S[:i + 1]) & set(S[i + 1:])))
print(ans)
Problem:
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.  To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:    * The `0` key: a letter `0` will be inserted to the right of the string.   * The `1` key: a letter `1` will be inserted to the right of the string.   * The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.  Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?

Incorrect submission (verdict: Wrong Answer):
#ABC043.B
s = input()
L = []

def kan(a):
    if s =='0':
        L.append('0')
    elif s =='1':
        L.append('1')
    else:
        if L !=[]:
            L.pop()
for b in L:
    kan(b)

c =''
for d in L:
    c +=d
print(c)


Fixed, accepted submission:
#ABC043.B
s = input()
L = []

def kan(a):
    if a =='0':
        L.append('0')
    elif a =='1':
        L.append('1')
    else:
        if L !=[]:
            L.pop()
for b in s:
    kan(b)

c =''
for d in L:
    c +=d
print(c)
Problem:
Square1001 has seen an electric bulletin board displaying the integer 1. He can perform the following operations A and B to change this value:    * Operation A: The displayed value is doubled.   * Operation B: The displayed value increases by K.  Square1001 needs to perform these operations N times in total. Find the minimum possible value displayed in the board after N operations.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = int(input())

d = 1

for i in range(n):
	print(d)
	if d < k:
		d = d*2
	else:
		d += k

print(d)

Fixed, accepted submission:
n = int(input())
k = int(input())

d = 1

for i in range(n):
	if d + k <= d * 2:
		d += k
	else:
		d *= 2

print(d)
Problem:
Takahashi loves numbers divisible by 2.  You are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.  Here, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.  For example,    * 6 can be divided by 2 once: 6 -> 3.   * 8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.   * 3 can be divided by 2 zero times.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
import math

print(int(math.sqrt(n)))

Fixed, accepted submission:
n=int(input())
result = 1
for i in range(n):
  a = n-i
  while a % 2 == 0:
    a /= 2
    if a == 1:
      result = n-i
      break
  else:
    continue
  break
  
  

print(result)
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
# python3 (3.4.3)
import sys
input = sys.stdin.readline

# main
Sx,Sy,Tx,Ty = map(int,input().split())

dx = Tx - Sx
dy = Ty - Sy

ans1 = "U"*dy + "R"*dx
ans2 = "D"*dy + "L"*dy
ans3 = "L" + "U"*(dy+1) + "R"*(dx+1) + "D"
ans4 = "R" + "D"*(dy+1) + "L"*(dy+1) + "U"

print(ans1 + ans2 + ans3 + ans4)

Fixed, accepted submission:
# Python3 (3.4.3)
import sys
input = sys.stdin.readline

# -------------------------------------------------------------
# function
# -------------------------------------------------------------


# -------------------------------------------------------------
# main
# -------------------------------------------------------------
Sx,Sy,Tx,Ty = map(int,input().split())

dx = Tx - Sx
dy = Ty - Sy
 
ans1 = "U"*dy + "R"*dx
ans2 = "D"*dy + "L"*dx
ans3 = "L" + "U"*(dy+1) + "R"*(dx+1) + "D"
ans4 = "R" + "D"*(dy+1) + "L"*(dx+1) + "U"
 
print(ans1 + ans2 + ans3 + ans4)
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
a = int(input())

if n % 500 + a > n:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
n = int(input())
a = int(input())
 
if n % 500 - a <= 0:
  print('Yes')
else:
  print('No')
Problem:
Takahashi is organizing a party.  At the party, each guest will receive one or more snack pieces.  Takahashi predicts that the number of guests at this party will be A or B.  Find the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.  We assume that a piece cannot be divided and distributed to multiple guests.

Incorrect submission (verdict: Wrong Answer):
Ar =list(map(int,input().split()))

if Ar[0]>=Ar[1]:
  A=Ar[0]
  B=Ar[1]
else:
  A=Ar[1]
  B=Ar[0]
print(A,B)

r=None
while r!=0:
  r = (A%B)
  A = B
  B = r

Ans=int(Ar[0]*Ar[1]/A)
print(Ans)

Fixed, accepted submission:
Ar =list(map(int,input().split()))

if Ar[0]>=Ar[1]:
  A=Ar[0]
  B=Ar[1]
else:
  A=Ar[1]
  B=Ar[0]

r=None
while r!=0:
  r = (A%B)
  A = B
  B = r

Ans=int(Ar[0]*Ar[1]/A)
print(Ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

count = 0
if n % 100 == 1:
    count += 1
    n = n % 100
if n % 10 == 1:
    count += 1
    n = n % 10
if n == 1:
    count += 1

print(count)


Fixed, accepted submission:
n = int(input())

count = 0
if int(n / 100) == 1:
    count += 1
    n = n % 100
else:
    pass

if int(n / 10) == 1:
    count += 1
    n = n % 10
else:
    pass

if n == 1:
    count += 1
else:
    pass

print(count)
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

x = int(input());

ans = math.log(1.01, x / 100);

print(math.ceil(ans));

Fixed, accepted submission:
import math

x = int(input());

a = 100;
i = 0;

while a < x:
  i += 1;
  a += int(a * 0.01);
  
print(i)
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-

import sys
import math

def main():
    input = sys.stdin.readline
    N = int(input())

    result = 0
    ok_flag = False
    for n in range(N+1):
        root_n = int(math.sqrt(n)) + 1
        if n < 3:
            print(0)
            continue
        for i in range(1,root_n):
            for j in range(1,root_n):
                for k in range(i,root_n):
                    if i*i + j*j + k*k + i*j + i*k + j*k == n:
                        if i == j and j == k:
                            result += 1
                        elif i == j or j == k or i == k:
                            result += 3
                        else:
                            result += 6
                        print(result)
                        result = 0
                        ok_flag = True
                        break
                if ok_flag:
                    break
            if ok_flag:
                break
            
        if not ok_flag:
            print(0)
        ok_flag = False
        

Fixed, accepted submission:
# -*- coding: utf-8 -*-

import sys
import math

def main():
    input = sys.stdin.readline
    N = int(input())

    result = 0
    ans_list = [0]*(N+1)
    root_n =int(math.sqrt(N))+1

    for i in range(1,root_n):
        for j in range(1,root_n):
            for k in range(1,root_n):
                f = i**2+j**2+k**2+i*j+i*k+j*k
                if f <= N:
                    ans_list[f] += 1 
    
    for i in range(1,N+1):
        print(ans_list[i])
        
                        

    return


if __name__ == '__main__':
    main()
Problem:
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.  The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)  Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?

Incorrect submission (verdict: Wrong Answer):
import math

x=int(input())
a=100
cnt=0
while a<x:
  a*=1.01
  cnt+=1
  a=int(a)
print(a)
print(cnt)

Fixed, accepted submission:
import math

x=int(input())
a=100
cnt=0
while a<x:
  a*=1.01
  cnt+=1
  a=int(a)
print(cnt)
Problem:
We held two competitions: Coding Contest and Robot Maneuver.  In each competition, the contestants taking the 3-rd, 2-nd, and 1-st places receive 100000, 200000, and 300000 yen (the currency of Japan), respectively. Furthermore, a contestant taking the first place in both competitions receives an additional 400000 yen.  DISCO-Kun took the X-th place in Coding Contest and the Y-th place in Robot Maneuver. Find the total amount of money he earned.

Incorrect submission (verdict: Wrong Answer):
a = list(map(int, input().split()))

for i in range(len(a)):
  if a[i] == 1:
    a[i] = 300000
  elif a[i] == 2:
    a[i] = 200000
  elif a[i] == 3:
    a[i] = 100000
  else:
    a[i] = 0
    
if a[0] == 1 and a[1] == 1:
  p = a[0] + a[1] + 400000
else:
  p = a[0] + a[1]
      
print(p)

Fixed, accepted submission:
a = list(map(int, input().split()))

for i in range(len(a)):
  if a[i] == 1:
    a[i] = 300000
  elif a[i] == 2:
    a[i] = 200000
  elif a[i] == 3:
    a[i] = 100000
  else:
    a[i] = 0

    
if a[0] == 300000 and a[1] == 300000:
  p = 1000000
else:
  p = a[0] + a[1]
      
print(p)
Problem:
Iroha is very particular about numbers. There are K digits that she dislikes: D_1, D_2, ..., D_K.  She is shopping, and now paying at the cashier. Her total is N yen (the currency of Japan), thus she has to hand at least N yen to the cashier (and possibly receive the change).  However, as mentioned before, she is very particular about numbers. When she hands money to the cashier, the decimal notation of the amount must not contain any digits that she dislikes. Under this condition, she will hand the minimum amount of money.  Find the amount of money that she will hand to the cashier.

Incorrect submission (verdict: Time Limit Exceeded):
n,k=map(int,input().split())
d=set(map(int,input().split()))
i=n
while True:
    if not set((str(i)))&d: i+=1
    else:
        print(i)
        exit()

Fixed, accepted submission:
n,k=map(int,input().split())
d=set(map(int,input().split()))
i=n
while True:
    temp=i
    flag=1
    while temp>0:
        if temp%10 in d:
            flag=0
            break
        temp//=10
    if flag:
        print(i)
        break
    i+=1