TnT/CodeNet4Repair huggingface dataset:
Problem:
Takahashi wants to gain muscle, and decides to work out at AtCoder Gym.  The exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up. These buttons are numbered 1 through N. When Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i. When Button i is not lighten up, nothing will happen by pressing it.  Initially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.  Determine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
nums = [0]
for _ in range(N):
  nums.append(int(input()))
check_cnt = 1
_next = nums[1]
while True:
  if check_cnt >= N:
    break
  else:
    if next == 2:
      print(check_cnt)
      exit()
    _next = nums[_next]
    check_cnt += 1
print(-1)

Fixed, accepted submission:
N = int(input())
nums = [0]
for _ in range(N):
  nums.append(int(input()))
check_cnt = 1
_next = nums[1]
while True:
  if check_cnt >= N:
    break
  else:
    if _next == 2:
      print(check_cnt)
      exit()
    _next = nums[_next]
    check_cnt += 1
print(-1)
Problem:
It is only six months until Christmas, and AtCoDeer the reindeer is now planning his travel to deliver gifts.   There are N houses along _TopCoDeer street_. The i-th house is located at coordinate a_i. He has decided to deliver gifts to all these houses.   Find the minimum distance to be traveled when AtCoDeer can start and end his travel at any positions.

Incorrect submission (verdict: Wrong Answer):
s = list(map(int, input().split()))
print(max(s)-min(s))

Fixed, accepted submission:
n = int(input())
s = list(map(int, input().split()))
print(max(s)-min(s))
Problem:
Snuke has one biscuit and zero Japanese yen (the currency) in his pocket. He will perform the following operations exactly K times in total, in the order he likes:    * Hit his pocket, which magically increases the number of biscuits by one.   * Exchange A biscuits to 1 yen.   * Exchange 1 yen to B biscuits.  Find the maximum possible number of biscuits in Snuke's pocket after K operations.

Incorrect submission (verdict: Wrong Answer):
k,a,b=map(int,input().split())
if b<a+2:
    print(1+k)
else:
    if k<=a:
        print(1+k)
    else:
        if (k-a-1)%2!=0:
            print(b+(b-a)*(k-a-1)//2+1)
        else:
            print(b+(b-a)*(k-a-1)//2)

Fixed, accepted submission:
k,a,b=map(int,input().split())
if b<a+2:
    print(1+k)
else:
    if k<=a:
        print(1+k)
    else:
        if (k-a-1)%2==0:
            print(b+(b-a)*((k-a-1)//2))
        else:
            print(b+(b-a)*((k-a-1)//2)+1)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

C0 = 0
C1 = 0
C2 = 0
C3 = 0

for i in range(0,N):
  S = str(input())
  if S == 'AC':
    C0 += 1
  elif S == 'WA':
    C1 += 1
  elif S == 'TLE':
    C2 += 1
  elif S == 'RE':
    C3 += 1
    
print('AC ×',C0)
print('WA ×',C1)
print('TLE ×',C2)
print('RE ×',C3)

Fixed, accepted submission:
N = int(input())

C0 = 0
C1 = 0
C2 = 0
C3 = 0

for i in range(0,N):
  S = str(input())
  if S == 'AC':
    C0 += 1
  elif S == 'WA':
    C1 += 1
  elif S == 'TLE':
    C2 += 1
  elif S == 'RE':
    C3 += 1
    
print('AC x',C0)
print('WA x',C1)
print('TLE x',C2)
print('RE x',C3)
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
N = list(map(int, input().split(" ")))

if N.count(5) == 2 and N.count(7) == 1:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
N = list(map(int, input().split(" ")))

if N.count(5) == 2 and N.count(7) == 1:
  print('YES')
else:
  print('NO')
Problem:
Your friend who lives in undisclosed country is involved in debt. He is borrowing 100,000-yen from a loan shark. The loan shark adds 5% interest of the debt and rounds it to the nearest 1,000 above week by week.  Write a program which computes the amount of the debt in n weeks.

Incorrect submission (verdict: Wrong Answer):
x=100000
n=int(input())
for i in range(n):
    x*=1.05
    if x%1000!=0:
        x+=1000-x%1000
print(x)


Fixed, accepted submission:
x=100000
for i in range(int(input())):
    x*=1.05
    if x%1000!=0:
        x+=1000-x%1000
print(int(x))
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
from numpy import log
print(pow(2,int(log(n)/log(2))))


Fixed, accepted submission:
print("ABC"+input())
Problem:
It is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.  You are given an integer N. Find the N-th Lucas number.  Here, the i-th Lucas number L_i is defined as follows:    * L_0=2   * L_1=1   * L_i=L_{i-1}+L_{i-2} (i≥2)

Incorrect submission (verdict: Wrong Answer):
n = int(input())

lf = 2
ls = 1
for _ in range(n-1):
    lf, ls = ls, lf + ls
    print(ls)


Fixed, accepted submission:
n = int(input())

lf = 2
ls = 1
for _ in range(n-1):
    lf, ls = ls, lf + ls

print(ls)
Problem:
This contest, _AtCoder Beginner Contest_ , is abbreviated as _ABC_.  When we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.  What is the abbreviation for the N-th round of ABC? Write a program to output the answer.

Incorrect submission (verdict: Wrong Answer):
input = int(input())

input_list = list(range(1, input + 1))

count_list = []

for e in input_list:
    count = 0
    e_tmp = e
    while True:
        if e_tmp % 2 == 0:
            e_tmp = e_tmp/2
            count += 1
        else:
            break
    count_list.append([e, count])

max_value = 0
max_key = 0

for i in range(input):    
    curr_value = int(count_list[i][1])
    if curr_value > max_value:
        max_value = curr_value
        max_key = count_list[i][0]
    
print(max_key)


Fixed, accepted submission:


N = input()

ans = 'ABC' + N
print(ans)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
from collections import Counter

N = int(input())
S = [input() for i in range(N)]

s = Counter(S)

print('AC×'+ str(s['AC']))
print('WA×' + str(s['WA']))
print('TLE×' + str(s['TLE']))
print('RE×' + str(s['RE']))

Fixed, accepted submission:
from collections import Counter

N = int(input())
S = [input() for i in range(N)]

s = Counter(S)

print('AC x ',end='')
print(s['AC'])
print('WA x ', end='')
print(s['WA'])
print('TLE x ',end='')
print(s['TLE'])
print('RE x ', end='')
print(s['RE'])
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
import sys

(N, H) = tuple(map(int, input().split(" ")))

a = []
b = []
result = -1

for i in range(N):
    (ai,bi) = tuple(map(int, input().split(" ")))
    a.append(ai)
    b.append(bi)

a_max = max(a)
sorted(b).reverse()
b_length = len(b)

for i, bi in enumerate(b):
    if bi < a_max:
        b_length = i

S = 0

for l in range(b_length):
    S += b[l]
    if S >= H:
        result = l + 1
        print(result)
        sys.exit()

j = b_length

result = b_length + int((H - S)/a_max)

print(result)


Fixed, accepted submission:
import sys
import math

(N, H) = tuple(map(int, input().split(" ")))

a = []
b = []
result = 0

for i in range(N):
    (ai,bi) = tuple(map(int, input().split(" ")))
    a.append(ai)
    b.append(bi)

a_max = max(a)
b.sort()
b.reverse()
b_length = len(b)

for i, bi in enumerate(b):
    if bi < a_max:
        b_length = i
        break


S = 0

for l in range(b_length):
    S += b[l]
    if S >= H:
        result = l + 1
        print(result)
        sys.exit()


result = b_length + int(math.ceil((H - S)/a_max))

print(result)
Problem:
When l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.  You are given N numbers X_1, X_2, ..., X_N, where N is an even number. For each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.  Find B_i for each i = 1, 2, ..., N.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
As = list(map(int, input().split()))

As.sort()

left = As[n//2 - 1]
right = As[n//2]

for x in As:
  if x <= left:
    print(right)
  else:
    print(left)

Fixed, accepted submission:
n = int(input())
As = list(map(int, input().split()))

Xs = sorted(As)

left = Xs[n//2 - 1]
right = Xs[n//2]

for x in As:
  if x <= left:
    print(right)
  else:
    print(left)
Problem:
Snuke, who loves animals, built a zoo.  There are N animals in this zoo. They are conveniently numbered 1 through N, and arranged in a circle. The animal numbered i (2≤i≤N-1) is adjacent to the animals numbered i-1 and i+1. Also, the animal numbered 1 is adjacent to the animals numbered 2 and N, and the animal numbered N is adjacent to the animals numbered N-1 and 1.  There are two kinds of animals in this zoo: honest sheep that only speak the truth, and lying wolves that only tell lies.  Snuke cannot tell the difference between these two species, and asked each animal the following question: "Are your neighbors of the same species?" The animal numbered i answered s_i. Here, if s_i is `o`, the animal said that the two neighboring animals are of the same species, and if s_i is `x`, the animal said that the two neighboring animals are of different species.  More formally, a sheep answered `o` if the two neighboring animals are both sheep or both wolves, and answered `x` otherwise. Similarly, a wolf answered `x` if the two neighboring animals are both sheep or both wolves, and answered `o` otherwise.  Snuke is wondering whether there is a valid assignment of species to the animals that is consistent with these responses. If there is such an assignment, show one such assignment. Otherwise, print `-1`.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
s = input()

a = False
b = False

sw = [None] * n

sw[0] = False
sw[1] = False

def next(s,sw,i,j):
    if s[i] == 'o':
        return not (sw[j] ^ sw[i])
    else:
        return sw[j] ^ sw[i]

def printsw(sw,n):
    s = ''
    for i in range(n):
        if sw[i]:
            s += 'S'
        else:
            s += 'W'
    print(s)

flag = True

for j in range(4):
    for i in range(2,n):
        sw[i] = next(s,sw,i-2,i-1)

    zero = next(s,sw,n-2,n-1)
    one = next(s,sw,n-1,0)
    if zero == sw[0]:
        if one == sw[1]:
            printsw(sw,n)
            flag = False
            break

    sw[0] = not sw[0]
    if j == 1:
        sw[1] = True

if flag:
    print(-1)


Fixed, accepted submission:
n = int(input())
s = input()

a = False
b = False

sw = [None] * n

sw[0] = True
sw[1] = True

def next(s,sw,j,i):
    if s[i] == 'o':
        return not (sw[j] ^ sw[i])
    else:
        return sw[j] ^ sw[i]

def printsw(sw,n):
    s = ''
    for i in range(n):
        if sw[i]:
            s += 'S'
        else:
            s += 'W'
    print(s)

flag = True

for j in range(4):
    for i in range(2,n):
        sw[i] = next(s,sw,i-2,i-1)

    zero = next(s,sw,n-2,n-1)
    one = next(s,sw,n-1,0)
    if zero == sw[0]:
        if one == sw[1]:
            printsw(sw,n)
            flag = False
            break

    sw[0] = not sw[0]
    if j == 1:
        sw[1] = False

if flag:
    print(-1)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
print(list(map(int, input().split())).count(1))

Fixed, accepted submission:
print(list(map(int, list(input()))).count(1))
Problem:
Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier. He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.  Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.  Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.  Write a program that outputs `delicious` if he found it delicious, `safe` if he did not found it delicious but did not get a stomachache either, and `dangerous` if he got a stomachache.

Incorrect submission (verdict: Wrong Answer):
#coding: utf-8
X, A, B = map(int, input().split())
print(["delicious", "safe", "dangerous"][(A > B) + (A + X < B) ])


Fixed, accepted submission:
#coding: utf-8
X, A, B = map(int, input().split())
print(["delicious", "safe", "dangerous"][(A < B) + (A + X < B)])
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s=input()
t=input()
schar=[]
tchar=[]
for i in range(len(s)):
  schar.append(ord(s[i]))
for i in range(len(t)):
  tchar.append(ord(t[i]))
schar.sort()
tchar.sort(reverse=True)
flag=0
for i in range(min(len(s),len(t))):
  if schar[i]>tchar[i]:
    flag=1
    break
if flag==1:
  print("No")
else:
  if len(s)>=len(t):
    print("No")
  else:
    print("Yes")

Fixed, accepted submission:
s=input()
t=input()
schar=[]
tchar=[]
for i in range(len(s)):
  schar.append(ord(s[i]))
for i in range(len(t)):
  tchar.append(ord(t[i]))
schar.sort()
tchar.sort(reverse=True)
flag=0
for i in range(min(len(s),len(t))):
  if schar[i]==tchar[i]:
    continue
  elif schar[i]>tchar[i]:
    flag=1
    break
  else:
    flag=-1
    break
if flag==1:
  print("No")
elif flag==-1:
  print("Yes")
else:
  if len(s)<len(t):  
    print("Yes")
  else:
    print("No")
Problem:
Let f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:    * 1 \leq x,y,z   * x^2 + y^2 + z^2 + xy + yz + zx = n  Given an integer N, find each of f(1),f(2),f(3),\ldots,f(N).

Incorrect submission (verdict: Wrong Answer):
n = int(input())
ans = [0 for i in range(10001)]

for i in range(105):
    for j in range(105):
        for m in range(105):
            v = i**2+j**2+m**2+i*j+j*m+m*i
            #print(v)
            if v<10001:
                ans[v]+=1
#print(count)

for i in range(n):
    print(ans[i+1])

Fixed, accepted submission:
n = int(input())
ans = [0 for i in range(10001)]

for i in range(1,105):
    for j in range(1,105):
        for m in range(1,105):
            v = i**2+j**2+m**2+i*j+j*m+m*i
            #print(v)
            if v<10001:
                ans[v]+=1
#print(count)

for i in range(n):
    print(ans[i+1])
Problem:
It is September 9 in Japan now.  You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Incorrect submission (verdict: Wrong Answer):
N = str(input())

for a in N:
    if a == '9':
        print('Yes')
    else:
        print('No')


Fixed, accepted submission:
N = str(input())

ans = 'No'

for a in N:
    if a == '9':
        ans = 'Yes'
        break
    else:
        ans = 'No'

print(ans)
Problem:
You are given a string S consisting of lowercase English letters. Another string T is initially empty. Determine whether it is possible to obtain S = T by performing the following operation an arbitrary number of times:    * Append one of the following at the end of T: `dream`, `dreamer`, `erase` and `eraser`.

Incorrect submission (verdict: Wrong Answer):
s = input().replace("eracer", "").replace("erace", "").replace("dreamer", "").replace("dream", "")
if s:
    print("NO")
else:
    print("YES")

Fixed, accepted submission:
s = input().replace("eraser", "").replace("erase", "").replace("dreamer", "").replace("dream", "")
if s:
    print("NO")
else:
    print("YES")
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
print(N%1000)

Fixed, accepted submission:
N=int(input())
if N%1000==0:
    print(0)
else:
    print(1000-N%1000)
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
a,b,k = map(int,input().split())

for i in range(k):
    if i % 2 == 0:
        if a % 2 == 1:
            a -= 1
        
        b += a / 2
        a /= 2
    else:
        if b % 2 == 1:
            b -= 1

        a += b / 2
        b /= 2


print(a,b)

Fixed, accepted submission:
a,b,k = map(int,input().split())

for i in range(k):
    if i % 2 == 0:
        if a % 2 == 1:
            a -= 1
        
        b += a // 2
        a = a // 2
    else:
        if b % 2 == 1:
            b -= 1

        a += b // 2
        b = b // 2


print(a,b)
Problem:
Compute A \times B, truncate its fractional part, and print the result as an integer.

Incorrect submission (verdict: Wrong Answer):
import sys

input = sys.stdin.readline

x = sorted(list(map(float, input().split())))

print(x)
print(int(x[0]*x[1]))

Fixed, accepted submission:

a,b=map(float,input().split())
B=round(100*b)
print(int(a)*B//100)
Problem:
In programming languages like C/C++, a goto statement provides an unconditional jump from the "goto" to a labeled statement. For example, a statement "goto CHECK_NUM;" is executed, control of the program jumps to CHECK_NUM. Using these constructs, you can implement, for example, loops.  Note that use of goto statement is highly discouraged, because it is difficult to trace the control flow of a program which includes goto.  Write a program which does precisely the same thing as the following program (this example is wrtten in C++). Let's try to write the program without goto statements.                 void call(int n){   int i = 1;  CHECK_NUM:   int x = i;   if ( x % 3 == 0 ){     cout << " " << i;     goto END_CHECK_NUM;   }  INCLUDE3:   if ( x % 10 == 3 ){     cout << " " << i;     goto END_CHECK_NUM;   }   x /= 10;   if ( x ) goto INCLUDE3;  END_CHECK_NUM:   if ( ++i <= n ) goto CHECK_NUM;    cout << endl; }

Incorrect submission (verdict: Wrong Answer):
num = int(input())
x=""

for i in range(1, num+1):
	 if i % 3 == 0:
	 	x += (" " + str(i))
print(x)

Fixed, accepted submission:
x = int(input())
for i in range(3, x + 1):
  if i % 3 == 0 or '3' in str(i):
    print('', i , end = '')
print()
Problem:
The postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen `-`, and the other characters are digits from `0` through `9`.  You are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.

Incorrect submission (verdict: Wrong Answer):
a ,b = (map(int,input().split()))
post = input().split("-")

if len(post) == 2:
    if(len(post[0])==a and len(post[1])==b):
        print("YES")
    else:
        print("NO")
else:
    print("NO")

Fixed, accepted submission:
a ,b = (map(int,input().split()))
post = input().split("-")

if len(post) == 2:
    if(len(post[0])==a and len(post[1])==b):
        print("Yes")
    else:
        print("No")
else:
    print("No")
Problem:
You are given a positive integer X. Find the largest _perfect power_ that is at most X. Here, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
l = []
l.append(1)
for i in range(2,40):
  b = i**2
  while b <= 1000:
    l.append(b)
    b*= i
l.sort()
for i in range(len(l)):
  if n > l[i]:
    print(l[i-1])
    exit()
  
  

Fixed, accepted submission:
n = int(input())
l = []
l.append(1)
for i in range(2,40):
  b = i**2
  while b <= 1000:
    l.append(b)
    b*= i
l.sort()

for i in range(len(l)):
  if n < l[i]:
    print(l[i-1])
    exit()
print(1000)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
n=int(input())

num=int(n/1000)+1

ans=num*1000-n

print(n)


Fixed, accepted submission:
n=int(input())

if n%1000 == 0:
  ans=n%1000

else:
  num=n//1000+1
  ans=num*1000-n

print(int(ans))
Problem:
AtCoDeer the deer has found two positive integers, a and b. Determine whether the concatenation of a and b in this order is a square number.

Incorrect submission (verdict: Wrong Answer):
import math

a, b = input().split()
a = a+b

if math.sqrt(int(a)).is_integer():
	print(a, "YES")
else:
	print(a, "NO")


Fixed, accepted submission:
import numpy as np

a, b = input().split()
a = a+b

if np.sqrt(int(a)).is_integer():
	print("Yes")
else:
	print("No")
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
print((a+b)//1+1)

Fixed, accepted submission:
a,b=map(int,input().split())
print((a+b)//2 + 1) if (a+b)%2 else print((a+b)//2)