TnT/CodeNet4Repair huggingface dataset:
Problem:
E869120 found a chest which is likely to contain treasure.   However, the chest is locked. In order to open it, he needs to enter a string S consisting of lowercase English letters.   He also found a string S', which turns out to be the string S with some of its letters (possibly all or none) replaced with `?`.  One more thing he found is a sheet of paper with the following facts written on it:    * Condition 1: The string S contains a string T as a contiguous substring.   * Condition 2: S is the lexicographically smallest string among the ones that satisfy Condition 1.  Print the string S.   If such a string does not exist, print `UNRESTORABLE`.

Incorrect submission (verdict: Wrong Answer):
import bisect
import numpy as np
import sys
input = sys.stdin.readline
def IL(): return list(map(int,input().split()))
def SL(): return input().split()
def I(): return int(sys.stdin.readline())
def S(): return input()

s = S()
t = S()

f = 0
for i in range(len(s)-len(t)+1):
	cnt = 0
	for j in range(i,i+len(t)-1):
		if s[j] == t[j-i] or s[j] == "?":
			cnt += 1
			continue
		else:
			break
	if cnt == len(t)-1:
		A = i
		f = 1
		break

if f == 0:
	print("UNRESTORABLE")
else:
	print(s.translate(str.maketrans({'?':'a'}))[:A]+t+s[A+len(t):])

Fixed, accepted submission:
import bisect
import numpy as np
import sys

def IL(): return list(map(int,input().split()))
def SL(): return input().split()
def I(): return int(sys.stdin.readline())
def S(): return input()

s = S()
t = S()

f = 0
for i in range(len(s)-len(t),-1,-1):
    for j in range(len(t)):
        if s[i+j] == t[j] or s[i+j] == "?":
            continue
        else:
            break
    else:
        a = s[:i]+t+s[i+len(t):]
        print(a.replace('?', 'a'))
        break
else:
    print("UNRESTORABLE")
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
S = sorted(list(map(int, input().split(' '))))
print(S)
total = S[0] + S[1] + S[2]
if(total == 17):
    if (S[0]==5 and S[1]==5):
        print('YES')
    else:
        print('NO')
else:
    print('NO')


Fixed, accepted submission:
S = sorted(list(map(int, input().split(' '))))
total = S[0] + S[1] + S[2]
if(total == 17):
    if (S[0]==5 and S[1]==5):
        print('YES')
    else:
        print('NO')
else:
    print('NO')
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
N, Y=map(int,input().split())
flag=False

for k in range(N):
    for j in range(N-k):
        for i in range(N-k-j):
            if Y==10000*i+5000*j+1000*k and N==i+j+k:
                flag=True
                print(i, j, k)
                break
        if flag:
            break
    if flag:
        break
else:
    print('-1 -1 -1')

Fixed, accepted submission:
N, Y=map(int,input().split())
flag=False

for i in range(0,N+1):
    for j in range(0, N+1):
        if Y==10000*(N-i-j)+5000*i+1000*j and i+j<=N:
            flag=True
            print(N-i-j, i, j)
            break
    if flag:
        break
else:
    print('-1 -1 -1')
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

dic = {'AC':0, 'WA':0, 'TLE':0, 'RE':0}

for _ in range(N):
    w = input()
    dic[w] += 1

print('AC ×', dic['AC'])
print('WA ×', dic['WA'])
print('TLE ×', dic['TLE'])
print('RE ×', dic['RE'])


Fixed, accepted submission:
N = int(input())

dic = {'AC':0, 'WA':0, 'TLE':0, 'RE':0}

for _ in range(N):
    w = input()
    dic[w] += 1

print('AC x', dic['AC'])
print('WA x', dic['WA'])
print('TLE x', dic['TLE'])
print('RE x', dic['RE'])
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a=input()
b=input()
h=input()
a=int(a)
b=int(b)
h=int(h)
x=(a+b)*h
print(x*0.5)

Fixed, accepted submission:
a=input()
b=input()
h=input()
a=int(a)
b=int(b)
h=int(h)
x=(a+b)*h
print(x//2)
Problem:
We have a 3×3 square grid, where each square contains a lowercase English letters. The letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.  Print the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.

Incorrect submission (verdict: Wrong Answer):
x= input()
y=input()
z=input()
result=x[0]+y[1]+x[2]
print(result)


Fixed, accepted submission:
x= input()
y=input()
z=input()
result=x[0]+y[1]+z[2]
print(result)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
import sys

args = sys.argv

print(args)

def f(arg_list):
    even_arg_list = []
    for i in arg_list:
        if i % 2 == 0:
            even_arg_list.append(i/2)
        else:
            return False
    return even_arg_list


counter = 0
_list = map(lambda x:int(x),args[1:])
while True:
    _list = f(_list)
    if _list == False:
        print(counter)
        sys.exit()
    counter+=1
    print(_list)
    

Fixed, accepted submission:
import sys

N = int(input())
Ai = map(lambda x:int(x),input().split(" "))
 
def f(arg_list):
    even_arg_list = []
    for i in arg_list:
        if i % 2 == 0:
            even_arg_list.append(i/2)
        else:
            return False
    return even_arg_list


counter = 0
while True:
    Ai = f(Ai)
    if Ai == False:
        print(counter)
        sys.exit()
    counter+=1
    # print(Ai)
Problem:
In _K-city_ , there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?

Incorrect submission (verdict: Wrong Answer):
n, m = map(int, input().split())
x = (n - 2) + (m - 2)
ans = 1
for i in range(x):
  ans *= 2
print(ans)

Fixed, accepted submission:
n, m = map(int, input().split())
x = (n - 1) * (m - 1)
print(x)
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map( int, input().split() )

x = max(a,b,c)
if a == x:
  print(b+c)
elif b == x:
  print(a+c)
else:
  print(a+c)

Fixed, accepted submission:
a, b, c = map( int, input().split() )

x = max(a,b,c)
if a == x:
  print(b+c)
elif b == x:
  print(a+c)
else:
  print(a+b)
Problem:
There are N cities. There are also K roads and L railways, extending between the cities. The i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities. No two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.  We will say city A and B are _connected by roads_ if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads. We will also define _connectivity by railways_ similarly.  For each city, find the number of the cities connected to that city by both roads and railways.

Incorrect submission (verdict: Wrong Answer):
def root(x,d):
    if d[x]==x:
        return x
    x=d[x]
    return root(d[x],d)
def unite(x,y,h,d):
    x=root(x,h)
    y=root(y,h)
    if x!=y:
        if h[x]<h[y]:
            h[x]=y
            d[y]+=1
        else:
            h[y]=x
            d[x]+=1
from collections import Counter
n,k,l=map(int,input().split())
a=[i for i in range(n+1)]
b=[i for i in range(n+1)]
u=[1]*(n+1)
r=[1]*(n+1)
for i in range(k):
    s,t=map(int,input().split())
    unite(s,t,a,u)
for i in range(l):
    s,t=map(int,input().split())
    unite(s,t,b,r)
k=list(zip(a,b))[1:]
d=Counter(k)
l=""
for i in range(n):
    l+=str(d[k[i]])+" "
print(l[:-1])

Fixed, accepted submission:
def root(x,d):
    if d[x]!=x:
        d[x]=root(d[x],d)
    return d[x]
def unite(x,y,h):
    x=root(x,h)
    y=root(y,h)
    if x!=y:
        h[x]=min(x,y)
        h[y]=h[x]
from collections import defaultdict
n,k,l=map(int,input().split())
a=[i for i in range(n+1)]
b=[i for i in range(n+1)]
for i in range(k):
    s,t=map(int,input().split())
    unite(s,t,a)
for i in range(l):
    s,t=map(int,input().split())
    unite(s,t,b)
d=defaultdict(int)
l=""
for i in range(1,n+1):
    d[(root(a[i],a),root(b[i],b))]+=1
for i in range(1,n+1):
    l+=str(d[(root(a[i],a),root(b[i],b))])+" "
print(l[:-1])
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
print('yes' if sorted(input()) < sorted(input(), reverse=True) else 'No')


Fixed, accepted submission:
print('Yes' if sorted(input()) < sorted(input(), reverse=True) else 'No')
Problem:
There are N items, numbered 1, 2, \ldots, N. For each i (1 \leq i \leq N), Item i has a weight of w_i and a value of v_i.  Taro has decided to choose some of the N items and carry them home in a knapsack. The capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.  Find the maximum possible sum of the values of items that Taro takes home.

Incorrect submission (verdict: Wrong Answer):
N,W = map(int,input().split())
A = [list(map(int,input().split())) for i in range(N)]

ans = [[-1 for i in range(N+1)]  for i in range(W+1)]

Fixed, accepted submission:

import sys
import numpy as np

sys.setrecursionlimit(10 ** 9)

N, W = map(int,input().split())
wv = [list(map(int,input().split())) for _ in range(N)]

wv.sort()

ans = 0
dp = np.zeros(W + 1, dtype=int)

for w, v in wv:
    np.maximum(dp[:-w] + v, dp[w:], out = dp[w:])

ans = dp[-1]
print(ans)
Problem:
Does \sqrt{a} + \sqrt{b} < \sqrt{c} hold?

Incorrect submission (verdict: Wrong Answer):
import math

a,b,c = map(int, input().split())

if math.sqrt(a) + math.sqrt(b) >= math.sqrt(c):
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
from decimal import *

a,b,c = map(int, input().split())

if c - (a+b) <= 2*Decimal(a*b).sqrt():
  print('No')
else:
  print('Yes')
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
"""
Created on Sun Jul  5 22:49:34 2020

@author: Aruto Hosaka
"""


N = int(input())
A = list(map(int,input().split()))
A = sorted(A,reverse = True)
count = 0
count += A[0]
if N % 2 == 1:
    for n in range(1,(N-1)//2):
        count += 2*A[n]
        count += A[N//2]
else:
    for n in range(1,N//2):
        count += 2*A[n]    

Fixed, accepted submission:
# -*- coding: utf-8 -*-
"""
Created on Sun Jul  5 22:49:34 2020

@author: Aruto Hosaka
"""


N = int(input())
A = list(map(int,input().split()))
A = sorted(A,reverse = True)

count = A[0]
if N % 2 == 1:
    for n in range(1,(N-1)//2):
        count += 2*A[n]
    count += A[N//2]
else:
    for n in range(1,N//2):
        count += 2*A[n]
print(count)
Problem:
Write a program which reads an integer $S$ [second] and converts it to $h:m:s$ where $h$, $m$, $s$ denote hours, minutes (less than 60) and seconds (less than 60) respectively.

Incorrect submission (verdict: Wrong Answer):
S = int( input() )
h = S / 3600
m = S % 3600 / 60
s = S % 60
print(h, m, s, sep= ":" )

Fixed, accepted submission:
S = int(input())
h = S // 3600
m = S % 3600 // 60
s = S % 60
print(h, m, s, sep = ':')
Problem:
Given an integer N not less than 3, find the sum of the interior angles of a regular polygon with N sides.  Print the answer in degrees, but do not print units.

Incorrect submission (verdict: Wrong Answer):
print(180 *  (int(input()) - 1))

Fixed, accepted submission:
print(180 *  (int(input()) - 2))
Problem:
We have a long seat of width X centimeters. There are many people who wants to sit here. A person sitting on the seat will always occupy an interval of length Y centimeters.  We would like to seat as many people as possible, but they are all very shy, and there must be a gap of length at least Z centimeters between two people, and between the end of the seat and a person.  At most how many people can sit on the seat?

Incorrect submission (verdict: Wrong Answer):
X, Y, Z = map(int, input().split())
X -= 1
print(X/(Y+Z))
print(int(X/(Y+Z)))


Fixed, accepted submission:
X, Y, Z = map(int, input().split())
X -= Z
print(int(X/(Y+Z)))
Problem:
You are given a string S of length N consisting of lowercase English letters, and an integer K. Print the string obtained by replacing every character in S that differs from the K-th character of S, with `*`.

Incorrect submission (verdict: Wrong Answer):
length = int(input())
string = input()
K_str_id = int(input())

K_str = string[K_str_id - 1]

output = ""
for tmp_str in string:
    print(K_str, tmp_str)
    if tmp_str == K_str:
        output += tmp_str
    else:
        output += "*"
print(output)

Fixed, accepted submission:
length = int(input())
string = input()
K_str_id = int(input())

K_str = string[K_str_id - 1]

output = ""
for tmp_str in string:
    if tmp_str == K_str:
        output += tmp_str
    else:
        output += "*"
print(output)
Problem:
Write a program of the Insertion Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:                 for i = 1 to A.length-1     key = A[i]     /* insert A[i] into the sorted sequence A[0,...,j-1] */     j = i - 1     while j >= 0 and A[j] > key         A[j+1] = A[j]         j--     A[j+1] = key   Note that, indices for array elements are based on 0-origin.  To illustrate the algorithms, your program should trace intermediate result for each step.

Incorrect submission (verdict: Wrong Answer):
def insertionSort(lst, n):
    for i in range(1, n):
        v = lst[i]
        j = i - 1
        while j >= 0 and lst[j] > v:
            lst[j+1] = lst[j]
            j = j - 1
        lst[j+1] = v
        print(lst)


if __name__ == "__main__":
    n = int(input())
    lst = [int(n) for n in input().split()]
    print(lst)
    insertionSort(lst, n)

Fixed, accepted submission:
def insertionSort(lst, n):
    print(" ".join([str(n) for n in lst]))
    for i in range(1, n):
        v = lst[i]
        for j in range(0, i):
            if lst[j] > v:
                lst.insert(j, lst.pop(i))
                break

        print(" ".join([str(n) for n in lst]))

    return lst


if __name__ == "__main__":
    n = int(input())
    lst = [int(n) for n in input().split()]
    insertionSort(lst, n)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
A,B,C=tuple(map(int, input().split()))
if A<C &C<B:
  print("yes")
else:
  print("no")

Fixed, accepted submission:
A,B,C=map(int, input().split())
if A<=C<=B:
  print("Yes")
else:
  print("No")
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
for i in range(n):
    t, x, y = map(int, input().split())
    if x + y < t or (x + y + t) % 2:
        print("No")
        exit()
print("Yes")

Fixed, accepted submission:
# 11th
n = int(input())
a = [[int(i) for i in input().split()] for j in range(n)]
t = [i[0] for i in a]
x = [i[1] for i in a]
y = [i[2] for i in a]
tmpt=0
tmpx=0
tmpy=0
for i in range(n):
    tmp = (t[i] - tmpt) - abs(x[i] - tmpx) - abs(y[i] - tmpy)
    tmpt = t[i]
    tmpx = x[i]
    tmpy = y[i]
    if tmp >= 0 and tmp%2 == 0:
        continue
    print("No")
    break
else:
    
    print("Yes")
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split())) 
count=0
for j in range(1,9):
  k=0  
  for i in range(n):
    if a[i]%2==0:
      a[i]=a[i]/2
    else:
      k=k+1
  print(a)
  if k==0:
    count=count+1
  else:
    break
print(count)
        

Fixed, accepted submission:
n=int(input())
a=list(map(int,input().split())) 
count=0
for j in range(1,36):
  k=0  
  for i in range(n):
    if a[i]%2==0:
      a[i]=a[i]/2
    else:
      k=k+1
  if k==0:
    count=count+1
  else:
    break
print(count)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
ac=0
wa=0
tle=0
re=0
for i in range(n):
  s=input()
  if s=='ac':
    ac+=1
  elif s=='wa':
    wa+=1
  elif s=='tle':
    tle+=1
  else:
    re+=1
print("AC x %s"%ac)
print("WA x %s"%wa)
print("TLE x %s"%tle)
print("RE x %s"%re)


Fixed, accepted submission:
n=int(input())
ac=0
wa=0
tle=0
re=0
for i in range(n):
  s=input()
  if s=='AC':
    ac+=1
  elif s=='WA':
    wa+=1
  elif s=='TLE':
    tle+=1
  else:
    re+=1
print("AC x %s"%ac)
print("WA x %s"%wa)
print("TLE x %s"%tle)
print("RE x %s"%re)
Problem:
There is a hotel with the following accommodation fee:    * X yen (the currency of Japan) per night, for the first K nights   * Y yen per night, for the (K+1)-th and subsequent nights  Tak is staying at this hotel for N consecutive nights. Find his total accommodation fee.

Incorrect submission (verdict: Wrong Answer):
*a,= [int(input(i)) for i in range(4)]
print(a[1]*a[2]+(a[0]-a[1])*a[3])

Fixed, accepted submission:
*a,= [int(input()) for i in range(4)]
print(a[1]*a[2]+(a[0]-a[1])*a[3] if a[0]>a[1] else a[0]*a[2])
Problem:
You are given nonnegative integers a and b (a ≤ b), and a positive integer x. Among the integers between a and b, inclusive, how many are divisible by x?

Incorrect submission (verdict: Wrong Answer):
k = list(map(int,input().split()))

print(k[0]//k[2]-k[1]//k[2])


Fixed, accepted submission:
n = list(map(int,input().split()))
if n[0] == 0:
        print(n[1]//n[2]+1)
else:
        print(n[1]//n[2]-(n[0]-1)//n[2])
Problem:
There are a total of A + B cats and dogs. Among them, A are known to be cats, but the remaining B are not known to be either cats or dogs.  Determine if it is possible that there are exactly X cats among these A + B animals.

Incorrect submission (verdict: Wrong Answer):
a,b,x = [int(i) for i in input().split()]
print('Yes') if x>=a and a+b>x else print('No')

Fixed, accepted submission:
a,b,x = [int(i) for i in input().split()]
print('YES') if x>=a and a+b>=x else print('NO')
Problem:
Given is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:    * For every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.

Incorrect submission (verdict: Wrong Answer):
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)


def main():
    N = int(input())
    A = list(map(int, input().split()))
    B = list(map(int, input().split()))

    print('Yes')


if __name__ == '__main__':
    main()


Fixed, accepted submission:
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)

def main():
    N = int(input())
    D = list(map(int, input().split()))

    count = [0] * N
    for d in D:
        count[d] += 1
    
    if D[0] != 0 or count[0] >= 2:
        print(0)
        exit()

    ans = 1
    for i in range(N):
        if i > 0:
            ans *= (count[i-1] ** count[i]) % 998244353
            ans %= 998244353

    print(ans)

    

if __name__ == '__main__':
        main()
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
print('Yes' if any(a*i%b==c for i in range(1, b+1)) else 'No')


Fixed, accepted submission:
a, b, c = map(int, input().split())
print('YES' if any(a*i%b==c for i in range(1, b+1)) else 'NO')