TnT/CodeNet4Repair huggingface dataset:
Problem:
Evi has N integers a_1,a_2,..,a_N. His objective is to have N equal **integers** by transforming some of them.  He may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).  Find the minimum total cost to achieve his objective.

Incorrect submission (verdict: Wrong Answer):

N = int(input())
list = [int(a) for a in input().split()]
print(list)
print(sum(list))

A = sum(list)//N

for i in range(N):
    sum = (list[i] - A) ** 2
    sum_new = (list[i] - i) ** 2
    if(sum > sum_new):
        sum = sum_new
print(sum)

Fixed, accepted submission:

N = int(input())
list = [int(a) for a in input().split()]

A = sum(list)//N
ans = 0

for k in range(N):
    ans = ans + (list[k] - A) ** 2

for i in range(-100,100):
    sum_new = 0
    for j in range(N):
        sum_new = sum_new + (list[j] - i) ** 2
    if(ans > sum_new):
        ans = sum_new

print(ans)
Problem:
The commonly used bills in Japan are 10000-yen, 5000-yen and 1000-yen bills. Below, the word "bill" refers to only these.  According to Aohashi, he received an otoshidama (New Year money gift) envelope from his grandfather that contained N bills for a total of Y yen, but he may be lying. Determine whether such a situation is possible, and if it is, find a possible set of bills contained in the envelope. Assume that his grandfather is rich enough, and the envelope was large enough.

Incorrect submission (verdict: Wrong Answer):
N, Y = map(int,input().split())
ans = []

for x in range(N+1):
    for y in range(N+1):
        z = N - x - y
        if 10000 * x + 5000 * y + 1000 * z == Y and z >= 0:
            ans = [x,y,z]

if len(ans) == 0:
    print("-1 -1 -1")
else:
    print(ans)


Fixed, accepted submission:
N, Y = map(int,input().split())
ans = []

for x in range(N+1):
    for y in range(N+1):
        z = N - x - y
        if 10000 * x + 5000 * y + 1000 * z == Y and z >= 0:
            ans = [x,y,z]
            break

if len(ans) == 0:
    print("-1 -1 -1")
else:
    print(str(ans[0]),str(ans[1]),str(ans[2]))
Problem:
Takahashi has N balls. Initially, an integer A_i is written on the i-th ball.  He would like to rewrite the integer on some balls so that there are at most K different integers written on the N balls.  Find the minimum number of balls that Takahashi needs to rewrite the integers on them.

Incorrect submission (verdict: Wrong Answer):



def main()->None:
    N, K = map(int, input().split())
    A = list(map(int, input().split()))

    if len(A) > K:
        set_A = set(A)
        count = []
        for s_a in set_A:
            card = A.count(s_a)
            count.append(card)
        sorted_count = sorted(count)
        print(sorted_count)
        reduce_num = len(count) - K
        print(reduce_num)
        sum_count = 0
        counter = 0
        for c in sorted_count:
            if counter == reduce_num :
                break
            sum_count += c
            counter += 1

        print(sum_count)
    else:
        print(0)

if __name__ == "__main__":
    main()

Fixed, accepted submission:
from collections import Counter


def main()->None:
    n, k = map(int, input().split())
    a = list(map(int, input().split()))
    a = sorted(Counter(a).values(), reverse=True)
    print(sum(a[k:]))

if __name__ == "__main__":
    main()
Problem:
There are N integers, A_1, A_2, ..., A_N, written on a blackboard.  We will repeat the following operation N-1 times so that we have only one integer on the blackboard.    * Choose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.  Find the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
L = list(map(int,input().split()))
L.sort()
T = []
while len(L) != 2:
  cura = L.pop(len(L)-1)
  curb = L.pop(0)
  T.append([curb,cura])
  L.append(curb-cura)
  L.sort()
T.append([L[1],L[0]])
print(L[1]-L[0])
for i in range(len(T)):
  print(T[i][0],T[i][1])

Fixed, accepted submission:
n = int(input())
L = list(map(int,input().split()))
L.sort()
T = []
plus = []
minus = []
for i in range(n):
  if L[i] >= 0:
    plus.append(L[i])
  else:
    minus.append(L[i])
if len(L) == 2:
  if len(plus) == len(minus):
    print(plus[0]-minus[0])
    print(plus[0],minus[0])
  elif len(plus) == 2:
    print(plus[1]-plus[0])
    print(plus[1],plus[0])
  else:
    print(minus[1]-minus[0])
    print(minus[1],minus[0])
else:
  if len(plus) != 0 and len(minus) != 0:
    if min(len(plus),len(minus)) >= 2:
      T.append([minus[0],plus[0]])
      cur = minus[0]-plus[0]
      for i in range(1,len(plus)-1):
        T.append([cur,plus[i]])
        cur = cur-plus[i]
      T.append([plus[len(plus)-1],cur])
      cur = plus[len(plus)-1]-cur
      for i in range(1,len(minus)):
        T.append([cur,minus[i]])
        cur = cur-minus[i]
      print(cur)
      for i in range(len(T)):
        print(T[i][0],T[i][1])
    else:
      if len(minus) == 1:
        cur = minus[0]
        T.append([cur,plus[0]])
        cur = cur-plus[0]
        for i in range(1,len(plus)-1):
          T.append([cur,plus[i]])
          cur = cur-plus[i]
        T.append([plus[len(plus)-1],cur])
        cur = plus[len(plus)-1]-cur
        print(cur)
        for i in range(len(T)):
          print(T[i][0],T[i][1])
      else:
        cur = plus[0]
        T.append([cur,minus[0]])
        cur = cur-minus[0]
        for i in range(1,len(minus)):
          T.append([cur,minus[i]])
          cur = cur-minus[i]
        print(cur)
        for i in range(len(T)):
          print(T[i][0],T[i][1])
  elif len(plus) == 0:
    cur = minus[len(minus)-1]
    for i in range(n-1):
      T.append([cur,minus[n-i-2]])
      cur = cur-minus[n-i-2]
    print(cur)
    for i in range(len(T)):
      print(T[i][0],T[i][1])
  else:
    cur = plus[0]
    for i in range(1,n-1):
      T.append([cur,plus[i]])
      cur = cur-plus[i]
    T.append([plus[n-1],cur])
    cur = plus[n-1]-cur
    print(cur)
    for i in range(len(T)):
      print(T[i][0],T[i][1])
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a, b, k = map(int, input().split())
for x in range(a,b):
  if x <= a + 1 or x >= b - 1:
    print(x)
  else:
    continue

Fixed, accepted submission:
a, b, k= map(int, input().split())
for x in range(a,min(a+k,b+1)):
    print(x)
for x in range(b-k+1,b+1):
    if x < a+k:
        continue
    else:
        print(x)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
n = int(input())

ans = 0
for q in range(n):
    limit, x, y = map(int, input().split())
    if (limit < x + y) or (limit - x - y) % 2 != 0:
        ans += 1


print("NO" if ans else "YES")



Fixed, accepted submission:
from sys import exit

n = int(input())

ans = 0
for q in range(n):
    limit, x, y = map(int, input().split())
    if (limit < x + y) or (limit - x - y) % 2:
        print("No")
        exit(0)


print("Yes")
Problem:
An elementary school student Takahashi has come to a variety store.  He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?  Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())

if a+b >= c:
    print('yes')
else:
    print('no')

Fixed, accepted submission:
a,b,c = map(int, input().split())

if a+b >= c:
    print('Yes')
else:
    print('No')
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int,input().split())
k = input()
if(2 * b <= a or 2 * b <= c ):
  print("No")
else:
  print("Yes")

Fixed, accepted submission:
a, b, c = map(int,input().split())
k = int(input())

for i in range(k):
  if  b <= a:
    b *=2
  elif c <= b:
    c*=2
  else:
    break
    
if a >= b or b >= c:
  print('No')
else:
  print('Yes')
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s = input()
t = input()

s1 = sorted(s)
s2 = "".join(s)
t1 = sorted(t, reverse=True)
t2 = "".join(t)

l = [s2, t2]
l.sort()

if l[0] == s2:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
s = input()
t = input()

s1 = sorted(s)
s2 = "".join(s1)
t1 = sorted(t, reverse=True)
t2 = "".join(t1)

l = [s2, t2]
l.sort()

if s == t:
  print("No")
elif l[0] == s2:
  print("Yes")
else:
  print("No")
Problem:
Mountaineers Mr. Takahashi and Mr. Aoki recently trekked across a certain famous mountain range. The mountain range consists of N mountains, extending from west to east in a straight line as Mt. 1, Mt. 2, ..., Mt. N. Mr. Takahashi traversed the range from the west and Mr. Aoki from the east.  The height of Mt. i is h_i, but they have forgotten the value of each h_i. Instead, for each i (1 ≤ i ≤ N), they recorded the maximum height of the mountains climbed up to the time they reached the peak of Mt. i (including Mt. i). Mr. Takahashi's record is T_i and Mr. Aoki's record is A_i.  We know that the height of each mountain h_i is a positive integer. Compute the number of the possible sequences of the mountains' heights, modulo 10^9 + 7.  Note that the records may be incorrect and thus there may be no possible sequence of the mountains' heights. In such a case, output 0.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
f=[-1]*n
ma=[-1]*n
f[0]=a[0]
for i in range(n-1):
    if a[i]!=a[i+1]:
        f[i+1]=a[i+1]
    else:
        ma[i+1]=a[i+1]
if f[-1]>=0 and f[-1]!=b[-1]:
    print(0)
    exit()
f[-1]=b[-1]
for i in range(n-1):
    if b[n-i-1]!=b[n-i-2]:
        if f[n-i-2]>=0 and f[n-i-2]!=b[n-i-2]:
            print(0)
            exit()
        f[n-i-2]=b[n-i-2]
    else:
        ma[n-i-2]=min(ma[n-i-2],b[n-i-2])
ans=1
mod=10**9+7
for i in ma:
    if i>=0:
        ans*=i
        ans%=mod
print(ans)
       

Fixed, accepted submission:
n = int(input())
t = list(map(int, input().split()))
a = list(map(int, input().split()))
mod = 10**9+7
ans = 1
if n == 1 and t != a:
    print(0)
    exit()
for i in range(1,n-1):
    if t[i-1] == t[i] and a[i] == a[i+1]:
        ans = (ans*min(t[i],a[i]))%mod
    elif t[i-1] < t[i] and t[i] > a[i]:
        print(0)
        exit()
    elif a[i] > a[i+1] and t[i] < a[i]:
        print(0)
        exit()
print(ans)
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split(" "))
print("Yes") if a<=c and b<=c else print("No")

Fixed, accepted submission:
a,b,c=map(int,input().split(" "))
print("Yes") if a<=c and c<=b else print("No")
Problem:
There are N participants in the CODE FESTIVAL 2016 Qualification contests. The participants are either students in Japan, students from overseas, or neither of these.  Only Japanese students or overseas students can pass the Qualification contests. The students pass when they satisfy the conditions listed below, from the top rank down. Participants who are not students cannot pass the Qualification contests.    * A Japanese student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B.   * An overseas student passes the Qualification contests if the number of the participants who have already definitively passed is currently fewer than A+B and the student ranks B-th or above among all overseas students.  A string S is assigned indicating attributes of all participants. If the i-th character of string S is `a`, this means the participant ranked i-th in the Qualification contests is a Japanese student; `b` means the participant ranked i-th is an overseas student; and `c` means the participant ranked i-th is neither of these.  Write a program that outputs for all the participants in descending rank either `Yes` if they passed the Qualification contests or `No` if they did not pass.

Incorrect submission (verdict: Wrong Answer):
n, a, b = map(int, input().split())
s = str(input())
domestic = 0
abroad = 0

for i in s:
    if i == 'a':
        if domestic + abroad <= a + b:
            print('Yes')
        else:
            print('No')
        domestic += 1
    elif i == 'b':
        if domestic + abroad <= a + b and abroad <= b:
            print('Yes')
        else:
            print('No')
        abroad += 1
    else:
        print('No')


Fixed, accepted submission:
n, a, b = map(int, input().split())
s = str(input())
domestic = 0
abroad = 0

for i in s:
    if i == 'a':
        if domestic + abroad <= a + b - 1:
            print('Yes')
            domestic += 1
        else:
            print('No')
    elif i == 'b':
        if domestic + abroad <= a + b - 1 and abroad <= b - 1:
            print('Yes')
            abroad += 1
        else:
            print('No')
    else:
        print('No')
Problem:
A prime number is a natural number which has exactly two distinct natural number divisors: 1 and itself. For example, the first four prime numbers are: 2, 3, 5 and 7.  Write a program which reads a list of _N_ integers and prints the number of prime numbers in the list.

Incorrect submission (verdict: Wrong Answer):
cnt_num = int(input())
dataset = [int(input()) for i in range(cnt_num)]

for i in dataset:
    if i <= 1:
        continue
    if i == 2:
        print(i)
        continue
    if i % 2 == 0:
        continue

    ok = ''
    for j in range(3,i,2):
        if i % j == 0:
           break
        else:
           ok = 'X'
           break

    if ok == 'X':
        print(i)
        continue

Fixed, accepted submission:
def check_prime(num):
    if num == 2:
        return True

    if num < 2 or num % 2 == 0:
        return False

    return pow(2,num-1,num) == 1

cnt_num = int(input())
dataset = [int(input()) for i in range(cnt_num)]

count = 0
for i in dataset:
    if check_prime(i):
        count += 1

print(count)
Problem:
You are given a string S of length N consisting of `(` and `)`. Your task is to insert some number of `(` and `)` into S to obtain a _correct bracket sequence_.   Here, a correct bracket sequence is defined as follows:    * `()` is a correct bracket sequence.   * If X is a correct bracket sequence, the concatenation of `(`, X and `)` in this order is also a correct bracket sequence.   * If X and Y are correct bracket sequences, the concatenation of X and Y in this order is also a correct bracket sequence.   * Every correct bracket sequence can be derived from the rules above.  Find the shortest correct bracket sequence that can be obtained. If there is more than one such sequence, find the lexicographically smallest one.

Incorrect submission (verdict: Wrong Answer):
kakko=[0]*(int(input())+1)
S=input()
kakkoSum=0
for n,s in enumerate(S):
    if s=="(":
        kakkoSum +=1
    else:
        kakkoSum -=1
    kakko[n+1] = kakkoSum
print(kakko)
D=min(kakko)
if kakko[-1] ==0:print(S)
elif D<0:
    d=kakko[-1]
    kakkoleft=-D
    kakkoright=-D+d
    print("(" * kakkoleft + S + ")" * kakkoright)
else:
    d=kakko[-1]
    print(S + ")"* d)

Fixed, accepted submission:
kakko=[0]*(int(input())+1)
S=input()
kakkoSum=0
for n,s in enumerate(S):
    if s=="(":
        kakkoSum +=1
    else:
        kakkoSum -=1
    kakko[n+1] = kakkoSum
D=min(kakko)
if D<0:
    d=kakko[-1]
    kakkoleft=-D
    kakkoright=-D+d
    print("(" * kakkoleft + S + ")" * kakkoright)
elif kakko[-1] ==0:print(S)
else:
    d=kakko[-1]
    print(S + ")"* d)
Problem:
Write a program which reads two integers x and y, and prints them in ascending order.

Incorrect submission (verdict: Wrong Answer):
x,y = map(int, input().split())
while (x,y) == (0,0):
 if x < y:
  print(x,y)
 else:
  print(y,x)



Fixed, accepted submission:
while True:
 x,y = map(int, input().split())
 if x==0 and y==0:
  break
 if x <= y:
  print(x,y)
 else:
  print(y,x)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

ans = 0

while N > 1000:
  N = N - 1000

print(ans)

Fixed, accepted submission:
N = int(input())

ans = 0

while N >= 1000:
  N = N - 1000

if N == 0:
  print(0)
else:
  ans = 1000 - N
  print(ans)
Problem:
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.   According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.   Determine if he is correct.

Incorrect submission (verdict: Wrong Answer):
def a():return input()#s
def ai():return int(input())#a,n or k
def ma():return map(int, input().split())#a,b,c,d or n,k
def ms():return map(str, input().split())#,a,b,c,d
def lma():return list(map(int, input().split()))#x or y
def lms():return list(map(str, input().split()))#x or y
k= []
l = []
f = 0
def say(i):return print("Yes" if i == 0 else "No")
def Say(i):return print("YES" if i == 0 else "NO")

def addarray(k,l):
    for i in range(n):
        a ,b = map(int,input().split())
        w.append(b)
        v.append(a)

for i in range(3):
    k.append(lma())
a = k[0][0]//2 if k[0][0]%2 == 0 else  -1
b = k[1][1]//2 if k[1][1]%2 == 0 else  -1
c = k[2][2]//2 if k[2][2]%2 == 0 else  -1
if k[0][1] == a+b and k[1][0] == a+b and k[0][2] == a + c and k[2][0] == a + c and k[2][1] == b + c and k[1][2] == b + c:
    print("Yes")
else:print("No")



Fixed, accepted submission:
import copy
def a():return input()#s
def ai():return int(input())#a,n or k
def ma():return map(int, input().split())#a,b,c,d or n,k
def ms():return map(str, input().split())#,a,b,c,d
def lma():return list(map(int, input().split()))#x or y
def lms():return list(map(str, input().split()))#x or y
k= []
l = []
for i in range(3):
    k.append(lma())
l = copy.deepcopy(k)
p = copy.deepcopy(k)

for i in range(1,3):
    for j in range(0,3):
        l[i][j] -= k[i-1][j]
        p[j][i] -= k[j][i-1]
if l[1][0]==l[1][1] and l[1][1]==l[1][2] and l[2][0]==l[2][1] and l[2][1]==l[2][2] and p[0][1] == p[1][1] and p[2][1] == p[1][1] and p[2][2] == p[1][2] and p[0][2]==p[1][2]:
    print("Yes")
else:print("No")
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
print(3**3)

Fixed, accepted submission:
a,b = map(int, input().split())
if a<=b:
    print(a)
else:
    print(a-1)
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
n=int(input())

a=list(map(int, input().split())) 

count=0

while all(x%2==0 for x in a):
    x=[x/2 for x in a]
    count+=1

print(count)

Fixed, accepted submission:
input()
a=list(map(int, input().split())) 
count=0
while all(x%2==0 for x in a):
    a=[x/2 for x in a]
    count+=1
print(count)
Problem:
Dolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.   Currently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.   Here, both the x\- and y-coordinates before and after each movement must be integers.   He will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).   Here, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).   Under this condition, find a shortest path for him.

Incorrect submission (verdict: Wrong Answer):
#coding: utf-8
sx, sy, tx, ty = map(int, input().split())
x = tx - sx
y = ty - sy
ans = ""
ans += "L" + "U" * y + "R" * x + "D"
ans += "R" + "D" * y + "L" * x + "U"
ans += "R" * x + "U" * y
ans += "L" * x + "D" * y
print(ans)

Fixed, accepted submission:
#coding: utf-8
sx, sy, tx, ty = map(int, input().split())
x = tx - sx
y = ty - sy
ans = ""
ans += "U" * y + "R" * x
ans += "D" * y + "L" * x
ans += "L" + "U" * (y+1) + "R" * (x+1) + "D"
ans += "R" + "D" * (y+1) + "L" * (x+1) + "U"
print(ans)