TnT/CodeNet4Repair huggingface dataset:
Problem:
You are going out for a walk, when you suddenly encounter a monster. Fortunately, you have N katana (swords), Katana 1, Katana 2, …, Katana N, and can perform the following two kinds of attacks in any order:    * Wield one of the katana you have. When you wield Katana i (1 ≤ i ≤ N), the monster receives a_i points of damage. The same katana can be wielded any number of times.   * Throw one of the katana you have. When you throw Katana i (1 ≤ i ≤ N) at the monster, it receives b_i points of damage, and you lose the katana. That is, you can no longer wield or throw that katana.  The monster will vanish when the total damage it has received is H points or more. At least how many attacks do you need in order to vanish it in total?

Incorrect submission (verdict: Wrong Answer):
def main():

    N, H = map(int, input().split())
    sword = []
    for _ in range(N):
        a, b = map(int, input().split())
        sword.append([a, b])
    sword.sort(key = lambda x: x[1], reverse= True)

    count = float('inf')

    # the case with just throwing the swords
    damage = 0
    count1 = 0
    for a, b in sword:
        damage += b
        count1 += 1
        if damage >= H:
            break
    if damage >= H:
        count = min(count, count1)

    sword.sort(key = lambda x: x[0], reverse = True)
    a0, b0 = sword.pop(0)
    sword.sort(key = lambda x: x[1], reverse = True)

    damage = 0
    count2 = 0
    i = 0
    while i < len(sword) and sword[i][1] > a0:
        damage += sword[i][1]
        count2 += 1
        i += 1
    if damage < H:
        c = (H - damage - b0) // a0
        if (H - damage - b0) % a0 != 0:
            c += 1
        count2 += c + 1
        count = min(count, count2)

    return count

Fixed, accepted submission:
import collections

def main():

    N, H = map(int, input().split())
    sword = []
    for _ in range(N):
        a, b = map(int, input().split())
        sword.append([a, b])
    sword.sort(key = lambda x: x[1], reverse= True)

    count = float('inf')

    # the case with just throwing the swords
    damage = 0
    count1 = 0
    for a, b in sword:
        damage += b
        count1 += 1
        if damage >= H:
            break
    if damage >= H:
        count = min(count, count1)

    # the case with some swinging swords
    sword.sort(key = lambda x: x[0], reverse = True)
    a0, b0 = sword.pop(0) # best sword for swinging
    sword.sort(key = lambda x: x[1], reverse = True)

    damage = 0
    count2 = 0
    i = 0
    while i < len(sword) and sword[i][1] > a0:
        damage += sword[i][1]
        count2 += 1
        i += 1
    if damage + b0 < H:
        c = (H - damage - b0) // a0
        if (H - damage - b0) % a0 != 0:
            c += 1
        count2 += c + 1
        count = min(count, count2)

    return count


if __name__ == '__main__':
    print(main())
Problem:
In the beginning, Takahashi has A cookies, and Aoki has B cookies. They will perform the following operation alternately, starting from Takahashi:    * If the number of cookies in his hand is odd, eat one of those cookies; if the number is even, do nothing. Then, give one-half of the cookies in his hand to the other person.  Find the numbers of cookies Takahashi and Aoki respectively have after performing K operations in total.

Incorrect submission (verdict: Wrong Answer):
A, B, K = map(int, input().split())

while True:
    if K == 0:
        break
    else:        
        if A%2 !=0:
            A -= 1
        B += A//2
        A = A//2
        print(A,B)
        K -= 1

    if K == 0:
        break
    else:       
        if B%2 !=0:
            B -= 1
        A += B//2
        B = B//2
        print(A,B)
        K -= 1
    
print(A,B)

Fixed, accepted submission:
A, B, K = map(int, input().split())

while True:
    if K == 0:
        break
    else:        
        if A%2 !=0:
            A -= 1
        B += A//2
        A = A//2
        K -= 1

    if K == 0:
        break
    else:       
        if B%2 !=0:
            B -= 1
        A += B//2
        B = B//2
        K -= 1
    
print(A,B)
Problem:
In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.   For example, May 3, 2018 is written as 2018-5-3, or 5-3 without the year.  In this country, a date is called _Takahashi_ when the month and the day are equal as numbers. For example, 5-5 is Takahashi.   How many days from 2018-1-1 through 2018-a-b are Takahashi?

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
if a<b:
    print(a)
else:
    print(a-1)

Fixed, accepted submission:
a,b=map(int,input().split())
if a<=b:
    print(a)
else:
    print(a-1)
Problem:
Write a program which reads two integers a, b and an operator op, and then prints the value of a op b.  The operator op is '+', '-', '*' or '/' (sum, difference, product or quotient). The division should truncate any fractional part.

Incorrect submission (verdict: Wrong Answer):
result = []
while True:
    a,op,b = input().split()
    if op == '?':
        break
    elif op == '+':
        result.append(a + b)
    elif op == '-':
        result.append(a - b)
    elif op == '*':
        result.append(a * b)
    elif op == '/':
        result.append(a / b)
        
for i in result:
    print(i)

Fixed, accepted submission:
result = []
while True:
    a,op,b = input().split()
    
    if op == '?':
        break
    elif op == '+':
        result.append(int(a) + int(b))
    elif op == '-':
        result.append(int(a) - int(b))
    elif op == '*':
        result.append(int(a) * int(b))
    elif op == '/':
        result.append(int(int(a) / int(b)))
        
for i in result:
    print(i)
Problem:
AtCoDeer the deer is going on a trip in a two-dimensional plane. In his plan, he will depart from point (0, 0) at time 0, then for each i between 1 and N (inclusive), he will visit point (x_i,y_i) at time t_i.  If AtCoDeer is at point (x, y) at time t, he can be at one of the following points at time t+1: (x+1,y), (x-1,y), (x,y+1) and (x,y-1). Note that **he cannot stay at his place**. Determine whether he can carry out his plan.

Incorrect submission (verdict: Wrong Answer):
from pprint import pprint

# import math
# import collections

n = int(input())

# a = list(map(int, input().split(' ')))
t, x, y = [0], [0], [0]
d = [0]

for i in range(1, n + 1):
    _t, _x, _y = map(int, input().split(' '))
    t.append(_t)
    x.append(_x)
    y.append(_y)

    d.append(abs(x[i] - x[0]) + abs(y[i] - y[0]))



movable = [False] * (n + 1)

for i in range(n + 1):
    if d[i] <= t[i] and (t[i] % 2 == d[i] % 2):
        movable[i] = True

if all(movable):
    res = 'YES'
else:
    res = 'NO'

# pprint(d)
# pprint(movable)
print(res)


Fixed, accepted submission:
from pprint import pprint

# import math
# import collections

n = int(input())

# a = list(map(int, input().split(' ')))
t, x, y = [0], [0], [0]
d = [0]
dd = [0]
td = [0]

for i in range(1, n + 1):
    _t, _x, _y = map(int, input().split(' '))
    t.append(_t)
    x.append(_x)
    y.append(_y)

    d.append(abs(x[i] - x[0]) + abs(y[i] - y[0]))
    dd.append(abs(x[i] - x[i-1]) + abs(y[i] - y[i-1]))
    td.append(t[i] - t[i-1])



movable = [False] * (n + 1)

for i in range(n + 1):
    if d[i] <= t[i] and (t[i] % 2 == d[i] % 2) and dd[i] <= td[i]:
        movable[i] = True

if all(movable):
    res = 'Yes'
else:
    res = 'No'

# pprint(d)
# pprint(movable)
print(res)
Problem:
Let's first write a program to calculate the score from a pair of input and output. You can know the total score by submitting your solution, or an official program to calculate a score is often provided for local evaluation as in this contest. Nevertheless, writing a score calculator by yourself is still useful to check your understanding of the problem specification. Moreover, the source code of the score calculator can often be reused for solving the problem or debugging your solution. So it is worthwhile to write a score calculator unless it is very complicated.

Incorrect submission (verdict: Wrong Answer):
D = int(input())
C = list(map(int, input().split()))
S = [list(map(int, input().split())) for _ in range(D)]

tL = []
for i in range(D):
    tL.append(max(S))

for t in tL:
    print(t)

Fixed, accepted submission:
D = int(input())
C = list(map(int, input().split()))
S = [list(map(int, input().split())) for _ in range(D)]

socre = 0
his = [0] * len(C)

for i in range(D):
    t = int(input())
    t -= 1
    his[t] = i + 1
    sat = 0
    for j in range(len(C)):
        sat += C[j] * (i - his[j] + 1)
    socre += S[i][t] - sat

    print(socre)
Problem:
There is an image with a height of H pixels and a width of W pixels. Each of the pixels is represented by either `.` or `*`. The character representing the pixel at the i-th row from the top and the j-th column from the left, is denoted by C_{i,j}.  Extend this image vertically so that its height is doubled. That is, print a image with a height of 2H pixels and a width of W pixels where the pixel at the i-th row and j-th column is equal to C_{(i+1)/2,j} (the result of division is rounded down).

Incorrect submission (verdict: Wrong Answer):
import numpy as np

s = input().split()


h = int(s[0])


w = int(s[1])


answer = []

for num in range(h):
    x = input().split()
    answer.append(x[0])
    answer.append(x[0])

for nun in range(h * 2):
    print(answer[num])






Fixed, accepted submission:
import numpy as np

s = input().split()


h = int(s[0])


w = int(s[1])


answer = []

for num in range(h):
    x = input().split()
    answer.append(x[0])
    answer.append(x[0])

for num in range(h * 2):
    print(answer[num])
Problem:
M-kun has the following three cards:    * A red card with the integer A.   * A green card with the integer B.   * A blue card with the integer C.  He is a genius magician who can do the following operation at most K times:    * Choose one of the three cards and multiply the written integer by 2.  His magic is successful if both of the following conditions are satisfied after the operations:    * The integer on the green card is **strictly** greater than the integer on the red card.   * The integer on the blue card is **strictly** greater than the integer on the green card.  Determine whether the magic can be successful.

Incorrect submission (verdict: Wrong Answer):
b , g , r = map(int,input().split())

c = int(input())

flag = 'No' 

for i in range(c):
    if r < g or r < b:
        r = r *2
    
    elif g < b:
        g = g *2
    
    if r > g > b:
        flag = 'YES'
        break
    
print(flag)

Fixed, accepted submission:
a, b, c = map(int, input().split())
k = int(input())

cnt = 0

while a >= b:
    b *= 2
    cnt += 1

while b >= c:
    c *= 2
    cnt += 1

if cnt <= k:
    print("Yes")
else:
    print("No")
Problem:
Snuke lives at position x on a number line. On this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.  Snuke decided to get food delivery from the closer of stores A and B. Find out which store is closer to Snuke's residence.  Here, the distance between two points s and t on a number line is represented by |s-t|.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-


def main():
    """Function."""
    x, a, b = map(int, input().split())
    if abs(a - x) < abs(b - x):
        print("A")
    else:
        print("b")


if __name__ == "__main__":
    main()


Fixed, accepted submission:
# -*- coding: utf-8 -*-


def main():
    """Function."""
    x, a, b = map(int, input().split())
    if abs(a - x) < abs(b - x):
        print("A")
    else:
        print("B")


if __name__ == "__main__":
    main()
Problem:
There are N positive integers written on a blackboard: A_1, ..., A_N.  Snuke can perform the following operation when all integers on the blackboard are even:    * Replace each integer X on the blackboard by X divided by 2.  Find the maximum possible number of operations that Snuke can perform.

Incorrect submission (verdict: Time Limit Exceeded):
input()
c = map(int,input().split())
count = 0
while all(w%2 == 0 for w in c):
    c = [w/2 for s in c]
    count =+ 1
print(count)

Fixed, accepted submission:
input()
c =list(map(int,input().split()))
count = 0
while all(w%2==0 for w in c):
    c=[w/2 for w in c]
    count+=1
print(count)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
a = input()

a= int(a)

x=(1000 - a)
y=abs(x)





#input 1900  print 100 (2000)
#input 3000  print 0 (3000)

Fixed, accepted submission:
a = input()
a= int(a)

if 1<= a < 1000:
    print(1000 - a)
if 1000 < a < 2000:
    print(2000 - a)
if 2000 < a < 3000:
    print(3000 - a)
if 3000 < a < 4000:
    print(4000 - a)
if 4000< a < 5000:
    print(5000 - a)
if 5000< a < 6000:
    print(6000 - a)
if 6000< a < 7000:
    print(7000 - a)
if 7000 < a < 8000:
    print(8000 - a)
if 8000 < a < 9000:
    print(9000 - a)
if 9000 < a <10000:
    print(10000 - a)
if a == 1000:
    print(0)
if a == 2000:
    print(0)
if a == 3000:
    print(0)
if a == 4000:
    print(0)
if a == 5000:
    print(0)
if a == 6000:
    print(0)
if a == 7000:
    print(0)
if a == 8000:
    print(0)
if a == 9000:
    print(0)
if a == 10000:
    print(0)





#input 1900  print 100 (2000)
# input 1525 print 475 (2000)
# input 2500 print 500 (3000)
Problem:
There are N empty boxes arranged in a row from left to right. The integer i is written on the i-th box from the left (1 \leq i \leq N).  For each of these boxes, Snuke can choose either to put a ball in it or to put nothing in it.  We say a set of choices to put a ball or not in the boxes is good when the following condition is satisfied:    * For every integer i between 1 and N (inclusive), the total number of balls contained in the boxes with multiples of i written on them is congruent to a_i modulo 2.  Does there exist a good set of choices? If the answer is yes, find one good set of choices.

Incorrect submission (verdict: Wrong Answer):
import sys,math,copy
input = sys.stdin.readline

N=int(input().strip())
An=[int(x) for x in input().strip().split()]
Bn=[-1 for _ in range(N)]
Sum=0
for i in range(N-1,-1,-1):
    temp=0
    c=2
    index=(i+1)*c
    while index <= N:
        temp=temp^An[index-1]
        c+=1
        index+=(i+1)

    ball=An[i] ^ temp
    Sum+=ball
    Bn[i]= str(ball)


print(Sum)
if Sum!=0:
    print(' '.join(Bn))



Fixed, accepted submission:
import sys,math,copy
input = sys.stdin.readline

N=int(input().strip())
An=[int(x) for x in input().strip().split()]
Bn=[-1 for _ in range(N)]
Sum=0
for i in range(N-1,-1,-1):
    temp=0
    index=(i+1)*2
    while index <= N:
        temp=temp^Bn[index-1]
        index+=(i+1)

    ball= An[i] ^ temp
    Sum+=ball
    Bn[i]= ball

print(Sum)
if Sum!=0:
    ans=[str(x+1) for x in range(N) if Bn[x]==1]
    print(' '.join(ans))
Problem:
Iroha loves _Haiku_. Haiku is a short form of Japanese poetry. A Haiku consists of three phrases with 5, 7 and 5 syllables, in this order.  To create a Haiku, Iroha has come up with three different phrases. These phrases have A, B and C syllables, respectively. Determine whether she can construct a Haiku by using each of the phrases once, in some order.

Incorrect submission (verdict: Wrong Answer):
a=list(map(int,input().split()))
print("Yes" if sorted(a)==[5,5,7] else "No")

Fixed, accepted submission:
a=list(map(int,input().split()))
print("YES" if sorted(a)==[5,5,7] else "NO")
Problem:
There are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i). Thus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.  In order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B. Then, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i). Thus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.  When activated, each type of robot will operate as follows.    * When a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.    * When a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.  Snuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = int(input())

x = tuple([int(t)for t in input().split()]) 

print(sum(x))

Fixed, accepted submission:
n = int(input())
k = int(input())
 
x = tuple([int(t)for t in input().split()]) 
 
ans = 0
for x_i in x:
  if k-x_i>x_i:
    ans+=x_i*2
  else:
    ans+=(k-x_i)*2
    
print(ans)
Problem:
You are given an integer N. Build an undirected graph with N vertices with indices 1 to N that satisfies the following two conditions:    * The graph is simple and connected.   * There exists an integer S such that, for every vertex, the sum of the indices of the vertices adjacent to that vertex is S.  It can be proved that at least one such graph exists under the constraints of this problem.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
flag=0
if n%2==0:flag=1
for i in range(1,n):
    for j in range(i+1,n+1):
        if i+j!=n+flag:print(i,j)


Fixed, accepted submission:
n=int(input())
flag=0
ans=[]
cnt=0
if n%2==0:flag=1
for i in range(1,n):
    for j in range(i+1,n+1):
        if i+j!=n+flag:
            cnt+=1
            ans.append([i,j])
print(cnt)
for i in ans:
    print(*i)
Problem:
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = input()

max_count = 0
for i in range(0, N-1):
  X = S[0:i+1]
  Y = S[i+1:]

  X_set = set(X)
  Y_set = set(Y)
  print(X,Y,X_set)

  count = len(X_set & Y_set)
  if max_count < count:
    max_count = count

print(max_count)

Fixed, accepted submission:
N = int(input())
S = input()

max_count = 0
for i in range(0, N-1):
  X = S[0:i+1]
  Y = S[i+1:]

  X_set = set(X)
  Y_set = set(Y)

  count = len(X_set & Y_set)
  if max_count < count:
    max_count = count

print(max_count)
Problem:
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.   But he couldn't see some parts of the list. Invisible part is denoted `?`.      Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.   Note: If there are pair of people with same handle name, either one may come first.

Incorrect submission (verdict: Wrong Answer):
import sys
N = int(input())
S = [sys.stdin.readline().rstrip() for i in range(N)]
T = sys.stdin.readline().rstrip()
FS = [S[i].replace('?','z') for i in range(N)]
BS = [S[i].replace('?','a') for i in range(N)]
FS.append(T)
BS.append(T)
list.sort(FS)
list.sort(BS)
for i in range(FS.index(T)+1,len(BS) - BS[-1::-1].index(T)+1):
	print(i,end=" ")

Fixed, accepted submission:
import sys
N = int(input())
S = [sys.stdin.readline().rstrip() for i in range(N)]
T = sys.stdin.readline().rstrip()
FS = [S[i].replace('?','z') for i in range(N)]
BS = [S[i].replace('?','a') for i in range(N)]
FS.append(T)
BS.append(T)
list.sort(FS)
list.sort(BS)
ends = len(BS) - BS[-1::-1].index(T)
for i in range(FS.index(T)+1,ends):
	print(i,end=" ")
print(ends)
Problem:
Snuke received a positive integer N from Takahashi. A positive integer m is called a _favorite number_ when the following condition is satisfied:    * The quotient and remainder of N divided by m are equal, that is, \lfloor \frac{N}{m} \rfloor = N \bmod m holds.  Find all favorite numbers and print the sum of those.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
ans = 0
for i in range(1,int(N**(0.5))):
    if N%i == 0:
        ans += N//i -1
print(ans)

Fixed, accepted submission:
N = int(input())
ans = 0
for i in range(1,int(N**(0.5))+1):
    if N%i == 0 and N//i > i+1:
        ans += N//i - 1
print(ans)
Problem:
In a public bath, there is a shower which emits water for T seconds when the switch is pushed.  If the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds. Note that it does not mean that the shower emits water for T additional seconds.  N people will push the switch while passing by the shower. The i-th person will push the switch t_i seconds after the first person pushes it.  How long will the shower emit water in total?

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
k=list(map(int,input().split()))

time=0
for i in range(a-1):
    tc=k[i+1]-k[i]
    if tc<b:
        time = time+tc
    else:
        time=time+b
print(time)

Fixed, accepted submission:
a,b=map(int,input().split())
k=list(map(int,input().split()))

time=b
for i in range(a-1):
    tc=k[i+1]-k[i]
    if tc<b:
        time = time+tc
    else:
        time=time+b
print(time)
Problem:
Find the number of _palindromic numbers_ among the integers between A and B (inclusive). Here, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.

Incorrect submission (verdict: Wrong Answer):
a,b = map(int,input().split())
n = 0
for i in range(a,b+1):
    c = [int(i) for c in str(i)]
    if c[0] == c[4] and c[1] == c[3]:
        n += 1
print(n)

Fixed, accepted submission:
a,b = map(int,input().split())
n = 0
for i in range(a,b+1):
    c = [int(j) for j in list(str(i))]
    if c[0] == c[4] and c[1] == c[3]:
        n += 1
print(n)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
import sys
read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
from collections import Counter
def main():
    n = int(input())
    d1 = {'AC':0, 'WA':0, 'TLE': 0,'RE':0}
    s = []
    for _ in range(n):
        s.append(input())
    sa = Counter(s)
    print(sa)
    for k, v in sa.items():
        d1[k] += v
    print('AC x', d1['AC'])
    print('WA x', d1['WA'])
    print('TLE x', d1['TLE'])
    print('RE x', d1['RE'])

if __name__ == '__main__':
    main()

Fixed, accepted submission:
import sys
read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
from collections import Counter
def main():
    n = int(input())
    d1 = {'AC':0, 'WA':0, 'TLE': 0,'RE':0}
    s = []
    for _ in range(n):
        s.append(input())
    sa = Counter(s)
    for k, v in sa.items():
        d1[k] += v
    print('AC x', d1['AC'])
    print('WA x', d1['WA'])
    print('TLE x', d1['TLE'])
    print('RE x', d1['RE'])

if __name__ == '__main__':
    main()
Problem:
E869120 has A 1-yen coins and infinitely many 500-yen coins.   Determine if he can pay exactly N yen using only these coins.

Incorrect submission (verdict: Wrong Answer):

N,A =[int(input()) for i in range(2)]
for k in range(1,A+1):
    if N % k == 0:
        print("YES")
    else:
        print("NO")


Fixed, accepted submission:

N,A =[int(input()) for i in range(2)]
if 0 <= (N % 500) <= A:
    print("Yes")
else:
    print("No")