TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given three integers A, B and C. Determine whether C is not less than A and not greater than B.

Incorrect submission (verdict: Wrong Answer):
a, b, c = map(int, input().split())
if (c >= a) and (b >= c):
  print('YES')
else:
  print('NO')

Fixed, accepted submission:
a, b, c = map(int, input().split())
if a <= c <= b:
  print('Yes')
else:
  print('No')
Problem:
Snuke is buying a bicycle. The bicycle of his choice does not come with a bell, so he has to buy one separately.  He has very high awareness of safety, and decides to buy two bells, one for each hand.  The store sells three kinds of bells for the price of a, b and c yen (the currency of Japan), respectively. Find the minimum total price of two different bells.

Incorrect submission (verdict: Wrong Answer):
a,b,c=map(int,input().split())
n=[a+b,a+c,b+c]
n.sort()
print(n[-1])

Fixed, accepted submission:
a,b,c=map(int,input().split())
n=[a+b,a+c,b+c]
n.sort()
print(n[0])
Problem:
We have an H-by-W matrix. Let a_{ij} be the element at the i-th row from the top and j-th column from the left. In this matrix, each a_{ij} is a lowercase English letter.  Snuke is creating another H-by-W matrix, A', by freely rearranging the elements in A. Here, he wants to satisfy the following condition:    * Every row and column in A' can be read as a palindrome.  Determine whether he can create a matrix satisfying the condition.

Incorrect submission (verdict: Wrong Answer):
# -*- coding: utf-8 -*-
from collections import Counter
h,w = map(int, input().split())
al = []
for _ in range(h):
    al += list(input())

c = Counter(al)

if h==1 or w==1:
    res = "YES"
    one = []
    for k in c.keys():
        if c[k]%2==0:
            pass
        elif c[k]%2==1:
            one.append(k)
        else:
            res = "NO"
            break
    if res=="YES" and len(one)!=1:
        res = "NO"
elif h%2==0 and w%2==0:
    res = "YES"
    for k in c.keys():
        if c[k]%4!=0:
            res = "NO"
            break
elif h%2==1 and w%2==1:
    res = "YES"
    one = []
    for k in c.keys():
        if c[k]%4==0:
            pass
        elif c[k]%4==1:
            one.append(k)
        else:
            res = "NO"
            break
    if res=="YES" and len(one)!=1:
        res = "NO"
else:
    res = "YES"
    for k in c.keys():
        if c[k]%2!=0:
            res = "NO"
            break

print(res)


Fixed, accepted submission:
# -*- coding: utf-8 -*-
from collections import Counter
h,w = map(int, input().split())
al = []
for _ in range(h):
    al += list(input())

c = Counter(al)

if h%2==1 and w%2==1:
    for k in c.keys():
        if c[k]%2==1:
            c[k] -= 1
            break

g4 = (h//2)*(w//2)*4
for k in c.keys():
    while c[k]>=4 and g4>0:
        c[k] -= 4
        g4 -= 4
if g4>0:
    print("No")
    exit()

g2 = (h%2)*(w//2)*2 + (w%2)*(h//2)*2
for k in c.keys():
    while c[k]>=2 and g2>0:
        c[k] -= 2
        g2 -= 2
if g2>0:
    print("No")
    exit()

for k in c.keys():
    if c[k]>0:
        print("No")
        exit()
print("Yes")
Problem:
The factory of the Impractically Complicated Products Corporation has many manufacturing lines and the same number of corresponding storage rooms. The same number of conveyor lanes are laid out in parallel to transfer goods from manufacturing lines directly to the corresponding storage rooms. Now, they plan to install a number of robot arms here and there between pairs of adjacent conveyor lanes so that goods in one of the lanes can be picked up and released down on the other, and also in the opposite way. This should allow mixing up goods from different manufacturing lines to the storage rooms.  Depending on the positions of robot arms, the goods from each of the manufacturing lines can only be delivered to some of the storage rooms. Your task is to find the number of manufacturing lines from which goods can be transferred to each of the storage rooms, given the number of conveyor lanes and positions of robot arms.

Incorrect submission (verdict: Wrong Answer):
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    n,q = LI()
    qa = sorted([LI() for _ in range(q)])
    u = [0] * (n+2)
    d = [0] * (n+2)

    for x,i in qa:
        u[i+1] = u[i] + 1
        d[i] = d[i+1] + 1
    rr = []
    for i in range(1,n+1):
        rr.append(u[i]+d[i]+1)


    return '\n'.join(map(str,rr))


print(main())




Fixed, accepted submission:
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools

sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
dd = [(0,-1),(1,0),(0,1),(-1,0)]
ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)


def main():
    n,q = LI()
    qa = sorted([LI() for _ in range(q)])
    u = [0] * (n+2)
    d = [0] * (n+2)

    for x,i in qa:
        u[i+1] = u[i] + 1
        d[i] = d[i+1] + 1
    rr = []
    for i in range(1,n+1):
        rr.append(u[i]+d[i]+1)


    return ' '.join(map(str,rr))


print(main())
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
#coding: utf-8
i = 0
AC = 0
WA = 0
TLE = 0
RE = 0
num = int(input())
print(num)
while i <num:
  line = input()
  #print(line)
  if line == "AC":
    AC += 1
  if line == "WA":
    WA += 1
  if line == "TLE":
    TLE += 1
  if line == "RE":
    RE += 1
  i += 1
print("AC x " + str(AC))
print("WA x " + str(WA))
print("TLE x " + str(TLE))
print("RE x " + str(RE))

Fixed, accepted submission:
#coding: utf-8
i = 0
AC = 0
WA = 0
TLE = 0
RE = 0
num = int(input())
#print(num)
while i <num:
  line = input()
  #print(line)
  if line == "AC":
    AC += 1
  if line == "WA":
    WA += 1
  if line == "TLE":
    TLE += 1
  if line == "RE":
    RE += 1
  i += 1
print("AC x " + str(AC))
print("WA x " + str(WA))
print("TLE x " + str(TLE))
print("RE x " + str(RE))
Problem:
We have N sticks with negligible thickness. The length of the i-th stick is A_i.  Snuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides. Find the maximum possible area of the rectangle.

Incorrect submission (verdict: Wrong Answer):
# encoding: utf-8
N = int(input())
A = list(map(int, input().split()))

A.sort()

view = -1
lengths = []
cnt = 0
for Ai in reversed(A):
    if Ai > view:
        view = Ai
        cnt = 0
    cnt += 1
    if cnt >= 2:
        lengths.append(Ai)
        cnt = 0
    if len(lengths) > 1: break

print(lengths[-1] * lengths[-2] if len(lengths) > 1 else 0)

Fixed, accepted submission:
# encoding: utf-8
N = int(input())
A = list(map(int, input().split()))

A.sort()

view = 10 ** 9 + 7
lengths = [0] * 2
idx = 0
for Ai in reversed(A):
    if Ai < view:
        view = Ai
        cnt = 0
    cnt += 1
    if cnt >= 2:
        lengths[idx] = view
        cnt = 0
        idx += 1
    if idx > 1: break


print(lengths[0] * lengths[1] if idx > 1 else 0)
Problem:
Rng is going to a festival.  The name of the festival is given to you as a string S, which ends with `FESTIVAL`, from input. Answer the question: "Rng is going to a festival of what?" Output the answer.  Here, assume that the name of "a festival of s" is a string obtained by appending `FESTIVAL` to the end of s. For example, `CODEFESTIVAL` is a festival of `CODE`.

Incorrect submission (verdict: Wrong Answer):
print(input().rstrip('FESTIVAL'))

Fixed, accepted submission:
x=input()
print(x[0:len(x)-8])
Problem:
A Hitachi string is a concatenation of one or more copies of the string `hi`.  For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.  Given a string S, determine whether S is a Hitachi string.

Incorrect submission (verdict: Wrong Answer):
s = input()
t =0 
for s in s:
  if s == "h":
    t=1
  elif s =="i":
    if t == 0:
      t = 0
      print("No")
      quit()
  else:
    print("No")
    quit()
if t == 1:
  print("No")
else:
  print("Yes")

Fixed, accepted submission:
s = input()
t =0 
for s in s:
  if s == "h":
    t=1
  elif s =="i":
    if t == 0:
      t = 0
      print("No")
      quit()
    t = 0
  else:
    print("No")
    quit()
if t == 1:
  print("No")
else:
  print("Yes")
Problem:
Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) otherwise.  You are given Smeke's current rating, x. Print `ABC` if Smeke will participate in ABC, and print `ARC` otherwise.

Incorrect submission (verdict: Wrong Answer):
print(['ABC','ARC'][int(input())<1200])

Fixed, accepted submission:
print(['ABC','ARC'][int(int(input())>=1200)])
Problem:
We call a 4-digit integer with three or more consecutive same digits, such as 1118, **good**.  You are given a 4-digit integer N. Answer the question: Is N **good**?

Incorrect submission (verdict: Wrong Answer):
S = input()
res = S[0]
ans = 0
for i in range(1,len(S)):
  if S[i] == res:
    ans += 1
    res = S[i]
  else:
    ans = 0
    res = S[i]
if ans == 3:
  print('Yes')
else:
  print('No')

Fixed, accepted submission:
S = input()
res = S[0]
ans = 1
for i in range(1,len(S)):
  if S[i] == res:
    ans += 1
    res = S[i]
    if ans == 3:
      print('Yes')
      exit()
  else:
    ans = 1
    res = S[i]

print('No')
Problem:
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.

Incorrect submission (verdict: Wrong Answer):
a, b = map(int, input().split())
if a % 2 == 0 or b % 2 == 0:
  print("even")
else:
  print("odd")

Fixed, accepted submission:
a, b = map(int, input().split())
if a % 2 == 0 or b % 2 == 0:
  print("Even")
else:
  print("Odd")
Problem:
Quickly after finishing the tutorial of the online game _ATChat_ , you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the **friendliness** of Player i is A_i.  The N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.  When each player, except the first one to arrive, arrives at the place, the player gets **comfort** equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.  What is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?

Incorrect submission (verdict: Wrong Answer):
N = int(input())
A=list(map(int,input().split()))
A.sort(reverse=True)
print(A)
sum=0
for i in range(1,N):
    sum+=A[i//2]
print(sum)

Fixed, accepted submission:
N = int(input())
A=list(map(int,input().split()))
A.sort(reverse=True)
sum=0
for i in range(1,N):
    sum+=A[i//2]
print(sum)
Problem:
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).  Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.

Incorrect submission (verdict: Wrong Answer):
import re

s = input()

result = re.search(r"A.*Z", s)
print(result.group(0))


Fixed, accepted submission:
import re

s = input()

result = re.search(r"A.*Z", s)
print(len(result.group(0)))
Problem:
Joisino is planning to open a shop in a shopping street.  Each of the five weekdays is divided into two periods, the morning and the evening. For each of those ten periods, a shop must be either open during the whole period, or closed during the whole period. Naturally, a shop must be open during at least one of those periods.  There are already N stores in the street, numbered 1 through N.  You are given information of the business hours of those shops, F_{i,j,k}. If F_{i,j,k}=1, Shop i is open during Period k on Day j (this notation is explained below); if F_{i,j,k}=0, Shop i is closed during that period. Here, the days of the week are denoted as follows. Monday: Day 1, Tuesday: Day 2, Wednesday: Day 3, Thursday: Day 4, Friday: Day 5. Also, the morning is denoted as Period 1, and the afternoon is denoted as Period 2.  Let c_i be the number of periods during which both Shop i and Joisino's shop are open. Then, the profit of Joisino's shop will be P_{1,c_1}+P_{2,c_2}+...+P_{N,c_N}.  Find the maximum possible profit of Joisino's shop when she decides whether her shop is open during each period, making sure that it is open during at least one period.

Incorrect submission (verdict: Wrong Answer):
n=int(input())
F=[]
for i in range(n):
    F.append(list(map(int,input().split())))
P=[]
for i in range(n):
    P.append(list(map(int,input().split())))

count=2**10
both=[0]*n
ans=-1000000000
profit=0
num=0
for i in range(1023):
    count+=1
    bit=bin(count)
    for j in range(n):
        for k in range(10):
            if int(bit[k+3])&F[j][k]:
                num+=1
        profit+=P[j][num]   
        num=0           
    if profit>ans:
        print(profit)
        print(count)
        ans=profit
    profit=0
print(ans)

Fixed, accepted submission:
n=int(input())
F=[]
for i in range(n):
    F.append(list(map(int,input().split())))
P=[]
for i in range(n):
    P.append(list(map(int,input().split())))

count=2**10
both=[0]*n
ans=-1000000000
profit=0
num=0
for i in range(1023):
    count+=1
    bit=bin(count)
    for j in range(n):
        for k in range(10):
            if int(bit[k+3])&F[j][k]:
                num+=1
        profit+=P[j][num]   
        num=0           
    if profit>ans:
        ans=profit
    profit=0
print(ans)
Problem:
How many ways are there to choose two distinct positive integers totaling N, disregarding the order?

Incorrect submission (verdict: Wrong Answer):
import os
import numpy as np

class getStdin(object):
    @classmethod
    def get_int(cls):
        return int(input())

    @classmethod
    def get_ss_int(cls):
        return list(map(int, input().split()))

    @classmethod
    def get_na_int(cls):
        return np.array(sorted(list(map(int, input().split()))))

    @classmethod
    def get_na_intr(cls):
        return np.array(sorted(list(map(int, input().split())))[::-1])

if __name__ == '__main__':
    n = getStdin.get_int()
    print(n//2)
    os.sys.exit(0)

Fixed, accepted submission:
import os
import numpy as np

class getStdin(object):
    @classmethod
    def get_int(cls):
        return int(input())

    @classmethod
    def get_ss_int(cls):
        return list(map(int, input().split()))

    @classmethod
    def get_na_int(cls):
        return np.array(sorted(list(map(int, input().split()))))

    @classmethod
    def get_na_intr(cls):
        return np.array(sorted(list(map(int, input().split())))[::-1])

if __name__ == '__main__':
    n = getStdin.get_int()
    if n % 2 == 0:
        print(n//2 -1)
    else:
        print(n//2)
    os.sys.exit(0)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
s = input()
t = input()

s=sorted(s)
t=sorted(t)

if s<t:
    print("Yes")
else:
    print("No")

Fixed, accepted submission:
s = input()
t = input()

s=sorted(s)
t=sorted(t,reverse=True)

if s<t:
    print("Yes")
else:
    print("No")
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())
print(N*(N+1)/2)


Fixed, accepted submission:










N=int(input())

sum_candy=(N * (N+1) / 2)
print(int(sum_candy))
Problem:
Write a program which reads three integers a, b and c, and prints the number of divisors of c between a and b.

Incorrect submission (verdict: Time Limit Exceeded):
a, b, c= map(int, input().split())
d=0
while a != b+1:
    if c%a == 0:
        d+=1
        a+=1
print(d)


Fixed, accepted submission:
a, b, c= map(int, input().split())
d=0
while a != b+1:
    if c%a == 0:
        d+=1
    a+=1
print(d)
Problem:
Takahashi has a strong stomach. He never gets a stomachache from eating something whose "best-by" date is at most X days earlier. He gets a stomachache if the "best-by" date of the food is X+1 or more days earlier, though.  Other than that, he finds the food delicious if he eats it not later than the "best-by" date. Otherwise, he does not find it delicious.  Takahashi bought some food A days before the "best-by" date, and ate it B days after he bought it.  Write a program that outputs `delicious` if he found it delicious, `safe` if he did not found it delicious but did not get a stomachache either, and `dangerous` if he got a stomachache.

Incorrect submission (verdict: Wrong Answer):
X, A, B = map(int, input().split())

if A <= B:
  print("delicious")
elif X + A <= B:
  print("safe")
else:
  print("dangerous")

Fixed, accepted submission:
X, A, B = map(int, input().split())

if A >= B:
  print("delicious")
elif X + A >= B:
  print("safe")
else:
  print("dangerous")
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Time Limit Exceeded):
import math
N = int(input())
d = math.factorial(N)

k, ans = 1, 1
for i in range(1, N + 1):
    while d % i == 0:
        d //= i
        k += 1
    ans *= k
    k = 1
print(ans % (10**9 + 7))


Fixed, accepted submission:
import math
N = int(input())
d = math.factorial(N)

k, ans = 1, 1
for i in range(2, N + 1):
    while d % i == 0:
        d //= i
        k += 1
    ans *= k
    k = 1
print(ans % (10**9 + 7))
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
x = list(map(int, input().split()))
res=[]

if x[0]+x[2]>x[1]-x[2]:
    for i in range(x[0],x[1]+1):
        print(i)
    quit()

for i in range(x[0],x[0]+x[2]):
    res.append(i)
for i in range(x[1]-x[2]+1,x[1]+1):
    res.append(i)

print(res)

Fixed, accepted submission:
x = list(map(int, input().split()))
res=[]

if x[0]+x[2]-1>=x[1]-x[2]:
    for i in range(x[0],x[1]+1):
        print(i)
    quit()

for i in range(x[0],x[0]+x[2]):
    res.append(i)
for i in range(x[1]-x[2]+1,x[1]+1):
    res.append(i)

for i in res:
    print(i)
Problem:
Snuke loves puzzles.  Today, he is working on a puzzle using `S`\- and `c`-shaped pieces. In this puzzle, you can combine two `c`-shaped pieces into one `S`-shaped piece, as shown in the figure below:    Snuke decided to create as many `Scc` groups as possible by putting together one `S`-shaped piece and two `c`-shaped pieces.  Find the maximum number of `Scc` groups that can be created when Snuke has N `S`-shaped pieces and M `c`-shaped pieces.

Incorrect submission (verdict: Wrong Answer):
s_num, c_num = map(int, input().split())
print(s_num, c_num)
if s_num * 2 > c_num:
    print(s_num)
else:
    ans = s_num
    c_num -= s_num * 2
    ans += c_num // 4
    print(ans)
    


Fixed, accepted submission:
s_num, c_num = map(int, input().split())

ans = 0

if s_num * 2 >= c_num:
    ans = c_num // 2
else:
    ans += s_num
    c_num -= s_num * 2
    ans += c_num // 4

print(ans)
Problem:
Snuke has a grid consisting of three squares numbered 1, 2 and 3. In each square, either `0` or `1` is written. The number written in Square i is s_i.  Snuke will place a marble on each square that says `1`. Find the number of squares on which Snuke will place a marble.

Incorrect submission (verdict: Wrong Answer):
s = input()
s1 = int(s[0])
s2 = int(s[1])
s3 = int(s[2])
ans = 0
if s1 == 1:
    ans += 1
elif s2 ==1:
    ans += 1
elif s3 == 1:
    ans += 1
print(ans)

Fixed, accepted submission:
s = input()
s1 = int(s[0])
s2 = int(s[1])
s3 = int(s[2])
ans = s1+s2+s3
print(ans)
Problem:
It is September 9 in Japan now.  You are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?

Incorrect submission (verdict: Wrong Answer):
a=input()
print('YES'if '9'in a else 'NO')

Fixed, accepted submission:
a=input()
print('Yes'if '9'in a else 'No')
Problem:
You have A 500-yen coins, B 100-yen coins and C 50-yen coins (yen is the currency of Japan). In how many ways can we select some of these coins so that they are X yen in total?  Coins of the same kind cannot be distinguished. Two ways to select coins are distinguished when, for some kind of coin, the numbers of that coin are different.

Incorrect submission (verdict: Wrong Answer):
A = int(input())
B = int(input())
C = int(input())
X = int(input())

def solve(A,B,C):
    count = 0
    for a in A: 
        for b in B:
            for c in C:
                if 500*a + 100*b + 50*c == X:
                    count += 1
            
    return count

Fixed, accepted submission:
A = int(input())
B = int(input())
C = int(input())
X = int(input())
res=0
for  i in range(A + 1):
    for j in range(B + 1):
        for k in range(C + 1):
            if 500*i + 100*j + 50*k == X:
                res += 1
print(res)
Problem:
As a token of his gratitude, Takahashi has decided to give his mother an integer sequence. The sequence A needs to satisfy the conditions below:    * A consists of integers between X and Y (inclusive).   * For each 1\leq i \leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.  Find the maximum possible length of the sequence.

Incorrect submission (verdict: Time Limit Exceeded):
x,y = map(int,input().split())
d = y//x
ans = 0
while 0 < d:
  ans += 1
  d // 2
print(ans)

Fixed, accepted submission:
x,y = map(int,input().split())
d = y//x
ans = 0
while 0 < d:
  ans += 1
  d //= 2
print(ans)