TnT/CodeNet4Repair huggingface dataset:
Problem:
You are given an integer N. Find the number of the positive divisors of N!, modulo 10^9+7.

Incorrect submission (verdict: Wrong Answer):
N=int(input())
div=1000000007

primedict= {i:True for i in range(2,N+1)}

for i in range(2,N+1):
        if primedict[i]==True:
                j=2
                while i*j<=N:
                        primedict[i*j]=False
                        j+=1

primelist = [i for i in  range(2,N+1) if primedict[i]==True]

print(primelist)

primecntdict={p:0 for p in primelist}

for n in range(2,N+1):
        for p in [p for p in primelist if p <= n]:
                while n%p==0:
                        n/=p
                        primecntdict[p]+=1

res=1
for p in primelist:
        res*=primecntdict[p]+1
        res%=div
print(primecntdict[2])
print(res)


Fixed, accepted submission:
N=int(input())
div=1000000007

primelist=list(range(2,N+1))

for i in range(2,N+1):
        j=2
        while i*j<=N:
                if i*j in primelist:
                        primelist.remove(i*j)
                j+=1

primecntdict={p:0 for p in primelist}

for n in range(2,N+1):
        for p in [p for p in primelist if p <= n]:
                while n%p==0:
                        n/=p
                        primecntdict[p]+=1

res=1
for p in primelist:
        res*=primecntdict[p]+1
        res%=div

print(res)
Problem:
You are given strings s and t, consisting of lowercase English letters. You will create a string s' by freely rearranging the characters in s. You will also create a string t' by freely rearranging the characters in t. Determine whether it is possible to satisfy s' < t' for the lexicographic order.

Incorrect submission (verdict: Wrong Answer):
import numpy as np
from collections import Counter
import collections
round = lambda x:(x*2+1)//2
a = input()
b = input()
a = list(a)
b = list(b)
b = sorted(b,reverse = True)
a = sorted(a)
a = str(a)
b = str(b)
if a >  b :
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
import numpy as np
from collections import Counter
import collections
round = lambda x:(x*2+1)//2
a = input()
b = input()
a = list(a)
b = list(b)
b = sorted(b,reverse = True)
a = sorted(a)
#a = a[1:]
a = "".join(a)
b = "".join(b)
if a <  b :
  print("Yes")
else:
  print("No")
Problem:
Takahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.  The consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \times 1.08 yen (rounded down to the nearest integer).  Takahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.  If there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.

Incorrect submission (verdict: Wrong Answer):
#B
N = int(input())

X = N / 1.08
if N % 1.08 >= 0.5:
    X = int(X) + 1
else:
    X = int(X)

Y = int(X * 1.08)
if N == Y:
    print(Y)
else:
    print(":(")

Fixed, accepted submission:
#B
N = int(input())

X = N // 1.08
Xminus = X - 1
Xplus = X + 1

X_list = [X, Xplus, Xminus]
# print(X_list)
flug = False

for x in X_list:
#     print(x * 1.08)
    if int(x * 1.08) == N:
        print(int(x))
        flug = True
        break

if flug == False:
    print(":(")
Problem:
    図１に例示するように整数（0 以上 99 以下）をひしがたに並べます。このような、ひしがたを表すデータを読み込んで、一番上からスタートして一番下まで次のルールに従って進むとき、通過する整数の和の最大値を出力するプログラムを作成してください。    * 各ステップで、対角線上の左下か対角線上の右下に進むことができます。  例えば図1の例では、図2に示すように、7,3,8,7,5,7,8,3,7を選んで通ったとき、その和は最大の 55 （7+3+8+7+5+7+8+3+7=55） となります。

Incorrect submission (verdict: Wrong Answer):
path=[]
while(True):
    try:
        temp=list(map(int,input().split(',')))
        path.append(temp)
    except:
        break


Fixed, accepted submission:
INF=1e8
path=[]
dp=[]
while(True):
    try:
        temp=list(map(int,input().split(',')))
        path.append(temp)
        dp.append([INF for i in range(len(temp))])
    except:
        break
dp[0][0]=path[0][0]
for i in range(1,len(dp)):
    for j in range(len(dp[i])):
        if len(dp[i])>len(dp[i-1]):
            start=0 if j-1<0 else j-1
            dp[i][j]=max(dp[i-1][start:j+1])+path[i][j]
        else:
            dp[i][j]=max(dp[i-1][j:j+2])+path[i][j]
print(dp[-1][-1])
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
print(int(input())%1000)

Fixed, accepted submission:
print(-int(input())%1000)
Problem:
There are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i). Thus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.  In order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B. Then, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i). Thus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.  When activated, each type of robot will operate as follows.    * When a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.    * When a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.  Snuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
K = int(input())
a = list(map(int, input().split()))
sum_a = 0

for i in range(N):
    A = a[i]
    B = K-a[i]
    sum_a += min(A,B)
    
    
print(sum_a)

Fixed, accepted submission:
N = int(input())
K = int(input())
a = list(map(int, input().split()))
sum_a = 0

for i in range(N):
    A = 2*a[i]
    B = 2*(K-a[i])
    sum_a += min(A,B)
    
    
print(sum_a)
Problem:
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.  Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.

Incorrect submission (verdict: Wrong Answer):
c1 = input()
c2 = input()
c1 = c1[::-1]
if c1 == c2:
  print("Yes")
else:
  print("No")

Fixed, accepted submission:
c1 = input()
c2 = input()
c1 = c1[::-1]
if c1 == c2:
  print("YES")
else:
  print("NO")
Problem:
In _K-city_ , there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?

Incorrect submission (verdict: Wrong Answer):
a=input()
print(a[0]+str(len(a)-2)+a[-1])

Fixed, accepted submission:
n,m=map(int,input().split())
print((n-1)*(m-1))
Problem:
There is a directed graph G with N vertices and M edges. The vertices are numbered 1, 2, \ldots, N, and for each i (1 \leq i \leq M), the i-th directed edge goes from Vertex x_i to y_i. G **does not contain directed cycles**.  Find the length of the longest directed path in G. Here, the length of a directed path is the number of edges in it.

Incorrect submission (verdict: Wrong Answer):
import sys

sys.setrecursionlimit(10**5+10)

N, M = [int(_) for _ in input().split()]


lst_edge = [[] for _ in range(N)]

for _ in range(M):
  x, y = map(int, input().split()) 
  
  lst_edge[x-1].append(y-1)
  print(lst_edge)
        


dp = [-1] * N


def rec(v):
  
  if dp[v] != -1:
    return dp[v]
  ans = 0
  lst_nv = lst_edge[v]
  for nv in lst_nv:
    ans = max(ans, rec(nv) + 1)
  dp[v] = ans
  return dp[v]
    

ans = 0
for v in range(N):
  ans = max(ans, rec(v))
    
print(ans)
    

Fixed, accepted submission:
import sys

sys.setrecursionlimit(10**5+10)

N, M = [int(_) for _ in input().split()]


lst_edge = [[] for _ in range(N)]

for _ in range(M):
  
  x, y = [int(_)-1 for _ in input().split()] 
  lst_edge[x].append(y)
        


dp = [-1] * N


def rec(v):
  
  if dp[v] != -1:
    return dp[v]
  ans = 0
  lst_nv = lst_edge[v] 
  for nv in lst_nv:
    ans = max(ans, rec(nv) + 1) 
  dp[v] = ans 
  return dp[v]
    

ans = 0
for v in range(N):
  ans = max(ans, rec(v))
    
print(ans)
Problem:
AtCoder's head office consists of N rooms numbered 1 to N. For any two rooms, there is a direct passage connecting these rooms.  For security reasons, Takahashi the president asked you to set a **level** for every passage, which is a positive integer and must satisfy the following condition:    * For each room i\ (1 \leq i \leq N), if we leave Room i, pass through some passages whose levels are all equal and get back to Room i, the number of times we pass through a passage is always even.  Your task is to set levels to the passages so that the highest level of a passage is minimized.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

for i in range(1, N):
    print(' '.join(str(i) * (N - i)))


Fixed, accepted submission:
N = int(input())

for i in range(N - 1):
    row = []
    for j in range(i + 1, N):
        d = 0
        while (i & (1 << d)) == (j & (1 << d)):
            d += 1
        row.append(d + 1)
    print(*row)
Problem:
We will buy a product for N yen (the currency of Japan) at a shop.  If we use only 1000-yen bills to pay the price, how much change will we receive?  Assume we use the minimum number of bills required.

Incorrect submission (verdict: Wrong Answer):
a = int(input())

print(a%1000)

Fixed, accepted submission:
a = int(input())

if a%1000 == 0:
    print(0)
else:
    print(1000-a%1000)
Problem:
Print all the integers that satisfies the following in ascending order:    * Among the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.

Incorrect submission (verdict: Wrong Answer):
a,b,k=map(int,input().split())
A=[]
for i  in range(a,min(a+k,b+1)):
  A.append(i)
for i in range(max(b-k+1,a),b+1):
  A.append (i)
A=list(set(A))
for i in range(len(A)):
  print(i)

Fixed, accepted submission:
a,b,k=map(int,input().split())
A=[]
for i  in range(a,min(a+k,b+1)):
  A.append(i)
for i in range(max(b-k+1,a),b+1):
  A.append (i)
A=list(set(A))
A.sort()
for i in A:
  print(i)
Problem:
You are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.    An example of a trapezoid  Find the area of this trapezoid.

Incorrect submission (verdict: Wrong Answer):
a=[]
for i in range(3):
  a.append(int(input()))
  
print((a[0]+a[1])*a[2]/2)

Fixed, accepted submission:
a=[]
for i in range(3):
  a.append(int(input()))
  
print(int((a[0]+a[1])*a[2]/2))
Problem:
You are given two positive integers a and b. Let x be the average of a and b. Print x rounded up to the nearest integer.

Incorrect submission (verdict: Wrong Answer):
a,b=map(int,input().split())
c=(a+b)/2
d=(a+b)//2
if (d+0.5)<=c:
    print(d)
else:
    print(d-1)

Fixed, accepted submission:
import math
a,b=map(int,input().split())
c=(a+b)/2
print(math.ceil(c))
Problem:
Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers.  She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of **distinct** positive integers is called **special** if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is **not** 1.  Nagase wants to find a **special** set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a **special** set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
if n == 3:
    res = [2, 5, 63]
elif n == 4:
    res = [2, 5, 20, 63]
elif n == 5:
    res = [2, 5, 20, 30, 63]
else:
    res = [i for i in range(1, 30001)
           if i % 6 not in (1, 5)][:n]
    s = sum(res)
    if s % 6 == 2:
        res.pop(res.index(2))
        res.append(30000)
    elif s % 6 == 3:
        res.pop(res.index(3))
        res.append(30000)
    elif s % 6 == 5:
        res.pop(res.index(3))
        res.append(29998)

    print(*res)

Fixed, accepted submission:
n = int(input())
if n == 3:
    res = [2, 5, 63]
elif n == 4:
    res = [2, 5, 20, 63]
elif n == 5:
    res = [2, 5, 20, 30, 63]
else:
    res = [i for i in range(1, 30001)
           if i % 6 not in (1, 5)][:n]
    s = sum(res)
    if s % 6 == 2:
        res.pop(res.index(2))
        res.append(30000)
    elif s % 6 == 3:
        res.pop(res.index(3))
        res.append(30000)
    elif s % 6 == 5:
        res.pop(res.index(3))
        res.append(29998)

print(*res)
Problem:
We ask you to select some number of positive integers, and calculate the sum of them.  It is allowed to select as many integers as you like, and as large integers as you wish. You have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.  Your objective is to make the sum congruent to C modulo B. Determine whether this is possible.  If the objective is achievable, print `YES`. Otherwise, print `NO`.

Incorrect submission (verdict: Wrong Answer):
a,b,c = map(int, input().split())
af = (a%2==0)
bf = ((b+c)%2==0)
if af==bf:
  print("YES")
else:
  print("NO")

Fixed, accepted submission:
a, b, c = map(int, input().split())

flg = 0
for i in range(1, b+1):
    if (a * i) % b == c:
        flg = 1
        break
if flg:
    print("YES")
else:
    print("NO")
Problem:
You are given a string S of length N consisting of lowercase English letters, and an integer K. Print the string obtained by replacing every character in S that differs from the K-th character of S, with `*`.

Incorrect submission (verdict: Wrong Answer):
N = int(input())
S = input()
K = int(input())

s = ''
for i in range(N):
    if S[i] != S[K-1]:
        s += S[i]
    else:
        s += '*'

print(s)

Fixed, accepted submission:
N = int(input())
S = input()
K = int(input())

s = ''
for i in range(N):
    if S[i] == S[K-1]:
        s += S[i]
    else:
        s += '*'

print(s)
Problem:
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.  The problem has N test cases.  For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.  See the Output section for the output format.

Incorrect submission (verdict: Wrong Answer):
N = int(input())

AC=0
WA=0
TLE=0
RE=0

for i in range(N):
  TEST = input()
  if TEST == "AC":
    AC += 1
  elif TEST == "WA":
    WA += 1
  elif TEST == "TLE":
    TLE += 1
  else:
    RE += 1

print("AC × "+str(AC))
print("WA × "+str(WA))
print("TLE × "+str(TLE))
print("RE × "+str(RE))

Fixed, accepted submission:
N = int(input())

AC=0
WA=0
TLE=0
RE=0

for i in range(N):
  TEST = input()
  if TEST == "AC":
    AC += 1
  elif TEST == "WA":
    WA += 1
  elif TEST == "TLE":
    TLE += 1
  else:
    RE += 1

print("AC x "+str(AC))
print("WA x "+str(WA))
print("TLE x "+str(TLE))
print("RE x "+str(RE))
Problem:
You are given a string s consisting of lowercase English letters. Extract all the characters in the odd-indexed positions and print the string obtained by concatenating them. Here, the leftmost character is assigned the index 1.

Incorrect submission (verdict: Wrong Answer):
print(input()[1::2])

Fixed, accepted submission:
print(input()[::2])
Problem:
There are N rabbits, numbered 1 through N.  The i-th (1≤i≤N) rabbit likes rabbit a_i. Note that no rabbit can like itself, that is, a_i≠i.  For a pair of rabbits i and j (i＜j), we call the pair (i，j) a _friendly pair_ if the following condition is met.    * Rabbit i likes rabbit j and rabbit j likes rabbit i.  Calculate the number of the friendly pairs.

Incorrect submission (verdict: Wrong Answer):
a=open(0).read().split();print(sum(a[int(x)]==x for x in a)//2)

Fixed, accepted submission:
*a,=map(int,open(0).read().split());print(sum(a[a[i]]==i for i in range(len(a)))//2)
Problem:
There are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?

Incorrect submission (verdict: Wrong Answer):
N=int(input())

out=(N+1)*N/2
print(out)

Fixed, accepted submission:
N=int(input())

count=0
for i in range(N+1):
    count=count+i

print(count)
Problem:
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:    * Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.  What is the largest possible sum of the integers written on the blackboard after K operations?

Incorrect submission (verdict: Wrong Answer):
A, B, C=map(int, input().split())
K = int(input())
M = max(A, B, C)
G=A+B+C-M
print(G+M**K)

Fixed, accepted submission:
A, B, C = map(int, input().split())
K = int(input())
M = max(A, B, C)
G = A+B+C-M
print(G+M*(2**K))
Problem:
"Pizza At", a fast food chain, offers three kinds of pizza: "A-pizza", "B-pizza" and "AB-pizza". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.  Nakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.

Incorrect submission (verdict: Wrong Answer):
A,B,C,X,Y = map(int,input().split())
if A<=C  and B<=C:
  print(A*X+B*Y)
  
elif C<=A and C<=B:
  if X<=Y:
    a = 2*C*X+(Y-X)*B
    b = 2*C*Y 
    print(min(a,b))
  else:
    a = 2*C*Y+(X-Y)*A
    b = 2*C*X
    print(min(a,b))
    
elif A<=C and B>C:
  print(A*X+min(B,2*C)*Y)
  
else:
  print(B*Y + min(A,2*C)*X)

Fixed, accepted submission:
A,B,C,X,Y = map(int,input().split())
if A<C  and B<C:
  print(A*X+B*Y)
  
elif C<=A and C<=B:
  if X<=Y:
    a = 2*C*X+(Y-X)*B
    b = 2*C*Y 
    print(min(a,b))
  else:
    a = 2*C*Y+(X-Y)*A
    b = 2*C*X
    print(min(a,b))
    
elif A<=C and B>=C:
  if X<=Y:
    a = 2*C*X+(Y-X)*B
    b = A*X +B*Y
    print(min(a,b))
  else:
    a = 2*C*Y+(X-Y)*A
    b = A*X +B*Y
    print(min(a,b))
else:
  if X<=Y:
    a = 2*C*X+(Y-X)*B
    b = A*X +B*Y
    print(min(a,b))
  else:
    a = 2*C*Y+(X-Y)*A
    b = A*X +B*Y
    print(min(a,b))
Problem:
There are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i). Thus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.  In order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B. Then, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i). Thus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.  When activated, each type of robot will operate as follows.    * When a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.    * When a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.  Snuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.

Incorrect submission (verdict: Wrong Answer):
n = int(input())
k = int(input())
x = [int(i) for i in input().split()]

ans = 0

for i in range(n):
  if abs(x[i]) >= abs(k-x[i]):
    ans += abs(k-x[i])
    
  else:
    ans += abs(x[i])
    
print(ans)

Fixed, accepted submission:
n = int(input())
k = int(input())
x = [int(i) for i in input().split()]

ans = 0

for i in range(n):
  if abs(x[i]) >= abs(k-x[i]):
    ans += abs(k-x[i])*2
    
  else:
    ans += abs(x[i])*2
    
print(ans)
Problem:
Our world is one-dimensional, and ruled by two empires called Empire A and Empire B.  The capital of Empire A is located at coordinate X, and that of Empire B is located at coordinate Y.  One day, Empire A becomes inclined to put the cities at coordinates x_1, x_2, ..., x_N under its control, and Empire B becomes inclined to put the cities at coordinates y_1, y_2, ..., y_M under its control.  If there exists an integer Z that satisfies all of the following three conditions, they will come to an agreement, but otherwise war will break out.    * X < Z \leq Y   * x_1, x_2, ..., x_N < Z   * y_1, y_2, ..., y_M \geq Z  Determine if war will break out.

Incorrect submission (verdict: Wrong Answer):
N, M, X, Y = map(int, input().split())

x = list(map(int, input().split()))
y = list(map(int, input().split()))

if max(x) >= min(y):
  print("War")
  quit()
else:
  if X < min(y) - max(x) <= Y:
    print("No War")
  else:
    print("War")

Fixed, accepted submission:
N, M, X, Y = map(int, input().split())

x = list(map(int, input().split()))
y = list(map(int, input().split()))

if max(x) >= min(y):
  print("War")
  quit()
else:
  if max(x) <= X or min(y) > Y:
    print("War")
  else:
    print("No War")
Problem:
It has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.  The bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.  How many ways are there to choose where to put the notice so that it completely covers exactly HW squares?

Incorrect submission (verdict: Wrong Answer):
n=int(input())
h=int(input())
w=int(input())
print((n-h)*(n-w))

Fixed, accepted submission:
n=int(input())
h=int(input())
w=int(input())
print((n-h+1)*(n-w+1))