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|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
|
instruction
| 0
| 97,862
| 0
| 195,724
|
Tags: implementation
Correct Solution:
```
t = int(input())
for i in range(t):
n, k = input().split(' ')
n = int(n)
k = int(k)
res = []
y = 97
for i in range(n):
res.append(y + i%k)
print("".join([chr(e) for e in res]))
```
|
output
| 1
| 97,862
| 0
| 195,725
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
|
instruction
| 0
| 97,863
| 0
| 195,726
|
Tags: implementation
Correct Solution:
```
t = int(input())
for _ in range(t) :
n, k = map(int, input().split())
for i in range(n) :
print(chr(ord('a') + i % k), end='');
print()
```
|
output
| 1
| 97,863
| 0
| 195,727
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
|
instruction
| 0
| 97,864
| 0
| 195,728
|
Tags: implementation
Correct Solution:
```
t=int(input())
for _ in range(t):
n,k=map(int,input().split())
s=''
for i in range(97,97+k):
s+=chr(i)
s=s*(n//k)+s[:n%k]
print(s)
```
|
output
| 1
| 97,864
| 0
| 195,729
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
|
instruction
| 0
| 97,865
| 0
| 195,730
|
Tags: implementation
Correct Solution:
```
for _ in range(int(input())):
n, k = [int(i) for i in input().split()]
res = ""
for i in range(k-1):
for _ in range(n // k):
res += chr(97 + i)
res += chr(97+k-1) * (n - ((n // k) * (k - 1)))
print(res)
```
|
output
| 1
| 97,865
| 0
| 195,731
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
n = int(input())
for i in range(n):
a,b=list(map(int,input().split()))
c = 0
st=[]
for j in range(a):
s = (c+ord("a"))
st.append(chr(s))
c = (c+1)%b
for k in range(len(st)):
print(st[k],end="")
print("\n")
a = []
```
|
instruction
| 0
| 97,866
| 0
| 195,732
|
Yes
|
output
| 1
| 97,866
| 0
| 195,733
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
def main():
n, k = map(int, input().split())
res = ''
for i in range(n):
res += chr(ord('a') + i % k)
print(res)
if __name__ == '__main__':
t = int(input())
for _ in range(t):
main()
```
|
instruction
| 0
| 97,867
| 0
| 195,734
|
Yes
|
output
| 1
| 97,867
| 0
| 195,735
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
def solve():
n, k = map(int, input().split())
for i in range(n):
print(chr(ord('a') + i % k), end="")
print("")
t = eval(input())
while t:
solve()
t -= 1
```
|
instruction
| 0
| 97,868
| 0
| 195,736
|
Yes
|
output
| 1
| 97,868
| 0
| 195,737
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
import sys
t = int(input())
for i in range(t):
n, k = map(int, sys.stdin.readline().split())
s = ""
for a in range(n):
s+= chr(ord("a")+(a%k))
print(s)
```
|
instruction
| 0
| 97,869
| 0
| 195,738
|
Yes
|
output
| 1
| 97,869
| 0
| 195,739
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
from random import randint
a=int(input())
b=[]
c=0
d=[]
e=0
f='abcdefghijklmnopqrstuvwxyz'
for i in range(a):
n,k=map(int,input().split())
for i in range(n):
print(f[e],end='')
e+=1
e=0
print()
```
|
instruction
| 0
| 97,870
| 0
| 195,740
|
No
|
output
| 1
| 97,870
| 0
| 195,741
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
import string
cases = int(input())
for _ in range(cases):
lst = [int(x) for x in input().split()]
letter = string.ascii_lowercase
word = ""
while len(word) < lst[0]:
for i in letter[:lst[1]]:
word = word + i
print(word)
```
|
instruction
| 0
| 97,871
| 0
| 195,742
|
No
|
output
| 1
| 97,871
| 0
| 195,743
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
t=int(input())
a="abcdefghijklmnopqrstuvxyz"
for i in range(t):
n,k=map(int,input().split())
print(((n//k)*a[:k])+a[:n%k])
```
|
instruction
| 0
| 97,872
| 0
| 195,744
|
No
|
output
| 1
| 97,872
| 0
| 195,745
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
T = int(input())
k = 0
s = ''
while True:
if T == 0: break
T = T - 1
a, b = map(int, input().split())
for i in range(b):
for j in range(a // b):
s += chr(ord('a') + i)
for i in range(a % b):
s += 'a'
print(s)
```
|
instruction
| 0
| 97,873
| 0
| 195,746
|
No
|
output
| 1
| 97,873
| 0
| 195,747
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,954
| 0
| 195,908
|
Tags: implementation, number theory, strings
Correct Solution:
```
s = input().strip()
import math, functools, sys, heapq
@functools.lru_cache(None)
def check_prime(p):
for i in range(2, int(math.sqrt(p)) + 1):
if p % i == 0:
return False
return True
primes = []
n = len(s)
for p in range(2, n + 1):
if check_prime(p):
primes.append(p)
cnt = {}
for c in s:
try:
cnt[c] += 1
except KeyError:
cnt[c] = 1
pq = []
for key in cnt:
heapq.heappush(pq, (-cnt[key], key))
sets = []
for p in primes:
inds = set()
for i in range(1, n // p + 1):
inds.add(p * i)
done = False
for i, st in enumerate(sets):
if st & inds:
sets[i] = st | inds
done = True
break
if not done:
sets.append(inds)
# print(inds, sets)
sets.sort(key=lambda x: len(x), reverse=True)
# print(primes)
# print(sets)
ans = [None for _ in range(n)]
for st in sets:
if not pq:
print('NO')
sys.exit()
cnt, c = heapq.heappop(pq)
if -cnt >= len(st):
for i in st:
ans[i-1] = c
cnt = -cnt - len(st)
if cnt > 0:
heapq.heappush(pq, (-cnt, c))
else:
print('NO')
sys.exit()
# print(ans)
i = 0
cnt, c = heapq.heappop(pq)
cnt = -cnt
while i < n:
if ans[i] is not None:
i += 1
continue
if cnt == 0 and pq:
cnt, c = heapq.heappop(pq)
cnt = -cnt
ans[i] = c
cnt -= 1
i += 1
print('YES')
print(''.join(ans))
```
|
output
| 1
| 97,954
| 0
| 195,909
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,955
| 0
| 195,910
|
Tags: implementation, number theory, strings
Correct Solution:
```
from collections import Counter
d, t = 'NO', input()
c, n = Counter(t), len(t)
p = [1] * (n + 1)
for i in range(2, n // 2 + 1):
if p[i]: p[i::i] = [0] * (n // i)
p.pop(0)
s = n - sum(p)
u = v = ''
for q, k in c.items():
if not (v or k < s):
k -= s
v = q
u += q * k
if v:
d, j = 'YES\n', 0
for q in p:
d += u[j] if q else v
j += q
print(d)
```
|
output
| 1
| 97,955
| 0
| 195,911
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,956
| 0
| 195,912
|
Tags: implementation, number theory, strings
Correct Solution:
```
from collections import Counter
d, t = 'NO', input()
c, n = Counter(t), len(t)
p = [0] * (n + 1)
for i in range(2, n // 2 + 1):
if 1 - p[i]: p[i::i] = [1] * (n // i)
s = sum(p)
u = v = ''
for q, k in c.items():
if v or k < s:
u += q * k
else:
u += q * (k - s)
v = q
if v:
d, j = 'YES\n', 0
for i in range(1, n + 1):
if p[i]:
d += v
else:
d += u[j]
j += 1
print(d)
```
|
output
| 1
| 97,956
| 0
| 195,913
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,957
| 0
| 195,914
|
Tags: implementation, number theory, strings
Correct Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
# from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
from time import perf_counter
from fractions import Fraction
import copy
import time
starttime = time.time()
mod = int(pow(10, 9) + 7)
mod2 = 998244353
def data(): return sys.stdin.readline().strip()
def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
def L(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
try:
# sys.setrecursionlimit(int(pow(10,4)))
sys.stdin = open("input.txt", "r")
# sys.stdout = open("../output.txt", "w")
except:
pass
def pmat(A):
for ele in A:
print(*ele,end="\n")
# def seive():
# prime=[1 for i in range(10**6+1)]
# prime[0]=0
# prime[1]=0
# for i in range(10**6+1):
# if(prime[i]):
# for j in range(2*i,10**6+1,i):
# prime[j]=0
# return prime
s=input()
n=len(s)
A=[i for i in range(n+1)]
def par(x):
if A[x]==x:
return x
return par(A[x])
def union(x,y):
u=par(x)
v=par(y)
if u==v:
return
if u<v:
A[v]=u
else:
A[u]=v
for i in range(2,n+1):
if A[i]!=i:
continue
for j in range(2*i,n+1,i):
union(i,j)
d={}
for i in range(1,n+1):
d[A[i]]=d.get(A[i],0)+1
cnt={}
for c in s:
cnt[c]=cnt.get(c,0)+1
B1=[[d[i],i] for i in d]
B2=[[cnt[i],i] for i in cnt]
B1.sort(reverse=True)
B2.sort()
i=0
C={}
if len(B1)<len(B2):
print("NO")
exit()
while(i<len(B1)):
x=B1[i][0]
for j in range(len(B2)):
if B2[j][0]>=x:
B2[j][0]-=x
C[B1[i][1]]=B2[j][1]
break
else:
print("NO")
exit()
i+=1
print("YES")
for i in range(1,n+1):
print(C[A[i]],end="")
print()
endtime = time.time()
# print(f"Runtime of the program is {endtime - starttime}")
```
|
output
| 1
| 97,957
| 0
| 195,915
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,958
| 0
| 195,916
|
Tags: implementation, number theory, strings
Correct Solution:
```
from collections import Counter
def is_prime(x):
if x < 2:
return 0
for i in range(2, x):
if x % i == 0:
return False
return True
def proc(s):
n = len(s)
same = set()
for p in range(2,n+1):
if not is_prime(p):
continue
if p * 2 > n:
continue
for i in range(2, n//p+1):
same.add(p*i)
same.add(p)
counter = Counter(s)
ch, count = counter.most_common(1)[0]
if count < len(same):
print("NO")
return
same = [x-1 for x in same]
w = [x for x in s]
for i in same:
if w[i] == ch:
continue
for j in range(n):
if j not in same and w[j] == ch:
tmp = w[j]
w[j] = w[i]
w[i] = tmp
break
print("YES")
print(''.join(w))
s = input()
proc(s)
```
|
output
| 1
| 97,958
| 0
| 195,917
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,959
| 0
| 195,918
|
Tags: implementation, number theory, strings
Correct Solution:
```
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and initialize
# all entries it as true. A value in prime[i] will
# finally be false if i is Not a prime, else true.
prime = [True for i in range(n + 1)]
p = 2
while (p * p <= n):
# If prime[p] is not changed, then it is a prime
if (prime[p] == True):
# Update all multiples of p
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
return prime
s = input()
primes = SieveOfEratosthenes(len(s))
length = len(s)
unique = set()
unique.add(1)
for i in range(2, len(s)+1):
if primes[i] and 2*i > length:
unique.add(i)
# print(unique)
count = dict()
sameHave = 1
sameC = s[0]
for c in s:
if c not in count:
count[c] = 1
else:
count[c] += 1
if(count[c] > sameHave):
sameHave = count[c]
sameC = c
# print(count)
uniqueList = []
for char in s:
if char != sameC:
uniqueList.append(char)
# print(uniqueList)
sameNeed = length - len(unique)
# print(sameNeed, sameHave, sameC)
if sameHave >= sameNeed:
print("YES")
out = ""
for i in range(1, len(s)+1):
if i in unique:
if len(uniqueList) != 0:
out += uniqueList.pop()
else:
out += sameC
else:
out += sameC
print(out)
else:
print("NO")
```
|
output
| 1
| 97,959
| 0
| 195,919
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,960
| 0
| 195,920
|
Tags: implementation, number theory, strings
Correct Solution:
```
#!/usr/bin/python3
s = input()
d = dict()
for c in s:
if c not in d:
d[c] = 0
d[c] += 1
cnto = 1
isprime = [True] * (len(s) + 1)
for p in range(2, len(s) + 1):
if isprime[p]:
for i in range(p * p, len(s) + 1, p):
isprime[i] = False
for i in range(1, len(s) + 1):
if i > len(s) // 2 and isprime[i]:
cnto += 1
cnto = len(s) - cnto
if max(d.values()) < cnto:
print("NO")
else:
print("YES")
m = max(d.values())
for c, v in d.items():
if v == m:
d[c] -= cnto
mc = c
break
ans = []
buf = []
for c, v in d.items():
for i in range(v):
buf.append(c)
for i in range(1, len(s) + 1):
if i == 1 or (i > len(s) // 2 and isprime[i]):
ans.append(buf[-1])
buf.pop()
else:
ans.append(mc)
print("".join(ans))
```
|
output
| 1
| 97,960
| 0
| 195,921
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
|
instruction
| 0
| 97,961
| 0
| 195,922
|
Tags: implementation, number theory, strings
Correct Solution:
```
import math
ch='abcdefghijklmnopqrstuvwxyz'
def sieve(n):
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
s = ['#']+list(input())
lis=[0]*26
n = len(s)-1
prime = [True for i in range(1000 + 1)]
sieve(1000)
ans=['']*(n+1)
aa=[]
aa.append(1)
for i in s[1:]:
lis[ord(i)-ord('a')]+=1
for i in range(n//2+1,n+1,1):
if prime[i]:
aa.append(i)
v = n-len(aa)
th=-1
for i in range(26):
if lis[i]>=v:
th=i
if th==-1:
print("NO")
exit()
for i in range(2,n+1):
if i not in aa:
ans[i]=ch[th]
lis[th]-=1
j=0
#print(ans,aa,lis)
for i in aa:
while j<26 and lis[j]<=0:
j+=1
ans[i]=ch[j]
lis[j]-=1
# print(ans,lis)
print("YES")
print(*ans[1:],sep='')
```
|
output
| 1
| 97,961
| 0
| 195,923
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
s = input()
if len(s) == 1:
exit(print('YES\n' + s))
d, ans, sieve = {}, [0] * len(s), [0] * 1005
for i in s:
d[i] = d.get(i, 0) + 1
for i in range(2, len(s) + 1):
if not sieve[i]:
for j in range(i * i, 1005, i):
sieve[j] = 1
mx = max(d, key=lambda x: d[x])
for j in range(2, len(s) // 2 + 1):
ans[j - 1] = mx
d[mx] -= 1
if d[mx] < 0:
exit(print('NO'))
for i in range(len(s) // 2 + 1, len(s) + 1):
if not sieve[i]:
mx = max(d, key=lambda x: d[x] and x != ans[1])
if not d[mx]:
mx = ans[1]
ans[i - 1] = mx
d[mx] -= 1
else:
ans[i - 1] = ans[1]
d[ans[1]] -= 1
if d[mx] < 0 or d[ans[1]] < 0:
exit(print('NO'))
print('YES')
mx = max(d, key=lambda x: d[x])
print(mx + ''.join(ans[1:]))
```
|
instruction
| 0
| 97,962
| 0
| 195,924
|
Yes
|
output
| 1
| 97,962
| 0
| 195,925
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
import sys
import math
from collections import defaultdict
MAXNUM = math.inf
MINNUM = -1 * math.inf
ASCIILOWER = 97
ASCIIUPPER = 65
def getInt():
return int(sys.stdin.readline().rstrip())
def getInts():
return map(int, sys.stdin.readline().rstrip().split(" "))
def getString():
return sys.stdin.readline().rstrip()
def printOutput(ans):
sys.stdout.write()
pass
def getPrimes(s):
primes = [2]
MAX = s + 1
for i in range(3, MAX):
STOP = math.ceil(math.sqrt(i) + 1)
isPrime = True
for j in range(2, STOP):
if i % j == 0:
isPrime = False
if isPrime:
primes.append(i)
return primes
def solve(let, s):
primes = getPrimes(len(s))
bigindices = []
oneIndices = []
ones = 0
for i in primes:
k = len(s) // i
if k > 1:
bigindices.append(i)
if k == 1:
oneIndices.append(i)
ones += 1
solution = [0 for _ in range(len(s))]
bigK = max(let, key=lambda x: let[x])
total = 0
for index in bigindices:
for i in range(index, len(solution) + 1, index):
if solution[i-1] == 0:
solution[i - 1] = bigK
total += 1
#print(len(s))
#print(total)
#print(bigindices)
#print(oneIndices)
if total > let[bigK]:
return "NO", None
else:
let[bigK] -= total
#print("afterbig")
#print(solution)
for item in oneIndices:
for key, val in let.items():
if val >= 1:
let[key] -= 1
ones -= 1
solution[item - 1] = key
break
if ones != 0:
return "NO", None
#print("afteroneind")
#print(solution)
for i in range(len(solution)):
if solution[i] == 0:
for key, val in let.items():
if val > 0:
val -= 1
solution[i] = key
break
return "YES", "".join(solution)
def readinput():
lettercount = defaultdict(int)
string = getString()
for ele in string:
lettercount[ele] += 1
ans = solve(lettercount, string)
print(ans[0])
if ans[0] != "NO":
print(ans[1])
readinput()
```
|
instruction
| 0
| 97,963
| 0
| 195,926
|
Yes
|
output
| 1
| 97,963
| 0
| 195,927
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
p=[1]*1001
for i in range(2,1001):
if p[i]:
for j in range(i,1001,i):p[j]=0
p[i]=1
a=input()
z=len(a)
l=[0]*26
for i in a:l[ord(i)-97]+=1
gh=0
for i in range(z//2+1,z+1):gh+=p[i]
if max(l)<z-1-gh:exit(print("NO"))
ans=['']*(z+1)
t=l.index(max(l))
for i in range(2,1+(z//2)):ans[i]=chr(t+97);l[t]-=1
for i in range(1+(z//2),z+1):
if p[i]==0:ans[i]=chr(t+97);l[t]-=1
j=0
for i in range(1,z+1):
if ans[i]=='':
while l[j]<=0:j+=1
ans[i]=chr(j+97);l[j]-=1
print("YES")
print(''.join(ans[1::]))
```
|
instruction
| 0
| 97,964
| 0
| 195,928
|
Yes
|
output
| 1
| 97,964
| 0
| 195,929
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
from collections import Counter
is_prime = lambda x: all(x % d for d in range(2, int(x **.5) + 1))
s = input()
n = len(s)
K = {1} | {x for x in range(n // 2 + 1, n + 1) if is_prime(x)}
k = len(K)
ch, m = max(Counter(s).items(), key=lambda x: x[1])
if m + k < n:
print('NO')
else:
print('YES')
s = list(s.replace(ch, '', n - k))
A = [0] * n
for i in range(n):
A[i] = s.pop() if (i + 1) in K else ch
print(''.join(A))
```
|
instruction
| 0
| 97,965
| 0
| 195,930
|
Yes
|
output
| 1
| 97,965
| 0
| 195,931
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
dp=[]
def sieve():
n=10**4
global dp
dp=[True]*n
dp[0]=False
dp[1]=False
i=0
while (i*i)<=n:
j=i
if dp[i]:
for jj in range(2*j,n,j):
dp[jj]=False
i+=1
sieve()
s=input()
if s=='abcd':
print('NO')
exit()
n=len(s)
d={}
for i in s:
if i in d:d[i]+=1
else:d[i]=1
#print(dp[:4])
for p in range(2,len(s)+1):
if dp[p]:
arr=[]
for i in range(len(s)//p):
arr.append(p*(i+1))
for i in s:
if max(arr)<=n and len(arr)<=d[i]:
s1=[0]*n
print(arr)
for j in arr:s1[j-1]=i
d[i]-=len(arr)
#print(d)
#print(s1)
for ii in s:
if d[ii]>0:
k=0
kk=0
while kk<n and k<d[ii]:
if s1[kk]==0:
s1[kk]=ii
k+=1
kk+=1
d[ii]-=k# print(d)
# print(s1)
print('YES')
print(''.join(s1))
exit()
print('NO')
```
|
instruction
| 0
| 97,966
| 0
| 195,932
|
No
|
output
| 1
| 97,966
| 0
| 195,933
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
s = input()
d, ans, sieve = {}, [0] * len(s), [0] * 1005
for i in s:
d[i] = d.get(i, 0) + 1
for i in range(2, len(s) + 1):
if not sieve[i]:
for j in range(i * i, 1005, i):
sieve[j] = 1
mx = max(d, key=lambda x: d[x])
for j in range(i, len(s) + 1, i):
if not ans[j - 1]:
ans[j - 1] = mx
d[mx] -= 1
if d[mx] < 0:
exit(print('NO'))
print('YES')
mx = max(d, key=lambda x: d[x])
print(mx + ''.join(ans[1:]))
```
|
instruction
| 0
| 97,967
| 0
| 195,934
|
No
|
output
| 1
| 97,967
| 0
| 195,935
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
import heapq
primenumbers=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,
53,59,61,67,71,73,79,83,89,97,
101,103,107,109,113,127,131,137,139,149,
151,157,163,167,173,179,181,191,193,197,199,
211,223,227,229,233,239,241,
251,257,263,269,271,277,281,283,293,
307,311,313,317,331,337,347,349,
353,359,367,373,379,383,389,397,
401,409,419,421,431,433,439,443,449,
457,461,463,467,479,487,491,499,
503,509,521,523,541,547,
557,563,569,571,577,587,593,599,
601,607,613,617,619,631,641,643,647,
653,659,661,673,677,683,691,
701,709,719,727,733,739,743,
751,757,761,769,773,787,797,
809,811,821,823,827,829,839,
853,857,859,863,877,881,883,887,
907,911,919,929,937,941,947,
953,967,971,977,983,991,997]
ss=input()
s=len(ss)
for index in range(168):
if primenumbers[index]==s:
indextemp=index
break
elif primenumbers[index]>s:
indextemp=index-1
break
same=[[]]
for i in range(indextemp+1):
tempV=[]
temp=primenumbers[i]
while temp<=s:
if temp not in same[-1]:
tempV.append(temp)
temp+=primenumbers[i]
same.append(tempV)
same.remove(same[0])
amount=[]
for i in same:
heapq.heappush(amount,len(i))
dic={}
for i in ss:
if i not in dic.keys():
dic[i]=1
else:
dic[i]+=1
amountC=[]
for i in dic.keys():
heapq.heappush(amountC,dic[i])
pointer=True
if len(amount)>len(amountC):
print('NO')
else:
for i in range(len(amount)):
if amount[i]>amountC[i]:
print('NO')
pointer=False
break
if pointer:
print('YES')
print(ss)
```
|
instruction
| 0
| 97,968
| 0
| 195,936
|
No
|
output
| 1
| 97,968
| 0
| 195,937
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s, consisting of small Latin letters. Let's denote the length of the string as |s|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string s so that for any prime number p ≤ |s| and for any integer i ranging from 1 to |s| / p (inclusive) the following condition was fulfilled sp = sp × i. If the answer is positive, find one way to rearrange the characters.
Input
The only line contains the initial string s, consisting of small Latin letters (1 ≤ |s| ≤ 1000).
Output
If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO".
Examples
Input
abc
Output
YES
abc
Input
abcd
Output
NO
Input
xxxyxxx
Output
YES
xxxxxxy
Note
In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at p = 2 (s2 = s4).
In the third test any string where character "y" doesn't occupy positions 2, 3, 4, 6 will be valid.
Submitted Solution:
```
import os,io
from sys import stdout
import collections
import random
import math
from operator import itemgetter
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
from collections import Counter
# import sys
# sys.setrecursionlimit(10**6)
def primes(n):
""" Returns a list of primes < n """
sieve = [True] * n
for i in range(3,int(n**0.5)+1,2):
if sieve[i]:
sieve[i*i::2*i]=[False]*((n-i*i-1)//(2*i)+1)
return [2] + [i for i in range(3,n,2) if sieve[i]]
def binomial_coefficient(n, k):
if 0 <= k <= n:
ntok = 1
ktok = 1
for t in range(1, min(k, n - k) + 1):
ntok *= n
ktok *= t
n -= 1
return ntok // ktok
else:
return 0
def powerOfK(k, max):
if k == 1:
return [1]
if k == -1:
return [-1, 1]
result = []
n = 1
while n <= max:
result.append(n)
n *= k
return result
def prefixSum(arr):
for i in range(1, len(arr)):
arr[i] = arr[i] + arr[i-1]
return arr
def divisors(n):
i = 1
result = []
while i*i <= n:
if n%i == 0:
if n/i == i:
result.append(i)
else:
result.append(i)
result.append(n/i)
i+=1
return result
# from functools import lru_cache
# @lru_cache(maxsize=None)
s = input().decode('utf-8').strip()
# n = int(input())
# l = list(map(int, input().split()))
c = Counter(s)
dp = [0] * len(s)
primes = primes(len(s))
components = []
for p in primes:
l = []
for i in range(p, len(s)+1, p):
l.append(i)
for comp in components:
if len(list(set(comp) & set(l))):
comp += l
break
else:
if len(l):
components.append(l)
need = []
for comp in components:
need.append(len(set(comp)))
import heapq
heap = []
for e, v in c.items():
heapq.heappush(heap, (-v, e))
result = [""] * (len(s))
for comp in components:
i, letter = heapq.heappop(heap)
i = -i
indexes = set(comp)
if i >= len(indexes):
heapq.heappush(heap, (-(i-len(indexes)), letter))
for index in set(comp):
result[index-1] = letter
else:
print("NO")
break
else:
while len(heap):
i, letter = heapq.heappop(heap)
for j in range(len(result)):
if i == 0:
break
if result[j] == "":
result[j] = letter
i -= 1
print("YES")
print("".join(result))
# a = sorted(list(c.values()))
# b = sorted(need)
#
# i, j = len(b)-1, len(a)-1
# while i >= 0 and j >= 0:
# if b[i] <= a[j]:
# a[j] -= b[i]
# i -= 1
# else:
# j -= 1
#
# if i == -1:
# print("YES")
# else:
# print("NO")
```
|
instruction
| 0
| 97,969
| 0
| 195,938
|
No
|
output
| 1
| 97,969
| 0
| 195,939
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,083
| 0
| 196,166
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
import sys,io,os;Z=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def f(l,h):
global L,S
if h-l<2:return L[l]%2
m=(l+h)//2;c=x=r=s=0;d=1
for i in range(m-1,l-1,-1):
if L[i]%2:
c+=1
if c>x:x=c
if d:r=c
else:c=d=0
S[i]=x;s+=x
c=x=t=0;d=e=1;p=m-max(1,r);w=S[m-1]
for i in range(m,h):
if L[i]%2:
c+=1
if c>x:x=c
if d:
while S[p]<x+r:
if p>l:v=min(S[p-1],x+r)-S[p]
else:v=x+r-S[l];S[l]=x+r
s+=v*(m-p);w+=v
if p>l:p-=1
else:
if e<r and w<x:w+=1;s+=e;e+=1
while S[p]<x:
if p>l:s+=(min(S[p-1],x)-S[p])*(m-p);p-=1
else:s+=(x-S[l])*(m-l);S[l]=x
else:c=d=0
t+=s
return t+f(l,m)+f(m,h)
n=int(Z());S=[0]*n;L=Z();print(f(0,n))
```
|
output
| 1
| 98,083
| 0
| 196,167
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,084
| 0
| 196,168
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
from sys import stdin
import sys
import heapq
def bitadd(a,w,bit):
x = a+1
while x <= (len(bit)-1):
bit[x] += w
x += x & (-1 * x)
def bitsum(a,bit):
ret = 0
x = a+1
while x > 0:
ret += bit[x]
x -= x & (-1 * x)
return ret
n = int(stdin.readline())
s = stdin.readline()[:-1]
bit = [0] * (n+10)
dp = [0] * (n+10)
y = 0
ans = 0
for i in range(n):
if s[i] == "0":
while y > 0:
dp[y] += 1
bitadd(y,y,bit)
y -= 1
dp[0] += 1
else:
bitadd(y,-1*dp[y]*y,bit)
bitadd(y+1,-1*dp[y+1]*(y+1),bit)
dp[y+1] += dp[y]
dp[y] = 0
y += 1
bitadd(y,dp[y]*y,bit)
now = bitsum(i,bit) + (1+y)*y//2
#print (bitsum(i,bit),(1+y)*y//2,dp)
ans += now
print (ans)
```
|
output
| 1
| 98,084
| 0
| 196,169
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,085
| 0
| 196,170
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
n = int(input());a = map(int, input());acc = 0;back = 0;top = 0;cur = 0;s = []
for i,x in enumerate(a):
if x == 0:cur = 0
else:
if cur > 0:s.pop()
cur += 1
if cur >= top:top = cur;back = (cur + 1) * (cur) // 2 + (i - cur + 1) * cur;s = [(cur, i)]
else:
back += i - (s[-1][1] - cur + 1)
if cur >= s[-1][0]:s.pop()
s += [(cur, i)]
acc += back
print(acc)
```
|
output
| 1
| 98,085
| 0
| 196,171
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,086
| 0
| 196,172
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
n = int(input())
s = input()
tot=0
cur=0
hist=[0]*(n)
i=0
while (i<n):
if (s[i]=='0'):
tot+=cur
else:
l=i
r=i
while (r+1<n and s[r+1]=='1'): r+=1
for x in range(r-l+1):
cur+=(l+x+1)-hist[x]
tot+=cur
hist[x]=r-x+1
i=r
i+=1
print(tot)
```
|
output
| 1
| 98,086
| 0
| 196,173
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,087
| 0
| 196,174
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
import sys
input = sys.stdin.buffer.readline
n = int(input())
s = input().decode()[:n]
one, rm, pos = 0, [0]*n, [n]*(n+1)
for p in range(n-1, -1, -1):
u = s[p]
if u == '1':
one += 1
rm[p] = pos[one]-p
elif one:
for i in range(one):
pos[i+1] = p+i+1
one = 0
sm, mx, one = 0, 0, 0
for u in s:
if u == '1': one += 1
else: one = 0
mx = max(mx, one)
sm += mx
res = sm
for u in rm:
sm -= u
res += sm
print(res)
```
|
output
| 1
| 98,087
| 0
| 196,175
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,088
| 0
| 196,176
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
n=int(input())
l=map(int,input())
c,s,w,p=[0]*(n+3),0,0,0
for i in l:
if i==1:
p+=1
s+=c[p-1]+max(1,p-1)
c[p]+=c[p-1]
c[p-1]=0
c[max(1,p-1)]+=1
else:
p=0
c[0]+=1
w+=s
print(w)
```
|
output
| 1
| 98,088
| 0
| 196,177
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,089
| 0
| 196,178
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
import math,sys
n=int(input())
s=input()
dp=[0]*(n+1)
currlength=0
d=[-1]*(n+1)
for i in range(n):
if s[i]=='0':
dp[i+1]=dp[i]
if currlength>0:
for j in range(currlength):
d[j+1]=i-j-1
currlength=0
else:
currlength+=1
numsegs=i-d[currlength]-1
dp[i+1]=dp[i]+numsegs+1
print(sum(dp))
```
|
output
| 1
| 98,089
| 0
| 196,179
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
|
instruction
| 0
| 98,090
| 0
| 196,180
|
Tags: binary search, data structures, divide and conquer, dp, two pointers
Correct Solution:
```
from sys import stdin
n= int(stdin.readline())
s = stdin.readline().strip()
total = 0
crnt = 0
hist = [0] * n
i = 0
while(i < n):
if (s[i] == '0'):
total += crnt
else:
#find longest segment of ones from here
l = i
r = i
while(r+1 < n and s[r+1] == '1'):
r += 1
#Update with found segment
#print(l,r, "l,r")
for j in range(r-l+1):
#print((l+j+1), hist[j])
crnt += (l+j+1) - hist[j]
total += crnt
hist[j] = r-j+1
#print()
i = r
i+= 1
print(total)
```
|
output
| 1
| 98,090
| 0
| 196,181
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
n = int(input())
s = input()
res,now,r = 0,0,0
x = [-1]*(n+1)
while r<n:
l = r
if s[r]=='0':
while r<n and s[r]=='0':
r+=1
res += (r-l)*now
else:
while r<n and s[r]=='1':
r+=1
for k in range(1,r-l+1):
now += l+k-1-x[k]
res += now
x[k] = r-k
print(res)
```
|
instruction
| 0
| 98,091
| 0
| 196,182
|
Yes
|
output
| 1
| 98,091
| 0
| 196,183
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
class SegmentTree:
def __init__(self, data, default=0, func=max):
"""initialize the segment tree with data"""
self._default = default
self._func = func
self._len = len(data)
self._size = _size = 1 << (self._len - 1).bit_length()
self.data = [default] * (2 * _size)
self.data[_size:_size + self._len] = data
for i in reversed(range(_size)):
self.data[i] = func(self.data[i + i], self.data[i + i + 1])
def __delitem__(self, idx):
self[idx] = self._default
def __getitem__(self, idx):
return self.data[idx + self._size]
def __setitem__(self, idx, value):
idx += self._size
self.data[idx] = value
idx >>= 1
while idx:
self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1])
idx >>= 1
def __len__(self):
return self._len
def query(self, start, stop):
"""func of data[start, stop)"""
start += self._size
stop += self._size
res_left = res_right = self._default
while start < stop:
if start & 1:
res_left = self._func(res_left, self.data[start])
start += 1
if stop & 1:
stop -= 1
res_right = self._func(self.data[stop], res_right)
start >>= 1
stop >>= 1
return self._func(res_left, res_right)
def __repr__(self):
return "SegmentTree({0})".format(self.data)
def main():
n = int(input())
s = input()
lastZero = -1
contiguousOneAfter = [0] * n
contiguousOneBefore = [0] * n
for i in range(n):
if s[i] == '0':
cnt = 1
for j in range(i-1,lastZero,-1):
contiguousOneAfter[j] = cnt
cnt += 1
lastZero = i
if s[-1] == '1':
cnt = 1
for j in range(n-1,lastZero,-1):
contiguousOneAfter[j] = cnt
cnt += 1
primAns = 0
curMax = 0
curCnt = 0
for i in range(n):
if s[i] == "1":
curCnt += 1
if s[i] == "0":
curCnt = 0
if curCnt > curMax:
curMax = curCnt
contiguousOneBefore[i] = curCnt
primAns += curMax
whenBlocked = [0] * n
segTree = SegmentTree([0] * (n + 1),0)
for i in range(n-1,-1,-1):
if s[i] == '1':
whenBlocked[i] = n - segTree.query(contiguousOneAfter[i],n + 1)
if contiguousOneBefore[i] == 1:
for j in range(i, i + contiguousOneAfter[i] + 1):
if n - j >= 0 and n - j <= n and j < n:
segTree.__setitem__(contiguousOneBefore[j],n - j)
ans = primAns
for i in range(n):
if s[i] == "1":
primAns -= whenBlocked[i] - i
ans += primAns
print(ans)
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
```
|
instruction
| 0
| 98,092
| 0
| 196,184
|
Yes
|
output
| 1
| 98,092
| 0
| 196,185
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
N=int(input())
S=input()
p=0
b=[0 for i in range(N+1)]
a=0
s=0
for c in S:
if c=='0':
p=0;b[0]+=1
else:
if p==0:
p=1;s+=b[0]+1;b[1]+=b[0];b[0]=0;b[1]+=1
else:
p+=1;s+=b[p-1]+p-1;b[p]+=b[p-1];b[p-1]=1
a+=s
print(a)
```
|
instruction
| 0
| 98,093
| 0
| 196,186
|
Yes
|
output
| 1
| 98,093
| 0
| 196,187
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
n = int(input())
s = input()
i = 0
ans = 0
curr = 0
prev = [-1] * 500005
while (i < n):
if s[i] == '0':
#print('0->', i, curr)
ans += curr
else:
left = i
right = i
while (right+1 < n) and (s[right+1] == '1'):
right += 1
for j in range(right+1-left):
curr += (left + j) - prev[j]
#print(left, right, j, curr)
ans += curr
prev[j] = right - j
i = right
i += 1
print(ans)
```
|
instruction
| 0
| 98,094
| 0
| 196,188
|
Yes
|
output
| 1
| 98,094
| 0
| 196,189
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
n=int(input())
s=input()
t=0
for i in range(n):
if s[i]==1:
t+=(i+1)*(n-i)
print(t)
```
|
instruction
| 0
| 98,095
| 0
| 196,190
|
No
|
output
| 1
| 98,095
| 0
| 196,191
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
n=int(input())
s=list(map(int,input().split()))
t=0
for i,v in enumerate(s):
t+=v*(i+1)*(n-i)
print(t)
```
|
instruction
| 0
| 98,096
| 0
| 196,192
|
No
|
output
| 1
| 98,096
| 0
| 196,193
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
import sys
sys.setrecursionlimit(10 ** 7)
f_inf = float('inf')
mod = 10 ** 9 + 7
def resolve():
n = int(input())
S = input()
res = 0
for i in range(n):
if S[i] == "1":
res += pow(2, n - i)
print(res)
if __name__ == '__main__':
resolve()
```
|
instruction
| 0
| 98,097
| 0
| 196,194
|
No
|
output
| 1
| 98,097
| 0
| 196,195
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Zookeeper is buying a carton of fruit to feed his pet wabbit. The fruits are a sequence of apples and oranges, which is represented by a binary string s_1s_2… s_n of length n. 1 represents an apple and 0 represents an orange.
Since wabbit is allergic to eating oranges, Zookeeper would like to find the longest contiguous sequence of apples. Let f(l,r) be the longest contiguous sequence of apples in the substring s_{l}s_{l+1}… s_{r}.
Help Zookeeper find ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r), or the sum of f across all substrings.
Input
The first line contains a single integer n (1 ≤ n ≤ 5 ⋅ 10^5).
The next line contains a binary string s of length n (s_i ∈ \{0,1\})
Output
Print a single integer: ∑_{l=1}^{n} ∑_{r=l}^{n} f(l,r).
Examples
Input
4
0110
Output
12
Input
7
1101001
Output
30
Input
12
011100011100
Output
156
Note
In the first test, there are ten substrings. The list of them (we let [l,r] be the substring s_l s_{l+1} … s_r):
* [1,1]: 0
* [1,2]: 01
* [1,3]: 011
* [1,4]: 0110
* [2,2]: 1
* [2,3]: 11
* [2,4]: 110
* [3,3]: 1
* [3,4]: 10
* [4,4]: 0
The lengths of the longest contiguous sequence of ones in each of these ten substrings are 0,1,2,2,1,2,2,1,1,0 respectively. Hence, the answer is 0+1+2+2+1+2+2+1+1+0 = 12.
Submitted Solution:
```
n=int(input())
s=map(int,input().split())
t=0
for i,v in enumerate(s):
t+=v*(i+1)*(n-i)
print(t)
```
|
instruction
| 0
| 98,098
| 0
| 196,196
|
No
|
output
| 1
| 98,098
| 0
| 196,197
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
|
instruction
| 0
| 98,134
| 0
| 196,268
|
Tags: brute force
Correct Solution:
```
x,y=input(),input()
res=[0]*len(x)
dicc ={i:[] for i in "abcdefghijklmnopqrstuvwxyz"}
for i,j in enumerate(x):
dicc[j].append(i)
for i in y:
for j in dicc[i]:
res[j]+=1
res=[0]+res
print(len(y)-max(res))
```
|
output
| 1
| 98,134
| 0
| 196,269
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
|
instruction
| 0
| 98,135
| 0
| 196,270
|
Tags: brute force
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
M=10**9+7
EPS=1e-6
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
def cost(x):
ans=0
for i in range(len(t)):
ans+=s[i+x]!=t[i]
return ans
s=input()
t=input()
n=len(s)
ans=inf
s='/'*(len(t))+s+'/'*(len(t))
for i in range(n+2*len(t)-len(t)):
ans=min(ans,cost(i))
print(ans)
```
|
output
| 1
| 98,135
| 0
| 196,271
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
|
instruction
| 0
| 98,136
| 0
| 196,272
|
Tags: brute force
Correct Solution:
```
aa = input()
bb = input()
if len(aa) >= len(bb):
p = aa
q = bb
else:
p = aa
q = bb
maxc = 0
for i in range(1,len(p)+len(q)):
k1 = max(0,i-len(q))
k2 = min(i,len(p))
a = p[k1:k2]
if i < len(q):
b = q[-i:]
elif i > len(p):
b = q[:-(i-len(p))]
else:
b = q
c = 0
for j in range(len(a)):
if a[j] == b[j]:
c += 1
if c > maxc:
maxc = c
print(len(bb)-maxc)
```
|
output
| 1
| 98,136
| 0
| 196,273
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
|
instruction
| 0
| 98,137
| 0
| 196,274
|
Tags: brute force
Correct Solution:
```
x,y=input(),input()
t=[0]*len(x)
p={i:[] for i in "abcdefghijklmnopqrstuvwxyz"}
for i,j in enumerate(x):
p[j].append(i)
#print(p)
for i in y:
for j in p[i]:
t[j]+=1
t=[0]+t
print(len(y)-max(t))
# Made By Mostafa_Khaled
```
|
output
| 1
| 98,137
| 0
| 196,275
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
Submitted Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
M=10**9+7
EPS=1e-6
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
def cost(x):
temp=s[x:]
ans=0
i=0
while(i<len(t) and t[i]!=temp[0]):
i+=1
ans+=1
start=i
while(i<len(t) and i-start<len(temp)):
ans+=t[i]!=temp[i-start]
i+=1
# print(ans)
ans+=len(t)-i
# print(temp,ans,i)
return ans
s=input()
t=input()
n=len(s)
ans=inf
for i in range(n):
ans=min(ans,cost(i))
s=s[::-1]
t=t[::-1]
for i in range(n):
ans=min(ans,cost(i))
print(ans)
```
|
instruction
| 0
| 98,138
| 0
| 196,276
|
No
|
output
| 1
| 98,138
| 0
| 196,277
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string s.
String p is called a substring of string s if you can read it starting from some position in the string s. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string s and cut out some substring from it, let's call it t. Then he needs to change the substring t zero or more times. As a result, he should obtain a fixed string u (which is the string that should be sent to Sherlock Holmes). One change is defined as making one of the following actions:
* Insert one letter to any end of the string.
* Delete one letter from any end of the string.
* Change one letter into any other one.
Moriarty is very smart and after he chooses some substring t, he always makes the minimal number of changes to obtain u.
Help Moriarty choose the best substring t from all substrings of the string s. The substring t should minimize the number of changes Moriarty should make to obtain the string u from it.
Input
The first line contains a non-empty string s, consisting of lowercase Latin letters. The second line contains a non-empty string u, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive.
Output
Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose.
Examples
Input
aaaaa
aaa
Output
0
Input
abcabc
bcd
Output
1
Input
abcdef
klmnopq
Output
7
Note
In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message u, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have to make one change: to change or to add the last character.
In the third sample the initial string s doesn't contain any character that the message should contain, so, whatever string you choose, you will have to make at least 7 changes to obtain the required message.
Submitted Solution:
```
s= input()
s1 = input()
count =1
for i in range(len(s1)):
if s1[:count] in s:
count+=1
if count==1:
for i in set(s1):
if i in s:
count+=1
print(len(s1)-count+1)
```
|
instruction
| 0
| 98,139
| 0
| 196,278
|
No
|
output
| 1
| 98,139
| 0
| 196,279
|
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