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|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
|
instruction
| 0
| 96,769
| 0
| 193,538
|
"Correct Solution:
```
n,s=open(0);a=i=j=0
while j<int(n):
t=s[i:j]
if t in s[j:]:a=max(a,j-i);j+=1
else:i+=1
print(a)
```
|
output
| 1
| 96,769
| 0
| 193,539
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
n = int(input())
s = input()
ans = 0
lenS = 1
for i in range(n):
tempS = s[i:i+lenS]
while (tempS in s[i+lenS:]):
lenS += 1
tempS = s[i:i+lenS]
ans += 1
if (i + 2*lenS>= n):
break
print(ans)
```
|
instruction
| 0
| 96,770
| 0
| 193,540
|
Yes
|
output
| 1
| 96,770
| 0
| 193,541
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
n,s=open(0);a=i=j=0
while j<int(n):
if s[i:j]in s[j:]:a=max(a,j-i);j+=1
else:i+=1
print(a)
```
|
instruction
| 0
| 96,771
| 0
| 193,542
|
Yes
|
output
| 1
| 96,771
| 0
| 193,543
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
N = int(input())
S = input()
dp = [[0] * (N + 1) for _ in range(N + 1)]
ans = 0
for i in range(N - 1, -1, -1):
for j in range(N - 1, -1, -1):
if i >= j: break
if S[i] == S[j]:
dp[i][j] = min(1 + dp[i + 1][j + 1], j - i)
if dp[i][j] > ans:
ans = dp[i][j]
print(ans)
```
|
instruction
| 0
| 96,772
| 0
| 193,544
|
Yes
|
output
| 1
| 96,772
| 0
| 193,545
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
N = int(input())
S = input()
dp = [[0]*(N+1) for _ in range(N+1)]
for i in reversed(range(N)):
for j in reversed(range(N)):
if S[i] == S[j]:
dp[i][j] = dp[i+1][j+1] + 1
ans = 0
for i in range(N):
for j in range(i, N):
ans = max(min(dp[i][j], j-i), ans)
print(ans)
```
|
instruction
| 0
| 96,773
| 0
| 193,546
|
Yes
|
output
| 1
| 96,773
| 0
| 193,547
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
N=int(input())
S=input()
max=0
for f in range(len(S)-1):
#print("roop "+str(f))
i = f+1
A = [0] * (len(S)-f+i)
A[0]=len(S)
while(i<len(S)):
j=0
#print("i=" + str(i) + " j=" + str(j))
while(i+j<len(S) and S[f+j]==S[i+j] and j<i):
j+=1
#print(S[f+j]+" "+S[i+j])
A[i]=j
if(j>max):
max=j
#print("update max ="+str(max))
if(j==0):
i+=1
continue
k=1
while(k+i<len(S) and k+A[k]<j):
A[i+k]=A[k]
k+=1
i+=k
#print(A)
print(max)
```
|
instruction
| 0
| 96,774
| 0
| 193,548
|
No
|
output
| 1
| 96,774
| 0
| 193,549
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
n = int(input())
s = list(input())
res = 0
for k in range(1,n//2+10):
d = [0]*n
for i in range(n-k):
if i+k <= n-1 and s[i] == s[i+k]:
d[i] = min(k,d[i-1]+1)
res = max(res,d[i])
print(res)
```
|
instruction
| 0
| 96,775
| 0
| 193,550
|
No
|
output
| 1
| 96,775
| 0
| 193,551
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
def main():
n=int(input())
s=input()
dp=[[0]*(n+1) for i in range(n+1)]
for i in range(n-1,-1,-1):
for j in range(n-1,-1,-1):
if s[i]==s[j]:
dp[i][j]=dp[i+1][j+1]+1
for i in dp:
print(i)
ans=0
for i in range(n-1):
for j in range(i+1,n):
ans=max(ans,min(j-i,dp[i][j]))
print(ans)
if __name__=='__main__':
main()
```
|
instruction
| 0
| 96,776
| 0
| 193,552
|
No
|
output
| 1
| 96,776
| 0
| 193,553
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given is a string S of length N.
Find the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping.
More formally, find the maximum positive integer len such that there exist integers l_1 and l_2 ( 1 \leq l_1, l_2 \leq N - len + 1 ) that satisfy the following:
* l_1 + len \leq l_2
* S[l_1+i] = S[l_2+i] (i = 0, 1, ..., len - 1)
If there is no such integer len, print 0.
Constraints
* 2 \leq N \leq 5 \times 10^3
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the maximum length of a non-empty string that occurs twice or more in S as contiguous substrings without overlapping. If there is no such non-empty string, print 0 instead.
Examples
Input
5
ababa
Output
2
Input
2
xy
Output
0
Input
13
strangeorange
Output
5
Submitted Solution:
```
N = int(input())
S = input().strip()
dp = [[0 for _ in range(N+1)] for _ in range(N+1)]
for i in reversed(range(N)):
for j in reversed(range(N)):
if i >= j:
continue
if S[i] != S[j]:
dp[i][j] = 0
if S[i] == S[j]:
dp[i][j] = dp[i+1][j+1] + 1
ans = 0
for i in range(N):
for j in range(N):
now = min([dp[i][j], j-i])
ans = max(ans, now)
print(ans)
```
|
instruction
| 0
| 96,777
| 0
| 193,554
|
No
|
output
| 1
| 96,777
| 0
| 193,555
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has N strings. The i-th string is s_i.
Let us concatenate these strings into one string after arranging them in some order. Find the maximum possible number of occurrences of `AB` in the resulting string.
Constraints
* 1 \leq N \leq 10^{4}
* 2 \leq |s_i| \leq 10
* s_i consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
\vdots
s_N
Output
Print the answer.
Examples
Input
3
ABCA
XBAZ
BAD
Output
2
Input
9
BEWPVCRWH
ZZNQYIJX
BAVREA
PA
HJMYITEOX
BCJHMRMNK
BP
QVFABZ
PRGKSPUNA
Output
4
Input
7
RABYBBE
JOZ
BMHQUVA
BPA
ISU
MCMABAOBHZ
SZMEHMA
Output
4
Submitted Solution:
```
def ab_substrings(N: int, S: list)->int:
res = 0
endA = 0
startB = 0
for s in S:
res += s.count('AB')
endA += s.endswith('A')
startB += s.startswith('B')
res1, endA1, startB1 = res, endA, startB
for s in S:
if s.endswith('A') and endA1 > 0:
if not s.startswith('B') or startB1 > 1:
res1 += 1
endA1 -= 1
startB1 -= 1
res2, endA2, startB2 = res, endA, startB
for s in S:
if s.endswith('A') and endA2 > 0:
if not s.startswith('B') or startB2 > 1:
res2 += 1
endA2 -= 1
startB2 -= 1
return max(res1, res2)
if __name__ == "__main__":
N = int(input())
S = [input() for _ in range(N)]
ans = ab_substrings(N, S)
print(ans)
```
|
instruction
| 0
| 96,791
| 0
| 193,582
|
No
|
output
| 1
| 96,791
| 0
| 193,583
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t, both of length N. s and t consist of `0` and `1`. Additionally, in these strings, the same character never occurs three or more times in a row.
You can modify s by repeatedly performing the following operation:
* Choose an index i (1 \leq i \leq N) freely and invert the i-th character in s (that is, replace `0` with `1`, and `1` with `0`), under the condition that the same character would not occur three or more times in a row in s after the operation.
Your objective is to make s equal to t. Find the minimum number of operations required.
Constraints
* 1 \leq N \leq 5000
* The lengths of s and t are both N.
* s and t consists of `0` and `1`.
* In s and t, the same character never occurs three or more times in a row.
Input
Input is given from Standard Input in the following format:
N
s
t
Output
Find the minimum number of operations required to make s equal to t. It can be proved that the objective is always achievable in a finite number of operations.
Examples
Input
4
0011
0101
Output
4
Input
1
0
0
Output
0
Input
8
00110011
10101010
Output
10
Submitted Solution:
```
N = int(input())
s = input()
t = input()
# N = 8
# s = "0011" * 2
# t = "1010" * 2
s_list = [i for i in range(N-1) if s[i:i+2] in ("00", "11")]
s_list2 = [-1 for i in range(N+1)] + s_list + [(N-1) for i in range(N+1)]
t_list = [i for i in range(N-1) if t[i:i+2] in ("00", "11")]
ans = 10 ** 10
if s[0] == t[0]:
for i in range(-(len(t_list) + len(s_list))//2 - 1, len(t_list) + len(s_list) + 2):
new_ans = sum([abs(a-b) for a, b in zip(s_list2[N+1+2*i:N+1+2*i+len(t_list)], t_list)])
if N+1+2*i > N+1:
new_ans += sum(s_list2[N+1:min(N+1+2*i, N+1+len(s_list2))]) + min(2*i, len(s_list2))
if N+1+len(s_list) > N+1+2*i+len(t_list):
new_ans += (N-1) * (N+1+len(s_list) - max(N+1+2*i+len(t_list), N+1)) - \
sum(s_list2[max(N+1+2*i+len(t_list), N+1):N+1+len(s_list)])
if new_ans < ans:
ans = new_ans
else:
add_one = 0
if s_list[0] == 0:
s_list = s_list[1:]
s_list2 = [-1 for i in range(N + 1)] + s_list + [N for i in range(N + 1)]
add_one = 1
for i in range(-(len(t_list) + len(s_list))//2 - 1, len(t_list) + len(s_list) + 2):
new_ans = sum([abs(a-b) for a, b in zip(s_list2[N+1+2*i:N+1+2*i+len(t_list)], t_list)])
if N+1+2*i > N+1:
new_ans += sum(s_list2[N+1:min(N+1+2*i, N+1+len(s_list2))]) + min(2*i, len(s_list2))
if N+1+len(s_list) > N+1+2*i+len(t_list):
new_ans += (N-1) * (N+1+len(s_list) - max(N+1+2*i+len(t_list), N+1)) - \
sum(s_list2[max(N+1+2*i+len(t_list), N+1):N+1+len(s_list)])
if new_ans + add_one < ans:
ans = new_ans + add_one
print(str(ans))
```
|
instruction
| 0
| 96,794
| 0
| 193,588
|
No
|
output
| 1
| 96,794
| 0
| 193,589
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t, both of length N. s and t consist of `0` and `1`. Additionally, in these strings, the same character never occurs three or more times in a row.
You can modify s by repeatedly performing the following operation:
* Choose an index i (1 \leq i \leq N) freely and invert the i-th character in s (that is, replace `0` with `1`, and `1` with `0`), under the condition that the same character would not occur three or more times in a row in s after the operation.
Your objective is to make s equal to t. Find the minimum number of operations required.
Constraints
* 1 \leq N \leq 5000
* The lengths of s and t are both N.
* s and t consists of `0` and `1`.
* In s and t, the same character never occurs three or more times in a row.
Input
Input is given from Standard Input in the following format:
N
s
t
Output
Find the minimum number of operations required to make s equal to t. It can be proved that the objective is always achievable in a finite number of operations.
Examples
Input
4
0011
0101
Output
4
Input
1
0
0
Output
0
Input
8
00110011
10101010
Output
10
Submitted Solution:
```
import numpy as np
N = int(input())
S = np.array(list(map(int,list(input()))),dtype=np.int)
T = np.array(list(map(int,list(input()))),dtype=np.int)
def lessthan3(s,t,N,k,f):
if k >= N:
return 0
elif s[k]==t[k]:
if f==0:
return lessthan3(s,t,N,k+1,0)
elif f==1:
if k < N-1:
return lessthan3(s,t,N,k+1,2)
else:
s[k] ^= 1
return lessthan3(s,t,N,k,1) + 1
else:
s[k] ^= 1
return lessthan3(s,t,N,k,2) + 1
elif (k >= 2 and s[k-1]==t[k] and s[k-2] == t[k]) or (N-k >= 3 and s[k+1]==t[k] and s[k+2]==t[k]) or (k>=1 and N-k>=2 and s[k-1]==t[k] and s[k+1]==t[k]):
return lessthan3(s,t,N,k+1,1)+1
# elif f==0:
else:
s[k] = t[k]
return lessthan3(s,t,N,k+1,0)+1
# else:
# return lessthan3(s,t,N,k-f,0)
print(lessthan3(S,T,N,0,0))
```
|
instruction
| 0
| 96,795
| 0
| 193,590
|
No
|
output
| 1
| 96,795
| 0
| 193,591
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t, both of length N. s and t consist of `0` and `1`. Additionally, in these strings, the same character never occurs three or more times in a row.
You can modify s by repeatedly performing the following operation:
* Choose an index i (1 \leq i \leq N) freely and invert the i-th character in s (that is, replace `0` with `1`, and `1` with `0`), under the condition that the same character would not occur three or more times in a row in s after the operation.
Your objective is to make s equal to t. Find the minimum number of operations required.
Constraints
* 1 \leq N \leq 5000
* The lengths of s and t are both N.
* s and t consists of `0` and `1`.
* In s and t, the same character never occurs three or more times in a row.
Input
Input is given from Standard Input in the following format:
N
s
t
Output
Find the minimum number of operations required to make s equal to t. It can be proved that the objective is always achievable in a finite number of operations.
Examples
Input
4
0011
0101
Output
4
Input
1
0
0
Output
0
Input
8
00110011
10101010
Output
10
Submitted Solution:
```
# input
N = int(input())
S = input()
T = input()
# red nad blue bar pos
sr, sb = [], []
tr, tb = [], []
for i in range(N-1):
if S[i:i+2] == '01':
sr.append(i+1)
if S[i:i+2] == '10':
sb.append(i+1)
if T[i:i+2] == '01':
tr.append(i+1)
if T[i:i+2] == '10':
tb.append(i+1)
def dist(s, t):
long, short = (s, t) if len(s) > len(t) else t, s
dif = len(long) - len(short)
res = []
for ofs in range(dif + 1):
fit = [0] * ofs + short + [N] * (dif-ofs)
res.append(sum(abs(a-b) for a, b in zip(fit, long)))
return res
dr, db = dist(sr, tr), dist(sb, tb)
long, short = (dr, db) if len(dr) > len(db) else db, dr
dif = len(long) - len(short)
res = []
for ofs in range(dif + 1):
res.append(min(a+b for a, b in zip(short, long[ofs:ofs+len(short)])))
print(min(res))
```
|
instruction
| 0
| 96,796
| 0
| 193,592
|
No
|
output
| 1
| 96,796
| 0
| 193,593
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given strings s and t, both of length N. s and t consist of `0` and `1`. Additionally, in these strings, the same character never occurs three or more times in a row.
You can modify s by repeatedly performing the following operation:
* Choose an index i (1 \leq i \leq N) freely and invert the i-th character in s (that is, replace `0` with `1`, and `1` with `0`), under the condition that the same character would not occur three or more times in a row in s after the operation.
Your objective is to make s equal to t. Find the minimum number of operations required.
Constraints
* 1 \leq N \leq 5000
* The lengths of s and t are both N.
* s and t consists of `0` and `1`.
* In s and t, the same character never occurs three or more times in a row.
Input
Input is given from Standard Input in the following format:
N
s
t
Output
Find the minimum number of operations required to make s equal to t. It can be proved that the objective is always achievable in a finite number of operations.
Examples
Input
4
0011
0101
Output
4
Input
1
0
0
Output
0
Input
8
00110011
10101010
Output
10
Submitted Solution:
```
N = int(input())
s = input()
t = input()
# N = 8
# s = "0011" * 2
# t = "1010" * 2
s_list = [i for i in range(N-1) if s[i:i+2] in ("00", "11")]
s_list2 = [-1 for i in range(N+1)] + s_list + [(N-1) for i in range(N+1)]
t_list = [i for i in range(N-1) if t[i:i+2] in ("00", "11")]
ans = 10 ** 10
if s[0] == t[0]:
for i in range(-(len(t_list) + len(s_list))//2 - 1, len(t_list) + len(s_list) + 2):
new_ans = sum([abs(a-b) for a, b in zip(s_list2[N+1+2*i:N+1+2*i+len(t_list)], t_list)])
if N+1+2*i > N+1:
new_ans += sum(s_list2[N+1:min(N+1+2*i, N+1+len(s_list2))]) + min(2*i, len(s_list2))
if N+1+len(s_list) > N+1+2*i+len(t_list):
new_ans += (N-1) * (N+1+len(s_list) - max(N+1+2*i+len(t_list), N+1)) - \
sum(s_list2[max(N+1+2*i+len(t_list), N+1):N+1+len(s_list)])
if new_ans < ans:
ans = new_ans
else:
add_one = 0
if s_list[0] == 0:
s_list = s_list[1:]
s_list2 = [-1 for i in range(N + 1)] + s_list + [N for i in range(N + 1)]
add_one = 1
for i in range(-(len(t_list) + len(s_list))//2 - 1, len(t_list) + len(s_list) + 2):
new_ans = sum([abs(a-b) for a, b in zip(s_list2[N+1+2*i:N+1+2*i+len(t_list)], t_list)])
if N+1+2*i > N+1:
new_ans += sum(s_list2[N+1:min(N+1+2*i, N+1+len(s_list2))]) + min(2*i, len(s_list2))
if N+1+len(s_list) > N+1+2*i+len(t_list):
new_ans += (N-1) * (N+1+len(s_list) - max(N+1+2*i+len(t_list), N+1)) - \
sum(s_list2[max(N+1+2*i+len(t_list), N+1):N+1+len(s_list)])
if new_ans < ans + add_one:
ans = new_ans + add_one
print(str(ans))
```
|
instruction
| 0
| 96,797
| 0
| 193,594
|
No
|
output
| 1
| 96,797
| 0
| 193,595
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,842
| 0
| 193,684
|
"Correct Solution:
```
s = input()
print(s.rfind('Z')-s.index('A')+1)
```
|
output
| 1
| 96,842
| 0
| 193,685
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,843
| 0
| 193,686
|
"Correct Solution:
```
ss = input()
print(ss.rindex('Z') - ss.index('A') + 1)
```
|
output
| 1
| 96,843
| 0
| 193,687
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,844
| 0
| 193,688
|
"Correct Solution:
```
s=input()
a=s.index("A")
z=s[::-1].index("Z")
print(len(s)-z-a)
```
|
output
| 1
| 96,844
| 0
| 193,689
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,845
| 0
| 193,690
|
"Correct Solution:
```
import re
s = input()
print(len(re.search('A.*Z', s).group()))
```
|
output
| 1
| 96,845
| 0
| 193,691
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,846
| 0
| 193,692
|
"Correct Solution:
```
s = input()
print(len(s) - s.find('A') - s[::-1].find('Z'))
```
|
output
| 1
| 96,846
| 0
| 193,693
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,847
| 0
| 193,694
|
"Correct Solution:
```
s=input()
print(-s.find("A")+s.rfind("Z")+1)
```
|
output
| 1
| 96,847
| 0
| 193,695
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,848
| 0
| 193,696
|
"Correct Solution:
```
s = input()
print(len(s)-s[::-1].find('Z')-s.find('A'))
```
|
output
| 1
| 96,848
| 0
| 193,697
|
Provide a correct Python 3 solution for this coding contest problem.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
|
instruction
| 0
| 96,849
| 0
| 193,698
|
"Correct Solution:
```
s = input()
d1 = s.find("A")
d2 = s.rfind("Z")
print(d2-d1+1)
```
|
output
| 1
| 96,849
| 0
| 193,699
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
s=input()
print(len(s[s.find('A'):s.rfind("Z")+1]))
```
|
instruction
| 0
| 96,850
| 0
| 193,700
|
Yes
|
output
| 1
| 96,850
| 0
| 193,701
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
s=input()
print(s.rfind("Z")-s.find("A")+1)
#コピペです
```
|
instruction
| 0
| 96,851
| 0
| 193,702
|
Yes
|
output
| 1
| 96,851
| 0
| 193,703
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
s=str(input())
a,b=s.find("A"),s.rfind("Z")
print(b-a+1)
```
|
instruction
| 0
| 96,852
| 0
| 193,704
|
Yes
|
output
| 1
| 96,852
| 0
| 193,705
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
s = input()
ans = s.rfind('Z') - s.find('A') + 1
print(ans)
```
|
instruction
| 0
| 96,853
| 0
| 193,706
|
Yes
|
output
| 1
| 96,853
| 0
| 193,707
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
import sys
def yn(b):
print("Yes" if b==1 else "No")
return
def resolve():
readline=sys.stdin.readline
ss=readline().strip()
n=0
a=100000000
z=0
for s in sss:
if s=="A":
a=min(a,n)
elif s=="Z":
z=n
n+=1
print(z-a+1)
return
resolve()
```
|
instruction
| 0
| 96,854
| 0
| 193,708
|
No
|
output
| 1
| 96,854
| 0
| 193,709
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
s=list(input())
a=s.index("A")
for i in range(len(s),0):
if s[i-1]=="Z":
z=i-1
z-=len(s)-1
sum=z-a+1
print(sum)
```
|
instruction
| 0
| 96,855
| 0
| 193,710
|
No
|
output
| 1
| 96,855
| 0
| 193,711
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
# -*- coding: utf-8 -*-
s = input()
print(s)
for i in range(len(s)):
if s[i] == 'A':
s = s[i:]
break
s = s[::-1]
print(s)
for i in range(len(s)):
if s[i] == 'Z':
s = s[i:]
print(len(s))
break
```
|
instruction
| 0
| 96,856
| 0
| 193,712
|
No
|
output
| 1
| 96,856
| 0
| 193,713
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has decided to construct a string that starts with `A` and ends with `Z`, by taking out a substring of a string s (that is, a consecutive part of s).
Find the greatest length of the string Snuke can construct. Here, the test set guarantees that there always exists a substring of s that starts with `A` and ends with `Z`.
Constraints
* 1 ≦ |s| ≦ 200{,}000
* s consists of uppercase English letters.
* There exists a substring of s that starts with `A` and ends with `Z`.
Input
The input is given from Standard Input in the following format:
s
Output
Print the answer.
Examples
Input
QWERTYASDFZXCV
Output
5
Input
ZABCZ
Output
4
Input
HASFJGHOGAKZZFEGA
Output
12
Submitted Solution:
```
S=input()
ans=0
tmp=0
end=0
for i in range(len(S)):
if S[i]=="A":
tmp=i
break
for i in range(1,len(S)):
if S[-i]=="Z":
end=len(S)-i
break
print(tmp,end)
print(end-tmp+1)
```
|
instruction
| 0
| 96,857
| 0
| 193,714
|
No
|
output
| 1
| 96,857
| 0
| 193,715
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,101
| 0
| 194,202
|
Tags: implementation, strings
Correct Solution:
```
def erase(s):
c =0
if len(s) == 1:
return 0
ns = ""
if "1" in s:
ns = s[s.index("1")]
for i in range(s.index("1"),len(s)-1):
if ns[-1] == "1" and s[i] == "0" and "1" in s[i:]:
ns+="1"
c+=1
return c
tc = int(input())
for i in range(tc):
s = input()
print(erase(s))
```
|
output
| 1
| 97,101
| 0
| 194,203
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,102
| 0
| 194,204
|
Tags: implementation, strings
Correct Solution:
```
for _ in range(int(input())):
s = input()
l = []
c=0
for i in range(len(s)):
if s[i]=='1':
c+=1
l.append(i)
if len(l)>1:
d = l[-1]-l[0]+1
print(d-c)
else:
print('0')
```
|
output
| 1
| 97,102
| 0
| 194,205
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,103
| 0
| 194,206
|
Tags: implementation, strings
Correct Solution:
```
t=int(input())
while t>0:
t-=1
l=input()
d=dict()
d['0']=[]
d['1']=[]
for i in range(len(l)):
d[l[i]].append(i)
if len(d['0'])==0 or len(d['1'])==0:
print(0)
else:
n=len(d['0'])-(d['1'])[0]
n-=len(l)-1-(d['1'])[len(d['1'])-1]
print(n)
```
|
output
| 1
| 97,103
| 0
| 194,207
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,104
| 0
| 194,208
|
Tags: implementation, strings
Correct Solution:
```
t = int(input())
for _ in range(t):
s = input()
i = 0
while s[i] == '0' and i != len(s) - 1:
i += 1
j = -1
while s[j] == '0' and -j != len(s):
j -= 1
print(s[i:j].count('0'))
```
|
output
| 1
| 97,104
| 0
| 194,209
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,105
| 0
| 194,210
|
Tags: implementation, strings
Correct Solution:
```
q = int(input())
for _ in range(q):
s = input()
t = s[::-1]
try:
id1 = s.index('1')
id2 = len(s) - t.index('1')
a = s[id1:id2]
b = a.replace('0','')
print(len(a)-len(b))
except:
print(0)
```
|
output
| 1
| 97,105
| 0
| 194,211
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,106
| 0
| 194,212
|
Tags: implementation, strings
Correct Solution:
```
for _ in [0]*int(input()):
First1 = False
One = False
ans,scet0 = 0,0
for i in input():
if i =="1":
First1 = True
One ==True
ans += scet0
scet0 = 0
else:
if First1:
scet0+=1
print(ans)
```
|
output
| 1
| 97,106
| 0
| 194,213
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,107
| 0
| 194,214
|
Tags: implementation, strings
Correct Solution:
```
for _ in range(int(input())):
s = input()
i = 0
l = len(s)
while i<l:
if s[i]=='1':
break
i+=1
j = l-1
while j>-1:
if s[j]=='1':
break
j-=1
s = s[i:j+1]
print(s.count('0'))
```
|
output
| 1
| 97,107
| 0
| 194,215
|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
|
instruction
| 0
| 97,108
| 0
| 194,216
|
Tags: implementation, strings
Correct Solution:
```
#A erasing zeroes
for i in range(int(input())):
arr = input()
a = []
sum = 0
for j in range(0,len(arr)):
if(arr[j]=='1'):
a.append(j)
for j in range(len(a)-1):
sum = sum + (a[j+1]-a[j]-1)
print(sum)
```
|
output
| 1
| 97,108
| 0
| 194,217
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
t = int(input())
for _ in range(t):
s = str(int(input()))
cnt = 0
hasOne = False
for i in reversed(s):
if i=="1":
hasOne = True
if i=="0" and hasOne:
cnt+=1
print(cnt)
```
|
instruction
| 0
| 97,109
| 0
| 194,218
|
Yes
|
output
| 1
| 97,109
| 0
| 194,219
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
n=int(input())
for i in range(n):
t=str(input())
h=list(t)
for j in range(len(h)):
if h[j]=='0':
h[j]='k'
else:
break
r=len(h)
for y in range(r-1,-1,-1):
if h[y]=='0':
h[y]='k'
else:
break
print(h.count('0'))
```
|
instruction
| 0
| 97,110
| 0
| 194,220
|
Yes
|
output
| 1
| 97,110
| 0
| 194,221
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
t = int(input())
for i in range(t):
s = input()
enter = False
endind = -1
counter = 0
for l in range(1, len(s) + 1):
if s[len(s) - l] == '1':
endind = len(s) - l
break
if endind != -1:
s1 = s[s.index('1'):endind]
for k in s1:
if k == '0':
counter += 1
print(counter)
```
|
instruction
| 0
| 97,111
| 0
| 194,222
|
Yes
|
output
| 1
| 97,111
| 0
| 194,223
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
# ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# ------------------- fast io --------------------
for _ in range(int(input())):
s = input()
ans = 0
for i in range(len(s)):
if s[i] == "1":
for j in range(i+1, s.rfind("1")):
if s[j] == "0": ans += 1
break
print(ans)
```
|
instruction
| 0
| 97,112
| 0
| 194,224
|
Yes
|
output
| 1
| 97,112
| 0
| 194,225
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
T = int(input())
for i in range(1, T+1):
s = list(input())
if '1' not in s:
print(0)
else:
first = s.index('1')
for j in range(len(s)-1, -1, -1):
if s[j] == '1':
last = j
count = 0
for k in range(first, last):
if s[k] == '0':
count += 1
print(count)
```
|
instruction
| 0
| 97,113
| 0
| 194,226
|
No
|
output
| 1
| 97,113
| 0
| 194,227
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
for _ in range(int(input())):
s=input()
if '1' not in s:
print(0);continue
t=s.index('1');m=10000000000
for i in range(t+1,len(s)):
if s[i]=='1':
if m>=i-t and i-t>1:
m=i-t
t=i
print(m-1) if m<10000000000 else print(0)
```
|
instruction
| 0
| 97,114
| 0
| 194,228
|
No
|
output
| 1
| 97,114
| 0
| 194,229
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
t=int(input())
while t!=0:
s=input()
li=list(s)
if '1' not in li:
print(0)
else:
count=0
index=li.index('1')
for i in range(index,len(li)-1,1):
if li[i+1]=='0':
count+=1
elif li[i+1]=='1':
break
print(count)
t=t-1
```
|
instruction
| 0
| 97,115
| 0
| 194,230
|
No
|
output
| 1
| 97,115
| 0
| 194,231
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s. Each character is either 0 or 1.
You want all 1's in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1's form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0's from the string. What is the minimum number of 0's that you have to erase?
Input
The first line contains one integer t (1 ≤ t ≤ 100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1 ≤ |s| ≤ 100); each character of s is either 0 or 1.
Output
Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0's that you have to erase from s).
Example
Input
3
010011
0
1111000
Output
2
0
0
Note
In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).
Submitted Solution:
```
s = []
for i in range(int(input())):
s.append(input())
def working(pattern):
start = 0
end = 0
zeros_removed = 0
while start == 0:
start_one = pattern.find('1')
end_one = pattern.rfind('1')
start_zero = pattern.find('0')
if start_one < start_zero < end_one:
pattern = pattern[:start_zero] + pattern[start_zero + 1:]
zeros_removed += 1
else:
start = 1
while end == 0:
start_one = pattern.find('1')
end_one = pattern.rfind('1')
end_zero = pattern.rfind('0')
if start_one < end_zero < end_one:
pattern = pattern[:end_zero] + pattern[end_zero + 1:]
zeros_removed += 1
else:
end = 1
return zeros_removed
for i in s:
print(working(i))
```
|
instruction
| 0
| 97,116
| 0
| 194,232
|
No
|
output
| 1
| 97,116
| 0
| 194,233
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Karl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least k subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.
Formally, a codeforces subsequence of a string s is a subset of ten characters of s that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.
Help Karl find any shortest string that contains at least k codeforces subsequences.
Input
The only line contains a single integer k (1 ≤ k ≤ 10^{16}).
Output
Print a shortest string of lowercase English letters that contains at least k codeforces subsequences. If there are several such strings, print any of them.
Examples
Input
1
Output
codeforces
Input
3
Output
codeforcesss
|
instruction
| 0
| 97,133
| 0
| 194,266
|
Tags: brute force, constructive algorithms, greedy, math, strings
Correct Solution:
```
k=int(input())
out=''
t=list('codeforces')
d=[1]*10
m=1
i=0
while m<k:
#print(i,m)
d[i]+=1
i=(i+1)%10
m=1
for j in range(10):
m*=d[j]
out=''
for i in range(10):
out+=t[i]*d[i]
print(out)
```
|
output
| 1
| 97,133
| 0
| 194,267
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Karl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least k subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.
Formally, a codeforces subsequence of a string s is a subset of ten characters of s that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.
Help Karl find any shortest string that contains at least k codeforces subsequences.
Input
The only line contains a single integer k (1 ≤ k ≤ 10^{16}).
Output
Print a shortest string of lowercase English letters that contains at least k codeforces subsequences. If there are several such strings, print any of them.
Examples
Input
1
Output
codeforces
Input
3
Output
codeforcesss
|
instruction
| 0
| 97,134
| 0
| 194,268
|
Tags: brute force, constructive algorithms, greedy, math, strings
Correct Solution:
```
#!/usr/bin/env python3
import io
import os
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def get_str():
return input().decode().strip()
def rint():
return map(int, input().split())
def oint():
return int(input())
n = oint()
s = 'codeforces'
l = len(s)
r = 1
while r**10 < n:
r += 1
if r**10 == n:
print(''.join([s[i]*r for i in range(l)]))
exit()
r -= 1
mul = r**l
cnt = 0
while True:
cnt += 1
mul = mul*(r+1)//r
if mul >= n:
break
ans = []
ans += [s[i]*(r+1) for i in range(cnt)]
ans += [s[i]*r for i in range(cnt, l)]
print(''.join(ans))
```
|
output
| 1
| 97,134
| 0
| 194,269
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Karl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least k subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.
Formally, a codeforces subsequence of a string s is a subset of ten characters of s that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.
Help Karl find any shortest string that contains at least k codeforces subsequences.
Input
The only line contains a single integer k (1 ≤ k ≤ 10^{16}).
Output
Print a shortest string of lowercase English letters that contains at least k codeforces subsequences. If there are several such strings, print any of them.
Examples
Input
1
Output
codeforces
Input
3
Output
codeforcesss
|
instruction
| 0
| 97,135
| 0
| 194,270
|
Tags: brute force, constructive algorithms, greedy, math, strings
Correct Solution:
```
import math
n=int(input())
p=int(math.floor(math.pow(n,0.1)))
a=0
x=p**10
while n>x:
a+=1
x=((p+1)**a)*(p**(10-a))
s='codeforces'
ans=''
for i in range(10):
if i<a:
ans+=s[i]*(p+1)
else:
ans+=s[i]*p
print(ans)
```
|
output
| 1
| 97,135
| 0
| 194,271
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Karl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least k subsequences codeforces. Out of all possible strings, Karl wants to find a shortest one.
Formally, a codeforces subsequence of a string s is a subset of ten characters of s that read codeforces from left to right. For example, codeforces contains codeforces a single time, while codeforcesisawesome contains codeforces four times: codeforcesisawesome, codeforcesisawesome, codeforcesisawesome, codeforcesisawesome.
Help Karl find any shortest string that contains at least k codeforces subsequences.
Input
The only line contains a single integer k (1 ≤ k ≤ 10^{16}).
Output
Print a shortest string of lowercase English letters that contains at least k codeforces subsequences. If there are several such strings, print any of them.
Examples
Input
1
Output
codeforces
Input
3
Output
codeforcesss
|
instruction
| 0
| 97,136
| 0
| 194,272
|
Tags: brute force, constructive algorithms, greedy, math, strings
Correct Solution:
```
from math import log, floor, ceil
k = int(input())
base = 1
while base ** 10 < k:
base += 1
counts_base = 0
count_1 = 10
while (base ** counts_base) * ((base-1) ** count_1) < k:
counts_base += 1
count_1 -= 1
# print("counts_base", counts_base)
# print("count_1", count_1)
codeforces = "codeforces"
ans = ""
for i in range(counts_base):
ans += codeforces[i] * base
for i in range(count_1):
ans += codeforces[counts_base+i] * (base-1)
print(ans)
```
|
output
| 1
| 97,136
| 0
| 194,273
|
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