premise
stringlengths 923
1.41k
| hypothesis
stringlengths 11
33
| label
stringclasses 4
values |
|---|---|---|
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Leith is smoggy. | neutral |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Janet is ugliest. | neutral |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Lester is not ugliest. | self_contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Kelsey is not fine. | entailment |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Lincoln is not fine. | contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Janet is not smoggy. | neutral |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Kelsey is smoggy. | contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Lester is not blushing. | entailment |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Janet is not blushing. | neutral |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Otis is ugliest. | self_contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Janet is not fine. | entailment |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Lincoln is not stormy. | self_contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Kelsey is not stormy. | contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Kelsey is not ugliest. | contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Leith is not helpless. | entailment |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Otis is blushing. | self_contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Kelsey is stormy. | entailment |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Otis is not fine. | contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Otis is not blushing. | self_contradiction |
Leith is not helpless.
Lester is not stormy.
Otis is smoggy.
Kelsey is not fine.
Lincoln is ugliest.
Kelsey is not smoggy.
Lincoln is helpless.
Leith is not fine.
Janet is not fine.
Kelsey is ugliest.
Otis is not helpless.
Lester is fine.If there is at least one people who is both not helpless and not smoggy, then Otis is blushing.
Kelsey being stormy and Lester being not helpless imply that Lincoln is smoggy.
Someone who is both not smoggy and not blushing is always fine.
Someone being both stormy and helpless is equivalent to being not blushing and fine.
Leith being not stormy is equivalent to Lester being not helpless and Otis being not ugliest.
If there is at least one people who is both fine and helpless, then Lincoln is not stormy.
If there is someone who is either not ugliest or stormy, then Leith is not blushing.
Someone who is both fine and stormy is always helpless.
Someone being fine is equivalent to being not ugliest.
Someone who is eithor blushing or not ugliest is always stormy.
As long as someone is either helpless or not smoggy, he is ugliest and stormy.
If someone is not ugliest or he is smoggy, then he is fine. | Paxton is helpless. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Quillan is crooked. | contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Amanda is crooked. | entailment |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Harris is not petite. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Amanda is petite. | entailment |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Harvey is not hurt. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Jesse is not crooked. | entailment |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Jesse is crooked. | contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Quillan is not magnificent. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Quillan is not hurt. | entailment |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Jesse is attentive. | self_contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Jesse is not petite. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Aiken is not magnificent. | contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Quillan is not crooked. | entailment |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Aiken is not attentive. | self_contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Aiken is difficult. | self_contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Harvey is not crooked. | neutral |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Quillan is hurt. | contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Aiken is attentive. | self_contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Harvey is difficult. | self_contradiction |
Aiken is attentive.
Harvey is difficult.
Quillan is not crooked.
Amanda is not attentive.
Aiken is petite.
Amanda is crooked.
Jesse is not hurt.
Quillan is not hurt.
Chester is not magnificent.
Aiken is difficult.
Aiken is magnificent.
Aiken is hurt.Jesse being not attentive is equivalent to Amanda being hurt.
If someone is petite and hurt, then he is both not attentive and crooked, and vice versa.
Someone is not hurt if and only if he is not crooked.
If there is at least one people who is not crooked or not petite, then Jesse is attentive.
If Quillan is not magnificent and Quillan is petite, then Harris is crooked.
If someone is attentive or petite, then he is hurt.
If someone is both attentive and not petite, then he is not hurt.
If everyone is not attentive or not petite, then Jesse is not difficult.
It can be concluded that Jesse is not crooked once knowing that Chester is not difficult or Quillan is hurt.
If someone is magnificent, then he is difficult, and vice versa.
If Jesse is not hurt or Harris is not attentive, then Amanda is crooked.
Someone who is magnificent is always not difficult. | Amanda is not hurt. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is rude. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Clifford is rude. | entailment |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Culbert is rude. | entailment |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is not rude. | entailment |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Kianna is not delightful. | neutral |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Boris is not chestnut. | neutral |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Clifford is not chestnut. | neutral |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Culbert is not conscious. | neutral |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Boris is not happy. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is conscious. | entailment |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Kianna is not tremendous. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is not tremendous. | entailment |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Boris is delightful. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is not delightful. | self_contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Clifford is not conscious. | neutral |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Culbert is not happy. | contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Ryan is not happy. | self_contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is happy. | self_contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Ryan is happy. | self_contradiction |
Culbert is rude.
Tommy is conscious.
Ryan is happy.
Clifford is rude.
Kianna is happy.
Tommy is not rude.
Culbert is happy.
Boris is happy.
Boris is rude.
Leona is not delightful.
Tommy is not tremendous.
Kianna is tremendous.If there is at least one people who is tremendous, then Boris is not delightful and Ryan is not happy.
Ryan being not rude implies that Kianna is delightful and Clifford is not chestnut.
Clifford being chestnut implies that Culbert is delightful.
Ryan being not rude implies that Leona is not conscious.
Leona being conscious and Kianna being not delightful imply that Ryan is happy.
Someone is not delightful and not rude if and only if he is not tremendous.
If someone is conscious and not tremendous, then he is both not chestnut and not rude, and vice versa.
Someone who is both not tremendous and not rude is always not chestnut.
Someone is delightful and happy if and only if he is not tremendous.
If there is at least one people who is not chestnut or happy, then Boris is not delightful.
Someone is not happy and not delightful if and only if he is not tremendous and not rude.
It can be concluded that Ryan is not conscious once knowing that Leona is delightful or Clifford is tremendous. | Tommy is delightful. | self_contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Robyn is not shallow. | contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is not yellow. | contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Kingsley is not desperate. | self_contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Buck is aware. | neutral |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is boring. | entailment |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is desperate. | self_contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Caldwell is boring. | entailment |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Bryant is not boring. | neutral |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Justin is not boring. | self_contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Robyn is not yellow. | contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Bryant is desperate. | neutral |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Robyn is aware. | entailment |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Caldwell is not bumpy. | neutral |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Justin is boring. | self_contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is not boring. | contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Buck is shallow. | entailment |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Justin is not shallow. | contradiction |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is shallow. | entailment |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Kingsley is yellow. | neutral |
Robyn is aware.
Bryant is bumpy.
Buck is shallow.
Kingsley is bumpy.
Sophia is not desperate.
Kingsley is not desperate.
Justin is yellow.
Robyn is shallow.
Justin is not boring.
Sophia is yellow.
Caldwell is not yellow.
Robyn is not bumpy.Sophia being aware or Bryant being not shallow implies that Robyn is not desperate.
If Justin is shallow, then Robyn is not desperate and Caldwell is boring, and vice versa.
If someone is not bumpy and shallow, then he is yellow, and vice versa.
If there is someone who is either not yellow or desperate, then Caldwell is aware.
It can be concluded that Sophia is desperate once knowing that Bryant is shallow or Robyn is boring.
It can be concluded that Justin is not bumpy once knowing that Caldwell is shallow or Justin is not yellow.
All not shallow people are desperate.
If there is someone who is both not aware and not desperate, then Buck is boring.
If someone is yellow, then he is both not desperate and boring.
If there is someone who is bumpy, then Kingsley is not shallow.
It can be concluded that Kingsley is bumpy once knowing that Justin is not desperate and Bryant is not boring.
It can be concluded that Kingsley is desperate once knowing that Kingsley is aware. | Sophia is not desperate. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Crispin is not smart. | neutral |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Theodore is not expensive. | contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Deborah is expensive. | neutral |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Theodore is not pleasant. | contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Harlan is not pleasant. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Braden is pleasant. | neutral |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Crispin is not pleasant. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Aubrey is happy. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Aubrey is not cheeky. | neutral |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Braden is not cheeky. | neutral |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Harlan is expensive. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Theodore is expensive. | entailment |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Crispin is expensive. | self_contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Crispin is not cheeky. | contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Deborah is cool. | contradiction |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Harlan is cheeky. | entailment |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Theodore is pleasant. | entailment |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Deborah is not cool. | entailment |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Crispin is cheeky. | entailment |
Crispin is pleasant.
Blanca is smart.
Braden is not smart.
Theodore is pleasant.
Deborah is not cool.
Braden is happy.
Crispin is cheeky.
Harlan is not pleasant.
Harlan is expensive.
Aubrey is not cool.
Aubrey is happy.
Crispin is not expensive.Aubrey being not cheeky and Blanca being not smart imply that Harlan is not cool.
Someone being not pleasant is equivalent to being not expensive.
If someone is not cool and pleasant, then he is both smart and happy, and vice versa.
If Crispin is not expensive or Harlan is not smart, then Aubrey is not happy.
If someone is cheeky, then he is both pleasant and expensive.
Deborah being not cheeky and Braden being happy imply that Aubrey is smart.
If there is at least one people who is both expensive and cool, then Braden is not smart.
Someone who is eithor expensive or pleasant is always cheeky.
It can be concluded that Theodore is not smart and Theodore is cool once knowing that Harlan is pleasant.
If there is someone who is expensive, then Braden is not smart.
If Crispin is smart, then Crispin is cheeky and Harlan is pleasant.
If there is someone who is not expensive, then Blanca is pleasant. | Blanca is not pleasant. | contradiction |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.