Datasets:

math-eval

/

TAL-SCQ5K

like 39

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$$17$$ " } ], [ { "aoVal": "B", "content": "$$$52$$ " } ], [ { "aoVal": "C", "content": "$$$68$$ " } ], [ { "aoVal": "D", "content": "$$$102$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts" ]

[ "After discount, price became $100\\textbackslash\\%-20\\textbackslash\\%=80\\textbackslash\\%$ of original price. $\\textbackslash$85\\times80\\textbackslash\\%=\\textbackslash$85\\times0.8=\\textbackslash$68$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$1:3$$ " } ], [ { "aoVal": "B", "content": "$$3:1 $$ " } ], [ { "aoVal": "C", "content": "$$1:4 $$ " } ], [ { "aoVal": "D", "content": "$$4:1$$ " } ], [ { "aoVal": "E", "content": "$$4:3$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units" ]

[ "Julia has eaten one-quarter of the pizza. So three-quarters of the pizza remain. Therefore the required ratio is $$\\frac{3}{4}:\\frac{1}{4}=3:1$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$7$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$6$$ " } ], [ { "aoVal": "E", "content": "$$4$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis->Basic Type->Non-typical Types" ]

[ "Full score: $10+10\\times1=20$. Smith gets $(20-14)\\div(1+1)=3$ questions wrong, and $10-3=7$ questions correct. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Sunday " } ], [ { "aoVal": "B", "content": "Monday " } ], [ { "aoVal": "C", "content": "Tuesday " } ], [ { "aoVal": "D", "content": "Thursday " } ], [ { "aoVal": "E", "content": "Saturday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$$55\\div7=7 \\text{R}6$$. It is Saturday. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$273$$ " } ], [ { "aoVal": "B", "content": "$$272$$ " } ], [ { "aoVal": "C", "content": "$$271$$ " } ], [ { "aoVal": "D", "content": "$$270$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division" ]

[ "Continue subtracting $$4$$￠ from $$2458$$￠ until the difference is a multiple of $$9$$. This happens when the difference is $$2430$$￠ which is $$270 \\times 9$$￠. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$24\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$25\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$30\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$36\\textbackslash\\%$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts" ]

[ "$$5500\\div(1+10\\textbackslash\\%)=5000$$, $$1800\\div5000=36\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$8$$ " } ], [ { "aoVal": "B", "content": "$$7$$ " } ], [ { "aoVal": "C", "content": "$$6$$ " } ], [ { "aoVal": "D", "content": "$$5$$ " } ], [ { "aoVal": "E", "content": "$$4$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems" ]

[ "It climbs up $$3$$ meters in the day time and slips down $$1$$ meter at night, so it climbs up $$2$$ meters in a whole day. For the first $$4$$ days, it climbs $$8$$ meters. During the day time of the fifth day, it climbs $$3$$ meters and reaches the ground. Then it needs five days to climb up to the ground. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$15$$ ounces " } ], [ { "aoVal": "B", "content": "$$12$$ ounces " } ], [ { "aoVal": "C", "content": "$$9$$ ounces " } ], [ { "aoVal": "D", "content": "$$6$$ ounces " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Finding and Making Use of Invariants" ]

[ "$$40-40\\times25\\textbackslash\\%\\div40\\textbackslash\\%=40-25=15$$ ounces. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$50$$ " } ], [ { "aoVal": "B", "content": "$$52$$ " } ], [ { "aoVal": "C", "content": "$$55$$ " } ], [ { "aoVal": "D", "content": "$$58$$ " } ], [ { "aoVal": "E", "content": "$$60$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$80 \\textbackslash\\% \\cdot 10=8$, $60\\textbackslash\\% \\cdot 20=12$, $50\\textbackslash\\% \\cdot 30=15$ Adding them up gets $8+12+15=35$. The overall percentage correct would be $\\frac{35}{60} \\approx 0.58$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "on the $2$\\textsuperscript{nd} floor " } ], [ { "aoVal": "B", "content": "on the $3$\\textsuperscript{rd} floor " } ], [ { "aoVal": "C", "content": "on the $4$\\textsuperscript{th} floor " } ], [ { "aoVal": "D", "content": "on the $5$\\textsuperscript{th} floor " } ], [ { "aoVal": "E", "content": "on the $6$\\textsuperscript{th} floor " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "Gawel lives on the second floor, so he only needs to walk up one floor. Pawel has to walk up twice as many stairs as Gawel, so he needs to walk up two floors. So, Pawel lives on the $3$\\textsuperscript{rd} floor. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$33$$ " } ], [ { "aoVal": "B", "content": "$$34$$ " } ], [ { "aoVal": "C", "content": "$$35$$ " } ], [ { "aoVal": "D", "content": "$$36$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of one Character in a Line" ]

[ "If there are a total of $$110$$ people in line, subtract those behind Ben and Ben himself: $$110-76-1=33$$, the number in front of Ben. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$135\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$180\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$75\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$$25\\textbackslash\\%$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts" ]

[ "$$1-135\\div180=25\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$1156$$ " } ], [ { "aoVal": "B", "content": "$$556$$ " } ], [ { "aoVal": "C", "content": "$$454$$ " } ], [ { "aoVal": "D", "content": "$$444$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples", "Overseas In-curriculum->Knowledge Point->Operations of Numbers ->Addition and Subtraction of Whole Numbers->Adding and Subtracting within 10000->Subtraction of 3-digit Numbers" ]

[ "$$800-356=444$$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$8$$ " } ], [ { "aoVal": "D", "content": "$$10$$ " } ], [ { "aoVal": "E", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis" ]

[ "If all were rabbits, $20\\times 4= 80$ the total number of legs would be $$$80$$. $80- 48=32$ The difference is $$$32$$. $4-2=2$ $32\\div 2=16$ $20-16=4$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$20\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$25\\textbackslash\\%$ " } ], [ { "aoVal": "C", "content": "$30\\textbackslash\\%$ " } ], [ { "aoVal": "D", "content": "$40\\textbackslash\\%$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems" ]

[ "$$10\\div(10+15)=40\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$7$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$10$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with One Variable" ]

[ "$$40-8=32$$, $$32\\div4=8$$. Mother used $$8$$ bottles. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Friday " } ], [ { "aoVal": "B", "content": "Saturday " } ], [ { "aoVal": "C", "content": "Sunday " } ], [ { "aoVal": "D", "content": "Monday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "Thursday to Sunday $$\\rightarrow 6\\times 2+11\\times 2=34$$ pages $$348-34=314$$ $1$ week (Monday to Sunday) $$\\rightarrow 11\\times 2+6\\times 5=52$$ pages $6$ weeks $$\\rightarrow 52\\times6=312$$ pages After reading another $312$ pages in $6$ weeks, Julian has another $(314 -- 312) = 2$ pages left to read. It will now be a Monday and Julian can finish reading the last $2$ pages. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$40$$ " } ], [ { "aoVal": "C", "content": "$$400$$ " } ], [ { "aoVal": "D", "content": "$$760$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$800 \\times 5$\\%=$40$, $40$ students at Hamilton Middle School have red hair. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "＄$$11346$$ " } ], [ { "aoVal": "B", "content": "＄$$11315$$ " } ], [ { "aoVal": "C", "content": "＄$$10980$$ " } ], [ { "aoVal": "D", "content": "＄$$10950$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value" ]

[ "In March, there are $$31$$ days. I earned ＄$$930 \\div 31$$, which is ＄$$30$$ each day. For all of $$1992$$, I earned $$366\\times$$ ＄$$30 =$$＄$$10980$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$$$Blue " } ], [ { "aoVal": "B", "content": "$$$$Green " } ], [ { "aoVal": "C", "content": "$$$$Red " } ], [ { "aoVal": "D", "content": "$$$$Black " } ], [ { "aoVal": "E", "content": "$$$$Yellow " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation" ]

[ "A group of the blue one, the green one, the red one, and the yellow one is repeating. $17 \\div 4 = 4R1$, so the seventeenth one is blue. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$23$$ " } ], [ { "aoVal": "B", "content": "$$31$$ " } ], [ { "aoVal": "C", "content": "$$38$$ " } ], [ { "aoVal": "D", "content": "$$26$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems" ]

[ "omitted " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$7$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$10$$ " } ], [ { "aoVal": "E", "content": "$$11$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems" ]

[ "Six years ago, the sum of ages of Luna, Lily, and Lucy was $33-6\\times3=15$. Lucy was $15-0-5=10$ years old. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$15\\textbackslash\\%$ " } ], [ { "aoVal": "B", "content": "$16\\textbackslash\\%$ " } ], [ { "aoVal": "C", "content": "$16.25\\textbackslash\\%$ " } ], [ { "aoVal": "D", "content": "$17\\textbackslash\\%$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems->Calculating Solution from Solute and Solvent" ]

[ "$$\\frac{200\\times 10\\textbackslash\\%+200\\times 15\\textbackslash\\%+400\\times 20\\textbackslash\\%}{200+200+400}\\times 100\\textbackslash\\%=16.25\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$2$$ " } ], [ { "aoVal": "B", "content": "$$3$$ " } ], [ { "aoVal": "C", "content": "$$4$$ " } ], [ { "aoVal": "D", "content": "$$5$$ " } ], [ { "aoVal": "E", "content": "$$6$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Sally made $0.75 * 20=15$ shots originally. Letting $x$ be the number of shots she made, we have $\\frac{15+x}{30}=0.6$. Solving for $x$ gives us $x=3$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$8$$ " } ], [ { "aoVal": "D", "content": "$$10$$ " } ], [ { "aoVal": "E", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "Angela recited $$11-7=4$$ poems more than Crystal. There are 4$$\\times$$2$$=8$$ points " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$60$$ " } ], [ { "aoVal": "B", "content": "$$61$$ " } ], [ { "aoVal": "C", "content": "$$66$$ " } ], [ { "aoVal": "D", "content": "$$70$$ " } ], [ { "aoVal": "E", "content": "$$71$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "$92\\times5-(100+99+98+97)=66$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Thursday " } ], [ { "aoVal": "B", "content": "Saturday " } ], [ { "aoVal": "C", "content": "Tuesday " } ], [ { "aoVal": "D", "content": "Wednesday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "Counting from April $$15$$, $$2011$$, after $30-15=15$ days it will be April $$30$$, $$2011$$. After $11$ days, it will be May $$11$$, $$2011$$. In total, there are $15+11=26$ days. $26\\div 7 =3R5$, which means May $$11$$, $$2011$$ was Wednesday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$216$$ " } ], [ { "aoVal": "B", "content": "$$3375$$ " } ], [ { "aoVal": "C", "content": "$$720$$ " } ], [ { "aoVal": "D", "content": "$$9600$$ " } ], [ { "aoVal": "E", "content": "$$1200$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Problems Involving Extreme Value" ]

[ "$180\\div12=15$ $15\\times15\\times15=3375$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "The $$6$$th day " } ], [ { "aoVal": "B", "content": "The $$7$$th day " } ], [ { "aoVal": "C", "content": "The $$8$$th day " } ], [ { "aoVal": "D", "content": "The $$9$$th day " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems" ]

[ "omitted " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$55km$$ " } ], [ { "aoVal": "B", "content": "$$145km$$ " } ], [ { "aoVal": "C", "content": "$$275km$$ " } ], [ { "aoVal": "D", "content": "$$420km$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road" ]

[ "$420-\\left( 55\\times5\\right)=420-275=145$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$40$$ " } ], [ { "aoVal": "B", "content": "$$25$$ " } ], [ { "aoVal": "C", "content": "$$50$$ " } ], [ { "aoVal": "D", "content": "$$36$$ " } ], [ { "aoVal": "E", "content": "$$44$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications" ]

[ "$6\\times4+4\\times2+3\\times6=50$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$9$$ " } ], [ { "aoVal": "B", "content": "$$1$$ " } ], [ { "aoVal": "C", "content": "$$6$$ " } ], [ { "aoVal": "D", "content": "$$5$$ " } ], [ { "aoVal": "E", "content": "$$8$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division->Simple Multiplication Applications" ]

[ "Moving up $3$ times is $6$ steps. Now she is on the third step, after moving up $6$ steps, she is on the ninth step. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Wednesday " } ], [ { "aoVal": "B", "content": "Thursday " } ], [ { "aoVal": "C", "content": "Friday " } ], [ { "aoVal": "D", "content": "Saturday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time->Period of Dates" ]

[ "$$86\\div 7=12\\cdots \\cdots 2$$． 2 days later will be Thursday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$6.66\\textbackslash\\%$ " } ], [ { "aoVal": "B", "content": "$5\\textbackslash\\%$ " } ], [ { "aoVal": "C", "content": "$6.25\\textbackslash\\%$ " } ], [ { "aoVal": "D", "content": "None of the above. " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages" ]

[ "Price before discount $=\\frac{100}{75}\\times\\textbackslash$2250=\\textbackslash$3000$ Original price of the couch before increase $=\\textbackslash$3000-\\textbackslash$600=\\textbackslash$2400$ Price decrease $=\\textbackslash$2400-\\textbackslash$2250=\\textbackslash$150$ Percentage decrease $=\\frac{\\textbackslash$150}{\\textbackslash$2400}\\times100\\textbackslash\\%=6.25\\textbackslash\\%$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$9$$ " } ], [ { "aoVal": "B", "content": "$$10$$ " } ], [ { "aoVal": "C", "content": "$$11$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "$$4+7-1=10$$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "＄$$426$$ " } ], [ { "aoVal": "B", "content": "＄$$426.3$$ " } ], [ { "aoVal": "C", "content": "＄$$4,263$$ " } ], [ { "aoVal": "D", "content": "＄$$4,263.6$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Interest Problems" ]

[ "$$7000\\times \\left( 1+3\\textbackslash\\% \\right)\\times \\left( 1+3\\textbackslash\\% \\right)-7000=426.3$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "＄$$22$$ " } ], [ { "aoVal": "B", "content": "＄$$33$$ " } ], [ { "aoVal": "C", "content": "＄$$35$$ " } ], [ { "aoVal": "D", "content": "＄$$44$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Basic Profit and Loss Concepts" ]

[ "$$22+11=33$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$2620\\text{g}$$ " } ], [ { "aoVal": "B", "content": "$$3270\\text{g}$$ " } ], [ { "aoVal": "C", "content": "$$3840\\text{g}$$ " } ], [ { "aoVal": "D", "content": "$$4100\\text{g}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Including and Excluding " ]

[ "The almanac, the dictionary, the biography, and the cookbook together weigh $$4310\\text{g}+2325\\text{g=6635g}$$. Since the almanac and the biography together weigh $$2795\\text{g}$$, the cookbook and the dictionary together weigh $$6635\\text{g}-2795\\text{g=3840g}$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$20$$ " } ], [ { "aoVal": "B", "content": "$$32$$ " } ], [ { "aoVal": "C", "content": "$$40$$ " } ], [ { "aoVal": "D", "content": "$$52$$ " } ], [ { "aoVal": "E", "content": "$$60$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base" ]

[ "$72\\times(1-\\dfrac{4}{9})=32$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$$$Tuesday " } ], [ { "aoVal": "B", "content": "$$$$Thursday " } ], [ { "aoVal": "C", "content": "$$$$Saturday " } ], [ { "aoVal": "D", "content": "$$$$Sunday " } ], [ { "aoVal": "E", "content": "$$$$Monday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Snail Climbing out of Well Problems->Snail Climbing out of Well (completed)" ]

[ "Except the last day, the snail could climb up $2-1=1$ m. Thus, it takes the snail $(10-2)\\div1+1=9$ days to get out of the well. $9$ days from Monday is the next Tuesday. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$22\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$24\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$25\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$$30\\textbackslash\\%$$ " } ], [ { "aoVal": "E", "content": "$$33\\frac{1}{3}\\textbackslash\\%$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Concentration Problems->Basic Concentration Problems" ]

[ "Let $$a$$ be the original number of ounces of acid and $$w$$ be the original number of ounces of water. We can write two equations $$\\frac{a}{a+w+1}=\\frac{1}{5}$$ and $$\\frac{a+1}{a+w+2}=\\frac{1}{3}$$. Then cross-multiply to get rid of the fractions. $$5a=a+w+1$$, $$3a+3=a+w+1$$ Solve the system to get $$a=1$$ and $$w=3$$. The percentage of acid in the original mixture is $$\\frac{1}{1+3}=25 \\textbackslash\\% $$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$65$$ " } ], [ { "aoVal": "B", "content": "$$70$$ " } ], [ { "aoVal": "C", "content": "$$78$$ " } ], [ { "aoVal": "D", "content": "$$84$$ " } ], [ { "aoVal": "E", "content": "$$96$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "$(5 + 1 + 8) \\times (5 +1) = 84$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$40\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$42.5\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$57.5\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$$62.5\\textbackslash\\%$$ " } ], [ { "aoVal": "E", "content": "$$70\\textbackslash\\%$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$75 \\textbackslash\\% \\cdot 50\\textbackslash\\% =37.5\\textbackslash\\%$ $1 -37.5\\textbackslash\\% = 62.5\\textbackslash\\%$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$50$$ " } ], [ { "aoVal": "B", "content": "$$60$$ " } ], [ { "aoVal": "C", "content": "$$80$$ " } ], [ { "aoVal": "D", "content": "$$90$$ " } ], [ { "aoVal": "E", "content": "$$100$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Work Word Problems->Collaborative Work Word Problems" ]

[ "In $$600$$ seconds ($$10$$ minutes), James will frost $$\\dfrac{600}{12}=50$$ cookies, and Lacey will frost $$\\dfrac{600}{15}=40$$ cookies. Therefore, working together they will frost $$50+40=\\boxed{(\\text{D})90}$$ cookies. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$800$$ " } ], [ { "aoVal": "B", "content": "$$5$$ " } ], [ { "aoVal": "C", "content": "$$1280$$ " } ], [ { "aoVal": "D", "content": "$$96$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "$$80\\times 16 = 1280$$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$90$$ " } ], [ { "aoVal": "B", "content": "$$99$$ " } ], [ { "aoVal": "C", "content": "$$100$$ " } ], [ { "aoVal": "D", "content": "$$101$$ " } ], [ { "aoVal": "E", "content": "$$110$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "In a rectangle with dimensions $10 \\times 10$, the new rectangle would have dimensions $11 \\times 9$. The ratio of the new area to the old area is $99 / 100=(\\text{B}) 99$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$\\textbackslash$315$$, $$\\textbackslash$90$$ " } ], [ { "aoVal": "B", "content": "$$\\textbackslash$320$$, $$\\textbackslash$100$$ " } ], [ { "aoVal": "C", "content": "$$\\textbackslash$330$$, $$\\textbackslash$120$$ " } ], [ { "aoVal": "D", "content": "$$\\textbackslash$350$$, $$\\textbackslash$200$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Complex Ratio Problems" ]

[ "The price difference between the two goods did not change. Before $\\to$ $$A:B:Difference$$ is $$7:2:5$$ After $\\to$ $$A:B:Difference$$ is $$5:2:3$$ $\\textasciitilde$ Make difference the same number of units in both ratios by finding LCM. Before $\\to$ $$A:B:Difference$$ is $$21:6:15$$ After $\\to$ $$A:B:Difference$$ is $$25:10:15$$ $\\textasciitilde$ Therefore, $$4u=\\textbackslash$60$$ $$1u=$$ $$\\textbackslash$60\\div4=\\textbackslash$15$$ $\\textasciitilde$ The original prices of these two goods were $$A=21u=21\\times15=\\textbackslash$315$$ and $$B=6u=6\\times15=\\textbackslash$90$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$48$$ " } ], [ { "aoVal": "B", "content": "$$49$$ " } ], [ { "aoVal": "C", "content": "$$50$$ " } ], [ { "aoVal": "D", "content": "$$51$$ " } ], [ { "aoVal": "E", "content": "$$52$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Problems Involving Queuing->Finding the Total Number According to the Position of Two Characters in a Line" ]

[ "$17 + 34 - 1 = 50$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$2\\textbackslash\\%$$; $$8\\textbackslash\\%$$. " } ], [ { "aoVal": "B", "content": "$$3\\textbackslash\\%$$; $$7\\textbackslash\\%$$. " } ], [ { "aoVal": "C", "content": "$$4\\textbackslash\\%$$; $$6\\textbackslash\\%$$. " } ], [ { "aoVal": "D", "content": "$$5\\textbackslash\\%$$; $$5\\textbackslash\\%$$. " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Word Problems in Economics->Interest Problems" ]

[ "Let $$x$$ be the interest rate of bank $$A$$: $$7000x+3000(10\\textbackslash\\%-x)=460$$ $$x=4\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$425$$ cm " } ], [ { "aoVal": "B", "content": "$$432$$ cm " } ], [ { "aoVal": "C", "content": "$$456$$ cm " } ], [ { "aoVal": "D", "content": "$$478$$ cm " } ], [ { "aoVal": "E", "content": "$$480$$ cm " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "$25\\times10+(25+1)\\times7=432$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$90$$ miles " } ], [ { "aoVal": "B", "content": "$$120$$ miles " } ], [ { "aoVal": "C", "content": "$$150$$ miles " } ], [ { "aoVal": "D", "content": "$$160$$ miles " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Ratio Word Problems with an Invariant Part" ]

[ "Since $$12 \\div \\frac{3}{4}=16$$, the actual distance between the towns is $$16\\times10 = 160$$ miles. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "on the $2$\\textsuperscript{nd} floor " } ], [ { "aoVal": "B", "content": "on the $3$\\textsuperscript{rd} floor " } ], [ { "aoVal": "C", "content": "on the $4$\\textsuperscript{th} floor " } ], [ { "aoVal": "D", "content": "on the $5$\\textsuperscript{th} floor " } ], [ { "aoVal": "E", "content": "on the $6$\\textsuperscript{th} floor " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Interval Problems" ]

[ "Gawel lives on the second floor, so he only needs to walk up one floor. Pawel has to walk up twice as many stairs as Gawel, so he needs to walk up two floors. So, Pawel lives on the $3$\\textsuperscript{rd} floor. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "None　 " } ], [ { "aoVal": "B", "content": "$$\\frac{1}{2}$$ " } ], [ { "aoVal": "C", "content": "$$\\frac{1}{3}$$ " } ], [ { "aoVal": "D", "content": "$$\\frac{2}{3}$$ " } ], [ { "aoVal": "E", "content": "$$\\frac{1}{6}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Understanding the Base" ]

[ "After I eat one half, half of the apple pie is left. Eating two thirds of this half leaves one third of one half of the pie, which is one sixth, for Monday. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$54\\text{cm}$$ " } ], [ { "aoVal": "B", "content": "$$49\\text{cm}$$ " } ], [ { "aoVal": "C", "content": "$$64\\text{cm}$$ " } ], [ { "aoVal": "D", "content": "$$65\\text{cm}$$ " } ], [ { "aoVal": "E", "content": "$$66\\text{cm}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction" ]

[ "$$35+29=64$$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$6$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$8$ " } ], [ { "aoVal": "E", "content": "$$10$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis" ]

[ "$$12\\times2=24$$ $$8-2=6$$ $$66-24=42$$ $$42\\div6=7$$ " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$46$$ " } ], [ { "aoVal": "B", "content": "$$20$$ " } ], [ { "aoVal": "C", "content": "$$40$$ " } ], [ { "aoVal": "D", "content": "$$38$$ " } ], [ { "aoVal": "E", "content": "$$29$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Unitary Method with Two Variables" ]

[ "If we sum up the number of A and P, the result is 18. But if we sum up A and O, result is 28 instead. Hence, there must be 10 more O than P. Note that there are a total of 30 I and P. Therefore, there are (30+10)/2 = 20 Oranges. Total = 20+18=38. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$5$$ " } ], [ { "aoVal": "B", "content": "$$35$$ " } ], [ { "aoVal": "C", "content": "$$75$$ " } ], [ { "aoVal": "D", "content": "$133\\frac{1}{3}$ " } ], [ { "aoVal": "E", "content": "$$300$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Since $20 \\textbackslash\\%=\\frac{1}{5}$, multiplying the given condition by 5 shows that $y$ is $15 \\cdot 5=(\\mathbf{C}) 75$ percent of $x$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$90$$ miles " } ], [ { "aoVal": "B", "content": "$$120$$ miles " } ], [ { "aoVal": "C", "content": "$$150$$ miles " } ], [ { "aoVal": "D", "content": "$$160$$ miles " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Ratio Word Problems with an Invariant Part" ]

[ "Since $$12 \\div \\frac{3}{4}=16$$, the actual distance between the towns is $$16\\times10 = 160$$ miles. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$80$$ " } ], [ { "aoVal": "B", "content": "$$76$$ " } ], [ { "aoVal": "C", "content": "$$73$$ " } ], [ { "aoVal": "D", "content": "$$63$$ " } ], [ { "aoVal": "E", "content": "$$56$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "There are $0+5+2+10=17$ points more than the average, so the last score is $80-17=63$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$43\\frac 7{11}$ minutes " } ], [ { "aoVal": "B", "content": "$10\\frac {10}{11}$ minutes " } ], [ { "aoVal": "C", "content": "$21\\frac 9{11}$ minutes " } ], [ { "aoVal": "D", "content": "$22\\frac 9{11}$ minutes " } ], [ { "aoVal": "E", "content": "$42\\frac 7{11}$ minutes " } ] ]

[ "Overseas Competition->Knowledge Point->Distance Word Problems->Clock Problems" ]

[ "$(30\\times 4)\\div (6-0.5)=120\\div 5.5=\\frac {240}{11}=21\\frac 9{11}$ minutes. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$89$$ " } ], [ { "aoVal": "B", "content": "$$92$$ " } ], [ { "aoVal": "C", "content": "$$93$$ " } ], [ { "aoVal": "D", "content": "$$96$$ " } ], [ { "aoVal": "E", "content": "$$98$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "Assume the total amount of problems is 100 per half homework assignment, since we are dealing with percentages, and not values. Then, we know that Chloe got 80 problems correct by herself, and got 176 problems correct overall. We also know that Zoe had 90 problems she did correct alone. We can see that the total amount of correct problems Chloe and Zoe did was $176-80=96$. Therefore Zoe has $96+90=186$ problems out of 200 problems correct. This is (C) $93$ percent. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$14$$ " } ], [ { "aoVal": "B", "content": "$$16$$ " } ], [ { "aoVal": "C", "content": "$$18$$ " } ], [ { "aoVal": "D", "content": "$$20$$ " } ], [ { "aoVal": "E", "content": "$$36$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable" ]

[ "$(1-\\frac19)\\div2=\\frac49$, $\\frac49-\\frac19=\\frac13$, $12\\div\\frac13=36$, $36\\times\\frac49=16$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$2$$ " } ], [ { "aoVal": "B", "content": "$$3$$ " } ], [ { "aoVal": "C", "content": "$$4$$ " } ], [ { "aoVal": "D", "content": "$$5$$ " } ], [ { "aoVal": "E", "content": "None of the above. " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction->Simple Addition and Subtraction" ]

[ "total number of duck and ducklings in the queue is 6+(8-1) = 13. if 2 ducklings at the back moved away, it would be 13-2=11 in the queue, and the middle ducking would be 6th from the front, which is Joey\\textquotesingle s position. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$6$$ " } ], [ { "aoVal": "B", "content": "$$8$$ " } ], [ { "aoVal": "C", "content": "$$10$$ " } ], [ { "aoVal": "D", "content": "$$12$$ " } ], [ { "aoVal": "E", "content": "$$18$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Applying Multiplication and Division" ]

[ "Sam sings $$2$$ songs in the time that Robyn swims $$9$$ lengths. The time that she takes for $$54$$ lengths is $$54\\div9 =6$$ times longer, so Sam will sing $$2\\times6 =12$$ songs. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Tuesday " } ], [ { "aoVal": "B", "content": "Wednesday " } ], [ { "aoVal": "C", "content": "Thursday " } ], [ { "aoVal": "D", "content": "Friday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "Today is Wednesday. $$21$$ days ago was Wednesday. $$22$$ days ago was Tuesday. $\\textasciitilde$ or $\\textasciitilde$ $$22\\div7=3$$ weeks $$1$$ day. $$1$$ day before Wednesday was a Tuesday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$x+2$ " } ], [ { "aoVal": "B", "content": "$5x+2$ " } ], [ { "aoVal": "C", "content": "$5x+1$ " } ], [ { "aoVal": "D", "content": "$5x-1$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems" ]

[ "The boba that John drinks during weekdays: $$5x$$ The boba that John drinks during weekends: $$2\\times 1 =2$$ The total boba that John drinks during a week: $$5x+2$$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$16$$ years " } ], [ { "aoVal": "B", "content": "$$20$$ years " } ], [ { "aoVal": "C", "content": "$$24$$ years " } ], [ { "aoVal": "D", "content": "$$36$$ years " } ], [ { "aoVal": "E", "content": "$$42$$ years " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Basic Relationships in Age Problems" ]

[ "Let Herbie\\textquotesingle s age this year be $$h$$ years. Then Gareth\\textquotesingle s age this year is $$7h$$ years. In $$6$$ years\\textquotesingle{} time, their ages will be $$h+6$$ years and $$7h+6$$ years respectively. We are told that $$7h+6=$$$$4$$$$\\left(h+6\\right)$$. This gives $$7h+6=4h+24$$ so that $$3h=18$$ and $$h=6$$. So the present ages are $$6$$ and $$7\\times 6=42$$, giving a difference of $$36$$ years. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$38$$ " } ], [ { "aoVal": "B", "content": "$$45$$ " } ], [ { "aoVal": "C", "content": "$$49$$ " } ], [ { "aoVal": "D", "content": "$$52$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Newton's Problem of Cows and Fields" ]

[ "$17\\times30=510$ $19\\times 24=456$ $510-456=54$ $54\\div(30-24)=9$ $510-30\\times9=240$ $240+6\\times9=294$ $294\\div 6=49$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Tuesday " } ], [ { "aoVal": "B", "content": "Thursday " } ], [ { "aoVal": "C", "content": "Friday " } ], [ { "aoVal": "D", "content": "Saturday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "There are seven days in a week; so, in order to have five Fridays, a month has at least $$4\\times7+1=29$$ days. Since February has at most $$29$$ days, the $$1^{\\rm st}$$ and $$29^{\\rm th}$$ days of this February must both be Fridays, which means that January $$31$$ is a Thursday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$5$ " } ], [ { "aoVal": "B", "content": "$6$ " } ], [ { "aoVal": "C", "content": "$7$ " } ], [ { "aoVal": "D", "content": "$8$ " } ], [ { "aoVal": "E", "content": "$9$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction" ]

[ "It comes $4+4=8$ when we count Amy twice. The number of all singing students is $4+4-1=7$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$7\\textbackslash\\%$ " } ], [ { "aoVal": "B", "content": "$10\\textbackslash\\%$ " } ], [ { "aoVal": "C", "content": "$12\\textbackslash\\%$ " } ], [ { "aoVal": "D", "content": "$15\\textbackslash\\%$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Rate" ]

[ "Least percentage of pupils who participated in both basketball and football $=80\\textbackslash\\%+ 85\\textbackslash\\%-100\\textbackslash\\% =65\\textbackslash\\%$, Least percentage of pupils who participated in basketball, football and softball $=65\\textbackslash\\%+74\\textbackslash\\%-100\\textbackslash\\% =39\\textbackslash\\%$, Least percentage of pupils who participated in basketball, football, softball and squash $=39\\textbackslash\\%+ 68\\textbackslash\\%-100\\textbackslash\\% = 7\\textbackslash\\%$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Monday　 " } ], [ { "aoVal": "B", "content": "Tuesday　 " } ], [ { "aoVal": "C", "content": "Wednesday　 " } ], [ { "aoVal": "D", "content": "Thursday　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$$6$$ days ago was a Tuesday. Today is Monday. Thus, in $$8$$ days\\textquotesingle{} time, it will be a Tuesday. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$\\text{K}$$ " } ], [ { "aoVal": "B", "content": "$$\\text{N}$$ " } ], [ { "aoVal": "C", "content": "$$\\text{G}$$ " } ], [ { "aoVal": "D", "content": "$$\\text{R}$$ " } ], [ { "aoVal": "E", "content": "$$\\text{O}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation" ]

[ "The sequence $$\\text{KANGAROOKANGAROOKANG}\\cdots$$ repeats every $$8$$ letters. Since $$2017=8\\times252+1$$, the $$2017\\text{th}$$ letter in the sequence is the first of the repeating sequence and hence is $$\\text{K}$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$30$$ and $$20$$ " } ], [ { "aoVal": "B", "content": "$$20$$ and $$30$$ " } ], [ { "aoVal": "C", "content": "$$18$$ and $$12$$ " } ], [ { "aoVal": "D", "content": "$$12$$ and $$18$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units" ]

[ "According to the ratio $$3:2$$, we could know the total is $$5$$. Then the number of boys is $$30\\times \\dfrac{3}{5} =18$$.The number of girls is $$30\\times\\dfrac{2}{5}=12$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$48$$ " } ], [ { "aoVal": "B", "content": "$$49$$ " } ], [ { "aoVal": "C", "content": "$$50$$ " } ], [ { "aoVal": "D", "content": "$$51$$ " } ], [ { "aoVal": "E", "content": "$$52$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Complex Ratio Problems" ]

[ "First we must work out the number of tickets of each colour. Let the numbers of red, white and blue tickets be $$r$$, $$w$$ and b respectively; we have $$r : w = 5 : 4$$ and $$w : b = 8 : 7$$. Writing $$r : w$$ as $$10 : 8$$, we can combine the ratios to find $$r : w : b = 10 : 8 : 7$$. Hence for a total of $$100$$ tickets, there must be $$40$$ red, $$32$$ white and $$28$$ blue tickets. Now the largest number of red tickets one can select without having half of them is $$19$$, and likewise $$15$$ and $$13$$ for white and blue tickets. So it would be possible to select $$19 + 15 + 13 = 47$$ tickets and still not have half or more of any particular colour of ticket. However, the very next ticket, the $$48\\text{th}$$, would have to be a red, a white or a blue one, and so one of the colours would now have at least half of its number selected. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "Friday " } ], [ { "aoVal": "B", "content": "Saturday " } ], [ { "aoVal": "C", "content": "Sunday " } ], [ { "aoVal": "D", "content": "Monday " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "40th day = 39th day after first day joining. 39 days/7 = 5 weeks R 4 days. 4 days after Tues is Saturday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$3$$ " } ], [ { "aoVal": "B", "content": "$$4$$ " } ], [ { "aoVal": "C", "content": "$$5$$ " } ], [ { "aoVal": "D", "content": "$$6$$ " } ], [ { "aoVal": "E", "content": "$$7$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems" ]

[ "NA " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$1:3$$ " } ], [ { "aoVal": "B", "content": "$$3:1 $$ " } ], [ { "aoVal": "C", "content": "$$1:4 $$ " } ], [ { "aoVal": "D", "content": "$$4:1$$ " } ], [ { "aoVal": "E", "content": "$$4:3$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Proportions->Basic Units" ]

[ "Julia has eaten one-quarters of the pizza. So three-quarter of the pizza remain. Therefore the required ratio is $$\\frac{3}{4}:\\frac{1}{4}=3:1$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$16$$ " } ], [ { "aoVal": "B", "content": "$$18$$ " } ], [ { "aoVal": "C", "content": "$$24$$ " } ], [ { "aoVal": "D", "content": "$$32$$ " } ], [ { "aoVal": "E", "content": "$$48$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "1-1/2-1/2*3/4=1/8，1/8means 6 bulbs，$$so$$ in total there are 6\\div 1/8=48 bulbs. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$250$$ " } ], [ { "aoVal": "B", "content": "$$375$$ " } ], [ { "aoVal": "C", "content": "$$90$$ " } ], [ { "aoVal": "D", "content": "$$60$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Base" ]

[ "He has $\\dfrac{3}{5}$~remaining after selling $\\dfrac{2}{5}$. We can write the equation as:~$150\\div\\dfrac{3}{5}=250$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$65$$ " } ], [ { "aoVal": "B", "content": "$$70$$ " } ], [ { "aoVal": "C", "content": "$$78$$ " } ], [ { "aoVal": "D", "content": "$$84$$ " } ], [ { "aoVal": "E", "content": "$$96$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules" ]

[ "There are $5+8+1=14$ players in each group. There are $14\\times 6=84$ players in total. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$14$$ " } ], [ { "aoVal": "B", "content": "$$18$$ " } ], [ { "aoVal": "C", "content": "$$20$$ " } ], [ { "aoVal": "D", "content": "$$21$$ " } ], [ { "aoVal": "E", "content": "$$22$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Equation Word Problems->Word Problems for Linear Equations with One Variable" ]

[ "Let the number of birds remaining in each tree be $$x$$. Therefore $$x+6+x+8+x+4= 60$$, which has solution $$x=14$$. Hence the number of birds originally perched in the second tree is $$14 + 8 = 22$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$120\\rm{kg}$$ " } ], [ { "aoVal": "B", "content": "$$150\\rm{kg}$$ " } ], [ { "aoVal": "C", "content": "$$165\\rm{kg}$$ " } ], [ { "aoVal": "D", "content": "$$210\\rm{kg}$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Applying Addition and Subtraction" ]

[ "T + 200L = 350kg $\\cdots $ ① -) T + 150L = 315kg $\\cdots $ ② \\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_ (50L = 35kg) x3 = 150L = 105kg 315kg - 105kg = 210kg " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$20$; $12$ " } ], [ { "aoVal": "B", "content": "$22$; $20$ " } ], [ { "aoVal": "C", "content": "$20$; $24$ " } ], [ { "aoVal": "D", "content": "$19$; $21$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Chicken-Rabbit Problems->Solving Chicken-Rabbit Problems by Using Hypothesis" ]

[ "Suppose all the animals in the cage are chickens: there should be $$2\\times 42=84$$ legs. However, $$124-84=40$$ legs are missing because we counted $$40\\div2=20$$ rabbits. Hence, there are $$20$$ rabbits and $$42-20=22$$ chickens. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$2\\text{m}$$ " } ], [ { "aoVal": "B", "content": "$$4\\text{m}$$ " } ], [ { "aoVal": "C", "content": "$$6\\text{m}$$ " } ], [ { "aoVal": "D", "content": "$$8\\text{m}$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Unitary Method Problems->Finding the Unit Rate and then the Total Value" ]

[ "The string $$12$$ meters long is cut into $$6$$ pieces of length $$2\\text{m}$$. The sum of the lengths of any $$4$$ of these pieces is $$4\\times2\\text{m}=8\\text{m}$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$480$$ miles " } ], [ { "aoVal": "B", "content": "$$1080$$ miles " } ], [ { "aoVal": "C", "content": "$$960$$ miles " } ], [ { "aoVal": "D", "content": "$$720$$ miles " } ], [ { "aoVal": "E", "content": "$$1200$$ miles " } ] ]

[ "Overseas Competition->Knowledge Point->Distance Word Problems->Distance Word Problems on Straight Road" ]

[ "We set up an equation in terms of $d$ as the distance and $x$ as the speed in miles per day originally. We have $d=16x=24(x-20)$ $16x=24x-480$ $480=8x$ $x=60$ Thus, the distance between William\\textquotesingle s home and New York City is $60\\times16=960$ miles. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$200$$ " } ], [ { "aoVal": "B", "content": "$$140$$ " } ], [ { "aoVal": "C", "content": "$$210$$ " } ], [ { "aoVal": "D", "content": "$$180$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Questions Involving Sum, Difference and Multiples" ]

[ "E " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$24$$ " } ], [ { "aoVal": "B", "content": "$$48$$ " } ], [ { "aoVal": "C", "content": "$$72$$ " } ], [ { "aoVal": "D", "content": "$$96$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Sums and Multiples in Age Problems" ]

[ "The sum of Ben\\textquotesingle s age and Ben\\textquotesingle s grandma\\textquotesingle s age is $$96$$. Since grandma is three times older than Ben, on the number line, $96$ can be divided into $$4$$ portions, and each portion is $$96\\div(1+3)=24$$. Ben is $$24$$ years old, and grandma is three times older. $$24\\times 3=72$$ " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$5\\textbackslash\\%$$ " } ], [ { "aoVal": "B", "content": "$$10\\textbackslash\\%$$ " } ], [ { "aoVal": "C", "content": "$$20\\textbackslash\\%$$ " } ], [ { "aoVal": "D", "content": "$$40\\textbackslash\\%$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Finding the Rate" ]

[ "Five children divided some cake equally. Two of the children totally got $$\\dfrac{2}{5}$$ of the cake and $$\\dfrac{2}{5}=0.4 = 40\\textbackslash\\%$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Wednesday　 " } ], [ { "aoVal": "B", "content": "Thursday　 " } ], [ { "aoVal": "C", "content": "Friday　 " } ], [ { "aoVal": "D", "content": "Saturday　 " } ], [ { "aoVal": "E", "content": "Sunday　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$$30\\div4=7 \\text{ R } 2$$, two days after a Thursday is a Saturday. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$15$$ " } ], [ { "aoVal": "B", "content": "$$10$$ " } ], [ { "aoVal": "C", "content": "$$9$$ " } ], [ { "aoVal": "D", "content": "$$20$$ " } ], [ { "aoVal": "E", "content": "$$23$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "Every boy picks $$30-26=4$$ more than the average, so boys pick $$4\\times 15=60$$ more in total, which is equal to the number that girls picked less than the average in total. Every girl picks $$26-20=6$$ less than the average, so there are $$60\\div 6=10$$ girls. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Sunday　 " } ], [ { "aoVal": "B", "content": "Monday　 " } ], [ { "aoVal": "C", "content": "Wednesday　 " } ], [ { "aoVal": "D", "content": "Friday " } ], [ { "aoVal": "E", "content": "Saturday　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "We can count backward by days or by weeks. There are 9 days in between, that means 1 week and 2 days. Then count a few days back to find that $$1$$\\textsuperscript{st} June is a Friday. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$$40$$ " } ], [ { "aoVal": "B", "content": "$$60$$ " } ], [ { "aoVal": "C", "content": "$$80$$ " } ], [ { "aoVal": "D", "content": "$$100$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Percentages Word Problems" ]

[ "$$200\\times \\left( 1-\\frac{1}{10}-\\frac{1}{5}-25 \\textbackslash\\% -15 \\textbackslash\\% ~\\right)=60$$. " ]

"2023-07-07T00:00:00"

[ "其它" ]

[ [ { "aoVal": "A", "content": "$36$ kilograms " } ], [ { "aoVal": "B", "content": "$38$ kilograms " } ], [ { "aoVal": "C", "content": "$40$ kilograms " } ], [ { "aoVal": "D", "content": "$43$ kilograms " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Average Problems " ]

[ "$4 \\times 37 + 11 \\times 41+ 161 = 760$ kilograms in total. $760 \\div (4 + 11 + 5) = 38$ kg. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Both have the same amount of pocket money now. " } ], [ { "aoVal": "B", "content": "John has more pocket money now. " } ], [ { "aoVal": "C", "content": "Mary has more pocket money now. " } ], [ { "aoVal": "D", "content": "It is impossible to tell who has more pocket money now. " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Solving Problems Involving Fractions and Percentages->Knowing the Base" ]

[ "Statement $$\\text{A}$$ is correct. In the amount of pocket money that each has be $$x$$. In $$2007$$, John has $$1.1\\times0.9x=0.99x$$ while Mary has $$0.9\\times1.1x=0.99x$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Monday " } ], [ { "aoVal": "B", "content": "Tuesday " } ], [ { "aoVal": "C", "content": "Wednesday " } ], [ { "aoVal": "D", "content": "Thursday " } ], [ { "aoVal": "E", "content": "Friday " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Newton's Problem of Cows and Fields->Basic Newton's Problem of Cows and Fields->Finding the Number of Days" ]

[ "NA " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$280$$ " } ], [ { "aoVal": "B", "content": "$$284$$ " } ], [ { "aoVal": "C", "content": "$$288$$ " } ], [ { "aoVal": "D", "content": "$$292$$ " } ], [ { "aoVal": "E", "content": "None of the above " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Basic Permutation" ]

[ "Amount of food fed to the cattle follows the pattern: $789756$~ ~ $$789756$$~ ~ $789756$~ ~ $789756\\cdots\\cdots$ Total amount of food fed in the first $6$ days$=42 \\text{kg}$. $2018 =48\\times6+1= 289$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$4$$ " } ], [ { "aoVal": "B", "content": "$$5$$ " } ], [ { "aoVal": "C", "content": "$$7$$ " } ], [ { "aoVal": "D", "content": "$$13$$ " } ], [ { "aoVal": "E", "content": "$$14$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Age Problems->Basic Relationships in Age Problems->Difference of Ages" ]

[ "Emily was $$6$$ years old last year , which means Emily is $7$ years old this year. Her sister was~ $$6$$ years old six years ago, which tells us her sister is~ $12$ years old this year, so the age difference is $5$ today. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "$$0$$ " } ], [ { "aoVal": "B", "content": "$$2$$ " } ], [ { "aoVal": "C", "content": "$$4$$ " } ], [ { "aoVal": "D", "content": "$$8$$ " } ] ]

[ "Overseas Competition->Knowledge Point->Number Theory Modules->Division without Remainders->Applying the Properties of Dividing without Remainders->Maximum/Minimum Problems of Division without Remainders " ]

[ "The ones\\textquotesingle{} digits repeat in groups of four: $$2$$, $$4$$, $$8$$, $$6$$, $$2$$, $$4$$, $$8$$, $$6$$, $$\\cdots $$. The ones\\textquotesingle{} digits of $$2^{48}$$, $$2^{49}$$, $$2\\%{50}$$ are $$6$$, $$2$$, $$4$$. " ]

"2023-07-07T00:00:00"

[]

[ [ { "aoVal": "A", "content": "Monday　 " } ], [ { "aoVal": "B", "content": "Tuesday　 " } ], [ { "aoVal": "C", "content": "Wednesday　 " } ], [ { "aoVal": "D", "content": "Thursday　 " } ] ]

[ "Overseas Competition->Knowledge Point->Word Problem Modules->Periodic Problems->Periodic Problems of Time" ]

[ "$$6$$ days ago was Tues. Today is Mon. In $$8$$ days it will be Tues. " ]