bug_id
stringlengths 1
3
| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
19 | daf316e556bc9fa1edf1e578a18f27a34f9954866d4f48e7b9f3fa47dacaf86f | private void checkParameters() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Checks dimensions and values of boundaries and inputSigma if defined.
*/
private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(boundaries[1][i] - boundaries[0][i])) {
final double max = Double.MAX_VALUE + boundaries[0][i];
final NumberIsTooLargeException e
= new NumberIsTooLargeException(boundaries[1][i],
max,
true);
e.getContext().addMessage(LocalizedFormats.OVERFLOW);
e.getContext().addMessage(LocalizedFormats.INDEX, i);
throw e;
}
}
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
}
```
| private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(boundaries[1][i] - boundaries[0][i])) {
final double max = Double.MAX_VALUE + boundaries[0][i];
final NumberIsTooLargeException e
= new NumberIsTooLargeException(boundaries[1][i],
max,
true);
e.getContext().addMessage(LocalizedFormats.OVERFLOW);
e.getContext().addMessage(LocalizedFormats.INDEX, i);
throw e;
}
}
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Checks dimensions and values of boundaries and inputSigma if defined.
*/
private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(boundaries[1][i] - boundaries[0][i])) {
final double max = Double.MAX_VALUE + boundaries[0][i];
final NumberIsTooLargeException e
= new NumberIsTooLargeException(boundaries[1][i],
max,
true);
e.getContext().addMessage(LocalizedFormats.OVERFLOW);
e.getContext().addMessage(LocalizedFormats.INDEX, i);
throw e;
}
}
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
85 | dafda8acabb2c718b8f9f2b40f5f9796b428e73b99892656d910bea0f2801c7e | public Attribute(String key, String val, Attributes parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a new attribute from unencoded (raw) key and value.
* @param key attribute key; case is preserved.
* @param val attribute value
* @param parent the containing Attributes (this Attribute is not automatically added to said Attributes)
* @see #createFromEncoded*/
public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.key = key;
this.val = val;
this.parent = parent;
}
```
| public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.key = key;
this.val = val;
this.parent = parent;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a new attribute from unencoded (raw) key and value.
* @param key attribute key; case is preserved.
* @param val attribute value
* @param parent the containing Attributes (this Attribute is not automatically added to said Attributes)
* @see #createFromEncoded*/
public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.key = key;
this.val = val;
this.parent = parent;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | db16514a894644621a4d0d52b42c65f335e097205b4d762698dcef1b6de4ca3d | void add(String newcode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void add(String newcode) {
maybeEndStatement();
if (newcode.length() == 0) {
return;
}
char c = newcode.charAt(0);
if ((isWordChar(c) || c == '\\') &&
isWordChar(getLastChar())) {
// need space to separate. This is not pretty printing.
// For example: "return foo;"
append(" ");
// Do not allow a forward slash to appear after a DIV.
// For example,
// REGEXP DIV REGEXP
// is valid and should print like
// / // / /
}
append(newcode);
}
```
| void add(String newcode) {
maybeEndStatement();
if (newcode.length() == 0) {
return;
}
char c = newcode.charAt(0);
if ((isWordChar(c) || c == '\\') &&
isWordChar(getLastChar())) {
// need space to separate. This is not pretty printing.
// For example: "return foo;"
append(" ");
// Do not allow a forward slash to appear after a DIV.
// For example,
// REGEXP DIV REGEXP
// is valid and should print like
// / // / /
}
append(newcode);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void add(String newcode) {
maybeEndStatement();
if (newcode.length() == 0) {
return;
}
char c = newcode.charAt(0);
if ((isWordChar(c) || c == '\\') &&
isWordChar(getLastChar())) {
// need space to separate. This is not pretty printing.
// For example: "return foo;"
append(" ");
// Do not allow a forward slash to appear after a DIV.
// For example,
// REGEXP DIV REGEXP
// is valid and should print like
// / // / /
}
append(newcode);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | db619423627f76b2cbf51f671b93a9ac519a704c8bafa710b94f040caf3a739a | static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
// some charsets can read but not encode; switch to an encodable charset and update the meta el
}
input.close();
return doc;
}
```
| static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
// some charsets can read but not encode; switch to an encodable charset and update the meta el
}
input.close();
return doc;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static Document parseInputStream(InputStream input, String charsetName, String baseUri, Parser parser) throws IOException {
if (input == null) // empty body
return new Document(baseUri);
input = ConstrainableInputStream.wrap(input, bufferSize, 0);
Document doc = null;
boolean fullyRead = false;
// read the start of the stream and look for a BOM or meta charset
input.mark(bufferSize);
ByteBuffer firstBytes = readToByteBuffer(input, firstReadBufferSize - 1); // -1 because we read one more to see if completed. First read is < buffer size, so can't be invalid.
fullyRead = input.read() == -1;
input.reset();
// look for BOM - overrides any other header or input
BomCharset bomCharset = detectCharsetFromBom(firstBytes);
if (bomCharset != null)
charsetName = bomCharset.charset;
if (charsetName == null) { // determine from meta. safe first parse as UTF-8
String docData = Charset.forName(defaultCharset).decode(firstBytes).toString();
doc = parser.parseInput(docData, baseUri);
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
Elements metaElements = doc.select("meta[http-equiv=content-type], meta[charset]");
String foundCharset = null; // if not found, will keep utf-8 as best attempt
for (Element meta : metaElements) {
if (meta.hasAttr("http-equiv"))
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset"))
foundCharset = meta.attr("charset");
if (foundCharset != null)
break;
}
// look for <?xml encoding='ISO-8859-1'?>
if (foundCharset == null && doc.childNodeSize() > 0) {
Node first = doc.childNode(0);
XmlDeclaration decl = null;
if (first instanceof XmlDeclaration)
decl = (XmlDeclaration) first;
else if (first instanceof Comment) {
Comment comment = (Comment) first;
if (comment.isXmlDeclaration())
decl = comment.asXmlDeclaration();
}
if (decl != null) {
if (decl.name().equalsIgnoreCase("xml"))
foundCharset = decl.attr("encoding");
}
}
foundCharset = validateCharset(foundCharset);
if (foundCharset != null && !foundCharset.equalsIgnoreCase(defaultCharset)) { // need to re-decode. (case insensitive check here to match how validate works)
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
doc = null;
} else if (!fullyRead) {
doc = null;
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
}
if (doc == null) {
if (charsetName == null)
charsetName = defaultCharset;
BufferedReader reader = new BufferedReader(new InputStreamReader(input, charsetName), bufferSize);
if (bomCharset != null && bomCharset.offset) // creating the buffered reader ignores the input pos, so must skip here
reader.skip(1);
try {
doc = parser.parseInput(reader, baseUri);
} catch (UncheckedIOException e) {
// io exception when parsing (not seen before because reading the stream as we go)
throw e.ioException();
}
Charset charset = Charset.forName(charsetName);
doc.outputSettings().charset(charset);
// some charsets can read but not encode; switch to an encodable charset and update the meta el
}
input.close();
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
114 | db725590a7a2c3908189146cd3cd25d45ac24be8b6751cbc776c697712cf97d9 | private void recordAssignment(NodeTraversal t, Node n, Node recordNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void recordAssignment(NodeTraversal t, Node n, Node recordNode) {
Node nameNode = n.getFirstChild();
Node parent = n.getParent();
NameInformation ns = createNameInformation(t, nameNode);
if (ns != null) {
if (parent.isFor() && !NodeUtil.isForIn(parent)) {
// Patch for assignments that appear in the init,
// condition or iteration part of a FOR loop. Without
// this change, all 3 of those parts try to claim the for
// loop as their dependency scope. The last assignment in
// those three fields wins, which can result in incorrect
// reference edges between referenced and assigned variables.
//
// TODO(user) revisit the dependency scope calculation
// logic.
if (parent.getFirstChild().getNext() != n) {
recordDepScope(recordNode, ns);
} else {
recordDepScope(nameNode, ns);
}
} else {
// The rhs of the assignment is the caller, so it's used by the
// context. Don't associate it w/ the lhs.
// FYI: this fixes only the specific case where the assignment is the
// caller expression, but it could be nested deeper in the caller and
// we would still get a bug.
// See testAssignWithCall2 for an example of this.
recordDepScope(recordNode, ns);
}
}
}
```
| private void recordAssignment(NodeTraversal t, Node n, Node recordNode) {
Node nameNode = n.getFirstChild();
Node parent = n.getParent();
NameInformation ns = createNameInformation(t, nameNode);
if (ns != null) {
if (parent.isFor() && !NodeUtil.isForIn(parent)) {
// Patch for assignments that appear in the init,
// condition or iteration part of a FOR loop. Without
// this change, all 3 of those parts try to claim the for
// loop as their dependency scope. The last assignment in
// those three fields wins, which can result in incorrect
// reference edges between referenced and assigned variables.
//
// TODO(user) revisit the dependency scope calculation
// logic.
if (parent.getFirstChild().getNext() != n) {
recordDepScope(recordNode, ns);
} else {
recordDepScope(nameNode, ns);
}
} else {
// The rhs of the assignment is the caller, so it's used by the
// context. Don't associate it w/ the lhs.
// FYI: this fixes only the specific case where the assignment is the
// caller expression, but it could be nested deeper in the caller and
// we would still get a bug.
// See testAssignWithCall2 for an example of this.
recordDepScope(recordNode, ns);
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void recordAssignment(NodeTraversal t, Node n, Node recordNode) {
Node nameNode = n.getFirstChild();
Node parent = n.getParent();
NameInformation ns = createNameInformation(t, nameNode);
if (ns != null) {
if (parent.isFor() && !NodeUtil.isForIn(parent)) {
// Patch for assignments that appear in the init,
// condition or iteration part of a FOR loop. Without
// this change, all 3 of those parts try to claim the for
// loop as their dependency scope. The last assignment in
// those three fields wins, which can result in incorrect
// reference edges between referenced and assigned variables.
//
// TODO(user) revisit the dependency scope calculation
// logic.
if (parent.getFirstChild().getNext() != n) {
recordDepScope(recordNode, ns);
} else {
recordDepScope(nameNode, ns);
}
} else {
// The rhs of the assignment is the caller, so it's used by the
// context. Don't associate it w/ the lhs.
// FYI: this fixes only the specific case where the assignment is the
// caller expression, but it could be nested deeper in the caller and
// we would still get a bug.
// See testAssignWithCall2 for an example of this.
recordDepScope(recordNode, ns);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | db7703d65698d37ff407d3a22183c655c4b5048be282648ee3e0bd55719c825b | public void setSelected(Option option) throws AlreadySelectedException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Set the selected option of this group to <code>name</code>.
*
* @param option the option that is selected
* @throws AlreadySelectedException if an option from this group has
* already been selected.
*/
public void setSelected(Option option) throws AlreadySelectedException
{
if (option == null)
{
// reset the option previously selected
selected = null;
return;
}
// if no option has already been selected or the
// same option is being reselected then set the
// selected member variable
if (selected == null || selected.equals(option.getKey()))
{
selected = option.getKey();
}
else
{
throw new AlreadySelectedException(this, option);
}
}
```
| public void setSelected(Option option) throws AlreadySelectedException
{
if (option == null)
{
// reset the option previously selected
selected = null;
return;
}
// if no option has already been selected or the
// same option is being reselected then set the
// selected member variable
if (selected == null || selected.equals(option.getKey()))
{
selected = option.getKey();
}
else
{
throw new AlreadySelectedException(this, option);
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Set the selected option of this group to <code>name</code>.
*
* @param option the option that is selected
* @throws AlreadySelectedException if an option from this group has
* already been selected.
*/
public void setSelected(Option option) throws AlreadySelectedException
{
if (option == null)
{
// reset the option previously selected
selected = null;
return;
}
// if no option has already been selected or the
// same option is being reselected then set the
// selected member variable
if (selected == null || selected.equals(option.getKey()))
{
selected = option.getKey();
}
else
{
throw new AlreadySelectedException(this, option);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | dbb8b79b8b77886bed719781d20b1dfbf08b34939fd4656538ada3c5b70ab2af | public static Date parse(String date, ParsePosition pos) throws ParseException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse a date from ISO-8601 formatted string. It expects a format
* [yyyy-MM-dd|yyyyMMdd][T(hh:mm[:ss[.sss]]|hhmm[ss[.sss]])]?[Z|[+-]hh[:mm]]]
*
* @param date ISO string to parse in the appropriate format.
* @param pos The position to start parsing from, updated to where parsing stopped.
* @return the parsed date
* @throws ParseException if the date is not in the appropriate format
*/
/*
/**********************************************************
/* Parsing
/**********************************************************
*/
public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
}
```
| public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse a date from ISO-8601 formatted string. It expects a format
* [yyyy-MM-dd|yyyyMMdd][T(hh:mm[:ss[.sss]]|hhmm[ss[.sss]])]?[Z|[+-]hh[:mm]]]
*
* @param date ISO string to parse in the appropriate format.
* @param pos The position to start parsing from, updated to where parsing stopped.
* @return the parsed date
* @throws ParseException if the date is not in the appropriate format
*/
/*
/**********************************************************
/* Parsing
/**********************************************************
*/
public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | dbd8132b98986fb11be6ec8dbc448b368ac00fd0a4859377754c650b2ad31442 | private boolean isShortOption(String token)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
if (options.hasShortOption(optName))
{
return true;
}
// check for several concatenated short options
return optName.length() > 0 && options.hasShortOption(String.valueOf(optName.charAt(0)));
}
```
| private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
if (options.hasShortOption(optName))
{
return true;
}
// check for several concatenated short options
return optName.length() > 0 && options.hasShortOption(String.valueOf(optName.charAt(0)));
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
if (options.hasShortOption(optName))
{
return true;
}
// check for several concatenated short options
return optName.length() > 0 && options.hasShortOption(String.valueOf(optName.charAt(0)));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | dc4f6516136b3dde20b0d63f99c95df2b97640e9923e39a3c4fd440a6c59789d | public final boolean isEmptyType() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType() ||
(registry.getNativeFunctionType(
JSTypeNative.LEAST_FUNCTION_TYPE) == this);
}
```
| public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType() ||
(registry.getNativeFunctionType(
JSTypeNative.LEAST_FUNCTION_TYPE) == this);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType() ||
(registry.getNativeFunctionType(
JSTypeNative.LEAST_FUNCTION_TYPE) == this);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
65 | dcb6907b00acb0454cfe198143cd9c729f9794e90de4746c0dae1bab061c3c29 | static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Helper to escape javascript string as well as regular expression */
static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\0': sb.append("\\000"); break;
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c < 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
}
```
| static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\0': sb.append("\\000"); break;
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c < 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Helper to escape javascript string as well as regular expression */
static String strEscape(String s, char quote,
String doublequoteEscape,
String singlequoteEscape,
String backslashEscape,
CharsetEncoder outputCharsetEncoder) {
StringBuilder sb = new StringBuilder(s.length() + 2);
sb.append(quote);
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
switch (c) {
case '\0': sb.append("\\000"); break;
case '\n': sb.append("\\n"); break;
case '\r': sb.append("\\r"); break;
case '\t': sb.append("\\t"); break;
case '\\': sb.append(backslashEscape); break;
case '\"': sb.append(doublequoteEscape); break;
case '\'': sb.append(singlequoteEscape); break;
case '>': // Break --> into --\> or ]]> into ]]\>
if (i >= 2 &&
((s.charAt(i - 1) == '-' && s.charAt(i - 2) == '-') ||
(s.charAt(i - 1) == ']' && s.charAt(i - 2) == ']'))) {
sb.append("\\>");
} else {
sb.append(c);
}
break;
case '<':
// Break </script into <\/script
final String END_SCRIPT = "/script";
// Break <!-- into <\!--
final String START_COMMENT = "!--";
if (s.regionMatches(true, i + 1, END_SCRIPT, 0,
END_SCRIPT.length())) {
sb.append("<\\");
} else if (s.regionMatches(false, i + 1, START_COMMENT, 0,
START_COMMENT.length())) {
sb.append("<\\");
} else {
sb.append(c);
}
break;
default:
// If we're given an outputCharsetEncoder, then check if the
// character can be represented in this character set.
if (outputCharsetEncoder != null) {
if (outputCharsetEncoder.canEncode(c)) {
sb.append(c);
} else {
// Unicode-escape the character.
appendHexJavaScriptRepresentation(sb, c);
}
} else {
// No charsetEncoder provided - pass straight latin characters
// through, and escape the rest. Doing the explicit character
// check is measurably faster than using the CharsetEncoder.
if (c > 0x1f && c < 0x7f) {
sb.append(c);
} else {
// Other characters can be misinterpreted by some js parsers,
// or perhaps mangled by proxies along the way,
// so we play it safe and unicode escape them.
appendHexJavaScriptRepresentation(sb, c);
}
}
}
}
sb.append(quote);
return sb.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | dd506d107454c1db8b088a3e3cabf9856b7da2c3c2973f51e00ad735b0133ba9 | public String caverphone(String txt) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Encodes the given String into a Caverphone value.
*
* @param txt String the source string
* @return A caverphone code for the given String
*/
public String caverphone(String txt) {
// NOTE: Version 1.0 of Caverphone is easily derivable from this code
// by commenting out the 2.0 lines and adding in the 1.0 lines
if( txt == null || txt.length() == 0 ) {
return "1111111111";
}
// 1. Convert to lowercase
txt = txt.toLowerCase(java.util.Locale.ENGLISH);
// 2. Remove anything not A-Z
txt = txt.replaceAll("[^a-z]", "");
// 2.5. Remove final e
txt = txt.replaceAll("e$", ""); // 2.0 only
// 3. Handle various start options
txt = txt.replaceAll("^cough", "cou2f");
txt = txt.replaceAll("^rough", "rou2f");
txt = txt.replaceAll("^tough", "tou2f");
txt = txt.replaceAll("^enough", "enou2f"); // 2.0 only
txt = txt.replaceAll("^trough", "trou2f"); // 2.0 only - note the spec says ^enough here again, c+p error I assume
txt = txt.replaceAll("^gn", "2n");
// End
txt = txt.replaceAll("^mb", "m2");
// 4. Handle replacements
txt = txt.replaceAll("cq", "2q");
txt = txt.replaceAll("ci", "si");
txt = txt.replaceAll("ce", "se");
txt = txt.replaceAll("cy", "sy");
txt = txt.replaceAll("tch", "2ch");
txt = txt.replaceAll("c", "k");
txt = txt.replaceAll("q", "k");
txt = txt.replaceAll("x", "k");
txt = txt.replaceAll("v", "f");
txt = txt.replaceAll("dg", "2g");
txt = txt.replaceAll("tio", "sio");
txt = txt.replaceAll("tia", "sia");
txt = txt.replaceAll("d", "t");
txt = txt.replaceAll("ph", "fh");
txt = txt.replaceAll("b", "p");
txt = txt.replaceAll("sh", "s2");
txt = txt.replaceAll("z", "s");
txt = txt.replaceAll("^[aeiou]", "A");
txt = txt.replaceAll("[aeiou]", "3");
txt = txt.replaceAll("j", "y"); // 2.0 only
txt = txt.replaceAll("^y3", "Y3"); // 2.0 only
txt = txt.replaceAll("^y", "A"); // 2.0 only
txt = txt.replaceAll("y", "3"); // 2.0 only
txt = txt.replaceAll("3gh3", "3kh3");
txt = txt.replaceAll("gh", "22");
txt = txt.replaceAll("g", "k");
txt = txt.replaceAll("s+", "S");
txt = txt.replaceAll("t+", "T");
txt = txt.replaceAll("p+", "P");
txt = txt.replaceAll("k+", "K");
txt = txt.replaceAll("f+", "F");
txt = txt.replaceAll("m+", "M");
txt = txt.replaceAll("n+", "N");
txt = txt.replaceAll("w3", "W3");
//txt = txt.replaceAll("wy", "Wy"); // 1.0 only
txt = txt.replaceAll("wh3", "Wh3");
txt = txt.replaceAll("w$", "3"); // 2.0 only
//txt = txt.replaceAll("why", "Why"); // 1.0 only
txt = txt.replaceAll("w", "2");
txt = txt.replaceAll("^h", "A");
txt = txt.replaceAll("h", "2");
txt = txt.replaceAll("r3", "R3");
txt = txt.replaceAll("r$", "3"); // 2.0 only
//txt = txt.replaceAll("ry", "Ry"); // 1.0 only
txt = txt.replaceAll("r", "2");
txt = txt.replaceAll("l3", "L3");
txt = txt.replaceAll("l$", "3"); // 2.0 only
//txt = txt.replaceAll("ly", "Ly"); // 1.0 only
txt = txt.replaceAll("l", "2");
//txt = txt.replaceAll("j", "y"); // 1.0 only
//txt = txt.replaceAll("y3", "Y3"); // 1.0 only
//txt = txt.replaceAll("y", "2"); // 1.0 only
// 5. Handle removals
txt = txt.replaceAll("2", "");
txt = txt.replaceAll("3$", "A"); // 2.0 only
txt = txt.replaceAll("3", "");
// 6. put ten 1s on the end
txt = txt + "111111" + "1111"; // 1.0 only has 6 1s
// 7. take the first six characters as the code
return txt.substring(0, 10); // 1.0 truncates to 6
}
```
| public String caverphone(String txt) {
// NOTE: Version 1.0 of Caverphone is easily derivable from this code
// by commenting out the 2.0 lines and adding in the 1.0 lines
if( txt == null || txt.length() == 0 ) {
return "1111111111";
}
// 1. Convert to lowercase
txt = txt.toLowerCase(java.util.Locale.ENGLISH);
// 2. Remove anything not A-Z
txt = txt.replaceAll("[^a-z]", "");
// 2.5. Remove final e
txt = txt.replaceAll("e$", ""); // 2.0 only
// 3. Handle various start options
txt = txt.replaceAll("^cough", "cou2f");
txt = txt.replaceAll("^rough", "rou2f");
txt = txt.replaceAll("^tough", "tou2f");
txt = txt.replaceAll("^enough", "enou2f"); // 2.0 only
txt = txt.replaceAll("^trough", "trou2f"); // 2.0 only - note the spec says ^enough here again, c+p error I assume
txt = txt.replaceAll("^gn", "2n");
// End
txt = txt.replaceAll("^mb", "m2");
// 4. Handle replacements
txt = txt.replaceAll("cq", "2q");
txt = txt.replaceAll("ci", "si");
txt = txt.replaceAll("ce", "se");
txt = txt.replaceAll("cy", "sy");
txt = txt.replaceAll("tch", "2ch");
txt = txt.replaceAll("c", "k");
txt = txt.replaceAll("q", "k");
txt = txt.replaceAll("x", "k");
txt = txt.replaceAll("v", "f");
txt = txt.replaceAll("dg", "2g");
txt = txt.replaceAll("tio", "sio");
txt = txt.replaceAll("tia", "sia");
txt = txt.replaceAll("d", "t");
txt = txt.replaceAll("ph", "fh");
txt = txt.replaceAll("b", "p");
txt = txt.replaceAll("sh", "s2");
txt = txt.replaceAll("z", "s");
txt = txt.replaceAll("^[aeiou]", "A");
txt = txt.replaceAll("[aeiou]", "3");
txt = txt.replaceAll("j", "y"); // 2.0 only
txt = txt.replaceAll("^y3", "Y3"); // 2.0 only
txt = txt.replaceAll("^y", "A"); // 2.0 only
txt = txt.replaceAll("y", "3"); // 2.0 only
txt = txt.replaceAll("3gh3", "3kh3");
txt = txt.replaceAll("gh", "22");
txt = txt.replaceAll("g", "k");
txt = txt.replaceAll("s+", "S");
txt = txt.replaceAll("t+", "T");
txt = txt.replaceAll("p+", "P");
txt = txt.replaceAll("k+", "K");
txt = txt.replaceAll("f+", "F");
txt = txt.replaceAll("m+", "M");
txt = txt.replaceAll("n+", "N");
txt = txt.replaceAll("w3", "W3");
//txt = txt.replaceAll("wy", "Wy"); // 1.0 only
txt = txt.replaceAll("wh3", "Wh3");
txt = txt.replaceAll("w$", "3"); // 2.0 only
//txt = txt.replaceAll("why", "Why"); // 1.0 only
txt = txt.replaceAll("w", "2");
txt = txt.replaceAll("^h", "A");
txt = txt.replaceAll("h", "2");
txt = txt.replaceAll("r3", "R3");
txt = txt.replaceAll("r$", "3"); // 2.0 only
//txt = txt.replaceAll("ry", "Ry"); // 1.0 only
txt = txt.replaceAll("r", "2");
txt = txt.replaceAll("l3", "L3");
txt = txt.replaceAll("l$", "3"); // 2.0 only
//txt = txt.replaceAll("ly", "Ly"); // 1.0 only
txt = txt.replaceAll("l", "2");
//txt = txt.replaceAll("j", "y"); // 1.0 only
//txt = txt.replaceAll("y3", "Y3"); // 1.0 only
//txt = txt.replaceAll("y", "2"); // 1.0 only
// 5. Handle removals
txt = txt.replaceAll("2", "");
txt = txt.replaceAll("3$", "A"); // 2.0 only
txt = txt.replaceAll("3", "");
// 6. put ten 1s on the end
txt = txt + "111111" + "1111"; // 1.0 only has 6 1s
// 7. take the first six characters as the code
return txt.substring(0, 10); // 1.0 truncates to 6
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Encodes the given String into a Caverphone value.
*
* @param txt String the source string
* @return A caverphone code for the given String
*/
public String caverphone(String txt) {
// NOTE: Version 1.0 of Caverphone is easily derivable from this code
// by commenting out the 2.0 lines and adding in the 1.0 lines
if( txt == null || txt.length() == 0 ) {
return "1111111111";
}
// 1. Convert to lowercase
txt = txt.toLowerCase(java.util.Locale.ENGLISH);
// 2. Remove anything not A-Z
txt = txt.replaceAll("[^a-z]", "");
// 2.5. Remove final e
txt = txt.replaceAll("e$", ""); // 2.0 only
// 3. Handle various start options
txt = txt.replaceAll("^cough", "cou2f");
txt = txt.replaceAll("^rough", "rou2f");
txt = txt.replaceAll("^tough", "tou2f");
txt = txt.replaceAll("^enough", "enou2f"); // 2.0 only
txt = txt.replaceAll("^trough", "trou2f"); // 2.0 only - note the spec says ^enough here again, c+p error I assume
txt = txt.replaceAll("^gn", "2n");
// End
txt = txt.replaceAll("^mb", "m2");
// 4. Handle replacements
txt = txt.replaceAll("cq", "2q");
txt = txt.replaceAll("ci", "si");
txt = txt.replaceAll("ce", "se");
txt = txt.replaceAll("cy", "sy");
txt = txt.replaceAll("tch", "2ch");
txt = txt.replaceAll("c", "k");
txt = txt.replaceAll("q", "k");
txt = txt.replaceAll("x", "k");
txt = txt.replaceAll("v", "f");
txt = txt.replaceAll("dg", "2g");
txt = txt.replaceAll("tio", "sio");
txt = txt.replaceAll("tia", "sia");
txt = txt.replaceAll("d", "t");
txt = txt.replaceAll("ph", "fh");
txt = txt.replaceAll("b", "p");
txt = txt.replaceAll("sh", "s2");
txt = txt.replaceAll("z", "s");
txt = txt.replaceAll("^[aeiou]", "A");
txt = txt.replaceAll("[aeiou]", "3");
txt = txt.replaceAll("j", "y"); // 2.0 only
txt = txt.replaceAll("^y3", "Y3"); // 2.0 only
txt = txt.replaceAll("^y", "A"); // 2.0 only
txt = txt.replaceAll("y", "3"); // 2.0 only
txt = txt.replaceAll("3gh3", "3kh3");
txt = txt.replaceAll("gh", "22");
txt = txt.replaceAll("g", "k");
txt = txt.replaceAll("s+", "S");
txt = txt.replaceAll("t+", "T");
txt = txt.replaceAll("p+", "P");
txt = txt.replaceAll("k+", "K");
txt = txt.replaceAll("f+", "F");
txt = txt.replaceAll("m+", "M");
txt = txt.replaceAll("n+", "N");
txt = txt.replaceAll("w3", "W3");
//txt = txt.replaceAll("wy", "Wy"); // 1.0 only
txt = txt.replaceAll("wh3", "Wh3");
txt = txt.replaceAll("w$", "3"); // 2.0 only
//txt = txt.replaceAll("why", "Why"); // 1.0 only
txt = txt.replaceAll("w", "2");
txt = txt.replaceAll("^h", "A");
txt = txt.replaceAll("h", "2");
txt = txt.replaceAll("r3", "R3");
txt = txt.replaceAll("r$", "3"); // 2.0 only
//txt = txt.replaceAll("ry", "Ry"); // 1.0 only
txt = txt.replaceAll("r", "2");
txt = txt.replaceAll("l3", "L3");
txt = txt.replaceAll("l$", "3"); // 2.0 only
//txt = txt.replaceAll("ly", "Ly"); // 1.0 only
txt = txt.replaceAll("l", "2");
//txt = txt.replaceAll("j", "y"); // 1.0 only
//txt = txt.replaceAll("y3", "Y3"); // 1.0 only
//txt = txt.replaceAll("y", "2"); // 1.0 only
// 5. Handle removals
txt = txt.replaceAll("2", "");
txt = txt.replaceAll("3$", "A"); // 2.0 only
txt = txt.replaceAll("3", "");
// 6. put ten 1s on the end
txt = txt + "111111" + "1111"; // 1.0 only has 6 1s
// 7. take the first six characters as the code
return txt.substring(0, 10); // 1.0 truncates to 6
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
55 | dd7722805ade32346672e4f96f936190f0fbf5de949230d2de34ebaea0cf6517 | private static boolean isReduceableFunctionExpression(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n);
}
```
| private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
67 | ddb9a51ca41d30ef7c9eee9f4ba03ca58177d3c37e66497d666bcdd5eabc2fe5 | private boolean isPrototypePropertyAssign(Node assign) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
&& assign.getParent().getType() == Token.EXPR_RESULT) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
}
```
| private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
&& assign.getParent().getType() == Token.EXPR_RESULT) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
&& assign.getParent().getType() == Token.EXPR_RESULT) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | ddf6986b8181232032d4a49e0d34372f75ff87e80da4c7329ab3c37de66c84d5 | @Override
public boolean isDirectory() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Return whether or not this entry represents a directory.
*
* @return True if this entry is a directory.
*/
@Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (!isPaxHeader() && !isGlobalPaxHeader() && getName().endsWith("/")) {
return true;
}
return false;
}
```
| @Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (!isPaxHeader() && !isGlobalPaxHeader() && getName().endsWith("/")) {
return true;
}
return false;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Return whether or not this entry represents a directory.
*
* @return True if this entry is a directory.
*/
@Override
public boolean isDirectory() {
if (file != null) {
return file.isDirectory();
}
if (linkFlag == LF_DIR) {
return true;
}
if (!isPaxHeader() && !isGlobalPaxHeader() && getName().endsWith("/")) {
return true;
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | de2c66ef8daafe9313b19823d81dac900a6a5243eb7b27af238847f7d09ad726 | public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a printer that will print values to the given stream following the CSVFormat.
* <p>
* Currently, only a pure encapsulation format or a pure escaping format is supported. Hybrid formats (encapsulation
* and escaping with a different character) are not supported.
* </p>
*
* @param out
* stream to which to print. Must not be null.
* @param format
* the CSV format. Must not be null.
* @throws IOException
* thrown if the optional header cannot be printed.
* @throws IllegalArgumentException
* thrown if the parameters of the format are inconsistent or if either out or format are null.
*/
public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
}
```
| public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a printer that will print values to the given stream following the CSVFormat.
* <p>
* Currently, only a pure encapsulation format or a pure escaping format is supported. Hybrid formats (encapsulation
* and escaping with a different character) are not supported.
* </p>
*
* @param out
* stream to which to print. Must not be null.
* @param format
* the CSV format. Must not be null.
* @throws IOException
* thrown if the optional header cannot be printed.
* @throws IllegalArgumentException
* thrown if the parameters of the format are inconsistent or if either out or format are null.
*/
public CSVPrinter(final Appendable out, final CSVFormat format) throws IOException {
Assertions.notNull(out, "out");
Assertions.notNull(format, "format");
this.out = out;
this.format = format;
this.format.validate();
// TODO: Is it a good idea to do this here instead of on the first call to a print method?
// It seems a pain to have to track whether the header has already been printed or not.
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | def4072014d8ffbdbdfe94b78cf181de97c17b3bc04dd6caf9b334d881d62bfb | @Override
protected Object _deserializeFromEmptyString() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
if (_kind == STD_LOCALE) {
return Locale.ROOT;
}
return super._deserializeFromEmptyString();
}
```
| @Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
if (_kind == STD_LOCALE) {
return Locale.ROOT;
}
return super._deserializeFromEmptyString();
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected Object _deserializeFromEmptyString() throws IOException {
// As per [databind#398], URI requires special handling
if (_kind == STD_URI) {
return URI.create("");
}
// As per [databind#1123], Locale too
if (_kind == STD_LOCALE) {
return Locale.ROOT;
}
return super._deserializeFromEmptyString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | df1d58532e31068c60caa3941cc36b566fca4e771106f91440f916da5815eefe | protected int findWrapPos(String text, int width, int startPos)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Finds the next text wrap position after <code>startPos</code> for the
* text in <code>text</code> with the column width <code>width</code>.
* The wrap point is the last position before startPos+width having a
* whitespace character (space, \n, \r). If there is no whitespace character
* before startPos+width, it will return startPos+width.
*
* @param text The text being searched for the wrap position
* @param width width of the wrapped text
* @param startPos position from which to start the lookup whitespace
* character
* @return postion on which the text must be wrapped or -1 if the wrap
* position is at the end of the text
*/
protected int findWrapPos(String text, int width, int startPos)
{
int pos;
// the line ends before the max wrap pos or a new line char found
if (((pos = text.indexOf('\n', startPos)) != -1 && pos <= width)
|| ((pos = text.indexOf('\t', startPos)) != -1 && pos <= width))
{
return pos + 1;
}
else if (startPos + width >= text.length())
{
return -1;
}
// look for the last whitespace character before startPos+width
pos = startPos + width;
char c;
while ((pos >= startPos) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
--pos;
}
// if we found it - just return
if (pos > startPos)
{
return pos;
}
// if we didn't find one, simply chop at startPos+width
pos = startPos + width;
while ((pos <= text.length()) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
++pos;
}
return pos == text.length() ? -1 : pos;
}
```
| protected int findWrapPos(String text, int width, int startPos)
{
int pos;
// the line ends before the max wrap pos or a new line char found
if (((pos = text.indexOf('\n', startPos)) != -1 && pos <= width)
|| ((pos = text.indexOf('\t', startPos)) != -1 && pos <= width))
{
return pos + 1;
}
else if (startPos + width >= text.length())
{
return -1;
}
// look for the last whitespace character before startPos+width
pos = startPos + width;
char c;
while ((pos >= startPos) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
--pos;
}
// if we found it - just return
if (pos > startPos)
{
return pos;
}
// if we didn't find one, simply chop at startPos+width
pos = startPos + width;
while ((pos <= text.length()) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
++pos;
}
return pos == text.length() ? -1 : pos;
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Finds the next text wrap position after <code>startPos</code> for the
* text in <code>text</code> with the column width <code>width</code>.
* The wrap point is the last position before startPos+width having a
* whitespace character (space, \n, \r). If there is no whitespace character
* before startPos+width, it will return startPos+width.
*
* @param text The text being searched for the wrap position
* @param width width of the wrapped text
* @param startPos position from which to start the lookup whitespace
* character
* @return postion on which the text must be wrapped or -1 if the wrap
* position is at the end of the text
*/
protected int findWrapPos(String text, int width, int startPos)
{
int pos;
// the line ends before the max wrap pos or a new line char found
if (((pos = text.indexOf('\n', startPos)) != -1 && pos <= width)
|| ((pos = text.indexOf('\t', startPos)) != -1 && pos <= width))
{
return pos + 1;
}
else if (startPos + width >= text.length())
{
return -1;
}
// look for the last whitespace character before startPos+width
pos = startPos + width;
char c;
while ((pos >= startPos) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
--pos;
}
// if we found it - just return
if (pos > startPos)
{
return pos;
}
// if we didn't find one, simply chop at startPos+width
pos = startPos + width;
while ((pos <= text.length()) && ((c = text.charAt(pos)) != ' ')
&& (c != '\n') && (c != '\r'))
{
++pos;
}
return pos == text.length() ? -1 : pos;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | df6a4c4cc7146a8cb6d5fa2696f3f2e5fd9fe35dcf8545f0ed9f8910a809ef02 | protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Arranges the items within a container.
*
* @param container the container.
* @param constraint the constraint.
* @param g2 the graphics device.
*
* @return The container size after the arrangement.
*/
protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth() - w[2]),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
}
```
| protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth() - w[2]),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Arranges the items within a container.
*
* @param container the container.
* @param constraint the constraint.
* @param g2 the graphics device.
*
* @return The container size after the arrangement.
*/
protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth() - w[2]),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | df82db8cd4b67279d25bd98883fc02bca5cd39868c7855d683f2e4b8b4712c2d | private void prelim(double[] lowerBound,
double[] upperBound) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* SUBROUTINE PRELIM sets the elements of XBASE, XPT, FVAL, GOPT, HQ, PQ,
* BMAT and ZMAT for the first iteration, and it maintains the values of
* NF and KOPT. The vector X is also changed by PRELIM.
*
* The arguments N, NPT, X, XL, XU, RHOBEG, IPRINT and MAXFUN are the
* same as the corresponding arguments in SUBROUTINE BOBYQA.
* The arguments XBASE, XPT, FVAL, HQ, PQ, BMAT, ZMAT, NDIM, SL and SU
* are the same as the corresponding arguments in BOBYQB, the elements
* of SL and SU being set in BOBYQA.
* GOPT is usually the gradient of the quadratic model at XOPT+XBASE, but
* it is set by PRELIM to the gradient of the quadratic model at XBASE.
* If XOPT is nonzero, BOBYQB will change it to its usual value later.
* NF is maintaned as the number of calls of CALFUN so far.
* KOPT will be such that the least calculated value of F so far is at
* the point XPT(KOPT,.)+XBASE in the space of the variables.
*
* @param lowerBound Lower bounds.
* @param upperBound Upper bounds.
*/
// ----------------------------------------------------------------------------------------
} // altmov
private void prelim(double[] lowerBound,
double[] upperBound) {
printMethod(); // XXX
final int n = currentBest.getDimension();
final int npt = numberOfInterpolationPoints;
final int ndim = bMatrix.getRowDimension();
final double rhosq = initialTrustRegionRadius * initialTrustRegionRadius;
final double recip = 1d / rhosq;
final int np = n + 1;
// Set XBASE to the initial vector of variables, and set the initial
// elements of XPT, BMAT, HQ, PQ and ZMAT to zero.
for (int j = 0; j < n; j++) {
originShift.setEntry(j, currentBest.getEntry(j));
for (int k = 0; k < npt; k++) {
interpolationPoints.setEntry(k, j, ZERO);
}
for (int i = 0; i < ndim; i++) {
bMatrix.setEntry(i, j, ZERO);
}
}
for (int i = 0, max = n * np / 2; i < max; i++) {
modelSecondDerivativesValues.setEntry(i, ZERO);
}
for (int k = 0; k < npt; k++) {
modelSecondDerivativesParameters.setEntry(k, ZERO);
for (int j = 0, max = npt - np; j < max; j++) {
zMatrix.setEntry(k, j, ZERO);
}
}
// Begin the initialization procedure. NF becomes one more than the number
// of function values so far. The coordinates of the displacement of the
// next initial interpolation point from XBASE are set in XPT(NF+1,.).
int ipt = 0;
int jpt = 0;
double fbeg = Double.NaN;
do {
final int nfm = getEvaluations();
final int nfx = nfm - n;
final int nfmm = nfm - 1;
final int nfxm = nfx - 1;
double stepa = 0;
double stepb = 0;
if (nfm <= 2 * n) {
if (nfm >= 1 &&
nfm <= n) {
stepa = initialTrustRegionRadius;
if (upperDifference.getEntry(nfmm) == ZERO) {
stepa = -stepa;
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfmm, stepa);
} else if (nfm > n) {
stepa = interpolationPoints.getEntry(nfx, nfxm);
stepb = -initialTrustRegionRadius;
if (lowerDifference.getEntry(nfxm) == ZERO) {
stepb = Math.min(TWO * initialTrustRegionRadius, upperDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
if (upperDifference.getEntry(nfxm) == ZERO) {
stepb = Math.max(-TWO * initialTrustRegionRadius, lowerDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfxm, stepb);
}
} else {
final int tmp1 = (nfm - np) / n;
jpt = nfm - tmp1 * n - n;
ipt = jpt + tmp1;
if (ipt > n) {
final int tmp2 = jpt;
jpt = ipt - n;
ipt = tmp2;
// throw new PathIsExploredException(); // XXX
}
final int iptMinus1 = ipt - 1;
final int jptMinus1 = jpt - 1;
interpolationPoints.setEntry(nfm, iptMinus1, interpolationPoints.getEntry(ipt, iptMinus1));
interpolationPoints.setEntry(nfm, jptMinus1, interpolationPoints.getEntry(jpt, jptMinus1));
}
// Calculate the next value of F. The least function value so far and
// its index are required.
for (int j = 0; j < n; j++) {
currentBest.setEntry(j, Math.min(Math.max(lowerBound[j],
originShift.getEntry(j) + interpolationPoints.getEntry(nfm, j)),
upperBound[j]));
if (interpolationPoints.getEntry(nfm, j) == lowerDifference.getEntry(j)) {
currentBest.setEntry(j, lowerBound[j]);
}
if (interpolationPoints.getEntry(nfm, j) == upperDifference.getEntry(j)) {
currentBest.setEntry(j, upperBound[j]);
}
}
final double objectiveValue = computeObjectiveValue(currentBest.toArray());
final double f = isMinimize ? objectiveValue : -objectiveValue;
final int numEval = getEvaluations(); // nfm + 1
fAtInterpolationPoints.setEntry(nfm, f);
if (numEval == 1) {
fbeg = f;
trustRegionCenterInterpolationPointIndex = 0;
} else if (f < fAtInterpolationPoints.getEntry(trustRegionCenterInterpolationPointIndex)) {
trustRegionCenterInterpolationPointIndex = nfm;
}
// Set the nonzero initial elements of BMAT and the quadratic model in the
// cases when NF is at most 2*N+1. If NF exceeds N+1, then the positions
// of the NF-th and (NF-N)-th interpolation points may be switched, in
// order that the function value at the first of them contributes to the
// off-diagonal second derivative terms of the initial quadratic model.
if (numEval <= 2 * n + 1) {
if (numEval >= 2 &&
numEval <= n + 1) {
gradientAtTrustRegionCenter.setEntry(nfmm, (f - fbeg) / stepa);
if (npt < numEval + n) {
final double oneOverStepA = ONE / stepa;
bMatrix.setEntry(0, nfmm, -oneOverStepA);
bMatrix.setEntry(nfm, nfmm, oneOverStepA);
bMatrix.setEntry(npt + nfmm, nfmm, -HALF * rhosq);
throw new PathIsExploredException(); // XXX
}
} else if (numEval >= n + 2) {
final int ih = nfx * (nfx + 1) / 2 - 1;
final double tmp = (f - fbeg) / stepb;
final double diff = stepb - stepa;
modelSecondDerivativesValues.setEntry(ih, TWO * (tmp - gradientAtTrustRegionCenter.getEntry(nfxm)) / diff);
gradientAtTrustRegionCenter.setEntry(nfxm, (gradientAtTrustRegionCenter.getEntry(nfxm) * stepb - tmp * stepa) / diff);
if (stepa * stepb < ZERO) {
if (f < fAtInterpolationPoints.getEntry(nfm - n)) {
fAtInterpolationPoints.setEntry(nfm, fAtInterpolationPoints.getEntry(nfm - n));
fAtInterpolationPoints.setEntry(nfm - n, f);
if (trustRegionCenterInterpolationPointIndex == nfm) {
trustRegionCenterInterpolationPointIndex = nfm - n;
}
interpolationPoints.setEntry(nfm - n, nfxm, stepb);
interpolationPoints.setEntry(nfm, nfxm, stepa);
}
}
bMatrix.setEntry(0, nfxm, -(stepa + stepb) / (stepa * stepb));
bMatrix.setEntry(nfm, nfxm, -HALF / interpolationPoints.getEntry(nfm - n, nfxm));
bMatrix.setEntry(nfm - n, nfxm,
-bMatrix.getEntry(0, nfxm) - bMatrix.getEntry(nfm, nfxm));
zMatrix.setEntry(0, nfxm, Math.sqrt(TWO) / (stepa * stepb));
zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) / rhosq);
// zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) * recip); // XXX "testAckley" and "testDiffPow" fail.
zMatrix.setEntry(nfm - n, nfxm,
-zMatrix.getEntry(0, nfxm) - zMatrix.getEntry(nfm, nfxm));
}
// Set the off-diagonal second derivatives of the Lagrange functions and
// the initial quadratic model.
} else {
zMatrix.setEntry(0, nfxm, recip);
zMatrix.setEntry(nfm, nfxm, recip);
zMatrix.setEntry(ipt, nfxm, -recip);
zMatrix.setEntry(jpt, nfxm, -recip);
final int ih = ipt * (ipt - 1) / 2 + jpt - 1;
final double tmp = interpolationPoints.getEntry(nfm, ipt - 1) * interpolationPoints.getEntry(nfm, jpt - 1);
modelSecondDerivativesValues.setEntry(ih, (fbeg - fAtInterpolationPoints.getEntry(ipt) - fAtInterpolationPoints.getEntry(jpt) + f) / tmp);
// throw new PathIsExploredException(); // XXX
}
} while (getEvaluations() < npt);
} // prelim
```
| private void prelim(double[] lowerBound,
double[] upperBound) {
printMethod(); // XXX
final int n = currentBest.getDimension();
final int npt = numberOfInterpolationPoints;
final int ndim = bMatrix.getRowDimension();
final double rhosq = initialTrustRegionRadius * initialTrustRegionRadius;
final double recip = 1d / rhosq;
final int np = n + 1;
// Set XBASE to the initial vector of variables, and set the initial
// elements of XPT, BMAT, HQ, PQ and ZMAT to zero.
for (int j = 0; j < n; j++) {
originShift.setEntry(j, currentBest.getEntry(j));
for (int k = 0; k < npt; k++) {
interpolationPoints.setEntry(k, j, ZERO);
}
for (int i = 0; i < ndim; i++) {
bMatrix.setEntry(i, j, ZERO);
}
}
for (int i = 0, max = n * np / 2; i < max; i++) {
modelSecondDerivativesValues.setEntry(i, ZERO);
}
for (int k = 0; k < npt; k++) {
modelSecondDerivativesParameters.setEntry(k, ZERO);
for (int j = 0, max = npt - np; j < max; j++) {
zMatrix.setEntry(k, j, ZERO);
}
}
// Begin the initialization procedure. NF becomes one more than the number
// of function values so far. The coordinates of the displacement of the
// next initial interpolation point from XBASE are set in XPT(NF+1,.).
int ipt = 0;
int jpt = 0;
double fbeg = Double.NaN;
do {
final int nfm = getEvaluations();
final int nfx = nfm - n;
final int nfmm = nfm - 1;
final int nfxm = nfx - 1;
double stepa = 0;
double stepb = 0;
if (nfm <= 2 * n) {
if (nfm >= 1 &&
nfm <= n) {
stepa = initialTrustRegionRadius;
if (upperDifference.getEntry(nfmm) == ZERO) {
stepa = -stepa;
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfmm, stepa);
} else if (nfm > n) {
stepa = interpolationPoints.getEntry(nfx, nfxm);
stepb = -initialTrustRegionRadius;
if (lowerDifference.getEntry(nfxm) == ZERO) {
stepb = Math.min(TWO * initialTrustRegionRadius, upperDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
if (upperDifference.getEntry(nfxm) == ZERO) {
stepb = Math.max(-TWO * initialTrustRegionRadius, lowerDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfxm, stepb);
}
} else {
final int tmp1 = (nfm - np) / n;
jpt = nfm - tmp1 * n - n;
ipt = jpt + tmp1;
if (ipt > n) {
final int tmp2 = jpt;
jpt = ipt - n;
ipt = tmp2;
// throw new PathIsExploredException(); // XXX
}
final int iptMinus1 = ipt - 1;
final int jptMinus1 = jpt - 1;
interpolationPoints.setEntry(nfm, iptMinus1, interpolationPoints.getEntry(ipt, iptMinus1));
interpolationPoints.setEntry(nfm, jptMinus1, interpolationPoints.getEntry(jpt, jptMinus1));
}
// Calculate the next value of F. The least function value so far and
// its index are required.
for (int j = 0; j < n; j++) {
currentBest.setEntry(j, Math.min(Math.max(lowerBound[j],
originShift.getEntry(j) + interpolationPoints.getEntry(nfm, j)),
upperBound[j]));
if (interpolationPoints.getEntry(nfm, j) == lowerDifference.getEntry(j)) {
currentBest.setEntry(j, lowerBound[j]);
}
if (interpolationPoints.getEntry(nfm, j) == upperDifference.getEntry(j)) {
currentBest.setEntry(j, upperBound[j]);
}
}
final double objectiveValue = computeObjectiveValue(currentBest.toArray());
final double f = isMinimize ? objectiveValue : -objectiveValue;
final int numEval = getEvaluations(); // nfm + 1
fAtInterpolationPoints.setEntry(nfm, f);
if (numEval == 1) {
fbeg = f;
trustRegionCenterInterpolationPointIndex = 0;
} else if (f < fAtInterpolationPoints.getEntry(trustRegionCenterInterpolationPointIndex)) {
trustRegionCenterInterpolationPointIndex = nfm;
}
// Set the nonzero initial elements of BMAT and the quadratic model in the
// cases when NF is at most 2*N+1. If NF exceeds N+1, then the positions
// of the NF-th and (NF-N)-th interpolation points may be switched, in
// order that the function value at the first of them contributes to the
// off-diagonal second derivative terms of the initial quadratic model.
if (numEval <= 2 * n + 1) {
if (numEval >= 2 &&
numEval <= n + 1) {
gradientAtTrustRegionCenter.setEntry(nfmm, (f - fbeg) / stepa);
if (npt < numEval + n) {
final double oneOverStepA = ONE / stepa;
bMatrix.setEntry(0, nfmm, -oneOverStepA);
bMatrix.setEntry(nfm, nfmm, oneOverStepA);
bMatrix.setEntry(npt + nfmm, nfmm, -HALF * rhosq);
throw new PathIsExploredException(); // XXX
}
} else if (numEval >= n + 2) {
final int ih = nfx * (nfx + 1) / 2 - 1;
final double tmp = (f - fbeg) / stepb;
final double diff = stepb - stepa;
modelSecondDerivativesValues.setEntry(ih, TWO * (tmp - gradientAtTrustRegionCenter.getEntry(nfxm)) / diff);
gradientAtTrustRegionCenter.setEntry(nfxm, (gradientAtTrustRegionCenter.getEntry(nfxm) * stepb - tmp * stepa) / diff);
if (stepa * stepb < ZERO) {
if (f < fAtInterpolationPoints.getEntry(nfm - n)) {
fAtInterpolationPoints.setEntry(nfm, fAtInterpolationPoints.getEntry(nfm - n));
fAtInterpolationPoints.setEntry(nfm - n, f);
if (trustRegionCenterInterpolationPointIndex == nfm) {
trustRegionCenterInterpolationPointIndex = nfm - n;
}
interpolationPoints.setEntry(nfm - n, nfxm, stepb);
interpolationPoints.setEntry(nfm, nfxm, stepa);
}
}
bMatrix.setEntry(0, nfxm, -(stepa + stepb) / (stepa * stepb));
bMatrix.setEntry(nfm, nfxm, -HALF / interpolationPoints.getEntry(nfm - n, nfxm));
bMatrix.setEntry(nfm - n, nfxm,
-bMatrix.getEntry(0, nfxm) - bMatrix.getEntry(nfm, nfxm));
zMatrix.setEntry(0, nfxm, Math.sqrt(TWO) / (stepa * stepb));
zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) / rhosq);
// zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) * recip); // XXX "testAckley" and "testDiffPow" fail.
zMatrix.setEntry(nfm - n, nfxm,
-zMatrix.getEntry(0, nfxm) - zMatrix.getEntry(nfm, nfxm));
}
// Set the off-diagonal second derivatives of the Lagrange functions and
// the initial quadratic model.
} else {
zMatrix.setEntry(0, nfxm, recip);
zMatrix.setEntry(nfm, nfxm, recip);
zMatrix.setEntry(ipt, nfxm, -recip);
zMatrix.setEntry(jpt, nfxm, -recip);
final int ih = ipt * (ipt - 1) / 2 + jpt - 1;
final double tmp = interpolationPoints.getEntry(nfm, ipt - 1) * interpolationPoints.getEntry(nfm, jpt - 1);
modelSecondDerivativesValues.setEntry(ih, (fbeg - fAtInterpolationPoints.getEntry(ipt) - fAtInterpolationPoints.getEntry(jpt) + f) / tmp);
// throw new PathIsExploredException(); // XXX
}
} while (getEvaluations() < npt);
} // prelim | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* SUBROUTINE PRELIM sets the elements of XBASE, XPT, FVAL, GOPT, HQ, PQ,
* BMAT and ZMAT for the first iteration, and it maintains the values of
* NF and KOPT. The vector X is also changed by PRELIM.
*
* The arguments N, NPT, X, XL, XU, RHOBEG, IPRINT and MAXFUN are the
* same as the corresponding arguments in SUBROUTINE BOBYQA.
* The arguments XBASE, XPT, FVAL, HQ, PQ, BMAT, ZMAT, NDIM, SL and SU
* are the same as the corresponding arguments in BOBYQB, the elements
* of SL and SU being set in BOBYQA.
* GOPT is usually the gradient of the quadratic model at XOPT+XBASE, but
* it is set by PRELIM to the gradient of the quadratic model at XBASE.
* If XOPT is nonzero, BOBYQB will change it to its usual value later.
* NF is maintaned as the number of calls of CALFUN so far.
* KOPT will be such that the least calculated value of F so far is at
* the point XPT(KOPT,.)+XBASE in the space of the variables.
*
* @param lowerBound Lower bounds.
* @param upperBound Upper bounds.
*/
// ----------------------------------------------------------------------------------------
} // altmov
private void prelim(double[] lowerBound,
double[] upperBound) {
printMethod(); // XXX
final int n = currentBest.getDimension();
final int npt = numberOfInterpolationPoints;
final int ndim = bMatrix.getRowDimension();
final double rhosq = initialTrustRegionRadius * initialTrustRegionRadius;
final double recip = 1d / rhosq;
final int np = n + 1;
// Set XBASE to the initial vector of variables, and set the initial
// elements of XPT, BMAT, HQ, PQ and ZMAT to zero.
for (int j = 0; j < n; j++) {
originShift.setEntry(j, currentBest.getEntry(j));
for (int k = 0; k < npt; k++) {
interpolationPoints.setEntry(k, j, ZERO);
}
for (int i = 0; i < ndim; i++) {
bMatrix.setEntry(i, j, ZERO);
}
}
for (int i = 0, max = n * np / 2; i < max; i++) {
modelSecondDerivativesValues.setEntry(i, ZERO);
}
for (int k = 0; k < npt; k++) {
modelSecondDerivativesParameters.setEntry(k, ZERO);
for (int j = 0, max = npt - np; j < max; j++) {
zMatrix.setEntry(k, j, ZERO);
}
}
// Begin the initialization procedure. NF becomes one more than the number
// of function values so far. The coordinates of the displacement of the
// next initial interpolation point from XBASE are set in XPT(NF+1,.).
int ipt = 0;
int jpt = 0;
double fbeg = Double.NaN;
do {
final int nfm = getEvaluations();
final int nfx = nfm - n;
final int nfmm = nfm - 1;
final int nfxm = nfx - 1;
double stepa = 0;
double stepb = 0;
if (nfm <= 2 * n) {
if (nfm >= 1 &&
nfm <= n) {
stepa = initialTrustRegionRadius;
if (upperDifference.getEntry(nfmm) == ZERO) {
stepa = -stepa;
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfmm, stepa);
} else if (nfm > n) {
stepa = interpolationPoints.getEntry(nfx, nfxm);
stepb = -initialTrustRegionRadius;
if (lowerDifference.getEntry(nfxm) == ZERO) {
stepb = Math.min(TWO * initialTrustRegionRadius, upperDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
if (upperDifference.getEntry(nfxm) == ZERO) {
stepb = Math.max(-TWO * initialTrustRegionRadius, lowerDifference.getEntry(nfxm));
throw new PathIsExploredException(); // XXX
}
interpolationPoints.setEntry(nfm, nfxm, stepb);
}
} else {
final int tmp1 = (nfm - np) / n;
jpt = nfm - tmp1 * n - n;
ipt = jpt + tmp1;
if (ipt > n) {
final int tmp2 = jpt;
jpt = ipt - n;
ipt = tmp2;
// throw new PathIsExploredException(); // XXX
}
final int iptMinus1 = ipt - 1;
final int jptMinus1 = jpt - 1;
interpolationPoints.setEntry(nfm, iptMinus1, interpolationPoints.getEntry(ipt, iptMinus1));
interpolationPoints.setEntry(nfm, jptMinus1, interpolationPoints.getEntry(jpt, jptMinus1));
}
// Calculate the next value of F. The least function value so far and
// its index are required.
for (int j = 0; j < n; j++) {
currentBest.setEntry(j, Math.min(Math.max(lowerBound[j],
originShift.getEntry(j) + interpolationPoints.getEntry(nfm, j)),
upperBound[j]));
if (interpolationPoints.getEntry(nfm, j) == lowerDifference.getEntry(j)) {
currentBest.setEntry(j, lowerBound[j]);
}
if (interpolationPoints.getEntry(nfm, j) == upperDifference.getEntry(j)) {
currentBest.setEntry(j, upperBound[j]);
}
}
final double objectiveValue = computeObjectiveValue(currentBest.toArray());
final double f = isMinimize ? objectiveValue : -objectiveValue;
final int numEval = getEvaluations(); // nfm + 1
fAtInterpolationPoints.setEntry(nfm, f);
if (numEval == 1) {
fbeg = f;
trustRegionCenterInterpolationPointIndex = 0;
} else if (f < fAtInterpolationPoints.getEntry(trustRegionCenterInterpolationPointIndex)) {
trustRegionCenterInterpolationPointIndex = nfm;
}
// Set the nonzero initial elements of BMAT and the quadratic model in the
// cases when NF is at most 2*N+1. If NF exceeds N+1, then the positions
// of the NF-th and (NF-N)-th interpolation points may be switched, in
// order that the function value at the first of them contributes to the
// off-diagonal second derivative terms of the initial quadratic model.
if (numEval <= 2 * n + 1) {
if (numEval >= 2 &&
numEval <= n + 1) {
gradientAtTrustRegionCenter.setEntry(nfmm, (f - fbeg) / stepa);
if (npt < numEval + n) {
final double oneOverStepA = ONE / stepa;
bMatrix.setEntry(0, nfmm, -oneOverStepA);
bMatrix.setEntry(nfm, nfmm, oneOverStepA);
bMatrix.setEntry(npt + nfmm, nfmm, -HALF * rhosq);
throw new PathIsExploredException(); // XXX
}
} else if (numEval >= n + 2) {
final int ih = nfx * (nfx + 1) / 2 - 1;
final double tmp = (f - fbeg) / stepb;
final double diff = stepb - stepa;
modelSecondDerivativesValues.setEntry(ih, TWO * (tmp - gradientAtTrustRegionCenter.getEntry(nfxm)) / diff);
gradientAtTrustRegionCenter.setEntry(nfxm, (gradientAtTrustRegionCenter.getEntry(nfxm) * stepb - tmp * stepa) / diff);
if (stepa * stepb < ZERO) {
if (f < fAtInterpolationPoints.getEntry(nfm - n)) {
fAtInterpolationPoints.setEntry(nfm, fAtInterpolationPoints.getEntry(nfm - n));
fAtInterpolationPoints.setEntry(nfm - n, f);
if (trustRegionCenterInterpolationPointIndex == nfm) {
trustRegionCenterInterpolationPointIndex = nfm - n;
}
interpolationPoints.setEntry(nfm - n, nfxm, stepb);
interpolationPoints.setEntry(nfm, nfxm, stepa);
}
}
bMatrix.setEntry(0, nfxm, -(stepa + stepb) / (stepa * stepb));
bMatrix.setEntry(nfm, nfxm, -HALF / interpolationPoints.getEntry(nfm - n, nfxm));
bMatrix.setEntry(nfm - n, nfxm,
-bMatrix.getEntry(0, nfxm) - bMatrix.getEntry(nfm, nfxm));
zMatrix.setEntry(0, nfxm, Math.sqrt(TWO) / (stepa * stepb));
zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) / rhosq);
// zMatrix.setEntry(nfm, nfxm, Math.sqrt(HALF) * recip); // XXX "testAckley" and "testDiffPow" fail.
zMatrix.setEntry(nfm - n, nfxm,
-zMatrix.getEntry(0, nfxm) - zMatrix.getEntry(nfm, nfxm));
}
// Set the off-diagonal second derivatives of the Lagrange functions and
// the initial quadratic model.
} else {
zMatrix.setEntry(0, nfxm, recip);
zMatrix.setEntry(nfm, nfxm, recip);
zMatrix.setEntry(ipt, nfxm, -recip);
zMatrix.setEntry(jpt, nfxm, -recip);
final int ih = ipt * (ipt - 1) / 2 + jpt - 1;
final double tmp = interpolationPoints.getEntry(nfm, ipt - 1) * interpolationPoints.getEntry(nfm, jpt - 1);
modelSecondDerivativesValues.setEntry(ih, (fbeg - fAtInterpolationPoints.getEntry(ipt) - fAtInterpolationPoints.getEntry(jpt) + f) / tmp);
// throw new PathIsExploredException(); // XXX
}
} while (getEvaluations() < npt);
} // prelim
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | df8899064b614070082c65412fe74fc4297a568e0f82fcd4193834a90399451a | public void reparseCentralDirectoryData(boolean hasUncompressedSize,
boolean hasCompressedSize,
boolean hasRelativeHeaderOffset,
boolean hasDiskStart)
throws ZipException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses the raw bytes read from the central directory extra
* field with knowledge which fields are expected to be there.
*
* <p>All four fields inside the zip64 extended information extra
* field are optional and must only be present if their corresponding
* entry inside the central directory contains the correct magic
* value.</p>
*/
public void reparseCentralDirectoryData(boolean hasUncompressedSize,
boolean hasCompressedSize,
boolean hasRelativeHeaderOffset,
boolean hasDiskStart)
throws ZipException {
if (rawCentralDirectoryData != null) {
int expectedLength = (hasUncompressedSize ? DWORD : 0)
+ (hasCompressedSize ? DWORD : 0)
+ (hasRelativeHeaderOffset ? DWORD : 0)
+ (hasDiskStart ? WORD : 0);
if (rawCentralDirectoryData.length != expectedLength) {
throw new ZipException("central directory zip64 extended"
+ " information extra field's length"
+ " doesn't match central directory"
+ " data. Expected length "
+ expectedLength + " but is "
+ rawCentralDirectoryData.length);
}
int offset = 0;
if (hasUncompressedSize) {
size = new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasCompressedSize) {
compressedSize = new ZipEightByteInteger(rawCentralDirectoryData,
offset);
offset += DWORD;
}
if (hasRelativeHeaderOffset) {
relativeHeaderOffset =
new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasDiskStart) {
diskStart = new ZipLong(rawCentralDirectoryData, offset);
offset += WORD;
}
}
}
```
| public void reparseCentralDirectoryData(boolean hasUncompressedSize,
boolean hasCompressedSize,
boolean hasRelativeHeaderOffset,
boolean hasDiskStart)
throws ZipException {
if (rawCentralDirectoryData != null) {
int expectedLength = (hasUncompressedSize ? DWORD : 0)
+ (hasCompressedSize ? DWORD : 0)
+ (hasRelativeHeaderOffset ? DWORD : 0)
+ (hasDiskStart ? WORD : 0);
if (rawCentralDirectoryData.length != expectedLength) {
throw new ZipException("central directory zip64 extended"
+ " information extra field's length"
+ " doesn't match central directory"
+ " data. Expected length "
+ expectedLength + " but is "
+ rawCentralDirectoryData.length);
}
int offset = 0;
if (hasUncompressedSize) {
size = new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasCompressedSize) {
compressedSize = new ZipEightByteInteger(rawCentralDirectoryData,
offset);
offset += DWORD;
}
if (hasRelativeHeaderOffset) {
relativeHeaderOffset =
new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasDiskStart) {
diskStart = new ZipLong(rawCentralDirectoryData, offset);
offset += WORD;
}
}
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses the raw bytes read from the central directory extra
* field with knowledge which fields are expected to be there.
*
* <p>All four fields inside the zip64 extended information extra
* field are optional and must only be present if their corresponding
* entry inside the central directory contains the correct magic
* value.</p>
*/
public void reparseCentralDirectoryData(boolean hasUncompressedSize,
boolean hasCompressedSize,
boolean hasRelativeHeaderOffset,
boolean hasDiskStart)
throws ZipException {
if (rawCentralDirectoryData != null) {
int expectedLength = (hasUncompressedSize ? DWORD : 0)
+ (hasCompressedSize ? DWORD : 0)
+ (hasRelativeHeaderOffset ? DWORD : 0)
+ (hasDiskStart ? WORD : 0);
if (rawCentralDirectoryData.length != expectedLength) {
throw new ZipException("central directory zip64 extended"
+ " information extra field's length"
+ " doesn't match central directory"
+ " data. Expected length "
+ expectedLength + " but is "
+ rawCentralDirectoryData.length);
}
int offset = 0;
if (hasUncompressedSize) {
size = new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasCompressedSize) {
compressedSize = new ZipEightByteInteger(rawCentralDirectoryData,
offset);
offset += DWORD;
}
if (hasRelativeHeaderOffset) {
relativeHeaderOffset =
new ZipEightByteInteger(rawCentralDirectoryData, offset);
offset += DWORD;
}
if (hasDiskStart) {
diskStart = new ZipLong(rawCentralDirectoryData, offset);
offset += WORD;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | dfa01e1c534b1b07d870889daee6cc949578b36e752bc04e06b9ba8ec90b1c7c | protected RealPointValuePair getSolution() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the current solution.
*
* @return current solution
*/
protected RealPointValuePair getSolution() {
int negativeVarColumn = columnLabels.indexOf(NEGATIVE_VAR_COLUMN_LABEL);
Integer negativeVarBasicRow = negativeVarColumn > 0 ? getBasicRow(negativeVarColumn) : null;
double mostNegative = negativeVarBasicRow == null ? 0 : getEntry(negativeVarBasicRow, getRhsOffset());
Set<Integer> basicRows = new HashSet<Integer>();
double[] coefficients = new double[getOriginalNumDecisionVariables()];
for (int i = 0; i < coefficients.length; i++) {
int colIndex = columnLabels.indexOf("x" + i);
if (colIndex < 0) {
coefficients[i] = 0;
continue;
}
Integer basicRow = getBasicRow(colIndex);
// if the basic row is found to be the objective function row
// set the coefficient to 0 -> this case handles unconstrained
// variables that are still part of the objective function
if (basicRows.contains(basicRow)) {
// if multiple variables can take a given value
// then we choose the first and set the rest equal to 0
coefficients[i] = 0 - (restrictToNonNegative ? 0 : mostNegative);
} else {
basicRows.add(basicRow);
coefficients[i] =
(basicRow == null ? 0 : getEntry(basicRow, getRhsOffset())) -
(restrictToNonNegative ? 0 : mostNegative);
}
}
return new RealPointValuePair(coefficients, f.getValue(coefficients));
}
```
| protected RealPointValuePair getSolution() {
int negativeVarColumn = columnLabels.indexOf(NEGATIVE_VAR_COLUMN_LABEL);
Integer negativeVarBasicRow = negativeVarColumn > 0 ? getBasicRow(negativeVarColumn) : null;
double mostNegative = negativeVarBasicRow == null ? 0 : getEntry(negativeVarBasicRow, getRhsOffset());
Set<Integer> basicRows = new HashSet<Integer>();
double[] coefficients = new double[getOriginalNumDecisionVariables()];
for (int i = 0; i < coefficients.length; i++) {
int colIndex = columnLabels.indexOf("x" + i);
if (colIndex < 0) {
coefficients[i] = 0;
continue;
}
Integer basicRow = getBasicRow(colIndex);
// if the basic row is found to be the objective function row
// set the coefficient to 0 -> this case handles unconstrained
// variables that are still part of the objective function
if (basicRows.contains(basicRow)) {
// if multiple variables can take a given value
// then we choose the first and set the rest equal to 0
coefficients[i] = 0 - (restrictToNonNegative ? 0 : mostNegative);
} else {
basicRows.add(basicRow);
coefficients[i] =
(basicRow == null ? 0 : getEntry(basicRow, getRhsOffset())) -
(restrictToNonNegative ? 0 : mostNegative);
}
}
return new RealPointValuePair(coefficients, f.getValue(coefficients));
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the current solution.
*
* @return current solution
*/
protected RealPointValuePair getSolution() {
int negativeVarColumn = columnLabels.indexOf(NEGATIVE_VAR_COLUMN_LABEL);
Integer negativeVarBasicRow = negativeVarColumn > 0 ? getBasicRow(negativeVarColumn) : null;
double mostNegative = negativeVarBasicRow == null ? 0 : getEntry(negativeVarBasicRow, getRhsOffset());
Set<Integer> basicRows = new HashSet<Integer>();
double[] coefficients = new double[getOriginalNumDecisionVariables()];
for (int i = 0; i < coefficients.length; i++) {
int colIndex = columnLabels.indexOf("x" + i);
if (colIndex < 0) {
coefficients[i] = 0;
continue;
}
Integer basicRow = getBasicRow(colIndex);
// if the basic row is found to be the objective function row
// set the coefficient to 0 -> this case handles unconstrained
// variables that are still part of the objective function
if (basicRows.contains(basicRow)) {
// if multiple variables can take a given value
// then we choose the first and set the rest equal to 0
coefficients[i] = 0 - (restrictToNonNegative ? 0 : mostNegative);
} else {
basicRows.add(basicRow);
coefficients[i] =
(basicRow == null ? 0 : getEntry(basicRow, getRhsOffset())) -
(restrictToNonNegative ? 0 : mostNegative);
}
}
return new RealPointValuePair(coefficients, f.getValue(coefficients));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | dfa3398eb2008394513220828c61ba467d7fb923fdf7464044843fbc7374675f | public long computeMillis(boolean resetFields, String text) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Computes the parsed datetime by setting the saved fields.
* This method is idempotent, but it is not thread-safe.
*
* @param resetFields false by default, but when true, unsaved field values are cleared
* @param text optional text being parsed, to be included in any error message
* @return milliseconds since 1970-01-01T00:00:00Z
* @throws IllegalArgumentException if any field is out of range
* @since 1.3
*/
public long computeMillis(boolean resetFields, String text) {
SavedField[] savedFields = iSavedFields;
int count = iSavedFieldsCount;
if (iSavedFieldsShared) {
iSavedFields = savedFields = (SavedField[])iSavedFields.clone();
iSavedFieldsShared = false;
}
sort(savedFields, count);
if (count > 0) {
// alter base year for parsing if first field is month or day
DurationField months = DurationFieldType.months().getField(iChrono);
DurationField days = DurationFieldType.days().getField(iChrono);
DurationField first = savedFields[0].iField.getDurationField();
if (compareReverse(first, months) >= 0 && compareReverse(first, days) <= 0) {
saveField(DateTimeFieldType.year(), iDefaultYear);
return computeMillis(resetFields, text);
}
}
long millis = iMillis;
try {
for (int i = 0; i < count; i++) {
millis = savedFields[i].set(millis, resetFields);
}
} catch (IllegalFieldValueException e) {
if (text != null) {
e.prependMessage("Cannot parse \"" + text + '"');
}
throw e;
}
if (iZone == null) {
millis -= iOffset;
} else {
int offset = iZone.getOffsetFromLocal(millis);
millis -= offset;
if (offset != iZone.getOffset(millis)) {
String message =
"Illegal instant due to time zone offset transition (" + iZone + ')';
if (text != null) {
message = "Cannot parse \"" + text + "\": " + message;
}
throw new IllegalArgumentException(message);
}
}
return millis;
}
```
| public long computeMillis(boolean resetFields, String text) {
SavedField[] savedFields = iSavedFields;
int count = iSavedFieldsCount;
if (iSavedFieldsShared) {
iSavedFields = savedFields = (SavedField[])iSavedFields.clone();
iSavedFieldsShared = false;
}
sort(savedFields, count);
if (count > 0) {
// alter base year for parsing if first field is month or day
DurationField months = DurationFieldType.months().getField(iChrono);
DurationField days = DurationFieldType.days().getField(iChrono);
DurationField first = savedFields[0].iField.getDurationField();
if (compareReverse(first, months) >= 0 && compareReverse(first, days) <= 0) {
saveField(DateTimeFieldType.year(), iDefaultYear);
return computeMillis(resetFields, text);
}
}
long millis = iMillis;
try {
for (int i = 0; i < count; i++) {
millis = savedFields[i].set(millis, resetFields);
}
} catch (IllegalFieldValueException e) {
if (text != null) {
e.prependMessage("Cannot parse \"" + text + '"');
}
throw e;
}
if (iZone == null) {
millis -= iOffset;
} else {
int offset = iZone.getOffsetFromLocal(millis);
millis -= offset;
if (offset != iZone.getOffset(millis)) {
String message =
"Illegal instant due to time zone offset transition (" + iZone + ')';
if (text != null) {
message = "Cannot parse \"" + text + "\": " + message;
}
throw new IllegalArgumentException(message);
}
}
return millis;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Computes the parsed datetime by setting the saved fields.
* This method is idempotent, but it is not thread-safe.
*
* @param resetFields false by default, but when true, unsaved field values are cleared
* @param text optional text being parsed, to be included in any error message
* @return milliseconds since 1970-01-01T00:00:00Z
* @throws IllegalArgumentException if any field is out of range
* @since 1.3
*/
public long computeMillis(boolean resetFields, String text) {
SavedField[] savedFields = iSavedFields;
int count = iSavedFieldsCount;
if (iSavedFieldsShared) {
iSavedFields = savedFields = (SavedField[])iSavedFields.clone();
iSavedFieldsShared = false;
}
sort(savedFields, count);
if (count > 0) {
// alter base year for parsing if first field is month or day
DurationField months = DurationFieldType.months().getField(iChrono);
DurationField days = DurationFieldType.days().getField(iChrono);
DurationField first = savedFields[0].iField.getDurationField();
if (compareReverse(first, months) >= 0 && compareReverse(first, days) <= 0) {
saveField(DateTimeFieldType.year(), iDefaultYear);
return computeMillis(resetFields, text);
}
}
long millis = iMillis;
try {
for (int i = 0; i < count; i++) {
millis = savedFields[i].set(millis, resetFields);
}
} catch (IllegalFieldValueException e) {
if (text != null) {
e.prependMessage("Cannot parse \"" + text + '"');
}
throw e;
}
if (iZone == null) {
millis -= iOffset;
} else {
int offset = iZone.getOffsetFromLocal(millis);
millis -= offset;
if (offset != iZone.getOffset(millis)) {
String message =
"Illegal instant due to time zone offset transition (" + iZone + ')';
if (text != null) {
message = "Cannot parse \"" + text + "\": " + message;
}
throw new IllegalArgumentException(message);
}
}
return millis;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
80 | dfbd99f8d14ddcd6136a60d9de00773aba79a67db92357f59a312df187c14108 | void insert(Token.Comment commentToken) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
} // else, we couldn't parse it as a decl, so leave as a comment
}
}
insertNode(insert);
}
```
| void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
} // else, we couldn't parse it as a decl, so leave as a comment
}
}
insertNode(insert);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
if (doc.childNodeSize() > 0) {
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
} // else, we couldn't parse it as a decl, so leave as a comment
}
}
insertNode(insert);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | e017ea786d4007067373ccf1092a8c4c2ce8494994fa9ceeb20fdfee148c77e6 | protected void burstToken(String token, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
}
```
| protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Breaks <code>token</code> into its constituent parts
* using the following algorithm.
* <ul>
* <li>ignore the first character ("<b>-</b>")</li>
* <li>foreach remaining character check if an {@link Option}
* exists with that id.</li>
* <li>if an {@link Option} does exist then add that character
* prepended with "<b>-</b>" to the list of processed tokens.</li>
* <li>if the {@link Option} can have an argument value and there
* are remaining characters in the token then add the remaining
* characters as a token to the list of processed tokens.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS</b> set then add the special token
* "<b>--</b>" followed by the remaining characters and also
* the remaining tokens directly to the processed tokens list.</li>
* <li>if an {@link Option} does <b>NOT</b> exist <b>AND</b>
* <code>stopAtNonOption</code> <b>IS NOT</b> set then add that
* character prepended with "<b>-</b>".</li>
* </ul>
* </p>
*
* @param token The current token to be <b>burst</b>
* @param stopAtNonOption Specifies whether to stop processing
* at the first non-Option encountered.
*/
protected void burstToken(String token, boolean stopAtNonOption)
{
int tokenLength = token.length();
for (int i = 1; i < tokenLength; i++)
{
String ch = String.valueOf(token.charAt(i));
boolean hasOption = options.hasOption(ch);
if (hasOption)
{
tokens.add("-" + ch);
currentOption = options.getOption(ch);
if (currentOption.hasArg() && (token.length() != (i + 1)))
{
tokens.add(token.substring(i + 1));
break;
}
}
else if (stopAtNonOption)
{
process(token.substring(i));
}
else
{
tokens.add(token);
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | e056dc1906810e7ab97610619afad8cb87755749a94396eb118382d3f9c715a6 | private void removeUnreferencedFunctionArgs(Scope fnScope) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Removes unreferenced arguments from a function declaration and when
* possible the function's callSites.
*
* @param fnScope The scope inside the function
*/
private void removeUnreferencedFunctionArgs(Scope fnScope) {
// Notice that removing unreferenced function args breaks
// Function.prototype.length. In advanced mode, we don't really care
// about this: we consider "length" the equivalent of reflecting on
// the function's lexical source.
//
// Rather than create a new option for this, we assume that if the user
// is removing globals, then it's OK to remove unused function args.
//
// See http://code.google.com/p/closure-compiler/issues/detail?id=253
Node function = fnScope.getRootNode();
Preconditions.checkState(function.isFunction());
if (NodeUtil.isGetOrSetKey(function.getParent())) {
// The parameters object literal setters can not be removed.
return;
}
Node argList = getFunctionArgList(function);
boolean modifyCallers = modifyCallSites
&& callSiteOptimizer.canModifyCallers(function);
if (!modifyCallers) {
// Strip unreferenced args off the end of the function declaration.
Node lastArg;
while ((lastArg = argList.getLastChild()) != null) {
Var var = fnScope.getVar(lastArg.getString());
if (!referenced.contains(var)) {
argList.removeChild(lastArg);
compiler.reportCodeChange();
} else {
break;
}
}
} else {
callSiteOptimizer.optimize(fnScope, referenced);
}
}
```
| private void removeUnreferencedFunctionArgs(Scope fnScope) {
// Notice that removing unreferenced function args breaks
// Function.prototype.length. In advanced mode, we don't really care
// about this: we consider "length" the equivalent of reflecting on
// the function's lexical source.
//
// Rather than create a new option for this, we assume that if the user
// is removing globals, then it's OK to remove unused function args.
//
// See http://code.google.com/p/closure-compiler/issues/detail?id=253
Node function = fnScope.getRootNode();
Preconditions.checkState(function.isFunction());
if (NodeUtil.isGetOrSetKey(function.getParent())) {
// The parameters object literal setters can not be removed.
return;
}
Node argList = getFunctionArgList(function);
boolean modifyCallers = modifyCallSites
&& callSiteOptimizer.canModifyCallers(function);
if (!modifyCallers) {
// Strip unreferenced args off the end of the function declaration.
Node lastArg;
while ((lastArg = argList.getLastChild()) != null) {
Var var = fnScope.getVar(lastArg.getString());
if (!referenced.contains(var)) {
argList.removeChild(lastArg);
compiler.reportCodeChange();
} else {
break;
}
}
} else {
callSiteOptimizer.optimize(fnScope, referenced);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Removes unreferenced arguments from a function declaration and when
* possible the function's callSites.
*
* @param fnScope The scope inside the function
*/
private void removeUnreferencedFunctionArgs(Scope fnScope) {
// Notice that removing unreferenced function args breaks
// Function.prototype.length. In advanced mode, we don't really care
// about this: we consider "length" the equivalent of reflecting on
// the function's lexical source.
//
// Rather than create a new option for this, we assume that if the user
// is removing globals, then it's OK to remove unused function args.
//
// See http://code.google.com/p/closure-compiler/issues/detail?id=253
Node function = fnScope.getRootNode();
Preconditions.checkState(function.isFunction());
if (NodeUtil.isGetOrSetKey(function.getParent())) {
// The parameters object literal setters can not be removed.
return;
}
Node argList = getFunctionArgList(function);
boolean modifyCallers = modifyCallSites
&& callSiteOptimizer.canModifyCallers(function);
if (!modifyCallers) {
// Strip unreferenced args off the end of the function declaration.
Node lastArg;
while ((lastArg = argList.getLastChild()) != null) {
Var var = fnScope.getVar(lastArg.getString());
if (!referenced.contains(var)) {
argList.removeChild(lastArg);
compiler.reportCodeChange();
} else {
break;
}
}
} else {
callSiteOptimizer.optimize(fnScope, referenced);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
111 | e0644a06876f68bf7c3e5cc1bd2a55908e2eb43d3de7ae05cb4f2f01e8212e5b | @Override
protected JSType caseTopType(JSType topType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected JSType caseTopType(JSType topType) {
return topType.isAllType() ?
getNativeType(ARRAY_TYPE) : topType;
}
```
| @Override
protected JSType caseTopType(JSType topType) {
return topType.isAllType() ?
getNativeType(ARRAY_TYPE) : topType;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected JSType caseTopType(JSType topType) {
return topType.isAllType() ?
getNativeType(ARRAY_TYPE) : topType;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | e0882493ab8b1765841be157528972848d753f881663cc9a6458536cdecbe7fc | public void describeTo(Description description) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted == null ? "null" : wanted.toString());
appendQuoting(description);
description.appendText(")");
}
```
| public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted == null ? "null" : wanted.toString());
appendQuoting(description);
description.appendText(")");
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void describeTo(Description description) {
description.appendText("same(");
appendQuoting(description);
description.appendText(wanted == null ? "null" : wanted.toString());
appendQuoting(description);
description.appendText(")");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | e0bf960c0cd1b7071d005791d8d4f320971d86807b517d50108bc7d9bc091df3 | public double getNumericalMean() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*
* For population size {@code N}, number of successes {@code m}, and sample
* size {@code n}, the mean is {@code n * m / N}.
*/
public double getNumericalMean() {
return getSampleSize() * (getNumberOfSuccesses() / (double) getPopulationSize());
}
```
| public double getNumericalMean() {
return getSampleSize() * (getNumberOfSuccesses() / (double) getPopulationSize());
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*
* For population size {@code N}, number of successes {@code m}, and sample
* size {@code n}, the mean is {@code n * m / N}.
*/
public double getNumericalMean() {
return getSampleSize() * (getNumberOfSuccesses() / (double) getPopulationSize());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | e0f4fbd84d49ac3e71e4f3dcdc6e986d52d2303d4d7748a93ecf13db67da723b | static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns true if calls to this function have side effects.
*
* @param callNode The call node to inspected.
* @param compiler A compiler object to provide program state changing
* context information. Can be null.
*/
static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (nameNode.getFirstChild().getType() == Token.NAME) {
String namespaceName = nameNode.getFirstChild().getString();
if (namespaceName.equals("Math")) {
return false;
}
}
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
}
```
| static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (nameNode.getFirstChild().getType() == Token.NAME) {
String namespaceName = nameNode.getFirstChild().getString();
if (namespaceName.equals("Math")) {
return false;
}
}
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns true if calls to this function have side effects.
*
* @param callNode The call node to inspected.
* @param compiler A compiler object to provide program state changing
* context information. Can be null.
*/
static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (nameNode.getFirstChild().getType() == Token.NAME) {
String namespaceName = nameNode.getFirstChild().getString();
if (namespaceName.equals("Math")) {
return false;
}
}
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | e1224e3dc4951edc16d9ebc32b74d5a1ec0b427205e27398427ac56e42592706 | private void parseStartTag() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void parseStartTag() {
tq.consume("<");
String tagName = tq.consumeWord();
if (tagName.length() == 0) { // doesn't look like a start tag after all; put < back on stack and handle as text
tq.addFirst("<");
parseTextNode();
return;
}
Attributes attributes = new Attributes();
while (!tq.matchesAny("<", "/>", ">") && !tq.isEmpty()) {
Attribute attribute = parseAttribute();
if (attribute != null)
attributes.put(attribute);
}
Tag tag = Tag.valueOf(tagName);
Element child = new Element(tag, baseUri, attributes);
boolean isEmptyElement = tag.isEmpty(); // empty element if empty tag (e.g. img) or self-closed el (<div/>
if (tq.matchChomp("/>")) { // close empty element or tag
isEmptyElement = true;
} else {
tq.matchChomp(">");
}
addChildToParent(child, isEmptyElement);
// pc data only tags (textarea, script): chomp to end tag, add content as text node
if (tag.isData()) {
String data = tq.chompTo("</" + tagName);
tq.chompTo(">");
Node dataNode;
if (tag.equals(titleTag) || tag.equals(textareaTag)) // want to show as text, but not contain inside tags (so not a data tag?)
dataNode = TextNode.createFromEncoded(data, baseUri);
else
dataNode = new DataNode(data, baseUri); // data not encoded but raw (for " in script)
child.appendChild(dataNode);
}
// <base href>: update the base uri
if (child.tagName().equals("base")) {
String href = child.absUrl("href");
if (href.length() != 0) { // ignore <base target> etc
baseUri = href;
doc.setBaseUri(href); // set on the doc so doc.createElement(Tag) will get updated base
}
}
}
```
| private void parseStartTag() {
tq.consume("<");
String tagName = tq.consumeWord();
if (tagName.length() == 0) { // doesn't look like a start tag after all; put < back on stack and handle as text
tq.addFirst("<");
parseTextNode();
return;
}
Attributes attributes = new Attributes();
while (!tq.matchesAny("<", "/>", ">") && !tq.isEmpty()) {
Attribute attribute = parseAttribute();
if (attribute != null)
attributes.put(attribute);
}
Tag tag = Tag.valueOf(tagName);
Element child = new Element(tag, baseUri, attributes);
boolean isEmptyElement = tag.isEmpty(); // empty element if empty tag (e.g. img) or self-closed el (<div/>
if (tq.matchChomp("/>")) { // close empty element or tag
isEmptyElement = true;
} else {
tq.matchChomp(">");
}
addChildToParent(child, isEmptyElement);
// pc data only tags (textarea, script): chomp to end tag, add content as text node
if (tag.isData()) {
String data = tq.chompTo("</" + tagName);
tq.chompTo(">");
Node dataNode;
if (tag.equals(titleTag) || tag.equals(textareaTag)) // want to show as text, but not contain inside tags (so not a data tag?)
dataNode = TextNode.createFromEncoded(data, baseUri);
else
dataNode = new DataNode(data, baseUri); // data not encoded but raw (for " in script)
child.appendChild(dataNode);
}
// <base href>: update the base uri
if (child.tagName().equals("base")) {
String href = child.absUrl("href");
if (href.length() != 0) { // ignore <base target> etc
baseUri = href;
doc.setBaseUri(href); // set on the doc so doc.createElement(Tag) will get updated base
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void parseStartTag() {
tq.consume("<");
String tagName = tq.consumeWord();
if (tagName.length() == 0) { // doesn't look like a start tag after all; put < back on stack and handle as text
tq.addFirst("<");
parseTextNode();
return;
}
Attributes attributes = new Attributes();
while (!tq.matchesAny("<", "/>", ">") && !tq.isEmpty()) {
Attribute attribute = parseAttribute();
if (attribute != null)
attributes.put(attribute);
}
Tag tag = Tag.valueOf(tagName);
Element child = new Element(tag, baseUri, attributes);
boolean isEmptyElement = tag.isEmpty(); // empty element if empty tag (e.g. img) or self-closed el (<div/>
if (tq.matchChomp("/>")) { // close empty element or tag
isEmptyElement = true;
} else {
tq.matchChomp(">");
}
addChildToParent(child, isEmptyElement);
// pc data only tags (textarea, script): chomp to end tag, add content as text node
if (tag.isData()) {
String data = tq.chompTo("</" + tagName);
tq.chompTo(">");
Node dataNode;
if (tag.equals(titleTag) || tag.equals(textareaTag)) // want to show as text, but not contain inside tags (so not a data tag?)
dataNode = TextNode.createFromEncoded(data, baseUri);
else
dataNode = new DataNode(data, baseUri); // data not encoded but raw (for " in script)
child.appendChild(dataNode);
}
// <base href>: update the base uri
if (child.tagName().equals("base")) {
String href = child.absUrl("href");
if (href.length() != 0) { // ignore <base target> etc
baseUri = href;
doc.setBaseUri(href); // set on the doc so doc.createElement(Tag) will get updated base
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | e19d5e51eabe5db954f1a2203e4f3d534bc515520387c3002500957bf177dc0f | void decode(byte[] in, int inPos, int inAvail) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Decodes all of the provided data, starting at inPos, for inAvail bytes. Should be called at least twice: once
* with the data to decode, and once with inAvail set to "-1" to alert decoder that EOF has been reached. The "-1"
* call is not necessary when decoding, but it doesn't hurt, either.
* </p>
* <p>
* Ignores all non-base64 characters. This is how chunked (e.g. 76 character) data is handled, since CR and LF are
* silently ignored, but has implications for other bytes, too. This method subscribes to the garbage-in,
* garbage-out philosophy: it will not check the provided data for validity.
* </p>
* <p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations, and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in
* byte[] array of ascii data to base64 decode.
* @param inPos
* Position to start reading data from.
* @param inAvail
* Amount of bytes available from input for encoding.
*/
void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
}
```
| void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Decodes all of the provided data, starting at inPos, for inAvail bytes. Should be called at least twice: once
* with the data to decode, and once with inAvail set to "-1" to alert decoder that EOF has been reached. The "-1"
* call is not necessary when decoding, but it doesn't hurt, either.
* </p>
* <p>
* Ignores all non-base64 characters. This is how chunked (e.g. 76 character) data is handled, since CR and LF are
* silently ignored, but has implications for other bytes, too. This method subscribes to the garbage-in,
* garbage-out philosophy: it will not check the provided data for validity.
* </p>
* <p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations, and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in
* byte[] array of ascii data to base64 decode.
* @param inPos
* Position to start reading data from.
* @param inAvail
* Amount of bytes available from input for encoding.
*/
void decode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
if (inAvail < 0) {
eof = true;
}
for (int i = 0; i < inAvail; i++) {
if (buffer == null || buffer.length - pos < decodeSize) {
resizeBuffer();
}
byte b = in[inPos++];
if (b == PAD) {
// We're done.
eof = true;
break;
} else {
if (b >= 0 && b < DECODE_TABLE.length) {
int result = DECODE_TABLE[b];
if (result >= 0) {
modulus = (++modulus) % 4;
x = (x << 6) + result;
if (modulus == 0) {
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
buffer[pos++] = (byte) (x & MASK_8BITS);
}
}
}
}
}
// Two forms of EOF as far as base64 decoder is concerned: actual
// EOF (-1) and first time '=' character is encountered in stream.
// This approach makes the '=' padding characters completely optional.
if (eof && modulus != 0) {
x = x << 6;
switch (modulus) {
case 2 :
x = x << 6;
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
break;
case 3 :
buffer[pos++] = (byte) ((x >> 16) & MASK_8BITS);
buffer[pos++] = (byte) ((x >> 8) & MASK_8BITS);
break;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | e19f5bc6438a49daecfa0e9ea12be76c60c9910d041a802859881df4d87af00b | @Override public void skipValue() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
if (stackSize > 0) {
pathNames[stackSize - 1] = "null";
}
}
if (stackSize > 0) {
pathIndices[stackSize - 1]++;
}
}
```
| @Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
if (stackSize > 0) {
pathNames[stackSize - 1] = "null";
}
}
if (stackSize > 0) {
pathIndices[stackSize - 1]++;
}
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
if (stackSize > 0) {
pathNames[stackSize - 1] = "null";
}
}
if (stackSize > 0) {
pathIndices[stackSize - 1]++;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
86 | e1da6ed63dcf23137ca34010a01caa0b82c583bc7f0e1b82650707a9898377c6 | public CholeskyDecompositionImpl(final RealMatrix matrix,
final double relativeSymmetryThreshold,
final double absolutePositivityThreshold)
throws NonSquareMatrixException,
NotSymmetricMatrixException, NotPositiveDefiniteMatrixException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Calculates the Cholesky decomposition of the given matrix.
* @param matrix the matrix to decompose
* @param relativeSymmetryThreshold threshold above which off-diagonal
* elements are considered too different and matrix not symmetric
* @param absolutePositivityThreshold threshold below which diagonal
* elements are considered null and matrix not positive definite
* @exception NonSquareMatrixException if matrix is not square
* @exception NotSymmetricMatrixException if matrix is not symmetric
* @exception NotPositiveDefiniteMatrixException if the matrix is not
* strictly positive definite
* @see #CholeskyDecompositionImpl(RealMatrix)
* @see #DEFAULT_RELATIVE_SYMMETRY_THRESHOLD
* @see #DEFAULT_ABSOLUTE_POSITIVITY_THRESHOLD
*/
public CholeskyDecompositionImpl(final RealMatrix matrix,
final double relativeSymmetryThreshold,
final double absolutePositivityThreshold)
throws NonSquareMatrixException,
NotSymmetricMatrixException, NotPositiveDefiniteMatrixException {
if (!matrix.isSquare()) {
throw new NonSquareMatrixException(matrix.getRowDimension(),
matrix.getColumnDimension());
}
final int order = matrix.getRowDimension();
lTData = matrix.getData();
cachedL = null;
cachedLT = null;
// check the matrix before transformation
for (int i = 0; i < order; ++i) {
final double[] lI = lTData[i];
if (lTData[i][i] < absolutePositivityThreshold) {
throw new NotPositiveDefiniteMatrixException();
}
// check off-diagonal elements (and reset them to 0)
for (int j = i + 1; j < order; ++j) {
final double[] lJ = lTData[j];
final double lIJ = lI[j];
final double lJI = lJ[i];
final double maxDelta =
relativeSymmetryThreshold * Math.max(Math.abs(lIJ), Math.abs(lJI));
if (Math.abs(lIJ - lJI) > maxDelta) {
throw new NotSymmetricMatrixException();
}
lJ[i] = 0;
}
}
// transform the matrix
for (int i = 0; i < order; ++i) {
final double[] ltI = lTData[i];
// check diagonal element
ltI[i] = Math.sqrt(ltI[i]);
final double inverse = 1.0 / ltI[i];
for (int q = order - 1; q > i; --q) {
ltI[q] *= inverse;
final double[] ltQ = lTData[q];
for (int p = q; p < order; ++p) {
ltQ[p] -= ltI[q] * ltI[p];
}
}
}
}
```
| public CholeskyDecompositionImpl(final RealMatrix matrix,
final double relativeSymmetryThreshold,
final double absolutePositivityThreshold)
throws NonSquareMatrixException,
NotSymmetricMatrixException, NotPositiveDefiniteMatrixException {
if (!matrix.isSquare()) {
throw new NonSquareMatrixException(matrix.getRowDimension(),
matrix.getColumnDimension());
}
final int order = matrix.getRowDimension();
lTData = matrix.getData();
cachedL = null;
cachedLT = null;
// check the matrix before transformation
for (int i = 0; i < order; ++i) {
final double[] lI = lTData[i];
if (lTData[i][i] < absolutePositivityThreshold) {
throw new NotPositiveDefiniteMatrixException();
}
// check off-diagonal elements (and reset them to 0)
for (int j = i + 1; j < order; ++j) {
final double[] lJ = lTData[j];
final double lIJ = lI[j];
final double lJI = lJ[i];
final double maxDelta =
relativeSymmetryThreshold * Math.max(Math.abs(lIJ), Math.abs(lJI));
if (Math.abs(lIJ - lJI) > maxDelta) {
throw new NotSymmetricMatrixException();
}
lJ[i] = 0;
}
}
// transform the matrix
for (int i = 0; i < order; ++i) {
final double[] ltI = lTData[i];
// check diagonal element
ltI[i] = Math.sqrt(ltI[i]);
final double inverse = 1.0 / ltI[i];
for (int q = order - 1; q > i; --q) {
ltI[q] *= inverse;
final double[] ltQ = lTData[q];
for (int p = q; p < order; ++p) {
ltQ[p] -= ltI[q] * ltI[p];
}
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Calculates the Cholesky decomposition of the given matrix.
* @param matrix the matrix to decompose
* @param relativeSymmetryThreshold threshold above which off-diagonal
* elements are considered too different and matrix not symmetric
* @param absolutePositivityThreshold threshold below which diagonal
* elements are considered null and matrix not positive definite
* @exception NonSquareMatrixException if matrix is not square
* @exception NotSymmetricMatrixException if matrix is not symmetric
* @exception NotPositiveDefiniteMatrixException if the matrix is not
* strictly positive definite
* @see #CholeskyDecompositionImpl(RealMatrix)
* @see #DEFAULT_RELATIVE_SYMMETRY_THRESHOLD
* @see #DEFAULT_ABSOLUTE_POSITIVITY_THRESHOLD
*/
public CholeskyDecompositionImpl(final RealMatrix matrix,
final double relativeSymmetryThreshold,
final double absolutePositivityThreshold)
throws NonSquareMatrixException,
NotSymmetricMatrixException, NotPositiveDefiniteMatrixException {
if (!matrix.isSquare()) {
throw new NonSquareMatrixException(matrix.getRowDimension(),
matrix.getColumnDimension());
}
final int order = matrix.getRowDimension();
lTData = matrix.getData();
cachedL = null;
cachedLT = null;
// check the matrix before transformation
for (int i = 0; i < order; ++i) {
final double[] lI = lTData[i];
if (lTData[i][i] < absolutePositivityThreshold) {
throw new NotPositiveDefiniteMatrixException();
}
// check off-diagonal elements (and reset them to 0)
for (int j = i + 1; j < order; ++j) {
final double[] lJ = lTData[j];
final double lIJ = lI[j];
final double lJI = lJ[i];
final double maxDelta =
relativeSymmetryThreshold * Math.max(Math.abs(lIJ), Math.abs(lJI));
if (Math.abs(lIJ - lJI) > maxDelta) {
throw new NotSymmetricMatrixException();
}
lJ[i] = 0;
}
}
// transform the matrix
for (int i = 0; i < order; ++i) {
final double[] ltI = lTData[i];
// check diagonal element
ltI[i] = Math.sqrt(ltI[i]);
final double inverse = 1.0 / ltI[i];
for (int q = order - 1; q > i; --q) {
ltI[q] *= inverse;
final double[] ltQ = lTData[q];
for (int p = q; p < order; ++p) {
ltQ[p] -= ltI[q] * ltI[p];
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
73 | e286c7188e231e4d7cc8ca90ba55acc9539b78275bcb7b5b4e99a081c6853de4 | public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
```
| public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(yMin, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(yMax, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
164 | e2889fadbdfcac17c79ac3110dd1dc89d93cafd35ce385f3155643d1ccdca21d | @Override
public boolean isSubtype(JSType other) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
boolean thisIsOptional = thisIsVarArgs || thisParam.isOptionalArg();
boolean thatIsOptional = thatIsVarArgs || thatParam.isOptionalArg();
// "that" can't be a supertype, because it's missing a required argument.
if (!thisIsOptional && thatIsOptional) {
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
boolean isTopFunction =
thatIsVarArgs &&
(thatParamType == null ||
thatParamType.isUnknownType() ||
thatParamType.isNoType());
if (!isTopFunction) {
return false;
}
}
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
if (thisParam != null
&& !thisParam.isOptionalArg() && !thisParam.isVarArgs()
&& thatParam == null) {
return false;
}
return true;
}
```
| @Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
boolean thisIsOptional = thisIsVarArgs || thisParam.isOptionalArg();
boolean thatIsOptional = thatIsVarArgs || thatParam.isOptionalArg();
// "that" can't be a supertype, because it's missing a required argument.
if (!thisIsOptional && thatIsOptional) {
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
boolean isTopFunction =
thatIsVarArgs &&
(thatParamType == null ||
thatParamType.isUnknownType() ||
thatParamType.isNoType());
if (!isTopFunction) {
return false;
}
}
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
if (thisParam != null
&& !thisParam.isOptionalArg() && !thisParam.isVarArgs()
&& thatParam == null) {
return false;
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
boolean thisIsOptional = thisIsVarArgs || thisParam.isOptionalArg();
boolean thatIsOptional = thatIsVarArgs || thatParam.isOptionalArg();
// "that" can't be a supertype, because it's missing a required argument.
if (!thisIsOptional && thatIsOptional) {
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
boolean isTopFunction =
thatIsVarArgs &&
(thatParamType == null ||
thatParamType.isUnknownType() ||
thatParamType.isNoType());
if (!isTopFunction) {
return false;
}
}
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
if (thisParam != null
&& !thisParam.isOptionalArg() && !thisParam.isVarArgs()
&& thatParam == null) {
return false;
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | e2b7efc123b1e9a9ba6d62e94ddf7254c12e68e4083f9b9e746f1d618be68a1e | public static Number createNumber(final String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
```
| public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | e2b7efc123b1e9a9ba6d62e94ddf7254c12e68e4083f9b9e746f1d618be68a1e | public static Number createNumber(final String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
```
| public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>If the string starts with {@code 0x} or {@code -0x} (lower or upper case) or {@code #} or {@code -#}, it
* will be interpreted as a hexadecimal Integer - or Long, if the number of digits after the
* prefix is more than 8 - or BigInteger if there are more than 16 digits.
* </p>
* <p>Then, the value is examined for a type qualifier on the end, i.e. one of
* <code>'f','F','d','D','l','L'</code>. If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>
* Integral values with a leading {@code 0} will be interpreted as octal; the returned number will
* be Integer, Long or BigDecimal as appropriate.
* </p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(final String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
// Need to deal with all possible hex prefixes here
final String[] hex_prefixes = {"0x", "0X", "-0x", "-0X", "#", "-#"};
int pfxLen = 0;
for(final String pfx : hex_prefixes) {
if (str.startsWith(pfx)) {
pfxLen += pfx.length();
break;
}
}
if (pfxLen > 0) { // we have a hex number
final int hexDigits = str.length() - pfxLen;
if (hexDigits > 16) { // too many for Long
return createBigInteger(str);
}
if (hexDigits > 8) { // too many for an int
return createLong(str);
}
return createInteger(str);
}
final char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
final int decPos = str.indexOf('.');
final int expPos = str.indexOf('e') + str.indexOf('E') + 1; // assumes both not present
// if both e and E are present, this is caught by the checks on expPos (which prevent IOOBE)
// and the parsing which will detect if e or E appear in a number due to using the wrong offset
int numDecimals = 0; // Check required precision (LANG-693)
if (decPos > -1) { // there is a decimal point
if (expPos > -1) { // there is an exponent
if (expPos < decPos || expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
numDecimals = dec.length(); // gets number of digits past the decimal to ensure no loss of precision for floating point numbers.
} else {
if (expPos > -1) {
if (expPos > str.length()) { // prevents double exponent causing IOOBE
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
final String numeric = str.substring(0, str.length() - 1);
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (final NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
final Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
final Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (final NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
}
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) { // no decimal point and no exponent
//Must be an Integer, Long, Biginteger
try {
return createInteger(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
}
//Must be a Float, Double, BigDecimal
final boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
if(numDecimals <= 7){// If number has 7 or fewer digits past the decimal point then make it a float
final Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
if(numDecimals <= 16){// If number has between 8 and 16 digits past the decimal point then make it a double
final Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
}
} catch (final NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | e2ba0f4493fbd8a712d52e799903a28f4f574cff65268e0c6cbec17ed93ffc72 | @Override
@Deprecated
protected JavaType _narrow(Class<?> subclass)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
@Deprecated
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values (`Void`, `NoClass`), so can not quite do yet.
// TODO: fix in 2.8
/*
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
*/
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
// Otherwise, stitch together the hierarchy. First, super-class
// if not found, try a super-interface
// should not get here but...
}
```
| @Override
@Deprecated
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values (`Void`, `NoClass`), so can not quite do yet.
// TODO: fix in 2.8
/*
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
*/
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
// Otherwise, stitch together the hierarchy. First, super-class
// if not found, try a super-interface
// should not get here but...
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
@Deprecated
protected JavaType _narrow(Class<?> subclass)
{
if (_class == subclass) {
return this;
}
// Should we check that there is a sub-class relationship?
// 15-Jan-2016, tatu: Almost yes, but there are some complications with
// placeholder values (`Void`, `NoClass`), so can not quite do yet.
// TODO: fix in 2.8
/*
throw new IllegalArgumentException("Class "+subclass.getName()+" not sub-type of "
+_class.getName());
*/
return new SimpleType(subclass, _bindings, this, _superInterfaces,
_valueHandler, _typeHandler, _asStatic);
// Otherwise, stitch together the hierarchy. First, super-class
// if not found, try a super-interface
// should not get here but...
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | e2de61f74e23c67c0d1a06a2f4c66ab6ea22cc595447dc5c0ea168a814536808 | public static Date parse(String date, ParsePosition pos) throws ParseException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse a date from ISO-8601 formatted string. It expects a format
* [yyyy-MM-dd|yyyyMMdd][T(hh:mm[:ss[.sss]]|hhmm[ss[.sss]])]?[Z|[+-]hh[:mm]]]
*
* @param date ISO string to parse in the appropriate format.
* @param pos The position to start parsing from, updated to where parsing stopped.
* @return the parsed date
* @throws ParseException if the date is not in the appropriate format
*/
/*
/**********************************************************
/* Parsing
/**********************************************************
*/
public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
timezoneOffset = timezoneOffset.length() >= 5 ? timezoneOffset : timezoneOffset + "00";
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
}
```
| public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
timezoneOffset = timezoneOffset.length() >= 5 ? timezoneOffset : timezoneOffset + "00";
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse a date from ISO-8601 formatted string. It expects a format
* [yyyy-MM-dd|yyyyMMdd][T(hh:mm[:ss[.sss]]|hhmm[ss[.sss]])]?[Z|[+-]hh[:mm]]]
*
* @param date ISO string to parse in the appropriate format.
* @param pos The position to start parsing from, updated to where parsing stopped.
* @return the parsed date
* @throws ParseException if the date is not in the appropriate format
*/
/*
/**********************************************************
/* Parsing
/**********************************************************
*/
public static Date parse(String date, ParsePosition pos) throws ParseException {
Exception fail = null;
try {
int offset = pos.getIndex();
// extract year
int year = parseInt(date, offset, offset += 4);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract month
int month = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, '-')) {
offset += 1;
}
// extract day
int day = parseInt(date, offset, offset += 2);
// default time value
int hour = 0;
int minutes = 0;
int seconds = 0;
int milliseconds = 0; // always use 0 otherwise returned date will include millis of current time
// if the value has no time component (and no time zone), we are done
boolean hasT = checkOffset(date, offset, 'T');
if (!hasT && (date.length() <= offset)) {
Calendar calendar = new GregorianCalendar(year, month - 1, day);
pos.setIndex(offset);
return calendar.getTime();
}
if (hasT) {
// extract hours, minutes, seconds and milliseconds
hour = parseInt(date, offset += 1, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
minutes = parseInt(date, offset, offset += 2);
if (checkOffset(date, offset, ':')) {
offset += 1;
}
// second and milliseconds can be optional
if (date.length() > offset) {
char c = date.charAt(offset);
if (c != 'Z' && c != '+' && c != '-') {
seconds = parseInt(date, offset, offset += 2);
if (seconds > 59 && seconds < 63) seconds = 59; // truncate up to 3 leap seconds
// milliseconds can be optional in the format
if (checkOffset(date, offset, '.')) {
offset += 1;
int endOffset = indexOfNonDigit(date, offset + 1); // assume at least one digit
int parseEndOffset = Math.min(endOffset, offset + 3); // parse up to 3 digits
int fraction = parseInt(date, offset, parseEndOffset);
// compensate for "missing" digits
switch (parseEndOffset - offset) { // number of digits parsed
case 2:
milliseconds = fraction * 10;
break;
case 1:
milliseconds = fraction * 100;
break;
default:
milliseconds = fraction;
}
offset = endOffset;
}
}
}
}
// extract timezone
if (date.length() <= offset) {
throw new IllegalArgumentException("No time zone indicator");
}
TimeZone timezone = null;
char timezoneIndicator = date.charAt(offset);
if (timezoneIndicator == 'Z') {
timezone = TIMEZONE_UTC;
offset += 1;
} else if (timezoneIndicator == '+' || timezoneIndicator == '-') {
String timezoneOffset = date.substring(offset);
// When timezone has no minutes, we should append it, valid timezones are, for example: +00:00, +0000 and +00
timezoneOffset = timezoneOffset.length() >= 5 ? timezoneOffset : timezoneOffset + "00";
offset += timezoneOffset.length();
// 18-Jun-2015, tatu: Minor simplification, skip offset of "+0000"/"+00:00"
if ("+0000".equals(timezoneOffset) || "+00:00".equals(timezoneOffset)) {
timezone = TIMEZONE_UTC;
} else {
// 18-Jun-2015, tatu: Looks like offsets only work from GMT, not UTC...
// not sure why, but that's the way it looks. Further, Javadocs for
// `java.util.TimeZone` specifically instruct use of GMT as base for
// custom timezones... odd.
String timezoneId = "GMT" + timezoneOffset;
// String timezoneId = "UTC" + timezoneOffset;
timezone = TimeZone.getTimeZone(timezoneId);
String act = timezone.getID();
if (!act.equals(timezoneId)) {
/* 22-Jan-2015, tatu: Looks like canonical version has colons, but we may be given
* one without. If so, don't sweat.
* Yes, very inefficient. Hopefully not hit often.
* If it becomes a perf problem, add 'loose' comparison instead.
*/
String cleaned = act.replace(":", "");
if (!cleaned.equals(timezoneId)) {
throw new IndexOutOfBoundsException("Mismatching time zone indicator: "+timezoneId+" given, resolves to "
+timezone.getID());
}
}
}
} else {
throw new IndexOutOfBoundsException("Invalid time zone indicator '" + timezoneIndicator+"'");
}
Calendar calendar = new GregorianCalendar(timezone);
calendar.setLenient(false);
calendar.set(Calendar.YEAR, year);
calendar.set(Calendar.MONTH, month - 1);
calendar.set(Calendar.DAY_OF_MONTH, day);
calendar.set(Calendar.HOUR_OF_DAY, hour);
calendar.set(Calendar.MINUTE, minutes);
calendar.set(Calendar.SECOND, seconds);
calendar.set(Calendar.MILLISECOND, milliseconds);
pos.setIndex(offset);
return calendar.getTime();
// If we get a ParseException it'll already have the right message/offset.
// Other exception types can convert here.
} catch (IndexOutOfBoundsException e) {
fail = e;
} catch (NumberFormatException e) {
fail = e;
} catch (IllegalArgumentException e) {
fail = e;
}
String input = (date == null) ? null : ('"' + date + "'");
String msg = fail.getMessage();
if (msg == null || msg.isEmpty()) {
msg = "("+fail.getClass().getName()+")";
}
ParseException ex = new ParseException("Failed to parse date [" + input + "]: " + msg, pos.getIndex());
ex.initCause(fail);
throw ex;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
109 | e3256bd2417bc1cb5d835a7f19a44e1d637e395e91fd98aa4b99b886ef0acb13 | private Node parseContextTypeExpression(JsDocToken token) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* ContextTypeExpression := BasicTypeExpression | '?'
* For expressions on the right hand side of a this: or new:
*/
private Node parseContextTypeExpression(JsDocToken token) {
return parseTypeName(token);
}
```
| private Node parseContextTypeExpression(JsDocToken token) {
return parseTypeName(token);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* ContextTypeExpression := BasicTypeExpression | '?'
* For expressions on the right hand side of a this: or new:
*/
private Node parseContextTypeExpression(JsDocToken token) {
return parseTypeName(token);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | e345e5925316dbb4a8feb3afe9ca75c567333607f352405377ef3591f04597c6 | public void validate(final WriteableCommandLine commandLine)
throws OptionException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void validate(final WriteableCommandLine commandLine)
throws OptionException {
// number of options found
int present = 0;
// reference to first unexpected option
Option unexpected = null;
for (final Iterator i = options.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
// needs validation?
boolean validate = option.isRequired() || option instanceof Group;
// if the child option is present then validate it
if (commandLine.hasOption(option)) {
if (++present > maximum) {
unexpected = option;
break;
}
validate = true;
}
if (validate) {
option.validate(commandLine);
}
}
// too many options
if (unexpected != null) {
throw new OptionException(this, ResourceConstants.UNEXPECTED_TOKEN,
unexpected.getPreferredName());
}
// too few option
if (present < minimum) {
throw new OptionException(this, ResourceConstants.MISSING_OPTION);
}
// validate each anonymous argument
for (final Iterator i = anonymous.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
option.validate(commandLine);
}
}
```
| public void validate(final WriteableCommandLine commandLine)
throws OptionException {
// number of options found
int present = 0;
// reference to first unexpected option
Option unexpected = null;
for (final Iterator i = options.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
// needs validation?
boolean validate = option.isRequired() || option instanceof Group;
// if the child option is present then validate it
if (commandLine.hasOption(option)) {
if (++present > maximum) {
unexpected = option;
break;
}
validate = true;
}
if (validate) {
option.validate(commandLine);
}
}
// too many options
if (unexpected != null) {
throw new OptionException(this, ResourceConstants.UNEXPECTED_TOKEN,
unexpected.getPreferredName());
}
// too few option
if (present < minimum) {
throw new OptionException(this, ResourceConstants.MISSING_OPTION);
}
// validate each anonymous argument
for (final Iterator i = anonymous.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
option.validate(commandLine);
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void validate(final WriteableCommandLine commandLine)
throws OptionException {
// number of options found
int present = 0;
// reference to first unexpected option
Option unexpected = null;
for (final Iterator i = options.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
// needs validation?
boolean validate = option.isRequired() || option instanceof Group;
// if the child option is present then validate it
if (commandLine.hasOption(option)) {
if (++present > maximum) {
unexpected = option;
break;
}
validate = true;
}
if (validate) {
option.validate(commandLine);
}
}
// too many options
if (unexpected != null) {
throw new OptionException(this, ResourceConstants.UNEXPECTED_TOKEN,
unexpected.getPreferredName());
}
// too few option
if (present < minimum) {
throw new OptionException(this, ResourceConstants.MISSING_OPTION);
}
// validate each anonymous argument
for (final Iterator i = anonymous.iterator(); i.hasNext();) {
final Option option = (Option) i.next();
option.validate(commandLine);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | e371dac550370950d3c0c3c982510a83409ec9d8703acc75a5880c1f6ae36fd6 | private void traverse(Node node) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void traverse(Node node) {
// The goal here is to avoid retraversing
// the entire AST to catch newly created opportunities.
// So we track whether a "unit of code" has changed,
// and revisit immediately.
if (!shouldVisit(node)) {
return;
}
int visits = 0;
do {
Node c = node.getFirstChild();
while(c != null) {
traverse(c);
Node next = c.getNext();
c = next;
}
visit(node);
visits++;
Preconditions.checkState(visits < 10000, "too many interations");
} while (shouldRetraverse(node));
exitNode(node);
}
```
| private void traverse(Node node) {
// The goal here is to avoid retraversing
// the entire AST to catch newly created opportunities.
// So we track whether a "unit of code" has changed,
// and revisit immediately.
if (!shouldVisit(node)) {
return;
}
int visits = 0;
do {
Node c = node.getFirstChild();
while(c != null) {
traverse(c);
Node next = c.getNext();
c = next;
}
visit(node);
visits++;
Preconditions.checkState(visits < 10000, "too many interations");
} while (shouldRetraverse(node));
exitNode(node);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void traverse(Node node) {
// The goal here is to avoid retraversing
// the entire AST to catch newly created opportunities.
// So we track whether a "unit of code" has changed,
// and revisit immediately.
if (!shouldVisit(node)) {
return;
}
int visits = 0;
do {
Node c = node.getFirstChild();
while(c != null) {
traverse(c);
Node next = c.getNext();
c = next;
}
visit(node);
visits++;
Preconditions.checkState(visits < 10000, "too many interations");
} while (shouldRetraverse(node));
exitNode(node);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
104 | e39ac8d4aede7300fc4bb9f7a7cc8ecf68205d92062c7c4fa0d3c09def2d2f72 | JSType meet(JSType that) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
JSType meet(JSType that) {
UnionTypeBuilder builder = new UnionTypeBuilder(registry);
for (JSType alternate : alternates) {
if (alternate.isSubtype(that)) {
builder.addAlternate(alternate);
}
}
if (that instanceof UnionType) {
for (JSType otherAlternate : ((UnionType) that).alternates) {
if (otherAlternate.isSubtype(this)) {
builder.addAlternate(otherAlternate);
}
}
} else if (that.isSubtype(this)) {
builder.addAlternate(that);
}
JSType result = builder.build();
if (!result.isNoType()) {
return result;
} else if (this.isObject() && that.isObject()) {
return getNativeType(JSTypeNative.NO_OBJECT_TYPE);
} else {
return getNativeType(JSTypeNative.NO_TYPE);
}
}
```
| JSType meet(JSType that) {
UnionTypeBuilder builder = new UnionTypeBuilder(registry);
for (JSType alternate : alternates) {
if (alternate.isSubtype(that)) {
builder.addAlternate(alternate);
}
}
if (that instanceof UnionType) {
for (JSType otherAlternate : ((UnionType) that).alternates) {
if (otherAlternate.isSubtype(this)) {
builder.addAlternate(otherAlternate);
}
}
} else if (that.isSubtype(this)) {
builder.addAlternate(that);
}
JSType result = builder.build();
if (!result.isNoType()) {
return result;
} else if (this.isObject() && that.isObject()) {
return getNativeType(JSTypeNative.NO_OBJECT_TYPE);
} else {
return getNativeType(JSTypeNative.NO_TYPE);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
JSType meet(JSType that) {
UnionTypeBuilder builder = new UnionTypeBuilder(registry);
for (JSType alternate : alternates) {
if (alternate.isSubtype(that)) {
builder.addAlternate(alternate);
}
}
if (that instanceof UnionType) {
for (JSType otherAlternate : ((UnionType) that).alternates) {
if (otherAlternate.isSubtype(this)) {
builder.addAlternate(otherAlternate);
}
}
} else if (that.isSubtype(this)) {
builder.addAlternate(that);
}
JSType result = builder.build();
if (!result.isNoType()) {
return result;
} else if (this.isObject() && that.isObject()) {
return getNativeType(JSTypeNative.NO_OBJECT_TYPE);
} else {
return getNativeType(JSTypeNative.NO_TYPE);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | e49e3c78bc18a56af0985bbfa8226b2bcb35f003dcf3a25c03fb1be2ae0687ce | @Override
protected double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*/
@Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
final int p = agingA - MAXIMAL_AGING;
final double weightA = (1 << p) - 1;
final double weightB = p + 1;
targetY = (weightA * yA - weightB * REDUCTION_FACTOR * yB) / (weightA + weightB);
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
final int p = agingB - MAXIMAL_AGING;
final double weightA = p + 1;
final double weightB = (1 << p) - 1;
targetY = (weightB * yB - weightA * REDUCTION_FACTOR * yA) / (weightA + weightB);
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
}
```
| @Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
final int p = agingA - MAXIMAL_AGING;
final double weightA = (1 << p) - 1;
final double weightB = p + 1;
targetY = (weightA * yA - weightB * REDUCTION_FACTOR * yB) / (weightA + weightB);
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
final int p = agingB - MAXIMAL_AGING;
final double weightA = p + 1;
final double weightB = (1 << p) - 1;
targetY = (weightB * yB - weightA * REDUCTION_FACTOR * yA) / (weightA + weightB);
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*/
@Override
protected double doSolve() {
// prepare arrays with the first points
final double[] x = new double[maximalOrder + 1];
final double[] y = new double[maximalOrder + 1];
x[0] = getMin();
x[1] = getStartValue();
x[2] = getMax();
verifySequence(x[0], x[1], x[2]);
// evaluate initial guess
y[1] = computeObjectiveValue(x[1]);
if (Precision.equals(y[1], 0.0, 1)) {
// return the initial guess if it is a perfect root.
return x[1];
}
// evaluate first endpoint
y[0] = computeObjectiveValue(x[0]);
if (Precision.equals(y[0], 0.0, 1)) {
// return the first endpoint if it is a perfect root.
return x[0];
}
int nbPoints;
int signChangeIndex;
if (y[0] * y[1] < 0) {
// reduce interval if it brackets the root
nbPoints = 2;
signChangeIndex = 1;
} else {
// evaluate second endpoint
y[2] = computeObjectiveValue(x[2]);
if (Precision.equals(y[2], 0.0, 1)) {
// return the second endpoint if it is a perfect root.
return x[2];
}
if (y[1] * y[2] < 0) {
// use all computed point as a start sampling array for solving
nbPoints = 3;
signChangeIndex = 2;
} else {
throw new NoBracketingException(x[0], x[2], y[0], y[2]);
}
}
// prepare a work array for inverse polynomial interpolation
final double[] tmpX = new double[x.length];
// current tightest bracketing of the root
double xA = x[signChangeIndex - 1];
double yA = y[signChangeIndex - 1];
double absYA = FastMath.abs(yA);
int agingA = 0;
double xB = x[signChangeIndex];
double yB = y[signChangeIndex];
double absYB = FastMath.abs(yB);
int agingB = 0;
// search loop
while (true) {
// check convergence of bracketing interval
final double xTol = getAbsoluteAccuracy() +
getRelativeAccuracy() * FastMath.max(FastMath.abs(xA), FastMath.abs(xB));
if (((xB - xA) <= xTol) || (FastMath.max(absYA, absYB) < getFunctionValueAccuracy())) {
switch (allowed) {
case ANY_SIDE :
return absYA < absYB ? xA : xB;
case LEFT_SIDE :
return xA;
case RIGHT_SIDE :
return xB;
case BELOW_SIDE :
return (yA <= 0) ? xA : xB;
case ABOVE_SIDE :
return (yA < 0) ? xB : xA;
default :
// this should never happen
throw new MathInternalError(null);
}
}
// target for the next evaluation point
double targetY;
if (agingA >= MAXIMAL_AGING) {
// we keep updating the high bracket, try to compensate this
final int p = agingA - MAXIMAL_AGING;
final double weightA = (1 << p) - 1;
final double weightB = p + 1;
targetY = (weightA * yA - weightB * REDUCTION_FACTOR * yB) / (weightA + weightB);
} else if (agingB >= MAXIMAL_AGING) {
// we keep updating the low bracket, try to compensate this
final int p = agingB - MAXIMAL_AGING;
final double weightA = p + 1;
final double weightB = (1 << p) - 1;
targetY = (weightB * yB - weightA * REDUCTION_FACTOR * yA) / (weightA + weightB);
} else {
// bracketing is balanced, try to find the root itself
targetY = 0;
}
// make a few attempts to guess a root,
double nextX;
int start = 0;
int end = nbPoints;
do {
// guess a value for current target, using inverse polynomial interpolation
System.arraycopy(x, start, tmpX, start, end - start);
nextX = guessX(targetY, tmpX, y, start, end);
if (!((nextX > xA) && (nextX < xB))) {
// the guessed root is not strictly inside of the tightest bracketing interval
// the guessed root is either not strictly inside the interval or it
// is a NaN (which occurs when some sampling points share the same y)
// we try again with a lower interpolation order
if (signChangeIndex - start >= end - signChangeIndex) {
// we have more points before the sign change, drop the lowest point
++start;
} else {
// we have more points after sign change, drop the highest point
--end;
}
// we need to do one more attempt
nextX = Double.NaN;
}
} while (Double.isNaN(nextX) && (end - start > 1));
if (Double.isNaN(nextX)) {
// fall back to bisection
nextX = xA + 0.5 * (xB - xA);
start = signChangeIndex - 1;
end = signChangeIndex;
}
// evaluate the function at the guessed root
final double nextY = computeObjectiveValue(nextX);
if (Precision.equals(nextY, 0.0, 1)) {
// we have found an exact root, since it is not an approximation
// we don't need to bother about the allowed solutions setting
return nextX;
}
if ((nbPoints > 2) && (end - start != nbPoints)) {
// we have been forced to ignore some points to keep bracketing,
// they are probably too far from the root, drop them from now on
nbPoints = end - start;
System.arraycopy(x, start, x, 0, nbPoints);
System.arraycopy(y, start, y, 0, nbPoints);
signChangeIndex -= start;
} else if (nbPoints == x.length) {
// we have to drop one point in order to insert the new one
nbPoints--;
// keep the tightest bracketing interval as centered as possible
if (signChangeIndex >= (x.length + 1) / 2) {
// we drop the lowest point, we have to shift the arrays and the index
System.arraycopy(x, 1, x, 0, nbPoints);
System.arraycopy(y, 1, y, 0, nbPoints);
--signChangeIndex;
}
}
// insert the last computed point
//(by construction, we know it lies inside the tightest bracketing interval)
System.arraycopy(x, signChangeIndex, x, signChangeIndex + 1, nbPoints - signChangeIndex);
x[signChangeIndex] = nextX;
System.arraycopy(y, signChangeIndex, y, signChangeIndex + 1, nbPoints - signChangeIndex);
y[signChangeIndex] = nextY;
++nbPoints;
// update the bracketing interval
if (nextY * yA <= 0) {
// the sign change occurs before the inserted point
xB = nextX;
yB = nextY;
absYB = FastMath.abs(yB);
++agingA;
agingB = 0;
} else {
// the sign change occurs after the inserted point
xA = nextX;
yA = nextY;
absYA = FastMath.abs(yA);
agingA = 0;
++agingB;
// update the sign change index
signChangeIndex++;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | e55dcaf7475bcf6a21f3db61e8d7958f1e2496a9e741431fc11ad9f724d7eb88 | private void visitGetProp(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a GETPROP node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of <code>n</code>
*/
private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (n.getJSType() != null && parent.isAssign()) {
return;
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
}
```
| private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (n.getJSType() != null && parent.isAssign()) {
return;
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a GETPROP node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
* @param parent The parent of <code>n</code>
*/
private void visitGetProp(NodeTraversal t, Node n, Node parent) {
// obj.prop or obj.method()
// Lots of types can appear on the left, a call to a void function can
// never be on the left. getPropertyType will decide what is acceptable
// and what isn't.
Node property = n.getLastChild();
Node objNode = n.getFirstChild();
JSType childType = getJSType(objNode);
if (childType.isDict()) {
report(t, property, TypeValidator.ILLEGAL_PROPERTY_ACCESS, "'.'", "dict");
} else if (n.getJSType() != null && parent.isAssign()) {
return;
} else if (validator.expectNotNullOrUndefined(t, n, childType,
"No properties on this expression", getNativeType(OBJECT_TYPE))) {
checkPropertyAccess(childType, property.getString(), t, n);
}
ensureTyped(t, n);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
3 | e58c2c95c227b2be493c547c8e0af5599c6e6e9be8f1fca9e79b7ca93cfb68a3 | public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the index of the first time period to copy.
* @param end the index of the last time period to copy.
*
* @return A series containing a copy of this times series from start until
* end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
}
```
| public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the index of the first time period to copy.
* @param end the index of the last time period to copy.
*
* @return A series containing a copy of this times series from start until
* end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(int start, int end)
throws CloneNotSupportedException {
if (start < 0) {
throw new IllegalArgumentException("Requires start >= 0.");
}
if (end < start) {
throw new IllegalArgumentException("Requires start <= end.");
}
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
if (this.data.size() > 0) {
for (int index = start; index <= end; index++) {
TimeSeriesDataItem item
= (TimeSeriesDataItem) this.data.get(index);
TimeSeriesDataItem clone = (TimeSeriesDataItem) item.clone();
try {
copy.add(clone);
}
catch (SeriesException e) {
e.printStackTrace();
}
}
}
return copy;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | e5bbeadea610f4a2ce58a577c08753546e1e9cf1a1dc37795e70a4f86c6208c8 | @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
}
```
| @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
// Note! Should not skip if `property` null since that'd skip check
// for config overrides, in case of root value
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if (format.hasPattern()) {
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(format.getPattern(), loc);
TimeZone tz = format.hasTimeZone() ? format.getTimeZone()
: serializers.getTimeZone();
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
final boolean hasLocale = format.hasLocale();
final boolean hasTZ = format.hasTimeZone();
final boolean asString = (shape == JsonFormat.Shape.STRING);
if (!hasLocale && !hasTZ && !asString) {
return this;
}
DateFormat df0 = serializers.getConfig().getDateFormat();
// Jackson's own `StdDateFormat` is quite easy to deal with...
if (df0 instanceof StdDateFormat) {
StdDateFormat std = (StdDateFormat) df0;
if (format.hasLocale()) {
std = std.withLocale(format.getLocale());
}
if (format.hasTimeZone()) {
std = std.withTimeZone(format.getTimeZone());
}
return withFormat(Boolean.FALSE, std);
}
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
if (!(df0 instanceof SimpleDateFormat)) {
serializers.reportBadDefinition(handledType(), String.format(
"Configured `DateFormat` (%s) not a `SimpleDateFormat`; cannot configure `Locale` or `TimeZone`",
df0.getClass().getName()));
}
SimpleDateFormat df = (SimpleDateFormat) df0;
if (hasLocale) {
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
df = new SimpleDateFormat(df.toPattern(), format.getLocale());
} else {
df = (SimpleDateFormat) df.clone();
}
TimeZone newTz = format.getTimeZone();
boolean changeTZ = (newTz != null) && !newTz.equals(df.getTimeZone());
if (changeTZ) {
df.setTimeZone(newTz);
}
return withFormat(Boolean.FALSE, df);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
22 | e5ef48f8a98043b394aaa7713ee6e8a0ab7e3af961bdee7ba0d0dd84b74c71e7 | protected BasePeriod(long duration) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a period from the given millisecond duration with the standard period type
* and ISO rules, ensuring that the calculation is performed with the time-only period type.
* <p>
* The calculation uses the hour, minute, second and millisecond fields.
*
* @param duration the duration, in milliseconds
*/
protected BasePeriod(long duration) {
this(duration, null, null);
// bug [3264409]
}
```
| protected BasePeriod(long duration) {
this(duration, null, null);
// bug [3264409]
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a period from the given millisecond duration with the standard period type
* and ISO rules, ensuring that the calculation is performed with the time-only period type.
* <p>
* The calculation uses the hour, minute, second and millisecond fields.
*
* @param duration the duration, in milliseconds
*/
protected BasePeriod(long duration) {
this(duration, null, null);
// bug [3264409]
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | e606956e6ba6b4f3cb9d5a139a6113f03eae5a4a3c981405fd20b2d2596046a1 | @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Resolve the referenced type within the enclosing scope.
*/
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
}
```
| @Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Resolve the referenced type within the enclosing scope.
*/
@Override
JSType resolveInternal(ErrorReporter t, StaticScope<JSType> enclosing) {
// TODO(user): Investigate whether it is really necessary to keep two
// different mechanisms for resolving named types, and if so, which order
// makes more sense. Now, resolution via registry is first in order to
// avoid triggering the warnings built into the resolution via properties.
boolean resolved = resolveViaRegistry(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
if (resolved) {
super.resolveInternal(t, enclosing);
finishPropertyContinuations();
return registry.isLastGeneration() ?
getReferencedType() : this;
}
resolveViaProperties(t, enclosing);
if (detectInheritanceCycle()) {
handleTypeCycle(t);
}
super.resolveInternal(t, enclosing);
if (isResolved()) {
finishPropertyContinuations();
}
return registry.isLastGeneration() ?
getReferencedType() : this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | e60de68fe31a45476d4f1f2d48a5ca6e55a6391062dbe7581118a93bdfcfa0d1 | public ZipArchiveInputStream(InputStream inputStream,
String encoding,
boolean useUnicodeExtraFields,
boolean allowStoredEntriesWithDataDescriptor) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @param encoding the encoding to use for file names, use null
* for the platform's default encoding
* @param useUnicodeExtraFields whether to use InfoZIP Unicode
* Extra Fields (if present) to set the file names.
* @param allowStoredEntriesWithDataDescriptor whether the stream
* will try to read STORED entries that use a data descriptor
* @since 1.1
*/
public ZipArchiveInputStream(InputStream inputStream,
String encoding,
boolean useUnicodeExtraFields,
boolean allowStoredEntriesWithDataDescriptor) {
zipEncoding = ZipEncodingHelper.getZipEncoding(encoding);
this.useUnicodeExtraFields = useUnicodeExtraFields;
in = new PushbackInputStream(inputStream, buf.capacity());
this.allowStoredEntriesWithDataDescriptor =
allowStoredEntriesWithDataDescriptor;
// haven't read anything so far
}
```
| public ZipArchiveInputStream(InputStream inputStream,
String encoding,
boolean useUnicodeExtraFields,
boolean allowStoredEntriesWithDataDescriptor) {
zipEncoding = ZipEncodingHelper.getZipEncoding(encoding);
this.useUnicodeExtraFields = useUnicodeExtraFields;
in = new PushbackInputStream(inputStream, buf.capacity());
this.allowStoredEntriesWithDataDescriptor =
allowStoredEntriesWithDataDescriptor;
// haven't read anything so far
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @param encoding the encoding to use for file names, use null
* for the platform's default encoding
* @param useUnicodeExtraFields whether to use InfoZIP Unicode
* Extra Fields (if present) to set the file names.
* @param allowStoredEntriesWithDataDescriptor whether the stream
* will try to read STORED entries that use a data descriptor
* @since 1.1
*/
public ZipArchiveInputStream(InputStream inputStream,
String encoding,
boolean useUnicodeExtraFields,
boolean allowStoredEntriesWithDataDescriptor) {
zipEncoding = ZipEncodingHelper.getZipEncoding(encoding);
this.useUnicodeExtraFields = useUnicodeExtraFields;
in = new PushbackInputStream(inputStream, buf.capacity());
this.allowStoredEntriesWithDataDescriptor =
allowStoredEntriesWithDataDescriptor;
// haven't read anything so far
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | e673e73f830fd0f7bf1da0d8fb71bac733f498bc401c2722b831cec459779c2e | private void readTypeVariables() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeParametersOn(new TypeVariable[] { typeVariable });
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
}
```
| private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeParametersOn(new TypeVariable[] { typeVariable });
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeParametersOn(new TypeVariable[] { typeVariable });
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | e6783247032d4105d11e5c4d9a1466d31295a75f86721fc5b9938c61ffec52e2 | protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
throw new IllegalStateException("Total width is less than the width of the argument and indent " +
"- no room for the description");
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
```
| protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
throw new IllegalStateException("Total width is less than the width of the argument and indent " +
"- no room for the description");
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
throw new IllegalStateException("Total width is less than the width of the argument and indent " +
"- no room for the description");
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
101 | e6a2f770ff64810ac469bbe72440dfe1f12bf6844aa7e2a36d20d1d5fbbf04e0 | @SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithUnwrapped(JsonParser p, DeserializationContext ctxt)
throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithUnwrapped(JsonParser p, DeserializationContext ctxt)
throws IOException
{
// 01-Dec-2016, tatu: Note: This IS legal to call, but only when unwrapped
// value itself is NOT passed via `CreatorProperty` (which isn't supported).
// Ok however to pass via setter or field.
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p, ctxt);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// Last creator property to set?
if (buffer.assignParameter(creatorProp,
_deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
bean = wrapInstantiationProblem(e, ctxt);
}
// [databind#631]: Assign current value, to be accessible by custom serializers
p.setCurrentValue(bean);
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
// NOTE: do NOT skip name as it needs to be copied; `copyCurrentStructure` does that
p.nextToken();
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
// 28-Aug-2018, tatu: Let's add sanity check here, easier to catch off-by-some
// problems if we maintain invariants
tokens.writeEndObject();
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could probably support; but for now
// it's too complicated, so bail out
ctxt.reportInputMismatch(creatorProp,
"Cannot create polymorphic instances with unwrapped values");
return null;
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, _deserializeWithErrorWrapping(p, ctxt, prop));
continue;
}
// Things marked as ignorable should not be passed to any setter
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// 29-Nov-2016, tatu: probably should try to avoid sending content
// both to any setter AND buffer... but, for now, the only thing
// we can do.
// how about any setter? We'll get copies but...
if (_anySetter == null) {
// but... others should be passed to unwrapped property deserializers
tokens.writeFieldName(propName);
tokens.copyCurrentStructure(p);
} else {
// Need to copy to a separate buffer first
TokenBuffer b2 = TokenBuffer.asCopyOfValue(p);
tokens.writeFieldName(propName);
tokens.append(b2);
try {
buffer.bufferAnyProperty(_anySetter, propName,
_anySetter.deserialize(b2.asParserOnFirstToken(), ctxt));
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
}
continue;
}
}
// We hit END_OBJECT, so:
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
}
```
| @SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithUnwrapped(JsonParser p, DeserializationContext ctxt)
throws IOException
{
// 01-Dec-2016, tatu: Note: This IS legal to call, but only when unwrapped
// value itself is NOT passed via `CreatorProperty` (which isn't supported).
// Ok however to pass via setter or field.
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p, ctxt);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// Last creator property to set?
if (buffer.assignParameter(creatorProp,
_deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
bean = wrapInstantiationProblem(e, ctxt);
}
// [databind#631]: Assign current value, to be accessible by custom serializers
p.setCurrentValue(bean);
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
// NOTE: do NOT skip name as it needs to be copied; `copyCurrentStructure` does that
p.nextToken();
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
// 28-Aug-2018, tatu: Let's add sanity check here, easier to catch off-by-some
// problems if we maintain invariants
tokens.writeEndObject();
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could probably support; but for now
// it's too complicated, so bail out
ctxt.reportInputMismatch(creatorProp,
"Cannot create polymorphic instances with unwrapped values");
return null;
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, _deserializeWithErrorWrapping(p, ctxt, prop));
continue;
}
// Things marked as ignorable should not be passed to any setter
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// 29-Nov-2016, tatu: probably should try to avoid sending content
// both to any setter AND buffer... but, for now, the only thing
// we can do.
// how about any setter? We'll get copies but...
if (_anySetter == null) {
// but... others should be passed to unwrapped property deserializers
tokens.writeFieldName(propName);
tokens.copyCurrentStructure(p);
} else {
// Need to copy to a separate buffer first
TokenBuffer b2 = TokenBuffer.asCopyOfValue(p);
tokens.writeFieldName(propName);
tokens.append(b2);
try {
buffer.bufferAnyProperty(_anySetter, propName,
_anySetter.deserialize(b2.asParserOnFirstToken(), ctxt));
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
}
continue;
}
}
// We hit END_OBJECT, so:
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@SuppressWarnings("resource")
protected Object deserializeUsingPropertyBasedWithUnwrapped(JsonParser p, DeserializationContext ctxt)
throws IOException
{
// 01-Dec-2016, tatu: Note: This IS legal to call, but only when unwrapped
// value itself is NOT passed via `CreatorProperty` (which isn't supported).
// Ok however to pass via setter or field.
final PropertyBasedCreator creator = _propertyBasedCreator;
PropertyValueBuffer buffer = creator.startBuilding(p, ctxt, _objectIdReader);
TokenBuffer tokens = new TokenBuffer(p, ctxt);
tokens.writeStartObject();
JsonToken t = p.getCurrentToken();
for (; t == JsonToken.FIELD_NAME; t = p.nextToken()) {
String propName = p.getCurrentName();
p.nextToken(); // to point to value
// creator property?
SettableBeanProperty creatorProp = creator.findCreatorProperty(propName);
if (creatorProp != null) {
// Last creator property to set?
if (buffer.assignParameter(creatorProp,
_deserializeWithErrorWrapping(p, ctxt, creatorProp))) {
t = p.nextToken(); // to move to following FIELD_NAME/END_OBJECT
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
bean = wrapInstantiationProblem(e, ctxt);
}
// [databind#631]: Assign current value, to be accessible by custom serializers
p.setCurrentValue(bean);
// if so, need to copy all remaining tokens into buffer
while (t == JsonToken.FIELD_NAME) {
// NOTE: do NOT skip name as it needs to be copied; `copyCurrentStructure` does that
p.nextToken();
tokens.copyCurrentStructure(p);
t = p.nextToken();
}
// 28-Aug-2018, tatu: Let's add sanity check here, easier to catch off-by-some
// problems if we maintain invariants
tokens.writeEndObject();
if (bean.getClass() != _beanType.getRawClass()) {
// !!! 08-Jul-2011, tatu: Could probably support; but for now
// it's too complicated, so bail out
ctxt.reportInputMismatch(creatorProp,
"Cannot create polymorphic instances with unwrapped values");
return null;
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
}
continue;
}
// Object Id property?
if (buffer.readIdProperty(propName)) {
continue;
}
// regular property? needs buffering
SettableBeanProperty prop = _beanProperties.find(propName);
if (prop != null) {
buffer.bufferProperty(prop, _deserializeWithErrorWrapping(p, ctxt, prop));
continue;
}
// Things marked as ignorable should not be passed to any setter
if (_ignorableProps != null && _ignorableProps.contains(propName)) {
handleIgnoredProperty(p, ctxt, handledType(), propName);
continue;
}
// 29-Nov-2016, tatu: probably should try to avoid sending content
// both to any setter AND buffer... but, for now, the only thing
// we can do.
// how about any setter? We'll get copies but...
if (_anySetter == null) {
// but... others should be passed to unwrapped property deserializers
tokens.writeFieldName(propName);
tokens.copyCurrentStructure(p);
} else {
// Need to copy to a separate buffer first
TokenBuffer b2 = TokenBuffer.asCopyOfValue(p);
tokens.writeFieldName(propName);
tokens.append(b2);
try {
buffer.bufferAnyProperty(_anySetter, propName,
_anySetter.deserialize(b2.asParserOnFirstToken(), ctxt));
} catch (Exception e) {
wrapAndThrow(e, _beanType.getRawClass(), propName, ctxt);
}
continue;
}
}
// We hit END_OBJECT, so:
Object bean;
try {
bean = creator.build(ctxt, buffer);
} catch (Exception e) {
wrapInstantiationProblem(e, ctxt);
return null; // never gets here
}
return _unwrappedPropertyHandler.processUnwrapped(p, ctxt, bean, tokens);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | e6fcebdd8f10de857196cb7c643b2b5a828900aeea8a7e7000eeceb098eafcfd | protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>An implementation of {@link Parser}'s abstract
* {@link Parser#flatten(Options,String[],boolean) flatten} method.</p>
*
* <p>The following are the rules used by this flatten method.
* <ol>
* <li>if <code>stopAtNonOption</code> is <b>true</b> then do not
* burst anymore of <code>arguments</code> entries, just add each
* successive entry without further processing. Otherwise, ignore
* <code>stopAtNonOption</code>.</li>
* <li>if the current <code>arguments</code> entry is "<b>--</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is "<b>-</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is two characters
* in length and the first character is "<b>-</b>" then check if this
* is a valid {@link Option} id. If it is a valid id, then add the
* entry to the list of processed tokens and set the current {@link Option}
* member. If it is not a valid id and <code>stopAtNonOption</code>
* is true, then the remaining entries are copied to the list of
* processed tokens. Otherwise, the current entry is ignored.</li>
* <li>if the current <code>arguments</code> entry is more than two
* characters in length and the first character is "<b>-</b>" then
* we need to burst the entry to determine its constituents. For more
* information on the bursting algorithm see
* {@link PosixParser#burstToken(String, boolean) burstToken}.</li>
* <li>if the current <code>arguments</code> entry is not handled
* by any of the previous rules, then the entry is added to the list
* of processed tokens.</li>
* </ol>
* </p>
*
* @param options The command line {@link Options}
* @param arguments The command line arguments to be parsed
* @param stopAtNonOption Specifies whether to stop flattening
* when an non option is found.
* @return The flattened <code>arguments</code> String array.
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
int pos = token.indexOf('=');
String opt = pos == -1 ? token : token.substring(0, pos); // --foo
if (!options.hasOption(opt) && stopAtNonOption)
{
process(token);
}
else
{
tokens.add(opt);
if (pos != -1) {
tokens.add(token.substring(pos + 1));
}
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
```
| protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
int pos = token.indexOf('=');
String opt = pos == -1 ? token : token.substring(0, pos); // --foo
if (!options.hasOption(opt) && stopAtNonOption)
{
process(token);
}
else
{
tokens.add(opt);
if (pos != -1) {
tokens.add(token.substring(pos + 1));
}
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>An implementation of {@link Parser}'s abstract
* {@link Parser#flatten(Options,String[],boolean) flatten} method.</p>
*
* <p>The following are the rules used by this flatten method.
* <ol>
* <li>if <code>stopAtNonOption</code> is <b>true</b> then do not
* burst anymore of <code>arguments</code> entries, just add each
* successive entry without further processing. Otherwise, ignore
* <code>stopAtNonOption</code>.</li>
* <li>if the current <code>arguments</code> entry is "<b>--</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is "<b>-</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is two characters
* in length and the first character is "<b>-</b>" then check if this
* is a valid {@link Option} id. If it is a valid id, then add the
* entry to the list of processed tokens and set the current {@link Option}
* member. If it is not a valid id and <code>stopAtNonOption</code>
* is true, then the remaining entries are copied to the list of
* processed tokens. Otherwise, the current entry is ignored.</li>
* <li>if the current <code>arguments</code> entry is more than two
* characters in length and the first character is "<b>-</b>" then
* we need to burst the entry to determine its constituents. For more
* information on the bursting algorithm see
* {@link PosixParser#burstToken(String, boolean) burstToken}.</li>
* <li>if the current <code>arguments</code> entry is not handled
* by any of the previous rules, then the entry is added to the list
* of processed tokens.</li>
* </ol>
* </p>
*
* @param options The command line {@link Options}
* @param arguments The command line arguments to be parsed
* @param stopAtNonOption Specifies whether to stop flattening
* when an non option is found.
* @return The flattened <code>arguments</code> String array.
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
int pos = token.indexOf('=');
String opt = pos == -1 ? token : token.substring(0, pos); // --foo
if (!options.hasOption(opt) && stopAtNonOption)
{
process(token);
}
else
{
tokens.add(opt);
if (pos != -1) {
tokens.add(token.substring(pos + 1));
}
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
74 | e7737cff4fafe352465a6dd1c59b7845b91f7bea4053cef5a91beb1be19266a7 | @Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale;
if (vecAbsoluteTolerance == null) {
scale = new double[y0.length];
java.util.Arrays.fill(scale, scalAbsoluteTolerance);
} else {
scale = vecAbsoluteTolerance;
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
}
```
| @Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale;
if (vecAbsoluteTolerance == null) {
scale = new double[y0.length];
java.util.Arrays.fill(scale, scalAbsoluteTolerance);
} else {
scale = vecAbsoluteTolerance;
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale;
if (vecAbsoluteTolerance == null) {
scale = new double[y0.length];
java.util.Arrays.fill(scale, scalAbsoluteTolerance);
} else {
scale = vecAbsoluteTolerance;
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
69 | e78e6d4c81472397a4c5d4c9925c4d9a8a5e9236064b940fc4d8e76e2a246af1 | private void visitCall(NodeTraversal t, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits a CALL node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
*/
private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
}
```
| private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits a CALL node.
*
* @param t The node traversal object that supplies context, such as the
* scope chain to use in name lookups as well as error reporting.
* @param n The node being visited.
*/
private void visitCall(NodeTraversal t, Node n) {
Node child = n.getFirstChild();
JSType childType = getJSType(child).restrictByNotNullOrUndefined();
if (!childType.canBeCalled()) {
report(t, n, NOT_CALLABLE, childType.toString());
ensureTyped(t, n);
return;
}
// A couple of types can be called as if they were functions.
// If it is a function type, then validate parameters.
if (childType instanceof FunctionType) {
FunctionType functionType = (FunctionType) childType;
boolean isExtern = false;
JSDocInfo functionJSDocInfo = functionType.getJSDocInfo();
if(functionJSDocInfo != null) {
String sourceName = functionJSDocInfo.getSourceName();
CompilerInput functionSource = compiler.getInput(sourceName);
isExtern = functionSource.isExtern();
}
// Non-native constructors should not be called directly
// unless they specify a return type and are defined
// in an extern.
if (functionType.isConstructor() &&
!functionType.isNativeObjectType() &&
(functionType.getReturnType().isUnknownType() ||
functionType.getReturnType().isVoidType() ||
!isExtern)) {
report(t, n, CONSTRUCTOR_NOT_CALLABLE, childType.toString());
}
// Functions with explcit 'this' types must be called in a GETPROP
// or GETELEM.
visitParameterList(t, n, functionType);
ensureTyped(t, n, functionType.getReturnType());
} else {
ensureTyped(t, n);
}
// TODO: Add something to check for calls of RegExp objects, which is not
// supported by IE. Either say something about the return type or warn
// about the non-portability of the call or both.
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | e79de3a3a1c516a08f5bb78706bb7f470613fbec7dfd70d3b8ea8daab1c1c321 | int nextIndexOf(CharSequence seq) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the number of characters between the current position and the next instance of the input sequence
*
* @param seq scan target
* @return offset between current position and next instance of target. -1 if not found.
*/
int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length && last <= length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
}
```
| int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length && last <= length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the number of characters between the current position and the next instance of the input sequence
*
* @param seq scan target
* @return offset between current position and next instance of target. -1 if not found.
*/
int nextIndexOf(CharSequence seq) {
// doesn't handle scanning for surrogates
char startChar = seq.charAt(0);
for (int offset = pos; offset < length; offset++) {
// scan to first instance of startchar:
if (startChar != input[offset])
while(++offset < length && startChar != input[offset]);
int i = offset + 1;
int last = i + seq.length()-1;
if (offset < length && last <= length) {
for (int j = 1; i < last && seq.charAt(j) == input[i]; i++, j++);
if (i == last) // found full sequence
return offset - pos;
}
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
131 | e7a7ad0d9e3bfb1dac672fafbc305bb6889a2006c6cdaba50defe87e08ae4268 | public static boolean isJSIdentifier(String s) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
}
```
| public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public static boolean isJSIdentifier(String s) {
int length = s.length();
if (length == 0 ||
!Character.isJavaIdentifierStart(s.charAt(0))) {
return false;
}
for (int i = 1; i < length; i++) {
if (
!Character.isJavaIdentifierPart(s.charAt(i))) {
return false;
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
101 | e7ea9d073125e33b541bcca589091606b44ec4f67a382042deba324afa13ddf0 | @Override
protected CompilerOptions createOptions() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
if (flags.process_closure_primitives) {
options.closurePass = true;
}
initOptionsFromFlags(options);
return options;
}
```
| @Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
if (flags.process_closure_primitives) {
options.closurePass = true;
}
initOptionsFromFlags(options);
return options;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
protected CompilerOptions createOptions() {
CompilerOptions options = new CompilerOptions();
options.setCodingConvention(new ClosureCodingConvention());
CompilationLevel level = flags.compilation_level;
level.setOptionsForCompilationLevel(options);
if (flags.debug) {
level.setDebugOptionsForCompilationLevel(options);
}
WarningLevel wLevel = flags.warning_level;
wLevel.setOptionsForWarningLevel(options);
for (FormattingOption formattingOption : flags.formatting) {
formattingOption.applyToOptions(options);
}
if (flags.process_closure_primitives) {
options.closurePass = true;
}
initOptionsFromFlags(options);
return options;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
117 | e7f2bdfb0cb7c8f610add94f8f8454bacfec803959c1a3cd1552e49b23804b57 | String getReadableJSTypeName(Node n, boolean dereference) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Given a node, get a human-readable name for the type of that node so
* that will be easy for the programmer to find the original declaration.
*
* For example, if SubFoo's property "bar" might have the human-readable
* name "Foo.prototype.bar".
*
* @param n The node.
* @param dereference If true, the type of the node will be dereferenced
* to an Object type, if possible.
*/
String getReadableJSTypeName(Node n, boolean dereference) {
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
// The best type name is the actual type name.
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
}
```
| String getReadableJSTypeName(Node n, boolean dereference) {
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
// The best type name is the actual type name.
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Given a node, get a human-readable name for the type of that node so
* that will be easy for the programmer to find the original declaration.
*
* For example, if SubFoo's property "bar" might have the human-readable
* name "Foo.prototype.bar".
*
* @param n The node.
* @param dereference If true, the type of the node will be dereferenced
* to an Object type, if possible.
*/
String getReadableJSTypeName(Node n, boolean dereference) {
JSType type = getJSType(n);
if (dereference) {
ObjectType dereferenced = type.dereference();
if (dereferenced != null) {
type = dereferenced;
}
}
// The best type name is the actual type name.
if (type.isFunctionPrototypeType() ||
(type.toObjectType() != null &&
type.toObjectType().getConstructor() != null)) {
return type.toString();
}
// If we're analyzing a GETPROP, the property may be inherited by the
// prototype chain. So climb the prototype chain and find out where
// the property was originally defined.
if (n.isGetProp()) {
ObjectType objectType = getJSType(n.getFirstChild()).dereference();
if (objectType != null) {
String propName = n.getLastChild().getString();
if (objectType.getConstructor() != null &&
objectType.getConstructor().isInterface()) {
objectType = FunctionType.getTopDefiningInterface(
objectType, propName);
} else {
// classes
while (objectType != null && !objectType.hasOwnProperty(propName)) {
objectType = objectType.getImplicitPrototype();
}
}
// Don't show complex function names or anonymous types.
// Instead, try to get a human-readable type name.
if (objectType != null &&
(objectType.getConstructor() != null ||
objectType.isFunctionPrototypeType())) {
return objectType.toString() + "." + propName;
}
}
}
String qualifiedName = n.getQualifiedName();
if (qualifiedName != null) {
return qualifiedName;
} else if (type.isFunctionType()) {
// Don't show complex function names.
return "function";
} else {
return type.toString();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | e853f33f2eea5afb04e0f0101ea8701a6a18c5e78d6ef75a619ef7394902046d | private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// the original object is needed so can check for Number
/*
* Note: must only be called if quoting is enabled, otherwise will generate NPE
*/
private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
case ALL_NON_NULL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
}
```
| private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
case ALL_NON_NULL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// the original object is needed so can check for Number
/*
* Note: must only be called if quoting is enabled, otherwise will generate NPE
*/
private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
case ALL_NON_NULL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | e8694948bf91acd220cd8b8317e48e418cd2c4e53fe245ae3cfc0498cc754ef9 | @Override public void skipValue() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
pathNames[stackSize - 1] = "null";
}
pathIndices[stackSize - 1]++;
}
```
| @Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
pathNames[stackSize - 1] = "null";
}
pathIndices[stackSize - 1]++;
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override public void skipValue() throws IOException {
if (peek() == JsonToken.NAME) {
nextName();
pathNames[stackSize - 2] = "null";
} else {
popStack();
pathNames[stackSize - 1] = "null";
}
pathIndices[stackSize - 1]++;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
166 | e885b2ef3418eb89c53f109fcb5420ef42068541b00ea1ff7d1783baacb9dd93 | @Override
public void matchConstraint(JSType constraint) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
}
}
```
| @Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void matchConstraint(JSType constraint) {
// We only want to match constraints on anonymous types.
if (hasReferenceName()) {
return;
}
// Handle the case where the constraint object is a record type.
//
// param constraint {{prop: (number|undefined)}}
// function f(constraint) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraint.isRecordType()) {
matchRecordTypeConstraint(constraint.toObjectType());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
96 | e889e20916b39e234499e2bbe0c4880896628d2db28678323a1ff0f9a0071874 | protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Helper method called when there is the explicit "is-creator", but no mode declaration.
*
* @since 2.9.2
*/
protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.paramName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
}
```
| protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.paramName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Helper method called when there is the explicit "is-creator", but no mode declaration.
*
* @since 2.9.2
*/
protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.paramName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | e8942952de0a54400ffb3d74bd990bb514f7808b8ab62e6ae4510f05966719f1 | @Override
public int translate(CharSequence input, int index, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*/
@Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
// TODO: Protect from ArrayIndexOutOfBounds
if(input.charAt(index) == '&' && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
}
int end = start;
while(input.charAt(end) != ';') {
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
return 0;
}
out.write(entityValue);
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
}
```
| @Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
// TODO: Protect from ArrayIndexOutOfBounds
if(input.charAt(index) == '&' && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
}
int end = start;
while(input.charAt(end) != ';') {
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
return 0;
}
out.write(entityValue);
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*/
@Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
// TODO: Protect from ArrayIndexOutOfBounds
if(input.charAt(index) == '&' && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
}
int end = start;
while(input.charAt(end) != ';') {
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
return 0;
}
out.write(entityValue);
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | e921fd2d51f1f8f1b2eafb3856efbd9658cd2fd6e73c8148a8c033aebdd28c2a | public Dfp multiply(final int x) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** Multiply this by a single digit x.
* @param x multiplicand
* @return product of this and x
*/
public Dfp multiply(final int x) {
return multiplyFast(x);
}
```
| public Dfp multiply(final int x) {
return multiplyFast(x);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** Multiply this by a single digit x.
* @param x multiplicand
* @return product of this and x
*/
public Dfp multiply(final int x) {
return multiplyFast(x);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
47 | e93835436e146e491ff08897deb79f1081b2868b0b3340b78d6f0e32b4f55bd7 | static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
// escape when in character data or when in a xml attribue val; not needed in html attr val
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
```
| static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
// escape when in character data or when in a xml attribue val; not needed in html attr val
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
// escape when in character data or when in a xml attribue val; not needed in html attr val
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | e98d2923d17708bd45744f8f4e88bbf4021afa56fa992491eb30023389ed0f1d | @Override
protected UnivariatePointValuePair doOptimize() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return best(current, previous, isMinim);
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return best(current, previous, isMinim);
}
++iter;
}
}
```
| @Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return best(current, previous, isMinim);
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return best(current, previous, isMinim);
}
++iter;
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return best(current, previous, isMinim);
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return best(current, previous, isMinim);
}
++iter;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | e99f4d9d3db76a9417b38a0d6e10f426c97be1e250844350ef3b0baa8c9757a3 | @Override
public JsonToken nextToken() throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
//Check for _allowMultipleMatches - false and atleast there is one token - which is _currToken
// check for no buffered context _exposedContext - null
//If all the conditions matches then check for scalar / non-scalar property
if(!_allowMultipleMatches && _currToken != null && _exposedContext == null){
//if not scalar and ended successfully, then return null
if((_currToken.isStructEnd() && _headContext.isStartHandled()) ){
return (_currToken = null);
}
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
else if(_currToken.isScalarValue() && !_headContext.isStartHandled() && !_includePath
&& _itemFilter == TokenFilter.INCLUDE_ALL) {
return (_currToken = null);
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
return (_currToken = t);
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
```
| @Override
public JsonToken nextToken() throws IOException
{
//Check for _allowMultipleMatches - false and atleast there is one token - which is _currToken
// check for no buffered context _exposedContext - null
//If all the conditions matches then check for scalar / non-scalar property
if(!_allowMultipleMatches && _currToken != null && _exposedContext == null){
//if not scalar and ended successfully, then return null
if((_currToken.isStructEnd() && _headContext.isStartHandled()) ){
return (_currToken = null);
}
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
else if(_currToken.isScalarValue() && !_headContext.isStartHandled() && !_includePath
&& _itemFilter == TokenFilter.INCLUDE_ALL) {
return (_currToken = null);
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
return (_currToken = t);
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
//Check for _allowMultipleMatches - false and atleast there is one token - which is _currToken
// check for no buffered context _exposedContext - null
//If all the conditions matches then check for scalar / non-scalar property
if(!_allowMultipleMatches && _currToken != null && _exposedContext == null){
//if not scalar and ended successfully, then return null
if((_currToken.isStructEnd() && _headContext.isStartHandled()) ){
return (_currToken = null);
}
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
else if(_currToken.isScalarValue() && !_headContext.isStartHandled() && !_includePath
&& _itemFilter == TokenFilter.INCLUDE_ALL) {
return (_currToken = null);
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
return (_currToken = t);
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | eb7568d40bf32fbdd458e3e09d48377ce53c162aa7e26d6e433e00ce6a98a53c | @Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
if (value instanceof Date) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else {
str = value.toString();
}
jgen.writeFieldName(str);
}
```
| @Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
if (value instanceof Date) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else {
str = value.toString();
}
jgen.writeFieldName(str);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
if (value instanceof Date) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else {
str = value.toString();
}
jgen.writeFieldName(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | eb96dc28802d9ec5b9b46b6ef572495ee6d4d44330e7b2d0c41e62e38602b512 | private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a fraction given the double value and either the maximum error
* allowed or the maximum number of denominator digits.
* <p>
*
* NOTE: This constructor is called with EITHER
* - a valid epsilon value and the maxDenominator set to Integer.MAX_VALUE
* (that way the maxDenominator has no effect).
* OR
* - a valid maxDenominator value and the epsilon value set to zero
* (that way epsilon only has effect if there is an exact match before
* the maxDenominator value is reached).
* </p><p>
*
* It has been done this way so that the same code can be (re)used for both
* scenarios. However this could be confusing to users if it were part of
* the public API and this constructor should therefore remain PRIVATE.
* </p>
*
* See JIRA issue ticket MATH-181 for more details:
*
* https://issues.apache.org/jira/browse/MATH-181
*
* @param value the double value to convert to a fraction.
* @param epsilon maximum error allowed. The resulting fraction is within
* {@code epsilon} of {@code value}, in absolute terms.
* @param maxDenominator maximum denominator value allowed.
* @param maxIterations maximum number of convergents
* @throws FractionConversionException if the continued fraction failed to
* converge.
*/
private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (a0 > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((p2 > overflow) || (q2 > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
}
```
| private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (a0 > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((p2 > overflow) || (q2 > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a fraction given the double value and either the maximum error
* allowed or the maximum number of denominator digits.
* <p>
*
* NOTE: This constructor is called with EITHER
* - a valid epsilon value and the maxDenominator set to Integer.MAX_VALUE
* (that way the maxDenominator has no effect).
* OR
* - a valid maxDenominator value and the epsilon value set to zero
* (that way epsilon only has effect if there is an exact match before
* the maxDenominator value is reached).
* </p><p>
*
* It has been done this way so that the same code can be (re)used for both
* scenarios. However this could be confusing to users if it were part of
* the public API and this constructor should therefore remain PRIVATE.
* </p>
*
* See JIRA issue ticket MATH-181 for more details:
*
* https://issues.apache.org/jira/browse/MATH-181
*
* @param value the double value to convert to a fraction.
* @param epsilon maximum error allowed. The resulting fraction is within
* {@code epsilon} of {@code value}, in absolute terms.
* @param maxDenominator maximum denominator value allowed.
* @param maxIterations maximum number of convergents
* @throws FractionConversionException if the continued fraction failed to
* converge.
*/
private Fraction(double value, double epsilon, int maxDenominator, int maxIterations)
throws FractionConversionException
{
long overflow = Integer.MAX_VALUE;
double r0 = value;
long a0 = (long)FastMath.floor(r0);
if (a0 > overflow) {
throw new FractionConversionException(value, a0, 1l);
}
// check for (almost) integer arguments, which should not go
// to iterations.
if (FastMath.abs(a0 - value) < epsilon) {
this.numerator = (int) a0;
this.denominator = 1;
return;
}
long p0 = 1;
long q0 = 0;
long p1 = a0;
long q1 = 1;
long p2 = 0;
long q2 = 1;
int n = 0;
boolean stop = false;
do {
++n;
double r1 = 1.0 / (r0 - a0);
long a1 = (long)FastMath.floor(r1);
p2 = (a1 * p1) + p0;
q2 = (a1 * q1) + q0;
if ((p2 > overflow) || (q2 > overflow)) {
throw new FractionConversionException(value, p2, q2);
}
double convergent = (double)p2 / (double)q2;
if (n < maxIterations && FastMath.abs(convergent - value) > epsilon && q2 < maxDenominator) {
p0 = p1;
p1 = p2;
q0 = q1;
q1 = q2;
a0 = a1;
r0 = r1;
} else {
stop = true;
}
} while (!stop);
if (n >= maxIterations) {
throw new FractionConversionException(value, maxIterations);
}
if (q2 < maxDenominator) {
this.numerator = (int) p2;
this.denominator = (int) q2;
} else {
this.numerator = (int) p1;
this.denominator = (int) q1;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | ebe2d7b1d49fd92f503fdcd13ccbec7945193415828e3cb52ad3efd98be9c738 | public void writeEmbeddedObject(Object object) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method that can be called on backends that support passing opaque datatypes of
* non-JSON formats
*
* @since 2.8
*/
public void writeEmbeddedObject(Object object) throws IOException {
// 01-Sep-2016, tatu: As per [core#318], handle small number of cases
throw new JsonGenerationException("No native support for writing embedded objects",
this);
}
```
| public void writeEmbeddedObject(Object object) throws IOException {
// 01-Sep-2016, tatu: As per [core#318], handle small number of cases
throw new JsonGenerationException("No native support for writing embedded objects",
this);
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method that can be called on backends that support passing opaque datatypes of
* non-JSON formats
*
* @since 2.8
*/
public void writeEmbeddedObject(Object object) throws IOException {
// 01-Sep-2016, tatu: As per [core#318], handle small number of cases
throw new JsonGenerationException("No native support for writing embedded objects",
this);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | ec09241f2513ab0363415906397b8872a3d21be37aa11833881a5cc3995da6a8 | @Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
Class<?> cls = value.getClass();
if (cls == String.class) {
str = (String) value;
} else if (Date.class.isAssignableFrom(cls)) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else if (cls == Class.class) {
str = ((Class<?>) value).getName();
} else {
str = value.toString();
}
jgen.writeFieldName(str);
}
```
| @Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
Class<?> cls = value.getClass();
if (cls == String.class) {
str = (String) value;
} else if (Date.class.isAssignableFrom(cls)) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else if (cls == Class.class) {
str = ((Class<?>) value).getName();
} else {
str = value.toString();
}
jgen.writeFieldName(str);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void serialize(Object value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
String str;
Class<?> cls = value.getClass();
if (cls == String.class) {
str = (String) value;
} else if (Date.class.isAssignableFrom(cls)) {
provider.defaultSerializeDateKey((Date) value, jgen);
return;
} else if (cls == Class.class) {
str = ((Class<?>) value).getName();
} else {
str = value.toString();
}
jgen.writeFieldName(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
30 | ec67a2c56e08fb26ade4312de4bcad8b25ef231b4b6743782c15e50b320c04f4 | @Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
* (non-Javadoc)
*
* @see java.io.InputStream#read(byte[], int, int)
*/
@Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
if (len == 0) {
return 0;
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
}
```
| @Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
if (len == 0) {
return 0;
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
* (non-Javadoc)
*
* @see java.io.InputStream#read(byte[], int, int)
*/
@Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
if (len == 0) {
return 0;
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | ec72e9f19769186ea1698745e3676fbf2ac42db5828d791fe1bd5fe2d81acbd0 | @Override
protected UnivariatePointValuePair doOptimize() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return current;
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return current;
}
++iter;
}
}
```
| @Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return current;
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return current;
}
++iter;
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected UnivariatePointValuePair doOptimize() {
final boolean isMinim = getGoalType() == GoalType.MINIMIZE;
final double lo = getMin();
final double mid = getStartValue();
final double hi = getMax();
// Optional additional convergence criteria.
final ConvergenceChecker<UnivariatePointValuePair> checker
= getConvergenceChecker();
double a;
double b;
if (lo < hi) {
a = lo;
b = hi;
} else {
a = hi;
b = lo;
}
double x = mid;
double v = x;
double w = x;
double d = 0;
double e = 0;
double fx = computeObjectiveValue(x);
if (!isMinim) {
fx = -fx;
}
double fv = fx;
double fw = fx;
UnivariatePointValuePair previous = null;
UnivariatePointValuePair current
= new UnivariatePointValuePair(x, isMinim ? fx : -fx);
int iter = 0;
while (true) {
final double m = 0.5 * (a + b);
final double tol1 = relativeThreshold * FastMath.abs(x) + absoluteThreshold;
final double tol2 = 2 * tol1;
// Default stopping criterion.
final boolean stop = FastMath.abs(x - m) <= tol2 - 0.5 * (b - a);
if (!stop) {
double p = 0;
double q = 0;
double r = 0;
double u = 0;
if (FastMath.abs(e) > tol1) { // Fit parabola.
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = 2 * (q - r);
if (q > 0) {
p = -p;
} else {
q = -q;
}
r = e;
e = d;
if (p > q * (a - x) &&
p < q * (b - x) &&
FastMath.abs(p) < FastMath.abs(0.5 * q * r)) {
// Parabolic interpolation step.
d = p / q;
u = x + d;
// f must not be evaluated too close to a or b.
if (u - a < tol2 || b - u < tol2) {
if (x <= m) {
d = tol1;
} else {
d = -tol1;
}
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
} else {
// Golden section step.
if (x < m) {
e = b - x;
} else {
e = a - x;
}
d = GOLDEN_SECTION * e;
}
// Update by at least "tol1".
if (FastMath.abs(d) < tol1) {
if (d >= 0) {
u = x + tol1;
} else {
u = x - tol1;
}
} else {
u = x + d;
}
double fu = computeObjectiveValue(u);
if (!isMinim) {
fu = -fu;
}
// User-defined convergence checker.
previous = current;
current = new UnivariatePointValuePair(u, isMinim ? fu : -fu);
if (checker != null) {
if (checker.converged(iter, previous, current)) {
return current;
}
}
// Update a, b, v, w and x.
if (fu <= fx) {
if (u < x) {
b = x;
} else {
a = x;
}
v = w;
fv = fw;
w = x;
fw = fx;
x = u;
fx = fu;
} else {
if (u < x) {
a = u;
} else {
b = u;
}
if (fu <= fw ||
Precision.equals(w, x)) {
v = w;
fv = fw;
w = u;
fw = fu;
} else if (fu <= fv ||
Precision.equals(v, x) ||
Precision.equals(v, w)) {
v = u;
fv = fu;
}
}
} else { // Default termination (Brent's criterion).
return current;
}
++iter;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | ed1ee9f56ccb87a0fb773cfe2402c6e1559cf632d97620172929873e489fe970 | <M extends Map<String, String>> M putIn(final M map) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
map.put(entry.getKey(), values[col]);
}
return map;
}
```
| <M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
map.put(entry.getKey(), values[col]);
}
return map;
} | true | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Puts all values of this record into the given Map.
*
* @param map The Map to populate.
* @return the given map.
*/
<M extends Map<String, String>> M putIn(final M map) {
for (final Entry<String, Integer> entry : mapping.entrySet()) {
final int col = entry.getValue().intValue();
map.put(entry.getKey(), values[col]);
}
return map;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | ed8614e57a0a02541f8f5f28ca74166f536d21104301fae4e989a54926d6925e | static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
```
| static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// this method is ugly, and does a lot. but other breakups cause rescanning and stringbuilder generations
static void escape(StringBuilder accum, String string, Document.OutputSettings out,
boolean inAttribute, boolean normaliseWhite, boolean stripLeadingWhite) {
boolean lastWasWhite = false;
boolean reachedNonWhite = false;
final EscapeMode escapeMode = out.escapeMode();
final CharsetEncoder encoder = out.encoder();
final CoreCharset coreCharset = CoreCharset.byName(encoder.charset().name());
final Map<Character, String> map = escapeMode.getMap();
final int length = string.length();
int codePoint;
for (int offset = 0; offset < length; offset += Character.charCount(codePoint)) {
codePoint = string.codePointAt(offset);
if (normaliseWhite) {
if (StringUtil.isWhitespace(codePoint)) {
if ((stripLeadingWhite && !reachedNonWhite) || lastWasWhite)
continue;
accum.append(' ');
lastWasWhite = true;
continue;
} else {
lastWasWhite = false;
reachedNonWhite = true;
}
}
// surrogate pairs, split implementation for efficiency on single char common case (saves creating strings, char[]):
if (codePoint < Character.MIN_SUPPLEMENTARY_CODE_POINT) {
final char c = (char) codePoint;
// html specific and required escapes:
switch (c) {
case '&':
accum.append("&");
break;
case 0xA0:
if (escapeMode != EscapeMode.xhtml)
accum.append(" ");
else
accum.append(" ");
break;
case '<':
if (!inAttribute)
accum.append("<");
else
accum.append(c);
break;
case '>':
if (!inAttribute)
accum.append(">");
else
accum.append(c);
break;
case '"':
if (inAttribute)
accum.append(""");
else
accum.append(c);
break;
default:
if (canEncode(coreCharset, c, encoder))
accum.append(c);
else if (map.containsKey(c))
accum.append('&').append(map.get(c)).append(';');
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
} else {
final String c = new String(Character.toChars(codePoint));
if (encoder.canEncode(c)) // uses fallback encoder for simplicity
accum.append(c);
else
accum.append("&#x").append(Integer.toHexString(codePoint)).append(';');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | eddfa1cbe790e81ae2f9df7987487f750769817b50167b00106f7a4b5aefea9d | @SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the <code>Object</code> of type <code>clazz</code>
* with the value of <code>str</code>.
*
* @param str the command line value
* @param clazz the type of argument
* @return The instance of <code>clazz</code> initialised with
* the value of <code>str</code>.
* @throws ParseException if the value creation for the given class failed
*/
@SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
throw new ParseException("Unable to handle the class: " + clazz);
}
}
```
| @SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
throw new ParseException("Unable to handle the class: " + clazz);
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the <code>Object</code> of type <code>clazz</code>
* with the value of <code>str</code>.
*
* @param str the command line value
* @param clazz the type of argument
* @return The instance of <code>clazz</code> initialised with
* the value of <code>str</code>.
* @throws ParseException if the value creation for the given class failed
*/
@SuppressWarnings("unchecked") // returned value will have type T because it is fixed by clazz
public static <T> T createValue(final String str, final Class<T> clazz) throws ParseException
{
if (PatternOptionBuilder.STRING_VALUE == clazz)
{
return (T) str;
}
else if (PatternOptionBuilder.OBJECT_VALUE == clazz)
{
return (T) createObject(str);
}
else if (PatternOptionBuilder.NUMBER_VALUE == clazz)
{
return (T) createNumber(str);
}
else if (PatternOptionBuilder.DATE_VALUE == clazz)
{
return (T) createDate(str);
}
else if (PatternOptionBuilder.CLASS_VALUE == clazz)
{
return (T) createClass(str);
}
else if (PatternOptionBuilder.FILE_VALUE == clazz)
{
return (T) createFile(str);
}
else if (PatternOptionBuilder.EXISTING_FILE_VALUE == clazz)
{
return (T) openFile(str);
}
else if (PatternOptionBuilder.FILES_VALUE == clazz)
{
return (T) createFiles(str);
}
else if (PatternOptionBuilder.URL_VALUE == clazz)
{
return (T) createURL(str);
}
else
{
throw new ParseException("Unable to handle the class: " + clazz);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | eec5ef8a08a8d12ed799daf5c315348edd98c02bfa356f17cd3b767502111f43 | static String unescape(String string) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static String unescape(String string) {
if (!string.contains("&"))
return string;
Matcher m = unescapePattern.matcher(string); // &(#(x|X)?([0-9a-fA-F]+)|[a-zA-Z]+);?
StringBuffer accum = new StringBuffer(string.length()); // pity matcher can't use stringbuilder, avoid syncs
// todo: replace m.appendReplacement with own impl, so StringBuilder and quoteReplacement not required
while (m.find()) {
int charval = -1;
String num = m.group(3);
if (num != null) {
try {
int base = m.group(2) != null ? 16 : 10; // 2 is hex indicator
charval = Integer.valueOf(num, base);
} catch (NumberFormatException e) {
} // skip
} else {
String name = m.group(1);
if (full.containsKey(name))
charval = full.get(name);
}
if (charval != -1 || charval > 0xFFFF) { // out of range
String c = Character.toString((char) charval);
m.appendReplacement(accum, Matcher.quoteReplacement(c));
} else {
m.appendReplacement(accum, Matcher.quoteReplacement(m.group(0))); // replace with original string
}
}
m.appendTail(accum);
return accum.toString();
}
```
| static String unescape(String string) {
if (!string.contains("&"))
return string;
Matcher m = unescapePattern.matcher(string); // &(#(x|X)?([0-9a-fA-F]+)|[a-zA-Z]+);?
StringBuffer accum = new StringBuffer(string.length()); // pity matcher can't use stringbuilder, avoid syncs
// todo: replace m.appendReplacement with own impl, so StringBuilder and quoteReplacement not required
while (m.find()) {
int charval = -1;
String num = m.group(3);
if (num != null) {
try {
int base = m.group(2) != null ? 16 : 10; // 2 is hex indicator
charval = Integer.valueOf(num, base);
} catch (NumberFormatException e) {
} // skip
} else {
String name = m.group(1);
if (full.containsKey(name))
charval = full.get(name);
}
if (charval != -1 || charval > 0xFFFF) { // out of range
String c = Character.toString((char) charval);
m.appendReplacement(accum, Matcher.quoteReplacement(c));
} else {
m.appendReplacement(accum, Matcher.quoteReplacement(m.group(0))); // replace with original string
}
}
m.appendTail(accum);
return accum.toString();
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static String unescape(String string) {
if (!string.contains("&"))
return string;
Matcher m = unescapePattern.matcher(string); // &(#(x|X)?([0-9a-fA-F]+)|[a-zA-Z]+);?
StringBuffer accum = new StringBuffer(string.length()); // pity matcher can't use stringbuilder, avoid syncs
// todo: replace m.appendReplacement with own impl, so StringBuilder and quoteReplacement not required
while (m.find()) {
int charval = -1;
String num = m.group(3);
if (num != null) {
try {
int base = m.group(2) != null ? 16 : 10; // 2 is hex indicator
charval = Integer.valueOf(num, base);
} catch (NumberFormatException e) {
} // skip
} else {
String name = m.group(1);
if (full.containsKey(name))
charval = full.get(name);
}
if (charval != -1 || charval > 0xFFFF) { // out of range
String c = Character.toString((char) charval);
m.appendReplacement(accum, Matcher.quoteReplacement(c));
} else {
m.appendReplacement(accum, Matcher.quoteReplacement(m.group(0))); // replace with original string
}
}
m.appendTail(accum);
return accum.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | eec91ec413b47dc6aef1d31a6137c3cd44759675f09019b25d809ff0726607cf | protected void registerTypeVariablesOn(Type classType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void registerTypeVariablesOn(Type classType) {
if (!(classType instanceof ParameterizedType)) {
return;
}
ParameterizedType parameterizedType = (ParameterizedType) classType;
TypeVariable[] typeParameters = ((Class<?>) parameterizedType.getRawType()).getTypeParameters();
Type[] actualTypeArguments = parameterizedType.getActualTypeArguments();
for (int i = 0; i < actualTypeArguments.length; i++) {
TypeVariable typeParameter = typeParameters[i];
Type actualTypeArgument = actualTypeArguments[i];
if (actualTypeArgument instanceof WildcardType) {
contextualActualTypeParameters.put(typeParameter, boundsOf((WildcardType) actualTypeArgument));
} else if (typeParameter != actualTypeArgument) {
contextualActualTypeParameters.put(typeParameter, actualTypeArgument);
}
// logger.log("For '" + parameterizedType + "' found type variable : { '" + typeParameter + "(" + System.identityHashCode(typeParameter) + ")" + "' : '" + actualTypeArgument + "(" + System.identityHashCode(typeParameter) + ")" + "' }");
}
}
```
| protected void registerTypeVariablesOn(Type classType) {
if (!(classType instanceof ParameterizedType)) {
return;
}
ParameterizedType parameterizedType = (ParameterizedType) classType;
TypeVariable[] typeParameters = ((Class<?>) parameterizedType.getRawType()).getTypeParameters();
Type[] actualTypeArguments = parameterizedType.getActualTypeArguments();
for (int i = 0; i < actualTypeArguments.length; i++) {
TypeVariable typeParameter = typeParameters[i];
Type actualTypeArgument = actualTypeArguments[i];
if (actualTypeArgument instanceof WildcardType) {
contextualActualTypeParameters.put(typeParameter, boundsOf((WildcardType) actualTypeArgument));
} else if (typeParameter != actualTypeArgument) {
contextualActualTypeParameters.put(typeParameter, actualTypeArgument);
}
// logger.log("For '" + parameterizedType + "' found type variable : { '" + typeParameter + "(" + System.identityHashCode(typeParameter) + ")" + "' : '" + actualTypeArgument + "(" + System.identityHashCode(typeParameter) + ")" + "' }");
}
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void registerTypeVariablesOn(Type classType) {
if (!(classType instanceof ParameterizedType)) {
return;
}
ParameterizedType parameterizedType = (ParameterizedType) classType;
TypeVariable[] typeParameters = ((Class<?>) parameterizedType.getRawType()).getTypeParameters();
Type[] actualTypeArguments = parameterizedType.getActualTypeArguments();
for (int i = 0; i < actualTypeArguments.length; i++) {
TypeVariable typeParameter = typeParameters[i];
Type actualTypeArgument = actualTypeArguments[i];
if (actualTypeArgument instanceof WildcardType) {
contextualActualTypeParameters.put(typeParameter, boundsOf((WildcardType) actualTypeArgument));
} else if (typeParameter != actualTypeArgument) {
contextualActualTypeParameters.put(typeParameter, actualTypeArgument);
}
// logger.log("For '" + parameterizedType + "' found type variable : { '" + typeParameter + "(" + System.identityHashCode(typeParameter) + ")" + "' : '" + actualTypeArgument + "(" + System.identityHashCode(typeParameter) + ")" + "' }");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | eecfc4cb2178333621c1a7752fdc4e0b491cb59fddd9719936d3420cbffbb94d | void processResponseHeaders(Map<String, List<String>> resHeaders) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (values.size() == 1)
header(name, values.get(0));
else if (values.size() > 1) {
StringBuilder accum = new StringBuilder();
for (int i = 0; i < values.size(); i++) {
final String val = values.get(i);
if (i != 0)
accum.append(", ");
accum.append(val);
}
header(name, accum.toString());
}
}
}
}
```
| void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (values.size() == 1)
header(name, values.get(0));
else if (values.size() > 1) {
StringBuilder accum = new StringBuilder();
for (int i = 0; i < values.size(); i++) {
final String val = values.get(i);
if (i != 0)
accum.append(", ");
accum.append(val);
}
header(name, accum.toString());
}
}
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void processResponseHeaders(Map<String, List<String>> resHeaders) {
for (Map.Entry<String, List<String>> entry : resHeaders.entrySet()) {
String name = entry.getKey();
if (name == null)
continue; // http/1.1 line
List<String> values = entry.getValue();
if (name.equalsIgnoreCase("Set-Cookie")) {
for (String value : values) {
if (value == null)
continue;
TokenQueue cd = new TokenQueue(value);
String cookieName = cd.chompTo("=").trim();
String cookieVal = cd.consumeTo(";").trim();
// ignores path, date, domain, validateTLSCertificates et al. req'd?
// name not blank, value not null
if (cookieName.length() > 0)
cookie(cookieName, cookieVal);
}
} else { // combine same header names with comma: http://www.w3.org/Protocols/rfc2616/rfc2616-sec4.html#sec4.2
if (values.size() == 1)
header(name, values.get(0));
else if (values.size() > 1) {
StringBuilder accum = new StringBuilder();
for (int i = 0; i < values.size(); i++) {
final String val = values.get(i);
if (i != 0)
accum.append(", ");
accum.append(val);
}
header(name, accum.toString());
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
85 | eed83ef4cca977282824331971e03f41ac8cdaddc490c1f2fcbfedeac390369f | @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
// Jackson's own `StdDateFormat` is quite easy to deal with...
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
// serializers.reportBadDefinition(handledType(), String.format(
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
return this;
}
```
| @Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
// Jackson's own `StdDateFormat` is quite easy to deal with...
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
// serializers.reportBadDefinition(handledType(), String.format(
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
return this;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public JsonSerializer<?> createContextual(SerializerProvider serializers,
BeanProperty property) throws JsonMappingException
{
if (property == null) {
return this;
}
JsonFormat.Value format = findFormatOverrides(serializers, property, handledType());
if (format == null) {
return this;
}
// Simple case first: serialize as numeric timestamp?
JsonFormat.Shape shape = format.getShape();
if (shape.isNumeric()) {
return withFormat(Boolean.TRUE, null);
}
// 08-Jun-2017, tatu: With [databind#1648], this gets bit tricky..
// First: custom pattern will override things
if ((shape == JsonFormat.Shape.STRING) || format.hasPattern()
|| format.hasLocale() || format.hasTimeZone()) {
TimeZone tz = format.getTimeZone();
final String pattern = format.hasPattern()
? format.getPattern()
: StdDateFormat.DATE_FORMAT_STR_ISO8601;
final Locale loc = format.hasLocale()
? format.getLocale()
: serializers.getLocale();
SimpleDateFormat df = new SimpleDateFormat(pattern, loc);
if (tz == null) {
tz = serializers.getTimeZone();
}
df.setTimeZone(tz);
return withFormat(Boolean.FALSE, df);
}
// Otherwise, need one of these changes:
// Jackson's own `StdDateFormat` is quite easy to deal with...
// 08-Jun-2017, tatu: Unfortunately there's no generally usable
// mechanism for changing `DateFormat` instances (or even clone()ing)
// So: require it be `SimpleDateFormat`; can't config other types
// serializers.reportBadDefinition(handledType(), String.format(
// Ugh. No way to change `Locale`, create copy; must re-crete completely:
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | eee8b8b4cb0f19992bb88996b596288425d2d0dd86cb9738a4bceda0bfbbf377 | @Override
protected void computeGeometricalProperties() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if (tree.getCut() == null && (Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
}
```
| @Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if (tree.getCut() == null && (Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if (tree.getCut() == null && (Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
42 | ef53d4fbbf61446595fcc96dd9eedd6101cf0b2b0908992049628fbfccee6618 | public void escape(Writer writer, String str) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Escapes the characters in the <code>String</code> passed and writes the result to the <code>Writer</code>
* passed.
* </p>
*
* @param writer
* The <code>Writer</code> to write the results of the escaping to. Assumed to be a non-null value.
* @param str
* The <code>String</code> to escape. Assumed to be a non-null value.
* @throws IOException
* when <code>Writer</code> passed throws the exception from calls to the {@link Writer#write(int)}
* methods.
*
* @see #escape(String)
* @see Writer
*/
public void escape(Writer writer, String str) throws IOException {
int len = str.length();
for (int i = 0; i < len; i++) {
int c = Character.codePointAt(str, i);
String entityName = this.entityName(c);
if (entityName == null) {
if (c >= 0x010000 && i < len - 1) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
i++;
} else if (c > 0x7F) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
} else {
writer.write(c);
}
} else {
writer.write('&');
writer.write(entityName);
writer.write(';');
}
}
}
```
| public void escape(Writer writer, String str) throws IOException {
int len = str.length();
for (int i = 0; i < len; i++) {
int c = Character.codePointAt(str, i);
String entityName = this.entityName(c);
if (entityName == null) {
if (c >= 0x010000 && i < len - 1) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
i++;
} else if (c > 0x7F) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
} else {
writer.write(c);
}
} else {
writer.write('&');
writer.write(entityName);
writer.write(';');
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Escapes the characters in the <code>String</code> passed and writes the result to the <code>Writer</code>
* passed.
* </p>
*
* @param writer
* The <code>Writer</code> to write the results of the escaping to. Assumed to be a non-null value.
* @param str
* The <code>String</code> to escape. Assumed to be a non-null value.
* @throws IOException
* when <code>Writer</code> passed throws the exception from calls to the {@link Writer#write(int)}
* methods.
*
* @see #escape(String)
* @see Writer
*/
public void escape(Writer writer, String str) throws IOException {
int len = str.length();
for (int i = 0; i < len; i++) {
int c = Character.codePointAt(str, i);
String entityName = this.entityName(c);
if (entityName == null) {
if (c >= 0x010000 && i < len - 1) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
i++;
} else if (c > 0x7F) {
writer.write("&#");
writer.write(Integer.toString(c, 10));
writer.write(';');
} else {
writer.write(c);
}
} else {
writer.write('&');
writer.write(entityName);
writer.write(';');
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | ef67fc2ef8344d92f4c4ebe12d5dcc3fbd02277a0242f850aea54a3aac13efa0 | @Override
public int translate(CharSequence input, int index, Writer out) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*/
@Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
int seqEnd = input.length();
// Uses -2 to ensure there is something after the &#
if(input.charAt(index) == '&' && index < seqEnd - 1 && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
// Check there's more than just an x after the &#
}
int end = start;
// Note that this supports character codes without a ; on the end
while(input.charAt(end) != ';')
{
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
System.err.println("FAIL: " + input.subSequence(start, end) + "[" + start +"]["+ end +"]");
return 0;
}
if(entityValue > 0xFFFF) {
char[] chrs = Character.toChars(entityValue);
out.write(chrs[0]);
out.write(chrs[1]);
} else {
out.write(entityValue);
}
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
}
```
| @Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
int seqEnd = input.length();
// Uses -2 to ensure there is something after the &#
if(input.charAt(index) == '&' && index < seqEnd - 1 && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
// Check there's more than just an x after the &#
}
int end = start;
// Note that this supports character codes without a ; on the end
while(input.charAt(end) != ';')
{
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
System.err.println("FAIL: " + input.subSequence(start, end) + "[" + start +"]["+ end +"]");
return 0;
}
if(entityValue > 0xFFFF) {
char[] chrs = Character.toChars(entityValue);
out.write(chrs[0]);
out.write(chrs[1]);
} else {
out.write(entityValue);
}
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*/
@Override
public int translate(CharSequence input, int index, Writer out) throws IOException {
int seqEnd = input.length();
// Uses -2 to ensure there is something after the &#
if(input.charAt(index) == '&' && index < seqEnd - 1 && input.charAt(index + 1) == '#') {
int start = index + 2;
boolean isHex = false;
char firstChar = input.charAt(start);
if(firstChar == 'x' || firstChar == 'X') {
start++;
isHex = true;
// Check there's more than just an x after the &#
}
int end = start;
// Note that this supports character codes without a ; on the end
while(input.charAt(end) != ';')
{
end++;
}
int entityValue;
try {
if(isHex) {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 16);
} else {
entityValue = Integer.parseInt(input.subSequence(start, end).toString(), 10);
}
} catch(NumberFormatException nfe) {
System.err.println("FAIL: " + input.subSequence(start, end) + "[" + start +"]["+ end +"]");
return 0;
}
if(entityValue > 0xFFFF) {
char[] chrs = Character.toChars(entityValue);
out.write(chrs[0]);
out.write(chrs[1]);
} else {
out.write(entityValue);
}
return 2 + (end - start) + (isHex ? 1 : 0) + 1;
}
return 0;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | ef8b3cfdc466116b6892ac77dc74e2b0813167eb1b2a6feb48751369e076a99f | private void writeBits(final DataOutput header, final BitSet bits, final int length) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void writeBits(final DataOutput header, final BitSet bits, final int length) throws IOException {
int cache = 0;
int shift = 7;
for (int i = 0; i < length; i++) {
cache |= ((bits.get(i) ? 1 : 0) << shift);
--shift;
if (shift == 0) {
header.write(cache);
shift = 7;
cache = 0;
}
}
if (length > 0 && shift > 0) {
header.write(cache);
}
}
```
| private void writeBits(final DataOutput header, final BitSet bits, final int length) throws IOException {
int cache = 0;
int shift = 7;
for (int i = 0; i < length; i++) {
cache |= ((bits.get(i) ? 1 : 0) << shift);
--shift;
if (shift == 0) {
header.write(cache);
shift = 7;
cache = 0;
}
}
if (length > 0 && shift > 0) {
header.write(cache);
}
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void writeBits(final DataOutput header, final BitSet bits, final int length) throws IOException {
int cache = 0;
int shift = 7;
for (int i = 0; i < length; i++) {
cache |= ((bits.get(i) ? 1 : 0) << shift);
--shift;
if (shift == 0) {
header.write(cache);
shift = 7;
cache = 0;
}
}
if (length > 0 && shift > 0) {
header.write(cache);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | efd94df67f1e8d97388f8babdd4c7c3ca0be475e4b50bd6f7513c3fd21ff2a92 | protected final double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
if (x == x1) {
throw new ConvergenceException();
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
```
| protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
if (x == x1) {
throw new ConvergenceException();
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
if (x == x1) {
throw new ConvergenceException();
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
34 | f011ed74f76270272a8275add9f2858715aca6a008506d617bebc0e3d369c082 | public Iterator<Chromosome> iterator() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns an iterator over the unmodifiable list of chromosomes.
* <p>Any call to {@link Iterator#remove()} will result in a {@link UnsupportedOperationException}.</p>
*
* @return chromosome iterator
*/
public Iterator<Chromosome> iterator() {
return chromosomes.iterator();
}
```
| public Iterator<Chromosome> iterator() {
return chromosomes.iterator();
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns an iterator over the unmodifiable list of chromosomes.
* <p>Any call to {@link Iterator#remove()} will result in a {@link UnsupportedOperationException}.</p>
*
* @return chromosome iterator
*/
public Iterator<Chromosome> iterator() {
return chromosomes.iterator();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
47 | f05763e1f52065d6c86fd8dcc6b3a00045025c84393b72ba55e26019b7fe285b | public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method called to find out possible type refinements to use
* for deserialization.
*
* @since 2.7
*/
public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
type = tf.constructGeneralizedType(type, serClass);
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
}
```
| public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
type = tf.constructGeneralizedType(type, serClass);
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method called to find out possible type refinements to use
* for deserialization.
*
* @since 2.7
*/
public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
type = tf.constructGeneralizedType(type, serClass);
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
133 | f05d0cdc7a0b42ae185bd81db70e1f712ad10b578c41a1f83f948181a15adeaf | private String getRemainingJSDocLine() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the remainder of the line.
*/
private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
return result;
}
```
| private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
return result;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the remainder of the line.
*/
private String getRemainingJSDocLine() {
String result = stream.getRemainingJSDocLine();
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
55 | f0c46f125a01e6c77f1ce8170ce06bbacb401a1834f7e8a3043f9ef6af7ab61f | private static boolean isReduceableFunctionExpression(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n)
&& !NodeUtil.isGetOrSetKey(n.getParent());
}
```
| private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n)
&& !NodeUtil.isGetOrSetKey(n.getParent());
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static boolean isReduceableFunctionExpression(Node n) {
return NodeUtil.isFunctionExpression(n)
&& !NodeUtil.isGetOrSetKey(n.getParent());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
22 | f0d1f179c7d941937ebe8e620b6ee15dac1f757143bb0b93f1253677016dc460 | private static int greatestCommonDivisor(int u, int v) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Gets the greatest common divisor of the absolute value of
* two numbers, using the "binary gcd" method which avoids
* division and modulo operations. See Knuth 4.5.2 algorithm B.
* This algorithm is due to Josef Stein (1961).</p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
*/
private static int greatestCommonDivisor(int u, int v) {
// From Commons Math:
if ((u == 0) || (v == 0)) {
if ((u == Integer.MIN_VALUE) || (v == Integer.MIN_VALUE)) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
return Math.abs(u) + Math.abs(v);
}
//if either operand is abs 1, return 1:
if (Math.abs(u) == 1 || Math.abs(v) == 1) {
return 1;
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
if (u>0) { u=-u; } // make u negative
if (v>0) { v=-v; } // make v negative
// B1. [Find power of 2]
int k=0;
while ((u&1)==0 && (v&1)==0 && k<31) { // while u and v are both even...
u/=2; v/=2; k++; // cast out twos.
}
if (k==31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u&1)==1) ? v : -(u/2)/*B3*/;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t&1)==0) { // while t is even..
t/=2; // cast out twos
}
// B5 [reset max(u,v)]
if (t>0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u)/2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t!=0);
return -u*(1<<k); // gcd is u*2^k
}
```
| private static int greatestCommonDivisor(int u, int v) {
// From Commons Math:
if ((u == 0) || (v == 0)) {
if ((u == Integer.MIN_VALUE) || (v == Integer.MIN_VALUE)) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
return Math.abs(u) + Math.abs(v);
}
//if either operand is abs 1, return 1:
if (Math.abs(u) == 1 || Math.abs(v) == 1) {
return 1;
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
if (u>0) { u=-u; } // make u negative
if (v>0) { v=-v; } // make v negative
// B1. [Find power of 2]
int k=0;
while ((u&1)==0 && (v&1)==0 && k<31) { // while u and v are both even...
u/=2; v/=2; k++; // cast out twos.
}
if (k==31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u&1)==1) ? v : -(u/2)/*B3*/;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t&1)==0) { // while t is even..
t/=2; // cast out twos
}
// B5 [reset max(u,v)]
if (t>0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u)/2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t!=0);
return -u*(1<<k); // gcd is u*2^k
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Gets the greatest common divisor of the absolute value of
* two numbers, using the "binary gcd" method which avoids
* division and modulo operations. See Knuth 4.5.2 algorithm B.
* This algorithm is due to Josef Stein (1961).</p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
*/
private static int greatestCommonDivisor(int u, int v) {
// From Commons Math:
if ((u == 0) || (v == 0)) {
if ((u == Integer.MIN_VALUE) || (v == Integer.MIN_VALUE)) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
return Math.abs(u) + Math.abs(v);
}
//if either operand is abs 1, return 1:
if (Math.abs(u) == 1 || Math.abs(v) == 1) {
return 1;
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
if (u>0) { u=-u; } // make u negative
if (v>0) { v=-v; } // make v negative
// B1. [Find power of 2]
int k=0;
while ((u&1)==0 && (v&1)==0 && k<31) { // while u and v are both even...
u/=2; v/=2; k++; // cast out twos.
}
if (k==31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u&1)==1) ? v : -(u/2)/*B3*/;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t&1)==0) { // while t is even..
t/=2; // cast out twos
}
// B5 [reset max(u,v)]
if (t>0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u)/2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t!=0);
return -u*(1<<k); // gcd is u*2^k
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | f0f008b1a1763f5d8efa623333e2a80a457f5e1824faf462dcb2f99f68e48654 | private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Check whether there's any property conflict for for a particular super
* interface
* @param t The node traversal object that supplies context
* @param n The node being visited
* @param functionName The function name being checked
* @param properties The property names in the super interfaces that have
* been visited
* @param currentProperties The property names in the super interface
* that have been visited
* @param interfaceType The super interface that is being visited
*/
private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
if (implicitProto == null) {
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = ImmutableSet.of();
} else {
currentPropertyNames = implicitProto.getOwnPropertyNames();
}
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
}
```
| private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
if (implicitProto == null) {
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = ImmutableSet.of();
} else {
currentPropertyNames = implicitProto.getOwnPropertyNames();
}
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Check whether there's any property conflict for for a particular super
* interface
* @param t The node traversal object that supplies context
* @param n The node being visited
* @param functionName The function name being checked
* @param properties The property names in the super interfaces that have
* been visited
* @param currentProperties The property names in the super interface
* that have been visited
* @param interfaceType The super interface that is being visited
*/
private void checkInterfaceConflictProperties(NodeTraversal t, Node n,
String functionName, HashMap<String, ObjectType> properties,
HashMap<String, ObjectType> currentProperties,
ObjectType interfaceType) {
ObjectType implicitProto = interfaceType.getImplicitPrototype();
Set<String> currentPropertyNames;
if (implicitProto == null) {
// This can be the case if interfaceType is proxy to a non-existent
// object (which is a bad type annotation, but shouldn't crash).
currentPropertyNames = ImmutableSet.of();
} else {
currentPropertyNames = implicitProto.getOwnPropertyNames();
}
for (String name : currentPropertyNames) {
ObjectType oType = properties.get(name);
if (oType != null) {
if (!interfaceType.getPropertyType(name).isEquivalentTo(
oType.getPropertyType(name))) {
compiler.report(
t.makeError(n, INCOMPATIBLE_EXTENDED_PROPERTY_TYPE,
functionName, name, oType.toString(),
interfaceType.toString()));
}
}
currentProperties.put(name, interfaceType);
}
for (ObjectType iType : interfaceType.getCtorExtendedInterfaces()) {
checkInterfaceConflictProperties(t, n, functionName, properties,
currentProperties, iType);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | f0fcffd2d75d935fce4b5a1ea0e015e79c2d676cf04dc97734dbb4bf718afa95 | @Override
public void process(Node externs, Node root) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
removeDuplicateDeclarations(root);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
}
```
| @Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
removeDuplicateDeclarations(root);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void process(Node externs, Node root) {
NodeTraversal.traverse(compiler, root, this);
removeDuplicateDeclarations(root);
if (MAKE_LOCAL_NAMES_UNIQUE) {
MakeDeclaredNamesUnique renamer = new MakeDeclaredNamesUnique();
NodeTraversal t = new NodeTraversal(compiler, renamer);
t.traverseRoots(externs, root);
}
new PropogateConstantAnnotations(compiler, assertOnChange)
.process(externs, root);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | f16275f94cb6c6289295abf114946dff7230332aa301d722d27a57637d32471c | @Override
public void feedInput(byte[] buf, int start, int end) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
}
```
| @Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void feedInput(byte[] buf, int start, int end) throws IOException
{
// Must not have remaining input
if (_inputPtr < _inputEnd) {
_reportError("Still have %d undecoded bytes, should not call 'feedInput'", _inputEnd - _inputPtr);
}
if (end < start) {
_reportError("Input end (%d) may not be before start (%d)", end, start);
}
// and shouldn't have been marked as end-of-input
if (_endOfInput) {
_reportError("Already closed, can not feed more input");
}
// Time to update pointers first
_currInputProcessed += _origBufferLen;
// Also need to adjust row start, to work as if it extended into the past wrt new buffer
_currInputRowStart = start - (_inputEnd - _currInputRowStart);
// And then update buffer settings
_inputBuffer = buf;
_inputPtr = start;
_inputEnd = end;
_origBufferLen = end - start;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
85 | f1877c0c923871ba89ab17d89bd8cbdb219f6a83f6615a5c04c83a08d408475d | public Attribute(String key, String val, Attributes parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Create a new attribute from unencoded (raw) key and value.
* @param key attribute key; case is preserved.
* @param val attribute value
* @param parent the containing Attributes (this Attribute is not automatically added to said Attributes)
* @see #createFromEncoded*/
public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
this.key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.val = val;
this.parent = parent;
}
```
| public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
this.key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.val = val;
this.parent = parent;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Create a new attribute from unencoded (raw) key and value.
* @param key attribute key; case is preserved.
* @param val attribute value
* @param parent the containing Attributes (this Attribute is not automatically added to said Attributes)
* @see #createFromEncoded*/
public Attribute(String key, String val, Attributes parent) {
Validate.notNull(key);
this.key = key.trim();
Validate.notEmpty(key); // trimming could potentially make empty, so validate here
this.val = val;
this.parent = parent;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | f1943eaddece94c9841234fb81ca949d86870ec86a7e2288e13e01d750c021ca | static int toJavaVersionInt(String version) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Converts the given Java version string to an <code>int</code>.
* </p>
*
* <p>
* Example return values:
* </p>
* <ul>
* <li><code>120</code> for Java 1.2</li>
* <li><code>131</code> for Java 1.3.1</li>
* <li><code>160</code> for Java 1.6.0_20</li>
* </ul>
*
* <p>
* Patch releases are not reported.
* </p>
* <p>
* This method is package private instead of private to support unit test invocation.
* </p>
*
* @return the version, for example 131 for Java 1.3.1
*/
static int toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
}
```
| static int toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Converts the given Java version string to an <code>int</code>.
* </p>
*
* <p>
* Example return values:
* </p>
* <ul>
* <li><code>120</code> for Java 1.2</li>
* <li><code>131</code> for Java 1.3.1</li>
* <li><code>160</code> for Java 1.6.0_20</li>
* </ul>
*
* <p>
* Patch releases are not reported.
* </p>
* <p>
* This method is package private instead of private to support unit test invocation.
* </p>
*
* @return the version, for example 131 for Java 1.3.1
*/
static int toJavaVersionInt(String version) {
return toVersionInt(toJavaVersionIntArray(version, JAVA_VERSION_TRIM_SIZE));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
99 | f1a877204ef0f5ac9cd969415ac15d8128c788889cd8fbccc891aebb569d288c | public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN)) {
return false;
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
```
| public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN)) {
return false;
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN)) {
return false;
}
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
49 | f1c00080cf8612c3e4cd21a9d41e21de2c28e35d1154eb5e6b198dda56a849b7 | protected void addChildren(int index, Node... children) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void addChildren(int index, Node... children) {
Validate.noNullElements(children);
ensureChildNodes();
for (int i = children.length - 1; i >= 0; i--) {
Node in = children[i];
reparentChild(in);
childNodes.add(index, in);
}
reindexChildren(index);
}
```
| protected void addChildren(int index, Node... children) {
Validate.noNullElements(children);
ensureChildNodes();
for (int i = children.length - 1; i >= 0; i--) {
Node in = children[i];
reparentChild(in);
childNodes.add(index, in);
}
reindexChildren(index);
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void addChildren(int index, Node... children) {
Validate.noNullElements(children);
ensureChildNodes();
for (int i = children.length - 1; i >= 0; i--) {
Node in = children[i];
reparentChild(in);
childNodes.add(index, in);
}
reindexChildren(index);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
29 | f1da3edf68efe4f92ebdbedad241c888c235909029b697328b650ceb7df0e94f | static String stripLeadingAndTrailingQuotes(String str)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Remove the leading and trailing quotes from <code>str</code>.
* E.g. if str is '"one two"', then 'one two' is returned.
*
* @param str The string from which the leading and trailing quotes
* should be removed.
*
* @return The string without the leading and trailing quotes.
*/
static String stripLeadingAndTrailingQuotes(String str)
{
int length = str.length();
if (length > 1 && str.startsWith("\"") && str.endsWith("\"") && str.substring(1, length - 1).indexOf('"') == -1)
{
str = str.substring(1, length - 1);
}
return str;
}
```
| static String stripLeadingAndTrailingQuotes(String str)
{
int length = str.length();
if (length > 1 && str.startsWith("\"") && str.endsWith("\"") && str.substring(1, length - 1).indexOf('"') == -1)
{
str = str.substring(1, length - 1);
}
return str;
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Remove the leading and trailing quotes from <code>str</code>.
* E.g. if str is '"one two"', then 'one two' is returned.
*
* @param str The string from which the leading and trailing quotes
* should be removed.
*
* @return The string without the leading and trailing quotes.
*/
static String stripLeadingAndTrailingQuotes(String str)
{
int length = str.length();
if (length > 1 && str.startsWith("\"") && str.endsWith("\"") && str.substring(1, length - 1).indexOf('"') == -1)
{
str = str.substring(1, length - 1);
}
return str;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |