bug_id
stringlengths 1
3
| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
49 | 000bd8114192f589e849a9f2a68d4edaaec806bd8ed37b6cb678ad8842453d82 | public Object generateId(Object forPojo) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
id = generator.generateId(forPojo);
return id;
}
```
| public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
id = generator.generateId(forPojo);
return id;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public Object generateId(Object forPojo) {
// 04-Jun-2016, tatu: As per [databind#1255], need to consider possibility of
// id being generated for "alwaysAsId", but not being written as POJO; regardless,
// need to use existing id if there is one:
id = generator.generateId(forPojo);
return id;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
56 | 005766411469575f53bb173eea8c7bf90dde1a7f0a41babdf02122b2f96f7975 | public int[] getCounts(int index) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Convert to multidimensional counter.
*
* @param index Index in unidimensional counter.
* @return the multidimensional counts.
* @throws OutOfRangeException if {@code index} is not between
* {@code 0} and the value returned by {@link #getSize()} (excluded).
*/
public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
indices[last] = index - count;
return indices;
}
```
| public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
indices[last] = index - count;
return indices;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Convert to multidimensional counter.
*
* @param index Index in unidimensional counter.
* @return the multidimensional counts.
* @throws OutOfRangeException if {@code index} is not between
* {@code 0} and the value returned by {@link #getSize()} (excluded).
*/
public int[] getCounts(int index) {
if (index < 0 ||
index >= totalSize) {
throw new OutOfRangeException(index, 0, totalSize);
}
final int[] indices = new int[dimension];
int count = 0;
for (int i = 0; i < last; i++) {
int idx = 0;
final int offset = uniCounterOffset[i];
while (count <= index) {
count += offset;
++idx;
}
--idx;
count -= offset;
indices[i] = idx;
}
indices[last] = index - count;
return indices;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 009c707abb74fee8886efd9438bf903d296c8a30fda3f2d2eba55ba6d536e836 | public static byte[] encodeBase64(byte[] binaryData, boolean isChunked, boolean urlSafe, int maxResultSize) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Encodes binary data using the base64 algorithm, optionally chunking the output into 76 character blocks.
*
* @param binaryData
* Array containing binary data to encode.
* @param isChunked
* if <code>true</code> this encoder will chunk the base64 output into 76 character blocks
* @param urlSafe
* if <code>true</code> this encoder will emit - and _ instead of the usual + and / characters.
* @param maxResultSize
* The maximum result size to accept.
* @return Base64-encoded data.
* @throws IllegalArgumentException
* Thrown when the input array needs an output array bigger than maxResultSize
* @since 1.4
*/
public static byte[] encodeBase64(byte[] binaryData, boolean isChunked, boolean urlSafe, int maxResultSize) {
if (binaryData == null || binaryData.length == 0) {
return binaryData;
}
long len = getEncodeLength(binaryData, isChunked ? MIME_CHUNK_SIZE : 0, CHUNK_SEPARATOR);
if (len > maxResultSize) {
throw new IllegalArgumentException("Input array too big, the output array would be bigger (" +
len +
") than the specified maxium size of " +
maxResultSize);
}
Base64 b64 = isChunked ? new Base64(urlSafe) : new Base64(0, CHUNK_SEPARATOR, urlSafe);
return b64.encode(binaryData);
}
```
| public static byte[] encodeBase64(byte[] binaryData, boolean isChunked, boolean urlSafe, int maxResultSize) {
if (binaryData == null || binaryData.length == 0) {
return binaryData;
}
long len = getEncodeLength(binaryData, isChunked ? MIME_CHUNK_SIZE : 0, CHUNK_SEPARATOR);
if (len > maxResultSize) {
throw new IllegalArgumentException("Input array too big, the output array would be bigger (" +
len +
") than the specified maxium size of " +
maxResultSize);
}
Base64 b64 = isChunked ? new Base64(urlSafe) : new Base64(0, CHUNK_SEPARATOR, urlSafe);
return b64.encode(binaryData);
} | false | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Encodes binary data using the base64 algorithm, optionally chunking the output into 76 character blocks.
*
* @param binaryData
* Array containing binary data to encode.
* @param isChunked
* if <code>true</code> this encoder will chunk the base64 output into 76 character blocks
* @param urlSafe
* if <code>true</code> this encoder will emit - and _ instead of the usual + and / characters.
* @param maxResultSize
* The maximum result size to accept.
* @return Base64-encoded data.
* @throws IllegalArgumentException
* Thrown when the input array needs an output array bigger than maxResultSize
* @since 1.4
*/
public static byte[] encodeBase64(byte[] binaryData, boolean isChunked, boolean urlSafe, int maxResultSize) {
if (binaryData == null || binaryData.length == 0) {
return binaryData;
}
long len = getEncodeLength(binaryData, isChunked ? MIME_CHUNK_SIZE : 0, CHUNK_SEPARATOR);
if (len > maxResultSize) {
throw new IllegalArgumentException("Input array too big, the output array would be bigger (" +
len +
") than the specified maxium size of " +
maxResultSize);
}
Base64 b64 = isChunked ? new Base64(urlSafe) : new Base64(0, CHUNK_SEPARATOR, urlSafe);
return b64.encode(binaryData);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | 00d45f48dfdcff13baeaca61654b0467fae727dfc323d7f3c67af5b8b5e266db | public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
this.checksum = checksum;
this.in = in;
}
```
| public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
this.checksum = checksum;
this.in = in;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public ChecksumCalculatingInputStream(final Checksum checksum, final InputStream in) {
this.checksum = checksum;
this.in = in;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
64 | 0158d98cfe414fb8a3a32ae6d96b1f61a405dfb4990b3823d1a57a8895dffe26 | @Override
protected VectorialPointValuePair doOptimize()
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected VectorialPointValuePair doOptimize()
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
// arrays shared with the other private methods
solvedCols = Math.min(rows, cols);
diagR = new double[cols];
jacNorm = new double[cols];
beta = new double[cols];
permutation = new int[cols];
lmDir = new double[cols];
// local point
double delta = 0;
double xNorm = 0;
double[] diag = new double[cols];
double[] oldX = new double[cols];
double[] oldRes = new double[rows];
double[] work1 = new double[cols];
double[] work2 = new double[cols];
double[] work3 = new double[cols];
// evaluate the function at the starting point and calculate its norm
updateResidualsAndCost();
// outer loop
lmPar = 0;
boolean firstIteration = true;
VectorialPointValuePair current = new VectorialPointValuePair(point, objective);
while (true) {
incrementIterationsCounter();
// compute the Q.R. decomposition of the jacobian matrix
VectorialPointValuePair previous = current;
updateJacobian();
qrDecomposition();
// compute Qt.res
qTy(residuals);
// now we don't need Q anymore,
// so let jacobian contain the R matrix with its diagonal elements
for (int k = 0; k < solvedCols; ++k) {
int pk = permutation[k];
jacobian[k][pk] = diagR[pk];
}
if (firstIteration) {
// scale the point according to the norms of the columns
// of the initial jacobian
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double dk = jacNorm[k];
if (dk == 0) {
dk = 1.0;
}
double xk = dk * point[k];
xNorm += xk * xk;
diag[k] = dk;
}
xNorm = Math.sqrt(xNorm);
// initialize the step bound delta
delta = (xNorm == 0) ? initialStepBoundFactor : (initialStepBoundFactor * xNorm);
}
// check orthogonality between function vector and jacobian columns
double maxCosine = 0;
if (cost != 0) {
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double s = jacNorm[pj];
if (s != 0) {
double sum = 0;
for (int i = 0; i <= j; ++i) {
sum += jacobian[i][pj] * residuals[i];
}
maxCosine = Math.max(maxCosine, Math.abs(sum) / (s * cost));
}
}
}
if (maxCosine <= orthoTolerance) {
// convergence has been reached
return current;
}
// rescale if necessary
for (int j = 0; j < cols; ++j) {
diag[j] = Math.max(diag[j], jacNorm[j]);
}
// inner loop
for (double ratio = 0; ratio < 1.0e-4;) {
// save the state
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
oldX[pj] = point[pj];
}
double previousCost = cost;
double[] tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
// determine the Levenberg-Marquardt parameter
determineLMParameter(oldRes, delta, diag, work1, work2, work3);
// compute the new point and the norm of the evolution direction
double lmNorm = 0;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
lmDir[pj] = -lmDir[pj];
point[pj] = oldX[pj] + lmDir[pj];
double s = diag[pj] * lmDir[pj];
lmNorm += s * s;
}
lmNorm = Math.sqrt(lmNorm);
// on the first iteration, adjust the initial step bound.
if (firstIteration) {
delta = Math.min(delta, lmNorm);
}
// evaluate the function at x + p and calculate its norm
updateResidualsAndCost();
current = new VectorialPointValuePair(point, objective);
// compute the scaled actual reduction
double actRed = -1.0;
if (0.1 * cost < previousCost) {
double r = cost / previousCost;
actRed = 1.0 - r * r;
}
// compute the scaled predicted reduction
// and the scaled directional derivative
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double dirJ = lmDir[pj];
work1[j] = 0;
for (int i = 0; i <= j; ++i) {
work1[i] += jacobian[i][pj] * dirJ;
}
}
double coeff1 = 0;
for (int j = 0; j < solvedCols; ++j) {
coeff1 += work1[j] * work1[j];
}
double pc2 = previousCost * previousCost;
coeff1 = coeff1 / pc2;
double coeff2 = lmPar * lmNorm * lmNorm / pc2;
double preRed = coeff1 + 2 * coeff2;
double dirDer = -(coeff1 + coeff2);
// ratio of the actual to the predicted reduction
ratio = (preRed == 0) ? 0 : (actRed / preRed);
// update the step bound
if (ratio <= 0.25) {
double tmp =
(actRed < 0) ? (0.5 * dirDer / (dirDer + 0.5 * actRed)) : 0.5;
if ((0.1 * cost >= previousCost) || (tmp < 0.1)) {
tmp = 0.1;
}
delta = tmp * Math.min(delta, 10.0 * lmNorm);
lmPar /= tmp;
} else if ((lmPar == 0) || (ratio >= 0.75)) {
delta = 2 * lmNorm;
lmPar *= 0.5;
}
// test for successful iteration.
if (ratio >= 1.0e-4) {
// successful iteration, update the norm
firstIteration = false;
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double xK = diag[k] * point[k];
xNorm += xK * xK;
}
xNorm = Math.sqrt(xNorm);
// tests for convergence.
// we use the vectorial convergence checker
} else {
// failed iteration, reset the previous values
cost = previousCost;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
point[pj] = oldX[pj];
}
tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
}
if (checker==null) {
if (((Math.abs(actRed) <= costRelativeTolerance) &&
(preRed <= costRelativeTolerance) &&
(ratio <= 2.0)) ||
(delta <= parRelativeTolerance * xNorm)) {
return current;
}
} else {
if (checker.converged(getIterations(), previous, current)) {
return current;
}
}
// tests for termination and stringent tolerances
// (2.2204e-16 is the machine epsilon for IEEE754)
if ((Math.abs(actRed) <= 2.2204e-16) && (preRed <= 2.2204e-16) && (ratio <= 2.0)) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_COST_RELATIVE_TOLERANCE,
costRelativeTolerance);
} else if (delta <= 2.2204e-16 * xNorm) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_PARAMETERS_RELATIVE_TOLERANCE,
parRelativeTolerance);
} else if (maxCosine <= 2.2204e-16) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_ORTHOGONALITY_TOLERANCE,
orthoTolerance);
}
}
}
}
```
| @Override
protected VectorialPointValuePair doOptimize()
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
// arrays shared with the other private methods
solvedCols = Math.min(rows, cols);
diagR = new double[cols];
jacNorm = new double[cols];
beta = new double[cols];
permutation = new int[cols];
lmDir = new double[cols];
// local point
double delta = 0;
double xNorm = 0;
double[] diag = new double[cols];
double[] oldX = new double[cols];
double[] oldRes = new double[rows];
double[] work1 = new double[cols];
double[] work2 = new double[cols];
double[] work3 = new double[cols];
// evaluate the function at the starting point and calculate its norm
updateResidualsAndCost();
// outer loop
lmPar = 0;
boolean firstIteration = true;
VectorialPointValuePair current = new VectorialPointValuePair(point, objective);
while (true) {
incrementIterationsCounter();
// compute the Q.R. decomposition of the jacobian matrix
VectorialPointValuePair previous = current;
updateJacobian();
qrDecomposition();
// compute Qt.res
qTy(residuals);
// now we don't need Q anymore,
// so let jacobian contain the R matrix with its diagonal elements
for (int k = 0; k < solvedCols; ++k) {
int pk = permutation[k];
jacobian[k][pk] = diagR[pk];
}
if (firstIteration) {
// scale the point according to the norms of the columns
// of the initial jacobian
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double dk = jacNorm[k];
if (dk == 0) {
dk = 1.0;
}
double xk = dk * point[k];
xNorm += xk * xk;
diag[k] = dk;
}
xNorm = Math.sqrt(xNorm);
// initialize the step bound delta
delta = (xNorm == 0) ? initialStepBoundFactor : (initialStepBoundFactor * xNorm);
}
// check orthogonality between function vector and jacobian columns
double maxCosine = 0;
if (cost != 0) {
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double s = jacNorm[pj];
if (s != 0) {
double sum = 0;
for (int i = 0; i <= j; ++i) {
sum += jacobian[i][pj] * residuals[i];
}
maxCosine = Math.max(maxCosine, Math.abs(sum) / (s * cost));
}
}
}
if (maxCosine <= orthoTolerance) {
// convergence has been reached
return current;
}
// rescale if necessary
for (int j = 0; j < cols; ++j) {
diag[j] = Math.max(diag[j], jacNorm[j]);
}
// inner loop
for (double ratio = 0; ratio < 1.0e-4;) {
// save the state
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
oldX[pj] = point[pj];
}
double previousCost = cost;
double[] tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
// determine the Levenberg-Marquardt parameter
determineLMParameter(oldRes, delta, diag, work1, work2, work3);
// compute the new point and the norm of the evolution direction
double lmNorm = 0;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
lmDir[pj] = -lmDir[pj];
point[pj] = oldX[pj] + lmDir[pj];
double s = diag[pj] * lmDir[pj];
lmNorm += s * s;
}
lmNorm = Math.sqrt(lmNorm);
// on the first iteration, adjust the initial step bound.
if (firstIteration) {
delta = Math.min(delta, lmNorm);
}
// evaluate the function at x + p and calculate its norm
updateResidualsAndCost();
current = new VectorialPointValuePair(point, objective);
// compute the scaled actual reduction
double actRed = -1.0;
if (0.1 * cost < previousCost) {
double r = cost / previousCost;
actRed = 1.0 - r * r;
}
// compute the scaled predicted reduction
// and the scaled directional derivative
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double dirJ = lmDir[pj];
work1[j] = 0;
for (int i = 0; i <= j; ++i) {
work1[i] += jacobian[i][pj] * dirJ;
}
}
double coeff1 = 0;
for (int j = 0; j < solvedCols; ++j) {
coeff1 += work1[j] * work1[j];
}
double pc2 = previousCost * previousCost;
coeff1 = coeff1 / pc2;
double coeff2 = lmPar * lmNorm * lmNorm / pc2;
double preRed = coeff1 + 2 * coeff2;
double dirDer = -(coeff1 + coeff2);
// ratio of the actual to the predicted reduction
ratio = (preRed == 0) ? 0 : (actRed / preRed);
// update the step bound
if (ratio <= 0.25) {
double tmp =
(actRed < 0) ? (0.5 * dirDer / (dirDer + 0.5 * actRed)) : 0.5;
if ((0.1 * cost >= previousCost) || (tmp < 0.1)) {
tmp = 0.1;
}
delta = tmp * Math.min(delta, 10.0 * lmNorm);
lmPar /= tmp;
} else if ((lmPar == 0) || (ratio >= 0.75)) {
delta = 2 * lmNorm;
lmPar *= 0.5;
}
// test for successful iteration.
if (ratio >= 1.0e-4) {
// successful iteration, update the norm
firstIteration = false;
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double xK = diag[k] * point[k];
xNorm += xK * xK;
}
xNorm = Math.sqrt(xNorm);
// tests for convergence.
// we use the vectorial convergence checker
} else {
// failed iteration, reset the previous values
cost = previousCost;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
point[pj] = oldX[pj];
}
tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
}
if (checker==null) {
if (((Math.abs(actRed) <= costRelativeTolerance) &&
(preRed <= costRelativeTolerance) &&
(ratio <= 2.0)) ||
(delta <= parRelativeTolerance * xNorm)) {
return current;
}
} else {
if (checker.converged(getIterations(), previous, current)) {
return current;
}
}
// tests for termination and stringent tolerances
// (2.2204e-16 is the machine epsilon for IEEE754)
if ((Math.abs(actRed) <= 2.2204e-16) && (preRed <= 2.2204e-16) && (ratio <= 2.0)) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_COST_RELATIVE_TOLERANCE,
costRelativeTolerance);
} else if (delta <= 2.2204e-16 * xNorm) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_PARAMETERS_RELATIVE_TOLERANCE,
parRelativeTolerance);
} else if (maxCosine <= 2.2204e-16) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_ORTHOGONALITY_TOLERANCE,
orthoTolerance);
}
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected VectorialPointValuePair doOptimize()
throws FunctionEvaluationException, OptimizationException, IllegalArgumentException {
// arrays shared with the other private methods
solvedCols = Math.min(rows, cols);
diagR = new double[cols];
jacNorm = new double[cols];
beta = new double[cols];
permutation = new int[cols];
lmDir = new double[cols];
// local point
double delta = 0;
double xNorm = 0;
double[] diag = new double[cols];
double[] oldX = new double[cols];
double[] oldRes = new double[rows];
double[] work1 = new double[cols];
double[] work2 = new double[cols];
double[] work3 = new double[cols];
// evaluate the function at the starting point and calculate its norm
updateResidualsAndCost();
// outer loop
lmPar = 0;
boolean firstIteration = true;
VectorialPointValuePair current = new VectorialPointValuePair(point, objective);
while (true) {
incrementIterationsCounter();
// compute the Q.R. decomposition of the jacobian matrix
VectorialPointValuePair previous = current;
updateJacobian();
qrDecomposition();
// compute Qt.res
qTy(residuals);
// now we don't need Q anymore,
// so let jacobian contain the R matrix with its diagonal elements
for (int k = 0; k < solvedCols; ++k) {
int pk = permutation[k];
jacobian[k][pk] = diagR[pk];
}
if (firstIteration) {
// scale the point according to the norms of the columns
// of the initial jacobian
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double dk = jacNorm[k];
if (dk == 0) {
dk = 1.0;
}
double xk = dk * point[k];
xNorm += xk * xk;
diag[k] = dk;
}
xNorm = Math.sqrt(xNorm);
// initialize the step bound delta
delta = (xNorm == 0) ? initialStepBoundFactor : (initialStepBoundFactor * xNorm);
}
// check orthogonality between function vector and jacobian columns
double maxCosine = 0;
if (cost != 0) {
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double s = jacNorm[pj];
if (s != 0) {
double sum = 0;
for (int i = 0; i <= j; ++i) {
sum += jacobian[i][pj] * residuals[i];
}
maxCosine = Math.max(maxCosine, Math.abs(sum) / (s * cost));
}
}
}
if (maxCosine <= orthoTolerance) {
// convergence has been reached
return current;
}
// rescale if necessary
for (int j = 0; j < cols; ++j) {
diag[j] = Math.max(diag[j], jacNorm[j]);
}
// inner loop
for (double ratio = 0; ratio < 1.0e-4;) {
// save the state
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
oldX[pj] = point[pj];
}
double previousCost = cost;
double[] tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
// determine the Levenberg-Marquardt parameter
determineLMParameter(oldRes, delta, diag, work1, work2, work3);
// compute the new point and the norm of the evolution direction
double lmNorm = 0;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
lmDir[pj] = -lmDir[pj];
point[pj] = oldX[pj] + lmDir[pj];
double s = diag[pj] * lmDir[pj];
lmNorm += s * s;
}
lmNorm = Math.sqrt(lmNorm);
// on the first iteration, adjust the initial step bound.
if (firstIteration) {
delta = Math.min(delta, lmNorm);
}
// evaluate the function at x + p and calculate its norm
updateResidualsAndCost();
current = new VectorialPointValuePair(point, objective);
// compute the scaled actual reduction
double actRed = -1.0;
if (0.1 * cost < previousCost) {
double r = cost / previousCost;
actRed = 1.0 - r * r;
}
// compute the scaled predicted reduction
// and the scaled directional derivative
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
double dirJ = lmDir[pj];
work1[j] = 0;
for (int i = 0; i <= j; ++i) {
work1[i] += jacobian[i][pj] * dirJ;
}
}
double coeff1 = 0;
for (int j = 0; j < solvedCols; ++j) {
coeff1 += work1[j] * work1[j];
}
double pc2 = previousCost * previousCost;
coeff1 = coeff1 / pc2;
double coeff2 = lmPar * lmNorm * lmNorm / pc2;
double preRed = coeff1 + 2 * coeff2;
double dirDer = -(coeff1 + coeff2);
// ratio of the actual to the predicted reduction
ratio = (preRed == 0) ? 0 : (actRed / preRed);
// update the step bound
if (ratio <= 0.25) {
double tmp =
(actRed < 0) ? (0.5 * dirDer / (dirDer + 0.5 * actRed)) : 0.5;
if ((0.1 * cost >= previousCost) || (tmp < 0.1)) {
tmp = 0.1;
}
delta = tmp * Math.min(delta, 10.0 * lmNorm);
lmPar /= tmp;
} else if ((lmPar == 0) || (ratio >= 0.75)) {
delta = 2 * lmNorm;
lmPar *= 0.5;
}
// test for successful iteration.
if (ratio >= 1.0e-4) {
// successful iteration, update the norm
firstIteration = false;
xNorm = 0;
for (int k = 0; k < cols; ++k) {
double xK = diag[k] * point[k];
xNorm += xK * xK;
}
xNorm = Math.sqrt(xNorm);
// tests for convergence.
// we use the vectorial convergence checker
} else {
// failed iteration, reset the previous values
cost = previousCost;
for (int j = 0; j < solvedCols; ++j) {
int pj = permutation[j];
point[pj] = oldX[pj];
}
tmpVec = residuals;
residuals = oldRes;
oldRes = tmpVec;
}
if (checker==null) {
if (((Math.abs(actRed) <= costRelativeTolerance) &&
(preRed <= costRelativeTolerance) &&
(ratio <= 2.0)) ||
(delta <= parRelativeTolerance * xNorm)) {
return current;
}
} else {
if (checker.converged(getIterations(), previous, current)) {
return current;
}
}
// tests for termination and stringent tolerances
// (2.2204e-16 is the machine epsilon for IEEE754)
if ((Math.abs(actRed) <= 2.2204e-16) && (preRed <= 2.2204e-16) && (ratio <= 2.0)) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_COST_RELATIVE_TOLERANCE,
costRelativeTolerance);
} else if (delta <= 2.2204e-16 * xNorm) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_PARAMETERS_RELATIVE_TOLERANCE,
parRelativeTolerance);
} else if (maxCosine <= 2.2204e-16) {
throw new OptimizationException(LocalizedFormats.TOO_SMALL_ORTHOGONALITY_TOLERANCE,
orthoTolerance);
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
69 | 01aaeb035d01d4c8d1d27f08b006c3795b07c44d885803cc0661356ebeeb7b73 | public RealMatrix getCorrelationPValues() throws MathException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a matrix of p-values associated with the (two-sided) null
* hypothesis that the corresponding correlation coefficient is zero.
* <p><code>getCorrelationPValues().getEntry(i,j)</code> is the probability
* that a random variable distributed as <code>t<sub>n-2</sub></code> takes
* a value with absolute value greater than or equal to <br>
* <code>|r|((n - 2) / (1 - r<sup>2</sup>))<sup>1/2</sup></code></p>
* <p>The values in the matrix are sometimes referred to as the
* <i>significance</i> of the corresponding correlation coefficients.</p>
*
* @return matrix of p-values
* @throws MathException if an error occurs estimating probabilities
*/
public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * tDistribution.cumulativeProbability(-t);
}
}
}
return new BlockRealMatrix(out);
}
```
| public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * tDistribution.cumulativeProbability(-t);
}
}
}
return new BlockRealMatrix(out);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a matrix of p-values associated with the (two-sided) null
* hypothesis that the corresponding correlation coefficient is zero.
* <p><code>getCorrelationPValues().getEntry(i,j)</code> is the probability
* that a random variable distributed as <code>t<sub>n-2</sub></code> takes
* a value with absolute value greater than or equal to <br>
* <code>|r|((n - 2) / (1 - r<sup>2</sup>))<sup>1/2</sup></code></p>
* <p>The values in the matrix are sometimes referred to as the
* <i>significance</i> of the corresponding correlation coefficients.</p>
*
* @return matrix of p-values
* @throws MathException if an error occurs estimating probabilities
*/
public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * tDistribution.cumulativeProbability(-t);
}
}
}
return new BlockRealMatrix(out);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | 01acbcdc461431351ae990a3bc3f41652287a663f475ee3bdb36f97d6848f8d0 | protected Object readResolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Recalculate the hash code after deserialization. The hash code of some
* keys might have change (hash codes based on the system hash code are
* only stable for the same process).
* @return the instance with recalculated hash code
*/
protected Object readResolve() {
calculateHashCode(keys);
return this;
}
```
| protected Object readResolve() {
calculateHashCode(keys);
return this;
} | false | Collections | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Recalculate the hash code after deserialization. The hash code of some
* keys might have change (hash codes based on the system hash code are
* only stable for the same process).
* @return the instance with recalculated hash code
*/
protected Object readResolve() {
calculateHashCode(keys);
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 026e584d9fa27a59125325a3b985716cbda4a1f1e4f8f006fc1909aacd7e0574 | public static boolean testNode(Node node, NodeTest test) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public static boolean testNode(Node node, NodeTest test) {
if (test == null) {
return true;
}
if (test instanceof NodeNameTest) {
if (node.getNodeType() != Node.ELEMENT_NODE) {
return false;
}
NodeNameTest nodeNameTest = (NodeNameTest) test;
QName testName = nodeNameTest.getNodeName();
String namespaceURI = nodeNameTest.getNamespaceURI();
boolean wildcard = nodeNameTest.isWildcard();
String testPrefix = testName.getPrefix();
if (wildcard && testPrefix == null) {
return true;
}
if (wildcard
|| testName.getName()
.equals(DOMNodePointer.getLocalName(node))) {
String nodeNS = DOMNodePointer.getNamespaceURI(node);
return equalStrings(namespaceURI, nodeNS) || nodeNS == null
&& equalStrings(testPrefix, getPrefix(node));
}
return false;
}
if (test instanceof NodeTypeTest) {
int nodeType = node.getNodeType();
switch (((NodeTypeTest) test).getNodeType()) {
case Compiler.NODE_TYPE_NODE :
return nodeType == Node.ELEMENT_NODE
|| nodeType == Node.DOCUMENT_NODE;
case Compiler.NODE_TYPE_TEXT :
return nodeType == Node.CDATA_SECTION_NODE
|| nodeType == Node.TEXT_NODE;
case Compiler.NODE_TYPE_COMMENT :
return nodeType == Node.COMMENT_NODE;
case Compiler.NODE_TYPE_PI :
return nodeType == Node.PROCESSING_INSTRUCTION_NODE;
}
return false;
}
if (test instanceof ProcessingInstructionTest) {
if (node.getNodeType() == Node.PROCESSING_INSTRUCTION_NODE) {
String testPI = ((ProcessingInstructionTest) test).getTarget();
String nodePI = ((ProcessingInstruction) node).getTarget();
return testPI.equals(nodePI);
}
}
return false;
}
```
| public static boolean testNode(Node node, NodeTest test) {
if (test == null) {
return true;
}
if (test instanceof NodeNameTest) {
if (node.getNodeType() != Node.ELEMENT_NODE) {
return false;
}
NodeNameTest nodeNameTest = (NodeNameTest) test;
QName testName = nodeNameTest.getNodeName();
String namespaceURI = nodeNameTest.getNamespaceURI();
boolean wildcard = nodeNameTest.isWildcard();
String testPrefix = testName.getPrefix();
if (wildcard && testPrefix == null) {
return true;
}
if (wildcard
|| testName.getName()
.equals(DOMNodePointer.getLocalName(node))) {
String nodeNS = DOMNodePointer.getNamespaceURI(node);
return equalStrings(namespaceURI, nodeNS) || nodeNS == null
&& equalStrings(testPrefix, getPrefix(node));
}
return false;
}
if (test instanceof NodeTypeTest) {
int nodeType = node.getNodeType();
switch (((NodeTypeTest) test).getNodeType()) {
case Compiler.NODE_TYPE_NODE :
return nodeType == Node.ELEMENT_NODE
|| nodeType == Node.DOCUMENT_NODE;
case Compiler.NODE_TYPE_TEXT :
return nodeType == Node.CDATA_SECTION_NODE
|| nodeType == Node.TEXT_NODE;
case Compiler.NODE_TYPE_COMMENT :
return nodeType == Node.COMMENT_NODE;
case Compiler.NODE_TYPE_PI :
return nodeType == Node.PROCESSING_INSTRUCTION_NODE;
}
return false;
}
if (test instanceof ProcessingInstructionTest) {
if (node.getNodeType() == Node.PROCESSING_INSTRUCTION_NODE) {
String testPI = ((ProcessingInstructionTest) test).getTarget();
String nodePI = ((ProcessingInstruction) node).getTarget();
return testPI.equals(nodePI);
}
}
return false;
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public static boolean testNode(Node node, NodeTest test) {
if (test == null) {
return true;
}
if (test instanceof NodeNameTest) {
if (node.getNodeType() != Node.ELEMENT_NODE) {
return false;
}
NodeNameTest nodeNameTest = (NodeNameTest) test;
QName testName = nodeNameTest.getNodeName();
String namespaceURI = nodeNameTest.getNamespaceURI();
boolean wildcard = nodeNameTest.isWildcard();
String testPrefix = testName.getPrefix();
if (wildcard && testPrefix == null) {
return true;
}
if (wildcard
|| testName.getName()
.equals(DOMNodePointer.getLocalName(node))) {
String nodeNS = DOMNodePointer.getNamespaceURI(node);
return equalStrings(namespaceURI, nodeNS) || nodeNS == null
&& equalStrings(testPrefix, getPrefix(node));
}
return false;
}
if (test instanceof NodeTypeTest) {
int nodeType = node.getNodeType();
switch (((NodeTypeTest) test).getNodeType()) {
case Compiler.NODE_TYPE_NODE :
return nodeType == Node.ELEMENT_NODE
|| nodeType == Node.DOCUMENT_NODE;
case Compiler.NODE_TYPE_TEXT :
return nodeType == Node.CDATA_SECTION_NODE
|| nodeType == Node.TEXT_NODE;
case Compiler.NODE_TYPE_COMMENT :
return nodeType == Node.COMMENT_NODE;
case Compiler.NODE_TYPE_PI :
return nodeType == Node.PROCESSING_INSTRUCTION_NODE;
}
return false;
}
if (test instanceof ProcessingInstructionTest) {
if (node.getNodeType() == Node.PROCESSING_INSTRUCTION_NODE) {
String testPI = ((ProcessingInstructionTest) test).getTarget();
String nodePI = ((ProcessingInstruction) node).getTarget();
return testPI.equals(nodePI);
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 02dbd41bb642cf837928089c43b8120f408701131b9f2e29919f8c7ecc4cbc93 | private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// the original object is needed so can check for Number
/*
* Note: must only be called if quoting is enabled, otherwise will generate NPE
*/
private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
// RFC4180 (https://tools.ietf.org/html/rfc4180) TEXTDATA = %x20-21 / %x23-2B / %x2D-7E
if (newRecord && (c < 0x20 || c > 0x21 && c < 0x23 || c > 0x2B && c < 0x2D || c > 0x7E)) {
quote = true;
} else if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
}
```
| private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
// RFC4180 (https://tools.ietf.org/html/rfc4180) TEXTDATA = %x20-21 / %x23-2B / %x2D-7E
if (newRecord && (c < 0x20 || c > 0x21 && c < 0x23 || c > 0x2B && c < 0x2D || c > 0x7E)) {
quote = true;
} else if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// the original object is needed so can check for Number
/*
* Note: must only be called if quoting is enabled, otherwise will generate NPE
*/
private void printAndQuote(final Object object, final CharSequence value, final int offset, final int len,
final Appendable out, final boolean newRecord) throws IOException {
boolean quote = false;
int start = offset;
int pos = offset;
final int end = offset + len;
final char delimChar = getDelimiter();
final char quoteChar = getQuoteCharacter().charValue();
QuoteMode quoteModePolicy = getQuoteMode();
if (quoteModePolicy == null) {
quoteModePolicy = QuoteMode.MINIMAL;
}
switch (quoteModePolicy) {
case ALL:
quote = true;
break;
case NON_NUMERIC:
quote = !(object instanceof Number);
break;
case NONE:
// Use the existing escaping code
printAndEscape(value, offset, len, out);
return;
case MINIMAL:
if (len <= 0) {
// always quote an empty token that is the first
// on the line, as it may be the only thing on the
// line. If it were not quoted in that case,
// an empty line has no tokens.
if (newRecord) {
quote = true;
}
} else {
char c = value.charAt(pos);
// RFC4180 (https://tools.ietf.org/html/rfc4180) TEXTDATA = %x20-21 / %x23-2B / %x2D-7E
if (newRecord && (c < 0x20 || c > 0x21 && c < 0x23 || c > 0x2B && c < 0x2D || c > 0x7E)) {
quote = true;
} else if (c <= COMMENT) {
// Some other chars at the start of a value caused the parser to fail, so for now
// encapsulate if we start in anything less than '#'. We are being conservative
// by including the default comment char too.
quote = true;
} else {
while (pos < end) {
c = value.charAt(pos);
if (c == LF || c == CR || c == quoteChar || c == delimChar) {
quote = true;
break;
}
pos++;
}
if (!quote) {
pos = end - 1;
c = value.charAt(pos);
// Some other chars at the end caused the parser to fail, so for now
// encapsulate if we end in anything less than ' '
if (c <= SP) {
quote = true;
}
}
}
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
break;
default:
throw new IllegalStateException("Unexpected Quote value: " + quoteModePolicy);
}
if (!quote) {
// no encapsulation needed - write out the original value
out.append(value, start, end);
return;
}
// we hit something that needed encapsulation
out.append(quoteChar);
// Pick up where we left off: pos should be positioned on the first character that caused
// the need for encapsulation.
while (pos < end) {
final char c = value.charAt(pos);
if (c == quoteChar) {
// write out the chunk up until this point
// add 1 to the length to write out the encapsulator also
out.append(value, start, pos + 1);
// put the next starting position on the encapsulator so we will
// write it out again with the next string (effectively doubling it)
start = pos;
}
pos++;
}
// write the last segment
out.append(value, start, pos);
out.append(quoteChar);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 0333892c1bc5fe1cc714de6516cda940d9c7be98f623022728005a3d849e6f18 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NULs or spaces
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 03df2fb19b2492481fa56e8b47f12b009db93985a08ad7d5b5b020579d41486a | protected Date parseAsISO8601(String dateStr, ParsePosition pos)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
int timeLen = len - dateStr.lastIndexOf('T') - 6;
if (timeLen < 12) { // 8 for hh:mm:ss, 4 for .sss
int offset = len - 5; // insertion offset, before tz-offset
StringBuilder sb = new StringBuilder(dateStr);
switch (timeLen) {
case 11:
sb.insert(offset, '0'); break;
case 10:
sb.insert(offset, "00"); break;
case 9: // is this legal? (just second fraction marker)
sb.insert(offset, "000"); break;
case 8:
sb.insert(offset, ".000"); break;
case 7: // not legal to have single-digit second
break;
case 6: // probably not legal, but let's allow
sb.insert(offset, "00.000");
case 5: // is legal to omit seconds
sb.insert(offset, ":00.000");
}
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen < 12) { // missing, or partial
switch (timeLen) {
case 11: sb.append('0');
case 10: sb.append('0');
case 9: sb.append('0');
break;
default:
sb.append(".000");
}
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
}
```
| protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
int timeLen = len - dateStr.lastIndexOf('T') - 6;
if (timeLen < 12) { // 8 for hh:mm:ss, 4 for .sss
int offset = len - 5; // insertion offset, before tz-offset
StringBuilder sb = new StringBuilder(dateStr);
switch (timeLen) {
case 11:
sb.insert(offset, '0'); break;
case 10:
sb.insert(offset, "00"); break;
case 9: // is this legal? (just second fraction marker)
sb.insert(offset, "000"); break;
case 8:
sb.insert(offset, ".000"); break;
case 7: // not legal to have single-digit second
break;
case 6: // probably not legal, but let's allow
sb.insert(offset, "00.000");
case 5: // is legal to omit seconds
sb.insert(offset, ":00.000");
}
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen < 12) { // missing, or partial
switch (timeLen) {
case 11: sb.append('0');
case 10: sb.append('0');
case 9: sb.append('0');
break;
default:
sb.append(".000");
}
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected Date parseAsISO8601(String dateStr, ParsePosition pos)
{
/* 21-May-2009, tatu: DateFormat has very strict handling of
* timezone modifiers for ISO-8601. So we need to do some scrubbing.
*/
/* First: do we have "zulu" format ('Z' == "GMT")? If yes, that's
* quite simple because we already set date format timezone to be
* GMT, and hence can just strip out 'Z' altogether
*/
int len = dateStr.length();
char c = dateStr.charAt(len-1);
DateFormat df;
// [JACKSON-200]: need to support "plain" date...
if (len <= 10 && Character.isDigit(c)) {
df = _formatPlain;
if (df == null) {
df = _formatPlain = _cloneFormat(DATE_FORMAT_PLAIN, DATE_FORMAT_STR_PLAIN, _timezone, _locale);
}
} else if (c == 'Z') {
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z, _timezone, _locale);
}
// [JACKSON-334]: may be missing milliseconds... if so, add
if (dateStr.charAt(len-4) == ':') {
StringBuilder sb = new StringBuilder(dateStr);
sb.insert(len-1, ".000");
dateStr = sb.toString();
}
} else {
// Let's see if we have timezone indicator or not...
if (hasTimeZone(dateStr)) {
c = dateStr.charAt(len-3);
if (c == ':') { // remove optional colon
// remove colon
StringBuilder sb = new StringBuilder(dateStr);
sb.delete(len-3, len-2);
dateStr = sb.toString();
} else if (c == '+' || c == '-') { // missing minutes
// let's just append '00'
dateStr += "00";
}
// Milliseconds partial or missing; and even seconds are optional
len = dateStr.length();
// remove 'T', '+'/'-' and 4-digit timezone-offset
int timeLen = len - dateStr.lastIndexOf('T') - 6;
if (timeLen < 12) { // 8 for hh:mm:ss, 4 for .sss
int offset = len - 5; // insertion offset, before tz-offset
StringBuilder sb = new StringBuilder(dateStr);
switch (timeLen) {
case 11:
sb.insert(offset, '0'); break;
case 10:
sb.insert(offset, "00"); break;
case 9: // is this legal? (just second fraction marker)
sb.insert(offset, "000"); break;
case 8:
sb.insert(offset, ".000"); break;
case 7: // not legal to have single-digit second
break;
case 6: // probably not legal, but let's allow
sb.insert(offset, "00.000");
case 5: // is legal to omit seconds
sb.insert(offset, ":00.000");
}
dateStr = sb.toString();
}
df = _formatISO8601;
if (_formatISO8601 == null) {
df = _formatISO8601 = _cloneFormat(DATE_FORMAT_ISO8601, DATE_FORMAT_STR_ISO8601, _timezone, _locale);
}
} else {
// If not, plain date. Easiest to just patch 'Z' in the end?
StringBuilder sb = new StringBuilder(dateStr);
// And possible also millisecond part if missing
int timeLen = len - dateStr.lastIndexOf('T') - 1;
if (timeLen < 12) { // missing, or partial
switch (timeLen) {
case 11: sb.append('0');
case 10: sb.append('0');
case 9: sb.append('0');
break;
default:
sb.append(".000");
}
}
sb.append('Z');
dateStr = sb.toString();
df = _formatISO8601_z;
if (df == null) {
df = _formatISO8601_z = _cloneFormat(DATE_FORMAT_ISO8601_Z, DATE_FORMAT_STR_ISO8601_Z,
_timezone, _locale);
}
}
}
return df.parse(dateStr, pos);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 03dfd2232cf696847135295ae934fc27908fa8cc7a0a8491f431b3a5531402c2 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Must have trailing NUL or space
byte trailer;
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
// May have additional NUL or space
trailer = buffer[end-1];
if (trailer == 0 || trailer == ' '){
end--;
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 0426404284b434dcab9d3df59660c1da80b843010e30986b61dd60d251151ead | private void _verifySharing()
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
_verifyNeedForRehash();
}
if (_needRehash) {
rehash();
}
}
```
| private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
_verifyNeedForRehash();
}
if (_needRehash) {
rehash();
}
} | false | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void _verifySharing()
{
if (_hashShared) {
_hashArea = Arrays.copyOf(_hashArea, _hashArea.length);
_names = Arrays.copyOf(_names, _names.length);
_hashShared = false;
// 09-Sep-2015, tatu: As per [jackson-core#216], also need to ensure
// we rehash as needed, as need-rehash flag is not copied from parent
_verifyNeedForRehash();
}
if (_needRehash) {
rehash();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 042f86defc783a66d90a7bbcd371e7cf674c42422b5ecb86983b718ca0e130bf | @Override
public boolean apply(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
if (n.isDelProp()) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
}
```
| @Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
if (n.isDelProp()) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
if (n.isDelProp()) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | 04739a2666d8a52509ac2cc157e4936459655fc861f416ce206bf64a70e0d5ca | public static Number createNumber(String val) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can hold the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* @param val String containing a number
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//--------------------------------------------------------------------
public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
}
```
| public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can hold the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* @param val String containing a number
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//--------------------------------------------------------------------
public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 04d155999360524fd46b44fc324a483c0db95ea565f9c99743f83d0e5d139894 | public OpenMapRealMatrix(int rowDimension, int columnDimension) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Build a sparse matrix with the supplied row and column dimensions.
*
* @param rowDimension Number of rows of the matrix.
* @param columnDimension Number of columns of the matrix.
*/
public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
}
```
| public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Build a sparse matrix with the supplied row and column dimensions.
*
* @param rowDimension Number of rows of the matrix.
* @param columnDimension Number of columns of the matrix.
*/
public OpenMapRealMatrix(int rowDimension, int columnDimension) {
super(rowDimension, columnDimension);
this.rows = rowDimension;
this.columns = columnDimension;
this.entries = new OpenIntToDoubleHashMap(0.0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | 068d55466571807d31d50cb8e91b4398b4b895756f6a1bf4979c8609e3409375 | public RectangularCholeskyDecomposition(RealMatrix matrix, double small)
throws NonPositiveDefiniteMatrixException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Decompose a symmetric positive semidefinite matrix.
*
* @param matrix Symmetric positive semidefinite matrix.
* @param small Diagonal elements threshold under which column are
* considered to be dependent on previous ones and are discarded.
* @exception NonPositiveDefiniteMatrixException if the matrix is not
* positive semidefinite.
*/
public RectangularCholeskyDecomposition(RealMatrix matrix, double small)
throws NonPositiveDefiniteMatrixException {
final int order = matrix.getRowDimension();
final double[][] c = matrix.getData();
final double[][] b = new double[order][order];
int[] index = new int[order];
for (int i = 0; i < order; ++i) {
index[i] = i;
}
int r = 0;
for (boolean loop = true; loop;) {
// find maximal diagonal element
int swapR = r;
for (int i = r + 1; i < order; ++i) {
int ii = index[i];
int isr = index[swapR];
if (c[ii][ii] > c[isr][isr]) {
swapR = i;
}
}
// swap elements
if (swapR != r) {
final int tmpIndex = index[r];
index[r] = index[swapR];
index[swapR] = tmpIndex;
final double[] tmpRow = b[r];
b[r] = b[swapR];
b[swapR] = tmpRow;
}
// check diagonal element
int ir = index[r];
if (c[ir][ir] < small) {
if (r == 0) {
throw new NonPositiveDefiniteMatrixException(c[ir][ir], ir, small);
}
// check remaining diagonal elements
for (int i = r; i < order; ++i) {
if (c[index[i]][index[i]] < -small) {
// there is at least one sufficiently negative diagonal element,
// the symmetric positive semidefinite matrix is wrong
throw new NonPositiveDefiniteMatrixException(c[index[i]][index[i]], i, small);
}
}
// all remaining diagonal elements are close to zero, we consider we have
// found the rank of the symmetric positive semidefinite matrix
++r;
loop = false;
} else {
// transform the matrix
final double sqrt = FastMath.sqrt(c[ir][ir]);
b[r][r] = sqrt;
final double inverse = 1 / sqrt;
final double inverse2 = 1 / c[ir][ir];
for (int i = r + 1; i < order; ++i) {
final int ii = index[i];
final double e = inverse * c[ii][ir];
b[i][r] = e;
c[ii][ii] -= c[ii][ir] * c[ii][ir] * inverse2;
for (int j = r + 1; j < i; ++j) {
final int ij = index[j];
final double f = c[ii][ij] - e * b[j][r];
c[ii][ij] = f;
c[ij][ii] = f;
}
}
// prepare next iteration
loop = ++r < order;
}
}
// build the root matrix
rank = r;
root = MatrixUtils.createRealMatrix(order, r);
for (int i = 0; i < order; ++i) {
for (int j = 0; j < r; ++j) {
root.setEntry(index[i], j, b[i][j]);
}
}
}
```
| public RectangularCholeskyDecomposition(RealMatrix matrix, double small)
throws NonPositiveDefiniteMatrixException {
final int order = matrix.getRowDimension();
final double[][] c = matrix.getData();
final double[][] b = new double[order][order];
int[] index = new int[order];
for (int i = 0; i < order; ++i) {
index[i] = i;
}
int r = 0;
for (boolean loop = true; loop;) {
// find maximal diagonal element
int swapR = r;
for (int i = r + 1; i < order; ++i) {
int ii = index[i];
int isr = index[swapR];
if (c[ii][ii] > c[isr][isr]) {
swapR = i;
}
}
// swap elements
if (swapR != r) {
final int tmpIndex = index[r];
index[r] = index[swapR];
index[swapR] = tmpIndex;
final double[] tmpRow = b[r];
b[r] = b[swapR];
b[swapR] = tmpRow;
}
// check diagonal element
int ir = index[r];
if (c[ir][ir] < small) {
if (r == 0) {
throw new NonPositiveDefiniteMatrixException(c[ir][ir], ir, small);
}
// check remaining diagonal elements
for (int i = r; i < order; ++i) {
if (c[index[i]][index[i]] < -small) {
// there is at least one sufficiently negative diagonal element,
// the symmetric positive semidefinite matrix is wrong
throw new NonPositiveDefiniteMatrixException(c[index[i]][index[i]], i, small);
}
}
// all remaining diagonal elements are close to zero, we consider we have
// found the rank of the symmetric positive semidefinite matrix
++r;
loop = false;
} else {
// transform the matrix
final double sqrt = FastMath.sqrt(c[ir][ir]);
b[r][r] = sqrt;
final double inverse = 1 / sqrt;
final double inverse2 = 1 / c[ir][ir];
for (int i = r + 1; i < order; ++i) {
final int ii = index[i];
final double e = inverse * c[ii][ir];
b[i][r] = e;
c[ii][ii] -= c[ii][ir] * c[ii][ir] * inverse2;
for (int j = r + 1; j < i; ++j) {
final int ij = index[j];
final double f = c[ii][ij] - e * b[j][r];
c[ii][ij] = f;
c[ij][ii] = f;
}
}
// prepare next iteration
loop = ++r < order;
}
}
// build the root matrix
rank = r;
root = MatrixUtils.createRealMatrix(order, r);
for (int i = 0; i < order; ++i) {
for (int j = 0; j < r; ++j) {
root.setEntry(index[i], j, b[i][j]);
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Decompose a symmetric positive semidefinite matrix.
*
* @param matrix Symmetric positive semidefinite matrix.
* @param small Diagonal elements threshold under which column are
* considered to be dependent on previous ones and are discarded.
* @exception NonPositiveDefiniteMatrixException if the matrix is not
* positive semidefinite.
*/
public RectangularCholeskyDecomposition(RealMatrix matrix, double small)
throws NonPositiveDefiniteMatrixException {
final int order = matrix.getRowDimension();
final double[][] c = matrix.getData();
final double[][] b = new double[order][order];
int[] index = new int[order];
for (int i = 0; i < order; ++i) {
index[i] = i;
}
int r = 0;
for (boolean loop = true; loop;) {
// find maximal diagonal element
int swapR = r;
for (int i = r + 1; i < order; ++i) {
int ii = index[i];
int isr = index[swapR];
if (c[ii][ii] > c[isr][isr]) {
swapR = i;
}
}
// swap elements
if (swapR != r) {
final int tmpIndex = index[r];
index[r] = index[swapR];
index[swapR] = tmpIndex;
final double[] tmpRow = b[r];
b[r] = b[swapR];
b[swapR] = tmpRow;
}
// check diagonal element
int ir = index[r];
if (c[ir][ir] < small) {
if (r == 0) {
throw new NonPositiveDefiniteMatrixException(c[ir][ir], ir, small);
}
// check remaining diagonal elements
for (int i = r; i < order; ++i) {
if (c[index[i]][index[i]] < -small) {
// there is at least one sufficiently negative diagonal element,
// the symmetric positive semidefinite matrix is wrong
throw new NonPositiveDefiniteMatrixException(c[index[i]][index[i]], i, small);
}
}
// all remaining diagonal elements are close to zero, we consider we have
// found the rank of the symmetric positive semidefinite matrix
++r;
loop = false;
} else {
// transform the matrix
final double sqrt = FastMath.sqrt(c[ir][ir]);
b[r][r] = sqrt;
final double inverse = 1 / sqrt;
final double inverse2 = 1 / c[ir][ir];
for (int i = r + 1; i < order; ++i) {
final int ii = index[i];
final double e = inverse * c[ii][ir];
b[i][r] = e;
c[ii][ii] -= c[ii][ir] * c[ii][ir] * inverse2;
for (int j = r + 1; j < i; ++j) {
final int ij = index[j];
final double f = c[ii][ij] - e * b[j][r];
c[ii][ij] = f;
c[ij][ii] = f;
}
}
// prepare next iteration
loop = ++r < order;
}
}
// build the root matrix
rank = r;
root = MatrixUtils.createRealMatrix(order, r);
for (int i = 0; i < order; ++i) {
for (int j = 0; j < r; ++j) {
root.setEntry(index[i], j, b[i][j]);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
168 | 06aff8eb61731834f153e0ebd4862796ddd9439f5d7cb0cf739708a7d6493b56 | @Override public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 1) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
}
```
| @Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 1) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (t.inGlobalScope()) {
return;
}
if (n.isReturn() && n.getFirstChild() != null) {
data.get(t.getScopeRoot()).recordNonEmptyReturn();
}
if (t.getScopeDepth() <= 1) {
// The first-order function analyzer looks at two types of variables:
//
// 1) Local variables that are assigned in inner scopes ("escaped vars")
//
// 2) Local variables that are assigned more than once.
//
// We treat all global variables as escaped by default, so there's
// no reason to do this extra computation for them.
return;
}
if (n.isName() && NodeUtil.isLValue(n) &&
// Be careful of bleeding functions, which create variables
// in the inner scope, not the scope where the name appears.
!NodeUtil.isBleedingFunctionName(n)) {
String name = n.getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordAssignedName(name);
}
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode()).recordEscapedVarName(name);
}
}
} else if (n.isGetProp() && n.isUnscopedQualifiedName() &&
NodeUtil.isLValue(n)) {
String name = NodeUtil.getRootOfQualifiedName(n).getString();
Scope scope = t.getScope();
Var var = scope.getVar(name);
if (var != null) {
Scope ownerScope = var.getScope();
if (scope != ownerScope && ownerScope.isLocal()) {
data.get(ownerScope.getRootNode())
.recordEscapedQualifiedName(n.getQualifiedName());
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
83 | 0783635360dc21c95655011b167c16394efb66666d557066ca8acc6995ef3f0b | @Override
public int parseArguments(Parameters params) throws CmdLineException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = params.getParameter(0);
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
}
```
| @Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = params.getParameter(0);
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public int parseArguments(Parameters params) throws CmdLineException {
String param = params.getParameter(0);
if (param == null) {
setter.addValue(true);
return 0;
} else {
String lowerParam = param.toLowerCase();
if (TRUES.contains(lowerParam)) {
setter.addValue(true);
} else if (FALSES.contains(lowerParam)) {
setter.addValue(false);
} else {
setter.addValue(true);
return 0;
}
return 1;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 079402779a26dce393da6ca298bc19d09b8703bec0f4593cf8034e7b18c7d1c5 | static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
if (docData.charAt(0) == 65279)
docData = docData.substring(1);
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
```
| static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
if (docData.charAt(0) == 65279)
docData = docData.substring(1);
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = meta.hasAttr("http-equiv") ? getCharsetFromContentType(meta.attr("content")) : meta.attr("charset");
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
// there are times where there is a spurious byte-order-mark at the start of the text. Shouldn't be present
// in utf-8. If after decoding, there is a BOM, strip it; otherwise will cause the parser to go straight
// into head mode
if (docData.charAt(0) == 65279)
docData = docData.substring(1);
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
95 | 07a011996f0aa1a4cea591d2c1c9d1f096021c48b76b2b9df92dfdfd2479f1fe | protected double getInitialDomain(double p) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Access the initial domain value, based on <code>p</code>, used to
* bracket a CDF root. This method is used by
* {@link #inverseCumulativeProbability(double)} to find critical values.
*
* @param p the desired probability for the critical value
* @return initial domain value
*/
protected double getInitialDomain(double p) {
double ret = 1.0;
double d = getDenominatorDegreesOfFreedom();
if (d > 2.0) {
// use mean
ret = d / (d - 2.0);
}
return ret;
}
```
| protected double getInitialDomain(double p) {
double ret = 1.0;
double d = getDenominatorDegreesOfFreedom();
if (d > 2.0) {
// use mean
ret = d / (d - 2.0);
}
return ret;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Access the initial domain value, based on <code>p</code>, used to
* bracket a CDF root. This method is used by
* {@link #inverseCumulativeProbability(double)} to find critical values.
*
* @param p the desired probability for the critical value
* @return initial domain value
*/
protected double getInitialDomain(double p) {
double ret = 1.0;
double d = getDenominatorDegreesOfFreedom();
if (d > 2.0) {
// use mean
ret = d / (d - 2.0);
}
return ret;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
36 | 07b29c0cd169aad6430b1a113913eb6957246c1822e255e5cba09d579e849ff1 | private InputStream getCurrentStream() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private InputStream getCurrentStream() throws IOException {
if (archive.files[currentEntryIndex].getSize() == 0) {
return new ByteArrayInputStream(new byte[0]);
}
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
}
```
| private InputStream getCurrentStream() throws IOException {
if (archive.files[currentEntryIndex].getSize() == 0) {
return new ByteArrayInputStream(new byte[0]);
}
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private InputStream getCurrentStream() throws IOException {
if (archive.files[currentEntryIndex].getSize() == 0) {
return new ByteArrayInputStream(new byte[0]);
}
if (deferredBlockStreams.isEmpty()) {
throw new IllegalStateException("No current 7z entry (call getNextEntry() first).");
}
while (deferredBlockStreams.size() > 1) {
// In solid compression mode we need to decompress all leading folder'
// streams to get access to an entry. We defer this until really needed
// so that entire blocks can be skipped without wasting time for decompression.
final InputStream stream = deferredBlockStreams.remove(0);
IOUtils.skip(stream, Long.MAX_VALUE);
stream.close();
}
return deferredBlockStreams.get(0);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
59 | 07daaa8f91ebc407de1cd3d021952bfa037348cbc71a1b72d1c1e3b10c41542f | public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Appends an object to the builder padding on the right to a fixed length.
* The <code>toString</code> of the object is used.
* If the object is larger than the length, the right hand side is lost.
* If the object is null, null text value is used.
*
* @param obj the object to append, null uses null text
* @param width the fixed field width, zero or negative has no effect
* @param padChar the pad character to use
* @return this, to enable chaining
*/
public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, width, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
}
```
| public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, width, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Appends an object to the builder padding on the right to a fixed length.
* The <code>toString</code> of the object is used.
* If the object is larger than the length, the right hand side is lost.
* If the object is null, null text value is used.
*
* @param obj the object to append, null uses null text
* @param width the fixed field width, zero or negative has no effect
* @param padChar the pad character to use
* @return this, to enable chaining
*/
public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, width, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
118 | 07f5b8bb0f832ce072b83a5aa961be65f33719848ae57fb002f5b30b0b2d0ab3 | private void handleObjectLit(NodeTraversal t, Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Processes a OBJECTLIT node.
*/
private void handleObjectLit(NodeTraversal t, Node n) {
for (Node child = n.getFirstChild();
child != null;
child = child.getNext()) {
// Maybe STRING, GET, SET
if (child.isQuotedString()) {
continue;
}
// We should never see a mix of numbers and strings.
String name = child.getString();
T type = typeSystem.getType(getScope(), n, name);
Property prop = getProperty(name);
if (!prop.scheduleRenaming(child,
processProperty(t, prop, type, null))) {
// TODO(user): It doesn't look like the user can do much in this
// case right now.
if (propertiesToErrorFor.containsKey(name)) {
compiler.report(JSError.make(
t.getSourceName(), child, propertiesToErrorFor.get(name),
Warnings.INVALIDATION, name,
(type == null ? "null" : type.toString()), n.toString(), ""));
}
}
}
}
```
| private void handleObjectLit(NodeTraversal t, Node n) {
for (Node child = n.getFirstChild();
child != null;
child = child.getNext()) {
// Maybe STRING, GET, SET
if (child.isQuotedString()) {
continue;
}
// We should never see a mix of numbers and strings.
String name = child.getString();
T type = typeSystem.getType(getScope(), n, name);
Property prop = getProperty(name);
if (!prop.scheduleRenaming(child,
processProperty(t, prop, type, null))) {
// TODO(user): It doesn't look like the user can do much in this
// case right now.
if (propertiesToErrorFor.containsKey(name)) {
compiler.report(JSError.make(
t.getSourceName(), child, propertiesToErrorFor.get(name),
Warnings.INVALIDATION, name,
(type == null ? "null" : type.toString()), n.toString(), ""));
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Processes a OBJECTLIT node.
*/
private void handleObjectLit(NodeTraversal t, Node n) {
for (Node child = n.getFirstChild();
child != null;
child = child.getNext()) {
// Maybe STRING, GET, SET
if (child.isQuotedString()) {
continue;
}
// We should never see a mix of numbers and strings.
String name = child.getString();
T type = typeSystem.getType(getScope(), n, name);
Property prop = getProperty(name);
if (!prop.scheduleRenaming(child,
processProperty(t, prop, type, null))) {
// TODO(user): It doesn't look like the user can do much in this
// case right now.
if (propertiesToErrorFor.containsKey(name)) {
compiler.report(JSError.make(
t.getSourceName(), child, propertiesToErrorFor.get(name),
Warnings.INVALIDATION, name,
(type == null ? "null" : type.toString()), n.toString(), ""));
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | 0846960b992e4a8040ef86ec06c11a637514ce1462ea6e84cad6b84a1315ad33 | public int getLength() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* If the property contains a collection, then the length of that
* collection, otherwise - 1.
* @return int length
*/
public int getLength() {
Object baseValue = getBaseValue();
return baseValue == null ? 1 : ValueUtils.getLength(baseValue);
}
```
| public int getLength() {
Object baseValue = getBaseValue();
return baseValue == null ? 1 : ValueUtils.getLength(baseValue);
} | false | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* If the property contains a collection, then the length of that
* collection, otherwise - 1.
* @return int length
*/
public int getLength() {
Object baseValue = getBaseValue();
return baseValue == null ? 1 : ValueUtils.getLength(baseValue);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
164 | 084f5dc2711ef725c091e6cd67c4619f09e9bc078de5e80c6a2fb8b138535e64 | @Override
public boolean isSubtype(JSType other) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
// "that" can't be a supertype, because it's missing a required argument.
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
return true;
}
```
| @Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
// "that" can't be a supertype, because it's missing a required argument.
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
return true;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean isSubtype(JSType other) {
if (!(other instanceof ArrowType)) {
return false;
}
ArrowType that = (ArrowType) other;
// This is described in Draft 2 of the ES4 spec,
// Section 3.4.7: Subtyping Function Types.
// this.returnType <: that.returnType (covariant)
if (!this.returnType.isSubtype(that.returnType)) {
return false;
}
// that.paramType[i] <: this.paramType[i] (contravariant)
//
// If this.paramType[i] is required,
// then that.paramType[i] is required.
//
// In theory, the "required-ness" should work in the other direction as
// well. In other words, if we have
//
// function f(number, number) {}
// function g(number) {}
//
// Then f *should* not be a subtype of g, and g *should* not be
// a subtype of f. But in practice, we do not implement it this way.
// We want to support the use case where you can pass g where f is
// expected, and pretend that g ignores the second argument.
// That way, you can have a single "no-op" function, and you don't have
// to create a new no-op function for every possible type signature.
//
// So, in this case, g < f, but f !< g
Node thisParam = parameters.getFirstChild();
Node thatParam = that.parameters.getFirstChild();
while (thisParam != null && thatParam != null) {
JSType thisParamType = thisParam.getJSType();
JSType thatParamType = thatParam.getJSType();
if (thisParamType != null) {
if (thatParamType == null ||
!thatParamType.isSubtype(thisParamType)) {
return false;
}
}
boolean thisIsVarArgs = thisParam.isVarArgs();
boolean thatIsVarArgs = thatParam.isVarArgs();
// "that" can't be a supertype, because it's missing a required argument.
// NOTE(nicksantos): In our type system, we use {function(...?)} and
// {function(...NoType)} to to indicate that arity should not be
// checked. Strictly speaking, this is not a correct formulation,
// because now a sub-function can required arguments that are var_args
// in the super-function. So we special-case this.
// don't advance if we have variable arguments
if (!thisIsVarArgs) {
thisParam = thisParam.getNext();
}
if (!thatIsVarArgs) {
thatParam = thatParam.getNext();
}
// both var_args indicates the end
if (thisIsVarArgs && thatIsVarArgs) {
thisParam = null;
thatParam = null;
}
}
// "that" can't be a supertype, because it's missing a required arguement.
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 0850194fb5777f24b36a5e96a8d888951cdcbac37ae6f36a5120d600f5a69665 | public StringBuffer format(Calendar calendar, StringBuffer buf) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Formats a <code>Calendar</code> object into the
* supplied <code>StringBuffer</code>.</p>
*
* @param calendar the calendar to format
* @param buf the buffer to format into
* @return the specified string buffer
*/
public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
}
```
| public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Formats a <code>Calendar</code> object into the
* supplied <code>StringBuffer</code>.</p>
*
* @param calendar the calendar to format
* @param buf the buffer to format into
* @return the specified string buffer
*/
public StringBuffer format(Calendar calendar, StringBuffer buf) {
if (mTimeZoneForced) {
calendar = (Calendar) calendar.clone();
calendar.setTimeZone(mTimeZone);
}
return applyRules(calendar, buf);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 08fc9988f6048d44560808970fe0d0d66ea9f18e5875140d2e7b9dcb6f550775 | public Range getDataRange(ValueAxis axis) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the range for the specified axis.
*
* @param axis the axis.
*
* @return The range.
*/
public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
}
```
| public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the range for the specified axis.
*
* @param axis the axis.
*
* @return The range.
*/
public Range getDataRange(ValueAxis axis) {
Range result = null;
List mappedDatasets = new ArrayList();
List includedAnnotations = new ArrayList();
boolean isDomainAxis = true;
// is it a domain axis?
int domainIndex = getDomainAxisIndex(axis);
if (domainIndex >= 0) {
isDomainAxis = true;
mappedDatasets.addAll(getDatasetsMappedToDomainAxis(
new Integer(domainIndex)));
if (domainIndex == 0) {
// grab the plot's annotations
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// or is it a range axis?
int rangeIndex = getRangeAxisIndex(axis);
if (rangeIndex >= 0) {
isDomainAxis = false;
mappedDatasets.addAll(getDatasetsMappedToRangeAxis(
new Integer(rangeIndex)));
if (rangeIndex == 0) {
Iterator iterator = this.annotations.iterator();
while (iterator.hasNext()) {
XYAnnotation annotation = (XYAnnotation) iterator.next();
if (annotation instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(annotation);
}
}
}
}
// iterate through the datasets that map to the axis and get the union
// of the ranges.
Iterator iterator = mappedDatasets.iterator();
while (iterator.hasNext()) {
XYDataset d = (XYDataset) iterator.next();
if (d != null) {
XYItemRenderer r = getRendererForDataset(d);
if (isDomainAxis) {
if (r != null) {
result = Range.combine(result, r.findDomainBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findDomainBounds(d));
}
}
else {
if (r != null) {
result = Range.combine(result, r.findRangeBounds(d));
}
else {
result = Range.combine(result,
DatasetUtilities.findRangeBounds(d));
}
}
Collection c = r.getAnnotations();
Iterator i = c.iterator();
while (i.hasNext()) {
XYAnnotation a = (XYAnnotation) i.next();
if (a instanceof XYAnnotationBoundsInfo) {
includedAnnotations.add(a);
}
}
}
}
Iterator it = includedAnnotations.iterator();
while (it.hasNext()) {
XYAnnotationBoundsInfo xyabi = (XYAnnotationBoundsInfo) it.next();
if (xyabi.getIncludeInDataBounds()) {
if (isDomainAxis) {
result = Range.combine(result, xyabi.getXRange());
}
else {
result = Range.combine(result, xyabi.getYRange());
}
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | 0944f0e2b2a9f44474524e9c1ea70b977117b84dbb71e9d4b738c3ac4e1862ff | @SuppressWarnings("fallthrough")
private ExtractionInfo extractMultilineTextualBlock(JsDocToken token,
WhitespaceOption option) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Extracts the text found on the current line and all subsequent
* until either an annotation, end of comment or end of file is reached.
* Note that if this method detects an end of line as the first token, it
* will quit immediately (indicating that there is no text where it was
* expected). Note that token = info.token; should be called after this
* method is used to update the token properly in the parser.
*
* @param token The start token.
* @param option How to handle whitespace.
*
* @return The extraction information.
*/
@SuppressWarnings("fallthrough")
private ExtractionInfo extractMultilineTextualBlock(JsDocToken token,
WhitespaceOption option) {
if (token == JsDocToken.EOC || token == JsDocToken.EOL ||
token == JsDocToken.EOF) {
return new ExtractionInfo("", token);
}
stream.update();
int startLineno = stream.getLineno();
int startCharno = stream.getCharno() + 1;
// Read the content from the first line.
String line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = line.trim();
}
StringBuilder builder = new StringBuilder();
builder.append(line);
state = State.SEARCHING_ANNOTATION;
token = next();
boolean ignoreStar = false;
// Track the start of the line to count whitespace that
// the tokenizer skipped. Because this case is rare, it's easier
// to do this here than in the tokenizer.
int lineStartChar = -1;
do {
switch (token) {
case STAR:
if (ignoreStar) {
// Mark the position after the star as the new start of the line.
lineStartChar = stream.getCharno() + 1;
} else {
// The star is part of the comment.
if (builder.length() > 0) {
builder.append(' ');
}
builder.append('*');
}
token = next();
continue;
case EOL:
if (option != WhitespaceOption.SINGLE_LINE) {
builder.append("\n");
}
ignoreStar = true;
lineStartChar = 0;
token = next();
continue;
default:
ignoreStar = false;
state = State.SEARCHING_ANNOTATION;
boolean isEOC = token == JsDocToken.EOC;
if (!isEOC) {
if (lineStartChar != -1 && option == WhitespaceOption.PRESERVE) {
int numSpaces = stream.getCharno() - lineStartChar;
for (int i = 0; i < numSpaces; i++) {
builder.append(' ');
}
lineStartChar = -1;
} else if (builder.length() > 0) {
// All tokens must be separated by a space.
builder.append(' ');
}
}
if (token == JsDocToken.EOC ||
token == JsDocToken.EOF ||
// When we're capturing a license block, annotations
// in the block are ok.
(token == JsDocToken.ANNOTATION &&
option != WhitespaceOption.PRESERVE)) {
String multilineText = builder.toString();
if (option != WhitespaceOption.PRESERVE) {
multilineText = multilineText.trim();
}
int endLineno = stream.getLineno();
int endCharno = stream.getCharno();
if (multilineText.length() > 0) {
jsdocBuilder.markText(multilineText, startLineno, startCharno,
endLineno, endCharno);
}
return new ExtractionInfo(multilineText, token);
}
builder.append(toString(token));
line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = trimEnd(line);
}
builder.append(line);
token = next();
}
} while (true);
}
```
| @SuppressWarnings("fallthrough")
private ExtractionInfo extractMultilineTextualBlock(JsDocToken token,
WhitespaceOption option) {
if (token == JsDocToken.EOC || token == JsDocToken.EOL ||
token == JsDocToken.EOF) {
return new ExtractionInfo("", token);
}
stream.update();
int startLineno = stream.getLineno();
int startCharno = stream.getCharno() + 1;
// Read the content from the first line.
String line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = line.trim();
}
StringBuilder builder = new StringBuilder();
builder.append(line);
state = State.SEARCHING_ANNOTATION;
token = next();
boolean ignoreStar = false;
// Track the start of the line to count whitespace that
// the tokenizer skipped. Because this case is rare, it's easier
// to do this here than in the tokenizer.
int lineStartChar = -1;
do {
switch (token) {
case STAR:
if (ignoreStar) {
// Mark the position after the star as the new start of the line.
lineStartChar = stream.getCharno() + 1;
} else {
// The star is part of the comment.
if (builder.length() > 0) {
builder.append(' ');
}
builder.append('*');
}
token = next();
continue;
case EOL:
if (option != WhitespaceOption.SINGLE_LINE) {
builder.append("\n");
}
ignoreStar = true;
lineStartChar = 0;
token = next();
continue;
default:
ignoreStar = false;
state = State.SEARCHING_ANNOTATION;
boolean isEOC = token == JsDocToken.EOC;
if (!isEOC) {
if (lineStartChar != -1 && option == WhitespaceOption.PRESERVE) {
int numSpaces = stream.getCharno() - lineStartChar;
for (int i = 0; i < numSpaces; i++) {
builder.append(' ');
}
lineStartChar = -1;
} else if (builder.length() > 0) {
// All tokens must be separated by a space.
builder.append(' ');
}
}
if (token == JsDocToken.EOC ||
token == JsDocToken.EOF ||
// When we're capturing a license block, annotations
// in the block are ok.
(token == JsDocToken.ANNOTATION &&
option != WhitespaceOption.PRESERVE)) {
String multilineText = builder.toString();
if (option != WhitespaceOption.PRESERVE) {
multilineText = multilineText.trim();
}
int endLineno = stream.getLineno();
int endCharno = stream.getCharno();
if (multilineText.length() > 0) {
jsdocBuilder.markText(multilineText, startLineno, startCharno,
endLineno, endCharno);
}
return new ExtractionInfo(multilineText, token);
}
builder.append(toString(token));
line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = trimEnd(line);
}
builder.append(line);
token = next();
}
} while (true);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Extracts the text found on the current line and all subsequent
* until either an annotation, end of comment or end of file is reached.
* Note that if this method detects an end of line as the first token, it
* will quit immediately (indicating that there is no text where it was
* expected). Note that token = info.token; should be called after this
* method is used to update the token properly in the parser.
*
* @param token The start token.
* @param option How to handle whitespace.
*
* @return The extraction information.
*/
@SuppressWarnings("fallthrough")
private ExtractionInfo extractMultilineTextualBlock(JsDocToken token,
WhitespaceOption option) {
if (token == JsDocToken.EOC || token == JsDocToken.EOL ||
token == JsDocToken.EOF) {
return new ExtractionInfo("", token);
}
stream.update();
int startLineno = stream.getLineno();
int startCharno = stream.getCharno() + 1;
// Read the content from the first line.
String line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = line.trim();
}
StringBuilder builder = new StringBuilder();
builder.append(line);
state = State.SEARCHING_ANNOTATION;
token = next();
boolean ignoreStar = false;
// Track the start of the line to count whitespace that
// the tokenizer skipped. Because this case is rare, it's easier
// to do this here than in the tokenizer.
int lineStartChar = -1;
do {
switch (token) {
case STAR:
if (ignoreStar) {
// Mark the position after the star as the new start of the line.
lineStartChar = stream.getCharno() + 1;
} else {
// The star is part of the comment.
if (builder.length() > 0) {
builder.append(' ');
}
builder.append('*');
}
token = next();
continue;
case EOL:
if (option != WhitespaceOption.SINGLE_LINE) {
builder.append("\n");
}
ignoreStar = true;
lineStartChar = 0;
token = next();
continue;
default:
ignoreStar = false;
state = State.SEARCHING_ANNOTATION;
boolean isEOC = token == JsDocToken.EOC;
if (!isEOC) {
if (lineStartChar != -1 && option == WhitespaceOption.PRESERVE) {
int numSpaces = stream.getCharno() - lineStartChar;
for (int i = 0; i < numSpaces; i++) {
builder.append(' ');
}
lineStartChar = -1;
} else if (builder.length() > 0) {
// All tokens must be separated by a space.
builder.append(' ');
}
}
if (token == JsDocToken.EOC ||
token == JsDocToken.EOF ||
// When we're capturing a license block, annotations
// in the block are ok.
(token == JsDocToken.ANNOTATION &&
option != WhitespaceOption.PRESERVE)) {
String multilineText = builder.toString();
if (option != WhitespaceOption.PRESERVE) {
multilineText = multilineText.trim();
}
int endLineno = stream.getLineno();
int endCharno = stream.getCharno();
if (multilineText.length() > 0) {
jsdocBuilder.markText(multilineText, startLineno, startCharno,
endLineno, endCharno);
}
return new ExtractionInfo(multilineText, token);
}
builder.append(toString(token));
line = stream.getRemainingJSDocLine();
if (option != WhitespaceOption.PRESERVE) {
line = trimEnd(line);
}
builder.append(line);
token = next();
}
} while (true);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 097622231efeb8689ca82aca570d651e2ad3f8b0262910d6db93e96206e363d9 | private void resolveLocalFileHeaderData(Map<ZipArchiveEntry, NameAndComment>
entriesWithoutUTF8Flag)
throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Walks through all recorded entries and adds the data available
* from the local file header.
*
* <p>Also records the offsets for the data to read from the
* entries.</p>
*/
private void resolveLocalFileHeaderData(Map<ZipArchiveEntry, NameAndComment>
entriesWithoutUTF8Flag)
throws IOException {
// changing the name of a ZipArchiveEntry is going to change
// the hashcode - see COMPRESS-164
// Map needs to be reconstructed in order to keep central
// directory order
Map<ZipArchiveEntry, OffsetEntry> origMap =
new LinkedHashMap<ZipArchiveEntry, OffsetEntry>(entries);
entries.clear();
for (ZipArchiveEntry ze : origMap.keySet()) {
OffsetEntry offsetEntry = origMap.get(ze);
long offset = offsetEntry.headerOffset;
archive.seek(offset + LFH_OFFSET_FOR_FILENAME_LENGTH);
byte[] b = new byte[SHORT];
archive.readFully(b);
int fileNameLen = ZipShort.getValue(b);
archive.readFully(b);
int extraFieldLen = ZipShort.getValue(b);
int lenToSkip = fileNameLen;
while (lenToSkip > 0) {
int skipped = archive.skipBytes(lenToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip file name in"
+ " local file header");
}
lenToSkip -= skipped;
}
byte[] localExtraData = new byte[extraFieldLen];
archive.readFully(localExtraData);
ze.setExtra(localExtraData);
offsetEntry.dataOffset = offset + LFH_OFFSET_FOR_FILENAME_LENGTH
+ SHORT + SHORT + fileNameLen + extraFieldLen;
if (entriesWithoutUTF8Flag.containsKey(ze)) {
String orig = ze.getName();
NameAndComment nc = entriesWithoutUTF8Flag.get(ze);
ZipUtil.setNameAndCommentFromExtraFields(ze, nc.name,
nc.comment);
if (!orig.equals(ze.getName())) {
nameMap.remove(orig);
nameMap.put(ze.getName(), ze);
}
}
entries.put(ze, offsetEntry);
}
}
```
| private void resolveLocalFileHeaderData(Map<ZipArchiveEntry, NameAndComment>
entriesWithoutUTF8Flag)
throws IOException {
// changing the name of a ZipArchiveEntry is going to change
// the hashcode - see COMPRESS-164
// Map needs to be reconstructed in order to keep central
// directory order
Map<ZipArchiveEntry, OffsetEntry> origMap =
new LinkedHashMap<ZipArchiveEntry, OffsetEntry>(entries);
entries.clear();
for (ZipArchiveEntry ze : origMap.keySet()) {
OffsetEntry offsetEntry = origMap.get(ze);
long offset = offsetEntry.headerOffset;
archive.seek(offset + LFH_OFFSET_FOR_FILENAME_LENGTH);
byte[] b = new byte[SHORT];
archive.readFully(b);
int fileNameLen = ZipShort.getValue(b);
archive.readFully(b);
int extraFieldLen = ZipShort.getValue(b);
int lenToSkip = fileNameLen;
while (lenToSkip > 0) {
int skipped = archive.skipBytes(lenToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip file name in"
+ " local file header");
}
lenToSkip -= skipped;
}
byte[] localExtraData = new byte[extraFieldLen];
archive.readFully(localExtraData);
ze.setExtra(localExtraData);
offsetEntry.dataOffset = offset + LFH_OFFSET_FOR_FILENAME_LENGTH
+ SHORT + SHORT + fileNameLen + extraFieldLen;
if (entriesWithoutUTF8Flag.containsKey(ze)) {
String orig = ze.getName();
NameAndComment nc = entriesWithoutUTF8Flag.get(ze);
ZipUtil.setNameAndCommentFromExtraFields(ze, nc.name,
nc.comment);
if (!orig.equals(ze.getName())) {
nameMap.remove(orig);
nameMap.put(ze.getName(), ze);
}
}
entries.put(ze, offsetEntry);
}
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Walks through all recorded entries and adds the data available
* from the local file header.
*
* <p>Also records the offsets for the data to read from the
* entries.</p>
*/
private void resolveLocalFileHeaderData(Map<ZipArchiveEntry, NameAndComment>
entriesWithoutUTF8Flag)
throws IOException {
// changing the name of a ZipArchiveEntry is going to change
// the hashcode - see COMPRESS-164
// Map needs to be reconstructed in order to keep central
// directory order
Map<ZipArchiveEntry, OffsetEntry> origMap =
new LinkedHashMap<ZipArchiveEntry, OffsetEntry>(entries);
entries.clear();
for (ZipArchiveEntry ze : origMap.keySet()) {
OffsetEntry offsetEntry = origMap.get(ze);
long offset = offsetEntry.headerOffset;
archive.seek(offset + LFH_OFFSET_FOR_FILENAME_LENGTH);
byte[] b = new byte[SHORT];
archive.readFully(b);
int fileNameLen = ZipShort.getValue(b);
archive.readFully(b);
int extraFieldLen = ZipShort.getValue(b);
int lenToSkip = fileNameLen;
while (lenToSkip > 0) {
int skipped = archive.skipBytes(lenToSkip);
if (skipped <= 0) {
throw new RuntimeException("failed to skip file name in"
+ " local file header");
}
lenToSkip -= skipped;
}
byte[] localExtraData = new byte[extraFieldLen];
archive.readFully(localExtraData);
ze.setExtra(localExtraData);
offsetEntry.dataOffset = offset + LFH_OFFSET_FOR_FILENAME_LENGTH
+ SHORT + SHORT + fileNameLen + extraFieldLen;
if (entriesWithoutUTF8Flag.containsKey(ze)) {
String orig = ze.getName();
NameAndComment nc = entriesWithoutUTF8Flag.get(ze);
ZipUtil.setNameAndCommentFromExtraFields(ze, nc.name,
nc.comment);
if (!orig.equals(ze.getName())) {
nameMap.remove(orig);
nameMap.put(ze.getName(), ze);
}
}
entries.put(ze, offsetEntry);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 09d92adc1225998188f8a91cc0a943211d9e4e48c0f7224e2be5fd2899bdb460 | private boolean hasExceptionHandler(Node cfgNode) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean hasExceptionHandler(Node cfgNode) {
List<DiGraphEdge<Node, Branch>> branchEdges = getCfg().getOutEdges(cfgNode);
for (DiGraphEdge<Node, Branch> edge : branchEdges) {
if (edge.getValue() == Branch.ON_EX) {
return true;
}
}
return false;
}
```
| private boolean hasExceptionHandler(Node cfgNode) {
List<DiGraphEdge<Node, Branch>> branchEdges = getCfg().getOutEdges(cfgNode);
for (DiGraphEdge<Node, Branch> edge : branchEdges) {
if (edge.getValue() == Branch.ON_EX) {
return true;
}
}
return false;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean hasExceptionHandler(Node cfgNode) {
List<DiGraphEdge<Node, Branch>> branchEdges = getCfg().getOutEdges(cfgNode);
for (DiGraphEdge<Node, Branch> edge : branchEdges) {
if (edge.getValue() == Branch.ON_EX) {
return true;
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | 09f88660dabc223bfae7dee61f66d7bfe7276d4941c29db08beb099f986a8a4d | public int indexOf(String str, int startIndex) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Searches the string builder to find the first reference to the specified
* string starting searching from the given index.
* <p>
* Note that a null input string will return -1, whereas the JDK throws an exception.
*
* @param str the string to find, null returns -1
* @param startIndex the index to start at, invalid index rounded to edge
* @return the first index of the string, or -1 if not found
*/
public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = size - strLen + 1;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
}
```
| public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = size - strLen + 1;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Searches the string builder to find the first reference to the specified
* string starting searching from the given index.
* <p>
* Note that a null input string will return -1, whereas the JDK throws an exception.
*
* @param str the string to find, null returns -1
* @param startIndex the index to start at, invalid index rounded to edge
* @return the first index of the string, or -1 if not found
*/
public int indexOf(String str, int startIndex) {
startIndex = (startIndex < 0 ? 0 : startIndex);
if (str == null || startIndex >= size) {
return -1;
}
int strLen = str.length();
if (strLen == 1) {
return indexOf(str.charAt(0), startIndex);
}
if (strLen == 0) {
return startIndex;
}
if (strLen > size) {
return -1;
}
char[] thisBuf = buffer;
int len = size - strLen + 1;
outer:
for (int i = startIndex; i < len; i++) {
for (int j = 0; j < strLen; j++) {
if (str.charAt(j) != thisBuf[i + j]) {
continue outer;
}
}
return i;
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 0a01a6961c8ec802697a500f651bc8bcea1c7272fd6d2547b796706fac13ca79 | public double getNumericalMean() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
*
* For population size {@code N}, number of successes {@code m}, and sample
* size {@code n}, the mean is {@code n * m / N}.
*/
public double getNumericalMean() {
return (double) (getSampleSize() * getNumberOfSuccesses()) / (double) getPopulationSize();
}
```
| public double getNumericalMean() {
return (double) (getSampleSize() * getNumberOfSuccesses()) / (double) getPopulationSize();
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
*
* For population size {@code N}, number of successes {@code m}, and sample
* size {@code n}, the mean is {@code n * m / N}.
*/
public double getNumericalMean() {
return (double) (getSampleSize() * getNumberOfSuccesses()) / (double) getPopulationSize();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
59 | 0a190f56087abaa2221efb154e3f83fb676ccd262a8db86c3776add1bd4c5958 | public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Appends an object to the builder padding on the right to a fixed length.
* The <code>toString</code> of the object is used.
* If the object is larger than the length, the right hand side is lost.
* If the object is null, null text value is used.
*
* @param obj the object to append, null uses null text
* @param width the fixed field width, zero or negative has no effect
* @param padChar the pad character to use
* @return this, to enable chaining
*/
public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, strLen, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
}
```
| public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, strLen, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Appends an object to the builder padding on the right to a fixed length.
* The <code>toString</code> of the object is used.
* If the object is larger than the length, the right hand side is lost.
* If the object is null, null text value is used.
*
* @param obj the object to append, null uses null text
* @param width the fixed field width, zero or negative has no effect
* @param padChar the pad character to use
* @return this, to enable chaining
*/
public StrBuilder appendFixedWidthPadRight(Object obj, int width, char padChar) {
if (width > 0) {
ensureCapacity(size + width);
String str = (obj == null ? getNullText() : obj.toString());
int strLen = str.length();
if (strLen >= width) {
str.getChars(0, strLen, buffer, size);
} else {
int padLen = width - strLen;
str.getChars(0, strLen, buffer, size);
for (int i = 0; i < padLen; i++) {
buffer[size + strLen + i] = padChar;
}
}
size += width;
}
return this;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
21 | 0a6f4520ac6d6e5047a33b478dd2171b7c3305f9c6cf7956617a44434a28d62a | @Override
public JsonToken nextToken() throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
```
| @Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Public API, traversal
/**********************************************************
*/
@Override
public JsonToken nextToken() throws IOException
{
// 23-May-2017, tatu: To be honest, code here is rather hairy and I don't like all
// conditionals; and it seems odd to return `null` but NOT considering input
// as closed... would love a rewrite to simplify/clear up logic here.
// Check for _allowMultipleMatches - false and at least there is one token - which is _currToken
// check for no buffered context _exposedContext - null
// If all the conditions matches then check for scalar / non-scalar property
if (!_allowMultipleMatches && (_currToken != null) && (_exposedContext == null)) {
//if not scalar and ended successfully, and !includePath, then return null
if (_currToken.isStructEnd()) {
if (_headContext.isStartHandled()) {
return (_currToken = null);
}
} else if (_currToken.isScalarValue()) {
//else if scalar, and scalar not present in obj/array and !includePath and INCLUDE_ALL matched once
// then return null
if (!_headContext.isStartHandled() && (_itemFilter == TokenFilter.INCLUDE_ALL)) {
return (_currToken = null);
}
}
}
// Anything buffered?
TokenFilterContext ctxt = _exposedContext;
if (ctxt != null) {
while (true) {
JsonToken t = ctxt.nextTokenToRead();
if (t != null) {
_currToken = t;
return t;
}
// all done with buffered stuff?
if (ctxt == _headContext) {
_exposedContext = null;
if (ctxt.inArray()) {
t = delegate.getCurrentToken();
// Is this guaranteed to work without further checks?
// if (t != JsonToken.START_ARRAY) {
_currToken = t;
return t;
}
// Almost! Most likely still have the current token;
// with the sole exception of
/*
t = delegate.getCurrentToken();
if (t != JsonToken.FIELD_NAME) {
_currToken = t;
return t;
}
*/
break;
}
// If not, traverse down the context chain
ctxt = _headContext.findChildOf(ctxt);
_exposedContext = ctxt;
if (ctxt == null) { // should never occur
throw _constructError("Unexpected problem: chain of filtered context broken");
}
}
}
// If not, need to read more. If we got any:
JsonToken t = delegate.nextToken();
if (t == null) {
// no strict need to close, since we have no state here
_currToken = t;
return t;
}
// otherwise... to include or not?
TokenFilter f;
switch (t.id()) {
case ID_START_ARRAY:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartArray();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildArrayContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildArrayContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
case ID_START_OBJECT:
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
if (f == null) { // does this occur?
delegate.skipChildren();
break;
}
// Otherwise still iffy, need to check
f = _headContext.checkValue(f);
if (f == null) {
delegate.skipChildren();
break;
}
if (f != TokenFilter.INCLUDE_ALL) {
f = f.filterStartObject();
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
_headContext = _headContext.createChildObjectContext(f, true);
return (_currToken = t);
}
_headContext = _headContext.createChildObjectContext(f, false);
// Also: only need buffering if parent path to be included
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
// note: inclusion of surrounding Object handled separately via
// FIELD_NAME
break;
case ID_END_ARRAY:
case ID_END_OBJECT:
{
boolean returnEnd = _headContext.isStartHandled();
f = _headContext.getFilter();
if ((f != null) && (f != TokenFilter.INCLUDE_ALL)) {
f.filterFinishArray();
}
_headContext = _headContext.getParent();
_itemFilter = _headContext.getFilter();
if (returnEnd) {
return (_currToken = t);
}
}
break;
case ID_FIELD_NAME:
{
final String name = delegate.getCurrentName();
// note: this will also set 'needToHandleName'
f = _headContext.setFieldName(name);
if (f == TokenFilter.INCLUDE_ALL) {
_itemFilter = f;
if (!_includePath) {
// Minor twist here: if parent NOT included, may need to induce output of
// surrounding START_OBJECT/END_OBJECT
if (_includeImmediateParent && !_headContext.isStartHandled()) {
t = _headContext.nextTokenToRead(); // returns START_OBJECT but also marks it handled
_exposedContext = _headContext;
}
}
return (_currToken = t);
}
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
f = f.includeProperty(name);
if (f == null) {
delegate.nextToken();
delegate.skipChildren();
break;
}
_itemFilter = f;
if (f == TokenFilter.INCLUDE_ALL) {
if (_includePath) {
return (_currToken = t);
}
}
if (_includePath) {
t = _nextTokenWithBuffering(_headContext);
if (t != null) {
_currToken = t;
return t;
}
}
break;
}
default: // scalar value
f = _itemFilter;
if (f == TokenFilter.INCLUDE_ALL) {
return (_currToken = t);
}
if (f != null) {
f = _headContext.checkValue(f);
if ((f == TokenFilter.INCLUDE_ALL)
|| ((f != null) && f.includeValue(delegate))) {
return (_currToken = t);
}
}
// Otherwise not included (leaves must be explicitly included)
break;
}
// We get here if token was not yet found; offlined handling
return _nextToken2();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 0a8fad6e89405d844e4d486e48da436cabcbb83779ba8c7262d3a674aca094d9 | static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// todo - this is getting gnarly. needs a rewrite.
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
} else {
foundCharset = meta.attr("charset");
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
// UTF-8 BOM indicator. takes precedence over everything else. rarely used. re-decodes incase above decoded incorrectly
if (docData.length() > 0 && docData.charAt(0) == 65279) {
byteData.rewind();
docData = Charset.forName(defaultCharset).decode(byteData).toString();
docData = docData.substring(1);
charsetName = defaultCharset;
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
```
| static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
} else {
foundCharset = meta.attr("charset");
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
// UTF-8 BOM indicator. takes precedence over everything else. rarely used. re-decodes incase above decoded incorrectly
if (docData.length() > 0 && docData.charAt(0) == 65279) {
byteData.rewind();
docData = Charset.forName(defaultCharset).decode(byteData).toString();
docData = docData.substring(1);
charsetName = defaultCharset;
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// todo - this is getting gnarly. needs a rewrite.
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
} else {
foundCharset = meta.attr("charset");
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
// UTF-8 BOM indicator. takes precedence over everything else. rarely used. re-decodes incase above decoded incorrectly
if (docData.length() > 0 && docData.charAt(0) == 65279) {
byteData.rewind();
docData = Charset.forName(defaultCharset).decode(byteData).toString();
docData = docData.substring(1);
charsetName = defaultCharset;
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
30 | 0ac0cc60bdfde0470e33992d3dd1b90b9bee378ab42e2f0b7c0193b9e56faf55 | @Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
* (non-Javadoc)
*
* @see java.io.InputStream#read(byte[], int, int)
*/
@Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
}
```
| @Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
* (non-Javadoc)
*
* @see java.io.InputStream#read(byte[], int, int)
*/
@Override
public int read(final byte[] dest, final int offs, final int len)
throws IOException {
if (offs < 0) {
throw new IndexOutOfBoundsException("offs(" + offs + ") < 0.");
}
if (len < 0) {
throw new IndexOutOfBoundsException("len(" + len + ") < 0.");
}
if (offs + len > dest.length) {
throw new IndexOutOfBoundsException("offs(" + offs + ") + len("
+ len + ") > dest.length(" + dest.length + ").");
}
if (this.in == null) {
throw new IOException("stream closed");
}
final int hi = offs + len;
int destOffs = offs;
int b;
while (destOffs < hi && ((b = read0()) >= 0)) {
dest[destOffs++] = (byte) b;
count(1);
}
int c = (destOffs == offs) ? -1 : (destOffs - offs);
return c;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 0b47527f9c3c4dc70c020fb9ab610e96502f031d41f4a722bcce93160a9b0df0 | public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Alternative to {@link #serializeAsField} that is used when a POJO
* is serialized as JSON Array; the difference is that no field names
* are written.
*
* @since 2.1
*/
public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
}
```
| public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Alternative to {@link #serializeAsField} that is used when a POJO
* is serialized as JSON Array; the difference is that no field names
* are written.
*
* @since 2.1
*/
public void serializeAsColumn(Object bean, JsonGenerator jgen, SerializerProvider prov)
throws Exception
{
Object value = get(bean);
if (value == null) { // nulls need specialized handling
if (_nullSerializer != null) {
_nullSerializer.serialize(null, jgen, prov);
} else { // can NOT suppress entries in tabular output
jgen.writeNull();
}
}
// otherwise find serializer to use
JsonSerializer<Object> ser = _serializer;
if (ser == null) {
Class<?> cls = value.getClass();
PropertySerializerMap map = _dynamicSerializers;
ser = map.serializerFor(cls);
if (ser == null) {
ser = _findAndAddDynamic(map, cls, prov);
}
}
// and then see if we must suppress certain values (default, empty)
if (_suppressableValue != null) {
if (MARKER_FOR_EMPTY == _suppressableValue) {
if (ser.isEmpty(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
} else if (_suppressableValue.equals(value)) { // can NOT suppress entries in tabular output
serializeAsPlaceholder(bean, jgen, prov);
return;
}
}
// For non-nulls: simple check for direct cycles
if (value == bean) {
_handleSelfReference(bean, ser);
}
if (_typeSerializer == null) {
ser.serialize(value, jgen, prov);
} else {
ser.serializeWithType(value, jgen, prov, _typeSerializer);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
172 | 0ba36ff4a851e937d3f8a57ac2e8694973086271f9313ac3bf248fbd5269166b | private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Determines whether a qualified name is inferred.
* NOTE(nicksantos): Determining whether a property is declared or not
* is really really obnoxious.
*
* The problem is that there are two (equally valid) coding styles:
*
* (function() {
* /* The authoritative definition of goog.bar. /
* goog.bar = function() {};
* })();
*
* function f() {
* goog.bar();
* /* Reset goog.bar to a no-op. /
* goog.bar = function() {};
* }
*
* In a dynamic language with first-class functions, it's very difficult
* to know which one the user intended without looking at lots of
* contextual information (the second example demonstrates a small case
* of this, but there are some really pathological cases as well).
*
* The current algorithm checks if either the declaration has
* JsDoc type information, or @const with a known type,
* or a function literal with a name we haven't seen before.
*/
private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
String className = qName.substring(0, qName.lastIndexOf(".prototype"));
Var slot = scope.getSlot(className);
JSType classType = slot == null ? null : slot.getType();
if (classType != null
&& (classType.isConstructor() || classType.isInterface())) {
return false;
}
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
}
```
| private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
String className = qName.substring(0, qName.lastIndexOf(".prototype"));
Var slot = scope.getSlot(className);
JSType classType = slot == null ? null : slot.getType();
if (classType != null
&& (classType.isConstructor() || classType.isInterface())) {
return false;
}
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Determines whether a qualified name is inferred.
* NOTE(nicksantos): Determining whether a property is declared or not
* is really really obnoxious.
*
* The problem is that there are two (equally valid) coding styles:
*
* (function() {
* /* The authoritative definition of goog.bar. /
* goog.bar = function() {};
* })();
*
* function f() {
* goog.bar();
* /* Reset goog.bar to a no-op. /
* goog.bar = function() {};
* }
*
* In a dynamic language with first-class functions, it's very difficult
* to know which one the user intended without looking at lots of
* contextual information (the second example demonstrates a small case
* of this, but there are some really pathological cases as well).
*
* The current algorithm checks if either the declaration has
* JsDoc type information, or @const with a known type,
* or a function literal with a name we haven't seen before.
*/
private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
String className = qName.substring(0, qName.lastIndexOf(".prototype"));
Var slot = scope.getSlot(className);
JSType classType = slot == null ? null : slot.getType();
if (classType != null
&& (classType.isConstructor() || classType.isInterface())) {
return false;
}
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 0bd1280500426a1ff4c688e87b0ba30adb728c0d617308f1d85a0945d661fbb8 | @SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
typeAdapter = typeAdapter.nullSafe();
return typeAdapter;
}
```
| @SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
typeAdapter = typeAdapter.nullSafe();
return typeAdapter;
} | true | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@SuppressWarnings("unchecked") // Casts guarded by conditionals.
static TypeAdapter<?> getTypeAdapter(ConstructorConstructor constructorConstructor, Gson gson,
TypeToken<?> fieldType, JsonAdapter annotation) {
Class<?> value = annotation.value();
TypeAdapter<?> typeAdapter;
if (TypeAdapter.class.isAssignableFrom(value)) {
Class<TypeAdapter<?>> typeAdapterClass = (Class<TypeAdapter<?>>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterClass)).construct();
} else if (TypeAdapterFactory.class.isAssignableFrom(value)) {
Class<TypeAdapterFactory> typeAdapterFactory = (Class<TypeAdapterFactory>) value;
typeAdapter = constructorConstructor.get(TypeToken.get(typeAdapterFactory))
.construct()
.create(gson, fieldType);
} else {
throw new IllegalArgumentException(
"@JsonAdapter value must be TypeAdapter or TypeAdapterFactory reference.");
}
typeAdapter = typeAdapter.nullSafe();
return typeAdapter;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 0c09627a4fd774eb088a6015cf9e921f44308c055c46ca9b3ba2c72585783c42 | public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the weighted variance of the entries in the specified portion of
* the input array, using the precomputed weighted mean value. Returns
* <code>Double.NaN</code> if the designated subarray is empty.
* <p>
* Uses the formula <pre>
* Σ(weights[i]*(values[i] - mean)<sup>2</sup>)/(Σ(weights[i]) - 1)
* </pre></p>
* <p>
* The formula used assumes that the supplied mean value is the weighted arithmetic
* mean of the sample data, not a known population parameter. This method
* is supplied only to save computation when the mean has already been
* computed.</p>
* <p>
* This formula will not return the same result as the unweighted variance when all
* weights are equal, unless all weights are equal to 1. The formula assumes that
* weights are to be treated as "expansion values," as will be the case if for example
* the weights represent frequency counts. To normalize weights so that the denominator
* in the variance computation equals the length of the input vector minus one, use <pre>
* <code>evaluate(values, MathArrays.normalizeArray(weights, values.length), mean); </code>
* </pre>
* <p>
* Returns 0 for a single-value (i.e. length = 1) sample.</p>
* <p>
* Throws <code>IllegalArgumentException</code> if any of the following are true:
* <ul><li>the values array is null</li>
* <li>the weights array is null</li>
* <li>the weights array does not have the same length as the values array</li>
* <li>the weights array contains one or more infinite values</li>
* <li>the weights array contains one or more NaN values</li>
* <li>the weights array contains negative values</li>
* <li>the start and length arguments do not determine a valid array</li>
* </ul></p>
* <p>
* Does not change the internal state of the statistic.</p>
*
* @param values the input array
* @param weights the weights array
* @param mean the precomputed weighted mean value
* @param begin index of the first array element to include
* @param length the number of elements to include
* @return the variance of the values or Double.NaN if length = 0
* @throws IllegalArgumentException if the parameters are not valid
* @since 2.1
*/
public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = 0; i < weights.length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
}
```
| public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = 0; i < weights.length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the weighted variance of the entries in the specified portion of
* the input array, using the precomputed weighted mean value. Returns
* <code>Double.NaN</code> if the designated subarray is empty.
* <p>
* Uses the formula <pre>
* Σ(weights[i]*(values[i] - mean)<sup>2</sup>)/(Σ(weights[i]) - 1)
* </pre></p>
* <p>
* The formula used assumes that the supplied mean value is the weighted arithmetic
* mean of the sample data, not a known population parameter. This method
* is supplied only to save computation when the mean has already been
* computed.</p>
* <p>
* This formula will not return the same result as the unweighted variance when all
* weights are equal, unless all weights are equal to 1. The formula assumes that
* weights are to be treated as "expansion values," as will be the case if for example
* the weights represent frequency counts. To normalize weights so that the denominator
* in the variance computation equals the length of the input vector minus one, use <pre>
* <code>evaluate(values, MathArrays.normalizeArray(weights, values.length), mean); </code>
* </pre>
* <p>
* Returns 0 for a single-value (i.e. length = 1) sample.</p>
* <p>
* Throws <code>IllegalArgumentException</code> if any of the following are true:
* <ul><li>the values array is null</li>
* <li>the weights array is null</li>
* <li>the weights array does not have the same length as the values array</li>
* <li>the weights array contains one or more infinite values</li>
* <li>the weights array contains one or more NaN values</li>
* <li>the weights array contains negative values</li>
* <li>the start and length arguments do not determine a valid array</li>
* </ul></p>
* <p>
* Does not change the internal state of the statistic.</p>
*
* @param values the input array
* @param weights the weights array
* @param mean the precomputed weighted mean value
* @param begin index of the first array element to include
* @param length the number of elements to include
* @return the variance of the values or Double.NaN if length = 0
* @throws IllegalArgumentException if the parameters are not valid
* @since 2.1
*/
public double evaluate(final double[] values, final double[] weights,
final double mean, final int begin, final int length) {
double var = Double.NaN;
if (test(values, weights, begin, length)) {
if (length == 1) {
var = 0.0;
} else if (length > 1) {
double accum = 0.0;
double dev = 0.0;
double accum2 = 0.0;
for (int i = begin; i < begin + length; i++) {
dev = values[i] - mean;
accum += weights[i] * (dev * dev);
accum2 += weights[i] * dev;
}
double sumWts = 0;
for (int i = 0; i < weights.length; i++) {
sumWts += weights[i];
}
if (isBiasCorrected) {
var = (accum - (accum2 * accum2 / sumWts)) / (sumWts - 1.0);
} else {
var = (accum - (accum2 * accum2 / sumWts)) / sumWts;
}
}
}
return var;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
54 | 0c4d3108de04bbe87c098206c046792b09310d094b59b25e86c8678ab2a45440 | public static Locale toLocale(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
}
```
| public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(String str) {
if (str == null) {
return null;
}
int len = str.length();
if (len != 2 && len != 5 && len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch0 = str.charAt(0);
char ch1 = str.charAt(1);
if (ch0 < 'a' || ch0 > 'z' || ch1 < 'a' || ch1 > 'z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str, "");
} else {
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
char ch4 = str.charAt(4);
if (ch3 < 'A' || ch3 > 'Z' || ch4 < 'A' || ch4 > 'Z') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
} else {
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
150 | 0c8899c93d55afa07d064b2b634f8eb29c45009dea631a97d1fcd7171370afaf | @Override public void visit(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visit a node in a local scope, and add any local variables or catch
* parameters into the local symbol table.
*
* @param t The node traversal.
* @param n The node being visited.
* @param parent The parent of n
*/
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (n == scope.getRootNode()) return;
if (n.getType() == Token.LP && parent == scope.getRootNode()) {
handleFunctionInputs(parent);
return;
}
attachLiteralTypes(n);
switch (n.getType()) {
case Token.FUNCTION:
if (parent.getType() == Token.NAME) {
return;
}
defineDeclaredFunction(n, parent);
break;
case Token.CATCH:
defineCatch(n, parent);
break;
case Token.VAR:
defineVar(n, parent);
break;
}
}
```
| @Override public void visit(NodeTraversal t, Node n, Node parent) {
if (n == scope.getRootNode()) return;
if (n.getType() == Token.LP && parent == scope.getRootNode()) {
handleFunctionInputs(parent);
return;
}
attachLiteralTypes(n);
switch (n.getType()) {
case Token.FUNCTION:
if (parent.getType() == Token.NAME) {
return;
}
defineDeclaredFunction(n, parent);
break;
case Token.CATCH:
defineCatch(n, parent);
break;
case Token.VAR:
defineVar(n, parent);
break;
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visit a node in a local scope, and add any local variables or catch
* parameters into the local symbol table.
*
* @param t The node traversal.
* @param n The node being visited.
* @param parent The parent of n
*/
@Override public void visit(NodeTraversal t, Node n, Node parent) {
if (n == scope.getRootNode()) return;
if (n.getType() == Token.LP && parent == scope.getRootNode()) {
handleFunctionInputs(parent);
return;
}
attachLiteralTypes(n);
switch (n.getType()) {
case Token.FUNCTION:
if (parent.getType() == Token.NAME) {
return;
}
defineDeclaredFunction(n, parent);
break;
case Token.CATCH:
defineCatch(n, parent);
break;
case Token.VAR:
defineVar(n, parent);
break;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 0d22c1df69b2760db6ada8c800c6b9d94ce66449ec6067a6fc08339009aac2d2 | private static synchronized String getConvertedId(String id) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Converts an old style id to a new style id.
*
* @param id the old style id
* @return the new style id, null if not found
*/
//-----------------------------------------------------------------------
private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("WET", "WET");
map.put("CET", "CET");
map.put("MET", "CET");
map.put("ECT", "CET");
map.put("EET", "EET");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indiana/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Argentina/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EAT", "Africa/Addis_Ababa");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Kolkata");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Ho_Chi_Minh");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
}
```
| private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("WET", "WET");
map.put("CET", "CET");
map.put("MET", "CET");
map.put("ECT", "CET");
map.put("EET", "EET");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indiana/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Argentina/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EAT", "Africa/Addis_Ababa");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Kolkata");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Ho_Chi_Minh");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Converts an old style id to a new style id.
*
* @param id the old style id
* @return the new style id, null if not found
*/
//-----------------------------------------------------------------------
private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("WET", "WET");
map.put("CET", "CET");
map.put("MET", "CET");
map.put("ECT", "CET");
map.put("EET", "EET");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indiana/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Argentina/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EAT", "Africa/Addis_Ababa");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Kolkata");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Ho_Chi_Minh");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 0d9ca1170a7135c22555c17660bbe9e69ed08b1ab6fc18217e607735803729bf | @Override
public boolean isCachable() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Turns out that these are expensive enough to create so that caching
* does make sense.
*<p>
* IMPORTANT: but, note, that instances CAN NOT BE CACHED if there is
* a value type deserializer; this caused an issue with 2.4.4 of
* JAXB Annotations (failing a test).
* It is also possible that some other settings could make deserializers
* un-cacheable; but on the other hand, caching can make a big positive
* difference with performance... so it's a hard choice.
*
* @since 2.4.4
*/
/*
/**********************************************************
/* JsonDeserializer API
/**********************************************************
*/
@Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
}
```
| @Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Turns out that these are expensive enough to create so that caching
* does make sense.
*<p>
* IMPORTANT: but, note, that instances CAN NOT BE CACHED if there is
* a value type deserializer; this caused an issue with 2.4.4 of
* JAXB Annotations (failing a test).
* It is also possible that some other settings could make deserializers
* un-cacheable; but on the other hand, caching can make a big positive
* difference with performance... so it's a hard choice.
*
* @since 2.4.4
*/
/*
/**********************************************************
/* JsonDeserializer API
/**********************************************************
*/
@Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
68 | 0def35667757601a6fa377d13aae12642da45bda526e1ec4db289c4199224f17 | private boolean inSpecificScope(String[] targetNames, String[] baseTypes, String[] extraTypes) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean inSpecificScope(String[] targetNames, String[] baseTypes, String[] extraTypes) {
// https://html.spec.whatwg.org/multipage/parsing.html#has-an-element-in-the-specific-scope
final int bottom = stack.size() -1;
final int top = bottom > MaxScopeSearchDepth ? bottom - MaxScopeSearchDepth : 0;
// don't walk too far up the tree
for (int pos = bottom; pos >= top; pos--) {
final String elName = stack.get(pos).nodeName();
if (inSorted(elName, targetNames))
return true;
if (inSorted(elName, baseTypes))
return false;
if (extraTypes != null && inSorted(elName, extraTypes))
return false;
}
//Validate.fail("Should not be reachable"); // would end up false because hitting 'html' at root (basetypes)
return false;
}
```
| private boolean inSpecificScope(String[] targetNames, String[] baseTypes, String[] extraTypes) {
// https://html.spec.whatwg.org/multipage/parsing.html#has-an-element-in-the-specific-scope
final int bottom = stack.size() -1;
final int top = bottom > MaxScopeSearchDepth ? bottom - MaxScopeSearchDepth : 0;
// don't walk too far up the tree
for (int pos = bottom; pos >= top; pos--) {
final String elName = stack.get(pos).nodeName();
if (inSorted(elName, targetNames))
return true;
if (inSorted(elName, baseTypes))
return false;
if (extraTypes != null && inSorted(elName, extraTypes))
return false;
}
//Validate.fail("Should not be reachable"); // would end up false because hitting 'html' at root (basetypes)
return false;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean inSpecificScope(String[] targetNames, String[] baseTypes, String[] extraTypes) {
// https://html.spec.whatwg.org/multipage/parsing.html#has-an-element-in-the-specific-scope
final int bottom = stack.size() -1;
final int top = bottom > MaxScopeSearchDepth ? bottom - MaxScopeSearchDepth : 0;
// don't walk too far up the tree
for (int pos = bottom; pos >= top; pos--) {
final String elName = stack.get(pos).nodeName();
if (inSorted(elName, targetNames))
return true;
if (inSorted(elName, baseTypes))
return false;
if (extraTypes != null && inSorted(elName, extraTypes))
return false;
}
//Validate.fail("Should not be reachable"); // would end up false because hitting 'html' at root (basetypes)
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
27 | 0e10e9b5f0a6a5b31f7150f2a9cf2379b7cb59aa86767876527911ce08b988e1 | public <T> void resetMock(T mock) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MockHandler<T> newMockHandler = new MockHandler<T>(oldMockHandler);
MethodInterceptorFilter newFilter = new MethodInterceptorFilter(newMockHandler, (MockSettingsImpl) org.mockito.Mockito.withSettings().defaultAnswer(org.mockito.Mockito.RETURNS_DEFAULTS));
((Factory) mock).setCallback(0, newFilter);
}
```
| public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MockHandler<T> newMockHandler = new MockHandler<T>(oldMockHandler);
MethodInterceptorFilter newFilter = new MethodInterceptorFilter(newMockHandler, (MockSettingsImpl) org.mockito.Mockito.withSettings().defaultAnswer(org.mockito.Mockito.RETURNS_DEFAULTS));
((Factory) mock).setCallback(0, newFilter);
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public <T> void resetMock(T mock) {
MockHandlerInterface<T> oldMockHandler = getMockHandler(mock);
MockHandler<T> newMockHandler = new MockHandler<T>(oldMockHandler);
MethodInterceptorFilter newFilter = new MethodInterceptorFilter(newMockHandler, (MockSettingsImpl) org.mockito.Mockito.withSettings().defaultAnswer(org.mockito.Mockito.RETURNS_DEFAULTS));
((Factory) mock).setCallback(0, newFilter);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 0e2ba237711770bb37dc99985526b6d0c3db39708a285842de2bd572acd09f43 | protected void checkRequiredOptions()
throws MissingOptionException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
protected void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (getRequiredOptions().size() > 0)
{
Iterator iter = getRequiredOptions().iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(getRequiredOptions().size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
buff.append(", ");
}
throw new MissingOptionException(buff.substring(0, buff.length() - 2));
}
}
```
| protected void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (getRequiredOptions().size() > 0)
{
Iterator iter = getRequiredOptions().iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(getRequiredOptions().size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
buff.append(", ");
}
throw new MissingOptionException(buff.substring(0, buff.length() - 2));
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
protected void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (getRequiredOptions().size() > 0)
{
Iterator iter = getRequiredOptions().iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(getRequiredOptions().size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
buff.append(", ");
}
throw new MissingOptionException(buff.substring(0, buff.length() - 2));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 0e6448dc59cece728aea470c9fe6c2edbb565903e1d0b1f4668373ef86d510d0 | public boolean hasAttr(String attributeKey) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Test if this element has an attribute.
* @param attributeKey The attribute key to check.
* @return true if the attribute exists, false if not.
*/
public boolean hasAttr(String attributeKey) {
Validate.notNull(attributeKey);
if (attributeKey.toLowerCase().startsWith("abs:")) {
String key = attributeKey.substring("abs:".length());
if (attributes.hasKey(key) && !absUrl(key).equals(""))
return true;
}
return attributes.hasKey(attributeKey);
}
```
| public boolean hasAttr(String attributeKey) {
Validate.notNull(attributeKey);
if (attributeKey.toLowerCase().startsWith("abs:")) {
String key = attributeKey.substring("abs:".length());
if (attributes.hasKey(key) && !absUrl(key).equals(""))
return true;
}
return attributes.hasKey(attributeKey);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Test if this element has an attribute.
* @param attributeKey The attribute key to check.
* @return true if the attribute exists, false if not.
*/
public boolean hasAttr(String attributeKey) {
Validate.notNull(attributeKey);
if (attributeKey.toLowerCase().startsWith("abs:")) {
String key = attributeKey.substring("abs:".length());
if (attributes.hasKey(key) && !absUrl(key).equals(""))
return true;
}
return attributes.hasKey(attributeKey);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 0e76699578886aa38e0be6757d5de9f602ed8e00cbe13762a5a18884b00860ff | @Override
public Object deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Deserializer API
/**********************************************************
*/
@Override
public Object deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 29-Jan-2016, tatu: Simple skipping for all other tokens, but FIELD_NAME bit
// special unfortunately
p.skipChildren();
return null;
}
```
| @Override
public Object deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 29-Jan-2016, tatu: Simple skipping for all other tokens, but FIELD_NAME bit
// special unfortunately
p.skipChildren();
return null;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Deserializer API
/**********************************************************
*/
@Override
public Object deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
// 29-Jan-2016, tatu: Simple skipping for all other tokens, but FIELD_NAME bit
// special unfortunately
p.skipChildren();
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 0ed79c4903010a50f09d9a2fd380672f36cee89f0ae3c9c97be32e35fcb4c4d6 | private void checkParameters() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Checks dimensions and values of boundaries and inputSigma if defined.
*/
private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
}
```
| private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Checks dimensions and values of boundaries and inputSigma if defined.
*/
private void checkParameters() {
final double[] init = getStartPoint();
final double[] lB = getLowerBound();
final double[] uB = getUpperBound();
// Checks whether there is at least one finite bound value.
boolean hasFiniteBounds = false;
for (int i = 0; i < lB.length; i++) {
if (!Double.isInfinite(lB[i]) ||
!Double.isInfinite(uB[i])) {
hasFiniteBounds = true;
break;
}
}
// Checks whether there is at least one infinite bound value.
boolean hasInfiniteBounds = false;
if (hasFiniteBounds) {
for (int i = 0; i < lB.length; i++) {
if (Double.isInfinite(lB[i]) ||
Double.isInfinite(uB[i])) {
hasInfiniteBounds = true;
break;
}
}
if (hasInfiniteBounds) {
// If there is at least one finite bound, none can be infinite,
// because mixed cases are not supported by the current code.
throw new MathUnsupportedOperationException();
} else {
// Convert API to internal handling of boundaries.
boundaries = new double[2][];
boundaries[0] = lB;
boundaries[1] = uB;
// Abort early if the normalization will overflow (cf. "encode" method).
}
} else {
// Convert API to internal handling of boundaries.
boundaries = null;
}
if (inputSigma != null) {
if (inputSigma.length != init.length) {
throw new DimensionMismatchException(inputSigma.length, init.length);
}
for (int i = 0; i < init.length; i++) {
if (inputSigma[i] < 0) {
throw new NotPositiveException(inputSigma[i]);
}
if (boundaries != null) {
if (inputSigma[i] > boundaries[1][i] - boundaries[0][i]) {
throw new OutOfRangeException(inputSigma[i], 0, boundaries[1][i] - boundaries[0][i]);
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
96 | 0f40d8ca107e3be943664268ed96e169fdcb2a20a8e2e9dbef8143d75b9cf1ce | public boolean equals(Object other) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Test for the equality of two Complex objects.
* <p>
* If both the real and imaginary parts of two Complex numbers
* are exactly the same, and neither is <code>Double.NaN</code>, the two
* Complex objects are considered to be equal.</p>
* <p>
* All <code>NaN</code> values are considered to be equal - i.e, if either
* (or both) real and imaginary parts of the complex number are equal
* to <code>Double.NaN</code>, the complex number is equal to
* <code>Complex.NaN</code>.</p>
*
* @param other Object to test for equality to this
* @return true if two Complex objects are equal, false if
* object is null, not an instance of Complex, or
* not equal to this Complex instance
*
*/
public boolean equals(Object other) {
boolean ret;
if (this == other) {
ret = true;
} else if (other == null) {
ret = false;
} else {
try {
Complex rhs = (Complex)other;
if (rhs.isNaN()) {
ret = this.isNaN();
} else {
ret = (Double.doubleToRawLongBits(real) == Double.doubleToRawLongBits(rhs.getReal())) && (Double.doubleToRawLongBits(imaginary) == Double.doubleToRawLongBits(rhs.getImaginary()));
}
} catch (ClassCastException ex) {
// ignore exception
ret = false;
}
}
return ret;
}
```
| public boolean equals(Object other) {
boolean ret;
if (this == other) {
ret = true;
} else if (other == null) {
ret = false;
} else {
try {
Complex rhs = (Complex)other;
if (rhs.isNaN()) {
ret = this.isNaN();
} else {
ret = (Double.doubleToRawLongBits(real) == Double.doubleToRawLongBits(rhs.getReal())) && (Double.doubleToRawLongBits(imaginary) == Double.doubleToRawLongBits(rhs.getImaginary()));
}
} catch (ClassCastException ex) {
// ignore exception
ret = false;
}
}
return ret;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Test for the equality of two Complex objects.
* <p>
* If both the real and imaginary parts of two Complex numbers
* are exactly the same, and neither is <code>Double.NaN</code>, the two
* Complex objects are considered to be equal.</p>
* <p>
* All <code>NaN</code> values are considered to be equal - i.e, if either
* (or both) real and imaginary parts of the complex number are equal
* to <code>Double.NaN</code>, the complex number is equal to
* <code>Complex.NaN</code>.</p>
*
* @param other Object to test for equality to this
* @return true if two Complex objects are equal, false if
* object is null, not an instance of Complex, or
* not equal to this Complex instance
*
*/
public boolean equals(Object other) {
boolean ret;
if (this == other) {
ret = true;
} else if (other == null) {
ret = false;
} else {
try {
Complex rhs = (Complex)other;
if (rhs.isNaN()) {
ret = this.isNaN();
} else {
ret = (Double.doubleToRawLongBits(real) == Double.doubleToRawLongBits(rhs.getReal())) && (Double.doubleToRawLongBits(imaginary) == Double.doubleToRawLongBits(rhs.getImaginary()));
}
} catch (ClassCastException ex) {
// ignore exception
ret = false;
}
}
return ret;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
89 | 0f812e5db8da1b60d7a5b3264978a208d7d8ced37f0cbbe5c1b52c635ea1cc45 | public String setValue(String val) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
Set the attribute value.
@param val the new attribute value; must not be null
*/
public String setValue(String val) {
String oldVal = this.val;
if (parent != null) {
oldVal = parent.get(this.key); // trust the container more
int i = parent.indexOfKey(this.key);
if (i != Attributes.NotFound)
parent.vals[i] = val;
}
this.val = val;
return Attributes.checkNotNull(oldVal);
}
```
| public String setValue(String val) {
String oldVal = this.val;
if (parent != null) {
oldVal = parent.get(this.key); // trust the container more
int i = parent.indexOfKey(this.key);
if (i != Attributes.NotFound)
parent.vals[i] = val;
}
this.val = val;
return Attributes.checkNotNull(oldVal);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
Set the attribute value.
@param val the new attribute value; must not be null
*/
public String setValue(String val) {
String oldVal = this.val;
if (parent != null) {
oldVal = parent.get(this.key); // trust the container more
int i = parent.indexOfKey(this.key);
if (i != Attributes.NotFound)
parent.vals[i] = val;
}
this.val = val;
return Attributes.checkNotNull(oldVal);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
53 | 10458c3d17c12e0ebec0f4c5249aee35665687eaac303d66cee145f4849ccd42 | private static void modify(Calendar val, int field, boolean round) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Internal calculation method.</p>
*
* @param val the calendar
* @param field the field constant
* @param round true to round, false to truncate
* @throws ArithmeticException if the year is over 280 million
*/
//-----------------------------------------------------------------------
private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
}
if (field == Calendar.SECOND) {
done = true;
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
}
if (field == Calendar.MINUTE) {
done = true;
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
}
```
| private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
}
if (field == Calendar.SECOND) {
done = true;
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
}
if (field == Calendar.MINUTE) {
done = true;
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Internal calculation method.</p>
*
* @param val the calendar
* @param field the field constant
* @param round true to round, false to truncate
* @throws ArithmeticException if the year is over 280 million
*/
//-----------------------------------------------------------------------
private static void modify(Calendar val, int field, boolean round) {
if (val.get(Calendar.YEAR) > 280000000) {
throw new ArithmeticException("Calendar value too large for accurate calculations");
}
if (field == Calendar.MILLISECOND) {
return;
}
// ----------------- Fix for LANG-59 ---------------------- START ---------------
// see http://issues.apache.org/jira/browse/LANG-59
//
// Manually truncate milliseconds, seconds and minutes, rather than using
// Calendar methods.
Date date = val.getTime();
long time = date.getTime();
boolean done = false;
// truncate milliseconds
int millisecs = val.get(Calendar.MILLISECOND);
if (!round || millisecs < 500) {
time = time - millisecs;
}
if (field == Calendar.SECOND) {
done = true;
}
// truncate seconds
int seconds = val.get(Calendar.SECOND);
if (!done && (!round || seconds < 30)) {
time = time - (seconds * 1000L);
}
if (field == Calendar.MINUTE) {
done = true;
}
// truncate minutes
int minutes = val.get(Calendar.MINUTE);
if (!done && (!round || minutes < 30)) {
time = time - (minutes * 60000L);
}
// reset time
if (date.getTime() != time) {
date.setTime(time);
val.setTime(date);
}
// ----------------- Fix for LANG-59 ----------------------- END ----------------
boolean roundUp = false;
for (int i = 0; i < fields.length; i++) {
for (int j = 0; j < fields[i].length; j++) {
if (fields[i][j] == field) {
//This is our field... we stop looping
if (round && roundUp) {
if (field == DateUtils.SEMI_MONTH) {
//This is a special case that's hard to generalize
//If the date is 1, we round up to 16, otherwise
// we subtract 15 days and add 1 month
if (val.get(Calendar.DATE) == 1) {
val.add(Calendar.DATE, 15);
} else {
val.add(Calendar.DATE, -15);
val.add(Calendar.MONTH, 1);
}
} else {
//We need at add one to this field since the
// last number causes us to round up
val.add(fields[i][0], 1);
}
}
return;
}
}
//We have various fields that are not easy roundings
int offset = 0;
boolean offsetSet = false;
//These are special types of fields that require different rounding rules
switch (field) {
case DateUtils.SEMI_MONTH:
if (fields[i][0] == Calendar.DATE) {
//If we're going to drop the DATE field's value,
// we want to do this our own way.
//We need to subtrace 1 since the date has a minimum of 1
offset = val.get(Calendar.DATE) - 1;
//If we're above 15 days adjustment, that means we're in the
// bottom half of the month and should stay accordingly.
if (offset >= 15) {
offset -= 15;
}
//Record whether we're in the top or bottom half of that range
roundUp = offset > 7;
offsetSet = true;
}
break;
case Calendar.AM_PM:
if (fields[i][0] == Calendar.HOUR_OF_DAY) {
//If we're going to drop the HOUR field's value,
// we want to do this our own way.
offset = val.get(Calendar.HOUR_OF_DAY);
if (offset >= 12) {
offset -= 12;
}
roundUp = offset > 6;
offsetSet = true;
}
break;
}
if (!offsetSet) {
int min = val.getActualMinimum(fields[i][0]);
int max = val.getActualMaximum(fields[i][0]);
//Calculate the offset from the minimum allowed value
offset = val.get(fields[i][0]) - min;
//Set roundUp if this is more than half way between the minimum and maximum
roundUp = offset > ((max - min) / 2);
}
//We need to remove this field
if (offset != 0) {
val.set(fields[i][0], val.get(fields[i][0]) - offset);
}
}
throw new IllegalArgumentException("The field " + field + " is not supported");
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
64 | 109177e881e17fbbaa4e847d4b64eb5388daf13bd4febbb165d53a4589426e15 | @SuppressWarnings("deprecation")
protected BeanPropertyWriter buildWriter(SerializerProvider prov,
BeanPropertyDefinition propDef, JavaType declaredType, JsonSerializer<?> ser,
TypeSerializer typeSer, TypeSerializer contentTypeSer,
AnnotatedMember am, boolean defaultUseStaticTyping)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @param contentTypeSer Optional explicit type information serializer
* to use for contained values (only used for properties that are
* of container type)
*/
@SuppressWarnings("deprecation")
protected BeanPropertyWriter buildWriter(SerializerProvider prov,
BeanPropertyDefinition propDef, JavaType declaredType, JsonSerializer<?> ser,
TypeSerializer typeSer, TypeSerializer contentTypeSer,
AnnotatedMember am, boolean defaultUseStaticTyping)
throws JsonMappingException
{
// do we have annotation that forces type to use (to declared type or its super type)?
JavaType serializationType;
try {
serializationType = findSerializationType(am, defaultUseStaticTyping, declaredType);
} catch (JsonMappingException e) {
return prov.reportBadPropertyDefinition(_beanDesc, propDef, e.getMessage());
}
// Container types can have separate type serializers for content (value / element) type
if (contentTypeSer != null) {
/* 04-Feb-2010, tatu: Let's force static typing for collection, if there is
* type information for contents. Should work well (for JAXB case); can be
* revisited if this causes problems.
*/
if (serializationType == null) {
// serializationType = TypeFactory.type(am.getGenericType(), _beanDesc.getType());
serializationType = declaredType;
}
JavaType ct = serializationType.getContentType();
// Not exactly sure why, but this used to occur; better check explicitly:
if (ct == null) {
prov.reportBadPropertyDefinition(_beanDesc, propDef,
"serialization type "+serializationType+" has no content");
}
serializationType = serializationType.withContentTypeHandler(contentTypeSer);
ct = serializationType.getContentType();
}
Object valueToSuppress = null;
boolean suppressNulls = false;
// 12-Jul-2016, tatu: [databind#1256] Need to make sure we consider type refinement
JavaType actualType = (serializationType == null) ? declaredType : serializationType;
// 17-Aug-2016, tatu: Default inclusion covers global default (for all types), as well
// as type-default for enclosing POJO. What we need, then, is per-type default (if any)
// for declared property type... and finally property annotation overrides
JsonInclude.Value inclV = _config.getDefaultPropertyInclusion(actualType.getRawClass(),
_defaultInclusion);
// property annotation override
inclV = inclV.withOverrides(propDef.findInclusion());
JsonInclude.Include inclusion = inclV.getValueInclusion();
if (inclusion == JsonInclude.Include.USE_DEFAULTS) { // should not occur but...
inclusion = JsonInclude.Include.ALWAYS;
}
switch (inclusion) {
case NON_DEFAULT:
// 11-Nov-2015, tatu: This is tricky because semantics differ between cases,
// so that if enclosing class has this, we may need to access values of property,
// whereas for global defaults OR per-property overrides, we have more
// static definition. Sigh.
// First: case of class/type specifying it; try to find POJO property defaults
// 16-Oct-2016, tatu: Note: if we can not for some reason create "default instance",
// revert logic to the case of general/per-property handling, so both
// type-default AND null are to be excluded.
// (as per [databind#1417]
if (_useRealPropertyDefaults) {
// 07-Sep-2016, tatu: may also need to front-load access forcing now
if (prov.isEnabled(MapperFeature.CAN_OVERRIDE_ACCESS_MODIFIERS)) {
am.fixAccess(_config.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
valueToSuppress = getPropertyDefaultValue(propDef.getName(), am, actualType);
} else {
valueToSuppress = getDefaultValue(actualType);
suppressNulls = true;
}
if (valueToSuppress == null) {
suppressNulls = true;
} else {
if (valueToSuppress.getClass().isArray()) {
valueToSuppress = ArrayBuilders.getArrayComparator(valueToSuppress);
}
}
break;
case NON_ABSENT: // new with 2.6, to support Guava/JDK8 Optionals
// always suppress nulls
suppressNulls = true;
// and for referential types, also "empty", which in their case means "absent"
if (actualType.isReferenceType()) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
case NON_EMPTY:
// always suppress nulls
suppressNulls = true;
// but possibly also 'empty' values:
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
break;
case NON_NULL:
suppressNulls = true;
// fall through
case ALWAYS: // default
default:
// we may still want to suppress empty collections, as per [JACKSON-254]:
if (actualType.isContainerType()
&& !_config.isEnabled(SerializationFeature.WRITE_EMPTY_JSON_ARRAYS)) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
}
BeanPropertyWriter bpw = new BeanPropertyWriter(propDef,
am, _beanDesc.getClassAnnotations(), declaredType,
ser, typeSer, serializationType, suppressNulls, valueToSuppress);
// How about custom null serializer?
Object serDef = _annotationIntrospector.findNullSerializer(am);
if (serDef != null) {
bpw.assignNullSerializer(prov.serializerInstance(am, serDef));
}
// And then, handling of unwrapping
NameTransformer unwrapper = _annotationIntrospector.findUnwrappingNameTransformer(am);
if (unwrapper != null) {
bpw = bpw.unwrappingWriter(unwrapper);
}
return bpw;
}
```
| @SuppressWarnings("deprecation")
protected BeanPropertyWriter buildWriter(SerializerProvider prov,
BeanPropertyDefinition propDef, JavaType declaredType, JsonSerializer<?> ser,
TypeSerializer typeSer, TypeSerializer contentTypeSer,
AnnotatedMember am, boolean defaultUseStaticTyping)
throws JsonMappingException
{
// do we have annotation that forces type to use (to declared type or its super type)?
JavaType serializationType;
try {
serializationType = findSerializationType(am, defaultUseStaticTyping, declaredType);
} catch (JsonMappingException e) {
return prov.reportBadPropertyDefinition(_beanDesc, propDef, e.getMessage());
}
// Container types can have separate type serializers for content (value / element) type
if (contentTypeSer != null) {
/* 04-Feb-2010, tatu: Let's force static typing for collection, if there is
* type information for contents. Should work well (for JAXB case); can be
* revisited if this causes problems.
*/
if (serializationType == null) {
// serializationType = TypeFactory.type(am.getGenericType(), _beanDesc.getType());
serializationType = declaredType;
}
JavaType ct = serializationType.getContentType();
// Not exactly sure why, but this used to occur; better check explicitly:
if (ct == null) {
prov.reportBadPropertyDefinition(_beanDesc, propDef,
"serialization type "+serializationType+" has no content");
}
serializationType = serializationType.withContentTypeHandler(contentTypeSer);
ct = serializationType.getContentType();
}
Object valueToSuppress = null;
boolean suppressNulls = false;
// 12-Jul-2016, tatu: [databind#1256] Need to make sure we consider type refinement
JavaType actualType = (serializationType == null) ? declaredType : serializationType;
// 17-Aug-2016, tatu: Default inclusion covers global default (for all types), as well
// as type-default for enclosing POJO. What we need, then, is per-type default (if any)
// for declared property type... and finally property annotation overrides
JsonInclude.Value inclV = _config.getDefaultPropertyInclusion(actualType.getRawClass(),
_defaultInclusion);
// property annotation override
inclV = inclV.withOverrides(propDef.findInclusion());
JsonInclude.Include inclusion = inclV.getValueInclusion();
if (inclusion == JsonInclude.Include.USE_DEFAULTS) { // should not occur but...
inclusion = JsonInclude.Include.ALWAYS;
}
switch (inclusion) {
case NON_DEFAULT:
// 11-Nov-2015, tatu: This is tricky because semantics differ between cases,
// so that if enclosing class has this, we may need to access values of property,
// whereas for global defaults OR per-property overrides, we have more
// static definition. Sigh.
// First: case of class/type specifying it; try to find POJO property defaults
// 16-Oct-2016, tatu: Note: if we can not for some reason create "default instance",
// revert logic to the case of general/per-property handling, so both
// type-default AND null are to be excluded.
// (as per [databind#1417]
if (_useRealPropertyDefaults) {
// 07-Sep-2016, tatu: may also need to front-load access forcing now
if (prov.isEnabled(MapperFeature.CAN_OVERRIDE_ACCESS_MODIFIERS)) {
am.fixAccess(_config.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
valueToSuppress = getPropertyDefaultValue(propDef.getName(), am, actualType);
} else {
valueToSuppress = getDefaultValue(actualType);
suppressNulls = true;
}
if (valueToSuppress == null) {
suppressNulls = true;
} else {
if (valueToSuppress.getClass().isArray()) {
valueToSuppress = ArrayBuilders.getArrayComparator(valueToSuppress);
}
}
break;
case NON_ABSENT: // new with 2.6, to support Guava/JDK8 Optionals
// always suppress nulls
suppressNulls = true;
// and for referential types, also "empty", which in their case means "absent"
if (actualType.isReferenceType()) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
case NON_EMPTY:
// always suppress nulls
suppressNulls = true;
// but possibly also 'empty' values:
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
break;
case NON_NULL:
suppressNulls = true;
// fall through
case ALWAYS: // default
default:
// we may still want to suppress empty collections, as per [JACKSON-254]:
if (actualType.isContainerType()
&& !_config.isEnabled(SerializationFeature.WRITE_EMPTY_JSON_ARRAYS)) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
}
BeanPropertyWriter bpw = new BeanPropertyWriter(propDef,
am, _beanDesc.getClassAnnotations(), declaredType,
ser, typeSer, serializationType, suppressNulls, valueToSuppress);
// How about custom null serializer?
Object serDef = _annotationIntrospector.findNullSerializer(am);
if (serDef != null) {
bpw.assignNullSerializer(prov.serializerInstance(am, serDef));
}
// And then, handling of unwrapping
NameTransformer unwrapper = _annotationIntrospector.findUnwrappingNameTransformer(am);
if (unwrapper != null) {
bpw = bpw.unwrappingWriter(unwrapper);
}
return bpw;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @param contentTypeSer Optional explicit type information serializer
* to use for contained values (only used for properties that are
* of container type)
*/
@SuppressWarnings("deprecation")
protected BeanPropertyWriter buildWriter(SerializerProvider prov,
BeanPropertyDefinition propDef, JavaType declaredType, JsonSerializer<?> ser,
TypeSerializer typeSer, TypeSerializer contentTypeSer,
AnnotatedMember am, boolean defaultUseStaticTyping)
throws JsonMappingException
{
// do we have annotation that forces type to use (to declared type or its super type)?
JavaType serializationType;
try {
serializationType = findSerializationType(am, defaultUseStaticTyping, declaredType);
} catch (JsonMappingException e) {
return prov.reportBadPropertyDefinition(_beanDesc, propDef, e.getMessage());
}
// Container types can have separate type serializers for content (value / element) type
if (contentTypeSer != null) {
/* 04-Feb-2010, tatu: Let's force static typing for collection, if there is
* type information for contents. Should work well (for JAXB case); can be
* revisited if this causes problems.
*/
if (serializationType == null) {
// serializationType = TypeFactory.type(am.getGenericType(), _beanDesc.getType());
serializationType = declaredType;
}
JavaType ct = serializationType.getContentType();
// Not exactly sure why, but this used to occur; better check explicitly:
if (ct == null) {
prov.reportBadPropertyDefinition(_beanDesc, propDef,
"serialization type "+serializationType+" has no content");
}
serializationType = serializationType.withContentTypeHandler(contentTypeSer);
ct = serializationType.getContentType();
}
Object valueToSuppress = null;
boolean suppressNulls = false;
// 12-Jul-2016, tatu: [databind#1256] Need to make sure we consider type refinement
JavaType actualType = (serializationType == null) ? declaredType : serializationType;
// 17-Aug-2016, tatu: Default inclusion covers global default (for all types), as well
// as type-default for enclosing POJO. What we need, then, is per-type default (if any)
// for declared property type... and finally property annotation overrides
JsonInclude.Value inclV = _config.getDefaultPropertyInclusion(actualType.getRawClass(),
_defaultInclusion);
// property annotation override
inclV = inclV.withOverrides(propDef.findInclusion());
JsonInclude.Include inclusion = inclV.getValueInclusion();
if (inclusion == JsonInclude.Include.USE_DEFAULTS) { // should not occur but...
inclusion = JsonInclude.Include.ALWAYS;
}
switch (inclusion) {
case NON_DEFAULT:
// 11-Nov-2015, tatu: This is tricky because semantics differ between cases,
// so that if enclosing class has this, we may need to access values of property,
// whereas for global defaults OR per-property overrides, we have more
// static definition. Sigh.
// First: case of class/type specifying it; try to find POJO property defaults
// 16-Oct-2016, tatu: Note: if we can not for some reason create "default instance",
// revert logic to the case of general/per-property handling, so both
// type-default AND null are to be excluded.
// (as per [databind#1417]
if (_useRealPropertyDefaults) {
// 07-Sep-2016, tatu: may also need to front-load access forcing now
if (prov.isEnabled(MapperFeature.CAN_OVERRIDE_ACCESS_MODIFIERS)) {
am.fixAccess(_config.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
valueToSuppress = getPropertyDefaultValue(propDef.getName(), am, actualType);
} else {
valueToSuppress = getDefaultValue(actualType);
suppressNulls = true;
}
if (valueToSuppress == null) {
suppressNulls = true;
} else {
if (valueToSuppress.getClass().isArray()) {
valueToSuppress = ArrayBuilders.getArrayComparator(valueToSuppress);
}
}
break;
case NON_ABSENT: // new with 2.6, to support Guava/JDK8 Optionals
// always suppress nulls
suppressNulls = true;
// and for referential types, also "empty", which in their case means "absent"
if (actualType.isReferenceType()) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
case NON_EMPTY:
// always suppress nulls
suppressNulls = true;
// but possibly also 'empty' values:
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
break;
case NON_NULL:
suppressNulls = true;
// fall through
case ALWAYS: // default
default:
// we may still want to suppress empty collections, as per [JACKSON-254]:
if (actualType.isContainerType()
&& !_config.isEnabled(SerializationFeature.WRITE_EMPTY_JSON_ARRAYS)) {
valueToSuppress = BeanPropertyWriter.MARKER_FOR_EMPTY;
}
break;
}
BeanPropertyWriter bpw = new BeanPropertyWriter(propDef,
am, _beanDesc.getClassAnnotations(), declaredType,
ser, typeSer, serializationType, suppressNulls, valueToSuppress);
// How about custom null serializer?
Object serDef = _annotationIntrospector.findNullSerializer(am);
if (serDef != null) {
bpw.assignNullSerializer(prov.serializerInstance(am, serDef));
}
// And then, handling of unwrapping
NameTransformer unwrapper = _annotationIntrospector.findUnwrappingNameTransformer(am);
if (unwrapper != null) {
bpw = bpw.unwrappingWriter(unwrapper);
}
return bpw;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 109c4def2974df0f3b296718a7fb609b3668dab415a37e5d41c6786fd12d6e0b | @Override
public boolean isCachable() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Turns out that these are expensive enough to create so that caching
* does make sense.
*<p>
* IMPORTANT: but, note, that instances CAN NOT BE CACHED if there is
* a value type deserializer; this caused an issue with 2.4.4 of
* JAXB Annotations (failing a test).
* It is also possible that some other settings could make deserializers
* un-cacheable; but on the other hand, caching can make a big positive
* difference with performance... so it's a hard choice.
*
* @since 2.4.4
*/
/*
/**********************************************************
/* JsonDeserializer API
/**********************************************************
*/
@Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueDeserializer == null)
&& (_keyDeserializer == null)
&& (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
}
```
| @Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueDeserializer == null)
&& (_keyDeserializer == null)
&& (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Turns out that these are expensive enough to create so that caching
* does make sense.
*<p>
* IMPORTANT: but, note, that instances CAN NOT BE CACHED if there is
* a value type deserializer; this caused an issue with 2.4.4 of
* JAXB Annotations (failing a test).
* It is also possible that some other settings could make deserializers
* un-cacheable; but on the other hand, caching can make a big positive
* difference with performance... so it's a hard choice.
*
* @since 2.4.4
*/
/*
/**********************************************************
/* JsonDeserializer API
/**********************************************************
*/
@Override
public boolean isCachable() {
/* As per [databind#735], existence of value or key deserializer (only passed
* if annotated to use non-standard one) should also prevent caching.
*/
return (_valueDeserializer == null)
&& (_keyDeserializer == null)
&& (_valueTypeDeserializer == null)
&& (_ignorableProperties == null);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 11228ed4ee00c460b0f6858de88bac326582028df826f583295cc4bfced5a5c4 | public String generateToolTipFragment(String toolTipText) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Generates a tooltip string to go in an HTML image map.
*
* @param toolTipText the tooltip.
*
* @return The formatted HTML area tag attribute(s).
*/
public String generateToolTipFragment(String toolTipText) {
return " title=\"" + ImageMapUtilities.htmlEscape(toolTipText)
+ "\" alt=\"\"";
}
```
| public String generateToolTipFragment(String toolTipText) {
return " title=\"" + ImageMapUtilities.htmlEscape(toolTipText)
+ "\" alt=\"\"";
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Generates a tooltip string to go in an HTML image map.
*
* @param toolTipText the tooltip.
*
* @return The formatted HTML area tag attribute(s).
*/
public String generateToolTipFragment(String toolTipText) {
return " title=\"" + ImageMapUtilities.htmlEscape(toolTipText)
+ "\" alt=\"\"";
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
44 | 1243be4aed2aeed978683480ef50c1035b2055f6596728bdf36be44c5ade998c | public static Number createNumber(String val) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can hold the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* @param val String containing a number
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//--------------------------------------------------------------------
public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.length() == 1 && !Character.isDigit(val.charAt(0))) {
throw new NumberFormatException(val + " is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
}
```
| public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.length() == 1 && !Character.isDigit(val.charAt(0))) {
throw new NumberFormatException(val + " is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can hold the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code>, it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* @param val String containing a number
* @return Number created from the string
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// new Short(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// new Long(String)
// new Byte(String)
// new Double(String)
// new Integer(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// new Float(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//--------------------------------------------------------------------
public static Number createNumber(String val) throws NumberFormatException {
if (val == null) {
return null;
}
if (val.length() == 0) {
throw new NumberFormatException("\"\" is not a valid number.");
}
if (val.length() == 1 && !Character.isDigit(val.charAt(0))) {
throw new NumberFormatException(val + " is not a valid number.");
}
if (val.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (val.startsWith("0x") || val.startsWith("-0x")) {
return createInteger(val);
}
char lastChar = val.charAt(val.length() - 1);
String mant;
String dec;
String exp;
int decPos = val.indexOf('.');
int expPos = val.indexOf('e') + val.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos) {
throw new NumberFormatException(val + " is not a valid number.");
}
dec = val.substring(decPos + 1, expPos);
} else {
dec = val.substring(decPos + 1);
}
mant = val.substring(0, decPos);
} else {
if (expPos > -1) {
mant = val.substring(0, expPos);
} else {
mant = val;
}
dec = null;
}
if (!Character.isDigit(lastChar)) {
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = val.substring(0, val.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) {
//Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(val + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException e) {
// ignore the bad number
}
//Fall through
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) {
// empty catch
}
//Fall through
default :
throw new NumberFormatException(val + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < val.length() - 1) {
exp = val.substring(expPos + 1, val.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(val);
} catch (NumberFormatException nfe) {
// empty catch
}
try {
return createLong(val);
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigInteger(val);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(val);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) {
// empty catch
}
try {
Double d = createDouble(val);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) {
// empty catch
}
return createBigDecimal(val);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
105 | 1280c28afccbff5a7490df9a93b9f6cbed102ae00d6a485158a8d4b8d5fd1762 | void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try to fold an array join: ['a', 'b', 'c'].join('') -> 'abc';
*/
void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = null;
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb == null) {
sb = new StringBuilder();
} else {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = null;
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
}
```
| void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = null;
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb == null) {
sb = new StringBuilder();
} else {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = null;
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try to fold an array join: ['a', 'b', 'c'].join('') -> 'abc';
*/
void tryFoldStringJoin(NodeTraversal t, Node n, Node left, Node right,
Node parent) {
if (!NodeUtil.isGetProp(left) || !NodeUtil.isImmutableValue(right)) {
return;
}
Node arrayNode = left.getFirstChild();
Node functionName = arrayNode.getNext();
if ((arrayNode.getType() != Token.ARRAYLIT) ||
!functionName.getString().equals("join")) {
return;
}
String joinString = NodeUtil.getStringValue(right);
List<Node> arrayFoldedChildren = Lists.newLinkedList();
StringBuilder sb = null;
int foldedSize = 0;
Node elem = arrayNode.getFirstChild();
// Merges adjacent String nodes.
while (elem != null) {
if (NodeUtil.isImmutableValue(elem)) {
if (sb == null) {
sb = new StringBuilder();
} else {
sb.append(joinString);
}
sb.append(NodeUtil.getStringValue(elem));
} else {
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
sb = null;
}
foldedSize += InlineCostEstimator.getCost(elem);
arrayFoldedChildren.add(elem);
}
elem = elem.getNext();
}
if (sb != null) {
// + 2 for the quotes.
foldedSize += sb.length() + 2;
arrayFoldedChildren.add(Node.newString(sb.toString()));
}
// one for each comma.
foldedSize += arrayFoldedChildren.size() - 1;
int originalSize = InlineCostEstimator.getCost(n);
switch (arrayFoldedChildren.size()) {
case 0:
Node emptyStringNode = Node.newString("");
parent.replaceChild(n, emptyStringNode);
break;
case 1:
Node foldedStringNode = arrayFoldedChildren.remove(0);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
if (foldedStringNode.getType() != Token.STRING) {
// If the Node is not a string literal, ensure that
// it is coerced to a string.
Node replacement = new Node(Token.ADD,
Node.newString(""), foldedStringNode);
foldedStringNode = replacement;
}
parent.replaceChild(n, foldedStringNode);
break;
default:
// No folding could actually be performed.
if (arrayFoldedChildren.size() == arrayNode.getChildCount()) {
return;
}
int kJoinOverhead = "[].join()".length();
foldedSize += kJoinOverhead;
foldedSize += InlineCostEstimator.getCost(right);
if (foldedSize > originalSize) {
return;
}
arrayNode.detachChildren();
for (Node node : arrayFoldedChildren) {
arrayNode.addChildToBack(node);
}
break;
}
t.getCompiler().reportCodeChange();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 1293d0bdc243e9a26c8c734242b07a222c68e7bbdbf24223991a0b80c7ec9937 | public Object[] sample(int sampleSize) throws NotStrictlyPositiveException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Generate a random sample from the distribution.
*
* @param sampleSize the number of random values to generate.
* @return an array representing the random sample.
* @throws NotStrictlyPositiveException if {@code sampleSize} is not
* positive.
*/
public Object[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final Object[] out = new Object[sampleSize];
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
}
```
| public Object[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final Object[] out = new Object[sampleSize];
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Generate a random sample from the distribution.
*
* @param sampleSize the number of random values to generate.
* @return an array representing the random sample.
* @throws NotStrictlyPositiveException if {@code sampleSize} is not
* positive.
*/
public Object[] sample(int sampleSize) throws NotStrictlyPositiveException {
if (sampleSize <= 0) {
throw new NotStrictlyPositiveException(LocalizedFormats.NUMBER_OF_SAMPLES,
sampleSize);
}
final Object[] out = new Object[sampleSize];
for (int i = 0; i < sampleSize; i++) {
out[i] = sample();
}
return out;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
123 | 12c6731d1f9c2ab8e8972cc2f2f96561002da43eab850676f0e78e3e0d3c802c | void add(Node n, Context context) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void add(Node n, Context context) {
if (!cc.continueProcessing()) {
return;
}
int type = n.getType();
String opstr = NodeUtil.opToStr(type);
int childCount = n.getChildCount();
Node first = n.getFirstChild();
Node last = n.getLastChild();
// Handle all binary operators
if (opstr != null && first != last) {
Preconditions.checkState(
childCount == 2,
"Bad binary operator \"%s\": expected 2 arguments but got %s",
opstr, childCount);
int p = NodeUtil.precedence(type);
// For right-hand-side of operations, only pass context if it's
// the IN_FOR_INIT_CLAUSE one.
Context rhsContext = getContextForNoInOperator(context);
// Handle associativity.
// e.g. if the parse tree is a * (b * c),
// we can simply generate a * b * c.
if (last.getType() == type &&
NodeUtil.isAssociative(type)) {
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else if (NodeUtil.isAssignmentOp(n) && NodeUtil.isAssignmentOp(last)) {
// Assignments are the only right-associative binary operators
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else {
unrollBinaryOperator(n, type, opstr, context, rhsContext, p, p + 1);
}
return;
}
cc.startSourceMapping(n);
switch (type) {
case Token.TRY: {
Preconditions.checkState(first.getNext().isBlock() &&
!first.getNext().hasMoreThanOneChild());
Preconditions.checkState(childCount >= 2 && childCount <= 3);
add("try");
add(first, Context.PRESERVE_BLOCK);
// second child contains the catch block, or nothing if there
// isn't a catch block
Node catchblock = first.getNext().getFirstChild();
if (catchblock != null) {
add(catchblock);
}
if (childCount == 3) {
add("finally");
add(last, Context.PRESERVE_BLOCK);
}
break;
}
case Token.CATCH:
Preconditions.checkState(childCount == 2);
add("catch(");
add(first);
add(")");
add(last, Context.PRESERVE_BLOCK);
break;
case Token.THROW:
Preconditions.checkState(childCount == 1);
add("throw");
add(first);
// Must have a ';' after a throw statement, otherwise safari can't
// parse this.
cc.endStatement(true);
break;
case Token.RETURN:
add("return");
if (childCount == 1) {
add(first);
} else {
Preconditions.checkState(childCount == 0);
}
cc.endStatement();
break;
case Token.VAR:
if (first != null) {
add("var ");
addList(first, false, getContextForNoInOperator(context));
}
break;
case Token.LABEL_NAME:
Preconditions.checkState(!n.getString().isEmpty());
addIdentifier(n.getString());
break;
case Token.NAME:
if (first == null || first.isEmpty()) {
addIdentifier(n.getString());
} else {
Preconditions.checkState(childCount == 1);
addIdentifier(n.getString());
cc.addOp("=", true);
if (first.isComma()) {
addExpr(first, NodeUtil.precedence(Token.ASSIGN), Context.OTHER);
} else {
// Add expression, consider nearby code at lowest level of
// precedence.
addExpr(first, 0, getContextForNoInOperator(context));
}
}
break;
case Token.ARRAYLIT:
add("[");
addArrayList(first);
add("]");
break;
case Token.PARAM_LIST:
add("(");
addList(first);
add(")");
break;
case Token.COMMA:
Preconditions.checkState(childCount == 2);
unrollBinaryOperator(n, Token.COMMA, ",", context,
getContextForNoInOperator(context), 0, 0);
break;
case Token.NUMBER:
Preconditions.checkState(childCount == 0);
cc.addNumber(n.getDouble());
break;
case Token.TYPEOF:
case Token.VOID:
case Token.NOT:
case Token.BITNOT:
case Token.POS: {
// All of these unary operators are right-associative
Preconditions.checkState(childCount == 1);
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
break;
}
case Token.NEG: {
Preconditions.checkState(childCount == 1);
// It's important to our sanity checker that the code
// we print produces the same AST as the code we parse back.
// NEG is a weird case because Rhino parses "- -2" as "2".
if (n.getFirstChild().isNumber()) {
cc.addNumber(-n.getFirstChild().getDouble());
} else {
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
}
break;
}
case Token.HOOK: {
Preconditions.checkState(childCount == 3);
int p = NodeUtil.precedence(type);
Context rhsContext = Context.OTHER;
addExpr(first, p + 1, context);
cc.addOp("?", true);
addExpr(first.getNext(), 1, rhsContext);
cc.addOp(":", true);
addExpr(last, 1, rhsContext);
break;
}
case Token.REGEXP:
if (!first.isString() ||
!last.isString()) {
throw new Error("Expected children to be strings");
}
String regexp = regexpEscape(first.getString(), outputCharsetEncoder);
// I only use one .add because whitespace matters
if (childCount == 2) {
add(regexp + last.getString());
} else {
Preconditions.checkState(childCount == 1);
add(regexp);
}
break;
case Token.FUNCTION:
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
Preconditions.checkState(childCount == 3);
boolean funcNeedsParens = (context == Context.START_OF_EXPR);
if (funcNeedsParens) {
add("(");
}
add("function");
add(first);
add(first.getNext());
add(last, Context.PRESERVE_BLOCK);
cc.endFunction(context == Context.STATEMENT);
if (funcNeedsParens) {
add(")");
}
break;
case Token.GETTER_DEF:
case Token.SETTER_DEF:
Preconditions.checkState(n.getParent().isObjectLit());
Preconditions.checkState(childCount == 1);
Preconditions.checkState(first.isFunction());
// Get methods are unnamed
Preconditions.checkState(first.getFirstChild().getString().isEmpty());
if (type == Token.GETTER_DEF) {
// Get methods have no parameters.
Preconditions.checkState(!first.getChildAtIndex(1).hasChildren());
add("get ");
} else {
// Set methods have one parameter.
Preconditions.checkState(first.getChildAtIndex(1).hasOneChild());
add("set ");
}
// The name is on the GET or SET node.
String name = n.getString();
Node fn = first;
Node parameters = fn.getChildAtIndex(1);
Node body = fn.getLastChild();
// Add the property name.
if (!n.isQuotedString() &&
TokenStream.isJSIdentifier(name) &&
// do not encode literally any non-literal characters that were
// Unicode escaped.
NodeUtil.isLatin(name)) {
add(name);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(name);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addJsString(n);
}
}
add(parameters);
add(body, Context.PRESERVE_BLOCK);
break;
case Token.SCRIPT:
case Token.BLOCK: {
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
boolean preserveBlock = context == Context.PRESERVE_BLOCK;
if (preserveBlock) {
cc.beginBlock();
}
boolean preferLineBreaks =
type == Token.SCRIPT ||
(type == Token.BLOCK &&
!preserveBlock &&
n.getParent() != null &&
n.getParent().isScript());
for (Node c = first; c != null; c = c.getNext()) {
add(c, Context.STATEMENT);
// VAR doesn't include ';' since it gets used in expressions
if (c.isVar()) {
cc.endStatement();
}
if (c.isFunction()) {
cc.maybeLineBreak();
}
// Prefer to break lines in between top-level statements
// because top-level statements are more homogeneous.
if (preferLineBreaks) {
cc.notePreferredLineBreak();
}
}
if (preserveBlock) {
cc.endBlock(cc.breakAfterBlockFor(n, context == Context.STATEMENT));
}
break;
}
case Token.FOR:
if (childCount == 4) {
add("for(");
if (first.isVar()) {
add(first, Context.IN_FOR_INIT_CLAUSE);
} else {
addExpr(first, 0, Context.IN_FOR_INIT_CLAUSE);
}
add(";");
add(first.getNext());
add(";");
add(first.getNext().getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
Preconditions.checkState(childCount == 3);
add("for(");
add(first);
add("in");
add(first.getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
}
break;
case Token.DO:
Preconditions.checkState(childCount == 2);
add("do");
addNonEmptyStatement(first, Context.OTHER, false);
add("while(");
add(last);
add(")");
cc.endStatement();
break;
case Token.WHILE:
Preconditions.checkState(childCount == 2);
add("while(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.EMPTY:
Preconditions.checkState(childCount == 0);
break;
case Token.GETPROP: {
Preconditions.checkState(
childCount == 2,
"Bad GETPROP: expected 2 children, but got %s", childCount);
Preconditions.checkState(
last.isString(),
"Bad GETPROP: RHS should be STRING");
boolean needsParens = (first.isNumber());
if (needsParens) {
add("(");
}
addExpr(first, NodeUtil.precedence(type), context);
if (needsParens) {
add(")");
}
if (this.languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(last.getString())) {
// Check for ECMASCRIPT3 keywords.
add("[");
add(last);
add("]");
} else {
add(".");
addIdentifier(last.getString());
}
break;
}
case Token.GETELEM:
Preconditions.checkState(
childCount == 2,
"Bad GETELEM: expected 2 children but got %s", childCount);
addExpr(first, NodeUtil.precedence(type), context);
add("[");
add(first.getNext());
add("]");
break;
case Token.WITH:
Preconditions.checkState(childCount == 2);
add("with(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.INC:
case Token.DEC: {
Preconditions.checkState(childCount == 1);
String o = type == Token.INC ? "++" : "--";
int postProp = n.getIntProp(Node.INCRDECR_PROP);
// A non-zero post-prop value indicates a post inc/dec, default of zero
// is a pre-inc/dec.
if (postProp != 0) {
addExpr(first, NodeUtil.precedence(type), context);
cc.addOp(o, false);
} else {
cc.addOp(o, false);
add(first);
}
break;
}
case Token.CALL:
// We have two special cases here:
// 1) If the left hand side of the call is a direct reference to eval,
// then it must have a DIRECT_EVAL annotation. If it does not, then
// that means it was originally an indirect call to eval, and that
// indirectness must be preserved.
// 2) If the left hand side of the call is a property reference,
// then the call must not a FREE_CALL annotation. If it does, then
// that means it was originally an call without an explicit this and
// that must be preserved.
if (isIndirectEval(first)
|| n.getBooleanProp(Node.FREE_CALL) && NodeUtil.isGet(first)) {
add("(0,");
addExpr(first, NodeUtil.precedence(Token.COMMA), Context.OTHER);
add(")");
} else {
addExpr(first, NodeUtil.precedence(type), context);
}
add("(");
addList(first.getNext());
add(")");
break;
case Token.IF:
boolean hasElse = childCount == 3;
boolean ambiguousElseClause =
context == Context.BEFORE_DANGLING_ELSE && !hasElse;
if (ambiguousElseClause) {
cc.beginBlock();
}
add("if(");
add(first);
add(")");
if (hasElse) {
addNonEmptyStatement(
first.getNext(), Context.BEFORE_DANGLING_ELSE, false);
add("else");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
addNonEmptyStatement(first.getNext(), Context.OTHER, false);
Preconditions.checkState(childCount == 2);
}
if (ambiguousElseClause) {
cc.endBlock();
}
break;
case Token.NULL:
Preconditions.checkState(childCount == 0);
cc.addConstant("null");
break;
case Token.THIS:
Preconditions.checkState(childCount == 0);
add("this");
break;
case Token.FALSE:
Preconditions.checkState(childCount == 0);
cc.addConstant("false");
break;
case Token.TRUE:
Preconditions.checkState(childCount == 0);
cc.addConstant("true");
break;
case Token.CONTINUE:
Preconditions.checkState(childCount <= 1);
add("continue");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.DEBUGGER:
Preconditions.checkState(childCount == 0);
add("debugger");
cc.endStatement();
break;
case Token.BREAK:
Preconditions.checkState(childCount <= 1);
add("break");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.EXPR_RESULT:
Preconditions.checkState(childCount == 1);
add(first, Context.START_OF_EXPR);
cc.endStatement();
break;
case Token.NEW:
add("new ");
int precedence = NodeUtil.precedence(type);
// If the first child contains a CALL, then claim higher precedence
// to force parentheses. Otherwise, when parsed, NEW will bind to the
// first viable parentheses (don't traverse into functions).
if (NodeUtil.containsType(
first, Token.CALL, NodeUtil.MATCH_NOT_FUNCTION)) {
precedence = NodeUtil.precedence(first.getType()) + 1;
}
addExpr(first, precedence, Context.OTHER);
// '()' is optional when no arguments are present
Node next = first.getNext();
if (next != null) {
add("(");
addList(next);
add(")");
}
break;
case Token.STRING_KEY:
Preconditions.checkState(
childCount == 1, "Object lit key must have 1 child");
addJsString(n);
break;
case Token.STRING:
Preconditions.checkState(
childCount == 0, "A string may not have children");
addJsString(n);
break;
case Token.DELPROP:
Preconditions.checkState(childCount == 1);
add("delete ");
add(first);
break;
case Token.OBJECTLIT: {
boolean needsParens = (context == Context.START_OF_EXPR);
if (needsParens) {
add("(");
}
add("{");
for (Node c = first; c != null; c = c.getNext()) {
if (c != first) {
cc.listSeparator();
}
if (c.isGetterDef() || c.isSetterDef()) {
add(c);
} else {
Preconditions.checkState(c.isStringKey());
String key = c.getString();
// Object literal property names don't have to be quoted if they
// are not JavaScript keywords
if (!c.isQuotedString()
&& !(languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(key))
&& TokenStream.isJSIdentifier(key)
// do not encode literally any non-literal characters that
// were Unicode escaped.
&& NodeUtil.isLatin(key)) {
add(key);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(key);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addExpr(c, 1, Context.OTHER);
}
}
add(":");
addExpr(c.getFirstChild(), 1, Context.OTHER);
}
}
add("}");
if (needsParens) {
add(")");
}
break;
}
case Token.SWITCH:
add("switch(");
add(first);
add(")");
cc.beginBlock();
addAllSiblings(first.getNext());
cc.endBlock(context == Context.STATEMENT);
break;
case Token.CASE:
Preconditions.checkState(childCount == 2);
add("case ");
add(first);
addCaseBody(last);
break;
case Token.DEFAULT_CASE:
Preconditions.checkState(childCount == 1);
add("default");
addCaseBody(first);
break;
case Token.LABEL:
Preconditions.checkState(childCount == 2);
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(first);
add(":");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), true);
break;
case Token.CAST:
add("(");
add(first);
add(")");
break;
default:
throw new Error("Unknown type " + type + "\n" + n.toStringTree());
}
cc.endSourceMapping(n);
}
```
| void add(Node n, Context context) {
if (!cc.continueProcessing()) {
return;
}
int type = n.getType();
String opstr = NodeUtil.opToStr(type);
int childCount = n.getChildCount();
Node first = n.getFirstChild();
Node last = n.getLastChild();
// Handle all binary operators
if (opstr != null && first != last) {
Preconditions.checkState(
childCount == 2,
"Bad binary operator \"%s\": expected 2 arguments but got %s",
opstr, childCount);
int p = NodeUtil.precedence(type);
// For right-hand-side of operations, only pass context if it's
// the IN_FOR_INIT_CLAUSE one.
Context rhsContext = getContextForNoInOperator(context);
// Handle associativity.
// e.g. if the parse tree is a * (b * c),
// we can simply generate a * b * c.
if (last.getType() == type &&
NodeUtil.isAssociative(type)) {
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else if (NodeUtil.isAssignmentOp(n) && NodeUtil.isAssignmentOp(last)) {
// Assignments are the only right-associative binary operators
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else {
unrollBinaryOperator(n, type, opstr, context, rhsContext, p, p + 1);
}
return;
}
cc.startSourceMapping(n);
switch (type) {
case Token.TRY: {
Preconditions.checkState(first.getNext().isBlock() &&
!first.getNext().hasMoreThanOneChild());
Preconditions.checkState(childCount >= 2 && childCount <= 3);
add("try");
add(first, Context.PRESERVE_BLOCK);
// second child contains the catch block, or nothing if there
// isn't a catch block
Node catchblock = first.getNext().getFirstChild();
if (catchblock != null) {
add(catchblock);
}
if (childCount == 3) {
add("finally");
add(last, Context.PRESERVE_BLOCK);
}
break;
}
case Token.CATCH:
Preconditions.checkState(childCount == 2);
add("catch(");
add(first);
add(")");
add(last, Context.PRESERVE_BLOCK);
break;
case Token.THROW:
Preconditions.checkState(childCount == 1);
add("throw");
add(first);
// Must have a ';' after a throw statement, otherwise safari can't
// parse this.
cc.endStatement(true);
break;
case Token.RETURN:
add("return");
if (childCount == 1) {
add(first);
} else {
Preconditions.checkState(childCount == 0);
}
cc.endStatement();
break;
case Token.VAR:
if (first != null) {
add("var ");
addList(first, false, getContextForNoInOperator(context));
}
break;
case Token.LABEL_NAME:
Preconditions.checkState(!n.getString().isEmpty());
addIdentifier(n.getString());
break;
case Token.NAME:
if (first == null || first.isEmpty()) {
addIdentifier(n.getString());
} else {
Preconditions.checkState(childCount == 1);
addIdentifier(n.getString());
cc.addOp("=", true);
if (first.isComma()) {
addExpr(first, NodeUtil.precedence(Token.ASSIGN), Context.OTHER);
} else {
// Add expression, consider nearby code at lowest level of
// precedence.
addExpr(first, 0, getContextForNoInOperator(context));
}
}
break;
case Token.ARRAYLIT:
add("[");
addArrayList(first);
add("]");
break;
case Token.PARAM_LIST:
add("(");
addList(first);
add(")");
break;
case Token.COMMA:
Preconditions.checkState(childCount == 2);
unrollBinaryOperator(n, Token.COMMA, ",", context,
getContextForNoInOperator(context), 0, 0);
break;
case Token.NUMBER:
Preconditions.checkState(childCount == 0);
cc.addNumber(n.getDouble());
break;
case Token.TYPEOF:
case Token.VOID:
case Token.NOT:
case Token.BITNOT:
case Token.POS: {
// All of these unary operators are right-associative
Preconditions.checkState(childCount == 1);
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
break;
}
case Token.NEG: {
Preconditions.checkState(childCount == 1);
// It's important to our sanity checker that the code
// we print produces the same AST as the code we parse back.
// NEG is a weird case because Rhino parses "- -2" as "2".
if (n.getFirstChild().isNumber()) {
cc.addNumber(-n.getFirstChild().getDouble());
} else {
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
}
break;
}
case Token.HOOK: {
Preconditions.checkState(childCount == 3);
int p = NodeUtil.precedence(type);
Context rhsContext = Context.OTHER;
addExpr(first, p + 1, context);
cc.addOp("?", true);
addExpr(first.getNext(), 1, rhsContext);
cc.addOp(":", true);
addExpr(last, 1, rhsContext);
break;
}
case Token.REGEXP:
if (!first.isString() ||
!last.isString()) {
throw new Error("Expected children to be strings");
}
String regexp = regexpEscape(first.getString(), outputCharsetEncoder);
// I only use one .add because whitespace matters
if (childCount == 2) {
add(regexp + last.getString());
} else {
Preconditions.checkState(childCount == 1);
add(regexp);
}
break;
case Token.FUNCTION:
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
Preconditions.checkState(childCount == 3);
boolean funcNeedsParens = (context == Context.START_OF_EXPR);
if (funcNeedsParens) {
add("(");
}
add("function");
add(first);
add(first.getNext());
add(last, Context.PRESERVE_BLOCK);
cc.endFunction(context == Context.STATEMENT);
if (funcNeedsParens) {
add(")");
}
break;
case Token.GETTER_DEF:
case Token.SETTER_DEF:
Preconditions.checkState(n.getParent().isObjectLit());
Preconditions.checkState(childCount == 1);
Preconditions.checkState(first.isFunction());
// Get methods are unnamed
Preconditions.checkState(first.getFirstChild().getString().isEmpty());
if (type == Token.GETTER_DEF) {
// Get methods have no parameters.
Preconditions.checkState(!first.getChildAtIndex(1).hasChildren());
add("get ");
} else {
// Set methods have one parameter.
Preconditions.checkState(first.getChildAtIndex(1).hasOneChild());
add("set ");
}
// The name is on the GET or SET node.
String name = n.getString();
Node fn = first;
Node parameters = fn.getChildAtIndex(1);
Node body = fn.getLastChild();
// Add the property name.
if (!n.isQuotedString() &&
TokenStream.isJSIdentifier(name) &&
// do not encode literally any non-literal characters that were
// Unicode escaped.
NodeUtil.isLatin(name)) {
add(name);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(name);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addJsString(n);
}
}
add(parameters);
add(body, Context.PRESERVE_BLOCK);
break;
case Token.SCRIPT:
case Token.BLOCK: {
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
boolean preserveBlock = context == Context.PRESERVE_BLOCK;
if (preserveBlock) {
cc.beginBlock();
}
boolean preferLineBreaks =
type == Token.SCRIPT ||
(type == Token.BLOCK &&
!preserveBlock &&
n.getParent() != null &&
n.getParent().isScript());
for (Node c = first; c != null; c = c.getNext()) {
add(c, Context.STATEMENT);
// VAR doesn't include ';' since it gets used in expressions
if (c.isVar()) {
cc.endStatement();
}
if (c.isFunction()) {
cc.maybeLineBreak();
}
// Prefer to break lines in between top-level statements
// because top-level statements are more homogeneous.
if (preferLineBreaks) {
cc.notePreferredLineBreak();
}
}
if (preserveBlock) {
cc.endBlock(cc.breakAfterBlockFor(n, context == Context.STATEMENT));
}
break;
}
case Token.FOR:
if (childCount == 4) {
add("for(");
if (first.isVar()) {
add(first, Context.IN_FOR_INIT_CLAUSE);
} else {
addExpr(first, 0, Context.IN_FOR_INIT_CLAUSE);
}
add(";");
add(first.getNext());
add(";");
add(first.getNext().getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
Preconditions.checkState(childCount == 3);
add("for(");
add(first);
add("in");
add(first.getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
}
break;
case Token.DO:
Preconditions.checkState(childCount == 2);
add("do");
addNonEmptyStatement(first, Context.OTHER, false);
add("while(");
add(last);
add(")");
cc.endStatement();
break;
case Token.WHILE:
Preconditions.checkState(childCount == 2);
add("while(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.EMPTY:
Preconditions.checkState(childCount == 0);
break;
case Token.GETPROP: {
Preconditions.checkState(
childCount == 2,
"Bad GETPROP: expected 2 children, but got %s", childCount);
Preconditions.checkState(
last.isString(),
"Bad GETPROP: RHS should be STRING");
boolean needsParens = (first.isNumber());
if (needsParens) {
add("(");
}
addExpr(first, NodeUtil.precedence(type), context);
if (needsParens) {
add(")");
}
if (this.languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(last.getString())) {
// Check for ECMASCRIPT3 keywords.
add("[");
add(last);
add("]");
} else {
add(".");
addIdentifier(last.getString());
}
break;
}
case Token.GETELEM:
Preconditions.checkState(
childCount == 2,
"Bad GETELEM: expected 2 children but got %s", childCount);
addExpr(first, NodeUtil.precedence(type), context);
add("[");
add(first.getNext());
add("]");
break;
case Token.WITH:
Preconditions.checkState(childCount == 2);
add("with(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.INC:
case Token.DEC: {
Preconditions.checkState(childCount == 1);
String o = type == Token.INC ? "++" : "--";
int postProp = n.getIntProp(Node.INCRDECR_PROP);
// A non-zero post-prop value indicates a post inc/dec, default of zero
// is a pre-inc/dec.
if (postProp != 0) {
addExpr(first, NodeUtil.precedence(type), context);
cc.addOp(o, false);
} else {
cc.addOp(o, false);
add(first);
}
break;
}
case Token.CALL:
// We have two special cases here:
// 1) If the left hand side of the call is a direct reference to eval,
// then it must have a DIRECT_EVAL annotation. If it does not, then
// that means it was originally an indirect call to eval, and that
// indirectness must be preserved.
// 2) If the left hand side of the call is a property reference,
// then the call must not a FREE_CALL annotation. If it does, then
// that means it was originally an call without an explicit this and
// that must be preserved.
if (isIndirectEval(first)
|| n.getBooleanProp(Node.FREE_CALL) && NodeUtil.isGet(first)) {
add("(0,");
addExpr(first, NodeUtil.precedence(Token.COMMA), Context.OTHER);
add(")");
} else {
addExpr(first, NodeUtil.precedence(type), context);
}
add("(");
addList(first.getNext());
add(")");
break;
case Token.IF:
boolean hasElse = childCount == 3;
boolean ambiguousElseClause =
context == Context.BEFORE_DANGLING_ELSE && !hasElse;
if (ambiguousElseClause) {
cc.beginBlock();
}
add("if(");
add(first);
add(")");
if (hasElse) {
addNonEmptyStatement(
first.getNext(), Context.BEFORE_DANGLING_ELSE, false);
add("else");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
addNonEmptyStatement(first.getNext(), Context.OTHER, false);
Preconditions.checkState(childCount == 2);
}
if (ambiguousElseClause) {
cc.endBlock();
}
break;
case Token.NULL:
Preconditions.checkState(childCount == 0);
cc.addConstant("null");
break;
case Token.THIS:
Preconditions.checkState(childCount == 0);
add("this");
break;
case Token.FALSE:
Preconditions.checkState(childCount == 0);
cc.addConstant("false");
break;
case Token.TRUE:
Preconditions.checkState(childCount == 0);
cc.addConstant("true");
break;
case Token.CONTINUE:
Preconditions.checkState(childCount <= 1);
add("continue");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.DEBUGGER:
Preconditions.checkState(childCount == 0);
add("debugger");
cc.endStatement();
break;
case Token.BREAK:
Preconditions.checkState(childCount <= 1);
add("break");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.EXPR_RESULT:
Preconditions.checkState(childCount == 1);
add(first, Context.START_OF_EXPR);
cc.endStatement();
break;
case Token.NEW:
add("new ");
int precedence = NodeUtil.precedence(type);
// If the first child contains a CALL, then claim higher precedence
// to force parentheses. Otherwise, when parsed, NEW will bind to the
// first viable parentheses (don't traverse into functions).
if (NodeUtil.containsType(
first, Token.CALL, NodeUtil.MATCH_NOT_FUNCTION)) {
precedence = NodeUtil.precedence(first.getType()) + 1;
}
addExpr(first, precedence, Context.OTHER);
// '()' is optional when no arguments are present
Node next = first.getNext();
if (next != null) {
add("(");
addList(next);
add(")");
}
break;
case Token.STRING_KEY:
Preconditions.checkState(
childCount == 1, "Object lit key must have 1 child");
addJsString(n);
break;
case Token.STRING:
Preconditions.checkState(
childCount == 0, "A string may not have children");
addJsString(n);
break;
case Token.DELPROP:
Preconditions.checkState(childCount == 1);
add("delete ");
add(first);
break;
case Token.OBJECTLIT: {
boolean needsParens = (context == Context.START_OF_EXPR);
if (needsParens) {
add("(");
}
add("{");
for (Node c = first; c != null; c = c.getNext()) {
if (c != first) {
cc.listSeparator();
}
if (c.isGetterDef() || c.isSetterDef()) {
add(c);
} else {
Preconditions.checkState(c.isStringKey());
String key = c.getString();
// Object literal property names don't have to be quoted if they
// are not JavaScript keywords
if (!c.isQuotedString()
&& !(languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(key))
&& TokenStream.isJSIdentifier(key)
// do not encode literally any non-literal characters that
// were Unicode escaped.
&& NodeUtil.isLatin(key)) {
add(key);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(key);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addExpr(c, 1, Context.OTHER);
}
}
add(":");
addExpr(c.getFirstChild(), 1, Context.OTHER);
}
}
add("}");
if (needsParens) {
add(")");
}
break;
}
case Token.SWITCH:
add("switch(");
add(first);
add(")");
cc.beginBlock();
addAllSiblings(first.getNext());
cc.endBlock(context == Context.STATEMENT);
break;
case Token.CASE:
Preconditions.checkState(childCount == 2);
add("case ");
add(first);
addCaseBody(last);
break;
case Token.DEFAULT_CASE:
Preconditions.checkState(childCount == 1);
add("default");
addCaseBody(first);
break;
case Token.LABEL:
Preconditions.checkState(childCount == 2);
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(first);
add(":");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), true);
break;
case Token.CAST:
add("(");
add(first);
add(")");
break;
default:
throw new Error("Unknown type " + type + "\n" + n.toStringTree());
}
cc.endSourceMapping(n);
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void add(Node n, Context context) {
if (!cc.continueProcessing()) {
return;
}
int type = n.getType();
String opstr = NodeUtil.opToStr(type);
int childCount = n.getChildCount();
Node first = n.getFirstChild();
Node last = n.getLastChild();
// Handle all binary operators
if (opstr != null && first != last) {
Preconditions.checkState(
childCount == 2,
"Bad binary operator \"%s\": expected 2 arguments but got %s",
opstr, childCount);
int p = NodeUtil.precedence(type);
// For right-hand-side of operations, only pass context if it's
// the IN_FOR_INIT_CLAUSE one.
Context rhsContext = getContextForNoInOperator(context);
// Handle associativity.
// e.g. if the parse tree is a * (b * c),
// we can simply generate a * b * c.
if (last.getType() == type &&
NodeUtil.isAssociative(type)) {
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else if (NodeUtil.isAssignmentOp(n) && NodeUtil.isAssignmentOp(last)) {
// Assignments are the only right-associative binary operators
addExpr(first, p, context);
cc.addOp(opstr, true);
addExpr(last, p, rhsContext);
} else {
unrollBinaryOperator(n, type, opstr, context, rhsContext, p, p + 1);
}
return;
}
cc.startSourceMapping(n);
switch (type) {
case Token.TRY: {
Preconditions.checkState(first.getNext().isBlock() &&
!first.getNext().hasMoreThanOneChild());
Preconditions.checkState(childCount >= 2 && childCount <= 3);
add("try");
add(first, Context.PRESERVE_BLOCK);
// second child contains the catch block, or nothing if there
// isn't a catch block
Node catchblock = first.getNext().getFirstChild();
if (catchblock != null) {
add(catchblock);
}
if (childCount == 3) {
add("finally");
add(last, Context.PRESERVE_BLOCK);
}
break;
}
case Token.CATCH:
Preconditions.checkState(childCount == 2);
add("catch(");
add(first);
add(")");
add(last, Context.PRESERVE_BLOCK);
break;
case Token.THROW:
Preconditions.checkState(childCount == 1);
add("throw");
add(first);
// Must have a ';' after a throw statement, otherwise safari can't
// parse this.
cc.endStatement(true);
break;
case Token.RETURN:
add("return");
if (childCount == 1) {
add(first);
} else {
Preconditions.checkState(childCount == 0);
}
cc.endStatement();
break;
case Token.VAR:
if (first != null) {
add("var ");
addList(first, false, getContextForNoInOperator(context));
}
break;
case Token.LABEL_NAME:
Preconditions.checkState(!n.getString().isEmpty());
addIdentifier(n.getString());
break;
case Token.NAME:
if (first == null || first.isEmpty()) {
addIdentifier(n.getString());
} else {
Preconditions.checkState(childCount == 1);
addIdentifier(n.getString());
cc.addOp("=", true);
if (first.isComma()) {
addExpr(first, NodeUtil.precedence(Token.ASSIGN), Context.OTHER);
} else {
// Add expression, consider nearby code at lowest level of
// precedence.
addExpr(first, 0, getContextForNoInOperator(context));
}
}
break;
case Token.ARRAYLIT:
add("[");
addArrayList(first);
add("]");
break;
case Token.PARAM_LIST:
add("(");
addList(first);
add(")");
break;
case Token.COMMA:
Preconditions.checkState(childCount == 2);
unrollBinaryOperator(n, Token.COMMA, ",", context,
getContextForNoInOperator(context), 0, 0);
break;
case Token.NUMBER:
Preconditions.checkState(childCount == 0);
cc.addNumber(n.getDouble());
break;
case Token.TYPEOF:
case Token.VOID:
case Token.NOT:
case Token.BITNOT:
case Token.POS: {
// All of these unary operators are right-associative
Preconditions.checkState(childCount == 1);
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
break;
}
case Token.NEG: {
Preconditions.checkState(childCount == 1);
// It's important to our sanity checker that the code
// we print produces the same AST as the code we parse back.
// NEG is a weird case because Rhino parses "- -2" as "2".
if (n.getFirstChild().isNumber()) {
cc.addNumber(-n.getFirstChild().getDouble());
} else {
cc.addOp(NodeUtil.opToStrNoFail(type), false);
addExpr(first, NodeUtil.precedence(type), Context.OTHER);
}
break;
}
case Token.HOOK: {
Preconditions.checkState(childCount == 3);
int p = NodeUtil.precedence(type);
Context rhsContext = Context.OTHER;
addExpr(first, p + 1, context);
cc.addOp("?", true);
addExpr(first.getNext(), 1, rhsContext);
cc.addOp(":", true);
addExpr(last, 1, rhsContext);
break;
}
case Token.REGEXP:
if (!first.isString() ||
!last.isString()) {
throw new Error("Expected children to be strings");
}
String regexp = regexpEscape(first.getString(), outputCharsetEncoder);
// I only use one .add because whitespace matters
if (childCount == 2) {
add(regexp + last.getString());
} else {
Preconditions.checkState(childCount == 1);
add(regexp);
}
break;
case Token.FUNCTION:
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
Preconditions.checkState(childCount == 3);
boolean funcNeedsParens = (context == Context.START_OF_EXPR);
if (funcNeedsParens) {
add("(");
}
add("function");
add(first);
add(first.getNext());
add(last, Context.PRESERVE_BLOCK);
cc.endFunction(context == Context.STATEMENT);
if (funcNeedsParens) {
add(")");
}
break;
case Token.GETTER_DEF:
case Token.SETTER_DEF:
Preconditions.checkState(n.getParent().isObjectLit());
Preconditions.checkState(childCount == 1);
Preconditions.checkState(first.isFunction());
// Get methods are unnamed
Preconditions.checkState(first.getFirstChild().getString().isEmpty());
if (type == Token.GETTER_DEF) {
// Get methods have no parameters.
Preconditions.checkState(!first.getChildAtIndex(1).hasChildren());
add("get ");
} else {
// Set methods have one parameter.
Preconditions.checkState(first.getChildAtIndex(1).hasOneChild());
add("set ");
}
// The name is on the GET or SET node.
String name = n.getString();
Node fn = first;
Node parameters = fn.getChildAtIndex(1);
Node body = fn.getLastChild();
// Add the property name.
if (!n.isQuotedString() &&
TokenStream.isJSIdentifier(name) &&
// do not encode literally any non-literal characters that were
// Unicode escaped.
NodeUtil.isLatin(name)) {
add(name);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(name);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addJsString(n);
}
}
add(parameters);
add(body, Context.PRESERVE_BLOCK);
break;
case Token.SCRIPT:
case Token.BLOCK: {
if (n.getClass() != Node.class) {
throw new Error("Unexpected Node subclass.");
}
boolean preserveBlock = context == Context.PRESERVE_BLOCK;
if (preserveBlock) {
cc.beginBlock();
}
boolean preferLineBreaks =
type == Token.SCRIPT ||
(type == Token.BLOCK &&
!preserveBlock &&
n.getParent() != null &&
n.getParent().isScript());
for (Node c = first; c != null; c = c.getNext()) {
add(c, Context.STATEMENT);
// VAR doesn't include ';' since it gets used in expressions
if (c.isVar()) {
cc.endStatement();
}
if (c.isFunction()) {
cc.maybeLineBreak();
}
// Prefer to break lines in between top-level statements
// because top-level statements are more homogeneous.
if (preferLineBreaks) {
cc.notePreferredLineBreak();
}
}
if (preserveBlock) {
cc.endBlock(cc.breakAfterBlockFor(n, context == Context.STATEMENT));
}
break;
}
case Token.FOR:
if (childCount == 4) {
add("for(");
if (first.isVar()) {
add(first, Context.IN_FOR_INIT_CLAUSE);
} else {
addExpr(first, 0, Context.IN_FOR_INIT_CLAUSE);
}
add(";");
add(first.getNext());
add(";");
add(first.getNext().getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
Preconditions.checkState(childCount == 3);
add("for(");
add(first);
add("in");
add(first.getNext());
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
}
break;
case Token.DO:
Preconditions.checkState(childCount == 2);
add("do");
addNonEmptyStatement(first, Context.OTHER, false);
add("while(");
add(last);
add(")");
cc.endStatement();
break;
case Token.WHILE:
Preconditions.checkState(childCount == 2);
add("while(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.EMPTY:
Preconditions.checkState(childCount == 0);
break;
case Token.GETPROP: {
Preconditions.checkState(
childCount == 2,
"Bad GETPROP: expected 2 children, but got %s", childCount);
Preconditions.checkState(
last.isString(),
"Bad GETPROP: RHS should be STRING");
boolean needsParens = (first.isNumber());
if (needsParens) {
add("(");
}
addExpr(first, NodeUtil.precedence(type), context);
if (needsParens) {
add(")");
}
if (this.languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(last.getString())) {
// Check for ECMASCRIPT3 keywords.
add("[");
add(last);
add("]");
} else {
add(".");
addIdentifier(last.getString());
}
break;
}
case Token.GETELEM:
Preconditions.checkState(
childCount == 2,
"Bad GETELEM: expected 2 children but got %s", childCount);
addExpr(first, NodeUtil.precedence(type), context);
add("[");
add(first.getNext());
add("]");
break;
case Token.WITH:
Preconditions.checkState(childCount == 2);
add("with(");
add(first);
add(")");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
break;
case Token.INC:
case Token.DEC: {
Preconditions.checkState(childCount == 1);
String o = type == Token.INC ? "++" : "--";
int postProp = n.getIntProp(Node.INCRDECR_PROP);
// A non-zero post-prop value indicates a post inc/dec, default of zero
// is a pre-inc/dec.
if (postProp != 0) {
addExpr(first, NodeUtil.precedence(type), context);
cc.addOp(o, false);
} else {
cc.addOp(o, false);
add(first);
}
break;
}
case Token.CALL:
// We have two special cases here:
// 1) If the left hand side of the call is a direct reference to eval,
// then it must have a DIRECT_EVAL annotation. If it does not, then
// that means it was originally an indirect call to eval, and that
// indirectness must be preserved.
// 2) If the left hand side of the call is a property reference,
// then the call must not a FREE_CALL annotation. If it does, then
// that means it was originally an call without an explicit this and
// that must be preserved.
if (isIndirectEval(first)
|| n.getBooleanProp(Node.FREE_CALL) && NodeUtil.isGet(first)) {
add("(0,");
addExpr(first, NodeUtil.precedence(Token.COMMA), Context.OTHER);
add(")");
} else {
addExpr(first, NodeUtil.precedence(type), context);
}
add("(");
addList(first.getNext());
add(")");
break;
case Token.IF:
boolean hasElse = childCount == 3;
boolean ambiguousElseClause =
context == Context.BEFORE_DANGLING_ELSE && !hasElse;
if (ambiguousElseClause) {
cc.beginBlock();
}
add("if(");
add(first);
add(")");
if (hasElse) {
addNonEmptyStatement(
first.getNext(), Context.BEFORE_DANGLING_ELSE, false);
add("else");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), false);
} else {
addNonEmptyStatement(first.getNext(), Context.OTHER, false);
Preconditions.checkState(childCount == 2);
}
if (ambiguousElseClause) {
cc.endBlock();
}
break;
case Token.NULL:
Preconditions.checkState(childCount == 0);
cc.addConstant("null");
break;
case Token.THIS:
Preconditions.checkState(childCount == 0);
add("this");
break;
case Token.FALSE:
Preconditions.checkState(childCount == 0);
cc.addConstant("false");
break;
case Token.TRUE:
Preconditions.checkState(childCount == 0);
cc.addConstant("true");
break;
case Token.CONTINUE:
Preconditions.checkState(childCount <= 1);
add("continue");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.DEBUGGER:
Preconditions.checkState(childCount == 0);
add("debugger");
cc.endStatement();
break;
case Token.BREAK:
Preconditions.checkState(childCount <= 1);
add("break");
if (childCount == 1) {
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(" ");
add(first);
}
cc.endStatement();
break;
case Token.EXPR_RESULT:
Preconditions.checkState(childCount == 1);
add(first, Context.START_OF_EXPR);
cc.endStatement();
break;
case Token.NEW:
add("new ");
int precedence = NodeUtil.precedence(type);
// If the first child contains a CALL, then claim higher precedence
// to force parentheses. Otherwise, when parsed, NEW will bind to the
// first viable parentheses (don't traverse into functions).
if (NodeUtil.containsType(
first, Token.CALL, NodeUtil.MATCH_NOT_FUNCTION)) {
precedence = NodeUtil.precedence(first.getType()) + 1;
}
addExpr(first, precedence, Context.OTHER);
// '()' is optional when no arguments are present
Node next = first.getNext();
if (next != null) {
add("(");
addList(next);
add(")");
}
break;
case Token.STRING_KEY:
Preconditions.checkState(
childCount == 1, "Object lit key must have 1 child");
addJsString(n);
break;
case Token.STRING:
Preconditions.checkState(
childCount == 0, "A string may not have children");
addJsString(n);
break;
case Token.DELPROP:
Preconditions.checkState(childCount == 1);
add("delete ");
add(first);
break;
case Token.OBJECTLIT: {
boolean needsParens = (context == Context.START_OF_EXPR);
if (needsParens) {
add("(");
}
add("{");
for (Node c = first; c != null; c = c.getNext()) {
if (c != first) {
cc.listSeparator();
}
if (c.isGetterDef() || c.isSetterDef()) {
add(c);
} else {
Preconditions.checkState(c.isStringKey());
String key = c.getString();
// Object literal property names don't have to be quoted if they
// are not JavaScript keywords
if (!c.isQuotedString()
&& !(languageMode == LanguageMode.ECMASCRIPT3
&& TokenStream.isKeyword(key))
&& TokenStream.isJSIdentifier(key)
// do not encode literally any non-literal characters that
// were Unicode escaped.
&& NodeUtil.isLatin(key)) {
add(key);
} else {
// Determine if the string is a simple number.
double d = getSimpleNumber(key);
if (!Double.isNaN(d)) {
cc.addNumber(d);
} else {
addExpr(c, 1, Context.OTHER);
}
}
add(":");
addExpr(c.getFirstChild(), 1, Context.OTHER);
}
}
add("}");
if (needsParens) {
add(")");
}
break;
}
case Token.SWITCH:
add("switch(");
add(first);
add(")");
cc.beginBlock();
addAllSiblings(first.getNext());
cc.endBlock(context == Context.STATEMENT);
break;
case Token.CASE:
Preconditions.checkState(childCount == 2);
add("case ");
add(first);
addCaseBody(last);
break;
case Token.DEFAULT_CASE:
Preconditions.checkState(childCount == 1);
add("default");
addCaseBody(first);
break;
case Token.LABEL:
Preconditions.checkState(childCount == 2);
if (!first.isLabelName()) {
throw new Error("Unexpected token type. Should be LABEL_NAME.");
}
add(first);
add(":");
addNonEmptyStatement(
last, getContextForNonEmptyExpression(context), true);
break;
case Token.CAST:
add("(");
add(first);
add(")");
break;
default:
throw new Error("Unknown type " + type + "\n" + n.toStringTree());
}
cc.endSourceMapping(n);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | 138f73c1a4092c3b35e8b66203ad0562f616282cd747dfe3fd5401470db4895c | public Object answer(InvocationOnMock invocation) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/* (non-Javadoc)
* @see org.mockito.stubbing.Answer#answer(org.mockito.invocation.InvocationOnMock)
*/
public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
}
```
| public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/* (non-Javadoc)
* @see org.mockito.stubbing.Answer#answer(org.mockito.invocation.InvocationOnMock)
*/
public Object answer(InvocationOnMock invocation) {
if (methodsGuru.isToString(invocation.getMethod())) {
Object mock = invocation.getMock();
MockName name = mockUtil.getMockName(mock);
if (name.isDefault()) {
return "Mock for " + mockUtil.getMockSettings(mock).getTypeToMock().getSimpleName() + ", hashCode: " + mock.hashCode();
} else {
return name.toString();
}
} else if (methodsGuru.isCompareToMethod(invocation.getMethod())) {
//see issue 184.
//mocks by default should return 0 if references are the same, otherwise some other value because they are not the same. Hence we return 1 (anything but 0 is good).
//Only for compareTo() method by the Comparable interface
return 1;
}
Class<?> returnType = invocation.getMethod().getReturnType();
return returnValueFor(returnType);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
96 | 13b2c3137391f239784ce491bfc6e329f42251e19442ecd696d5b08ab6af7768 | private void visitParameterList(NodeTraversal t, Node call,
FunctionType functionType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Visits the parameters of a CALL or a NEW node.
*/
private void visitParameterList(NodeTraversal t, Node call,
FunctionType functionType) {
Iterator<Node> arguments = call.children().iterator();
arguments.next(); // skip the function name
Iterator<Node> parameters = functionType.getParameters().iterator();
int ordinal = 0;
Node parameter = null;
Node argument = null;
while (arguments.hasNext() &&
(parameters.hasNext() ||
parameter != null && parameter.isVarArgs())) {
// If there are no parameters left in the list, then the while loop
// above implies that this must be a var_args function.
if (parameters.hasNext()) {
parameter = parameters.next();
}
argument = arguments.next();
ordinal++;
validator.expectArgumentMatchesParameter(t, argument,
getJSType(argument), getJSType(parameter), call, ordinal);
}
int numArgs = call.getChildCount() - 1;
int minArgs = functionType.getMinArguments();
int maxArgs = functionType.getMaxArguments();
if (minArgs > numArgs || maxArgs < numArgs) {
report(t, call, WRONG_ARGUMENT_COUNT,
validator.getReadableJSTypeName(call.getFirstChild(), false),
String.valueOf(numArgs), String.valueOf(minArgs),
maxArgs != Integer.MAX_VALUE ?
" and no more than " + maxArgs + " argument(s)" : "");
}
}
```
| private void visitParameterList(NodeTraversal t, Node call,
FunctionType functionType) {
Iterator<Node> arguments = call.children().iterator();
arguments.next(); // skip the function name
Iterator<Node> parameters = functionType.getParameters().iterator();
int ordinal = 0;
Node parameter = null;
Node argument = null;
while (arguments.hasNext() &&
(parameters.hasNext() ||
parameter != null && parameter.isVarArgs())) {
// If there are no parameters left in the list, then the while loop
// above implies that this must be a var_args function.
if (parameters.hasNext()) {
parameter = parameters.next();
}
argument = arguments.next();
ordinal++;
validator.expectArgumentMatchesParameter(t, argument,
getJSType(argument), getJSType(parameter), call, ordinal);
}
int numArgs = call.getChildCount() - 1;
int minArgs = functionType.getMinArguments();
int maxArgs = functionType.getMaxArguments();
if (minArgs > numArgs || maxArgs < numArgs) {
report(t, call, WRONG_ARGUMENT_COUNT,
validator.getReadableJSTypeName(call.getFirstChild(), false),
String.valueOf(numArgs), String.valueOf(minArgs),
maxArgs != Integer.MAX_VALUE ?
" and no more than " + maxArgs + " argument(s)" : "");
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Visits the parameters of a CALL or a NEW node.
*/
private void visitParameterList(NodeTraversal t, Node call,
FunctionType functionType) {
Iterator<Node> arguments = call.children().iterator();
arguments.next(); // skip the function name
Iterator<Node> parameters = functionType.getParameters().iterator();
int ordinal = 0;
Node parameter = null;
Node argument = null;
while (arguments.hasNext() &&
(parameters.hasNext() ||
parameter != null && parameter.isVarArgs())) {
// If there are no parameters left in the list, then the while loop
// above implies that this must be a var_args function.
if (parameters.hasNext()) {
parameter = parameters.next();
}
argument = arguments.next();
ordinal++;
validator.expectArgumentMatchesParameter(t, argument,
getJSType(argument), getJSType(parameter), call, ordinal);
}
int numArgs = call.getChildCount() - 1;
int minArgs = functionType.getMinArguments();
int maxArgs = functionType.getMaxArguments();
if (minArgs > numArgs || maxArgs < numArgs) {
report(t, call, WRONG_ARGUMENT_COUNT,
validator.getReadableJSTypeName(call.getFirstChild(), false),
String.valueOf(numArgs), String.valueOf(minArgs),
maxArgs != Integer.MAX_VALUE ?
" and no more than " + maxArgs + " argument(s)" : "");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 13bfbf1a895e815da4c1c2e9ee450558c654e245a7185b85a512ba5653547d1d | public static boolean equal(GeneralPath p1, GeneralPath p2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Tests two polygons for equality. If both are <code>null</code> this
* method returns <code>true</code>.
*
* @param p1 path 1 (<code>null</code> permitted).
* @param p2 path 2 (<code>null</code> permitted).
*
* @return A boolean.
*/
public static boolean equal(GeneralPath p1, GeneralPath p2) {
if (p1 == null) {
return (p2 == null);
}
if (p2 == null) {
return false;
}
if (p1.getWindingRule() != p2.getWindingRule()) {
return false;
}
PathIterator iterator1 = p1.getPathIterator(null);
PathIterator iterator2 = p1.getPathIterator(null);
double[] d1 = new double[6];
double[] d2 = new double[6];
boolean done = iterator1.isDone() && iterator2.isDone();
while (!done) {
if (iterator1.isDone() != iterator2.isDone()) {
return false;
}
int seg1 = iterator1.currentSegment(d1);
int seg2 = iterator2.currentSegment(d2);
if (seg1 != seg2) {
return false;
}
if (!Arrays.equals(d1, d2)) {
return false;
}
iterator1.next();
iterator2.next();
done = iterator1.isDone() && iterator2.isDone();
}
return true;
}
```
| public static boolean equal(GeneralPath p1, GeneralPath p2) {
if (p1 == null) {
return (p2 == null);
}
if (p2 == null) {
return false;
}
if (p1.getWindingRule() != p2.getWindingRule()) {
return false;
}
PathIterator iterator1 = p1.getPathIterator(null);
PathIterator iterator2 = p1.getPathIterator(null);
double[] d1 = new double[6];
double[] d2 = new double[6];
boolean done = iterator1.isDone() && iterator2.isDone();
while (!done) {
if (iterator1.isDone() != iterator2.isDone()) {
return false;
}
int seg1 = iterator1.currentSegment(d1);
int seg2 = iterator2.currentSegment(d2);
if (seg1 != seg2) {
return false;
}
if (!Arrays.equals(d1, d2)) {
return false;
}
iterator1.next();
iterator2.next();
done = iterator1.isDone() && iterator2.isDone();
}
return true;
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Tests two polygons for equality. If both are <code>null</code> this
* method returns <code>true</code>.
*
* @param p1 path 1 (<code>null</code> permitted).
* @param p2 path 2 (<code>null</code> permitted).
*
* @return A boolean.
*/
public static boolean equal(GeneralPath p1, GeneralPath p2) {
if (p1 == null) {
return (p2 == null);
}
if (p2 == null) {
return false;
}
if (p1.getWindingRule() != p2.getWindingRule()) {
return false;
}
PathIterator iterator1 = p1.getPathIterator(null);
PathIterator iterator2 = p1.getPathIterator(null);
double[] d1 = new double[6];
double[] d2 = new double[6];
boolean done = iterator1.isDone() && iterator2.isDone();
while (!done) {
if (iterator1.isDone() != iterator2.isDone()) {
return false;
}
int seg1 = iterator1.currentSegment(d1);
int seg2 = iterator2.currentSegment(d2);
if (seg1 != seg2) {
return false;
}
if (!Arrays.equals(d1, d2)) {
return false;
}
iterator1.next();
iterator2.next();
done = iterator1.isDone() && iterator2.isDone();
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
15 | 13cf5fbeaf57e25541d9033d27ffca9c891c93a51b26e61773076a2318f543ce | @Override
public boolean apply(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
}
```
| @Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean apply(Node n) {
// When the node is null it means, we reached the implicit return
// where the function returns (possibly without an return statement)
if (n == null) {
return false;
}
// TODO(user): We only care about calls to functions that
// passes one of the dependent variable to a non-side-effect free
// function.
if (n.isCall() && NodeUtil.functionCallHasSideEffects(n)) {
return true;
}
if (n.isNew() && NodeUtil.constructorCallHasSideEffects(n)) {
return true;
}
for (Node c = n.getFirstChild(); c != null; c = c.getNext()) {
if (!ControlFlowGraph.isEnteringNewCfgNode(c) && apply(c)) {
return true;
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | 13eb3aa8a93ed194d8677b150654397440a7070025f089a2b261e4e71ad59218 | public boolean hasClass(String className) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// performance sensitive
/**
* Tests if this element has a class. Case insensitive.
* @param className name of class to check for
* @return true if it does, false if not
*/
public boolean hasClass(String className) {
final String classAttr = attributes.getIgnoreCase("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
}
```
| public boolean hasClass(String className) {
final String classAttr = attributes.getIgnoreCase("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// performance sensitive
/**
* Tests if this element has a class. Case insensitive.
* @param className name of class to check for
* @return true if it does, false if not
*/
public boolean hasClass(String className) {
final String classAttr = attributes.getIgnoreCase("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 148054c2d8b6c922f0ca1a6c82cc4b6c5c2d82642fb722152f6aa7f476e14609 | public long adjustOffset(long instant, boolean earlierOrLater) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Adjusts the offset to be the earlier or later one during an overlap.
*
* @param instant the instant to adjust
* @param earlierOrLater false for earlier, true for later
* @return the adjusted instant millis
*/
public long adjustOffset(long instant, boolean earlierOrLater) {
// a bit messy, but will work in all non-pathological cases
// evaluate 3 hours before and after to work out if anything is happening
long instantBefore = instant - 3 * DateTimeConstants.MILLIS_PER_HOUR;
long instantAfter = instant + 3 * DateTimeConstants.MILLIS_PER_HOUR;
long offsetBefore = getOffset(instantBefore);
long offsetAfter = getOffset(instantAfter);
if (offsetBefore <= offsetAfter) {
return instant; // not an overlap (less than is a gap, equal is normal case)
}
// work out range of instants that have duplicate local times
long diff = offsetBefore - offsetAfter;
long transition = nextTransition(instantBefore);
long overlapStart = transition - diff;
long overlapEnd = transition + diff;
if (instant < overlapStart || instant >= overlapEnd) {
return instant; // not an overlap
}
// calculate result
long afterStart = instant - overlapStart;
if (afterStart >= diff) {
// currently in later offset
return earlierOrLater ? instant : instant - diff;
} else {
// currently in earlier offset
return earlierOrLater ? instant + diff : instant;
}
}
```
| public long adjustOffset(long instant, boolean earlierOrLater) {
// a bit messy, but will work in all non-pathological cases
// evaluate 3 hours before and after to work out if anything is happening
long instantBefore = instant - 3 * DateTimeConstants.MILLIS_PER_HOUR;
long instantAfter = instant + 3 * DateTimeConstants.MILLIS_PER_HOUR;
long offsetBefore = getOffset(instantBefore);
long offsetAfter = getOffset(instantAfter);
if (offsetBefore <= offsetAfter) {
return instant; // not an overlap (less than is a gap, equal is normal case)
}
// work out range of instants that have duplicate local times
long diff = offsetBefore - offsetAfter;
long transition = nextTransition(instantBefore);
long overlapStart = transition - diff;
long overlapEnd = transition + diff;
if (instant < overlapStart || instant >= overlapEnd) {
return instant; // not an overlap
}
// calculate result
long afterStart = instant - overlapStart;
if (afterStart >= diff) {
// currently in later offset
return earlierOrLater ? instant : instant - diff;
} else {
// currently in earlier offset
return earlierOrLater ? instant + diff : instant;
}
} | false | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Adjusts the offset to be the earlier or later one during an overlap.
*
* @param instant the instant to adjust
* @param earlierOrLater false for earlier, true for later
* @return the adjusted instant millis
*/
public long adjustOffset(long instant, boolean earlierOrLater) {
// a bit messy, but will work in all non-pathological cases
// evaluate 3 hours before and after to work out if anything is happening
long instantBefore = instant - 3 * DateTimeConstants.MILLIS_PER_HOUR;
long instantAfter = instant + 3 * DateTimeConstants.MILLIS_PER_HOUR;
long offsetBefore = getOffset(instantBefore);
long offsetAfter = getOffset(instantAfter);
if (offsetBefore <= offsetAfter) {
return instant; // not an overlap (less than is a gap, equal is normal case)
}
// work out range of instants that have duplicate local times
long diff = offsetBefore - offsetAfter;
long transition = nextTransition(instantBefore);
long overlapStart = transition - diff;
long overlapEnd = transition + diff;
if (instant < overlapStart || instant >= overlapEnd) {
return instant; // not an overlap
}
// calculate result
long afterStart = instant - overlapStart;
if (afterStart >= diff) {
// currently in later offset
return earlierOrLater ? instant : instant - diff;
} else {
// currently in earlier offset
return earlierOrLater ? instant + diff : instant;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
67 | 1480c1582c675ea8eaaf18f43e49b8450b77b5c5b0c7d4522bcb945603fb427c | @Override
public KeyDeserializer createKeyDeserializer(DeserializationContext ctxt,
JavaType type)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* JsonDeserializerFactory impl (partial): key deserializers
/**********************************************************
*/
@Override
public KeyDeserializer createKeyDeserializer(DeserializationContext ctxt,
JavaType type)
throws JsonMappingException
{
final DeserializationConfig config = ctxt.getConfig();
KeyDeserializer deser = null;
if (_factoryConfig.hasKeyDeserializers()) {
BeanDescription beanDesc = config.introspectClassAnnotations(type.getRawClass());
for (KeyDeserializers d : _factoryConfig.keyDeserializers()) {
deser = d.findKeyDeserializer(type, config, beanDesc);
if (deser != null) {
break;
}
}
}
// the only non-standard thing is this:
if (deser == null) {
if (type.isEnumType()) {
deser = _createEnumKeyDeserializer(ctxt, type);
} else {
deser = StdKeyDeserializers.findStringBasedKeyDeserializer(config, type);
}
}
// and then post-processing
if (deser != null) {
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
deser = mod.modifyKeyDeserializer(config, type, deser);
}
}
}
return deser;
}
```
| @Override
public KeyDeserializer createKeyDeserializer(DeserializationContext ctxt,
JavaType type)
throws JsonMappingException
{
final DeserializationConfig config = ctxt.getConfig();
KeyDeserializer deser = null;
if (_factoryConfig.hasKeyDeserializers()) {
BeanDescription beanDesc = config.introspectClassAnnotations(type.getRawClass());
for (KeyDeserializers d : _factoryConfig.keyDeserializers()) {
deser = d.findKeyDeserializer(type, config, beanDesc);
if (deser != null) {
break;
}
}
}
// the only non-standard thing is this:
if (deser == null) {
if (type.isEnumType()) {
deser = _createEnumKeyDeserializer(ctxt, type);
} else {
deser = StdKeyDeserializers.findStringBasedKeyDeserializer(config, type);
}
}
// and then post-processing
if (deser != null) {
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
deser = mod.modifyKeyDeserializer(config, type, deser);
}
}
}
return deser;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* JsonDeserializerFactory impl (partial): key deserializers
/**********************************************************
*/
@Override
public KeyDeserializer createKeyDeserializer(DeserializationContext ctxt,
JavaType type)
throws JsonMappingException
{
final DeserializationConfig config = ctxt.getConfig();
KeyDeserializer deser = null;
if (_factoryConfig.hasKeyDeserializers()) {
BeanDescription beanDesc = config.introspectClassAnnotations(type.getRawClass());
for (KeyDeserializers d : _factoryConfig.keyDeserializers()) {
deser = d.findKeyDeserializer(type, config, beanDesc);
if (deser != null) {
break;
}
}
}
// the only non-standard thing is this:
if (deser == null) {
if (type.isEnumType()) {
deser = _createEnumKeyDeserializer(ctxt, type);
} else {
deser = StdKeyDeserializers.findStringBasedKeyDeserializer(config, type);
}
}
// and then post-processing
if (deser != null) {
if (_factoryConfig.hasDeserializerModifiers()) {
for (BeanDeserializerModifier mod : _factoryConfig.deserializerModifiers()) {
deser = mod.modifyKeyDeserializer(config, type, deser);
}
}
}
return deser;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
57 | 148a1b6360a4e0dd578a453b85655c1126fb5d9a27ab7144d13f44acaf90b5b3 | public static boolean isAvailableLocale(Locale locale) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Checks if the locale specified is in the list of available locales.</p>
*
* @param locale the Locale object to check if it is available
* @return true if the locale is a known locale
*/
//-----------------------------------------------------------------------
public static boolean isAvailableLocale(Locale locale) {
return cAvailableLocaleSet.contains(locale);
}
```
| public static boolean isAvailableLocale(Locale locale) {
return cAvailableLocaleSet.contains(locale);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Checks if the locale specified is in the list of available locales.</p>
*
* @param locale the Locale object to check if it is available
* @return true if the locale is a known locale
*/
//-----------------------------------------------------------------------
public static boolean isAvailableLocale(Locale locale) {
return cAvailableLocaleSet.contains(locale);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
54 | 149b0db74fa1513b6e538a78e44eeac266b9d37d8ffd0c3fd2a4e5d969e97f74 | private void copyAttributes(org.jsoup.nodes.Node source, Element el) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void copyAttributes(org.jsoup.nodes.Node source, Element el) {
for (Attribute attribute : source.attributes()) {
// valid xml attribute names are: ^[a-zA-Z_:][-a-zA-Z0-9_:.]
String key = attribute.getKey().replaceAll("[^-a-zA-Z0-9_:.]", "");
if (key.matches("[a-zA-Z_:]{1}[-a-zA-Z0-9_:.]*"))
el.setAttribute(key, attribute.getValue());
}
}
```
| private void copyAttributes(org.jsoup.nodes.Node source, Element el) {
for (Attribute attribute : source.attributes()) {
// valid xml attribute names are: ^[a-zA-Z_:][-a-zA-Z0-9_:.]
String key = attribute.getKey().replaceAll("[^-a-zA-Z0-9_:.]", "");
if (key.matches("[a-zA-Z_:]{1}[-a-zA-Z0-9_:.]*"))
el.setAttribute(key, attribute.getValue());
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void copyAttributes(org.jsoup.nodes.Node source, Element el) {
for (Attribute attribute : source.attributes()) {
// valid xml attribute names are: ^[a-zA-Z_:][-a-zA-Z0-9_:.]
String key = attribute.getKey().replaceAll("[^-a-zA-Z0-9_:.]", "");
if (key.matches("[a-zA-Z_:]{1}[-a-zA-Z0-9_:.]*"))
el.setAttribute(key, attribute.getValue());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
109 | 14c8709814bc0e8e4999aeb49d5419be2aa50b4eeec5a77e43a6cc4aa92e9e37 | private Node parseContextTypeExpression(JsDocToken token) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* ContextTypeExpression := BasicTypeExpression | '?'
* For expressions on the right hand side of a this: or new:
*/
private Node parseContextTypeExpression(JsDocToken token) {
if (token == JsDocToken.QMARK) {
return newNode(Token.QMARK);
} else {
return parseBasicTypeExpression(token);
}
}
```
| private Node parseContextTypeExpression(JsDocToken token) {
if (token == JsDocToken.QMARK) {
return newNode(Token.QMARK);
} else {
return parseBasicTypeExpression(token);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* ContextTypeExpression := BasicTypeExpression | '?'
* For expressions on the right hand side of a this: or new:
*/
private Node parseContextTypeExpression(JsDocToken token) {
if (token == JsDocToken.QMARK) {
return newNode(Token.QMARK);
} else {
return parseBasicTypeExpression(token);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 1507b71fb0763f20c5ef973e913c5c49f3b8c78b02a7b16b92a9be1edfc814e4 | public void close() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Closes the CPIO output stream as well as the stream being filtered.
*
* @throws IOException
* if an I/O error has occurred or if a CPIO file error has
* occurred
*/
public void close() throws IOException {
if (!this.closed) {
this.finish();
super.close();
this.closed = true;
}
}
```
| public void close() throws IOException {
if (!this.closed) {
this.finish();
super.close();
this.closed = true;
}
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Closes the CPIO output stream as well as the stream being filtered.
*
* @throws IOException
* if an I/O error has occurred or if a CPIO file error has
* occurred
*/
public void close() throws IOException {
if (!this.closed) {
this.finish();
super.close();
this.closed = true;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
60 | 1520d79277f57c778a6be4a1a850b24190eac1f459d3c92f7235fbc7b7c0300d | public double cumulativeProbability(double x) throws MathException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* For this distribution, {@code X}, this method returns {@code P(X < x)}.
* If {@code x}is more than 40 standard deviations from the mean, 0 or 1 is returned,
* as in these cases the actual value is within {@code Double.MIN_VALUE} of 0 or 1.
*
* @param x Value at which the CDF is evaluated.
* @return CDF evaluated at {@code x}.
* @throws MathException if the algorithm fails to converge
*/
public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
if (FastMath.abs(dev) > 40 * standardDeviation) {
return dev < 0 ? 0.0d : 1.0d;
}
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
}
```
| public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
if (FastMath.abs(dev) > 40 * standardDeviation) {
return dev < 0 ? 0.0d : 1.0d;
}
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* For this distribution, {@code X}, this method returns {@code P(X < x)}.
* If {@code x}is more than 40 standard deviations from the mean, 0 or 1 is returned,
* as in these cases the actual value is within {@code Double.MIN_VALUE} of 0 or 1.
*
* @param x Value at which the CDF is evaluated.
* @return CDF evaluated at {@code x}.
* @throws MathException if the algorithm fails to converge
*/
public double cumulativeProbability(double x) throws MathException {
final double dev = x - mean;
if (FastMath.abs(dev) > 40 * standardDeviation) {
return dev < 0 ? 0.0d : 1.0d;
}
return 0.5 * (1.0 + Erf.erf((dev) /
(standardDeviation * FastMath.sqrt(2.0))));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 1581daec823d0bc7eeb7d566bc3332d22741cf4885202f1097cebb0d9d3863ef | private void updateBounds(TimePeriod period, int index) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Update the index values for the maximum and minimum bounds.
*
* @param period the time period.
* @param index the index of the time period.
*/
private void updateBounds(TimePeriod period, int index) {
long start = period.getStart().getTime();
long end = period.getEnd().getTime();
long middle = start + ((end - start) / 2);
if (this.minStartIndex >= 0) {
long minStart = getDataItem(this.minStartIndex).getPeriod()
.getStart().getTime();
if (start < minStart) {
this.minStartIndex = index;
}
}
else {
this.minStartIndex = index;
}
if (this.maxStartIndex >= 0) {
long maxStart = getDataItem(this.maxStartIndex).getPeriod()
.getStart().getTime();
if (start > maxStart) {
this.maxStartIndex = index;
}
}
else {
this.maxStartIndex = index;
}
if (this.minMiddleIndex >= 0) {
long s = getDataItem(this.minMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.minMiddleIndex).getPeriod().getEnd()
.getTime();
long minMiddle = s + (e - s) / 2;
if (middle < minMiddle) {
this.minMiddleIndex = index;
}
}
else {
this.minMiddleIndex = index;
}
if (this.maxMiddleIndex >= 0) {
long s = getDataItem(this.maxMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.maxMiddleIndex).getPeriod().getEnd()
.getTime();
long maxMiddle = s + (e - s) / 2;
if (middle > maxMiddle) {
this.maxMiddleIndex = index;
}
}
else {
this.maxMiddleIndex = index;
}
if (this.minEndIndex >= 0) {
long minEnd = getDataItem(this.minEndIndex).getPeriod().getEnd()
.getTime();
if (end < minEnd) {
this.minEndIndex = index;
}
}
else {
this.minEndIndex = index;
}
if (this.maxEndIndex >= 0) {
long maxEnd = getDataItem(this.maxEndIndex).getPeriod().getEnd()
.getTime();
if (end > maxEnd) {
this.maxEndIndex = index;
}
}
else {
this.maxEndIndex = index;
}
}
```
| private void updateBounds(TimePeriod period, int index) {
long start = period.getStart().getTime();
long end = period.getEnd().getTime();
long middle = start + ((end - start) / 2);
if (this.minStartIndex >= 0) {
long minStart = getDataItem(this.minStartIndex).getPeriod()
.getStart().getTime();
if (start < minStart) {
this.minStartIndex = index;
}
}
else {
this.minStartIndex = index;
}
if (this.maxStartIndex >= 0) {
long maxStart = getDataItem(this.maxStartIndex).getPeriod()
.getStart().getTime();
if (start > maxStart) {
this.maxStartIndex = index;
}
}
else {
this.maxStartIndex = index;
}
if (this.minMiddleIndex >= 0) {
long s = getDataItem(this.minMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.minMiddleIndex).getPeriod().getEnd()
.getTime();
long minMiddle = s + (e - s) / 2;
if (middle < minMiddle) {
this.minMiddleIndex = index;
}
}
else {
this.minMiddleIndex = index;
}
if (this.maxMiddleIndex >= 0) {
long s = getDataItem(this.maxMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.maxMiddleIndex).getPeriod().getEnd()
.getTime();
long maxMiddle = s + (e - s) / 2;
if (middle > maxMiddle) {
this.maxMiddleIndex = index;
}
}
else {
this.maxMiddleIndex = index;
}
if (this.minEndIndex >= 0) {
long minEnd = getDataItem(this.minEndIndex).getPeriod().getEnd()
.getTime();
if (end < minEnd) {
this.minEndIndex = index;
}
}
else {
this.minEndIndex = index;
}
if (this.maxEndIndex >= 0) {
long maxEnd = getDataItem(this.maxEndIndex).getPeriod().getEnd()
.getTime();
if (end > maxEnd) {
this.maxEndIndex = index;
}
}
else {
this.maxEndIndex = index;
}
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Update the index values for the maximum and minimum bounds.
*
* @param period the time period.
* @param index the index of the time period.
*/
private void updateBounds(TimePeriod period, int index) {
long start = period.getStart().getTime();
long end = period.getEnd().getTime();
long middle = start + ((end - start) / 2);
if (this.minStartIndex >= 0) {
long minStart = getDataItem(this.minStartIndex).getPeriod()
.getStart().getTime();
if (start < minStart) {
this.minStartIndex = index;
}
}
else {
this.minStartIndex = index;
}
if (this.maxStartIndex >= 0) {
long maxStart = getDataItem(this.maxStartIndex).getPeriod()
.getStart().getTime();
if (start > maxStart) {
this.maxStartIndex = index;
}
}
else {
this.maxStartIndex = index;
}
if (this.minMiddleIndex >= 0) {
long s = getDataItem(this.minMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.minMiddleIndex).getPeriod().getEnd()
.getTime();
long minMiddle = s + (e - s) / 2;
if (middle < minMiddle) {
this.minMiddleIndex = index;
}
}
else {
this.minMiddleIndex = index;
}
if (this.maxMiddleIndex >= 0) {
long s = getDataItem(this.maxMiddleIndex).getPeriod().getStart()
.getTime();
long e = getDataItem(this.maxMiddleIndex).getPeriod().getEnd()
.getTime();
long maxMiddle = s + (e - s) / 2;
if (middle > maxMiddle) {
this.maxMiddleIndex = index;
}
}
else {
this.maxMiddleIndex = index;
}
if (this.minEndIndex >= 0) {
long minEnd = getDataItem(this.minEndIndex).getPeriod().getEnd()
.getTime();
if (end < minEnd) {
this.minEndIndex = index;
}
}
else {
this.minEndIndex = index;
}
if (this.maxEndIndex >= 0) {
long maxEnd = getDataItem(this.maxEndIndex).getPeriod().getEnd()
.getTime();
if (end > maxEnd) {
this.maxEndIndex = index;
}
}
else {
this.maxEndIndex = index;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 15a3b5a96a77c2d91f352b0b8e0f7dc05fbd524a22b6869ace107ca32ea5481e | @Override
public PropertyName findNameForSerialization(Annotated a)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Serialization: property annotations
/**********************************************************
*/
@Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)
|| _hasAnnotation(a, JsonUnwrapped.class)
|| _hasAnnotation(a, JsonBackReference.class)
|| _hasAnnotation(a, JsonManagedReference.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
}
```
| @Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)
|| _hasAnnotation(a, JsonUnwrapped.class)
|| _hasAnnotation(a, JsonBackReference.class)
|| _hasAnnotation(a, JsonManagedReference.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Serialization: property annotations
/**********************************************************
*/
@Override
public PropertyName findNameForSerialization(Annotated a)
{
String name = null;
JsonGetter jg = _findAnnotation(a, JsonGetter.class);
if (jg != null) {
name = jg.value();
} else {
JsonProperty pann = _findAnnotation(a, JsonProperty.class);
if (pann != null) {
name = pann.value();
/* 22-Apr-2014, tatu: Should figure out a better way to do this, but
* it's actually bit tricky to do it more efficiently (meta-annotations
* add more lookups; AnnotationMap costs etc)
*/
} else if (_hasAnnotation(a, JsonSerialize.class)
|| _hasAnnotation(a, JsonView.class)
|| _hasAnnotation(a, JsonRawValue.class)
|| _hasAnnotation(a, JsonUnwrapped.class)
|| _hasAnnotation(a, JsonBackReference.class)
|| _hasAnnotation(a, JsonManagedReference.class)) {
name = "";
} else {
return null;
}
}
return PropertyName.construct(name);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 15af5e4ba22b74be3277572b401b1fc558fc710b3546c1f559422058df72065c | public int read(byte b[], int offset, int len) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Attempts to read <code>len</code> bytes into the specified <code>b</code> array starting at <code>offset</code>
* from this InputStream.
*
* @param b
* destination byte array
* @param offset
* where to start writing the bytes
* @param len
* maximum number of bytes to read
*
* @return number of bytes read
* @throws IOException
* if an I/O error occurs.
* @throws NullPointerException
* if the byte array parameter is null
* @throws IndexOutOfBoundsException
* if offset, len or buffer size are invalid
*/
public int read(byte b[], int offset, int len) throws IOException {
if (b == null) {
throw new NullPointerException();
} else if (offset < 0 || len < 0) {
throw new IndexOutOfBoundsException();
} else if (offset > b.length || offset + len > b.length) {
throw new IndexOutOfBoundsException();
} else if (len == 0) {
return 0;
} else {
/*
Rationale for while-loop on (readLen == 0):
-----
Base64.readResults() usually returns > 0 or EOF (-1). In the
rare case where it returns 0, we just keep trying.
This is essentially an undocumented contract for InputStream
implementors that want their code to work properly with
java.io.InputStreamReader, since the latter hates it when
InputStream.read(byte[]) returns a zero. Unfortunately our
readResults() call must return 0 if a large amount of the data
being decoded was non-base64, so this while-loop enables proper
interop with InputStreamReader for that scenario.
-----
This is a fix for CODEC-101
*/
if (!base64.hasData()) {
byte[] buf = new byte[doEncode ? 4096 : 8192];
int c = in.read(buf);
// A little optimization to avoid System.arraycopy()
// when possible.
if (c > 0 && b.length == len) {
base64.setInitialBuffer(b, offset, len);
}
if (doEncode) {
base64.encode(buf, 0, c);
} else {
base64.decode(buf, 0, c);
}
}
return base64.readResults(b, offset, len);
}
}
```
| public int read(byte b[], int offset, int len) throws IOException {
if (b == null) {
throw new NullPointerException();
} else if (offset < 0 || len < 0) {
throw new IndexOutOfBoundsException();
} else if (offset > b.length || offset + len > b.length) {
throw new IndexOutOfBoundsException();
} else if (len == 0) {
return 0;
} else {
/*
Rationale for while-loop on (readLen == 0):
-----
Base64.readResults() usually returns > 0 or EOF (-1). In the
rare case where it returns 0, we just keep trying.
This is essentially an undocumented contract for InputStream
implementors that want their code to work properly with
java.io.InputStreamReader, since the latter hates it when
InputStream.read(byte[]) returns a zero. Unfortunately our
readResults() call must return 0 if a large amount of the data
being decoded was non-base64, so this while-loop enables proper
interop with InputStreamReader for that scenario.
-----
This is a fix for CODEC-101
*/
if (!base64.hasData()) {
byte[] buf = new byte[doEncode ? 4096 : 8192];
int c = in.read(buf);
// A little optimization to avoid System.arraycopy()
// when possible.
if (c > 0 && b.length == len) {
base64.setInitialBuffer(b, offset, len);
}
if (doEncode) {
base64.encode(buf, 0, c);
} else {
base64.decode(buf, 0, c);
}
}
return base64.readResults(b, offset, len);
}
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Attempts to read <code>len</code> bytes into the specified <code>b</code> array starting at <code>offset</code>
* from this InputStream.
*
* @param b
* destination byte array
* @param offset
* where to start writing the bytes
* @param len
* maximum number of bytes to read
*
* @return number of bytes read
* @throws IOException
* if an I/O error occurs.
* @throws NullPointerException
* if the byte array parameter is null
* @throws IndexOutOfBoundsException
* if offset, len or buffer size are invalid
*/
public int read(byte b[], int offset, int len) throws IOException {
if (b == null) {
throw new NullPointerException();
} else if (offset < 0 || len < 0) {
throw new IndexOutOfBoundsException();
} else if (offset > b.length || offset + len > b.length) {
throw new IndexOutOfBoundsException();
} else if (len == 0) {
return 0;
} else {
/*
Rationale for while-loop on (readLen == 0):
-----
Base64.readResults() usually returns > 0 or EOF (-1). In the
rare case where it returns 0, we just keep trying.
This is essentially an undocumented contract for InputStream
implementors that want their code to work properly with
java.io.InputStreamReader, since the latter hates it when
InputStream.read(byte[]) returns a zero. Unfortunately our
readResults() call must return 0 if a large amount of the data
being decoded was non-base64, so this while-loop enables proper
interop with InputStreamReader for that scenario.
-----
This is a fix for CODEC-101
*/
if (!base64.hasData()) {
byte[] buf = new byte[doEncode ? 4096 : 8192];
int c = in.read(buf);
// A little optimization to avoid System.arraycopy()
// when possible.
if (c > 0 && b.length == len) {
base64.setInitialBuffer(b, offset, len);
}
if (doEncode) {
base64.encode(buf, 0, c);
} else {
base64.decode(buf, 0, c);
}
}
return base64.readResults(b, offset, len);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 15c63a36b247ecec1f26fa3d96941485922947aeb63381f6f9dbc29258e3df95 | public static String encodeBase64String(byte[] binaryData) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Encodes binary data using the base64 algorithm into 76 character blocks separated by CRLF.
*
* @param binaryData
* binary data to encode
* @return String containing Base64 characters.
* @since 1.4
*/
public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, true));
}
```
| public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, true));
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Encodes binary data using the base64 algorithm into 76 character blocks separated by CRLF.
*
* @param binaryData
* binary data to encode
* @return String containing Base64 characters.
* @since 1.4
*/
public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, true));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 15f9f1071a4a0d1f9077542c08e7bb369b4ee8cf1e0533f6db33fc844fba33fa | @Override
public boolean equals(Object o) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return tag.equals(element.tag);
}
```
| @Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return tag.equals(element.tag);
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
if (!super.equals(o)) return false;
Element element = (Element) o;
return tag.equals(element.tag);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
2 | 160a933fd5557dd175d6ec716c3c3dc0fc0e049958da6a0213964e9d1b6426d6 | void encode(byte[] in, int inPos, int inAvail) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Encodes all of the provided data, starting at inPos, for inAvail bytes.
* Must be called at least twice: once with the data to encode, and once
* with inAvail set to "-1" to alert encoder that EOF has been reached,
* so flush last remaining bytes (if not multiple of 3).
* </p><p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations,
* and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in byte[] array of binary data to base64 encode.
* @param inPos Position to start reading data from.
* @param inAvail Amount of bytes available from input for encoding.
*/
void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
}
```
| void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Encodes all of the provided data, starting at inPos, for inAvail bytes.
* Must be called at least twice: once with the data to encode, and once
* with inAvail set to "-1" to alert encoder that EOF has been reached,
* so flush last remaining bytes (if not multiple of 3).
* </p><p>
* Thanks to "commons" project in ws.apache.org for the bitwise operations,
* and general approach.
* http://svn.apache.org/repos/asf/webservices/commons/trunk/modules/util/
* </p>
*
* @param in byte[] array of binary data to base64 encode.
* @param inPos Position to start reading data from.
* @param inAvail Amount of bytes available from input for encoding.
*/
void encode(byte[] in, int inPos, int inAvail) {
if (eof) {
return;
}
// inAvail < 0 is how we're informed of EOF in the underlying data we're
// encoding.
if (inAvail < 0) {
eof = true;
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
switch (modulus) {
case 1:
buf[pos++] = encodeTable[(x >> 2) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 4) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
buf[pos++] = PAD;
}
break;
case 2:
buf[pos++] = encodeTable[(x >> 10) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 4) & MASK_6BITS];
buf[pos++] = encodeTable[(x << 2) & MASK_6BITS];
// URL-SAFE skips the padding to further reduce size.
if (encodeTable == STANDARD_ENCODE_TABLE) {
buf[pos++] = PAD;
}
break;
}
if (lineLength > 0) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
}
} else {
for (int i = 0; i < inAvail; i++) {
if (buf == null || buf.length - pos < encodeSize) {
resizeBuf();
}
modulus = (++modulus) % 3;
int b = in[inPos++];
if (b < 0) { b += 256; }
x = (x << 8) + b;
if (0 == modulus) {
buf[pos++] = encodeTable[(x >> 18) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 12) & MASK_6BITS];
buf[pos++] = encodeTable[(x >> 6) & MASK_6BITS];
buf[pos++] = encodeTable[x & MASK_6BITS];
currentLinePos += 4;
if (lineLength > 0 && lineLength <= currentLinePos) {
System.arraycopy(lineSeparator, 0, buf, pos, lineSeparator.length);
pos += lineSeparator.length;
currentLinePos = 0;
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
57 | 1650ce1e45ed0642183e6b14a151b0afcbdec6320a4d66aaf103c71193ca7bfb | public void removeIgnoreCase(String key) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
Remove an attribute by key. <b>Case insensitive.</b>
@param key attribute key to remove
*/
public void removeIgnoreCase(String key) {
Validate.notEmpty(key);
if (attributes == null)
return;
for (Iterator<String> it = attributes.keySet().iterator(); it.hasNext(); ) {
String attrKey = it.next();
if (attrKey.equalsIgnoreCase(key))
it.remove();
}
}
```
| public void removeIgnoreCase(String key) {
Validate.notEmpty(key);
if (attributes == null)
return;
for (Iterator<String> it = attributes.keySet().iterator(); it.hasNext(); ) {
String attrKey = it.next();
if (attrKey.equalsIgnoreCase(key))
it.remove();
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
Remove an attribute by key. <b>Case insensitive.</b>
@param key attribute key to remove
*/
public void removeIgnoreCase(String key) {
Validate.notEmpty(key);
if (attributes == null)
return;
for (Iterator<String> it = attributes.keySet().iterator(); it.hasNext(); ) {
String attrKey = it.next();
if (attrKey.equalsIgnoreCase(key))
it.remove();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 1671a6ad1d73901e5d10be9dbdd43294538be28d0f77282d80f9279eecab8336 | public Map<String, Integer> getHeaderMap() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a copy of the header map that iterates in column order.
* <p>
* The map keys are column names. The map values are 0-based indices.
* </p>
* @return a copy of the header map that iterates in column order.
*/
public Map<String, Integer> getHeaderMap() {
return this.headerMap == null ? null : new LinkedHashMap<String, Integer>(this.headerMap);
}
```
| public Map<String, Integer> getHeaderMap() {
return this.headerMap == null ? null : new LinkedHashMap<String, Integer>(this.headerMap);
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a copy of the header map that iterates in column order.
* <p>
* The map keys are column names. The map values are 0-based indices.
* </p>
* @return a copy of the header map that iterates in column order.
*/
public Map<String, Integer> getHeaderMap() {
return this.headerMap == null ? null : new LinkedHashMap<String, Integer>(this.headerMap);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | 168529b4dad3d469089d5634e95cd895178ce36bb1de2b7031057507cb505183 | static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns true if calls to this function have side effects.
*
* @param callNode The call node to inspected.
* @param compiler A compiler object to provide program state changing
* context information. Can be null.
*/
static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
}
```
| static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns true if calls to this function have side effects.
*
* @param callNode The call node to inspected.
* @param compiler A compiler object to provide program state changing
* context information. Can be null.
*/
static boolean functionCallHasSideEffects(
Node callNode, @Nullable AbstractCompiler compiler) {
if (callNode.getType() != Token.CALL) {
throw new IllegalStateException(
"Expected CALL node, got " + Token.name(callNode.getType()));
}
if (callNode.isNoSideEffectsCall()) {
return false;
}
Node nameNode = callNode.getFirstChild();
// Built-in functions with no side effects.
if (nameNode.getType() == Token.NAME) {
String name = nameNode.getString();
if (BUILTIN_FUNCTIONS_WITHOUT_SIDEEFFECTS.contains(name)) {
return false;
}
} else if (nameNode.getType() == Token.GETPROP) {
if (callNode.hasOneChild()
&& OBJECT_METHODS_WITHOUT_SIDEEFFECTS.contains(
nameNode.getLastChild().getString())) {
return false;
}
if (callNode.isOnlyModifiesThisCall()
&& evaluatesToLocalValue(nameNode.getFirstChild())) {
return false;
}
// Functions in the "Math" namespace have no side effects.
if (compiler != null && !compiler.hasRegExpGlobalReferences()) {
if (nameNode.getFirstChild().getType() == Token.REGEXP
&& REGEXP_METHODS.contains(nameNode.getLastChild().getString())) {
return false;
} else if (nameNode.getFirstChild().getType() == Token.STRING
&& STRING_REGEXP_METHODS.contains(
nameNode.getLastChild().getString())) {
Node param = nameNode.getNext();
if (param != null &&
(param.getType() == Token.STRING
|| param.getType() == Token.REGEXP))
return false;
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 17ace30a651964468ec16c74728a14e5a2917c4d406d040f75b6ae4c69d727d9 | @Override
public void matchConstraint(ObjectType constraintObj) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
}
```
| @Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public void matchConstraint(ObjectType constraintObj) {
// We only want to match contraints on anonymous types.
// Handle the case where the constraint object is a record type.
//
// param constraintObj {{prop: (number|undefined)}}
// function f(constraintObj) {}
// f({});
//
// We want to modify the object literal to match the constraint, by
// taking any each property on the record and trying to match
// properties on this object.
if (constraintObj.isRecordType()) {
for (String prop : constraintObj.getOwnPropertyNames()) {
JSType propType = constraintObj.getPropertyType(prop);
if (!isPropertyTypeDeclared(prop)) {
JSType typeToInfer = propType;
if (!hasProperty(prop)) {
typeToInfer = getNativeType(JSTypeNative.VOID_TYPE)
.getLeastSupertype(propType);
}
defineInferredProperty(prop, typeToInfer, null);
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 17e194ab82d97fe777443a94f11ef0a18eefb9e27ba8cc8e9a9a971d58e587fd | public static String abbreviate(String str, int lower, int upper, String appendToEnd) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Abbreviates a string nicely.
*
* This method searches for the first space after the lower limit and abbreviates
* the String there. It will also append any String passed as a parameter
* to the end of the String. The upper limit can be specified to forcibly
* abbreviate a String.
*
* @param str the string to be abbreviated. If null is passed, null is returned.
* If the empty String is passed, the empty string is returned.
* @param lower the lower limit.
* @param upper the upper limit; specify -1 if no limit is desired.
* If the upper limit is lower than the lower limit, it will be
* adjusted to be the same as the lower limit.
* @param appendToEnd String to be appended to the end of the abbreviated string.
* This is appended ONLY if the string was indeed abbreviated.
* The append does not count towards the lower or upper limits.
* @return the abbreviated String.
* @since 2.4
*/
//-----------------------------------------------------------------------
public static String abbreviate(String str, int lower, int upper, String appendToEnd) {
// initial parameter checks
if (str == null) {
return null;
}
if (str.length() == 0) {
return StringUtils.EMPTY;
}
// if the lower value is greater than the length of the string,
// set to the length of the string
// if the upper value is -1 (i.e. no limit) or is greater
// than the length of the string, set to the length of the string
if (upper == -1 || upper > str.length()) {
upper = str.length();
}
// if upper is less than lower, raise it to lower
if (upper < lower) {
upper = lower;
}
StringBuffer result = new StringBuffer();
int index = StringUtils.indexOf(str, " ", lower);
if (index == -1) {
result.append(str.substring(0, upper));
// only if abbreviation has occured do we append the appendToEnd value
if (upper != str.length()) {
result.append(StringUtils.defaultString(appendToEnd));
}
} else if (index > upper) {
result.append(str.substring(0, upper));
result.append(StringUtils.defaultString(appendToEnd));
} else {
result.append(str.substring(0, index));
result.append(StringUtils.defaultString(appendToEnd));
}
return result.toString();
}
```
| public static String abbreviate(String str, int lower, int upper, String appendToEnd) {
// initial parameter checks
if (str == null) {
return null;
}
if (str.length() == 0) {
return StringUtils.EMPTY;
}
// if the lower value is greater than the length of the string,
// set to the length of the string
// if the upper value is -1 (i.e. no limit) or is greater
// than the length of the string, set to the length of the string
if (upper == -1 || upper > str.length()) {
upper = str.length();
}
// if upper is less than lower, raise it to lower
if (upper < lower) {
upper = lower;
}
StringBuffer result = new StringBuffer();
int index = StringUtils.indexOf(str, " ", lower);
if (index == -1) {
result.append(str.substring(0, upper));
// only if abbreviation has occured do we append the appendToEnd value
if (upper != str.length()) {
result.append(StringUtils.defaultString(appendToEnd));
}
} else if (index > upper) {
result.append(str.substring(0, upper));
result.append(StringUtils.defaultString(appendToEnd));
} else {
result.append(str.substring(0, index));
result.append(StringUtils.defaultString(appendToEnd));
}
return result.toString();
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Abbreviates a string nicely.
*
* This method searches for the first space after the lower limit and abbreviates
* the String there. It will also append any String passed as a parameter
* to the end of the String. The upper limit can be specified to forcibly
* abbreviate a String.
*
* @param str the string to be abbreviated. If null is passed, null is returned.
* If the empty String is passed, the empty string is returned.
* @param lower the lower limit.
* @param upper the upper limit; specify -1 if no limit is desired.
* If the upper limit is lower than the lower limit, it will be
* adjusted to be the same as the lower limit.
* @param appendToEnd String to be appended to the end of the abbreviated string.
* This is appended ONLY if the string was indeed abbreviated.
* The append does not count towards the lower or upper limits.
* @return the abbreviated String.
* @since 2.4
*/
//-----------------------------------------------------------------------
public static String abbreviate(String str, int lower, int upper, String appendToEnd) {
// initial parameter checks
if (str == null) {
return null;
}
if (str.length() == 0) {
return StringUtils.EMPTY;
}
// if the lower value is greater than the length of the string,
// set to the length of the string
// if the upper value is -1 (i.e. no limit) or is greater
// than the length of the string, set to the length of the string
if (upper == -1 || upper > str.length()) {
upper = str.length();
}
// if upper is less than lower, raise it to lower
if (upper < lower) {
upper = lower;
}
StringBuffer result = new StringBuffer();
int index = StringUtils.indexOf(str, " ", lower);
if (index == -1) {
result.append(str.substring(0, upper));
// only if abbreviation has occured do we append the appendToEnd value
if (upper != str.length()) {
result.append(StringUtils.defaultString(appendToEnd));
}
} else if (index > upper) {
result.append(str.substring(0, upper));
result.append(StringUtils.defaultString(appendToEnd));
} else {
result.append(str.substring(0, index));
result.append(StringUtils.defaultString(appendToEnd));
}
return result.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
63 | 17e9e7e5bbd743eca8520a834e6eae3fcf433111a7e8d8eadeb6d010a9e07b90 | public static boolean equals(double x, double y) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns true iff they are equal as defined by
* {@link #equals(double,double,int) equals(x, y, 1)}.
*
* @param x first value
* @param y second value
* @return {@code true} if the values are equal.
*/
public static boolean equals(double x, double y) {
return (Double.isNaN(x) && Double.isNaN(y)) || x == y;
}
```
| public static boolean equals(double x, double y) {
return (Double.isNaN(x) && Double.isNaN(y)) || x == y;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns true iff they are equal as defined by
* {@link #equals(double,double,int) equals(x, y, 1)}.
*
* @param x first value
* @param y second value
* @return {@code true} if the values are equal.
*/
public static boolean equals(double x, double y) {
return (Double.isNaN(x) && Double.isNaN(y)) || x == y;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 18455cf74e7f2fdd427063274f7294a639bd7a61bc4f90adbfe4c889d8ff065c | private boolean isShortOption(String token)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
// check for several concatenated short options
}
```
| private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
// check for several concatenated short options
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Tells if the token looks like a short option.
*
* @param token
*/
private boolean isShortOption(String token)
{
// short options (-S, -SV, -S=V, -SV1=V2, -S1S2)
if (!token.startsWith("-") || token.length() == 1)
{
return false;
}
// remove leading "-" and "=value"
int pos = token.indexOf("=");
String optName = pos == -1 ? token.substring(1) : token.substring(1, pos);
return options.hasShortOption(optName);
// check for several concatenated short options
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
91 | 188746deba1932d74351da8cfe21b70f6afcf69d27c91894fb2bfa63236c1d81 | private boolean _hasCustomHandlers(JavaType t) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Helper method used to prevent both caching and cache lookups for structured
* types that have custom value handlers
*
* @since 2.8.11
*/
/*
/**********************************************************
/* Helper methods, other
/**********************************************************
*/
private boolean _hasCustomHandlers(JavaType t) {
if (t.isContainerType()) {
// First: value types may have both value and type handlers
JavaType ct = t.getContentType();
if (ct != null) {
return (ct.getValueHandler() != null) || (ct.getTypeHandler() != null);
// Second: map(-like) types may have value handler for key (but not type; keys are untyped)
}
}
return false;
}
```
| private boolean _hasCustomHandlers(JavaType t) {
if (t.isContainerType()) {
// First: value types may have both value and type handlers
JavaType ct = t.getContentType();
if (ct != null) {
return (ct.getValueHandler() != null) || (ct.getTypeHandler() != null);
// Second: map(-like) types may have value handler for key (but not type; keys are untyped)
}
}
return false;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Helper method used to prevent both caching and cache lookups for structured
* types that have custom value handlers
*
* @since 2.8.11
*/
/*
/**********************************************************
/* Helper methods, other
/**********************************************************
*/
private boolean _hasCustomHandlers(JavaType t) {
if (t.isContainerType()) {
// First: value types may have both value and type handlers
JavaType ct = t.getContentType();
if (ct != null) {
return (ct.getValueHandler() != null) || (ct.getTypeHandler() != null);
// Second: map(-like) types may have value handler for key (but not type; keys are untyped)
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 18c261c18c7dcf715cba1867e0c3785ba00c24e97e38f2445982b5492eac8629 | protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
// otherwise only verify if neither explicitly annotated.
}
// one more thing: ok to override in sub-class
if (oldOne.getClass() == newOne.getClass()) {
// [databind#667]: avoid one particular class of bogus problems
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
// otherwise, which one to choose?
// new type more generic, use old
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
}
```
| protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
// otherwise only verify if neither explicitly annotated.
}
// one more thing: ok to override in sub-class
if (oldOne.getClass() == newOne.getClass()) {
// [databind#667]: avoid one particular class of bogus problems
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
// otherwise, which one to choose?
// new type more generic, use old
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
// otherwise only verify if neither explicitly annotated.
}
// one more thing: ok to override in sub-class
if (oldOne.getClass() == newOne.getClass()) {
// [databind#667]: avoid one particular class of bogus problems
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
// otherwise, which one to choose?
// new type more generic, use old
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
70 | 18d3520ea959d69004f2d4e4abdcf712073b3ce067988eee3f641730dd7f421f | public void remove(SettableBeanProperty propToRm)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Specialized method for removing specified existing entry.
* NOTE: entry MUST exist, otherwise an exception is thrown.
*/
public void remove(SettableBeanProperty propToRm)
{
ArrayList<SettableBeanProperty> props = new ArrayList<SettableBeanProperty>(_size);
String key = getPropertyName(propToRm);
boolean found = false;
for (int i = 1, end = _hashArea.length; i < end; i += 2) {
SettableBeanProperty prop = (SettableBeanProperty) _hashArea[i];
if (prop == null) {
continue;
}
if (!found) {
// 09-Jan-2017, tatu: Important: must check name slot and NOT property name,
// as only former is lower-case in case-insensitive case
found = key.equals(_hashArea[i-1]);
if (found) {
// need to leave a hole here
_propsInOrder[_findFromOrdered(prop)] = null;
continue;
}
}
props.add(prop);
}
if (!found) {
throw new NoSuchElementException("No entry '"+propToRm.getName()+"' found, can't remove");
}
init(props);
}
```
| public void remove(SettableBeanProperty propToRm)
{
ArrayList<SettableBeanProperty> props = new ArrayList<SettableBeanProperty>(_size);
String key = getPropertyName(propToRm);
boolean found = false;
for (int i = 1, end = _hashArea.length; i < end; i += 2) {
SettableBeanProperty prop = (SettableBeanProperty) _hashArea[i];
if (prop == null) {
continue;
}
if (!found) {
// 09-Jan-2017, tatu: Important: must check name slot and NOT property name,
// as only former is lower-case in case-insensitive case
found = key.equals(_hashArea[i-1]);
if (found) {
// need to leave a hole here
_propsInOrder[_findFromOrdered(prop)] = null;
continue;
}
}
props.add(prop);
}
if (!found) {
throw new NoSuchElementException("No entry '"+propToRm.getName()+"' found, can't remove");
}
init(props);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Specialized method for removing specified existing entry.
* NOTE: entry MUST exist, otherwise an exception is thrown.
*/
public void remove(SettableBeanProperty propToRm)
{
ArrayList<SettableBeanProperty> props = new ArrayList<SettableBeanProperty>(_size);
String key = getPropertyName(propToRm);
boolean found = false;
for (int i = 1, end = _hashArea.length; i < end; i += 2) {
SettableBeanProperty prop = (SettableBeanProperty) _hashArea[i];
if (prop == null) {
continue;
}
if (!found) {
// 09-Jan-2017, tatu: Important: must check name slot and NOT property name,
// as only former is lower-case in case-insensitive case
found = key.equals(_hashArea[i-1]);
if (found) {
// need to leave a hole here
_propsInOrder[_findFromOrdered(prop)] = null;
continue;
}
}
props.add(prop);
}
if (!found) {
throw new NoSuchElementException("No entry '"+propToRm.getName()+"' found, can't remove");
}
init(props);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
48 | 18ddcd7031196a3e13fc9386a883e562424e111a0a540c60eb84bdbf7a9b5619 | protected final double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
```
| protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
// Detect early that algorithm is stuck, instead of waiting
// for the maximum number of iterations to be exceeded.
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 18dee9c9452c91ab4bd6bd9c8b020e05524637d3c44ef00715be434c3254898e | public MultiplePiePlot(CategoryDataset dataset) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new plot.
*
* @param dataset the dataset (<code>null</code> permitted).
*/
public MultiplePiePlot(CategoryDataset dataset) {
super();
this.dataset = dataset;
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
}
```
| public MultiplePiePlot(CategoryDataset dataset) {
super();
this.dataset = dataset;
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new plot.
*
* @param dataset the dataset (<code>null</code> permitted).
*/
public MultiplePiePlot(CategoryDataset dataset) {
super();
this.dataset = dataset;
PiePlot piePlot = new PiePlot(null);
this.pieChart = new JFreeChart(piePlot);
this.pieChart.removeLegend();
this.dataExtractOrder = TableOrder.BY_COLUMN;
this.pieChart.setBackgroundPaint(null);
TextTitle seriesTitle = new TextTitle("Series Title",
new Font("SansSerif", Font.BOLD, 12));
seriesTitle.setPosition(RectangleEdge.BOTTOM);
this.pieChart.setTitle(seriesTitle);
this.aggregatedItemsKey = "Other";
this.aggregatedItemsPaint = Color.lightGray;
this.sectionPaints = new HashMap();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
52 | 1924e55eb1166ddbb189691f313093514be424c554623edbab9deca4fff4fc16 | private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Worker method for the {@link #escapeJavaScript(String)} method.</p>
*
* @param out write to receieve the escaped string
* @param str String to escape values in, may be null
* @param escapeSingleQuote escapes single quotes if <code>true</code>
* @throws IOException if an IOException occurs
*/
private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
case '/':
out.write('\\');
out.write('/');
break;
default :
out.write(ch);
break;
}
}
}
}
```
| private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
case '/':
out.write('\\');
out.write('/');
break;
default :
out.write(ch);
break;
}
}
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Worker method for the {@link #escapeJavaScript(String)} method.</p>
*
* @param out write to receieve the escaped string
* @param str String to escape values in, may be null
* @param escapeSingleQuote escapes single quotes if <code>true</code>
* @throws IOException if an IOException occurs
*/
private static void escapeJavaStyleString(Writer out, String str, boolean escapeSingleQuote) throws IOException {
if (out == null) {
throw new IllegalArgumentException("The Writer must not be null");
}
if (str == null) {
return;
}
int sz;
sz = str.length();
for (int i = 0; i < sz; i++) {
char ch = str.charAt(i);
// handle unicode
if (ch > 0xfff) {
out.write("\\u" + hex(ch));
} else if (ch > 0xff) {
out.write("\\u0" + hex(ch));
} else if (ch > 0x7f) {
out.write("\\u00" + hex(ch));
} else if (ch < 32) {
switch (ch) {
case '\b':
out.write('\\');
out.write('b');
break;
case '\n':
out.write('\\');
out.write('n');
break;
case '\t':
out.write('\\');
out.write('t');
break;
case '\f':
out.write('\\');
out.write('f');
break;
case '\r':
out.write('\\');
out.write('r');
break;
default :
if (ch > 0xf) {
out.write("\\u00" + hex(ch));
} else {
out.write("\\u000" + hex(ch));
}
break;
}
} else {
switch (ch) {
case '\'':
if (escapeSingleQuote) {
out.write('\\');
}
out.write('\'');
break;
case '"':
out.write('\\');
out.write('"');
break;
case '\\':
out.write('\\');
out.write('\\');
break;
case '/':
out.write('\\');
out.write('/');
break;
default :
out.write(ch);
break;
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | 199e0ee25304f46776a179c8f7ca0ae3c9cf2ee96101c1d33ea6c1b05214bbac | private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Integer.parseInt(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Integer.parseInt(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
}
```
| private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Integer.parseInt(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Integer.parseInt(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Integer.parseInt(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Integer.parseInt(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
121 | 1b0d65c265e9b03f66a6e037b63d115de75ae1fedf96e7ff852f2986fa41ea72 | private void inlineNonConstants(
Var v, ReferenceCollection referenceInfo,
boolean maybeModifiedArguments) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void inlineNonConstants(
Var v, ReferenceCollection referenceInfo,
boolean maybeModifiedArguments) {
int refCount = referenceInfo.references.size();
Reference declaration = referenceInfo.references.get(0);
Reference init = referenceInfo.getInitializingReference();
int firstRefAfterInit = (declaration == init) ? 2 : 3;
if (refCount > 1 &&
isImmutableAndWellDefinedVariable(v, referenceInfo)) {
// if the variable is referenced more than once, we can only
// inline it if it's immutable and never defined before referenced.
Node value;
if (init != null) {
value = init.getAssignedValue();
} else {
// Create a new node for variable that is never initialized.
Node srcLocation = declaration.getNode();
value = NodeUtil.newUndefinedNode(srcLocation);
}
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
} else if (refCount == firstRefAfterInit) {
// The variable likely only read once, try some more
// complex inlining heuristics.
Reference reference = referenceInfo.references.get(
firstRefAfterInit - 1);
if (canInline(declaration, init, reference)) {
inline(v, declaration, init, reference);
staleVars.add(v);
}
} else if (declaration != init && refCount == 2) {
if (isValidDeclaration(declaration) && isValidInitialization(init)) {
// The only reference is the initialization, remove the assignment and
// the variable declaration.
Node value = init.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
}
}
// If this variable was not inlined normally, check if we can
// inline an alias of it. (If the variable was inlined, then the
// reference data is out of sync. We're better off just waiting for
// the next pass.)
if (!maybeModifiedArguments &&
!staleVars.contains(v) &&
referenceInfo.isWellDefined() &&
referenceInfo.isAssignedOnceInLifetime() &&
// Inlining the variable based solely on well-defined and assigned
// once is *NOT* correct. We relax the correctness requirement if
// the variable is declared constant.
(isInlineableDeclaredConstant(v, referenceInfo) ||
referenceInfo.isOnlyAssignmentSameScopeAsDeclaration())) {
List<Reference> refs = referenceInfo.references;
for (int i = 1 /* start from a read */; i < refs.size(); i++) {
Node nameNode = refs.get(i).getNode();
if (aliasCandidates.containsKey(nameNode)) {
AliasCandidate candidate = aliasCandidates.get(nameNode);
if (!staleVars.contains(candidate.alias) &&
!isVarInlineForbidden(candidate.alias)) {
Reference aliasInit;
aliasInit = candidate.refInfo.getInitializingReference();
Node value = aliasInit.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(candidate.alias,
value,
candidate.refInfo.references);
staleVars.add(candidate.alias);
}
}
}
}
}
```
| private void inlineNonConstants(
Var v, ReferenceCollection referenceInfo,
boolean maybeModifiedArguments) {
int refCount = referenceInfo.references.size();
Reference declaration = referenceInfo.references.get(0);
Reference init = referenceInfo.getInitializingReference();
int firstRefAfterInit = (declaration == init) ? 2 : 3;
if (refCount > 1 &&
isImmutableAndWellDefinedVariable(v, referenceInfo)) {
// if the variable is referenced more than once, we can only
// inline it if it's immutable and never defined before referenced.
Node value;
if (init != null) {
value = init.getAssignedValue();
} else {
// Create a new node for variable that is never initialized.
Node srcLocation = declaration.getNode();
value = NodeUtil.newUndefinedNode(srcLocation);
}
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
} else if (refCount == firstRefAfterInit) {
// The variable likely only read once, try some more
// complex inlining heuristics.
Reference reference = referenceInfo.references.get(
firstRefAfterInit - 1);
if (canInline(declaration, init, reference)) {
inline(v, declaration, init, reference);
staleVars.add(v);
}
} else if (declaration != init && refCount == 2) {
if (isValidDeclaration(declaration) && isValidInitialization(init)) {
// The only reference is the initialization, remove the assignment and
// the variable declaration.
Node value = init.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
}
}
// If this variable was not inlined normally, check if we can
// inline an alias of it. (If the variable was inlined, then the
// reference data is out of sync. We're better off just waiting for
// the next pass.)
if (!maybeModifiedArguments &&
!staleVars.contains(v) &&
referenceInfo.isWellDefined() &&
referenceInfo.isAssignedOnceInLifetime() &&
// Inlining the variable based solely on well-defined and assigned
// once is *NOT* correct. We relax the correctness requirement if
// the variable is declared constant.
(isInlineableDeclaredConstant(v, referenceInfo) ||
referenceInfo.isOnlyAssignmentSameScopeAsDeclaration())) {
List<Reference> refs = referenceInfo.references;
for (int i = 1 /* start from a read */; i < refs.size(); i++) {
Node nameNode = refs.get(i).getNode();
if (aliasCandidates.containsKey(nameNode)) {
AliasCandidate candidate = aliasCandidates.get(nameNode);
if (!staleVars.contains(candidate.alias) &&
!isVarInlineForbidden(candidate.alias)) {
Reference aliasInit;
aliasInit = candidate.refInfo.getInitializingReference();
Node value = aliasInit.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(candidate.alias,
value,
candidate.refInfo.references);
staleVars.add(candidate.alias);
}
}
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void inlineNonConstants(
Var v, ReferenceCollection referenceInfo,
boolean maybeModifiedArguments) {
int refCount = referenceInfo.references.size();
Reference declaration = referenceInfo.references.get(0);
Reference init = referenceInfo.getInitializingReference();
int firstRefAfterInit = (declaration == init) ? 2 : 3;
if (refCount > 1 &&
isImmutableAndWellDefinedVariable(v, referenceInfo)) {
// if the variable is referenced more than once, we can only
// inline it if it's immutable and never defined before referenced.
Node value;
if (init != null) {
value = init.getAssignedValue();
} else {
// Create a new node for variable that is never initialized.
Node srcLocation = declaration.getNode();
value = NodeUtil.newUndefinedNode(srcLocation);
}
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
} else if (refCount == firstRefAfterInit) {
// The variable likely only read once, try some more
// complex inlining heuristics.
Reference reference = referenceInfo.references.get(
firstRefAfterInit - 1);
if (canInline(declaration, init, reference)) {
inline(v, declaration, init, reference);
staleVars.add(v);
}
} else if (declaration != init && refCount == 2) {
if (isValidDeclaration(declaration) && isValidInitialization(init)) {
// The only reference is the initialization, remove the assignment and
// the variable declaration.
Node value = init.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(v, value, referenceInfo.references);
staleVars.add(v);
}
}
// If this variable was not inlined normally, check if we can
// inline an alias of it. (If the variable was inlined, then the
// reference data is out of sync. We're better off just waiting for
// the next pass.)
if (!maybeModifiedArguments &&
!staleVars.contains(v) &&
referenceInfo.isWellDefined() &&
referenceInfo.isAssignedOnceInLifetime() &&
// Inlining the variable based solely on well-defined and assigned
// once is *NOT* correct. We relax the correctness requirement if
// the variable is declared constant.
(isInlineableDeclaredConstant(v, referenceInfo) ||
referenceInfo.isOnlyAssignmentSameScopeAsDeclaration())) {
List<Reference> refs = referenceInfo.references;
for (int i = 1 /* start from a read */; i < refs.size(); i++) {
Node nameNode = refs.get(i).getNode();
if (aliasCandidates.containsKey(nameNode)) {
AliasCandidate candidate = aliasCandidates.get(nameNode);
if (!staleVars.contains(candidate.alias) &&
!isVarInlineForbidden(candidate.alias)) {
Reference aliasInit;
aliasInit = candidate.refInfo.getInitializingReference();
Node value = aliasInit.getAssignedValue();
Preconditions.checkNotNull(value);
inlineWellDefinedVariable(candidate.alias,
value,
candidate.refInfo.references);
staleVars.add(candidate.alias);
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 1b22b4fd0bd8fc25a14ac23061a0544ddca347a404ec028d3fb27a3e1663dc7d | public boolean hasSameMethod(Invocation candidate) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
if (m1.getName() != null && m1.getName().equals(m2.getName())) {
/* Avoid unnecessary cloning */
Class[] params1 = m1.getParameterTypes();
Class[] params2 = m2.getParameterTypes();
if (params1.length == params2.length) {
for (int i = 0; i < params1.length; i++) {
if (params1[i] != params2[i])
return false;
}
return true;
}
}
return false;
}
```
| public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
if (m1.getName() != null && m1.getName().equals(m2.getName())) {
/* Avoid unnecessary cloning */
Class[] params1 = m1.getParameterTypes();
Class[] params2 = m2.getParameterTypes();
if (params1.length == params2.length) {
for (int i = 0; i < params1.length; i++) {
if (params1[i] != params2[i])
return false;
}
return true;
}
}
return false;
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
if (m1.getName() != null && m1.getName().equals(m2.getName())) {
/* Avoid unnecessary cloning */
Class[] params1 = m1.getParameterTypes();
Class[] params2 = m2.getParameterTypes();
if (params1.length == params2.length) {
for (int i = 0; i < params1.length; i++) {
if (params1[i] != params2[i])
return false;
}
return true;
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | 1b401d208014b0690f7d7a7c7832ec8b62c462a3304a8b629750d97f2c32c267 | @Override
public ObjectNode deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public ObjectNode deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
if (p.getCurrentToken() == JsonToken.START_OBJECT) {
p.nextToken();
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
// 23-Sep-2015, tatu: Ugh. We may also be given END_OBJECT (similar to FIELD_NAME),
// if caller has advanced to the first token of Object, but for empty Object
if (p.getCurrentToken() == JsonToken.FIELD_NAME) {
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
throw ctxt.mappingException(ObjectNode.class);
}
```
| @Override
public ObjectNode deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
if (p.getCurrentToken() == JsonToken.START_OBJECT) {
p.nextToken();
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
// 23-Sep-2015, tatu: Ugh. We may also be given END_OBJECT (similar to FIELD_NAME),
// if caller has advanced to the first token of Object, but for empty Object
if (p.getCurrentToken() == JsonToken.FIELD_NAME) {
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
throw ctxt.mappingException(ObjectNode.class);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public ObjectNode deserialize(JsonParser p, DeserializationContext ctxt) throws IOException
{
if (p.getCurrentToken() == JsonToken.START_OBJECT) {
p.nextToken();
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
// 23-Sep-2015, tatu: Ugh. We may also be given END_OBJECT (similar to FIELD_NAME),
// if caller has advanced to the first token of Object, but for empty Object
if (p.getCurrentToken() == JsonToken.FIELD_NAME) {
return deserializeObject(p, ctxt, ctxt.getNodeFactory());
}
throw ctxt.mappingException(ObjectNode.class);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 1b6b6eafd8e6afca68244fbf6ed166c3dc27e6cc8375dd8616b727cca2e631e9 | public static boolean equals(CharSequence cs1, CharSequence cs2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Compares two CharSequences, returning {@code true} if they represent
* equal sequences of characters.</p>
*
* <p>{@code null}s are handled without exceptions. Two {@code null}
* references are considered to be equal. The comparison is case sensitive.</p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* @see java.lang.CharSequence#equals(Object)
* @param cs1 the first CharSequence, may be {@code null}
* @param cs2 the second CharSequence, may be {@code null}
* @return {@code true} if the CharSequences are equal (case-sensitive), or both {@code null}
* @since 3.0 Changed signature from equals(String, String) to equals(CharSequence, CharSequence)
*/
//-----------------------------------------------------------------------
// Equals
public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
return cs1.equals(cs2);
}
```
| public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
return cs1.equals(cs2);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Compares two CharSequences, returning {@code true} if they represent
* equal sequences of characters.</p>
*
* <p>{@code null}s are handled without exceptions. Two {@code null}
* references are considered to be equal. The comparison is case sensitive.</p>
*
* <pre>
* StringUtils.equals(null, null) = true
* StringUtils.equals(null, "abc") = false
* StringUtils.equals("abc", null) = false
* StringUtils.equals("abc", "abc") = true
* StringUtils.equals("abc", "ABC") = false
* </pre>
*
* @see java.lang.CharSequence#equals(Object)
* @param cs1 the first CharSequence, may be {@code null}
* @param cs2 the second CharSequence, may be {@code null}
* @return {@code true} if the CharSequences are equal (case-sensitive), or both {@code null}
* @since 3.0 Changed signature from equals(String, String) to equals(CharSequence, CharSequence)
*/
//-----------------------------------------------------------------------
// Equals
public static boolean equals(CharSequence cs1, CharSequence cs2) {
if (cs1 == cs2) {
return true;
}
if (cs1 == null || cs2 == null) {
return false;
}
return cs1.equals(cs2);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
72 | 1ba611f6ae378e7a9f0fb81ec31089258ee8ca1c85dbc0674a5884e5d57ec95e | public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(min, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(max, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
```
| public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(min, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(max, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Find a zero in the given interval with an initial guess.
* <p>Throws <code>IllegalArgumentException</code> if the values of the
* function at the three points have the same sign (note that it is
* allowed to have endpoints with the same sign if the initial point has
* opposite sign function-wise).</p>
*
* @param f function to solve.
* @param min the lower bound for the interval.
* @param max the upper bound for the interval.
* @param initial the start value to use (must be set to min if no
* initial point is known).
* @return the value where the function is zero
* @throws MaxIterationsExceededException the maximum iteration count
* is exceeded
* @throws FunctionEvaluationException if an error occurs evaluating
* the function
* @throws IllegalArgumentException if initial is not between min and max
* (even if it <em>is</em> a root)
*/
public double solve(final UnivariateRealFunction f,
final double min, final double max, final double initial)
throws MaxIterationsExceededException, FunctionEvaluationException {
clearResult();
verifySequence(min, initial, max);
// return the initial guess if it is good enough
double yInitial = f.value(initial);
if (Math.abs(yInitial) <= functionValueAccuracy) {
setResult(initial, 0);
return result;
}
// return the first endpoint if it is good enough
double yMin = f.value(min);
if (Math.abs(yMin) <= functionValueAccuracy) {
setResult(min, 0);
return result;
}
// reduce interval if min and initial bracket the root
if (yInitial * yMin < 0) {
return solve(f, min, yMin, initial, yInitial, min, yMin);
}
// return the second endpoint if it is good enough
double yMax = f.value(max);
if (Math.abs(yMax) <= functionValueAccuracy) {
setResult(max, 0);
return result;
}
// reduce interval if initial and max bracket the root
if (yInitial * yMax < 0) {
return solve(f, initial, yInitial, max, yMax, initial, yInitial);
}
if (yMin * yMax > 0) {
throw MathRuntimeException.createIllegalArgumentException(
NON_BRACKETING_MESSAGE, min, max, yMin, yMax);
}
// full Brent algorithm starting with provided initial guess
return solve(f, min, yMin, max, yMax, initial, yInitial);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | 1cba20fefacd7f39100fa7287b4a7232bec15914cf6f634fbfe9c3991d2ea81b | public Paint getPaint(double value) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a paint for the specified value.
*
* @param value the value (must be within the range specified by the
* lower and upper bounds for the scale).
*
* @return A paint for the specified value.
*/
public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((v - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
}
```
| public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((v - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a paint for the specified value.
*
* @param value the value (must be within the range specified by the
* lower and upper bounds for the scale).
*
* @return A paint for the specified value.
*/
public Paint getPaint(double value) {
double v = Math.max(value, this.lowerBound);
v = Math.min(v, this.upperBound);
int g = (int) ((v - this.lowerBound) / (this.upperBound
- this.lowerBound) * 255.0);
return new Color(g, g, g);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
14 | 1cd43e03198cbd0117bcfea48b7b18c507cd6a597316bc0797259ce97cdd2f03 | private static Node computeFollowNode(
Node fromNode, Node node, ControlFlowAnalysis cfa) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Computes the follow() node of a given node and its parent. There is a side
* effect when calling this function. If this function computed an edge that
* exists a FINALLY, it'll attempt to connect the fromNode to the outer
* FINALLY according to the finallyMap.
*
* @param fromNode The original source node since {@code node} is changed
* during recursion.
* @param node The node that follow() should compute.
*/
private static Node computeFollowNode(
Node fromNode, Node node, ControlFlowAnalysis cfa) {
/*
* This is the case where:
*
* 1. Parent is null implies that we are transferring control to the end of
* the script.
*
* 2. Parent is a function implies that we are transferring control back to
* the caller of the function.
*
* 3. If the node is a return statement, we should also transfer control
* back to the caller of the function.
*
* 4. If the node is root then we have reached the end of what we have been
* asked to traverse.
*
* In all cases we should transfer control to a "symbolic return" node.
* This will make life easier for DFAs.
*/
Node parent = node.getParent();
if (parent == null || parent.isFunction() ||
(cfa != null && node == cfa.root)) {
return null;
}
// If we are just before a IF/WHILE/DO/FOR:
switch (parent.getType()) {
// The follow() of any of the path from IF would be what follows IF.
case Token.IF:
return computeFollowNode(fromNode, parent, cfa);
case Token.CASE:
case Token.DEFAULT_CASE:
// After the body of a CASE, the control goes to the body of the next
// case, without having to go to the case condition.
if (parent.getNext() != null) {
if (parent.getNext().isCase()) {
return parent.getNext().getFirstChild().getNext();
} else if (parent.getNext().isDefaultCase()) {
return parent.getNext().getFirstChild();
} else {
Preconditions.checkState(false, "Not reachable");
}
} else {
return computeFollowNode(fromNode, parent, cfa);
}
break;
case Token.FOR:
if (NodeUtil.isForIn(parent)) {
return parent;
} else {
return parent.getFirstChild().getNext().getNext();
}
case Token.WHILE:
case Token.DO:
return parent;
case Token.TRY:
// If we are coming out of the TRY block...
if (parent.getFirstChild() == node) {
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(parent.getLastChild());
} else { // and have no FINALLY.
return computeFollowNode(fromNode, parent, cfa);
}
// CATCH block.
} else if (NodeUtil.getCatchBlock(parent) == node){
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(node.getNext());
} else {
return computeFollowNode(fromNode, parent, cfa);
}
// If we are coming out of the FINALLY block...
} else if (parent.getLastChild() == node){
if (cfa != null) {
for (Node finallyNode : cfa.finallyMap.get(parent)) {
cfa.createEdge(fromNode, Branch.UNCOND, finallyNode);
}
}
return computeFollowNode(fromNode, parent, cfa);
}
}
// Now that we are done with the special cases follow should be its
// immediate sibling, unless its sibling is a function
Node nextSibling = node.getNext();
// Skip function declarations because control doesn't get pass into it.
while (nextSibling != null && nextSibling.isFunction()) {
nextSibling = nextSibling.getNext();
}
if (nextSibling != null) {
return computeFallThrough(nextSibling);
} else {
// If there are no more siblings, control is transferred up the AST.
return computeFollowNode(fromNode, parent, cfa);
}
}
```
| private static Node computeFollowNode(
Node fromNode, Node node, ControlFlowAnalysis cfa) {
/*
* This is the case where:
*
* 1. Parent is null implies that we are transferring control to the end of
* the script.
*
* 2. Parent is a function implies that we are transferring control back to
* the caller of the function.
*
* 3. If the node is a return statement, we should also transfer control
* back to the caller of the function.
*
* 4. If the node is root then we have reached the end of what we have been
* asked to traverse.
*
* In all cases we should transfer control to a "symbolic return" node.
* This will make life easier for DFAs.
*/
Node parent = node.getParent();
if (parent == null || parent.isFunction() ||
(cfa != null && node == cfa.root)) {
return null;
}
// If we are just before a IF/WHILE/DO/FOR:
switch (parent.getType()) {
// The follow() of any of the path from IF would be what follows IF.
case Token.IF:
return computeFollowNode(fromNode, parent, cfa);
case Token.CASE:
case Token.DEFAULT_CASE:
// After the body of a CASE, the control goes to the body of the next
// case, without having to go to the case condition.
if (parent.getNext() != null) {
if (parent.getNext().isCase()) {
return parent.getNext().getFirstChild().getNext();
} else if (parent.getNext().isDefaultCase()) {
return parent.getNext().getFirstChild();
} else {
Preconditions.checkState(false, "Not reachable");
}
} else {
return computeFollowNode(fromNode, parent, cfa);
}
break;
case Token.FOR:
if (NodeUtil.isForIn(parent)) {
return parent;
} else {
return parent.getFirstChild().getNext().getNext();
}
case Token.WHILE:
case Token.DO:
return parent;
case Token.TRY:
// If we are coming out of the TRY block...
if (parent.getFirstChild() == node) {
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(parent.getLastChild());
} else { // and have no FINALLY.
return computeFollowNode(fromNode, parent, cfa);
}
// CATCH block.
} else if (NodeUtil.getCatchBlock(parent) == node){
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(node.getNext());
} else {
return computeFollowNode(fromNode, parent, cfa);
}
// If we are coming out of the FINALLY block...
} else if (parent.getLastChild() == node){
if (cfa != null) {
for (Node finallyNode : cfa.finallyMap.get(parent)) {
cfa.createEdge(fromNode, Branch.UNCOND, finallyNode);
}
}
return computeFollowNode(fromNode, parent, cfa);
}
}
// Now that we are done with the special cases follow should be its
// immediate sibling, unless its sibling is a function
Node nextSibling = node.getNext();
// Skip function declarations because control doesn't get pass into it.
while (nextSibling != null && nextSibling.isFunction()) {
nextSibling = nextSibling.getNext();
}
if (nextSibling != null) {
return computeFallThrough(nextSibling);
} else {
// If there are no more siblings, control is transferred up the AST.
return computeFollowNode(fromNode, parent, cfa);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Computes the follow() node of a given node and its parent. There is a side
* effect when calling this function. If this function computed an edge that
* exists a FINALLY, it'll attempt to connect the fromNode to the outer
* FINALLY according to the finallyMap.
*
* @param fromNode The original source node since {@code node} is changed
* during recursion.
* @param node The node that follow() should compute.
*/
private static Node computeFollowNode(
Node fromNode, Node node, ControlFlowAnalysis cfa) {
/*
* This is the case where:
*
* 1. Parent is null implies that we are transferring control to the end of
* the script.
*
* 2. Parent is a function implies that we are transferring control back to
* the caller of the function.
*
* 3. If the node is a return statement, we should also transfer control
* back to the caller of the function.
*
* 4. If the node is root then we have reached the end of what we have been
* asked to traverse.
*
* In all cases we should transfer control to a "symbolic return" node.
* This will make life easier for DFAs.
*/
Node parent = node.getParent();
if (parent == null || parent.isFunction() ||
(cfa != null && node == cfa.root)) {
return null;
}
// If we are just before a IF/WHILE/DO/FOR:
switch (parent.getType()) {
// The follow() of any of the path from IF would be what follows IF.
case Token.IF:
return computeFollowNode(fromNode, parent, cfa);
case Token.CASE:
case Token.DEFAULT_CASE:
// After the body of a CASE, the control goes to the body of the next
// case, without having to go to the case condition.
if (parent.getNext() != null) {
if (parent.getNext().isCase()) {
return parent.getNext().getFirstChild().getNext();
} else if (parent.getNext().isDefaultCase()) {
return parent.getNext().getFirstChild();
} else {
Preconditions.checkState(false, "Not reachable");
}
} else {
return computeFollowNode(fromNode, parent, cfa);
}
break;
case Token.FOR:
if (NodeUtil.isForIn(parent)) {
return parent;
} else {
return parent.getFirstChild().getNext().getNext();
}
case Token.WHILE:
case Token.DO:
return parent;
case Token.TRY:
// If we are coming out of the TRY block...
if (parent.getFirstChild() == node) {
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(parent.getLastChild());
} else { // and have no FINALLY.
return computeFollowNode(fromNode, parent, cfa);
}
// CATCH block.
} else if (NodeUtil.getCatchBlock(parent) == node){
if (NodeUtil.hasFinally(parent)) { // and have FINALLY block.
return computeFallThrough(node.getNext());
} else {
return computeFollowNode(fromNode, parent, cfa);
}
// If we are coming out of the FINALLY block...
} else if (parent.getLastChild() == node){
if (cfa != null) {
for (Node finallyNode : cfa.finallyMap.get(parent)) {
cfa.createEdge(fromNode, Branch.UNCOND, finallyNode);
}
}
return computeFollowNode(fromNode, parent, cfa);
}
}
// Now that we are done with the special cases follow should be its
// immediate sibling, unless its sibling is a function
Node nextSibling = node.getNext();
// Skip function declarations because control doesn't get pass into it.
while (nextSibling != null && nextSibling.isFunction()) {
nextSibling = nextSibling.getNext();
}
if (nextSibling != null) {
return computeFallThrough(nextSibling);
} else {
// If there are no more siblings, control is transferred up the AST.
return computeFollowNode(fromNode, parent, cfa);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |