message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,147 | 0 | 68,294 |
"Correct Solution:
```
n, l = map(int, input().split())
s = sorted([input() for _ in range(n)])
print(*s, sep='')
``` | output | 1 | 34,147 | 0 | 68,295 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,148 | 0 | 68,296 |
"Correct Solution:
```
n,l=input().split();s=[input() for _ in range(int(n))];print("".join(sorted(s)))
``` | output | 1 | 34,148 | 0 | 68,297 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,149 | 0 | 68,298 |
"Correct Solution:
```
n, l = map(int,input().split())
print(''.join(sorted([input() for _ in range(n)])))
``` | output | 1 | 34,149 | 0 | 68,299 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,150 | 0 | 68,300 |
"Correct Solution:
```
N,L=map(int,input().split());print(''.join(sorted([input() for _ in range(N)])))
``` | output | 1 | 34,150 | 0 | 68,301 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,151 | 0 | 68,302 |
"Correct Solution:
```
a, b = map(int, input().split())
print("".join(sorted([input() for _ in range(a)])))
``` | output | 1 | 34,151 | 0 | 68,303 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,152 | 0 | 68,304 |
"Correct Solution:
```
N,L=map(int,input().split())
S=sorted(list(input() for _ in range(N)))
print("".join(S))
``` | output | 1 | 34,152 | 0 | 68,305 |
Provide a correct Python 3 solution for this coding contest problem.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx | instruction | 0 | 34,153 | 0 | 68,306 |
"Correct Solution:
```
n,l = map(int, input().split())
print("".join(sorted([input() for _ in range(n)])))
``` | output | 1 | 34,153 | 0 | 68,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n,l=map(int,input().split())
a=[input() for _ in range(n)]
a.sort()
print(*a,sep="")
``` | instruction | 0 | 34,154 | 0 | 68,308 |
Yes | output | 1 | 34,154 | 0 | 68,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n, l = map(int, input().split())
print(*sorted([input() for _ in range(n)]), sep='')
``` | instruction | 0 | 34,155 | 0 | 68,310 |
Yes | output | 1 | 34,155 | 0 | 68,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n,l =map(int,input().split())
x = sorted(input() for _ in range(n))
print(*x,sep="")
``` | instruction | 0 | 34,156 | 0 | 68,312 |
Yes | output | 1 | 34,156 | 0 | 68,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n,l = map(int,input().split())
S = sorted([input() for _ in range(n)])
print(*S,sep="")
``` | instruction | 0 | 34,157 | 0 | 68,314 |
Yes | output | 1 | 34,157 | 0 | 68,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n,l = map(int, input().split())
s = [input() for _ in range(n)]
print(sorted(s))
``` | instruction | 0 | 34,158 | 0 | 68,316 |
No | output | 1 | 34,158 | 0 | 68,317 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
n,l=map(int,input().split())
li=[input() for i in range(n)]
sortli=sorted(li)
print("{}{}{}".format(sortli[0],sortli[1],sortli[2]))
``` | instruction | 0 | 34,159 | 0 | 68,318 |
No | output | 1 | 34,159 | 0 | 68,319 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
import itertools
N,L,*s = open(0).read().split()
x = list(map(lambda x:"".join(x), itertools.permutations(s, int(N))))
min_str = x[0]
for s in x[1:]:
if s < min_str:
min_str = s
print(min_str)
``` | instruction | 0 | 34,160 | 0 | 68,320 |
No | output | 1 | 34,160 | 0 | 68,321 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iroha has a sequence of N strings S_1, S_2, ..., S_N. The length of each string is L.
She will concatenate all of the strings in some order, to produce a long string.
Among all strings that she can produce in this way, find the lexicographically smallest one.
Here, a string s=s_1s_2s_3...s_n is lexicographically smaller than another string t=t_1t_2t_3...t_m if and only if one of the following holds:
* There exists an index i(1≦i≦min(n,m)), such that s_j = t_j for all indices j(1≦j<i), and s_i<t_i.
* s_i = t_i for all integers i(1≦i≦min(n,m)), and n<m.
Constraints
* 1 ≦ N, L ≦ 100
* For each i, the length of S_i equals L.
* For each i, S_i consists of lowercase letters.
Input
The input is given from Standard Input in the following format:
N L
S_1
S_2
:
S_N
Output
Print the lexicographically smallest string that Iroha can produce.
Example
Input
3 3
dxx
axx
cxx
Output
axxcxxdxx
Submitted Solution:
```
l,n=map(int,input().split())
list=[]
for _ in range(n):
list.append(input())
list.sort()
ans=""
for i in list:
ans+=i
print(ans)
``` | instruction | 0 | 34,161 | 0 | 68,322 |
No | output | 1 | 34,161 | 0 | 68,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,732 | 0 | 69,464 |
Tags: combinatorics, strings
Correct Solution:
```
import sys
a = input()
b = input()
l1 = len(a)
one = [0]*len(b)
zero = [0]*len(b)
cnt = cnt1 = cnt0 = 0
for i in range(len(b)):
if b[i] == '1':
cnt1 += 1
elif b[i] == '0':
cnt0 += 1
one[i] = cnt1
zero[i] = cnt0
last = len(b) - len(a)
first = -1
for i in range(l1):
if a[i] == '0':
if i == 0:
cnt += one[last]
else:
cnt += one[last] - one[first]
elif a[i] == '1':
if i == 0:
cnt += zero[last]
else:
cnt += zero[last] - zero[first]
first += 1
last += 1
print(cnt)
``` | output | 1 | 34,732 | 0 | 69,465 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,733 | 0 | 69,466 |
Tags: combinatorics, strings
Correct Solution:
```
sub = input().rstrip()
s = input().rstrip()
def sumRange(left, right):
return psums[right + 1] - psums[left]
n = len(s)
subSize = len(sub)
psums = [0]
for i, ch in enumerate(sub):
psums.append(psums[-1] + int(ch))
ret = 0
for i in range(len(s)):
ch = s[i]
left = max(0, i + subSize - n)
right = min(i, subSize - 1)
oneCnt = sumRange(left, right)
size = right - left + 1
ret += oneCnt if ch == '0' else size - oneCnt
print(ret)
``` | output | 1 | 34,733 | 0 | 69,467 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,734 | 0 | 69,468 |
Tags: combinatorics, strings
Correct Solution:
```
import math
import itertools
a = [int(x) for x in input().rstrip()]
b = [int(x) for x in input().rstrip()]
n = len(a)
m = len(b)
prefix_b = [0] + list(itertools.accumulate(b))
res = 0
for i in range(n):
ones = prefix_b[-n+i] - prefix_b[i]
res += m-n+1 - ones if a[i] else ones
print(res)
``` | output | 1 | 34,734 | 0 | 69,469 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,735 | 0 | 69,470 |
Tags: combinatorics, strings
Correct Solution:
```
a=[int(x) for x in input().strip()]
b=[int(x) for x in input().strip()]
c=[[b[0]^1]+[0]*(len(b)-1), [b[0]]+[0]*(len(b)-1)]
for i in range(1,len(b)):
c[0][i]=c[0][i-1]+(b[i]^1)
for i in range(1,len(b)):
c[1][i]=c[1][i-1]+b[i]
ans=0
for x in range(len(a)):
ans+=c[a[x]^1][x+len(b)-len(a)]-(c[a[x]^1][x-1] if x!=0 else 0)
print(ans)
``` | output | 1 | 34,735 | 0 | 69,471 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,736 | 0 | 69,472 |
Tags: combinatorics, strings
Correct Solution:
```
a=input();b=input();c=[0];s=0;ans=0
for i in range(len(b)):
s+=int(b[i])
c.append(s)
x=len(b)-len(a)+1
for i in range(len(a)):
if a[i]=='0':
ans+=c[x+i]-c[i]
else:
ans+=x-c[x+i]+c[i]
print(ans)
``` | output | 1 | 34,736 | 0 | 69,473 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,737 | 0 | 69,474 |
Tags: combinatorics, strings
Correct Solution:
```
a = list(input())
b = list(input())
sum = 0
for i in range(len(a)):
sum += int(a[i])
a[i] = sum
a.insert(0, 0)
sum = 0
for i in range(len(b)):
l = max(0, len(a) - 1 - (len(b) - i))
r = min(len(a) - 2, i)
col1 = a[r + 1] - a[l]
col2 = r - l + 1 - col1
if b[i] == '0':
sum += col1
else:
sum += col2
print(sum)
``` | output | 1 | 34,737 | 0 | 69,475 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,738 | 0 | 69,476 |
Tags: combinatorics, strings
Correct Solution:
```
import sys
a = input()
b = input()
sums = []
for i in range(len(b)):
sums.append(ord(b[i]) - ord('0'))
if len(sums) >= 2:
sums[-1] += sums[-2]
ans = 0
for i in range(len(a)):
onenum = sums[len(b) - len(a) +i]
if i > 0:
onenum -= sums[i-1]
if a[i] == '1':
ans += len(b) - len(a) - onenum + 1
else:
ans += onenum
print(ans)
``` | output | 1 | 34,738 | 0 | 69,477 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement. | instruction | 0 | 34,739 | 0 | 69,478 |
Tags: combinatorics, strings
Correct Solution:
```
from sys import stdin,stdout
# input=stdin.readline
mod=10**9+7
t=1
for _ in range(t):
a=input()
b=input()
n=len(a)
m=len(b)
dp=[[0 for i in range(2)] for j in range(m+1)]
dp[1][0]=int(b[0])^1
dp[1][1]=int(b[0])
for i in range(2,m+1):
dp[i][0]=dp[i-1][0]+(int(b[i-1])^1)
dp[i][1]=dp[i-1][1]+int(b[i-1])
ans=0
for i in range(n):
count0=dp[m-n+i+1][0]-dp[i][0]
count1=dp[m-n+i+1][1]-dp[i][1]
ans+=count0*int(a[i])+count1*(int(a[i])^1)
print(ans)
``` | output | 1 | 34,739 | 0 | 69,479 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
a = input()
b = input()
num_n = [0]
num_one = [0]
for elem in a:
if elem == '1':
num_one.append(num_one[-1] + 1)
num_n.append(num_n[-1])
else:
num_one.append(num_one[-1])
num_n.append(num_n[-1] + 1)
res = 0
la = len(a)
lb = len(b)
for i in range(lb):
left = max(0, i - lb + la)
right = min(la - 1, i)
if b[i] == '1':
res += num_n[right + 1] - num_n[left]
else:
res += num_one[right + 1] - num_one[left]
print(res)
``` | instruction | 0 | 34,740 | 0 | 69,480 |
Yes | output | 1 | 34,740 | 0 | 69,481 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
a=input()
b=input()
l1=len(a)
l2=len(b)
pre_sum=[0]*l2
pre_sum[0]=b[0].count('1')
for i in range(1,l2):
if b[i]=='1':
pre_sum[i]=pre_sum[i-1]+1
else:
pre_sum[i]=pre_sum[i-1]
ans=0
if a[0]=='0':
ans+=pre_sum[l2-l1]
else:
ans+=(l2-l1+1-pre_sum[l2-l1])
for i in range(1,l1):
x=pre_sum[l2-l1+i]-pre_sum[i-1]
if a[i]=='0':
ans+=x
else:
ans+=(l2-l1+1-x)
print(ans)
``` | instruction | 0 | 34,741 | 0 | 69,482 |
Yes | output | 1 | 34,741 | 0 | 69,483 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
a = input()
b = input()
cs = [0]
for ch in b:
cs.append(cs[-1] + (ch == '1'))
diff = len(b) - len(a)
ans = 0
for idx, ch in enumerate(a):
ones = cs[idx+diff +1] - cs[idx-1 +1]
zeros = diff+1 - ones
if ch == '1':
ans += zeros
else:
ans += ones
print(ans)
``` | instruction | 0 | 34,742 | 0 | 69,484 |
Yes | output | 1 | 34,742 | 0 | 69,485 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
import sys
if False:
inp = open('B.txt', 'r')
else:
inp = sys.stdin
count = [0]
a = inp.readline().strip()
b = inp.readline().strip()
for i in range(len(b)):
count.append(count[i] + int(b[i]))
lengthA = len(a)
lengthB = len(b)
ans = 0
for i in range(lengthA):
if a[i] == '0':
ans += count[lengthB + i - lengthA + 1] - count[i]
else:
ans += lengthB - lengthA + 1 - count[lengthB + i - lengthA + 1] + count[i]
print(ans)
``` | instruction | 0 | 34,743 | 0 | 69,486 |
Yes | output | 1 | 34,743 | 0 | 69,487 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
s1=input()
s2=input()
x=len(s1)
is1=int(s1,2)
su=0
p=2**x
# implement rolling hash
st=int(s2[0:x],2)
su=0
x=len(s2)-x+1
su=bin(is1^st).count('1')
for i in range(1,x):
st=st-int(s2[i-1])*p
st=st*2+int(s2[i+1])
su=su+bin(is1^st).count('1')
print(su)
``` | instruction | 0 | 34,744 | 0 | 69,488 |
No | output | 1 | 34,744 | 0 | 69,489 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
from math import sqrt
a=input()
b=input()
lb=len(b)
la=len(a)
c0=0
c1=0
c=[ [b[0:lb-la+1].count('0'), b[0:lb-la+1].count('1')] ]
s=0
if la==lb:
for i in range(la):
if a[i]!=b[i]: s+=1
print(s)
else:
for i in range(1, la):
c.append(c[i-1])
if b[i-1]==b[i+lb-la]:
pass
elif int(b[i-1])>int(b[i+lb-la]):
c[i][1]-=1
c[i][0]+=1
else:
c[i][0]-=1
c[i][1]+-1
print(c)
for i in range(la):
if a[i]=='0': s+=c[i][1]
else: s+=c[i][0]
print(s)
``` | instruction | 0 | 34,745 | 0 | 69,490 |
No | output | 1 | 34,745 | 0 | 69,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
def sub(a, b):
c = int(a) - int(b)
if c < 0:
c = -c
return sum(int(digit) for digit in str(c))
pattern = input()
string = input()
sumt = 0
already = []
costs = []
for i in range(len(string) - len(pattern) + 1):
now = string[i:i+len(pattern)]
if now in already:
sumt += costs[already.index(now)]
else:
already.append(now)
a = sub(pattern, string[i:i+len(pattern)])
costs.append(a)
sumt += a
print(sumt)
``` | instruction | 0 | 34,746 | 0 | 69,492 |
No | output | 1 | 34,746 | 0 | 69,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as <image>, where si is the i-th character of s and ti is the i-th character of t. For example, the Hamming distance between string "0011" and string "0110" is |0 - 0| + |0 - 1| + |1 - 1| + |1 - 0| = 0 + 1 + 0 + 1 = 2.
Given two binary strings a and b, find the sum of the Hamming distances between a and all contiguous substrings of b of length |a|.
Input
The first line of the input contains binary string a (1 ≤ |a| ≤ 200 000).
The second line of the input contains binary string b (|a| ≤ |b| ≤ 200 000).
Both strings are guaranteed to consist of characters '0' and '1' only.
Output
Print a single integer — the sum of Hamming distances between a and all contiguous substrings of b of length |a|.
Examples
Input
01
00111
Output
3
Input
0011
0110
Output
2
Note
For the first sample case, there are four contiguous substrings of b of length |a|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts twice, as there are two occurrences of string "11". The sum of these edit distances is 1 + 0 + 1 + 1 = 3.
The second sample case is described in the statement.
Submitted Solution:
```
from collections import deque
a = (input())
b = (input())
n = len(a)
m = len(b)
if (n == m):
s = 0
for j in range(m):
r = abs(int(b[j]) - int(a[j]))
s += r
print(s)
exit(0)
i = 0
d = deque()
smm = deque()
while(True):
s = b[i : i + n]
sm = 0
if len(s) == n :
for j in range(len(s)):
r = abs(int(s[j]) - int(a[j]))
sm += r
smm.append(sm)
i = i + n - 1
if (i >= m):
break
print(sum(smm))
``` | instruction | 0 | 34,747 | 0 | 69,494 |
No | output | 1 | 34,747 | 0 | 69,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,556 | 0 | 71,112 |
Tags: math, strings
Correct Solution:
```
n = int(input())
s = input()
a = [0] * 300
for i in s:
a[ord(i)] += 1
print((a.count(max(a)) ** len(s)) % (10**9 + 7))
``` | output | 1 | 35,556 | 0 | 71,113 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,557 | 0 | 71,114 |
Tags: math, strings
Correct Solution:
```
from itertools import groupby
try:
while True:
n, s = int(input()), input()
L = groupby(sorted(list(s), key = ord), lambda x : x)
L = [len(tuple(v)) for u, v in L]
print(pow(sum(1 for u in L if u == max(L)), n, int(1e9 + 7)))
except:
pass
``` | output | 1 | 35,557 | 0 | 71,115 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,558 | 0 | 71,116 |
Tags: math, strings
Correct Solution:
```
n=int(input())
s=input()
x=[s.count(i) for i in ['A','C','G','T']]
z=x.count(max(x))
print((z**n)%(10**9+7))
``` | output | 1 | 35,558 | 0 | 71,117 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,559 | 0 | 71,118 |
Tags: math, strings
Correct Solution:
```
from random import randint, choice
MOD = 10 ** 9 + 7
fact = [1]
for i in range(1, 500):
fact.append(fact[-1] * i)
def stupid(s):
n = len(s)
d = dict()
for x in 'ACGT':
d[x] = s.count(x)
mx = -1
cnt = 0
for a in range(n + 1):
for c in range(n - a + 1):
for g in range(n - a - c + 1):
cur = fact[n] // fact[a] // fact[g] // fact[c] // fact[n - a - c - g]
val = d['A'] * a + d['C'] * c + d['G'] * g + d['T'] * (n - a - c - g)
val *= n
if val > mx:
mx = val
cnt = cur
elif val == mx:
cnt += cur
return (mx, cnt)
def check_dist():
while True:
n = randint(1, 100)
s = ''
for i in range(n):
s += choice('ACGT')
if stupid(s)[0] == max(s.count(x) for x in 'ACGT') * n * n:
print('OK')
else:
print('WA')
print(s)
break
n = int(input())
s = input()
cnt = dict()
for x in 'ACGT':
cnt[x] = s.count(x)
mx = max(cnt.values())
r = list(cnt.values()).count(mx)
print(pow(r, n, MOD))
``` | output | 1 | 35,559 | 0 | 71,119 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,560 | 0 | 71,120 |
Tags: math, strings
Correct Solution:
```
from collections import Counter
n = int(input())
c = Counter(input())
commons = c.most_common()
max_cnt = 0
for x in commons:
if commons[0][1] == x[1]:
max_cnt += 1
ans = 1
for i in range(n):
ans *= max_cnt
ans = ans % (1000000007)
print(ans)
``` | output | 1 | 35,560 | 0 | 71,121 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,561 | 0 | 71,122 |
Tags: math, strings
Correct Solution:
```
n = int(input())
s = input()
arr, t = [0 for i in range(4)], "AGCT"
for i in range(n):
for j in range(4):
if s[i] == t[j]:
arr[j] += 1
mx, c = 0, 0
for i in range(4): mx = max(mx, arr[i])
for i in range(4): c += (mx == arr[i])
res = 1
for i in range(n): res = (res * c) % 1000000007
print(res)
``` | output | 1 | 35,561 | 0 | 71,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,562 | 0 | 71,124 |
Tags: math, strings
Correct Solution:
```
numero=int(input())
letras = input()
lista=list(letras)
a=lista.count("A")
t=lista.count("T")
g=lista.count("G")
c=lista.count("C")
numeroSig=max(a,t,g,c)
listaACGT=[a,t,g,c]
z=0
for i in listaACGT:
if(i==numeroSig):
z+=1
print(pow(z, numero, 1000000007))
``` | output | 1 | 35,562 | 0 | 71,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27 | instruction | 0 | 35,563 | 0 | 71,126 |
Tags: math, strings
Correct Solution:
```
n, s = input(), input()
a = {'A' : 0, 'C' : 1, 'G' : 2, 'T' : 3}
A = [0, 0, 0, 0]
for x in s:
A[a[x]] += 1
MOD = 10 ** 9 + 7
print((A.count(max(A)) ** len(s)) % MOD)
``` | output | 1 | 35,563 | 0 | 71,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
n = int(input())
s = input()
dflt = "ACGT"
a = []
a.append(s.count(dflt[0]))
a.append(s.count(dflt[1]))
a.append(s.count(dflt[2]))
a.append(s.count(dflt[3]))
k = 1
max = a[0]
for i in range(1, 4):
if a[i] > max:
k = 1
max = a[i]
elif a[i] == max:
k += 1
print((k ** n) % (10 ** 9 + 7))
``` | instruction | 0 | 35,564 | 0 | 71,128 |
Yes | output | 1 | 35,564 | 0 | 71,129 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
n, s = int(input()), input()
c = sorted(s.count(b) for b in 'ACGT')
print(c.count(c[-1]) ** n % (10 ** 9 + 7))
# Made By Mostafa_Khaled
``` | instruction | 0 | 35,565 | 0 | 71,130 |
Yes | output | 1 | 35,565 | 0 | 71,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
n = int(input())
s = input()
lst = {'A' : 0, 'C' : 0, 'G' : 0, 'T' : 0}
k, l = 0, 1
for i in s:
lst[i] += 1
if k < lst[i]:
k = lst[i]
l = 1
else:
if k == lst[i]:
l += 1
print(l ** n % (10 ** 9 + 7))
``` | instruction | 0 | 35,566 | 0 | 71,132 |
Yes | output | 1 | 35,566 | 0 | 71,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
n = int(input())
code = str(input()).upper()
cont = [0]*4
cont[0] = code.count("A")
cont[1] = code.count("C")
cont[2] = code.count("G")
cont[3] = code.count("T")
modulo = 1000000007
res = cont.count(max(cont))
print(res ** n % modulo)
``` | instruction | 0 | 35,567 | 0 | 71,134 |
Yes | output | 1 | 35,567 | 0 | 71,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
numero=int(input())
letras=input()
unicos=len(set(letras))
print(pow(unicos,numero))
``` | instruction | 0 | 35,568 | 0 | 71,136 |
No | output | 1 | 35,568 | 0 | 71,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
import itertools
n=int(input())
string=input()
counter=0
for i in range(n,0,-1):
a=set(itertools.permutations(string,i))
counter+=len(a)
print(counter)
``` | instruction | 0 | 35,569 | 0 | 71,138 |
No | output | 1 | 35,569 | 0 | 71,139 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
import math
import itertools
a=input()
b=input()
countA=0
countC=0
countG=0
countT=0
for i in b:
if i == 'A':
countA+=1
elif i == 'C':
countC+=1
elif i == 'G':
countG+=1
elif i == 'T':
countT+=1
if countA==0 and countC==0 and countG==0:
print (1)
elif countA==0 and countC==0 and countT==0:
print(1)
elif countG==0 and countC==0 and countT==0:
print(1)
elif countA==0 and countG==0 and countT==0:
print(1)
else:
x=list(itertools.permutations(b))
print(len(x)*2)
``` | instruction | 0 | 35,570 | 0 | 71,140 |
No | output | 1 | 35,570 | 0 | 71,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a new method for determining the similarity of cyclic sequences.
Let's assume that strings s and t have the same length n, then the function h(s, t) is defined as the number of positions in which the respective symbols of s and t are the same. Function h(s, t) can be used to define the function of Vasya distance ρ(s, t):
<image> where <image> is obtained from string s, by applying left circular shift i times. For example, ρ("AGC", "CGT") = h("AGC", "CGT") + h("AGC", "GTC") + h("AGC", "TCG") + h("GCA", "CGT") + h("GCA", "GTC") + h("GCA", "TCG") + h("CAG", "CGT") + h("CAG", "GTC") + h("CAG", "TCG") = 1 + 1 + 0 + 0 + 1 + 1 + 1 + 0 + 1 = 6
Vasya found a string s of length n on the Internet. Now he wants to count how many strings t there are such that the Vasya distance from the string s attains maximum possible value. Formally speaking, t must satisfy the equation: <image>.
Vasya could not try all possible strings to find an answer, so he needs your help. As the answer may be very large, count the number of such strings modulo 109 + 7.
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 105).
The second line of the input contains a single string of length n, consisting of characters "ACGT".
Output
Print a single number — the answer modulo 109 + 7.
Examples
Input
1
C
Output
1
Input
2
AG
Output
4
Input
3
TTT
Output
1
Note
Please note that if for two distinct strings t1 and t2 values ρ(s, t1) и ρ(s, t2) are maximum among all possible t, then both strings must be taken into account in the answer even if one of them can be obtained by a circular shift of another one.
In the first sample, there is ρ("C", "C") = 1, for the remaining strings t of length 1 the value of ρ(s, t) is 0.
In the second sample, ρ("AG", "AG") = ρ("AG", "GA") = ρ("AG", "AA") = ρ("AG", "GG") = 4.
In the third sample, ρ("TTT", "TTT") = 27
Submitted Solution:
```
from collections import Counter
n = int(input())
c = Counter(input())
commons = c.most_common()
max_cnt = 0
for x in commons:
if commons[0][1] == x[1]:
max_cnt += x[1]
ans = 1
for i in range(n):
ans *= max_cnt
ans = ans % (1000000007)
print(ans)
``` | instruction | 0 | 35,571 | 0 | 71,142 |
No | output | 1 | 35,571 | 0 | 71,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input
The first and only line of input contains a single nonempty string s of length at most 1000 composed of lowercase letters (a-z).
Output
Output YES if the string s contains heidi as a subsequence and NO otherwise.
Examples
Input
abcheaibcdi
Output
YES
Input
hiedi
Output
NO
Note
A string s contains another string p as a subsequence if it is possible to delete some characters from s and obtain p. | instruction | 0 | 35,661 | 0 | 71,322 |
Tags: implementation, strings
Correct Solution:
```
s = input()
i = -1
for ch in 'heidi':
i = s.find(ch, i+1)
if i < 0:
print('NO')
break
else:
print('YES')
``` | output | 1 | 35,661 | 0 | 71,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input
The first and only line of input contains a single nonempty string s of length at most 1000 composed of lowercase letters (a-z).
Output
Output YES if the string s contains heidi as a subsequence and NO otherwise.
Examples
Input
abcheaibcdi
Output
YES
Input
hiedi
Output
NO
Note
A string s contains another string p as a subsequence if it is possible to delete some characters from s and obtain p. | instruction | 0 | 35,662 | 0 | 71,324 |
Tags: implementation, strings
Correct Solution:
```
n=input()
a='heidi'
count=i=0
while i<len(n):
if a[count]==n[i]:
count+=1
i+=1
if count==5:
break
if count==5 and i<=len(n):
print('YES')
else:
print('NO')
``` | output | 1 | 35,662 | 0 | 71,325 |
Provide tags and a correct Python 3 solution for this coding contest problem.
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input
The first and only line of input contains a single nonempty string s of length at most 1000 composed of lowercase letters (a-z).
Output
Output YES if the string s contains heidi as a subsequence and NO otherwise.
Examples
Input
abcheaibcdi
Output
YES
Input
hiedi
Output
NO
Note
A string s contains another string p as a subsequence if it is possible to delete some characters from s and obtain p. | instruction | 0 | 35,664 | 0 | 71,328 |
Tags: implementation, strings
Correct Solution:
```
ch = input()
ch1 = ['h','e','i','d','i']
i=0; j=0;
while(i<len(ch) and j<5):
if(ch[i]==ch1[j]): j+=1;
i+=1
if(j==5): print("YES")
else: print("NO")
``` | output | 1 | 35,664 | 0 | 71,329 |
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