message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
s=input()
d={}
k=int(input())
for x in s:
if x in d:
d[x] += 1
else:
d[x] = 1
while len(d):
x = min(d,key=d.get)
if k>=d[x]:
k -= d[x]
del d[x]
else:
break
ans = ''.join([x for x in s if x in d])
print(len(d),ans,sep='\n')
``` | instruction | 0 | 32,500 | 0 | 65,000 |
Yes | output | 1 | 32,500 | 0 | 65,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
s = input()
k = int(input())
l = {}
distinct = 0
for i in range(len(s)):
if ord(s[i])-97 not in l: distinct += 1; l[ord(s[i])-97] = 0
l[ord(s[i])-97] += 1
d = sorted([[l[i],i] for i in l.keys()])
for i in range(distinct):
if k>0:
k -= d[i][0]
if k >= 0: distinct -= 1; d[i][0] = 0; l[d[i][1]] = 0
else:break
else:break
print(max(distinct,0))
if distinct > 0:
for i in range(len(s)):
if l[ord(s[i])-97]: print(s[i],end="")
else:
print()
``` | instruction | 0 | 32,501 | 0 | 65,002 |
Yes | output | 1 | 32,501 | 0 | 65,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
def solve():
str0 = input()
k = int(input())
# print("str0 = ", str0)
# print("k = ", k)
if len(str0) < int(k):
print(0)
print()
exit()
dict = {}
for each in str0:
if each not in dict.keys():
dict[each] = 1
else:
dict[each] += 1
dict = sorted(dict.items(), key=lambda d: d[1])
delete_list = []
for i, each in enumerate(dict):
k -= each[1]
if k == 0:
# print(1)
delete_list.append(each[0])
# print("dict = ", len(dict))
print(len(dict) - i - 1)
for each_char in str0:
if each_char not in delete_list:
print(each_char, end='')
print()
break
elif k < 0:
# print(2)
print(len(dict) - i)
# delete_list.append(each[0])
# k = -k
# print("k = ", k)
for each_char in str0:
if each_char not in delete_list and each_char != each[0]:
print(each_char, end='')
if k < 0 and each_char == each[0]:
k += 1
# print("k = ", k)
print(each[0], end='')
print()
break
else:
delete_list.append(each[0])
# print(delete_list)
solve()
``` | instruction | 0 | 32,502 | 0 | 65,004 |
Yes | output | 1 | 32,502 | 0 | 65,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
import sys
import math
st = (sys.stdin.readline())
k = int(sys.stdin.readline())
d = dict()
alla = 0
for i in range(len(st) - 1):
if st[i] in d:
d[st[i]] += 1
else:
d[st[i]] = 1
alla += 1
f = sorted(d.items(), key = lambda x: x[1])
v = []
p = 0
for i in f:
if(k - i[1] >= 0):
v.append(i[0])
k -= i[1]
p += 1
else:
break
print(alla - p)
for i in range(len(st) - 1):
fl = False
for j in v:
if(st[i] == j):
fl = True
if(not fl):
sys.stdout.write(st[i])
``` | instruction | 0 | 32,503 | 0 | 65,006 |
Yes | output | 1 | 32,503 | 0 | 65,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
a = input()
Huruf = [0]*26
Banyak = [0]*26
Teks = ""
Maks =0
banyak = int(input())
for i in range (26):
Huruf[i] = chr(97+i)
for i in range(len(a)):
for j in range(len(Banyak)):
if(a[i] == Huruf[j]):
Banyak[j] += 1
for i in range(len(Banyak)):
if(banyak== 0):
Teks = a
if(int(Banyak[i])> 0):
Maks += 1
elif(int(Banyak[i])>= banyak):
Maks += int(Banyak[i])//banyak
Teks += Huruf[i]*int(Banyak[i])
print(Maks)
print(Teks)
``` | instruction | 0 | 32,504 | 0 | 65,008 |
No | output | 1 | 32,504 | 0 | 65,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
from collections import *
s = list(input())
k = int(input())
n = len(s)
if k >= n:
print(0)
print()
else:
lst = sorted(Counter(s).items(), key=s.count, reverse=True)[:n-k]
print(len(set(lst)))
d = defaultdict(int)
for i in range(len(lst)):
d[lst[i]] += 1
ans = ""
for i in range(n):
if d[s[i]]:
d[s[i]] -= 1
ans += s[i]
print(ans)
``` | instruction | 0 | 32,505 | 0 | 65,010 |
No | output | 1 | 32,505 | 0 | 65,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
import sys
import math
st = (sys.stdin.readline())
k = int(sys.stdin.readline())
d = dict()
for i in range(len(st) - 1):
if st[i] in d:
d[st[i]] += 1
else:
d[st[i]] = 1
f = sorted(d.items(), key = lambda x: x[1])
v = []
for i in f:
if(k - i[1] > 0):
v.append(i[0])
k -= i[1]
else:
break
res = []
for i in range(len(st) - 1):
fl = False
for j in v:
if(st[i] == j):
fl = True
if(not fl):
res.append(st[i])
print(len(d.items()) - len(v))
print("".join(res))
``` | instruction | 0 | 32,506 | 0 | 65,012 |
No | output | 1 | 32,506 | 0 | 65,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once when Gerald studied in the first year at school, his teacher gave the class the following homework. She offered the students a string consisting of n small Latin letters; the task was to learn the way the letters that the string contains are written. However, as Gerald is too lazy, he has no desire whatsoever to learn those letters. That's why he decided to lose some part of the string (not necessarily a connected part). The lost part can consist of any number of segments of any length, at any distance from each other. However, Gerald knows that if he loses more than k characters, it will be very suspicious.
Find the least number of distinct characters that can remain in the string after no more than k characters are deleted. You also have to find any possible way to delete the characters.
Input
The first input data line contains a string whose length is equal to n (1 ≤ n ≤ 105). The string consists of lowercase Latin letters. The second line contains the number k (0 ≤ k ≤ 105).
Output
Print on the first line the only number m — the least possible number of different characters that could remain in the given string after it loses no more than k characters.
Print on the second line the string that Gerald can get after some characters are lost. The string should have exactly m distinct characters. The final string should be the subsequence of the initial string. If Gerald can get several different strings with exactly m distinct characters, print any of them.
Examples
Input
aaaaa
4
Output
1
aaaaa
Input
abacaba
4
Output
1
aaaa
Input
abcdefgh
10
Output
0
Note
In the first sample the string consists of five identical letters but you are only allowed to delete 4 of them so that there was at least one letter left. Thus, the right answer is 1 and any string consisting of characters "a" from 1 to 5 in length.
In the second sample you are allowed to delete 4 characters. You cannot delete all the characters, because the string has length equal to 7. However, you can delete all characters apart from "a" (as they are no more than four), which will result in the "aaaa" string.
In the third sample you are given a line whose length is equal to 8, and k = 10, so that the whole line can be deleted. The correct answer is 0 and an empty string.
Submitted Solution:
```
import collections
s=input()
k=int(input())
d=dict()
for i in s:
if i in d:d[i]+=1
else:d[i]=1
d=sorted(d.items(), key=lambda x: x[1])
A=set()
ans=0
for i in d:
if k-i[1]>0:
A.add(i[0])
k-=i[1]
ans+=1
print(len(d)-ans)
for i in s:
if i not in A:
print(i,end="")
``` | instruction | 0 | 32,507 | 0 | 65,014 |
No | output | 1 | 32,507 | 0 | 65,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No | instruction | 0 | 32,667 | 0 | 65,334 |
Tags: data structures, hashing, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
MOD = 987654103
n = int(input())
t = input()
place = []
f1 = []
e1 = []
s = []
curr = 0
count1 = 0
for i in range(n):
c = t[i]
if c == '0':
if count1:
e1.append(i - 1)
if count1 & 1:
s.append(1)
curr += 1
e1.append(-1)
f1.append(-1)
count1 = 0
else:
f1.append(-1)
e1.append(-1)
place.append(curr)
curr += 1
s.append(0)
else:
if count1 == 0:
f1.append(i)
count1 += 1
place.append(curr)
if count1:
if count1 & 1:
s.append(1)
else:
s.append(0)
curr += 1
e1.append(n - 1)
e1.append(-1)
f1.append(-1)
place.append(curr)
pref = [0]
val = 0
for i in s:
val *= 3
val += i + 1
val %= MOD
pref.append(val)
q = int(input())
out = []
for _ in range(q):
l1, l2, leng = map(int, input().split())
l1 -= 1
l2 -= 1
starts = (l1, l2)
hashes = []
for start in starts:
end = start + leng - 1
smap = place[start]
emap = place[end]
if t[end] == '1':
emap -= 1
if s[smap] == 1:
smap += 1
prep = False
app = False
if t[start] == '1':
last = e1[place[start]]
last = min(last, end)
count = last - start + 1
if count % 2:
prep = True
if t[end] == '1':
first = f1[place[end]]
first = max(first, start)
count = end - first + 1
if count % 2:
app = True
preHash = 0
length = 0
if smap <= emap:
length = emap - smap + 1
preHash = pref[emap + 1]
preHash -= pref[smap] * pow(3, emap - smap + 1, MOD)
preHash %= MOD
if length == 0 and prep and app:
app = False
#print(preHash, prep, app, length)
if prep:
preHash += pow(3, length, MOD) * 2
length += 1
if app:
preHash *= 3
preHash += 2
#print(preHash)
preHash %= MOD
hashes.append(preHash)
if hashes[0] == hashes[1]:
out.append('Yes')
else:
out.append('No')
print('\n'.join(out))
``` | output | 1 | 32,667 | 0 | 65,335 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No | instruction | 0 | 32,668 | 0 | 65,336 |
Tags: data structures, hashing, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
t=input().strip()
q=int(input())
ZEROS=[0]*n
ZERO_ONE=[]
ONECOUNT=[0]*n
ind=0
count=0
for i in range(n):
ZEROS[i]=ind
if t[i]=="0":
ind+=1
ONECOUNT[i]=count%2
ZERO_ONE.append(count%2)
count=0
else:
count+=1
ONECOUNT[i]=count
ZEROS.append(ind)
S=ZERO_ONE
LEN=len(S)
p=2
import random
mod=random.randint(10**8,10**9)*2+1
mod2=random.randint(10**8,10**9)*2+1
mod3=random.randint(10**8,10**9)*2+1
mod4=random.randint(10**8,10**9)*2+1
TABLE=[0]
TABLE2=[0]
TABLE3=[0]
TABLE4=[0]
for i in range(LEN):
TABLE.append(p*TABLE[-1]%mod+S[i]%mod) # テーブルを埋める
TABLE2.append(p*TABLE2[-1]%mod2+S[i]%mod2) # テーブルを埋める
TABLE3.append(p*TABLE3[-1]%mod3+S[i]%mod2) # テーブルを埋める
TABLE4.append(p*TABLE4[-1]%mod4+S[i]%mod4) # テーブルを埋める
def hash_ij(i,j): # [i,j)のハッシュ値を求める
return (TABLE[j]-TABLE[i]*pow(p,j-i,mod))%mod
def hash_ij2(i,j): # [i,j)のハッシュ値を求める
return (TABLE2[j]-TABLE2[i]*pow(p,j-i,mod2))%mod2
def hash_ij3(i,j): # [i,j)のハッシュ値を求める
return (TABLE3[j]-TABLE3[i]*pow(p,j-i,mod3))%mod3
def hash_ij4(i,j): # [i,j)のハッシュ値を求める
return (TABLE4[j]-TABLE4[i]*pow(p,j-i,mod4))%mod4
def zcount(l,LEN):
return ZEROS[l+LEN]-ZEROS[l]
def first_check(l,LEN):
if t[l]=="0":
return 0
else:
return (ZERO_ONE[ZEROS[l]]-ONECOUNT[l]+1)%2
def equalcheck(l1,l2,LEN):
f1,f2=ZEROS[l1]+1,ZEROS[l2]+1
if l1+LEN-1=="0":
la1=ZEROS[l1+LEN]
else:
la1=ZEROS[l1+LEN]-1
if l2+LEN-1=="0":
la2=ZEROS[l2+LEN]
else:
la2=ZEROS[l2+LEN]-1
if hash_ij(f1,la1+1)==hash_ij(f2,la2+1) and hash_ij2(f1,la1+1)==hash_ij2(f2,la2+1) and hash_ij3(f1,la1+1)==hash_ij3(f2,la2+1) and hash_ij4(f1,la1+1)==hash_ij4(f2,la2+1):
return "Yes"
else:
return "No"
for queries in range(q):
l1,l2,LEN=map(int,input().split())
l1-=1
l2-=1
#print(l1,l2,LEN)
if zcount(l1,LEN)!=zcount(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==0:
print("Yes")
continue
if first_check(l1,LEN)!=first_check(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==1:
print("Yes")
continue
print(equalcheck(l1,l2,LEN))
``` | output | 1 | 32,668 | 0 | 65,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No
Submitted Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
t=input().strip()
q=int(input())
ZEROS=[0]*n
ZERO_ONE=[]
ONECOUNT=[0]*n
ind=0
count=0
for i in range(n):
ZEROS[i]=ind
if t[i]=="0":
ind+=1
ONECOUNT[i]=count%2
ZERO_ONE.append(count%2)
count=0
else:
count+=1
ONECOUNT[i]=count
ZEROS.append(ind)
S=ZERO_ONE
LEN=len(S)
p=2
import random
mod=(1<<random.randint(31,40))+1
mod2=(1<<random.randint(51,60))+1
mod3=(1<<random.randint(41,50))+1
TABLE=[0]
TABLE2=[0]
TABLE3=[0]
for i in range(LEN):
TABLE.append(p*TABLE[-1]%mod+S[i]%mod) # テーブルを埋める
TABLE2.append(p*TABLE2[-1]%mod2+S[i]%mod2) # テーブルを埋める
TABLE3.append(p*TABLE3[-1]%mod3+S[i]%mod2) # テーブルを埋める
def hash_ij(i,j): # [i,j)のハッシュ値を求める
return (TABLE[j]-TABLE[i]*pow(p,j-i,mod))%mod
def hash_ij2(i,j): # [i,j)のハッシュ値を求める
return (TABLE2[j]-TABLE2[i]*pow(p,j-i,mod2))%mod2
def hash_ij3(i,j): # [i,j)のハッシュ値を求める
return (TABLE3[j]-TABLE3[i]*pow(p,j-i,mod3))%mod3
def zcount(l,LEN):
return ZEROS[l+LEN]-ZEROS[l]
def first_check(l,LEN):
if t[l]=="0":
return 0
else:
return (ZERO_ONE[ZEROS[l]]-ONECOUNT[l]+1)%2
def equalcheck(l1,l2,LEN):
f1,f2=ZEROS[l1]+1,ZEROS[l2]+1
if l1+LEN-1=="0":
la1=ZEROS[l1+LEN]
else:
la1=ZEROS[l1+LEN]-1
if l2+LEN-1=="0":
la2=ZEROS[l2+LEN]
else:
la2=ZEROS[l2+LEN]-1
if hash_ij(f1,la1+1)==hash_ij(f2,la2+1) and hash_ij2(f1,la1+1)==hash_ij2(f2,la2+1) and hash_ij3(f1,la1+1)==hash_ij3(f2,la2+1):
return "Yes"
else:
return "No"
for queries in range(q):
l1,l2,LEN=map(int,input().split())
l1-=1
l2-=1
#print(l1,l2,LEN)
if zcount(l1,LEN)!=zcount(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==0:
print("Yes")
continue
if first_check(l1,LEN)!=first_check(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==1:
print("Yes")
continue
print(equalcheck(l1,l2,LEN))
``` | instruction | 0 | 32,669 | 0 | 65,338 |
No | output | 1 | 32,669 | 0 | 65,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No
Submitted Solution:
```
n = int(input())
t = input()
q = int(input())
qw = [list(map(int, input().split())) for _ in range(q)]
z = [0]
d1 = [0]
d2 = [0]
for i in range(n):
if t[i] == '1':
z.append((z[-1]+1)%2)
d1.append(d1[-1])
d2.append(d2[-1])
else:
z.append(z[-1])
d1.append(d1[-1] + (z[-1] + 1)%2)
d2.append(d2[-1] + z[-1])
for w in qw:
w[0] -= 1
w[1] -= 1
if '11' in t[w[0]:w[0] + w[2]] and '11' in t[w[1]:w[1] + w[2]]:
p = True
if z[w[0]] == z[w[1]]:
p = d1[w[0] + w[2]] - d1[w[0]] == d1[w[1] + w[2]] - d1[w[1]] and d2[w[0] + w[2]] - d2[w[0]] == d2[w[1] + w[2]] - d2[w[1]]
else:
p = d1[w[0] + w[2]] - d1[w[0]] == d2[w[1] + w[2]] - d2[w[1]] and d2[w[0] + w[2]] - d2[w[0]] == d1[w[1] + w[2]] - d1[w[1]]
print('yes' if p else 'no')
else:
print('yes' if t[w[0]:w[0] + w[2]] == t[w[1]:w[1] + w[2]] else 'no')
``` | instruction | 0 | 32,670 | 0 | 65,340 |
No | output | 1 | 32,670 | 0 | 65,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No
Submitted Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
t=input().strip()
q=int(input())
ZEROS=[0]*n
ZERO_ONE=[]
ONECOUNT=[0]*n
ind=0
count=0
for i in range(n):
ZEROS[i]=ind
if t[i]=="0":
ind+=1
ONECOUNT[i]=count%2
ZERO_ONE.append(count%2)
count=0
else:
count+=1
ONECOUNT[i]=count
ZEROS.append(ind)
S=ZERO_ONE
LEN=len(S)
p=2
import random
mod=(1<<50)+1
mod2=(1<<random.randint(20,60))+1
TABLE=[0]
TABLE2=[0]
for i in range(LEN):
TABLE.append(p*TABLE[-1]%mod+S[i]%mod) # テーブルを埋める
TABLE2.append(p*TABLE2[-1]%mod2+S[i]%mod2) # テーブルを埋める
def hash_ij(i,j): # [i,j)のハッシュ値を求める
return (TABLE[j]-TABLE[i]*pow(p,j-i,mod))%mod
def hash_ij2(i,j): # [i,j)のハッシュ値を求める
return (TABLE2[j]-TABLE2[i]*pow(p,j-i,mod2))%mod2
def zcount(l,LEN):
return ZEROS[l+LEN]-ZEROS[l]
def first_check(l,LEN):
if t[l]=="0":
return 0
else:
return (ZERO_ONE[ZEROS[l]]-ONECOUNT[l]+1)%2
def equalcheck(l1,l2,LEN):
f1,f2=ZEROS[l1]+1,ZEROS[l2]+1
if l1+LEN-1=="0":
la1=ZEROS[l1+LEN]
else:
la1=ZEROS[l1+LEN]-1
if l2+LEN-1=="0":
la2=ZEROS[l2+LEN]
else:
la2=ZEROS[l2+LEN]-1
if hash_ij(f1,la1+1)==hash_ij(f2,la2+1) and hash_ij2(f1,la1+1)==hash_ij2(f2,la2+1):
return "Yes"
else:
return "No"
for queries in range(q):
l1,l2,LEN=map(int,input().split())
l1-=1
l2-=1
#print(l1,l2,LEN)
if zcount(l1,LEN)!=zcount(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==0:
print("Yes")
continue
if first_check(l1,LEN)!=first_check(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==1:
print("Yes")
continue
print(equalcheck(l1,l2,LEN))
``` | instruction | 0 | 32,671 | 0 | 65,342 |
No | output | 1 | 32,671 | 0 | 65,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we will deal with binary strings. Each character of a binary string is either a 0 or a 1. We will also deal with substrings; recall that a substring is a contiguous subsequence of a string. We denote the substring of string s starting from the l-th character and ending with the r-th character as s[l ... r]. The characters of each string are numbered from 1.
We can perform several operations on the strings we consider. Each operation is to choose a substring of our string and replace it with another string. There are two possible types of operations: replace 011 with 110, or replace 110 with 011. For example, if we apply exactly one operation to the string 110011110, it can be transformed into 011011110, 110110110, or 110011011.
Binary string a is considered reachable from binary string b if there exists a sequence s_1, s_2, ..., s_k such that s_1 = a, s_k = b, and for every i ∈ [1, k - 1], s_i can be transformed into s_{i + 1} using exactly one operation. Note that k can be equal to 1, i. e., every string is reachable from itself.
You are given a string t and q queries to it. Each query consists of three integers l_1, l_2 and len. To answer each query, you have to determine whether t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1].
Input
The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the length of string t.
The second line contains one string t (|t| = n). Each character of t is either 0 or 1.
The third line contains one integer q (1 ≤ q ≤ 2 ⋅ 10^5) — the number of queries.
Then q lines follow, each line represents a query. The i-th line contains three integers l_1, l_2 and len (1 ≤ l_1, l_2 ≤ |t|, 1 ≤ len ≤ |t| - max(l_1, l_2) + 1) for the i-th query.
Output
For each query, print either YES if t[l_1 ... l_1 + len - 1] is reachable from t[l_2 ... l_2 + len - 1], or NO otherwise. You may print each letter in any register.
Example
Input
5
11011
3
1 3 3
1 4 2
1 2 3
Output
Yes
Yes
No
Submitted Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
t=input().strip()
q=int(input())
ZEROS=[0]*n
ZERO_ONE=[]
ONECOUNT=[0]*n
ind=0
count=0
for i in range(n):
ZEROS[i]=ind
if t[i]=="0":
ind+=1
ONECOUNT[i]=count%2
ZERO_ONE.append(count%2)
count=0
else:
count+=1
ONECOUNT[i]=count
ZEROS.append(ind)
S=ZERO_ONE
LEN=len(S)
p=2
import random
mod=1<<50+1
mod2=1<<random.randint(20,60)+1
TABLE=[0]
TABLE2=[0]
for i in range(LEN):
TABLE.append(p*TABLE[-1]%mod+S[i]%mod) # テーブルを埋める
TABLE2.append(p*TABLE2[-1]%mod2+S[i]%mod2) # テーブルを埋める
def hash_ij(i,j): # [i,j)のハッシュ値を求める
return (TABLE[j]-TABLE[i]*pow(p,j-i,mod))%mod
def hash_ij2(i,j): # [i,j)のハッシュ値を求める
return (TABLE2[j]-TABLE2[i]*pow(p,j-i,mod2))%mod2
def zcount(l,LEN):
return ZEROS[l+LEN]-ZEROS[l]
def first_check(l,LEN):
if t[l]=="0":
return 0
else:
return (ZERO_ONE[ZEROS[l]]-ONECOUNT[l]+1)%2
def equalcheck(l1,l2,LEN):
f1,f2=ZEROS[l1]+1,ZEROS[l2]+1
if l1+LEN-1=="0":
la1=ZEROS[l1+LEN]
else:
la1=ZEROS[l1+LEN]-1
if l2+LEN-1=="0":
la2=ZEROS[l2+LEN]
else:
la2=ZEROS[l2+LEN]-1
if hash_ij(f1,la1+1)==hash_ij(f2,la2+1) and hash_ij2(f1,la1+1)==hash_ij2(f2,la2+1):
return "Yes"
else:
return "No"
for queries in range(q):
l1,l2,LEN=map(int,input().split())
l1-=1
l2-=1
#print(l1,l2,LEN)
if zcount(l1,LEN)!=zcount(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==0:
print("Yes")
continue
if first_check(l1,LEN)!=first_check(l2,LEN):
print("No")
continue
if zcount(l1,LEN)==1:
print("Yes")
continue
print(equalcheck(l1,l2,LEN))
``` | instruction | 0 | 32,672 | 0 | 65,344 |
No | output | 1 | 32,672 | 0 | 65,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,890 | 0 | 65,780 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
def calculate_z_array(s):
n = len(s)
z = [0]*n
z[0] = n
l = 0
r = 0
for i in range(1, n):
if(i>=l and i<=r):
z[i] = min(z[i-l], r-i+1)
while(i+z[i]<n and s[z[i]] == s[z[i]+i]):
z[i] +=1
if(i+z[i] -1< n and i+z[i]-1>r):
l = i
r = i+z[i]-1
return z
s = input()
n = len(s)
z = calculate_z_array(s)
no_of_prefix_suffix = 0
is_prefix_sufix = [False]*(n+1)
for i in range(n):
if(i+z[i] == n):
no_of_prefix_suffix += 1
is_prefix_sufix[z[i]] = True
cnt = [0]*(n+1)
for i in range(n):
cnt[z[i]] += 1
for i in range(n-1,-1,-1):
cnt[i] += cnt[i+1]
print(no_of_prefix_suffix)
for i in range(1, n+1):
if(is_prefix_sufix[i] == True):
print(i, " ", cnt[i])
``` | output | 1 | 32,890 | 0 | 65,781 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,891 | 0 | 65,782 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
def zfunc(s):
n = len(s)
z = [0] * n
left = right = 0
for i in range(1, n):
if i <= right:
z[i] = min(z[i - left], right - i + 1)
while i + z[i] < n and s[z[i]] == s[i + z[i]]:
z[i] += 1
if i + z[i] - 1 > right:
left, right = i, i + z[i] - 1
return z
s = input()
ans = set()
z = zfunc(s)
z[0] = len(s)
res = [0] * (len(s) + 1)
for i in z:
res[i] += 1
from itertools import accumulate
res = [*accumulate(res[::-1])][::-1]
for i, j in enumerate(z[::-1]):
if j > i:
ans.add((j, res[j]))
print(len(ans))
for i in sorted([*ans]):
print(*i)
``` | output | 1 | 32,891 | 0 | 65,783 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,892 | 0 | 65,784 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
import sys
import bisect
input_=lambda: sys.stdin.readline().strip("\r\n")
from math import log
from math import gcd
from random import randint
sa=lambda :input_()
sb=lambda:int(input_())
sc=lambda:input_().split()
sd=lambda:list(map(int,input_().split()))
se=lambda:float(input_())
sf=lambda:list(input_())
flsh=lambda: sys.stdout.flush()
#sys.setrecursionlimit(10**6)
mod=10**9+7
gp=[]
cost=[]
dp=[]
mx=[]
def dfs(root,par):
global gp,cost,dp
dp[root]=cost[root]
for i in gp[root]:
if i==par:continue
dfs(i,root)
dp[root]=max(dp[root],dp[i])
def z_algo(ar):
n=len(ar)
ans=[0]*n
l,r=0,0
ans[0]=n
for i in range(1,n):
if(i<=r):
ans[i]=min(r-i+1,ans[i-l])
while(i+ans[i]<n and ar[ans[i]]==ar[i+ans[i]]):
ans[i]+=1
if i+ans[i]-1>r:
l=i
r=i+ans[i]-1
return ans
def hnbhai():
s=sa()
n=len(s)
z=z_algo(s)
#print(z)
count=[0]*(n+1)
mark=[0]*(n+1)
tot=0
for i in range(n-1,-1,-1):
if z[i]+i==n:
mark[z[i]]=1
tot+=1
for i in range(n):
count[z[i]]+=1
for i in range(n-1,-1,-1):
count[i]+=count[i+1]
print(tot)
for i in range(1,n+1):
if mark[i]:
print(i,count[i])
for _ in range(1):
hnbhai()
``` | output | 1 | 32,892 | 0 | 65,785 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,893 | 0 | 65,786 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
s = input()
n = len(s)
p = [0]*(n+1)
ans = [0]*(n+1)
j = 0
li = [n]
for i in range(1,n):
while(j>0 and s[i]!=s[j]):
j = p[j-1]
if(s[i]==s[j]):
j+=1
p[i] = j
for i in range(0,n):
ans[p[i]]+=1
for i in range(n-1,-1,-1):
ans[p[i-1]] += ans[i]
for i in range(0,n+1):
ans[i]+=1
j = n-1
while(j>0):
if(p[j]):
li.append(p[j])
j = p[j]-1
li.reverse()
print(len(li))
for i in range(0,len(li)):
print(li[i],ans[li[i]])
``` | output | 1 | 32,893 | 0 | 65,787 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,894 | 0 | 65,788 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
import sys
import random
import bisect
from collections import deque
#sys.setrecursionlimit(10**6)
from queue import PriorityQueue
from math import gcd
input_ = lambda: sys.stdin.readline().strip("\r\n")
ii = lambda : int(input_())
il = lambda : list(map(int, input_().split()))
ilf = lambda : list(map(float, input_().split()))
ip = lambda : input_()
fi = lambda : float(input_())
ap = lambda ab,bc,cd : ab[bc].append(cd)
li = lambda : list(input_())
pr = lambda x : print(x)
prinT = lambda x : print(x)
f = lambda : sys.stdout.flush()
mod = 10**9 + 7
def zfunc(s) :
n = len(s)
z = [0 for i in range(n)]
l = 0
r = 0
for i in range (1,n) :
if (i<=r) :
z[i] = min(r-i+1, z[i-l])
while (i+z[i] < n) and (s[z[i]] == s[i + z[i]]) :
z[i] += 1
if (i+z[i]-1 > r) :
l = i
r = i+z[i]-1
return z
s = ip()
n = len(s)
mn = zfunc(s)
ans = []
d = {}
for i in range (1,n) :
if (i + mn[i] == n) :
m1 = 2
ans.append([mn[i],m1])
x2 = mn.copy()
x2.sort()
ans.append([n,1])
ans.sort()
#print(x2)
for i in range(len(ans)-1) :
m2 = bisect.bisect_left(x2,ans[i][0])
#print(m2)
ans[i][1] += (n-m2-1)
print(len(ans))
for i in ans :
print(*i)
``` | output | 1 | 32,894 | 0 | 65,789 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,895 | 0 | 65,790 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
import sys
input = sys.stdin.readline
from collections import deque
S=input().strip()
LEN=len(S)
i=1
j=0
A=[0]*LEN
A[0]=LEN
while i<LEN:
while i+j<LEN and S[j]==S[i+j]:
j+=1
A[i]=j
if j==0:
i+=1
continue
k=1
while i+k<LEN and k+A[k]<j:
A[i+k]=A[k]
k+=1
i+=k
j-=k
ANS=[0]*(LEN+1)
for a in A:
ANS[a]+=1
for i in range(LEN-1,-1,-1):
ANS[i]+=ANS[i+1]
ANS2=[]
for i in range(1,LEN+1):
if A[LEN-i]==i:
ANS2.append((i,ANS[i]))
print(len(ANS2))
for x,y in ANS2:
print(x,y)
``` | output | 1 | 32,895 | 0 | 65,791 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,896 | 0 | 65,792 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
s = ' ' + input()
n = len(s)
r, c = [-1] * n, [1] * n
for i in range(1, n):
r[i] = r[i - 1] + 1
while r[i] and s[r[i]] != s[i]:
r[i] = r[r[i] - 1] + 1
d, n = [], n - 1
for i in range(n, 1, -1): c[r[i]] += c[i]
while n > 0:
d.append(str(n) + ' ' + str(c[n]))
n = r[n]
print(len(d))
d.reverse()
print('\n'.join(d))
``` | output | 1 | 32,896 | 0 | 65,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1 | instruction | 0 | 32,897 | 0 | 65,794 |
Tags: dp, string suffix structures, strings, two pointers
Correct Solution:
```
from itertools import accumulate
def z_algorithm(s):
n = len(s)
l, d = 1, 0
ans = [0] * n
ans[0] = n
while l < n:
while l + d < n and s[d] == s[l + d]:
d += 1
ans[l] = d
if d == 0:
l += 1
continue
k = 1
while l + k < n and k + ans[k] < d:
ans[l + k] = ans[k]
k += 1
l += k
d -= k
return ans
z = z_algorithm(input())
n = len(z)
ct = [0] * (n + 1)
match = [False] * (n + 1)
for i, v in enumerate(z):
ct[v] += 1
match[n - i] = (n - i) == v
for i in range(n - 1, -1, -1):
ct[i] += ct[i + 1]
buf = []
for i, v in enumerate(ct):
if i > 0 and v > 0 and match[i]:
buf.append('{} {}'.format(i, v))
print(len(buf))
print('\n'.join(buf))
``` | output | 1 | 32,897 | 0 | 65,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
#!/usr/bin/env python3
#ref: book_DG!
def preZ(s): #preprocessing by Z algo
n = len(s)
z = [0]*n
z[0] = n
r = 0
if n==1: return z
while r+1<n and s[r]==s[r+1]: r+=1
z[1] = r #note z=length! not 0-indexed
l = 1 if r>0 else 0
for k in range(2,n):
bl = r+1-k #|\beta|
gl = z[k-l] #|\gamma|
if gl<bl:
z[k]=z[k-l] #Case2a
else:
j=max(0,r-k+1) #Case1 & 2b
while k+j<n and s[j]==s[k+j]: j+=1
z[k]=j
l,r =k,k+j-1
return z
def f(s):
n = len(s)
c = [0]*(n+1)
b = [False]*(n+1) #is suffix
z = preZ(s)
for i in range(n):
t = z[i]
b[t] = b[t] or (z[i]+i==n)
c[t] += 1
for t in range(n-1,0,-1):
c[t] += c[t+1]
return '\n'.join(["%d"%sum(b)] + ["%d %d"%(t,c[t]) for t in range(1,n+1) if b[t]])
print(f(input()))
``` | instruction | 0 | 32,898 | 0 | 65,796 |
Yes | output | 1 | 32,898 | 0 | 65,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
def computeLPSArray(pat, M, lps):
len = 0
lps[0]
i = 1
while i < M:
if pat[i]== pat[len]:
len += 1
lps[i] = len
i += 1
else:
if len != 0:
len = lps[len-1]
else:
lps[i] = 0
i += 1
return lps
def count_subs_occ(s,m,l):
occ=[0]*(m+1)
for i in range(m):
occ[l[i]]+=1
for i in range(m-1,0,-1):
occ[l[i-1]]+=occ[i]
for i in range(m+1):
occ[i]+=1
return occ
s=input()
m=len(s)
l=[0]*m
x=computeLPSArray(s,m,l)
x=[0]+x
y=count_subs_occ(s,m,l)
a=x[-1]
if a==0:
print(1)
print(m,1)
elif a==1:
print(2)
print(1,y[a])
print(m,1)
else:
u=x[-1]
v=x[u]
ans=[[u,y[u]]]
while(1):
if v==0:
break
u=v
v=x[u]
temp=[u,y[u]]
ans.append(temp)
ans.sort()
print(len(ans)+1)
for i in range(len(ans)):
print(ans[i][0],ans[i][1])
print(m,1)
``` | instruction | 0 | 32,899 | 0 | 65,798 |
Yes | output | 1 | 32,899 | 0 | 65,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
def Count(s, t):
res = 0
for i in range(len(s) - len(t) + 1):
if s[i:i+len(t)] == t:
res += 1
return res
s = input()
n = len(s)
p = [0] * (n + 1)
z = [0] * n
ans = [0] * (n + 1)
#Prefix
for i in range(1, n):
p[i] = p[i - 1]
while p[i] > 0 and s[i] != s[p[i]]:
p[i] = p[p[i] - 1]
if s[i] == s[p[i]]:
p[i] += 1
#Z func
l = r = 0
for i in range(1, n):
if i <= r:
z[i] = min(z[i - l], r - i + 1)
while i + z[i] < n and s[i + z[i]] == s[z[i]]: z[i] += 1
if i + z[i] - 1 > r:
l, r = i, i + z[i] - 1
#for i in range(n - 2, -1, -1):
# ans[i] += ans[i + 1] + count[i + 1]
for i in range(n):
ans[p[i]] += 1
#print(ans)
for i in range(n - 1, 0, -1):
ans[p[i - 1]] += ans[i]
# print(i, ': ', ans)
output = []
for i in range(n):
if z[n - i - 1] == i + 1:
output.append((i, ans[i + 1]))
print(len(output) + 1)
for i in range(len(output)):
print(output[i][0] + 1, output[i][1] + 1)
print(n, 1)
``` | instruction | 0 | 32,900 | 0 | 65,800 |
Yes | output | 1 | 32,900 | 0 | 65,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
s = str(input())
n = len(s)
z = [0]
li = [-1]
d = dict()
ans = set()
lis = []
def zf(s):
l = r = 0
for i in range(1, n):
z.append(0)
if i <= r:
z[-1] = min(z[i - l], r - i + 1)
while i + z[i] < n and s[i+z[i]] == s[z[i]]:
z[i] += 1
if i + z[i] - 1 > r:
l = i
r = i + z[i] - 1
li.append(z[i])
if z[i] + i == n:
ans.add(z[i])
zf(s)
li.sort()
# print(n)
# print(z)
x = 1
for i in range(1, len(li)):
if li[i] == li[i - 1]:
x += 1
else:
d.update({li[i-1]: x})
x = 1
d.update({li[-1]: x})
# print(d)
x = len(li)+1
for i in d:
x -= d[i]
d[i] += x
print(len(ans)+1)
for i in ans:
lis.append((i, d[i]))
#print(i, d[i])
lis.sort()
for i in lis:
print(i[0], i[1])
print(n, 1)
``` | instruction | 0 | 32,901 | 0 | 65,802 |
Yes | output | 1 | 32,901 | 0 | 65,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
def zfunc(arr):
n=len(arr)
z=[[0,0] for x in range(n)]
l,r=0,0
for x in range(n):
if x<=r:
z[x][0]=min(z[l-x][0],r-x+1)
while (x+z[x][0]<n and arr[x+z[x][0]]==arr[z[x][0]]):
z[x][0]+=1
if x>r:
l,r=x,x+z[x][0]-1
l,r=n-1,n-1
for x in range(n-1,-1,-1):
if x>=l:
z[x][1]=min(z[n-1-(r-x)][1],x+1)
while (x-z[x][1]>=0 and arr[x-z[x][1]]==arr[n-1-z[x][1]]):
z[x][1]+=1
if x<l:
l,r=x-z[x][1],x
#print(z)
return (z)
def main():
string=input()
arr=zfunc(string)
#print(arr)
pairs={}
for x in range(len(arr)):
for y in range(1,arr[x][0]+1):
if y<=arr[x+y-1][1]:
if y in pairs:
pairs[y]+=1
else:
pairs[y]=1
#print(pairs)
store=[]
for x in pairs:
store.append(x)
store.sort()
print(len(store))
for x in store:
print(x,pairs[x])
main()
``` | instruction | 0 | 32,902 | 0 | 65,804 |
No | output | 1 | 32,902 | 0 | 65,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
s=input()
n=len(s)
p=[-1]*n
c=[0]*(n+1)
q=-1
for i in range(1,n):
while q>=0 and s[i]!=s[q+1]:
q=p[q]
if s[i] == s[q + 1]:
q += 1
p[i] = q
if q>=0:
c[q]+=1
#print(p)
#print(c)
ans=[(n,1)]
q=p[n-1]
while q>0:
ans.append((q+1,c[q]+1))
q=p[q]
if s[0]==s[-1]:
ans.append((1,s.count(s[0])))
ans.reverse()
print(len(ans))
for t in ans:
print(str(t[0])+' '+str(t[1]))
``` | instruction | 0 | 32,903 | 0 | 65,806 |
No | output | 1 | 32,903 | 0 | 65,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
def zfunc(arr):
n=len(arr)
z=[[0,0] for x in range(n)]
l,r=0,0
for x in range(n):
if x<=r:
z[x][0]=min(z[l-x][0],r-x+1)
while (x+z[x][0]<n and arr[x+z[x][0]]==arr[z[x][0]]):
z[x][0]+=1
if x>r:
l,r=x,x+z[x][0]-1
l,r=n-1,n-1
for x in range(n-1,-1,-1):
if x>=l:
z[x][1]=min(z[n-1-(r-x)][1],x+1)
while (x-z[x][1]>=0 and arr[x-z[x][1]]==arr[n-1-z[x][1]]):
z[x][1]+=1
if x<l:
l,r=x-z[x][1],x
#print(z)
return (z)
def main():
string=input()
arr=zfunc(string)
#print(arr)
pairs={}
for x in range(1,len(arr)):
if arr[x][0]<=arr[x+arr[x][0]-1][1] and arr[x][0]!=0:
if arr[x][0] in pairs:
pairs[arr[x][0]]+=1
else:
pairs[arr[x][0]]=1
for x in range(len(arr)-1,-1,-1):
if arr[x][1]<=arr[x-arr[x][1]+1][0] and arr[x][1]!=0:
if arr[x][1] in pairs:
pairs[arr[x][1]]+=1
else:
pairs[arr[x][1]]=1
store=[]
for x in pairs:
store.append(x)
store.sort()
print(len(store))
for x in store:
print(x,pairs[x])
main()
``` | instruction | 0 | 32,904 | 0 | 65,808 |
No | output | 1 | 32,904 | 0 | 65,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character.
Let's introduce several definitions:
* A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj.
* The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l].
* The suffix of string s of length l (1 ≤ l ≤ |s|) is string s[|s| - l + 1..|s|].
Your task is, for any prefix of string s which matches a suffix of string s, print the number of times it occurs in string s as a substring.
Input
The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters.
Output
In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in the order of increasing li.
Examples
Input
ABACABA
Output
3
1 4
3 2
7 1
Input
AAA
Output
3
1 3
2 2
3 1
Submitted Solution:
```
class Hash:
def __init__(self, s, p1=31, p2=53, m1=int(1e9 + 9), m2=int(1e9 + 7)):
self.n = len(s)
self.hashs1 = [0] * (self.n + 1)
self.pows1 = [1] + [0] * self.n
self.p1 = p1
self.m1 = m1
self.hashs2 = [0] * (self.n + 1)
self.pows2 = [1] + [0] * self.n
self.p2 = p2
self.m2 = m2
for i in range(1, self.n):
self.pows1[i] = (self.pows1[i - 1] * self.p1) % self.m1
self.pows2[i] = (self.pows2[i - 1] * self.p2) % self.m2
for i in range(self.n):
self.hashs1[i + 1] = self.hashs1[i] + self.pows1[i] * \
(ord(s[i]) % 97 + 1)
self.hashs2[i + 1] = self.hashs2[i] + self.pows2[i] * \
(ord(s[i]) % 97 + 1)
self.hashs1[i] %= self.m1
self.hashs2[i] %= self.m2
def get_hash(self, l, r):
ans = [(((self.hashs1[r] + self.m1 -
self.hashs1[l]) % self.m1) * self.pows1[self.n - l - 1]) % self.m1, 0]
ans[1] = (((self.hashs2[r] + self.m2 -
self.hashs2[l]) % self.m2) * self.pows2[self.n - l - 1]) % self.m2
return tuple(ans)
def zfunc(s):
n = len(s)
z = [0] * n
left = right = 0
for i in range(n):
if i <= right:
z[i] = min(z[i - left], right - i + 1)
while i + z[i] < n and s[z[i]] == s[i + z[i]]:
z[i] += 1
if i + z[i] - 1 > right:
left, right = i, i + z[i] - 1
return z
s = input()
ans = set()
z = zfunc(s)
res = [0] * (len(s) + 1)
for i in z:
res[i] += 1
from itertools import accumulate
res = [*accumulate(res[::-1])][::-1]
for i in z[::-1]:
if i == 0:
continue
ans.add((i, res[i]))
print(len(ans))
for i in sorted([*ans]):
print(*i)
``` | instruction | 0 | 32,905 | 0 | 65,810 |
No | output | 1 | 32,905 | 0 | 65,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,002 | 0 | 66,004 |
Tags: implementation, strings
Correct Solution:
```
rever = "AHIMOTUVWXYovwx"
rev = ["bd", "pq","db","qp"]
line = input().rstrip()
if len(line) & 1 and line[len(line) // 2] not in rever:
print("NIE")
exit()
l = len(line) // 2 - 1
r = len(line) // 2 if len(line) & 1 == 0 else\
len(line) // 2 + 1
for i in range(len(line) // 2):
if line[l] + line[r] not in rev and (line[l] not in rever or line[l] != line[r]):
break
l-=1
r+=1
if l != -1 or r != len(line):
print("NIE")
else:
print("TAK")
``` | output | 1 | 33,002 | 0 | 66,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,003 | 0 | 66,006 |
Tags: implementation, strings
Correct Solution:
```
lst = [
'AA', 'HH', 'II', 'MM', 'OO', 'TT', 'UU', 'VV', 'WW', 'XX', 'YY',
'bd', 'db', 'oo', 'pq', 'qp', 'vv', 'ww', 'xx'
]
def palindrom(s):
l, r = 0, len(s) - 1
while l <= r:
if s[l] + s[r] not in lst:
return "NIE"
l += 1
r -= 1
return "TAK"
print(palindrom(input()))
``` | output | 1 | 33,003 | 0 | 66,007 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,004 | 0 | 66,008 |
Tags: implementation, strings
Correct Solution:
```
def main():
s = input()
for a, b in zip(s, s[::-1]):
if a != {'A': 'A', 'H': 'H', 'I': 'I', 'M': 'M', 'O': 'O', 'T': 'T', 'U': 'U', 'V': 'V', 'W': 'W', 'X': 'X',
'Y': 'Y', 'b': 'd', 'd': 'b', 'o': 'o', 'p': 'q', 'q': 'p', 'v': 'v', 'w': 'w', 'x': 'x'}.get(b):
print("NIE")
break
else:
print("TAK")
if __name__ == '__main__':
main()
``` | output | 1 | 33,004 | 0 | 66,009 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,006 | 0 | 66,012 |
Tags: implementation, strings
Correct Solution:
```
s = input()
n = len(s)
c = ['A', 'H', 'I', 'M', 'O', 'o', 'T', 'U', 'V', 'v', 'W', 'w', 'X', 'x', 'Y']
p = ['b', 'd', 'q', 'p']
ok = 1
for i in range(n):
if s[i] == s[n-i-1] or (s[i] in p and s[n-i-1] in p):
continue
ok = 0
if ok == 1:
for i in range(n):
if s[i] in c:
continue
elif s[i] in p:
if s[i] == p[0] and s[n-i-1] == p[1]:
continue
elif s[i] == p[1] and s[n-i-1] == p[0]:
continue
elif s[i] == p[2] and s[n-i-1] == p[3]:
continue
elif s[i] == p[3] and s[n-i-1] == p[2]:
continue
ok = 0
if ok == 1:
print("TAK")
else:
print("NIE")
``` | output | 1 | 33,006 | 0 | 66,013 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,007 | 0 | 66,014 |
Tags: implementation, strings
Correct Solution:
```
s = input()
n = len(s)
pair = {
"a" : -1, "A" : "A",
"b" : "d", "B" : -1,
"c" : -1, "C" : -1,
"d" : "b", "D" : -1,
"e" : -1, "E" : -1,
"f" : -1, "F" : -1,
"g" : -1, "G" : -1,
"h" : -1, "H" : "H",
"i" : -1, "I" : "I",
"j" : -1, "J" : -1,
"k" : -1, "K" : -1,
"l" : -1, "L" : -1,
"m" : -1, "M" : "M",
"n" : -1, "N" : -1,
"o" : "o", "O" : "O",
"p" : "q", "P" : -1,
"q" : "p", "Q" : -1,
"r" : -1, "R" : -1,
"s" : -1, "S" : -1,
"t" : -1, "T" : "T",
"u" : -1, "U" : "U",
"v" : "v", "V" : "V",
"w" : "w", "W" : "W",
"x" : "x", "X" : "X",
"y" : -1, "Y" : "Y",
"z" : -1, "Z" : -1
}
ans = "TAK"
for i in range((n - 1) // 2 + 1):
if pair[s[i]] != s[n - 1 - i]:
ans = "NIE"
break
print(ans)
``` | output | 1 | 33,007 | 0 | 66,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,008 | 0 | 66,016 |
Tags: implementation, strings
Correct Solution:
```
s = input()
D = {'A': 'A', 'b': 'd', 'd': 'b', 'H': 'H', 'I': 'I', 'M': 'M', 'O': 'O', 'o': 'o', 'p': 'q', 'q': 'p', 'T': 'T', 'U': 'U', 'V': 'V', 'v': 'v', 'W': 'W', 'w': 'w', 'X': 'X', 'x': 'x', 'Y': 'Y'}
for(c1,c2) in zip(s, s[::-1]):
if(D.get(c1, '') != c2):
print("NIE")
exit()
print("TAK")
``` | output | 1 | 33,008 | 0 | 66,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
<image> English alphabet
You are given a string s. Check if the string is "s-palindrome".
Input
The only line contains the string s (1 ≤ |s| ≤ 1000) which consists of only English letters.
Output
Print "TAK" if the string s is "s-palindrome" and "NIE" otherwise.
Examples
Input
oXoxoXo
Output
TAK
Input
bod
Output
TAK
Input
ER
Output
NIE | instruction | 0 | 33,009 | 0 | 66,018 |
Tags: implementation, strings
Correct Solution:
```
#!/usr/bin/python3.4
a="AHIMOTUVWXYovwx"
b={'b':'d', 'd':'b', 'p':'q', 'q':'p'}
s=str(input())
ok = True
slen = len(s)
for i in range((slen - 1) // 2 + 1):
if (s[i] in a and s[i] == s[slen - i - 1]) or (b.get(s[i], 0) and b[s[i]] == s[slen - 1 - i]):
continue
else:
ok = False
break;
print(['NIE', 'TAK'][ok])
``` | output | 1 | 33,009 | 0 | 66,019 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,183 | 0 | 66,366 |
"Correct Solution:
```
n = int(input())
s = input()
count = 0
for i in range(n):
count = max(count, len(set(s[:i]) & set(s[i:])))
print(count)
``` | output | 1 | 33,183 | 0 | 66,367 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,184 | 0 | 66,368 |
"Correct Solution:
```
N=int(input())
S=input()
m=0
for i in range(1,N):
X=S[0:i]
Y=S[i:]
a=len(set(X) & set(Y))
if a>m:
m=a
print(m)
``` | output | 1 | 33,184 | 0 | 66,369 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,185 | 0 | 66,370 |
"Correct Solution:
```
n=int(input())
s=input()
c=0
for i in range(1,n):
p=set(s[:i])
b=set(s[i:])
c=max(c,len(p&b))
print(c)
``` | output | 1 | 33,185 | 0 | 66,371 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,186 | 0 | 66,372 |
"Correct Solution:
```
#098_B
n=int(input())
s=input()
print(max([len(set(s[:i])&set(s[i:])) for i in range(1,n)]))
``` | output | 1 | 33,186 | 0 | 66,373 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,187 | 0 | 66,374 |
"Correct Solution:
```
N = int(input())
S = input()
print(max(len(set(S[:n])&set(S[n:])) for n in range(N)))
``` | output | 1 | 33,187 | 0 | 66,375 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,188 | 0 | 66,376 |
"Correct Solution:
```
n=int(input());s=input();print(max(len(set(s[:i])&set(s[i:]))for i in range(n)))
``` | output | 1 | 33,188 | 0 | 66,377 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,189 | 0 | 66,378 |
"Correct Solution:
```
_ = input()
S = input()
print(max([len(set(S[:i]) & set(S[i:])) for i in range(len(S))]))
``` | output | 1 | 33,189 | 0 | 66,379 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S of length N consisting of lowercase English letters. We will cut this string at one position into two strings X and Y. Here, we would like to maximize the number of different letters contained in both X and Y. Find the largest possible number of different letters contained in both X and Y when we cut the string at the optimal position.
Constraints
* 2 \leq N \leq 100
* |S| = N
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the largest possible number of different letters contained in both X and Y.
Examples
Input
6
aabbca
Output
2
Input
10
aaaaaaaaaa
Output
1
Input
45
tgxgdqkyjzhyputjjtllptdfxocrylqfqjynmfbfucbir
Output
9 | instruction | 0 | 33,190 | 0 | 66,380 |
"Correct Solution:
```
n = int(input())
s = list(input())
ans = 0
for i in range(1, n):
ans = max(ans, len(set(s[:i]) & set(s[i:])))
print(ans)
``` | output | 1 | 33,190 | 0 | 66,381 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string and a number k. You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them.
Input
The input is given in the following format.
s
k
The first line provides a string s. The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 109). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 105.
Output
Output the lexicographically smallest string.
Examples
Input
pckoshien
3
Output
ckopshien
Input
pckoshien
10
Output
cekophsin | instruction | 0 | 33,257 | 0 | 66,514 |
"Correct Solution:
```
import sys
def main():
NI = lambda : int(sys.stdin.readline())
SI = lambda : sys.stdin.readline().rstrip()
s = SI()
n = len(s)
k = NI()
def conv(x):
return ord(x) - ord('a')
bit = [0] * (n+1)
def bit_add(i):
while i <= n:
bit[i] += 1
i += i & (-i)
def bit_sum(i):
ret = 0
while i > 0:
ret += bit[i]
i -= i & (-i)
return ret
z = [0] * n
top = [-1] * 26
nxt = [-1] * n
bef = [-1] * 26
for i in range(n):
cv = conv(s[i])
if bef[cv] >= 0:
nxt[bef[cv]] = i
bef[cv] = i
if top[cv] < 0:
top[cv] = i
ans = []
while k > 0:
for i in range(26):
if top[i] < 0: continue
p = top[i]
cost = p - bit_sum(p+1)
if cost <= k:
ans.append(chr(ord('a')+i))
z[top[i]] = 1
k -= cost
top[i] = nxt[top[i]]
bit_add(p+1)
break
else:
break
for i in range(n):
if z[i] == 0: ans.append(s[i])
print(*ans,sep='')
if __name__ == '__main__':
main()
``` | output | 1 | 33,257 | 0 | 66,515 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string and a number k. You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them.
Input
The input is given in the following format.
s
k
The first line provides a string s. The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 109). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 105.
Output
Output the lexicographically smallest string.
Examples
Input
pckoshien
3
Output
ckopshien
Input
pckoshien
10
Output
cekophsin | instruction | 0 | 33,258 | 0 | 66,516 |
"Correct Solution:
```
from bisect import bisect_left as bl
def main():
s = list(map(ord, list(input())))
k = int(input())
used = []
used_index = []
pos_dict = {}
as_a = ord("a")
as_z = ord("z")
for i, v in enumerate(s):
if v in pos_dict:
pos_dict[v].append(i)
else:
pos_dict[v] = [i]
keys = sorted(pos_dict.keys())
for key in keys:
pos_dict[key].reverse()
while k:
for key in keys:
init = pos_dict[key][-1]
pre_used = bl(used_index, init)
cost = init - pre_used
if cost <= k:
k -= cost
used.append(key)
ins = bl(used_index, init)
used_index.insert(ins, init)
pos_dict[key].pop()
if not pos_dict[key]:
keys.remove(key)
break
else:
break
used_index.sort(reverse=True)
for i in used_index:
s.pop(i)
print("".join(map(chr, used + s)))
main()
``` | output | 1 | 33,258 | 0 | 66,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string and a number k. You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them.
Input
The input is given in the following format.
s
k
The first line provides a string s. The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 109). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 105.
Output
Output the lexicographically smallest string.
Examples
Input
pckoshien
3
Output
ckopshien
Input
pckoshien
10
Output
cekophsin
Submitted Solution:
```
def solve(k,s):
for i in range(len(s)):
ss = s[i:i+k+1]
# print("ss={}".format(ss))
min_c = min(ss)
min_i = ss.index(min_c)
if min_i != 0:
k -= min_i
s.pop(i+min_i)
s.insert(i,min_c)
if k == 0:
break
# print("".join(s))
return s
s = list(input())
k = int(input())
o = solve(k,s)
print("".join(o))
``` | instruction | 0 | 33,259 | 0 | 66,518 |
No | output | 1 | 33,259 | 0 | 66,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string and a number k. You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them.
Input
The input is given in the following format.
s
k
The first line provides a string s. The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 109). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 105.
Output
Output the lexicographically smallest string.
Examples
Input
pckoshien
3
Output
ckopshien
Input
pckoshien
10
Output
cekophsin
Submitted Solution:
```
def solve(k,s):
if k == 0:
return s
elif s == []:
return []
else:
ss = s[0:k+1]
min_c = min(ss)
min_i = ss.index(min_c)
if min_i == 0:
ss = s[1:len(s)]
return [s[0]] + solve(k,ss)
else:
s.pop(min_i)
k -= min_i
return [min_c] + solve(k,s)
s = list(input())
k = int(input())
o = solve(k,s)
print("".join(o))
``` | instruction | 0 | 33,260 | 0 | 66,520 |
No | output | 1 | 33,260 | 0 | 66,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string and a number k. You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them.
Input
The input is given in the following format.
s
k
The first line provides a string s. The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 109). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 105.
Output
Output the lexicographically smallest string.
Examples
Input
pckoshien
3
Output
ckopshien
Input
pckoshien
10
Output
cekophsin
Submitted Solution:
```
s = list(input())
k = int(input())
j = 0
while True:
i = s[j:j + k + 1].index(min(s[j:j + k + 1]))
s = s[:j] + [s[j + i]] + s[j :j + i] + s[j + i + 1:]
j += 1
k -= i
if k == 0 or j >= len(s) - 1:
break
print("".join(s))
``` | instruction | 0 | 33,261 | 0 | 66,522 |
No | output | 1 | 33,261 | 0 | 66,523 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.