db_id
stringclasses
146 values
question
stringlengths
3
224
sql
stringlengths
18
577
database_schema
stringclasses
146 values
debate
Show the distinct venues of debates
SELECT DISTINCT Venue FROM debate
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
Show the names of people, and dates and venues of debates they are on the affirmative side.
SELECT T3.Name , T2.Date , T2.Venue FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Affirmative = T3.People_ID
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
Show the names of people, and dates and venues of debates they are on the negative side, ordered in ascending alphabetical order of name.
SELECT T3.Name , T2.Date , T2.Venue FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Negative = T3.People_ID ORDER BY T3.Name ASC
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
Show the names of people that are on affirmative side of debates with number of audience bigger than 200.
SELECT T3.Name FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Affirmative = T3.People_ID WHERE T2.Num_of_Audience > 200
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
Show the names of people and the number of times they have been on the affirmative side of debates.
SELECT T2.Name , COUNT(*) FROM debate_people AS T1 JOIN people AS T2 ON T1.Affirmative = T2.People_ID GROUP BY T2.Name
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
Show the names of people who have been on the negative side of debates at least twice.
SELECT T2.Name FROM debate_people AS T1 JOIN people AS T2 ON T1.Negative = T2.People_ID GROUP BY T2.Name HAVING COUNT(*) >= 2
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
debate
List the names of people that have not been on the affirmative side of debates.
SELECT Name FROM people WHERE People_id NOT IN (SELECT Affirmative FROM debate_people)
CREATE TABLE "people" ( "People_ID" int, "District" text, "Name" text, "Party" text, "Age" int, PRIMARY KEY ("People_ID") ) 3 rows from people table: People_ID District Name Party Age 1 New York 1 Luther C. Carter Republican 35 2 New York 2 James Humphrey Republican 38 ...
insurance_and_eClaims
List the names of all the customers in alphabetical order.
SELECT customer_details FROM customers ORDER BY customer_details
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Sort the customer names in alphabetical order.
SELECT customer_details FROM customers ORDER BY customer_details
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find all the policy type codes associated with the customer "Dayana Robel"
SELECT policy_type_code FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_details = "Dayana Robel"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What are the type codes of the policies used by the customer "Dayana Robel"?
SELECT policy_type_code FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_details = "Dayana Robel"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which type of policy is most frequently used? Give me the policy type code.
SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the type code of the most frequently used policy.
SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find all the policy types that are used by more than 2 customers.
SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING count(*) > 2
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which types of policy are chosen by more than 2 customers? Give me the policy type codes.
SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING count(*) > 2
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the total and average amount paid in claim headers.
SELECT sum(amount_piad) , avg(amount_piad) FROM claim_headers
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What are the total amount and average amount paid in claim headers?
SELECT sum(amount_piad) , avg(amount_piad) FROM claim_headers
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the total amount claimed in the most recently created document.
SELECT sum(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
How much amount in total were claimed in the most recently created document?
SELECT sum(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What is the name of the customer who has made the largest amount of claim in a single claim?
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT max(amount_claimed) FROM claim_headers)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customer made the largest amount of claim in a single claim? Return the customer details.
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT max(amount_claimed) FROM claim_headers)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What is the name of the customer who has made the minimum amount of payment in one claim?
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT min(amount_piad) FROM claim_headers)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customer made the smallest amount of claim in one claim? Return the customer details.
SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT min(amount_piad) FROM claim_headers)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the names of customers who have no policies associated.
SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What are the names of customers who do not have any policies?
SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
How many claim processing stages are there in total?
SELECT count(*) FROM claims_processing_stages
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the number of distinct stages in claim processing.
SELECT count(*) FROM claims_processing_stages
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What is the name of the claim processing stage that most of the claims are on?
SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which claim processing stage has the most claims? Show the claim status name.
SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the names of customers whose name contains "Diana".
SELECT customer_details FROM customers WHERE customer_details LIKE "%Diana%"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customers have the substring "Diana" in their names? Return the customer details.
SELECT customer_details FROM customers WHERE customer_details LIKE "%Diana%"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the names of the customers who have an deputy policy.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customers have an insurance policy with the type code "Deputy"? Give me the customer details.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the names of customers who either have an deputy policy or uniformed policy.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy" OR t1.policy_type_code = "Uniform"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customers have an insurance policy with the type code "Deputy" or "Uniform"? Return the customer details.
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy" OR t1.policy_type_code = "Uniform"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the names of all the customers and staff members.
SELECT customer_details FROM customers UNION SELECT staff_details FROM staff
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What are the names of the customers and staff members?
SELECT customer_details FROM customers UNION SELECT staff_details FROM staff
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the number of records of each policy type and its type code.
SELECT policy_type_code , count(*) FROM policies GROUP BY policy_type_code
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
For each policy type, return its type code and its count in the record.
SELECT policy_type_code , count(*) FROM policies GROUP BY policy_type_code
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the name of the customer that has been involved in the most policies.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customer have the most policies? Give me the customer details.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY count(*) DESC LIMIT 1
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
What is the description of the claim status "Open"?
SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the description of the claim status "Open".
SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
How many distinct claim outcome codes are there?
SELECT count(DISTINCT claim_outcome_code) FROM claims_processing
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Count the number of distinct claim outcome codes.
SELECT count(DISTINCT claim_outcome_code) FROM claims_processing
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Which customer is associated with the latest policy?
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT max(start_date) FROM policies)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
insurance_and_eClaims
Find the customer who started a policy most recently.
SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT max(start_date) FROM policies)
CREATE TABLE Customers ( Customer_ID INTEGER NOT NULL, Customer_Details VARCHAR(255) NOT NULL, PRIMARY KEY (Customer_ID) ) 3 rows from Customers table: Customer_ID Customer_Details 252 America Jaskolski 263 Ellsworth Paucek 334 Mrs. Hanna Willms CREATE TABLE Staff ( Staff_ID INTEGER NO...
customers_and_invoices
Show the number of accounts.
SELECT count(*) FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many accounts are there?
SELECT count(*) FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many customers have opened an account?
SELECT count(DISTINCT customer_id) FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of customers who have an account.
SELECT count(DISTINCT customer_id) FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the id, the date of account opened, the account name, and other account detail for all accounts.
SELECT account_id , date_account_opened , account_name , other_account_details FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the ids, date opened, name, and other details for all accounts?
SELECT account_id , date_account_opened , account_name , other_account_details FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the id, the account name, and other account details for all accounts by the customer with first name 'Meaghan'.
SELECT T1.account_id , T1.date_account_opened , T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = 'Meaghan'
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the ids, names, dates of opening, and other details for accounts corresponding to the customer with the first name "Meaghan"?
SELECT T1.account_id , T1.date_account_opened , T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = 'Meaghan'
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the account name and other account detail for all accounts by the customer with first name Meaghan and last name Keeling.
SELECT T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Meaghan" AND T2.customer_last_name = "Keeling"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the names and other details for accounts corresponding to the customer named Meaghan Keeling?
SELECT T1.account_name , T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Meaghan" AND T2.customer_last_name = "Keeling"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the first name and last name for the customer with account name 900.
SELECT T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "900"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the full names of customers with the account name 900?
SELECT T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "900"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many customers don't have an account?
SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of customers who do not have an account.
SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts)
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the unique first names, last names, and phone numbers for all customers with any account.
SELECT DISTINCT T1.customer_first_name , T1.customer_last_name , T1.phone_number FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the distinct first names, last names, and phone numbers for customers with accounts?
SELECT DISTINCT T1.customer_first_name , T1.customer_last_name , T1.phone_number FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show customer ids who don't have an account.
SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the customer ids for customers who do not have an account?
SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Accounts
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many accounts does each customer have? List the number and customer id.
SELECT count(*) , customer_id FROM Accounts GROUP BY customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of accounts corresponding to each customer id.
SELECT count(*) , customer_id FROM Accounts GROUP BY customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What is the customer id, first and last name with most number of accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Return the id and full name of the customer with the most accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show id, first name and last name for all customers and the number of accounts.
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name , count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the the full names and ids for all customers, and how many accounts does each have?
SELECT T1.customer_id , T2.customer_first_name , T2.customer_last_name , count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show first name and id for all customers with at least 2 accounts.
SELECT T2.customer_first_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the first names and ids for customers who have two or more accounts?
SELECT T2.customer_first_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) >= 2
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the number of customers.
SELECT count(*) FROM Customers
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of customers.
SELECT count(*) FROM Customers
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the number of customers for each gender.
SELECT gender , count(*) FROM Customers GROUP BY gender
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many customers are there of each gender?
SELECT gender , count(*) FROM Customers GROUP BY gender
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many transactions do we have?
SELECT count(*) FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of transactions.
SELECT count(*) FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many transaction does each account have? Show the number and account id.
SELECT count(*) , account_id FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of financial transactions that correspond to each account id.
SELECT count(*) , account_id FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
How many transaction does account with name 337 have?
SELECT count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id WHERE T2.account_name = "337"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Count the number of financial transactions that the account with the name 337 has.
SELECT count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id WHERE T2.account_name = "337"
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What is the average, minimum, maximum, and total transaction amount?
SELECT avg(transaction_amount) , min(transaction_amount) , max(transaction_amount) , sum(transaction_amount) FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Return the average, minimum, maximum, and total transaction amounts.
SELECT avg(transaction_amount) , min(transaction_amount) , max(transaction_amount) , sum(transaction_amount) FROM Financial_transactions
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show ids for all transactions whose amounts are greater than the average.
SELECT transaction_id FROM Financial_transactions WHERE transaction_amount > (SELECT avg(transaction_amount) FROM Financial_transactions)
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the ids for transactions that have an amount greater than the average amount of a transaction?
SELECT transaction_id FROM Financial_transactions WHERE transaction_amount > (SELECT avg(transaction_amount) FROM Financial_transactions)
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the transaction types and the total amount of transactions.
SELECT transaction_type , sum(transaction_amount) FROM Financial_transactions GROUP BY transaction_type
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are total transaction amounts for each transaction type?
SELECT transaction_type , sum(transaction_amount) FROM Financial_transactions GROUP BY transaction_type
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the account name, id and the number of transactions for each account.
SELECT T2.account_name , T1.account_id , count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Return the names and ids of each account, as well as the number of transactions.
SELECT T2.account_name , T1.account_id , count(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the account id with most number of transactions.
SELECT account_id FROM Financial_transactions GROUP BY account_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What is the id of the account with the most transactions?
SELECT account_id FROM Financial_transactions GROUP BY account_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the account id and name with at least 4 transactions.
SELECT T1.account_id , T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING count(*) >= 4
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the ids and names of accounts with 4 or more transactions?
SELECT T1.account_id , T2.account_name FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id GROUP BY T1.account_id HAVING count(*) >= 4
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show all product sizes.
SELECT DISTINCT product_size FROM Products
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the different product sizes?
SELECT DISTINCT product_size FROM Products
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show all product colors.
SELECT DISTINCT product_color FROM Products
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
What are the different product colors?
SELECT DISTINCT product_color FROM Products
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...
customers_and_invoices
Show the invoice number and the number of transactions for each invoice.
SELECT invoice_number , count(*) FROM Financial_transactions GROUP BY invoice_number
CREATE TABLE `Customers` ( `customer_id` INTEGER PRIMARY KEY, `customer_first_name` VARCHAR(50), `customer_middle_initial` VARCHAR(1), `customer_last_name` VARCHAR(50), `gender` VARCHAR(1), `email_address` VARCHAR(255), `login_name` VARCHAR(80), `login_password` VARCHAR(20), `phone_number` VARCHAR(255), `town_city` VAR...