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target-benchmark

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bird-queries-validation

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superhero

Calculate the percentage of superheroes with blue eyes.

SELECT CAST(COUNT(CASE WHEN T2.colour = 'Blue' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id

moderate

percentage = MULTIPLY(DIVIDE(SUM(superhero_name WHERE eye_colour_id = 7), COUNT(superhero_name)), 100.0); blue eyes refers to eye_colour_id = 7;

superhero

Find the ratio between male superheroes and female superheroes.

SELECT CAST(COUNT(CASE WHEN T2.gender = 'Male' THEN T1.id ELSE NULL END) AS REAL) / COUNT(CASE WHEN T2.gender = 'Female' THEN T1.id ELSE NULL END) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id

moderate

ratio = DIVIDE(SUM(gender_id = 1) / SUM(gender_id = 2)); male superheroes refers to gender_id = 1; female superheroes refers to gender_id = 2;

superhero

Who is the tallest superhero?

SELECT superhero_name FROM superhero ORDER BY height_cm DESC LIMIT 1

simple

who refers to superhero_name; tallest superhero refers to MAX(height_cm);

superhero

What is the power ID of cryokinesis?

SELECT id FROM superpower WHERE power_name = 'Cryokinesis'

simple

power ID refers to superpower.id; cryokinesis refers to power_name = 'cryokinesis';

superhero

Provide the name of superhero with superhero ID 294.

SELECT superhero_name FROM superhero WHERE id = 294

simple

name of superhero refers to superhero_name; superhero ID 294 refers to superhero.id = 294;

superhero

List the full names of superheroes with missing weight.

SELECT DISTINCT full_name FROM superhero WHERE full_name IS NOT NULL AND (weight_kg IS NULL OR weight_kg = 0)

simple

missing weight refers to weight_kg = 0 OR weight_kg = NULL;

superhero

Provide the eye colour of the superhero who has Karen Beecher-Duncan as their full name.

SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.full_name = 'Karen Beecher-Duncan'

simple

eye colour refers to colour.colour where eye_colour_id = colour.id; Karen Beecher-Duncan is the full name of superhero;

superhero

What is the superpowers of the superhero has Helen Parr as their full name?

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.full_name = 'Helen Parr'

simple

superpowers refers to power_name; Helen Parr is the full name of superhero;

superhero

Find the race of the superhero who weighs 108kg and is 188cm tall.

SELECT DISTINCT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.weight_kg = 108 AND T1.height_cm = 188

simple

weighs 108kg refers to weight_kg = 108; 188cm tall refers to height_cm = 188;

superhero

What is the publisher name of the superhero ID 38?

SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.id = 38

simple

superhero ID 38 refers to superhero.id = 38;

superhero

What is the race of the superhero with maximum attribute value?

SELECT T3.race FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN race AS T3 ON T1.race_id = T3.id ORDER BY T2.attribute_value DESC LIMIT 1

simple

maximum attribute value refers to MAX(attribute_value);

superhero

Give the alignment and superpowers of the superhero named Atom IV.

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T3.id = T2.power_id WHERE T1.superhero_name = 'Atom IV'

simple

superpowers refers to power_name;

superhero

List down at least five full names of superheroes with blue eyes.

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T2.colour = 'Blue' LIMIT 5

simple

blue eyes refers to colour.colour = 'Blue' WHERE eye_colour_id = colour.id;

superhero

Calculate the average attribute value of all neutral superheroes.

SELECT AVG(T1.attribute_value) FROM hero_attribute AS T1 INNER JOIN superhero AS T2 ON T1.hero_id = T2.id INNER JOIN alignment AS T3 ON T2.alignment_id = T3.id WHERE T3.alignment = 'Neutral'

simple

average = AVG(attribute_value); neutral superheroes refers to alignment_id = 3;

superhero

List the skin colour of the superheroes with 100 attribute value.

SELECT DISTINCT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.skin_colour_id = T2.id INNER JOIN hero_attribute AS T3 ON T1.id = T3.hero_id WHERE T3.attribute_value = 100

moderate

skin colour refers to colour.colour where skin_colour_id = colour.id; 100 attribute value refers to attribute_value = 100;

superhero

Count the good female superheroes.

SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.alignment = 'Good' AND T3.gender = 'Female'

simple

good refers to alignment.id = 1; female refers to gender.id = 2;

superhero

Provide the names of superheroes with attribute value between 75 to 80.

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id WHERE T2.attribute_value BETWEEN 75 AND 80

simple

names of superheroes refers to superhero_name; attribute value between 75 to 80 refers to attribute_value BETWEEN 75 AND 80;

superhero

Give the race of the blue-haired male superhero.

SELECT T3.race FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.hair_colour_id = T2.id INNER JOIN race AS T3 ON T1.race_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T2.colour = 'Blue' AND T4.gender = 'Male'

moderate

blue-haired refers to colour.colour = 'blue' WHERE hair_colour_id = colour.id; male refers to gender = 'male';

superhero

Among the bad superheroes, what is the percentage of female superheroes?

SELECT CAST(COUNT(CASE WHEN T3.gender = 'Female' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.alignment = 'Bad'

challenging

bad superheroes refers to alignment.id = 2; percentage = MULTIPLY(DIVIDE(SUM(gender.id = 2 WHERE alignment.id = 2), COUNT(alignment.id = 2)), 100.0); female refers to gender.id = 2;

superhero

In superheroes with missing weight data, calculate the difference between the number of superheroes with blue eyes and no eye color.

SELECT SUM(CASE WHEN T2.id = 7 THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.id = 1 THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.weight_kg = 0 OR T1.weight_kg is NULL

challenging

missing weight data refers to weight_kg = 0 OR T1.weight_kg = NULL; difference = SUBTRACT(SUM(colour.id = 7), SUM(colour.id = 1)); blue eyes refers to eye_colour_id WHERE colour.id = 7; no eye color refers to eye_colour_id WHERE colour.id = 1;

superhero

How strong is the Hulk?

SELECT T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = 'Hulk' AND T3.attribute_name = 'Strength'

moderate

how strong refers to attribute_value WHERE attribute_name = 'Strength'; the Hulk refers to superhero_name = 'Hulk';

superhero

List down Ajax's superpowers.

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Ajax'

simple

Ajax refers to superhero_name = 'Ajax'; superpowers refers to power_name;

superhero

How many green-skinned villains are there in the superhero universe?

SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.alignment = 'Bad' AND T3.colour = 'Green'

moderate

green-skinned refers to colour.colour = 'Green' WHERE skin_colour_id = colour.id; villains refers to alignment = 'Bad';

superhero

How many female superheroes are in Marvel Comics?

SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.gender = 'Female'

moderate

female refers to gender = 'Female'; Marvel Comics refers to publisher_name = 'Marvel Comics';

superhero

Identify superheroes who can control wind and list their names in alphabetical order.

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Wind Control' ORDER BY T1.superhero_name

moderate

superheroes refers to superhero_name; can control wind refers to power_name = 'Wind Control';

superhero

Identify the gender of the superhero who has the ability of Phoenix Force.

SELECT T4.gender FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.power_name = 'Phoenix Force'

moderate

ability of Phoenix Force refers to power_name = 'Phoenix Force';

superhero

Identify the heaviest superhero in DC Comics.

SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'DC Comics' ORDER BY T1.weight_kg DESC LIMIT 1

simple

heaviest refers to MAX(weight_kg); DC Comics refers to publisher_name = 'DC Comics'; superhero refers to superhero_name;

superhero

What is the average height of a non-human superhero in Dark Horse Comics?

SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN race AS T3 ON T1.race_id = T3.id WHERE T2.publisher_name = 'Dark Horse Comics' AND T3.race != 'Human'

moderate

average = AVG(height_cm); non-human superhero refers to race <> 'Human'; Dark Horse Comics refers to publisher_name = 'Dark Horse Comics';

superhero

Count the fastest superheroes.

SELECT COUNT(T3.superhero_name) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id INNER JOIN superhero AS T3 ON T1.hero_id = T3.id WHERE T2.attribute_name = 'Speed' ORDER BY T1.attribute_value DESC LIMIT 1

simple

fastest refers to attribute_value = 100 WHERE attribute_name = 'Speed';

superhero

Which publisher created more superheroes: DC or Marvel Comics? Find the difference in the number of superheroes.

SELECT SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id

challenging

DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; if SUM(publisher_name = 'DC Comics') > SUM(publisher_name = 'Marvel Comics'), it means DC Comics published more superheroes than Marvel Comics; if SUM(publisher_name = 'Marvel Comics') > SUM(publisher_name = 'Marvel Comics'), it means Marvel Comics published more heroes than DC Comics; difference = SUBTRACT(SUM(publisher_name = 'DC Comics'), SUM(publisher_name = 'Marvel Comics'));

superhero

Identify the weakest attribute of the Black Panther.

SELECT T3.attribute_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = 'Black Panther' ORDER BY T2.attribute_value ASC LIMIT 1

moderate

weakest attribute refers to attribute_name WHERE MIN(attribute_value); Black Panther refers to superhero_name = 'Black Panther';

superhero

What is Abomination's eye colour?

SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.superhero_name = 'Abomination'

simple

Abomination refers to superhero_name = 'Abomination'; eye colour refers to colour.colour where eye_colour_id = colour.id;

superhero

Name the tallest superhero.

SELECT superhero_name FROM superhero ORDER BY height_cm DESC LIMIT 1

simple

tallest superhero refers to MAX(height_cm);

superhero

Name the superhero, otherwise known as Charles Chandler.

SELECT superhero_name FROM superhero WHERE full_name = 'Charles Chandler'

simple

name the superhero refers to superhero_name; Charles Chandler is the full name of superhero;

superhero

Among all superheroes created by George Lucas, identify the percentage of female superheroes.

SELECT CAST(COUNT(CASE WHEN T3.gender = 'Female' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T2.publisher_name = 'George Lucas'

challenging

created by George Lucas refers to publisher_name = 'George Lucas'; percentage = MULTIPLY(DIVIDE(SUM(gender = 'Female' WHERE publisher_name = 'George Lucas'), COUNT(publisher_name = 'George Lucas')), 100.0); female refers to gender = 'Female';

superhero

Among all superheroes in Marvel Comics, identify the percentage of 'good' superheroes.

SELECT CAST(COUNT(CASE WHEN T3.alignment = 'Good' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN alignment AS T3 ON T1.alignment_id = T3.id WHERE T2.publisher_name = 'Marvel Comics'

challenging

Marvel Comics refers to publisher_name = 'Marvel Comics'; percentage = MULTIPLY(DIVIDE(SUM(alignment = 'Good' WHERE publisher_name = 'Marvel Comics'), COUNT(publisher_name = 'Marvel Comics')), 100.0); good superheroes refers to alignment = 'Good';

superhero

What is the total number of superheroes that have John as their first name?

SELECT COUNT(id) FROM superhero WHERE full_name LIKE 'John%'

simple

have John as their first name refers to full_name LIKE 'John%';

superhero

Give the hero ID of superhero with the lowest attribute value.

SELECT hero_id FROM hero_attribute WHERE attribute_value = ( SELECT MIN(attribute_value) FROM hero_attribute )

simple

lowest attribute value refers to MIN(attribute_value);

superhero

Provide the full name of the superhero named Alien.

SELECT full_name FROM superhero WHERE superhero_name = 'Alien'

simple

superhero

In superheroes with weight less than 100, list the full name of the superheroes with brown eyes.

SELECT T1.full_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.weight_kg < 100 AND T2.colour = 'Brown'

simple

weight less than 100 refers to weight_kg < 100

superhero

List the attribute value of the superhero named Aquababy.

SELECT T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id WHERE T1.superhero_name = 'Aquababy'

simple

superhero

Provide the weight and race of the superhero with superhero ID 40.

SELECT T1.weight_kg, T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.id = 40

simple

weight refers to weight_kg; superhero ID 40 refers to superhero.id = 40;

superhero

Calculate the average height of all neutral superheroes.

SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral'

simple

superhero

List the hero ID of superheroes have intellegence as their power.

SELECT T1.hero_id FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Intelligence'

simple

hero ID refers to superhero.id; have intelligence as their power refers to power_name = 'Intelligence';

superhero

Give the eye colour of Blackwulf.

SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.superhero_name = 'Blackwulf'

simple

eye colour refers to colour.colour where eye_colour_id = colour.id; Blackwulf refers to superhero_name = 'Blackwulf';

superhero

List the power of superheroes with height greater than 80% of the average height of all superheroes.

SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.height_cm * 100 > ( SELECT AVG(height_cm) FROM superhero ) * 80

moderate

power of superheroes refers to power_name; height greater than 80% of the average height of all superheroes = height_cm > MULTIPLY(AVG(height_cm), 0.8);

formula_1

Please list the reference names of the drivers who are eliminated in the first period in race number 18.

SELECT T2.driverRef FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 18 ORDER BY T1.q1 DESC LIMIT 5

moderate

driver reference name refers to driverRef; first qualifying period refers to q1; drivers who are eliminated in the first qualifying period refers to 5 drivers with MAX(q1); race number refers to raceId;

formula_1

What is the surname of the driver with the best lap time in race number 19 in the second period?

SELECT T2.surname FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 19 AND T1.q2 IS NOT NULL ORDER BY T1.q2 ASC LIMIT 1

simple

race number refers to raceId; second qualifying period refers to q2; best lap time refers to MIN(q2);

formula_1

Please list the year during which the race is held on circuits in Shanghai.

SELECT T2.year FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.location = 'Shanghai'

simple

Shanghai is a name of location;

formula_1

Where can the introduction of the races held on Circuit de Barcelona-Catalunya be found?

SELECT DISTINCT T1.url FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.name = 'Circuit de Barcelona-Catalunya'

simple

introduction of races refers to url; Circuit de Barcelona-Catalunya is a name of circuit;

formula_1

Please give the name of the race held on the circuits in Germany.

SELECT DISTINCT T2.name FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.country = 'Germany'

simple

Germany is a name of country;

formula_1

Please list the positions of the circuits built by the constructor Renault.

SELECT DISTINCT T1.position FROM constructorStandings AS T1 INNER JOIN constructors AS T2 ON T2.constructorId = T1.constructorId WHERE T2.name = 'Renault'

simple

Renault is a name of constructor;

formula_1

How many races in the year 2010 are held on grand prixs outside Asia and Europe?

SELECT COUNT(T3.raceId) FROM circuits AS T1 INNER JOIN races AS T3 ON T3.circuitID = T1.circuitId WHERE T1.country NOT IN ( 'Bahrain', 'China', 'Singapore', 'Japan', 'Korea', 'Turkey', 'UAE', 'Malaysia', 'Spain', 'Monaco', 'Azerbaijan', 'Austria', 'Belgium', 'France', 'Germany', 'Hungary', 'Italy', 'UK' ) AND T3.year = 2010

moderate

formula_1

Please give the names of the races held on the circuits in Spain.

SELECT DISTINCT T2.name FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.country = 'Spain'

simple

Spain is a name of country;

formula_1

What is the location coordinates of the circuits for Australian grand prix?

SELECT DISTINCT T1.lat, T1.lng FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.name = 'Australian Grand Prix'

simple

coordinates refers to (lat, lng);

formula_1

Where can I find the information about the races held on Sepang International Circuit?

SELECT DISTINCT T1.url FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.name = 'Sepang International Circuit'

simple

information about races refers to url;

formula_1

Please list the time of the races held on Sepang International Circuit.

SELECT DISTINCT T2.time FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.name = 'Sepang International Circuit'

simple

formula_1

Give the coordinate position for Abu Dhabi Grand Prix.

SELECT DISTINCT T1.lat, T1.lng, T1.location FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.name = 'Abu Dhabi Grand Prix'

simple

coordinates refers to (lat, lng); position and location shares the same meaning.

formula_1

Which country is the constructor which got 1 point in the race No. 24 from?

SELECT T2.nationality FROM constructorResults AS T1 INNER JOIN constructors AS T2 ON T2.constructorId = T1.constructorId WHERE T1.raceId = 24 AND T1.points = 1

simple

race number refers to raceId;

formula_1

What's Bruno Senna's Q1 result in the qualifying race No. 354?

SELECT T1.q1 FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 354 AND T2.forename = 'Bruno' AND T2.surname = 'Senna'

simple

race number refers to raceId;

formula_1

For the driver who had the Q2 time as 0:01:40 in the qualifying race No. 355, what is his nationality?

SELECT DISTINCT T2.nationality FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 355 AND T1.q2 LIKE '1:40%'

simple

race number refers to raceId;

formula_1

What is his number of the driver who finished 0:01:54 in the Q3 of qualifying race No.903?

SELECT T2.number FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 903 AND T1.q3 LIKE '1:54%'

simple

race number refers to raceId;

formula_1

For the Bahrain Grand Prix in 2007, how many drivers not finished the game?

SELECT COUNT(T3.driverId) FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T1.year = 2007 AND T1.name = 'Bahrain Grand Prix' AND T2.time IS NULL

simple

drivers who finished the race refers to time has records;

formula_1

Show me the season page of year when the race No. 901 took place.

SELECT T2.url FROM races AS T1 INNER JOIN seasons AS T2 ON T2.year = T1.year WHERE T1.raceId = 901

simple

race number refers to raceId;

formula_1

For the race happened on 2015/11/29, how many drivers finished the game?

SELECT COUNT(T2.driverId) FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId WHERE T1.date = '2015-11-29' AND T2.time IS NOT NULL

simple

game and race are synonyms; drivers who finished the race should have record in time;

formula_1

For all the drivers who finished the game in race No. 592, who is the oldest?

SELECT T1.forename, T1.surname FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T2.raceId = 592 AND T2.time IS NOT NULL AND T1.dob IS NOT NULL ORDER BY T1.dob ASC LIMIT 1

moderate

drivers who finished the race refers to time is not empty; oldest driver refers to oldest dob;

formula_1

Who was the player that got the lap time of 0:01:27 in the race No. 161? Show his introduction website.

SELECT DISTINCT T2.forename, T2.surname, T2.url FROM lapTimes AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 161 AND T1.time LIKE '1:27%'

moderate

player and driver are synonyms; race number refers to raceId; introduction website of the drivers refers to url;

formula_1

For the driver who set the fastest lap speed in race No.933, where does he come from?

SELECT T1.nationality FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T2.raceId = 933 AND T2.fastestLapTime IS NOT NULL ORDER BY T2.fastestLapSpeed DESC LIMIT 1

simple

fastest lap speed refers to MAX(fastestLapSpeed);

formula_1

Where is Malaysian Grand Prix held? Give the location coordinates.

SELECT DISTINCT T1.lat, T1.lng FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.name = 'Malaysian Grand Prix'

simple

coordinates refers to (lat, lng);

formula_1

For the constructor which got the highest point in the race No. 9 , what is its introduction website?

SELECT T2.url FROM constructorResults AS T1 INNER JOIN constructors AS T2 ON T2.constructorId = T1.constructorId WHERE T1.raceId = 9 ORDER BY T1.points DESC LIMIT 1

moderate

race number refers to raceId; introduction website of the constructor refers to url;

formula_1

What's Lucas di Grassi's Q1 result in the race No. 345?

SELECT T1.q1 FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 345 AND T2.forename = 'Lucas' AND T2.surname = 'di Grassi'

simple

race number refers to raceId;

formula_1

For the driver who had the Q2 time as 0:01:15 in race No. 347, where is he from?

SELECT DISTINCT T2.nationality FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 347 AND T1.q2 LIKE '1:15%'

simple

race number refers to raceId;

formula_1

In the race No. 45, for the driver who had the Q3 time as 0:01:33, what is his abbreviated code?

SELECT T2.code FROM qualifying AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 45 AND T1.q3 LIKE '1:33%'

simple

race number refers to raceId;

formula_1

What is the actual finish time for Bruce McLaren in the race No.743?

SELECT T2.time FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T2.raceId = 743 AND T1.forename = 'Bruce' AND T1.surname = 'McLaren'

simple

race number refers to raceId;

formula_1

Who finished second in the San Marino Grand Prix in 2006?

SELECT T3.forename, T3.surname FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T1.year = 2006 AND T1.name = 'San Marino Grand Prix' AND T2.position = 2

simple

finished second refers to position = 2;

formula_1

Show me the season page of year when the race No. 901 took place.

SELECT T2.url FROM races AS T1 INNER JOIN seasons AS T2 ON T2.year = T1.year WHERE T1.raceId = 901

simple

race number refers to raceId;

formula_1

For the race happened in 2015/11/29, how many drivers finished the game?

SELECT COUNT(T2.driverId) FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId WHERE T1.date = '2015-11-29' AND T2.time IS NOT NULL

simple

formula_1

For all the drivers who finished the game in race No. 872, who is the youngest?

SELECT T1.forename, T1.surname FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T2.raceId = 872 AND T2.time IS NOT NULL ORDER BY T1.dob DESC LIMIT 1

moderate

race number refers to raceId; drivers who finished the race refers to time has value; the youngest is a driver where MAX(dob);

formula_1

Who was the driver that got the best lap time in the race No. 348? Give his full name.

SELECT T2.forename, T2.surname FROM lapTimes AS T1 INNER JOIN drivers AS T2 ON T2.driverId = T1.driverId WHERE T1.raceId = 348 ORDER BY T1.time ASC LIMIT 1

simple

race number refers to raceId; the best lap time refers to MIN(time)

formula_1

For the driver who set the fastest lap speed, what is his nationality?

SELECT T1.nationality FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T2.fastestLapTime IS NOT NULL ORDER BY T2.fastestLapSpeed DESC LIMIT 1

moderate

the fastest lap speed refers to (MAX) fastestLapSpeed SQL mentions raceId = 348, that is not in the question

formula_1

Paul di Resta was in the No. 853 race, what percent faster did he finish in the 853rd race than the next race for the fastest lap speed?

SELECT (SUM(IIF(T2.raceId = 853, T2.fastestLapSpeed, 0)) - SUM(IIF(T2.raceId = 854, T2.fastestLapSpeed, 0))) * 100 / SUM(IIF(T2.raceId = 853, T2.fastestLapSpeed, 0)) FROM drivers AS T1 INNER JOIN results AS T2 ON T2.driverId = T1.driverId WHERE T1.forename = 'Paul' AND T1.surname = 'di Resta'

challenging

race number refers to raceId; DIVIDE(SUBTRACT(fastestLapSpeed(raceId = 853), (fastestLapSpeed (raceId = 854)), (fastestLapSpeed(raceId = 853)) as percentage

formula_1

For the drivers who took part in the race in 1983/7/16, what's their race completion rate?

SELECT CAST(COUNT(CASE WHEN T2.time IS NOT NULL THEN T2.driverId END) AS REAL) * 100 / COUNT(T2.driverId) FROM races AS T1 INNER JOIN results AS T2 ON T2.raceId = T1.raceId WHERE T1.date = '1983-07-16'

moderate

DIVIDE(COUNT(driverid where time has value and date = '1983-07-16'), (COUNT(driverid where date = '1983-07-16')) as percentage

formula_1

Which year was the first Singapore Grand Prix?

SELECT year FROM races WHERE name = 'Singapore Grand Prix' ORDER BY year ASC LIMIT 1

simple

the first race refers to race happened in min(year);

formula_1

How many races were there in 2005? Name all the races in descending order.

SELECT name FROM races WHERE year = 2005 ORDER BY name DESC

simple

formula_1

Name the first race recorded. What are the other races that happened within the same month and year of that race.

SELECT name FROM races WHERE STRFTIME('%Y', date) = ( SELECT STRFTIME('%Y', date) FROM races ORDER BY date ASC LIMIT 1 ) AND STRFTIME('%m', date) = ( SELECT STRFTIME('%m', date) FROM races ORDER BY date ASC LIMIT 1 )

moderate

the first race refers to year = year(min(date)) and month = month(min(date));

formula_1

State the name and date of the last round of race in year 1999.

SELECT name, date FROM races WHERE year = 1999 ORDER BY round DESC LIMIT 1

simple

the last round refers to max(round);

formula_1

Which year has the most number of races?

SELECT year FROM races GROUP BY year ORDER BY COUNT(round) DESC LIMIT 1

simple

the most number of races refers to max(round);

formula_1

Name the races in year 2017 that are not hosted in year 2000.

SELECT name FROM races WHERE year = 2017 AND name NOT IN ( SELECT name FROM races WHERE year = 2000 )

simple

not hosted means not in;

formula_1

In which country was the first European Grand Prix hosted? Name the circuit and location.

SELECT T1.country, T1.location FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T2.name = 'European Grand Prix' ORDER BY T2.year ASC LIMIT 1

simple

the first refers to min(year);

formula_1

When was the last f1 season whereby Brands Hatch hosted the British Grand Prix?

SELECT T2.date FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.name = 'Brands Hatch' AND T2.name = 'British Grand Prix' ORDER BY T2.year DESC LIMIT 1

simple

the last refers to max(year);

formula_1

How many seasons has Silverstone Circuit hosted the United Kindom grand prix?

SELECT COUNT(T2.circuitid) FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE T1.name = 'Silverstone Circuit' AND T2.name = 'British Grand Prix'

simple

British Grand Prix is the name of race; British refers to the United Kindom

formula_1

Name all drivers in the 2010 Singapore Grand Prix order by their position stands.

SELECT T3.forename, T3.surname FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T1.name = 'Singapore Grand Prix' AND T1.year = 2010 ORDER BY T2.position ASC

simple

formula_1

State the driver with the most points scored. Find his full name with that points.

SELECT T3.forename, T3.surname, T2.points FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId ORDER BY T2.points DESC LIMIT 1

moderate

the most points scored refers to max(points); full name contains forename and surname.

formula_1

Name the top 3 drivers and the points they scored in the 2017 Chinese Grand Prix.

SELECT T3.forename, T3.surname, T2.points FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T1.name = 'Chinese Grand Prix' AND T1.year = 2017 ORDER BY T2.points DESC LIMIT 3

simple

formula_1

What is the best lap time recorded? List the driver and race with such recorded lap time.

SELECT T2.milliseconds, T1.forename, T1.surname, T3.name FROM drivers AS T1 INNER JOIN lapTimes AS T2 ON T1.driverId = T2.driverId INNER JOIN races AS T3 ON T2.raceId = T3.raceId ORDER BY T2.milliseconds ASC LIMIT 1

moderate

the best lap time refers to min(time)

formula_1

What is the average lap time for Sebastian Vettel in the 2009 Chinese Grand Prix?

SELECT AVG(T2.milliseconds) FROM races AS T1 INNER JOIN lapTimes AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.forename = 'Sebastian' AND T3.surname = 'Vettel' AND T1.year = 2009 AND T1.name = 'Chinese GrAND Prix'

moderate

AVG(time);

formula_1

Calculate the percentage whereby Hamilton was not at the 1st track of the the f1 circuit since 2010.

SELECT CAST(COUNT(CASE WHEN T2.position <> 1 THEN T2.position END) AS REAL) * 100 / COUNT(T2.driverStandingsId) FROM races AS T1 INNER JOIN driverStandings AS T2 ON T2.raceId = T1.raceId INNER JOIN drivers AS T3 ON T3.driverId = T2.driverId WHERE T3.surname = 'Hamilton' AND T1.year >= 2010

challenging

DIVIDE(COUNT(raceId) where surname = 'Hamilton', year >= 2010 and position>1), (COUNT(raceId) where surname = 'Hamilton', year >= 2010) as percentage;

formula_1

Name the driver with the most winning. Mention his nationality and what is his average point scores.

SELECT T1.forename, T1.surname, T1.nationality, AVG(T2.points) FROM drivers AS T1 INNER JOIN driverStandings AS T2 ON T2.driverId = T1.driverId WHERE T2.wins = 1 GROUP BY T1.forename, T1.surname, T1.nationality ORDER BY COUNT(T2.wins) DESC LIMIT 1

moderate

the most winning refers to MAX(COUNT(wins)); avg(points);

formula_1

How old is the youngest Japanese driver? What is his name?

SELECT STRFTIME('%Y', CURRENT_TIMESTAMP) - STRFTIME('%Y', dob), forename , surname FROM drivers WHERE nationality = 'Japanese' ORDER BY dob DESC LIMIT 1

simple

youngest Japanese driver refers to max(dob); Japanese refers to nationality = 'Japanese'; age = 2022-year(dob)+1

formula_1

List circuits which host 4 f1 races from year 1990 to 2000.

SELECT DISTINCT T1.name FROM circuits AS T1 INNER JOIN races AS T2 ON T2.circuitID = T1.circuitId WHERE STRFTIME('%Y', T2.date) BETWEEN '1990' AND '2000' GROUP BY T1.name HAVING COUNT(T2.raceId) = 4

moderate

from year 1990 to 2000 refers to year(date) between 1990 and 2000;