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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 10:53:44 | i thought i knew this 😭😭 | 1 | 0 | nan | nan | nan | nan | 5,449,950 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:54:58 | are you literally in tears over this? | 0 | 1 | nan | nan | nan | nan | 5,449,951 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:55:13 | if so, i would advise you to do your best to calm down. | 0 | 1 | 220517274845577216 | Lena Jones | Lena Jones | False | 5,449,952 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:55:41 | emotional distress is a much more significant issue than one otherwise inconsequential math problem. | 0 | 1 | nan | nan | nan | nan | 5,449,953 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 10:56:40 | ur right. im just unsure as to how i should learn this tbh | 1 | 0 | nan | nan | nan | nan | 5,449,954 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 10:56:56 | like solving simultaneous equations with 3 variables? | 1 | 0 | nan | nan | nan | nan | 5,449,955 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:57:16 | no | 0 | 1 | nan | nan | nan | nan | 5,449,956 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:57:24 | what you have here is not a system of equations in three variables | 0 | 1 | nan | nan | nan | nan | 5,449,957 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:57:33 | at least, not presented as such by the problem | 0 | 1 | nan | nan | nan | nan | 5,449,958 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 10:58:11 | rather it is a family of systems of equations in two variables (x,y) where each system within the family is identified by a number (m) called the parameter | 0 | 1 | nan | nan | nan | nan | 5,449,959 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:01:23 | lowk not gonna lie i dont know what a parameter is | 1 | 0 | nan | nan | nan | nan | 5,449,960 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:01:30 | family of systems of equations? | 1 | 0 | 420244167726333953 | James Anderson | James Anderson | False | 5,449,961 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:02:18 | a collection of many systems of equations | 0 | 1 | 921607226098090074 | Pedro Green | Pedro Green | False | 5,449,962 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:02:33 | ...have you used desmos before in any capacity? | 0 | 1 | nan | nan | nan | nan | 5,449,963 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:03:24 | tep | 1 | 0 | nan | nan | nan | nan | 5,449,964 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:03:25 | yep | 1 | 0 | nan | nan | nan | nan | 5,449,965 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:03:29 | to graph equations | 1 | 0 | nan | nan | nan | nan | 5,449,966 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:03:59 | you can think of m as a slider | 0 | 1 | 235104133110169610 | Marc Garcia | Marc Garcia | False | 5,449,967 |
||
205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:04:18 | and each of these equations as a line that is graphed | 0 | 1 | nan | nan | nan | nan | 5,449,968 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:04:46 | and your task is to find the position(s) of the slider at which certain things happen | 0 | 1 | nan | nan | nan | nan | 5,449,969 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:04:54 | such as the system having infinitely many solutions, as in your problem | 0 | 1 | nan | nan | nan | nan | 5,449,970 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:09:04 | ohh ok!! | 1 | 0 | nan | nan | nan | nan | 5,449,971 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:09:25 | can you recommend a video that would teach me all this? | 1 | 0 | nan | nan | nan | nan | 5,449,972 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 647035568076881920 | Cesar White | 02/03/2022 11:09:37 | i tried looking for one but cant find a suitable one | 1 | 0 | nan | nan | nan | nan | 5,449,973 |
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205,867 | help-1 | 1ed2083b18b84d12ba7c78fe5bdb9e5b | 183668144404037632 | Kendra Brown | 02/03/2022 11:24:02 | i don't have any videos on hand sorry | 0 | 1 | nan | nan | nan | nan | 5,449,974 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:15:32 | unknown.png | 1 | 0 | nan | nan | nan | nan | 5,449,975 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:19:33 | Do u know log laws | 0 | 1 | nan | nan | nan | nan | 5,449,976 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 514829926449545218 | Cody Jackson | 02/03/2022 12:19:35 | . | 0 | 1 | nan | nan | nan | nan | 5,449,977 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:20:18 | yes | 1 | 0 | nan | nan | nan | nan | 5,449,978 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 514829926449545218 | Cody Jackson | 02/03/2022 12:20:31 | use log laws | 0 | 1 | nan | nan | nan | nan | 5,449,979 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 514829926449545218 | Cody Jackson | 02/03/2022 12:21:29 | do you know what e^ln(x) is? | 0 | 1 | nan | nan | nan | nan | 5,449,980 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:21:59 | ah its the 7th one | unknown.png | 1 | 0 | nan | nan | nan | nan | 5,449,981 |
|
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:22:04 | i only learned it till 5 | 1 | 0 | nan | nan | nan | nan | 5,449,982 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:22:11 | use this | unknown.png | 0 | 1 | nan | nan | nan | nan | 5,449,983 |
|
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 514829926449545218 | Cody Jackson | 02/03/2022 12:22:23 | yes | 0 | 1 | nan | nan | nan | nan | 5,449,984 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:22:34 | thank u both | 1 | 0 | nan | nan | nan | nan | 5,449,985 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:22:40 | do you know the base of ln? | 0 | 1 | nan | nan | nan | nan | 5,449,986 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:22:44 | ye e | 1 | 0 | nan | nan | nan | nan | 5,449,987 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:22:50 | yup | 0 | 1 | nan | nan | nan | nan | 5,449,988 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:23:07 | so $e^{\operatorname{log}_e(x)} = x$ | 0 | 1 | nan | nan | nan | nan | 5,449,989 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 610829937292869644 | Wayne Thompson | 02/03/2022 12:30:55 | how would u do this tho | unknown.png | 1 | 0 | nan | nan | nan | nan | 5,449,990 |
|
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:31:24 | ok so | 0 | 1 | nan | nan | nan | nan | 5,449,991 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:31:56 | sec | 0 | 1 | nan | nan | nan | nan | 5,449,992 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:36:28 | idk an easy solution to it. According to symbolab u should get $\operatorname{ln}^2(x) = \operatorname{ln}^3(x)$ | 0 | 1 | nan | nan | nan | nan | 5,449,993 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:36:53 | thus x = 1 or x = e, but i dont kkknow how they got to that equality | 0 | 1 | nan | nan | nan | nan | 5,449,994 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:39:43 | Take ln of both sides | 0 | 1 | nan | nan | nan | nan | 5,449,995 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:40:16 | And use logarith properties to simplify/bring stuff out of exponents | 0 | 1 | nan | nan | nan | nan | 5,449,996 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:41:42 | Take ln of the left side you get
ln (x^ln(x))
You can bring that exponent out as multiplication:
ln(x) * ln(x) = ln^2(x) | 0 | 1 | nan | nan | nan | nan | 5,449,997 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:42:36 | Take ln of the right
ln(e^ln^3(x)))
Ln cancels exponentiation with base e
So you get
ln^3(x) | 0 | 1 | 528652702184374278 | Gage Jackson | Gage Jackson | False | 5,449,998 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:44:39 | \begin{align} x^{\operatorname{ln}\,x} &= e^{(\operatorname{ln}\,x)^3} \notag\\
\operatorname{ln}(x^{\operatorname{ln}\,(x)}) &= \operatorname{ln}(e^{\operatorname{ln}^3 x}) \notag\\
\operatorname{ln}\,x \cdot \operatorname{ln}(x^1) &= (e^{(\operatorname{ln}^3 x)})\notag \\
\operatorname{ln}^2\,x &= (e^{(\operatorname{ln}^3 x)})\notag \\
\end{align} wip | 0 | 1 | 485903210272391178 | Kelvin Taylor | Kelvin Taylor | False | 5,449,999 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:56:35 | \begin{align} x^{\operatorname{ln}\,x} &= e^{(\operatorname{ln}\,x)^3} \notag\\
\operatorname{ln}(x^{\operatorname{ln}\,(x)}) &= \operatorname{ln}(e^{\operatorname{ln}^3 x}) \notag\\
\operatorname{ln}\,x \cdot \operatorname{ln}(x^1) &= \operatorname{ln}^3 x \cdot ln(e^1) \notag \\
\operatorname{ln}^2\,x &= \operatorname{ln}^3 x \cdot 1 \notag
\end{align} wip | 0 | 1 | nan | nan | nan | nan | 5,450,000 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:57:44 | can u correct this @zedzilla | 0 | 1 | nan | nan | nan | nan | 5,450,001 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:58:45 | Third line should be this on the right:
ln^3(x) * ln(e)
= ln^3(x) | 0 | 1 | nan | nan | nan | nan | 5,450,002 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:59:16 | Ln was dropped on the right between line 2 and 3 | 0 | 1 | nan | nan | nan | nan | 5,450,003 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 12:59:42 | Yea that looks ok | 0 | 1 | nan | nan | nan | nan | 5,450,004 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 12:59:46 | sec | 0 | 1 | nan | nan | nan | nan | 5,450,005 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 13:00:34 | i myself dont understand from line 2 to 3 RHS | 0 | 1 | nan | nan | nan | nan | 5,450,006 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:00:44 | Ok you have | 0 | 1 | 321445119171756033 | Bryce Martinez | Bryce Martinez | False | 5,450,007 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:00:50 | e^a | 0 | 1 | nan | nan | nan | nan | 5,450,008 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:00:55 | Take ln of that | 0 | 1 | nan | nan | nan | nan | 5,450,009 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:01:01 | ln(e^a) | 0 | 1 | nan | nan | nan | nan | 5,450,010 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:01:22 | Log property lets me bring that exponent inside the log outside as multiplication | 0 | 1 | nan | nan | nan | nan | 5,450,011 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:01:39 | So
ln(e^a) = a*ln(e) | 0 | 1 | 321445119171756033 | Bryce Martinez | Bryce Martinez | False | 5,450,012 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 13:01:39 | omg yes | 0 | 1 | nan | nan | nan | nan | 5,450,013 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:01:50 | Yep good stuff | 0 | 1 | nan | nan | nan | nan | 5,450,014 |
||
205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 13:01:56 | logs are the worst algebra ever | 0 | 1 | nan | nan | nan | nan | 5,450,015 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 205143587749494784 | Oliver Jones | 02/03/2022 13:02:10 | i'd take trig substitution integration over it (sometimes) | 0 | 1 | nan | nan | nan | nan | 5,450,016 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:02:11 | It doesn't matter what kind of weird exponent you have the property still works the same | 0 | 1 | nan | nan | nan | nan | 5,450,017 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:02:19 | Hahaha i love logs xD | 0 | 1 | nan | nan | nan | nan | 5,450,018 |
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205,868 | help-1 | 0dc25adf24cb40d2b847dfdbd9a8750d | 279869739415633920 | Erika Davis | 02/03/2022 13:02:48 | Well let me not say that who knows what kinda weird shit they have you do with them in some theory courses | 0 | 1 | nan | nan | nan | nan | 5,450,019 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 714074341809061898 | Mariah Ramirez | 02/03/2022 13:07:41 | P(x) = x^3+bx^2+cx+d is a polynomial in x. You are given that P(1) < 0, P(4) > 0, P(6) < 0 and P(10) > 0. If all of the roots of P(x) are integers, what is the maximum possible value of |d|? | 1 | 0 | nan | nan | nan | nan | 5,450,020 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:11:30 | oh this isn't so bad | 0 | 1 | nan | nan | nan | nan | 5,450,021 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:11:34 | think about it | 0 | 1 | 675710631143538688 | Reese Harris | Reese Harris | False | 5,450,022 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:11:50 | The roots are integers | 0 | 1 | nan | nan | nan | nan | 5,450,023 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:12:07 | If P(1) <0 and | 0 | 1 | nan | nan | nan | nan | 5,450,024 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:12:12 | P(4) > 0 | 0 | 1 | nan | nan | nan | nan | 5,450,025 |
||
205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:12:19 | What can you say happened between (1,4) | 0 | 1 | nan | nan | nan | nan | 5,450,026 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 872024354572103731 | Jessica Hill | 02/03/2022 13:12:22 | ? | 0 | 1 | nan | nan | nan | nan | 5,450,027 |
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205,869 | help-1 | 07e4a3e4223f4dc4a2318e46105e3641 | 706934233012371577 | Darius Clark | 02/03/2022 13:13:34 | ~~that sounds so haunted in so many ways~~ | 0 | 1 | nan | nan | nan | nan | 5,450,028 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 589246519295737857 | Brett Perez | 02/03/2022 13:39:51 | If i have 1000 images and i randomly view 50 of them every day, after how many days would i view every images in theory? Is it like coupon collector's problem? | 1 | 0 | nan | nan | nan | nan | 5,450,029 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 205143587749494784 | Oliver Jones | 02/03/2022 13:53:01 | I think they're asking for the mean of the distribution | 0 | 1 | nan | nan | nan | nan | 5,450,030 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 205143587749494784 | Oliver Jones | 02/03/2022 13:53:50 | idk which distribution it would be though, if its a common one | 0 | 1 | nan | nan | nan | nan | 5,450,031 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 261933205387477002 | Nicolas Miller | 02/03/2022 14:10:04 | yes it's exactly the coupon collector's problem | 0 | 1 | nan | nan | nan | nan | 5,450,032 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 589246519295737857 | Brett Perez | 02/03/2022 14:19:49 | Thanks | 1 | 0 | nan | nan | nan | nan | 5,450,033 |
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205,871 | help-1 | 2a3aff6718e54cd2a226b34e380abe79 | 589246519295737857 | Brett Perez | 02/03/2022 14:19:50 | .close | 1 | 0 | nan | nan | nan | nan | 5,450,034 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:22:55 | i am not sure how to find the probability of these. | unknown.png | 1 | 0 | nan | nan | nan | nan | 5,450,035 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:23:30 | im supposed to use the z table and this equation | 1 | 0 | nan | nan | nan | nan | 5,450,036 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:23:31 | unknown.png | 1 | 0 | nan | nan | nan | nan | 5,450,037 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:32:25 | do you know what $P(X=a)$ means? | 0 | 1 | nan | nan | nan | nan | 5,450,038 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:33:26 | it means the probability of x=something | 1 | 0 | nan | nan | nan | nan | 5,450,039 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:33:37 | and do you know what the formula $f(a)$ means? | 0 | 1 | nan | nan | nan | nan | 5,450,040 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:34:07 | isnt it just y? | 1 | 0 | nan | nan | nan | nan | 5,450,041 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:34:23 | im stuck at the part finding the mean | 1 | 0 | 706934233012371577 | Darius Clark | Darius Clark | False | 5,450,042 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:38:21 | where does it ask for the mean? | 0 | 1 | nan | nan | nan | nan | 5,450,043 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:38:47 | to find z, i need to find the mean | 1 | 0 | nan | nan | nan | nan | 5,450,044 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:39:09 | there are 4 parts here | 0 | 1 | nan | nan | nan | nan | 5,450,045 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:39:13 | none of them have z, nor need z | 0 | 1 | nan | nan | nan | nan | 5,450,046 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:39:57 | z is the z-table for the probability of the normal distribution | 1 | 0 | nan | nan | nan | nan | 5,450,047 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 326803048041283585 | Liliana Martinez | 02/03/2022 14:40:08 | i am supposed to use it to find the probability | 1 | 0 | nan | nan | nan | nan | 5,450,048 |
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205,872 | help-1 | dde2ece08f3c442cbc8e27ea116709cb | 261933205387477002 | Nicolas Miller | 02/03/2022 14:41:29 | i know z-tables. i also know none of the 4 questions in your image require z-tables | 0 | 1 | nan | nan | nan | nan | 5,450,049 |