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SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID
2,401
Please show the titles of films and the types of market estimations.
CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR)
SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995
2,402
Show the distinct director of films with market estimation in the year of 1995.
CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR)
SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000
2,403
What is the average number of cities of markets with low film market estimate bigger than 10000?
CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER)
SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID
2,404
Please list the countries and years of film market estimations.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR)
SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC
2,405
Please list the years of film market estimations when the market is in country "Japan" in descending order.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR)
SELECT Studio, COUNT(*) FROM film GROUP BY Studio
2,406
List the studios of each film and the number of films produced by that studio.
CREATE TABLE film (Studio VARCHAR)
SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1
2,407
List the name of film studio that have the most number of films.
CREATE TABLE film (Studio VARCHAR)
SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2
2,408
List the names of studios that have at least two films.
CREATE TABLE film (Studio VARCHAR)
SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation)
2,409
List the title of films that do not have any market estimation.
CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR)
SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill"
2,410
Show the studios that have produced films with director "Nicholas Meyer" and "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%"
2,411
Find the titles and studios of the films that are produced by some film studios that contained the word "Universal".
CREATE TABLE film (title VARCHAR, Studio VARCHAR)
SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill"
2,412
Show the studios that have not produced films with director "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000
2,413
List the studios which average gross is above 4500000.
CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER)
SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1
2,414
What is the title of the film that has the highest high market estimation.
CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR)
SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China')
2,415
What are the titles and directors of the films were never presented in China?
CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR)
SELECT COUNT(*) FROM Ref_calendar
2,416
How many calendar items do we have?
CREATE TABLE Ref_calendar (Id VARCHAR)
SELECT calendar_date, day_Number FROM Ref_calendar
2,417
Show all calendar dates and day Numbers.
CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR)
SELECT COUNT(*) FROM Ref_document_types
2,418
Show the number of document types.
CREATE TABLE Ref_document_types (Id VARCHAR)
SELECT document_type_code, document_type_name FROM Ref_document_types
2,419
List all document type codes and document type names.
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV"
2,420
What is the name and description for document type code RV?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR)
SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper"
2,421
What is the document type code for document type "Paper"?
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK"
2,422
Show the number of documents with document type code CV or BK.
CREATE TABLE All_documents (document_type_code VARCHAR)
SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV"
2,423
What is the date when the document "Marry CV" was stored?
CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR)
SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date
2,424
What is the day Number and date of all the documents?
CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR)
SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book"
2,425
What is the document type name for the document with name "How to read a book"?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR)
SELECT COUNT(*) FROM Ref_locations
2,426
Show the number of locations.
CREATE TABLE Ref_locations (Id VARCHAR)
SELECT location_code, location_name FROM Ref_locations
2,427
List all location codes and location names.
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x"
2,428
What are the name and description for location code x?
CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR)
SELECT location_code FROM Ref_locations WHERE location_name = "Canada"
2,429
What is the location code for the country "Canada"?
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
SELECT COUNT(*) FROM ROLES
2,430
How many roles are there?
CREATE TABLE ROLES (Id VARCHAR)
SELECT role_code, role_name, role_description FROM ROLES
2,431
List all role codes, role names, and role descriptions.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR)
SELECT role_name, role_description FROM ROLES WHERE role_code = "MG"
2,432
What are the name and description for role code "MG"?
CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
SELECT role_description FROM ROLES WHERE role_name = "Proof Reader"
2,433
Show the description for role name "Proof Reader".
CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR)
SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani'
2,434
Show the name, role code, and date of birth for the employee with name 'Armani'.
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR)
SELECT employee_ID FROM Employees WHERE employee_name = "Ebba"
2,435
What is the id for the employee called Ebba?
CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR)
SELECT employee_name FROM Employees WHERE role_code = "HR"
2,436
Show the names of all the employees with role "HR".
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code
2,437
Show all role codes and the number of employees in each role.
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1
2,438
What is the role code with the largest number of employees?
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3
2,439
Show all role codes with at least 3 employees.
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1
2,440
Show the role code with the least employees.
CREATE TABLE Employees (role_code VARCHAR)
SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba"
2,441
What is the role name and role description for employee called Ebba?
CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor"
2,442
Show the names of employees with role name Editor.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager"
2,443
Show the employee ids for all employees with role name "Human Resource" or "Manager".
CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR)
SELECT DISTINCT location_code FROM Document_locations
2,444
What are the different location codes for documents?
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV"
2,445
Show the location name for document "Robin CV".
CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR)
SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations
2,446
Show the location code, the starting date and ending data in that location for all the documents.
CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR)
SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV"
2,447
What is "the date in location from" and "the date in location to" for the document with name "Robin CV"?
CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR)
SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code
2,448
Show the location codes and the number of documents in each location.
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1
2,449
What is the location code with the most documents?
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3
2,450
Show the location codes with at least 3 documents.
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1
2,451
Show the location name and code with the least documents.
CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR)
SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id
2,452
What are the names of the employees who authorised the destruction and the employees who destroyed the corresponding documents?
CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR)
SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID
2,453
Show the id of each employee and the number of document destruction authorised by that employee.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID
2,454
Show the employee ids and the number of documents destroyed by each employee.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
2,455
Show the ids of the employees who don't authorize destruction for any document.
CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
2,456
Show the ids of all employees who have authorized destruction.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed
2,457
Show the ids of all employees who have destroyed a document.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed
2,458
Show the ids of all employees who don't destroy any document.
CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR)
SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
2,459
Show the ids of all employees who have either destroyed a document or made an authorization to do this.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT clubname FROM club
2,460
What are the names of all clubs?
CREATE TABLE club (clubname VARCHAR)
SELECT COUNT(*) FROM student
2,461
How many students are there?
CREATE TABLE student (Id VARCHAR)
SELECT DISTINCT fname FROM student
2,462
What are the first names of all the students?
CREATE TABLE student (fname VARCHAR)
SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore"
2,463
Find the last names of the members of the club "Bootup Baltimore".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises"
2,464
Who are the members of the club named "Hopkins Student Enterprises"? Show the last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club"
2,465
How many members does the club "Tennis Club" has?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming"
2,466
Find the number of members of club "Pen and Paper Gaming".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith"
2,467
How many clubs does "Linda Smith" belong to?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim"
2,468
Find the number of clubs where "Tracy Kim" is a member.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F"
2,469
Find all the female members of club "Bootup Baltimore". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M"
2,470
Find all the male members of club "Hopkins Student Enterprises". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600"
2,471
Find all members of "Bootup Baltimore" whose major is "600". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR)
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
2,472
Which club has the most members majoring in "600"?
CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
2,473
Find the name of the club that has the most female students.
CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT clubdesc FROM club WHERE clubname = "Tennis Club"
2,474
What is the description of the club named "Tennis Club"?
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming"
2,475
Find the description of the club "Pen and Paper Gaming".
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Tennis Club"
2,476
What is the location of the club named "Tennis Club"?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming"
2,477
Find the location of the club "Pen and Paper Gaming".
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises"
2,478
Where is the club "Hopkins Student Enterprises" located?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clubname FROM club WHERE clublocation = "AKW"
2,479
Find the name of all the clubs at "AKW".
CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR)
SELECT COUNT(*) FROM club WHERE clublocation = "HHH"
2,480
How many clubs are located at "HHH"?
CREATE TABLE club (clublocation VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President"
2,481
What are the first and last name of the president of the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO"
2,482
Who is the "CTO" of club "Hopkins Student Enterprises"? Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore"
2,483
How many different roles are there in the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18
2,484
How many members of "Bootup Baltimore" are older than 18?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18
2,485
How many members of club "Bootup Baltimore" are younger than 18?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL"
2,486
Find the names of all the clubs that have at least a member from the city with city code "BAL".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU"
2,487
Find the names of the clubs that have at least a member from the city with city code "HOU".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai"
2,488
How many clubs does the student named "Eric Tai" belong to?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven"
2,489
List the clubs having "Davis Steven" as a member.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121
2,490
List the clubs that have at least a member with advisor "1121".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore"
2,491
What is the average age of the members of the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises"
2,492
Find the average age of members of the club "Hopkins Student Enterprises".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club"
2,493
Retrieve the average age of members of the club "Tennis Club".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16'
2,494
What are the distinct grant amount for the grants where the documents were sent before '1986-08-26 20:49:27' and grant were ended after '1989-03-16 18:27:16'?
CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER)
SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent'
2,495
List the project details of the project both producing patent and paper as outcomes.
CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR)
SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research'
2,496
What is the total grant amount of the organisations described as research?
CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR)
SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader'
2,497
List from which date and to which date these staff work: project staff of the project which hires the most staffs
CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR)
SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000
2,498
Find the organisation ids and details of the organisations which are involved in
CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR)
SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1
2,499
What is the organisation type and id of the organisation which has the most number of research staff?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)
SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1
2,500
Which organisation type hires most research staff?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)