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allergy_1 | SELECT advisor , count(*) FROM Student GROUP BY advisor | How many students does each advisor have? | 500 |
allergy_1 | SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1 | Which advisor has most number of students? | 501 |
allergy_1 | SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1 | Give the advisor with the most students. | 502 |
allergy_1 | SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat" | How many students have cat allergies? | 503 |
allergy_1 | SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat" | How many students are affected by cat allergies? | 504 |
allergy_1 | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2 | Show all student IDs who have at least two allergies. | 505 |
allergy_1 | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2 | What are the students ids of students who have more than one allergy? | 506 |
allergy_1 | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy | What are the student ids of students who don't have any allergies? | 507 |
allergy_1 | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy | Which students are unaffected by allergies? | 508 |
allergy_1 | SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs" | How many female students have milk or egg allergies? | 509 |
allergy_1 | SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs" | How many students who are female are allergic to milk or eggs? | 510 |
allergy_1 | SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food" | How many students have a food allergy? | 511 |
allergy_1 | SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food" | How many students are affected by food related allergies? | 512 |
allergy_1 | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1 | Which allergy has most number of students affected? | 513 |
allergy_1 | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1 | Which allergy is the most common? | 514 |
allergy_1 | SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy | Show all allergies with number of students affected. | 515 |
allergy_1 | SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy | How many students have each different allergy? | 516 |
allergy_1 | SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype | Show all allergy type with number of students affected. | 517 |
allergy_1 | SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype | How many students are affected by each allergy type? | 518 |
allergy_1 | SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | Find the last name and age of the student who has allergy to both milk and cat. | 519 |
allergy_1 | SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | What are the last names and ages of the students who are allergic to milk and cat? | 520 |
allergy_1 | SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy | What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies. | 521 |
allergy_1 | SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy | What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names. | 522 |
allergy_1 | SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | Find the first name and gender of the student who has allergy to milk but not cat. | 523 |
allergy_1 | SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | What are the first name and gender of the students who have allergy to milk but can put up with cats? | 524 |
allergy_1 | SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal") | Find the average age of the students who have allergies with food and animal types. | 525 |
allergy_1 | SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal") | How old are the students with allergies to food and animal types on average? | 526 |
allergy_1 | SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | List the first and last name of the students who do not have any food type allergy. | 527 |
allergy_1 | SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | What is the full name of each student who is not allergic to any type of food. | 528 |
allergy_1 | SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | Find the number of male (sex is 'M') students who have some food type allery. | 529 |
allergy_1 | SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | How many male students (sex is 'M') are allergic to any type of food? | 530 |
allergy_1 | SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat" | Find the different first names and cities of the students who have allergy to milk or cat. | 531 |
allergy_1 | SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat" | What are the distinct first names and cities of the students who have allergy either to milk or to cat? | 532 |
allergy_1 | SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal") | Find the number of students who are older than 18 and do not have allergy to either food or animal. | 533 |
allergy_1 | SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal") | How many students are over 18 and do not have allergy to food type or animal type? | 534 |
allergy_1 | SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy") | Find the first name and major of the students who are not allegry to soy. | 535 |
allergy_1 | SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy") | What are the first name and major of the students who are able to consume soy? | 536 |
store_1 | SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5; | A list of the top 5 countries by number of invoices. List country name and number of invoices. | 537 |
store_1 | SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5; | What are the top 5 countries by number of invoices and how many do they have? | 538 |
store_1 | SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8; | A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size. | 539 |
store_1 | SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8; | What are the names of the top 8 countries by total invoice size and what are those sizes? | 540 |
store_1 | SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10; | A list of the top 10 countries by average invoice size. List country name and average invoice size. | 541 |
store_1 | SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10; | What are the names of the countries and average invoice size of the top countries by size? | 542 |
store_1 | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5; | Find out 5 customers who most recently purchased something. List customers' first and last name. | 543 |
store_1 | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5; | What are the first and last names of the 5 customers who purchased something most recently? | 544 |
store_1 | SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10; | Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders. | 545 |
store_1 | SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10; | What are the top 10 customers' first and last names by total number of orders and how many orders did they make? | 546 |
store_1 | SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10; | List the top 10 customers by total gross sales. List customers' first and last name and total gross sales. | 547 |
store_1 | SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10; | What are the top 10 customers' first and last names with the highest gross sales, and also what are the sales? | 548 |
store_1 | SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5; | List the top 5 genres by number of tracks. List genres name and total tracks. | 549 |
store_1 | SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5; | How many tracks does each genre have and what are the names of the top 5? | 550 |
store_1 | SELECT title FROM albums; | List every album's title. | 551 |
store_1 | SELECT title FROM albums; | What are the titles of all the albums? | 552 |
store_1 | SELECT title FROM albums ORDER BY title; | List every album ordered by album title in ascending order. | 553 |
store_1 | SELECT title FROM albums ORDER BY title; | What are the titles of all the albums alphabetically ascending? | 554 |
store_1 | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title; | List every album whose title starts with A in alphabetical order. | 555 |
store_1 | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title; | What are the titles of all albums that start with A in alphabetical order? | 556 |
store_1 | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10; | List the customers first and last name of 10 least expensive invoices. | 557 |
store_1 | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10; | What are the first and last names of the customers with the 10 cheapest invoices? | 558 |
store_1 | SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | List total amount of invoice from Chicago, IL. | 559 |
store_1 | SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | What are the total amount of money in the invoices billed from Chicago, Illinois? | 560 |
store_1 | SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | List the number of invoices from Chicago, IL. | 561 |
store_1 | SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | How many invoices were billed from Chicago, IL? | 562 |
store_1 | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state; | List the number of invoices from the US, grouped by state. | 563 |
store_1 | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state; | How many invoices were billed from each state? | 564 |
store_1 | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1; | List the state in the US with the most invoices. | 565 |
store_1 | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1; | What are the states with the most invoices? | 566 |
store_1 | SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA"; | List the number of invoices and the invoice total from California. | 567 |
store_1 | SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA"; | What is the number of invoices and total money billed in them from CA? | 568 |
store_1 | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"; | List Aerosmith's albums. | 569 |
store_1 | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"; | What are the titles of all the Aerosmith albums? | 570 |
store_1 | SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"; | How many albums does Billy Cobham has? | 571 |
store_1 | SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"; | How many albums has Billy Cobam released? | 572 |
store_1 | SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"; | Eduardo Martins is a customer at which company? | 573 |
store_1 | SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"; | What is the company where Eduardo Martins is a customer? | 574 |
store_1 | SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"; | What is Astrid Gruber's email and phone number? | 575 |
store_1 | SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"; | What is the email and phone number of Astrid Gruber the customer? | 576 |
store_1 | SELECT count(*) FROM customers WHERE city = "Prague"; | How many customers live in Prague city? | 577 |
store_1 | SELECT count(*) FROM customers WHERE city = "Prague"; | How many customers live in the city of Prague? | 578 |
store_1 | SELECT count(*) FROM customers WHERE state = "CA"; | How many customers in state of CA? | 579 |
store_1 | SELECT count(*) FROM customers WHERE state = "CA"; | How many customers are from California? | 580 |
store_1 | SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"; | What country does Roberto Almeida live? | 581 |
store_1 | SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"; | In which country does Roberto Almeida? | 582 |
store_1 | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' | List the name of albums that are released by aritist whose name has 'Led' | 583 |
store_1 | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' | What is the title of the album that was released by the artist whose name has the phrase 'Led'? | 584 |
store_1 | SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"; | How many customers does Steve Johnson support? | 585 |
store_1 | SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"; | What is the count of customers that Steve Johnson supports? | 586 |
store_1 | SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is the title, phone and hire date of Nancy Edwards? | 587 |
store_1 | SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is the title, phone number and hire date for the employee named Nancy Edwards? | 588 |
store_1 | SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"; | find the full name of employees who report to Nancy Edwards? | 589 |
store_1 | SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"; | What is the first and last name of the employee who reports to Nancy Edwards? | 590 |
store_1 | SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is the address of employee Nancy Edwards? | 591 |
store_1 | SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is Nancy Edwards's address? | 592 |
store_1 | SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | Find the full name of employee who supported the most number of customers. | 593 |
store_1 | SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | What is the full name of the employee who has the most customers? | 594 |
store_1 | SELECT count(*) FROM employees WHERE country = "Canada"; | How many employees are living in Canada? | 595 |
store_1 | SELECT count(*) FROM employees WHERE country = "Canada"; | How many employees live in Canada? | 596 |
store_1 | SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is employee Nancy Edwards's phone number? | 597 |
store_1 | SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | What is the the phone number of Nancy Edwards? | 598 |
store_1 | SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1; | Who is the youngest employee in the company? List employee's first and last name. | 599 |