Q:

Read files from Stream

I posted two files to my custom web service.  Now I need to read this stream into separate files. 
I've sent an XML and a Text file and in the web service I read it as following:
StreamReader stream = new StreamReader(HttpContext. Current. Request. InputStream);
string xmls = stream. ReadToEnd(); 

I get the stream as string as following (I've also added the boundaries):
"\r\n------------------------------8cfd42d26566ff0\r\nContent-Disposition: form-data; name=\"uplTheFile\"; filename=\"E:\\AJ\\Demo\\EktronSite2\\XMLFiles\\XMLFile.xml\"\r\n Content-Type: application/octet-stream\r\n\r\n﻿<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n<note xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns=\"http://tempuri.org/XMLFile.xsd\">\r\n  <ID>101</ID>\r\n</note>\r\n------------------------------8cfd42d26566ff0\r\nContent-Disposition: form-data; name=\"uplTheFile\"; filename=\"C:\\TEMP\\log.txt\"\r\n Content-Type: application/octet-stream\r\n\r\nABCDEFGHIJKLMNOPQRSTUVWXYZ\r\n------------------------------8cfd42d26566ff0\r\n"

I need to read the same into different files.  For example I need the XML read to XmlDocument type and the text to .docx.  
Thanks in advance. 

A:

Have you try this :
Stream xmlStream = System. Web. HttpContext. Current. Request. Files[0].InputStream;
Stream txtStream = System. Web. HttpContext. Current. Request. Files[1].InputStream;

