Q:

Java set accept on http get

I am trying to send a request to a server using GET that will respond with XML.   I am told that I need to set the "Accept" property, code follows:
StringBuffer url = new StringBuffer(BASE_URL);
url.append(DRS_SERVICE_RELATIVE_URL);
url.append("?").append(DOC_PARAM_NAME).append("=").append(docId);
url.append("&").append(DOB_PARAM_NAME).append("=").append(dob);

try
{
    this.server = new URL(url.toString());

    URLConnection urlCon = this.server.openConnection();
    HttpURLConnection con = (HttpURLConnection)urlCon;

    con.addRequestProperty("Accept", "text/xml, application/*+xml, application/xml, text/xml, application/*+xml");

    con.connect();

    input = new BufferedReader(new InputStreamReader(con.getInputStream()));
    String line = null;

    while((line = input.readLine()) ! = null)
        System.out.println(line);

I get response code 500.   When I talk to the developers of the URL I am trying to access they say I am not setting the "Accept" property to XML?   What am I doing wrong?   How are you supposed to set that property? 
EDIT:
OK this is embarassing.   The problem had to do with my development enviroment, specifically the way I set up a TCP/IP monitoring tool.   When I stopped monitoring the network messages it worked as expected. 

A:

The problem had to do with my development enviroment, specifically the way I set up a TCP/IP monitoring tool.  When I stopped monitoring the network messages it worked as expected.