Q:

Probability with one percentage

If 40% of people have watched TV today, what is the probability that the three people you pick haven't watched TV today?  The people are randomly selected and not replaced.  I've just been stumped on this problem even though I know I've done something similar. 

A:

P(TV) = 0.4
P(Not TV) = 0.6
0.6 * 0.6 * 0.6 = 0.216 OR 21.6%
This is assuming that it is a complementary scenario.