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Question: Find the dates on which more than one revisions were made.
Context: CREATE TABLE Catalogs (date_of_latest_revision VARCHAR)
Answer: | SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING COUNT(*) > 1 |
Question: How many products are there in the records?
Context: CREATE TABLE catalog_contents (Id VARCHAR)
Answer: | SELECT COUNT(*) FROM catalog_contents |
Question: Name all the products with next entry ID greater than 8.
Context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, next_entry_id INTEGER)
Answer: | SELECT catalog_entry_name FROM catalog_contents WHERE next_entry_id > 8 |
Question: How many aircrafts do we have?
Context: CREATE TABLE Aircraft (Id VARCHAR)
Answer: | SELECT COUNT(*) FROM Aircraft |
Question: Show name and distance for all aircrafts.
Context: CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
Answer: | SELECT name, distance FROM Aircraft |
Question: Show ids for all aircrafts with more than 1000 distance.
Context: CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER)
Answer: | SELECT aid FROM Aircraft WHERE distance > 1000 |
Question: How many aircrafts have distance between 1000 and 5000?
Context: CREATE TABLE Aircraft (distance INTEGER)
Answer: | SELECT COUNT(*) FROM Aircraft WHERE distance BETWEEN 1000 AND 5000 |
Question: What is the name and distance for aircraft with id 12?
Context: CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR, aid VARCHAR)
Answer: | SELECT name, distance FROM Aircraft WHERE aid = 12 |
Question: What is the minimum, average, and maximum distance of all aircrafts.
Context: CREATE TABLE Aircraft (distance INTEGER)
Answer: | SELECT MIN(distance), AVG(distance), MAX(distance) FROM Aircraft |
Question: Show the id and name of the aircraft with the maximum distance.
Context: CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR, distance VARCHAR)
Answer: | SELECT aid, name FROM Aircraft ORDER BY distance DESC LIMIT 1 |
Question: Show the name of aircrafts with top three lowest distances.
Context: CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
Answer: | SELECT name FROM Aircraft ORDER BY distance LIMIT 3 |
Question: Show names for all aircrafts with distances more than the average.
Context: CREATE TABLE Aircraft (name VARCHAR, distance INTEGER)
Answer: | SELECT name FROM Aircraft WHERE distance > (SELECT AVG(distance) FROM Aircraft) |
Question: How many employees do we have?
Context: CREATE TABLE Employee (Id VARCHAR)
Answer: | SELECT COUNT(*) FROM Employee |
Question: Show name and salary for all employees sorted by salary.
Context: CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
Answer: | SELECT name, salary FROM Employee ORDER BY salary |
Question: Show ids for all employees with at least 100000 salary.
Context: CREATE TABLE Employee (eid VARCHAR, salary INTEGER)
Answer: | SELECT eid FROM Employee WHERE salary > 100000 |
Question: How many employees have salary between 100000 and 200000?
Context: CREATE TABLE Employee (salary INTEGER)
Answer: | SELECT COUNT(*) FROM Employee WHERE salary BETWEEN 100000 AND 200000 |
Question: What is the name and salary for employee with id 242518965?
Context: CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
Answer: | SELECT name, salary FROM Employee WHERE eid = 242518965 |
Question: What is average and maximum salary of all employees.
Context: CREATE TABLE Employee (salary INTEGER)
Answer: | SELECT AVG(salary), MAX(salary) FROM Employee |
Question: Show the id and name of the employee with maximum salary.
Context: CREATE TABLE Employee (eid VARCHAR, name VARCHAR, salary VARCHAR)
Answer: | SELECT eid, name FROM Employee ORDER BY salary DESC LIMIT 1 |
Question: Show the name of employees with three lowest salaries.
Context: CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
Answer: | SELECT name FROM Employee ORDER BY salary LIMIT 3 |
Question: Show names for all employees with salary more than the average.
Context: CREATE TABLE Employee (name VARCHAR, salary INTEGER)
Answer: | SELECT name FROM Employee WHERE salary > (SELECT AVG(salary) FROM Employee) |
Question: Show the id and salary of Mark Young.
Context: CREATE TABLE Employee (eid VARCHAR, salary VARCHAR, name VARCHAR)
Answer: | SELECT eid, salary FROM Employee WHERE name = 'Mark Young' |
Question: How many flights do we have?
Context: CREATE TABLE Flight (Id VARCHAR)
Answer: | SELECT COUNT(*) FROM Flight |
Question: Show flight number, origin, destination of all flights in the alphabetical order of the departure cities.
Context: CREATE TABLE Flight (flno VARCHAR, origin VARCHAR, destination VARCHAR)
Answer: | SELECT flno, origin, destination FROM Flight ORDER BY origin |
Question: Show all flight number from Los Angeles.
Context: CREATE TABLE Flight (flno VARCHAR, origin VARCHAR)
Answer: | SELECT flno FROM Flight WHERE origin = "Los Angeles" |
Question: Show origins of all flights with destination Honolulu.
Context: CREATE TABLE Flight (origin VARCHAR, destination VARCHAR)
Answer: | SELECT origin FROM Flight WHERE destination = "Honolulu" |
Question: Show me the departure date and arrival date for all flights from Los Angeles to Honolulu.
Context: CREATE TABLE Flight (departure_date VARCHAR, arrival_date VARCHAR, origin VARCHAR, destination VARCHAR)
Answer: | SELECT departure_date, arrival_date FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu" |
Question: Show flight number for all flights with more than 2000 distance.
Context: CREATE TABLE Flight (flno VARCHAR, distance INTEGER)
Answer: | SELECT flno FROM Flight WHERE distance > 2000 |
Question: What is the average price for flights from Los Angeles to Honolulu.
Context: CREATE TABLE Flight (price INTEGER, origin VARCHAR, destination VARCHAR)
Answer: | SELECT AVG(price) FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu" |
Question: Show origin and destination for flights with price higher than 300.
Context: CREATE TABLE Flight (origin VARCHAR, destination VARCHAR, price INTEGER)
Answer: | SELECT origin, destination FROM Flight WHERE price > 300 |
Question: Show the flight number and distance of the flight with maximum price.
Context: CREATE TABLE Flight (flno VARCHAR, distance VARCHAR, price VARCHAR)
Answer: | SELECT flno, distance FROM Flight ORDER BY price DESC LIMIT 1 |
Question: Show the flight number of flights with three lowest distances.
Context: CREATE TABLE Flight (flno VARCHAR, distance VARCHAR)
Answer: | SELECT flno FROM Flight ORDER BY distance LIMIT 3 |
Question: What is the average distance and average price for flights from Los Angeles.
Context: CREATE TABLE Flight (distance INTEGER, price INTEGER, origin VARCHAR)
Answer: | SELECT AVG(distance), AVG(price) FROM Flight WHERE origin = "Los Angeles" |
Question: Show all origins and the number of flights from each origin.
Context: CREATE TABLE Flight (origin VARCHAR)
Answer: | SELECT origin, COUNT(*) FROM Flight GROUP BY origin |
Question: Show all destinations and the number of flights to each destination.
Context: CREATE TABLE Flight (destination VARCHAR)
Answer: | SELECT destination, COUNT(*) FROM Flight GROUP BY destination |
Question: Which origin has most number of flights?
Context: CREATE TABLE Flight (origin VARCHAR)
Answer: | SELECT origin FROM Flight GROUP BY origin ORDER BY COUNT(*) DESC LIMIT 1 |
Question: Which destination has least number of flights?
Context: CREATE TABLE Flight (destination VARCHAR)
Answer: | SELECT destination FROM Flight GROUP BY destination ORDER BY COUNT(*) LIMIT 1 |
Question: What is the aircraft name for the flight with number 99
Context: CREATE TABLE Flight (aid VARCHAR, flno VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
Answer: | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99 |
Question: Show all flight numbers with aircraft Airbus A340-300.
Context: CREATE TABLE Flight (flno VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
Answer: | SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300" |
Question: Show aircraft names and number of flights for each aircraft.
Context: CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
Answer: | SELECT T2.name, COUNT(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid |
Question: Show names for all aircraft with at least two flights.
Context: CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
Answer: | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING COUNT(*) >= 2 |
Question: How many employees have certificate.
Context: CREATE TABLE Certificate (eid VARCHAR)
Answer: | SELECT COUNT(DISTINCT eid) FROM Certificate |
Question: Show ids for all employees who don't have a certificate.
Context: CREATE TABLE Employee (eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR)
Answer: | SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate |
Question: Show names for all aircrafts of which John Williams has certificates.
Context: CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Employee (eid VARCHAR, name VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
Answer: | SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams" |
Question: Show names for all employees who have certificate of Boeing 737-800.
Context: CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
Answer: | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" |
Question: Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.
Context: CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
Answer: | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300" |
Question: Show names for all employees who do not have certificate of Boeing 737-800.
Context: CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Employee (name VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
Answer: | SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" |
Question: Show the name of aircraft which fewest people have its certificate.
Context: CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
Answer: | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY COUNT(*) DESC LIMIT 1 |
Question: Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.
Context: CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR, distance INTEGER)
Answer: | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY COUNT(*) >= 5 |
Question: what is the salary and name of the employee who has the most number of aircraft certificates?
Context: CREATE TABLE Certificate (eid VARCHAR); CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
Answer: | SELECT T1.name, T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1 |
Question: What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?
Context: CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
Answer: | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1 |
Question: How many allergies are there?
Context: CREATE TABLE Allergy_type (allergy VARCHAR)
Answer: | SELECT COUNT(DISTINCT allergy) FROM Allergy_type |
Question: How many different allergy types exist?
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT COUNT(DISTINCT allergytype) FROM Allergy_type |
Question: Show all allergy types.
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT DISTINCT allergytype FROM Allergy_type |
Question: Show all allergies and their types.
Context: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
Answer: | SELECT allergy, allergytype FROM Allergy_type |
Question: Show all allergies with type food.
Context: CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
Answer: | SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food" |
Question: What is the type of allergy Cat?
Context: CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR)
Answer: | SELECT allergytype FROM Allergy_type WHERE allergy = "Cat" |
Question: How many allergies have type animal?
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT COUNT(*) FROM Allergy_type WHERE allergytype = "animal" |
Question: Show all allergy types and the number of allergies in each type.
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT allergytype, COUNT(*) FROM Allergy_type GROUP BY allergytype |
Question: Which allergy type has most number of allergies?
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) DESC LIMIT 1 |
Question: Which allergy type has least number of allergies?
Context: CREATE TABLE Allergy_type (allergytype VARCHAR)
Answer: | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) LIMIT 1 |
Question: How many students are there?
Context: CREATE TABLE Student (Id VARCHAR)
Answer: | SELECT COUNT(*) FROM Student |
Question: Show first name and last name for all students.
Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR)
Answer: | SELECT Fname, Lname FROM Student |
Question: How many different advisors are listed?
Context: CREATE TABLE Student (advisor VARCHAR)
Answer: | SELECT COUNT(DISTINCT advisor) FROM Student |
Question: Show all majors.
Context: CREATE TABLE Student (Major VARCHAR)
Answer: | SELECT DISTINCT Major FROM Student |
Question: Show all cities where students live.
Context: CREATE TABLE Student (city_code VARCHAR)
Answer: | SELECT DISTINCT city_code FROM Student |
Question: Show first name, last name, age for all female students. Their sex is F.
Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Sex VARCHAR)
Answer: | SELECT Fname, Lname, Age FROM Student WHERE Sex = 'F' |
Question: Show student ids for all male students.
Context: CREATE TABLE Student (StuID VARCHAR, Sex VARCHAR)
Answer: | SELECT StuID FROM Student WHERE Sex = 'M' |
Question: How many students are age 18?
Context: CREATE TABLE Student (age VARCHAR)
Answer: | SELECT COUNT(*) FROM Student WHERE age = 18 |
Question: Show all student ids who are older than 20.
Context: CREATE TABLE Student (StuID VARCHAR, age INTEGER)
Answer: | SELECT StuID FROM Student WHERE age > 20 |
Question: Which city does the student whose last name is "Kim" live in?
Context: CREATE TABLE Student (city_code VARCHAR, LName VARCHAR)
Answer: | SELECT city_code FROM Student WHERE LName = "Kim" |
Question: Who is the advisor of student with ID 1004?
Context: CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
Answer: | SELECT Advisor FROM Student WHERE StuID = 1004 |
Question: How many students live in HKG or CHI?
Context: CREATE TABLE Student (city_code VARCHAR)
Answer: | SELECT COUNT(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI" |
Question: Show the minimum, average, and maximum age of all students.
Context: CREATE TABLE Student (age INTEGER)
Answer: | SELECT MIN(age), AVG(age), MAX(age) FROM Student |
Question: What is the last name of the youngest student?
Context: CREATE TABLE Student (LName VARCHAR, age INTEGER)
Answer: | SELECT LName FROM Student WHERE age = (SELECT MIN(age) FROM Student) |
Question: Show the student id of the oldest student.
Context: CREATE TABLE Student (StuID VARCHAR, age INTEGER)
Answer: | SELECT StuID FROM Student WHERE age = (SELECT MAX(age) FROM Student) |
Question: Show all majors and corresponding number of students.
Context: CREATE TABLE Student (major VARCHAR)
Answer: | SELECT major, COUNT(*) FROM Student GROUP BY major |
Question: Which major has most number of students?
Context: CREATE TABLE Student (major VARCHAR)
Answer: | SELECT major FROM Student GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1 |
Question: Show all ages and corresponding number of students.
Context: CREATE TABLE Student (age VARCHAR)
Answer: | SELECT age, COUNT(*) FROM Student GROUP BY age |
Question: Show the average age for male and female students.
Context: CREATE TABLE Student (sex VARCHAR, age INTEGER)
Answer: | SELECT AVG(age), sex FROM Student GROUP BY sex |
Question: Show all cities and corresponding number of students.
Context: CREATE TABLE Student (city_code VARCHAR)
Answer: | SELECT city_code, COUNT(*) FROM Student GROUP BY city_code |
Question: Show all advisors and corresponding number of students.
Context: CREATE TABLE Student (advisor VARCHAR)
Answer: | SELECT advisor, COUNT(*) FROM Student GROUP BY advisor |
Question: Which advisor has most number of students?
Context: CREATE TABLE Student (advisor VARCHAR)
Answer: | SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1 |
Question: How many students have cat allergies?
Context: CREATE TABLE Has_allergy (Allergy VARCHAR)
Answer: | SELECT COUNT(*) FROM Has_allergy WHERE Allergy = "Cat" |
Question: Show all student IDs who have at least two allergies.
Context: CREATE TABLE Has_allergy (StuID VARCHAR)
Answer: | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2 |
Question: What are the student ids of students who don't have any allergies?
Context: CREATE TABLE Has_allergy (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
Answer: | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy |
Question: How many female students have milk or egg allergies?
Context: CREATE TABLE Student (StuID VARCHAR, sex VARCHAR); CREATE TABLE has_allergy (StuID VARCHAR, allergy VARCHAR)
Answer: | SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs" |
Question: How many students have a food allergy?
Context: CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
Answer: | SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food" |
Question: Which allergy has most number of students affected?
Context: CREATE TABLE Has_allergy (Allergy VARCHAR)
Answer: | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1 |
Question: Show all allergies with number of students affected.
Context: CREATE TABLE Has_allergy (Allergy VARCHAR)
Answer: | SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy |
Question: Show all allergy type with number of students affected.
Context: CREATE TABLE Has_allergy (allergy VARCHAR); CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR)
Answer: | SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype |
Question: Find the last name and age of the student who has allergy to both milk and cat.
Context: CREATE TABLE Has_allergy (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (lname VARCHAR, age VARCHAR, StuID VARCHAR, Allergy VARCHAR)
Answer: | SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") |
Question: What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
Context: CREATE TABLE Has_allergy (Allergy VARCHAR, StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR); CREATE TABLE Allergy_type (Allergy VARCHAR, AllergyType VARCHAR)
Answer: | SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy |
Question: Find the first name and gender of the student who has allergy to milk but not cat.
Context: CREATE TABLE Student (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Has_allergy (fname VARCHAR, sex VARCHAR, StuID VARCHAR, Allergy VARCHAR)
Answer: | SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") |
Question: Find the average age of the students who have allergies with food and animal types.
Context: CREATE TABLE Student (age INTEGER, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR)
Answer: | SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal") |
Question: List the first and last name of the students who do not have any food type allergy.
Context: CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (StuID VARCHAR, Allergy VARCHAR)
Answer: | SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") |
Question: Find the number of male (sex is 'M') students who have some food type allery.
Context: CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Student (sex VARCHAR, StuID VARCHAR)
Answer: | SELECT COUNT(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") |
Question: Find the different first names and cities of the students who have allergy to milk or cat.
Context: CREATE TABLE Has_Allergy (stuid VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, city_code VARCHAR, stuid VARCHAR)
Answer: | SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat" |
Question: Find the number of students who are older than 18 and do not have allergy to either food or animal.
Context: CREATE TABLE Allergy_Type (Allergy VARCHAR, allergytype VARCHAR); CREATE TABLE Has_allergy (Allergy VARCHAR); CREATE TABLE Student (age VARCHAR, StuID VARCHAR)
Answer: | SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal") |
Question: Find the first name and major of the students who are not allegry to soy.
Context: CREATE TABLE Has_allergy (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR); CREATE TABLE Student (fname VARCHAR, major VARCHAR, StuID VARCHAR, Allergy VARCHAR)
Answer: | SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy") |