context
stringlengths
27
489
answer
stringlengths
18
557
question
stringlengths
12
244
CREATE TABLE tweets (text VARCHAR, createdate VARCHAR)
SELECT text FROM tweets ORDER BY createdate
List the text of all tweets in the order of date.
CREATE TABLE tweets (uid VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR)
SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid
Find the name of each user and number of tweets tweeted by each of them.
CREATE TABLE user_profiles (name VARCHAR, partitionid VARCHAR, uid VARCHAR); CREATE TABLE tweets (uid VARCHAR)
SELECT T1.name, T1.partitionid FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) < 2
Find the name and partition id for users who tweeted less than twice.
CREATE TABLE tweets (uid VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR)
SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) > 1
Find the name of the user who tweeted more than once, and number of tweets tweeted by them.
CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR); CREATE TABLE tweets (followers INTEGER, UID VARCHAR)
SELECT AVG(followers) FROM user_profiles WHERE NOT UID IN (SELECT UID FROM tweets)
Find the average number of followers for the users who do not have any tweet.
CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR); CREATE TABLE tweets (followers INTEGER, UID VARCHAR)
SELECT AVG(followers) FROM user_profiles WHERE UID IN (SELECT UID FROM tweets)
Find the average number of followers for the users who had some tweets.
CREATE TABLE user_profiles (followers INTEGER)
SELECT MAX(followers), SUM(followers) FROM user_profiles
Find the maximum and total number of followers of all users.
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR)
SELECT DISTINCT (catalog_entry_name) FROM catalog_contents
Find the names of all the catalog entries.
CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR)
SELECT attribute_data_type FROM Attribute_Definitions GROUP BY attribute_data_type HAVING COUNT(*) > 3
Find the list of attribute data types possessed by more than 3 attribute definitions.
CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR, attribute_name VARCHAR)
SELECT attribute_data_type FROM Attribute_Definitions WHERE attribute_name = "Green"
What is the attribute data type of the attribute with name "Green"?
CREATE TABLE Catalog_Structure (catalog_level_name VARCHAR, catalog_level_number INTEGER)
SELECT catalog_level_name, catalog_level_number FROM Catalog_Structure WHERE catalog_level_number BETWEEN 5 AND 10
Find the name and level of catalog structure with level between 5 and 10.
CREATE TABLE catalogs (catalog_publisher VARCHAR)
SELECT DISTINCT (catalog_publisher) FROM catalogs WHERE catalog_publisher LIKE "%Murray%"
Find all the catalog publishers whose name contains "Murray"
CREATE TABLE catalogs (catalog_publisher VARCHAR)
SELECT catalog_publisher FROM catalogs GROUP BY catalog_publisher ORDER BY COUNT(*) DESC LIMIT 1
Which catalog publisher has published the most catalogs?
CREATE TABLE catalogs (catalog_name VARCHAR, date_of_publication VARCHAR, catalog_id VARCHAR); CREATE TABLE catalog_structure (catalog_id VARCHAR)
SELECT t1.catalog_name, t1.date_of_publication FROM catalogs AS t1 JOIN catalog_structure AS t2 ON t1.catalog_id = t2.catalog_id WHERE catalog_level_number > 5
Find the names and publication dates of all catalogs that have catalog level number greater than 5.
CREATE TABLE Catalog_Contents_Additional_Attributes (catalog_entry_id VARCHAR, attribute_value VARCHAR); CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, catalog_entry_id VARCHAR); CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_value VARCHAR)
SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id = t2.catalog_entry_id WHERE t2.attribute_value = (SELECT attribute_value FROM Catalog_Contents_Additional_Attributes GROUP BY attribute_value ORDER BY COUNT(*) DESC LIMIT 1)
What are the entry names of catalog with the attribute possessed by most entries.
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, price_in_dollars VARCHAR)
SELECT catalog_entry_name FROM catalog_contents ORDER BY price_in_dollars DESC LIMIT 1
What is the entry name of the most expensive catalog (in USD)?
CREATE TABLE catalog_structure (catalog_level_name VARCHAR, catalog_level_number VARCHAR); CREATE TABLE catalog_contents (catalog_level_number VARCHAR, price_in_dollars VARCHAR)
SELECT t2.catalog_level_name FROM catalog_contents AS t1 JOIN catalog_structure AS t2 ON t1.catalog_level_number = t2.catalog_level_number ORDER BY t1.price_in_dollars LIMIT 1
What is the level name of the cheapest catalog (in USD)?
CREATE TABLE catalog_contents (price_in_euros INTEGER)
SELECT AVG(price_in_euros), MIN(price_in_euros) FROM catalog_contents
What are the average and minimum price (in Euro) of all products?
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, height VARCHAR)
SELECT catalog_entry_name FROM catalog_contents ORDER BY height DESC LIMIT 1
What is the product with the highest height? Give me the catalog entry name.
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, capacity VARCHAR)
SELECT catalog_entry_name FROM catalog_contents ORDER BY capacity LIMIT 1
Find the name of the product that has the smallest capacity.
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, product_stock_number VARCHAR)
SELECT catalog_entry_name FROM catalog_contents WHERE product_stock_number LIKE "2%"
Find the names of all the products whose stock number starts with "2".
CREATE TABLE Catalog_Contents_Additional_Attributes (catalog_entry_id VARCHAR, catalog_level_number VARCHAR); CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, catalog_entry_id VARCHAR)
SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id = t2.catalog_entry_id WHERE t2.catalog_level_number = "8"
Find the names of catalog entries with level number 8.
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, LENGTH VARCHAR, width VARCHAR)
SELECT catalog_entry_name FROM catalog_contents WHERE LENGTH < 3 OR width > 5
Find the names of the products with length smaller than 3 or height greater than 5.
CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_id VARCHAR, attribute_value VARCHAR); CREATE TABLE Attribute_Definitions (attribute_name VARCHAR, attribute_id VARCHAR)
SELECT t1.attribute_name, t1.attribute_id FROM Attribute_Definitions AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.attribute_id = t2.attribute_id WHERE t2.attribute_value = 0
Find the name and attribute ID of the attribute definitions with attribute value 0.
CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, capacity VARCHAR, price_in_dollars INTEGER)
SELECT catalog_entry_name, capacity FROM Catalog_Contents WHERE price_in_dollars > 700
Find the name and capacity of products with price greater than 700 (in USD).
CREATE TABLE Catalogs (date_of_latest_revision VARCHAR)
SELECT date_of_latest_revision FROM Catalogs GROUP BY date_of_latest_revision HAVING COUNT(*) > 1
Find the dates on which more than one revisions were made.
CREATE TABLE catalog_contents (Id VARCHAR)
SELECT COUNT(*) FROM catalog_contents
How many products are there in the records?
CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, next_entry_id INTEGER)
SELECT catalog_entry_name FROM catalog_contents WHERE next_entry_id > 8
Name all the products with next entry ID greater than 8.
CREATE TABLE Aircraft (Id VARCHAR)
SELECT COUNT(*) FROM Aircraft
How many aircrafts do we have?
CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
SELECT name, distance FROM Aircraft
Show name and distance for all aircrafts.
CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER)
SELECT aid FROM Aircraft WHERE distance > 1000
Show ids for all aircrafts with more than 1000 distance.
CREATE TABLE Aircraft (distance INTEGER)
SELECT COUNT(*) FROM Aircraft WHERE distance BETWEEN 1000 AND 5000
How many aircrafts have distance between 1000 and 5000?
CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR, aid VARCHAR)
SELECT name, distance FROM Aircraft WHERE aid = 12
What is the name and distance for aircraft with id 12?
CREATE TABLE Aircraft (distance INTEGER)
SELECT MIN(distance), AVG(distance), MAX(distance) FROM Aircraft
What is the minimum, average, and maximum distance of all aircrafts.
CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR, distance VARCHAR)
SELECT aid, name FROM Aircraft ORDER BY distance DESC LIMIT 1
Show the id and name of the aircraft with the maximum distance.
CREATE TABLE Aircraft (name VARCHAR, distance VARCHAR)
SELECT name FROM Aircraft ORDER BY distance LIMIT 3
Show the name of aircrafts with top three lowest distances.
CREATE TABLE Aircraft (name VARCHAR, distance INTEGER)
SELECT name FROM Aircraft WHERE distance > (SELECT AVG(distance) FROM Aircraft)
Show names for all aircrafts with distances more than the average.
CREATE TABLE Employee (Id VARCHAR)
SELECT COUNT(*) FROM Employee
How many employees do we have?
CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
SELECT name, salary FROM Employee ORDER BY salary
Show name and salary for all employees sorted by salary.
CREATE TABLE Employee (eid VARCHAR, salary INTEGER)
SELECT eid FROM Employee WHERE salary > 100000
Show ids for all employees with at least 100000 salary.
CREATE TABLE Employee (salary INTEGER)
SELECT COUNT(*) FROM Employee WHERE salary BETWEEN 100000 AND 200000
How many employees have salary between 100000 and 200000?
CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
SELECT name, salary FROM Employee WHERE eid = 242518965
What is the name and salary for employee with id 242518965?
CREATE TABLE Employee (salary INTEGER)
SELECT AVG(salary), MAX(salary) FROM Employee
What is average and maximum salary of all employees.
CREATE TABLE Employee (eid VARCHAR, name VARCHAR, salary VARCHAR)
SELECT eid, name FROM Employee ORDER BY salary DESC LIMIT 1
Show the id and name of the employee with maximum salary.
CREATE TABLE Employee (name VARCHAR, salary VARCHAR)
SELECT name FROM Employee ORDER BY salary LIMIT 3
Show the name of employees with three lowest salaries.
CREATE TABLE Employee (name VARCHAR, salary INTEGER)
SELECT name FROM Employee WHERE salary > (SELECT AVG(salary) FROM Employee)
Show names for all employees with salary more than the average.
CREATE TABLE Employee (eid VARCHAR, salary VARCHAR, name VARCHAR)
SELECT eid, salary FROM Employee WHERE name = 'Mark Young'
Show the id and salary of Mark Young.
CREATE TABLE Flight (Id VARCHAR)
SELECT COUNT(*) FROM Flight
How many flights do we have?
CREATE TABLE Flight (flno VARCHAR, origin VARCHAR, destination VARCHAR)
SELECT flno, origin, destination FROM Flight ORDER BY origin
Show flight number, origin, destination of all flights in the alphabetical order of the departure cities.
CREATE TABLE Flight (flno VARCHAR, origin VARCHAR)
SELECT flno FROM Flight WHERE origin = "Los Angeles"
Show all flight number from Los Angeles.
CREATE TABLE Flight (origin VARCHAR, destination VARCHAR)
SELECT origin FROM Flight WHERE destination = "Honolulu"
Show origins of all flights with destination Honolulu.
CREATE TABLE Flight (departure_date VARCHAR, arrival_date VARCHAR, origin VARCHAR, destination VARCHAR)
SELECT departure_date, arrival_date FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"
Show me the departure date and arrival date for all flights from Los Angeles to Honolulu.
CREATE TABLE Flight (flno VARCHAR, distance INTEGER)
SELECT flno FROM Flight WHERE distance > 2000
Show flight number for all flights with more than 2000 distance.
CREATE TABLE Flight (price INTEGER, origin VARCHAR, destination VARCHAR)
SELECT AVG(price) FROM Flight WHERE origin = "Los Angeles" AND destination = "Honolulu"
What is the average price for flights from Los Angeles to Honolulu.
CREATE TABLE Flight (origin VARCHAR, destination VARCHAR, price INTEGER)
SELECT origin, destination FROM Flight WHERE price > 300
Show origin and destination for flights with price higher than 300.
CREATE TABLE Flight (flno VARCHAR, distance VARCHAR, price VARCHAR)
SELECT flno, distance FROM Flight ORDER BY price DESC LIMIT 1
Show the flight number and distance of the flight with maximum price.
CREATE TABLE Flight (flno VARCHAR, distance VARCHAR)
SELECT flno FROM Flight ORDER BY distance LIMIT 3
Show the flight number of flights with three lowest distances.
CREATE TABLE Flight (distance INTEGER, price INTEGER, origin VARCHAR)
SELECT AVG(distance), AVG(price) FROM Flight WHERE origin = "Los Angeles"
What is the average distance and average price for flights from Los Angeles.
CREATE TABLE Flight (origin VARCHAR)
SELECT origin, COUNT(*) FROM Flight GROUP BY origin
Show all origins and the number of flights from each origin.
CREATE TABLE Flight (destination VARCHAR)
SELECT destination, COUNT(*) FROM Flight GROUP BY destination
Show all destinations and the number of flights to each destination.
CREATE TABLE Flight (origin VARCHAR)
SELECT origin FROM Flight GROUP BY origin ORDER BY COUNT(*) DESC LIMIT 1
Which origin has most number of flights?
CREATE TABLE Flight (destination VARCHAR)
SELECT destination FROM Flight GROUP BY destination ORDER BY COUNT(*) LIMIT 1
Which destination has least number of flights?
CREATE TABLE Flight (aid VARCHAR, flno VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99
What is the aircraft name for the flight with number 99
CREATE TABLE Flight (flno VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300"
Show all flight numbers with aircraft Airbus A340-300.
CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
SELECT T2.name, COUNT(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid
Show aircraft names and number of flights for each aircraft.
CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Flight (aid VARCHAR)
SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING COUNT(*) >= 2
Show names for all aircraft with at least two flights.
CREATE TABLE Certificate (eid VARCHAR)
SELECT COUNT(DISTINCT eid) FROM Certificate
How many employees have certificate.
CREATE TABLE Employee (eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR)
SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate
Show ids for all employees who don't have a certificate.
CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR); CREATE TABLE Employee (eid VARCHAR, name VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams"
Show names for all aircrafts of which John Williams has certificates.
CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
Show names for all employees who have certificate of Boeing 737-800.
CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300"
Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300.
CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Employee (name VARCHAR); CREATE TABLE Aircraft (aid VARCHAR, name VARCHAR)
SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800"
Show names for all employees who do not have certificate of Boeing 737-800.
CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR)
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY COUNT(*) DESC LIMIT 1
Show the name of aircraft which fewest people have its certificate.
CREATE TABLE Certificate (aid VARCHAR); CREATE TABLE Aircraft (name VARCHAR, aid VARCHAR, distance INTEGER)
SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY COUNT(*) >= 5
Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate.
CREATE TABLE Certificate (eid VARCHAR); CREATE TABLE Employee (name VARCHAR, salary VARCHAR, eid VARCHAR)
SELECT T1.name, T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
what is the salary and name of the employee who has the most number of aircraft certificates?
CREATE TABLE Aircraft (aid VARCHAR, distance INTEGER); CREATE TABLE Employee (name VARCHAR, eid VARCHAR); CREATE TABLE Certificate (eid VARCHAR, aid VARCHAR)
SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY COUNT(*) DESC LIMIT 1
What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000?
CREATE TABLE Allergy_type (allergy VARCHAR)
SELECT COUNT(DISTINCT allergy) FROM Allergy_type
How many allergies are there?
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT COUNT(DISTINCT allergytype) FROM Allergy_type
How many different allergy types exist?
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT DISTINCT allergytype FROM Allergy_type
Show all allergy types.
CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
SELECT allergy, allergytype FROM Allergy_type
Show all allergies and their types.
CREATE TABLE Allergy_type (allergy VARCHAR, allergytype VARCHAR)
SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food"
Show all allergies with type food.
CREATE TABLE Allergy_type (allergytype VARCHAR, allergy VARCHAR)
SELECT allergytype FROM Allergy_type WHERE allergy = "Cat"
What is the type of allergy Cat?
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT COUNT(*) FROM Allergy_type WHERE allergytype = "animal"
How many allergies have type animal?
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT allergytype, COUNT(*) FROM Allergy_type GROUP BY allergytype
Show all allergy types and the number of allergies in each type.
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) DESC LIMIT 1
Which allergy type has most number of allergies?
CREATE TABLE Allergy_type (allergytype VARCHAR)
SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY COUNT(*) LIMIT 1
Which allergy type has least number of allergies?
CREATE TABLE Student (Id VARCHAR)
SELECT COUNT(*) FROM Student
How many students are there?
CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR)
SELECT Fname, Lname FROM Student
Show first name and last name for all students.
CREATE TABLE Student (advisor VARCHAR)
SELECT COUNT(DISTINCT advisor) FROM Student
How many different advisors are listed?
CREATE TABLE Student (Major VARCHAR)
SELECT DISTINCT Major FROM Student
Show all majors.
CREATE TABLE Student (city_code VARCHAR)
SELECT DISTINCT city_code FROM Student
Show all cities where students live.
CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Sex VARCHAR)
SELECT Fname, Lname, Age FROM Student WHERE Sex = 'F'
Show first name, last name, age for all female students. Their sex is F.
CREATE TABLE Student (StuID VARCHAR, Sex VARCHAR)
SELECT StuID FROM Student WHERE Sex = 'M'
Show student ids for all male students.
CREATE TABLE Student (age VARCHAR)
SELECT COUNT(*) FROM Student WHERE age = 18
How many students are age 18?
CREATE TABLE Student (StuID VARCHAR, age INTEGER)
SELECT StuID FROM Student WHERE age > 20
Show all student ids who are older than 20.
CREATE TABLE Student (city_code VARCHAR, LName VARCHAR)
SELECT city_code FROM Student WHERE LName = "Kim"
Which city does the student whose last name is "Kim" live in?
CREATE TABLE Student (Advisor VARCHAR, StuID VARCHAR)
SELECT Advisor FROM Student WHERE StuID = 1004
Who is the advisor of student with ID 1004?
CREATE TABLE Student (city_code VARCHAR)
SELECT COUNT(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI"
How many students live in HKG or CHI?
CREATE TABLE Student (age INTEGER)
SELECT MIN(age), AVG(age), MAX(age) FROM Student
Show the minimum, average, and maximum age of all students.
CREATE TABLE Student (LName VARCHAR, age INTEGER)
SELECT LName FROM Student WHERE age = (SELECT MIN(age) FROM Student)
What is the last name of the youngest student?