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the effective annual rate of interest corresponding to a nominal rate of 14 % per annum payable half - yearly is ? | "each of the other explanations to this question has properly explained that you need to break down the calculation into pieces and figure out the repeatingpatternof the units digits . here ' s another way to organize the information . we ' re given [ ( 2222 ) ^ 333 ] [ ( 3333 ) ^ 222 ] we can ' combine ' some of the pieces and rewrite this product as . . . . ( [ ( 2222 ) ( 3333 ) ] ^ 222 ) [ ( 2222 ) ^ 111 ] ( 2222 ) ( 3333 ) = a big number that ends in a 6 taking a number that ends in a 6 and raising it to a power creates a nice pattern : 6 ^ 1 = 6 6 ^ 2 = 36 6 ^ 3 = 216 etc . thus , we know that ( [ ( 2222 ) ( 3333 ) ] ^ 222 ) will be a gigantic number that ends in a 6 . 2 ^ 111 requires us to figure out thecycleof the units digit . . . 2 ^ 1 = 2 2 ^ 2 = 4 2 ^ 3 = 8 2 ^ 4 = 16 2 ^ 5 = 32 2 ^ 6 = 64 2 ^ 7 = 128 2 ^ 8 = 256 so , every 4 powers , the pattern of the units digits repeats ( 2 , 4 , 8 , 6 . . . . . 2 , 4 , 8 , 6 . . . . ) . 111 = 27 sets of 4 with a remainder of 3 . . . . this means that 2 ^ 111 = a big number that ends in an 8 so we have to multiply a big number that ends in a 6 and a big number that ends in an 8 . ( 6 ) ( 8 ) = 48 , so the final product will be a gigantic number that ends in an 4 . final answer : c" | a ) 0 , b ) 2 , c ) 4 , d ) 6 , e ) 8 | c | add(add(const_4, const_3), const_2) | add(const_3,const_4)|add(#0,const_2)| | general |
in what time will a train 110 m long cross an electric pole , it its speed be 128 km / hr ? | length of the courtyard = 75 m breadth of the courtyard = 32 m perimeter of the courtyard = 2 ( 75 + 32 ) m = 2 Γ 107 m = 214 m distance covered by the boy in taking 4 rounds = 4 Γ perimeter of courtyard = 4 Γ 214 = 856 m we know that area of the courtyard = length Γ breadth = 75 Γ 32 m 2 = 2400 m 2 for 1 m 2 , the cost of levelling = $ 3 for 2400 m 2 , the cost of levelling = $ 3 Γ 2400 = $ 7200 answer : e | a ) 3573 , b ) 3455 , c ) 8600 , d ) 7000 , e ) 7200 | e | multiply(3, multiply(75, 32)) | multiply(n0,n1)|multiply(n2,#0) | physics |
pumps a , b , and c operate at their respective constant rates . pumps a and b , operating simultaneously , can fill a certain tank in 1 / 2 hours ; pumps a and c , operating simultaneously , can fill the tank in 1 / 2 hours ; and pumps b and c , operating simultaneously , can fill the tank in 2 hours . how many hours does it take pumps a , b , and c , operating simultaneously , to fill the tank . | "train c has traveled 20 mi in the half hour before train d has started its journey . 140 - 20 = 120 40 + 20 = 60 mph 120 mi / 60 mph = 2 hrs 4 : 40 pm + 2 hrs = 6 : 40 pm answer : c . 6 : 40" | a ) 5 : 00 , b ) 5 : 30 , c ) 6 : 40 , d ) 6 : 30 , e ) 7 : 00 | c | divide(add(4, const_2), 40) | add(n4,const_2)|divide(#0,n5)| | physics |
three numbers are in the ratio 3 : 4 : 5 and their l . c . m . is 1800 . their h . c . f is ? | "required answer = [ employee benefit / profit ] * 100 = [ ( 100 million ) / ( 2 billion ) ] * 100 = [ ( 100 * 10 ^ 6 ) / ( 2 * 10 ^ 9 ) ] * 100 = ( 50 / 1000 ) * 100 = 5 % so answer is ( c )" | a ) 50 % , b ) 20 % , c ) 5 % , d ) 2 % , e ) 0.2 % | c | multiply(divide(multiply(100, power(10, add(const_3, const_3))), multiply(2, power(10, 9))), const_100) | add(const_3,const_3)|power(n3,n4)|multiply(n0,#1)|power(n3,#0)|multiply(n1,#3)|divide(#4,#2)|multiply(#5,const_100)| | general |
at a certain company , each employee has a salary grade s that is at least 1 and at most 5 . each employee receives an hourly wage p , in dollars , determined by the formula p = 11.50 + 0.25 ( s β 1 ) . an employee with a salary grade of 5 receives how many more dollars per hour than an employee with a salary grade of 1 ? | explanation : ( man + boy ) β s 1 day β s work = 1 / 24 their 20 day β s work = 1 / 24 Γ 20 = 5 / 6 the remaining 1 / 6 work is done by the man in 6 days therefore , the man alone will finish the work in 6 Γ 6 days = 36 days man β s 1 day β s work = 1 / 36 therefore , boy β s 1 day β s work = 1 / 24 β 1 / 36 = 3 β 2 / 72 = 1 / 72 therefore , the boy alone will finish the work in 72 days . answer : option a | a ) 72 days , b ) 20 days , c ) 24 days , d ) 36 days , e ) 34 days | a | add(subtract(26, 6), multiply(26, const_2)) | multiply(n2,const_2)|subtract(n2,n1)|add(#0,#1) | physics |
a man two flats for $ 675958 each . on one he gains 16 % while on the other he loses 16 % . how much does he gain or lose in the whole transaction ? | answer is ( d ) . if mathew is left with about $ 350 after all expenses each month , he would need to divide the total expense budget to london ( $ 3000 ) by 12 months to determine how much he would need to put away every single month to hit his target . $ 3000 / 12 = $ 250 . | a ) $ 240 , b ) $ 350 , c ) $ 217 , d ) $ 250 , e ) $ 340 | d | divide(3000, 12) | divide(n1,n6) | general |
x does a work in 40 days . y does the same work in 60 days . in how many days they together will do the same work ? | "part filled by ( a + b + c ) in 3 minutes = 3 ( 1 / 30 + 1 / 20 + 1 / 10 ) = 11 / 20 part filled by c in 3 minutes = 3 / 10 required ratio = 3 / 10 * 20 / 11 = 6 / 11 answer : b" | a ) 6 / 15 , b ) 6 / 11 , c ) 6 / 14 , d ) 6 / 12 , e ) 6 / 13 | b | multiply(divide(3, 10), divide(const_1, multiply(3, add(divide(const_1, 10), add(divide(const_1, 30), divide(const_1, 30)))))) | divide(n3,n2)|divide(const_1,n0)|divide(const_1,n2)|add(#1,#1)|add(#3,#2)|multiply(n3,#4)|divide(const_1,#5)|multiply(#0,#6)| | physics |
in a certain group of 10 developers , 4 developers code only in python and the rest program in either ruby on rails or php - but not both . if a developer organization is to choose a 3 - member team , which must have at least 1 developer who codes in python , how many different programming teams can be chosen ? | "solution present worth = rs . [ 1014 / ( 1 + 4 / 100 ) Β² ] = rs . ( 1014 x 25 / 26 x 25 / 26 ) = rs . 937.5 answer b" | a ) rs . 150.50 , b ) rs . 937.5 , c ) rs . 156.25 , d ) rs . 158 , e ) none | b | divide(1014, power(add(divide(4, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | gain |
two bullet trains of equal lengths take 10 seconds and 30 seconds respectively to cross a telegraph post . if the length of each bullet train be 120 metres , in what time ( in seconds ) will they cross each other travelling in opposite direction ? | "( a β b ) β ( c + d ) = 15 and ( c β d ) β ( a + b ) = 3 = > ( a β c ) β ( b + d ) = 15 and ( c β a ) β ( b + d ) = 3 = > ( b + d ) = ( a β c ) β 15 and ( b + d ) = ( c β a ) β 3 = > ( a β c ) β 15 = ( c β a ) β 3 = > 2 ( a β c ) = 12 = > ( a β c ) = 6 answer : a" | a ) 6 , b ) 2 , c ) 3 , d ) 4 , e ) 5 | a | divide(15, 3) | divide(n0,n1)| | general |
if 0.5 : x : : 5 : 8 , then x is equal to : | "j + k = 281 and so k = 281 - j j - 8 = 2 k j - 8 = 2 ( 281 - j ) 3 j = 570 j = 190 the answer is e ." | a ) 125 , b ) 135 , c ) 140 , d ) 165 , e ) 190 | e | add(multiply(divide(subtract(281, 8), const_3), const_2), 8) | subtract(n1,n0)|divide(#0,const_3)|multiply(#1,const_2)|add(n0,#2)| | general |
3251 + 587 + 369 - ? = 3007 | "u dont need to go through all this what u have with u is 100 p + 200 c = $ 8.00 just divide the equation by 5 and you will get what u are looking for 20 p + 40 c = $ 1.60 therefore oa is e" | a ) $ . 90 , b ) $ 1.00 , c ) $ 1.20 , d ) $ 1.50 , e ) $ 1.60 | e | multiply(divide(20, 100), 8.00) | divide(n3,n0)|multiply(n2,#0)| | gain |
if 150 ! / 10 ^ n is an integer , what is the largest possible value of n ? | "a 42415758 4242 Γ 9999 = 4242 Γ ( 10000 - 1 ) = 4242 Γ 10000 - 4242 Γ 1 = 42420000 - 4242 = 42415758" | a ) 42415758 , b ) 42415751 , c ) 42415752 , d ) 42415753 , e ) 42415754 | a | multiply(divide(4242, 9999), const_100) | divide(n0,n1)|multiply(#0,const_100)| | general |
if n is an integer , f ( n ) = f ( n - 1 ) - n and f ( 4 ) = 13 . what is the value of f ( 6 ) ? | "explanation : average price of a goat = rs . 90 total price of 5 goats = 5 * 90 = rs . 450 but total price of 2 cows and 5 goats = rs . 1050 total price of 2 cows is = 1050 - 450 = 600 average price of a cow = 600 / 2 = rs . 300 answer : a" | a ) 300 , b ) 320 , c ) 330 , d ) 350 , e ) 375 | a | divide(subtract(1050, multiply(5, 90)), 2) | multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0)| | general |
the list price of an article is rs . 66 . a customer pays rs . 56.16 for it . he was given two successive discounts , one of them being 10 % . the other discount is ? | let us now solve for x : ( 4 / 5 ) x + ( 1 / 6 ) ( 49 - x ) = 24 24 x + 5 ( 49 - x ) = ( 24 ) ( 30 ) 24 x + 245 - 5 x = ( 24 ) ( 30 ) 19 x = 720 - 245 19 x = 475 x = 25 answer : e | a ) 5 , b ) 10 , c ) 15 , d ) 20 , e ) 25 | e | multiply(25, 1) | multiply(n1,n3) | other |
a certain animal in the zoo has consumed 39 pounds of food in 6 days . if it continues to eat at the same rate , in how many more days will its total consumption be 117 pounds ? | "let the required number of seconds be x more cloth , more time , ( direct proportion ) hence we can write as ( cloth ) 0.13 : 15 : : 1 : x = > 0.13 * x = 15 = > x = 15 / 0.13 = > x = 115 answer : b" | a ) 114 , b ) 115 , c ) 116 , d ) 117 , e ) 118 | b | divide(15, 0.13) | divide(n1,n0)| | physics |
30 men can complete a piece of work in 18 days . in how many days will 27 men complete the same work ? | "good question . so we have a garden where all the flowers have two properties : color ( green or yellow ) and shape ( straight or curved ) . we ' re told that 1 / 8 of the garden is green , so , since all the flowers must be either green or yellow , we know that 7 / 8 are yellow . we ' re also told there is an equal probability of straight or curved , 1 / 2 . we want to find out the probability of something being yellow and straight , pr ( yellow and straight ) . so if we recall , the probability of two unique events occurring simultaneously is the product of the two probabilities , pr ( a and b ) = p ( a ) * p ( b ) . so we multiply the two probabilities , pr ( yellow ) * pr ( straight ) = 7 / 8 * 1 / 2 = 4 / 9 , or e ." | a ) 1 / 7 , b ) 1 / 8 , c ) 1 / 4 , d ) 3 / 4 , e ) 4 / 9 | e | multiply(subtract(1, divide(1, 8)), divide(1, 2)) | divide(n2,n3)|divide(n0,n1)|subtract(n2,#1)|multiply(#0,#2)| | probability |
of the 150 employees at company x , 70 are full - time , and 100 have worked at company x for at least a year . there are 20 employees at company x who aren β t full - time and haven β t worked at company x for at least a year . how many full - time employees of company x have worked at the company for at least a year ? | a number not to be a multiple of 10 should not have the units digit of 0 . xxx 9 options for the first digit ( from 1 to 9 inclusive ) . 8 options for the third digit ( from 1 to 9 inclusive minus the one we used for the first digit ) . 8 options for the second digit ( from 0 to 9 inclusive minus 2 digits we used for the first and the third digits ) 9 * 8 * 8 = 576 . answer : a . | a ) 576 , b ) 520 , c ) 504 , d ) 432 , e ) 348 | a | multiply(multiply(multiply(3, 3), subtract(multiply(3, 3), const_1)), subtract(multiply(3, 3), const_1)) | multiply(n0,n0)|subtract(#0,const_1)|multiply(#0,#1)|multiply(#2,#1) | general |
an auction house charges a commission of 17 % on the first $ 50,000 of the sale price of an item , plus 10 % on the amount of of the sale price in excess of $ 50,000 . what was the price of a painting for which the house charged a total commission of $ 24,000 ? | 05 grass seed contains 5 % herbicide and its amount is 3 pound 20 grass seed contains 20 % herbicide and its amount is x when these two types of grass seeds are mixed , their average becomes 15 % thus we have 3 ( 1 ) + x ( 20 ) / ( x + 3 ) = 15 3 + 20 x = 15 x + 45 5 x = 42 or x = 8.4 d | a ) 3 , b ) 3.75 , c ) 4.5 , d ) 8.4 , e ) 9 | d | divide(subtract(multiply(15, 3), 3), subtract(20, 15)) | multiply(n0,n10)|subtract(n3,n10)|subtract(#0,n0)|divide(#2,#1) | general |
the pinedale bus line travels at an average speed of 60 km / h , and has stops every 5 minutes along its route . yahya wants to go from his house to the pinedale mall , which is 9 stops away . how far away , in kilometers , is pinedale mall away from yahya ' s house ? | "put n = 0 then f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 β β f ( 1 ) + 1 = 3 β β f ( 1 ) = 2 put n = 1 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 β β f ( 2 ) + 2 = 5 β β f ( 2 ) = 3 put n = 2 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 β β f ( 3 ) + 3 = 7 β β f ( 3 ) = 4 . . . . . . f ( 2012 ) = 2013 answer : c" | a ) 222 , b ) 2787 , c ) 2013 , d ) 2778 , e ) 10222 | c | add(1, 2012) | add(n3,n4)| | general |
there are 180 doctors and nurses at a hospital . if the ratio of doctors to nurses is 2 to 3 , how many nurses are at the hospital ? | radius of first cylinder = r , diameter = 2 r , height = h radius of second cylinder = 2 r , diamter = 2 d and height = 2 h volume of first cylinder = pie ( r ^ 2 ) * h = 60 volume of second cylinder = pie ( 2 r ^ 2 ) 2 h put the value of pie ( r ^ 2 ) * h = 60 in the second cylinder , volume = pie ( r ^ 2 ) * 4 * 2 = 60 * 8 = 480 gallons empty capacity = 420 gallons answer d | ['a ) there is no empty capacity', 'b ) 100 gallons', 'c ) 300 gallons', 'd ) 420 gallons', 'e ) 840 gallons'] | d | subtract(multiply(60, power(const_2, const_3)), 60) | power(const_2,const_3)|multiply(n0,#0)|subtract(#1,n0) | geometry |
x varies inversely as square of y . given that y = 3 for x = 1 . the value of x for y = 5 will be equal to : | concentrated apples juice comes inside a cylinder tube since height of a tube is 15 inches , the tubes can fit only in one way now , diameter of each tube = 5 inches therefore , 4 * 2 can be put in each wooden box in 3 boxes 3 * 4 * 2 can be accommodated = 24 = a | a ) 24 . , b ) 28 . , c ) 36 . , d ) 42 . , e ) 48 . | a | subtract(divide(multiply(multiply(multiply(11, 10), 31), 3), multiply(multiply(divide(multiply(add(const_10, const_1), const_2), add(const_3, const_4)), power(2.5, const_2)), 15)), 10) | add(const_1,const_10)|add(const_3,const_4)|multiply(n2,n3)|power(n0,const_2)|multiply(n4,#2)|multiply(#0,const_2)|divide(#5,#1)|multiply(n5,#4)|multiply(#6,#3)|multiply(n1,#8)|divide(#7,#9)|subtract(#10,n3) | gain |
a worker is paid a regular rate of rs . 20 for completing a survey . the worker completes 100 surveys per week . for any survey involving the use of her cellphone , she is paid at a rate of that is 10 % higher than her regular rate . if she completed 70 surveys involving the use of her cellphone , how much did she get that week ? | "explanation : money collected = ( 51.84 x 100 ) paise = 5184 paise . β΄ number of members = β ( 5184 ) = 72 . answer : c" | a ) 57 , b ) 67 , c ) 72 , d ) 87 , e ) 97 | c | sqrt(multiply(51.84, const_100)) | multiply(n0,const_100)|sqrt(#0)| | general |
the area of a triangle will be when a = 3 m , b = 5 m , c = 10 m , a , b , c being lengths of respective sides ? | "given that the total purchase of two items cost 1550 . so the average purchase of one item will cost 1550 / 2 = 775 . its given as total shirt cost 250 $ less . hence total shirt cost = 775 - 125 and total trouser cost = 775 + 125 5 shirts = 650 $ = = > one shirt = 130 $ one trouser = 130 + 20 = 150 $ total trousers = 900 / 150 = 6 . c" | a ) 4 , b ) 5 , c ) 6 , d ) 7 , e ) 8 | c | divide(subtract(1550, multiply(5, add(20, 20))), add(add(20, 20), 20)) | add(n3,n3)|add(n3,#0)|multiply(n2,#0)|subtract(n0,#2)|divide(#3,#1)| | general |
a group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 4 students left over . what is the sum of the two smallest possible values of n ? | "volume = 125 = side ^ 3 i . e . side of cube = 5 new cube has dimensions 10 , 10 , and 10 as all sides are twice of teh side of first cube volume = 10 * 10 * 10 = 1000 square feet answer : option e" | a ) 24 , b ) 48 , c ) 64 , d ) 80 , e ) 1000 | e | volume_cube(multiply(const_2, cube_edge_by_volume(125))) | cube_edge_by_volume(n0)|multiply(#0,const_2)|volume_cube(#1)| | geometry |
a shopkeeper sold an book offering a discount of 5 % and earned a profit of 25 % . what would have been the percentage of profit earned if no discount was offered ? | "speed = 110 kmph = 110 * 5 / 18 = 31 m / s distance covered in 9 sec = 31 * 9 = 279 m answer is b" | a ) 100 m , b ) 279 m , c ) 180 m , d ) 200 m , e ) 250 m | b | multiply(divide(110, const_3_6), 9) | divide(n0,const_3_6)|multiply(n1,#0)| | physics |
a 125 meter long train crosses a man standing on the platform in 5 sec . what is the speed of the train ? | "total number of invalid votes = 15 % of 560000 = 15 / 100 Γ 560000 = 8400000 / 100 = 84000 total number of valid votes 560000 β 84000 = 476000 percentage of votes polled in favour of candidate a = 65 % therefore , the number of valid votes polled in favour of candidate a = 65 % of 476000 = 65 / 100 Γ 476000 = 30940000 / 100 = 309400 d )" | a ) 355600 , b ) 355800 , c ) 356500 , d ) 309400 , e ) 357000 | d | multiply(multiply(560000, subtract(const_1, divide(15, const_100))), divide(65, const_100)) | divide(n0,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(n2,#2)|multiply(#0,#3)| | gain |
the sum of two numbers is 528 and their h . c . f is 33 . the number of pairs of numbers satisfying the above condition is | "total number of ways in which h or t can appear in 3 tosses of coin is = 2 * 2 = 4 ways for 2 h hh , thus probability is = p ( hh ) = 1 / 4 = . 25 answer : c" | a ) 0.125 , b ) 0.225 , c ) 0.25 , d ) 0.5 , e ) 0.666 | c | multiply(power(divide(const_1, const_2), 2), 2) | divide(const_1,const_2)|power(#0,n0)|multiply(n0,#1)| | general |
what profit percent is made by selling an article at a certain price , if by selling at 2 / 3 rd of that price , there would be a loss of 25 % ? | the choices give away the answer . . 36 machines take 4 hours to fill 8 standard orders . . in next eq we aredoubling the machines from 36 to 72 , but thework is not doubling ( only 1 1 / 2 times ) , = 4 * 48 / 72 * 12 / 6 = 4 ans a | a ) 4 , b ) 6 , c ) 8 , d ) 9 , e ) 12 | a | divide(divide(multiply(multiply(36, 12), const_4), 72), 6) | multiply(n0,n4)|multiply(#0,const_4)|divide(#1,n3)|divide(#2,n2) | physics |
the ratio of the cost price and the selling price is 4 : 5 . the profit percent is ? | "speed = 90 kmph = 90 * 5 / 18 = 25 m / s distance covered in 10 sec = 25 * 10 = 250 m answer is e" | a ) 100 m , b ) 150 m , c ) 180 m , d ) 200 m , e ) 250 m | e | multiply(divide(90, const_3_6), 10) | divide(n0,const_3_6)|multiply(n1,#0)| | physics |
out of 40 applicants to a law school , 15 majored in political science , 20 had a grade point average higher than 3.0 , and 10 did not major in political science and had a gpa equal to or lower than 3.0 . how many t applicants majored in political science and had a gpa higher than 3.0 ? | 4 * 2 * 1 = 8 at one ' s place only 5 will come and at ten ' s place 4 and 7 can be placed , and at 100 th place rest of the 4 digits can come . . . so the answer is 8 answer : a | a ) 8 , b ) 13 , c ) 12 , d ) 20 , e ) 22 | a | add(divide(divide(45, 3), 3), const_3) | divide(n2,n0)|divide(#0,n0)|add(#1,const_3) | general |
a man can row 5 kmph in still water . when the river is running at 2 kmph , it takes him 1 hour to row to a place and black . what is the total distance traveled by the man ? | "minimum three digit number is 100 and maximum three digit number is 999 . the first three digit number that leaves remainder 5 when divided by 7 is 103 . 14 * 7 = 98 + 5 = 103 the second three digit number that leaves remainder 5 when divided by 7 is 110 . 15 * 7 = 105 + 5 = 110 the third three digit number that leaves remainder 5 when divided by 7 is 117 and so on the last three digit number that leaves remainder 5 when divided by 7 is 999 142 * 7 = 994 + 5 = 999 therefore , we identify the sequence 103 , 110,117 . . . . . 999 use the formula of last term last term = first term + ( n - 1 ) * common difference you will get the answer 129 that is definitely e ." | a ) 128 , b ) 142 , c ) 143 , d ) 141 , e ) 129 | e | divide(subtract(subtract(multiply(const_100, const_10), const_1), add(multiply(add(const_10, const_4), 7), 5)), 7) | add(const_10,const_4)|multiply(const_10,const_100)|multiply(n1,#0)|subtract(#1,const_1)|add(n2,#2)|subtract(#3,#4)|divide(#5,n1)| | general |
how many distinct prime numbers are factors of 33150 ? | "solution simple out of 100 10 % are male i . e 10 and 20 % are female i . e 20 , so total homeowner is 30 . now min number homeowner is 10 and max is 30 so question ask us to find maximum and 29 has maximum value among all option . so ans is 29 . ans : a" | a ) 29 , b ) 27 , c ) 25 , d ) 23 , e ) 21 | a | add(multiply(multiply(divide(20, const_100), 10), multiply(divide(20, const_100), 10)), divide(subtract(100, 10), 10)) | divide(n2,const_100)|subtract(n0,n1)|divide(#1,n1)|multiply(n1,#0)|multiply(#3,#3)|add(#2,#4)| | gain |
a and b go around a circular track of length 150 m on a cycle at speeds of 36 kmph and 54 kmph . after how much time will they meet for the first time at the starting point ? | the possible number n can be written as follow : n = multiple of lcm ( 610 ) + 1 st such number n = 30 x + 1 possible values = 1 answer : b | a ) none , b ) one , c ) two , d ) three , e ) four | b | multiply(1, 1) | multiply(n0,n0) | general |
a circle graph shows how the megatech corporation allocates its research and development budget : 17 % microphotonics ; 24 % home electronics ; 15 % food additives ; 29 % genetically modified microorganisms ; 8 % industrial lubricants ; and the remainder for basic astrophysics . if the arc of each sector of the graph is proportional to the percentage of the budget it represents , how many degrees of the circle are used to represent basic astrophysics research ? | "explanation : 10 * 16 + 36 β 26 = 170 = > 170 / 10 = 17 a )" | a ) a ) 17 , b ) b ) 18 , c ) c ) 19 , d ) d ) 22 , e ) e ) 24 | a | add(16, divide(subtract(36, 26), 10)) | subtract(n2,n3)|divide(#0,n0)|add(n1,#1)| | general |
if the simple interest on a certain amount in at 4 % rate 5 years amounted to rs . 2160 less than the principal . what was the principal ? | "let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 30 : 48 : : 12 : x working hours / day 6 : 5 30 x 6 x x = 48 x 5 x 12 x = ( 48 x 5 x 12 ) / ( 30 x 6 ) x = 16 answer b" | a ) 10 , b ) 16 , c ) 13 , d ) 18 , e ) 19 | b | divide(multiply(multiply(48, 12), 5), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | physics |
in one hour , a boat goes 11 km along the stream and 5 km against the stream . the speed of the boat in still water ( in km / hr ) is : | "r ^ 2 = ( - 3 - 1 ) ^ 2 + ( 4 - 1 ) ^ 2 = 16 + 9 = 25 area of circle = Ο r ^ 2 = 25 Ο answer : c" | a ) 9 Ο , b ) 18 Ο , c ) 25 Ο , d ) 37 Ο , e ) 41 Ο | c | circle_area(sqrt(add(power(subtract(3, 1), const_2), power(add(1, 4), const_2)))) | add(n1,n2)|subtract(n0,n2)|power(#1,const_2)|power(#0,const_2)|add(#2,#3)|sqrt(#4)|circle_area(#5)| | geometry |
the sector of a circle has radius of 21 cm and central angle 108 o . find its perimeter ? | "1 / x - 1 / 20 = - 1 / 24 x = 120 120 * 7 = 840 answer : d" | a ) 480 , b ) 487 , c ) 481 , d ) 840 , e ) 268 | d | multiply(24, 20) | multiply(n0,n2)| | physics |
on the independence day , bananas were be equally distributed among the children in a school so that each child would get two bananas . on the particular day 380 children were absent and as a result each child got two extra bananas . find the actual number of children in the school ? | "ratio = 7 k / 9 k = 7 / 9 , 14 / 18 , etc . x is multiplied by x and y is multiplied by y - - > ( 7 k * 7 k ) / ( 9 k * 9 k ) = 49 k ^ 2 / 81 k ^ 2 = 49 / 81 = 7 / 9 answer : a" | a ) 8 / 3 , b ) 3 / 8 , c ) 1 , d ) 64 / 9 , e ) it can not be determined | a | divide(multiply(8, 3), multiply(3, 8)) | multiply(n0,n1)|divide(#0,#0)| | general |
a train 300 m long , running with a speed of 54 km / hr will pass a tree in ? | "a : b = 2 : 3 b : c = 2 : 5 a : b : c = 4 : 6 : 15 4 / 25 * 100 = 16 answer : d" | a ) 11 , b ) 18 , c ) 13 , d ) 16 , e ) 12 | d | multiply(divide(100, add(add(divide(2, 3), divide(5, 2)), 2)), 5) | divide(n0,n1)|divide(n3,n0)|add(#0,#1)|add(#2,n0)|divide(n4,#3)|multiply(n3,#4)| | general |
simplify : 250 x 250 - 100 x 100 | "this is an arithmetic progression , and we can write down a = 1 a = 1 , d = 2 d = 2 , n = 50 n = 50 . we now use the formula , so that sn = 12 n ( 2 a + ( n β 1 ) l ) sn = 12 n ( 2 a + ( n β 1 ) l ) s 50 = 12 Γ 50 Γ ( 2 Γ 1 + ( 50 β 1 ) Γ 2 ) s 50 = 12 Γ 50 Γ ( 2 Γ 1 + ( 50 β 1 ) Γ 2 ) = 25 Γ ( 2 + 49 Γ 2 ) = 25 Γ ( 2 + 49 Γ 2 ) = 25 Γ ( 2 + 98 ) = 25 Γ ( 2 + 98 ) = 2500 = 2500 . e" | a ) 1230 , b ) 1300 , c ) 1500 , d ) 1679 , e ) 2500 | e | subtract(negate(50), multiply(subtract(3,5, 7,9), divide(subtract(3,5, 7,9), subtract(1, 3,5)))) | negate(n3)|subtract(n1,n2)|subtract(n0,n1)|divide(#1,#2)|multiply(#3,#1)|subtract(#0,#4)| | general |
subtracting 30 from a number , the remainder is one fourth of the number . find the number ? | "a palindrome is a number that reads the same forward and backward . examples of four digit palindromes are 1221 , 4334 , 2222 etc you basically get to choose the first two digits and you repeat them in opposite order . say , you choose 45 as your first two digits . the next two digits are 54 and the number is 4554 . also , you need only odd palindromes . this means that you need an odd digit at the end i . e . 1 / 3 / 5 / 7 / 9 . this means that you need to start the number with an odd digit . only then will it end with an odd digit . in how many ways can you pick two digits such that the first one is an odd digit ? the first digit can be selected in 5 ways . ( 1 / 3 / 5 / 7 / 9 ) the second digit can be selected in 10 ways . ( 0 / 1 / 2 / 3 . . . 8 / 9 ) total = 5 * 11 = 55 ways b" | a ) 40 , b ) 55 , c ) 50 , d ) 90 , e ) 2500 | b | divide(power(const_10, divide(4, const_2)), const_2) | divide(n1,const_2)|power(const_10,#0)|divide(#1,const_2)| | general |
n = 1 ! + 2 ! + 3 ! . . . . . + 10 ! . what is the last digit of n ^ n ? | "ab = ( a - 1 ) ( b - 1 ) x 20 = ( x - 1 ) ( 20 - 1 ) = 190 - - > x - 1 = 10 - - > x = 11 answer : c" | a ) 10 , b ) 12 , c ) 11 , d ) 13 , e ) 14 | c | add(divide(190, subtract(20, 1)), 1) | subtract(n2,n0)|divide(n3,#0)|add(n0,#1)| | general |
the sector of a circle has radius of 14 cm and central angle 108 o . find its perimeter ? | a . 4 is used once : oo * * 4 - - > ( 5 * 5 * 9 * 9 ) * 3 : 5 choices for the first digit as there are 5 odd numbers , 5 choices for the second digit for the same reason , 9 choices for one of the two * ( not - 4 digit ) , 9 choices for another * ( not - 4 digit ) , multiplied by 3 as 4 can take the place of any of the three last digits ( oo * * 4 , oo * 4 * , oo 4 * * ) ; b . 4 is not used : oo * * * - - > 5 * 5 * 9 * 9 * 9 : the same logic as above . 5 * 5 * 9 * 9 * 3 + 5 * 5 * 9 * 9 * 9 = 24300 . answer : a | a ) 24300 , b ) 25700 , c ) 26500 , d ) 24400 , e ) 26300 | a | multiply(multiply(multiply(multiply(subtract(multiply(4, 5), 1), 5), 5), 5), const_10) | multiply(n0,n2)|subtract(#0,n3)|multiply(n0,#1)|multiply(n0,#2)|multiply(n0,#3)|multiply(#4,const_10) | general |
in a garden , there are 10 rows and 14 columns of mango trees . the distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden . the length of the garden is | "3 ^ 8 * ( 2 ) = 13122 the answer is c" | a ) 512 , b ) 768 , c ) 13122 , d ) 2048 , e ) 4096 | c | subtract(power(3, add(8, const_1)), const_1) | add(n0,const_1)|power(n1,#0)|subtract(#1,const_1)| | physics |
the average of first five prime numbers greater than 5 is ? | "given ; 2 dog = 3 cat ; or , dog / cat = 3 / 2 ; let cat ' s 1 leap = 2 meter and dogs 1 leap = 3 meter . then , ratio of speed of cat and dog = 2 * 6 / 3 * 5 = 4 : 5 ' ' answer : 4 : 5 ;" | a ) 4 : 5 , b ) 2 : 3 , c ) 4 : 1 , d ) 1 : 9 , e ) 3 : 2 | a | divide(multiply(divide(2, 3), 6), 5) | divide(n2,n3)|multiply(n0,#0)|divide(#1,n1)| | other |
an artist wishes to paint a circular region on a square poster that is 2.4 feet on a side . if the area of the circular region is to be 1 / 2 the area of the poster , what must be the radius of the circular region in feet ? | "area of the shaded portion = 1 β 4 Γ Ο Γ ( 18 ) 2 = 254 m 2 answer c" | a ) 154 cm 2 , b ) 308 m 2 , c ) 254 m 2 , d ) 260 m 2 , e ) none of these | c | divide(multiply(power(18, const_2), const_pi), const_4) | power(n2,const_2)|multiply(#0,const_pi)|divide(#1,const_4)| | geometry |
a sum of money at simple interest amounts to rs . 835 in 3 years and to rs . 854 in 4 years . the sum is : | a . m . of 75 numbers = 35 sum of 75 numbers = 75 * 35 = 2625 total increase = 75 * 5 = 375 increased sum = 2625 + 375 = 3000 increased average = 3000 / 75 = 40 . answer : b | a ) 87 , b ) 40 , c ) 37 , d ) 28 , e ) 26 | b | add(35, 5) | add(n0,n1) | general |
the average ( arithmetic mean ) of 20 , 40 , and 60 is 5 more than the average of 10 , 70 , and what number ? | answer x = 13200 - 8873 = 4327 option : b | a ) 3327 , b ) 4327 , c ) 3337 , d ) 2337 , e ) none of these | b | subtract(13200, 8873) | subtract(n1,n0) | general |
a certain university will select 1 of 5 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department . if none of the candidates is eligible for a position in both departments , how many different sets of 3 candidates are there to fill the 3 positions ? | "the problem with your solution is that we do n ' t choose 1 shoe from 16 , but rather choose the needed one after we just took one and need the second to be the pair of it . so , the probability would simply be : 1 / 1 * 1 / 15 ( as after taking one at random there are 15 shoes left and only one is the pair of the first one ) = 1 / 15 answer : e ." | a ) 1 / 190 , b ) 1 / 20 , c ) 1 / 19 , d ) 1 / 10 , e ) 1 / 15 | e | divide(const_1, subtract(16, const_1)) | subtract(n1,const_1)|divide(const_1,#0)| | general |
34 . the side surface of a cylinder is rolled with a rectangular plate . if the perimeter of the circular base is 9 feet , and the diagonal of the rectangular plate was 15 ft . what is height of the of the cylinder ? | "cost + profit = sales cost + ( 140 / 100 ) cost = 60 cost = 25 profit = 60 - 25 = 35 answer ( d )" | a ) 32 , b ) 33 , c ) 39 , d ) 35 , e ) 42 | d | subtract(60, divide(60, add(const_1, divide(140, const_100)))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | gain |
if x / 5 + 9 / x = 14 / 5 , what are the values of 3 x - 7 ? | the table you made does n ' t make sense to me . all three meet at the same point means the distance they cover is the same . we know their rates are 30 , 40 and 60 . say the time taken by b is t hrs . then a takes 6 + t hrs . and we need to find the time taken by k . distance covered by a = distance covered by b 30 * ( 6 + t ) = 40 * t t = 18 hrs distance covered by b = distance covered by k 40 * t = 60 * time taken by k time taken by k = 40 * 18 / 60 = 12 hrs time taken by a = 6 + t = 6 + 18 = 24 hrs time taken by k = 12 hrs so k starts 24 - 12 = 12 hrs after a . ( answer d ) | a ) 3 , b ) 4.5 , c ) 4 , d ) d ) 12 , e ) e ) 5 | d | divide(multiply(30, add(6, divide(multiply(30, 6), subtract(40, 30)))), 60) | multiply(n0,n3)|subtract(n1,n0)|divide(#0,#1)|add(n3,#2)|multiply(n0,#3)|divide(#4,n2) | physics |
a and b began business with rs . 3000 and rs . 4000 after 8 months , a withdraws rs . 1000 and b advances rs . 1000 more . at the end of the year , their profits amounted to rs . 672 find the share of a . | let the number of boys = x , number of girls = y 40 y / 100 = 120 y = 300 120 = 2 / 3 * 20 x / 100 = 2 x / 15 x = 900 total = x + y = 300 + 900 = 1200 answer : a | a ) 1200 , b ) 380 , c ) 3800 , d ) 2180 , e ) 3180 | a | add(divide(120, multiply(divide(subtract(const_100, 80), const_100), divide(2, 3))), divide(120, divide(40, const_100))) | divide(n3,n4)|divide(n1,const_100)|subtract(const_100,n0)|divide(#2,const_100)|divide(n2,#1)|multiply(#3,#0)|divide(n2,#5)|add(#6,#4) | general |
what is the smallest integer e greater than 1 that leaves a remainder of 1 when divided by any of the integers 6 , 8 , and 10 ? | "explanation : let the number be 4 + 1 / 2 [ 1 / 3 ( a / 5 ) ] = a / 15 = > 4 = a / 30 = > a = 120 answer : d" | a ) 32 , b ) 81 , c ) 60 , d ) 120 , e ) 11 | d | divide(4, divide(divide(const_1, multiply(4, add(const_2, 4))), const_2)) | add(const_2,n0)|multiply(#0,n0)|divide(const_1,#1)|divide(#2,const_2)|divide(n0,#3)| | general |
what is the largest number of 4 digits which is divisible by 15 , 25 , 40 and 75 ? | "let total number of mice = m number of white mice = 2 / 3 m number of brown mice = 1 / 3 m = 15 = > m = 45 answer a" | a ) 45 , b ) 33 , c ) 26 , d ) 21 , e ) 10 | a | subtract(divide(15, divide(2, 3)), 15) | divide(n0,n1)|divide(n2,#0)|subtract(#1,n2)| | general |
a car traveling at a certain constant speed takes 30 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 30 kilometers per hour . at what speed , in kilometers per hour , is the car traveling ? | "original sp = x cost = c current selling price = . 8 x ( 20 % discount ) . 8 x = 1.3 c ( 30 % profit ) x = 1.3 / . 8 * c x = 13 / 8 c original selling price is 1.625 c which is 62.5 % profit answer d" | a ) 20 % , b ) 40 % , c ) 50 % , d ) 62.5 % , e ) 75 % | d | subtract(const_100, subtract(subtract(const_100, 20), 30)) | subtract(const_100,n0)|subtract(#0,n1)|subtract(const_100,#1)| | gain |
a rectangular swimming pool is 20 feet by 20 feet . a deck that has uniform width surrounds the pool . the total area of the pool and deck is 576 square feet . what is the width of the deck ? | "a ' s rate is 1 / 42 and b ' s rate is 1 / 7 . the combined rate is 1 / 42 + 1 / 7 = 1 / 6 the pipes will fill the tank in 6 minutes . the answer is d ." | a ) 3 , b ) 4 , c ) 5 , d ) 6 , e ) 7 | d | inverse(add(divide(const_1, 42), divide(6, 42))) | divide(const_1,n0)|divide(n1,n0)|add(#0,#1)|inverse(#2)| | physics |
a man engaged a servant on the condition that he would pay him rs . 1000 and a uniform after one year service . he served only for 9 months and received uniform and rs . 550 , find the price of the uniform ? | "the number of grams of liquid x is 1.5 ( 200 ) / 100 + 6.5 ( 800 ) / 100 = 3 + 52 = 55 grams . 55 / 1000 = 5.5 % the answer is c ." | a ) 4.5 % , b ) 5.0 % , c ) 5.5 % , d ) 5.8 % , e ) 6.0 % | c | multiply(divide(add(const_1, divide(multiply(6.5, 800), const_100)), const_1000), const_100) | multiply(n1,n3)|divide(#0,const_100)|add(#1,const_1)|divide(#2,const_1000)|multiply(#3,const_100)| | gain |
in an examination , there were 2,000 candidates , out of which 900 candidates were girls and rest were boys . if 36 % of the boys and 32 % of the girls passed , then the total percentage of failed candidates is ? | "900 * 15 = 1100 * x x = 12.27 . answer : e" | a ) 12.88 , b ) 12.6 , c ) 12.55 , d ) 12.21 , e ) 12.27 | e | divide(multiply(15, 900), add(900, 200)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0)| | physics |
what least number must be added to 1145 , so that the sum is completely divisible by 23 ? | points to remember - 1 . if oneadd / subtractthe same amont from every term in a set , sd does n ' t change . 2 . if onemultiply / divideevery term by the same number in a set , sd changes by same number . hence the answer to the above question is b | a ) a ) 1 , b ) b ) 2 , c ) c ) 4 , d ) d ) 8 , e ) e ) 16 | b | multiply(2, 1) | multiply(n4,n5) | general |
a rectangular block 10 cm by 20 cm by 30 cm is cut into an exact number of equal cubes . find the least possible number of cubes ? | total transaction in two days = 4 - 2 = 2 feet in 20 days it will climb 20 feet on the 21 st day , the snail will climb 4 feet , thus reaching the top therefore , total no of days required = 21 e | a ) 12 , b ) 16 , c ) 17 , d ) 20 , e ) 21 | e | subtract(24, 4) | subtract(n0,n1) | physics |
a number increased by 20 % gives 600 . the number is | "we have the ratio of a β s speed and b β s speed . this means , we know how much distance a covers compared with b in the same time . this is what the beginning of the race will look like : ( start ) a _________ b ______________________________ if a covers 25 meters , b covers 18 meters in that time . so if the race is 25 meters long , when a reaches the finish line , b would be 7 meters behind him . if we want the race to end in a dead heat , we want b to be at the finish line too at the same time . this means b should get a head start of 7 meters so that he doesn β t need to cover that . in that case , the time required by a ( to cover 25 meters ) would be the same as the time required by b ( to cover 18 meters ) to reach the finish line . so b should get a head start of 7 / 25 th of the race . answer ( c )" | a ) 1 / 18 , b ) 7 / 18 , c ) 7 / 25 , d ) 3 / 25 , e ) 1 / 25 | c | divide(subtract(25, 18), 25) | subtract(n0,n1)|divide(#0,n0)| | general |
country c imposes a two - tiered tax on imported cars : the first tier imposes a tax of 12 % of the car ' s price up to a certain price level . if the car ' s price is higher than the first tier ' s level , the tax on the portion of the price that exceeds this value is 8 % . if ron imported a $ 12,000 imported car and ended up paying $ 1440 in taxes , what is the first tier ' s price level ? | let the incorrect cost price be c 1 and let the original cost price be c 2 . marked price of book is rs . 30 . it is 20 % more than c 1 . therefore , ( 120 / 100 ) x c 1 = 30 or c 1 = 25 . c 1 is more than c 2 margin of 25 % . or c 1 = ( 125 / 100 ) c 2 therefore , c 2 = ( 100 / 125 ) x 25 = rs 20 answer : d | a ) rs . 30 , b ) rs . 25 , c ) rs . 45 , d ) rs . 20 , e ) rs . 10 | d | divide(divide(30, add(const_1, divide(20, const_100))), add(const_1, divide(25, const_100))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|divide(n2,#2)|divide(#4,#3) | gain |
a person has 100 $ in 10 $ and 5 $ bill . if the 5 $ bill quantity is twice that of 10 $ bill . what is quantity of 10 $ . | "the numbers are ( 18 x 11 ) and ( 18 x 15 ) . larger number = ( 18 x 15 ) = 270 . answer : a" | a ) 270 , b ) 300 , c ) 299 , d ) 322 , e ) 345 | a | multiply(18, 15) | multiply(n0,n2)| | other |
two trains are moving in the same direction at 72 kmph and 36 kmph . the faster train crosses a man in the slower train in 27 seconds . find the length of the faster train ? | "b / c = 1 / 3 c - b = 20 . . . . . . . . . > b = c - 20 ( c - 20 ) / c = 1 / 3 testing answers . clearly eliminate abce put c = 30 . . . . . . . . . > ( 30 - 20 ) / 30 = 10 / 30 = 1 / 3 answer : d" | a ) 100 , b ) 120 , c ) 140 , d ) 30 , e ) 150 | d | multiply(divide(20, subtract(3, 1)), 3) | subtract(n1,n0)|divide(n2,#0)|multiply(n1,#1)| | other |
o ( x ) represents the least odd integer greater than x , whereas o ( x ) represents the greatest odd integer less than x . likewise , e ( x ) represents the least even integer greater than x , whereas e ( x ) represents the greatest even integer less than x . according to these definitions , the value of o ( 11.6 ) + e ( β 10.4 ) + o ( β 9.2 ) + e ( 9.5 ) is : | "speed upstream = 7.5 kmph speed downstream = 12.5 kmph total time taken = 105 / 7.5 + 105 / 12.5 = 22.4 hours answer is b" | a ) 23.4 hours , b ) 22.4 hours , c ) 21.4 hours , d ) 20.4 hours , e ) 19.4 hours | b | add(multiply(add(add(10, 2.5), subtract(10, 2.5)), 105), multiply(subtract(add(divide(105, add(10, 2.5)), divide(105, subtract(10, 2.5))), add(add(10, 2.5), subtract(10, 2.5))), const_60)) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|divide(n2,#0)|divide(n2,#1)|add(#3,#4)|multiply(n2,#2)|subtract(#5,#2)|multiply(#7,const_60)|add(#6,#8)| | physics |
11 different biology books and 8 different chemistry books lie on a shelf . in how many ways can a student pick 2 books of each type ? | "explanation : let the number of 20 paise coins be x . then the no of 25 paise coins = ( 324 - x ) . 0.20 * ( x ) + 0.25 ( 324 - x ) = 71 = > x = 200 . . answer : d ) 200" | a ) 238 , b ) 277 , c ) 278 , d ) 200 , e ) 288 | d | divide(subtract(multiply(324, 25), multiply(71, const_100)), subtract(25, 20)) | multiply(n0,n2)|multiply(n3,const_100)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)| | general |
the price of an item is discounted 6 percent on day 1 of a sale . on day 2 , the item is discounted another 6 percent , and on day 3 , it is discounted an additional 10 percent . the price of the item on day 3 is what percentage of the sale price on day 1 ? | population in 2 years = 40000 ( 1 - 5 / 100 ) ^ 2 = 40000 * 19 * 19 / 20 * 20 = 36100 answer is c | a ) 24560 , b ) 26450 , c ) 36100 , d ) 38920 , e ) 45200 | c | multiply(power(divide(subtract(const_100, 5), const_100), 2), 40000) | subtract(const_100,n0)|divide(#0,const_100)|power(#1,n2)|multiply(n1,#2) | gain |
5359 x 51 = ? | take the initial price before the gratuity is 100 the gratuity is calculated on the final price , so as we assumed the final bill before adding gratuity is 100 so gratuity is 15 % of 100 is 15 so the total price of meals is 115 so the given amount i . e 206 is for 115 then we have to calculate for 100 for 115 206 for 100 x so by cross multiplication we get 115 x = 100 * 206 = > x = 100 * 206 / 110 by simplifying we get x as 187.27 which is the price of lunch before gratuity so the gratuity is 18.73 so as the question ask the average price person excluding gratuity is 187.27 / 15 = 12.48 so our answer is b ) | a ) $ 11.73 , b ) $ 12.48 , c ) $ 13.80 , d ) $ 14.00 , e ) $ 15.87 | b | multiply(multiply(divide(206, add(const_100, 15)), const_100), divide(const_1, 15)) | add(n0,const_100)|divide(const_1,n0)|divide(n1,#0)|multiply(#2,const_100)|multiply(#1,#3) | general |
daniel went to a shop and bought things worth rs . 50 , out of which 90 paise went on sales tax on taxable purchases . if the tax rate was 15 % , then what was the cost of the tax free items ? | "son ' s 1 day work = 1 / 3 - 1 / 5 = 2 / 15 son alone can do the work in 15 / 2 days = 7 1 / 2 days answer is c" | a ) 5 , b ) 5 1 / 2 , c ) 7 1 / 2 , d ) 6 , e ) 9 1 / 2 | c | divide(multiply(5, 3), subtract(5, 3)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | physics |
the cross - section of a cannel is a trapezium in shape . if the cannel is 14 m wide at the top and 8 m wide at the bottom and the area of cross - section is 550 sq m , the depth of cannel is ? | "t 1 = 600 / 60 = 10 hours t 2 = 120 / 40 = 3 hours t = t 1 + t 2 = 13 hours avg speed = total distance / t = 720 / 13 = 55 mph = b" | a ) 42 , b ) 55 , c ) 50 , d ) 54 , e ) 56 | b | divide(add(600, 120), add(divide(600, 60), divide(120, 40))) | add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3)| | physics |
8 , 12 , 18 , 27 , 40.5 , ( . . . ) | "for retail price = $ 20 first maximum discounted price = 20 - 30 % of 20 = 20 - 6 = 14 price after additional discount of 20 % = 14 - 20 % of 14 = 14 - 2.8 = 11.2 answer : option b" | a ) $ 10.00 , b ) $ 11.20 , c ) $ 14.40 , d ) $ 16.00 , e ) $ 18.00 | b | multiply(divide(subtract(const_100, 20), const_100), multiply(divide(subtract(const_100, 30), const_100), 20.00)) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(n3,#3)|multiply(#2,#4)| | gain |
at 12 : 30 , the hour hand and the minute hand of a clock form an angle of | "the amount of chemical x in the solution is 20 + 0.15 ( 80 ) = 32 liters . 32 liters / 100 liters = 32 % the answer is b ." | a ) 30 % , b ) 32 % , c ) 35 % , d ) 38 % , e ) 40 % | b | add(20, multiply(divide(15, const_100), 80)) | divide(n2,const_100)|multiply(n1,#0)|add(n0,#1)| | general |
when 200 is divided by positive integer x , the remainder is 3 . what is the remainder when 297 is divided by x ? | "{ total } = { even } + { multiple of 5 } - { both } + { nether } . since { neither } = 0 ( allare even or multiple of 5 ) then : 12 = 4 + 10 - { both } + 0 ; { both } = 2 ( so 1 number is both even and multiple of 5 , so it must be a multiple of 10 ) . answer : c ." | a ) 0 , b ) 1 , c ) 2 , d ) 3 , e ) 5 | c | subtract(12, 10) | subtract(n0,n3)| | general |
a boatman selling a boat along river flow . if he sell boat in steal water at 3 m / sec and flow of river is 2 m / sec . how much time he will take to sell 100 m . | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 506 but x = 120 % of y = 120 y / 100 = 12 y / 10 β΄ 12 y / 10 + y = 506 β y [ 12 / 10 + 1 ] = 506 β 22 y / 10 = 506 β 22 y = 5060 β y = 5060 / 22 = 460 / 2 = rs . 230 e" | a ) s . 250 , b ) s . 280 , c ) s . 290 , d ) s . 299 , e ) s . 230 | e | divide(multiply(506, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | general |
liz drove from point a to point b at 40 km / h . on her way back she drove at 50 km / h and therefore her way back lasted one hour less . what is the distance ( in km ) between a and b ? | "when dealing with ' symbolism ' questions , it often helps to ' play with ' the symbol for a few moments before you attempt to answer the question that ' s asked . by understanding how the symbol ' works ' , you should be able to do the latter calculations faster . here , we ' re told that k * is the product of all the fractions of the form 1 / t , where t is an integer between 1 and k , inclusive . based on this definition . . . . if . . . . k = 2 k * = ( 1 / 1 ) ( 1 / 2 ) = 1 / 2 if . . . . k = 3 k * = ( 1 / 1 ) ( 1 / 2 ) ( 1 / 3 ) = 1 / 6 we ' re asked to find the value of 5 * / 4 * now that we know how the symbol ' works ' , solving this problem should n ' t be too difficult . you can actually choose to do the math in a couple of different ways . . . . 5 * = ( 1 / 1 ) ( 1 / 2 ) ( 1 / 3 ) ( 1 / 4 ) ( 1 / 5 ) do n ' t calculate this just yet though . . . . since we ' re dividing by 4 * , many of those fractions will ' cancel out . ' 4 * = ( 1 / 1 ) ( 1 / 2 ) ( 1 / 3 ) ( 1 / 4 ) we ' re looking for the value of : ( 1 / 1 ) ( 1 / 2 ) ( 1 / 3 ) ( 1 / 4 ) ( 1 / 5 ) / ( 1 / 1 ) ( 1 / 2 ) ( 1 / 3 ) ( 1 / 4 ) since the first four fraction in the numerator and denominator cancel out , we ' re left with just one fraction : 5 / 4 b" | a ) 5 , b ) 5 / 4 , c ) 4 / 5 , d ) 1 / 4 , e ) 1 / 5 | b | divide(divide(divide(1, const_3), const_3), add(1, const_4)) | add(n0,const_4)|divide(n2,const_3)|divide(#1,const_3)|divide(#2,#0)| | general |
a container contains 1000 liters of milk , from this container 10 liters of milk was taken out and replaced by water . this process was repeated further 2 times . how much milk is now contained by the container ? | "let x % of 25 = 2.125 . then , ( x / 100 ) * 25 = 2.125 x = ( 2.125 * 4 ) = 8.5 . answer is e ." | a ) 4.5 , b ) 6.5 , c ) 2.5 , d ) 7.5 , e ) 8.5 | e | divide(20125, divide(25, const_100)) | divide(n0,const_100)|divide(n1,#0)| | gain |
a number when divided by 4 , gives 40 as quotient and 0 as remainder . what will be the remainder when dividing the same number by 3 | "solution age of the 15 th student = [ 15 x 15 - ( 14 x 4 + 16 x 10 ) ] = ( 225 - 216 ) = 9 years . answer e" | a ) 9 years , b ) 11 years , c ) 14 years , d ) 21 years , e ) 9 years | e | subtract(multiply(15, 15), add(multiply(4, 14), multiply(10, 16))) | multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)| | general |
bag contains 7 green and 8 white balls . if two balls are drawn simultaneously , the probability that both are of the same colour is - . | "a : b : c = 100 : 65 : 40 = 20 : 13 : 8 8 - - - - 40 41 - - - - ? = > rs . 205 answer : d" | a ) 288 , b ) 262 , c ) 72 , d ) 205 , e ) 267 | d | multiply(divide(40, 40), add(add(const_100, 65), 40)) | add(n0,const_100)|divide(n2,n1)|add(n1,#0)|multiply(#2,#1)| | general |
4 liters of a 25 percent solution of alcohol in water are mixed with 3 liters of a 11 percent alcohol in water solution . what is the percentage of alcohol in the new solution ? | each train is averaging 40 km / hour in an opposite direction . after 1 hour , they will be 80 km apart , and after 1.25 hours , they will be 100 km apart . ( 80 * 1.25 = 100 ) answer is d | a ) 2 hours , b ) 2.25 hours , c ) 1 hour , d ) 1.25 hours , e ) not enough information | d | divide(divide(100, const_2), 40) | divide(n2,const_2)|divide(#0,n0) | general |
set a contains all the even numbers between 12 and 50 inclusive . set b contains all the even numbers between 112 and 150 inclusive . what is the difference between the sum of elements of set b and the sum of the elements of set a ? | "suppose enrollment in 1991 was 100 then enrollment in 1992 will be 130 and enrollment in 1993 will be 130 * 1.1 = 143 increase in 1993 from 1991 = 143 - 100 = 43 answer : a" | a ) 43 % , b ) 45 % , c ) 50 % , d ) 35 % , e ) 38 % | a | subtract(multiply(add(const_100, 30), divide(add(const_100, 10), const_100)), const_100) | add(n1,const_100)|add(n4,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100)| | gain |
what is the unit digit in the product ( 3 ^ 65 x 6 ^ 59 x 7 ^ 71 ) ? | "required length = hcf of 1050 cm , 1455 cm , 50 cm = 5 cm answer is e" | a ) 20 cm , b ) 24 cm , c ) 30 cm , d ) 10 cm , e ) 5 cm | e | multiply(55, const_4) | multiply(n3,const_4)| | physics |
the edges of a cuboid are 4 cm , 5 cm and 7 cm . find the volume of the cuboid ? | "generally * p or p ! will be divisible by all numbers from 1 to p . therefore , * 9 would be divisible by all numbers from 1 to 9 . = > * 9 + 3 would give me a number which is a multiple of 3 and therefore divisible ( since * 9 is divisible by 3 ) in fact adding anyprimenumber between 1 to 9 to * 9 will definitely be divisible . so the answer is none ( a ) ! supposing if the question had asked for prime numbers between * 9 + 3 and * 9 + 11 then the answer would be 1 . for * 9 + 3 and * 9 + 13 , it is 2 and so on . . . a" | a ) none , b ) one , c ) two , d ) three , e ) four | a | subtract(subtract(add(multiply(multiply(multiply(9, 3), const_2), const_4), 9), add(multiply(multiply(multiply(9, 3), const_2), const_4), 3)), 1) | multiply(n1,n2)|multiply(#0,const_2)|multiply(#1,const_4)|add(n1,#2)|add(n2,#2)|subtract(#3,#4)|subtract(#5,n0)| | general |
there are 418 doctors and nurses in a hospital . if the ratio of the doctors to the nurses is 8 : 11 , then how many nurses are there in the hospital ? | "explanation : a runs 1000 meters while b runs 880 meters and c runs 800 meters . therefore , b runs 880 meters while c runs 800 meters . so , the number of meters that c runs when b runs 1000 meters = ( 1000 x 800 ) / 880 = 909.09 meters thus , b can give c ( 1000 - 909.09 ) = 90.09 meters start answer : a" | a ) 90.09 meters , b ) 111.12 meters , c ) 112.12 meters , d ) 113.12 meters , e ) none of these | a | subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 200)), subtract(multiply(const_100, const_10), 120))) | multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4)| | physics |
for 2 consecutive yrs , my incomes are in the ratio of 4 : 7 and expenses in the ratio of 3 : 5 . if my income in the 2 nd yr is rs . 42000 & my expenses in the first yr in rs . 21000 , my total savings for the two - year is | "1 mile = 1760 yards 40 miles = 40 * 1760 = 70400 yards answer is e" | a ) 25630 yards , b ) 35200 yards , c ) 39520 yards , d ) 42560 yards , e ) 70400 yards | e | divide(multiply(multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2)), 40), multiply(multiply(add(const_3, const_2), const_2), multiply(add(const_3, const_2), const_2))) | add(const_2,const_3)|multiply(#0,const_2)|multiply(#1,#1)|multiply(n0,#2)|divide(#3,#2)| | physics |
a rectangular with dimensions 35 inches by 45 inches is to be divided into squares of equal size . which of the following could be a length of a side of the squares ? | "let the price be 100 . the price becomes 130 after a 30 % markup . now a discount of 20 % on 130 . profit = 104 - 100 4 % answer e" | a ) 8 % , b ) 10 % , c ) 21 % , d ) 15 % , e ) 4 % | e | subtract(subtract(add(30, const_100), divide(multiply(add(30, const_100), 20), const_100)), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(#3,const_100)| | gain |
the speed of the boat in still water in 12 kmph . it can travel downstream through 45 kms in 3 hrs . in what time would it cover the same distance upstream ? | cp = sp * ( 100 / ( 100 + profit % ) ) = 8300 ( 100 / 142 ) = rs . 5845 . answer : b | a ) rs . 5725 , b ) rs . 5845 , c ) rs . 6275 , d ) rs . 6725 , e ) none of these | b | divide(8300, add(const_1, divide(42, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1) | gain |
there are 9 fictions and 6 non - fictions . how many cases are there such that 2 fictions and 2 non - fictions are selected from them ? | "sp = 1.18 * 320 = 378 answer : d" | a ) 198 , b ) 200 , c ) 204 , d ) 378 , e ) 347 | d | add(320, multiply(320, divide(18, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | gain |
a furniture dealer purchased a desk for $ 180 and then set the selling price equal to the purchase price plus a markup that was 40 % of the selling price . if the dealer sold the desk at the selling price , what was the amount of the dealer ' s gross profit from the purchase and the sale of the desk ? | "if 5 / 7 of tub ' s content is drained 2 / 7 th of tub still needs to be drained . if it takes 5 minutes to drain 5 / 7 th of tub it takes 5 * ( 7 / 5 ) minutes to drain the entire tub and 5 * ( 7 / 5 ) * ( 2 / 7 ) min to drain 2 / 7 th of the tub which is 2 minutes so answer is d" | a ) 48 seconds , b ) 1 minute , 12 seconds , c ) 1 minute , 50 seconds , d ) 2 minutes , 00 seconds , e ) 4 minutes , 12 seconds | d | add(subtract(const_1, divide(5, 7)), divide(5, 7)) | divide(n1,n2)|subtract(const_1,#0)|add(#0,#1)| | general |
what is the average of xx , 2 x 2 x , and 66 ? | "if 20 books constitute 1 / 3 rd of the total , then 2 / 3 rd of the total = 40 books amount received for sold books = 40 * 3.25 = $ 130 answer : a" | a ) $ 130 , b ) $ 185 , c ) $ 175 , d ) $ 165 , e ) $ 155 | a | multiply(2, divide(multiply(20, divide(2, 3)), divide(const_1, 3))) | divide(n0,n1)|divide(const_1,n1)|multiply(n3,#0)|divide(#2,#1)|multiply(n0,#3)| | general |
mahesh can do a piece of work in 30 days . he works at it for 20 days and then rajesh finished it in 30 days . how long will y take to complete the work ? | "here , drawing a quick sketch of the ' actions ' described will end in a diagonal line that you canbuilda right triangle around : the right triangle will have a base of 120 and a height of 160 . the hidden pattern here is a 3 / 4 / 5 right triangle ( the 120 lines up with the ' 3 ' and the 160 lines up with the ' 4 ' ) . in this way , you can deduce that each side is ' 40 times ' bigger than it ' s corresponding side : 3 / 4 / 5 becomes 120 / 160 / 200 thus the distance between the two cars is the length of the hypotenuse of this larger right triangle . . . final answer : b" | a ) 180 , b ) 200 , c ) 220 , d ) 240 , e ) 250 | b | sqrt(add(power(add(multiply(30, 3), multiply(10, 3)), const_2), power(multiply(30, 3), const_2))) | multiply(n2,n3)|multiply(n1,n3)|add(#0,#1)|power(#0,const_2)|power(#2,const_2)|add(#4,#3)|sqrt(#5)| | physics |
an engine moves at the speed of 90 kmph without any coaches attached to it . speed of the train reduces at the rate that varies directly as the square root of the number of coaches attached . when 9 coaches are attached speed decreases to 78 kmph . what will be the speed of train when 25 coaches are attached . | "number of runs made by running = 120 - ( 5 x 4 + 8 x 6 ) = 120 - ( 68 ) = 52 now , we need to calculate 60 is what percent of 120 . = > 52 / 120 * 100 = 43.33 % a" | a ) 43.33 % , b ) 50 % , c ) 65 % , d ) 70 % , e ) 75 % | a | multiply(divide(subtract(120, add(multiply(5, 8), multiply(8, 5))), 120), const_100) | multiply(n1,n2)|multiply(n1,n2)|add(#0,#1)|subtract(n0,#2)|divide(#3,n0)|multiply(#4,const_100)| | general |
a driver just filled the car ' s gas tank with 18 liters of gasohol , a mixture consisting of 5 % ethanol and 95 % gasoline . if the car runs best on a mixture consisting of 10 % ethanol and 90 % gasoline , how many liters of ethanol must be added into the gas tank for the car to achieve optimum performance ? | "xz = y 2 10 ( 0.48 z ) = 10 ( 2 x 0.70 ) = 101.40 0.48 z = 1.40 z = 140 = 35 = 2.9 ( approx . ) 48 12 answer : c" | a ) 2.2 , b ) 8.2 , c ) 2.9 , d ) 2.1 , e ) 2.6 | c | divide(multiply(subtract(100.70, const_100), const_2), subtract(100.48, const_100)) | subtract(n1,const_100)|subtract(n0,const_100)|multiply(#0,const_2)|divide(#2,#1)| | general |
in a certain brick wall , each row of bricks above the bottom row contains one less brick than the row just below it . if there are 4 rows in all and a total of 134 bricks in the wall , how many bricks does the bottom row contain ? | "9 pages from 1 to 9 will require 9 digits . 90 pages from 10 to 99 will require 90 * 2 = 180 digits . 250 - ( 90 + 9 ) = 151 pages will require 151 * 3 = 453 digits . the total number of digits is 9 + 180 + 453 = 642 . the answer is b ." | a ) 756 , b ) 642 , c ) 492 , d ) 372 , e ) 250 | b | add(add(subtract(const_10, const_1), multiply(multiply(subtract(const_10, const_1), const_10), const_2)), multiply(add(subtract(250, const_100), const_1), const_3)) | subtract(const_10,const_1)|subtract(n0,const_100)|add(#1,const_1)|multiply(#0,const_10)|multiply(#3,const_2)|multiply(#2,const_3)|add(#4,#0)|add(#6,#5)| | general |
o ( x ) represents the least odd integer greater than x , whereas o ( x ) represents the greatest odd integer less than x . likewise , e ( x ) represents the least even integer greater than x , whereas e ( x ) represents the greatest even integer less than x . according to these definitions , the value of o ( 11.6 ) + e ( β 10.4 ) + o ( β 9.2 ) + e ( 9.5 ) is : | for sad : saddaily = $ 34.95 / day sadmile = $ 0.23 / mile for ral : raldaily = $ 25.00 / day ralmile = $ 1.31 / mile we want the raltotal = sadtotal , so we get ( raldaily * days ) + ( ralmile * miles ) = ( saddaily * days ) + ( sadmile * miles ) = > miles = ( ( saddaily * days ) - ( raldaily * days ) ) / ( ralmiles - sadmiles ) = ( ( saddaily - raldaily ) * days ) / ( ralmiles - sadmiles ) miles = ( ( $ 34.95 * 3 ) - ( $ 25.00 * 3 ) ) / ( $ 1.31 - $ 0.23 ) = 27.6 miles c . 27.6 miles | a ) 25.7 miles , b ) 26.2 miles , c ) 27.6 miles , d ) 27.9 miles , e ) 29.9 miles | c | divide(subtract(multiply(34.95, 3), multiply(25, 3)), subtract(1.31, 0.23)) | multiply(n0,n4)|multiply(n2,n4)|subtract(n3,n1)|subtract(#0,#1)|divide(#3,#2) | general |
what is the greatest prime factor of 5 ^ 6 - 1 ? | "let the leak can empty the full tank in x hours 1 / 9 - 1 / x = 1 / 12 = > 1 / x = 1 / 9 - 1 / 12 = 1 / 12 = > x = 36 . answer : a" | a ) 36 , b ) 88 , c ) 18 , d ) 26 , e ) 12 | a | divide(multiply(12, 9), subtract(12, 9)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)| | physics |
the number 70 can be written as the sum of the squares of 3 different positive integers . what is the sum of these 3 integers ? | every prime number greater than 3 can be written 6 n + 1 or 6 n - 1 . if p = 6 n + 1 , then p ^ 2 + 16 = 36 n ^ 2 + 12 n + 1 + 16 = 36 n ^ 2 + 12 n + 12 + 5 if p = 6 n - 1 , then p ^ 2 + 16 = 36 n ^ 2 - 12 n + 1 + 16 = 36 n ^ 2 - 12 n + 12 + 5 when divided by 12 , it must leave a remainder of 5 . the answer is a . | a ) 5 , b ) 1 , c ) 0 , d ) 8 , e ) 7 | a | subtract(add(16, power(add(const_1, const_4), const_2)), multiply(12, 3)) | add(const_1,const_4)|multiply(n0,n3)|power(#0,const_2)|add(n2,#2)|subtract(#3,#1) | general |
a train running at a speed of 36 km / h passes an electric pole in 15 seconds . in how many seconds will the whole train pass a 370 - meter long platform ? | "first day - 18 miles with 3 miles per hours then total - 6 hours for that day second day - 4 miles per hour and 5 hours - 20 miles third day - 7 miles per hour and 2 hours - 14 miles total 18 + 20 + 14 = 52 answer : option b ." | a ) 24 , b ) 52 , c ) 58 , d ) 60 , e ) 62 | b | add(add(18, multiply(7, const_4)), multiply(7, 2)) | multiply(n3,const_4)|multiply(n3,n4)|add(n1,#0)|add(#2,#1)| | physics |
if n is the greatest positive integer for which 2 ^ n is a factor of 8 ! , then n = ? | "f ( - 1 ) = 3 ( - 1 ) ^ 4 - 4 ( - 1 ) ^ 3 - 2 ( - 1 ) ^ 2 + 5 ( - 1 ) = 3 + 4 - 2 - 5 = 0 the answer is c ." | a ) - 4 , b ) - 2 , c ) 0 , d ) 2 , e ) 4 | c | add(subtract(subtract(multiply(3, power(negate(1), 4)), multiply(4, power(negate(1), 3))), multiply(3, power(negate(1), 2))), multiply(5, negate(1))) | negate(n7)|multiply(n6,#0)|power(#0,n1)|power(#0,n0)|power(#0,n5)|multiply(n0,#2)|multiply(n1,#3)|multiply(n0,#4)|subtract(#5,#6)|subtract(#8,#7)|add(#1,#9)| | general |
what percent of 5.2 kg is 16 gms ? | "total savings = s amount spent on stereo = ( 1 / 4 ) s amount spent on television = ( 1 - 1 / 5 ) ( 1 / 4 ) s = ( 4 / 5 ) * ( 1 / 4 ) * s = ( 1 / 5 ) s ( stereo + tv ) / total savings = s ( 1 / 4 + 1 / 5 ) / s = 9 / 20 answer : d" | a ) 1 / 4 , b ) 2 / 7 , c ) 5 / 12 , d ) 9 / 20 , e ) 7 / 12 | d | divide(1, 4) | divide(n0,n1)| | general |
a money lender finds that due to a fall in the annual rate of interest from 8 % to 7 1 / 5 % his yearly income diminishes by rs . 61.50 . his capital is | x is 20 % greater than 55 means x is 1.2 times 55 ( in other words 55 + 20 / 100 * 55 = 1.2 * 55 ) therefore , x = 1.2 * 55 = 66 answer : d | a ) 68 , b ) 70.4 , c ) 86 , d ) 66 , e ) 108 | d | add(55, multiply(divide(20, const_100), 55)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1) | general |