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Quais são os idiomas oficiais dos países dos jogadores de Maryland ou da faculdade de Duke?
CREATE TABLE country (Official_native_language VARCHAR, Country_id VARCHAR); CREATE TABLE match_season (Country VARCHAR, College VARCHAR)
SELECT T1.Official_native_language FROM country AS T1 JOIN match_season AS T2 ON T1.Country_id = T2.Country WHERE T2.College = "Maryland" OR T2.College = "Duke"
Quantos idiomas oficiais diferentes há entre os países de jogadores cujas posições são defensores.
CREATE TABLE country (Official_native_language VARCHAR, Country_id VARCHAR); CREATE TABLE match_season (Country VARCHAR, Position VARCHAR)
SELECT COUNT(DISTINCT T1.Official_native_language) FROM country AS T1 JOIN match_season AS T2 ON T1.Country_id = T2.Country WHERE T2.Position = "Defender"
Mostrar a temporada, o jogador e o nome da equipe a que os jogadores pertencem.
CREATE TABLE team (Name VARCHAR, Team_id VARCHAR); CREATE TABLE match_season (Season VARCHAR, Player VARCHAR, Team VARCHAR)
SELECT T1.Season, T1.Player, T2.Name FROM match_season AS T1 JOIN team AS T2 ON T1.Team = T2.Team_id
Mostrar as posições dos jogadores da equipa com o nome "Ryley Goldner".
CREATE TABLE match_season (Position VARCHAR, Team VARCHAR); CREATE TABLE team (Team_id VARCHAR, Name VARCHAR)
SELECT T1.Position FROM match_season AS T1 JOIN team AS T2 ON T1.Team = T2.Team_id WHERE T2.Name = "Ryley Goldner"
Quantas faculdades estão associadas a jogadores da equipa com o nome "Columbus Crew".
CREATE TABLE match_season (College VARCHAR, Team VARCHAR); CREATE TABLE team (Team_id VARCHAR, Name VARCHAR)
SELECT COUNT(DISTINCT T1.College) FROM match_season AS T1 JOIN team AS T2 ON T1.Team = T2.Team_id WHERE T2.Name = "Columbus Crew"
Mostrar os jogadores e anos jogados para jogadores da equipe "Columbus Crew".
CREATE TABLE player (Player VARCHAR, Years_Played VARCHAR, Team VARCHAR); CREATE TABLE team (Team_id VARCHAR, Name VARCHAR)
SELECT T1.Player, T1.Years_Played FROM player AS T1 JOIN team AS T2 ON T1.Team = T2.Team_id WHERE T2.Name = "Columbus Crew"
Indicar a posição dos jogadores e o número correspondente de jogadores.
CREATE TABLE match_season (POSITION VARCHAR)
SELECT POSITION, COUNT(*) FROM match_season GROUP BY POSITION
Indicar os nomes dos países e o número correspondente de jogadores.
CREATE TABLE match_season (Country VARCHAR); CREATE TABLE country (Country_name VARCHAR, Country_id VARCHAR)
SELECT Country_name, COUNT(*) FROM country AS T1 JOIN match_season AS T2 ON T1.Country_id = T2.Country GROUP BY T1.Country_name
Regressem todos os jogadores ordenados por faculdade em ordem alfabética ascendente.
CREATE TABLE match_season (player VARCHAR, College VARCHAR)
SELECT player FROM match_season ORDER BY College
Mostrar a posição mais comum dos jogadores nas temporadas de jogo.
CREATE TABLE match_season (POSITION VARCHAR)
SELECT POSITION FROM match_season GROUP BY POSITION ORDER BY COUNT(*) DESC LIMIT 1
Mostra as 3 escolas mais comuns de jogadores em temporadas de jogos.
CREATE TABLE match_season (College VARCHAR)
SELECT College FROM match_season GROUP BY College ORDER BY COUNT(*) DESC LIMIT 3
Mostrar o nome das faculdades que têm pelo menos dois jogadores.
CREATE TABLE match_season (College VARCHAR)
SELECT College FROM match_season GROUP BY College HAVING COUNT(*) >= 2
Mostrar o nome das faculdades que têm pelo menos dois jogadores em ordem alfabética descendente.
CREATE TABLE match_season (College VARCHAR)
SELECT College FROM match_season GROUP BY College HAVING COUNT(*) >= 2 ORDER BY College DESC
Quais são os nomes das equipas que não têm um recorde de temporada de jogos?
CREATE TABLE match_season (Name VARCHAR, Team_id VARCHAR, Team VARCHAR); CREATE TABLE team (Name VARCHAR, Team_id VARCHAR, Team VARCHAR)
SELECT Name FROM team WHERE NOT Team_id IN (SELECT Team FROM match_season)
Quais são os nomes dos países que têm jogadores com posição de ataque e jogadores com posição de defesa?
CREATE TABLE country (Country_name VARCHAR, Country_id VARCHAR); CREATE TABLE match_season (Country VARCHAR, Position VARCHAR)
SELECT T1.Country_name FROM country AS T1 JOIN match_season AS T2 ON T1.Country_id = T2.Country WHERE T2.Position = "Forward" INTERSECT SELECT T1.Country_name FROM country AS T1 JOIN match_season AS T2 ON T1.Country_id = T2.Country WHERE T2.Position = "Defender"
Que faculdade tem jogadores com posição de meio-campo e jogadores com posição de defesa?
CREATE TABLE match_season (College VARCHAR, POSITION VARCHAR)
SELECT College FROM match_season WHERE POSITION = "Midfielder" INTERSECT SELECT College FROM match_season WHERE POSITION = "Defender"
Quantos alpinistas há?
CREATE TABLE climber (Id VARCHAR)
SELECT COUNT(*) FROM climber
Escreva os nomes dos alpinistas em ordem decrescente de pontos.
CREATE TABLE climber (Name VARCHAR, Points VARCHAR)
SELECT Name FROM climber ORDER BY Points DESC
Escreva os nomes de alpinistas cujo país não é a Suíça.
CREATE TABLE climber (Name VARCHAR, Country VARCHAR)
SELECT Name FROM climber WHERE Country <> "Switzerland"
Qual é o ponto máximo para os alpinistas cujo país é o Reino Unido?
CREATE TABLE climber (Points INTEGER, Country VARCHAR)
SELECT MAX(Points) FROM climber WHERE Country = "United Kingdom"
De quantos países são os alpinistas?
CREATE TABLE climber (Country VARCHAR)
SELECT COUNT(DISTINCT Country) FROM climber
Quais são os nomes das montanhas em ordem alfabética ascendente?
CREATE TABLE mountain (Name VARCHAR)
SELECT Name FROM mountain ORDER BY Name
Quais são os países de montanhas com altitude maior que 5000?
CREATE TABLE mountain (Country VARCHAR, Height INTEGER)
SELECT Country FROM mountain WHERE Height > 5000
Qual é o nome da montanha mais alta?
CREATE TABLE mountain (Name VARCHAR, Height VARCHAR)
SELECT Name FROM mountain ORDER BY Height DESC LIMIT 1
Escreva as diferentes cadeias de montanhas com a proeminência dos três primeiros.
CREATE TABLE mountain (Range VARCHAR, Prominence VARCHAR)
SELECT DISTINCT Range FROM mountain ORDER BY Prominence DESC LIMIT 3
Mostrar os nomes dos alpinistas e os nomes das montanhas que eles escalam.
CREATE TABLE mountain (Name VARCHAR, Mountain_ID VARCHAR); CREATE TABLE climber (Name VARCHAR, Mountain_ID VARCHAR)
SELECT T1.Name, T2.Name FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID
Mostrar os nomes dos alpinistas e as alturas das montanhas que eles escalam.
CREATE TABLE mountain (Height VARCHAR, Mountain_ID VARCHAR); CREATE TABLE climber (Name VARCHAR, Mountain_ID VARCHAR)
SELECT T1.Name, T2.Height FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID
Mostrar a altura da montanha escalada pelo alpinista com os pontos máximos.
CREATE TABLE climber (Mountain_ID VARCHAR, Points VARCHAR); CREATE TABLE mountain (Height VARCHAR, Mountain_ID VARCHAR)
SELECT T2.Height FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID ORDER BY T1.Points DESC LIMIT 1
Mostrar os nomes distintos das montanhas escaladas por alpinistas do país "Alemanha Ocidental".
CREATE TABLE mountain (Name VARCHAR, Mountain_ID VARCHAR); CREATE TABLE climber (Mountain_ID VARCHAR, Country VARCHAR)
SELECT DISTINCT T2.Name FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID WHERE T1.Country = "West Germany"
Mostre os horários usados pelos alpinistas para escalar montanhas no País de Uganda.
CREATE TABLE mountain (Mountain_ID VARCHAR, Country VARCHAR); CREATE TABLE climber (Time VARCHAR, Mountain_ID VARCHAR)
SELECT T1.Time FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID = T2.Mountain_ID WHERE T2.Country = "Uganda"
Indique os países e o número de alpinistas de cada país.
CREATE TABLE climber (Country VARCHAR)
SELECT Country, COUNT(*) FROM climber GROUP BY Country
Liste os países que têm mais de uma montanha.
CREATE TABLE mountain (Country VARCHAR)
SELECT Country FROM mountain GROUP BY Country HAVING COUNT(*) > 1
Escreva os nomes de montanhas que não têm escalador.
CREATE TABLE mountain (Name VARCHAR, Mountain_ID VARCHAR); CREATE TABLE climber (Name VARCHAR, Mountain_ID VARCHAR)
SELECT Name FROM mountain WHERE NOT Mountain_ID IN (SELECT Mountain_ID FROM climber)
Mostre os países que têm montanhas com altura superior a 5600 andares e montanhas com altura inferior a 5200.
CREATE TABLE mountain (Country VARCHAR, Height INTEGER)
SELECT Country FROM mountain WHERE Height > 5600 INTERSECT SELECT Country FROM mountain WHERE Height < 5200
Mostre a faixa que tem o maior número de montanhas.
CREATE TABLE mountain (Range VARCHAR)
SELECT Range FROM mountain GROUP BY Range ORDER BY COUNT(*) DESC LIMIT 1
Mostrar os nomes de montanhas com altura superior a 5000 ou proeminência superior a 1000.
CREATE TABLE mountain (Name VARCHAR, Height VARCHAR, Prominence VARCHAR)
SELECT Name FROM mountain WHERE Height > 5000 OR Prominence > 1000
Quantos fisiculturistas há?
CREATE TABLE body_builder (Id VARCHAR)
SELECT COUNT(*) FROM body_builder
Lista as pontuações totais dos fisiculturistas em ordem ascendente.
CREATE TABLE body_builder (Total VARCHAR)
SELECT Total FROM body_builder ORDER BY Total
Escreva a pontuação de rapto e a pontuação de roubo dos fisiculturistas em ordem ascendente de pontuação.
CREATE TABLE body_builder (Snatch VARCHAR, Clean_Jerk VARCHAR)
SELECT Snatch, Clean_Jerk FROM body_builder ORDER BY Snatch
Qual é a pontuação média de rapto dos fisiculturistas?
CREATE TABLE body_builder (Snatch INTEGER)
SELECT AVG(Snatch) FROM body_builder
Qual é a pontuação de limpeza e de estupro do fisiculturista com a pontuação total mais alta?
CREATE TABLE body_builder (Clean_Jerk VARCHAR, Total VARCHAR)
SELECT Clean_Jerk FROM body_builder ORDER BY Total DESC LIMIT 1
Quais são os aniversários das pessoas em ordem ascendente de altura?
CREATE TABLE People (Birth_Date VARCHAR, Height VARCHAR)
SELECT Birth_Date FROM People ORDER BY Height
Como se chamam os fisiculturistas?
CREATE TABLE body_builder (People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
SELECT T2.Name FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID
Quais são os nomes dos fisiculturistas cuja pontuação total é superior a 300?
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE body_builder (People_ID VARCHAR, Total INTEGER)
SELECT T2.Name FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Total > 300
Como se chama o fisiculturista com o maior peso corporal?
CREATE TABLE body_builder (People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR, Weight VARCHAR)
SELECT T2.Name FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Weight DESC LIMIT 1
Qual é a data e o local de nascimento do fisiculturista com o maior total de pontos?
CREATE TABLE body_builder (People_ID VARCHAR, Total VARCHAR); CREATE TABLE people (Birth_Date VARCHAR, Birth_Place VARCHAR, People_ID VARCHAR)
SELECT T2.Birth_Date, T2.Birth_Place FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Total DESC LIMIT 1
Qual é a altura dos fisiculturistas com pontuação total inferior a 315?
CREATE TABLE people (Height VARCHAR, People_ID VARCHAR); CREATE TABLE body_builder (People_ID VARCHAR, Total INTEGER)
SELECT T2.Height FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Total < 315
Qual é a pontuação média total de fisiculturistas com altura superior a 200?
CREATE TABLE people (People_ID VARCHAR, Height INTEGER); CREATE TABLE body_builder (Total INTEGER, People_ID VARCHAR)
SELECT AVG(T1.Total) FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Height > 200
Quais são os nomes dos fisiculturistas em ordem decrescente de pontuação total?
CREATE TABLE body_builder (People_ID VARCHAR, Total VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
SELECT T2.Name FROM body_builder AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Total DESC
Escreva cada lugar de nascimento, juntamente com o número de pessoas de lá.
CREATE TABLE people (Birth_Place VARCHAR)
SELECT Birth_Place, COUNT(*) FROM people GROUP BY Birth_Place
Qual é o local de nascimento mais comum das pessoas?
CREATE TABLE people (Birth_Place VARCHAR)
SELECT Birth_Place FROM people GROUP BY Birth_Place ORDER BY COUNT(*) DESC LIMIT 1
Quais são os lugares de nascimento que pelo menos duas pessoas compartilham?
CREATE TABLE people (Birth_Place VARCHAR)
SELECT Birth_Place FROM people GROUP BY Birth_Place HAVING COUNT(*) >= 2
Escreva a altura e o peso das pessoas em ordem decrescente de altura.
CREATE TABLE people (Height VARCHAR, Weight VARCHAR)
SELECT Height, Weight FROM people ORDER BY Height DESC
Mostra todas as informações sobre cada fisiculturista.
CREATE TABLE body_builder (Id VARCHAR)
SELECT * FROM body_builder
Escreva os nomes e origens de pessoas que não são fisiculturistas.
CREATE TABLE people (Name VARCHAR, birth_place VARCHAR, people_id VARCHAR); CREATE TABLE body_builder (people_id VARCHAR); CREATE TABLE people (Name VARCHAR, birth_place VARCHAR)
SELECT Name, birth_place FROM people EXCEPT SELECT T1.Name, T1.birth_place FROM people AS T1 JOIN body_builder AS T2 ON T1.people_id = T2.people_id
Quantos lugares diferentes de nascimento há?
CREATE TABLE people (Birth_Place VARCHAR)
SELECT COUNT(DISTINCT Birth_Place) FROM people
Quantas pessoas não são fisiculturistas?
CREATE TABLE body_builder (people_id VARCHAR, People_ID VARCHAR); CREATE TABLE people (people_id VARCHAR, People_ID VARCHAR)
SELECT COUNT(*) FROM people WHERE NOT people_id IN (SELECT People_ID FROM body_builder)
Escreva o peso dos fisiculturistas que têm pontuação superior a 140 ou têm a altura superior a 200.
CREATE TABLE people (weight VARCHAR, people_id VARCHAR, height VARCHAR); CREATE TABLE body_builder (people_id VARCHAR, snatch VARCHAR)
SELECT T2.weight FROM body_builder AS T1 JOIN people AS T2 ON T1.people_id = T2.people_id WHERE T1.snatch > 140 OR T2.height > 200
Quais são as pontuações totais dos fisiculturistas cujo aniversário contém a string "January"?
CREATE TABLE people (people_id VARCHAR, Birth_Date VARCHAR); CREATE TABLE body_builder (total VARCHAR, people_id VARCHAR)
SELECT T1.total FROM body_builder AS T1 JOIN people AS T2 ON T1.people_id = T2.people_id WHERE T2.Birth_Date LIKE "%January%"
Qual é o escore mínimo de rapto?
CREATE TABLE body_builder (snatch INTEGER)
SELECT MIN(snatch) FROM body_builder
Quantas eleições há?
CREATE TABLE election (Id VARCHAR)
SELECT COUNT(*) FROM election
Lista os votos das eleições em ordem decrescente.
CREATE TABLE election (Votes VARCHAR)
SELECT Votes FROM election ORDER BY Votes DESC
Listar as datas e percentagens de votos das eleições.
CREATE TABLE election (Date VARCHAR, Vote_Percent VARCHAR)
SELECT Date, Vote_Percent FROM election
Quais são as percentagens mínimas e máximas de votos nas eleições?
CREATE TABLE election (Vote_Percent INTEGER)
SELECT MIN(Vote_Percent), MAX(Vote_Percent) FROM election
Quais são os nomes e partidos dos representantes?
CREATE TABLE representative (Name VARCHAR, Party VARCHAR)
SELECT Name, Party FROM representative
Quais são os nomes dos representantes cujo partido não é "Republicano"?
CREATE TABLE Representative (Name VARCHAR, Party VARCHAR)
SELECT Name FROM Representative WHERE Party <> "Republican"
Qual é a expectativa de vida dos representantes do estado de Nova Iorque ou do estado de Indiana?
CREATE TABLE representative (Lifespan VARCHAR, State VARCHAR)
SELECT Lifespan FROM representative WHERE State = "New York" OR State = "Indiana"
Quais são os nomes dos representantes e as datas das eleições em que participaram?
CREATE TABLE election (Date VARCHAR, Representative_ID VARCHAR); CREATE TABLE representative (Name VARCHAR, Representative_ID VARCHAR)
SELECT T2.Name, T1.Date FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID
Quais são os nomes dos representantes com mais de 10.000 votos nas eleições?
CREATE TABLE representative (Name VARCHAR, Representative_ID VARCHAR); CREATE TABLE election (Representative_ID VARCHAR)
SELECT T2.Name FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID WHERE Votes > 10000
Quais são os nomes dos representantes em ordem decrescente de votos?
CREATE TABLE representative (Name VARCHAR, Representative_ID VARCHAR); CREATE TABLE election (Representative_ID VARCHAR)
SELECT T2.Name FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID ORDER BY votes DESC
Qual é o partido do representante que tem o menor número de votos.
CREATE TABLE representative (Party VARCHAR, Representative_ID VARCHAR); CREATE TABLE election (Representative_ID VARCHAR)
SELECT T2.Party FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID ORDER BY votes LIMIT 1
Qual é a expectativa de vida dos representantes em ordem decrescente de percentagem de votos?
CREATE TABLE election (Representative_ID VARCHAR); CREATE TABLE representative (Lifespan VARCHAR, Representative_ID VARCHAR)
SELECT T2.Lifespan FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID ORDER BY Vote_Percent DESC
Qual é o número médio de votos de representantes do partido "Republicano"?
CREATE TABLE election (Votes INTEGER, Representative_ID VARCHAR); CREATE TABLE representative (Representative_ID VARCHAR, Party VARCHAR)
SELECT AVG(T1.Votes) FROM election AS T1 JOIN representative AS T2 ON T1.Representative_ID = T2.Representative_ID WHERE T2.Party = "Republican"
Quais são os diferentes partidos de representantes?
CREATE TABLE representative (Party VARCHAR)
SELECT Party, COUNT(*) FROM representative GROUP BY Party
Qual é o partido que tem o maior número de representantes?
CREATE TABLE representative (Party VARCHAR)
SELECT Party, COUNT(*) FROM representative GROUP BY Party ORDER BY COUNT(*) DESC LIMIT 1
Que partidos têm pelo menos três representantes?
CREATE TABLE representative (Party VARCHAR)
SELECT Party FROM representative GROUP BY Party HAVING COUNT(*) >= 3
Que estados têm pelo menos dois representantes?
CREATE TABLE representative (State VARCHAR)
SELECT State FROM representative GROUP BY State HAVING COUNT(*) >= 2
Escreva os nomes dos representantes que não participaram nas eleições listadas aqui.
CREATE TABLE election (Name VARCHAR, Representative_ID VARCHAR); CREATE TABLE representative (Name VARCHAR, Representative_ID VARCHAR)
SELECT Name FROM representative WHERE NOT Representative_ID IN (SELECT Representative_ID FROM election)
Mostre os partidos que têm representantes no estado de Nova York e representantes no estado da Pensilvânia.
CREATE TABLE representative (Party VARCHAR, State VARCHAR)
SELECT Party FROM representative WHERE State = "New York" INTERSECT SELECT Party FROM representative WHERE State = "Pennsylvania"
Quantos partidos diferentes existem para representantes?
CREATE TABLE representative (Party VARCHAR)
SELECT COUNT(DISTINCT Party) FROM representative
Quantos apartamentos estão reservados no total?
CREATE TABLE Apartment_Bookings (Id VARCHAR)
SELECT COUNT(*) FROM Apartment_Bookings
Mostrar as datas de início e de fim de todas as reservas de apartamentos.
CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, booking_end_date VARCHAR)
SELECT booking_start_date, booking_end_date FROM Apartment_Bookings
Mostre todas as descrições dos edifícios.
CREATE TABLE Apartment_Buildings (building_description VARCHAR)
SELECT DISTINCT building_description FROM Apartment_Buildings
Mostre os nomes abreviados dos edifícios geridos pela "Emma".
CREATE TABLE Apartment_Buildings (building_short_name VARCHAR, building_manager VARCHAR)
SELECT building_short_name FROM Apartment_Buildings WHERE building_manager = "Emma"
Mostra-me os endereços e telefones de todos os edifícios geridos pelo "Brenden".
CREATE TABLE Apartment_Buildings (building_address VARCHAR, building_phone VARCHAR, building_manager VARCHAR)
SELECT building_address, building_phone FROM Apartment_Buildings WHERE building_manager = "Brenden"
Quais são os nomes completos dos edifícios que contêm a palavra "corte"?
CREATE TABLE Apartment_Buildings (building_full_name VARCHAR)
SELECT building_full_name FROM Apartment_Buildings WHERE building_full_name LIKE "%court%"
Qual é o número mínimo e máximo de banheiros de todos os apartamentos?
CREATE TABLE Apartments (bathroom_count INTEGER)
SELECT MIN(bathroom_count), MAX(bathroom_count) FROM Apartments
Qual é o número médio de quartos de todos os apartamentos?
CREATE TABLE Apartments (bedroom_count INTEGER)
SELECT AVG(bedroom_count) FROM Apartments
Registre o número do apartamento e o número de quartos de cada apartamento.
CREATE TABLE Apartments (apt_number VARCHAR, room_count VARCHAR)
SELECT apt_number, room_count FROM Apartments
Qual é o número médio de quartos de apartamentos com código de tipo "Studio"?
CREATE TABLE Apartments (room_count INTEGER, apt_type_code VARCHAR)
SELECT AVG(room_count) FROM Apartments WHERE apt_type_code = "Studio"
Regressar os números de apartamento dos apartamentos com tipo de código "Flat".
CREATE TABLE Apartments (apt_number VARCHAR, apt_type_code VARCHAR)
SELECT apt_number FROM Apartments WHERE apt_type_code = "Flat"
Devolver os primeiros nomes e apelidos de todos os convidados
CREATE TABLE Guests (guest_first_name VARCHAR, guest_last_name VARCHAR)
SELECT guest_first_name, guest_last_name FROM Guests
Devolva a data de nascimento de todos os convidados com código de género "Homem".
CREATE TABLE Guests (date_of_birth VARCHAR, gender_code VARCHAR)
SELECT date_of_birth FROM Guests WHERE gender_code = "Male"
Mostrar os números de apartamentos, datas de início e de fim de todas as reservas de apartamentos.
CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, apt_id VARCHAR); CREATE TABLE Apartments (apt_number VARCHAR, apt_id VARCHAR)
SELECT T2.apt_number, T1.booking_start_date, T1.booking_start_date FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id
Quais são as datas de início e de fim da reserva dos apartamentos com código de tipo "Duplex"?
CREATE TABLE Apartments (apt_id VARCHAR, apt_type_code VARCHAR); CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, apt_id VARCHAR)
SELECT T1.booking_start_date, T1.booking_start_date FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T2.apt_type_code = "Duplex"
Quais são as datas de início e de fim das reservas dos apartamentos com mais de 2 quartos?
CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, apt_id VARCHAR); CREATE TABLE Apartments (apt_id VARCHAR, bedroom_count INTEGER)
SELECT T1.booking_start_date, T1.booking_start_date FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T2.bedroom_count > 2
Qual é o código de estado da reserva do apartamento com o número de apartamento "Suite 634"?
CREATE TABLE Apartments (apt_id VARCHAR, apt_number VARCHAR); CREATE TABLE Apartment_Bookings (booking_status_code VARCHAR, apt_id VARCHAR)
SELECT T1.booking_status_code FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T2.apt_number = "Suite 634"
Mostrar os números de apartamentos dos apartamentos que têm reservas com o código de status "Confirmado".
CREATE TABLE Apartments (apt_number VARCHAR, apt_id VARCHAR); CREATE TABLE Apartment_Bookings (apt_id VARCHAR, booking_status_code VARCHAR)
SELECT DISTINCT T2.apt_number FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T1.booking_status_code = "Confirmed"
Mostrar o número médio de quartos dos apartamentos que têm o código de status de reserva "Provisório".
CREATE TABLE Apartment_Bookings (apt_id VARCHAR, booking_status_code VARCHAR); CREATE TABLE Apartments (apt_id VARCHAR)
SELECT AVG(room_count) FROM Apartment_Bookings AS T1 JOIN Apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T1.booking_status_code = "Provisional"
Mostra aos convidados os nomes, datas de início e de fim de todas as reservas de apartamentos.
CREATE TABLE Apartment_Bookings (booking_start_date VARCHAR, guest_id VARCHAR); CREATE TABLE Guests (guest_first_name VARCHAR, guest_id VARCHAR)
SELECT T2.guest_first_name, T1.booking_start_date, T1.booking_start_date FROM Apartment_Bookings AS T1 JOIN Guests AS T2 ON T1.guest_id = T2.guest_id