question
stringlengths 63
269
| answer
stringlengths 18
557
|
|---|---|
How many students does each advisor have?
Additional table information: table: allergy_1 | SELECT advisor, COUNT(*) FROM Student GROUP BY advisor |
Which advisor has most number of students?
Additional table information: table: allergy_1 | SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1 |
Give the advisor with the most students.
Additional table information: table: allergy_1 | SELECT advisor FROM Student GROUP BY advisor ORDER BY COUNT(*) DESC LIMIT 1 |
How many students have cat allergies?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Has_allergy WHERE Allergy = 'Cat' |
How many students are affected by cat allergies?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Has_allergy WHERE Allergy = 'Cat' |
Show all student IDs who have at least two allergies.
Additional table information: table: allergy_1 | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2 |
What are the students ids of students who have more than one allergy?
Additional table information: table: allergy_1 | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING COUNT(*) >= 2 |
What are the student ids of students who don't have any allergies?
Additional table information: table: allergy_1 | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy |
Which students are unaffected by allergies?
Additional table information: table: allergy_1 | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy |
How many female students have milk or egg allergies?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = 'F' AND T1.allergy = 'Milk' OR T1.allergy = 'Eggs' |
How many students who are female are allergic to milk or eggs?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = 'F' AND T1.allergy = 'Milk' OR T1.allergy = 'Eggs' |
How many students have a food allergy?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = 'food' |
How many students are affected by food related allergies?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = 'food' |
Which allergy has most number of students affected?
Additional table information: table: allergy_1 | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1 |
Which allergy is the most common?
Additional table information: table: allergy_1 | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY COUNT(*) DESC LIMIT 1 |
Show all allergies with number of students affected.
Additional table information: table: allergy_1 | SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy |
How many students have each different allergy?
Additional table information: table: allergy_1 | SELECT Allergy, COUNT(*) FROM Has_allergy GROUP BY Allergy |
Show all allergy type with number of students affected.
Additional table information: table: allergy_1 | SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype |
How many students are affected by each allergy type?
Additional table information: table: allergy_1 | SELECT T2.allergytype, COUNT(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype |
Find the last name and age of the student who has allergy to both milk and cat.
Additional table information: table: allergy_1 | SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat') |
What are the last names and ages of the students who are allergic to milk and cat?
Additional table information: table: allergy_1 | SELECT lname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat') |
What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies.
Additional table information: table: allergy_1 | SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = 'Lisa' ORDER BY T1.Allergy NULLS FIRST |
What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names.
Additional table information: table: allergy_1 | SELECT T1.Allergy, T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = 'Lisa' ORDER BY T1.Allergy NULLS FIRST |
Find the first name and gender of the student who has allergy to milk but not cat.
Additional table information: table: allergy_1 | SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat') |
What are the first name and gender of the students who have allergy to milk but can put up with cats?
Additional table information: table: allergy_1 | SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Milk' EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = 'Cat') |
Find the average age of the students who have allergies with food and animal types.
Additional table information: table: allergy_1 | SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'animal') |
How old are the students with allergies to food and animal types on average?
Additional table information: table: allergy_1 | SELECT AVG(age) FROM Student WHERE StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'animal') |
List the first and last name of the students who do not have any food type allergy.
Additional table information: table: allergy_1 | SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food') |
What is the full name of each student who is not allergic to any type of food.
Additional table information: table: allergy_1 | SELECT fname, lname FROM Student WHERE NOT StuID IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food') |
Find the number of male (sex is 'M') students who have some food type allery.
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Student WHERE sex = 'M' AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food') |
How many male students (sex is 'M') are allergic to any type of food?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Student WHERE sex = 'M' AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food') |
Find the different first names and cities of the students who have allergy to milk or cat.
Additional table information: table: allergy_1 | SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = 'Milk' OR T2.Allergy = 'Cat' |
What are the distinct first names and cities of the students who have allergy either to milk or to cat?
Additional table information: table: allergy_1 | SELECT DISTINCT T1.fname, T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = 'Milk' OR T2.Allergy = 'Cat' |
Find the number of students who are older than 18 and do not have allergy to either food or animal.
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' OR T2.allergytype = 'animal') |
How many students are over 18 and do not have allergy to food type or animal type?
Additional table information: table: allergy_1 | SELECT COUNT(*) FROM Student WHERE age > 18 AND NOT StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = 'food' OR T2.allergytype = 'animal') |
Find the first name and major of the students who are not allegry to soy.
Additional table information: table: allergy_1 | SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Soy') |
What are the first name and major of the students who are able to consume soy?
Additional table information: table: allergy_1 | SELECT fname, major FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = 'Soy') |
A list of the top 5 countries by number of invoices. List country name and number of invoices.
Additional table information: table: store_1 | SELECT billing_country, COUNT(*) FROM invoices GROUP BY billing_country ORDER BY COUNT(*) DESC LIMIT 5 |
What are the top 5 countries by number of invoices and how many do they have?
Additional table information: table: store_1 | SELECT billing_country, COUNT(*) FROM invoices GROUP BY billing_country ORDER BY COUNT(*) DESC LIMIT 5 |
A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size.
Additional table information: table: store_1 | SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8 |
What are the names of the top 8 countries by total invoice size and what are those sizes?
Additional table information: table: store_1 | SELECT billing_country, SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8 |
A list of the top 10 countries by average invoice size. List country name and average invoice size.
Additional table information: table: store_1 | SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10 |
What are the names of the countries and average invoice size of the top countries by size?
Additional table information: table: store_1 | SELECT billing_country, AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10 |
Find out 5 customers who most recently purchased something. List customers' first and last name.
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5 |
What are the first and last names of the 5 customers who purchased something most recently?
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5 |
Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders.
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name, COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10 |
What are the top 10 customers' first and last names by total number of orders and how many orders did they make?
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name, COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10 |
List the top 10 customers by total gross sales. List customers' first and last name and total gross sales.
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10 |
What are the top 10 customers' first and last names with the highest gross sales, and also what are the sales?
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name, SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10 |
List the top 5 genres by number of tracks. List genres name and total tracks.
Additional table information: table: store_1 | SELECT T1.name, COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 5 |
How many tracks does each genre have and what are the names of the top 5?
Additional table information: table: store_1 | SELECT T1.name, COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 5 |
List every album's title.
Additional table information: table: store_1 | SELECT title FROM albums |
What are the titles of all the albums?
Additional table information: table: store_1 | SELECT title FROM albums |
List every album ordered by album title in ascending order.
Additional table information: table: store_1 | SELECT title FROM albums ORDER BY title NULLS FIRST |
What are the titles of all the albums alphabetically ascending?
Additional table information: table: store_1 | SELECT title FROM albums ORDER BY title NULLS FIRST |
List every album whose title starts with A in alphabetical order.
Additional table information: table: store_1 | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title NULLS FIRST |
What are the titles of all albums that start with A in alphabetical order?
Additional table information: table: store_1 | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title NULLS FIRST |
List the customers first and last name of 10 least expensive invoices.
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total NULLS FIRST LIMIT 10 |
What are the first and last names of the customers with the 10 cheapest invoices?
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total NULLS FIRST LIMIT 10 |
List total amount of invoice from Chicago, IL.
Additional table information: table: store_1 | SELECT SUM(total) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL' |
What are the total amount of money in the invoices billed from Chicago, Illinois?
Additional table information: table: store_1 | SELECT SUM(total) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL' |
List the number of invoices from Chicago, IL.
Additional table information: table: store_1 | SELECT COUNT(*) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL' |
How many invoices were billed from Chicago, IL?
Additional table information: table: store_1 | SELECT COUNT(*) FROM invoices WHERE billing_city = 'Chicago' AND billing_state = 'IL' |
List the number of invoices from the US, grouped by state.
Additional table information: table: store_1 | SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state |
How many invoices were billed from each state?
Additional table information: table: store_1 | SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state |
List the state in the US with the most invoices.
Additional table information: table: store_1 | SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1 |
What are the states with the most invoices?
Additional table information: table: store_1 | SELECT billing_state, COUNT(*) FROM invoices WHERE billing_country = 'USA' GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1 |
List the number of invoices and the invoice total from California.
Additional table information: table: store_1 | SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = 'CA' |
What is the number of invoices and total money billed in them from CA?
Additional table information: table: store_1 | SELECT billing_state, COUNT(*), SUM(total) FROM invoices WHERE billing_state = 'CA' |
List Aerosmith's albums.
Additional table information: table: store_1 | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = 'Aerosmith' |
What are the titles of all the Aerosmith albums?
Additional table information: table: store_1 | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = 'Aerosmith' |
How many albums does Billy Cobham has?
Additional table information: table: store_1 | SELECT COUNT(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = 'Billy Cobham' |
How many albums has Billy Cobam released?
Additional table information: table: store_1 | SELECT COUNT(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = 'Billy Cobham' |
Eduardo Martins is a customer at which company?
Additional table information: table: store_1 | SELECT company FROM customers WHERE first_name = 'Eduardo' AND last_name = 'Martins' |
What is the company where Eduardo Martins is a customer?
Additional table information: table: store_1 | SELECT company FROM customers WHERE first_name = 'Eduardo' AND last_name = 'Martins' |
What is Astrid Gruber's email and phone number?
Additional table information: table: store_1 | SELECT email, phone FROM customers WHERE first_name = 'Astrid' AND last_name = 'Gruber' |
What is the email and phone number of Astrid Gruber the customer?
Additional table information: table: store_1 | SELECT email, phone FROM customers WHERE first_name = 'Astrid' AND last_name = 'Gruber' |
How many customers live in Prague city?
Additional table information: table: store_1 | SELECT COUNT(*) FROM customers WHERE city = 'Prague' |
How many customers live in the city of Prague?
Additional table information: table: store_1 | SELECT COUNT(*) FROM customers WHERE city = 'Prague' |
How many customers in state of CA?
Additional table information: table: store_1 | SELECT COUNT(*) FROM customers WHERE state = 'CA' |
How many customers are from California?
Additional table information: table: store_1 | SELECT COUNT(*) FROM customers WHERE state = 'CA' |
What country does Roberto Almeida live?
Additional table information: table: store_1 | SELECT country FROM customers WHERE first_name = 'Roberto' AND last_name = 'Almeida' |
In which country does Roberto Almeida?
Additional table information: table: store_1 | SELECT country FROM customers WHERE first_name = 'Roberto' AND last_name = 'Almeida' |
List the name of albums that are released by aritist whose name has 'Led'
Additional table information: table: store_1 | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' |
What is the title of the album that was released by the artist whose name has the phrase 'Led'?
Additional table information: table: store_1 | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' |
How many customers does Steve Johnson support?
Additional table information: table: store_1 | SELECT COUNT(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = 'Steve' AND T1.last_name = 'Johnson' |
What is the count of customers that Steve Johnson supports?
Additional table information: table: store_1 | SELECT COUNT(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = 'Steve' AND T1.last_name = 'Johnson' |
What is the title, phone and hire date of Nancy Edwards?
Additional table information: table: store_1 | SELECT title, phone, hire_date FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
What is the title, phone number and hire date for the employee named Nancy Edwards?
Additional table information: table: store_1 | SELECT title, phone, hire_date FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
find the full name of employees who report to Nancy Edwards?
Additional table information: table: store_1 | SELECT T2.first_name, T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = 'Nancy' AND T1.last_name = 'Edwards' |
What is the first and last name of the employee who reports to Nancy Edwards?
Additional table information: table: store_1 | SELECT T2.first_name, T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = 'Nancy' AND T1.last_name = 'Edwards' |
What is the address of employee Nancy Edwards?
Additional table information: table: store_1 | SELECT address FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
What is Nancy Edwards's address?
Additional table information: table: store_1 | SELECT address FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
Find the full name of employee who supported the most number of customers.
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1 |
What is the full name of the employee who has the most customers?
Additional table information: table: store_1 | SELECT T1.first_name, T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1 |
How many employees are living in Canada?
Additional table information: table: store_1 | SELECT COUNT(*) FROM employees WHERE country = 'Canada' |
How many employees live in Canada?
Additional table information: table: store_1 | SELECT COUNT(*) FROM employees WHERE country = 'Canada' |
What is employee Nancy Edwards's phone number?
Additional table information: table: store_1 | SELECT phone FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
What is the the phone number of Nancy Edwards?
Additional table information: table: store_1 | SELECT phone FROM employees WHERE first_name = 'Nancy' AND last_name = 'Edwards' |
Who is the youngest employee in the company? List employee's first and last name.
Additional table information: table: store_1 | SELECT first_name, last_name FROM employees ORDER BY birth_date DESC LIMIT 1 |