name
stringlengths
34
63
language
stringclasses
3 values
prompt
stringlengths
91
2.81k
suffix
stringlengths
0
1.57k
canonical_solution
stringlengths
1
219
tests
stringlengths
149
4.98k
humaneval-HumanEval_156_int_to_mini_roman.json-L21
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> intToMiniRoman((19l)) // ("xix") // >>> intToMiniRoman((152l)) // ("clii") // >>> intToMiniRoman((426l)) // ("cdxxvi") public static String intToMiniRoman(long number) { int num = (int) number;
if (num == 0) return ""; while (num >= 1000) { res += "m"; num -= 1000; } if (num >= 900) { res += "cm"; num -= 900; } if (num >= 500) { res += "d"; num -= 500; } if (num >= 400) { res += "cd"; num -= 400; } while (num >= 100) { res += "c"; num -= 100; } if (num >= 90) { res += "xc"; num -= 90; } if (num >= 50) { res += "l"; num -= 50; } if (num >= 40) { res += "xl"; num -= 40; } while (num >= 10) { res += "x"; num -= 10; } if (num >= 9) { res += "ix"; num -= 9; } if (num >= 5) { res += "v"; num -= 5; } if (num >= 4) { res += "iv"; num -= 4; } while (num >= 1) { res += "i"; num -= 1; } return res; } }
String res = "";
} public static void main(String[] args) { assert(intToMiniRoman((19l)).equals(("xix"))); assert(intToMiniRoman((152l)).equals(("clii"))); assert(intToMiniRoman((251l)).equals(("ccli"))); assert(intToMiniRoman((426l)).equals(("cdxxvi"))); assert(intToMiniRoman((500l)).equals(("d"))); assert(intToMiniRoman((1l)).equals(("i"))); assert(intToMiniRoman((4l)).equals(("iv"))); assert(intToMiniRoman((43l)).equals(("xliii"))); assert(intToMiniRoman((90l)).equals(("xc"))); assert(intToMiniRoman((94l)).equals(("xciv"))); assert(intToMiniRoman((532l)).equals(("dxxxii"))); assert(intToMiniRoman((900l)).equals(("cm"))); assert(intToMiniRoman((994l)).equals(("cmxciv"))); assert(intToMiniRoman((1000l)).equals(("m"))); } }
humaneval-HumanEval_67_fruit_distribution.json-L23
py
def fruit_distribution(s: str, n: int) -> int: """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket. for examble: >>> fruit_distribution('5 apples and 6 oranges', 19) 8 >>> fruit_distribution('0 apples and 1 oranges', 3) 2 >>> fruit_distribution('2 apples and 3 oranges', 100) 95 >>> fruit_distribution('100 apples and 1 oranges', 120) 19 """ fruits = [] for fruit in s.split(' '): try: fruits.append(int(fruit)) except:
return n - sum(fruits)
pass
def check(candidate): assert candidate('5 apples and 6 oranges', 19) == 8 assert candidate('5 apples and 6 oranges', 21) == 10 assert candidate('0 apples and 1 oranges', 3) == 2 assert candidate('1 apples and 0 oranges', 3) == 2 assert candidate('2 apples and 3 oranges', 100) == 95 assert candidate('2 apples and 3 oranges', 5) == 0 assert candidate('1 apples and 100 oranges', 120) == 19 def test_check(): check(fruit_distribution) test_check()
humaneval-HumanEval_70_strange_sort_list.json-L36
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given array list of integers, return array list in strange order. // Strange sorting, is when you start with the minimum value, // then maximum of the remaining integers, then minimum and so on. // Examples: // >>> strangeSortList((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)2l, (long)3l))) // >>> strangeSortList((new ArrayList<Long>(Arrays.asList((long)5l, (long)5l, (long)5l, (long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)5l, (long)5l, (long)5l, (long)5l))) // >>> strangeSortList((new ArrayList<Long>(Arrays.asList()))) // (new ArrayList<Long>(Arrays.asList())) public static ArrayList<Long> strangeSortList(ArrayList<Long> lst) { if (lst.size() <= 1) { return lst; } ArrayList<Long> result = new ArrayList<Long>(); ArrayList<Long> sorted = new ArrayList<Long>(lst); Collections.sort(sorted); int min = 0; int max = sorted.size() - 1; while (min <= max) { result.add(sorted.get(min)); min++; if (min <= max) { result.add(sorted.get(max)); max--; } }
} }
return result;
} public static void main(String[] args) { assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)2l, (long)3l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)7l, (long)8l, (long)9l)))).equals((new ArrayList<Long>(Arrays.asList((long)5l, (long)9l, (long)6l, (long)8l, (long)7l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)5l, (long)2l, (long)4l, (long)3l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)7l, (long)8l, (long)9l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)9l, (long)5l, (long)8l, (long)6l, (long)7l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)5l, (long)5l, (long)5l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)5l, (long)5l, (long)5l, (long)5l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<Long>(Arrays.asList())))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l, (long)8l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)8l, (long)2l, (long)7l, (long)3l, (long)6l, (long)4l, (long)5l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)0l, (long)2l, (long)2l, (long)2l, (long)5l, (long)5l, (long)-5l, (long)-5l)))).equals((new ArrayList<Long>(Arrays.asList((long)-5l, (long)5l, (long)-5l, (long)5l, (long)0l, (long)2l, (long)2l, (long)2l))))); assert(strangeSortList((new ArrayList<Long>(Arrays.asList((long)111111l)))).equals((new ArrayList<Long>(Arrays.asList((long)111111l))))); } }
humaneval-HumanEval_35_max_element.json-L16
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return maximum element in the array list. // >>> maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (3l) // >>> maxElement((new ArrayList<Long>(Arrays.asList((long)5l, (long)3l, (long)-5l, (long)2l, (long)-3l, (long)3l, (long)9l, (long)0l, (long)123l, (long)1l, (long)-10l)))) // (123l) public static long maxElement(ArrayList<Long> l) { Long max = Long.MIN_VALUE;
if (l.get(i) > max) { max = l.get(i); } } return max; } }
for (int i = 0; i < l.size(); i += 1) {
} public static void main(String[] args) { assert(maxElement((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) == (3l)); assert(maxElement((new ArrayList<Long>(Arrays.asList((long)5l, (long)3l, (long)-5l, (long)2l, (long)-3l, (long)3l, (long)9l, (long)0l, (long)124l, (long)1l, (long)-10l)))) == (124l)); } }
humaneval-HumanEval_40_triples_sum_to_zero.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // triples_sum_to_zero takes an array array list of integers as an input. // it returns true if there are three distinct elements in the array list that // sum to zero, and false otherwise. // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) // (false) public static boolean triplesSumToZero(ArrayList<Long> l) { if (l.size() < 3) { return false; } ArrayList<Long> sortedList = new ArrayList<Long>(l); Collections.sort(sortedList); for (int i = 0; i < sortedList.size() - 2; i++) { int j = i + 1; int k = sortedList.size() - 1; while (j < k) { long currSum = sortedList.get(i) + sortedList.get(j) + sortedList.get(k); if (currSum == 0) {
} else if (currSum < 0) { j++; } else { k--; } } } return false; } }
return true;
} public static void main(String[] args) { assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)5l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-100l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)100l, (long)3l, (long)5l, (long)-100l)))) == (false)); } }
humaneval-HumanEval_72_will_it_fly.json-L21
js
//Write a function that returns true if the object q will fly, and false otherwise. // The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w. // Example: // >>> will_it_fly([1, 2], 5) // false // # 1+2 is less than the maximum possible weight, but it's unbalanced. // >>> will_it_fly([3, 2, 3], 1) // false // # it's balanced, but 3+2+3 is more than the maximum possible weight. // >>> will_it_fly([3, 2, 3], 9) // true // # 3+2+3 is less than the maximum possible weight, and it's balanced. // >>> will_it_fly([3], 5) // true // # 3 is less than the maximum possible weight, and it's balanced. function will_it_fly(q, w){ let sum = 0; let balanced = true; for(let i = 0; i < q.length; i++){ sum += q[i];
for(let i = 0; i < q.length; i++){ if(q[i] !== q[q.length - 1 - i]){ balanced = false; break; } } return balanced && sum <= w; }
}
const assert = require('node:assert'); function test() { let candidate = will_it_fly; assert.deepEqual(candidate([3, 2, 3], 9),true); assert.deepEqual(candidate([1, 2], 5),false); assert.deepEqual(candidate([3], 5),true); assert.deepEqual(candidate([3, 2, 3], 1),false); assert.deepEqual(candidate([1, 2, 3], 6),false); assert.deepEqual(candidate([5], 5),true); } test();
humaneval-HumanEval_123_get_odd_collatz.json-L24
py
from typing import List def get_odd_collatz(n: int) -> List[int]: """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the previous term as follows: if the previous term is even, the next term is one half of the previous term. If the previous term is odd, the next term is 3 times the previous term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1. Note: 1. Collatz(1) is [1]. 2. returned list sorted in increasing order. For example: get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5. >>> get_odd_collatz(5) [1, 5] """ collatz_list = [] current_num = n
collatz_list.append(current_num) if (current_num % 2 == 0): current_num = current_num // 2 else: current_num = current_num * 3 + 1 collatz_list.append(1) return sorted(list(set([x for x in collatz_list if x % 2 != 0])))
while (current_num > 1):
def check(candidate): assert candidate(14) == [1, 5, 7, 11, 13, 17] assert candidate(5) == [1, 5] assert candidate(12) == [1, 3, 5] assert candidate(1) == [1] def test_check(): check(get_odd_collatz) test_check()
humaneval-HumanEval_142_sum_squares.json-L18
py
from typing import List def sum_squares(lst: List[int]) -> int: """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. Examples: >>> lst [1, 2, 3] >>> lst [] >>> lst [-1, -5, 2, -1, -5] """ for index in range(len(lst)):
lst[index] = lst[index] ** 2 elif index % 4 == 0: lst[index] = lst[index] ** 3 return sum(lst)
if index % 3 == 0:
def check(candidate): assert candidate([1, 2, 3]) == 6 assert candidate([1, 4, 9]) == 14 assert candidate([]) == 0 assert candidate([1, 1, 1, 1, 1, 1, 1, 1, 1]) == 9 assert candidate([-1, -1, -1, -1, -1, -1, -1, -1, -1]) == -3 assert candidate([0]) == 0 assert candidate([-1, -5, 2, -1, -5]) == -126 assert candidate([-56, -99, 1, 0, -2]) == 3030 assert candidate([-1, 0, 0, 0, 0, 0, 0, 0, -1]) == 0 assert candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]) == -14196 assert candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]) == -1448 def test_check(): check(sum_squares) test_check()
humaneval-HumanEval_3_below_zero.json-L24
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You're given an array array list of deposit and withdrawal operations on a bank account that starts with // zero balance. Your task is to detect if at any point the balance of account fallls below zero, and // at that point function should return true. Otherwise it should return false. // >>> belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (false) // >>> belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-4l, (long)5l)))) // (true) public static boolean belowZero(ArrayList<Long> operations) { long balance = 0; for (long op : operations) { balance += op; if (balance < 0) { return true; } }
} }
return false;
} public static void main(String[] args) { assert(belowZero((new ArrayList<Long>(Arrays.asList()))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-3l, (long)1l, (long)2l, (long)-3l)))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-4l, (long)5l, (long)6l)))) == (true)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-4l)))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-5l)))) == (true)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-2l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-4l)))) == (true)); } }
humaneval-HumanEval_160_do_algebra.json-L31
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given two array lists operator, and operand. The first array list has basic algebra operations, and // the second array list is an array array list of integers. Use the two given array lists to build the algebric // expression and return the evaluation of this expression. // The basic algebra operations: // Addition ( + ) // Subtraction ( - ) // Multiplication ( * ) // Floor division ( // ) // Exponentiation ( ** ) // Example: // operator['+', '*', '-'] // array array list = [2, 3, 4, 5] // result = 2 + 3 * 4 - 5 // => result = 9 // Note: // The length of operator array list is equal to the length of operand array list minus one. // Operand is an array array list of of non-negative integers. // Operator array list has at least one operator, and operand array list has at least two operands. public static long doAlgebra(ArrayList<String> op, ArrayList<Long> operand) { ArrayList<Long> list = new ArrayList<>(); list.add(operand.get(0)); for (int i = 0; i < op.size(); i++) {
list.add(operand.get(i + 1)); else if (op.get(i).equals("-")) list.add(-operand.get(i + 1)); else if (op.get(i).equals("*")) list.set(list.size() - 1, list.get(list.size() - 1) * operand.get(i + 1)); else if (op.get(i).equals("//")) list.set(list.size() - 1, list.get(list.size() - 1) / operand.get(i + 1)); else if (op.get(i).equals("**")) list.set(list.size() - 1, (long) Math.pow(list.get(list.size() - 1), operand.get(i + 1))); } return list.stream().mapToLong(x -> x).sum(); } }
if (op.get(i).equals("+"))
} public static void main(String[] args) { assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"**", (String)"*", (String)"+"))), (new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)5l)))) == (37l)); assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"+", (String)"*", (String)"-"))), (new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)5l)))) == (9l)); assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"//", (String)"*"))), (new ArrayList<Long>(Arrays.asList((long)7l, (long)3l, (long)4l)))) == (8l)); } }
humaneval-HumanEval_143_words_in_sentence.json-L24
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a string representing a sentence, // the sentence contains some words separated by a space, // and you have to return a string that contains the words from the original sentence, // whose lengths are prime numbers, // the order of the words in the new string should be the same as the original one. // Example 1: // >>> wordsInSentence(("This is a test")) // ("is") // Example 2: // >>> wordsInSentence(("lets go for swimming")) // ("go for") // Constraints: // * 1 <= len(sentence) <= 100 // * sentence contains only letters public static String wordsInSentence(String sentence) {
String[] words = sentence.split(" "); int[] primes = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}; boolean isPrime; for (String word : words) { isPrime = false; for (int prime : primes) { if (word.length() == prime) { isPrime = true; break; } } if (isPrime) { ans.append(word + " "); } } if (ans.length() > 0) { ans.deleteCharAt(ans.length() - 1); } return ans.toString(); } }
StringBuilder ans = new StringBuilder();
} public static void main(String[] args) { assert(wordsInSentence(("This is a test")).equals(("is"))); assert(wordsInSentence(("lets go for swimming")).equals(("go for"))); assert(wordsInSentence(("there is no place available here")).equals(("there is no place"))); assert(wordsInSentence(("Hi I am Hussein")).equals(("Hi am Hussein"))); assert(wordsInSentence(("go for it")).equals(("go for it"))); assert(wordsInSentence(("here")).equals((""))); assert(wordsInSentence(("here is")).equals(("is"))); } }
humaneval-HumanEval_10_make_palindrome.json-L18
py
def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. >>> make_palindrome('') '' >>> make_palindrome('cat') 'catac' >>> make_palindrome('cata') 'catac' """ if not string: return string prefix = string[::-1]
if string[i:] == prefix[:len(string) - i]: return string + prefix[len(string) - i:] return string
for i in range(len(string)):
def check(candidate): assert candidate('') == '' assert candidate('x') == 'x' assert candidate('xyz') == 'xyzyx' assert candidate('xyx') == 'xyx' assert candidate('jerry') == 'jerryrrej' def test_check(): check(make_palindrome) test_check()
humaneval-HumanEval_62_derivative.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // xs represent coefficients of a polynomial. // xs[0] + xs[1] * x + xs[2] * x^2 + .... // Return derivative of this polynomial in the same form. // >>> derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long)4l, (long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)12l, (long)20l))) // >>> derivative((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (new ArrayList<Long>(Arrays.asList((long)2l, (long)6l))) public static ArrayList<Long> derivative(ArrayList<Long> xs) {
for (int i = 1; i < xs.size(); i++) { ans.add(xs.get(i) * i); } return ans; } }
ArrayList<Long> ans = new ArrayList<Long>();
} public static void main(String[] args) { assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long)4l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)12l, (long)20l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)6l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l, (long)0l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)0l, (long)16l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)1l)))).equals((new ArrayList<Long>(Arrays.asList())))); } }
humaneval-HumanEval_144_simplify.json-L25
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Your task is to implement a function that will simplify the expression // x * n. The function returns true if x * n evaluates to a whole number and false // otherwise. Both x and n, are string representation of a fraction, and have the following format, // <numerator>/<denominator> where both numerator and denominator are positive whole numbers. // You can assume that x, and n are valid fractions, and do not have zero as denominator. // >>> simplify(("1/5"), ("5/1")) // (true) // >>> simplify(("1/6"), ("2/1")) // (false) // >>> simplify(("7/10"), ("10/2")) // (false) public static boolean simplify(String x, String n) { String[] nums = x.split("/"); String[] n_nums = n.split("/"); int x_num = Integer.parseInt(nums[0]); int n_num = Integer.parseInt(n_nums[0]);
int n_denom = Integer.parseInt(n_nums[1]); int res_num = x_num * n_num; int res_denom = x_denom * n_denom; return (res_num % res_denom == 0); } }
int x_denom = Integer.parseInt(nums[1]);
} public static void main(String[] args) { assert(simplify(("1/5"), ("5/1")) == (true)); assert(simplify(("1/6"), ("2/1")) == (false)); assert(simplify(("5/1"), ("3/1")) == (true)); assert(simplify(("7/10"), ("10/2")) == (false)); assert(simplify(("2/10"), ("50/10")) == (true)); assert(simplify(("7/2"), ("4/2")) == (true)); assert(simplify(("11/6"), ("6/1")) == (true)); assert(simplify(("2/3"), ("5/2")) == (false)); assert(simplify(("5/2"), ("3/5")) == (false)); assert(simplify(("2/4"), ("8/4")) == (true)); assert(simplify(("2/4"), ("4/2")) == (true)); assert(simplify(("1/5"), ("5/1")) == (true)); assert(simplify(("1/5"), ("1/5")) == (false)); } }
humaneval-HumanEval_52_below_threshold.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return true if all numbers in the array list l are below threshold t. // >>> belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)10l))), (100l)) // (true) // >>> belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l))), (5l)) // (false) public static boolean belowThreshold(ArrayList<Long> l, long t) { Long[] a = l.toArray(new Long[l.size()]); for (int i = 0; i < a.length; i++) {
return false; } } return true; } }
if (a[i] >= t) {
} public static void main(String[] args) { assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)10l))), (100l)) == (true)); assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l))), (5l)) == (false)); assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l))), (21l)) == (true)); assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l))), (22l)) == (true)); assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)8l, (long)4l, (long)10l))), (11l)) == (true)); assert(belowThreshold((new ArrayList<Long>(Arrays.asList((long)1l, (long)8l, (long)4l, (long)10l))), (10l)) == (false)); } }
humaneval-HumanEval_117_select_words.json-L50
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string s and a natural number n, you have been tasked to implement // a function that returns an array array list of all words from string s that contain exactly // n consonants, in order these words appear in the string s. // If the string s is empty then the function should return an empty array list. // Note: you may assume the input string contains only letters and spaces. // Examples: // >>> selectWords(("Mary had a little lamb"), (4l)) // (new ArrayList<String>(Arrays.asList((String)"little"))) // >>> selectWords(("Mary had a little lamb"), (3l)) // (new ArrayList<String>(Arrays.asList((String)"Mary", (String)"lamb"))) // >>> selectWords(("simple white space"), (2l)) // (new ArrayList<String>(Arrays.asList())) // >>> selectWords(("Hello world"), (4l)) // (new ArrayList<String>(Arrays.asList((String)"world"))) // >>> selectWords(("Uncle sam"), (3l)) // (new ArrayList<String>(Arrays.asList((String)"Uncle"))) public static ArrayList<String> selectWords(String s, long n) { ArrayList<String> ret = new ArrayList<String>(); String[] words = s.split(" "); for (String word : words) { String wordInLowerCase = word.toLowerCase(); long consonants = 0l; for (char c : wordInLowerCase.toCharArray()) { switch (c) { case 'a': case 'e': case 'i': case 'o': case 'u': break; default: consonants++; break; } } if (consonants == n) { ret.add(word); } } return ret; }
}
} public static void main(String[] args) { assert(selectWords(("Mary had a little lamb"), (4l)).equals((new ArrayList<String>(Arrays.asList((String)"little"))))); assert(selectWords(("Mary had a little lamb"), (3l)).equals((new ArrayList<String>(Arrays.asList((String)"Mary", (String)"lamb"))))); assert(selectWords(("simple white space"), (2l)).equals((new ArrayList<String>(Arrays.asList())))); assert(selectWords(("Hello world"), (4l)).equals((new ArrayList<String>(Arrays.asList((String)"world"))))); assert(selectWords(("Uncle sam"), (3l)).equals((new ArrayList<String>(Arrays.asList((String)"Uncle"))))); assert(selectWords((""), (4l)).equals((new ArrayList<String>(Arrays.asList())))); assert(selectWords(("a b c d e f"), (1l)).equals((new ArrayList<String>(Arrays.asList((String)"b", (String)"c", (String)"d", (String)"f"))))); } }
humaneval-HumanEval_124_valid_date.json-L43
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You have to write a function which validates a given date string and // returns true if the date is valid otherwise false. // The date is valid if all of the following rules are satisfied: // 1. The date string is not empty. // 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2. // 3. The months should not be less than 1 or higher than 12. // 4. The date should be in the format: mm-dd-yyyy // >>> validDate(("03-11-2000")) // (true) // >>> validDate(("15-01-2012")) // (false) // >>> validDate(("04-0-2040")) // (false) // >>> validDate(("06-04-2020")) // (true) // >>> validDate(("06/04/2020")) // (false) public static boolean validDate(String date) { boolean valid_date = false; if (date.equals("")) return valid_date; String[] parts = date.split("-"); if (parts.length != 3) return valid_date; try { int month = Integer.parseInt(parts[0]); int day = Integer.parseInt(parts[1]); int year = Integer.parseInt(parts[2]); if (month < 1 || month > 12) return valid_date; if (month == 2) { if (day < 1 || day > 29) return valid_date; } else if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) { if (day < 1 || day > 31) return valid_date; } else { if (day < 1 || day > 30) return valid_date; }
} catch (Exception e) { valid_date = false; } return valid_date; } }
valid_date = true;
} public static void main(String[] args) { assert(validDate(("03-11-2000")) == (true)); assert(validDate(("15-01-2012")) == (false)); assert(validDate(("04-0-2040")) == (false)); assert(validDate(("06-04-2020")) == (true)); assert(validDate(("01-01-2007")) == (true)); assert(validDate(("03-32-2011")) == (false)); assert(validDate(("")) == (false)); assert(validDate(("04-31-3000")) == (false)); assert(validDate(("06-06-2005")) == (true)); assert(validDate(("21-31-2000")) == (false)); assert(validDate(("04-12-2003")) == (true)); assert(validDate(("04122003")) == (false)); assert(validDate(("20030412")) == (false)); assert(validDate(("2003-04")) == (false)); assert(validDate(("2003-04-12")) == (false)); assert(validDate(("04-2003")) == (false)); } }
humaneval-HumanEval_121_solution.json-L19
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers, return the sum of all of the odd elements that are in even positions. // Examples // >>> solution((new ArrayList<Long>(Arrays.asList((long)5l, (long)8l, (long)7l, (long)1l)))) // (12l) // >>> solution((new ArrayList<Long>(Arrays.asList((long)3l, (long)3l, (long)3l, (long)3l, (long)3l)))) // (9l) // >>> solution((new ArrayList<Long>(Arrays.asList((long)30l, (long)13l, (long)24l, (long)321l)))) // (0l) public static long solution(ArrayList<Long> lst) { long sum = 0;
if (i % 2 == 0 && lst.get(i) % 2 == 1) { sum += lst.get(i); } } return sum; } }
for (int i = 0; i < lst.size(); i++) {
} public static void main(String[] args) { assert(solution((new ArrayList<Long>(Arrays.asList((long)5l, (long)8l, (long)7l, (long)1l)))) == (12l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)3l, (long)3l, (long)3l, (long)3l, (long)3l)))) == (9l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)30l, (long)13l, (long)24l, (long)321l)))) == (0l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)5l, (long)9l)))) == (5l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)8l)))) == (0l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)30l, (long)13l, (long)23l, (long)32l)))) == (23l)); assert(solution((new ArrayList<Long>(Arrays.asList((long)3l, (long)13l, (long)2l, (long)9l)))) == (3l)); } }
humaneval-HumanEval_107_even_odd_palindrome.json-L32
js
//Given a positive integer n, return an array that has the number of even and odd // integer palindromes that fall within the range(1, n), inclusive. // Example 1: // >>> even_odd_palindrome(3) // [1, 2] // Explanation: // Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. // Example 2: // >>> even_odd_palindrome(12) // [4, 6] // Explanation: // Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. // Note: // 1. 1 <= n <= 10^3 // 2. returned array has the number of even and odd integer palindromes respectively. function even_odd_palindrome(n){ var pal = []; var isPalindrome = function(x){ var y = x.toString().split('').reverse().join(''); return y == x; } for(var i = 1; i <= n; i++){ if(isPalindrome(i)){ pal.push(i); } } var odd = 0; var even = 0; for(var i = 0; i < pal.length; i++){ if(pal[i] % 2 == 0){ even++;
else{ odd++; } } return [even, odd]; }
}
const assert = require('node:assert'); function test() { let candidate = even_odd_palindrome; assert.deepEqual(candidate(123),[8, 13]); assert.deepEqual(candidate(12),[4, 6]); assert.deepEqual(candidate(3),[1, 2]); assert.deepEqual(candidate(63),[6, 8]); assert.deepEqual(candidate(25),[5, 6]); assert.deepEqual(candidate(19),[4, 6]); assert.deepEqual(candidate(9),[4, 5]); assert.deepEqual(candidate(1),[0, 1]); } test();
humaneval-HumanEval_46_fib4.json-L25
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1) -> 0 // fib4(2) -> 2 // fib4(3) -> 0 // fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). // Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. // >>> fib4((5l)) // (4l) // >>> fib4((6l)) // (8l) // >>> fib4((7l)) // (14l) public static long fib4(long n) { if (n == 0) return 0; if (n == 1) return 0;
if (n == 3) return 0; return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4); } }
if (n == 2) return 2;
} public static void main(String[] args) { assert(fib4((5l)) == (4l)); assert(fib4((8l)) == (28l)); assert(fib4((10l)) == (104l)); assert(fib4((12l)) == (386l)); } }
humaneval-HumanEval_15_string_sequence.json-L18
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a string containing space-delimited numbers starting from 0 upto n inclusive. // >>> stringSequence((0l)) // ("0") // >>> stringSequence((5l)) // ("0 1 2 3 4 5") public static String stringSequence(long n) { String result = ""; for (long i = 0; i <= n; i++) { result += i + " ";
return result.trim(); } }
}
} public static void main(String[] args) { assert(stringSequence((0l)).equals(("0"))); assert(stringSequence((3l)).equals(("0 1 2 3"))); assert(stringSequence((10l)).equals(("0 1 2 3 4 5 6 7 8 9 10"))); } }
humaneval-HumanEval_109_move_one_ball.json-L37
py
from typing import List def move_one_ball(arr: List[int]) -> bool: """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: You are allowed to perform right shift operation any number of times. One right shift operation means shifting all elements of the array by one position in the right direction. The last element of the array will be moved to the starting position in the array i.e. 0th index. If it is possible to obtain the sorted array by performing the above operation then return True else return False. If the given array is empty then return True. Note: The given list is guaranteed to have unique elements. For Example: >>> move_one_ball([3, 4, 5, 1, 2]) True Explanation: By performin 2 right shift operations, non-decreasing order can be achieved for the given array. >>> move_one_ball([3, 5, 4, 1, 2]) False Explanation:It is not possible to get non-decreasing order for the given array by performing any number of right shift operations. """ flag = False for i in range(1, len(arr)): if arr[i-1] > arr[i]: if flag == True: return False
elif arr[i-1] < arr[i]: flag = False return True
flag = True
def check(candidate): assert candidate([3, 4, 5, 1, 2]) == True assert candidate([3, 5, 10, 1, 2]) == True assert candidate([4, 3, 1, 2]) == False assert candidate([3, 5, 4, 1, 2]) == False assert candidate([]) == True def test_check(): check(move_one_ball) test_check()
humaneval-HumanEval_86_anti_shuffle.json-L30
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes a string and returns an ordered version of it. // Ordered version of string, is a string where all words (separated by space) // are replaced by a new word where all the characters arranged in // ascending order based on ascii value. // Note: You should keep the order of words and blank spaces in the sentence. // For example: // >>> antiShuffle(("Hi")) // ("Hi") // >>> antiShuffle(("hello")) // ("ehllo") // >>> antiShuffle(("Hello World!!!")) // ("Hello !!!Wdlor") public static String antiShuffle(String s) { StringBuilder sb = new StringBuilder(); String[] words = s.split(" "); for (String word : words) { char[] chars = word.toCharArray(); Arrays.sort(chars); sb.append(new String(chars)); sb.append(" "); }
return sb.toString(); } }
sb.deleteCharAt(sb.length() - 1);
} public static void main(String[] args) { assert(antiShuffle(("Hi")).equals(("Hi"))); assert(antiShuffle(("hello")).equals(("ehllo"))); assert(antiShuffle(("number")).equals(("bemnru"))); assert(antiShuffle(("abcd")).equals(("abcd"))); assert(antiShuffle(("Hello World!!!")).equals(("Hello !!!Wdlor"))); assert(antiShuffle(("")).equals((""))); assert(antiShuffle(("Hi. My name is Mister Robot. How are you?")).equals((".Hi My aemn is Meirst .Rboot How aer ?ouy"))); } }
humaneval-HumanEval_156_int_to_mini_roman.json-L70
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> intToMiniRoman((19l)) // ("xix") // >>> intToMiniRoman((152l)) // ("clii") // >>> intToMiniRoman((426l)) // ("cdxxvi") public static String intToMiniRoman(long number) { int num = (int) number; String res = ""; if (num == 0) return ""; while (num >= 1000) { res += "m"; num -= 1000; } if (num >= 900) { res += "cm"; num -= 900; } if (num >= 500) { res += "d"; num -= 500; } if (num >= 400) { res += "cd"; num -= 400; } while (num >= 100) { res += "c"; num -= 100; } if (num >= 90) { res += "xc"; num -= 90; } if (num >= 50) { res += "l"; num -= 50; } if (num >= 40) { res += "xl"; num -= 40; } while (num >= 10) { res += "x"; num -= 10; } if (num >= 9) { res += "ix"; num -= 9; } if (num >= 5) { res += "v"; num -= 5; } if (num >= 4) { res += "iv";
} while (num >= 1) { res += "i"; num -= 1; } return res; } }
num -= 4;
} public static void main(String[] args) { assert(intToMiniRoman((19l)).equals(("xix"))); assert(intToMiniRoman((152l)).equals(("clii"))); assert(intToMiniRoman((251l)).equals(("ccli"))); assert(intToMiniRoman((426l)).equals(("cdxxvi"))); assert(intToMiniRoman((500l)).equals(("d"))); assert(intToMiniRoman((1l)).equals(("i"))); assert(intToMiniRoman((4l)).equals(("iv"))); assert(intToMiniRoman((43l)).equals(("xliii"))); assert(intToMiniRoman((90l)).equals(("xc"))); assert(intToMiniRoman((94l)).equals(("xciv"))); assert(intToMiniRoman((532l)).equals(("dxxxii"))); assert(intToMiniRoman((900l)).equals(("cm"))); assert(intToMiniRoman((994l)).equals(("cmxciv"))); assert(intToMiniRoman((1000l)).equals(("m"))); } }
humaneval-HumanEval_79_decimal_to_binary.json-L21
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given a number in decimal form and your task is to convert it to // binary format. The function should return a string, with each character representing a binary // number. Each character in the string will be '0' or '1'. // There will be an extra couple of characters 'db' at the beginning and at the end of the string. // The extra characters are there to help with the format. // Examples: // >>> decimalToBinary((15l)) // ("db1111db") // >>> decimalToBinary((32l)) // ("db100000db") public static String decimalToBinary(long decimal) { return "db" + Long.toBinaryString(decimal) + "db";
}
}
} public static void main(String[] args) { assert(decimalToBinary((0l)).equals(("db0db"))); assert(decimalToBinary((32l)).equals(("db100000db"))); assert(decimalToBinary((103l)).equals(("db1100111db"))); assert(decimalToBinary((15l)).equals(("db1111db"))); } }
humaneval-HumanEval_158_find_max.json-L18
js
//Write a function that accepts an array of strings. // The array contains different words. Return the word with maximum number // of unique characters. If multiple strings have maximum number of unique // characters, return the one which comes first in lexicographical order. // >>> find_max(["name", "of", "string"]) // "string" // >>> find_max(["name", "enam", "game"]) // "enam" // >>> find_max(["aaaaaaa", "bb", "cc"]) // "aaaaaaa" function find_max(words){ var max_unique = {}; var max_unique_word = ""; for(var i = 0; i < words.length; i++){ var unique_word = {}; var word = words[i]; for(var j = 0; j < word.length; j++){
if(unique_word[char] === undefined){ unique_word[char] = 1; } } if(max_unique_word === ""){ max_unique_word = word; max_unique = unique_word; } else if(Object.keys(unique_word).length > Object.keys(max_unique).length){ max_unique_word = word; max_unique = unique_word; } else if(Object.keys(unique_word).length === Object.keys(max_unique).length){ if(word < max_unique_word){ max_unique_word = word; max_unique = unique_word; } } } return max_unique_word; }
var char = word[j];
const assert = require('node:assert'); function test() { let candidate = find_max; assert.deepEqual(candidate(["name", "of", "string"]),"string"); assert.deepEqual(candidate(["name", "enam", "game"]),"enam"); assert.deepEqual(candidate(["aaaaaaa", "bb", "cc"]),"aaaaaaa"); assert.deepEqual(candidate(["abc", "cba"]),"abc"); assert.deepEqual(candidate(["play", "this", "game", "of", "footbott"]),"footbott"); assert.deepEqual(candidate(["we", "are", "gonna", "rock"]),"gonna"); assert.deepEqual(candidate(["we", "are", "a", "mad", "nation"]),"nation"); assert.deepEqual(candidate(["this", "is", "a", "prrk"]),"this"); assert.deepEqual(candidate(["b"]),"b"); assert.deepEqual(candidate(["play", "play", "play"]),"play"); } test();
humaneval-HumanEval_56_correct_bracketing.json-L17
py
def correct_bracketing(brackets: str) -> bool: """ brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing('<') False >>> correct_bracketing('<>') True >>> correct_bracketing('<<><>>') True >>> correct_bracketing('><<>') False """ num_left_brackets = 0 for bracket in brackets: if bracket == '<':
elif bracket == '>': num_left_brackets -= 1 if num_left_brackets < 0: return False return num_left_brackets == 0
num_left_brackets += 1
def check(candidate): assert candidate('<>') == True assert candidate('<<><>>') == True assert candidate('<><><<><>><>') == True assert candidate('<><><<<><><>><>><<><><<>>>') == True assert candidate('<<<><>>>>') == False assert candidate('><<>') == False assert candidate('<') == False assert candidate('<<<<') == False assert candidate('>') == False assert candidate('<<>') == False assert candidate('<><><<><>><>><<>') == False assert candidate('<><><<><>><>>><>') == False def test_check(): check(correct_bracketing) test_check()
humaneval-HumanEval_109_move_one_ball.json-L23
js
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array will be randomly ordered. Your task is to determine if // it is possible to get an array sorted in non-decreasing order by performing // the following operation on the given array: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array by one // position in the right direction. The last element of the array will be moved to // the starting position in the array i.e. 0th index. // If it is possible to obtain the sorted array by performing the above operation // then return true else return false. // If the given array is empty then return true. // Note: The given array is guaranteed to have unique elements. // For Example: // >>> move_one_ball([3, 4, 5, 1, 2]) // true // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array. // >>> move_one_ball([3, 5, 4, 1, 2]) // false // Explanation:It is not possible to get non-decreasing order for the given // array by performing any number of right shift operations. function move_one_ball(arr){
var i = 0; var temp = 0; for(var i = 0; i < arr.length - 1; i++){ if(arr[i] > arr[i + 1]){ diff_count += 1; } } if(diff_count > 1){ return false; } else{ return true; } }
var diff_count = 0;
const assert = require('node:assert'); function test() { let candidate = move_one_ball; assert.deepEqual(candidate([3, 4, 5, 1, 2]),true); assert.deepEqual(candidate([3, 5, 10, 1, 2]),true); assert.deepEqual(candidate([4, 3, 1, 2]),false); assert.deepEqual(candidate([3, 5, 4, 1, 2]),false); assert.deepEqual(candidate([]),true); } test();
humaneval-HumanEval_105_by_length.json-L38
js
//Given an array of integers, sort the integers that are between 1 and 9 inclusive, // reverse the resulting array, and then replace each digit by its corresponding name from // "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". // For example: // >>> by_length([2, 1, 1, 4, 5, 8, 2, 3]) // ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] // If the array is empty, return an empty array: // >>> by_length([]) // [] // If the array has any strange number ignore it: // >>> by_length([1, -1, 55]) // ["One"] function by_length(arr){ var arr2 = []; for(var i = 0; i < arr.length; i++){ var num = arr[i]; if(num > 0 && num < 10){ arr2.push(num); } } arr2.sort(); arr2.reverse(); var arr3 = []; for(var i = 0; i < arr2.length; i++){ var num = arr2[i]; if(num == 1){ arr3.push("One"); } else if(num == 2){ arr3.push("Two"); } else if(num == 3){ arr3.push("Three"); } else if(num == 4){ arr3.push("Four"); }
arr3.push("Five"); } else if(num == 6){ arr3.push("Six"); } else if(num == 7){ arr3.push("Seven"); } else if(num == 8){ arr3.push("Eight"); } else if(num == 9){ arr3.push("Nine"); } } return arr3; }
else if(num == 5){
const assert = require('node:assert'); function test() { let candidate = by_length; assert.deepEqual(candidate([2, 1, 1, 4, 5, 8, 2, 3]),["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]); assert.deepEqual(candidate([]),[]); assert.deepEqual(candidate([1, -1, 55]),["One"]); assert.deepEqual(candidate([1, -1, 3, 2]),["Three", "Two", "One"]); assert.deepEqual(candidate([9, 4, 8]),["Nine", "Eight", "Four"]); } test();
humaneval-HumanEval_95_check_dict_case.json-L48
js
//Given an object, return true if all keys are strings in lower // case or all keys are strings in upper case, else return false. // The function should return false is the given object is empty. // Examples: // >>> check_dict_case({"a": "apple", "b": "banana"}) // true // >>> check_dict_case({"a": "apple", "A": "banana", "B": "banana"}) // false // >>> check_dict_case({"a": "apple", 8: "banana", "a": "apple"}) // false // >>> check_dict_case({"Name": "John", "Age": "36", "City": "Houston"}) // false // >>> check_dict_case({"STATE": "NC", "ZIP": "12345"}) // true function check_dict_case(dict){ if (Object.keys(dict).length == 0){ return false; } var case_type = -1; for (let key in dict){ if (typeof key == "string"){ if (case_type == -1){ if (key == key.toUpperCase()){ case_type = 1; } else if (key == key.toLowerCase()){ case_type = 0; } else{ return false; } } else if (case_type == 1){ if (key != key.toUpperCase()){ return false; } } else if (case_type == 0){ if (key != key.toLowerCase()){ return false; } } } else{ return false; } }
}
return true;
const assert = require('node:assert'); function test() { let candidate = check_dict_case; assert.deepEqual(candidate({"p": "pineapple", "b": "banana"}),true); assert.deepEqual(candidate({"p": "pineapple", "A": "banana", "B": "banana"}),false); assert.deepEqual(candidate({"p": "pineapple", "5": "banana", "a": "apple"}),false); assert.deepEqual(candidate({"Name": "John", "Age": "36", "City": "Houston"}),false); assert.deepEqual(candidate({"STATE": "NC", "ZIP": "12345"}),true); assert.deepEqual(candidate({"fruit": "Orange", "taste": "Sweet"}),true); assert.deepEqual(candidate({}),false); } test();
humaneval-HumanEval_45_triangle_area.json-L5
js
//Given length of a side and high return area for a triangle. // >>> triangle_area(5, 3) // 7.5 function triangle_area(a, h){
};
return a*h/2;
const assert = require('node:assert'); function test() { let candidate = triangle_area; assert.deepEqual(candidate(5, 3),7.5); assert.deepEqual(candidate(2, 2),2.0); assert.deepEqual(candidate(10, 8),40.0); } test();
humaneval-HumanEval_73_smallest_change.json-L15
js
//Given an array arr of integers, find the minimum number of elements that // need to be changed to make the array palindromic. A palindromic array is an array that // is read the same backwards and forwards. In one change, you can change one element to any other element. // For example: // >>> smallest_change([1, 2, 3, 5, 4, 7, 9, 6]) // 4 // >>> smallest_change([1, 2, 3, 4, 3, 2, 2]) // 1 // >>> smallest_change([1, 2, 3, 2, 1]) // 0 function smallest_change(arr){ let changes = 0; for(let i = 0; i < arr.length/2; i++){ if(arr[i] != arr[arr.length - 1 - i]){
} } return changes; }
changes++;
const assert = require('node:assert'); function test() { let candidate = smallest_change; assert.deepEqual(candidate([1, 2, 3, 5, 4, 7, 9, 6]),4); assert.deepEqual(candidate([1, 2, 3, 4, 3, 2, 2]),1); assert.deepEqual(candidate([1, 4, 2]),1); assert.deepEqual(candidate([1, 4, 4, 2]),1); assert.deepEqual(candidate([1, 2, 3, 2, 1]),0); assert.deepEqual(candidate([3, 1, 1, 3]),0); assert.deepEqual(candidate([1]),0); assert.deepEqual(candidate([0, 1]),1); } test();
humaneval-HumanEval_73_smallest_change.json-L31
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list arr of integers, find the minimum number of elements that // need to be changed to make the array array list palindromic. A palindromic array array list is an array array list that // is read the same backwards and forwards. In one change, you can change one element to any other element. // For example: // >>> smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)5l, (long)4l, (long)7l, (long)9l, (long)6l)))) // (4l) // >>> smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)3l, (long)2l, (long)2l)))) // (1l) // >>> smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)2l, (long)1l)))) // (0l) public static long smallestChange(ArrayList<Long> arr) { int first = 0; int last = arr.size() - 1; int count = 0; while (first < last) { if (arr.get(first) != arr.get(last)) { count++; } first++; last--; } return count;
}
}
} public static void main(String[] args) { assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)5l, (long)4l, (long)7l, (long)9l, (long)6l)))) == (4l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)3l, (long)2l, (long)2l)))) == (1l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)2l)))) == (1l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)4l, (long)2l)))) == (1l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)2l, (long)1l)))) == (0l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)1l, (long)3l)))) == (0l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)1l)))) == (0l)); assert(smallestChange((new ArrayList<Long>(Arrays.asList((long)0l, (long)1l)))) == (1l)); } }
humaneval-HumanEval_69_search.json-L30
js
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Examples: // >>> search([4, 1, 2, 2, 3, 1]) // 2 // >>> search([1, 2, 2, 3, 3, 3, 4, 4, 4]) // 3 // >>> search([5, 5, 4, 4, 4]) // -1 function search(lst){ var h = {}; for (var i=0; i<lst.length; i++){ var x = lst[i]; if (x in h){ h[x] += 1; } else{ h[x] = 1; } } var keys = Object.keys(h); var max = 0; for (var i=0; i<keys.length; i++){ if (keys[i] > max && h[keys[i]] >= keys[i]){ max = keys[i]; } }
return -1; } return max; }
if (max == 0){
const assert = require('node:assert'); function test() { let candidate = search; assert.deepEqual(candidate([5, 5, 5, 5, 1]),1); assert.deepEqual(candidate([4, 1, 4, 1, 4, 4]),4); assert.deepEqual(candidate([3, 3]),-1); assert.deepEqual(candidate([8, 8, 8, 8, 8, 8, 8, 8]),8); assert.deepEqual(candidate([2, 3, 3, 2, 2]),2); assert.deepEqual(candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]),1); assert.deepEqual(candidate([3, 2, 8, 2]),2); assert.deepEqual(candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]),1); assert.deepEqual(candidate([8, 8, 3, 6, 5, 6, 4]),-1); assert.deepEqual(candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]),1); assert.deepEqual(candidate([1, 9, 10, 1, 3]),1); assert.deepEqual(candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]),5); assert.deepEqual(candidate([1]),1); assert.deepEqual(candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]),4); assert.deepEqual(candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]),2); assert.deepEqual(candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]),1); assert.deepEqual(candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]),4); assert.deepEqual(candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]),4); assert.deepEqual(candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]),2); assert.deepEqual(candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]),-1); assert.deepEqual(candidate([10]),-1); assert.deepEqual(candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]),2); assert.deepEqual(candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]),1); assert.deepEqual(candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]),1); assert.deepEqual(candidate([3, 10, 10, 9, 2]),-1); } test();
humaneval-HumanEval_140_fix_spaces.json-L13
js
//Given a string text, replace all spaces in it with underscores, // and if a string has more than 2 consecutive spaces, // then replace all consecutive spaces with - // >>> fix_spaces(" Example") // "Example" // >>> fix_spaces(" Example 1") // "Example_1" // >>> fix_spaces(" Example 2") // "_Example_2" // >>> fix_spaces(" Example 3") // "_Example-3" function fix_spaces(text){
var k = n.replace(/___/g, "-"); return k; }
var n = text.replace(/\s/g, "_");
const assert = require('node:assert'); function test() { let candidate = fix_spaces; assert.deepEqual(candidate("Example"),"Example"); assert.deepEqual(candidate("Mudasir Hanif "),"Mudasir_Hanif_"); assert.deepEqual(candidate("Yellow Yellow Dirty Fellow"),"Yellow_Yellow__Dirty__Fellow"); assert.deepEqual(candidate("Exa mple"),"Exa-mple"); assert.deepEqual(candidate(" Exa 1 2 2 mple"),"-Exa_1_2_2_mple"); } test();
humaneval-HumanEval_126_is_sorted.json-L49
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 duplicate of the same // number, return false. Assume no negative numbers and only integers. // Examples // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) // (false) public static boolean isSorted(ArrayList<Long> lst) { if (lst.size() == 0) { return true; } else { int running_max = 0; int previous_number = 0; boolean first_time = true; boolean seen_2_in_a_row = false; for (Long number : lst) { if (first_time) { first_time = false; previous_number = number.intValue(); running_max = number.intValue(); } else { if (running_max > number.intValue()) { return false; } else {
if (seen_2_in_a_row) { return false; } else { seen_2_in_a_row = true; } } else { seen_2_in_a_row = false; } previous_number = number.intValue(); running_max = number.intValue(); } } } return true; } } }
if (previous_number == number.intValue()) {
} public static void main(String[] args) { assert(isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList()))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)3l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))) == (true)); } }
humaneval-HumanEval_113_odd_count.json-L18
js
//Given an array of strings, where each string consists of only digits, return an array. // Each element i of the output should be "the number of odd elements in the // string i of the input." where all the i's should be replaced by the number // of odd digits in the i'th string of the input. // >>> odd_count(["1234567"]) // ["the number of odd elements 4n the str4ng 4 of the 4nput."] // >>> odd_count(["3", "11111111"]) // ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."] function odd_count(lst){ var new_lst = []; for (var i = 0; i < lst.length; i++){ var word = lst[i]; var odd_sum = 0; for (var j = 0; j < word.length; j++){ if (word[j] % 2 == 1){ odd_sum += 1; }
var odd_word = "the number of odd elements " + odd_sum + "n the str" + odd_sum + "ng " + odd_sum + " of the " + odd_sum + "nput."; new_lst.push(odd_word); } return new_lst; }
}
const assert = require('node:assert'); function test() { let candidate = odd_count; assert.deepEqual(candidate(["1234567"]),["the number of odd elements 4n the str4ng 4 of the 4nput."]); assert.deepEqual(candidate(["3", "11111111"]),["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]); assert.deepEqual(candidate(["271", "137", "314"]),["the number of odd elements 2n the str2ng 2 of the 2nput.", "the number of odd elements 3n the str3ng 3 of the 3nput.", "the number of odd elements 2n the str2ng 2 of the 2nput."]); } test();
humaneval-HumanEval_78_hex_key.json-L32
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You have been tasked to write a function that receives // a hexadecimal number as a string and counts the number of hexadecimal // digits that are primes (prime number, or a prime, is a natural number // greater than 1 that is not a product of two smaller natural numbers). // Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. // Prime numbers are 2, 3, 5, 7, 11, 13, 17,... // So you have to determine a number of the following digits: 2, 3, 5, 7, // B (=decimal 11), D (=decimal 13). // Note: you may assume the input is always correct or empty string, // and symbols A,B,C,D,E,F are always uppercase. // Examples: // >>> hexKey(("AB")) // (1l) // >>> hexKey(("1077E")) // (2l) // >>> hexKey(("ABED1A33")) // (4l) // >>> hexKey(("123456789ABCDEF0")) // (6l) // >>> hexKey(("2020")) // (2l) public static long hexKey(String num) { long result = 0;
if (num.charAt(i) == '2' || num.charAt(i) == '3' || num.charAt(i) == '5' || num.charAt(i) == '7' || num.charAt(i) == 'B' || num.charAt(i) == 'D') { result++; } } return result; } }
for (int i = 0; i < num.length(); i++) {
} public static void main(String[] args) { assert(hexKey(("AB")) == (1l)); assert(hexKey(("1077E")) == (2l)); assert(hexKey(("ABED1A33")) == (4l)); assert(hexKey(("2020")) == (2l)); assert(hexKey(("123456789ABCDEF0")) == (6l)); assert(hexKey(("112233445566778899AABBCCDDEEFF00")) == (12l)); } }
humaneval-HumanEval_64_vowels_count.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function vowels_count which takes a string representing // a word as input and returns the number of vowels in the string. // Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a // vowel, but only when it is at the end of the given word. // Example: // >>> vowelsCount(("abcde")) // (2l) // >>> vowelsCount(("ACEDY")) // (3l) public static long vowelsCount(String s) { long sum = 0; String sUpper = s.toUpperCase(); int lastIndex = sUpper.length() - 1;
if (sUpper.charAt(i) == 'A' || sUpper.charAt(i) == 'E' || sUpper.charAt(i) == 'I' || sUpper.charAt(i) == 'O' || sUpper.charAt(i) == 'U') { sum++; } if (sUpper.charAt(i) == 'Y' && i == lastIndex) { sum++; } } return sum; } }
for (int i = 0; i < sUpper.length(); i++) {
} public static void main(String[] args) { assert(vowelsCount(("abcde")) == (2l)); assert(vowelsCount(("Alone")) == (3l)); assert(vowelsCount(("key")) == (2l)); assert(vowelsCount(("bye")) == (1l)); assert(vowelsCount(("keY")) == (2l)); assert(vowelsCount(("bYe")) == (1l)); assert(vowelsCount(("ACEDY")) == (3l)); } }
humaneval-HumanEval_110_exchange.json-L30
js
//In this problem, you will implement a function that takes two arrays of numbers, // and determines whether it is possible to perform an exchange of elements // between them to make lst1 an array of only even numbers. // There is no limit on the number of exchanged elements between lst1 and lst2. // If it is possible to exchange elements between the lst1 and lst2 to make // all the elements of lst1 to be even, return "YES". // Otherwise, return "NO". // For example: // >>> exchange([1, 2, 3, 4], [1, 2, 3, 4]) // "YES" // >>> exchange([1, 2, 3, 4], [1, 5, 3, 4]) // "NO" // It is assumed that the input arrays will be non-empty. function exchange(lst1, lst2){ var num1 = 0; var num2 = 0; var exchange = true; while(num1 < lst1.length && exchange){ if(lst1[num1] % 2 !== 0){ exchange = false; if(num2 < lst2.length){ while(num2 < lst2.length && exchange == false){ if(lst2[num2] % 2 == 0){ lst1[num1] = lst2[num2]; exchange = true; } num2++; } }
num1++; } if(exchange){ return "YES"; }else{ return "NO"; } }
}
const assert = require('node:assert'); function test() { let candidate = exchange; assert.deepEqual(candidate([1, 2, 3, 4], [1, 2, 3, 4]),"YES"); assert.deepEqual(candidate([1, 2, 3, 4], [1, 5, 3, 4]),"NO"); assert.deepEqual(candidate([1, 2, 3, 4], [2, 1, 4, 3]),"YES"); assert.deepEqual(candidate([5, 7, 3], [2, 6, 4]),"YES"); assert.deepEqual(candidate([5, 7, 3], [2, 6, 3]),"NO"); assert.deepEqual(candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]),"NO"); assert.deepEqual(candidate([100, 200], [200, 200]),"YES"); } test();
humaneval-HumanEval_142_sum_squares.json-L15
js
//" // This function will take an array of integers. For all entries in the array, the function shall square the integer entry if its index is a // multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not // change the entries in the array whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. // Examples: // >>> lst // [1, 2, 3] // >>> lst // [] // >>> lst // [-1, -5, 2, -1, -5] function sum_squares(lst){ var sum = 0; var len = lst.length;
if (i % 3 == 0){ sum += lst[i]*lst[i]; } else if (i % 4 == 0){ sum += lst[i]*lst[i]*lst[i]; } else { sum += lst[i]; } } return sum; }
for (var i = 0; i < len; i++){
const assert = require('node:assert'); function test() { let candidate = sum_squares; assert.deepEqual(candidate([1, 2, 3]),6); assert.deepEqual(candidate([1, 4, 9]),14); assert.deepEqual(candidate([]),0); assert.deepEqual(candidate([1, 1, 1, 1, 1, 1, 1, 1, 1]),9); assert.deepEqual(candidate([-1, -1, -1, -1, -1, -1, -1, -1, -1]),-3); assert.deepEqual(candidate([0]),0); assert.deepEqual(candidate([-1, -5, 2, -1, -5]),-126); assert.deepEqual(candidate([-56, -99, 1, 0, -2]),3030); assert.deepEqual(candidate([-1, 0, 0, 0, 0, 0, 0, 0, -1]),0); assert.deepEqual(candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]),-14196); assert.deepEqual(candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]),-1448); } test();
humaneval-HumanEval_138_is_equal_to_sum_even.json-L27
js
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> is_equal_to_sum_even(4) // false // >>> is_equal_to_sum_even(6) // false // >>> is_equal_to_sum_even(8) // true function is_equal_to_sum_even(n){ let m =0; for(let i=2;i<n;i+=2){ for(let j=2;j<n;j+=2){ for(let k=2;k<n;k+=2){ for(let l=2;l<n;l+=2){ if((i+j+k+l)==n){ m=1; break; } } } } } if(m==1){ return true; } else{
} }
return false;
const assert = require('node:assert'); function test() { let candidate = is_equal_to_sum_even; assert.deepEqual(candidate(4),false); assert.deepEqual(candidate(6),false); assert.deepEqual(candidate(8),true); assert.deepEqual(candidate(10),true); assert.deepEqual(candidate(11),false); assert.deepEqual(candidate(12),true); assert.deepEqual(candidate(13),false); assert.deepEqual(candidate(16),true); } test();
humaneval-HumanEval_41_car_race_collision.json-L19
py
def car_race_collision(n: int) -> int: """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions. """ l = n * n count = 0 left_cars = [i for i in range(l)] right_cars = [i for i in range(l)] for i in range(l): for j in range(l):
count += 1 return count
if left_cars[i] == right_cars[j]:
def check(candidate): assert candidate(2) == 4 assert candidate(3) == 9 assert candidate(4) == 16 assert candidate(8) == 64 assert candidate(10) == 100 def test_check(): check(car_race_collision) test_check()
humaneval-HumanEval_117_select_words.json-L28
py
from typing import List def select_words(s: str, n: int) -> List[str]: """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. Examples: >>> select_words('Mary had a little lamb', 4) ['little'] >>> select_words('Mary had a little lamb', 3) ['Mary', 'lamb'] >>> select_words('simple white space', 2) [] >>> select_words('Hello world', 4) ['world'] >>> select_words('Uncle sam', 3) ['Uncle'] """ CONSONANTS = 'bcdfghjklmnpqrstvwxyz' words = s.split() result = [] for word in words: count = 0 for char in word: if char.lower() in CONSONANTS:
if count == n: result.append(word) return result
count += 1
def check(candidate): assert candidate('Mary had a little lamb', 4) == ['little'] assert candidate('Mary had a little lamb', 3) == ['Mary', 'lamb'] assert candidate('simple white space', 2) == [] assert candidate('Hello world', 4) == ['world'] assert candidate('Uncle sam', 3) == ['Uncle'] assert candidate('', 4) == [] assert candidate('a b c d e f', 1) == ['b', 'c', 'd', 'f'] def test_check(): check(select_words) test_check()
humaneval-HumanEval_105_by_length.json-L26
js
//Given an array of integers, sort the integers that are between 1 and 9 inclusive, // reverse the resulting array, and then replace each digit by its corresponding name from // "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". // For example: // >>> by_length([2, 1, 1, 4, 5, 8, 2, 3]) // ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] // If the array is empty, return an empty array: // >>> by_length([]) // [] // If the array has any strange number ignore it: // >>> by_length([1, -1, 55]) // ["One"] function by_length(arr){ var arr2 = []; for(var i = 0; i < arr.length; i++){ var num = arr[i]; if(num > 0 && num < 10){ arr2.push(num); } } arr2.sort(); arr2.reverse(); var arr3 = []; for(var i = 0; i < arr2.length; i++){ var num = arr2[i];
arr3.push("One"); } else if(num == 2){ arr3.push("Two"); } else if(num == 3){ arr3.push("Three"); } else if(num == 4){ arr3.push("Four"); } else if(num == 5){ arr3.push("Five"); } else if(num == 6){ arr3.push("Six"); } else if(num == 7){ arr3.push("Seven"); } else if(num == 8){ arr3.push("Eight"); } else if(num == 9){ arr3.push("Nine"); } } return arr3; }
if(num == 1){
const assert = require('node:assert'); function test() { let candidate = by_length; assert.deepEqual(candidate([2, 1, 1, 4, 5, 8, 2, 3]),["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]); assert.deepEqual(candidate([]),[]); assert.deepEqual(candidate([1, -1, 55]),["One"]); assert.deepEqual(candidate([1, -1, 3, 2]),["Three", "Two", "One"]); assert.deepEqual(candidate([9, 4, 8]),["Nine", "Eight", "Four"]); } test();
humaneval-HumanEval_86_anti_shuffle.json-L27
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes a string and returns an ordered version of it. // Ordered version of string, is a string where all words (separated by space) // are replaced by a new word where all the characters arranged in // ascending order based on ascii value. // Note: You should keep the order of words and blank spaces in the sentence. // For example: // >>> antiShuffle(("Hi")) // ("Hi") // >>> antiShuffle(("hello")) // ("ehllo") // >>> antiShuffle(("Hello World!!!")) // ("Hello !!!Wdlor") public static String antiShuffle(String s) { StringBuilder sb = new StringBuilder(); String[] words = s.split(" "); for (String word : words) { char[] chars = word.toCharArray(); Arrays.sort(chars);
sb.append(" "); } sb.deleteCharAt(sb.length() - 1); return sb.toString(); } }
sb.append(new String(chars));
} public static void main(String[] args) { assert(antiShuffle(("Hi")).equals(("Hi"))); assert(antiShuffle(("hello")).equals(("ehllo"))); assert(antiShuffle(("number")).equals(("bemnru"))); assert(antiShuffle(("abcd")).equals(("abcd"))); assert(antiShuffle(("Hello World!!!")).equals(("Hello !!!Wdlor"))); assert(antiShuffle(("")).equals((""))); assert(antiShuffle(("Hi. My name is Mister Robot. How are you?")).equals((".Hi My aemn is Meirst .Rboot How aer ?ouy"))); } }
humaneval-HumanEval_93_encode.json-L17
js
//Write a function that takes a message, and encodes in such a // way that it swaps case of all letters, replaces all vowels in // the message with the letter that appears 2 places ahead of that // vowel in the english alphabet. // Assume only letters. // Examples: // >>> encode("test") // "TGST" // >>> encode("This is a message") // "tHKS KS C MGSSCGG" function encode(message){ const vowels = "aeiou"; let result = ""; for(let i = 0; i < message.length; i++){ let letter = message[i]; if(vowels.includes(letter.toLowerCase())){
letter = String.fromCharCode(newIndex + (letter.toLowerCase() === letter ? 'a'.charCodeAt(0) : 'A'.charCodeAt(0))); } result += letter.toUpperCase() === letter ? letter.toLowerCase() : letter.toUpperCase(); } return result; }
let newIndex = (letter.charCodeAt(0) + 2 - (letter.toLowerCase() === letter ? 'a'.charCodeAt(0) : 'A'.charCodeAt(0))) % 26;
const assert = require('node:assert'); function test() { let candidate = encode; assert.deepEqual(candidate("TEST"),"tgst"); assert.deepEqual(candidate("Mudasir"),"mWDCSKR"); assert.deepEqual(candidate("YES"),"ygs"); assert.deepEqual(candidate("This is a message"),"tHKS KS C MGSSCGG"); assert.deepEqual(candidate("I DoNt KnOw WhAt tO WrItE"),"k dQnT kNqW wHcT Tq wRkTg"); } test();
humaneval-HumanEval_39_prime_fib.json-L16
js
//prime_fib returns n-th number that is a Fibonacci number and it's also prime. // >>> prime_fib(1) // 2 // >>> prime_fib(2) // 3 // >>> prime_fib(3) // 5 // >>> prime_fib(4) // 13 // >>> prime_fib(5) // 89 function prime_fib(n){ function isPrime(number){ if(number <= 3){ return number > 1;
else if(number % 2 == 0 || number % 3 == 0){ return false; } else{ for(var i = 5; i * i <= number; i += 6){ if(number % i == 0 || number % (i + 2) == 0){ return false; } } return true; } } function fib(num){ var a = 1, b = 0, temp; while (num >= 0){ temp = a; a = a + b; b = temp; num--; } return b; } var res = 0; var fibNum = 0; while(res < n){ if(isPrime(fib(fibNum))){ res++; } fibNum++; } return fib(fibNum - 1); }
}
const assert = require('node:assert'); function test() { let candidate = prime_fib; assert.deepEqual(candidate(1),2); assert.deepEqual(candidate(2),3); assert.deepEqual(candidate(3),5); assert.deepEqual(candidate(4),13); assert.deepEqual(candidate(5),89); assert.deepEqual(candidate(6),233); assert.deepEqual(candidate(7),1597); assert.deepEqual(candidate(8),28657); assert.deepEqual(candidate(9),514229); assert.deepEqual(candidate(10),433494437); } test();
humaneval-HumanEval_135_can_arrange.json-L18
py
from typing import List def can_arrange(arr: List[int]) -> int: """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: >>> can_arrange([1, 2, 4, 3, 5]) 3 >>> can_arrange([1, 2, 3]) -1 """ ans = -1 for i in range(len(arr)): if i != 0 and arr[i] < arr[i - 1]:
return ans
ans = i
def check(candidate): assert candidate([1, 2, 4, 3, 5]) == 3 assert candidate([1, 2, 4, 5]) == -1 assert candidate([1, 4, 2, 5, 6, 7, 8, 9, 10]) == 2 assert candidate([4, 8, 5, 7, 3]) == 4 assert candidate([]) == -1 def test_check(): check(can_arrange) test_check()
humaneval-HumanEval_109_move_one_ball.json-L35
js
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array will be randomly ordered. Your task is to determine if // it is possible to get an array sorted in non-decreasing order by performing // the following operation on the given array: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array by one // position in the right direction. The last element of the array will be moved to // the starting position in the array i.e. 0th index. // If it is possible to obtain the sorted array by performing the above operation // then return true else return false. // If the given array is empty then return true. // Note: The given array is guaranteed to have unique elements. // For Example: // >>> move_one_ball([3, 4, 5, 1, 2]) // true // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array. // >>> move_one_ball([3, 5, 4, 1, 2]) // false // Explanation:It is not possible to get non-decreasing order for the given // array by performing any number of right shift operations. function move_one_ball(arr){ var diff_count = 0; var i = 0; var temp = 0; for(var i = 0; i < arr.length - 1; i++){ if(arr[i] > arr[i + 1]){ diff_count += 1; } } if(diff_count > 1){ return false; } else{
} }
return true;
const assert = require('node:assert'); function test() { let candidate = move_one_ball; assert.deepEqual(candidate([3, 4, 5, 1, 2]),true); assert.deepEqual(candidate([3, 5, 10, 1, 2]),true); assert.deepEqual(candidate([4, 3, 1, 2]),false); assert.deepEqual(candidate([3, 5, 4, 1, 2]),false); assert.deepEqual(candidate([]),true); } test();
humaneval-HumanEval_117_select_words.json-L30
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string s and a natural number n, you have been tasked to implement // a function that returns an array array list of all words from string s that contain exactly // n consonants, in order these words appear in the string s. // If the string s is empty then the function should return an empty array list. // Note: you may assume the input string contains only letters and spaces. // Examples: // >>> selectWords(("Mary had a little lamb"), (4l)) // (new ArrayList<String>(Arrays.asList((String)"little"))) // >>> selectWords(("Mary had a little lamb"), (3l)) // (new ArrayList<String>(Arrays.asList((String)"Mary", (String)"lamb"))) // >>> selectWords(("simple white space"), (2l)) // (new ArrayList<String>(Arrays.asList())) // >>> selectWords(("Hello world"), (4l)) // (new ArrayList<String>(Arrays.asList((String)"world"))) // >>> selectWords(("Uncle sam"), (3l)) // (new ArrayList<String>(Arrays.asList((String)"Uncle"))) public static ArrayList<String> selectWords(String s, long n) { ArrayList<String> ret = new ArrayList<String>(); String[] words = s.split(" "); for (String word : words) { String wordInLowerCase = word.toLowerCase();
for (char c : wordInLowerCase.toCharArray()) { switch (c) { case 'a': case 'e': case 'i': case 'o': case 'u': break; default: consonants++; break; } } if (consonants == n) { ret.add(word); } } return ret; } }
long consonants = 0l;
} public static void main(String[] args) { assert(selectWords(("Mary had a little lamb"), (4l)).equals((new ArrayList<String>(Arrays.asList((String)"little"))))); assert(selectWords(("Mary had a little lamb"), (3l)).equals((new ArrayList<String>(Arrays.asList((String)"Mary", (String)"lamb"))))); assert(selectWords(("simple white space"), (2l)).equals((new ArrayList<String>(Arrays.asList())))); assert(selectWords(("Hello world"), (4l)).equals((new ArrayList<String>(Arrays.asList((String)"world"))))); assert(selectWords(("Uncle sam"), (3l)).equals((new ArrayList<String>(Arrays.asList((String)"Uncle"))))); assert(selectWords((""), (4l)).equals((new ArrayList<String>(Arrays.asList())))); assert(selectWords(("a b c d e f"), (1l)).equals((new ArrayList<String>(Arrays.asList((String)"b", (String)"c", (String)"d", (String)"f"))))); } }
humaneval-HumanEval_76_is_simple_power.json-L27
js
//Your task is to write a function that returns true if a number x is a simple // power of n and false in other cases. // x is a simple power of n if n**int=x // For example: // >>> is_simple_power(1, 4) // true // >>> is_simple_power(2, 2) // true // >>> is_simple_power(8, 2) // true // >>> is_simple_power(3, 2) // false // >>> is_simple_power(3, 1) // false // >>> is_simple_power(5, 3) // false function is_simple_power(x, n){ if(x===1){ return true; } if(x < n){ return false; } if(x % n !== 0){ return false; }
}
return is_simple_power(x/n, n);
const assert = require('node:assert'); function test() { let candidate = is_simple_power; assert.deepEqual(candidate(16, 2),true); assert.deepEqual(candidate(143214, 16),false); assert.deepEqual(candidate(4, 2),true); assert.deepEqual(candidate(9, 3),true); assert.deepEqual(candidate(16, 4),true); assert.deepEqual(candidate(24, 2),false); assert.deepEqual(candidate(128, 4),false); assert.deepEqual(candidate(12, 6),false); assert.deepEqual(candidate(1, 1),true); assert.deepEqual(candidate(1, 12),true); } test();
humaneval-HumanEval_134_check_if_last_char_is_a_letter.json-L32
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function that returns true if the last character // of a given string is an alphabetical character and is not // a part of a word, and false otherwise. // Note: "word" is a group of characters separated by space. // Examples: // >>> checkIfLastCharIsALetter(("apple pie")) // (false) // >>> checkIfLastCharIsALetter(("apple pi e")) // (true) // >>> checkIfLastCharIsALetter(("apple pi e ")) // (false) // >>> checkIfLastCharIsALetter(("")) // (false) public static boolean checkIfLastCharIsALetter(String txt) { if (txt.length() == 0) { return false; } int len = txt.length(); if (txt.substring(len - 1, len).matches("[A-Z]") || txt.substring(len - 1, len).matches("[a-z]")) { if (len == 1) { return true; } if (txt.substring(len - 2, len - 1).matches(" ")) {
} } return false; } }
return true;
} public static void main(String[] args) { assert(checkIfLastCharIsALetter(("apple")) == (false)); assert(checkIfLastCharIsALetter(("apple pi e")) == (true)); assert(checkIfLastCharIsALetter(("eeeee")) == (false)); assert(checkIfLastCharIsALetter(("A")) == (true)); assert(checkIfLastCharIsALetter(("Pumpkin pie ")) == (false)); assert(checkIfLastCharIsALetter(("Pumpkin pie 1")) == (false)); assert(checkIfLastCharIsALetter(("")) == (false)); assert(checkIfLastCharIsALetter(("eeeee e ")) == (false)); assert(checkIfLastCharIsALetter(("apple pie")) == (false)); assert(checkIfLastCharIsALetter(("apple pi e ")) == (false)); } }
humaneval-HumanEval_99_closest_integer.json-L25
js
//Create a function that takes a value (string) representing a number // and returns the closest integer to it. If the number is equidistant // from two integers, round it away from zero. // Examples // >>> closest_integer("10") // 10 // >>> closest_integer("15.3") // 15 // Note: // Rounding away from zero means that if the given number is equidistant // from two integers, the one you should return is the one that is the // farthest from zero. For example closest_integer("14.5") should // return 15 and closest_integer("-14.5") should return -15. function closest_integer(value){ value = parseFloat(value); if(value > 0){ if(value - Math.floor(value) < 0.5){ return Math.floor(value); }else{ return Math.ceil(value); } }else{ if(value - Math.floor(value) > -0.5){ return Math.floor(value);
return Math.ceil(value); } } }
}else{
const assert = require('node:assert'); function test() { let candidate = closest_integer; assert.deepEqual(candidate("10"),10); assert.deepEqual(candidate("14.5"),15); assert.deepEqual(candidate("-15.5"),-16); assert.deepEqual(candidate("15.3"),15); assert.deepEqual(candidate("0"),0); } test();
humaneval-HumanEval_149_sorted_list_sum.json-L19
js
//Write a function that accepts an array of strings as a parameter, // deletes the strings that have odd lengths from it, // and returns the resulted array with a sorted order, // The array is always an array of strings and never an array of numbers, // and it may contain duplicates. // The order of the array should be ascending by length of each word, and you // should return the array sorted by that rule. // If two words have the same length, sort the array alphabetically. // The function should return an array of strings in sorted order. // You may assume that all words will have the same length. // For example: // >>> list_sort(["aa", "a", "aaa"]) // ["aa"] // >>> list_sort(["ab", "a", "aaa", "cd"]) // ["ab", "cd"] function sorted_list_sum(lst){ var result = []; for(var i = 0; i < lst.length; i++){
result.push(lst[i]); } } return result.sort(function(a, b){ if(a.length < b.length){ return -1; } else if(a.length > b.length){ return 1; } else{ if(a < b){ return -1; } else if(a > b){ return 1; } else{ return 0; } } }); } var a = ["aa", "a", "aaa"]; var b = ["ab", "a", "aaa", "cd"];
if(lst[i].length % 2 == 0){
const assert = require('node:assert'); function test() { let candidate = sorted_list_sum; assert.deepEqual(candidate(["aa", "a", "aaa"]),["aa"]); assert.deepEqual(candidate(["school", "AI", "asdf", "b"]),["AI", "asdf", "school"]); assert.deepEqual(candidate(["d", "b", "c", "a"]),[]); assert.deepEqual(candidate(["d", "dcba", "abcd", "a"]),["abcd", "dcba"]); assert.deepEqual(candidate(["AI", "ai", "au"]),["AI", "ai", "au"]); assert.deepEqual(candidate(["a", "b", "b", "c", "c", "a"]),[]); assert.deepEqual(candidate(["aaaa", "bbbb", "dd", "cc"]),["cc", "dd", "aaaa", "bbbb"]); } test();
humaneval-HumanEval_142_sum_squares.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // " // This function will take an array array list of integers. For all entries in the array list, the function shall square the integer entry if its index is a // multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not // change the entries in the array list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. // Examples: // >>> lst // (long)new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)) // >>> lst // (long)new ArrayList<Long>(Arrays.asList()) // >>> lst // (long)new ArrayList<Long>(Arrays.asList((long)-1l, (long)-5l, (long)2l, (long)-1l, (long)-5l)) public static long sumSquares(ArrayList<Long> lst) { int sz = lst.size(); for (int i = 0; i < sz; i++) { if (i % 3 == 0) { lst.set(i, lst.get(i) * lst.get(i)); } else if (i % 4 == 0) { lst.set(i, lst.get(i) * lst.get(i) * lst.get(i)); } } long ans = 0; for (int i = 0; i < sz; i++) { ans += lst.get(i); } return ans;
}
}
} public static void main(String[] args) { assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) == (6l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)9l)))) == (14l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList()))) == (0l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)1l, (long)1l, (long)1l, (long)1l, (long)1l, (long)1l, (long)1l, (long)1l, (long)1l)))) == (9l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-1l, (long)-1l, (long)-1l, (long)-1l, (long)-1l, (long)-1l, (long)-1l, (long)-1l)))) == (-3l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)0l)))) == (0l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-5l, (long)2l, (long)-1l, (long)-5l)))) == (-126l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-56l, (long)-99l, (long)1l, (long)0l, (long)-2l)))) == (3030l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-1l, (long)0l, (long)0l, (long)0l, (long)0l, (long)0l, (long)0l, (long)0l, (long)-1l)))) == (0l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-16l, (long)-9l, (long)-2l, (long)36l, (long)36l, (long)26l, (long)-20l, (long)25l, (long)-40l, (long)20l, (long)-4l, (long)12l, (long)-26l, (long)35l, (long)37l)))) == (-14196l)); assert(sumSquares((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-3l, (long)17l, (long)-1l, (long)-15l, (long)13l, (long)-1l, (long)14l, (long)-14l, (long)-12l, (long)-5l, (long)14l, (long)-14l, (long)6l, (long)13l, (long)11l, (long)16l, (long)16l, (long)4l, (long)10l)))) == (-1448l)); } }
humaneval-HumanEval_91_is_bored.json-L18
py
def is_bored(S: str) -> int: """ You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'. For example: >>> is_bored('Hello world') 0 >>> is_bored('The sky is blue. The sun is shining. I love this weather') 1 """ boredoms = 0 sentences = S.split('.') for sentence in sentences: words = sentence.split() if words and words[0] == 'I':
return boredoms
boredoms += 1
def check(candidate): assert candidate('Hello world') == 0 assert candidate('Is the sky blue?') == 0 assert candidate('I love It !') == 1 assert candidate('bIt') == 0 assert candidate('I feel good today. I will be productive. will kill It') == 2 assert candidate('You and I are going for a walk') == 0 def test_check(): check(is_bored) test_check()
humaneval-HumanEval_11_string_xor.json-L14
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input are two strings a and b consisting only of 1s and 0s. // Perform binary XOR on these inputs and return result also as a string. // >>> stringXor(("010"), ("110")) // ("100") public static String stringXor(String a, String b) {
for (int i = 0; i < a.length(); i++) { c.append(a.charAt(i) ^ b.charAt(i)); } return c.toString(); } }
StringBuilder c = new StringBuilder();
} public static void main(String[] args) { assert(stringXor(("111000"), ("101010")).equals(("010010"))); assert(stringXor(("1"), ("1")).equals(("0"))); assert(stringXor(("0101"), ("0000")).equals(("0101"))); } }
humaneval-HumanEval_102_choose_num.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // This function takes two positive numbers x and y and returns the // biggest even integer number that is in the range [x, y] inclusive. If // there's no such number, then the function should return -1. // For example: // >>> chooseNum((12l), (15l)) // (14l) // >>> chooseNum((13l), (12l)) // (-1l) public static long chooseNum(long x, long y) { long chosen = -1; for (long i = x; i <= y; i++) { if (i % 2 == 0) { chosen = i;
} return chosen; } }
}
} public static void main(String[] args) { assert(chooseNum((12l), (15l)) == (14l)); assert(chooseNum((13l), (12l)) == (-1l)); assert(chooseNum((33l), (12354l)) == (12354l)); assert(chooseNum((5234l), (5233l)) == (-1l)); assert(chooseNum((6l), (29l)) == (28l)); assert(chooseNum((27l), (10l)) == (-1l)); assert(chooseNum((7l), (7l)) == (-1l)); assert(chooseNum((546l), (546l)) == (546l)); } }
humaneval-HumanEval_33_sort_third.json-L20
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // This function takes an array array list l and returns an array array list l' such that // l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal // to the values of the corresponding indicies of l, but sorted. // >>> sortThird((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l))) // >>> sortThird((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)2l)))) // (new ArrayList<Long>(Arrays.asList((long)2l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)5l))) public static ArrayList<Long> sortThird(ArrayList<Long> l) { ArrayList<Long> l_r = new ArrayList<Long>(); ArrayList<Long> l_e = new ArrayList<Long>(); ArrayList<Long> l_s = new ArrayList<Long>();
if (i % 3 == 0) { l_e.add(l.get(i)); } else { l_r.add(l.get(i)); } } for (int i = 0; i < l_e.size(); i++) { long min = l_e.get(i); for (int j = i; j < l_e.size(); j++) { if (l_e.get(j) < min) { min = l_e.get(j); l_e.set(j, l_e.get(i)); l_e.set(i, min); } } } int j = 0; for (int i = 0; i < l.size(); i++) { if (i % 3 == 0) { l_s.add(l_e.get(j)); j++; } else { l_s.add(l_r.get(i - j)); } } return l_s; } }
for (int i = 0; i < l.size(); i++) {
} public static void main(String[] args) { assert(sortThird((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)2l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)5l))))); assert(sortThird((new ArrayList<Long>(Arrays.asList((long)5l, (long)8l, (long)3l, (long)4l, (long)6l, (long)9l, (long)2l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)8l, (long)3l, (long)4l, (long)6l, (long)9l, (long)5l))))); assert(sortThird((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)9l, (long)4l, (long)8l, (long)3l, (long)2l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)6l, (long)9l, (long)4l, (long)8l, (long)3l, (long)5l))))); assert(sortThird((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)2l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)6l, (long)3l, (long)4l, (long)8l, (long)9l, (long)5l, (long)1l))))); } }
humaneval-HumanEval_85_add.json-L18
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add((new ArrayList<Long>(Arrays.asList((long)4l, (long)2l, (long)6l, (long)7l)))) // (2l) public static long add(ArrayList<Long> lst) { long sum = 0; for (int i = 0; i < lst.size(); i++) { if (i % 2 == 1 && lst.get(i) % 2 == 0) { sum += lst.get(i);
} return sum; } }
}
} public static void main(String[] args) { assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)88l)))) == (88l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)5l, (long)6l, (long)7l, (long)2l, (long)122l)))) == (122l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)0l, (long)6l, (long)7l)))) == (0l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)4l, (long)6l, (long)8l)))) == (12l)); } }
humaneval-HumanEval_109_move_one_ball.json-L35
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // We have an array array list 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array array list will be randomly ordered. Your task is to determine if // it is possible to get an array array list sorted in non-decreasing order by performing // the following operation on the given array array list: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array array list by one // position in the right direction. The last element of the array array list will be moved to // the starting position in the array array list i.e. 0th index. // If it is possible to obtain the sorted array array list by performing the above operation // then return true else return false. // If the given array array list is empty then return true. // Note: The given array list is guaranteed to have unique elements. // For Example: // >>> moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)4l, (long)5l, (long)1l, (long)2l)))) // (true) // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array array list. // >>> moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)4l, (long)1l, (long)2l)))) // (false) // Explanation:It is not possible to get non-decreasing order for the given // array array list by performing any number of right shift operations. public static boolean moveOneBall(ArrayList<Long> arr) { if (arr.size() == 0) return true; ArrayList<Long> sorted = new ArrayList<Long>(arr); Collections.sort(sorted); for (int i = 0; i < arr.size(); i++) {
long last = copy.remove(copy.size() - 1); copy.add(0, last); if (copy.equals(sorted)) return true; arr = copy; } return false; } }
ArrayList<Long> copy = new ArrayList<Long>(arr);
} public static void main(String[] args) { assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)4l, (long)5l, (long)1l, (long)2l)))) == (true)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)10l, (long)1l, (long)2l)))) == (true)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)4l, (long)3l, (long)1l, (long)2l)))) == (false)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)4l, (long)1l, (long)2l)))) == (false)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList()))) == (true)); } }
humaneval-HumanEval_57_monotonic.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return true is array list elements are monotonically increasing or decreasing. // >>> monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)20l)))) // (true) // >>> monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l)))) // (false) // >>> monotonic((new ArrayList<Long>(Arrays.asList((long)4l, (long)1l, (long)0l, (long)-10l)))) // (true) public static boolean monotonic(ArrayList<Long> l) {
boolean inc = true; boolean dec = true; for (int i = 1; i < l.size(); i++) { if (l.get(i) < a) { inc = false; } if (l.get(i) > a) { dec = false; } a = l.get(i); } return inc || dec; } }
long a = l.get(0);
} public static void main(String[] args) { assert(monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)10l)))) == (true)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)20l)))) == (true)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)20l, (long)4l, (long)10l)))) == (false)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)4l, (long)1l, (long)0l, (long)-10l)))) == (true)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)4l, (long)1l, (long)1l, (long)0l)))) == (true)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)2l, (long)5l, (long)60l)))) == (false)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)60l)))) == (true)); assert(monotonic((new ArrayList<Long>(Arrays.asList((long)9l, (long)9l, (long)9l, (long)9l)))) == (true)); } }
humaneval-HumanEval_46_fib4.json-L22
js
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1) -> 0 // fib4(2) -> 2 // fib4(3) -> 0 // fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). // Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. // >>> fib4(5) // 4 // >>> fib4(6) // 8 // >>> fib4(7) // 14 function fib4(n){ var prev = [0,0,2,0]; if(n<prev.length){ return prev[n]; } for(var i=4;i<=n;i++){ var curr = prev[0]+prev[1]+prev[2]+prev[3]; prev[0] = prev[1];
prev[2] = prev[3]; prev[3] = curr; } return prev[3]; }
prev[1] = prev[2];
const assert = require('node:assert'); function test() { let candidate = fib4; assert.deepEqual(candidate(5),4); assert.deepEqual(candidate(8),28); assert.deepEqual(candidate(10),104); assert.deepEqual(candidate(12),386); } test();
humaneval-HumanEval_90_next_smallest.json-L17
py
from typing import List, Optional def next_smallest(lst: List[int]) -> Optional[int]: """ You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element. >>> next_smallest([1, 2, 3, 4, 5]) 2 >>> next_smallest([5, 1, 4, 3, 2]) 2 >>> next_smallest([]) None >>> next_smallest([1, 1]) None """
return None min1 = min(lst[0], lst[1]) min2 = max(lst[0], lst[1]) for i in range(2, len(lst)): if lst[i] < min1: min2 = min1 min1 = lst[i] elif lst[i] < min2: min2 = lst[i] return min2 if min1 != min2 else None
if len(lst) < 2:
def check(candidate): assert candidate([1, 2, 3, 4, 5]) == 2 assert candidate([5, 1, 4, 3, 2]) == 2 assert candidate([]) == None assert candidate([1, 1]) == None assert candidate([1, 1, 1, 1, 0]) == 1 assert candidate([1, 1]) == None assert candidate([-35, 34, 12, -45]) == -35 def test_check(): check(next_smallest) test_check()
humaneval-HumanEval_63_fibfib.json-L37
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fibfib(0) == 0 // fibfib(1) == 0 // fibfib(2) == 1 // fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). // Please write a function to efficiently compute the n-th element of the fibfib number sequence. // >>> fibfib((1l)) // (0l) // >>> fibfib((5l)) // (4l) // >>> fibfib((8l)) // (24l) public static long fibfib(long n) { if (n == 0) { return 0; } if (n == 1) { return 0; } if (n == 2) { return 1; } long[] memo = new long[(int) n + 1]; memo[0] = 0; memo[1] = 0; memo[2] = 1; for (int i = 3; i <= n; i++) { memo[i] = memo[i - 1] + memo[i - 2] + memo[i - 3];
return memo[(int) n]; } }
}
} public static void main(String[] args) { assert(fibfib((2l)) == (1l)); assert(fibfib((1l)) == (0l)); assert(fibfib((5l)) == (4l)); assert(fibfib((8l)) == (24l)); assert(fibfib((10l)) == (81l)); assert(fibfib((12l)) == (274l)); assert(fibfib((14l)) == (927l)); } }
humaneval-HumanEval_14_all_prefixes.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return array list of all prefixes from shortest to longest of the input string // >>> allPrefixes(("abc")) // (new ArrayList<String>(Arrays.asList((String)"a", (String)"ab", (String)"abc"))) public static ArrayList<String> allPrefixes(String string) { ArrayList<String> result = new ArrayList<String>(); for (int i = 0; i < string.length(); i++) { result.add(string.substring(0, i + 1)); }
} }
return result;
} public static void main(String[] args) { assert(allPrefixes(("")).equals((new ArrayList<String>(Arrays.asList())))); assert(allPrefixes(("asdfgh")).equals((new ArrayList<String>(Arrays.asList((String)"a", (String)"as", (String)"asd", (String)"asdf", (String)"asdfg", (String)"asdfgh"))))); assert(allPrefixes(("WWW")).equals((new ArrayList<String>(Arrays.asList((String)"W", (String)"WW", (String)"WWW"))))); } }
humaneval-HumanEval_128_prod_signs.json-L32
js
//You are given an array arr of integers and you need to return // sum of magnitudes of integers multiplied by product of all signs // of each number in the array, represented by 1, -1 or 0. // Note: return undefined for empty arr. // Example: // >>> prod_signs([1, 2, 2, -4]) // 9 // >>> prod_signs([0, 1]) // 0 // >>> prod_signs([]) // undefined function prod_signs(arr){ var total = 0; var len = arr.length; var pro = 1; if(len == 0){ return undefined; } else{ for(var i = 0; i < len; i++){ total += Math.abs(arr[i]); if(arr[i] < 0){ pro *= -1; } else if(arr[i] == 0){ pro *= 0; } } total *= pro; return total; }
}
const assert = require('node:assert'); function test() { let candidate = prod_signs; assert.deepEqual(candidate([1, 2, 2, -4]),-9); assert.deepEqual(candidate([0, 1]),0); assert.deepEqual(candidate([1, 1, 1, 2, 3, -1, 1]),-10); assert.deepEqual(candidate([]),undefined); assert.deepEqual(candidate([2, 4, 1, 2, -1, -1, 9]),20); assert.deepEqual(candidate([-1, 1, -1, 1]),4); assert.deepEqual(candidate([-1, 1, 1, 1]),-4); assert.deepEqual(candidate([-1, 1, 1, 0]),0); } test();
humaneval-HumanEval_64_vowels_count.json-L21
py
def vowels_count(s: str) -> int: """Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word. Example: >>> vowels_count('abcde') 2 >>> vowels_count('ACEDY') 3 """ s = s.lower() i = 0 count = 0 while i < len(s): if (s[i] == 'a' or s[i] == 'e' or s[i] == 'i' or s[i] == 'o' or s[i] == 'u'): count += 1 if (s[i] == 'y' and i == len(s) - 1): count += 1
return count
i += 1
def check(candidate): assert candidate('abcde') == 2 assert candidate('Alone') == 3 assert candidate('key') == 2 assert candidate('bye') == 1 assert candidate('keY') == 2 assert candidate('bYe') == 1 assert candidate('ACEDY') == 3 def test_check(): check(vowels_count) test_check()
humaneval-HumanEval_55_fib.json-L13
py
def fib(n: int) -> int: """Return n-th Fibonacci number. >>> fib(10) 55 >>> fib(1) 1 >>> fib(8) 21 """ assert n >= 1 f0, f1 = 0, 1 for i in range(n - 1):
return f1
f0, f1 = f1, f0 + f1
def check(candidate): assert candidate(10) == 55 assert candidate(1) == 1 assert candidate(8) == 21 assert candidate(11) == 89 assert candidate(12) == 144 def test_check(): check(fib) test_check()
humaneval-HumanEval_17_parse_music.json-L17
py
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat >>> parse_music('o o| .| o| o| .| .| .| .| o o') [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4] """ music_types = {'o': 4, 'o|': 2, '.|': 1}
return [music_types[x] for x in music_string.split()]
def check(candidate): assert candidate('') == [] assert candidate('o o o o') == [4, 4, 4, 4] assert candidate('.| .| .| .|') == [1, 1, 1, 1] assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4] assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2] def test_check(): check(parse_music) test_check()
humaneval-HumanEval_54_same_chars.json-L29
js
//Check if two words have the same characters. // >>> same_chars("eabcdzzzz", "dddzzzzzzzddeddabc") // true // >>> same_chars("abcd", "dddddddabc") // true // >>> same_chars("dddddddabc", "abcd") // true // >>> same_chars("eabcd", "dddddddabc") // false // >>> same_chars("abcd", "dddddddabce") // false // >>> same_chars("eabcdzzzz", "dddzzzzzzzddddabc") // false function same_chars(s0, s1){ let res = true; for(let i = 0; i < s0.length; i++){ if(s1.indexOf(s0[i]) === -1){ res = false; break; } } for(let i = 0; i < s1.length; i++){ if(s0.indexOf(s1[i]) === -1){ res = false; break; } } return res;
}
const assert = require('node:assert'); function test() { let candidate = same_chars; assert.deepEqual(candidate("eabcdzzzz", "dddzzzzzzzddeddabc"),true); assert.deepEqual(candidate("abcd", "dddddddabc"),true); assert.deepEqual(candidate("dddddddabc", "abcd"),true); assert.deepEqual(candidate("eabcd", "dddddddabc"),false); assert.deepEqual(candidate("abcd", "dddddddabcf"),false); assert.deepEqual(candidate("eabcdzzzz", "dddzzzzzzzddddabc"),false); assert.deepEqual(candidate("aabb", "aaccc"),false); } test();
humaneval-HumanEval_158_find_max.json-L23
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that accepts an array array list of strings. // The array list contains different words. Return the word with maximum number // of unique characters. If multiple strings have maximum number of unique // characters, return the one which comes first in lexicographical order. // >>> findMax((new ArrayList<String>(Arrays.asList((String)"name", (String)"of", (String)"string")))) // ("string") // >>> findMax((new ArrayList<String>(Arrays.asList((String)"name", (String)"enam", (String)"game")))) // ("enam") // >>> findMax((new ArrayList<String>(Arrays.asList((String)"aaaaaaa", (String)"bb", (String)"cc")))) // ("aaaaaaa") public static String findMax(ArrayList<String> words) { Map<String, Integer> wordsToUniqueCharacters = new HashMap<String, Integer>(); for (String word : words) { Set<Character> uniqueCharacters = new HashSet<Character>();
uniqueCharacters.add(c); } wordsToUniqueCharacters.put(word, uniqueCharacters.size()); } words.sort(new Comparator<String>() { @Override public int compare(String o1, String o2) { int compareResult = wordsToUniqueCharacters.get(o2).compareTo(wordsToUniqueCharacters.get(o1)); if (compareResult == 0) { return o1.compareTo(o2); } return compareResult; } }); return words.get(0); } }
for (char c : word.toCharArray()) {
} public static void main(String[] args) { assert(findMax((new ArrayList<String>(Arrays.asList((String)"name", (String)"of", (String)"string")))).equals(("string"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"name", (String)"enam", (String)"game")))).equals(("enam"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"aaaaaaa", (String)"bb", (String)"cc")))).equals(("aaaaaaa"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"abc", (String)"cba")))).equals(("abc"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"play", (String)"this", (String)"game", (String)"of", (String)"footbott")))).equals(("footbott"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"we", (String)"are", (String)"gonna", (String)"rock")))).equals(("gonna"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"we", (String)"are", (String)"a", (String)"mad", (String)"nation")))).equals(("nation"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"this", (String)"is", (String)"a", (String)"prrk")))).equals(("this"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"b")))).equals(("b"))); assert(findMax((new ArrayList<String>(Arrays.asList((String)"play", (String)"play", (String)"play")))).equals(("play"))); } }
humaneval-HumanEval_128_prod_signs.json-L24
py
from typing import List, Optional def prod_signs(arr: List[int]) -> Optional[int]: """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty arr. Example: >>> prod_signs([1, 2, 2, -4]) 9 >>> prod_signs([0, 1]) 0 >>> prod_signs([]) None """ def product(lst: List[int]) -> int: out = 1 for item in lst: out *= item return out
return None else: sign_arr = [] for num in arr: if num > 0: sign_arr.append(1) elif num < 0: sign_arr.append(-1) else: sign_arr.append(0) return sum(map(abs, arr)) * product(sign_arr)
if len(arr) == 0:
def check(candidate): assert candidate([1, 2, 2, -4]) == -9 assert candidate([0, 1]) == 0 assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10 assert candidate([]) == None assert candidate([2, 4, 1, 2, -1, -1, 9]) == 20 assert candidate([-1, 1, -1, 1]) == 4 assert candidate([-1, 1, 1, 1]) == -4 assert candidate([-1, 1, 1, 0]) == 0 def test_check(): check(prod_signs) test_check()
humaneval-HumanEval_104_unique_digits.json-L15
py
from typing import List def unique_digits(x: List[int]) -> List[int]: """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """
for i in x: temp=i while temp: if temp%2==0: s.append(i) break temp=temp//10 for i in s: x.remove(i) return sorted(x)
s=[]
def check(candidate): assert candidate([15, 33, 1422, 1]) == [1, 15, 33] assert candidate([152, 323, 1422, 10]) == [] assert candidate([12345, 2033, 111, 151]) == [111, 151] assert candidate([135, 103, 31]) == [31, 135] def test_check(): check(unique_digits) test_check()
humaneval-HumanEval_17_parse_music.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string representing musical notes in a special ASCII format. // Your task is to parse this string and return array list of integers corresponding to how many beats does each // not last. // Here is a legend: // 'o' - whole note, lasts four beats // 'o|' - half note, lasts two beats // '.|' - quater note, lasts one beat // >>> parseMusic(("o o| .| o| o| .| .| .| .| o o")) // (new ArrayList<Long>(Arrays.asList((long)4l, (long)2l, (long)1l, (long)2l, (long)2l, (long)1l, (long)1l, (long)1l, (long)1l, (long)4l, (long)4l))) public static ArrayList<Long> parseMusic(String music_string) { ArrayList<Long> res = new ArrayList<Long>(); char[] chars = music_string.toCharArray(); for (int i = 0; i < chars.length; i++) { if (chars[i] == 'o') { if (i + 1 < chars.length && chars[i + 1] == '|') { res.add((long)2l); i += 1; } else { res.add((long)4l); } } else if (chars[i] == '.') { if (i + 1 < chars.length && chars[i + 1] == '|') { res.add((long)1l); i += 1; }
} return res; } }
}
} public static void main(String[] args) { assert(parseMusic(("")).equals((new ArrayList<Long>(Arrays.asList())))); assert(parseMusic(("o o o o")).equals((new ArrayList<Long>(Arrays.asList((long)4l, (long)4l, (long)4l, (long)4l))))); assert(parseMusic((".| .| .| .|")).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)1l, (long)1l, (long)1l))))); assert(parseMusic(("o| o| .| .| o o o o")).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)1l, (long)1l, (long)4l, (long)4l, (long)4l, (long)4l))))); assert(parseMusic(("o| .| o| .| o o| o o|")).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)1l, (long)2l, (long)1l, (long)4l, (long)2l, (long)4l, (long)2l))))); } }
humaneval-HumanEval_148_bf.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // There are eight planets in our solar system: the closerst to the Sun // is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, // Uranus, Neptune. // Write a function that takes two planet names as strings planet1 and planet2. // The function should return a pair containing all planets whose orbits are // located between the orbit of planet1 and the orbit of planet2, sorted by // the proximity to the sun. // The function should return an empty pair if planet1 or planet2 // are not correct planet names. // Examples // >>> bf(("Jupiter"), ("Neptune")) // (new ArrayList<String>(Arrays.asList((String)"Saturn", (String)"Uranus"))) // >>> bf(("Earth"), ("Mercury")) // (ArrayList<String>("Venus")) // >>> bf(("Mercury"), ("Uranus")) // (new ArrayList<String>(Arrays.asList((String)"Venus", (String)"Earth", (String)"Mars", (String)"Jupiter", (String)"Saturn"))) public static ArrayList<String> bf(String planet1, String planet2) { ArrayList<String> planets = new ArrayList<String>(Arrays.asList((String)"Mercury", (String)"Venus", (String)"Earth", (String)"Mars", (String)"Jupiter", (String)"Saturn", (String)"Uranus", (String)"Neptune")); int indexPlanet1 = planets.indexOf(planet1); int indexPlanet2 = planets.indexOf(planet2); int indexMin = 0; int indexMax = 0; if (indexPlanet1 >= 0 && indexPlanet2 >= 0) { if (indexPlanet1 < indexPlanet2) { indexMin = indexPlanet1;
} else { indexMin = indexPlanet2; indexMax = indexPlanet1; } ArrayList<String> planetsInBetween = new ArrayList<String>(); for (int i = indexMin + 1; i < indexMax; i++) { planetsInBetween.add(planets.get(i)); } return planetsInBetween; } else { return new ArrayList<String>(); } } }
indexMax = indexPlanet2;
} public static void main(String[] args) { assert(bf(("Jupiter"), ("Neptune")).equals((new ArrayList<String>(Arrays.asList((String)"Saturn", (String)"Uranus"))))); assert(bf(("Earth"), ("Mercury")).equals((new ArrayList<String>(Arrays.asList((String)"Venus"))))); assert(bf(("Mercury"), ("Uranus")).equals((new ArrayList<String>(Arrays.asList((String)"Venus", (String)"Earth", (String)"Mars", (String)"Jupiter", (String)"Saturn"))))); assert(bf(("Neptune"), ("Venus")).equals((new ArrayList<String>(Arrays.asList((String)"Earth", (String)"Mars", (String)"Jupiter", (String)"Saturn", (String)"Uranus"))))); assert(bf(("Earth"), ("Earth")).equals((new ArrayList<String>(Arrays.asList())))); assert(bf(("Mars"), ("Earth")).equals((new ArrayList<String>(Arrays.asList())))); assert(bf(("Jupiter"), ("Makemake")).equals((new ArrayList<String>(Arrays.asList())))); } }
humaneval-HumanEval_113_odd_count.json-L22
js
//Given an array of strings, where each string consists of only digits, return an array. // Each element i of the output should be "the number of odd elements in the // string i of the input." where all the i's should be replaced by the number // of odd digits in the i'th string of the input. // >>> odd_count(["1234567"]) // ["the number of odd elements 4n the str4ng 4 of the 4nput."] // >>> odd_count(["3", "11111111"]) // ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."] function odd_count(lst){ var new_lst = []; for (var i = 0; i < lst.length; i++){ var word = lst[i]; var odd_sum = 0; for (var j = 0; j < word.length; j++){ if (word[j] % 2 == 1){ odd_sum += 1; } } var odd_word = "the number of odd elements " + odd_sum + "n the str" + odd_sum + "ng " + odd_sum + " of the " + odd_sum + "nput."; new_lst.push(odd_word); }
}
return new_lst;
const assert = require('node:assert'); function test() { let candidate = odd_count; assert.deepEqual(candidate(["1234567"]),["the number of odd elements 4n the str4ng 4 of the 4nput."]); assert.deepEqual(candidate(["3", "11111111"]),["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]); assert.deepEqual(candidate(["271", "137", "314"]),["the number of odd elements 2n the str2ng 2 of the 2nput.", "the number of odd elements 3n the str3ng 3 of the 3nput.", "the number of odd elements 2n the str2ng 2 of the 2nput."]); } test();
humaneval-HumanEval_53_add.json-L7
js
//Add two numbers x and y // >>> add(2, 3) // 5 // >>> add(5, 7) // 12 function add(x, y){
}
return x + y;
const assert = require('node:assert'); function test() { let candidate = add; assert.deepEqual(candidate(0, 1),1); assert.deepEqual(candidate(1, 0),1); assert.deepEqual(candidate(2, 3),5); assert.deepEqual(candidate(5, 7),12); assert.deepEqual(candidate(7, 5),12); } test();
humaneval-HumanEval_31_is_prime.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return true if a given number is prime, and false otherwise. // >>> isPrime((6l)) // (false) // >>> isPrime((101l)) // (true) // >>> isPrime((11l)) // (true) // >>> isPrime((13441l)) // (true) // >>> isPrime((61l)) // (true) // >>> isPrime((4l)) // (false) // >>> isPrime((1l)) // (false) public static boolean isPrime(long n) { if (n <= 1) return false; if (n <= 3) return true; if (n % 2 == 0 || n % 3 == 0) return false; long i = 5; while (i * i <= n) { if (n % i == 0 || n % (i + 2) == 0) return false; i += 6; } return true;
}
}
} public static void main(String[] args) { assert(isPrime((6l)) == (false)); assert(isPrime((101l)) == (true)); assert(isPrime((11l)) == (true)); assert(isPrime((13441l)) == (true)); assert(isPrime((61l)) == (true)); assert(isPrime((4l)) == (false)); assert(isPrime((1l)) == (false)); assert(isPrime((5l)) == (true)); assert(isPrime((11l)) == (true)); assert(isPrime((17l)) == (true)); assert(isPrime((85l)) == (false)); assert(isPrime((77l)) == (false)); assert(isPrime((255379l)) == (false)); } }
humaneval-HumanEval_143_words_in_sentence.json-L40
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a string representing a sentence, // the sentence contains some words separated by a space, // and you have to return a string that contains the words from the original sentence, // whose lengths are prime numbers, // the order of the words in the new string should be the same as the original one. // Example 1: // >>> wordsInSentence(("This is a test")) // ("is") // Example 2: // >>> wordsInSentence(("lets go for swimming")) // ("go for") // Constraints: // * 1 <= len(sentence) <= 100 // * sentence contains only letters public static String wordsInSentence(String sentence) { StringBuilder ans = new StringBuilder(); String[] words = sentence.split(" "); int[] primes = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}; boolean isPrime; for (String word : words) { isPrime = false; for (int prime : primes) { if (word.length() == prime) { isPrime = true; break; } } if (isPrime) { ans.append(word + " "); } }
ans.deleteCharAt(ans.length() - 1); } return ans.toString(); } }
if (ans.length() > 0) {
} public static void main(String[] args) { assert(wordsInSentence(("This is a test")).equals(("is"))); assert(wordsInSentence(("lets go for swimming")).equals(("go for"))); assert(wordsInSentence(("there is no place available here")).equals(("there is no place"))); assert(wordsInSentence(("Hi I am Hussein")).equals(("Hi am Hussein"))); assert(wordsInSentence(("go for it")).equals(("go for it"))); assert(wordsInSentence(("here")).equals((""))); assert(wordsInSentence(("here is")).equals(("is"))); } }
humaneval-HumanEval_160_do_algebra.json-L33
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given two array lists operator, and operand. The first array list has basic algebra operations, and // the second array list is an array array list of integers. Use the two given array lists to build the algebric // expression and return the evaluation of this expression. // The basic algebra operations: // Addition ( + ) // Subtraction ( - ) // Multiplication ( * ) // Floor division ( // ) // Exponentiation ( ** ) // Example: // operator['+', '*', '-'] // array array list = [2, 3, 4, 5] // result = 2 + 3 * 4 - 5 // => result = 9 // Note: // The length of operator array list is equal to the length of operand array list minus one. // Operand is an array array list of of non-negative integers. // Operator array list has at least one operator, and operand array list has at least two operands. public static long doAlgebra(ArrayList<String> op, ArrayList<Long> operand) { ArrayList<Long> list = new ArrayList<>(); list.add(operand.get(0)); for (int i = 0; i < op.size(); i++) { if (op.get(i).equals("+")) list.add(operand.get(i + 1));
list.add(-operand.get(i + 1)); else if (op.get(i).equals("*")) list.set(list.size() - 1, list.get(list.size() - 1) * operand.get(i + 1)); else if (op.get(i).equals("//")) list.set(list.size() - 1, list.get(list.size() - 1) / operand.get(i + 1)); else if (op.get(i).equals("**")) list.set(list.size() - 1, (long) Math.pow(list.get(list.size() - 1), operand.get(i + 1))); } return list.stream().mapToLong(x -> x).sum(); } }
else if (op.get(i).equals("-"))
} public static void main(String[] args) { assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"**", (String)"*", (String)"+"))), (new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)5l)))) == (37l)); assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"+", (String)"*", (String)"-"))), (new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)5l)))) == (9l)); assert(doAlgebra((new ArrayList<String>(Arrays.asList((String)"//", (String)"*"))), (new ArrayList<Long>(Arrays.asList((long)7l, (long)3l, (long)4l)))) == (8l)); } }
humaneval-HumanEval_111_histogram.json-L17
js
//Given a string representing a space separated lowercase letters, return an object // of the letter with the most repetition and containing the corresponding count. // If several letters have the same occurrence, return all of them. // Example: // >>> histogram("a b c") // {"a": 1, "b": 1, "c": 1} // >>> histogram("a b b a") // {"a": 2, "b": 2} // >>> histogram("a b c a b") // {"a": 2, "b": 2} // >>> histogram("b b b b a") // {"b": 4} // >>> histogram("") // {} function histogram(test){ if (test.length === 0){
} var lst = test.split(" "); var count = {}; for (var i = 0; i < lst.length; i++){ if (count[lst[i]]){ count[lst[i]] += 1; } else{ count[lst[i]] = 1; } } console.log(count); var max = 0; var result = {}; for (var key in count){ if (count[key] > max){ max = count[key]; result = {}; result[key] = max; } else if (count[key] === max){ result[key] = max; } } return result; }
return {};
const assert = require('node:assert'); function test() { let candidate = histogram; assert.deepEqual(candidate("a b b a"),{"a": 2, "b": 2}); assert.deepEqual(candidate("a b c a b"),{"a": 2, "b": 2}); assert.deepEqual(candidate("a b c d g"),{"a": 1, "b": 1, "c": 1, "d": 1, "g": 1}); assert.deepEqual(candidate("r t g"),{"r": 1, "t": 1, "g": 1}); assert.deepEqual(candidate("b b b b a"),{"b": 4}); assert.deepEqual(candidate("r t g"),{"r": 1, "t": 1, "g": 1}); assert.deepEqual(candidate(""),{}); assert.deepEqual(candidate("a"),{"a": 1}); } test();
humaneval-HumanEval_26_remove_duplicates.json-L20
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // From an array array list of integers, remove all elements that occur more than once. // Keep order of elements left the same as in the input. // >>> removeDuplicates((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)2l, (long)4l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)4l))) public static ArrayList<Long> removeDuplicates(ArrayList<Long> numbers) { HashMap<Long, Long> hashmap = new HashMap<Long, Long>(); for (int i = 0; i < numbers.size(); i++) { Long key = numbers.get(i); if (hashmap.containsKey(key)) { hashmap.put(key, hashmap.get(key) + 1); } else {
} } ArrayList<Long> out = new ArrayList<Long>(); for (int i = 0; i < numbers.size(); i++) { Long key = numbers.get(i); if (hashmap.get(key) == 1) { out.add(key); } } return out; } }
hashmap.put(key, 1L);
} public static void main(String[] args) { assert(removeDuplicates((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<Long>(Arrays.asList())))); assert(removeDuplicates((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l))))); assert(removeDuplicates((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)2l, (long)4l, (long)3l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)5l))))); } }
humaneval-HumanEval_39_prime_fib.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // prime_fib returns n-th number that is a Fibonacci number and it's also prime. // >>> primeFib((1l)) // (2l) // >>> primeFib((2l)) // (3l) // >>> primeFib((3l)) // (5l) // >>> primeFib((4l)) // (13l) // >>> primeFib((5l)) // (89l) public static long primeFib(long n) { long fib = 1;
long count = 0; while (count != n) { long tmp = fib; fib += prev; prev = tmp; if (BigInteger.valueOf(fib).isProbablePrime(1)) { count++; } } return fib; } }
long prev = 0;
} public static void main(String[] args) { assert(primeFib((1l)) == (2l)); assert(primeFib((2l)) == (3l)); assert(primeFib((3l)) == (5l)); assert(primeFib((4l)) == (13l)); assert(primeFib((5l)) == (89l)); assert(primeFib((6l)) == (233l)); assert(primeFib((7l)) == (1597l)); assert(primeFib((8l)) == (28657l)); assert(primeFib((9l)) == (514229l)); assert(primeFib((10l)) == (433494437l)); } }
humaneval-HumanEval_131_digits.json-L16
js
//Given a positive integer n, return the product of the odd digits. // Return 0 if all digits are even. // For example: // >>> digits(1) // 1 // >>> digits(4) // 0 // >>> digits(235) // 15 function digits(n){ if(!n){ return "error"; } if(n < 0){ return "error";
var temp = 0; var prod = 1; var odd = true; for(n; n > 0; n = Math.floor(n/10)){ temp = n % 10; if(temp % 2 != 0){ prod *= temp; odd = false; } } if(odd){ return 0; } return prod; }
}
const assert = require('node:assert'); function test() { let candidate = digits; assert.deepEqual(candidate(5),5); assert.deepEqual(candidate(54),5); assert.deepEqual(candidate(120),1); assert.deepEqual(candidate(5014),5); assert.deepEqual(candidate(98765),315); assert.deepEqual(candidate(5576543),2625); assert.deepEqual(candidate(2468),0); } test();
humaneval-HumanEval_111_histogram.json-L45
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string representing a space separated lowercase letters, return a hash map // of the letter with the most repetition and containing the corresponding count. // If several letters have the same occurrence, return all of them. // Example: // >>> histogram(("a b c")) // (new HashMap<String,Long>(Map.of("a", 1l, "b", 1l, "c", 1l))) // >>> histogram(("a b b a")) // (new HashMap<String,Long>(Map.of("a", 2l, "b", 2l))) // >>> histogram(("a b c a b")) // (new HashMap<String,Long>(Map.of("a", 2l, "b", 2l))) // >>> histogram(("b b b b a")) // (new HashMap<String,Long>(Map.of("b", 4l))) // >>> histogram(("")) // (new HashMap<String,Long>()) public static HashMap<String,Long> histogram(String test) { HashMap<String,Long> s = new HashMap<String,Long>(); if (test.length() > 0) { HashMap<String,Long> hm = new HashMap<String,Long>(); String[] ss = test.split(" "); for (String sss : ss) { if (hm.containsKey(sss)) { hm.put(sss, hm.get(sss) + 1); } else { hm.put(sss, 1l); } } long max = 0; for (String key : hm.keySet()) { if (hm.get(key) > max) { max = hm.get(key); } } for (String key : hm.keySet()) { if (hm.get(key) == max) { s.put(key, hm.get(key)); }
} return s; } }
}
} public static void main(String[] args) { assert(histogram(("a b b a")).equals((new HashMap<String,Long>(Map.of("a", 2l, "b", 2l))))); assert(histogram(("a b c a b")).equals((new HashMap<String,Long>(Map.of("a", 2l, "b", 2l))))); assert(histogram(("a b c d g")).equals((new HashMap<String,Long>(Map.of("a", 1l, "b", 1l, "c", 1l, "d", 1l, "g", 1l))))); assert(histogram(("r t g")).equals((new HashMap<String,Long>(Map.of("r", 1l, "t", 1l, "g", 1l))))); assert(histogram(("b b b b a")).equals((new HashMap<String,Long>(Map.of("b", 4l))))); assert(histogram(("r t g")).equals((new HashMap<String,Long>(Map.of("r", 1l, "t", 1l, "g", 1l))))); assert(histogram(("")).equals((new HashMap<String,Long>()))); assert(histogram(("a")).equals((new HashMap<String,Long>(Map.of("a", 1l))))); } }
humaneval-HumanEval_40_triples_sum_to_zero.json-L26
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // triples_sum_to_zero takes an array array list of integers as an input. // it returns true if there are three distinct elements in the array list that // sum to zero, and false otherwise. // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) // (false) public static boolean triplesSumToZero(ArrayList<Long> l) { if (l.size() < 3) { return false; }
Collections.sort(sortedList); for (int i = 0; i < sortedList.size() - 2; i++) { int j = i + 1; int k = sortedList.size() - 1; while (j < k) { long currSum = sortedList.get(i) + sortedList.get(j) + sortedList.get(k); if (currSum == 0) { return true; } else if (currSum < 0) { j++; } else { k--; } } } return false; } }
ArrayList<Long> sortedList = new ArrayList<Long>(l);
} public static void main(String[] args) { assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)5l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-100l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)100l, (long)3l, (long)5l, (long)-100l)))) == (false)); } }
humaneval-HumanEval_88_sort_array.json-L30
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of non-negative integers, return a cojava of the given array array list after sorting, // you will sort the given array array list in ascending order if the sum( first index value, last index value) is odd, // or sort it in descending order if the sum( first index value, last index value) is even. // Note: // * don't change the given array array list. // Examples: // >>> sortArray((new ArrayList<Long>(Arrays.asList()))) // (new ArrayList<Long>(Arrays.asList())) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)5l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)3l, (long)4l, (long)5l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l, (long)6l)))) // (new ArrayList<Long>(Arrays.asList((long)6l, (long)5l, (long)4l, (long)3l, (long)2l, (long)1l, (long)0l))) public static ArrayList<Long> sortArray(ArrayList<Long> array) { if(array.size()==0) { return array; } if(array.size()==1) { return array; }
if((array.get(0)+array.get(array.size()-1))%2==0) { Collections.sort(array, Collections.reverseOrder()); } else { Collections.sort(array); } } return array; } }
if(array.size()>1) {
} public static void main(String[] args) { assert(sortArray((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<Long>(Arrays.asList())))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)5l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)3l, (long)4l, (long)5l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l, (long)6l)))).equals((new ArrayList<Long>(Arrays.asList((long)6l, (long)5l, (long)4l, (long)3l, (long)2l, (long)1l, (long)0l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)15l, (long)42l, (long)87l, (long)32l, (long)11l, (long)0l)))).equals((new ArrayList<Long>(Arrays.asList((long)0l, (long)11l, (long)15l, (long)32l, (long)42l, (long)87l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)21l, (long)14l, (long)23l, (long)11l)))).equals((new ArrayList<Long>(Arrays.asList((long)23l, (long)21l, (long)14l, (long)11l))))); } }
humaneval-HumanEval_148_bf.json-L30
py
from typing import Tuple def bf(planet1: str, planet2: str) -> Tuple[str, ...]: """ There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings planet1 and planet2. The function should return a tuple containing all planets whose orbits are located between the orbit of planet1 and the orbit of planet2, sorted by the proximity to the sun. The function should return an empty tuple if planet1 or planet2 are not correct planet names. Examples >>> bf('Jupiter', 'Neptune') ('Saturn', 'Uranus') >>> bf('Earth', 'Mercury') 'Venus' >>> bf('Mercury', 'Uranus') ('Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn') """ planets = ('Mercury', 'Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn', 'Uranus', 'Neptune') if planet1 not in planets or planet2 not in planets: return () start = planets.index(planet1) end = planets.index(planet2) if start < end: planets = planets[start+1:end] else:
return tuple(planets)
planets = planets[end+1:start]
def check(candidate): assert candidate('Jupiter', 'Neptune') == ('Saturn', 'Uranus') assert candidate('Earth', 'Mercury') == ('Venus',) assert candidate('Mercury', 'Uranus') == ('Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn') assert candidate('Neptune', 'Venus') == ('Earth', 'Mars', 'Jupiter', 'Saturn', 'Uranus') assert candidate('Earth', 'Earth') == () assert candidate('Mars', 'Earth') == () assert candidate('Jupiter', 'Makemake') == () def test_check(): check(bf) test_check()
humaneval-HumanEval_85_add.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add((new ArrayList<Long>(Arrays.asList((long)4l, (long)2l, (long)6l, (long)7l)))) // (2l) public static long add(ArrayList<Long> lst) { long sum = 0; for (int i = 0; i < lst.size(); i++) { if (i % 2 == 1 && lst.get(i) % 2 == 0) { sum += lst.get(i); } } return sum; }
}
} public static void main(String[] args) { assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)88l)))) == (88l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)5l, (long)6l, (long)7l, (long)2l, (long)122l)))) == (122l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)0l, (long)6l, (long)7l)))) == (0l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)4l, (long)6l, (long)8l)))) == (12l)); } }
humaneval-HumanEval_123_get_odd_collatz.json-L18
js
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence. // The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined // as follows: start with any positive integer n. Then each term is obtained from the // previous term as follows: if the previous term is even, the next term is one half of // the previous term. If the previous term is odd, the next term is 3 times the previous // term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1. // Note: // 1. Collatz(1) is [1]. // 2. returned array sorted in increasing order. // For example: // get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5. // >>> get_odd_collatz(5) // [1, 5] function get_odd_collatz(n){ var collatz_sequence = [] var odd_numbers = [] var odd_count = 0
for(var i = 0; i < collatz_sequence.length; i++){ if(collatz_sequence[i]%2 == 0){ collatz_sequence.push(collatz_sequence[i]/2) } else if(collatz_sequence[i]%2 == 1){ collatz_sequence.push(collatz_sequence[i]*3+1) } if(collatz_sequence[i]%2 == 1){ odd_numbers.push(collatz_sequence[i]) odd_count += 1 } if(collatz_sequence[i] == 1){ break } } if(odd_count != 0){ odd_numbers.sort(function(a, b){return a-b}) return odd_numbers } else{ odd_numbers.push(1) return odd_numbers } }
collatz_sequence.push(n)
const assert = require('node:assert'); function test() { let candidate = get_odd_collatz; assert.deepEqual(candidate(14),[1, 5, 7, 11, 13, 17]); assert.deepEqual(candidate(5),[1, 5]); assert.deepEqual(candidate(12),[1, 3, 5]); assert.deepEqual(candidate(1),[1]); } test();
humaneval-HumanEval_114_minSubArraySum.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list // of nums. // Example // >>> minSubArraySum((new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)1l, (long)2l, (long)4l)))) // (1l) // >>> minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l)))) // (-6l) public static long minSubArraySum(ArrayList<Long> nums) { long minSum = Long.MAX_VALUE; long prevMinSum = Long.MAX_VALUE; for (int i = 0; i < nums.size(); i++) { long currSum = nums.get(i); if (currSum < prevMinSum) { prevMinSum = currSum; } if (currSum < minSum) { minSum = currSum; } for (int j = i + 1; j < nums.size(); j++) { currSum += nums.get(j); if (currSum < prevMinSum) { prevMinSum = currSum; } if (currSum < minSum) { minSum = currSum;
} } return minSum; } }
}
} public static void main(String[] args) { assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)1l, (long)2l, (long)4l)))) == (1l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l, (long)2l, (long)-10l)))) == (-14l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-9999999999999999l)))) == (-9999999999999999l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)0l, (long)10l, (long)20l, (long)1000000l)))) == (0l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l, (long)10l, (long)-5l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)100l, (long)-1l, (long)-2l, (long)-3l, (long)10l, (long)-5l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)10l, (long)11l, (long)13l, (long)8l, (long)3l, (long)4l)))) == (3l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)100l, (long)-33l, (long)32l, (long)-1l, (long)0l, (long)-2l)))) == (-33l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-10l)))) == (-10l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)7l)))) == (7l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l)))) == (-1l)); } }
humaneval-HumanEval_114_minSubArraySum.json-L21
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of integers nums, find the minimum sum of any non-empty sub-array array list // of nums. // Example // >>> minSubArraySum((new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)1l, (long)2l, (long)4l)))) // (1l) // >>> minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l)))) // (-6l) public static long minSubArraySum(ArrayList<Long> nums) { long minSum = Long.MAX_VALUE; long prevMinSum = Long.MAX_VALUE; for (int i = 0; i < nums.size(); i++) { long currSum = nums.get(i);
prevMinSum = currSum; } if (currSum < minSum) { minSum = currSum; } for (int j = i + 1; j < nums.size(); j++) { currSum += nums.get(j); if (currSum < prevMinSum) { prevMinSum = currSum; } if (currSum < minSum) { minSum = currSum; } } } return minSum; } }
if (currSum < prevMinSum) {
} public static void main(String[] args) { assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)4l, (long)1l, (long)2l, (long)4l)))) == (1l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l, (long)2l, (long)-10l)))) == (-14l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-9999999999999999l)))) == (-9999999999999999l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)0l, (long)10l, (long)20l, (long)1000000l)))) == (0l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-1l, (long)-2l, (long)-3l, (long)10l, (long)-5l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)100l, (long)-1l, (long)-2l, (long)-3l, (long)10l, (long)-5l)))) == (-6l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)10l, (long)11l, (long)13l, (long)8l, (long)3l, (long)4l)))) == (3l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)100l, (long)-33l, (long)32l, (long)-1l, (long)0l, (long)-2l)))) == (-33l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)-10l)))) == (-10l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)7l)))) == (7l)); assert(minSubArraySum((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l)))) == (-1l)); } }
humaneval-HumanEval_119_match_parens.json-L28
js
//You are given an array of two strings, both strings consist of open // parentheses '(' or close parentheses ')' only. // Your job is to check if it is possible to concatenate the two strings in // some order, that the resulting string will be good. // A string S is considered to be good if and only if all parentheses in S // are balanced. For example: the string '(())()' is good, while the string // '())' is not. // Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. // Examples: // >>> match_parens(["()(", ")"]) // "Yes" // >>> match_parens([")", ")"]) // "No" function match_parens(lst){ const open = '('; const close = ')'; const is_good = (s) => { let stack = []; for (let p of s){ if (p === open){ stack.push(p); } else if (p === close){ if (stack.length === 0){ return false; } stack.pop(); }
return stack.length === 0; }; const str1 = lst[0]; const str2 = lst[1]; if (is_good(str1 + str2)){ return 'Yes'; } if (is_good(str2 + str1)){ return 'Yes'; } return 'No'; }
}
const assert = require('node:assert'); function test() { let candidate = match_parens; assert.deepEqual(candidate(["()(", ")"]),"Yes"); assert.deepEqual(candidate([")", ")"]),"No"); assert.deepEqual(candidate(["(()(())", "())())"]),"No"); assert.deepEqual(candidate([")())", "(()()("]),"Yes"); assert.deepEqual(candidate(["(())))", "(()())(("]),"Yes"); assert.deepEqual(candidate(["()", "())"]),"No"); assert.deepEqual(candidate(["(()(", "()))()"]),"Yes"); assert.deepEqual(candidate(["((((", "((())"]),"No"); assert.deepEqual(candidate([")(()", "(()("]),"No"); assert.deepEqual(candidate([")(", ")("]),"No"); assert.deepEqual(candidate(["(", ")"]),"Yes"); assert.deepEqual(candidate([")", "("]),"Yes"); } test();
humaneval-HumanEval_85_add.json-L14
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a non-empty array list of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add((new ArrayList<Long>(Arrays.asList((long)4l, (long)2l, (long)6l, (long)7l)))) // (2l) public static long add(ArrayList<Long> lst) {
for (int i = 0; i < lst.size(); i++) { if (i % 2 == 1 && lst.get(i) % 2 == 0) { sum += lst.get(i); } } return sum; } }
long sum = 0;
} public static void main(String[] args) { assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)88l)))) == (88l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)5l, (long)6l, (long)7l, (long)2l, (long)122l)))) == (122l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)0l, (long)6l, (long)7l)))) == (0l)); assert(add((new ArrayList<Long>(Arrays.asList((long)4l, (long)4l, (long)6l, (long)8l)))) == (12l)); } }
humaneval-HumanEval_109_move_one_ball.json-L39
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // We have an array array list 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array array list will be randomly ordered. Your task is to determine if // it is possible to get an array array list sorted in non-decreasing order by performing // the following operation on the given array array list: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array array list by one // position in the right direction. The last element of the array array list will be moved to // the starting position in the array array list i.e. 0th index. // If it is possible to obtain the sorted array array list by performing the above operation // then return true else return false. // If the given array array list is empty then return true. // Note: The given array list is guaranteed to have unique elements. // For Example: // >>> moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)4l, (long)5l, (long)1l, (long)2l)))) // (true) // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array array list. // >>> moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)4l, (long)1l, (long)2l)))) // (false) // Explanation:It is not possible to get non-decreasing order for the given // array array list by performing any number of right shift operations. public static boolean moveOneBall(ArrayList<Long> arr) { if (arr.size() == 0) return true; ArrayList<Long> sorted = new ArrayList<Long>(arr); Collections.sort(sorted); for (int i = 0; i < arr.size(); i++) { ArrayList<Long> copy = new ArrayList<Long>(arr); long last = copy.remove(copy.size() - 1); copy.add(0, last); if (copy.equals(sorted)) return true;
} return false; } }
arr = copy;
} public static void main(String[] args) { assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)4l, (long)5l, (long)1l, (long)2l)))) == (true)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)10l, (long)1l, (long)2l)))) == (true)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)4l, (long)3l, (long)1l, (long)2l)))) == (false)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList((long)3l, (long)5l, (long)4l, (long)1l, (long)2l)))) == (false)); assert(moveOneBall((new ArrayList<Long>(Arrays.asList()))) == (true)); } }
humaneval-HumanEval_118_get_closest_vowel.json-L26
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a word. Your task is to find the closest vowel that stands between // two consonants from the right side of the word (case sensitive). // Vowels in the beginning and ending doesn't count. Return empty string if you didn't // find any vowel met the above condition. // You may assume that the given string contains English letter only. // Example: // >>> getClosestVowel(("yogurt")) // ("u") // >>> getClosestVowel(("FULL")) // ("U") // >>> getClosestVowel(("quick")) // ("") // >>> getClosestVowel(("ab")) // ("") public static String getClosestVowel(String word) { final String vowels = "aeiou"; final String consonants = "bcdfghjklmnpqrstvwxyz";
word = word.toLowerCase(); for (int i = 0; i < word.length(); i++) { if (vowels.indexOf(word.charAt(i)) != -1) { idx.add(i); } } for (int i = idx.size() - 1; i >= 0; i--) { int j = idx.get(i); if (j == 0 || j == word.length() - 1) continue; char left = word.charAt(j - 1); char right = word.charAt(j + 1); if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) { return String.valueOf(word.charAt(j)); } } return ""; } }
List<Integer> idx = new ArrayList<>();
} public static void main(String[] args) { assert(getClosestVowel(("yogurt")).equals(("u"))); assert(getClosestVowel(("full")).equals(("u"))); assert(getClosestVowel(("easy")).equals((""))); assert(getClosestVowel(("eAsy")).equals((""))); assert(getClosestVowel(("ali")).equals((""))); assert(getClosestVowel(("bad")).equals(("a"))); assert(getClosestVowel(("most")).equals(("o"))); assert(getClosestVowel(("ab")).equals((""))); assert(getClosestVowel(("ba")).equals((""))); assert(getClosestVowel(("quick")).equals((""))); assert(getClosestVowel(("anime")).equals(("i"))); assert(getClosestVowel(("Asia")).equals((""))); assert(getClosestVowel(("Above")).equals(("o"))); } }
humaneval-HumanEval_40_triples_sum_to_zero.json-L38
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // triples_sum_to_zero takes an array array list of integers as an input. // it returns true if there are three distinct elements in the array list that // sum to zero, and false otherwise. // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) // (false) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) // (true) // >>> triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) // (false) public static boolean triplesSumToZero(ArrayList<Long> l) { if (l.size() < 3) { return false; } ArrayList<Long> sortedList = new ArrayList<Long>(l); Collections.sort(sortedList); for (int i = 0; i < sortedList.size() - 2; i++) { int j = i + 1; int k = sortedList.size() - 1; while (j < k) { long currSum = sortedList.get(i) + sortedList.get(j) + sortedList.get(k); if (currSum == 0) { return true; } else if (currSum < 0) { j++; } else {
} } } return false; } }
k--;
} public static void main(String[] args) { assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)0l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)-2l, (long)1l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)5l, (long)7l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)-5l, (long)3l, (long)9l, (long)7l)))) == (true)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)5l, (long)-100l)))) == (false)); assert(triplesSumToZero((new ArrayList<Long>(Arrays.asList((long)100l, (long)3l, (long)5l, (long)-100l)))) == (false)); } }
humaneval-HumanEval_85_add.json-L7
js
//Given a non-empty array of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add([4, 2, 6, 7]) // 2 function add(lst){ var add = 0;
if(lst[i] % 2 == 0 && i % 2 != 0) { add += lst[i]; } } return add; }
for(var i = 0; i < lst.length; i++) {
const assert = require('node:assert'); function test() { let candidate = add; assert.deepEqual(candidate([4, 88]),88); assert.deepEqual(candidate([4, 5, 6, 7, 2, 122]),122); assert.deepEqual(candidate([4, 0, 6, 7]),0); assert.deepEqual(candidate([4, 4, 6, 8]),12); } test();