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How many lessons were in cancelled state? | CREATE TABLE Lessons (lesson_status_code VARCHAR) | SELECT COUNT(*) FROM Lessons WHERE lesson_status_code = "Cancelled" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (lesson_status_code VARCHAR)
### question:How many lessons were in cancelled state? | SELECT COUNT(*) FROM Lessons WHERE lesson_status_code = "Cancelled" |
List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'. | CREATE TABLE Lessons (lesson_id VARCHAR, staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR) | SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (lesson_id VARCHAR, staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
### question:List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'. | SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%" |
How many lessons taught by staff whose first name has letter 'a' in it? | CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR) | SELECT COUNT(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR)
### question:How many lessons taught by staff whose first name has letter 'a' in it? | SELECT COUNT(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%" |
How long is the total lesson time taught by staff with first name as Janessa and last name as Sawayn? | CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR) | SELECT SUM(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
### question:How long is the total lesson time taught by staff with first name as Janessa and last name as Sawayn? | SELECT SUM(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" |
What is average lesson price taught by staff with first name as Janessa and last name as Sawayn? | CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR) | SELECT AVG(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (staff_id VARCHAR, first_name VARCHAR, last_name VARCHAR)
### question:What is average lesson price taught by staff with first name as Janessa and last name as Sawayn? | SELECT AVG(price) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" |
How many lesson does customer with first name Ray took? | CREATE TABLE Customers (customer_id VARCHAR, first_name VARCHAR); CREATE TABLE Lessons (customer_id VARCHAR) | SELECT COUNT(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Ray" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Customers (customer_id VARCHAR, first_name VARCHAR); CREATE TABLE Lessons (customer_id VARCHAR)
### question:How many lesson does customer with first name Ray took? | SELECT COUNT(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Ray" |
Which last names are both used by customers and by staff? | CREATE TABLE Customers (last_name VARCHAR); CREATE TABLE Staff (last_name VARCHAR) | SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Customers (last_name VARCHAR); CREATE TABLE Staff (last_name VARCHAR)
### question:Which last names are both used by customers and by staff? | SELECT last_name FROM Customers INTERSECT SELECT last_name FROM Staff |
What is the first name of the staff who did not give any lesson? | CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (first_name VARCHAR); CREATE TABLE Staff (first_name VARCHAR, staff_id VARCHAR) | SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (staff_id VARCHAR); CREATE TABLE Staff (first_name VARCHAR); CREATE TABLE Staff (first_name VARCHAR, staff_id VARCHAR)
### question:What is the first name of the staff who did not give any lesson? | SELECT first_name FROM Staff EXCEPT SELECT T2.first_name FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id |
What is the id and detail of the vehicle used in lessons for most of the times? | CREATE TABLE Lessons (vehicle_id VARCHAR); CREATE TABLE Vehicles (vehicle_id VARCHAR, vehicle_details VARCHAR) | SELECT T1.vehicle_id, T1.vehicle_details FROM Vehicles AS T1 JOIN Lessons AS T2 ON T1.vehicle_id = T2.vehicle_id GROUP BY T1.vehicle_id ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Lessons (vehicle_id VARCHAR); CREATE TABLE Vehicles (vehicle_id VARCHAR, vehicle_details VARCHAR)
### question:What is the id and detail of the vehicle used in lessons for most of the times? | SELECT T1.vehicle_id, T1.vehicle_details FROM Vehicles AS T1 JOIN Lessons AS T2 ON T1.vehicle_id = T2.vehicle_id GROUP BY T1.vehicle_id ORDER BY COUNT(*) DESC LIMIT 1 |
How many faculty do we have? | CREATE TABLE Faculty (Id VARCHAR) | SELECT COUNT(*) FROM Faculty | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (Id VARCHAR)
### question:How many faculty do we have? | SELECT COUNT(*) FROM Faculty |
What ranks do we have for faculty? | CREATE TABLE Faculty (rank VARCHAR) | SELECT DISTINCT rank FROM Faculty | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (rank VARCHAR)
### question:What ranks do we have for faculty? | SELECT DISTINCT rank FROM Faculty |
Show all the distinct buildings that have faculty rooms. | CREATE TABLE Faculty (building VARCHAR) | SELECT DISTINCT building FROM Faculty | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (building VARCHAR)
### question:Show all the distinct buildings that have faculty rooms. | SELECT DISTINCT building FROM Faculty |
Show the rank, first name, and last name for all the faculty. | CREATE TABLE Faculty (rank VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT rank, Fname, Lname FROM Faculty | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (rank VARCHAR, Fname VARCHAR, Lname VARCHAR)
### question:Show the rank, first name, and last name for all the faculty. | SELECT rank, Fname, Lname FROM Faculty |
Show the first name, last name, and phone number for all female faculty members. | CREATE TABLE Faculty (Fname VARCHAR, Lname VARCHAR, phone VARCHAR, Sex VARCHAR) | SELECT Fname, Lname, phone FROM Faculty WHERE Sex = 'F' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (Fname VARCHAR, Lname VARCHAR, phone VARCHAR, Sex VARCHAR)
### question:Show the first name, last name, and phone number for all female faculty members. | SELECT Fname, Lname, phone FROM Faculty WHERE Sex = 'F' |
Show ids for all the male faculty. | CREATE TABLE Faculty (FacID VARCHAR, Sex VARCHAR) | SELECT FacID FROM Faculty WHERE Sex = 'M' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR, Sex VARCHAR)
### question:Show ids for all the male faculty. | SELECT FacID FROM Faculty WHERE Sex = 'M' |
How many female Professors do we have? | CREATE TABLE Faculty (Sex VARCHAR, Rank VARCHAR) | SELECT COUNT(*) FROM Faculty WHERE Sex = 'F' AND Rank = "Professor" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (Sex VARCHAR, Rank VARCHAR)
### question:How many female Professors do we have? | SELECT COUNT(*) FROM Faculty WHERE Sex = 'F' AND Rank = "Professor" |
Show the phone, room, and building for the faculty named Jerry Prince. | CREATE TABLE Faculty (phone VARCHAR, room VARCHAR, building VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT phone, room, building FROM Faculty WHERE Fname = "Jerry" AND Lname = "Prince" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (phone VARCHAR, room VARCHAR, building VARCHAR, Fname VARCHAR, Lname VARCHAR)
### question:Show the phone, room, and building for the faculty named Jerry Prince. | SELECT phone, room, building FROM Faculty WHERE Fname = "Jerry" AND Lname = "Prince" |
How many Professors are in building NEB? | CREATE TABLE Faculty (Rank VARCHAR, building VARCHAR) | SELECT COUNT(*) FROM Faculty WHERE Rank = "Professor" AND building = "NEB" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (Rank VARCHAR, building VARCHAR)
### question:How many Professors are in building NEB? | SELECT COUNT(*) FROM Faculty WHERE Rank = "Professor" AND building = "NEB" |
Show the first name and last name for all the instructors. | CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, Rank VARCHAR) | SELECT fname, lname FROM Faculty WHERE Rank = "Instructor" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, Rank VARCHAR)
### question:Show the first name and last name for all the instructors. | SELECT fname, lname FROM Faculty WHERE Rank = "Instructor" |
Show all the buildings along with the number of faculty members the buildings have. | CREATE TABLE Faculty (building VARCHAR) | SELECT building, COUNT(*) FROM Faculty GROUP BY building | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (building VARCHAR)
### question:Show all the buildings along with the number of faculty members the buildings have. | SELECT building, COUNT(*) FROM Faculty GROUP BY building |
Which building has most faculty members? | CREATE TABLE Faculty (building VARCHAR) | SELECT building FROM Faculty GROUP BY building ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (building VARCHAR)
### question:Which building has most faculty members? | SELECT building FROM Faculty GROUP BY building ORDER BY COUNT(*) DESC LIMIT 1 |
Show all the buildings that have at least 10 professors. | CREATE TABLE Faculty (building VARCHAR, rank VARCHAR) | SELECT building FROM Faculty WHERE rank = "Professor" GROUP BY building HAVING COUNT(*) >= 10 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (building VARCHAR, rank VARCHAR)
### question:Show all the buildings that have at least 10 professors. | SELECT building FROM Faculty WHERE rank = "Professor" GROUP BY building HAVING COUNT(*) >= 10 |
For each faculty rank, show the number of faculty members who have it. | CREATE TABLE Faculty (rank VARCHAR) | SELECT rank, COUNT(*) FROM Faculty GROUP BY rank | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (rank VARCHAR)
### question:For each faculty rank, show the number of faculty members who have it. | SELECT rank, COUNT(*) FROM Faculty GROUP BY rank |
Show all the ranks and the number of male and female faculty for each rank. | CREATE TABLE Faculty (rank VARCHAR, sex VARCHAR) | SELECT rank, sex, COUNT(*) FROM Faculty GROUP BY rank, sex | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (rank VARCHAR, sex VARCHAR)
### question:Show all the ranks and the number of male and female faculty for each rank. | SELECT rank, sex, COUNT(*) FROM Faculty GROUP BY rank, sex |
Which rank has the smallest number of faculty members? | CREATE TABLE Faculty (rank VARCHAR) | SELECT rank FROM Faculty GROUP BY rank ORDER BY COUNT(*) LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (rank VARCHAR)
### question:Which rank has the smallest number of faculty members? | SELECT rank FROM Faculty GROUP BY rank ORDER BY COUNT(*) LIMIT 1 |
Show the number of male and female assistant professors. | CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR) | SELECT sex, COUNT(*) FROM Faculty WHERE rank = "AsstProf" GROUP BY sex | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (sex VARCHAR, rank VARCHAR)
### question:Show the number of male and female assistant professors. | SELECT sex, COUNT(*) FROM Faculty WHERE rank = "AsstProf" GROUP BY sex |
What are the first name and last name of Linda Smith's advisor? | CREATE TABLE Student (advisor VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR) | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T2.fname = "Linda" AND T2.lname = "Smith" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (advisor VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR)
### question:What are the first name and last name of Linda Smith's advisor? | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T2.fname = "Linda" AND T2.lname = "Smith" |
Show the ids of students whose advisors are professors. | CREATE TABLE Student (StuID VARCHAR, advisor VARCHAR); CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR) | SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.rank = "Professor" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (StuID VARCHAR, advisor VARCHAR); CREATE TABLE Faculty (FacID VARCHAR, rank VARCHAR)
### question:Show the ids of students whose advisors are professors. | SELECT T2.StuID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.rank = "Professor" |
Show first name and last name for all the students advised by Michael Goodrich. | CREATE TABLE Faculty (FacID VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Student (fname VARCHAR, lname VARCHAR, advisor VARCHAR) | SELECT T2.fname, T2.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.fname = "Michael" AND T1.lname = "Goodrich" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Student (fname VARCHAR, lname VARCHAR, advisor VARCHAR)
### question:Show first name and last name for all the students advised by Michael Goodrich. | SELECT T2.fname, T2.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor WHERE T1.fname = "Michael" AND T1.lname = "Goodrich" |
Show the faculty id of each faculty member, along with the number of students he or she advises. | CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Student (advisor VARCHAR) | SELECT T1.FacID, COUNT(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Student (advisor VARCHAR)
### question:Show the faculty id of each faculty member, along with the number of students he or she advises. | SELECT T1.FacID, COUNT(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID |
Show all the faculty ranks and the number of students advised by each rank. | CREATE TABLE Student (advisor VARCHAR); CREATE TABLE Faculty (rank VARCHAR, FacID VARCHAR) | SELECT T1.rank, COUNT(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.rank | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (advisor VARCHAR); CREATE TABLE Faculty (rank VARCHAR, FacID VARCHAR)
### question:Show all the faculty ranks and the number of students advised by each rank. | SELECT T1.rank, COUNT(*) FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.rank |
What are the first and last name of the faculty who has the most students? | CREATE TABLE Student (advisor VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR) | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (advisor VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR)
### question:What are the first and last name of the faculty who has the most students? | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID ORDER BY COUNT(*) DESC LIMIT 1 |
Show the ids for all the faculty members who have at least 2 students. | CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Student (advisor VARCHAR) | SELECT T1.FacID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID HAVING COUNT(*) >= 2 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Student (advisor VARCHAR)
### question:Show the ids for all the faculty members who have at least 2 students. | SELECT T1.FacID FROM Faculty AS T1 JOIN Student AS T2 ON T1.FacID = T2.advisor GROUP BY T1.FacID HAVING COUNT(*) >= 2 |
Show ids for the faculty members who don't advise any student. | CREATE TABLE Faculty (FacID VARCHAR, advisor VARCHAR); CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR) | SELECT FacID FROM Faculty EXCEPT SELECT advisor FROM Student | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR, advisor VARCHAR); CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR)
### question:Show ids for the faculty members who don't advise any student. | SELECT FacID FROM Faculty EXCEPT SELECT advisor FROM Student |
What activities do we have? | CREATE TABLE Activity (activity_name VARCHAR) | SELECT activity_name FROM Activity | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Activity (activity_name VARCHAR)
### question:What activities do we have? | SELECT activity_name FROM Activity |
How many activities do we have? | CREATE TABLE Activity (Id VARCHAR) | SELECT COUNT(*) FROM Activity | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Activity (Id VARCHAR)
### question:How many activities do we have? | SELECT COUNT(*) FROM Activity |
How many faculty members participate in an activity? | CREATE TABLE Faculty_participates_in (FacID VARCHAR) | SELECT COUNT(DISTINCT FacID) FROM Faculty_participates_in | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (FacID VARCHAR)
### question:How many faculty members participate in an activity? | SELECT COUNT(DISTINCT FacID) FROM Faculty_participates_in |
Show the ids of the faculty who don't participate in any activity. | CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Faculty_participates_in (FacID VARCHAR) | SELECT FacID FROM Faculty EXCEPT SELECT FacID FROM Faculty_participates_in | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty (FacID VARCHAR); CREATE TABLE Faculty_participates_in (FacID VARCHAR)
### question:Show the ids of the faculty who don't participate in any activity. | SELECT FacID FROM Faculty EXCEPT SELECT FacID FROM Faculty_participates_in |
Show the ids of all the faculty members who participate in an activity and advise a student. | CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR); CREATE TABLE Faculty_participates_in (FacID VARCHAR, advisor VARCHAR) | SELECT FacID FROM Faculty_participates_in INTERSECT SELECT advisor FROM Student | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (FacID VARCHAR, advisor VARCHAR); CREATE TABLE Faculty_participates_in (FacID VARCHAR, advisor VARCHAR)
### question:Show the ids of all the faculty members who participate in an activity and advise a student. | SELECT FacID FROM Faculty_participates_in INTERSECT SELECT advisor FROM Student |
How many activities does Mark Giuliano participate in? | CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (facID VARCHAR, fname VARCHAR, lname VARCHAR) | SELECT COUNT(*) FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID WHERE T1.fname = "Mark" AND T1.lname = "Giuliano" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (facID VARCHAR, fname VARCHAR, lname VARCHAR)
### question:How many activities does Mark Giuliano participate in? | SELECT COUNT(*) FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID WHERE T1.fname = "Mark" AND T1.lname = "Giuliano" |
Show the names of all the activities Mark Giuliano participates in. | CREATE TABLE Activity (activity_name VARCHAR, actid VARCHAR); CREATE TABLE Faculty (facID VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR) | SELECT T3.activity_name FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN Activity AS T3 ON T3.actid = T2.actid WHERE T1.fname = "Mark" AND T1.lname = "Giuliano" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Activity (activity_name VARCHAR, actid VARCHAR); CREATE TABLE Faculty (facID VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR)
### question:Show the names of all the activities Mark Giuliano participates in. | SELECT T3.activity_name FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN Activity AS T3 ON T3.actid = T2.actid WHERE T1.fname = "Mark" AND T1.lname = "Giuliano" |
Show the first and last name of all the faculty members who participated in some activity, together with the number of activities they participated in. | CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR, facID VARCHAR) | SELECT T1.fname, T1.lname, COUNT(*), T1.FacID FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID GROUP BY T1.FacID | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR, facID VARCHAR)
### question:Show the first and last name of all the faculty members who participated in some activity, together with the number of activities they participated in. | SELECT T1.fname, T1.lname, COUNT(*), T1.FacID FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID GROUP BY T1.FacID |
Show all the activity names and the number of faculty involved in each activity. | CREATE TABLE Faculty_participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR) | SELECT T1.activity_name, COUNT(*) FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR)
### question:Show all the activity names and the number of faculty involved in each activity. | SELECT T1.activity_name, COUNT(*) FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID |
What is the first and last name of the faculty participating in the most activities? | CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR, facID VARCHAR) | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID GROUP BY T1.FacID ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (facID VARCHAR); CREATE TABLE Faculty (fname VARCHAR, lname VARCHAR, FacID VARCHAR, facID VARCHAR)
### question:What is the first and last name of the faculty participating in the most activities? | SELECT T1.fname, T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID GROUP BY T1.FacID ORDER BY COUNT(*) DESC LIMIT 1 |
What is the name of the activity that has the most faculty members involved in? | CREATE TABLE Faculty_participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR) | SELECT T1.activity_name FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Faculty_participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR)
### question:What is the name of the activity that has the most faculty members involved in? | SELECT T1.activity_name FROM Activity AS T1 JOIN Faculty_participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1 |
Show the ids of the students who don't participate in any activity. | CREATE TABLE Participates_in (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Participates_in | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Participates_in (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
### question:Show the ids of the students who don't participate in any activity. | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Participates_in |
Show the ids for all the students who participate in an activity and are under 20. | CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Participates_in (StuID VARCHAR, age INTEGER) | SELECT StuID FROM Participates_in INTERSECT SELECT StuID FROM Student WHERE age < 20 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Participates_in (StuID VARCHAR, age INTEGER)
### question:Show the ids for all the students who participate in an activity and are under 20. | SELECT StuID FROM Participates_in INTERSECT SELECT StuID FROM Student WHERE age < 20 |
What is the first and last name of the student participating in the most activities? | CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Participates_in (StuID VARCHAR) | SELECT T1.fname, T1.lname FROM Student AS T1 JOIN Participates_in AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Student (fname VARCHAR, lname VARCHAR, StuID VARCHAR); CREATE TABLE Participates_in (StuID VARCHAR)
### question:What is the first and last name of the student participating in the most activities? | SELECT T1.fname, T1.lname FROM Student AS T1 JOIN Participates_in AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1 |
What is the name of the activity with the most students? | CREATE TABLE Participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR) | SELECT T1.activity_name FROM Activity AS T1 JOIN Participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE Participates_in (actID VARCHAR); CREATE TABLE Activity (activity_name VARCHAR, actID VARCHAR)
### question:What is the name of the activity with the most students? | SELECT T1.activity_name FROM Activity AS T1 JOIN Participates_in AS T2 ON T1.actID = T2.actID GROUP BY T1.actID ORDER BY COUNT(*) DESC LIMIT 1 |
Find the first names of the faculty members who are playing Canoeing or Kayaking. | CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR) | SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR)
### question:Find the first names of the faculty members who are playing Canoeing or Kayaking. | SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking' |
Find the first names of professors who are not playing Canoeing or Kayaking. | CREATE TABLE faculty (lname VARCHAR, rank VARCHAR); CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR) | SELECT lname FROM faculty WHERE rank = 'Professor' EXCEPT SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE faculty (lname VARCHAR, rank VARCHAR); CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR)
### question:Find the first names of professors who are not playing Canoeing or Kayaking. | SELECT lname FROM faculty WHERE rank = 'Professor' EXCEPT SELECT DISTINCT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' OR T3.activity_name = 'Kayaking' |
Find the first names of the faculty members who participate in Canoeing and Kayaking. | CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR) | SELECT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' INTERSECT SELECT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Kayaking' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE activity (activity_name VARCHAR); CREATE TABLE Faculty_participates_in (facID VARCHAR, actid VARCHAR); CREATE TABLE Faculty (lname VARCHAR, facID VARCHAR)
### question:Find the first names of the faculty members who participate in Canoeing and Kayaking. | SELECT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Canoeing' INTERSECT SELECT T1.lname FROM Faculty AS T1 JOIN Faculty_participates_in AS T2 ON T1.facID = T2.facID JOIN activity AS T3 ON T2.actid = T2.actid WHERE T3.activity_name = 'Kayaking' |
Find the ids of the students who participate in Canoeing and Kayaking. | CREATE TABLE activity (actid VARCHAR, activity_name VARCHAR); CREATE TABLE participates_in (stuid VARCHAR) | SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Canoeing' INTERSECT SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Kayaking' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE activity (actid VARCHAR, activity_name VARCHAR); CREATE TABLE participates_in (stuid VARCHAR)
### question:Find the ids of the students who participate in Canoeing and Kayaking. | SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Canoeing' INTERSECT SELECT T1.stuid FROM participates_in AS T1 JOIN activity AS T2 ON T2.actid = T2.actid WHERE T2.activity_name = 'Kayaking' |
Find the name of the airport in the city of Goroka. | CREATE TABLE airports (name VARCHAR, city VARCHAR) | SELECT name FROM airports WHERE city = 'Goroka' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR)
### question:Find the name of the airport in the city of Goroka. | SELECT name FROM airports WHERE city = 'Goroka' |
Find the name, city, country, and altitude (or elevation) of the airports in the city of New York. | CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR) | SELECT name, city, country, elevation FROM airports WHERE city = 'New York' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
### question:Find the name, city, country, and altitude (or elevation) of the airports in the city of New York. | SELECT name, city, country, elevation FROM airports WHERE city = 'New York' |
How many airlines are there? | CREATE TABLE airlines (Id VARCHAR) | SELECT COUNT(*) FROM airlines | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (Id VARCHAR)
### question:How many airlines are there? | SELECT COUNT(*) FROM airlines |
How many airlines does Russia has? | CREATE TABLE airlines (country VARCHAR) | SELECT COUNT(*) FROM airlines WHERE country = 'Russia' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR)
### question:How many airlines does Russia has? | SELECT COUNT(*) FROM airlines WHERE country = 'Russia' |
What is the maximum elevation of all airports in the country of Iceland? | CREATE TABLE airports (elevation INTEGER, country VARCHAR) | SELECT MAX(elevation) FROM airports WHERE country = 'Iceland' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (elevation INTEGER, country VARCHAR)
### question:What is the maximum elevation of all airports in the country of Iceland? | SELECT MAX(elevation) FROM airports WHERE country = 'Iceland' |
Find the name of the airports located in Cuba or Argentina. | CREATE TABLE airports (name VARCHAR, country VARCHAR) | SELECT name FROM airports WHERE country = 'Cuba' OR country = 'Argentina' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, country VARCHAR)
### question:Find the name of the airports located in Cuba or Argentina. | SELECT name FROM airports WHERE country = 'Cuba' OR country = 'Argentina' |
Find the country of the airlines whose name starts with 'Orbit'. | CREATE TABLE airlines (country VARCHAR, name VARCHAR) | SELECT country FROM airlines WHERE name LIKE 'Orbit%' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR, name VARCHAR)
### question:Find the country of the airlines whose name starts with 'Orbit'. | SELECT country FROM airlines WHERE name LIKE 'Orbit%' |
Find the name of airports whose altitude is between -50 and 50. | CREATE TABLE airports (name VARCHAR, elevation INTEGER) | SELECT name FROM airports WHERE elevation BETWEEN -50 AND 50 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, elevation INTEGER)
### question:Find the name of airports whose altitude is between -50 and 50. | SELECT name FROM airports WHERE elevation BETWEEN -50 AND 50 |
Which country is the airport that has the highest altitude located in? | CREATE TABLE airports (country VARCHAR, elevation VARCHAR) | SELECT country FROM airports ORDER BY elevation DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (country VARCHAR, elevation VARCHAR)
### question:Which country is the airport that has the highest altitude located in? | SELECT country FROM airports ORDER BY elevation DESC LIMIT 1 |
Find the number of airports whose name contain the word 'International'. | CREATE TABLE airports (name VARCHAR) | SELECT COUNT(*) FROM airports WHERE name LIKE '%International%' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR)
### question:Find the number of airports whose name contain the word 'International'. | SELECT COUNT(*) FROM airports WHERE name LIKE '%International%' |
How many different cities do have some airport in the country of Greenland? | CREATE TABLE airports (city VARCHAR, country VARCHAR) | SELECT COUNT(DISTINCT city) FROM airports WHERE country = 'Greenland' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR, country VARCHAR)
### question:How many different cities do have some airport in the country of Greenland? | SELECT COUNT(DISTINCT city) FROM airports WHERE country = 'Greenland' |
Find the number of routes operated by American Airlines. | CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR) | SELECT COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
### question:Find the number of routes operated by American Airlines. | SELECT COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines' |
Find the number of routes whose destination airports are in Canada. | CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR) | SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE country = 'Canada' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR)
### question:Find the number of routes whose destination airports are in Canada. | SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE country = 'Canada' |
Find the name, city, and country of the airport that has the lowest altitude. | CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR) | SELECT name, city, country FROM airports ORDER BY elevation LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
### question:Find the name, city, and country of the airport that has the lowest altitude. | SELECT name, city, country FROM airports ORDER BY elevation LIMIT 1 |
Find the name, city, and country of the airport that has the highest latitude. | CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR) | SELECT name, city, country FROM airports ORDER BY elevation DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR, country VARCHAR, elevation VARCHAR)
### question:Find the name, city, and country of the airport that has the highest latitude. | SELECT name, city, country FROM airports ORDER BY elevation DESC LIMIT 1 |
Find the name and city of the airport which is the destination of the most number of routes. | CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (dst_apid VARCHAR) | SELECT T1.name, T1.city, T2.dst_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid GROUP BY T2.dst_apid ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (dst_apid VARCHAR)
### question:Find the name and city of the airport which is the destination of the most number of routes. | SELECT T1.name, T1.city, T2.dst_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid GROUP BY T2.dst_apid ORDER BY COUNT(*) DESC LIMIT 1 |
Find the names of the top 10 airlines that operate the most number of routes. | CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR) | SELECT T1.name, T2.alid FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T2.alid ORDER BY COUNT(*) DESC LIMIT 10 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
### question:Find the names of the top 10 airlines that operate the most number of routes. | SELECT T1.name, T2.alid FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T2.alid ORDER BY COUNT(*) DESC LIMIT 10 |
Find the name and city of the airport which is the source for the most number of flight routes. | CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR) | SELECT T1.name, T1.city, T2.src_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T2.src_apid ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, city VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
### question:Find the name and city of the airport which is the source for the most number of flight routes. | SELECT T1.name, T1.city, T2.src_apid FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T2.src_apid ORDER BY COUNT(*) DESC LIMIT 1 |
Find the number of different airports which are the destinations of the American Airlines. | CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR) | SELECT COUNT(DISTINCT dst_apid) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (alid VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
### question:Find the number of different airports which are the destinations of the American Airlines. | SELECT COUNT(DISTINCT dst_apid) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid WHERE T1.name = 'American Airlines' |
Which countries has the most number of airlines? | CREATE TABLE airlines (country VARCHAR) | SELECT country FROM airlines GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR)
### question:Which countries has the most number of airlines? | SELECT country FROM airlines GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1 |
Which countries has the most number of airlines whose active status is 'Y'? | CREATE TABLE airlines (country VARCHAR, active VARCHAR) | SELECT country FROM airlines WHERE active = 'Y' GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR, active VARCHAR)
### question:Which countries has the most number of airlines whose active status is 'Y'? | SELECT country FROM airlines WHERE active = 'Y' GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1 |
List all countries and their number of airlines in the descending order of number of airlines. | CREATE TABLE airlines (country VARCHAR) | SELECT country, COUNT(*) FROM airlines GROUP BY country ORDER BY COUNT(*) DESC | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR)
### question:List all countries and their number of airlines in the descending order of number of airlines. | SELECT country, COUNT(*) FROM airlines GROUP BY country ORDER BY COUNT(*) DESC |
How many airports are there per country? Order the countries by decreasing number of airports. | CREATE TABLE airports (country VARCHAR) | SELECT COUNT(*), country FROM airports GROUP BY country ORDER BY COUNT(*) DESC | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (country VARCHAR)
### question:How many airports are there per country? Order the countries by decreasing number of airports. | SELECT COUNT(*), country FROM airports GROUP BY country ORDER BY COUNT(*) DESC |
How many airports are there per city in the United States? Order the cities by decreasing number of airports. | CREATE TABLE airports (city VARCHAR, country VARCHAR) | SELECT COUNT(*), city FROM airports WHERE country = 'United States' GROUP BY city ORDER BY COUNT(*) DESC | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR, country VARCHAR)
### question:How many airports are there per city in the United States? Order the cities by decreasing number of airports. | SELECT COUNT(*), city FROM airports WHERE country = 'United States' GROUP BY city ORDER BY COUNT(*) DESC |
Return the cities with more than 3 airports in the United States. | CREATE TABLE airports (city VARCHAR, country VARCHAR) | SELECT city FROM airports WHERE country = 'United States' GROUP BY city HAVING COUNT(*) > 3 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR, country VARCHAR)
### question:Return the cities with more than 3 airports in the United States. | SELECT city FROM airports WHERE country = 'United States' GROUP BY city HAVING COUNT(*) > 3 |
How many cities are there that have more than 3 airports? | CREATE TABLE airports (city VARCHAR) | SELECT COUNT(*) FROM (SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 3) | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR)
### question:How many cities are there that have more than 3 airports? | SELECT COUNT(*) FROM (SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 3) |
List the cities which have more than one airport and number of airports. | CREATE TABLE airports (city VARCHAR) | SELECT city, COUNT(*) FROM airports GROUP BY city HAVING COUNT(*) > 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR)
### question:List the cities which have more than one airport and number of airports. | SELECT city, COUNT(*) FROM airports GROUP BY city HAVING COUNT(*) > 1 |
List the cities which have more than 2 airports sorted by the number of airports. | CREATE TABLE airports (city VARCHAR) | SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 2 ORDER BY COUNT(*) | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR)
### question:List the cities which have more than 2 airports sorted by the number of airports. | SELECT city FROM airports GROUP BY city HAVING COUNT(*) > 2 ORDER BY COUNT(*) |
Find the number of routes for each source airport and the airport name. | CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR) | SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
### question:Find the number of routes for each source airport and the airport name. | SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name |
Find the number of routes and airport name for each source airport, order the results by decreasing number of routes. | CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR) | SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name ORDER BY COUNT(*) DESC | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (name VARCHAR, apid VARCHAR); CREATE TABLE routes (src_apid VARCHAR)
### question:Find the number of routes and airport name for each source airport, order the results by decreasing number of routes. | SELECT COUNT(*), T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid GROUP BY T1.name ORDER BY COUNT(*) DESC |
Find the average elevation of all airports for each country. | CREATE TABLE airports (country VARCHAR, elevation INTEGER) | SELECT AVG(elevation), country FROM airports GROUP BY country | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (country VARCHAR, elevation INTEGER)
### question:Find the average elevation of all airports for each country. | SELECT AVG(elevation), country FROM airports GROUP BY country |
Find the cities which have exactly two airports. | CREATE TABLE airports (city VARCHAR) | SELECT city FROM airports GROUP BY city HAVING COUNT(*) = 2 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (city VARCHAR)
### question:Find the cities which have exactly two airports. | SELECT city FROM airports GROUP BY city HAVING COUNT(*) = 2 |
For each country and airline name, how many routes are there? | CREATE TABLE airlines (country VARCHAR, name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR) | SELECT T1.country, T1.name, COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.country, T1.name | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (country VARCHAR, name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
### question:For each country and airline name, how many routes are there? | SELECT T1.country, T1.name, COUNT(*) FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.country, T1.name |
Find the number of routes with destination airports in Italy. | CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR) | SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid WHERE T2.country = 'Italy' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR)
### question:Find the number of routes with destination airports in Italy. | SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid WHERE T2.country = 'Italy' |
Return the number of routes with destination airport in Italy operated by the airline with name 'American Airlines'. | CREATE TABLE routes (dst_apid VARCHAR, alid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR) | SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid JOIN airlines AS T3 ON T1.alid = T3.alid WHERE T2.country = 'Italy' AND T3.name = 'American Airlines' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (dst_apid VARCHAR, alid VARCHAR); CREATE TABLE airports (apid VARCHAR, country VARCHAR); CREATE TABLE airlines (alid VARCHAR, name VARCHAR)
### question:Return the number of routes with destination airport in Italy operated by the airline with name 'American Airlines'. | SELECT COUNT(*) FROM routes AS T1 JOIN airports AS T2 ON T1.dst_apid = T2.apid JOIN airlines AS T3 ON T1.alid = T3.alid WHERE T2.country = 'Italy' AND T3.name = 'American Airlines' |
Find the number of routes that have destination John F Kennedy International Airport. | CREATE TABLE airports (apid VARCHAR, name VARCHAR); CREATE TABLE routes (dst_apid VARCHAR) | SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.name = 'John F Kennedy International Airport' | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (apid VARCHAR, name VARCHAR); CREATE TABLE routes (dst_apid VARCHAR)
### question:Find the number of routes that have destination John F Kennedy International Airport. | SELECT COUNT(*) FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.name = 'John F Kennedy International Airport' |
Find the number of routes from the United States to Canada. | CREATE TABLE airports (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE routes (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR) | SELECT COUNT(*) FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'Canada') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States') | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airports (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE routes (dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR)
### question:Find the number of routes from the United States to Canada. | SELECT COUNT(*) FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'Canada') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States') |
Find the id of routes whose source and destination airports are in the United States. | CREATE TABLE routes (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE airports (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR) | SELECT rid FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'United States') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States') | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR); CREATE TABLE airports (rid VARCHAR, dst_apid VARCHAR, src_apid VARCHAR, apid VARCHAR, country VARCHAR)
### question:Find the id of routes whose source and destination airports are in the United States. | SELECT rid FROM routes WHERE dst_apid IN (SELECT apid FROM airports WHERE country = 'United States') AND src_apid IN (SELECT apid FROM airports WHERE country = 'United States') |
Find the name of airline which runs the most number of routes. | CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR) | SELECT T1.name FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE airlines (name VARCHAR, alid VARCHAR); CREATE TABLE routes (alid VARCHAR)
### question:Find the name of airline which runs the most number of routes. | SELECT T1.name FROM airlines AS T1 JOIN routes AS T2 ON T1.alid = T2.alid GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 |
Find the busiest source airport that runs most number of routes in China. | CREATE TABLE routes (src_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR) | SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (src_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR)
### question:Find the busiest source airport that runs most number of routes in China. | SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.src_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 |
Find the busiest destination airport that runs most number of routes in China. | CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR) | SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE routes (dst_apid VARCHAR); CREATE TABLE airports (name VARCHAR, apid VARCHAR, country VARCHAR)
### question:Find the busiest destination airport that runs most number of routes in China. | SELECT T1.name FROM airports AS T1 JOIN routes AS T2 ON T1.apid = T2.dst_apid WHERE T1.country = 'China' GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 |
What is the id of the most recent order? | CREATE TABLE orders (order_id VARCHAR, date_order_placed VARCHAR) | SELECT order_id FROM orders ORDER BY date_order_placed DESC LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE orders (order_id VARCHAR, date_order_placed VARCHAR)
### question:What is the id of the most recent order? | SELECT order_id FROM orders ORDER BY date_order_placed DESC LIMIT 1 |
what are the order id and customer id of the oldest order? | CREATE TABLE orders (order_id VARCHAR, customer_id VARCHAR, date_order_placed VARCHAR) | SELECT order_id, customer_id FROM orders ORDER BY date_order_placed LIMIT 1 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE orders (order_id VARCHAR, customer_id VARCHAR, date_order_placed VARCHAR)
### question:what are the order id and customer id of the oldest order? | SELECT order_id, customer_id FROM orders ORDER BY date_order_placed LIMIT 1 |
Find the id of the order whose shipment tracking number is "3452". | CREATE TABLE shipments (order_id VARCHAR, shipment_tracking_number VARCHAR) | SELECT order_id FROM shipments WHERE shipment_tracking_number = "3452" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE shipments (order_id VARCHAR, shipment_tracking_number VARCHAR)
### question:Find the id of the order whose shipment tracking number is "3452". | SELECT order_id FROM shipments WHERE shipment_tracking_number = "3452" |
Find the ids of all the order items whose product id is 11. | CREATE TABLE order_items (order_item_id VARCHAR, product_id VARCHAR) | SELECT order_item_id FROM order_items WHERE product_id = 11 | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE order_items (order_item_id VARCHAR, product_id VARCHAR)
### question:Find the ids of all the order items whose product id is 11. | SELECT order_item_id FROM order_items WHERE product_id = 11 |
List the name of all the distinct customers who have orders with status "Packing". | CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) | SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Packing" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
### question:List the name of all the distinct customers who have orders with status "Packing". | SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Packing" |
Find the details of all the distinct customers who have orders with status "On Road". | CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR) | SELECT DISTINCT T1.customer_details FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" | Translate the question into SQL query by using the schema.
### schema:CREATE TABLE orders (customer_id VARCHAR, order_status VARCHAR); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR)
### question:Find the details of all the distinct customers who have orders with status "On Road". | SELECT DISTINCT T1.customer_details FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" |