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Show gas station id, location, and manager_name for all gas stations ordered by open year.
CREATE TABLE gas_station (station_id VARCHAR, LOCATION VARCHAR, manager_name VARCHAR, open_year VARCHAR)
SELECT station_id, LOCATION, manager_name FROM gas_station ORDER BY open_year
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (station_id VARCHAR, LOCATION VARCHAR, manager_name VARCHAR, open_year VARCHAR) ### question:Show gas station id, location, and manager_name for all gas stations ordered by open year.
SELECT station_id, LOCATION, manager_name FROM gas_station ORDER BY open_year
How many gas station are opened between 2000 and 2005?
CREATE TABLE gas_station (open_year INTEGER)
SELECT COUNT(*) FROM gas_station WHERE open_year BETWEEN 2000 AND 2005
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (open_year INTEGER) ### question:How many gas station are opened between 2000 and 2005?
SELECT COUNT(*) FROM gas_station WHERE open_year BETWEEN 2000 AND 2005
Show all locations and the number of gas stations in each location ordered by the count.
CREATE TABLE gas_station (LOCATION VARCHAR)
SELECT LOCATION, COUNT(*) FROM gas_station GROUP BY LOCATION ORDER BY COUNT(*)
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (LOCATION VARCHAR) ### question:Show all locations and the number of gas stations in each location ordered by the count.
SELECT LOCATION, COUNT(*) FROM gas_station GROUP BY LOCATION ORDER BY COUNT(*)
Show all headquarters with both a company in banking industry and a company in Oil and gas.
CREATE TABLE company (headquarters VARCHAR, main_industry VARCHAR)
SELECT headquarters FROM company WHERE main_industry = 'Banking' INTERSECT SELECT headquarters FROM company WHERE main_industry = 'Oil and gas'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE company (headquarters VARCHAR, main_industry VARCHAR) ### question:Show all headquarters with both a company in banking industry and a company in Oil and gas.
SELECT headquarters FROM company WHERE main_industry = 'Banking' INTERSECT SELECT headquarters FROM company WHERE main_industry = 'Oil and gas'
Show all headquarters without a company in banking industry.
CREATE TABLE company (headquarters VARCHAR, main_industry VARCHAR)
SELECT headquarters FROM company EXCEPT SELECT headquarters FROM company WHERE main_industry = 'Banking'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE company (headquarters VARCHAR, main_industry VARCHAR) ### question:Show all headquarters without a company in banking industry.
SELECT headquarters FROM company EXCEPT SELECT headquarters FROM company WHERE main_industry = 'Banking'
Show the company name with the number of gas station.
CREATE TABLE station_company (company_id VARCHAR); CREATE TABLE company (company VARCHAR, company_id VARCHAR)
SELECT T2.company, COUNT(*) FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id GROUP BY T1.company_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE station_company (company_id VARCHAR); CREATE TABLE company (company VARCHAR, company_id VARCHAR) ### question:Show the company name with the number of gas station.
SELECT T2.company, COUNT(*) FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id GROUP BY T1.company_id
Show company name and main industry without a gas station.
CREATE TABLE station_company (company VARCHAR, main_industry VARCHAR, company_id VARCHAR); CREATE TABLE company (company VARCHAR, main_industry VARCHAR, company_id VARCHAR)
SELECT company, main_industry FROM company WHERE NOT company_id IN (SELECT company_id FROM station_company)
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE station_company (company VARCHAR, main_industry VARCHAR, company_id VARCHAR); CREATE TABLE company (company VARCHAR, main_industry VARCHAR, company_id VARCHAR) ### question:Show company name and main industry without a gas station.
SELECT company, main_industry FROM company WHERE NOT company_id IN (SELECT company_id FROM station_company)
Show the manager name for gas stations belonging to the ExxonMobil company.
CREATE TABLE gas_station (manager_name VARCHAR, station_id VARCHAR); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, company VARCHAR)
SELECT T3.manager_name FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id WHERE T2.company = 'ExxonMobil'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (manager_name VARCHAR, station_id VARCHAR); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, company VARCHAR) ### question:Show the manager name for gas stations belonging to the ExxonMobil company.
SELECT T3.manager_name FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id WHERE T2.company = 'ExxonMobil'
Show all locations where a gas station for company with market value greater than 100 is located.
CREATE TABLE gas_station (location VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, market_value INTEGER); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR)
SELECT T3.location FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id WHERE T2.market_value > 100
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (location VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, market_value INTEGER); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR) ### question:Show all locations where a gas station for company with market value greater than 100 is located.
SELECT T3.location FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id WHERE T2.market_value > 100
Show the manager name with most number of gas stations opened after 2000.
CREATE TABLE gas_station (manager_name VARCHAR, open_year INTEGER)
SELECT manager_name FROM gas_station WHERE open_year > 2000 GROUP BY manager_name ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (manager_name VARCHAR, open_year INTEGER) ### question:Show the manager name with most number of gas stations opened after 2000.
SELECT manager_name FROM gas_station WHERE open_year > 2000 GROUP BY manager_name ORDER BY COUNT(*) DESC LIMIT 1
order all gas station locations by the opening year.
CREATE TABLE gas_station (LOCATION VARCHAR, open_year VARCHAR)
SELECT LOCATION FROM gas_station ORDER BY open_year
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (LOCATION VARCHAR, open_year VARCHAR) ### question:order all gas station locations by the opening year.
SELECT LOCATION FROM gas_station ORDER BY open_year
find the rank, company names, market values of the companies in the banking industry order by their sales and profits in billion.
CREATE TABLE company (rank VARCHAR, company VARCHAR, market_value VARCHAR, main_industry VARCHAR, sales_billion VARCHAR, profits_billion VARCHAR)
SELECT rank, company, market_value FROM company WHERE main_industry = 'Banking' ORDER BY sales_billion, profits_billion
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE company (rank VARCHAR, company VARCHAR, market_value VARCHAR, main_industry VARCHAR, sales_billion VARCHAR, profits_billion VARCHAR) ### question:find the rank, company names, market values of the companies in the banking industry order by their sales and profits in billion.
SELECT rank, company, market_value FROM company WHERE main_industry = 'Banking' ORDER BY sales_billion, profits_billion
find the location and Representative name of the gas stations owned by the companies with top 3 Asset amounts.
CREATE TABLE gas_station (location VARCHAR, Representative_Name VARCHAR, station_id VARCHAR); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, Assets_billion VARCHAR)
SELECT T3.location, T3.Representative_Name FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id ORDER BY T2.Assets_billion DESC LIMIT 3
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE gas_station (location VARCHAR, Representative_Name VARCHAR, station_id VARCHAR); CREATE TABLE station_company (company_id VARCHAR, station_id VARCHAR); CREATE TABLE company (company_id VARCHAR, Assets_billion VARCHAR) ### question:find the location and Representative name of the gas stations owned by the companies with top 3 Asset amounts.
SELECT T3.location, T3.Representative_Name FROM station_company AS T1 JOIN company AS T2 ON T1.company_id = T2.company_id JOIN gas_station AS T3 ON T1.station_id = T3.station_id ORDER BY T2.Assets_billion DESC LIMIT 3
How many regions do we have?
CREATE TABLE region (Id VARCHAR)
SELECT COUNT(*) FROM region
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE region (Id VARCHAR) ### question:How many regions do we have?
SELECT COUNT(*) FROM region
Show all distinct region names ordered by their labels.
CREATE TABLE region (region_name VARCHAR, Label VARCHAR)
SELECT DISTINCT region_name FROM region ORDER BY Label
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE region (region_name VARCHAR, Label VARCHAR) ### question:Show all distinct region names ordered by their labels.
SELECT DISTINCT region_name FROM region ORDER BY Label
How many parties do we have?
CREATE TABLE party (party_name VARCHAR)
SELECT COUNT(DISTINCT party_name) FROM party
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR) ### question:How many parties do we have?
SELECT COUNT(DISTINCT party_name) FROM party
Show the ministers and the time they took and left office, listed by the time they left office.
CREATE TABLE party (minister VARCHAR, took_office VARCHAR, left_office VARCHAR)
SELECT minister, took_office, left_office FROM party ORDER BY left_office
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (minister VARCHAR, took_office VARCHAR, left_office VARCHAR) ### question:Show the ministers and the time they took and left office, listed by the time they left office.
SELECT minister, took_office, left_office FROM party ORDER BY left_office
Show the minister who took office after 1961 or before 1959.
CREATE TABLE party (minister VARCHAR, took_office VARCHAR)
SELECT minister FROM party WHERE took_office > 1961 OR took_office < 1959
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (minister VARCHAR, took_office VARCHAR) ### question:Show the minister who took office after 1961 or before 1959.
SELECT minister FROM party WHERE took_office > 1961 OR took_office < 1959
Show all ministers who do not belong to Progress Party.
CREATE TABLE party (minister VARCHAR, party_name VARCHAR)
SELECT minister FROM party WHERE party_name <> 'Progress Party'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (minister VARCHAR, party_name VARCHAR) ### question:Show all ministers who do not belong to Progress Party.
SELECT minister FROM party WHERE party_name <> 'Progress Party'
Show all ministers and parties they belong to in descending order of the time they took office.
CREATE TABLE party (minister VARCHAR, party_name VARCHAR, took_office VARCHAR)
SELECT minister, party_name FROM party ORDER BY took_office DESC
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (minister VARCHAR, party_name VARCHAR, took_office VARCHAR) ### question:Show all ministers and parties they belong to in descending order of the time they took office.
SELECT minister, party_name FROM party ORDER BY took_office DESC
Return the minister who left office at the latest time.
CREATE TABLE party (minister VARCHAR, left_office VARCHAR)
SELECT minister FROM party ORDER BY left_office DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (minister VARCHAR, left_office VARCHAR) ### question:Return the minister who left office at the latest time.
SELECT minister FROM party ORDER BY left_office DESC LIMIT 1
List member names and their party names.
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (member_name VARCHAR, party_id VARCHAR)
SELECT T1.member_name, T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (member_name VARCHAR, party_id VARCHAR) ### question:List member names and their party names.
SELECT T1.member_name, T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id
Show all party names and the number of members in each party.
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_id VARCHAR)
SELECT T2.party_name, COUNT(*) FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_id VARCHAR) ### question:Show all party names and the number of members in each party.
SELECT T2.party_name, COUNT(*) FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id
What is the name of party with most number of members?
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_id VARCHAR)
SELECT T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_id VARCHAR) ### question:What is the name of party with most number of members?
SELECT T2.party_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id ORDER BY COUNT(*) DESC LIMIT 1
Show all party names and their region names.
CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE party (party_name VARCHAR, region_id VARCHAR)
SELECT T1.party_name, T2.region_name FROM party AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE party (party_name VARCHAR, region_id VARCHAR) ### question:Show all party names and their region names.
SELECT T1.party_name, T2.region_name FROM party AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id
Show names of parties that does not have any members.
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_name VARCHAR, party_id VARCHAR)
SELECT party_name FROM party WHERE NOT party_id IN (SELECT party_id FROM Member)
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE Member (party_name VARCHAR, party_id VARCHAR) ### question:Show names of parties that does not have any members.
SELECT party_name FROM party WHERE NOT party_id IN (SELECT party_id FROM Member)
Show the member names which are in both the party with id 3 and the party with id 1.
CREATE TABLE member (member_name VARCHAR, party_id VARCHAR)
SELECT member_name FROM member WHERE party_id = 3 INTERSECT SELECT member_name FROM member WHERE party_id = 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE member (member_name VARCHAR, party_id VARCHAR) ### question:Show the member names which are in both the party with id 3 and the party with id 1.
SELECT member_name FROM member WHERE party_id = 3 INTERSECT SELECT member_name FROM member WHERE party_id = 1
Show member names that are not in the Progress Party.
CREATE TABLE party (party_id VARCHAR, Party_name VARCHAR); CREATE TABLE Member (member_name VARCHAR, party_id VARCHAR)
SELECT T1.member_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id WHERE T2.Party_name <> "Progress Party"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_id VARCHAR, Party_name VARCHAR); CREATE TABLE Member (member_name VARCHAR, party_id VARCHAR) ### question:Show member names that are not in the Progress Party.
SELECT T1.member_name FROM Member AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id WHERE T2.Party_name <> "Progress Party"
How many party events do we have?
CREATE TABLE party_events (Id VARCHAR)
SELECT COUNT(*) FROM party_events
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party_events (Id VARCHAR) ### question:How many party events do we have?
SELECT COUNT(*) FROM party_events
Show party names and the number of events for each party.
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE party_events (party_id VARCHAR)
SELECT T2.party_name, COUNT(*) FROM party_events AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE party_events (party_id VARCHAR) ### question:Show party names and the number of events for each party.
SELECT T2.party_name, COUNT(*) FROM party_events AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id
Show all member names who are not in charge of any event.
CREATE TABLE member (member_name VARCHAR); CREATE TABLE party_events (member_in_charge_id VARCHAR); CREATE TABLE member (member_name VARCHAR, member_id VARCHAR)
SELECT member_name FROM member EXCEPT SELECT T1.member_name FROM member AS T1 JOIN party_events AS T2 ON T1.member_id = T2.member_in_charge_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE member (member_name VARCHAR); CREATE TABLE party_events (member_in_charge_id VARCHAR); CREATE TABLE member (member_name VARCHAR, member_id VARCHAR) ### question:Show all member names who are not in charge of any event.
SELECT member_name FROM member EXCEPT SELECT T1.member_name FROM member AS T1 JOIN party_events AS T2 ON T1.member_id = T2.member_in_charge_id
What are the names of parties with at least 2 events?
CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE party_events (party_id VARCHAR)
SELECT T2.party_name FROM party_events AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id HAVING COUNT(*) >= 2
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party (party_name VARCHAR, party_id VARCHAR); CREATE TABLE party_events (party_id VARCHAR) ### question:What are the names of parties with at least 2 events?
SELECT T2.party_name FROM party_events AS T1 JOIN party AS T2 ON T1.party_id = T2.party_id GROUP BY T1.party_id HAVING COUNT(*) >= 2
What is the name of member in charge of greatest number of events?
CREATE TABLE party_events (member_in_charge_id VARCHAR); CREATE TABLE member (member_name VARCHAR, member_id VARCHAR)
SELECT T1.member_name FROM member AS T1 JOIN party_events AS T2 ON T1.member_id = T2.member_in_charge_id GROUP BY T2.member_in_charge_id ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party_events (member_in_charge_id VARCHAR); CREATE TABLE member (member_name VARCHAR, member_id VARCHAR) ### question:What is the name of member in charge of greatest number of events?
SELECT T1.member_name FROM member AS T1 JOIN party_events AS T2 ON T1.member_id = T2.member_in_charge_id GROUP BY T2.member_in_charge_id ORDER BY COUNT(*) DESC LIMIT 1
find the event names that have more than 2 records.
CREATE TABLE party_events (event_name VARCHAR)
SELECT event_name FROM party_events GROUP BY event_name HAVING COUNT(*) > 2
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party_events (event_name VARCHAR) ### question:find the event names that have more than 2 records.
SELECT event_name FROM party_events GROUP BY event_name HAVING COUNT(*) > 2
How many Annual Meeting events happened in the United Kingdom region?
CREATE TABLE party_events (party_id VARCHAR, Event_Name VARCHAR); CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE party (region_id VARCHAR, party_id VARCHAR)
SELECT COUNT(*) FROM region AS t1 JOIN party AS t2 ON t1.region_id = t2.region_id JOIN party_events AS t3 ON t2.party_id = t3.party_id WHERE t1.region_name = "United Kingdom" AND t3.Event_Name = "Annaual Meeting"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE party_events (party_id VARCHAR, Event_Name VARCHAR); CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE party (region_id VARCHAR, party_id VARCHAR) ### question:How many Annual Meeting events happened in the United Kingdom region?
SELECT COUNT(*) FROM region AS t1 JOIN party AS t2 ON t1.region_id = t2.region_id JOIN party_events AS t3 ON t2.party_id = t3.party_id WHERE t1.region_name = "United Kingdom" AND t3.Event_Name = "Annaual Meeting"
How many pilots are there?
CREATE TABLE pilot (Id VARCHAR)
SELECT COUNT(*) FROM pilot
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Id VARCHAR) ### question:How many pilots are there?
SELECT COUNT(*) FROM pilot
List the names of pilots in ascending order of rank.
CREATE TABLE pilot (Pilot_name VARCHAR, Rank VARCHAR)
SELECT Pilot_name FROM pilot ORDER BY Rank
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Pilot_name VARCHAR, Rank VARCHAR) ### question:List the names of pilots in ascending order of rank.
SELECT Pilot_name FROM pilot ORDER BY Rank
What are the positions and teams of pilots?
CREATE TABLE pilot (POSITION VARCHAR, Team VARCHAR)
SELECT POSITION, Team FROM pilot
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (POSITION VARCHAR, Team VARCHAR) ### question:What are the positions and teams of pilots?
SELECT POSITION, Team FROM pilot
List the distinct positions of pilots older than 30.
CREATE TABLE pilot (POSITION VARCHAR, Age INTEGER)
SELECT DISTINCT POSITION FROM pilot WHERE Age > 30
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (POSITION VARCHAR, Age INTEGER) ### question:List the distinct positions of pilots older than 30.
SELECT DISTINCT POSITION FROM pilot WHERE Age > 30
Show the names of pilots from team "Bradley" or "Fordham".
CREATE TABLE pilot (Pilot_name VARCHAR, Team VARCHAR)
SELECT Pilot_name FROM pilot WHERE Team = "Bradley" OR Team = "Fordham"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Pilot_name VARCHAR, Team VARCHAR) ### question:Show the names of pilots from team "Bradley" or "Fordham".
SELECT Pilot_name FROM pilot WHERE Team = "Bradley" OR Team = "Fordham"
What is the joined year of the pilot of the highest rank?
CREATE TABLE pilot (Join_Year VARCHAR, Rank VARCHAR)
SELECT Join_Year FROM pilot ORDER BY Rank LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Join_Year VARCHAR, Rank VARCHAR) ### question:What is the joined year of the pilot of the highest rank?
SELECT Join_Year FROM pilot ORDER BY Rank LIMIT 1
What are the different nationalities of pilots? Show each nationality and the number of pilots of each nationality.
CREATE TABLE pilot (Nationality VARCHAR)
SELECT Nationality, COUNT(*) FROM pilot GROUP BY Nationality
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Nationality VARCHAR) ### question:What are the different nationalities of pilots? Show each nationality and the number of pilots of each nationality.
SELECT Nationality, COUNT(*) FROM pilot GROUP BY Nationality
Show the most common nationality of pilots.
CREATE TABLE pilot (Nationality VARCHAR)
SELECT Nationality FROM pilot GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Nationality VARCHAR) ### question:Show the most common nationality of pilots.
SELECT Nationality FROM pilot GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
Show the pilot positions that have both pilots joining after year 2005 and pilots joining before 2000.
CREATE TABLE pilot (POSITION VARCHAR, Join_Year INTEGER)
SELECT POSITION FROM pilot WHERE Join_Year < 2000 INTERSECT SELECT POSITION FROM pilot WHERE Join_Year > 2005
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (POSITION VARCHAR, Join_Year INTEGER) ### question:Show the pilot positions that have both pilots joining after year 2005 and pilots joining before 2000.
SELECT POSITION FROM pilot WHERE Join_Year < 2000 INTERSECT SELECT POSITION FROM pilot WHERE Join_Year > 2005
Show the names of pilots and models of aircrafts they have flied with.
CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR); CREATE TABLE aircraft (Model VARCHAR, Aircraft_ID VARCHAR)
SELECT T3.Pilot_name, T2.Model FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR); CREATE TABLE aircraft (Model VARCHAR, Aircraft_ID VARCHAR) ### question:Show the names of pilots and models of aircrafts they have flied with.
SELECT T3.Pilot_name, T2.Model FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID
Show the names of pilots and fleet series of the aircrafts they have flied with in ascending order of the rank of the pilot.
CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR, Rank VARCHAR); CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE aircraft (Fleet_Series VARCHAR, Aircraft_ID VARCHAR)
SELECT T3.Pilot_name, T2.Fleet_Series FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID ORDER BY T3.Rank
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR, Rank VARCHAR); CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE aircraft (Fleet_Series VARCHAR, Aircraft_ID VARCHAR) ### question:Show the names of pilots and fleet series of the aircrafts they have flied with in ascending order of the rank of the pilot.
SELECT T3.Pilot_name, T2.Fleet_Series FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID ORDER BY T3.Rank
Show the fleet series of the aircrafts flied by pilots younger than 34
CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_ID VARCHAR, Age INTEGER); CREATE TABLE aircraft (Fleet_Series VARCHAR, Aircraft_ID VARCHAR)
SELECT T2.Fleet_Series FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID WHERE T3.Age < 34
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot_record (Aircraft_ID VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_ID VARCHAR, Age INTEGER); CREATE TABLE aircraft (Fleet_Series VARCHAR, Aircraft_ID VARCHAR) ### question:Show the fleet series of the aircrafts flied by pilots younger than 34
SELECT T2.Fleet_Series FROM pilot_record AS T1 JOIN aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN pilot AS T3 ON T1.Pilot_ID = T3.Pilot_ID WHERE T3.Age < 34
Show the names of pilots and the number of records they have.
CREATE TABLE pilot (Pilot_name VARCHAR, pilot_ID VARCHAR); CREATE TABLE pilot_record (pilot_ID VARCHAR)
SELECT T2.Pilot_name, COUNT(*) FROM pilot_record AS T1 JOIN pilot AS T2 ON T1.pilot_ID = T2.pilot_ID GROUP BY T2.Pilot_name
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Pilot_name VARCHAR, pilot_ID VARCHAR); CREATE TABLE pilot_record (pilot_ID VARCHAR) ### question:Show the names of pilots and the number of records they have.
SELECT T2.Pilot_name, COUNT(*) FROM pilot_record AS T1 JOIN pilot AS T2 ON T1.pilot_ID = T2.pilot_ID GROUP BY T2.Pilot_name
Show names of pilots that have more than one record.
CREATE TABLE pilot (Pilot_name VARCHAR, pilot_ID VARCHAR); CREATE TABLE pilot_record (pilot_ID VARCHAR)
SELECT T2.Pilot_name, COUNT(*) FROM pilot_record AS T1 JOIN pilot AS T2 ON T1.pilot_ID = T2.pilot_ID GROUP BY T2.Pilot_name HAVING COUNT(*) > 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot (Pilot_name VARCHAR, pilot_ID VARCHAR); CREATE TABLE pilot_record (pilot_ID VARCHAR) ### question:Show names of pilots that have more than one record.
SELECT T2.Pilot_name, COUNT(*) FROM pilot_record AS T1 JOIN pilot AS T2 ON T1.pilot_ID = T2.pilot_ID GROUP BY T2.Pilot_name HAVING COUNT(*) > 1
List the names of pilots that do not have any record.
CREATE TABLE pilot_record (Pilot_name VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR)
SELECT Pilot_name FROM pilot WHERE NOT Pilot_ID IN (SELECT Pilot_ID FROM pilot_record)
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE pilot_record (Pilot_name VARCHAR, Pilot_ID VARCHAR); CREATE TABLE pilot (Pilot_name VARCHAR, Pilot_ID VARCHAR) ### question:List the names of pilots that do not have any record.
SELECT Pilot_name FROM pilot WHERE NOT Pilot_ID IN (SELECT Pilot_ID FROM pilot_record)
What document status codes do we have?
CREATE TABLE Ref_Document_Status (document_status_code VARCHAR)
SELECT document_status_code FROM Ref_Document_Status
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Document_Status (document_status_code VARCHAR) ### question:What document status codes do we have?
SELECT document_status_code FROM Ref_Document_Status
What is the description of document status code 'working'?
CREATE TABLE Ref_Document_Status (document_status_description VARCHAR, document_status_code VARCHAR)
SELECT document_status_description FROM Ref_Document_Status WHERE document_status_code = "working"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Document_Status (document_status_description VARCHAR, document_status_code VARCHAR) ### question:What is the description of document status code 'working'?
SELECT document_status_description FROM Ref_Document_Status WHERE document_status_code = "working"
What document type codes do we have?
CREATE TABLE Ref_Document_Types (document_type_code VARCHAR)
SELECT document_type_code FROM Ref_Document_Types
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Document_Types (document_type_code VARCHAR) ### question:What document type codes do we have?
SELECT document_type_code FROM Ref_Document_Types
What is the description of document type 'Paper'?
CREATE TABLE Ref_Document_Types (document_type_description VARCHAR, document_type_code VARCHAR)
SELECT document_type_description FROM Ref_Document_Types WHERE document_type_code = "Paper"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Document_Types (document_type_description VARCHAR, document_type_code VARCHAR) ### question:What is the description of document type 'Paper'?
SELECT document_type_description FROM Ref_Document_Types WHERE document_type_code = "Paper"
What are the shipping agent names?
CREATE TABLE Ref_Shipping_Agents (shipping_agent_name VARCHAR)
SELECT shipping_agent_name FROM Ref_Shipping_Agents
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Shipping_Agents (shipping_agent_name VARCHAR) ### question:What are the shipping agent names?
SELECT shipping_agent_name FROM Ref_Shipping_Agents
What is the shipping agent code of shipping agent UPS?
CREATE TABLE Ref_Shipping_Agents (shipping_agent_code VARCHAR, shipping_agent_name VARCHAR)
SELECT shipping_agent_code FROM Ref_Shipping_Agents WHERE shipping_agent_name = "UPS"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Shipping_Agents (shipping_agent_code VARCHAR, shipping_agent_name VARCHAR) ### question:What is the shipping agent code of shipping agent UPS?
SELECT shipping_agent_code FROM Ref_Shipping_Agents WHERE shipping_agent_name = "UPS"
What are all role codes?
CREATE TABLE ROLES (role_code VARCHAR)
SELECT role_code FROM ROLES
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE ROLES (role_code VARCHAR) ### question:What are all role codes?
SELECT role_code FROM ROLES
What is the description of role code ED?
CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR)
SELECT role_description FROM ROLES WHERE role_code = "ED"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR) ### question:What is the description of role code ED?
SELECT role_description FROM ROLES WHERE role_code = "ED"
How many employees do we have?
CREATE TABLE Employees (Id VARCHAR)
SELECT COUNT(*) FROM Employees
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Employees (Id VARCHAR) ### question:How many employees do we have?
SELECT COUNT(*) FROM Employees
What is the role of the employee named Koby?
CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR); CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR)
SELECT T1.role_description FROM ROLES AS T1 JOIN Employees AS T2 ON T1.role_code = T2.role_code WHERE T2.employee_name = "Koby"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR); CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR) ### question:What is the role of the employee named Koby?
SELECT T1.role_description FROM ROLES AS T1 JOIN Employees AS T2 ON T1.role_code = T2.role_code WHERE T2.employee_name = "Koby"
List all document ids and receipt dates of documents.
CREATE TABLE Documents (document_id VARCHAR, receipt_date VARCHAR)
SELECT document_id, receipt_date FROM Documents
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (document_id VARCHAR, receipt_date VARCHAR) ### question:List all document ids and receipt dates of documents.
SELECT document_id, receipt_date FROM Documents
How many employees does each role have? List role description, id and number of employees.
CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR); CREATE TABLE Employees (role_code VARCHAR)
SELECT T1.role_description, T2.role_code, COUNT(*) FROM ROLES AS T1 JOIN Employees AS T2 ON T1.role_code = T2.role_code GROUP BY T2.role_code
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE ROLES (role_description VARCHAR, role_code VARCHAR); CREATE TABLE Employees (role_code VARCHAR) ### question:How many employees does each role have? List role description, id and number of employees.
SELECT T1.role_description, T2.role_code, COUNT(*) FROM ROLES AS T1 JOIN Employees AS T2 ON T1.role_code = T2.role_code GROUP BY T2.role_code
List roles that have more than one employee. List the role description and number of employees.
CREATE TABLE ROLES (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR)
SELECT Roles.role_description, COUNT(Employees.employee_id) FROM ROLES JOIN Employees ON Employees.role_code = Roles.role_code GROUP BY Employees.role_code HAVING COUNT(Employees.employee_id) > 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE ROLES (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR) ### question:List roles that have more than one employee. List the role description and number of employees.
SELECT Roles.role_description, COUNT(Employees.employee_id) FROM ROLES JOIN Employees ON Employees.role_code = Roles.role_code GROUP BY Employees.role_code HAVING COUNT(Employees.employee_id) > 1
What is the document status description of the document with id 1?
CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Document_Status (Id VARCHAR)
SELECT Ref_Document_Status.document_status_description FROM Ref_Document_Status JOIN Documents ON Documents.document_status_code = Ref_Document_Status.document_status_code WHERE Documents.document_id = 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Document_Status (Id VARCHAR) ### question:What is the document status description of the document with id 1?
SELECT Ref_Document_Status.document_status_description FROM Ref_Document_Status JOIN Documents ON Documents.document_status_code = Ref_Document_Status.document_status_code WHERE Documents.document_id = 1
How many documents have the status code done?
CREATE TABLE Documents (document_status_code VARCHAR)
SELECT COUNT(*) FROM Documents WHERE document_status_code = "done"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (document_status_code VARCHAR) ### question:How many documents have the status code done?
SELECT COUNT(*) FROM Documents WHERE document_status_code = "done"
List the document type code for the document with the id 2.
CREATE TABLE Documents (document_type_code VARCHAR, document_id VARCHAR)
SELECT document_type_code FROM Documents WHERE document_id = 2
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (document_type_code VARCHAR, document_id VARCHAR) ### question:List the document type code for the document with the id 2.
SELECT document_type_code FROM Documents WHERE document_id = 2
List the document ids for any documents with the status code done and the type code paper.
CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR)
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR) ### question:List the document ids for any documents with the status code done and the type code paper.
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper"
What is the name of the shipping agent of the document with id 2?
CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR)
SELECT Ref_Shipping_Agents.shipping_agent_name FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Documents.document_id = 2
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR) ### question:What is the name of the shipping agent of the document with id 2?
SELECT Ref_Shipping_Agents.shipping_agent_name FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Documents.document_id = 2
How many documents were shipped by USPS?
CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR)
SELECT COUNT(*) FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR) ### question:How many documents were shipped by USPS?
SELECT COUNT(*) FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
Which shipping agent shipped the most documents? List the shipping agent name and the number of documents.
CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR)
SELECT Ref_Shipping_Agents.shipping_agent_name, COUNT(Documents.document_id) FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code GROUP BY Ref_Shipping_Agents.shipping_agent_code ORDER BY COUNT(Documents.document_id) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (Id VARCHAR); CREATE TABLE Ref_Shipping_Agents (Id VARCHAR) ### question:Which shipping agent shipped the most documents? List the shipping agent name and the number of documents.
SELECT Ref_Shipping_Agents.shipping_agent_name, COUNT(Documents.document_id) FROM Ref_Shipping_Agents JOIN Documents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code GROUP BY Ref_Shipping_Agents.shipping_agent_code ORDER BY COUNT(Documents.document_id) DESC LIMIT 1
What is the receipt date of the document with id 3?
CREATE TABLE Documents (receipt_date VARCHAR, document_id VARCHAR)
SELECT receipt_date FROM Documents WHERE document_id = 3
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents (receipt_date VARCHAR, document_id VARCHAR) ### question:What is the receipt date of the document with id 3?
SELECT receipt_date FROM Documents WHERE document_id = 3
What address was the document with id 4 mailed to?
CREATE TABLE Addresses (document_id VARCHAR); CREATE TABLE Documents_Mailed (document_id VARCHAR)
SELECT Addresses.address_details FROM Addresses JOIN Documents_Mailed ON Documents_Mailed.mailed_to_address_id = Addresses.address_id WHERE document_id = 4
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Addresses (document_id VARCHAR); CREATE TABLE Documents_Mailed (document_id VARCHAR) ### question:What address was the document with id 4 mailed to?
SELECT Addresses.address_details FROM Addresses JOIN Documents_Mailed ON Documents_Mailed.mailed_to_address_id = Addresses.address_id WHERE document_id = 4
What is the mail date of the document with id 7?
CREATE TABLE Documents_Mailed (mailing_date VARCHAR, document_id VARCHAR)
SELECT mailing_date FROM Documents_Mailed WHERE document_id = 7
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Documents_Mailed (mailing_date VARCHAR, document_id VARCHAR) ### question:What is the mail date of the document with id 7?
SELECT mailing_date FROM Documents_Mailed WHERE document_id = 7
List the document ids of documents with the status done and type Paper, which not shipped by the shipping agent named USPS.
CREATE TABLE Ref_Shipping_Agents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR); CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR)
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper" EXCEPT SELECT document_id FROM Documents JOIN Ref_Shipping_Agents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Shipping_Agents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR); CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR) ### question:List the document ids of documents with the status done and type Paper, which not shipped by the shipping agent named USPS.
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper" EXCEPT SELECT document_id FROM Documents JOIN Ref_Shipping_Agents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
List document id of documents status is done and document type is Paper and the document is shipped by shipping agent named USPS.
CREATE TABLE Ref_Shipping_Agents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR); CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR)
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper" INTERSECT SELECT document_id FROM Documents JOIN Ref_Shipping_Agents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Ref_Shipping_Agents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR); CREATE TABLE Documents (document_id VARCHAR, document_status_code VARCHAR, document_type_code VARCHAR) ### question:List document id of documents status is done and document type is Paper and the document is shipped by shipping agent named USPS.
SELECT document_id FROM Documents WHERE document_status_code = "done" AND document_type_code = "Paper" INTERSECT SELECT document_id FROM Documents JOIN Ref_Shipping_Agents ON Documents.shipping_agent_code = Ref_Shipping_Agents.shipping_agent_code WHERE Ref_Shipping_Agents.shipping_agent_name = "USPS"
What is draft detail of the document with id 7?
CREATE TABLE Document_Drafts (draft_details VARCHAR, document_id VARCHAR)
SELECT draft_details FROM Document_Drafts WHERE document_id = 7
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Document_Drafts (draft_details VARCHAR, document_id VARCHAR) ### question:What is draft detail of the document with id 7?
SELECT draft_details FROM Document_Drafts WHERE document_id = 7
How many draft copies does the document with id 2 have?
CREATE TABLE Draft_Copies (document_id VARCHAR)
SELECT COUNT(*) FROM Draft_Copies WHERE document_id = 2
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Draft_Copies (document_id VARCHAR) ### question:How many draft copies does the document with id 2 have?
SELECT COUNT(*) FROM Draft_Copies WHERE document_id = 2
Which document has the most draft copies? List its document id and number of draft copies.
CREATE TABLE Draft_Copies (document_id VARCHAR, copy_number VARCHAR)
SELECT document_id, COUNT(copy_number) FROM Draft_Copies GROUP BY document_id ORDER BY COUNT(copy_number) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Draft_Copies (document_id VARCHAR, copy_number VARCHAR) ### question:Which document has the most draft copies? List its document id and number of draft copies.
SELECT document_id, COUNT(copy_number) FROM Draft_Copies GROUP BY document_id ORDER BY COUNT(copy_number) DESC LIMIT 1
Which documents have more than 1 draft copies? List document id and number of draft copies.
CREATE TABLE Draft_Copies (document_id VARCHAR)
SELECT document_id, COUNT(*) FROM Draft_Copies GROUP BY document_id HAVING COUNT(*) > 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Draft_Copies (document_id VARCHAR) ### question:Which documents have more than 1 draft copies? List document id and number of draft copies.
SELECT document_id, COUNT(*) FROM Draft_Copies GROUP BY document_id HAVING COUNT(*) > 1
List all employees in the circulation history of the document with id 1. List the employee's name.
CREATE TABLE Circulation_History (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR)
SELECT Employees.employee_name FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id WHERE Circulation_History.document_id = 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Circulation_History (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR) ### question:List all employees in the circulation history of the document with id 1. List the employee's name.
SELECT Employees.employee_name FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id WHERE Circulation_History.document_id = 1
List the employees who have not showed up in any circulation history of documents. List the employee's name.
CREATE TABLE Circulation_History (employee_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR)
SELECT employee_name FROM Employees EXCEPT SELECT Employees.employee_name FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Circulation_History (employee_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR) ### question:List the employees who have not showed up in any circulation history of documents. List the employee's name.
SELECT employee_name FROM Employees EXCEPT SELECT Employees.employee_name FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id
Which employee has showed up in most circulation history documents. List the employee's name and the number of drafts and copies.
CREATE TABLE Circulation_History (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR)
SELECT Employees.employee_name, COUNT(*) FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id GROUP BY Circulation_History.document_id, Circulation_History.draft_number, Circulation_History.copy_number ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Circulation_History (Id VARCHAR); CREATE TABLE Employees (Id VARCHAR) ### question:Which employee has showed up in most circulation history documents. List the employee's name and the number of drafts and copies.
SELECT Employees.employee_name, COUNT(*) FROM Employees JOIN Circulation_History ON Circulation_History.employee_id = Employees.employee_id GROUP BY Circulation_History.document_id, Circulation_History.draft_number, Circulation_History.copy_number ORDER BY COUNT(*) DESC LIMIT 1
For each document, list the number of employees who have showed up in the circulation history of that document. List the document ids and number of employees.
CREATE TABLE Circulation_History (document_id VARCHAR, employee_id VARCHAR)
SELECT document_id, COUNT(DISTINCT employee_id) FROM Circulation_History GROUP BY document_id
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Circulation_History (document_id VARCHAR, employee_id VARCHAR) ### question:For each document, list the number of employees who have showed up in the circulation history of that document. List the document ids and number of employees.
SELECT document_id, COUNT(DISTINCT employee_id) FROM Circulation_History GROUP BY document_id
List all department names ordered by their starting date.
CREATE TABLE department (dname VARCHAR, mgr_start_date VARCHAR)
SELECT dname FROM department ORDER BY mgr_start_date
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE department (dname VARCHAR, mgr_start_date VARCHAR) ### question:List all department names ordered by their starting date.
SELECT dname FROM department ORDER BY mgr_start_date
find all dependent names who have a spouse relation with some employee.
CREATE TABLE dependent (Dependent_name VARCHAR, relationship VARCHAR)
SELECT Dependent_name FROM dependent WHERE relationship = 'Spouse'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE dependent (Dependent_name VARCHAR, relationship VARCHAR) ### question:find all dependent names who have a spouse relation with some employee.
SELECT Dependent_name FROM dependent WHERE relationship = 'Spouse'
how many female dependents are there?
CREATE TABLE dependent (sex VARCHAR)
SELECT COUNT(*) FROM dependent WHERE sex = 'F'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE dependent (sex VARCHAR) ### question:how many female dependents are there?
SELECT COUNT(*) FROM dependent WHERE sex = 'F'
Find the names of departments that are located in Houston.
CREATE TABLE dept_locations (dnumber VARCHAR, dlocation VARCHAR); CREATE TABLE department (dname VARCHAR, dnumber VARCHAR)
SELECT t1.dname FROM department AS t1 JOIN dept_locations AS t2 ON t1.dnumber = t2.dnumber WHERE t2.dlocation = 'Houston'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE dept_locations (dnumber VARCHAR, dlocation VARCHAR); CREATE TABLE department (dname VARCHAR, dnumber VARCHAR) ### question:Find the names of departments that are located in Houston.
SELECT t1.dname FROM department AS t1 JOIN dept_locations AS t2 ON t1.dnumber = t2.dnumber WHERE t2.dlocation = 'Houston'
Return the first names and last names of employees who earn more than 30000 in salary.
CREATE TABLE employee (fname VARCHAR, lname VARCHAR, salary INTEGER)
SELECT fname, lname FROM employee WHERE salary > 30000
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE employee (fname VARCHAR, lname VARCHAR, salary INTEGER) ### question:Return the first names and last names of employees who earn more than 30000 in salary.
SELECT fname, lname FROM employee WHERE salary > 30000
Find the number of employees of each gender whose salary is lower than 50000.
CREATE TABLE employee (sex VARCHAR, salary INTEGER)
SELECT COUNT(*), sex FROM employee WHERE salary < 50000 GROUP BY sex
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE employee (sex VARCHAR, salary INTEGER) ### question:Find the number of employees of each gender whose salary is lower than 50000.
SELECT COUNT(*), sex FROM employee WHERE salary < 50000 GROUP BY sex
list the first and last names, and the addresses of all employees in the ascending order of their birth date.
CREATE TABLE employee (fname VARCHAR, lname VARCHAR, address VARCHAR, Bdate VARCHAR)
SELECT fname, lname, address FROM employee ORDER BY Bdate
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE employee (fname VARCHAR, lname VARCHAR, address VARCHAR, Bdate VARCHAR) ### question:list the first and last names, and the addresses of all employees in the ascending order of their birth date.
SELECT fname, lname, address FROM employee ORDER BY Bdate
what are the event details of the services that have the type code 'Marriage'?
CREATE TABLE EVENTS (event_details VARCHAR, Service_ID VARCHAR); CREATE TABLE Services (Service_ID VARCHAR, Service_Type_Code VARCHAR)
SELECT T1.event_details FROM EVENTS AS T1 JOIN Services AS T2 ON T1.Service_ID = T2.Service_ID WHERE T2.Service_Type_Code = 'Marriage'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE EVENTS (event_details VARCHAR, Service_ID VARCHAR); CREATE TABLE Services (Service_ID VARCHAR, Service_Type_Code VARCHAR) ### question:what are the event details of the services that have the type code 'Marriage'?
SELECT T1.event_details FROM EVENTS AS T1 JOIN Services AS T2 ON T1.Service_ID = T2.Service_ID WHERE T2.Service_Type_Code = 'Marriage'
What are the ids and details of events that have more than one participants?
CREATE TABLE EVENTS (event_id VARCHAR, event_details VARCHAR, Event_ID VARCHAR); CREATE TABLE Participants_in_Events (Event_ID VARCHAR)
SELECT T1.event_id, T1.event_details FROM EVENTS AS T1 JOIN Participants_in_Events AS T2 ON T1.Event_ID = T2.Event_ID GROUP BY T1.Event_ID HAVING COUNT(*) > 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE EVENTS (event_id VARCHAR, event_details VARCHAR, Event_ID VARCHAR); CREATE TABLE Participants_in_Events (Event_ID VARCHAR) ### question:What are the ids and details of events that have more than one participants?
SELECT T1.event_id, T1.event_details FROM EVENTS AS T1 JOIN Participants_in_Events AS T2 ON T1.Event_ID = T2.Event_ID GROUP BY T1.Event_ID HAVING COUNT(*) > 1
How many events have each participants attended? List the participant id, type and the number.
CREATE TABLE Participants (Participant_ID VARCHAR, Participant_Type_Code VARCHAR); CREATE TABLE Participants_in_Events (Participant_ID VARCHAR)
SELECT T1.Participant_ID, T1.Participant_Type_Code, COUNT(*) FROM Participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID GROUP BY T1.Participant_ID
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Participants (Participant_ID VARCHAR, Participant_Type_Code VARCHAR); CREATE TABLE Participants_in_Events (Participant_ID VARCHAR) ### question:How many events have each participants attended? List the participant id, type and the number.
SELECT T1.Participant_ID, T1.Participant_Type_Code, COUNT(*) FROM Participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID GROUP BY T1.Participant_ID
What are all the the participant ids, type code and details?
CREATE TABLE Participants (Participant_ID VARCHAR, Participant_Type_Code VARCHAR, Participant_Details VARCHAR)
SELECT Participant_ID, Participant_Type_Code, Participant_Details FROM Participants
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Participants (Participant_ID VARCHAR, Participant_Type_Code VARCHAR, Participant_Details VARCHAR) ### question:What are all the the participant ids, type code and details?
SELECT Participant_ID, Participant_Type_Code, Participant_Details FROM Participants
How many participants belong to the type 'Organizer'?
CREATE TABLE participants (participant_type_code VARCHAR)
SELECT COUNT(*) FROM participants WHERE participant_type_code = 'Organizer'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE participants (participant_type_code VARCHAR) ### question:How many participants belong to the type 'Organizer'?
SELECT COUNT(*) FROM participants WHERE participant_type_code = 'Organizer'
List the type of the services in alphabetical order.
CREATE TABLE services (service_type_code VARCHAR)
SELECT service_type_code FROM services ORDER BY service_type_code
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE services (service_type_code VARCHAR) ### question:List the type of the services in alphabetical order.
SELECT service_type_code FROM services ORDER BY service_type_code
List the service id and details for the events.
CREATE TABLE EVENTS (service_id VARCHAR, event_details VARCHAR)
SELECT service_id, event_details FROM EVENTS
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE EVENTS (service_id VARCHAR, event_details VARCHAR) ### question:List the service id and details for the events.
SELECT service_id, event_details FROM EVENTS
How many events had participants whose details had the substring 'Dr.'
CREATE TABLE participants (Participant_ID VARCHAR, participant_details VARCHAR); CREATE TABLE Participants_in_Events (Participant_ID VARCHAR)
SELECT COUNT(*) FROM participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID WHERE T1.participant_details LIKE '%Dr.%'
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE participants (Participant_ID VARCHAR, participant_details VARCHAR); CREATE TABLE Participants_in_Events (Participant_ID VARCHAR) ### question:How many events had participants whose details had the substring 'Dr.'
SELECT COUNT(*) FROM participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID WHERE T1.participant_details LIKE '%Dr.%'
What is the most common participant type?
CREATE TABLE participants (participant_type_code VARCHAR)
SELECT participant_type_code FROM participants GROUP BY participant_type_code ORDER BY COUNT(*) DESC LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE participants (participant_type_code VARCHAR) ### question:What is the most common participant type?
SELECT participant_type_code FROM participants GROUP BY participant_type_code ORDER BY COUNT(*) DESC LIMIT 1
Which service id and type has the least number of participants?
CREATE TABLE Participants_in_Events (Participant_ID VARCHAR, Event_ID VARCHAR); CREATE TABLE services (Service_Type_Code VARCHAR, service_id VARCHAR); CREATE TABLE EVENTS (service_id VARCHAR, Event_ID VARCHAR); CREATE TABLE participants (Participant_ID VARCHAR)
SELECT T3.service_id, T4.Service_Type_Code FROM participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID JOIN EVENTS AS T3 ON T2.Event_ID = T3.Event_ID JOIN services AS T4 ON T3.service_id = T4.service_id GROUP BY T3.service_id ORDER BY COUNT(*) LIMIT 1
Translate the question into SQL query by using the schema. ### schema:CREATE TABLE Participants_in_Events (Participant_ID VARCHAR, Event_ID VARCHAR); CREATE TABLE services (Service_Type_Code VARCHAR, service_id VARCHAR); CREATE TABLE EVENTS (service_id VARCHAR, Event_ID VARCHAR); CREATE TABLE participants (Participant_ID VARCHAR) ### question:Which service id and type has the least number of participants?
SELECT T3.service_id, T4.Service_Type_Code FROM participants AS T1 JOIN Participants_in_Events AS T2 ON T1.Participant_ID = T2.Participant_ID JOIN EVENTS AS T3 ON T2.Event_ID = T3.Event_ID JOIN services AS T4 ON T3.service_id = T4.service_id GROUP BY T3.service_id ORDER BY COUNT(*) LIMIT 1