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<question>: What is the card type code with most number of cards? <context>: CREATE TABLE Customers_cards (card_type_code VARCHAR) <answer>: SELECT card_type_code FROM Customers_cards GROUP BY card_type_code ORDER BY COUNT(*) DESC LIMIT 1
401
<question>: Show card type codes with at least 5 cards. <context>: CREATE TABLE Customers_cards (card_type_code VARCHAR) <answer>: SELECT card_type_code FROM Customers_cards GROUP BY card_type_code HAVING COUNT(*) >= 5
402
<question>: Show all card type codes and the number of customers holding cards in each type. <context>: CREATE TABLE Customers_cards (card_type_code VARCHAR, customer_id VARCHAR) <answer>: SELECT card_type_code, COUNT(DISTINCT customer_id) FROM Customers_cards GROUP BY card_type_code
403
<question>: Show the customer ids and firstname without a credit card. <context>: CREATE TABLE Customers_cards (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, card_type_code VARCHAR) <answer>: SELECT customer_id, customer_first_name FROM Customers EXCEPT SELECT T1.customer_id, T2.customer_first_name FROM Customers_cards AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE card_type_code = "Credit"
404
<question>: Show all card type codes. <context>: CREATE TABLE Customers_Cards (card_type_code VARCHAR) <answer>: SELECT DISTINCT card_type_code FROM Customers_Cards
405
<question>: Show the number of card types. <context>: CREATE TABLE Customers_Cards (card_type_code VARCHAR) <answer>: SELECT COUNT(DISTINCT card_type_code) FROM Customers_Cards
406
<question>: Show all transaction types. <context>: CREATE TABLE Financial_Transactions (transaction_type VARCHAR) <answer>: SELECT DISTINCT transaction_type FROM Financial_Transactions
407
<question>: Show the number of transaction types. <context>: CREATE TABLE Financial_Transactions (transaction_type VARCHAR) <answer>: SELECT COUNT(DISTINCT transaction_type) FROM Financial_Transactions
408
<question>: What is the average and total transaction amount? <context>: CREATE TABLE Financial_transactions (transaction_amount INTEGER) <answer>: SELECT AVG(transaction_amount), SUM(transaction_amount) FROM Financial_transactions
409
<question>: Show the card type codes and the number of transactions. <context>: CREATE TABLE Financial_transactions (card_id VARCHAR); CREATE TABLE Customers_cards (card_type_code VARCHAR, card_id VARCHAR) <answer>: SELECT T2.card_type_code, COUNT(*) FROM Financial_transactions AS T1 JOIN Customers_cards AS T2 ON T1.card_id = T2.card_id GROUP BY T2.card_type_code
410
<question>: Show the transaction type and the number of transactions. <context>: CREATE TABLE Financial_transactions (transaction_type VARCHAR) <answer>: SELECT transaction_type, COUNT(*) FROM Financial_transactions GROUP BY transaction_type
411
<question>: What is the transaction type that has processed the greatest total amount in transactions? <context>: CREATE TABLE Financial_transactions (transaction_type VARCHAR, transaction_amount INTEGER) <answer>: SELECT transaction_type FROM Financial_transactions GROUP BY transaction_type ORDER BY SUM(transaction_amount) DESC LIMIT 1
412
<question>: Show the account id and the number of transactions for each account <context>: CREATE TABLE Financial_transactions (account_id VARCHAR) <answer>: SELECT account_id, COUNT(*) FROM Financial_transactions GROUP BY account_id
413
<question>: How many tracks do we have? <context>: CREATE TABLE track (Id VARCHAR) <answer>: SELECT COUNT(*) FROM track
414
<question>: Show the name and location for all tracks. <context>: CREATE TABLE track (name VARCHAR, LOCATION VARCHAR) <answer>: SELECT name, LOCATION FROM track
415
<question>: Show names and seatings, ordered by seating for all tracks opened after 2000. <context>: CREATE TABLE track (name VARCHAR, seating VARCHAR, year_opened INTEGER) <answer>: SELECT name, seating FROM track WHERE year_opened > 2000 ORDER BY seating
416
<question>: What is the name, location and seating for the most recently opened track? <context>: CREATE TABLE track (name VARCHAR, LOCATION VARCHAR, seating VARCHAR, year_opened VARCHAR) <answer>: SELECT name, LOCATION, seating FROM track ORDER BY year_opened DESC LIMIT 1
417
<question>: What is the minimum, maximum, and average seating for all tracks. <context>: CREATE TABLE track (seating INTEGER) <answer>: SELECT MIN(seating), MAX(seating), AVG(seating) FROM track
418
<question>: Show the name, location, open year for all tracks with a seating higher than the average. <context>: CREATE TABLE track (name VARCHAR, LOCATION VARCHAR, year_opened VARCHAR, seating INTEGER) <answer>: SELECT name, LOCATION, year_opened FROM track WHERE seating > (SELECT AVG(seating) FROM track)
419
<question>: What are distinct locations where tracks are located? <context>: CREATE TABLE track (LOCATION VARCHAR) <answer>: SELECT DISTINCT LOCATION FROM track
420
<question>: How many races are there? <context>: CREATE TABLE race (Id VARCHAR) <answer>: SELECT COUNT(*) FROM race
421
<question>: What are the distinct classes that races can have? <context>: CREATE TABLE race (CLASS VARCHAR) <answer>: SELECT DISTINCT CLASS FROM race
422
<question>: Show name, class, and date for all races. <context>: CREATE TABLE race (name VARCHAR, CLASS VARCHAR, date VARCHAR) <answer>: SELECT name, CLASS, date FROM race
423
<question>: Show the race class and number of races in each class. <context>: CREATE TABLE race (CLASS VARCHAR) <answer>: SELECT CLASS, COUNT(*) FROM race GROUP BY CLASS
424
<question>: What is the race class with most number of races. <context>: CREATE TABLE race (CLASS VARCHAR) <answer>: SELECT CLASS FROM race GROUP BY CLASS ORDER BY COUNT(*) DESC LIMIT 1
425
<question>: List the race class with at least two races. <context>: CREATE TABLE race (CLASS VARCHAR) <answer>: SELECT CLASS FROM race GROUP BY CLASS HAVING COUNT(*) >= 2
426
<question>: What are the names for tracks without a race in class 'GT'. <context>: CREATE TABLE race (track_id VARCHAR, class VARCHAR); CREATE TABLE track (name VARCHAR); CREATE TABLE track (name VARCHAR, track_id VARCHAR) <answer>: SELECT name FROM track EXCEPT SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id WHERE T1.class = 'GT'
427
<question>: Show all track names that have had no races. <context>: CREATE TABLE track (name VARCHAR, track_id VARCHAR); CREATE TABLE race (name VARCHAR, track_id VARCHAR) <answer>: SELECT name FROM track WHERE NOT track_id IN (SELECT track_id FROM race)
428
<question>: Show year where a track with a seating at least 5000 opened and a track with seating no more than 4000 opened. <context>: CREATE TABLE track (year_opened VARCHAR, seating INTEGER) <answer>: SELECT year_opened FROM track WHERE seating BETWEEN 4000 AND 5000
429
<question>: Show the name of track and the number of races in each track. <context>: CREATE TABLE track (name VARCHAR, track_id VARCHAR); CREATE TABLE race (track_id VARCHAR) <answer>: SELECT T2.name, COUNT(*) FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id
430
<question>: Show the name of track with most number of races. <context>: CREATE TABLE track (name VARCHAR, track_id VARCHAR); CREATE TABLE race (track_id VARCHAR) <answer>: SELECT T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id ORDER BY COUNT(*) DESC LIMIT 1
431
<question>: Show the name and date for each race and its track name. <context>: CREATE TABLE race (name VARCHAR, date VARCHAR, track_id VARCHAR); CREATE TABLE track (name VARCHAR, track_id VARCHAR) <answer>: SELECT T1.name, T1.date, T2.name FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id
432
<question>: Show the name and location of track with 1 race. <context>: CREATE TABLE race (track_id VARCHAR); CREATE TABLE track (name VARCHAR, location VARCHAR, track_id VARCHAR) <answer>: SELECT T2.name, T2.location FROM race AS T1 JOIN track AS T2 ON T1.track_id = T2.track_id GROUP BY T1.track_id HAVING COUNT(*) = 1
433
<question>: Find the locations where have both tracks with more than 90000 seats and tracks with less than 70000 seats. <context>: CREATE TABLE track (LOCATION VARCHAR, seating INTEGER) <answer>: SELECT LOCATION FROM track WHERE seating > 90000 INTERSECT SELECT LOCATION FROM track WHERE seating < 70000
434
<question>: How many members have the black membership card? <context>: CREATE TABLE member (Membership_card VARCHAR) <answer>: SELECT COUNT(*) FROM member WHERE Membership_card = 'Black'
435
<question>: Find the number of members living in each address. <context>: CREATE TABLE member (address VARCHAR) <answer>: SELECT COUNT(*), address FROM member GROUP BY address
436
<question>: Give me the names of members whose address is in Harford or Waterbury. <context>: CREATE TABLE member (name VARCHAR, address VARCHAR) <answer>: SELECT name FROM member WHERE address = 'Harford' OR address = 'Waterbury'
437
<question>: Find the ids and names of members who are under age 30 or with black membership card. <context>: CREATE TABLE member (name VARCHAR, member_id VARCHAR, Membership_card VARCHAR, age VARCHAR) <answer>: SELECT name, member_id FROM member WHERE Membership_card = 'Black' OR age < 30
438
<question>: Find the purchase time, age and address of each member, and show the results in the order of purchase time. <context>: CREATE TABLE member (Time_of_purchase VARCHAR, age VARCHAR, address VARCHAR) <answer>: SELECT Time_of_purchase, age, address FROM member ORDER BY Time_of_purchase
439
<question>: Which membership card has more than 5 members? <context>: CREATE TABLE member (Membership_card VARCHAR) <answer>: SELECT Membership_card FROM member GROUP BY Membership_card HAVING COUNT(*) > 5
440
<question>: Which address has both members younger than 30 and members older than 40? <context>: CREATE TABLE member (address VARCHAR, age INTEGER) <answer>: SELECT address FROM member WHERE age < 30 INTERSECT SELECT address FROM member WHERE age > 40
441
<question>: What is the membership card held by both members living in Hartford and ones living in Waterbury address? <context>: CREATE TABLE member (membership_card VARCHAR, address VARCHAR) <answer>: SELECT membership_card FROM member WHERE address = 'Hartford' INTERSECT SELECT membership_card FROM member WHERE address = 'Waterbury'
442
<question>: How many members are not living in Hartford? <context>: CREATE TABLE member (address VARCHAR) <answer>: SELECT COUNT(*) FROM member WHERE address <> 'Hartford'
443
<question>: Which address do not have any member with the black membership card? <context>: CREATE TABLE member (address VARCHAR, Membership_card VARCHAR) <answer>: SELECT address FROM member EXCEPT SELECT address FROM member WHERE Membership_card = 'Black'
444
<question>: Show the shop addresses ordered by their opening year. <context>: CREATE TABLE shop (address VARCHAR, open_year VARCHAR) <answer>: SELECT address FROM shop ORDER BY open_year
445
<question>: What are the average score and average staff number of all shops? <context>: CREATE TABLE shop (num_of_staff INTEGER, score INTEGER) <answer>: SELECT AVG(num_of_staff), AVG(score) FROM shop
446
<question>: Find the id and address of the shops whose score is below the average score. <context>: CREATE TABLE shop (shop_id VARCHAR, address VARCHAR, score INTEGER) <answer>: SELECT shop_id, address FROM shop WHERE score < (SELECT AVG(score) FROM shop)
447
<question>: Find the address and staff number of the shops that do not have any happy hour. <context>: CREATE TABLE shop (address VARCHAR, num_of_staff VARCHAR, shop_id VARCHAR); CREATE TABLE happy_hour (address VARCHAR, num_of_staff VARCHAR, shop_id VARCHAR) <answer>: SELECT address, num_of_staff FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM happy_hour)
448
<question>: What are the id and address of the shops which have a happy hour in May? <context>: CREATE TABLE shop (address VARCHAR, shop_id VARCHAR); CREATE TABLE happy_hour (shop_id VARCHAR) <answer>: SELECT t1.address, t1.shop_id FROM shop AS t1 JOIN happy_hour AS t2 ON t1.shop_id = t2.shop_id WHERE MONTH = 'May'
449
<question>: which shop has happy hour most frequently? List its id and number of happy hours. <context>: CREATE TABLE happy_hour (shop_id VARCHAR) <answer>: SELECT shop_id, COUNT(*) FROM happy_hour GROUP BY shop_id ORDER BY COUNT(*) DESC LIMIT 1
450
<question>: Which month has the most happy hours? <context>: CREATE TABLE happy_hour (MONTH VARCHAR) <answer>: SELECT MONTH FROM happy_hour GROUP BY MONTH ORDER BY COUNT(*) DESC LIMIT 1
451
<question>: Which months have more than 2 happy hours? <context>: CREATE TABLE happy_hour (MONTH VARCHAR) <answer>: SELECT MONTH FROM happy_hour GROUP BY MONTH HAVING COUNT(*) > 2
452
<question>: How many albums are there? <context>: CREATE TABLE ALBUM (Id VARCHAR) <answer>: SELECT COUNT(*) FROM ALBUM
453
<question>: List the names of all music genres. <context>: CREATE TABLE GENRE (Name VARCHAR) <answer>: SELECT Name FROM GENRE
454
<question>: Find all the customer information in state NY. <context>: CREATE TABLE CUSTOMER (State VARCHAR) <answer>: SELECT * FROM CUSTOMER WHERE State = "NY"
455
<question>: What are the first names and last names of the employees who live in Calgary city. <context>: CREATE TABLE EMPLOYEE (FirstName VARCHAR, LastName VARCHAR, City VARCHAR) <answer>: SELECT FirstName, LastName FROM EMPLOYEE WHERE City = "Calgary"
456
<question>: What are the distinct billing countries of the invoices? <context>: CREATE TABLE INVOICE (BillingCountry VARCHAR) <answer>: SELECT DISTINCT (BillingCountry) FROM INVOICE
457
<question>: Find the names of all artists that have "a" in their names. <context>: CREATE TABLE ARTIST (Name VARCHAR) <answer>: SELECT Name FROM ARTIST WHERE Name LIKE "%a%"
458
<question>: Find the title of all the albums of the artist "AC/DC". <context>: CREATE TABLE ARTIST (ArtistId VARCHAR, Name VARCHAR); CREATE TABLE ALBUM (ArtistId VARCHAR) <answer>: SELECT Title FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "AC/DC"
459
<question>: Hom many albums does the artist "Metallica" have? <context>: CREATE TABLE ARTIST (ArtistId VARCHAR, Name VARCHAR); CREATE TABLE ALBUM (ArtistId VARCHAR) <answer>: SELECT COUNT(*) FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T2.Name = "Metallica"
460
<question>: Which artist does the album "Balls to the Wall" belong to? <context>: CREATE TABLE ALBUM (ArtistId VARCHAR, Title VARCHAR); CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR) <answer>: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId WHERE T1.Title = "Balls to the Wall"
461
<question>: Which artist has the most albums? <context>: CREATE TABLE ALBUM (ArtistId VARCHAR); CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR) <answer>: SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId GROUP BY T2.Name ORDER BY COUNT(*) DESC LIMIT 1
462
<question>: Find the names of all the tracks that contain the word "you". <context>: CREATE TABLE TRACK (Name VARCHAR) <answer>: SELECT Name FROM TRACK WHERE Name LIKE '%you%'
463
<question>: What is the average unit price of all the tracks? <context>: CREATE TABLE TRACK (UnitPrice INTEGER) <answer>: SELECT AVG(UnitPrice) FROM TRACK
464
<question>: What are the durations of the longest and the shortest tracks in milliseconds? <context>: CREATE TABLE TRACK (Milliseconds INTEGER) <answer>: SELECT MAX(Milliseconds), MIN(Milliseconds) FROM TRACK
465
<question>: Show the album names, ids and the number of tracks for each album. <context>: CREATE TABLE ALBUM (Title VARCHAR, AlbumId VARCHAR); CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR) <answer>: SELECT T1.Title, T2.AlbumID, COUNT(*) FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId GROUP BY T2.AlbumID
466
<question>: What is the name of the most common genre in all tracks? <context>: CREATE TABLE GENRE (Name VARCHAR, GenreId VARCHAR); CREATE TABLE TRACK (GenreId VARCHAR) <answer>: SELECT T1.Name FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId GROUP BY T2.GenreId ORDER BY COUNT(*) DESC LIMIT 1
467
<question>: What is the least common media type in all tracks? <context>: CREATE TABLE MEDIATYPE (Name VARCHAR, MediaTypeId VARCHAR); CREATE TABLE TRACK (MediaTypeId VARCHAR) <answer>: SELECT T1.Name FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId GROUP BY T2.MediaTypeId ORDER BY COUNT(*) LIMIT 1
468
<question>: Show the album names and ids for albums that contain tracks with unit price bigger than 1. <context>: CREATE TABLE ALBUM (Title VARCHAR, AlbumId VARCHAR); CREATE TABLE TRACK (AlbumID VARCHAR, AlbumId VARCHAR, UnitPrice INTEGER) <answer>: SELECT T1.Title, T2.AlbumID FROM ALBUM AS T1 JOIN TRACK AS T2 ON T1.AlbumId = T2.AlbumId WHERE T2.UnitPrice > 1 GROUP BY T2.AlbumID
469
<question>: How many tracks belong to rock genre? <context>: CREATE TABLE TRACK (GenreId VARCHAR); CREATE TABLE GENRE (GenreId VARCHAR, Name VARCHAR) <answer>: SELECT COUNT(*) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"
470
<question>: What is the average unit price of tracks that belong to Jazz genre? <context>: CREATE TABLE TRACK (GenreId VARCHAR); CREATE TABLE GENRE (GenreId VARCHAR, Name VARCHAR) <answer>: SELECT AVG(UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Jazz"
471
<question>: What is the first name and last name of the customer that has email "luisg@embraer.com.br"? <context>: CREATE TABLE CUSTOMER (FirstName VARCHAR, LastName VARCHAR, Email VARCHAR) <answer>: SELECT FirstName, LastName FROM CUSTOMER WHERE Email = "luisg@embraer.com.br"
472
<question>: How many customers have email that contains "gmail.com"? <context>: CREATE TABLE CUSTOMER (Email VARCHAR) <answer>: SELECT COUNT(*) FROM CUSTOMER WHERE Email LIKE "%gmail.com%"
473
<question>: What is the first name and last name employee helps the customer with first name Leonie? <context>: CREATE TABLE CUSTOMER (SupportRepId VARCHAR, FirstName VARCHAR); CREATE TABLE EMPLOYEE (FirstName VARCHAR, LastName VARCHAR, EmployeeId VARCHAR) <answer>: SELECT T2.FirstName, T2.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.FirstName = "Leonie"
474
<question>: What city does the employee who helps the customer with postal code 70174 live in? <context>: CREATE TABLE EMPLOYEE (City VARCHAR, EmployeeId VARCHAR); CREATE TABLE CUSTOMER (SupportRepId VARCHAR, PostalCode VARCHAR) <answer>: SELECT T2.City FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId WHERE T1.PostalCode = "70174"
475
<question>: How many distinct cities does the employees live in? <context>: CREATE TABLE EMPLOYEE (city VARCHAR) <answer>: SELECT COUNT(DISTINCT city) FROM EMPLOYEE
476
<question>: Find all invoice dates corresponding to customers with first name Astrid and last name Gruber. <context>: CREATE TABLE CUSTOMER (CustomerId VARCHAR, FirstName VARCHAR); CREATE TABLE INVOICE (InvoiceDate VARCHAR, CustomerId VARCHAR) <answer>: SELECT T2.InvoiceDate FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.FirstName = "Astrid" AND LastName = "Gruber"
477
<question>: Find all the customer last names that do not have invoice totals larger than 20. <context>: CREATE TABLE CUSTOMER (LastName VARCHAR); CREATE TABLE CUSTOMER (LastName VARCHAR, CustomerId VARCHAR); CREATE TABLE Invoice (CustomerId VARCHAR, total INTEGER) <answer>: SELECT LastName FROM CUSTOMER EXCEPT SELECT T1.LastName FROM CUSTOMER AS T1 JOIN Invoice AS T2 ON T1.CustomerId = T2.CustomerId WHERE T2.total > 20
478
<question>: Find the first names of all customers that live in Brazil and have an invoice. <context>: CREATE TABLE CUSTOMER (FirstName VARCHAR, CustomerId VARCHAR, country VARCHAR); CREATE TABLE INVOICE (CustomerId VARCHAR) <answer>: SELECT DISTINCT T1.FirstName FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Brazil"
479
<question>: Find the address of all customers that live in Germany and have invoice. <context>: CREATE TABLE INVOICE (CustomerId VARCHAR); CREATE TABLE CUSTOMER (Address VARCHAR, CustomerId VARCHAR, country VARCHAR) <answer>: SELECT DISTINCT T1.Address FROM CUSTOMER AS T1 JOIN INVOICE AS T2 ON T1.CustomerId = T2.CustomerId WHERE T1.country = "Germany"
480
<question>: List the phone numbers of all employees. <context>: CREATE TABLE EMPLOYEE (Phone VARCHAR) <answer>: SELECT Phone FROM EMPLOYEE
481
<question>: How many tracks are in the AAC audio file media type? <context>: CREATE TABLE MEDIATYPE (MediaTypeId VARCHAR, Name VARCHAR); CREATE TABLE TRACK (MediaTypeId VARCHAR) <answer>: SELECT COUNT(*) FROM MEDIATYPE AS T1 JOIN TRACK AS T2 ON T1.MediaTypeId = T2.MediaTypeId WHERE T1.Name = "AAC audio file"
482
<question>: What is the average duration in milliseconds of tracks that belong to Latin or Pop genre? <context>: CREATE TABLE TRACK (GenreId VARCHAR); CREATE TABLE GENRE (GenreId VARCHAR, Name VARCHAR) <answer>: SELECT AVG(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Latin" OR T1.Name = "Pop"
483
<question>: Please show the employee first names and ids of employees who serve at least 10 customers. <context>: CREATE TABLE CUSTOMER (FirstName VARCHAR, SupportRepId VARCHAR); CREATE TABLE EMPLOYEE (EmployeeId VARCHAR) <answer>: SELECT T1.FirstName, T1.SupportRepId FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) >= 10
484
<question>: Please show the employee last names that serves no more than 20 customers. <context>: CREATE TABLE EMPLOYEE (EmployeeId VARCHAR); CREATE TABLE CUSTOMER (LastName VARCHAR, SupportRepId VARCHAR) <answer>: SELECT T1.LastName FROM CUSTOMER AS T1 JOIN EMPLOYEE AS T2 ON T1.SupportRepId = T2.EmployeeId GROUP BY T1.SupportRepId HAVING COUNT(*) <= 20
485
<question>: Please list all album titles in alphabetical order. <context>: CREATE TABLE ALBUM (Title VARCHAR) <answer>: SELECT Title FROM ALBUM ORDER BY Title
486
<question>: Please list the name and id of all artists that have at least 3 albums in alphabetical order. <context>: CREATE TABLE ARTIST (Name VARCHAR, ArtistID VARCHAR); CREATE TABLE ALBUM (ArtistId VARCHAR) <answer>: SELECT T2.Name, T1.ArtistId FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistID GROUP BY T1.ArtistId HAVING COUNT(*) >= 3 ORDER BY T2.Name
487
<question>: Find the names of artists that do not have any albums. <context>: CREATE TABLE ARTIST (Name VARCHAR); CREATE TABLE ALBUM (ArtistId VARCHAR); CREATE TABLE ARTIST (Name VARCHAR, ArtistId VARCHAR) <answer>: SELECT Name FROM ARTIST EXCEPT SELECT T2.Name FROM ALBUM AS T1 JOIN ARTIST AS T2 ON T1.ArtistId = T2.ArtistId
488
<question>: What is the average unit price of rock tracks? <context>: CREATE TABLE GENRE (GenreId VARCHAR, Name VARCHAR); CREATE TABLE TRACK (UnitPrice INTEGER, GenreId VARCHAR) <answer>: SELECT AVG(T2.UnitPrice) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Rock"
489
<question>: What are the duration of the longest and shortest pop tracks in milliseconds? <context>: CREATE TABLE TRACK (GenreId VARCHAR); CREATE TABLE GENRE (GenreId VARCHAR, Name VARCHAR) <answer>: SELECT MAX(Milliseconds), MIN(Milliseconds) FROM GENRE AS T1 JOIN TRACK AS T2 ON T1.GenreId = T2.GenreId WHERE T1.Name = "Pop"
490
<question>: What are the birth dates of employees living in Edmonton? <context>: CREATE TABLE EMPLOYEE (BirthDate VARCHAR, City VARCHAR) <answer>: SELECT BirthDate FROM EMPLOYEE WHERE City = "Edmonton"
491
<question>: What are the distinct unit prices of all tracks? <context>: CREATE TABLE TRACK (UnitPrice VARCHAR) <answer>: SELECT DISTINCT (UnitPrice) FROM TRACK
492
<question>: How many artists do not have any album? <context>: CREATE TABLE ARTIST (artistid VARCHAR); CREATE TABLE ALBUM (artistid VARCHAR) <answer>: SELECT COUNT(*) FROM ARTIST WHERE NOT artistid IN (SELECT artistid FROM ALBUM)
493
<question>: What are the album titles for albums containing both 'Reggae' and 'Rock' genre tracks? <context>: CREATE TABLE Genre (GenreID VARCHAR, Name VARCHAR); CREATE TABLE Track (AlbumId VARCHAR, GenreID VARCHAR); CREATE TABLE Album (Title VARCHAR, AlbumId VARCHAR) <answer>: SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Reggae' INTERSECT SELECT T1.Title FROM Album AS T1 JOIN Track AS T2 ON T1.AlbumId = T2.AlbumId JOIN Genre AS T3 ON T2.GenreID = T3.GenreID WHERE T3.Name = 'Rock'
494
<question>: Find all the phone numbers. <context>: CREATE TABLE available_policies (customer_phone VARCHAR) <answer>: SELECT customer_phone FROM available_policies
495
<question>: What are the customer phone numbers under the policy "Life Insurance"? <context>: CREATE TABLE available_policies (customer_phone VARCHAR, policy_type_code VARCHAR) <answer>: SELECT customer_phone FROM available_policies WHERE policy_type_code = "Life Insurance"
496
<question>: Which policy type has the most records in the database? <context>: CREATE TABLE available_policies (policy_type_code VARCHAR) <answer>: SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1
497
<question>: What are all the customer phone numbers under the most popular policy type? <context>: CREATE TABLE available_policies (customer_phone VARCHAR, policy_type_code VARCHAR) <answer>: SELECT customer_phone FROM available_policies WHERE policy_type_code = (SELECT policy_type_code FROM available_policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1)
498
<question>: Find the policy type used by more than 4 customers. <context>: CREATE TABLE available_policies (policy_type_code VARCHAR) <answer>: SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING COUNT(*) > 4
499
<question>: Find the total and average amount of settlements. <context>: CREATE TABLE settlements (settlement_amount INTEGER) <answer>: SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements