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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among universities that score below 80 in 2015, what is the percentage of international students?
SELECT SUM(CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) / COUNT(*) * 100 FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.score < 80 AND T1.year = 2015
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many students attended universities were there in 2011?
SELECT SUM(num_students) FROM university_year WHERE year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among all universities, how many female students were there in 2011?
SELECT SUM(CAST(num_students * pct_female_students AS REAL) / 100) FROM university_year WHERE year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the student staff ratio at the university with the greatest student staff ratio of all time?
SELECT MAX(student_staff_ratio) FROM university_year ORDER BY student_staff_ratio DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the university ID with the most students in 2011?
SELECT university_id FROM university_year WHERE year = 2011 ORDER BY num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many institutions with over 50,000 students in 2011 had a percentage of oversea students of more than 10%?
SELECT COUNT(*) FROM university_year WHERE year = 2011 AND num_students > 50000 AND pct_international_students > 10
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the ID of the university with the highest percentage of female students in 2012.
SELECT university_id FROM university_year WHERE year = 2012 ORDER BY pct_female_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which university had the highest reputation in 2012?
SELECT T2.university_name FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2012 ORDER BY T1.score DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Name the university that had the most students in 2011.
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Indicate the university's name with the highest ranking score in Teaching.
SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN ranking_criteria AS T3 ON T3.id = T2.ranking_criteria_id WHERE T3.criteria_name = 'Teaching' ORDER BY T2.score DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the percentage of Harvard university's international students in 2011?
SELECT T1.pct_international_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Harvard University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many female students were there at Stanford University in 2011?
SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Stanford University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
In which nation is Harvard University located?
SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'Harvard University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the name of the ranking system for Teaching criteria?
SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Teaching'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Name the most famous university in Argentina.
SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Argentina' GROUP BY T1.university_name ORDER BY SUM(T2.score) DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
In Argentina, how many universities are there?
SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Argentina'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which universities have more than 100,000 students in 2011?
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T1.num_students > 100000
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many criteria are associated with ranking system Center for World University Rankings?
SELECT COUNT(T2.criteria_name) FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Center for World University Rankings'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many students at the university earned a score of 90 in 2011?
SELECT COUNT(*) FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.score = 90 AND T1.year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What are the top three universities with the most international students?
SELECT DISTINCT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id GROUP BY T2.university_name ORDER BY SUM(T1.num_students * T1.pct_international_students / 100) DESC LIMIT 3
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the difference in overall student enrollment and international student enrollment at the Harvard university from 2011 to 2012?
SELECT SUM(T1.num_students) - SUM(CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Harvard University' AND T1.year BETWEEN 2011 AND 2012
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many universities had over 30000 students in 2011?
SELECT COUNT(*) FROM university_year WHERE year = 2011 AND num_students > 30000
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the country ID of the University of Tokyo?
SELECT country_id FROM university WHERE university_name = 'University of Tokyo'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the ranking system ID of the Center for World University Rankings.
SELECT id FROM ranking_system WHERE system_name = 'Center for World University Rankings'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the ID of the Publications Rank criteria?
SELECT id FROM ranking_criteria WHERE criteria_name = 'Publications Rank'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many universities had above 30% of international students in 2013?
SELECT COUNT(*) FROM university_year WHERE pct_international_students > 30 AND year = 2013
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many universities got less than 50 scores under ranking criteria ID 6 in 2011?
SELECT COUNT(*) FROM university_ranking_year WHERE ranking_criteria_id = 6 AND year = 2011 AND score < 50
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the number of students at Yale University in 2016.
SELECT T1.num_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Yale University' AND T1.year = 2016
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
List the universities in Denmark.
SELECT T1.university_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Denmark'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the number of staff at the University of Auckland in 2015.
SELECT CAST(SUM(T1.num_students) AS REAL) / SUM(T1.student_staff_ratio) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'University of Auckland' AND T1.year = 2015
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which country has the University of São Paulo?
SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'University of São Paulo'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many international students attended Harvard University in 2012?
SELECT CAST(T2.num_students * T2.pct_international_students AS REAL) / 100 FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'Harvard University' AND T2.year = 2012
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the number of female students at Arizona State University in 2014.
SELECT CAST(T2.num_students * T2.pct_female_students AS REAL) / 100 FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'Arizona State University' AND T2.year = 2014
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the universities which got the highest scores.
SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id GROUP BY T1.university_name ORDER BY SUM(T2.score) DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
List the ranking criteria under the Shanghai Ranking system.
SELECT T2.criteria_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Shanghai Ranking'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
In 2011, which university got the lowest score in teaching criteria?
SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 ORDER BY T2.score ASC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the ranking system name for the "Quality of Education Rank" criteria.
SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Quality of Education Rank'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many percent of universities got a score above 80 under International criteria in 2016? Among them, name the university which got the highest score.
SELECT CAST(SUM(CASE WHEN T2.score > 80 THEN 1 ELSE 0 END) AS REAL) / COUNT(*), ( SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'International' AND T2.year ...
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the ranking criteria and scores in 2005 that were received by Harvard University.
SELECT T1.criteria_name, T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Harvard University' AND T2.year = 2005
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the average score per university under Alumni criteria in 2008.
SELECT AVG(T2.score) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id WHERE T1.criteria_name = 'Alumni' AND T2.year = 2008
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Name the university and country which had the highest number of international students in 2015.
SELECT T1.university_name, T3.country_name FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2015 ORDER BY T2.num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many students were there in university ID 1 in 2011?
SELECT num_students FROM university_year WHERE year = 2011 AND university_id = 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the ID of the university with the most students in 2011?
SELECT university_id FROM university_year WHERE year = 2011 ORDER BY num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the IDs of the universities with a student staff ratio of over 15 in 2011.
SELECT university_id FROM university_year WHERE year = 2011 AND student_staff_ratio > 15
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among the universities with over 20000 students in 2011, how many of them have an international students percentage of over 25% in the same year?
SELECT COUNT(*) FROM university_year WHERE year = 2011 AND pct_international_students > 25 AND num_students > 20000
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the IDs of the universities with the top 3 female students percentage in 2011.
SELECT university_id FROM university_year WHERE year = 2011 ORDER BY pct_female_students DESC LIMIT 3
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
In which year did university ID 1 have the most students?
SELECT year FROM university_year WHERE university_id = 1 ORDER BY num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many students did Harvard University have in 2011?
SELECT T1.num_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Harvard University' AND T1.year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the name of the university with the most international students in 2011?
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.pct_international_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the names of all the universities in Australia.
SELECT T1.university_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Australia'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among the universities in Australia, how many of them have more than 15000 students in 2011?
SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Australia' AND T2.year = 2011 AND T2.num_students > 15000
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which country is Harvard University in?
SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'Harvard University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the name of the university with the highest score in teaching in the year 2011?
SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 ORDER BY T2.score DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the names of the universities with a score in teaching of over 90 in 2011.
SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score > 90
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among the universities with a score in teaching of over 90 in 2011, how many of them are in the United States of America?
SELECT COUNT(*) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score > 90
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the names of all the ranking criteria of Harvard University in 2011.
SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Harvard University' AND T2.year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What are the names of the universities that got 98 in teaching in 2011?
SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score = 98
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Please list the names of all the universities that scored under 60 in teaching in 2011 and are in the United States of America.
SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id INNER JOIN country AS T4 ON T4.id = T3.country_id WHERE T4.country_name = 'United States of America' AND T2.year = 2011 AND T2.score < ...
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among the universities in Australia, how many of them have a student staff ratio of over 15 in 2011?
SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Australia' AND T2.student_staff_ratio > 15 AND T2.year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many female students did Stanford University have in 2011?
SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Stanford University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Among the universities with a score in teaching of over 90 in 2011, what is the percentage of those in the United States of America?
SELECT CAST(SUM(CASE WHEN T4.country_name = 'United States of America' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) AS per FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id INNER JOIN country AS T4 ON T4.id = T3...
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Give the id of "Center for World University Rankings".
SELECT id FROM ranking_system WHERE system_name = 'Center for World University Rankings'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which country is University of Veterinary Medicine Vienna located in? Give its country id.
SELECT country_id FROM university WHERE university_name = 'University of Veterinary Medicine Vienna'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the id of the criteria "Citations Rank"?
SELECT id FROM ranking_criteria WHERE criteria_name = 'Citations Rank'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Show the id of University of Orléans.
SELECT id FROM university WHERE university_name = 'University of Orléans'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
For the university id 268, show its number of students in 2013.
SELECT num_students FROM university_year WHERE university_id = 268 AND year = 2013
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Show the name of country id 66.
SELECT country_name FROM country WHERE id = 66
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which country is McMaster University located in?
SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'McMaster University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many Turkish universities are there in the database?
SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Turkey'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which university had the most students in 2011? Show its name.
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many students were there in University of Michigan in 2011?
SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'University of Michigan' AND T2.year = 2011
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
For Chosun University, what was its score on "Influence Rank" in 2015?
SELECT T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Chosun University' AND T1.criteria_name = 'Influence Rank' AND T2.year = 2015
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the percentage of the international students in University of Oslo in 2015?
SELECT T2.pct_international_students FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'University of Oslo' AND T2.year = 2015
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
For the University of Southampton in 2015, on which criteria did it score the best?
SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'University of Southampton' AND T2.year = 2015 ORDER BY T2.score DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Which ranking system is criteria "Total Shanghai" in?
SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Total Shanghai'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many female students were there in Pierre and Marie Curie University in 2015?
SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2015 AND T2.university_name = 'Pierre and Marie Curie University'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What was the score for University of Florida in "N and S" in 2014?
SELECT T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'University of Florida' AND T2.year = 2014 AND T1.criteria_name = 'N and S'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the number of international students of University of Wisconsin-Madison in 2013.
SELECT CAST(T1.num_students * T1.pct_international_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2013 AND T2.university_name = 'University of Wisconsin-Madison'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Show the name of the university with the lowest number of students in 2015.
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2015 ORDER BY T1.num_students ASC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many times more was the number of students of University of Ottawa than Joseph Fourier University in 2013?
SELECT CAST(SUM(CASE WHEN T2.university_name = 'University of Ottawa' THEN T1.num_students ELSE 0 END) AS REAL) / SUM(CASE WHEN T2.university_name = 'Joseph Fourier University' THEN T1.num_students ELSE 0 END) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2013
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the average number of criterias among "Times Higher Education World University Ranking","Shanghai Ranking" and "Center for World University Rankings".
SELECT (SUM(CASE WHEN T1.system_name = 'Center for World University Rankings' THEN 1 ELSE 0 END) + SUM(CASE WHEN T1.system_name = 'Shanghai Ranking' THEN 1 ELSE 0 END) + SUM(CASE WHEN T1.system_name = 'Times Higher Education World University Ranking' THEN 1 ELSE 0 END)) / 3 FROM ranking_system AS T1 INNER JOIN ranking_...
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the average number of students of all universities in 2012.
SELECT AVG(num_students) FROM university_year WHERE year = 2012
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the score of university ID 68 in 2015?
SELECT score FROM university_ranking_year WHERE year = 2015 AND university_id = 68
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the country ID of Cyprus.
SELECT id FROM country WHERE country_name = 'Cyprus'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the ID of university with the largest percentage of international students?
SELECT university_id FROM university_year ORDER BY pct_international_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the criteria name of the ranking criteria ID 13.
SELECT criteria_name FROM ranking_criteria WHERE id = 13
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the average score of all universities in 2012?
SELECT AVG(score) FROM university_ranking_year WHERE year = 2012
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
In years 2011 to 2013, what is the total number of female students in university ID 40?
SELECT SUM(CAST(num_students * pct_female_students AS REAL) / 100) FROM university_year WHERE year BETWEEN 2011 AND 2013 AND university_id = 40
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Calculate the average score of university ID 79 between year 2013 to 2015.
SELECT AVG(score) FROM university_ranking_year WHERE year BETWEEN 2013 AND 2015 AND university_id = 79
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Give the student staff ratio of university ID 35.
SELECT student_staff_ratio FROM university_year WHERE university_id = 35
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the score of the most populated university in 2011.
SELECT T2.score FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Give the criteria name where Harvard University scored 100.
SELECT DISTINCT T3.criteria_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN ranking_criteria AS T3 ON T3.id = T2.ranking_criteria_id WHERE T1.university_name = 'Harvard University' AND T2.score = 100
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the university name and ID of the university found in Turkey.
SELECT T1.university_name, T1.id FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Turkey'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
What is the total number of ranking criteria under the ranking system called Shanghai Ranking?
SELECT COUNT(*) FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Shanghai Ranking'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Give the name and score of the university ID 124.
SELECT T2.university_name, T1.score FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.id = 124
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many female students are there in University of Pennsylvania in 2011?
SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'University of Pennsylvania'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
List down all universities that scored below 50.
SELECT DISTINCT T2.university_name FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.score < 50
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
How many universities are located in Japan?
SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Japan'
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
Provide the name of the university with the highest number of male students.
SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id ORDER BY T1.num_students * T1.pct_female_students / 100 - T1.num_students DESC LIMIT 1
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CREATE TABLE university (id integer, country_name text, id integer, system_name text, id integer, ranking_system_id integer, criteria_name text, id integer, country_id integer, university_name text, university_id integer, ranking_criteria_id integer, year integer, score integer, university_id integer, year integer, num...
List the countries of universities that scored 70 and below in 2016.
SELECT DISTINCT T3.country_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.score < 70 AND T2.year = 2016
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