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### question: List all the cities in a decreasing order of each city's stations' highest latitude. ### answer: SELECT city FROM station GROUP BY city ORDER BY MAX(lat) DESC ### context: CREATE TABLE station (city VARCHAR, lat INTEGER) |
### question: What are the dates that had the top 5 cloud cover rates? Also tell me the cloud cover rate. ### answer: SELECT date, cloud_cover FROM weather ORDER BY cloud_cover DESC LIMIT 5 ### context: CREATE TABLE weather (date VARCHAR, cloud_cover VARCHAR) |
### question: What are the ids and durations of the trips with the top 3 durations? ### answer: SELECT id, duration FROM trip ORDER BY duration DESC LIMIT 3 ### context: CREATE TABLE trip (id VARCHAR, duration VARCHAR) |
### question: For each station, return its longitude and the average duration of trips that started from the station. ### answer: SELECT T1.name, T1.long, AVG(T2.duration) FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id GROUP BY T2.start_station_id ### context: CREATE TABLE station (name VARCHAR, long VARCHAR, id VARCHAR); CREATE TABLE trip (duration INTEGER, start_station_id VARCHAR) |
### question: For each station, find its latitude and the minimum duration of trips that ended at the station. ### answer: SELECT T1.name, T1.lat, MIN(T2.duration) FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.end_station_id GROUP BY T2.end_station_id ### context: CREATE TABLE trip (duration INTEGER, end_station_id VARCHAR); CREATE TABLE station (name VARCHAR, lat VARCHAR, id VARCHAR) |
### question: List all the distinct stations from which a trip of duration below 100 started. ### answer: SELECT DISTINCT start_station_name FROM trip WHERE duration < 100 ### context: CREATE TABLE trip (start_station_name VARCHAR, duration INTEGER) |
### question: Find all the zip codes in which the max dew point have never reached 70. ### answer: SELECT DISTINCT zip_code FROM weather EXCEPT SELECT DISTINCT zip_code FROM weather WHERE max_dew_point_f >= 70 ### context: CREATE TABLE weather (zip_code VARCHAR, max_dew_point_f VARCHAR) |
### question: Find the id for the trips that lasted at least as long as the average duration of trips in zip code 94103. ### answer: SELECT id FROM trip WHERE duration >= (SELECT AVG(duration) FROM trip WHERE zip_code = 94103) ### context: CREATE TABLE trip (id VARCHAR, duration INTEGER, zip_code VARCHAR) |
### question: What are the dates in which the mean sea level pressure was between 30.3 and 31? ### answer: SELECT date FROM weather WHERE mean_sea_level_pressure_inches BETWEEN 30.3 AND 31 ### context: CREATE TABLE weather (date VARCHAR, mean_sea_level_pressure_inches INTEGER) |
### question: Find the day in which the difference between the max temperature and min temperature was the smallest. Also report the difference. ### answer: SELECT date, max_temperature_f - min_temperature_f FROM weather ORDER BY max_temperature_f - min_temperature_f LIMIT 1 ### context: CREATE TABLE weather (date VARCHAR, max_temperature_f VARCHAR, min_temperature_f VARCHAR) |
### question: What are the id and name of the stations that have ever had more than 12 bikes available? ### answer: SELECT DISTINCT T1.id, T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available > 12 ### context: CREATE TABLE station (id VARCHAR, name VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER) |
### question: Give me the zip code where the average mean humidity is below 70 and at least 100 trips took place. ### answer: SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_humidity) < 70 INTERSECT SELECT zip_code FROM trip GROUP BY zip_code HAVING COUNT(*) >= 100 ### context: CREATE TABLE weather (zip_code VARCHAR, mean_humidity INTEGER); CREATE TABLE trip (zip_code VARCHAR, mean_humidity INTEGER) |
### question: What are the names of stations that are located in Palo Alto city but have never been the ending point of trips more than 100 times? ### answer: SELECT name FROM station WHERE city = "Palo Alto" EXCEPT SELECT end_station_name FROM trip GROUP BY end_station_name HAVING COUNT(*) > 100 ### context: CREATE TABLE trip (name VARCHAR, end_station_name VARCHAR, city VARCHAR); CREATE TABLE station (name VARCHAR, end_station_name VARCHAR, city VARCHAR) |
### question: How many trips started from Mountain View city and ended at Palo Alto city? ### answer: SELECT COUNT(*) FROM station AS T1 JOIN trip AS T2 JOIN station AS T3 JOIN trip AS T4 ON T1.id = T2.start_station_id AND T2.id = T4.id AND T3.id = T4.end_station_id WHERE T1.city = "Mountain View" AND T3.city = "Palo Alto" ### context: CREATE TABLE station (city VARCHAR, id VARCHAR); CREATE TABLE trip (end_station_id VARCHAR, id VARCHAR); CREATE TABLE station (id VARCHAR, city VARCHAR); CREATE TABLE trip (start_station_id VARCHAR, id VARCHAR) |
### question: What is the average latitude and longitude of the starting points of all trips? ### answer: SELECT AVG(T1.lat), AVG(T1.long) FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id ### context: CREATE TABLE trip (start_station_id VARCHAR); CREATE TABLE station (lat INTEGER, long INTEGER, id VARCHAR) |
### question: How many books are there? ### answer: SELECT COUNT(*) FROM book ### context: CREATE TABLE book (Id VARCHAR) |
### question: List the writers of the books in ascending alphabetical order. ### answer: SELECT Writer FROM book ORDER BY Writer ### context: CREATE TABLE book (Writer VARCHAR) |
### question: List the titles of the books in ascending order of issues. ### answer: SELECT Title FROM book ORDER BY Issues ### context: CREATE TABLE book (Title VARCHAR, Issues VARCHAR) |
### question: What are the titles of the books whose writer is not "Elaine Lee"? ### answer: SELECT Title FROM book WHERE Writer <> "Elaine Lee" ### context: CREATE TABLE book (Title VARCHAR, Writer VARCHAR) |
### question: What are the title and issues of the books? ### answer: SELECT Title, Issues FROM book ### context: CREATE TABLE book (Title VARCHAR, Issues VARCHAR) |
### question: What are the dates of publications in descending order of price? ### answer: SELECT Publication_Date FROM publication ORDER BY Price DESC ### context: CREATE TABLE publication (Publication_Date VARCHAR, Price VARCHAR) |
### question: What are the distinct publishers of publications with price higher than 5000000? ### answer: SELECT DISTINCT Publisher FROM publication WHERE Price > 5000000 ### context: CREATE TABLE publication (Publisher VARCHAR, Price INTEGER) |
### question: List the publisher of the publication with the highest price. ### answer: SELECT Publisher FROM publication ORDER BY Price DESC LIMIT 1 ### context: CREATE TABLE publication (Publisher VARCHAR, Price VARCHAR) |
### question: List the publication dates of publications with 3 lowest prices. ### answer: SELECT Publication_Date FROM publication ORDER BY Price LIMIT 3 ### context: CREATE TABLE publication (Publication_Date VARCHAR, Price VARCHAR) |
### question: Show the title and publication dates of books. ### answer: SELECT T1.Title, T2.Publication_Date FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID ### context: CREATE TABLE book (Title VARCHAR, Book_ID VARCHAR); CREATE TABLE publication (Publication_Date VARCHAR, Book_ID VARCHAR) |
### question: Show writers who have published a book with price more than 4000000. ### answer: SELECT T1.Writer FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID WHERE T2.Price > 4000000 ### context: CREATE TABLE publication (Book_ID VARCHAR, Price INTEGER); CREATE TABLE book (Writer VARCHAR, Book_ID VARCHAR) |
### question: Show the titles of books in descending order of publication price. ### answer: SELECT T1.Title FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID ORDER BY T2.Price DESC ### context: CREATE TABLE publication (Book_ID VARCHAR, Price VARCHAR); CREATE TABLE book (Title VARCHAR, Book_ID VARCHAR) |
### question: Show publishers that have more than one publication. ### answer: SELECT Publisher FROM publication GROUP BY Publisher HAVING COUNT(*) > 1 ### context: CREATE TABLE publication (Publisher VARCHAR) |
### question: Show different publishers together with the number of publications they have. ### answer: SELECT Publisher, COUNT(*) FROM publication GROUP BY Publisher ### context: CREATE TABLE publication (Publisher VARCHAR) |
### question: Please show the most common publication date. ### answer: SELECT Publication_Date FROM publication GROUP BY Publication_Date ORDER BY COUNT(*) DESC LIMIT 1 ### context: CREATE TABLE publication (Publication_Date VARCHAR) |
### question: List the writers who have written more than one book. ### answer: SELECT Writer FROM book GROUP BY Writer HAVING COUNT(*) > 1 ### context: CREATE TABLE book (Writer VARCHAR) |
### question: List the titles of books that are not published. ### answer: SELECT Title FROM book WHERE NOT Book_ID IN (SELECT Book_ID FROM publication) ### context: CREATE TABLE book (Title VARCHAR, Book_ID VARCHAR); CREATE TABLE publication (Title VARCHAR, Book_ID VARCHAR) |
### question: Show the publishers that have publications with price higher than 10000000 and publications with price lower than 5000000. ### answer: SELECT Publisher FROM publication WHERE Price > 10000000 INTERSECT SELECT Publisher FROM publication WHERE Price < 5000000 ### context: CREATE TABLE publication (Publisher VARCHAR, Price INTEGER) |
### question: What is the number of distinct publication dates? ### answer: SELECT COUNT(DISTINCT Publication_Date) FROM publication ### context: CREATE TABLE publication (Publication_Date VARCHAR) |
### question: Show the prices of publications whose publisher is either "Person" or "Wiley" ### answer: SELECT Price FROM publication WHERE Publisher = "Person" OR Publisher = "Wiley" ### context: CREATE TABLE publication (Price VARCHAR, Publisher VARCHAR) |
### question: How many actors are there? ### answer: SELECT COUNT(*) FROM actor ### context: CREATE TABLE actor (Id VARCHAR) |
### question: List the name of actors in ascending alphabetical order. ### answer: SELECT Name FROM actor ORDER BY Name ### context: CREATE TABLE actor (Name VARCHAR) |
### question: What are the characters and duration of actors? ### answer: SELECT Character, Duration FROM actor ### context: CREATE TABLE actor (Character VARCHAR, Duration VARCHAR) |
### question: List the name of actors whose age is not 20. ### answer: SELECT Name FROM actor WHERE Age <> 20 ### context: CREATE TABLE actor (Name VARCHAR, Age VARCHAR) |
### question: What are the characters of actors in descending order of age? ### answer: SELECT Character FROM actor ORDER BY age DESC ### context: CREATE TABLE actor (Character VARCHAR, age VARCHAR) |
### question: What is the duration of the oldest actor? ### answer: SELECT Duration FROM actor ORDER BY Age DESC LIMIT 1 ### context: CREATE TABLE actor (Duration VARCHAR, Age VARCHAR) |
### question: What are the names of musicals with nominee "Bob Fosse"? ### answer: SELECT Name FROM musical WHERE Nominee = "Bob Fosse" ### context: CREATE TABLE musical (Name VARCHAR, Nominee VARCHAR) |
### question: What are the distinct nominees of the musicals with the award that is not "Tony Award"? ### answer: SELECT DISTINCT Nominee FROM musical WHERE Award <> "Tony Award" ### context: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR) |
### question: Show names of actors and names of musicals they are in. ### answer: SELECT T1.Name, T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID ### context: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR); CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR) |
### question: Show names of actors that have appeared in musical with name "The Phantom of the Opera". ### answer: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID WHERE T2.Name = "The Phantom of the Opera" ### context: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR); CREATE TABLE musical (Musical_ID VARCHAR, Name VARCHAR) |
### question: Show names of actors in descending order of the year their musical is awarded. ### answer: SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID ORDER BY T2.Year DESC ### context: CREATE TABLE musical (Musical_ID VARCHAR, Year VARCHAR); CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR) |
### question: Show names of musicals and the number of actors who have appeared in the musicals. ### answer: SELECT T2.Name, COUNT(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID ### context: CREATE TABLE actor (Musical_ID VARCHAR); CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR) |
### question: Show names of musicals which have at least three actors. ### answer: SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT(*) >= 3 ### context: CREATE TABLE actor (Musical_ID VARCHAR); CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR) |
### question: Show different nominees and the number of musicals they have been nominated. ### answer: SELECT Nominee, COUNT(*) FROM musical GROUP BY Nominee ### context: CREATE TABLE musical (Nominee VARCHAR) |
### question: Please show the nominee who has been nominated the greatest number of times. ### answer: SELECT Nominee FROM musical GROUP BY Nominee ORDER BY COUNT(*) DESC LIMIT 1 ### context: CREATE TABLE musical (Nominee VARCHAR) |
### question: List the most common result of the musicals. ### answer: SELECT RESULT FROM musical GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1 ### context: CREATE TABLE musical (RESULT VARCHAR) |
### question: List the nominees that have been nominated more than two musicals. ### answer: SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT(*) > 2 ### context: CREATE TABLE musical (Nominee VARCHAR) |
### question: List the name of musicals that do not have actors. ### answer: SELECT Name FROM musical WHERE NOT Musical_ID IN (SELECT Musical_ID FROM actor) ### context: CREATE TABLE actor (Name VARCHAR, Musical_ID VARCHAR); CREATE TABLE musical (Name VARCHAR, Musical_ID VARCHAR) |
### question: Show the nominees that have nominated musicals for both "Tony Award" and "Drama Desk Award". ### answer: SELECT Nominee FROM musical WHERE Award = "Tony Award" INTERSECT SELECT Nominee FROM musical WHERE Award = "Drama Desk Award" ### context: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR) |
### question: Show the musical nominee with award "Bob Fosse" or "Cleavant Derricks". ### answer: SELECT Nominee FROM musical WHERE Award = "Tony Award" OR Award = "Cleavant Derricks" ### context: CREATE TABLE musical (Nominee VARCHAR, Award VARCHAR) |
### question: Find the emails of the user named "Mary". ### answer: SELECT email FROM user_profiles WHERE name = 'Mary' ### context: CREATE TABLE user_profiles (email VARCHAR, name VARCHAR) |
### question: What is the partition id of the user named "Iron Man". ### answer: SELECT partitionid FROM user_profiles WHERE name = 'Iron Man' ### context: CREATE TABLE user_profiles (partitionid VARCHAR, name VARCHAR) |
### question: How many users are there? ### answer: SELECT COUNT(*) FROM user_profiles ### context: CREATE TABLE user_profiles (Id VARCHAR) |
### question: How many followers does each user have? ### answer: SELECT COUNT(*) FROM follows ### context: CREATE TABLE follows (Id VARCHAR) |
### question: Find the number of followers for each user. ### answer: SELECT COUNT(*) FROM follows GROUP BY f1 ### context: CREATE TABLE follows (f1 VARCHAR) |
### question: Find the number of tweets in record. ### answer: SELECT COUNT(*) FROM tweets ### context: CREATE TABLE tweets (Id VARCHAR) |
### question: Find the number of users who posted some tweets. ### answer: SELECT COUNT(DISTINCT UID) FROM tweets ### context: CREATE TABLE tweets (UID VARCHAR) |
### question: Find the name and email of the user whose name contains the word ‘Swift’. ### answer: SELECT name, email FROM user_profiles WHERE name LIKE '%Swift%' ### context: CREATE TABLE user_profiles (name VARCHAR, email VARCHAR) |
### question: Find the names of users whose emails contain ‘superstar’ or ‘edu’. ### answer: SELECT name FROM user_profiles WHERE email LIKE '%superstar%' OR email LIKE '%edu%' ### context: CREATE TABLE user_profiles (name VARCHAR, email VARCHAR) |
### question: Return the text of tweets about the topic 'intern'. ### answer: SELECT text FROM tweets WHERE text LIKE '%intern%' ### context: CREATE TABLE tweets (text VARCHAR) |
### question: Find the name and email of the users who have more than 1000 followers. ### answer: SELECT name, email FROM user_profiles WHERE followers > 1000 ### context: CREATE TABLE user_profiles (name VARCHAR, email VARCHAR, followers INTEGER) |
### question: Find the names of the users whose number of followers is greater than that of the user named "Tyler Swift". ### answer: SELECT T1.name FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT(*) > (SELECT COUNT(*) FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 WHERE T1.name = 'Tyler Swift') ### context: CREATE TABLE follows (f1 VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR) |
### question: Find the name and email for the users who have more than one follower. ### answer: SELECT T1.name, T1.email FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT(*) > 1 ### context: CREATE TABLE follows (f1 VARCHAR); CREATE TABLE user_profiles (name VARCHAR, email VARCHAR, uid VARCHAR) |
### question: Find the names of users who have more than one tweet. ### answer: SELECT T1.name FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) > 1 ### context: CREATE TABLE tweets (uid VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR) |
### question: Find the id of users who are followed by Mary and Susan. ### answer: SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = "Mary" INTERSECT SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = "Susan" ### context: CREATE TABLE follows (f1 VARCHAR, f2 VARCHAR); CREATE TABLE user_profiles (uid VARCHAR, name VARCHAR) |
### question: Find the id of users who are followed by Mary or Susan. ### answer: SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = "Mary" OR T1.name = "Susan" ### context: CREATE TABLE follows (f1 VARCHAR, f2 VARCHAR); CREATE TABLE user_profiles (uid VARCHAR, name VARCHAR) |
### question: Find the name of the user who has the largest number of followers. ### answer: SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 1 ### context: CREATE TABLE user_profiles (name VARCHAR, followers VARCHAR) |
### question: Find the name and email of the user followed by the least number of people. ### answer: SELECT name, email FROM user_profiles ORDER BY followers LIMIT 1 ### context: CREATE TABLE user_profiles (name VARCHAR, email VARCHAR, followers VARCHAR) |
### question: List the name and number of followers for each user, and sort the results by the number of followers in descending order. ### answer: SELECT name, followers FROM user_profiles ORDER BY followers DESC ### context: CREATE TABLE user_profiles (name VARCHAR, followers VARCHAR) |
### question: List the names of 5 users followed by the largest number of other users. ### answer: SELECT name FROM user_profiles ORDER BY followers DESC LIMIT 5 ### context: CREATE TABLE user_profiles (name VARCHAR, followers VARCHAR) |
### question: List the text of all tweets in the order of date. ### answer: SELECT text FROM tweets ORDER BY createdate ### context: CREATE TABLE tweets (text VARCHAR, createdate VARCHAR) |
### question: Find the name of each user and number of tweets tweeted by each of them. ### answer: SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid ### context: CREATE TABLE tweets (uid VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR) |
### question: Find the name and partition id for users who tweeted less than twice. ### answer: SELECT T1.name, T1.partitionid FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) < 2 ### context: CREATE TABLE user_profiles (name VARCHAR, partitionid VARCHAR, uid VARCHAR); CREATE TABLE tweets (uid VARCHAR) |
### question: Find the name of the user who tweeted more than once, and number of tweets tweeted by them. ### answer: SELECT T1.name, COUNT(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT(*) > 1 ### context: CREATE TABLE tweets (uid VARCHAR); CREATE TABLE user_profiles (name VARCHAR, uid VARCHAR) |
### question: Find the average number of followers for the users who do not have any tweet. ### answer: SELECT AVG(followers) FROM user_profiles WHERE NOT UID IN (SELECT UID FROM tweets) ### context: CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR); CREATE TABLE tweets (followers INTEGER, UID VARCHAR) |
### question: Find the average number of followers for the users who had some tweets. ### answer: SELECT AVG(followers) FROM user_profiles WHERE UID IN (SELECT UID FROM tweets) ### context: CREATE TABLE user_profiles (followers INTEGER, UID VARCHAR); CREATE TABLE tweets (followers INTEGER, UID VARCHAR) |
### question: Find the maximum and total number of followers of all users. ### answer: SELECT MAX(followers), SUM(followers) FROM user_profiles ### context: CREATE TABLE user_profiles (followers INTEGER) |
### question: Find the names of all the catalog entries. ### answer: SELECT DISTINCT (catalog_entry_name) FROM catalog_contents ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR) |
### question: Find the list of attribute data types possessed by more than 3 attribute definitions. ### answer: SELECT attribute_data_type FROM Attribute_Definitions GROUP BY attribute_data_type HAVING COUNT(*) > 3 ### context: CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR) |
### question: What is the attribute data type of the attribute with name "Green"? ### answer: SELECT attribute_data_type FROM Attribute_Definitions WHERE attribute_name = "Green" ### context: CREATE TABLE Attribute_Definitions (attribute_data_type VARCHAR, attribute_name VARCHAR) |
### question: Find the name and level of catalog structure with level between 5 and 10. ### answer: SELECT catalog_level_name, catalog_level_number FROM Catalog_Structure WHERE catalog_level_number BETWEEN 5 AND 10 ### context: CREATE TABLE Catalog_Structure (catalog_level_name VARCHAR, catalog_level_number INTEGER) |
### question: Find all the catalog publishers whose name contains "Murray" ### answer: SELECT DISTINCT (catalog_publisher) FROM catalogs WHERE catalog_publisher LIKE "%Murray%" ### context: CREATE TABLE catalogs (catalog_publisher VARCHAR) |
### question: Which catalog publisher has published the most catalogs? ### answer: SELECT catalog_publisher FROM catalogs GROUP BY catalog_publisher ORDER BY COUNT(*) DESC LIMIT 1 ### context: CREATE TABLE catalogs (catalog_publisher VARCHAR) |
### question: Find the names and publication dates of all catalogs that have catalog level number greater than 5. ### answer: SELECT t1.catalog_name, t1.date_of_publication FROM catalogs AS t1 JOIN catalog_structure AS t2 ON t1.catalog_id = t2.catalog_id WHERE catalog_level_number > 5 ### context: CREATE TABLE catalogs (catalog_name VARCHAR, date_of_publication VARCHAR, catalog_id VARCHAR); CREATE TABLE catalog_structure (catalog_id VARCHAR) |
### question: What are the entry names of catalog with the attribute possessed by most entries. ### answer: SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id = t2.catalog_entry_id WHERE t2.attribute_value = (SELECT attribute_value FROM Catalog_Contents_Additional_Attributes GROUP BY attribute_value ORDER BY COUNT(*) DESC LIMIT 1) ### context: CREATE TABLE Catalog_Contents_Additional_Attributes (catalog_entry_id VARCHAR, attribute_value VARCHAR); CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, catalog_entry_id VARCHAR); CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_value VARCHAR) |
### question: What is the entry name of the most expensive catalog (in USD)? ### answer: SELECT catalog_entry_name FROM catalog_contents ORDER BY price_in_dollars DESC LIMIT 1 ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, price_in_dollars VARCHAR) |
### question: What is the level name of the cheapest catalog (in USD)? ### answer: SELECT t2.catalog_level_name FROM catalog_contents AS t1 JOIN catalog_structure AS t2 ON t1.catalog_level_number = t2.catalog_level_number ORDER BY t1.price_in_dollars LIMIT 1 ### context: CREATE TABLE catalog_structure (catalog_level_name VARCHAR, catalog_level_number VARCHAR); CREATE TABLE catalog_contents (catalog_level_number VARCHAR, price_in_dollars VARCHAR) |
### question: What are the average and minimum price (in Euro) of all products? ### answer: SELECT AVG(price_in_euros), MIN(price_in_euros) FROM catalog_contents ### context: CREATE TABLE catalog_contents (price_in_euros INTEGER) |
### question: What is the product with the highest height? Give me the catalog entry name. ### answer: SELECT catalog_entry_name FROM catalog_contents ORDER BY height DESC LIMIT 1 ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, height VARCHAR) |
### question: Find the name of the product that has the smallest capacity. ### answer: SELECT catalog_entry_name FROM catalog_contents ORDER BY capacity LIMIT 1 ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, capacity VARCHAR) |
### question: Find the names of all the products whose stock number starts with "2". ### answer: SELECT catalog_entry_name FROM catalog_contents WHERE product_stock_number LIKE "2%" ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, product_stock_number VARCHAR) |
### question: Find the names of catalog entries with level number 8. ### answer: SELECT t1.catalog_entry_name FROM Catalog_Contents AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.catalog_entry_id = t2.catalog_entry_id WHERE t2.catalog_level_number = "8" ### context: CREATE TABLE Catalog_Contents_Additional_Attributes (catalog_entry_id VARCHAR, catalog_level_number VARCHAR); CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, catalog_entry_id VARCHAR) |
### question: Find the names of the products with length smaller than 3 or height greater than 5. ### answer: SELECT catalog_entry_name FROM catalog_contents WHERE LENGTH < 3 OR width > 5 ### context: CREATE TABLE catalog_contents (catalog_entry_name VARCHAR, LENGTH VARCHAR, width VARCHAR) |
### question: Find the name and attribute ID of the attribute definitions with attribute value 0. ### answer: SELECT t1.attribute_name, t1.attribute_id FROM Attribute_Definitions AS t1 JOIN Catalog_Contents_Additional_Attributes AS t2 ON t1.attribute_id = t2.attribute_id WHERE t2.attribute_value = 0 ### context: CREATE TABLE Catalog_Contents_Additional_Attributes (attribute_id VARCHAR, attribute_value VARCHAR); CREATE TABLE Attribute_Definitions (attribute_name VARCHAR, attribute_id VARCHAR) |
### question: Find the name and capacity of products with price greater than 700 (in USD). ### answer: SELECT catalog_entry_name, capacity FROM Catalog_Contents WHERE price_in_dollars > 700 ### context: CREATE TABLE Catalog_Contents (catalog_entry_name VARCHAR, capacity VARCHAR, price_in_dollars INTEGER) |