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Matrix工作室 3

A

Infinity Gauntlet

PROGRAMMING

You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems: - the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color. Using colors of Gems you saw in the Gauntlet determine the names of absent Gems.

In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet. In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters.

In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems. Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase.

In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space. In the second sample Thanos doesn't have any Gems, so he needs all six.

Python 3

OK

TESTS

dict1={"purple":"Power", "green":"Time", "blue":"Space", "orange":"Soul", "red":"Reality", "yellow":"Mind"} n=int(input()) n_list=[] print(6-n) for i in range(n): g=input() n_list.append(g) for k,v in dict1.items(): if k not in n_list: print(v)

Title: Infinity Gauntlet Time Limit: None seconds Memory Limit: None megabytes Problem Description: You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems: - the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color. Using colors of Gems you saw in the Gauntlet determine the names of absent Gems. Input Specification: In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet. In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters. Output Specification: In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems. Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. Demo Input: ['4\nred\npurple\nyellow\norange\n', '0\n'] Demo Output: ['2\nSpace\nTime\n', '6\nTime\nMind\nSoul\nPower\nReality\nSpace\n'] Note: In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space. In the second sample Thanos doesn't have any Gems, so he needs all six.

```python dict1={"purple":"Power", "green":"Time", "blue":"Space", "orange":"Soul", "red":"Reality", "yellow":"Mind"} n=int(input()) n_list=[] print(6-n) for i in range(n): g=input() n_list.append(g) for k,v in dict1.items(): if k not in n_list: print(v) ```

B

Books

PROGRAMMING

When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to read the *i*-th book. Valera decided to choose an arbitrary book with number *i* and read the books one by one, starting from this book. In other words, he will first read book number *i*, then book number *i*<=+<=1, then book number *i*<=+<=2 and so on. He continues the process until he either runs out of the free time or finishes reading the *n*-th book. Valera reads each book up to the end, that is, he doesn't start reading the book if he doesn't have enough free time to finish reading it. Print the maximum number of books Valera can read.

The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy needs to read the *i*-th book.

Print a single integer — the maximum number of books Valera can read.

none

Python 3

OK

TESTS

p=lambda:list(map(int,input().split())) n,t=p() l=p() i=j=s=0 for j in range(n): s+=l[j] if s>t: s-=l[i] i+=1 print(n-i)

Title: Books Time Limit: None seconds Memory Limit: None megabytes Problem Description: When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to read the *i*-th book. Valera decided to choose an arbitrary book with number *i* and read the books one by one, starting from this book. In other words, he will first read book number *i*, then book number *i*<=+<=1, then book number *i*<=+<=2 and so on. He continues the process until he either runs out of the free time or finishes reading the *n*-th book. Valera reads each book up to the end, that is, he doesn't start reading the book if he doesn't have enough free time to finish reading it. Print the maximum number of books Valera can read. Input Specification: The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy needs to read the *i*-th book. Output Specification: Print a single integer — the maximum number of books Valera can read. Demo Input: ['4 5\n3 1 2 1\n', '3 3\n2 2 3\n'] Demo Output: ['3\n', '1\n'] Note: none

```python p=lambda:list(map(int,input().split())) n,t=p() l=p() i=j=s=0 for j in range(n): s+=l[j] if s>t: s-=l[i] i+=1 print(n-i) ```

A

Statues

PROGRAMMING

In this task Anna and Maria play a game with a very unpleasant rival. Anna and Maria are in the opposite squares of a chessboard (8<=×<=8): Anna is in the upper right corner, and Maria is in the lower left one. Apart from them, the board has several statues. Each statue occupies exactly one square. A square that contains a statue cannot have anything or anyone — neither any other statues, nor Anna, nor Maria. Anna is present on the board as a figurant (she stands still and never moves), and Maria has been actively involved in the game. Her goal is — to come to Anna's square. Maria and statues move in turn, Maria moves first. During one move Maria can go to any adjacent on the side or diagonal cell in which there is no statue, or she can stay in the cell where she is. The statues during their move must go one square down simultaneously, and those statues that were in the bottom row fall from the board and are no longer appeared. At that moment, when one of the statues is in the cell in which the Maria is, the statues are declared winners. At the moment when Maria comes into the cell where Anna has been waiting, Maria is declared the winner. Obviously, nothing depends on the statues, so it all depends on Maria. Determine who will win, if Maria does not make a strategic error.

You are given the 8 strings whose length equals 8, describing the initial position on the board. The first line represents the top row of the board, the next one — for the second from the top, and so on, the last line represents the bottom row. Each character string matches a single cell board in the appropriate row, and the characters are in the same manner as that of the corresponding cell. If the cell is empty, the corresponding character is ".". If a cell has Maria, then it is represented by character "M". If a cell has Anna, it is represented by the character "A". If a cell has a statue, then the cell is represented by character "S". It is guaranteed that the last character of the first row is always "A", the first character of the last line is always "M". The remaining characters are "." or "S".

If Maria wins, print string "WIN". If the statues win, print string "LOSE".

none

Python 3

WRONG_ANSWER

TESTS

from collections import deque as dq r = 8 c = 8 start = [] end = [] g = [list(input()) for i in range(r)] s = [0 for i in range(r)] for i in range(r): for j in range(c): if g[i][j] == 'M': start = [i, j] a = [] elif g[i][j] == 'A': end = [i, j] a = [] elif g[i][j] == '.': a = [] elif g[i][j] == 'S': a = [1] if i == 0: g[i][j] = a else: for k in range(len(g[i-1][j])): a.append(int(g[i-1][j][k])+1) g[i][j] = a d = dq() d.append([start[0], start[1], 1]) vis = [[-1 for i in range(c)] for j in range(r)] while len(d) > 0: x, y, nb = d.popleft() vis[x][y] = nb row = [1, 0, 0, -1] col = [0, 1, -1, 0] for k in range(4): a = x+row[k] b = y+col[k] if 0 <= a < r and 0 <= b < c: if nb not in g[a][b] and vis[a][b] == -1: vis[a][b] = nb+1 d.append([a, b, nb+1]) x = end[0] y = end[1] if vis[x][y] == -1: print('NO') else: print('YES')

Title: Statues Time Limit: None seconds Memory Limit: None megabytes Problem Description: In this task Anna and Maria play a game with a very unpleasant rival. Anna and Maria are in the opposite squares of a chessboard (8<=×<=8): Anna is in the upper right corner, and Maria is in the lower left one. Apart from them, the board has several statues. Each statue occupies exactly one square. A square that contains a statue cannot have anything or anyone — neither any other statues, nor Anna, nor Maria. Anna is present on the board as a figurant (she stands still and never moves), and Maria has been actively involved in the game. Her goal is — to come to Anna's square. Maria and statues move in turn, Maria moves first. During one move Maria can go to any adjacent on the side or diagonal cell in which there is no statue, or she can stay in the cell where she is. The statues during their move must go one square down simultaneously, and those statues that were in the bottom row fall from the board and are no longer appeared. At that moment, when one of the statues is in the cell in which the Maria is, the statues are declared winners. At the moment when Maria comes into the cell where Anna has been waiting, Maria is declared the winner. Obviously, nothing depends on the statues, so it all depends on Maria. Determine who will win, if Maria does not make a strategic error. Input Specification: You are given the 8 strings whose length equals 8, describing the initial position on the board. The first line represents the top row of the board, the next one — for the second from the top, and so on, the last line represents the bottom row. Each character string matches a single cell board in the appropriate row, and the characters are in the same manner as that of the corresponding cell. If the cell is empty, the corresponding character is ".". If a cell has Maria, then it is represented by character "M". If a cell has Anna, it is represented by the character "A". If a cell has a statue, then the cell is represented by character "S". It is guaranteed that the last character of the first row is always "A", the first character of the last line is always "M". The remaining characters are "." or "S". Output Specification: If Maria wins, print string "WIN". If the statues win, print string "LOSE". Demo Input: ['.......A\n........\n........\n........\n........\n........\n........\nM.......\n', '.......A\n........\n........\n........\n........\n........\nSS......\nM.......\n', '.......A\n........\n........\n........\n........\n.S......\nS.......\nMS......\n'] Demo Output: ['WIN\n', 'LOSE\n', 'LOSE\n'] Note: none

```python from collections import deque as dq r = 8 c = 8 start = [] end = [] g = [list(input()) for i in range(r)] s = [0 for i in range(r)] for i in range(r): for j in range(c): if g[i][j] == 'M': start = [i, j] a = [] elif g[i][j] == 'A': end = [i, j] a = [] elif g[i][j] == '.': a = [] elif g[i][j] == 'S': a = [1] if i == 0: g[i][j] = a else: for k in range(len(g[i-1][j])): a.append(int(g[i-1][j][k])+1) g[i][j] = a d = dq() d.append([start[0], start[1], 1]) vis = [[-1 for i in range(c)] for j in range(r)] while len(d) > 0: x, y, nb = d.popleft() vis[x][y] = nb row = [1, 0, 0, -1] col = [0, 1, -1, 0] for k in range(4): a = x+row[k] b = y+col[k] if 0 <= a < r and 0 <= b < c: if nb not in g[a][b] and vis[a][b] == -1: vis[a][b] = nb+1 d.append([a, b, nb+1]) x = end[0] y = end[1] if vis[x][y] == -1: print('NO') else: print('YES') ```

A

Keyboard

PROGRAMMING

Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way: Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That means that now he presses not a button he wants, but one neighboring button (left or right, as specified in input). We have a sequence of characters he has typed and we want to find the original message.

First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right). Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain spaces as there is no space on Mole's keyboard. It is guaranteed that even though Mole hands are moved, he is still pressing buttons on keyboard and not hitting outside it.

Print a line that contains the original message.

none

Python 3

OK

TESTS

a = input() b = list(input()) key = list("qwertyuiopasdfghjkl;zxcvbnm,./") if a =="L": d=1 else: d=-1 n=[] for i in range(len(b)): e = b[i] f = key.index(e) n.append(key[f+d]) print(''.join(n))

Title: Keyboard Time Limit: None seconds Memory Limit: None megabytes Problem Description: Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way: Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That means that now he presses not a button he wants, but one neighboring button (left or right, as specified in input). We have a sequence of characters he has typed and we want to find the original message. Input Specification: First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right). Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain spaces as there is no space on Mole's keyboard. It is guaranteed that even though Mole hands are moved, he is still pressing buttons on keyboard and not hitting outside it. Output Specification: Print a line that contains the original message. Demo Input: ['R\ns;;upimrrfod;pbr\n'] Demo Output: ['allyouneedislove\n'] Note: none

```python a = input() b = list(input()) key = list("qwertyuiopasdfghjkl;zxcvbnm,./") if a =="L": d=1 else: d=-1 n=[] for i in range(len(b)): e = b[i] f = key.index(e) n.append(key[f+d]) print(''.join(n)) ```

B

Big Segment

PROGRAMMING

A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*]. You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1. Formally we will assume that segment [*a*,<=*b*] covers segment [*c*,<=*d*], if they meet this condition *a*<=≤<=*c*<=≤<=*d*<=≤<=*b*.

The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment. It is guaranteed that no two segments coincide.

Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1. The segments are numbered starting from 1 in the order in which they appear in the input.

none

Python 3

TIME_LIMIT_EXCEEDED

TESTS

n = int(input()) pieces = [] for i in range(n): pieces.append([int(i) for i in input().split()]) raw_pieces = pieces[:] pieces.sort() for (s, f) in pieces: if s > pieces[0][0]: break for (s2, f2) in pieces: if s <= s2 <= f2 <= f: continue break else: print(raw_pieces.index([s, f]) + 1) exit(0) print(-1)

Title: Big Segment Time Limit: None seconds Memory Limit: None megabytes Problem Description: A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*]. You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all other ones. Now you want to test your assumption. Find in the given set the segment which covers all other segments, and print its number. If such a segment doesn't exist, print -1. Formally we will assume that segment [*a*,<=*b*] covers segment [*c*,<=*d*], if they meet this condition *a*<=≤<=*c*<=≤<=*d*<=≤<=*b*. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment. It is guaranteed that no two segments coincide. Output Specification: Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1. The segments are numbered starting from 1 in the order in which they appear in the input. Demo Input: ['3\n1 1\n2 2\n3 3\n', '6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n'] Demo Output: ['-1\n', '3\n'] Note: none

```python n = int(input()) pieces = [] for i in range(n): pieces.append([int(i) for i in input().split()]) raw_pieces = pieces[:] pieces.sort() for (s, f) in pieces: if s > pieces[0][0]: break for (s2, f2) in pieces: if s <= s2 <= f2 <= f: continue break else: print(raw_pieces.index([s, f]) + 1) exit(0) print(-1) ```

C

Little Girl and Maximum Sum

PROGRAMMING

The little girl loves the problems on array queries very much. One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1); also, there are $q$ queries, each one is defined by a pair of integers $l_i$, $r_i$ $(1 \le l_i \le r_i \le n)$. You need to find for each query the sum of elements of the array with indexes from $l_i$ to $r_i$, inclusive. The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.

The first line contains two space-separated integers $n$ ($1 \le n \le 2\cdot10^5$) and $q$ ($1 \le q \le 2\cdot10^5$) — the number of elements in the array and the number of queries, correspondingly. The next line contains $n$ space-separated integers $a_i$ ($1 \le a_i \le 2\cdot10^5$) — the array elements. Each of the following $q$ lines contains two space-separated integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le n$) — the $i$-th query.

In a single line print, a single integer — the maximum sum of query replies after the array elements are reordered. Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.

none

Python 3

TIME_LIMIT_EXCEEDED

TESTS

def main(): n, q = list(map(int, input().strip().split())) a = list(map(int, input().strip().split())) queries = [] array = [0]*(n+1) for i in range(q): li, ri = list(map(int, input().strip().split())) for i in range(li, ri+1): array[i] += 1 a.sort(reverse = True) array.sort(reverse = True) solution = 0 for i in range(0, n): solution += (a[i]*array[i]) print(str(solution)) if __name__ == '__main__': main()

Title: Little Girl and Maximum Sum Time Limit: None seconds Memory Limit: None megabytes Problem Description: The little girl loves the problems on array queries very much. One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1); also, there are $q$ queries, each one is defined by a pair of integers $l_i$, $r_i$ $(1 \le l_i \le r_i \le n)$. You need to find for each query the sum of elements of the array with indexes from $l_i$ to $r_i$, inclusive. The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum. Input Specification: The first line contains two space-separated integers $n$ ($1 \le n \le 2\cdot10^5$) and $q$ ($1 \le q \le 2\cdot10^5$) — the number of elements in the array and the number of queries, correspondingly. The next line contains $n$ space-separated integers $a_i$ ($1 \le a_i \le 2\cdot10^5$) — the array elements. Each of the following $q$ lines contains two space-separated integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le n$) — the $i$-th query. Output Specification: In a single line print, a single integer — the maximum sum of query replies after the array elements are reordered. Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Demo Input: ['3 3\n5 3 2\n1 2\n2 3\n1 3\n', '5 3\n5 2 4 1 3\n1 5\n2 3\n2 3\n'] Demo Output: ['25\n', '33\n'] Note: none

```python def main(): n, q = list(map(int, input().strip().split())) a = list(map(int, input().strip().split())) queries = [] array = [0]*(n+1) for i in range(q): li, ri = list(map(int, input().strip().split())) for i in range(li, ri+1): array[i] += 1 a.sort(reverse = True) array.sort(reverse = True) solution = 0 for i in range(0, n): solution += (a[i]*array[i]) print(str(solution)) if __name__ == '__main__': main() ```

C

Valera and Elections

PROGRAMMING

The city Valera lives in is going to hold elections to the city Parliament. The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other district. Let's enumerate all districts in some way by integers from 1 to *n*, inclusive. Furthermore, for each road the residents decided if it is the problem road or not. A problem road is a road that needs to be repaired. There are *n* candidates running the elections. Let's enumerate all candidates in some way by integers from 1 to *n*, inclusive. If the candidate number *i* will be elected in the city Parliament, he will perform exactly one promise — to repair all problem roads on the way from the *i*-th district to the district 1, where the city Parliament is located. Help Valera and determine the subset of candidates such that if all candidates from the subset will be elected to the city Parliament, all problem roads in the city will be repaired. If there are several such subsets, you should choose the subset consisting of the minimum number of candidates.

The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of districts in the city. Then *n*<=-<=1 lines follow. Each line contains the description of a city road as three positive integers *x**i*, *y**i*, *t**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*, 1<=≤<=*t**i*<=≤<=2) — the districts connected by the *i*-th bidirectional road and the road type. If *t**i* equals to one, then the *i*-th road isn't the problem road; if *t**i* equals to two, then the *i*-th road is the problem road. It's guaranteed that the graph structure of the city is a tree.

In the first line print a single non-negative number *k* — the minimum size of the required subset of candidates. Then on the second line print *k* space-separated integers *a*1,<=*a*2,<=... *a**k* — the numbers of the candidates that form the required subset. If there are multiple solutions, you are allowed to print any of them.

none

Python 3

RUNTIME_ERROR

TESTS

a = int(input()) nodesx = [] nodesy = [] nodesz = [] out = [] for i in range(a-1): tmp = list(map(int, input().split())) nodesx.append(tmp[0]) nodesy.append(tmp[1]) nodesz.append(tmp[2]) summ = 0 for i in range(len(nodesy)): if nodesy[i] not in nodesx: start = i current = i flag = False while True: # print(curren) if nodesz[current] == 3: break elif nodesz[current] == 2 and flag == False: flag = True summ += 1 out.append(nodesy[start]) nodesz[current] = 3 if nodesx[current] == 1: break current = nodesy.index(nodesx[current]) print(summ) for item in out: print(item,end=' ')

Title: Valera and Elections Time Limit: None seconds Memory Limit: None megabytes Problem Description: The city Valera lives in is going to hold elections to the city Parliament. The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other district. Let's enumerate all districts in some way by integers from 1 to *n*, inclusive. Furthermore, for each road the residents decided if it is the problem road or not. A problem road is a road that needs to be repaired. There are *n* candidates running the elections. Let's enumerate all candidates in some way by integers from 1 to *n*, inclusive. If the candidate number *i* will be elected in the city Parliament, he will perform exactly one promise — to repair all problem roads on the way from the *i*-th district to the district 1, where the city Parliament is located. Help Valera and determine the subset of candidates such that if all candidates from the subset will be elected to the city Parliament, all problem roads in the city will be repaired. If there are several such subsets, you should choose the subset consisting of the minimum number of candidates. Input Specification: The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of districts in the city. Then *n*<=-<=1 lines follow. Each line contains the description of a city road as three positive integers *x**i*, *y**i*, *t**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*, 1<=≤<=*t**i*<=≤<=2) — the districts connected by the *i*-th bidirectional road and the road type. If *t**i* equals to one, then the *i*-th road isn't the problem road; if *t**i* equals to two, then the *i*-th road is the problem road. It's guaranteed that the graph structure of the city is a tree. Output Specification: In the first line print a single non-negative number *k* — the minimum size of the required subset of candidates. Then on the second line print *k* space-separated integers *a*1,<=*a*2,<=... *a**k* — the numbers of the candidates that form the required subset. If there are multiple solutions, you are allowed to print any of them. Demo Input: ['5\n1 2 2\n2 3 2\n3 4 2\n4 5 2\n', '5\n1 2 1\n2 3 2\n2 4 1\n4 5 1\n', '5\n1 2 2\n1 3 2\n1 4 2\n1 5 2\n'] Demo Output: ['1\n5 \n', '1\n3 \n', '4\n5 4 3 2 \n'] Note: none

```python a = int(input()) nodesx = [] nodesy = [] nodesz = [] out = [] for i in range(a-1): tmp = list(map(int, input().split())) nodesx.append(tmp[0]) nodesy.append(tmp[1]) nodesz.append(tmp[2]) summ = 0 for i in range(len(nodesy)): if nodesy[i] not in nodesx: start = i current = i flag = False while True: # print(curren) if nodesz[current] == 3: break elif nodesz[current] == 2 and flag == False: flag = True summ += 1 out.append(nodesy[start]) nodesz[current] = 3 if nodesx[current] == 1: break current = nodesy.index(nodesx[current]) print(summ) for item in out: print(item,end=' ') ```

A

Petr and a calendar

PROGRAMMING

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture: Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Print single integer: the number of columns the table should have.

The first example corresponds to the January 2017 shown on the picture in the statements. In the second example 1-st January is Monday, so the whole month fits into 5 columns. In the third example 1-st November is Saturday and 5 columns is enough.

Python 3

OK

TESTS

import math m, d = map(int, input().split()) a = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] print(math.ceil((a[m-1]+d-1)/7))

Title: Petr and a calendar Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture: Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap. Input Specification: The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). Output Specification: Print single integer: the number of columns the table should have. Demo Input: ['1 7\n', '1 1\n', '11 6\n'] Demo Output: ['6\n', '5\n', '5\n'] Note: The first example corresponds to the January 2017 shown on the picture in the statements. In the second example 1-st January is Monday, so the whole month fits into 5 columns. In the third example 1-st November is Saturday and 5 columns is enough.

```python import math m, d = map(int, input().split()) a = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] print(math.ceil((a[m-1]+d-1)/7)) ```

A

Grasshopper And the String

PROGRAMMING

One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump. Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability. The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'.

The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100.

Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels.

none

PyPy 3

OK

TESTS

l=['A','U','O','I','E','Y'] s=input() c=0 m=0 for i in s: if(i in l): m=max(m,c) c=0 else: c=c+1 m=max(c,m) print(m+1)

Title: Grasshopper And the String Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump. Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability. The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'. Input Specification: The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. Output Specification: Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. Demo Input: ['ABABBBACFEYUKOTT\n', 'AAA\n'] Demo Output: ['4', '1'] Note: none

```python l=['A','U','O','I','E','Y'] s=input() c=0 m=0 for i in s: if(i in l): m=max(m,c) c=0 else: c=c+1 m=max(c,m) print(m+1) ```

A

Young Physicist

PROGRAMMING

A. Young Physicist

2

256

A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.

The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).

Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.

none

Python 3

WRONG_ANSWER

TESTS

n=int(input()) i=n d,e,f=0,0,0 while(i!=0): a,b,c=input().split() a,b,c=int(a),int(b),int(c) d=a+d e=b+d f=c+f i=i-1 if(d==0 and e==0 and f==0): print("YES") else: print("NO")

Title: Young Physicist Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. Input Specification: The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). Output Specification: Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. Demo Input: ['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n'] Demo Output: ['NO', 'YES'] Note: none

```python n=int(input()) i=n d,e,f=0,0,0 while(i!=0): a,b,c=input().split() a,b,c=int(a),int(b),int(c) d=a+d e=b+d f=c+f i=i-1 if(d==0 and e==0 and f==0): print("YES") else: print("NO") ```

B

Not simply beatiful strings

PROGRAMMING

Let's call a string adorable if its letters can be realigned in such a way that they form two consequent groups of equal symbols (note that different groups must contain different symbols). For example, ababa is adorable (you can transform it to aaabb, where the first three letters form a group of *a*-s and others — a group of *b*-s), but cccc is not since in each possible consequent partition letters in these two groups coincide. You're given a string *s*. Check whether it can be split into two non-empty subsequences such that the strings formed by these subsequences are adorable. Here a subsequence is an arbitrary set of indexes of the string.

The only line contains *s* (1<=≤<=|*s*|<=≤<=105) consisting of lowercase latin letters.

Print «Yes» if the string can be split according to the criteria above or «No» otherwise. Each letter can be printed in arbitrary case.

In sample case two zzcxx can be split into subsequences zc and zxx each of which is adorable. There's no suitable partition in sample case three.

Python 3

OK

TESTS

s = input() l = list(set(s)) ans = 1 if (len(l)>4) or (len(l)<=1): ans = 0 else: if len(l)==2: c1=0 c0=0 for i in range(len(s)): if s[i]==l[0]: c0+=1 else: c1+=1 if (c1<2) or (c0<2): ans = 0 if (len(l)==3): c1 = 0 c2 = 0 c0 = 0 for i in range(len(s)): if s[i]==l[0]: c0+=1 if s[i]==l[1]: c1+=1 if s[i]==l[2]: c2+=1 if (c1+c2+c0)<4: ans = 0 if (ans==0): print('No') else: print('Yes')

Title: Not simply beatiful strings Time Limit: None seconds Memory Limit: None megabytes Problem Description: Let's call a string adorable if its letters can be realigned in such a way that they form two consequent groups of equal symbols (note that different groups must contain different symbols). For example, ababa is adorable (you can transform it to aaabb, where the first three letters form a group of *a*-s and others — a group of *b*-s), but cccc is not since in each possible consequent partition letters in these two groups coincide. You're given a string *s*. Check whether it can be split into two non-empty subsequences such that the strings formed by these subsequences are adorable. Here a subsequence is an arbitrary set of indexes of the string. Input Specification: The only line contains *s* (1<=≤<=|*s*|<=≤<=105) consisting of lowercase latin letters. Output Specification: Print «Yes» if the string can be split according to the criteria above or «No» otherwise. Each letter can be printed in arbitrary case. Demo Input: ['ababa\n', 'zzcxx\n', 'yeee\n'] Demo Output: ['Yes\n', 'Yes\n', 'No\n'] Note: In sample case two zzcxx can be split into subsequences zc and zxx each of which is adorable. There's no suitable partition in sample case three.

```python s = input() l = list(set(s)) ans = 1 if (len(l)>4) or (len(l)<=1): ans = 0 else: if len(l)==2: c1=0 c0=0 for i in range(len(s)): if s[i]==l[0]: c0+=1 else: c1+=1 if (c1<2) or (c0<2): ans = 0 if (len(l)==3): c1 = 0 c2 = 0 c0 = 0 for i in range(len(s)): if s[i]==l[0]: c0+=1 if s[i]==l[1]: c1+=1 if s[i]==l[2]: c2+=1 if (c1+c2+c0)<4: ans = 0 if (ans==0): print('No') else: print('Yes') ```

A

Buy a Shovel

PROGRAMMING

Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop. In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9). What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel.

The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins". Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels.

Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change.

In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change. In the second example it is enough for Polycarp to buy one shovel. In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change.

Python 3

WRONG_ANSWER

TESTS

k,r=list(map(int,input().split())) ls=[] for i in range(1,10): if (k*i)%10==0: print(i) break if k%10==0: print(k//10) else: k=k%10 for i in range(10): ls.append(k*i) for i in ls: if (i-r)%10==0: print(ls.index(i))

Title: Buy a Shovel Time Limit: None seconds Memory Limit: None megabytes Problem Description: Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop. In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9). What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel. Input Specification: The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins". Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels. Output Specification: Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. Demo Input: ['117 3\n', '237 7\n', '15 2\n'] Demo Output: ['9\n', '1\n', '2\n'] Note: In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change. In the second example it is enough for Polycarp to buy one shovel. In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change.

```python k,r=list(map(int,input().split())) ls=[] for i in range(1,10): if (k*i)%10==0: print(i) break if k%10==0: print(k//10) else: k=k%10 for i in range(10): ls.append(k*i) for i in ls: if (i-r)%10==0: print(ls.index(i)) ```

B

A and B and Compilation Errors

PROGRAMMING

A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code. Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix some mistake and then another one mistake. However, despite the fact that B is sure that he corrected the two errors, he can not understand exactly what compilation errors disappeared — the compiler of the language which B uses shows errors in the new order every time! B is sure that unlike many other programming languages, compilation errors for his programming language do not depend on each other, that is, if you correct one error, the set of other error does not change. Can you help B find out exactly what two errors he corrected?

The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time. The third line contains *n*<=-<=1 space-separated integers *b*1,<=*b*2,<=...,<=*b**n*<=-<=1 — the errors displayed at the second compilation. It is guaranteed that the sequence in the third line contains all numbers of the second string except for exactly one. The fourth line contains *n*<=-<=2 space-separated integers *с*1,<=*с*2,<=...,<=*с**n*<=-<=2 — the errors displayed at the third compilation. It is guaranteed that the sequence in the fourth line contains all numbers of the third line except for exactly one.

Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively.

In the first test sample B first corrects the error number 8, then the error number 123. In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step.

Python 3

TIME_LIMIT_EXCEEDED

TESTS

cantidad_digitos = (input()) cantidad_digitos = int(cantidad_digitos) lista_u = (input()).split(" ") lista_d = (input()).split(" ") lista_t = (input()).split(" ") pe = 0 se = 0 m = 0 n = 0 f = 0 x = 0 y = 0 z = 0 i = 0 j = 0 h = 0 a = 0 b = 0 c = 0 diccionario_l_u = {} diccionario_l_d = {} #Contador de repeticiones de la primera lista while m < cantidad_digitos: while n < cantidad_digitos: if lista_u[m] == lista_u[n]: f += 1 n += 1 diccionario_l_u[lista_u[m]] = f f = 0 n = 0 m += 1 #Contador de repeticiones de la Segunda lista while x < cantidad_digitos-1: while y < cantidad_digitos-1: if lista_d[x] == lista_d[y]: z += 1 y += 1 diccionario_l_d[lista_d[x]] = z z = 0 y = 0 x += 1 #Ver error en primera parte while i < cantidad_digitos: while j < cantidad_digitos-1: if lista_u[i] == lista_d[j]: h += 1 j += 1 if h == 0: pe = lista_u[i] elif h >= 1: if h != int(diccionario_l_u[lista_u[i]]): pe = lista_u[i] i += 1 h = 0 j = 0 #Ver error en segunda parte while a < cantidad_digitos-1: while b < cantidad_digitos-2: if lista_d[a] == lista_t[b]: c += 1 b += 1 if c == 0: se = lista_d[a] elif c >= 1: if c != int(diccionario_l_d[lista_d[a]]): se = lista_d[a] a += 1 c = 0 b = 0 print(pe) print(se)

Title: A and B and Compilation Errors Time Limit: None seconds Memory Limit: None megabytes Problem Description: A and B are preparing themselves for programming contests. B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code. Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix some mistake and then another one mistake. However, despite the fact that B is sure that he corrected the two errors, he can not understand exactly what compilation errors disappeared — the compiler of the language which B uses shows errors in the new order every time! B is sure that unlike many other programming languages, compilation errors for his programming language do not depend on each other, that is, if you correct one error, the set of other error does not change. Can you help B find out exactly what two errors he corrected? Input Specification: The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time. The third line contains *n*<=-<=1 space-separated integers *b*1,<=*b*2,<=...,<=*b**n*<=-<=1 — the errors displayed at the second compilation. It is guaranteed that the sequence in the third line contains all numbers of the second string except for exactly one. The fourth line contains *n*<=-<=2 space-separated integers *с*1,<=*с*2,<=...,<=*с**n*<=-<=2 — the errors displayed at the third compilation. It is guaranteed that the sequence in the fourth line contains all numbers of the third line except for exactly one. Output Specification: Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. Demo Input: ['5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n', '6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n'] Demo Output: ['8\n123\n', '1\n3\n'] Note: In the first test sample B first corrects the error number 8, then the error number 123. In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step.

```python cantidad_digitos = (input()) cantidad_digitos = int(cantidad_digitos) lista_u = (input()).split(" ") lista_d = (input()).split(" ") lista_t = (input()).split(" ") pe = 0 se = 0 m = 0 n = 0 f = 0 x = 0 y = 0 z = 0 i = 0 j = 0 h = 0 a = 0 b = 0 c = 0 diccionario_l_u = {} diccionario_l_d = {} #Contador de repeticiones de la primera lista while m < cantidad_digitos: while n < cantidad_digitos: if lista_u[m] == lista_u[n]: f += 1 n += 1 diccionario_l_u[lista_u[m]] = f f = 0 n = 0 m += 1 #Contador de repeticiones de la Segunda lista while x < cantidad_digitos-1: while y < cantidad_digitos-1: if lista_d[x] == lista_d[y]: z += 1 y += 1 diccionario_l_d[lista_d[x]] = z z = 0 y = 0 x += 1 #Ver error en primera parte while i < cantidad_digitos: while j < cantidad_digitos-1: if lista_u[i] == lista_d[j]: h += 1 j += 1 if h == 0: pe = lista_u[i] elif h >= 1: if h != int(diccionario_l_u[lista_u[i]]): pe = lista_u[i] i += 1 h = 0 j = 0 #Ver error en segunda parte while a < cantidad_digitos-1: while b < cantidad_digitos-2: if lista_d[a] == lista_t[b]: c += 1 b += 1 if c == 0: se = lista_d[a] elif c >= 1: if c != int(diccionario_l_d[lista_d[a]]): se = lista_d[a] a += 1 c = 0 b = 0 print(pe) print(se) ```

A

Olesya and Rodion

PROGRAMMING

Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them. Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1.

The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by.

Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.

none

Python 3

TIME_LIMIT_EXCEEDED

TESTS

n,t=map(int,input().split()) for i in range(1000000000000000): if len(str(i*t))==n: print(i*t) break

Title: Olesya and Rodion Time Limit: None seconds Memory Limit: None megabytes Problem Description: Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them. Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1. Input Specification: The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. Output Specification: Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. Demo Input: ['3 2\n'] Demo Output: ['712'] Note: none

```python n,t=map(int,input().split()) for i in range(1000000000000000): if len(str(i*t))==n: print(i*t) break ```

A

Shooshuns and Sequence

PROGRAMMING

One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps: 1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current sequence. The shooshuns wonder after how many operations all numbers on the board will be the same and whether all numbers will ever be the same.

The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found.

Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1.

In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one. In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1. Thus, the answer equals -1.

Python 3

WRONG_ANSWER

TESTS

n, k = [int(i) for i in input().split()] res = [int(x) for x in input().split()] counter = 0 while len(res) != res.count(res[0]) and counter < len(res): cur = res[k - 1] res.pop(0) res.append(cur) counter += 1 if counter == 3 and len(res) != res.count(res[0]): print(-1) else: print(counter)

Title: Shooshuns and Sequence Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps: 1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current sequence. The shooshuns wonder after how many operations all numbers on the board will be the same and whether all numbers will ever be the same. Input Specification: The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. Output Specification: Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. Demo Input: ['3 2\n3 1 1\n', '3 1\n3 1 1\n'] Demo Output: ['1\n', '-1\n'] Note: In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one. In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1. Thus, the answer equals -1.

```python n, k = [int(i) for i in input().split()] res = [int(x) for x in input().split()] counter = 0 while len(res) != res.count(res[0]) and counter < len(res): cur = res[k - 1] res.pop(0) res.append(cur) counter += 1 if counter == 3 and len(res) != res.count(res[0]): print(-1) else: print(counter) ```

A

Arpa and a research in Mexican wave

PROGRAMMING

Arpa is researching the Mexican wave. There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0. - At time 1, the first spectator stands. - At time 2, the second spectator stands. - ... - At time *k*, the *k*-th spectator stands. - At time *k*<=+<=1, the (*k*<=+<=1)-th spectator stands and the first spectator sits. - At time *k*<=+<=2, the (*k*<=+<=2)-th spectator stands and the second spectator sits. - ... - At time *n*, the *n*-th spectator stands and the (*n*<=-<=*k*)-th spectator sits. - At time *n*<=+<=1, the (*n*<=+<=1<=-<=*k*)-th spectator sits. - ... - At time *n*<=+<=*k*, the *n*-th spectator sits. Arpa wants to know how many spectators are standing at time *t*.

The first line contains three integers *n*, *k*, *t* (1<=≤<=*n*<=≤<=109, 1<=≤<=*k*<=≤<=*n*, 1<=≤<=*t*<=&lt;<=*n*<=+<=*k*).

Print single integer: how many spectators are standing at time *t*.

In the following a sitting spectator is represented as -, a standing spectator is represented as ^. - At *t* = 0  ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 0. - At *t* = 1  ^--------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 1. - At *t* = 2  ^^-------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 2. - At *t* = 3  ^^^------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 3. - At *t* = 4  ^^^^------ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 4. - At *t* = 5  ^^^^^----- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 6  -^^^^^---- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 7  --^^^^^--- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 8  ---^^^^^-- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 9  ----^^^^^- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 10 -----^^^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 11 ------^^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 4. - At *t* = 12 -------^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 3. - At *t* = 13 --------^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 2. - At *t* = 14 ---------^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 1. - At *t* = 15 ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 0.

PyPy 3-64

RUNTIME_ERROR

TESTS

q,w=map(int,input().split()) if q==w or w==0: a=0 else: a=1 if w==0: print(a,0) elif w<=q//3: print(a,w*2) else: print(a,q-w)

Title: Arpa and a research in Mexican wave Time Limit: None seconds Memory Limit: None megabytes Problem Description: Arpa is researching the Mexican wave. There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0. - At time 1, the first spectator stands. - At time 2, the second spectator stands. - ... - At time *k*, the *k*-th spectator stands. - At time *k*<=+<=1, the (*k*<=+<=1)-th spectator stands and the first spectator sits. - At time *k*<=+<=2, the (*k*<=+<=2)-th spectator stands and the second spectator sits. - ... - At time *n*, the *n*-th spectator stands and the (*n*<=-<=*k*)-th spectator sits. - At time *n*<=+<=1, the (*n*<=+<=1<=-<=*k*)-th spectator sits. - ... - At time *n*<=+<=*k*, the *n*-th spectator sits. Arpa wants to know how many spectators are standing at time *t*. Input Specification: The first line contains three integers *n*, *k*, *t* (1<=≤<=*n*<=≤<=109, 1<=≤<=*k*<=≤<=*n*, 1<=≤<=*t*<=&lt;<=*n*<=+<=*k*). Output Specification: Print single integer: how many spectators are standing at time *t*. Demo Input: ['10 5 3\n', '10 5 7\n', '10 5 12\n'] Demo Output: ['3\n', '5\n', '3\n'] Note: In the following a sitting spectator is represented as -, a standing spectator is represented as ^. - At *t* = 0  ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 0. - At *t* = 1  ^--------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 1. - At *t* = 2  ^^-------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 2. - At *t* = 3  ^^^------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 3. - At *t* = 4  ^^^^------ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 4. - At *t* = 5  ^^^^^----- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 6  -^^^^^---- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 7  --^^^^^--- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 8  ---^^^^^-- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 9  ----^^^^^- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 10 -----^^^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 5. - At *t* = 11 ------^^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 4. - At *t* = 12 -------^^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 3. - At *t* = 13 --------^^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 2. - At *t* = 14 ---------^ <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 1. - At *t* = 15 ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spectators = 0.

```python q,w=map(int,input().split()) if q==w or w==0: a=0 else: a=1 if w==0: print(a,0) elif w<=q//3: print(a,w*2) else: print(a,q-w) ```

A

Key races

PROGRAMMING

Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *t*2 milliseconds. If connection ping (delay) is *t* milliseconds, the competition passes for a participant as follows: 1. Exactly after *t* milliseconds after the start of the competition the participant receives the text to be entered. 1. Right after that he starts to type it. 1. Exactly *t* milliseconds after he ends typing all the text, the site receives information about it. The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw. Given the length of the text and the information about participants, determine the result of the game.

The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.

If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".

In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins. In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins. In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.

Python 3

OK

TESTS

s,v1,v2,t1,t2=map(int,input().split()) first=s*v1+2*t1 second=s*v2+2*t2 if first > second: print ("Second") if first < second: print("First") if first ==second: print("Friendship")

Title: Key races Time Limit: None seconds Memory Limit: None megabytes Problem Description: Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *t*2 milliseconds. If connection ping (delay) is *t* milliseconds, the competition passes for a participant as follows: 1. Exactly after *t* milliseconds after the start of the competition the participant receives the text to be entered. 1. Right after that he starts to type it. 1. Exactly *t* milliseconds after he ends typing all the text, the site receives information about it. The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw. Given the length of the text and the information about participants, determine the result of the game. Input Specification: The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant. Output Specification: If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". Demo Input: ['5 1 2 1 2\n', '3 3 1 1 1\n', '4 5 3 1 5\n'] Demo Output: ['First\n', 'Second\n', 'Friendship\n'] Note: In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins. In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins. In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.

```python s,v1,v2,t1,t2=map(int,input().split()) first=s*v1+2*t1 second=s*v2+2*t2 if first > second: print ("Second") if first < second: print("First") if first ==second: print("Friendship") ```

A

Free Ice Cream

PROGRAMMING

After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer. At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the queue wants either to take several ice cream packs for himself and his friends or to give several ice cream packs to Kay and Gerda (carriers that bring ice cream have to stand in the same queue). If a carrier with *d* ice cream packs comes to the house, then Kay and Gerda take all his packs. If a child who wants to take *d* ice cream packs comes to the house, then Kay and Gerda will give him *d* packs if they have enough ice cream, otherwise the child will get no ice cream at all and will leave in distress. Kay wants to find the amount of ice cream they will have after all people will leave from the queue, and Gerda wants to find the number of distressed kids.

The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109). Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occupies *i*-th place from the start of the queue, and record "- *d**i*" means that a child who wants to take *d**i* packs stands in *i*-th place.

Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress.

Consider the first sample. 1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1. Carrier bring 40 packs, now Kay and Gerda have 42 packs. 1. Kid asks for 20 packs and receives them. There are 22 packs remaining.

PyPy 3

OK

TESTS

def solve(test): ans = 0 n, x = map(int, input().split()) for i in range(n): c = input().split() if c[0] == '+': x += int(c[1]) elif int(c[1]) > x: ans += 1 else: x -= int(c[1]) print(x, ans) t = 1 #t = int(input()) for _ in range(t): solve(_ + 1)

Title: Free Ice Cream Time Limit: None seconds Memory Limit: None megabytes Problem Description: After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer. At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the queue wants either to take several ice cream packs for himself and his friends or to give several ice cream packs to Kay and Gerda (carriers that bring ice cream have to stand in the same queue). If a carrier with *d* ice cream packs comes to the house, then Kay and Gerda take all his packs. If a child who wants to take *d* ice cream packs comes to the house, then Kay and Gerda will give him *d* packs if they have enough ice cream, otherwise the child will get no ice cream at all and will leave in distress. Kay wants to find the amount of ice cream they will have after all people will leave from the queue, and Gerda wants to find the number of distressed kids. Input Specification: The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109). Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occupies *i*-th place from the start of the queue, and record "- *d**i*" means that a child who wants to take *d**i* packs stands in *i*-th place. Output Specification: Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. Demo Input: ['5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n', '5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n'] Demo Output: ['22 1\n', '3 2\n'] Note: Consider the first sample. 1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1. Carrier bring 40 packs, now Kay and Gerda have 42 packs. 1. Kid asks for 20 packs and receives them. There are 22 packs remaining.

```python def solve(test): ans = 0 n, x = map(int, input().split()) for i in range(n): c = input().split() if c[0] == '+': x += int(c[1]) elif int(c[1]) > x: ans += 1 else: x -= int(c[1]) print(x, ans) t = 1 #t = int(input()) for _ in range(t): solve(_ + 1) ```

A

I'm bored with life

PROGRAMMING

Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopolis. Thus Leha was left completely alone in a quiet town Vičkopolis. He almost even fell into a depression from boredom! Leha came up with a task for himself to relax a little. He chooses two integers *A* and *B* and then calculates the greatest common divisor of integers "*A* factorial" and "*B* factorial". Formally the hacker wants to find out GCD(*A*!,<=*B*!). It's well known that the factorial of an integer *x* is a product of all positive integers less than or equal to *x*. Thus *x*!<==<=1·2·3·...·(*x*<=-<=1)·*x*. For example 4!<==<=1·2·3·4<==<=24. Recall that GCD(*x*,<=*y*) is the largest positive integer *q* that divides (without a remainder) both *x* and *y*. Leha has learned how to solve this task very effective. You are able to cope with it not worse, aren't you?

The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12).

Print a single integer denoting the greatest common divisor of integers *A*! and *B*!.

Consider the sample. 4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6.

Python 3

OK

TESTS

import math as m a,b=map(int,input().split()) c=min(a,b) print(m.factorial(c))

Title: I'm bored with life Time Limit: None seconds Memory Limit: None megabytes Problem Description: Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopolis. Thus Leha was left completely alone in a quiet town Vičkopolis. He almost even fell into a depression from boredom! Leha came up with a task for himself to relax a little. He chooses two integers *A* and *B* and then calculates the greatest common divisor of integers "*A* factorial" and "*B* factorial". Formally the hacker wants to find out GCD(*A*!,<=*B*!). It's well known that the factorial of an integer *x* is a product of all positive integers less than or equal to *x*. Thus *x*!<==<=1·2·3·...·(*x*<=-<=1)·*x*. For example 4!<==<=1·2·3·4<==<=24. Recall that GCD(*x*,<=*y*) is the largest positive integer *q* that divides (without a remainder) both *x* and *y*. Leha has learned how to solve this task very effective. You are able to cope with it not worse, aren't you? Input Specification: The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). Output Specification: Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. Demo Input: ['4 3\n'] Demo Output: ['6\n'] Note: Consider the sample. 4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6.

```python import math as m a,b=map(int,input().split()) c=min(a,b) print(m.factorial(c)) ```

B

BerSU Ball

PROGRAMMING

The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves. We know that several boy&amp;girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one. For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from *n* boys and *m* girls.

The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill. Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth line contains sequence *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**j*<=≤<=100), where *b**j* is the *j*-th girl's dancing skill.

Print a single number — the required maximum possible number of pairs.

none

Python 3

WRONG_ANSWER

TESTS

n=int(input()) a=list(map(int,input().split())) m=int(input()) b=list(map(int,input().split())) def mod(n): if n<=0: return -1*n else: return n a.sort() b.sort() count=0 for i in range(n): if mod(a[i]-b[0])<=1: count+=1 b.pop(0) print(count)

Title: BerSU Ball Time Limit: None seconds Memory Limit: None megabytes Problem Description: The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves. We know that several boy&amp;girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one. For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from *n* boys and *m* girls. Input Specification: The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill. Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth line contains sequence *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**j*<=≤<=100), where *b**j* is the *j*-th girl's dancing skill. Output Specification: Print a single number — the required maximum possible number of pairs. Demo Input: ['4\n1 4 6 2\n5\n5 1 5 7 9\n', '4\n1 2 3 4\n4\n10 11 12 13\n', '5\n1 1 1 1 1\n3\n1 2 3\n'] Demo Output: ['3\n', '0\n', '2\n'] Note: none

```python n=int(input()) a=list(map(int,input().split())) m=int(input()) b=list(map(int,input().split())) def mod(n): if n<=0: return -1*n else: return n a.sort() b.sort() count=0 for i in range(n): if mod(a[i]-b[0])<=1: count+=1 b.pop(0) print(count) ```

A

Life Without Zeros

PROGRAMMING

A. Life Without Zeros

2

256

Can you imagine our life if we removed all zeros from it? For sure we will have many problems. In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c* is the sum of *a* and *b*. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros? For example if the equation is 101<=+<=102<==<=203, if we removed all zeros it will be 11<=+<=12<==<=23 which is still a correct equation. But if the equation is 105<=+<=106<==<=211, if we removed all zeros it will be 15<=+<=16<==<=211 which is not a correct equation.

The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*.

The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.

none

Python 3

OK

TESTS

a = (input()) b = (input()) res = int(a)+int(b) a = a.replace("0",'') b = b.replace("0",'') res = str(res) res = res.replace("0",'') res = int(res) a = int(a) b = int(b) if res == (a+b): print("YES") else: print("NO")

Title: Life Without Zeros Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Can you imagine our life if we removed all zeros from it? For sure we will have many problems. In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c* is the sum of *a* and *b*. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros? For example if the equation is 101<=+<=102<==<=203, if we removed all zeros it will be 11<=+<=12<==<=23 which is still a correct equation. But if the equation is 105<=+<=106<==<=211, if we removed all zeros it will be 15<=+<=16<==<=211 which is not a correct equation. Input Specification: The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. Output Specification: The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. Demo Input: ['101\n102\n', '105\n106\n'] Demo Output: ['YES\n', 'NO\n'] Note: none

```python a = (input()) b = (input()) res = int(a)+int(b) a = a.replace("0",'') b = b.replace("0",'') res = str(res) res = res.replace("0",'') res = int(res) a = int(a) b = int(b) if res == (a+b): print("YES") else: print("NO") ```

A

Infinite Sequence

PROGRAMMING

Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears in this sequence, that is, there exists a positive integer *i*, such that *s**i*<==<=*b*. Of course, you are the person he asks for a help.

The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively.

If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes).

In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element. In the second sample, the favorite integer of Vasya is equal to the first element of the sequence. In the third sample all elements of the sequence are greater than Vasya's favorite integer. In the fourth sample, the sequence starts from 0, 50, 100, and all the following elements are greater than Vasya's favorite integer.

Python 3

COMPILATION_ERROR

TESTS

a , b , c= map(int,input().split()) if(c!=0 and (b-a)//c==(b-a)/c and (b-a)//c>=0): print('YES') elif c==0 and a==b : ptiny('YES') else : print('NO')

Title: Infinite Sequence Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears in this sequence, that is, there exists a positive integer *i*, such that *s**i*<==<=*b*. Of course, you are the person he asks for a help. Input Specification: The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. Output Specification: If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). Demo Input: ['1 7 3\n', '10 10 0\n', '1 -4 5\n', '0 60 50\n'] Demo Output: ['YES\n', 'YES\n', 'NO\n', 'NO\n'] Note: In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element. In the second sample, the favorite integer of Vasya is equal to the first element of the sequence. In the third sample all elements of the sequence are greater than Vasya's favorite integer. In the fourth sample, the sequence starts from 0, 50, 100, and all the following elements are greater than Vasya's favorite integer.

```python a , b , c= map(int,input().split()) if(c!=0 and (b-a)//c==(b-a)/c and (b-a)//c>=0): print('YES') elif c==0 and a==b : ptiny('YES') else : print('NO') ```

B

3-palindrome

PROGRAMMING

In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick. He is too selfish, so for a given *n* he wants to obtain a string of *n* characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a substring. For example, the strings "abc" and "abca" suit him, while the string "aba" doesn't. He also want the number of letters 'c' in his string to be as little as possible.

The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105) — the length of the string.

Print the string that satisfies all the constraints. If there are multiple answers, print any of them.

A palindrome is a sequence of characters which reads the same backward and forward.

Python 3

WRONG_ANSWER

TESTS

n=int(input()) if n==3: print('bba') else: for i in range(n//2): if i%2==0: print('aa',end='') else: print('bb',end='') if n%2!=0: print('a')

Title: 3-palindrome Time Limit: None seconds Memory Limit: None megabytes Problem Description: In the beginning of the new year Keivan decided to reverse his name. He doesn't like palindromes, so he changed Naviek to Navick. He is too selfish, so for a given *n* he wants to obtain a string of *n* characters, each of which is either 'a', 'b' or 'c', with no palindromes of length 3 appearing in the string as a substring. For example, the strings "abc" and "abca" suit him, while the string "aba" doesn't. He also want the number of letters 'c' in his string to be as little as possible. Input Specification: The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105) — the length of the string. Output Specification: Print the string that satisfies all the constraints. If there are multiple answers, print any of them. Demo Input: ['2\n', '3\n'] Demo Output: ['aa\n', 'bba\n'] Note: A palindrome is a sequence of characters which reads the same backward and forward.

```python n=int(input()) if n==3: print('bba') else: for i in range(n//2): if i%2==0: print('aa',end='') else: print('bb',end='') if n%2!=0: print('a') ```

A

IQ test

PROGRAMMING

A. IQ test

2

256

Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.

The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.

Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.

none

Python 3

WRONG_ANSWER

TESTS

n = int(input()) a = input() ch = [] ch+=a.split() res = [] for i in range(0, len(ch)): ch[i] = int(ch[i]) for i in range(0, len(ch)): if ch[i]%2!=0 and 0<=len(res)<1: for i in range(0, len(ch)): if ch[i] %2 == 0: res.insert(i, ch[i]) break if ch[i]%2 == 0 and 0<=len(res)<1: for i in range(0, len(ch)): if ch[i] %2 != 0: res.insert(i, ch[i]) break print(*res)

Title: IQ test Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. Input Specification: The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. Output Specification: Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. Demo Input: ['5\n2 4 7 8 10\n', '4\n1 2 1 1\n'] Demo Output: ['3\n', '2\n'] Note: none

```python n = int(input()) a = input() ch = [] ch+=a.split() res = [] for i in range(0, len(ch)): ch[i] = int(ch[i]) for i in range(0, len(ch)): if ch[i]%2!=0 and 0<=len(res)<1: for i in range(0, len(ch)): if ch[i] %2 == 0: res.insert(i, ch[i]) break if ch[i]%2 == 0 and 0<=len(res)<1: for i in range(0, len(ch)): if ch[i] %2 != 0: res.insert(i, ch[i]) break print(*res) ```

A

Magic Spheres

PROGRAMMING

Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible, in multiple actions)?

The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal. The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that he needs to get.

If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No".

In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.

Python 3

WRONG_ANSWER

TESTS

a = list(map( int , input().split())) b = list(map( int , input().split())) z = 0 for i in range(3): z += max((a[i]-b[i])/2,0) if b[i] > a[i]: z -= b[i] - a[i] print('Yes' if z >= 0 else 'No')

Title: Magic Spheres Time Limit: None seconds Memory Limit: None megabytes Problem Description: Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible, in multiple actions)? Input Specification: The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal. The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that he needs to get. Output Specification: If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". Demo Input: ['4 4 0\n2 1 2\n', '5 6 1\n2 7 2\n', '3 3 3\n2 2 2\n'] Demo Output: ['Yes\n', 'No\n', 'Yes\n'] Note: In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what he needs.

```python a = list(map( int , input().split())) b = list(map( int , input().split())) z = 0 for i in range(3): z += max((a[i]-b[i])/2,0) if b[i] > a[i]: z -= b[i] - a[i] print('Yes' if z >= 0 else 'No') ```

A

Chat room

PROGRAMMING

A. Chat room

1

256

Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.

The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.

If Vasya managed to say hello, print "YES", otherwise print "NO".

none

PyPy 3-64

OK

TESTS

str = list(input()) n = len(str) hello = "hello" counter = 0 for i in range(0,n): if(counter < 5 and str[i] == hello[counter]): counter += 1 if(counter >= 5): print("YES") else: print("NO")

Title: Chat room Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. Input Specification: The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. Output Specification: If Vasya managed to say hello, print "YES", otherwise print "NO". Demo Input: ['ahhellllloou\n', 'hlelo\n'] Demo Output: ['YES\n', 'NO\n'] Note: none

```python str = list(input()) n = len(str) hello = "hello" counter = 0 for i in range(0,n): if(counter < 5 and str[i] == hello[counter]): counter += 1 if(counter >= 5): print("YES") else: print("NO") ```

A

Theatre Square

PROGRAMMING

A. Theatre Square

1

256

Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.

The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).

Write the needed number of flagstones.

none

Python 3

WRONG_ANSWER

TESTS

class Solution: def needed_flagstones(n: int, m: int, a: int) -> int: flagstone_count = (m * n) / (a * a) if flagstone_count != int(flagstone_count): flagstone_count += 1 return flagstone_count

Title: Theatre Square Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*. What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. Input Specification: The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). Output Specification: Write the needed number of flagstones. Demo Input: ['6 6 4\n'] Demo Output: ['4\n'] Note: none

```python class Solution: def needed_flagstones(n: int, m: int, a: int) -> int: flagstone_count = (m * n) / (a * a) if flagstone_count != int(flagstone_count): flagstone_count += 1 return flagstone_count ```

A

Rank List

PROGRAMMING

Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place. You know the rules of comparing the results of two given teams very well. Let's say that team *a* solved *p**a* problems with total penalty time *t**a* and team *b* solved *p**b* problems with total penalty time *t**b*. Team *a* gets a higher place than team *b* in the end, if it either solved more problems on the contest, or solved the same number of problems but in less total time. In other words, team *a* gets a higher place than team *b* in the final results' table if either *p**a*<=&gt;<=*p**b*, or *p**a*<==<=*p**b* and *t**a*<=&lt;<=*t**b*. It is considered that the teams that solve the same number of problems with the same penalty time share all corresponding places. More formally, let's say there is a group of *x* teams that solved the same number of problems with the same penalty time. Let's also say that *y* teams performed better than the teams from this group. In this case all teams from the group share places *y*<=+<=1, *y*<=+<=2, ..., *y*<=+<=*x*. The teams that performed worse than the teams from this group, get their places in the results table starting from the *y*<=+<=*x*<=+<=1-th place. Your task is to count what number of teams from the given list shared the *k*-th place.

The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All numbers in the lines are separated by spaces.

In the only line print the sought number of teams that got the *k*-th place in the final results' table.

The final results' table for the first sample is: - 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10 The table shows that the second place is shared by the teams that solved 4 problems with penalty time 10. There are 3 such teams. The final table for the second sample is: - 1 place — 5 solved problems, the penalty time equals 3 - 2-5 places — 3 solved problems, the penalty time equals 1 The table shows that the fourth place is shared by the teams that solved 3 problems with penalty time 1. There are 4 such teams.

Python 3

OK

TESTS

a,b = map(int,input().split()) mat = [] for i in range(a) : arr = list(map(int,input().split())) mat.append(arr) mat = sorted(mat, key = lambda x : (-x[0],x[1])) print(mat.count(mat[b-1]))

Title: Rank List Time Limit: None seconds Memory Limit: None megabytes Problem Description: Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place. You know the rules of comparing the results of two given teams very well. Let's say that team *a* solved *p**a* problems with total penalty time *t**a* and team *b* solved *p**b* problems with total penalty time *t**b*. Team *a* gets a higher place than team *b* in the end, if it either solved more problems on the contest, or solved the same number of problems but in less total time. In other words, team *a* gets a higher place than team *b* in the final results' table if either *p**a*<=&gt;<=*p**b*, or *p**a*<==<=*p**b* and *t**a*<=&lt;<=*t**b*. It is considered that the teams that solve the same number of problems with the same penalty time share all corresponding places. More formally, let's say there is a group of *x* teams that solved the same number of problems with the same penalty time. Let's also say that *y* teams performed better than the teams from this group. In this case all teams from the group share places *y*<=+<=1, *y*<=+<=2, ..., *y*<=+<=*x*. The teams that performed worse than the teams from this group, get their places in the results table starting from the *y*<=+<=*x*<=+<=1-th place. Your task is to count what number of teams from the given list shared the *k*-th place. Input Specification: The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All numbers in the lines are separated by spaces. Output Specification: In the only line print the sought number of teams that got the *k*-th place in the final results' table. Demo Input: ['7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n', '5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n'] Demo Output: ['3\n', '4\n'] Note: The final results' table for the first sample is: - 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10 The table shows that the second place is shared by the teams that solved 4 problems with penalty time 10. There are 3 such teams. The final table for the second sample is: - 1 place — 5 solved problems, the penalty time equals 3 - 2-5 places — 3 solved problems, the penalty time equals 1 The table shows that the fourth place is shared by the teams that solved 3 problems with penalty time 1. There are 4 such teams.

```python a,b = map(int,input().split()) mat = [] for i in range(a) : arr = list(map(int,input().split())) mat.append(arr) mat = sorted(mat, key = lambda x : (-x[0],x[1])) print(mat.count(mat[b-1])) ```

A

Party

PROGRAMMING

A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true: - Employee *A* is the immediate manager of employee *B* - Employee *B* has an immediate manager employee *C* such that employee *A* is the superior of employee *C*. The company will not have a managerial cycle. That is, there will not exist an employee who is the superior of his/her own immediate manager. Today the company is going to arrange a party. This involves dividing all *n* employees into several groups: every employee must belong to exactly one group. Furthermore, within any single group, there must not be two employees *A* and *B* such that *A* is the superior of *B*. What is the minimum number of groups that must be formed?

The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees. The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate manager. It is guaranteed, that no employee will be the immediate manager of him/herself (*p**i*<=≠<=*i*). Also, there will be no managerial cycles.

Print a single integer denoting the minimum number of groups that will be formed in the party.

For the first example, three groups are sufficient, for example: - Employee 1 - Employees 2 and 4 - Employees 3 and 5

PyPy 3-64

RUNTIME_ERROR

TESTS

def dfs(deep, father, son): answer = [] if(not son[father]): return [deep-1] for i in son[father]: answer += dfs(deep+1, i, son) return answer n = int(input()) son = [[] for i in range(n+1)] for i in range(1, n+1): a = int(input()) if(a == -1): son[0].append(i) else: son[a].append(i) answer = dfs(1, 0, son) print(max(answer))

Title: Party Time Limit: None seconds Memory Limit: None megabytes Problem Description: A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true: - Employee *A* is the immediate manager of employee *B* - Employee *B* has an immediate manager employee *C* such that employee *A* is the superior of employee *C*. The company will not have a managerial cycle. That is, there will not exist an employee who is the superior of his/her own immediate manager. Today the company is going to arrange a party. This involves dividing all *n* employees into several groups: every employee must belong to exactly one group. Furthermore, within any single group, there must not be two employees *A* and *B* such that *A* is the superior of *B*. What is the minimum number of groups that must be formed? Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees. The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate manager. It is guaranteed, that no employee will be the immediate manager of him/herself (*p**i*<=≠<=*i*). Also, there will be no managerial cycles. Output Specification: Print a single integer denoting the minimum number of groups that will be formed in the party. Demo Input: ['5\n-1\n1\n2\n1\n-1\n'] Demo Output: ['3\n'] Note: For the first example, three groups are sufficient, for example: - Employee 1 - Employees 2 and 4 - Employees 3 and 5

```python def dfs(deep, father, son): answer = [] if(not son[father]): return [deep-1] for i in son[father]: answer += dfs(deep+1, i, son) return answer n = int(input()) son = [[] for i in range(n+1)] for i in range(1, n+1): a = int(input()) if(a == -1): son[0].append(i) else: son[a].append(i) answer = dfs(1, 0, son) print(max(answer)) ```

B

Petya and Staircases

PROGRAMMING

Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them. Now Petya is on the first stair of the staircase, consisting of *n* stairs. He also knows the numbers of the dirty stairs of this staircase. Help Petya find out if he can jump through the entire staircase and reach the last stair number *n* without touching a dirty stair once. One has to note that anyway Petya should step on the first and last stairs, so if the first or the last stair is dirty, then Petya cannot choose a path with clean steps only.

The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty stairs (in an arbitrary order).

Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO".

none

Python 3

RUNTIME_ERROR

TESTS

n,m=list(map(int, input().split(' '))) f1 = False f = True if m!=0: a=list(map(int, input().split(' '))) f1 = True else: f = False a = sorted(a) if f1 == True: for i in range(1,len(a)+1): if (i in a and i+1 in a and i+2 in a) or (1 in a) or (n in a): f = False break if f == True: print('YES') else: print('NO')

Title: Petya and Staircases Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them. Now Petya is on the first stair of the staircase, consisting of *n* stairs. He also knows the numbers of the dirty stairs of this staircase. Help Petya find out if he can jump through the entire staircase and reach the last stair number *n* without touching a dirty stair once. One has to note that anyway Petya should step on the first and last stairs, so if the first or the last stair is dirty, then Petya cannot choose a path with clean steps only. Input Specification: The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty stairs (in an arbitrary order). Output Specification: Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO". Demo Input: ['10 5\n2 4 8 3 6\n', '10 5\n2 4 5 7 9\n'] Demo Output: ['NO', 'YES'] Note: none

```python n,m=list(map(int, input().split(' '))) f1 = False f = True if m!=0: a=list(map(int, input().split(' '))) f1 = True else: f = False a = sorted(a) if f1 == True: for i in range(1,len(a)+1): if (i in a and i+1 in a and i+2 in a) or (1 in a) or (n in a): f = False break if f == True: print('YES') else: print('NO') ```

G

Fake News (easy)

PROGRAMMING

As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...

The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z).

Output YES if the string *s* contains heidi as a subsequence and NO otherwise.

A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*.

PyPy 3

WRONG_ANSWER

TESTS

a=input() for i in range((len(a))-4): if a[i]=='h' and a[i+1]=='e' and a[i+2] =='i' and a[i+3]=='d' and a[i+4]=='i': print('NO') quit() print('YES')

Title: Fake News (easy) Time Limit: None seconds Memory Limit: None megabytes Problem Description: As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... Input Specification: The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). Output Specification: Output YES if the string *s* contains heidi as a subsequence and NO otherwise. Demo Input: ['abcheaibcdi\n', 'hiedi\n'] Demo Output: ['YES', 'NO'] Note: A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*.

```python a=input() for i in range((len(a))-4): if a[i]=='h' and a[i+1]=='e' and a[i+2] =='i' and a[i+3]=='d' and a[i+4]=='i': print('NO') quit() print('YES') ```

B

Bear and Strings

PROGRAMMING

The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string "bear" as a substring. String *x*(*i*,<=*j*) contains string "bear", if there is such index *k* (*i*<=≤<=*k*<=≤<=*j*<=-<=3), that *s**k*<==<=*b*, *s**k*<=+<=1<==<=*e*, *s**k*<=+<=2<==<=*a*, *s**k*<=+<=3<==<=*r*. Help the bear cope with the given problem.

The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters.

Print a single number — the answer to the problem.

In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9). In the second sample, the following pairs (*i*, *j*) match: (1,  4), (1,  5), (1,  6), (1,  7), (1,  8), (1,  9), (1,  10), (1,  11), (2,  10), (2,  11), (3,  10), (3,  11), (4,  10), (4,  11), (5,  10), (5,  11), (6,  10), (6,  11), (7,  10), (7,  11).

Python 3

RUNTIME_ERROR

TESTS

''' def count(a): s = 'bear' c = 0 n = 0 if(len(a)<len(s)): return -1 for i in range(0,len(a)-3): if(s == a[i:i+4]): k = i - n k = (len(a[i+4:]))*k c += k+(len(a)-i+1) n = i return c-4 def main(): s = input() print(count(s)) main() ''' def checkDistance(nums): prev = -1 for i in range(0,len(nums)): if nums[i] == 1: if(prev != -1 and i-prev<6): return "NO" prev = i return "YES" def main(): test = int(input()) for i in range(0,test): n = int(input()) nums = [int(j) for j in input().split()] print(checkDistance(nums)) main()

Title: Bear and Strings Time Limit: None seconds Memory Limit: None megabytes Problem Description: The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string "bear" as a substring. String *x*(*i*,<=*j*) contains string "bear", if there is such index *k* (*i*<=≤<=*k*<=≤<=*j*<=-<=3), that *s**k*<==<=*b*, *s**k*<=+<=1<==<=*e*, *s**k*<=+<=2<==<=*a*, *s**k*<=+<=3<==<=*r*. Help the bear cope with the given problem. Input Specification: The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. Output Specification: Print a single number — the answer to the problem. Demo Input: ['bearbtear\n', 'bearaabearc\n'] Demo Output: ['6\n', '20\n'] Note: In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9). In the second sample, the following pairs (*i*, *j*) match: (1,  4), (1,  5), (1,  6), (1,  7), (1,  8), (1,  9), (1,  10), (1,  11), (2,  10), (2,  11), (3,  10), (3,  11), (4,  10), (4,  11), (5,  10), (5,  11), (6,  10), (6,  11), (7,  10), (7,  11).

```python ''' def count(a): s = 'bear' c = 0 n = 0 if(len(a)<len(s)): return -1 for i in range(0,len(a)-3): if(s == a[i:i+4]): k = i - n k = (len(a[i+4:]))*k c += k+(len(a)-i+1) n = i return c-4 def main(): s = input() print(count(s)) main() ''' def checkDistance(nums): prev = -1 for i in range(0,len(nums)): if nums[i] == 1: if(prev != -1 and i-prev<6): return "NO" prev = i return "YES" def main(): test = int(input()) for i in range(0,test): n = int(input()) nums = [int(j) for j in input().split()] print(checkDistance(nums)) main() ```

B

Two Cakes

PROGRAMMING

It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces. Ivan knows that there will be *n* people at the celebration (including himself), so Ivan has set *n* plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met: 1. Each piece of each cake is put on some plate; 1. Each plate contains at least one piece of cake; 1. No plate contains pieces of both cakes. To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number *x* such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least *x* pieces of cake. Help Ivan to calculate this number *x*!

The first line contains three integers *n*, *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100, 2<=≤<=*n*<=≤<=*a*<=+<=*b*) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.

Print the maximum possible number *x* such that Ivan can distribute the cake in such a way that each plate will contain at least *x* pieces of cake.

In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it. In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.

PyPy 3

WRONG_ANSWER

TESTS

n, a, b = list(map(int, input().split())) for i in range(1,101,1): if a//i + b//i < n: print(i-1) break

Title: Two Cakes Time Limit: None seconds Memory Limit: None megabytes Problem Description: It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into *a* pieces, and the second one — into *b* pieces. Ivan knows that there will be *n* people at the celebration (including himself), so Ivan has set *n* plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met: 1. Each piece of each cake is put on some plate; 1. Each plate contains at least one piece of cake; 1. No plate contains pieces of both cakes. To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number *x* such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least *x* pieces of cake. Help Ivan to calculate this number *x*! Input Specification: The first line contains three integers *n*, *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100, 2<=≤<=*n*<=≤<=*a*<=+<=*b*) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively. Output Specification: Print the maximum possible number *x* such that Ivan can distribute the cake in such a way that each plate will contain at least *x* pieces of cake. Demo Input: ['5 2 3\n', '4 7 10\n'] Demo Output: ['1\n', '3\n'] Note: In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it. In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.

```python n, a, b = list(map(int, input().split())) for i in range(1,101,1): if a//i + b//i < n: print(i-1) break ```

A

Shooshuns and Sequence

PROGRAMMING

One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps: 1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current sequence. The shooshuns wonder after how many operations all numbers on the board will be the same and whether all numbers will ever be the same.

The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found.

Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1.

In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one. In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1. Thus, the answer equals -1.

Python 3

COMPILATION_ERROR

TESTS

#include<bits/stdc++.h> using namespace std; #define endl '\n' #define sp " " //const double pi = acos(-1); long long mod = 1e9 + 7; //int dp[100000007]; //long long f[100001]; /*long long pow(long long a, long long b, long long MOD) {long long x=1,y=a; while(b > 0){if(b%2 == 1){x=(x*y);if(x>MOD) x%=MOD;}y = (y*y);if(y>MOD) y%=MOD;b /= 2;}return x;} long long InverseEuler(long long n, long long MOD) {return pow(n,MOD-2,MOD);} */ long long multicases(bool q) { if(q == 0) return 1; else {long long x;cin >> x;return x;} } void test_case() { int n,ans = 0,k;cin >> n >> k; set<int>l1; vector<int>l(n);for(int &e : l) {cin >> e;l1.insert(e);} int sz = l1.size(); int k1 = l[k - 1]; for(int i = k ; i < l.size();i++) { if(l[i] != k1) {cout << -1;return;} } while(sz != 1) { l.push_back(k1); if(l.at(0) != k1) sz--; l.erase(l.begin()); ans++; } cout << ans; } int main() { #ifndef ONLINE_JUDGE std::ios_base::sync_with_stdio(0); std::cin.tie(nullptr),std::cout.tie(nullptr); #endif long long t = multicases(0); //cin.ignore(); while(t--) {test_case();} return 0; }

Title: Shooshuns and Sequence Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps: 1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current sequence. The shooshuns wonder after how many operations all numbers on the board will be the same and whether all numbers will ever be the same. Input Specification: The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. Output Specification: Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. Demo Input: ['3 2\n3 1 1\n', '3 1\n3 1 1\n'] Demo Output: ['1\n', '-1\n'] Note: In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one. In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1. Thus, the answer equals -1.

```python #include<bits/stdc++.h> using namespace std; #define endl '\n' #define sp " " //const double pi = acos(-1); long long mod = 1e9 + 7; //int dp[100000007]; //long long f[100001]; /*long long pow(long long a, long long b, long long MOD) {long long x=1,y=a; while(b > 0){if(b%2 == 1){x=(x*y);if(x>MOD) x%=MOD;}y = (y*y);if(y>MOD) y%=MOD;b /= 2;}return x;} long long InverseEuler(long long n, long long MOD) {return pow(n,MOD-2,MOD);} */ long long multicases(bool q) { if(q == 0) return 1; else {long long x;cin >> x;return x;} } void test_case() { int n,ans = 0,k;cin >> n >> k; set<int>l1; vector<int>l(n);for(int &e : l) {cin >> e;l1.insert(e);} int sz = l1.size(); int k1 = l[k - 1]; for(int i = k ; i < l.size();i++) { if(l[i] != k1) {cout << -1;return;} } while(sz != 1) { l.push_back(k1); if(l.at(0) != k1) sz--; l.erase(l.begin()); ans++; } cout << ans; } int main() { #ifndef ONLINE_JUDGE std::ios_base::sync_with_stdio(0); std::cin.tie(nullptr),std::cout.tie(nullptr); #endif long long t = multicases(0); //cin.ignore(); while(t--) {test_case();} return 0; } ```

A

Football

PROGRAMMING

A. Football

2

256

Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.

The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.

Print "YES" if the situation is dangerous. Otherwise, print "NO".

none

Python 3

WRONG_ANSWER

TESTS

n=input() x=0 y=0 i=0 while True: if n[i]=='0': y=0 x+=1 i+=1 if x>7: print("YES") break if i==len(n)-1: print("NO") break else: x=0 y+=1 i+=1 if y>7: print("YES") break if i==len(n)-1: print("NO") break

Title: Football Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not. Input Specification: The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. Output Specification: Print "YES" if the situation is dangerous. Otherwise, print "NO". Demo Input: ['001001\n', '1000000001\n'] Demo Output: ['NO\n', 'YES\n'] Note: none

```python n=input() x=0 y=0 i=0 while True: if n[i]=='0': y=0 x+=1 i+=1 if x>7: print("YES") break if i==len(n)-1: print("NO") break else: x=0 y+=1 i+=1 if y>7: print("YES") break if i==len(n)-1: print("NO") break ```

A

Lucky Sum

PROGRAMMING

Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not. Let *next*(*x*) be the minimum lucky number which is larger than or equals *x*. Petya is interested what is the value of the expression *next*(*l*)<=+<=*next*(*l*<=+<=1)<=+<=...<=+<=*next*(*r*<=-<=1)<=+<=*next*(*r*). Help him solve this problem.

The single line contains two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=109) — the left and right interval limits.

In the single line print the only number — the sum *next*(*l*)<=+<=*next*(*l*<=+<=1)<=+<=...<=+<=*next*(*r*<=-<=1)<=+<=*next*(*r*). Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.

In the first sample: *next*(2) + *next*(3) + *next*(4) + *next*(5) + *next*(6) + *next*(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33 In the second sample: *next*(7) = 7

Python 3

TIME_LIMIT_EXCEEDED

TESTS

# cook your dish here from sys import stdin, stdout import math from itertools import permutations, combinations from itertools import combinations_with_replacement from collections import defaultdict from bisect import bisect_right def L(): return list(map(int, stdin.readline().split())) def In(): return map(int, stdin.readline().split()) def I(): return int(stdin.readline()) P = 1000000007 arr = [4, 7, 44, 47, 74, 77, 444, 447, 474, 477, 744, 747, 774, 777, 4444, 4447, 4474, 4477, 4744, 4747, 4774, 4777, 7444, 7447, 7474, 7477, 7744, 7747, 7774, 7777, 44444, 44447, 44474, 44477, 44744, 44747, 44774, 44777, 47444, 47447, 47474, 47477, 47744, 47747, 47774, 47777, 74444, 74447, 74474, 74477, 74744, 74747, 74774, 74777, 77444, 77447, 77474, 77477, 77744, 77747, 77774, 77777, 444444, 444447, 444474, 444477, 444744, 444747, 444774, 444777, 447444, 447447, 447474, 447477, 447744, 447747, 447774, 447777, 474444, 474447, 474474, 474477, 474744, 474747, 474774, 474777, 477444, 477447, 477474, 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77777474744, 77777474747, 77777474774, 77777474777, 77777477444, 77777477447, 77777477474, 77777477477, 77777477744, 77777477747, 77777477774, 77777477777, 77777744444, 77777744447, 77777744474, 77777744477, 77777744744, 77777744747, 77777744774, 77777744777, 77777747444, 77777747447, 77777747474, 77777747477, 77777747744, 77777747747, 77777747774, 77777747777, 77777774444, 77777774447, 77777774474, 77777774477, 77777774744, 77777774747, 77777774774, 77777774777, 77777777444, 77777777447, 77777777474, 77777777477, 77777777744, 77777777747, 77777777774, 77777777777] l, r = In() sm = 0 for i in range(l, r+1): x = bisect_right(arr, i) if arr[x-1] == i: sm += i else: sm += arr[x] print(sm)

Title: Lucky Sum Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not. Let *next*(*x*) be the minimum lucky number which is larger than or equals *x*. Petya is interested what is the value of the expression *next*(*l*)<=+<=*next*(*l*<=+<=1)<=+<=...<=+<=*next*(*r*<=-<=1)<=+<=*next*(*r*). Help him solve this problem. Input Specification: The single line contains two integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=109) — the left and right interval limits. Output Specification: In the single line print the only number — the sum *next*(*l*)<=+<=*next*(*l*<=+<=1)<=+<=...<=+<=*next*(*r*<=-<=1)<=+<=*next*(*r*). Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator. Demo Input: ['2 7\n', '7 7\n'] Demo Output: ['33\n', '7\n'] Note: In the first sample: *next*(2) + *next*(3) + *next*(4) + *next*(5) + *next*(6) + *next*(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33 In the second sample: *next*(7) = 7

```python # cook your dish here from sys import stdin, stdout import math from itertools import permutations, combinations from itertools import combinations_with_replacement from collections import defaultdict from bisect import bisect_right def L(): return list(map(int, stdin.readline().split())) def In(): return map(int, stdin.readline().split()) def I(): return int(stdin.readline()) P = 1000000007 arr = [4, 7, 44, 47, 74, 77, 444, 447, 474, 477, 744, 747, 774, 777, 4444, 4447, 4474, 4477, 4744, 4747, 4774, 4777, 7444, 7447, 7474, 7477, 7744, 7747, 7774, 7777, 44444, 44447, 44474, 44477, 44744, 44747, 44774, 44777, 47444, 47447, 47474, 47477, 47744, 47747, 47774, 47777, 74444, 74447, 74474, 74477, 74744, 74747, 74774, 74777, 77444, 77447, 77474, 77477, 77744, 77747, 77774, 77777, 444444, 444447, 444474, 444477, 444744, 444747, 444774, 444777, 447444, 447447, 447474, 447477, 447744, 447747, 447774, 447777, 474444, 474447, 474474, 474477, 474744, 474747, 474774, 474777, 477444, 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77774444747, 77774444774, 77774444777, 77774447444, 77774447447, 77774447474, 77774447477, 77774447744, 77774447747, 77774447774, 77774447777, 77774474444, 77774474447, 77774474474, 77774474477, 77774474744, 77774474747, 77774474774, 77774474777, 77774477444, 77774477447, 77774477474, 77774477477, 77774477744, 77774477747, 77774477774, 77774477777, 77774744444, 77774744447, 77774744474, 77774744477, 77774744744, 77774744747, 77774744774, 77774744777, 77774747444, 77774747447, 77774747474, 77774747477, 77774747744, 77774747747, 77774747774, 77774747777, 77774774444, 77774774447, 77774774474, 77774774477, 77774774744, 77774774747, 77774774774, 77774774777, 77774777444, 77774777447, 77774777474, 77774777477, 77774777744, 77774777747, 77774777774, 77774777777, 77777444444, 77777444447, 77777444474, 77777444477, 77777444744, 77777444747, 77777444774, 77777444777, 77777447444, 77777447447, 77777447474, 77777447477, 77777447744, 77777447747, 77777447774, 77777447777, 77777474444, 77777474447, 77777474474, 77777474477, 77777474744, 77777474747, 77777474774, 77777474777, 77777477444, 77777477447, 77777477474, 77777477477, 77777477744, 77777477747, 77777477774, 77777477777, 77777744444, 77777744447, 77777744474, 77777744477, 77777744744, 77777744747, 77777744774, 77777744777, 77777747444, 77777747447, 77777747474, 77777747477, 77777747744, 77777747747, 77777747774, 77777747777, 77777774444, 77777774447, 77777774474, 77777774477, 77777774744, 77777774747, 77777774774, 77777774777, 77777777444, 77777777447, 77777777474, 77777777477, 77777777744, 77777777747, 77777777774, 77777777777] l, r = In() sm = 0 for i in range(l, r+1): x = bisect_right(arr, i) if arr[x-1] == i: sm += i else: sm += arr[x] print(sm) ```

A

Chat room

PROGRAMMING

A. Chat room

1

256

Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.

The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.

If Vasya managed to say hello, print "YES", otherwise print "NO".

none

Python 3

WRONG_ANSWER

TESTS

word = input() test = "hello" index = 0 for i in word: if i == test[index]: index += 1 if index == 5: break if index == 5: print("yes") else: print("no")

Title: Chat room Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. Input Specification: The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. Output Specification: If Vasya managed to say hello, print "YES", otherwise print "NO". Demo Input: ['ahhellllloou\n', 'hlelo\n'] Demo Output: ['YES\n', 'NO\n'] Note: none

```python word = input() test = "hello" index = 0 for i in word: if i == test[index]: index += 1 if index == 5: break if index == 5: print("yes") else: print("no") ```

none

none

none

Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options: 1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out. On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day). Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days.

The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations. The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where: - *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out.

Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses: - to do sport on any two consecutive days, - to write the contest on any two consecutive days.

In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days. In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day. In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day.

PyPy 3-64

WRONG_ANSWER

TESTS

n = int(input()) a = list(map(int, input().split())) dp = [0] * n dp[0] = a[0] for i in range(1, n): if a[i] == 1: if dp[i - 1] == 1: dp[i] = 0 else: dp[i] = 1 if a[i] == 2: if dp[i - 1] == 2: dp[i] = 0 else: dp[i] = 2 if a[i] == 3: if dp[i - 1] == 1: dp[i] = 2 if dp[i - 1] == 2: dp[i] = 1 if dp[i - 1] == 3: dp[i] = 3 cnt=0 for i in range(n): if dp[i]==0: cnt+=1 print(cnt)

Title: none Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options: 1. on this day the gym is closed and the contest is not carried out; 1. on this day the gym is closed and the contest is carried out; 1. on this day the gym is open and the contest is not carried out; 1. on this day the gym is open and the contest is carried out. On each of days Vasya can either have a rest or write the contest (if it is carried out on this day), or do sport (if the gym is open on this day). Find the minimum number of days on which Vasya will have a rest (it means, he will not do sport and write the contest at the same time). The only limitation that Vasya has — he does not want to do the same activity on two consecutive days: it means, he will not do sport on two consecutive days, and write the contest on two consecutive days. Input Specification: The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations. The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where: - *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the contest is not carried out; - *a**i* equals 1, if on the *i*-th day of vacations the gym is closed, but the contest is carried out; - *a**i* equals 2, if on the *i*-th day of vacations the gym is open and the contest is not carried out; - *a**i* equals 3, if on the *i*-th day of vacations the gym is open and the contest is carried out. Output Specification: Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses: - to do sport on any two consecutive days, - to write the contest on any two consecutive days. Demo Input: ['4\n1 3 2 0\n', '7\n1 3 3 2 1 2 3\n', '2\n2 2\n'] Demo Output: ['2\n', '0\n', '1\n'] Note: In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days. In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day. In the third test Vasya can do sport either on a day number 1 or number 2. He can not do sport in two days, because it will be contrary to the his limitation. Thus, he will have a rest for only one day.

```python n = int(input()) a = list(map(int, input().split())) dp = [0] * n dp[0] = a[0] for i in range(1, n): if a[i] == 1: if dp[i - 1] == 1: dp[i] = 0 else: dp[i] = 1 if a[i] == 2: if dp[i - 1] == 2: dp[i] = 0 else: dp[i] = 2 if a[i] == 3: if dp[i - 1] == 1: dp[i] = 2 if dp[i - 1] == 2: dp[i] = 1 if dp[i - 1] == 3: dp[i] = 3 cnt=0 for i in range(n): if dp[i]==0: cnt+=1 print(cnt) ```

B

Mashmokh and Tokens

PROGRAMMING

Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest of tokens but he can't use it in any other day to get more money. If a worker gives back *w* tokens then he'll get dollars. Mashmokh likes the tokens however he likes money more. That's why he wants to save as many tokens as possible so that the amount of money he gets is maximal possible each day. He has *n* numbers *x*1,<=*x*2,<=...,<=*x**n*. Number *x**i* is the number of tokens given to each worker on the *i*-th day. Help him calculate for each of *n* days the number of tokens he can save.

The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109).

Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day.

none

PyPy 3

WRONG_ANSWER

TESTS

n, a, b = map(int, input().split()) print(*[(w * a) - (w * a) // b * b for w in map(int, input().split())])

Title: Mashmokh and Tokens Time Limit: None seconds Memory Limit: None megabytes Problem Description: Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest of tokens but he can't use it in any other day to get more money. If a worker gives back *w* tokens then he'll get dollars. Mashmokh likes the tokens however he likes money more. That's why he wants to save as many tokens as possible so that the amount of money he gets is maximal possible each day. He has *n* numbers *x*1,<=*x*2,<=...,<=*x**n*. Number *x**i* is the number of tokens given to each worker on the *i*-th day. Help him calculate for each of *n* days the number of tokens he can save. Input Specification: The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109). Output Specification: Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day. Demo Input: ['5 1 4\n12 6 11 9 1\n', '3 1 2\n1 2 3\n', '1 1 1\n1\n'] Demo Output: ['0 2 3 1 1 ', '1 0 1 ', '0 '] Note: none

```python n, a, b = map(int, input().split()) print(*[(w * a) - (w * a) // b * b for w in map(int, input().split())]) ```

A

Infinity Gauntlet

PROGRAMMING

You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems: - the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color. Using colors of Gems you saw in the Gauntlet determine the names of absent Gems.

In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet. In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters.

In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems. Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase.

In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space. In the second sample Thanos doesn't have any Gems, so he needs all six.

PyPy 3

RUNTIME_ERROR

TESTS

stone = { 'purple': 'Power', 'green' : 'Time', 'blue' : 'Space', 'organge' : 'Soul', 'red' : 'Reality', 'yellow' : 'Mind' } n = int(input()) for i in range(0 ,n): k = input() del stone[k] print(6 - n) for index in stone: print(stone[index])

Title: Infinity Gauntlet Time Limit: None seconds Memory Limit: None megabytes Problem Description: You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems: - the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color. Using colors of Gems you saw in the Gauntlet determine the names of absent Gems. Input Specification: In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet. In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters. Output Specification: In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems. Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. Demo Input: ['4\nred\npurple\nyellow\norange\n', '0\n'] Demo Output: ['2\nSpace\nTime\n', '6\nTime\nMind\nSoul\nPower\nReality\nSpace\n'] Note: In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space. In the second sample Thanos doesn't have any Gems, so he needs all six.

```python stone = { 'purple': 'Power', 'green' : 'Time', 'blue' : 'Space', 'organge' : 'Soul', 'red' : 'Reality', 'yellow' : 'Mind' } n = int(input()) for i in range(0 ,n): k = input() del stone[k] print(6 - n) for index in stone: print(stone[index]) ```

A

ACM ICPC

PROGRAMMING

In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams. After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question.

The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants

Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise. You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES").

In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5. In the second sample, score of participant number 6 is too high: his team score will be definitely greater.

Python 3

WRONG_ANSWER

PRETESTS

a = list(map(int,input().split())) ans = False power_of_t = sum(a) if power_of_t %2 !=0: print('NO') elif max(a) >= (power_of_t // 2): print('NO') else: for i in range(0,6): for j in range(1,6): for e in range(5,0,-1): if a[i] + a[j] + a[e] == a[-i] + a[-j] + a[-e]: ans = True if ans: print('YES')

Title: ACM ICPC Time Limit: None seconds Memory Limit: None megabytes Problem Description: In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams. After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question. Input Specification: The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants Output Specification: Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise. You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). Demo Input: ['1 3 2 1 2 1\n', '1 1 1 1 1 99\n'] Demo Output: ['YES\n', 'NO\n'] Note: In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5. In the second sample, score of participant number 6 is too high: his team score will be definitely greater.

```python a = list(map(int,input().split())) ans = False power_of_t = sum(a) if power_of_t %2 !=0: print('NO') elif max(a) >= (power_of_t // 2): print('NO') else: for i in range(0,6): for j in range(1,6): for e in range(5,0,-1): if a[i] + a[j] + a[e] == a[-i] + a[-j] + a[-e]: ans = True if ans: print('YES') ```

A

Shaass and Oskols

PROGRAMMING

Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i* oskols sitting on the *i*-th wire. Sometimes Shaass shots one of the birds and the bird dies (suppose that this bird sat at the *i*-th wire). Consequently all the birds on the *i*-th wire to the left of the dead bird get scared and jump up on the wire number *i*<=-<=1, if there exists no upper wire they fly away. Also all the birds to the right of the dead bird jump down on wire number *i*<=+<=1, if there exists no such wire they fly away. Shaass has shot *m* birds. You're given the initial number of birds on each wire, tell him how many birds are sitting on each wire after the shots.

The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100). The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The integers mean that for the *i*-th time Shaass shoot the *y**i*-th (from left) bird on the *x**i*-th wire, (1<=≤<=*x**i*<=≤<=*n*,<=1<=≤<=*y**i*). It's guaranteed there will be at least *y**i* birds on the *x**i*-th wire at that moment.

On the *i*-th line of the output print the number of birds on the *i*-th wire.

none

Python 3

OK

TESTS

n=int(input()) s=input() s=s.split() l=[] for i in range(n): l.append(int(s[i])) m = int(input()) for i in range(m): ss=input() ss=ss.split() xi=int(ss[0]) yi=int(ss[1]) ox=l[xi-1] l[xi-1]-=yi if xi-2>=0: l[xi-2]+=(yi-1) ox=ox-yi l[xi-1]-=ox if xi-1<n-1: l[xi]+=ox for j in l: print(j)

Title: Shaass and Oskols Time Limit: None seconds Memory Limit: None megabytes Problem Description: Shaass has decided to hunt some birds. There are *n* horizontal electricity wires aligned parallel to each other. Wires are numbered 1 to *n* from top to bottom. On each wire there are some oskols sitting next to each other. Oskol is the name of a delicious kind of birds in Shaass's territory. Supposed there are *a**i* oskols sitting on the *i*-th wire. Sometimes Shaass shots one of the birds and the bird dies (suppose that this bird sat at the *i*-th wire). Consequently all the birds on the *i*-th wire to the left of the dead bird get scared and jump up on the wire number *i*<=-<=1, if there exists no upper wire they fly away. Also all the birds to the right of the dead bird jump down on wire number *i*<=+<=1, if there exists no such wire they fly away. Shaass has shot *m* birds. You're given the initial number of birds on each wire, tell him how many birds are sitting on each wire after the shots. Input Specification: The first line of the input contains an integer *n*, (1<=≤<=*n*<=≤<=100). The next line contains a list of space-separated integers *a*1,<=*a*2,<=...,<=*a**n*, (0<=≤<=*a**i*<=≤<=100). The third line contains an integer *m*, (0<=≤<=*m*<=≤<=100). Each of the next *m* lines contains two integers *x**i* and *y**i*. The integers mean that for the *i*-th time Shaass shoot the *y**i*-th (from left) bird on the *x**i*-th wire, (1<=≤<=*x**i*<=≤<=*n*,<=1<=≤<=*y**i*). It's guaranteed there will be at least *y**i* birds on the *x**i*-th wire at that moment. Output Specification: On the *i*-th line of the output print the number of birds on the *i*-th wire. Demo Input: ['5\n10 10 10 10 10\n5\n2 5\n3 13\n2 12\n1 13\n4 6\n', '3\n2 4 1\n1\n2 2\n'] Demo Output: ['0\n12\n5\n0\n16\n', '3\n0\n3\n'] Note: none

```python n=int(input()) s=input() s=s.split() l=[] for i in range(n): l.append(int(s[i])) m = int(input()) for i in range(m): ss=input() ss=ss.split() xi=int(ss[0]) yi=int(ss[1]) ox=l[xi-1] l[xi-1]-=yi if xi-2>=0: l[xi-2]+=(yi-1) ox=ox-yi l[xi-1]-=ox if xi-1<n-1: l[xi]+=ox for j in l: print(j) ```

A

Chat room

PROGRAMMING

A. Chat room

1

256

Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.

The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.

If Vasya managed to say hello, print "YES", otherwise print "NO".

none

Python 3

OK

TESTS

s=list(input()) n='NO' for i in range(len(s)): if s[i]=='h' : for i_1 in range(i,len(s)): if s[i_1]=='e' : for i_2 in range(i_1,len(s)): if s[i_2]=='l' : for i_3 in range(i_2+1,len(s)): if s[i_3]=='l' : for i_4 in range(i_3,len(s)): if s[i_4]=='o' : n='YES' break continue continue continue print(n)

Title: Chat room Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. Input Specification: The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. Output Specification: If Vasya managed to say hello, print "YES", otherwise print "NO". Demo Input: ['ahhellllloou\n', 'hlelo\n'] Demo Output: ['YES\n', 'NO\n'] Note: none

```python s=list(input()) n='NO' for i in range(len(s)): if s[i]=='h' : for i_1 in range(i,len(s)): if s[i_1]=='e' : for i_2 in range(i_1,len(s)): if s[i_2]=='l' : for i_3 in range(i_2+1,len(s)): if s[i_3]=='l' : for i_4 in range(i_3,len(s)): if s[i_4]=='o' : n='YES' break continue continue continue print(n) ```

A

Choosing Teams

PROGRAMMING

The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times. The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times?

The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship.

Print a single number — the answer to the problem.

In the first sample only one team could be made: the first, the fourth and the fifth participants. In the second sample no teams could be created. In the third sample two teams could be created. Any partition into two teams fits.

PyPy 3-64

OK

TESTS

fristNum,secondNum=map(int,input().split()) listNum=list(map(int,input().split())) counts=0 for i in range(fristNum): if(listNum[i]+secondNum <= 5): counts+=1 print(counts//3)

Title: Choosing Teams Time Limit: None seconds Memory Limit: None megabytes Problem Description: The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times. The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times? Input Specification: The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. Output Specification: Print a single number — the answer to the problem. Demo Input: ['5 2\n0 4 5 1 0\n', '6 4\n0 1 2 3 4 5\n', '6 5\n0 0 0 0 0 0\n'] Demo Output: ['1\n', '0\n', '2\n'] Note: In the first sample only one team could be made: the first, the fourth and the fifth participants. In the second sample no teams could be created. In the third sample two teams could be created. Any partition into two teams fits.

```python fristNum,secondNum=map(int,input().split()) listNum=list(map(int,input().split())) counts=0 for i in range(fristNum): if(listNum[i]+secondNum <= 5): counts+=1 print(counts//3) ```

C

Python Indentation

PROGRAMMING

In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation. We will consider an extremely simplified subset of Python with only two types of statements. Simple statements are written in a single line, one per line. An example of a simple statement is assignment. For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty. You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program.

The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement.

Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7.

In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one. In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one. or

Python 3

WRONG_ANSWER

TESTS

lines = int(input()) code = [] for i in range(lines): code.append(input()) print(pow(2, len(''.join(''.join(code).split('f'))) - 1, 1000000007))

Title: Python Indentation Time Limit: None seconds Memory Limit: None megabytes Problem Description: In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation. We will consider an extremely simplified subset of Python with only two types of statements. Simple statements are written in a single line, one per line. An example of a simple statement is assignment. For statements are compound statements: they contain one or several other statements. For statement consists of a header written in a separate line which starts with "for" prefix, and loop body. Loop body is a block of statements indented one level further than the header of the loop. Loop body can contain both types of statements. Loop body can't be empty. You are given a sequence of statements without indentation. Find the number of ways in which the statements can be indented to form a valid Python program. Input Specification: The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. Output Specification: Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. Demo Input: ['4\ns\nf\nf\ns\n', '4\nf\ns\nf\ns\n'] Demo Output: ['1\n', '2\n'] Note: In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one. In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one. or

```python lines = int(input()) code = [] for i in range(lines): code.append(input()) print(pow(2, len(''.join(''.join(code).split('f'))) - 1, 1000000007)) ```

A

DZY Loves Sequences

PROGRAMMING

DZY has a sequence *a*, consisting of *n* integers. We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment. Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing. You only need to output the length of the subsegment you find.

The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).

In a single line print the answer to the problem — the maximum length of the required subsegment.

You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4.

Python 3

WRONG_ANSWER

TESTS

def find_longest_streak(nums): if len(nums) < 2: return n last_streak = 0 current_streak = 1 longest = 0 for i in range(1, n): if nums[i] > nums[i-1]: current_streak += 1 else: if current_streak + last_streak > longest: longest = current_streak + last_streak last_streak = current_streak current_streak = 1 if current_streak + last_streak > longest: longest = current_streak + last_streak return longest if __name__ == '__main__': n = int(input()) nums = [int(i) for i in input().split(" ")] print(find_longest_streak(nums))

Title: DZY Loves Sequences Time Limit: None seconds Memory Limit: None megabytes Problem Description: DZY has a sequence *a*, consisting of *n* integers. We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment. Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing. You only need to output the length of the subsegment you find. Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). Output Specification: In a single line print the answer to the problem — the maximum length of the required subsegment. Demo Input: ['6\n7 2 3 1 5 6\n'] Demo Output: ['5\n'] Note: You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4.

```python def find_longest_streak(nums): if len(nums) < 2: return n last_streak = 0 current_streak = 1 longest = 0 for i in range(1, n): if nums[i] > nums[i-1]: current_streak += 1 else: if current_streak + last_streak > longest: longest = current_streak + last_streak last_streak = current_streak current_streak = 1 if current_streak + last_streak > longest: longest = current_streak + last_streak return longest if __name__ == '__main__': n = int(input()) nums = [int(i) for i in input().split(" ")] print(find_longest_streak(nums)) ```

A

Chat room

PROGRAMMING

A. Chat room

1

256

Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.

The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.

If Vasya managed to say hello, print "YES", otherwise print "NO".

none

Python 3

OK

TESTS

import re k=input() helloRegex=re.compile(r'(h)+((\w)?)+(e)+((\w)?)+(l)+((\w)?)+(l)+((\w)?)+(o)+') if helloRegex.search(k)== None : print('NO') else : print('YES')

Title: Chat room Time Limit: 1 seconds Memory Limit: 256 megabytes Problem Description: Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. Input Specification: The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. Output Specification: If Vasya managed to say hello, print "YES", otherwise print "NO". Demo Input: ['ahhellllloou\n', 'hlelo\n'] Demo Output: ['YES\n', 'NO\n'] Note: none

```python import re k=input() helloRegex=re.compile(r'(h)+((\w)?)+(e)+((\w)?)+(l)+((\w)?)+(l)+((\w)?)+(o)+') if helloRegex.search(k)== None : print('NO') else : print('YES') ```

A

Help Far Away Kingdom

PROGRAMMING

A. Help Far Away Kingdom

2

256

In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there. Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Kingdom healers had already had three appointments with the merchants who were asked to sell, say, exactly 0.273549107 beer barrels. To deal with the problem somehow, the King issued an order obliging rounding up all numbers to the closest integer to simplify calculations. Specifically, the order went like this: - If a number's integer part does not end with digit 9 and its fractional part is strictly less than 0.5, then the rounded up number coincides with the number’s integer part. - If a number's integer part does not end with digit 9 and its fractional part is not less than 0.5, the rounded up number is obtained if we add 1 to the last digit of the number’s integer part.- If the number’s integer part ends with digit 9, to round up the numbers one should go to Vasilisa the Wise. In the whole Kingdom she is the only one who can perform the tricky operation of carrying into the next position. Merchants found the algorithm very sophisticated and they asked you (the ACMers) to help them. Can you write a program that would perform the rounding according to the King’s order?

The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empty set of decimal digits). The number's length does not exceed 1000 characters, including the dot. There are no other characters in the input data.

If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes).

none

PyPy 3-64

COMPILATION_ERROR

TESTS

a=float(input()) if a%10>=9: print("GOTO vasilisa") elif a%1?=0.5: print(str(int(a))[:-1]+str(int(a)%10+1)) else: print(a//1)

Title: Help Far Away Kingdom Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: In a far away kingdom lived the King, the Prince, the Shoemaker, the Dressmaker and many other citizens. They lived happily until great trouble came into the Kingdom. The ACMers settled there. Most damage those strange creatures inflicted upon the kingdom was that they loved high precision numbers. As a result, the Kingdom healers had already had three appointments with the merchants who were asked to sell, say, exactly 0.273549107 beer barrels. To deal with the problem somehow, the King issued an order obliging rounding up all numbers to the closest integer to simplify calculations. Specifically, the order went like this: - If a number's integer part does not end with digit 9 and its fractional part is strictly less than 0.5, then the rounded up number coincides with the number’s integer part. - If a number's integer part does not end with digit 9 and its fractional part is not less than 0.5, the rounded up number is obtained if we add 1 to the last digit of the number’s integer part.- If the number’s integer part ends with digit 9, to round up the numbers one should go to Vasilisa the Wise. In the whole Kingdom she is the only one who can perform the tricky operation of carrying into the next position. Merchants found the algorithm very sophisticated and they asked you (the ACMers) to help them. Can you write a program that would perform the rounding according to the King’s order? Input Specification: The first line contains a single number to round up — the integer part (a non-empty set of decimal digits that do not start with 0 — with the exception of a case when the set consists of a single digit — in this case 0 can go first), then follows character «.» (a dot), and then follows the fractional part (any non-empty set of decimal digits). The number's length does not exceed 1000 characters, including the dot. There are no other characters in the input data. Output Specification: If the last number of the integer part is not equal to 9, print the rounded-up number without leading zeroes. Otherwise, print the message "GOTO Vasilisa." (without the quotes). Demo Input: ['0.0\n', '1.49\n', '1.50\n', '2.71828182845904523536\n', '3.14159265358979323846\n', '12345678901234567890.1\n', '123456789123456789.999\n'] Demo Output: ['0', '1', '2', '3', '3', '12345678901234567890', 'GOTO Vasilisa.'] Note: none

```python a=float(input()) if a%10>=9: print("GOTO vasilisa") elif a%1?=0.5: print(str(int(a))[:-1]+str(int(a)%10+1)) else: print(a//1) ```

A

Circle Line

PROGRAMMING

The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations: - *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th station;- *d**n* is the distance between the *n*-th and the 1-st station. The trains go along the circle line in both directions. Find the shortest distance between stations with numbers *s* and *t*.

The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) — the numbers of stations, between which you need to find the shortest distance. These numbers can be the same. The numbers in the lines are separated by single spaces.

Print a single number — the length of the shortest path between stations number *s* and *t*.

In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13. In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15. In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2. In the fourth sample the numbers of stations are the same, so the shortest distance equals 0.

Python 3

OK

TESTS

num = int(input()) stations = list(map(int,list(input().split()))) points = sorted(list(map(int,list(input().split())))) sum1 = sum(stations[points[0]-1:points[1]-1]) sum2 = sum(stations) - sum(stations[points[0]-1:points[1]-1]) if sum1 < sum2: print(sum1) else: print(sum2)

Title: Circle Line Time Limit: None seconds Memory Limit: None megabytes Problem Description: The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations: - *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th station;- *d**n* is the distance between the *n*-th and the 1-st station. The trains go along the circle line in both directions. Find the shortest distance between stations with numbers *s* and *t*. Input Specification: The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) — the numbers of stations, between which you need to find the shortest distance. These numbers can be the same. The numbers in the lines are separated by single spaces. Output Specification: Print a single number — the length of the shortest path between stations number *s* and *t*. Demo Input: ['4\n2 3 4 9\n1 3\n', '4\n5 8 2 100\n4 1\n', '3\n1 1 1\n3 1\n', '3\n31 41 59\n1 1\n'] Demo Output: ['5\n', '15\n', '1\n', '0\n'] Note: In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13. In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15. In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2. In the fourth sample the numbers of stations are the same, so the shortest distance equals 0.

```python num = int(input()) stations = list(map(int,list(input().split()))) points = sorted(list(map(int,list(input().split())))) sum1 = sum(stations[points[0]-1:points[1]-1]) sum2 = sum(stations) - sum(stations[points[0]-1:points[1]-1]) if sum1 < sum2: print(sum1) else: print(sum2) ```

A

The number of positions

PROGRAMMING

Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy.

The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=&lt;<=*n*<=≤<=100).

Print the single number — the number of the sought positions.

The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1). In the second sample they are 3, 4 and 5.

PyPy 3-64

WRONG_ANSWER

TESTS

n,a,b = map(int,input().split()) count = 2 if n % 2 == 0: print(count) else: print(count + (n% 2))

Title: The number of positions Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. Input Specification: The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=&lt;<=*n*<=≤<=100). Output Specification: Print the single number — the number of the sought positions. Demo Input: ['3 1 1\n', '5 2 3\n'] Demo Output: ['2\n', '3\n'] Note: The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1). In the second sample they are 3, 4 and 5.

```python n,a,b = map(int,input().split()) count = 2 if n % 2 == 0: print(count) else: print(count + (n% 2)) ```

A

Bulbs

PROGRAMMING

Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs? If Vasya presses the button such that some bulbs connected to it are already turned on, they do not change their state, i.e. remain turned on.

The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively. Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**ij*<=≤<=*m*) — the numbers of these bulbs.

If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO".

In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp.

Python 3

OK

TESTS

a,b=map(int,input().split()) g=set() for i in range(a): n=list(map(int,input().split())) n.pop(0) g.update(n) print(['NO','YES'][len(g) == b])

Title: Bulbs Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs? If Vasya presses the button such that some bulbs connected to it are already turned on, they do not change their state, i.e. remain turned on. Input Specification: The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively. Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**ij*<=≤<=*m*) — the numbers of these bulbs. Output Specification: If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". Demo Input: ['3 4\n2 1 4\n3 1 3 1\n1 2\n', '3 3\n1 1\n1 2\n1 1\n'] Demo Output: ['YES\n', 'NO\n'] Note: In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp.

```python a,b=map(int,input().split()) g=set() for i in range(a): n=list(map(int,input().split())) n.pop(0) g.update(n) print(['NO','YES'][len(g) == b]) ```

C

Swap Adjacent Elements

PROGRAMMING

You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array. For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. There is no limit on the number of times you swap *i*-th element with (*i*<=+<=1)-th (if the position is not forbidden). Can you make this array sorted in ascending order performing some sequence of swapping operations?

The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array. The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once. The third line contains a string of *n*<=-<=1 characters, each character is either 0 or 1. If *i*-th character is 1, then you can swap *i*-th element with (*i*<=+<=1)-th any number of times, otherwise it is forbidden to swap *i*-th element with (*i*<=+<=1)-th.

If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO.

In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>.

Python 3

OK

TESTS

n=int(input()) a=input().split() b=input()+'1' c=[] k=0 for u in b: c.append(k) if u=='0': k+=1 for i in range(0,n): if c[i]!=c[int(a[i])-1]: print('NO') exit() print('YES') exit()

Title: Swap Adjacent Elements Time Limit: None seconds Memory Limit: None megabytes Problem Description: You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array. For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. There is no limit on the number of times you swap *i*-th element with (*i*<=+<=1)-th (if the position is not forbidden). Can you make this array sorted in ascending order performing some sequence of swapping operations? Input Specification: The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array. The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once. The third line contains a string of *n*<=-<=1 characters, each character is either 0 or 1. If *i*-th character is 1, then you can swap *i*-th element with (*i*<=+<=1)-th any number of times, otherwise it is forbidden to swap *i*-th element with (*i*<=+<=1)-th. Output Specification: If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. Demo Input: ['6\n1 2 5 3 4 6\n01110\n', '6\n1 2 5 3 4 6\n01010\n'] Demo Output: ['YES\n', 'NO\n'] Note: In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>.

```python n=int(input()) a=input().split() b=input()+'1' c=[] k=0 for u in b: c.append(k) if u=='0': k+=1 for i in range(0,n): if c[i]!=c[int(a[i])-1]: print('NO') exit() print('YES') exit() ```

A

Chores

PROGRAMMING

Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*. As Petya is older, he wants to take the chores with complexity larger than some value *x* (*h**i*<=&gt;<=*x*) to leave to Vasya the chores with complexity less than or equal to *x* (*h**i*<=≤<=*x*). The brothers have already decided that Petya will do exactly *a* chores and Vasya will do exactly *b* chores (*a*<=+<=*b*<==<=*n*). In how many ways can they choose an integer *x* so that Petya got exactly *a* chores and Vasya got exactly *b* chores?

The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores. The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* is the complexity of the *i*-th chore. The numbers in the given sequence are not necessarily different. All numbers on the lines are separated by single spaces.

Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0.

In the first sample the possible values of *x* are 3, 4 or 5. In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4.

Python 3

RUNTIME_ERROR

TESTS

n=int(input()) c=0 for i in range (n) : a,b,d=list(map(int,input().split())) c+=a+b+d if c : print("NO") else : print("YES")

Title: Chores Time Limit: None seconds Memory Limit: None megabytes Problem Description: Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*. As Petya is older, he wants to take the chores with complexity larger than some value *x* (*h**i*<=&gt;<=*x*) to leave to Vasya the chores with complexity less than or equal to *x* (*h**i*<=≤<=*x*). The brothers have already decided that Petya will do exactly *a* chores and Vasya will do exactly *b* chores (*a*<=+<=*b*<==<=*n*). In how many ways can they choose an integer *x* so that Petya got exactly *a* chores and Vasya got exactly *b* chores? Input Specification: The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores. The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* is the complexity of the *i*-th chore. The numbers in the given sequence are not necessarily different. All numbers on the lines are separated by single spaces. Output Specification: Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. Demo Input: ['5 2 3\n6 2 3 100 1\n', '7 3 4\n1 1 9 1 1 1 1\n'] Demo Output: ['3\n', '0\n'] Note: In the first sample the possible values of *x* are 3, 4 or 5. In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4.

```python n=int(input()) c=0 for i in range (n) : a,b,d=list(map(int,input().split())) c+=a+b+d if c : print("NO") else : print("YES") ```

A

Curriculum Vitae

PROGRAMMING

Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job. During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zero) from his CV to make a better impression on employers. As a result there should be no unsuccessful game which comes right after successful one in his CV. More formally, you are given an array *s*1,<=*s*2,<=...,<=*s**n* of zeros and ones. Zero corresponds to an unsuccessful game, one — to a successful one. Games are given in order they were produced, and Hideo can't swap these values. He should remove some elements from this array in such a way that no zero comes right after one. Besides that, Hideo still wants to mention as much games in his CV as possible. Help this genius of a man determine the maximum number of games he can leave in his CV.

The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one.

Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one.

none

Python 3

RUNTIME_ERROR

TESTS

a=int(input()) p=0 t=0 q=[] for k in range(0,a): b=input() q.append(b) for j in q: if(j=="1"): p=p+1 else: t=t+1 if(p>=t): print(p) else: print(t)

Title: Curriculum Vitae Time Limit: None seconds Memory Limit: None megabytes Problem Description: Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job. During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zero) from his CV to make a better impression on employers. As a result there should be no unsuccessful game which comes right after successful one in his CV. More formally, you are given an array *s*1,<=*s*2,<=...,<=*s**n* of zeros and ones. Zero corresponds to an unsuccessful game, one — to a successful one. Games are given in order they were produced, and Hideo can't swap these values. He should remove some elements from this array in such a way that no zero comes right after one. Besides that, Hideo still wants to mention as much games in his CV as possible. Help this genius of a man determine the maximum number of games he can leave in his CV. Input Specification: The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. Output Specification: Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. Demo Input: ['4\n1 1 0 1\n', '6\n0 1 0 0 1 0\n', '1\n0\n'] Demo Output: ['3\n', '4\n', '1\n'] Note: none

```python a=int(input()) p=0 t=0 q=[] for k in range(0,a): b=input() q.append(b) for j in q: if(j=="1"): p=p+1 else: t=t+1 if(p>=t): print(p) else: print(t) ```

A

Left-handers, Right-handers and Ambidexters

PROGRAMMING

You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand. The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands. Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand. Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively.

The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training.

Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players.

In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team. In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand.

Python 3

WRONG_ANSWER

TESTS

import math in_put = input('') in_put = in_put.split(' ') l = int(in_put[0]) r = int(in_put[1]) a = int(in_put[2]) c = 0 if (l > r): c = r if (a > (l - r)): c = c + (l - r) elif (a <= (l - r)): c = c + a elif (l < r): c = l if (a < r - l): c = c + a elif (a >= r - l): c = c + l - r elif (l == r): c = l c = c + math.floor(a / 2) print(c*2, end='')

Title: Left-handers, Right-handers and Ambidexters Time Limit: None seconds Memory Limit: None megabytes Problem Description: You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand. The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands. Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand. Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively. Input Specification: The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. Output Specification: Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. Demo Input: ['1 4 2\n', '5 5 5\n', '0 2 0\n'] Demo Output: ['6\n', '14\n', '0\n'] Note: In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team. In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand.

```python import math in_put = input('') in_put = in_put.split(' ') l = int(in_put[0]) r = int(in_put[1]) a = int(in_put[2]) c = 0 if (l > r): c = r if (a > (l - r)): c = c + (l - r) elif (a <= (l - r)): c = c + a elif (l < r): c = l if (a < r - l): c = c + a elif (a >= r - l): c = c + l - r elif (l == r): c = l c = c + math.floor(a / 2) print(c*2, end='') ```

B

Photo to Remember

PROGRAMMING

One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together. Simply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the *i*-th of them occupies the rectangle of width *w**i* pixels and height *h**i* pixels. On the group photo everybody stands in a line, thus the minimum pixel size of the photo including all the photographed friends, is *W*<=×<=*H*, where *W* is the total sum of all widths and *H* is the maximum height of all the photographed friends. As is usually the case, the friends made *n* photos — the *j*-th (1<=≤<=*j*<=≤<=*n*) photo had everybody except for the *j*-th friend as he was the photographer. Print the minimum size of each made photo in pixels.

The first line contains integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of friends. Then *n* lines follow: the *i*-th line contains information about the *i*-th friend. The line contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=10,<=1<=≤<=*h**i*<=≤<=1000) — the width and height in pixels of the corresponding rectangle.

Print *n* space-separated numbers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of pixels on the minimum photo containing all friends expect for the *i*-th one.

none

Python 3

OK

TESTS

n = int(input()) W = 0 pers = [] H1 = 0; H2 = 0 I = 0 for i in range(n): w, h = map(int, input().split()) pers.append([w,h]) W += w if h > H2: H2 = h I = i for i in range(n): if i == I: continue w, h = pers[i] if H2 >= h > H1: H1 = h for i in range(0, n): if i == I: print((W-pers[i][0])*H1, end = " ") else: print((W-pers[i][0])*H2, end = " ")

Title: Photo to Remember Time Limit: None seconds Memory Limit: None megabytes Problem Description: One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together. Simply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the *i*-th of them occupies the rectangle of width *w**i* pixels and height *h**i* pixels. On the group photo everybody stands in a line, thus the minimum pixel size of the photo including all the photographed friends, is *W*<=×<=*H*, where *W* is the total sum of all widths and *H* is the maximum height of all the photographed friends. As is usually the case, the friends made *n* photos — the *j*-th (1<=≤<=*j*<=≤<=*n*) photo had everybody except for the *j*-th friend as he was the photographer. Print the minimum size of each made photo in pixels. Input Specification: The first line contains integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of friends. Then *n* lines follow: the *i*-th line contains information about the *i*-th friend. The line contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=10,<=1<=≤<=*h**i*<=≤<=1000) — the width and height in pixels of the corresponding rectangle. Output Specification: Print *n* space-separated numbers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of pixels on the minimum photo containing all friends expect for the *i*-th one. Demo Input: ['3\n1 10\n5 5\n10 1\n', '3\n2 1\n1 2\n2 1\n'] Demo Output: ['75 110 60 ', '6 4 6 '] Note: none

```python n = int(input()) W = 0 pers = [] H1 = 0; H2 = 0 I = 0 for i in range(n): w, h = map(int, input().split()) pers.append([w,h]) W += w if h > H2: H2 = h I = i for i in range(n): if i == I: continue w, h = pers[i] if H2 >= h > H1: H1 = h for i in range(0, n): if i == I: print((W-pers[i][0])*H1, end = " ") else: print((W-pers[i][0])*H2, end = " ") ```

A

Jzzhu and Children

PROGRAMMING

There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies. Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm: 1. Give *m* candies to the first child of the line. 1. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home. 1. Repeat the first two steps while the line is not empty. Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?

The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100).

Output a single integer, representing the number of the last child.

Let's consider the first sample. Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home. Child 4 is the last one who goes home.

Python 3

WRONG_ANSWER

TESTS

n, m = map(int, input().split()) a = list(map(int, input().split())) for i in range(n): a[i] -= m mx = max(a) a.reverse() print(n - a.index(mx))

Title: Jzzhu and Children Time Limit: None seconds Memory Limit: None megabytes Problem Description: There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies. Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm: 1. Give *m* candies to the first child of the line. 1. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home. 1. Repeat the first two steps while the line is not empty. Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order? Input Specification: The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). Output Specification: Output a single integer, representing the number of the last child. Demo Input: ['5 2\n1 3 1 4 2\n', '6 4\n1 1 2 2 3 3\n'] Demo Output: ['4\n', '6\n'] Note: Let's consider the first sample. Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home. Child 4 is the last one who goes home.

```python n, m = map(int, input().split()) a = list(map(int, input().split())) for i in range(n): a[i] -= m mx = max(a) a.reverse() print(n - a.index(mx)) ```

B

Borze

PROGRAMMING

B. Borze

2

256

Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output the decoded ternary number. It can have leading zeroes.

none

Python 3

WRONG_ANSWER

TESTS

from collections import defaultdict def solve(): s = input() m = '' code = defaultdict(int) code['.'] = '0' code['-.'] = '1' code['--'] = '2' i = 0 prev = '' while (i<len(s)): prev += s[i] if(code[prev] == 0 ): i+=1 else: m+= code[prev] prev = '' i+=1 return m

Title: Borze Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. Input Specification: The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). Output Specification: Output the decoded ternary number. It can have leading zeroes. Demo Input: ['.-.--\n', '--.\n', '-..-.--\n'] Demo Output: ['012', '20', '1012'] Note: none

```python from collections import defaultdict def solve(): s = input() m = '' code = defaultdict(int) code['.'] = '0' code['-.'] = '1' code['--'] = '2' i = 0 prev = '' while (i<len(s)): prev += s[i] if(code[prev] == 0 ): i+=1 else: m+= code[prev] prev = '' i+=1 return m ```

A

Wrong Subtraction

PROGRAMMING

Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm: - if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero, she divides the number by 10 (i.e. removes the last digit). You are given an integer number $n$. Tanya will subtract one from it $k$ times. Your task is to print the result after all $k$ subtractions. It is guaranteed that the result will be positive integer number.

The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly.

Print one integer number — the result of the decreasing $n$ by one $k$ times. It is guaranteed that the result will be positive integer number.

The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$.

PyPy 3

OK

TESTS

n, k = [int(z) for z in input().split(" ")] for i in range(1,k+1): if(n%10!=0): n=n-1 else: n=n/10 print(int(n))

Title: Wrong Subtraction Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm: - if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero, she divides the number by 10 (i.e. removes the last digit). You are given an integer number $n$. Tanya will subtract one from it $k$ times. Your task is to print the result after all $k$ subtractions. It is guaranteed that the result will be positive integer number. Input Specification: The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. Output Specification: Print one integer number — the result of the decreasing $n$ by one $k$ times. It is guaranteed that the result will be positive integer number. Demo Input: ['512 4\n', '1000000000 9\n'] Demo Output: ['50\n', '1\n'] Note: The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$.

```python n, k = [int(z) for z in input().split(" ")] for i in range(1,k+1): if(n%10!=0): n=n-1 else: n=n/10 print(int(n)) ```

A

Bear and Raspberry

PROGRAMMING

The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1<=≤<=*i*<=≤<=*n*) day, the price for one barrel of honey is going to is *x**i* kilos of raspberry. Unfortunately, the bear has neither a honey barrel, nor the raspberry. At the same time, the bear's got a friend who is ready to lend him a barrel of honey for exactly one day for *c* kilograms of raspberry. That's why the bear came up with a smart plan. He wants to choose some day *d* (1<=≤<=*d*<=&lt;<=*n*), lent a barrel of honey and immediately (on day *d*) sell it according to a daily exchange rate. The next day (*d*<=+<=1) the bear wants to buy a new barrel of honey according to a daily exchange rate (as he's got some raspberry left from selling the previous barrel) and immediately (on day *d*<=+<=1) give his friend the borrowed barrel of honey as well as *c* kilograms of raspberry for renting the barrel. The bear wants to execute his plan at most once and then hibernate. What maximum number of kilograms of raspberry can he earn? Note that if at some point of the plan the bear runs out of the raspberry, then he won't execute such a plan.

The first line contains two space-separated integers, *n* and *c* (2<=≤<=*n*<=≤<=100,<=0<=≤<=*c*<=≤<=100), — the number of days and the number of kilos of raspberry that the bear should give for borrowing the barrel. The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=≤<=100), the price of a honey barrel on day *i*.

Print a single integer — the answer to the problem.

In the first sample the bear will lend a honey barrel at day 3 and then sell it for 7. Then the bear will buy a barrel for 3 and return it to the friend. So, the profit is (7 - 3 - 1) = 3. In the second sample bear will lend a honey barrel at day 1 and then sell it for 100. Then the bear buy the barrel for 1 at the day 2. So, the profit is (100 - 1 - 2) = 97.

PyPy 3

OK

TESTS

n,c=map(int,input().split()) x=list(map(int,input().split())) e=0 for i in range(n-1): e=max(e,x[i]-x[i+1]-c) print(e)

Title: Bear and Raspberry Time Limit: None seconds Memory Limit: None megabytes Problem Description: The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1<=≤<=*i*<=≤<=*n*) day, the price for one barrel of honey is going to is *x**i* kilos of raspberry. Unfortunately, the bear has neither a honey barrel, nor the raspberry. At the same time, the bear's got a friend who is ready to lend him a barrel of honey for exactly one day for *c* kilograms of raspberry. That's why the bear came up with a smart plan. He wants to choose some day *d* (1<=≤<=*d*<=&lt;<=*n*), lent a barrel of honey and immediately (on day *d*) sell it according to a daily exchange rate. The next day (*d*<=+<=1) the bear wants to buy a new barrel of honey according to a daily exchange rate (as he's got some raspberry left from selling the previous barrel) and immediately (on day *d*<=+<=1) give his friend the borrowed barrel of honey as well as *c* kilograms of raspberry for renting the barrel. The bear wants to execute his plan at most once and then hibernate. What maximum number of kilograms of raspberry can he earn? Note that if at some point of the plan the bear runs out of the raspberry, then he won't execute such a plan. Input Specification: The first line contains two space-separated integers, *n* and *c* (2<=≤<=*n*<=≤<=100,<=0<=≤<=*c*<=≤<=100), — the number of days and the number of kilos of raspberry that the bear should give for borrowing the barrel. The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=≤<=100), the price of a honey barrel on day *i*. Output Specification: Print a single integer — the answer to the problem. Demo Input: ['5 1\n5 10 7 3 20\n', '6 2\n100 1 10 40 10 40\n', '3 0\n1 2 3\n'] Demo Output: ['3\n', '97\n', '0\n'] Note: In the first sample the bear will lend a honey barrel at day 3 and then sell it for 7. Then the bear will buy a barrel for 3 and return it to the friend. So, the profit is (7 - 3 - 1) = 3. In the second sample bear will lend a honey barrel at day 1 and then sell it for 100. Then the bear buy the barrel for 1 at the day 2. So, the profit is (100 - 1 - 2) = 97.

```python n,c=map(int,input().split()) x=list(map(int,input().split())) e=0 for i in range(n-1): e=max(e,x[i]-x[i+1]-c) print(e) ```

A

Testing Pants for Sadness

PROGRAMMING

A. Testing Pants for Sadness

2

256

The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness". The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 to question *n*. Question *i* contains *a**i* answer variants, exactly one of them is correct. A click is regarded as selecting any answer in any question. The goal is to select the correct answer for each of the *n* questions. If Vaganych selects a wrong answer for some question, then all selected answers become unselected and the test starts from the very beginning, from question 1 again. But Vaganych remembers everything. The order of answers for each question and the order of questions remain unchanged, as well as the question and answers themselves. Vaganych is very smart and his memory is superb, yet he is unbelievably unlucky and knows nothing whatsoever about the test's theme. How many clicks will he have to perform in the worst case?

The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*.

Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario. Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.

Note to the second sample. In the worst-case scenario you will need five clicks: - the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the third click selects the first variant to the second question, it is wrong and we go back to question 1; - the fourth click selects the second variant to the first question, it proves as correct as it was and we move on to the second question; - the fifth click selects the second variant to the second question, it proves correct, the test is finished.

Python 3

OK

TESTS

try: t=int(input()) a=[int(i) for i in input().split()] c=0 j=[] for i in range(t): c=(a[i]-1)*(i+1)+1 j.append(c) print(sum(j)) except: pass

Title: Testing Pants for Sadness Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness". The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 to question *n*. Question *i* contains *a**i* answer variants, exactly one of them is correct. A click is regarded as selecting any answer in any question. The goal is to select the correct answer for each of the *n* questions. If Vaganych selects a wrong answer for some question, then all selected answers become unselected and the test starts from the very beginning, from question 1 again. But Vaganych remembers everything. The order of answers for each question and the order of questions remain unchanged, as well as the question and answers themselves. Vaganych is very smart and his memory is superb, yet he is unbelievably unlucky and knows nothing whatsoever about the test's theme. How many clicks will he have to perform in the worst case? Input Specification: The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*. Output Specification: Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario. Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. Demo Input: ['2\n1 1\n', '2\n2 2\n', '1\n10\n'] Demo Output: ['2', '5', '10'] Note: Note to the second sample. In the worst-case scenario you will need five clicks: - the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the third click selects the first variant to the second question, it is wrong and we go back to question 1; - the fourth click selects the second variant to the first question, it proves as correct as it was and we move on to the second question; - the fifth click selects the second variant to the second question, it proves correct, the test is finished.

```python try: t=int(input()) a=[int(i) for i in input().split()] c=0 j=[] for i in range(t): c=(a[i]-1)*(i+1)+1 j.append(c) print(sum(j)) except: pass ```

A

DZY Loves Chessboard

PROGRAMMING

DZY loves chessboard, and he enjoys playing with it. He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with the same color are on two adjacent cells. Two cells are adjacent if and only if they share a common edge. You task is to find any suitable placement of chessmen on the given chessboard.

The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a "-" means it is bad.

Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell. If multiple answers exist, print any of them. It is guaranteed that at least one answer exists.

In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK. In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output. In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are.

Python 3

COMPILATION_ERROR

TESTS

a, b = map(int, input().split()) for i in range(0, a): n = input() resultado = "" for j in range(0, b): if n[j] == '.': if (i + j) & 1 == 1: resultado = resultado + "B" else: resultado = resultado + "W" else: resultado = resultado + n[j] print(resultado)

Title: DZY Loves Chessboard Time Limit: None seconds Memory Limit: None megabytes Problem Description: DZY loves chessboard, and he enjoys playing with it. He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with the same color are on two adjacent cells. Two cells are adjacent if and only if they share a common edge. You task is to find any suitable placement of chessmen on the given chessboard. Input Specification: The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a "-" means it is bad. Output Specification: Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell. If multiple answers exist, print any of them. It is guaranteed that at least one answer exists. Demo Input: ['1 1\n.\n', '2 2\n..\n..\n', '3 3\n.-.\n---\n--.'] Demo Output: ['B\n', 'BW\nWB\n', 'B-B\n---\n--B'] Note: In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK. In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output. In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are.

```python a, b = map(int, input().split()) for i in range(0, a): n = input() resultado = "" for j in range(0, b): if n[j] == '.': if (i + j) & 1 == 1: resultado = resultado + "B" else: resultado = resultado + "W" else: resultado = resultado + n[j] print(resultado) ```

B

Vlad and Cafes

PROGRAMMING

Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research. First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe.

In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad. In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted.

Print one integer — index of the cafe that Vlad hasn't visited for as long as possible.

In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer. In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.

Python 3

RUNTIME_ERROR

PRETESTS

n = int(input()) queue = [int(i) for i in input().split()] last = queue.pop() n -= queue.count(last) + 1 while queue.count(last): del queue[queue.index(last)] the_longest_distance = 0 all_canteenes = set(queue) for canteen in all_canteenes: tmp = queue.copy()[::-1] first = n - 1 - tmp.index(canteen) del tmp[tmp.index(canteen)] if tmp.count(canteen): end = n - tmp.index(canteen) else: end = n - 1 if end - first > the_longest_distance: the_longest_distance = end - first answer = canteen print(answer)

Title: Vlad and Cafes Time Limit: None seconds Memory Limit: None megabytes Problem Description: Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research. First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes he visited in a row, in order of visiting them. Now, Vlad wants to find such a cafe that his last visit to that cafe was before his last visits to every other cafe. In other words, he wants to find such a cafe that he hasn't been there for as long as possible. Help Vlad to find that cafe. Input Specification: In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad. In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, some indices could be omitted. Output Specification: Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. Demo Input: ['5\n1 3 2 1 2\n', '6\n2 1 2 2 4 1\n'] Demo Output: ['3\n', '2\n'] Note: In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer. In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with index 2, so the answer is 2. Note that Vlad could omit some numbers while numerating the cafes.

```python n = int(input()) queue = [int(i) for i in input().split()] last = queue.pop() n -= queue.count(last) + 1 while queue.count(last): del queue[queue.index(last)] the_longest_distance = 0 all_canteenes = set(queue) for canteen in all_canteenes: tmp = queue.copy()[::-1] first = n - 1 - tmp.index(canteen) del tmp[tmp.index(canteen)] if tmp.count(canteen): end = n - tmp.index(canteen) else: end = n - 1 if end - first > the_longest_distance: the_longest_distance = end - first answer = canteen print(answer) ```

B

Drinks

PROGRAMMING

Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent. One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has. Find the volume fraction of orange juice in the final drink.

The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space.

Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4.

Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent.

Python 3

OK

TESTS

n=int(input()) x=input() num=x.split(" ") sum=0 for m in num: sum+=int(m) print(sum/n)

Title: Drinks Time Limit: None seconds Memory Limit: None megabytes Problem Description: Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent. One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has. Find the volume fraction of orange juice in the final drink. Input Specification: The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. Output Specification: Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. Demo Input: ['3\n50 50 100\n', '4\n0 25 50 75\n'] Demo Output: ['66.666666666667\n', '37.500000000000\n'] Note: Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent.

```python n=int(input()) x=input() num=x.split(" ") sum=0 for m in num: sum+=int(m) print(sum/n) ```

C

Gargari and Bishops

PROGRAMMING

Gargari is jealous that his friend Caisa won the game from the previous problem. He wants to prove that he is a genius. He has a *n*<=×<=*n* chessboard. Each cell of the chessboard has a number written on it. Gargari wants to place two bishops on the chessboard in such a way that there is no cell that is attacked by both of them. Consider a cell with number *x* written on it, if this cell is attacked by one of the bishops Gargari will get *x* dollars for it. Tell Gargari, how to place bishops on the chessboard to get maximum amount of money. We assume a cell is attacked by a bishop, if the cell is located on the same diagonal with the bishop (the cell, where the bishop is, also considered attacked by it).

The first line contains a single integer *n* (2<=≤<=*n*<=≤<=2000). Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=109) — description of the chessboard.

On the first line print the maximal number of dollars Gargari will get. On the next line print four integers: *x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*), where *x**i* is the number of the row where the *i*-th bishop should be placed, *y**i* is the number of the column where the *i*-th bishop should be placed. Consider rows are numbered from 1 to *n* from top to bottom, and columns are numbered from 1 to *n* from left to right. If there are several optimal solutions, you can print any of them.

none

PyPy 3

WRONG_ANSWER

TESTS

import itertools from sys import maxsize, stdout, stdin,stderr mod = int(1e9+7) import sys from collections import defaultdict, Counter, deque import math import heapq from heapq import heappop , heappush import bisect from math import factorial, inf from itertools import groupby from itertools import permutations as comb def ask(a,b,c): print('? {} {} {}'.format(a,b,c),flush=True) n=int(input()) return n t=1 # t=int(input()) for _ in range(t): n=int(input()) s=[] d1=[0]*(2*n) d2=[0]*(2*n) for i in range(n): s.append(list(map(int,input().split()))) o,e=-1,-1 x1,y1,x2,y2=None,None,None,None for i in range(n): for j in range(n): d1[i+j] += s[i][j] d2[i-j+n] += s[i][j] for i in range(n): for j in range(n): if (i+j)%2: if o<d1[i+j]+d2[i-j+n]-s[i][j]: o=d1[i+j]+d2[i-j+n]-s[i][j] x1,y1=i+1,j+1 else: if e<d1[i+j]+d2[i-j+n]-s[i][j]: e=d1[i+j]+d2[i-j+n]-s[i][j] x2,y2=i+1,j+1 print(o+e) print(x1,y2,x2,y2)

Title: Gargari and Bishops Time Limit: None seconds Memory Limit: None megabytes Problem Description: Gargari is jealous that his friend Caisa won the game from the previous problem. He wants to prove that he is a genius. He has a *n*<=×<=*n* chessboard. Each cell of the chessboard has a number written on it. Gargari wants to place two bishops on the chessboard in such a way that there is no cell that is attacked by both of them. Consider a cell with number *x* written on it, if this cell is attacked by one of the bishops Gargari will get *x* dollars for it. Tell Gargari, how to place bishops on the chessboard to get maximum amount of money. We assume a cell is attacked by a bishop, if the cell is located on the same diagonal with the bishop (the cell, where the bishop is, also considered attacked by it). Input Specification: The first line contains a single integer *n* (2<=≤<=*n*<=≤<=2000). Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=109) — description of the chessboard. Output Specification: On the first line print the maximal number of dollars Gargari will get. On the next line print four integers: *x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*), where *x**i* is the number of the row where the *i*-th bishop should be placed, *y**i* is the number of the column where the *i*-th bishop should be placed. Consider rows are numbered from 1 to *n* from top to bottom, and columns are numbered from 1 to *n* from left to right. If there are several optimal solutions, you can print any of them. Demo Input: ['4\n1 1 1 1\n2 1 1 0\n1 1 1 0\n1 0 0 1\n'] Demo Output: ['12\n2 2 3 2\n'] Note: none

```python import itertools from sys import maxsize, stdout, stdin,stderr mod = int(1e9+7) import sys from collections import defaultdict, Counter, deque import math import heapq from heapq import heappop , heappush import bisect from math import factorial, inf from itertools import groupby from itertools import permutations as comb def ask(a,b,c): print('? {} {} {}'.format(a,b,c),flush=True) n=int(input()) return n t=1 # t=int(input()) for _ in range(t): n=int(input()) s=[] d1=[0]*(2*n) d2=[0]*(2*n) for i in range(n): s.append(list(map(int,input().split()))) o,e=-1,-1 x1,y1,x2,y2=None,None,None,None for i in range(n): for j in range(n): d1[i+j] += s[i][j] d2[i-j+n] += s[i][j] for i in range(n): for j in range(n): if (i+j)%2: if o<d1[i+j]+d2[i-j+n]-s[i][j]: o=d1[i+j]+d2[i-j+n]-s[i][j] x1,y1=i+1,j+1 else: if e<d1[i+j]+d2[i-j+n]-s[i][j]: e=d1[i+j]+d2[i-j+n]-s[i][j] x2,y2=i+1,j+1 print(o+e) print(x1,y2,x2,y2) ```

B

Perfect Number

PROGRAMMING

We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer.

A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$).

A single number, denoting the $k$-th smallest perfect integer.

The first perfect integer is $19$ and the second one is $28$.

Python 3

WRONG_ANSWER

TESTS

n=int(input()) k=0 if n>=10: print(19+(9*n))

Title: Perfect Number Time Limit: None seconds Memory Limit: None megabytes Problem Description: We consider a positive integer perfect, if and only if the sum of its digits is exactly $10$. Given a positive integer $k$, your task is to find the $k$-th smallest perfect positive integer. Input Specification: A single line with a positive integer $k$ ($1 \leq k \leq 10\,000$). Output Specification: A single number, denoting the $k$-th smallest perfect integer. Demo Input: ['1\n', '2\n'] Demo Output: ['19\n', '28\n'] Note: The first perfect integer is $19$ and the second one is $28$.

```python n=int(input()) k=0 if n>=10: print(19+(9*n)) ```

B

Party

PROGRAMMING

B. Party

2

256

*n* people came to a party. Then those, who had no friends among people at the party, left. Then those, who had exactly 1 friend among those who stayed, left as well. Then those, who had exactly 2,<=3,<=...,<=*n*<=-<=1 friends among those who stayed by the moment of their leaving, did the same. What is the maximum amount of people that could stay at the party in the end?

The first input line contains one number *t* — amount of tests (1<=≤<=*t*<=≤<=105). Each of the following *t* lines contains one integer number *n* (1<=≤<=*n*<=≤<=105).

For each test output in a separate line one number — the maximum amount of people that could stay in the end.

none

PyPy 3-64

TIME_LIMIT_EXCEEDED

TESTS

t = int(input()) for _ in range(t): print(max(0, int(input()) - 2))

Title: Party Time Limit: 2 seconds Memory Limit: 256 megabytes Problem Description: *n* people came to a party. Then those, who had no friends among people at the party, left. Then those, who had exactly 1 friend among those who stayed, left as well. Then those, who had exactly 2,<=3,<=...,<=*n*<=-<=1 friends among those who stayed by the moment of their leaving, did the same. What is the maximum amount of people that could stay at the party in the end? Input Specification: The first input line contains one number *t* — amount of tests (1<=≤<=*t*<=≤<=105). Each of the following *t* lines contains one integer number *n* (1<=≤<=*n*<=≤<=105). Output Specification: For each test output in a separate line one number — the maximum amount of people that could stay in the end. Demo Input: ['1\n3\n'] Demo Output: ['1\n'] Note: none

```python t = int(input()) for _ in range(t): print(max(0, int(input()) - 2)) ```

A

Cinema Line

PROGRAMMING

The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?

The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.

Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".

none

PyPy 3-64

TIME_LIMIT_EXCEEDED

TESTS

n=int(input()) l=list(map(int,input().split())) change=[] ans="YES" for i in range(n): if(l[i]==25): change.append(25) elif(l[i]==50): if(25 in change): change.append(50) change.remove(25) else: ans="NO" break else: if(25 in change and 50 in change): change.remove(25) change.remove(50) elif(change.count(25)>=3): change.append(100) change.remove(25) change.remove(25) change.remove(25) else: ans="NO" break print(ans)

Title: Cinema Line Time Limit: None seconds Memory Limit: None megabytes Problem Description: The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line? Input Specification: The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. Output Specification: Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". Demo Input: ['4\n25 25 50 50\n', '2\n25 100\n', '4\n50 50 25 25\n'] Demo Output: ['YES\n', 'NO\n', 'NO\n'] Note: none