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For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: for i in range(int(input())):
n, x = map(int, input().split())
if x >= 10:
print(0)
else:
print((10-x)*(n-1)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n, x;
cin >> n >> x;
if(x >= 10)
cout << 0 << endl;
else
cout << (10-x)*(n-1) << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
while (T -->0){
String s[] = br.readLine().split(" ");
int n = Integer.parseInt(s[0]);
int p = Integer.parseInt(s[1]);
if (p<10)
System.out.println(Math.abs(n-1)*(10-p));
else System.out.println(0);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr, of N integers find the sum of max(A[i], A[j]) for all i, j such that i < j.The first line of the input contains an integer N, the size of the array.
The second line of the input contains N integers, the elements of the array Arr.
<b>Constraints:</b>
1 <= N <= 100000
1 <= Arr[i] <= 100000000Print a single integer which is the sum of min(A[i], A[j]) for all i, j such that i < j.Sample Input 1
4
5 3 3 1
Sample Output 1
24
Sample Input 2
2
1 10
Sample Output 2
10
<b>Explanation 1</b>
max(5,3) + max(5,3) + max(5,1) + max(3,3) + max(3,1) + max(3,1) = 24
, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int N = Integer.parseInt(read.readLine());
long[] arr = new long[N];
StringTokenizer st = new StringTokenizer(read.readLine());
for(int i=0; i<N; i++) {
arr[i] = Long.parseLong(st.nextToken());
}
Arrays.sort(arr);
long res = 0;
for(int i=N-1;i >-1; i--) {
res += arr[i]*i;
}
System.out.println(res);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr, of N integers find the sum of max(A[i], A[j]) for all i, j such that i < j.The first line of the input contains an integer N, the size of the array.
The second line of the input contains N integers, the elements of the array Arr.
<b>Constraints:</b>
1 <= N <= 100000
1 <= Arr[i] <= 100000000Print a single integer which is the sum of min(A[i], A[j]) for all i, j such that i < j.Sample Input 1
4
5 3 3 1
Sample Output 1
24
Sample Input 2
2
1 10
Sample Output 2
10
<b>Explanation 1</b>
max(5,3) + max(5,3) + max(5,1) + max(3,3) + max(3,1) + max(3,1) = 24
, I have written this Solution Code: n=int(input())
arr=list(map(int,input().split()))
arr.sort(reverse=True)
l=[]
for i in range(n-1):
l.append(arr[i]*((n-1)-i))
print(sum(l)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array Arr, of N integers find the sum of max(A[i], A[j]) for all i, j such that i < j.The first line of the input contains an integer N, the size of the array.
The second line of the input contains N integers, the elements of the array Arr.
<b>Constraints:</b>
1 <= N <= 100000
1 <= Arr[i] <= 100000000Print a single integer which is the sum of min(A[i], A[j]) for all i, j such that i < j.Sample Input 1
4
5 3 3 1
Sample Output 1
24
Sample Input 2
2
1 10
Sample Output 2
10
<b>Explanation 1</b>
max(5,3) + max(5,3) + max(5,1) + max(3,3) + max(3,1) + max(3,1) = 24
, I have written this Solution Code: #pragma GCC optimize ("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define VV vector
#define pb push_back
#define bitc __builtin_popcountll
#define m_p make_pair
#define infi 1e18+1
#define eps 0.000000000001
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);
string char_to_str(char c){string tem(1,c);return tem;}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T>//usage rand<long long>()
T rand() {
return uniform_int_distribution<T>()(rng);
}
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// string to integer stoi()
// string to long long stoll()
// string.substr(position,length);
// integer to string to_string();
//////////////
auto clk=clock();
#define all(x) x.begin(),x.end()
#define S second
#define F first
#define sz(x) ((long long)x.size())
#define int long long
#define f80 __float128
#define pii pair<int,int>
/////////////
signed main()
{
fastio;
#ifdef ANIKET_GOYAL
freopen("inputf.in","r",stdin);
freopen("outputf.in","w",stdout);
#endif
int n;
cin>>n;
int a[n+1];
for(int i=1;i<=n;++i){
cin>>a[i];
}
sort(a+1,a+n+1);
int ans=0;
for(int i=1;i<=n;++i)
ans+=(a[i]*(i-1));
cout<<ans;
#ifdef ANIKET_GOYAL
// cout<<endl<<endl<<endl<<endl<<"Time elapsed: "<<(double)(clock()-clk)/CLOCKS_PER_SEC<<endl;
#endif
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your task is to implement a stack using an array and perform given queries
<b>Note</b>: Description of each query is given in the <b>input and output format</b>User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the functions:
<b>push()</b>:- that takes the integer to be added and the maximum size of the array as a parameter.
<b>pop()</b>:- that takes no parameter.
<b>top()</b> :- that takes no parameter.
Constraints:
1 <= N(number of queries) <= 10<sup>3</sup>During a <b>pop</b> operation if the stack is empty you need to print "<b>Stack underflow</b>",
during <b>push</b> operation, if the maximum size of the array is reached you need to print "<b>Stack overflow</b>", <br> during <b>top</b> operation, you need to print the element which is at the top
if the stack is empty you need to print "<b>Empty stack</b>".
<b>Note</b>:- Each message or element is to be printed on a new line
Sample Input:-
6 3
pop
push 3
push 2
push 4
push 6
top
Sample Output:-
Stack underflow
Stack overflow
4
Explanation:-
Here maximum size of the array is 3, so element 6 can not be added to stack
Sample input:-
8 4
push 2
top
push 4
top
push 6
top
push 8
top
Sample Output:-
2
4
6
8
, I have written this Solution Code: void push(int x,int k)
{
if (top >= k-1) {
System.out.println("Stack overflow");
}
else {
a[++top] = x;
}
}
void pop()
{
if (top < 0) {
System.out.println("Stack underflow");
}
else {
int x = a[top--];
}
}
void top()
{
if (top < 0) {
System.out.println("Empty stack");
}
else {
int x = a[top];
System.out.println(x);
}
} , In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(br.readLine().trim());
String array[] = br.readLine().trim().split(" ");
StringBuilder sb = new StringBuilder("");
int[] arr = new int[n];
int oddCount = 0,
evenCount = 0;
for(int i = 0; i < n; i++) {
arr[i] = Integer.parseInt(array[i]);
if(arr[i] % 2 == 0)
++evenCount;
else
++oddCount;
}
if(evenCount > 0 && oddCount > 0)
Arrays.sort(arr);
for(int i = 0; i < n; i++)
sb.append(arr[i] + " ");
System.out.println(sb.substring(0, sb.length() - 1));
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: n=int(input())
p=[int(x) for x in input().split()[:n]]
o=0;e=0
for i in range(n):
if (p[i] % 2 == 1):
o += 1;
else:
e += 1;
if (o > 0 and e > 0):
p.sort();
for i in range(n):
print(p[i], end = " ");, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an array of length N in which you can swap two elements if their sum is odd i.e for every i (1 to N) and j (1 to N) if (Arr[i] + Arr[j]) is odd then you can swap these elements.
What is the lexicographically smallest array you can obtain?First line of input contains a single integer N. Next line contains N space separated integers depicting the elements of the array.
Constraints:-
1 <= N <= 100000
1 <= Arr[i] <= 100000Print N space separated elements i. e the array which is the lexicographically smallest possibleSample Input:-
3
4 1 7
Sample Output:-
1 4 7
Explanation:-
Swap numbers at indices 1 and 2 as their sum 4 + 1 = 5 is odd
Sample Input:-
2
2 4
Sample Output:-
2 4
Sample Input:-
2
5 3
Sample Output:-
5 3, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
int main() {
int n;
cin>>n;
long long a[n];
bool win=false,win1=false;
for(int i=0;i<n;i++){
cin>>a[i];
if(a[i]&1){win=true;}
if(a[i]%2==0){win1=true;}
}
if(win==true && win1==true){sort(a,a+n);}
for(int i=0;i<n;i++){
cout<<a[i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: static int focal_length(int R, char Mirror)
{
int f=R/2;
if((R%2==1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code:
int focal_length(int R, char Mirror)
{
int f=R/2;
if((R&1) && Mirror==')'){f++;}
if(Mirror == ')'){f=-f;}
return f;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the length of the radius of curvature and the type of mirror, calculate its focal length.
<b>Note:</b> '(' represents a convex mirror while ')' represents a concave mirror<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>focal_length()</b> that takes the integer R(radius of curvature) and the character Mirror (type of mirror) as parameter
<b>Constraints:-</b>
1 <= R <= 100
Mirror will be either of '('(convex type) or ')'(concave type)Return the <b>floor value of focal length.</b>Sample Input:-
9 (
Sample Output:-
4
Sample Input:-
9 )
Sample Output:-
-5, I have written this Solution Code: def focal_length(R,Mirror):
f=R/2;
if(Mirror == ')'):
f=-f
if R%2==1:
f=f-1
return int(f)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int T=sc.nextInt();
for(int i=0;i<T;i++)
{
int a=sc.nextInt();
int b=sc.nextInt();
int c=sc.nextInt();
if(a>b && a>c)
{
System.out.println("Alice");
}
else if(b>a && b>c)
{
System.out.println("Bob");
}
else if(c>a && c>b)
{
System.out.println("Charlie");
}
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: #include <bits/stdc++.h>
int main() {
int T = 0;
std::cin >> T;
while (T--) {
int A = 0, B = 0, C = 0;
std::cin >> A >> B >> C;
assert(A != B && B != C && C != A);
if (A > B && A > C) {
std::cout << "Alice" << '\n';
} else if (B > A && B > C) {
std::cout << "Bob" << '\n';
} else {
std::cout << "Charlie" << '\n';
}
}
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Alice, Bob and Charlie are bidding for an artifact at an auction. Alice bids A rupees, Bob bids B rupees, and Charlie bids C rupees (where A, B, and C are distinct). According to the rules of the auction, the person who bids the highest amount will win the auction. Determine who will win the auction.The first line contains a single integer T — the number of test cases. Then the test cases follow.
The first and only line of each test case contains three integers A, B, and C, — the amount bid by Alice, Bob, and Charlie respectively.
<b>Constraints</b>
1 ≤ T ≤ 1000
1 ≤ A, B, C ≤ 1000
A, B, and C are distinct.For each test case, output who (out of Alice, Bob, and Charlie) will win the auction.Sample Input :
4
200 100 400
155 1000 566
736 234 470
124 67 2
Sample Output :
Charlie
Bob
Alice
Alice
Explanation :
<ul>
<li>Charlie wins the auction since he bid the highest amount. </li>
<li>Bob wins the auction since he bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
<li>Alice wins the auction since she bid the highest amount. </li>
</ul>, I have written this Solution Code: T = int(input())
for i in range(T):
A,B,C = list(map(int,input().split()))
if A>B and A>C:
print("Alice")
elif B>A and B>C:
print("Bob")
else:
print("Charlie"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Find the level in a binary tree which has the maximum number of nodes. The root is at level 0.
If multiple levels have the highest amount of nodes, print the lowest level.The first line contains the integer N, denoting the number of nodes in the binary tree.
Next N lines contain two integers, denoting the left and right child of the i-th node respectively.
If the node doesn't have a left or right child, it is denoted by '-1'
Constraints
1 <= N <= 100000Print the level number with maximum nodes.
If multiple levels have the highest amount of nodes, print the lowest level.Sample Input:
7
2 4
5 3
-1 -1
-1 7
6 -1
-1 -1
-1 -1
Sample output:
2
Explanation: Given binary tree
1
/ \
2 4
/ \ \
5 3 7 <-- Level 2
/
6
Level 0 has 1 node
Level 1 has 2 nodes
Level 2 has 3 nodes
Level 3 has 1 node, I have written this Solution Code: #include "bits/stdc++.h"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
int l[N], r[N], p[N];
void dfs(int u, int dep){
p[dep]++;
if(l[u] != -1)
dfs(l[u], dep+1);
if(r[u] != -1)
dfs(r[u], dep+1);
}
void solve(){
int n;
cin >> n;
for(int i = 1; i <= n; i++)
cin >> l[i] >> r[i];
dfs(1, 0);
int mx = 0, id = -1;
for(int i = 0; i <= n; i++){
if(p[i] > mx){
mx = p[i];
id = i;
}
}
cout << id;
}
void testcases(){
int tt = 1;
//cin >> tt;
while(tt--){
solve();
}
}
signed main() {
IOS;
clock_t start = clock();
testcases();
cerr << (double)(clock() - start)*1000/CLOCKS_PER_SEC << " ms" << endl;
return 0;
} , In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: n=int(input())
a=map(int,input().split())
b=[]
mx=-200000
cnt=0
for i in a:
if i>mx:
cnt+=1
mx=i
print(cnt), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: function numberOfRoofs(arr)
{
let count=1;
let max = arr[0];
for(let i=1;i<arrSize;i++)
{
if(arr[i] > max)
{
count++;
max = arr[i];
}
}
return count;
}
, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: There are N buildings in a row with different heights H[i] (1 <= i <= N).
You are standing on the left side of the first building .From this position you can see the roof of a building <b>i</b> if no building to the left of the i<sup>th</sup> building has a height greater than or equal to the height of the i<sup>th</sup> building.
You are asked to find the number of buildings whose roofs you can see.The first line contains N denoting number of buildings.
The next line contains N space seperated integers denoting heights of the buildings from left to right.
Constraints
1 <= N <= 100000
1 <= H[i] <= 1000000000000000The output should contain one integer which is the number of buildings whose roofs you can see.Sample input:
5
1 2 2 4 3
Sample output:
3
Explanation:-
the building at index 3 will hide before building at index 2 and building at index 5 will hide before building at index 4
Sample input:
5
1 2 3 4 5
Sample output:
5
, I have written this Solution Code: import java.util.*;
import java.io.*;
class Main{
public static void main(String args[]){
Scanner s=new Scanner(System.in);
int n=s.nextInt();
int []a=new int[n];
for(int i=0;i<n;i++){
a[i]=s.nextInt();
}
int count=1;
int max = a[0];
for(int i=1;i<n;i++)
{
if(a[i] > max)
{
count++;
max = a[i];
}
}
System.out.println(count);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Your task is to implement a stack using a linked list and perform given queries
Note:-if stack is already empty than pop operation will do nothing and 0 will be printed as a top element of stack if it is empty.User task:
Since this will be a functional problem, you don't have to take input. You just have to complete the functions:
<b>push()</b>:- that takes the integer to be added as a parameter.
<b>pop()</b>:- that takes no parameter.
<b>top()</b> :- that takes no parameter.
Constraints:
1 <= N(number of queries) <= 10<sup>3</sup>You don't need to print anything else other than in top function in which you require to print the top most element of your stack in a new line, if the stack is empty you just need to print 0.Input:
7
push 1
push 2
top
pop
top
pop
top
Output:
2
1
0
, I have written this Solution Code:
Node top = null;
public void push(int x)
{
Node temp = new Node(x);
temp.next = top;
top = temp;
}
public void pop()
{
if (top == null) {
}
else {
top = (top).next;}
}
public void top()
{
// check for stack underflow
if (top == null) {
System.out.println("0");
}
else {
Node temp = top;
System.out.println(temp.val);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given the following
- An Array A of size N
- An integer h
Your task is to print number of elements in A that are greater than h. You are given a total of K such tasks.The first line contains N denoting the size of array
The next line contains N space- separated integer denoting the elements of array A.
The next line contains an integer K denoting the number of tasks.
The next line contains an integer h.
<b>Constraints</b>
1 <= N <= 1e5
1 <= A[i] <= 1e9
1 <= K <= 1e5
1 <= h <= 1e9For each task, print the number of elements of A that are greater than h.Sample Input:
5
1 5 3 2 4
1
2
Sample Output :
3, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
PrintWriter wr = new PrintWriter(System.out);
int A_size = Integer.parseInt(br.readLine().trim());
String[] arr_A = br.readLine().trim().split(" ");
int[] A = new int[A_size];
for (int i_A = 0; i_A < arr_A.length; i_A++) {
A[i_A] = Integer.parseInt(arr_A[i_A]);
}
int K_Array_size = Integer.parseInt(br.readLine().trim());
int[] K_Array = new int[K_Array_size];
for (int i_K_Array = 0; i_K_Array < K_Array_size; i_K_Array++) {
K_Array[i_K_Array] = Integer.parseInt(br.readLine().trim());
}
int[] out_ = process_queries(A, K_Array, A_size, K_Array_size);
for (int i_out_ = 0; i_out_ < out_.length; i_out_++) {
wr.println(out_[i_out_]);
}
wr.close();
br.close();
}
static int[] process_queries(int[] A, int[] K_Array, int N, int k) {
int ab[]=new int[k];
Arrays.sort(A);
int h=0;
while(h<k)
{ int f=K_Array[h];int l=0;
int r=N-1;int g=N;
while(l<=r)
{
int m=l+(r-l)/2;
if(A[m]>f)
{
g=m;
r=m-1;
}
else{
l=m+1;
}
}
ab[h]=N-g;
h++;
}
return ab;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given the following
- An Array A of size N
- An integer h
Your task is to print number of elements in A that are greater than h. You are given a total of K such tasks.The first line contains N denoting the size of array
The next line contains N space- separated integer denoting the elements of array A.
The next line contains an integer K denoting the number of tasks.
The next line contains an integer h.
<b>Constraints</b>
1 <= N <= 1e5
1 <= A[i] <= 1e9
1 <= K <= 1e5
1 <= h <= 1e9For each task, print the number of elements of A that are greater than h.Sample Input:
5
1 5 3 2 4
1
2
Sample Output :
3, I have written this Solution Code: /**
* Author : tourist1256
* Time : 2022-01-19 02:44:22
**/
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int k;
cin >> k;
sort(a.begin(), a.end());
for (int i = 0; i < k; i++) {
int temp;
cin >> temp;
auto it = upper_bound(a.begin(), a.end(), temp) - a.begin();
cout << n - it << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: for i in range(int(input())):
n, x = map(int, input().split())
if x >= 10:
print(0)
else:
print((10-x)*(n-1)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: #include "bits/stdc++.h"
#pragma GCC optimize "03"
using namespace std;
#define int long long int
#define ld long double
#define pi pair<int, int>
#define pb push_back
#define fi first
#define se second
#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#ifndef LOCAL
#define endl '\n'
#endif
const int N = 2e5 + 5;
const int mod = 1e9 + 7;
const int inf = 1e9 + 9;
signed main() {
IOS;
int t; cin >> t;
while(t--){
int n, x;
cin >> n >> x;
if(x >= 10)
cout << 0 << endl;
else
cout << (10-x)*(n-1) << endl;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two positive integers N and X, where N is the number of total patients and X is the time duration (in minutes) after which a new patient arrives. Also, doctor will give only 10 minutes to each patient. The task is to calculate the time (in minutes) the last patient needs to wait.The first line of input contains the number of test cases T.
The next T subsequent lines denote the total number of patients N and time interval X (in minutes) in which the next patients are visiting.
Constraints:
1 <= T <= 100
0 <= N <= 100
0 <= X <= 30Output the waiting time of last patient.Input:
5
4 5
5 3
6 5
7 6
8 2
Output:
15
28
25
24
56, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
while (T -->0){
String s[] = br.readLine().split(" ");
int n = Integer.parseInt(s[0]);
int p = Integer.parseInt(s[1]);
if (p<10)
System.out.println(Math.abs(n-1)*(10-p));
else System.out.println(0);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: def area(side_of_square):
print(side_of_square*side_of_square)
def main():
N = int(input())
area(N)
if __name__ == '__main__':
main(), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a side of a square, your task is to calculate and print its area.The first line of the input contains the side of the square.
<b>Constraints:</b>
1 <= side <=100You just have to print the area of a squareSample Input:-
3
Sample Output:-
9
Sample Input:-
6
Sample Output:-
36, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int side = Integer.parseInt(br.readLine());
System.out.print(side*side);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
try{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int testcase = Integer.parseInt(br.readLine());
for(int t=0;t<testcase;t++){
int num = Integer.parseInt(br.readLine().trim());
if(num==1)
System.out.println("No");
else if(num<=3)
System.out.println("Yes");
else{
if((num%2==0)||(num%3==0))
System.out.println("No");
else{
int flag=0;
for(int i=5;i*i<=num;i+=6){
if(((num%i)==0)||(num%(i+2)==0)){
System.out.println("No");
flag=1;
break;
}
}
if(flag==0)
System.out.println("Yes");
}
}
}
}catch (Exception e) {
System.out.println("I caught: " + e);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: t=int(input())
for i in range(t):
number = int(input())
if number > 1:
i=2
while i*i<=number:
if (number % i) == 0:
print("No")
break
i+=1
else:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer, print whether that integer is a prime number or not.First line of input contains an integer T, showing the number of test cases. Every test case is a single integer A.
Constraints
1 <= T <= 100
1 <= A <= 10^8If the given integer is prime, print 'Yes', else print 'No'.Sample Input
3
5
9
13
Output
Yes
No
Yes, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--){
long long n,k;
cin>>n;
long x=sqrt(n);
int cnt=0;
vector<int> v;
for(long long i=2;i<=x;i++){
if(n%i==0){
cout<<"No"<<endl;
goto f;
}}
cout<<"Yes"<<endl;
f:;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: static void printDataTypes(int a, long b, float c, double d, char e)
{
System.out.println(a);
System.out.println(b);
System.out.printf("%.2f",c);
System.out.println();
System.out.printf("%.4f",d);
System.out.println();
System.out.println(e);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: void printDataTypes(int a, long long b, float c, double d, char e){
cout<<a<<endl;
cout<<b<<endl;
cout <<fixed<< std::setprecision(2) << c << '\n';
cout <<fixed<< std::setprecision(4) << d << '\n';
cout<<e<<endl;
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Some Data types are given below:-
Integer
Long
float
Double
char
Your task is to take input in the given format and print them in the same order.You don't have to worry about input, you just have to complete the function <b>printDataTypes()</b>Print each element in a new line in the same order as the input.
Note:- <b>Print float round off to two decimal places and double to 4 decimal places.</b>Sample Input:-
2
2312351235
1.21
543.1321
c
Sample Output:-
2
2312351235
1.21
543.1321
c, I have written this Solution Code: a=int(input())
b=int(input())
x=float(input())
g = "{:.2f}".format(x)
d=float(input())
e = "{:.4f}".format(d)
u=input()
print(a)
print(b)
print(g)
print(e)
print(u), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N integers, your task is to add these elements to the PriorityQueue. Also, given M integers, the task is to check if element is present in PriorityQueue. If present, print 1 and return the max element of priority queue, and then delete the max element. If not present, print -1.First line contains N, number of elements to be inserted into the Priority Queue. Second line contains N positive integers separated by space. Third line contains M, fourth line contains M positive integers.
Constraints:
1 <= M <= N <= 10^3
1 <= Arr[i] <= 10^3For each query, print "1" and max element in newlines if element to be found is present in the PriorityQueue, else print "-1". (use new line for each output, as shown in example)Sample Input:
1
8
1 2 3 4 5 2 3 1
5
1 3 2 9 10
Sample Output:
1
5
1
4
1
3
-1
-1, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int size1 = Integer.parseInt(br.readLine());
PriorityQueue<Integer> pq = new PriorityQueue<>(Collections.reverseOrder());
HashMap<Integer,Integer> hm = new HashMap<>();
String str[] = br.readLine().split(" ");
int i=0;
while(i!=size1)
{
pq.add(Integer.parseInt(str[i]));
if(hm.containsKey(Integer.parseInt(str[i])))
{
int count = hm.get(Integer.parseInt(str[i]));
hm.remove(Integer.parseInt(str[i]));
hm.put(Integer.parseInt(str[i]),count+1);
}
else{
hm.put(Integer.parseInt(str[i]),1);
}
i++;
}
size1 = Integer.parseInt(br.readLine());
str = br.readLine().split(" ");
i=0;
while(i!=size1)
{
if(hm.containsKey(Integer.parseInt(str[i])))
{
System.out.println("1");
System.out.println(pq.peek());
int count = hm.get(pq.peek());
if(count>1)
hm.put(pq.peek(),count-1);
else
hm.remove(pq.peek());
if(pq.size()>0)
pq.remove();
}
else{
System.out.println("-1");
}
i++;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N integers, your task is to add these elements to the PriorityQueue. Also, given M integers, the task is to check if element is present in PriorityQueue. If present, print 1 and return the max element of priority queue, and then delete the max element. If not present, print -1.First line contains N, number of elements to be inserted into the Priority Queue. Second line contains N positive integers separated by space. Third line contains M, fourth line contains M positive integers.
Constraints:
1 <= M <= N <= 10^3
1 <= Arr[i] <= 10^3For each query, print "1" and max element in newlines if element to be found is present in the PriorityQueue, else print "-1". (use new line for each output, as shown in example)Sample Input:
1
8
1 2 3 4 5 2 3 1
5
1 3 2 9 10
Sample Output:
1
5
1
4
1
3
-1
-1, I have written this Solution Code: m=int(input())
l=list(map(int,input().split()))
p=int(input())
q=list(map(int,input().split()))
for i in q:
if(i in l):
print("1")
print(max(l))
l.remove(max(l))
else:
print("-1"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given N integers, your task is to add these elements to the PriorityQueue. Also, given M integers, the task is to check if element is present in PriorityQueue. If present, print 1 and return the max element of priority queue, and then delete the max element. If not present, print -1.First line contains N, number of elements to be inserted into the Priority Queue. Second line contains N positive integers separated by space. Third line contains M, fourth line contains M positive integers.
Constraints:
1 <= M <= N <= 10^3
1 <= Arr[i] <= 10^3For each query, print "1" and max element in newlines if element to be found is present in the PriorityQueue, else print "-1". (use new line for each output, as shown in example)Sample Input:
1
8
1 2 3 4 5 2 3 1
5
1 3 2 9 10
Sample Output:
1
5
1
4
1
3
-1
-1, I have written this Solution Code: #include <bits/stdc++.h>
#define int long long int
#define max1 1000000007
using namespace std;
signed main(){
int n;
cin>>n;
int a[n];
priority_queue<int> q;
for(int i=0;i<n;i++){
cin>>a[i];
q.push(a[i]);
}
int m;
cin>>m;
while(m--){
cin>>a[0];
bool win=false;
vector<int> v;
while(q.empty()==false){
if(a[0]==q.top()){cout<<1<<endl;win=true;break;}
v.emplace_back(q.top());
q.pop();
}
if(q.empty()){
cout<<-1<<endl;
}
for(int i=0;i<v.size();i++){
q.push(v[i]);
}
if(win){
cout<<q.top()<<endl;
q.pop();
}
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s=br.readLine().toString();
int n=Integer.parseInt(s);
int ch=0;
if(n>0){
ch=1;
}
else if(n<0) ch=-1;
switch(ch){
case 1: System.out.println("Positive");break;
case 0: System.out.println("Zero");break;
case -1: System.out.println("Negative");break;
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: n = input()
if '-' in list(n):
print('Negative')
elif int(n) == 0 :
print('Zero')
else:
print('Positive'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Write a program to check whether a number is positive, negative or zero using switch case.The first line of the input contains the number
<b>Constraints</b>
-10<sup>9</sup> ≤ n ≤ 10<sup>9</sup>Print the single line wether it's "Positive", "Negative" or "Zero"Sample Input :
13
Sample Output :
Positive
Sample Input :
-13
Sample Output :
Negative, I have written this Solution Code: #include <stdio.h>
int main()
{
int num;
scanf("%d", &num);
switch (num > 0)
{
// Num is positive
case 1:
printf("Positive");
break;
// Num is either negative or zero
case 0:
switch (num < 0)
{
case 1:
printf("Negative");
break;
case 0:
printf("Zero");
break;
}
break;
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given an array of integers. Consider absolute difference between all the pairs of the the elements. You need to find Kth smallest absolute difference. If the size of the array is N then value of K will be less than N and more than or equal to 1.The first line of input contains number of test cases T.
The first line of each test case contains a two integers N and K denoting the number of elements in the array A and difference you need to output. The second line of each test case contains N space separated integers denoting the elements of the array A
Constraints:
1<= T <= 10
2 <= N <= 100000
1 <= K < N < 100000
0 <= A[i] <= 100000For each test case, output Kth smallest absolute difference.Input :
1
6 2
1 3 4 1 3 8
Output :
0
Explanation :
Test case 1: First smallest difference is 0, between the pair (1, 1) and second smallest absolute difference difference is also 0 between the pairs (3, 3)., I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
class Main{
public static void main(String[] args)throws IOException {
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
int t = Integer.parseInt(read.readLine().trim());
while (t-- > 0) {
String str[] = read.readLine().trim().split(" ");
int n = Integer.parseInt(str[0]);
int k = Integer.parseInt(str[1]);
int arr[] = new int[n];
str = read.readLine().trim().split(" ");
for (int i = 0; i < n; i++)
arr[i] = Integer.parseInt(str[i]);
System.out.println(Math.abs(small(arr, k)));
}
}
public static int small(int arr[], int k) {
Arrays.sort(arr);
int l = 0, r = arr[arr.length - 1] - arr[0];
while (r > l) {
int mid = l + (r - l) / 2;
if (count(arr, mid) < k) {
l = mid + 1;
} else {
r = mid;
}
}
return r;
}
public static int count(int arr[], int mid) {
int ans = 0, j = 0;
for (int i = 1; i < arr.length; ++i) {
while (j < i && arr[i] - arr[j] > mid) {
++j;
}
ans += i - j;
}
return ans;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Yogi wants to be the best programmer in the world but today she stuck on an easy problem. Help her to solve it.
<b>Problem description:-</b>
Choose an integer N and subtract the sum of digits of the number N from it i.e. if N is 245 then subtract 2+4+5 from it making it 245 - 11 = 234.
Keep on doing this operation until the number becomes 0 (for eg. 25 requires 3 operations to reduce to 0
25 -> 18 -> 9 -> 0).
Given a number N, your task is to print the number of operations required to make the number 0.The input contains a single integer N.
<b>Constraints:-</b>
1 <= N <= 10000Print the number of operations required to make the number 0.Sample Input:-
25
Sample Output:-
3
Explanation:-
25 -> 18 -> 9 -> 0
Sample Input:-
4
Sample Output:-
1, I have written this Solution Code: t=1
p=1
while t>0:
n=int(input())
c=0
while n>0:
p=n
while n>0:
k=n%10
#print(k)
p=(p-k)
n=int(n/10)
#print(n)
n=p
#print(n)
c+=1
t-=1
print(c), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Yogi wants to be the best programmer in the world but today she stuck on an easy problem. Help her to solve it.
<b>Problem description:-</b>
Choose an integer N and subtract the sum of digits of the number N from it i.e. if N is 245 then subtract 2+4+5 from it making it 245 - 11 = 234.
Keep on doing this operation until the number becomes 0 (for eg. 25 requires 3 operations to reduce to 0
25 -> 18 -> 9 -> 0).
Given a number N, your task is to print the number of operations required to make the number 0.The input contains a single integer N.
<b>Constraints:-</b>
1 <= N <= 10000Print the number of operations required to make the number 0.Sample Input:-
25
Sample Output:-
3
Explanation:-
25 -> 18 -> 9 -> 0
Sample Input:-
4
Sample Output:-
1, I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
int main(){
int t=1;
while(t--){
int n;
cin>>n;
int p;
int cnt=0;
while(n){
p=n;
while(n){
p-=n%10;
n/=10;
}
n=p;
cnt++;
}
cout<<cnt;}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Yogi wants to be the best programmer in the world but today she stuck on an easy problem. Help her to solve it.
<b>Problem description:-</b>
Choose an integer N and subtract the sum of digits of the number N from it i.e. if N is 245 then subtract 2+4+5 from it making it 245 - 11 = 234.
Keep on doing this operation until the number becomes 0 (for eg. 25 requires 3 operations to reduce to 0
25 -> 18 -> 9 -> 0).
Given a number N, your task is to print the number of operations required to make the number 0.The input contains a single integer N.
<b>Constraints:-</b>
1 <= N <= 10000Print the number of operations required to make the number 0.Sample Input:-
25
Sample Output:-
3
Explanation:-
25 -> 18 -> 9 -> 0
Sample Input:-
4
Sample Output:-
1, I have written this Solution Code: import java.util.Scanner;
class Main{
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
int count=0;
while(n!=0){
int sum=digitsum(n);
n=n-sum;
count++;
}
System.out.println(count);
}
public static int digitsum(int n){
int s=0,r;
while(n>0){
r=n%10;
s=s+r;
n=n/10;
}
return s;
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import static java.lang.System.out;
public class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader() {
br = new BufferedReader(new InputStreamReader(System.in));
}
String next() {
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
} catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
long nextLong() {
return Long.parseLong(next());
}
double nextDouble() {
return Double.parseDouble(next());
}
String nextLine() {
String str = "";
try {
str = br.readLine();
} catch (IOException e) {
e.printStackTrace();
}
return str;
}
}
public static void main(String[] args) {
FastReader reader = new FastReader();
int n = reader.nextInt();
String S = reader.next();
int ncount = 0;
int tcount = 0;
for (char c : S.toCharArray()) {
if (c == 'N') ncount++;
else tcount++;
}
if (ncount > tcount) {
out.print("Nutan\n");
} else {
out.print("Tusla\n");
}
out.flush();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: n = int(input())
s = input()
a1 = s.count('N')
a2 = s.count('T')
if(a1 > a2):
print("Nutan")
else:
print('Tusla'), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Nutan and Tusla are both students at Newton School. They are both among the best students in the class. In order to know who is better among them, a game was organised. The game consisted of L rounds, where L is an odd integer. The student winning more rounds than the other was declared the winner.
You would be given a string of odd length L in which each character is 'N' or 'T'. If the i<sup>th</sup> character is 'N', then the i<sup>th</sup> round was won by Nutan, else if the character is 'T' it was won by Tusla. Print "Nutan'' if Nutan has won more rounds than Tusla, else print "Tusla'' if Tusla has won more rounds than Nutan.
Note: You have to print everything without quotes.The first line of the input contains a single integer L — the number of rounds (1 ≤ L ≤ 100 and L is odd).
The second line contains a string S of length L. Each character of S is either 'N' or 'T'.Print "Nutan" or "Tusla" according to the input.Sample Input:
3
NNT
Sample Output:
Nutan
Explanation:
Nutan has won two games while Tusla has only won a single game, so the overall winner is Nutan., I have written this Solution Code: //Author: Xzirium
//Time and Date: 02:18:28 24 March 2022
//Optional FAST
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native")
//Required Libraries
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
//Required namespaces
using namespace std;
using namespace __gnu_pbds;
//Required defines
#define endl '\n'
#define READ(X) cin>>X;
#define READV(X) long long X; cin>>X;
#define READAR(A,N) long long A[N]; for(long long i=0;i<N;i++) {cin>>A[i];}
#define rz(A,N) A.resize(N);
#define sz(X) (long long)(X.size())
#define pb push_back
#define pf push_front
#define fi first
#define se second
#define FORI(a,b,c) for(long long a=b;a<c;a++)
#define FORD(a,b,c) for(long long a=b;a>c;a--)
//Required typedefs
template <typename T> using ordered_set = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
template <typename T> using ordered_set1 = tree<T,null_type,greater<T>,rb_tree_tag,tree_order_statistics_node_update>;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<long long,long long> pll;
//Required Constants
const long long inf=(long long)1e18;
const long long MOD=(long long)(1e9+7);
const long long INIT=(long long)(1e6+1);
const long double PI=3.14159265358979;
// Required random number generators
// mt19937 gen_rand_int(chrono::steady_clock::now().time_since_epoch().count());
// mt19937_64 gen_rand_ll(chrono::steady_clock::now().time_since_epoch().count());
//Required Functions
ll power(ll b, ll e)
{
ll r = 1ll;
for(; e > 0; e /= 2, (b *= b) %= MOD)
if(e % 2) (r *= b) %= MOD;
return r;
}
ll modInverse(ll a)
{
return power(a,MOD-2);
}
//Work
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
//-----------------------------------------------------------------------------------------------------------//
READV(N);
string S;
cin>>S;
ll n=0,t=0;
FORI(i,0,N)
{
if(S[i]=='N')
{
n++;
}
else if(S[i]=='T')
{
t++;
}
}
if(n>t)
{
cout<<"Nutan"<<endl;
}
else
{
cout<<"Tusla"<<endl;
}
//-----------------------------------------------------------------------------------------------------------//
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a positive integer N. Print the square of N.The input consists of a single integer N.
<b> Constraints: </b>
1 ≤ N ≤ 50Print a single integer – the value of N<sup>2</sup>.Sample Input 1:
5
Sample Output 1:
25, I have written this Solution Code:
import java.io.*;
import java.util.*;
public class Main {
public static void main(String[] args) throws IOException {
int n = in.nextInt();
out.println(n*n);
out.flush();
}
static FastScanner in = new FastScanner();
static PrintWriter out = new PrintWriter(System.out);
static int oo = Integer.MAX_VALUE;
static long ooo = Long.MAX_VALUE;
static class FastScanner {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer("");
void ini() throws FileNotFoundException {
br = new BufferedReader(new FileReader("input.txt"));
}
String next() {
while(!st.hasMoreTokens())
try { st = new StringTokenizer(br.readLine()); }
catch(IOException e) {}
return st.nextToken();
}
String nextLine(){
try{ return br.readLine(); }
catch(IOException e) { } return "";
}
int nextInt() {
return Integer.parseInt(next());
}
int[] readArray(int n) {
int a[] = new int[n];
for(int i=0;i<n;i++) a[i] = nextInt();
return a;
}
long nextLong() {
return Long.parseLong(next());
}
long[] readArrayL(int n) {
long a[] = new long[n];
for(int i=0;i<n;i++) a[i] = nextLong();
return a;
}
double nextDouble() {
return Double.parseDouble(next());
}
double[] readArrayD(int n) {
double a[] = new double[n];
for(int i=0;i<n;i++) a[i] = nextDouble();
return a;
}
}
static final Random random = new Random();
static void ruffleSort(int[] a){
int n = a.length;
for(int i=0;i<n;i++){
int j = random.nextInt(n), temp = a[j];
a[j] = a[i]; a[i] = temp;
}
Arrays.sort(a);
}
static void ruffleSortL(long[] a){
int n = a.length;
for(int i=0;i<n;i++){
int j = random.nextInt(n);
long temp = a[j];
a[j] = a[i]; a[i] = temp;
}
Arrays.sort(a);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a positive integer N. Print the square of N.The input consists of a single integer N.
<b> Constraints: </b>
1 ≤ N ≤ 50Print a single integer – the value of N<sup>2</sup>.Sample Input 1:
5
Sample Output 1:
25, I have written this Solution Code: #include<bits/stdc++.h>
using namespace std;
int main(){
int n;
cin>>n;
cout<<(n*n)<<'\n';
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given a positive integer N. Print the square of N.The input consists of a single integer N.
<b> Constraints: </b>
1 ≤ N ≤ 50Print a single integer – the value of N<sup>2</sup>.Sample Input 1:
5
Sample Output 1:
25, I have written this Solution Code: n=int(input())
print(n*n), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: static void printInteger(int N){
System.out.println(N);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: void printInteger(int x){
printf("%d", x);
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: void printIntger(int n)
{
cout<<n;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer N, your task is to print out the integer N.You don't have to worry about the input, you just have to complete the function <b>printIntger()</b>
<b>Constraints:-</b>
1 ≤ N ≤ 10<sup>9</sup>Print the integer N.Sample Input:-
3
Sample Output:
3
Sample Input:
56
Sample Output:
56, I have written this Solution Code: n=int(input())
print (n), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args) throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
String[] inp = br.readLine().split(" ");
int a = Integer.parseInt(inp[0]);
int b = Integer.parseInt(inp[1]);
int c = Integer.parseInt(inp[2]);
if(a * a == b * b + c * c)
bw.write("Yes"+"\n");
else if(b * b == a * a + c * c)
bw.write("Yes"+"\n");
else if(c * c == b * b + a * a)
bw.write("Yes"+"\n");
else
bw.write("No"+"\n");
bw.flush();
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code: a,b,c=map(int,input().split())
if(a*a+b*b==c*c or a*a+c*c==b*b or b*b+c*c==a*a):
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given three integers A, B and C, which are the side lengths of a triangle in some order. Print "Yes" if this triangle is right-angled, otherwise print "No".The input consists of a single line containing three space-separated integers A, B and C.
Constraints:
1 ≤ A, B, C ≤ 1000Print a single word "Yes" if the given triangle is right-angled, otherwise print "No".
Note:
The quotation marks are only for clarity, you should not print them in output.
The output is case-sensitive.Sample Input 1:
3 4 5
Sample Output 1:
Yes
Sample Input 2:
10 9 10
Sample Output 2:
No
Sample Input 3:
5 4 3
Sample Output 3:
Yes, I have written this Solution Code:
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,fma")
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pi 3.141592653589793238
#define int long long
#define ll long long
#define ld long double
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
long long powm(long long a, long long b,long long mod) {
long long res = 1;
while (b > 0) {
if (b & 1)
res = res * a %mod;
a = a * a %mod;
b >>= 1;
}
return res;
}
ll gcd(ll a, ll b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);
#ifndef ONLINE_JUDGE
if(fopen("input.txt","r"))
{
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
}
#endif
int a[3];
for(int i=0;i<3;i++)
cin>>a[i];
sort(a,a+3);
if(a[0]*a[0]+a[1]*a[1]==a[2]*a[2])
cout<<"Yes";
else
cout<<"No";
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a 2D matrix of size [M, N], Q number of queries. In each query, you will be given a number X to check whether it is present in the matrix or not.The first line contains three integers M(number of rows), N(Number of columns), and Q(number of queries)
Next M lines contain N integers which are the elements of the matrix.
Next, Q lines will contain a single integer X.
Constraints:-
1<=M,N<=1000
1<=Q<=10000
1<=X, Arr[i]<=1000000000For each query, in a new line print "Yes" if the element is present in matrix or print "No" if the element is absent.Input:-
3 3 2
1 2 3
5 6 7
8 9 10
7
11
Output:-
Yes
No
Input:-
3 4 4
4 8 11 14
15 54 45 47
1 2 3 4
5
15
45
26
Output:-
No
Yes
Yes
No, I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int m = sc.nextInt();
int n = sc.nextInt();
int q = sc.nextInt();
int mat[] = new int[m*n];
int matSize = m*n;
for(int i = 0; i < m*n; i++)
{
int ele = sc.nextInt();
mat[i] = ele;
}
Arrays.sort(mat);
for(int i = 1; i <= q; i++)
{
int qs = sc.nextInt();
System.out.println(isPresent(mat, matSize, qs));
}
}
static String isPresent(int mat[], int size, int ele)
{
int l = 0, h = size-1;
while(l <= h)
{
int mid = l + (h-l)/2;
if(mat[mid] == ele)
return "Yes";
else if(mat[mid] > ele)
h = mid - 1;
else l = mid+1;
}
return "No";
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a 2D matrix of size [M, N], Q number of queries. In each query, you will be given a number X to check whether it is present in the matrix or not.The first line contains three integers M(number of rows), N(Number of columns), and Q(number of queries)
Next M lines contain N integers which are the elements of the matrix.
Next, Q lines will contain a single integer X.
Constraints:-
1<=M,N<=1000
1<=Q<=10000
1<=X, Arr[i]<=1000000000For each query, in a new line print "Yes" if the element is present in matrix or print "No" if the element is absent.Input:-
3 3 2
1 2 3
5 6 7
8 9 10
7
11
Output:-
Yes
No
Input:-
3 4 4
4 8 11 14
15 54 45 47
1 2 3 4
5
15
45
26
Output:-
No
Yes
Yes
No, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define N 1000000
long a[N];
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n,m,q;
cin>>n>>m>>q;
n=n*m;
long long sum=0,sum1=0;
for(int i=0;i<n;i++){
cin>>a[i];
}
sort(a,a+n);
while(q--){
long x;
cin>>x;
int l=0;
int r=n-1;
while (r >= l) {
int mid = l + (r - l) / 2;
if (a[mid] == x) {
cout<<"Yes"<<endl;goto f;}
if (a[mid] > x)
{
r=mid-1;
}
else {l=mid+1;
}
}
cout<<"No"<<endl;
f:;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers a and b, your task is to check following conditions:-
1. If a <= 10 and b >= 10 (Logical AND).
2. Atleast one from a or b will be even (Logical OR).
3. if a is not equal to b (Logical NOT).The first line of the input contains 2 integers a and b.
<b>Constraints:</b>
1 <= a, b <= 100Print the string <b>"true"</b> if the condition holds in each function else <b>"false"</b> .
Sample Input:-
3 12
Sample Output:-
true true true
Explanation
So a = 3 and b = 12, so a<=10 and b>=10 hence first condition true, a is not even but b is even so atleast one of them is even hence true, third a != b which is also true hence the final output comes true true true.
Sample Input:-
10 10
Sample Output:-
true true false
, I have written this Solution Code: a, b = list(map(int, input().split(" ")))
print(str(a <= 10 and b >= 10).lower(), end=' ')
print(str(a % 2 == 0 or b % 2 == 0).lower(), end=' ')
print(str(not a == b).lower()), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given two integers a and b, your task is to check following conditions:-
1. If a <= 10 and b >= 10 (Logical AND).
2. Atleast one from a or b will be even (Logical OR).
3. if a is not equal to b (Logical NOT).The first line of the input contains 2 integers a and b.
<b>Constraints:</b>
1 <= a, b <= 100Print the string <b>"true"</b> if the condition holds in each function else <b>"false"</b> .
Sample Input:-
3 12
Sample Output:-
true true true
Explanation
So a = 3 and b = 12, so a<=10 and b>=10 hence first condition true, a is not even but b is even so atleast one of them is even hence true, third a != b which is also true hence the final output comes true true true.
Sample Input:-
10 10
Sample Output:-
true true false
, I have written this Solution Code: import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
class Main {
static boolean Logical_AND(int a, int b){
if(a<=10 && b>=10){
return true;}
return false;}
static boolean Logical_OR(int a, int b){
if(a%2==0 || b%2==0){
return true;}
return false;}
static boolean Logical_NOT(int a, int b){
if(a!=b){
return true;}
return false;}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int a=in.nextInt();
int b=in.nextInt();
System.out.print(Logical_AND(a, b)+" ");
System.out.print(Logical_OR(a,b)+" ");
System.out.print(Logical_NOT(a,b)+" ");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, For each i (1<=i<=n) if i is even print "<b>even</b>" else print "<b>odd</b>".<b>User task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the functions <b>For_Loop()</b> that take the integer n as a parameter.
</b>Constraints:</b>
1 ≤ n ≤ 100Print even or odd for each i, separated by white spaces.Sample Input:
5
Sample Output:
odd even odd even odd
Sample Input:
2
Sample Output:
odd even, I have written this Solution Code: public static void For_Loop(int n){
for(int i=1;i<=n;i++){
if(i%2==1){System.out.print("odd ");}
else{
System.out.print("even ");
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given an integer n, For each i (1<=i<=n) if i is even print "<b>even</b>" else print "<b>odd</b>".<b>User task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the functions <b>For_Loop()</b> that take the integer n as a parameter.
</b>Constraints:</b>
1 ≤ n ≤ 100Print even or odd for each i, separated by white spaces.Sample Input:
5
Sample Output:
odd even odd even odd
Sample Input:
2
Sample Output:
odd even, I have written this Solution Code: n = int(input())
for i in range(1, n+1):
if(i%2)==0:
print("even ",end="")
else:
print("odd ",end=""), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two classes, Person and Student, where Person is the base class and Student is the derived class. Complete code for Person and a declaration for Student are provided for you in the editor. Observe that Student inherits all the properties of Person.
Complete the Student class by writing the following:
A Student class constructor, which has parameters:
* A string firstName.
* A string lastName.
* An integer idNumber.
* An integer array (or vector) of test scores,.
A char calculate() method that calculates a Student object's average and returns the grade character representative of their calculated average:
Grading Scale:
Letter Average
O 90 <= a <= 100
E 80 <= a < 90
A 70 <= a < 80
P 55 <= a < 70
D 40 <= a < 55
T < 40The locked stub code in the editor reads the input and calls the Student class constructor with the necessary arguments. It also calls the calculate method which takes no arguments.
The first line contains firstName, lastName, and isNumber, separated by a space. The second line contains the number of test scores. The third line of space-separated integers describes scores.Output is handled by the locked stub code. Your output will be correct if your Student class constructor and calculate() method are properly implemented.
Sample Input:
Heraldo Memelli 8135627
2
100 80
Sample Output:
Name: Memelli, Heraldo
ID: 8135627
Grade: O
Explanation:
This student had 2 scores to average: 100 and 80. The student's average grade is (100+80)/2 = 90 . An average grade of 90 corresponds to the letter grade O, so the calculate() method should return the character'O'.
, I have written this Solution Code: class Person:
firstName = 'Default'
lastName = 'Default'
idNumber = 0
class Student(Person):
def __init__(self):
self.fname, self.lname, self.idnum = map(str, input().split())
self.cnt = int(input())
self.score = list(map(int, input().split()))
def calculate():
s = Student()
sum_grade = 0
count = 0
for i in s.score:
sum_grade += i
count += 1
grade_n = sum_grade//count
print("Name: {}, {}".format(s.lname, s.fname))
print("ID: {}".format(s.idnum))
if grade_n <= 100 and grade_n > 89:
return 'O'
elif grade_n > 79:
return 'E'
elif grade_n > 69:
return 'A'
elif grade_n > 54:
return 'P'
elif grade_n > 40:
return 'D'
elif grade_n >= 0:
return 'T'
res = calculate()
print("Grade: {}".format(res)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: You are given two classes, Person and Student, where Person is the base class and Student is the derived class. Complete code for Person and a declaration for Student are provided for you in the editor. Observe that Student inherits all the properties of Person.
Complete the Student class by writing the following:
A Student class constructor, which has parameters:
* A string firstName.
* A string lastName.
* An integer idNumber.
* An integer array (or vector) of test scores,.
A char calculate() method that calculates a Student object's average and returns the grade character representative of their calculated average:
Grading Scale:
Letter Average
O 90 <= a <= 100
E 80 <= a < 90
A 70 <= a < 80
P 55 <= a < 70
D 40 <= a < 55
T < 40The locked stub code in the editor reads the input and calls the Student class constructor with the necessary arguments. It also calls the calculate method which takes no arguments.
The first line contains firstName, lastName, and isNumber, separated by a space. The second line contains the number of test scores. The third line of space-separated integers describes scores.Output is handled by the locked stub code. Your output will be correct if your Student class constructor and calculate() method are properly implemented.
Sample Input:
Heraldo Memelli 8135627
2
100 80
Sample Output:
Name: Memelli, Heraldo
ID: 8135627
Grade: O
Explanation:
This student had 2 scores to average: 100 and 80. The student's average grade is (100+80)/2 = 90 . An average grade of 90 corresponds to the letter grade O, so the calculate() method should return the character'O'.
, I have written this Solution Code: class Student extends Person {
private int[] testScores;
Student(String firstName, String lastName, int identification, int[] scores){
super(firstName, lastName, identification);
this.testScores = scores;
}
public char calculate() {
int average = 0;
for(int i = 0; i < testScores.length; i++){
average += testScores[i];
}
average = average / testScores.length;
if(average >= 90) {
return 'O'; // Outstanding
}
else if(average >= 80) {
return 'E'; // Exceeds Expectations
}
else if(average >= 70) {
return 'A'; // Acceptable
}
else if(average >= 55) {
return 'P'; // Poor
}
else if(average >= 40) {
return 'D'; // Dreadful
}
else {
return 'T'; // Troll
}
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code: public static Node shuffle(Node head){
int cnt=0;
Node temp=head;
while(temp!=null){
cnt++;
temp=temp.next;
}
int p = cnt/2;
cnt=0;
temp=head;
while(cnt!=p){
temp=temp.next;
cnt++;
}
cnt=0;
Node res;
Node rem;
//return temp;
rem=head.next;
res=temp;
Node ans = head;
while(cnt!=p-1){
// System.out.println(res.data+" "+rem.data);
head.next=res;
res=res.next;
head=head.next;
head.next=rem;
rem=rem.next;
head=head.next;
cnt++;
}
head.next=res;
res=null;
return ans;
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code:
def shuffle(arr,size):
l=[]
for i in range(size):
print(arr[i],end=" ")
print(arr[size+i],end=" ")
size = int(input())
arr= list(map(int,input().rstrip().split()))
shuffle(arr,size), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a list of size 2*N in the form as x<sub>1</sub>->x<sub>2</sub>->x<sub>3</sub>.... x<sub>n</sub>, y<sub>1</sub>->y<sub>2</sub>->y<sub>3</sub>,.... y<sub>n</sub>, Your task is to shuffle the list in the form given as x<sub>1</sub>->y<sub>1</sub>->x<sub>2</sub>->y<sub>2</sub>,.... x<sub>n</sub>,->y<sub>n</sub>.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>shuffle()</b> that takes the head node of the linked lists as a parameter.
Constraints:-
1 ≤ N ≤ 1000Return the head of the modified list.Sample Input:-
3
1 2 3 4 5 6
Sample Output:-
1 4 2 5 3 6
Explanation:
1-> 4-> 2-> 5-> 3-> 6
, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define max1 10001
#define MOD 1000000007
#define read(type) readInt<type>()
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
signed main()
{
int n;
cin>>n;
int a[2*n];
FOR(i,2*n){
cin>>a[i];}
FOR(i,n){
cout<<a[i]<<" "<<a[n+i]<<" ";
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a 2D matrix of size [M, N], Q number of queries. In each query, you will be given a number X to check whether it is present in the matrix or not.The first line contains three integers M(number of rows), N(Number of columns), and Q(number of queries)
Next M lines contain N integers which are the elements of the matrix.
Next, Q lines will contain a single integer X.
Constraints:-
1<=M,N<=1000
1<=Q<=10000
1<=X, Arr[i]<=1000000000For each query, in a new line print "Yes" if the element is present in matrix or print "No" if the element is absent.Input:-
3 3 2
1 2 3
5 6 7
8 9 10
7
11
Output:-
Yes
No
Input:-
3 4 4
4 8 11 14
15 54 45 47
1 2 3 4
5
15
45
26
Output:-
No
Yes
Yes
No, I have written this Solution Code: import java.io.*; // for handling input/output
import java.util.*; // contains Collections framework
// don't change the name of this class
// you can add inner classes if needed
class Main {
public static void main (String[] args) {
// Your code here
Scanner sc = new Scanner(System.in);
int m = sc.nextInt();
int n = sc.nextInt();
int q = sc.nextInt();
int mat[] = new int[m*n];
int matSize = m*n;
for(int i = 0; i < m*n; i++)
{
int ele = sc.nextInt();
mat[i] = ele;
}
Arrays.sort(mat);
for(int i = 1; i <= q; i++)
{
int qs = sc.nextInt();
System.out.println(isPresent(mat, matSize, qs));
}
}
static String isPresent(int mat[], int size, int ele)
{
int l = 0, h = size-1;
while(l <= h)
{
int mid = l + (h-l)/2;
if(mat[mid] == ele)
return "Yes";
else if(mat[mid] > ele)
h = mid - 1;
else l = mid+1;
}
return "No";
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a 2D matrix of size [M, N], Q number of queries. In each query, you will be given a number X to check whether it is present in the matrix or not.The first line contains three integers M(number of rows), N(Number of columns), and Q(number of queries)
Next M lines contain N integers which are the elements of the matrix.
Next, Q lines will contain a single integer X.
Constraints:-
1<=M,N<=1000
1<=Q<=10000
1<=X, Arr[i]<=1000000000For each query, in a new line print "Yes" if the element is present in matrix or print "No" if the element is absent.Input:-
3 3 2
1 2 3
5 6 7
8 9 10
7
11
Output:-
Yes
No
Input:-
3 4 4
4 8 11 14
15 54 45 47
1 2 3 4
5
15
45
26
Output:-
No
Yes
Yes
No, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define N 1000000
long a[N];
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n,m,q;
cin>>n>>m>>q;
n=n*m;
long long sum=0,sum1=0;
for(int i=0;i<n;i++){
cin>>a[i];
}
sort(a,a+n);
while(q--){
long x;
cin>>x;
int l=0;
int r=n-1;
while (r >= l) {
int mid = l + (r - l) / 2;
if (a[mid] == x) {
cout<<"Yes"<<endl;goto f;}
if (a[mid] > x)
{
r=mid-1;
}
else {l=mid+1;
}
}
cout<<"No"<<endl;
f:;
}
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Print a sequence of numbers starting with N, without using loop, in which A[i+1] = A[i] - 5, if A[i]>0, else A[i+1] = A[i] + 5 repeat it until A[i]=N.
Note:- Once you change a operation you need to continue doing it.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>PrintPattern()</b> that takes the integer N and the integer curr (curr = N) and bool flag (flag = true) as a parameter.
Constraints:
1<=T<=10
0 < N < 1000Print the pattern with space-separated integers.Sample Input:
2
16
10
Sample Output:
16 11 6 1 -4 1 6 11 16
10 5 0 5 10
Explanation:
We basically first reduce 5 one by one until we reach a negative or 0. After we reach 0 or negative, we one by one add 5 until we reach N., I have written this Solution Code: static void printPattern(int n,int curr, boolean flag)
{System.out.print(curr+" ");
if(flag==false && curr==n){return;}
if(curr<=0){flag=false;}
if(flag){printPattern(n,curr-5,flag);}
else{printPattern(n,curr+5,flag);}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: When learning a new language, we first learn to output some message. Here, we'll start with the famous "Hello World" message. There is no input, you just have to print "Hello World".No InputHello WorldExplanation:
Hello World is printed., I have written this Solution Code: a="Hello World"
print(a), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: When learning a new language, we first learn to output some message. Here, we'll start with the famous "Hello World" message. There is no input, you just have to print "Hello World".No InputHello WorldExplanation:
Hello World is printed., I have written this Solution Code: import java.util.*;
import java.io.*;
class Main{
public static void main(String args[]){
System.out.println("Hello World");
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: import java.io.*;
import java.util.*;
class Main {
public static void main (String[] args)throws Exception {
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String str[]=br.readLine().split(" ");
int a[]=new int[str.length];
int sum=0;
for(int i=0;i<str.length;i++)
{
a[i]=Integer.parseInt(str[i]);
sum=sum+a[i];
}
System.out.println(sum/4);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Ram is studying in Class V and has four subjects, each subject carry 100 marks. He passed with flying colors in his exam, but when his neighbour asked how much percentage did he got in exam, he got stuck in calculation. Ram is a good student but he forgot how to calculate percentage. Help Ram to get him out of this problem.
Given four numbers a , b , c and d denoting the marks in four subjects . Calculate the overall percentage (floor value ) Ram got in exam .First line contains four variables a, b, c and d.
<b>Constraints</b>
1<= a, b, c, d <= 100
Print single line containing the percentage.Sample Input 1:
25 25 25 25
Sample Output 1:
25
Sample Input 2:
75 25 75 25
Sample Output 2:
50, I have written this Solution Code: a,b,c,d = map(int,input().split())
print((a+b+c+d)*100//400), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given three integers your task is to calculate the maximum integer among the given integers.The input contains three integers a, b, and c
<b>Constraint:</b>
1<=integers<=10000Print the maximum integer among the given integers.Sample Input:-
2 6 3
Sample Output:-
6
Sample Input:-
48 100 100
Sample Output:
100, I have written this Solution Code: a,b,c=[int(a) for a in input().split()]
print(max(a,b,c)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given three integers your task is to calculate the maximum integer among the given integers.The input contains three integers a, b, and c
<b>Constraint:</b>
1<=integers<=10000Print the maximum integer among the given integers.Sample Input:-
2 6 3
Sample Output:-
6
Sample Input:-
48 100 100
Sample Output:
100, I have written this Solution Code: import java.util.Scanner;
class Main {
public static void main (String[] args)
{
//Capture the user's input
Scanner scanner = new Scanner(System.in);
//Storing the captured value in a variable
int p = scanner.nextInt();
int tm = scanner.nextInt();
int r = scanner.nextInt();
int intrst = MaxInteger(p,tm,r);
System.out.println(intrst);
}
static int MaxInteger(int a ,int b, int c){
if(a>=b && a>=c){return a;}
if(b>=a && b>=c){return b;}
return c;}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a letter of lowercase English alphabet, your task is to determine whether it is a vowel or a consonant.User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>VowelorConsonant()</b> which contains M as a parameter.
Constraints:-
'a' <= alpha <= 'z'Print C if the given alphabet is Consonant else Print V.Sample Input:-
a
Sample Output:-
V
Sample Input:-
b
Sample Output:-
C, I have written this Solution Code: ch = input()
if(ch=='a' or ch =='e' or ch=='i' or ch=='o' or ch=='u'):
print("V")
else:
print("C"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a letter of lowercase English alphabet, your task is to determine whether it is a vowel or a consonant.User task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>VowelorConsonant()</b> which contains M as a parameter.
Constraints:-
'a' <= alpha <= 'z'Print C if the given alphabet is Consonant else Print V.Sample Input:-
a
Sample Output:-
V
Sample Input:-
b
Sample Output:-
C, I have written this Solution Code:
static void VowelorConsonant(char C){
if(C=='a' || C=='e' || C=='i' || C=='o' || C=='u'){System.out.print("V");}
else{
System.out.print("C");
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Take an integer as input and print it.The first line contains integer as input.
<b>Constraints</b>
1 <= N <= 10Print the input integer in a single lineSample Input:-
2
Sample Output:-
2
Sample Input:-
4
Sample Output:-
4, I have written this Solution Code: /* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Main
{
public static void printVariable(int variable){
System.out.println(variable);
}
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
printVariable(num);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code: function numberOfDays(n)
{
let ans;
switch(n)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
ans = Number(31);
break;
case 2:
ans = Number(28);
break;
default:
ans = Number(30);
break;
}
return ans;
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code:
static void numberofdays(int M){
if(M==4 || M ==6 || M==9 || M==11){System.out.print(30);}
else if(M==2){System.out.print(28);}
else{
System.out.print(31);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <i>Your Grace, I feel I've been remiss in my duties. I've given you meat and wine and music, but I haven’t shown you the hospitality you deserve. My King has married and I owe my new Queen a wedding gift. </i>
Roose Bolton thinks of attacking Robb Stark, but since Catelyn has realised his traumatising idea, she signals Robb by shouting two numbers A and B. For Robb to understand the signal, he needs to solve the following problem with the two numbers:
Given A and B, find whether A can be transformed to B if A can be converted to A + fact(A) any number of times, where fact(A) is any factor of A other than 1 and A itself.
For example: A = 9, B = 14 can follow the given steps during conversion
A = 9
A = 9 + 3 = 12 (3 is a factor of 9)
A = 12 + 2 = 14 = B (2 is a factor of 12)The first and the only line of input contains two numbers A and B.
Constraints
1 <= A, B <= 10<sup>12</sup>Output "Yes" (without quotes) if we can transform A to B, else output "No" (without quotes)Sample Input
9 14
Sample Output
Yes
Explanation: In the problem statement
Sample Input
33 35
Sample Output
No
Explanation
The minimum factor of 33 is 3, so we cannot transform 33 to 35., I have written this Solution Code: import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;
import java.util.StringTokenizer;
public class Main {
static class FastReader {
BufferedReader br;
StringTokenizer st;
public FastReader() {
br = new BufferedReader(new
InputStreamReader(System.in));
}
String next() {
while (st == null || !st.hasMoreElements()) {
try {
st = new StringTokenizer(br.readLine());
} catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt() {
return Integer.parseInt(next());
}
long nextLong() {
return Long.parseLong(next());
}
double nextDouble() {
return Double.parseDouble(next());
}
String nextLine() {
String str = "";
try {
str = br.readLine();
} catch (IOException e) {
e.printStackTrace();
}
return str;
}
};
public static void main(String[] args) {
FastReader sc = new FastReader();
PrintWriter pw = new PrintWriter(System.out);
long a=sc.nextLong();
long b=sc.nextLong();
long tmp=a;
res=new ArrayList<>();
factorize(a);
if(res.size()==1&&res.get(0)==a)
{
System.out.println("No");
return;
}
if(a==b)
{
System.out.println("Yes");
return;
}
for(long i=2;i <= (long) Math.sqrt(b);i++)
{
if(b%i==0&&(b-i)>=a)
{
for(long j:res)
{
if((b-i)%j==0)
{
System.out.println("Yes");
return;
}
}
}
}
System.out.println("No");
}
static ArrayList<Long> res;
static void factorize(long n) {
int count = 0;
while (!(n % 2 > 0)) {
n >>= 1;
count++;
}
if (count > 0) {
res.add(2l);
}
for (long i = 3; i <= (long) Math.sqrt(n); i += 2) {
count = 0;
while (n % i == 0) {
count++;
n = n / i;
}
if (count > 0) {
res.add(i);
}
}
if (n > 2) {
res.add(n);
}
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <i>Your Grace, I feel I've been remiss in my duties. I've given you meat and wine and music, but I haven’t shown you the hospitality you deserve. My King has married and I owe my new Queen a wedding gift. </i>
Roose Bolton thinks of attacking Robb Stark, but since Catelyn has realised his traumatising idea, she signals Robb by shouting two numbers A and B. For Robb to understand the signal, he needs to solve the following problem with the two numbers:
Given A and B, find whether A can be transformed to B if A can be converted to A + fact(A) any number of times, where fact(A) is any factor of A other than 1 and A itself.
For example: A = 9, B = 14 can follow the given steps during conversion
A = 9
A = 9 + 3 = 12 (3 is a factor of 9)
A = 12 + 2 = 14 = B (2 is a factor of 12)The first and the only line of input contains two numbers A and B.
Constraints
1 <= A, B <= 10<sup>12</sup>Output "Yes" (without quotes) if we can transform A to B, else output "No" (without quotes)Sample Input
9 14
Sample Output
Yes
Explanation: In the problem statement
Sample Input
33 35
Sample Output
No
Explanation
The minimum factor of 33 is 3, so we cannot transform 33 to 35., I have written this Solution Code: import math
arr=[int (x) for x in input().split()]
a,b=arr[0],arr[1]
if a>=b:
print("No")
else:
m=-1
i=2
while i**2<=a:
if a%i==0:
m=i
break
i+=1
if m==-1:
print("No")
elif math.gcd(a,b)!=1:
print("Yes")
else:
a=a+m
if a<b and math.gcd(a,b)!=1:
print("Yes")
else:
print("No"), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: <i>Your Grace, I feel I've been remiss in my duties. I've given you meat and wine and music, but I haven’t shown you the hospitality you deserve. My King has married and I owe my new Queen a wedding gift. </i>
Roose Bolton thinks of attacking Robb Stark, but since Catelyn has realised his traumatising idea, she signals Robb by shouting two numbers A and B. For Robb to understand the signal, he needs to solve the following problem with the two numbers:
Given A and B, find whether A can be transformed to B if A can be converted to A + fact(A) any number of times, where fact(A) is any factor of A other than 1 and A itself.
For example: A = 9, B = 14 can follow the given steps during conversion
A = 9
A = 9 + 3 = 12 (3 is a factor of 9)
A = 12 + 2 = 14 = B (2 is a factor of 12)The first and the only line of input contains two numbers A and B.
Constraints
1 <= A, B <= 10<sup>12</sup>Output "Yes" (without quotes) if we can transform A to B, else output "No" (without quotes)Sample Input
9 14
Sample Output
Yes
Explanation: In the problem statement
Sample Input
33 35
Sample Output
No
Explanation
The minimum factor of 33 is 3, so we cannot transform 33 to 35., I have written this Solution Code: #include <bits/stdc++.h>
using namespace std;
#define sd(x) scanf("%d", &x)
#define sz(v) (int) v.size()
#define pr(v) For(i, 0, sz(v)) {cout<<v[i]<<" ";} cout<<endl;
#define slld(x) scanf("%lld", &x)
#define all(x) x.begin(), x.end()
#define For(i, st, en) for(int i=st; i<en; i++)
#define tr(x) for(auto it=x.begin(); it!=x.end(); it++)
#define fast std::ios::sync_with_stdio(false);cin.tie(NULL);
#define pb push_back
#define ll long long
#define ld long double
#define int long long
#define double long double
#define mp make_pair
#define F first
#define S second
typedef pair<int, int> pii;
typedef vector<int> vi;
#define pi 3.141592653589793238
const int MOD = 1e9+7;
const int INF = 1LL<<60;
const int N = 2e5+5;
// it's swapnil07 ;)
#ifdef SWAPNIL07
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
cout << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
int begtime = clock();
#define end_routine() cout << "\n\nTime elapsed: " << (clock() - begtime)*1000/CLOCKS_PER_SEC << " ms\n\n";
#else
#define endl '\n'
#define trace(...)
#define end_routine()
#endif
int small_prime(int x) {
for(int i=2; i*i<=x; i++){
if(x%i==0){
return i;
}
}
return -1;
}
void solve(){
int a, b;
cin>>a>>b;
int aa = a, bb = b;
int d1 = small_prime(a);
int d2 = small_prime(b);
if (d1 == -1 || d2 == -1) {
cout<<"No";
return;
}
if ((a % 2) == 1) {
a += d1;
}
if ((b % 2) == 1) {
b -= d2;
}
if (a > b) {
cout<<"No";
return;
}
cout<<"Yes";
}
signed main()
{
fast
#ifdef SWAPNIL07
freopen("input.txt","r",stdin);
freopen("output.txt","w",stdout);
#endif
int t=1;
// cin>>t;
while(t--){
solve();
cout<<"\n";
}
return 0;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code: function numberOfDays(n)
{
let ans;
switch(n)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
ans = Number(31);
break;
case 2:
ans = Number(28);
break;
default:
ans = Number(30);
break;
}
return ans;
}, In this Programming Language: JavaScript, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given the number of the month, your task is to calculate the number of days present in the particular month.
<b>Note:-</b>
Consider non-leap yearUser task:
Since this is a functional problem you don't have to worry about the input. You just have to complete the function <b>numberofdays()</b> which contains M as a parameter.
<b>Constraints:-</b>
1 <= M <= 12Print the number of days in the particular month.Sample Input 1:-
1
Sample Output 1:
31
Sample Input 2:-
2
Sample Output 2:-
28, I have written this Solution Code:
static void numberofdays(int M){
if(M==4 || M ==6 || M==9 || M==11){System.out.print(30);}
else if(M==2){System.out.print(28);}
else{
System.out.print(31);
}
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: void farhenheitToCelsius(int n){
n-=32;
n/=9;
n*=5;
cout<<n;
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: Fahrenheit= int(input())
Celsius = int(((Fahrenheit-32)*5)/9 )
print(Celsius), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a temperature F in Farenheit, your task is to convert it into Celsius using the following equation:-
T(°c) = (T(°f) - 32)*5/9You don't have to worry about the input, you just have to complete the function <b>fahrenheitToCelsius</b>
Constraints:-
-10^3 <= F <= 10^3
<b>Note:-</b> It is guaranteed that F - 32 will be a multiple of 9.Print an integer containing converted temperature in Fahrenheit.Sample Input 1:
77
Sample Output 1:
25
Sample Input 2:-
-40
Sample Output 2:-
-40
<b>Explanation 1</b>:
T(°c) = (T(°f) - 32)*5/9
T(°c) = (77-32)*5/9
T(°c) =25, I have written this Solution Code: static void farhrenheitToCelsius(int farhrenheit)
{
int celsius = ((farhrenheit-32)*5)/9;
System.out.println(celsius);
}
, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.The input contains a single line containing the value of N.
Constraints:-
1 <= N <= 1000Print the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: import java.util.*;
import java.io.*;
import java.lang.*;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int x=sc.nextInt();
int ans = 9 * (x-1);
System.out.print(ans);
}
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.The input contains a single line containing the value of N.
Constraints:-
1 <= N <= 1000Print the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code:
#include <bits/stdc++.h>
using namespace std;
#define MEM(a, b) memset(a, (b), sizeof(a))
#define FOREACH(it, l) for (auto it = l.begin(); it != l.end(); it++)
#define IN(A, B, C) assert( B <= A && A <= C)
#define MP make_pair
#define FOR(i,a) for(int i=0;i<a;i++)
#define FOR1(i,j,a) for(int i=j;i<a;i++)
#define EB emplace_back
#define INF (int)1e9
#define EPS 1e-9
#define PI 3.1415926535897932384626433832795
#define max1 1000001
#define MOD 1000000000000007
#define read(type) readInt<type>()
#define out(x) cout<<x<<'\n'
#define out1(x) cout<<x<<" "
#define END cout<<'\n'
#define int long long
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(), (v).end()
void fast(){
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
int cnt[max1];
signed main(){
int n;
cin>>n;
out((n-1)*9);
}
, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.The input contains a single line containing the value of N.
Constraints:-
1 <= N <= 1000Print the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: a=int(input())
print(9*(a-1)), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>StrangeNumber()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 1000Return the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: def StrangeNumber(N):
return 9*(N-1)
, In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>StrangeNumber()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 1000Return the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: int StrangeNumber(int N){
return 9*(N-1);
}, In this Programming Language: C++, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>StrangeNumber()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 1000Return the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: int StrangeNumber(int N){
return 9*(N-1);
}, In this Programming Language: C, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A number X (X>=0) is called strange if the sum of its digits is divisible by 9. Given an integer N, your task is to find the Nth strange number.<b>User Task:</b>
Since this will be a functional problem, you don't have to take input. You just have to complete the function <b>StrangeNumber()</b> that takes integer N as argument.
Constraints:-
1 <= N <= 1000Return the Nth strange number.Sample Input:-
3
Sample Output:-
18
Explanation:-
0, 9, and 18 are the first three strange numbers.
Sample Input:-
2
Sample Output:-
9, I have written this Solution Code: static int StrangeNumber(int N){
return 9*(N-1);
}, In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: Given a Binary Tree, your task is to convert it to a Doubly Linked List. The left and right pointers in nodes are to be used as previous and next pointers respectively in converted Double linked list. The order of nodes in Double linked list must be same as Inorder of the given Binary Tree. The first node of Inorder traversal (left most node in Binary tree) must be head node of the Doubly linked list.<b>User Task:</b>
Since this will be a functional problem. You don't have to take input. You just have to complete the function <b>BToDLL()</b> that takes "root" node of binary tree as parameter.
Constraint:-
1 <= Number of Nodes <= 1000
1 <= Node.data <= 1000
The printing is done by the driver code you just need to complete the function.Sample Input:-
3
1 2 3
Sample Output:-
2 1 3
Sample Input:-
5
6 5 4 3 2
Sample Output:-
3 5 2 6 4 , I have written this Solution Code: static void BToDLL(Node root)
{
// Base cases
if (root == null)
return ;
// Recursively convert right subtree
BToDLL(root.right);
// insert root into DLL
root.right = head;
// Change left pointer of previous head
if (head != null)
(head).left = root;
// Change head of Doubly linked list
head = root;
// Recursively convert left subtree
BToDLL(root.left);
} , In this Programming Language: Java, Now tell me if this Code is compilable or not? | Compilable |
For this Question: A Tribonacci number T(n) is the sum of the preceding three elements in a series.
Calculate the value of the nth Tribonacci number modulo 1000000007. The initial three numbers of this series will be a, b and c i.e., T(1)=a, T(2)=b, T(3)=c.The only line of input contains 4 integers n, a, b, c.
Constraints
4 ≤ n ≤ 10^5
1 ≤ a, b, c ≤ 1000000000Print the result containing one integer i.e., T(n) modulo 1000000007.Input1:
5 1 2 3
Output1:
11
Input2:
4 1 1 1
Output2:
3
Explanation(might now be the optimal solution):
Input 1:
Follow the below steps:-
T(1) = 1
T(2) = 2
T(3) = 3
T(4) = 6
T(5) = 11, I have written this Solution Code: n,a,b,c = map(int, input().split())
m = 1000000007
result = 0
while n > 3:
result = (a%m + b%m + c%m)%m
a = b
b = c
c = result
n -= 1
print(result), In this Programming Language: Python, Now tell me if this Code is compilable or not? | Compilable |