message stringlengths 2 23.4k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 129 108k | cluster float64 6 6 | __index_level_0__ int64 258 216k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Most C/C++ programmers know about excellent opportunities that preprocessor #define directives give; but many know as well about the problems that can arise because of their careless use.
In this problem we consider the following model of #define constructions (also called macros). Each macro has its name and value. The generic syntax for declaring a macro is the following:
#define macro_name macro_value
After the macro has been declared, "macro_name" is replaced with "macro_value" each time it is met in the program (only the whole tokens can be replaced; i.e. "macro_name" is replaced only when it is surrounded by spaces or other non-alphabetic symbol). A "macro_value" within our model can only be an arithmetic expression consisting of variables, four arithmetic operations, brackets, and also the names of previously declared macros (in this case replacement is performed sequentially). The process of replacing macros with their values is called substitution.
One of the main problems arising while using macros β the situation when as a result of substitution we get an arithmetic expression with the changed order of calculation because of different priorities of the operations.
Let's consider the following example. Say, we declared such a #define construction:
#define sum x + y
and further in the program the expression "2 * sum" is calculated. After macro substitution is performed we get "2 * x + y", instead of intuitively expected "2 * (x + y)".
Let's call the situation "suspicious", if after the macro substitution the order of calculation changes, falling outside the bounds of some macro. Thus, your task is to find out by the given set of #define definitions and the given expression if this expression is suspicious or not.
Let's speak more formally. We should perform an ordinary macros substitution in the given expression. Moreover, we should perform a "safe" macros substitution in the expression, putting in brackets each macro value; after this, guided by arithmetic rules of brackets expansion, we can omit some of the brackets. If there exist a way to get an expression, absolutely coinciding with the expression that is the result of an ordinary substitution (character-by-character, but ignoring spaces), then this expression and the macros system are called correct, otherwise β suspicious.
Note that we consider the "/" operation as the usual mathematical division, not the integer division like in C/C++. That's why, for example, in the expression "a*(b/c)" we can omit brackets to get the expression "a*b/c".
Input
The first line contains the only number n (0 β€ n β€ 100) β the amount of #define constructions in the given program.
Then there follow n lines, each of them contains just one #define construction. Each construction has the following syntax:
#define name expression
where
* name β the macro name,
* expression β the expression with which the given macro will be replaced. An expression is a non-empty string, containing digits,names of variables, names of previously declared macros, round brackets and operational signs +-*/. It is guaranteed that the expression (before and after macros substitution) is a correct arithmetic expression, having no unary operations. The expression contains only non-negative integers, not exceeding 109.
All the names (#define constructions' names and names of their arguments) are strings of case-sensitive Latin characters. It is guaranteed that the name of any variable is different from any #define construction.
Then, the last line contains an expression that you are to check. This expression is non-empty and satisfies the same limitations as the expressions in #define constructions.
The input lines may contain any number of spaces anywhere, providing these spaces do not break the word "define" or the names of constructions and variables. In particular, there can be any number of spaces before and after the "#" symbol.
The length of any line from the input file does not exceed 100 characters.
Output
Output "OK", if the expression is correct according to the above given criterion, otherwise output "Suspicious".
Examples
Input
1
#define sum x + y
1 * sum
Output
Suspicious
Input
1
#define sum (x + y)
sum - sum
Output
OK
Input
4
#define sum x + y
#define mul a * b
#define div a / b
#define expr sum + mul * div * mul
expr
Output
OK
Input
3
#define SumSafe (a+b)
#define DivUnsafe a/b
#define DenominatorUnsafe a*b
((SumSafe) + DivUnsafe/DivUnsafe + x/DenominatorUnsafe)
Output
Suspicious
Submitted Solution:
```
# 1:correct, 2:incorrect, 3:(a+b), no - at front, no * or / neighbor, 4:(a*b),(a/b) no / at front
def helper(s, d):
# print(s)
if s in d:
return d[s]
cnt = 0
for idx, c in reversed(list(enumerate(s))):
if c == ')':
cnt += 1
elif c == '(':
cnt -= 1
if cnt == 0 and c in ['+', '-']:
s1 = s[0:idx]
s2 = s[idx+1:]
t1 = helper(s1, d)
t2 = helper(s2, d)
t = 3
if t1 == 2 or t2 == 2:
t = 2
elif t2 == 3 and c == '-':
t = 2
d[s] = t
return t
cnt = 0
for idx, c in reversed(list(enumerate(s))):
if c == ')':
cnt += 1
elif c == '(':
cnt -= 1
if cnt == 0 and c in ['*', '/']:
s1 = s[0:idx]
s2 = s[idx+1:]
t1 = helper(s1, d)
t2 = helper(s2, d)
# print(s)
# print(s1, ' ', s2)
t = 4
if t1 == 2 or t2 == 2:
t = 2
elif t1 == 3 or t2 == 3:
t = 2
elif t2 == 4 and c == '/':
t = 2
d[s] = t
return t
if s[0] == '(' and s[-1] == ')':
if helper(s[1:-1], d) == 2:
return 2
else:
return 1
d[s] = 1
return 1
d = {}
n = int(input())
for i in range(0, n):
temp = input()[8:].split(' ', 1)
name, exp = temp[0], ''.join(temp[1].split())
t = helper(exp, d)
d[name] = t
# print(t)
final = ''.join(input().split())
res = helper(final, d)
if res == 2:
print('Suspicious')
else:
print('OK')
# print(arr)
# print(helper('(a-a)*(x/x-1)', d))
``` | instruction | 0 | 38,229 | 6 | 76,458 |
No | output | 1 | 38,229 | 6 | 76,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Most C/C++ programmers know about excellent opportunities that preprocessor #define directives give; but many know as well about the problems that can arise because of their careless use.
In this problem we consider the following model of #define constructions (also called macros). Each macro has its name and value. The generic syntax for declaring a macro is the following:
#define macro_name macro_value
After the macro has been declared, "macro_name" is replaced with "macro_value" each time it is met in the program (only the whole tokens can be replaced; i.e. "macro_name" is replaced only when it is surrounded by spaces or other non-alphabetic symbol). A "macro_value" within our model can only be an arithmetic expression consisting of variables, four arithmetic operations, brackets, and also the names of previously declared macros (in this case replacement is performed sequentially). The process of replacing macros with their values is called substitution.
One of the main problems arising while using macros β the situation when as a result of substitution we get an arithmetic expression with the changed order of calculation because of different priorities of the operations.
Let's consider the following example. Say, we declared such a #define construction:
#define sum x + y
and further in the program the expression "2 * sum" is calculated. After macro substitution is performed we get "2 * x + y", instead of intuitively expected "2 * (x + y)".
Let's call the situation "suspicious", if after the macro substitution the order of calculation changes, falling outside the bounds of some macro. Thus, your task is to find out by the given set of #define definitions and the given expression if this expression is suspicious or not.
Let's speak more formally. We should perform an ordinary macros substitution in the given expression. Moreover, we should perform a "safe" macros substitution in the expression, putting in brackets each macro value; after this, guided by arithmetic rules of brackets expansion, we can omit some of the brackets. If there exist a way to get an expression, absolutely coinciding with the expression that is the result of an ordinary substitution (character-by-character, but ignoring spaces), then this expression and the macros system are called correct, otherwise β suspicious.
Note that we consider the "/" operation as the usual mathematical division, not the integer division like in C/C++. That's why, for example, in the expression "a*(b/c)" we can omit brackets to get the expression "a*b/c".
Input
The first line contains the only number n (0 β€ n β€ 100) β the amount of #define constructions in the given program.
Then there follow n lines, each of them contains just one #define construction. Each construction has the following syntax:
#define name expression
where
* name β the macro name,
* expression β the expression with which the given macro will be replaced. An expression is a non-empty string, containing digits,names of variables, names of previously declared macros, round brackets and operational signs +-*/. It is guaranteed that the expression (before and after macros substitution) is a correct arithmetic expression, having no unary operations. The expression contains only non-negative integers, not exceeding 109.
All the names (#define constructions' names and names of their arguments) are strings of case-sensitive Latin characters. It is guaranteed that the name of any variable is different from any #define construction.
Then, the last line contains an expression that you are to check. This expression is non-empty and satisfies the same limitations as the expressions in #define constructions.
The input lines may contain any number of spaces anywhere, providing these spaces do not break the word "define" or the names of constructions and variables. In particular, there can be any number of spaces before and after the "#" symbol.
The length of any line from the input file does not exceed 100 characters.
Output
Output "OK", if the expression is correct according to the above given criterion, otherwise output "Suspicious".
Examples
Input
1
#define sum x + y
1 * sum
Output
Suspicious
Input
1
#define sum (x + y)
sum - sum
Output
OK
Input
4
#define sum x + y
#define mul a * b
#define div a / b
#define expr sum + mul * div * mul
expr
Output
OK
Input
3
#define SumSafe (a+b)
#define DivUnsafe a/b
#define DenominatorUnsafe a*b
((SumSafe) + DivUnsafe/DivUnsafe + x/DenominatorUnsafe)
Output
Suspicious
Submitted Solution:
```
def helper(s):
if s[0] == '(' and s[-1] == ')':
return helper(s[1:-1])
cnt = 0
for i in range(0, len(s)):
c = s[i]
if c == '(':
cnt += 1
elif c == ')':
cnt -= 1
if c in ['+', '-', '*', '/'] and cnt == 0:
s1 = s[0:i]
s2 = s[i + 1:]
t1 = helper(s1)
t2 = helper(s2)
if t1 == 3 or t2 == 3:
return 3
if t2 == 1 and c == '/':
return 3
if t2 == 2 and c != '+':
return 3
if c == '+' or c == '-':
return 2
if c == '*' or c == '/':
return 1
return 0
return 0
n = int(input())
arr = []
for i in range(0, n):
temp = input()[8:].split(' ', 1)
name, exp = temp[0], ''.join(temp[1].split())
arr.append((name, exp))
# print(arr[i])
final = ''.join(input().split())
for i in range(0, n):
final = final.replace(arr[i][0], arr[i][1])
# print(final)
res = helper(final)
if res == 3:
print('Suspicious')
else:
print('OK')
# print(arr)
# print(helper('(a+b)+a/b/a/b+x/a*b'))
# sign = ['+']
# exp = []
# cnt = 0
# prev = 0
# for i in range(0, len(s)):
# c = s.charAt(i)
# if c == '(':
# cnt += 1
# elif c == ')':
# cnt -= 1
# if cnt == 0:
# t = helper(s[prev + 1 : i])
# if t != 2:
# exp.append(1)
# else:
# exp.append(2)
# elif c in ('+', '-', '*', '\\') and cnt == 0:
# sign.append(c)
# t = helper(s[prev + 1 : i])
# exp.append(t)
# prev = i
#
#
# for i in range(0, len(sign)):
# ss = sign[i]
# tt = exp[i]
#
# if ss == '+':
``` | instruction | 0 | 38,230 | 6 | 76,460 |
No | output | 1 | 38,230 | 6 | 76,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Most C/C++ programmers know about excellent opportunities that preprocessor #define directives give; but many know as well about the problems that can arise because of their careless use.
In this problem we consider the following model of #define constructions (also called macros). Each macro has its name and value. The generic syntax for declaring a macro is the following:
#define macro_name macro_value
After the macro has been declared, "macro_name" is replaced with "macro_value" each time it is met in the program (only the whole tokens can be replaced; i.e. "macro_name" is replaced only when it is surrounded by spaces or other non-alphabetic symbol). A "macro_value" within our model can only be an arithmetic expression consisting of variables, four arithmetic operations, brackets, and also the names of previously declared macros (in this case replacement is performed sequentially). The process of replacing macros with their values is called substitution.
One of the main problems arising while using macros β the situation when as a result of substitution we get an arithmetic expression with the changed order of calculation because of different priorities of the operations.
Let's consider the following example. Say, we declared such a #define construction:
#define sum x + y
and further in the program the expression "2 * sum" is calculated. After macro substitution is performed we get "2 * x + y", instead of intuitively expected "2 * (x + y)".
Let's call the situation "suspicious", if after the macro substitution the order of calculation changes, falling outside the bounds of some macro. Thus, your task is to find out by the given set of #define definitions and the given expression if this expression is suspicious or not.
Let's speak more formally. We should perform an ordinary macros substitution in the given expression. Moreover, we should perform a "safe" macros substitution in the expression, putting in brackets each macro value; after this, guided by arithmetic rules of brackets expansion, we can omit some of the brackets. If there exist a way to get an expression, absolutely coinciding with the expression that is the result of an ordinary substitution (character-by-character, but ignoring spaces), then this expression and the macros system are called correct, otherwise β suspicious.
Note that we consider the "/" operation as the usual mathematical division, not the integer division like in C/C++. That's why, for example, in the expression "a*(b/c)" we can omit brackets to get the expression "a*b/c".
Input
The first line contains the only number n (0 β€ n β€ 100) β the amount of #define constructions in the given program.
Then there follow n lines, each of them contains just one #define construction. Each construction has the following syntax:
#define name expression
where
* name β the macro name,
* expression β the expression with which the given macro will be replaced. An expression is a non-empty string, containing digits,names of variables, names of previously declared macros, round brackets and operational signs +-*/. It is guaranteed that the expression (before and after macros substitution) is a correct arithmetic expression, having no unary operations. The expression contains only non-negative integers, not exceeding 109.
All the names (#define constructions' names and names of their arguments) are strings of case-sensitive Latin characters. It is guaranteed that the name of any variable is different from any #define construction.
Then, the last line contains an expression that you are to check. This expression is non-empty and satisfies the same limitations as the expressions in #define constructions.
The input lines may contain any number of spaces anywhere, providing these spaces do not break the word "define" or the names of constructions and variables. In particular, there can be any number of spaces before and after the "#" symbol.
The length of any line from the input file does not exceed 100 characters.
Output
Output "OK", if the expression is correct according to the above given criterion, otherwise output "Suspicious".
Examples
Input
1
#define sum x + y
1 * sum
Output
Suspicious
Input
1
#define sum (x + y)
sum - sum
Output
OK
Input
4
#define sum x + y
#define mul a * b
#define div a / b
#define expr sum + mul * div * mul
expr
Output
OK
Input
3
#define SumSafe (a+b)
#define DivUnsafe a/b
#define DenominatorUnsafe a*b
((SumSafe) + DivUnsafe/DivUnsafe + x/DenominatorUnsafe)
Output
Suspicious
Submitted Solution:
```
print("Still has no idea")
``` | instruction | 0 | 38,231 | 6 | 76,462 |
No | output | 1 | 38,231 | 6 | 76,463 |
Provide a correct Python 3 solution for this coding contest problem.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^ | instruction | 0 | 38,514 | 6 | 77,028 |
"Correct Solution:
```
for _ in [0]*int(input()):
s=input()
char=0
for _ in [0]*int(input()):
c=input()
if c[0]=='i':
c=c.split('"')[1]
s=s[:char]+c+s[char:]
char += len(c)
elif c[8]=='w':
while char <len(s) and s[char]==' ':
char += 1
while char < len(s) and s[char]!=' ':
char += 1
elif c[7]=='c':
s=s[:char]+s[char+1:]
elif c[9]=='w':
while char > 0 and s[char-1]==' ':
char-=1
while char > 0 and s[char-1]!=' ':
char-=1
elif c[8]=='c':
char=min(len(s),char+1)
elif c[7]=='w':
if s[char:].count(' ') == len(s[char:]):
continue
while char<len(s) and s[char]==' ':
s=s[:char]+s[char+1:]
while char<len(s) and s[char]!=' ':
s=s[:char]+s[char+1:]
else:
char=max(0,char-1)
print(s[:char]+'^'+s[char:])
``` | output | 1 | 38,514 | 6 | 77,029 |
Provide a correct Python 3 solution for this coding contest problem.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^ | instruction | 0 | 38,515 | 6 | 77,030 |
"Correct Solution:
```
for _ in [0]*int(input()):
s=input()
cur=0
for _ in [0]*int(input()):
c=input()
if c=='forward word':
while cur<len(s) and s[cur]==' ':cur+=1
while cur<len(s) and s[cur]!=' ':cur+=1
elif c=='delete char' and cur!=len(s):s=s[:cur]+s[cur+1:]
elif c=='backward word':
while cur>0 and s[cur-1]==' ':cur-=1
while cur>0 and s[cur-1]!=' ':cur-=1
elif c=='forward char':cur=min(len(s),cur+1)
elif c=='delete word':
if s[cur:].count(' ') == len(s[cur:]): continue
while cur<len(s) and s[cur]==' ':s=s[:cur]+s[cur+1:]
while cur<len(s) and s[cur]!=' ':s=s[:cur]+s[cur+1:]
elif c[0]=='i':
c=c.split('"')[1]
s=s[:cur]+c+s[cur:]
cur+=len(c)
elif 'backward char':cur=max(0,cur-1)
print(s[:cur]+'^'+s[cur:])
``` | output | 1 | 38,515 | 6 | 77,031 |
Provide a correct Python 3 solution for this coding contest problem.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^ | instruction | 0 | 38,516 | 6 | 77,032 |
"Correct Solution:
```
for _ in [0]*int(input()):
s=input()
cur=0
for _ in [0]*int(input()):
c=input()
if c=='forward word':
while cur<len(s) and s[cur]==' ':cur+=1
while cur<len(s) and s[cur]!=' ':cur+=1
elif c=='delete char':s=s[:cur]+s[cur+1:]
elif c=='backward word':
while cur>0 and s[cur-1]==' ':cur-=1
while cur>0 and s[cur-1]!=' ':cur-=1
elif c=='forward char':cur=min(len(s),cur+1)
elif c=='delete word':
if s[cur:].count(' ') == len(s[cur:]): continue
while cur<len(s) and s[cur]==' ':s=s[:cur]+s[cur+1:]
while cur<len(s) and s[cur]!=' ':s=s[:cur]+s[cur+1:]
elif c[0]=='i':
c=c.split('"')[1]
s=s[:cur]+c+s[cur:]
cur+=len(c)
elif 'backward char':cur=max(0,cur-1)
print(s[:cur]+'^'+s[cur:])
``` | output | 1 | 38,516 | 6 | 77,033 |
Provide a correct Python 3 solution for this coding contest problem.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^ | instruction | 0 | 38,517 | 6 | 77,034 |
"Correct Solution:
```
class TextEditor:
cur_w = 0
cur_c = 0
def __init__(self, txt):
self.words = txt.split(' ')
self.queries = {
'forward char': self.forward_char,
'forward word': self.forward_word,
'backward char': self.backward_char,
'backward word': self.backward_word,
'delete char': self.delete_char,
'delete word': self.delete_word
}
def query(self, q):
if q[0] == 'i':
txt = q.split(maxsplit=1)[1][1:-1]
self.insert(txt)
else:
self.queries[q]()
def forward_char(self):
if self.cur_c < len(self.words[self.cur_w]):
self.cur_c += 1
elif self.cur_w < len(self.words) - 1:
self.cur_w += 1
self.cur_c = 0
else:
pass
def forward_word(self):
if self.cur_c < len(self.words[self.cur_w]):
self.cur_c = len(self.words[self.cur_w])
elif self.cur_w < len(self.words) - 1:
self.cur_w += 1
while not len(self.words[self.cur_w]) and self.cur_w < len(self.words) - 1:
self.cur_w += 1
self.cur_c = len(self.words[self.cur_w])
else:
pass
def backward_char(self):
if self.cur_c > 0:
self.cur_c -= 1
elif self.cur_w > 0:
self.cur_w -= 1
self.cur_c = len(self.words[self.cur_w])
else:
pass
def backward_word(self):
if self.cur_c > 0:
self.cur_c = 0
elif self.cur_w > 0:
self.cur_w -= 1
while not len(self.words[self.cur_w]) and self.cur_w > 0:
self.cur_w -= 1
else:
pass
def insert(self, txt):
st = txt.split(' ')
new_words = self.words[:self.cur_w]
if len(st) > 1:
cw = self.words[self.cur_w]
new_words.append(cw[:self.cur_c] + st[0])
new_words.extend(st[1:-1])
new_words.append(st[-1] + cw[self.cur_c:])
self.cur_c = len(st[-1])
else:
cw = self.words[self.cur_w]
new_words.append(cw[:self.cur_c] + st[0] + cw[self.cur_c:])
self.cur_c = self.cur_c + len(st[0])
new_words.extend(self.words[self.cur_w + 1:])
self.cur_w = self.cur_w + len(st) - 1
self.words = new_words
def delete_char(self):
cw = self.words[self.cur_w]
if self.cur_c < len(cw):
self.words[self.cur_w] = cw[:self.cur_c] + cw[self.cur_c + 1:]
elif self.cur_w < len(self.words) - 1:
if len(cw):
nw = self.words.pop(self.cur_w + 1)
self.words[self.cur_w] = cw + nw
else:
self.words.pop(self.cur_w)
else:
pass
def delete_word(self):
if self.cur_c < len(self.words[self.cur_w]):
self.words[self.cur_w] = self.words[self.cur_w][:self.cur_c]
elif self.cur_w < len(self.words) - 1:
tmp_w = self.cur_w + 1
while tmp_w < len(self.words) and not len(self.words[tmp_w]):
tmp_w += 1
if tmp_w < len(self.words):
del self.words[self.cur_w + 1:tmp_w + 1]
def output(self):
words = self.words.copy()
words[self.cur_w] = self.words[self.cur_w][:self.cur_c] + '^' + \
self.words[self.cur_w][self.cur_c:]
print(*words)
n = int(input())
for _ in range(n):
te = TextEditor(input().strip())
q = int(input())
for _ in range(q):
te.query(input().strip())
te.output()
``` | output | 1 | 38,517 | 6 | 77,035 |
Provide a correct Python 3 solution for this coding contest problem.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^ | instruction | 0 | 38,518 | 6 | 77,036 |
"Correct Solution:
```
for _ in [0]*int(input()):
s=input()
cur=0
for _ in [0]*int(input()):
c=input()
if c[0]=='i':
c=c.split('"')[1]
s=s[:cur]+c+s[cur:]
cur+=len(c)
elif c[8]=='w':
while cur<len(s) and s[cur]==' ':cur+=1
while cur<len(s) and s[cur]!=' ':cur+=1
elif c[7]=='c':s=s[:cur]+s[cur+1:]
elif c[9]=='w':
while cur>0 and s[cur-1]==' ':cur-=1
while cur>0 and s[cur-1]!=' ':cur-=1
elif c[8]=='c':cur=min(len(s),cur+1)
elif c[7]=='w':
if s[cur:].count(' ') == len(s[cur:]): continue
while cur<len(s) and s[cur]==' ':s=s[:cur]+s[cur+1:]
while cur<len(s) and s[cur]!=' ':s=s[:cur]+s[cur+1:]
else:cur=max(0,cur-1)
print(s[:cur]+'^'+s[cur:])
``` | output | 1 | 38,518 | 6 | 77,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^
Submitted Solution:
```
n = int(input())
for _ in range(n):
tx = list(input())
m = int(input())
cursorpoint = 0
for i in range(m):
qur = input().split()
if qur[0] == "forward":
if qur[1] == "char":
cursorpoint = min(len(tx), cursorpoint+1)
else:
flag = cursorpoint == 0
while cursorpoint < len(tx):
if tx[cursorpoint] == " ":
if flag:
break
else:
cursorpoint += 1
else:
cursorpoint += 1
flag = True
if qur[0] == "backward":
if qur[1] == "char":
cursorpoint = max(0,cursorpoint-1)
else:
flag = False
while cursorpoint > 0:
if tx[cursorpoint-1] == " ":
cursorpoint -= 1
flag = True
elif flag:
break
else:
cursorpoint -= 1
if qur[0] == "insert":
txtt = list("".join(qur[1:]))
txtt.remove("\"")
txtt.remove("\"")
if cursorpoint <len(tx):
tx = tx[:cursorpoint] + txtt + tx[cursorpoint:]
else:
tx = tx[:cursorpoint] + txtt
cursorpoint += len(txtt)
if qur[0] == "delete":
if qur[1] == "char":
if cursorpoint < len(tx):
tx.pop(cursorpoint)
else:
memo = cursorpoint
flag = cursorpoint == len(tx)
dodelete = True
while cursorpoint < len(tx):
if tx[cursorpoint] == " ":
if flag:
break
else:
cursorpoint += 1
else:
cursorpoint += 1
flag = True
else:
dodelete = False
if dodelete:
tx = tx[:memo]+tx[cursorpoint:]
cursorpoint = memo
print("".join(tx[:cursorpoint])+"^"+"".join(tx[cursorpoint:]))
``` | instruction | 0 | 38,519 | 6 | 77,038 |
No | output | 1 | 38,519 | 6 | 77,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A text editor is a useful software tool that can help people in various situations including writing and programming. Your job in this problem is to construct an offline text editor, i.e., to write a program that first reads a given text and a sequence of editing commands and finally reports the text obtained by performing successively the commands in the given sequence.
The editor has a text buffer and a cursor. The target text is stored in the text buffer and most editing commands are performed around the cursor. The cursor has its position that is either the beginning of the text, the end of the text, or between two consecutive characters in the text. The initial cursor position (i.e., the cursor position just after reading the initial text) is the beginning of the text.
A text manipulated by the editor is a single line consisting of a sequence of characters, each of which must be one of the following: 'a' through 'z', 'A' through 'Z', '0' through '9', '.' (period), ',' (comma), and ' ' (blank). You can assume that any other characters never occur in the text buffer. You can also assume that the target text consists of at most 1,000 characters at any time. The definition of words in this problem is a little strange: a word is a non-empty character sequence delimited by not only blank characters but also the cursor. For instance, in the following text with a cursor represented as '^',
He^llo, World.
the words are the following.
He
llo,
World.
Notice that punctuation characters may appear in words as shown in this example.
The editor accepts the following set of commands. In the command list, "any-text" represents any text surrounded by a pair of double quotation marks such as "abc" and "Co., Ltd.".
Command |
Descriptions
---|---
forward char |
Move the cursor by one character to the right, unless the cursor is already at the end of the text.
forward word |
Move the cursor to the end of the leftmost word in the right. If no words occur in the right, move it to the end of the text.
backward char |
Move the cursor by one character to the left, unless the cursor is already at the beginning of the text.
backward word |
Move the cursor to the beginning of the rightmost word in the left. If no words occur in the left, move it to the beginning of the text.
insert "any-text" |
Insert any-text (excluding double quotation marks) at the position specified by the cursor. After performing this command, the new cursor position is at the end of the inserted text. The length of any-text is less than or equal to 100.
delete char |
Delete the character that is right next to the cursor, if it exists.
delete word |
Delete the leftmost word in the right of the cursor. If one or more blank characters occur between the cursor and the word before performing this command, delete these blanks, too. If no words occur in the right, delete no characters in the text buffer.
Input
The first input line contains a positive integer, which represents the number of texts the editor will edit. For each text, the input contains the following descriptions:
* The first line is an initial text whose length is at most 100.
* The second line contains an integer M representing the number of editing commands.
* Each of the third through the M+2nd lines contains an editing command.
You can assume that every input line is in a proper format or has no syntax errors. You can also assume that every input line has no leading or trailing spaces and that just a single blank character occurs between a command name (e.g., forward) and its argument (e.g., char).
Output
For each input text, print the final text with a character '^' representing the cursor position. Each output line shall contain exactly a single text with a character '^'.
Examples
Input
Output
Input
3
A sample input
9
forward word
delete char
forward word
delete char
forward word
delete char
backward word
backward word
forward word
Hallow, Word.
7
forward char
delete word
insert "ello, "
forward word
backward char
backward char
insert "l"
3
forward word
backward word
delete word
Output
Asampleinput^
Hello, Worl^d.
^
Submitted Solution:
```
class TextEditor:
cur_w = 0
cur_c = 0
def __init__(self, txt):
self.words = txt.split(' ')
self.queries = {
'forward char': self.forward_char,
'forward word': self.forward_word,
'backward char': self.backward_char,
'backward word': self.backward_word,
'delete char': self.delete_char,
'delete word': self.delete_word
}
def query(self, q):
if q[0] == 'i':
txt = q.split(maxsplit=1)[1][1:-1]
self.insert(txt)
else:
self.queries[q]()
def forward_word(self):
cw = self.words[self.cur_w]
if self.cur_c < len(cw):
self.cur_c = len(cw)
elif self.cur_w < len(self.words) - 1:
self.cur_w += 1
self.cur_c = len(self.words[self.cur_w])
else:
pass
def forward_char(self):
if self.cur_c < len(self.words[self.cur_w]):
self.cur_c += 1
elif self.cur_w < len(self.words) - 1:
self.cur_w += 1
self.cur_c = 0
else:
pass
def backward_char(self):
if self.cur_c > 0:
self.cur_c -= 1
elif self.cur_w > 0:
self.cur_w -= 1
self.cur_c = len(self.words[self.cur_w])
else:
pass
def backward_word(self):
if self.cur_w > 0:
self.cur_w -= 1
self.cur_c = len(self.words[self.cur_w])
else:
self.cur_c = 0
def insert(self, txt):
st = txt.split(' ')
new_words = self.words[:self.cur_w]
if len(st) > 1:
cw = self.words[self.cur_w]
new_words.append(cw[:self.cur_c] + st[0])
new_words.extend(st[1:-1])
new_words.append(st[-1] + cw[self.cur_c:])
else:
cw = self.words[self.cur_w]
new_words.append(cw[:self.cur_c] + st[0] + cw[self.cur_c:])
new_words.extend(self.words[self.cur_w + 1:])
self.cur_w = self.cur_w + len(st) - 1
self.cur_c = self.cur_c + len(st[-1])
self.words = new_words
def delete_char(self):
cw = self.words[self.cur_w]
if len(cw) == 0:
self.words.pop(self.cur_w)
elif self.cur_c < len(cw):
self.words[self.cur_w] = cw[:self.cur_c] + cw[self.cur_c + 1:]
elif self.cur_w < len(self.words) - 1:
nw = self.words.pop(self.cur_w + 1)
self.words[self.cur_w] = cw + nw
else:
pass
def delete_word(self):
while not len(self.words[self.cur_w]) and len(self.words) > 1:
self.words.pop(self.cur_w)
self.cur_c = 0
self.words[self.cur_w] = self.words[self.cur_w][:self.cur_c]
def output(self):
words = self.words.copy()
words[self.cur_w] = self.words[self.cur_w][:self.cur_c] + '^' + \
self.words[self.cur_w][self.cur_c:]
print(*words)
n = int(input())
for _ in range(n):
te = TextEditor(input().strip())
q = int(input())
for _ in range(q):
te.query(input().strip())
te.output()
``` | instruction | 0 | 38,520 | 6 | 77,040 |
No | output | 1 | 38,520 | 6 | 77,041 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,042 | 6 | 78,084 |
Tags: constructive algorithms, implementation
Correct Solution:
```
set=list(''.join(list(input().split(','))))[1:-1]
present={}
for i in range(97,123):
present[chr(i)]=0
for letter in set:
present[letter]=1
distinct=0
for i in range(97,123):
if(present[chr(i)]):
distinct+=1
print(distinct)
``` | output | 1 | 39,042 | 6 | 78,085 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,043 | 6 | 78,086 |
Tags: constructive algorithms, implementation
Correct Solution:
```
s = input()
s = s[1:len(s)-1]
if s != "":
s = s.split(",")
for i in range(1, len(s)):
s[i] = s[i][1]
print(len(set(s)))
else:
print("0")
``` | output | 1 | 39,043 | 6 | 78,087 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,044 | 6 | 78,088 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a=input()
if a=="{}":
print(0)
else:
print(len(set(a[1:-1].split(", "))))
``` | output | 1 | 39,044 | 6 | 78,089 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,045 | 6 | 78,090 |
Tags: constructive algorithms, implementation
Correct Solution:
```
br=input()
brs=set(br.strip('{}').split(', '))
if brs=={''}:
print(0)
else:
print(len(brs))
``` | output | 1 | 39,045 | 6 | 78,091 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,046 | 6 | 78,092 |
Tags: constructive algorithms, implementation
Correct Solution:
```
if __name__ == '__main__':
setString = input()
if len(setString) > 2: setString = set(setString[1:-1].split(', '))
else: setString = []
print(len(setString))
``` | output | 1 | 39,046 | 6 | 78,093 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,047 | 6 | 78,094 |
Tags: constructive algorithms, implementation
Correct Solution:
```
lst=input()
lst=lst.strip('{')
lst=lst.strip('}')
lst=lst.split(', ')
n=len(lst)
text={}
for l in lst:
if l!='':
text[l]=text.get(l,0)+1
num=len(text)
print(num)
``` | output | 1 | 39,047 | 6 | 78,095 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,048 | 6 | 78,096 |
Tags: constructive algorithms, implementation
Correct Solution:
```
a=input()
import re
c=re.findall(r'[a-z]',a)
d=set(c)
print(len(d))
``` | output | 1 | 39,048 | 6 | 78,097 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0 | instruction | 0 | 39,049 | 6 | 78,098 |
Tags: constructive algorithms, implementation
Correct Solution:
```
s = input()
if len(s) == 2:
print(0)
else:
myset = set(s[1:-1].split(', '))
print(len(myset))
``` | output | 1 | 39,049 | 6 | 78,099 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,058 | 6 | 78,116 |
Tags: implementation
Correct Solution:
```
n = int(input())
l = ''.join(input().split())
l = l.strip('0')
divs = 0
for a, b in zip(l[:-1], l[1:]):
if a == '1' and b == '0':
divs += 1
if l.count('1') == 0:
print(0)
elif l.count('0') == 0:
print(len(l))
else:
print(l.count('1') + divs)
``` | output | 1 | 39,058 | 6 | 78,117 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,059 | 6 | 78,118 |
Tags: implementation
Correct Solution:
```
input()
a = input()
if a.count('1') == 0:
print(0)
exit()
while '0 0' in a:
a = a.replace('0 0', '0')
a = a.split()
print(len(a[a.index('1'): len(a) - list(reversed(a)).index('1')]))
``` | output | 1 | 39,059 | 6 | 78,119 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,060 | 6 | 78,120 |
Tags: implementation
Correct Solution:
```
input()
lis = list(map(int,input().split()))
for i in range(1,len(lis)):
if lis[len(lis) - 1] == 0:
lis.pop()
count = 0
i = 0
while i <len(lis):
if lis[i] == 1:
count += 1
if i + 1 == len(lis):
break
else:
if lis[i+1] == 0:
count += 1
i += 1
i += 1
print(count)
``` | output | 1 | 39,060 | 6 | 78,121 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,061 | 6 | 78,122 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = input()
beg = a.find('1')
ending = a.rfind('1')
sub = a[beg:ending + 1]
if not sub:
print(0)
else:
s = [i for i in sub.split('0') if not i.isspace()]
t = len(s)
p = 0
for i in s:
for j in i:
if j == '1':
p += 1
print(p + t - 1)
``` | output | 1 | 39,061 | 6 | 78,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,062 | 6 | 78,124 |
Tags: implementation
Correct Solution:
```
n = int(input())
m = [int(x) for x in input().split(' ')]
ans = sum(m)
m = m[::-1]
if(ans > 0):
m = m[m.index(1):]
m = m[::-1]
for i in range(len(m)):
if(i == 0):
curr = m[i]
past = m[i]
else:
curr = m[i]
if(past == 1 and curr == 0):
ans += 1
past = m[i]
print(ans)
``` | output | 1 | 39,062 | 6 | 78,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,063 | 6 | 78,126 |
Tags: implementation
Correct Solution:
```
ncartas = int(input())#nΓΊmero total de cartas
geral = ''.join(input().split(' ')) #descrição atual dos emails
anterior = -1
necessarias = 0
for carta in range(0,ncartas): #lançou o loop
if(geral[carta] == '1'): #se o elemento da string Γ© igual a 1
if (carta-anterior<=2 and anterior!=-1):
necessarias+=carta-anterior
elif (anterior==-1):
necessarias += 1
else:
necessarias += 2
anterior = carta
print(necessarias)
``` | output | 1 | 39,063 | 6 | 78,127 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,064 | 6 | 78,128 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = input().split()
print(max(0, sum(1 + (i + 1 == n or a[i + 1] == '0') for i in range(n) if a[i] == '1') - 1))
``` | output | 1 | 39,064 | 6 | 78,129 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | instruction | 0 | 39,065 | 6 | 78,130 |
Tags: implementation
Correct Solution:
```
input()
print(len('a'.join(input().replace(' ', '').replace('0', ' ').split())))
# Made By Mostafa_Khaled
``` | output | 1 | 39,065 | 6 | 78,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n = int(input())
a = list(map(int,input().split(" ")))
res = 0
i = 0
while i < len(a):
if a[i] == 1:
res += 1
while i < len(a) and a[i] == 1:
i += 1
res += 1
i += 1
print(max(0,res-1))
``` | instruction | 0 | 39,066 | 6 | 78,132 |
Yes | output | 1 | 39,066 | 6 | 78,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n=int(input())
l=input().split()
s,i=0,0
while(i<n):
if(l[i]=='1'):
while(i<n and l[i]=='1'):
i+=1
s+=1
s+=1
i+=1
if(s==0):
print(0)
else:
print(s-1)
``` | instruction | 0 | 39,067 | 6 | 78,134 |
Yes | output | 1 | 39,067 | 6 | 78,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n = int(input())
x = list(map(int,input().split()))
otv = 0
for i in range(n):
if x[i] == 1:
otv += 1
if i < n-1 and x[i+1] != 1:
otv += 1
if x[i] != 1:
print(max(otv-1,0))
else:
print(otv)
``` | instruction | 0 | 39,068 | 6 | 78,136 |
Yes | output | 1 | 39,068 | 6 | 78,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n = int(input())
letters = input()
letters = letters.split(' ')
#print(letters)
cont = 0
lei_zero = 0
lei_uno = False
for x in letters:
if x == '1':
if lei_zero >= 1:
cont+=1
cont+=1
lei_zero=0
lei_uno = True
elif lei_uno:
lei_zero+=1
print(cont)
``` | instruction | 0 | 39,069 | 6 | 78,138 |
Yes | output | 1 | 39,069 | 6 | 78,139 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
res,ans,temp=0,0,0
for i in a:
if i==1:
ans+=1
temp=1
elif i==0 and temp==1:
ans+=1
temp=0
if temp==0:
print(ans-1)
else:
print(ans)
``` | instruction | 0 | 39,070 | 6 | 78,140 |
No | output | 1 | 39,070 | 6 | 78,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
t = int(input())
entrada = input().split()
for i in range(t):
entrada[i] = int(entrada[i])
total = 0
k = 0
while(k < t):
if(entrada[k] == 1):
total += 1
else:
k+= 1
continue
if(k + 1 == t): break
# 1 0 0 0 0 1 1
if(entrada[k+1] == 1):
k += 1
elif(k + 2 == t):
k += 2
else:
k += 2
total += 1
print(total)
``` | instruction | 0 | 39,071 | 6 | 78,142 |
No | output | 1 | 39,071 | 6 | 78,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n=int(input())
l=[int(i) for i in input().split()]
if sum(l)==n:
print(n)
elif sum(l)==0:
print(0)
else:
ashok=0
c=0
karma=0
ans=l.count(1)
for i in range(n):
if l[i]==0:
#print('hi')
ashok+=100
else:
if karma==0:
karma=1
else:
ans+=1
print(ans)
``` | instruction | 0 | 39,072 | 6 | 78,144 |
No | output | 1 | 39,072 | 6 | 78,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
* Move from the list of letters to the content of any single letter.
* Return to the list of letters from single letter viewing mode.
* In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input
The first line contains a single integer n (1 β€ n β€ 1000) β the number of letters in the mailbox.
The second line contains n space-separated integers (zeros and ones) β the state of the letter list. The i-th number equals either 1, if the i-th number is unread, or 0, if the i-th letter is read.
Output
Print a single number β the minimum number of operations needed to make all the letters read.
Examples
Input
5
0 1 0 1 0
Output
3
Input
5
1 1 0 0 1
Output
4
Input
2
0 0
Output
0
Note
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read.
Submitted Solution:
```
n = int(input())
m = [int(x) for x in input().split(' ')]
ans = sum(m)
for i in range(n-1):
if(i == 0):
curr = m[i]
past = m[i]
else:
curr = m[i]
if(curr == 0 and past == 1):
ans += 1
past = m[i]
print(ans)
``` | instruction | 0 | 39,073 | 6 | 78,146 |
No | output | 1 | 39,073 | 6 | 78,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,090 | 6 | 78,180 |
Tags: brute force, implementation
Correct Solution:
```
s = input()
flag = False
s = s.strip()
if(len(s) >= 10):
if( s[-10:] == "CODEFORCES"):
flag = True
elif (s[0:1] == "C" ) and (s[-9:] == "ODEFORCES"):
flag = True
elif (s[0:2] == "CO") and (s[-8:] == "DEFORCES"):
flag = True
elif (s[0:3] == "COD") and (s[-7:] == "EFORCES"):
flag = True
elif (s[0:4] == "CODE") and (s[-6:] == "FORCES"):
flag = True
elif (s[0:5] == "CODEF") and (s[-5:] == "ORCES"):
flag = True
elif (s[0:6] == "CODEFO") and (s[-4:] == "RCES"):
flag = True
elif (s[0:7] == "CODEFOR") and (s[-3:] == "CES"):
flag = True
elif (s[0:8] == "CODEFORC") and (s[-2:] == "ES"):
flag = True
elif (s[0:9] == "CODEFORCE") and (s[-1:] == "S"):
flag = True
elif (s[0:10] == "CODEFORCES"):
flag = True
if(flag == True):
print("YES")
else:
print("NO")
``` | output | 1 | 39,090 | 6 | 78,181 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,091 | 6 | 78,182 |
Tags: brute force, implementation
Correct Solution:
```
t = 'CODEFORCES'
s = input()
for i in range(len(s)):
for j in range(i, len(s) + 1):
if ''.join((s[:i], s[j:])) == t:
print('YES')
exit()
print('NO')
``` | output | 1 | 39,091 | 6 | 78,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,092 | 6 | 78,184 |
Tags: brute force, implementation
Correct Solution:
```
#!/usr/bin/python3
#Cutting Banner Round #300
#CodeForces
def solve():
string = input()
word = "CODEFORCES"
found = False
for i in range(len(string)):
for j in range(len(string)):
str1 = string[:i]+string[i+j:]
#print(str1)
if str1 == word:
found = True
break
if found:
break
if found:
print("YES")
else:
print("NO")
'''
if string.find(word) != -1 :
print("YES")
else:
isfound = False
for i in range(len(string)):
prefix = string.find(word[:i])
suffix = string.find(word[i:])
if prefix == 0 and suffix == len(string)-len(word[i:]) :
isfound = True
break
if isfound :
print("YES")
else:
print("NO")
'''
def main():
solve()
if __name__ == "__main__":
main()
``` | output | 1 | 39,092 | 6 | 78,185 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,093 | 6 | 78,186 |
Tags: brute force, implementation
Correct Solution:
```
s=input()
s1=len(s)
l=['C','O','D','E','F','O','R','C','E','S']
i=0
j=0
m=0
k=1
if(s[0]!=l[0]):
while(k<=10):
if(s[-k]==l[-k]):
m+=1
else:
print("NO")
break
k+=1
if(m==10):
print("YES")
else:
while(i<s1):
if(s[i]==l[j] and s1>=10):
m+=1
j+=1
if(m==10):
print("YES")
break
else:
while(1):
if(s[-k]==l[-k]):
k+=1
m+=1
else:
print("NO")
break
if(m==10):
print("YES")
break
break
i+=1
``` | output | 1 | 39,093 | 6 | 78,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,094 | 6 | 78,188 |
Tags: brute force, implementation
Correct Solution:
```
s = input()
s1 = "CODEFORCES"
for i in range(len(s1)):
num1 = s.find(s1[:i+1])
num2 = s.find(s1[i+1:])
#print()
#print(s1[:i+1]+' '+s1[i+1:])
#print(num1)
if num1 < num2:
#print(str(num1)+' '+s1[-(len(s1)-i)+1:]+' '+s[-(len(s1)-i)+1:]+' '+str(i))
if (num1 == 0) and (s1[-(len(s1)-i)+1:] == s[-(len(s1)-i)+1:]):
#print(1)
print("YES")
exit()
#else:
if s1 == s[:len(s1)] :
#print(2)
print("YES")
exit()
elif s1 == s[-len(s1):]:
#print(3)
print("YES")
exit()
print("NO")
``` | output | 1 | 39,094 | 6 | 78,189 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,095 | 6 | 78,190 |
Tags: brute force, implementation
Correct Solution:
```
s = input()
t = 'CODEFORCES'
for i in range(len(s)):
if (s[0:i] == t):
print('YES')
exit()
for j in range(i + 1, len(s)):
if (s[0:i] + s[j:len(s)] == t or s[j:len(s)] == t):
print('YES')
exit()
print('NO')
``` | output | 1 | 39,095 | 6 | 78,191 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,096 | 6 | 78,192 |
Tags: brute force, implementation
Correct Solution:
```
s = input()
s2 = "CODEFORCES"
while s and s2 and s[0] == s2[0]:
s = s[1:]
s2 = s2[1:]
while s and s2 and s[-1] == s2[-1]:
s = s[:-1]
s2 = s2[:-1]
if s2 == '':
print("YES")
else:
print("NO")
``` | output | 1 | 39,096 | 6 | 78,193 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of CodeforcesΟ that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO | instruction | 0 | 39,097 | 6 | 78,194 |
Tags: brute force, implementation
Correct Solution:
```
x = input()
check = 0
p = len(x)
if x[:10] == 'CODEFORCES' or x[p - 9:] == 'CODEFORCES' :
print('YES')
check = 1
for i in range(len(x)):
for j in range(i , len(x)):
#print(str(i) + " " + str(j))
p1 = x[:i]
p2 = x[j:]
word = p1 + p2
#print(word)
if word == 'CODEFORCES':
if check == 0:
print("YES")
check = 1
if check == 0:
print("NO")
``` | output | 1 | 39,097 | 6 | 78,195 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,196 | 6 | 78,392 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
st = input()
if n % 4 != 0:
print('===')
else:
ca, cb, cc, cd = 0, 0, 0, 0
av = n // 4
for i in range(len(st)):
if st[i] == 'A':
ca += 1
elif st[i] == 'C':
cb += 1
elif st[i] == 'G':
cc += 1
elif st[i] == 'T':
cd += 1
if ca > av or cb > av or cc > av or cd > av:
print('===')
else:
aa, ab, ac, ad = av - ca, av - cb, av - cc, av -cd
ss = aa * 'A' + ab * 'C' + ac * 'G' + ad * 'T'
cnt = 0
for i in range(len(st)):
if st[i] == '?':
print(ss[cnt], end='')
cnt += 1
else:
print(st[i], end='')
``` | output | 1 | 39,196 | 6 | 78,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,197 | 6 | 78,394 |
Tags: implementation, strings
Correct Solution:
```
import math
n=int(input())
s=list(input())
ar=[0]*1000
for ch in s:
if ch!='?':
ar[ord(ch)]+=1
if n%4==0:
val=n//4
for i in range(n):
if s[i]=='?' and val>ar[ord('A')]:
s[i]='A'
ar[ord('A')]+=1
for i in range(n):
if s[i]=='?' and val>ar[ord('G')]:
s[i]='G'
ar[ord('G')]+=1
for i in range(n):
if s[i]=='?' and val>ar[ord('C')]:
s[i]='C'
ar[ord('C')]+=1
for i in range(n):
if s[i]=='?' and val>ar[ord('T')]:
s[i]='T'
ar[ord('T')]+=1
if n%4==0 and ar[ord('A')]==ar[ord('G')] and ar[ord('G')]==ar[ord('C')] and ar[ord('C')]==ar[ord('T')]:
for ch in s:
print(ch,end="")
else:
print("===")
``` | output | 1 | 39,197 | 6 | 78,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,198 | 6 | 78,396 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
s=input()
arr=[]
for i in range(0,len(s)):
arr.append(s[i])
a=0
g=0
c=0
t=0
q=0
index=[]
for i in range(0,len(s)):
if(s[i]=="A"):
a+=1
elif(s[i]=="G"):
g+=1
elif(s[i]=="C"):
c+=1
elif(s[i]=="T"):
t=t+1
else:
q+=1
index.append(i)
ans=0
maxi=max(a,g,c,t)
if(4*max(a,g,c,t)-a-g-c-t<=q):
#print(a,g,c,t,arr,index,q)
if((q-4*max(a,g,c,t)+a+g+c+t)%4==0 and (q-4*max(a,g,c,t)+a+g+c+t)>=0 ):
i=0
while(maxi-a>0):
arr[index[i]]="A"
i=i+1
a=a+1
while(maxi-g>0):
arr[index[i]]="G"
i=i+1
g=g+1
while(maxi-c>0):
arr[index[i]]="C"
i=i+1
c=c+1
while(maxi-t>0):
arr[index[i]]="T"
i=i+1
t=t+1
while(i<q):
arr[index[i]]="A"
i=i+1
arr[index[i]]="G"
i=i+1
arr[index[i]]="C"
i=i+1
arr[index[i]]="T"
i=i+1
for i in range(0,len(arr)):
print(arr[i],end="")
else:
print("===")
else:
print("===")
``` | output | 1 | 39,198 | 6 | 78,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,199 | 6 | 78,398 |
Tags: implementation, strings
Correct Solution:
```
f=int(input())
t=list(input())
if f%4!=0:
print('===')
else:
a=t.count('A')
y= t.count('T')
c= t.count('C')
g=t.count('G')
b=t.count('?')
v=f//4
if max(a,y,c,g)<=v:
for j in range(v-a):
t[t.index('?')]='A'
for j in range(v-y):
t[t.index('?')]='T'
for j in range(v-c):
t[t.index('?')]='C'
for j in range(v-g):
t[t.index('?')]='G'
print(''.join(t))
else:
print('===')
``` | output | 1 | 39,199 | 6 | 78,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,200 | 6 | 78,400 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
genomes = list(input())
if n % 4 != 0 or any([genomes.count(x) > n // 4 for x in 'ACGT']):
print('===')
else:
cnt = {}
for x in 'ACGT':
cnt[x] = n // 4 - genomes.count(x)
for i in range(n):
if genomes[i] == '?':
for x in 'ACGT':
if cnt[x] > 0:
genomes[i] = x
cnt[x] -= 1
break
print(''.join(genomes))
``` | output | 1 | 39,200 | 6 | 78,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,201 | 6 | 78,402 |
Tags: implementation, strings
Correct Solution:
```
n = int(input())
s = input()
def yolo():
if n % 4:
print("===")
return
A = s.count("A")
C = s.count("C")
T = s.count("T")
G = s.count("G")
if max(A,C,T,G) > n / 4:
print("===")
return
filled = ""
for i in s:
if i != "?":
filled += i
else:
if A < n / 4:
filled += "A"
A += 1
elif G < n / 4:
filled += "G"
G += 1
elif C < n / 4:
filled += "C"
C += 1
elif T < n / 4:
filled += "T"
T += 1
print(filled)
return
yolo()
``` | output | 1 | 39,201 | 6 | 78,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,202 | 6 | 78,404 |
Tags: implementation, strings
Correct Solution:
```
input()
s = input()
a = s.count('A')
c = s.count('C')
g = s.count('G')
t = s.count('T')
n = len(s)
if n%4!=0:
print('===')
exit()
n=int(n/4)
if a > n or c > n or g > n or t > n:
print('===')
exit()
s = s.replace('?','A',n - a)
s = s.replace('?', 'C',n - c)
s = s.replace('?', 'G',n - g)
s = s.replace('?', 'T',n - t)
print(s)
``` | output | 1 | 39,202 | 6 | 78,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain s. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, s is a string consisting of letters 'A', 'C', 'G', 'T' and characters '?'.
It is known that the number of nucleotides of each of the four types in the decoded genome of mammoth in Berland should be equal.
Your task is to decode the genome and replace each unrecognized nucleotide with one of the four types so that the number of nucleotides of each of the four types becomes equal.
Input
The first line contains the integer n (4 β€ n β€ 255) β the length of the genome.
The second line contains the string s of length n β the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'.
Output
If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes).
Examples
Input
8
AG?C??CT
Output
AGACGTCT
Input
4
AGCT
Output
AGCT
Input
6
????G?
Output
===
Input
4
AA??
Output
===
Note
In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is exactly once in it.
In the third and the fourth examples it is impossible to decode the genom. | instruction | 0 | 39,203 | 6 | 78,406 |
Tags: implementation, strings
Correct Solution:
```
n=int(input())
s=input()
if (n%4!=0):
print("===")
else:
t=n//4
a=t-s.count("A")
b=t-s.count("C")
c=t-s.count("G")
d=t-s.count("T")
if (a>=0 and b>=0 and c>=0 and d>=0):
e="A"*a+"C"*b+"G"*c+"T"*d
i=0
f=""
for c in s:
if(c=='?'):
f=f+e[i]
i=i+1
else:
f=f+c
print(f)
else:
print("===")
``` | output | 1 | 39,203 | 6 | 78,407 |
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