message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 450 109k | cluster float64 2 2 | __index_level_0__ int64 900 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
A few years ago, Hitagi encountered a giant crab, who stole the whole of her body weight. Ever since, she tried to avoid contact with others, for fear that this secret might be noticed.
To get rid of the oddity and recover her weight, a special integer sequence is needed. Hitagi's sequence has been broken for a long time, but now Kaiki provides an opportunity.
Hitagi's sequence a has a length of n. Lost elements in it are denoted by zeros. Kaiki provides another sequence b, whose length k equals the number of lost elements in a (i.e. the number of zeros). Hitagi is to replace each zero in a with an element from b so that each element in b should be used exactly once. Hitagi knows, however, that, apart from 0, no integer occurs in a and b more than once in total.
If the resulting sequence is not an increasing sequence, then it has the power to recover Hitagi from the oddity. You are to determine whether this is possible, or Kaiki's sequence is just another fake. In other words, you should detect whether it is possible to replace each zero in a with an integer from b so that each integer from b is used exactly once, and the resulting sequence is not increasing.
Input
The first line of input contains two space-separated positive integers n (2 ≤ n ≤ 100) and k (1 ≤ k ≤ n) — the lengths of sequence a and b respectively.
The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 200) — Hitagi's broken sequence with exactly k zero elements.
The third line contains k space-separated integers b1, b2, ..., bk (1 ≤ bi ≤ 200) — the elements to fill into Hitagi's sequence.
Input guarantees that apart from 0, no integer occurs in a and b more than once in total.
Output
Output "Yes" if it's possible to replace zeros in a with elements in b and make the resulting sequence not increasing, and "No" otherwise.
Examples
Input
4 2
11 0 0 14
5 4
Output
Yes
Input
6 1
2 3 0 8 9 10
5
Output
No
Input
4 1
8 94 0 4
89
Output
Yes
Input
7 7
0 0 0 0 0 0 0
1 2 3 4 5 6 7
Output
Yes
Note
In the first sample:
* Sequence a is 11, 0, 0, 14.
* Two of the elements are lost, and the candidates in b are 5 and 4.
* There are two possible resulting sequences: 11, 5, 4, 14 and 11, 4, 5, 14, both of which fulfill the requirements. Thus the answer is "Yes".
In the second sample, the only possible resulting sequence is 2, 3, 5, 8, 9, 10, which is an increasing sequence and therefore invalid. | instruction | 0 | 33,925 | 2 | 67,850 |
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
import sys
input = sys.stdin.readline
n,k = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
b = sorted(b,reverse = True)
j = 0
for i in range(0,n):
if(a[i]==0):
a[i] = b[j]
j+=1
ca = sorted(a)
if(ca == a):
print("No")
else:
print("Yes")
``` | output | 1 | 33,925 | 2 | 67,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,934 | 2 | 67,868 |
Tags: math
Correct Solution:
```
from sys import *
from bisect import *
from collections import *
from itertools import *
from fractions import *
from datetime import *
from math import *
Input = []
#stdin = open('in', 'r')
#stdout = open('out', 'w')
## for i, val in enumerate(array, start_i_value)
def Out(x):
stdout.write(str(x) + '\n')
def In():
return stdin.readline().strip()
def inputGrab():
for line in stdin:
Input.extend(map(str, line.strip().split()))
'''--------------------------------------------------------------------------------'''
def main():
n = input()
v = list(map(int, In().split()))
#print(v)
pst = -1e9 - 2
cnt = 0
ans = 0
for val in v:
if pst == val:
cnt += 1
else:
cnt = 1
ans += cnt
pst = val
print(ans)
if __name__ == '__main__':
main()
``` | output | 1 | 33,934 | 2 | 67,869 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,935 | 2 | 67,870 |
Tags: math
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
ans = 0
c = 1
temp = l[0]
for i in range(1, n):
if temp==l[i]:
c+=1
else:
ans+=((c*(c+1))//2)
c=1
temp=l[i]
print(ans+(c*(c+1))//2)
``` | output | 1 | 33,935 | 2 | 67,871 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,936 | 2 | 67,872 |
Tags: math
Correct Solution:
```
t = int(input())
a = list(map(int, input().split()))
#a.sort()
n = 1
res = 0
for i in range(t - 1):
if a[i + 1] == a[i]:
n += 1
else:
res += (n * (n + 1)) // 2
n = 1
res += (n * (n + 1)) // 2
print(res)
``` | output | 1 | 33,936 | 2 | 67,873 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,937 | 2 | 67,874 |
Tags: math
Correct Solution:
```
def nCr(n, r):
m = 1
for i in range(n, n - r, -1):
m *= i
return int(m // 2)
n, a, coin, ans = int(input()), list(map(int, input().split())), 1, 0
for i in range(n):
if i > 0 and a[i] == a[i - 1]:
coin += 1
else:
ans += nCr(coin, 2)
coin = 1
ans += 1
ans += nCr(coin, 2)
print(ans)
``` | output | 1 | 33,937 | 2 | 67,875 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,938 | 2 | 67,876 |
Tags: math
Correct Solution:
```
n, a = int(input()), list(map(int, input().split()))
consequtive, ans = 1, 0
for i in range(1, n):
if a[i] == a[i - 1]:
consequtive += 1
else:
ans += (consequtive * consequtive - consequtive) // 2 + consequtive
consequtive = 1
print(ans + ((consequtive * consequtive - consequtive) // 2 + consequtive))
``` | output | 1 | 33,938 | 2 | 67,877 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,939 | 2 | 67,878 |
Tags: math
Correct Solution:
```
import os
import sys
import math
import heapq
from decimal import *
from io import BytesIO, IOBase
from collections import defaultdict, deque
def r():
return int(input())
def rm():
return map(int,input().split())
def rl():
return list(map(int,input().split()))
n = r()
a = rl()
lo=0
hi=0
ans=0
while lo<n and hi<n:
if a[lo]!=a[hi]:
lo=hi
ans+=hi-lo+1
hi+=1
print(ans)
``` | output | 1 | 33,939 | 2 | 67,879 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,940 | 2 | 67,880 |
Tags: math
Correct Solution:
```
from sys import stdin, stdout
from math import factorial
n = int(stdin.readline())
values = list(map(int, stdin.readline().split()))
ans = 0
cnt = 1
for i in range(1, n):
if values[i] != values[i - 1]:
ans += cnt * (cnt + 1) // 2
cnt = 1
else:
cnt += 1
ans += cnt * (cnt + 1) // 2
stdout.write(str(ans))
``` | output | 1 | 33,940 | 2 | 67,881 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | instruction | 0 | 33,941 | 2 | 67,882 |
Tags: math
Correct Solution:
```
input()
c=0 #For tracking the current count of consecutive numbers
a=0 #For keeping track of previous number
ans=0
for i in input().split():
c=(a==i)*c+1
a=i
ans+=c
print(ans)
``` | output | 1 | 33,941 | 2 | 67,883 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
a=int(input())
k=list(map(int,input().split()))
ans=0
t=1
for i in range(1,a):
if k[i-1]==k[i]:
t+=1
else:
ans+=(t*(t+1))//2
t=1
ans+=(t*(t+1))//2
print(ans)
``` | instruction | 0 | 33,942 | 2 | 67,884 |
Yes | output | 1 | 33,942 | 2 | 67,885 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
ans=0
i=0
while i<n:
t=l[i]
c=0
while t==l[i]:
i=i+1
c=c+1
if i==n:
break
ans=ans+(c*(c+1))//2
print(ans)
``` | instruction | 0 | 33,943 | 2 | 67,886 |
Yes | output | 1 | 33,943 | 2 | 67,887 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
def single():
return input()
def multiple():
return list(map(int, input().split()))
ln=int(single())
a=multiple()
i=res=0
while i<ln:
start=i+1
while start<ln:
if a[start]==a[i]:
start+=1
else:
break
ns=(start-i)
res+=(ns*(ns+1))//2
if start==ln:
break
else:
i=start-1
i+=1
print(res)
``` | instruction | 0 | 33,944 | 2 | 67,888 |
Yes | output | 1 | 33,944 | 2 | 67,889 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
k = 1
s = 0
for i in range(1, n):
if a[i] == a[i - 1]:
k += 1
else:
s += (1 + k) * k // 2
k = 1
s += (1 + k) * k // 2
print(s)
``` | instruction | 0 | 33,945 | 2 | 67,890 |
Yes | output | 1 | 33,945 | 2 | 67,891 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
flag = 0
for i in range(1, n):
if(a[i] == a[i-1]):
j = i - 1
while(a[i] == a[j] and j > 0):
flag += 1
j -= 1
print(flag + n)
``` | instruction | 0 | 33,946 | 2 | 67,892 |
No | output | 1 | 33,946 | 2 | 67,893 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n = int(input())
a = []
d = {}
a = list(map(int, input().split()))
for i in a:
if i in d:
d[i]+=1
else:
d[i] = 1
sum = 0
for i in d:
sum+=((d[i])*(d[i]+1))//2
print(sum)
``` | instruction | 0 | 33,947 | 2 | 67,894 |
No | output | 1 | 33,947 | 2 | 67,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n=int(input())
a=[int(x) for x in input().split()]
i=0
c=1
ans=0
while i+1<n:
if a[i+1]==a[i]:
c+=1
if i+1==n-1:
ans+=(c*(c+1))/2
i+=1
else:
ans+=(c*(c+1))/2
if i+1==n-1:
ans+=1
c=1
i+=1
print(int(ans))
``` | instruction | 0 | 33,948 | 2 | 67,896 |
No | output | 1 | 33,948 | 2 | 67,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n=int(input())
lis=list(map(int,input().split()))
ans=1
count=1
for i in range(1,n):
if lis[i]==lis[i-1]:
count+=1
else:
ans+=count*(count+1)//2
# print(count)
count=1
print(ans)
``` | instruction | 0 | 33,949 | 2 | 67,898 |
No | output | 1 | 33,949 | 2 | 67,899 |
Provide a correct Python 3 solution for this coding contest problem.
Brave Ponta has finally arrived at the final dungeon. This is a dark wilderness in front of the fort of the evil emperor Boromos, with fairly strong monsters guarding their territories.
<image>
Figure 1: Wilderness
As shown in Fig. 1, the wilderness is represented by a 4 × 4 square region with the southwest as the origin (0, 0). Inside this area are monsters, as shown by the dots in the figure. Brave Ponta must cross this area from west to east (W to E). That is, you must start from the point where the x coordinate is 0.0 and the y coordinate is 0.0 or more and 4.0 or less, and move to the point where the x coordinate is 4.0 and the y coordinate is 0.0 or more and 4.0 or less.
When an enemy enters the area, the monster attacks the enemy if the distance between him and the enemy is shorter than the distance between any other monster and the enemy.
Now that there are not enough items, it was Ponta who really wanted to avoid fighting as much as possible before fighting Boromos. There, Ponta noticed: If you follow the path where there are always two or more monsters with the shortest distance to you, you won't be attacked by monsters.
Whether the brave Ponta can reach Boromos unscathed depends on your control. Create a program to find the shortest distance through the dark wilderness.
For reference, the shortest path in FIG. 1 is shown in FIG.
<image>
Figure 2: Shortest path
Input
Multiple datasets are given as input. Each dataset is given in the following format:
n (number of monsters: integer)
x1 y1 (Position of the first monster: Real number separated by blanks)
x2 y2 (Position of the second monster: Real number separated by blanks)
..
..
xn yn (position of nth monster: real number separated by blanks)
n is 1 or more and 20 or less. The x and y coordinate values that indicate the position of the monster are 0.0 or more and 4.0 or less.
When n is 0, it indicates the end of input.
Output
Output the shortest distance on one line for each dataset. If you can't cross the wilderness without being attacked by a monster, print "impossible".
The distance output may have an error of 0.00001 or less.
Example
Input
2
1 1
3 3
4
1.0 0.5
1.0 2.5
3.0 1.5
3.0 3.5
1
2.0 2.0
0
Output
5.656854249492
4.618033988750
impossible | instruction | 0 | 34,201 | 2 | 68,402 |
"Correct Solution:
```
# AOJ 1050 The Last Dungeon
# Python3 2018.7.7 bal4u
import math
import heapq
EPS = 1e-8
pp0 = [0j, 4+0j, 4+4j, 4j]
def EQ(a,b): return abs(a-b)<EPS
def PPeQ(a,b): return EQ(a.real, b.real) and EQ(a.imag, b.imag)
def dcmp(x):
if PPeQ(x, 0): return 0
return -1 if x <= 0 else 1
def cross(a, b): return a.real*b.imag - a.imag*b.real
def vabs(a): return math.hypot(a.real, a.imag)
# ２線分間の交点 (SEG a, PP bs, PP be)
def crossPointS2P(seg, bs, be):
a1 = cross(be-bs, seg[0]-bs)
a2 = cross(be-bs, seg[1]-bs)
return complex((seg[0].real*a2-seg[1].real*a1)/(a2-a1), (seg[0].imag*a2-seg[1].imag*a1)/(a2-a1))
# 垂直二等分線 (PP a, PP b)
def bisector(a, b):
ax, ay = (a.real + b.real)/2, (a.imag + b.imag)/2
if EQ(a.imag, b.imag): return [complex(ax, ay), complex(ax, ay+(b.real-a.real)*100)]
t = ax-(b.imag-a.imag)*100
return [complex(ax, ay), complex(t, (ax-t)*(b.real-a.real)/(b.imag-a.imag)+ay)]
# 凸包を直線で切断して左側を残す (SEG a, PP *p)
def convex_cut(seg, p):
ans, n = [], len(p)
for i in range(n):
d1 = dcmp(cross(seg[1]-seg[0], p[i]-seg[0]))
t = p[0] if i+1 == n else p[i+1]
d2 = dcmp(cross(seg[1]-seg[0], t-seg[0]))
if d1 >= 0: ans.append(p[i])
if d1*d2 < 0: ans.append(crossPointS2P(seg, p[i], t))
return ans
def pushBack(a, b):
if EQ(tbl[a].imag, 0) and EQ(tbl[b].imag, 0): return
if EQ(tbl[a].imag, 4) and EQ(tbl[b].imag, 4): return
if b in to[a]: return;
to[a].append(b)
def dijkstra(V, to, tbl):
visited = [0]*V
Q = []
for i in range(V):
if EQ(tbl[i].real, 0):
heapq.heappush(Q, (0, i, 0))
visited[i] = 1
while Q:
t, s, x = heapq.heappop(Q)
if EQ(x, 4): return t
for e in to[s]:
if visited[e]: continue
visited[e] = 1
heapq.heappush(Q, (t+vabs(tbl[s]-tbl[e]), e, tbl[e].real))
return -1
while True:
n = int(input())
if n == 0: break
p = []
for i in range(n):
x, y = map(float, input().split())
p.append(complex(x, y))
if n == 1:
print("impossible")
continue;
tbl, sz = [], 0
to = [[] for i in range(50)]
for i in range(n):
po = pp0[0:]
for j in range(n):
if j == i: continue
seg = bisector(p[i], p[j])
po = convex_cut(seg, po)
w = len(po)
if w <= 1: continue
if w == 2:
a, sz = sz, sz+1
tbl.append(po[0])
b, sz = sz, sz+1
tbl.append(po[1])
pushBack(a, b)
pushBack(b, a)
else: # k >= 3
j = sz # j as memo
sz += w
tbl.extend(po)
a, c = w-1, 1
for b in range(w):
pushBack(j+b, j+a)
pushBack(j+b, j+c)
a, c = a+1, c+1
if a == w: a = 0
if c == w: c = 0
for i in range(sz):
for j in range(i+1, sz):
if PPeQ(tbl[i], tbl[j]):
pushBack(i, j)
pushBack(j, i)
ans = dijkstra(sz, to, tbl)
print("impossible" if ans < 0 else ans)
``` | output | 1 | 34,201 | 2 | 68,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Melody Pond was stolen from her parents as a newborn baby by Madame Kovarian, to become a weapon of the Silence in their crusade against the Doctor. Madame Kovarian changed Melody's name to River Song, giving her a new identity that allowed her to kill the Eleventh Doctor.
Heidi figured out that Madame Kovarian uses a very complicated hashing function in order to change the names of the babies she steals. In order to prevent this from happening to future Doctors, Heidi decided to prepare herself by learning some basic hashing techniques.
The first hashing function she designed is as follows.
Given two positive integers (x, y) she defines H(x,y):=x^2+2xy+x+1.
Now, Heidi wonders if the function is reversible. That is, given a positive integer r, can you find a pair (x, y) (of positive integers) such that H(x, y) = r?
If multiple such pairs exist, output the one with smallest possible x. If there is no such pair, output "NO".
Input
The first and only line contains an integer r (1 ≤ r ≤ 10^{12}).
Output
Output integers x, y such that H(x,y) = r and x is smallest possible, or "NO" if no such pair exists.
Examples
Input
19
Output
1 8
Input
16
Output
NO | instruction | 0 | 34,334 | 2 | 68,668 |
Tags: brute force, math, number theory
Correct Solution:
```
# prottoyfuad
# python was named after the tv show :
# Monty Python's Flying Circus
# NOT THE REPTILE
n = int(input())
if n & 1 and n > 4:
print("1 " + str((n - 3) // 2))
else:
print("NO")
``` | output | 1 | 34,334 | 2 | 68,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Natalia was walking in the woods when she met a little mushroom gnome. The gnome told her the following story:
Everybody knows that the mushroom gnomes' power lies in the magic mushrooms that grow in the native woods of the gnomes. There are n trees and m magic mushrooms in the woods: the i-th tree grows at a point on a straight line with coordinates ai and has the height of hi, the j-th mushroom grows at the point with coordinates bj and has magical powers zj.
But one day wild mushroommunchers, the sworn enemies of mushroom gnomes unleashed a terrible storm on their home forest. As a result, some of the trees began to fall and crush the magic mushrooms. The supreme oracle of mushroom gnomes calculated in advance the probability for each tree that it will fall to the left, to the right or will stand on. If the tree with the coordinate x and height h falls to the left, then all the mushrooms that belong to the right-open interval [x - h, x), are destroyed. If a tree falls to the right, then the mushrooms that belong to the left-open interval (x, x + h] are destroyed. Only those mushrooms that are not hit by a single tree survive.
Knowing that all the trees fall independently of each other (i.e., all the events are mutually independent, and besides, the trees do not interfere with other trees falling in an arbitrary direction), the supreme oracle was also able to quickly calculate what would be the expectation of the total power of the mushrooms which survived after the storm. His calculations ultimately saved the mushroom gnomes from imminent death.
Natalia, as a good Olympiad programmer, got interested in this story, and she decided to come up with a way to quickly calculate the expectation of the sum of the surviving mushrooms' power.
Input
The first line contains two integers n and m (1 ≤ n ≤ 105, 1 ≤ m ≤ 104) — the number of trees and mushrooms, respectively.
Each of the next n lines contain four integers — ai, hi, li, ri (|ai| ≤ 109, 1 ≤ hi ≤ 109, 0 ≤ li, ri, li + ri ≤ 100) which represent the coordinate of the i-th tree, its height, the percentage of the probabilities that the tree falls to the left and to the right, respectively (the remaining percentage is the probability that the tree will stand on).
Each of next m lines contain two integers bj, zj (|bj| ≤ 109, 1 ≤ zj ≤ 103) which represent the coordinate and the magical power of the j-th mushroom, respectively.
An arbitrary number of trees and mushrooms can grow in one point.
Output
Print a real number — the expectation of the total magical power of the surviving mushrooms. The result is accepted with relative or absolute accuracy 10 - 4.
Examples
Input
1 1
2 2 50 50
1 1
Output
0.5000000000
Input
2 1
2 2 50 50
4 2 50 50
3 1
Output
0.2500000000
Note
It is believed that the mushroom with the coordinate x belongs to the right-open interval [l, r) if and only if l ≤ x < r. Similarly, the mushroom with the coordinate x belongs to the left-open interval (l, r] if and only if l < x ≤ r.
In the first test the mushroom survives with the probability of 50%, depending on where the single tree falls.
In the second test the mushroom survives only if neither of the two trees falls on it. It occurs with the probability of 50% × 50% = 25%.
Pretest №12 is the large test with 105 trees and one mushroom.
Submitted Solution:
```
import sys
def mushrooms():
pass
def mushroom_danger_check(a, b, h):
pass
def left_danger(a, b, h):
dbg and print(f"left a={a} < b={b} <= a+h={a+h}: {a < b <= a+h}")
return a < b <= a+h
def right_danger(a, b, h):
dbg and print(f"right a-h={a-h} <= b={b} < a={a}: {a-h <= b < a}")
return a-h <= b < a
dbg = False
def main():
# sys.stdin = open('test2.txt')
N, M = [int(i) for i in sys.stdin.readline().strip().split()]
# print(N, M)
max_height = 0
dict_trees = {}
# params_t = []
for _ in range(N):
a, h, l, r = [int(i) for i in sys.stdin.readline().strip().split()]
l, r = l/100, r/100
# params_t.append((a, h, l, r))
dict_trees[a] = (h, l, r)
if max_height < h:
max_height = h
params_m = []
for _ in range(M):
b, z = [int(i) for i in sys.stdin.readline().strip().split()]
params_m.append((b, z))
# mushroom_power = 0.0
# for b, z in params_m:
# dbg and print(f'mushroom {b} {z}')
# survival_prob = 1.0
# for a, h, l, r in params_t:
#
# if left_danger(a, b, h):
# dbg and print(f"survival_prob: {survival_prob}=>{survival_prob*(1-r)}")
# survival_prob *= 1 - r
# if right_danger(a, b, h):
# dbg and print(f"survival_prob: {survival_prob}=>{survival_prob*(1-l)}")
# survival_prob *= 1 - l
#
# mushroom_power += survival_prob * z
# dbg and print(mushroom_power)
# print(mushroom_power)
mushroom_power = 0.0
for b, z in params_m:
survival_prob = 1.0
for a in range(b-max_height,b+max_height, 1):
if a in dict_trees:
h, l, r = dict_trees[a]
if left_danger(a, b, h):
survival_prob *= 1 - r
if right_danger(a, b, h):
survival_prob *= 1 - l
mushroom_power += survival_prob * z
print(mushroom_power)
main()
``` | instruction | 0 | 34,457 | 2 | 68,914 |
No | output | 1 | 34,457 | 2 | 68,915 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Natalia was walking in the woods when she met a little mushroom gnome. The gnome told her the following story:
Everybody knows that the mushroom gnomes' power lies in the magic mushrooms that grow in the native woods of the gnomes. There are n trees and m magic mushrooms in the woods: the i-th tree grows at a point on a straight line with coordinates ai and has the height of hi, the j-th mushroom grows at the point with coordinates bj and has magical powers zj.
But one day wild mushroommunchers, the sworn enemies of mushroom gnomes unleashed a terrible storm on their home forest. As a result, some of the trees began to fall and crush the magic mushrooms. The supreme oracle of mushroom gnomes calculated in advance the probability for each tree that it will fall to the left, to the right or will stand on. If the tree with the coordinate x and height h falls to the left, then all the mushrooms that belong to the right-open interval [x - h, x), are destroyed. If a tree falls to the right, then the mushrooms that belong to the left-open interval (x, x + h] are destroyed. Only those mushrooms that are not hit by a single tree survive.
Knowing that all the trees fall independently of each other (i.e., all the events are mutually independent, and besides, the trees do not interfere with other trees falling in an arbitrary direction), the supreme oracle was also able to quickly calculate what would be the expectation of the total power of the mushrooms which survived after the storm. His calculations ultimately saved the mushroom gnomes from imminent death.
Natalia, as a good Olympiad programmer, got interested in this story, and she decided to come up with a way to quickly calculate the expectation of the sum of the surviving mushrooms' power.
Input
The first line contains two integers n and m (1 ≤ n ≤ 105, 1 ≤ m ≤ 104) — the number of trees and mushrooms, respectively.
Each of the next n lines contain four integers — ai, hi, li, ri (|ai| ≤ 109, 1 ≤ hi ≤ 109, 0 ≤ li, ri, li + ri ≤ 100) which represent the coordinate of the i-th tree, its height, the percentage of the probabilities that the tree falls to the left and to the right, respectively (the remaining percentage is the probability that the tree will stand on).
Each of next m lines contain two integers bj, zj (|bj| ≤ 109, 1 ≤ zj ≤ 103) which represent the coordinate and the magical power of the j-th mushroom, respectively.
An arbitrary number of trees and mushrooms can grow in one point.
Output
Print a real number — the expectation of the total magical power of the surviving mushrooms. The result is accepted with relative or absolute accuracy 10 - 4.
Examples
Input
1 1
2 2 50 50
1 1
Output
0.5000000000
Input
2 1
2 2 50 50
4 2 50 50
3 1
Output
0.2500000000
Note
It is believed that the mushroom with the coordinate x belongs to the right-open interval [l, r) if and only if l ≤ x < r. Similarly, the mushroom with the coordinate x belongs to the left-open interval (l, r] if and only if l < x ≤ r.
In the first test the mushroom survives with the probability of 50%, depending on where the single tree falls.
In the second test the mushroom survives only if neither of the two trees falls on it. It occurs with the probability of 50% × 50% = 25%.
Pretest №12 is the large test with 105 trees and one mushroom.
Submitted Solution:
```
import sys
def mushrooms():
pass
def mushroom_danger_check(a, b, h):
pass
def left_danger(a, b, h):
return a < b <= a+h
def right_danger(a, b, h):
return a-h <= b < a
def main():
# sys.stdin = open('test1.txt')
N, M = [int(i) for i in sys.stdin.readline().strip().split()]
# print(N, M)
params_t = []
for _ in range(N):
a, h, l, r = [int(i) for i in sys.stdin.readline().strip().split()]
l, r = l/100, r/100
params_t.append((a, h, l, r))
params_m = []
for _ in range(M):
b, z = [int(i) for i in sys.stdin.readline().strip().split()]
params_m.append((b, z))
survival_prob = 1.0
mushroom_power = 0.0
for b, z in params_m:
for a, h, l, r in params_t:
if left_danger(a, b, h):
survival_prob *= 1 - r
if right_danger(a, b, h):
survival_prob *= 1 - l
mushroom_power += survival_prob * z
print(mushroom_power)
main()
``` | instruction | 0 | 34,458 | 2 | 68,916 |
No | output | 1 | 34,458 | 2 | 68,917 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Natalia was walking in the woods when she met a little mushroom gnome. The gnome told her the following story:
Everybody knows that the mushroom gnomes' power lies in the magic mushrooms that grow in the native woods of the gnomes. There are n trees and m magic mushrooms in the woods: the i-th tree grows at a point on a straight line with coordinates ai and has the height of hi, the j-th mushroom grows at the point with coordinates bj and has magical powers zj.
But one day wild mushroommunchers, the sworn enemies of mushroom gnomes unleashed a terrible storm on their home forest. As a result, some of the trees began to fall and crush the magic mushrooms. The supreme oracle of mushroom gnomes calculated in advance the probability for each tree that it will fall to the left, to the right or will stand on. If the tree with the coordinate x and height h falls to the left, then all the mushrooms that belong to the right-open interval [x - h, x), are destroyed. If a tree falls to the right, then the mushrooms that belong to the left-open interval (x, x + h] are destroyed. Only those mushrooms that are not hit by a single tree survive.
Knowing that all the trees fall independently of each other (i.e., all the events are mutually independent, and besides, the trees do not interfere with other trees falling in an arbitrary direction), the supreme oracle was also able to quickly calculate what would be the expectation of the total power of the mushrooms which survived after the storm. His calculations ultimately saved the mushroom gnomes from imminent death.
Natalia, as a good Olympiad programmer, got interested in this story, and she decided to come up with a way to quickly calculate the expectation of the sum of the surviving mushrooms' power.
Input
The first line contains two integers n and m (1 ≤ n ≤ 105, 1 ≤ m ≤ 104) — the number of trees and mushrooms, respectively.
Each of the next n lines contain four integers — ai, hi, li, ri (|ai| ≤ 109, 1 ≤ hi ≤ 109, 0 ≤ li, ri, li + ri ≤ 100) which represent the coordinate of the i-th tree, its height, the percentage of the probabilities that the tree falls to the left and to the right, respectively (the remaining percentage is the probability that the tree will stand on).
Each of next m lines contain two integers bj, zj (|bj| ≤ 109, 1 ≤ zj ≤ 103) which represent the coordinate and the magical power of the j-th mushroom, respectively.
An arbitrary number of trees and mushrooms can grow in one point.
Output
Print a real number — the expectation of the total magical power of the surviving mushrooms. The result is accepted with relative or absolute accuracy 10 - 4.
Examples
Input
1 1
2 2 50 50
1 1
Output
0.5000000000
Input
2 1
2 2 50 50
4 2 50 50
3 1
Output
0.2500000000
Note
It is believed that the mushroom with the coordinate x belongs to the right-open interval [l, r) if and only if l ≤ x < r. Similarly, the mushroom with the coordinate x belongs to the left-open interval (l, r] if and only if l < x ≤ r.
In the first test the mushroom survives with the probability of 50%, depending on where the single tree falls.
In the second test the mushroom survives only if neither of the two trees falls on it. It occurs with the probability of 50% × 50% = 25%.
Pretest №12 is the large test with 105 trees and one mushroom.
Submitted Solution:
```
from array import array
from sys import stdin, stdout
def from_lines(l):
return [int(x) for x in l.split()]
lines = stdin.readlines()
n, m = from_lines(lines[0])
a = [from_lines(lines[i]) for i in range(1,n+1)]
b = [from_lines(lines[i]) for i in range(n+1,n+m+1)]
bv = [from_lines(lines[i])[1] for i in range(n+1,n+m+1)]
global_value = sum(bv)
defect_value = 0
bx = [from_lines(lines[i])[0] for i in range(n+1,n+m+1)]
ax = [x[0] for x in a]
axl = [x[0]-x[1] for x in a]
axr = [x[0]+x[1] for x in a]
#a_left = [[axl[i],ax[i]] for i in range(n)]
a_sorted = sorted(a)
a_dict = {}
for x in a:
if a_dict.get(x[0], 'no') == 'no':
a_dict[x[0]] = [x]
else:
a_dict[x[0]].append(x)
#a_dict = dict([[x[0],x] for x in a])
b_sorted = sorted(b)
b_dict = {}
for x in b:
if b_dict.get(x[0], 'no') == 'no':
b_dict[x[0]] = [x]
else:
b_dict[x[0]].append(x)
#b_dict = dict([[x[0],x] for x in b])
#Произвольное число деревьев и грибов могут расти в одной точке.(((
all_cords = sorted(set(bx+ax+axl+axr))
pos = dict(zip(all_cords, range(len(all_cords))))
maxX = len(pos)
N = maxX
t = array('f', [1 for x in range(maxX)])
#print(a,b,a_dict, b_dict)
zero_flag = 1
qum_prob = 1
zero_pos = -1
for i in range(len(all_cords)):
b_elem = b_dict.get(all_cords[i], 'no')
if b_elem != 'no':
for grib in b_elem:
if zero_flag == 2:
grib[1] = 0
else:
grib[1] *= qum_prob
t_elem = t[pos[all_cords[i]]]
qum_prob /= t_elem
if i > zero_pos:
zero_flag = 1
a_elem = a_dict.get(all_cords[i], 'no')
if a_elem != 'no':
for tree in a_elem:
t2 = pos[tree[0] + tree[1]]
prob = tree[3]
if prob != 0:
qum_prob *= float(prob/100)
t[t2] *= float(prob/100)
else:
zero_flag = 2
zero_pos = t2
#print(i, b_dict, zero_flag, zero_pos, qum_prob, t)
zero_flag = 1
qum_prob = 1
zero_pos = maxX + 1
t = array('f', [1 for x in range(maxX)])
for i in reversed(range(len(all_cords))):
b_elem = b_dict.get(all_cords[i], 'no')
if b_elem != 'no':
for grib in b_elem:
if zero_flag == 2:
grib[1] = 0
else:
grib[1] *= qum_prob
t_elem = t[pos[all_cords[i]]]
qum_prob /= t_elem
if i < zero_pos:
zero_flag = 1
a_elem = a_dict.get(all_cords[i], 'no')
if a_elem != 'no':
for tree in a_elem:
t2 = pos[tree[0] - tree[1]]
prob = tree[2]
if prob != 0:
qum_prob *= float(prob/100)
t[t2] *= float(prob/100)
else:
zero_flag = 2
zero_pos = t2
#print(i, b_dict, zero_flag, zero_pos, qum_prob, t)
survived = 0
for b_ind in bx:
for grib in b_dict[b_ind]:
#print(bx, grib, grib[1])
survived += grib[1]
print(float(survived/global_value))
``` | instruction | 0 | 34,459 | 2 | 68,918 |
No | output | 1 | 34,459 | 2 | 68,919 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,460 | 2 | 68,920 |
Tags: constructive algorithms, math
Correct Solution:
```
for i in range(int(input())):
n = int(input())
a = input().split()
print(*[str(-int(a[k+1])) if k%2 == 0 else a[k-1]
for k in range(len(a))])
``` | output | 1 | 34,460 | 2 | 68,921 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,461 | 2 | 68,922 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
for q in range(t):
n = int(input())
mass = [int(x) for x in input().split()]
answer = [0] * n
for i in range(n // 2):
answer[i] = -mass[n - i - 1]
answer[n - i - 1] = mass[i]
print(*answer)
``` | output | 1 | 34,461 | 2 | 68,923 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,462 | 2 | 68,924 |
Tags: constructive algorithms, math
Correct Solution:
```
for q in range(int(input())):
n = int(input())
a = [int(i) for i in input().split()]
for i in range(0, n, 2):
print(-a[i + 1], a[i], end=' ')
``` | output | 1 | 34,462 | 2 | 68,925 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,463 | 2 | 68,926 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
b = []
for i in range(t):
n = int(input())
for i in range(n):
a = [int(i) for i in input().split()]
b.append(a)
break
for k in range(len(b)):
for j in range(1, len(b[k]), 2):
print(b[k][j]*(-1), b[k][j-1], end=' ')
print()
``` | output | 1 | 34,463 | 2 | 68,927 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,464 | 2 | 68,928 |
Tags: constructive algorithms, math
Correct Solution:
```
a = int(input())
b = {}
c = None
d = None
o = None
for i in range(a):
c = int(input())
b[i] = [int(i) for i in input().split()]
for i in b.values():
for j, k in enumerate(i):
if j % 2 == 0:
continue
d = k * -1
o = i[j-1]
# d = i[j-1] // k if i[j-1]>k else 1
# o = k // i[j-1] if k>i[j-1] else 1
# d = d * -1
print(d, o, end=' ')
print()
``` | output | 1 | 34,464 | 2 | 68,929 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,465 | 2 | 68,930 |
Tags: constructive algorithms, math
Correct Solution:
```
a = int(input())
y = str()
for i in range(a):
input()
x = list(map(int, input().split()))
for ii in range(0, len(x), 2):
if x[ii + 1] < 0 or x[ii] < 0:
if x[ii + 1] < 0 and x[ii] < 0:
print(abs(x[ii + 1]), x[ii], end=' ')
else:
print(abs(x[ii + 1]), abs(x[ii]), end=' ')
else:
print(x[ii + 1], -x[ii], end=' ')
print()
``` | output | 1 | 34,465 | 2 | 68,931 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,466 | 2 | 68,932 |
Tags: constructive algorithms, math
Correct Solution:
```
from math import gcd
t = int(input())
ans = []
for i in range(t):
n = int(input())
arr = [int(i) for i in input().split()]
tmp = []
itog = []
for j in arr:
if len(tmp)<2:
tmp.append(j)
else:
f,s = map(int,tmp)
tmp = [j]
g = gcd(f,s)
nok = f*s//g
itog.append(-nok//f)
itog.append(nok//s)
if len(tmp)==2:
f,s = map(int,tmp)
tmp = [j]
g = gcd(f,s)
nok = f*s//g
itog.append(-nok//f)
itog.append(nok//s)
ans.append(itog)
for i in ans:
print(*i)
``` | output | 1 | 34,466 | 2 | 68,933 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0. | instruction | 0 | 34,467 | 2 | 68,934 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
a = []
for i in range(t):
n = int(input())
p = list(map(int, input().split()))
for j in range(1, n//2+1):
print(-p[-j], end = " ")
for j in range(n//2 + 1, n+1):
print(p[-j], end = " ")
print("")
``` | output | 1 | 34,467 | 2 | 68,935 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
t = int(input())
for i in range(t):
ot = []
n = int(input())
a = list(map(int, input().split()))
s = 0
if n % 2 == 0:
for j in range(n):
if j % 2 == 0:
ot.append(a[j + 1])
elif j % 2 != 0:
ot.append(a[j - 1] * (-1))
elif n % 2 != 0:
for j in range(n):
s += a[j]
ww = s // 2
for j in range(n):
if a[j] < ww:
if a[j] < 0:
ot.append(-1)
elif a[j] > 0:
ot.append(1)
elif a[j] == ww:
if a[j] < 0:
ot.append(1)
elif a[j] > 0:
ot.append(-1)
print(*ot)
``` | instruction | 0 | 34,468 | 2 | 68,936 |
Yes | output | 1 | 34,468 | 2 | 68,937 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
from math import gcd
lcm = lambda a, b: a//gcd(a, b)*b
t = int(input())
for _ in range(t):
n = int(input())
a = list(map(int, input().split()))
res = [0]*n
for i in range(n//2):
l = lcm(a[i], a[n-i-1])
res[i] = l//a[i]
res[n-i-1] = -l//a[n-i-1]
for el in res:
print(el, end = ' ')
print()
``` | instruction | 0 | 34,469 | 2 | 68,938 |
Yes | output | 1 | 34,469 | 2 | 68,939 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
#!/usr/bin/python3
rooms_num = int(input())
for _ in range(rooms_num):
number_of_seals = int(input())
list_of_seals_energies = list(map(int, input().split()))
print(*(f"{b} {-a}" for a, b in zip(list_of_seals_energies[::2], list_of_seals_energies[1::2])))
# lst = []
# for a, b in zip(list_of_seals_energies[::2], list_of_seals_energies[1::2]):
# lst.append(b)
# lst.append(-a)
#
# print(*lst)
# for a, b in zip(list_of_seals_energies[::2], list_of_seals_energies[1::2]):
# print(b, -a, end=' ')
# print()
``` | instruction | 0 | 34,470 | 2 | 68,940 |
Yes | output | 1 | 34,470 | 2 | 68,941 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
t=int(input())
output=[]
for i in range(t):
k=int(input())
a=input().split()
for i in range(int(len(a)/2)):
a[i]=int(a[i])
a[i]*=(-1)
a[i]=str(a[i])
a.reverse()
output.append(a)
for i in output:
print(' '.join(i))
``` | instruction | 0 | 34,471 | 2 | 68,942 |
Yes | output | 1 | 34,471 | 2 | 68,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
a = int(input())
y = str()
for i in range(a):
input()
x = list(map(int, input().split()))
for ii in range(0, len(x), 2):
if x[ii + 1] < 0 or x[ii] < 0:
if x[ii + 1] < 0 and x[ii] < 0:
print(abs(x[ii + 1]), x[ii], end=' ')
else:
print(x[ii + 1], x[ii], end=' ')
else:
print(x[ii + 1], -x[ii], end=' ')
print()
``` | instruction | 0 | 34,472 | 2 | 68,944 |
No | output | 1 | 34,472 | 2 | 68,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
n = int(input())
b = 1
while True:
c = 1
while c != 10:
a = str(c) * b
c += 1
if int(a) >= n:
break
else:
print(a)
b += 1
if int(a) >= n:
break
``` | instruction | 0 | 34,473 | 2 | 68,946 |
No | output | 1 | 34,473 | 2 | 68,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
t=int(input())
import math
for i in range(t):
n=int(input())
a=list(map(int,input().split()))
b=[0]*n
g=1
nok=1
for m in range(n):
g=g*a[m]
gdc=1
for j in range(0,n):
gdc=math.gcd(gdc,a[j])
gdc=gdc*a[j]//gdc
for k in range(0,n//2):
print(-1*gdc//a[k],end=' ')
for l in range(n//2,n):
print(gdc//a[l],end=' ')
print('')
``` | instruction | 0 | 34,474 | 2 | 68,948 |
No | output | 1 | 34,474 | 2 | 68,949 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Naruto has sneaked into the Orochimaru's lair and is now looking for Sasuke. There are T rooms there. Every room has a door into it, each door can be described by the number n of seals on it and their integer energies a_1, a_2, ..., a_n. All energies a_i are nonzero and do not exceed 100 by absolute value. Also, n is even.
In order to open a door, Naruto must find such n seals with integer energies b_1, b_2, ..., b_n that the following equality holds: a_{1} ⋅ b_{1} + a_{2} ⋅ b_{2} + ... + a_{n} ⋅ b_{n} = 0. All b_i must be nonzero as well as a_i are, and also must not exceed 100 by absolute value. Please find required seals for every room there.
Input
The first line contains the only integer T (1 ≤ T ≤ 1000) standing for the number of rooms in the Orochimaru's lair. The other lines contain descriptions of the doors.
Each description starts with the line containing the only even integer n (2 ≤ n ≤ 100) denoting the number of seals.
The following line contains the space separated sequence of nonzero integers a_1, a_2, ..., a_n (|a_{i}| ≤ 100, a_{i} ≠ 0) denoting the energies of seals.
Output
For each door print a space separated sequence of nonzero integers b_1, b_2, ..., b_n (|b_{i}| ≤ 100, b_{i} ≠ 0) denoting the seals that can open the door. If there are multiple valid answers, print any. It can be proven that at least one answer always exists.
Example
Input
2
2
1 100
4
1 2 3 6
Output
-100 1
1 1 1 -1
Note
For the first door Naruto can use energies [-100, 1]. The required equality does indeed hold: 1 ⋅ (-100) + 100 ⋅ 1 = 0.
For the second door Naruto can use, for example, energies [1, 1, 1, -1]. The required equality also holds: 1 ⋅ 1 + 2 ⋅ 1 + 3 ⋅ 1 + 6 ⋅ (-1) = 0.
Submitted Solution:
```
def main():
n = int(input())
q = list(map(int, input().split()))
for i in q[::-1]:
print(-i, end=" ")
print()
for i in range(int(input())):
main()
``` | instruction | 0 | 34,475 | 2 | 68,950 |
No | output | 1 | 34,475 | 2 | 68,951 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,913 | 2 | 69,826 |
"Correct Solution:
```
a,b,c,d=map(int,input().split())
if (c-1)//b<=(a-1)//d:
print("Yes")
else:
print("No")
``` | output | 1 | 34,913 | 2 | 69,827 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,914 | 2 | 69,828 |
"Correct Solution:
```
a,b,c,d = map(int,input().split())
if (a-1)//d+1 - ((c-1)//b+1) <0 :
print('No')
else:
print('Yes')
``` | output | 1 | 34,914 | 2 | 69,829 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,915 | 2 | 69,830 |
"Correct Solution:
```
a,b,c,d=map(int,input().split())
print("Yes" if -c//b>=-a//d else "No")
``` | output | 1 | 34,915 | 2 | 69,831 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,916 | 2 | 69,832 |
"Correct Solution:
```
import math
A,B,C,D=map(int,input().split())
print("Yes" if math.ceil(A/D) >= math.ceil(C/B) else "No")
``` | output | 1 | 34,916 | 2 | 69,833 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,917 | 2 | 69,834 |
"Correct Solution:
```
a,b,c,d=map(int,input().split())
taka=(c+b-1)//b
ao=(a+d-1)//d
print("Yes" if taka<=ao else "No")
``` | output | 1 | 34,917 | 2 | 69,835 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,918 | 2 | 69,836 |
"Correct Solution:
```
import math
a,b,c,d=map(int,input().split())
x,y=math.ceil(a/d),math.ceil(c/b)
print("Yes" if x>=y else "No")
``` | output | 1 | 34,918 | 2 | 69,837 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,919 | 2 | 69,838 |
"Correct Solution:
```
a, b, c, d = map(int, input().split())
print('No' if 0--c//b > 0--a//d else 'Yes')
``` | output | 1 | 34,919 | 2 | 69,839 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes | instruction | 0 | 34,920 | 2 | 69,840 |
"Correct Solution:
```
a,b,c,d=map(int,input().split())
ta=(c-1)//b+1
ao=(a-1)//d+1
print('Yes') if ta<=ao else print('No')
``` | output | 1 | 34,920 | 2 | 69,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes
Submitted Solution:
```
a,b,c,d=list(map(int,input().split()))
ad=-(-a//d)
cb=-(-c//b)
print('Yes' if ad>=cb else 'No')
``` | instruction | 0 | 34,921 | 2 | 69,842 |
Yes | output | 1 | 34,921 | 2 | 69,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes
Submitted Solution:
```
a,b,c,d = map(int, input().split())
while a > 0 and c > 0:
c-=b
a-=d
print('Yes' if c <= 0 else 'No')
``` | instruction | 0 | 34,922 | 2 | 69,844 |
Yes | output | 1 | 34,922 | 2 | 69,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes
Submitted Solution:
```
a, b, c, d = map(int, input().split())
if -(-c // b) <= -(-a // d):
print('Yes')
else:
print('No')
``` | instruction | 0 | 34,923 | 2 | 69,846 |
Yes | output | 1 | 34,923 | 2 | 69,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki will have a battle using their monsters.
The health and strength of Takahashi's monster are A and B, respectively, and those of Aoki's monster are C and D, respectively.
The two monsters will take turns attacking, in the order Takahashi's, Aoki's, Takahashi's, Aoki's, ... Here, an attack decreases the opponent's health by the value equal to the attacker's strength. The monsters keep attacking until the health of one monster becomes 0 or below. The person with the monster whose health becomes 0 or below loses, and the other person wins.
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Constraints
* 1 \leq A,B,C,D \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
If Takahashi will win, print `Yes`; if he will lose, print `No`.
Examples
Input
10 9 10 10
Output
No
Input
46 4 40 5
Output
Yes
Submitted Solution:
```
A,B,C,D = map(int, input().split())
x=-(-A//D)
y=-(-C//B)
if x>=y:
print('Yes')
else:
print('No')
``` | instruction | 0 | 34,924 | 2 | 69,848 |
Yes | output | 1 | 34,924 | 2 | 69,849 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.