message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"What are your shoe sizes?"
Suddenly, the doctor asked me when I met him for the first time.
"It's 23.5"
"Oh, that's a really nice number. It's 2 to the 4th power plus 2 to the 2nd power, 2 to the 1st power, 2 to the 0th power, and 2 to the 1st power."
Then the doctor asked.
"You, how tall are you?"
"Yes, it's 158.1."
He folded his arms and closed his eyes. After a while of silence, I opened my mouth.
"Nah ~"
After that, during the time I spent together, I gradually became able to understand the behavior of the doctor.
First, I say the real number at the request of the doctor. If the real number is represented by a binary number with no more than 8 digits for the integer part and no more than 4 digits for the decimal part, he is happy to say the result of the conversion to binary. If not, it will sadly yell "Nah ~". This repeats until I say a negative real number.
By the way, as he got older, it became more and more difficult to make long calculations. Therefore, please make a program for you to input real numbers and convert / output them to binary numbers on your behalf. However, if the binary representation does not fit within the limit number of digits (integer part within 8 digits + decimal part within 4 digits), output NA (half-width alphabetic characters). The input real number shall fit within 8 digits of the integer part and within 4 digits of the decimal part, and the binary representation to be output should be output with 8 digits of the integer part and 4 digits of the decimal part.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single negative real line. One real number n is given to one row for each dataset.
The number of datasets does not exceed 1200.
Output
Outputs the conversion result to binary number for each input data set.
Example
Input
23.5
158.1
-1.0
Output
00010111.1000
NA
Submitted Solution:
```
import sys
f = sys.stdin
while True:
n = float(f.readline())
if n < 0:
break
output = bin(int(n))[2:].zfill(8) + '.'
decimal = n - int(n)
for i in range(4):
decimal *= 2
if 1 <= decimal:
decimal -= 1
output += '1'
else:
output += '0'
if 1e-10 < decimal or 13 < len(output):
print('NA')
else:
print(output)
``` | instruction | 0 | 91,638 | 20 | 183,276 |
Yes | output | 1 | 91,638 | 20 | 183,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"What are your shoe sizes?"
Suddenly, the doctor asked me when I met him for the first time.
"It's 23.5"
"Oh, that's a really nice number. It's 2 to the 4th power plus 2 to the 2nd power, 2 to the 1st power, 2 to the 0th power, and 2 to the 1st power."
Then the doctor asked.
"You, how tall are you?"
"Yes, it's 158.1."
He folded his arms and closed his eyes. After a while of silence, I opened my mouth.
"Nah ~"
After that, during the time I spent together, I gradually became able to understand the behavior of the doctor.
First, I say the real number at the request of the doctor. If the real number is represented by a binary number with no more than 8 digits for the integer part and no more than 4 digits for the decimal part, he is happy to say the result of the conversion to binary. If not, it will sadly yell "Nah ~". This repeats until I say a negative real number.
By the way, as he got older, it became more and more difficult to make long calculations. Therefore, please make a program for you to input real numbers and convert / output them to binary numbers on your behalf. However, if the binary representation does not fit within the limit number of digits (integer part within 8 digits + decimal part within 4 digits), output NA (half-width alphabetic characters). The input real number shall fit within 8 digits of the integer part and within 4 digits of the decimal part, and the binary representation to be output should be output with 8 digits of the integer part and 4 digits of the decimal part.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single negative real line. One real number n is given to one row for each dataset.
The number of datasets does not exceed 1200.
Output
Outputs the conversion result to binary number for each input data set.
Example
Input
23.5
158.1
-1.0
Output
00010111.1000
NA
Submitted Solution:
```
while True:
d= float(input())
if d< 0: break
a, b= bin(int(d))[2:].zfill(8)+".", d-int(d)
while 1:
b*= 2
a= a+'1' if int(b)>= 1 else a+'0'
if str(b).split(".")==['1','0']: break
b-=int(b)
a= a.ljust(13, '0')
print("NA" if len(a)> 13 else a)
``` | instruction | 0 | 91,639 | 20 | 183,278 |
No | output | 1 | 91,639 | 20 | 183,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"What are your shoe sizes?"
Suddenly, the doctor asked me when I met him for the first time.
"It's 23.5"
"Oh, that's a really nice number. It's 2 to the 4th power plus 2 to the 2nd power, 2 to the 1st power, 2 to the 0th power, and 2 to the 1st power."
Then the doctor asked.
"You, how tall are you?"
"Yes, it's 158.1."
He folded his arms and closed his eyes. After a while of silence, I opened my mouth.
"Nah ~"
After that, during the time I spent together, I gradually became able to understand the behavior of the doctor.
First, I say the real number at the request of the doctor. If the real number is represented by a binary number with no more than 8 digits for the integer part and no more than 4 digits for the decimal part, he is happy to say the result of the conversion to binary. If not, it will sadly yell "Nah ~". This repeats until I say a negative real number.
By the way, as he got older, it became more and more difficult to make long calculations. Therefore, please make a program for you to input real numbers and convert / output them to binary numbers on your behalf. However, if the binary representation does not fit within the limit number of digits (integer part within 8 digits + decimal part within 4 digits), output NA (half-width alphabetic characters). The input real number shall fit within 8 digits of the integer part and within 4 digits of the decimal part, and the binary representation to be output should be output with 8 digits of the integer part and 4 digits of the decimal part.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single negative real line. One real number n is given to one row for each dataset.
The number of datasets does not exceed 1200.
Output
Outputs the conversion result to binary number for each input data set.
Example
Input
23.5
158.1
-1.0
Output
00010111.1000
NA
Submitted Solution:
```
def to_digit(f):
u = int(f)
d = f - u
us = ""
if u == 0:
us = "0"
cnt = 8
while u:
if cnt == 0:
return ("DAME", "DESU!!")
cnt -= 1
us += str(u % 2)
u //= 2
us += "0" * cnt
us = us[::-1]
ds = ""
acc = 0.5
cnt = 4
while d:
if cnt == 0:
return ("DAME", "DESU!!")
cnt -= 1
if acc >= d:
d -= acc
ds += "1"
acc /= 2
else:
ds += "0"
acc /= 2
ds += "0" * cnt
return (us, ds)
while True:
f = float(input())
if f < 0:
break
us, ds = to_digit(f)
if us == "DAME":
print("NA")
else:
print(us.zfill(8) + "." + ds.zfill(4))
``` | instruction | 0 | 91,640 | 20 | 183,280 |
No | output | 1 | 91,640 | 20 | 183,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"What are your shoe sizes?"
Suddenly, the doctor asked me when I met him for the first time.
"It's 23.5"
"Oh, that's a really nice number. It's 2 to the 4th power plus 2 to the 2nd power, 2 to the 1st power, 2 to the 0th power, and 2 to the 1st power."
Then the doctor asked.
"You, how tall are you?"
"Yes, it's 158.1."
He folded his arms and closed his eyes. After a while of silence, I opened my mouth.
"Nah ~"
After that, during the time I spent together, I gradually became able to understand the behavior of the doctor.
First, I say the real number at the request of the doctor. If the real number is represented by a binary number with no more than 8 digits for the integer part and no more than 4 digits for the decimal part, he is happy to say the result of the conversion to binary. If not, it will sadly yell "Nah ~". This repeats until I say a negative real number.
By the way, as he got older, it became more and more difficult to make long calculations. Therefore, please make a program for you to input real numbers and convert / output them to binary numbers on your behalf. However, if the binary representation does not fit within the limit number of digits (integer part within 8 digits + decimal part within 4 digits), output NA (half-width alphabetic characters). The input real number shall fit within 8 digits of the integer part and within 4 digits of the decimal part, and the binary representation to be output should be output with 8 digits of the integer part and 4 digits of the decimal part.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single negative real line. One real number n is given to one row for each dataset.
The number of datasets does not exceed 1200.
Output
Outputs the conversion result to binary number for each input data set.
Example
Input
23.5
158.1
-1.0
Output
00010111.1000
NA
Submitted Solution:
```
# AOJ 0220 Binary Digit A Doctor Loved
# Python3 2018.6.23 bal4u
while 1:
a, b = map(int, input().split('.'))
if a < 0: break
if a > 255:
print("NA")
continue
sa = format(a, '08b')
sb, s = '', str(b)
k = 10**len(s)
for i in range(4):
b *= 2
if b >= k: sb += '1'
else: sb += '0'
b %= k
if b == 0: print(sa, '.', sb, sep='')
else: print("NA")
``` | instruction | 0 | 91,641 | 20 | 183,282 |
No | output | 1 | 91,641 | 20 | 183,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"What are your shoe sizes?"
Suddenly, the doctor asked me when I met him for the first time.
"It's 23.5"
"Oh, that's a really nice number. It's 2 to the 4th power plus 2 to the 2nd power, 2 to the 1st power, 2 to the 0th power, and 2 to the 1st power."
Then the doctor asked.
"You, how tall are you?"
"Yes, it's 158.1."
He folded his arms and closed his eyes. After a while of silence, I opened my mouth.
"Nah ~"
After that, during the time I spent together, I gradually became able to understand the behavior of the doctor.
First, I say the real number at the request of the doctor. If the real number is represented by a binary number with no more than 8 digits for the integer part and no more than 4 digits for the decimal part, he is happy to say the result of the conversion to binary. If not, it will sadly yell "Nah ~". This repeats until I say a negative real number.
By the way, as he got older, it became more and more difficult to make long calculations. Therefore, please make a program for you to input real numbers and convert / output them to binary numbers on your behalf. However, if the binary representation does not fit within the limit number of digits (integer part within 8 digits + decimal part within 4 digits), output NA (half-width alphabetic characters). The input real number shall fit within 8 digits of the integer part and within 4 digits of the decimal part, and the binary representation to be output should be output with 8 digits of the integer part and 4 digits of the decimal part.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single negative real line. One real number n is given to one row for each dataset.
The number of datasets does not exceed 1200.
Output
Outputs the conversion result to binary number for each input data set.
Example
Input
23.5
158.1
-1.0
Output
00010111.1000
NA
Submitted Solution:
```
while True:
d= float(input())
if d< 0: break
a, b= bin(int(d))[2:].zfill(8)+".", d-int(d)
for _ in range(4):
b*= 2
a= a+'1' if int(b)>= 1 else a+'0'
if str(b).split(".")==['1','0']: break
b-=int(b)
a= a.ljust(13, '0')
print("NA" if len(a)> 13 else a)
``` | instruction | 0 | 91,642 | 20 | 183,284 |
No | output | 1 | 91,642 | 20 | 183,285 |
Provide tags and a correct Python 3 solution for this coding contest problem.
All bus tickets in Berland have their numbers. A number consists of n digits (n is even). Only k decimal digits d_1, d_2, ..., d_k can be used to form ticket numbers. If 0 is among these digits, then numbers may have leading zeroes. For example, if n = 4 and only digits 0 and 4 can be used, then 0000, 4004, 4440 are valid ticket numbers, and 0002, 00, 44443 are not.
A ticket is lucky if the sum of first n / 2 digits is equal to the sum of remaining n / 2 digits.
Calculate the number of different lucky tickets in Berland. Since the answer may be big, print it modulo 998244353.
Input
The first line contains two integers n and k (2 β€ n β€ 2 β
10^5, 1 β€ k β€ 10) β the number of digits in each ticket number, and the number of different decimal digits that may be used. n is even.
The second line contains a sequence of pairwise distinct integers d_1, d_2, ..., d_k (0 β€ d_i β€ 9) β the digits that may be used in ticket numbers. The digits are given in arbitrary order.
Output
Print the number of lucky ticket numbers, taken modulo 998244353.
Examples
Input
4 2
1 8
Output
6
Input
20 1
6
Output
1
Input
10 5
6 1 4 0 3
Output
569725
Input
1000 7
5 4 0 1 8 3 2
Output
460571165
Note
In the first example there are 6 lucky ticket numbers: 1111, 1818, 1881, 8118, 8181 and 8888.
There is only one ticket number in the second example, it consists of 20 digits 6. This ticket number is lucky, so the answer is 1. | instruction | 0 | 91,740 | 20 | 183,480 |
Tags: divide and conquer, dp, fft
Correct Solution:
```
from math import trunc
MOD = 998244353
MODF = float(MOD)
SHRT = float(1 << 16)
# Using pajenegod's crazy method for multiplication using floating point
fmod = lambda x: x - MODF * trunc(x / MODF)
mod_prod = lambda a, b: fmod(trunc(a / SHRT) * fmod(b * SHRT) + (a - SHRT * trunc(a / SHRT)) * b)
def fpow(a, b):
r = 1.0
while b:
if b & 1: r = mod_prod(r, a)
a = mod_prod(a, a)
b >>= 1
return r
n, k = map(int, input().split())
f = [0] * (5 * n + 5)
for d in map(int, input().split()):
f[d] = 1
def ntt_transform(a, G, inv=False):
n, k = 1, 0
while n < len(a):
k += 1
n *= 2
a += [0] * (n - len(a))
n2 = n // 2
w = [1] * n2
w[1] = fpow(G, (MOD - 1) // n)
if inv: w[1] = fpow(w[1], MOD - 2)
for i in range(2, n2):
w[i] = mod_prod(w[i - 1], w[1])
rev = [0] * n
for i in range(n):
rev[i] = rev[i >> 1] >> 1
if i & 1: rev[i] |= n2
if i < rev[i]: a[i], a[rev[i]] = a[rev[i]], a[i]
l = 2
while l <= n:
half, diff = l // 2, n // l
for i in range(0, n, l):
pw = 0
for j in range(i, i + half):
v = mod_prod(a[j + half], w[pw]);
a[j + half] = a[j] - v if a[j] - v >= 0 else a[j] - v + MOD
a[j] = a[j] + v if a[j] + v < MOD else a[j] + v - MOD
pw += diff
l *= 2
if inv:
inv_n = fpow(n, MOD - 2)
for i in range(n): a[i] = mod_prod(a[i], inv_n);
ntt_transform(f, 3)
f = [fpow(x, n // 2) for x in f]
ntt_transform(f, 3, inv=True)
ans = sum(mod_prod(x, x) for x in f) % MODF
print(int(ans))
``` | output | 1 | 91,740 | 20 | 183,481 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
All bus tickets in Berland have their numbers. A number consists of n digits (n is even). Only k decimal digits d_1, d_2, ..., d_k can be used to form ticket numbers. If 0 is among these digits, then numbers may have leading zeroes. For example, if n = 4 and only digits 0 and 4 can be used, then 0000, 4004, 4440 are valid ticket numbers, and 0002, 00, 44443 are not.
A ticket is lucky if the sum of first n / 2 digits is equal to the sum of remaining n / 2 digits.
Calculate the number of different lucky tickets in Berland. Since the answer may be big, print it modulo 998244353.
Input
The first line contains two integers n and k (2 β€ n β€ 2 β
10^5, 1 β€ k β€ 10) β the number of digits in each ticket number, and the number of different decimal digits that may be used. n is even.
The second line contains a sequence of pairwise distinct integers d_1, d_2, ..., d_k (0 β€ d_i β€ 9) β the digits that may be used in ticket numbers. The digits are given in arbitrary order.
Output
Print the number of lucky ticket numbers, taken modulo 998244353.
Examples
Input
4 2
1 8
Output
6
Input
20 1
6
Output
1
Input
10 5
6 1 4 0 3
Output
569725
Input
1000 7
5 4 0 1 8 3 2
Output
460571165
Note
In the first example there are 6 lucky ticket numbers: 1111, 1818, 1881, 8118, 8181 and 8888.
There is only one ticket number in the second example, it consists of 20 digits 6. This ticket number is lucky, so the answer is 1.
Submitted Solution:
```
def main():
arr=input().split()
n=int(arr[0])//2
k=int(arr[1])
arr=input().split()
for x in range(k):
arr[x]=int(arr[x])
store=[0 for x in range(n*9)]
store[0]=1
for a in range(n):
duplicate=[0 for x in range(n*9)]
for x in range(n*9-9):
if store[x]!=0:
for y in range(k):
duplicate[x+arr[y]]+=store[x]
store=duplicate.copy()
total=0
for x in store:
total+=x**2
total%=998244353
print(total)
main()
``` | instruction | 0 | 91,741 | 20 | 183,482 |
No | output | 1 | 91,741 | 20 | 183,483 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
All bus tickets in Berland have their numbers. A number consists of n digits (n is even). Only k decimal digits d_1, d_2, ..., d_k can be used to form ticket numbers. If 0 is among these digits, then numbers may have leading zeroes. For example, if n = 4 and only digits 0 and 4 can be used, then 0000, 4004, 4440 are valid ticket numbers, and 0002, 00, 44443 are not.
A ticket is lucky if the sum of first n / 2 digits is equal to the sum of remaining n / 2 digits.
Calculate the number of different lucky tickets in Berland. Since the answer may be big, print it modulo 998244353.
Input
The first line contains two integers n and k (2 β€ n β€ 2 β
10^5, 1 β€ k β€ 10) β the number of digits in each ticket number, and the number of different decimal digits that may be used. n is even.
The second line contains a sequence of pairwise distinct integers d_1, d_2, ..., d_k (0 β€ d_i β€ 9) β the digits that may be used in ticket numbers. The digits are given in arbitrary order.
Output
Print the number of lucky ticket numbers, taken modulo 998244353.
Examples
Input
4 2
1 8
Output
6
Input
20 1
6
Output
1
Input
10 5
6 1 4 0 3
Output
569725
Input
1000 7
5 4 0 1 8 3 2
Output
460571165
Note
In the first example there are 6 lucky ticket numbers: 1111, 1818, 1881, 8118, 8181 and 8888.
There is only one ticket number in the second example, it consists of 20 digits 6. This ticket number is lucky, so the answer is 1.
Submitted Solution:
```
n, k = map(int, input().split(' '))
n //= 2
inv = [1] * (9*n + 2)
for i in range(2, 9*n + 2):
inv[i] = -inv[998244353 % i] * (998244353 // i) % 998244353
a = list(map(int, input().split(' ')))
mi = min(a)
a = list(map(lambda x: x - mi, a))
a.remove(a.index(0))
ans = 0
b = [0] * 16
b[0] = 1
for i in range(9*n + 1):
ans += b[i & 15] * b[i & 15]
if ans > 7971934306371108872:
ans -= 7971934306371108872
s = 0
for x in a:
s += b[(i - x + 17) & 15] * (n * x - (i - x + 1))
b[(i + 1) & 15] = s % 998244353 * inv[i + 1] % 998244353
print(ans % 998244353)
``` | instruction | 0 | 91,742 | 20 | 183,484 |
No | output | 1 | 91,742 | 20 | 183,485 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
All bus tickets in Berland have their numbers. A number consists of n digits (n is even). Only k decimal digits d_1, d_2, ..., d_k can be used to form ticket numbers. If 0 is among these digits, then numbers may have leading zeroes. For example, if n = 4 and only digits 0 and 4 can be used, then 0000, 4004, 4440 are valid ticket numbers, and 0002, 00, 44443 are not.
A ticket is lucky if the sum of first n / 2 digits is equal to the sum of remaining n / 2 digits.
Calculate the number of different lucky tickets in Berland. Since the answer may be big, print it modulo 998244353.
Input
The first line contains two integers n and k (2 β€ n β€ 2 β
10^5, 1 β€ k β€ 10) β the number of digits in each ticket number, and the number of different decimal digits that may be used. n is even.
The second line contains a sequence of pairwise distinct integers d_1, d_2, ..., d_k (0 β€ d_i β€ 9) β the digits that may be used in ticket numbers. The digits are given in arbitrary order.
Output
Print the number of lucky ticket numbers, taken modulo 998244353.
Examples
Input
4 2
1 8
Output
6
Input
20 1
6
Output
1
Input
10 5
6 1 4 0 3
Output
569725
Input
1000 7
5 4 0 1 8 3 2
Output
460571165
Note
In the first example there are 6 lucky ticket numbers: 1111, 1818, 1881, 8118, 8181 and 8888.
There is only one ticket number in the second example, it consists of 20 digits 6. This ticket number is lucky, so the answer is 1.
Submitted Solution:
```
print("Does this work?")
``` | instruction | 0 | 91,743 | 20 | 183,486 |
No | output | 1 | 91,743 | 20 | 183,487 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
All bus tickets in Berland have their numbers. A number consists of n digits (n is even). Only k decimal digits d_1, d_2, ..., d_k can be used to form ticket numbers. If 0 is among these digits, then numbers may have leading zeroes. For example, if n = 4 and only digits 0 and 4 can be used, then 0000, 4004, 4440 are valid ticket numbers, and 0002, 00, 44443 are not.
A ticket is lucky if the sum of first n / 2 digits is equal to the sum of remaining n / 2 digits.
Calculate the number of different lucky tickets in Berland. Since the answer may be big, print it modulo 998244353.
Input
The first line contains two integers n and k (2 β€ n β€ 2 β
10^5, 1 β€ k β€ 10) β the number of digits in each ticket number, and the number of different decimal digits that may be used. n is even.
The second line contains a sequence of pairwise distinct integers d_1, d_2, ..., d_k (0 β€ d_i β€ 9) β the digits that may be used in ticket numbers. The digits are given in arbitrary order.
Output
Print the number of lucky ticket numbers, taken modulo 998244353.
Examples
Input
4 2
1 8
Output
6
Input
20 1
6
Output
1
Input
10 5
6 1 4 0 3
Output
569725
Input
1000 7
5 4 0 1 8 3 2
Output
460571165
Note
In the first example there are 6 lucky ticket numbers: 1111, 1818, 1881, 8118, 8181 and 8888.
There is only one ticket number in the second example, it consists of 20 digits 6. This ticket number is lucky, so the answer is 1.
Submitted Solution:
```
n,m = list(int(e) for e in input().split())
num = [e for e in input().split()]
ans = list()
def check(char):
half = len(char)//2
if eval('+'.join(char[:half])) == eval('+'.join(char[half:])):
return True
else:
return False
def go(char,i):
print(char)
if i == n:
if check(char):
ans.append(char)
return
for k in range (len(num)):
go(char+num[k],i+1)
go('',0)
print(len(ans))
#ΰΉΰΈΰΉΰΈΰΉΰΈΰΉΰΈΰΉΰΈΰΈ±ΰΉΰΈΰΈ«ΰΈ‘ΰΈ n**m ΰΉΰΈΰΈ
``` | instruction | 0 | 91,744 | 20 | 183,488 |
No | output | 1 | 91,744 | 20 | 183,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,796 | 20 | 183,592 |
Tags: implementation
Correct Solution:
```
import sys,math
from collections import deque,defaultdict
import operator as op
from functools import reduce
from itertools import permutations
import heapq
#sys.setrecursionlimit(10**7)
# OneDrive\Documents\codeforces
I=sys.stdin.readline
alpha="abcdefghijklmnopqrstuvwxyz"
mod=10**9 + 7
"""
x_move=[-1,0,1,0,-1,1,1,-1]
y_move=[0,1,0,-1,1,1,-1,-1]
"""
def ii():
return int(I().strip())
def li():
return list(map(int,I().strip().split()))
def mi():
return map(int,I().strip().split())
def ncr(n, r):
r = min(r, n-r)
numer = reduce(op.mul, range(n, n-r, -1), 1)
denom = reduce(op.mul, range(1, r+1), 1)
return numer // denom
def ispali(s):
i=0
j=len(s)-1
while i<j:
if s[i]!=s[j]:
return False
i+=1
j-=1
return True
def isPrime(n):
if n<=1:
return False
elif n<=2:
return True
else:
for i in range(2,int(n**.5)+1):
if n%i==0:
return False
return True
lucky_nums=[4,7]
f=0
i=0
cnt=1
while True:
tmp=[]
for n in [4,7]:
for j in lucky_nums[i:]:
x=str(n)+str(j)
if len(x)>10:
f=1
break
else:
tmp.append(int(x))
if f:
break
if tmp:
lucky_nums+=tmp
i+=(2**cnt)
cnt+=1
if f:
break
def main():
l,r=mi()
i=0
last=l
ans=0
while lucky_nums[i]<last:
i+=1
while last<=r:
ans+=lucky_nums[i]*((min(lucky_nums[i],r)-last)+1)
last=lucky_nums[i]+1
i+=1
print(ans)
if __name__ == '__main__':
main()
``` | output | 1 | 91,796 | 20 | 183,593 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,797 | 20 | 183,594 |
Tags: implementation
Correct Solution:
```
from bisect import bisect_left
l, r = map(int, input().split())
t, p, u, v = [4, 7], [4, 7], 4, 7
while t[-1] < r:
u, v = u * 10, v * 10
t = [u + i for i in t] + [v + i for i in t]
p.extend(t)
p = p[bisect_left(p, l): bisect_left(p, r) + 1]
print((p[0] - l + 1) * p[0] + (r - p[-1]) * p[-1] + sum((p[i] - p[i - 1]) * p[i] for i in range(1, len(p))))
``` | output | 1 | 91,797 | 20 | 183,595 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,798 | 20 | 183,596 |
Tags: implementation
Correct Solution:
```
a=10000
z=set()
for i in range(a):
x=("{:b}".format(i))
x=x.replace("1","7")
x=x.replace("0","4")
z.add(x)
for i in range(a):
x=("{:b}".format(i))
x=x.replace("0","7")
x=x.replace("1","4")
z.add(x)
z=list(z)
z=list(map(int,z))
z.sort()
l,r=map(int,input().split())
c=0
i=0
while True:
if z[i]>=l:
break
i+=1
j=i
l-=1
for i in range(j,100000):
if z[i]>=r:
c+=(r-l)*z[i]
break
if z[i]>=l:
c+=(z[i]-l)*(z[i])
l=z[i]
print(c)
``` | output | 1 | 91,798 | 20 | 183,597 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,799 | 20 | 183,598 |
Tags: implementation
Correct Solution:
```
def mapit():
temp=list(map(int,input().split()))
return temp
import bisect
arr=[]
def rec(ch):
if ch>4444444444:
return
if ch>0:
arr.append(ch)
ch*=10
ch+=4
rec(ch)
ch+=3
rec(ch)
l,r=mapit()
rec(0)
arr.sort()
left=bisect.bisect_left(arr, l)
right=bisect.bisect_right(arr, r)
if left==right:
ans=arr[left]*(r-l+1)
print(ans)
else:
ans=arr[left]*(arr[left]-l+1)
for i in range(left+1,right+1):
ans+=((arr[i])*(min(arr[i],r)-arr[i-1]))
print(ans)
``` | output | 1 | 91,799 | 20 | 183,599 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,800 | 20 | 183,600 |
Tags: implementation
Correct Solution:
```
from math import *
#from bisect import *
#from collections import *
#from random import *
#from decimal import *"""
#from heapq import *
#from random import *
import sys
input=sys.stdin.readline
#sys.setrecursionlimit(3*(10**5))
global flag
def inp():
return int(input())
def st():
return input().rstrip('\n')
def lis():
return list(map(int,input().split()))
def ma():
return map(int,input().split())
t=1
global li
li=[]
def rec(st,tu):
global li
if(tu>10):
return
if(st):
li.append(int(st))
rec(st+'4',tu+1)
rec(st+'7',tu+1)
rec('',0)
while(t):
t-=1
l,r=ma()
li.sort()
co=0
for i in li:
if(int(i)<l):
continue
need=min(int(i)-l+1,r-l+1)
#print(need,l,i)
l+=need
co+=need*int(i)
if(l>r):
break
print(co)
``` | output | 1 | 91,800 | 20 | 183,601 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,801 | 20 | 183,602 |
Tags: implementation
Correct Solution:
```
MAX = 10 ** 10
def doit(cur):
if cur > MAX:
return
if cur <= MAX:
a.append(cur)
doit(cur * 10 + 4)
doit(cur * 10 + 7)
a = []
doit(0)
a.sort()
ret = 0
left, right = map(int, input().split())
for i in range(len(a) - 1):
l = max(left, a[i] + 1)
r = min(right, a[i + 1])
ret += max(r - l + 1, 0) * a[i + 1]
print(ret)
``` | output | 1 | 91,801 | 20 | 183,603 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,802 | 20 | 183,604 |
Tags: implementation
Correct Solution:
```
def countGreater(arr, n, k):
l = 0
r = n - 1
# Stores the index of the left most element
# from the array which is greater than k
leftGreater = n
# Finds number of elements greater than k
while (l <= r):
m = int(l + (r - l) / 2)
# If mid element is greater than
# k update leftGreater and r
if (arr[m] >= k):
leftGreater = m
r = m - 1
# If mid element is less than
# or equal to k update l
else:
l = m + 1
# Return the count of elements
# greater than k
return (n - leftGreater)
l,r=map(int,input().split())
e=[4,7]
t=2
c=0
while(e[-1]<=1000000000):
te=len(e)
c+=1
for i in range(t):
e.append(4*pow(10,c)+e[te-t+i])
for i in range(t):
e.append(7*pow(10,c)+e[te-t+i])
t*=2
ind=countGreater(e,len(e),l)
s=l
ind=len(e)-ind
end=min(r,e[ind])
mul=e[ind]
#print(mul)
ans=0
ty=1
while(True):
#print(s,end,mul)
ans+=(end-s+1)*mul
if end==r:
break
s=end+1
end=min(r,e[ind+ty])
mul=e[ind+ty]
ty+=1
#print(ans)
print(ans)
``` | output | 1 | 91,802 | 20 | 183,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7 | instruction | 0 | 91,803 | 20 | 183,606 |
Tags: implementation
Correct Solution:
```
l,r = [int(x) for x in input().strip().split()]
def next(n,k):
s = n
n = int(n)
if int("4"*k)>=n:
return "4"*k
elif int("7"*k)<n:
return "4"*(k+1)
elif 4<int(s[0])<7:
return "7"+"4"*(k-1)
if not s[1:]=="":
a = next(s[1:],k-1)
if s[0]=="4":
if len(str(a))==k:
return "7"+a[1:]
else:
return "4"+a
else:
return "7"+a
else:
return "7"
last = int(next(str(l),len(str(l))))
tot = 0
count = l
while count<=r:
# print(count,tot,last)
tot+=last*(min(last,r)-count+1)
count = last+1
b = str(last+1)
last=int(next(b,len(b)))
print(tot)
# print(next("1000000000",len("1000000000")))
``` | output | 1 | 91,803 | 20 | 183,607 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
pre = []
prev = ['']
for i in range(1, 11):
cur = [s + '4' for s in prev] + [s + '7' for s in prev]
pre.extend(cur)
prev = cur
l = sorted(map(int, pre))
x, y = map(int, input().split())
res = 0
for i in l:
if i<x:
continue
res+=i*(min(i,y)-x+1)
x=i+1
if x>y:
break
print(res)
``` | instruction | 0 | 91,804 | 20 | 183,608 |
Yes | output | 1 | 91,804 | 20 | 183,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
l, r = map(int, input().split())
lst = []
def rec(n):
lst.append(n)
if n > 10 *r:
return
rec(n*10+4)
rec(n*10+7)
return
rec(0)
lst.sort()
s = 0
s2 = 0
for i in range(len(lst)):
s += lst[i] * (min(lst[i], r) - min(lst[i-1], r))
s2 += lst[i] * (min(lst[i], l-1) - min(lst[i-1], l-1))
print(s-s2)
``` | instruction | 0 | 91,805 | 20 | 183,610 |
Yes | output | 1 | 91,805 | 20 | 183,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
def getLuckyNumber(digit , arr):
temp = list()
for i in arr:
temp.append('4' + i)
temp.append('7' + i)
return temp
def digitCount(number):
digits = 1
while True:
digits += 1
number = number // 10
if number == 0:
break
return getLuckyList(digits)
def getLuckyList(digitCount):
temp = ['']
arr = list()
for i in range(1 , digitCount + 1):
temp = getLuckyNumber(i , temp)
luck = list(map(int , temp))
arr += luck
arr.sort()
return arr
def nextLuckyNumber(x , arr):
for j in arr:
if j >= x:
return j
if __name__ == "__main__":
n = list(map(int , input().rstrip().split()))
l = n[0]
r = n[1]
arr = digitCount(r)
total = 0
prev = 0
i = l
while i <= r:
if i > prev:
prev = nextLuckyNumber(i , arr)
#print (prev , i)
total += prev
i += 1
else:
if prev <= r:
total += (prev - i + 1) * prev
else:
total += (r - i + 1) * prev
i = prev + 1
print (total)
``` | instruction | 0 | 91,806 | 20 | 183,612 |
Yes | output | 1 | 91,806 | 20 | 183,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
x, y = map(int,input().split())
a=list()
a = [4, 7]
l = 0
mid = -1
k = len(list(str(y)))
while l<k:
for m in range(mid+1,len(a)):
a.append(str(a[m])+"4")
a.append(str(a[m])+"7")
l+=1
suma = 0
for m in range(len(a)):
if x<= int(a[m]) and y <= int(a[m]) and x <= y:
suma+=int(a[m])*(y - x+1)
break
elif x<=int(a[m]) and y > int(a[m]):
suma+=int(a[m])*(int(a[m]) - x+1)
x = int(a[m])+1
print(suma)
``` | instruction | 0 | 91,807 | 20 | 183,614 |
Yes | output | 1 | 91,807 | 20 | 183,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
maxn=1024
luck=[0]*maxn
luck[1]=4
luck[2]=7
def return_sum(n):
if n==0:
return 0
ans=0
for i in range(maxn):
if luck[i]<n:
ans+=luck[i]*(luck[i]-luck[i-1])
else:
ans+=luck[i]*(n-luck[i-1])
break
return ans
l,r=map(int,input().split())
x=3
for i in range(1,maxn//2):
luck[x]=luck[i]*10+4
x+=1
if x==maxn//2:
break
luck[x]=luck[i]*10+7
x+=1
print(return_sum(r)-return_sum(l-1))
``` | instruction | 0 | 91,808 | 20 | 183,616 |
No | output | 1 | 91,808 | 20 | 183,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
l,r = map(int,input().split(' '))
a = set()
for i in range(1, 11):
for j in range(2**i):
c = j
cnt = 0
t = 0
while c or cnt < i:
if c&1:
t = t*10+7
else:
t = t*10+4
cnt += 1
c //= 2
a.add(t)
a = sorted(list(a))
print(max(a))
ans = 0
for j in range(len(a)):
i = a[j]
if l <= i and r > i:
ans += (i - l + 1) * i
l = i + 1
elif l <= i and r <= i:
ans += (r - l + 1) * i
break
print(ans)
``` | instruction | 0 | 91,809 | 20 | 183,618 |
No | output | 1 | 91,809 | 20 | 183,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
l,r=map(int,(input().split()))
lucky=[4,7]
if l==1000000000 and r==1000000000:
print(4444444444)
else:
for i in range(1,10):
for j in lucky[pow(2,i)-2:pow(2,i+1)+1]:
lucky.append(4*pow(10,i) + j)
lucky.append(7*pow(10,i)+ j)
lucky.sort()
add=0
for i in lucky:
if i<l:
lucky.pop(0)
for i in range(l,r+1):
if i<=lucky[0]:
add=add+lucky[0]
else:
lucky.pop(0)
add=add+lucky[0]
print(add)
``` | instruction | 0 | 91,810 | 20 | 183,620 |
No | output | 1 | 91,810 | 20 | 183,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.
Input
The single line contains two integers l and r (1 β€ l β€ r β€ 109) β the left and right interval limits.
Output
In the single line print the only number β the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).
Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.
Examples
Input
2 7
Output
33
Input
7 7
Output
7
Note
In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33
In the second sample: next(7) = 7
Submitted Solution:
```
from itertools import product
x = ['4','7']
lucky_nums = [4,7]
for i in range(2,11):
for p in product(x,repeat=i):
lucky_nums.append(int("".join(p)))
n = len(lucky_nums)
l,r = map(int,input().split())
li = -1
ri = -1
for i in range(n):
if li==-1 and lucky_nums[i] >= l:
li = i
if lucky_nums[i] <= r:
ri = i
prev = l
ans = 0
for i in range(li,ri+1):
ans += (lucky_nums[i]-prev+1)*lucky_nums[i]
prev = lucky_nums[i]+1
print(ans)
``` | instruction | 0 | 91,811 | 20 | 183,622 |
No | output | 1 | 91,811 | 20 | 183,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a square matrix n Γ n, consisting of non-negative integer numbers. You should find such a way on it that
* starts in the upper left cell of the matrix;
* each following cell is to the right or down from the current cell;
* the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
Input
The first line contains an integer number n (2 β€ n β€ 1000), n is the size of the matrix. Then follow n lines containing the matrix elements (non-negative integer numbers not exceeding 109).
Output
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
Examples
Input
3
1 2 3
4 5 6
7 8 9
Output
0
DDRR | instruction | 0 | 92,050 | 20 | 184,100 |
Tags: dp, math
Correct Solution:
```
n = int(input())
xr = range(n)
a5 = [list(map(int, input().split())) for _ in xr]
a2 = [[0 for _ in xr] for _ in xr]
y = 0
x0 = -1
for y in xr:
for x in xr:
i = a5[y][x]
m5 = 0
m2 = 0
if i == 0:
x0 = x
while i and i%2 == 0:
i/=2
m2+=1
while i and i%5 == 0:
i/=5
m5+=1
if y == 0 and x == 0:
a5[y][x] = m5
a2[y][x] = m2
continue
left5 = a5[y][x-1]
left2 = a2[y][x-1]
up5 = a5[y-1][x]
up2 = a2[y-1][x]
if y == 0:
a5[y][x] = left5 + m5
a2[y][x] = left2 + m2
continue
if x == 0:
a5[y][x] = up5 + m5
a2[y][x] = up2 + m2
continue
a5[y][x] = min(up5, left5) + m5
a2[y][x] = min(up2, left2) + m2
def getpath(k):
p = ''
y = x = n-1
while not (y == 0 and x == 0):
if y and x:
if k == 5:
if a5[y-1][x] < a5[y][x-1]:
p+='D'
y-=1
else:
p+='R'
x-=1
else:
if a2[y-1][x] < a2[y][x-1]:
p+='D'
y-=1
else:
p+='R'
x-=1
elif y == 0:
p+='R'
x-=1
elif x == 0:
p+='D'
y-=1
return p[::-1]
ten = 0
path = ''
if a5[n-1][n-1] < a2[n-1][n-1]:
ten = a5[n-1][n-1]
path = getpath(5)
else:
ten = a2[n-1][n-1]
path = getpath(2)
if ten > 1 and x0 > -1:
ten = 1
path = 'R'*x0 + 'D'*(n-1) + 'R'*(n-1-x0)
print(ten)
print(path)
``` | output | 1 | 92,050 | 20 | 184,101 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a square matrix n Γ n, consisting of non-negative integer numbers. You should find such a way on it that
* starts in the upper left cell of the matrix;
* each following cell is to the right or down from the current cell;
* the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
Input
The first line contains an integer number n (2 β€ n β€ 1000), n is the size of the matrix. Then follow n lines containing the matrix elements (non-negative integer numbers not exceeding 109).
Output
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
Examples
Input
3
1 2 3
4 5 6
7 8 9
Output
0
DDRR | instruction | 0 | 92,051 | 20 | 184,102 |
Tags: dp, math
Correct Solution:
```
n = int(input())
field = []
field_two = []
field_five = []
fields = [field_two, field_five]
max_zero = 20000
zero_i = None
def make_mult(number, div, i):
global zero_i
if number == 0:
zero_i = i
return max_zero
count = 0
while number % div == 0:
count += 1
number //= div
return count
def get_path():
for i in range(1, n):
field_two[i][0] += field_two[i - 1][0]
field_five[i][0] += field_five[i - 1][0]
for j in range(1, n):
field_two[0][j] += field_two[0][j - 1]
field_five[0][j] += field_five[0][j - 1]
for i in range(1, n):
for j in range(1, n):
field_two[i][j] += min(field_two[i - 1][j], field_two[i][j - 1])
field_five[i][j] += min(field_five[i - 1][j], field_five[i][j - 1])
if field_two[-1][-1] < field_five[-1][-1]:
return field_two[-1][-1], build_path(field_two)
else:
return field_five[-1][-1], build_path(field_five)
def build_path(mult_field):
path = []
i = j = n - 1
while i + j:
if i == 0 or not j == 0 and mult_field[i][j - 1] < mult_field[i - 1][j]:
path.append("R")
j -= 1
else:
path.append("D")
i -= 1
path.reverse()
return "".join(path)
def solver():
zeros, path = get_path()
if zeros < 2:
return zeros, path
if zero_i is None:
return zeros, path
else:
return 1, "D" * zero_i + "R" * (n - 1) + "D" * (n - 1 - zero_i)
def main():
for i in range(n):
field.append([int(e) for e in input().split()])
field_two.append([make_mult(e, 2, i) for e in field[i]])
field_five.append([make_mult(e, 5, i) for e in field[i]])
zeros, path = solver()
print(zeros, path, sep="\n")
if __name__ == '__main__':
main()
``` | output | 1 | 92,051 | 20 | 184,103 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a square matrix n Γ n, consisting of non-negative integer numbers. You should find such a way on it that
* starts in the upper left cell of the matrix;
* each following cell is to the right or down from the current cell;
* the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
Input
The first line contains an integer number n (2 β€ n β€ 1000), n is the size of the matrix. Then follow n lines containing the matrix elements (non-negative integer numbers not exceeding 109).
Output
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
Examples
Input
3
1 2 3
4 5 6
7 8 9
Output
0
DDRR | instruction | 0 | 92,052 | 20 | 184,104 |
Tags: dp, math
Correct Solution:
```
def solve():
n = int(input())
A = []
for _ in range(n):
A.append([int(x) for x in input().split()])
A2 = [[0 for _ in range(n)] for __ in range(n)]
A5 = [[0 for _ in range(n)] for __ in range(n)]
ans = 0; act_path = ""
for i in range(n):
for j in range(n):
if(A[i][j]==0):
ans = 1
act_path = "R"*j+"D"*i+"R"*(n-1-j)+"D"*(n-1-i)
A[i][j]=10
for i in range(n):
for j in range(n):
x = A[i][j]
while(x%2==0 and x>0):
A2[i][j]+=1
x//=2
while(x%5==0 and x>0):
A5[i][j]+=1
x//=5
dp2 = A2
dp5 = A5
for i in range(1,n):
dp2[i][0]+=dp2[i-1][0]
dp2[0][i]+=dp2[0][i-1]
for i in range(1,n):
dp5[i][0]+=dp5[i-1][0]
dp5[0][i]+=dp5[0][i-1]
for i in range(1,n):
for j in range(1,n):
dp2[i][j]+= min(dp2[i-1][j],dp2[i][j-1])
dp5[i][j]+= min(dp5[i-1][j],dp5[i][j-1])
dp = dp2 if dp2[-1][-1]<dp5[-1][-1] else dp5
if ans==1 and dp[-1][-1]:
print(ans)
print(act_path)
return
ans = dp[-1][-1]
pi,pj = n-1,n-1
act_path = ""
while(pi and pj):
up = dp[pi-1][pj]<dp[pi][pj-1]
act_path+= "D" if up else "R"
pi-= int(up)
pj-= int(not up)
if(not pi):
act_path+= "R"*pj
else:
act_path+= "D"*pi
print(ans)
print(act_path[::-1])
solve()
``` | output | 1 | 92,052 | 20 | 184,105 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There is a square matrix n Γ n, consisting of non-negative integer numbers. You should find such a way on it that
* starts in the upper left cell of the matrix;
* each following cell is to the right or down from the current cell;
* the way ends in the bottom right cell.
Moreover, if we multiply together all the numbers along the way, the result should be the least "round". In other words, it should end in the least possible number of zeros.
Input
The first line contains an integer number n (2 β€ n β€ 1000), n is the size of the matrix. Then follow n lines containing the matrix elements (non-negative integer numbers not exceeding 109).
Output
In the first line print the least number of trailing zeros. In the second line print the correspondent way itself.
Examples
Input
3
1 2 3
4 5 6
7 8 9
Output
0
DDRR | instruction | 0 | 92,053 | 20 | 184,106 |
Tags: dp, math
Correct Solution:
```
def solve(x,y):
z=0
while not x%y and x!=0:
z+=1
x=x//y
return z
def main():
n=int(input())
m_2=[list(map(int,input().split())) for _ in range(n)]
m_5=[[0 for _ in range(n)] for _ in range(n)]
x=(-1,-1)
for i in range(n):
for j in range(n):
if m_2[i][j]==0:
x=(i,j)
break
if x[0]!=-1:
break
m_2[0][0],m_5[0][0]=solve(m_2[0][0],2),solve(m_2[0][0],5)
for i in range(1,n):
m_5[0][i],m_2[0][i]=m_5[0][i-1]+solve(m_2[0][i],5),m_2[0][i-1]+solve(m_2[0][i],2)
m_5[i][0],m_2[i][0]=m_5[i-1][0]+solve(m_2[i][0],5),m_2[i-1][0]+solve(m_2[i][0],2)
for i in range(1,n):
for j in range(1,n):
m_5[i][j]=min(m_5[i-1][j],m_5[i][j-1])+solve(m_2[i][j],5)
m_2[i][j]=min(m_2[i-1][j],m_2[i][j-1])+solve(m_2[i][j],2)
if min(m_5[-1][-1],m_2[-1][-1])>1 and x[0]!=-1:
print(1)
print("R"*(x[1])+"D"*(n-1)+"R"*(n-x[1]-1))
else:
global c
if m_5[-1][-1]<m_2[-1][-1]:
c=m_5
else:
c=m_2
b,i,j=[],n-1,n-1
while i or j:
if i-1>=0 and j-1>=0:
if c[i-1][j]<c[i][j-1]:
b.append("D")
i-=1
else:
b.append("R")
j-=1
elif i==0:
b.append("R")
j-=1
else:
b.append("D")
i-=1
print(c[-1][-1])
b.reverse()
print("".join(b))
main()
``` | output | 1 | 92,053 | 20 | 184,107 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,131 | 20 | 184,262 |
Tags: implementation
Correct Solution:
```
n=int(input())
x=input()
s="0b"+x[::-1]
s=bin(int(s,2)+1)[2:]
if len(s)>n:
s=s[1:]
elif len(s)<n:
d=n-len(s)
s="0"*d+s
s=s[::-1]
c=0
for i in range(n):
if s[i]!=x[i]:
c+=1
print(c)
``` | output | 1 | 92,131 | 20 | 184,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,132 | 20 | 184,264 |
Tags: implementation
Correct Solution:
```
n = int(input())
ls = [int(u) for u in input()]
if 0 in ls:
print(ls.index(0)+1)
else:
print(len(ls))
``` | output | 1 | 92,132 | 20 | 184,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,133 | 20 | 184,266 |
Tags: implementation
Correct Solution:
```
import re
def main():
n = int(input())
num = input()
l = len(re.match(r'^1*', num).group(0))
print(l + 1 if l < n else n)
if __name__ == '__main__':
main()
``` | output | 1 | 92,133 | 20 | 184,267 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,134 | 20 | 184,268 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(input())
sum = 0
for i in range(n):
if a[i] == '1':
sum += 1
else:
sum += 1
break
print(sum)
``` | output | 1 | 92,134 | 20 | 184,269 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,135 | 20 | 184,270 |
Tags: implementation
Correct Solution:
```
N = int(input())
S = input().split("0")
print(min(N,1+len(S[0])))
``` | output | 1 | 92,135 | 20 | 184,271 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,136 | 20 | 184,272 |
Tags: implementation
Correct Solution:
```
n=input()
s=input()
count=0
for i in s:
count+=1
if i=='0':
break
print(count)
``` | output | 1 | 92,136 | 20 | 184,273 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,137 | 20 | 184,274 |
Tags: implementation
Correct Solution:
```
def input_ints():
return list(map(int, input().split()))
def solve():
n = int(input())
s = input()
x = int(s[::-1], 2)
y = (x + 1) % (1 << n)
print(bin(x ^ y).count('1'))
if __name__ == '__main__':
solve()
``` | output | 1 | 92,137 | 20 | 184,275 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000. | instruction | 0 | 92,138 | 20 | 184,276 |
Tags: implementation
Correct Solution:
```
n=int(input())
s=input()
print(min(len((s.split('0')[0]))+1,n))
``` | output | 1 | 92,138 | 20 | 184,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
n = int(input())
s = input()
i = 0
while i < n and s[i] == '1':
i += 1
if i < n:
print(i+1)
else:
print(i)
``` | instruction | 0 | 92,139 | 20 | 184,278 |
Yes | output | 1 | 92,139 | 20 | 184,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
x=int(input());a=list(map(int,input()));p=1;j=0
for i in range(x):
if a[i]==1 and p==1:
a[i]=0
j+=1
elif a[i]==0 and p==1:
a[i]=1
p=0
j+=1
print(j)
``` | instruction | 0 | 92,140 | 20 | 184,280 |
Yes | output | 1 | 92,140 | 20 | 184,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
n=int(input())
a=input()
c,d=0,0
for i in range(n):
if a[i]=="1":
c+=1
d=1
elif a[i]=="0" and d==1:
c+=1
d=0
break
elif i==0 and a[i]=="0" and d==0:
c+=1
break
print(c)
``` | instruction | 0 | 92,141 | 20 | 184,282 |
Yes | output | 1 | 92,141 | 20 | 184,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
n=int(input())
st=input()
num=0
for i in range(n):
if(st[i]=='1'):
num+=(2**i)
num=num+1
b=bin(num).replace("0b","")
b=b[::-1]
ans=0
l=min(n,len(b))
for i in range(l):
if(st[i]!=b[i]):
ans+=1
for i in range(l,n):
if(st[i]!='0'):
ans=ans+1
print(ans)
``` | instruction | 0 | 92,142 | 20 | 184,284 |
Yes | output | 1 | 92,142 | 20 | 184,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
b=int(input())
a=input()
l=0
i=0
p=[]
while i<(len(a)):
while True:
if a[i]=="1":
l=l+1
i=i+1
if i==len(a):
p.append(l)
l=0
break
else:
p.append(l)
l=0
i=i+1
break
if max(p)==len(a):
print(max(p))
else:
print(max(p)+1)
``` | instruction | 0 | 92,143 | 20 | 184,286 |
No | output | 1 | 92,143 | 20 | 184,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
input()
a = input()
a += "0"
print(a.index("0")+1)
``` | instruction | 0 | 92,144 | 20 | 184,288 |
No | output | 1 | 92,144 | 20 | 184,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
'''input
4
1100
'''
n = int(input())
b = list(input())
if set(b) == {"1"}:
print(n)
else:
print(n-1)
``` | instruction | 0 | 92,145 | 20 | 184,290 |
No | output | 1 | 92,145 | 20 | 184,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sergey is testing a next-generation processor. Instead of bytes the processor works with memory cells consisting of n bits. These bits are numbered from 1 to n. An integer is stored in the cell in the following way: the least significant bit is stored in the first bit of the cell, the next significant bit is stored in the second bit, and so on; the most significant bit is stored in the n-th bit.
Now Sergey wants to test the following instruction: "add 1 to the value of the cell". As a result of the instruction, the integer that is written in the cell must be increased by one; if some of the most significant bits of the resulting number do not fit into the cell, they must be discarded.
Sergey wrote certain values ββof the bits in the cell and is going to add one to its value. How many bits of the cell will change after the operation?
Input
The first line contains a single integer n (1 β€ n β€ 100) β the number of bits in the cell.
The second line contains a string consisting of n characters β the initial state of the cell. The first character denotes the state of the first bit of the cell. The second character denotes the second least significant bit and so on. The last character denotes the state of the most significant bit.
Output
Print a single integer β the number of bits in the cell which change their state after we add 1 to the cell.
Examples
Input
4
1100
Output
3
Input
4
1111
Output
4
Note
In the first sample the cell ends up with value 0010, in the second sample β with 0000.
Submitted Solution:
```
n = int(input())
ar = input()
ind = 0
s = 0
print(ar)
for i in ar:
if i == '1' and ind == 0:
s += 1
else:
ind = 1
if s < len(ar):
print(s + 1)
else:
print(len(ar))
``` | instruction | 0 | 92,146 | 20 | 184,292 |
No | output | 1 | 92,146 | 20 | 184,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 β€ n β€ 55) β the maximum length of a number that a door-plate can hold.
Output
Output one integer β the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,171 | 20 | 184,342 |
Tags: combinatorics, math
Correct Solution:
```
a=int(input());print(sum([2*2**i for i in range(a)]))
``` | output | 1 | 92,171 | 20 | 184,343 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 β€ n β€ 55) β the maximum length of a number that a door-plate can hold.
Output
Output one integer β the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,172 | 20 | 184,344 |
Tags: combinatorics, math
Correct Solution:
```
n = int ( input() )
ans = 0
i = 1
while i <= n :
ans += 2**i
i += 1
print ( ans )
``` | output | 1 | 92,172 | 20 | 184,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 β€ n β€ 55) β the maximum length of a number that a door-plate can hold.
Output
Output one integer β the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,173 | 20 | 184,346 |
Tags: combinatorics, math
Correct Solution:
```
n = input()
c = 0
for i in range(1, int(n)+1):
c += 2**i
print (c)
``` | output | 1 | 92,173 | 20 | 184,347 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 β€ n β€ 55) β the maximum length of a number that a door-plate can hold.
Output
Output one integer β the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,174 | 20 | 184,348 |
Tags: combinatorics, math
Correct Solution:
```
from math import factorial
n = int(input())
a = 0
for i in range(1, n+1):
for j in range(0, i+1):
a += int(factorial(i) / (factorial(j) * factorial(i-j)))
print(a)
``` | output | 1 | 92,174 | 20 | 184,349 |
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