message stringlengths 2 16.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 575 109k | cluster float64 16 16 | __index_level_0__ int64 1.15k 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has N sticks. The length of the i-th stick is l_i.
Snuke is making a snake toy by joining K of the sticks together.
The length of the toy is represented by the sum of the individual sticks that compose it. Find the maximum possible length of the toy.
Constraints
* 1 \leq K \leq N \leq 50
* 1 \leq l_i \leq 50
* l_i is an integer.
Input
Input is given from Standard Input in the following format:
N K
l_1 l_2 l_3 ... l_{N}
Output
Print the answer.
Examples
Input
5 3
1 2 3 4 5
Output
12
Input
15 14
50 26 27 21 41 7 42 35 7 5 5 36 39 1 45
Output
386
Submitted Solution:
```
def main():
N, K = map(lambda i: int(i), input().split(' '))
l = list(map(lambda i: int(i), input().split(' '))
l.sort()
l.reverse()
m = 0
for i in range(K):
m += l[i]
print(m)
main()
``` | instruction | 0 | 96,841 | 16 | 193,682 |
No | output | 1 | 96,841 | 16 | 193,683 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,735 | 16 | 195,470 |
"Correct Solution:
```
n,m=map(int,input().split())
ans=set()
ans.add(0)
l=[1 for i in range(n)]
for i in range(m):
x,y=[int(j)-1 for j in input().split()]
l[x]-=1
l[y]+=1
if x in ans:
ans.add(y)
if l[x]==0:
ans.remove(x)
print(len(ans))
``` | output | 1 | 97,735 | 16 | 195,471 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,736 | 16 | 195,472 |
"Correct Solution:
```
N, M = map(int, input().split())
Red = [0]*N
Red[0] = 1
Num = [1]*N
for i in range(M):
In, Out = map(int, input().split())
In -= 1
Out -= 1
Num[In] -= 1
Num[Out] += 1
if Red[In]:
Red[Out] = 1
if Num[In] == 0:
Red[In] = 0
print(sum(Red))
``` | output | 1 | 97,736 | 16 | 195,473 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,737 | 16 | 195,474 |
"Correct Solution:
```
n,m=map(int,input().split())
ans=[False]*n
ans[0]=True
co=[1]*n
for i in range(m):
x,y=map(int,input().split())
ans[y-1]|=ans[x-1]
co[x-1]-=1
co[y-1]+=1
if co[x-1]==0:ans[x-1]=False
print(ans.count(True))
``` | output | 1 | 97,737 | 16 | 195,475 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,738 | 16 | 195,476 |
"Correct Solution:
```
N,M=map(int,input().split())
S={1}
C=[1] * (N+1)
for _ in range(M):
a,b=map(int,input().split())
if a in S:
S.add(b)
if C[a] == 1:
S.remove(a)
C[b] += 1
C[a] -= 1
print(len(S))
``` | output | 1 | 97,738 | 16 | 195,477 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,739 | 16 | 195,478 |
"Correct Solution:
```
n,m=map(int,input().split())
a=[1]*n
b=[0]*n
b[0]=1
for _ in range(m):
x,y=map(lambda x:int(x)-1,input().split())
a[x] -= 1
a[y] += 1
if b[x]:
if a[x] == 0:
b[x]=0
b[y]=1
print(sum(b))
``` | output | 1 | 97,739 | 16 | 195,479 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,740 | 16 | 195,480 |
"Correct Solution:
```
N,M = map(int, input().split())
ans = set([0])
cnt = [1] * N
for _ in range(M):
x,y = [int(i) - 1 for i in input().split()]
cnt[x] -= 1
cnt[y] += 1
if x in ans:
if cnt[x] == 0:
ans.remove(x)
ans.add(y)
print(len(ans))
``` | output | 1 | 97,740 | 16 | 195,481 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,741 | 16 | 195,482 |
"Correct Solution:
```
N,M = map(int, input().split())
balls = [1]*(N+1)
reds = [False]*(N+1)
reds[0] = True
for i in range(M):
x,y = map(int, input().split())
x -= 1
y -= 1
balls[x] -= 1
balls[y] += 1
if reds[x]:
reds[y] = True
if balls[x] == 0:
reds[x] = False
print(sum(reds))
``` | output | 1 | 97,741 | 16 | 195,483 |
Provide a correct Python 3 solution for this coding contest problem.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3 | instruction | 0 | 97,742 | 16 | 195,484 |
"Correct Solution:
```
n,m = map(int, input().split())
xy = [list(map(int, input().split())) for _ in range(m)]
red = [0] * (n+1)
red[1] = 1
ball = [1] * (n+1)
for x,y in xy:
ball[x] -= 1
ball[y] += 1
if red[x] == 1:
red[y] = 1
if ball[x] == 0: red[x] = 0
print(sum(red))
``` | output | 1 | 97,742 | 16 | 195,485 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
N,M=map(int,input().split())
xy=[list(map(int,input().split())) for i in range(M)]
b=[1]*N
r=[1]+[0]*(N-1)
for x,y in xy:
b[x-1]-=1
b[y-1]+=1
if r[x-1]==1:
r[y-1]=1
if b[x-1]==0:
r[x-1]=0
print(sum(r))
``` | instruction | 0 | 97,743 | 16 | 195,486 |
Yes | output | 1 | 97,743 | 16 | 195,487 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n,m=map(int,input().split())
p=[1]*n
c=['w']*n
c[0]='r'
def ope(x,y):
if c[x-1]=='r':
c[y-1]='r'
p[x-1] -= 1
p[y-1] += 1
if p[x-1]==0:
c[x-1]='w'
for i in range(m):
x,y=map(int,input().split())
ope(x,y)
print(c.count('r'))
``` | instruction | 0 | 97,744 | 16 | 195,488 |
Yes | output | 1 | 97,744 | 16 | 195,489 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
N,M=map(int,input().split())
A=[1]*(N+1)
B=[0]*(N+1)
B[1]=1
for i in range(M):
x,y=map(int,input().split())
A[x]-=1
A[y]+=1
if B[x]:
B[y]=1
if not A[x]:
B[x]=0
#print(A)
#print(B)
#print("")
print(sum(B))
``` | instruction | 0 | 97,745 | 16 | 195,490 |
Yes | output | 1 | 97,745 | 16 | 195,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n,m=map(int,input().split())
r=[False]*n
c=[1]*n
r[0]=True
for _ in range(m):
x,y=map(lambda n:int(n)-1,input().split())
if r[x]:
r[y]=True
c[x]-=1
c[y]+=1
if c[x]==0:
r[x]=False
print(sum(r))
``` | instruction | 0 | 97,746 | 16 | 195,492 |
Yes | output | 1 | 97,746 | 16 | 195,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n,m=map(int,input().split())
xy = [list(map(int, input().split())) for _ in range(m)]
l=[1]*n
out_=[0]*n
in_=[0]*n#入れられたことがある履歴。0番目だけは初期値1
c=1
#print(in_)
check=0
for i in range(m):
if check==0:
if xy[i][0]==1:#箱1に入ってくる前に初めて箱1から赤いボールを移す場合
in_[xy[i][1]-1]+=1
check=1
else:#箱１から赤いボールを移す前に白いボールが入ってくる場合
if xy[i][1]==1:
in_[xy[i][1]-1]+=1
check=1
l[xy[i][0]-1]-=1
l[xy[i][1]-1]+=1
else:
l[xy[i][0]-1]-=1
l[xy[i][1]-1]+=1
if in_[xy[i][0]-1]!=0 and in_[xy[i][1]-1]==0:#今までボールを入れられたことがなければ移しようがない。既に入れられたことあるものは重複するので除外。
c+=1
in_[xy[i][1]-1]+=1
#print(l,in_)
#print(l,in_,c)
c2=0#ボールが入っている箱の数
ans=0
for i in l:
if i!=0:
c2+=1
for i in range(n):
if l[i]!=0 and in_[i]!=0:
ans+=1
#print(min(c,c2))
print(ans)
``` | instruction | 0 | 97,747 | 16 | 195,494 |
No | output | 1 | 97,747 | 16 | 195,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n, m = map(int,input().split())
f = [False for _ in range(n)]
f[0] = True
for i in range(m):
x, y = map(int,input().split())
f[y] = f[y] or f[x]
print(f.count(True))
``` | instruction | 0 | 97,748 | 16 | 195,496 |
No | output | 1 | 97,748 | 16 | 195,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n, m = map(int, input().split())
xs, ys = [], []
for i in range(m):
x, y = map(int, input().split())
xs.append(x)
ys.append(y)
num_balls = [1] * (n+1)
r_boxes = [1]
for x, y in zip(xs, ys):
num_balls[x] -= 1
num_balls[y] += 1
if x in r_boxes:
r_boxes.append(y)
if not num_balls[x]:
r_boxes.remove(x)
print(1 if(len(r_boxes) == 1) else len(r_boxes)-1)
``` | instruction | 0 | 97,749 | 16 | 195,498 |
No | output | 1 | 97,749 | 16 | 195,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.
Snuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.
Find the number of boxes that may contain the red ball after all operations are performed.
Constraints
* 2≤N≤10^5
* 1≤M≤10^5
* 1≤x_i,y_i≤N
* x_i≠y_i
* Just before the i-th operation is performed, box x_i contains at least 1 ball.
Input
The input is given from Standard Input in the following format:
N M
x_1 y_1
:
x_M y_M
Output
Print the number of boxes that may contain the red ball after all operations are performed.
Examples
Input
3 2
1 2
2 3
Output
2
Input
3 3
1 2
2 3
2 3
Output
1
Input
4 4
1 2
2 3
4 1
3 4
Output
3
Submitted Solution:
```
n,m=map(int,input().split())
li=[list(map(int,input().split())) for _ in range(m)]
box=[[1,0]]
for i in range(n-1):
box.append([0,1])
for x,y in li:
tmp=box[x-1].copy()
box[x-1][0]-=tmp[0]/(tmp[0]+tmp[1])
box[x-1][1]-=tmp[1]/(tmp[0]+tmp[1])
box[y-1][0]+=tmp[0]/(tmp[0]+tmp[1])
box[y-1][1]+=tmp[1]/(tmp[0]+tmp[1])
ans=0
for i in box:
if i[0]>0:
ans+=1
print(ans)
``` | instruction | 0 | 97,750 | 16 | 195,500 |
No | output | 1 | 97,750 | 16 | 195,501 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,443 | 16 | 196,886 |
"Correct Solution:
```
mod = 10**9+7
n,m = map(int,input().split())
s = list(map(int,input().split()))
s.sort()
s = [None] + s
dp = [[0 for i in range(m+1)] for j in range(n+1)]
dp[1] = [i % s[1] for i in range(m+1)]
for i in range(2,n+1):
for j in range(m+1):
dp[i][j] = (dp[i-1][j] * (i-1) + dp[i-1][j%s[i]]) % mod
print(dp[n][m])
``` | output | 1 | 98,443 | 16 | 196,887 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,444 | 16 | 196,888 |
"Correct Solution:
```
n, x = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
MOD = 10 ** 9 + 7
S = [0] * (x+1)
T = [0] * (x+1)
S[x] = 1
for i in range(n-1, -1, -1):
T = [0] * (x + 1)
for j in range(x+1):
S[j] %= MOD
T[j] += S[j] * i % MOD
T[j % a[i]] += S[j]
S, T = T, S
print(sum(i * S[i] % MOD for i in range(a[0]) ) % MOD)
``` | output | 1 | 98,444 | 16 | 196,889 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,445 | 16 | 196,890 |
"Correct Solution:
```
MOD = 10**9 + 7
N, X = map(int, input().split())
Ss = list(map(int, input().split()))
Ss.sort(reverse=True)
minS = Ss[-1]
D = {X: 1}
for i, S in enumerate(Ss[:-1]):
D2 = {}
for x, num in D.items():
D2[x] = (D2.get(x, 0) + num*(N-1-i)) % MOD
D2[x%S] = (D2.get(x%S, 0) + num) % MOD
D = D2
ans = 0
for x, num in D.items():
ans += (x%minS) * num % MOD
ans %= MOD
print(ans)
``` | output | 1 | 98,445 | 16 | 196,891 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,446 | 16 | 196,892 |
"Correct Solution:
```
N,X=map(int,input().split())
S=list(map(int,input().split()))
pr=10**9+7
b={X:1}
S.sort(reverse=1)
def ir(k,v):
global d
if k in d:
d[k]=(d[k]+v)%pr
else:
d[k]=v
for i in range(N):
t=S[i]
n=N-i-1
d={}
for k,v in b.items():
ir(k%t,v)
ir(k,v*n)
b=d
a=0
for k,v in b.items():
a=(a+k*v)%pr
print(a)
``` | output | 1 | 98,446 | 16 | 196,893 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,447 | 16 | 196,894 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict,deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
res = list(sys.stdin.readline())
if res[-1] == "\n":
return res[:-1]
return res
def IR(n):
return [I() for i in range(n)]
def LIR(n):
return [LI() for i in range(n)]
def SR(n):
return [S() for i in range(n)]
def LSR(n):
return [LS() for i in range(n)]
sys.setrecursionlimit(1000000)
mod = 1000000007
# 挿入dp
def solve():
n,x = LI()
s = LI()
s.sort()
dp = [[0]*(x+1) for i in range(n+1)] # dp[i][j] := スタート時点の値がjの時に最初のi個の順列すべてを試し、えられる総和
for j in range(x+1):
dp[0][j] = j # dpの定義より明らか
for i in range(n):
si = s[i]
ni = i+1
nd = dp[i][j%si] # 先頭にsiを挿入 (スタートの値がj%siとなる)
nd += i*dp[i][j] # 先頭以外にsiを挿入 (スタートの値も間の値も変わらない)
dp[ni][j] += nd
if dp[ni][j] >= mod:
dp[ni][j] %= mod
print(dp[n][x])
return
#Solve
if __name__ == "__main__":
solve()
``` | output | 1 | 98,447 | 16 | 196,895 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,448 | 16 | 196,896 |
"Correct Solution:
```
mod=10**9+7
N,X=map(int,input().split())
S=[int(i) for i in input().split()]
S.sort(reverse=True)
Factorial=[1]*(N+1)
for i in range(1,N+1):
Factorial[i]=Factorial[i-1]*(i)%mod
def power(x,y):
if y==0:
return 1
elif y==1:
return x%mod
elif y%2==0:
return power(x,y//2)**2%mod
else:
return ((power(x,y//2)**2)*x)%mod
inv=[0]*(N+1)
for i in range(N+1):
inv[i]=power(i,mod-2)
dp=[[0]*(X+1) for i in range(N+1)]
for x in range(X+1):
dp[N][x]=x
for i in range(N)[::-1]:
for x in range(X+1):
dp[i][x]=dp[i+1][x%S[i]]+(N-i-1)*dp[i+1][x]
dp[i][x]%=mod
print((dp[0][X])%mod)
``` | output | 1 | 98,448 | 16 | 196,897 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,449 | 16 | 196,898 |
"Correct Solution:
```
N,X = map(int,input().split())
S = list(map(int,input().split()))
S.sort()
mod = 10**9+7
dp = [[x]+[0]*N for x in range(X+1)]
for x in range(X+1):
for n in range(1,N+1):
dp[x][n] = (dp[x%S[n-1]][n-1] + (n-1)*dp[x][n-1])%mod
print(dp[X][N])
``` | output | 1 | 98,449 | 16 | 196,899 |
Provide a correct Python 3 solution for this coding contest problem.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259 | instruction | 0 | 98,450 | 16 | 196,900 |
"Correct Solution:
```
from collections import defaultdict
inpl = lambda: list(map(int,input().split()))
M = 10**9 + 7
N, X = inpl()
S = sorted(inpl())
P = defaultdict(lambda: -1)
def ModuloOperations(i, x):
if i == 0:
return x
else:
if P[(i,x)] < 0:
P[(i,x)] = (ModuloOperations(i-1,x)*(i-1) + ModuloOperations(i-1, x % S[i-1])) % M
return P[(i,x)]
print(ModuloOperations(N,X))
``` | output | 1 | 98,450 | 16 | 196,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
MOD = 10**9 + 7
N,X = map(int,input().split())
S = list(map(int,input().split()))
S.sort()
S = [None] + S
dp = [[0 for i in range(X+1)] for j in range(N+1)]
dp[1] = [i % S[1] for i in range(X+1)]
for n in range(2, N+1):
for x in range(X+1):
dp[n][x] = (dp[n-1][x] * (n-1) + dp[n-1][x%S[n]]) % MOD
print(dp[N][X])
``` | instruction | 0 | 98,451 | 16 | 196,902 |
Yes | output | 1 | 98,451 | 16 | 196,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
N,X=map(int,input().split())
S=list(map(int,input().split()))
S.sort()
mod=10**9+7
dp=[[0 for i in range(10**5+1)] for j in range(N)]
for i in range(10**5+1):
dp[0][i]=i%S[0]
for i in range(1,N):
for j in range(10**5+1):
dp[i][j]=(i*dp[i-1][j]+dp[i-1][j%S[i]])%mod
print(dp[N-1][X])
``` | instruction | 0 | 98,452 | 16 | 196,904 |
Yes | output | 1 | 98,452 | 16 | 196,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
def examA():
ABC =LI(); ABC.sort()
if ABC[0]==ABC[-1]:
print("Yes")
else:
print("No")
return
def examB():
N = I()
S = SI()
red = S.count("R")
if red>N//2:
print("Yes")
else:
print("No")
return
def examC():
N,Q = LI()
S = SI()
T = [LSI()for _ in range(Q)]
l = -1; r = N
while(r-l>1):
cur = (r+l)//2
now = copy.deepcopy(cur)
flag = False
for t,d in T:
if S[now]==t:
if d=="R":
now += 1
else:
now -= 1
if now==N:
flag = True
break
if now==-1:
break
if flag:
r = cur
else:
l = cur
R = r
l = -1; r = N
while(r-l>1):
cur = (r+l)//2
now = copy.deepcopy(cur)
flag = False
for t,d in T:
if S[now]==t:
if d=="R":
now += 1
else:
now -= 1
if now==-1:
flag = True
break
if now==N:
break
if flag:
l = cur
else:
r = cur
L = l
ans = max(0,R-L-1)
print(ans)
return
def examD():
N, X = LI()
S = LI()
S.sort(reverse=True)
dp = [[0]*(X+1)for _ in range(N+1)]
dp[0][X] = 1
for i in range(N):
s = S[i]
for j in range(X+1):
dp[i+1][j%s] += dp[i][j]
dp[i+1][j%s] %= mod
for j in range(X+1):
dp[i+1][j] += dp[i][j]*(N-i-1)
dp[i+1][j] %= mod
#print(dp)
ans = 0
for i,d in enumerate(dp[-1]):
ans += d*i
ans %= mod
print(ans)
return
def examE():
ans = 0
print(ans)
return
def examF():
ans = 0
print(ans)
return
import sys,copy,bisect,itertools,heapq,math
from heapq import heappop,heappush,heapify
from collections import Counter,defaultdict,deque
def I(): return int(sys.stdin.readline())
def LI(): return list(map(int,sys.stdin.readline().split()))
def LSI(): return list(map(str,sys.stdin.readline().split()))
def LS(): return sys.stdin.readline().split()
def SI(): return sys.stdin.readline().strip()
global mod,mod2,inf,alphabet
mod = 10**9 + 7
mod2 = 998244353
inf = 10**18
alphabet = [chr(ord('a') + i) for i in range(26)]
if __name__ == '__main__':
examD()
"""
"""
``` | instruction | 0 | 98,453 | 16 | 196,906 |
Yes | output | 1 | 98,453 | 16 | 196,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
from collections import defaultdict
n,x = map(int,input().split())
a = list(map(int,input().split()))
a.sort(reverse=True)
mod = 10**9+7
dp = [defaultdict(int) for i in range(n+1)]
dp[0][x] = 1
for i in range(1,n+1):
for j in dp[i-1].keys():
k = j%a[i-1]
dp[i][j] = (dp[i][j]+dp[i-1][j]*(n-i))%mod
dp[i][k] = (dp[i][k]+dp[i-1][j])%mod
ans = 0
for i,x in dp[n].items():
ans = (ans+i*x)%mod
print(ans)
``` | instruction | 0 | 98,454 | 16 | 196,908 |
Yes | output | 1 | 98,454 | 16 | 196,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
mod = 10**9+7
n,m = map(int,input().split())
s = list(map(int,input().split()))
s.sort()
s = [None] + s
dp = [[0 for i in range(m+1)] for j in range(n+1)]
dp[1] = [i % s[1] for i in range(m+1)]
for i in range(2,n+1):
for j in range(m+1):
dp[i][j] = (dp[i-1][j] * (i-1) + dp[n-1][j%s[i]]) % mod
print(dp[n][m])
``` | instruction | 0 | 98,455 | 16 | 196,910 |
No | output | 1 | 98,455 | 16 | 196,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
N, X = map(int, input().split())
S = list(map(int, input().split()))
numbers = S[:]
def dps(numbers, x):
if len(numbers) == 1:
return x % numbers[0]
ret = 0
for i, n in enumerate(numbers):
x_mod = x % n
if x_mod == 0:
ret += x_mod
ret += dps(numbers[0:i] + numbers[i+1:], x_mod)
return ret
ans = dps(numbers, X)
ans = ans % (10 ** 9 + 7)
print(ans)
``` | instruction | 0 | 98,456 | 16 | 196,912 |
No | output | 1 | 98,456 | 16 | 196,913 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
import math
N, X = map(int, input().split())
Ss = sorted(list(map(int, input().split())))
memo = {}
MOD = 10 ** 9 + 7
def mod(x, ss):
if (x, tuple(ss)) in memo:
print('hit')
return memo[(x, tuple(ss))]
if len(ss) == 1:
return x % ss[0]
if x < ss[0]:
res = x * math.factorial(len(ss))
memo[(x, tuple(ss))] = res
return res
total = 0
for s in ss:
ss2 = ss[:]
ss2.remove(s)
total = (total + mod(x % s, ss2)) % MOD
memo[(x, tuple(ss))] = total
return total
print(mod(X, Ss))
``` | instruction | 0 | 98,457 | 16 | 196,914 |
No | output | 1 | 98,457 | 16 | 196,915 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Snuke has a blackboard and a set S consisting of N integers. The i-th element in S is S_i.
He wrote an integer X on the blackboard, then performed the following operation N times:
* Choose one element from S and remove it.
* Let x be the number written on the blackboard now, and y be the integer removed from S. Replace the number on the blackboard with x \bmod {y}.
There are N! possible orders in which the elements are removed from S. For each of them, find the number that would be written on the blackboard after the N operations, and compute the sum of all those N! numbers modulo 10^{9}+7.
Constraints
* All values in input are integers.
* 1 \leq N \leq 200
* 1 \leq S_i, X \leq 10^{5}
* S_i are pairwise distinct.
Input
Input is given from Standard Input in the following format:
N X
S_1 S_2 \ldots S_{N}
Output
Print the answer.
Examples
Input
2 19
3 7
Output
3
Input
5 82
22 11 6 5 13
Output
288
Input
10 100000
50000 50001 50002 50003 50004 50005 50006 50007 50008 50009
Output
279669259
Submitted Solution:
```
import numpy as np
N, X = map(int, input().split())
S = list(map(int, input().split()))
MOD = 1000000007
numbers = S[:]
numbers.sort()
dp = np.zeros((N+1, X+1), dtype=int)
dp = np.arange(X+1)
dp_n = []
for n in numbers:
dp_n = np.zeros((X+1), dtype=np.int64)
dp_n += [dp[x % n] for x in range(X+1)]
dp_n = dp_n % MOD
dp_n += dp * i % MOD
dp_n = dp_n % MOD
dp = dp_n
print(int(dp_n[X]) % MOD)
``` | instruction | 0 | 98,458 | 16 | 196,916 |
No | output | 1 | 98,458 | 16 | 196,917 |
Provide a correct Python 3 solution for this coding contest problem.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5 | instruction | 0 | 99,333 | 16 | 198,666 |
"Correct Solution:
```
n,a,b=int(input()),list(map(int,input().split()))+[0],list(map(int,input().split()))+[0]
for i in range(n):
a[n]^=a[i]
b[n]^=b[i]
na,nb=sorted(a),sorted(b)
if na!=nb:
print("-1")
exit()
f=dict()
def find(x):
if f[x]==x:
return x
else:
f[x]=find(f[x])
return f[x]
ans=0
for i in range(n):
if a[i]!=b[i]:
f[a[i]]=a[i]
f[a[n]]=a[n]
for i in range(n):
if a[i]!=b[i]:
ans+=1
f[find(b[i])]=find(a[i])
for i in f:
if i==f[i]:
ans+=1
print(ans-1)
``` | output | 1 | 99,333 | 16 | 198,667 |
Provide a correct Python 3 solution for this coding contest problem.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5 | instruction | 0 | 99,334 | 16 | 198,668 |
"Correct Solution:
```
class UnionFindVerSize():
def __init__(self, N):
self._parent = [n for n in range(0, N)]
self._size = [1] * N
def find_root(self, x):
if self._parent[x] == x: return x
self._parent[x] = self.find_root(self._parent[x])
return self._parent[x]
def unite(self, x, y):
gx = self.find_root(x)
gy = self.find_root(y)
if gx == gy: return
if self._size[gx] < self._size[gy]:
self._parent[gx] = gy
self._size[gy] += self._size[gx]
else:
self._parent[gy] = gx
self._size[gx] += self._size[gy]
def get_size(self, x):
return self._size[self.find_root(x)]
def is_same_group(self, x, y):
return self.find_root(x) == self.find_root(y)
def calc_group_num(self):
N = len(self._parent)
ans = 0
for i in range(N):
if self.find_root(i) == i:
ans += 1
return ans
from collections import Counter
N=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
A=0
for i in range(N):
A^=a[i]
B=0
for i in range(N):
B^=b[i]
a.append(A)
b.append(B)
if Counter(a)!=Counter(b):
exit(print(-1))
val=set([])
for i in range(N+1):
if a[i]!=b[i]:
val.add(a[i])
if not val:
exit(print(0))
val=list(val)
val.sort()
comp={i:e for e,i in enumerate(val)}
n=max(comp[d] for d in comp)+1
uf=UnionFindVerSize(n)
check=False
cnt=0
for i in range(N):
if a[i]!=b[i]:
uf.unite(comp[a[i]],comp[b[i]])
if a[i]==b[-1]:
check=True
cnt+=1
print(cnt+uf.calc_group_num()-int(check))
``` | output | 1 | 99,334 | 16 | 198,669 |
Provide a correct Python 3 solution for this coding contest problem.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5 | instruction | 0 | 99,335 | 16 | 198,670 |
"Correct Solution:
```
def examA():
N = I()
ans = 0
print(ans)
return
def examB():
ans = 0
print(ans)
return
def examC():
ans = 0
print(ans)
return
def examD():
class UnionFind():
def __init__(self, n):
self.parent = [-1 for _ in range(n)]
# 正==子: 根の頂点番号 / 負==根: 連結頂点数
def find(self, x):
# 要素xが属するグループの根を返す
if self.parent[x] < 0:
return x
else:
self.parent[x] = self.find(self.parent[x])
return self.parent[x]
def unite(self, x, y):
# 要素xが属するグループと要素yが属するグループとを併合する
x, y = self.find(x), self.find(y)
if x == y:
return False
else:
if self.size(x) < self.size(y):
x, y = y, x
self.parent[x] += self.parent[y]
self.parent[y] = x
def same(self, x, y):
# 要素x, yが同じグループに属するかどうかを返す
return self.find(x) == self.find(y)
def size(self, x):
# 要素xが属するグループのサイズ（要素数）を返す
x = self.find(x)
return -self.parent[x]
def is_root(self, x):
# 要素の根をリストで返す
return self.parent[x] < 0
def roots(self):
# すべての根の要素をリストで返す
return [i for i, x in enumerate(self.parent) if x < 0]
def members(self, x):
# 要素xが属するグループに属する要素をリストで返す
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def group_count(self):
# グループの数を返す
return len(self.roots())
def all_group_members(self):
# {ルート要素: [そのグループに含まれる要素のリスト], ...}の辞書を返す
return {r: self.members(r) for r in self.roots()}
N = I()
A = LI()
B = LI()
uf = UnionFind(N+1)
Da = defaultdict(list)
Db = defaultdict(list)
bita = 0
same = [False]*(N+1)
for i in range(N):
if A[i]==B[i]:
same[i] = True
if sum(same)==N:
print(0)
return
for i,a in enumerate(A):
bita ^= a
if same[i]:
continue
Da[a].append(i)
Da[bita].append(N)
bitb = 0
for i,b in enumerate(B):
bitb ^= b
if same[i]:
continue
Db[b].append(i)
Db[bitb].append(N)
#print(Da)
#print(Db)
for key,a in Da.items():
if len(Db[key])!=len(a):
print(-1)
return
for key,a in Da.items():
uf.unite(a[0],Db[key][0])
if len(a)==1:
continue
for i in a[1:]:
uf.unite(a[0],i)
for b in Db.values():
if len(b)==1:
continue
for i in b[1:]:
uf.unite(b[0],i)
if uf.size(N)==N-sum(same):
ans = uf.size(N)
if bita!=bitb:
ans -= 1
print(ans)
return
ans = 0
used = [False]*(N+1)
for i in range(N):
#print(ans)
if same[i]:
continue
p = uf.find(i)
if used[p]:
continue
used[p] = True
ans += (-uf.parent[p]+1)
#print(ans)
#if sum(used)>1:
# ans += 1
if uf.size(N)>1:
ans -= 1
if bita!=bitb or len(Da[bita])>1:
ans -= 1
print(ans)
return
def examE():
ans = 0
print(ans)
return
def examF():
ans = 0
print(ans)
return
def test():
i = I()
li = LI()
lsi = LSI()
si = LS()
print(i)
print(li)
print(lsi)
print(si)
return
from decimal import Decimal as dec
import sys,bisect,itertools,heapq,math,random
from copy import deepcopy
from heapq import heappop,heappush,heapify
from collections import Counter,defaultdict,deque
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
def I(): return int(input())
def LI(): return list(map(int,sys.stdin.readline().split()))
def DI(): return dec(input())
def LDI(): return list(map(dec,sys.stdin.readline().split()))
def LSI(): return list(map(str,sys.stdin.readline().split()))
def LS(): return sys.stdin.readline().split()
def SI(): return sys.stdin.readline().strip()
global mod,mod2,inf,alphabet,_ep
mod = 10**9 + 7
mod2 = 998244353
inf = 10**18
_ep = 10**(-12)
alphabet = [chr(ord('a') + i) for i in range(26)]
sys.setrecursionlimit(10**7)
if __name__ == '__main__':
examD()
"""
5
0 2 3 6 9
2 9 0 6 3
5
0 2 3 6 9
2 9 0 6 14
# 4
5
0 2 3 6 9
2 3 0 6 14
# 5
5
0 2 3 6 9
2 0 3 9 14
# 5
4
1 2 4 8
2 1 8 4
# 6
"""
``` | output | 1 | 99,335 | 16 | 198,671 |
Provide a correct Python 3 solution for this coding contest problem.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5 | instruction | 0 | 99,336 | 16 | 198,672 |
"Correct Solution:
```
from collections import defaultdict
from functools import reduce
from operator import xor
def dfs(s, links, fixed):
q = [s]
while q:
v = q.pop()
if fixed[v]:
continue
fixed[v] = True
q.extend(links[v])
def solve(n, aaa, bbb):
a0 = reduce(xor, aaa, 0)
b0 = reduce(xor, bbb, 0)
aaa.append(a0)
bbb.append(b0)
ad = defaultdict(set)
bd = defaultdict(set)
for i, a in enumerate(aaa):
ad[a].add(i)
for i, b in enumerate(bbb):
bd[b].add(i)
ac = {a: len(s) for a, s in ad.items()}
bc = {b: len(s) for b, s in bd.items()}
if ac != bc:
return -1
links = defaultdict(set)
ans = 0
for a, b in zip(aaa, bbb):
if a == b:
continue
ans += 1
links[a].add(b)
if not ans:
return 0
if a0 == b0:
links[a0].add(b0)
else:
ans -= 1
fixed = {a: False for a in links}
for a in links:
if fixed[a]:
continue
ans += 1
dfs(a, links, fixed)
return ans - 1
n = int(input())
aaa = list(map(int, input().split()))
bbb = list(map(int, input().split()))
print(solve(n, aaa, bbb))
``` | output | 1 | 99,336 | 16 | 198,673 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5
Submitted Solution:
```
print(-1)
``` | instruction | 0 | 99,337 | 16 | 198,674 |
No | output | 1 | 99,337 | 16 | 198,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5
Submitted Solution:
```
def examA():
N = I()
ans = 0
print(ans)
return
def examB():
ans = 0
print(ans)
return
def examC():
ans = 0
print(ans)
return
def examD():
class UnionFind():
def __init__(self, n):
self.parent = [-1 for _ in range(n)]
# 正==子: 根の頂点番号 / 負==根: 連結頂点数
def find(self, x):
# 要素xが属するグループの根を返す
if self.parent[x] < 0:
return x
else:
self.parent[x] = self.find(self.parent[x])
return self.parent[x]
def unite(self, x, y):
# 要素xが属するグループと要素yが属するグループとを併合する
x, y = self.find(x), self.find(y)
if x == y:
return False
else:
if self.size(x) < self.size(y):
x, y = y, x
self.parent[x] += self.parent[y]
self.parent[y] = x
def same(self, x, y):
# 要素x, yが同じグループに属するかどうかを返す
return self.find(x) == self.find(y)
def size(self, x):
# 要素xが属するグループのサイズ（要素数）を返す
x = self.find(x)
return -self.parent[x]
def is_root(self, x):
# 要素の根をリストで返す
return self.parent[x] < 0
def roots(self):
# すべての根の要素をリストで返す
return [i for i, x in enumerate(self.parent) if x < 0]
def members(self, x):
# 要素xが属するグループに属する要素をリストで返す
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def group_count(self):
# グループの数を返す
return len(self.roots())
def all_group_members(self):
# {ルート要素: [そのグループに含まれる要素のリスト], ...}の辞書を返す
return {r: self.members(r) for r in self.roots()}
N = I()
A = LI()
B = LI()
uf = UnionFind(N+1)
Da = defaultdict(list)
Db = defaultdict(list)
bita = 0
same = [False]*(N+1)
for i in range(N):
if A[i]==B[i]:
same[i] = True
if sum(same)==N:
print(0)
return
for i,a in enumerate(A):
bita ^= a
if same[i]:
continue
Da[a].append(i)
Da[bita].append(N)
bitb = 0
for i,b in enumerate(B):
bitb ^= b
if same[i]:
continue
Db[b].append(i)
Db[bitb].append(N)
#print(Da)
#print(Db)
for key,a in Da.items():
if len(Db[key])!=len(a):
print(-1)
return
for key,a in Da.items():
uf.unite(a[0],Db[key][0])
if len(a)==1:
continue
for i in a[1:]:
uf.unite(a[0],i)
for b in Db.values():
if len(b)==1:
continue
for i in b[1:]:
uf.unite(b[0],i)
if uf.size(N)==N-sum(same):
ans = uf.size(N)
if bita!=bitb:
ans -= 1
print(ans)
return
ans = -1
used = [False]*(N+1)
for i in range(N+1):
#print(ans)
if same[i]:
continue
p = uf.find(i)
if used[p]:
continue
used[p] = True
ans += (-uf.parent[p]+1)
#print(ans)
#if sum(used)>1:
# ans += 1
if uf.size(N)>1 or bita!=bitb:
ans -= 1
print(ans)
return
def examE():
ans = 0
print(ans)
return
def examF():
ans = 0
print(ans)
return
def test():
i = I()
li = LI()
lsi = LSI()
si = LS()
print(i)
print(li)
print(lsi)
print(si)
return
from decimal import Decimal as dec
import sys,bisect,itertools,heapq,math,random
from copy import deepcopy
from heapq import heappop,heappush,heapify
from collections import Counter,defaultdict,deque
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
def I(): return int(input())
def LI(): return list(map(int,sys.stdin.readline().split()))
def DI(): return dec(input())
def LDI(): return list(map(dec,sys.stdin.readline().split()))
def LSI(): return list(map(str,sys.stdin.readline().split()))
def LS(): return sys.stdin.readline().split()
def SI(): return sys.stdin.readline().strip()
global mod,mod2,inf,alphabet,_ep
mod = 10**9 + 7
mod2 = 998244353
inf = 10**18
_ep = 10**(-12)
alphabet = [chr(ord('a') + i) for i in range(26)]
sys.setrecursionlimit(10**7)
if __name__ == '__main__':
examD()
"""
5
0 2 3 6 9
2 9 0 6 3
5
0 2 3 6 9
2 9 0 6 14
# 4
5
0 2 3 6 9
2 3 0 6 14
# 5
5
0 2 3 6 9
2 0 3 9 14
# 5
"""
``` | instruction | 0 | 99,338 | 16 | 198,676 |
No | output | 1 | 99,338 | 16 | 198,677 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5
Submitted Solution:
```
from collections import Counter
n = int(input())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
bonusNumber = 0
for i in range(n):
bonusNumber ^= a[i]
aa = Counter({bonusNumber: 1})
bb = Counter()
for i in range(n):
aa[a[i]] += 1
bb[b[i]] += 1
for x in bb.keys():
if bb[x] > aa[x]:
print(-1)
exit()
#############################
ans = 0
tmp = []
first = True
for i in range(n):
if first and b[i] == bonusNumber and b[i] != a[i]:
bonusNumber = a[i]
a[i] = b[i]
ans += 1
first = False
elif b[i] != a[i]:
tmp.append(b[i])
while bonusNumber in tmp:
tmp.remove(bonusNumber)
bonusNumber = a[b.index(bonusNumber)]
ans += 1
if len(tmp) == 0:
print(ans)
else:
ans += len(tmp) + 1
print(ans)
``` | instruction | 0 | 99,339 | 16 | 198,678 |
No | output | 1 | 99,339 | 16 | 198,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a sequence of length N: a = (a_1, a_2, ..., a_N). Here, each a_i is a non-negative integer.
Snuke can repeatedly perform the following operation:
* Let the XOR of all the elements in a be x. Select an integer i (1 ≤ i ≤ N) and replace a_i with x.
Snuke's objective is to match a with another sequence b = (b_1, b_2, ..., b_N). Here, each b_i is a non-negative integer.
Determine whether the objective is achievable, and find the minimum necessary number of operations if the answer is positive.
Constraints
* 2 ≤ N ≤ 10^5
* a_i and b_i are integers.
* 0 ≤ a_i, b_i < 2^{30}
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 ... a_N
b_1 b_2 ... b_N
Output
If the objective is achievable, print the minimum necessary number of operations. Otherwise, print `-1` instead.
Examples
Input
3
0 1 2
3 1 0
Output
2
Input
3
0 1 2
0 1 2
Output
0
Input
2
1 1
0 0
Output
-1
Input
4
0 1 2 3
1 0 3 2
Output
5
Submitted Solution:
```
n,a,b=int(input()),list(map(int,input().split()))+[0],list(map(int,input().split()))+[0]
for i in range(n):
a[n]^=a[i]
b[n]^=b[i]
na,nb=sorted(a),sorted(b)
if sum([na[i]!=nb[i] for i in range(n+1)]):
print("-1")
exit()
f=dict()
def find(x):
if f[x]==x:
return x
else:
f[x]=find(f[x])
return f[x]
ans=0
for i in range(n):
if a[i]!=b[i]:
f[a[i]]=a[i]
f[a[n]]=a[n]
for i in range(n):
if a[i]!=b[i]:
ans+=1
f[find(b[i])]=find(a[i])
for i,j in f:
if i==j:
ans+=1
print(ans-1)
``` | instruction | 0 | 99,340 | 16 | 198,680 |
No | output | 1 | 99,340 | 16 | 198,681 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,207 | 16 | 200,414 |
"Correct Solution:
```
N, x = map(int, input().split())
a = list(map(int, input().split()))
cost = 0
num = 0
for i in range(N-1):
cost = max(0, a[i] + a[i+1] - x)
num += cost
a[i+1] = max(0, a[i+1] - cost)
print(num)
``` | output | 1 | 100,207 | 16 | 200,415 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,208 | 16 | 200,416 |
"Correct Solution:
```
N,x = map(int,input().split())
A = list(map(int,input().split()))
ans = 0
ans += max(0,A[0]-x)
A[0] -= max(0,A[0]-x)
for i in range(N-1) :
ans += max(0,A[i]+A[i+1]-x)
A[i+1] -= max(0,A[i]+A[i+1]-x)
print(ans)
``` | output | 1 | 100,208 | 16 | 200,417 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,209 | 16 | 200,418 |
"Correct Solution:
```
N,x=map(int,input().split())
l=list(map(int,input().split()))
c=0
if l[0]>x:
c+=(l[0]-x)
l[0]=x
for i in range(len(l)-1):
if l[i]+l[i+1]>x:
c+=(l[i+1]+l[i]-x)
l[i+1]=x-l[i]
print(c)
``` | output | 1 | 100,209 | 16 | 200,419 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,210 | 16 | 200,420 |
"Correct Solution:
```
a,b=map(int,input().split())
L=list(map(int,input().split()))
s=0
if L[0]>b:
s+=L[0]-b
L[0]=b
for i in range(1,a):
if L[i-1]+L[i]>b:
s+=L[i]-b+L[i-1]
L[i]=b-L[i-1]
print(s)
``` | output | 1 | 100,210 | 16 | 200,421 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,211 | 16 | 200,422 |
"Correct Solution:
```
N,x=map(int,input().split())
A=list(map(int,input().split()))
count=0
for i in range(N-1):
if A[i]+A[i+1]>x:
count+=A[i]+A[i+1]-x
A[i+1]=max(x-A[i],0)
print(count)
``` | output | 1 | 100,211 | 16 | 200,423 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,212 | 16 | 200,424 |
"Correct Solution:
```
N,x=map(int,input().split())
A=list(map(int,input().split()))
if A[0]>x:
cnt=A[0]-x
A[0]=A[0]-cnt
else:
cnt=0
for i in range(1,N):
gap=A[i]+A[i-1]-x
if gap>0:
cnt+=gap
A[i]-=gap
print(cnt)
``` | output | 1 | 100,212 | 16 | 200,425 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,213 | 16 | 200,426 |
"Correct Solution:
```
N,X,*A = map(int,open(0).read().split())
A+=[0]
s = 0
for n in range(N):
d=max(0,A[n]+A[n-1]-X)
s+=d
A[n]-=d
print(s)
``` | output | 1 | 100,213 | 16 | 200,427 |
Provide a correct Python 3 solution for this coding contest problem.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10 | instruction | 0 | 100,214 | 16 | 200,428 |
"Correct Solution:
```
n, x = map(int, input().split())
a = list(map(int, input().split())) + [0]
ans = 0
for i in range(1, n + 1):
if a[i] + a[i - 1] > x:
ans += a[i] + a[i - 1] - x
a[i] -= a[i] + a[i - 1] - x
print(ans)
``` | output | 1 | 100,214 | 16 | 200,429 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N boxes arranged in a row. Initially, the i-th box from the left contains a_i candies.
Snuke can perform the following operation any number of times:
* Choose a box containing at least one candy, and eat one of the candies in the chosen box.
His objective is as follows:
* Any two neighboring boxes contain at most x candies in total.
Find the minimum number of operations required to achieve the objective.
Constraints
* 2 ≤ N ≤ 10^5
* 0 ≤ a_i ≤ 10^9
* 0 ≤ x ≤ 10^9
Input
The input is given from Standard Input in the following format:
N x
a_1 a_2 ... a_N
Output
Print the minimum number of operations required to achieve the objective.
Examples
Input
3 3
2 2 2
Output
1
Input
6 1
1 6 1 2 0 4
Output
11
Input
5 9
3 1 4 1 5
Output
0
Input
2 0
5 5
Output
10
Submitted Solution:
```
n, x, *A = map(int, open(0).read().split())
s = 0
if A[0] > x:
s += A[0] - x
A[0] = x
for i in range(1, n):
if A[i] + A[i-1] > x:
s += A[i] + A[i-1] - x
A[i] = x - A[i-1]
print(s)
``` | instruction | 0 | 100,215 | 16 | 200,430 |
Yes | output | 1 | 100,215 | 16 | 200,431 |
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