message stringlengths 2 16.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 575 109k | cluster float64 16 16 | __index_level_0__ int64 1.15k 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Cat Snuke is learning to write characters. Today, he practiced writing digits `1` and `9`, but he did it the other way around.
You are given a three-digit integer n written by Snuke. Print the integer obtained by replacing each digit `1` with `9` and each digit `9` with `1` in n.
Constraints
* 111 \leq n \leq 999
* n is an integer consisting of digits `1` and `9`.
Input
Input is given from Standard Input in the following format:
n
Output
Print the integer obtained by replacing each occurrence of `1` with `9` and each occurrence of `9` with `1` in n.
Examples
Input
119
Output
991
Input
999
Output
111
Submitted Solution:
```
print(input().replace("9","n").replace("1","o").replace("o","1").replace("n","9"))
``` | instruction | 0 | 70,583 | 16 | 141,166 |
No | output | 1 | 70,583 | 16 | 141,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Cat Snuke is learning to write characters. Today, he practiced writing digits `1` and `9`, but he did it the other way around.
You are given a three-digit integer n written by Snuke. Print the integer obtained by replacing each digit `1` with `9` and each digit `9` with `1` in n.
Constraints
* 111 \leq n \leq 999
* n is an integer consisting of digits `1` and `9`.
Input
Input is given from Standard Input in the following format:
n
Output
Print the integer obtained by replacing each occurrence of `1` with `9` and each occurrence of `9` with `1` in n.
Examples
Input
119
Output
991
Input
999
Output
111
Submitted Solution:
```
#112a
s=list(input())
for i in range(3):
if s[i]==1:
s[i]=9
else:
s[i]=1
print(s)
``` | instruction | 0 | 70,584 | 16 | 141,168 |
No | output | 1 | 70,584 | 16 | 141,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Cat Snuke is learning to write characters. Today, he practiced writing digits `1` and `9`, but he did it the other way around.
You are given a three-digit integer n written by Snuke. Print the integer obtained by replacing each digit `1` with `9` and each digit `9` with `1` in n.
Constraints
* 111 \leq n \leq 999
* n is an integer consisting of digits `1` and `9`.
Input
Input is given from Standard Input in the following format:
n
Output
Print the integer obtained by replacing each occurrence of `1` with `9` and each occurrence of `9` with `1` in n.
Examples
Input
119
Output
991
Input
999
Output
111
Submitted Solution:
```
s = input()
ss = ""
for i in range(len(s)):
if s[i] == "1"
ss += "9"
else:
ss += "1"
print(ss)
``` | instruction | 0 | 70,585 | 16 | 141,170 |
No | output | 1 | 70,585 | 16 | 141,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Cat Snuke is learning to write characters. Today, he practiced writing digits `1` and `9`, but he did it the other way around.
You are given a three-digit integer n written by Snuke. Print the integer obtained by replacing each digit `1` with `9` and each digit `9` with `1` in n.
Constraints
* 111 \leq n \leq 999
* n is an integer consisting of digits `1` and `9`.
Input
Input is given from Standard Input in the following format:
n
Output
Print the integer obtained by replacing each occurrence of `1` with `9` and each occurrence of `9` with `1` in n.
Examples
Input
119
Output
991
Input
999
Output
111
Submitted Solution:
```
n=input()
n.replace(1,x)
n.replace(9,1)
print(n.replace(x,9))
``` | instruction | 0 | 70,586 | 16 | 141,172 |
No | output | 1 | 70,586 | 16 | 141,173 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,603 | 16 | 141,206 |
"Correct Solution:
```
from bisect import*
r=lambda:sorted(map(int,input().split()))
N=r()[0]
A,B,C,w,i=r(),r(),r(),[0]*(N+1),N
while i:w[i-1]=w[i]+N-bisect(C,B[i-1]);i-=1
print(sum(w[bisect(B,A[i])]for i in range(N)))
``` | output | 1 | 70,603 | 16 | 141,207 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,604 | 16 | 141,208 |
"Correct Solution:
```
import bisect
N=int(input())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
C=list(map(int,input().split()))
A.sort()
B.sort()
C.sort()
ans=0
for b in B: #O(N)
s = bisect.bisect_left(A,b) #O(logN)
t = bisect.bisect_right(C,b) #O(logN)
#print(s,N-t,s*(N-t))
ans += s*(N-t)
print(ans)
``` | output | 1 | 70,604 | 16 | 141,209 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,605 | 16 | 141,210 |
"Correct Solution:
```
from bisect import bisect_right as br
N=int(input())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
C=list(map(int,input().split()))
A.sort()
B.sort()
C.sort()
ans=0
Bc=[]
for i in range(N):
Bc.append(N-br(C,B[i]))
S=[sum(Bc)]
for j in range(N):
S.append(S[j]-Bc[j])
for a in A:
b=br(B,a)
ans+=S[b]
print(ans)
``` | output | 1 | 70,605 | 16 | 141,211 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,606 | 16 | 141,212 |
"Correct Solution:
```
# ABC 84, C - sunuke festival
import bisect
n = int(input())
A = sorted([int(el) for el in input().split(' ')])
B = [int(el) for el in input().split(' ')]
C = sorted([int(el) for el in input().split(' ')])
total = 0
for b in B:
total += bisect.bisect_left(A, b) * (len(C) - bisect.bisect_right(C, b))
print(total)
``` | output | 1 | 70,606 | 16 | 141,213 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,607 | 16 | 141,214 |
"Correct Solution:
```
from bisect import *;N=int(input());A,B,C=[sorted(map(int,input().split())) for _ in "ABC"];print(sum([bisect_left(A,i)*(N-bisect_right(C,i)) for i in B]))
``` | output | 1 | 70,607 | 16 | 141,215 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,608 | 16 | 141,216 |
"Correct Solution:
```
from bisect import bisect_right
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = list(map(int, input().split()))
b.sort()
c.sort()
ans = 0
bcb_cum = [0] * (n+1)
for i in range(n):
bcb_cum[i+1] = bcb_cum[i] + n - bisect_right(c, b[i])
for x in a:
l = bisect_right(b, x)
ans += bcb_cum[n] - bcb_cum[l]
print(ans)
``` | output | 1 | 70,608 | 16 | 141,217 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,609 | 16 | 141,218 |
"Correct Solution:
```
import bisect
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))
a.sort()
b.sort()
c.sort()
ans=0
for i in range(n):
a_l=bisect.bisect_left(a,b[i])
c_l=bisect.bisect(c,b[i])
ans+=a_l*(n-c_l)
print(ans)
``` | output | 1 | 70,609 | 16 | 141,219 |
Provide a correct Python 3 solution for this coding contest problem.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87 | instruction | 0 | 70,610 | 16 | 141,220 |
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))
a.sort()
b.sort()
c.sort()
from bisect import bisect_left
from bisect import bisect_right
count = 0
for bi in range(n):
c_right = bisect_right(c, b[bi])
a_left = bisect_left(a, b[bi])
count += (n-c_right) * a_left
print(count)
``` | output | 1 | 70,610 | 16 | 141,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
from bisect import*;(N,),A,B,C=[sorted(map(int,input().split()))for _ in[0]*4];print(sum(bisect_left(A,b)*(N-bisect(C,b))for b in B))
``` | instruction | 0 | 70,611 | 16 | 141,222 |
Yes | output | 1 | 70,611 | 16 | 141,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
N=int(input())
A=list(map(int,input().split()))
B=list(map(int,input().split()))
C=list(map(int,input().split()))
A.sort()
B.sort()
C.sort()
ans=0
from bisect import bisect_left,bisect_right
for i in B:
ans+=(bisect_left(A,i))*(N-bisect_right(C,i))
print(ans)
``` | instruction | 0 | 70,612 | 16 | 141,224 |
Yes | output | 1 | 70,612 | 16 | 141,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
import sys
import bisect
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
c = list(map(int, sys.stdin.readline().split()))
a.sort()
b.sort()
c.sort()
r = 0
for bn in b:
cn = n - bisect.bisect_right(c, bn)
an = bisect.bisect_left(a, bn)
r += an * cn
print(r)
``` | instruction | 0 | 70,613 | 16 | 141,226 |
Yes | output | 1 | 70,613 | 16 | 141,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
n=int(input())
a=sorted(list(map(int,input().split())))
b=sorted(list(map(int,input().split())))
c=sorted(list(map(int,input().split())))
import bisect
ans=0
for i in range(n):
num_a=bisect.bisect_left(a,b[i])
idx_c=bisect.bisect_right(c,b[i])
num_c=n-idx_c
ans+=num_a*num_c
print(ans)
``` | instruction | 0 | 70,614 | 16 | 141,228 |
Yes | output | 1 | 70,614 | 16 | 141,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
import bisect
n = int(input())
a = sorted(map(int,input().split()))
b = sorted(map(int,input().split()))
c = sorted(map(int,input().split()))
aa = [0] * n
bb = [0] * n
for i in range(n):
bb[i] = n - bisect.bisect_right(c,b[i])
for i in range(n):
aa[i] = sum(bb[bisect.bisect_right(b,a[i]):])
print(sum(aa))
``` | instruction | 0 | 70,615 | 16 | 141,230 |
No | output | 1 | 70,615 | 16 | 141,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
# -*- coding: utf-8 -*-
#ARC084C
import sys
import math
n=int(input())
tmp = input().split()
a = list(map(lambda a: int(a), tmp))
tmp = input().split()
b = list(map(lambda a: int(a), tmp))
tmp = input().split()
c = list(map(lambda a: int(a), tmp))
a.sort()
b.sort()
#c.sort()
#print(a)
#print(b)
#print(c)
sum=0
for i in range(0,n):
for j in range(0,n):
if(b[j]<c[i]):
for k in range(0,n):
if(a[k]<b[j]):
# print("goal i:{} j:{} k:{}".format(c[i],b[j],a[k]))
sum+=1
else:
break
else:
break
print(sum)
``` | instruction | 0 | 70,616 | 16 | 141,232 |
No | output | 1 | 70,616 | 16 | 141,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
N = int(input())
A = [int(a) for a in input().split()]
B = [int(b) for b in input().split()]
C = [int(c) for c in input().split()]
A.sort()
B.sort()
C.sort()
A_pat = [0] * N
B_pat = [0] * N
c = 0
for b in range(N):
for i in range(c,N):
if B[b] < C[i]:
c = i
B_pat[b] = N-i
break
b = 0
for a in range(N):
for i in range(b,N):
if A[a] < B[i]:
b = i
A_pat[a] = sum(B_pat[i:])
break
print(sum(A_pat))
``` | instruction | 0 | 70,617 | 16 | 141,234 |
No | output | 1 | 70,617 | 16 | 141,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.
He has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.
To build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.
How many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.
Constraints
* 1 \leq N \leq 10^5
* 1 \leq A_i \leq 10^9(1\leq i\leq N)
* 1 \leq B_i \leq 10^9(1\leq i\leq N)
* 1 \leq C_i \leq 10^9(1\leq i\leq N)
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 ... A_N
B_1 ... B_N
C_1 ... C_N
Output
Print the number of different altars that Ringo can build.
Examples
Input
2
1 5
2 4
3 6
Output
3
Input
3
1 1 1
2 2 2
3 3 3
Output
27
Input
6
3 14 159 2 6 53
58 9 79 323 84 6
2643 383 2 79 50 288
Output
87
Submitted Solution:
```
import bisect
N = int(input())
A = []
for _ in range(3):
a = list(map(int, input().split()))
a.sort()
A.append(a)
print(A)
ans = 0
for b in A[1]:
a = bisect.bisect_left(A[0], b)
c = bisect.bisect_right(A[2], b)
ans += a * (N-c)
print(ans)
``` | instruction | 0 | 70,618 | 16 | 141,236 |
No | output | 1 | 70,618 | 16 | 141,237 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,619 | 16 | 141,238 |
"Correct Solution:
```
h,w = map(int,input().split())
ans = float("Inf")
if h % 3 == 0 or w % 3 == 0:
print(0)
exit()
for i in range(1,h):
a = (h-i)*(w//2)
b = (h-i)*-(-w//2)
ans = min(ans,abs(max(i*w,a,b)-min(i*w,a,b)))
for i in range(1,w):
a = (w-i)*(h//2)
b = (w-i)*-(-h//2)
ans = min(ans,abs(max(i*h,a,b)-min(i*h,a,b)))
print(min(ans,h,w))
``` | output | 1 | 70,619 | 16 | 141,239 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,620 | 16 | 141,240 |
"Correct Solution:
```
h,w=map(int,input().split())
ans=10**9
for i in range(1,w):
ans=min(max(abs(i*h-h//2*(w-i)),abs(i*h-(h+1)//2*(w-i)),((h+1)//2-h//2)*(w-i)),ans)
for i in range(1,h):
ans=min(max(abs(i*w-w//2*(h-i)),abs(i*w-(w+1)//2*(h-i)),((w+1)//2-w//2)*(h-i)),ans)
if h%3==0 or w%3==0:
ans=0
else:
ans=min(ans,h,w)
print(ans)
``` | output | 1 | 70,620 | 16 | 141,241 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,621 | 16 | 141,242 |
"Correct Solution:
```
def solve(s1, s2, s3):
S = [s1, s2, s3]
return(max(S) - min(S))
H, W = map(int, input().split())
S = H * W
for j in range(1, W):
S1 = H * j
i = H // 2
S2 = (W - j) * i
S3 = (W - j) * (H - i)
S = min(S, solve(S1, S2, S3))
for i in range(1, H):
S1 = W * i
j = W // 2
S2 = (H - i) * j
S3 = (H - i) * (W - j)
S = min(S, solve(S1, S2, S3))
S = min(S, H * (W % 3 > 0))
S = min(S, W * (H % 3 > 0))
print(S)
``` | output | 1 | 70,621 | 16 | 141,243 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,622 | 16 | 141,244 |
"Correct Solution:
```
h,w = sorted(list(map(int,input().split())))
if h % 3 == 0 or w % 3 == 0:
ans = 0
else:
c1 = ((w//3+1)*h)-((w-1-w//3)*(h//2))
c2 = ((w-w//3)*(h-h//2))-(w//3*h)
c3 = h
c4 = ((h//3+1)*w)-((h-1-h//3)*(w//2))
c5 = ((h-h//3)*(w-w//2))-(h//3*w)
ans = min(c1,c2,c3,c4,c5)
print(ans)
``` | output | 1 | 70,622 | 16 | 141,245 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,623 | 16 | 141,246 |
"Correct Solution:
```
h,w=map(int,input().split())
ans=10**5
for _ in range(2):
for i in range(1,h):
th=(h-i)//2
m1=max(i*w,th*w,(h-i-th)*w)-min(i*w,th*w,(h-i-th)*w)
tw=w//2
m2=max(i*w,(h-i)*tw,(h-i)*(w-tw))-min(i*w,(h-i)*tw,(h-i)*(w-tw))
ans=min(ans,m1,m2)
h,w=w,h
print(ans)
``` | output | 1 | 70,623 | 16 | 141,247 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,624 | 16 | 141,248 |
"Correct Solution:
```
import math
H,W=map(int,input().split())
d=[H,W],[W,H]
ans=10**15
for x,y in d:
for i in range(1,x):
A=(x-i)*y;B=i*y
if(i%2==0 or y%2==0):
ans=min(ans,max(A,B//2)-min(A,B//2))
else:
e=[y,i],[i,y]
for c,d in e:
C=math.floor(c/2)*d;D=math.ceil(c/2)*d
ans=min(ans,max(A,C,D)-min(A,C,D))
print(ans)
``` | output | 1 | 70,624 | 16 | 141,249 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,625 | 16 | 141,250 |
"Correct Solution:
```
h,w=map(int,input().split());f=lambda x:max(x)-min(x);g=lambda h,w:min([min(f([j if j else -1e9for j in[i*w,((h-i)//2)*w,((h-i)-(h-i)//2)*w]]),f([j if j else -1e9for j in[i*w,(h-i)*(w//2),(h-i)*(w-w//2)]]))for i in range(1,h)]);print(min(g(h,w),g(w,h)))
``` | output | 1 | 70,625 | 16 | 141,251 |
Provide a correct Python 3 solution for this coding contest problem.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000 | instruction | 0 | 70,626 | 16 | 141,252 |
"Correct Solution:
```
H,W = map(int,input().split())
s = H*W
def func(h,w):
tmp = float("inf")
for x in range(1,w):
s1 = h*x
s2 = (w-x)*(h//2)
s3 = s - s1 - s2
d = max(s1,s2,s3) - min(s1,s2,s3)
if d < tmp:
tmp = d
return tmp
ans = min(func(H,W),func(W,H),min(W%3,1)*H,(min(H%3,1)*W))
print(ans)
``` | output | 1 | 70,626 | 16 | 141,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
def main():
h, w = map(int, input().split())
S = h*w
if S%3==0:
return 0
ds = [h, w]
h1 = (h+1)//3
s1 = h1*w; s2 = w//2*(h-h1); s3 = S-s1-s2
ds.append(max(s1,s2,s3)-min(s1,s2,s3))
w1 = (w+1)//3
s1 = w1*h; s2 = h//2*(w-w1); s3 = S-s1-s2
ds.append(max(s1,s2,s3)-min(s1,s2,s3))
return min(ds)
print(main())
``` | instruction | 0 | 70,627 | 16 | 141,254 |
Yes | output | 1 | 70,627 | 16 | 141,255 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
h, w = map(int, input().split())
if (h % 3) * (w % 3) == 0:
print(0)
exit()
ans = min(h, w)
a = [0,0,0]
for i in range(2):
b = h // 3 + i
a[0] = b * w
a[1] = (h - b) * (w // 2)
a[2] = (h - b) * (w - (w // 2))
ans = min(ans, max(a) - min(a))
for i in range(2):
b = w // 3 + i
a[0] = b * h
a[1] = (w - b) * (h // 2)
a[2] = (w - b) * (h - (h // 2))
ans = min(ans, max(a) - min(a))
print(ans)
``` | instruction | 0 | 70,628 | 16 | 141,256 |
Yes | output | 1 | 70,628 | 16 | 141,257 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
H,W=map(int,input().split())
def calc2(H,W):
if H>W:
H,W=W,H
if H%2==1 and W%2==1:
return [H*(W//2),H*W-H*(W//2)]
else:
return [H*W//2]
def calc(H,H2,W):
SQ=[H2*W]
SQ+=calc2(H-H2,W)
return max(SQ)-min(SQ)
ANS=float("inf")
ANS=min(ANS,calc(H,H//3,W))
ANS=min(ANS,calc(H,H//3+1,W))
ANS=min(ANS,calc(W,W//3,H))
ANS=min(ANS,calc(W,W//3+1,H))
print(ANS)
``` | instruction | 0 | 70,629 | 16 | 141,258 |
Yes | output | 1 | 70,629 | 16 | 141,259 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
W,H = map(int,input().split())
ans = 10**30
for i in range(1,W):
a = H*i
w = W - i
b = max((w//2)*H,w*(H//2))
c = w*H - b
x = max(a,b,c) - min(a,b,c)
ans = min(ans,x)
for i in range(1,H):
a = W*i
h = H - i
b = max((W//2)*h,W*(h//2))
c = h*W - b
x = max(a,b,c) - min(a,b,c)
ans = min(ans,x)
print(ans)
``` | instruction | 0 | 70,630 | 16 | 141,260 |
Yes | output | 1 | 70,630 | 16 | 141,261 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)
H, W = map(int, input().split())
if H > W:
H, W = W, H
if H%3 == 0 or W%3 == 0:
print(0)
elif H%2 == 0:
H_div = H//2
W_div = round(W/3)
print(abs(H_div*(W-W_div) - H*W_div))
elif W%2 == 0:
W_div = W//2
H_div = round(H/3)
print(abs(W_div*(H-H_div) - W*H_div))
else:
H_div = round(H/3)
W_div = W//2
H_div2 = H//2
W_div2 = round(W/3)
print(min(abs(H_div*W - (H-H_div)*W_div), abs(W_div2*H - (W-W_div2)*H_div2)))
``` | instruction | 0 | 70,631 | 16 | 141,262 |
No | output | 1 | 70,631 | 16 | 141,263 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
h,w=map(int,input().split())
if h%3==0 or w%3==0:
print(0)
else:
ans=float('inf')
for i in range(1,h):
c=max(i*(w//2),i*(w-w//2),(h-i)*w)-min(i*(w//2),i*(w-w//2),(h-i)*w)
if ans>c:
ans=c
for i in range(1,w):
c=max(i*(h//2),i*(h-h//2),(w-i)*h)-min(i*(h//2),i*(h-h//2),(w-i)*h)
if ans>c:
ans=c
print(ans)
``` | instruction | 0 | 70,632 | 16 | 141,264 |
No | output | 1 | 70,632 | 16 | 141,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
#!usr/bin/env python3
from collections import defaultdict
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = I()
return l
def LIR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = LI()
return l
def SR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = S()
return l
def LSR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = SR()
return l
mod = 1000000007
#A
#B
#C
h,w = LI()
ans = float("inf")
if h%3 == 0 or w%3 == 0:
print(0)
quit()
x = w//2
y = h//2
if not w%2:
for i in range(1,h):
ans = min(ans,abs(w*i-x*(h-i)))
else:
for i in range(1,h):
if w*i < x*(h-i):
ans = min(ans,abs(w*i-(x+1)*(h-i)))
elif w*i < (x+1)*(h-i):
ans = min(ans,h-i)
else:
ans = min(ans,abs(w*i-x*(h-i)))
if not h%2:
for i in range(1,w):
ans = min(ans,abs(h*i-y*(w-i)))
else:
for i in range(1,w):
if h*i < y*(w-i):
ans = min(ans,abs(h*i-(y+1)*(w-i)))
elif h*i < (y+1)*(w-i):
ans = min(ans,w-i)
else:
ans = min(ans,abs(h*i-y*(w-i)))
print(ans)
#D
#E
#F
#G
#H
#I
#J
#K
#L
#M
#N
#O
#P
#Q
#R
#S
#T
``` | instruction | 0 | 70,633 | 16 | 141,266 |
No | output | 1 | 70,633 | 16 | 141,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle.
Snuke is trying to divide the bar as evenly as possible. More specifically, he is trying to minimize S_{max} - S_{min}, where S_{max} is the area (the number of blocks contained) of the largest piece, and S_{min} is the area of the smallest piece. Find the minimum possible value of S_{max} - S_{min}.
Constraints
* 2 ≤ H, W ≤ 10^5
Input
Input is given from Standard Input in the following format:
H W
Output
Print the minimum possible value of S_{max} - S_{min}.
Examples
Input
3 5
Output
0
Input
4 5
Output
2
Input
5 5
Output
4
Input
100000 2
Output
1
Input
100000 100000
Output
50000
Submitted Solution:
```
def a(n,m):
l1=n//3*2+1
l2=n-l1
l3=m//2
l4=m-l3
A=[l2*m,l1*l3,l1*l4]
return max(A)-min(A)
h,w=map(int,input().split())
if h%3==0 or w%3==0:
print(0)
else:
print(min(a(h,w),a(w,h)))
``` | instruction | 0 | 70,634 | 16 | 141,268 |
No | output | 1 | 70,634 | 16 | 141,269 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,636 | 16 | 141,272 |
"Correct Solution:
```
n,l=map(int,input().split())
a=list(map(int,input().split()))
ok=False
for i in range(n-1):
if a[i]+a[i+1]>=l:
ok=True
idx=i
if ok:
print("Possible")
for i in range(1,idx+1):
print(i)
for i in reversed(range(idx+2,n)):
print(i)
print(idx+1)
else:
print("Impossible")
``` | output | 1 | 70,636 | 16 | 141,273 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,637 | 16 | 141,274 |
"Correct Solution:
```
n, l = map(int, input().split())
a = list(map(int, input().split()))
ma = 0
midx = 0
for i in range(n - 1):
if ma < a[i] + a[i + 1]:
midx = i
ma = a[i] + a[i + 1]
if l > ma:
print('Impossible')
else:
print('Possible')
for i in range(midx):
print(i + 1)
for i in range(n - 1, midx, -1):
print(i)
``` | output | 1 | 70,637 | 16 | 141,275 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,638 | 16 | 141,276 |
"Correct Solution:
```
n,l=[int(x) for x in input().split()]
a=[int(x) for x in input().split()]
j=-1
for i in range(n-1):
if a[i]+a[i+1]>=l:
j=i
break
if j==-1:
print("Impossible")
else:
#print(j)
print("Possible")
for i in range(j):
print(i+1)
for i in range(n-1,j,-1):
print(i)
``` | output | 1 | 70,638 | 16 | 141,277 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,639 | 16 | 141,278 |
"Correct Solution:
```
def s():
n, l, *a = map(int, open(0).read().split())
for i, (x, y) in enumerate(zip(a, a[1:])):
if x + y >= l:
print("Possible")
r = list(range(n))
print("\n".join(map(str, r[1:i + 1] + r[n:i:-1])))
break
else:
print("Impossible")
if __name__=="__main__":
s()
``` | output | 1 | 70,639 | 16 | 141,279 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,640 | 16 | 141,280 |
"Correct Solution:
```
n,l=map(int,input().split())
A=list(map(int,input().split()))
for i in range(n-1):
if A[i]+A[i+1]>=l:
print('Possible')
t=i+1
break
else:
print('Impossible')
exit()
for i in range(1,t):
print(i)
for i in range(n-1,t,-1):
print(i)
print(t)
``` | output | 1 | 70,640 | 16 | 141,281 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,641 | 16 | 141,282 |
"Correct Solution:
```
def main():
N, L, *A = map(int, open(0).read().split())
L = [i for i,(x,y) in enumerate(zip(A, A[1:]), 1) if x+y >= L]
if L:
print("Possible")
B = [i for i in range(L[0], N)]+[i for i in range(1,L[0])][::-1]
print(*B[::-1], sep="\n")
else:
print("Impossible")
if __name__ == "__main__":
main()
``` | output | 1 | 70,641 | 16 | 141,283 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,642 | 16 | 141,284 |
"Correct Solution:
```
n,l = map(int,input().split())
a = list(map(int,input().split()))
for i in range(n-1):
if a[i] + a[i+1] >= l:
print("Possible")
break
else:
print("Impossible")
exit()
li = list(range(1,i+1))+list(range(n-1,i+1,-1))+[i+1]
for x in li:
print(x)
``` | output | 1 | 70,642 | 16 | 141,285 |
Provide a correct Python 3 solution for this coding contest problem.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4 | instruction | 0 | 70,643 | 16 | 141,286 |
"Correct Solution:
```
n,l = map(int, input().split())
a = list(map(int, input().split()))
sumax=0
for i in range(n-1):
if sumax < a[i]+a[i+1]:
sumax=a[i]+a[i+1]
ind=i
if sumax < l:
print("Impossible")
exit()
print("Possible")
for i in range(1,n):
if i>ind:
break
print(i)
for i in reversed(range(n)):
if i==ind:
break
print(i)
``` | output | 1 | 70,643 | 16 | 141,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
N,L = map(int,input().split())
A = list(map(int,input().split()))
untiable = False
lastknot = None
for i in range(N-1):
if A[i]+A[i+1] >= L:
untiable = True
lastknot = i+1
break
if untiable:
ans = [i for i in range(1,lastknot)] + [i for i in range(lastknot+1,N)[::-1]] + [lastknot]
print('Possible')
print('\n'.join(map(str,ans)))
else:
print('Impossible')
``` | instruction | 0 | 70,644 | 16 | 141,288 |
Yes | output | 1 | 70,644 | 16 | 141,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
N, L = map(int, input().split())
A = list(map(int, input().split()))
d = [A[i] + A[i+1] for i in range(N-1)]
if max(d) < L:
print("Impossible")
else:
print("Possible")
j = 0
while d[j] < L:
j += 1
for i in range(j):
print(i+1)
for i in range(j, N-1):
print(N-i+j-1)
``` | instruction | 0 | 70,645 | 16 | 141,290 |
Yes | output | 1 | 70,645 | 16 | 141,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
#C
#各ペアについてみていき、一つでもｌ以上⇔Possible
n,l = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
maxsum=0
maxind = 0
for i in range(n-1):
s = a[i]+a[i+1]
if s > maxsum:
maxsum = s
maxind = i+1
if maxsum<l:
print("Impossible")
else:
print("Possible")
for i in range(1,maxind):
print(i)
for i in range(n-1,maxind,-1):
print(i)
print(maxind)
``` | instruction | 0 | 70,646 | 16 | 141,292 |
Yes | output | 1 | 70,646 | 16 | 141,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
N, L, *a = map(int, open(0).read().split())
for i, (n, m) in enumerate(zip(a, a[1:]), 1):
if n + m >= L:
print('Possible')
print('\n'.join(c for it in (range(1,i), range(N-1,i,-1), [i]) for c in map(str, it)))
break
else:
print('Impossible')
``` | instruction | 0 | 70,647 | 16 | 141,294 |
Yes | output | 1 | 70,647 | 16 | 141,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
# -*- coding: utf-8 -*-
#############
# Libraries #
#############
import sys
input = sys.stdin.readline
import math
from collections import deque
from fractions import gcd
from functools import lru_cache
#############
# Constants #
#############
MOD = 10**9+7
INF = float('inf')
#############
# Functions #
#############
######INPUT######
def inputI(): return int(input().strip())
def inputS(): return input().strip()
def inputIL(): return list(map(int,input().split()))
def inputSL(): return list(map(str,input().split()))
def inputILs(n): return list(int(input()) for _ in range(n))
def inputSLs(n): return list(input().strip() for _ in range(n))
def inputILL(n): return [list(map(int, input().split())) for _ in range(n)]
def inputSLL(n): return [list(map(str, input().split())) for _ in range(n)]
#####Inverse#####
def inv(n): return pow(n, MOD-2, MOD)
######Combination######
kaijo_memo = []
def kaijo(n):
if(len(kaijo_memo) > n):
return kaijo_memo[n]
if(len(kaijo_memo) == 0):
kaijo_memo.append(1)
while(len(kaijo_memo) <= n):
kaijo_memo.append(kaijo_memo[-1] * len(kaijo_memo) % MOD)
return kaijo_memo[n]
gyaku_kaijo_memo = []
def gyaku_kaijo(n):
if(len(gyaku_kaijo_memo) > n):
return gyaku_kaijo_memo[n]
if(len(gyaku_kaijo_memo) == 0):
gyaku_kaijo_memo.append(1)
while(len(gyaku_kaijo_memo) <= n):
gyaku_kaijo_memo.append(gyaku_kaijo_memo[-1] * pow(len(gyaku_kaijo_memo),MOD-2,MOD) % MOD)
return gyaku_kaijo_memo[n]
def nCr(n,r):
if(n == r):
return 1
if(n < r or r < 0):
return 0
ret = 1
ret = ret * kaijo(n) % MOD
ret = ret * gyaku_kaijo(r) % MOD
ret = ret * gyaku_kaijo(n-r) % MOD
return ret
######Factorization######
def factorization(n):
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i==0:
cnt=0
while temp%i==0:
cnt+=1
temp //= i
arr.append([i, cnt])
if temp!=1:
arr.append([temp, 1])
if arr==[]:
arr.append([n, 1])
return arr
#####LCM#####
def lcm(a, b):
return a * b // gcd (a, b)
#############
# Main Code #
#############
N,L = inputIL()
A = inputIL()
M = max(A)
for i in range(N):
if A[i]==M:
index = i
if index == 0:
if A[0]+A[1] >= L:
print("Possible")
for i in range(N-1)[::-1]:
print(i+1)
else:
print("Impossible")
elif index == N-1:
if A[N-1]+A[N-2] >= L:
print("Possible")
for i in range(N-1):
print(i+1)
else:
print("Impossible")
else:
if A[index]+A[index-1] >= L:
print("Possible")
for i in range(index,N-1)[::-1]:
print(i+1)
for i in range(index):
print(i+1)
elif A[index]+A[index+1] >= L:
print("Possible")
for i in range(index):
print(i+1)
for i in range(index,N-1)[::-1]:
print(i+1)
else:
print("Impossible")
``` | instruction | 0 | 70,648 | 16 | 141,296 |
No | output | 1 | 70,648 | 16 | 141,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N pieces of ropes, numbered 1 through N. The length of piece i is a_i.
At first, for each i (1≤i≤N-1), piece i and piece i+1 are tied at the ends, forming one long rope with N-1 knots. Snuke will try to untie all of the knots by performing the following operation repeatedly:
* Choose a (connected) rope with a total length of at least L, then untie one of its knots.
Is it possible to untie all of the N-1 knots by properly applying this operation? If the answer is positive, find one possible order to untie the knots.
Constraints
* 2≤N≤10^5
* 1≤L≤10^9
* 1≤a_i≤10^9
* All input values are integers.
Input
The input is given from Standard Input in the following format:
N L
a_1 a_2 ... a_n
Output
If it is not possible to untie all of the N-1 knots, print `Impossible`.
If it is possible to untie all of the knots, print `Possible`, then print another N-1 lines that describe a possible order to untie the knots. The j-th of those N-1 lines should contain the index of the knot that is untied in the j-th operation. Here, the index of the knot connecting piece i and piece i+1 is i.
If there is more than one solution, output any.
Examples
Input
3 50
30 20 10
Output
Possible
2
1
Input
2 21
10 10
Output
Impossible
Input
5 50
10 20 30 40 50
Output
Possible
1
2
3
4
Submitted Solution:
```
N, L = map(int, input().split())
A = list(map(int, input().split()))
ans_index = -1
for i in range(N-1):
if A[i] + A[i+1] >= L:
ans_index = i+1
break
if ans_index == -1:
print('Impossible')
exit()
print('Possible')
for i in range(1, N):
if i == ans_index:
continue
print(i)
print(ans_index)
``` | instruction | 0 | 70,649 | 16 | 141,298 |
No | output | 1 | 70,649 | 16 | 141,299 |
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