message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is smaller than the current one. Alyona ca... | instruction | 0 | 25,211 | 12 | 50,422 |
Tags: sortings
Correct Solution:
```
n = int(input())
mex = 1
for num in sorted(map(int, input().split())):
if num >= mex:
mex += 1
print(mex)
``` | output | 1 | 25,211 | 12 | 50,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,212 | 12 | 50,424 |
Yes | output | 1 | 25,212 | 12 | 50,425 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,213 | 12 | 50,426 |
Yes | output | 1 | 25,213 | 12 | 50,427 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,214 | 12 | 50,428 |
Yes | output | 1 | 25,214 | 12 | 50,429 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,215 | 12 | 50,430 |
Yes | output | 1 | 25,215 | 12 | 50,431 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,216 | 12 | 50,432 |
No | output | 1 | 25,216 | 12 | 50,433 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,217 | 12 | 50,434 |
No | output | 1 | 25,217 | 12 | 50,435 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,218 | 12 | 50,436 |
No | output | 1 | 25,218 | 12 | 50,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Someone gave Alyona an array containing n positive integers a1, a2, ..., an. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer ... | instruction | 0 | 25,219 | 12 | 50,438 |
No | output | 1 | 25,219 | 12 | 50,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,266 | 12 | 50,532 |
Tags: combinatorics, dp, math
Correct Solution:
```
n,k =map(int,input().split())
ans=[1,0]
#dearrangment [0,1,2,9]
#D(n) = nCx* (d(n-1)+d(n-2))
#n choose 2
ans.append(n*(n-1)//2)
#n choose 3
ans.append(n*(n-1)*(n-2)//3)
#n choose 4
ans.append(n*(n-1)*(n-2)*(n-3)*3//8)
print(sum(ans[:k+1]))
``` | output | 1 | 25,266 | 12 | 50,533 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,267 | 12 | 50,534 |
Tags: combinatorics, dp, math
Correct Solution:
```
n, k = map(int, input().split()); ans = 1; ct = n
spoils = [0, 1, 1, 2, 9]
for i in range(2, k + 1):
ct = ct*(n - i + 1) // i
ans += ct*spoils[i]
print(ans)
``` | output | 1 | 25,267 | 12 | 50,535 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,268 | 12 | 50,536 |
Tags: combinatorics, dp, math
Correct Solution:
```
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(m... | output | 1 | 25,268 | 12 | 50,537 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,269 | 12 | 50,538 |
Tags: combinatorics, dp, math
Correct Solution:
```
def C(n, k):
res = 1
for i in range(1, k + 1):
res *= (n - i + 1)
for i in range(2, k + 1):
res //= i
return res
if __name__ == "__main__":
n, k = map(int, input().split())
ans = 1
val = {
1: 1,
2: 2,
3: 9,
}
for i in range(k, 1, -1):
ans +=... | output | 1 | 25,269 | 12 | 50,539 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,270 | 12 | 50,540 |
Tags: combinatorics, dp, math
Correct Solution:
```
a,b=map(int,input().split())
s=1
if b>=2:
s+=a*(a-1)>>1
if b>=3:
s+=a*(a-1)*(a-2)/3
if b==4:
s+=3*a*(a-1)*(a-2)*(a-3)>>3
print(int(s))
``` | output | 1 | 25,270 | 12 | 50,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,271 | 12 | 50,542 |
Tags: combinatorics, dp, math
Correct Solution:
```
from sys import stdin, stdout
def solve(n):
ret = factor[n]
for i in range(1, n+1):
ret += (-1 if i % 2 == 1 else 1) * C[n][i] * factor[n-i]
return ret
n, k = map(int, input().split())
C = [[0 for j in range(n+1)] for i in range(n+1)]
for i in ... | output | 1 | 25,271 | 12 | 50,543 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,272 | 12 | 50,544 |
Tags: combinatorics, dp, math
Correct Solution:
```
import math
from sys import stdin
string = stdin.readline().strip().split()
n=int(string[0])
k=int(string[1])
def factorial(N):
result=1
for i in range(1,N+1):
result*=i
return result
output=1
for i in range(2,k+1):
if i==2:
output=outp... | output | 1 | 25,272 | 12 | 50,545 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n - k indices i (1 ≤ i ≤ n) such that pi = i.
You... | instruction | 0 | 25,273 | 12 | 50,546 |
Tags: combinatorics, dp, math
Correct Solution:
```
def nCr(n,r):
p = 1
for i in range(n,n-r,-1):
p*=i
for i in range(1,r+1):
p//=i
return p
n,k = list(map(int,input().split()))
out = 1
if k>=2:
out += nCr(n,2)
if k>=3:
out += 2*nCr(n,3)
if k==4:
out += 9*nCr(n,4)
print(out)... | output | 1 | 25,273 | 12 | 50,547 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,274 | 12 | 50,548 |
Yes | output | 1 | 25,274 | 12 | 50,549 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,275 | 12 | 50,550 |
Yes | output | 1 | 25,275 | 12 | 50,551 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,276 | 12 | 50,552 |
Yes | output | 1 | 25,276 | 12 | 50,553 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,277 | 12 | 50,554 |
Yes | output | 1 | 25,277 | 12 | 50,555 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,278 | 12 | 50,556 |
No | output | 1 | 25,278 | 12 | 50,557 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,279 | 12 | 50,558 |
No | output | 1 | 25,279 | 12 | 50,559 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,280 | 12 | 50,560 |
No | output | 1 | 25,280 | 12 | 50,561 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A permutation p of size n is an array such that every integer from 1 to n occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least n -... | instruction | 0 | 25,281 | 12 | 50,562 |
No | output | 1 | 25,281 | 12 | 50,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,701 | 12 | 51,402 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
test_cases = [(input(), list(map(int, input().split())))[1] for _ in range(int(input()))]
for case in test_cases:
flag = True
for i in range(1, len(case)):
if abs(case[i] - case[i - 1]) > 1:
print('YES')
print(i, i + 1)
flag = ... | output | 1 | 25,701 | 12 | 51,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,702 | 12 | 51,404 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
ar=list(map(int,input().split()))
found=0
for i in range(n-1):
if abs(ar[i]-ar[i+1])>1:
print("YES")
print(i+1,i+2)
found=1
break
if ... | output | 1 | 25,702 | 12 | 51,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,703 | 12 | 51,406 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
if __name__ == '__main__':
ans = []
for t in range(int(input())):
n = int(input())
a = [int(x) for x in input().split()]
for i in range(len(a) - 1):
if abs(a[i] - a[i + 1]) >= 2:
ans.append("YE... | output | 1 | 25,703 | 12 | 51,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,704 | 12 | 51,408 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
t= int(input())
for _ in range(t):
n = int(input())
a = list(map(int,input().split()))
f = -1
for i in range(n-1):
if abs(a[i] - a[i+1]) >= 2:
f = i+1
break
if f == -1:
print("NO")
else:
print("YES")
print(f,f+1)
``` | output | 1 | 25,704 | 12 | 51,409 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,705 | 12 | 51,410 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
from sys import stdin,stdout
for a in range(int(stdin.readline())):
n=int(stdin.readline())
L=list(map(int,input().split()))
f=False
for a in range(len(L)-1):
if(max(L[a],L[a+1])-min(L[a],L[a+1])>=2):
f=True
... | output | 1 | 25,705 | 12 | 51,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,706 | 12 | 51,412 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
l = list(map(int, input().split()))
for i in range(n-1):
if abs(l[i]-l[i+1]) > 1:
print('YES')
print(i+1, i+2, sep=' ')
break
else:
p... | output | 1 | 25,706 | 12 | 51,413 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,707 | 12 | 51,414 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for i in range(int(input())):
n=int(input())
arr=list(map(int,input().split()))
f=0
for i in range(n-1):
if abs(arr[i]-arr[i+1])>=2:
print("YES")
print(i+1, i+2)
f=1
break
if f==... | output | 1 | 25,707 | 12 | 51,415 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, 4, 3] isn't interesting as max(a) - min(a) = 4 ... | instruction | 0 | 25,708 | 12 | 51,416 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for i in range(int(input())):
n = int(input())
l = list(map(int,input().split()))
i = 1
flag = 0
while i < len(l):
if abs(l[i]-l[i-1])>=2:
print("YES")
print(i,i+1)
flag = 1
brea... | output | 1 | 25,708 | 12 | 51,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,709 | 12 | 51,418 |
Yes | output | 1 | 25,709 | 12 | 51,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,710 | 12 | 51,420 |
Yes | output | 1 | 25,710 | 12 | 51,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,711 | 12 | 51,422 |
Yes | output | 1 | 25,711 | 12 | 51,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,712 | 12 | 51,424 |
Yes | output | 1 | 25,712 | 12 | 51,425 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,713 | 12 | 51,426 |
No | output | 1 | 25,713 | 12 | 51,427 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,714 | 12 | 51,428 |
No | output | 1 | 25,714 | 12 | 51,429 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,715 | 12 | 51,430 |
No | output | 1 | 25,715 | 12 | 51,431 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For an array a of integers let's denote its maximal element as max(a), and minimal as min(a). We will call an array a of k integers interesting if max(a) - min(a) ≥ k. For example, array [1, 3, ... | instruction | 0 | 25,716 | 12 | 51,432 |
No | output | 1 | 25,716 | 12 | 51,433 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,750 | 12 | 51,500 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
#!/usr/bin/python3
n = int(input())
a = list(map(int, input().split()))
b = sorted([(a[i], i) for i in range(n)])
res = []
for _ in range(n):
for i in range(n - 1):
if b[i][1] > b[i + 1][1]:
res.append((b[i + 1][1], b[i][1]))
b[i], b[i + 1... | output | 1 | 25,750 | 12 | 51,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,751 | 12 | 51,502 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
n=int(input())
arr=list(map(int,input().split()))
brr=[]
for i in range(n):
for j in range(i+1,n):
if arr[i]>arr[j]:
brr.append((arr[i],i+1,j+1))
brr.sort();brr.sort(reverse=True,key=lambda x:x[2])
print(len(brr))
for a,b,c in... | output | 1 | 25,751 | 12 | 51,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,752 | 12 | 51,504 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
n=int(input())
li=list(map(int,input().split()))
lp=li.copy()
j=1
lf=[]
c=max(lp)
while j<=n:
a=min(lp)
i=lp.index(a)
li[i]=j
lp[i]=c+j
j+=1
while n>1:
a=li.pop()
while a<n:
i=li.index(a+1)
li[i]=a
lf+=[f'{i+1} {n}']
a=a+1
n-=1
print(... | output | 1 | 25,752 | 12 | 51,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,753 | 12 | 51,506 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
# from math import factorial as fac
from collections import defaultdict
# from copy import deepcopy
import sys, math
f = None
try:
f = open('q1.input', 'r')
except IOError:
f = sys.stdin
if 'xrange' in dir(__builtins__):
range = xrange
# print(f... | output | 1 | 25,753 | 12 | 51,507 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,754 | 12 | 51,508 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
n=int(input())
a=[int(i) for i in input().split()]
ans=0
dc=[[] for i in range(n)]
for i in range(n):
for j in range(i):
if(a[i]<a[j]):
dc[i].append((a[j],j))
ans+=1
print(ans)
for i in range(n-1,-1,-1):
dc[i]... | output | 1 | 25,754 | 12 | 51,509 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,755 | 12 | 51,510 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
aWithIndex = []
for i in range(n):
aWithIndex.append((a[i],i))
aWithIndex.sort(key = lambda x: x[0])
aOrder = [-1] * n
for i in range(n):
aOrder[aWithIndex[i][1]] = i
aOrderInverse = [-1] * ... | output | 1 | 25,755 | 12 | 51,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,756 | 12 | 51,512 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
it = lambda: list(map(int, input().strip().split()))
def solve():
N = int(input())
A = it()
inversions = []
for i in range(N):
inversion = []
for j in range(i):
if A[j] > A[i]:
inversion.... | output | 1 | 25,756 | 12 | 51,513 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to write two indices u and v and swap the values a... | instruction | 0 | 25,757 | 12 | 51,514 |
Tags: constructive algorithms, greedy, sortings
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
order = [(l[i],i) for i in range(n)]
order.sort(reverse = True)
out = []
for v, ind in order:
for i in range(ind):
if v < l[i]:
out.append(str(i + 1)+' '+str(ind + 1))
pri... | output | 1 | 25,757 | 12 | 51,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Madeline has an array a of n integers. A pair (u, v) of integers forms an inversion in a if:
* 1 ≤ u < v ≤ n.
* a_u > a_v.
Madeline recently found a magical paper, which allows her to ... | instruction | 0 | 25,758 | 12 | 51,516 |
Yes | output | 1 | 25,758 | 12 | 51,517 |
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